Data.Random.Distribution.Normal:normalF from random-fu-0.2.6.2

Percentage Accurate: 100.0% → 100.0%
Time: 28.7s
Alternatives: 15
Speedup: 1.0×

Specification

?
\[\begin{array}{l} \\ e^{\left(x \cdot y\right) \cdot y} \end{array} \]
(FPCore (x y) :precision binary64 (exp (* (* x y) y)))
double code(double x, double y) {
	return exp(((x * y) * y));
}
real(8) function code(x, y)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    code = exp(((x * y) * y))
end function
public static double code(double x, double y) {
	return Math.exp(((x * y) * y));
}
def code(x, y):
	return math.exp(((x * y) * y))
function code(x, y)
	return exp(Float64(Float64(x * y) * y))
end
function tmp = code(x, y)
	tmp = exp(((x * y) * y));
end
code[x_, y_] := N[Exp[N[(N[(x * y), $MachinePrecision] * y), $MachinePrecision]], $MachinePrecision]
\begin{array}{l}

\\
e^{\left(x \cdot y\right) \cdot y}
\end{array}

Sampling outcomes in binary64 precision:

Local Percentage Accuracy vs ?

The average percentage accuracy by input value. Horizontal axis shows value of an input variable; the variable is choosen in the title. Vertical axis is accuracy; higher is better. Red represent the original program, while blue represents Herbie's suggestion. These can be toggled with buttons below the plot. The line is an average while dots represent individual samples.

Accuracy vs Speed?

Herbie found 15 alternatives:

AlternativeAccuracySpeedup
The accuracy (vertical axis) and speed (horizontal axis) of each alternatives. Up and to the right is better. The red square shows the initial program, and each blue circle shows an alternative.The line shows the best available speed-accuracy tradeoffs.

Initial Program: 100.0% accurate, 1.0× speedup?

\[\begin{array}{l} \\ e^{\left(x \cdot y\right) \cdot y} \end{array} \]
(FPCore (x y) :precision binary64 (exp (* (* x y) y)))
double code(double x, double y) {
	return exp(((x * y) * y));
}
real(8) function code(x, y)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    code = exp(((x * y) * y))
end function
public static double code(double x, double y) {
	return Math.exp(((x * y) * y));
}
def code(x, y):
	return math.exp(((x * y) * y))
function code(x, y)
	return exp(Float64(Float64(x * y) * y))
end
function tmp = code(x, y)
	tmp = exp(((x * y) * y));
end
code[x_, y_] := N[Exp[N[(N[(x * y), $MachinePrecision] * y), $MachinePrecision]], $MachinePrecision]
\begin{array}{l}

\\
e^{\left(x \cdot y\right) \cdot y}
\end{array}

Alternative 1: 100.0% accurate, 1.0× speedup?

\[\begin{array}{l} \\ e^{y \cdot \left(x \cdot y\right)} \end{array} \]
(FPCore (x y) :precision binary64 (exp (* y (* x y))))
double code(double x, double y) {
	return exp((y * (x * y)));
}
real(8) function code(x, y)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    code = exp((y * (x * y)))
end function
public static double code(double x, double y) {
	return Math.exp((y * (x * y)));
}
def code(x, y):
	return math.exp((y * (x * y)))
function code(x, y)
	return exp(Float64(y * Float64(x * y)))
end
function tmp = code(x, y)
	tmp = exp((y * (x * y)));
end
code[x_, y_] := N[Exp[N[(y * N[(x * y), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]
\begin{array}{l}

\\
e^{y \cdot \left(x \cdot y\right)}
\end{array}
Derivation
  1. Initial program 99.9%

    \[e^{\left(x \cdot y\right) \cdot y} \]
  2. Add Preprocessing
  3. Final simplification99.9%

    \[\leadsto e^{y \cdot \left(x \cdot y\right)} \]
  4. Add Preprocessing

Alternative 2: 66.3% accurate, 0.9× speedup?

\[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;e^{y \cdot \left(x \cdot y\right)} \leq 2:\\ \;\;\;\;1\\ \mathbf{else}:\\ \;\;\;\;x \cdot \left(y \cdot y\right)\\ \end{array} \end{array} \]
(FPCore (x y)
 :precision binary64
 (if (<= (exp (* y (* x y))) 2.0) 1.0 (* x (* y y))))
double code(double x, double y) {
	double tmp;
	if (exp((y * (x * y))) <= 2.0) {
		tmp = 1.0;
	} else {
		tmp = x * (y * y);
	}
	return tmp;
}
real(8) function code(x, y)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    real(8) :: tmp
    if (exp((y * (x * y))) <= 2.0d0) then
        tmp = 1.0d0
    else
        tmp = x * (y * y)
    end if
    code = tmp
end function
public static double code(double x, double y) {
	double tmp;
	if (Math.exp((y * (x * y))) <= 2.0) {
		tmp = 1.0;
	} else {
		tmp = x * (y * y);
	}
	return tmp;
}
def code(x, y):
	tmp = 0
	if math.exp((y * (x * y))) <= 2.0:
		tmp = 1.0
	else:
		tmp = x * (y * y)
	return tmp
function code(x, y)
	tmp = 0.0
	if (exp(Float64(y * Float64(x * y))) <= 2.0)
		tmp = 1.0;
	else
		tmp = Float64(x * Float64(y * y));
	end
	return tmp
end
function tmp_2 = code(x, y)
	tmp = 0.0;
	if (exp((y * (x * y))) <= 2.0)
		tmp = 1.0;
	else
		tmp = x * (y * y);
	end
	tmp_2 = tmp;
end
code[x_, y_] := If[LessEqual[N[Exp[N[(y * N[(x * y), $MachinePrecision]), $MachinePrecision]], $MachinePrecision], 2.0], 1.0, N[(x * N[(y * y), $MachinePrecision]), $MachinePrecision]]
\begin{array}{l}

\\
\begin{array}{l}
\mathbf{if}\;e^{y \cdot \left(x \cdot y\right)} \leq 2:\\
\;\;\;\;1\\

\mathbf{else}:\\
\;\;\;\;x \cdot \left(y \cdot y\right)\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if (exp.f64 (*.f64 (*.f64 x y) y)) < 2

    1. Initial program 100.0%

      \[e^{\left(x \cdot y\right) \cdot y} \]
    2. Add Preprocessing
    3. Taylor expanded in x around 0

      \[\leadsto \color{blue}{1} \]
    4. Step-by-step derivation
      1. Applied rewrites66.9%

        \[\leadsto \color{blue}{1} \]

      if 2 < (exp.f64 (*.f64 (*.f64 x y) y))

