Data.Array.Repa.Algorithms.Pixel:doubleRmsOfRGB8 from repa-algorithms-3.4.0.1

Percentage Accurate: 45.5% → 98.8%
Time: 12.3s
Alternatives: 3
Speedup: 2.7×

Specification

?
\[\begin{array}{l} \\ \sqrt{\frac{\left(x \cdot x + y \cdot y\right) + z \cdot z}{3}} \end{array} \]
(FPCore (x y z)
 :precision binary64
 (sqrt (/ (+ (+ (* x x) (* y y)) (* z z)) 3.0)))
double code(double x, double y, double z) {
	return sqrt(((((x * x) + (y * y)) + (z * z)) / 3.0));
}
real(8) function code(x, y, z)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    real(8), intent (in) :: z
    code = sqrt(((((x * x) + (y * y)) + (z * z)) / 3.0d0))
end function
public static double code(double x, double y, double z) {
	return Math.sqrt(((((x * x) + (y * y)) + (z * z)) / 3.0));
}
def code(x, y, z):
	return math.sqrt(((((x * x) + (y * y)) + (z * z)) / 3.0))
function code(x, y, z)
	return sqrt(Float64(Float64(Float64(Float64(x * x) + Float64(y * y)) + Float64(z * z)) / 3.0))
end
function tmp = code(x, y, z)
	tmp = sqrt(((((x * x) + (y * y)) + (z * z)) / 3.0));
end
code[x_, y_, z_] := N[Sqrt[N[(N[(N[(N[(x * x), $MachinePrecision] + N[(y * y), $MachinePrecision]), $MachinePrecision] + N[(z * z), $MachinePrecision]), $MachinePrecision] / 3.0), $MachinePrecision]], $MachinePrecision]
\begin{array}{l}

\\
\sqrt{\frac{\left(x \cdot x + y \cdot y\right) + z \cdot z}{3}}
\end{array}

Sampling outcomes in binary64 precision:

Local Percentage Accuracy vs ?

The average percentage accuracy by input value. Horizontal axis shows value of an input variable; the variable is choosen in the title. Vertical axis is accuracy; higher is better. Red represent the original program, while blue represents Herbie's suggestion. These can be toggled with buttons below the plot. The line is an average while dots represent individual samples.

Accuracy vs Speed?

Herbie found 3 alternatives:

AlternativeAccuracySpeedup
The accuracy (vertical axis) and speed (horizontal axis) of each alternatives. Up and to the right is better. The red square shows the initial program, and each blue circle shows an alternative.The line shows the best available speed-accuracy tradeoffs.

Initial Program: 45.5% accurate, 1.0× speedup?

\[\begin{array}{l} \\ \sqrt{\frac{\left(x \cdot x + y \cdot y\right) + z \cdot z}{3}} \end{array} \]
(FPCore (x y z)
 :precision binary64
 (sqrt (/ (+ (+ (* x x) (* y y)) (* z z)) 3.0)))
double code(double x, double y, double z) {
	return sqrt(((((x * x) + (y * y)) + (z * z)) / 3.0));
}
real(8) function code(x, y, z)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    real(8), intent (in) :: z
    code = sqrt(((((x * x) + (y * y)) + (z * z)) / 3.0d0))
end function
public static double code(double x, double y, double z) {
	return Math.sqrt(((((x * x) + (y * y)) + (z * z)) / 3.0));
}
def code(x, y, z):
	return math.sqrt(((((x * x) + (y * y)) + (z * z)) / 3.0))
function code(x, y, z)
	return sqrt(Float64(Float64(Float64(Float64(x * x) + Float64(y * y)) + Float64(z * z)) / 3.0))
end
function tmp = code(x, y, z)
	tmp = sqrt(((((x * x) + (y * y)) + (z * z)) / 3.0));
end
code[x_, y_, z_] := N[Sqrt[N[(N[(N[(N[(x * x), $MachinePrecision] + N[(y * y), $MachinePrecision]), $MachinePrecision] + N[(z * z), $MachinePrecision]), $MachinePrecision] / 3.0), $MachinePrecision]], $MachinePrecision]
\begin{array}{l}

\\
\sqrt{\frac{\left(x \cdot x + y \cdot y\right) + z \cdot z}{3}}
\end{array}

Alternative 1: 98.8% accurate, 0.2× speedup?

