Data.Random.Distribution.Normal:normalF from random-fu-0.2.6.2

Percentage Accurate: 100.0% → 100.0%
Time: 26.1s
Alternatives: 14
Speedup: 1.0×

Specification

?
\[\begin{array}{l} \\ e^{\left(x \cdot y\right) \cdot y} \end{array} \]
(FPCore (x y) :precision binary64 (exp (* (* x y) y)))
double code(double x, double y) {
	return exp(((x * y) * y));
}
real(8) function code(x, y)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    code = exp(((x * y) * y))
end function
public static double code(double x, double y) {
	return Math.exp(((x * y) * y));
}
def code(x, y):
	return math.exp(((x * y) * y))
function code(x, y)
	return exp(Float64(Float64(x * y) * y))
end
function tmp = code(x, y)
	tmp = exp(((x * y) * y));
end
code[x_, y_] := N[Exp[N[(N[(x * y), $MachinePrecision] * y), $MachinePrecision]], $MachinePrecision]
\begin{array}{l}

\\
e^{\left(x \cdot y\right) \cdot y}
\end{array}

Sampling outcomes in binary64 precision:

Local Percentage Accuracy vs ?

The average percentage accuracy by input value. Horizontal axis shows value of an input variable; the variable is choosen in the title. Vertical axis is accuracy; higher is better. Red represent the original program, while blue represents Herbie's suggestion. These can be toggled with buttons below the plot. The line is an average while dots represent individual samples.

Accuracy vs Speed?

Herbie found 14 alternatives:

AlternativeAccuracySpeedup
The accuracy (vertical axis) and speed (horizontal axis) of each alternatives. Up and to the right is better. The red square shows the initial program, and each blue circle shows an alternative.The line shows the best available speed-accuracy tradeoffs.

Initial Program: 100.0% accurate, 1.0× speedup?

\[\begin{array}{l} \\ e^{\left(x \cdot y\right) \cdot y} \end{array} \]
(FPCore (x y) :precision binary64 (exp (* (* x y) y)))
double code(double x, double y) {
	return exp(((x * y) * y));
}
real(8) function code(x, y)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    code = exp(((x * y) * y))
end function
public static double code(double x, double y) {
	return Math.exp(((x * y) * y));
}
def code(x, y):
	return math.exp(((x * y) * y))
function code(x, y)
	return exp(Float64(Float64(x * y) * y))
end
function tmp = code(x, y)
	tmp = exp(((x * y) * y));
end
code[x_, y_] := N[Exp[N[(N[(x * y), $MachinePrecision] * y), $MachinePrecision]], $MachinePrecision]
\begin{array}{l}

\\
e^{\left(x \cdot y\right) \cdot y}
\end{array}

Alternative 1: 100.0% accurate, 1.0× speedup?

\[\begin{array}{l} \\ e^{\left(y \cdot x\right) \cdot y} \end{array} \]
(FPCore (x y) :precision binary64 (exp (* (* y x) y)))
double code(double x, double y) {
	return exp(((y * x) * y));
}
real(8) function code(x, y)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    code = exp(((y * x) * y))
end function
public static double code(double x, double y) {
	return Math.exp(((y * x) * y));
}
def code(x, y):
	return math.exp(((y * x) * y))
function code(x, y)
	return exp(Float64(Float64(y * x) * y))
end
function tmp = code(x, y)
	tmp = exp(((y * x) * y));
end
code[x_, y_] := N[Exp[N[(N[(y * x), $MachinePrecision] * y), $MachinePrecision]], $MachinePrecision]
\begin{array}{l}

\\
e^{\left(y \cdot x\right) \cdot y}
\end{array}
Derivation
  1. Initial program 100.0%

    \[e^{\left(x \cdot y\right) \cdot y} \]
  2. Add Preprocessing
  3. Final simplification100.0%

    \[\leadsto e^{\left(y \cdot x\right) \cdot y} \]
  4. Add Preprocessing

Alternative 2: 65.9% accurate, 0.9× speedup?

\[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;e^{\left(y \cdot x\right) \cdot y} \leq 2:\\ \;\;\;\;\mathsf{fma}\left(y \cdot x, y, 1\right)\\ \mathbf{else}:\\ \;\;\;\;\left(y \cdot y\right) \cdot x\\ \end{array} \end{array} \]
(FPCore (x y)
 :precision binary64
 (if (<= (exp (* (* y x) y)) 2.0) (fma (* y x) y 1.0) (* (* y y) x)))
double code(double x, double y) {
	double tmp;
	if (exp(((y * x) * y)) <= 2.0) {
		tmp = fma((y * x), y, 1.0);
	} else {
		tmp = (y * y) * x;
	}
	return tmp;
}
function code(x, y)
	tmp = 0.0
	if (exp(Float64(Float64(y * x) * y)) <= 2.0)
		tmp = fma(Float64(y * x), y, 1.0);
	else
		tmp = Float64(Float64(y * y) * x);
	end
	return tmp
end
code[x_, y_] := If[LessEqual[N[Exp[N[(N[(y * x), $MachinePrecision] * y), $MachinePrecision]], $MachinePrecision], 2.0], N[(N[(y * x), $MachinePrecision] * y + 1.0), $MachinePrecision], N[(N[(y * y), $MachinePrecision] * x), $MachinePrecision]]
\begin{array}{l}

\\
\begin{array}{l}
\mathbf{if}\;e^{\left(y \cdot x\right) \cdot y} \leq 2:\\
\;\;\;\;\mathsf{fma}\left(y \cdot x, y, 1\right)\\

\mathbf{else}:\\
\;\;\;\;\left(y \cdot y\right) \cdot x\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if (exp.f64 (*.f64 (*.f64 x y) y)) < 2

    1. Initial program 100.0%

      \[e^{\left(x \cdot y\right) \cdot y} \]
    2. Add Preprocessing
    3. Taylor expanded in x around 0

      \[\leadsto \color{blue}{1 + x \cdot {y}^{2}} \]
    4. Step-by-step derivation
      1. +-commutativeN/A

        \[\leadsto \color{blue}{x \cdot {y}^{2} + 1} \]
      2. *-commutativeN/A

        \[\leadsto \color{blue}{{y}^{2} \cdot x} + 1 \]
      3. lower-fma.f64N/A

        \[\leadsto \color{blue}{\mathsf{fma}\left({y}^{2}, x, 1\right)} \]
      4. unpow2N/A

        \[\leadsto \mathsf{fma}\left(\color{blue}{y \cdot y}, x, 1\right) \]
      5. lower-*.f6469.7

        \[\leadsto \mathsf{fma}\left(\color{blue}{y \cdot y}, x, 1\right) \]
    5. Applied rewrites69.7%

      \[\leadsto \color{blue}{\mathsf{fma}\left(y \cdot y, x, 1\right)} \]
    6. Step-by-step derivation
      1. Applied rewrites69.7%

        \[\leadsto \mathsf{fma}\left(y \cdot x, \color{blue}{y}, 1\right) \]

      if 2 < (exp.f64 (*.f64 (*.f64 x y) y))

      1. Initial program 100.0%

        \[e^{\left(x \cdot y\right) \cdot y} \]
      2. Add Preprocessing
      3. Taylor expanded in x around 0

        \[\leadsto \color{blue}{1 + x \cdot {y}^{2}} \]
      4. Step-by-step derivation
        1. +-commutativeN/A

          \[\leadsto \color{blue}{x \cdot {y}^{2} + 1} \]
        2. *-commutativeN/A

          \[\leadsto \color{blue}{{y}^{2} \cdot x} + 1 \]
        3. lower-fma.f64N/A

          \[\leadsto \color{blue}{\mathsf{fma}\left({y}^{2}, x, 1\right)} \]
        4. unpow2N/A

          \[\leadsto \mathsf{fma}\left(\color{blue}{y \cdot y}, x, 1\right) \]
        5. lower-*.f6465.1

          \[\leadsto \mathsf{fma}\left(\color{blue}{y \cdot y}, x, 1\right) \]
      5. Applied rewrites65.1%

        \[\leadsto \color{blue}{\mathsf{fma}\left(y \cdot y, x, 1\right)} \]
      6. Taylor expanded in y around inf

        \[\leadsto x \cdot \color{blue}{{y}^{2}} \]
      7. Step-by-step derivation
        1. Applied rewrites65.1%

          \[\leadsto \left(y \cdot y\right) \cdot \color{blue}{x} \]
      8. Recombined 2 regimes into one program.
      9. Final simplification68.3%

        \[\leadsto \begin{array}{l} \mathbf{if}\;e^{\left(y \cdot x\right) \cdot y} \leq 2:\\ \;\;\;\;\mathsf{fma}\left(y \cdot x, y, 1\right)\\ \mathbf{else}:\\ \;\;\;\;\left(y \cdot y\right) \cdot x\\ \end{array} \]
      10. Add Preprocessing

      Alternative 3: 65.9% accurate, 0.9× speedup?

