Given's Rotation SVD example, simplified

Percentage Accurate: 76.1% → 99.6%
Time: 6.6s
Alternatives: 6
Speedup: 1.1×

Specification

?
\[\begin{array}{l} \\ 1 - \sqrt{0.5 \cdot \left(1 + \frac{1}{\mathsf{hypot}\left(1, x\right)}\right)} \end{array} \]
(FPCore (x)
 :precision binary64
 (- 1.0 (sqrt (* 0.5 (+ 1.0 (/ 1.0 (hypot 1.0 x)))))))
double code(double x) {
	return 1.0 - sqrt((0.5 * (1.0 + (1.0 / hypot(1.0, x)))));
}
public static double code(double x) {
	return 1.0 - Math.sqrt((0.5 * (1.0 + (1.0 / Math.hypot(1.0, x)))));
}
def code(x):
	return 1.0 - math.sqrt((0.5 * (1.0 + (1.0 / math.hypot(1.0, x)))))
function code(x)
	return Float64(1.0 - sqrt(Float64(0.5 * Float64(1.0 + Float64(1.0 / hypot(1.0, x))))))
end
function tmp = code(x)
	tmp = 1.0 - sqrt((0.5 * (1.0 + (1.0 / hypot(1.0, x)))));
end
code[x_] := N[(1.0 - N[Sqrt[N[(0.5 * N[(1.0 + N[(1.0 / N[Sqrt[1.0 ^ 2 + x ^ 2], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
1 - \sqrt{0.5 \cdot \left(1 + \frac{1}{\mathsf{hypot}\left(1, x\right)}\right)}
\end{array}

Sampling outcomes in binary64 precision:

Local Percentage Accuracy vs ?

The average percentage accuracy by input value. Horizontal axis shows value of an input variable; the variable is choosen in the title. Vertical axis is accuracy; higher is better. Red represent the original program, while blue represents Herbie's suggestion. These can be toggled with buttons below the plot. The line is an average while dots represent individual samples.

Accuracy vs Speed?

Herbie found 6 alternatives:

AlternativeAccuracySpeedup
The accuracy (vertical axis) and speed (horizontal axis) of each alternatives. Up and to the right is better. The red square shows the initial program, and each blue circle shows an alternative.The line shows the best available speed-accuracy tradeoffs.

Initial Program: 76.1% accurate, 1.0× speedup?

\[\begin{array}{l} \\ 1 - \sqrt{0.5 \cdot \left(1 + \frac{1}{\mathsf{hypot}\left(1, x\right)}\right)} \end{array} \]
(FPCore (x)
 :precision binary64
 (- 1.0 (sqrt (* 0.5 (+ 1.0 (/ 1.0 (hypot 1.0 x)))))))
double code(double x) {
	return 1.0 - sqrt((0.5 * (1.0 + (1.0 / hypot(1.0, x)))));
}
public static double code(double x) {
	return 1.0 - Math.sqrt((0.5 * (1.0 + (1.0 / Math.hypot(1.0, x)))));
}
def code(x):
	return 1.0 - math.sqrt((0.5 * (1.0 + (1.0 / math.hypot(1.0, x)))))
function code(x)
	return Float64(1.0 - sqrt(Float64(0.5 * Float64(1.0 + Float64(1.0 / hypot(1.0, x))))))
end
function tmp = code(x)
	tmp = 1.0 - sqrt((0.5 * (1.0 + (1.0 / hypot(1.0, x)))));
end
code[x_] := N[(1.0 - N[Sqrt[N[(0.5 * N[(1.0 + N[(1.0 / N[Sqrt[1.0 ^ 2 + x ^ 2], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
1 - \sqrt{0.5 \cdot \left(1 + \frac{1}{\mathsf{hypot}\left(1, x\right)}\right)}
\end{array}

Alternative 1: 99.6% accurate, 0.7× speedup?

