Toniolo and Linder, Equation (3a)

Percentage Accurate: 98.5% → 99.3%
Time: 13.4s
Alternatives: 7
Speedup: 1.0×

Specification

?
\[\begin{array}{l} \\ \sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{\sqrt{1 + {\left(\frac{2 \cdot \ell}{Om}\right)}^{2} \cdot \left({\sin kx}^{2} + {\sin ky}^{2}\right)}}\right)} \end{array} \]
(FPCore (l Om kx ky)
 :precision binary64
 (sqrt
  (*
   (/ 1.0 2.0)
   (+
    1.0
    (/
     1.0
     (sqrt
      (+
       1.0
       (*
        (pow (/ (* 2.0 l) Om) 2.0)
        (+ (pow (sin kx) 2.0) (pow (sin ky) 2.0))))))))))
double code(double l, double Om, double kx, double ky) {
	return sqrt(((1.0 / 2.0) * (1.0 + (1.0 / sqrt((1.0 + (pow(((2.0 * l) / Om), 2.0) * (pow(sin(kx), 2.0) + pow(sin(ky), 2.0)))))))));
}
real(8) function code(l, om, kx, ky)
    real(8), intent (in) :: l
    real(8), intent (in) :: om
    real(8), intent (in) :: kx
    real(8), intent (in) :: ky
    code = sqrt(((1.0d0 / 2.0d0) * (1.0d0 + (1.0d0 / sqrt((1.0d0 + ((((2.0d0 * l) / om) ** 2.0d0) * ((sin(kx) ** 2.0d0) + (sin(ky) ** 2.0d0)))))))))
end function
public static double code(double l, double Om, double kx, double ky) {
	return Math.sqrt(((1.0 / 2.0) * (1.0 + (1.0 / Math.sqrt((1.0 + (Math.pow(((2.0 * l) / Om), 2.0) * (Math.pow(Math.sin(kx), 2.0) + Math.pow(Math.sin(ky), 2.0)))))))));
}
def code(l, Om, kx, ky):
	return math.sqrt(((1.0 / 2.0) * (1.0 + (1.0 / math.sqrt((1.0 + (math.pow(((2.0 * l) / Om), 2.0) * (math.pow(math.sin(kx), 2.0) + math.pow(math.sin(ky), 2.0)))))))))
function code(l, Om, kx, ky)
	return sqrt(Float64(Float64(1.0 / 2.0) * Float64(1.0 + Float64(1.0 / sqrt(Float64(1.0 + Float64((Float64(Float64(2.0 * l) / Om) ^ 2.0) * Float64((sin(kx) ^ 2.0) + (sin(ky) ^ 2.0)))))))))
end
function tmp = code(l, Om, kx, ky)
	tmp = sqrt(((1.0 / 2.0) * (1.0 + (1.0 / sqrt((1.0 + ((((2.0 * l) / Om) ^ 2.0) * ((sin(kx) ^ 2.0) + (sin(ky) ^ 2.0)))))))));
end
code[l_, Om_, kx_, ky_] := N[Sqrt[N[(N[(1.0 / 2.0), $MachinePrecision] * N[(1.0 + N[(1.0 / N[Sqrt[N[(1.0 + N[(N[Power[N[(N[(2.0 * l), $MachinePrecision] / Om), $MachinePrecision], 2.0], $MachinePrecision] * N[(N[Power[N[Sin[kx], $MachinePrecision], 2.0], $MachinePrecision] + N[Power[N[Sin[ky], $MachinePrecision], 2.0], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]
\begin{array}{l}

\\
\sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{\sqrt{1 + {\left(\frac{2 \cdot \ell}{Om}\right)}^{2} \cdot \left({\sin kx}^{2} + {\sin ky}^{2}\right)}}\right)}
\end{array}

Sampling outcomes in binary64 precision:

Local Percentage Accuracy vs ?

The average percentage accuracy by input value. Horizontal axis shows value of an input variable; the variable is choosen in the title. Vertical axis is accuracy; higher is better. Red represent the original program, while blue represents Herbie's suggestion. These can be toggled with buttons below the plot. The line is an average while dots represent individual samples.

Accuracy vs Speed?

Herbie found 7 alternatives:

AlternativeAccuracySpeedup
The accuracy (vertical axis) and speed (horizontal axis) of each alternatives. Up and to the right is better. The red square shows the initial program, and each blue circle shows an alternative.The line shows the best available speed-accuracy tradeoffs.

Initial Program: 98.5% accurate, 1.0× speedup?

\[\begin{array}{l} \\ \sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{\sqrt{1 + {\left(\frac{2 \cdot \ell}{Om}\right)}^{2} \cdot \left({\sin kx}^{2} + {\sin ky}^{2}\right)}}\right)} \end{array} \]
(FPCore (l Om kx ky)
 :precision binary64
 (sqrt
  (*
   (/ 1.0 2.0)
   (+
    1.0
    (/
     1.0
     (sqrt
      (+
       1.0
       (*
        (pow (/ (* 2.0 l) Om) 2.0)
        (+ (pow (sin kx) 2.0) (pow (sin ky) 2.0))))))))))
double code(double l, double Om, double kx, double ky) {
	return sqrt(((1.0 / 2.0) * (1.0 + (1.0 / sqrt((1.0 + (pow(((2.0 * l) / Om), 2.0) * (pow(sin(kx), 2.0) + pow(sin(ky), 2.0)))))))));
}
real(8) function code(l, om, kx, ky)
    real(8), intent (in) :: l
    real(8), intent (in) :: om
    real(8), intent (in) :: kx
    real(8), intent (in) :: ky
    code = sqrt(((1.0d0 / 2.0d0) * (1.0d0 + (1.0d0 / sqrt((1.0d0 + ((((2.0d0 * l) / om) ** 2.0d0) * ((sin(kx) ** 2.0d0) + (sin(ky) ** 2.0d0)))))))))
end function
public static double code(double l, double Om, double kx, double ky) {
	return Math.sqrt(((1.0 / 2.0) * (1.0 + (1.0 / Math.sqrt((1.0 + (Math.pow(((2.0 * l) / Om), 2.0) * (Math.pow(Math.sin(kx), 2.0) + Math.pow(Math.sin(ky), 2.0)))))))));
}
def code(l, Om, kx, ky):
	return math.sqrt(((1.0 / 2.0) * (1.0 + (1.0 / math.sqrt((1.0 + (math.pow(((2.0 * l) / Om), 2.0) * (math.pow(math.sin(kx), 2.0) + math.pow(math.sin(ky), 2.0)))))))))
function code(l, Om, kx, ky)
	return sqrt(Float64(Float64(1.0 / 2.0) * Float64(1.0 + Float64(1.0 / sqrt(Float64(1.0 + Float64((Float64(Float64(2.0 * l) / Om) ^ 2.0) * Float64((sin(kx) ^ 2.0) + (sin(ky) ^ 2.0)))))))))
end
function tmp = code(l, Om, kx, ky)
	tmp = sqrt(((1.0 / 2.0) * (1.0 + (1.0 / sqrt((1.0 + ((((2.0 * l) / Om) ^ 2.0) * ((sin(kx) ^ 2.0) + (sin(ky) ^ 2.0)))))))));
end
code[l_, Om_, kx_, ky_] := N[Sqrt[N[(N[(1.0 / 2.0), $MachinePrecision] * N[(1.0 + N[(1.0 / N[Sqrt[N[(1.0 + N[(N[Power[N[(N[(2.0 * l), $MachinePrecision] / Om), $MachinePrecision], 2.0], $MachinePrecision] * N[(N[Power[N[Sin[kx], $MachinePrecision], 2.0], $MachinePrecision] + N[Power[N[Sin[ky], $MachinePrecision], 2.0], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]
\begin{array}{l}

