ABCF->ab-angle angle

Percentage Accurate: 53.4% → 88.2%
Time: 12.6s
Alternatives: 15
Speedup: 0.6×

Specification

?
\[\begin{array}{l} \\ 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \end{array} \]
(FPCore (A B C)
 :precision binary64
 (*
  180.0
  (/
   (atan (* (/ 1.0 B) (- (- C A) (sqrt (+ (pow (- A C) 2.0) (pow B 2.0))))))
   PI)))
double code(double A, double B, double C) {
	return 180.0 * (atan(((1.0 / B) * ((C - A) - sqrt((pow((A - C), 2.0) + pow(B, 2.0)))))) / ((double) M_PI));
}
public static double code(double A, double B, double C) {
	return 180.0 * (Math.atan(((1.0 / B) * ((C - A) - Math.sqrt((Math.pow((A - C), 2.0) + Math.pow(B, 2.0)))))) / Math.PI);
}
def code(A, B, C):
	return 180.0 * (math.atan(((1.0 / B) * ((C - A) - math.sqrt((math.pow((A - C), 2.0) + math.pow(B, 2.0)))))) / math.pi)
function code(A, B, C)
	return Float64(180.0 * Float64(atan(Float64(Float64(1.0 / B) * Float64(Float64(C - A) - sqrt(Float64((Float64(A - C) ^ 2.0) + (B ^ 2.0)))))) / pi))
end
function tmp = code(A, B, C)
	tmp = 180.0 * (atan(((1.0 / B) * ((C - A) - sqrt((((A - C) ^ 2.0) + (B ^ 2.0)))))) / pi);
end
code[A_, B_, C_] := N[(180.0 * N[(N[ArcTan[N[(N[(1.0 / B), $MachinePrecision] * N[(N[(C - A), $MachinePrecision] - N[Sqrt[N[(N[Power[N[(A - C), $MachinePrecision], 2.0], $MachinePrecision] + N[Power[B, 2.0], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi}
\end{array}

Sampling outcomes in binary64 precision:

Local Percentage Accuracy vs ?

The average percentage accuracy by input value. Horizontal axis shows value of an input variable; the variable is choosen in the title. Vertical axis is accuracy; higher is better. Red represent the original program, while blue represents Herbie's suggestion. These can be toggled with buttons below the plot. The line is an average while dots represent individual samples.

Accuracy vs Speed?

Herbie found 15 alternatives:

AlternativeAccuracySpeedup
The accuracy (vertical axis) and speed (horizontal axis) of each alternatives. Up and to the right is better. The red square shows the initial program, and each blue circle shows an alternative.The line shows the best available speed-accuracy tradeoffs.

Initial Program: 53.4% accurate, 1.0× speedup?

\[\begin{array}{l} \\ 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \end{array} \]
(FPCore (A B C)
 :precision binary64
 (*
  180.0
  (/
   (atan (* (/ 1.0 B) (- (- C A) (sqrt (+ (pow (- A C) 2.0) (pow B 2.0))))))
   PI)))
double code(double A, double B, double C) {
	return 180.0 * (atan(((1.0 / B) * ((C - A) - sqrt((pow((A - C), 2.0) + pow(B, 2.0)))))) / ((double) M_PI));
}
public static double code(double A, double B, double C) {
	return 180.0 * (Math.atan(((1.0 / B) * ((C - A) - Math.sqrt((Math.pow((A - C), 2.0) + Math.pow(B, 2.0)))))) / Math.PI);
}
def code(A, B, C):
	return 180.0 * (math.atan(((1.0 / B) * ((C - A) - math.sqrt((math.pow((A - C), 2.0) + math.pow(B, 2.0)))))) / math.pi)
function code(A, B, C)
	return Float64(180.0 * Float64(atan(Float64(Float64(1.0 / B) * Float64(Float64(C - A) - sqrt(Float64((Float64(A - C) ^ 2.0) + (B ^ 2.0)))))) / pi))
end
function tmp = code(A, B, C)
	tmp = 180.0 * (atan(((1.0 / B) * ((C - A) - sqrt((((A - C) ^ 2.0) + (B ^ 2.0)))))) / pi);
end
code[A_, B_, C_] := N[(180.0 * N[(N[ArcTan[N[(N[(1.0 / B), $MachinePrecision] * N[(N[(C - A), $MachinePrecision] - N[Sqrt[N[(N[Power[N[(A - C), $MachinePrecision], 2.0], $MachinePrecision] + N[Power[B, 2.0], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi}
\end{array}

Alternative 1: 88.2% accurate, 0.5× speedup?

\[\begin{array}{l} \\ \begin{array}{l} t_0 := 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \mathsf{hypot}\left(C - A, B\right)\right)\right)}{\pi}\\ t_1 := \frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\\ \mathbf{if}\;t\_1 \leq -4 \cdot 10^{-22}:\\ \;\;\;\;t\_0\\ \mathbf{elif}\;t\_1 \leq 0.0002:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{1}{\frac{\mathsf{fma}\left(-0.5, \frac{B \cdot B}{C - A}, \left(C - A\right) \cdot -2\right)}{B}}\right)}{\pi}\\ \mathbf{else}:\\ \;\;\;\;t\_0\\ \end{array} \end{array} \]
(FPCore (A B C)
 :precision binary64
 (let* ((t_0
         (* 180.0 (/ (atan (* (/ 1.0 B) (- (- C A) (hypot (- C A) B)))) PI)))
        (t_1
         (* (/ 1.0 B) (- (- C A) (sqrt (+ (pow (- A C) 2.0) (pow B 2.0)))))))
   (if (<= t_1 -4e-22)
     t_0
     (if (<= t_1 0.0002)
       (*
        180.0
        (/
         (atan (/ 1.0 (/ (fma -0.5 (/ (* B B) (- C A)) (* (- C A) -2.0)) B)))
         PI))
       t_0))))
double code(double A, double B, double C) {
	double t_0 = 180.0 * (atan(((1.0 / B) * ((C - A) - hypot((C - A), B)))) / ((double) M_PI));
	double t_1 = (1.0 / B) * ((C - A) - sqrt((pow((A - C), 2.0) + pow(B, 2.0))));
	double tmp;
	if (t_1 <= -4e-22) {
		tmp = t_0;
	} else if (t_1 <= 0.0002) {
		tmp = 180.0 * (atan((1.0 / (fma(-0.5, ((B * B) / (C - A)), ((C - A) * -2.0)) / B))) / ((double) M_PI));
	} else {
		tmp = t_0;
	}
	return tmp;
}
function code(A, B, C)
	t_0 = Float64(180.0 * Float64(atan(Float64(Float64(1.0 / B) * Float64(Float64(C - A) - hypot(Float64(C - A), B)))) / pi))
	t_1 = Float64(Float64(1.0 / B) * Float64(Float64(C - A) - sqrt(Float64((Float64(A - C) ^ 2.0) + (B ^ 2.0)))))
	tmp = 0.0
	if (t_1 <= -4e-22)
		tmp = t_0;
	elseif (t_1 <= 0.0002)
		tmp = Float64(180.0 * Float64(atan(Float64(1.0 / Float64(fma(-0.5, Float64(Float64(B * B) / Float64(C - A)), Float64(Float64(C - A) * -2.0)) / B))) / pi));
	else
		tmp = t_0;
	end
	return tmp
end
code[A_, B_, C_] := Block[{t$95$0 = N[(180.0 * N[(N[ArcTan[N[(N[(1.0 / B), $MachinePrecision] * N[(N[(C - A), $MachinePrecision] - N[Sqrt[N[(C - A), $MachinePrecision] ^ 2 + B ^ 2], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$1 = N[(N[(1.0 / B), $MachinePrecision] * N[(N[(C - A), $MachinePrecision] - N[Sqrt[N[(N[Power[N[(A - C), $MachinePrecision], 2.0], $MachinePrecision] + N[Power[B, 2.0], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[t$95$1, -4e-22], t$95$0, If[LessEqual[t$95$1, 0.0002], N[(180.0 * N[(N[ArcTan[N[(1.0 / N[(N[(-0.5 * N[(N[(B * B), $MachinePrecision] / N[(C - A), $MachinePrecision]), $MachinePrecision] + N[(N[(C - A), $MachinePrecision] * -2.0), $MachinePrecision]), $MachinePrecision] / B), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision], t$95$0]]]]
\begin{array}{l}

\\
\begin{array}{l}
t_0 := 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \mathsf{hypot}\left(C - A, B\right)\right)\right)}{\pi}\\
t_1 := \frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\\
\mathbf{if}\;t\_1 \leq -4 \cdot 10^{-22}:\\
\;\;\;\;t\_0\\

\mathbf{elif}\;t\_1 \leq 0.0002:\\
\;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{1}{\frac{\mathsf{fma}\left(-0.5, \frac{B \cdot B}{C - A}, \left(C - A\right) \cdot -2\right)}{B}}\right)}{\pi}\\

\mathbf{else}:\\
\;\;\;\;t\_0\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if (*.f64 (/.f64 #s(literal 1 binary64) B) (-.f64 (-.f64 C A) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))) < -4.0000000000000002e-22 or 2.0000000000000001e-4 < (*.f64 (/.f64 #s(literal 1 binary64) B) (-.f64 (-.f64 C A) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64))))))

    1. Initial program 61.5%

      \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
    2. Add Preprocessing
    3. Step-by-step derivation
      1. lift-sqrt.f64N/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \color{blue}{\sqrt{{\left(A - C\right)}^{2} + {B}^{2}}}\right)\right)}{\mathsf{PI}\left(\right)} \]
      2. lift-+.f64N/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{\color{blue}{{\left(A - C\right)}^{2} + {B}^{2}}}\right)\right)}{\mathsf{PI}\left(\right)} \]
    4. Applied rewrites91.5%

      \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \color{blue}{\mathsf{hypot}\left(C - A, B\right)}\right)\right)}{\pi} \]

    if -4.0000000000000002e-22 < (*.f64 (/.f64 #s(literal 1 binary64) B) (-.f64 (-.f64 C A) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))) < 2.0000000000000001e-4

    1. Initial program 22.2%

      \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
    2. Add Preprocessing
    3. Step-by-step derivation
      1. lift-sqrt.f64N/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \color{blue}{\sqrt{{\left(A - C\right)}^{2} + {B}^{2}}}\right)\right)}{\mathsf{PI}\left(\right)} \]
      2. lift-+.f64N/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{\color{blue}{{\left(A - C\right)}^{2} + {B}^{2}}}\right)\right)}{\mathsf{PI}\left(\right)} \]
    4. Applied rewrites22.2%

      \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \color{blue}{\mathsf{hypot}\left(C - A, B\right)}\right)\right)}{\pi} \]
    5. Step-by-step derivation
      1. lift-*.f64N/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{1}{B} \cdot \left(\left(C - A\right) - \mathsf{hypot}\left(C - A, B\right)\right)\right)}}{\mathsf{PI}\left(\right)} \]
      2. lift-/.f64N/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\color{blue}{\frac{1}{B}} \cdot \left(\left(C - A\right) - \mathsf{hypot}\left(C - A, B\right)\right)\right)}{\mathsf{PI}\left(\right)} \]
      3. associate-*l/N/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{1 \cdot \left(\left(C - A\right) - \mathsf{hypot}\left(C - A, B\right)\right)}{B}\right)}}{\mathsf{PI}\left(\right)} \]
      4. clear-numN/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{1}{\frac{B}{1 \cdot \left(\left(C - A\right) - \mathsf{hypot}\left(C - A, B\right)\right)}}\right)}}{\mathsf{PI}\left(\right)} \]
      5. lower-/.f64N/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{1}{\frac{B}{1 \cdot \left(\left(C - A\right) - \mathsf{hypot}\left(C - A, B\right)\right)}}\right)}}{\mathsf{PI}\left(\right)} \]
      6. *-lft-identityN/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{\frac{B}{\color{blue}{\left(C - A\right) - \mathsf{hypot}\left(C - A, B\right)}}}\right)}{\mathsf{PI}\left(\right)} \]
      7. lower-/.f6422.2

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{\color{blue}{\frac{B}{\left(C - A\right) - \mathsf{hypot}\left(C - A, B\right)}}}\right)}{\pi} \]
      8. lift-hypot.f64N/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{\frac{B}{\left(C - A\right) - \color{blue}{\sqrt{\left(C - A\right) \cdot \left(C - A\right) + B \cdot B}}}}\right)}{\mathsf{PI}\left(\right)} \]
      9. lower-sqrt.f64N/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{\frac{B}{\left(C - A\right) - \color{blue}{\sqrt{\left(C - A\right) \cdot \left(C - A\right) + B \cdot B}}}}\right)}{\mathsf{PI}\left(\right)} \]
      10. lift-*.f64N/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{\frac{B}{\left(C - A\right) - \sqrt{\left(C - A\right) \cdot \left(C - A\right) + \color{blue}{B \cdot B}}}}\right)}{\mathsf{PI}\left(\right)} \]
      11. lower-fma.f6422.2

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{\frac{B}{\left(C - A\right) - \sqrt{\color{blue}{\mathsf{fma}\left(C - A, C - A, B \cdot B\right)}}}}\right)}{\pi} \]
    6. Applied rewrites22.2%

      \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{1}{\frac{B}{\left(C - A\right) - \sqrt{\mathsf{fma}\left(C - A, C - A, B \cdot B\right)}}}\right)}}{\pi} \]
    7. Taylor expanded in B around 0

      \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{\color{blue}{\frac{-2 \cdot \left(C - A\right) + \frac{-1}{2} \cdot \frac{{B}^{2}}{C - A}}{B}}}\right)}{\mathsf{PI}\left(\right)} \]
    8. Step-by-step derivation
      1. lower-/.f64N/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{\color{blue}{\frac{-2 \cdot \left(C - A\right) + \frac{-1}{2} \cdot \frac{{B}^{2}}{C - A}}{B}}}\right)}{\mathsf{PI}\left(\right)} \]
      2. +-commutativeN/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{\frac{\color{blue}{\frac{-1}{2} \cdot \frac{{B}^{2}}{C - A} + -2 \cdot \left(C - A\right)}}{B}}\right)}{\mathsf{PI}\left(\right)} \]
      3. lower-fma.f64N/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{\frac{\color{blue}{\mathsf{fma}\left(\frac{-1}{2}, \frac{{B}^{2}}{C - A}, -2 \cdot \left(C - A\right)\right)}}{B}}\right)}{\mathsf{PI}\left(\right)} \]
      4. lower-/.f64N/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{\frac{\mathsf{fma}\left(\frac{-1}{2}, \color{blue}{\frac{{B}^{2}}{C - A}}, -2 \cdot \left(C - A\right)\right)}{B}}\right)}{\mathsf{PI}\left(\right)} \]
      5. unpow2N/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{\frac{\mathsf{fma}\left(\frac{-1}{2}, \frac{\color{blue}{B \cdot B}}{C - A}, -2 \cdot \left(C - A\right)\right)}{B}}\right)}{\mathsf{PI}\left(\right)} \]
      6. lower-*.f64N/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{\frac{\mathsf{fma}\left(\frac{-1}{2}, \frac{\color{blue}{B \cdot B}}{C - A}, -2 \cdot \left(C - A\right)\right)}{B}}\right)}{\mathsf{PI}\left(\right)} \]
      7. lower--.f64N/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{\frac{\mathsf{fma}\left(\frac{-1}{2}, \frac{B \cdot B}{\color{blue}{C - A}}, -2 \cdot \left(C - A\right)\right)}{B}}\right)}{\mathsf{PI}\left(\right)} \]
      8. *-commutativeN/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{\frac{\mathsf{fma}\left(\frac{-1}{2}, \frac{B \cdot B}{C - A}, \color{blue}{\left(C - A\right) \cdot -2}\right)}{B}}\right)}{\mathsf{PI}\left(\right)} \]
      9. lower-*.f64N/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{\frac{\mathsf{fma}\left(\frac{-1}{2}, \frac{B \cdot B}{C - A}, \color{blue}{\left(C - A\right) \cdot -2}\right)}{B}}\right)}{\mathsf{PI}\left(\right)} \]
      10. lower--.f6499.2

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{\frac{\mathsf{fma}\left(-0.5, \frac{B \cdot B}{C - A}, \color{blue}{\left(C - A\right)} \cdot -2\right)}{B}}\right)}{\pi} \]
    9. Applied rewrites99.2%

      \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{\color{blue}{\frac{\mathsf{fma}\left(-0.5, \frac{B \cdot B}{C - A}, \left(C - A\right) \cdot -2\right)}{B}}}\right)}{\pi} \]
  3. Recombined 2 regimes into one program.
  4. Add Preprocessing

Alternative 2: 79.1% accurate, 0.5× speedup?

\[\begin{array}{l} \\ \begin{array}{l} t_0 := \frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\\ \mathbf{if}\;t\_0 \leq -4 \cdot 10^{-22}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{C - A}{B} + -1\right)}{\pi}\\ \mathbf{elif}\;t\_0 \leq 0.0002:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{1}{\frac{\mathsf{fma}\left(-0.5, \frac{B \cdot B}{C - A}, \left(C - A\right) \cdot -2\right)}{B}}\right)}{\pi}\\ \mathbf{else}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(1 - \frac{\mathsf{fma}\left(-0.5, \left(A - C\right) \cdot \frac{A - C}{B}, A - C\right)}{B}\right)}{\pi}\\ \end{array} \end{array} \]
(FPCore (A B C)
 :precision binary64
 (let* ((t_0
         (* (/ 1.0 B) (- (- C A) (sqrt (+ (pow (- A C) 2.0) (pow B 2.0)))))))
   (if (<= t_0 -4e-22)
     (* 180.0 (/ (atan (+ (/ (- C A) B) -1.0)) PI))
     (if (<= t_0 0.0002)
       (*
        180.0
        (/
         (atan (/ 1.0 (/ (fma -0.5 (/ (* B B) (- C A)) (* (- C A) -2.0)) B)))
         PI))
       (*
        180.0
        (/
         (atan (- 1.0 (/ (fma -0.5 (* (- A C) (/ (- A C) B)) (- A C)) B)))
         PI))))))
double code(double A, double B, double C) {
	double t_0 = (1.0 / B) * ((C - A) - sqrt((pow((A - C), 2.0) + pow(B, 2.0))));
	double tmp;
	if (t_0 <= -4e-22) {
		tmp = 180.0 * (atan((((C - A) / B) + -1.0)) / ((double) M_PI));
	} else if (t_0 <= 0.0002) {
		tmp = 180.0 * (atan((1.0 / (fma(-0.5, ((B * B) / (C - A)), ((C - A) * -2.0)) / B))) / ((double) M_PI));
	} else {
		tmp = 180.0 * (atan((1.0 - (fma(-0.5, ((A - C) * ((A - C) / B)), (A - C)) / B))) / ((double) M_PI));
	}
	return tmp;
}
function code(A, B, C)
	t_0 = Float64(Float64(1.0 / B) * Float64(Float64(C - A) - sqrt(Float64((Float64(A - C) ^ 2.0) + (B ^ 2.0)))))
	tmp = 0.0
	if (t_0 <= -4e-22)
		tmp = Float64(180.0 * Float64(atan(Float64(Float64(Float64(C - A) / B) + -1.0)) / pi));
	elseif (t_0 <= 0.0002)
		tmp = Float64(180.0 * Float64(atan(Float64(1.0 / Float64(fma(-0.5, Float64(Float64(B * B) / Float64(C - A)), Float64(Float64(C - A) * -2.0)) / B))) / pi));
	else
		tmp = Float64(180.0 * Float64(atan(Float64(1.0 - Float64(fma(-0.5, Float64(Float64(A - C) * Float64(Float64(A - C) / B)), Float64(A - C)) / B))) / pi));
	end
	return tmp
end
code[A_, B_, C_] := Block[{t$95$0 = N[(N[(1.0 / B), $MachinePrecision] * N[(N[(C - A), $MachinePrecision] - N[Sqrt[N[(N[Power[N[(A - C), $MachinePrecision], 2.0], $MachinePrecision] + N[Power[B, 2.0], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[t$95$0, -4e-22], N[(180.0 * N[(N[ArcTan[N[(N[(N[(C - A), $MachinePrecision] / B), $MachinePrecision] + -1.0), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision], If[LessEqual[t$95$0, 0.0002], N[(180.0 * N[(N[ArcTan[N[(1.0 / N[(N[(-0.5 * N[(N[(B * B), $MachinePrecision] / N[(C - A), $MachinePrecision]), $MachinePrecision] + N[(N[(C - A), $MachinePrecision] * -2.0), $MachinePrecision]), $MachinePrecision] / B), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision], N[(180.0 * N[(N[ArcTan[N[(1.0 - N[(N[(-0.5 * N[(N[(A - C), $MachinePrecision] * N[(N[(A - C), $MachinePrecision] / B), $MachinePrecision]), $MachinePrecision] + N[(A - C), $MachinePrecision]), $MachinePrecision] / B), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision]]]]
\begin{array}{l}