      \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;e^{\left(y \cdot x\right) \cdot y} \leq 2:\\ \;\;\;\;1\\ \mathbf{else}:\\ \;\;\;\;\left(y \cdot y\right) \cdot x\\ \end{array} \end{array} \]
      (FPCore (x y)
       :precision binary64
       (if (<= (exp (* (* y x) y)) 2.0) 1.0 (* (* y y) x)))
      double code(double x, double y) {
      	double tmp;
      	if (exp(((y * x) * y)) <= 2.0) {
      		tmp = 1.0;
      	} else {
      		tmp = (y * y) * x;
      	}
      	return tmp;
      }
      
      real(8) function code(x, y)
          real(8), intent (in) :: x
          real(8), intent (in) :: y
          real(8) :: tmp
          if (exp(((y * x) * y)) <= 2.0d0) then
              tmp = 1.0d0
          else
              tmp = (y * y) * x
          end if
          code = tmp
      end function
      
      public static double code(double x, double y) {
      	double tmp;
      	if (Math.exp(((y * x) * y)) <= 2.0) {
      		tmp = 1.0;
      	} else {
      		tmp = (y * y) * x;
      	}
      	return tmp;
      }
      
      def code(x, y):
      	tmp = 0
      	if math.exp(((y * x) * y)) <= 2.0:
      		tmp = 1.0
      	else:
      		tmp = (y * y) * x
      	return tmp
      
      function code(x, y)
      	tmp = 0.0
      	if (exp(Float64(Float64(y * x) * y)) <= 2.0)
      		tmp = 1.0;
      	else
      		tmp = Float64(Float64(y * y) * x);
      	end
      	return tmp
      end
      
      function tmp_2 = code(x, y)
      	tmp = 0.0;
      	if (exp(((y * x) * y)) <= 2.0)
      		tmp = 1.0;
      	else
      		tmp = (y * y) * x;
      	end
      	tmp_2 = tmp;
      end
      
      code[x_, y_] := If[LessEqual[N[Exp[N[(N[(y * x), $MachinePrecision] * y), $MachinePrecision]], $MachinePrecision], 2.0], 1.0, N[(N[(y * y), $MachinePrecision] * x), $MachinePrecision]]
      
      \begin{array}{l}
      
      \\
      \begin{array}{l}
      \mathbf{if}\;e^{\left(y \cdot x\right) \cdot y} \leq 2:\\
      \;\;\;\;1\\
      
      \mathbf{else}:\\
      \;\;\;\;\left(y \cdot y\right) \cdot x\\
      
      
      \end{array}
      \end{array}
      
      Derivation
      1. Split input into 2 regimes
      2. if (exp.f64 (*.f64 (*.f64 x y) y)) < 2

        1. Initial program 100.0%

          \[e^{\left(x \cdot y\right) \cdot y} \]
        2. Add Preprocessing
        3. Taylor expanded in x around 0

          \[\leadsto \color{blue}{1} \]
        4. Step-by-step derivation
          1. Applied rewrites69.4%

            \[\leadsto \color{blue}{1} \]

          if 2 < (exp.f64 (*.f64 (*.f64 x y) y))

          1. Initial program 100.0%

            \[e^{\left(x \cdot y\right) \cdot y} \]
          2. Add Preprocessing
          3. Taylor expanded in x around 0

            \[\leadsto \color{blue}{1 + x \cdot {y}^{2}} \]
          4. Step-by-step derivation
            1. +-commutativeN/A

              \[\leadsto \color{blue}{x \cdot {y}^{2} + 1} \]
            2. *-commutativeN/A

              \[\leadsto \color{blue}{{y}^{2} \cdot x} + 1 \]
            3. lower-fma.f64N/A

              \[\leadsto \color{blue}{\mathsf{fma}\left({y}^{2}, x, 1\right)} \]
            4. unpow2N/A

              \[\leadsto \mathsf{fma}\left(\color{blue}{y \cdot y}, x, 1\right) \]
            5. lower-*.f6465.1

              \[\leadsto \mathsf{fma}\left(\color{blue}{y \cdot y}, x, 1\right) \]
          5. Applied rewrites65.1%

            \[\leadsto \color{blue}{\mathsf{fma}\left(y \cdot y, x, 1\right)} \]
          6. Taylor expanded in y around inf

            \[\leadsto x \cdot \color{blue}{{y}^{2}} \]
          7. Step-by-step derivation
            1. Applied rewrites65.1%

              \[\leadsto \left(y \cdot y\right) \cdot \color{blue}{x} \]
          8. Recombined 2 regimes into one program.
          9. Final simplification68.1%

            \[\leadsto \begin{array}{l} \mathbf{if}\;e^{\left(y \cdot x\right) \cdot y} \leq 2:\\ \;\;\;\;1\\ \mathbf{else}:\\ \;\;\;\;\left(y \cdot y\right) \cdot x\\ \end{array} \]
          10. Add Preprocessing

          Alternative 4: 53.9% accurate, 0.9× speedup?

          \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;e^{\left(y \cdot x\right) \cdot y} \leq 2:\\ \;\;\;\;1\\ \mathbf{else}:\\ \;\;\;\;\mathsf{fma}\left(y, x, 1\right)\\ \end{array} \end{array} \]
          (FPCore (x y)
           :precision binary64
           (if (<= (exp (* (* y x) y)) 2.0) 1.0 (fma y x 1.0)))
          double code(double x, double y) {
          	double tmp;
          	if (exp(((y * x) * y)) <= 2.0) {
          		tmp = 1.0;
          	} else {
          		tmp = fma(y, x, 1.0);
          	}
          	return tmp;
          }
          
          function code(x, y)
          	tmp = 0.0
          	if (exp(Float64(Float64(y * x) * y)) <= 2.0)
          		tmp = 1.0;
          	else
          		tmp = fma(y, x, 1.0);
          	end
          	return tmp
          end
          
          code[x_, y_] := If[LessEqual[N[Exp[N[(N[(y * x), $MachinePrecision] * y), $MachinePrecision]], $MachinePrecision], 2.0], 1.0, N[(y * x + 1.0), $MachinePrecision]]
          
          \begin{array}{l}
          
          \\
          \begin{array}{l}
          \mathbf{if}\;e^{\left(y \cdot x\right) \cdot y} \leq 2:\\
          \;\;\;\;1\\
          
          \mathbf{else}:\\
          \;\;\;\;\mathsf{fma}\left(y, x, 1\right)\\
          
          
          \end{array}
          \end{array}
          
          Derivation
          1. Split input into 2 regimes
          2. if (exp.f64 (*.f64 (*.f64 x y) y)) < 2

            1. Initial program 100.0%

              \[e^{\left(x \cdot y\right) \cdot y} \]
            2. Add Preprocessing
            3. Taylor expanded in x around 0

              \[\leadsto \color{blue}{1} \]
            4. Step-by-step derivation
              1. Applied rewrites69.4%

                \[\leadsto \color{blue}{1} \]

              if 2 < (exp.f64 (*.f64 (*.f64 x y) y))

              1. Initial program 100.0%

                \[e^{\left(x \cdot y\right) \cdot y} \]
              2. Add Preprocessing
              3. Applied rewrites55.4%

                \[\leadsto e^{\color{blue}{x} \cdot y} \]
              4. Taylor expanded in x around 0

                \[\leadsto \color{blue}{1 + x \cdot y} \]
              5. Step-by-step derivation
                1. +-commutativeN/A

                  \[\leadsto \color{blue}{x \cdot y + 1} \]
                2. *-commutativeN/A

                  \[\leadsto \color{blue}{y \cdot x} + 1 \]
                3. lower-fma.f6416.6

                  \[\leadsto \color{blue}{\mathsf{fma}\left(y, x, 1\right)} \]
              6. Applied rewrites16.6%

                \[\leadsto \color{blue}{\mathsf{fma}\left(y, x, 1\right)} \]
            5. Recombined 2 regimes into one program.
            6. Final simplification53.1%

              \[\leadsto \begin{array}{l} \mathbf{if}\;e^{\left(y \cdot x\right) \cdot y} \leq 2:\\ \;\;\;\;1\\ \mathbf{else}:\\ \;\;\;\;\mathsf{fma}\left(y, x, 1\right)\\ \end{array} \]
            7. Add Preprocessing

            Alternative 5: 82.4% accurate, 0.9× speedup?

            \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;\left(y \cdot x\right) \cdot y \leq -5000000000000:\\ \;\;\;\;e^{y \cdot x}\\ \mathbf{else}:\\ \;\;\;\;\mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(0.16666666666666666 \cdot y, y \cdot x, 0.5\right) \cdot x, y \cdot y, 1\right) \cdot y, y \cdot x, 1\right)\\ \end{array} \end{array} \]
            (FPCore (x y)
             :precision binary64
             (if (<= (* (* y x) y) -5000000000000.0)
               (exp (* y x))
               (fma
                (* (fma (* (fma (* 0.16666666666666666 y) (* y x) 0.5) x) (* y y) 1.0) y)
                (* y x)
                1.0)))
            double code(double x, double y) {
            	double tmp;
            	if (((y * x) * y) <= -5000000000000.0) {
            		tmp = exp((y * x));
            	} else {
            		tmp = fma((fma((fma((0.16666666666666666 * y), (y * x), 0.5) * x), (y * y), 1.0) * y), (y * x), 1.0);
            	}
            	return tmp;
            }
            
            function code(x, y)
            	tmp = 0.0
            	if (Float64(Float64(y * x) * y) <= -5000000000000.0)
            		tmp = exp(Float64(y * x));
            	else
            		tmp = fma(Float64(fma(Float64(fma(Float64(0.16666666666666666 * y), Float64(y * x), 0.5) * x), Float64(y * y), 1.0) * y), Float64(y * x), 1.0);
            	end
            	return tmp
            end
            
            code[x_, y_] := If[LessEqual[N[(N[(y * x), $MachinePrecision] * y), $MachinePrecision], -5000000000000.0], N[Exp[N[(y * x), $MachinePrecision]], $MachinePrecision], N[(N[(N[(N[(N[(N[(0.16666666666666666 * y), $MachinePrecision] * N[(y * x), $MachinePrecision] + 0.5), $MachinePrecision] * x), $MachinePrecision] * N[(y * y), $MachinePrecision] + 1.0), $MachinePrecision] * y), $MachinePrecision] * N[(y * x), $MachinePrecision] + 1.0), $MachinePrecision]]
            
            \begin{array}{l}
            
            \\
            \begin{array}{l}
            \mathbf{if}\;\left(y \cdot x\right) \cdot y \leq -5000000000000:\\
            \;\;\;\;e^{y \cdot x}\\
            
            \mathbf{else}:\\
            \;\;\;\;\mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(0.16666666666666666 \cdot y, y \cdot x, 0.5\right) \cdot x, y \cdot y, 1\right) \cdot y, y \cdot x, 1\right)\\
            
