expfmod (used to be hard to sample)

Percentage Accurate: 7.0% → 26.6%
Time: 11.6s
Alternatives: 11
Speedup: 3.9×

Specification

?
\[\begin{array}{l} \\ \left(\left(e^{x}\right) \bmod \left(\sqrt{\cos x}\right)\right) \cdot e^{-x} \end{array} \]
(FPCore (x) :precision binary64 (* (fmod (exp x) (sqrt (cos x))) (exp (- x))))
double code(double x) {
	return fmod(exp(x), sqrt(cos(x))) * exp(-x);
}
real(8) function code(x)
    real(8), intent (in) :: x
    code = mod(exp(x), sqrt(cos(x))) * exp(-x)
end function
def code(x):
	return math.fmod(math.exp(x), math.sqrt(math.cos(x))) * math.exp(-x)
function code(x)
	return Float64(rem(exp(x), sqrt(cos(x))) * exp(Float64(-x)))
end
code[x_] := N[(N[With[{TMP1 = N[Exp[x], $MachinePrecision], TMP2 = N[Sqrt[N[Cos[x], $MachinePrecision]], $MachinePrecision]}, Mod[Abs[TMP1], Abs[TMP2]] * Sign[TMP1]], $MachinePrecision] * N[Exp[(-x)], $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
\left(\left(e^{x}\right) \bmod \left(\sqrt{\cos x}\right)\right) \cdot e^{-x}
\end{array}

Sampling outcomes in binary64 precision:

Local Percentage Accuracy vs ?

The average percentage accuracy by input value. Horizontal axis shows value of an input variable; the variable is choosen in the title. Vertical axis is accuracy; higher is better. Red represent the original program, while blue represents Herbie's suggestion. These can be toggled with buttons below the plot. The line is an average while dots represent individual samples.

Accuracy vs Speed?

Herbie found 11 alternatives:

AlternativeAccuracySpeedup
The accuracy (vertical axis) and speed (horizontal axis) of each alternatives. Up and to the right is better. The red square shows the initial program, and each blue circle shows an alternative.The line shows the best available speed-accuracy tradeoffs.

Initial Program: 7.0% accurate, 1.0× speedup?

\[\begin{array}{l} \\ \left(\left(e^{x}\right) \bmod \left(\sqrt{\cos x}\right)\right) \cdot e^{-x} \end{array} \]
(FPCore (x) :precision binary64 (* (fmod (exp x) (sqrt (cos x))) (exp (- x))))
double code(double x) {
	return fmod(exp(x), sqrt(cos(x))) * exp(-x);
}
real(8) function code(x)
    real(8), intent (in) :: x
    code = mod(exp(x), sqrt(cos(x))) * exp(-x)
end function
def code(x):
	return math.fmod(math.exp(x), math.sqrt(math.cos(x))) * math.exp(-x)
function code(x)
	return Float64(rem(exp(x), sqrt(cos(x))) * exp(Float64(-x)))
end
code[x_] := N[(N[With[{TMP1 = N[Exp[x], $MachinePrecision], TMP2 = N[Sqrt[N[Cos[x], $MachinePrecision]], $MachinePrecision]}, Mod[Abs[TMP1], Abs[TMP2]] * Sign[TMP1]], $MachinePrecision] * N[Exp[(-x)], $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
\left(\left(e^{x}\right) \bmod \left(\sqrt{\cos x}\right)\right) \cdot e^{-x}
\end{array}

Alternative 1: 26.6% accurate, 0.5× speedup?

\[\begin{array}{l} \\ \begin{array}{l} t_0 := \left(\left(e^{x}\right) \bmod \left(\sqrt{\cos x}\right)\right)\\ \mathbf{if}\;e^{-x} \cdot t\_0 \leq 2:\\ \;\;\;\;\frac{1}{\frac{e^{x}}{t\_0}}\\ \mathbf{else}:\\ \;\;\;\;1 \cdot \left(1 \bmod 1\right)\\ \end{array} \end{array} \]
(FPCore (x)
 :precision binary64
 (let* ((t_0 (fmod (exp x) (sqrt (cos x)))))
   (if (<= (* (exp (- x)) t_0) 2.0)
     (/ 1.0 (/ (exp x) t_0))
     (* 1.0 (fmod 1.0 1.0)))))
double code(double x) {
	double t_0 = fmod(exp(x), sqrt(cos(x)));
	double tmp;
	if ((exp(-x) * t_0) <= 2.0) {
		tmp = 1.0 / (exp(x) / t_0);
	} else {
		tmp = 1.0 * fmod(1.0, 1.0);
	}
	return tmp;
}
real(8) function code(x)
    real(8), intent (in) :: x
    real(8) :: t_0
    real(8) :: tmp
    t_0 = mod(exp(x), sqrt(cos(x)))
    if ((exp(-x) * t_0) <= 2.0d0) then
        tmp = 1.0d0 / (exp(x) / t_0)
    else
        tmp = 1.0d0 * mod(1.0d0, 1.0d0)
    end if
    code = tmp
end function
def code(x):
	t_0 = math.fmod(math.exp(x), math.sqrt(math.cos(x)))
	tmp = 0
	if (math.exp(-x) * t_0) <= 2.0:
		tmp = 1.0 / (math.exp(x) / t_0)
	else:
		tmp = 1.0 * math.fmod(1.0, 1.0)
	return tmp
function code(x)
	t_0 = rem(exp(x), sqrt(cos(x)))
	tmp = 0.0
	if (Float64(exp(Float64(-x)) * t_0) <= 2.0)
		tmp = Float64(1.0 / Float64(exp(x) / t_0));
	else
		tmp = Float64(1.0 * rem(1.0, 1.0));
	end
	return tmp
end
code[x_] := Block[{t$95$0 = N[With[{TMP1 = N[Exp[x], $MachinePrecision], TMP2 = N[Sqrt[N[Cos[x], $MachinePrecision]], $MachinePrecision]}, Mod[Abs[TMP1], Abs[TMP2]] * Sign[TMP1]], $MachinePrecision]}, If[LessEqual[N[(N[Exp[(-x)], $MachinePrecision] * t$95$0), $MachinePrecision], 2.0], N[(1.0 / N[(N[Exp[x], $MachinePrecision] / t$95$0), $MachinePrecision]), $MachinePrecision], N[(1.0 * N[With[{TMP1 = 1.0, TMP2 = 1.0}, Mod[Abs[TMP1], Abs[TMP2]] * Sign[TMP1]], $MachinePrecision]), $MachinePrecision]]]
\begin{array}{l}

\\
\begin{array}{l}
t_0 := \left(\left(e^{x}\right) \bmod \left(\sqrt{\cos x}\right)\right)\\
\mathbf{if}\;e^{-x} \cdot t\_0 \leq 2:\\
\;\;\;\;\frac{1}{\frac{e^{x}}{t\_0}}\\

\mathbf{else}:\\
\;\;\;\;1 \cdot \left(1 \bmod 1\right)\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if (*.f64 (fmod.f64 (exp.f64 x) (sqrt.f64 (cos.f64 x))) (exp.f64 (neg.f64 x))) < 2

    1. Initial program 9.0%

      \[\left(\left(e^{x}\right) \bmod \left(\sqrt{\cos x}\right)\right) \cdot e^{-x} \]
    2. Add Preprocessing
    3. Step-by-step derivation
      1. lift-*.f64N/A

        \[\leadsto \color{blue}{\left(\left(e^{x}\right) \bmod \left(\sqrt{\cos x}\right)\right) \cdot e^{-x}} \]
      2. lift-exp.f64N/A

        \[\leadsto \left(\left(e^{x}\right) \bmod \left(\sqrt{\cos x}\right)\right) \cdot \color{blue}{e^{-x}} \]
      3. lift-neg.f64N/A

        \[\leadsto \left(\left(e^{x}\right) \bmod \left(\sqrt{\cos x}\right)\right) \cdot e^{\color{blue}{\mathsf{neg}\left(x\right)}} \]
      4. exp-negN/A

        \[\leadsto \left(\left(e^{x}\right) \bmod \left(\sqrt{\cos x}\right)\right) \cdot \color{blue}{\frac{1}{e^{x}}} \]
      5. lift-exp.f64N/A

        \[\leadsto \left(\left(e^{x}\right) \bmod \left(\sqrt{\cos x}\right)\right) \cdot \frac{1}{\color{blue}{e^{x}}} \]
      6. un-div-invN/A

        \[\leadsto \color{blue}{\frac{\left(\left(e^{x}\right) \bmod \left(\sqrt{\cos x}\right)\right)}{e^{x}}} \]
      7. clear-numN/A

        \[\leadsto \color{blue}{\frac{1}{\frac{e^{x}}{\left(\left(e^{x}\right) \bmod \left(\sqrt{\cos x}\right)\right)}}} \]
      8. lower-/.f64N/A

        \[\leadsto \color{blue}{\frac{1}{\frac{e^{x}}{\left(\left(e^{x}\right) \bmod \left(\sqrt{\cos x}\right)\right)}}} \]
      9. lower-/.f649.0

        \[\leadsto \frac{1}{\color{blue}{\frac{e^{x}}{\left(\left(e^{x}\right) \bmod \left(\sqrt{\cos x}\right)\right)}}} \]
    4. Applied rewrites9.0%

      \[\leadsto \color{blue}{\frac{1}{\frac{e^{x}}{\left(\left(e^{x}\right) \bmod \left(\sqrt{\cos x}\right)\right)}}} \]

    if 2 < (*.f64 (fmod.f64 (exp.f64 x) (sqrt.f64 (cos.f64 x))) (exp.f64 (neg.f64 x)))

    1. Initial program 0.0%

      \[\left(\left(e^{x}\right) \bmod \left(\sqrt{\cos x}\right)\right) \cdot e^{-x} \]
    2. Add Preprocessing
    3. Taylor expanded in x around 0

      \[\leadsto \left(\color{blue}{1} \bmod \left(\sqrt{\cos x}\right)\right) \cdot e^{-x} \]
    4. Step-by-step derivation
      1. Applied rewrites98.2%

        \[\leadsto \left(\color{blue}{1} \bmod \left(\sqrt{\cos x}\right)\right) \cdot e^{-x} \]
      2. Taylor expanded in x around 0

        \[\leadsto \left(1 \bmod \color{blue}{1}\right) \cdot e^{-x} \]
      3. Step-by-step derivation
        1. Applied rewrites98.1%

          \[\leadsto \left(1 \bmod \color{blue}{1}\right) \cdot e^{-x} \]
        2. Taylor expanded in x around 0

          \[\leadsto \left(1 \bmod 1\right) \cdot \color{blue}{1} \]
        3. Step-by-step derivation
          1. Applied rewrites98.2%

            \[\leadsto \left(1 \bmod 1\right) \cdot \color{blue}{1} \]
        4. Recombined 2 regimes into one program.
        5. Final simplification27.5%

          \[\leadsto \begin{array}{l} \mathbf{if}\;e^{-x} \cdot \left(\left(e^{x}\right) \bmod \left(\sqrt{\cos x}\right)\right) \leq 2:\\ \;\;\;\;\frac{1}{\frac{e^{x}}{\left(\left(e^{x}\right) \bmod \left(\sqrt{\cos x}\right)\right)}}\\ \mathbf{else}:\\ \;\;\;\;1 \cdot \left(1 \bmod 1\right)\\ \end{array} \]
        6. Add Preprocessing