      1. Initial program 99.8%

        \[e^{\left(x \cdot y\right) \cdot y} \]
      2. Add Preprocessing
      3. Taylor expanded in x around 0

        \[\leadsto \color{blue}{1 + x \cdot {y}^{2}} \]
      4. Step-by-step derivation
        1. +-commutativeN/A

          \[\leadsto \color{blue}{x \cdot {y}^{2} + 1} \]
        2. lower-fma.f64N/A

          \[\leadsto \color{blue}{\mathsf{fma}\left(x, {y}^{2}, 1\right)} \]
        3. unpow2N/A

          \[\leadsto \mathsf{fma}\left(x, \color{blue}{y \cdot y}, 1\right) \]
        4. lower-*.f6462.5

          \[\leadsto \mathsf{fma}\left(x, \color{blue}{y \cdot y}, 1\right) \]
      5. Applied rewrites62.5%

        \[\leadsto \color{blue}{\mathsf{fma}\left(x, y \cdot y, 1\right)} \]
      6. Taylor expanded in x around inf

        \[\leadsto x \cdot \color{blue}{{y}^{2}} \]
      7. Step-by-step derivation
        1. Applied rewrites62.5%

          \[\leadsto x \cdot \color{blue}{\left(y \cdot y\right)} \]
      8. Recombined 2 regimes into one program.
      9. Final simplification65.8%

        \[\leadsto \begin{array}{l} \mathbf{if}\;e^{y \cdot \left(x \cdot y\right)} \leq 2:\\ \;\;\;\;1\\ \mathbf{else}:\\ \;\;\;\;x \cdot \left(y \cdot y\right)\\ \end{array} \]
      10. Add Preprocessing

      Alternative 3: 83.0% accurate, 0.9× speedup?

      \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;y \cdot \left(x \cdot y\right) \leq -500000:\\ \;\;\;\;e^{x \cdot y}\\ \mathbf{else}:\\ \;\;\;\;\mathsf{fma}\left(y \cdot y, \mathsf{fma}\left(x \cdot \left(x \cdot \left(y \cdot y\right)\right), \mathsf{fma}\left(x, \left(y \cdot y\right) \cdot 0.16666666666666666, 0.5\right), x\right), 1\right)\\ \end{array} \end{array} \]
      (FPCore (x y)
       :precision binary64
       (if (<= (* y (* x y)) -500000.0)
         (exp (* x y))
         (fma
          (* y y)
          (fma (* x (* x (* y y))) (fma x (* (* y y) 0.16666666666666666) 0.5) x)
          1.0)))
      double code(double x, double y) {
      	double tmp;
      	if ((y * (x * y)) <= -500000.0) {
      		tmp = exp((x * y));
      	} else {
      		tmp = fma((y * y), fma((x * (x * (y * y))), fma(x, ((y * y) * 0.16666666666666666), 0.5), x), 1.0);
      	}
      	return tmp;
      }
      
      function code(x, y)
      	tmp = 0.0
      	if (Float64(y * Float64(x * y)) <= -500000.0)
      		tmp = exp(Float64(x * y));
      	else
      		tmp = fma(Float64(y * y), fma(Float64(x * Float64(x * Float64(y * y))), fma(x, Float64(Float64(y * y) * 0.16666666666666666), 0.5), x), 1.0);
      	end
      	return tmp
      end
      
      code[x_, y_] := If[LessEqual[N[(y * N[(x * y), $MachinePrecision]), $MachinePrecision], -500000.0], N[Exp[N[(x * y), $MachinePrecision]], $MachinePrecision], N[(N[(y * y), $MachinePrecision] * N[(N[(x * N[(x * N[(y * y), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] * N[(x * N[(N[(y * y), $MachinePrecision] * 0.16666666666666666), $MachinePrecision] + 0.5), $MachinePrecision] + x), $MachinePrecision] + 1.0), $MachinePrecision]]
      
      \begin{array}{l}
      
      \\
      \begin{array}{l}
      \mathbf{if}\;y \cdot \left(x \cdot y\right) \leq -500000:\\
      \;\;\;\;e^{x \cdot y}\\
      
      \mathbf{else}:\\
      \;\;\;\;\mathsf{fma}\left(y \cdot y, \mathsf{fma}\left(x \cdot \left(x \cdot \left(y \cdot y\right)\right), \mathsf{fma}\left(x, \left(y \cdot y\right) \cdot 0.16666666666666666, 0.5\right), x\right), 1\right)\\
      
      
      \end{array}
      \end{array}
      
      Derivation
      1. Split input into 2 regimes
      2. if (*.f64 (*.f64 x y) y) < -5e5

        1. Initial program 100.0%

          \[e^{\left(x \cdot y\right) \cdot y} \]
        2. Add Preprocessing
        3. Applied rewrites40.2%

          \[\leadsto e^{\color{blue}{x} \cdot y} \]

        if -5e5 < (*.f64 (*.f64 x y) y)

        1. Initial program 99.9%

          \[e^{\left(x \cdot y\right) \cdot y} \]
        2. Add Preprocessing
        3. Taylor expanded in x around 0

          \[\leadsto \color{blue}{1 + x \cdot \left(x \cdot \left(\frac{1}{6} \cdot \left(x \cdot {y}^{6}\right) + \frac{1}{2} \cdot {y}^{4}\right) + {y}^{2}\right)} \]
        4. Applied rewrites94.6%

          \[\leadsto \color{blue}{\mathsf{fma}\left(y \cdot y, \mathsf{fma}\left(x \cdot \left(x \cdot \left(y \cdot y\right)\right), \mathsf{fma}\left(x, \left(y \cdot y\right) \cdot 0.16666666666666666, 0.5\right), x\right), 1\right)} \]
      3. Recombined 2 regimes into one program.
      4. Final simplification81.0%

        \[\leadsto \begin{array}{l} \mathbf{if}\;y \cdot \left(x \cdot y\right) \leq -500000:\\ \;\;\;\;e^{x \cdot y}\\ \mathbf{else}:\\ \;\;\;\;\mathsf{fma}\left(y \cdot y, \mathsf{fma}\left(x \cdot \left(x \cdot \left(y \cdot y\right)\right), \mathsf{fma}\left(x, \left(y \cdot y\right) \cdot 0.16666666666666666, 0.5\right), x\right), 1\right)\\ \end{array} \]
      5. Add Preprocessing

      Alternative 4: 87.6% accurate, 0.9× speedup?

      \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;y \cdot \left(x \cdot y\right) \leq -500000:\\ \;\;\;\;e^{x}\\ \mathbf{else}:\\ \;\;\;\;\mathsf{fma}\left(y \cdot y, \mathsf{fma}\left(x \cdot \left(x \cdot \left(y \cdot y\right)\right), \mathsf{fma}\left(x, \left(y \cdot y\right) \cdot 0.16666666666666666, 0.5\right), x\right), 1\right)\\ \end{array} \end{array} \]
      (FPCore (x y)
       :precision binary64
       (if (<= (* y (* x y)) -500000.0)
         (exp x)
         (fma
          (* y y)
          (fma (* x (* x (* y y))) (fma x (* (* y y) 0.16666666666666666) 0.5) x)
          1.0)))
      double code(double x, double y) {
      	double tmp;
      	if ((y * (x * y)) <= -500000.0) {
      		tmp = exp(x);
      	} else {
      		tmp = fma((y * y), fma((x * (x * (y * y))), fma(x, ((y * y) * 0.16666666666666666), 0.5), x), 1.0);
      	}
      	return tmp;
      }
      
      function code(x, y)
      	tmp = 0.0
      	if (Float64(y * Float64(x * y)) <= -500000.0)
      		tmp = exp(x);
      	else
      		tmp = fma(Float64(y * y), fma(Float64(x * Float64(x * Float64(y * y))), fma(x, Float64(Float64(y * y) * 0.16666666666666666), 0.5), x), 1.0);
      	end
      	return tmp
      end
      
      code[x_, y_] := If[LessEqual[N[(y * N[(x * y), $MachinePrecision]), $MachinePrecision], -500000.0], N[Exp[x], $MachinePrecision], N[(N[(y * y), $MachinePrecision] * N[(N[(x * N[(x * N[(y * y), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] * N[(x * N[(N[(y * y), $MachinePrecision] * 0.16666666666666666), $MachinePrecision] + 0.5), $MachinePrecision] + x), $MachinePrecision] + 1.0), $MachinePrecision]]
      
      \begin{array}{l}
      
      \\
      \begin{array}{l}
      \mathbf{if}\;y \cdot \left(x \cdot y\right) \leq -500000:\\
      \;\;\;\;e^{x}\\
      