\[\begin{array}{l} z_m = \left|z\right| \\ y_m = \left|y\right| \\ x_m = \left|x\right| \\ [x_m, y_m, z_m] = \mathsf{sort}([x_m, y_m, z_m])\\ \\ \mathsf{fma}\left(y\_m, y\_m \cdot e^{-\log \left(\frac{z\_m}{\sqrt{0.3333333333333333} \cdot 0.5}\right)}, z\_m \cdot \sqrt{0.3333333333333333}\right) \end{array} \]
z_m = (fabs.f64 z)
y_m = (fabs.f64 y)
x_m = (fabs.f64 x)
NOTE: x_m, y_m, and z_m should be sorted in increasing order before calling this function.
(FPCore (x_m y_m z_m)
 :precision binary64
 (fma
  y_m
  (* y_m (exp (- (log (/ z_m (* (sqrt 0.3333333333333333) 0.5))))))
  (* z_m (sqrt 0.3333333333333333))))
z_m = fabs(z);
y_m = fabs(y);
x_m = fabs(x);
assert(x_m < y_m && y_m < z_m);
double code(double x_m, double y_m, double z_m) {
	return fma(y_m, (y_m * exp(-log((z_m / (sqrt(0.3333333333333333) * 0.5))))), (z_m * sqrt(0.3333333333333333)));
}
z_m = abs(z)
y_m = abs(y)
x_m = abs(x)
x_m, y_m, z_m = sort([x_m, y_m, z_m])
function code(x_m, y_m, z_m)
	return fma(y_m, Float64(y_m * exp(Float64(-log(Float64(z_m / Float64(sqrt(0.3333333333333333) * 0.5)))))), Float64(z_m * sqrt(0.3333333333333333)))
end
z_m = N[Abs[z], $MachinePrecision]
y_m = N[Abs[y], $MachinePrecision]
x_m = N[Abs[x], $MachinePrecision]
NOTE: x_m, y_m, and z_m should be sorted in increasing order before calling this function.
code[x$95$m_, y$95$m_, z$95$m_] := N[(y$95$m * N[(y$95$m * N[Exp[(-N[Log[N[(z$95$m / N[(N[Sqrt[0.3333333333333333], $MachinePrecision] * 0.5), $MachinePrecision]), $MachinePrecision]], $MachinePrecision])], $MachinePrecision]), $MachinePrecision] + N[(z$95$m * N[Sqrt[0.3333333333333333], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
\begin{array}{l}
z_m = \left|z\right|
\\
y_m = \left|y\right|
\\
x_m = \left|x\right|
\\
[x_m, y_m, z_m] = \mathsf{sort}([x_m, y_m, z_m])\\
\\
\mathsf{fma}\left(y\_m, y\_m \cdot e^{-\log \left(\frac{z\_m}{\sqrt{0.3333333333333333} \cdot 0.5}\right)}, z\_m \cdot \sqrt{0.3333333333333333}\right)
\end{array}
Derivation
  1. Initial program 45.9%

    \[\sqrt{\frac{\left(x \cdot x + y \cdot y\right) + z \cdot z}{3}} \]
  2. Add Preprocessing
  3. Taylor expanded in z around inf

    \[\leadsto \color{blue}{z \cdot \left(\sqrt{\frac{1}{3}} + \frac{1}{2} \cdot \frac{\sqrt{\frac{1}{3}} \cdot \left({x}^{2} + {y}^{2}\right)}{{z}^{2}}\right)} \]
  4. Step-by-step derivation
    1. distribute-rgt-inN/A

      \[\leadsto \color{blue}{\sqrt{\frac{1}{3}} \cdot z + \left(\frac{1}{2} \cdot \frac{\sqrt{\frac{1}{3}} \cdot \left({x}^{2} + {y}^{2}\right)}{{z}^{2}}\right) \cdot z} \]
    2. *-commutativeN/A

      \[\leadsto \color{blue}{z \cdot \sqrt{\frac{1}{3}}} + \left(\frac{1}{2} \cdot \frac{\sqrt{\frac{1}{3}} \cdot \left({x}^{2} + {y}^{2}\right)}{{z}^{2}}\right) \cdot z \]
    3. lower-fma.f64N/A

