Data.Random.Distribution.Normal:normalF from random-fu-0.2.6.2

Percentage Accurate: 100.0% → 100.0%
Time: 26.5s
Alternatives: 12
Speedup: 1.0×

Specification

?
\[\begin{array}{l} \\ e^{\left(x \cdot y\right) \cdot y} \end{array} \]
(FPCore (x y) :precision binary64 (exp (* (* x y) y)))
double code(double x, double y) {
	return exp(((x * y) * y));
}
real(8) function code(x, y)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    code = exp(((x * y) * y))
end function
public static double code(double x, double y) {
	return Math.exp(((x * y) * y));
}
def code(x, y):
	return math.exp(((x * y) * y))
function code(x, y)
	return exp(Float64(Float64(x * y) * y))
end
function tmp = code(x, y)
	tmp = exp(((x * y) * y));
end
code[x_, y_] := N[Exp[N[(N[(x * y), $MachinePrecision] * y), $MachinePrecision]], $MachinePrecision]
\begin{array}{l}

\\
e^{\left(x \cdot y\right) \cdot y}
\end{array}

Sampling outcomes in binary64 precision:

Local Percentage Accuracy vs ?

The average percentage accuracy by input value. Horizontal axis shows value of an input variable; the variable is choosen in the title. Vertical axis is accuracy; higher is better. Red represent the original program, while blue represents Herbie's suggestion. These can be toggled with buttons below the plot. The line is an average while dots represent individual samples.

Accuracy vs Speed?

Herbie found 12 alternatives:

AlternativeAccuracySpeedup
The accuracy (vertical axis) and speed (horizontal axis) of each alternatives. Up and to the right is better. The red square shows the initial program, and each blue circle shows an alternative.The line shows the best available speed-accuracy tradeoffs.

Initial Program: 100.0% accurate, 1.0× speedup?

\[\begin{array}{l} \\ e^{\left(x \cdot y\right) \cdot y} \end{array} \]
(FPCore (x y) :precision binary64 (exp (* (* x y) y)))
double code(double x, double y) {
	return exp(((x * y) * y));
}
real(8) function code(x, y)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    code = exp(((x * y) * y))
end function
public static double code(double x, double y) {
	return Math.exp(((x * y) * y));
}
def code(x, y):
	return math.exp(((x * y) * y))
function code(x, y)
	return exp(Float64(Float64(x * y) * y))
end
function tmp = code(x, y)
	tmp = exp(((x * y) * y));
end
code[x_, y_] := N[Exp[N[(N[(x * y), $MachinePrecision] * y), $MachinePrecision]], $MachinePrecision]
\begin{array}{l}

\\
e^{\left(x \cdot y\right) \cdot y}
\end{array}

Alternative 1: 100.0% accurate, 1.0× speedup?

\[\begin{array}{l} \\ e^{\left(y \cdot x\right) \cdot y} \end{array} \]
(FPCore (x y) :precision binary64 (exp (* (* y x) y)))
double code(double x, double y) {
	return exp(((y * x) * y));
}
real(8) function code(x, y)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    code = exp(((y * x) * y))
end function
public static double code(double x, double y) {
	return Math.exp(((y * x) * y));
}
def code(x, y):
	return math.exp(((y * x) * y))
function code(x, y)
	return exp(Float64(Float64(y * x) * y))
end
function tmp = code(x, y)
	tmp = exp(((y * x) * y));
end
code[x_, y_] := N[Exp[N[(N[(y * x), $MachinePrecision] * y), $MachinePrecision]], $MachinePrecision]
\begin{array}{l}

\\
e^{\left(y \cdot x\right) \cdot y}
\end{array}
Derivation
  1. Initial program 100.0%

    \[e^{\left(x \cdot y\right) \cdot y} \]
  2. Add Preprocessing
  3. Final simplification100.0%

    \[\leadsto e^{\left(y \cdot x\right) \cdot y} \]
  4. Add Preprocessing

Alternative 2: 67.6% accurate, 0.9× speedup?

\[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;e^{\left(y \cdot x\right) \cdot y} \leq 2:\\ \;\;\;\;1\\ \mathbf{else}:\\ \;\;\;\;\left(y \cdot y\right) \cdot x\\ \end{array} \end{array} \]
(FPCore (x y)
 :precision binary64
 (if (<= (exp (* (* y x) y)) 2.0) 1.0 (* (* y y) x)))
double code(double x, double y) {
	double tmp;
	if (exp(((y * x) * y)) <= 2.0) {
		tmp = 1.0;
	} else {
		tmp = (y * y) * x;
	}
	return tmp;
}
real(8) function code(x, y)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    real(8) :: tmp
    if (exp(((y * x) * y)) <= 2.0d0) then
        tmp = 1.0d0
    else
        tmp = (y * y) * x
    end if
    code = tmp
end function
public static double code(double x, double y) {
	double tmp;
	if (Math.exp(((y * x) * y)) <= 2.0) {
		tmp = 1.0;
	} else {
		tmp = (y * y) * x;
	}
	return tmp;
}
def code(x, y):
	tmp = 0
	if math.exp(((y * x) * y)) <= 2.0:
		tmp = 1.0
	else:
		tmp = (y * y) * x
	return tmp
function code(x, y)
	tmp = 0.0
	if (exp(Float64(Float64(y * x) * y)) <= 2.0)
		tmp = 1.0;
	else
		tmp = Float64(Float64(y * y) * x);
	end
	return tmp
end
function tmp_2 = code(x, y)
	tmp = 0.0;
	if (exp(((y * x) * y)) <= 2.0)
		tmp = 1.0;
	else
		tmp = (y * y) * x;
	end
	tmp_2 = tmp;
end
code[x_, y_] := If[LessEqual[N[Exp[N[(N[(y * x), $MachinePrecision] * y), $MachinePrecision]], $MachinePrecision], 2.0], 1.0, N[(N[(y * y), $MachinePrecision] * x), $MachinePrecision]]
\begin{array}{l}

\\
\begin{array}{l}
\mathbf{if}\;e^{\left(y \cdot x\right) \cdot y} \leq 2:\\
\;\;\;\;1\\

\mathbf{else}:\\
\;\;\;\;\left(y \cdot y\right) \cdot x\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if (exp.f64 (*.f64 (*.f64 x y) y)) < 2

    1. Initial program 100.0%

      \[e^{\left(x \cdot y\right) \cdot y} \]
    2. Add Preprocessing
    3. Taylor expanded in y around 0

      \[\leadsto \color{blue}{1} \]
    4. Step-by-step derivation
      1. Applied rewrites71.7%

        \[\leadsto \color{blue}{1} \]

      if 2 < (exp.f64 (*.f64 (*.f64 x y) y))