      \mathbf{else}:\\
      \;\;\;\;\mathsf{fma}\left(y \cdot y, \mathsf{fma}\left(x \cdot \left(x \cdot \left(y \cdot y\right)\right), \mathsf{fma}\left(x, \left(y \cdot y\right) \cdot 0.16666666666666666, 0.5\right), x\right), 1\right)\\
      
      
      \end{array}
      \end{array}
      
      Derivation
      1. Split input into 2 regimes
      2. if (*.f64 (*.f64 x y) y) < -5e5

        1. Initial program 100.0%

          \[e^{\left(x \cdot y\right) \cdot y} \]
        2. Add Preprocessing
        3. Applied rewrites50.0%

          \[\leadsto e^{\color{blue}{x}} \]

        if -5e5 < (*.f64 (*.f64 x y) y)

        1. Initial program 99.9%

          \[e^{\left(x \cdot y\right) \cdot y} \]
        2. Add Preprocessing
        3. Taylor expanded in x around 0

          \[\leadsto \color{blue}{1 + x \cdot \left(x \cdot \left(\frac{1}{6} \cdot \left(x \cdot {y}^{6}\right) + \frac{1}{2} \cdot {y}^{4}\right) + {y}^{2}\right)} \]
        4. Applied rewrites94.6%

          \[\leadsto \color{blue}{\mathsf{fma}\left(y \cdot y, \mathsf{fma}\left(x \cdot \left(x \cdot \left(y \cdot y\right)\right), \mathsf{fma}\left(x, \left(y \cdot y\right) \cdot 0.16666666666666666, 0.5\right), x\right), 1\right)} \]
      3. Recombined 2 regimes into one program.
      4. Final simplification83.5%

        \[\leadsto \begin{array}{l} \mathbf{if}\;y \cdot \left(x \cdot y\right) \leq -500000:\\ \;\;\;\;e^{x}\\ \mathbf{else}:\\ \;\;\;\;\mathsf{fma}\left(y \cdot y, \mathsf{fma}\left(x \cdot \left(x \cdot \left(y \cdot y\right)\right), \mathsf{fma}\left(x, \left(y \cdot y\right) \cdot 0.16666666666666666, 0.5\right), x\right), 1\right)\\ \end{array} \]
      5. Add Preprocessing

      Alternative 5: 72.1% accurate, 2.3× speedup?

      \[\begin{array}{l} \\ \mathsf{fma}\left(y \cdot y, \mathsf{fma}\left(x \cdot \left(x \cdot \left(y \cdot y\right)\right), \mathsf{fma}\left(x, \left(y \cdot y\right) \cdot 0.16666666666666666, 0.5\right), x\right), 1\right) \end{array} \]
      (FPCore (x y)
       :precision binary64
       (fma
        (* y y)
        (fma (* x (* x (* y y))) (fma x (* (* y y) 0.16666666666666666) 0.5) x)
        1.0))
      double code(double x, double y) {
      	return fma((y * y), fma((x * (x * (y * y))), fma(x, ((y * y) * 0.16666666666666666), 0.5), x), 1.0);
      }
      
      function code(x, y)
      	return fma(Float64(y * y), fma(Float64(x * Float64(x * Float64(y * y))), fma(x, Float64(Float64(y * y) * 0.16666666666666666), 0.5), x), 1.0)
      end
      
      code[x_, y_] := N[(N[(y * y), $MachinePrecision] * N[(N[(x * N[(x * N[(y * y), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] * N[(x * N[(N[(y * y), $MachinePrecision] * 0.16666666666666666), $MachinePrecision] + 0.5), $MachinePrecision] + x), $MachinePrecision] + 1.0), $MachinePrecision]
      
      \begin{array}{l}
      
      \\
      \mathsf{fma}\left(y \cdot y, \mathsf{fma}\left(x \cdot \left(x \cdot \left(y \cdot y\right)\right), \mathsf{fma}\left(x, \left(y \cdot y\right) \cdot 0.16666666666666666, 0.5\right), x\right), 1\right)
      \end{array}
      
      Derivation
      1. Initial program 99.9%

        \[e^{\left(x \cdot y\right) \cdot y} \]
      2. Add Preprocessing
      3. Taylor expanded in x around 0

        \[\leadsto \color{blue}{1 + x \cdot \left(x \cdot \left(\frac{1}{6} \cdot \left(x \cdot {y}^{6}\right) + \frac{1}{2} \cdot {y}^{4}\right) + {y}^{2}\right)} \]
      4. Applied rewrites71.4%

        \[\leadsto \color{blue}{\mathsf{fma}\left(y \cdot y, \mathsf{fma}\left(x \cdot \left(x \cdot \left(y \cdot y\right)\right), \mathsf{fma}\left(x, \left(y \cdot y\right) \cdot 0.16666666666666666, 0.5\right), x\right), 1\right)} \]
      5. Add Preprocessing

      Alternative 6: 72.0% accurate, 2.3× speedup?

      \[\begin{array}{l} \\ \mathsf{fma}\left(y \cdot y, \mathsf{fma}\left(x \cdot \left(x \cdot \left(y \cdot y\right)\right), x \cdot \left(\left(y \cdot y\right) \cdot 0.16666666666666666\right), x\right), 1\right) \end{array} \]
      (FPCore (x y)
       :precision binary64
       (fma
        (* y y)
        (fma (* x (* x (* y y))) (* x (* (* y y) 0.16666666666666666)) x)
        1.0))
      double code(double x, double y) {
      	return fma((y * y), fma((x * (x * (y * y))), (x * ((y * y) * 0.16666666666666666)), x), 1.0);
      }
      
      function code(x, y)
      	return fma(Float64(y * y), fma(Float64(x * Float64(x * Float64(y * y))), Float64(x * Float64(Float64(y * y) * 0.16666666666666666)), x), 1.0)
      end
      
      code[x_, y_] := N[(N[(y * y), $MachinePrecision] * N[(N[(x * N[(x * N[(y * y), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] * N[(x * N[(N[(y * y), $MachinePrecision] * 0.16666666666666666), $MachinePrecision]), $MachinePrecision] + x), $MachinePrecision] + 1.0), $MachinePrecision]
      
      \begin{array}{l}
      
      \\
      \mathsf{fma}\left(y \cdot y, \mathsf{fma}\left(x \cdot \left(x \cdot \left(y \cdot y\right)\right), x \cdot \left(\left(y \cdot y\right) \cdot 0.16666666666666666\right), x\right), 1\right)
      \end{array}
      