        Alternative 2: 26.6% accurate, 0.5× speedup?

        \[\begin{array}{l} \\ \begin{array}{l} t_0 := \left(\left(e^{x}\right) \bmod \left(\sqrt{\cos x}\right)\right)\\ \mathbf{if}\;e^{-x} \cdot t\_0 \leq 2:\\ \;\;\;\;\frac{t\_0}{e^{x}}\\ \mathbf{else}:\\ \;\;\;\;1 \cdot \left(1 \bmod 1\right)\\ \end{array} \end{array} \]
        (FPCore (x)
         :precision binary64
         (let* ((t_0 (fmod (exp x) (sqrt (cos x)))))
           (if (<= (* (exp (- x)) t_0) 2.0) (/ t_0 (exp x)) (* 1.0 (fmod 1.0 1.0)))))
        double code(double x) {
        	double t_0 = fmod(exp(x), sqrt(cos(x)));
        	double tmp;
        	if ((exp(-x) * t_0) <= 2.0) {
        		tmp = t_0 / exp(x);
        	} else {
        		tmp = 1.0 * fmod(1.0, 1.0);
        	}
        	return tmp;
        }
        
        real(8) function code(x)
            real(8), intent (in) :: x
            real(8) :: t_0
            real(8) :: tmp
            t_0 = mod(exp(x), sqrt(cos(x)))
            if ((exp(-x) * t_0) <= 2.0d0) then
                tmp = t_0 / exp(x)
            else
                tmp = 1.0d0 * mod(1.0d0, 1.0d0)
            end if
            code = tmp
        end function
        
        def code(x):
        	t_0 = math.fmod(math.exp(x), math.sqrt(math.cos(x)))
        	tmp = 0
        	if (math.exp(-x) * t_0) <= 2.0:
        		tmp = t_0 / math.exp(x)
        	else:
        		tmp = 1.0 * math.fmod(1.0, 1.0)
        	return tmp
        
        function code(x)
        	t_0 = rem(exp(x), sqrt(cos(x)))
        	tmp = 0.0
        	if (Float64(exp(Float64(-x)) * t_0) <= 2.0)
        		tmp = Float64(t_0 / exp(x));
        	else
        		tmp = Float64(1.0 * rem(1.0, 1.0));
        	end
        	return tmp
        end
        
        code[x_] := Block[{t$95$0 = N[With[{TMP1 = N[Exp[x], $MachinePrecision], TMP2 = N[Sqrt[N[Cos[x], $MachinePrecision]], $MachinePrecision]}, Mod[Abs[TMP1], Abs[TMP2]] * Sign[TMP1]], $MachinePrecision]}, If[LessEqual[N[(N[Exp[(-x)], $MachinePrecision] * t$95$0), $MachinePrecision], 2.0], N[(t$95$0 / N[Exp[x], $MachinePrecision]), $MachinePrecision], N[(1.0 * N[With[{TMP1 = 1.0, TMP2 = 1.0}, Mod[Abs[TMP1], Abs[TMP2]] * Sign[TMP1]], $MachinePrecision]), $MachinePrecision]]]
        
        \begin{array}{l}
        
        \\
        \begin{array}{l}
        t_0 := \left(\left(e^{x}\right) \bmod \left(\sqrt{\cos x}\right)\right)\\
        \mathbf{if}\;e^{-x} \cdot t\_0 \leq 2:\\
        \;\;\;\;\frac{t\_0}{e^{x}}\\
        
        \mathbf{else}:\\
        \;\;\;\;1 \cdot \left(1 \bmod 1\right)\\
        
        
        \end{array}
        \end{array}
        
        Derivation
        1. Split input into 2 regimes
        2. if (*.f64 (fmod.f64 (exp.f64 x) (sqrt.f64 (cos.f64 x))) (exp.f64 (neg.f64 x))) < 2

          1. Initial program 9.0%

            \[\left(\left(e^{x}\right) \bmod \left(\sqrt{\cos x}\right)\right) \cdot e^{-x} \]
          2. Add Preprocessing
          3. Step-by-step derivation
            1. lift-*.f64N/A

              \[\leadsto \color{blue}{\left(\left(e^{x}\right) \bmod \left(\sqrt{\cos x}\right)\right) \cdot e^{-x}} \]
            2. lift-exp.f64N/A

              \[\leadsto \left(\left(e^{x}\right) \bmod \left(\sqrt{\cos x}\right)\right) \cdot \color{blue}{e^{-x}} \]
            3. lift-neg.f64N/A

              \[\leadsto \left(\left(e^{x}\right) \bmod \left(\sqrt{\cos x}\right)\right) \cdot e^{\color{blue}{\mathsf{neg}\left(x\right)}} \]
            4. exp-negN/A

              \[\leadsto \left(\left(e^{x}\right) \bmod \left(\sqrt{\cos x}\right)\right) \cdot \color{blue}{\frac{1}{e^{x}}} \]
            5. lift-exp.f64N/A

              \[\leadsto \left(\left(e^{x}\right) \bmod \left(\sqrt{\cos x}\right)\right) \cdot \frac{1}{\color{blue}{e^{x}}} \]
            6. un-div-invN/A

              \[\leadsto \color{blue}{\frac{\left(\left(e^{x}\right) \bmod \left(\sqrt{\cos x}\right)\right)}{e^{x}}} \]
            7. lower-/.f649.0

              \[\leadsto \color{blue}{\frac{\left(\left(e^{x}\right) \bmod \left(\sqrt{\cos x}\right)\right)}{e^{x}}} \]
          4. Applied rewrites9.0%

            \[\leadsto \color{blue}{\frac{\left(\left(e^{x}\right) \bmod \left(\sqrt{\cos x}\right)\right)}{e^{x}}} \]

          if 2 < (*.f64 (fmod.f64 (exp.f64 x) (sqrt.f64 (cos.f64 x))) (exp.f64 (neg.f64 x)))

          1. Initial program 0.0%

            \[\left(\left(e^{x}\right) \bmod \left(\sqrt{\cos x}\right)\right) \cdot e^{-x} \]
          2. Add Preprocessing
          3. Taylor expanded in x around 0

            \[\leadsto \left(\color{blue}{1} \bmod \left(\sqrt{\cos x}\right)\right) \cdot e^{-x} \]
          4. Step-by-step derivation
            1. Applied rewrites98.2%

              \[\leadsto \left(\color{blue}{1} \bmod \left(\sqrt{\cos x}\right)\right) \cdot e^{-x} \]
            2. Taylor expanded in x around 0

              \[\leadsto \left(1 \bmod \color{blue}{1}\right) \cdot e^{-x} \]
            3. Step-by-step derivation
              1. Applied rewrites98.1%

                \[\leadsto \left(1 \bmod \color{blue}{1}\right) \cdot e^{-x} \]
              2. Taylor expanded in x around 0

                \[\leadsto \left(1 \bmod 1\right) \cdot \color{blue}{1} \]
              3. Step-by-step derivation
                1. Applied rewrites98.2%

                  \[\leadsto \left(1 \bmod 1\right) \cdot \color{blue}{1} \]
              4. Recombined 2 regimes into one program.
              5. Final simplification27.5%

                \[\leadsto \begin{array}{l} \mathbf{if}\;e^{-x} \cdot \left(\left(e^{x}\right) \bmod \left(\sqrt{\cos x}\right)\right) \leq 2:\\ \;\;\;\;\frac{\left(\left(e^{x}\right) \bmod \left(\sqrt{\cos x}\right)\right)}{e^{x}}\\ \mathbf{else}:\\ \;\;\;\;1 \cdot \left(1 \bmod 1\right)\\ \end{array} \]
              6. Add Preprocessing

              Alternative 3: 26.4% accurate, 0.5× speedup?

              \[\begin{array}{l} \\ \begin{array}{l} t_0 := e^{-x}\\ \mathbf{if}\;t\_0 \cdot \left(\left(e^{x}\right) \bmod \left(\sqrt{\cos x}\right)\right) \leq 2:\\ \;\;\;\;\left(\left(e^{x}\right) \bmod \left(\sqrt{\mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(-0.001388888888888889, x \cdot x, 0.041666666666666664\right), x \cdot x, -0.5\right), x \cdot x, 1\right)}\right)\right) \cdot t\_0\\ \mathbf{else}:\\ \;\;\;\;1 \cdot \left(1 \bmod 1\right)\\ \end{array} \end{array} \]
              (FPCore (x)
               :precision binary64
               (let* ((t_0 (exp (- x))))
                 (if (<= (* t_0 (fmod (exp x) (sqrt (cos x)))) 2.0)
                   (*
                    (fmod
                     (exp x)
                     (sqrt
                      (fma
                       (fma
                        (fma -0.001388888888888889 (* x x) 0.041666666666666664)
                        (* x x)
                        -0.5)
                       (* x x)
                       1.0)))
                    t_0)
                   (* 1.0 (fmod 1.0 1.0)))))
              double code(double x) {
              	double t_0 = exp(-x);
              	double tmp;
              	if ((t_0 * fmod(exp(x), sqrt(cos(x)))) <= 2.0) {
              		tmp = fmod(exp(x), sqrt(fma(fma(fma(-0.001388888888888889, (x * x), 0.041666666666666664), (x * x), -0.5), (x * x), 1.0))) * t_0;
              	} else {
              		tmp = 1.0 * fmod(1.0, 1.0);
              	}
              	return tmp;
              }
              
              function code(x)
              	t_0 = exp(Float64(-x))
              	tmp = 0.0
              	if (Float64(t_0 * rem(exp(x), sqrt(cos(x)))) <= 2.0)
              		tmp = Float64(rem(exp(x), sqrt(fma(fma(fma(-0.001388888888888889, Float64(x * x), 0.041666666666666664), Float64(x * x), -0.5), Float64(x * x), 1.0))) * t_0);
              	else
              		tmp = Float64(1.0 * rem(1.0, 1.0));
              	end
              	return tmp
              end
              
              code[x_] := Block[{t$95$0 = N[Exp[(-x)], $MachinePrecision]}, If[LessEqual[N[(t$95$0 * N[With[{TMP1 = N[Exp[x], $MachinePrecision], TMP2 = N[Sqrt[N[Cos[x], $MachinePrecision]], $MachinePrecision]}, Mod[Abs[TMP1], Abs[TMP2]] * Sign[TMP1]], $MachinePrecision]), $MachinePrecision], 2.0], N[(N[With[{TMP1 = N[Exp[x], $MachinePrecision], TMP2 = N[Sqrt[N[(N[(N[(-0.001388888888888889 * N[(x * x), $MachinePrecision] + 0.041666666666666664), $MachinePrecision] * N[(x * x), $MachinePrecision] + -0.5), $MachinePrecision] * N[(x * x), $MachinePrecision] + 1.0), $MachinePrecision]], $MachinePrecision]}, Mod[Abs[TMP1], Abs[TMP2]] * Sign[TMP1]], $MachinePrecision] * t$95$0), $MachinePrecision], N[(1.0 * N[With[{TMP1 = 1.0, TMP2 = 1.0}, Mod[Abs[TMP1], Abs[TMP2]] * Sign[TMP1]], $MachinePrecision]), $MachinePrecision]]]
              
              \begin{array}{l}
              
              \\
              \begin{array}{l}
              t_0 := e^{-x}\\
              \mathbf{if}\;t\_0 \cdot \left(\left(e^{x}\right) \bmod \left(\sqrt{\cos x}\right)\right) \leq 2:\\
              \;\;\;\;\left(\left(e^{x}\right) \bmod \left(\sqrt{\mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(-0.001388888888888889, x \cdot x, 0.041666666666666664\right), x \cdot x, -0.5\right), x \cdot x, 1\right)}\right)\right) \cdot t\_0\\
              
