Rosa's FloatVsDoubleBenchmark

Percentage Accurate: 70.4% → 99.1%
Time: 35.1s
Alternatives: 23
Speedup: 9.3×

Specification

?
\[\begin{array}{l} \\ \begin{array}{l} t_0 := \left(3 \cdot x1\right) \cdot x1\\ t_1 := x1 \cdot x1 + 1\\ t_2 := \frac{\left(t\_0 + 2 \cdot x2\right) - x1}{t\_1}\\ x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot t\_2\right) \cdot \left(t\_2 - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot t\_2 - 6\right)\right) \cdot t\_1 + t\_0 \cdot t\_2\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(t\_0 - 2 \cdot x2\right) - x1}{t\_1}\right) \end{array} \end{array} \]
(FPCore (x1 x2)
 :precision binary64
 (let* ((t_0 (* (* 3.0 x1) x1))
        (t_1 (+ (* x1 x1) 1.0))
        (t_2 (/ (- (+ t_0 (* 2.0 x2)) x1) t_1)))
   (+
    x1
    (+
     (+
      (+
       (+
        (*
         (+
          (* (* (* 2.0 x1) t_2) (- t_2 3.0))
          (* (* x1 x1) (- (* 4.0 t_2) 6.0)))
         t_1)
        (* t_0 t_2))
       (* (* x1 x1) x1))
      x1)
     (* 3.0 (/ (- (- t_0 (* 2.0 x2)) x1) t_1))))))
double code(double x1, double x2) {
	double t_0 = (3.0 * x1) * x1;
	double t_1 = (x1 * x1) + 1.0;
	double t_2 = ((t_0 + (2.0 * x2)) - x1) / t_1;
	return x1 + (((((((((2.0 * x1) * t_2) * (t_2 - 3.0)) + ((x1 * x1) * ((4.0 * t_2) - 6.0))) * t_1) + (t_0 * t_2)) + ((x1 * x1) * x1)) + x1) + (3.0 * (((t_0 - (2.0 * x2)) - x1) / t_1)));
}
real(8) function code(x1, x2)
    real(8), intent (in) :: x1
    real(8), intent (in) :: x2
    real(8) :: t_0
    real(8) :: t_1
    real(8) :: t_2
    t_0 = (3.0d0 * x1) * x1
    t_1 = (x1 * x1) + 1.0d0
    t_2 = ((t_0 + (2.0d0 * x2)) - x1) / t_1
    code = x1 + (((((((((2.0d0 * x1) * t_2) * (t_2 - 3.0d0)) + ((x1 * x1) * ((4.0d0 * t_2) - 6.0d0))) * t_1) + (t_0 * t_2)) + ((x1 * x1) * x1)) + x1) + (3.0d0 * (((t_0 - (2.0d0 * x2)) - x1) / t_1)))
end function
public static double code(double x1, double x2) {
	double t_0 = (3.0 * x1) * x1;
	double t_1 = (x1 * x1) + 1.0;
	double t_2 = ((t_0 + (2.0 * x2)) - x1) / t_1;
	return x1 + (((((((((2.0 * x1) * t_2) * (t_2 - 3.0)) + ((x1 * x1) * ((4.0 * t_2) - 6.0))) * t_1) + (t_0 * t_2)) + ((x1 * x1) * x1)) + x1) + (3.0 * (((t_0 - (2.0 * x2)) - x1) / t_1)));
}
def code(x1, x2):
	t_0 = (3.0 * x1) * x1
	t_1 = (x1 * x1) + 1.0
	t_2 = ((t_0 + (2.0 * x2)) - x1) / t_1
	return x1 + (((((((((2.0 * x1) * t_2) * (t_2 - 3.0)) + ((x1 * x1) * ((4.0 * t_2) - 6.0))) * t_1) + (t_0 * t_2)) + ((x1 * x1) * x1)) + x1) + (3.0 * (((t_0 - (2.0 * x2)) - x1) / t_1)))
function code(x1, x2)
	t_0 = Float64(Float64(3.0 * x1) * x1)
	t_1 = Float64(Float64(x1 * x1) + 1.0)
	t_2 = Float64(Float64(Float64(t_0 + Float64(2.0 * x2)) - x1) / t_1)
	return Float64(x1 + Float64(Float64(Float64(Float64(Float64(Float64(Float64(Float64(Float64(2.0 * x1) * t_2) * Float64(t_2 - 3.0)) + Float64(Float64(x1 * x1) * Float64(Float64(4.0 * t_2) - 6.0))) * t_1) + Float64(t_0 * t_2)) + Float64(Float64(x1 * x1) * x1)) + x1) + Float64(3.0 * Float64(Float64(Float64(t_0 - Float64(2.0 * x2)) - x1) / t_1))))
end
function tmp = code(x1, x2)
	t_0 = (3.0 * x1) * x1;
	t_1 = (x1 * x1) + 1.0;
	t_2 = ((t_0 + (2.0 * x2)) - x1) / t_1;
	tmp = x1 + (((((((((2.0 * x1) * t_2) * (t_2 - 3.0)) + ((x1 * x1) * ((4.0 * t_2) - 6.0))) * t_1) + (t_0 * t_2)) + ((x1 * x1) * x1)) + x1) + (3.0 * (((t_0 - (2.0 * x2)) - x1) / t_1)));
end
code[x1_, x2_] := Block[{t$95$0 = N[(N[(3.0 * x1), $MachinePrecision] * x1), $MachinePrecision]}, Block[{t$95$1 = N[(N[(x1 * x1), $MachinePrecision] + 1.0), $MachinePrecision]}, Block[{t$95$2 = N[(N[(N[(t$95$0 + N[(2.0 * x2), $MachinePrecision]), $MachinePrecision] - x1), $MachinePrecision] / t$95$1), $MachinePrecision]}, N[(x1 + N[(N[(N[(N[(N[(N[(N[(N[(N[(2.0 * x1), $MachinePrecision] * t$95$2), $MachinePrecision] * N[(t$95$2 - 3.0), $MachinePrecision]), $MachinePrecision] + N[(N[(x1 * x1), $MachinePrecision] * N[(N[(4.0 * t$95$2), $MachinePrecision] - 6.0), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] * t$95$1), $MachinePrecision] + N[(t$95$0 * t$95$2), $MachinePrecision]), $MachinePrecision] + N[(N[(x1 * x1), $MachinePrecision] * x1), $MachinePrecision]), $MachinePrecision] + x1), $MachinePrecision] + N[(3.0 * N[(N[(N[(t$95$0 - N[(2.0 * x2), $MachinePrecision]), $MachinePrecision] - x1), $MachinePrecision] / t$95$1), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]]]]
\begin{array}{l}

\\
\begin{array}{l}
t_0 := \left(3 \cdot x1\right) \cdot x1\\
t_1 := x1 \cdot x1 + 1\\
t_2 := \frac{\left(t\_0 + 2 \cdot x2\right) - x1}{t\_1}\\
x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot t\_2\right) \cdot \left(t\_2 - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot t\_2 - 6\right)\right) \cdot t\_1 + t\_0 \cdot t\_2\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(t\_0 - 2 \cdot x2\right) - x1}{t\_1}\right)
\end{array}
\end{array}

Sampling outcomes in binary64 precision:

Local Percentage Accuracy vs ?

The average percentage accuracy by input value. Horizontal axis shows value of an input variable; the variable is choosen in the title. Vertical axis is accuracy; higher is better. Red represent the original program, while blue represents Herbie's suggestion. These can be toggled with buttons below the plot. The line is an average while dots represent individual samples.

Accuracy vs Speed?

Herbie found 23 alternatives:

AlternativeAccuracySpeedup
The accuracy (vertical axis) and speed (horizontal axis) of each alternatives. Up and to the right is better. The red square shows the initial program, and each blue circle shows an alternative.The line shows the best available speed-accuracy tradeoffs.

Initial Program: 70.4% accurate, 1.0× speedup?

\[\begin{array}{l} \\ \begin{array}{l} t_0 := \left(3 \cdot x1\right) \cdot x1\\ t_1 := x1 \cdot x1 + 1\\ t_2 := \frac{\left(t\_0 + 2 \cdot x2\right) - x1}{t\_1}\\ x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot t\_2\right) \cdot \left(t\_2 - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot t\_2 - 6\right)\right) \cdot t\_1 + t\_0 \cdot t\_2\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(t\_0 - 2 \cdot x2\right) - x1}{t\_1}\right) \end{array} \end{array} \]
(FPCore (x1 x2)
 :precision binary64
 (let* ((t_0 (* (* 3.0 x1) x1))
        (t_1 (+ (* x1 x1) 1.0))
        (t_2 (/ (- (+ t_0 (* 2.0 x2)) x1) t_1)))
   (+
    x1
    (+
     (+
      (+
       (+
        (*
         (+
          (* (* (* 2.0 x1) t_2) (- t_2 3.0))
          (* (* x1 x1) (- (* 4.0 t_2) 6.0)))
         t_1)
        (* t_0 t_2))
       (* (* x1 x1) x1))
      x1)
     (* 3.0 (/ (- (- t_0 (* 2.0 x2)) x1) t_1))))))
double code(double x1, double x2) {
	double t_0 = (3.0 * x1) * x1;
	double t_1 = (x1 * x1) + 1.0;
	double t_2 = ((t_0 + (2.0 * x2)) - x1) / t_1;
	return x1 + (((((((((2.0 * x1) * t_2) * (t_2 - 3.0)) + ((x1 * x1) * ((4.0 * t_2) - 6.0))) * t_1) + (t_0 * t_2)) + ((x1 * x1) * x1)) + x1) + (3.0 * (((t_0 - (2.0 * x2)) - x1) / t_1)));
}
real(8) function code(x1, x2)
    real(8), intent (in) :: x1
    real(8), intent (in) :: x2
    real(8) :: t_0
    real(8) :: t_1
    real(8) :: t_2
    t_0 = (3.0d0 * x1) * x1
    t_1 = (x1 * x1) + 1.0d0
    t_2 = ((t_0 + (2.0d0 * x2)) - x1) / t_1
    code = x1 + (((((((((2.0d0 * x1) * t_2) * (t_2 - 3.0d0)) + ((x1 * x1) * ((4.0d0 * t_2) - 6.0d0))) * t_1) + (t_0 * t_2)) + ((x1 * x1) * x1)) + x1) + (3.0d0 * (((t_0 - (2.0d0 * x2)) - x1) / t_1)))
end function
public static double code(double x1, double x2) {
	double t_0 = (3.0 * x1) * x1;
	double t_1 = (x1 * x1) + 1.0;
	double t_2 = ((t_0 + (2.0 * x2)) - x1) / t_1;
	return x1 + (((((((((2.0 * x1) * t_2) * (t_2 - 3.0)) + ((x1 * x1) * ((4.0 * t_2) - 6.0))) * t_1) + (t_0 * t_2)) + ((x1 * x1) * x1)) + x1) + (3.0 * (((t_0 - (2.0 * x2)) - x1) / t_1)));
}
def code(x1, x2):
	t_0 = (3.0 * x1) * x1
	t_1 = (x1 * x1) + 1.0
	t_2 = ((t_0 + (2.0 * x2)) - x1) / t_1
	return x1 + (((((((((2.0 * x1) * t_2) * (t_2 - 3.0)) + ((x1 * x1) * ((4.0 * t_2) - 6.0))) * t_1) + (t_0 * t_2)) + ((x1 * x1) * x1)) + x1) + (3.0 * (((t_0 - (2.0 * x2)) - x1) / t_1)))
function code(x1, x2)
	t_0 = Float64(Float64(3.0 * x1) * x1)
	t_1 = Float64(Float64(x1 * x1) + 1.0)
	t_2 = Float64(Float64(Float64(t_0 + Float64(2.0 * x2)) - x1) / t_1)
	return Float64(x1 + Float64(Float64(Float64(Float64(Float64(Float64(Float64(Float64(Float64(2.0 * x1) * t_2) * Float64(t_2 - 3.0)) + Float64(Float64(x1 * x1) * Float64(Float64(4.0 * t_2) - 6.0))) * t_1) + Float64(t_0 * t_2)) + Float64(Float64(x1 * x1) * x1)) + x1) + Float64(3.0 * Float64(Float64(Float64(t_0 - Float64(2.0 * x2)) - x1) / t_1))))
end
function tmp = code(x1, x2)
	t_0 = (3.0 * x1) * x1;
	t_1 = (x1 * x1) + 1.0;
	t_2 = ((t_0 + (2.0 * x2)) - x1) / t_1;
	tmp = x1 + (((((((((2.0 * x1) * t_2) * (t_2 - 3.0)) + ((x1 * x1) * ((4.0 * t_2) - 6.0))) * t_1) + (t_0 * t_2)) + ((x1 * x1) * x1)) + x1) + (3.0 * (((t_0 - (2.0 * x2)) - x1) / t_1)));
end
code[x1_, x2_] := Block[{t$95$0 = N[(N[(3.0 * x1), $MachinePrecision] * x1), $MachinePrecision]}, Block[{t$95$1 = N[(N[(x1 * x1), $MachinePrecision] + 1.0), $MachinePrecision]}, Block[{t$95$2 = N[(N[(N[(t$95$0 + N[(2.0 * x2), $MachinePrecision]), $MachinePrecision] - x1), $MachinePrecision] / t$95$1), $MachinePrecision]}, N[(x1 + N[(N[(N[(N[(N[(N[(N[(N[(N[(2.0 * x1), $MachinePrecision] * t$95$2), $MachinePrecision] * N[(t$95$2 - 3.0), $MachinePrecision]), $MachinePrecision] + N[(N[(x1 * x1), $MachinePrecision] * N[(N[(4.0 * t$95$2), $MachinePrecision] - 6.0), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] * t$95$1), $MachinePrecision] + N[(t$95$0 * t$95$2), $MachinePrecision]), $MachinePrecision] + N[(N[(x1 * x1), $MachinePrecision] * x1), $MachinePrecision]), $MachinePrecision] + x1), $MachinePrecision] + N[(3.0 * N[(N[(N[(t$95$0 - N[(2.0 * x2), $MachinePrecision]), $MachinePrecision] - x1), $MachinePrecision] / t$95$1), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]]]]
\begin{array}{l}

\\
\begin{array}{l}
t_0 := \left(3 \cdot x1\right) \cdot x1\\
t_1 := x1 \cdot x1 + 1\\
t_2 := \frac{\left(t\_0 + 2 \cdot x2\right) - x1}{t\_1}\\
x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot t\_2\right) \cdot \left(t\_2 - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot t\_2 - 6\right)\right) \cdot t\_1 + t\_0 \cdot t\_2\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(t\_0 - 2 \cdot x2\right) - x1}{t\_1}\right)
\end{array}
\end{array}

Alternative 1: 99.1% accurate, 0.5× speedup?

\[\begin{array}{l} \\ \begin{array}{l} t_0 := \left(3 \cdot x1\right) \cdot x1\\ t_1 := -1 - x1 \cdot x1\\ t_2 := \mathsf{fma}\left(x2, 2, t\_0\right) - x1\\ t_3 := \frac{t\_2}{\mathsf{fma}\left(x1, x1, 1\right)}\\ t_4 := \left(x2 \cdot 2 + t\_0\right) - x1\\ t_5 := x1 \cdot x1 - -1\\ t_6 := \frac{t\_4}{t\_5}\\ \mathbf{if}\;x1 - \left(\left(\left(\left(\frac{t\_4}{t\_1} \cdot t\_0 - t\_1 \cdot \left(\left(3 - t\_6\right) \cdot \left(\left(2 \cdot x1\right) \cdot t\_6\right) - \left(4 \cdot t\_6 - 6\right) \cdot \left(x1 \cdot x1\right)\right)\right) - \left(x1 \cdot x1\right) \cdot x1\right) - x1\right) - \frac{\left(t\_0 - x2 \cdot 2\right) - x1}{t\_5} \cdot 3\right) \leq \infty:\\ \;\;\;\;\mathsf{fma}\left(\frac{\mathsf{fma}\left(-2, x2, t\_0\right) - x1}{\mathsf{fma}\left(x1, x1, 1\right)}, 3, \mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(4, t\_3, -6\right), x1 \cdot x1, \left(\left(2 \cdot x1\right) \cdot t\_3\right) \cdot \left(t\_3 - 3\right)\right), \mathsf{fma}\left(x1, x1, 1\right), \mathsf{fma}\left(\frac{t\_2 \cdot x1}{\mathsf{fma}\left(x1, x1, 1\right)}, 3 \cdot x1, \mathsf{fma}\left(x1, x1, 1\right) \cdot x1\right)\right)\right) + x1\\ \mathbf{else}:\\ \;\;\;\;\left(\left(6 \cdot x1\right) \cdot x1\right) \cdot \left(x1 \cdot x1\right) + x1\\ \end{array} \end{array} \]
(FPCore (x1 x2)
 :precision binary64
 (let* ((t_0 (* (* 3.0 x1) x1))
        (t_1 (- -1.0 (* x1 x1)))
        (t_2 (- (fma x2 2.0 t_0) x1))
        (t_3 (/ t_2 (fma x1 x1 1.0)))
        (t_4 (- (+ (* x2 2.0) t_0) x1))
        (t_5 (- (* x1 x1) -1.0))
        (t_6 (/ t_4 t_5)))
   (if (<=
        (-
         x1
         (-
          (-
           (-
            (-
             (* (/ t_4 t_1) t_0)
             (*
              t_1
              (-
               (* (- 3.0 t_6) (* (* 2.0 x1) t_6))
               (* (- (* 4.0 t_6) 6.0) (* x1 x1)))))
            (* (* x1 x1) x1))
           x1)
          (* (/ (- (- t_0 (* x2 2.0)) x1) t_5) 3.0)))
        INFINITY)
     (+
      (fma
       (/ (- (fma -2.0 x2 t_0) x1) (fma x1 x1 1.0))
       3.0
       (fma
        (fma (fma 4.0 t_3 -6.0) (* x1 x1) (* (* (* 2.0 x1) t_3) (- t_3 3.0)))
        (fma x1 x1 1.0)
        (fma
         (/ (* t_2 x1) (fma x1 x1 1.0))
         (* 3.0 x1)
         (* (fma x1 x1 1.0) x1))))
      x1)
     (+ (* (* (* 6.0 x1) x1) (* x1 x1)) x1))))
double code(double x1, double x2) {
	double t_0 = (3.0 * x1) * x1;
	double t_1 = -1.0 - (x1 * x1);
	double t_2 = fma(x2, 2.0, t_0) - x1;
	double t_3 = t_2 / fma(x1, x1, 1.0);
	double t_4 = ((x2 * 2.0) + t_0) - x1;
	double t_5 = (x1 * x1) - -1.0;
	double t_6 = t_4 / t_5;
	double tmp;
	if ((x1 - ((((((t_4 / t_1) * t_0) - (t_1 * (((3.0 - t_6) * ((2.0 * x1) * t_6)) - (((4.0 * t_6) - 6.0) * (x1 * x1))))) - ((x1 * x1) * x1)) - x1) - ((((t_0 - (x2 * 2.0)) - x1) / t_5) * 3.0))) <= ((double) INFINITY)) {
		tmp = fma(((fma(-2.0, x2, t_0) - x1) / fma(x1, x1, 1.0)), 3.0, fma(fma(fma(4.0, t_3, -6.0), (x1 * x1), (((2.0 * x1) * t_3) * (t_3 - 3.0))), fma(x1, x1, 1.0), fma(((t_2 * x1) / fma(x1, x1, 1.0)), (3.0 * x1), (fma(x1, x1, 1.0) * x1)))) + x1;
	} else {
		tmp = (((6.0 * x1) * x1) * (x1 * x1)) + x1;
	}
	return tmp;
}
function code(x1, x2)
	t_0 = Float64(Float64(3.0 * x1) * x1)
	t_1 = Float64(-1.0 - Float64(x1 * x1))
	t_2 = Float64(fma(x2, 2.0, t_0) - x1)
	t_3 = Float64(t_2 / fma(x1, x1, 1.0))
	t_4 = Float64(Float64(Float64(x2 * 2.0) + t_0) - x1)
	t_5 = Float64(Float64(x1 * x1) - -1.0)
	t_6 = Float64(t_4 / t_5)
	tmp = 0.0
	if (Float64(x1 - Float64(Float64(Float64(Float64(Float64(Float64(t_4 / t_1) * t_0) - Float64(t_1 * Float64(Float64(Float64(3.0 - t_6) * Float64(Float64(2.0 * x1) * t_6)) - Float64(Float64(Float64(4.0 * t_6) - 6.0) * Float64(x1 * x1))))) - Float64(Float64(x1 * x1) * x1)) - x1) - Float64(Float64(Float64(Float64(t_0 - Float64(x2 * 2.0)) - x1) / t_5) * 3.0))) <= Inf)
		tmp = Float64(fma(Float64(Float64(fma(-2.0, x2, t_0) - x1) / fma(x1, x1, 1.0)), 3.0, fma(fma(fma(4.0, t_3, -6.0), Float64(x1 * x1), Float64(Float64(Float64(2.0 * x1) * t_3) * Float64(t_3 - 3.0))), fma(x1, x1, 1.0), fma(Float64(Float64(t_2 * x1) / fma(x1, x1, 1.0)), Float64(3.0 * x1), Float64(fma(x1, x1, 1.0) * x1)))) + x1);
	else
		tmp = Float64(Float64(Float64(Float64(6.0 * x1) * x1) * Float64(x1 * x1)) + x1);
	end
	return tmp
end
code[x1_, x2_] := Block[{t$95$0 = N[(N[(3.0 * x1), $MachinePrecision] * x1), $MachinePrecision]}, Block[{t$95$1 = N[(-1.0 - N[(x1 * x1), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$2 = N[(N[(x2 * 2.0 + t$95$0), $MachinePrecision] - x1), $MachinePrecision]}, Block[{t$95$3 = N[(t$95$2 / N[(x1 * x1 + 1.0), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$4 = N[(N[(N[(x2 * 2.0), $MachinePrecision] + t$95$0), $MachinePrecision] - x1), $MachinePrecision]}, Block[{t$95$5 = N[(N[(x1 * x1), $MachinePrecision] - -1.0), $MachinePrecision]}, Block[{t$95$6 = N[(t$95$4 / t$95$5), $MachinePrecision]}, If[LessEqual[N[(x1 - N[(N[(N[(N[(N[(N[(t$95$4 / t$95$1), $MachinePrecision] * t$95$0), $MachinePrecision] - N[(t$95$1 * N[(N[(N[(3.0 - t$95$6), $MachinePrecision] * N[(N[(2.0 * x1), $MachinePrecision] * t$95$6), $MachinePrecision]), $MachinePrecision] - N[(N[(N[(4.0 * t$95$6), $MachinePrecision] - 6.0), $MachinePrecision] * N[(x1 * x1), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] - N[(N[(x1 * x1), $MachinePrecision] * x1), $MachinePrecision]), $MachinePrecision] - x1), $MachinePrecision] - N[(N[(N[(N[(t$95$0 - N[(x2 * 2.0), $MachinePrecision]), $MachinePrecision] - x1), $MachinePrecision] / t$95$5), $MachinePrecision] * 3.0), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], Infinity], N[(N[(N[(N[(N[(-2.0 * x2 + t$95$0), $MachinePrecision] - x1), $MachinePrecision] / N[(x1 * x1 + 1.0), $MachinePrecision]), $MachinePrecision] * 3.0 + N[(N[(N[(4.0 * t$95$3 + -6.0), $MachinePrecision] * N[(x1 * x1), $MachinePrecision] + N[(N[(N[(2.0 * x1), $MachinePrecision] * t$95$3), $MachinePrecision] * N[(t$95$3 - 3.0), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] * N[(x1 * x1 + 1.0), $MachinePrecision] + N[(N[(N[(t$95$2 * x1), $MachinePrecision] / N[(x1 * x1 + 1.0), $MachinePrecision]), $MachinePrecision] * N[(3.0 * x1), $MachinePrecision] + N[(N[(x1 * x1 + 1.0), $MachinePrecision] * x1), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] + x1), $MachinePrecision], N[(N[(N[(N[(6.0 * x1), $MachinePrecision] * x1), $MachinePrecision] * N[(x1 * x1), $MachinePrecision]), $MachinePrecision] + x1), $MachinePrecision]]]]]]]]]
\begin{array}{l}

\\
\begin{array}{l}
t_0 := \left(3 \cdot x1\right) \cdot x1\\
t_1 := -1 - x1 \cdot x1\\
t_2 := \mathsf{fma}\left(x2, 2, t\_0\right) - x1\\
t_3 := \frac{t\_2}{\mathsf{fma}\left(x1, x1, 1\right)}\\
t_4 := \left(x2 \cdot 2 + t\_0\right) - x1\\
t_5 := x1 \cdot x1 - -1\\
t_6 := \frac{t\_4}{t\_5}\\
\mathbf{if}\;x1 - \left(\left(\left(\left(\frac{t\_4}{t\_1} \cdot t\_0 - t\_1 \cdot \left(\left(3 - t\_6\right) \cdot \left(\left(2 \cdot x1\right) \cdot t\_6\right) - \left(4 \cdot t\_6 - 6\right) \cdot \left(x1 \cdot x1\right)\right)\right) - \left(x1 \cdot x1\right) \cdot x1\right) - x1\right) - \frac{\left(t\_0 - x2 \cdot 2\right) - x1}{t\_5} \cdot 3\right) \leq \infty:\\
\;\;\;\;\mathsf{fma}\left(\frac{\mathsf{fma}\left(-2, x2, t\_0\right) - x1}{\mathsf{fma}\left(x1, x1, 1\right)}, 3, \mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(4, t\_3, -6\right), x1 \cdot x1, \left(\left(2 \cdot x1\right) \cdot t\_3\right) \cdot \left(t\_3 - 3\right)\right), \mathsf{fma}\left(x1, x1, 1\right), \mathsf{fma}\left(\frac{t\_2 \cdot x1}{\mathsf{fma}\left(x1, x1, 1\right)}, 3 \cdot x1, \mathsf{fma}\left(x1, x1, 1\right) \cdot x1\right)\right)\right) + x1\\

\mathbf{else}:\\
\;\;\;\;\left(\left(6 \cdot x1\right) \cdot x1\right) \cdot \left(x1 \cdot x1\right) + x1\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if (+.f64 x1 (+.f64 (+.f64 (+.f64 (+.f64 (*.f64 (+.f64 (*.f64 (*.f64 (*.f64 #s(literal 2 binary64) x1) (/.f64 (-.f64 (+.f64 (*.f64 (*.f64 #s(literal 3 binary64) x1) x1) (*.f64 #s(literal 2 binary64) x2)) x1) (+.f64 (*.f64 x1 x1) #s(literal 1 binary64)))) (-.f64 (/.f64 (-.f64 (+.f64 (*.f64 (*.f64 #s(literal 3 binary64) x1) x1) (*.f64 #s(literal 2 binary64) x2)) x1) (+.f64 (*.f64 x1 x1) #s(literal 1 binary64))) #s(literal 3 binary64))) (*.f64 (*.f64 x1 x1) (-.f64 (*.f64 #s(literal 4 binary64) (/.f64 (-.f64 (+.f64 (*.f64 (*.f64 #s(literal 3 binary64) x1) x1) (*.f64 #s(literal 2 binary64) x2)) x1) (+.f64 (*.f64 x1 x1) #s(literal 1 binary64)))) #s(literal 6 binary64)))) (+.f64 (*.f64 x1 x1) #s(literal 1 binary64))) (*.f64 (*.f64 (*.f64 #s(literal 3 binary64) x1) x1) (/.f64 (-.f64 (+.f64 (*.f64 (*.f64 #s(literal 3 binary64) x1) x1) (*.f64 #s(literal 2 binary64) x2)) x1) (+.f64 (*.f64 x1 x1) #s(literal 1 binary64))))) (*.f64 (*.f64 x1 x1) x1)) x1) (*.f64 #s(literal 3 binary64) (/.f64 (-.f64 (-.f64 (*.f64 (*.f64 #s(literal 3 binary64) x1) x1) (*.f64 #s(literal 2 binary64) x2)) x1) (+.f64 (*.f64 x1 x1) #s(literal 1 binary64)))))) < +inf.0

    1. Initial program 99.5%

      \[x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
    2. Add Preprocessing
    3. Applied rewrites99.7%

      \[\leadsto x1 + \color{blue}{\mathsf{fma}\left(\frac{\mathsf{fma}\left(-2, x2, \left(3 \cdot x1\right) \cdot x1\right) - x1}{\mathsf{fma}\left(x1, x1, 1\right)}, 3, \mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(4, \frac{\mathsf{fma}\left(x2, 2, \left(3 \cdot x1\right) \cdot x1\right) - x1}{\mathsf{fma}\left(x1, x1, 1\right)}, -6\right), x1 \cdot x1, \left(\frac{\mathsf{fma}\left(x2, 2, \left(3 \cdot x1\right) \cdot x1\right) - x1}{\mathsf{fma}\left(x1, x1, 1\right)} - 3\right) \cdot \left(\frac{\mathsf{fma}\left(x2, 2, \left(3 \cdot x1\right) \cdot x1\right) - x1}{\mathsf{fma}\left(x1, x1, 1\right)} \cdot \left(x1 \cdot 2\right)\right)\right), \mathsf{fma}\left(x1, x1, 1\right), \mathsf{fma}\left(\frac{x1 \cdot \left(\mathsf{fma}\left(x2, 2, \left(3 \cdot x1\right) \cdot x1\right) - x1\right)}{\mathsf{fma}\left(x1, x1, 1\right)}, 3 \cdot x1, \mathsf{fma}\left(x1, x1, 1\right) \cdot x1\right)\right)\right)} \]

    if +inf.0 < (+.f64 x1 (+.f64 (+.f64 (+.f64 (+.f64 (*.f64 (+.f64 (*.f64 (*.f64 (*.f64 #s(literal 2 binary64) x1) (/.f64 (-.f64 (+.f64 (*.f64 (*.f64 #s(literal 3 binary64) x1) x1) (*.f64 #s(literal 2 binary64) x2)) x1) (+.f64 (*.f64 x1 x1) #s(literal 1 binary64)))) (-.f64 (/.f64 (-.f64 (+.f64 (*.f64 (*.f64 #s(literal 3 binary64) x1) x1) (*.f64 #s(literal 2 binary64) x2)) x1) (+.f64 (*.f64 x1 x1) #s(literal 1 binary64))) #s(literal 3 binary64))) (*.f64 (*.f64 x1 x1) (-.f64 (*.f64 #s(literal 4 binary64) (/.f64 (-.f64 (+.f64 (*.f64 (*.f64 #s(literal 3 binary64) x1) x1) (*.f64 #s(literal 2 binary64) x2)) x1) (+.f64 (*.f64 x1 x1) #s(literal 1 binary64)))) #s(literal 6 binary64)))) (+.f64 (*.f64 x1 x1) #s(literal 1 binary64))) (*.f64 (*.f64 (*.f64 #s(literal 3 binary64) x1) x1) (/.f64 (-.f64 (+.f64 (*.f64 (*.f64 #s(literal 3 binary64) x1) x1) (*.f64 #s(literal 2 binary64) x2)) x1) (+.f64 (*.f64 x1 x1) #s(literal 1 binary64))))) (*.f64 (*.f64 x1 x1) x1)) x1) (*.f64 #s(literal 3 binary64) (/.f64 (-.f64 (-.f64 (*.f64 (*.f64 #s(literal 3 binary64) x1) x1) (*.f64 #s(literal 2 binary64) x2)) x1) (+.f64 (*.f64 x1 x1) #s(literal 1 binary64))))))

    1. Initial program 0.0%

      \[x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
    2. Add Preprocessing
    3. Taylor expanded in x1 around inf

      \[\leadsto x1 + \color{blue}{6 \cdot {x1}^{4}} \]
    4. Step-by-step derivation
      1. *-commutativeN/A

        \[\leadsto x1 + \color{blue}{{x1}^{4} \cdot 6} \]
      2. lower-*.f64N/A

        \[\leadsto x1 + \color{blue}{{x1}^{4} \cdot 6} \]
      3. lower-pow.f64100.0

        \[\leadsto x1 + \color{blue}{{x1}^{4}} \cdot 6 \]
    5. Applied rewrites100.0%

      \[\leadsto x1 + \color{blue}{{x1}^{4} \cdot 6} \]
    6. Step-by-step derivation
      1. Applied rewrites100.0%

        \[\leadsto x1 + \left(\left(\left(x1 \cdot x1\right) \cdot x1\right) \cdot x1\right) \cdot \color{blue}{6} \]
      2. Step-by-step derivation
        1. Applied rewrites100.0%

          \[\leadsto x1 + \left(x1 \cdot x1\right) \cdot \color{blue}{\left(x1 \cdot \left(6 \cdot x1\right)\right)} \]
      3. Recombined 2 regimes into one program.
      4. Final simplification99.8%

        \[\leadsto \begin{array}{l} \mathbf{if}\;x1 - \left(\left(\left(\left(\frac{\left(x2 \cdot 2 + \left(3 \cdot x1\right) \cdot x1\right) - x1}{-1 - x1 \cdot x1} \cdot \left(\left(3 \cdot x1\right) \cdot x1\right) - \left(-1 - x1 \cdot x1\right) \cdot \left(\left(3 - \frac{\left(x2 \cdot 2 + \left(3 \cdot x1\right) \cdot x1\right) - x1}{x1 \cdot x1 - -1}\right) \cdot \left(\left(2 \cdot x1\right) \cdot \frac{\left(x2 \cdot 2 + \left(3 \cdot x1\right) \cdot x1\right) - x1}{x1 \cdot x1 - -1}\right) - \left(4 \cdot \frac{\left(x2 \cdot 2 + \left(3 \cdot x1\right) \cdot x1\right) - x1}{x1 \cdot x1 - -1} - 6\right) \cdot \left(x1 \cdot x1\right)\right)\right) - \left(x1 \cdot x1\right) \cdot x1\right) - x1\right) - \frac{\left(\left(3 \cdot x1\right) \cdot x1 - x2 \cdot 2\right) - x1}{x1 \cdot x1 - -1} \cdot 3\right) \leq \infty:\\ \;\;\;\;\mathsf{fma}\left(\frac{\mathsf{fma}\left(-2, x2, \left(3 \cdot x1\right) \cdot x1\right) - x1}{\mathsf{fma}\left(x1, x1, 1\right)}, 3, \mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(4, \frac{\mathsf{fma}\left(x2, 2, \left(3 \cdot x1\right) \cdot x1\right) - x1}{\mathsf{fma}\left(x1, x1, 1\right)}, -6\right), x1 \cdot x1, \left(\left(2 \cdot x1\right) \cdot \frac{\mathsf{fma}\left(x2, 2, \left(3 \cdot x1\right) \cdot x1\right) - x1}{\mathsf{fma}\left(x1, x1, 1\right)}\right) \cdot \left(\frac{\mathsf{fma}\left(x2, 2, \left(3 \cdot x1\right) \cdot x1\right) - x1}{\mathsf{fma}\left(x1, x1, 1\right)} - 3\right)\right), \mathsf{fma}\left(x1, x1, 1\right), \mathsf{fma}\left(\frac{\left(\mathsf{fma}\left(x2, 2, \left(3 \cdot x1\right) \cdot x1\right) - x1\right) \cdot x1}{\mathsf{fma}\left(x1, x1, 1\right)}, 3 \cdot x1, \mathsf{fma}\left(x1, x1, 1\right) \cdot x1\right)\right)\right) + x1\\ \mathbf{else}:\\ \;\;\;\;\left(\left(6 \cdot x1\right) \cdot x1\right) \cdot \left(x1 \cdot x1\right) + x1\\ \end{array} \]
      5. Add Preprocessing

      Alternative 2: 78.5% accurate, 0.3× speedup?

      \[\begin{array}{l} \\ \begin{array}{l} t_0 := \left(3 \cdot x1\right) \cdot x1\\ t_1 := \mathsf{fma}\left(8 \cdot x1, x2, -6\right) \cdot x2 + x1\\ t_2 := -1 - x1 \cdot x1\\ t_3 := \left(x2 \cdot 2 + t\_0\right) - x1\\ t_4 := x1 \cdot x1 - -1\\ t_5 := \frac{t\_3}{t\_4}\\ t_6 := x1 - \left(\left(\left(\left(\frac{t\_3}{t\_2} \cdot t\_0 - t\_2 \cdot \left(\left(3 - t\_5\right) \cdot \left(\left(2 \cdot x1\right) \cdot t\_5\right) - \left(4 \cdot t\_5 - 6\right) \cdot \left(x1 \cdot x1\right)\right)\right) - \left(x1 \cdot x1\right) \cdot x1\right) - x1\right) - \frac{\left(t\_0 - x2 \cdot 2\right) - x1}{t\_4} \cdot 3\right)\\ \mathbf{if}\;t\_6 \leq -1 \cdot 10^{+88}:\\ \;\;\;\;t\_1\\ \mathbf{elif}\;t\_6 \leq 5 \cdot 10^{+158}:\\ \;\;\;\;\mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(-19, x1, 9\right), x1, -1\right), x1, -6 \cdot x2\right)\\ \mathbf{elif}\;t\_6 \leq \infty:\\ \;\;\;\;t\_1\\ \mathbf{else}:\\ \;\;\;\;\left(9 \cdot x1\right) \cdot x1 + x1\\ \end{array} \end{array} \]
      (FPCore (x1 x2)
       :precision binary64
       (let* ((t_0 (* (* 3.0 x1) x1))
              (t_1 (+ (* (fma (* 8.0 x1) x2 -6.0) x2) x1))
              (t_2 (- -1.0 (* x1 x1)))
              (t_3 (- (+ (* x2 2.0) t_0) x1))
              (t_4 (- (* x1 x1) -1.0))
              (t_5 (/ t_3 t_4))
              (t_6
               (-
                x1
                (-
                 (-
                  (-
                   (-
                    (* (/ t_3 t_2) t_0)
                    (*
                     t_2
                     (-
                      (* (- 3.0 t_5) (* (* 2.0 x1) t_5))
                      (* (- (* 4.0 t_5) 6.0) (* x1 x1)))))
                   (* (* x1 x1) x1))
                  x1)
                 (* (/ (- (- t_0 (* x2 2.0)) x1) t_4) 3.0)))))
         (if (<= t_6 -1e+88)
           t_1
           (if (<= t_6 5e+158)
             (fma (fma (fma -19.0 x1 9.0) x1 -1.0) x1 (* -6.0 x2))
             (if (<= t_6 INFINITY) t_1 (+ (* (* 9.0 x1) x1) x1))))))
      double code(double x1, double x2) {
      	double t_0 = (3.0 * x1) * x1;
      	double t_1 = (fma((8.0 * x1), x2, -6.0) * x2) + x1;
      	double t_2 = -1.0 - (x1 * x1);
      	double t_3 = ((x2 * 2.0) + t_0) - x1;
      	double t_4 = (x1 * x1) - -1.0;
      	double t_5 = t_3 / t_4;
      	double t_6 = x1 - ((((((t_3 / t_2) * t_0) - (t_2 * (((3.0 - t_5) * ((2.0 * x1) * t_5)) - (((4.0 * t_5) - 6.0) * (x1 * x1))))) - ((x1 * x1) * x1)) - x1) - ((((t_0 - (x2 * 2.0)) - x1) / t_4) * 3.0));
      	double tmp;
      	if (t_6 <= -1e+88) {
      		tmp = t_1;
      	} else if (t_6 <= 5e+158) {
      		tmp = fma(fma(fma(-19.0, x1, 9.0), x1, -1.0), x1, (-6.0 * x2));
      	} else if (t_6 <= ((double) INFINITY)) {
      		tmp = t_1;
      	} else {
      		tmp = ((9.0 * x1) * x1) + x1;
      	}
      	return tmp;
      }
      
      function code(x1, x2)
      	t_0 = Float64(Float64(3.0 * x1) * x1)
      	t_1 = Float64(Float64(fma(Float64(8.0 * x1), x2, -6.0) * x2) + x1)
      	t_2 = Float64(-1.0 - Float64(x1 * x1))
      	t_3 = Float64(Float64(Float64(x2 * 2.0) + t_0) - x1)
      	t_4 = Float64(Float64(x1 * x1) - -1.0)
      	t_5 = Float64(t_3 / t_4)
      	t_6 = Float64(x1 - Float64(Float64(Float64(Float64(Float64(Float64(t_3 / t_2) * t_0) - Float64(t_2 * Float64(Float64(Float64(3.0 - t_5) * Float64(Float64(2.0 * x1) * t_5)) - Float64(Float64(Float64(4.0 * t_5) - 6.0) * Float64(x1 * x1))))) - Float64(Float64(x1 * x1) * x1)) - x1) - Float64(Float64(Float64(Float64(t_0 - Float64(x2 * 2.0)) - x1) / t_4) * 3.0)))
      	tmp = 0.0
      	if (t_6 <= -1e+88)
      		tmp = t_1;
      	elseif (t_6 <= 5e+158)
      		tmp = fma(fma(fma(-19.0, x1, 9.0), x1, -1.0), x1, Float64(-6.0 * x2));
      	elseif (t_6 <= Inf)
      		tmp = t_1;
      	else
      		tmp = Float64(Float64(Float64(9.0 * x1) * x1) + x1);
      	end
      	return tmp
      end
      
      code[x1_, x2_] := Block[{t$95$0 = N[(N[(3.0 * x1), $MachinePrecision] * x1), $MachinePrecision]}, Block[{t$95$1 = N[(N[(N[(N[(8.0 * x1), $MachinePrecision] * x2 + -6.0), $MachinePrecision] * x2), $MachinePrecision] + x1), $MachinePrecision]}, Block[{t$95$2 = N[(-1.0 - N[(x1 * x1), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$3 = N[(N[(N[(x2 * 2.0), $MachinePrecision] + t$95$0), $MachinePrecision] - x1), $MachinePrecision]}, Block[{t$95$4 = N[(N[(x1 * x1), $MachinePrecision] - -1.0), $MachinePrecision]}, Block[{t$95$5 = N[(t$95$3 / t$95$4), $MachinePrecision]}, Block[{t$95$6 = N[(x1 - N[(N[(N[(N[(N[(N[(t$95$3 / t$95$2), $MachinePrecision] * t$95$0), $MachinePrecision] - N[(t$95$2 * N[(N[(N[(3.0 - t$95$5), $MachinePrecision] * N[(N[(2.0 * x1), $MachinePrecision] * t$95$5), $MachinePrecision]), $MachinePrecision] - N[(N[(N[(4.0 * t$95$5), $MachinePrecision] - 6.0), $MachinePrecision] * N[(x1 * x1), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] - N[(N[(x1 * x1), $MachinePrecision] * x1), $MachinePrecision]), $MachinePrecision] - x1), $MachinePrecision] - N[(N[(N[(N[(t$95$0 - N[(x2 * 2.0), $MachinePrecision]), $MachinePrecision] - x1), $MachinePrecision] / t$95$4), $MachinePrecision] * 3.0), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[t$95$6, -1e+88], t$95$1, If[LessEqual[t$95$6, 5e+158], N[(N[(N[(-19.0 * x1 + 9.0), $MachinePrecision] * x1 + -1.0), $MachinePrecision] * x1 + N[(-6.0 * x2), $MachinePrecision]), $MachinePrecision], If[LessEqual[t$95$6, Infinity], t$95$1, N[(N[(N[(9.0 * x1), $MachinePrecision] * x1), $MachinePrecision] + x1), $MachinePrecision]]]]]]]]]]]
      
      \begin{array}{l}
      
      \\
      \begin{array}{l}
      t_0 := \left(3 \cdot x1\right) \cdot x1\\
      t_1 := \mathsf{fma}\left(8 \cdot x1, x2, -6\right) \cdot x2 + x1\\
      t_2 := -1 - x1 \cdot x1\\
      t_3 := \left(x2 \cdot 2 + t\_0\right) - x1\\
      t_4 := x1 \cdot x1 - -1\\
      t_5 := \frac{t\_3}{t\_4}\\
      t_6 := x1 - \left(\left(\left(\left(\frac{t\_3}{t\_2} \cdot t\_0 - t\_2 \cdot \left(\left(3 - t\_5\right) \cdot \left(\left(2 \cdot x1\right) \cdot t\_5\right) - \left(4 \cdot t\_5 - 6\right) \cdot \left(x1 \cdot x1\right)\right)\right) - \left(x1 \cdot x1\right) \cdot x1\right) - x1\right) - \frac{\left(t\_0 - x2 \cdot 2\right) - x1}{t\_4} \cdot 3\right)\\
      \mathbf{if}\;t\_6 \leq -1 \cdot 10^{+88}:\\
      \;\;\;\;t\_1\\
      
      \mathbf{elif}\;t\_6 \leq 5 \cdot 10^{+158}:\\
      \;\;\;\;\mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(-19, x1, 9\right), x1, -1\right), x1, -6 \cdot x2\right)\\
      
      \mathbf{elif}\;t\_6 \leq \infty:\\
      \;\;\;\;t\_1\\
      
      \mathbf{else}:\\
      \;\;\;\;\left(9 \cdot x1\right) \cdot x1 + x1\\
      
      
      \end{array}
      \end{array}
      
      Derivation
      1. Split input into 3 regimes
      2. if (+.f64 x1 (+.f64 (+.f64 (+.f64 (+.f64 (*.f64 (+.f64 (*.f64 (*.f64 (*.f64 #s(literal 2 binary64) x1) (/.f64 (-.f64 (+.f64 (*.f64 (*.f64 #s(literal 3 binary64) x1) x1) (*.f64 #s(literal 2 binary64) x2)) x1) (+.f64 (*.f64 x1 x1) #s(literal 1 binary64)))) (-.f64 (/.f64 (-.f64 (+.f64 (*.f64 (*.f64 #s(literal 3 binary64) x1) x1) (*.f64 #s(literal 2 binary64) x2)) x1) (+.f64 (*.f64 x1 x1) #s(literal 1 binary64))) #s(literal 3 binary64))) (*.f64 (*.f64 x1 x1) (-.f64 (*.f64 #s(literal 4 binary64) (/.f64 (-.f64 (+.f64 (*.f64 (*.f64 #s(literal 3 binary64) x1) x1) (*.f64 #s(literal 2 binary64) x2)) x1) (+.f64 (*.f64 x1 x1) #s(literal 1 binary64)))) #s(literal 6 binary64)))) (+.f64 (*.f64 x1 x1) #s(literal 1 binary64))) (*.f64 (*.f64 (*.f64 #s(literal 3 binary64) x1) x1) (/.f64 (-.f64 (+.f64 (*.f64 (*.f64 #s(literal 3 binary64) x1) x1) (*.f64 #s(literal 2 binary64) x2)) x1) (+.f64 (*.f64 x1 x1) #s(literal 1 binary64))))) (*.f64 (*.f64 x1 x1) x1)) x1) (*.f64 #s(literal 3 binary64) (/.f64 (-.f64 (-.f64 (*.f64 (*.f64 #s(literal 3 binary64) x1) x1) (*.f64 #s(literal 2 binary64) x2)) x1) (+.f64 (*.f64 x1 x1) #s(literal 1 binary64)))))) < -9.99999999999999959e87 or 4.9999999999999996e158 < (+.f64 x1 (+.f64 (+.f64 (+.f64 (+.f64 (*.f64 (+.f64 (*.f64 (*.f64 (*.f64 #s(literal 2 binary64) x1) (/.f64 (-.f64 (+.f64 (*.f64 (*.f64 #s(literal 3 binary64) x1) x1) (*.f64 #s(literal 2 binary64) x2)) x1) (+.f64 (*.f64 x1 x1) #s(literal 1 binary64)))) (-.f64 (/.f64 (-.f64 (+.f64 (*.f64 (*.f64 #s(literal 3 binary64) x1) x1) (*.f64 #s(literal 2 binary64) x2)) x1) (+.f64 (*.f64 x1 x1) #s(literal 1 binary64))) #s(literal 3 binary64))) (*.f64 (*.f64 x1 x1) (-.f64 (*.f64 #s(literal 4 binary64) (/.f64 (-.f64 (+.f64 (*.f64 (*.f64 #s(literal 3 binary64) x1) x1) (*.f64 #s(literal 2 binary64) x2)) x1) (+.f64 (*.f64 x1 x1) #s(literal 1 binary64)))) #s(literal 6 binary64)))) (+.f64 (*.f64 x1 x1) #s(literal 1 binary64))) (*.f64 (*.f64 (*.f64 #s(literal 3 binary64) x1) x1) (/.f64 (-.f64 (+.f64 (*.f64 (*.f64 #s(literal 3 binary64) x1) x1) (*.f64 #s(literal 2 binary64) x2)) x1) (+.f64 (*.f64 x1 x1) #s(literal 1 binary64))))) (*.f64 (*.f64 x1 x1) x1)) x1) (*.f64 #s(literal 3 binary64) (/.f64 (-.f64 (-.f64 (*.f64 (*.f64 #s(literal 3 binary64) x1) x1) (*.f64 #s(literal 2 binary64) x2)) x1) (+.f64 (*.f64 x1 x1) #s(literal 1 binary64)))))) < +inf.0