            
            \end{array}
            \end{array}
            
            Derivation
            1. Split input into 2 regimes
            2. if (*.f64 (*.f64 x y) y) < -5e12

              1. Initial program 100.0%

                \[e^{\left(x \cdot y\right) \cdot y} \]
              2. Add Preprocessing
              3. Applied rewrites38.2%

                \[\leadsto e^{\color{blue}{x} \cdot y} \]

              if -5e12 < (*.f64 (*.f64 x y) y)

              1. Initial program 100.0%

                \[e^{\left(x \cdot y\right) \cdot y} \]
              2. Add Preprocessing
              3. Taylor expanded in x around 0

                \[\leadsto \color{blue}{1 + x \cdot \left(x \cdot \left(\frac{1}{6} \cdot \left(x \cdot {y}^{6}\right) + \frac{1}{2} \cdot {y}^{4}\right) + {y}^{2}\right)} \]
              4. Applied rewrites95.3%

                \[\leadsto \color{blue}{\mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(0.16666666666666666 \cdot y, y \cdot x, 0.5\right) \cdot x, y \cdot y, 1\right) \cdot y, y \cdot x, 1\right)} \]
            3. Recombined 2 regimes into one program.
            4. Final simplification83.2%

              \[\leadsto \begin{array}{l} \mathbf{if}\;\left(y \cdot x\right) \cdot y \leq -5000000000000:\\ \;\;\;\;e^{y \cdot x}\\ \mathbf{else}:\\ \;\;\;\;\mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(0.16666666666666666 \cdot y, y \cdot x, 0.5\right) \cdot x, y \cdot y, 1\right) \cdot y, y \cdot x, 1\right)\\ \end{array} \]
            5. Add Preprocessing

            Alternative 6: 86.9% accurate, 0.9× speedup?

            \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;\left(y \cdot x\right) \cdot y \leq -5000000000000:\\ \;\;\;\;e^{x}\\ \mathbf{else}:\\ \;\;\;\;\mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(0.16666666666666666 \cdot y, y \cdot x, 0.5\right) \cdot x, y \cdot y, 1\right) \cdot y, y \cdot x, 1\right)\\ \end{array} \end{array} \]
            (FPCore (x y)
             :precision binary64
             (if (<= (* (* y x) y) -5000000000000.0)
               (exp x)
               (fma
                (* (fma (* (fma (* 0.16666666666666666 y) (* y x) 0.5) x) (* y y) 1.0) y)
                (* y x)
                1.0)))
            double code(double x, double y) {
            	double tmp;
            	if (((y * x) * y) <= -5000000000000.0) {
            		tmp = exp(x);
            	} else {
            		tmp = fma((fma((fma((0.16666666666666666 * y), (y * x), 0.5) * x), (y * y), 1.0) * y), (y * x), 1.0);
            	}
            	return tmp;
            }
            
            function code(x, y)
            	tmp = 0.0
            	if (Float64(Float64(y * x) * y) <= -5000000000000.0)
            		tmp = exp(x);
            	else
            		tmp = fma(Float64(fma(Float64(fma(Float64(0.16666666666666666 * y), Float64(y * x), 0.5) * x), Float64(y * y), 1.0) * y), Float64(y * x), 1.0);
            	end
            	return tmp
            end
            
            code[x_, y_] := If[LessEqual[N[(N[(y * x), $MachinePrecision] * y), $MachinePrecision], -5000000000000.0], N[Exp[x], $MachinePrecision], N[(N[(N[(N[(N[(N[(0.16666666666666666 * y), $MachinePrecision] * N[(y * x), $MachinePrecision] + 0.5), $MachinePrecision] * x), $MachinePrecision] * N[(y * y), $MachinePrecision] + 1.0), $MachinePrecision] * y), $MachinePrecision] * N[(y * x), $MachinePrecision] + 1.0), $MachinePrecision]]
            
            \begin{array}{l}
            
            \\
            \begin{array}{l}
            \mathbf{if}\;\left(y \cdot x\right) \cdot y \leq -5000000000000:\\
            \;\;\;\;e^{x}\\
            
            \mathbf{else}:\\
            \;\;\;\;\mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(0.16666666666666666 \cdot y, y \cdot x, 0.5\right) \cdot x, y \cdot y, 1\right) \cdot y, y \cdot x, 1\right)\\
            
            
            \end{array}
            \end{array}
            
            Derivation
            1. Split input into 2 regimes
            2. if (*.f64 (*.f64 x y) y) < -5e12

              1. Initial program 100.0%

                \[e^{\left(x \cdot y\right) \cdot y} \]
              2. Add Preprocessing
              3. Applied rewrites64.1%

                \[\leadsto e^{\color{blue}{x}} \]

              if -5e12 < (*.f64 (*.f64 x y) y)

              1. Initial program 100.0%

                \[e^{\left(x \cdot y\right) \cdot y} \]
              2. Add Preprocessing
              3. Taylor expanded in x around 0

                \[\leadsto \color{blue}{1 + x \cdot \left(x \cdot \left(\frac{1}{6} \cdot \left(x \cdot {y}^{6}\right) + \frac{1}{2} \cdot {y}^{4}\right) + {y}^{2}\right)} \]
              4. Applied rewrites95.3%

                \[\leadsto \color{blue}{\mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(0.16666666666666666 \cdot y, y \cdot x, 0.5\right) \cdot x, y \cdot y, 1\right) \cdot y, y \cdot x, 1\right)} \]
            3. Recombined 2 regimes into one program.
            4. Final simplification88.7%

              \[\leadsto \begin{array}{l} \mathbf{if}\;\left(y \cdot x\right) \cdot y \leq -5000000000000:\\ \;\;\;\;e^{x}\\ \mathbf{else}:\\ \;\;\;\;\mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(0.16666666666666666 \cdot y, y \cdot x, 0.5\right) \cdot x, y \cdot y, 1\right) \cdot y, y \cdot x, 1\right)\\ \end{array} \]
            5. Add Preprocessing

            Alternative 7: 73.5% accurate, 1.7× speedup?

            \[\begin{array}{l} \\ \begin{array}{l} t_0 := \left(y \cdot x\right) \cdot y\\ \mathbf{if}\;t\_0 \leq -1 \cdot 10^{+74}:\\ \;\;\;\;\left(\left(\left(x \cdot x\right) \cdot y\right) \cdot y\right) \cdot 0.5\\ \mathbf{elif}\;t\_0 \leq 10^{+15}:\\ \;\;\;\;\mathsf{fma}\left(\mathsf{fma}\left(\left(0.5 \cdot y\right) \cdot x, y, 1\right) \cdot y, y \cdot x, 1\right)\\ \mathbf{else}:\\ \;\;\;\;\left(\left(\left(\left(\left(y \cdot y\right) \cdot y\right) \cdot y\right) \cdot 0.5\right) \cdot x\right) \cdot x\\ \end{array} \end{array} \]
            (FPCore (x y)
             :precision binary64
             (let* ((t_0 (* (* y x) y)))
               (if (<= t_0 -1e+74)
                 (* (* (* (* x x) y) y) 0.5)
                 (if (<= t_0 1e+15)
                   (fma (* (fma (* (* 0.5 y) x) y 1.0) y) (* y x) 1.0)
                   (* (* (* (* (* (* y y) y) y) 0.5) x) x)))))
            double code(double x, double y) {
            	double t_0 = (y * x) * y;
            	double tmp;
            	if (t_0 <= -1e+74) {
            		tmp = (((x * x) * y) * y) * 0.5;
            	} else if (t_0 <= 1e+15) {
            		tmp = fma((fma(((0.5 * y) * x), y, 1.0) * y), (y * x), 1.0);
            	} else {
            		tmp = (((((y * y) * y) * y) * 0.5) * x) * x;
            	}
            	return tmp;
            }
            
            function code(x, y)
            	t_0 = Float64(Float64(y * x) * y)
            	tmp = 0.0
            	if (t_0 <= -1e+74)
            		tmp = Float64(Float64(Float64(Float64(x * x) * y) * y) * 0.5);
            	elseif (t_0 <= 1e+15)
            		tmp = fma(Float64(fma(Float64(Float64(0.5 * y) * x), y, 1.0) * y), Float64(y * x), 1.0);
            	else
            		tmp = Float64(Float64(Float64(Float64(Float64(Float64(y * y) * y) * y) * 0.5) * x) * x);
            	end
            	return tmp
            end
            
            code[x_, y_] := Block[{t$95$0 = N[(N[(y * x), $MachinePrecision] * y), $MachinePrecision]}, If[LessEqual[t$95$0, -1e+74], N[(N[(N[(N[(x * x), $MachinePrecision] * y), $MachinePrecision] * y), $MachinePrecision] * 0.5), $MachinePrecision], If[LessEqual[t$95$0, 1e+15], N[(N[(N[(N[(N[(0.5 * y), $MachinePrecision] * x), $MachinePrecision] * y + 1.0), $MachinePrecision] * y), $MachinePrecision] * N[(y * x), $MachinePrecision] + 1.0), $MachinePrecision], N[(N[(N[(N[(N[(N[(y * y), $MachinePrecision] * y), $MachinePrecision] * y), $MachinePrecision] * 0.5), $MachinePrecision] * x), $MachinePrecision] * x), $MachinePrecision]]]]
            
            \begin{array}{l}
            
            \\
            \begin{array}{l}
            t_0 := \left(y \cdot x\right) \cdot y\\
            \mathbf{if}\;t\_0 \leq -1 \cdot 10^{+74}:\\
            \;\;\;\;\left(\left(\left(x \cdot x\right) \cdot y\right) \cdot y\right) \cdot 0.5\\
            
            \mathbf{elif}\;t\_0 \leq 10^{+15}:\\
            \;\;\;\;\mathsf{fma}\left(\mathsf{fma}\left(\left(0.5 \cdot y\right) \cdot x, y, 1\right) \cdot y, y \cdot x, 1\right)\\
            