      Derivation
      1. Initial program 99.9%

        \[e^{\left(x \cdot y\right) \cdot y} \]
      2. Add Preprocessing
      3. Taylor expanded in x around 0

        \[\leadsto \color{blue}{1 + x \cdot \left(x \cdot \left(\frac{1}{6} \cdot \left(x \cdot {y}^{6}\right) + \frac{1}{2} \cdot {y}^{4}\right) + {y}^{2}\right)} \]
      4. Applied rewrites71.4%

        \[\leadsto \color{blue}{\mathsf{fma}\left(y \cdot y, \mathsf{fma}\left(x \cdot \left(x \cdot \left(y \cdot y\right)\right), \mathsf{fma}\left(x, \left(y \cdot y\right) \cdot 0.16666666666666666, 0.5\right), x\right), 1\right)} \]
      5. Taylor expanded in x around inf

        \[\leadsto \mathsf{fma}\left(y \cdot y, \mathsf{fma}\left(x \cdot \left(x \cdot \left(y \cdot y\right)\right), \frac{1}{6} \cdot \color{blue}{\left(x \cdot {y}^{2}\right)}, x\right), 1\right) \]
      6. Step-by-step derivation
        1. Applied rewrites71.2%

          \[\leadsto \mathsf{fma}\left(y \cdot y, \mathsf{fma}\left(x \cdot \left(x \cdot \left(y \cdot y\right)\right), x \cdot \color{blue}{\left(\left(y \cdot y\right) \cdot 0.16666666666666666\right)}, x\right), 1\right) \]
        2. Add Preprocessing

        Alternative 7: 70.4% accurate, 2.4× speedup?

        \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;y \cdot \left(x \cdot y\right) \leq 10^{-11}:\\ \;\;\;\;1\\ \mathbf{else}:\\ \;\;\;\;0.5 \cdot \left(\left(y \cdot y\right) \cdot \left(y \cdot \left(x \cdot \left(x \cdot y\right)\right)\right)\right)\\ \end{array} \end{array} \]
        (FPCore (x y)
         :precision binary64
         (if (<= (* y (* x y)) 1e-11) 1.0 (* 0.5 (* (* y y) (* y (* x (* x y)))))))
        double code(double x, double y) {
        	double tmp;
        	if ((y * (x * y)) <= 1e-11) {
        		tmp = 1.0;
        	} else {
        		tmp = 0.5 * ((y * y) * (y * (x * (x * y))));
        	}
        	return tmp;
        }
        
        real(8) function code(x, y)
            real(8), intent (in) :: x
            real(8), intent (in) :: y
            real(8) :: tmp
            if ((y * (x * y)) <= 1d-11) then
                tmp = 1.0d0
            else
                tmp = 0.5d0 * ((y * y) * (y * (x * (x * y))))
            end if
            code = tmp
        end function
        
        public static double code(double x, double y) {
        	double tmp;
        	if ((y * (x * y)) <= 1e-11) {
        		tmp = 1.0;
        	} else {
        		tmp = 0.5 * ((y * y) * (y * (x * (x * y))));
        	}
        	return tmp;
        }
        
        def code(x, y):
        	tmp = 0
        	if (y * (x * y)) <= 1e-11:
        		tmp = 1.0
        	else:
        		tmp = 0.5 * ((y * y) * (y * (x * (x * y))))
        	return tmp
        
        function code(x, y)
        	tmp = 0.0
        	if (Float64(y * Float64(x * y)) <= 1e-11)
        		tmp = 1.0;
        	else
        		tmp = Float64(0.5 * Float64(Float64(y * y) * Float64(y * Float64(x * Float64(x * y)))));
        	end
        	return tmp
        end
        
        function tmp_2 = code(x, y)
        	tmp = 0.0;
        	if ((y * (x * y)) <= 1e-11)
        		tmp = 1.0;
        	else
        		tmp = 0.5 * ((y * y) * (y * (x * (x * y))));
        	end
        	tmp_2 = tmp;
        end
        
        code[x_, y_] := If[LessEqual[N[(y * N[(x * y), $MachinePrecision]), $MachinePrecision], 1e-11], 1.0, N[(0.5 * N[(N[(y * y), $MachinePrecision] * N[(y * N[(x * N[(x * y), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]]
        
        \begin{array}{l}
        
        \\
        \begin{array}{l}
        \mathbf{if}\;y \cdot \left(x \cdot y\right) \leq 10^{-11}:\\
        \;\;\;\;1\\
        
        \mathbf{else}:\\
        \;\;\;\;0.5 \cdot \left(\left(y \cdot y\right) \cdot \left(y \cdot \left(x \cdot \left(x \cdot y\right)\right)\right)\right)\\
        
        
        \end{array}
        \end{array}
        
        Derivation
        1. Split input into 2 regimes
        2. if (*.f64 (*.f64 x y) y) < 9.99999999999999939e-12

          1. Initial program 100.0%

            \[e^{\left(x \cdot y\right) \cdot y} \]
          2. Add Preprocessing
          3. Taylor expanded in x around 0

            \[\leadsto \color{blue}{1} \]
          4. Step-by-step derivation
            1. Applied rewrites66.9%

              \[\leadsto \color{blue}{1} \]

            if 9.99999999999999939e-12 < (*.f64 (*.f64 x y) y)

            1. Initial program 99.8%

              \[e^{\left(x \cdot y\right) \cdot y} \]
            2. Add Preprocessing
            3. Taylor expanded in x around 0

              \[\leadsto \color{blue}{1 + x \cdot \left(\frac{1}{2} \cdot \left(x \cdot {y}^{4}\right) + {y}^{2}\right)} \]
            4. Step-by-step derivation
              1. +-commutativeN/A

                \[\leadsto \color{blue}{x \cdot \left(\frac{1}{2} \cdot \left(x \cdot {y}^{4}\right) + {y}^{2}\right) + 1} \]
            5. Applied rewrites77.1%

              \[\leadsto \color{blue}{\mathsf{fma}\left(y \cdot y, \mathsf{fma}\left(x, \left(x \cdot \left(y \cdot y\right)\right) \cdot 0.5, x\right), 1\right)} \]
            6. Taylor expanded in y around inf

              \[\leadsto \frac{1}{2} \cdot \color{blue}{\left({x}^{2} \cdot {y}^{4}\right)} \]
            7. Step-by-step derivation
              1. Applied rewrites77.1%

                \[\leadsto \left(0.5 \cdot \left(y \cdot y\right)\right) \cdot \color{blue}{\left(x \cdot \left(x \cdot \left(y \cdot y\right)\right)\right)} \]
              2. Step-by-step derivation
                1. Applied rewrites79.8%

                  \[\leadsto \left(\left(y \cdot y\right) \cdot \left(y \cdot \left(x \cdot \left(x \cdot y\right)\right)\right)\right) \cdot 0.5 \]
              3. Recombined 2 regimes into one program.
              4. Final simplification70.2%

                \[\leadsto \begin{array}{l} \mathbf{if}\;y \cdot \left(x \cdot y\right) \leq 10^{-11}:\\ \;\;\;\;1\\ \mathbf{else}:\\ \;\;\;\;0.5 \cdot \left(\left(y \cdot y\right) \cdot \left(y \cdot \left(x \cdot \left(x \cdot y\right)\right)\right)\right)\\ \end{array} \]
              5. Add Preprocessing

              Alternative 8: 70.6% accurate, 2.4× speedup?