      1. Initial program 99.8%

        \[e^{\left(x \cdot y\right) \cdot y} \]
      2. Add Preprocessing
      3. Taylor expanded in y around 0

        \[\leadsto \color{blue}{1 + x \cdot {y}^{2}} \]
      4. Step-by-step derivation
        1. +-commutativeN/A

          \[\leadsto \color{blue}{x \cdot {y}^{2} + 1} \]
        2. *-commutativeN/A

          \[\leadsto \color{blue}{{y}^{2} \cdot x} + 1 \]
        3. lower-fma.f64N/A

          \[\leadsto \color{blue}{\mathsf{fma}\left({y}^{2}, x, 1\right)} \]
        4. unpow2N/A

          \[\leadsto \mathsf{fma}\left(\color{blue}{y \cdot y}, x, 1\right) \]
        5. lower-*.f6463.2

          \[\leadsto \mathsf{fma}\left(\color{blue}{y \cdot y}, x, 1\right) \]
      5. Applied rewrites63.2%

        \[\leadsto \color{blue}{\mathsf{fma}\left(y \cdot y, x, 1\right)} \]
      6. Taylor expanded in y around inf

        \[\leadsto x \cdot \color{blue}{{y}^{2}} \]
      7. Step-by-step derivation
        1. Applied rewrites63.2%

          \[\leadsto \left(y \cdot y\right) \cdot \color{blue}{x} \]
      8. Recombined 2 regimes into one program.
      9. Final simplification69.7%

        \[\leadsto \begin{array}{l} \mathbf{if}\;e^{\left(y \cdot x\right) \cdot y} \leq 2:\\ \;\;\;\;1\\ \mathbf{else}:\\ \;\;\;\;\left(y \cdot y\right) \cdot x\\ \end{array} \]
      10. Add Preprocessing

      Alternative 3: 54.2% accurate, 0.9× speedup?

      \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;e^{\left(y \cdot x\right) \cdot y} \leq 2:\\ \;\;\;\;1\\ \mathbf{else}:\\ \;\;\;\;\mathsf{fma}\left(y, x, 1\right)\\ \end{array} \end{array} \]
      (FPCore (x y)
       :precision binary64
       (if (<= (exp (* (* y x) y)) 2.0) 1.0 (fma y x 1.0)))
      double code(double x, double y) {
      	double tmp;
      	if (exp(((y * x) * y)) <= 2.0) {
      		tmp = 1.0;
      	} else {
      		tmp = fma(y, x, 1.0);
      	}
      	return tmp;
      }
      
      function code(x, y)
      	tmp = 0.0
      	if (exp(Float64(Float64(y * x) * y)) <= 2.0)
      		tmp = 1.0;
      	else
      		tmp = fma(y, x, 1.0);
      	end
      	return tmp
      end
      
      code[x_, y_] := If[LessEqual[N[Exp[N[(N[(y * x), $MachinePrecision] * y), $MachinePrecision]], $MachinePrecision], 2.0], 1.0, N[(y * x + 1.0), $MachinePrecision]]
      
      \begin{array}{l}
      
      \\
      \begin{array}{l}
      \mathbf{if}\;e^{\left(y \cdot x\right) \cdot y} \leq 2:\\
      \;\;\;\;1\\
      
      \mathbf{else}:\\
      \;\;\;\;\mathsf{fma}\left(y, x, 1\right)\\
      
      
      \end{array}
      \end{array}
      
      Derivation
      1. Split input into 2 regimes
      2. if (exp.f64 (*.f64 (*.f64 x y) y)) < 2

        1. Initial program 100.0%

          \[e^{\left(x \cdot y\right) \cdot y} \]
        2. Add Preprocessing
        3. Taylor expanded in y around 0

          \[\leadsto \color{blue}{1} \]
        4. Step-by-step derivation
          1. Applied rewrites71.7%

            \[\leadsto \color{blue}{1} \]

          if 2 < (exp.f64 (*.f64 (*.f64 x y) y))

          1. Initial program 99.8%

            \[e^{\left(x \cdot y\right) \cdot y} \]
          2. Add Preprocessing
          3. Applied rewrites47.0%

            \[\leadsto e^{\color{blue}{x} \cdot y} \]
          4. Taylor expanded in y around 0

            \[\leadsto \color{blue}{1 + x \cdot y} \]
          5. Step-by-step derivation
            1. +-commutativeN/A

              \[\leadsto \color{blue}{x \cdot y + 1} \]
            2. *-commutativeN/A

              \[\leadsto \color{blue}{y \cdot x} + 1 \]
            3. lower-fma.f6414.3

              \[\leadsto \color{blue}{\mathsf{fma}\left(y, x, 1\right)} \]
          6. Applied rewrites14.3%

            \[\leadsto \color{blue}{\mathsf{fma}\left(y, x, 1\right)} \]
        5. Recombined 2 regimes into one program.
        6. Final simplification58.5%

          \[\leadsto \begin{array}{l} \mathbf{if}\;e^{\left(y \cdot x\right) \cdot y} \leq 2:\\ \;\;\;\;1\\ \mathbf{else}:\\ \;\;\;\;\mathsf{fma}\left(y, x, 1\right)\\ \end{array} \]
        7. Add Preprocessing

        Alternative 4: 83.8% accurate, 0.9× speedup?

        \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;\left(y \cdot x\right) \cdot y \leq -1 \cdot 10^{+25}:\\ \;\;\;\;e^{y \cdot x}\\ \mathbf{else}:\\ \;\;\;\;\mathsf{fma}\left(\left(\mathsf{fma}\left(\mathsf{fma}\left(y \cdot x, 0.16666666666666666 \cdot y, 0.5\right) \cdot x, y \cdot y, 1\right) \cdot y\right) \cdot y, x, 1\right)\\ \end{array} \end{array} \]
        (FPCore (x y)
         :precision binary64
         (if (<= (* (* y x) y) -1e+25)
           (exp (* y x))
           (fma
            (*
             (* (fma (* (fma (* y x) (* 0.16666666666666666 y) 0.5) x) (* y y) 1.0) y)
             y)
            x
            1.0)))
        double code(double x, double y) {
        	double tmp;
        	if (((y * x) * y) <= -1e+25) {
        		tmp = exp((y * x));
        	} else {
        		tmp = fma(((fma((fma((y * x), (0.16666666666666666 * y), 0.5) * x), (y * y), 1.0) * y) * y), x, 1.0);
        	}
        	return tmp;
        }
        
        function code(x, y)
        	tmp = 0.0
        	if (Float64(Float64(y * x) * y) <= -1e+25)
        		tmp = exp(Float64(y * x));
        	else
        		tmp = fma(Float64(Float64(fma(Float64(fma(Float64(y * x), Float64(0.16666666666666666 * y), 0.5) * x), Float64(y * y), 1.0) * y) * y), x, 1.0);
        	end
        	return tmp
        end
        
        code[x_, y_] := If[LessEqual[N[(N[(y * x), $MachinePrecision] * y), $MachinePrecision], -1e+25], N[Exp[N[(y * x), $MachinePrecision]], $MachinePrecision], N[(N[(N[(N[(N[(N[(N[(y * x), $MachinePrecision] * N[(0.16666666666666666 * y), $MachinePrecision] + 0.5), $MachinePrecision] * x), $MachinePrecision] * N[(y * y), $MachinePrecision] + 1.0), $MachinePrecision] * y), $MachinePrecision] * y), $MachinePrecision] * x + 1.0), $MachinePrecision]]
        
        \begin{array}{l}
        
        \\
        \begin{array}{l}
        \mathbf{if}\;\left(y \cdot x\right) \cdot y \leq -1 \cdot 10^{+25}:\\
        \;\;\;\;e^{y \cdot x}\\
        