            \mathbf{else}:\\
            \;\;\;\;\left(\left(\left(\left(\left(y \cdot y\right) \cdot y\right) \cdot y\right) \cdot 0.5\right) \cdot x\right) \cdot x\\
            
            
            \end{array}
            \end{array}
            
            Derivation
            1. Split input into 3 regimes
            2. if (*.f64 (*.f64 x y) y) < -9.99999999999999952e73

              1. Initial program 100.0%

                \[e^{\left(x \cdot y\right) \cdot y} \]
              2. Add Preprocessing
              3. Applied rewrites41.9%

                \[\leadsto e^{\color{blue}{x} \cdot y} \]
              4. Taylor expanded in y around 0

                \[\leadsto \color{blue}{1 + y \cdot \left(x + y \cdot \left(\frac{1}{6} \cdot \left({x}^{3} \cdot y\right) + \frac{1}{2} \cdot {x}^{2}\right)\right)} \]
              5. Step-by-step derivation
                1. +-commutativeN/A

                  \[\leadsto \color{blue}{y \cdot \left(x + y \cdot \left(\frac{1}{6} \cdot \left({x}^{3} \cdot y\right) + \frac{1}{2} \cdot {x}^{2}\right)\right) + 1} \]
                2. *-commutativeN/A

                  \[\leadsto \color{blue}{\left(x + y \cdot \left(\frac{1}{6} \cdot \left({x}^{3} \cdot y\right) + \frac{1}{2} \cdot {x}^{2}\right)\right) \cdot y} + 1 \]
                3. lower-fma.f64N/A

                  \[\leadsto \color{blue}{\mathsf{fma}\left(x + y \cdot \left(\frac{1}{6} \cdot \left({x}^{3} \cdot y\right) + \frac{1}{2} \cdot {x}^{2}\right), y, 1\right)} \]
              6. Applied rewrites1.6%

                \[\leadsto \color{blue}{\mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(\left(\left(x \cdot x\right) \cdot x\right) \cdot y, 0.16666666666666666, \left(x \cdot x\right) \cdot 0.5\right), y, x\right), y, 1\right)} \]
              7. Taylor expanded in x around inf

                \[\leadsto {x}^{3} \cdot \color{blue}{\left(\frac{1}{6} \cdot {y}^{3} + \frac{1}{2} \cdot \frac{{y}^{2}}{x}\right)} \]
              8. Step-by-step derivation
                1. Applied rewrites1.4%

                  \[\leadsto \left(\left(y \cdot y\right) \cdot \mathsf{fma}\left(0.16666666666666666, y, \frac{0.5}{x}\right)\right) \cdot \color{blue}{\left(\left(x \cdot x\right) \cdot x\right)} \]
                2. Taylor expanded in y around 0

                  \[\leadsto \frac{1}{2} \cdot \left({x}^{2} \cdot \color{blue}{{y}^{2}}\right) \]
                3. Step-by-step derivation
                  1. Applied rewrites15.8%

                    \[\leadsto \left(\left(\left(x \cdot x\right) \cdot y\right) \cdot y\right) \cdot 0.5 \]

                  if -9.99999999999999952e73 < (*.f64 (*.f64 x y) y) < 1e15

                  1. Initial program 100.0%

                    \[e^{\left(x \cdot y\right) \cdot y} \]
                  2. Add Preprocessing
                  3. Taylor expanded in x around 0

                    \[\leadsto \color{blue}{1 + x \cdot \left(\frac{1}{2} \cdot \left(x \cdot {y}^{4}\right) + {y}^{2}\right)} \]
                  4. Applied rewrites95.4%

                    \[\leadsto \color{blue}{\mathsf{fma}\left(\mathsf{fma}\left(\left(0.5 \cdot y\right) \cdot x, y, 1\right) \cdot y, y \cdot x, 1\right)} \]

                  if 1e15 < (*.f64 (*.f64 x y) y)

                  1. Initial program 100.0%

                    \[e^{\left(x \cdot y\right) \cdot y} \]
                  2. Add Preprocessing
                  3. Taylor expanded in x around 0

                    \[\leadsto \color{blue}{1 + x \cdot \left(\frac{1}{2} \cdot \left(x \cdot {y}^{4}\right) + {y}^{2}\right)} \]
                  4. Applied rewrites79.3%

                    \[\leadsto \color{blue}{\mathsf{fma}\left(\mathsf{fma}\left(\left(0.5 \cdot y\right) \cdot x, y, 1\right) \cdot y, y \cdot x, 1\right)} \]
                  5. Taylor expanded in y around inf

                    \[\leadsto \frac{1}{2} \cdot \color{blue}{\left({x}^{2} \cdot {y}^{4}\right)} \]
                  6. Step-by-step derivation
                    1. Applied rewrites89.0%

                      \[\leadsto \left(\left(\left(\left(\left(y \cdot y\right) \cdot y\right) \cdot y\right) \cdot 0.5\right) \cdot x\right) \cdot \color{blue}{x} \]
                  7. Recombined 3 regimes into one program.
                  8. Final simplification78.2%

                    \[\leadsto \begin{array}{l} \mathbf{if}\;\left(y \cdot x\right) \cdot y \leq -1 \cdot 10^{+74}:\\ \;\;\;\;\left(\left(\left(x \cdot x\right) \cdot y\right) \cdot y\right) \cdot 0.5\\ \mathbf{elif}\;\left(y \cdot x\right) \cdot y \leq 10^{+15}:\\ \;\;\;\;\mathsf{fma}\left(\mathsf{fma}\left(\left(0.5 \cdot y\right) \cdot x, y, 1\right) \cdot y, y \cdot x, 1\right)\\ \mathbf{else}:\\ \;\;\;\;\left(\left(\left(\left(\left(y \cdot y\right) \cdot y\right) \cdot y\right) \cdot 0.5\right) \cdot x\right) \cdot x\\ \end{array} \]
                  9. Add Preprocessing

                  Alternative 8: 74.3% accurate, 1.7× speedup?

                  \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;\left(y \cdot x\right) \cdot y \leq -1 \cdot 10^{+72}:\\ \;\;\;\;\left(\left(\left(x \cdot x\right) \cdot y\right) \cdot y\right) \cdot 0.5\\ \mathbf{else}:\\ \;\;\;\;\mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(0.16666666666666666 \cdot y, y \cdot x, 0.5\right) \cdot x, y \cdot y, 1\right) \cdot y, y \cdot x, 1\right)\\ \end{array} \end{array} \]
                  (FPCore (x y)
                   :precision binary64
                   (if (<= (* (* y x) y) -1e+72)
                     (* (* (* (* x x) y) y) 0.5)
                     (fma
                      (* (fma (* (fma (* 0.16666666666666666 y) (* y x) 0.5) x) (* y y) 1.0) y)
                      (* y x)
                      1.0)))
                  double code(double x, double y) {
                  	double tmp;
                  	if (((y * x) * y) <= -1e+72) {
                  		tmp = (((x * x) * y) * y) * 0.5;
                  	} else {
                  		tmp = fma((fma((fma((0.16666666666666666 * y), (y * x), 0.5) * x), (y * y), 1.0) * y), (y * x), 1.0);
                  	}
                  	return tmp;
                  }
                  
                  function code(x, y)
                  	tmp = 0.0
                  	if (Float64(Float64(y * x) * y) <= -1e+72)
                  		tmp = Float64(Float64(Float64(Float64(x * x) * y) * y) * 0.5);
                  	else
                  		tmp = fma(Float64(fma(Float64(fma(Float64(0.16666666666666666 * y), Float64(y * x), 0.5) * x), Float64(y * y), 1.0) * y), Float64(y * x), 1.0);
                  	end
                  	return tmp
                  end
                  
                  code[x_, y_] := If[LessEqual[N[(N[(y * x), $MachinePrecision] * y), $MachinePrecision], -1e+72], N[(N[(N[(N[(x * x), $MachinePrecision] * y), $MachinePrecision] * y), $MachinePrecision] * 0.5), $MachinePrecision], N[(N[(N[(N[(N[(N[(0.16666666666666666 * y), $MachinePrecision] * N[(y * x), $MachinePrecision] + 0.5), $MachinePrecision] * x), $MachinePrecision] * N[(y * y), $MachinePrecision] + 1.0), $MachinePrecision] * y), $MachinePrecision] * N[(y * x), $MachinePrecision] + 1.0), $MachinePrecision]]
                  
                  \begin{array}{l}
                  
                  \\
                  \begin{array}{l}
                  \mathbf{if}\;\left(y \cdot x\right) \cdot y \leq -1 \cdot 10^{+72}:\\
                  \;\;\;\;\left(\left(\left(x \cdot x\right) \cdot y\right) \cdot y\right) \cdot 0.5\\
                  
                  \mathbf{else}:\\
                  \;\;\;\;\mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(0.16666666666666666 \cdot y, y \cdot x, 0.5\right) \cdot x, y \cdot y, 1\right) \cdot y, y \cdot x, 1\right)\\
                  
                  
                  \end{array}
                  \end{array}
                  
                  Derivation
                  1. Split input into 2 regimes
                  2. if (*.f64 (*.f64 x y) y) < -9.99999999999999944e71

                    1. Initial program 100.0%

                      \[e^{\left(x \cdot y\right) \cdot y} \]
                    2. Add Preprocessing
                    3. Applied rewrites41.1%

                      \[\leadsto e^{\color{blue}{x} \cdot y} \]
                    4. Taylor expanded in y around 0

                      \[\leadsto \color{blue}{1 + y \cdot \left(x + y \cdot \left(\frac{1}{6} \cdot \left({x}^{3} \cdot y\right) + \frac{1}{2} \cdot {x}^{2}\right)\right)} \]
                    5. Step-by-step derivation
                      1. +-commutativeN/A

