2nthrt (problem 3.4.6)

Percentage Accurate: 52.6% → 85.2%
Time: 25.7s
Alternatives: 13
Speedup: 1.9×

Specification

?
\[\begin{array}{l} \\ {\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \end{array} \]
(FPCore (x n)
 :precision binary64
 (- (pow (+ x 1.0) (/ 1.0 n)) (pow x (/ 1.0 n))))
double code(double x, double n) {
	return pow((x + 1.0), (1.0 / n)) - pow(x, (1.0 / n));
}
real(8) function code(x, n)
    real(8), intent (in) :: x
    real(8), intent (in) :: n
    code = ((x + 1.0d0) ** (1.0d0 / n)) - (x ** (1.0d0 / n))
end function
public static double code(double x, double n) {
	return Math.pow((x + 1.0), (1.0 / n)) - Math.pow(x, (1.0 / n));
}
def code(x, n):
	return math.pow((x + 1.0), (1.0 / n)) - math.pow(x, (1.0 / n))
function code(x, n)
	return Float64((Float64(x + 1.0) ^ Float64(1.0 / n)) - (x ^ Float64(1.0 / n)))
end
function tmp = code(x, n)
	tmp = ((x + 1.0) ^ (1.0 / n)) - (x ^ (1.0 / n));
end
code[x_, n_] := N[(N[Power[N[(x + 1.0), $MachinePrecision], N[(1.0 / n), $MachinePrecision]], $MachinePrecision] - N[Power[x, N[(1.0 / n), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)}
\end{array}

Sampling outcomes in binary64 precision:

Local Percentage Accuracy vs ?

The average percentage accuracy by input value. Horizontal axis shows value of an input variable; the variable is choosen in the title. Vertical axis is accuracy; higher is better. Red represent the original program, while blue represents Herbie's suggestion. These can be toggled with buttons below the plot. The line is an average while dots represent individual samples.

Accuracy vs Speed?

Herbie found 13 alternatives:

AlternativeAccuracySpeedup
The accuracy (vertical axis) and speed (horizontal axis) of each alternatives. Up and to the right is better. The red square shows the initial program, and each blue circle shows an alternative.The line shows the best available speed-accuracy tradeoffs.

Initial Program: 52.6% accurate, 1.0× speedup?

\[\begin{array}{l} \\ {\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \end{array} \]
(FPCore (x n)
 :precision binary64
 (- (pow (+ x 1.0) (/ 1.0 n)) (pow x (/ 1.0 n))))
double code(double x, double n) {
	return pow((x + 1.0), (1.0 / n)) - pow(x, (1.0 / n));
}
real(8) function code(x, n)
    real(8), intent (in) :: x
    real(8), intent (in) :: n
    code = ((x + 1.0d0) ** (1.0d0 / n)) - (x ** (1.0d0 / n))
end function
public static double code(double x, double n) {
	return Math.pow((x + 1.0), (1.0 / n)) - Math.pow(x, (1.0 / n));
}
def code(x, n):
	return math.pow((x + 1.0), (1.0 / n)) - math.pow(x, (1.0 / n))
function code(x, n)
	return Float64((Float64(x + 1.0) ^ Float64(1.0 / n)) - (x ^ Float64(1.0 / n)))
end
function tmp = code(x, n)
	tmp = ((x + 1.0) ^ (1.0 / n)) - (x ^ (1.0 / n));
end
code[x_, n_] := N[(N[Power[N[(x + 1.0), $MachinePrecision], N[(1.0 / n), $MachinePrecision]], $MachinePrecision] - N[Power[x, N[(1.0 / n), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)}
\end{array}

Alternative 1: 85.2% accurate, 0.8× speedup?

\[\begin{array}{l} \\ \begin{array}{l} t_0 := {x}^{\left(\frac{1}{n}\right)}\\ \mathbf{if}\;\frac{1}{n} \leq -5 \cdot 10^{-19}:\\ \;\;\;\;\frac{t\_0}{x \cdot n}\\ \mathbf{elif}\;\frac{1}{n} \leq 10^{-107}:\\ \;\;\;\;\frac{\mathsf{log1p}\left(x\right) - \log x}{n}\\ \mathbf{elif}\;\frac{1}{n} \leq 10^{-6}:\\ \;\;\;\;\frac{\frac{t\_0}{x}}{n}\\ \mathbf{else}:\\ \;\;\;\;e^{\frac{x}{n}} - t\_0\\ \end{array} \end{array} \]
(FPCore (x n)
 :precision binary64
 (let* ((t_0 (pow x (/ 1.0 n))))
   (if (<= (/ 1.0 n) -5e-19)
     (/ t_0 (* x n))
     (if (<= (/ 1.0 n) 1e-107)
       (/ (- (log1p x) (log x)) n)
       (if (<= (/ 1.0 n) 1e-6) (/ (/ t_0 x) n) (- (exp (/ x n)) t_0))))))
double code(double x, double n) {
	double t_0 = pow(x, (1.0 / n));
	double tmp;
	if ((1.0 / n) <= -5e-19) {
		tmp = t_0 / (x * n);
	} else if ((1.0 / n) <= 1e-107) {
		tmp = (log1p(x) - log(x)) / n;
	} else if ((1.0 / n) <= 1e-6) {
		tmp = (t_0 / x) / n;
	} else {
		tmp = exp((x / n)) - t_0;
	}
	return tmp;
}
public static double code(double x, double n) {
	double t_0 = Math.pow(x, (1.0 / n));
	double tmp;
	if ((1.0 / n) <= -5e-19) {
		tmp = t_0 / (x * n);
	} else if ((1.0 / n) <= 1e-107) {
		tmp = (Math.log1p(x) - Math.log(x)) / n;
	} else if ((1.0 / n) <= 1e-6) {
		tmp = (t_0 / x) / n;
	} else {
		tmp = Math.exp((x / n)) - t_0;
	}
	return tmp;
}
def code(x, n):
	t_0 = math.pow(x, (1.0 / n))
	tmp = 0
	if (1.0 / n) <= -5e-19:
		tmp = t_0 / (x * n)
	elif (1.0 / n) <= 1e-107:
		tmp = (math.log1p(x) - math.log(x)) / n
	elif (1.0 / n) <= 1e-6:
		tmp = (t_0 / x) / n
	else:
		tmp = math.exp((x / n)) - t_0
	return tmp
function code(x, n)
	t_0 = x ^ Float64(1.0 / n)
	tmp = 0.0
	if (Float64(1.0 / n) <= -5e-19)
		tmp = Float64(t_0 / Float64(x * n));
	elseif (Float64(1.0 / n) <= 1e-107)
		tmp = Float64(Float64(log1p(x) - log(x)) / n);
	elseif (Float64(1.0 / n) <= 1e-6)
		tmp = Float64(Float64(t_0 / x) / n);
	else
		tmp = Float64(exp(Float64(x / n)) - t_0);
	end
	return tmp
end
code[x_, n_] := Block[{t$95$0 = N[Power[x, N[(1.0 / n), $MachinePrecision]], $MachinePrecision]}, If[LessEqual[N[(1.0 / n), $MachinePrecision], -5e-19], N[(t$95$0 / N[(x * n), $MachinePrecision]), $MachinePrecision], If[LessEqual[N[(1.0 / n), $MachinePrecision], 1e-107], N[(N[(N[Log[1 + x], $MachinePrecision] - N[Log[x], $MachinePrecision]), $MachinePrecision] / n), $MachinePrecision], If[LessEqual[N[(1.0 / n), $MachinePrecision], 1e-6], N[(N[(t$95$0 / x), $MachinePrecision] / n), $MachinePrecision], N[(N[Exp[N[(x / n), $MachinePrecision]], $MachinePrecision] - t$95$0), $MachinePrecision]]]]]
\begin{array}{l}

\\
\begin{array}{l}
t_0 := {x}^{\left(\frac{1}{n}\right)}\\
\mathbf{if}\;\frac{1}{n} \leq -5 \cdot 10^{-19}:\\
\;\;\;\;\frac{t\_0}{x \cdot n}\\

\mathbf{elif}\;\frac{1}{n} \leq 10^{-107}:\\
\;\;\;\;\frac{\mathsf{log1p}\left(x\right) - \log x}{n}\\

\mathbf{elif}\;\frac{1}{n} \leq 10^{-6}:\\
\;\;\;\;\frac{\frac{t\_0}{x}}{n}\\

\mathbf{else}:\\
\;\;\;\;e^{\frac{x}{n}} - t\_0\\


\end{array}
\end{array}
Derivation
  1. Split input into 4 regimes
  2. if (/.f64 #s(literal 1 binary64) n) < -5.0000000000000004e-19

    1. Initial program 94.5%

      \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
    2. Add Preprocessing
    3. Taylor expanded in x around inf

      \[\leadsto \color{blue}{\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{n \cdot x}} \]
    4. Step-by-step derivation
      1. lower-/.f64N/A

        \[\leadsto \color{blue}{\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{n \cdot x}} \]
      2. log-recN/A

        \[\leadsto \frac{e^{-1 \cdot \frac{\color{blue}{\mathsf{neg}\left(\log x\right)}}{n}}}{n \cdot x} \]
      3. mul-1-negN/A

        \[\leadsto \frac{e^{-1 \cdot \frac{\color{blue}{-1 \cdot \log x}}{n}}}{n \cdot x} \]
      4. associate-*r/N/A

        \[\leadsto \frac{e^{\color{blue}{\frac{-1 \cdot \left(-1 \cdot \log x\right)}{n}}}}{n \cdot x} \]
      5. associate-*r*N/A

        \[\leadsto \frac{e^{\frac{\color{blue}{\left(-1 \cdot -1\right) \cdot \log x}}{n}}}{n \cdot x} \]
      6. metadata-evalN/A

        \[\leadsto \frac{e^{\frac{\color{blue}{1} \cdot \log x}{n}}}{n \cdot x} \]
      7. *-commutativeN/A

        \[\leadsto \frac{e^{\frac{\color{blue}{\log x \cdot 1}}{n}}}{n \cdot x} \]
      8. associate-/l*N/A

        \[\leadsto \frac{e^{\color{blue}{\log x \cdot \frac{1}{n}}}}{n \cdot x} \]
      9. exp-to-powN/A

        \[\leadsto \frac{\color{blue}{{x}^{\left(\frac{1}{n}\right)}}}{n \cdot x} \]
      10. lower-pow.f64N/A

        \[\leadsto \frac{\color{blue}{{x}^{\left(\frac{1}{n}\right)}}}{n \cdot x} \]
      11. lower-/.f64N/A

        \[\leadsto \frac{{x}^{\color{blue}{\left(\frac{1}{n}\right)}}}{n \cdot x} \]
      12. *-commutativeN/A

        \[\leadsto \frac{{x}^{\left(\frac{1}{n}\right)}}{\color{blue}{x \cdot n}} \]
      13. lower-*.f6497.6

        \[\leadsto \frac{{x}^{\left(\frac{1}{n}\right)}}{\color{blue}{x \cdot n}} \]
    5. Applied rewrites97.6%

      \[\leadsto \color{blue}{\frac{{x}^{\left(\frac{1}{n}\right)}}{x \cdot n}} \]

    if -5.0000000000000004e-19 < (/.f64 #s(literal 1 binary64) n) < 1e-107

    1. Initial program 37.4%

      \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
    2. Add Preprocessing
    3. Taylor expanded in n around inf

      \[\leadsto \color{blue}{\frac{\log \left(1 + x\right) - \log x}{n}} \]
    4. Step-by-step derivation
      1. lower-/.f64N/A

        \[\leadsto \color{blue}{\frac{\log \left(1 + x\right) - \log x}{n}} \]
      2. lower--.f64N/A

        \[\leadsto \frac{\color{blue}{\log \left(1 + x\right) - \log x}}{n} \]
      3. lower-log1p.f64N/A

        \[\leadsto \frac{\color{blue}{\mathsf{log1p}\left(x\right)} - \log x}{n} \]
      4. lower-log.f6484.9

        \[\leadsto \frac{\mathsf{log1p}\left(x\right) - \color{blue}{\log x}}{n} \]
    5. Applied rewrites84.9%

      \[\leadsto \color{blue}{\frac{\mathsf{log1p}\left(x\right) - \log x}{n}} \]

    if 1e-107 < (/.f64 #s(literal 1 binary64) n) < 9.99999999999999955e-7

    1. Initial program 15.9%

      \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
    2. Add Preprocessing
    3. Taylor expanded in x around inf

      \[\leadsto \color{blue}{\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{n \cdot x}} \]
    4. Step-by-step derivation
      1. lower-/.f64N/A

        \[\leadsto \color{blue}{\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{n \cdot x}} \]
      2. log-recN/A

        \[\leadsto \frac{e^{-1 \cdot \frac{\color{blue}{\mathsf{neg}\left(\log x\right)}}{n}}}{n \cdot x} \]
      3. mul-1-negN/A

        \[\leadsto \frac{e^{-1 \cdot \frac{\color{blue}{-1 \cdot \log x}}{n}}}{n \cdot x} \]
      4. associate-*r/N/A

        \[\leadsto \frac{e^{\color{blue}{\frac{-1 \cdot \left(-1 \cdot \log x\right)}{n}}}}{n \cdot x} \]
      5. associate-*r*N/A

        \[\leadsto \frac{e^{\frac{\color{blue}{\left(-1 \cdot -1\right) \cdot \log x}}{n}}}{n \cdot x} \]
      6. metadata-evalN/A

        \[\leadsto \frac{e^{\frac{\color{blue}{1} \cdot \log x}{n}}}{n \cdot x} \]
      7. *-commutativeN/A

        \[\leadsto \frac{e^{\frac{\color{blue}{\log x \cdot 1}}{n}}}{n \cdot x} \]
      8. associate-/l*N/A

        \[\leadsto \frac{e^{\color{blue}{\log x \cdot \frac{1}{n}}}}{n \cdot x} \]
      9. exp-to-powN/A

        \[\leadsto \frac{\color{blue}{{x}^{\left(\frac{1}{n}\right)}}}{n \cdot x} \]
      10. lower-pow.f64N/A

        \[\leadsto \frac{\color{blue}{{x}^{\left(\frac{1}{n}\right)}}}{n \cdot x} \]
      11. lower-/.f64N/A

        \[\leadsto \frac{{x}^{\color{blue}{\left(\frac{1}{n}\right)}}}{n \cdot x} \]
      12. *-commutativeN/A

        \[\leadsto \frac{{x}^{\left(\frac{1}{n}\right)}}{\color{blue}{x \cdot n}} \]
      13. lower-*.f6467.8

        \[\leadsto \frac{{x}^{\left(\frac{1}{n}\right)}}{\color{blue}{x \cdot n}} \]
    5. Applied rewrites67.8%

      \[\leadsto \color{blue}{\frac{{x}^{\left(\frac{1}{n}\right)}}{x \cdot n}} \]
    6. Step-by-step derivation
      1. Applied rewrites67.9%

        \[\leadsto \frac{\frac{{x}^{\left(\frac{1}{n}\right)}}{x}}{\color{blue}{n}} \]

      if 9.99999999999999955e-7 < (/.f64 #s(literal 1 binary64) n)

      1. Initial program 62.4%

        \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
      2. Add Preprocessing
      3. Step-by-step derivation
        1. lift-pow.f64N/A

          \[\leadsto \color{blue}{{\left(x + 1\right)}^{\left(\frac{1}{n}\right)}} - {x}^{\left(\frac{1}{n}\right)} \]
        2. pow-to-expN/A

          \[\leadsto \color{blue}{e^{\log \left(x + 1\right) \cdot \frac{1}{n}}} - {x}^{\left(\frac{1}{n}\right)} \]
        3. lower-exp.f64N/A

          \[\leadsto \color{blue}{e^{\log \left(x + 1\right) \cdot \frac{1}{n}}} - {x}^{\left(\frac{1}{n}\right)} \]
        4. lift-/.f64N/A

          \[\leadsto e^{\log \left(x + 1\right) \cdot \color{blue}{\frac{1}{n}}} - {x}^{\left(\frac{1}{n}\right)} \]
        5. un-div-invN/A

          \[\leadsto e^{\color{blue}{\frac{\log \left(x + 1\right)}{n}}} - {x}^{\left(\frac{1}{n}\right)} \]
        6. lower-/.f64N/A

          \[\leadsto e^{\color{blue}{\frac{\log \left(x + 1\right)}{n}}} - {x}^{\left(\frac{1}{n}\right)} \]
        7. lift-+.f64N/A

          \[\leadsto e^{\frac{\log \color{blue}{\left(x + 1\right)}}{n}} - {x}^{\left(\frac{1}{n}\right)} \]
        8. +-commutativeN/A

          \[\leadsto e^{\frac{\log \color{blue}{\left(1 + x\right)}}{n}} - {x}^{\left(\frac{1}{n}\right)} \]
        9. lower-log1p.f6499.7

          \[\leadsto e^{\frac{\color{blue}{\mathsf{log1p}\left(x\right)}}{n}} - {x}^{\left(\frac{1}{n}\right)} \]
      4. Applied rewrites99.7%

        \[\leadsto \color{blue}{e^{\frac{\mathsf{log1p}\left(x\right)}{n}}} - {x}^{\left(\frac{1}{n}\right)} \]
      5. Taylor expanded in x around 0

        \[\leadsto e^{\color{blue}{\frac{x}{n}}} - {x}^{\left(\frac{1}{n}\right)} \]
      6. Step-by-step derivation
        1. lower-/.f6499.7

          \[\leadsto e^{\color{blue}{\frac{x}{n}}} - {x}^{\left(\frac{1}{n}\right)} \]
      7. Applied rewrites99.7%

        \[\leadsto e^{\color{blue}{\frac{x}{n}}} - {x}^{\left(\frac{1}{n}\right)} \]
    7. Recombined 4 regimes into one program.
    8. Add Preprocessing

    Alternative 2: 87.0% accurate, 0.2× speedup?