\\
\sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{\sqrt{1 + {\left(\frac{2 \cdot \ell}{Om}\right)}^{2} \cdot \left({\sin kx}^{2} + {\sin ky}^{2}\right)}}\right)}
\end{array}

Alternative 1: 99.3% accurate, 0.7× speedup?

\[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;\left({\sin ky}^{2} + {\sin kx}^{2}\right) \cdot {\left(\frac{\ell \cdot 2}{Om}\right)}^{2} \leq 2 \cdot 10^{+25}:\\ \;\;\;\;\sqrt{\left(\frac{1}{\sqrt{\mathsf{fma}\left(4 \cdot \frac{\ell}{Om}, \left(0.5 - \left(\cos \left(ky + ky\right) \cdot 0.5 - \left(0.5 - \cos \left(kx + kx\right) \cdot 0.5\right)\right)\right) \cdot \frac{\ell}{Om}, 1\right)}} + 1\right) \cdot \frac{1}{2}}\\ \mathbf{else}:\\ \;\;\;\;\sqrt{0.5}\\ \end{array} \end{array} \]
(FPCore (l Om kx ky)
 :precision binary64
 (if (<=
      (* (+ (pow (sin ky) 2.0) (pow (sin kx) 2.0)) (pow (/ (* l 2.0) Om) 2.0))
      2e+25)
   (sqrt
    (*
     (+
      (/
       1.0
       (sqrt
        (fma
         (* 4.0 (/ l Om))
         (*
          (- 0.5 (- (* (cos (+ ky ky)) 0.5) (- 0.5 (* (cos (+ kx kx)) 0.5))))
          (/ l Om))
         1.0)))
      1.0)
     (/ 1.0 2.0)))
   (sqrt 0.5)))
double code(double l, double Om, double kx, double ky) {
	double tmp;
	if (((pow(sin(ky), 2.0) + pow(sin(kx), 2.0)) * pow(((l * 2.0) / Om), 2.0)) <= 2e+25) {
		tmp = sqrt((((1.0 / sqrt(fma((4.0 * (l / Om)), ((0.5 - ((cos((ky + ky)) * 0.5) - (0.5 - (cos((kx + kx)) * 0.5)))) * (l / Om)), 1.0))) + 1.0) * (1.0 / 2.0)));
	} else {
		tmp = sqrt(0.5);
	}
	return tmp;
}
function code(l, Om, kx, ky)
	tmp = 0.0
	if (Float64(Float64((sin(ky) ^ 2.0) + (sin(kx) ^ 2.0)) * (Float64(Float64(l * 2.0) / Om) ^ 2.0)) <= 2e+25)
		tmp = sqrt(Float64(Float64(Float64(1.0 / sqrt(fma(Float64(4.0 * Float64(l / Om)), Float64(Float64(0.5 - Float64(Float64(cos(Float64(ky + ky)) * 0.5) - Float64(0.5 - Float64(cos(Float64(kx + kx)) * 0.5)))) * Float64(l / Om)), 1.0))) + 1.0) * Float64(1.0 / 2.0)));
	else
		tmp = sqrt(0.5);
	end
	return tmp
end
code[l_, Om_, kx_, ky_] := If[LessEqual[N[(N[(N[Power[N[Sin[ky], $MachinePrecision], 2.0], $MachinePrecision] + N[Power[N[Sin[kx], $MachinePrecision], 2.0], $MachinePrecision]), $MachinePrecision] * N[Power[N[(N[(l * 2.0), $MachinePrecision] / Om), $MachinePrecision], 2.0], $MachinePrecision]), $MachinePrecision], 2e+25], N[Sqrt[N[(N[(N[(1.0 / N[Sqrt[N[(N[(4.0 * N[(l / Om), $MachinePrecision]), $MachinePrecision] * N[(N[(0.5 - N[(N[(N[Cos[N[(ky + ky), $MachinePrecision]], $MachinePrecision] * 0.5), $MachinePrecision] - N[(0.5 - N[(N[Cos[N[(kx + kx), $MachinePrecision]], $MachinePrecision] * 0.5), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] * N[(l / Om), $MachinePrecision]), $MachinePrecision] + 1.0), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] + 1.0), $MachinePrecision] * N[(1.0 / 2.0), $MachinePrecision]), $MachinePrecision]], $MachinePrecision], N[Sqrt[0.5], $MachinePrecision]]
\begin{array}{l}

\\
\begin{array}{l}
\mathbf{if}\;\left({\sin ky}^{2} + {\sin kx}^{2}\right) \cdot {\left(\frac{\ell \cdot 2}{Om}\right)}^{2} \leq 2 \cdot 10^{+25}:\\
\;\;\;\;\sqrt{\left(\frac{1}{\sqrt{\mathsf{fma}\left(4 \cdot \frac{\ell}{Om}, \left(0.5 - \left(\cos \left(ky + ky\right) \cdot 0.5 - \left(0.5 - \cos \left(kx + kx\right) \cdot 0.5\right)\right)\right) \cdot \frac{\ell}{Om}, 1\right)}} + 1\right) \cdot \frac{1}{2}}\\

\mathbf{else}:\\
\;\;\;\;\sqrt{0.5}\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if (*.f64 (pow.f64 (/.f64 (*.f64 #s(literal 2 binary64) l) Om) #s(literal 2 binary64)) (+.f64 (pow.f64 (sin.f64 kx) #s(literal 2 binary64)) (pow.f64 (sin.f64 ky) #s(literal 2 binary64)))) < 2.00000000000000018e25

    1. Initial program 100.0%

      \[\sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{\sqrt{1 + {\left(\frac{2 \cdot \ell}{Om}\right)}^{2} \cdot \left({\sin kx}^{2} + {\sin ky}^{2}\right)}}\right)} \]
    2. Add Preprocessing
    3. Applied rewrites98.9%

      \[\leadsto \sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{\sqrt{\color{blue}{\mathsf{fma}\left(\frac{\ell}{Om} \cdot 4, \frac{\ell}{Om} \cdot \left(0.5 - \left(0.5 \cdot \cos \left(ky + ky\right) - \left(0.5 - 0.5 \cdot \cos \left(kx + kx\right)\right)\right)\right), 1\right)}}}\right)} \]

    if 2.00000000000000018e25 < (*.f64 (pow.f64 (/.f64 (*.f64 #s(literal 2 binary64) l) Om) #s(literal 2 binary64)) (+.f64 (pow.f64 (sin.f64 kx) #s(literal 2 binary64)) (pow.f64 (sin.f64 ky) #s(literal 2 binary64))))

    1. Initial program 96.3%

      \[\sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{\sqrt{1 + {\left(\frac{2 \cdot \ell}{Om}\right)}^{2} \cdot \left({\sin kx}^{2} + {\sin ky}^{2}\right)}}\right)} \]
    2. Add Preprocessing
    3. Taylor expanded in Om around 0

      \[\leadsto \sqrt{\color{blue}{\frac{1}{2}}} \]
    4. Step-by-step derivation
      1. Applied rewrites100.0%

        \[\leadsto \sqrt{\color{blue}{0.5}} \]
    5. Recombined 2 regimes into one program.
    6. Final simplification99.4%

      \[\leadsto \begin{array}{l} \mathbf{if}\;\left({\sin ky}^{2} + {\sin kx}^{2}\right) \cdot {\left(\frac{\ell \cdot 2}{Om}\right)}^{2} \leq 2 \cdot 10^{+25}:\\ \;\;\;\;\sqrt{\left(\frac{1}{\sqrt{\mathsf{fma}\left(4 \cdot \frac{\ell}{Om}, \left(0.5 - \left(\cos \left(ky + ky\right) \cdot 0.5 - \left(0.5 - \cos \left(kx + kx\right) \cdot 0.5\right)\right)\right) \cdot \frac{\ell}{Om}, 1\right)}} + 1\right) \cdot \frac{1}{2}}\\ \mathbf{else}:\\ \;\;\;\;\sqrt{0.5}\\ \end{array} \]
    7. Add Preprocessing

    Alternative 2: 91.8% accurate, 0.9× speedup?