              \mathbf{else}:\\
              \;\;\;\;1 \cdot \left(1 \bmod 1\right)\\
              
              
              \end{array}
              \end{array}
              
              Derivation
              1. Split input into 2 regimes
              2. if (*.f64 (fmod.f64 (exp.f64 x) (sqrt.f64 (cos.f64 x))) (exp.f64 (neg.f64 x))) < 2

                1. Initial program 9.0%

                  \[\left(\left(e^{x}\right) \bmod \left(\sqrt{\cos x}\right)\right) \cdot e^{-x} \]
                2. Add Preprocessing
                3. Taylor expanded in x around 0

                  \[\leadsto \left(\left(e^{x}\right) \bmod \left(\sqrt{\color{blue}{1 + {x}^{2} \cdot \left({x}^{2} \cdot \left(\frac{1}{24} + \frac{-1}{720} \cdot {x}^{2}\right) - \frac{1}{2}\right)}}\right)\right) \cdot e^{-x} \]
                4. Step-by-step derivation
                  1. +-commutativeN/A

                    \[\leadsto \left(\left(e^{x}\right) \bmod \left(\sqrt{\color{blue}{{x}^{2} \cdot \left({x}^{2} \cdot \left(\frac{1}{24} + \frac{-1}{720} \cdot {x}^{2}\right) - \frac{1}{2}\right) + 1}}\right)\right) \cdot e^{-x} \]
                  2. *-commutativeN/A

                    \[\leadsto \left(\left(e^{x}\right) \bmod \left(\sqrt{\color{blue}{\left({x}^{2} \cdot \left(\frac{1}{24} + \frac{-1}{720} \cdot {x}^{2}\right) - \frac{1}{2}\right) \cdot {x}^{2}} + 1}\right)\right) \cdot e^{-x} \]
                  3. lower-fma.f64N/A

                    \[\leadsto \left(\left(e^{x}\right) \bmod \left(\sqrt{\color{blue}{\mathsf{fma}\left({x}^{2} \cdot \left(\frac{1}{24} + \frac{-1}{720} \cdot {x}^{2}\right) - \frac{1}{2}, {x}^{2}, 1\right)}}\right)\right) \cdot e^{-x} \]
                  4. sub-negN/A

                    \[\leadsto \left(\left(e^{x}\right) \bmod \left(\sqrt{\mathsf{fma}\left(\color{blue}{{x}^{2} \cdot \left(\frac{1}{24} + \frac{-1}{720} \cdot {x}^{2}\right) + \left(\mathsf{neg}\left(\frac{1}{2}\right)\right)}, {x}^{2}, 1\right)}\right)\right) \cdot e^{-x} \]
                  5. *-commutativeN/A

                    \[\leadsto \left(\left(e^{x}\right) \bmod \left(\sqrt{\mathsf{fma}\left(\color{blue}{\left(\frac{1}{24} + \frac{-1}{720} \cdot {x}^{2}\right) \cdot {x}^{2}} + \left(\mathsf{neg}\left(\frac{1}{2}\right)\right), {x}^{2}, 1\right)}\right)\right) \cdot e^{-x} \]
                  6. metadata-evalN/A

                    \[\leadsto \left(\left(e^{x}\right) \bmod \left(\sqrt{\mathsf{fma}\left(\left(\frac{1}{24} + \frac{-1}{720} \cdot {x}^{2}\right) \cdot {x}^{2} + \color{blue}{\frac{-1}{2}}, {x}^{2}, 1\right)}\right)\right) \cdot e^{-x} \]
                  7. lower-fma.f64N/A

                    \[\leadsto \left(\left(e^{x}\right) \bmod \left(\sqrt{\mathsf{fma}\left(\color{blue}{\mathsf{fma}\left(\frac{1}{24} + \frac{-1}{720} \cdot {x}^{2}, {x}^{2}, \frac{-1}{2}\right)}, {x}^{2}, 1\right)}\right)\right) \cdot e^{-x} \]
                  8. +-commutativeN/A

                    \[\leadsto \left(\left(e^{x}\right) \bmod \left(\sqrt{\mathsf{fma}\left(\mathsf{fma}\left(\color{blue}{\frac{-1}{720} \cdot {x}^{2} + \frac{1}{24}}, {x}^{2}, \frac{-1}{2}\right), {x}^{2}, 1\right)}\right)\right) \cdot e^{-x} \]
                  9. lower-fma.f64N/A

                    \[\leadsto \left(\left(e^{x}\right) \bmod \left(\sqrt{\mathsf{fma}\left(\mathsf{fma}\left(\color{blue}{\mathsf{fma}\left(\frac{-1}{720}, {x}^{2}, \frac{1}{24}\right)}, {x}^{2}, \frac{-1}{2}\right), {x}^{2}, 1\right)}\right)\right) \cdot e^{-x} \]
                  10. unpow2N/A

                    \[\leadsto \left(\left(e^{x}\right) \bmod \left(\sqrt{\mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(\frac{-1}{720}, \color{blue}{x \cdot x}, \frac{1}{24}\right), {x}^{2}, \frac{-1}{2}\right), {x}^{2}, 1\right)}\right)\right) \cdot e^{-x} \]
                  11. lower-*.f64N/A

                    \[\leadsto \left(\left(e^{x}\right) \bmod \left(\sqrt{\mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(\frac{-1}{720}, \color{blue}{x \cdot x}, \frac{1}{24}\right), {x}^{2}, \frac{-1}{2}\right), {x}^{2}, 1\right)}\right)\right) \cdot e^{-x} \]
                  12. unpow2N/A

                    \[\leadsto \left(\left(e^{x}\right) \bmod \left(\sqrt{\mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(\frac{-1}{720}, x \cdot x, \frac{1}{24}\right), \color{blue}{x \cdot x}, \frac{-1}{2}\right), {x}^{2}, 1\right)}\right)\right) \cdot e^{-x} \]
                  13. lower-*.f64N/A

                    \[\leadsto \left(\left(e^{x}\right) \bmod \left(\sqrt{\mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(\frac{-1}{720}, x \cdot x, \frac{1}{24}\right), \color{blue}{x \cdot x}, \frac{-1}{2}\right), {x}^{2}, 1\right)}\right)\right) \cdot e^{-x} \]
                  14. unpow2N/A

                    \[\leadsto \left(\left(e^{x}\right) \bmod \left(\sqrt{\mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(\frac{-1}{720}, x \cdot x, \frac{1}{24}\right), x \cdot x, \frac{-1}{2}\right), \color{blue}{x \cdot x}, 1\right)}\right)\right) \cdot e^{-x} \]
                  15. lower-*.f649.0

                    \[\leadsto \left(\left(e^{x}\right) \bmod \left(\sqrt{\mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(-0.001388888888888889, x \cdot x, 0.041666666666666664\right), x \cdot x, -0.5\right), \color{blue}{x \cdot x}, 1\right)}\right)\right) \cdot e^{-x} \]
                5. Applied rewrites9.0%

                  \[\leadsto \left(\left(e^{x}\right) \bmod \left(\sqrt{\color{blue}{\mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(-0.001388888888888889, x \cdot x, 0.041666666666666664\right), x \cdot x, -0.5\right), x \cdot x, 1\right)}}\right)\right) \cdot e^{-x} \]

                if 2 < (*.f64 (fmod.f64 (exp.f64 x) (sqrt.f64 (cos.f64 x))) (exp.f64 (neg.f64 x)))

                1. Initial program 0.0%

                  \[\left(\left(e^{x}\right) \bmod \left(\sqrt{\cos x}\right)\right) \cdot e^{-x} \]
                2. Add Preprocessing
                3. Taylor expanded in x around 0

                  \[\leadsto \left(\color{blue}{1} \bmod \left(\sqrt{\cos x}\right)\right) \cdot e^{-x} \]
                4. Step-by-step derivation
                  1. Applied rewrites98.2%

                    \[\leadsto \left(\color{blue}{1} \bmod \left(\sqrt{\cos x}\right)\right) \cdot e^{-x} \]
                  2. Taylor expanded in x around 0

                    \[\leadsto \left(1 \bmod \color{blue}{1}\right) \cdot e^{-x} \]
                  3. Step-by-step derivation
                    1. Applied rewrites98.1%

                      \[\leadsto \left(1 \bmod \color{blue}{1}\right) \cdot e^{-x} \]
                    2. Taylor expanded in x around 0

                      \[\leadsto \left(1 \bmod 1\right) \cdot \color{blue}{1} \]
                    3. Step-by-step derivation
                      1. Applied rewrites98.2%

                        \[\leadsto \left(1 \bmod 1\right) \cdot \color{blue}{1} \]
                    4. Recombined 2 regimes into one program.
                    5. Final simplification27.5%

                      \[\leadsto \begin{array}{l} \mathbf{if}\;e^{-x} \cdot \left(\left(e^{x}\right) \bmod \left(\sqrt{\cos x}\right)\right) \leq 2:\\ \;\;\;\;\left(\left(e^{x}\right) \bmod \left(\sqrt{\mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(-0.001388888888888889, x \cdot x, 0.041666666666666664\right), x \cdot x, -0.5\right), x \cdot x, 1\right)}\right)\right) \cdot e^{-x}\\ \mathbf{else}:\\ \;\;\;\;1 \cdot \left(1 \bmod 1\right)\\ \end{array} \]
                    6. Add Preprocessing

                    Alternative 4: 26.4% accurate, 0.5× speedup?