        1. Initial program 99.8%

          \[x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
        2. Add Preprocessing
        3. Taylor expanded in x1 around 0

          \[\leadsto x1 + \color{blue}{\left(-6 \cdot x2 + x1 \cdot \left(\left(4 \cdot \left(x2 \cdot \left(2 \cdot x2 - 3\right)\right) + x1 \cdot \left(\left(2 \cdot \left(-2 \cdot x2 + -1 \cdot \left(2 \cdot x2 - 3\right)\right) + \left(3 \cdot \left(3 - -2 \cdot x2\right) + \left(6 \cdot x2 + 8 \cdot x2\right)\right)\right) - 6\right)\right) - 2\right)\right)} \]
        4. Applied rewrites53.5%

          \[\leadsto x1 + \color{blue}{\mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(-4, x2, \mathsf{fma}\left(\mathsf{fma}\left(-2, x2, 3\right), 2, \mathsf{fma}\left(\mathsf{fma}\left(2, x2, 3\right), 3, \mathsf{fma}\left(14, x2, -6\right)\right)\right)\right), x1, \mathsf{fma}\left(\mathsf{fma}\left(2, x2, -3\right) \cdot 4, x2, -2\right)\right), x1, -6 \cdot x2\right)} \]
        5. Taylor expanded in x2 around -inf

          \[\leadsto x1 + {x2}^{2} \cdot \color{blue}{\left(-1 \cdot \frac{6 + x1 \cdot \left(12 + -12 \cdot x1\right)}{x2} + 8 \cdot x1\right)} \]
        6. Step-by-step derivation
          1. Applied rewrites53.0%

            \[\leadsto x1 + \mathsf{fma}\left(x1, 8, \frac{\mathsf{fma}\left(\mathsf{fma}\left(x1, -12, 12\right), x1, 6\right)}{-x2}\right) \cdot \color{blue}{\left(x2 \cdot x2\right)} \]
          2. Taylor expanded in x2 around 0

            \[\leadsto x1 + x2 \cdot \left(-1 \cdot \left(6 + x1 \cdot \left(12 + -12 \cdot x1\right)\right) + \color{blue}{8 \cdot \left(x1 \cdot x2\right)}\right) \]
          3. Step-by-step derivation
            1. Applied rewrites69.3%

              \[\leadsto x1 + \mathsf{fma}\left(x1 \cdot 8, x2, -\mathsf{fma}\left(\mathsf{fma}\left(x1, -12, 12\right), x1, 6\right)\right) \cdot x2 \]
            2. Taylor expanded in x1 around 0

              \[\leadsto x1 + \mathsf{fma}\left(x1 \cdot 8, x2, -6\right) \cdot x2 \]
            3. Step-by-step derivation
              1. Applied rewrites70.4%

                \[\leadsto x1 + \mathsf{fma}\left(x1 \cdot 8, x2, -6\right) \cdot x2 \]

              if -9.99999999999999959e87 < (+.f64 x1 (+.f64 (+.f64 (+.f64 (+.f64 (*.f64 (+.f64 (*.f64 (*.f64 (*.f64 #s(literal 2 binary64) x1) (/.f64 (-.f64 (+.f64 (*.f64 (*.f64 #s(literal 3 binary64) x1) x1) (*.f64 #s(literal 2 binary64) x2)) x1) (+.f64 (*.f64 x1 x1) #s(literal 1 binary64)))) (-.f64 (/.f64 (-.f64 (+.f64 (*.f64 (*.f64 #s(literal 3 binary64) x1) x1) (*.f64 #s(literal 2 binary64) x2)) x1) (+.f64 (*.f64 x1 x1) #s(literal 1 binary64))) #s(literal 3 binary64))) (*.f64 (*.f64 x1 x1) (-.f64 (*.f64 #s(literal 4 binary64) (/.f64 (-.f64 (+.f64 (*.f64 (*.f64 #s(literal 3 binary64) x1) x1) (*.f64 #s(literal 2 binary64) x2)) x1) (+.f64 (*.f64 x1 x1) #s(literal 1 binary64)))) #s(literal 6 binary64)))) (+.f64 (*.f64 x1 x1) #s(literal 1 binary64))) (*.f64 (*.f64 (*.f64 #s(literal 3 binary64) x1) x1) (/.f64 (-.f64 (+.f64 (*.f64 (*.f64 #s(literal 3 binary64) x1) x1) (*.f64 #s(literal 2 binary64) x2)) x1) (+.f64 (*.f64 x1 x1) #s(literal 1 binary64))))) (*.f64 (*.f64 x1 x1) x1)) x1) (*.f64 #s(literal 3 binary64) (/.f64 (-.f64 (-.f64 (*.f64 (*.f64 #s(literal 3 binary64) x1) x1) (*.f64 #s(literal 2 binary64) x2)) x1) (+.f64 (*.f64 x1 x1) #s(literal 1 binary64)))))) < 4.9999999999999996e158

              1. Initial program 99.3%

                \[x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
              2. Add Preprocessing
              3. Taylor expanded in x1 around 0

                \[\leadsto x1 + \color{blue}{-6 \cdot x2} \]
              4. Step-by-step derivation
                1. lower-*.f6461.5

                  \[\leadsto x1 + \color{blue}{-6 \cdot x2} \]
              5. Applied rewrites61.5%

                \[\leadsto x1 + \color{blue}{-6 \cdot x2} \]
              6. Taylor expanded in x1 around 0

                \[\leadsto \color{blue}{-6 \cdot x2 + x1 \cdot \left(\left(4 \cdot \left(x2 \cdot \left(2 \cdot x2 - 3\right)\right) + x1 \cdot \left(\left(2 \cdot \left(-2 \cdot x2 + -1 \cdot \left(2 \cdot x2 - 3\right)\right) + \left(3 \cdot \left(3 - -2 \cdot x2\right) + \left(6 \cdot x2 + \left(8 \cdot x2 + x1 \cdot \left(\left(2 \cdot \left(\left(1 + \left(2 \cdot \left(x2 \cdot \left(3 + -2 \cdot x2\right)\right) + 3 \cdot \left(2 \cdot x2 - 3\right)\right)\right) - 2 \cdot \left(x2 \cdot \left(2 \cdot x2 - 3\right)\right)\right) + 4 \cdot \left(x2 \cdot \left(2 \cdot x2 - 3\right)\right)\right) - 3\right)\right)\right)\right)\right) - 6\right)\right) - 1\right)} \]
              7. Applied rewrites87.2%

                \[\leadsto \color{blue}{\mathsf{fma}\left(\mathsf{fma}\left(\left(\mathsf{fma}\left(14, x2, \mathsf{fma}\left(\mathsf{fma}\left(\left(1 + \mathsf{fma}\left(-4, x2, 6\right) \cdot x2\right) + \mathsf{fma}\left(\mathsf{fma}\left(-4, x2, 6\right), x2, \mathsf{fma}\left(6, x2, -9\right)\right), 2, \mathsf{fma}\left(\mathsf{fma}\left(2, x2, -3\right) \cdot 4, x2, -3\right)\right), x1, \mathsf{fma}\left(6, x2, 9\right)\right)\right) + \mathsf{fma}\left(-4, x2, \mathsf{fma}\left(-4, x2, 6\right)\right)\right) - 6, x1, \mathsf{fma}\left(\mathsf{fma}\left(2, x2, -3\right) \cdot x2, 4, -1\right)\right), x1, -6 \cdot x2\right)} \]
              8. Taylor expanded in x2 around 0

                \[\leadsto \mathsf{fma}\left(x1 \cdot \left(9 + -19 \cdot x1\right) - 1, x1, -6 \cdot x2\right) \]
              9. Step-by-step derivation
                1. Applied rewrites87.1%

                  \[\leadsto \mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(-19, x1, 9\right), x1, -1\right), x1, -6 \cdot x2\right) \]

                if +inf.0 < (+.f64 x1 (+.f64 (+.f64 (+.f64 (+.f64 (*.f64 (+.f64 (*.f64 (*.f64 (*.f64 #s(literal 2 binary64) x1) (/.f64 (-.f64 (+.f64 (*.f64 (*.f64 #s(literal 3 binary64) x1) x1) (*.f64 #s(literal 2 binary64) x2)) x1) (+.f64 (*.f64 x1 x1) #s(literal 1 binary64)))) (-.f64 (/.f64 (-.f64 (+.f64 (*.f64 (*.f64 #s(literal 3 binary64) x1) x1) (*.f64 #s(literal 2 binary64) x2)) x1) (+.f64 (*.f64 x1 x1) #s(literal 1 binary64))) #s(literal 3 binary64))) (*.f64 (*.f64 x1 x1) (-.f64 (*.f64 #s(literal 4 binary64) (/.f64 (-.f64 (+.f64 (*.f64 (*.f64 #s(literal 3 binary64) x1) x1) (*.f64 #s(literal 2 binary64) x2)) x1) (+.f64 (*.f64 x1 x1) #s(literal 1 binary64)))) #s(literal 6 binary64)))) (+.f64 (*.f64 x1 x1) #s(literal 1 binary64))) (*.f64 (*.f64 (*.f64 #s(literal 3 binary64) x1) x1) (/.f64 (-.f64 (+.f64 (*.f64 (*.f64 #s(literal 3 binary64) x1) x1) (*.f64 #s(literal 2 binary64) x2)) x1) (+.f64 (*.f64 x1 x1) #s(literal 1 binary64))))) (*.f64 (*.f64 x1 x1) x1)) x1) (*.f64 #s(literal 3 binary64) (/.f64 (-.f64 (-.f64 (*.f64 (*.f64 #s(literal 3 binary64) x1) x1) (*.f64 #s(literal 2 binary64) x2)) x1) (+.f64 (*.f64 x1 x1) #s(literal 1 binary64))))))

                1. Initial program 0.0%

                  \[x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                2. Add Preprocessing
                3. Taylor expanded in x1 around 0

                  \[\leadsto x1 + \color{blue}{\left(-6 \cdot x2 + x1 \cdot \left(\left(4 \cdot \left(x2 \cdot \left(2 \cdot x2 - 3\right)\right) + x1 \cdot \left(\left(2 \cdot \left(-2 \cdot x2 + -1 \cdot \left(2 \cdot x2 - 3\right)\right) + \left(3 \cdot \left(3 - -2 \cdot x2\right) + \left(6 \cdot x2 + 8 \cdot x2\right)\right)\right) - 6\right)\right) - 2\right)\right)} \]
                4. Applied rewrites78.1%

                  \[\leadsto x1 + \color{blue}{\mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(-4, x2, \mathsf{fma}\left(\mathsf{fma}\left(-2, x2, 3\right), 2, \mathsf{fma}\left(\mathsf{fma}\left(2, x2, 3\right), 3, \mathsf{fma}\left(14, x2, -6\right)\right)\right)\right), x1, \mathsf{fma}\left(\mathsf{fma}\left(2, x2, -3\right) \cdot 4, x2, -2\right)\right), x1, -6 \cdot x2\right)} \]
                5. Taylor expanded in x2 around 0

                  \[\leadsto x1 + x1 \cdot \color{blue}{\left(9 \cdot x1 - 2\right)} \]
                6. Step-by-step derivation
                  1. Applied rewrites87.0%

                    \[\leadsto x1 + \mathsf{fma}\left(x1, 9, -2\right) \cdot \color{blue}{x1} \]
                  2. Taylor expanded in x1 around inf

                    \[\leadsto x1 + 9 \cdot {x1}^{\color{blue}{2}} \]
                  3. Step-by-step derivation
                    1. Applied rewrites87.0%

                      \[\leadsto x1 + \left(9 \cdot x1\right) \cdot x1 \]
                  4. Recombined 3 regimes into one program.
                  5. Final simplification81.7%

                    \[\leadsto \begin{array}{l} \mathbf{if}\;x1 - \left(\left(\left(\left(\frac{\left(x2 \cdot 2 + \left(3 \cdot x1\right) \cdot x1\right) - x1}{-1 - x1 \cdot x1} \cdot \left(\left(3 \cdot x1\right) \cdot x1\right) - \left(-1 - x1 \cdot x1\right) \cdot \left(\left(3 - \frac{\left(x2 \cdot 2 + \left(3 \cdot x1\right) \cdot x1\right) - x1}{x1 \cdot x1 - -1}\right) \cdot \left(\left(2 \cdot x1\right) \cdot \frac{\left(x2 \cdot 2 + \left(3 \cdot x1\right) \cdot x1\right) - x1}{x1 \cdot x1 - -1}\right) - \left(4 \cdot \frac{\left(x2 \cdot 2 + \left(3 \cdot x1\right) \cdot x1\right) - x1}{x1 \cdot x1 - -1} - 6\right) \cdot \left(x1 \cdot x1\right)\right)\right) - \left(x1 \cdot x1\right) \cdot x1\right) - x1\right) - \frac{\left(\left(3 \cdot x1\right) \cdot x1 - x2 \cdot 2\right) - x1}{x1 \cdot x1 - -1} \cdot 3\right) \leq -1 \cdot 10^{+88}:\\ \;\;\;\;\mathsf{fma}\left(8 \cdot x1, x2, -6\right) \cdot x2 + x1\\ \mathbf{elif}\;x1 - \left(\left(\left(\left(\frac{\left(x2 \cdot 2 + \left(3 \cdot x1\right) \cdot x1\right) - x1}{-1 - x1 \cdot x1} \cdot \left(\left(3 \cdot x1\right) \cdot x1\right) - \left(-1 - x1 \cdot x1\right) \cdot \left(\left(3 - \frac{\left(x2 \cdot 2 + \left(3 \cdot x1\right) \cdot x1\right) - x1}{x1 \cdot x1 - -1}\right) \cdot \left(\left(2 \cdot x1\right) \cdot \frac{\left(x2 \cdot 2 + \left(3 \cdot x1\right) \cdot x1\right) - x1}{x1 \cdot x1 - -1}\right) - \left(4 \cdot \frac{\left(x2 \cdot 2 + \left(3 \cdot x1\right) \cdot x1\right) - x1}{x1 \cdot x1 - -1} - 6\right) \cdot \left(x1 \cdot x1\right)\right)\right) - \left(x1 \cdot x1\right) \cdot x1\right) - x1\right) - \frac{\left(\left(3 \cdot x1\right) \cdot x1 - x2 \cdot 2\right) - x1}{x1 \cdot x1 - -1} \cdot 3\right) \leq 5 \cdot 10^{+158}:\\ \;\;\;\;\mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(-19, x1, 9\right), x1, -1\right), x1, -6 \cdot x2\right)\\ \mathbf{elif}\;x1 - \left(\left(\left(\left(\frac{\left(x2 \cdot 2 + \left(3 \cdot x1\right) \cdot x1\right) - x1}{-1 - x1 \cdot x1} \cdot \left(\left(3 \cdot x1\right) \cdot x1\right) - \left(-1 - x1 \cdot x1\right) \cdot \left(\left(3 - \frac{\left(x2 \cdot 2 + \left(3 \cdot x1\right) \cdot x1\right) - x1}{x1 \cdot x1 - -1}\right) \cdot \left(\left(2 \cdot x1\right) \cdot \frac{\left(x2 \cdot 2 + \left(3 \cdot x1\right) \cdot x1\right) - x1}{x1 \cdot x1 - -1}\right) - \left(4 \cdot \frac{\left(x2 \cdot 2 + \left(3 \cdot x1\right) \cdot x1\right) - x1}{x1 \cdot x1 - -1} - 6\right) \cdot \left(x1 \cdot x1\right)\right)\right) - \left(x1 \cdot x1\right) \cdot x1\right) - x1\right) - \frac{\left(\left(3 \cdot x1\right) \cdot x1 - x2 \cdot 2\right) - x1}{x1 \cdot x1 - -1} \cdot 3\right) \leq \infty:\\ \;\;\;\;\mathsf{fma}\left(8 \cdot x1, x2, -6\right) \cdot x2 + x1\\ \mathbf{else}:\\ \;\;\;\;\left(9 \cdot x1\right) \cdot x1 + x1\\ \end{array} \]
                  6. Add Preprocessing

                  Alternative 3: 78.4% accurate, 0.3× speedup?

                  \[\begin{array}{l} \\ \begin{array}{l} t_0 := \left(3 \cdot x1\right) \cdot x1\\ t_1 := \mathsf{fma}\left(8 \cdot x1, x2, -6\right) \cdot x2 + x1\\ t_2 := -1 - x1 \cdot x1\\ t_3 := \left(x2 \cdot 2 + t\_0\right) - x1\\ t_4 := x1 \cdot x1 - -1\\ t_5 := \frac{t\_3}{t\_4}\\ t_6 := x1 - \left(\left(\left(\left(\frac{t\_3}{t\_2} \cdot t\_0 - t\_2 \cdot \left(\left(3 - t\_5\right) \cdot \left(\left(2 \cdot x1\right) \cdot t\_5\right) - \left(4 \cdot t\_5 - 6\right) \cdot \left(x1 \cdot x1\right)\right)\right) - \left(x1 \cdot x1\right) \cdot x1\right) - x1\right) - \frac{\left(t\_0 - x2 \cdot 2\right) - x1}{t\_4} \cdot 3\right)\\ \mathbf{if}\;t\_6 \leq -5 \cdot 10^{+85}:\\ \;\;\;\;t\_1\\ \mathbf{elif}\;t\_6 \leq 2 \cdot 10^{+161}:\\ \;\;\;\;\mathsf{fma}\left(x2, -6, \mathsf{fma}\left(9, x1, -2\right) \cdot x1\right) + x1\\ \mathbf{elif}\;t\_6 \leq \infty:\\ \;\;\;\;t\_1\\ \mathbf{else}:\\ \;\;\;\;\left(9 \cdot x1\right) \cdot x1 + x1\\ \end{array} \end{array} \]
                  (FPCore (x1 x2)
                   :precision binary64
                   (let* ((t_0 (* (* 3.0 x1) x1))
                          (t_1 (+ (* (fma (* 8.0 x1) x2 -6.0) x2) x1))
                          (t_2 (- -1.0 (* x1 x1)))
                          (t_3 (- (+ (* x2 2.0) t_0) x1))
                          (t_4 (- (* x1 x1) -1.0))
                          (t_5 (/ t_3 t_4))
                          (t_6
                           (-
                            x1
                            (-
                             (-
                              (-
                               (-
                                (* (/ t_3 t_2) t_0)
                                (*
                                 t_2
                                 (-
                                  (* (- 3.0 t_5) (* (* 2.0 x1) t_5))
                                  (* (- (* 4.0 t_5) 6.0) (* x1 x1)))))
                               (* (* x1 x1) x1))
                              x1)
                             (* (/ (- (- t_0 (* x2 2.0)) x1) t_4) 3.0)))))
                     (if (<= t_6 -5e+85)
                       t_1
                       (if (<= t_6 2e+161)
                         (+ (fma x2 -6.0 (* (fma 9.0 x1 -2.0) x1)) x1)
                         (if (<= t_6 INFINITY) t_1 (+ (* (* 9.0 x1) x1) x1))))))
                  double code(double x1, double x2) {
                  	double t_0 = (3.0 * x1) * x1;
                  	double t_1 = (fma((8.0 * x1), x2, -6.0) * x2) + x1;
                  	double t_2 = -1.0 - (x1 * x1);
                  	double t_3 = ((x2 * 2.0) + t_0) - x1;
                  	double t_4 = (x1 * x1) - -1.0;
                  	double t_5 = t_3 / t_4;
                  	double t_6 = x1 - ((((((t_3 / t_2) * t_0) - (t_2 * (((3.0 - t_5) * ((2.0 * x1) * t_5)) - (((4.0 * t_5) - 6.0) * (x1 * x1))))) - ((x1 * x1) * x1)) - x1) - ((((t_0 - (x2 * 2.0)) - x1) / t_4) * 3.0));
                  	double tmp;
                  	if (t_6 <= -5e+85) {
                  		tmp = t_1;
                  	} else if (t_6 <= 2e+161) {
                  		tmp = fma(x2, -6.0, (fma(9.0, x1, -2.0) * x1)) + x1;
                  	} else if (t_6 <= ((double) INFINITY)) {
                  		tmp = t_1;
                  	} else {
                  		tmp = ((9.0 * x1) * x1) + x1;
                  	}
                  	return tmp;
                  }
                  
                  function code(x1, x2)
                  	t_0 = Float64(Float64(3.0 * x1) * x1)
                  	t_1 = Float64(Float64(fma(Float64(8.0 * x1), x2, -6.0) * x2) + x1)
                  	t_2 = Float64(-1.0 - Float64(x1 * x1))
                  	t_3 = Float64(Float64(Float64(x2 * 2.0) + t_0) - x1)
                  	t_4 = Float64(Float64(x1 * x1) - -1.0)
                  	t_5 = Float64(t_3 / t_4)
                  	t_6 = Float64(x1 - Float64(Float64(Float64(Float64(Float64(Float64(t_3 / t_2) * t_0) - Float64(t_2 * Float64(Float64(Float64(3.0 - t_5) * Float64(Float64(2.0 * x1) * t_5)) - Float64(Float64(Float64(4.0 * t_5) - 6.0) * Float64(x1 * x1))))) - Float64(Float64(x1 * x1) * x1)) - x1) - Float64(Float64(Float64(Float64(t_0 - Float64(x2 * 2.0)) - x1) / t_4) * 3.0)))
                  	tmp = 0.0
                  	if (t_6 <= -5e+85)
                  		tmp = t_1;
                  	elseif (t_6 <= 2e+161)
                  		tmp = Float64(fma(x2, -6.0, Float64(fma(9.0, x1, -2.0) * x1)) + x1);
                  	elseif (t_6 <= Inf)
                  		tmp = t_1;
                  	else
                  		tmp = Float64(Float64(Float64(9.0 * x1) * x1) + x1);
                  	end
                  	return tmp
                  end
                  
                  code[x1_, x2_] := Block[{t$95$0 = N[(N[(3.0 * x1), $MachinePrecision] * x1), $MachinePrecision]}, Block[{t$95$1 = N[(N[(N[(N[(8.0 * x1), $MachinePrecision] * x2 + -6.0), $MachinePrecision] * x2), $MachinePrecision] + x1), $MachinePrecision]}, Block[{t$95$2 = N[(-1.0 - N[(x1 * x1), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$3 = N[(N[(N[(x2 * 2.0), $MachinePrecision] + t$95$0), $MachinePrecision] - x1), $MachinePrecision]}, Block[{t$95$4 = N[(N[(x1 * x1), $MachinePrecision] - -1.0), $MachinePrecision]}, Block[{t$95$5 = N[(t$95$3 / t$95$4), $MachinePrecision]}, Block[{t$95$6 = N[(x1 - N[(N[(N[(N[(N[(N[(t$95$3 / t$95$2), $MachinePrecision] * t$95$0), $MachinePrecision] - N[(t$95$2 * N[(N[(N[(3.0 - t$95$5), $MachinePrecision] * N[(N[(2.0 * x1), $MachinePrecision] * t$95$5), $MachinePrecision]), $MachinePrecision] - N[(N[(N[(4.0 * t$95$5), $MachinePrecision] - 6.0), $MachinePrecision] * N[(x1 * x1), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] - N[(N[(x1 * x1), $MachinePrecision] * x1), $MachinePrecision]), $MachinePrecision] - x1), $MachinePrecision] - N[(N[(N[(N[(t$95$0 - N[(x2 * 2.0), $MachinePrecision]), $MachinePrecision] - x1), $MachinePrecision] / t$95$4), $MachinePrecision] * 3.0), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[t$95$6, -5e+85], t$95$1, If[LessEqual[t$95$6, 2e+161], N[(N[(x2 * -6.0 + N[(N[(9.0 * x1 + -2.0), $MachinePrecision] * x1), $MachinePrecision]), $MachinePrecision] + x1), $MachinePrecision], If[LessEqual[t$95$6, Infinity], t$95$1, N[(N[(N[(9.0 * x1), $MachinePrecision] * x1), $MachinePrecision] + x1), $MachinePrecision]]]]]]]]]]]
                  
                  \begin{array}{l}
                  
                  \\
                  \begin{array}{l}
                  t_0 := \left(3 \cdot x1\right) \cdot x1\\
                  t_1 := \mathsf{fma}\left(8 \cdot x1, x2, -6\right) \cdot x2 + x1\\
                  t_2 := -1 - x1 \cdot x1\\
                  t_3 := \left(x2 \cdot 2 + t\_0\right) - x1\\
                  t_4 := x1 \cdot x1 - -1\\
                  t_5 := \frac{t\_3}{t\_4}\\
                  t_6 := x1 - \left(\left(\left(\left(\frac{t\_3}{t\_2} \cdot t\_0 - t\_2 \cdot \left(\left(3 - t\_5\right) \cdot \left(\left(2 \cdot x1\right) \cdot t\_5\right) - \left(4 \cdot t\_5 - 6\right) \cdot \left(x1 \cdot x1\right)\right)\right) - \left(x1 \cdot x1\right) \cdot x1\right) - x1\right) - \frac{\left(t\_0 - x2 \cdot 2\right) - x1}{t\_4} \cdot 3\right)\\
                  \mathbf{if}\;t\_6 \leq -5 \cdot 10^{+85}:\\
                  \;\;\;\;t\_1\\
                  
                  \mathbf{elif}\;t\_6 \leq 2 \cdot 10^{+161}:\\
                  \;\;\;\;\mathsf{fma}\left(x2, -6, \mathsf{fma}\left(9, x1, -2\right) \cdot x1\right) + x1\\
                  
                  \mathbf{elif}\;t\_6 \leq \infty:\\
                  \;\;\;\;t\_1\\
                  
                  \mathbf{else}:\\
                  \;\;\;\;\left(9 \cdot x1\right) \cdot x1 + x1\\
                  
                  
                  \end{array}
                  \end{array}
                  
                  Derivation
                  1. Split input into 3 regimes
                  2. if (+.f64 x1 (+.f64 (+.f64 (+.f64 (+.f64 (*.f64 (+.f64 (*.f64 (*.f64 (*.f64 #s(literal 2 binary64) x1) (/.f64 (-.f64 (+.f64 (*.f64 (*.f64 #s(literal 3 binary64) x1) x1) (*.f64 #s(literal 2 binary64) x2)) x1) (+.f64 (*.f64 x1 x1) #s(literal 1 binary64)))) (-.f64 (/.f64 (-.f64 (+.f64 (*.f64 (*.f64 #s(literal 3 binary64) x1) x1) (*.f64 #s(literal 2 binary64) x2)) x1) (+.f64 (*.f64 x1 x1) #s(literal 1 binary64))) #s(literal 3 binary64))) (*.f64 (*.f64 x1 x1) (-.f64 (*.f64 #s(literal 4 binary64) (/.f64 (-.f64 (+.f64 (*.f64 (*.f64 #s(literal 3 binary64) x1) x1) (*.f64 #s(literal 2 binary64) x2)) x1) (+.f64 (*.f64 x1 x1) #s(literal 1 binary64)))) #s(literal 6 binary64)))) (+.f64 (*.f64 x1 x1) #s(literal 1 binary64))) (*.f64 (*.f64 (*.f64 #s(literal 3 binary64) x1) x1) (/.f64 (-.f64 (+.f64 (*.f64 (*.f64 #s(literal 3 binary64) x1) x1) (*.f64 #s(literal 2 binary64) x2)) x1) (+.f64 (*.f64 x1 x1) #s(literal 1 binary64))))) (*.f64 (*.f64 x1 x1) x1)) x1) (*.f64 #s(literal 3 binary64) (/.f64 (-.f64 (-.f64 (*.f64 (*.f64 #s(literal 3 binary64) x1) x1) (*.f64 #s(literal 2 binary64) x2)) x1) (+.f64 (*.f64 x1 x1) #s(literal 1 binary64)))))) < -5.0000000000000001e85 or 2.0000000000000001e161 < (+.f64 x1 (+.f64 (+.f64 (+.f64 (+.f64 (*.f64 (+.f64 (*.f64 (*.f64 (*.f64 #s(literal 2 binary64) x1) (/.f64 (-.f64 (+.f64 (*.f64 (*.f64 #s(literal 3 binary64) x1) x1) (*.f64 #s(literal 2 binary64) x2)) x1) (+.f64 (*.f64 x1 x1) #s(literal 1 binary64)))) (-.f64 (/.f64 (-.f64 (+.f64 (*.f64 (*.f64 #s(literal 3 binary64) x1) x1) (*.f64 #s(literal 2 binary64) x2)) x1) (+.f64 (*.f64 x1 x1) #s(literal 1 binary64))) #s(literal 3 binary64))) (*.f64 (*.f64 x1 x1) (-.f64 (*.f64 #s(literal 4 binary64) (/.f64 (-.f64 (+.f64 (*.f64 (*.f64 #s(literal 3 binary64) x1) x1) (*.f64 #s(literal 2 binary64) x2)) x1) (+.f64 (*.f64 x1 x1) #s(literal 1 binary64)))) #s(literal 6 binary64)))) (+.f64 (*.f64 x1 x1) #s(literal 1 binary64))) (*.f64 (*.f64 (*.f64 #s(literal 3 binary64) x1) x1) (/.f64 (-.f64 (+.f64 (*.f64 (*.f64 #s(literal 3 binary64) x1) x1) (*.f64 #s(literal 2 binary64) x2)) x1) (+.f64 (*.f64 x1 x1) #s(literal 1 binary64))))) (*.f64 (*.f64 x1 x1) x1)) x1) (*.f64 #s(literal 3 binary64) (/.f64 (-.f64 (-.f64 (*.f64 (*.f64 #s(literal 3 binary64) x1) x1) (*.f64 #s(literal 2 binary64) x2)) x1) (+.f64 (*.f64 x1 x1) #s(literal 1 binary64)))))) < +inf.0

                    1. Initial program 99.8%

                      \[x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                    2. Add Preprocessing
                    3. Taylor expanded in x1 around 0

                      \[\leadsto x1 + \color{blue}{\left(-6 \cdot x2 + x1 \cdot \left(\left(4 \cdot \left(x2 \cdot \left(2 \cdot x2 - 3\right)\right) + x1 \cdot \left(\left(2 \cdot \left(-2 \cdot x2 + -1 \cdot \left(2 \cdot x2 - 3\right)\right) + \left(3 \cdot \left(3 - -2 \cdot x2\right) + \left(6 \cdot x2 + 8 \cdot x2\right)\right)\right) - 6\right)\right) - 2\right)\right)} \]
                    4. Applied rewrites54.6%

                      \[\leadsto x1 + \color{blue}{\mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(-4, x2, \mathsf{fma}\left(\mathsf{fma}\left(-2, x2, 3\right), 2, \mathsf{fma}\left(\mathsf{fma}\left(2, x2, 3\right), 3, \mathsf{fma}\left(14, x2, -6\right)\right)\right)\right), x1, \mathsf{fma}\left(\mathsf{fma}\left(2, x2, -3\right) \cdot 4, x2, -2\right)\right), x1, -6 \cdot x2\right)} \]
                    5. Taylor expanded in x2 around -inf

                      \[\leadsto x1 + {x2}^{2} \cdot \color{blue}{\left(-1 \cdot \frac{6 + x1 \cdot \left(12 + -12 \cdot x1\right)}{x2} + 8 \cdot x1\right)} \]
                    6. Step-by-step derivation
                      1. Applied rewrites54.2%

                        \[\leadsto x1 + \mathsf{fma}\left(x1, 8, \frac{\mathsf{fma}\left(\mathsf{fma}\left(x1, -12, 12\right), x1, 6\right)}{-x2}\right) \cdot \color{blue}{\left(x2 \cdot x2\right)} \]
                      2. Taylor expanded in x2 around 0

                        \[\leadsto x1 + x2 \cdot \left(-1 \cdot \left(6 + x1 \cdot \left(12 + -12 \cdot x1\right)\right) + \color{blue}{8 \cdot \left(x1 \cdot x2\right)}\right) \]
                      3. Step-by-step derivation
                        1. Applied rewrites70.5%

                          \[\leadsto x1 + \mathsf{fma}\left(x1 \cdot 8, x2, -\mathsf{fma}\left(\mathsf{fma}\left(x1, -12, 12\right), x1, 6\right)\right) \cdot x2 \]
                        2. Taylor expanded in x1 around 0

                          \[\leadsto x1 + \mathsf{fma}\left(x1 \cdot 8, x2, -6\right) \cdot x2 \]
                        3. Step-by-step derivation
                          1. Applied rewrites71.6%

                            \[\leadsto x1 + \mathsf{fma}\left(x1 \cdot 8, x2, -6\right) \cdot x2 \]

                          if -5.0000000000000001e85 < (+.f64 x1 (+.f64 (+.f64 (+.f64 (+.f64 (*.f64 (+.f64 (*.f64 (*.f64 (*.f64 #s(literal 2 binary64) x1) (/.f64 (-.f64 (+.f64 (*.f64 (*.f64 #s(literal 3 binary64) x1) x1) (*.f64 #s(literal 2 binary64) x2)) x1) (+.f64 (*.f64 x1 x1) #s(literal 1 binary64)))) (-.f64 (/.f64 (-.f64 (+.f64 (*.f64 (*.f64 #s(literal 3 binary64) x1) x1) (*.f64 #s(literal 2 binary64) x2)) x1) (+.f64 (*.f64 x1 x1) #s(literal 1 binary64))) #s(literal 3 binary64))) (*.f64 (*.f64 x1 x1) (-.f64 (*.f64 #s(literal 4 binary64) (/.f64 (-.f64 (+.f64 (*.f64 (*.f64 #s(literal 3 binary64) x1) x1) (*.f64 #s(literal 2 binary64) x2)) x1) (+.f64 (*.f64 x1 x1) #s(literal 1 binary64)))) #s(literal 6 binary64)))) (+.f64 (*.f64 x1 x1) #s(literal 1 binary64))) (*.f64 (*.f64 (*.f64 #s(literal 3 binary64) x1) x1) (/.f64 (-.f64 (+.f64 (*.f64 (*.f64 #s(literal 3 binary64) x1) x1) (*.f64 #s(literal 2 binary64) x2)) x1) (+.f64 (*.f64 x1 x1) #s(literal 1 binary64))))) (*.f64 (*.f64 x1 x1) x1)) x1) (*.f64 #s(literal 3 binary64) (/.f64 (-.f64 (-.f64 (*.f64 (*.f64 #s(literal 3 binary64) x1) x1) (*.f64 #s(literal 2 binary64) x2)) x1) (+.f64 (*.f64 x1 x1) #s(literal 1 binary64)))))) < 2.0000000000000001e161

                          1. Initial program 99.3%

                            \[x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                          2. Add Preprocessing
                          3. Taylor expanded in x1 around 0

                            \[\leadsto x1 + \color{blue}{\left(-6 \cdot x2 + x1 \cdot \left(\left(4 \cdot \left(x2 \cdot \left(2 \cdot x2 - 3\right)\right) + x1 \cdot \left(\left(2 \cdot \left(-2 \cdot x2 + -1 \cdot \left(2 \cdot x2 - 3\right)\right) + \left(3 \cdot \left(3 - -2 \cdot x2\right) + \left(6 \cdot x2 + 8 \cdot x2\right)\right)\right) - 6\right)\right) - 2\right)\right)} \]
                          4. Applied rewrites85.6%

                            \[\leadsto x1 + \color{blue}{\mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(-4, x2, \mathsf{fma}\left(\mathsf{fma}\left(-2, x2, 3\right), 2, \mathsf{fma}\left(\mathsf{fma}\left(2, x2, 3\right), 3, \mathsf{fma}\left(14, x2, -6\right)\right)\right)\right), x1, \mathsf{fma}\left(\mathsf{fma}\left(2, x2, -3\right) \cdot 4, x2, -2\right)\right), x1, -6 \cdot x2\right)} \]
                          5. Taylor expanded in x2 around 0

                            \[\leadsto x1 + \mathsf{fma}\left(9 \cdot x1 - 2, x1, -6 \cdot x2\right) \]
                          6. Step-by-step derivation
                            1. Applied rewrites85.6%

                              \[\leadsto x1 + \mathsf{fma}\left(\mathsf{fma}\left(x1, 9, -2\right), x1, -6 \cdot x2\right) \]
                            2. Step-by-step derivation
                              1. Applied rewrites85.6%

                                \[\leadsto x1 + \mathsf{fma}\left(x2, \color{blue}{-6}, \mathsf{fma}\left(9, x1, -2\right) \cdot x1\right) \]

                              if +inf.0 < (+.f64 x1 (+.f64 (+.f64 (+.f64 (+.f64 (*.f64 (+.f64 (*.f64 (*.f64 (*.f64 #s(literal 2 binary64) x1) (/.f64 (-.f64 (+.f64 (*.f64 (*.f64 #s(literal 3 binary64) x1) x1) (*.f64 #s(literal 2 binary64) x2)) x1) (+.f64 (*.f64 x1 x1) #s(literal 1 binary64)))) (-.f64 (/.f64 (-.f64 (+.f64 (*.f64 (*.f64 #s(literal 3 binary64) x1) x1) (*.f64 #s(literal 2 binary64) x2)) x1) (+.f64 (*.f64 x1 x1) #s(literal 1 binary64))) #s(literal 3 binary64))) (*.f64 (*.f64 x1 x1) (-.f64 (*.f64 #s(literal 4 binary64) (/.f64 (-.f64 (+.f64 (*.f64 (*.f64 #s(literal 3 binary64) x1) x1) (*.f64 #s(literal 2 binary64) x2)) x1) (+.f64 (*.f64 x1 x1) #s(literal 1 binary64)))) #s(literal 6 binary64)))) (+.f64 (*.f64 x1 x1) #s(literal 1 binary64))) (*.f64 (*.f64 (*.f64 #s(literal 3 binary64) x1) x1) (/.f64 (-.f64 (+.f64 (*.f64 (*.f64 #s(literal 3 binary64) x1) x1) (*.f64 #s(literal 2 binary64) x2)) x1) (+.f64 (*.f64 x1 x1) #s(literal 1 binary64))))) (*.f64 (*.f64 x1 x1) x1)) x1) (*.f64 #s(literal 3 binary64) (/.f64 (-.f64 (-.f64 (*.f64 (*.f64 #s(literal 3 binary64) x1) x1) (*.f64 #s(literal 2 binary64) x2)) x1) (+.f64 (*.f64 x1 x1) #s(literal 1 binary64))))))

                              1. Initial program 0.0%

                                \[x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                              2. Add Preprocessing
                              3. Taylor expanded in x1 around 0

                                \[\leadsto x1 + \color{blue}{\left(-6 \cdot x2 + x1 \cdot \left(\left(4 \cdot \left(x2 \cdot \left(2 \cdot x2 - 3\right)\right) + x1 \cdot \left(\left(2 \cdot \left(-2 \cdot x2 + -1 \cdot \left(2 \cdot x2 - 3\right)\right) + \left(3 \cdot \left(3 - -2 \cdot x2\right) + \left(6 \cdot x2 + 8 \cdot x2\right)\right)\right) - 6\right)\right) - 2\right)\right)} \]
                              4. Applied rewrites78.1%

                                \[\leadsto x1 + \color{blue}{\mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(-4, x2, \mathsf{fma}\left(\mathsf{fma}\left(-2, x2, 3\right), 2, \mathsf{fma}\left(\mathsf{fma}\left(2, x2, 3\right), 3, \mathsf{fma}\left(14, x2, -6\right)\right)\right)\right), x1, \mathsf{fma}\left(\mathsf{fma}\left(2, x2, -3\right) \cdot 4, x2, -2\right)\right), x1, -6 \cdot x2\right)} \]
                              5. Taylor expanded in x2 around 0

                                \[\leadsto x1 + x1 \cdot \color{blue}{\left(9 \cdot x1 - 2\right)} \]
                              6. Step-by-step derivation
                                1. Applied rewrites87.0%

                                  \[\leadsto x1 + \mathsf{fma}\left(x1, 9, -2\right) \cdot \color{blue}{x1} \]
                                2. Taylor expanded in x1 around inf

                                  \[\leadsto x1 + 9 \cdot {x1}^{\color{blue}{2}} \]
                                3. Step-by-step derivation
                                  1. Applied rewrites87.0%

                                    \[\leadsto x1 + \left(9 \cdot x1\right) \cdot x1 \]
                                4. Recombined 3 regimes into one program.
                                5. Final simplification81.6%

                                  \[\leadsto \begin{array}{l} \mathbf{if}\;x1 - \left(\left(\left(\left(\frac{\left(x2 \cdot 2 + \left(3 \cdot x1\right) \cdot x1\right) - x1}{-1 - x1 \cdot x1} \cdot \left(\left(3 \cdot x1\right) \cdot x1\right) - \left(-1 - x1 \cdot x1\right) \cdot \left(\left(3 - \frac{\left(x2 \cdot 2 + \left(3 \cdot x1\right) \cdot x1\right) - x1}{x1 \cdot x1 - -1}\right) \cdot \left(\left(2 \cdot x1\right) \cdot \frac{\left(x2 \cdot 2 + \left(3 \cdot x1\right) \cdot x1\right) - x1}{x1 \cdot x1 - -1}\right) - \left(4 \cdot \frac{\left(x2 \cdot 2 + \left(3 \cdot x1\right) \cdot x1\right) - x1}{x1 \cdot x1 - -1} - 6\right) \cdot \left(x1 \cdot x1\right)\right)\right) - \left(x1 \cdot x1\right) \cdot x1\right) - x1\right) - \frac{\left(\left(3 \cdot x1\right) \cdot x1 - x2 \cdot 2\right) - x1}{x1 \cdot x1 - -1} \cdot 3\right) \leq -5 \cdot 10^{+85}:\\ \;\;\;\;\mathsf{fma}\left(8 \cdot x1, x2, -6\right) \cdot x2 + x1\\ \mathbf{elif}\;x1 - \left(\left(\left(\left(\frac{\left(x2 \cdot 2 + \left(3 \cdot x1\right) \cdot x1\right) - x1}{-1 - x1 \cdot x1} \cdot \left(\left(3 \cdot x1\right) \cdot x1\right) - \left(-1 - x1 \cdot x1\right) \cdot \left(\left(3 - \frac{\left(x2 \cdot 2 + \left(3 \cdot x1\right) \cdot x1\right) - x1}{x1 \cdot x1 - -1}\right) \cdot \left(\left(2 \cdot x1\right) \cdot \frac{\left(x2 \cdot 2 + \left(3 \cdot x1\right) \cdot x1\right) - x1}{x1 \cdot x1 - -1}\right) - \left(4 \cdot \frac{\left(x2 \cdot 2 + \left(3 \cdot x1\right) \cdot x1\right) - x1}{x1 \cdot x1 - -1} - 6\right) \cdot \left(x1 \cdot x1\right)\right)\right) - \left(x1 \cdot x1\right) \cdot x1\right) - x1\right) - \frac{\left(\left(3 \cdot x1\right) \cdot x1 - x2 \cdot 2\right) - x1}{x1 \cdot x1 - -1} \cdot 3\right) \leq 2 \cdot 10^{+161}:\\ \;\;\;\;\mathsf{fma}\left(x2, -6, \mathsf{fma}\left(9, x1, -2\right) \cdot x1\right) + x1\\ \mathbf{elif}\;x1 - \left(\left(\left(\left(\frac{\left(x2 \cdot 2 + \left(3 \cdot x1\right) \cdot x1\right) - x1}{-1 - x1 \cdot x1} \cdot \left(\left(3 \cdot x1\right) \cdot x1\right) - \left(-1 - x1 \cdot x1\right) \cdot \left(\left(3 - \frac{\left(x2 \cdot 2 + \left(3 \cdot x1\right) \cdot x1\right) - x1}{x1 \cdot x1 - -1}\right) \cdot \left(\left(2 \cdot x1\right) \cdot \frac{\left(x2 \cdot 2 + \left(3 \cdot x1\right) \cdot x1\right) - x1}{x1 \cdot x1 - -1}\right) - \left(4 \cdot \frac{\left(x2 \cdot 2 + \left(3 \cdot x1\right) \cdot x1\right) - x1}{x1 \cdot x1 - -1} - 6\right) \cdot \left(x1 \cdot x1\right)\right)\right) - \left(x1 \cdot x1\right) \cdot x1\right) - x1\right) - \frac{\left(\left(3 \cdot x1\right) \cdot x1 - x2 \cdot 2\right) - x1}{x1 \cdot x1 - -1} \cdot 3\right) \leq \infty:\\ \;\;\;\;\mathsf{fma}\left(8 \cdot x1, x2, -6\right) \cdot x2 + x1\\ \mathbf{else}:\\ \;\;\;\;\left(9 \cdot x1\right) \cdot x1 + x1\\ \end{array} \]
                                6. Add Preprocessing

                                Alternative 4: 84.5% accurate, 0.5× speedup?