        \mathbf{else}:\\
        \;\;\;\;\mathsf{fma}\left(\left(\mathsf{fma}\left(\mathsf{fma}\left(y \cdot x, 0.16666666666666666 \cdot y, 0.5\right) \cdot x, y \cdot y, 1\right) \cdot y\right) \cdot y, x, 1\right)\\
        
        
        \end{array}
        \end{array}
        
        Derivation
        1. Split input into 2 regimes
        2. if (*.f64 (*.f64 x y) y) < -1.00000000000000009e25

          1. Initial program 100.0%

            \[e^{\left(x \cdot y\right) \cdot y} \]
          2. Add Preprocessing
          3. Applied rewrites55.3%

            \[\leadsto e^{\color{blue}{x} \cdot y} \]

          if -1.00000000000000009e25 < (*.f64 (*.f64 x y) y)

          1. Initial program 99.9%

            \[e^{\left(x \cdot y\right) \cdot y} \]
          2. Add Preprocessing
          3. Taylor expanded in y around 0

            \[\leadsto \color{blue}{1 + {y}^{2} \cdot \left(x + {y}^{2} \cdot \left(\frac{1}{6} \cdot \left({x}^{3} \cdot {y}^{2}\right) + \frac{1}{2} \cdot {x}^{2}\right)\right)} \]
          4. Applied rewrites95.3%

            \[\leadsto \color{blue}{\mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(0.16666666666666666 \cdot y, y \cdot x, 0.5\right) \cdot x, y \cdot y, 1\right) \cdot y, y \cdot x, 1\right)} \]
          5. Step-by-step derivation
            1. Applied rewrites96.7%

              \[\leadsto \mathsf{fma}\left(\left(\mathsf{fma}\left(\mathsf{fma}\left(y \cdot x, 0.16666666666666666 \cdot y, 0.5\right) \cdot x, y \cdot y, 1\right) \cdot y\right) \cdot y, \color{blue}{x}, 1\right) \]
          6. Recombined 2 regimes into one program.
          7. Final simplification87.5%

            \[\leadsto \begin{array}{l} \mathbf{if}\;\left(y \cdot x\right) \cdot y \leq -1 \cdot 10^{+25}:\\ \;\;\;\;e^{y \cdot x}\\ \mathbf{else}:\\ \;\;\;\;\mathsf{fma}\left(\left(\mathsf{fma}\left(\mathsf{fma}\left(y \cdot x, 0.16666666666666666 \cdot y, 0.5\right) \cdot x, y \cdot y, 1\right) \cdot y\right) \cdot y, x, 1\right)\\ \end{array} \]
          8. Add Preprocessing

          Alternative 5: 54.1% accurate, 0.9× speedup?

          \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;e^{\left(y \cdot x\right) \cdot y} \leq 20:\\ \;\;\;\;1\\ \mathbf{else}:\\ \;\;\;\;y \cdot x\\ \end{array} \end{array} \]
          (FPCore (x y)
           :precision binary64
           (if (<= (exp (* (* y x) y)) 20.0) 1.0 (* y x)))
          double code(double x, double y) {
          	double tmp;
          	if (exp(((y * x) * y)) <= 20.0) {
          		tmp = 1.0;
          	} else {
          		tmp = y * x;
          	}
          	return tmp;
          }
          
          real(8) function code(x, y)
              real(8), intent (in) :: x
              real(8), intent (in) :: y
              real(8) :: tmp
              if (exp(((y * x) * y)) <= 20.0d0) then
                  tmp = 1.0d0
              else
                  tmp = y * x
              end if
              code = tmp
          end function
          
          public static double code(double x, double y) {
          	double tmp;
          	if (Math.exp(((y * x) * y)) <= 20.0) {
          		tmp = 1.0;
          	} else {
          		tmp = y * x;
          	}
          	return tmp;
          }
          
          def code(x, y):
          	tmp = 0
          	if math.exp(((y * x) * y)) <= 20.0:
          		tmp = 1.0
          	else:
          		tmp = y * x
          	return tmp
          
          function code(x, y)
          	tmp = 0.0
          	if (exp(Float64(Float64(y * x) * y)) <= 20.0)
          		tmp = 1.0;
          	else
          		tmp = Float64(y * x);
          	end
          	return tmp
          end
          
          function tmp_2 = code(x, y)
          	tmp = 0.0;
          	if (exp(((y * x) * y)) <= 20.0)
          		tmp = 1.0;
          	else
          		tmp = y * x;
          	end
          	tmp_2 = tmp;
          end
          
          code[x_, y_] := If[LessEqual[N[Exp[N[(N[(y * x), $MachinePrecision] * y), $MachinePrecision]], $MachinePrecision], 20.0], 1.0, N[(y * x), $MachinePrecision]]
          
          \begin{array}{l}
          
          \\
          \begin{array}{l}
          \mathbf{if}\;e^{\left(y \cdot x\right) \cdot y} \leq 20:\\
          \;\;\;\;1\\
          
          \mathbf{else}:\\
          \;\;\;\;y \cdot x\\
          
          
          \end{array}
          \end{array}
          
          Derivation
          1. Split input into 2 regimes
          2. if (exp.f64 (*.f64 (*.f64 x y) y)) < 20

            1. Initial program 100.0%

              \[e^{\left(x \cdot y\right) \cdot y} \]
            2. Add Preprocessing
            3. Taylor expanded in y around 0

              \[\leadsto \color{blue}{1} \]
            4. Step-by-step derivation
              1. Applied rewrites71.4%

                \[\leadsto \color{blue}{1} \]

              if 20 < (exp.f64 (*.f64 (*.f64 x y) y))

              1. Initial program 99.8%

                \[e^{\left(x \cdot y\right) \cdot y} \]
              2. Add Preprocessing
              3. Applied rewrites47.6%

                \[\leadsto e^{\color{blue}{x} \cdot y} \]
              4. Taylor expanded in y around 0

                \[\leadsto \color{blue}{1 + x \cdot y} \]
              5. Step-by-step derivation
                1. +-commutativeN/A

                  \[\leadsto \color{blue}{x \cdot y + 1} \]
                2. *-commutativeN/A

                  \[\leadsto \color{blue}{y \cdot x} + 1 \]
                3. lower-fma.f6414.3

                  \[\leadsto \color{blue}{\mathsf{fma}\left(y, x, 1\right)} \]
              6. Applied rewrites14.3%

                \[\leadsto \color{blue}{\mathsf{fma}\left(y, x, 1\right)} \]
              7. Taylor expanded in y around inf

                \[\leadsto x \cdot \color{blue}{y} \]
              8. Step-by-step derivation
                1. Applied rewrites14.1%

                  \[\leadsto y \cdot \color{blue}{x} \]
              9. Recombined 2 regimes into one program.
              10. Final simplification58.4%

                \[\leadsto \begin{array}{l} \mathbf{if}\;e^{\left(y \cdot x\right) \cdot y} \leq 20:\\ \;\;\;\;1\\ \mathbf{else}:\\ \;\;\;\;y \cdot x\\ \end{array} \]
              11. Add Preprocessing

              Alternative 6: 88.4% accurate, 0.9× speedup?