                        \[\leadsto \color{blue}{y \cdot \left(x + y \cdot \left(\frac{1}{6} \cdot \left({x}^{3} \cdot y\right) + \frac{1}{2} \cdot {x}^{2}\right)\right) + 1} \]
                      2. *-commutativeN/A

                        \[\leadsto \color{blue}{\left(x + y \cdot \left(\frac{1}{6} \cdot \left({x}^{3} \cdot y\right) + \frac{1}{2} \cdot {x}^{2}\right)\right) \cdot y} + 1 \]
                      3. lower-fma.f64N/A

                        \[\leadsto \color{blue}{\mathsf{fma}\left(x + y \cdot \left(\frac{1}{6} \cdot \left({x}^{3} \cdot y\right) + \frac{1}{2} \cdot {x}^{2}\right), y, 1\right)} \]
                    6. Applied rewrites1.6%

                      \[\leadsto \color{blue}{\mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(\left(\left(x \cdot x\right) \cdot x\right) \cdot y, 0.16666666666666666, \left(x \cdot x\right) \cdot 0.5\right), y, x\right), y, 1\right)} \]
                    7. Taylor expanded in x around inf

                      \[\leadsto {x}^{3} \cdot \color{blue}{\left(\frac{1}{6} \cdot {y}^{3} + \frac{1}{2} \cdot \frac{{y}^{2}}{x}\right)} \]
                    8. Step-by-step derivation
                      1. Applied rewrites1.4%

                        \[\leadsto \left(\left(y \cdot y\right) \cdot \mathsf{fma}\left(0.16666666666666666, y, \frac{0.5}{x}\right)\right) \cdot \color{blue}{\left(\left(x \cdot x\right) \cdot x\right)} \]
                      2. Taylor expanded in y around 0

                        \[\leadsto \frac{1}{2} \cdot \left({x}^{2} \cdot \color{blue}{{y}^{2}}\right) \]
                      3. Step-by-step derivation
                        1. Applied rewrites15.5%

                          \[\leadsto \left(\left(\left(x \cdot x\right) \cdot y\right) \cdot y\right) \cdot 0.5 \]

                        if -9.99999999999999944e71 < (*.f64 (*.f64 x y) y)

                        1. Initial program 100.0%

                          \[e^{\left(x \cdot y\right) \cdot y} \]
                        2. Add Preprocessing
                        3. Taylor expanded in x around 0

                          \[\leadsto \color{blue}{1 + x \cdot \left(x \cdot \left(\frac{1}{6} \cdot \left(x \cdot {y}^{6}\right) + \frac{1}{2} \cdot {y}^{4}\right) + {y}^{2}\right)} \]
                        4. Applied rewrites93.5%

                          \[\leadsto \color{blue}{\mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(0.16666666666666666 \cdot y, y \cdot x, 0.5\right) \cdot x, y \cdot y, 1\right) \cdot y, y \cdot x, 1\right)} \]
                      4. Recombined 2 regimes into one program.
                      5. Final simplification78.3%

                        \[\leadsto \begin{array}{l} \mathbf{if}\;\left(y \cdot x\right) \cdot y \leq -1 \cdot 10^{+72}:\\ \;\;\;\;\left(\left(\left(x \cdot x\right) \cdot y\right) \cdot y\right) \cdot 0.5\\ \mathbf{else}:\\ \;\;\;\;\mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(0.16666666666666666 \cdot y, y \cdot x, 0.5\right) \cdot x, y \cdot y, 1\right) \cdot y, y \cdot x, 1\right)\\ \end{array} \]
                      6. Add Preprocessing

                      Alternative 9: 73.4% accurate, 1.8× speedup?

                      \[\begin{array}{l} \\ \begin{array}{l} t_0 := \left(y \cdot x\right) \cdot y\\ \mathbf{if}\;t\_0 \leq -1 \cdot 10^{+74}:\\ \;\;\;\;\left(\left(\left(x \cdot x\right) \cdot y\right) \cdot y\right) \cdot 0.5\\ \mathbf{elif}\;t\_0 \leq 10^{+15}:\\ \;\;\;\;\mathsf{fma}\left(y \cdot x, y, 1\right)\\ \mathbf{else}:\\ \;\;\;\;\left(\left(\left(\left(\left(y \cdot y\right) \cdot y\right) \cdot y\right) \cdot 0.5\right) \cdot x\right) \cdot x\\ \end{array} \end{array} \]
                      (FPCore (x y)
                       :precision binary64
                       (let* ((t_0 (* (* y x) y)))
                         (if (<= t_0 -1e+74)
                           (* (* (* (* x x) y) y) 0.5)
                           (if (<= t_0 1e+15)
                             (fma (* y x) y 1.0)
                             (* (* (* (* (* (* y y) y) y) 0.5) x) x)))))
                      double code(double x, double y) {
                      	double t_0 = (y * x) * y;
                      	double tmp;
                      	if (t_0 <= -1e+74) {
                      		tmp = (((x * x) * y) * y) * 0.5;
                      	} else if (t_0 <= 1e+15) {
                      		tmp = fma((y * x), y, 1.0);
                      	} else {
                      		tmp = (((((y * y) * y) * y) * 0.5) * x) * x;
                      	}
                      	return tmp;
                      }
                      
                      function code(x, y)
                      	t_0 = Float64(Float64(y * x) * y)
                      	tmp = 0.0
                      	if (t_0 <= -1e+74)
                      		tmp = Float64(Float64(Float64(Float64(x * x) * y) * y) * 0.5);
                      	elseif (t_0 <= 1e+15)
                      		tmp = fma(Float64(y * x), y, 1.0);
                      	else
                      		tmp = Float64(Float64(Float64(Float64(Float64(Float64(y * y) * y) * y) * 0.5) * x) * x);
                      	end
                      	return tmp
                      end
                      
                      code[x_, y_] := Block[{t$95$0 = N[(N[(y * x), $MachinePrecision] * y), $MachinePrecision]}, If[LessEqual[t$95$0, -1e+74], N[(N[(N[(N[(x * x), $MachinePrecision] * y), $MachinePrecision] * y), $MachinePrecision] * 0.5), $MachinePrecision], If[LessEqual[t$95$0, 1e+15], N[(N[(y * x), $MachinePrecision] * y + 1.0), $MachinePrecision], N[(N[(N[(N[(N[(N[(y * y), $MachinePrecision] * y), $MachinePrecision] * y), $MachinePrecision] * 0.5), $MachinePrecision] * x), $MachinePrecision] * x), $MachinePrecision]]]]
                      
                      \begin{array}{l}
                      
                      \\
                      \begin{array}{l}
                      t_0 := \left(y \cdot x\right) \cdot y\\
                      \mathbf{if}\;t\_0 \leq -1 \cdot 10^{+74}:\\
                      \;\;\;\;\left(\left(\left(x \cdot x\right) \cdot y\right) \cdot y\right) \cdot 0.5\\
                      
                      \mathbf{elif}\;t\_0 \leq 10^{+15}:\\
                      \;\;\;\;\mathsf{fma}\left(y \cdot x, y, 1\right)\\
                      
                      \mathbf{else}:\\
                      \;\;\;\;\left(\left(\left(\left(\left(y \cdot y\right) \cdot y\right) \cdot y\right) \cdot 0.5\right) \cdot x\right) \cdot x\\
                      
                      
                      \end{array}
                      \end{array}
                      
                      Derivation
                      1. Split input into 3 regimes
                      2. if (*.f64 (*.f64 x y) y) < -9.99999999999999952e73

                        1. Initial program 100.0%

                          \[e^{\left(x \cdot y\right) \cdot y} \]
                        2. Add Preprocessing
                        3. Applied rewrites41.9%

                          \[\leadsto e^{\color{blue}{x} \cdot y} \]
                        4. Taylor expanded in y around 0

                          \[\leadsto \color{blue}{1 + y \cdot \left(x + y \cdot \left(\frac{1}{6} \cdot \left({x}^{3} \cdot y\right) + \frac{1}{2} \cdot {x}^{2}\right)\right)} \]
                        5. Step-by-step derivation
                          1. +-commutativeN/A

                            \[\leadsto \color{blue}{y \cdot \left(x + y \cdot \left(\frac{1}{6} \cdot \left({x}^{3} \cdot y\right) + \frac{1}{2} \cdot {x}^{2}\right)\right) + 1} \]
                          2. *-commutativeN/A

                            \[\leadsto \color{blue}{\left(x + y \cdot \left(\frac{1}{6} \cdot \left({x}^{3} \cdot y\right) + \frac{1}{2} \cdot {x}^{2}\right)\right) \cdot y} + 1 \]
                          3. lower-fma.f64N/A

                            \[\leadsto \color{blue}{\mathsf{fma}\left(x + y \cdot \left(\frac{1}{6} \cdot \left({x}^{3} \cdot y\right) + \frac{1}{2} \cdot {x}^{2}\right), y, 1\right)} \]
                        6. Applied rewrites1.6%

                          \[\leadsto \color{blue}{\mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(\left(\left(x \cdot x\right) \cdot x\right) \cdot y, 0.16666666666666666, \left(x \cdot x\right) \cdot 0.5\right), y, x\right), y, 1\right)} \]
                        7. Taylor expanded in x around inf

                          \[\leadsto {x}^{3} \cdot \color{blue}{\left(\frac{1}{6} \cdot {y}^{3} + \frac{1}{2} \cdot \frac{{y}^{2}}{x}\right)} \]
                        8. Step-by-step derivation
                          1. Applied rewrites1.4%

                            \[\leadsto \left(\left(y \cdot y\right) \cdot \mathsf{fma}\left(0.16666666666666666, y, \frac{0.5}{x}\right)\right) \cdot \color{blue}{\left(\left(x \cdot x\right) \cdot x\right)} \]
                          2. Taylor expanded in y around 0

                            \[\leadsto \frac{1}{2} \cdot \left({x}^{2} \cdot \color{blue}{{y}^{2}}\right) \]
                          3. Step-by-step derivation
                            1. Applied rewrites15.8%