\[\begin{array}{l} \\ \begin{array}{l} t_0 := 0.5 - \frac{-0.5}{\sqrt{\mathsf{fma}\left(x, x, 1\right)}}\\ \mathbf{if}\;\mathsf{hypot}\left(1, x\right) \leq 2:\\ \;\;\;\;\mathsf{fma}\left(-0.0859375, x \cdot x, 0.125\right) \cdot \left(x \cdot x\right)\\ \mathbf{else}:\\ \;\;\;\;\frac{t\_0 - 1}{-1 - \sqrt{t\_0}}\\ \end{array} \end{array} \]
(FPCore (x)
 :precision binary64
 (let* ((t_0 (- 0.5 (/ -0.5 (sqrt (fma x x 1.0))))))
   (if (<= (hypot 1.0 x) 2.0)
     (* (fma -0.0859375 (* x x) 0.125) (* x x))
     (/ (- t_0 1.0) (- -1.0 (sqrt t_0))))))
double code(double x) {
	double t_0 = 0.5 - (-0.5 / sqrt(fma(x, x, 1.0)));
	double tmp;
	if (hypot(1.0, x) <= 2.0) {
		tmp = fma(-0.0859375, (x * x), 0.125) * (x * x);
	} else {
		tmp = (t_0 - 1.0) / (-1.0 - sqrt(t_0));
	}
	return tmp;
}
function code(x)
	t_0 = Float64(0.5 - Float64(-0.5 / sqrt(fma(x, x, 1.0))))
	tmp = 0.0
	if (hypot(1.0, x) <= 2.0)
		tmp = Float64(fma(-0.0859375, Float64(x * x), 0.125) * Float64(x * x));
	else
		tmp = Float64(Float64(t_0 - 1.0) / Float64(-1.0 - sqrt(t_0)));
	end
	return tmp
end
code[x_] := Block[{t$95$0 = N[(0.5 - N[(-0.5 / N[Sqrt[N[(x * x + 1.0), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[N[Sqrt[1.0 ^ 2 + x ^ 2], $MachinePrecision], 2.0], N[(N[(-0.0859375 * N[(x * x), $MachinePrecision] + 0.125), $MachinePrecision] * N[(x * x), $MachinePrecision]), $MachinePrecision], N[(N[(t$95$0 - 1.0), $MachinePrecision] / N[(-1.0 - N[Sqrt[t$95$0], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]]]
\begin{array}{l}

\\
\begin{array}{l}
t_0 := 0.5 - \frac{-0.5}{\sqrt{\mathsf{fma}\left(x, x, 1\right)}}\\
\mathbf{if}\;\mathsf{hypot}\left(1, x\right) \leq 2:\\
\;\;\;\;\mathsf{fma}\left(-0.0859375, x \cdot x, 0.125\right) \cdot \left(x \cdot x\right)\\

\mathbf{else}:\\
\;\;\;\;\frac{t\_0 - 1}{-1 - \sqrt{t\_0}}\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if (hypot.f64 #s(literal 1 binary64) x) < 2

    1. Initial program 55.7%

      \[1 - \sqrt{0.5 \cdot \left(1 + \frac{1}{\mathsf{hypot}\left(1, x\right)}\right)} \]
    2. Add Preprocessing
    3. Applied rewrites55.8%

      \[\leadsto \color{blue}{\frac{\left(0.5 - \frac{-0.5}{\sqrt{\mathsf{fma}\left(x, x, 1\right)}}\right) - 1}{\left(-\sqrt{0.5 - \frac{-0.5}{\sqrt{\mathsf{fma}\left(x, x, 1\right)}}}\right) - 1}} \]
    4. Taylor expanded in x around 0

      \[\leadsto \color{blue}{{x}^{2} \cdot \left(\frac{1}{8} + \frac{-11}{128} \cdot {x}^{2}\right)} \]
    5. Step-by-step derivation
      1. *-commutativeN/A

        \[\leadsto \color{blue}{\left(\frac{1}{8} + \frac{-11}{128} \cdot {x}^{2}\right) \cdot {x}^{2}} \]
      2. unpow2N/A

        \[\leadsto \left(\frac{1}{8} + \frac{-11}{128} \cdot {x}^{2}\right) \cdot \color{blue}{\left(x \cdot x\right)} \]
      3. associate-*r*N/A

        \[\leadsto \color{blue}{\left(\left(\frac{1}{8} + \frac{-11}{128} \cdot {x}^{2}\right) \cdot x\right) \cdot x} \]
      4. lower-*.f64N/A

        \[\leadsto \color{blue}{\left(\left(\frac{1}{8} + \frac{-11}{128} \cdot {x}^{2}\right) \cdot x\right) \cdot x} \]
      5. lower-*.f64N/A

        \[\leadsto \color{blue}{\left(\left(\frac{1}{8} + \frac{-11}{128} \cdot {x}^{2}\right) \cdot x\right)} \cdot x \]
      6. +-commutativeN/A

        \[\leadsto \left(\color{blue}{\left(\frac{-11}{128} \cdot {x}^{2} + \frac{1}{8}\right)} \cdot x\right) \cdot x \]
      7. lower-fma.f64N/A

        \[\leadsto \left(\color{blue}{\mathsf{fma}\left(\frac{-11}{128}, {x}^{2}, \frac{1}{8}\right)} \cdot x\right) \cdot x \]
      8. unpow2N/A

        \[\leadsto \left(\mathsf{fma}\left(\frac{-11}{128}, \color{blue}{x \cdot x}, \frac{1}{8}\right) \cdot x\right) \cdot x \]
      9. lower-*.f64100.0

        \[\leadsto \left(\mathsf{fma}\left(-0.0859375, \color{blue}{x \cdot x}, 0.125\right) \cdot x\right) \cdot x \]
    6. Applied rewrites100.0%

      \[\leadsto \color{blue}{\left(\mathsf{fma}\left(-0.0859375, x \cdot x, 0.125\right) \cdot x\right) \cdot x} \]
    7. Step-by-step derivation
      1. Applied rewrites100.0%

        \[\leadsto \mathsf{fma}\left(-0.0859375, x \cdot x, 0.125\right) \cdot \color{blue}{\left(x \cdot x\right)} \]

      if 2 < (hypot.f64 #s(literal 1 binary64) x)