              \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;\left(y \cdot x\right) \cdot y \leq -1 \cdot 10^{+25}:\\ \;\;\;\;e^{x}\\ \mathbf{else}:\\ \;\;\;\;\mathsf{fma}\left(\left(\mathsf{fma}\left(\mathsf{fma}\left(y \cdot x, 0.16666666666666666 \cdot y, 0.5\right) \cdot x, y \cdot y, 1\right) \cdot y\right) \cdot y, x, 1\right)\\ \end{array} \end{array} \]
              (FPCore (x y)
               :precision binary64
               (if (<= (* (* y x) y) -1e+25)
                 (exp x)
                 (fma
                  (*
                   (* (fma (* (fma (* y x) (* 0.16666666666666666 y) 0.5) x) (* y y) 1.0) y)
                   y)
                  x
                  1.0)))
              double code(double x, double y) {
              	double tmp;
              	if (((y * x) * y) <= -1e+25) {
              		tmp = exp(x);
              	} else {
              		tmp = fma(((fma((fma((y * x), (0.16666666666666666 * y), 0.5) * x), (y * y), 1.0) * y) * y), x, 1.0);
              	}
              	return tmp;
              }
              
              function code(x, y)
              	tmp = 0.0
              	if (Float64(Float64(y * x) * y) <= -1e+25)
              		tmp = exp(x);
              	else
              		tmp = fma(Float64(Float64(fma(Float64(fma(Float64(y * x), Float64(0.16666666666666666 * y), 0.5) * x), Float64(y * y), 1.0) * y) * y), x, 1.0);
              	end
              	return tmp
              end
              
              code[x_, y_] := If[LessEqual[N[(N[(y * x), $MachinePrecision] * y), $MachinePrecision], -1e+25], N[Exp[x], $MachinePrecision], N[(N[(N[(N[(N[(N[(N[(y * x), $MachinePrecision] * N[(0.16666666666666666 * y), $MachinePrecision] + 0.5), $MachinePrecision] * x), $MachinePrecision] * N[(y * y), $MachinePrecision] + 1.0), $MachinePrecision] * y), $MachinePrecision] * y), $MachinePrecision] * x + 1.0), $MachinePrecision]]
              
              \begin{array}{l}
              
              \\
              \begin{array}{l}
              \mathbf{if}\;\left(y \cdot x\right) \cdot y \leq -1 \cdot 10^{+25}:\\
              \;\;\;\;e^{x}\\
              
              \mathbf{else}:\\
              \;\;\;\;\mathsf{fma}\left(\left(\mathsf{fma}\left(\mathsf{fma}\left(y \cdot x, 0.16666666666666666 \cdot y, 0.5\right) \cdot x, y \cdot y, 1\right) \cdot y\right) \cdot y, x, 1\right)\\
              
              
              \end{array}
              \end{array}
              
              Derivation
              1. Split input into 2 regimes
              2. if (*.f64 (*.f64 x y) y) < -1.00000000000000009e25

                1. Initial program 100.0%

                  \[e^{\left(x \cdot y\right) \cdot y} \]
                2. Add Preprocessing
                3. Applied rewrites60.9%

                  \[\leadsto e^{\color{blue}{x}} \]

                if -1.00000000000000009e25 < (*.f64 (*.f64 x y) y)

                1. Initial program 99.9%

                  \[e^{\left(x \cdot y\right) \cdot y} \]
                2. Add Preprocessing
                3. Taylor expanded in y around 0

                  \[\leadsto \color{blue}{1 + {y}^{2} \cdot \left(x + {y}^{2} \cdot \left(\frac{1}{6} \cdot \left({x}^{3} \cdot {y}^{2}\right) + \frac{1}{2} \cdot {x}^{2}\right)\right)} \]
                4. Applied rewrites95.3%

                  \[\leadsto \color{blue}{\mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(0.16666666666666666 \cdot y, y \cdot x, 0.5\right) \cdot x, y \cdot y, 1\right) \cdot y, y \cdot x, 1\right)} \]
                5. Step-by-step derivation
                  1. Applied rewrites96.7%

                    \[\leadsto \mathsf{fma}\left(\left(\mathsf{fma}\left(\mathsf{fma}\left(y \cdot x, 0.16666666666666666 \cdot y, 0.5\right) \cdot x, y \cdot y, 1\right) \cdot y\right) \cdot y, \color{blue}{x}, 1\right) \]
                6. Recombined 2 regimes into one program.
                7. Final simplification88.7%

                  \[\leadsto \begin{array}{l} \mathbf{if}\;\left(y \cdot x\right) \cdot y \leq -1 \cdot 10^{+25}:\\ \;\;\;\;e^{x}\\ \mathbf{else}:\\ \;\;\;\;\mathsf{fma}\left(\left(\mathsf{fma}\left(\mathsf{fma}\left(y \cdot x, 0.16666666666666666 \cdot y, 0.5\right) \cdot x, y \cdot y, 1\right) \cdot y\right) \cdot y, x, 1\right)\\ \end{array} \]
                8. Add Preprocessing

                Alternative 7: 66.9% accurate, 1.8× speedup?

                \[\begin{array}{l} \\ \begin{array}{l} t_0 := \left(y \cdot x\right) \cdot y\\ \mathbf{if}\;t\_0 \leq 4:\\ \;\;\;\;1\\ \mathbf{elif}\;t\_0 \leq 4 \cdot 10^{+258}:\\ \;\;\;\;\left(\left(\left(\left(x \cdot x\right) \cdot x\right) \cdot 0.16666666666666666\right) \cdot y\right) \cdot \left(y \cdot y\right)\\ \mathbf{else}:\\ \;\;\;\;\mathsf{fma}\left(y \cdot y, x, 1\right)\\ \end{array} \end{array} \]
                (FPCore (x y)
                 :precision binary64
                 (let* ((t_0 (* (* y x) y)))
                   (if (<= t_0 4.0)
                     1.0
                     (if (<= t_0 4e+258)
                       (* (* (* (* (* x x) x) 0.16666666666666666) y) (* y y))
                       (fma (* y y) x 1.0)))))
                double code(double x, double y) {
                	double t_0 = (y * x) * y;
                	double tmp;
                	if (t_0 <= 4.0) {
                		tmp = 1.0;
                	} else if (t_0 <= 4e+258) {
                		tmp = ((((x * x) * x) * 0.16666666666666666) * y) * (y * y);
                	} else {
                		tmp = fma((y * y), x, 1.0);
                	}
                	return tmp;
                }
                