    \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;\left({\sin ky}^{2} + {\sin kx}^{2}\right) \cdot {\left(\frac{\ell \cdot 2}{Om}\right)}^{2} \leq 2:\\ \;\;\;\;1\\ \mathbf{else}:\\ \;\;\;\;\sqrt{\mathsf{fma}\left(-0.25, \frac{Om}{\sin ky \cdot \ell}, 0.5\right)}\\ \end{array} \end{array} \]
    (FPCore (l Om kx ky)
     :precision binary64
     (if (<=
          (* (+ (pow (sin ky) 2.0) (pow (sin kx) 2.0)) (pow (/ (* l 2.0) Om) 2.0))
          2.0)
       1.0
       (sqrt (fma -0.25 (/ Om (* (sin ky) l)) 0.5))))
    double code(double l, double Om, double kx, double ky) {
    	double tmp;
    	if (((pow(sin(ky), 2.0) + pow(sin(kx), 2.0)) * pow(((l * 2.0) / Om), 2.0)) <= 2.0) {
    		tmp = 1.0;
    	} else {
    		tmp = sqrt(fma(-0.25, (Om / (sin(ky) * l)), 0.5));
    	}
    	return tmp;
    }
    
    function code(l, Om, kx, ky)
    	tmp = 0.0
    	if (Float64(Float64((sin(ky) ^ 2.0) + (sin(kx) ^ 2.0)) * (Float64(Float64(l * 2.0) / Om) ^ 2.0)) <= 2.0)
    		tmp = 1.0;
    	else
    		tmp = sqrt(fma(-0.25, Float64(Om / Float64(sin(ky) * l)), 0.5));
    	end
    	return tmp
    end
    
    code[l_, Om_, kx_, ky_] := If[LessEqual[N[(N[(N[Power[N[Sin[ky], $MachinePrecision], 2.0], $MachinePrecision] + N[Power[N[Sin[kx], $MachinePrecision], 2.0], $MachinePrecision]), $MachinePrecision] * N[Power[N[(N[(l * 2.0), $MachinePrecision] / Om), $MachinePrecision], 2.0], $MachinePrecision]), $MachinePrecision], 2.0], 1.0, N[Sqrt[N[(-0.25 * N[(Om / N[(N[Sin[ky], $MachinePrecision] * l), $MachinePrecision]), $MachinePrecision] + 0.5), $MachinePrecision]], $MachinePrecision]]
    
    \begin{array}{l}
    
    \\
    \begin{array}{l}
    \mathbf{if}\;\left({\sin ky}^{2} + {\sin kx}^{2}\right) \cdot {\left(\frac{\ell \cdot 2}{Om}\right)}^{2} \leq 2:\\
    \;\;\;\;1\\
    
    \mathbf{else}:\\
    \;\;\;\;\sqrt{\mathsf{fma}\left(-0.25, \frac{Om}{\sin ky \cdot \ell}, 0.5\right)}\\
    
    
    \end{array}
    \end{array}
    
    Derivation
    1. Split input into 2 regimes
    2. if (*.f64 (pow.f64 (/.f64 (*.f64 #s(literal 2 binary64) l) Om) #s(literal 2 binary64)) (+.f64 (pow.f64 (sin.f64 kx) #s(literal 2 binary64)) (pow.f64 (sin.f64 ky) #s(literal 2 binary64)))) < 2

      1. Initial program 100.0%

        \[\sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{\sqrt{1 + {\left(\frac{2 \cdot \ell}{Om}\right)}^{2} \cdot \left({\sin kx}^{2} + {\sin ky}^{2}\right)}}\right)} \]
      2. Add Preprocessing
      3. Applied rewrites0.4%

        \[\leadsto \sqrt{\color{blue}{\frac{0.25 \cdot \frac{1}{\mathsf{fma}\left(0.5 - \left(0.5 \cdot \cos \left(ky + ky\right) - \left(0.5 - 0.5 \cdot \cos \left(kx + kx\right)\right)\right), \frac{\left(\ell \cdot \ell\right) \cdot 4}{Om \cdot Om}, 1\right)} - 0.25}{\frac{0.5}{\sqrt{\mathsf{fma}\left(0.5 - \left(0.5 \cdot \cos \left(ky + ky\right) - \left(0.5 - 0.5 \cdot \cos \left(kx + kx\right)\right)\right), \frac{\left(\ell \cdot \ell\right) \cdot 4}{Om \cdot Om}, 1\right)}} - 0.5}}} \]
      4. Taylor expanded in Om around inf

        \[\leadsto \sqrt{\color{blue}{1}} \]
      5. Step-by-step derivation
        1. Applied rewrites98.6%

          \[\leadsto \sqrt{\color{blue}{1}} \]
        2. Taylor expanded in Om around inf

          \[\leadsto \color{blue}{1} \]
        3. Step-by-step derivation
          1. Applied rewrites98.6%

            \[\leadsto \color{blue}{1} \]

          if 2 < (*.f64 (pow.f64 (/.f64 (*.f64 #s(literal 2 binary64) l) Om) #s(literal 2 binary64)) (+.f64 (pow.f64 (sin.f64 kx) #s(literal 2 binary64)) (pow.f64 (sin.f64 ky) #s(literal 2 binary64))))

          1. Initial program 96.5%

            \[\sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{\sqrt{1 + {\left(\frac{2 \cdot \ell}{Om}\right)}^{2} \cdot \left({\sin kx}^{2} + {\sin ky}^{2}\right)}}\right)} \]
          2. Add Preprocessing
          3. Taylor expanded in kx around 0

            \[\leadsto \sqrt{\color{blue}{\frac{1}{2} \cdot \left(1 + \sqrt{\frac{1}{1 + 4 \cdot \frac{{\ell}^{2} \cdot {\sin ky}^{2}}{{Om}^{2}}}}\right)}} \]
          4. Step-by-step derivation
            1. +-commutativeN/A

              \[\leadsto \sqrt{\frac{1}{2} \cdot \color{blue}{\left(\sqrt{\frac{1}{1 + 4 \cdot \frac{{\ell}^{2} \cdot {\sin ky}^{2}}{{Om}^{2}}}} + 1\right)}} \]
            2. distribute-rgt-inN/A

              \[\leadsto \sqrt{\color{blue}{\sqrt{\frac{1}{1 + 4 \cdot \frac{{\ell}^{2} \cdot {\sin ky}^{2}}{{Om}^{2}}}} \cdot \frac{1}{2} + 1 \cdot \frac{1}{2}}} \]
            3. metadata-evalN/A