\\
\begin{array}{l}
t_0 := \frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\\
\mathbf{if}\;t\_0 \leq -4 \cdot 10^{-22}:\\
\;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{C - A}{B} + -1\right)}{\pi}\\

\mathbf{elif}\;t\_0 \leq 0.0002:\\
\;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{1}{\frac{\mathsf{fma}\left(-0.5, \frac{B \cdot B}{C - A}, \left(C - A\right) \cdot -2\right)}{B}}\right)}{\pi}\\

\mathbf{else}:\\
\;\;\;\;180 \cdot \frac{\tan^{-1} \left(1 - \frac{\mathsf{fma}\left(-0.5, \left(A - C\right) \cdot \frac{A - C}{B}, A - C\right)}{B}\right)}{\pi}\\


\end{array}
\end{array}
Derivation
  1. Split input into 3 regimes
  2. if (*.f64 (/.f64 #s(literal 1 binary64) B) (-.f64 (-.f64 C A) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))) < -4.0000000000000002e-22

    1. Initial program 62.0%

      \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
    2. Add Preprocessing
    3. Taylor expanded in B around inf

      \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{C}{B} - \left(1 + \frac{A}{B}\right)\right)}}{\mathsf{PI}\left(\right)} \]
    4. Step-by-step derivation
      1. +-commutativeN/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{C}{B} - \color{blue}{\left(\frac{A}{B} + 1\right)}\right)}{\mathsf{PI}\left(\right)} \]
      2. associate--r+N/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\left(\frac{C}{B} - \frac{A}{B}\right) - 1\right)}}{\mathsf{PI}\left(\right)} \]
      3. div-subN/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\color{blue}{\frac{C - A}{B}} - 1\right)}{\mathsf{PI}\left(\right)} \]
      4. sub-negN/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{C - A}{B} + \left(\mathsf{neg}\left(1\right)\right)\right)}}{\mathsf{PI}\left(\right)} \]
      5. metadata-evalN/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{C - A}{B} + \color{blue}{-1}\right)}{\mathsf{PI}\left(\right)} \]
      6. lower-+.f64N/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{C - A}{B} + -1\right)}}{\mathsf{PI}\left(\right)} \]
      7. lower-/.f64N/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\color{blue}{\frac{C - A}{B}} + -1\right)}{\mathsf{PI}\left(\right)} \]
      8. lower--.f6484.8

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\color{blue}{C - A}}{B} + -1\right)}{\pi} \]
    5. Applied rewrites84.8%

      \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{C - A}{B} + -1\right)}}{\pi} \]

    if -4.0000000000000002e-22 < (*.f64 (/.f64 #s(literal 1 binary64) B) (-.f64 (-.f64 C A) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))) < 2.0000000000000001e-4

    1. Initial program 22.2%

      \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
    2. Add Preprocessing
    3. Step-by-step derivation
      1. lift-sqrt.f64N/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \color{blue}{\sqrt{{\left(A - C\right)}^{2} + {B}^{2}}}\right)\right)}{\mathsf{PI}\left(\right)} \]
      2. lift-+.f64N/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{\color{blue}{{\left(A - C\right)}^{2} + {B}^{2}}}\right)\right)}{\mathsf{PI}\left(\right)} \]
    4. Applied rewrites22.2%

      \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \color{blue}{\mathsf{hypot}\left(C - A, B\right)}\right)\right)}{\pi} \]
    5. Step-by-step derivation
      1. lift-*.f64N/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{1}{B} \cdot \left(\left(C - A\right) - \mathsf{hypot}\left(C - A, B\right)\right)\right)}}{\mathsf{PI}\left(\right)} \]
      2. lift-/.f64N/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\color{blue}{\frac{1}{B}} \cdot \left(\left(C - A\right) - \mathsf{hypot}\left(C - A, B\right)\right)\right)}{\mathsf{PI}\left(\right)} \]
      3. associate-*l/N/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{1 \cdot \left(\left(C - A\right) - \mathsf{hypot}\left(C - A, B\right)\right)}{B}\right)}}{\mathsf{PI}\left(\right)} \]
      4. clear-numN/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{1}{\frac{B}{1 \cdot \left(\left(C - A\right) - \mathsf{hypot}\left(C - A, B\right)\right)}}\right)}}{\mathsf{PI}\left(\right)} \]
      5. lower-/.f64N/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{1}{\frac{B}{1 \cdot \left(\left(C - A\right) - \mathsf{hypot}\left(C - A, B\right)\right)}}\right)}}{\mathsf{PI}\left(\right)} \]
      6. *-lft-identityN/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{\frac{B}{\color{blue}{\left(C - A\right) - \mathsf{hypot}\left(C - A, B\right)}}}\right)}{\mathsf{PI}\left(\right)} \]
      7. lower-/.f6422.2

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{\color{blue}{\frac{B}{\left(C - A\right) - \mathsf{hypot}\left(C - A, B\right)}}}\right)}{\pi} \]
      8. lift-hypot.f64N/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{\frac{B}{\left(C - A\right) - \color{blue}{\sqrt{\left(C - A\right) \cdot \left(C - A\right) + B \cdot B}}}}\right)}{\mathsf{PI}\left(\right)} \]
      9. lower-sqrt.f64N/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{\frac{B}{\left(C - A\right) - \color{blue}{\sqrt{\left(C - A\right) \cdot \left(C - A\right) + B \cdot B}}}}\right)}{\mathsf{PI}\left(\right)} \]
      10. lift-*.f64N/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{\frac{B}{\left(C - A\right) - \sqrt{\left(C - A\right) \cdot \left(C - A\right) + \color{blue}{B \cdot B}}}}\right)}{\mathsf{PI}\left(\right)} \]
      11. lower-fma.f6422.2

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{\frac{B}{\left(C - A\right) - \sqrt{\color{blue}{\mathsf{fma}\left(C - A, C - A, B \cdot B\right)}}}}\right)}{\pi} \]
    6. Applied rewrites22.2%

      \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{1}{\frac{B}{\left(C - A\right) - \sqrt{\mathsf{fma}\left(C - A, C - A, B \cdot B\right)}}}\right)}}{\pi} \]
    7. Taylor expanded in B around 0

      \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{\color{blue}{\frac{-2 \cdot \left(C - A\right) + \frac{-1}{2} \cdot \frac{{B}^{2}}{C - A}}{B}}}\right)}{\mathsf{PI}\left(\right)} \]
    8. Step-by-step derivation
      1. lower-/.f64N/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{\color{blue}{\frac{-2 \cdot \left(C - A\right) + \frac{-1}{2} \cdot \frac{{B}^{2}}{C - A}}{B}}}\right)}{\mathsf{PI}\left(\right)} \]
      2. +-commutativeN/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{\frac{\color{blue}{\frac{-1}{2} \cdot \frac{{B}^{2}}{C - A} + -2 \cdot \left(C - A\right)}}{B}}\right)}{\mathsf{PI}\left(\right)} \]
      3. lower-fma.f64N/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{\frac{\color{blue}{\mathsf{fma}\left(\frac{-1}{2}, \frac{{B}^{2}}{C - A}, -2 \cdot \left(C - A\right)\right)}}{B}}\right)}{\mathsf{PI}\left(\right)} \]
      4. lower-/.f64N/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{\frac{\mathsf{fma}\left(\frac{-1}{2}, \color{blue}{\frac{{B}^{2}}{C - A}}, -2 \cdot \left(C - A\right)\right)}{B}}\right)}{\mathsf{PI}\left(\right)} \]
      5. unpow2N/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{\frac{\mathsf{fma}\left(\frac{-1}{2}, \frac{\color{blue}{B \cdot B}}{C - A}, -2 \cdot \left(C - A\right)\right)}{B}}\right)}{\mathsf{PI}\left(\right)} \]
      6. lower-*.f64N/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{\frac{\mathsf{fma}\left(\frac{-1}{2}, \frac{\color{blue}{B \cdot B}}{C - A}, -2 \cdot \left(C - A\right)\right)}{B}}\right)}{\mathsf{PI}\left(\right)} \]
      7. lower--.f64N/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{\frac{\mathsf{fma}\left(\frac{-1}{2}, \frac{B \cdot B}{\color{blue}{C - A}}, -2 \cdot \left(C - A\right)\right)}{B}}\right)}{\mathsf{PI}\left(\right)} \]
      8. *-commutativeN/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{\frac{\mathsf{fma}\left(\frac{-1}{2}, \frac{B \cdot B}{C - A}, \color{blue}{\left(C - A\right) \cdot -2}\right)}{B}}\right)}{\mathsf{PI}\left(\right)} \]
      9. lower-*.f64N/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{\frac{\mathsf{fma}\left(\frac{-1}{2}, \frac{B \cdot B}{C - A}, \color{blue}{\left(C - A\right) \cdot -2}\right)}{B}}\right)}{\mathsf{PI}\left(\right)} \]
      10. lower--.f6499.2

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{\frac{\mathsf{fma}\left(-0.5, \frac{B \cdot B}{C - A}, \color{blue}{\left(C - A\right)} \cdot -2\right)}{B}}\right)}{\pi} \]
    9. Applied rewrites99.2%

      \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{\color{blue}{\frac{\mathsf{fma}\left(-0.5, \frac{B \cdot B}{C - A}, \left(C - A\right) \cdot -2\right)}{B}}}\right)}{\pi} \]

    if 2.0000000000000001e-4 < (*.f64 (/.f64 #s(literal 1 binary64) B) (-.f64 (-.f64 C A) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64))))))

    1. Initial program 61.0%

      \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
    2. Add Preprocessing
    3. Taylor expanded in C around inf

      \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(-1 \cdot \frac{A + -1 \cdot A}{B}\right)}}{\mathsf{PI}\left(\right)} \]
    4. Step-by-step derivation
      1. distribute-rgt1-inN/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(-1 \cdot \frac{\color{blue}{\left(-1 + 1\right) \cdot A}}{B}\right)}{\mathsf{PI}\left(\right)} \]
      2. metadata-evalN/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(-1 \cdot \frac{\color{blue}{0} \cdot A}{B}\right)}{\mathsf{PI}\left(\right)} \]
      3. mul0-lftN/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(-1 \cdot \frac{\color{blue}{0}}{B}\right)}{\mathsf{PI}\left(\right)} \]
      4. div0N/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(-1 \cdot \color{blue}{0}\right)}{\mathsf{PI}\left(\right)} \]
      5. metadata-eval11.1

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{0}}{\pi} \]
    5. Applied rewrites11.1%

      \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{0}}{\pi} \]
    6. Taylor expanded in B around -inf

      \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(1 + -1 \cdot \frac{-1 \cdot \left(C - A\right) + \frac{-1}{2} \cdot \frac{{\left(A - C\right)}^{2}}{B}}{B}\right)}}{\mathsf{PI}\left(\right)} \]
    7. Step-by-step derivation
      1. mul-1-negN/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \color{blue}{\left(\mathsf{neg}\left(\frac{-1 \cdot \left(C - A\right) + \frac{-1}{2} \cdot \frac{{\left(A - C\right)}^{2}}{B}}{B}\right)\right)}\right)}{\mathsf{PI}\left(\right)} \]
      2. unsub-negN/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(1 - \frac{-1 \cdot \left(C - A\right) + \frac{-1}{2} \cdot \frac{{\left(A - C\right)}^{2}}{B}}{B}\right)}}{\mathsf{PI}\left(\right)} \]
      3. lower--.f64N/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(1 - \frac{-1 \cdot \left(C - A\right) + \frac{-1}{2} \cdot \frac{{\left(A - C\right)}^{2}}{B}}{B}\right)}}{\mathsf{PI}\left(\right)} \]
      4. lower-/.f64N/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 - \color{blue}{\frac{-1 \cdot \left(C - A\right) + \frac{-1}{2} \cdot \frac{{\left(A - C\right)}^{2}}{B}}{B}}\right)}{\mathsf{PI}\left(\right)} \]
    8. Applied rewrites79.4%

      \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(1 - \frac{\mathsf{fma}\left(-0.5, \left(A - C\right) \cdot \frac{A - C}{B}, A - C\right)}{B}\right)}}{\pi} \]
  3. Recombined 3 regimes into one program.
  4. Add Preprocessing

Alternative 3: 79.3% accurate, 0.5× speedup?

\[\begin{array}{l} \\ \begin{array}{l} t_0 := \frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\\ \mathbf{if}\;t\_0 \leq -4 \cdot 10^{-22}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{C - A}{B} + -1\right)}{\pi}\\ \mathbf{elif}\;t\_0 \leq 0.0002:\\ \;\;\;\;\frac{180 \cdot \tan^{-1} \left(-0.5 \cdot \frac{B}{C - A}\right)}{\pi}\\ \mathbf{else}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(1 - \frac{\mathsf{fma}\left(-0.5, \left(A - C\right) \cdot \frac{A - C}{B}, A - C\right)}{B}\right)}{\pi}\\ \end{array} \end{array} \]
(FPCore (A B C)
 :precision binary64
 (let* ((t_0
         (* (/ 1.0 B) (- (- C A) (sqrt (+ (pow (- A C) 2.0) (pow B 2.0)))))))
   (if (<= t_0 -4e-22)
     (* 180.0 (/ (atan (+ (/ (- C A) B) -1.0)) PI))
     (if (<= t_0 0.0002)
       (/ (* 180.0 (atan (* -0.5 (/ B (- C A))))) PI)
       (*
        180.0
        (/
         (atan (- 1.0 (/ (fma -0.5 (* (- A C) (/ (- A C) B)) (- A C)) B)))
         PI))))))
double code(double A, double B, double C) {
	double t_0 = (1.0 / B) * ((C - A) - sqrt((pow((A - C), 2.0) + pow(B, 2.0))));
	double tmp;
	if (t_0 <= -4e-22) {
		tmp = 180.0 * (atan((((C - A) / B) + -1.0)) / ((double) M_PI));
	} else if (t_0 <= 0.0002) {
		tmp = (180.0 * atan((-0.5 * (B / (C - A))))) / ((double) M_PI);
	} else {
		tmp = 180.0 * (atan((1.0 - (fma(-0.5, ((A - C) * ((A - C) / B)), (A - C)) / B))) / ((double) M_PI));
	}
	return tmp;
}
function code(A, B, C)
	t_0 = Float64(Float64(1.0 / B) * Float64(Float64(C - A) - sqrt(Float64((Float64(A - C) ^ 2.0) + (B ^ 2.0)))))
	tmp = 0.0
	if (t_0 <= -4e-22)
		tmp = Float64(180.0 * Float64(atan(Float64(Float64(Float64(C - A) / B) + -1.0)) / pi));
	elseif (t_0 <= 0.0002)
		tmp = Float64(Float64(180.0 * atan(Float64(-0.5 * Float64(B / Float64(C - A))))) / pi);
	else
		tmp = Float64(180.0 * Float64(atan(Float64(1.0 - Float64(fma(-0.5, Float64(Float64(A - C) * Float64(Float64(A - C) / B)), Float64(A - C)) / B))) / pi));
	end
	return tmp
end
code[A_, B_, C_] := Block[{t$95$0 = N[(N[(1.0 / B), $MachinePrecision] * N[(N[(C - A), $MachinePrecision] - N[Sqrt[N[(N[Power[N[(A - C), $MachinePrecision], 2.0], $MachinePrecision] + N[Power[B, 2.0], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[t$95$0, -4e-22], N[(180.0 * N[(N[ArcTan[N[(N[(N[(C - A), $MachinePrecision] / B), $MachinePrecision] + -1.0), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision], If[LessEqual[t$95$0, 0.0002], N[(N[(180.0 * N[ArcTan[N[(-0.5 * N[(B / N[(C - A), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] / Pi), $MachinePrecision], N[(180.0 * N[(N[ArcTan[N[(1.0 - N[(N[(-0.5 * N[(N[(A - C), $MachinePrecision] * N[(N[(A - C), $MachinePrecision] / B), $MachinePrecision]), $MachinePrecision] + N[(A - C), $MachinePrecision]), $MachinePrecision] / B), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision]]]]
\begin{array}{l}

\\
\begin{array}{l}
t_0 := \frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\\
\mathbf{if}\;t\_0 \leq -4 \cdot 10^{-22}:\\
\;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{C - A}{B} + -1\right)}{\pi}\\

\mathbf{elif}\;t\_0 \leq 0.0002:\\
\;\;\;\;\frac{180 \cdot \tan^{-1} \left(-0.5 \cdot \frac{B}{C - A}\right)}{\pi}\\

\mathbf{else}:\\
\;\;\;\;180 \cdot \frac{\tan^{-1} \left(1 - \frac{\mathsf{fma}\left(-0.5, \left(A - C\right) \cdot \frac{A - C}{B}, A - C\right)}{B}\right)}{\pi}\\


\end{array}
\end{array}
Derivation
  1. Split input into 3 regimes
  2. if (*.f64 (/.f64 #s(literal 1 binary64) B) (-.f64 (-.f64 C A) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))) < -4.0000000000000002e-22

    1. Initial program 62.0%

      \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
    2. Add Preprocessing
    3. Taylor expanded in B around inf

      \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{C}{B} - \left(1 + \frac{A}{B}\right)\right)}}{\mathsf{PI}\left(\right)} \]
    4. Step-by-step derivation
      1. +-commutativeN/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{C}{B} - \color{blue}{\left(\frac{A}{B} + 1\right)}\right)}{\mathsf{PI}\left(\right)} \]
      2. associate--r+N/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\left(\frac{C}{B} - \frac{A}{B}\right) - 1\right)}}{\mathsf{PI}\left(\right)} \]
      3. div-subN/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\color{blue}{\frac{C - A}{B}} - 1\right)}{\mathsf{PI}\left(\right)} \]
      4. sub-negN/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{C - A}{B} + \left(\mathsf{neg}\left(1\right)\right)\right)}}{\mathsf{PI}\left(\right)} \]
      5. metadata-evalN/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{C - A}{B} + \color{blue}{-1}\right)}{\mathsf{PI}\left(\right)} \]
      6. lower-+.f64N/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{C - A}{B} + -1\right)}}{\mathsf{PI}\left(\right)} \]
      7. lower-/.f64N/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\color{blue}{\frac{C - A}{B}} + -1\right)}{\mathsf{PI}\left(\right)} \]
      8. lower--.f6484.8