      1. Initial program 98.5%

        \[1 - \sqrt{0.5 \cdot \left(1 + \frac{1}{\mathsf{hypot}\left(1, x\right)}\right)} \]
      2. Add Preprocessing
      3. Applied rewrites100.0%

        \[\leadsto \color{blue}{\frac{\left(0.5 - \frac{-0.5}{\sqrt{\mathsf{fma}\left(x, x, 1\right)}}\right) - 1}{\left(-\sqrt{0.5 - \frac{-0.5}{\sqrt{\mathsf{fma}\left(x, x, 1\right)}}}\right) - 1}} \]
    8. Recombined 2 regimes into one program.
    9. Final simplification100.0%

      \[\leadsto \begin{array}{l} \mathbf{if}\;\mathsf{hypot}\left(1, x\right) \leq 2:\\ \;\;\;\;\mathsf{fma}\left(-0.0859375, x \cdot x, 0.125\right) \cdot \left(x \cdot x\right)\\ \mathbf{else}:\\ \;\;\;\;\frac{\left(0.5 - \frac{-0.5}{\sqrt{\mathsf{fma}\left(x, x, 1\right)}}\right) - 1}{-1 - \sqrt{0.5 - \frac{-0.5}{\sqrt{\mathsf{fma}\left(x, x, 1\right)}}}}\\ \end{array} \]
    10. Add Preprocessing

    Alternative 2: 98.4% accurate, 1.0× speedup?

    \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;\mathsf{hypot}\left(1, x\right) \leq 2:\\ \;\;\;\;\mathsf{fma}\left(-0.0859375, x \cdot x, 0.125\right) \cdot \left(x \cdot x\right)\\ \mathbf{else}:\\ \;\;\;\;\frac{0.5}{\sqrt{0.5} + 1}\\ \end{array} \end{array} \]
    (FPCore (x)
     :precision binary64
     (if (<= (hypot 1.0 x) 2.0)
       (* (fma -0.0859375 (* x x) 0.125) (* x x))
       (/ 0.5 (+ (sqrt 0.5) 1.0))))
    double code(double x) {
    	double tmp;
    	if (hypot(1.0, x) <= 2.0) {
    		tmp = fma(-0.0859375, (x * x), 0.125) * (x * x);
    	} else {
    		tmp = 0.5 / (sqrt(0.5) + 1.0);
    	}
    	return tmp;
    }
    
    function code(x)
    	tmp = 0.0
    	if (hypot(1.0, x) <= 2.0)
    		tmp = Float64(fma(-0.0859375, Float64(x * x), 0.125) * Float64(x * x));
    	else
    		tmp = Float64(0.5 / Float64(sqrt(0.5) + 1.0));
    	end
    	return tmp
    end
    
    code[x_] := If[LessEqual[N[Sqrt[1.0 ^ 2 + x ^ 2], $MachinePrecision], 2.0], N[(N[(-0.0859375 * N[(x * x), $MachinePrecision] + 0.125), $MachinePrecision] * N[(x * x), $MachinePrecision]), $MachinePrecision], N[(0.5 / N[(N[Sqrt[0.5], $MachinePrecision] + 1.0), $MachinePrecision]), $MachinePrecision]]
    
    \begin{array}{l}
    
    \\
    \begin{array}{l}
    \mathbf{if}\;\mathsf{hypot}\left(1, x\right) \leq 2:\\
    \;\;\;\;\mathsf{fma}\left(-0.0859375, x \cdot x, 0.125\right) \cdot \left(x \cdot x\right)\\
    
    \mathbf{else}:\\
    \;\;\;\;\frac{0.5}{\sqrt{0.5} + 1}\\
    
    
    \end{array}
    \end{array}
    
    Derivation
    1. Split input into 2 regimes
    2. if (hypot.f64 #s(literal 1 binary64) x) < 2