              \[\leadsto \sqrt{\sqrt{\frac{1}{1 + 4 \cdot \frac{{\ell}^{2} \cdot {\sin ky}^{2}}{{Om}^{2}}}} \cdot \frac{1}{2} + \color{blue}{\frac{1}{2}}} \]
            4. lower-fma.f64N/A

              \[\leadsto \sqrt{\color{blue}{\mathsf{fma}\left(\sqrt{\frac{1}{1 + 4 \cdot \frac{{\ell}^{2} \cdot {\sin ky}^{2}}{{Om}^{2}}}}, \frac{1}{2}, \frac{1}{2}\right)}} \]
          5. Applied rewrites67.5%

            \[\leadsto \sqrt{\color{blue}{\mathsf{fma}\left(\sqrt{\frac{1}{\mathsf{fma}\left(4 \cdot \left(\ell \cdot \ell\right), \frac{{\sin ky}^{2}}{Om \cdot Om}, 1\right)}}, 0.5, 0.5\right)}} \]
          6. Taylor expanded in l around -inf

            \[\leadsto \sqrt{\frac{1}{2} + \color{blue}{\frac{-1}{4} \cdot \frac{Om}{\ell \cdot \sin ky}}} \]
          7. Step-by-step derivation
            1. Applied rewrites86.1%

              \[\leadsto \sqrt{\mathsf{fma}\left(-0.25, \color{blue}{\frac{Om}{\ell \cdot \sin ky}}, 0.5\right)} \]
          8. Recombined 2 regimes into one program.
          9. Final simplification92.9%

            \[\leadsto \begin{array}{l} \mathbf{if}\;\left({\sin ky}^{2} + {\sin kx}^{2}\right) \cdot {\left(\frac{\ell \cdot 2}{Om}\right)}^{2} \leq 2:\\ \;\;\;\;1\\ \mathbf{else}:\\ \;\;\;\;\sqrt{\mathsf{fma}\left(-0.25, \frac{Om}{\sin ky \cdot \ell}, 0.5\right)}\\ \end{array} \]
          10. Add Preprocessing

          Alternative 3: 91.7% accurate, 1.0× speedup?

          \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;\left({\sin ky}^{2} + {\sin kx}^{2}\right) \cdot {\left(\frac{\ell \cdot 2}{Om}\right)}^{2} \leq 0.1:\\ \;\;\;\;1\\ \mathbf{else}:\\ \;\;\;\;\sqrt{\mathsf{fma}\left(\frac{Om}{\ell} \cdot 0.25, \frac{\sqrt{0.5}}{ky}, 0.5\right)}\\ \end{array} \end{array} \]
          (FPCore (l Om kx ky)
           :precision binary64
           (if (<=
                (* (+ (pow (sin ky) 2.0) (pow (sin kx) 2.0)) (pow (/ (* l 2.0) Om) 2.0))
                0.1)
             1.0
             (sqrt (fma (* (/ Om l) 0.25) (/ (sqrt 0.5) ky) 0.5))))
          double code(double l, double Om, double kx, double ky) {
          	double tmp;
          	if (((pow(sin(ky), 2.0) + pow(sin(kx), 2.0)) * pow(((l * 2.0) / Om), 2.0)) <= 0.1) {
          		tmp = 1.0;
          	} else {
          		tmp = sqrt(fma(((Om / l) * 0.25), (sqrt(0.5) / ky), 0.5));
          	}
          	return tmp;
          }
          
          function code(l, Om, kx, ky)
          	tmp = 0.0
          	if (Float64(Float64((sin(ky) ^ 2.0) + (sin(kx) ^ 2.0)) * (Float64(Float64(l * 2.0) / Om) ^ 2.0)) <= 0.1)
          		tmp = 1.0;
          	else
          		tmp = sqrt(fma(Float64(Float64(Om / l) * 0.25), Float64(sqrt(0.5) / ky), 0.5));
          	end
          	return tmp
          end
          
          code[l_, Om_, kx_, ky_] := If[LessEqual[N[(N[(N[Power[N[Sin[ky], $MachinePrecision], 2.0], $MachinePrecision] + N[Power[N[Sin[kx], $MachinePrecision], 2.0], $MachinePrecision]), $MachinePrecision] * N[Power[N[(N[(l * 2.0), $MachinePrecision] / Om), $MachinePrecision], 2.0], $MachinePrecision]), $MachinePrecision], 0.1], 1.0, N[Sqrt[N[(N[(N[(Om / l), $MachinePrecision] * 0.25), $MachinePrecision] * N[(N[Sqrt[0.5], $MachinePrecision] / ky), $MachinePrecision] + 0.5), $MachinePrecision]], $MachinePrecision]]
          
          \begin{array}{l}
          
          \\
          \begin{array}{l}
          \mathbf{if}\;\left({\sin ky}^{2} + {\sin kx}^{2}\right) \cdot {\left(\frac{\ell \cdot 2}{Om}\right)}^{2} \leq 0.1:\\
          \;\;\;\;1\\
          
          \mathbf{else}:\\
          \;\;\;\;\sqrt{\mathsf{fma}\left(\frac{Om}{\ell} \cdot 0.25, \frac{\sqrt{0.5}}{ky}, 0.5\right)}\\
          
          
          \end{array}
          \end{array}
          
          Derivation
          1. Split input into 2 regimes
          2. if (*.f64 (pow.f64 (/.f64 (*.f64 #s(literal 2 binary64) l) Om) #s(literal 2 binary64)) (+.f64 (pow.f64 (sin.f64 kx) #s(literal 2 binary64)) (pow.f64 (sin.f64 ky) #s(literal 2 binary64)))) < 0.10000000000000001

            1. Initial program 100.0%

              \[\sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{\sqrt{1 + {\left(\frac{2 \cdot \ell}{Om}\right)}^{2} \cdot \left({\sin kx}^{2} + {\sin ky}^{2}\right)}}\right)} \]
            2. Add Preprocessing
            3. Applied rewrites0.4%

              \[\leadsto \sqrt{\color{blue}{\frac{0.25 \cdot \frac{1}{\mathsf{fma}\left(0.5 - \left(0.5 \cdot \cos \left(ky + ky\right) - \left(0.5 - 0.5 \cdot \cos \left(kx + kx\right)\right)\right), \frac{\left(\ell \cdot \ell\right) \cdot 4}{Om \cdot Om}, 1\right)} - 0.25}{\frac{0.5}{\sqrt{\mathsf{fma}\left(0.5 - \left(0.5 \cdot \cos \left(ky + ky\right) - \left(0.5 - 0.5 \cdot \cos \left(kx + kx\right)\right)\right), \frac{\left(\ell \cdot \ell\right) \cdot 4}{Om \cdot Om}, 1\right)}} - 0.5}}} \]
            4. Taylor expanded in Om around inf

              \[\leadsto \sqrt{\color{blue}{1}} \]
            5. Step-by-step derivation
              1. Applied rewrites99.2%

                \[\leadsto \sqrt{\color{blue}{1}} \]
              2. Taylor expanded in Om around inf

                \[\leadsto \color{blue}{1} \]
              3. Step-by-step derivation
                1. Applied rewrites99.2%

                  \[\leadsto \color{blue}{1} \]

                if 0.10000000000000001 < (*.f64 (pow.f64 (/.f64 (*.f64 #s(literal 2 binary64) l) Om) #s(literal 2 binary64)) (+.f64 (pow.f64 (sin.f64 kx) #s(literal 2 binary64)) (pow.f64 (sin.f64 ky) #s(literal 2 binary64))))