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\color{blue}{C - A}}{B} + -1\right)}{\pi} \]
    5. Applied rewrites84.8%

      \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{C - A}{B} + -1\right)}}{\pi} \]

    if -4.0000000000000002e-22 < (*.f64 (/.f64 #s(literal 1 binary64) B) (-.f64 (-.f64 C A) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))) < 2.0000000000000001e-4

    1. Initial program 22.2%

      \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
    2. Add Preprocessing
    3. Step-by-step derivation
      1. lift-sqrt.f64N/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \color{blue}{\sqrt{{\left(A - C\right)}^{2} + {B}^{2}}}\right)\right)}{\mathsf{PI}\left(\right)} \]
      2. lift-+.f64N/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{\color{blue}{{\left(A - C\right)}^{2} + {B}^{2}}}\right)\right)}{\mathsf{PI}\left(\right)} \]
    4. Applied rewrites22.2%

      \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \color{blue}{\mathsf{hypot}\left(C - A, B\right)}\right)\right)}{\pi} \]
    5. Taylor expanded in B around 0

      \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{-1}{2} \cdot \frac{B}{C - A}\right)}}{\mathsf{PI}\left(\right)} \]
    6. Step-by-step derivation
      1. lower-*.f64N/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{-1}{2} \cdot \frac{B}{C - A}\right)}}{\mathsf{PI}\left(\right)} \]
      2. lower-/.f64N/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{-1}{2} \cdot \color{blue}{\frac{B}{C - A}}\right)}{\mathsf{PI}\left(\right)} \]
      3. lower--.f6498.3

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(-0.5 \cdot \frac{B}{\color{blue}{C - A}}\right)}{\pi} \]
    7. Applied rewrites98.3%

      \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(-0.5 \cdot \frac{B}{C - A}\right)}}{\pi} \]
    8. Step-by-step derivation
      1. lift-*.f64N/A

        \[\leadsto \color{blue}{180 \cdot \frac{\tan^{-1} \left(\frac{-1}{2} \cdot \frac{B}{C - A}\right)}{\mathsf{PI}\left(\right)}} \]
      2. lift-/.f64N/A

        \[\leadsto 180 \cdot \color{blue}{\frac{\tan^{-1} \left(\frac{-1}{2} \cdot \frac{B}{C - A}\right)}{\mathsf{PI}\left(\right)}} \]
      3. associate-*r/N/A

        \[\leadsto \color{blue}{\frac{180 \cdot \tan^{-1} \left(\frac{-1}{2} \cdot \frac{B}{C - A}\right)}{\mathsf{PI}\left(\right)}} \]
      4. lower-/.f64N/A

        \[\leadsto \color{blue}{\frac{180 \cdot \tan^{-1} \left(\frac{-1}{2} \cdot \frac{B}{C - A}\right)}{\mathsf{PI}\left(\right)}} \]
      5. lower-*.f6498.5

        \[\leadsto \frac{\color{blue}{180 \cdot \tan^{-1} \left(-0.5 \cdot \frac{B}{C - A}\right)}}{\pi} \]
    9. Applied rewrites98.5%

      \[\leadsto \color{blue}{\frac{180 \cdot \tan^{-1} \left(-0.5 \cdot \frac{B}{C - A}\right)}{\pi}} \]

    if 2.0000000000000001e-4 < (*.f64 (/.f64 #s(literal 1 binary64) B) (-.f64 (-.f64 C A) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64))))))

    1. Initial program 61.0%

      \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
    2. Add Preprocessing
    3. Taylor expanded in C around inf

      \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(-1 \cdot \frac{A + -1 \cdot A}{B}\right)}}{\mathsf{PI}\left(\right)} \]
    4. Step-by-step derivation
      1. distribute-rgt1-inN/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(-1 \cdot \frac{\color{blue}{\left(-1 + 1\right) \cdot A}}{B}\right)}{\mathsf{PI}\left(\right)} \]
      2. metadata-evalN/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(-1 \cdot \frac{\color{blue}{0} \cdot A}{B}\right)}{\mathsf{PI}\left(\right)} \]
      3. mul0-lftN/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(-1 \cdot \frac{\color{blue}{0}}{B}\right)}{\mathsf{PI}\left(\right)} \]
      4. div0N/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(-1 \cdot \color{blue}{0}\right)}{\mathsf{PI}\left(\right)} \]
      5. metadata-eval11.1

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{0}}{\pi} \]
    5. Applied rewrites11.1%

      \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{0}}{\pi} \]
    6. Taylor expanded in B around -inf

      \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(1 + -1 \cdot \frac{-1 \cdot \left(C - A\right) + \frac{-1}{2} \cdot \frac{{\left(A - C\right)}^{2}}{B}}{B}\right)}}{\mathsf{PI}\left(\right)} \]
    7. Step-by-step derivation
      1. mul-1-negN/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \color{blue}{\left(\mathsf{neg}\left(\frac{-1 \cdot \left(C - A\right) + \frac{-1}{2} \cdot \frac{{\left(A - C\right)}^{2}}{B}}{B}\right)\right)}\right)}{\mathsf{PI}\left(\right)} \]
      2. unsub-negN/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(1 - \frac{-1 \cdot \left(C - A\right) + \frac{-1}{2} \cdot \frac{{\left(A - C\right)}^{2}}{B}}{B}\right)}}{\mathsf{PI}\left(\right)} \]
      3. lower--.f64N/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(1 - \frac{-1 \cdot \left(C - A\right) + \frac{-1}{2} \cdot \frac{{\left(A - C\right)}^{2}}{B}}{B}\right)}}{\mathsf{PI}\left(\right)} \]
      4. lower-/.f64N/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 - \color{blue}{\frac{-1 \cdot \left(C - A\right) + \frac{-1}{2} \cdot \frac{{\left(A - C\right)}^{2}}{B}}{B}}\right)}{\mathsf{PI}\left(\right)} \]
    8. Applied rewrites79.4%

      \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(1 - \frac{\mathsf{fma}\left(-0.5, \left(A - C\right) \cdot \frac{A - C}{B}, A - C\right)}{B}\right)}}{\pi} \]
  3. Recombined 3 regimes into one program.
  4. Add Preprocessing

Alternative 4: 79.0% accurate, 0.6× speedup?

\[\begin{array}{l} \\ \begin{array}{l} t_0 := \frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\\ t_1 := \frac{C - A}{B}\\ \mathbf{if}\;t\_0 \leq -4 \cdot 10^{-22}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(t\_1 + -1\right)}{\pi}\\ \mathbf{elif}\;t\_0 \leq 0.0002:\\ \;\;\;\;\frac{180 \cdot \tan^{-1} \left(-0.5 \cdot \frac{B}{C - A}\right)}{\pi}\\ \mathbf{else}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(1 + t\_1\right)}{\pi}\\ \end{array} \end{array} \]
(FPCore (A B C)
 :precision binary64
 (let* ((t_0
         (* (/ 1.0 B) (- (- C A) (sqrt (+ (pow (- A C) 2.0) (pow B 2.0))))))
        (t_1 (/ (- C A) B)))
   (if (<= t_0 -4e-22)
     (* 180.0 (/ (atan (+ t_1 -1.0)) PI))
     (if (<= t_0 0.0002)
       (/ (* 180.0 (atan (* -0.5 (/ B (- C A))))) PI)
       (* 180.0 (/ (atan (+ 1.0 t_1)) PI))))))
double code(double A, double B, double C) {
	double t_0 = (1.0 / B) * ((C - A) - sqrt((pow((A - C), 2.0) + pow(B, 2.0))));
	double t_1 = (C - A) / B;
	double tmp;
	if (t_0 <= -4e-22) {
		tmp = 180.0 * (atan((t_1 + -1.0)) / ((double) M_PI));
	} else if (t_0 <= 0.0002) {
		tmp = (180.0 * atan((-0.5 * (B / (C - A))))) / ((double) M_PI);
	} else {
		tmp = 180.0 * (atan((1.0 + t_1)) / ((double) M_PI));
	}
	return tmp;
}
public static double code(double A, double B, double C) {
	double t_0 = (1.0 / B) * ((C - A) - Math.sqrt((Math.pow((A - C), 2.0) + Math.pow(B, 2.0))));
	double t_1 = (C - A) / B;
	double tmp;
	if (t_0 <= -4e-22) {
		tmp = 180.0 * (Math.atan((t_1 + -1.0)) / Math.PI);
	} else if (t_0 <= 0.0002) {
		tmp = (180.0 * Math.atan((-0.5 * (B / (C - A))))) / Math.PI;
	} else {
		tmp = 180.0 * (Math.atan((1.0 + t_1)) / Math.PI);
	}
	return tmp;
}
def code(A, B, C):
	t_0 = (1.0 / B) * ((C - A) - math.sqrt((math.pow((A - C), 2.0) + math.pow(B, 2.0))))
	t_1 = (C - A) / B
	tmp = 0
	if t_0 <= -4e-22:
		tmp = 180.0 * (math.atan((t_1 + -1.0)) / math.pi)
	elif t_0 <= 0.0002:
		tmp = (180.0 * math.atan((-0.5 * (B / (C - A))))) / math.pi
	else:
		tmp = 180.0 * (math.atan((1.0 + t_1)) / math.pi)
	return tmp
function code(A, B, C)
	t_0 = Float64(Float64(1.0 / B) * Float64(Float64(C - A) - sqrt(Float64((Float64(A - C) ^ 2.0) + (B ^ 2.0)))))
	t_1 = Float64(Float64(C - A) / B)
	tmp = 0.0
	if (t_0 <= -4e-22)
		tmp = Float64(180.0 * Float64(atan(Float64(t_1 + -1.0)) / pi));
	elseif (t_0 <= 0.0002)
		tmp = Float64(Float64(180.0 * atan(Float64(-0.5 * Float64(B / Float64(C - A))))) / pi);
	else
		tmp = Float64(180.0 * Float64(atan(Float64(1.0 + t_1)) / pi));
	end
	return tmp
end
function tmp_2 = code(A, B, C)
	t_0 = (1.0 / B) * ((C - A) - sqrt((((A - C) ^ 2.0) + (B ^ 2.0))));
	t_1 = (C - A) / B;
	tmp = 0.0;
	if (t_0 <= -4e-22)
		tmp = 180.0 * (atan((t_1 + -1.0)) / pi);
	elseif (t_0 <= 0.0002)
		tmp = (180.0 * atan((-0.5 * (B / (C - A))))) / pi;
	else
		tmp = 180.0 * (atan((1.0 + t_1)) / pi);
	end
	tmp_2 = tmp;
end
code[A_, B_, C_] := Block[{t$95$0 = N[(N[(1.0 / B), $MachinePrecision] * N[(N[(C - A), $MachinePrecision] - N[Sqrt[N[(N[Power[N[(A - C), $MachinePrecision], 2.0], $MachinePrecision] + N[Power[B, 2.0], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$1 = N[(N[(C - A), $MachinePrecision] / B), $MachinePrecision]}, If[LessEqual[t$95$0, -4e-22], N[(180.0 * N[(N[ArcTan[N[(t$95$1 + -1.0), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision], If[LessEqual[t$95$0, 0.0002], N[(N[(180.0 * N[ArcTan[N[(-0.5 * N[(B / N[(C - A), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] / Pi), $MachinePrecision], N[(180.0 * N[(N[ArcTan[N[(1.0 + t$95$1), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision]]]]]
\begin{array}{l}

\\
\begin{array}{l}
t_0 := \frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\\
t_1 := \frac{C - A}{B}\\
\mathbf{if}\;t\_0 \leq -4 \cdot 10^{-22}:\\
\;\;\;\;180 \cdot \frac{\tan^{-1} \left(t\_1 + -1\right)}{\pi}\\

\mathbf{elif}\;t\_0 \leq 0.0002:\\
\;\;\;\;\frac{180 \cdot \tan^{-1} \left(-0.5 \cdot \frac{B}{C - A}\right)}{\pi}\\

\mathbf{else}:\\
\;\;\;\;180 \cdot \frac{\tan^{-1} \left(1 + t\_1\right)}{\pi}\\


\end{array}
\end{array}
Derivation
  1. Split input into 3 regimes
  2. if (*.f64 (/.f64 #s(literal 1 binary64) B) (-.f64 (-.f64 C A) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))) < -4.0000000000000002e-22

    1. Initial program 62.0%

      \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
    2. Add Preprocessing
    3. Taylor expanded in B around inf

      \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{C}{B} - \left(1 + \frac{A}{B}\right)\right)}}{\mathsf{PI}\left(\right)} \]
    4. Step-by-step derivation
      1. +-commutativeN/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{C}{B} - \color{blue}{\left(\frac{A}{B} + 1\right)}\right)}{\mathsf{PI}\left(\right)} \]
      2. associate--r+N/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\left(\frac{C}{B} - \frac{A}{B}\right) - 1\right)}}{\mathsf{PI}\left(\right)} \]
      3. div-subN/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\color{blue}{\frac{C - A}{B}} - 1\right)}{\mathsf{PI}\left(\right)} \]
      4. sub-negN/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{C - A}{B} + \left(\mathsf{neg}\left(1\right)\right)\right)}}{\mathsf{PI}\left(\right)} \]
      5. metadata-evalN/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{C - A}{B} + \color{blue}{-1}\right)}{\mathsf{PI}\left(\right)} \]
      6. lower-+.f64N/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{C - A}{B} + -1\right)}}{\mathsf{PI}\left(\right)} \]
      7. lower-/.f64N/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\color{blue}{\frac{C - A}{B}} + -1\right)}{\mathsf{PI}\left(\right)} \]
      8. lower--.f6484.8

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\color{blue}{C - A}}{B} + -1\right)}{\pi} \]
    5. Applied rewrites84.8%

      \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{C - A}{B} + -1\right)}}{\pi} \]

    if -4.0000000000000002e-22 < (*.f64 (/.f64 #s(literal 1 binary64) B) (-.f64 (-.f64 C A) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))) < 2.0000000000000001e-4

    1. Initial program 22.2%

      \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
    2. Add Preprocessing
    3. Step-by-step derivation
      1. lift-sqrt.f64N/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \color{blue}{\sqrt{{\left(A - C\right)}^{2} + {B}^{2}}}\right)\right)}{\mathsf{PI}\left(\right)} \]
      2. lift-+.f64N/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{\color{blue}{{\left(A - C\right)}^{2} + {B}^{2}}}\right)\right)}{\mathsf{PI}\left(\right)} \]
    4. Applied rewrites22.2%

      \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \color{blue}{\mathsf{hypot}\left(C - A, B\right)}\right)\right)}{\pi} \]
    5. Taylor expanded in B around 0

      \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{-1}{2} \cdot \frac{B}{C - A}\right)}}{\mathsf{PI}\left(\right)} \]
    6. Step-by-step derivation
      1. lower-*.f64N/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{-1}{2} \cdot \frac{B}{C - A}\right)}}{\mathsf{PI}\left(\right)} \]
      2. lower-/.f64N/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{-1}{2} \cdot \color{blue}{\frac{B}{C - A}}\right)}{\mathsf{PI}\left(\right)} \]
      3. lower--.f6498.3

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(-0.5 \cdot \frac{B}{\color{blue}{C - A}}\right)}{\pi} \]
    7. Applied rewrites98.3%

      \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(-0.5 \cdot \frac{B}{C - A}\right)}}{\pi} \]
    8. Step-by-step derivation
      1. lift-*.f64N/A

        \[\leadsto \color{blue}{180 \cdot \frac{\tan^{-1} \left(\frac{-1}{2} \cdot \frac{B}{C - A}\right)}{\mathsf{PI}\left(\right)}} \]
      2. lift-/.f64N/A

        \[\leadsto 180 \cdot \color{blue}{\frac{\tan^{-1} \left(\frac{-1}{2} \cdot \frac{B}{C - A}\right)}{\mathsf{PI}\left(\right)}} \]
      3. associate-*r/N/A

        \[\leadsto \color{blue}{\frac{180 \cdot \tan^{-1} \left(\frac{-1}{2} \cdot \frac{B}{C - A}\right)}{\mathsf{PI}\left(\right)}} \]
      4. lower-/.f64N/A

        \[\leadsto \color{blue}{\frac{180 \cdot \tan^{-1} \left(\frac{-1}{2} \cdot \frac{B}{C - A}\right)}{\mathsf{PI}\left(\right)}} \]
      5. lower-*.f6498.5

        \[\leadsto \frac{\color{blue}{180 \cdot \tan^{-1} \left(-0.5 \cdot \frac{B}{C - A}\right)}}{\pi} \]
    9. Applied rewrites98.5%

      \[\leadsto \color{blue}{\frac{180 \cdot \tan^{-1} \left(-0.5 \cdot \frac{B}{C - A}\right)}{\pi}} \]

    if 2.0000000000000001e-4 < (*.f64 (/.f64 #s(literal 1 binary64) B) (-.f64 (-.f64 C A) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64))))))

    1. Initial program 61.0%

      \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
    2. Add Preprocessing
    3. Taylor expanded in B around -inf

      \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\left(1 + \frac{C}{B}\right) - \frac{A}{B}\right)}}{\mathsf{PI}\left(\right)} \]
    4. Step-by-step derivation
      1. associate--l+N/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(1 + \left(\frac{C}{B} - \frac{A}{B}\right)\right)}}{\mathsf{PI}\left(\right)} \]
      2. div-subN/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \color{blue}{\frac{C - A}{B}}\right)}{\mathsf{PI}\left(\right)} \]
      3. lower-+.f64N/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(1 + \frac{C - A}{B}\right)}}{\mathsf{PI}\left(\right)} \]
      4. lower-/.f64N/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \color{blue}{\frac{C - A}{B}}\right)}{\mathsf{PI}\left(\right)} \]
      5. lower--.f6478.9

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \frac{\color{blue}{C - A}}{B}\right)}{\pi} \]
    5. Applied rewrites78.9%

      \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(1 + \frac{C - A}{B}\right)}}{\pi} \]
  3. Recombined 3 regimes into one program.
  4. Add Preprocessing

Alternative 5: 78.9% accurate, 0.6× speedup?