                              \[\leadsto \left(\left(\left(x \cdot x\right) \cdot y\right) \cdot y\right) \cdot 0.5 \]

                            if -9.99999999999999952e73 < (*.f64 (*.f64 x y) y) < 1e15

                            1. Initial program 100.0%

                              \[e^{\left(x \cdot y\right) \cdot y} \]
                            2. Add Preprocessing
                            3. Taylor expanded in x around 0

                              \[\leadsto \color{blue}{1 + x \cdot {y}^{2}} \]
                            4. Step-by-step derivation
                              1. +-commutativeN/A

                                \[\leadsto \color{blue}{x \cdot {y}^{2} + 1} \]
                              2. *-commutativeN/A

                                \[\leadsto \color{blue}{{y}^{2} \cdot x} + 1 \]
                              3. lower-fma.f64N/A

                                \[\leadsto \color{blue}{\mathsf{fma}\left({y}^{2}, x, 1\right)} \]
                              4. unpow2N/A

                                \[\leadsto \mathsf{fma}\left(\color{blue}{y \cdot y}, x, 1\right) \]
                              5. lower-*.f6494.9

                                \[\leadsto \mathsf{fma}\left(\color{blue}{y \cdot y}, x, 1\right) \]
                            5. Applied rewrites94.9%

                              \[\leadsto \color{blue}{\mathsf{fma}\left(y \cdot y, x, 1\right)} \]
                            6. Step-by-step derivation
                              1. Applied rewrites94.9%

                                \[\leadsto \mathsf{fma}\left(y \cdot x, \color{blue}{y}, 1\right) \]

                              if 1e15 < (*.f64 (*.f64 x y) y)

                              1. Initial program 100.0%

                                \[e^{\left(x \cdot y\right) \cdot y} \]
                              2. Add Preprocessing
                              3. Taylor expanded in x around 0

                                \[\leadsto \color{blue}{1 + x \cdot \left(\frac{1}{2} \cdot \left(x \cdot {y}^{4}\right) + {y}^{2}\right)} \]
                              4. Applied rewrites79.3%

                                \[\leadsto \color{blue}{\mathsf{fma}\left(\mathsf{fma}\left(\left(0.5 \cdot y\right) \cdot x, y, 1\right) \cdot y, y \cdot x, 1\right)} \]
                              5. Taylor expanded in y around inf

                                \[\leadsto \frac{1}{2} \cdot \color{blue}{\left({x}^{2} \cdot {y}^{4}\right)} \]
                              6. Step-by-step derivation
                                1. Applied rewrites89.0%

                                  \[\leadsto \left(\left(\left(\left(\left(y \cdot y\right) \cdot y\right) \cdot y\right) \cdot 0.5\right) \cdot x\right) \cdot \color{blue}{x} \]
                              7. Recombined 3 regimes into one program.
                              8. Final simplification78.0%

                                \[\leadsto \begin{array}{l} \mathbf{if}\;\left(y \cdot x\right) \cdot y \leq -1 \cdot 10^{+74}:\\ \;\;\;\;\left(\left(\left(x \cdot x\right) \cdot y\right) \cdot y\right) \cdot 0.5\\ \mathbf{elif}\;\left(y \cdot x\right) \cdot y \leq 10^{+15}:\\ \;\;\;\;\mathsf{fma}\left(y \cdot x, y, 1\right)\\ \mathbf{else}:\\ \;\;\;\;\left(\left(\left(\left(\left(y \cdot y\right) \cdot y\right) \cdot y\right) \cdot 0.5\right) \cdot x\right) \cdot x\\ \end{array} \]
                              9. Add Preprocessing

                              Alternative 10: 70.0% accurate, 1.8× speedup?

                              \[\begin{array}{l} \\ \begin{array}{l} t_0 := \left(y \cdot x\right) \cdot y\\ t_1 := \left(\left(\left(x \cdot x\right) \cdot y\right) \cdot y\right) \cdot 0.5\\ \mathbf{if}\;t\_0 \leq -1 \cdot 10^{+74}:\\ \;\;\;\;t\_1\\ \mathbf{elif}\;t\_0 \leq 4 \cdot 10^{+145}:\\ \;\;\;\;\mathsf{fma}\left(y \cdot y, x, 1\right)\\ \mathbf{else}:\\ \;\;\;\;\left(t\_1 \cdot y\right) \cdot y\\ \end{array} \end{array} \]
                              (FPCore (x y)
                               :precision binary64
                               (let* ((t_0 (* (* y x) y)) (t_1 (* (* (* (* x x) y) y) 0.5)))
                                 (if (<= t_0 -1e+74)
                                   t_1
                                   (if (<= t_0 4e+145) (fma (* y y) x 1.0) (* (* t_1 y) y)))))
                              double code(double x, double y) {
                              	double t_0 = (y * x) * y;
                              	double t_1 = (((x * x) * y) * y) * 0.5;
                              	double tmp;
                              	if (t_0 <= -1e+74) {
                              		tmp = t_1;
                              	} else if (t_0 <= 4e+145) {
                              		tmp = fma((y * y), x, 1.0);
                              	} else {
                              		tmp = (t_1 * y) * y;
                              	}
                              	return tmp;
                              }
                              
                              function code(x, y)
                              	t_0 = Float64(Float64(y * x) * y)
                              	t_1 = Float64(Float64(Float64(Float64(x * x) * y) * y) * 0.5)
                              	tmp = 0.0
                              	if (t_0 <= -1e+74)
                              		tmp = t_1;
                              	elseif (t_0 <= 4e+145)
                              		tmp = fma(Float64(y * y), x, 1.0);
                              	else
                              		tmp = Float64(Float64(t_1 * y) * y);
                              	end
                              	return tmp
                              end
                              
                              code[x_, y_] := Block[{t$95$0 = N[(N[(y * x), $MachinePrecision] * y), $MachinePrecision]}, Block[{t$95$1 = N[(N[(N[(N[(x * x), $MachinePrecision] * y), $MachinePrecision] * y), $MachinePrecision] * 0.5), $MachinePrecision]}, If[LessEqual[t$95$0, -1e+74], t$95$1, If[LessEqual[t$95$0, 4e+145], N[(N[(y * y), $MachinePrecision] * x + 1.0), $MachinePrecision], N[(N[(t$95$1 * y), $MachinePrecision] * y), $MachinePrecision]]]]]
                              
                              \begin{array}{l}
                              
                              \\
                              \begin{array}{l}
                              t_0 := \left(y \cdot x\right) \cdot y\\
                              t_1 := \left(\left(\left(x \cdot x\right) \cdot y\right) \cdot y\right) \cdot 0.5\\
                              \mathbf{if}\;t\_0 \leq -1 \cdot 10^{+74}:\\
                              \;\;\;\;t\_1\\
                              
                              \mathbf{elif}\;t\_0 \leq 4 \cdot 10^{+145}:\\
                              \;\;\;\;\mathsf{fma}\left(y \cdot y, x, 1\right)\\
                              
                              \mathbf{else}:\\
                              \;\;\;\;\left(t\_1 \cdot y\right) \cdot y\\
                              
                              
                              \end{array}
                              \end{array}
                              
                              Derivation
                              1. Split input into 3 regimes
                              2. if (*.f64 (*.f64 x y) y) < -9.99999999999999952e73

                                1. Initial program 100.0%

                                  \[e^{\left(x \cdot y\right) \cdot y} \]
                                2. Add Preprocessing
                                3. Applied rewrites41.9%

                                  \[\leadsto e^{\color{blue}{x} \cdot y} \]
                                4. Taylor expanded in y around 0

                                  \[\leadsto \color{blue}{1 + y \cdot \left(x + y \cdot \left(\frac{1}{6} \cdot \left({x}^{3} \cdot y\right) + \frac{1}{2} \cdot {x}^{2}\right)\right)} \]
                                5. Step-by-step derivation
                                  1. +-commutativeN/A

                                    \[\leadsto \color{blue}{y \cdot \left(x + y \cdot \left(\frac{1}{6} \cdot \left({x}^{3} \cdot y\right) + \frac{1}{2} \cdot {x}^{2}\right)\right) + 1} \]
                                  2. *-commutativeN/A

                                    \[\leadsto \color{blue}{\left(x + y \cdot \left(\frac{1}{6} \cdot \left({x}^{3} \cdot y\right) + \frac{1}{2} \cdot {x}^{2}\right)\right) \cdot y} + 1 \]
                                  3. lower-fma.f64N/A

                                    \[\leadsto \color{blue}{\mathsf{fma}\left(x + y \cdot \left(\frac{1}{6} \cdot \left({x}^{3} \cdot y\right) + \frac{1}{2} \cdot {x}^{2}\right), y, 1\right)} \]
                                6. Applied rewrites1.6%

                                  \[\leadsto \color{blue}{\mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(\left(\left(x \cdot x\right) \cdot x\right) \cdot y, 0.16666666666666666, \left(x \cdot x\right) \cdot 0.5\right), y, x\right), y, 1\right)} \]
                                7. Taylor expanded in x around inf

                                  \[\leadsto {x}^{3} \cdot \color{blue}{\left(\frac{1}{6} \cdot {y}^{3} + \frac{1}{2} \cdot \frac{{y}^{2}}{x}\right)} \]
                                8. Step-by-step derivation
                                  1. Applied rewrites1.4%

                                    \[\leadsto \left(\left(y \cdot y\right) \cdot \mathsf{fma}\left(0.16666666666666666, y, \frac{0.5}{x}\right)\right) \cdot \color{blue}{\left(\left(x \cdot x\right) \cdot x\right)} \]
                                  2. Taylor expanded in y around 0

                                    \[\leadsto \frac{1}{2} \cdot \left({x}^{2} \cdot \color{blue}{{y}^{2}}\right) \]
                                  3. Step-by-step derivation
                                    1. Applied rewrites15.8%