      \[\leadsto \color{blue}{\mathsf{fma}\left(z, \sqrt{\frac{1}{3}}, \left(\frac{1}{2} \cdot \frac{\sqrt{\frac{1}{3}} \cdot \left({x}^{2} + {y}^{2}\right)}{{z}^{2}}\right) \cdot z\right)} \]
    4. lower-sqrt.f64N/A

      \[\leadsto \mathsf{fma}\left(z, \color{blue}{\sqrt{\frac{1}{3}}}, \left(\frac{1}{2} \cdot \frac{\sqrt{\frac{1}{3}} \cdot \left({x}^{2} + {y}^{2}\right)}{{z}^{2}}\right) \cdot z\right) \]
    5. *-commutativeN/A

      \[\leadsto \mathsf{fma}\left(z, \sqrt{\frac{1}{3}}, \color{blue}{z \cdot \left(\frac{1}{2} \cdot \frac{\sqrt{\frac{1}{3}} \cdot \left({x}^{2} + {y}^{2}\right)}{{z}^{2}}\right)}\right) \]
    6. associate-*r/N/A

      \[\leadsto \mathsf{fma}\left(z, \sqrt{\frac{1}{3}}, z \cdot \color{blue}{\frac{\frac{1}{2} \cdot \left(\sqrt{\frac{1}{3}} \cdot \left({x}^{2} + {y}^{2}\right)\right)}{{z}^{2}}}\right) \]
    7. associate-*r/N/A

      \[\leadsto \mathsf{fma}\left(z, \sqrt{\frac{1}{3}}, \color{blue}{\frac{z \cdot \left(\frac{1}{2} \cdot \left(\sqrt{\frac{1}{3}} \cdot \left({x}^{2} + {y}^{2}\right)\right)\right)}{{z}^{2}}}\right) \]
    8. unpow2N/A

      \[\leadsto \mathsf{fma}\left(z, \sqrt{\frac{1}{3}}, \frac{z \cdot \left(\frac{1}{2} \cdot \left(\sqrt{\frac{1}{3}} \cdot \left({x}^{2} + {y}^{2}\right)\right)\right)}{\color{blue}{z \cdot z}}\right) \]
    9. times-fracN/A

      \[\leadsto \mathsf{fma}\left(z, \sqrt{\frac{1}{3}}, \color{blue}{\frac{z}{z} \cdot \frac{\frac{1}{2} \cdot \left(\sqrt{\frac{1}{3}} \cdot \left({x}^{2} + {y}^{2}\right)\right)}{z}}\right) \]
    10. *-inversesN/A

      \[\leadsto \mathsf{fma}\left(z, \sqrt{\frac{1}{3}}, \color{blue}{1} \cdot \frac{\frac{1}{2} \cdot \left(\sqrt{\frac{1}{3}} \cdot \left({x}^{2} + {y}^{2}\right)\right)}{z}\right) \]
    11. lower-*.f64N/A

      \[\leadsto \mathsf{fma}\left(z, \sqrt{\frac{1}{3}}, \color{blue}{1 \cdot \frac{\frac{1}{2} \cdot \left(\sqrt{\frac{1}{3}} \cdot \left({x}^{2} + {y}^{2}\right)\right)}{z}}\right) \]
    12. *-commutativeN/A

      \[\leadsto \mathsf{fma}\left(z, \sqrt{\frac{1}{3}}, 1 \cdot \frac{\color{blue}{\left(\sqrt{\frac{1}{3}} \cdot \left({x}^{2} + {y}^{2}\right)\right) \cdot \frac{1}{2}}}{z}\right) \]
    13. associate-/l*N/A

      \[\leadsto \mathsf{fma}\left(z, \sqrt{\frac{1}{3}}, 1 \cdot \color{blue}{\left(\left(\sqrt{\frac{1}{3}} \cdot \left({x}^{2} + {y}^{2}\right)\right) \cdot \frac{\frac{1}{2}}{z}\right)}\right) \]
    14. lower-*.f64N/A

      \[\leadsto \mathsf{fma}\left(z, \sqrt{\frac{1}{3}}, 1 \cdot \color{blue}{\left(\left(\sqrt{\frac{1}{3}} \cdot \left({x}^{2} + {y}^{2}\right)\right) \cdot \frac{\frac{1}{2}}{z}\right)}\right) \]
  5. Applied rewrites17.3%