    \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;x \leq 108000:\\ \;\;\;\;\frac{\frac{\mathsf{fma}\left(0.5, {\left(\mathsf{log1p}\left(x\right)\right)}^{2} - {\log x}^{2}, \frac{0.16666666666666666 \cdot \left({\left(\mathsf{log1p}\left(x\right)\right)}^{3} - {\log x}^{3}\right)}{n}\right)}{n} + \left(\mathsf{log1p}\left(x\right) - \log x\right)}{n}\\ \mathbf{else}:\\ \;\;\;\;\frac{\frac{{x}^{\left(\frac{1}{n}\right)}}{x}}{n}\\ \end{array} \end{array} \]
    (FPCore (x n)
     :precision binary64
     (if (<= x 108000.0)
       (/
        (+
         (/
          (fma
           0.5
           (- (pow (log1p x) 2.0) (pow (log x) 2.0))
           (/ (* 0.16666666666666666 (- (pow (log1p x) 3.0) (pow (log x) 3.0))) n))
          n)
         (- (log1p x) (log x)))
        n)
       (/ (/ (pow x (/ 1.0 n)) x) n)))
    double code(double x, double n) {
    	double tmp;
    	if (x <= 108000.0) {
    		tmp = ((fma(0.5, (pow(log1p(x), 2.0) - pow(log(x), 2.0)), ((0.16666666666666666 * (pow(log1p(x), 3.0) - pow(log(x), 3.0))) / n)) / n) + (log1p(x) - log(x))) / n;
    	} else {
    		tmp = (pow(x, (1.0 / n)) / x) / n;
    	}
    	return tmp;
    }
    
    function code(x, n)
    	tmp = 0.0
    	if (x <= 108000.0)
    		tmp = Float64(Float64(Float64(fma(0.5, Float64((log1p(x) ^ 2.0) - (log(x) ^ 2.0)), Float64(Float64(0.16666666666666666 * Float64((log1p(x) ^ 3.0) - (log(x) ^ 3.0))) / n)) / n) + Float64(log1p(x) - log(x))) / n);
    	else
    		tmp = Float64(Float64((x ^ Float64(1.0 / n)) / x) / n);
    	end
    	return tmp
    end
    
    code[x_, n_] := If[LessEqual[x, 108000.0], N[(N[(N[(N[(0.5 * N[(N[Power[N[Log[1 + x], $MachinePrecision], 2.0], $MachinePrecision] - N[Power[N[Log[x], $MachinePrecision], 2.0], $MachinePrecision]), $MachinePrecision] + N[(N[(0.16666666666666666 * N[(N[Power[N[Log[1 + x], $MachinePrecision], 3.0], $MachinePrecision] - N[Power[N[Log[x], $MachinePrecision], 3.0], $MachinePrecision]), $MachinePrecision]), $MachinePrecision] / n), $MachinePrecision]), $MachinePrecision] / n), $MachinePrecision] + N[(N[Log[1 + x], $MachinePrecision] - N[Log[x], $MachinePrecision]), $MachinePrecision]), $MachinePrecision] / n), $MachinePrecision], N[(N[(N[Power[x, N[(1.0 / n), $MachinePrecision]], $MachinePrecision] / x), $MachinePrecision] / n), $MachinePrecision]]
    
    \begin{array}{l}
    
    \\
    \begin{array}{l}
    \mathbf{if}\;x \leq 108000:\\
    \;\;\;\;\frac{\frac{\mathsf{fma}\left(0.5, {\left(\mathsf{log1p}\left(x\right)\right)}^{2} - {\log x}^{2}, \frac{0.16666666666666666 \cdot \left({\left(\mathsf{log1p}\left(x\right)\right)}^{3} - {\log x}^{3}\right)}{n}\right)}{n} + \left(\mathsf{log1p}\left(x\right) - \log x\right)}{n}\\
    
    \mathbf{else}:\\
    \;\;\;\;\frac{\frac{{x}^{\left(\frac{1}{n}\right)}}{x}}{n}\\
    
    
    \end{array}
    \end{array}
    
    Derivation
    1. Split input into 2 regimes
    2. if x < 108000

      1. Initial program 45.0%

        \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
      2. Add Preprocessing
      3. Taylor expanded in n around -inf

        \[\leadsto \color{blue}{-1 \cdot \frac{\left(-1 \cdot \log \left(1 + x\right) + -1 \cdot \frac{\left(-1 \cdot \frac{\frac{-1}{6} \cdot {\log \left(1 + x\right)}^{3} - \frac{-1}{6} \cdot {\log x}^{3}}{n} + \frac{1}{2} \cdot {\log \left(1 + x\right)}^{2}\right) - \frac{1}{2} \cdot {\log x}^{2}}{n}\right) - -1 \cdot \log x}{n}} \]
      4. Applied rewrites76.9%

        \[\leadsto \color{blue}{\frac{\left(\log x - \mathsf{log1p}\left(x\right)\right) - \frac{\mathsf{fma}\left(0.5, {\left(\mathsf{log1p}\left(x\right)\right)}^{2} - {\log x}^{2}, \frac{0.16666666666666666 \cdot \left({\left(\mathsf{log1p}\left(x\right)\right)}^{3} - {\log x}^{3}\right)}{n}\right)}{n}}{-n}} \]

      if 108000 < x

      1. Initial program 70.6%

        \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
      2. Add Preprocessing
      3. Taylor expanded in x around inf

        \[\leadsto \color{blue}{\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{n \cdot x}} \]
      4. Step-by-step derivation
        1. lower-/.f64N/A

          \[\leadsto \color{blue}{\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{n \cdot x}} \]
        2. log-recN/A

          \[\leadsto \frac{e^{-1 \cdot \frac{\color{blue}{\mathsf{neg}\left(\log x\right)}}{n}}}{n \cdot x} \]
        3. mul-1-negN/A

          \[\leadsto \frac{e^{-1 \cdot \frac{\color{blue}{-1 \cdot \log x}}{n}}}{n \cdot x} \]
        4. associate-*r/N/A

          \[\leadsto \frac{e^{\color{blue}{\frac{-1 \cdot \left(-1 \cdot \log x\right)}{n}}}}{n \cdot x} \]
        5. associate-*r*N/A

          \[\leadsto \frac{e^{\frac{\color{blue}{\left(-1 \cdot -1\right) \cdot \log x}}{n}}}{n \cdot x} \]
        6. metadata-evalN/A

          \[\leadsto \frac{e^{\frac{\color{blue}{1} \cdot \log x}{n}}}{n \cdot x} \]
        7. *-commutativeN/A

          \[\leadsto \frac{e^{\frac{\color{blue}{\log x \cdot 1}}{n}}}{n \cdot x} \]
        8. associate-/l*N/A

          \[\leadsto \frac{e^{\color{blue}{\log x \cdot \frac{1}{n}}}}{n \cdot x} \]
        9. exp-to-powN/A

          \[\leadsto \frac{\color{blue}{{x}^{\left(\frac{1}{n}\right)}}}{n \cdot x} \]
        10. lower-pow.f64N/A

          \[\leadsto \frac{\color{blue}{{x}^{\left(\frac{1}{n}\right)}}}{n \cdot x} \]
        11. lower-/.f64N/A

          \[\leadsto \frac{{x}^{\color{blue}{\left(\frac{1}{n}\right)}}}{n \cdot x} \]
        12. *-commutativeN/A

          \[\leadsto \frac{{x}^{\left(\frac{1}{n}\right)}}{\color{blue}{x \cdot n}} \]
        13. lower-*.f6498.9

          \[\leadsto \frac{{x}^{\left(\frac{1}{n}\right)}}{\color{blue}{x \cdot n}} \]
      5. Applied rewrites98.9%

        \[\leadsto \color{blue}{\frac{{x}^{\left(\frac{1}{n}\right)}}{x \cdot n}} \]
      6. Step-by-step derivation
        1. Applied rewrites99.8%

          \[\leadsto \frac{\frac{{x}^{\left(\frac{1}{n}\right)}}{x}}{\color{blue}{n}} \]
      7. Recombined 2 regimes into one program.
      8. Final simplification87.4%

        \[\leadsto \begin{array}{l} \mathbf{if}\;x \leq 108000:\\ \;\;\;\;\frac{\frac{\mathsf{fma}\left(0.5, {\left(\mathsf{log1p}\left(x\right)\right)}^{2} - {\log x}^{2}, \frac{0.16666666666666666 \cdot \left({\left(\mathsf{log1p}\left(x\right)\right)}^{3} - {\log x}^{3}\right)}{n}\right)}{n} + \left(\mathsf{log1p}\left(x\right) - \log x\right)}{n}\\ \mathbf{else}:\\ \;\;\;\;\frac{\frac{{x}^{\left(\frac{1}{n}\right)}}{x}}{n}\\ \end{array} \]
      9. Add Preprocessing

      Alternative 3: 86.2% accurate, 0.4× speedup?

      \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;x \leq 0.74:\\ \;\;\;\;\frac{\log x + \mathsf{fma}\left(\frac{{\log x}^{3}}{n \cdot n}, 0.16666666666666666, \frac{0.5 \cdot {\log x}^{2}}{n}\right)}{-n}\\ \mathbf{else}:\\ \;\;\;\;\frac{\frac{{x}^{\left(\frac{1}{n}\right)}}{x}}{n}\\ \end{array} \end{array} \]
      (FPCore (x n)
       :precision binary64
       (if (<= x 0.74)
         (/
          (+
           (log x)
           (fma
            (/ (pow (log x) 3.0) (* n n))
            0.16666666666666666
            (/ (* 0.5 (pow (log x) 2.0)) n)))
          (- n))
         (/ (/ (pow x (/ 1.0 n)) x) n)))
      double code(double x, double n) {
      	double tmp;
      	if (x <= 0.74) {
      		tmp = (log(x) + fma((pow(log(x), 3.0) / (n * n)), 0.16666666666666666, ((0.5 * pow(log(x), 2.0)) / n))) / -n;
      	} else {
      		tmp = (pow(x, (1.0 / n)) / x) / n;
      	}
      	return tmp;
      }
      
      function code(x, n)
      	tmp = 0.0
      	if (x <= 0.74)
      		tmp = Float64(Float64(log(x) + fma(Float64((log(x) ^ 3.0) / Float64(n * n)), 0.16666666666666666, Float64(Float64(0.5 * (log(x) ^ 2.0)) / n))) / Float64(-n));
      	else
      		tmp = Float64(Float64((x ^ Float64(1.0 / n)) / x) / n);
      	end
      	return tmp
      end
      
      code[x_, n_] := If[LessEqual[x, 0.74], N[(N[(N[Log[x], $MachinePrecision] + N[(N[(N[Power[N[Log[x], $MachinePrecision], 3.0], $MachinePrecision] / N[(n * n), $MachinePrecision]), $MachinePrecision] * 0.16666666666666666 + N[(N[(0.5 * N[Power[N[Log[x], $MachinePrecision], 2.0], $MachinePrecision]), $MachinePrecision] / n), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] / (-n)), $MachinePrecision], N[(N[(N[Power[x, N[(1.0 / n), $MachinePrecision]], $MachinePrecision] / x), $MachinePrecision] / n), $MachinePrecision]]
      
      \begin{array}{l}
      
      \\
      \begin{array}{l}
      \mathbf{if}\;x \leq 0.74:\\
      \;\;\;\;\frac{\log x + \mathsf{fma}\left(\frac{{\log x}^{3}}{n \cdot n}, 0.16666666666666666, \frac{0.5 \cdot {\log x}^{2}}{n}\right)}{-n}\\
      
      \mathbf{else}:\\
      \;\;\;\;\frac{\frac{{x}^{\left(\frac{1}{n}\right)}}{x}}{n}\\
      
      
      \end{array}
      \end{array}
      
      Derivation
      1. Split input into 2 regimes
      2. if x < 0.73999999999999999

        1. Initial program 45.3%

          \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
        2. Add Preprocessing
        3. Taylor expanded in n around -inf

          \[\leadsto \color{blue}{-1 \cdot \frac{\left(-1 \cdot \log \left(1 + x\right) + -1 \cdot \frac{\left(-1 \cdot \frac{\frac{-1}{6} \cdot {\log \left(1 + x\right)}^{3} - \frac{-1}{6} \cdot {\log x}^{3}}{n} + \frac{1}{2} \cdot {\log \left(1 + x\right)}^{2}\right) - \frac{1}{2} \cdot {\log x}^{2}}{n}\right) - -1 \cdot \log x}{n}} \]
        4. Applied rewrites76.8%

          \[\leadsto \color{blue}{\frac{\left(\log x - \mathsf{log1p}\left(x\right)\right) - \frac{\mathsf{fma}\left(0.5, {\left(\mathsf{log1p}\left(x\right)\right)}^{2} - {\log x}^{2}, \frac{0.16666666666666666 \cdot \left({\left(\mathsf{log1p}\left(x\right)\right)}^{3} - {\log x}^{3}\right)}{n}\right)}{n}}{-n}} \]
        5. Taylor expanded in x around 0

          \[\leadsto \frac{\log x - \left(\frac{-1}{2} \cdot \frac{{\log x}^{2}}{n} + \frac{-1}{6} \cdot \frac{{\log x}^{3}}{{n}^{2}}\right)}{\mathsf{neg}\left(\color{blue}{n}\right)} \]
        6. Step-by-step derivation
          1. Applied rewrites76.1%

            \[\leadsto \frac{\log x + \mathsf{fma}\left(\frac{{\log x}^{3}}{n \cdot n}, 0.16666666666666666, \frac{0.5 \cdot {\log x}^{2}}{n}\right)}{-\color{blue}{n}} \]

          if 0.73999999999999999 < x

          1. Initial program 70.0%

            \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
          2. Add Preprocessing
          3. Taylor expanded in x around inf

            \[\leadsto \color{blue}{\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{n \cdot x}} \]
          4. Step-by-step derivation
            1. lower-/.f64N/A

              \[\leadsto \color{blue}{\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{n \cdot x}} \]
            2. log-recN/A

              \[\leadsto \frac{e^{-1 \cdot \frac{\color{blue}{\mathsf{neg}\left(\log x\right)}}{n}}}{n \cdot x} \]
            3. mul-1-negN/A

              \[\leadsto \frac{e^{-1 \cdot \frac{\color{blue}{-1 \cdot \log x}}{n}}}{n \cdot x} \]
            4. associate-*r/N/A

              \[\leadsto \frac{e^{\color{blue}{\frac{-1 \cdot \left(-1 \cdot \log x\right)}{n}}}}{n \cdot x} \]
            5. associate-*r*N/A

              \[\leadsto \frac{e^{\frac{\color{blue}{\left(-1 \cdot -1\right) \cdot \log x}}{n}}}{n \cdot x} \]
            6. metadata-evalN/A

              \[\leadsto \frac{e^{\frac{\color{blue}{1} \cdot \log x}{n}}}{n \cdot x} \]
            7. *-commutativeN/A

              \[\leadsto \frac{e^{\frac{\color{blue}{\log x \cdot 1}}{n}}}{n \cdot x} \]
            8. associate-/l*N/A

              \[\leadsto \frac{e^{\color{blue}{\log x \cdot \frac{1}{n}}}}{n \cdot x} \]
            9. exp-to-powN/A

              \[\leadsto \frac{\color{blue}{{x}^{\left(\frac{1}{n}\right)}}}{n \cdot x} \]
            10. lower-pow.f64N/A

              \[\leadsto \frac{\color{blue}{{x}^{\left(\frac{1}{n}\right)}}}{n \cdot x} \]
            11. lower-/.f64N/A

              \[\leadsto \frac{{x}^{\color{blue}{\left(\frac{1}{n}\right)}}}{n \cdot x} \]
            12. *-commutativeN/A

              \[\leadsto \frac{{x}^{\left(\frac{1}{n}\right)}}{\color{blue}{x \cdot n}} \]
            13. lower-*.f6498.4

              \[\leadsto \frac{{x}^{\left(\frac{1}{n}\right)}}{\color{blue}{x \cdot n}} \]
          5. Applied rewrites98.4%

            \[\leadsto \color{blue}{\frac{{x}^{\left(\frac{1}{n}\right)}}{x \cdot n}} \]
          6. Step-by-step derivation
            1. Applied rewrites99.3%

              \[\leadsto \frac{\frac{{x}^{\left(\frac{1}{n}\right)}}{x}}{\color{blue}{n}} \]
          7. Recombined 2 regimes into one program.
          8. Add Preprocessing

          Alternative 4: 85.7% accurate, 0.4× speedup?