                                      \[\leadsto \left(\left(\left(x \cdot x\right) \cdot y\right) \cdot y\right) \cdot 0.5 \]

                                    if -9.99999999999999952e73 < (*.f64 (*.f64 x y) y) < 4e145

                                    1. Initial program 100.0%

                                      \[e^{\left(x \cdot y\right) \cdot y} \]
                                    2. Add Preprocessing
                                    3. Taylor expanded in x around 0

                                      \[\leadsto \color{blue}{1 + x \cdot {y}^{2}} \]
                                    4. Step-by-step derivation
                                      1. +-commutativeN/A

                                        \[\leadsto \color{blue}{x \cdot {y}^{2} + 1} \]
                                      2. *-commutativeN/A

                                        \[\leadsto \color{blue}{{y}^{2} \cdot x} + 1 \]
                                      3. lower-fma.f64N/A

                                        \[\leadsto \color{blue}{\mathsf{fma}\left({y}^{2}, x, 1\right)} \]
                                      4. unpow2N/A

                                        \[\leadsto \mathsf{fma}\left(\color{blue}{y \cdot y}, x, 1\right) \]
                                      5. lower-*.f6486.4

                                        \[\leadsto \mathsf{fma}\left(\color{blue}{y \cdot y}, x, 1\right) \]
                                    5. Applied rewrites86.4%

                                      \[\leadsto \color{blue}{\mathsf{fma}\left(y \cdot y, x, 1\right)} \]

                                    if 4e145 < (*.f64 (*.f64 x y) y)

                                    1. Initial program 100.0%

                                      \[e^{\left(x \cdot y\right) \cdot y} \]
                                    2. Add Preprocessing
                                    3. Taylor expanded in x around 0

                                      \[\leadsto \color{blue}{1 + x \cdot \left(\frac{1}{2} \cdot \left(x \cdot {y}^{4}\right) + {y}^{2}\right)} \]
                                    4. Applied rewrites98.5%

                                      \[\leadsto \color{blue}{\mathsf{fma}\left(\mathsf{fma}\left(\left(0.5 \cdot y\right) \cdot x, y, 1\right) \cdot y, y \cdot x, 1\right)} \]
                                    5. Taylor expanded in y around inf

                                      \[\leadsto \frac{1}{2} \cdot \color{blue}{\left({x}^{2} \cdot {y}^{4}\right)} \]
                                    6. Step-by-step derivation
                                      1. Applied rewrites98.5%

                                        \[\leadsto \left(\left(\left(\left(\left(y \cdot y\right) \cdot y\right) \cdot y\right) \cdot 0.5\right) \cdot x\right) \cdot \color{blue}{x} \]
                                      2. Taylor expanded in y around inf

                                        \[\leadsto \frac{1}{2} \cdot \color{blue}{\left({x}^{2} \cdot {y}^{4}\right)} \]
                                      3. Step-by-step derivation
                                        1. Applied rewrites86.9%

                                          \[\leadsto \left(\left(\left(\left(\left(x \cdot x\right) \cdot y\right) \cdot y\right) \cdot 0.5\right) \cdot y\right) \cdot \color{blue}{y} \]
                                      4. Recombined 3 regimes into one program.
                                      5. Final simplification73.0%

                                        \[\leadsto \begin{array}{l} \mathbf{if}\;\left(y \cdot x\right) \cdot y \leq -1 \cdot 10^{+74}:\\ \;\;\;\;\left(\left(\left(x \cdot x\right) \cdot y\right) \cdot y\right) \cdot 0.5\\ \mathbf{elif}\;\left(y \cdot x\right) \cdot y \leq 4 \cdot 10^{+145}:\\ \;\;\;\;\mathsf{fma}\left(y \cdot y, x, 1\right)\\ \mathbf{else}:\\ \;\;\;\;\left(\left(\left(\left(\left(x \cdot x\right) \cdot y\right) \cdot y\right) \cdot 0.5\right) \cdot y\right) \cdot y\\ \end{array} \]
                                      6. Add Preprocessing

                                      Alternative 11: 68.5% accurate, 3.0× speedup?

                                      \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;\left(y \cdot x\right) \cdot y \leq -1 \cdot 10^{+74}:\\ \;\;\;\;\left(\left(\left(x \cdot x\right) \cdot y\right) \cdot y\right) \cdot 0.5\\ \mathbf{else}:\\ \;\;\;\;\mathsf{fma}\left(y \cdot y, x, 1\right)\\ \end{array} \end{array} \]
                                      (FPCore (x y)
                                       :precision binary64
                                       (if (<= (* (* y x) y) -1e+74)
                                         (* (* (* (* x x) y) y) 0.5)
                                         (fma (* y y) x 1.0)))
                                      double code(double x, double y) {
                                      	double tmp;
                                      	if (((y * x) * y) <= -1e+74) {
                                      		tmp = (((x * x) * y) * y) * 0.5;
                                      	} else {
                                      		tmp = fma((y * y), x, 1.0);
                                      	}
                                      	return tmp;
                                      }
                                      
                                      function code(x, y)
                                      	tmp = 0.0
                                      	if (Float64(Float64(y * x) * y) <= -1e+74)
                                      		tmp = Float64(Float64(Float64(Float64(x * x) * y) * y) * 0.5);
                                      	else
                                      		tmp = fma(Float64(y * y), x, 1.0);
                                      	end
                                      	return tmp
                                      end
                                      
                                      code[x_, y_] := If[LessEqual[N[(N[(y * x), $MachinePrecision] * y), $MachinePrecision], -1e+74], N[(N[(N[(N[(x * x), $MachinePrecision] * y), $MachinePrecision] * y), $MachinePrecision] * 0.5), $MachinePrecision], N[(N[(y * y), $MachinePrecision] * x + 1.0), $MachinePrecision]]
                                      
                                      \begin{array}{l}
                                      
                                      \\
                                      \begin{array}{l}
                                      \mathbf{if}\;\left(y \cdot x\right) \cdot y \leq -1 \cdot 10^{+74}:\\
                                      \;\;\;\;\left(\left(\left(x \cdot x\right) \cdot y\right) \cdot y\right) \cdot 0.5\\
                                      
                                      \mathbf{else}:\\
                                      \;\;\;\;\mathsf{fma}\left(y \cdot y, x, 1\right)\\
                                      
                                      
                                      \end{array}
                                      \end{array}
                                      
                                      Derivation
                                      1. Split input into 2 regimes
                                      2. if (*.f64 (*.f64 x y) y) < -9.99999999999999952e73

                                        1. Initial program 100.0%

                                          \[e^{\left(x \cdot y\right) \cdot y} \]
                                        2. Add Preprocessing
                                        3. Applied rewrites41.9%

                                          \[\leadsto e^{\color{blue}{x} \cdot y} \]
                                        4. Taylor expanded in y around 0

                                          \[\leadsto \color{blue}{1 + y \cdot \left(x + y \cdot \left(\frac{1}{6} \cdot \left({x}^{3} \cdot y\right) + \frac{1}{2} \cdot {x}^{2}\right)\right)} \]
                                        5. Step-by-step derivation
                                          1. +-commutativeN/A

                                            \[\leadsto \color{blue}{y \cdot \left(x + y \cdot \left(\frac{1}{6} \cdot \left({x}^{3} \cdot y\right) + \frac{1}{2} \cdot {x}^{2}\right)\right) + 1} \]
                                          2. *-commutativeN/A

                                            \[\leadsto \color{blue}{\left(x + y \cdot \left(\frac{1}{6} \cdot \left({x}^{3} \cdot y\right) + \frac{1}{2} \cdot {x}^{2}\right)\right) \cdot y} + 1 \]
                                          3. lower-fma.f64N/A

                                            \[\leadsto \color{blue}{\mathsf{fma}\left(x + y \cdot \left(\frac{1}{6} \cdot \left({x}^{3} \cdot y\right) + \frac{1}{2} \cdot {x}^{2}\right), y, 1\right)} \]
                                        6. Applied rewrites1.6%

                                          \[\leadsto \color{blue}{\mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(\left(\left(x \cdot x\right) \cdot x\right) \cdot y, 0.16666666666666666, \left(x \cdot x\right) \cdot 0.5\right), y, x\right), y, 1\right)} \]
                                        7. Taylor expanded in x around inf

                                          \[\leadsto {x}^{3} \cdot \color{blue}{\left(\frac{1}{6} \cdot {y}^{3} + \frac{1}{2} \cdot \frac{{y}^{2}}{x}\right)} \]
                                        8. Step-by-step derivation
                                          1. Applied rewrites1.4%

                                            \[\leadsto \left(\left(y \cdot y\right) \cdot \mathsf{fma}\left(0.16666666666666666, y, \frac{0.5}{x}\right)\right) \cdot \color{blue}{\left(\left(x \cdot x\right) \cdot x\right)} \]
                                          2. Taylor expanded in y around 0

                                            \[\leadsto \frac{1}{2} \cdot \left({x}^{2} \cdot \color{blue}{{y}^{2}}\right) \]
                                          3. Step-by-step derivation
                                            1. Applied rewrites15.8%

                                              \[\leadsto \left(\left(\left(x \cdot x\right) \cdot y\right) \cdot y\right) \cdot 0.5 \]

                                            if -9.99999999999999952e73 < (*.f64 (*.f64 x y) y)

                                            1. Initial program 100.0%

                                              \[e^{\left(x \cdot y\right) \cdot y} \]
                                            2. Add Preprocessing
                                            3. Taylor expanded in x around 0

                                              \[\leadsto \color{blue}{1 + x \cdot {y}^{2}} \]
                                            4. Step-by-step derivation
                                              1. +-commutativeN/A

                                                \[\leadsto \color{blue}{x \cdot {y}^{2} + 1} \]
                                              2. *-commutativeN/A

                                                \[\leadsto \color{blue}{{y}^{2} \cdot x} + 1 \]
                                              3. lower-fma.f64N/A

                                                \[\leadsto \color{blue}{\mathsf{fma}\left({y}^{2}, x, 1\right)} \]
                                              4. unpow2N/A

                                                \[\leadsto \mathsf{fma}\left(\color{blue}{y \cdot y}, x, 1\right) \]
                                              5. lower-*.f6484.0

                                                \[\leadsto \mathsf{fma}\left(\color{blue}{y \cdot y}, x, 1\right) \]
                                            5. Applied rewrites84.0%

                                              \[\leadsto \color{blue}{\mathsf{fma}\left(y \cdot y, x, 1\right)} \]
                                          4. Recombined 2 regimes into one program.
                                          5. Final simplification70.9%

                                            \[\leadsto \begin{array}{l} \mathbf{if}\;\left(y \cdot x\right) \cdot y \leq -1 \cdot 10^{+74}:\\ \;\;\;\;\left(\left(\left(x \cdot x\right) \cdot y\right) \cdot y\right) \cdot 0.5\\ \mathbf{else}:\\ \;\;\;\;\mathsf{fma}\left(y \cdot y, x, 1\right)\\ \end{array} \]
                                          6. Add Preprocessing

                                          Alternative 12: 53.9% accurate, 5.0× speedup?