                    \[\begin{array}{l} \\ \begin{array}{l} t_0 := e^{-x}\\ \mathbf{if}\;t\_0 \cdot \left(\left(e^{x}\right) \bmod \left(\sqrt{\cos x}\right)\right) \leq 2:\\ \;\;\;\;\left(\left(e^{x}\right) \bmod \left(\mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(-0.003298611111111111, x \cdot x, -0.010416666666666666\right), x \cdot x, -0.25\right), x \cdot x, 1\right)\right)\right) \cdot t\_0\\ \mathbf{else}:\\ \;\;\;\;1 \cdot \left(1 \bmod 1\right)\\ \end{array} \end{array} \]
                    (FPCore (x)
                     :precision binary64
                     (let* ((t_0 (exp (- x))))
                       (if (<= (* t_0 (fmod (exp x) (sqrt (cos x)))) 2.0)
                         (*
                          (fmod
                           (exp x)
                           (fma
                            (fma
                             (fma -0.003298611111111111 (* x x) -0.010416666666666666)
                             (* x x)
                             -0.25)
                            (* x x)
                            1.0))
                          t_0)
                         (* 1.0 (fmod 1.0 1.0)))))
                    double code(double x) {
                    	double t_0 = exp(-x);
                    	double tmp;
                    	if ((t_0 * fmod(exp(x), sqrt(cos(x)))) <= 2.0) {
                    		tmp = fmod(exp(x), fma(fma(fma(-0.003298611111111111, (x * x), -0.010416666666666666), (x * x), -0.25), (x * x), 1.0)) * t_0;
                    	} else {
                    		tmp = 1.0 * fmod(1.0, 1.0);
                    	}
                    	return tmp;
                    }
                    
                    function code(x)
                    	t_0 = exp(Float64(-x))
                    	tmp = 0.0
                    	if (Float64(t_0 * rem(exp(x), sqrt(cos(x)))) <= 2.0)
                    		tmp = Float64(rem(exp(x), fma(fma(fma(-0.003298611111111111, Float64(x * x), -0.010416666666666666), Float64(x * x), -0.25), Float64(x * x), 1.0)) * t_0);
                    	else
                    		tmp = Float64(1.0 * rem(1.0, 1.0));
                    	end
                    	return tmp
                    end
                    
                    code[x_] := Block[{t$95$0 = N[Exp[(-x)], $MachinePrecision]}, If[LessEqual[N[(t$95$0 * N[With[{TMP1 = N[Exp[x], $MachinePrecision], TMP2 = N[Sqrt[N[Cos[x], $MachinePrecision]], $MachinePrecision]}, Mod[Abs[TMP1], Abs[TMP2]] * Sign[TMP1]], $MachinePrecision]), $MachinePrecision], 2.0], N[(N[With[{TMP1 = N[Exp[x], $MachinePrecision], TMP2 = N[(N[(N[(-0.003298611111111111 * N[(x * x), $MachinePrecision] + -0.010416666666666666), $MachinePrecision] * N[(x * x), $MachinePrecision] + -0.25), $MachinePrecision] * N[(x * x), $MachinePrecision] + 1.0), $MachinePrecision]}, Mod[Abs[TMP1], Abs[TMP2]] * Sign[TMP1]], $MachinePrecision] * t$95$0), $MachinePrecision], N[(1.0 * N[With[{TMP1 = 1.0, TMP2 = 1.0}, Mod[Abs[TMP1], Abs[TMP2]] * Sign[TMP1]], $MachinePrecision]), $MachinePrecision]]]
                    
                    \begin{array}{l}
                    
                    \\
                    \begin{array}{l}
                    t_0 := e^{-x}\\
                    \mathbf{if}\;t\_0 \cdot \left(\left(e^{x}\right) \bmod \left(\sqrt{\cos x}\right)\right) \leq 2:\\
                    \;\;\;\;\left(\left(e^{x}\right) \bmod \left(\mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(-0.003298611111111111, x \cdot x, -0.010416666666666666\right), x \cdot x, -0.25\right), x \cdot x, 1\right)\right)\right) \cdot t\_0\\
                    
                    \mathbf{else}:\\
                    \;\;\;\;1 \cdot \left(1 \bmod 1\right)\\
                    
                    
                    \end{array}
                    \end{array}
                    
                    Derivation
                    1. Split input into 2 regimes
                    2. if (*.f64 (fmod.f64 (exp.f64 x) (sqrt.f64 (cos.f64 x))) (exp.f64 (neg.f64 x))) < 2

                      1. Initial program 9.0%

                        \[\left(\left(e^{x}\right) \bmod \left(\sqrt{\cos x}\right)\right) \cdot e^{-x} \]
                      2. Add Preprocessing
                      3. Taylor expanded in x around 0

                        \[\leadsto \left(\left(e^{x}\right) \bmod \color{blue}{\left(1 + {x}^{2} \cdot \left({x}^{2} \cdot \left(\frac{-19}{5760} \cdot {x}^{2} - \frac{1}{96}\right) - \frac{1}{4}\right)\right)}\right) \cdot e^{-x} \]
                      4. Step-by-step derivation
                        1. +-commutativeN/A

                          \[\leadsto \left(\left(e^{x}\right) \bmod \color{blue}{\left({x}^{2} \cdot \left({x}^{2} \cdot \left(\frac{-19}{5760} \cdot {x}^{2} - \frac{1}{96}\right) - \frac{1}{4}\right) + 1\right)}\right) \cdot e^{-x} \]
                        2. *-commutativeN/A

                          \[\leadsto \left(\left(e^{x}\right) \bmod \left(\color{blue}{\left({x}^{2} \cdot \left(\frac{-19}{5760} \cdot {x}^{2} - \frac{1}{96}\right) - \frac{1}{4}\right) \cdot {x}^{2}} + 1\right)\right) \cdot e^{-x} \]
                        3. lower-fma.f64N/A

                          \[\leadsto \left(\left(e^{x}\right) \bmod \color{blue}{\left(\mathsf{fma}\left({x}^{2} \cdot \left(\frac{-19}{5760} \cdot {x}^{2} - \frac{1}{96}\right) - \frac{1}{4}, {x}^{2}, 1\right)\right)}\right) \cdot e^{-x} \]
                        4. sub-negN/A

                          \[\leadsto \left(\left(e^{x}\right) \bmod \left(\mathsf{fma}\left(\color{blue}{{x}^{2} \cdot \left(\frac{-19}{5760} \cdot {x}^{2} - \frac{1}{96}\right) + \left(\mathsf{neg}\left(\frac{1}{4}\right)\right)}, {x}^{2}, 1\right)\right)\right) \cdot e^{-x} \]
                        5. *-commutativeN/A

                          \[\leadsto \left(\left(e^{x}\right) \bmod \left(\mathsf{fma}\left(\color{blue}{\left(\frac{-19}{5760} \cdot {x}^{2} - \frac{1}{96}\right) \cdot {x}^{2}} + \left(\mathsf{neg}\left(\frac{1}{4}\right)\right), {x}^{2}, 1\right)\right)\right) \cdot e^{-x} \]
                        6. metadata-evalN/A

                          \[\leadsto \left(\left(e^{x}\right) \bmod \left(\mathsf{fma}\left(\left(\frac{-19}{5760} \cdot {x}^{2} - \frac{1}{96}\right) \cdot {x}^{2} + \color{blue}{\frac{-1}{4}}, {x}^{2}, 1\right)\right)\right) \cdot e^{-x} \]
                        7. lower-fma.f64N/A

                          \[\leadsto \left(\left(e^{x}\right) \bmod \left(\mathsf{fma}\left(\color{blue}{\mathsf{fma}\left(\frac{-19}{5760} \cdot {x}^{2} - \frac{1}{96}, {x}^{2}, \frac{-1}{4}\right)}, {x}^{2}, 1\right)\right)\right) \cdot e^{-x} \]
                        8. sub-negN/A

                          \[\leadsto \left(\left(e^{x}\right) \bmod \left(\mathsf{fma}\left(\mathsf{fma}\left(\color{blue}{\frac{-19}{5760} \cdot {x}^{2} + \left(\mathsf{neg}\left(\frac{1}{96}\right)\right)}, {x}^{2}, \frac{-1}{4}\right), {x}^{2}, 1\right)\right)\right) \cdot e^{-x} \]
                        9. metadata-evalN/A

                          \[\leadsto \left(\left(e^{x}\right) \bmod \left(\mathsf{fma}\left(\mathsf{fma}\left(\frac{-19}{5760} \cdot {x}^{2} + \color{blue}{\frac{-1}{96}}, {x}^{2}, \frac{-1}{4}\right), {x}^{2}, 1\right)\right)\right) \cdot e^{-x} \]
                        10. lower-fma.f64N/A

                          \[\leadsto \left(\left(e^{x}\right) \bmod \left(\mathsf{fma}\left(\mathsf{fma}\left(\color{blue}{\mathsf{fma}\left(\frac{-19}{5760}, {x}^{2}, \frac{-1}{96}\right)}, {x}^{2}, \frac{-1}{4}\right), {x}^{2}, 1\right)\right)\right) \cdot e^{-x} \]
                        11. unpow2N/A

                          \[\leadsto \left(\left(e^{x}\right) \bmod \left(\mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(\frac{-19}{5760}, \color{blue}{x \cdot x}, \frac{-1}{96}\right), {x}^{2}, \frac{-1}{4}\right), {x}^{2}, 1\right)\right)\right) \cdot e^{-x} \]
                        12. lower-*.f64N/A

                          \[\leadsto \left(\left(e^{x}\right) \bmod \left(\mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(\frac{-19}{5760}, \color{blue}{x \cdot x}, \frac{-1}{96}\right), {x}^{2}, \frac{-1}{4}\right), {x}^{2}, 1\right)\right)\right) \cdot e^{-x} \]
                        13. unpow2N/A

                          \[\leadsto \left(\left(e^{x}\right) \bmod \left(\mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(\frac{-19}{5760}, x \cdot x, \frac{-1}{96}\right), \color{blue}{x \cdot x}, \frac{-1}{4}\right), {x}^{2}, 1\right)\right)\right) \cdot e^{-x} \]
                        14. lower-*.f64N/A

                          \[\leadsto \left(\left(e^{x}\right) \bmod \left(\mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(\frac{-19}{5760}, x \cdot x, \frac{-1}{96}\right), \color{blue}{x \cdot x}, \frac{-1}{4}\right), {x}^{2}, 1\right)\right)\right) \cdot e^{-x} \]
                        15. unpow2N/A

                          \[\leadsto \left(\left(e^{x}\right) \bmod \left(\mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(\frac{-19}{5760}, x \cdot x, \frac{-1}{96}\right), x \cdot x, \frac{-1}{4}\right), \color{blue}{x \cdot x}, 1\right)\right)\right) \cdot e^{-x} \]
                        16. lower-*.f649.0

                          \[\leadsto \left(\left(e^{x}\right) \bmod \left(\mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(-0.003298611111111111, x \cdot x, -0.010416666666666666\right), x \cdot x, -0.25\right), \color{blue}{x \cdot x}, 1\right)\right)\right) \cdot e^{-x} \]
                      5. Applied rewrites9.0%

                        \[\leadsto \left(\left(e^{x}\right) \bmod \color{blue}{\left(\mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(-0.003298611111111111, x \cdot x, -0.010416666666666666\right), x \cdot x, -0.25\right), x \cdot x, 1\right)\right)}\right) \cdot e^{-x} \]

                      if 2 < (*.f64 (fmod.f64 (exp.f64 x) (sqrt.f64 (cos.f64 x))) (exp.f64 (neg.f64 x)))

                      1. Initial program 0.0%

                        \[\left(\left(e^{x}\right) \bmod \left(\sqrt{\cos x}\right)\right) \cdot e^{-x} \]
                      2. Add Preprocessing
                      3. Taylor expanded in x around 0

                        \[\leadsto \left(\color{blue}{1} \bmod \left(\sqrt{\cos x}\right)\right) \cdot e^{-x} \]
                      4. Step-by-step derivation
                        1. Applied rewrites98.2%

                          \[\leadsto \left(\color{blue}{1} \bmod \left(\sqrt{\cos x}\right)\right) \cdot e^{-x} \]
                        2. Taylor expanded in x around 0

                          \[\leadsto \left(1 \bmod \color{blue}{1}\right) \cdot e^{-x} \]
                        3. Step-by-step derivation
                          1. Applied rewrites98.1%

                            \[\leadsto \left(1 \bmod \color{blue}{1}\right) \cdot e^{-x} \]
                          2. Taylor expanded in x around 0

                            \[\leadsto \left(1 \bmod 1\right) \cdot \color{blue}{1} \]
                          3. Step-by-step derivation
                            1. Applied rewrites98.2%

                              \[\leadsto \left(1 \bmod 1\right) \cdot \color{blue}{1} \]
                          4. Recombined 2 regimes into one program.
                          5. Final simplification27.4%

                            \[\leadsto \begin{array}{l} \mathbf{if}\;e^{-x} \cdot \left(\left(e^{x}\right) \bmod \left(\sqrt{\cos x}\right)\right) \leq 2:\\ \;\;\;\;\left(\left(e^{x}\right) \bmod \left(\mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(-0.003298611111111111, x \cdot x, -0.010416666666666666\right), x \cdot x, -0.25\right), x \cdot x, 1\right)\right)\right) \cdot e^{-x}\\ \mathbf{else}:\\ \;\;\;\;1 \cdot \left(1 \bmod 1\right)\\ \end{array} \]
                          6. Add Preprocessing

                          Alternative 5: 26.4% accurate, 0.5× speedup?