\[\begin{array}{l} \\ \begin{array}{l} t_0 := \frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\\ t_1 := \frac{C - A}{B}\\ \mathbf{if}\;t\_0 \leq -4 \cdot 10^{-22}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(t\_1 + -1\right)}{\pi}\\ \mathbf{elif}\;t\_0 \leq 0.0002:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(-0.5 \cdot \frac{B}{C - A}\right)}{\pi}\\ \mathbf{else}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(1 + t\_1\right)}{\pi}\\ \end{array} \end{array} \]
(FPCore (A B C)
 :precision binary64
 (let* ((t_0
         (* (/ 1.0 B) (- (- C A) (sqrt (+ (pow (- A C) 2.0) (pow B 2.0))))))
        (t_1 (/ (- C A) B)))
   (if (<= t_0 -4e-22)
     (* 180.0 (/ (atan (+ t_1 -1.0)) PI))
     (if (<= t_0 0.0002)
       (* 180.0 (/ (atan (* -0.5 (/ B (- C A)))) PI))
       (* 180.0 (/ (atan (+ 1.0 t_1)) PI))))))
double code(double A, double B, double C) {
	double t_0 = (1.0 / B) * ((C - A) - sqrt((pow((A - C), 2.0) + pow(B, 2.0))));
	double t_1 = (C - A) / B;
	double tmp;
	if (t_0 <= -4e-22) {
		tmp = 180.0 * (atan((t_1 + -1.0)) / ((double) M_PI));
	} else if (t_0 <= 0.0002) {
		tmp = 180.0 * (atan((-0.5 * (B / (C - A)))) / ((double) M_PI));
	} else {
		tmp = 180.0 * (atan((1.0 + t_1)) / ((double) M_PI));
	}
	return tmp;
}
public static double code(double A, double B, double C) {
	double t_0 = (1.0 / B) * ((C - A) - Math.sqrt((Math.pow((A - C), 2.0) + Math.pow(B, 2.0))));
	double t_1 = (C - A) / B;
	double tmp;
	if (t_0 <= -4e-22) {
		tmp = 180.0 * (Math.atan((t_1 + -1.0)) / Math.PI);
	} else if (t_0 <= 0.0002) {
		tmp = 180.0 * (Math.atan((-0.5 * (B / (C - A)))) / Math.PI);
	} else {
		tmp = 180.0 * (Math.atan((1.0 + t_1)) / Math.PI);
	}
	return tmp;
}
def code(A, B, C):
	t_0 = (1.0 / B) * ((C - A) - math.sqrt((math.pow((A - C), 2.0) + math.pow(B, 2.0))))
	t_1 = (C - A) / B
	tmp = 0
	if t_0 <= -4e-22:
		tmp = 180.0 * (math.atan((t_1 + -1.0)) / math.pi)
	elif t_0 <= 0.0002:
		tmp = 180.0 * (math.atan((-0.5 * (B / (C - A)))) / math.pi)
	else:
		tmp = 180.0 * (math.atan((1.0 + t_1)) / math.pi)
	return tmp
function code(A, B, C)
	t_0 = Float64(Float64(1.0 / B) * Float64(Float64(C - A) - sqrt(Float64((Float64(A - C) ^ 2.0) + (B ^ 2.0)))))
	t_1 = Float64(Float64(C - A) / B)
	tmp = 0.0
	if (t_0 <= -4e-22)
		tmp = Float64(180.0 * Float64(atan(Float64(t_1 + -1.0)) / pi));
	elseif (t_0 <= 0.0002)
		tmp = Float64(180.0 * Float64(atan(Float64(-0.5 * Float64(B / Float64(C - A)))) / pi));
	else
		tmp = Float64(180.0 * Float64(atan(Float64(1.0 + t_1)) / pi));
	end
	return tmp
end
function tmp_2 = code(A, B, C)
	t_0 = (1.0 / B) * ((C - A) - sqrt((((A - C) ^ 2.0) + (B ^ 2.0))));
	t_1 = (C - A) / B;
	tmp = 0.0;
	if (t_0 <= -4e-22)
		tmp = 180.0 * (atan((t_1 + -1.0)) / pi);
	elseif (t_0 <= 0.0002)
		tmp = 180.0 * (atan((-0.5 * (B / (C - A)))) / pi);
	else
		tmp = 180.0 * (atan((1.0 + t_1)) / pi);
	end
	tmp_2 = tmp;
end
code[A_, B_, C_] := Block[{t$95$0 = N[(N[(1.0 / B), $MachinePrecision] * N[(N[(C - A), $MachinePrecision] - N[Sqrt[N[(N[Power[N[(A - C), $MachinePrecision], 2.0], $MachinePrecision] + N[Power[B, 2.0], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$1 = N[(N[(C - A), $MachinePrecision] / B), $MachinePrecision]}, If[LessEqual[t$95$0, -4e-22], N[(180.0 * N[(N[ArcTan[N[(t$95$1 + -1.0), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision], If[LessEqual[t$95$0, 0.0002], N[(180.0 * N[(N[ArcTan[N[(-0.5 * N[(B / N[(C - A), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision], N[(180.0 * N[(N[ArcTan[N[(1.0 + t$95$1), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision]]]]]
\begin{array}{l}

\\
\begin{array}{l}
t_0 := \frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\\
t_1 := \frac{C - A}{B}\\
\mathbf{if}\;t\_0 \leq -4 \cdot 10^{-22}:\\
\;\;\;\;180 \cdot \frac{\tan^{-1} \left(t\_1 + -1\right)}{\pi}\\

\mathbf{elif}\;t\_0 \leq 0.0002:\\
\;\;\;\;180 \cdot \frac{\tan^{-1} \left(-0.5 \cdot \frac{B}{C - A}\right)}{\pi}\\

\mathbf{else}:\\
\;\;\;\;180 \cdot \frac{\tan^{-1} \left(1 + t\_1\right)}{\pi}\\


\end{array}
\end{array}
Derivation
  1. Split input into 3 regimes
  2. if (*.f64 (/.f64 #s(literal 1 binary64) B) (-.f64 (-.f64 C A) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))) < -4.0000000000000002e-22

    1. Initial program 62.0%

      \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
    2. Add Preprocessing
    3. Taylor expanded in B around inf

      \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{C}{B} - \left(1 + \frac{A}{B}\right)\right)}}{\mathsf{PI}\left(\right)} \]
    4. Step-by-step derivation
      1. +-commutativeN/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{C}{B} - \color{blue}{\left(\frac{A}{B} + 1\right)}\right)}{\mathsf{PI}\left(\right)} \]
      2. associate--r+N/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\left(\frac{C}{B} - \frac{A}{B}\right) - 1\right)}}{\mathsf{PI}\left(\right)} \]
      3. div-subN/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\color{blue}{\frac{C - A}{B}} - 1\right)}{\mathsf{PI}\left(\right)} \]
      4. sub-negN/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{C - A}{B} + \left(\mathsf{neg}\left(1\right)\right)\right)}}{\mathsf{PI}\left(\right)} \]
      5. metadata-evalN/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{C - A}{B} + \color{blue}{-1}\right)}{\mathsf{PI}\left(\right)} \]
      6. lower-+.f64N/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{C - A}{B} + -1\right)}}{\mathsf{PI}\left(\right)} \]
      7. lower-/.f64N/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\color{blue}{\frac{C - A}{B}} + -1\right)}{\mathsf{PI}\left(\right)} \]
      8. lower--.f6484.8

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\color{blue}{C - A}}{B} + -1\right)}{\pi} \]
    5. Applied rewrites84.8%

      \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{C - A}{B} + -1\right)}}{\pi} \]

    if -4.0000000000000002e-22 < (*.f64 (/.f64 #s(literal 1 binary64) B) (-.f64 (-.f64 C A) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))) < 2.0000000000000001e-4

    1. Initial program 22.2%

      \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
    2. Add Preprocessing
    3. Step-by-step derivation
      1. lift-sqrt.f64N/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \color{blue}{\sqrt{{\left(A - C\right)}^{2} + {B}^{2}}}\right)\right)}{\mathsf{PI}\left(\right)} \]
      2. lift-+.f64N/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{\color{blue}{{\left(A - C\right)}^{2} + {B}^{2}}}\right)\right)}{\mathsf{PI}\left(\right)} \]
    4. Applied rewrites22.2%

      \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \color{blue}{\mathsf{hypot}\left(C - A, B\right)}\right)\right)}{\pi} \]
    5. Taylor expanded in B around 0

      \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{-1}{2} \cdot \frac{B}{C - A}\right)}}{\mathsf{PI}\left(\right)} \]
    6. Step-by-step derivation
      1. lower-*.f64N/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{-1}{2} \cdot \frac{B}{C - A}\right)}}{\mathsf{PI}\left(\right)} \]
      2. lower-/.f64N/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{-1}{2} \cdot \color{blue}{\frac{B}{C - A}}\right)}{\mathsf{PI}\left(\right)} \]
      3. lower--.f6498.3

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(-0.5 \cdot \frac{B}{\color{blue}{C - A}}\right)}{\pi} \]
    7. Applied rewrites98.3%

      \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(-0.5 \cdot \frac{B}{C - A}\right)}}{\pi} \]

    if 2.0000000000000001e-4 < (*.f64 (/.f64 #s(literal 1 binary64) B) (-.f64 (-.f64 C A) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64))))))

    1. Initial program 61.0%

      \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
    2. Add Preprocessing
    3. Taylor expanded in B around -inf

      \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\left(1 + \frac{C}{B}\right) - \frac{A}{B}\right)}}{\mathsf{PI}\left(\right)} \]
    4. Step-by-step derivation
      1. associate--l+N/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(1 + \left(\frac{C}{B} - \frac{A}{B}\right)\right)}}{\mathsf{PI}\left(\right)} \]
      2. div-subN/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \color{blue}{\frac{C - A}{B}}\right)}{\mathsf{PI}\left(\right)} \]
      3. lower-+.f64N/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(1 + \frac{C - A}{B}\right)}}{\mathsf{PI}\left(\right)} \]
      4. lower-/.f64N/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \color{blue}{\frac{C - A}{B}}\right)}{\mathsf{PI}\left(\right)} \]
      5. lower--.f6478.9

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \frac{\color{blue}{C - A}}{B}\right)}{\pi} \]
    5. Applied rewrites78.9%

      \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(1 + \frac{C - A}{B}\right)}}{\pi} \]
  3. Recombined 3 regimes into one program.
  4. Add Preprocessing

Alternative 6: 72.7% accurate, 0.6× speedup?

\[\begin{array}{l} \\ \begin{array}{l} t_0 := \frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\\ t_1 := \frac{C - A}{B}\\ \mathbf{if}\;t\_0 \leq -4 \cdot 10^{-22}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(t\_1 + -1\right)}{\pi}\\ \mathbf{elif}\;t\_0 \leq 0.0002:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\mathsf{fma}\left(B, \frac{-0.5}{C}, 0\right)\right)}{\pi}\\ \mathbf{else}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(1 + t\_1\right)}{\pi}\\ \end{array} \end{array} \]
(FPCore (A B C)
 :precision binary64
 (let* ((t_0
         (* (/ 1.0 B) (- (- C A) (sqrt (+ (pow (- A C) 2.0) (pow B 2.0))))))
        (t_1 (/ (- C A) B)))
   (if (<= t_0 -4e-22)
     (* 180.0 (/ (atan (+ t_1 -1.0)) PI))
     (if (<= t_0 0.0002)
       (* 180.0 (/ (atan (fma B (/ -0.5 C) 0.0)) PI))
       (* 180.0 (/ (atan (+ 1.0 t_1)) PI))))))
double code(double A, double B, double C) {
	double t_0 = (1.0 / B) * ((C - A) - sqrt((pow((A - C), 2.0) + pow(B, 2.0))));
	double t_1 = (C - A) / B;
	double tmp;
	if (t_0 <= -4e-22) {
		tmp = 180.0 * (atan((t_1 + -1.0)) / ((double) M_PI));
	} else if (t_0 <= 0.0002) {
		tmp = 180.0 * (atan(fma(B, (-0.5 / C), 0.0)) / ((double) M_PI));
	} else {
		tmp = 180.0 * (atan((1.0 + t_1)) / ((double) M_PI));
	}
	return tmp;
}
function code(A, B, C)
	t_0 = Float64(Float64(1.0 / B) * Float64(Float64(C - A) - sqrt(Float64((Float64(A - C) ^ 2.0) + (B ^ 2.0)))))
	t_1 = Float64(Float64(C - A) / B)
	tmp = 0.0
	if (t_0 <= -4e-22)
		tmp = Float64(180.0 * Float64(atan(Float64(t_1 + -1.0)) / pi));
	elseif (t_0 <= 0.0002)
		tmp = Float64(180.0 * Float64(atan(fma(B, Float64(-0.5 / C), 0.0)) / pi));
	else
		tmp = Float64(180.0 * Float64(atan(Float64(1.0 + t_1)) / pi));
	end
	return tmp
end
code[A_, B_, C_] := Block[{t$95$0 = N[(N[(1.0 / B), $MachinePrecision] * N[(N[(C - A), $MachinePrecision] - N[Sqrt[N[(N[Power[N[(A - C), $MachinePrecision], 2.0], $MachinePrecision] + N[Power[B, 2.0], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$1 = N[(N[(C - A), $MachinePrecision] / B), $MachinePrecision]}, If[LessEqual[t$95$0, -4e-22], N[(180.0 * N[(N[ArcTan[N[(t$95$1 + -1.0), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision], If[LessEqual[t$95$0, 0.0002], N[(180.0 * N[(N[ArcTan[N[(B * N[(-0.5 / C), $MachinePrecision] + 0.0), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision], N[(180.0 * N[(N[ArcTan[N[(1.0 + t$95$1), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision]]]]]
\begin{array}{l}

\\
\begin{array}{l}
t_0 := \frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\\
t_1 := \frac{C - A}{B}\\
\mathbf{if}\;t\_0 \leq -4 \cdot 10^{-22}:\\
\;\;\;\;180 \cdot \frac{\tan^{-1} \left(t\_1 + -1\right)}{\pi}\\

\mathbf{elif}\;t\_0 \leq 0.0002:\\
\;\;\;\;180 \cdot \frac{\tan^{-1} \left(\mathsf{fma}\left(B, \frac{-0.5}{C}, 0\right)\right)}{\pi}\\

\mathbf{else}:\\
\;\;\;\;180 \cdot \frac{\tan^{-1} \left(1 + t\_1\right)}{\pi}\\


\end{array}
\end{array}
Derivation
  1. Split input into 3 regimes
  2. if (*.f64 (/.f64 #s(literal 1 binary64) B) (-.f64 (-.f64 C A) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))) < -4.0000000000000002e-22

    1. Initial program 62.0%

      \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
    2. Add Preprocessing
    3. Taylor expanded in B around inf

      \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{C}{B} - \left(1 + \frac{A}{B}\right)\right)}}{\mathsf{PI}\left(\right)} \]
    4. Step-by-step derivation
      1. +-commutativeN/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{C}{B} - \color{blue}{\left(\frac{A}{B} + 1\right)}\right)}{\mathsf{PI}\left(\right)} \]
      2. associate--r+N/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\left(\frac{C}{B} - \frac{A}{B}\right) - 1\right)}}{\mathsf{PI}\left(\right)} \]
      3. div-subN/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\color{blue}{\frac{C - A}{B}} - 1\right)}{\mathsf{PI}\left(\right)} \]
      4. sub-negN/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{C - A}{B} + \left(\mathsf{neg}\left(1\right)\right)\right)}}{\mathsf{PI}\left(\right)} \]
      5. metadata-evalN/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{C - A}{B} + \color{blue}{-1}\right)}{\mathsf{PI}\left(\right)} \]
      6. lower-+.f64N/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{C - A}{B} + -1\right)}}{\mathsf{PI}\left(\right)} \]
      7. lower-/.f64N/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\color{blue}{\frac{C - A}{B}} + -1\right)}{\mathsf{PI}\left(\right)} \]
      8. lower--.f6484.8

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\color{blue}{C - A}}{B} + -1\right)}{\pi} \]
    5. Applied rewrites84.8%

      \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{C - A}{B} + -1\right)}}{\pi} \]

    if -4.0000000000000002e-22 < (*.f64 (/.f64 #s(literal 1 binary64) B) (-.f64 (-.f64 C A) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))) < 2.0000000000000001e-4

    1. Initial program 22.2%

      \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
    2. Add Preprocessing
    3. Taylor expanded in C around inf

      \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(-1 \cdot \frac{A + -1 \cdot A}{B} + \frac{-1}{2} \cdot \frac{B}{C}\right)}}{\mathsf{PI}\left(\right)} \]
    4. Step-by-step derivation
      1. +-commutativeN/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{-1}{2} \cdot \frac{B}{C} + -1 \cdot \frac{A + -1 \cdot A}{B}\right)}}{\mathsf{PI}\left(\right)} \]
      2. associate-*r/N/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\color{blue}{\frac{\frac{-1}{2} \cdot B}{C}} + -1 \cdot \frac{A + -1 \cdot A}{B}\right)}{\mathsf{PI}\left(\right)} \]
      3. *-commutativeN/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\color{blue}{B \cdot \frac{-1}{2}}}{C} + -1 \cdot \frac{A + -1 \cdot A}{B}\right)}{\mathsf{PI}\left(\right)} \]
      4. associate-/l*N/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\color{blue}{B \cdot \frac{\frac{-1}{2}}{C}} + -1 \cdot \frac{A + -1 \cdot A}{B}\right)}{\mathsf{PI}\left(\right)} \]
      5. distribute-rgt1-inN/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(B \cdot \frac{\frac{-1}{2}}{C} + -1 \cdot \frac{\color{blue}{\left(-1 + 1\right) \cdot A}}{B}\right)}{\mathsf{PI}\left(\right)} \]
      6. metadata-evalN/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(B \cdot \frac{\frac{-1}{2}}{C} + -1 \cdot \frac{\color{blue}{0} \cdot A}{B}\right)}{\mathsf{PI}\left(\right)} \]
      7. mul0-lftN/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(B \cdot \frac{\frac{-1}{2}}{C} + -1 \cdot \frac{\color{blue}{0}}{B}\right)}{\mathsf{PI}\left(\right)} \]
      8. div0N/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(B \cdot \frac{\frac{-1}{2}}{C} + -1 \cdot \color{blue}{0}\right)}{\mathsf{PI}\left(\right)} \]
      9. metadata-evalN/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(B \cdot \frac{\frac{-1}{2}}{C} + \color{blue}{0}\right)}{\mathsf{PI}\left(\right)} \]
      10. lower-fma.f64N/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\mathsf{fma}\left(B, \frac{\frac{-1}{2}}{C}, 0\right)\right)}}{\mathsf{PI}\left(\right)} \]
      11. lower-/.f6457.5

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\mathsf{fma}\left(B, \color{blue}{\frac{-0.5}{C}}, 0\right)\right)}{\pi} \]
    5. Applied rewrites57.5%

      \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\mathsf{fma}\left(B, \frac{-0.5}{C}, 0\right)\right)}}{\pi} \]

    if 2.0000000000000001e-4 < (*.f64 (/.f64 #s(literal 1 binary64) B) (-.f64 (-.f64 C A) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64))))))

    1. Initial program 61.0%

      \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
    2. Add Preprocessing
    3. Taylor expanded in B around -inf

      \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\left(1 + \frac{C}{B}\right) - \frac{A}{B}\right)}}{\mathsf{PI}\left(\right)} \]
    4. Step-by-step derivation
      1. associate--l+N/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(1 + \left(\frac{C}{B} - \frac{A}{B}\right)\right)}}{\mathsf{PI}\left(\right)} \]
      2. div-subN/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \color{blue}{\frac{C - A}{B}}\right)}{\mathsf{PI}\left(\right)} \]
      3. lower-+.f64N/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(1 + \frac{C - A}{B}\right)}}{\mathsf{PI}\left(\right)} \]
      4. lower-/.f64N/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \color{blue}{\frac{C - A}{B}}\right)}{\mathsf{PI}\left(\right)} \]
      5. lower--.f6478.9

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \frac{\color{blue}{C - A}}{B}\right)}{\pi} \]
    5. Applied rewrites78.9%

      \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(1 + \frac{C - A}{B}\right)}}{\pi} \]
  3. Recombined 3 regimes into one program.
  4. Add Preprocessing

Alternative 7: 72.7% accurate, 0.6× speedup?