                1. Initial program 96.6%

                  \[\sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{\sqrt{1 + {\left(\frac{2 \cdot \ell}{Om}\right)}^{2} \cdot \left({\sin kx}^{2} + {\sin ky}^{2}\right)}}\right)} \]
                2. Add Preprocessing
                3. Applied rewrites72.9%

                  \[\leadsto \sqrt{\color{blue}{\frac{0.25 \cdot \frac{1}{\mathsf{fma}\left(0.5 - \left(0.5 \cdot \cos \left(ky + ky\right) - \left(0.5 - 0.5 \cdot \cos \left(kx + kx\right)\right)\right), \frac{\left(\ell \cdot \ell\right) \cdot 4}{Om \cdot Om}, 1\right)} - 0.25}{\frac{0.5}{\sqrt{\mathsf{fma}\left(0.5 - \left(0.5 \cdot \cos \left(ky + ky\right) - \left(0.5 - 0.5 \cdot \cos \left(kx + kx\right)\right)\right), \frac{\left(\ell \cdot \ell\right) \cdot 4}{Om \cdot Om}, 1\right)}} - 0.5}}} \]
                4. Taylor expanded in Om around 0

                  \[\leadsto \sqrt{\color{blue}{\frac{1}{2} + \frac{1}{4} \cdot \left(\frac{Om}{\ell} \cdot \sqrt{\frac{1}{1 - \left(\frac{1}{2} \cdot \cos \left(2 \cdot kx\right) + \frac{1}{2} \cdot \cos \left(2 \cdot ky\right)\right)}}\right)}} \]
                5. Step-by-step derivation
                  1. +-commutativeN/A

                    \[\leadsto \sqrt{\color{blue}{\frac{1}{4} \cdot \left(\frac{Om}{\ell} \cdot \sqrt{\frac{1}{1 - \left(\frac{1}{2} \cdot \cos \left(2 \cdot kx\right) + \frac{1}{2} \cdot \cos \left(2 \cdot ky\right)\right)}}\right) + \frac{1}{2}}} \]
                  2. associate-*r*N/A

                    \[\leadsto \sqrt{\color{blue}{\left(\frac{1}{4} \cdot \frac{Om}{\ell}\right) \cdot \sqrt{\frac{1}{1 - \left(\frac{1}{2} \cdot \cos \left(2 \cdot kx\right) + \frac{1}{2} \cdot \cos \left(2 \cdot ky\right)\right)}}} + \frac{1}{2}} \]
                  3. lower-fma.f64N/A

                    \[\leadsto \sqrt{\color{blue}{\mathsf{fma}\left(\frac{1}{4} \cdot \frac{Om}{\ell}, \sqrt{\frac{1}{1 - \left(\frac{1}{2} \cdot \cos \left(2 \cdot kx\right) + \frac{1}{2} \cdot \cos \left(2 \cdot ky\right)\right)}}, \frac{1}{2}\right)}} \]
                6. Applied rewrites82.7%

                  \[\leadsto \sqrt{\color{blue}{\mathsf{fma}\left(0.25 \cdot \frac{Om}{\ell}, \sqrt{\frac{1}{1 - 0.5 \cdot \left(\cos \left(2 \cdot kx\right) + \cos \left(2 \cdot ky\right)\right)}}, 0.5\right)}} \]
                7. Step-by-step derivation
                  1. Applied rewrites62.2%

                    \[\leadsto \sqrt{\mathsf{fma}\left(0.25 \cdot \frac{Om}{\ell}, \sqrt{\frac{1}{1 - 0.5 \cdot \left(\cos \left(ky + ky\right) + \cos \left(ky + ky\right)\right)}}, 0.5\right)} \]
                  2. Taylor expanded in ky around 0

                    \[\leadsto \sqrt{\mathsf{fma}\left(\frac{1}{4} \cdot \frac{Om}{\ell}, \frac{\sqrt{\frac{1}{2}}}{\color{blue}{ky}}, \frac{1}{2}\right)} \]
                  3. Step-by-step derivation
                    1. Applied rewrites85.4%

                      \[\leadsto \sqrt{\mathsf{fma}\left(0.25 \cdot \frac{Om}{\ell}, \frac{\sqrt{0.5}}{\color{blue}{ky}}, 0.5\right)} \]
                  4. Recombined 2 regimes into one program.
                  5. Final simplification92.8%

                    \[\leadsto \begin{array}{l} \mathbf{if}\;\left({\sin ky}^{2} + {\sin kx}^{2}\right) \cdot {\left(\frac{\ell \cdot 2}{Om}\right)}^{2} \leq 0.1:\\ \;\;\;\;1\\ \mathbf{else}:\\ \;\;\;\;\sqrt{\mathsf{fma}\left(\frac{Om}{\ell} \cdot 0.25, \frac{\sqrt{0.5}}{ky}, 0.5\right)}\\ \end{array} \]
                  6. Add Preprocessing

                  Alternative 4: 98.5% accurate, 1.0× speedup?

                  \[\begin{array}{l} \\ \sqrt{\left(\frac{1}{\sqrt{\left({\sin ky}^{2} + {\sin kx}^{2}\right) \cdot {\left(\frac{\ell \cdot 2}{Om}\right)}^{2} + 1}} + 1\right) \cdot \frac{1}{2}} \end{array} \]
                  (FPCore (l Om kx ky)
                   :precision binary64
                   (sqrt
                    (*
                     (+
                      (/
                       1.0
                       (sqrt
                        (+
                         (* (+ (pow (sin ky) 2.0) (pow (sin kx) 2.0)) (pow (/ (* l 2.0) Om) 2.0))
                         1.0)))
                      1.0)
                     (/ 1.0 2.0))))
                  double code(double l, double Om, double kx, double ky) {
                  	return sqrt((((1.0 / sqrt((((pow(sin(ky), 2.0) + pow(sin(kx), 2.0)) * pow(((l * 2.0) / Om), 2.0)) + 1.0))) + 1.0) * (1.0 / 2.0)));
                  }
                  
                  real(8) function code(l, om, kx, ky)
                      real(8), intent (in) :: l
                      real(8), intent (in) :: om
                      real(8), intent (in) :: kx
                      real(8), intent (in) :: ky
                      code = sqrt((((1.0d0 / sqrt(((((sin(ky) ** 2.0d0) + (sin(kx) ** 2.0d0)) * (((l * 2.0d0) / om) ** 2.0d0)) + 1.0d0))) + 1.0d0) * (1.0d0 / 2.0d0)))
                  end function
                  
                  public static double code(double l, double Om, double kx, double ky) {
                  	return Math.sqrt((((1.0 / Math.sqrt((((Math.pow(Math.sin(ky), 2.0) + Math.pow(Math.sin(kx), 2.0)) * Math.pow(((l * 2.0) / Om), 2.0)) + 1.0))) + 1.0) * (1.0 / 2.0)));
                  }
                  
                  def code(l, Om, kx, ky):
                  	return math.sqrt((((1.0 / math.sqrt((((math.pow(math.sin(ky), 2.0) + math.pow(math.sin(kx), 2.0)) * math.pow(((l * 2.0) / Om), 2.0)) + 1.0))) + 1.0) * (1.0 / 2.0)))
                  
                  function code(l, Om, kx, ky)
                  	return sqrt(Float64(Float64(Float64(1.0 / sqrt(Float64(Float64(Float64((sin(ky) ^ 2.0) + (sin(kx) ^ 2.0)) * (Float64(Float64(l * 2.0) / Om) ^ 2.0)) + 1.0))) + 1.0) * Float64(1.0 / 2.0)))
                  end
                  
                  function tmp = code(l, Om, kx, ky)
                  	tmp = sqrt((((1.0 / sqrt(((((sin(ky) ^ 2.0) + (sin(kx) ^ 2.0)) * (((l * 2.0) / Om) ^ 2.0)) + 1.0))) + 1.0) * (1.0 / 2.0)));
                  end
                  
                  code[l_, Om_, kx_, ky_] := N[Sqrt[N[(N[(N[(1.0 / N[Sqrt[N[(N[(N[(N[Power[N[Sin[ky], $MachinePrecision], 2.0], $MachinePrecision] + N[Power[N[Sin[kx], $MachinePrecision], 2.0], $MachinePrecision]), $MachinePrecision] * N[Power[N[(N[(l * 2.0), $MachinePrecision] / Om), $MachinePrecision], 2.0], $MachinePrecision]), $MachinePrecision] + 1.0), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] + 1.0), $MachinePrecision] * N[(1.0 / 2.0), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]
                  