                                \[\begin{array}{l} \\ \begin{array}{l} t_0 := \left(3 \cdot x1\right) \cdot x1\\ t_1 := -1 - x1 \cdot x1\\ t_2 := \left(x2 \cdot 2 + t\_0\right) - x1\\ t_3 := x1 \cdot x1 - -1\\ t_4 := \frac{t\_2}{t\_3}\\ t_5 := x1 - \left(\left(\left(\left(\frac{t\_2}{t\_1} \cdot t\_0 - t\_1 \cdot \left(\left(3 - t\_4\right) \cdot \left(\left(2 \cdot x1\right) \cdot t\_4\right) - \left(4 \cdot t\_4 - 6\right) \cdot \left(x1 \cdot x1\right)\right)\right) - \left(x1 \cdot x1\right) \cdot x1\right) - x1\right) - \frac{\left(t\_0 - x2 \cdot 2\right) - x1}{t\_3} \cdot 3\right)\\ \mathbf{if}\;t\_5 \leq -1 \cdot 10^{+88}:\\ \;\;\;\;\mathsf{fma}\left(8 \cdot x1, x2, -6\right) \cdot x2 + x1\\ \mathbf{elif}\;t\_5 \leq 10^{+141}:\\ \;\;\;\;\mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(-19, x1, 9\right), x1, -1\right), x1, -6 \cdot x2\right)\\ \mathbf{else}:\\ \;\;\;\;\left(\left(6 \cdot x1\right) \cdot x1\right) \cdot \left(x1 \cdot x1\right) + x1\\ \end{array} \end{array} \]
                                (FPCore (x1 x2)
                                 :precision binary64
                                 (let* ((t_0 (* (* 3.0 x1) x1))
                                        (t_1 (- -1.0 (* x1 x1)))
                                        (t_2 (- (+ (* x2 2.0) t_0) x1))
                                        (t_3 (- (* x1 x1) -1.0))
                                        (t_4 (/ t_2 t_3))
                                        (t_5
                                         (-
                                          x1
                                          (-
                                           (-
                                            (-
                                             (-
                                              (* (/ t_2 t_1) t_0)
                                              (*
                                               t_1
                                               (-
                                                (* (- 3.0 t_4) (* (* 2.0 x1) t_4))
                                                (* (- (* 4.0 t_4) 6.0) (* x1 x1)))))
                                             (* (* x1 x1) x1))
                                            x1)
                                           (* (/ (- (- t_0 (* x2 2.0)) x1) t_3) 3.0)))))
                                   (if (<= t_5 -1e+88)
                                     (+ (* (fma (* 8.0 x1) x2 -6.0) x2) x1)
                                     (if (<= t_5 1e+141)
                                       (fma (fma (fma -19.0 x1 9.0) x1 -1.0) x1 (* -6.0 x2))
                                       (+ (* (* (* 6.0 x1) x1) (* x1 x1)) x1)))))
                                double code(double x1, double x2) {
                                	double t_0 = (3.0 * x1) * x1;
                                	double t_1 = -1.0 - (x1 * x1);
                                	double t_2 = ((x2 * 2.0) + t_0) - x1;
                                	double t_3 = (x1 * x1) - -1.0;
                                	double t_4 = t_2 / t_3;
                                	double t_5 = x1 - ((((((t_2 / t_1) * t_0) - (t_1 * (((3.0 - t_4) * ((2.0 * x1) * t_4)) - (((4.0 * t_4) - 6.0) * (x1 * x1))))) - ((x1 * x1) * x1)) - x1) - ((((t_0 - (x2 * 2.0)) - x1) / t_3) * 3.0));
                                	double tmp;
                                	if (t_5 <= -1e+88) {
                                		tmp = (fma((8.0 * x1), x2, -6.0) * x2) + x1;
                                	} else if (t_5 <= 1e+141) {
                                		tmp = fma(fma(fma(-19.0, x1, 9.0), x1, -1.0), x1, (-6.0 * x2));
                                	} else {
                                		tmp = (((6.0 * x1) * x1) * (x1 * x1)) + x1;
                                	}
                                	return tmp;
                                }
                                
                                function code(x1, x2)
                                	t_0 = Float64(Float64(3.0 * x1) * x1)
                                	t_1 = Float64(-1.0 - Float64(x1 * x1))
                                	t_2 = Float64(Float64(Float64(x2 * 2.0) + t_0) - x1)
                                	t_3 = Float64(Float64(x1 * x1) - -1.0)
                                	t_4 = Float64(t_2 / t_3)
                                	t_5 = Float64(x1 - Float64(Float64(Float64(Float64(Float64(Float64(t_2 / t_1) * t_0) - Float64(t_1 * Float64(Float64(Float64(3.0 - t_4) * Float64(Float64(2.0 * x1) * t_4)) - Float64(Float64(Float64(4.0 * t_4) - 6.0) * Float64(x1 * x1))))) - Float64(Float64(x1 * x1) * x1)) - x1) - Float64(Float64(Float64(Float64(t_0 - Float64(x2 * 2.0)) - x1) / t_3) * 3.0)))
                                	tmp = 0.0
                                	if (t_5 <= -1e+88)
                                		tmp = Float64(Float64(fma(Float64(8.0 * x1), x2, -6.0) * x2) + x1);
                                	elseif (t_5 <= 1e+141)
                                		tmp = fma(fma(fma(-19.0, x1, 9.0), x1, -1.0), x1, Float64(-6.0 * x2));
                                	else
                                		tmp = Float64(Float64(Float64(Float64(6.0 * x1) * x1) * Float64(x1 * x1)) + x1);
                                	end
                                	return tmp
                                end
                                
                                code[x1_, x2_] := Block[{t$95$0 = N[(N[(3.0 * x1), $MachinePrecision] * x1), $MachinePrecision]}, Block[{t$95$1 = N[(-1.0 - N[(x1 * x1), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$2 = N[(N[(N[(x2 * 2.0), $MachinePrecision] + t$95$0), $MachinePrecision] - x1), $MachinePrecision]}, Block[{t$95$3 = N[(N[(x1 * x1), $MachinePrecision] - -1.0), $MachinePrecision]}, Block[{t$95$4 = N[(t$95$2 / t$95$3), $MachinePrecision]}, Block[{t$95$5 = N[(x1 - N[(N[(N[(N[(N[(N[(t$95$2 / t$95$1), $MachinePrecision] * t$95$0), $MachinePrecision] - N[(t$95$1 * N[(N[(N[(3.0 - t$95$4), $MachinePrecision] * N[(N[(2.0 * x1), $MachinePrecision] * t$95$4), $MachinePrecision]), $MachinePrecision] - N[(N[(N[(4.0 * t$95$4), $MachinePrecision] - 6.0), $MachinePrecision] * N[(x1 * x1), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] - N[(N[(x1 * x1), $MachinePrecision] * x1), $MachinePrecision]), $MachinePrecision] - x1), $MachinePrecision] - N[(N[(N[(N[(t$95$0 - N[(x2 * 2.0), $MachinePrecision]), $MachinePrecision] - x1), $MachinePrecision] / t$95$3), $MachinePrecision] * 3.0), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[t$95$5, -1e+88], N[(N[(N[(N[(8.0 * x1), $MachinePrecision] * x2 + -6.0), $MachinePrecision] * x2), $MachinePrecision] + x1), $MachinePrecision], If[LessEqual[t$95$5, 1e+141], N[(N[(N[(-19.0 * x1 + 9.0), $MachinePrecision] * x1 + -1.0), $MachinePrecision] * x1 + N[(-6.0 * x2), $MachinePrecision]), $MachinePrecision], N[(N[(N[(N[(6.0 * x1), $MachinePrecision] * x1), $MachinePrecision] * N[(x1 * x1), $MachinePrecision]), $MachinePrecision] + x1), $MachinePrecision]]]]]]]]]
                                
                                \begin{array}{l}
                                
                                \\
                                \begin{array}{l}
                                t_0 := \left(3 \cdot x1\right) \cdot x1\\
                                t_1 := -1 - x1 \cdot x1\\
                                t_2 := \left(x2 \cdot 2 + t\_0\right) - x1\\
                                t_3 := x1 \cdot x1 - -1\\
                                t_4 := \frac{t\_2}{t\_3}\\
                                t_5 := x1 - \left(\left(\left(\left(\frac{t\_2}{t\_1} \cdot t\_0 - t\_1 \cdot \left(\left(3 - t\_4\right) \cdot \left(\left(2 \cdot x1\right) \cdot t\_4\right) - \left(4 \cdot t\_4 - 6\right) \cdot \left(x1 \cdot x1\right)\right)\right) - \left(x1 \cdot x1\right) \cdot x1\right) - x1\right) - \frac{\left(t\_0 - x2 \cdot 2\right) - x1}{t\_3} \cdot 3\right)\\
                                \mathbf{if}\;t\_5 \leq -1 \cdot 10^{+88}:\\
                                \;\;\;\;\mathsf{fma}\left(8 \cdot x1, x2, -6\right) \cdot x2 + x1\\
                                
                                \mathbf{elif}\;t\_5 \leq 10^{+141}:\\
                                \;\;\;\;\mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(-19, x1, 9\right), x1, -1\right), x1, -6 \cdot x2\right)\\
                                
                                \mathbf{else}:\\
                                \;\;\;\;\left(\left(6 \cdot x1\right) \cdot x1\right) \cdot \left(x1 \cdot x1\right) + x1\\
                                
                                
                                \end{array}
                                \end{array}
                                
                                Derivation
                                1. Split input into 3 regimes
                                2. if (+.f64 x1 (+.f64 (+.f64 (+.f64 (+.f64 (*.f64 (+.f64 (*.f64 (*.f64 (*.f64 #s(literal 2 binary64) x1) (/.f64 (-.f64 (+.f64 (*.f64 (*.f64 #s(literal 3 binary64) x1) x1) (*.f64 #s(literal 2 binary64) x2)) x1) (+.f64 (*.f64 x1 x1) #s(literal 1 binary64)))) (-.f64 (/.f64 (-.f64 (+.f64 (*.f64 (*.f64 #s(literal 3 binary64) x1) x1) (*.f64 #s(literal 2 binary64) x2)) x1) (+.f64 (*.f64 x1 x1) #s(literal 1 binary64))) #s(literal 3 binary64))) (*.f64 (*.f64 x1 x1) (-.f64 (*.f64 #s(literal 4 binary64) (/.f64 (-.f64 (+.f64 (*.f64 (*.f64 #s(literal 3 binary64) x1) x1) (*.f64 #s(literal 2 binary64) x2)) x1) (+.f64 (*.f64 x1 x1) #s(literal 1 binary64)))) #s(literal 6 binary64)))) (+.f64 (*.f64 x1 x1) #s(literal 1 binary64))) (*.f64 (*.f64 (*.f64 #s(literal 3 binary64) x1) x1) (/.f64 (-.f64 (+.f64 (*.f64 (*.f64 #s(literal 3 binary64) x1) x1) (*.f64 #s(literal 2 binary64) x2)) x1) (+.f64 (*.f64 x1 x1) #s(literal 1 binary64))))) (*.f64 (*.f64 x1 x1) x1)) x1) (*.f64 #s(literal 3 binary64) (/.f64 (-.f64 (-.f64 (*.f64 (*.f64 #s(literal 3 binary64) x1) x1) (*.f64 #s(literal 2 binary64) x2)) x1) (+.f64 (*.f64 x1 x1) #s(literal 1 binary64)))))) < -9.99999999999999959e87

                                  1. Initial program 99.8%

                                    \[x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                                  2. Add Preprocessing
                                  3. Taylor expanded in x1 around 0

                                    \[\leadsto x1 + \color{blue}{\left(-6 \cdot x2 + x1 \cdot \left(\left(4 \cdot \left(x2 \cdot \left(2 \cdot x2 - 3\right)\right) + x1 \cdot \left(\left(2 \cdot \left(-2 \cdot x2 + -1 \cdot \left(2 \cdot x2 - 3\right)\right) + \left(3 \cdot \left(3 - -2 \cdot x2\right) + \left(6 \cdot x2 + 8 \cdot x2\right)\right)\right) - 6\right)\right) - 2\right)\right)} \]
                                  4. Applied rewrites68.3%

                                    \[\leadsto x1 + \color{blue}{\mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(-4, x2, \mathsf{fma}\left(\mathsf{fma}\left(-2, x2, 3\right), 2, \mathsf{fma}\left(\mathsf{fma}\left(2, x2, 3\right), 3, \mathsf{fma}\left(14, x2, -6\right)\right)\right)\right), x1, \mathsf{fma}\left(\mathsf{fma}\left(2, x2, -3\right) \cdot 4, x2, -2\right)\right), x1, -6 \cdot x2\right)} \]
                                  5. Taylor expanded in x2 around -inf

                                    \[\leadsto x1 + {x2}^{2} \cdot \color{blue}{\left(-1 \cdot \frac{6 + x1 \cdot \left(12 + -12 \cdot x1\right)}{x2} + 8 \cdot x1\right)} \]
                                  6. Step-by-step derivation
                                    1. Applied rewrites68.5%

                                      \[\leadsto x1 + \mathsf{fma}\left(x1, 8, \frac{\mathsf{fma}\left(\mathsf{fma}\left(x1, -12, 12\right), x1, 6\right)}{-x2}\right) \cdot \color{blue}{\left(x2 \cdot x2\right)} \]
                                    2. Taylor expanded in x2 around 0

                                      \[\leadsto x1 + x2 \cdot \left(-1 \cdot \left(6 + x1 \cdot \left(12 + -12 \cdot x1\right)\right) + \color{blue}{8 \cdot \left(x1 \cdot x2\right)}\right) \]
                                    3. Step-by-step derivation
                                      1. Applied rewrites94.8%

                                        \[\leadsto x1 + \mathsf{fma}\left(x1 \cdot 8, x2, -\mathsf{fma}\left(\mathsf{fma}\left(x1, -12, 12\right), x1, 6\right)\right) \cdot x2 \]
                                      2. Taylor expanded in x1 around 0

                                        \[\leadsto x1 + \mathsf{fma}\left(x1 \cdot 8, x2, -6\right) \cdot x2 \]
                                      3. Step-by-step derivation
                                        1. Applied rewrites94.8%

                                          \[\leadsto x1 + \mathsf{fma}\left(x1 \cdot 8, x2, -6\right) \cdot x2 \]

                                        if -9.99999999999999959e87 < (+.f64 x1 (+.f64 (+.f64 (+.f64 (+.f64 (*.f64 (+.f64 (*.f64 (*.f64 (*.f64 #s(literal 2 binary64) x1) (/.f64 (-.f64 (+.f64 (*.f64 (*.f64 #s(literal 3 binary64) x1) x1) (*.f64 #s(literal 2 binary64) x2)) x1) (+.f64 (*.f64 x1 x1) #s(literal 1 binary64)))) (-.f64 (/.f64 (-.f64 (+.f64 (*.f64 (*.f64 #s(literal 3 binary64) x1) x1) (*.f64 #s(literal 2 binary64) x2)) x1) (+.f64 (*.f64 x1 x1) #s(literal 1 binary64))) #s(literal 3 binary64))) (*.f64 (*.f64 x1 x1) (-.f64 (*.f64 #s(literal 4 binary64) (/.f64 (-.f64 (+.f64 (*.f64 (*.f64 #s(literal 3 binary64) x1) x1) (*.f64 #s(literal 2 binary64) x2)) x1) (+.f64 (*.f64 x1 x1) #s(literal 1 binary64)))) #s(literal 6 binary64)))) (+.f64 (*.f64 x1 x1) #s(literal 1 binary64))) (*.f64 (*.f64 (*.f64 #s(literal 3 binary64) x1) x1) (/.f64 (-.f64 (+.f64 (*.f64 (*.f64 #s(literal 3 binary64) x1) x1) (*.f64 #s(literal 2 binary64) x2)) x1) (+.f64 (*.f64 x1 x1) #s(literal 1 binary64))))) (*.f64 (*.f64 x1 x1) x1)) x1) (*.f64 #s(literal 3 binary64) (/.f64 (-.f64 (-.f64 (*.f64 (*.f64 #s(literal 3 binary64) x1) x1) (*.f64 #s(literal 2 binary64) x2)) x1) (+.f64 (*.f64 x1 x1) #s(literal 1 binary64)))))) < 1.00000000000000002e141

                                        1. Initial program 99.3%

                                          \[x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                                        2. Add Preprocessing
                                        3. Taylor expanded in x1 around 0

                                          \[\leadsto x1 + \color{blue}{-6 \cdot x2} \]
                                        4. Step-by-step derivation
                                          1. lower-*.f6462.8

                                            \[\leadsto x1 + \color{blue}{-6 \cdot x2} \]
                                        5. Applied rewrites62.8%

                                          \[\leadsto x1 + \color{blue}{-6 \cdot x2} \]
                                        6. Taylor expanded in x1 around 0

                                          \[\leadsto \color{blue}{-6 \cdot x2 + x1 \cdot \left(\left(4 \cdot \left(x2 \cdot \left(2 \cdot x2 - 3\right)\right) + x1 \cdot \left(\left(2 \cdot \left(-2 \cdot x2 + -1 \cdot \left(2 \cdot x2 - 3\right)\right) + \left(3 \cdot \left(3 - -2 \cdot x2\right) + \left(6 \cdot x2 + \left(8 \cdot x2 + x1 \cdot \left(\left(2 \cdot \left(\left(1 + \left(2 \cdot \left(x2 \cdot \left(3 + -2 \cdot x2\right)\right) + 3 \cdot \left(2 \cdot x2 - 3\right)\right)\right) - 2 \cdot \left(x2 \cdot \left(2 \cdot x2 - 3\right)\right)\right) + 4 \cdot \left(x2 \cdot \left(2 \cdot x2 - 3\right)\right)\right) - 3\right)\right)\right)\right)\right) - 6\right)\right) - 1\right)} \]
                                        7. Applied rewrites89.1%

                                          \[\leadsto \color{blue}{\mathsf{fma}\left(\mathsf{fma}\left(\left(\mathsf{fma}\left(14, x2, \mathsf{fma}\left(\mathsf{fma}\left(\left(1 + \mathsf{fma}\left(-4, x2, 6\right) \cdot x2\right) + \mathsf{fma}\left(\mathsf{fma}\left(-4, x2, 6\right), x2, \mathsf{fma}\left(6, x2, -9\right)\right), 2, \mathsf{fma}\left(\mathsf{fma}\left(2, x2, -3\right) \cdot 4, x2, -3\right)\right), x1, \mathsf{fma}\left(6, x2, 9\right)\right)\right) + \mathsf{fma}\left(-4, x2, \mathsf{fma}\left(-4, x2, 6\right)\right)\right) - 6, x1, \mathsf{fma}\left(\mathsf{fma}\left(2, x2, -3\right) \cdot x2, 4, -1\right)\right), x1, -6 \cdot x2\right)} \]
                                        8. Taylor expanded in x2 around 0

                                          \[\leadsto \mathsf{fma}\left(x1 \cdot \left(9 + -19 \cdot x1\right) - 1, x1, -6 \cdot x2\right) \]
                                        9. Step-by-step derivation
                                          1. Applied rewrites88.9%

                                            \[\leadsto \mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(-19, x1, 9\right), x1, -1\right), x1, -6 \cdot x2\right) \]

                                          if 1.00000000000000002e141 < (+.f64 x1 (+.f64 (+.f64 (+.f64 (+.f64 (*.f64 (+.f64 (*.f64 (*.f64 (*.f64 #s(literal 2 binary64) x1) (/.f64 (-.f64 (+.f64 (*.f64 (*.f64 #s(literal 3 binary64) x1) x1) (*.f64 #s(literal 2 binary64) x2)) x1) (+.f64 (*.f64 x1 x1) #s(literal 1 binary64)))) (-.f64 (/.f64 (-.f64 (+.f64 (*.f64 (*.f64 #s(literal 3 binary64) x1) x1) (*.f64 #s(literal 2 binary64) x2)) x1) (+.f64 (*.f64 x1 x1) #s(literal 1 binary64))) #s(literal 3 binary64))) (*.f64 (*.f64 x1 x1) (-.f64 (*.f64 #s(literal 4 binary64) (/.f64 (-.f64 (+.f64 (*.f64 (*.f64 #s(literal 3 binary64) x1) x1) (*.f64 #s(literal 2 binary64) x2)) x1) (+.f64 (*.f64 x1 x1) #s(literal 1 binary64)))) #s(literal 6 binary64)))) (+.f64 (*.f64 x1 x1) #s(literal 1 binary64))) (*.f64 (*.f64 (*.f64 #s(literal 3 binary64) x1) x1) (/.f64 (-.f64 (+.f64 (*.f64 (*.f64 #s(literal 3 binary64) x1) x1) (*.f64 #s(literal 2 binary64) x2)) x1) (+.f64 (*.f64 x1 x1) #s(literal 1 binary64))))) (*.f64 (*.f64 x1 x1) x1)) x1) (*.f64 #s(literal 3 binary64) (/.f64 (-.f64 (-.f64 (*.f64 (*.f64 #s(literal 3 binary64) x1) x1) (*.f64 #s(literal 2 binary64) x2)) x1) (+.f64 (*.f64 x1 x1) #s(literal 1 binary64))))))

                                          1. Initial program 34.5%

                                            \[x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                                          2. Add Preprocessing
                                          3. Taylor expanded in x1 around inf

                                            \[\leadsto x1 + \color{blue}{6 \cdot {x1}^{4}} \]
                                          4. Step-by-step derivation
                                            1. *-commutativeN/A

                                              \[\leadsto x1 + \color{blue}{{x1}^{4} \cdot 6} \]
                                            2. lower-*.f64N/A

                                              \[\leadsto x1 + \color{blue}{{x1}^{4} \cdot 6} \]
                                            3. lower-pow.f6485.4

                                              \[\leadsto x1 + \color{blue}{{x1}^{4}} \cdot 6 \]
                                          5. Applied rewrites85.4%

                                            \[\leadsto x1 + \color{blue}{{x1}^{4} \cdot 6} \]
                                          6. Step-by-step derivation
                                            1. Applied rewrites85.4%

                                              \[\leadsto x1 + \left(\left(\left(x1 \cdot x1\right) \cdot x1\right) \cdot x1\right) \cdot \color{blue}{6} \]
                                            2. Step-by-step derivation
                                              1. Applied rewrites85.4%

                                                \[\leadsto x1 + \left(x1 \cdot x1\right) \cdot \color{blue}{\left(x1 \cdot \left(6 \cdot x1\right)\right)} \]
                                            3. Recombined 3 regimes into one program.
                                            4. Final simplification88.1%

                                              \[\leadsto \begin{array}{l} \mathbf{if}\;x1 - \left(\left(\left(\left(\frac{\left(x2 \cdot 2 + \left(3 \cdot x1\right) \cdot x1\right) - x1}{-1 - x1 \cdot x1} \cdot \left(\left(3 \cdot x1\right) \cdot x1\right) - \left(-1 - x1 \cdot x1\right) \cdot \left(\left(3 - \frac{\left(x2 \cdot 2 + \left(3 \cdot x1\right) \cdot x1\right) - x1}{x1 \cdot x1 - -1}\right) \cdot \left(\left(2 \cdot x1\right) \cdot \frac{\left(x2 \cdot 2 + \left(3 \cdot x1\right) \cdot x1\right) - x1}{x1 \cdot x1 - -1}\right) - \left(4 \cdot \frac{\left(x2 \cdot 2 + \left(3 \cdot x1\right) \cdot x1\right) - x1}{x1 \cdot x1 - -1} - 6\right) \cdot \left(x1 \cdot x1\right)\right)\right) - \left(x1 \cdot x1\right) \cdot x1\right) - x1\right) - \frac{\left(\left(3 \cdot x1\right) \cdot x1 - x2 \cdot 2\right) - x1}{x1 \cdot x1 - -1} \cdot 3\right) \leq -1 \cdot 10^{+88}:\\ \;\;\;\;\mathsf{fma}\left(8 \cdot x1, x2, -6\right) \cdot x2 + x1\\ \mathbf{elif}\;x1 - \left(\left(\left(\left(\frac{\left(x2 \cdot 2 + \left(3 \cdot x1\right) \cdot x1\right) - x1}{-1 - x1 \cdot x1} \cdot \left(\left(3 \cdot x1\right) \cdot x1\right) - \left(-1 - x1 \cdot x1\right) \cdot \left(\left(3 - \frac{\left(x2 \cdot 2 + \left(3 \cdot x1\right) \cdot x1\right) - x1}{x1 \cdot x1 - -1}\right) \cdot \left(\left(2 \cdot x1\right) \cdot \frac{\left(x2 \cdot 2 + \left(3 \cdot x1\right) \cdot x1\right) - x1}{x1 \cdot x1 - -1}\right) - \left(4 \cdot \frac{\left(x2 \cdot 2 + \left(3 \cdot x1\right) \cdot x1\right) - x1}{x1 \cdot x1 - -1} - 6\right) \cdot \left(x1 \cdot x1\right)\right)\right) - \left(x1 \cdot x1\right) \cdot x1\right) - x1\right) - \frac{\left(\left(3 \cdot x1\right) \cdot x1 - x2 \cdot 2\right) - x1}{x1 \cdot x1 - -1} \cdot 3\right) \leq 10^{+141}:\\ \;\;\;\;\mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(-19, x1, 9\right), x1, -1\right), x1, -6 \cdot x2\right)\\ \mathbf{else}:\\ \;\;\;\;\left(\left(6 \cdot x1\right) \cdot x1\right) \cdot \left(x1 \cdot x1\right) + x1\\ \end{array} \]
                                            5. Add Preprocessing

                                            Alternative 5: 97.3% accurate, 1.1× speedup?

                                            \[\begin{array}{l} \\ \begin{array}{l} t_0 := \left(3 \cdot x1\right) \cdot x1\\ t_1 := \frac{\left(x2 \cdot 2 + t\_0\right) - x1}{x1 \cdot x1 - -1}\\ \mathbf{if}\;x1 \leq -53000000000:\\ \;\;\;\;{x1}^{4} \cdot \left(\mathsf{fma}\left(\frac{\mathsf{fma}\left(2, x2, -3\right)}{x1 \cdot x1}, 4, \frac{9}{x1 \cdot x1} + 6\right) - \frac{3}{x1}\right) + x1\\ \mathbf{elif}\;x1 \leq 2.3 \cdot 10^{-6}:\\ \;\;\;\;\mathsf{fma}\left(\mathsf{fma}\left(x2 \cdot x1, 8, \mathsf{fma}\left(\mathsf{fma}\left(x1, 12, -12\right), x1, -6\right)\right), x2, \mathsf{fma}\left(x1, 9, -2\right) \cdot x1\right) + x1\\ \mathbf{elif}\;x1 \leq 6.5 \cdot 10^{+63}:\\ \;\;\;\;\left(3 \cdot 3 - \left(\left(\left(\left(-1 - x1 \cdot x1\right) \cdot \left(\left(4 \cdot t\_1 - 6\right) \cdot \left(x1 \cdot x1\right) + \left(t\_1 - 3\right) \cdot \left(\left(2 \cdot x1\right) \cdot t\_1\right)\right) - \left(3 - \frac{1 - \frac{\mathsf{fma}\left(2, x2, -3\right)}{x1}}{x1}\right) \cdot t\_0\right) - \left(x1 \cdot x1\right) \cdot x1\right) - x1\right)\right) + x1\\ \mathbf{else}:\\ \;\;\;\;\left(\left(6 \cdot x1\right) \cdot x1\right) \cdot \left(x1 \cdot x1\right) + x1\\ \end{array} \end{array} \]
                                            (FPCore (x1 x2)
                                             :precision binary64
                                             (let* ((t_0 (* (* 3.0 x1) x1))
                                                    (t_1 (/ (- (+ (* x2 2.0) t_0) x1) (- (* x1 x1) -1.0))))
                                               (if (<= x1 -53000000000.0)
                                                 (+
                                                  (*
                                                   (pow x1 4.0)
                                                   (-
                                                    (fma (/ (fma 2.0 x2 -3.0) (* x1 x1)) 4.0 (+ (/ 9.0 (* x1 x1)) 6.0))
                                                    (/ 3.0 x1)))
                                                  x1)
                                                 (if (<= x1 2.3e-6)
                                                   (+
                                                    (fma
                                                     (fma (* x2 x1) 8.0 (fma (fma x1 12.0 -12.0) x1 -6.0))
                                                     x2
                                                     (* (fma x1 9.0 -2.0) x1))
                                                    x1)
                                                   (if (<= x1 6.5e+63)
                                                     (+
                                                      (-
                                                       (* 3.0 3.0)
                                                       (-
                                                        (-
                                                         (-
                                                          (*
                                                           (- -1.0 (* x1 x1))
                                                           (+
                                                            (* (- (* 4.0 t_1) 6.0) (* x1 x1))
                                                            (* (- t_1 3.0) (* (* 2.0 x1) t_1))))
                                                          (* (- 3.0 (/ (- 1.0 (/ (fma 2.0 x2 -3.0) x1)) x1)) t_0))
                                                         (* (* x1 x1) x1))
                                                        x1))
                                                      x1)
                                                     (+ (* (* (* 6.0 x1) x1) (* x1 x1)) x1))))))
                                            double code(double x1, double x2) {
                                            	double t_0 = (3.0 * x1) * x1;
                                            	double t_1 = (((x2 * 2.0) + t_0) - x1) / ((x1 * x1) - -1.0);
                                            	double tmp;
                                            	if (x1 <= -53000000000.0) {
                                            		tmp = (pow(x1, 4.0) * (fma((fma(2.0, x2, -3.0) / (x1 * x1)), 4.0, ((9.0 / (x1 * x1)) + 6.0)) - (3.0 / x1))) + x1;
                                            	} else if (x1 <= 2.3e-6) {
                                            		tmp = fma(fma((x2 * x1), 8.0, fma(fma(x1, 12.0, -12.0), x1, -6.0)), x2, (fma(x1, 9.0, -2.0) * x1)) + x1;
                                            	} else if (x1 <= 6.5e+63) {
                                            		tmp = ((3.0 * 3.0) - (((((-1.0 - (x1 * x1)) * ((((4.0 * t_1) - 6.0) * (x1 * x1)) + ((t_1 - 3.0) * ((2.0 * x1) * t_1)))) - ((3.0 - ((1.0 - (fma(2.0, x2, -3.0) / x1)) / x1)) * t_0)) - ((x1 * x1) * x1)) - x1)) + x1;
                                            	} else {
                                            		tmp = (((6.0 * x1) * x1) * (x1 * x1)) + x1;
                                            	}
                                            	return tmp;
                                            }
                                            
                                            function code(x1, x2)
                                            	t_0 = Float64(Float64(3.0 * x1) * x1)
                                            	t_1 = Float64(Float64(Float64(Float64(x2 * 2.0) + t_0) - x1) / Float64(Float64(x1 * x1) - -1.0))
                                            	tmp = 0.0
                                            	if (x1 <= -53000000000.0)
                                            		tmp = Float64(Float64((x1 ^ 4.0) * Float64(fma(Float64(fma(2.0, x2, -3.0) / Float64(x1 * x1)), 4.0, Float64(Float64(9.0 / Float64(x1 * x1)) + 6.0)) - Float64(3.0 / x1))) + x1);
                                            	elseif (x1 <= 2.3e-6)
                                            		tmp = Float64(fma(fma(Float64(x2 * x1), 8.0, fma(fma(x1, 12.0, -12.0), x1, -6.0)), x2, Float64(fma(x1, 9.0, -2.0) * x1)) + x1);
                                            	elseif (x1 <= 6.5e+63)
                                            		tmp = Float64(Float64(Float64(3.0 * 3.0) - Float64(Float64(Float64(Float64(Float64(-1.0 - Float64(x1 * x1)) * Float64(Float64(Float64(Float64(4.0 * t_1) - 6.0) * Float64(x1 * x1)) + Float64(Float64(t_1 - 3.0) * Float64(Float64(2.0 * x1) * t_1)))) - Float64(Float64(3.0 - Float64(Float64(1.0 - Float64(fma(2.0, x2, -3.0) / x1)) / x1)) * t_0)) - Float64(Float64(x1 * x1) * x1)) - x1)) + x1);
                                            	else
                                            		tmp = Float64(Float64(Float64(Float64(6.0 * x1) * x1) * Float64(x1 * x1)) + x1);
                                            	end
                                            	return tmp
                                            end
                                            
                                            code[x1_, x2_] := Block[{t$95$0 = N[(N[(3.0 * x1), $MachinePrecision] * x1), $MachinePrecision]}, Block[{t$95$1 = N[(N[(N[(N[(x2 * 2.0), $MachinePrecision] + t$95$0), $MachinePrecision] - x1), $MachinePrecision] / N[(N[(x1 * x1), $MachinePrecision] - -1.0), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[x1, -53000000000.0], N[(N[(N[Power[x1, 4.0], $MachinePrecision] * N[(N[(N[(N[(2.0 * x2 + -3.0), $MachinePrecision] / N[(x1 * x1), $MachinePrecision]), $MachinePrecision] * 4.0 + N[(N[(9.0 / N[(x1 * x1), $MachinePrecision]), $MachinePrecision] + 6.0), $MachinePrecision]), $MachinePrecision] - N[(3.0 / x1), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] + x1), $MachinePrecision], If[LessEqual[x1, 2.3e-6], N[(N[(N[(N[(x2 * x1), $MachinePrecision] * 8.0 + N[(N[(x1 * 12.0 + -12.0), $MachinePrecision] * x1 + -6.0), $MachinePrecision]), $MachinePrecision] * x2 + N[(N[(x1 * 9.0 + -2.0), $MachinePrecision] * x1), $MachinePrecision]), $MachinePrecision] + x1), $MachinePrecision], If[LessEqual[x1, 6.5e+63], N[(N[(N[(3.0 * 3.0), $MachinePrecision] - N[(N[(N[(N[(N[(-1.0 - N[(x1 * x1), $MachinePrecision]), $MachinePrecision] * N[(N[(N[(N[(4.0 * t$95$1), $MachinePrecision] - 6.0), $MachinePrecision] * N[(x1 * x1), $MachinePrecision]), $MachinePrecision] + N[(N[(t$95$1 - 3.0), $MachinePrecision] * N[(N[(2.0 * x1), $MachinePrecision] * t$95$1), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] - N[(N[(3.0 - N[(N[(1.0 - N[(N[(2.0 * x2 + -3.0), $MachinePrecision] / x1), $MachinePrecision]), $MachinePrecision] / x1), $MachinePrecision]), $MachinePrecision] * t$95$0), $MachinePrecision]), $MachinePrecision] - N[(N[(x1 * x1), $MachinePrecision] * x1), $MachinePrecision]), $MachinePrecision] - x1), $MachinePrecision]), $MachinePrecision] + x1), $MachinePrecision], N[(N[(N[(N[(6.0 * x1), $MachinePrecision] * x1), $MachinePrecision] * N[(x1 * x1), $MachinePrecision]), $MachinePrecision] + x1), $MachinePrecision]]]]]]
                                            
                                            \begin{array}{l}
                                            
                                            \\
                                            \begin{array}{l}
                                            t_0 := \left(3 \cdot x1\right) \cdot x1\\
                                            t_1 := \frac{\left(x2 \cdot 2 + t\_0\right) - x1}{x1 \cdot x1 - -1}\\
                                            \mathbf{if}\;x1 \leq -53000000000:\\
                                            \;\;\;\;{x1}^{4} \cdot \left(\mathsf{fma}\left(\frac{\mathsf{fma}\left(2, x2, -3\right)}{x1 \cdot x1}, 4, \frac{9}{x1 \cdot x1} + 6\right) - \frac{3}{x1}\right) + x1\\
                                            
                                            \mathbf{elif}\;x1 \leq 2.3 \cdot 10^{-6}:\\
                                            \;\;\;\;\mathsf{fma}\left(\mathsf{fma}\left(x2 \cdot x1, 8, \mathsf{fma}\left(\mathsf{fma}\left(x1, 12, -12\right), x1, -6\right)\right), x2, \mathsf{fma}\left(x1, 9, -2\right) \cdot x1\right) + x1\\
                                            
                                            \mathbf{elif}\;x1 \leq 6.5 \cdot 10^{+63}:\\
                                            \;\;\;\;\left(3 \cdot 3 - \left(\left(\left(\left(-1 - x1 \cdot x1\right) \cdot \left(\left(4 \cdot t\_1 - 6\right) \cdot \left(x1 \cdot x1\right) + \left(t\_1 - 3\right) \cdot \left(\left(2 \cdot x1\right) \cdot t\_1\right)\right) - \left(3 - \frac{1 - \frac{\mathsf{fma}\left(2, x2, -3\right)}{x1}}{x1}\right) \cdot t\_0\right) - \left(x1 \cdot x1\right) \cdot x1\right) - x1\right)\right) + x1\\
                                            
                                            \mathbf{else}:\\
                                            \;\;\;\;\left(\left(6 \cdot x1\right) \cdot x1\right) \cdot \left(x1 \cdot x1\right) + x1\\
                                            
                                            
                                            \end{array}
                                            \end{array}
                                            
                                            Derivation
                                            1. Split input into 4 regimes
                                            2. if x1 < -5.3e10

                                              1. Initial program 28.0%

                                                \[x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                                              2. Add Preprocessing
                                              3. Taylor expanded in x1 around inf

                                                \[\leadsto x1 + \color{blue}{{x1}^{4} \cdot \left(\left(6 + \left(4 \cdot \frac{2 \cdot x2 - 3}{{x1}^{2}} + \frac{9}{{x1}^{2}}\right)\right) - 3 \cdot \frac{1}{x1}\right)} \]
                                              4. Step-by-step derivation
                                                1. *-commutativeN/A

                                                  \[\leadsto x1 + \color{blue}{\left(\left(6 + \left(4 \cdot \frac{2 \cdot x2 - 3}{{x1}^{2}} + \frac{9}{{x1}^{2}}\right)\right) - 3 \cdot \frac{1}{x1}\right) \cdot {x1}^{4}} \]
                                                2. lower-*.f64N/A

                                                  \[\leadsto x1 + \color{blue}{\left(\left(6 + \left(4 \cdot \frac{2 \cdot x2 - 3}{{x1}^{2}} + \frac{9}{{x1}^{2}}\right)\right) - 3 \cdot \frac{1}{x1}\right) \cdot {x1}^{4}} \]
                                              5. Applied rewrites95.8%

                                                \[\leadsto x1 + \color{blue}{\left(\mathsf{fma}\left(\frac{\mathsf{fma}\left(2, x2, -3\right)}{x1 \cdot x1}, 4, \frac{9}{x1 \cdot x1} + 6\right) - \frac{3}{x1}\right) \cdot {x1}^{4}} \]

                                              if -5.3e10 < x1 < 2.3e-6

                                              1. Initial program 99.6%

                                                \[x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                                              2. Add Preprocessing
                                              3. Taylor expanded in x1 around 0

                                                \[\leadsto x1 + \color{blue}{\left(-6 \cdot x2 + x1 \cdot \left(\left(4 \cdot \left(x2 \cdot \left(2 \cdot x2 - 3\right)\right) + x1 \cdot \left(\left(2 \cdot \left(-2 \cdot x2 + -1 \cdot \left(2 \cdot x2 - 3\right)\right) + \left(3 \cdot \left(3 - -2 \cdot x2\right) + \left(6 \cdot x2 + 8 \cdot x2\right)\right)\right) - 6\right)\right) - 2\right)\right)} \]
                                              4. Applied rewrites87.9%

                                                \[\leadsto x1 + \color{blue}{\mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(-4, x2, \mathsf{fma}\left(\mathsf{fma}\left(-2, x2, 3\right), 2, \mathsf{fma}\left(\mathsf{fma}\left(2, x2, 3\right), 3, \mathsf{fma}\left(14, x2, -6\right)\right)\right)\right), x1, \mathsf{fma}\left(\mathsf{fma}\left(2, x2, -3\right) \cdot 4, x2, -2\right)\right), x1, -6 \cdot x2\right)} \]
                                              5. Taylor expanded in x2 around 0

                                                \[\leadsto x1 + \left(x1 \cdot \left(9 \cdot x1 - 2\right) + \color{blue}{x2 \cdot \left(\left(8 \cdot \left(x1 \cdot x2\right) + x1 \cdot \left(12 \cdot x1 - 12\right)\right) - 6\right)}\right) \]
                                              6. Step-by-step derivation
                                                1. Applied rewrites98.9%

                                                  \[\leadsto x1 + \mathsf{fma}\left(\mathsf{fma}\left(x1 \cdot x2, 8, \mathsf{fma}\left(\mathsf{fma}\left(x1, 12, -12\right), x1, -6\right)\right), \color{blue}{x2}, \mathsf{fma}\left(x1, 9, -2\right) \cdot x1\right) \]

                                                if 2.3e-6 < x1 < 6.49999999999999992e63

                                                1. Initial program 99.2%

                                                  \[x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                                                2. Add Preprocessing
                                                3. Taylor expanded in x1 around inf

                                                  \[\leadsto x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \color{blue}{3}\right) \]
                                                4. Step-by-step derivation
                                                  1. Applied rewrites88.6%

                                                    \[\leadsto x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \color{blue}{3}\right) \]
                                                  2. Taylor expanded in x1 around -inf

                                                    \[\leadsto x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \color{blue}{\left(3 + -1 \cdot \frac{1 + -1 \cdot \frac{2 \cdot x2 - 3}{x1}}{x1}\right)}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot 3\right) \]
                                                  3. Step-by-step derivation
                                                    1. mul-1-negN/A

                                                      \[\leadsto x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \left(3 + \color{blue}{\left(\mathsf{neg}\left(\frac{1 + -1 \cdot \frac{2 \cdot x2 - 3}{x1}}{x1}\right)\right)}\right)\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot 3\right) \]
                                                    2. unsub-negN/A

                                                      \[\leadsto x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \color{blue}{\left(3 - \frac{1 + -1 \cdot \frac{2 \cdot x2 - 3}{x1}}{x1}\right)}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot 3\right) \]
                                                    3. +-commutativeN/A

                                                      \[\leadsto x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \left(3 - \frac{\color{blue}{-1 \cdot \frac{2 \cdot x2 - 3}{x1} + 1}}{x1}\right)\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot 3\right) \]
                                                    4. metadata-evalN/A

                                                      \[\leadsto x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \left(3 - \frac{-1 \cdot \frac{2 \cdot x2 - 3}{x1} + \color{blue}{-1 \cdot -1}}{x1}\right)\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot 3\right) \]
                                                    5. distribute-lft-inN/A

                                                      \[\leadsto x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \left(3 - \frac{\color{blue}{-1 \cdot \left(\frac{2 \cdot x2 - 3}{x1} + -1\right)}}{x1}\right)\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot 3\right) \]
                                                    6. sub-negN/A

                                                      \[\leadsto x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \left(3 - \frac{-1 \cdot \left(\frac{\color{blue}{2 \cdot x2 + \left(\mathsf{neg}\left(3\right)\right)}}{x1} + -1\right)}{x1}\right)\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot 3\right) \]
                                                    7. metadata-evalN/A

                                                      \[\leadsto x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \left(3 - \frac{-1 \cdot \left(\frac{\color{blue}{\left(\mathsf{neg}\left(-2\right)\right)} \cdot x2 + \left(\mathsf{neg}\left(3\right)\right)}{x1} + -1\right)}{x1}\right)\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot 3\right) \]
                                                    8. distribute-lft-neg-inN/A

                                                      \[\leadsto x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \left(3 - \frac{-1 \cdot \left(\frac{\color{blue}{\left(\mathsf{neg}\left(-2 \cdot x2\right)\right)} + \left(\mathsf{neg}\left(3\right)\right)}{x1} + -1\right)}{x1}\right)\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot 3\right) \]
                                                    9. distribute-neg-inN/A

                                                      \[\leadsto x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \left(3 - \frac{-1 \cdot \left(\frac{\color{blue}{\mathsf{neg}\left(\left(-2 \cdot x2 + 3\right)\right)}}{x1} + -1\right)}{x1}\right)\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot 3\right) \]
                                                    10. +-commutativeN/A

                                                      \[\leadsto x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \left(3 - \frac{-1 \cdot \left(\frac{\mathsf{neg}\left(\color{blue}{\left(3 + -2 \cdot x2\right)}\right)}{x1} + -1\right)}{x1}\right)\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot 3\right) \]
                                                    11. distribute-frac-negN/A

                                                      \[\leadsto x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \left(3 - \frac{-1 \cdot \left(\color{blue}{\left(\mathsf{neg}\left(\frac{3 + -2 \cdot x2}{x1}\right)\right)} + -1\right)}{x1}\right)\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot 3\right) \]
                                                    12. mul-1-negN/A

                                                      \[\leadsto x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \left(3 - \frac{-1 \cdot \left(\color{blue}{-1 \cdot \frac{3 + -2 \cdot x2}{x1}} + -1\right)}{x1}\right)\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot 3\right) \]
                                                    13. metadata-evalN/A

                                                      \[\leadsto x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \left(3 - \frac{-1 \cdot \left(-1 \cdot \frac{3 + -2 \cdot x2}{x1} + \color{blue}{\left(\mathsf{neg}\left(1\right)\right)}\right)}{x1}\right)\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot 3\right) \]
                                                    14. sub-negN/A

                                                      \[\leadsto x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \left(3 - \frac{-1 \cdot \color{blue}{\left(-1 \cdot \frac{3 + -2 \cdot x2}{x1} - 1\right)}}{x1}\right)\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot 3\right) \]
                                                    15. associate-*r/N/A

                                                      \[\leadsto x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \left(3 - \color{blue}{-1 \cdot \frac{-1 \cdot \frac{3 + -2 \cdot x2}{x1} - 1}{x1}}\right)\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot 3\right) \]
                                                  4. Applied rewrites97.9%

                                                    \[\leadsto x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \color{blue}{\left(3 - \frac{1 - \frac{\mathsf{fma}\left(2, x2, -3\right)}{x1}}{x1}\right)}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot 3\right) \]

                                                  if 6.49999999999999992e63 < x1

                                                  1. Initial program 27.7%

                                                    \[x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                                                  2. Add Preprocessing
                                                  3. Taylor expanded in x1 around inf

                                                    \[\leadsto x1 + \color{blue}{6 \cdot {x1}^{4}} \]
                                                  4. Step-by-step derivation
                                                    1. *-commutativeN/A

                                                      \[\leadsto x1 + \color{blue}{{x1}^{4} \cdot 6} \]
                                                    2. lower-*.f64N/A

                                                      \[\leadsto x1 + \color{blue}{{x1}^{4} \cdot 6} \]
                                                    3. lower-pow.f6499.9

                                                      \[\leadsto x1 + \color{blue}{{x1}^{4}} \cdot 6 \]
                                                  5. Applied rewrites99.9%

                                                    \[\leadsto x1 + \color{blue}{{x1}^{4} \cdot 6} \]
                                                  6. Step-by-step derivation
                                                    1. Applied rewrites99.9%

                                                      \[\leadsto x1 + \left(\left(\left(x1 \cdot x1\right) \cdot x1\right) \cdot x1\right) \cdot \color{blue}{6} \]
                                                    2. Step-by-step derivation
                                                      1. Applied rewrites100.0%

                                                        \[\leadsto x1 + \left(x1 \cdot x1\right) \cdot \color{blue}{\left(x1 \cdot \left(6 \cdot x1\right)\right)} \]
                                                    3. Recombined 4 regimes into one program.
                                                    4. Final simplification98.3%

                                                      \[\leadsto \begin{array}{l} \mathbf{if}\;x1 \leq -53000000000:\\ \;\;\;\;{x1}^{4} \cdot \left(\mathsf{fma}\left(\frac{\mathsf{fma}\left(2, x2, -3\right)}{x1 \cdot x1}, 4, \frac{9}{x1 \cdot x1} + 6\right) - \frac{3}{x1}\right) + x1\\ \mathbf{elif}\;x1 \leq 2.3 \cdot 10^{-6}:\\ \;\;\;\;\mathsf{fma}\left(\mathsf{fma}\left(x2 \cdot x1, 8, \mathsf{fma}\left(\mathsf{fma}\left(x1, 12, -12\right), x1, -6\right)\right), x2, \mathsf{fma}\left(x1, 9, -2\right) \cdot x1\right) + x1\\ \mathbf{elif}\;x1 \leq 6.5 \cdot 10^{+63}:\\ \;\;\;\;\left(3 \cdot 3 - \left(\left(\left(\left(-1 - x1 \cdot x1\right) \cdot \left(\left(4 \cdot \frac{\left(x2 \cdot 2 + \left(3 \cdot x1\right) \cdot x1\right) - x1}{x1 \cdot x1 - -1} - 6\right) \cdot \left(x1 \cdot x1\right) + \left(\frac{\left(x2 \cdot 2 + \left(3 \cdot x1\right) \cdot x1\right) - x1}{x1 \cdot x1 - -1} - 3\right) \cdot \left(\left(2 \cdot x1\right) \cdot \frac{\left(x2 \cdot 2 + \left(3 \cdot x1\right) \cdot x1\right) - x1}{x1 \cdot x1 - -1}\right)\right) - \left(3 - \frac{1 - \frac{\mathsf{fma}\left(2, x2, -3\right)}{x1}}{x1}\right) \cdot \left(\left(3 \cdot x1\right) \cdot x1\right)\right) - \left(x1 \cdot x1\right) \cdot x1\right) - x1\right)\right) + x1\\ \mathbf{else}:\\ \;\;\;\;\left(\left(6 \cdot x1\right) \cdot x1\right) \cdot \left(x1 \cdot x1\right) + x1\\ \end{array} \]
                                                    5. Add Preprocessing

                                                    Alternative 6: 97.1% accurate, 1.1× speedup?