      1. Initial program 55.7%

        \[1 - \sqrt{0.5 \cdot \left(1 + \frac{1}{\mathsf{hypot}\left(1, x\right)}\right)} \]
      2. Add Preprocessing
      3. Applied rewrites55.8%

        \[\leadsto \color{blue}{\frac{\left(0.5 - \frac{-0.5}{\sqrt{\mathsf{fma}\left(x, x, 1\right)}}\right) - 1}{\left(-\sqrt{0.5 - \frac{-0.5}{\sqrt{\mathsf{fma}\left(x, x, 1\right)}}}\right) - 1}} \]
      4. Taylor expanded in x around 0

        \[\leadsto \color{blue}{{x}^{2} \cdot \left(\frac{1}{8} + \frac{-11}{128} \cdot {x}^{2}\right)} \]
      5. Step-by-step derivation
        1. *-commutativeN/A

          \[\leadsto \color{blue}{\left(\frac{1}{8} + \frac{-11}{128} \cdot {x}^{2}\right) \cdot {x}^{2}} \]
        2. unpow2N/A

          \[\leadsto \left(\frac{1}{8} + \frac{-11}{128} \cdot {x}^{2}\right) \cdot \color{blue}{\left(x \cdot x\right)} \]
        3. associate-*r*N/A

          \[\leadsto \color{blue}{\left(\left(\frac{1}{8} + \frac{-11}{128} \cdot {x}^{2}\right) \cdot x\right) \cdot x} \]
        4. lower-*.f64N/A

          \[\leadsto \color{blue}{\left(\left(\frac{1}{8} + \frac{-11}{128} \cdot {x}^{2}\right) \cdot x\right) \cdot x} \]
        5. lower-*.f64N/A

          \[\leadsto \color{blue}{\left(\left(\frac{1}{8} + \frac{-11}{128} \cdot {x}^{2}\right) \cdot x\right)} \cdot x \]
        6. +-commutativeN/A

          \[\leadsto \left(\color{blue}{\left(\frac{-11}{128} \cdot {x}^{2} + \frac{1}{8}\right)} \cdot x\right) \cdot x \]
        7. lower-fma.f64N/A

          \[\leadsto \left(\color{blue}{\mathsf{fma}\left(\frac{-11}{128}, {x}^{2}, \frac{1}{8}\right)} \cdot x\right) \cdot x \]
        8. unpow2N/A

          \[\leadsto \left(\mathsf{fma}\left(\frac{-11}{128}, \color{blue}{x \cdot x}, \frac{1}{8}\right) \cdot x\right) \cdot x \]
        9. lower-*.f64100.0

          \[\leadsto \left(\mathsf{fma}\left(-0.0859375, \color{blue}{x \cdot x}, 0.125\right) \cdot x\right) \cdot x \]
      6. Applied rewrites100.0%

        \[\leadsto \color{blue}{\left(\mathsf{fma}\left(-0.0859375, x \cdot x, 0.125\right) \cdot x\right) \cdot x} \]
      7. Step-by-step derivation
        1. Applied rewrites100.0%

          \[\leadsto \mathsf{fma}\left(-0.0859375, x \cdot x, 0.125\right) \cdot \color{blue}{\left(x \cdot x\right)} \]

        if 2 < (hypot.f64 #s(literal 1 binary64) x)

        1. Initial program 98.5%

          \[1 - \sqrt{0.5 \cdot \left(1 + \frac{1}{\mathsf{hypot}\left(1, x\right)}\right)} \]
        2. Add Preprocessing
        3. Applied rewrites100.0%

          \[\leadsto \color{blue}{\frac{\left(0.5 - \frac{-0.5}{\sqrt{\mathsf{fma}\left(x, x, 1\right)}}\right) - 1}{\left(-\sqrt{0.5 - \frac{-0.5}{\sqrt{\mathsf{fma}\left(x, x, 1\right)}}}\right) - 1}} \]
        4. Taylor expanded in x around inf

          \[\leadsto \color{blue}{\frac{\frac{1}{2}}{1 + \sqrt{\frac{1}{2}}}} \]
        5. Step-by-step derivation
          1. lower-/.f64N/A

            \[\leadsto \color{blue}{\frac{\frac{1}{2}}{1 + \sqrt{\frac{1}{2}}}} \]
          2. +-commutativeN/A

            \[\leadsto \frac{\frac{1}{2}}{\color{blue}{\sqrt{\frac{1}{2}} + 1}} \]
          3. lower-+.f64N/A

            \[\leadsto \frac{\frac{1}{2}}{\color{blue}{\sqrt{\frac{1}{2}} + 1}} \]
          4. lower-sqrt.f6499.0

            \[\leadsto \frac{0.5}{\color{blue}{\sqrt{0.5}} + 1} \]
        6. Applied rewrites99.0%

          \[\leadsto \color{blue}{\frac{0.5}{\sqrt{0.5} + 1}} \]
      8. Recombined 2 regimes into one program.
      9. Add Preprocessing

      Alternative 3: 97.7% accurate, 1.0× speedup?