          \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;x \leq 0.74:\\ \;\;\;\;\frac{\log x + \frac{\mathsf{fma}\left(0.5, n \cdot {\log x}^{2}, 0.16666666666666666 \cdot {\log x}^{3}\right)}{n \cdot n}}{-n}\\ \mathbf{else}:\\ \;\;\;\;\frac{\frac{{x}^{\left(\frac{1}{n}\right)}}{x}}{n}\\ \end{array} \end{array} \]
          (FPCore (x n)
           :precision binary64
           (if (<= x 0.74)
             (/
              (+
               (log x)
               (/
                (fma
                 0.5
                 (* n (pow (log x) 2.0))
                 (* 0.16666666666666666 (pow (log x) 3.0)))
                (* n n)))
              (- n))
             (/ (/ (pow x (/ 1.0 n)) x) n)))
          double code(double x, double n) {
          	double tmp;
          	if (x <= 0.74) {
          		tmp = (log(x) + (fma(0.5, (n * pow(log(x), 2.0)), (0.16666666666666666 * pow(log(x), 3.0))) / (n * n))) / -n;
          	} else {
          		tmp = (pow(x, (1.0 / n)) / x) / n;
          	}
          	return tmp;
          }
          
          function code(x, n)
          	tmp = 0.0
          	if (x <= 0.74)
          		tmp = Float64(Float64(log(x) + Float64(fma(0.5, Float64(n * (log(x) ^ 2.0)), Float64(0.16666666666666666 * (log(x) ^ 3.0))) / Float64(n * n))) / Float64(-n));
          	else
          		tmp = Float64(Float64((x ^ Float64(1.0 / n)) / x) / n);
          	end
          	return tmp
          end
          
          code[x_, n_] := If[LessEqual[x, 0.74], N[(N[(N[Log[x], $MachinePrecision] + N[(N[(0.5 * N[(n * N[Power[N[Log[x], $MachinePrecision], 2.0], $MachinePrecision]), $MachinePrecision] + N[(0.16666666666666666 * N[Power[N[Log[x], $MachinePrecision], 3.0], $MachinePrecision]), $MachinePrecision]), $MachinePrecision] / N[(n * n), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] / (-n)), $MachinePrecision], N[(N[(N[Power[x, N[(1.0 / n), $MachinePrecision]], $MachinePrecision] / x), $MachinePrecision] / n), $MachinePrecision]]
          
          \begin{array}{l}
          
          \\
          \begin{array}{l}
          \mathbf{if}\;x \leq 0.74:\\
          \;\;\;\;\frac{\log x + \frac{\mathsf{fma}\left(0.5, n \cdot {\log x}^{2}, 0.16666666666666666 \cdot {\log x}^{3}\right)}{n \cdot n}}{-n}\\
          
          \mathbf{else}:\\
          \;\;\;\;\frac{\frac{{x}^{\left(\frac{1}{n}\right)}}{x}}{n}\\
          
          
          \end{array}
          \end{array}
          
          Derivation
          1. Split input into 2 regimes
          2. if x < 0.73999999999999999

            1. Initial program 45.3%

              \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
            2. Add Preprocessing
            3. Taylor expanded in n around -inf

              \[\leadsto \color{blue}{-1 \cdot \frac{\left(-1 \cdot \log \left(1 + x\right) + -1 \cdot \frac{\left(-1 \cdot \frac{\frac{-1}{6} \cdot {\log \left(1 + x\right)}^{3} - \frac{-1}{6} \cdot {\log x}^{3}}{n} + \frac{1}{2} \cdot {\log \left(1 + x\right)}^{2}\right) - \frac{1}{2} \cdot {\log x}^{2}}{n}\right) - -1 \cdot \log x}{n}} \]
            4. Applied rewrites76.8%

              \[\leadsto \color{blue}{\frac{\left(\log x - \mathsf{log1p}\left(x\right)\right) - \frac{\mathsf{fma}\left(0.5, {\left(\mathsf{log1p}\left(x\right)\right)}^{2} - {\log x}^{2}, \frac{0.16666666666666666 \cdot \left({\left(\mathsf{log1p}\left(x\right)\right)}^{3} - {\log x}^{3}\right)}{n}\right)}{n}}{-n}} \]
            5. Taylor expanded in x around 0

              \[\leadsto \frac{\log x - \left(\frac{-1}{2} \cdot \frac{{\log x}^{2}}{n} + \frac{-1}{6} \cdot \frac{{\log x}^{3}}{{n}^{2}}\right)}{\mathsf{neg}\left(\color{blue}{n}\right)} \]
            6. Step-by-step derivation
              1. Applied rewrites76.1%

                \[\leadsto \frac{\log x + \mathsf{fma}\left(\frac{{\log x}^{3}}{n \cdot n}, 0.16666666666666666, \frac{0.5 \cdot {\log x}^{2}}{n}\right)}{-\color{blue}{n}} \]
              2. Taylor expanded in n around 0

                \[\leadsto \frac{\log x + \frac{\frac{1}{6} \cdot {\log x}^{3} + \frac{1}{2} \cdot \left(n \cdot {\log x}^{2}\right)}{{n}^{2}}}{\mathsf{neg}\left(n\right)} \]
              3. Step-by-step derivation
                1. Applied rewrites75.4%

                  \[\leadsto \frac{\log x + \frac{\mathsf{fma}\left(0.5, n \cdot {\log x}^{2}, 0.16666666666666666 \cdot {\log x}^{3}\right)}{n \cdot n}}{-n} \]

                if 0.73999999999999999 < x

                1. Initial program 70.0%

                  \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                2. Add Preprocessing
                3. Taylor expanded in x around inf

                  \[\leadsto \color{blue}{\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{n \cdot x}} \]
                4. Step-by-step derivation
                  1. lower-/.f64N/A

                    \[\leadsto \color{blue}{\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{n \cdot x}} \]
                  2. log-recN/A

                    \[\leadsto \frac{e^{-1 \cdot \frac{\color{blue}{\mathsf{neg}\left(\log x\right)}}{n}}}{n \cdot x} \]
                  3. mul-1-negN/A

                    \[\leadsto \frac{e^{-1 \cdot \frac{\color{blue}{-1 \cdot \log x}}{n}}}{n \cdot x} \]
                  4. associate-*r/N/A

                    \[\leadsto \frac{e^{\color{blue}{\frac{-1 \cdot \left(-1 \cdot \log x\right)}{n}}}}{n \cdot x} \]
                  5. associate-*r*N/A

                    \[\leadsto \frac{e^{\frac{\color{blue}{\left(-1 \cdot -1\right) \cdot \log x}}{n}}}{n \cdot x} \]
                  6. metadata-evalN/A

                    \[\leadsto \frac{e^{\frac{\color{blue}{1} \cdot \log x}{n}}}{n \cdot x} \]
                  7. *-commutativeN/A

                    \[\leadsto \frac{e^{\frac{\color{blue}{\log x \cdot 1}}{n}}}{n \cdot x} \]
                  8. associate-/l*N/A

                    \[\leadsto \frac{e^{\color{blue}{\log x \cdot \frac{1}{n}}}}{n \cdot x} \]
                  9. exp-to-powN/A

                    \[\leadsto \frac{\color{blue}{{x}^{\left(\frac{1}{n}\right)}}}{n \cdot x} \]
                  10. lower-pow.f64N/A

                    \[\leadsto \frac{\color{blue}{{x}^{\left(\frac{1}{n}\right)}}}{n \cdot x} \]
                  11. lower-/.f64N/A

                    \[\leadsto \frac{{x}^{\color{blue}{\left(\frac{1}{n}\right)}}}{n \cdot x} \]
                  12. *-commutativeN/A

                    \[\leadsto \frac{{x}^{\left(\frac{1}{n}\right)}}{\color{blue}{x \cdot n}} \]
                  13. lower-*.f6498.4

                    \[\leadsto \frac{{x}^{\left(\frac{1}{n}\right)}}{\color{blue}{x \cdot n}} \]
                5. Applied rewrites98.4%

                  \[\leadsto \color{blue}{\frac{{x}^{\left(\frac{1}{n}\right)}}{x \cdot n}} \]
                6. Step-by-step derivation
                  1. Applied rewrites99.3%

                    \[\leadsto \frac{\frac{{x}^{\left(\frac{1}{n}\right)}}{x}}{\color{blue}{n}} \]
                7. Recombined 2 regimes into one program.
                8. Add Preprocessing

                Alternative 5: 81.6% accurate, 0.9× speedup?

                \[\begin{array}{l} \\ \begin{array}{l} t_0 := {x}^{\left(\frac{1}{n}\right)}\\ \mathbf{if}\;\frac{1}{n} \leq -5 \cdot 10^{-19}:\\ \;\;\;\;\frac{t\_0}{x \cdot n}\\ \mathbf{elif}\;\frac{1}{n} \leq 10^{-107}:\\ \;\;\;\;\frac{\mathsf{log1p}\left(x\right) - \log x}{n}\\ \mathbf{elif}\;\frac{1}{n} \leq 10^{-6}:\\ \;\;\;\;\frac{\frac{t\_0}{x}}{n}\\ \mathbf{else}:\\ \;\;\;\;\mathsf{fma}\left(x, \frac{\mathsf{fma}\left(x, 0.5 + \frac{-0.5}{n}, -1\right)}{-n}, 1\right) - t\_0\\ \end{array} \end{array} \]
                (FPCore (x n)
                 :precision binary64
                 (let* ((t_0 (pow x (/ 1.0 n))))
                   (if (<= (/ 1.0 n) -5e-19)
                     (/ t_0 (* x n))
                     (if (<= (/ 1.0 n) 1e-107)
                       (/ (- (log1p x) (log x)) n)
                       (if (<= (/ 1.0 n) 1e-6)
                         (/ (/ t_0 x) n)
                         (- (fma x (/ (fma x (+ 0.5 (/ -0.5 n)) -1.0) (- n)) 1.0) t_0))))))
                double code(double x, double n) {
                	double t_0 = pow(x, (1.0 / n));
                	double tmp;
                	if ((1.0 / n) <= -5e-19) {
                		tmp = t_0 / (x * n);
                	} else if ((1.0 / n) <= 1e-107) {
                		tmp = (log1p(x) - log(x)) / n;
                	} else if ((1.0 / n) <= 1e-6) {
                		tmp = (t_0 / x) / n;
                	} else {
                		tmp = fma(x, (fma(x, (0.5 + (-0.5 / n)), -1.0) / -n), 1.0) - t_0;
                	}
                	return tmp;
                }
                
                function code(x, n)
                	t_0 = x ^ Float64(1.0 / n)
                	tmp = 0.0
                	if (Float64(1.0 / n) <= -5e-19)
                		tmp = Float64(t_0 / Float64(x * n));
                	elseif (Float64(1.0 / n) <= 1e-107)
                		tmp = Float64(Float64(log1p(x) - log(x)) / n);
                	elseif (Float64(1.0 / n) <= 1e-6)
                		tmp = Float64(Float64(t_0 / x) / n);
                	else
                		tmp = Float64(fma(x, Float64(fma(x, Float64(0.5 + Float64(-0.5 / n)), -1.0) / Float64(-n)), 1.0) - t_0);
                	end
                	return tmp
                end
                
                code[x_, n_] := Block[{t$95$0 = N[Power[x, N[(1.0 / n), $MachinePrecision]], $MachinePrecision]}, If[LessEqual[N[(1.0 / n), $MachinePrecision], -5e-19], N[(t$95$0 / N[(x * n), $MachinePrecision]), $MachinePrecision], If[LessEqual[N[(1.0 / n), $MachinePrecision], 1e-107], N[(N[(N[Log[1 + x], $MachinePrecision] - N[Log[x], $MachinePrecision]), $MachinePrecision] / n), $MachinePrecision], If[LessEqual[N[(1.0 / n), $MachinePrecision], 1e-6], N[(N[(t$95$0 / x), $MachinePrecision] / n), $MachinePrecision], N[(N[(x * N[(N[(x * N[(0.5 + N[(-0.5 / n), $MachinePrecision]), $MachinePrecision] + -1.0), $MachinePrecision] / (-n)), $MachinePrecision] + 1.0), $MachinePrecision] - t$95$0), $MachinePrecision]]]]]
                
                \begin{array}{l}
                
                \\
                \begin{array}{l}
                t_0 := {x}^{\left(\frac{1}{n}\right)}\\
                \mathbf{if}\;\frac{1}{n} \leq -5 \cdot 10^{-19}:\\
                \;\;\;\;\frac{t\_0}{x \cdot n}\\
                
                \mathbf{elif}\;\frac{1}{n} \leq 10^{-107}:\\
                \;\;\;\;\frac{\mathsf{log1p}\left(x\right) - \log x}{n}\\
                
                \mathbf{elif}\;\frac{1}{n} \leq 10^{-6}:\\
                \;\;\;\;\frac{\frac{t\_0}{x}}{n}\\
                
                \mathbf{else}:\\
                \;\;\;\;\mathsf{fma}\left(x, \frac{\mathsf{fma}\left(x, 0.5 + \frac{-0.5}{n}, -1\right)}{-n}, 1\right) - t\_0\\
                
                
                \end{array}
                \end{array}
                
                Derivation
                1. Split input into 4 regimes
                2. if (/.f64 #s(literal 1 binary64) n) < -5.0000000000000004e-19

                  1. Initial program 94.5%

                    \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                  2. Add Preprocessing
                  3. Taylor expanded in x around inf

                    \[\leadsto \color{blue}{\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{n \cdot x}} \]
                  4. Step-by-step derivation
                    1. lower-/.f64N/A

                      \[\leadsto \color{blue}{\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{n \cdot x}} \]
                    2. log-recN/A

                      \[\leadsto \frac{e^{-1 \cdot \frac{\color{blue}{\mathsf{neg}\left(\log x\right)}}{n}}}{n \cdot x} \]
                    3. mul-1-negN/A

                      \[\leadsto \frac{e^{-1 \cdot \frac{\color{blue}{-1 \cdot \log x}}{n}}}{n \cdot x} \]
                    4. associate-*r/N/A

                      \[\leadsto \frac{e^{\color{blue}{\frac{-1 \cdot \left(-1 \cdot \log x\right)}{n}}}}{n \cdot x} \]
                    5. associate-*r*N/A

                      \[\leadsto \frac{e^{\frac{\color{blue}{\left(-1 \cdot -1\right) \cdot \log x}}{n}}}{n \cdot x} \]
                    6. metadata-evalN/A

                      \[\leadsto \frac{e^{\frac{\color{blue}{1} \cdot \log x}{n}}}{n \cdot x} \]
                    7. *-commutativeN/A

                      \[\leadsto \frac{e^{\frac{\color{blue}{\log x \cdot 1}}{n}}}{n \cdot x} \]
                    8. associate-/l*N/A

                      \[\leadsto \frac{e^{\color{blue}{\log x \cdot \frac{1}{n}}}}{n \cdot x} \]
                    9. exp-to-powN/A

                      \[\leadsto \frac{\color{blue}{{x}^{\left(\frac{1}{n}\right)}}}{n \cdot x} \]
                    10. lower-pow.f64N/A

                      \[\leadsto \frac{\color{blue}{{x}^{\left(\frac{1}{n}\right)}}}{n \cdot x} \]
                    11. lower-/.f64N/A

                      \[\leadsto \frac{{x}^{\color{blue}{\left(\frac{1}{n}\right)}}}{n \cdot x} \]
                    12. *-commutativeN/A

                      \[\leadsto \frac{{x}^{\left(\frac{1}{n}\right)}}{\color{blue}{x \cdot n}} \]
                    13. lower-*.f6497.6

                      \[\leadsto \frac{{x}^{\left(\frac{1}{n}\right)}}{\color{blue}{x \cdot n}} \]
                  5. Applied rewrites97.6%

                    \[\leadsto \color{blue}{\frac{{x}^{\left(\frac{1}{n}\right)}}{x \cdot n}} \]

                  if -5.0000000000000004e-19 < (/.f64 #s(literal 1 binary64) n) < 1e-107

                  1. Initial program 37.4%

                    \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                  2. Add Preprocessing
                  3. Taylor expanded in n around inf

                    \[\leadsto \color{blue}{\frac{\log \left(1 + x\right) - \log x}{n}} \]
                  4. Step-by-step derivation
                    1. lower-/.f64N/A

                      \[\leadsto \color{blue}{\frac{\log \left(1 + x\right) - \log x}{n}} \]
                    2. lower--.f64N/A

                      \[\leadsto \frac{\color{blue}{\log \left(1 + x\right) - \log x}}{n} \]
                    3. lower-log1p.f64N/A

                      \[\leadsto \frac{\color{blue}{\mathsf{log1p}\left(x\right)} - \log x}{n} \]
                    4. lower-log.f6484.9

                      \[\leadsto \frac{\mathsf{log1p}\left(x\right) - \color{blue}{\log x}}{n} \]
                  5. Applied rewrites84.9%

                    \[\leadsto \color{blue}{\frac{\mathsf{log1p}\left(x\right) - \log x}{n}} \]

                  if 1e-107 < (/.f64 #s(literal 1 binary64) n) < 9.99999999999999955e-7

                  1. Initial program 15.9%

                    \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                  2. Add Preprocessing
                  3. Taylor expanded in x around inf