                                                    \[\begin{array}{l} \\ \begin{array}{l} t_0 := \left(3 \cdot x1\right) \cdot x1\\ t_1 := \frac{\mathsf{fma}\left(3 \cdot x1, x1, x2 \cdot 2\right) - x1}{\mathsf{fma}\left(x1, x1, 1\right)}\\ \mathbf{if}\;x1 \leq -53000000000:\\ \;\;\;\;{x1}^{4} \cdot \left(\mathsf{fma}\left(\frac{\mathsf{fma}\left(2, x2, -3\right)}{x1 \cdot x1}, 4, \frac{9}{x1 \cdot x1} + 6\right) - \frac{3}{x1}\right) + x1\\ \mathbf{elif}\;x1 \leq 0.135:\\ \;\;\;\;\mathsf{fma}\left(\mathsf{fma}\left(x2 \cdot x1, 8, \mathsf{fma}\left(\mathsf{fma}\left(x1, 12, -12\right), x1, -6\right)\right), x2, \mathsf{fma}\left(x1, 9, -2\right) \cdot x1\right) + x1\\ \mathbf{elif}\;x1 \leq 6.5 \cdot 10^{+63}:\\ \;\;\;\;\left(3 \cdot 3 - \left(\left(\left(\frac{\left(x2 \cdot 2 + t\_0\right) - x1}{-1 - x1 \cdot x1} \cdot t\_0 - \mathsf{fma}\left(t\_1, \left(t\_1 - 3\right) \cdot \left(2 \cdot x1\right), \mathsf{fma}\left(t\_1, 4, -6\right) \cdot \left(x1 \cdot x1\right)\right) \cdot \left(x1 \cdot x1 - -1\right)\right) - \left(x1 \cdot x1\right) \cdot x1\right) - x1\right)\right) + x1\\ \mathbf{else}:\\ \;\;\;\;\left(\left(6 \cdot x1\right) \cdot x1\right) \cdot \left(x1 \cdot x1\right) + x1\\ \end{array} \end{array} \]
                                                    (FPCore (x1 x2)
                                                     :precision binary64
                                                     (let* ((t_0 (* (* 3.0 x1) x1))
                                                            (t_1 (/ (- (fma (* 3.0 x1) x1 (* x2 2.0)) x1) (fma x1 x1 1.0))))
                                                       (if (<= x1 -53000000000.0)
                                                         (+
                                                          (*
                                                           (pow x1 4.0)
                                                           (-
                                                            (fma (/ (fma 2.0 x2 -3.0) (* x1 x1)) 4.0 (+ (/ 9.0 (* x1 x1)) 6.0))
                                                            (/ 3.0 x1)))
                                                          x1)
                                                         (if (<= x1 0.135)
                                                           (+
                                                            (fma
                                                             (fma (* x2 x1) 8.0 (fma (fma x1 12.0 -12.0) x1 -6.0))
                                                             x2
                                                             (* (fma x1 9.0 -2.0) x1))
                                                            x1)
                                                           (if (<= x1 6.5e+63)
                                                             (+
                                                              (-
                                                               (* 3.0 3.0)
                                                               (-
                                                                (-
                                                                 (-
                                                                  (* (/ (- (+ (* x2 2.0) t_0) x1) (- -1.0 (* x1 x1))) t_0)
                                                                  (*
                                                                   (fma
                                                                    t_1
                                                                    (* (- t_1 3.0) (* 2.0 x1))
                                                                    (* (fma t_1 4.0 -6.0) (* x1 x1)))
                                                                   (- (* x1 x1) -1.0)))
                                                                 (* (* x1 x1) x1))
                                                                x1))
                                                              x1)
                                                             (+ (* (* (* 6.0 x1) x1) (* x1 x1)) x1))))))
                                                    double code(double x1, double x2) {
                                                    	double t_0 = (3.0 * x1) * x1;
                                                    	double t_1 = (fma((3.0 * x1), x1, (x2 * 2.0)) - x1) / fma(x1, x1, 1.0);
                                                    	double tmp;
                                                    	if (x1 <= -53000000000.0) {
                                                    		tmp = (pow(x1, 4.0) * (fma((fma(2.0, x2, -3.0) / (x1 * x1)), 4.0, ((9.0 / (x1 * x1)) + 6.0)) - (3.0 / x1))) + x1;
                                                    	} else if (x1 <= 0.135) {
                                                    		tmp = fma(fma((x2 * x1), 8.0, fma(fma(x1, 12.0, -12.0), x1, -6.0)), x2, (fma(x1, 9.0, -2.0) * x1)) + x1;
                                                    	} else if (x1 <= 6.5e+63) {
                                                    		tmp = ((3.0 * 3.0) - ((((((((x2 * 2.0) + t_0) - x1) / (-1.0 - (x1 * x1))) * t_0) - (fma(t_1, ((t_1 - 3.0) * (2.0 * x1)), (fma(t_1, 4.0, -6.0) * (x1 * x1))) * ((x1 * x1) - -1.0))) - ((x1 * x1) * x1)) - x1)) + x1;
                                                    	} else {
                                                    		tmp = (((6.0 * x1) * x1) * (x1 * x1)) + x1;
                                                    	}
                                                    	return tmp;
                                                    }
                                                    
                                                    function code(x1, x2)
                                                    	t_0 = Float64(Float64(3.0 * x1) * x1)
                                                    	t_1 = Float64(Float64(fma(Float64(3.0 * x1), x1, Float64(x2 * 2.0)) - x1) / fma(x1, x1, 1.0))
                                                    	tmp = 0.0
                                                    	if (x1 <= -53000000000.0)
                                                    		tmp = Float64(Float64((x1 ^ 4.0) * Float64(fma(Float64(fma(2.0, x2, -3.0) / Float64(x1 * x1)), 4.0, Float64(Float64(9.0 / Float64(x1 * x1)) + 6.0)) - Float64(3.0 / x1))) + x1);
                                                    	elseif (x1 <= 0.135)
                                                    		tmp = Float64(fma(fma(Float64(x2 * x1), 8.0, fma(fma(x1, 12.0, -12.0), x1, -6.0)), x2, Float64(fma(x1, 9.0, -2.0) * x1)) + x1);
                                                    	elseif (x1 <= 6.5e+63)
                                                    		tmp = Float64(Float64(Float64(3.0 * 3.0) - Float64(Float64(Float64(Float64(Float64(Float64(Float64(Float64(x2 * 2.0) + t_0) - x1) / Float64(-1.0 - Float64(x1 * x1))) * t_0) - Float64(fma(t_1, Float64(Float64(t_1 - 3.0) * Float64(2.0 * x1)), Float64(fma(t_1, 4.0, -6.0) * Float64(x1 * x1))) * Float64(Float64(x1 * x1) - -1.0))) - Float64(Float64(x1 * x1) * x1)) - x1)) + x1);
                                                    	else
                                                    		tmp = Float64(Float64(Float64(Float64(6.0 * x1) * x1) * Float64(x1 * x1)) + x1);
                                                    	end
                                                    	return tmp
                                                    end
                                                    
                                                    code[x1_, x2_] := Block[{t$95$0 = N[(N[(3.0 * x1), $MachinePrecision] * x1), $MachinePrecision]}, Block[{t$95$1 = N[(N[(N[(N[(3.0 * x1), $MachinePrecision] * x1 + N[(x2 * 2.0), $MachinePrecision]), $MachinePrecision] - x1), $MachinePrecision] / N[(x1 * x1 + 1.0), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[x1, -53000000000.0], N[(N[(N[Power[x1, 4.0], $MachinePrecision] * N[(N[(N[(N[(2.0 * x2 + -3.0), $MachinePrecision] / N[(x1 * x1), $MachinePrecision]), $MachinePrecision] * 4.0 + N[(N[(9.0 / N[(x1 * x1), $MachinePrecision]), $MachinePrecision] + 6.0), $MachinePrecision]), $MachinePrecision] - N[(3.0 / x1), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] + x1), $MachinePrecision], If[LessEqual[x1, 0.135], N[(N[(N[(N[(x2 * x1), $MachinePrecision] * 8.0 + N[(N[(x1 * 12.0 + -12.0), $MachinePrecision] * x1 + -6.0), $MachinePrecision]), $MachinePrecision] * x2 + N[(N[(x1 * 9.0 + -2.0), $MachinePrecision] * x1), $MachinePrecision]), $MachinePrecision] + x1), $MachinePrecision], If[LessEqual[x1, 6.5e+63], N[(N[(N[(3.0 * 3.0), $MachinePrecision] - N[(N[(N[(N[(N[(N[(N[(N[(x2 * 2.0), $MachinePrecision] + t$95$0), $MachinePrecision] - x1), $MachinePrecision] / N[(-1.0 - N[(x1 * x1), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] * t$95$0), $MachinePrecision] - N[(N[(t$95$1 * N[(N[(t$95$1 - 3.0), $MachinePrecision] * N[(2.0 * x1), $MachinePrecision]), $MachinePrecision] + N[(N[(t$95$1 * 4.0 + -6.0), $MachinePrecision] * N[(x1 * x1), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] * N[(N[(x1 * x1), $MachinePrecision] - -1.0), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] - N[(N[(x1 * x1), $MachinePrecision] * x1), $MachinePrecision]), $MachinePrecision] - x1), $MachinePrecision]), $MachinePrecision] + x1), $MachinePrecision], N[(N[(N[(N[(6.0 * x1), $MachinePrecision] * x1), $MachinePrecision] * N[(x1 * x1), $MachinePrecision]), $MachinePrecision] + x1), $MachinePrecision]]]]]]
                                                    
                                                    \begin{array}{l}
                                                    
                                                    \\
                                                    \begin{array}{l}
                                                    t_0 := \left(3 \cdot x1\right) \cdot x1\\
                                                    t_1 := \frac{\mathsf{fma}\left(3 \cdot x1, x1, x2 \cdot 2\right) - x1}{\mathsf{fma}\left(x1, x1, 1\right)}\\
                                                    \mathbf{if}\;x1 \leq -53000000000:\\
                                                    \;\;\;\;{x1}^{4} \cdot \left(\mathsf{fma}\left(\frac{\mathsf{fma}\left(2, x2, -3\right)}{x1 \cdot x1}, 4, \frac{9}{x1 \cdot x1} + 6\right) - \frac{3}{x1}\right) + x1\\
                                                    
                                                    \mathbf{elif}\;x1 \leq 0.135:\\
                                                    \;\;\;\;\mathsf{fma}\left(\mathsf{fma}\left(x2 \cdot x1, 8, \mathsf{fma}\left(\mathsf{fma}\left(x1, 12, -12\right), x1, -6\right)\right), x2, \mathsf{fma}\left(x1, 9, -2\right) \cdot x1\right) + x1\\
                                                    
                                                    \mathbf{elif}\;x1 \leq 6.5 \cdot 10^{+63}:\\
                                                    \;\;\;\;\left(3 \cdot 3 - \left(\left(\left(\frac{\left(x2 \cdot 2 + t\_0\right) - x1}{-1 - x1 \cdot x1} \cdot t\_0 - \mathsf{fma}\left(t\_1, \left(t\_1 - 3\right) \cdot \left(2 \cdot x1\right), \mathsf{fma}\left(t\_1, 4, -6\right) \cdot \left(x1 \cdot x1\right)\right) \cdot \left(x1 \cdot x1 - -1\right)\right) - \left(x1 \cdot x1\right) \cdot x1\right) - x1\right)\right) + x1\\
                                                    
                                                    \mathbf{else}:\\
                                                    \;\;\;\;\left(\left(6 \cdot x1\right) \cdot x1\right) \cdot \left(x1 \cdot x1\right) + x1\\
                                                    
                                                    
                                                    \end{array}
                                                    \end{array}
                                                    
                                                    Derivation
                                                    1. Split input into 4 regimes
                                                    2. if x1 < -5.3e10

                                                      1. Initial program 28.0%

                                                        \[x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                                                      2. Add Preprocessing
                                                      3. Taylor expanded in x1 around inf

                                                        \[\leadsto x1 + \color{blue}{{x1}^{4} \cdot \left(\left(6 + \left(4 \cdot \frac{2 \cdot x2 - 3}{{x1}^{2}} + \frac{9}{{x1}^{2}}\right)\right) - 3 \cdot \frac{1}{x1}\right)} \]
                                                      4. Step-by-step derivation
                                                        1. *-commutativeN/A

                                                          \[\leadsto x1 + \color{blue}{\left(\left(6 + \left(4 \cdot \frac{2 \cdot x2 - 3}{{x1}^{2}} + \frac{9}{{x1}^{2}}\right)\right) - 3 \cdot \frac{1}{x1}\right) \cdot {x1}^{4}} \]
                                                        2. lower-*.f64N/A

                                                          \[\leadsto x1 + \color{blue}{\left(\left(6 + \left(4 \cdot \frac{2 \cdot x2 - 3}{{x1}^{2}} + \frac{9}{{x1}^{2}}\right)\right) - 3 \cdot \frac{1}{x1}\right) \cdot {x1}^{4}} \]
                                                      5. Applied rewrites95.8%

                                                        \[\leadsto x1 + \color{blue}{\left(\mathsf{fma}\left(\frac{\mathsf{fma}\left(2, x2, -3\right)}{x1 \cdot x1}, 4, \frac{9}{x1 \cdot x1} + 6\right) - \frac{3}{x1}\right) \cdot {x1}^{4}} \]

                                                      if -5.3e10 < x1 < 0.13500000000000001

                                                      1. Initial program 99.5%

                                                        \[x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                                                      2. Add Preprocessing
                                                      3. Taylor expanded in x1 around 0

                                                        \[\leadsto x1 + \color{blue}{\left(-6 \cdot x2 + x1 \cdot \left(\left(4 \cdot \left(x2 \cdot \left(2 \cdot x2 - 3\right)\right) + x1 \cdot \left(\left(2 \cdot \left(-2 \cdot x2 + -1 \cdot \left(2 \cdot x2 - 3\right)\right) + \left(3 \cdot \left(3 - -2 \cdot x2\right) + \left(6 \cdot x2 + 8 \cdot x2\right)\right)\right) - 6\right)\right) - 2\right)\right)} \]
                                                      4. Applied rewrites87.0%

                                                        \[\leadsto x1 + \color{blue}{\mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(-4, x2, \mathsf{fma}\left(\mathsf{fma}\left(-2, x2, 3\right), 2, \mathsf{fma}\left(\mathsf{fma}\left(2, x2, 3\right), 3, \mathsf{fma}\left(14, x2, -6\right)\right)\right)\right), x1, \mathsf{fma}\left(\mathsf{fma}\left(2, x2, -3\right) \cdot 4, x2, -2\right)\right), x1, -6 \cdot x2\right)} \]
                                                      5. Taylor expanded in x2 around 0

                                                        \[\leadsto x1 + \left(x1 \cdot \left(9 \cdot x1 - 2\right) + \color{blue}{x2 \cdot \left(\left(8 \cdot \left(x1 \cdot x2\right) + x1 \cdot \left(12 \cdot x1 - 12\right)\right) - 6\right)}\right) \]
                                                      6. Step-by-step derivation
                                                        1. Applied rewrites97.8%

                                                          \[\leadsto x1 + \mathsf{fma}\left(\mathsf{fma}\left(x1 \cdot x2, 8, \mathsf{fma}\left(\mathsf{fma}\left(x1, 12, -12\right), x1, -6\right)\right), \color{blue}{x2}, \mathsf{fma}\left(x1, 9, -2\right) \cdot x1\right) \]

                                                        if 0.13500000000000001 < x1 < 6.49999999999999992e63

                                                        1. Initial program 99.5%

                                                          \[x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                                                        2. Add Preprocessing
                                                        3. Taylor expanded in x1 around inf

                                                          \[\leadsto x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \color{blue}{3}\right) \]
                                                        4. Step-by-step derivation
                                                          1. Applied rewrites99.5%

                                                            \[\leadsto x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \color{blue}{3}\right) \]
                                                          2. Step-by-step derivation
                                                            1. lift-+.f64N/A

                                                              \[\leadsto x1 + \left(\left(\left(\left(\color{blue}{\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right)} \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot 3\right) \]
                                                            2. lift-*.f64N/A

                                                              \[\leadsto x1 + \left(\left(\left(\left(\left(\color{blue}{\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right)} + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot 3\right) \]
                                                            3. lift-*.f64N/A

                                                              \[\leadsto x1 + \left(\left(\left(\left(\left(\color{blue}{\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right)} \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot 3\right) \]
                                                            4. *-commutativeN/A

                                                              \[\leadsto x1 + \left(\left(\left(\left(\left(\color{blue}{\left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} \cdot \left(2 \cdot x1\right)\right)} \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot 3\right) \]
                                                            5. associate-*l*N/A

                                                              \[\leadsto x1 + \left(\left(\left(\left(\left(\color{blue}{\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} \cdot \left(\left(2 \cdot x1\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right)\right)} + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot 3\right) \]
                                                          3. Applied rewrites99.7%

                                                            \[\leadsto x1 + \left(\left(\left(\left(\color{blue}{\mathsf{fma}\left(\frac{\mathsf{fma}\left(x1 \cdot 3, x1, 2 \cdot x2\right) - x1}{\mathsf{fma}\left(x1, x1, 1\right)}, \left(x1 \cdot 2\right) \cdot \left(\frac{\mathsf{fma}\left(x1 \cdot 3, x1, 2 \cdot x2\right) - x1}{\mathsf{fma}\left(x1, x1, 1\right)} - 3\right), \mathsf{fma}\left(\frac{\mathsf{fma}\left(x1 \cdot 3, x1, 2 \cdot x2\right) - x1}{\mathsf{fma}\left(x1, x1, 1\right)}, 4, -6\right) \cdot \left(x1 \cdot x1\right)\right)} \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot 3\right) \]

                                                          if 6.49999999999999992e63 < x1

                                                          1. Initial program 27.7%

                                                            \[x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                                                          2. Add Preprocessing
                                                          3. Taylor expanded in x1 around inf

                                                            \[\leadsto x1 + \color{blue}{6 \cdot {x1}^{4}} \]
                                                          4. Step-by-step derivation
                                                            1. *-commutativeN/A

                                                              \[\leadsto x1 + \color{blue}{{x1}^{4} \cdot 6} \]
                                                            2. lower-*.f64N/A

                                                              \[\leadsto x1 + \color{blue}{{x1}^{4} \cdot 6} \]
                                                            3. lower-pow.f6499.9

                                                              \[\leadsto x1 + \color{blue}{{x1}^{4}} \cdot 6 \]
                                                          5. Applied rewrites99.9%

                                                            \[\leadsto x1 + \color{blue}{{x1}^{4} \cdot 6} \]
                                                          6. Step-by-step derivation
                                                            1. Applied rewrites99.9%

                                                              \[\leadsto x1 + \left(\left(\left(x1 \cdot x1\right) \cdot x1\right) \cdot x1\right) \cdot \color{blue}{6} \]
                                                            2. Step-by-step derivation
                                                              1. Applied rewrites100.0%

                                                                \[\leadsto x1 + \left(x1 \cdot x1\right) \cdot \color{blue}{\left(x1 \cdot \left(6 \cdot x1\right)\right)} \]
                                                            3. Recombined 4 regimes into one program.
                                                            4. Final simplification97.9%

                                                              \[\leadsto \begin{array}{l} \mathbf{if}\;x1 \leq -53000000000:\\ \;\;\;\;{x1}^{4} \cdot \left(\mathsf{fma}\left(\frac{\mathsf{fma}\left(2, x2, -3\right)}{x1 \cdot x1}, 4, \frac{9}{x1 \cdot x1} + 6\right) - \frac{3}{x1}\right) + x1\\ \mathbf{elif}\;x1 \leq 0.135:\\ \;\;\;\;\mathsf{fma}\left(\mathsf{fma}\left(x2 \cdot x1, 8, \mathsf{fma}\left(\mathsf{fma}\left(x1, 12, -12\right), x1, -6\right)\right), x2, \mathsf{fma}\left(x1, 9, -2\right) \cdot x1\right) + x1\\ \mathbf{elif}\;x1 \leq 6.5 \cdot 10^{+63}:\\ \;\;\;\;\left(3 \cdot 3 - \left(\left(\left(\frac{\left(x2 \cdot 2 + \left(3 \cdot x1\right) \cdot x1\right) - x1}{-1 - x1 \cdot x1} \cdot \left(\left(3 \cdot x1\right) \cdot x1\right) - \mathsf{fma}\left(\frac{\mathsf{fma}\left(3 \cdot x1, x1, x2 \cdot 2\right) - x1}{\mathsf{fma}\left(x1, x1, 1\right)}, \left(\frac{\mathsf{fma}\left(3 \cdot x1, x1, x2 \cdot 2\right) - x1}{\mathsf{fma}\left(x1, x1, 1\right)} - 3\right) \cdot \left(2 \cdot x1\right), \mathsf{fma}\left(\frac{\mathsf{fma}\left(3 \cdot x1, x1, x2 \cdot 2\right) - x1}{\mathsf{fma}\left(x1, x1, 1\right)}, 4, -6\right) \cdot \left(x1 \cdot x1\right)\right) \cdot \left(x1 \cdot x1 - -1\right)\right) - \left(x1 \cdot x1\right) \cdot x1\right) - x1\right)\right) + x1\\ \mathbf{else}:\\ \;\;\;\;\left(\left(6 \cdot x1\right) \cdot x1\right) \cdot \left(x1 \cdot x1\right) + x1\\ \end{array} \]
                                                            5. Add Preprocessing

                                                            Alternative 7: 97.1% accurate, 1.3× speedup?

                                                            \[\begin{array}{l} \\ \begin{array}{l} t_0 := \left(3 \cdot x1\right) \cdot x1\\ t_1 := \frac{\left(x2 \cdot 2 + t\_0\right) - x1}{x1 \cdot x1 - -1}\\ \mathbf{if}\;x1 \leq -53000000000:\\ \;\;\;\;{x1}^{4} \cdot \left(\mathsf{fma}\left(\frac{\mathsf{fma}\left(2, x2, -3\right)}{x1 \cdot x1}, 4, \frac{9}{x1 \cdot x1} + 6\right) - \frac{3}{x1}\right) + x1\\ \mathbf{elif}\;x1 \leq 0.135:\\ \;\;\;\;\mathsf{fma}\left(\mathsf{fma}\left(x2 \cdot x1, 8, \mathsf{fma}\left(\mathsf{fma}\left(x1, 12, -12\right), x1, -6\right)\right), x2, \mathsf{fma}\left(x1, 9, -2\right) \cdot x1\right) + x1\\ \mathbf{elif}\;x1 \leq 6.5 \cdot 10^{+63}:\\ \;\;\;\;\left(3 \cdot 3 - \left(\left(\left(\left(-1 - x1 \cdot x1\right) \cdot \left(\left(4 \cdot t\_1 - 6\right) \cdot \left(x1 \cdot x1\right) + \left(t\_1 - 3\right) \cdot \left(\left(2 \cdot x1\right) \cdot t\_1\right)\right) - 3 \cdot t\_0\right) - \left(x1 \cdot x1\right) \cdot x1\right) - x1\right)\right) + x1\\ \mathbf{else}:\\ \;\;\;\;\left(\left(6 \cdot x1\right) \cdot x1\right) \cdot \left(x1 \cdot x1\right) + x1\\ \end{array} \end{array} \]
                                                            (FPCore (x1 x2)
                                                             :precision binary64
                                                             (let* ((t_0 (* (* 3.0 x1) x1))
                                                                    (t_1 (/ (- (+ (* x2 2.0) t_0) x1) (- (* x1 x1) -1.0))))
                                                               (if (<= x1 -53000000000.0)
                                                                 (+
                                                                  (*
                                                                   (pow x1 4.0)
                                                                   (-
                                                                    (fma (/ (fma 2.0 x2 -3.0) (* x1 x1)) 4.0 (+ (/ 9.0 (* x1 x1)) 6.0))
                                                                    (/ 3.0 x1)))
                                                                  x1)
                                                                 (if (<= x1 0.135)
                                                                   (+
                                                                    (fma
                                                                     (fma (* x2 x1) 8.0 (fma (fma x1 12.0 -12.0) x1 -6.0))
                                                                     x2
                                                                     (* (fma x1 9.0 -2.0) x1))
                                                                    x1)
                                                                   (if (<= x1 6.5e+63)
                                                                     (+
                                                                      (-
                                                                       (* 3.0 3.0)
                                                                       (-
                                                                        (-
                                                                         (-
                                                                          (*
                                                                           (- -1.0 (* x1 x1))
                                                                           (+
                                                                            (* (- (* 4.0 t_1) 6.0) (* x1 x1))
                                                                            (* (- t_1 3.0) (* (* 2.0 x1) t_1))))
                                                                          (* 3.0 t_0))
                                                                         (* (* x1 x1) x1))
                                                                        x1))
                                                                      x1)
                                                                     (+ (* (* (* 6.0 x1) x1) (* x1 x1)) x1))))))
                                                            double code(double x1, double x2) {
                                                            	double t_0 = (3.0 * x1) * x1;
                                                            	double t_1 = (((x2 * 2.0) + t_0) - x1) / ((x1 * x1) - -1.0);
                                                            	double tmp;
                                                            	if (x1 <= -53000000000.0) {
                                                            		tmp = (pow(x1, 4.0) * (fma((fma(2.0, x2, -3.0) / (x1 * x1)), 4.0, ((9.0 / (x1 * x1)) + 6.0)) - (3.0 / x1))) + x1;
                                                            	} else if (x1 <= 0.135) {
                                                            		tmp = fma(fma((x2 * x1), 8.0, fma(fma(x1, 12.0, -12.0), x1, -6.0)), x2, (fma(x1, 9.0, -2.0) * x1)) + x1;
                                                            	} else if (x1 <= 6.5e+63) {
                                                            		tmp = ((3.0 * 3.0) - (((((-1.0 - (x1 * x1)) * ((((4.0 * t_1) - 6.0) * (x1 * x1)) + ((t_1 - 3.0) * ((2.0 * x1) * t_1)))) - (3.0 * t_0)) - ((x1 * x1) * x1)) - x1)) + x1;
                                                            	} else {
                                                            		tmp = (((6.0 * x1) * x1) * (x1 * x1)) + x1;
                                                            	}
                                                            	return tmp;
                                                            }
                                                            
                                                            function code(x1, x2)
                                                            	t_0 = Float64(Float64(3.0 * x1) * x1)
                                                            	t_1 = Float64(Float64(Float64(Float64(x2 * 2.0) + t_0) - x1) / Float64(Float64(x1 * x1) - -1.0))
                                                            	tmp = 0.0
                                                            	if (x1 <= -53000000000.0)
                                                            		tmp = Float64(Float64((x1 ^ 4.0) * Float64(fma(Float64(fma(2.0, x2, -3.0) / Float64(x1 * x1)), 4.0, Float64(Float64(9.0 / Float64(x1 * x1)) + 6.0)) - Float64(3.0 / x1))) + x1);
                                                            	elseif (x1 <= 0.135)
                                                            		tmp = Float64(fma(fma(Float64(x2 * x1), 8.0, fma(fma(x1, 12.0, -12.0), x1, -6.0)), x2, Float64(fma(x1, 9.0, -2.0) * x1)) + x1);
                                                            	elseif (x1 <= 6.5e+63)
                                                            		tmp = Float64(Float64(Float64(3.0 * 3.0) - Float64(Float64(Float64(Float64(Float64(-1.0 - Float64(x1 * x1)) * Float64(Float64(Float64(Float64(4.0 * t_1) - 6.0) * Float64(x1 * x1)) + Float64(Float64(t_1 - 3.0) * Float64(Float64(2.0 * x1) * t_1)))) - Float64(3.0 * t_0)) - Float64(Float64(x1 * x1) * x1)) - x1)) + x1);
                                                            	else
                                                            		tmp = Float64(Float64(Float64(Float64(6.0 * x1) * x1) * Float64(x1 * x1)) + x1);
                                                            	end
                                                            	return tmp
                                                            end
                                                            
                                                            code[x1_, x2_] := Block[{t$95$0 = N[(N[(3.0 * x1), $MachinePrecision] * x1), $MachinePrecision]}, Block[{t$95$1 = N[(N[(N[(N[(x2 * 2.0), $MachinePrecision] + t$95$0), $MachinePrecision] - x1), $MachinePrecision] / N[(N[(x1 * x1), $MachinePrecision] - -1.0), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[x1, -53000000000.0], N[(N[(N[Power[x1, 4.0], $MachinePrecision] * N[(N[(N[(N[(2.0 * x2 + -3.0), $MachinePrecision] / N[(x1 * x1), $MachinePrecision]), $MachinePrecision] * 4.0 + N[(N[(9.0 / N[(x1 * x1), $MachinePrecision]), $MachinePrecision] + 6.0), $MachinePrecision]), $MachinePrecision] - N[(3.0 / x1), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] + x1), $MachinePrecision], If[LessEqual[x1, 0.135], N[(N[(N[(N[(x2 * x1), $MachinePrecision] * 8.0 + N[(N[(x1 * 12.0 + -12.0), $MachinePrecision] * x1 + -6.0), $MachinePrecision]), $MachinePrecision] * x2 + N[(N[(x1 * 9.0 + -2.0), $MachinePrecision] * x1), $MachinePrecision]), $MachinePrecision] + x1), $MachinePrecision], If[LessEqual[x1, 6.5e+63], N[(N[(N[(3.0 * 3.0), $MachinePrecision] - N[(N[(N[(N[(N[(-1.0 - N[(x1 * x1), $MachinePrecision]), $MachinePrecision] * N[(N[(N[(N[(4.0 * t$95$1), $MachinePrecision] - 6.0), $MachinePrecision] * N[(x1 * x1), $MachinePrecision]), $MachinePrecision] + N[(N[(t$95$1 - 3.0), $MachinePrecision] * N[(N[(2.0 * x1), $MachinePrecision] * t$95$1), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] - N[(3.0 * t$95$0), $MachinePrecision]), $MachinePrecision] - N[(N[(x1 * x1), $MachinePrecision] * x1), $MachinePrecision]), $MachinePrecision] - x1), $MachinePrecision]), $MachinePrecision] + x1), $MachinePrecision], N[(N[(N[(N[(6.0 * x1), $MachinePrecision] * x1), $MachinePrecision] * N[(x1 * x1), $MachinePrecision]), $MachinePrecision] + x1), $MachinePrecision]]]]]]
                                                            
                                                            \begin{array}{l}
                                                            
                                                            \\
                                                            \begin{array}{l}
                                                            t_0 := \left(3 \cdot x1\right) \cdot x1\\
                                                            t_1 := \frac{\left(x2 \cdot 2 + t\_0\right) - x1}{x1 \cdot x1 - -1}\\
                                                            \mathbf{if}\;x1 \leq -53000000000:\\
                                                            \;\;\;\;{x1}^{4} \cdot \left(\mathsf{fma}\left(\frac{\mathsf{fma}\left(2, x2, -3\right)}{x1 \cdot x1}, 4, \frac{9}{x1 \cdot x1} + 6\right) - \frac{3}{x1}\right) + x1\\
                                                            
                                                            \mathbf{elif}\;x1 \leq 0.135:\\
                                                            \;\;\;\;\mathsf{fma}\left(\mathsf{fma}\left(x2 \cdot x1, 8, \mathsf{fma}\left(\mathsf{fma}\left(x1, 12, -12\right), x1, -6\right)\right), x2, \mathsf{fma}\left(x1, 9, -2\right) \cdot x1\right) + x1\\
                                                            
                                                            \mathbf{elif}\;x1 \leq 6.5 \cdot 10^{+63}:\\
                                                            \;\;\;\;\left(3 \cdot 3 - \left(\left(\left(\left(-1 - x1 \cdot x1\right) \cdot \left(\left(4 \cdot t\_1 - 6\right) \cdot \left(x1 \cdot x1\right) + \left(t\_1 - 3\right) \cdot \left(\left(2 \cdot x1\right) \cdot t\_1\right)\right) - 3 \cdot t\_0\right) - \left(x1 \cdot x1\right) \cdot x1\right) - x1\right)\right) + x1\\
                                                            
                                                            \mathbf{else}:\\
                                                            \;\;\;\;\left(\left(6 \cdot x1\right) \cdot x1\right) \cdot \left(x1 \cdot x1\right) + x1\\
                                                            
                                                            
                                                            \end{array}
                                                            \end{array}
                                                            
                                                            Derivation
                                                            1. Split input into 4 regimes
                                                            2. if x1 < -5.3e10

                                                              1. Initial program 28.0%

                                                                \[x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                                                              2. Add Preprocessing
                                                              3. Taylor expanded in x1 around inf

                                                                \[\leadsto x1 + \color{blue}{{x1}^{4} \cdot \left(\left(6 + \left(4 \cdot \frac{2 \cdot x2 - 3}{{x1}^{2}} + \frac{9}{{x1}^{2}}\right)\right) - 3 \cdot \frac{1}{x1}\right)} \]
                                                              4. Step-by-step derivation
                                                                1. *-commutativeN/A

                                                                  \[\leadsto x1 + \color{blue}{\left(\left(6 + \left(4 \cdot \frac{2 \cdot x2 - 3}{{x1}^{2}} + \frac{9}{{x1}^{2}}\right)\right) - 3 \cdot \frac{1}{x1}\right) \cdot {x1}^{4}} \]
                                                                2. lower-*.f64N/A

                                                                  \[\leadsto x1 + \color{blue}{\left(\left(6 + \left(4 \cdot \frac{2 \cdot x2 - 3}{{x1}^{2}} + \frac{9}{{x1}^{2}}\right)\right) - 3 \cdot \frac{1}{x1}\right) \cdot {x1}^{4}} \]
                                                              5. Applied rewrites95.8%

                                                                \[\leadsto x1 + \color{blue}{\left(\mathsf{fma}\left(\frac{\mathsf{fma}\left(2, x2, -3\right)}{x1 \cdot x1}, 4, \frac{9}{x1 \cdot x1} + 6\right) - \frac{3}{x1}\right) \cdot {x1}^{4}} \]

                                                              if -5.3e10 < x1 < 0.13500000000000001

                                                              1. Initial program 99.5%

                                                                \[x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                                                              2. Add Preprocessing
                                                              3. Taylor expanded in x1 around 0

                                                                \[\leadsto x1 + \color{blue}{\left(-6 \cdot x2 + x1 \cdot \left(\left(4 \cdot \left(x2 \cdot \left(2 \cdot x2 - 3\right)\right) + x1 \cdot \left(\left(2 \cdot \left(-2 \cdot x2 + -1 \cdot \left(2 \cdot x2 - 3\right)\right) + \left(3 \cdot \left(3 - -2 \cdot x2\right) + \left(6 \cdot x2 + 8 \cdot x2\right)\right)\right) - 6\right)\right) - 2\right)\right)} \]
                                                              4. Applied rewrites87.0%

                                                                \[\leadsto x1 + \color{blue}{\mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(-4, x2, \mathsf{fma}\left(\mathsf{fma}\left(-2, x2, 3\right), 2, \mathsf{fma}\left(\mathsf{fma}\left(2, x2, 3\right), 3, \mathsf{fma}\left(14, x2, -6\right)\right)\right)\right), x1, \mathsf{fma}\left(\mathsf{fma}\left(2, x2, -3\right) \cdot 4, x2, -2\right)\right), x1, -6 \cdot x2\right)} \]
                                                              5. Taylor expanded in x2 around 0

                                                                \[\leadsto x1 + \left(x1 \cdot \left(9 \cdot x1 - 2\right) + \color{blue}{x2 \cdot \left(\left(8 \cdot \left(x1 \cdot x2\right) + x1 \cdot \left(12 \cdot x1 - 12\right)\right) - 6\right)}\right) \]
                                                              6. Step-by-step derivation
                                                                1. Applied rewrites97.8%

                                                                  \[\leadsto x1 + \mathsf{fma}\left(\mathsf{fma}\left(x1 \cdot x2, 8, \mathsf{fma}\left(\mathsf{fma}\left(x1, 12, -12\right), x1, -6\right)\right), \color{blue}{x2}, \mathsf{fma}\left(x1, 9, -2\right) \cdot x1\right) \]

                                                                if 0.13500000000000001 < x1 < 6.49999999999999992e63

                                                                1. Initial program 99.5%

                                                                  \[x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                                                                2. Add Preprocessing
                                                                3. Taylor expanded in x1 around inf

                                                                  \[\leadsto x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \color{blue}{3}\right) \]
                                                                4. Step-by-step derivation
                                                                  1. Applied rewrites99.5%

                                                                    \[\leadsto x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \color{blue}{3}\right) \]
                                                                  2. Taylor expanded in x1 around inf

                                                                    \[\leadsto x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \color{blue}{3}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot 3\right) \]
                                                                  3. Step-by-step derivation
                                                                    1. Applied rewrites99.5%

                                                                      \[\leadsto x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \color{blue}{3}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot 3\right) \]

                                                                    if 6.49999999999999992e63 < x1

                                                                    1. Initial program 27.7%

                                                                      \[x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                                                                    2. Add Preprocessing
                                                                    3. Taylor expanded in x1 around inf

                                                                      \[\leadsto x1 + \color{blue}{6 \cdot {x1}^{4}} \]
                                                                    4. Step-by-step derivation
                                                                      1. *-commutativeN/A

                                                                        \[\leadsto x1 + \color{blue}{{x1}^{4} \cdot 6} \]
                                                                      2. lower-*.f64N/A

                                                                        \[\leadsto x1 + \color{blue}{{x1}^{4} \cdot 6} \]
                                                                      3. lower-pow.f6499.9

                                                                        \[\leadsto x1 + \color{blue}{{x1}^{4}} \cdot 6 \]
                                                                    5. Applied rewrites99.9%

                                                                      \[\leadsto x1 + \color{blue}{{x1}^{4} \cdot 6} \]
                                                                    6. Step-by-step derivation
                                                                      1. Applied rewrites99.9%

                                                                        \[\leadsto x1 + \left(\left(\left(x1 \cdot x1\right) \cdot x1\right) \cdot x1\right) \cdot \color{blue}{6} \]
                                                                      2. Step-by-step derivation
                                                                        1. Applied rewrites100.0%

                                                                          \[\leadsto x1 + \left(x1 \cdot x1\right) \cdot \color{blue}{\left(x1 \cdot \left(6 \cdot x1\right)\right)} \]
                                                                      3. Recombined 4 regimes into one program.
                                                                      4. Final simplification97.9%

                                                                        \[\leadsto \begin{array}{l} \mathbf{if}\;x1 \leq -53000000000:\\ \;\;\;\;{x1}^{4} \cdot \left(\mathsf{fma}\left(\frac{\mathsf{fma}\left(2, x2, -3\right)}{x1 \cdot x1}, 4, \frac{9}{x1 \cdot x1} + 6\right) - \frac{3}{x1}\right) + x1\\ \mathbf{elif}\;x1 \leq 0.135:\\ \;\;\;\;\mathsf{fma}\left(\mathsf{fma}\left(x2 \cdot x1, 8, \mathsf{fma}\left(\mathsf{fma}\left(x1, 12, -12\right), x1, -6\right)\right), x2, \mathsf{fma}\left(x1, 9, -2\right) \cdot x1\right) + x1\\ \mathbf{elif}\;x1 \leq 6.5 \cdot 10^{+63}:\\ \;\;\;\;\left(3 \cdot 3 - \left(\left(\left(\left(-1 - x1 \cdot x1\right) \cdot \left(\left(4 \cdot \frac{\left(x2 \cdot 2 + \left(3 \cdot x1\right) \cdot x1\right) - x1}{x1 \cdot x1 - -1} - 6\right) \cdot \left(x1 \cdot x1\right) + \left(\frac{\left(x2 \cdot 2 + \left(3 \cdot x1\right) \cdot x1\right) - x1}{x1 \cdot x1 - -1} - 3\right) \cdot \left(\left(2 \cdot x1\right) \cdot \frac{\left(x2 \cdot 2 + \left(3 \cdot x1\right) \cdot x1\right) - x1}{x1 \cdot x1 - -1}\right)\right) - 3 \cdot \left(\left(3 \cdot x1\right) \cdot x1\right)\right) - \left(x1 \cdot x1\right) \cdot x1\right) - x1\right)\right) + x1\\ \mathbf{else}:\\ \;\;\;\;\left(\left(6 \cdot x1\right) \cdot x1\right) \cdot \left(x1 \cdot x1\right) + x1\\ \end{array} \]
                                                                      5. Add Preprocessing

                                                                      Alternative 8: 94.3% accurate, 3.0× speedup?

                                                                      \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;x1 \leq -22000:\\ \;\;\;\;\left(\left(\mathsf{fma}\left(\frac{\mathsf{fma}\left(2, x2, -3\right)}{x1 \cdot x1}, 4, \frac{9}{x1 \cdot x1} + 6\right) - \frac{3}{x1}\right) \cdot \left(x1 \cdot x1\right)\right) \cdot \left(x1 \cdot x1\right) + x1\\ \mathbf{elif}\;x1 \leq 5 \cdot 10^{+46}:\\ \;\;\;\;\left(\left(\left(\left(\frac{x1}{\mathsf{fma}\left(x1, x1, 1\right)} \cdot 8\right) \cdot x2\right) \cdot x2 + x1\right) + \frac{\left(\left(3 \cdot x1\right) \cdot x1 - x2 \cdot 2\right) - x1}{x1 \cdot x1 - -1} \cdot 3\right) + x1\\ \mathbf{else}:\\ \;\;\;\;\left(\left(6 \cdot x1\right) \cdot x1\right) \cdot \left(x1 \cdot x1\right) + x1\\ \end{array} \end{array} \]
                                                                      (FPCore (x1 x2)
                                                                       :precision binary64
                                                                       (if (<= x1 -22000.0)
                                                                         (+
                                                                          (*
                                                                           (*
                                                                            (-
                                                                             (fma (/ (fma 2.0 x2 -3.0) (* x1 x1)) 4.0 (+ (/ 9.0 (* x1 x1)) 6.0))
                                                                             (/ 3.0 x1))
                                                                            (* x1 x1))
                                                                           (* x1 x1))
                                                                          x1)
                                                                         (if (<= x1 5e+46)
                                                                           (+
                                                                            (+
                                                                             (+ (* (* (* (/ x1 (fma x1 x1 1.0)) 8.0) x2) x2) x1)
                                                                             (* (/ (- (- (* (* 3.0 x1) x1) (* x2 2.0)) x1) (- (* x1 x1) -1.0)) 3.0))
                                                                            x1)
                                                                           (+ (* (* (* 6.0 x1) x1) (* x1 x1)) x1))))
                                                                      double code(double x1, double x2) {
                                                                      	double tmp;
                                                                      	if (x1 <= -22000.0) {
                                                                      		tmp = (((fma((fma(2.0, x2, -3.0) / (x1 * x1)), 4.0, ((9.0 / (x1 * x1)) + 6.0)) - (3.0 / x1)) * (x1 * x1)) * (x1 * x1)) + x1;
                                                                      	} else if (x1 <= 5e+46) {
                                                                      		tmp = ((((((x1 / fma(x1, x1, 1.0)) * 8.0) * x2) * x2) + x1) + ((((((3.0 * x1) * x1) - (x2 * 2.0)) - x1) / ((x1 * x1) - -1.0)) * 3.0)) + x1;
                                                                      	} else {
                                                                      		tmp = (((6.0 * x1) * x1) * (x1 * x1)) + x1;
                                                                      	}
                                                                      	return tmp;
                                                                      }
                                                                      
                                                                      function code(x1, x2)
                                                                      	tmp = 0.0
                                                                      	if (x1 <= -22000.0)
                                                                      		tmp = Float64(Float64(Float64(Float64(fma(Float64(fma(2.0, x2, -3.0) / Float64(x1 * x1)), 4.0, Float64(Float64(9.0 / Float64(x1 * x1)) + 6.0)) - Float64(3.0 / x1)) * Float64(x1 * x1)) * Float64(x1 * x1)) + x1);
                                                                      	elseif (x1 <= 5e+46)
                                                                      		tmp = Float64(Float64(Float64(Float64(Float64(Float64(Float64(x1 / fma(x1, x1, 1.0)) * 8.0) * x2) * x2) + x1) + Float64(Float64(Float64(Float64(Float64(Float64(3.0 * x1) * x1) - Float64(x2 * 2.0)) - x1) / Float64(Float64(x1 * x1) - -1.0)) * 3.0)) + x1);
                                                                      	else
                                                                      		tmp = Float64(Float64(Float64(Float64(6.0 * x1) * x1) * Float64(x1 * x1)) + x1);
                                                                      	end
                                                                      	return tmp
                                                                      end
                                                                      
                                                                      code[x1_, x2_] := If[LessEqual[x1, -22000.0], N[(N[(N[(N[(N[(N[(N[(2.0 * x2 + -3.0), $MachinePrecision] / N[(x1 * x1), $MachinePrecision]), $MachinePrecision] * 4.0 + N[(N[(9.0 / N[(x1 * x1), $MachinePrecision]), $MachinePrecision] + 6.0), $MachinePrecision]), $MachinePrecision] - N[(3.0 / x1), $MachinePrecision]), $MachinePrecision] * N[(x1 * x1), $MachinePrecision]), $MachinePrecision] * N[(x1 * x1), $MachinePrecision]), $MachinePrecision] + x1), $MachinePrecision], If[LessEqual[x1, 5e+46], N[(N[(N[(N[(N[(N[(N[(x1 / N[(x1 * x1 + 1.0), $MachinePrecision]), $MachinePrecision] * 8.0), $MachinePrecision] * x2), $MachinePrecision] * x2), $MachinePrecision] + x1), $MachinePrecision] + N[(N[(N[(N[(N[(N[(3.0 * x1), $MachinePrecision] * x1), $MachinePrecision] - N[(x2 * 2.0), $MachinePrecision]), $MachinePrecision] - x1), $MachinePrecision] / N[(N[(x1 * x1), $MachinePrecision] - -1.0), $MachinePrecision]), $MachinePrecision] * 3.0), $MachinePrecision]), $MachinePrecision] + x1), $MachinePrecision], N[(N[(N[(N[(6.0 * x1), $MachinePrecision] * x1), $MachinePrecision] * N[(x1 * x1), $MachinePrecision]), $MachinePrecision] + x1), $MachinePrecision]]]
                                                                      
                                                                      \begin{array}{l}
                                                                      
                                                                      \\
                                                                      \begin{array}{l}
                                                                      \mathbf{if}\;x1 \leq -22000:\\
                                                                      \;\;\;\;\left(\left(\mathsf{fma}\left(\frac{\mathsf{fma}\left(2, x2, -3\right)}{x1 \cdot x1}, 4, \frac{9}{x1 \cdot x1} + 6\right) - \frac{3}{x1}\right) \cdot \left(x1 \cdot x1\right)\right) \cdot \left(x1 \cdot x1\right) + x1\\
                                                                      
                                                                      \mathbf{elif}\;x1 \leq 5 \cdot 10^{+46}:\\
                                                                      \;\;\;\;\left(\left(\left(\left(\frac{x1}{\mathsf{fma}\left(x1, x1, 1\right)} \cdot 8\right) \cdot x2\right) \cdot x2 + x1\right) + \frac{\left(\left(3 \cdot x1\right) \cdot x1 - x2 \cdot 2\right) - x1}{x1 \cdot x1 - -1} \cdot 3\right) + x1\\
                                                                      
                                                                      \mathbf{else}:\\
                                                                      \;\;\;\;\left(\left(6 \cdot x1\right) \cdot x1\right) \cdot \left(x1 \cdot x1\right) + x1\\
                                                                      
                                                                      
                                                                      \end{array}
                                                                      \end{array}
                                                                      
                                                                      Derivation
                                                                      1. Split input into 3 regimes
                                                                      2. if x1 < -22000

                                                                        1. Initial program 30.1%

                                                                          \[x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                                                                        2. Add Preprocessing
                                                                        3. Taylor expanded in x1 around inf

                                                                          \[\leadsto x1 + \color{blue}{{x1}^{4} \cdot \left(\left(6 + \left(4 \cdot \frac{2 \cdot x2 - 3}{{x1}^{2}} + \frac{9}{{x1}^{2}}\right)\right) - 3 \cdot \frac{1}{x1}\right)} \]
                                                                        4. Step-by-step derivation
                                                                          1. *-commutativeN/A

                                                                            \[\leadsto x1 + \color{blue}{\left(\left(6 + \left(4 \cdot \frac{2 \cdot x2 - 3}{{x1}^{2}} + \frac{9}{{x1}^{2}}\right)\right) - 3 \cdot \frac{1}{x1}\right) \cdot {x1}^{4}} \]
                                                                          2. lower-*.f64N/A

                                                                            \[\leadsto x1 + \color{blue}{\left(\left(6 + \left(4 \cdot \frac{2 \cdot x2 - 3}{{x1}^{2}} + \frac{9}{{x1}^{2}}\right)\right) - 3 \cdot \frac{1}{x1}\right) \cdot {x1}^{4}} \]
                                                                        5. Applied rewrites94.6%