    \[\leadsto \color{blue}{\mathsf{fma}\left(z, \sqrt{0.3333333333333333}, 1 \cdot \left(\left(\mathsf{fma}\left(y, y, x \cdot x\right) \cdot \sqrt{0.3333333333333333}\right) \cdot \frac{0.5}{z}\right)\right)} \]
  6. Step-by-step derivation
    1. Applied rewrites17.3%

      \[\leadsto \frac{1}{\color{blue}{\frac{1}{\mathsf{fma}\left(z, \sqrt{0.3333333333333333}, \frac{\sqrt{0.3333333333333333} \cdot \mathsf{fma}\left(x, x, y \cdot y\right)}{z \cdot 2}\right)}}} \]
    2. Taylor expanded in x around 0

      \[\leadsto \frac{1}{2} \cdot \frac{{y}^{2} \cdot \sqrt{\frac{1}{3}}}{z} + \color{blue}{z \cdot \sqrt{\frac{1}{3}}} \]
    3. Step-by-step derivation
      1. Applied rewrites19.2%

        \[\leadsto \mathsf{fma}\left(y, \color{blue}{y \cdot \frac{\sqrt{0.3333333333333333} \cdot 0.5}{z}}, \sqrt{0.3333333333333333} \cdot z\right) \]
      2. Step-by-step derivation
        1. Applied rewrites18.9%

          \[\leadsto \mathsf{fma}\left(y, y \cdot e^{\log \left(\frac{z}{\sqrt{0.3333333333333333} \cdot 0.5}\right) \cdot -1}, \sqrt{0.3333333333333333} \cdot z\right) \]
        2. Final simplification18.9%

          \[\leadsto \mathsf{fma}\left(y, y \cdot e^{-\log \left(\frac{z}{\sqrt{0.3333333333333333} \cdot 0.5}\right)}, z \cdot \sqrt{0.3333333333333333}\right) \]
        3. Add Preprocessing

        Alternative 2: 98.8% accurate, 0.8× speedup?

        \[\begin{array}{l} z_m = \left|z\right| \\ y_m = \left|y\right| \\ x_m = \left|x\right| \\ [x_m, y_m, z_m] = \mathsf{sort}([x_m, y_m, z_m])\\ \\ \mathsf{fma}\left(y\_m, y\_m \cdot \frac{\sqrt{0.3333333333333333} \cdot 0.5}{z\_m}, z\_m \cdot \sqrt{0.3333333333333333}\right) \end{array} \]
        z_m = (fabs.f64 z)
        y_m = (fabs.f64 y)
        x_m = (fabs.f64 x)
        NOTE: x_m, y_m, and z_m should be sorted in increasing order before calling this function.
        (FPCore (x_m y_m z_m)
         :precision binary64
         (fma
          y_m
          (* y_m (/ (* (sqrt 0.3333333333333333) 0.5) z_m))
          (* z_m (sqrt 0.3333333333333333))))
        z_m = fabs(z);
        y_m = fabs(y);
        x_m = fabs(x);
        assert(x_m < y_m && y_m < z_m);
        double code(double x_m, double y_m, double z_m) {
        	return fma(y_m, (y_m * ((sqrt(0.3333333333333333) * 0.5) / z_m)), (z_m * sqrt(0.3333333333333333)));
        }
        
        z_m = abs(z)
        y_m = abs(y)
        x_m = abs(x)
        x_m, y_m, z_m = sort([x_m, y_m, z_m])
        function code(x_m, y_m, z_m)
        	return fma(y_m, Float64(y_m * Float64(Float64(sqrt(0.3333333333333333) * 0.5) / z_m)), Float64(z_m * sqrt(0.3333333333333333)))
        end
        
        z_m = N[Abs[z], $MachinePrecision]
        y_m = N[Abs[y], $MachinePrecision]
        x_m = N[Abs[x], $MachinePrecision]
        NOTE: x_m, y_m, and z_m should be sorted in increasing order before calling this function.
        code[x$95$m_, y$95$m_, z$95$m_] := N[(y$95$m * N[(y$95$m * N[(N[(N[Sqrt[0.3333333333333333], $MachinePrecision] * 0.5), $MachinePrecision] / z$95$m), $MachinePrecision]), $MachinePrecision] + N[(z$95$m * N[Sqrt[0.3333333333333333], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
        
        \begin{array}{l}
        z_m = \left|z\right|
        \\
        y_m = \left|y\right|
        \\
        x_m = \left|x\right|
        \\
        [x_m, y_m, z_m] = \mathsf{sort}([x_m, y_m, z_m])\\
        \\
        \mathsf{fma}\left(y\_m, y\_m \cdot \frac{\sqrt{0.3333333333333333} \cdot 0.5}{z\_m}, z\_m \cdot \sqrt{0.3333333333333333}\right)
        \end{array}
        