\[\begin{array}{l} \\ \begin{array}{l} t_0 := \frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\\ t_1 := \frac{C - A}{B}\\ \mathbf{if}\;t\_0 \leq -4 \cdot 10^{-22}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(t\_1 + -1\right)}{\pi}\\ \mathbf{elif}\;t\_0 \leq 0.0002:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{B \cdot -0.5}{C}\right)}{\pi}\\ \mathbf{else}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(1 + t\_1\right)}{\pi}\\ \end{array} \end{array} \]
(FPCore (A B C)
 :precision binary64
 (let* ((t_0
         (* (/ 1.0 B) (- (- C A) (sqrt (+ (pow (- A C) 2.0) (pow B 2.0))))))
        (t_1 (/ (- C A) B)))
   (if (<= t_0 -4e-22)
     (* 180.0 (/ (atan (+ t_1 -1.0)) PI))
     (if (<= t_0 0.0002)
       (* 180.0 (/ (atan (/ (* B -0.5) C)) PI))
       (* 180.0 (/ (atan (+ 1.0 t_1)) PI))))))
double code(double A, double B, double C) {
	double t_0 = (1.0 / B) * ((C - A) - sqrt((pow((A - C), 2.0) + pow(B, 2.0))));
	double t_1 = (C - A) / B;
	double tmp;
	if (t_0 <= -4e-22) {
		tmp = 180.0 * (atan((t_1 + -1.0)) / ((double) M_PI));
	} else if (t_0 <= 0.0002) {
		tmp = 180.0 * (atan(((B * -0.5) / C)) / ((double) M_PI));
	} else {
		tmp = 180.0 * (atan((1.0 + t_1)) / ((double) M_PI));
	}
	return tmp;
}
public static double code(double A, double B, double C) {
	double t_0 = (1.0 / B) * ((C - A) - Math.sqrt((Math.pow((A - C), 2.0) + Math.pow(B, 2.0))));
	double t_1 = (C - A) / B;
	double tmp;
	if (t_0 <= -4e-22) {
		tmp = 180.0 * (Math.atan((t_1 + -1.0)) / Math.PI);
	} else if (t_0 <= 0.0002) {
		tmp = 180.0 * (Math.atan(((B * -0.5) / C)) / Math.PI);
	} else {
		tmp = 180.0 * (Math.atan((1.0 + t_1)) / Math.PI);
	}
	return tmp;
}
def code(A, B, C):
	t_0 = (1.0 / B) * ((C - A) - math.sqrt((math.pow((A - C), 2.0) + math.pow(B, 2.0))))
	t_1 = (C - A) / B
	tmp = 0
	if t_0 <= -4e-22:
		tmp = 180.0 * (math.atan((t_1 + -1.0)) / math.pi)
	elif t_0 <= 0.0002:
		tmp = 180.0 * (math.atan(((B * -0.5) / C)) / math.pi)
	else:
		tmp = 180.0 * (math.atan((1.0 + t_1)) / math.pi)
	return tmp
function code(A, B, C)
	t_0 = Float64(Float64(1.0 / B) * Float64(Float64(C - A) - sqrt(Float64((Float64(A - C) ^ 2.0) + (B ^ 2.0)))))
	t_1 = Float64(Float64(C - A) / B)
	tmp = 0.0
	if (t_0 <= -4e-22)
		tmp = Float64(180.0 * Float64(atan(Float64(t_1 + -1.0)) / pi));
	elseif (t_0 <= 0.0002)
		tmp = Float64(180.0 * Float64(atan(Float64(Float64(B * -0.5) / C)) / pi));
	else
		tmp = Float64(180.0 * Float64(atan(Float64(1.0 + t_1)) / pi));
	end
	return tmp
end
function tmp_2 = code(A, B, C)
	t_0 = (1.0 / B) * ((C - A) - sqrt((((A - C) ^ 2.0) + (B ^ 2.0))));
	t_1 = (C - A) / B;
	tmp = 0.0;
	if (t_0 <= -4e-22)
		tmp = 180.0 * (atan((t_1 + -1.0)) / pi);
	elseif (t_0 <= 0.0002)
		tmp = 180.0 * (atan(((B * -0.5) / C)) / pi);
	else
		tmp = 180.0 * (atan((1.0 + t_1)) / pi);
	end
	tmp_2 = tmp;
end
code[A_, B_, C_] := Block[{t$95$0 = N[(N[(1.0 / B), $MachinePrecision] * N[(N[(C - A), $MachinePrecision] - N[Sqrt[N[(N[Power[N[(A - C), $MachinePrecision], 2.0], $MachinePrecision] + N[Power[B, 2.0], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$1 = N[(N[(C - A), $MachinePrecision] / B), $MachinePrecision]}, If[LessEqual[t$95$0, -4e-22], N[(180.0 * N[(N[ArcTan[N[(t$95$1 + -1.0), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision], If[LessEqual[t$95$0, 0.0002], N[(180.0 * N[(N[ArcTan[N[(N[(B * -0.5), $MachinePrecision] / C), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision], N[(180.0 * N[(N[ArcTan[N[(1.0 + t$95$1), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision]]]]]
\begin{array}{l}

\\
\begin{array}{l}
t_0 := \frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\\
t_1 := \frac{C - A}{B}\\
\mathbf{if}\;t\_0 \leq -4 \cdot 10^{-22}:\\
\;\;\;\;180 \cdot \frac{\tan^{-1} \left(t\_1 + -1\right)}{\pi}\\

\mathbf{elif}\;t\_0 \leq 0.0002:\\
\;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{B \cdot -0.5}{C}\right)}{\pi}\\

\mathbf{else}:\\
\;\;\;\;180 \cdot \frac{\tan^{-1} \left(1 + t\_1\right)}{\pi}\\


\end{array}
\end{array}
Derivation
  1. Split input into 3 regimes
  2. if (*.f64 (/.f64 #s(literal 1 binary64) B) (-.f64 (-.f64 C A) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))) < -4.0000000000000002e-22

    1. Initial program 62.0%

      \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
    2. Add Preprocessing
    3. Taylor expanded in B around inf

      \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{C}{B} - \left(1 + \frac{A}{B}\right)\right)}}{\mathsf{PI}\left(\right)} \]
    4. Step-by-step derivation
      1. +-commutativeN/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{C}{B} - \color{blue}{\left(\frac{A}{B} + 1\right)}\right)}{\mathsf{PI}\left(\right)} \]
      2. associate--r+N/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\left(\frac{C}{B} - \frac{A}{B}\right) - 1\right)}}{\mathsf{PI}\left(\right)} \]
      3. div-subN/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\color{blue}{\frac{C - A}{B}} - 1\right)}{\mathsf{PI}\left(\right)} \]
      4. sub-negN/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{C - A}{B} + \left(\mathsf{neg}\left(1\right)\right)\right)}}{\mathsf{PI}\left(\right)} \]
      5. metadata-evalN/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{C - A}{B} + \color{blue}{-1}\right)}{\mathsf{PI}\left(\right)} \]
      6. lower-+.f64N/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{C - A}{B} + -1\right)}}{\mathsf{PI}\left(\right)} \]
      7. lower-/.f64N/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\color{blue}{\frac{C - A}{B}} + -1\right)}{\mathsf{PI}\left(\right)} \]
      8. lower--.f6484.8

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\color{blue}{C - A}}{B} + -1\right)}{\pi} \]
    5. Applied rewrites84.8%

      \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{C - A}{B} + -1\right)}}{\pi} \]

    if -4.0000000000000002e-22 < (*.f64 (/.f64 #s(literal 1 binary64) B) (-.f64 (-.f64 C A) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))) < 2.0000000000000001e-4

    1. Initial program 22.2%

      \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
    2. Add Preprocessing
    3. Step-by-step derivation
      1. lift-sqrt.f64N/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \color{blue}{\sqrt{{\left(A - C\right)}^{2} + {B}^{2}}}\right)\right)}{\mathsf{PI}\left(\right)} \]
      2. lift-+.f64N/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{\color{blue}{{\left(A - C\right)}^{2} + {B}^{2}}}\right)\right)}{\mathsf{PI}\left(\right)} \]
    4. Applied rewrites22.2%

      \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \color{blue}{\mathsf{hypot}\left(C - A, B\right)}\right)\right)}{\pi} \]
    5. Taylor expanded in B around 0

      \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{-1}{2} \cdot \frac{B}{C - A}\right)}}{\mathsf{PI}\left(\right)} \]
    6. Step-by-step derivation
      1. lower-*.f64N/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{-1}{2} \cdot \frac{B}{C - A}\right)}}{\mathsf{PI}\left(\right)} \]
      2. lower-/.f64N/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{-1}{2} \cdot \color{blue}{\frac{B}{C - A}}\right)}{\mathsf{PI}\left(\right)} \]
      3. lower--.f6498.3

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(-0.5 \cdot \frac{B}{\color{blue}{C - A}}\right)}{\pi} \]
    7. Applied rewrites98.3%

      \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(-0.5 \cdot \frac{B}{C - A}\right)}}{\pi} \]
    8. Taylor expanded in C around inf

      \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{-1}{2} \cdot \color{blue}{\frac{B}{C}}\right)}{\mathsf{PI}\left(\right)} \]
    9. Step-by-step derivation
      1. Applied rewrites57.5%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{B \cdot -0.5}{\color{blue}{C}}\right)}{\pi} \]

      if 2.0000000000000001e-4 < (*.f64 (/.f64 #s(literal 1 binary64) B) (-.f64 (-.f64 C A) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64))))))

      1. Initial program 61.0%

        \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
      2. Add Preprocessing
      3. Taylor expanded in B around -inf

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\left(1 + \frac{C}{B}\right) - \frac{A}{B}\right)}}{\mathsf{PI}\left(\right)} \]
      4. Step-by-step derivation
        1. associate--l+N/A

          \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(1 + \left(\frac{C}{B} - \frac{A}{B}\right)\right)}}{\mathsf{PI}\left(\right)} \]
        2. div-subN/A

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \color{blue}{\frac{C - A}{B}}\right)}{\mathsf{PI}\left(\right)} \]
        3. lower-+.f64N/A

          \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(1 + \frac{C - A}{B}\right)}}{\mathsf{PI}\left(\right)} \]
        4. lower-/.f64N/A

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \color{blue}{\frac{C - A}{B}}\right)}{\mathsf{PI}\left(\right)} \]
        5. lower--.f6478.9

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \frac{\color{blue}{C - A}}{B}\right)}{\pi} \]
      5. Applied rewrites78.9%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(1 + \frac{C - A}{B}\right)}}{\pi} \]
    10. Recombined 3 regimes into one program.
    11. Add Preprocessing

    Alternative 8: 67.4% accurate, 0.6× speedup?

    \[\begin{array}{l} \\ \begin{array}{l} t_0 := \frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\\ \mathbf{if}\;t\_0 \leq -4 \cdot 10^{-22}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(-1 - \frac{A}{B}\right)}{\pi}\\ \mathbf{elif}\;t\_0 \leq 0.0002:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{B \cdot -0.5}{C}\right)}{\pi}\\ \mathbf{else}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(1 + \frac{C - A}{B}\right)}{\pi}\\ \end{array} \end{array} \]
    (FPCore (A B C)
     :precision binary64
     (let* ((t_0
             (* (/ 1.0 B) (- (- C A) (sqrt (+ (pow (- A C) 2.0) (pow B 2.0)))))))
       (if (<= t_0 -4e-22)
         (* 180.0 (/ (atan (- -1.0 (/ A B))) PI))
         (if (<= t_0 0.0002)
           (* 180.0 (/ (atan (/ (* B -0.5) C)) PI))
           (* 180.0 (/ (atan (+ 1.0 (/ (- C A) B))) PI))))))
    double code(double A, double B, double C) {
    	double t_0 = (1.0 / B) * ((C - A) - sqrt((pow((A - C), 2.0) + pow(B, 2.0))));
    	double tmp;
    	if (t_0 <= -4e-22) {
    		tmp = 180.0 * (atan((-1.0 - (A / B))) / ((double) M_PI));
    	} else if (t_0 <= 0.0002) {
    		tmp = 180.0 * (atan(((B * -0.5) / C)) / ((double) M_PI));
    	} else {
    		tmp = 180.0 * (atan((1.0 + ((C - A) / B))) / ((double) M_PI));
    	}
    	return tmp;
    }
    
    public static double code(double A, double B, double C) {
    	double t_0 = (1.0 / B) * ((C - A) - Math.sqrt((Math.pow((A - C), 2.0) + Math.pow(B, 2.0))));
    	double tmp;
    	if (t_0 <= -4e-22) {
    		tmp = 180.0 * (Math.atan((-1.0 - (A / B))) / Math.PI);
    	} else if (t_0 <= 0.0002) {
    		tmp = 180.0 * (Math.atan(((B * -0.5) / C)) / Math.PI);
    	} else {
    		tmp = 180.0 * (Math.atan((1.0 + ((C - A) / B))) / Math.PI);
    	}
    	return tmp;
    }
    
    def code(A, B, C):
    	t_0 = (1.0 / B) * ((C - A) - math.sqrt((math.pow((A - C), 2.0) + math.pow(B, 2.0))))
    	tmp = 0
    	if t_0 <= -4e-22:
    		tmp = 180.0 * (math.atan((-1.0 - (A / B))) / math.pi)
    	elif t_0 <= 0.0002:
    		tmp = 180.0 * (math.atan(((B * -0.5) / C)) / math.pi)
    	else:
    		tmp = 180.0 * (math.atan((1.0 + ((C - A) / B))) / math.pi)
    	return tmp
    
    function code(A, B, C)
    	t_0 = Float64(Float64(1.0 / B) * Float64(Float64(C - A) - sqrt(Float64((Float64(A - C) ^ 2.0) + (B ^ 2.0)))))
    	tmp = 0.0
    	if (t_0 <= -4e-22)
    		tmp = Float64(180.0 * Float64(atan(Float64(-1.0 - Float64(A / B))) / pi));
    	elseif (t_0 <= 0.0002)
    		tmp = Float64(180.0 * Float64(atan(Float64(Float64(B * -0.5) / C)) / pi));
    	else
    		tmp = Float64(180.0 * Float64(atan(Float64(1.0 + Float64(Float64(C - A) / B))) / pi));
    	end
    	return tmp
    end
    
    function tmp_2 = code(A, B, C)
    	t_0 = (1.0 / B) * ((C - A) - sqrt((((A - C) ^ 2.0) + (B ^ 2.0))));
    	tmp = 0.0;
    	if (t_0 <= -4e-22)
    		tmp = 180.0 * (atan((-1.0 - (A / B))) / pi);
    	elseif (t_0 <= 0.0002)
    		tmp = 180.0 * (atan(((B * -0.5) / C)) / pi);
    	else
    		tmp = 180.0 * (atan((1.0 + ((C - A) / B))) / pi);
    	end
    	tmp_2 = tmp;
    end
    
    code[A_, B_, C_] := Block[{t$95$0 = N[(N[(1.0 / B), $MachinePrecision] * N[(N[(C - A), $MachinePrecision] - N[Sqrt[N[(N[Power[N[(A - C), $MachinePrecision], 2.0], $MachinePrecision] + N[Power[B, 2.0], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[t$95$0, -4e-22], N[(180.0 * N[(N[ArcTan[N[(-1.0 - N[(A / B), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision], If[LessEqual[t$95$0, 0.0002], N[(180.0 * N[(N[ArcTan[N[(N[(B * -0.5), $MachinePrecision] / C), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision], N[(180.0 * N[(N[ArcTan[N[(1.0 + N[(N[(C - A), $MachinePrecision] / B), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision]]]]
    
    \begin{array}{l}
    
    \\
    \begin{array}{l}
    t_0 := \frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\\
    \mathbf{if}\;t\_0 \leq -4 \cdot 10^{-22}:\\
    \;\;\;\;180 \cdot \frac{\tan^{-1} \left(-1 - \frac{A}{B}\right)}{\pi}\\
    
    \mathbf{elif}\;t\_0 \leq 0.0002:\\
    \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{B \cdot -0.5}{C}\right)}{\pi}\\
    
    \mathbf{else}:\\
    \;\;\;\;180 \cdot \frac{\tan^{-1} \left(1 + \frac{C - A}{B}\right)}{\pi}\\
    
    
    \end{array}
    \end{array}
    
    Derivation
    1. Split input into 3 regimes
    2. if (*.f64 (/.f64 #s(literal 1 binary64) B) (-.f64 (-.f64 C A) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))) < -4.0000000000000002e-22

      1. Initial program 62.0%

        \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
      2. Add Preprocessing
      3. Taylor expanded in C around 0

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(-1 \cdot \frac{A + \sqrt{{A}^{2} + {B}^{2}}}{B}\right)}}{\mathsf{PI}\left(\right)} \]
      4. Step-by-step derivation
        1. mul-1-negN/A

          \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\mathsf{neg}\left(\frac{A + \sqrt{{A}^{2} + {B}^{2}}}{B}\right)\right)}}{\mathsf{PI}\left(\right)} \]
        2. distribute-neg-frac2N/A

          \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{A + \sqrt{{A}^{2} + {B}^{2}}}{\mathsf{neg}\left(B\right)}\right)}}{\mathsf{PI}\left(\right)} \]
        3. mul-1-negN/A

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{A + \sqrt{{A}^{2} + {B}^{2}}}{\color{blue}{-1 \cdot B}}\right)}{\mathsf{PI}\left(\right)} \]
        4. lower-/.f64N/A

          \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{A + \sqrt{{A}^{2} + {B}^{2}}}{-1 \cdot B}\right)}}{\mathsf{PI}\left(\right)} \]
        5. lower-+.f64N/A

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\color{blue}{A + \sqrt{{A}^{2} + {B}^{2}}}}{-1 \cdot B}\right)}{\mathsf{PI}\left(\right)} \]
        6. lower-sqrt.f64N/A

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{A + \color{blue}{\sqrt{{A}^{2} + {B}^{2}}}}{-1 \cdot B}\right)}{\mathsf{PI}\left(\right)} \]
        7. unpow2N/A

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{A + \sqrt{\color{blue}{A \cdot A} + {B}^{2}}}{-1 \cdot B}\right)}{\mathsf{PI}\left(\right)} \]
        8. lower-fma.f64N/A

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{A + \sqrt{\color{blue}{\mathsf{fma}\left(A, A, {B}^{2}\right)}}}{-1 \cdot B}\right)}{\mathsf{PI}\left(\right)} \]
        9. unpow2N/A

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{A + \sqrt{\mathsf{fma}\left(A, A, \color{blue}{B \cdot B}\right)}}{-1 \cdot B}\right)}{\mathsf{PI}\left(\right)} \]
        10. lower-*.f64N/A

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{A + \sqrt{\mathsf{fma}\left(A, A, \color{blue}{B \cdot B}\right)}}{-1 \cdot B}\right)}{\mathsf{PI}\left(\right)} \]
        11. mul-1-negN/A

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{A + \sqrt{\mathsf{fma}\left(A, A, B \cdot B\right)}}{\color{blue}{\mathsf{neg}\left(B\right)}}\right)}{\mathsf{PI}\left(\right)} \]
        12. lower-neg.f6449.2

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{A + \sqrt{\mathsf{fma}\left(A, A, B \cdot B\right)}}{\color{blue}{-B}}\right)}{\pi} \]
      5. Applied rewrites49.2%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{A + \sqrt{\mathsf{fma}\left(A, A, B \cdot B\right)}}{-B}\right)}}{\pi} \]
      6. Step-by-step derivation
        1. Applied rewrites76.5%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{A + \mathsf{hypot}\left(B, A\right)}{-B}\right)}{\pi} \]
        2. Taylor expanded in A around 0

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(-1 \cdot \frac{A}{B} - \color{blue}{1}\right)}{\mathsf{PI}\left(\right)} \]
        3. Step-by-step derivation
          1. Applied rewrites69.3%

            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(-1 - \color{blue}{\frac{A}{B}}\right)}{\pi} \]

          if -4.0000000000000002e-22 < (*.f64 (/.f64 #s(literal 1 binary64) B) (-.f64 (-.f64 C A) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))) < 2.0000000000000001e-4

          1. Initial program 22.2%

            \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
          2. Add Preprocessing
          3. Step-by-step derivation
            1. lift-sqrt.f64N/A