                    \[\leadsto \color{blue}{\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{n \cdot x}} \]
                  4. Step-by-step derivation
                    1. lower-/.f64N/A

                      \[\leadsto \color{blue}{\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{n \cdot x}} \]
                    2. log-recN/A

                      \[\leadsto \frac{e^{-1 \cdot \frac{\color{blue}{\mathsf{neg}\left(\log x\right)}}{n}}}{n \cdot x} \]
                    3. mul-1-negN/A

                      \[\leadsto \frac{e^{-1 \cdot \frac{\color{blue}{-1 \cdot \log x}}{n}}}{n \cdot x} \]
                    4. associate-*r/N/A

                      \[\leadsto \frac{e^{\color{blue}{\frac{-1 \cdot \left(-1 \cdot \log x\right)}{n}}}}{n \cdot x} \]
                    5. associate-*r*N/A

                      \[\leadsto \frac{e^{\frac{\color{blue}{\left(-1 \cdot -1\right) \cdot \log x}}{n}}}{n \cdot x} \]
                    6. metadata-evalN/A

                      \[\leadsto \frac{e^{\frac{\color{blue}{1} \cdot \log x}{n}}}{n \cdot x} \]
                    7. *-commutativeN/A

                      \[\leadsto \frac{e^{\frac{\color{blue}{\log x \cdot 1}}{n}}}{n \cdot x} \]
                    8. associate-/l*N/A

                      \[\leadsto \frac{e^{\color{blue}{\log x \cdot \frac{1}{n}}}}{n \cdot x} \]
                    9. exp-to-powN/A

                      \[\leadsto \frac{\color{blue}{{x}^{\left(\frac{1}{n}\right)}}}{n \cdot x} \]
                    10. lower-pow.f64N/A

                      \[\leadsto \frac{\color{blue}{{x}^{\left(\frac{1}{n}\right)}}}{n \cdot x} \]
                    11. lower-/.f64N/A

                      \[\leadsto \frac{{x}^{\color{blue}{\left(\frac{1}{n}\right)}}}{n \cdot x} \]
                    12. *-commutativeN/A

                      \[\leadsto \frac{{x}^{\left(\frac{1}{n}\right)}}{\color{blue}{x \cdot n}} \]
                    13. lower-*.f6467.8

                      \[\leadsto \frac{{x}^{\left(\frac{1}{n}\right)}}{\color{blue}{x \cdot n}} \]
                  5. Applied rewrites67.8%

                    \[\leadsto \color{blue}{\frac{{x}^{\left(\frac{1}{n}\right)}}{x \cdot n}} \]
                  6. Step-by-step derivation
                    1. Applied rewrites67.9%

                      \[\leadsto \frac{\frac{{x}^{\left(\frac{1}{n}\right)}}{x}}{\color{blue}{n}} \]

                    if 9.99999999999999955e-7 < (/.f64 #s(literal 1 binary64) n)

                    1. Initial program 62.4%

                      \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                    2. Add Preprocessing
                    3. Taylor expanded in x around 0

                      \[\leadsto \color{blue}{\left(1 + x \cdot \left(x \cdot \left(\frac{1}{2} \cdot \frac{1}{{n}^{2}} - \frac{1}{2} \cdot \frac{1}{n}\right) + \frac{1}{n}\right)\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                    4. Step-by-step derivation
                      1. +-commutativeN/A

                        \[\leadsto \color{blue}{\left(x \cdot \left(x \cdot \left(\frac{1}{2} \cdot \frac{1}{{n}^{2}} - \frac{1}{2} \cdot \frac{1}{n}\right) + \frac{1}{n}\right) + 1\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                      2. lower-fma.f64N/A

                        \[\leadsto \color{blue}{\mathsf{fma}\left(x, x \cdot \left(\frac{1}{2} \cdot \frac{1}{{n}^{2}} - \frac{1}{2} \cdot \frac{1}{n}\right) + \frac{1}{n}, 1\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                      3. lower-fma.f64N/A

                        \[\leadsto \mathsf{fma}\left(x, \color{blue}{\mathsf{fma}\left(x, \frac{1}{2} \cdot \frac{1}{{n}^{2}} - \frac{1}{2} \cdot \frac{1}{n}, \frac{1}{n}\right)}, 1\right) - {x}^{\left(\frac{1}{n}\right)} \]
                      4. sub-negN/A

                        \[\leadsto \mathsf{fma}\left(x, \mathsf{fma}\left(x, \color{blue}{\frac{1}{2} \cdot \frac{1}{{n}^{2}} + \left(\mathsf{neg}\left(\frac{1}{2} \cdot \frac{1}{n}\right)\right)}, \frac{1}{n}\right), 1\right) - {x}^{\left(\frac{1}{n}\right)} \]
                      5. lower-+.f64N/A

                        \[\leadsto \mathsf{fma}\left(x, \mathsf{fma}\left(x, \color{blue}{\frac{1}{2} \cdot \frac{1}{{n}^{2}} + \left(\mathsf{neg}\left(\frac{1}{2} \cdot \frac{1}{n}\right)\right)}, \frac{1}{n}\right), 1\right) - {x}^{\left(\frac{1}{n}\right)} \]
                      6. associate-*r/N/A

                        \[\leadsto \mathsf{fma}\left(x, \mathsf{fma}\left(x, \color{blue}{\frac{\frac{1}{2} \cdot 1}{{n}^{2}}} + \left(\mathsf{neg}\left(\frac{1}{2} \cdot \frac{1}{n}\right)\right), \frac{1}{n}\right), 1\right) - {x}^{\left(\frac{1}{n}\right)} \]
                      7. metadata-evalN/A

                        \[\leadsto \mathsf{fma}\left(x, \mathsf{fma}\left(x, \frac{\color{blue}{\frac{1}{2}}}{{n}^{2}} + \left(\mathsf{neg}\left(\frac{1}{2} \cdot \frac{1}{n}\right)\right), \frac{1}{n}\right), 1\right) - {x}^{\left(\frac{1}{n}\right)} \]
                      8. lower-/.f64N/A

                        \[\leadsto \mathsf{fma}\left(x, \mathsf{fma}\left(x, \color{blue}{\frac{\frac{1}{2}}{{n}^{2}}} + \left(\mathsf{neg}\left(\frac{1}{2} \cdot \frac{1}{n}\right)\right), \frac{1}{n}\right), 1\right) - {x}^{\left(\frac{1}{n}\right)} \]
                      9. unpow2N/A

                        \[\leadsto \mathsf{fma}\left(x, \mathsf{fma}\left(x, \frac{\frac{1}{2}}{\color{blue}{n \cdot n}} + \left(\mathsf{neg}\left(\frac{1}{2} \cdot \frac{1}{n}\right)\right), \frac{1}{n}\right), 1\right) - {x}^{\left(\frac{1}{n}\right)} \]
                      10. lower-*.f64N/A

                        \[\leadsto \mathsf{fma}\left(x, \mathsf{fma}\left(x, \frac{\frac{1}{2}}{\color{blue}{n \cdot n}} + \left(\mathsf{neg}\left(\frac{1}{2} \cdot \frac{1}{n}\right)\right), \frac{1}{n}\right), 1\right) - {x}^{\left(\frac{1}{n}\right)} \]
                      11. associate-*r/N/A

                        \[\leadsto \mathsf{fma}\left(x, \mathsf{fma}\left(x, \frac{\frac{1}{2}}{n \cdot n} + \left(\mathsf{neg}\left(\color{blue}{\frac{\frac{1}{2} \cdot 1}{n}}\right)\right), \frac{1}{n}\right), 1\right) - {x}^{\left(\frac{1}{n}\right)} \]
                      12. metadata-evalN/A

                        \[\leadsto \mathsf{fma}\left(x, \mathsf{fma}\left(x, \frac{\frac{1}{2}}{n \cdot n} + \left(\mathsf{neg}\left(\frac{\color{blue}{\frac{1}{2}}}{n}\right)\right), \frac{1}{n}\right), 1\right) - {x}^{\left(\frac{1}{n}\right)} \]
                      13. distribute-neg-fracN/A

                        \[\leadsto \mathsf{fma}\left(x, \mathsf{fma}\left(x, \frac{\frac{1}{2}}{n \cdot n} + \color{blue}{\frac{\mathsf{neg}\left(\frac{1}{2}\right)}{n}}, \frac{1}{n}\right), 1\right) - {x}^{\left(\frac{1}{n}\right)} \]
                      14. metadata-evalN/A

                        \[\leadsto \mathsf{fma}\left(x, \mathsf{fma}\left(x, \frac{\frac{1}{2}}{n \cdot n} + \frac{\color{blue}{\frac{-1}{2}}}{n}, \frac{1}{n}\right), 1\right) - {x}^{\left(\frac{1}{n}\right)} \]
                      15. lower-/.f64N/A

                        \[\leadsto \mathsf{fma}\left(x, \mathsf{fma}\left(x, \frac{\frac{1}{2}}{n \cdot n} + \color{blue}{\frac{\frac{-1}{2}}{n}}, \frac{1}{n}\right), 1\right) - {x}^{\left(\frac{1}{n}\right)} \]
                      16. lower-/.f6463.4

                        \[\leadsto \mathsf{fma}\left(x, \mathsf{fma}\left(x, \frac{0.5}{n \cdot n} + \frac{-0.5}{n}, \color{blue}{\frac{1}{n}}\right), 1\right) - {x}^{\left(\frac{1}{n}\right)} \]
                    5. Applied rewrites63.4%

                      \[\leadsto \color{blue}{\mathsf{fma}\left(x, \mathsf{fma}\left(x, \frac{0.5}{n \cdot n} + \frac{-0.5}{n}, \frac{1}{n}\right), 1\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                    6. Taylor expanded in n around -inf

                      \[\leadsto \mathsf{fma}\left(x, -1 \cdot \color{blue}{\frac{\left(\frac{-1}{2} \cdot \frac{x}{n} + \frac{1}{2} \cdot x\right) - 1}{n}}, 1\right) - {x}^{\left(\frac{1}{n}\right)} \]
                    7. Step-by-step derivation
                      1. Applied rewrites80.4%

                        \[\leadsto \mathsf{fma}\left(x, \frac{\mathsf{fma}\left(-0.5, \frac{x}{n}, \mathsf{fma}\left(x, 0.5, -1\right)\right)}{\color{blue}{-n}}, 1\right) - {x}^{\left(\frac{1}{n}\right)} \]
                      2. Taylor expanded in x around 0

                        \[\leadsto \mathsf{fma}\left(x, \frac{x \cdot \left(\frac{1}{2} - \frac{1}{2} \cdot \frac{1}{n}\right) - 1}{\mathsf{neg}\left(n\right)}, 1\right) - {x}^{\left(\frac{1}{n}\right)} \]
                      3. Step-by-step derivation
                        1. Applied rewrites80.4%

                          \[\leadsto \mathsf{fma}\left(x, \frac{\mathsf{fma}\left(x, 0.5 + \frac{-0.5}{n}, -1\right)}{-n}, 1\right) - {x}^{\left(\frac{1}{n}\right)} \]
                      4. Recombined 4 regimes into one program.
                      5. Add Preprocessing

                      Alternative 6: 67.8% accurate, 1.1× speedup?

                      \[\begin{array}{l} \\ \begin{array}{l} t_0 := {x}^{\left(\frac{1}{n}\right)}\\ \mathbf{if}\;\frac{1}{n} \leq -5 \cdot 10^{-19}:\\ \;\;\;\;\frac{t\_0}{x \cdot n}\\ \mathbf{elif}\;\frac{1}{n} \leq -2 \cdot 10^{-171}:\\ \;\;\;\;\frac{\log x}{-n}\\ \mathbf{elif}\;\frac{1}{n} \leq 10^{-6}:\\ \;\;\;\;\frac{\frac{t\_0}{x}}{n}\\ \mathbf{else}:\\ \;\;\;\;\mathsf{fma}\left(x, \frac{\mathsf{fma}\left(x, 0.5 + \frac{-0.5}{n}, -1\right)}{-n}, 1\right) - t\_0\\ \end{array} \end{array} \]
                      (FPCore (x n)
                       :precision binary64
                       (let* ((t_0 (pow x (/ 1.0 n))))
                         (if (<= (/ 1.0 n) -5e-19)
                           (/ t_0 (* x n))
                           (if (<= (/ 1.0 n) -2e-171)
                             (/ (log x) (- n))
                             (if (<= (/ 1.0 n) 1e-6)
                               (/ (/ t_0 x) n)
                               (- (fma x (/ (fma x (+ 0.5 (/ -0.5 n)) -1.0) (- n)) 1.0) t_0))))))
                      double code(double x, double n) {
                      	double t_0 = pow(x, (1.0 / n));
                      	double tmp;
                      	if ((1.0 / n) <= -5e-19) {
                      		tmp = t_0 / (x * n);
                      	} else if ((1.0 / n) <= -2e-171) {
                      		tmp = log(x) / -n;
                      	} else if ((1.0 / n) <= 1e-6) {
                      		tmp = (t_0 / x) / n;
                      	} else {
                      		tmp = fma(x, (fma(x, (0.5 + (-0.5 / n)), -1.0) / -n), 1.0) - t_0;
                      	}
                      	return tmp;
                      }
                      
                      function code(x, n)
                      	t_0 = x ^ Float64(1.0 / n)
                      	tmp = 0.0
                      	if (Float64(1.0 / n) <= -5e-19)
                      		tmp = Float64(t_0 / Float64(x * n));
                      	elseif (Float64(1.0 / n) <= -2e-171)
                      		tmp = Float64(log(x) / Float64(-n));
                      	elseif (Float64(1.0 / n) <= 1e-6)
                      		tmp = Float64(Float64(t_0 / x) / n);
                      	else
                      		tmp = Float64(fma(x, Float64(fma(x, Float64(0.5 + Float64(-0.5 / n)), -1.0) / Float64(-n)), 1.0) - t_0);
                      	end
                      	return tmp
                      end
                      
                      code[x_, n_] := Block[{t$95$0 = N[Power[x, N[(1.0 / n), $MachinePrecision]], $MachinePrecision]}, If[LessEqual[N[(1.0 / n), $MachinePrecision], -5e-19], N[(t$95$0 / N[(x * n), $MachinePrecision]), $MachinePrecision], If[LessEqual[N[(1.0 / n), $MachinePrecision], -2e-171], N[(N[Log[x], $MachinePrecision] / (-n)), $MachinePrecision], If[LessEqual[N[(1.0 / n), $MachinePrecision], 1e-6], N[(N[(t$95$0 / x), $MachinePrecision] / n), $MachinePrecision], N[(N[(x * N[(N[(x * N[(0.5 + N[(-0.5 / n), $MachinePrecision]), $MachinePrecision] + -1.0), $MachinePrecision] / (-n)), $MachinePrecision] + 1.0), $MachinePrecision] - t$95$0), $MachinePrecision]]]]]
                      
                      \begin{array}{l}
                      
                      \\
                      \begin{array}{l}
                      t_0 := {x}^{\left(\frac{1}{n}\right)}\\
                      \mathbf{if}\;\frac{1}{n} \leq -5 \cdot 10^{-19}:\\
                      \;\;\;\;\frac{t\_0}{x \cdot n}\\
                      
                      \mathbf{elif}\;\frac{1}{n} \leq -2 \cdot 10^{-171}:\\
                      \;\;\;\;\frac{\log x}{-n}\\
                      
                      \mathbf{elif}\;\frac{1}{n} \leq 10^{-6}:\\
                      \;\;\;\;\frac{\frac{t\_0}{x}}{n}\\
                      
                      \mathbf{else}:\\
                      \;\;\;\;\mathsf{fma}\left(x, \frac{\mathsf{fma}\left(x, 0.5 + \frac{-0.5}{n}, -1\right)}{-n}, 1\right) - t\_0\\
                      
                      
                      \end{array}
                      \end{array}
                      
                      Derivation
                      1. Split input into 4 regimes
                      2. if (/.f64 #s(literal 1 binary64) n) < -5.0000000000000004e-19

                        1. Initial program 94.5%

                          \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                        2. Add Preprocessing
                        3. Taylor expanded in x around inf

                          \[\leadsto \color{blue}{\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{n \cdot x}} \]
                        4. Step-by-step derivation
                          1. lower-/.f64N/A

                            \[\leadsto \color{blue}{\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{n \cdot x}} \]
                          2. log-recN/A

                            \[\leadsto \frac{e^{-1 \cdot \frac{\color{blue}{\mathsf{neg}\left(\log x\right)}}{n}}}{n \cdot x} \]
                          3. mul-1-negN/A

                            \[\leadsto \frac{e^{-1 \cdot \frac{\color{blue}{-1 \cdot \log x}}{n}}}{n \cdot x} \]
                          4. associate-*r/N/A

                            \[\leadsto \frac{e^{\color{blue}{\frac{-1 \cdot \left(-1 \cdot \log x\right)}{n}}}}{n \cdot x} \]
                          5. associate-*r*N/A

                            \[\leadsto \frac{e^{\frac{\color{blue}{\left(-1 \cdot -1\right) \cdot \log x}}{n}}}{n \cdot x} \]
                          6. metadata-evalN/A

                            \[\leadsto \frac{e^{\frac{\color{blue}{1} \cdot \log x}{n}}}{n \cdot x} \]
                          7. *-commutativeN/A