                function code(x, y)
                	t_0 = Float64(Float64(y * x) * y)
                	tmp = 0.0
                	if (t_0 <= 4.0)
                		tmp = 1.0;
                	elseif (t_0 <= 4e+258)
                		tmp = Float64(Float64(Float64(Float64(Float64(x * x) * x) * 0.16666666666666666) * y) * Float64(y * y));
                	else
                		tmp = fma(Float64(y * y), x, 1.0);
                	end
                	return tmp
                end
                
                code[x_, y_] := Block[{t$95$0 = N[(N[(y * x), $MachinePrecision] * y), $MachinePrecision]}, If[LessEqual[t$95$0, 4.0], 1.0, If[LessEqual[t$95$0, 4e+258], N[(N[(N[(N[(N[(x * x), $MachinePrecision] * x), $MachinePrecision] * 0.16666666666666666), $MachinePrecision] * y), $MachinePrecision] * N[(y * y), $MachinePrecision]), $MachinePrecision], N[(N[(y * y), $MachinePrecision] * x + 1.0), $MachinePrecision]]]]
                
                \begin{array}{l}
                
                \\
                \begin{array}{l}
                t_0 := \left(y \cdot x\right) \cdot y\\
                \mathbf{if}\;t\_0 \leq 4:\\
                \;\;\;\;1\\
                
                \mathbf{elif}\;t\_0 \leq 4 \cdot 10^{+258}:\\
                \;\;\;\;\left(\left(\left(\left(x \cdot x\right) \cdot x\right) \cdot 0.16666666666666666\right) \cdot y\right) \cdot \left(y \cdot y\right)\\
                
                \mathbf{else}:\\
                \;\;\;\;\mathsf{fma}\left(y \cdot y, x, 1\right)\\
                
                
                \end{array}
                \end{array}
                
                Derivation
                1. Split input into 3 regimes
                2. if (*.f64 (*.f64 x y) y) < 4

                  1. Initial program 100.0%

                    \[e^{\left(x \cdot y\right) \cdot y} \]
                  2. Add Preprocessing
                  3. Taylor expanded in y around 0

                    \[\leadsto \color{blue}{1} \]
                  4. Step-by-step derivation
                    1. Applied rewrites71.4%

                      \[\leadsto \color{blue}{1} \]

                    if 4 < (*.f64 (*.f64 x y) y) < 4.00000000000000023e258

                    1. Initial program 99.6%

                      \[e^{\left(x \cdot y\right) \cdot y} \]
                    2. Add Preprocessing
                    3. Applied rewrites40.5%

                      \[\leadsto e^{\color{blue}{x} \cdot y} \]
                    4. Taylor expanded in x around 0

                      \[\leadsto \color{blue}{1 + x \cdot \left(y + x \cdot \left(\frac{1}{6} \cdot \left(x \cdot {y}^{3}\right) + \frac{1}{2} \cdot {y}^{2}\right)\right)} \]
                    5. Step-by-step derivation
                      1. +-commutativeN/A

                        \[\leadsto \color{blue}{x \cdot \left(y + x \cdot \left(\frac{1}{6} \cdot \left(x \cdot {y}^{3}\right) + \frac{1}{2} \cdot {y}^{2}\right)\right) + 1} \]
                      2. *-commutativeN/A

                        \[\leadsto \color{blue}{\left(y + x \cdot \left(\frac{1}{6} \cdot \left(x \cdot {y}^{3}\right) + \frac{1}{2} \cdot {y}^{2}\right)\right) \cdot x} + 1 \]
                      3. lower-fma.f64N/A

                        \[\leadsto \color{blue}{\mathsf{fma}\left(y + x \cdot \left(\frac{1}{6} \cdot \left(x \cdot {y}^{3}\right) + \frac{1}{2} \cdot {y}^{2}\right), x, 1\right)} \]
                    6. Applied rewrites40.0%

                      \[\leadsto \color{blue}{\mathsf{fma}\left(\mathsf{fma}\left(\left(y \cdot y\right) \cdot \mathsf{fma}\left(0.16666666666666666 \cdot x, y, 0.5\right), x, y\right), x, 1\right)} \]
                    7. Taylor expanded in y around inf

                      \[\leadsto {y}^{3} \cdot \color{blue}{\left(\frac{1}{6} \cdot {x}^{3} + \left(\frac{1}{2} \cdot \frac{{x}^{2}}{y} + \frac{x}{{y}^{2}}\right)\right)} \]
                    8. Step-by-step derivation
                      1. Applied rewrites27.1%

                        \[\leadsto \left(\mathsf{fma}\left(x \cdot x, \mathsf{fma}\left(0.16666666666666666, x, \frac{0.5}{y}\right), \frac{x}{y \cdot y}\right) \cdot y\right) \cdot \color{blue}{\left(y \cdot y\right)} \]
                      2. Taylor expanded in y around inf

                        \[\leadsto \left(\frac{1}{6} \cdot \left({x}^{3} \cdot y\right)\right) \cdot \left(y \cdot y\right) \]
                      3. Step-by-step derivation
                        1. Applied rewrites27.0%

                          \[\leadsto \left(\left(\left(\left(x \cdot x\right) \cdot x\right) \cdot 0.16666666666666666\right) \cdot y\right) \cdot \left(y \cdot y\right) \]

                        if 4.00000000000000023e258 < (*.f64 (*.f64 x y) y)

                        1. Initial program 100.0%

                          \[e^{\left(x \cdot y\right) \cdot y} \]
                        2. Add Preprocessing
                        3. Taylor expanded in y around 0

                          \[\leadsto \color{blue}{1 + x \cdot {y}^{2}} \]
                        4. Step-by-step derivation
                          1. +-commutativeN/A

                            \[\leadsto \color{blue}{x \cdot {y}^{2} + 1} \]
                          2. *-commutativeN/A

                            \[\leadsto \color{blue}{{y}^{2} \cdot x} + 1 \]
                          3. lower-fma.f64N/A

                            \[\leadsto \color{blue}{\mathsf{fma}\left({y}^{2}, x, 1\right)} \]
                          4. unpow2N/A

                            \[\leadsto \mathsf{fma}\left(\color{blue}{y \cdot y}, x, 1\right) \]
                          5. lower-*.f6497.6

                            \[\leadsto \mathsf{fma}\left(\color{blue}{y \cdot y}, x, 1\right) \]
                        5. Applied rewrites97.6%

                          \[\leadsto \color{blue}{\mathsf{fma}\left(y \cdot y, x, 1\right)} \]
                      4. Recombined 3 regimes into one program.
                      5. Final simplification71.0%

                        \[\leadsto \begin{array}{l} \mathbf{if}\;\left(y \cdot x\right) \cdot y \leq 4:\\ \;\;\;\;1\\ \mathbf{elif}\;\left(y \cdot x\right) \cdot y \leq 4 \cdot 10^{+258}:\\ \;\;\;\;\left(\left(\left(\left(x \cdot x\right) \cdot x\right) \cdot 0.16666666666666666\right) \cdot y\right) \cdot \left(y \cdot y\right)\\ \mathbf{else}:\\ \;\;\;\;\mathsf{fma}\left(y \cdot y, x, 1\right)\\ \end{array} \]
                      6. Add Preprocessing