                  \begin{array}{l}
                  
                  \\
                  \sqrt{\left(\frac{1}{\sqrt{\left({\sin ky}^{2} + {\sin kx}^{2}\right) \cdot {\left(\frac{\ell \cdot 2}{Om}\right)}^{2} + 1}} + 1\right) \cdot \frac{1}{2}}
                  \end{array}
                  
                  Derivation
                  1. Initial program 98.4%

                    \[\sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{\sqrt{1 + {\left(\frac{2 \cdot \ell}{Om}\right)}^{2} \cdot \left({\sin kx}^{2} + {\sin ky}^{2}\right)}}\right)} \]
                  2. Add Preprocessing
                  3. Final simplification98.4%

                    \[\leadsto \sqrt{\left(\frac{1}{\sqrt{\left({\sin ky}^{2} + {\sin kx}^{2}\right) \cdot {\left(\frac{\ell \cdot 2}{Om}\right)}^{2} + 1}} + 1\right) \cdot \frac{1}{2}} \]
                  4. Add Preprocessing

                  Alternative 5: 91.7% accurate, 1.0× speedup?

                  \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;\left({\sin ky}^{2} + {\sin kx}^{2}\right) \cdot {\left(\frac{\ell \cdot 2}{Om}\right)}^{2} \leq 0.1:\\ \;\;\;\;1\\ \mathbf{else}:\\ \;\;\;\;\sqrt{\mathsf{fma}\left(0.25, \frac{Om}{ky \cdot \ell}, 0.5\right)}\\ \end{array} \end{array} \]
                  (FPCore (l Om kx ky)
                   :precision binary64
                   (if (<=
                        (* (+ (pow (sin ky) 2.0) (pow (sin kx) 2.0)) (pow (/ (* l 2.0) Om) 2.0))
                        0.1)
                     1.0
                     (sqrt (fma 0.25 (/ Om (* ky l)) 0.5))))
                  double code(double l, double Om, double kx, double ky) {
                  	double tmp;
                  	if (((pow(sin(ky), 2.0) + pow(sin(kx), 2.0)) * pow(((l * 2.0) / Om), 2.0)) <= 0.1) {
                  		tmp = 1.0;
                  	} else {
                  		tmp = sqrt(fma(0.25, (Om / (ky * l)), 0.5));
                  	}
                  	return tmp;
                  }
                  
                  function code(l, Om, kx, ky)
                  	tmp = 0.0
                  	if (Float64(Float64((sin(ky) ^ 2.0) + (sin(kx) ^ 2.0)) * (Float64(Float64(l * 2.0) / Om) ^ 2.0)) <= 0.1)
                  		tmp = 1.0;
                  	else
                  		tmp = sqrt(fma(0.25, Float64(Om / Float64(ky * l)), 0.5));
                  	end
                  	return tmp
                  end
                  
                  code[l_, Om_, kx_, ky_] := If[LessEqual[N[(N[(N[Power[N[Sin[ky], $MachinePrecision], 2.0], $MachinePrecision] + N[Power[N[Sin[kx], $MachinePrecision], 2.0], $MachinePrecision]), $MachinePrecision] * N[Power[N[(N[(l * 2.0), $MachinePrecision] / Om), $MachinePrecision], 2.0], $MachinePrecision]), $MachinePrecision], 0.1], 1.0, N[Sqrt[N[(0.25 * N[(Om / N[(ky * l), $MachinePrecision]), $MachinePrecision] + 0.5), $MachinePrecision]], $MachinePrecision]]
                  
                  \begin{array}{l}
                  
                  \\
                  \begin{array}{l}
                  \mathbf{if}\;\left({\sin ky}^{2} + {\sin kx}^{2}\right) \cdot {\left(\frac{\ell \cdot 2}{Om}\right)}^{2} \leq 0.1:\\
                  \;\;\;\;1\\
                  
                  \mathbf{else}:\\
                  \;\;\;\;\sqrt{\mathsf{fma}\left(0.25, \frac{Om}{ky \cdot \ell}, 0.5\right)}\\
                  
                  
                  \end{array}
                  \end{array}
                  
                  Derivation
                  1. Split input into 2 regimes
                  2. if (*.f64 (pow.f64 (/.f64 (*.f64 #s(literal 2 binary64) l) Om) #s(literal 2 binary64)) (+.f64 (pow.f64 (sin.f64 kx) #s(literal 2 binary64)) (pow.f64 (sin.f64 ky) #s(literal 2 binary64)))) < 0.10000000000000001

                    1. Initial program 100.0%

                      \[\sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{\sqrt{1 + {\left(\frac{2 \cdot \ell}{Om}\right)}^{2} \cdot \left({\sin kx}^{2} + {\sin ky}^{2}\right)}}\right)} \]
                    2. Add Preprocessing
                    3. Applied rewrites0.4%

                      \[\leadsto \sqrt{\color{blue}{\frac{0.25 \cdot \frac{1}{\mathsf{fma}\left(0.5 - \left(0.5 \cdot \cos \left(ky + ky\right) - \left(0.5 - 0.5 \cdot \cos \left(kx + kx\right)\right)\right), \frac{\left(\ell \cdot \ell\right) \cdot 4}{Om \cdot Om}, 1\right)} - 0.25}{\frac{0.5}{\sqrt{\mathsf{fma}\left(0.5 - \left(0.5 \cdot \cos \left(ky + ky\right) - \left(0.5 - 0.5 \cdot \cos \left(kx + kx\right)\right)\right), \frac{\left(\ell \cdot \ell\right) \cdot 4}{Om \cdot Om}, 1\right)}} - 0.5}}} \]
                    4. Taylor expanded in Om around inf

                      \[\leadsto \sqrt{\color{blue}{1}} \]
                    5. Step-by-step derivation
                      1. Applied rewrites99.2%

                        \[\leadsto \sqrt{\color{blue}{1}} \]
                      2. Taylor expanded in Om around inf

                        \[\leadsto \color{blue}{1} \]
                      3. Step-by-step derivation
                        1. Applied rewrites99.2%

                          \[\leadsto \color{blue}{1} \]

                        if 0.10000000000000001 < (*.f64 (pow.f64 (/.f64 (*.f64 #s(literal 2 binary64) l) Om) #s(literal 2 binary64)) (+.f64 (pow.f64 (sin.f64 kx) #s(literal 2 binary64)) (pow.f64 (sin.f64 ky) #s(literal 2 binary64))))