                            \[\leadsto \frac{e^{\frac{\color{blue}{\log x \cdot 1}}{n}}}{n \cdot x} \]
                          8. associate-/l*N/A

                            \[\leadsto \frac{e^{\color{blue}{\log x \cdot \frac{1}{n}}}}{n \cdot x} \]
                          9. exp-to-powN/A

                            \[\leadsto \frac{\color{blue}{{x}^{\left(\frac{1}{n}\right)}}}{n \cdot x} \]
                          10. lower-pow.f64N/A

                            \[\leadsto \frac{\color{blue}{{x}^{\left(\frac{1}{n}\right)}}}{n \cdot x} \]
                          11. lower-/.f64N/A

                            \[\leadsto \frac{{x}^{\color{blue}{\left(\frac{1}{n}\right)}}}{n \cdot x} \]
                          12. *-commutativeN/A

                            \[\leadsto \frac{{x}^{\left(\frac{1}{n}\right)}}{\color{blue}{x \cdot n}} \]
                          13. lower-*.f6497.6

                            \[\leadsto \frac{{x}^{\left(\frac{1}{n}\right)}}{\color{blue}{x \cdot n}} \]
                        5. Applied rewrites97.6%

                          \[\leadsto \color{blue}{\frac{{x}^{\left(\frac{1}{n}\right)}}{x \cdot n}} \]

                        if -5.0000000000000004e-19 < (/.f64 #s(literal 1 binary64) n) < -2e-171

                        1. Initial program 12.1%

                          \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                        2. Add Preprocessing
                        3. Taylor expanded in n around -inf

                          \[\leadsto \color{blue}{-1 \cdot \frac{\left(-1 \cdot \log \left(1 + x\right) + -1 \cdot \frac{\left(-1 \cdot \frac{\frac{-1}{6} \cdot {\log \left(1 + x\right)}^{3} - \frac{-1}{6} \cdot {\log x}^{3}}{n} + \frac{1}{2} \cdot {\log \left(1 + x\right)}^{2}\right) - \frac{1}{2} \cdot {\log x}^{2}}{n}\right) - -1 \cdot \log x}{n}} \]
                        4. Applied rewrites81.6%

                          \[\leadsto \color{blue}{\frac{\left(\log x - \mathsf{log1p}\left(x\right)\right) - \frac{\mathsf{fma}\left(0.5, {\left(\mathsf{log1p}\left(x\right)\right)}^{2} - {\log x}^{2}, \frac{0.16666666666666666 \cdot \left({\left(\mathsf{log1p}\left(x\right)\right)}^{3} - {\log x}^{3}\right)}{n}\right)}{n}}{-n}} \]
                        5. Taylor expanded in x around 0

                          \[\leadsto \frac{\log x - \left(\frac{-1}{2} \cdot \frac{{\log x}^{2}}{n} + \frac{-1}{6} \cdot \frac{{\log x}^{3}}{{n}^{2}}\right)}{\mathsf{neg}\left(\color{blue}{n}\right)} \]
                        6. Step-by-step derivation
                          1. Applied rewrites71.5%

                            \[\leadsto \frac{\log x + \mathsf{fma}\left(\frac{{\log x}^{3}}{n \cdot n}, 0.16666666666666666, \frac{0.5 \cdot {\log x}^{2}}{n}\right)}{-\color{blue}{n}} \]
                          2. Taylor expanded in n around inf

                            \[\leadsto \frac{\log x}{\mathsf{neg}\left(n\right)} \]
                          3. Step-by-step derivation
                            1. Applied rewrites71.5%

                              \[\leadsto \frac{\log x}{-n} \]

                            if -2e-171 < (/.f64 #s(literal 1 binary64) n) < 9.99999999999999955e-7

                            1. Initial program 40.0%

                              \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                            2. Add Preprocessing
                            3. Taylor expanded in x around inf

                              \[\leadsto \color{blue}{\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{n \cdot x}} \]
                            4. Step-by-step derivation
                              1. lower-/.f64N/A

                                \[\leadsto \color{blue}{\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{n \cdot x}} \]
                              2. log-recN/A

                                \[\leadsto \frac{e^{-1 \cdot \frac{\color{blue}{\mathsf{neg}\left(\log x\right)}}{n}}}{n \cdot x} \]
                              3. mul-1-negN/A

                                \[\leadsto \frac{e^{-1 \cdot \frac{\color{blue}{-1 \cdot \log x}}{n}}}{n \cdot x} \]
                              4. associate-*r/N/A

                                \[\leadsto \frac{e^{\color{blue}{\frac{-1 \cdot \left(-1 \cdot \log x\right)}{n}}}}{n \cdot x} \]
                              5. associate-*r*N/A

                                \[\leadsto \frac{e^{\frac{\color{blue}{\left(-1 \cdot -1\right) \cdot \log x}}{n}}}{n \cdot x} \]
                              6. metadata-evalN/A

                                \[\leadsto \frac{e^{\frac{\color{blue}{1} \cdot \log x}{n}}}{n \cdot x} \]
                              7. *-commutativeN/A

                                \[\leadsto \frac{e^{\frac{\color{blue}{\log x \cdot 1}}{n}}}{n \cdot x} \]
                              8. associate-/l*N/A

                                \[\leadsto \frac{e^{\color{blue}{\log x \cdot \frac{1}{n}}}}{n \cdot x} \]
                              9. exp-to-powN/A

                                \[\leadsto \frac{\color{blue}{{x}^{\left(\frac{1}{n}\right)}}}{n \cdot x} \]
                              10. lower-pow.f64N/A

                                \[\leadsto \frac{\color{blue}{{x}^{\left(\frac{1}{n}\right)}}}{n \cdot x} \]
                              11. lower-/.f64N/A

                                \[\leadsto \frac{{x}^{\color{blue}{\left(\frac{1}{n}\right)}}}{n \cdot x} \]
                              12. *-commutativeN/A

                                \[\leadsto \frac{{x}^{\left(\frac{1}{n}\right)}}{\color{blue}{x \cdot n}} \]
                              13. lower-*.f6461.9

                                \[\leadsto \frac{{x}^{\left(\frac{1}{n}\right)}}{\color{blue}{x \cdot n}} \]
                            5. Applied rewrites61.9%

                              \[\leadsto \color{blue}{\frac{{x}^{\left(\frac{1}{n}\right)}}{x \cdot n}} \]
                            6. Step-by-step derivation
                              1. Applied rewrites62.7%

                                \[\leadsto \frac{\frac{{x}^{\left(\frac{1}{n}\right)}}{x}}{\color{blue}{n}} \]

                              if 9.99999999999999955e-7 < (/.f64 #s(literal 1 binary64) n)

                              1. Initial program 62.4%

                                \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                              2. Add Preprocessing
                              3. Taylor expanded in x around 0

                                \[\leadsto \color{blue}{\left(1 + x \cdot \left(x \cdot \left(\frac{1}{2} \cdot \frac{1}{{n}^{2}} - \frac{1}{2} \cdot \frac{1}{n}\right) + \frac{1}{n}\right)\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                              4. Step-by-step derivation
                                1. +-commutativeN/A

                                  \[\leadsto \color{blue}{\left(x \cdot \left(x \cdot \left(\frac{1}{2} \cdot \frac{1}{{n}^{2}} - \frac{1}{2} \cdot \frac{1}{n}\right) + \frac{1}{n}\right) + 1\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                                2. lower-fma.f64N/A

                                  \[\leadsto \color{blue}{\mathsf{fma}\left(x, x \cdot \left(\frac{1}{2} \cdot \frac{1}{{n}^{2}} - \frac{1}{2} \cdot \frac{1}{n}\right) + \frac{1}{n}, 1\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                                3. lower-fma.f64N/A

                                  \[\leadsto \mathsf{fma}\left(x, \color{blue}{\mathsf{fma}\left(x, \frac{1}{2} \cdot \frac{1}{{n}^{2}} - \frac{1}{2} \cdot \frac{1}{n}, \frac{1}{n}\right)}, 1\right) - {x}^{\left(\frac{1}{n}\right)} \]
                                4. sub-negN/A

                                  \[\leadsto \mathsf{fma}\left(x, \mathsf{fma}\left(x, \color{blue}{\frac{1}{2} \cdot \frac{1}{{n}^{2}} + \left(\mathsf{neg}\left(\frac{1}{2} \cdot \frac{1}{n}\right)\right)}, \frac{1}{n}\right), 1\right) - {x}^{\left(\frac{1}{n}\right)} \]
                                5. lower-+.f64N/A

                                  \[\leadsto \mathsf{fma}\left(x, \mathsf{fma}\left(x, \color{blue}{\frac{1}{2} \cdot \frac{1}{{n}^{2}} + \left(\mathsf{neg}\left(\frac{1}{2} \cdot \frac{1}{n}\right)\right)}, \frac{1}{n}\right), 1\right) - {x}^{\left(\frac{1}{n}\right)} \]
                                6. associate-*r/N/A

                                  \[\leadsto \mathsf{fma}\left(x, \mathsf{fma}\left(x, \color{blue}{\frac{\frac{1}{2} \cdot 1}{{n}^{2}}} + \left(\mathsf{neg}\left(\frac{1}{2} \cdot \frac{1}{n}\right)\right), \frac{1}{n}\right), 1\right) - {x}^{\left(\frac{1}{n}\right)} \]
                                7. metadata-evalN/A

                                  \[\leadsto \mathsf{fma}\left(x, \mathsf{fma}\left(x, \frac{\color{blue}{\frac{1}{2}}}{{n}^{2}} + \left(\mathsf{neg}\left(\frac{1}{2} \cdot \frac{1}{n}\right)\right), \frac{1}{n}\right), 1\right) - {x}^{\left(\frac{1}{n}\right)} \]
                                8. lower-/.f64N/A

                                  \[\leadsto \mathsf{fma}\left(x, \mathsf{fma}\left(x, \color{blue}{\frac{\frac{1}{2}}{{n}^{2}}} + \left(\mathsf{neg}\left(\frac{1}{2} \cdot \frac{1}{n}\right)\right), \frac{1}{n}\right), 1\right) - {x}^{\left(\frac{1}{n}\right)} \]
                                9. unpow2N/A

                                  \[\leadsto \mathsf{fma}\left(x, \mathsf{fma}\left(x, \frac{\frac{1}{2}}{\color{blue}{n \cdot n}} + \left(\mathsf{neg}\left(\frac{1}{2} \cdot \frac{1}{n}\right)\right), \frac{1}{n}\right), 1\right) - {x}^{\left(\frac{1}{n}\right)} \]
                                10. lower-*.f64N/A

                                  \[\leadsto \mathsf{fma}\left(x, \mathsf{fma}\left(x, \frac{\frac{1}{2}}{\color{blue}{n \cdot n}} + \left(\mathsf{neg}\left(\frac{1}{2} \cdot \frac{1}{n}\right)\right), \frac{1}{n}\right), 1\right) - {x}^{\left(\frac{1}{n}\right)} \]
                                11. associate-*r/N/A

                                  \[\leadsto \mathsf{fma}\left(x, \mathsf{fma}\left(x, \frac{\frac{1}{2}}{n \cdot n} + \left(\mathsf{neg}\left(\color{blue}{\frac{\frac{1}{2} \cdot 1}{n}}\right)\right), \frac{1}{n}\right), 1\right) - {x}^{\left(\frac{1}{n}\right)} \]
                                12. metadata-evalN/A

                                  \[\leadsto \mathsf{fma}\left(x, \mathsf{fma}\left(x, \frac{\frac{1}{2}}{n \cdot n} + \left(\mathsf{neg}\left(\frac{\color{blue}{\frac{1}{2}}}{n}\right)\right), \frac{1}{n}\right), 1\right) - {x}^{\left(\frac{1}{n}\right)} \]
                                13. distribute-neg-fracN/A

                                  \[\leadsto \mathsf{fma}\left(x, \mathsf{fma}\left(x, \frac{\frac{1}{2}}{n \cdot n} + \color{blue}{\frac{\mathsf{neg}\left(\frac{1}{2}\right)}{n}}, \frac{1}{n}\right), 1\right) - {x}^{\left(\frac{1}{n}\right)} \]
                                14. metadata-evalN/A

                                  \[\leadsto \mathsf{fma}\left(x, \mathsf{fma}\left(x, \frac{\frac{1}{2}}{n \cdot n} + \frac{\color{blue}{\frac{-1}{2}}}{n}, \frac{1}{n}\right), 1\right) - {x}^{\left(\frac{1}{n}\right)} \]
                                15. lower-/.f64N/A

                                  \[\leadsto \mathsf{fma}\left(x, \mathsf{fma}\left(x, \frac{\frac{1}{2}}{n \cdot n} + \color{blue}{\frac{\frac{-1}{2}}{n}}, \frac{1}{n}\right), 1\right) - {x}^{\left(\frac{1}{n}\right)} \]
                                16. lower-/.f6463.4

                                  \[\leadsto \mathsf{fma}\left(x, \mathsf{fma}\left(x, \frac{0.5}{n \cdot n} + \frac{-0.5}{n}, \color{blue}{\frac{1}{n}}\right), 1\right) - {x}^{\left(\frac{1}{n}\right)} \]
                              5. Applied rewrites63.4%

                                \[\leadsto \color{blue}{\mathsf{fma}\left(x, \mathsf{fma}\left(x, \frac{0.5}{n \cdot n} + \frac{-0.5}{n}, \frac{1}{n}\right), 1\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                              6. Taylor expanded in n around -inf

                                \[\leadsto \mathsf{fma}\left(x, -1 \cdot \color{blue}{\frac{\left(\frac{-1}{2} \cdot \frac{x}{n} + \frac{1}{2} \cdot x\right) - 1}{n}}, 1\right) - {x}^{\left(\frac{1}{n}\right)} \]
                              7. Step-by-step derivation
                                1. Applied rewrites80.4%

                                  \[\leadsto \mathsf{fma}\left(x, \frac{\mathsf{fma}\left(-0.5, \frac{x}{n}, \mathsf{fma}\left(x, 0.5, -1\right)\right)}{\color{blue}{-n}}, 1\right) - {x}^{\left(\frac{1}{n}\right)} \]
                                2. Taylor expanded in x around 0

                                  \[\leadsto \mathsf{fma}\left(x, \frac{x \cdot \left(\frac{1}{2} - \frac{1}{2} \cdot \frac{1}{n}\right) - 1}{\mathsf{neg}\left(n\right)}, 1\right) - {x}^{\left(\frac{1}{n}\right)} \]
                                3. Step-by-step derivation
                                  1. Applied rewrites80.4%

                                    \[\leadsto \mathsf{fma}\left(x, \frac{\mathsf{fma}\left(x, 0.5 + \frac{-0.5}{n}, -1\right)}{-n}, 1\right) - {x}^{\left(\frac{1}{n}\right)} \]
                                4. Recombined 4 regimes into one program.
                                5. Add Preprocessing

                                Alternative 7: 71.3% accurate, 1.6× speedup?