              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \color{blue}{\sqrt{{\left(A - C\right)}^{2} + {B}^{2}}}\right)\right)}{\mathsf{PI}\left(\right)} \]
            2. lift-+.f64N/A

              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{\color{blue}{{\left(A - C\right)}^{2} + {B}^{2}}}\right)\right)}{\mathsf{PI}\left(\right)} \]
          4. Applied rewrites22.2%

            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \color{blue}{\mathsf{hypot}\left(C - A, B\right)}\right)\right)}{\pi} \]
          5. Taylor expanded in B around 0

            \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{-1}{2} \cdot \frac{B}{C - A}\right)}}{\mathsf{PI}\left(\right)} \]
          6. Step-by-step derivation
            1. lower-*.f64N/A

              \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{-1}{2} \cdot \frac{B}{C - A}\right)}}{\mathsf{PI}\left(\right)} \]
            2. lower-/.f64N/A

              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{-1}{2} \cdot \color{blue}{\frac{B}{C - A}}\right)}{\mathsf{PI}\left(\right)} \]
            3. lower--.f6498.3

              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(-0.5 \cdot \frac{B}{\color{blue}{C - A}}\right)}{\pi} \]
          7. Applied rewrites98.3%

            \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(-0.5 \cdot \frac{B}{C - A}\right)}}{\pi} \]
          8. Taylor expanded in C around inf

            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{-1}{2} \cdot \color{blue}{\frac{B}{C}}\right)}{\mathsf{PI}\left(\right)} \]
          9. Step-by-step derivation
            1. Applied rewrites57.5%

              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{B \cdot -0.5}{\color{blue}{C}}\right)}{\pi} \]

            if 2.0000000000000001e-4 < (*.f64 (/.f64 #s(literal 1 binary64) B) (-.f64 (-.f64 C A) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64))))))

            1. Initial program 61.0%

              \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
            2. Add Preprocessing
            3. Taylor expanded in B around -inf

              \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\left(1 + \frac{C}{B}\right) - \frac{A}{B}\right)}}{\mathsf{PI}\left(\right)} \]
            4. Step-by-step derivation
              1. associate--l+N/A

                \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(1 + \left(\frac{C}{B} - \frac{A}{B}\right)\right)}}{\mathsf{PI}\left(\right)} \]
              2. div-subN/A

                \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \color{blue}{\frac{C - A}{B}}\right)}{\mathsf{PI}\left(\right)} \]
              3. lower-+.f64N/A

                \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(1 + \frac{C - A}{B}\right)}}{\mathsf{PI}\left(\right)} \]
              4. lower-/.f64N/A

                \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \color{blue}{\frac{C - A}{B}}\right)}{\mathsf{PI}\left(\right)} \]
              5. lower--.f6478.9

                \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \frac{\color{blue}{C - A}}{B}\right)}{\pi} \]
            5. Applied rewrites78.9%

              \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(1 + \frac{C - A}{B}\right)}}{\pi} \]
          10. Recombined 3 regimes into one program.
          11. Add Preprocessing

          Alternative 9: 62.2% accurate, 0.6× speedup?

          \[\begin{array}{l} \\ \begin{array}{l} t_0 := \frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\\ \mathbf{if}\;t\_0 \leq -4 \cdot 10^{-22}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(-1 - \frac{A}{B}\right)}{\pi}\\ \mathbf{elif}\;t\_0 \leq 0.0002:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{B \cdot -0.5}{C}\right)}{\pi}\\ \mathbf{else}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(1 + \frac{C}{B}\right)}{\pi}\\ \end{array} \end{array} \]
          (FPCore (A B C)
           :precision binary64
           (let* ((t_0
                   (* (/ 1.0 B) (- (- C A) (sqrt (+ (pow (- A C) 2.0) (pow B 2.0)))))))
             (if (<= t_0 -4e-22)
               (* 180.0 (/ (atan (- -1.0 (/ A B))) PI))
               (if (<= t_0 0.0002)
                 (* 180.0 (/ (atan (/ (* B -0.5) C)) PI))
                 (* 180.0 (/ (atan (+ 1.0 (/ C B))) PI))))))
          double code(double A, double B, double C) {
          	double t_0 = (1.0 / B) * ((C - A) - sqrt((pow((A - C), 2.0) + pow(B, 2.0))));
          	double tmp;
          	if (t_0 <= -4e-22) {
          		tmp = 180.0 * (atan((-1.0 - (A / B))) / ((double) M_PI));
          	} else if (t_0 <= 0.0002) {
          		tmp = 180.0 * (atan(((B * -0.5) / C)) / ((double) M_PI));
          	} else {
          		tmp = 180.0 * (atan((1.0 + (C / B))) / ((double) M_PI));
          	}
          	return tmp;
          }
          
          public static double code(double A, double B, double C) {
          	double t_0 = (1.0 / B) * ((C - A) - Math.sqrt((Math.pow((A - C), 2.0) + Math.pow(B, 2.0))));
          	double tmp;
          	if (t_0 <= -4e-22) {
          		tmp = 180.0 * (Math.atan((-1.0 - (A / B))) / Math.PI);
          	} else if (t_0 <= 0.0002) {
          		tmp = 180.0 * (Math.atan(((B * -0.5) / C)) / Math.PI);
          	} else {
          		tmp = 180.0 * (Math.atan((1.0 + (C / B))) / Math.PI);
          	}
          	return tmp;
          }
          
          def code(A, B, C):
          	t_0 = (1.0 / B) * ((C - A) - math.sqrt((math.pow((A - C), 2.0) + math.pow(B, 2.0))))
          	tmp = 0
          	if t_0 <= -4e-22:
          		tmp = 180.0 * (math.atan((-1.0 - (A / B))) / math.pi)
          	elif t_0 <= 0.0002:
          		tmp = 180.0 * (math.atan(((B * -0.5) / C)) / math.pi)
          	else:
          		tmp = 180.0 * (math.atan((1.0 + (C / B))) / math.pi)
          	return tmp
          
          function code(A, B, C)
          	t_0 = Float64(Float64(1.0 / B) * Float64(Float64(C - A) - sqrt(Float64((Float64(A - C) ^ 2.0) + (B ^ 2.0)))))
          	tmp = 0.0
          	if (t_0 <= -4e-22)
          		tmp = Float64(180.0 * Float64(atan(Float64(-1.0 - Float64(A / B))) / pi));
          	elseif (t_0 <= 0.0002)
          		tmp = Float64(180.0 * Float64(atan(Float64(Float64(B * -0.5) / C)) / pi));
          	else
          		tmp = Float64(180.0 * Float64(atan(Float64(1.0 + Float64(C / B))) / pi));
          	end
          	return tmp
          end
          
          function tmp_2 = code(A, B, C)
          	t_0 = (1.0 / B) * ((C - A) - sqrt((((A - C) ^ 2.0) + (B ^ 2.0))));
          	tmp = 0.0;
          	if (t_0 <= -4e-22)
          		tmp = 180.0 * (atan((-1.0 - (A / B))) / pi);
          	elseif (t_0 <= 0.0002)
          		tmp = 180.0 * (atan(((B * -0.5) / C)) / pi);
          	else
          		tmp = 180.0 * (atan((1.0 + (C / B))) / pi);
          	end
          	tmp_2 = tmp;
          end
          
          code[A_, B_, C_] := Block[{t$95$0 = N[(N[(1.0 / B), $MachinePrecision] * N[(N[(C - A), $MachinePrecision] - N[Sqrt[N[(N[Power[N[(A - C), $MachinePrecision], 2.0], $MachinePrecision] + N[Power[B, 2.0], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[t$95$0, -4e-22], N[(180.0 * N[(N[ArcTan[N[(-1.0 - N[(A / B), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision], If[LessEqual[t$95$0, 0.0002], N[(180.0 * N[(N[ArcTan[N[(N[(B * -0.5), $MachinePrecision] / C), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision], N[(180.0 * N[(N[ArcTan[N[(1.0 + N[(C / B), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision]]]]
          
          \begin{array}{l}
          
          \\
          \begin{array}{l}
          t_0 := \frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\\
          \mathbf{if}\;t\_0 \leq -4 \cdot 10^{-22}:\\
          \;\;\;\;180 \cdot \frac{\tan^{-1} \left(-1 - \frac{A}{B}\right)}{\pi}\\
          
          \mathbf{elif}\;t\_0 \leq 0.0002:\\
          \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{B \cdot -0.5}{C}\right)}{\pi}\\
          
          \mathbf{else}:\\
          \;\;\;\;180 \cdot \frac{\tan^{-1} \left(1 + \frac{C}{B}\right)}{\pi}\\
          
          
          \end{array}
          \end{array}
          
          Derivation
          1. Split input into 3 regimes
          2. if (*.f64 (/.f64 #s(literal 1 binary64) B) (-.f64 (-.f64 C A) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))) < -4.0000000000000002e-22

            1. Initial program 62.0%

              \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
            2. Add Preprocessing
            3. Taylor expanded in C around 0

              \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(-1 \cdot \frac{A + \sqrt{{A}^{2} + {B}^{2}}}{B}\right)}}{\mathsf{PI}\left(\right)} \]
            4. Step-by-step derivation
              1. mul-1-negN/A

                \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\mathsf{neg}\left(\frac{A + \sqrt{{A}^{2} + {B}^{2}}}{B}\right)\right)}}{\mathsf{PI}\left(\right)} \]
              2. distribute-neg-frac2N/A

                \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{A + \sqrt{{A}^{2} + {B}^{2}}}{\mathsf{neg}\left(B\right)}\right)}}{\mathsf{PI}\left(\right)} \]
              3. mul-1-negN/A

                \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{A + \sqrt{{A}^{2} + {B}^{2}}}{\color{blue}{-1 \cdot B}}\right)}{\mathsf{PI}\left(\right)} \]
              4. lower-/.f64N/A

                \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{A + \sqrt{{A}^{2} + {B}^{2}}}{-1 \cdot B}\right)}}{\mathsf{PI}\left(\right)} \]
              5. lower-+.f64N/A

                \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\color{blue}{A + \sqrt{{A}^{2} + {B}^{2}}}}{-1 \cdot B}\right)}{\mathsf{PI}\left(\right)} \]
              6. lower-sqrt.f64N/A

                \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{A + \color{blue}{\sqrt{{A}^{2} + {B}^{2}}}}{-1 \cdot B}\right)}{\mathsf{PI}\left(\right)} \]
              7. unpow2N/A

                \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{A + \sqrt{\color{blue}{A \cdot A} + {B}^{2}}}{-1 \cdot B}\right)}{\mathsf{PI}\left(\right)} \]
              8. lower-fma.f64N/A

                \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{A + \sqrt{\color{blue}{\mathsf{fma}\left(A, A, {B}^{2}\right)}}}{-1 \cdot B}\right)}{\mathsf{PI}\left(\right)} \]
              9. unpow2N/A

                \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{A + \sqrt{\mathsf{fma}\left(A, A, \color{blue}{B \cdot B}\right)}}{-1 \cdot B}\right)}{\mathsf{PI}\left(\right)} \]
              10. lower-*.f64N/A

                \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{A + \sqrt{\mathsf{fma}\left(A, A, \color{blue}{B \cdot B}\right)}}{-1 \cdot B}\right)}{\mathsf{PI}\left(\right)} \]
              11. mul-1-negN/A

                \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{A + \sqrt{\mathsf{fma}\left(A, A, B \cdot B\right)}}{\color{blue}{\mathsf{neg}\left(B\right)}}\right)}{\mathsf{PI}\left(\right)} \]
              12. lower-neg.f6449.2

                \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{A + \sqrt{\mathsf{fma}\left(A, A, B \cdot B\right)}}{\color{blue}{-B}}\right)}{\pi} \]
            5. Applied rewrites49.2%

              \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{A + \sqrt{\mathsf{fma}\left(A, A, B \cdot B\right)}}{-B}\right)}}{\pi} \]
            6. Step-by-step derivation
              1. Applied rewrites76.5%

                \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{A + \mathsf{hypot}\left(B, A\right)}{-B}\right)}{\pi} \]
              2. Taylor expanded in A around 0

                \[\leadsto 180 \cdot \frac{\tan^{-1} \left(-1 \cdot \frac{A}{B} - \color{blue}{1}\right)}{\mathsf{PI}\left(\right)} \]
              3. Step-by-step derivation
                1. Applied rewrites69.3%

                  \[\leadsto 180 \cdot \frac{\tan^{-1} \left(-1 - \color{blue}{\frac{A}{B}}\right)}{\pi} \]

                if -4.0000000000000002e-22 < (*.f64 (/.f64 #s(literal 1 binary64) B) (-.f64 (-.f64 C A) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))) < 2.0000000000000001e-4

                1. Initial program 22.2%

                  \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
                2. Add Preprocessing
                3. Step-by-step derivation
                  1. lift-sqrt.f64N/A

                    \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \color{blue}{\sqrt{{\left(A - C\right)}^{2} + {B}^{2}}}\right)\right)}{\mathsf{PI}\left(\right)} \]
                  2. lift-+.f64N/A

                    \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{\color{blue}{{\left(A - C\right)}^{2} + {B}^{2}}}\right)\right)}{\mathsf{PI}\left(\right)} \]
                4. Applied rewrites22.2%

                  \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \color{blue}{\mathsf{hypot}\left(C - A, B\right)}\right)\right)}{\pi} \]
                5. Taylor expanded in B around 0

                  \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{-1}{2} \cdot \frac{B}{C - A}\right)}}{\mathsf{PI}\left(\right)} \]
                6. Step-by-step derivation
                  1. lower-*.f64N/A

                    \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{-1}{2} \cdot \frac{B}{C - A}\right)}}{\mathsf{PI}\left(\right)} \]
                  2. lower-/.f64N/A

                    \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{-1}{2} \cdot \color{blue}{\frac{B}{C - A}}\right)}{\mathsf{PI}\left(\right)} \]
                  3. lower--.f6498.3

                    \[\leadsto 180 \cdot \frac{\tan^{-1} \left(-0.5 \cdot \frac{B}{\color{blue}{C - A}}\right)}{\pi} \]
                7. Applied rewrites98.3%

                  \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(-0.5 \cdot \frac{B}{C - A}\right)}}{\pi} \]
                8. Taylor expanded in C around inf

                  \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{-1}{2} \cdot \color{blue}{\frac{B}{C}}\right)}{\mathsf{PI}\left(\right)} \]
                9. Step-by-step derivation
                  1. Applied rewrites57.5%

                    \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{B \cdot -0.5}{\color{blue}{C}}\right)}{\pi} \]

                  if 2.0000000000000001e-4 < (*.f64 (/.f64 #s(literal 1 binary64) B) (-.f64 (-.f64 C A) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64))))))

                  1. Initial program 61.0%

                    \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
                  2. Add Preprocessing
                  3. Taylor expanded in B around -inf

                    \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\left(1 + \frac{C}{B}\right) - \frac{A}{B}\right)}}{\mathsf{PI}\left(\right)} \]
                  4. Step-by-step derivation
                    1. associate--l+N/A

                      \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(1 + \left(\frac{C}{B} - \frac{A}{B}\right)\right)}}{\mathsf{PI}\left(\right)} \]
                    2. div-subN/A

                      \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \color{blue}{\frac{C - A}{B}}\right)}{\mathsf{PI}\left(\right)} \]
                    3. lower-+.f64N/A

                      \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(1 + \frac{C - A}{B}\right)}}{\mathsf{PI}\left(\right)} \]
                    4. lower-/.f64N/A

                      \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \color{blue}{\frac{C - A}{B}}\right)}{\mathsf{PI}\left(\right)} \]
                    5. lower--.f6478.9

                      \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \frac{\color{blue}{C - A}}{B}\right)}{\pi} \]
                  5. Applied rewrites78.9%

                    \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(1 + \frac{C - A}{B}\right)}}{\pi} \]
                  6. Taylor expanded in C around inf

                    \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \frac{C}{\color{blue}{B}}\right)}{\mathsf{PI}\left(\right)} \]
                  7. Step-by-step derivation
                    1. Applied rewrites63.7%

                      \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \frac{C}{\color{blue}{B}}\right)}{\pi} \]
                  8. Recombined 3 regimes into one program.
                  9. Add Preprocessing

                  Alternative 10: 57.2% accurate, 0.6× speedup?

                  \[\begin{array}{l} \\ \begin{array}{l} t_0 := \frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\\ \mathbf{if}\;t\_0 \leq -4 \cdot 10^{-22}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(-1 - \frac{A}{B}\right)}{\pi}\\ \mathbf{elif}\;t\_0 \leq 0.0002:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} 0}{\pi}\\ \mathbf{else}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(1 + \frac{C}{B}\right)}{\pi}\\ \end{array} \end{array} \]
                  (FPCore (A B C)
                   :precision binary64
                   (let* ((t_0
                           (* (/ 1.0 B) (- (- C A) (sqrt (+ (pow (- A C) 2.0) (pow B 2.0)))))))
                     (if (<= t_0 -4e-22)
                       (* 180.0 (/ (atan (- -1.0 (/ A B))) PI))
                       (if (<= t_0 0.0002)
                         (* 180.0 (/ (atan 0.0) PI))
                         (* 180.0 (/ (atan (+ 1.0 (/ C B))) PI))))))
                  double code(double A, double B, double C) {
                  	double t_0 = (1.0 / B) * ((C - A) - sqrt((pow((A - C), 2.0) + pow(B, 2.0))));
                  	double tmp;
                  	if (t_0 <= -4e-22) {
                  		tmp = 180.0 * (atan((-1.0 - (A / B))) / ((double) M_PI));
                  	} else if (t_0 <= 0.0002) {
                  		tmp = 180.0 * (atan(0.0) / ((double) M_PI));
                  	} else {
                  		tmp = 180.0 * (atan((1.0 + (C / B))) / ((double) M_PI));
                  	}
                  	return tmp;
                  }
                  
                  public static double code(double A, double B, double C) {
                  	double t_0 = (1.0 / B) * ((C - A) - Math.sqrt((Math.pow((A - C), 2.0) + Math.pow(B, 2.0))));
                  	double tmp;
                  	if (t_0 <= -4e-22) {
                  		tmp = 180.0 * (Math.atan((-1.0 - (A / B))) / Math.PI);
                  	} else if (t_0 <= 0.0002) {
                  		tmp = 180.0 * (Math.atan(0.0) / Math.PI);
                  	} else {
                  		tmp = 180.0 * (Math.atan((1.0 + (C / B))) / Math.PI);
                  	}
                  	return tmp;
                  }
                  
                  def code(A, B, C):
                  	t_0 = (1.0 / B) * ((C - A) - math.sqrt((math.pow((A - C), 2.0) + math.pow(B, 2.0))))
                  	tmp = 0
                  	if t_0 <= -4e-22:
                  		tmp = 180.0 * (math.atan((-1.0 - (A / B))) / math.pi)
                  	elif t_0 <= 0.0002:
                  		tmp = 180.0 * (math.atan(0.0) / math.pi)
                  	else:
                  		tmp = 180.0 * (math.atan((1.0 + (C / B))) / math.pi)
                  	return tmp
                  
                  function code(A, B, C)
                  	t_0 = Float64(Float64(1.0 / B) * Float64(Float64(C - A) - sqrt(Float64((Float64(A - C) ^ 2.0) + (B ^ 2.0)))))
                  	tmp = 0.0
                  	if (t_0 <= -4e-22)
                  		tmp = Float64(180.0 * Float64(atan(Float64(-1.0 - Float64(A / B))) / pi));
                  	elseif (t_0 <= 0.0002)
                  		tmp = Float64(180.0 * Float64(atan(0.0) / pi));
                  	else
                  		tmp = Float64(180.0 * Float64(atan(Float64(1.0 + Float64(C / B))) / pi));
                  	end
                  	return tmp
                  end
                  
                  function tmp_2 = code(A, B, C)
                  	t_0 = (1.0 / B) * ((C - A) - sqrt((((A - C) ^ 2.0) + (B ^ 2.0))));
                  	tmp = 0.0;
                  	if (t_0 <= -4e-22)
                  		tmp = 180.0 * (atan((-1.0 - (A / B))) / pi);
                  	elseif (t_0 <= 0.0002)
                  		tmp = 180.0 * (atan(0.0) / pi);
                  	else
                  		tmp = 180.0 * (atan((1.0 + (C / B))) / pi);
                  	end
                  	tmp_2 = tmp;
                  end
                  
                  code[A_, B_, C_] := Block[{t$95$0 = N[(N[(1.0 / B), $MachinePrecision] * N[(N[(C - A), $MachinePrecision] - N[Sqrt[N[(N[Power[N[(A - C), $MachinePrecision], 2.0], $MachinePrecision] + N[Power[B, 2.0], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[t$95$0, -4e-22], N[(180.0 * N[(N[ArcTan[N[(-1.0 - N[(A / B), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision], If[LessEqual[t$95$0, 0.0002], N[(180.0 * N[(N[ArcTan[0.0], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision], N[(180.0 * N[(N[ArcTan[N[(1.0 + N[(C / B), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision]]]]
                  