                          \[\begin{array}{l} \\ \begin{array}{l} t_0 := e^{-x}\\ \mathbf{if}\;t\_0 \cdot \left(\left(e^{x}\right) \bmod \left(\sqrt{\cos x}\right)\right) \leq 2:\\ \;\;\;\;\left(\left(e^{x}\right) \bmod \left(\sqrt{\mathsf{fma}\left(\mathsf{fma}\left(0.041666666666666664, x \cdot x, -0.5\right), x \cdot x, 1\right)}\right)\right) \cdot t\_0\\ \mathbf{else}:\\ \;\;\;\;1 \cdot \left(1 \bmod 1\right)\\ \end{array} \end{array} \]
                          (FPCore (x)
                           :precision binary64
                           (let* ((t_0 (exp (- x))))
                             (if (<= (* t_0 (fmod (exp x) (sqrt (cos x)))) 2.0)
                               (*
                                (fmod
                                 (exp x)
                                 (sqrt (fma (fma 0.041666666666666664 (* x x) -0.5) (* x x) 1.0)))
                                t_0)
                               (* 1.0 (fmod 1.0 1.0)))))
                          double code(double x) {
                          	double t_0 = exp(-x);
                          	double tmp;
                          	if ((t_0 * fmod(exp(x), sqrt(cos(x)))) <= 2.0) {
                          		tmp = fmod(exp(x), sqrt(fma(fma(0.041666666666666664, (x * x), -0.5), (x * x), 1.0))) * t_0;
                          	} else {
                          		tmp = 1.0 * fmod(1.0, 1.0);
                          	}
                          	return tmp;
                          }
                          
                          function code(x)
                          	t_0 = exp(Float64(-x))
                          	tmp = 0.0
                          	if (Float64(t_0 * rem(exp(x), sqrt(cos(x)))) <= 2.0)
                          		tmp = Float64(rem(exp(x), sqrt(fma(fma(0.041666666666666664, Float64(x * x), -0.5), Float64(x * x), 1.0))) * t_0);
                          	else
                          		tmp = Float64(1.0 * rem(1.0, 1.0));
                          	end
                          	return tmp
                          end
                          
                          code[x_] := Block[{t$95$0 = N[Exp[(-x)], $MachinePrecision]}, If[LessEqual[N[(t$95$0 * N[With[{TMP1 = N[Exp[x], $MachinePrecision], TMP2 = N[Sqrt[N[Cos[x], $MachinePrecision]], $MachinePrecision]}, Mod[Abs[TMP1], Abs[TMP2]] * Sign[TMP1]], $MachinePrecision]), $MachinePrecision], 2.0], N[(N[With[{TMP1 = N[Exp[x], $MachinePrecision], TMP2 = N[Sqrt[N[(N[(0.041666666666666664 * N[(x * x), $MachinePrecision] + -0.5), $MachinePrecision] * N[(x * x), $MachinePrecision] + 1.0), $MachinePrecision]], $MachinePrecision]}, Mod[Abs[TMP1], Abs[TMP2]] * Sign[TMP1]], $MachinePrecision] * t$95$0), $MachinePrecision], N[(1.0 * N[With[{TMP1 = 1.0, TMP2 = 1.0}, Mod[Abs[TMP1], Abs[TMP2]] * Sign[TMP1]], $MachinePrecision]), $MachinePrecision]]]
                          
                          \begin{array}{l}
                          
                          \\
                          \begin{array}{l}
                          t_0 := e^{-x}\\
                          \mathbf{if}\;t\_0 \cdot \left(\left(e^{x}\right) \bmod \left(\sqrt{\cos x}\right)\right) \leq 2:\\
                          \;\;\;\;\left(\left(e^{x}\right) \bmod \left(\sqrt{\mathsf{fma}\left(\mathsf{fma}\left(0.041666666666666664, x \cdot x, -0.5\right), x \cdot x, 1\right)}\right)\right) \cdot t\_0\\
                          
                          \mathbf{else}:\\
                          \;\;\;\;1 \cdot \left(1 \bmod 1\right)\\
                          
                          
                          \end{array}
                          \end{array}
                          
                          Derivation
                          1. Split input into 2 regimes
                          2. if (*.f64 (fmod.f64 (exp.f64 x) (sqrt.f64 (cos.f64 x))) (exp.f64 (neg.f64 x))) < 2

                            1. Initial program 9.0%

                              \[\left(\left(e^{x}\right) \bmod \left(\sqrt{\cos x}\right)\right) \cdot e^{-x} \]
                            2. Add Preprocessing
                            3. Taylor expanded in x around 0

                              \[\leadsto \left(\left(e^{x}\right) \bmod \left(\sqrt{\color{blue}{1 + {x}^{2} \cdot \left(\frac{1}{24} \cdot {x}^{2} - \frac{1}{2}\right)}}\right)\right) \cdot e^{-x} \]
                            4. Step-by-step derivation
                              1. +-commutativeN/A

                                \[\leadsto \left(\left(e^{x}\right) \bmod \left(\sqrt{\color{blue}{{x}^{2} \cdot \left(\frac{1}{24} \cdot {x}^{2} - \frac{1}{2}\right) + 1}}\right)\right) \cdot e^{-x} \]
                              2. *-commutativeN/A

                                \[\leadsto \left(\left(e^{x}\right) \bmod \left(\sqrt{\color{blue}{\left(\frac{1}{24} \cdot {x}^{2} - \frac{1}{2}\right) \cdot {x}^{2}} + 1}\right)\right) \cdot e^{-x} \]
                              3. lower-fma.f64N/A

                                \[\leadsto \left(\left(e^{x}\right) \bmod \left(\sqrt{\color{blue}{\mathsf{fma}\left(\frac{1}{24} \cdot {x}^{2} - \frac{1}{2}, {x}^{2}, 1\right)}}\right)\right) \cdot e^{-x} \]
                              4. sub-negN/A

                                \[\leadsto \left(\left(e^{x}\right) \bmod \left(\sqrt{\mathsf{fma}\left(\color{blue}{\frac{1}{24} \cdot {x}^{2} + \left(\mathsf{neg}\left(\frac{1}{2}\right)\right)}, {x}^{2}, 1\right)}\right)\right) \cdot e^{-x} \]
                              5. metadata-evalN/A

                                \[\leadsto \left(\left(e^{x}\right) \bmod \left(\sqrt{\mathsf{fma}\left(\frac{1}{24} \cdot {x}^{2} + \color{blue}{\frac{-1}{2}}, {x}^{2}, 1\right)}\right)\right) \cdot e^{-x} \]
                              6. lower-fma.f64N/A

                                \[\leadsto \left(\left(e^{x}\right) \bmod \left(\sqrt{\mathsf{fma}\left(\color{blue}{\mathsf{fma}\left(\frac{1}{24}, {x}^{2}, \frac{-1}{2}\right)}, {x}^{2}, 1\right)}\right)\right) \cdot e^{-x} \]
                              7. unpow2N/A

                                \[\leadsto \left(\left(e^{x}\right) \bmod \left(\sqrt{\mathsf{fma}\left(\mathsf{fma}\left(\frac{1}{24}, \color{blue}{x \cdot x}, \frac{-1}{2}\right), {x}^{2}, 1\right)}\right)\right) \cdot e^{-x} \]
                              8. lower-*.f64N/A

                                \[\leadsto \left(\left(e^{x}\right) \bmod \left(\sqrt{\mathsf{fma}\left(\mathsf{fma}\left(\frac{1}{24}, \color{blue}{x \cdot x}, \frac{-1}{2}\right), {x}^{2}, 1\right)}\right)\right) \cdot e^{-x} \]
                              9. unpow2N/A

                                \[\leadsto \left(\left(e^{x}\right) \bmod \left(\sqrt{\mathsf{fma}\left(\mathsf{fma}\left(\frac{1}{24}, x \cdot x, \frac{-1}{2}\right), \color{blue}{x \cdot x}, 1\right)}\right)\right) \cdot e^{-x} \]
                              10. lower-*.f648.9

                                \[\leadsto \left(\left(e^{x}\right) \bmod \left(\sqrt{\mathsf{fma}\left(\mathsf{fma}\left(0.041666666666666664, x \cdot x, -0.5\right), \color{blue}{x \cdot x}, 1\right)}\right)\right) \cdot e^{-x} \]
                            5. Applied rewrites8.9%

                              \[\leadsto \left(\left(e^{x}\right) \bmod \left(\sqrt{\color{blue}{\mathsf{fma}\left(\mathsf{fma}\left(0.041666666666666664, x \cdot x, -0.5\right), x \cdot x, 1\right)}}\right)\right) \cdot e^{-x} \]

                            if 2 < (*.f64 (fmod.f64 (exp.f64 x) (sqrt.f64 (cos.f64 x))) (exp.f64 (neg.f64 x)))

                            1. Initial program 0.0%

                              \[\left(\left(e^{x}\right) \bmod \left(\sqrt{\cos x}\right)\right) \cdot e^{-x} \]
                            2. Add Preprocessing
                            3. Taylor expanded in x around 0

                              \[\leadsto \left(\color{blue}{1} \bmod \left(\sqrt{\cos x}\right)\right) \cdot e^{-x} \]
                            4. Step-by-step derivation
                              1. Applied rewrites98.2%

                                \[\leadsto \left(\color{blue}{1} \bmod \left(\sqrt{\cos x}\right)\right) \cdot e^{-x} \]
                              2. Taylor expanded in x around 0

                                \[\leadsto \left(1 \bmod \color{blue}{1}\right) \cdot e^{-x} \]
                              3. Step-by-step derivation
                                1. Applied rewrites98.1%

                                  \[\leadsto \left(1 \bmod \color{blue}{1}\right) \cdot e^{-x} \]
                                2. Taylor expanded in x around 0

                                  \[\leadsto \left(1 \bmod 1\right) \cdot \color{blue}{1} \]
                                3. Step-by-step derivation
                                  1. Applied rewrites98.2%

                                    \[\leadsto \left(1 \bmod 1\right) \cdot \color{blue}{1} \]
                                4. Recombined 2 regimes into one program.
                                5. Final simplification27.4%

                                  \[\leadsto \begin{array}{l} \mathbf{if}\;e^{-x} \cdot \left(\left(e^{x}\right) \bmod \left(\sqrt{\cos x}\right)\right) \leq 2:\\ \;\;\;\;\left(\left(e^{x}\right) \bmod \left(\sqrt{\mathsf{fma}\left(\mathsf{fma}\left(0.041666666666666664, x \cdot x, -0.5\right), x \cdot x, 1\right)}\right)\right) \cdot e^{-x}\\ \mathbf{else}:\\ \;\;\;\;1 \cdot \left(1 \bmod 1\right)\\ \end{array} \]
                                6. Add Preprocessing

                                Alternative 6: 26.4% accurate, 0.6× speedup?