              \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;y \cdot \left(x \cdot y\right) \leq 10^{-11}:\\ \;\;\;\;1\\ \mathbf{else}:\\ \;\;\;\;\left(x \cdot \left(x \cdot \left(y \cdot y\right)\right)\right) \cdot \left(\left(y \cdot y\right) \cdot 0.5\right)\\ \end{array} \end{array} \]
              (FPCore (x y)
               :precision binary64
               (if (<= (* y (* x y)) 1e-11) 1.0 (* (* x (* x (* y y))) (* (* y y) 0.5))))
              double code(double x, double y) {
              	double tmp;
              	if ((y * (x * y)) <= 1e-11) {
              		tmp = 1.0;
              	} else {
              		tmp = (x * (x * (y * y))) * ((y * y) * 0.5);
              	}
              	return tmp;
              }
              
              real(8) function code(x, y)
                  real(8), intent (in) :: x
                  real(8), intent (in) :: y
                  real(8) :: tmp
                  if ((y * (x * y)) <= 1d-11) then
                      tmp = 1.0d0
                  else
                      tmp = (x * (x * (y * y))) * ((y * y) * 0.5d0)
                  end if
                  code = tmp
              end function
              
              public static double code(double x, double y) {
              	double tmp;
              	if ((y * (x * y)) <= 1e-11) {
              		tmp = 1.0;
              	} else {
              		tmp = (x * (x * (y * y))) * ((y * y) * 0.5);
              	}
              	return tmp;
              }
              
              def code(x, y):
              	tmp = 0
              	if (y * (x * y)) <= 1e-11:
              		tmp = 1.0
              	else:
              		tmp = (x * (x * (y * y))) * ((y * y) * 0.5)
              	return tmp
              
              function code(x, y)
              	tmp = 0.0
              	if (Float64(y * Float64(x * y)) <= 1e-11)
              		tmp = 1.0;
              	else
              		tmp = Float64(Float64(x * Float64(x * Float64(y * y))) * Float64(Float64(y * y) * 0.5));
              	end
              	return tmp
              end
              
              function tmp_2 = code(x, y)
              	tmp = 0.0;
              	if ((y * (x * y)) <= 1e-11)
              		tmp = 1.0;
              	else
              		tmp = (x * (x * (y * y))) * ((y * y) * 0.5);
              	end
              	tmp_2 = tmp;
              end
              
              code[x_, y_] := If[LessEqual[N[(y * N[(x * y), $MachinePrecision]), $MachinePrecision], 1e-11], 1.0, N[(N[(x * N[(x * N[(y * y), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] * N[(N[(y * y), $MachinePrecision] * 0.5), $MachinePrecision]), $MachinePrecision]]
              
              \begin{array}{l}
              
              \\
              \begin{array}{l}
              \mathbf{if}\;y \cdot \left(x \cdot y\right) \leq 10^{-11}:\\
              \;\;\;\;1\\
              
              \mathbf{else}:\\
              \;\;\;\;\left(x \cdot \left(x \cdot \left(y \cdot y\right)\right)\right) \cdot \left(\left(y \cdot y\right) \cdot 0.5\right)\\
              
              
              \end{array}
              \end{array}
              
              Derivation
              1. Split input into 2 regimes
              2. if (*.f64 (*.f64 x y) y) < 9.99999999999999939e-12

                1. Initial program 100.0%

                  \[e^{\left(x \cdot y\right) \cdot y} \]
                2. Add Preprocessing
                3. Taylor expanded in x around 0

                  \[\leadsto \color{blue}{1} \]
                4. Step-by-step derivation
                  1. Applied rewrites66.9%

                    \[\leadsto \color{blue}{1} \]

                  if 9.99999999999999939e-12 < (*.f64 (*.f64 x y) y)

                  1. Initial program 99.8%

                    \[e^{\left(x \cdot y\right) \cdot y} \]
                  2. Add Preprocessing
                  3. Taylor expanded in x around 0

                    \[\leadsto \color{blue}{1 + x \cdot \left(\frac{1}{2} \cdot \left(x \cdot {y}^{4}\right) + {y}^{2}\right)} \]
                  4. Step-by-step derivation
                    1. +-commutativeN/A

                      \[\leadsto \color{blue}{x \cdot \left(\frac{1}{2} \cdot \left(x \cdot {y}^{4}\right) + {y}^{2}\right) + 1} \]
                  5. Applied rewrites77.1%

                    \[\leadsto \color{blue}{\mathsf{fma}\left(y \cdot y, \mathsf{fma}\left(x, \left(x \cdot \left(y \cdot y\right)\right) \cdot 0.5, x\right), 1\right)} \]
                  6. Taylor expanded in y around inf

                    \[\leadsto \frac{1}{2} \cdot \color{blue}{\left({x}^{2} \cdot {y}^{4}\right)} \]
                  7. Step-by-step derivation
                    1. Applied rewrites77.1%

                      \[\leadsto \left(0.5 \cdot \left(y \cdot y\right)\right) \cdot \color{blue}{\left(x \cdot \left(x \cdot \left(y \cdot y\right)\right)\right)} \]
                  8. Recombined 2 regimes into one program.
                  9. Final simplification69.5%

                    \[\leadsto \begin{array}{l} \mathbf{if}\;y \cdot \left(x \cdot y\right) \leq 10^{-11}:\\ \;\;\;\;1\\ \mathbf{else}:\\ \;\;\;\;\left(x \cdot \left(x \cdot \left(y \cdot y\right)\right)\right) \cdot \left(\left(y \cdot y\right) \cdot 0.5\right)\\ \end{array} \]
                  10. Add Preprocessing

                  Alternative 9: 71.0% accurate, 2.4× speedup?

                  \[\begin{array}{l} \\ \mathsf{fma}\left(y \cdot y, \left(y \cdot y\right) \cdot \left(0.16666666666666666 \cdot \left(x \cdot \left(x \cdot \left(x \cdot \left(y \cdot y\right)\right)\right)\right)\right), 1\right) \end{array} \]
                  (FPCore (x y)
                   :precision binary64
                   (fma
                    (* y y)
                    (* (* y y) (* 0.16666666666666666 (* x (* x (* x (* y y))))))
                    1.0))
                  double code(double x, double y) {
                  	return fma((y * y), ((y * y) * (0.16666666666666666 * (x * (x * (x * (y * y)))))), 1.0);
                  }
                  
                  function code(x, y)
                  	return fma(Float64(y * y), Float64(Float64(y * y) * Float64(0.16666666666666666 * Float64(x * Float64(x * Float64(x * Float64(y * y)))))), 1.0)
                  end
                  
                  code[x_, y_] := N[(N[(y * y), $MachinePrecision] * N[(N[(y * y), $MachinePrecision] * N[(0.16666666666666666 * N[(x * N[(x * N[(x * N[(y * y), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] + 1.0), $MachinePrecision]
                  