                        1. Initial program 96.6%

                          \[\sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{\sqrt{1 + {\left(\frac{2 \cdot \ell}{Om}\right)}^{2} \cdot \left({\sin kx}^{2} + {\sin ky}^{2}\right)}}\right)} \]
                        2. Add Preprocessing
                        3. Taylor expanded in kx around 0

                          \[\leadsto \sqrt{\color{blue}{\frac{1}{2} \cdot \left(1 + \sqrt{\frac{1}{1 + 4 \cdot \frac{{\ell}^{2} \cdot {\sin ky}^{2}}{{Om}^{2}}}}\right)}} \]
                        4. Step-by-step derivation
                          1. +-commutativeN/A

                            \[\leadsto \sqrt{\frac{1}{2} \cdot \color{blue}{\left(\sqrt{\frac{1}{1 + 4 \cdot \frac{{\ell}^{2} \cdot {\sin ky}^{2}}{{Om}^{2}}}} + 1\right)}} \]
                          2. distribute-rgt-inN/A

                            \[\leadsto \sqrt{\color{blue}{\sqrt{\frac{1}{1 + 4 \cdot \frac{{\ell}^{2} \cdot {\sin ky}^{2}}{{Om}^{2}}}} \cdot \frac{1}{2} + 1 \cdot \frac{1}{2}}} \]
                          3. metadata-evalN/A

                            \[\leadsto \sqrt{\sqrt{\frac{1}{1 + 4 \cdot \frac{{\ell}^{2} \cdot {\sin ky}^{2}}{{Om}^{2}}}} \cdot \frac{1}{2} + \color{blue}{\frac{1}{2}}} \]
                          4. lower-fma.f64N/A

                            \[\leadsto \sqrt{\color{blue}{\mathsf{fma}\left(\sqrt{\frac{1}{1 + 4 \cdot \frac{{\ell}^{2} \cdot {\sin ky}^{2}}{{Om}^{2}}}}, \frac{1}{2}, \frac{1}{2}\right)}} \]
                        5. Applied rewrites66.9%

                          \[\leadsto \sqrt{\color{blue}{\mathsf{fma}\left(\sqrt{\frac{1}{\mathsf{fma}\left(4 \cdot \left(\ell \cdot \ell\right), \frac{{\sin ky}^{2}}{Om \cdot Om}, 1\right)}}, 0.5, 0.5\right)}} \]
                        6. Taylor expanded in Om around 0

                          \[\leadsto \sqrt{\frac{1}{2} + \color{blue}{\frac{1}{4} \cdot \frac{Om}{\ell \cdot \sin ky}}} \]
                        7. Step-by-step derivation
                          1. Applied rewrites85.2%

                            \[\leadsto \sqrt{\mathsf{fma}\left(0.25, \color{blue}{\frac{Om}{\ell \cdot \sin ky}}, 0.5\right)} \]
                          2. Taylor expanded in ky around 0

                            \[\leadsto \sqrt{\mathsf{fma}\left(\frac{1}{4}, \frac{Om}{ky \cdot \ell}, \frac{1}{2}\right)} \]
                          3. Step-by-step derivation
                            1. Applied rewrites85.3%

                              \[\leadsto \sqrt{\mathsf{fma}\left(0.25, \frac{Om}{\ell \cdot ky}, 0.5\right)} \]
                          4. Recombined 2 regimes into one program.
                          5. Final simplification92.8%

                            \[\leadsto \begin{array}{l} \mathbf{if}\;\left({\sin ky}^{2} + {\sin kx}^{2}\right) \cdot {\left(\frac{\ell \cdot 2}{Om}\right)}^{2} \leq 0.1:\\ \;\;\;\;1\\ \mathbf{else}:\\ \;\;\;\;\sqrt{\mathsf{fma}\left(0.25, \frac{Om}{ky \cdot \ell}, 0.5\right)}\\ \end{array} \]
                          6. Add Preprocessing

                          Alternative 6: 98.4% accurate, 1.1× speedup?

                          \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;\left({\sin ky}^{2} + {\sin kx}^{2}\right) \cdot {\left(\frac{\ell \cdot 2}{Om}\right)}^{2} \leq 3.8:\\ \;\;\;\;1\\ \mathbf{else}:\\ \;\;\;\;\sqrt{0.5}\\ \end{array} \end{array} \]
                          (FPCore (l Om kx ky)
                           :precision binary64
                           (if (<=
                                (* (+ (pow (sin ky) 2.0) (pow (sin kx) 2.0)) (pow (/ (* l 2.0) Om) 2.0))
                                3.8)
                             1.0
                             (sqrt 0.5)))
                          double code(double l, double Om, double kx, double ky) {
                          	double tmp;
                          	if (((pow(sin(ky), 2.0) + pow(sin(kx), 2.0)) * pow(((l * 2.0) / Om), 2.0)) <= 3.8) {
                          		tmp = 1.0;
                          	} else {
                          		tmp = sqrt(0.5);
                          	}
                          	return tmp;
                          }
                          
                          real(8) function code(l, om, kx, ky)
                              real(8), intent (in) :: l
                              real(8), intent (in) :: om
                              real(8), intent (in) :: kx
                              real(8), intent (in) :: ky
                              real(8) :: tmp
                              if ((((sin(ky) ** 2.0d0) + (sin(kx) ** 2.0d0)) * (((l * 2.0d0) / om) ** 2.0d0)) <= 3.8d0) then
                                  tmp = 1.0d0
                              else
                                  tmp = sqrt(0.5d0)
                              end if
                              code = tmp
                          end function
                          
                          public static double code(double l, double Om, double kx, double ky) {
                          	double tmp;
                          	if (((Math.pow(Math.sin(ky), 2.0) + Math.pow(Math.sin(kx), 2.0)) * Math.pow(((l * 2.0) / Om), 2.0)) <= 3.8) {
                          		tmp = 1.0;
                          	} else {
                          		tmp = Math.sqrt(0.5);
                          	}
                          	return tmp;
                          }
                          
                          def code(l, Om, kx, ky):
                          	tmp = 0
                          	if ((math.pow(math.sin(ky), 2.0) + math.pow(math.sin(kx), 2.0)) * math.pow(((l * 2.0) / Om), 2.0)) <= 3.8:
                          		tmp = 1.0
                          	else:
                          		tmp = math.sqrt(0.5)
                          	return tmp
                          
                          function code(l, Om, kx, ky)
                          	tmp = 0.0
                          	if (Float64(Float64((sin(ky) ^ 2.0) + (sin(kx) ^ 2.0)) * (Float64(Float64(l * 2.0) / Om) ^ 2.0)) <= 3.8)
                          		tmp = 1.0;
                          	else
                          		tmp = sqrt(0.5);
                          	end
                          	return tmp
                          end
                          
                          function tmp_2 = code(l, Om, kx, ky)
                          	tmp = 0.0;
                          	if ((((sin(ky) ^ 2.0) + (sin(kx) ^ 2.0)) * (((l * 2.0) / Om) ^ 2.0)) <= 3.8)
                          		tmp = 1.0;
                          	else
                          		tmp = sqrt(0.5);
                          	end
                          	tmp_2 = tmp;
                          end
                          