                      Alternative 8: 73.9% accurate, 2.3× speedup?

                      \[\begin{array}{l} \\ \mathsf{fma}\left(\left(\mathsf{fma}\left(\mathsf{fma}\left(y \cdot x, 0.16666666666666666 \cdot y, 0.5\right) \cdot x, y \cdot y, 1\right) \cdot y\right) \cdot y, x, 1\right) \end{array} \]
                      (FPCore (x y)
                       :precision binary64
                       (fma
                        (*
                         (* (fma (* (fma (* y x) (* 0.16666666666666666 y) 0.5) x) (* y y) 1.0) y)
                         y)
                        x
                        1.0))
                      double code(double x, double y) {
                      	return fma(((fma((fma((y * x), (0.16666666666666666 * y), 0.5) * x), (y * y), 1.0) * y) * y), x, 1.0);
                      }
                      
                      function code(x, y)
                      	return fma(Float64(Float64(fma(Float64(fma(Float64(y * x), Float64(0.16666666666666666 * y), 0.5) * x), Float64(y * y), 1.0) * y) * y), x, 1.0)
                      end
                      
                      code[x_, y_] := N[(N[(N[(N[(N[(N[(N[(y * x), $MachinePrecision] * N[(0.16666666666666666 * y), $MachinePrecision] + 0.5), $MachinePrecision] * x), $MachinePrecision] * N[(y * y), $MachinePrecision] + 1.0), $MachinePrecision] * y), $MachinePrecision] * y), $MachinePrecision] * x + 1.0), $MachinePrecision]
                      
                      \begin{array}{l}
                      
                      \\
                      \mathsf{fma}\left(\left(\mathsf{fma}\left(\mathsf{fma}\left(y \cdot x, 0.16666666666666666 \cdot y, 0.5\right) \cdot x, y \cdot y, 1\right) \cdot y\right) \cdot y, x, 1\right)
                      \end{array}
                      
                      Derivation
                      1. Initial program 100.0%

                        \[e^{\left(x \cdot y\right) \cdot y} \]
                      2. Add Preprocessing
                      3. Taylor expanded in y around 0

                        \[\leadsto \color{blue}{1 + {y}^{2} \cdot \left(x + {y}^{2} \cdot \left(\frac{1}{6} \cdot \left({x}^{3} \cdot {y}^{2}\right) + \frac{1}{2} \cdot {x}^{2}\right)\right)} \]
                      4. Applied rewrites74.4%

                        \[\leadsto \color{blue}{\mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(0.16666666666666666 \cdot y, y \cdot x, 0.5\right) \cdot x, y \cdot y, 1\right) \cdot y, y \cdot x, 1\right)} \]
                      5. Step-by-step derivation
                        1. Applied rewrites75.5%

                          \[\leadsto \mathsf{fma}\left(\left(\mathsf{fma}\left(\mathsf{fma}\left(y \cdot x, 0.16666666666666666 \cdot y, 0.5\right) \cdot x, y \cdot y, 1\right) \cdot y\right) \cdot y, \color{blue}{x}, 1\right) \]
                        2. Add Preprocessing

                        Alternative 9: 62.0% accurate, 2.4× speedup?

                        \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;\left(y \cdot x\right) \cdot y \leq 4:\\ \;\;\;\;1\\ \mathbf{else}:\\ \;\;\;\;\left(\left(\left(\left(\left(y \cdot y\right) \cdot y\right) \cdot x\right) \cdot 0.16666666666666666\right) \cdot x\right) \cdot x\\ \end{array} \end{array} \]
                        (FPCore (x y)
                         :precision binary64
                         (if (<= (* (* y x) y) 4.0)
                           1.0
                           (* (* (* (* (* (* y y) y) x) 0.16666666666666666) x) x)))
                        double code(double x, double y) {
                        	double tmp;
                        	if (((y * x) * y) <= 4.0) {
                        		tmp = 1.0;
                        	} else {
                        		tmp = (((((y * y) * y) * x) * 0.16666666666666666) * x) * x;
                        	}
                        	return tmp;
                        }
                        
                        real(8) function code(x, y)
                            real(8), intent (in) :: x
                            real(8), intent (in) :: y
                            real(8) :: tmp
                            if (((y * x) * y) <= 4.0d0) then
                                tmp = 1.0d0
                            else
                                tmp = (((((y * y) * y) * x) * 0.16666666666666666d0) * x) * x
                            end if
                            code = tmp
                        end function
                        
                        public static double code(double x, double y) {
                        	double tmp;
                        	if (((y * x) * y) <= 4.0) {
                        		tmp = 1.0;
                        	} else {
                        		tmp = (((((y * y) * y) * x) * 0.16666666666666666) * x) * x;
                        	}
                        	return tmp;
                        }
                        
                        def code(x, y):
                        	tmp = 0
                        	if ((y * x) * y) <= 4.0:
                        		tmp = 1.0
                        	else:
                        		tmp = (((((y * y) * y) * x) * 0.16666666666666666) * x) * x
                        	return tmp
                        
                        function code(x, y)
                        	tmp = 0.0
                        	if (Float64(Float64(y * x) * y) <= 4.0)
                        		tmp = 1.0;
                        	else
                        		tmp = Float64(Float64(Float64(Float64(Float64(Float64(y * y) * y) * x) * 0.16666666666666666) * x) * x);
                        	end
                        	return tmp
                        end
                        
                        function tmp_2 = code(x, y)
                        	tmp = 0.0;
                        	if (((y * x) * y) <= 4.0)
                        		tmp = 1.0;
                        	else
                        		tmp = (((((y * y) * y) * x) * 0.16666666666666666) * x) * x;
                        	end
                        	tmp_2 = tmp;
                        end
                        
                        code[x_, y_] := If[LessEqual[N[(N[(y * x), $MachinePrecision] * y), $MachinePrecision], 4.0], 1.0, N[(N[(N[(N[(N[(N[(y * y), $MachinePrecision] * y), $MachinePrecision] * x), $MachinePrecision] * 0.16666666666666666), $MachinePrecision] * x), $MachinePrecision] * x), $MachinePrecision]]
                        
                        \begin{array}{l}
                        
                        \\
                        \begin{array}{l}
                        \mathbf{if}\;\left(y \cdot x\right) \cdot y \leq 4:\\
                        \;\;\;\;1\\
                        
                        \mathbf{else}:\\
                        \;\;\;\;\left(\left(\left(\left(\left(y \cdot y\right) \cdot y\right) \cdot x\right) \cdot 0.16666666666666666\right) \cdot x\right) \cdot x\\
                        
                        
                        \end{array}
                        \end{array}
                        
                        Derivation
                        1. Split input into 2 regimes
                        2. if (*.f64 (*.f64 x y) y) < 4