                  \begin{array}{l}
                  
                  \\
                  \mathsf{fma}\left(y \cdot y, \left(y \cdot y\right) \cdot \left(0.16666666666666666 \cdot \left(x \cdot \left(x \cdot \left(x \cdot \left(y \cdot y\right)\right)\right)\right)\right), 1\right)
                  \end{array}
                  
                  Derivation
                  1. Initial program 99.9%

                    \[e^{\left(x \cdot y\right) \cdot y} \]
                  2. Add Preprocessing
                  3. Taylor expanded in x around 0

                    \[\leadsto \color{blue}{1 + x \cdot \left(x \cdot \left(\frac{1}{6} \cdot \left(x \cdot {y}^{6}\right) + \frac{1}{2} \cdot {y}^{4}\right) + {y}^{2}\right)} \]
                  4. Applied rewrites71.4%

                    \[\leadsto \color{blue}{\mathsf{fma}\left(y \cdot y, \mathsf{fma}\left(x \cdot \left(x \cdot \left(y \cdot y\right)\right), \mathsf{fma}\left(x, \left(y \cdot y\right) \cdot 0.16666666666666666, 0.5\right), x\right), 1\right)} \]
                  5. Taylor expanded in x around inf

                    \[\leadsto \mathsf{fma}\left(y \cdot y, \frac{1}{6} \cdot \color{blue}{\left({x}^{3} \cdot {y}^{4}\right)}, 1\right) \]
                  6. Step-by-step derivation
                    1. Applied rewrites70.3%

                      \[\leadsto \mathsf{fma}\left(y \cdot y, \left(y \cdot y\right) \cdot \color{blue}{\left(0.16666666666666666 \cdot \left(x \cdot \left(x \cdot \left(x \cdot \left(y \cdot y\right)\right)\right)\right)\right)}, 1\right) \]
                    2. Add Preprocessing

                    Alternative 10: 69.3% accurate, 2.8× speedup?

                    \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;y \cdot \left(x \cdot y\right) \leq 10^{-11}:\\ \;\;\;\;1\\ \mathbf{else}:\\ \;\;\;\;\mathsf{fma}\left(x, \mathsf{fma}\left(x, \left(y \cdot y\right) \cdot 0.5, y\right), 1\right)\\ \end{array} \end{array} \]
                    (FPCore (x y)
                     :precision binary64
                     (if (<= (* y (* x y)) 1e-11) 1.0 (fma x (fma x (* (* y y) 0.5) y) 1.0)))
                    double code(double x, double y) {
                    	double tmp;
                    	if ((y * (x * y)) <= 1e-11) {
                    		tmp = 1.0;
                    	} else {
                    		tmp = fma(x, fma(x, ((y * y) * 0.5), y), 1.0);
                    	}
                    	return tmp;
                    }
                    
                    function code(x, y)
                    	tmp = 0.0
                    	if (Float64(y * Float64(x * y)) <= 1e-11)
                    		tmp = 1.0;
                    	else
                    		tmp = fma(x, fma(x, Float64(Float64(y * y) * 0.5), y), 1.0);
                    	end
                    	return tmp
                    end
                    
                    code[x_, y_] := If[LessEqual[N[(y * N[(x * y), $MachinePrecision]), $MachinePrecision], 1e-11], 1.0, N[(x * N[(x * N[(N[(y * y), $MachinePrecision] * 0.5), $MachinePrecision] + y), $MachinePrecision] + 1.0), $MachinePrecision]]
                    
                    \begin{array}{l}
                    
                    \\
                    \begin{array}{l}
                    \mathbf{if}\;y \cdot \left(x \cdot y\right) \leq 10^{-11}:\\
                    \;\;\;\;1\\
                    
                    \mathbf{else}:\\
                    \;\;\;\;\mathsf{fma}\left(x, \mathsf{fma}\left(x, \left(y \cdot y\right) \cdot 0.5, y\right), 1\right)\\
                    
                    
                    \end{array}
                    \end{array}
                    
                    Derivation
                    1. Split input into 2 regimes
                    2. if (*.f64 (*.f64 x y) y) < 9.99999999999999939e-12

                      1. Initial program 100.0%

                        \[e^{\left(x \cdot y\right) \cdot y} \]
                      2. Add Preprocessing
                      3. Taylor expanded in x around 0

                        \[\leadsto \color{blue}{1} \]
                      4. Step-by-step derivation
                        1. Applied rewrites66.9%

                          \[\leadsto \color{blue}{1} \]

                        if 9.99999999999999939e-12 < (*.f64 (*.f64 x y) y)

                        1. Initial program 99.8%

                          \[e^{\left(x \cdot y\right) \cdot y} \]
                        2. Add Preprocessing
                        3. Applied rewrites43.9%

                          \[\leadsto e^{\color{blue}{x} \cdot y} \]
                        4. Taylor expanded in x around 0

                          \[\leadsto \color{blue}{1 + x \cdot \left(y + \frac{1}{2} \cdot \left(x \cdot {y}^{2}\right)\right)} \]
                        5. Step-by-step derivation
                          1. +-commutativeN/A

                            \[\leadsto \color{blue}{x \cdot \left(y + \frac{1}{2} \cdot \left(x \cdot {y}^{2}\right)\right) + 1} \]
                          2. +-commutativeN/A

                            \[\leadsto x \cdot \color{blue}{\left(\frac{1}{2} \cdot \left(x \cdot {y}^{2}\right) + y\right)} + 1 \]
                          3. *-commutativeN/A

                            \[\leadsto x \cdot \left(\frac{1}{2} \cdot \color{blue}{\left({y}^{2} \cdot x\right)} + y\right) + 1 \]
                          4. associate-*r*N/A

                            \[\leadsto x \cdot \left(\color{blue}{\left(\frac{1}{2} \cdot {y}^{2}\right) \cdot x} + y\right) + 1 \]
                          5. lower-fma.f64N/A

                            \[\leadsto \color{blue}{\mathsf{fma}\left(x, \left(\frac{1}{2} \cdot {y}^{2}\right) \cdot x + y, 1\right)} \]
                          6. *-commutativeN/A

                            \[\leadsto \mathsf{fma}\left(x, \color{blue}{x \cdot \left(\frac{1}{2} \cdot {y}^{2}\right)} + y, 1\right) \]
                          7. lower-fma.f64N/A

                            \[\leadsto \mathsf{fma}\left(x, \color{blue}{\mathsf{fma}\left(x, \frac{1}{2} \cdot {y}^{2}, y\right)}, 1\right) \]
                          8. lower-*.f64N/A

                            \[\leadsto \mathsf{fma}\left(x, \mathsf{fma}\left(x, \color{blue}{\frac{1}{2} \cdot {y}^{2}}, y\right), 1\right) \]
                          9. unpow2N/A

                            \[\leadsto \mathsf{fma}\left(x, \mathsf{fma}\left(x, \frac{1}{2} \cdot \color{blue}{\left(y \cdot y\right)}, y\right), 1\right) \]
                          10. lower-*.f6473.1