                                \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;x \leq 4.8 \cdot 10^{-13}:\\ \;\;\;\;\frac{\log x}{-n}\\ \mathbf{else}:\\ \;\;\;\;\frac{\frac{{x}^{\left(\frac{1}{n}\right)}}{x}}{n}\\ \end{array} \end{array} \]
                                (FPCore (x n)
                                 :precision binary64
                                 (if (<= x 4.8e-13) (/ (log x) (- n)) (/ (/ (pow x (/ 1.0 n)) x) n)))
                                double code(double x, double n) {
                                	double tmp;
                                	if (x <= 4.8e-13) {
                                		tmp = log(x) / -n;
                                	} else {
                                		tmp = (pow(x, (1.0 / n)) / x) / n;
                                	}
                                	return tmp;
                                }
                                
                                real(8) function code(x, n)
                                    real(8), intent (in) :: x
                                    real(8), intent (in) :: n
                                    real(8) :: tmp
                                    if (x <= 4.8d-13) then
                                        tmp = log(x) / -n
                                    else
                                        tmp = ((x ** (1.0d0 / n)) / x) / n
                                    end if
                                    code = tmp
                                end function
                                
                                public static double code(double x, double n) {
                                	double tmp;
                                	if (x <= 4.8e-13) {
                                		tmp = Math.log(x) / -n;
                                	} else {
                                		tmp = (Math.pow(x, (1.0 / n)) / x) / n;
                                	}
                                	return tmp;
                                }
                                
                                def code(x, n):
                                	tmp = 0
                                	if x <= 4.8e-13:
                                		tmp = math.log(x) / -n
                                	else:
                                		tmp = (math.pow(x, (1.0 / n)) / x) / n
                                	return tmp
                                
                                function code(x, n)
                                	tmp = 0.0
                                	if (x <= 4.8e-13)
                                		tmp = Float64(log(x) / Float64(-n));
                                	else
                                		tmp = Float64(Float64((x ^ Float64(1.0 / n)) / x) / n);
                                	end
                                	return tmp
                                end
                                
                                function tmp_2 = code(x, n)
                                	tmp = 0.0;
                                	if (x <= 4.8e-13)
                                		tmp = log(x) / -n;
                                	else
                                		tmp = ((x ^ (1.0 / n)) / x) / n;
                                	end
                                	tmp_2 = tmp;
                                end
                                
                                code[x_, n_] := If[LessEqual[x, 4.8e-13], N[(N[Log[x], $MachinePrecision] / (-n)), $MachinePrecision], N[(N[(N[Power[x, N[(1.0 / n), $MachinePrecision]], $MachinePrecision] / x), $MachinePrecision] / n), $MachinePrecision]]
                                
                                \begin{array}{l}
                                
                                \\
                                \begin{array}{l}
                                \mathbf{if}\;x \leq 4.8 \cdot 10^{-13}:\\
                                \;\;\;\;\frac{\log x}{-n}\\
                                
                                \mathbf{else}:\\
                                \;\;\;\;\frac{\frac{{x}^{\left(\frac{1}{n}\right)}}{x}}{n}\\
                                
                                
                                \end{array}
                                \end{array}
                                
                                Derivation
                                1. Split input into 2 regimes
                                2. if x < 4.7999999999999997e-13

                                  1. Initial program 43.8%

                                    \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                                  2. Add Preprocessing
                                  3. Taylor expanded in n around -inf

                                    \[\leadsto \color{blue}{-1 \cdot \frac{\left(-1 \cdot \log \left(1 + x\right) + -1 \cdot \frac{\left(-1 \cdot \frac{\frac{-1}{6} \cdot {\log \left(1 + x\right)}^{3} - \frac{-1}{6} \cdot {\log x}^{3}}{n} + \frac{1}{2} \cdot {\log \left(1 + x\right)}^{2}\right) - \frac{1}{2} \cdot {\log x}^{2}}{n}\right) - -1 \cdot \log x}{n}} \]
                                  4. Applied rewrites77.1%

                                    \[\leadsto \color{blue}{\frac{\left(\log x - \mathsf{log1p}\left(x\right)\right) - \frac{\mathsf{fma}\left(0.5, {\left(\mathsf{log1p}\left(x\right)\right)}^{2} - {\log x}^{2}, \frac{0.16666666666666666 \cdot \left({\left(\mathsf{log1p}\left(x\right)\right)}^{3} - {\log x}^{3}\right)}{n}\right)}{n}}{-n}} \]
                                  5. Taylor expanded in x around 0

                                    \[\leadsto \frac{\log x - \left(\frac{-1}{2} \cdot \frac{{\log x}^{2}}{n} + \frac{-1}{6} \cdot \frac{{\log x}^{3}}{{n}^{2}}\right)}{\mathsf{neg}\left(\color{blue}{n}\right)} \]
                                  6. Step-by-step derivation
                                    1. Applied rewrites77.1%

                                      \[\leadsto \frac{\log x + \mathsf{fma}\left(\frac{{\log x}^{3}}{n \cdot n}, 0.16666666666666666, \frac{0.5 \cdot {\log x}^{2}}{n}\right)}{-\color{blue}{n}} \]
                                    2. Taylor expanded in n around inf

                                      \[\leadsto \frac{\log x}{\mathsf{neg}\left(n\right)} \]
                                    3. Step-by-step derivation
                                      1. Applied rewrites51.4%

                                        \[\leadsto \frac{\log x}{-n} \]

                                      if 4.7999999999999997e-13 < x

                                      1. Initial program 70.1%

                                        \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                                      2. Add Preprocessing
                                      3. Taylor expanded in x around inf

                                        \[\leadsto \color{blue}{\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{n \cdot x}} \]
                                      4. Step-by-step derivation
                                        1. lower-/.f64N/A

                                          \[\leadsto \color{blue}{\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{n \cdot x}} \]
                                        2. log-recN/A

                                          \[\leadsto \frac{e^{-1 \cdot \frac{\color{blue}{\mathsf{neg}\left(\log x\right)}}{n}}}{n \cdot x} \]
                                        3. mul-1-negN/A

                                          \[\leadsto \frac{e^{-1 \cdot \frac{\color{blue}{-1 \cdot \log x}}{n}}}{n \cdot x} \]
                                        4. associate-*r/N/A

                                          \[\leadsto \frac{e^{\color{blue}{\frac{-1 \cdot \left(-1 \cdot \log x\right)}{n}}}}{n \cdot x} \]
                                        5. associate-*r*N/A

                                          \[\leadsto \frac{e^{\frac{\color{blue}{\left(-1 \cdot -1\right) \cdot \log x}}{n}}}{n \cdot x} \]
                                        6. metadata-evalN/A

                                          \[\leadsto \frac{e^{\frac{\color{blue}{1} \cdot \log x}{n}}}{n \cdot x} \]
                                        7. *-commutativeN/A

                                          \[\leadsto \frac{e^{\frac{\color{blue}{\log x \cdot 1}}{n}}}{n \cdot x} \]
                                        8. associate-/l*N/A

                                          \[\leadsto \frac{e^{\color{blue}{\log x \cdot \frac{1}{n}}}}{n \cdot x} \]
                                        9. exp-to-powN/A

                                          \[\leadsto \frac{\color{blue}{{x}^{\left(\frac{1}{n}\right)}}}{n \cdot x} \]
                                        10. lower-pow.f64N/A

                                          \[\leadsto \frac{\color{blue}{{x}^{\left(\frac{1}{n}\right)}}}{n \cdot x} \]
                                        11. lower-/.f64N/A

                                          \[\leadsto \frac{{x}^{\color{blue}{\left(\frac{1}{n}\right)}}}{n \cdot x} \]
                                        12. *-commutativeN/A

                                          \[\leadsto \frac{{x}^{\left(\frac{1}{n}\right)}}{\color{blue}{x \cdot n}} \]
                                        13. lower-*.f6494.8

                                          \[\leadsto \frac{{x}^{\left(\frac{1}{n}\right)}}{\color{blue}{x \cdot n}} \]
                                      5. Applied rewrites94.8%

                                        \[\leadsto \color{blue}{\frac{{x}^{\left(\frac{1}{n}\right)}}{x \cdot n}} \]
                                      6. Step-by-step derivation
                                        1. Applied rewrites95.6%

                                          \[\leadsto \frac{\frac{{x}^{\left(\frac{1}{n}\right)}}{x}}{\color{blue}{n}} \]
                                      7. Recombined 2 regimes into one program.
                                      8. Add Preprocessing

                                      Alternative 8: 70.7% accurate, 1.7× speedup?

                                      \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;x \leq 4.8 \cdot 10^{-13}:\\ \;\;\;\;\frac{\log x}{-n}\\ \mathbf{else}:\\ \;\;\;\;\frac{{x}^{\left(\frac{1}{n}\right)}}{x \cdot n}\\ \end{array} \end{array} \]
                                      (FPCore (x n)
                                       :precision binary64
                                       (if (<= x 4.8e-13) (/ (log x) (- n)) (/ (pow x (/ 1.0 n)) (* x n))))
                                      double code(double x, double n) {
                                      	double tmp;
                                      	if (x <= 4.8e-13) {
                                      		tmp = log(x) / -n;
                                      	} else {
                                      		tmp = pow(x, (1.0 / n)) / (x * n);
                                      	}
                                      	return tmp;
                                      }
                                      
                                      real(8) function code(x, n)
                                          real(8), intent (in) :: x
                                          real(8), intent (in) :: n
                                          real(8) :: tmp
                                          if (x <= 4.8d-13) then
                                              tmp = log(x) / -n
                                          else
                                              tmp = (x ** (1.0d0 / n)) / (x * n)
                                          end if
                                          code = tmp
                                      end function
                                      
                                      public static double code(double x, double n) {
                                      	double tmp;
                                      	if (x <= 4.8e-13) {
                                      		tmp = Math.log(x) / -n;
                                      	} else {
                                      		tmp = Math.pow(x, (1.0 / n)) / (x * n);
                                      	}
                                      	return tmp;
                                      }
                                      
                                      def code(x, n):
                                      	tmp = 0
                                      	if x <= 4.8e-13:
                                      		tmp = math.log(x) / -n
                                      	else:
                                      		tmp = math.pow(x, (1.0 / n)) / (x * n)
                                      	return tmp
                                      
                                      function code(x, n)
                                      	tmp = 0.0
                                      	if (x <= 4.8e-13)
                                      		tmp = Float64(log(x) / Float64(-n));
                                      	else
                                      		tmp = Float64((x ^ Float64(1.0 / n)) / Float64(x * n));
                                      	end
                                      	return tmp
                                      end
                                      
                                      function tmp_2 = code(x, n)
                                      	tmp = 0.0;
                                      	if (x <= 4.8e-13)
                                      		tmp = log(x) / -n;
                                      	else
                                      		tmp = (x ^ (1.0 / n)) / (x * n);
                                      	end
                                      	tmp_2 = tmp;
                                      end
                                      
                                      code[x_, n_] := If[LessEqual[x, 4.8e-13], N[(N[Log[x], $MachinePrecision] / (-n)), $MachinePrecision], N[(N[Power[x, N[(1.0 / n), $MachinePrecision]], $MachinePrecision] / N[(x * n), $MachinePrecision]), $MachinePrecision]]
                                      
                                      \begin{array}{l}
                                      
                                      \\
                                      \begin{array}{l}
                                      \mathbf{if}\;x \leq 4.8 \cdot 10^{-13}:\\
                                      \;\;\;\;\frac{\log x}{-n}\\
                                      
                                      \mathbf{else}:\\
                                      \;\;\;\;\frac{{x}^{\left(\frac{1}{n}\right)}}{x \cdot n}\\
                                      
                                      
                                      \end{array}
                                      \end{array}
                                      
                                      Derivation
                                      1. Split input into 2 regimes
                                      2. if x < 4.7999999999999997e-13

                                        1. Initial program 43.8%

                                          \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                                        2. Add Preprocessing
                                        3. Taylor expanded in n around -inf

                                          \[\leadsto \color{blue}{-1 \cdot \frac{\left(-1 \cdot \log \left(1 + x\right) + -1 \cdot \frac{\left(-1 \cdot \frac{\frac{-1}{6} \cdot {\log \left(1 + x\right)}^{3} - \frac{-1}{6} \cdot {\log x}^{3}}{n} + \frac{1}{2} \cdot {\log \left(1 + x\right)}^{2}\right) - \frac{1}{2} \cdot {\log x}^{2}}{n}\right) - -1 \cdot \log x}{n}} \]
                                        4. Applied rewrites77.1%

                                          \[\leadsto \color{blue}{\frac{\left(\log x - \mathsf{log1p}\left(x\right)\right) - \frac{\mathsf{fma}\left(0.5, {\left(\mathsf{log1p}\left(x\right)\right)}^{2} - {\log x}^{2}, \frac{0.16666666666666666 \cdot \left({\left(\mathsf{log1p}\left(x\right)\right)}^{3} - {\log x}^{3}\right)}{n}\right)}{n}}{-n}} \]
                                        5. Taylor expanded in x around 0

                                          \[\leadsto \frac{\log x - \left(\frac{-1}{2} \cdot \frac{{\log x}^{2}}{n} + \frac{-1}{6} \cdot \frac{{\log x}^{3}}{{n}^{2}}\right)}{\mathsf{neg}\left(\color{blue}{n}\right)} \]
                                        6. Step-by-step derivation
                                          1. Applied rewrites77.1%

                                            \[\leadsto \frac{\log x + \mathsf{fma}\left(\frac{{\log x}^{3}}{n \cdot n}, 0.16666666666666666, \frac{0.5 \cdot {\log x}^{2}}{n}\right)}{-\color{blue}{n}} \]
                                          2. Taylor expanded in n around inf

                                            \[\leadsto \frac{\log x}{\mathsf{neg}\left(n\right)} \]
                                          3. Step-by-step derivation
                                            1. Applied rewrites51.4%

                                              \[\leadsto \frac{\log x}{-n} \]

                                            if 4.7999999999999997e-13 < x

                                            1. Initial program 70.1%

                                              \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                                            2. Add Preprocessing
                                            3. Taylor expanded in x around inf

                                              \[\leadsto \color{blue}{\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{n \cdot x}} \]
                                            4. Step-by-step derivation
                                              1. lower-/.f64N/A

                                                \[\leadsto \color{blue}{\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{n \cdot x}} \]
                                              2. log-recN/A

                                                \[\leadsto \frac{e^{-1 \cdot \frac{\color{blue}{\mathsf{neg}\left(\log x\right)}}{n}}}{n \cdot x} \]
                                              3. mul-1-negN/A

                                                \[\leadsto \frac{e^{-1 \cdot \frac{\color{blue}{-1 \cdot \log x}}{n}}}{n \cdot x} \]
                                              4. associate-*r/N/A

                                                \[\leadsto \frac{e^{\color{blue}{\frac{-1 \cdot \left(-1 \cdot \log x\right)}{n}}}}{n \cdot x} \]
                                              5. associate-*r*N/A

                                                \[\leadsto \frac{e^{\frac{\color{blue}{\left(-1 \cdot -1\right) \cdot \log x}}{n}}}{n \cdot x} \]
                                              6. metadata-evalN/A

                                                \[\leadsto \frac{e^{\frac{\color{blue}{1} \cdot \log x}{n}}}{n \cdot x} \]
                                              7. *-commutativeN/A

                                                \[\leadsto \frac{e^{\frac{\color{blue}{\log x \cdot 1}}{n}}}{n \cdot x} \]
                                              8. associate-/l*N/A

                                                \[\leadsto \frac{e^{\color{blue}{\log x \cdot \frac{1}{n}}}}{n \cdot x} \]
                                              9. exp-to-powN/A

                                                \[\leadsto \frac{\color{blue}{{x}^{\left(\frac{1}{n}\right)}}}{n \cdot x} \]
                                              10. lower-pow.f64N/A

                                                \[\leadsto \frac{\color{blue}{{x}^{\left(\frac{1}{n}\right)}}}{n \cdot x} \]
                                              11. lower-/.f64N/A

                                                \[\leadsto \frac{{x}^{\color{blue}{\left(\frac{1}{n}\right)}}}{n \cdot x} \]
                                              12. *-commutativeN/A

                                                \[\leadsto \frac{{x}^{\left(\frac{1}{n}\right)}}{\color{blue}{x \cdot n}} \]
                                              13. lower-*.f6494.8

                                                \[\leadsto \frac{{x}^{\left(\frac{1}{n}\right)}}{\color{blue}{x \cdot n}} \]
                                            5. Applied rewrites94.8%

                                              \[\leadsto \color{blue}{\frac{{x}^{\left(\frac{1}{n}\right)}}{x \cdot n}} \]
                                          4. Recombined 2 regimes into one program.
                                          5. Add Preprocessing

                                          Alternative 9: 60.5% accurate, 1.9× speedup?

                                          \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;x \leq 0.7:\\ \;\;\;\;\frac{\log x}{-n}\\ \mathbf{elif}\;x \leq 4 \cdot 10^{+116}:\\ \;\;\;\;\frac{\frac{\left(\left(1 - \frac{-0.3333333333333333}{x \cdot x}\right) - \frac{0.25}{x \cdot \left(x \cdot x\right)}\right) - \frac{0.5}{x}}{n}}{x}\\ \mathbf{else}:\\ \;\;\;\;1 - 1\\ \end{array} \end{array} \]
                                          (FPCore (x n)
                                           :precision binary64
                                           (if (<= x 0.7)
                                             (/ (log x) (- n))
                                             (if (<= x 4e+116)
                                               (/
                                                (/
                                                 (-
                                                  (- (- 1.0 (/ -0.3333333333333333 (* x x))) (/ 0.25 (* x (* x x))))
                                                  (/ 0.5 x))
                                                 n)
                                                x)
                                               (- 1.0 1.0))))
                                          double code(double x, double n) {
                                          	double tmp;
                                          	if (x <= 0.7) {
                                          		tmp = log(x) / -n;
                                          	} else if (x <= 4e+116) {
                                          		tmp = ((((1.0 - (-0.3333333333333333 / (x * x))) - (0.25 / (x * (x * x)))) - (0.5 / x)) / n) / x;
                                          	} else {
                                          		tmp = 1.0 - 1.0;
                                          	}
                                          	return tmp;
                                          }
                                          
                                          real(8) function code(x, n)
                                              real(8), intent (in) :: x
                                              real(8), intent (in) :: n
                                              real(8) :: tmp
                                              if (x <= 0.7d0) then
                                                  tmp = log(x) / -n
                                              else if (x <= 4d+116) then
                                                  tmp = ((((1.0d0 - ((-0.3333333333333333d0) / (x * x))) - (0.25d0 / (x * (x * x)))) - (0.5d0 / x)) / n) / x
                                              else
                                                  tmp = 1.0d0 - 1.0d0
                                              end if
                                              code = tmp
                                          end function
                                          
                                          public static double code(double x, double n) {
                                          	double tmp;
                                          	if (x <= 0.7) {
                                          		tmp = Math.log(x) / -n;
                                          	} else if (x <= 4e+116) {
                                          		tmp = ((((1.0 - (-0.3333333333333333 / (x * x))) - (0.25 / (x * (x * x)))) - (0.5 / x)) / n) / x;
                                          	} else {
                                          		tmp = 1.0 - 1.0;
                                          	}
                                          	return tmp;
                                          }
                                          