                                                                          \[\leadsto x1 + \color{blue}{\left(\mathsf{fma}\left(\frac{\mathsf{fma}\left(2, x2, -3\right)}{x1 \cdot x1}, 4, \frac{9}{x1 \cdot x1} + 6\right) - \frac{3}{x1}\right) \cdot {x1}^{4}} \]
                                                                        6. Step-by-step derivation
                                                                          1. Applied rewrites94.6%

                                                                            \[\leadsto x1 + \left(\left(\mathsf{fma}\left(\frac{\mathsf{fma}\left(2, x2, -3\right)}{x1 \cdot x1}, 4, \frac{9}{x1 \cdot x1} + 6\right) - \frac{3}{x1}\right) \cdot \left(x1 \cdot x1\right)\right) \cdot \color{blue}{\left(x1 \cdot x1\right)} \]

                                                                          if -22000 < x1 < 5.0000000000000002e46

                                                                          1. Initial program 99.5%

                                                                            \[x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                                                                          2. Add Preprocessing
                                                                          3. Taylor expanded in x2 around inf

                                                                            \[\leadsto x1 + \left(\left(\color{blue}{8 \cdot \frac{x1 \cdot {x2}^{2}}{1 + {x1}^{2}}} + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                                                                          4. Step-by-step derivation
                                                                            1. associate-*r/N/A

                                                                              \[\leadsto x1 + \left(\left(\color{blue}{\frac{8 \cdot \left(x1 \cdot {x2}^{2}\right)}{1 + {x1}^{2}}} + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                                                                            2. associate-*r*N/A

                                                                              \[\leadsto x1 + \left(\left(\frac{\color{blue}{\left(8 \cdot x1\right) \cdot {x2}^{2}}}{1 + {x1}^{2}} + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                                                                            3. associate-*l/N/A

                                                                              \[\leadsto x1 + \left(\left(\color{blue}{\frac{8 \cdot x1}{1 + {x1}^{2}} \cdot {x2}^{2}} + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                                                                            4. associate-*r/N/A

                                                                              \[\leadsto x1 + \left(\left(\color{blue}{\left(8 \cdot \frac{x1}{1 + {x1}^{2}}\right)} \cdot {x2}^{2} + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                                                                            5. unpow2N/A

                                                                              \[\leadsto x1 + \left(\left(\left(8 \cdot \frac{x1}{1 + {x1}^{2}}\right) \cdot \color{blue}{\left(x2 \cdot x2\right)} + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                                                                            6. associate-*r*N/A

                                                                              \[\leadsto x1 + \left(\left(\color{blue}{\left(\left(8 \cdot \frac{x1}{1 + {x1}^{2}}\right) \cdot x2\right) \cdot x2} + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                                                                            7. lower-*.f64N/A

                                                                              \[\leadsto x1 + \left(\left(\color{blue}{\left(\left(8 \cdot \frac{x1}{1 + {x1}^{2}}\right) \cdot x2\right) \cdot x2} + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                                                                            8. lower-*.f64N/A

                                                                              \[\leadsto x1 + \left(\left(\color{blue}{\left(\left(8 \cdot \frac{x1}{1 + {x1}^{2}}\right) \cdot x2\right)} \cdot x2 + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                                                                            9. *-commutativeN/A

                                                                              \[\leadsto x1 + \left(\left(\left(\color{blue}{\left(\frac{x1}{1 + {x1}^{2}} \cdot 8\right)} \cdot x2\right) \cdot x2 + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                                                                            10. lower-*.f64N/A

                                                                              \[\leadsto x1 + \left(\left(\left(\color{blue}{\left(\frac{x1}{1 + {x1}^{2}} \cdot 8\right)} \cdot x2\right) \cdot x2 + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                                                                            11. lower-/.f64N/A

                                                                              \[\leadsto x1 + \left(\left(\left(\left(\color{blue}{\frac{x1}{1 + {x1}^{2}}} \cdot 8\right) \cdot x2\right) \cdot x2 + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                                                                            12. +-commutativeN/A

                                                                              \[\leadsto x1 + \left(\left(\left(\left(\frac{x1}{\color{blue}{{x1}^{2} + 1}} \cdot 8\right) \cdot x2\right) \cdot x2 + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                                                                            13. unpow2N/A

                                                                              \[\leadsto x1 + \left(\left(\left(\left(\frac{x1}{\color{blue}{x1 \cdot x1} + 1} \cdot 8\right) \cdot x2\right) \cdot x2 + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                                                                            14. lower-fma.f6494.2

                                                                              \[\leadsto x1 + \left(\left(\left(\left(\frac{x1}{\color{blue}{\mathsf{fma}\left(x1, x1, 1\right)}} \cdot 8\right) \cdot x2\right) \cdot x2 + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                                                                          5. Applied rewrites94.2%

                                                                            \[\leadsto x1 + \left(\left(\color{blue}{\left(\left(\frac{x1}{\mathsf{fma}\left(x1, x1, 1\right)} \cdot 8\right) \cdot x2\right) \cdot x2} + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]

                                                                          if 5.0000000000000002e46 < x1

                                                                          1. Initial program 27.7%

                                                                            \[x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                                                                          2. Add Preprocessing
                                                                          3. Taylor expanded in x1 around inf

                                                                            \[\leadsto x1 + \color{blue}{6 \cdot {x1}^{4}} \]
                                                                          4. Step-by-step derivation
                                                                            1. *-commutativeN/A

                                                                              \[\leadsto x1 + \color{blue}{{x1}^{4} \cdot 6} \]
                                                                            2. lower-*.f64N/A

                                                                              \[\leadsto x1 + \color{blue}{{x1}^{4} \cdot 6} \]
                                                                            3. lower-pow.f6499.9

                                                                              \[\leadsto x1 + \color{blue}{{x1}^{4}} \cdot 6 \]
                                                                          5. Applied rewrites99.9%

                                                                            \[\leadsto x1 + \color{blue}{{x1}^{4} \cdot 6} \]
                                                                          6. Step-by-step derivation
                                                                            1. Applied rewrites99.9%

                                                                              \[\leadsto x1 + \left(\left(\left(x1 \cdot x1\right) \cdot x1\right) \cdot x1\right) \cdot \color{blue}{6} \]
                                                                            2. Step-by-step derivation
                                                                              1. Applied rewrites100.0%

                                                                                \[\leadsto x1 + \left(x1 \cdot x1\right) \cdot \color{blue}{\left(x1 \cdot \left(6 \cdot x1\right)\right)} \]
                                                                            3. Recombined 3 regimes into one program.
                                                                            4. Final simplification95.5%

                                                                              \[\leadsto \begin{array}{l} \mathbf{if}\;x1 \leq -22000:\\ \;\;\;\;\left(\left(\mathsf{fma}\left(\frac{\mathsf{fma}\left(2, x2, -3\right)}{x1 \cdot x1}, 4, \frac{9}{x1 \cdot x1} + 6\right) - \frac{3}{x1}\right) \cdot \left(x1 \cdot x1\right)\right) \cdot \left(x1 \cdot x1\right) + x1\\ \mathbf{elif}\;x1 \leq 5 \cdot 10^{+46}:\\ \;\;\;\;\left(\left(\left(\left(\frac{x1}{\mathsf{fma}\left(x1, x1, 1\right)} \cdot 8\right) \cdot x2\right) \cdot x2 + x1\right) + \frac{\left(\left(3 \cdot x1\right) \cdot x1 - x2 \cdot 2\right) - x1}{x1 \cdot x1 - -1} \cdot 3\right) + x1\\ \mathbf{else}:\\ \;\;\;\;\left(\left(6 \cdot x1\right) \cdot x1\right) \cdot \left(x1 \cdot x1\right) + x1\\ \end{array} \]
                                                                            5. Add Preprocessing

                                                                            Alternative 9: 95.1% accurate, 3.3× speedup?

                                                                            \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;x1 \leq -53000000000:\\ \;\;\;\;\left(\left(\mathsf{fma}\left(\frac{\mathsf{fma}\left(2, x2, -3\right)}{x1 \cdot x1}, 4, \frac{9}{x1 \cdot x1} + 6\right) - \frac{3}{x1}\right) \cdot \left(x1 \cdot x1\right)\right) \cdot \left(x1 \cdot x1\right) + x1\\ \mathbf{elif}\;x1 \leq 10^{+29}:\\ \;\;\;\;\mathsf{fma}\left(\mathsf{fma}\left(x2 \cdot x1, 8, \mathsf{fma}\left(\mathsf{fma}\left(x1, 12, -12\right), x1, -6\right)\right), x2, \mathsf{fma}\left(x1, 9, -2\right) \cdot x1\right) + x1\\ \mathbf{else}:\\ \;\;\;\;\left(\mathsf{fma}\left(\mathsf{fma}\left(6, x1, -3\right), x1, \mathsf{fma}\left(\mathsf{fma}\left(2, x2, -3\right), 4, 9\right)\right) \cdot x1\right) \cdot x1 + x1\\ \end{array} \end{array} \]
                                                                            (FPCore (x1 x2)
                                                                             :precision binary64
                                                                             (if (<= x1 -53000000000.0)
                                                                               (+
                                                                                (*
                                                                                 (*
                                                                                  (-
                                                                                   (fma (/ (fma 2.0 x2 -3.0) (* x1 x1)) 4.0 (+ (/ 9.0 (* x1 x1)) 6.0))
                                                                                   (/ 3.0 x1))
                                                                                  (* x1 x1))
                                                                                 (* x1 x1))
                                                                                x1)
                                                                               (if (<= x1 1e+29)
                                                                                 (+
                                                                                  (fma
                                                                                   (fma (* x2 x1) 8.0 (fma (fma x1 12.0 -12.0) x1 -6.0))
                                                                                   x2
                                                                                   (* (fma x1 9.0 -2.0) x1))
                                                                                  x1)
                                                                                 (+
                                                                                  (* (* (fma (fma 6.0 x1 -3.0) x1 (fma (fma 2.0 x2 -3.0) 4.0 9.0)) x1) x1)
                                                                                  x1))))
                                                                            double code(double x1, double x2) {
                                                                            	double tmp;
                                                                            	if (x1 <= -53000000000.0) {
                                                                            		tmp = (((fma((fma(2.0, x2, -3.0) / (x1 * x1)), 4.0, ((9.0 / (x1 * x1)) + 6.0)) - (3.0 / x1)) * (x1 * x1)) * (x1 * x1)) + x1;
                                                                            	} else if (x1 <= 1e+29) {
                                                                            		tmp = fma(fma((x2 * x1), 8.0, fma(fma(x1, 12.0, -12.0), x1, -6.0)), x2, (fma(x1, 9.0, -2.0) * x1)) + x1;
                                                                            	} else {
                                                                            		tmp = ((fma(fma(6.0, x1, -3.0), x1, fma(fma(2.0, x2, -3.0), 4.0, 9.0)) * x1) * x1) + x1;
                                                                            	}
                                                                            	return tmp;
                                                                            }
                                                                            
                                                                            function code(x1, x2)
                                                                            	tmp = 0.0
                                                                            	if (x1 <= -53000000000.0)
                                                                            		tmp = Float64(Float64(Float64(Float64(fma(Float64(fma(2.0, x2, -3.0) / Float64(x1 * x1)), 4.0, Float64(Float64(9.0 / Float64(x1 * x1)) + 6.0)) - Float64(3.0 / x1)) * Float64(x1 * x1)) * Float64(x1 * x1)) + x1);
                                                                            	elseif (x1 <= 1e+29)
                                                                            		tmp = Float64(fma(fma(Float64(x2 * x1), 8.0, fma(fma(x1, 12.0, -12.0), x1, -6.0)), x2, Float64(fma(x1, 9.0, -2.0) * x1)) + x1);
                                                                            	else
                                                                            		tmp = Float64(Float64(Float64(fma(fma(6.0, x1, -3.0), x1, fma(fma(2.0, x2, -3.0), 4.0, 9.0)) * x1) * x1) + x1);
                                                                            	end
                                                                            	return tmp
                                                                            end
                                                                            
                                                                            code[x1_, x2_] := If[LessEqual[x1, -53000000000.0], N[(N[(N[(N[(N[(N[(N[(2.0 * x2 + -3.0), $MachinePrecision] / N[(x1 * x1), $MachinePrecision]), $MachinePrecision] * 4.0 + N[(N[(9.0 / N[(x1 * x1), $MachinePrecision]), $MachinePrecision] + 6.0), $MachinePrecision]), $MachinePrecision] - N[(3.0 / x1), $MachinePrecision]), $MachinePrecision] * N[(x1 * x1), $MachinePrecision]), $MachinePrecision] * N[(x1 * x1), $MachinePrecision]), $MachinePrecision] + x1), $MachinePrecision], If[LessEqual[x1, 1e+29], N[(N[(N[(N[(x2 * x1), $MachinePrecision] * 8.0 + N[(N[(x1 * 12.0 + -12.0), $MachinePrecision] * x1 + -6.0), $MachinePrecision]), $MachinePrecision] * x2 + N[(N[(x1 * 9.0 + -2.0), $MachinePrecision] * x1), $MachinePrecision]), $MachinePrecision] + x1), $MachinePrecision], N[(N[(N[(N[(N[(6.0 * x1 + -3.0), $MachinePrecision] * x1 + N[(N[(2.0 * x2 + -3.0), $MachinePrecision] * 4.0 + 9.0), $MachinePrecision]), $MachinePrecision] * x1), $MachinePrecision] * x1), $MachinePrecision] + x1), $MachinePrecision]]]
                                                                            
                                                                            \begin{array}{l}
                                                                            
                                                                            \\
                                                                            \begin{array}{l}
                                                                            \mathbf{if}\;x1 \leq -53000000000:\\
                                                                            \;\;\;\;\left(\left(\mathsf{fma}\left(\frac{\mathsf{fma}\left(2, x2, -3\right)}{x1 \cdot x1}, 4, \frac{9}{x1 \cdot x1} + 6\right) - \frac{3}{x1}\right) \cdot \left(x1 \cdot x1\right)\right) \cdot \left(x1 \cdot x1\right) + x1\\
                                                                            
                                                                            \mathbf{elif}\;x1 \leq 10^{+29}:\\
                                                                            \;\;\;\;\mathsf{fma}\left(\mathsf{fma}\left(x2 \cdot x1, 8, \mathsf{fma}\left(\mathsf{fma}\left(x1, 12, -12\right), x1, -6\right)\right), x2, \mathsf{fma}\left(x1, 9, -2\right) \cdot x1\right) + x1\\
                                                                            
                                                                            \mathbf{else}:\\
                                                                            \;\;\;\;\left(\mathsf{fma}\left(\mathsf{fma}\left(6, x1, -3\right), x1, \mathsf{fma}\left(\mathsf{fma}\left(2, x2, -3\right), 4, 9\right)\right) \cdot x1\right) \cdot x1 + x1\\
                                                                            
                                                                            
                                                                            \end{array}
                                                                            \end{array}
                                                                            
                                                                            Derivation
                                                                            1. Split input into 3 regimes
                                                                            2. if x1 < -5.3e10

                                                                              1. Initial program 28.0%

                                                                                \[x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                                                                              2. Add Preprocessing
                                                                              3. Taylor expanded in x1 around inf

                                                                                \[\leadsto x1 + \color{blue}{{x1}^{4} \cdot \left(\left(6 + \left(4 \cdot \frac{2 \cdot x2 - 3}{{x1}^{2}} + \frac{9}{{x1}^{2}}\right)\right) - 3 \cdot \frac{1}{x1}\right)} \]
                                                                              4. Step-by-step derivation
                                                                                1. *-commutativeN/A

                                                                                  \[\leadsto x1 + \color{blue}{\left(\left(6 + \left(4 \cdot \frac{2 \cdot x2 - 3}{{x1}^{2}} + \frac{9}{{x1}^{2}}\right)\right) - 3 \cdot \frac{1}{x1}\right) \cdot {x1}^{4}} \]
                                                                                2. lower-*.f64N/A

                                                                                  \[\leadsto x1 + \color{blue}{\left(\left(6 + \left(4 \cdot \frac{2 \cdot x2 - 3}{{x1}^{2}} + \frac{9}{{x1}^{2}}\right)\right) - 3 \cdot \frac{1}{x1}\right) \cdot {x1}^{4}} \]
                                                                              5. Applied rewrites95.8%

                                                                                \[\leadsto x1 + \color{blue}{\left(\mathsf{fma}\left(\frac{\mathsf{fma}\left(2, x2, -3\right)}{x1 \cdot x1}, 4, \frac{9}{x1 \cdot x1} + 6\right) - \frac{3}{x1}\right) \cdot {x1}^{4}} \]
                                                                              6. Step-by-step derivation
                                                                                1. Applied rewrites95.8%

                                                                                  \[\leadsto x1 + \left(\left(\mathsf{fma}\left(\frac{\mathsf{fma}\left(2, x2, -3\right)}{x1 \cdot x1}, 4, \frac{9}{x1 \cdot x1} + 6\right) - \frac{3}{x1}\right) \cdot \left(x1 \cdot x1\right)\right) \cdot \color{blue}{\left(x1 \cdot x1\right)} \]

                                                                                if -5.3e10 < x1 < 9.99999999999999914e28

                                                                                1. Initial program 99.5%

                                                                                  \[x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                                                                                2. Add Preprocessing
                                                                                3. Taylor expanded in x1 around 0

                                                                                  \[\leadsto x1 + \color{blue}{\left(-6 \cdot x2 + x1 \cdot \left(\left(4 \cdot \left(x2 \cdot \left(2 \cdot x2 - 3\right)\right) + x1 \cdot \left(\left(2 \cdot \left(-2 \cdot x2 + -1 \cdot \left(2 \cdot x2 - 3\right)\right) + \left(3 \cdot \left(3 - -2 \cdot x2\right) + \left(6 \cdot x2 + 8 \cdot x2\right)\right)\right) - 6\right)\right) - 2\right)\right)} \]
                                                                                4. Applied rewrites85.4%

                                                                                  \[\leadsto x1 + \color{blue}{\mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(-4, x2, \mathsf{fma}\left(\mathsf{fma}\left(-2, x2, 3\right), 2, \mathsf{fma}\left(\mathsf{fma}\left(2, x2, 3\right), 3, \mathsf{fma}\left(14, x2, -6\right)\right)\right)\right), x1, \mathsf{fma}\left(\mathsf{fma}\left(2, x2, -3\right) \cdot 4, x2, -2\right)\right), x1, -6 \cdot x2\right)} \]
                                                                                5. Taylor expanded in x2 around 0

                                                                                  \[\leadsto x1 + \left(x1 \cdot \left(9 \cdot x1 - 2\right) + \color{blue}{x2 \cdot \left(\left(8 \cdot \left(x1 \cdot x2\right) + x1 \cdot \left(12 \cdot x1 - 12\right)\right) - 6\right)}\right) \]
                                                                                6. Step-by-step derivation
                                                                                  1. Applied rewrites95.8%

                                                                                    \[\leadsto x1 + \mathsf{fma}\left(\mathsf{fma}\left(x1 \cdot x2, 8, \mathsf{fma}\left(\mathsf{fma}\left(x1, 12, -12\right), x1, -6\right)\right), \color{blue}{x2}, \mathsf{fma}\left(x1, 9, -2\right) \cdot x1\right) \]

                                                                                  if 9.99999999999999914e28 < x1

                                                                                  1. Initial program 38.9%

                                                                                    \[x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                                                                                  2. Add Preprocessing
                                                                                  3. Taylor expanded in x1 around inf

                                                                                    \[\leadsto x1 + \color{blue}{{x1}^{4} \cdot \left(\left(6 + \left(4 \cdot \frac{2 \cdot x2 - 3}{{x1}^{2}} + \frac{9}{{x1}^{2}}\right)\right) - 3 \cdot \frac{1}{x1}\right)} \]
                                                                                  4. Step-by-step derivation
                                                                                    1. *-commutativeN/A

                                                                                      \[\leadsto x1 + \color{blue}{\left(\left(6 + \left(4 \cdot \frac{2 \cdot x2 - 3}{{x1}^{2}} + \frac{9}{{x1}^{2}}\right)\right) - 3 \cdot \frac{1}{x1}\right) \cdot {x1}^{4}} \]
                                                                                    2. lower-*.f64N/A

                                                                                      \[\leadsto x1 + \color{blue}{\left(\left(6 + \left(4 \cdot \frac{2 \cdot x2 - 3}{{x1}^{2}} + \frac{9}{{x1}^{2}}\right)\right) - 3 \cdot \frac{1}{x1}\right) \cdot {x1}^{4}} \]
                                                                                  5. Applied rewrites94.0%

                                                                                    \[\leadsto x1 + \color{blue}{\left(\mathsf{fma}\left(\frac{\mathsf{fma}\left(2, x2, -3\right)}{x1 \cdot x1}, 4, \frac{9}{x1 \cdot x1} + 6\right) - \frac{3}{x1}\right) \cdot {x1}^{4}} \]
                                                                                  6. Taylor expanded in x1 around 0

                                                                                    \[\leadsto x1 + {x1}^{2} \cdot \color{blue}{\left(9 + \left(4 \cdot \left(2 \cdot x2 - 3\right) + x1 \cdot \left(6 \cdot x1 - 3\right)\right)\right)} \]
                                                                                  7. Step-by-step derivation
                                                                                    1. Applied rewrites93.9%

                                                                                      \[\leadsto x1 + \left(\mathsf{fma}\left(\mathsf{fma}\left(6, x1, -3\right), x1, \mathsf{fma}\left(\mathsf{fma}\left(2, x2, -3\right), 4, 9\right)\right) \cdot x1\right) \cdot \color{blue}{x1} \]
                                                                                  8. Recombined 3 regimes into one program.
                                                                                  9. Final simplification95.3%

                                                                                    \[\leadsto \begin{array}{l} \mathbf{if}\;x1 \leq -53000000000:\\ \;\;\;\;\left(\left(\mathsf{fma}\left(\frac{\mathsf{fma}\left(2, x2, -3\right)}{x1 \cdot x1}, 4, \frac{9}{x1 \cdot x1} + 6\right) - \frac{3}{x1}\right) \cdot \left(x1 \cdot x1\right)\right) \cdot \left(x1 \cdot x1\right) + x1\\ \mathbf{elif}\;x1 \leq 10^{+29}:\\ \;\;\;\;\mathsf{fma}\left(\mathsf{fma}\left(x2 \cdot x1, 8, \mathsf{fma}\left(\mathsf{fma}\left(x1, 12, -12\right), x1, -6\right)\right), x2, \mathsf{fma}\left(x1, 9, -2\right) \cdot x1\right) + x1\\ \mathbf{else}:\\ \;\;\;\;\left(\mathsf{fma}\left(\mathsf{fma}\left(6, x1, -3\right), x1, \mathsf{fma}\left(\mathsf{fma}\left(2, x2, -3\right), 4, 9\right)\right) \cdot x1\right) \cdot x1 + x1\\ \end{array} \]
                                                                                  10. Add Preprocessing

                                                                                  Alternative 10: 95.1% accurate, 5.3× speedup?

                                                                                  \[\begin{array}{l} \\ \begin{array}{l} t_0 := \left(\mathsf{fma}\left(\mathsf{fma}\left(6, x1, -3\right), x1, \mathsf{fma}\left(\mathsf{fma}\left(2, x2, -3\right), 4, 9\right)\right) \cdot x1\right) \cdot x1 + x1\\ \mathbf{if}\;x1 \leq -53000000000:\\ \;\;\;\;t\_0\\ \mathbf{elif}\;x1 \leq 10^{+29}:\\ \;\;\;\;\mathsf{fma}\left(\mathsf{fma}\left(x2 \cdot x1, 8, \mathsf{fma}\left(\mathsf{fma}\left(x1, 12, -12\right), x1, -6\right)\right), x2, \mathsf{fma}\left(x1, 9, -2\right) \cdot x1\right) + x1\\ \mathbf{else}:\\ \;\;\;\;t\_0\\ \end{array} \end{array} \]
                                                                                  (FPCore (x1 x2)
                                                                                   :precision binary64
                                                                                   (let* ((t_0
                                                                                           (+
                                                                                            (*
                                                                                             (* (fma (fma 6.0 x1 -3.0) x1 (fma (fma 2.0 x2 -3.0) 4.0 9.0)) x1)
                                                                                             x1)
                                                                                            x1)))
                                                                                     (if (<= x1 -53000000000.0)
                                                                                       t_0
                                                                                       (if (<= x1 1e+29)
                                                                                         (+
                                                                                          (fma
                                                                                           (fma (* x2 x1) 8.0 (fma (fma x1 12.0 -12.0) x1 -6.0))
                                                                                           x2
                                                                                           (* (fma x1 9.0 -2.0) x1))
                                                                                          x1)
                                                                                         t_0))))
                                                                                  double code(double x1, double x2) {
                                                                                  	double t_0 = ((fma(fma(6.0, x1, -3.0), x1, fma(fma(2.0, x2, -3.0), 4.0, 9.0)) * x1) * x1) + x1;
                                                                                  	double tmp;
                                                                                  	if (x1 <= -53000000000.0) {
                                                                                  		tmp = t_0;
                                                                                  	} else if (x1 <= 1e+29) {
                                                                                  		tmp = fma(fma((x2 * x1), 8.0, fma(fma(x1, 12.0, -12.0), x1, -6.0)), x2, (fma(x1, 9.0, -2.0) * x1)) + x1;
                                                                                  	} else {
                                                                                  		tmp = t_0;
                                                                                  	}
                                                                                  	return tmp;
                                                                                  }
                                                                                  
                                                                                  function code(x1, x2)
                                                                                  	t_0 = Float64(Float64(Float64(fma(fma(6.0, x1, -3.0), x1, fma(fma(2.0, x2, -3.0), 4.0, 9.0)) * x1) * x1) + x1)
                                                                                  	tmp = 0.0
                                                                                  	if (x1 <= -53000000000.0)
                                                                                  		tmp = t_0;
                                                                                  	elseif (x1 <= 1e+29)
                                                                                  		tmp = Float64(fma(fma(Float64(x2 * x1), 8.0, fma(fma(x1, 12.0, -12.0), x1, -6.0)), x2, Float64(fma(x1, 9.0, -2.0) * x1)) + x1);
                                                                                  	else
                                                                                  		tmp = t_0;
                                                                                  	end
                                                                                  	return tmp
                                                                                  end
                                                                                  
                                                                                  code[x1_, x2_] := Block[{t$95$0 = N[(N[(N[(N[(N[(6.0 * x1 + -3.0), $MachinePrecision] * x1 + N[(N[(2.0 * x2 + -3.0), $MachinePrecision] * 4.0 + 9.0), $MachinePrecision]), $MachinePrecision] * x1), $MachinePrecision] * x1), $MachinePrecision] + x1), $MachinePrecision]}, If[LessEqual[x1, -53000000000.0], t$95$0, If[LessEqual[x1, 1e+29], N[(N[(N[(N[(x2 * x1), $MachinePrecision] * 8.0 + N[(N[(x1 * 12.0 + -12.0), $MachinePrecision] * x1 + -6.0), $MachinePrecision]), $MachinePrecision] * x2 + N[(N[(x1 * 9.0 + -2.0), $MachinePrecision] * x1), $MachinePrecision]), $MachinePrecision] + x1), $MachinePrecision], t$95$0]]]
                                                                                  
                                                                                  \begin{array}{l}
                                                                                  
                                                                                  \\
                                                                                  \begin{array}{l}
                                                                                  t_0 := \left(\mathsf{fma}\left(\mathsf{fma}\left(6, x1, -3\right), x1, \mathsf{fma}\left(\mathsf{fma}\left(2, x2, -3\right), 4, 9\right)\right) \cdot x1\right) \cdot x1 + x1\\
                                                                                  \mathbf{if}\;x1 \leq -53000000000:\\
                                                                                  \;\;\;\;t\_0\\
                                                                                  
                                                                                  \mathbf{elif}\;x1 \leq 10^{+29}:\\
                                                                                  \;\;\;\;\mathsf{fma}\left(\mathsf{fma}\left(x2 \cdot x1, 8, \mathsf{fma}\left(\mathsf{fma}\left(x1, 12, -12\right), x1, -6\right)\right), x2, \mathsf{fma}\left(x1, 9, -2\right) \cdot x1\right) + x1\\
                                                                                  
                                                                                  \mathbf{else}:\\
                                                                                  \;\;\;\;t\_0\\
                                                                                  
                                                                                  
                                                                                  \end{array}
                                                                                  \end{array}
                                                                                  
                                                                                  Derivation
                                                                                  1. Split input into 2 regimes
                                                                                  2. if x1 < -5.3e10 or 9.99999999999999914e28 < x1

                                                                                    1. Initial program 33.5%

                                                                                      \[x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                                                                                    2. Add Preprocessing
                                                                                    3. Taylor expanded in x1 around inf

                                                                                      \[\leadsto x1 + \color{blue}{{x1}^{4} \cdot \left(\left(6 + \left(4 \cdot \frac{2 \cdot x2 - 3}{{x1}^{2}} + \frac{9}{{x1}^{2}}\right)\right) - 3 \cdot \frac{1}{x1}\right)} \]
                                                                                    4. Step-by-step derivation
                                                                                      1. *-commutativeN/A

                                                                                        \[\leadsto x1 + \color{blue}{\left(\left(6 + \left(4 \cdot \frac{2 \cdot x2 - 3}{{x1}^{2}} + \frac{9}{{x1}^{2}}\right)\right) - 3 \cdot \frac{1}{x1}\right) \cdot {x1}^{4}} \]
                                                                                      2. lower-*.f64N/A

                                                                                        \[\leadsto x1 + \color{blue}{\left(\left(6 + \left(4 \cdot \frac{2 \cdot x2 - 3}{{x1}^{2}} + \frac{9}{{x1}^{2}}\right)\right) - 3 \cdot \frac{1}{x1}\right) \cdot {x1}^{4}} \]
                                                                                    5. Applied rewrites94.9%

                                                                                      \[\leadsto x1 + \color{blue}{\left(\mathsf{fma}\left(\frac{\mathsf{fma}\left(2, x2, -3\right)}{x1 \cdot x1}, 4, \frac{9}{x1 \cdot x1} + 6\right) - \frac{3}{x1}\right) \cdot {x1}^{4}} \]
                                                                                    6. Taylor expanded in x1 around 0

                                                                                      \[\leadsto x1 + {x1}^{2} \cdot \color{blue}{\left(9 + \left(4 \cdot \left(2 \cdot x2 - 3\right) + x1 \cdot \left(6 \cdot x1 - 3\right)\right)\right)} \]
                                                                                    7. Step-by-step derivation
                                                                                      1. Applied rewrites94.9%

                                                                                        \[\leadsto x1 + \left(\mathsf{fma}\left(\mathsf{fma}\left(6, x1, -3\right), x1, \mathsf{fma}\left(\mathsf{fma}\left(2, x2, -3\right), 4, 9\right)\right) \cdot x1\right) \cdot \color{blue}{x1} \]

                                                                                      if -5.3e10 < x1 < 9.99999999999999914e28

                                                                                      1. Initial program 99.5%

                                                                                        \[x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                                                                                      2. Add Preprocessing
                                                                                      3. Taylor expanded in x1 around 0

                                                                                        \[\leadsto x1 + \color{blue}{\left(-6 \cdot x2 + x1 \cdot \left(\left(4 \cdot \left(x2 \cdot \left(2 \cdot x2 - 3\right)\right) + x1 \cdot \left(\left(2 \cdot \left(-2 \cdot x2 + -1 \cdot \left(2 \cdot x2 - 3\right)\right) + \left(3 \cdot \left(3 - -2 \cdot x2\right) + \left(6 \cdot x2 + 8 \cdot x2\right)\right)\right) - 6\right)\right) - 2\right)\right)} \]
                                                                                      4. Applied rewrites85.4%

                                                                                        \[\leadsto x1 + \color{blue}{\mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(-4, x2, \mathsf{fma}\left(\mathsf{fma}\left(-2, x2, 3\right), 2, \mathsf{fma}\left(\mathsf{fma}\left(2, x2, 3\right), 3, \mathsf{fma}\left(14, x2, -6\right)\right)\right)\right), x1, \mathsf{fma}\left(\mathsf{fma}\left(2, x2, -3\right) \cdot 4, x2, -2\right)\right), x1, -6 \cdot x2\right)} \]
                                                                                      5. Taylor expanded in x2 around 0

                                                                                        \[\leadsto x1 + \left(x1 \cdot \left(9 \cdot x1 - 2\right) + \color{blue}{x2 \cdot \left(\left(8 \cdot \left(x1 \cdot x2\right) + x1 \cdot \left(12 \cdot x1 - 12\right)\right) - 6\right)}\right) \]
                                                                                      6. Step-by-step derivation
                                                                                        1. Applied rewrites95.8%

                                                                                          \[\leadsto x1 + \mathsf{fma}\left(\mathsf{fma}\left(x1 \cdot x2, 8, \mathsf{fma}\left(\mathsf{fma}\left(x1, 12, -12\right), x1, -6\right)\right), \color{blue}{x2}, \mathsf{fma}\left(x1, 9, -2\right) \cdot x1\right) \]
                                                                                      7. Recombined 2 regimes into one program.
                                                                                      8. Final simplification95.3%

                                                                                        \[\leadsto \begin{array}{l} \mathbf{if}\;x1 \leq -53000000000:\\ \;\;\;\;\left(\mathsf{fma}\left(\mathsf{fma}\left(6, x1, -3\right), x1, \mathsf{fma}\left(\mathsf{fma}\left(2, x2, -3\right), 4, 9\right)\right) \cdot x1\right) \cdot x1 + x1\\ \mathbf{elif}\;x1 \leq 10^{+29}:\\ \;\;\;\;\mathsf{fma}\left(\mathsf{fma}\left(x2 \cdot x1, 8, \mathsf{fma}\left(\mathsf{fma}\left(x1, 12, -12\right), x1, -6\right)\right), x2, \mathsf{fma}\left(x1, 9, -2\right) \cdot x1\right) + x1\\ \mathbf{else}:\\ \;\;\;\;\left(\mathsf{fma}\left(\mathsf{fma}\left(6, x1, -3\right), x1, \mathsf{fma}\left(\mathsf{fma}\left(2, x2, -3\right), 4, 9\right)\right) \cdot x1\right) \cdot x1 + x1\\ \end{array} \]
                                                                                      9. Add Preprocessing

                                                                                      Alternative 11: 88.7% accurate, 6.0× speedup?

                                                                                      \[\begin{array}{l} \\ \begin{array}{l} t_0 := \left(\mathsf{fma}\left(\mathsf{fma}\left(6, x1, -3\right), x1, \mathsf{fma}\left(\mathsf{fma}\left(2, x2, -3\right), 4, 9\right)\right) \cdot x1\right) \cdot x1 + x1\\ \mathbf{if}\;x1 \leq -53000000000:\\ \;\;\;\;t\_0\\ \mathbf{elif}\;x1 \leq 10^{+29}:\\ \;\;\;\;\mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(2, x2, -3\right) \cdot 4, x2, -2\right), x1, -6 \cdot x2\right) + x1\\ \mathbf{else}:\\ \;\;\;\;t\_0\\ \end{array} \end{array} \]
                                                                                      (FPCore (x1 x2)
                                                                                       :precision binary64
                                                                                       (let* ((t_0
                                                                                               (+
                                                                                                (*
                                                                                                 (* (fma (fma 6.0 x1 -3.0) x1 (fma (fma 2.0 x2 -3.0) 4.0 9.0)) x1)
                                                                                                 x1)
                                                                                                x1)))
                                                                                         (if (<= x1 -53000000000.0)
                                                                                           t_0
                                                                                           (if (<= x1 1e+29)
                                                                                             (+ (fma (fma (* (fma 2.0 x2 -3.0) 4.0) x2 -2.0) x1 (* -6.0 x2)) x1)
                                                                                             t_0))))
                                                                                      double code(double x1, double x2) {
                                                                                      	double t_0 = ((fma(fma(6.0, x1, -3.0), x1, fma(fma(2.0, x2, -3.0), 4.0, 9.0)) * x1) * x1) + x1;
                                                                                      	double tmp;
                                                                                      	if (x1 <= -53000000000.0) {
                                                                                      		tmp = t_0;
                                                                                      	} else if (x1 <= 1e+29) {
                                                                                      		tmp = fma(fma((fma(2.0, x2, -3.0) * 4.0), x2, -2.0), x1, (-6.0 * x2)) + x1;
                                                                                      	} else {
                                                                                      		tmp = t_0;
                                                                                      	}
                                                                                      	return tmp;
                                                                                      }
                                                                                      
                                                                                      function code(x1, x2)
                                                                                      	t_0 = Float64(Float64(Float64(fma(fma(6.0, x1, -3.0), x1, fma(fma(2.0, x2, -3.0), 4.0, 9.0)) * x1) * x1) + x1)
                                                                                      	tmp = 0.0
                                                                                      	if (x1 <= -53000000000.0)
                                                                                      		tmp = t_0;
                                                                                      	elseif (x1 <= 1e+29)
                                                                                      		tmp = Float64(fma(fma(Float64(fma(2.0, x2, -3.0) * 4.0), x2, -2.0), x1, Float64(-6.0 * x2)) + x1);
                                                                                      	else
                                                                                      		tmp = t_0;
                                                                                      	end
                                                                                      	return tmp
                                                                                      end
                                                                                      
                                                                                      code[x1_, x2_] := Block[{t$95$0 = N[(N[(N[(N[(N[(6.0 * x1 + -3.0), $MachinePrecision] * x1 + N[(N[(2.0 * x2 + -3.0), $MachinePrecision] * 4.0 + 9.0), $MachinePrecision]), $MachinePrecision] * x1), $MachinePrecision] * x1), $MachinePrecision] + x1), $MachinePrecision]}, If[LessEqual[x1, -53000000000.0], t$95$0, If[LessEqual[x1, 1e+29], N[(N[(N[(N[(N[(2.0 * x2 + -3.0), $MachinePrecision] * 4.0), $MachinePrecision] * x2 + -2.0), $MachinePrecision] * x1 + N[(-6.0 * x2), $MachinePrecision]), $MachinePrecision] + x1), $MachinePrecision], t$95$0]]]
                                                                                      
                                                                                      \begin{array}{l}
                                                                                      
                                                                                      \\
                                                                                      \begin{array}{l}
                                                                                      t_0 := \left(\mathsf{fma}\left(\mathsf{fma}\left(6, x1, -3\right), x1, \mathsf{fma}\left(\mathsf{fma}\left(2, x2, -3\right), 4, 9\right)\right) \cdot x1\right) \cdot x1 + x1\\
                                                                                      \mathbf{if}\;x1 \leq -53000000000:\\
                                                                                      \;\;\;\;t\_0\\
                                                                                      
                                                                                      \mathbf{elif}\;x1 \leq 10^{+29}:\\
                                                                                      \;\;\;\;\mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(2, x2, -3\right) \cdot 4, x2, -2\right), x1, -6 \cdot x2\right) + x1\\
                                                                                      
                                                                                      \mathbf{else}:\\
                                                                                      \;\;\;\;t\_0\\
                                                                                      
                                                                                      
                                                                                      \end{array}
                                                                                      \end{array}
                                                                                      
                                                                                      Derivation
                                                                                      1. Split input into 2 regimes
                                                                                      2. if x1 < -5.3e10 or 9.99999999999999914e28 < x1

                                                                                        1. Initial program 33.5%

                                                                                          \[x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                                                                                        2. Add Preprocessing
                                                                                        3. Taylor expanded in x1 around inf

                                                                                          \[\leadsto x1 + \color{blue}{{x1}^{4} \cdot \left(\left(6 + \left(4 \cdot \frac{2 \cdot x2 - 3}{{x1}^{2}} + \frac{9}{{x1}^{2}}\right)\right) - 3 \cdot \frac{1}{x1}\right)} \]
                                                                                        4. Step-by-step derivation
                                                                                          1. *-commutativeN/A

                                                                                            \[\leadsto x1 + \color{blue}{\left(\left(6 + \left(4 \cdot \frac{2 \cdot x2 - 3}{{x1}^{2}} + \frac{9}{{x1}^{2}}\right)\right) - 3 \cdot \frac{1}{x1}\right) \cdot {x1}^{4}} \]
                                                                                          2. lower-*.f64N/A

                                                                                            \[\leadsto x1 + \color{blue}{\left(\left(6 + \left(4 \cdot \frac{2 \cdot x2 - 3}{{x1}^{2}} + \frac{9}{{x1}^{2}}\right)\right) - 3 \cdot \frac{1}{x1}\right) \cdot {x1}^{4}} \]
                                                                                        5. Applied rewrites94.9%

                                                                                          \[\leadsto x1 + \color{blue}{\left(\mathsf{fma}\left(\frac{\mathsf{fma}\left(2, x2, -3\right)}{x1 \cdot x1}, 4, \frac{9}{x1 \cdot x1} + 6\right) - \frac{3}{x1}\right) \cdot {x1}^{4}} \]
                                                                                        6. Taylor expanded in x1 around 0

                                                                                          \[\leadsto x1 + {x1}^{2} \cdot \color{blue}{\left(9 + \left(4 \cdot \left(2 \cdot x2 - 3\right) + x1 \cdot \left(6 \cdot x1 - 3\right)\right)\right)} \]
                                                                                        7. Step-by-step derivation
                                                                                          1. Applied rewrites94.9%

                                                                                            \[\leadsto x1 + \left(\mathsf{fma}\left(\mathsf{fma}\left(6, x1, -3\right), x1, \mathsf{fma}\left(\mathsf{fma}\left(2, x2, -3\right), 4, 9\right)\right) \cdot x1\right) \cdot \color{blue}{x1} \]

                                                                                          if -5.3e10 < x1 < 9.99999999999999914e28

                                                                                          1. Initial program 99.5%

                                                                                            \[x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                                                                                          2. Add Preprocessing
                                                                                          3. Taylor expanded in x1 around 0

                                                                                            \[\leadsto x1 + \color{blue}{\left(-6 \cdot x2 + x1 \cdot \left(4 \cdot \left(x2 \cdot \left(2 \cdot x2 - 3\right)\right) - 2\right)\right)} \]
                                                                                          4. Step-by-step derivation
                                                                                            1. +-commutativeN/A

                                                                                              \[\leadsto x1 + \color{blue}{\left(x1 \cdot \left(4 \cdot \left(x2 \cdot \left(2 \cdot x2 - 3\right)\right) - 2\right) + -6 \cdot x2\right)} \]
                                                                                            2. *-commutativeN/A

                                                                                              \[\leadsto x1 + \left(\color{blue}{\left(4 \cdot \left(x2 \cdot \left(2 \cdot x2 - 3\right)\right) - 2\right) \cdot x1} + -6 \cdot x2\right) \]
                                                                                            3. lower-fma.f64N/A

                                                                                              \[\leadsto x1 + \color{blue}{\mathsf{fma}\left(4 \cdot \left(x2 \cdot \left(2 \cdot x2 - 3\right)\right) - 2, x1, -6 \cdot x2\right)} \]
                                                                                            4. sub-negN/A

                                                                                              \[\leadsto x1 + \mathsf{fma}\left(\color{blue}{4 \cdot \left(x2 \cdot \left(2 \cdot x2 - 3\right)\right) + \left(\mathsf{neg}\left(2\right)\right)}, x1, -6 \cdot x2\right) \]
                                                                                            5. *-commutativeN/A

                                                                                              \[\leadsto x1 + \mathsf{fma}\left(4 \cdot \color{blue}{\left(\left(2 \cdot x2 - 3\right) \cdot x2\right)} + \left(\mathsf{neg}\left(2\right)\right), x1, -6 \cdot x2\right) \]
                                                                                            6. associate-*r*N/A

                                                                                              \[\leadsto x1 + \mathsf{fma}\left(\color{blue}{\left(4 \cdot \left(2 \cdot x2 - 3\right)\right) \cdot x2} + \left(\mathsf{neg}\left(2\right)\right), x1, -6 \cdot x2\right) \]
                                                                                            7. metadata-evalN/A

                                                                                              \[\leadsto x1 + \mathsf{fma}\left(\left(4 \cdot \left(2 \cdot x2 - 3\right)\right) \cdot x2 + \color{blue}{-2}, x1, -6 \cdot x2\right) \]
                                                                                            8. lower-fma.f64N/A

                                                                                              \[\leadsto x1 + \mathsf{fma}\left(\color{blue}{\mathsf{fma}\left(4 \cdot \left(2 \cdot x2 - 3\right), x2, -2\right)}, x1, -6 \cdot x2\right) \]
                                                                                            9. *-commutativeN/A

                                                                                              \[\leadsto x1 + \mathsf{fma}\left(\mathsf{fma}\left(\color{blue}{\left(2 \cdot x2 - 3\right) \cdot 4}, x2, -2\right), x1, -6 \cdot x2\right) \]
                                                                                            10. lower-*.f64N/A

                                                                                              \[\leadsto x1 + \mathsf{fma}\left(\mathsf{fma}\left(\color{blue}{\left(2 \cdot x2 - 3\right) \cdot 4}, x2, -2\right), x1, -6 \cdot x2\right) \]
                                                                                            11. sub-negN/A

                                                                                              \[\leadsto x1 + \mathsf{fma}\left(\mathsf{fma}\left(\color{blue}{\left(2 \cdot x2 + \left(\mathsf{neg}\left(3\right)\right)\right)} \cdot 4, x2, -2\right), x1, -6 \cdot x2\right) \]
                                                                                            12. lower-fma.f64N/A

                                                                                              \[\leadsto x1 + \mathsf{fma}\left(\mathsf{fma}\left(\color{blue}{\mathsf{fma}\left(2, x2, \mathsf{neg}\left(3\right)\right)} \cdot 4, x2, -2\right), x1, -6 \cdot x2\right) \]
                                                                                            13. metadata-evalN/A

                                                                                              \[\leadsto x1 + \mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(2, x2, \color{blue}{-3}\right) \cdot 4, x2, -2\right), x1, -6 \cdot x2\right) \]
                                                                                            14. lower-*.f6485.2

                                                                                              \[\leadsto x1 + \mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(2, x2, -3\right) \cdot 4, x2, -2\right), x1, \color{blue}{-6 \cdot x2}\right) \]
                                                                                          5. Applied rewrites85.2%

                                                                                            \[\leadsto x1 + \color{blue}{\mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(2, x2, -3\right) \cdot 4, x2, -2\right), x1, -6 \cdot x2\right)} \]
                                                                                        8. Recombined 2 regimes into one program.
                                                                                        9. Final simplification90.1%

                                                                                          \[\leadsto \begin{array}{l} \mathbf{if}\;x1 \leq -53000000000:\\ \;\;\;\;\left(\mathsf{fma}\left(\mathsf{fma}\left(6, x1, -3\right), x1, \mathsf{fma}\left(\mathsf{fma}\left(2, x2, -3\right), 4, 9\right)\right) \cdot x1\right) \cdot x1 + x1\\ \mathbf{elif}\;x1 \leq 10^{+29}:\\ \;\;\;\;\mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(2, x2, -3\right) \cdot 4, x2, -2\right), x1, -6 \cdot x2\right) + x1\\ \mathbf{else}:\\ \;\;\;\;\left(\mathsf{fma}\left(\mathsf{fma}\left(6, x1, -3\right), x1, \mathsf{fma}\left(\mathsf{fma}\left(2, x2, -3\right), 4, 9\right)\right) \cdot x1\right) \cdot x1 + x1\\ \end{array} \]
                                                                                        10. Add Preprocessing

                                                                                        Alternative 12: 86.3% accurate, 6.8× speedup?