                            \[\leadsto \mathsf{fma}\left(x, \mathsf{fma}\left(x, 0.5 \cdot \color{blue}{\left(y \cdot y\right)}, y\right), 1\right) \]
                        6. Applied rewrites73.1%

                          \[\leadsto \color{blue}{\mathsf{fma}\left(x, \mathsf{fma}\left(x, 0.5 \cdot \left(y \cdot y\right), y\right), 1\right)} \]
                      5. Recombined 2 regimes into one program.
                      6. Final simplification68.5%

                        \[\leadsto \begin{array}{l} \mathbf{if}\;y \cdot \left(x \cdot y\right) \leq 10^{-11}:\\ \;\;\;\;1\\ \mathbf{else}:\\ \;\;\;\;\mathsf{fma}\left(x, \mathsf{fma}\left(x, \left(y \cdot y\right) \cdot 0.5, y\right), 1\right)\\ \end{array} \]
                      7. Add Preprocessing

                      Alternative 11: 70.7% accurate, 3.4× speedup?

                      \[\begin{array}{l} \\ \mathsf{fma}\left(y \cdot y, \mathsf{fma}\left(x, \left(x \cdot \left(y \cdot y\right)\right) \cdot 0.5, x\right), 1\right) \end{array} \]
                      (FPCore (x y)
                       :precision binary64
                       (fma (* y y) (fma x (* (* x (* y y)) 0.5) x) 1.0))
                      double code(double x, double y) {
                      	return fma((y * y), fma(x, ((x * (y * y)) * 0.5), x), 1.0);
                      }
                      
                      function code(x, y)
                      	return fma(Float64(y * y), fma(x, Float64(Float64(x * Float64(y * y)) * 0.5), x), 1.0)
                      end
                      
                      code[x_, y_] := N[(N[(y * y), $MachinePrecision] * N[(x * N[(N[(x * N[(y * y), $MachinePrecision]), $MachinePrecision] * 0.5), $MachinePrecision] + x), $MachinePrecision] + 1.0), $MachinePrecision]
                      
                      \begin{array}{l}
                      
                      \\
                      \mathsf{fma}\left(y \cdot y, \mathsf{fma}\left(x, \left(x \cdot \left(y \cdot y\right)\right) \cdot 0.5, x\right), 1\right)
                      \end{array}
                      
                      Derivation
                      1. Initial program 99.9%

                        \[e^{\left(x \cdot y\right) \cdot y} \]
                      2. Add Preprocessing
                      3. Taylor expanded in x around 0

                        \[\leadsto \color{blue}{1 + x \cdot \left(\frac{1}{2} \cdot \left(x \cdot {y}^{4}\right) + {y}^{2}\right)} \]
                      4. Step-by-step derivation
                        1. +-commutativeN/A

                          \[\leadsto \color{blue}{x \cdot \left(\frac{1}{2} \cdot \left(x \cdot {y}^{4}\right) + {y}^{2}\right) + 1} \]
                      5. Applied rewrites69.4%

                        \[\leadsto \color{blue}{\mathsf{fma}\left(y \cdot y, \mathsf{fma}\left(x, \left(x \cdot \left(y \cdot y\right)\right) \cdot 0.5, x\right), 1\right)} \]
                      6. Add Preprocessing

                      Alternative 12: 54.0% accurate, 4.8× speedup?

                      \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;y \cdot \left(x \cdot y\right) \leq 10^{-11}:\\ \;\;\;\;1\\ \mathbf{else}:\\ \;\;\;\;\mathsf{fma}\left(x, y, 1\right)\\ \end{array} \end{array} \]
                      (FPCore (x y)
                       :precision binary64
                       (if (<= (* y (* x y)) 1e-11) 1.0 (fma x y 1.0)))
                      double code(double x, double y) {
                      	double tmp;
                      	if ((y * (x * y)) <= 1e-11) {
                      		tmp = 1.0;
                      	} else {
                      		tmp = fma(x, y, 1.0);
                      	}
                      	return tmp;
                      }
                      
                      function code(x, y)
                      	tmp = 0.0
                      	if (Float64(y * Float64(x * y)) <= 1e-11)
                      		tmp = 1.0;
                      	else
                      		tmp = fma(x, y, 1.0);
                      	end
                      	return tmp
                      end
                      
                      code[x_, y_] := If[LessEqual[N[(y * N[(x * y), $MachinePrecision]), $MachinePrecision], 1e-11], 1.0, N[(x * y + 1.0), $MachinePrecision]]
                      
                      \begin{array}{l}
                      
                      \\
                      \begin{array}{l}
                      \mathbf{if}\;y \cdot \left(x \cdot y\right) \leq 10^{-11}:\\
                      \;\;\;\;1\\
                      
                      \mathbf{else}:\\
                      \;\;\;\;\mathsf{fma}\left(x, y, 1\right)\\
                      
                      
                      \end{array}
                      \end{array}
                      
                      Derivation
                      1. Split input into 2 regimes
                      2. if (*.f64 (*.f64 x y) y) < 9.99999999999999939e-12

                        1. Initial program 100.0%

                          \[e^{\left(x \cdot y\right) \cdot y} \]
                        2. Add Preprocessing
                        3. Taylor expanded in x around 0

                          \[\leadsto \color{blue}{1} \]
                        4. Step-by-step derivation
                          1. Applied rewrites66.9%

                            \[\leadsto \color{blue}{1} \]

                          if 9.99999999999999939e-12 < (*.f64 (*.f64 x y) y)

                          1. Initial program 99.8%

                            \[e^{\left(x \cdot y\right) \cdot y} \]
                          2. Add Preprocessing
                          3. Applied rewrites43.9%

                            \[\leadsto e^{\color{blue}{x} \cdot y} \]
                          4. Taylor expanded in x around 0

                            \[\leadsto \color{blue}{1 + x \cdot y} \]
                          5. Step-by-step derivation
                            1. +-commutativeN/A

                              \[\leadsto \color{blue}{x \cdot y + 1} \]
                            2. lower-fma.f6418.9

                              \[\leadsto \color{blue}{\mathsf{fma}\left(x, y, 1\right)} \]
                          6. Applied rewrites18.9%

                            \[\leadsto \color{blue}{\mathsf{fma}\left(x, y, 1\right)} \]
                        5. Recombined 2 regimes into one program.
                        6. Final simplification54.5%

                          \[\leadsto \begin{array}{l} \mathbf{if}\;y \cdot \left(x \cdot y\right) \leq 10^{-11}:\\ \;\;\;\;1\\ \mathbf{else}:\\ \;\;\;\;\mathsf{fma}\left(x, y, 1\right)\\ \end{array} \]
                        7. Add Preprocessing

                        Alternative 13: 54.1% accurate, 5.0× speedup?