                          1. Initial program 100.0%

                            \[e^{\left(x \cdot y\right) \cdot y} \]
                          2. Add Preprocessing
                          3. Taylor expanded in y around 0

                            \[\leadsto \color{blue}{1} \]
                          4. Step-by-step derivation
                            1. Applied rewrites71.4%

                              \[\leadsto \color{blue}{1} \]

                            if 4 < (*.f64 (*.f64 x y) y)

                            1. Initial program 99.8%

                              \[e^{\left(x \cdot y\right) \cdot y} \]
                            2. Add Preprocessing
                            3. Applied rewrites47.6%

                              \[\leadsto e^{\color{blue}{x} \cdot y} \]
                            4. Taylor expanded in x around 0

                              \[\leadsto \color{blue}{1 + x \cdot \left(y + x \cdot \left(\frac{1}{6} \cdot \left(x \cdot {y}^{3}\right) + \frac{1}{2} \cdot {y}^{2}\right)\right)} \]
                            5. Step-by-step derivation
                              1. +-commutativeN/A

                                \[\leadsto \color{blue}{x \cdot \left(y + x \cdot \left(\frac{1}{6} \cdot \left(x \cdot {y}^{3}\right) + \frac{1}{2} \cdot {y}^{2}\right)\right) + 1} \]
                              2. *-commutativeN/A

                                \[\leadsto \color{blue}{\left(y + x \cdot \left(\frac{1}{6} \cdot \left(x \cdot {y}^{3}\right) + \frac{1}{2} \cdot {y}^{2}\right)\right) \cdot x} + 1 \]
                              3. lower-fma.f64N/A

                                \[\leadsto \color{blue}{\mathsf{fma}\left(y + x \cdot \left(\frac{1}{6} \cdot \left(x \cdot {y}^{3}\right) + \frac{1}{2} \cdot {y}^{2}\right), x, 1\right)} \]
                            6. Applied rewrites46.9%

                              \[\leadsto \color{blue}{\mathsf{fma}\left(\mathsf{fma}\left(\left(y \cdot y\right) \cdot \mathsf{fma}\left(0.16666666666666666 \cdot x, y, 0.5\right), x, y\right), x, 1\right)} \]
                            7. Taylor expanded in y around inf

                              \[\leadsto \frac{1}{6} \cdot \color{blue}{\left({x}^{3} \cdot {y}^{3}\right)} \]
                            8. Step-by-step derivation
                              1. Applied rewrites45.0%

                                \[\leadsto \left(\left(\left(\left(\left(y \cdot y\right) \cdot y\right) \cdot x\right) \cdot 0.16666666666666666\right) \cdot x\right) \cdot \color{blue}{x} \]
                            9. Recombined 2 regimes into one program.
                            10. Final simplification65.4%

                              \[\leadsto \begin{array}{l} \mathbf{if}\;\left(y \cdot x\right) \cdot y \leq 4:\\ \;\;\;\;1\\ \mathbf{else}:\\ \;\;\;\;\left(\left(\left(\left(\left(y \cdot y\right) \cdot y\right) \cdot x\right) \cdot 0.16666666666666666\right) \cdot x\right) \cdot x\\ \end{array} \]
                            11. Add Preprocessing

                            Alternative 10: 60.1% accurate, 2.4× speedup?

                            \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;\left(y \cdot x\right) \cdot y \leq 4:\\ \;\;\;\;1\\ \mathbf{else}:\\ \;\;\;\;\left(x \cdot x\right) \cdot \left(\left(\left(\left(y \cdot y\right) \cdot y\right) \cdot x\right) \cdot 0.16666666666666666\right)\\ \end{array} \end{array} \]
                            (FPCore (x y)
                             :precision binary64
                             (if (<= (* (* y x) y) 4.0)
                               1.0
                               (* (* x x) (* (* (* (* y y) y) x) 0.16666666666666666))))
                            double code(double x, double y) {
                            	double tmp;
                            	if (((y * x) * y) <= 4.0) {
                            		tmp = 1.0;
                            	} else {
                            		tmp = (x * x) * ((((y * y) * y) * x) * 0.16666666666666666);
                            	}
                            	return tmp;
                            }
                            
                            real(8) function code(x, y)
                                real(8), intent (in) :: x
                                real(8), intent (in) :: y
                                real(8) :: tmp
                                if (((y * x) * y) <= 4.0d0) then
                                    tmp = 1.0d0
                                else
                                    tmp = (x * x) * ((((y * y) * y) * x) * 0.16666666666666666d0)
                                end if
                                code = tmp
                            end function
                            
                            public static double code(double x, double y) {
                            	double tmp;
                            	if (((y * x) * y) <= 4.0) {
                            		tmp = 1.0;
                            	} else {
                            		tmp = (x * x) * ((((y * y) * y) * x) * 0.16666666666666666);
                            	}
                            	return tmp;
                            }
                            
                            def code(x, y):
                            	tmp = 0
                            	if ((y * x) * y) <= 4.0:
                            		tmp = 1.0
                            	else:
                            		tmp = (x * x) * ((((y * y) * y) * x) * 0.16666666666666666)
                            	return tmp
                            
                            function code(x, y)
                            	tmp = 0.0
                            	if (Float64(Float64(y * x) * y) <= 4.0)
                            		tmp = 1.0;
                            	else
                            		tmp = Float64(Float64(x * x) * Float64(Float64(Float64(Float64(y * y) * y) * x) * 0.16666666666666666));
                            	end
                            	return tmp
                            end
                            
                            function tmp_2 = code(x, y)
                            	tmp = 0.0;
                            	if (((y * x) * y) <= 4.0)
                            		tmp = 1.0;
                            	else
                            		tmp = (x * x) * ((((y * y) * y) * x) * 0.16666666666666666);
                            	end
                            	tmp_2 = tmp;
                            end
                            
                            code[x_, y_] := If[LessEqual[N[(N[(y * x), $MachinePrecision] * y), $MachinePrecision], 4.0], 1.0, N[(N[(x * x), $MachinePrecision] * N[(N[(N[(N[(y * y), $MachinePrecision] * y), $MachinePrecision] * x), $MachinePrecision] * 0.16666666666666666), $MachinePrecision]), $MachinePrecision]]
                            
                            \begin{array}{l}
                            
                            \\
                            \begin{array}{l}
                            \mathbf{if}\;\left(y \cdot x\right) \cdot y \leq 4:\\
                            \;\;\;\;1\\
                            
                            \mathbf{else}:\\
                            \;\;\;\;\left(x \cdot x\right) \cdot \left(\left(\left(\left(y \cdot y\right) \cdot y\right) \cdot x\right) \cdot 0.16666666666666666\right)\\
                            
                            
                            \end{array}
                            \end{array}
                            
                            Derivation
                            1. Split input into 2 regimes
                            2. if (*.f64 (*.f64 x y) y) < 4

                              1. Initial program 100.0%

                                \[e^{\left(x \cdot y\right) \cdot y} \]
                              2. Add Preprocessing
                              3. Taylor expanded in y around 0