      \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;\mathsf{hypot}\left(1, x\right) \leq 2:\\ \;\;\;\;\mathsf{fma}\left(-0.0859375, x \cdot x, 0.125\right) \cdot \left(x \cdot x\right)\\ \mathbf{else}:\\ \;\;\;\;1 - \sqrt{0.5}\\ \end{array} \end{array} \]
      (FPCore (x)
       :precision binary64
       (if (<= (hypot 1.0 x) 2.0)
         (* (fma -0.0859375 (* x x) 0.125) (* x x))
         (- 1.0 (sqrt 0.5))))
      double code(double x) {
      	double tmp;
      	if (hypot(1.0, x) <= 2.0) {
      		tmp = fma(-0.0859375, (x * x), 0.125) * (x * x);
      	} else {
      		tmp = 1.0 - sqrt(0.5);
      	}
      	return tmp;
      }
      
      function code(x)
      	tmp = 0.0
      	if (hypot(1.0, x) <= 2.0)
      		tmp = Float64(fma(-0.0859375, Float64(x * x), 0.125) * Float64(x * x));
      	else
      		tmp = Float64(1.0 - sqrt(0.5));
      	end
      	return tmp
      end
      
      code[x_] := If[LessEqual[N[Sqrt[1.0 ^ 2 + x ^ 2], $MachinePrecision], 2.0], N[(N[(-0.0859375 * N[(x * x), $MachinePrecision] + 0.125), $MachinePrecision] * N[(x * x), $MachinePrecision]), $MachinePrecision], N[(1.0 - N[Sqrt[0.5], $MachinePrecision]), $MachinePrecision]]
      
      \begin{array}{l}
      
      \\
      \begin{array}{l}
      \mathbf{if}\;\mathsf{hypot}\left(1, x\right) \leq 2:\\
      \;\;\;\;\mathsf{fma}\left(-0.0859375, x \cdot x, 0.125\right) \cdot \left(x \cdot x\right)\\
      
      \mathbf{else}:\\
      \;\;\;\;1 - \sqrt{0.5}\\
      
      
      \end{array}
      \end{array}
      
      Derivation
      1. Split input into 2 regimes
      2. if (hypot.f64 #s(literal 1 binary64) x) < 2

        1. Initial program 55.7%

          \[1 - \sqrt{0.5 \cdot \left(1 + \frac{1}{\mathsf{hypot}\left(1, x\right)}\right)} \]
        2. Add Preprocessing
        3. Applied rewrites55.8%

          \[\leadsto \color{blue}{\frac{\left(0.5 - \frac{-0.5}{\sqrt{\mathsf{fma}\left(x, x, 1\right)}}\right) - 1}{\left(-\sqrt{0.5 - \frac{-0.5}{\sqrt{\mathsf{fma}\left(x, x, 1\right)}}}\right) - 1}} \]
        4. Taylor expanded in x around 0

          \[\leadsto \color{blue}{{x}^{2} \cdot \left(\frac{1}{8} + \frac{-11}{128} \cdot {x}^{2}\right)} \]
        5. Step-by-step derivation
          1. *-commutativeN/A

            \[\leadsto \color{blue}{\left(\frac{1}{8} + \frac{-11}{128} \cdot {x}^{2}\right) \cdot {x}^{2}} \]
          2. unpow2N/A

            \[\leadsto \left(\frac{1}{8} + \frac{-11}{128} \cdot {x}^{2}\right) \cdot \color{blue}{\left(x \cdot x\right)} \]
          3. associate-*r*N/A

            \[\leadsto \color{blue}{\left(\left(\frac{1}{8} + \frac{-11}{128} \cdot {x}^{2}\right) \cdot x\right) \cdot x} \]
          4. lower-*.f64N/A

            \[\leadsto \color{blue}{\left(\left(\frac{1}{8} + \frac{-11}{128} \cdot {x}^{2}\right) \cdot x\right) \cdot x} \]
          5. lower-*.f64N/A

            \[\leadsto \color{blue}{\left(\left(\frac{1}{8} + \frac{-11}{128} \cdot {x}^{2}\right) \cdot x\right)} \cdot x \]
          6. +-commutativeN/A

            \[\leadsto \left(\color{blue}{\left(\frac{-11}{128} \cdot {x}^{2} + \frac{1}{8}\right)} \cdot x\right) \cdot x \]
          7. lower-fma.f64N/A

            \[\leadsto \left(\color{blue}{\mathsf{fma}\left(\frac{-11}{128}, {x}^{2}, \frac{1}{8}\right)} \cdot x\right) \cdot x \]
          8. unpow2N/A

            \[\leadsto \left(\mathsf{fma}\left(\frac{-11}{128}, \color{blue}{x \cdot x}, \frac{1}{8}\right) \cdot x\right) \cdot x \]
          9. lower-*.f64100.0

            \[\leadsto \left(\mathsf{fma}\left(-0.0859375, \color{blue}{x \cdot x}, 0.125\right) \cdot x\right) \cdot x \]
        6. Applied rewrites100.0%

          \[\leadsto \color{blue}{\left(\mathsf{fma}\left(-0.0859375, x \cdot x, 0.125\right) \cdot x\right) \cdot x} \]
        7. Step-by-step derivation
          1. Applied rewrites100.0%

            \[\leadsto \mathsf{fma}\left(-0.0859375, x \cdot x, 0.125\right) \cdot \color{blue}{\left(x \cdot x\right)} \]

          if 2 < (hypot.f64 #s(literal 1 binary64) x)