                                          def code(x, n):
                                          	tmp = 0
                                          	if x <= 0.7:
                                          		tmp = math.log(x) / -n
                                          	elif x <= 4e+116:
                                          		tmp = ((((1.0 - (-0.3333333333333333 / (x * x))) - (0.25 / (x * (x * x)))) - (0.5 / x)) / n) / x
                                          	else:
                                          		tmp = 1.0 - 1.0
                                          	return tmp
                                          
                                          function code(x, n)
                                          	tmp = 0.0
                                          	if (x <= 0.7)
                                          		tmp = Float64(log(x) / Float64(-n));
                                          	elseif (x <= 4e+116)
                                          		tmp = Float64(Float64(Float64(Float64(Float64(1.0 - Float64(-0.3333333333333333 / Float64(x * x))) - Float64(0.25 / Float64(x * Float64(x * x)))) - Float64(0.5 / x)) / n) / x);
                                          	else
                                          		tmp = Float64(1.0 - 1.0);
                                          	end
                                          	return tmp
                                          end
                                          
                                          function tmp_2 = code(x, n)
                                          	tmp = 0.0;
                                          	if (x <= 0.7)
                                          		tmp = log(x) / -n;
                                          	elseif (x <= 4e+116)
                                          		tmp = ((((1.0 - (-0.3333333333333333 / (x * x))) - (0.25 / (x * (x * x)))) - (0.5 / x)) / n) / x;
                                          	else
                                          		tmp = 1.0 - 1.0;
                                          	end
                                          	tmp_2 = tmp;
                                          end
                                          
                                          code[x_, n_] := If[LessEqual[x, 0.7], N[(N[Log[x], $MachinePrecision] / (-n)), $MachinePrecision], If[LessEqual[x, 4e+116], N[(N[(N[(N[(N[(1.0 - N[(-0.3333333333333333 / N[(x * x), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] - N[(0.25 / N[(x * N[(x * x), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] - N[(0.5 / x), $MachinePrecision]), $MachinePrecision] / n), $MachinePrecision] / x), $MachinePrecision], N[(1.0 - 1.0), $MachinePrecision]]]
                                          
                                          \begin{array}{l}
                                          
                                          \\
                                          \begin{array}{l}
                                          \mathbf{if}\;x \leq 0.7:\\
                                          \;\;\;\;\frac{\log x}{-n}\\
                                          
                                          \mathbf{elif}\;x \leq 4 \cdot 10^{+116}:\\
                                          \;\;\;\;\frac{\frac{\left(\left(1 - \frac{-0.3333333333333333}{x \cdot x}\right) - \frac{0.25}{x \cdot \left(x \cdot x\right)}\right) - \frac{0.5}{x}}{n}}{x}\\
                                          
                                          \mathbf{else}:\\
                                          \;\;\;\;1 - 1\\
                                          
                                          
                                          \end{array}
                                          \end{array}
                                          
                                          Derivation
                                          1. Split input into 3 regimes
                                          2. if x < 0.69999999999999996

                                            1. Initial program 45.3%

                                              \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                                            2. Add Preprocessing
                                            3. Taylor expanded in n around -inf

                                              \[\leadsto \color{blue}{-1 \cdot \frac{\left(-1 \cdot \log \left(1 + x\right) + -1 \cdot \frac{\left(-1 \cdot \frac{\frac{-1}{6} \cdot {\log \left(1 + x\right)}^{3} - \frac{-1}{6} \cdot {\log x}^{3}}{n} + \frac{1}{2} \cdot {\log \left(1 + x\right)}^{2}\right) - \frac{1}{2} \cdot {\log x}^{2}}{n}\right) - -1 \cdot \log x}{n}} \]
                                            4. Applied rewrites76.8%

                                              \[\leadsto \color{blue}{\frac{\left(\log x - \mathsf{log1p}\left(x\right)\right) - \frac{\mathsf{fma}\left(0.5, {\left(\mathsf{log1p}\left(x\right)\right)}^{2} - {\log x}^{2}, \frac{0.16666666666666666 \cdot \left({\left(\mathsf{log1p}\left(x\right)\right)}^{3} - {\log x}^{3}\right)}{n}\right)}{n}}{-n}} \]
                                            5. Taylor expanded in x around 0

                                              \[\leadsto \frac{\log x - \left(\frac{-1}{2} \cdot \frac{{\log x}^{2}}{n} + \frac{-1}{6} \cdot \frac{{\log x}^{3}}{{n}^{2}}\right)}{\mathsf{neg}\left(\color{blue}{n}\right)} \]
                                            6. Step-by-step derivation
                                              1. Applied rewrites76.1%

                                                \[\leadsto \frac{\log x + \mathsf{fma}\left(\frac{{\log x}^{3}}{n \cdot n}, 0.16666666666666666, \frac{0.5 \cdot {\log x}^{2}}{n}\right)}{-\color{blue}{n}} \]
                                              2. Taylor expanded in n around inf

                                                \[\leadsto \frac{\log x}{\mathsf{neg}\left(n\right)} \]
                                              3. Step-by-step derivation
                                                1. Applied rewrites50.3%

                                                  \[\leadsto \frac{\log x}{-n} \]

                                                if 0.69999999999999996 < x < 4.00000000000000006e116

                                                1. Initial program 49.2%

                                                  \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                                                2. Add Preprocessing
                                                3. Taylor expanded in x around inf

                                                  \[\leadsto \color{blue}{\frac{\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{n} + \left(\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}} \cdot \left(\frac{1}{2} \cdot \frac{1}{{n}^{2}} - \frac{1}{2} \cdot \frac{1}{n}\right)}{x} + \left(\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}} \cdot \left(\left(\frac{1}{24} \cdot \frac{1}{{n}^{4}} + \frac{11}{24} \cdot \frac{1}{{n}^{2}}\right) - \left(\frac{1}{4} \cdot \frac{1}{n} + \frac{1}{4} \cdot \frac{1}{{n}^{3}}\right)\right)}{{x}^{3}} + \frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}} \cdot \left(\left(\frac{1}{6} \cdot \frac{1}{{n}^{3}} + \frac{1}{3} \cdot \frac{1}{n}\right) - \frac{1}{2} \cdot \frac{1}{{n}^{2}}\right)}{{x}^{2}}\right)\right)}{x}} \]
                                                4. Applied rewrites72.0%

                                                  \[\leadsto \color{blue}{\frac{\mathsf{fma}\left({x}^{\left(\frac{1}{n}\right)}, \left(\frac{0.5}{x \cdot \left(n \cdot n\right)} - \frac{0.5}{x \cdot n}\right) + \left(\frac{\frac{0.16666666666666666}{n \cdot \left(n \cdot n\right)} + \left(\frac{0.3333333333333333}{n} + \frac{-0.5}{n \cdot n}\right)}{x \cdot x} + \frac{\frac{0.041666666666666664}{{n}^{4}} + \left(\frac{0.4583333333333333}{n \cdot n} + \left(\frac{-0.25}{n} + \frac{-0.25}{n \cdot \left(n \cdot n\right)}\right)\right)}{x \cdot \left(x \cdot x\right)}\right), \frac{{x}^{\left(\frac{1}{n}\right)}}{n}\right)}{x}} \]
                                                5. Taylor expanded in n around -inf

                                                  \[\leadsto \frac{-1 \cdot \frac{\left(\frac{1}{4} \cdot \frac{1}{{x}^{3}} + \frac{1}{2} \cdot \frac{1}{x}\right) - \left(1 + \frac{1}{3} \cdot \frac{1}{{x}^{2}}\right)}{n}}{x} \]
                                                6. Step-by-step derivation
                                                  1. Applied rewrites64.6%

                                                    \[\leadsto \frac{\frac{\frac{0.5}{x} + \left(\frac{0.25}{x \cdot \left(x \cdot x\right)} + \left(-1 + \frac{-0.3333333333333333}{x \cdot x}\right)\right)}{-n}}{x} \]

                                                  if 4.00000000000000006e116 < x

                                                  1. Initial program 79.1%

                                                    \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                                                  2. Add Preprocessing
                                                  3. Taylor expanded in x around 0

                                                    \[\leadsto \color{blue}{1} - {x}^{\left(\frac{1}{n}\right)} \]
                                                  4. Step-by-step derivation
                                                    1. Applied rewrites46.8%

                                                      \[\leadsto \color{blue}{1} - {x}^{\left(\frac{1}{n}\right)} \]
                                                    2. Taylor expanded in n around inf

                                                      \[\leadsto 1 - \color{blue}{1} \]
                                                    3. Step-by-step derivation
                                                      1. Applied rewrites79.1%

                                                        \[\leadsto 1 - \color{blue}{1} \]
                                                    4. Recombined 3 regimes into one program.
                                                    5. Final simplification61.5%

                                                      \[\leadsto \begin{array}{l} \mathbf{if}\;x \leq 0.7:\\ \;\;\;\;\frac{\log x}{-n}\\ \mathbf{elif}\;x \leq 4 \cdot 10^{+116}:\\ \;\;\;\;\frac{\frac{\left(\left(1 - \frac{-0.3333333333333333}{x \cdot x}\right) - \frac{0.25}{x \cdot \left(x \cdot x\right)}\right) - \frac{0.5}{x}}{n}}{x}\\ \mathbf{else}:\\ \;\;\;\;1 - 1\\ \end{array} \]
                                                    6. Add Preprocessing

                                                    Alternative 10: 46.4% accurate, 5.8× speedup?

                                                    \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;\frac{1}{n} \leq -1 \cdot 10^{+22}:\\ \;\;\;\;1 - 1\\ \mathbf{else}:\\ \;\;\;\;\frac{\frac{1}{x}}{n}\\ \end{array} \end{array} \]
                                                    (FPCore (x n)
                                                     :precision binary64
                                                     (if (<= (/ 1.0 n) -1e+22) (- 1.0 1.0) (/ (/ 1.0 x) n)))
                                                    double code(double x, double n) {
                                                    	double tmp;
                                                    	if ((1.0 / n) <= -1e+22) {
                                                    		tmp = 1.0 - 1.0;
                                                    	} else {
                                                    		tmp = (1.0 / x) / n;
                                                    	}
                                                    	return tmp;
                                                    }
                                                    
                                                    real(8) function code(x, n)
                                                        real(8), intent (in) :: x
                                                        real(8), intent (in) :: n
                                                        real(8) :: tmp
                                                        if ((1.0d0 / n) <= (-1d+22)) then
                                                            tmp = 1.0d0 - 1.0d0
                                                        else
                                                            tmp = (1.0d0 / x) / n
                                                        end if
                                                        code = tmp
                                                    end function
                                                    
                                                    public static double code(double x, double n) {
                                                    	double tmp;
                                                    	if ((1.0 / n) <= -1e+22) {
                                                    		tmp = 1.0 - 1.0;
                                                    	} else {
                                                    		tmp = (1.0 / x) / n;
                                                    	}
                                                    	return tmp;
                                                    }
                                                    
                                                    def code(x, n):
                                                    	tmp = 0
                                                    	if (1.0 / n) <= -1e+22:
                                                    		tmp = 1.0 - 1.0
                                                    	else:
                                                    		tmp = (1.0 / x) / n
                                                    	return tmp
                                                    
                                                    function code(x, n)
                                                    	tmp = 0.0
                                                    	if (Float64(1.0 / n) <= -1e+22)
                                                    		tmp = Float64(1.0 - 1.0);
                                                    	else
                                                    		tmp = Float64(Float64(1.0 / x) / n);
                                                    	end
                                                    	return tmp
                                                    end
                                                    
                                                    function tmp_2 = code(x, n)
                                                    	tmp = 0.0;
                                                    	if ((1.0 / n) <= -1e+22)
                                                    		tmp = 1.0 - 1.0;
                                                    	else
                                                    		tmp = (1.0 / x) / n;
                                                    	end
                                                    	tmp_2 = tmp;
                                                    end
                                                    
                                                    code[x_, n_] := If[LessEqual[N[(1.0 / n), $MachinePrecision], -1e+22], N[(1.0 - 1.0), $MachinePrecision], N[(N[(1.0 / x), $MachinePrecision] / n), $MachinePrecision]]
                                                    
                                                    \begin{array}{l}
                                                    
                                                    \\
                                                    \begin{array}{l}
                                                    \mathbf{if}\;\frac{1}{n} \leq -1 \cdot 10^{+22}:\\
                                                    \;\;\;\;1 - 1\\
                                                    
                                                    \mathbf{else}:\\
                                                    \;\;\;\;\frac{\frac{1}{x}}{n}\\
                                                    
                                                    
                                                    \end{array}
                                                    \end{array}
                                                    
                                                    Derivation
                                                    1. Split input into 2 regimes
                                                    2. if (/.f64 #s(literal 1 binary64) n) < -1e22

                                                      1. Initial program 100.0%

                                                        \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                                                      2. Add Preprocessing
                                                      3. Taylor expanded in x around 0

                                                        \[\leadsto \color{blue}{1} - {x}^{\left(\frac{1}{n}\right)} \]
                                                      4. Step-by-step derivation
                                                        1. Applied rewrites46.2%

                                                          \[\leadsto \color{blue}{1} - {x}^{\left(\frac{1}{n}\right)} \]
                                                        2. Taylor expanded in n around inf

                                                          \[\leadsto 1 - \color{blue}{1} \]
                                                        3. Step-by-step derivation
                                                          1. Applied rewrites56.3%

                                                            \[\leadsto 1 - \color{blue}{1} \]

                                                          if -1e22 < (/.f64 #s(literal 1 binary64) n)

                                                          1. Initial program 39.7%

                                                            \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                                                          2. Add Preprocessing
                                                          3. Taylor expanded in x around inf

                                                            \[\leadsto \color{blue}{\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{n \cdot x}} \]
                                                          4. Step-by-step derivation
                                                            1. lower-/.f64N/A

                                                              \[\leadsto \color{blue}{\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{n \cdot x}} \]
                                                            2. log-recN/A

                                                              \[\leadsto \frac{e^{-1 \cdot \frac{\color{blue}{\mathsf{neg}\left(\log x\right)}}{n}}}{n \cdot x} \]
                                                            3. mul-1-negN/A

                                                              \[\leadsto \frac{e^{-1 \cdot \frac{\color{blue}{-1 \cdot \log x}}{n}}}{n \cdot x} \]
                                                            4. associate-*r/N/A

                                                              \[\leadsto \frac{e^{\color{blue}{\frac{-1 \cdot \left(-1 \cdot \log x\right)}{n}}}}{n \cdot x} \]
                                                            5. associate-*r*N/A

                                                              \[\leadsto \frac{e^{\frac{\color{blue}{\left(-1 \cdot -1\right) \cdot \log x}}{n}}}{n \cdot x} \]
                                                            6. metadata-evalN/A

                                                              \[\leadsto \frac{e^{\frac{\color{blue}{1} \cdot \log x}{n}}}{n \cdot x} \]
                                                            7. *-commutativeN/A

                                                              \[\leadsto \frac{e^{\frac{\color{blue}{\log x \cdot 1}}{n}}}{n \cdot x} \]
                                                            8. associate-/l*N/A

                                                              \[\leadsto \frac{e^{\color{blue}{\log x \cdot \frac{1}{n}}}}{n \cdot x} \]
                                                            9. exp-to-powN/A

                                                              \[\leadsto \frac{\color{blue}{{x}^{\left(\frac{1}{n}\right)}}}{n \cdot x} \]
                                                            10. lower-pow.f64N/A

                                                              \[\leadsto \frac{\color{blue}{{x}^{\left(\frac{1}{n}\right)}}}{n \cdot x} \]
                                                            11. lower-/.f64N/A

                                                              \[\leadsto \frac{{x}^{\color{blue}{\left(\frac{1}{n}\right)}}}{n \cdot x} \]
                                                            12. *-commutativeN/A

                                                              \[\leadsto \frac{{x}^{\left(\frac{1}{n}\right)}}{\color{blue}{x \cdot n}} \]
                                                            13. lower-*.f6444.8

                                                              \[\leadsto \frac{{x}^{\left(\frac{1}{n}\right)}}{\color{blue}{x \cdot n}} \]
                                                          5. Applied rewrites44.8%

                                                            \[\leadsto \color{blue}{\frac{{x}^{\left(\frac{1}{n}\right)}}{x \cdot n}} \]
                                                          6. Step-by-step derivation
                                                            1. Applied rewrites45.6%

                                                              \[\leadsto \frac{\frac{{x}^{\left(\frac{1}{n}\right)}}{x}}{\color{blue}{n}} \]
                                                            2. Taylor expanded in n around inf

                                                              \[\leadsto \frac{\frac{1}{x}}{n} \]
                                                            3. Step-by-step derivation
                                                              1. Applied rewrites46.2%

                                                                \[\leadsto \frac{\frac{1}{x}}{n} \]
                                                            4. Recombined 2 regimes into one program.
                                                            5. Add Preprocessing

                                                            Alternative 11: 46.4% accurate, 5.8× speedup?