        Derivation
        1. Initial program 45.9%

          \[\sqrt{\frac{\left(x \cdot x + y \cdot y\right) + z \cdot z}{3}} \]
        2. Add Preprocessing
        3. Taylor expanded in z around inf

          \[\leadsto \color{blue}{z \cdot \left(\sqrt{\frac{1}{3}} + \frac{1}{2} \cdot \frac{\sqrt{\frac{1}{3}} \cdot \left({x}^{2} + {y}^{2}\right)}{{z}^{2}}\right)} \]
        4. Step-by-step derivation
          1. distribute-rgt-inN/A

            \[\leadsto \color{blue}{\sqrt{\frac{1}{3}} \cdot z + \left(\frac{1}{2} \cdot \frac{\sqrt{\frac{1}{3}} \cdot \left({x}^{2} + {y}^{2}\right)}{{z}^{2}}\right) \cdot z} \]
          2. *-commutativeN/A

            \[\leadsto \color{blue}{z \cdot \sqrt{\frac{1}{3}}} + \left(\frac{1}{2} \cdot \frac{\sqrt{\frac{1}{3}} \cdot \left({x}^{2} + {y}^{2}\right)}{{z}^{2}}\right) \cdot z \]
          3. lower-fma.f64N/A

            \[\leadsto \color{blue}{\mathsf{fma}\left(z, \sqrt{\frac{1}{3}}, \left(\frac{1}{2} \cdot \frac{\sqrt{\frac{1}{3}} \cdot \left({x}^{2} + {y}^{2}\right)}{{z}^{2}}\right) \cdot z\right)} \]
          4. lower-sqrt.f64N/A

            \[\leadsto \mathsf{fma}\left(z, \color{blue}{\sqrt{\frac{1}{3}}}, \left(\frac{1}{2} \cdot \frac{\sqrt{\frac{1}{3}} \cdot \left({x}^{2} + {y}^{2}\right)}{{z}^{2}}\right) \cdot z\right) \]
          5. *-commutativeN/A

            \[\leadsto \mathsf{fma}\left(z, \sqrt{\frac{1}{3}}, \color{blue}{z \cdot \left(\frac{1}{2} \cdot \frac{\sqrt{\frac{1}{3}} \cdot \left({x}^{2} + {y}^{2}\right)}{{z}^{2}}\right)}\right) \]
          6. associate-*r/N/A

            \[\leadsto \mathsf{fma}\left(z, \sqrt{\frac{1}{3}}, z \cdot \color{blue}{\frac{\frac{1}{2} \cdot \left(\sqrt{\frac{1}{3}} \cdot \left({x}^{2} + {y}^{2}\right)\right)}{{z}^{2}}}\right) \]
          7. associate-*r/N/A

            \[\leadsto \mathsf{fma}\left(z, \sqrt{\frac{1}{3}}, \color{blue}{\frac{z \cdot \left(\frac{1}{2} \cdot \left(\sqrt{\frac{1}{3}} \cdot \left({x}^{2} + {y}^{2}\right)\right)\right)}{{z}^{2}}}\right) \]
          8. unpow2N/A

            \[\leadsto \mathsf{fma}\left(z, \sqrt{\frac{1}{3}}, \frac{z \cdot \left(\frac{1}{2} \cdot \left(\sqrt{\frac{1}{3}} \cdot \left({x}^{2} + {y}^{2}\right)\right)\right)}{\color{blue}{z \cdot z}}\right) \]
          9. times-fracN/A

            \[\leadsto \mathsf{fma}\left(z, \sqrt{\frac{1}{3}}, \color{blue}{\frac{z}{z} \cdot \frac{\frac{1}{2} \cdot \left(\sqrt{\frac{1}{3}} \cdot \left({x}^{2} + {y}^{2}\right)\right)}{z}}\right) \]
          10. *-inversesN/A

            \[\leadsto \mathsf{fma}\left(z, \sqrt{\frac{1}{3}}, \color{blue}{1} \cdot \frac{\frac{1}{2} \cdot \left(\sqrt{\frac{1}{3}} \cdot \left({x}^{2} + {y}^{2}\right)\right)}{z}\right) \]
          11. lower-*.f64N/A