                                                                                        \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;x1 \leq -53000000000:\\ \;\;\;\;\left(6 \cdot \left(x1 \cdot x1\right)\right) \cdot \left(x1 \cdot x1\right) + x1\\ \mathbf{elif}\;x1 \leq 2.3 \cdot 10^{+36}:\\ \;\;\;\;\mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(2, x2, -3\right) \cdot 4, x2, -2\right), x1, -6 \cdot x2\right) + x1\\ \mathbf{else}:\\ \;\;\;\;\left(\left(6 \cdot x1\right) \cdot x1\right) \cdot \left(x1 \cdot x1\right) + x1\\ \end{array} \end{array} \]
                                                                                        (FPCore (x1 x2)
                                                                                         :precision binary64
                                                                                         (if (<= x1 -53000000000.0)
                                                                                           (+ (* (* 6.0 (* x1 x1)) (* x1 x1)) x1)
                                                                                           (if (<= x1 2.3e+36)
                                                                                             (+ (fma (fma (* (fma 2.0 x2 -3.0) 4.0) x2 -2.0) x1 (* -6.0 x2)) x1)
                                                                                             (+ (* (* (* 6.0 x1) x1) (* x1 x1)) x1))))
                                                                                        double code(double x1, double x2) {
                                                                                        	double tmp;
                                                                                        	if (x1 <= -53000000000.0) {
                                                                                        		tmp = ((6.0 * (x1 * x1)) * (x1 * x1)) + x1;
                                                                                        	} else if (x1 <= 2.3e+36) {
                                                                                        		tmp = fma(fma((fma(2.0, x2, -3.0) * 4.0), x2, -2.0), x1, (-6.0 * x2)) + x1;
                                                                                        	} else {
                                                                                        		tmp = (((6.0 * x1) * x1) * (x1 * x1)) + x1;
                                                                                        	}
                                                                                        	return tmp;
                                                                                        }
                                                                                        
                                                                                        function code(x1, x2)
                                                                                        	tmp = 0.0
                                                                                        	if (x1 <= -53000000000.0)
                                                                                        		tmp = Float64(Float64(Float64(6.0 * Float64(x1 * x1)) * Float64(x1 * x1)) + x1);
                                                                                        	elseif (x1 <= 2.3e+36)
                                                                                        		tmp = Float64(fma(fma(Float64(fma(2.0, x2, -3.0) * 4.0), x2, -2.0), x1, Float64(-6.0 * x2)) + x1);
                                                                                        	else
                                                                                        		tmp = Float64(Float64(Float64(Float64(6.0 * x1) * x1) * Float64(x1 * x1)) + x1);
                                                                                        	end
                                                                                        	return tmp
                                                                                        end
                                                                                        
                                                                                        code[x1_, x2_] := If[LessEqual[x1, -53000000000.0], N[(N[(N[(6.0 * N[(x1 * x1), $MachinePrecision]), $MachinePrecision] * N[(x1 * x1), $MachinePrecision]), $MachinePrecision] + x1), $MachinePrecision], If[LessEqual[x1, 2.3e+36], N[(N[(N[(N[(N[(2.0 * x2 + -3.0), $MachinePrecision] * 4.0), $MachinePrecision] * x2 + -2.0), $MachinePrecision] * x1 + N[(-6.0 * x2), $MachinePrecision]), $MachinePrecision] + x1), $MachinePrecision], N[(N[(N[(N[(6.0 * x1), $MachinePrecision] * x1), $MachinePrecision] * N[(x1 * x1), $MachinePrecision]), $MachinePrecision] + x1), $MachinePrecision]]]
                                                                                        
                                                                                        \begin{array}{l}
                                                                                        
                                                                                        \\
                                                                                        \begin{array}{l}
                                                                                        \mathbf{if}\;x1 \leq -53000000000:\\
                                                                                        \;\;\;\;\left(6 \cdot \left(x1 \cdot x1\right)\right) \cdot \left(x1 \cdot x1\right) + x1\\
                                                                                        
                                                                                        \mathbf{elif}\;x1 \leq 2.3 \cdot 10^{+36}:\\
                                                                                        \;\;\;\;\mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(2, x2, -3\right) \cdot 4, x2, -2\right), x1, -6 \cdot x2\right) + x1\\
                                                                                        
                                                                                        \mathbf{else}:\\
                                                                                        \;\;\;\;\left(\left(6 \cdot x1\right) \cdot x1\right) \cdot \left(x1 \cdot x1\right) + x1\\
                                                                                        
                                                                                        
                                                                                        \end{array}
                                                                                        \end{array}
                                                                                        
                                                                                        Derivation
                                                                                        1. Split input into 3 regimes
                                                                                        2. if x1 < -5.3e10

                                                                                          1. Initial program 28.0%

                                                                                            \[x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                                                                                          2. Add Preprocessing
                                                                                          3. Taylor expanded in x1 around inf

                                                                                            \[\leadsto x1 + \color{blue}{6 \cdot {x1}^{4}} \]
                                                                                          4. Step-by-step derivation
                                                                                            1. *-commutativeN/A

                                                                                              \[\leadsto x1 + \color{blue}{{x1}^{4} \cdot 6} \]
                                                                                            2. lower-*.f64N/A

                                                                                              \[\leadsto x1 + \color{blue}{{x1}^{4} \cdot 6} \]
                                                                                            3. lower-pow.f6492.1

                                                                                              \[\leadsto x1 + \color{blue}{{x1}^{4}} \cdot 6 \]
                                                                                          5. Applied rewrites92.1%

                                                                                            \[\leadsto x1 + \color{blue}{{x1}^{4} \cdot 6} \]
                                                                                          6. Step-by-step derivation
                                                                                            1. lift-+.f64N/A

                                                                                              \[\leadsto \color{blue}{x1 + {x1}^{4} \cdot 6} \]
                                                                                            2. +-commutativeN/A

                                                                                              \[\leadsto \color{blue}{{x1}^{4} \cdot 6 + x1} \]
                                                                                          7. Applied rewrites92.0%

                                                                                            \[\leadsto \color{blue}{\left(6 \cdot \left(x1 \cdot x1\right)\right) \cdot \left(x1 \cdot x1\right) + x1} \]

                                                                                          if -5.3e10 < x1 < 2.29999999999999996e36

                                                                                          1. Initial program 99.5%

                                                                                            \[x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                                                                                          2. Add Preprocessing
                                                                                          3. Taylor expanded in x1 around 0

                                                                                            \[\leadsto x1 + \color{blue}{\left(-6 \cdot x2 + x1 \cdot \left(4 \cdot \left(x2 \cdot \left(2 \cdot x2 - 3\right)\right) - 2\right)\right)} \]
                                                                                          4. Step-by-step derivation
                                                                                            1. +-commutativeN/A

                                                                                              \[\leadsto x1 + \color{blue}{\left(x1 \cdot \left(4 \cdot \left(x2 \cdot \left(2 \cdot x2 - 3\right)\right) - 2\right) + -6 \cdot x2\right)} \]
                                                                                            2. *-commutativeN/A

                                                                                              \[\leadsto x1 + \left(\color{blue}{\left(4 \cdot \left(x2 \cdot \left(2 \cdot x2 - 3\right)\right) - 2\right) \cdot x1} + -6 \cdot x2\right) \]
                                                                                            3. lower-fma.f64N/A

                                                                                              \[\leadsto x1 + \color{blue}{\mathsf{fma}\left(4 \cdot \left(x2 \cdot \left(2 \cdot x2 - 3\right)\right) - 2, x1, -6 \cdot x2\right)} \]
                                                                                            4. sub-negN/A

                                                                                              \[\leadsto x1 + \mathsf{fma}\left(\color{blue}{4 \cdot \left(x2 \cdot \left(2 \cdot x2 - 3\right)\right) + \left(\mathsf{neg}\left(2\right)\right)}, x1, -6 \cdot x2\right) \]
                                                                                            5. *-commutativeN/A

                                                                                              \[\leadsto x1 + \mathsf{fma}\left(4 \cdot \color{blue}{\left(\left(2 \cdot x2 - 3\right) \cdot x2\right)} + \left(\mathsf{neg}\left(2\right)\right), x1, -6 \cdot x2\right) \]
                                                                                            6. associate-*r*N/A

                                                                                              \[\leadsto x1 + \mathsf{fma}\left(\color{blue}{\left(4 \cdot \left(2 \cdot x2 - 3\right)\right) \cdot x2} + \left(\mathsf{neg}\left(2\right)\right), x1, -6 \cdot x2\right) \]
                                                                                            7. metadata-evalN/A

                                                                                              \[\leadsto x1 + \mathsf{fma}\left(\left(4 \cdot \left(2 \cdot x2 - 3\right)\right) \cdot x2 + \color{blue}{-2}, x1, -6 \cdot x2\right) \]
                                                                                            8. lower-fma.f64N/A

                                                                                              \[\leadsto x1 + \mathsf{fma}\left(\color{blue}{\mathsf{fma}\left(4 \cdot \left(2 \cdot x2 - 3\right), x2, -2\right)}, x1, -6 \cdot x2\right) \]
                                                                                            9. *-commutativeN/A

                                                                                              \[\leadsto x1 + \mathsf{fma}\left(\mathsf{fma}\left(\color{blue}{\left(2 \cdot x2 - 3\right) \cdot 4}, x2, -2\right), x1, -6 \cdot x2\right) \]
                                                                                            10. lower-*.f64N/A

                                                                                              \[\leadsto x1 + \mathsf{fma}\left(\mathsf{fma}\left(\color{blue}{\left(2 \cdot x2 - 3\right) \cdot 4}, x2, -2\right), x1, -6 \cdot x2\right) \]
                                                                                            11. sub-negN/A

                                                                                              \[\leadsto x1 + \mathsf{fma}\left(\mathsf{fma}\left(\color{blue}{\left(2 \cdot x2 + \left(\mathsf{neg}\left(3\right)\right)\right)} \cdot 4, x2, -2\right), x1, -6 \cdot x2\right) \]
                                                                                            12. lower-fma.f64N/A

                                                                                              \[\leadsto x1 + \mathsf{fma}\left(\mathsf{fma}\left(\color{blue}{\mathsf{fma}\left(2, x2, \mathsf{neg}\left(3\right)\right)} \cdot 4, x2, -2\right), x1, -6 \cdot x2\right) \]
                                                                                            13. metadata-evalN/A

                                                                                              \[\leadsto x1 + \mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(2, x2, \color{blue}{-3}\right) \cdot 4, x2, -2\right), x1, -6 \cdot x2\right) \]
                                                                                            14. lower-*.f6483.6

                                                                                              \[\leadsto x1 + \mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(2, x2, -3\right) \cdot 4, x2, -2\right), x1, \color{blue}{-6 \cdot x2}\right) \]
                                                                                          5. Applied rewrites83.6%

                                                                                            \[\leadsto x1 + \color{blue}{\mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(2, x2, -3\right) \cdot 4, x2, -2\right), x1, -6 \cdot x2\right)} \]

                                                                                          if 2.29999999999999996e36 < x1

                                                                                          1. Initial program 33.8%

                                                                                            \[x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                                                                                          2. Add Preprocessing
                                                                                          3. Taylor expanded in x1 around inf

                                                                                            \[\leadsto x1 + \color{blue}{6 \cdot {x1}^{4}} \]
                                                                                          4. Step-by-step derivation
                                                                                            1. *-commutativeN/A

                                                                                              \[\leadsto x1 + \color{blue}{{x1}^{4} \cdot 6} \]
                                                                                            2. lower-*.f64N/A

                                                                                              \[\leadsto x1 + \color{blue}{{x1}^{4} \cdot 6} \]
                                                                                            3. lower-pow.f6495.1

                                                                                              \[\leadsto x1 + \color{blue}{{x1}^{4}} \cdot 6 \]
                                                                                          5. Applied rewrites95.1%

                                                                                            \[\leadsto x1 + \color{blue}{{x1}^{4} \cdot 6} \]
                                                                                          6. Step-by-step derivation
                                                                                            1. Applied rewrites95.1%

                                                                                              \[\leadsto x1 + \left(\left(\left(x1 \cdot x1\right) \cdot x1\right) \cdot x1\right) \cdot \color{blue}{6} \]
                                                                                            2. Step-by-step derivation
                                                                                              1. Applied rewrites95.2%

                                                                                                \[\leadsto x1 + \left(x1 \cdot x1\right) \cdot \color{blue}{\left(x1 \cdot \left(6 \cdot x1\right)\right)} \]
                                                                                            3. Recombined 3 regimes into one program.
                                                                                            4. Final simplification88.4%

                                                                                              \[\leadsto \begin{array}{l} \mathbf{if}\;x1 \leq -53000000000:\\ \;\;\;\;\left(6 \cdot \left(x1 \cdot x1\right)\right) \cdot \left(x1 \cdot x1\right) + x1\\ \mathbf{elif}\;x1 \leq 2.3 \cdot 10^{+36}:\\ \;\;\;\;\mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(2, x2, -3\right) \cdot 4, x2, -2\right), x1, -6 \cdot x2\right) + x1\\ \mathbf{else}:\\ \;\;\;\;\left(\left(6 \cdot x1\right) \cdot x1\right) \cdot \left(x1 \cdot x1\right) + x1\\ \end{array} \]
                                                                                            5. Add Preprocessing

                                                                                            Alternative 13: 62.3% accurate, 6.9× speedup?

                                                                                            \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;x1 \leq -3.8 \cdot 10^{+42}:\\ \;\;\;\;\mathsf{fma}\left(\mathsf{fma}\left(-19, x1, 9\right), x1, -1\right) \cdot x1\\ \mathbf{elif}\;x1 \leq -2.8 \cdot 10^{-114}:\\ \;\;\;\;\left(8 \cdot \left(x2 \cdot x1\right)\right) \cdot x2 + x1\\ \mathbf{elif}\;x1 \leq 3.1 \cdot 10^{-81}:\\ \;\;\;\;-6 \cdot x2\\ \mathbf{elif}\;x1 \leq 4.5 \cdot 10^{+153}:\\ \;\;\;\;\left(\left(x2 \cdot x2\right) \cdot 8\right) \cdot x1 + x1\\ \mathbf{else}:\\ \;\;\;\;\left(9 \cdot x1\right) \cdot x1 + x1\\ \end{array} \end{array} \]
                                                                                            (FPCore (x1 x2)
                                                                                             :precision binary64
                                                                                             (if (<= x1 -3.8e+42)
                                                                                               (* (fma (fma -19.0 x1 9.0) x1 -1.0) x1)
                                                                                               (if (<= x1 -2.8e-114)
                                                                                                 (+ (* (* 8.0 (* x2 x1)) x2) x1)
                                                                                                 (if (<= x1 3.1e-81)
                                                                                                   (* -6.0 x2)
                                                                                                   (if (<= x1 4.5e+153)
                                                                                                     (+ (* (* (* x2 x2) 8.0) x1) x1)
                                                                                                     (+ (* (* 9.0 x1) x1) x1))))))
                                                                                            double code(double x1, double x2) {
                                                                                            	double tmp;
                                                                                            	if (x1 <= -3.8e+42) {
                                                                                            		tmp = fma(fma(-19.0, x1, 9.0), x1, -1.0) * x1;
                                                                                            	} else if (x1 <= -2.8e-114) {
                                                                                            		tmp = ((8.0 * (x2 * x1)) * x2) + x1;
                                                                                            	} else if (x1 <= 3.1e-81) {
                                                                                            		tmp = -6.0 * x2;
                                                                                            	} else if (x1 <= 4.5e+153) {
                                                                                            		tmp = (((x2 * x2) * 8.0) * x1) + x1;
                                                                                            	} else {
                                                                                            		tmp = ((9.0 * x1) * x1) + x1;
                                                                                            	}
                                                                                            	return tmp;
                                                                                            }
                                                                                            
                                                                                            function code(x1, x2)
                                                                                            	tmp = 0.0
                                                                                            	if (x1 <= -3.8e+42)
                                                                                            		tmp = Float64(fma(fma(-19.0, x1, 9.0), x1, -1.0) * x1);
                                                                                            	elseif (x1 <= -2.8e-114)
                                                                                            		tmp = Float64(Float64(Float64(8.0 * Float64(x2 * x1)) * x2) + x1);
                                                                                            	elseif (x1 <= 3.1e-81)
                                                                                            		tmp = Float64(-6.0 * x2);
                                                                                            	elseif (x1 <= 4.5e+153)
                                                                                            		tmp = Float64(Float64(Float64(Float64(x2 * x2) * 8.0) * x1) + x1);
                                                                                            	else
                                                                                            		tmp = Float64(Float64(Float64(9.0 * x1) * x1) + x1);
                                                                                            	end
                                                                                            	return tmp
                                                                                            end
                                                                                            
                                                                                            code[x1_, x2_] := If[LessEqual[x1, -3.8e+42], N[(N[(N[(-19.0 * x1 + 9.0), $MachinePrecision] * x1 + -1.0), $MachinePrecision] * x1), $MachinePrecision], If[LessEqual[x1, -2.8e-114], N[(N[(N[(8.0 * N[(x2 * x1), $MachinePrecision]), $MachinePrecision] * x2), $MachinePrecision] + x1), $MachinePrecision], If[LessEqual[x1, 3.1e-81], N[(-6.0 * x2), $MachinePrecision], If[LessEqual[x1, 4.5e+153], N[(N[(N[(N[(x2 * x2), $MachinePrecision] * 8.0), $MachinePrecision] * x1), $MachinePrecision] + x1), $MachinePrecision], N[(N[(N[(9.0 * x1), $MachinePrecision] * x1), $MachinePrecision] + x1), $MachinePrecision]]]]]
                                                                                            
                                                                                            \begin{array}{l}
                                                                                            
                                                                                            \\
                                                                                            \begin{array}{l}
                                                                                            \mathbf{if}\;x1 \leq -3.8 \cdot 10^{+42}:\\
                                                                                            \;\;\;\;\mathsf{fma}\left(\mathsf{fma}\left(-19, x1, 9\right), x1, -1\right) \cdot x1\\
                                                                                            
                                                                                            \mathbf{elif}\;x1 \leq -2.8 \cdot 10^{-114}:\\
                                                                                            \;\;\;\;\left(8 \cdot \left(x2 \cdot x1\right)\right) \cdot x2 + x1\\
                                                                                            
                                                                                            \mathbf{elif}\;x1 \leq 3.1 \cdot 10^{-81}:\\
                                                                                            \;\;\;\;-6 \cdot x2\\
                                                                                            
                                                                                            \mathbf{elif}\;x1 \leq 4.5 \cdot 10^{+153}:\\
                                                                                            \;\;\;\;\left(\left(x2 \cdot x2\right) \cdot 8\right) \cdot x1 + x1\\
                                                                                            
                                                                                            \mathbf{else}:\\
                                                                                            \;\;\;\;\left(9 \cdot x1\right) \cdot x1 + x1\\
                                                                                            
                                                                                            
                                                                                            \end{array}
                                                                                            \end{array}
                                                                                            
                                                                                            Derivation
                                                                                            1. Split input into 5 regimes
                                                                                            2. if x1 < -3.7999999999999998e42

                                                                                              1. Initial program 16.3%

                                                                                                \[x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                                                                                              2. Add Preprocessing
                                                                                              3. Taylor expanded in x1 around 0

                                                                                                \[\leadsto x1 + \color{blue}{-6 \cdot x2} \]
                                                                                              4. Step-by-step derivation
                                                                                                1. lower-*.f640.5

                                                                                                  \[\leadsto x1 + \color{blue}{-6 \cdot x2} \]
                                                                                              5. Applied rewrites0.5%

                                                                                                \[\leadsto x1 + \color{blue}{-6 \cdot x2} \]
                                                                                              6. Taylor expanded in x1 around 0

                                                                                                \[\leadsto \color{blue}{-6 \cdot x2 + x1 \cdot \left(\left(4 \cdot \left(x2 \cdot \left(2 \cdot x2 - 3\right)\right) + x1 \cdot \left(\left(2 \cdot \left(-2 \cdot x2 + -1 \cdot \left(2 \cdot x2 - 3\right)\right) + \left(3 \cdot \left(3 - -2 \cdot x2\right) + \left(6 \cdot x2 + \left(8 \cdot x2 + x1 \cdot \left(\left(2 \cdot \left(\left(1 + \left(2 \cdot \left(x2 \cdot \left(3 + -2 \cdot x2\right)\right) + 3 \cdot \left(2 \cdot x2 - 3\right)\right)\right) - 2 \cdot \left(x2 \cdot \left(2 \cdot x2 - 3\right)\right)\right) + 4 \cdot \left(x2 \cdot \left(2 \cdot x2 - 3\right)\right)\right) - 3\right)\right)\right)\right)\right) - 6\right)\right) - 1\right)} \]
                                                                                              7. Applied rewrites69.8%

                                                                                                \[\leadsto \color{blue}{\mathsf{fma}\left(\mathsf{fma}\left(\left(\mathsf{fma}\left(14, x2, \mathsf{fma}\left(\mathsf{fma}\left(\left(1 + \mathsf{fma}\left(-4, x2, 6\right) \cdot x2\right) + \mathsf{fma}\left(\mathsf{fma}\left(-4, x2, 6\right), x2, \mathsf{fma}\left(6, x2, -9\right)\right), 2, \mathsf{fma}\left(\mathsf{fma}\left(2, x2, -3\right) \cdot 4, x2, -3\right)\right), x1, \mathsf{fma}\left(6, x2, 9\right)\right)\right) + \mathsf{fma}\left(-4, x2, \mathsf{fma}\left(-4, x2, 6\right)\right)\right) - 6, x1, \mathsf{fma}\left(\mathsf{fma}\left(2, x2, -3\right) \cdot x2, 4, -1\right)\right), x1, -6 \cdot x2\right)} \]
                                                                                              8. Taylor expanded in x2 around 0

                                                                                                \[\leadsto x1 \cdot \color{blue}{\left(x1 \cdot \left(9 + -19 \cdot x1\right) - 1\right)} \]
                                                                                              9. Step-by-step derivation
                                                                                                1. Applied rewrites84.7%

                                                                                                  \[\leadsto \mathsf{fma}\left(\mathsf{fma}\left(-19, x1, 9\right), x1, -1\right) \cdot \color{blue}{x1} \]

                                                                                                if -3.7999999999999998e42 < x1 < -2.8000000000000001e-114

                                                                                                1. Initial program 99.3%

                                                                                                  \[x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                                                                                                2. Add Preprocessing
                                                                                                3. Taylor expanded in x1 around 0

                                                                                                  \[\leadsto x1 + \color{blue}{\left(-6 \cdot x2 + x1 \cdot \left(\left(4 \cdot \left(x2 \cdot \left(2 \cdot x2 - 3\right)\right) + x1 \cdot \left(\left(2 \cdot \left(-2 \cdot x2 + -1 \cdot \left(2 \cdot x2 - 3\right)\right) + \left(3 \cdot \left(3 - -2 \cdot x2\right) + \left(6 \cdot x2 + 8 \cdot x2\right)\right)\right) - 6\right)\right) - 2\right)\right)} \]
                                                                                                4. Applied rewrites72.0%

                                                                                                  \[\leadsto x1 + \color{blue}{\mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(-4, x2, \mathsf{fma}\left(\mathsf{fma}\left(-2, x2, 3\right), 2, \mathsf{fma}\left(\mathsf{fma}\left(2, x2, 3\right), 3, \mathsf{fma}\left(14, x2, -6\right)\right)\right)\right), x1, \mathsf{fma}\left(\mathsf{fma}\left(2, x2, -3\right) \cdot 4, x2, -2\right)\right), x1, -6 \cdot x2\right)} \]
                                                                                                5. Taylor expanded in x2 around -inf

                                                                                                  \[\leadsto x1 + {x2}^{2} \cdot \color{blue}{\left(-1 \cdot \frac{6 + x1 \cdot \left(12 + -12 \cdot x1\right)}{x2} + 8 \cdot x1\right)} \]
                                                                                                6. Step-by-step derivation
                                                                                                  1. Applied rewrites44.5%

                                                                                                    \[\leadsto x1 + \mathsf{fma}\left(x1, 8, \frac{\mathsf{fma}\left(\mathsf{fma}\left(x1, -12, 12\right), x1, 6\right)}{-x2}\right) \cdot \color{blue}{\left(x2 \cdot x2\right)} \]
                                                                                                  2. Taylor expanded in x2 around 0

                                                                                                    \[\leadsto x1 + x2 \cdot \left(-1 \cdot \left(6 + x1 \cdot \left(12 + -12 \cdot x1\right)\right) + \color{blue}{8 \cdot \left(x1 \cdot x2\right)}\right) \]
                                                                                                  3. Step-by-step derivation
                                                                                                    1. Applied rewrites49.5%

                                                                                                      \[\leadsto x1 + \mathsf{fma}\left(x1 \cdot 8, x2, -\mathsf{fma}\left(\mathsf{fma}\left(x1, -12, 12\right), x1, 6\right)\right) \cdot x2 \]
                                                                                                    2. Taylor expanded in x2 around inf

                                                                                                      \[\leadsto x1 + \left(8 \cdot \left(x1 \cdot x2\right)\right) \cdot x2 \]
                                                                                                    3. Step-by-step derivation
                                                                                                      1. Applied rewrites46.8%

                                                                                                        \[\leadsto x1 + \left(\left(x1 \cdot x2\right) \cdot 8\right) \cdot x2 \]

                                                                                                      if -2.8000000000000001e-114 < x1 < 3.09999999999999988e-81

                                                                                                      1. Initial program 99.6%

                                                                                                        \[x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                                                                                                      2. Add Preprocessing
                                                                                                      3. Taylor expanded in x1 around 0

                                                                                                        \[\leadsto x1 + \color{blue}{-6 \cdot x2} \]
                                                                                                      4. Step-by-step derivation
                                                                                                        1. lower-*.f6477.9

                                                                                                          \[\leadsto x1 + \color{blue}{-6 \cdot x2} \]
                                                                                                      5. Applied rewrites77.9%

                                                                                                        \[\leadsto x1 + \color{blue}{-6 \cdot x2} \]
                                                                                                      6. Taylor expanded in x1 around 0

                                                                                                        \[\leadsto \color{blue}{-6 \cdot x2} \]
                                                                                                      7. Step-by-step derivation
                                                                                                        1. lower-*.f6478.2

                                                                                                          \[\leadsto \color{blue}{-6 \cdot x2} \]
                                                                                                      8. Applied rewrites78.2%

                                                                                                        \[\leadsto \color{blue}{-6 \cdot x2} \]

                                                                                                      if 3.09999999999999988e-81 < x1 < 4.5000000000000001e153

                                                                                                      1. Initial program 99.5%

                                                                                                        \[x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                                                                                                      2. Add Preprocessing
                                                                                                      3. Taylor expanded in x1 around 0

                                                                                                        \[\leadsto x1 + \color{blue}{\left(-6 \cdot x2 + x1 \cdot \left(\left(4 \cdot \left(x2 \cdot \left(2 \cdot x2 - 3\right)\right) + x1 \cdot \left(\left(2 \cdot \left(-2 \cdot x2 + -1 \cdot \left(2 \cdot x2 - 3\right)\right) + \left(3 \cdot \left(3 - -2 \cdot x2\right) + \left(6 \cdot x2 + 8 \cdot x2\right)\right)\right) - 6\right)\right) - 2\right)\right)} \]
                                                                                                      4. Applied rewrites49.2%

                                                                                                        \[\leadsto x1 + \color{blue}{\mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(-4, x2, \mathsf{fma}\left(\mathsf{fma}\left(-2, x2, 3\right), 2, \mathsf{fma}\left(\mathsf{fma}\left(2, x2, 3\right), 3, \mathsf{fma}\left(14, x2, -6\right)\right)\right)\right), x1, \mathsf{fma}\left(\mathsf{fma}\left(2, x2, -3\right) \cdot 4, x2, -2\right)\right), x1, -6 \cdot x2\right)} \]
                                                                                                      5. Taylor expanded in x2 around inf

                                                                                                        \[\leadsto x1 + 8 \cdot \color{blue}{\left(x1 \cdot {x2}^{2}\right)} \]
                                                                                                      6. Step-by-step derivation
                                                                                                        1. Applied rewrites42.7%

                                                                                                          \[\leadsto x1 + \left(\left(x2 \cdot x2\right) \cdot 8\right) \cdot \color{blue}{x1} \]

                                                                                                        if 4.5000000000000001e153 < x1

                                                                                                        1. Initial program 0.0%

                                                                                                          \[x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                                                                                                        2. Add Preprocessing
                                                                                                        3. Taylor expanded in x1 around 0

                                                                                                          \[\leadsto x1 + \color{blue}{\left(-6 \cdot x2 + x1 \cdot \left(\left(4 \cdot \left(x2 \cdot \left(2 \cdot x2 - 3\right)\right) + x1 \cdot \left(\left(2 \cdot \left(-2 \cdot x2 + -1 \cdot \left(2 \cdot x2 - 3\right)\right) + \left(3 \cdot \left(3 - -2 \cdot x2\right) + \left(6 \cdot x2 + 8 \cdot x2\right)\right)\right) - 6\right)\right) - 2\right)\right)} \]
                                                                                                        4. Applied rewrites97.4%

                                                                                                          \[\leadsto x1 + \color{blue}{\mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(-4, x2, \mathsf{fma}\left(\mathsf{fma}\left(-2, x2, 3\right), 2, \mathsf{fma}\left(\mathsf{fma}\left(2, x2, 3\right), 3, \mathsf{fma}\left(14, x2, -6\right)\right)\right)\right), x1, \mathsf{fma}\left(\mathsf{fma}\left(2, x2, -3\right) \cdot 4, x2, -2\right)\right), x1, -6 \cdot x2\right)} \]
                                                                                                        5. Taylor expanded in x2 around 0

                                                                                                          \[\leadsto x1 + x1 \cdot \color{blue}{\left(9 \cdot x1 - 2\right)} \]
                                                                                                        6. Step-by-step derivation
                                                                                                          1. Applied rewrites100.0%

                                                                                                            \[\leadsto x1 + \mathsf{fma}\left(x1, 9, -2\right) \cdot \color{blue}{x1} \]
                                                                                                          2. Taylor expanded in x1 around inf

                                                                                                            \[\leadsto x1 + 9 \cdot {x1}^{\color{blue}{2}} \]
                                                                                                          3. Step-by-step derivation
                                                                                                            1. Applied rewrites100.0%

                                                                                                              \[\leadsto x1 + \left(9 \cdot x1\right) \cdot x1 \]
                                                                                                          4. Recombined 5 regimes into one program.
                                                                                                          5. Final simplification72.9%

                                                                                                            \[\leadsto \begin{array}{l} \mathbf{if}\;x1 \leq -3.8 \cdot 10^{+42}:\\ \;\;\;\;\mathsf{fma}\left(\mathsf{fma}\left(-19, x1, 9\right), x1, -1\right) \cdot x1\\ \mathbf{elif}\;x1 \leq -2.8 \cdot 10^{-114}:\\ \;\;\;\;\left(8 \cdot \left(x2 \cdot x1\right)\right) \cdot x2 + x1\\ \mathbf{elif}\;x1 \leq 3.1 \cdot 10^{-81}:\\ \;\;\;\;-6 \cdot x2\\ \mathbf{elif}\;x1 \leq 4.5 \cdot 10^{+153}:\\ \;\;\;\;\left(\left(x2 \cdot x2\right) \cdot 8\right) \cdot x1 + x1\\ \mathbf{else}:\\ \;\;\;\;\left(9 \cdot x1\right) \cdot x1 + x1\\ \end{array} \]
                                                                                                          6. Add Preprocessing

                                                                                                          Alternative 14: 62.5% accurate, 6.9× speedup?

                                                                                                          \[\begin{array}{l} \\ \begin{array}{l} t_0 := \left(8 \cdot \left(x2 \cdot x1\right)\right) \cdot x2 + x1\\ \mathbf{if}\;x1 \leq -3.8 \cdot 10^{+42}:\\ \;\;\;\;\mathsf{fma}\left(\mathsf{fma}\left(-19, x1, 9\right), x1, -1\right) \cdot x1\\ \mathbf{elif}\;x1 \leq -2.8 \cdot 10^{-114}:\\ \;\;\;\;t\_0\\ \mathbf{elif}\;x1 \leq 1.9 \cdot 10^{-84}:\\ \;\;\;\;-6 \cdot x2\\ \mathbf{elif}\;x1 \leq 4.5 \cdot 10^{+153}:\\ \;\;\;\;t\_0\\ \mathbf{else}:\\ \;\;\;\;\left(9 \cdot x1\right) \cdot x1 + x1\\ \end{array} \end{array} \]
                                                                                                          (FPCore (x1 x2)
                                                                                                           :precision binary64
                                                                                                           (let* ((t_0 (+ (* (* 8.0 (* x2 x1)) x2) x1)))
                                                                                                             (if (<= x1 -3.8e+42)
                                                                                                               (* (fma (fma -19.0 x1 9.0) x1 -1.0) x1)
                                                                                                               (if (<= x1 -2.8e-114)
                                                                                                                 t_0
                                                                                                                 (if (<= x1 1.9e-84)
                                                                                                                   (* -6.0 x2)
                                                                                                                   (if (<= x1 4.5e+153) t_0 (+ (* (* 9.0 x1) x1) x1)))))))
                                                                                                          double code(double x1, double x2) {
                                                                                                          	double t_0 = ((8.0 * (x2 * x1)) * x2) + x1;
                                                                                                          	double tmp;
                                                                                                          	if (x1 <= -3.8e+42) {
                                                                                                          		tmp = fma(fma(-19.0, x1, 9.0), x1, -1.0) * x1;
                                                                                                          	} else if (x1 <= -2.8e-114) {
                                                                                                          		tmp = t_0;
                                                                                                          	} else if (x1 <= 1.9e-84) {
                                                                                                          		tmp = -6.0 * x2;
                                                                                                          	} else if (x1 <= 4.5e+153) {
                                                                                                          		tmp = t_0;
                                                                                                          	} else {
                                                                                                          		tmp = ((9.0 * x1) * x1) + x1;
                                                                                                          	}
                                                                                                          	return tmp;
                                                                                                          }
                                                                                                          
                                                                                                          function code(x1, x2)
                                                                                                          	t_0 = Float64(Float64(Float64(8.0 * Float64(x2 * x1)) * x2) + x1)
                                                                                                          	tmp = 0.0
                                                                                                          	if (x1 <= -3.8e+42)
                                                                                                          		tmp = Float64(fma(fma(-19.0, x1, 9.0), x1, -1.0) * x1);
                                                                                                          	elseif (x1 <= -2.8e-114)
                                                                                                          		tmp = t_0;
                                                                                                          	elseif (x1 <= 1.9e-84)
                                                                                                          		tmp = Float64(-6.0 * x2);
                                                                                                          	elseif (x1 <= 4.5e+153)
                                                                                                          		tmp = t_0;
                                                                                                          	else
                                                                                                          		tmp = Float64(Float64(Float64(9.0 * x1) * x1) + x1);
                                                                                                          	end
                                                                                                          	return tmp
                                                                                                          end
                                                                                                          
                                                                                                          code[x1_, x2_] := Block[{t$95$0 = N[(N[(N[(8.0 * N[(x2 * x1), $MachinePrecision]), $MachinePrecision] * x2), $MachinePrecision] + x1), $MachinePrecision]}, If[LessEqual[x1, -3.8e+42], N[(N[(N[(-19.0 * x1 + 9.0), $MachinePrecision] * x1 + -1.0), $MachinePrecision] * x1), $MachinePrecision], If[LessEqual[x1, -2.8e-114], t$95$0, If[LessEqual[x1, 1.9e-84], N[(-6.0 * x2), $MachinePrecision], If[LessEqual[x1, 4.5e+153], t$95$0, N[(N[(N[(9.0 * x1), $MachinePrecision] * x1), $MachinePrecision] + x1), $MachinePrecision]]]]]]
                                                                                                          
                                                                                                          \begin{array}{l}
                                                                                                          
                                                                                                          \\
                                                                                                          \begin{array}{l}
                                                                                                          t_0 := \left(8 \cdot \left(x2 \cdot x1\right)\right) \cdot x2 + x1\\
                                                                                                          \mathbf{if}\;x1 \leq -3.8 \cdot 10^{+42}:\\
                                                                                                          \;\;\;\;\mathsf{fma}\left(\mathsf{fma}\left(-19, x1, 9\right), x1, -1\right) \cdot x1\\
                                                                                                          
                                                                                                          \mathbf{elif}\;x1 \leq -2.8 \cdot 10^{-114}:\\
                                                                                                          \;\;\;\;t\_0\\
                                                                                                          
                                                                                                          \mathbf{elif}\;x1 \leq 1.9 \cdot 10^{-84}:\\
                                                                                                          \;\;\;\;-6 \cdot x2\\
                                                                                                          
                                                                                                          \mathbf{elif}\;x1 \leq 4.5 \cdot 10^{+153}:\\
                                                                                                          \;\;\;\;t\_0\\
                                                                                                          
                                                                                                          \mathbf{else}:\\
                                                                                                          \;\;\;\;\left(9 \cdot x1\right) \cdot x1 + x1\\
                                                                                                          
                                                                                                          
                                                                                                          \end{array}
                                                                                                          \end{array}
                                                                                                          
                                                                                                          Derivation
                                                                                                          1. Split input into 4 regimes
                                                                                                          2. if x1 < -3.7999999999999998e42

                                                                                                            1. Initial program 16.3%

                                                                                                              \[x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                                                                                                            2. Add Preprocessing
                                                                                                            3. Taylor expanded in x1 around 0

                                                                                                              \[\leadsto x1 + \color{blue}{-6 \cdot x2} \]
                                                                                                            4. Step-by-step derivation
                                                                                                              1. lower-*.f640.5

                                                                                                                \[\leadsto x1 + \color{blue}{-6 \cdot x2} \]
                                                                                                            5. Applied rewrites0.5%

                                                                                                              \[\leadsto x1 + \color{blue}{-6 \cdot x2} \]
                                                                                                            6. Taylor expanded in x1 around 0

                                                                                                              \[\leadsto \color{blue}{-6 \cdot x2 + x1 \cdot \left(\left(4 \cdot \left(x2 \cdot \left(2 \cdot x2 - 3\right)\right) + x1 \cdot \left(\left(2 \cdot \left(-2 \cdot x2 + -1 \cdot \left(2 \cdot x2 - 3\right)\right) + \left(3 \cdot \left(3 - -2 \cdot x2\right) + \left(6 \cdot x2 + \left(8 \cdot x2 + x1 \cdot \left(\left(2 \cdot \left(\left(1 + \left(2 \cdot \left(x2 \cdot \left(3 + -2 \cdot x2\right)\right) + 3 \cdot \left(2 \cdot x2 - 3\right)\right)\right) - 2 \cdot \left(x2 \cdot \left(2 \cdot x2 - 3\right)\right)\right) + 4 \cdot \left(x2 \cdot \left(2 \cdot x2 - 3\right)\right)\right) - 3\right)\right)\right)\right)\right) - 6\right)\right) - 1\right)} \]
                                                                                                            7. Applied rewrites69.8%

                                                                                                              \[\leadsto \color{blue}{\mathsf{fma}\left(\mathsf{fma}\left(\left(\mathsf{fma}\left(14, x2, \mathsf{fma}\left(\mathsf{fma}\left(\left(1 + \mathsf{fma}\left(-4, x2, 6\right) \cdot x2\right) + \mathsf{fma}\left(\mathsf{fma}\left(-4, x2, 6\right), x2, \mathsf{fma}\left(6, x2, -9\right)\right), 2, \mathsf{fma}\left(\mathsf{fma}\left(2, x2, -3\right) \cdot 4, x2, -3\right)\right), x1, \mathsf{fma}\left(6, x2, 9\right)\right)\right) + \mathsf{fma}\left(-4, x2, \mathsf{fma}\left(-4, x2, 6\right)\right)\right) - 6, x1, \mathsf{fma}\left(\mathsf{fma}\left(2, x2, -3\right) \cdot x2, 4, -1\right)\right), x1, -6 \cdot x2\right)} \]
                                                                                                            8. Taylor expanded in x2 around 0

                                                                                                              \[\leadsto x1 \cdot \color{blue}{\left(x1 \cdot \left(9 + -19 \cdot x1\right) - 1\right)} \]
                                                                                                            9. Step-by-step derivation
                                                                                                              1. Applied rewrites84.7%

                                                                                                                \[\leadsto \mathsf{fma}\left(\mathsf{fma}\left(-19, x1, 9\right), x1, -1\right) \cdot \color{blue}{x1} \]

                                                                                                              if -3.7999999999999998e42 < x1 < -2.8000000000000001e-114 or 1.89999999999999993e-84 < x1 < 4.5000000000000001e153

                                                                                                              1. Initial program 99.4%

                                                                                                                \[x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                                                                                                              2. Add Preprocessing
                                                                                                              3. Taylor expanded in x1 around 0

                                                                                                                \[\leadsto x1 + \color{blue}{\left(-6 \cdot x2 + x1 \cdot \left(\left(4 \cdot \left(x2 \cdot \left(2 \cdot x2 - 3\right)\right) + x1 \cdot \left(\left(2 \cdot \left(-2 \cdot x2 + -1 \cdot \left(2 \cdot x2 - 3\right)\right) + \left(3 \cdot \left(3 - -2 \cdot x2\right) + \left(6 \cdot x2 + 8 \cdot x2\right)\right)\right) - 6\right)\right) - 2\right)\right)} \]
                                                                                                              4. Applied rewrites60.2%

                                                                                                                \[\leadsto x1 + \color{blue}{\mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(-4, x2, \mathsf{fma}\left(\mathsf{fma}\left(-2, x2, 3\right), 2, \mathsf{fma}\left(\mathsf{fma}\left(2, x2, 3\right), 3, \mathsf{fma}\left(14, x2, -6\right)\right)\right)\right), x1, \mathsf{fma}\left(\mathsf{fma}\left(2, x2, -3\right) \cdot 4, x2, -2\right)\right), x1, -6 \cdot x2\right)} \]
                                                                                                              5. Taylor expanded in x2 around -inf

                                                                                                                \[\leadsto x1 + {x2}^{2} \cdot \color{blue}{\left(-1 \cdot \frac{6 + x1 \cdot \left(12 + -12 \cdot x1\right)}{x2} + 8 \cdot x1\right)} \]
                                                                                                              6. Step-by-step derivation
                                                                                                                1. Applied rewrites43.1%

                                                                                                                  \[\leadsto x1 + \mathsf{fma}\left(x1, 8, \frac{\mathsf{fma}\left(\mathsf{fma}\left(x1, -12, 12\right), x1, 6\right)}{-x2}\right) \cdot \color{blue}{\left(x2 \cdot x2\right)} \]
                                                                                                                2. Taylor expanded in x2 around 0

                                                                                                                  \[\leadsto x1 + x2 \cdot \left(-1 \cdot \left(6 + x1 \cdot \left(12 + -12 \cdot x1\right)\right) + \color{blue}{8 \cdot \left(x1 \cdot x2\right)}\right) \]
                                                                                                                3. Step-by-step derivation
                                                                                                                  1. Applied rewrites45.8%

                                                                                                                    \[\leadsto x1 + \mathsf{fma}\left(x1 \cdot 8, x2, -\mathsf{fma}\left(\mathsf{fma}\left(x1, -12, 12\right), x1, 6\right)\right) \cdot x2 \]
                                                                                                                  2. Taylor expanded in x2 around inf

                                                                                                                    \[\leadsto x1 + \left(8 \cdot \left(x1 \cdot x2\right)\right) \cdot x2 \]
                                                                                                                  3. Step-by-step derivation
                                                                                                                    1. Applied rewrites44.7%

                                                                                                                      \[\leadsto x1 + \left(\left(x1 \cdot x2\right) \cdot 8\right) \cdot x2 \]

                                                                                                                    if -2.8000000000000001e-114 < x1 < 1.89999999999999993e-84

                                                                                                                    1. Initial program 99.6%

                                                                                                                      \[x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                                                                                                                    2. Add Preprocessing
                                                                                                                    3. Taylor expanded in x1 around 0

                                                                                                                      \[\leadsto x1 + \color{blue}{-6 \cdot x2} \]
                                                                                                                    4. Step-by-step derivation
                                                                                                                      1. lower-*.f6477.9

                                                                                                                        \[\leadsto x1 + \color{blue}{-6 \cdot x2} \]
                                                                                                                    5. Applied rewrites77.9%

                                                                                                                      \[\leadsto x1 + \color{blue}{-6 \cdot x2} \]
                                                                                                                    6. Taylor expanded in x1 around 0

                                                                                                                      \[\leadsto \color{blue}{-6 \cdot x2} \]
                                                                                                                    7. Step-by-step derivation
                                                                                                                      1. lower-*.f6478.2

                                                                                                                        \[\leadsto \color{blue}{-6 \cdot x2} \]
                                                                                                                    8. Applied rewrites78.2%

                                                                                                                      \[\leadsto \color{blue}{-6 \cdot x2} \]

                                                                                                                    if 4.5000000000000001e153 < x1

                                                                                                                    1. Initial program 0.0%

                                                                                                                      \[x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                                                                                                                    2. Add Preprocessing
                                                                                                                    3. Taylor expanded in x1 around 0

                                                                                                                      \[\leadsto x1 + \color{blue}{\left(-6 \cdot x2 + x1 \cdot \left(\left(4 \cdot \left(x2 \cdot \left(2 \cdot x2 - 3\right)\right) + x1 \cdot \left(\left(2 \cdot \left(-2 \cdot x2 + -1 \cdot \left(2 \cdot x2 - 3\right)\right) + \left(3 \cdot \left(3 - -2 \cdot x2\right) + \left(6 \cdot x2 + 8 \cdot x2\right)\right)\right) - 6\right)\right) - 2\right)\right)} \]
                                                                                                                    4. Applied rewrites97.4%

                                                                                                                      \[\leadsto x1 + \color{blue}{\mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(-4, x2, \mathsf{fma}\left(\mathsf{fma}\left(-2, x2, 3\right), 2, \mathsf{fma}\left(\mathsf{fma}\left(2, x2, 3\right), 3, \mathsf{fma}\left(14, x2, -6\right)\right)\right)\right), x1, \mathsf{fma}\left(\mathsf{fma}\left(2, x2, -3\right) \cdot 4, x2, -2\right)\right), x1, -6 \cdot x2\right)} \]
                                                                                                                    5. Taylor expanded in x2 around 0

                                                                                                                      \[\leadsto x1 + x1 \cdot \color{blue}{\left(9 \cdot x1 - 2\right)} \]
                                                                                                                    6. Step-by-step derivation
                                                                                                                      1. Applied rewrites100.0%

                                                                                                                        \[\leadsto x1 + \mathsf{fma}\left(x1, 9, -2\right) \cdot \color{blue}{x1} \]
                                                                                                                      2. Taylor expanded in x1 around inf

                                                                                                                        \[\leadsto x1 + 9 \cdot {x1}^{\color{blue}{2}} \]
                                                                                                                      3. Step-by-step derivation
                                                                                                                        1. Applied rewrites100.0%

                                                                                                                          \[\leadsto x1 + \left(9 \cdot x1\right) \cdot x1 \]
                                                                                                                      4. Recombined 4 regimes into one program.
                                                                                                                      5. Final simplification72.9%

                                                                                                                        \[\leadsto \begin{array}{l} \mathbf{if}\;x1 \leq -3.8 \cdot 10^{+42}:\\ \;\;\;\;\mathsf{fma}\left(\mathsf{fma}\left(-19, x1, 9\right), x1, -1\right) \cdot x1\\ \mathbf{elif}\;x1 \leq -2.8 \cdot 10^{-114}:\\ \;\;\;\;\left(8 \cdot \left(x2 \cdot x1\right)\right) \cdot x2 + x1\\ \mathbf{elif}\;x1 \leq 1.9 \cdot 10^{-84}:\\ \;\;\;\;-6 \cdot x2\\ \mathbf{elif}\;x1 \leq 4.5 \cdot 10^{+153}:\\ \;\;\;\;\left(8 \cdot \left(x2 \cdot x1\right)\right) \cdot x2 + x1\\ \mathbf{else}:\\ \;\;\;\;\left(9 \cdot x1\right) \cdot x1 + x1\\ \end{array} \]
                                                                                                                      6. Add Preprocessing

                                                                                                                      Alternative 15: 86.3% accurate, 7.3× speedup?