                                                            \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;\frac{1}{n} \leq -1 \cdot 10^{+22}:\\ \;\;\;\;1 - 1\\ \mathbf{else}:\\ \;\;\;\;\frac{\frac{1}{n}}{x}\\ \end{array} \end{array} \]
                                                            (FPCore (x n)
                                                             :precision binary64
                                                             (if (<= (/ 1.0 n) -1e+22) (- 1.0 1.0) (/ (/ 1.0 n) x)))
                                                            double code(double x, double n) {
                                                            	double tmp;
                                                            	if ((1.0 / n) <= -1e+22) {
                                                            		tmp = 1.0 - 1.0;
                                                            	} else {
                                                            		tmp = (1.0 / n) / x;
                                                            	}
                                                            	return tmp;
                                                            }
                                                            
                                                            real(8) function code(x, n)
                                                                real(8), intent (in) :: x
                                                                real(8), intent (in) :: n
                                                                real(8) :: tmp
                                                                if ((1.0d0 / n) <= (-1d+22)) then
                                                                    tmp = 1.0d0 - 1.0d0
                                                                else
                                                                    tmp = (1.0d0 / n) / x
                                                                end if
                                                                code = tmp
                                                            end function
                                                            
                                                            public static double code(double x, double n) {
                                                            	double tmp;
                                                            	if ((1.0 / n) <= -1e+22) {
                                                            		tmp = 1.0 - 1.0;
                                                            	} else {
                                                            		tmp = (1.0 / n) / x;
                                                            	}
                                                            	return tmp;
                                                            }
                                                            
                                                            def code(x, n):
                                                            	tmp = 0
                                                            	if (1.0 / n) <= -1e+22:
                                                            		tmp = 1.0 - 1.0
                                                            	else:
                                                            		tmp = (1.0 / n) / x
                                                            	return tmp
                                                            
                                                            function code(x, n)
                                                            	tmp = 0.0
                                                            	if (Float64(1.0 / n) <= -1e+22)
                                                            		tmp = Float64(1.0 - 1.0);
                                                            	else
                                                            		tmp = Float64(Float64(1.0 / n) / x);
                                                            	end
                                                            	return tmp
                                                            end
                                                            
                                                            function tmp_2 = code(x, n)
                                                            	tmp = 0.0;
                                                            	if ((1.0 / n) <= -1e+22)
                                                            		tmp = 1.0 - 1.0;
                                                            	else
                                                            		tmp = (1.0 / n) / x;
                                                            	end
                                                            	tmp_2 = tmp;
                                                            end
                                                            
                                                            code[x_, n_] := If[LessEqual[N[(1.0 / n), $MachinePrecision], -1e+22], N[(1.0 - 1.0), $MachinePrecision], N[(N[(1.0 / n), $MachinePrecision] / x), $MachinePrecision]]
                                                            
                                                            \begin{array}{l}
                                                            
                                                            \\
                                                            \begin{array}{l}
                                                            \mathbf{if}\;\frac{1}{n} \leq -1 \cdot 10^{+22}:\\
                                                            \;\;\;\;1 - 1\\
                                                            
                                                            \mathbf{else}:\\
                                                            \;\;\;\;\frac{\frac{1}{n}}{x}\\
                                                            
                                                            
                                                            \end{array}
                                                            \end{array}
                                                            
                                                            Derivation
                                                            1. Split input into 2 regimes
                                                            2. if (/.f64 #s(literal 1 binary64) n) < -1e22

                                                              1. Initial program 100.0%

                                                                \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                                                              2. Add Preprocessing
                                                              3. Taylor expanded in x around 0

                                                                \[\leadsto \color{blue}{1} - {x}^{\left(\frac{1}{n}\right)} \]
                                                              4. Step-by-step derivation
                                                                1. Applied rewrites46.2%

                                                                  \[\leadsto \color{blue}{1} - {x}^{\left(\frac{1}{n}\right)} \]
                                                                2. Taylor expanded in n around inf

                                                                  \[\leadsto 1 - \color{blue}{1} \]
                                                                3. Step-by-step derivation
                                                                  1. Applied rewrites56.3%

                                                                    \[\leadsto 1 - \color{blue}{1} \]

                                                                  if -1e22 < (/.f64 #s(literal 1 binary64) n)

                                                                  1. Initial program 39.7%

                                                                    \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                                                                  2. Add Preprocessing
                                                                  3. Taylor expanded in x around inf

                                                                    \[\leadsto \color{blue}{\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{n \cdot x}} \]
                                                                  4. Step-by-step derivation
                                                                    1. lower-/.f64N/A

                                                                      \[\leadsto \color{blue}{\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{n \cdot x}} \]
                                                                    2. log-recN/A

                                                                      \[\leadsto \frac{e^{-1 \cdot \frac{\color{blue}{\mathsf{neg}\left(\log x\right)}}{n}}}{n \cdot x} \]
                                                                    3. mul-1-negN/A

                                                                      \[\leadsto \frac{e^{-1 \cdot \frac{\color{blue}{-1 \cdot \log x}}{n}}}{n \cdot x} \]
                                                                    4. associate-*r/N/A

                                                                      \[\leadsto \frac{e^{\color{blue}{\frac{-1 \cdot \left(-1 \cdot \log x\right)}{n}}}}{n \cdot x} \]
                                                                    5. associate-*r*N/A

                                                                      \[\leadsto \frac{e^{\frac{\color{blue}{\left(-1 \cdot -1\right) \cdot \log x}}{n}}}{n \cdot x} \]
                                                                    6. metadata-evalN/A

                                                                      \[\leadsto \frac{e^{\frac{\color{blue}{1} \cdot \log x}{n}}}{n \cdot x} \]
                                                                    7. *-commutativeN/A

                                                                      \[\leadsto \frac{e^{\frac{\color{blue}{\log x \cdot 1}}{n}}}{n \cdot x} \]
                                                                    8. associate-/l*N/A

                                                                      \[\leadsto \frac{e^{\color{blue}{\log x \cdot \frac{1}{n}}}}{n \cdot x} \]
                                                                    9. exp-to-powN/A

                                                                      \[\leadsto \frac{\color{blue}{{x}^{\left(\frac{1}{n}\right)}}}{n \cdot x} \]
                                                                    10. lower-pow.f64N/A

                                                                      \[\leadsto \frac{\color{blue}{{x}^{\left(\frac{1}{n}\right)}}}{n \cdot x} \]
                                                                    11. lower-/.f64N/A

                                                                      \[\leadsto \frac{{x}^{\color{blue}{\left(\frac{1}{n}\right)}}}{n \cdot x} \]
                                                                    12. *-commutativeN/A

                                                                      \[\leadsto \frac{{x}^{\left(\frac{1}{n}\right)}}{\color{blue}{x \cdot n}} \]
                                                                    13. lower-*.f6444.8

                                                                      \[\leadsto \frac{{x}^{\left(\frac{1}{n}\right)}}{\color{blue}{x \cdot n}} \]
                                                                  5. Applied rewrites44.8%

                                                                    \[\leadsto \color{blue}{\frac{{x}^{\left(\frac{1}{n}\right)}}{x \cdot n}} \]
                                                                  6. Taylor expanded in n around inf

                                                                    \[\leadsto \frac{1}{\color{blue}{x} \cdot n} \]
                                                                  7. Step-by-step derivation
                                                                    1. Applied rewrites45.7%

                                                                      \[\leadsto \frac{1}{\color{blue}{x} \cdot n} \]
                                                                    2. Step-by-step derivation
                                                                      1. Applied rewrites46.2%

                                                                        \[\leadsto \frac{\frac{1}{n}}{\color{blue}{x}} \]
                                                                    3. Recombined 2 regimes into one program.
                                                                    4. Add Preprocessing

                                                                    Alternative 12: 45.8% accurate, 6.8× speedup?

                                                                    \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;\frac{1}{n} \leq -1 \cdot 10^{+22}:\\ \;\;\;\;1 - 1\\ \mathbf{else}:\\ \;\;\;\;\frac{1}{x \cdot n}\\ \end{array} \end{array} \]
                                                                    (FPCore (x n)
                                                                     :precision binary64
                                                                     (if (<= (/ 1.0 n) -1e+22) (- 1.0 1.0) (/ 1.0 (* x n))))
                                                                    double code(double x, double n) {
                                                                    	double tmp;
                                                                    	if ((1.0 / n) <= -1e+22) {
                                                                    		tmp = 1.0 - 1.0;
                                                                    	} else {
                                                                    		tmp = 1.0 / (x * n);
                                                                    	}
                                                                    	return tmp;
                                                                    }
                                                                    
                                                                    real(8) function code(x, n)
                                                                        real(8), intent (in) :: x
                                                                        real(8), intent (in) :: n
                                                                        real(8) :: tmp
                                                                        if ((1.0d0 / n) <= (-1d+22)) then
                                                                            tmp = 1.0d0 - 1.0d0
                                                                        else
                                                                            tmp = 1.0d0 / (x * n)
                                                                        end if
                                                                        code = tmp
                                                                    end function
                                                                    
                                                                    public static double code(double x, double n) {
                                                                    	double tmp;
                                                                    	if ((1.0 / n) <= -1e+22) {
                                                                    		tmp = 1.0 - 1.0;
                                                                    	} else {
                                                                    		tmp = 1.0 / (x * n);
                                                                    	}
                                                                    	return tmp;
                                                                    }
                                                                    
                                                                    def code(x, n):
                                                                    	tmp = 0
                                                                    	if (1.0 / n) <= -1e+22:
                                                                    		tmp = 1.0 - 1.0
                                                                    	else:
                                                                    		tmp = 1.0 / (x * n)
                                                                    	return tmp
                                                                    
                                                                    function code(x, n)
                                                                    	tmp = 0.0
                                                                    	if (Float64(1.0 / n) <= -1e+22)
                                                                    		tmp = Float64(1.0 - 1.0);
                                                                    	else
                                                                    		tmp = Float64(1.0 / Float64(x * n));
                                                                    	end
                                                                    	return tmp
                                                                    end
                                                                    
                                                                    function tmp_2 = code(x, n)
                                                                    	tmp = 0.0;
                                                                    	if ((1.0 / n) <= -1e+22)
                                                                    		tmp = 1.0 - 1.0;
                                                                    	else
                                                                    		tmp = 1.0 / (x * n);
                                                                    	end
                                                                    	tmp_2 = tmp;
                                                                    end
                                                                    
                                                                    code[x_, n_] := If[LessEqual[N[(1.0 / n), $MachinePrecision], -1e+22], N[(1.0 - 1.0), $MachinePrecision], N[(1.0 / N[(x * n), $MachinePrecision]), $MachinePrecision]]
                                                                    
                                                                    \begin{array}{l}
                                                                    
                                                                    \\
                                                                    \begin{array}{l}
                                                                    \mathbf{if}\;\frac{1}{n} \leq -1 \cdot 10^{+22}:\\
                                                                    \;\;\;\;1 - 1\\
                                                                    
                                                                    \mathbf{else}:\\
                                                                    \;\;\;\;\frac{1}{x \cdot n}\\
                                                                    
                                                                    
                                                                    \end{array}
                                                                    \end{array}
                                                                    
                                                                    Derivation
                                                                    1. Split input into 2 regimes
                                                                    2. if (/.f64 #s(literal 1 binary64) n) < -1e22

                                                                      1. Initial program 100.0%

                                                                        \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                                                                      2. Add Preprocessing
                                                                      3. Taylor expanded in x around 0

                                                                        \[\leadsto \color{blue}{1} - {x}^{\left(\frac{1}{n}\right)} \]
                                                                      4. Step-by-step derivation
                                                                        1. Applied rewrites46.2%

                                                                          \[\leadsto \color{blue}{1} - {x}^{\left(\frac{1}{n}\right)} \]
                                                                        2. Taylor expanded in n around inf

                                                                          \[\leadsto 1 - \color{blue}{1} \]
                                                                        3. Step-by-step derivation
                                                                          1. Applied rewrites56.3%

                                                                            \[\leadsto 1 - \color{blue}{1} \]

                                                                          if -1e22 < (/.f64 #s(literal 1 binary64) n)

                                                                          1. Initial program 39.7%

                                                                            \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                                                                          2. Add Preprocessing
                                                                          3. Taylor expanded in x around inf

                                                                            \[\leadsto \color{blue}{\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{n \cdot x}} \]
                                                                          4. Step-by-step derivation
                                                                            1. lower-/.f64N/A

                                                                              \[\leadsto \color{blue}{\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{n \cdot x}} \]
                                                                            2. log-recN/A

                                                                              \[\leadsto \frac{e^{-1 \cdot \frac{\color{blue}{\mathsf{neg}\left(\log x\right)}}{n}}}{n \cdot x} \]
                                                                            3. mul-1-negN/A

                                                                              \[\leadsto \frac{e^{-1 \cdot \frac{\color{blue}{-1 \cdot \log x}}{n}}}{n \cdot x} \]
                                                                            4. associate-*r/N/A

                                                                              \[\leadsto \frac{e^{\color{blue}{\frac{-1 \cdot \left(-1 \cdot \log x\right)}{n}}}}{n \cdot x} \]
                                                                            5. associate-*r*N/A

                                                                              \[\leadsto \frac{e^{\frac{\color{blue}{\left(-1 \cdot -1\right) \cdot \log x}}{n}}}{n \cdot x} \]
                                                                            6. metadata-evalN/A

                                                                              \[\leadsto \frac{e^{\frac{\color{blue}{1} \cdot \log x}{n}}}{n \cdot x} \]
                                                                            7. *-commutativeN/A

                                                                              \[\leadsto \frac{e^{\frac{\color{blue}{\log x \cdot 1}}{n}}}{n \cdot x} \]
                                                                            8. associate-/l*N/A

                                                                              \[\leadsto \frac{e^{\color{blue}{\log x \cdot \frac{1}{n}}}}{n \cdot x} \]
                                                                            9. exp-to-powN/A

                                                                              \[\leadsto \frac{\color{blue}{{x}^{\left(\frac{1}{n}\right)}}}{n \cdot x} \]
                                                                            10. lower-pow.f64N/A

                                                                              \[\leadsto \frac{\color{blue}{{x}^{\left(\frac{1}{n}\right)}}}{n \cdot x} \]
                                                                            11. lower-/.f64N/A

                                                                              \[\leadsto \frac{{x}^{\color{blue}{\left(\frac{1}{n}\right)}}}{n \cdot x} \]
                                                                            12. *-commutativeN/A

                                                                              \[\leadsto \frac{{x}^{\left(\frac{1}{n}\right)}}{\color{blue}{x \cdot n}} \]
                                                                            13. lower-*.f6444.8

                                                                              \[\leadsto \frac{{x}^{\left(\frac{1}{n}\right)}}{\color{blue}{x \cdot n}} \]
                                                                          5. Applied rewrites44.8%

                                                                            \[\leadsto \color{blue}{\frac{{x}^{\left(\frac{1}{n}\right)}}{x \cdot n}} \]
                                                                          6. Taylor expanded in n around inf

                                                                            \[\leadsto \frac{1}{\color{blue}{x} \cdot n} \]
                                                                          7. Step-by-step derivation
                                                                            1. Applied rewrites45.7%

                                                                              \[\leadsto \frac{1}{\color{blue}{x} \cdot n} \]
                                                                          8. Recombined 2 regimes into one program.
                                                                          9. Add Preprocessing

                                                                          Alternative 13: 30.4% accurate, 57.8× speedup?

                                                                          \[\begin{array}{l} \\ 1 - 1 \end{array} \]
                                                                          (FPCore (x n) :precision binary64 (- 1.0 1.0))
                                                                          double code(double x, double n) {
                                                                          	return 1.0 - 1.0;
                                                                          }
                                                                          
                                                                          real(8) function code(x, n)
                                                                              real(8), intent (in) :: x
                                                                              real(8), intent (in) :: n
                                                                              code = 1.0d0 - 1.0d0
                                                                          end function
                                                                          
                                                                          public static double code(double x, double n) {
                                                                          	return 1.0 - 1.0;
                                                                          }
                                                                          
                                                                          def code(x, n):
                                                                          	return 1.0 - 1.0
                                                                          
                                                                          function code(x, n)
                                                                          	return Float64(1.0 - 1.0)
                                                                          end
                                                                          
                                                                          function tmp = code(x, n)
                                                                          	tmp = 1.0 - 1.0;
                                                                          end
                                                                          
                                                                          code[x_, n_] := N[(1.0 - 1.0), $MachinePrecision]
                                                                          
                                                                          \begin{array}{l}
                                                                          
                                                                          \\
                                                                          1 - 1
                                                                          \end{array}
                                                                          
                                                                          Derivation
                                                                          1. Initial program 56.7%

                                                                            \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                                                                          2. Add Preprocessing
                                                                          3. Taylor expanded in x around 0

                                                                            \[\leadsto \color{blue}{1} - {x}^{\left(\frac{1}{n}\right)} \]
                                                                          4. Step-by-step derivation
                                                                            1. Applied rewrites40.3%

                                                                              \[\leadsto \color{blue}{1} - {x}^{\left(\frac{1}{n}\right)} \]
                                                                            2. Taylor expanded in n around inf

                                                                              \[\leadsto 1 - \color{blue}{1} \]
                                                                            3. Step-by-step derivation
                                                                              1. Applied rewrites34.1%

                                                                                \[\leadsto 1 - \color{blue}{1} \]
                                                                              2. Add Preprocessing

                                                                              Reproduce

                                                                              ?
                                                                              herbie shell --seed 2024237 
                                                                              (FPCore (x n)
                                                                                :name "2nthrt (problem 3.4.6)"
                                                                                :precision binary64
                                                                                (- (pow (+ x 1.0) (/ 1.0 n)) (pow x (/ 1.0 n))))