                  \begin{array}{l}
                  
                  \\
                  \begin{array}{l}
                  t_0 := \frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\\
                  \mathbf{if}\;t\_0 \leq -4 \cdot 10^{-22}:\\
                  \;\;\;\;180 \cdot \frac{\tan^{-1} \left(-1 - \frac{A}{B}\right)}{\pi}\\
                  
                  \mathbf{elif}\;t\_0 \leq 0.0002:\\
                  \;\;\;\;180 \cdot \frac{\tan^{-1} 0}{\pi}\\
                  
                  \mathbf{else}:\\
                  \;\;\;\;180 \cdot \frac{\tan^{-1} \left(1 + \frac{C}{B}\right)}{\pi}\\
                  
                  
                  \end{array}
                  \end{array}
                  
                  Derivation
                  1. Split input into 3 regimes
                  2. if (*.f64 (/.f64 #s(literal 1 binary64) B) (-.f64 (-.f64 C A) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))) < -4.0000000000000002e-22

                    1. Initial program 62.0%

                      \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
                    2. Add Preprocessing
                    3. Taylor expanded in C around 0

                      \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(-1 \cdot \frac{A + \sqrt{{A}^{2} + {B}^{2}}}{B}\right)}}{\mathsf{PI}\left(\right)} \]
                    4. Step-by-step derivation
                      1. mul-1-negN/A

                        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\mathsf{neg}\left(\frac{A + \sqrt{{A}^{2} + {B}^{2}}}{B}\right)\right)}}{\mathsf{PI}\left(\right)} \]
                      2. distribute-neg-frac2N/A

                        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{A + \sqrt{{A}^{2} + {B}^{2}}}{\mathsf{neg}\left(B\right)}\right)}}{\mathsf{PI}\left(\right)} \]
                      3. mul-1-negN/A

                        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{A + \sqrt{{A}^{2} + {B}^{2}}}{\color{blue}{-1 \cdot B}}\right)}{\mathsf{PI}\left(\right)} \]
                      4. lower-/.f64N/A

                        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{A + \sqrt{{A}^{2} + {B}^{2}}}{-1 \cdot B}\right)}}{\mathsf{PI}\left(\right)} \]
                      5. lower-+.f64N/A

                        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\color{blue}{A + \sqrt{{A}^{2} + {B}^{2}}}}{-1 \cdot B}\right)}{\mathsf{PI}\left(\right)} \]
                      6. lower-sqrt.f64N/A

                        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{A + \color{blue}{\sqrt{{A}^{2} + {B}^{2}}}}{-1 \cdot B}\right)}{\mathsf{PI}\left(\right)} \]
                      7. unpow2N/A

                        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{A + \sqrt{\color{blue}{A \cdot A} + {B}^{2}}}{-1 \cdot B}\right)}{\mathsf{PI}\left(\right)} \]
                      8. lower-fma.f64N/A

                        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{A + \sqrt{\color{blue}{\mathsf{fma}\left(A, A, {B}^{2}\right)}}}{-1 \cdot B}\right)}{\mathsf{PI}\left(\right)} \]
                      9. unpow2N/A

                        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{A + \sqrt{\mathsf{fma}\left(A, A, \color{blue}{B \cdot B}\right)}}{-1 \cdot B}\right)}{\mathsf{PI}\left(\right)} \]
                      10. lower-*.f64N/A

                        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{A + \sqrt{\mathsf{fma}\left(A, A, \color{blue}{B \cdot B}\right)}}{-1 \cdot B}\right)}{\mathsf{PI}\left(\right)} \]
                      11. mul-1-negN/A

                        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{A + \sqrt{\mathsf{fma}\left(A, A, B \cdot B\right)}}{\color{blue}{\mathsf{neg}\left(B\right)}}\right)}{\mathsf{PI}\left(\right)} \]
                      12. lower-neg.f6449.2

                        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{A + \sqrt{\mathsf{fma}\left(A, A, B \cdot B\right)}}{\color{blue}{-B}}\right)}{\pi} \]
                    5. Applied rewrites49.2%

                      \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{A + \sqrt{\mathsf{fma}\left(A, A, B \cdot B\right)}}{-B}\right)}}{\pi} \]
                    6. Step-by-step derivation
                      1. Applied rewrites76.5%

                        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{A + \mathsf{hypot}\left(B, A\right)}{-B}\right)}{\pi} \]
                      2. Taylor expanded in A around 0

                        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(-1 \cdot \frac{A}{B} - \color{blue}{1}\right)}{\mathsf{PI}\left(\right)} \]
                      3. Step-by-step derivation
                        1. Applied rewrites69.3%

                          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(-1 - \color{blue}{\frac{A}{B}}\right)}{\pi} \]

                        if -4.0000000000000002e-22 < (*.f64 (/.f64 #s(literal 1 binary64) B) (-.f64 (-.f64 C A) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))) < 2.0000000000000001e-4

                        1. Initial program 22.2%

                          \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
                        2. Add Preprocessing
                        3. Taylor expanded in C around inf

                          \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(-1 \cdot \frac{A + -1 \cdot A}{B}\right)}}{\mathsf{PI}\left(\right)} \]
                        4. Step-by-step derivation
                          1. distribute-rgt1-inN/A

                            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(-1 \cdot \frac{\color{blue}{\left(-1 + 1\right) \cdot A}}{B}\right)}{\mathsf{PI}\left(\right)} \]
                          2. metadata-evalN/A

                            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(-1 \cdot \frac{\color{blue}{0} \cdot A}{B}\right)}{\mathsf{PI}\left(\right)} \]
                          3. mul0-lftN/A

                            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(-1 \cdot \frac{\color{blue}{0}}{B}\right)}{\mathsf{PI}\left(\right)} \]
                          4. div0N/A

                            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(-1 \cdot \color{blue}{0}\right)}{\mathsf{PI}\left(\right)} \]
                          5. metadata-eval20.8

                            \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{0}}{\pi} \]
                        5. Applied rewrites20.8%

                          \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{0}}{\pi} \]

                        if 2.0000000000000001e-4 < (*.f64 (/.f64 #s(literal 1 binary64) B) (-.f64 (-.f64 C A) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64))))))

                        1. Initial program 61.0%

                          \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
                        2. Add Preprocessing
                        3. Taylor expanded in B around -inf

                          \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\left(1 + \frac{C}{B}\right) - \frac{A}{B}\right)}}{\mathsf{PI}\left(\right)} \]
                        4. Step-by-step derivation
                          1. associate--l+N/A

                            \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(1 + \left(\frac{C}{B} - \frac{A}{B}\right)\right)}}{\mathsf{PI}\left(\right)} \]
                          2. div-subN/A

                            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \color{blue}{\frac{C - A}{B}}\right)}{\mathsf{PI}\left(\right)} \]
                          3. lower-+.f64N/A

                            \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(1 + \frac{C - A}{B}\right)}}{\mathsf{PI}\left(\right)} \]
                          4. lower-/.f64N/A

                            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \color{blue}{\frac{C - A}{B}}\right)}{\mathsf{PI}\left(\right)} \]
                          5. lower--.f6478.9

                            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \frac{\color{blue}{C - A}}{B}\right)}{\pi} \]
                        5. Applied rewrites78.9%

                          \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(1 + \frac{C - A}{B}\right)}}{\pi} \]
                        6. Taylor expanded in C around inf

                          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \frac{C}{\color{blue}{B}}\right)}{\mathsf{PI}\left(\right)} \]
                        7. Step-by-step derivation
                          1. Applied rewrites63.7%

                            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \frac{C}{\color{blue}{B}}\right)}{\pi} \]
                        8. Recombined 3 regimes into one program.
                        9. Add Preprocessing

                        Alternative 11: 57.4% accurate, 0.6× speedup?

                        \[\begin{array}{l} \\ \begin{array}{l} t_0 := \frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\\ \mathbf{if}\;t\_0 \leq -4 \cdot 10^{-22}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(-1 - \frac{A}{B}\right)}{\pi}\\ \mathbf{elif}\;t\_0 \leq 0:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} 0}{\pi}\\ \mathbf{else}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(1 - \frac{A}{B}\right)}{\pi}\\ \end{array} \end{array} \]
                        (FPCore (A B C)
                         :precision binary64
                         (let* ((t_0
                                 (* (/ 1.0 B) (- (- C A) (sqrt (+ (pow (- A C) 2.0) (pow B 2.0)))))))
                           (if (<= t_0 -4e-22)
                             (* 180.0 (/ (atan (- -1.0 (/ A B))) PI))
                             (if (<= t_0 0.0)
                               (* 180.0 (/ (atan 0.0) PI))
                               (* 180.0 (/ (atan (- 1.0 (/ A B))) PI))))))
                        double code(double A, double B, double C) {
                        	double t_0 = (1.0 / B) * ((C - A) - sqrt((pow((A - C), 2.0) + pow(B, 2.0))));
                        	double tmp;
                        	if (t_0 <= -4e-22) {
                        		tmp = 180.0 * (atan((-1.0 - (A / B))) / ((double) M_PI));
                        	} else if (t_0 <= 0.0) {
                        		tmp = 180.0 * (atan(0.0) / ((double) M_PI));
                        	} else {
                        		tmp = 180.0 * (atan((1.0 - (A / B))) / ((double) M_PI));
                        	}
                        	return tmp;
                        }
                        
                        public static double code(double A, double B, double C) {
                        	double t_0 = (1.0 / B) * ((C - A) - Math.sqrt((Math.pow((A - C), 2.0) + Math.pow(B, 2.0))));
                        	double tmp;
                        	if (t_0 <= -4e-22) {
                        		tmp = 180.0 * (Math.atan((-1.0 - (A / B))) / Math.PI);
                        	} else if (t_0 <= 0.0) {
                        		tmp = 180.0 * (Math.atan(0.0) / Math.PI);
                        	} else {
                        		tmp = 180.0 * (Math.atan((1.0 - (A / B))) / Math.PI);
                        	}
                        	return tmp;
                        }
                        
                        def code(A, B, C):
                        	t_0 = (1.0 / B) * ((C - A) - math.sqrt((math.pow((A - C), 2.0) + math.pow(B, 2.0))))
                        	tmp = 0
                        	if t_0 <= -4e-22:
                        		tmp = 180.0 * (math.atan((-1.0 - (A / B))) / math.pi)
                        	elif t_0 <= 0.0:
                        		tmp = 180.0 * (math.atan(0.0) / math.pi)
                        	else:
                        		tmp = 180.0 * (math.atan((1.0 - (A / B))) / math.pi)
                        	return tmp
                        
                        function code(A, B, C)
                        	t_0 = Float64(Float64(1.0 / B) * Float64(Float64(C - A) - sqrt(Float64((Float64(A - C) ^ 2.0) + (B ^ 2.0)))))
                        	tmp = 0.0
                        	if (t_0 <= -4e-22)
                        		tmp = Float64(180.0 * Float64(atan(Float64(-1.0 - Float64(A / B))) / pi));
                        	elseif (t_0 <= 0.0)
                        		tmp = Float64(180.0 * Float64(atan(0.0) / pi));
                        	else
                        		tmp = Float64(180.0 * Float64(atan(Float64(1.0 - Float64(A / B))) / pi));
                        	end
                        	return tmp
                        end
                        
                        function tmp_2 = code(A, B, C)
                        	t_0 = (1.0 / B) * ((C - A) - sqrt((((A - C) ^ 2.0) + (B ^ 2.0))));
                        	tmp = 0.0;
                        	if (t_0 <= -4e-22)
                        		tmp = 180.0 * (atan((-1.0 - (A / B))) / pi);
                        	elseif (t_0 <= 0.0)
                        		tmp = 180.0 * (atan(0.0) / pi);
                        	else
                        		tmp = 180.0 * (atan((1.0 - (A / B))) / pi);
                        	end
                        	tmp_2 = tmp;
                        end
                        
                        code[A_, B_, C_] := Block[{t$95$0 = N[(N[(1.0 / B), $MachinePrecision] * N[(N[(C - A), $MachinePrecision] - N[Sqrt[N[(N[Power[N[(A - C), $MachinePrecision], 2.0], $MachinePrecision] + N[Power[B, 2.0], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[t$95$0, -4e-22], N[(180.0 * N[(N[ArcTan[N[(-1.0 - N[(A / B), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision], If[LessEqual[t$95$0, 0.0], N[(180.0 * N[(N[ArcTan[0.0], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision], N[(180.0 * N[(N[ArcTan[N[(1.0 - N[(A / B), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision]]]]
                        
                        \begin{array}{l}
                        
                        \\
                        \begin{array}{l}
                        t_0 := \frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\\
                        \mathbf{if}\;t\_0 \leq -4 \cdot 10^{-22}:\\
                        \;\;\;\;180 \cdot \frac{\tan^{-1} \left(-1 - \frac{A}{B}\right)}{\pi}\\
                        
                        \mathbf{elif}\;t\_0 \leq 0:\\
                        \;\;\;\;180 \cdot \frac{\tan^{-1} 0}{\pi}\\
                        
                        \mathbf{else}:\\
                        \;\;\;\;180 \cdot \frac{\tan^{-1} \left(1 - \frac{A}{B}\right)}{\pi}\\
                        
                        
                        \end{array}
                        \end{array}
                        
                        Derivation
                        1. Split input into 3 regimes
                        2. if (*.f64 (/.f64 #s(literal 1 binary64) B) (-.f64 (-.f64 C A) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))) < -4.0000000000000002e-22

                          1. Initial program 62.0%

                            \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
                          2. Add Preprocessing
                          3. Taylor expanded in C around 0

                            \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(-1 \cdot \frac{A + \sqrt{{A}^{2} + {B}^{2}}}{B}\right)}}{\mathsf{PI}\left(\right)} \]
                          4. Step-by-step derivation
                            1. mul-1-negN/A

                              \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\mathsf{neg}\left(\frac{A + \sqrt{{A}^{2} + {B}^{2}}}{B}\right)\right)}}{\mathsf{PI}\left(\right)} \]
                            2. distribute-neg-frac2N/A

                              \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{A + \sqrt{{A}^{2} + {B}^{2}}}{\mathsf{neg}\left(B\right)}\right)}}{\mathsf{PI}\left(\right)} \]
                            3. mul-1-negN/A

                              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{A + \sqrt{{A}^{2} + {B}^{2}}}{\color{blue}{-1 \cdot B}}\right)}{\mathsf{PI}\left(\right)} \]
                            4. lower-/.f64N/A

                              \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{A + \sqrt{{A}^{2} + {B}^{2}}}{-1 \cdot B}\right)}}{\mathsf{PI}\left(\right)} \]
                            5. lower-+.f64N/A

                              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\color{blue}{A + \sqrt{{A}^{2} + {B}^{2}}}}{-1 \cdot B}\right)}{\mathsf{PI}\left(\right)} \]
                            6. lower-sqrt.f64N/A

                              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{A + \color{blue}{\sqrt{{A}^{2} + {B}^{2}}}}{-1 \cdot B}\right)}{\mathsf{PI}\left(\right)} \]
                            7. unpow2N/A

                              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{A + \sqrt{\color{blue}{A \cdot A} + {B}^{2}}}{-1 \cdot B}\right)}{\mathsf{PI}\left(\right)} \]
                            8. lower-fma.f64N/A

                              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{A + \sqrt{\color{blue}{\mathsf{fma}\left(A, A, {B}^{2}\right)}}}{-1 \cdot B}\right)}{\mathsf{PI}\left(\right)} \]
                            9. unpow2N/A

                              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{A + \sqrt{\mathsf{fma}\left(A, A, \color{blue}{B \cdot B}\right)}}{-1 \cdot B}\right)}{\mathsf{PI}\left(\right)} \]
                            10. lower-*.f64N/A

                              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{A + \sqrt{\mathsf{fma}\left(A, A, \color{blue}{B \cdot B}\right)}}{-1 \cdot B}\right)}{\mathsf{PI}\left(\right)} \]
                            11. mul-1-negN/A

                              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{A + \sqrt{\mathsf{fma}\left(A, A, B \cdot B\right)}}{\color{blue}{\mathsf{neg}\left(B\right)}}\right)}{\mathsf{PI}\left(\right)} \]
                            12. lower-neg.f6449.2

                              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{A + \sqrt{\mathsf{fma}\left(A, A, B \cdot B\right)}}{\color{blue}{-B}}\right)}{\pi} \]
                          5. Applied rewrites49.2%

                            \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{A + \sqrt{\mathsf{fma}\left(A, A, B \cdot B\right)}}{-B}\right)}}{\pi} \]
                          6. Step-by-step derivation
                            1. Applied rewrites76.5%

                              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{A + \mathsf{hypot}\left(B, A\right)}{-B}\right)}{\pi} \]
                            2. Taylor expanded in A around 0

                              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(-1 \cdot \frac{A}{B} - \color{blue}{1}\right)}{\mathsf{PI}\left(\right)} \]
                            3. Step-by-step derivation
                              1. Applied rewrites69.3%

                                \[\leadsto 180 \cdot \frac{\tan^{-1} \left(-1 - \color{blue}{\frac{A}{B}}\right)}{\pi} \]

                              if -4.0000000000000002e-22 < (*.f64 (/.f64 #s(literal 1 binary64) B) (-.f64 (-.f64 C A) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))) < -0.0

                              1. Initial program 21.2%

                                \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
                              2. Add Preprocessing
                              3. Taylor expanded in C around inf

                                \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(-1 \cdot \frac{A + -1 \cdot A}{B}\right)}}{\mathsf{PI}\left(\right)} \]
                              4. Step-by-step derivation
                                1. distribute-rgt1-inN/A

                                  \[\leadsto 180 \cdot \frac{\tan^{-1} \left(-1 \cdot \frac{\color{blue}{\left(-1 + 1\right) \cdot A}}{B}\right)}{\mathsf{PI}\left(\right)} \]
                                2. metadata-evalN/A

                                  \[\leadsto 180 \cdot \frac{\tan^{-1} \left(-1 \cdot \frac{\color{blue}{0} \cdot A}{B}\right)}{\mathsf{PI}\left(\right)} \]
                                3. mul0-lftN/A

                                  \[\leadsto 180 \cdot \frac{\tan^{-1} \left(-1 \cdot \frac{\color{blue}{0}}{B}\right)}{\mathsf{PI}\left(\right)} \]
                                4. div0N/A