                                \[\begin{array}{l} \\ \begin{array}{l} t_0 := e^{-x}\\ \mathbf{if}\;t\_0 \cdot \left(\left(e^{x}\right) \bmod \left(\sqrt{\cos x}\right)\right) \leq 2:\\ \;\;\;\;\left(\left(e^{x}\right) \bmod \left(\mathsf{fma}\left(\mathsf{fma}\left(-0.010416666666666666, x \cdot x, -0.25\right), x \cdot x, 1\right)\right)\right) \cdot t\_0\\ \mathbf{else}:\\ \;\;\;\;1 \cdot \left(1 \bmod 1\right)\\ \end{array} \end{array} \]
                                (FPCore (x)
                                 :precision binary64
                                 (let* ((t_0 (exp (- x))))
                                   (if (<= (* t_0 (fmod (exp x) (sqrt (cos x)))) 2.0)
                                     (*
                                      (fmod
                                       (exp x)
                                       (fma (fma -0.010416666666666666 (* x x) -0.25) (* x x) 1.0))
                                      t_0)
                                     (* 1.0 (fmod 1.0 1.0)))))
                                double code(double x) {
                                	double t_0 = exp(-x);
                                	double tmp;
                                	if ((t_0 * fmod(exp(x), sqrt(cos(x)))) <= 2.0) {
                                		tmp = fmod(exp(x), fma(fma(-0.010416666666666666, (x * x), -0.25), (x * x), 1.0)) * t_0;
                                	} else {
                                		tmp = 1.0 * fmod(1.0, 1.0);
                                	}
                                	return tmp;
                                }
                                
                                function code(x)
                                	t_0 = exp(Float64(-x))
                                	tmp = 0.0
                                	if (Float64(t_0 * rem(exp(x), sqrt(cos(x)))) <= 2.0)
                                		tmp = Float64(rem(exp(x), fma(fma(-0.010416666666666666, Float64(x * x), -0.25), Float64(x * x), 1.0)) * t_0);
                                	else
                                		tmp = Float64(1.0 * rem(1.0, 1.0));
                                	end
                                	return tmp
                                end
                                
                                code[x_] := Block[{t$95$0 = N[Exp[(-x)], $MachinePrecision]}, If[LessEqual[N[(t$95$0 * N[With[{TMP1 = N[Exp[x], $MachinePrecision], TMP2 = N[Sqrt[N[Cos[x], $MachinePrecision]], $MachinePrecision]}, Mod[Abs[TMP1], Abs[TMP2]] * Sign[TMP1]], $MachinePrecision]), $MachinePrecision], 2.0], N[(N[With[{TMP1 = N[Exp[x], $MachinePrecision], TMP2 = N[(N[(-0.010416666666666666 * N[(x * x), $MachinePrecision] + -0.25), $MachinePrecision] * N[(x * x), $MachinePrecision] + 1.0), $MachinePrecision]}, Mod[Abs[TMP1], Abs[TMP2]] * Sign[TMP1]], $MachinePrecision] * t$95$0), $MachinePrecision], N[(1.0 * N[With[{TMP1 = 1.0, TMP2 = 1.0}, Mod[Abs[TMP1], Abs[TMP2]] * Sign[TMP1]], $MachinePrecision]), $MachinePrecision]]]
                                
                                \begin{array}{l}
                                
                                \\
                                \begin{array}{l}
                                t_0 := e^{-x}\\
                                \mathbf{if}\;t\_0 \cdot \left(\left(e^{x}\right) \bmod \left(\sqrt{\cos x}\right)\right) \leq 2:\\
                                \;\;\;\;\left(\left(e^{x}\right) \bmod \left(\mathsf{fma}\left(\mathsf{fma}\left(-0.010416666666666666, x \cdot x, -0.25\right), x \cdot x, 1\right)\right)\right) \cdot t\_0\\
                                
                                \mathbf{else}:\\
                                \;\;\;\;1 \cdot \left(1 \bmod 1\right)\\
                                
                                
                                \end{array}
                                \end{array}
                                
                                Derivation
                                1. Split input into 2 regimes
                                2. if (*.f64 (fmod.f64 (exp.f64 x) (sqrt.f64 (cos.f64 x))) (exp.f64 (neg.f64 x))) < 2

                                  1. Initial program 9.0%

                                    \[\left(\left(e^{x}\right) \bmod \left(\sqrt{\cos x}\right)\right) \cdot e^{-x} \]
                                  2. Add Preprocessing
                                  3. Taylor expanded in x around 0

                                    \[\leadsto \left(\left(e^{x}\right) \bmod \color{blue}{\left(1 + {x}^{2} \cdot \left(\frac{-1}{96} \cdot {x}^{2} - \frac{1}{4}\right)\right)}\right) \cdot e^{-x} \]
                                  4. Step-by-step derivation
                                    1. +-commutativeN/A

                                      \[\leadsto \left(\left(e^{x}\right) \bmod \color{blue}{\left({x}^{2} \cdot \left(\frac{-1}{96} \cdot {x}^{2} - \frac{1}{4}\right) + 1\right)}\right) \cdot e^{-x} \]
                                    2. *-commutativeN/A

                                      \[\leadsto \left(\left(e^{x}\right) \bmod \left(\color{blue}{\left(\frac{-1}{96} \cdot {x}^{2} - \frac{1}{4}\right) \cdot {x}^{2}} + 1\right)\right) \cdot e^{-x} \]
                                    3. lower-fma.f64N/A

                                      \[\leadsto \left(\left(e^{x}\right) \bmod \color{blue}{\left(\mathsf{fma}\left(\frac{-1}{96} \cdot {x}^{2} - \frac{1}{4}, {x}^{2}, 1\right)\right)}\right) \cdot e^{-x} \]
                                    4. sub-negN/A

                                      \[\leadsto \left(\left(e^{x}\right) \bmod \left(\mathsf{fma}\left(\color{blue}{\frac{-1}{96} \cdot {x}^{2} + \left(\mathsf{neg}\left(\frac{1}{4}\right)\right)}, {x}^{2}, 1\right)\right)\right) \cdot e^{-x} \]
                                    5. metadata-evalN/A

                                      \[\leadsto \left(\left(e^{x}\right) \bmod \left(\mathsf{fma}\left(\frac{-1}{96} \cdot {x}^{2} + \color{blue}{\frac{-1}{4}}, {x}^{2}, 1\right)\right)\right) \cdot e^{-x} \]
                                    6. lower-fma.f64N/A

                                      \[\leadsto \left(\left(e^{x}\right) \bmod \left(\mathsf{fma}\left(\color{blue}{\mathsf{fma}\left(\frac{-1}{96}, {x}^{2}, \frac{-1}{4}\right)}, {x}^{2}, 1\right)\right)\right) \cdot e^{-x} \]
                                    7. unpow2N/A

                                      \[\leadsto \left(\left(e^{x}\right) \bmod \left(\mathsf{fma}\left(\mathsf{fma}\left(\frac{-1}{96}, \color{blue}{x \cdot x}, \frac{-1}{4}\right), {x}^{2}, 1\right)\right)\right) \cdot e^{-x} \]
                                    8. lower-*.f64N/A

                                      \[\leadsto \left(\left(e^{x}\right) \bmod \left(\mathsf{fma}\left(\mathsf{fma}\left(\frac{-1}{96}, \color{blue}{x \cdot x}, \frac{-1}{4}\right), {x}^{2}, 1\right)\right)\right) \cdot e^{-x} \]
                                    9. unpow2N/A

                                      \[\leadsto \left(\left(e^{x}\right) \bmod \left(\mathsf{fma}\left(\mathsf{fma}\left(\frac{-1}{96}, x \cdot x, \frac{-1}{4}\right), \color{blue}{x \cdot x}, 1\right)\right)\right) \cdot e^{-x} \]
                                    10. lower-*.f648.9

                                      \[\leadsto \left(\left(e^{x}\right) \bmod \left(\mathsf{fma}\left(\mathsf{fma}\left(-0.010416666666666666, x \cdot x, -0.25\right), \color{blue}{x \cdot x}, 1\right)\right)\right) \cdot e^{-x} \]
                                  5. Applied rewrites8.9%

                                    \[\leadsto \left(\left(e^{x}\right) \bmod \color{blue}{\left(\mathsf{fma}\left(\mathsf{fma}\left(-0.010416666666666666, x \cdot x, -0.25\right), x \cdot x, 1\right)\right)}\right) \cdot e^{-x} \]

                                  if 2 < (*.f64 (fmod.f64 (exp.f64 x) (sqrt.f64 (cos.f64 x))) (exp.f64 (neg.f64 x)))

                                  1. Initial program 0.0%

                                    \[\left(\left(e^{x}\right) \bmod \left(\sqrt{\cos x}\right)\right) \cdot e^{-x} \]
                                  2. Add Preprocessing
                                  3. Taylor expanded in x around 0

                                    \[\leadsto \left(\color{blue}{1} \bmod \left(\sqrt{\cos x}\right)\right) \cdot e^{-x} \]
                                  4. Step-by-step derivation
                                    1. Applied rewrites98.2%

                                      \[\leadsto \left(\color{blue}{1} \bmod \left(\sqrt{\cos x}\right)\right) \cdot e^{-x} \]
                                    2. Taylor expanded in x around 0

                                      \[\leadsto \left(1 \bmod \color{blue}{1}\right) \cdot e^{-x} \]
                                    3. Step-by-step derivation
                                      1. Applied rewrites98.1%

                                        \[\leadsto \left(1 \bmod \color{blue}{1}\right) \cdot e^{-x} \]
                                      2. Taylor expanded in x around 0

                                        \[\leadsto \left(1 \bmod 1\right) \cdot \color{blue}{1} \]
                                      3. Step-by-step derivation
                                        1. Applied rewrites98.2%

                                          \[\leadsto \left(1 \bmod 1\right) \cdot \color{blue}{1} \]
                                      4. Recombined 2 regimes into one program.
                                      5. Final simplification27.4%

                                        \[\leadsto \begin{array}{l} \mathbf{if}\;e^{-x} \cdot \left(\left(e^{x}\right) \bmod \left(\sqrt{\cos x}\right)\right) \leq 2:\\ \;\;\;\;\left(\left(e^{x}\right) \bmod \left(\mathsf{fma}\left(\mathsf{fma}\left(-0.010416666666666666, x \cdot x, -0.25\right), x \cdot x, 1\right)\right)\right) \cdot e^{-x}\\ \mathbf{else}:\\ \;\;\;\;1 \cdot \left(1 \bmod 1\right)\\ \end{array} \]
                                      6. Add Preprocessing

                                      Alternative 7: 26.3% accurate, 0.6× speedup?