                                          \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;\left(y \cdot x\right) \cdot y \leq 5 \cdot 10^{+24}:\\ \;\;\;\;1\\ \mathbf{else}:\\ \;\;\;\;y \cdot x\\ \end{array} \end{array} \]
                                          (FPCore (x y) :precision binary64 (if (<= (* (* y x) y) 5e+24) 1.0 (* y x)))
                                          double code(double x, double y) {
                                          	double tmp;
                                          	if (((y * x) * y) <= 5e+24) {
                                          		tmp = 1.0;
                                          	} else {
                                          		tmp = y * x;
                                          	}
                                          	return tmp;
                                          }
                                          
                                          real(8) function code(x, y)
                                              real(8), intent (in) :: x
                                              real(8), intent (in) :: y
                                              real(8) :: tmp
                                              if (((y * x) * y) <= 5d+24) then
                                                  tmp = 1.0d0
                                              else
                                                  tmp = y * x
                                              end if
                                              code = tmp
                                          end function
                                          
                                          public static double code(double x, double y) {
                                          	double tmp;
                                          	if (((y * x) * y) <= 5e+24) {
                                          		tmp = 1.0;
                                          	} else {
                                          		tmp = y * x;
                                          	}
                                          	return tmp;
                                          }
                                          
                                          def code(x, y):
                                          	tmp = 0
                                          	if ((y * x) * y) <= 5e+24:
                                          		tmp = 1.0
                                          	else:
                                          		tmp = y * x
                                          	return tmp
                                          
                                          function code(x, y)
                                          	tmp = 0.0
                                          	if (Float64(Float64(y * x) * y) <= 5e+24)
                                          		tmp = 1.0;
                                          	else
                                          		tmp = Float64(y * x);
                                          	end
                                          	return tmp
                                          end
                                          
                                          function tmp_2 = code(x, y)
                                          	tmp = 0.0;
                                          	if (((y * x) * y) <= 5e+24)
                                          		tmp = 1.0;
                                          	else
                                          		tmp = y * x;
                                          	end
                                          	tmp_2 = tmp;
                                          end
                                          
                                          code[x_, y_] := If[LessEqual[N[(N[(y * x), $MachinePrecision] * y), $MachinePrecision], 5e+24], 1.0, N[(y * x), $MachinePrecision]]
                                          
                                          \begin{array}{l}
                                          
                                          \\
                                          \begin{array}{l}
                                          \mathbf{if}\;\left(y \cdot x\right) \cdot y \leq 5 \cdot 10^{+24}:\\
                                          \;\;\;\;1\\
                                          
                                          \mathbf{else}:\\
                                          \;\;\;\;y \cdot x\\
                                          
                                          
                                          \end{array}
                                          \end{array}
                                          
                                          Derivation
                                          1. Split input into 2 regimes
                                          2. if (*.f64 (*.f64 x y) y) < 5.00000000000000045e24

                                            1. Initial program 100.0%

                                              \[e^{\left(x \cdot y\right) \cdot y} \]
                                            2. Add Preprocessing
                                            3. Taylor expanded in x around 0

                                              \[\leadsto \color{blue}{1} \]
                                            4. Step-by-step derivation
                                              1. Applied rewrites68.3%

                                                \[\leadsto \color{blue}{1} \]

                                              if 5.00000000000000045e24 < (*.f64 (*.f64 x y) y)

                                              1. Initial program 100.0%

                                                \[e^{\left(x \cdot y\right) \cdot y} \]
                                              2. Add Preprocessing
                                              3. Applied rewrites56.2%

                                                \[\leadsto e^{\color{blue}{x} \cdot y} \]
                                              4. Taylor expanded in x around 0

                                                \[\leadsto \color{blue}{1 + x \cdot y} \]
                                              5. Step-by-step derivation
                                                1. +-commutativeN/A

                                                  \[\leadsto \color{blue}{x \cdot y + 1} \]
                                                2. *-commutativeN/A

                                                  \[\leadsto \color{blue}{y \cdot x} + 1 \]
                                                3. lower-fma.f6417.2

                                                  \[\leadsto \color{blue}{\mathsf{fma}\left(y, x, 1\right)} \]
                                              6. Applied rewrites17.2%

                                                \[\leadsto \color{blue}{\mathsf{fma}\left(y, x, 1\right)} \]
                                              7. Taylor expanded in y around inf

                                                \[\leadsto x \cdot \color{blue}{y} \]
                                              8. Step-by-step derivation
                                                1. Applied rewrites16.9%

                                                  \[\leadsto y \cdot \color{blue}{x} \]
                                              9. Recombined 2 regimes into one program.
                                              10. Final simplification53.0%

                                                \[\leadsto \begin{array}{l} \mathbf{if}\;\left(y \cdot x\right) \cdot y \leq 5 \cdot 10^{+24}:\\ \;\;\;\;1\\ \mathbf{else}:\\ \;\;\;\;y \cdot x\\ \end{array} \]
                                              11. Add Preprocessing

                                              Alternative 13: 65.9% accurate, 9.3× speedup?

                                              \[\begin{array}{l} \\ \mathsf{fma}\left(y \cdot y, x, 1\right) \end{array} \]
                                              (FPCore (x y) :precision binary64 (fma (* y y) x 1.0))
                                              double code(double x, double y) {
                                              	return fma((y * y), x, 1.0);
                                              }
                                              
                                              function code(x, y)
                                              	return fma(Float64(y * y), x, 1.0)
                                              end
                                              
                                              code[x_, y_] := N[(N[(y * y), $MachinePrecision] * x + 1.0), $MachinePrecision]
                                              
                                              \begin{array}{l}
                                              
                                              \\
                                              \mathsf{fma}\left(y \cdot y, x, 1\right)
                                              \end{array}
                                              
                                              Derivation
                                              1. Initial program 100.0%

                                                \[e^{\left(x \cdot y\right) \cdot y} \]
                                              2. Add Preprocessing
                                              3. Taylor expanded in x around 0

                                                \[\leadsto \color{blue}{1 + x \cdot {y}^{2}} \]
                                              4. Step-by-step derivation
                                                1. +-commutativeN/A

                                                  \[\leadsto \color{blue}{x \cdot {y}^{2} + 1} \]
                                                2. *-commutativeN/A

                                                  \[\leadsto \color{blue}{{y}^{2} \cdot x} + 1 \]
                                                3. lower-fma.f64N/A

                                                  \[\leadsto \color{blue}{\mathsf{fma}\left({y}^{2}, x, 1\right)} \]
                                                4. unpow2N/A

                                                  \[\leadsto \mathsf{fma}\left(\color{blue}{y \cdot y}, x, 1\right) \]
                                                5. lower-*.f6468.3

                                                  \[\leadsto \mathsf{fma}\left(\color{blue}{y \cdot y}, x, 1\right) \]
                                              5. Applied rewrites68.3%

                                                \[\leadsto \color{blue}{\mathsf{fma}\left(y \cdot y, x, 1\right)} \]
                                              6. Add Preprocessing

                                              Alternative 14: 50.7% accurate, 111.0× speedup?

                                              \[\begin{array}{l} \\ 1 \end{array} \]
                                              (FPCore (x y) :precision binary64 1.0)
                                              double code(double x, double y) {
                                              	return 1.0;
                                              }
                                              
                                              real(8) function code(x, y)
                                                  real(8), intent (in) :: x
                                                  real(8), intent (in) :: y
                                                  code = 1.0d0
                                              end function
                                              
                                              public static double code(double x, double y) {
                                              	return 1.0;
                                              }
                                              
                                              def code(x, y):
                                              	return 1.0
                                              
                                              function code(x, y)
                                              	return 1.0
                                              end
                                              
                                              function tmp = code(x, y)
                                              	tmp = 1.0;
                                              end
                                              
                                              code[x_, y_] := 1.0
                                              
                                              \begin{array}{l}
                                              
                                              \\
                                              1
                                              \end{array}
                                              
                                              Derivation
                                              1. Initial program 100.0%

                                                \[e^{\left(x \cdot y\right) \cdot y} \]
                                              2. Add Preprocessing
                                              3. Taylor expanded in x around 0

                                                \[\leadsto \color{blue}{1} \]
                                              4. Step-by-step derivation
                                                1. Applied rewrites48.9%

                                                  \[\leadsto \color{blue}{1} \]
                                                2. Add Preprocessing

                                                Reproduce

                                                ?
                                                herbie shell --seed 2024235 
                                                (FPCore (x y)
                                                  :name "Data.Random.Distribution.Normal:normalF from random-fu-0.2.6.2"
                                                  :precision binary64
                                                  (exp (* (* x y) y)))