          1. Initial program 98.5%

            \[1 - \sqrt{0.5 \cdot \left(1 + \frac{1}{\mathsf{hypot}\left(1, x\right)}\right)} \]
          2. Add Preprocessing
          3. Taylor expanded in x around inf

            \[\leadsto 1 - \sqrt{\color{blue}{\frac{1}{2}}} \]
          4. Step-by-step derivation
            1. Applied rewrites97.5%

              \[\leadsto 1 - \sqrt{\color{blue}{0.5}} \]
          5. Recombined 2 regimes into one program.
          6. Add Preprocessing

          Alternative 4: 97.7% accurate, 1.0× speedup?

          \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;\mathsf{hypot}\left(1, x\right) \leq 2:\\ \;\;\;\;\left(\mathsf{fma}\left(-0.0859375, x \cdot x, 0.125\right) \cdot x\right) \cdot x\\ \mathbf{else}:\\ \;\;\;\;1 - \sqrt{0.5}\\ \end{array} \end{array} \]
          (FPCore (x)
           :precision binary64
           (if (<= (hypot 1.0 x) 2.0)
             (* (* (fma -0.0859375 (* x x) 0.125) x) x)
             (- 1.0 (sqrt 0.5))))
          double code(double x) {
          	double tmp;
          	if (hypot(1.0, x) <= 2.0) {
          		tmp = (fma(-0.0859375, (x * x), 0.125) * x) * x;
          	} else {
          		tmp = 1.0 - sqrt(0.5);
          	}
          	return tmp;
          }
          
          function code(x)
          	tmp = 0.0
          	if (hypot(1.0, x) <= 2.0)
          		tmp = Float64(Float64(fma(-0.0859375, Float64(x * x), 0.125) * x) * x);
          	else
          		tmp = Float64(1.0 - sqrt(0.5));
          	end
          	return tmp
          end
          
          code[x_] := If[LessEqual[N[Sqrt[1.0 ^ 2 + x ^ 2], $MachinePrecision], 2.0], N[(N[(N[(-0.0859375 * N[(x * x), $MachinePrecision] + 0.125), $MachinePrecision] * x), $MachinePrecision] * x), $MachinePrecision], N[(1.0 - N[Sqrt[0.5], $MachinePrecision]), $MachinePrecision]]
          
          \begin{array}{l}
          
          \\
          \begin{array}{l}
          \mathbf{if}\;\mathsf{hypot}\left(1, x\right) \leq 2:\\
          \;\;\;\;\left(\mathsf{fma}\left(-0.0859375, x \cdot x, 0.125\right) \cdot x\right) \cdot x\\
          
          \mathbf{else}:\\
          \;\;\;\;1 - \sqrt{0.5}\\
          
          
          \end{array}
          \end{array}
          
          Derivation
          1. Split input into 2 regimes
          2. if (hypot.f64 #s(literal 1 binary64) x) < 2

            1. Initial program 55.7%

              \[1 - \sqrt{0.5 \cdot \left(1 + \frac{1}{\mathsf{hypot}\left(1, x\right)}\right)} \]
            2. Add Preprocessing
            3. Applied rewrites55.8%

              \[\leadsto \color{blue}{\frac{\left(0.5 - \frac{-0.5}{\sqrt{\mathsf{fma}\left(x, x, 1\right)}}\right) - 1}{\left(-\sqrt{0.5 - \frac{-0.5}{\sqrt{\mathsf{fma}\left(x, x, 1\right)}}}\right) - 1}} \]
            4. Taylor expanded in x around 0

              \[\leadsto \color{blue}{{x}^{2} \cdot \left(\frac{1}{8} + \frac{-11}{128} \cdot {x}^{2}\right)} \]
            5. Step-by-step derivation
              1. *-commutativeN/A

                \[\leadsto \color{blue}{\left(\frac{1}{8} + \frac{-11}{128} \cdot {x}^{2}\right) \cdot {x}^{2}} \]
              2. unpow2N/A

                \[\leadsto \left(\frac{1}{8} + \frac{-11}{128} \cdot {x}^{2}\right) \cdot \color{blue}{\left(x \cdot x\right)} \]
              3. associate-*r*N/A