                                      \[\begin{array}{l} \\ \begin{array}{l} t_0 := e^{-x}\\ \mathbf{if}\;t\_0 \cdot \left(\left(e^{x}\right) \bmod \left(\sqrt{\cos x}\right)\right) \leq 2:\\ \;\;\;\;\left(\left(e^{x}\right) \bmod \left(\mathsf{fma}\left(x \cdot x, -0.25, 1\right)\right)\right) \cdot t\_0\\ \mathbf{else}:\\ \;\;\;\;1 \cdot \left(1 \bmod 1\right)\\ \end{array} \end{array} \]
                                      (FPCore (x)
                                       :precision binary64
                                       (let* ((t_0 (exp (- x))))
                                         (if (<= (* t_0 (fmod (exp x) (sqrt (cos x)))) 2.0)
                                           (* (fmod (exp x) (fma (* x x) -0.25 1.0)) t_0)
                                           (* 1.0 (fmod 1.0 1.0)))))
                                      double code(double x) {
                                      	double t_0 = exp(-x);
                                      	double tmp;
                                      	if ((t_0 * fmod(exp(x), sqrt(cos(x)))) <= 2.0) {
                                      		tmp = fmod(exp(x), fma((x * x), -0.25, 1.0)) * t_0;
                                      	} else {
                                      		tmp = 1.0 * fmod(1.0, 1.0);
                                      	}
                                      	return tmp;
                                      }
                                      
                                      function code(x)
                                      	t_0 = exp(Float64(-x))
                                      	tmp = 0.0
                                      	if (Float64(t_0 * rem(exp(x), sqrt(cos(x)))) <= 2.0)
                                      		tmp = Float64(rem(exp(x), fma(Float64(x * x), -0.25, 1.0)) * t_0);
                                      	else
                                      		tmp = Float64(1.0 * rem(1.0, 1.0));
                                      	end
                                      	return tmp
                                      end
                                      
                                      code[x_] := Block[{t$95$0 = N[Exp[(-x)], $MachinePrecision]}, If[LessEqual[N[(t$95$0 * N[With[{TMP1 = N[Exp[x], $MachinePrecision], TMP2 = N[Sqrt[N[Cos[x], $MachinePrecision]], $MachinePrecision]}, Mod[Abs[TMP1], Abs[TMP2]] * Sign[TMP1]], $MachinePrecision]), $MachinePrecision], 2.0], N[(N[With[{TMP1 = N[Exp[x], $MachinePrecision], TMP2 = N[(N[(x * x), $MachinePrecision] * -0.25 + 1.0), $MachinePrecision]}, Mod[Abs[TMP1], Abs[TMP2]] * Sign[TMP1]], $MachinePrecision] * t$95$0), $MachinePrecision], N[(1.0 * N[With[{TMP1 = 1.0, TMP2 = 1.0}, Mod[Abs[TMP1], Abs[TMP2]] * Sign[TMP1]], $MachinePrecision]), $MachinePrecision]]]
                                      
                                      \begin{array}{l}
                                      
                                      \\
                                      \begin{array}{l}
                                      t_0 := e^{-x}\\
                                      \mathbf{if}\;t\_0 \cdot \left(\left(e^{x}\right) \bmod \left(\sqrt{\cos x}\right)\right) \leq 2:\\
                                      \;\;\;\;\left(\left(e^{x}\right) \bmod \left(\mathsf{fma}\left(x \cdot x, -0.25, 1\right)\right)\right) \cdot t\_0\\
                                      
                                      \mathbf{else}:\\
                                      \;\;\;\;1 \cdot \left(1 \bmod 1\right)\\
                                      
                                      
                                      \end{array}
                                      \end{array}
                                      
                                      Derivation
                                      1. Split input into 2 regimes
                                      2. if (*.f64 (fmod.f64 (exp.f64 x) (sqrt.f64 (cos.f64 x))) (exp.f64 (neg.f64 x))) < 2

                                        1. Initial program 9.0%

                                          \[\left(\left(e^{x}\right) \bmod \left(\sqrt{\cos x}\right)\right) \cdot e^{-x} \]
                                        2. Add Preprocessing
                                        3. Taylor expanded in x around 0

                                          \[\leadsto \left(\left(e^{x}\right) \bmod \color{blue}{\left(1 + \frac{-1}{4} \cdot {x}^{2}\right)}\right) \cdot e^{-x} \]
                                        4. Step-by-step derivation
                                          1. +-commutativeN/A

                                            \[\leadsto \left(\left(e^{x}\right) \bmod \color{blue}{\left(\frac{-1}{4} \cdot {x}^{2} + 1\right)}\right) \cdot e^{-x} \]
                                          2. *-commutativeN/A

                                            \[\leadsto \left(\left(e^{x}\right) \bmod \left(\color{blue}{{x}^{2} \cdot \frac{-1}{4}} + 1\right)\right) \cdot e^{-x} \]
                                          3. lower-fma.f64N/A

                                            \[\leadsto \left(\left(e^{x}\right) \bmod \color{blue}{\left(\mathsf{fma}\left({x}^{2}, \frac{-1}{4}, 1\right)\right)}\right) \cdot e^{-x} \]
                                          4. unpow2N/A

                                            \[\leadsto \left(\left(e^{x}\right) \bmod \left(\mathsf{fma}\left(\color{blue}{x \cdot x}, \frac{-1}{4}, 1\right)\right)\right) \cdot e^{-x} \]
                                          5. lower-*.f648.8

                                            \[\leadsto \left(\left(e^{x}\right) \bmod \left(\mathsf{fma}\left(\color{blue}{x \cdot x}, -0.25, 1\right)\right)\right) \cdot e^{-x} \]
                                        5. Applied rewrites8.8%

                                          \[\leadsto \left(\left(e^{x}\right) \bmod \color{blue}{\left(\mathsf{fma}\left(x \cdot x, -0.25, 1\right)\right)}\right) \cdot e^{-x} \]

                                        if 2 < (*.f64 (fmod.f64 (exp.f64 x) (sqrt.f64 (cos.f64 x))) (exp.f64 (neg.f64 x)))

                                        1. Initial program 0.0%

                                          \[\left(\left(e^{x}\right) \bmod \left(\sqrt{\cos x}\right)\right) \cdot e^{-x} \]
                                        2. Add Preprocessing
                                        3. Taylor expanded in x around 0

                                          \[\leadsto \left(\color{blue}{1} \bmod \left(\sqrt{\cos x}\right)\right) \cdot e^{-x} \]
                                        4. Step-by-step derivation
                                          1. Applied rewrites98.2%

                                            \[\leadsto \left(\color{blue}{1} \bmod \left(\sqrt{\cos x}\right)\right) \cdot e^{-x} \]
                                          2. Taylor expanded in x around 0

                                            \[\leadsto \left(1 \bmod \color{blue}{1}\right) \cdot e^{-x} \]
                                          3. Step-by-step derivation
                                            1. Applied rewrites98.1%

                                              \[\leadsto \left(1 \bmod \color{blue}{1}\right) \cdot e^{-x} \]
                                            2. Taylor expanded in x around 0

                                              \[\leadsto \left(1 \bmod 1\right) \cdot \color{blue}{1} \]
                                            3. Step-by-step derivation
                                              1. Applied rewrites98.2%

                                                \[\leadsto \left(1 \bmod 1\right) \cdot \color{blue}{1} \]
                                            4. Recombined 2 regimes into one program.
                                            5. Final simplification27.3%

                                              \[\leadsto \begin{array}{l} \mathbf{if}\;e^{-x} \cdot \left(\left(e^{x}\right) \bmod \left(\sqrt{\cos x}\right)\right) \leq 2:\\ \;\;\;\;\left(\left(e^{x}\right) \bmod \left(\mathsf{fma}\left(x \cdot x, -0.25, 1\right)\right)\right) \cdot e^{-x}\\ \mathbf{else}:\\ \;\;\;\;1 \cdot \left(1 \bmod 1\right)\\ \end{array} \]
                                            6. Add Preprocessing

                                            Alternative 8: 25.4% accurate, 3.5× speedup?

                                            \[\begin{array}{l} \\ \frac{\left(\left(1 + x\right) \bmod 1\right)}{1 + x} \end{array} \]
                                            (FPCore (x) :precision binary64 (/ (fmod (+ 1.0 x) 1.0) (+ 1.0 x)))
                                            double code(double x) {
                                            	return fmod((1.0 + x), 1.0) / (1.0 + x);
                                            }
                                            
                                            real(8) function code(x)
                                                real(8), intent (in) :: x
                                                code = mod((1.0d0 + x), 1.0d0) / (1.0d0 + x)
                                            end function
                                            
                                            def code(x):
                                            	return math.fmod((1.0 + x), 1.0) / (1.0 + x)
                                            
                                            function code(x)
                                            	return Float64(rem(Float64(1.0 + x), 1.0) / Float64(1.0 + x))
                                            end
                                            
                                            code[x_] := N[(N[With[{TMP1 = N[(1.0 + x), $MachinePrecision], TMP2 = 1.0}, Mod[Abs[TMP1], Abs[TMP2]] * Sign[TMP1]], $MachinePrecision] / N[(1.0 + x), $MachinePrecision]), $MachinePrecision]
                                            
                                            \begin{array}{l}
                                            
                                            \\
                                            \frac{\left(\left(1 + x\right) \bmod 1\right)}{1 + x}
                                            \end{array}
                                            
                                            Derivation
                                            1. Initial program 7.2%

                                              \[\left(\left(e^{x}\right) \bmod \left(\sqrt{\cos x}\right)\right) \cdot e^{-x} \]
                                            2. Add Preprocessing
                                            3. Taylor expanded in x around 0

                                              \[\leadsto \left(\left(e^{x}\right) \bmod \color{blue}{1}\right) \cdot e^{-x} \]
                                            4. Step-by-step derivation
                                              1. Applied rewrites6.6%

                                                \[\leadsto \left(\left(e^{x}\right) \bmod \color{blue}{1}\right) \cdot e^{-x} \]
                                              2. Step-by-step derivation
                                                1. lift-*.f64N/A

                                                  \[\leadsto \color{blue}{\left(\left(e^{x}\right) \bmod 1\right) \cdot e^{-x}} \]
                                                2. lift-exp.f64N/A

                                                  \[\leadsto \left(\left(e^{x}\right) \bmod 1\right) \cdot \color{blue}{e^{-x}} \]
                                                3. lift-neg.f64N/A

                                                  \[\leadsto \left(\left(e^{x}\right) \bmod 1\right) \cdot e^{\color{blue}{\mathsf{neg}\left(x\right)}} \]
                                                4. exp-negN/A

                                                  \[\leadsto \left(\left(e^{x}\right) \bmod 1\right) \cdot \color{blue}{\frac{1}{e^{x}}} \]
                                                5. lift-exp.f64N/A

                                                  \[\leadsto \left(\left(e^{x}\right) \bmod 1\right) \cdot \frac{1}{\color{blue}{e^{x}}} \]
                                                6. un-div-invN/A

                                                  \[\leadsto \color{blue}{\frac{\left(\left(e^{x}\right) \bmod 1\right)}{e^{x}}} \]
                                                7. lower-/.f646.7

                                                  \[\leadsto \color{blue}{\frac{\left(\left(e^{x}\right) \bmod 1\right)}{e^{x}}} \]
                                              3. Applied rewrites6.7%

                                                \[\leadsto \color{blue}{\frac{\left(\left(e^{x}\right) \bmod 1\right)}{e^{x}}} \]
                                              4. Taylor expanded in x around 0

                                                \[\leadsto \frac{\left(\left(e^{x}\right) \bmod 1\right)}{\color{blue}{1 + x}} \]
                                              5. Step-by-step derivation
                                                1. lower-+.f645.9

                                                  \[\leadsto \frac{\left(\left(e^{x}\right) \bmod 1\right)}{\color{blue}{1 + x}} \]
                                              6. Applied rewrites5.9%

                                                \[\leadsto \frac{\left(\left(e^{x}\right) \bmod 1\right)}{\color{blue}{1 + x}} \]
                                              7. Taylor expanded in x around 0

                                                \[\leadsto \frac{\left(\color{blue}{\left(1 + x\right)} \bmod 1\right)}{1 + x} \]
                                              8. Step-by-step derivation
                                                1. lower-+.f6425.5

                                                  \[\leadsto \frac{\left(\color{blue}{\left(1 + x\right)} \bmod 1\right)}{1 + x} \]
                                              9. Applied rewrites25.5%

                                                \[\leadsto \frac{\left(\color{blue}{\left(1 + x\right)} \bmod 1\right)}{1 + x} \]
                                              10. Add Preprocessing

                                              Alternative 9: 24.8% accurate, 3.7× speedup?