            \[\leadsto \mathsf{fma}\left(z, \sqrt{\frac{1}{3}}, \color{blue}{1 \cdot \frac{\frac{1}{2} \cdot \left(\sqrt{\frac{1}{3}} \cdot \left({x}^{2} + {y}^{2}\right)\right)}{z}}\right) \]
          12. *-commutativeN/A

            \[\leadsto \mathsf{fma}\left(z, \sqrt{\frac{1}{3}}, 1 \cdot \frac{\color{blue}{\left(\sqrt{\frac{1}{3}} \cdot \left({x}^{2} + {y}^{2}\right)\right) \cdot \frac{1}{2}}}{z}\right) \]
          13. associate-/l*N/A

            \[\leadsto \mathsf{fma}\left(z, \sqrt{\frac{1}{3}}, 1 \cdot \color{blue}{\left(\left(\sqrt{\frac{1}{3}} \cdot \left({x}^{2} + {y}^{2}\right)\right) \cdot \frac{\frac{1}{2}}{z}\right)}\right) \]
          14. lower-*.f64N/A

            \[\leadsto \mathsf{fma}\left(z, \sqrt{\frac{1}{3}}, 1 \cdot \color{blue}{\left(\left(\sqrt{\frac{1}{3}} \cdot \left({x}^{2} + {y}^{2}\right)\right) \cdot \frac{\frac{1}{2}}{z}\right)}\right) \]
        5. Applied rewrites17.3%

          \[\leadsto \color{blue}{\mathsf{fma}\left(z, \sqrt{0.3333333333333333}, 1 \cdot \left(\left(\mathsf{fma}\left(y, y, x \cdot x\right) \cdot \sqrt{0.3333333333333333}\right) \cdot \frac{0.5}{z}\right)\right)} \]
        6. Step-by-step derivation
          1. Applied rewrites17.3%

            \[\leadsto \frac{1}{\color{blue}{\frac{1}{\mathsf{fma}\left(z, \sqrt{0.3333333333333333}, \frac{\sqrt{0.3333333333333333} \cdot \mathsf{fma}\left(x, x, y \cdot y\right)}{z \cdot 2}\right)}}} \]
          2. Taylor expanded in x around 0

            \[\leadsto \frac{1}{2} \cdot \frac{{y}^{2} \cdot \sqrt{\frac{1}{3}}}{z} + \color{blue}{z \cdot \sqrt{\frac{1}{3}}} \]
          3. Step-by-step derivation
            1. Applied rewrites19.2%

              \[\leadsto \mathsf{fma}\left(y, \color{blue}{y \cdot \frac{\sqrt{0.3333333333333333} \cdot 0.5}{z}}, \sqrt{0.3333333333333333} \cdot z\right) \]
            2. Final simplification19.2%

              \[\leadsto \mathsf{fma}\left(y, y \cdot \frac{\sqrt{0.3333333333333333} \cdot 0.5}{z}, z \cdot \sqrt{0.3333333333333333}\right) \]
            3. Add Preprocessing

            Alternative 3: 98.0% accurate, 2.7× speedup?

            \[\begin{array}{l} z_m = \left|z\right| \\ y_m = \left|y\right| \\ x_m = \left|x\right| \\ [x_m, y_m, z_m] = \mathsf{sort}([x_m, y_m, z_m])\\ \\ z\_m \cdot \sqrt{0.3333333333333333} \end{array} \]
            z_m = (fabs.f64 z)
            y_m = (fabs.f64 y)
            x_m = (fabs.f64 x)
            NOTE: x_m, y_m, and z_m should be sorted in increasing order before calling this function.
            (FPCore (x_m y_m z_m) :precision binary64 (* z_m (sqrt 0.3333333333333333)))
            z_m = fabs(z);
            y_m = fabs(y);
            x_m = fabs(x);
            assert(x_m < y_m && y_m < z_m);
            double code(double x_m, double y_m, double z_m) {
            	return z_m * sqrt(0.3333333333333333);
            }
            
            z_m = abs(z)
            y_m = abs(y)
            x_m = abs(x)
            NOTE: x_m, y_m, and z_m should be sorted in increasing order before calling this function.
            real(8) function code(x_m, y_m, z_m)
                real(8), intent (in) :: x_m
                real(8), intent (in) :: y_m
                real(8), intent (in) :: z_m
                code = z_m * sqrt(0.3333333333333333d0)
            end function
            