                                \[\leadsto \color{blue}{1} \]
                              4. Step-by-step derivation
                                1. Applied rewrites71.4%

                                  \[\leadsto \color{blue}{1} \]

                                if 4 < (*.f64 (*.f64 x y) y)

                                1. Initial program 99.8%

                                  \[e^{\left(x \cdot y\right) \cdot y} \]
                                2. Add Preprocessing
                                3. Applied rewrites47.6%

                                  \[\leadsto e^{\color{blue}{x} \cdot y} \]
                                4. Taylor expanded in x around 0

                                  \[\leadsto \color{blue}{1 + x \cdot \left(y + x \cdot \left(\frac{1}{6} \cdot \left(x \cdot {y}^{3}\right) + \frac{1}{2} \cdot {y}^{2}\right)\right)} \]
                                5. Step-by-step derivation
                                  1. +-commutativeN/A

                                    \[\leadsto \color{blue}{x \cdot \left(y + x \cdot \left(\frac{1}{6} \cdot \left(x \cdot {y}^{3}\right) + \frac{1}{2} \cdot {y}^{2}\right)\right) + 1} \]
                                  2. *-commutativeN/A

                                    \[\leadsto \color{blue}{\left(y + x \cdot \left(\frac{1}{6} \cdot \left(x \cdot {y}^{3}\right) + \frac{1}{2} \cdot {y}^{2}\right)\right) \cdot x} + 1 \]
                                  3. lower-fma.f64N/A

                                    \[\leadsto \color{blue}{\mathsf{fma}\left(y + x \cdot \left(\frac{1}{6} \cdot \left(x \cdot {y}^{3}\right) + \frac{1}{2} \cdot {y}^{2}\right), x, 1\right)} \]
                                6. Applied rewrites46.9%

                                  \[\leadsto \color{blue}{\mathsf{fma}\left(\mathsf{fma}\left(\left(y \cdot y\right) \cdot \mathsf{fma}\left(0.16666666666666666 \cdot x, y, 0.5\right), x, y\right), x, 1\right)} \]
                                7. Taylor expanded in y around inf

                                  \[\leadsto \frac{1}{6} \cdot \color{blue}{\left({x}^{3} \cdot {y}^{3}\right)} \]
                                8. Step-by-step derivation
                                  1. Applied rewrites45.0%

                                    \[\leadsto \left(\left(\left(\left(\left(y \cdot y\right) \cdot y\right) \cdot x\right) \cdot 0.16666666666666666\right) \cdot x\right) \cdot \color{blue}{x} \]
                                  2. Step-by-step derivation
                                    1. Applied rewrites39.8%

                                      \[\leadsto \left(\left(\left(\left(y \cdot y\right) \cdot y\right) \cdot x\right) \cdot 0.16666666666666666\right) \cdot \left(x \cdot \color{blue}{x}\right) \]
                                  3. Recombined 2 regimes into one program.
                                  4. Final simplification64.3%

                                    \[\leadsto \begin{array}{l} \mathbf{if}\;\left(y \cdot x\right) \cdot y \leq 4:\\ \;\;\;\;1\\ \mathbf{else}:\\ \;\;\;\;\left(x \cdot x\right) \cdot \left(\left(\left(\left(y \cdot y\right) \cdot y\right) \cdot x\right) \cdot 0.16666666666666666\right)\\ \end{array} \]
                                  5. Add Preprocessing

                                  Alternative 11: 67.5% accurate, 9.3× speedup?

                                  \[\begin{array}{l} \\ \mathsf{fma}\left(y \cdot y, x, 1\right) \end{array} \]
                                  (FPCore (x y) :precision binary64 (fma (* y y) x 1.0))
                                  double code(double x, double y) {
                                  	return fma((y * y), x, 1.0);
                                  }
                                  
                                  function code(x, y)
                                  	return fma(Float64(y * y), x, 1.0)
                                  end
                                  
                                  code[x_, y_] := N[(N[(y * y), $MachinePrecision] * x + 1.0), $MachinePrecision]
                                  
                                  \begin{array}{l}
                                  
                                  \\
                                  \mathsf{fma}\left(y \cdot y, x, 1\right)
                                  \end{array}
                                  
                                  Derivation
                                  1. Initial program 100.0%

                                    \[e^{\left(x \cdot y\right) \cdot y} \]
                                  2. Add Preprocessing
                                  3. Taylor expanded in y around 0

                                    \[\leadsto \color{blue}{1 + x \cdot {y}^{2}} \]
                                  4. Step-by-step derivation
                                    1. +-commutativeN/A

                                      \[\leadsto \color{blue}{x \cdot {y}^{2} + 1} \]
                                    2. *-commutativeN/A

                                      \[\leadsto \color{blue}{{y}^{2} \cdot x} + 1 \]
                                    3. lower-fma.f64N/A

                                      \[\leadsto \color{blue}{\mathsf{fma}\left({y}^{2}, x, 1\right)} \]
                                    4. unpow2N/A

                                      \[\leadsto \mathsf{fma}\left(\color{blue}{y \cdot y}, x, 1\right) \]
                                    5. lower-*.f6469.6

                                      \[\leadsto \mathsf{fma}\left(\color{blue}{y \cdot y}, x, 1\right) \]
                                  5. Applied rewrites69.6%

                                    \[\leadsto \color{blue}{\mathsf{fma}\left(y \cdot y, x, 1\right)} \]
                                  6. Add Preprocessing

                                  Alternative 12: 51.4% accurate, 111.0× speedup?

                                  \[\begin{array}{l} \\ 1 \end{array} \]
                                  (FPCore (x y) :precision binary64 1.0)
                                  double code(double x, double y) {
                                  	return 1.0;
                                  }
                                  
                                  real(8) function code(x, y)
                                      real(8), intent (in) :: x
                                      real(8), intent (in) :: y
                                      code = 1.0d0
                                  end function
                                  
                                  public static double code(double x, double y) {
                                  	return 1.0;
                                  }
                                  
                                  def code(x, y):
                                  	return 1.0
                                  
                                  function code(x, y)
                                  	return 1.0
                                  end
                                  
                                  function tmp = code(x, y)
                                  	tmp = 1.0;
                                  end
                                  
                                  code[x_, y_] := 1.0
                                  
                                  \begin{array}{l}
                                  
                                  \\
                                  1
                                  \end{array}
                                  
                                  Derivation
                                  1. Initial program 100.0%

                                    \[e^{\left(x \cdot y\right) \cdot y} \]
                                  2. Add Preprocessing
                                  3. Taylor expanded in y around 0

                                    \[\leadsto \color{blue}{1} \]
                                  4. Step-by-step derivation
                                    1. Applied rewrites55.9%

                                      \[\leadsto \color{blue}{1} \]
                                    2. Add Preprocessing

                                    Reproduce

                                    ?
                                    herbie shell --seed 2024236 
                                    (FPCore (x y)
                                      :name "Data.Random.Distribution.Normal:normalF from random-fu-0.2.6.2"
                                      :precision binary64
                                      (exp (* (* x y) y)))