                                                                                                                      \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;x1 \leq -53000000000:\\ \;\;\;\;\left(6 \cdot \left(x1 \cdot x1\right)\right) \cdot \left(x1 \cdot x1\right) + x1\\ \mathbf{elif}\;x1 \leq 2.3 \cdot 10^{+36}:\\ \;\;\;\;\mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(2, x2, -3\right) \cdot x2, 4, -1\right), x1, -6 \cdot x2\right)\\ \mathbf{else}:\\ \;\;\;\;\left(\left(6 \cdot x1\right) \cdot x1\right) \cdot \left(x1 \cdot x1\right) + x1\\ \end{array} \end{array} \]
                                                                                                                      (FPCore (x1 x2)
                                                                                                                       :precision binary64
                                                                                                                       (if (<= x1 -53000000000.0)
                                                                                                                         (+ (* (* 6.0 (* x1 x1)) (* x1 x1)) x1)
                                                                                                                         (if (<= x1 2.3e+36)
                                                                                                                           (fma (fma (* (fma 2.0 x2 -3.0) x2) 4.0 -1.0) x1 (* -6.0 x2))
                                                                                                                           (+ (* (* (* 6.0 x1) x1) (* x1 x1)) x1))))
                                                                                                                      double code(double x1, double x2) {
                                                                                                                      	double tmp;
                                                                                                                      	if (x1 <= -53000000000.0) {
                                                                                                                      		tmp = ((6.0 * (x1 * x1)) * (x1 * x1)) + x1;
                                                                                                                      	} else if (x1 <= 2.3e+36) {
                                                                                                                      		tmp = fma(fma((fma(2.0, x2, -3.0) * x2), 4.0, -1.0), x1, (-6.0 * x2));
                                                                                                                      	} else {
                                                                                                                      		tmp = (((6.0 * x1) * x1) * (x1 * x1)) + x1;
                                                                                                                      	}
                                                                                                                      	return tmp;
                                                                                                                      }
                                                                                                                      
                                                                                                                      function code(x1, x2)
                                                                                                                      	tmp = 0.0
                                                                                                                      	if (x1 <= -53000000000.0)
                                                                                                                      		tmp = Float64(Float64(Float64(6.0 * Float64(x1 * x1)) * Float64(x1 * x1)) + x1);
                                                                                                                      	elseif (x1 <= 2.3e+36)
                                                                                                                      		tmp = fma(fma(Float64(fma(2.0, x2, -3.0) * x2), 4.0, -1.0), x1, Float64(-6.0 * x2));
                                                                                                                      	else
                                                                                                                      		tmp = Float64(Float64(Float64(Float64(6.0 * x1) * x1) * Float64(x1 * x1)) + x1);
                                                                                                                      	end
                                                                                                                      	return tmp
                                                                                                                      end
                                                                                                                      
                                                                                                                      code[x1_, x2_] := If[LessEqual[x1, -53000000000.0], N[(N[(N[(6.0 * N[(x1 * x1), $MachinePrecision]), $MachinePrecision] * N[(x1 * x1), $MachinePrecision]), $MachinePrecision] + x1), $MachinePrecision], If[LessEqual[x1, 2.3e+36], N[(N[(N[(N[(2.0 * x2 + -3.0), $MachinePrecision] * x2), $MachinePrecision] * 4.0 + -1.0), $MachinePrecision] * x1 + N[(-6.0 * x2), $MachinePrecision]), $MachinePrecision], N[(N[(N[(N[(6.0 * x1), $MachinePrecision] * x1), $MachinePrecision] * N[(x1 * x1), $MachinePrecision]), $MachinePrecision] + x1), $MachinePrecision]]]
                                                                                                                      
                                                                                                                      \begin{array}{l}
                                                                                                                      
                                                                                                                      \\
                                                                                                                      \begin{array}{l}
                                                                                                                      \mathbf{if}\;x1 \leq -53000000000:\\
                                                                                                                      \;\;\;\;\left(6 \cdot \left(x1 \cdot x1\right)\right) \cdot \left(x1 \cdot x1\right) + x1\\
                                                                                                                      
                                                                                                                      \mathbf{elif}\;x1 \leq 2.3 \cdot 10^{+36}:\\
                                                                                                                      \;\;\;\;\mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(2, x2, -3\right) \cdot x2, 4, -1\right), x1, -6 \cdot x2\right)\\
                                                                                                                      
                                                                                                                      \mathbf{else}:\\
                                                                                                                      \;\;\;\;\left(\left(6 \cdot x1\right) \cdot x1\right) \cdot \left(x1 \cdot x1\right) + x1\\
                                                                                                                      
                                                                                                                      
                                                                                                                      \end{array}
                                                                                                                      \end{array}
                                                                                                                      
                                                                                                                      Derivation
                                                                                                                      1. Split input into 3 regimes
                                                                                                                      2. if x1 < -5.3e10

                                                                                                                        1. Initial program 28.0%

                                                                                                                          \[x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                                                                                                                        2. Add Preprocessing
                                                                                                                        3. Taylor expanded in x1 around inf

                                                                                                                          \[\leadsto x1 + \color{blue}{6 \cdot {x1}^{4}} \]
                                                                                                                        4. Step-by-step derivation
                                                                                                                          1. *-commutativeN/A

                                                                                                                            \[\leadsto x1 + \color{blue}{{x1}^{4} \cdot 6} \]
                                                                                                                          2. lower-*.f64N/A

                                                                                                                            \[\leadsto x1 + \color{blue}{{x1}^{4} \cdot 6} \]
                                                                                                                          3. lower-pow.f6492.1

                                                                                                                            \[\leadsto x1 + \color{blue}{{x1}^{4}} \cdot 6 \]
                                                                                                                        5. Applied rewrites92.1%

                                                                                                                          \[\leadsto x1 + \color{blue}{{x1}^{4} \cdot 6} \]
                                                                                                                        6. Step-by-step derivation
                                                                                                                          1. lift-+.f64N/A

                                                                                                                            \[\leadsto \color{blue}{x1 + {x1}^{4} \cdot 6} \]
                                                                                                                          2. +-commutativeN/A

                                                                                                                            \[\leadsto \color{blue}{{x1}^{4} \cdot 6 + x1} \]
                                                                                                                        7. Applied rewrites92.0%

                                                                                                                          \[\leadsto \color{blue}{\left(6 \cdot \left(x1 \cdot x1\right)\right) \cdot \left(x1 \cdot x1\right) + x1} \]

                                                                                                                        if -5.3e10 < x1 < 2.29999999999999996e36

                                                                                                                        1. Initial program 99.5%

                                                                                                                          \[x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                                                                                                                        2. Add Preprocessing
                                                                                                                        3. Taylor expanded in x1 around 0

                                                                                                                          \[\leadsto x1 + \color{blue}{-6 \cdot x2} \]
                                                                                                                        4. Step-by-step derivation
                                                                                                                          1. lower-*.f6452.4

                                                                                                                            \[\leadsto x1 + \color{blue}{-6 \cdot x2} \]
                                                                                                                        5. Applied rewrites52.4%

                                                                                                                          \[\leadsto x1 + \color{blue}{-6 \cdot x2} \]
                                                                                                                        6. Taylor expanded in x1 around 0

                                                                                                                          \[\leadsto \color{blue}{-6 \cdot x2 + x1 \cdot \left(4 \cdot \left(x2 \cdot \left(2 \cdot x2 - 3\right)\right) - 1\right)} \]
                                                                                                                        7. Step-by-step derivation
                                                                                                                          1. +-commutativeN/A

                                                                                                                            \[\leadsto \color{blue}{x1 \cdot \left(4 \cdot \left(x2 \cdot \left(2 \cdot x2 - 3\right)\right) - 1\right) + -6 \cdot x2} \]
                                                                                                                          2. *-commutativeN/A

                                                                                                                            \[\leadsto \color{blue}{\left(4 \cdot \left(x2 \cdot \left(2 \cdot x2 - 3\right)\right) - 1\right) \cdot x1} + -6 \cdot x2 \]
                                                                                                                          3. lower-fma.f64N/A

                                                                                                                            \[\leadsto \color{blue}{\mathsf{fma}\left(4 \cdot \left(x2 \cdot \left(2 \cdot x2 - 3\right)\right) - 1, x1, -6 \cdot x2\right)} \]
                                                                                                                          4. sub-negN/A

                                                                                                                            \[\leadsto \mathsf{fma}\left(\color{blue}{4 \cdot \left(x2 \cdot \left(2 \cdot x2 - 3\right)\right) + \left(\mathsf{neg}\left(1\right)\right)}, x1, -6 \cdot x2\right) \]
                                                                                                                          5. *-commutativeN/A

                                                                                                                            \[\leadsto \mathsf{fma}\left(\color{blue}{\left(x2 \cdot \left(2 \cdot x2 - 3\right)\right) \cdot 4} + \left(\mathsf{neg}\left(1\right)\right), x1, -6 \cdot x2\right) \]
                                                                                                                          6. metadata-evalN/A

                                                                                                                            \[\leadsto \mathsf{fma}\left(\left(x2 \cdot \left(2 \cdot x2 - 3\right)\right) \cdot 4 + \color{blue}{-1}, x1, -6 \cdot x2\right) \]
                                                                                                                          7. lower-fma.f64N/A

                                                                                                                            \[\leadsto \mathsf{fma}\left(\color{blue}{\mathsf{fma}\left(x2 \cdot \left(2 \cdot x2 - 3\right), 4, -1\right)}, x1, -6 \cdot x2\right) \]
                                                                                                                          8. *-commutativeN/A

                                                                                                                            \[\leadsto \mathsf{fma}\left(\mathsf{fma}\left(\color{blue}{\left(2 \cdot x2 - 3\right) \cdot x2}, 4, -1\right), x1, -6 \cdot x2\right) \]
                                                                                                                          9. lower-*.f64N/A

                                                                                                                            \[\leadsto \mathsf{fma}\left(\mathsf{fma}\left(\color{blue}{\left(2 \cdot x2 - 3\right) \cdot x2}, 4, -1\right), x1, -6 \cdot x2\right) \]
                                                                                                                          10. sub-negN/A

                                                                                                                            \[\leadsto \mathsf{fma}\left(\mathsf{fma}\left(\color{blue}{\left(2 \cdot x2 + \left(\mathsf{neg}\left(3\right)\right)\right)} \cdot x2, 4, -1\right), x1, -6 \cdot x2\right) \]
                                                                                                                          11. metadata-evalN/A

                                                                                                                            \[\leadsto \mathsf{fma}\left(\mathsf{fma}\left(\left(2 \cdot x2 + \color{blue}{-3}\right) \cdot x2, 4, -1\right), x1, -6 \cdot x2\right) \]
                                                                                                                          12. lower-fma.f64N/A

                                                                                                                            \[\leadsto \mathsf{fma}\left(\mathsf{fma}\left(\color{blue}{\mathsf{fma}\left(2, x2, -3\right)} \cdot x2, 4, -1\right), x1, -6 \cdot x2\right) \]
                                                                                                                          13. lower-*.f6483.6

                                                                                                                            \[\leadsto \mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(2, x2, -3\right) \cdot x2, 4, -1\right), x1, \color{blue}{-6 \cdot x2}\right) \]
                                                                                                                        8. Applied rewrites83.6%

                                                                                                                          \[\leadsto \color{blue}{\mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(2, x2, -3\right) \cdot x2, 4, -1\right), x1, -6 \cdot x2\right)} \]

                                                                                                                        if 2.29999999999999996e36 < x1

                                                                                                                        1. Initial program 33.8%

                                                                                                                          \[x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                                                                                                                        2. Add Preprocessing
                                                                                                                        3. Taylor expanded in x1 around inf

                                                                                                                          \[\leadsto x1 + \color{blue}{6 \cdot {x1}^{4}} \]
                                                                                                                        4. Step-by-step derivation
                                                                                                                          1. *-commutativeN/A

                                                                                                                            \[\leadsto x1 + \color{blue}{{x1}^{4} \cdot 6} \]
                                                                                                                          2. lower-*.f64N/A

                                                                                                                            \[\leadsto x1 + \color{blue}{{x1}^{4} \cdot 6} \]
                                                                                                                          3. lower-pow.f6495.1

                                                                                                                            \[\leadsto x1 + \color{blue}{{x1}^{4}} \cdot 6 \]
                                                                                                                        5. Applied rewrites95.1%

                                                                                                                          \[\leadsto x1 + \color{blue}{{x1}^{4} \cdot 6} \]
                                                                                                                        6. Step-by-step derivation
                                                                                                                          1. Applied rewrites95.1%

                                                                                                                            \[\leadsto x1 + \left(\left(\left(x1 \cdot x1\right) \cdot x1\right) \cdot x1\right) \cdot \color{blue}{6} \]
                                                                                                                          2. Step-by-step derivation
                                                                                                                            1. Applied rewrites95.2%

                                                                                                                              \[\leadsto x1 + \left(x1 \cdot x1\right) \cdot \color{blue}{\left(x1 \cdot \left(6 \cdot x1\right)\right)} \]
                                                                                                                          3. Recombined 3 regimes into one program.
                                                                                                                          4. Final simplification88.4%

                                                                                                                            \[\leadsto \begin{array}{l} \mathbf{if}\;x1 \leq -53000000000:\\ \;\;\;\;\left(6 \cdot \left(x1 \cdot x1\right)\right) \cdot \left(x1 \cdot x1\right) + x1\\ \mathbf{elif}\;x1 \leq 2.3 \cdot 10^{+36}:\\ \;\;\;\;\mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(2, x2, -3\right) \cdot x2, 4, -1\right), x1, -6 \cdot x2\right)\\ \mathbf{else}:\\ \;\;\;\;\left(\left(6 \cdot x1\right) \cdot x1\right) \cdot \left(x1 \cdot x1\right) + x1\\ \end{array} \]
                                                                                                                          5. Add Preprocessing

                                                                                                                          Alternative 16: 58.6% accurate, 8.0× speedup?

                                                                                                                          \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;x1 \leq -1.85 \cdot 10^{-115}:\\ \;\;\;\;\mathsf{fma}\left(\mathsf{fma}\left(-19, x1, 9\right), x1, -1\right) \cdot x1\\ \mathbf{elif}\;x1 \leq 2.6 \cdot 10^{+17}:\\ \;\;\;\;-6 \cdot x2\\ \mathbf{elif}\;x1 \leq 2.3 \cdot 10^{+146}:\\ \;\;\;\;\left(\left(x2 \cdot x1\right) \cdot x1\right) \cdot 8 + x1\\ \mathbf{else}:\\ \;\;\;\;\left(9 \cdot x1\right) \cdot x1 + x1\\ \end{array} \end{array} \]
                                                                                                                          (FPCore (x1 x2)
                                                                                                                           :precision binary64
                                                                                                                           (if (<= x1 -1.85e-115)
                                                                                                                             (* (fma (fma -19.0 x1 9.0) x1 -1.0) x1)
                                                                                                                             (if (<= x1 2.6e+17)
                                                                                                                               (* -6.0 x2)
                                                                                                                               (if (<= x1 2.3e+146)
                                                                                                                                 (+ (* (* (* x2 x1) x1) 8.0) x1)
                                                                                                                                 (+ (* (* 9.0 x1) x1) x1)))))
                                                                                                                          double code(double x1, double x2) {
                                                                                                                          	double tmp;
                                                                                                                          	if (x1 <= -1.85e-115) {
                                                                                                                          		tmp = fma(fma(-19.0, x1, 9.0), x1, -1.0) * x1;
                                                                                                                          	} else if (x1 <= 2.6e+17) {
                                                                                                                          		tmp = -6.0 * x2;
                                                                                                                          	} else if (x1 <= 2.3e+146) {
                                                                                                                          		tmp = (((x2 * x1) * x1) * 8.0) + x1;
                                                                                                                          	} else {
                                                                                                                          		tmp = ((9.0 * x1) * x1) + x1;
                                                                                                                          	}
                                                                                                                          	return tmp;
                                                                                                                          }
                                                                                                                          
                                                                                                                          function code(x1, x2)
                                                                                                                          	tmp = 0.0
                                                                                                                          	if (x1 <= -1.85e-115)
                                                                                                                          		tmp = Float64(fma(fma(-19.0, x1, 9.0), x1, -1.0) * x1);
                                                                                                                          	elseif (x1 <= 2.6e+17)
                                                                                                                          		tmp = Float64(-6.0 * x2);
                                                                                                                          	elseif (x1 <= 2.3e+146)
                                                                                                                          		tmp = Float64(Float64(Float64(Float64(x2 * x1) * x1) * 8.0) + x1);
                                                                                                                          	else
                                                                                                                          		tmp = Float64(Float64(Float64(9.0 * x1) * x1) + x1);
                                                                                                                          	end
                                                                                                                          	return tmp
                                                                                                                          end
                                                                                                                          
                                                                                                                          code[x1_, x2_] := If[LessEqual[x1, -1.85e-115], N[(N[(N[(-19.0 * x1 + 9.0), $MachinePrecision] * x1 + -1.0), $MachinePrecision] * x1), $MachinePrecision], If[LessEqual[x1, 2.6e+17], N[(-6.0 * x2), $MachinePrecision], If[LessEqual[x1, 2.3e+146], N[(N[(N[(N[(x2 * x1), $MachinePrecision] * x1), $MachinePrecision] * 8.0), $MachinePrecision] + x1), $MachinePrecision], N[(N[(N[(9.0 * x1), $MachinePrecision] * x1), $MachinePrecision] + x1), $MachinePrecision]]]]
                                                                                                                          
                                                                                                                          \begin{array}{l}
                                                                                                                          
                                                                                                                          \\
                                                                                                                          \begin{array}{l}
                                                                                                                          \mathbf{if}\;x1 \leq -1.85 \cdot 10^{-115}:\\
                                                                                                                          \;\;\;\;\mathsf{fma}\left(\mathsf{fma}\left(-19, x1, 9\right), x1, -1\right) \cdot x1\\
                                                                                                                          
                                                                                                                          \mathbf{elif}\;x1 \leq 2.6 \cdot 10^{+17}:\\
                                                                                                                          \;\;\;\;-6 \cdot x2\\
                                                                                                                          
                                                                                                                          \mathbf{elif}\;x1 \leq 2.3 \cdot 10^{+146}:\\
                                                                                                                          \;\;\;\;\left(\left(x2 \cdot x1\right) \cdot x1\right) \cdot 8 + x1\\
                                                                                                                          
                                                                                                                          \mathbf{else}:\\
                                                                                                                          \;\;\;\;\left(9 \cdot x1\right) \cdot x1 + x1\\
                                                                                                                          
                                                                                                                          
                                                                                                                          \end{array}
                                                                                                                          \end{array}
                                                                                                                          
                                                                                                                          Derivation
                                                                                                                          1. Split input into 4 regimes
                                                                                                                          2. if x1 < -1.85e-115

                                                                                                                            1. Initial program 49.7%

                                                                                                                              \[x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                                                                                                                            2. Add Preprocessing
                                                                                                                            3. Taylor expanded in x1 around 0

                                                                                                                              \[\leadsto x1 + \color{blue}{-6 \cdot x2} \]
                                                                                                                            4. Step-by-step derivation
                                                                                                                              1. lower-*.f642.5

                                                                                                                                \[\leadsto x1 + \color{blue}{-6 \cdot x2} \]
                                                                                                                            5. Applied rewrites2.5%

                                                                                                                              \[\leadsto x1 + \color{blue}{-6 \cdot x2} \]
                                                                                                                            6. Taylor expanded in x1 around 0

                                                                                                                              \[\leadsto \color{blue}{-6 \cdot x2 + x1 \cdot \left(\left(4 \cdot \left(x2 \cdot \left(2 \cdot x2 - 3\right)\right) + x1 \cdot \left(\left(2 \cdot \left(-2 \cdot x2 + -1 \cdot \left(2 \cdot x2 - 3\right)\right) + \left(3 \cdot \left(3 - -2 \cdot x2\right) + \left(6 \cdot x2 + \left(8 \cdot x2 + x1 \cdot \left(\left(2 \cdot \left(\left(1 + \left(2 \cdot \left(x2 \cdot \left(3 + -2 \cdot x2\right)\right) + 3 \cdot \left(2 \cdot x2 - 3\right)\right)\right) - 2 \cdot \left(x2 \cdot \left(2 \cdot x2 - 3\right)\right)\right) + 4 \cdot \left(x2 \cdot \left(2 \cdot x2 - 3\right)\right)\right) - 3\right)\right)\right)\right)\right) - 6\right)\right) - 1\right)} \]
                                                                                                                            7. Applied rewrites62.0%

                                                                                                                              \[\leadsto \color{blue}{\mathsf{fma}\left(\mathsf{fma}\left(\left(\mathsf{fma}\left(14, x2, \mathsf{fma}\left(\mathsf{fma}\left(\left(1 + \mathsf{fma}\left(-4, x2, 6\right) \cdot x2\right) + \mathsf{fma}\left(\mathsf{fma}\left(-4, x2, 6\right), x2, \mathsf{fma}\left(6, x2, -9\right)\right), 2, \mathsf{fma}\left(\mathsf{fma}\left(2, x2, -3\right) \cdot 4, x2, -3\right)\right), x1, \mathsf{fma}\left(6, x2, 9\right)\right)\right) + \mathsf{fma}\left(-4, x2, \mathsf{fma}\left(-4, x2, 6\right)\right)\right) - 6, x1, \mathsf{fma}\left(\mathsf{fma}\left(2, x2, -3\right) \cdot x2, 4, -1\right)\right), x1, -6 \cdot x2\right)} \]
                                                                                                                            8. Taylor expanded in x2 around 0

                                                                                                                              \[\leadsto x1 \cdot \color{blue}{\left(x1 \cdot \left(9 + -19 \cdot x1\right) - 1\right)} \]
                                                                                                                            9. Step-by-step derivation
                                                                                                                              1. Applied rewrites62.6%

                                                                                                                                \[\leadsto \mathsf{fma}\left(\mathsf{fma}\left(-19, x1, 9\right), x1, -1\right) \cdot \color{blue}{x1} \]

                                                                                                                              if -1.85e-115 < x1 < 2.6e17

                                                                                                                              1. Initial program 99.5%

                                                                                                                                \[x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                                                                                                                              2. Add Preprocessing
                                                                                                                              3. Taylor expanded in x1 around 0

                                                                                                                                \[\leadsto x1 + \color{blue}{-6 \cdot x2} \]
                                                                                                                              4. Step-by-step derivation
                                                                                                                                1. lower-*.f6469.7

                                                                                                                                  \[\leadsto x1 + \color{blue}{-6 \cdot x2} \]
                                                                                                                              5. Applied rewrites69.7%

                                                                                                                                \[\leadsto x1 + \color{blue}{-6 \cdot x2} \]
                                                                                                                              6. Taylor expanded in x1 around 0

                                                                                                                                \[\leadsto \color{blue}{-6 \cdot x2} \]
                                                                                                                              7. Step-by-step derivation
                                                                                                                                1. lower-*.f6470.1

                                                                                                                                  \[\leadsto \color{blue}{-6 \cdot x2} \]
                                                                                                                              8. Applied rewrites70.1%

                                                                                                                                \[\leadsto \color{blue}{-6 \cdot x2} \]

                                                                                                                              if 2.6e17 < x1 < 2.3e146

                                                                                                                              1. Initial program 99.7%

                                                                                                                                \[x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                                                                                                                              2. Add Preprocessing
                                                                                                                              3. Taylor expanded in x1 around inf

                                                                                                                                \[\leadsto x1 + \color{blue}{{x1}^{4} \cdot \left(\left(6 + \left(4 \cdot \frac{2 \cdot x2 - 3}{{x1}^{2}} + \frac{9}{{x1}^{2}}\right)\right) - 3 \cdot \frac{1}{x1}\right)} \]
                                                                                                                              4. Step-by-step derivation
                                                                                                                                1. *-commutativeN/A

                                                                                                                                  \[\leadsto x1 + \color{blue}{\left(\left(6 + \left(4 \cdot \frac{2 \cdot x2 - 3}{{x1}^{2}} + \frac{9}{{x1}^{2}}\right)\right) - 3 \cdot \frac{1}{x1}\right) \cdot {x1}^{4}} \]
                                                                                                                                2. lower-*.f64N/A

                                                                                                                                  \[\leadsto x1 + \color{blue}{\left(\left(6 + \left(4 \cdot \frac{2 \cdot x2 - 3}{{x1}^{2}} + \frac{9}{{x1}^{2}}\right)\right) - 3 \cdot \frac{1}{x1}\right) \cdot {x1}^{4}} \]
                                                                                                                              5. Applied rewrites78.3%

                                                                                                                                \[\leadsto x1 + \color{blue}{\left(\mathsf{fma}\left(\frac{\mathsf{fma}\left(2, x2, -3\right)}{x1 \cdot x1}, 4, \frac{9}{x1 \cdot x1} + 6\right) - \frac{3}{x1}\right) \cdot {x1}^{4}} \]
                                                                                                                              6. Taylor expanded in x2 around inf

                                                                                                                                \[\leadsto x1 + 8 \cdot \color{blue}{\left({x1}^{2} \cdot x2\right)} \]
                                                                                                                              7. Step-by-step derivation
                                                                                                                                1. Applied rewrites28.3%

                                                                                                                                  \[\leadsto x1 + \left(\left(x1 \cdot x2\right) \cdot x1\right) \cdot \color{blue}{8} \]

                                                                                                                                if 2.3e146 < x1

                                                                                                                                1. Initial program 2.5%

                                                                                                                                  \[x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                                                                                                                                2. Add Preprocessing
                                                                                                                                3. Taylor expanded in x1 around 0

                                                                                                                                  \[\leadsto x1 + \color{blue}{\left(-6 \cdot x2 + x1 \cdot \left(\left(4 \cdot \left(x2 \cdot \left(2 \cdot x2 - 3\right)\right) + x1 \cdot \left(\left(2 \cdot \left(-2 \cdot x2 + -1 \cdot \left(2 \cdot x2 - 3\right)\right) + \left(3 \cdot \left(3 - -2 \cdot x2\right) + \left(6 \cdot x2 + 8 \cdot x2\right)\right)\right) - 6\right)\right) - 2\right)\right)} \]
                                                                                                                                4. Applied rewrites97.5%

                                                                                                                                  \[\leadsto x1 + \color{blue}{\mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(-4, x2, \mathsf{fma}\left(\mathsf{fma}\left(-2, x2, 3\right), 2, \mathsf{fma}\left(\mathsf{fma}\left(2, x2, 3\right), 3, \mathsf{fma}\left(14, x2, -6\right)\right)\right)\right), x1, \mathsf{fma}\left(\mathsf{fma}\left(2, x2, -3\right) \cdot 4, x2, -2\right)\right), x1, -6 \cdot x2\right)} \]
                                                                                                                                5. Taylor expanded in x2 around 0

                                                                                                                                  \[\leadsto x1 + x1 \cdot \color{blue}{\left(9 \cdot x1 - 2\right)} \]
                                                                                                                                6. Step-by-step derivation
                                                                                                                                  1. Applied rewrites97.8%

                                                                                                                                    \[\leadsto x1 + \mathsf{fma}\left(x1, 9, -2\right) \cdot \color{blue}{x1} \]
                                                                                                                                  2. Taylor expanded in x1 around inf

                                                                                                                                    \[\leadsto x1 + 9 \cdot {x1}^{\color{blue}{2}} \]
                                                                                                                                  3. Step-by-step derivation
                                                                                                                                    1. Applied rewrites97.8%

                                                                                                                                      \[\leadsto x1 + \left(9 \cdot x1\right) \cdot x1 \]
                                                                                                                                  4. Recombined 4 regimes into one program.
                                                                                                                                  5. Final simplification67.3%

                                                                                                                                    \[\leadsto \begin{array}{l} \mathbf{if}\;x1 \leq -1.85 \cdot 10^{-115}:\\ \;\;\;\;\mathsf{fma}\left(\mathsf{fma}\left(-19, x1, 9\right), x1, -1\right) \cdot x1\\ \mathbf{elif}\;x1 \leq 2.6 \cdot 10^{+17}:\\ \;\;\;\;-6 \cdot x2\\ \mathbf{elif}\;x1 \leq 2.3 \cdot 10^{+146}:\\ \;\;\;\;\left(\left(x2 \cdot x1\right) \cdot x1\right) \cdot 8 + x1\\ \mathbf{else}:\\ \;\;\;\;\left(9 \cdot x1\right) \cdot x1 + x1\\ \end{array} \]
                                                                                                                                  6. Add Preprocessing

                                                                                                                                  Alternative 17: 53.0% accurate, 9.3× speedup?

                                                                                                                                  \[\begin{array}{l} \\ \begin{array}{l} t_0 := \left(9 \cdot x1\right) \cdot x1 + x1\\ \mathbf{if}\;x1 \leq -8 \cdot 10^{-8}:\\ \;\;\;\;t\_0\\ \mathbf{elif}\;x1 \leq -1.85 \cdot 10^{-115}:\\ \;\;\;\;-2 \cdot x1 + x1\\ \mathbf{elif}\;x1 \leq 1.4:\\ \;\;\;\;-6 \cdot x2\\ \mathbf{else}:\\ \;\;\;\;t\_0\\ \end{array} \end{array} \]
                                                                                                                                  (FPCore (x1 x2)
                                                                                                                                   :precision binary64
                                                                                                                                   (let* ((t_0 (+ (* (* 9.0 x1) x1) x1)))
                                                                                                                                     (if (<= x1 -8e-8)
                                                                                                                                       t_0
                                                                                                                                       (if (<= x1 -1.85e-115)
                                                                                                                                         (+ (* -2.0 x1) x1)
                                                                                                                                         (if (<= x1 1.4) (* -6.0 x2) t_0)))))
                                                                                                                                  double code(double x1, double x2) {
                                                                                                                                  	double t_0 = ((9.0 * x1) * x1) + x1;
                                                                                                                                  	double tmp;
                                                                                                                                  	if (x1 <= -8e-8) {
                                                                                                                                  		tmp = t_0;
                                                                                                                                  	} else if (x1 <= -1.85e-115) {
                                                                                                                                  		tmp = (-2.0 * x1) + x1;
                                                                                                                                  	} else if (x1 <= 1.4) {
                                                                                                                                  		tmp = -6.0 * x2;
                                                                                                                                  	} else {
                                                                                                                                  		tmp = t_0;
                                                                                                                                  	}
                                                                                                                                  	return tmp;
                                                                                                                                  }
                                                                                                                                  
                                                                                                                                  real(8) function code(x1, x2)
                                                                                                                                      real(8), intent (in) :: x1
                                                                                                                                      real(8), intent (in) :: x2
                                                                                                                                      real(8) :: t_0
                                                                                                                                      real(8) :: tmp
                                                                                                                                      t_0 = ((9.0d0 * x1) * x1) + x1
                                                                                                                                      if (x1 <= (-8d-8)) then
                                                                                                                                          tmp = t_0
                                                                                                                                      else if (x1 <= (-1.85d-115)) then
                                                                                                                                          tmp = ((-2.0d0) * x1) + x1
                                                                                                                                      else if (x1 <= 1.4d0) then
                                                                                                                                          tmp = (-6.0d0) * x2
                                                                                                                                      else
                                                                                                                                          tmp = t_0
                                                                                                                                      end if
                                                                                                                                      code = tmp
                                                                                                                                  end function
                                                                                                                                  
                                                                                                                                  public static double code(double x1, double x2) {
                                                                                                                                  	double t_0 = ((9.0 * x1) * x1) + x1;
                                                                                                                                  	double tmp;
                                                                                                                                  	if (x1 <= -8e-8) {
                                                                                                                                  		tmp = t_0;
                                                                                                                                  	} else if (x1 <= -1.85e-115) {
                                                                                                                                  		tmp = (-2.0 * x1) + x1;
                                                                                                                                  	} else if (x1 <= 1.4) {
                                                                                                                                  		tmp = -6.0 * x2;
                                                                                                                                  	} else {
                                                                                                                                  		tmp = t_0;
                                                                                                                                  	}
                                                                                                                                  	return tmp;
                                                                                                                                  }
                                                                                                                                  
                                                                                                                                  def code(x1, x2):
                                                                                                                                  	t_0 = ((9.0 * x1) * x1) + x1
                                                                                                                                  	tmp = 0
                                                                                                                                  	if x1 <= -8e-8:
                                                                                                                                  		tmp = t_0
                                                                                                                                  	elif x1 <= -1.85e-115:
                                                                                                                                  		tmp = (-2.0 * x1) + x1
                                                                                                                                  	elif x1 <= 1.4:
                                                                                                                                  		tmp = -6.0 * x2
                                                                                                                                  	else:
                                                                                                                                  		tmp = t_0
                                                                                                                                  	return tmp
                                                                                                                                  
                                                                                                                                  function code(x1, x2)
                                                                                                                                  	t_0 = Float64(Float64(Float64(9.0 * x1) * x1) + x1)
                                                                                                                                  	tmp = 0.0
                                                                                                                                  	if (x1 <= -8e-8)
                                                                                                                                  		tmp = t_0;
                                                                                                                                  	elseif (x1 <= -1.85e-115)
                                                                                                                                  		tmp = Float64(Float64(-2.0 * x1) + x1);
                                                                                                                                  	elseif (x1 <= 1.4)
                                                                                                                                  		tmp = Float64(-6.0 * x2);
                                                                                                                                  	else
                                                                                                                                  		tmp = t_0;
                                                                                                                                  	end
                                                                                                                                  	return tmp
                                                                                                                                  end
                                                                                                                                  
                                                                                                                                  function tmp_2 = code(x1, x2)
                                                                                                                                  	t_0 = ((9.0 * x1) * x1) + x1;
                                                                                                                                  	tmp = 0.0;
                                                                                                                                  	if (x1 <= -8e-8)
                                                                                                                                  		tmp = t_0;
                                                                                                                                  	elseif (x1 <= -1.85e-115)
                                                                                                                                  		tmp = (-2.0 * x1) + x1;
                                                                                                                                  	elseif (x1 <= 1.4)
                                                                                                                                  		tmp = -6.0 * x2;
                                                                                                                                  	else
                                                                                                                                  		tmp = t_0;
                                                                                                                                  	end
                                                                                                                                  	tmp_2 = tmp;
                                                                                                                                  end
                                                                                                                                  
                                                                                                                                  code[x1_, x2_] := Block[{t$95$0 = N[(N[(N[(9.0 * x1), $MachinePrecision] * x1), $MachinePrecision] + x1), $MachinePrecision]}, If[LessEqual[x1, -8e-8], t$95$0, If[LessEqual[x1, -1.85e-115], N[(N[(-2.0 * x1), $MachinePrecision] + x1), $MachinePrecision], If[LessEqual[x1, 1.4], N[(-6.0 * x2), $MachinePrecision], t$95$0]]]]
                                                                                                                                  
                                                                                                                                  \begin{array}{l}
                                                                                                                                  
                                                                                                                                  \\
                                                                                                                                  \begin{array}{l}
                                                                                                                                  t_0 := \left(9 \cdot x1\right) \cdot x1 + x1\\
                                                                                                                                  \mathbf{if}\;x1 \leq -8 \cdot 10^{-8}:\\
                                                                                                                                  \;\;\;\;t\_0\\
                                                                                                                                  
                                                                                                                                  \mathbf{elif}\;x1 \leq -1.85 \cdot 10^{-115}:\\
                                                                                                                                  \;\;\;\;-2 \cdot x1 + x1\\
                                                                                                                                  
                                                                                                                                  \mathbf{elif}\;x1 \leq 1.4:\\
                                                                                                                                  \;\;\;\;-6 \cdot x2\\
                                                                                                                                  
                                                                                                                                  \mathbf{else}:\\
                                                                                                                                  \;\;\;\;t\_0\\
                                                                                                                                  
                                                                                                                                  
                                                                                                                                  \end{array}
                                                                                                                                  \end{array}
                                                                                                                                  
                                                                                                                                  Derivation
                                                                                                                                  1. Split input into 3 regimes
                                                                                                                                  2. if x1 < -8.0000000000000002e-8 or 1.3999999999999999 < x1

                                                                                                                                    1. Initial program 37.8%

                                                                                                                                      \[x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                                                                                                                                    2. Add Preprocessing
                                                                                                                                    3. Taylor expanded in x1 around 0

                                                                                                                                      \[\leadsto x1 + \color{blue}{\left(-6 \cdot x2 + x1 \cdot \left(\left(4 \cdot \left(x2 \cdot \left(2 \cdot x2 - 3\right)\right) + x1 \cdot \left(\left(2 \cdot \left(-2 \cdot x2 + -1 \cdot \left(2 \cdot x2 - 3\right)\right) + \left(3 \cdot \left(3 - -2 \cdot x2\right) + \left(6 \cdot x2 + 8 \cdot x2\right)\right)\right) - 6\right)\right) - 2\right)\right)} \]
                                                                                                                                    4. Applied rewrites60.8%

                                                                                                                                      \[\leadsto x1 + \color{blue}{\mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(-4, x2, \mathsf{fma}\left(\mathsf{fma}\left(-2, x2, 3\right), 2, \mathsf{fma}\left(\mathsf{fma}\left(2, x2, 3\right), 3, \mathsf{fma}\left(14, x2, -6\right)\right)\right)\right), x1, \mathsf{fma}\left(\mathsf{fma}\left(2, x2, -3\right) \cdot 4, x2, -2\right)\right), x1, -6 \cdot x2\right)} \]
                                                                                                                                    5. Taylor expanded in x2 around 0

                                                                                                                                      \[\leadsto x1 + x1 \cdot \color{blue}{\left(9 \cdot x1 - 2\right)} \]
                                                                                                                                    6. Step-by-step derivation
                                                                                                                                      1. Applied rewrites56.0%

                                                                                                                                        \[\leadsto x1 + \mathsf{fma}\left(x1, 9, -2\right) \cdot \color{blue}{x1} \]
                                                                                                                                      2. Taylor expanded in x1 around inf

                                                                                                                                        \[\leadsto x1 + 9 \cdot {x1}^{\color{blue}{2}} \]
                                                                                                                                      3. Step-by-step derivation
                                                                                                                                        1. Applied rewrites56.0%

                                                                                                                                          \[\leadsto x1 + \left(9 \cdot x1\right) \cdot x1 \]

                                                                                                                                        if -8.0000000000000002e-8 < x1 < -1.85e-115

                                                                                                                                        1. Initial program 99.3%

                                                                                                                                          \[x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                                                                                                                                        2. Add Preprocessing
                                                                                                                                        3. Taylor expanded in x1 around 0

                                                                                                                                          \[\leadsto x1 + \color{blue}{\left(-6 \cdot x2 + x1 \cdot \left(\left(4 \cdot \left(x2 \cdot \left(2 \cdot x2 - 3\right)\right) + x1 \cdot \left(\left(2 \cdot \left(-2 \cdot x2 + -1 \cdot \left(2 \cdot x2 - 3\right)\right) + \left(3 \cdot \left(3 - -2 \cdot x2\right) + \left(6 \cdot x2 + 8 \cdot x2\right)\right)\right) - 6\right)\right) - 2\right)\right)} \]
                                                                                                                                        4. Applied rewrites92.5%

                                                                                                                                          \[\leadsto x1 + \color{blue}{\mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(-4, x2, \mathsf{fma}\left(\mathsf{fma}\left(-2, x2, 3\right), 2, \mathsf{fma}\left(\mathsf{fma}\left(2, x2, 3\right), 3, \mathsf{fma}\left(14, x2, -6\right)\right)\right)\right), x1, \mathsf{fma}\left(\mathsf{fma}\left(2, x2, -3\right) \cdot 4, x2, -2\right)\right), x1, -6 \cdot x2\right)} \]
                                                                                                                                        5. Taylor expanded in x2 around 0

                                                                                                                                          \[\leadsto x1 + x1 \cdot \color{blue}{\left(9 \cdot x1 - 2\right)} \]
                                                                                                                                        6. Step-by-step derivation
                                                                                                                                          1. Applied rewrites40.7%

                                                                                                                                            \[\leadsto x1 + \mathsf{fma}\left(x1, 9, -2\right) \cdot \color{blue}{x1} \]
                                                                                                                                          2. Taylor expanded in x1 around 0

                                                                                                                                            \[\leadsto x1 + -2 \cdot x1 \]
                                                                                                                                          3. Step-by-step derivation
                                                                                                                                            1. Applied rewrites40.4%

                                                                                                                                              \[\leadsto x1 + -2 \cdot x1 \]

                                                                                                                                            if -1.85e-115 < x1 < 1.3999999999999999

                                                                                                                                            1. Initial program 99.5%

                                                                                                                                              \[x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                                                                                                                                            2. Add Preprocessing
                                                                                                                                            3. Taylor expanded in x1 around 0

                                                                                                                                              \[\leadsto x1 + \color{blue}{-6 \cdot x2} \]
                                                                                                                                            4. Step-by-step derivation
                                                                                                                                              1. lower-*.f6471.7

                                                                                                                                                \[\leadsto x1 + \color{blue}{-6 \cdot x2} \]
                                                                                                                                            5. Applied rewrites71.7%

                                                                                                                                              \[\leadsto x1 + \color{blue}{-6 \cdot x2} \]
                                                                                                                                            6. Taylor expanded in x1 around 0

                                                                                                                                              \[\leadsto \color{blue}{-6 \cdot x2} \]
                                                                                                                                            7. Step-by-step derivation
                                                                                                                                              1. lower-*.f6472.1

                                                                                                                                                \[\leadsto \color{blue}{-6 \cdot x2} \]
                                                                                                                                            8. Applied rewrites72.1%

                                                                                                                                              \[\leadsto \color{blue}{-6 \cdot x2} \]
                                                                                                                                          4. Recombined 3 regimes into one program.
                                                                                                                                          5. Final simplification60.4%

                                                                                                                                            \[\leadsto \begin{array}{l} \mathbf{if}\;x1 \leq -8 \cdot 10^{-8}:\\ \;\;\;\;\left(9 \cdot x1\right) \cdot x1 + x1\\ \mathbf{elif}\;x1 \leq -1.85 \cdot 10^{-115}:\\ \;\;\;\;-2 \cdot x1 + x1\\ \mathbf{elif}\;x1 \leq 1.4:\\ \;\;\;\;-6 \cdot x2\\ \mathbf{else}:\\ \;\;\;\;\left(9 \cdot x1\right) \cdot x1 + x1\\ \end{array} \]
                                                                                                                                          6. Add Preprocessing

                                                                                                                                          Alternative 18: 71.0% accurate, 9.3× speedup?