            z_m = Math.abs(z);
            y_m = Math.abs(y);
            x_m = Math.abs(x);
            assert x_m < y_m && y_m < z_m;
            public static double code(double x_m, double y_m, double z_m) {
            	return z_m * Math.sqrt(0.3333333333333333);
            }
            
            z_m = math.fabs(z)
            y_m = math.fabs(y)
            x_m = math.fabs(x)
            [x_m, y_m, z_m] = sort([x_m, y_m, z_m])
            def code(x_m, y_m, z_m):
            	return z_m * math.sqrt(0.3333333333333333)
            
            z_m = abs(z)
            y_m = abs(y)
            x_m = abs(x)
            x_m, y_m, z_m = sort([x_m, y_m, z_m])
            function code(x_m, y_m, z_m)
            	return Float64(z_m * sqrt(0.3333333333333333))
            end
            
            z_m = abs(z);
            y_m = abs(y);
            x_m = abs(x);
            x_m, y_m, z_m = num2cell(sort([x_m, y_m, z_m])){:}
            function tmp = code(x_m, y_m, z_m)
            	tmp = z_m * sqrt(0.3333333333333333);
            end
            
            z_m = N[Abs[z], $MachinePrecision]
            y_m = N[Abs[y], $MachinePrecision]
            x_m = N[Abs[x], $MachinePrecision]
            NOTE: x_m, y_m, and z_m should be sorted in increasing order before calling this function.
            code[x$95$m_, y$95$m_, z$95$m_] := N[(z$95$m * N[Sqrt[0.3333333333333333], $MachinePrecision]), $MachinePrecision]
            
            \begin{array}{l}
            z_m = \left|z\right|
            \\
            y_m = \left|y\right|
            \\
            x_m = \left|x\right|
            \\
            [x_m, y_m, z_m] = \mathsf{sort}([x_m, y_m, z_m])\\
            \\
            z\_m \cdot \sqrt{0.3333333333333333}
            \end{array}
            
            Derivation
            1. Initial program 45.9%

              \[\sqrt{\frac{\left(x \cdot x + y \cdot y\right) + z \cdot z}{3}} \]
            2. Add Preprocessing
            3. Taylor expanded in z around inf

              \[\leadsto \color{blue}{z \cdot \sqrt{\frac{1}{3}}} \]
            4. Step-by-step derivation
              1. lower-*.f64N/A

                \[\leadsto \color{blue}{z \cdot \sqrt{\frac{1}{3}}} \]
              2. lower-sqrt.f6418.7

                \[\leadsto z \cdot \color{blue}{\sqrt{0.3333333333333333}} \]
            5. Applied rewrites18.7%

              \[\leadsto \color{blue}{z \cdot \sqrt{0.3333333333333333}} \]
            6. Add Preprocessing

            Developer Target 1: 97.3% accurate, 0.7× speedup?

            \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;z < -6.396479394109776 \cdot 10^{+136}:\\ \;\;\;\;\frac{-z}{\sqrt{3}}\\ \mathbf{elif}\;z < 7.320293694404182 \cdot 10^{+117}:\\ \;\;\;\;\frac{\sqrt{\left(z \cdot z + x \cdot x\right) + y \cdot y}}{\sqrt{3}}\\ \mathbf{else}:\\ \;\;\;\;\sqrt{0.3333333333333333} \cdot z\\ \end{array} \end{array} \]
            (FPCore (x y z)
             :precision binary64
             (if (< z -6.396479394109776e+136)
               (/ (- z) (sqrt 3.0))
               (if (< z 7.320293694404182e+117)
                 (/ (sqrt (+ (+ (* z z) (* x x)) (* y y))) (sqrt 3.0))
                 (* (sqrt 0.3333333333333333) z))))
            double code(double x, double y, double z) {
            	double tmp;
            	if (z < -6.396479394109776e+136) {
            		tmp = -z / sqrt(3.0);
            	} else if (z < 7.320293694404182e+117) {
            		tmp = sqrt((((z * z) + (x * x)) + (y * y))) / sqrt(3.0);
            	} else {
            		tmp = sqrt(0.3333333333333333) * z;
            	}
            	return tmp;
            }
            