                \[\leadsto \color{blue}{\left(\left(\frac{1}{8} + \frac{-11}{128} \cdot {x}^{2}\right) \cdot x\right) \cdot x} \]
              4. lower-*.f64N/A

                \[\leadsto \color{blue}{\left(\left(\frac{1}{8} + \frac{-11}{128} \cdot {x}^{2}\right) \cdot x\right) \cdot x} \]
              5. lower-*.f64N/A

                \[\leadsto \color{blue}{\left(\left(\frac{1}{8} + \frac{-11}{128} \cdot {x}^{2}\right) \cdot x\right)} \cdot x \]
              6. +-commutativeN/A

                \[\leadsto \left(\color{blue}{\left(\frac{-11}{128} \cdot {x}^{2} + \frac{1}{8}\right)} \cdot x\right) \cdot x \]
              7. lower-fma.f64N/A

                \[\leadsto \left(\color{blue}{\mathsf{fma}\left(\frac{-11}{128}, {x}^{2}, \frac{1}{8}\right)} \cdot x\right) \cdot x \]
              8. unpow2N/A

                \[\leadsto \left(\mathsf{fma}\left(\frac{-11}{128}, \color{blue}{x \cdot x}, \frac{1}{8}\right) \cdot x\right) \cdot x \]
              9. lower-*.f64100.0

                \[\leadsto \left(\mathsf{fma}\left(-0.0859375, \color{blue}{x \cdot x}, 0.125\right) \cdot x\right) \cdot x \]
            6. Applied rewrites100.0%

              \[\leadsto \color{blue}{\left(\mathsf{fma}\left(-0.0859375, x \cdot x, 0.125\right) \cdot x\right) \cdot x} \]

            if 2 < (hypot.f64 #s(literal 1 binary64) x)

            1. Initial program 98.5%

              \[1 - \sqrt{0.5 \cdot \left(1 + \frac{1}{\mathsf{hypot}\left(1, x\right)}\right)} \]
            2. Add Preprocessing
            3. Taylor expanded in x around inf

              \[\leadsto 1 - \sqrt{\color{blue}{\frac{1}{2}}} \]
            4. Step-by-step derivation
              1. Applied rewrites97.5%

                \[\leadsto 1 - \sqrt{\color{blue}{0.5}} \]
            5. Recombined 2 regimes into one program.
            6. Add Preprocessing

            Alternative 5: 97.4% accurate, 1.1× speedup?

            \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;\mathsf{hypot}\left(1, x\right) \leq 2:\\ \;\;\;\;0.125 \cdot \left(x \cdot x\right)\\ \mathbf{else}:\\ \;\;\;\;1 - \sqrt{0.5}\\ \end{array} \end{array} \]
            (FPCore (x)
             :precision binary64
             (if (<= (hypot 1.0 x) 2.0) (* 0.125 (* x x)) (- 1.0 (sqrt 0.5))))
            double code(double x) {
            	double tmp;
            	if (hypot(1.0, x) <= 2.0) {
            		tmp = 0.125 * (x * x);
            	} else {
            		tmp = 1.0 - sqrt(0.5);
            	}
            	return tmp;
            }
            
            public static double code(double x) {
            	double tmp;
            	if (Math.hypot(1.0, x) <= 2.0) {
            		tmp = 0.125 * (x * x);
            	} else {
            		tmp = 1.0 - Math.sqrt(0.5);
            	}
            	return tmp;
            }
            
            def code(x):
            	tmp = 0
            	if math.hypot(1.0, x) <= 2.0:
            		tmp = 0.125 * (x * x)
            	else:
            		tmp = 1.0 - math.sqrt(0.5)
            	return tmp
            
            function code(x)
            	tmp = 0.0
            	if (hypot(1.0, x) <= 2.0)
            		tmp = Float64(0.125 * Float64(x * x));
            	else
            		tmp = Float64(1.0 - sqrt(0.5));
            	end
            	return tmp
            end
            
            function tmp_2 = code(x)
            	tmp = 0.0;
            	if (hypot(1.0, x) <= 2.0)
            		tmp = 0.125 * (x * x);
            	else
            		tmp = 1.0 - sqrt(0.5);
            	end
            	tmp_2 = tmp;
            end
            
            code[x_] := If[LessEqual[N[Sqrt[1.0 ^ 2 + x ^ 2], $MachinePrecision], 2.0], N[(0.125 * N[(x * x), $MachinePrecision]), $MachinePrecision], N[(1.0 - N[Sqrt[0.5], $MachinePrecision]), $MachinePrecision]]
            
            \begin{array}{l}
            
            \\
            \begin{array}{l}
            \mathbf{if}\;\mathsf{hypot}\left(1, x\right) \leq 2:\\
            \;\;\;\;0.125 \cdot \left(x \cdot x\right)\\
            