                                                                                                                                          \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;x1 \leq -3.8 \cdot 10^{+42}:\\ \;\;\;\;\mathsf{fma}\left(\mathsf{fma}\left(-19, x1, 9\right), x1, -1\right) \cdot x1\\ \mathbf{elif}\;x1 \leq 4.5 \cdot 10^{+153}:\\ \;\;\;\;\mathsf{fma}\left(8 \cdot x1, x2, -6\right) \cdot x2 + x1\\ \mathbf{else}:\\ \;\;\;\;\left(9 \cdot x1\right) \cdot x1 + x1\\ \end{array} \end{array} \]
                                                                                                                                          (FPCore (x1 x2)
                                                                                                                                           :precision binary64
                                                                                                                                           (if (<= x1 -3.8e+42)
                                                                                                                                             (* (fma (fma -19.0 x1 9.0) x1 -1.0) x1)
                                                                                                                                             (if (<= x1 4.5e+153)
                                                                                                                                               (+ (* (fma (* 8.0 x1) x2 -6.0) x2) x1)
                                                                                                                                               (+ (* (* 9.0 x1) x1) x1))))
                                                                                                                                          double code(double x1, double x2) {
                                                                                                                                          	double tmp;
                                                                                                                                          	if (x1 <= -3.8e+42) {
                                                                                                                                          		tmp = fma(fma(-19.0, x1, 9.0), x1, -1.0) * x1;
                                                                                                                                          	} else if (x1 <= 4.5e+153) {
                                                                                                                                          		tmp = (fma((8.0 * x1), x2, -6.0) * x2) + x1;
                                                                                                                                          	} else {
                                                                                                                                          		tmp = ((9.0 * x1) * x1) + x1;
                                                                                                                                          	}
                                                                                                                                          	return tmp;
                                                                                                                                          }
                                                                                                                                          
                                                                                                                                          function code(x1, x2)
                                                                                                                                          	tmp = 0.0
                                                                                                                                          	if (x1 <= -3.8e+42)
                                                                                                                                          		tmp = Float64(fma(fma(-19.0, x1, 9.0), x1, -1.0) * x1);
                                                                                                                                          	elseif (x1 <= 4.5e+153)
                                                                                                                                          		tmp = Float64(Float64(fma(Float64(8.0 * x1), x2, -6.0) * x2) + x1);
                                                                                                                                          	else
                                                                                                                                          		tmp = Float64(Float64(Float64(9.0 * x1) * x1) + x1);
                                                                                                                                          	end
                                                                                                                                          	return tmp
                                                                                                                                          end
                                                                                                                                          
                                                                                                                                          code[x1_, x2_] := If[LessEqual[x1, -3.8e+42], N[(N[(N[(-19.0 * x1 + 9.0), $MachinePrecision] * x1 + -1.0), $MachinePrecision] * x1), $MachinePrecision], If[LessEqual[x1, 4.5e+153], N[(N[(N[(N[(8.0 * x1), $MachinePrecision] * x2 + -6.0), $MachinePrecision] * x2), $MachinePrecision] + x1), $MachinePrecision], N[(N[(N[(9.0 * x1), $MachinePrecision] * x1), $MachinePrecision] + x1), $MachinePrecision]]]
                                                                                                                                          
                                                                                                                                          \begin{array}{l}
                                                                                                                                          
                                                                                                                                          \\
                                                                                                                                          \begin{array}{l}
                                                                                                                                          \mathbf{if}\;x1 \leq -3.8 \cdot 10^{+42}:\\
                                                                                                                                          \;\;\;\;\mathsf{fma}\left(\mathsf{fma}\left(-19, x1, 9\right), x1, -1\right) \cdot x1\\
                                                                                                                                          
                                                                                                                                          \mathbf{elif}\;x1 \leq 4.5 \cdot 10^{+153}:\\
                                                                                                                                          \;\;\;\;\mathsf{fma}\left(8 \cdot x1, x2, -6\right) \cdot x2 + x1\\
                                                                                                                                          
                                                                                                                                          \mathbf{else}:\\
                                                                                                                                          \;\;\;\;\left(9 \cdot x1\right) \cdot x1 + x1\\
                                                                                                                                          
                                                                                                                                          
                                                                                                                                          \end{array}
                                                                                                                                          \end{array}
                                                                                                                                          
                                                                                                                                          Derivation
                                                                                                                                          1. Split input into 3 regimes
                                                                                                                                          2. if x1 < -3.7999999999999998e42

                                                                                                                                            1. Initial program 16.3%

                                                                                                                                              \[x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                                                                                                                                            2. Add Preprocessing
                                                                                                                                            3. Taylor expanded in x1 around 0

                                                                                                                                              \[\leadsto x1 + \color{blue}{-6 \cdot x2} \]
                                                                                                                                            4. Step-by-step derivation
                                                                                                                                              1. lower-*.f640.5

                                                                                                                                                \[\leadsto x1 + \color{blue}{-6 \cdot x2} \]
                                                                                                                                            5. Applied rewrites0.5%

                                                                                                                                              \[\leadsto x1 + \color{blue}{-6 \cdot x2} \]
                                                                                                                                            6. Taylor expanded in x1 around 0

                                                                                                                                              \[\leadsto \color{blue}{-6 \cdot x2 + x1 \cdot \left(\left(4 \cdot \left(x2 \cdot \left(2 \cdot x2 - 3\right)\right) + x1 \cdot \left(\left(2 \cdot \left(-2 \cdot x2 + -1 \cdot \left(2 \cdot x2 - 3\right)\right) + \left(3 \cdot \left(3 - -2 \cdot x2\right) + \left(6 \cdot x2 + \left(8 \cdot x2 + x1 \cdot \left(\left(2 \cdot \left(\left(1 + \left(2 \cdot \left(x2 \cdot \left(3 + -2 \cdot x2\right)\right) + 3 \cdot \left(2 \cdot x2 - 3\right)\right)\right) - 2 \cdot \left(x2 \cdot \left(2 \cdot x2 - 3\right)\right)\right) + 4 \cdot \left(x2 \cdot \left(2 \cdot x2 - 3\right)\right)\right) - 3\right)\right)\right)\right)\right) - 6\right)\right) - 1\right)} \]
                                                                                                                                            7. Applied rewrites69.8%

                                                                                                                                              \[\leadsto \color{blue}{\mathsf{fma}\left(\mathsf{fma}\left(\left(\mathsf{fma}\left(14, x2, \mathsf{fma}\left(\mathsf{fma}\left(\left(1 + \mathsf{fma}\left(-4, x2, 6\right) \cdot x2\right) + \mathsf{fma}\left(\mathsf{fma}\left(-4, x2, 6\right), x2, \mathsf{fma}\left(6, x2, -9\right)\right), 2, \mathsf{fma}\left(\mathsf{fma}\left(2, x2, -3\right) \cdot 4, x2, -3\right)\right), x1, \mathsf{fma}\left(6, x2, 9\right)\right)\right) + \mathsf{fma}\left(-4, x2, \mathsf{fma}\left(-4, x2, 6\right)\right)\right) - 6, x1, \mathsf{fma}\left(\mathsf{fma}\left(2, x2, -3\right) \cdot x2, 4, -1\right)\right), x1, -6 \cdot x2\right)} \]
                                                                                                                                            8. Taylor expanded in x2 around 0

                                                                                                                                              \[\leadsto x1 \cdot \color{blue}{\left(x1 \cdot \left(9 + -19 \cdot x1\right) - 1\right)} \]
                                                                                                                                            9. Step-by-step derivation
                                                                                                                                              1. Applied rewrites84.7%

                                                                                                                                                \[\leadsto \mathsf{fma}\left(\mathsf{fma}\left(-19, x1, 9\right), x1, -1\right) \cdot \color{blue}{x1} \]

                                                                                                                                              if -3.7999999999999998e42 < x1 < 4.5000000000000001e153

                                                                                                                                              1. Initial program 99.5%

                                                                                                                                                \[x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                                                                                                                                              2. Add Preprocessing
                                                                                                                                              3. Taylor expanded in x1 around 0

                                                                                                                                                \[\leadsto x1 + \color{blue}{\left(-6 \cdot x2 + x1 \cdot \left(\left(4 \cdot \left(x2 \cdot \left(2 \cdot x2 - 3\right)\right) + x1 \cdot \left(\left(2 \cdot \left(-2 \cdot x2 + -1 \cdot \left(2 \cdot x2 - 3\right)\right) + \left(3 \cdot \left(3 - -2 \cdot x2\right) + \left(6 \cdot x2 + 8 \cdot x2\right)\right)\right) - 6\right)\right) - 2\right)\right)} \]
                                                                                                                                              4. Applied rewrites73.9%

                                                                                                                                                \[\leadsto x1 + \color{blue}{\mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(-4, x2, \mathsf{fma}\left(\mathsf{fma}\left(-2, x2, 3\right), 2, \mathsf{fma}\left(\mathsf{fma}\left(2, x2, 3\right), 3, \mathsf{fma}\left(14, x2, -6\right)\right)\right)\right), x1, \mathsf{fma}\left(\mathsf{fma}\left(2, x2, -3\right) \cdot 4, x2, -2\right)\right), x1, -6 \cdot x2\right)} \]
                                                                                                                                              5. Taylor expanded in x2 around -inf

                                                                                                                                                \[\leadsto x1 + {x2}^{2} \cdot \color{blue}{\left(-1 \cdot \frac{6 + x1 \cdot \left(12 + -12 \cdot x1\right)}{x2} + 8 \cdot x1\right)} \]
                                                                                                                                              6. Step-by-step derivation
                                                                                                                                                1. Applied rewrites56.7%

                                                                                                                                                  \[\leadsto x1 + \mathsf{fma}\left(x1, 8, \frac{\mathsf{fma}\left(\mathsf{fma}\left(x1, -12, 12\right), x1, 6\right)}{-x2}\right) \cdot \color{blue}{\left(x2 \cdot x2\right)} \]
                                                                                                                                                2. Taylor expanded in x2 around 0

                                                                                                                                                  \[\leadsto x1 + x2 \cdot \left(-1 \cdot \left(6 + x1 \cdot \left(12 + -12 \cdot x1\right)\right) + \color{blue}{8 \cdot \left(x1 \cdot x2\right)}\right) \]
                                                                                                                                                3. Step-by-step derivation
                                                                                                                                                  1. Applied rewrites68.2%

                                                                                                                                                    \[\leadsto x1 + \mathsf{fma}\left(x1 \cdot 8, x2, -\mathsf{fma}\left(\mathsf{fma}\left(x1, -12, 12\right), x1, 6\right)\right) \cdot x2 \]
                                                                                                                                                  2. Taylor expanded in x1 around 0

                                                                                                                                                    \[\leadsto x1 + \mathsf{fma}\left(x1 \cdot 8, x2, -6\right) \cdot x2 \]
                                                                                                                                                  3. Step-by-step derivation
                                                                                                                                                    1. Applied rewrites68.8%

                                                                                                                                                      \[\leadsto x1 + \mathsf{fma}\left(x1 \cdot 8, x2, -6\right) \cdot x2 \]

                                                                                                                                                    if 4.5000000000000001e153 < x1

                                                                                                                                                    1. Initial program 0.0%

                                                                                                                                                      \[x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                                                                                                                                                    2. Add Preprocessing
                                                                                                                                                    3. Taylor expanded in x1 around 0

                                                                                                                                                      \[\leadsto x1 + \color{blue}{\left(-6 \cdot x2 + x1 \cdot \left(\left(4 \cdot \left(x2 \cdot \left(2 \cdot x2 - 3\right)\right) + x1 \cdot \left(\left(2 \cdot \left(-2 \cdot x2 + -1 \cdot \left(2 \cdot x2 - 3\right)\right) + \left(3 \cdot \left(3 - -2 \cdot x2\right) + \left(6 \cdot x2 + 8 \cdot x2\right)\right)\right) - 6\right)\right) - 2\right)\right)} \]
                                                                                                                                                    4. Applied rewrites97.4%

                                                                                                                                                      \[\leadsto x1 + \color{blue}{\mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(-4, x2, \mathsf{fma}\left(\mathsf{fma}\left(-2, x2, 3\right), 2, \mathsf{fma}\left(\mathsf{fma}\left(2, x2, 3\right), 3, \mathsf{fma}\left(14, x2, -6\right)\right)\right)\right), x1, \mathsf{fma}\left(\mathsf{fma}\left(2, x2, -3\right) \cdot 4, x2, -2\right)\right), x1, -6 \cdot x2\right)} \]
                                                                                                                                                    5. Taylor expanded in x2 around 0

                                                                                                                                                      \[\leadsto x1 + x1 \cdot \color{blue}{\left(9 \cdot x1 - 2\right)} \]
                                                                                                                                                    6. Step-by-step derivation
                                                                                                                                                      1. Applied rewrites100.0%

                                                                                                                                                        \[\leadsto x1 + \mathsf{fma}\left(x1, 9, -2\right) \cdot \color{blue}{x1} \]
                                                                                                                                                      2. Taylor expanded in x1 around inf

                                                                                                                                                        \[\leadsto x1 + 9 \cdot {x1}^{\color{blue}{2}} \]
                                                                                                                                                      3. Step-by-step derivation
                                                                                                                                                        1. Applied rewrites100.0%

                                                                                                                                                          \[\leadsto x1 + \left(9 \cdot x1\right) \cdot x1 \]
                                                                                                                                                      4. Recombined 3 regimes into one program.
                                                                                                                                                      5. Final simplification77.0%

                                                                                                                                                        \[\leadsto \begin{array}{l} \mathbf{if}\;x1 \leq -3.8 \cdot 10^{+42}:\\ \;\;\;\;\mathsf{fma}\left(\mathsf{fma}\left(-19, x1, 9\right), x1, -1\right) \cdot x1\\ \mathbf{elif}\;x1 \leq 4.5 \cdot 10^{+153}:\\ \;\;\;\;\mathsf{fma}\left(8 \cdot x1, x2, -6\right) \cdot x2 + x1\\ \mathbf{else}:\\ \;\;\;\;\left(9 \cdot x1\right) \cdot x1 + x1\\ \end{array} \]
                                                                                                                                                      6. Add Preprocessing

                                                                                                                                                      Alternative 19: 58.8% accurate, 11.0× speedup?

                                                                                                                                                      \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;x1 \leq -1.85 \cdot 10^{-115}:\\ \;\;\;\;\mathsf{fma}\left(\mathsf{fma}\left(-19, x1, 9\right), x1, -1\right) \cdot x1\\ \mathbf{elif}\;x1 \leq 3.2 \cdot 10^{-84}:\\ \;\;\;\;-6 \cdot x2\\ \mathbf{else}:\\ \;\;\;\;\mathsf{fma}\left(x1, 9, -2\right) \cdot x1 + x1\\ \end{array} \end{array} \]
                                                                                                                                                      (FPCore (x1 x2)
                                                                                                                                                       :precision binary64
                                                                                                                                                       (if (<= x1 -1.85e-115)
                                                                                                                                                         (* (fma (fma -19.0 x1 9.0) x1 -1.0) x1)
                                                                                                                                                         (if (<= x1 3.2e-84) (* -6.0 x2) (+ (* (fma x1 9.0 -2.0) x1) x1))))
                                                                                                                                                      double code(double x1, double x2) {
                                                                                                                                                      	double tmp;
                                                                                                                                                      	if (x1 <= -1.85e-115) {
                                                                                                                                                      		tmp = fma(fma(-19.0, x1, 9.0), x1, -1.0) * x1;
                                                                                                                                                      	} else if (x1 <= 3.2e-84) {
                                                                                                                                                      		tmp = -6.0 * x2;
                                                                                                                                                      	} else {
                                                                                                                                                      		tmp = (fma(x1, 9.0, -2.0) * x1) + x1;
                                                                                                                                                      	}
                                                                                                                                                      	return tmp;
                                                                                                                                                      }
                                                                                                                                                      
                                                                                                                                                      function code(x1, x2)
                                                                                                                                                      	tmp = 0.0
                                                                                                                                                      	if (x1 <= -1.85e-115)
                                                                                                                                                      		tmp = Float64(fma(fma(-19.0, x1, 9.0), x1, -1.0) * x1);
                                                                                                                                                      	elseif (x1 <= 3.2e-84)
                                                                                                                                                      		tmp = Float64(-6.0 * x2);
                                                                                                                                                      	else
                                                                                                                                                      		tmp = Float64(Float64(fma(x1, 9.0, -2.0) * x1) + x1);
                                                                                                                                                      	end
                                                                                                                                                      	return tmp
                                                                                                                                                      end
                                                                                                                                                      
                                                                                                                                                      code[x1_, x2_] := If[LessEqual[x1, -1.85e-115], N[(N[(N[(-19.0 * x1 + 9.0), $MachinePrecision] * x1 + -1.0), $MachinePrecision] * x1), $MachinePrecision], If[LessEqual[x1, 3.2e-84], N[(-6.0 * x2), $MachinePrecision], N[(N[(N[(x1 * 9.0 + -2.0), $MachinePrecision] * x1), $MachinePrecision] + x1), $MachinePrecision]]]
                                                                                                                                                      
                                                                                                                                                      \begin{array}{l}
                                                                                                                                                      
                                                                                                                                                      \\
                                                                                                                                                      \begin{array}{l}
                                                                                                                                                      \mathbf{if}\;x1 \leq -1.85 \cdot 10^{-115}:\\
                                                                                                                                                      \;\;\;\;\mathsf{fma}\left(\mathsf{fma}\left(-19, x1, 9\right), x1, -1\right) \cdot x1\\
                                                                                                                                                      
                                                                                                                                                      \mathbf{elif}\;x1 \leq 3.2 \cdot 10^{-84}:\\
                                                                                                                                                      \;\;\;\;-6 \cdot x2\\
                                                                                                                                                      
                                                                                                                                                      \mathbf{else}:\\
                                                                                                                                                      \;\;\;\;\mathsf{fma}\left(x1, 9, -2\right) \cdot x1 + x1\\
                                                                                                                                                      
                                                                                                                                                      
                                                                                                                                                      \end{array}
                                                                                                                                                      \end{array}
                                                                                                                                                      
                                                                                                                                                      Derivation
                                                                                                                                                      1. Split input into 3 regimes
                                                                                                                                                      2. if x1 < -1.85e-115

                                                                                                                                                        1. Initial program 49.7%

                                                                                                                                                          \[x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                                                                                                                                                        2. Add Preprocessing
                                                                                                                                                        3. Taylor expanded in x1 around 0

                                                                                                                                                          \[\leadsto x1 + \color{blue}{-6 \cdot x2} \]
                                                                                                                                                        4. Step-by-step derivation
                                                                                                                                                          1. lower-*.f642.5

                                                                                                                                                            \[\leadsto x1 + \color{blue}{-6 \cdot x2} \]
                                                                                                                                                        5. Applied rewrites2.5%

                                                                                                                                                          \[\leadsto x1 + \color{blue}{-6 \cdot x2} \]
                                                                                                                                                        6. Taylor expanded in x1 around 0

                                                                                                                                                          \[\leadsto \color{blue}{-6 \cdot x2 + x1 \cdot \left(\left(4 \cdot \left(x2 \cdot \left(2 \cdot x2 - 3\right)\right) + x1 \cdot \left(\left(2 \cdot \left(-2 \cdot x2 + -1 \cdot \left(2 \cdot x2 - 3\right)\right) + \left(3 \cdot \left(3 - -2 \cdot x2\right) + \left(6 \cdot x2 + \left(8 \cdot x2 + x1 \cdot \left(\left(2 \cdot \left(\left(1 + \left(2 \cdot \left(x2 \cdot \left(3 + -2 \cdot x2\right)\right) + 3 \cdot \left(2 \cdot x2 - 3\right)\right)\right) - 2 \cdot \left(x2 \cdot \left(2 \cdot x2 - 3\right)\right)\right) + 4 \cdot \left(x2 \cdot \left(2 \cdot x2 - 3\right)\right)\right) - 3\right)\right)\right)\right)\right) - 6\right)\right) - 1\right)} \]
                                                                                                                                                        7. Applied rewrites62.0%

                                                                                                                                                          \[\leadsto \color{blue}{\mathsf{fma}\left(\mathsf{fma}\left(\left(\mathsf{fma}\left(14, x2, \mathsf{fma}\left(\mathsf{fma}\left(\left(1 + \mathsf{fma}\left(-4, x2, 6\right) \cdot x2\right) + \mathsf{fma}\left(\mathsf{fma}\left(-4, x2, 6\right), x2, \mathsf{fma}\left(6, x2, -9\right)\right), 2, \mathsf{fma}\left(\mathsf{fma}\left(2, x2, -3\right) \cdot 4, x2, -3\right)\right), x1, \mathsf{fma}\left(6, x2, 9\right)\right)\right) + \mathsf{fma}\left(-4, x2, \mathsf{fma}\left(-4, x2, 6\right)\right)\right) - 6, x1, \mathsf{fma}\left(\mathsf{fma}\left(2, x2, -3\right) \cdot x2, 4, -1\right)\right), x1, -6 \cdot x2\right)} \]
                                                                                                                                                        8. Taylor expanded in x2 around 0

                                                                                                                                                          \[\leadsto x1 \cdot \color{blue}{\left(x1 \cdot \left(9 + -19 \cdot x1\right) - 1\right)} \]
                                                                                                                                                        9. Step-by-step derivation
                                                                                                                                                          1. Applied rewrites62.6%

                                                                                                                                                            \[\leadsto \mathsf{fma}\left(\mathsf{fma}\left(-19, x1, 9\right), x1, -1\right) \cdot \color{blue}{x1} \]

                                                                                                                                                          if -1.85e-115 < x1 < 3.1999999999999999e-84

                                                                                                                                                          1. Initial program 99.6%

                                                                                                                                                            \[x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                                                                                                                                                          2. Add Preprocessing
                                                                                                                                                          3. Taylor expanded in x1 around 0

                                                                                                                                                            \[\leadsto x1 + \color{blue}{-6 \cdot x2} \]
                                                                                                                                                          4. Step-by-step derivation
                                                                                                                                                            1. lower-*.f6477.9

                                                                                                                                                              \[\leadsto x1 + \color{blue}{-6 \cdot x2} \]
                                                                                                                                                          5. Applied rewrites77.9%

                                                                                                                                                            \[\leadsto x1 + \color{blue}{-6 \cdot x2} \]
                                                                                                                                                          6. Taylor expanded in x1 around 0

                                                                                                                                                            \[\leadsto \color{blue}{-6 \cdot x2} \]
                                                                                                                                                          7. Step-by-step derivation
                                                                                                                                                            1. lower-*.f6478.2

                                                                                                                                                              \[\leadsto \color{blue}{-6 \cdot x2} \]
                                                                                                                                                          8. Applied rewrites78.2%

                                                                                                                                                            \[\leadsto \color{blue}{-6 \cdot x2} \]

                                                                                                                                                          if 3.1999999999999999e-84 < x1

                                                                                                                                                          1. Initial program 50.4%

                                                                                                                                                            \[x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                                                                                                                                                          2. Add Preprocessing
                                                                                                                                                          3. Taylor expanded in x1 around 0

                                                                                                                                                            \[\leadsto x1 + \color{blue}{\left(-6 \cdot x2 + x1 \cdot \left(\left(4 \cdot \left(x2 \cdot \left(2 \cdot x2 - 3\right)\right) + x1 \cdot \left(\left(2 \cdot \left(-2 \cdot x2 + -1 \cdot \left(2 \cdot x2 - 3\right)\right) + \left(3 \cdot \left(3 - -2 \cdot x2\right) + \left(6 \cdot x2 + 8 \cdot x2\right)\right)\right) - 6\right)\right) - 2\right)\right)} \]
                                                                                                                                                          4. Applied rewrites73.0%

                                                                                                                                                            \[\leadsto x1 + \color{blue}{\mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(-4, x2, \mathsf{fma}\left(\mathsf{fma}\left(-2, x2, 3\right), 2, \mathsf{fma}\left(\mathsf{fma}\left(2, x2, 3\right), 3, \mathsf{fma}\left(14, x2, -6\right)\right)\right)\right), x1, \mathsf{fma}\left(\mathsf{fma}\left(2, x2, -3\right) \cdot 4, x2, -2\right)\right), x1, -6 \cdot x2\right)} \]
                                                                                                                                                          5. Taylor expanded in x2 around 0

                                                                                                                                                            \[\leadsto x1 + x1 \cdot \color{blue}{\left(9 \cdot x1 - 2\right)} \]
                                                                                                                                                          6. Step-by-step derivation
                                                                                                                                                            1. Applied rewrites54.9%

                                                                                                                                                              \[\leadsto x1 + \mathsf{fma}\left(x1, 9, -2\right) \cdot \color{blue}{x1} \]
                                                                                                                                                          7. Recombined 3 regimes into one program.
                                                                                                                                                          8. Final simplification65.4%

                                                                                                                                                            \[\leadsto \begin{array}{l} \mathbf{if}\;x1 \leq -1.85 \cdot 10^{-115}:\\ \;\;\;\;\mathsf{fma}\left(\mathsf{fma}\left(-19, x1, 9\right), x1, -1\right) \cdot x1\\ \mathbf{elif}\;x1 \leq 3.2 \cdot 10^{-84}:\\ \;\;\;\;-6 \cdot x2\\ \mathbf{else}:\\ \;\;\;\;\mathsf{fma}\left(x1, 9, -2\right) \cdot x1 + x1\\ \end{array} \]
                                                                                                                                                          9. Add Preprocessing

                                                                                                                                                          Alternative 20: 54.9% accurate, 11.0× speedup?

                                                                                                                                                          \[\begin{array}{l} \\ \begin{array}{l} t_0 := \mathsf{fma}\left(x1, 9, -2\right) \cdot x1 + x1\\ \mathbf{if}\;x1 \leq -1.85 \cdot 10^{-115}:\\ \;\;\;\;t\_0\\ \mathbf{elif}\;x1 \leq 3.2 \cdot 10^{-84}:\\ \;\;\;\;-6 \cdot x2\\ \mathbf{else}:\\ \;\;\;\;t\_0\\ \end{array} \end{array} \]
                                                                                                                                                          (FPCore (x1 x2)
                                                                                                                                                           :precision binary64
                                                                                                                                                           (let* ((t_0 (+ (* (fma x1 9.0 -2.0) x1) x1)))
                                                                                                                                                             (if (<= x1 -1.85e-115) t_0 (if (<= x1 3.2e-84) (* -6.0 x2) t_0))))
                                                                                                                                                          double code(double x1, double x2) {
                                                                                                                                                          	double t_0 = (fma(x1, 9.0, -2.0) * x1) + x1;
                                                                                                                                                          	double tmp;
                                                                                                                                                          	if (x1 <= -1.85e-115) {
                                                                                                                                                          		tmp = t_0;
                                                                                                                                                          	} else if (x1 <= 3.2e-84) {
                                                                                                                                                          		tmp = -6.0 * x2;
                                                                                                                                                          	} else {
                                                                                                                                                          		tmp = t_0;
                                                                                                                                                          	}
                                                                                                                                                          	return tmp;
                                                                                                                                                          }
                                                                                                                                                          
                                                                                                                                                          function code(x1, x2)
                                                                                                                                                          	t_0 = Float64(Float64(fma(x1, 9.0, -2.0) * x1) + x1)
                                                                                                                                                          	tmp = 0.0
                                                                                                                                                          	if (x1 <= -1.85e-115)
                                                                                                                                                          		tmp = t_0;
                                                                                                                                                          	elseif (x1 <= 3.2e-84)
                                                                                                                                                          		tmp = Float64(-6.0 * x2);
                                                                                                                                                          	else
                                                                                                                                                          		tmp = t_0;
                                                                                                                                                          	end
                                                                                                                                                          	return tmp
                                                                                                                                                          end
                                                                                                                                                          
                                                                                                                                                          code[x1_, x2_] := Block[{t$95$0 = N[(N[(N[(x1 * 9.0 + -2.0), $MachinePrecision] * x1), $MachinePrecision] + x1), $MachinePrecision]}, If[LessEqual[x1, -1.85e-115], t$95$0, If[LessEqual[x1, 3.2e-84], N[(-6.0 * x2), $MachinePrecision], t$95$0]]]
                                                                                                                                                          
                                                                                                                                                          \begin{array}{l}
                                                                                                                                                          
                                                                                                                                                          \\
                                                                                                                                                          \begin{array}{l}
                                                                                                                                                          t_0 := \mathsf{fma}\left(x1, 9, -2\right) \cdot x1 + x1\\
                                                                                                                                                          \mathbf{if}\;x1 \leq -1.85 \cdot 10^{-115}:\\
                                                                                                                                                          \;\;\;\;t\_0\\
                                                                                                                                                          
                                                                                                                                                          \mathbf{elif}\;x1 \leq 3.2 \cdot 10^{-84}:\\
                                                                                                                                                          \;\;\;\;-6 \cdot x2\\
                                                                                                                                                          
                                                                                                                                                          \mathbf{else}:\\
                                                                                                                                                          \;\;\;\;t\_0\\
                                                                                                                                                          
                                                                                                                                                          
                                                                                                                                                          \end{array}
                                                                                                                                                          \end{array}
                                                                                                                                                          
                                                                                                                                                          Derivation
                                                                                                                                                          1. Split input into 2 regimes
                                                                                                                                                          2. if x1 < -1.85e-115 or 3.1999999999999999e-84 < x1

                                                                                                                                                            1. Initial program 50.0%

                                                                                                                                                              \[x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                                                                                                                                                            2. Add Preprocessing
                                                                                                                                                            3. Taylor expanded in x1 around 0

                                                                                                                                                              \[\leadsto x1 + \color{blue}{\left(-6 \cdot x2 + x1 \cdot \left(\left(4 \cdot \left(x2 \cdot \left(2 \cdot x2 - 3\right)\right) + x1 \cdot \left(\left(2 \cdot \left(-2 \cdot x2 + -1 \cdot \left(2 \cdot x2 - 3\right)\right) + \left(3 \cdot \left(3 - -2 \cdot x2\right) + \left(6 \cdot x2 + 8 \cdot x2\right)\right)\right) - 6\right)\right) - 2\right)\right)} \]
                                                                                                                                                            4. Applied rewrites66.6%

                                                                                                                                                              \[\leadsto x1 + \color{blue}{\mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(-4, x2, \mathsf{fma}\left(\mathsf{fma}\left(-2, x2, 3\right), 2, \mathsf{fma}\left(\mathsf{fma}\left(2, x2, 3\right), 3, \mathsf{fma}\left(14, x2, -6\right)\right)\right)\right), x1, \mathsf{fma}\left(\mathsf{fma}\left(2, x2, -3\right) \cdot 4, x2, -2\right)\right), x1, -6 \cdot x2\right)} \]
                                                                                                                                                            5. Taylor expanded in x2 around 0

                                                                                                                                                              \[\leadsto x1 + x1 \cdot \color{blue}{\left(9 \cdot x1 - 2\right)} \]
                                                                                                                                                            6. Step-by-step derivation
                                                                                                                                                              1. Applied rewrites52.4%

                                                                                                                                                                \[\leadsto x1 + \mathsf{fma}\left(x1, 9, -2\right) \cdot \color{blue}{x1} \]

                                                                                                                                                              if -1.85e-115 < x1 < 3.1999999999999999e-84

                                                                                                                                                              1. Initial program 99.6%

                                                                                                                                                                \[x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                                                                                                                                                              2. Add Preprocessing
                                                                                                                                                              3. Taylor expanded in x1 around 0

                                                                                                                                                                \[\leadsto x1 + \color{blue}{-6 \cdot x2} \]
                                                                                                                                                              4. Step-by-step derivation
                                                                                                                                                                1. lower-*.f6477.9

                                                                                                                                                                  \[\leadsto x1 + \color{blue}{-6 \cdot x2} \]
                                                                                                                                                              5. Applied rewrites77.9%

                                                                                                                                                                \[\leadsto x1 + \color{blue}{-6 \cdot x2} \]
                                                                                                                                                              6. Taylor expanded in x1 around 0

                                                                                                                                                                \[\leadsto \color{blue}{-6 \cdot x2} \]
                                                                                                                                                              7. Step-by-step derivation
                                                                                                                                                                1. lower-*.f6478.2

                                                                                                                                                                  \[\leadsto \color{blue}{-6 \cdot x2} \]
                                                                                                                                                              8. Applied rewrites78.2%

                                                                                                                                                                \[\leadsto \color{blue}{-6 \cdot x2} \]
                                                                                                                                                            7. Recombined 2 regimes into one program.
                                                                                                                                                            8. Final simplification61.0%

                                                                                                                                                              \[\leadsto \begin{array}{l} \mathbf{if}\;x1 \leq -1.85 \cdot 10^{-115}:\\ \;\;\;\;\mathsf{fma}\left(x1, 9, -2\right) \cdot x1 + x1\\ \mathbf{elif}\;x1 \leq 3.2 \cdot 10^{-84}:\\ \;\;\;\;-6 \cdot x2\\ \mathbf{else}:\\ \;\;\;\;\mathsf{fma}\left(x1, 9, -2\right) \cdot x1 + x1\\ \end{array} \]
                                                                                                                                                            9. Add Preprocessing

                                                                                                                                                            Alternative 21: 29.1% accurate, 19.8× speedup?

                                                                                                                                                            \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;x1 \leq -1.85 \cdot 10^{-115}:\\ \;\;\;\;-2 \cdot x1 + x1\\ \mathbf{else}:\\ \;\;\;\;-6 \cdot x2 + x1\\ \end{array} \end{array} \]
                                                                                                                                                            (FPCore (x1 x2)
                                                                                                                                                             :precision binary64
                                                                                                                                                             (if (<= x1 -1.85e-115) (+ (* -2.0 x1) x1) (+ (* -6.0 x2) x1)))
                                                                                                                                                            double code(double x1, double x2) {
                                                                                                                                                            	double tmp;
                                                                                                                                                            	if (x1 <= -1.85e-115) {
                                                                                                                                                            		tmp = (-2.0 * x1) + x1;
                                                                                                                                                            	} else {
                                                                                                                                                            		tmp = (-6.0 * x2) + x1;
                                                                                                                                                            	}
                                                                                                                                                            	return tmp;
                                                                                                                                                            }
                                                                                                                                                            
                                                                                                                                                            real(8) function code(x1, x2)
                                                                                                                                                                real(8), intent (in) :: x1
                                                                                                                                                                real(8), intent (in) :: x2
                                                                                                                                                                real(8) :: tmp
                                                                                                                                                                if (x1 <= (-1.85d-115)) then
                                                                                                                                                                    tmp = ((-2.0d0) * x1) + x1
                                                                                                                                                                else
                                                                                                                                                                    tmp = ((-6.0d0) * x2) + x1
                                                                                                                                                                end if
                                                                                                                                                                code = tmp
                                                                                                                                                            end function
                                                                                                                                                            
                                                                                                                                                            public static double code(double x1, double x2) {
                                                                                                                                                            	double tmp;
                                                                                                                                                            	if (x1 <= -1.85e-115) {
                                                                                                                                                            		tmp = (-2.0 * x1) + x1;
                                                                                                                                                            	} else {
                                                                                                                                                            		tmp = (-6.0 * x2) + x1;
                                                                                                                                                            	}
                                                                                                                                                            	return tmp;
                                                                                                                                                            }
                                                                                                                                                            
                                                                                                                                                            def code(x1, x2):
                                                                                                                                                            	tmp = 0
                                                                                                                                                            	if x1 <= -1.85e-115:
                                                                                                                                                            		tmp = (-2.0 * x1) + x1
                                                                                                                                                            	else:
                                                                                                                                                            		tmp = (-6.0 * x2) + x1
                                                                                                                                                            	return tmp
                                                                                                                                                            
                                                                                                                                                            function code(x1, x2)
                                                                                                                                                            	tmp = 0.0
                                                                                                                                                            	if (x1 <= -1.85e-115)
                                                                                                                                                            		tmp = Float64(Float64(-2.0 * x1) + x1);
                                                                                                                                                            	else
                                                                                                                                                            		tmp = Float64(Float64(-6.0 * x2) + x1);
                                                                                                                                                            	end
                                                                                                                                                            	return tmp
                                                                                                                                                            end
                                                                                                                                                            
                                                                                                                                                            function tmp_2 = code(x1, x2)
                                                                                                                                                            	tmp = 0.0;
                                                                                                                                                            	if (x1 <= -1.85e-115)
                                                                                                                                                            		tmp = (-2.0 * x1) + x1;
                                                                                                                                                            	else
                                                                                                                                                            		tmp = (-6.0 * x2) + x1;
                                                                                                                                                            	end
                                                                                                                                                            	tmp_2 = tmp;
                                                                                                                                                            end
                                                                                                                                                            
                                                                                                                                                            code[x1_, x2_] := If[LessEqual[x1, -1.85e-115], N[(N[(-2.0 * x1), $MachinePrecision] + x1), $MachinePrecision], N[(N[(-6.0 * x2), $MachinePrecision] + x1), $MachinePrecision]]
                                                                                                                                                            
                                                                                                                                                            \begin{array}{l}
                                                                                                                                                            
                                                                                                                                                            \\
                                                                                                                                                            \begin{array}{l}
                                                                                                                                                            \mathbf{if}\;x1 \leq -1.85 \cdot 10^{-115}:\\
                                                                                                                                                            \;\;\;\;-2 \cdot x1 + x1\\
                                                                                                                                                            
                                                                                                                                                            \mathbf{else}:\\
                                                                                                                                                            \;\;\;\;-6 \cdot x2 + x1\\
                                                                                                                                                            
                                                                                                                                                            
                                                                                                                                                            \end{array}
                                                                                                                                                            \end{array}
                                                                                                                                                            
                                                                                                                                                            Derivation
                                                                                                                                                            1. Split input into 2 regimes
                                                                                                                                                            2. if x1 < -1.85e-115

                                                                                                                                                              1. Initial program 49.7%

                                                                                                                                                                \[x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                                                                                                                                                              2. Add Preprocessing
                                                                                                                                                              3. Taylor expanded in x1 around 0

                                                                                                                                                                \[\leadsto x1 + \color{blue}{\left(-6 \cdot x2 + x1 \cdot \left(\left(4 \cdot \left(x2 \cdot \left(2 \cdot x2 - 3\right)\right) + x1 \cdot \left(\left(2 \cdot \left(-2 \cdot x2 + -1 \cdot \left(2 \cdot x2 - 3\right)\right) + \left(3 \cdot \left(3 - -2 \cdot x2\right) + \left(6 \cdot x2 + 8 \cdot x2\right)\right)\right) - 6\right)\right) - 2\right)\right)} \]
                                                                                                                                                              4. Applied rewrites61.2%

                                                                                                                                                                \[\leadsto x1 + \color{blue}{\mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(-4, x2, \mathsf{fma}\left(\mathsf{fma}\left(-2, x2, 3\right), 2, \mathsf{fma}\left(\mathsf{fma}\left(2, x2, 3\right), 3, \mathsf{fma}\left(14, x2, -6\right)\right)\right)\right), x1, \mathsf{fma}\left(\mathsf{fma}\left(2, x2, -3\right) \cdot 4, x2, -2\right)\right), x1, -6 \cdot x2\right)} \]
                                                                                                                                                              5. Taylor expanded in x2 around 0

                                                                                                                                                                \[\leadsto x1 + x1 \cdot \color{blue}{\left(9 \cdot x1 - 2\right)} \]
                                                                                                                                                              6. Step-by-step derivation
                                                                                                                                                                1. Applied rewrites50.2%

                                                                                                                                                                  \[\leadsto x1 + \mathsf{fma}\left(x1, 9, -2\right) \cdot \color{blue}{x1} \]
                                                                                                                                                                2. Taylor expanded in x1 around 0

                                                                                                                                                                  \[\leadsto x1 + -2 \cdot x1 \]
                                                                                                                                                                3. Step-by-step derivation
                                                                                                                                                                  1. Applied rewrites15.1%

                                                                                                                                                                    \[\leadsto x1 + -2 \cdot x1 \]

                                                                                                                                                                  if -1.85e-115 < x1

                                                                                                                                                                  1. Initial program 75.9%

                                                                                                                                                                    \[x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                                                                                                                                                                  2. Add Preprocessing
                                                                                                                                                                  3. Taylor expanded in x1 around 0

                                                                                                                                                                    \[\leadsto x1 + \color{blue}{-6 \cdot x2} \]
                                                                                                                                                                  4. Step-by-step derivation
                                                                                                                                                                    1. lower-*.f6443.5

                                                                                                                                                                      \[\leadsto x1 + \color{blue}{-6 \cdot x2} \]
                                                                                                                                                                  5. Applied rewrites43.5%

                                                                                                                                                                    \[\leadsto x1 + \color{blue}{-6 \cdot x2} \]
                                                                                                                                                                4. Recombined 2 regimes into one program.
                                                                                                                                                                5. Final simplification33.3%

                                                                                                                                                                  \[\leadsto \begin{array}{l} \mathbf{if}\;x1 \leq -1.85 \cdot 10^{-115}:\\ \;\;\;\;-2 \cdot x1 + x1\\ \mathbf{else}:\\ \;\;\;\;-6 \cdot x2 + x1\\ \end{array} \]
                                                                                                                                                                6. Add Preprocessing

                                                                                                                                                                Alternative 22: 28.5% accurate, 19.8× speedup?

                                                                                                                                                                \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;x1 \leq -1.85 \cdot 10^{-115}:\\ \;\;\;\;-2 \cdot x1 + x1\\ \mathbf{else}:\\ \;\;\;\;-6 \cdot x2\\ \end{array} \end{array} \]
                                                                                                                                                                (FPCore (x1 x2)
                                                                                                                                                                 :precision binary64
                                                                                                                                                                 (if (<= x1 -1.85e-115) (+ (* -2.0 x1) x1) (* -6.0 x2)))
                                                                                                                                                                double code(double x1, double x2) {
                                                                                                                                                                	double tmp;
                                                                                                                                                                	if (x1 <= -1.85e-115) {
                                                                                                                                                                		tmp = (-2.0 * x1) + x1;
                                                                                                                                                                	} else {
                                                                                                                                                                		tmp = -6.0 * x2;
                                                                                                                                                                	}
                                                                                                                                                                	return tmp;
                                                                                                                                                                }
                                                                                                                                                                
                                                                                                                                                                real(8) function code(x1, x2)
                                                                                                                                                                    real(8), intent (in) :: x1
                                                                                                                                                                    real(8), intent (in) :: x2
                                                                                                                                                                    real(8) :: tmp
                                                                                                                                                                    if (x1 <= (-1.85d-115)) then
                                                                                                                                                                        tmp = ((-2.0d0) * x1) + x1
                                                                                                                                                                    else
                                                                                                                                                                        tmp = (-6.0d0) * x2
                                                                                                                                                                    end if
                                                                                                                                                                    code = tmp
                                                                                                                                                                end function
                                                                                                                                                                
                                                                                                                                                                public static double code(double x1, double x2) {
                                                                                                                                                                	double tmp;
                                                                                                                                                                	if (x1 <= -1.85e-115) {
                                                                                                                                                                		tmp = (-2.0 * x1) + x1;
                                                                                                                                                                	} else {
                                                                                                                                                                		tmp = -6.0 * x2;
                                                                                                                                                                	}
                                                                                                                                                                	return tmp;
                                                                                                                                                                }
                                                                                                                                                                
                                                                                                                                                                def code(x1, x2):
                                                                                                                                                                	tmp = 0
                                                                                                                                                                	if x1 <= -1.85e-115:
                                                                                                                                                                		tmp = (-2.0 * x1) + x1
                                                                                                                                                                	else:
                                                                                                                                                                		tmp = -6.0 * x2
                                                                                                                                                                	return tmp
                                                                                                                                                                
                                                                                                                                                                function code(x1, x2)
                                                                                                                                                                	tmp = 0.0
                                                                                                                                                                	if (x1 <= -1.85e-115)
                                                                                                                                                                		tmp = Float64(Float64(-2.0 * x1) + x1);
                                                                                                                                                                	else
                                                                                                                                                                		tmp = Float64(-6.0 * x2);
                                                                                                                                                                	end
                                                                                                                                                                	return tmp
                                                                                                                                                                end
                                                                                                                                                                
                                                                                                                                                                function tmp_2 = code(x1, x2)
                                                                                                                                                                	tmp = 0.0;
                                                                                                                                                                	if (x1 <= -1.85e-115)
                                                                                                                                                                		tmp = (-2.0 * x1) + x1;
                                                                                                                                                                	else
                                                                                                                                                                		tmp = -6.0 * x2;
                                                                                                                                                                	end
                                                                                                                                                                	tmp_2 = tmp;
                                                                                                                                                                end
                                                                                                                                                                
                                                                                                                                                                code[x1_, x2_] := If[LessEqual[x1, -1.85e-115], N[(N[(-2.0 * x1), $MachinePrecision] + x1), $MachinePrecision], N[(-6.0 * x2), $MachinePrecision]]
                                                                                                                                                                
                                                                                                                                                                \begin{array}{l}
                                                                                                                                                                
                                                                                                                                                                \\
                                                                                                                                                                \begin{array}{l}
                                                                                                                                                                \mathbf{if}\;x1 \leq -1.85 \cdot 10^{-115}:\\
                                                                                                                                                                \;\;\;\;-2 \cdot x1 + x1\\
                                                                                                                                                                
                                                                                                                                                                \mathbf{else}:\\
                                                                                                                                                                \;\;\;\;-6 \cdot x2\\
                                                                                                                                                                
                                                                                                                                                                
                                                                                                                                                                \end{array}
                                                                                                                                                                \end{array}
                                                                                                                                                                
                                                                                                                                                                Derivation
                                                                                                                                                                1. Split input into 2 regimes
                                                                                                                                                                2. if x1 < -1.85e-115

                                                                                                                                                                  1. Initial program 49.7%

                                                                                                                                                                    \[x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                                                                                                                                                                  2. Add Preprocessing
                                                                                                                                                                  3. Taylor expanded in x1 around 0

                                                                                                                                                                    \[\leadsto x1 + \color{blue}{\left(-6 \cdot x2 + x1 \cdot \left(\left(4 \cdot \left(x2 \cdot \left(2 \cdot x2 - 3\right)\right) + x1 \cdot \left(\left(2 \cdot \left(-2 \cdot x2 + -1 \cdot \left(2 \cdot x2 - 3\right)\right) + \left(3 \cdot \left(3 - -2 \cdot x2\right) + \left(6 \cdot x2 + 8 \cdot x2\right)\right)\right) - 6\right)\right) - 2\right)\right)} \]
                                                                                                                                                                  4. Applied rewrites61.2%

                                                                                                                                                                    \[\leadsto x1 + \color{blue}{\mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(-4, x2, \mathsf{fma}\left(\mathsf{fma}\left(-2, x2, 3\right), 2, \mathsf{fma}\left(\mathsf{fma}\left(2, x2, 3\right), 3, \mathsf{fma}\left(14, x2, -6\right)\right)\right)\right), x1, \mathsf{fma}\left(\mathsf{fma}\left(2, x2, -3\right) \cdot 4, x2, -2\right)\right), x1, -6 \cdot x2\right)} \]
                                                                                                                                                                  5. Taylor expanded in x2 around 0

                                                                                                                                                                    \[\leadsto x1 + x1 \cdot \color{blue}{\left(9 \cdot x1 - 2\right)} \]
                                                                                                                                                                  6. Step-by-step derivation
                                                                                                                                                                    1. Applied rewrites50.2%

                                                                                                                                                                      \[\leadsto x1 + \mathsf{fma}\left(x1, 9, -2\right) \cdot \color{blue}{x1} \]
                                                                                                                                                                    2. Taylor expanded in x1 around 0

                                                                                                                                                                      \[\leadsto x1 + -2 \cdot x1 \]
                                                                                                                                                                    3. Step-by-step derivation
                                                                                                                                                                      1. Applied rewrites15.1%

                                                                                                                                                                        \[\leadsto x1 + -2 \cdot x1 \]

                                                                                                                                                                      if -1.85e-115 < x1

                                                                                                                                                                      1. Initial program 75.9%

                                                                                                                                                                        \[x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                                                                                                                                                                      2. Add Preprocessing
                                                                                                                                                                      3. Taylor expanded in x1 around 0

                                                                                                                                                                        \[\leadsto x1 + \color{blue}{-6 \cdot x2} \]
                                                                                                                                                                      4. Step-by-step derivation
                                                                                                                                                                        1. lower-*.f6443.5

                                                                                                                                                                          \[\leadsto x1 + \color{blue}{-6 \cdot x2} \]
                                                                                                                                                                      5. Applied rewrites43.5%

                                                                                                                                                                        \[\leadsto x1 + \color{blue}{-6 \cdot x2} \]
                                                                                                                                                                      6. Taylor expanded in x1 around 0

                                                                                                                                                                        \[\leadsto \color{blue}{-6 \cdot x2} \]
                                                                                                                                                                      7. Step-by-step derivation
                                                                                                                                                                        1. lower-*.f6442.3

                                                                                                                                                                          \[\leadsto \color{blue}{-6 \cdot x2} \]
                                                                                                                                                                      8. Applied rewrites42.3%

                                                                                                                                                                        \[\leadsto \color{blue}{-6 \cdot x2} \]
                                                                                                                                                                    4. Recombined 2 regimes into one program.
                                                                                                                                                                    5. Final simplification32.5%

                                                                                                                                                                      \[\leadsto \begin{array}{l} \mathbf{if}\;x1 \leq -1.85 \cdot 10^{-115}:\\ \;\;\;\;-2 \cdot x1 + x1\\ \mathbf{else}:\\ \;\;\;\;-6 \cdot x2\\ \end{array} \]
                                                                                                                                                                    6. Add Preprocessing

                                                                                                                                                                    Alternative 23: 26.4% accurate, 49.7× speedup?

                                                                                                                                                                    \[\begin{array}{l} \\ -6 \cdot x2 \end{array} \]
                                                                                                                                                                    (FPCore (x1 x2) :precision binary64 (* -6.0 x2))
                                                                                                                                                                    double code(double x1, double x2) {
                                                                                                                                                                    	return -6.0 * x2;
                                                                                                                                                                    }
                                                                                                                                                                    
                                                                                                                                                                    real(8) function code(x1, x2)
                                                                                                                                                                        real(8), intent (in) :: x1
                                                                                                                                                                        real(8), intent (in) :: x2
                                                                                                                                                                        code = (-6.0d0) * x2
                                                                                                                                                                    end function
                                                                                                                                                                    
                                                                                                                                                                    public static double code(double x1, double x2) {
                                                                                                                                                                    	return -6.0 * x2;
                                                                                                                                                                    }
                                                                                                                                                                    
                                                                                                                                                                    def code(x1, x2):
                                                                                                                                                                    	return -6.0 * x2
                                                                                                                                                                    
                                                                                                                                                                    function code(x1, x2)
                                                                                                                                                                    	return Float64(-6.0 * x2)
                                                                                                                                                                    end
                                                                                                                                                                    
                                                                                                                                                                    function tmp = code(x1, x2)
                                                                                                                                                                    	tmp = -6.0 * x2;
                                                                                                                                                                    end
                                                                                                                                                                    
                                                                                                                                                                    code[x1_, x2_] := N[(-6.0 * x2), $MachinePrecision]
                                                                                                                                                                    
                                                                                                                                                                    \begin{array}{l}
                                                                                                                                                                    
                                                                                                                                                                    \\
                                                                                                                                                                    -6 \cdot x2
                                                                                                                                                                    \end{array}
                                                                                                                                                                    
                                                                                                                                                                    Derivation
                                                                                                                                                                    1. Initial program 66.5%

                                                                                                                                                                      \[x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                                                                                                                                                                    2. Add Preprocessing
                                                                                                                                                                    3. Taylor expanded in x1 around 0

                                                                                                                                                                      \[\leadsto x1 + \color{blue}{-6 \cdot x2} \]
                                                                                                                                                                    4. Step-by-step derivation
                                                                                                                                                                      1. lower-*.f6428.8

                                                                                                                                                                        \[\leadsto x1 + \color{blue}{-6 \cdot x2} \]
                                                                                                                                                                    5. Applied rewrites28.8%

                                                                                                                                                                      \[\leadsto x1 + \color{blue}{-6 \cdot x2} \]
                                                                                                                                                                    6. Taylor expanded in x1 around 0

                                                                                                                                                                      \[\leadsto \color{blue}{-6 \cdot x2} \]
                                                                                                                                                                    7. Step-by-step derivation
                                                                                                                                                                      1. lower-*.f6428.4

                                                                                                                                                                        \[\leadsto \color{blue}{-6 \cdot x2} \]
                                                                                                                                                                    8. Applied rewrites28.4%

                                                                                                                                                                      \[\leadsto \color{blue}{-6 \cdot x2} \]
                                                                                                                                                                    9. Add Preprocessing

                                                                                                                                                                    Reproduce

                                                                                                                                                                    ?
                                                                                                                                                                    herbie shell --seed 2024235 
                                                                                                                                                                    (FPCore (x1 x2)
                                                                                                                                                                      :name "Rosa's FloatVsDoubleBenchmark"
                                                                                                                                                                      :precision binary64
                                                                                                                                                                      (+ x1 (+ (+ (+ (+ (* (+ (* (* (* 2.0 x1) (/ (- (+ (* (* 3.0 x1) x1) (* 2.0 x2)) x1) (+ (* x1 x1) 1.0))) (- (/ (- (+ (* (* 3.0 x1) x1) (* 2.0 x2)) x1) (+ (* x1 x1) 1.0)) 3.0)) (* (* x1 x1) (- (* 4.0 (/ (- (+ (* (* 3.0 x1) x1) (* 2.0 x2)) x1) (+ (* x1 x1) 1.0))) 6.0))) (+ (* x1 x1) 1.0)) (* (* (* 3.0 x1) x1) (/ (- (+ (* (* 3.0 x1) x1) (* 2.0 x2)) x1) (+ (* x1 x1) 1.0)))) (* (* x1 x1) x1)) x1) (* 3.0 (/ (- (- (* (* 3.0 x1) x1) (* 2.0 x2)) x1) (+ (* x1 x1) 1.0))))))