                        \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;y \cdot \left(x \cdot y\right) \leq 20:\\ \;\;\;\;1\\ \mathbf{else}:\\ \;\;\;\;x \cdot y\\ \end{array} \end{array} \]
                        (FPCore (x y) :precision binary64 (if (<= (* y (* x y)) 20.0) 1.0 (* x y)))
                        double code(double x, double y) {
                        	double tmp;
                        	if ((y * (x * y)) <= 20.0) {
                        		tmp = 1.0;
                        	} else {
                        		tmp = x * y;
                        	}
                        	return tmp;
                        }
                        
                        real(8) function code(x, y)
                            real(8), intent (in) :: x
                            real(8), intent (in) :: y
                            real(8) :: tmp
                            if ((y * (x * y)) <= 20.0d0) then
                                tmp = 1.0d0
                            else
                                tmp = x * y
                            end if
                            code = tmp
                        end function
                        
                        public static double code(double x, double y) {
                        	double tmp;
                        	if ((y * (x * y)) <= 20.0) {
                        		tmp = 1.0;
                        	} else {
                        		tmp = x * y;
                        	}
                        	return tmp;
                        }
                        
                        def code(x, y):
                        	tmp = 0
                        	if (y * (x * y)) <= 20.0:
                        		tmp = 1.0
                        	else:
                        		tmp = x * y
                        	return tmp
                        
                        function code(x, y)
                        	tmp = 0.0
                        	if (Float64(y * Float64(x * y)) <= 20.0)
                        		tmp = 1.0;
                        	else
                        		tmp = Float64(x * y);
                        	end
                        	return tmp
                        end
                        
                        function tmp_2 = code(x, y)
                        	tmp = 0.0;
                        	if ((y * (x * y)) <= 20.0)
                        		tmp = 1.0;
                        	else
                        		tmp = x * y;
                        	end
                        	tmp_2 = tmp;
                        end
                        
                        code[x_, y_] := If[LessEqual[N[(y * N[(x * y), $MachinePrecision]), $MachinePrecision], 20.0], 1.0, N[(x * y), $MachinePrecision]]
                        
                        \begin{array}{l}
                        
                        \\
                        \begin{array}{l}
                        \mathbf{if}\;y \cdot \left(x \cdot y\right) \leq 20:\\
                        \;\;\;\;1\\
                        
                        \mathbf{else}:\\
                        \;\;\;\;x \cdot y\\
                        
                        
                        \end{array}
                        \end{array}
                        
                        Derivation
                        1. Split input into 2 regimes
                        2. if (*.f64 (*.f64 x y) y) < 20

                          1. Initial program 100.0%

                            \[e^{\left(x \cdot y\right) \cdot y} \]
                          2. Add Preprocessing
                          3. Taylor expanded in x around 0

                            \[\leadsto \color{blue}{1} \]
                          4. Step-by-step derivation
                            1. Applied rewrites66.6%

                              \[\leadsto \color{blue}{1} \]

                            if 20 < (*.f64 (*.f64 x y) y)

                            1. Initial program 99.8%

                              \[e^{\left(x \cdot y\right) \cdot y} \]
                            2. Add Preprocessing
                            3. Applied rewrites44.4%

                              \[\leadsto e^{\color{blue}{x} \cdot y} \]
                            4. Taylor expanded in x around 0

                              \[\leadsto \color{blue}{1 + x \cdot y} \]
                            5. Step-by-step derivation
                              1. +-commutativeN/A

                                \[\leadsto \color{blue}{x \cdot y + 1} \]
                              2. lower-fma.f6419.0

                                \[\leadsto \color{blue}{\mathsf{fma}\left(x, y, 1\right)} \]
                            6. Applied rewrites19.0%

                              \[\leadsto \color{blue}{\mathsf{fma}\left(x, y, 1\right)} \]
                            7. Taylor expanded in x around inf

                              \[\leadsto x \cdot \color{blue}{y} \]
                            8. Step-by-step derivation
                              1. Applied rewrites18.8%

                                \[\leadsto x \cdot \color{blue}{y} \]
                            9. Recombined 2 regimes into one program.
                            10. Final simplification54.5%

                              \[\leadsto \begin{array}{l} \mathbf{if}\;y \cdot \left(x \cdot y\right) \leq 20:\\ \;\;\;\;1\\ \mathbf{else}:\\ \;\;\;\;x \cdot y\\ \end{array} \]
                            11. Add Preprocessing

                            Alternative 14: 66.2% accurate, 9.3× speedup?

                            \[\begin{array}{l} \\ \mathsf{fma}\left(x, y \cdot y, 1\right) \end{array} \]
                            (FPCore (x y) :precision binary64 (fma x (* y y) 1.0))
                            double code(double x, double y) {
                            	return fma(x, (y * y), 1.0);
                            }
                            
                            function code(x, y)
                            	return fma(x, Float64(y * y), 1.0)
                            end
                            
                            code[x_, y_] := N[(x * N[(y * y), $MachinePrecision] + 1.0), $MachinePrecision]
                            
                            \begin{array}{l}
                            
                            \\
                            \mathsf{fma}\left(x, y \cdot y, 1\right)
                            \end{array}
                            
                            Derivation
                            1. Initial program 99.9%

                              \[e^{\left(x \cdot y\right) \cdot y} \]
                            2. Add Preprocessing
                            3. Taylor expanded in x around 0

                              \[\leadsto \color{blue}{1 + x \cdot {y}^{2}} \]
                            4. Step-by-step derivation
                              1. +-commutativeN/A

                                \[\leadsto \color{blue}{x \cdot {y}^{2} + 1} \]
                              2. lower-fma.f64N/A

                                \[\leadsto \color{blue}{\mathsf{fma}\left(x, {y}^{2}, 1\right)} \]
                              3. unpow2N/A

                                \[\leadsto \mathsf{fma}\left(x, \color{blue}{y \cdot y}, 1\right) \]
                              4. lower-*.f6465.6

                                \[\leadsto \mathsf{fma}\left(x, \color{blue}{y \cdot y}, 1\right) \]
                            5. Applied rewrites65.6%

                              \[\leadsto \color{blue}{\mathsf{fma}\left(x, y \cdot y, 1\right)} \]
                            6. Add Preprocessing

                            Alternative 15: 51.0% accurate, 111.0× speedup?

                            \[\begin{array}{l} \\ 1 \end{array} \]
                            (FPCore (x y) :precision binary64 1.0)
                            double code(double x, double y) {
                            	return 1.0;
                            }
                            
                            real(8) function code(x, y)
                                real(8), intent (in) :: x
                                real(8), intent (in) :: y
                                code = 1.0d0
                            end function
                            
                            public static double code(double x, double y) {
                            	return 1.0;
                            }
                            
                            def code(x, y):
                            	return 1.0
                            
                            function code(x, y)
                            	return 1.0
                            end
                            
                            function tmp = code(x, y)
                            	tmp = 1.0;
                            end
                            
                            code[x_, y_] := 1.0
                            
                            \begin{array}{l}
                            
                            \\
                            1
                            \end{array}
                            
                            Derivation
                            1. Initial program 99.9%

                              \[e^{\left(x \cdot y\right) \cdot y} \]
                            2. Add Preprocessing
                            3. Taylor expanded in x around 0

                              \[\leadsto \color{blue}{1} \]
                            4. Step-by-step derivation
                              1. Applied rewrites50.5%

                                \[\leadsto \color{blue}{1} \]
                              2. Add Preprocessing

                              Reproduce

                              ?
                              herbie shell --seed 2024238 
                              (FPCore (x y)
                                :name "Data.Random.Distribution.Normal:normalF from random-fu-0.2.6.2"
                                :precision binary64
                                (exp (* (* x y) y)))