            \mathbf{else}:\\
            \;\;\;\;1 - \sqrt{0.5}\\
            
            
            \end{array}
            \end{array}
            
            Derivation
            1. Split input into 2 regimes
            2. if (hypot.f64 #s(literal 1 binary64) x) < 2

              1. Initial program 55.7%

                \[1 - \sqrt{0.5 \cdot \left(1 + \frac{1}{\mathsf{hypot}\left(1, x\right)}\right)} \]
              2. Add Preprocessing
              3. Applied rewrites55.8%

                \[\leadsto \color{blue}{\frac{\left(0.5 - \frac{-0.5}{\sqrt{\mathsf{fma}\left(x, x, 1\right)}}\right) - 1}{\left(-\sqrt{0.5 - \frac{-0.5}{\sqrt{\mathsf{fma}\left(x, x, 1\right)}}}\right) - 1}} \]
              4. Taylor expanded in x around 0

                \[\leadsto \color{blue}{\frac{1}{8} \cdot {x}^{2}} \]
              5. Step-by-step derivation
                1. lower-*.f64N/A

                  \[\leadsto \color{blue}{\frac{1}{8} \cdot {x}^{2}} \]
                2. unpow2N/A

                  \[\leadsto \frac{1}{8} \cdot \color{blue}{\left(x \cdot x\right)} \]
                3. lower-*.f6499.7

                  \[\leadsto 0.125 \cdot \color{blue}{\left(x \cdot x\right)} \]
              6. Applied rewrites99.7%

                \[\leadsto \color{blue}{0.125 \cdot \left(x \cdot x\right)} \]

              if 2 < (hypot.f64 #s(literal 1 binary64) x)

              1. Initial program 98.5%

                \[1 - \sqrt{0.5 \cdot \left(1 + \frac{1}{\mathsf{hypot}\left(1, x\right)}\right)} \]
              2. Add Preprocessing
              3. Taylor expanded in x around inf

                \[\leadsto 1 - \sqrt{\color{blue}{\frac{1}{2}}} \]
              4. Step-by-step derivation
                1. Applied rewrites97.5%

                  \[\leadsto 1 - \sqrt{\color{blue}{0.5}} \]
              5. Recombined 2 regimes into one program.
              6. Add Preprocessing

              Alternative 6: 51.2% accurate, 12.2× speedup?

              \[\begin{array}{l} \\ 0.125 \cdot \left(x \cdot x\right) \end{array} \]
              (FPCore (x) :precision binary64 (* 0.125 (* x x)))
              double code(double x) {
              	return 0.125 * (x * x);
              }
              
              real(8) function code(x)
                  real(8), intent (in) :: x
                  code = 0.125d0 * (x * x)
              end function
              
              public static double code(double x) {
              	return 0.125 * (x * x);
              }
              
              def code(x):
              	return 0.125 * (x * x)
              
              function code(x)
              	return Float64(0.125 * Float64(x * x))
              end
              
              function tmp = code(x)
              	tmp = 0.125 * (x * x);
              end
              
              code[x_] := N[(0.125 * N[(x * x), $MachinePrecision]), $MachinePrecision]
              
              \begin{array}{l}
              
              \\
              0.125 \cdot \left(x \cdot x\right)
              \end{array}
              
              Derivation
              1. Initial program 77.4%

                \[1 - \sqrt{0.5 \cdot \left(1 + \frac{1}{\mathsf{hypot}\left(1, x\right)}\right)} \]
              2. Add Preprocessing
              3. Applied rewrites78.2%

                \[\leadsto \color{blue}{\frac{\left(0.5 - \frac{-0.5}{\sqrt{\mathsf{fma}\left(x, x, 1\right)}}\right) - 1}{\left(-\sqrt{0.5 - \frac{-0.5}{\sqrt{\mathsf{fma}\left(x, x, 1\right)}}}\right) - 1}} \]
              4. Taylor expanded in x around 0

                \[\leadsto \color{blue}{\frac{1}{8} \cdot {x}^{2}} \]
              5. Step-by-step derivation
                1. lower-*.f64N/A

                  \[\leadsto \color{blue}{\frac{1}{8} \cdot {x}^{2}} \]
                2. unpow2N/A

                  \[\leadsto \frac{1}{8} \cdot \color{blue}{\left(x \cdot x\right)} \]
                3. lower-*.f6451.2

                  \[\leadsto 0.125 \cdot \color{blue}{\left(x \cdot x\right)} \]
              6. Applied rewrites51.2%

                \[\leadsto \color{blue}{0.125 \cdot \left(x \cdot x\right)} \]
              7. Add Preprocessing

              Reproduce

              ?
              herbie shell --seed 2024235 
              (FPCore (x)
                :name "Given's Rotation SVD example, simplified"
                :precision binary64
                (- 1.0 (sqrt (* 0.5 (+ 1.0 (/ 1.0 (hypot 1.0 x)))))))