                          code[l_, Om_, kx_, ky_] := If[LessEqual[N[(N[(N[Power[N[Sin[ky], $MachinePrecision], 2.0], $MachinePrecision] + N[Power[N[Sin[kx], $MachinePrecision], 2.0], $MachinePrecision]), $MachinePrecision] * N[Power[N[(N[(l * 2.0), $MachinePrecision] / Om), $MachinePrecision], 2.0], $MachinePrecision]), $MachinePrecision], 3.8], 1.0, N[Sqrt[0.5], $MachinePrecision]]
                          
                          \begin{array}{l}
                          
                          \\
                          \begin{array}{l}
                          \mathbf{if}\;\left({\sin ky}^{2} + {\sin kx}^{2}\right) \cdot {\left(\frac{\ell \cdot 2}{Om}\right)}^{2} \leq 3.8:\\
                          \;\;\;\;1\\
                          
                          \mathbf{else}:\\
                          \;\;\;\;\sqrt{0.5}\\
                          
                          
                          \end{array}
                          \end{array}
                          
                          Derivation
                          1. Split input into 2 regimes
                          2. if (*.f64 (pow.f64 (/.f64 (*.f64 #s(literal 2 binary64) l) Om) #s(literal 2 binary64)) (+.f64 (pow.f64 (sin.f64 kx) #s(literal 2 binary64)) (pow.f64 (sin.f64 ky) #s(literal 2 binary64)))) < 3.7999999999999998

                            1. Initial program 100.0%

                              \[\sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{\sqrt{1 + {\left(\frac{2 \cdot \ell}{Om}\right)}^{2} \cdot \left({\sin kx}^{2} + {\sin ky}^{2}\right)}}\right)} \]
                            2. Add Preprocessing
                            3. Applied rewrites0.4%

                              \[\leadsto \sqrt{\color{blue}{\frac{0.25 \cdot \frac{1}{\mathsf{fma}\left(0.5 - \left(0.5 \cdot \cos \left(ky + ky\right) - \left(0.5 - 0.5 \cdot \cos \left(kx + kx\right)\right)\right), \frac{\left(\ell \cdot \ell\right) \cdot 4}{Om \cdot Om}, 1\right)} - 0.25}{\frac{0.5}{\sqrt{\mathsf{fma}\left(0.5 - \left(0.5 \cdot \cos \left(ky + ky\right) - \left(0.5 - 0.5 \cdot \cos \left(kx + kx\right)\right)\right), \frac{\left(\ell \cdot \ell\right) \cdot 4}{Om \cdot Om}, 1\right)}} - 0.5}}} \]
                            4. Taylor expanded in Om around inf

                              \[\leadsto \sqrt{\color{blue}{1}} \]
                            5. Step-by-step derivation
                              1. Applied rewrites98.6%

                                \[\leadsto \sqrt{\color{blue}{1}} \]
                              2. Taylor expanded in Om around inf

                                \[\leadsto \color{blue}{1} \]
                              3. Step-by-step derivation
                                1. Applied rewrites98.6%

                                  \[\leadsto \color{blue}{1} \]

                                if 3.7999999999999998 < (*.f64 (pow.f64 (/.f64 (*.f64 #s(literal 2 binary64) l) Om) #s(literal 2 binary64)) (+.f64 (pow.f64 (sin.f64 kx) #s(literal 2 binary64)) (pow.f64 (sin.f64 ky) #s(literal 2 binary64))))

                                1. Initial program 96.5%

                                  \[\sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{\sqrt{1 + {\left(\frac{2 \cdot \ell}{Om}\right)}^{2} \cdot \left({\sin kx}^{2} + {\sin ky}^{2}\right)}}\right)} \]
                                2. Add Preprocessing
                                3. Taylor expanded in Om around 0

                                  \[\leadsto \sqrt{\color{blue}{\frac{1}{2}}} \]
                                4. Step-by-step derivation
                                  1. Applied rewrites97.3%

                                    \[\leadsto \sqrt{\color{blue}{0.5}} \]
                                5. Recombined 2 regimes into one program.
                                6. Final simplification98.0%

                                  \[\leadsto \begin{array}{l} \mathbf{if}\;\left({\sin ky}^{2} + {\sin kx}^{2}\right) \cdot {\left(\frac{\ell \cdot 2}{Om}\right)}^{2} \leq 3.8:\\ \;\;\;\;1\\ \mathbf{else}:\\ \;\;\;\;\sqrt{0.5}\\ \end{array} \]
                                7. Add Preprocessing

                                Alternative 7: 62.4% accurate, 581.0× speedup?

                                \[\begin{array}{l} \\ 1 \end{array} \]
                                (FPCore (l Om kx ky) :precision binary64 1.0)
                                double code(double l, double Om, double kx, double ky) {
                                	return 1.0;
                                }
                                
                                real(8) function code(l, om, kx, ky)
                                    real(8), intent (in) :: l
                                    real(8), intent (in) :: om
                                    real(8), intent (in) :: kx
                                    real(8), intent (in) :: ky
                                    code = 1.0d0
                                end function
                                
                                public static double code(double l, double Om, double kx, double ky) {
                                	return 1.0;
                                }
                                
                                def code(l, Om, kx, ky):
                                	return 1.0
                                
                                function code(l, Om, kx, ky)
                                	return 1.0
                                end
                                
                                function tmp = code(l, Om, kx, ky)
                                	tmp = 1.0;
                                end
                                
                                code[l_, Om_, kx_, ky_] := 1.0
                                
                                \begin{array}{l}
                                
                                \\
                                1
                                \end{array}
                                
                                Derivation
                                1. Initial program 98.4%

                                  \[\sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{\sqrt{1 + {\left(\frac{2 \cdot \ell}{Om}\right)}^{2} \cdot \left({\sin kx}^{2} + {\sin ky}^{2}\right)}}\right)} \]
                                2. Add Preprocessing
                                3. Applied rewrites33.8%

                                  \[\leadsto \sqrt{\color{blue}{\frac{0.25 \cdot \frac{1}{\mathsf{fma}\left(0.5 - \left(0.5 \cdot \cos \left(ky + ky\right) - \left(0.5 - 0.5 \cdot \cos \left(kx + kx\right)\right)\right), \frac{\left(\ell \cdot \ell\right) \cdot 4}{Om \cdot Om}, 1\right)} - 0.25}{\frac{0.5}{\sqrt{\mathsf{fma}\left(0.5 - \left(0.5 \cdot \cos \left(ky + ky\right) - \left(0.5 - 0.5 \cdot \cos \left(kx + kx\right)\right)\right), \frac{\left(\ell \cdot \ell\right) \cdot 4}{Om \cdot Om}, 1\right)}} - 0.5}}} \]
                                4. Taylor expanded in Om around inf

                                  \[\leadsto \sqrt{\color{blue}{1}} \]
                                5. Step-by-step derivation
                                  1. Applied rewrites62.7%

                                    \[\leadsto \sqrt{\color{blue}{1}} \]
                                  2. Taylor expanded in Om around inf

                                    \[\leadsto \color{blue}{1} \]
                                  3. Step-by-step derivation
                                    1. Applied rewrites62.7%

                                      \[\leadsto \color{blue}{1} \]
                                    2. Add Preprocessing

                                    Reproduce

                                    ?
                                    herbie shell --seed 2024240 
                                    (FPCore (l Om kx ky)
                                      :name "Toniolo and Linder, Equation (3a)"
                                      :precision binary64
                                      (sqrt (* (/ 1.0 2.0) (+ 1.0 (/ 1.0 (sqrt (+ 1.0 (* (pow (/ (* 2.0 l) Om) 2.0) (+ (pow (sin kx) 2.0) (pow (sin ky) 2.0))))))))))