                                              \[\begin{array}{l} \\ \left(1 - x\right) \cdot \left(\left(1 + x\right) \bmod 1\right) \end{array} \]
                                              (FPCore (x) :precision binary64 (* (- 1.0 x) (fmod (+ 1.0 x) 1.0)))
                                              double code(double x) {
                                              	return (1.0 - x) * fmod((1.0 + x), 1.0);
                                              }
                                              
                                              real(8) function code(x)
                                                  real(8), intent (in) :: x
                                                  code = (1.0d0 - x) * mod((1.0d0 + x), 1.0d0)
                                              end function
                                              
                                              def code(x):
                                              	return (1.0 - x) * math.fmod((1.0 + x), 1.0)
                                              
                                              function code(x)
                                              	return Float64(Float64(1.0 - x) * rem(Float64(1.0 + x), 1.0))
                                              end
                                              
                                              code[x_] := N[(N[(1.0 - x), $MachinePrecision] * N[With[{TMP1 = N[(1.0 + x), $MachinePrecision], TMP2 = 1.0}, Mod[Abs[TMP1], Abs[TMP2]] * Sign[TMP1]], $MachinePrecision]), $MachinePrecision]
                                              
                                              \begin{array}{l}
                                              
                                              \\
                                              \left(1 - x\right) \cdot \left(\left(1 + x\right) \bmod 1\right)
                                              \end{array}
                                              
                                              Derivation
                                              1. Initial program 7.2%

                                                \[\left(\left(e^{x}\right) \bmod \left(\sqrt{\cos x}\right)\right) \cdot e^{-x} \]
                                              2. Add Preprocessing
                                              3. Taylor expanded in x around 0

                                                \[\leadsto \left(\left(e^{x}\right) \bmod \color{blue}{1}\right) \cdot e^{-x} \]
                                              4. Step-by-step derivation
                                                1. Applied rewrites6.6%

                                                  \[\leadsto \left(\left(e^{x}\right) \bmod \color{blue}{1}\right) \cdot e^{-x} \]
                                                2. Taylor expanded in x around 0

                                                  \[\leadsto \left(\left(e^{x}\right) \bmod 1\right) \cdot \color{blue}{1} \]
                                                3. Step-by-step derivation
                                                  1. Applied rewrites5.3%

                                                    \[\leadsto \left(\left(e^{x}\right) \bmod 1\right) \cdot \color{blue}{1} \]
                                                  2. Taylor expanded in x around 0

                                                    \[\leadsto \left(\color{blue}{\left(1 + x\right)} \bmod 1\right) \cdot 1 \]
                                                  3. Step-by-step derivation
                                                    1. lower-+.f6424.2

                                                      \[\leadsto \left(\color{blue}{\left(1 + x\right)} \bmod 1\right) \cdot 1 \]
                                                  4. Applied rewrites24.2%

                                                    \[\leadsto \left(\color{blue}{\left(1 + x\right)} \bmod 1\right) \cdot 1 \]
                                                  5. Taylor expanded in x around 0

                                                    \[\leadsto \left(\left(1 + x\right) \bmod 1\right) \cdot \color{blue}{\left(1 + -1 \cdot x\right)} \]
                                                  6. Step-by-step derivation
                                                    1. neg-mul-1N/A

                                                      \[\leadsto \left(\left(1 + x\right) \bmod 1\right) \cdot \left(1 + \color{blue}{\left(\mathsf{neg}\left(x\right)\right)}\right) \]
                                                    2. unsub-negN/A

                                                      \[\leadsto \left(\left(1 + x\right) \bmod 1\right) \cdot \color{blue}{\left(1 - x\right)} \]
                                                    3. lower--.f6424.6

                                                      \[\leadsto \left(\left(1 + x\right) \bmod 1\right) \cdot \color{blue}{\left(1 - x\right)} \]
                                                  7. Applied rewrites24.6%

                                                    \[\leadsto \left(\left(1 + x\right) \bmod 1\right) \cdot \color{blue}{\left(1 - x\right)} \]
                                                  8. Final simplification24.6%

                                                    \[\leadsto \left(1 - x\right) \cdot \left(\left(1 + x\right) \bmod 1\right) \]
                                                  9. Add Preprocessing

                                                  Alternative 10: 24.4% accurate, 3.8× speedup?

                                                  \[\begin{array}{l} \\ \left(\left(1 + x\right) \bmod 1\right) \cdot 1 \end{array} \]
                                                  (FPCore (x) :precision binary64 (* (fmod (+ 1.0 x) 1.0) 1.0))
                                                  double code(double x) {
                                                  	return fmod((1.0 + x), 1.0) * 1.0;
                                                  }
                                                  
                                                  real(8) function code(x)
                                                      real(8), intent (in) :: x
                                                      code = mod((1.0d0 + x), 1.0d0) * 1.0d0
                                                  end function
                                                  
                                                  def code(x):
                                                  	return math.fmod((1.0 + x), 1.0) * 1.0
                                                  
                                                  function code(x)
                                                  	return Float64(rem(Float64(1.0 + x), 1.0) * 1.0)
                                                  end
                                                  
                                                  code[x_] := N[(N[With[{TMP1 = N[(1.0 + x), $MachinePrecision], TMP2 = 1.0}, Mod[Abs[TMP1], Abs[TMP2]] * Sign[TMP1]], $MachinePrecision] * 1.0), $MachinePrecision]
                                                  
                                                  \begin{array}{l}
                                                  
                                                  \\
                                                  \left(\left(1 + x\right) \bmod 1\right) \cdot 1
                                                  \end{array}
                                                  
                                                  Derivation
                                                  1. Initial program 7.2%

                                                    \[\left(\left(e^{x}\right) \bmod \left(\sqrt{\cos x}\right)\right) \cdot e^{-x} \]
                                                  2. Add Preprocessing
                                                  3. Taylor expanded in x around 0

                                                    \[\leadsto \left(\left(e^{x}\right) \bmod \color{blue}{1}\right) \cdot e^{-x} \]
                                                  4. Step-by-step derivation
                                                    1. Applied rewrites6.6%

                                                      \[\leadsto \left(\left(e^{x}\right) \bmod \color{blue}{1}\right) \cdot e^{-x} \]
                                                    2. Taylor expanded in x around 0

                                                      \[\leadsto \left(\left(e^{x}\right) \bmod 1\right) \cdot \color{blue}{1} \]
                                                    3. Step-by-step derivation
                                                      1. Applied rewrites5.3%

                                                        \[\leadsto \left(\left(e^{x}\right) \bmod 1\right) \cdot \color{blue}{1} \]
                                                      2. Taylor expanded in x around 0

                                                        \[\leadsto \left(\color{blue}{\left(1 + x\right)} \bmod 1\right) \cdot 1 \]
                                                      3. Step-by-step derivation
                                                        1. lower-+.f6424.2

                                                          \[\leadsto \left(\color{blue}{\left(1 + x\right)} \bmod 1\right) \cdot 1 \]
                                                      4. Applied rewrites24.2%

                                                        \[\leadsto \left(\color{blue}{\left(1 + x\right)} \bmod 1\right) \cdot 1 \]
                                                      5. Add Preprocessing

                                                      Alternative 11: 22.9% accurate, 3.9× speedup?

                                                      \[\begin{array}{l} \\ 1 \cdot \left(1 \bmod 1\right) \end{array} \]
                                                      (FPCore (x) :precision binary64 (* 1.0 (fmod 1.0 1.0)))
                                                      double code(double x) {
                                                      	return 1.0 * fmod(1.0, 1.0);
                                                      }
                                                      
                                                      real(8) function code(x)
                                                          real(8), intent (in) :: x
                                                          code = 1.0d0 * mod(1.0d0, 1.0d0)
                                                      end function
                                                      
                                                      def code(x):
                                                      	return 1.0 * math.fmod(1.0, 1.0)
                                                      
                                                      function code(x)
                                                      	return Float64(1.0 * rem(1.0, 1.0))
                                                      end
                                                      
                                                      code[x_] := N[(1.0 * N[With[{TMP1 = 1.0, TMP2 = 1.0}, Mod[Abs[TMP1], Abs[TMP2]] * Sign[TMP1]], $MachinePrecision]), $MachinePrecision]
                                                      
                                                      \begin{array}{l}
                                                      
                                                      \\
                                                      1 \cdot \left(1 \bmod 1\right)
                                                      \end{array}
                                                      
                                                      Derivation
                                                      1. Initial program 7.2%

                                                        \[\left(\left(e^{x}\right) \bmod \left(\sqrt{\cos x}\right)\right) \cdot e^{-x} \]
                                                      2. Add Preprocessing
                                                      3. Taylor expanded in x around 0

                                                        \[\leadsto \left(\color{blue}{1} \bmod \left(\sqrt{\cos x}\right)\right) \cdot e^{-x} \]
                                                      4. Step-by-step derivation
                                                        1. Applied rewrites24.2%

                                                          \[\leadsto \left(\color{blue}{1} \bmod \left(\sqrt{\cos x}\right)\right) \cdot e^{-x} \]
                                                        2. Taylor expanded in x around 0

                                                          \[\leadsto \left(1 \bmod \color{blue}{1}\right) \cdot e^{-x} \]
                                                        3. Step-by-step derivation
                                                          1. Applied rewrites23.9%

                                                            \[\leadsto \left(1 \bmod \color{blue}{1}\right) \cdot e^{-x} \]
                                                          2. Taylor expanded in x around 0

                                                            \[\leadsto \left(1 \bmod 1\right) \cdot \color{blue}{1} \]
                                                          3. Step-by-step derivation
                                                            1. Applied rewrites23.9%

                                                              \[\leadsto \left(1 \bmod 1\right) \cdot \color{blue}{1} \]
                                                            2. Final simplification23.9%

                                                              \[\leadsto 1 \cdot \left(1 \bmod 1\right) \]
                                                            3. Add Preprocessing

                                                            Reproduce

                                                            ?
                                                            herbie shell --seed 2024241 
                                                            (FPCore (x)
                                                              :name "expfmod (used to be hard to sample)"
                                                              :precision binary64
                                                              (* (fmod (exp x) (sqrt (cos x))) (exp (- x))))