            real(8) function code(x, y, z)
                real(8), intent (in) :: x
                real(8), intent (in) :: y
                real(8), intent (in) :: z
                real(8) :: tmp
                if (z < (-6.396479394109776d+136)) then
                    tmp = -z / sqrt(3.0d0)
                else if (z < 7.320293694404182d+117) then
                    tmp = sqrt((((z * z) + (x * x)) + (y * y))) / sqrt(3.0d0)
                else
                    tmp = sqrt(0.3333333333333333d0) * z
                end if
                code = tmp
            end function
            
            public static double code(double x, double y, double z) {
            	double tmp;
            	if (z < -6.396479394109776e+136) {
            		tmp = -z / Math.sqrt(3.0);
            	} else if (z < 7.320293694404182e+117) {
            		tmp = Math.sqrt((((z * z) + (x * x)) + (y * y))) / Math.sqrt(3.0);
            	} else {
            		tmp = Math.sqrt(0.3333333333333333) * z;
            	}
            	return tmp;
            }
            
            def code(x, y, z):
            	tmp = 0
            	if z < -6.396479394109776e+136:
            		tmp = -z / math.sqrt(3.0)
            	elif z < 7.320293694404182e+117:
            		tmp = math.sqrt((((z * z) + (x * x)) + (y * y))) / math.sqrt(3.0)
            	else:
            		tmp = math.sqrt(0.3333333333333333) * z
            	return tmp
            
            function code(x, y, z)
            	tmp = 0.0
            	if (z < -6.396479394109776e+136)
            		tmp = Float64(Float64(-z) / sqrt(3.0));
            	elseif (z < 7.320293694404182e+117)
            		tmp = Float64(sqrt(Float64(Float64(Float64(z * z) + Float64(x * x)) + Float64(y * y))) / sqrt(3.0));
            	else
            		tmp = Float64(sqrt(0.3333333333333333) * z);
            	end
            	return tmp
            end
            
            function tmp_2 = code(x, y, z)
            	tmp = 0.0;
            	if (z < -6.396479394109776e+136)
            		tmp = -z / sqrt(3.0);
            	elseif (z < 7.320293694404182e+117)
            		tmp = sqrt((((z * z) + (x * x)) + (y * y))) / sqrt(3.0);
            	else
            		tmp = sqrt(0.3333333333333333) * z;
            	end
            	tmp_2 = tmp;
            end
            
            code[x_, y_, z_] := If[Less[z, -6.396479394109776e+136], N[((-z) / N[Sqrt[3.0], $MachinePrecision]), $MachinePrecision], If[Less[z, 7.320293694404182e+117], N[(N[Sqrt[N[(N[(N[(z * z), $MachinePrecision] + N[(x * x), $MachinePrecision]), $MachinePrecision] + N[(y * y), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / N[Sqrt[3.0], $MachinePrecision]), $MachinePrecision], N[(N[Sqrt[0.3333333333333333], $MachinePrecision] * z), $MachinePrecision]]]
            
            \begin{array}{l}
            
            \\
            \begin{array}{l}
            \mathbf{if}\;z < -6.396479394109776 \cdot 10^{+136}:\\
            \;\;\;\;\frac{-z}{\sqrt{3}}\\
            
            \mathbf{elif}\;z < 7.320293694404182 \cdot 10^{+117}:\\
            \;\;\;\;\frac{\sqrt{\left(z \cdot z + x \cdot x\right) + y \cdot y}}{\sqrt{3}}\\
            
            \mathbf{else}:\\
            \;\;\;\;\sqrt{0.3333333333333333} \cdot z\\
            
            
            \end{array}
            \end{array}
            

            Reproduce

            ?
            herbie shell --seed 2024238 
            (FPCore (x y z)
              :name "Data.Array.Repa.Algorithms.Pixel:doubleRmsOfRGB8 from repa-algorithms-3.4.0.1"
              :precision binary64
            
              :alt
              (! :herbie-platform default (if (< z -63964793941097760000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000) (/ (- z) (sqrt 3)) (if (< z 7320293694404182000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000) (/ (sqrt (+ (+ (* z z) (* x x)) (* y y))) (sqrt 3)) (* (sqrt 3333333333333333/10000000000000000) z))))
            
              (sqrt (/ (+ (+ (* x x) (* y y)) (* z z)) 3.0)))