                                  \[\leadsto 180 \cdot \frac{\tan^{-1} \left(-1 \cdot \color{blue}{0}\right)}{\mathsf{PI}\left(\right)} \]
                                5. metadata-eval21.2

                                  \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{0}}{\pi} \]
                              5. Applied rewrites21.2%

                                \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{0}}{\pi} \]

                              if -0.0 < (*.f64 (/.f64 #s(literal 1 binary64) B) (-.f64 (-.f64 C A) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64))))))

                              1. Initial program 61.0%

                                \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
                              2. Add Preprocessing
                              3. Taylor expanded in C around 0

                                \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(-1 \cdot \frac{A + \sqrt{{A}^{2} + {B}^{2}}}{B}\right)}}{\mathsf{PI}\left(\right)} \]
                              4. Step-by-step derivation
                                1. mul-1-negN/A

                                  \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\mathsf{neg}\left(\frac{A + \sqrt{{A}^{2} + {B}^{2}}}{B}\right)\right)}}{\mathsf{PI}\left(\right)} \]
                                2. distribute-neg-frac2N/A

                                  \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{A + \sqrt{{A}^{2} + {B}^{2}}}{\mathsf{neg}\left(B\right)}\right)}}{\mathsf{PI}\left(\right)} \]
                                3. mul-1-negN/A

                                  \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{A + \sqrt{{A}^{2} + {B}^{2}}}{\color{blue}{-1 \cdot B}}\right)}{\mathsf{PI}\left(\right)} \]
                                4. lower-/.f64N/A

                                  \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{A + \sqrt{{A}^{2} + {B}^{2}}}{-1 \cdot B}\right)}}{\mathsf{PI}\left(\right)} \]
                                5. lower-+.f64N/A

                                  \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\color{blue}{A + \sqrt{{A}^{2} + {B}^{2}}}}{-1 \cdot B}\right)}{\mathsf{PI}\left(\right)} \]
                                6. lower-sqrt.f64N/A

                                  \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{A + \color{blue}{\sqrt{{A}^{2} + {B}^{2}}}}{-1 \cdot B}\right)}{\mathsf{PI}\left(\right)} \]
                                7. unpow2N/A

                                  \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{A + \sqrt{\color{blue}{A \cdot A} + {B}^{2}}}{-1 \cdot B}\right)}{\mathsf{PI}\left(\right)} \]
                                8. lower-fma.f64N/A

                                  \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{A + \sqrt{\color{blue}{\mathsf{fma}\left(A, A, {B}^{2}\right)}}}{-1 \cdot B}\right)}{\mathsf{PI}\left(\right)} \]
                                9. unpow2N/A

                                  \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{A + \sqrt{\mathsf{fma}\left(A, A, \color{blue}{B \cdot B}\right)}}{-1 \cdot B}\right)}{\mathsf{PI}\left(\right)} \]
                                10. lower-*.f64N/A

                                  \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{A + \sqrt{\mathsf{fma}\left(A, A, \color{blue}{B \cdot B}\right)}}{-1 \cdot B}\right)}{\mathsf{PI}\left(\right)} \]
                                11. mul-1-negN/A

                                  \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{A + \sqrt{\mathsf{fma}\left(A, A, B \cdot B\right)}}{\color{blue}{\mathsf{neg}\left(B\right)}}\right)}{\mathsf{PI}\left(\right)} \]
                                12. lower-neg.f6447.6

                                  \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{A + \sqrt{\mathsf{fma}\left(A, A, B \cdot B\right)}}{\color{blue}{-B}}\right)}{\pi} \]
                              5. Applied rewrites47.6%

                                \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{A + \sqrt{\mathsf{fma}\left(A, A, B \cdot B\right)}}{-B}\right)}}{\pi} \]
                              6. Taylor expanded in B around -inf

                                \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \color{blue}{-1 \cdot \frac{A}{B}}\right)}{\mathsf{PI}\left(\right)} \]
                              7. Step-by-step derivation
                                1. Applied rewrites61.9%

                                  \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 - \color{blue}{\frac{A}{B}}\right)}{\pi} \]
                              8. Recombined 3 regimes into one program.
                              9. Add Preprocessing

                              Alternative 12: 50.8% accurate, 2.6× speedup?

                              \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;B \leq 1900000:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(1 - \frac{A}{B}\right)}{\pi}\\ \mathbf{else}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} -1}{\pi}\\ \end{array} \end{array} \]
                              (FPCore (A B C)
                               :precision binary64
                               (if (<= B 1900000.0)
                                 (* 180.0 (/ (atan (- 1.0 (/ A B))) PI))
                                 (* 180.0 (/ (atan -1.0) PI))))
                              double code(double A, double B, double C) {
                              	double tmp;
                              	if (B <= 1900000.0) {
                              		tmp = 180.0 * (atan((1.0 - (A / B))) / ((double) M_PI));
                              	} else {
                              		tmp = 180.0 * (atan(-1.0) / ((double) M_PI));
                              	}
                              	return tmp;
                              }
                              
                              public static double code(double A, double B, double C) {
                              	double tmp;
                              	if (B <= 1900000.0) {
                              		tmp = 180.0 * (Math.atan((1.0 - (A / B))) / Math.PI);
                              	} else {
                              		tmp = 180.0 * (Math.atan(-1.0) / Math.PI);
                              	}
                              	return tmp;
                              }
                              
                              def code(A, B, C):
                              	tmp = 0
                              	if B <= 1900000.0:
                              		tmp = 180.0 * (math.atan((1.0 - (A / B))) / math.pi)
                              	else:
                              		tmp = 180.0 * (math.atan(-1.0) / math.pi)
                              	return tmp
                              
                              function code(A, B, C)
                              	tmp = 0.0
                              	if (B <= 1900000.0)
                              		tmp = Float64(180.0 * Float64(atan(Float64(1.0 - Float64(A / B))) / pi));
                              	else
                              		tmp = Float64(180.0 * Float64(atan(-1.0) / pi));
                              	end
                              	return tmp
                              end
                              
                              function tmp_2 = code(A, B, C)
                              	tmp = 0.0;
                              	if (B <= 1900000.0)
                              		tmp = 180.0 * (atan((1.0 - (A / B))) / pi);
                              	else
                              		tmp = 180.0 * (atan(-1.0) / pi);
                              	end
                              	tmp_2 = tmp;
                              end
                              
                              code[A_, B_, C_] := If[LessEqual[B, 1900000.0], N[(180.0 * N[(N[ArcTan[N[(1.0 - N[(A / B), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision], N[(180.0 * N[(N[ArcTan[-1.0], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision]]
                              
                              \begin{array}{l}
                              
                              \\
                              \begin{array}{l}
                              \mathbf{if}\;B \leq 1900000:\\
                              \;\;\;\;180 \cdot \frac{\tan^{-1} \left(1 - \frac{A}{B}\right)}{\pi}\\
                              
                              \mathbf{else}:\\
                              \;\;\;\;180 \cdot \frac{\tan^{-1} -1}{\pi}\\
                              
                              
                              \end{array}
                              \end{array}
                              
                              Derivation
                              1. Split input into 2 regimes
                              2. if B < 1.9e6

                                1. Initial program 59.6%

                                  \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
                                2. Add Preprocessing
                                3. Taylor expanded in C around 0

                                  \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(-1 \cdot \frac{A + \sqrt{{A}^{2} + {B}^{2}}}{B}\right)}}{\mathsf{PI}\left(\right)} \]
                                4. Step-by-step derivation
                                  1. mul-1-negN/A

                                    \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\mathsf{neg}\left(\frac{A + \sqrt{{A}^{2} + {B}^{2}}}{B}\right)\right)}}{\mathsf{PI}\left(\right)} \]
                                  2. distribute-neg-frac2N/A

                                    \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{A + \sqrt{{A}^{2} + {B}^{2}}}{\mathsf{neg}\left(B\right)}\right)}}{\mathsf{PI}\left(\right)} \]
                                  3. mul-1-negN/A

                                    \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{A + \sqrt{{A}^{2} + {B}^{2}}}{\color{blue}{-1 \cdot B}}\right)}{\mathsf{PI}\left(\right)} \]
                                  4. lower-/.f64N/A

                                    \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{A + \sqrt{{A}^{2} + {B}^{2}}}{-1 \cdot B}\right)}}{\mathsf{PI}\left(\right)} \]
                                  5. lower-+.f64N/A

                                    \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\color{blue}{A + \sqrt{{A}^{2} + {B}^{2}}}}{-1 \cdot B}\right)}{\mathsf{PI}\left(\right)} \]
                                  6. lower-sqrt.f64N/A

                                    \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{A + \color{blue}{\sqrt{{A}^{2} + {B}^{2}}}}{-1 \cdot B}\right)}{\mathsf{PI}\left(\right)} \]
                                  7. unpow2N/A

                                    \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{A + \sqrt{\color{blue}{A \cdot A} + {B}^{2}}}{-1 \cdot B}\right)}{\mathsf{PI}\left(\right)} \]
                                  8. lower-fma.f64N/A

                                    \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{A + \sqrt{\color{blue}{\mathsf{fma}\left(A, A, {B}^{2}\right)}}}{-1 \cdot B}\right)}{\mathsf{PI}\left(\right)} \]
                                  9. unpow2N/A

                                    \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{A + \sqrt{\mathsf{fma}\left(A, A, \color{blue}{B \cdot B}\right)}}{-1 \cdot B}\right)}{\mathsf{PI}\left(\right)} \]
                                  10. lower-*.f64N/A

                                    \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{A + \sqrt{\mathsf{fma}\left(A, A, \color{blue}{B \cdot B}\right)}}{-1 \cdot B}\right)}{\mathsf{PI}\left(\right)} \]
                                  11. mul-1-negN/A

                                    \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{A + \sqrt{\mathsf{fma}\left(A, A, B \cdot B\right)}}{\color{blue}{\mathsf{neg}\left(B\right)}}\right)}{\mathsf{PI}\left(\right)} \]
                                  12. lower-neg.f6442.5

                                    \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{A + \sqrt{\mathsf{fma}\left(A, A, B \cdot B\right)}}{\color{blue}{-B}}\right)}{\pi} \]
                                5. Applied rewrites42.5%

                                  \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{A + \sqrt{\mathsf{fma}\left(A, A, B \cdot B\right)}}{-B}\right)}}{\pi} \]
                                6. Taylor expanded in B around -inf

                                  \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \color{blue}{-1 \cdot \frac{A}{B}}\right)}{\mathsf{PI}\left(\right)} \]
                                7. Step-by-step derivation
                                  1. Applied rewrites45.2%

                                    \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 - \color{blue}{\frac{A}{B}}\right)}{\pi} \]

                                  if 1.9e6 < B

                                  1. Initial program 36.7%

                                    \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
                                  2. Add Preprocessing
                                  3. Taylor expanded in B around inf

                                    \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{-1}}{\mathsf{PI}\left(\right)} \]
                                  4. Step-by-step derivation
                                    1. Applied rewrites76.3%

                                      \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{-1}}{\pi} \]
                                  5. Recombined 2 regimes into one program.
                                  6. Add Preprocessing

                                  Alternative 13: 43.7% accurate, 2.8× speedup?

                                  \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;B \leq -2.5 \cdot 10^{-111}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} 1}{\pi}\\ \mathbf{elif}\;B \leq 4.6 \cdot 10^{-238}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} 0}{\pi}\\ \mathbf{else}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} -1}{\pi}\\ \end{array} \end{array} \]
                                  (FPCore (A B C)
                                   :precision binary64
                                   (if (<= B -2.5e-111)
                                     (* 180.0 (/ (atan 1.0) PI))
                                     (if (<= B 4.6e-238)
                                       (* 180.0 (/ (atan 0.0) PI))
                                       (* 180.0 (/ (atan -1.0) PI)))))
                                  double code(double A, double B, double C) {
                                  	double tmp;
                                  	if (B <= -2.5e-111) {
                                  		tmp = 180.0 * (atan(1.0) / ((double) M_PI));
                                  	} else if (B <= 4.6e-238) {
                                  		tmp = 180.0 * (atan(0.0) / ((double) M_PI));
                                  	} else {
                                  		tmp = 180.0 * (atan(-1.0) / ((double) M_PI));
                                  	}
                                  	return tmp;
                                  }
                                  
                                  public static double code(double A, double B, double C) {
                                  	double tmp;
                                  	if (B <= -2.5e-111) {
                                  		tmp = 180.0 * (Math.atan(1.0) / Math.PI);
                                  	} else if (B <= 4.6e-238) {
                                  		tmp = 180.0 * (Math.atan(0.0) / Math.PI);
                                  	} else {
                                  		tmp = 180.0 * (Math.atan(-1.0) / Math.PI);
                                  	}
                                  	return tmp;
                                  }
                                  
                                  def code(A, B, C):
                                  	tmp = 0
                                  	if B <= -2.5e-111:
                                  		tmp = 180.0 * (math.atan(1.0) / math.pi)
                                  	elif B <= 4.6e-238:
                                  		tmp = 180.0 * (math.atan(0.0) / math.pi)
                                  	else:
                                  		tmp = 180.0 * (math.atan(-1.0) / math.pi)
                                  	return tmp
                                  
                                  function code(A, B, C)
                                  	tmp = 0.0
                                  	if (B <= -2.5e-111)
                                  		tmp = Float64(180.0 * Float64(atan(1.0) / pi));
                                  	elseif (B <= 4.6e-238)
                                  		tmp = Float64(180.0 * Float64(atan(0.0) / pi));
                                  	else
                                  		tmp = Float64(180.0 * Float64(atan(-1.0) / pi));
                                  	end
                                  	return tmp
                                  end
                                  
                                  function tmp_2 = code(A, B, C)
                                  	tmp = 0.0;
                                  	if (B <= -2.5e-111)
                                  		tmp = 180.0 * (atan(1.0) / pi);
                                  	elseif (B <= 4.6e-238)
                                  		tmp = 180.0 * (atan(0.0) / pi);
                                  	else
                                  		tmp = 180.0 * (atan(-1.0) / pi);
                                  	end
                                  	tmp_2 = tmp;
                                  end
                                  
                                  code[A_, B_, C_] := If[LessEqual[B, -2.5e-111], N[(180.0 * N[(N[ArcTan[1.0], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision], If[LessEqual[B, 4.6e-238], N[(180.0 * N[(N[ArcTan[0.0], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision], N[(180.0 * N[(N[ArcTan[-1.0], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision]]]
                                  
                                  \begin{array}{l}
                                  
                                  \\
                                  \begin{array}{l}
                                  \mathbf{if}\;B \leq -2.5 \cdot 10^{-111}:\\
                                  \;\;\;\;180 \cdot \frac{\tan^{-1} 1}{\pi}\\
                                  
                                  \mathbf{elif}\;B \leq 4.6 \cdot 10^{-238}:\\
                                  \;\;\;\;180 \cdot \frac{\tan^{-1} 0}{\pi}\\
                                  
                                  \mathbf{else}:\\
                                  \;\;\;\;180 \cdot \frac{\tan^{-1} -1}{\pi}\\
                                  
                                  
                                  \end{array}
                                  \end{array}
                                  
                                  Derivation
                                  1. Split input into 3 regimes
                                  2. if B < -2.5000000000000001e-111

                                    1. Initial program 53.0%

                                      \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
                                    2. Add Preprocessing
                                    3. Taylor expanded in B around -inf

                                      \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{1}}{\mathsf{PI}\left(\right)} \]
                                    4. Step-by-step derivation
                                      1. Applied rewrites51.4%

                                        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{1}}{\pi} \]

                                      if -2.5000000000000001e-111 < B < 4.60000000000000009e-238

                                      1. Initial program 58.1%

                                        \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
                                      2. Add Preprocessing
                                      3. Taylor expanded in C around inf

                                        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(-1 \cdot \frac{A + -1 \cdot A}{B}\right)}}{\mathsf{PI}\left(\right)} \]
                                      4. Step-by-step derivation
                                        1. distribute-rgt1-inN/A

                                          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(-1 \cdot \frac{\color{blue}{\left(-1 + 1\right) \cdot A}}{B}\right)}{\mathsf{PI}\left(\right)} \]
                                        2. metadata-evalN/A

                                          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(-1 \cdot \frac{\color{blue}{0} \cdot A}{B}\right)}{\mathsf{PI}\left(\right)} \]
                                        3. mul0-lftN/A

                                          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(-1 \cdot \frac{\color{blue}{0}}{B}\right)}{\mathsf{PI}\left(\right)} \]
                                        4. div0N/A

                                          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(-1 \cdot \color{blue}{0}\right)}{\mathsf{PI}\left(\right)} \]
                                        5. metadata-eval33.9

                                          \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{0}}{\pi} \]
                                      5. Applied rewrites33.9%

                                        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{0}}{\pi} \]

                                      if 4.60000000000000009e-238 < B

                                      1. Initial program 54.8%

                                        \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
                                      2. Add Preprocessing
                                      3. Taylor expanded in B around inf

                                        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{-1}}{\mathsf{PI}\left(\right)} \]
                                      4. Step-by-step derivation
                                        1. Applied rewrites48.9%

                                          \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{-1}}{\pi} \]
                                      5. Recombined 3 regimes into one program.
                                      6. Add Preprocessing

                                      Alternative 14: 28.0% accurate, 2.9× speedup?

                                      \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;B \leq 4.6 \cdot 10^{-238}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} 0}{\pi}\\ \mathbf{else}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} -1}{\pi}\\ \end{array} \end{array} \]
                                      (FPCore (A B C)
                                       :precision binary64
                                       (if (<= B 4.6e-238) (* 180.0 (/ (atan 0.0) PI)) (* 180.0 (/ (atan -1.0) PI))))
                                      double code(double A, double B, double C) {
                                      	double tmp;
                                      	if (B <= 4.6e-238) {
                                      		tmp = 180.0 * (atan(0.0) / ((double) M_PI));
                                      	} else {
                                      		tmp = 180.0 * (atan(-1.0) / ((double) M_PI));
                                      	}
                                      	return tmp;
                                      }
                                      
                                      public static double code(double A, double B, double C) {
                                      	double tmp;
                                      	if (B <= 4.6e-238) {
                                      		tmp = 180.0 * (Math.atan(0.0) / Math.PI);
                                      	} else {
                                      		tmp = 180.0 * (Math.atan(-1.0) / Math.PI);
                                      	}
                                      	return tmp;
                                      }
                                      
                                      def code(A, B, C):
                                      	tmp = 0
                                      	if B <= 4.6e-238:
                                      		tmp = 180.0 * (math.atan(0.0) / math.pi)
                                      	else:
                                      		tmp = 180.0 * (math.atan(-1.0) / math.pi)
                                      	return tmp
                                      
                                      function code(A, B, C)
                                      	tmp = 0.0
                                      	if (B <= 4.6e-238)
                                      		tmp = Float64(180.0 * Float64(atan(0.0) / pi));
                                      	else
                                      		tmp = Float64(180.0 * Float64(atan(-1.0) / pi));
                                      	end
                                      	return tmp
                                      end
                                      
                                      function tmp_2 = code(A, B, C)
                                      	tmp = 0.0;
                                      	if (B <= 4.6e-238)
                                      		tmp = 180.0 * (atan(0.0) / pi);
                                      	else
                                      		tmp = 180.0 * (atan(-1.0) / pi);
                                      	end
                                      	tmp_2 = tmp;
                                      end
                                      
                                      code[A_, B_, C_] := If[LessEqual[B, 4.6e-238], N[(180.0 * N[(N[ArcTan[0.0], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision], N[(180.0 * N[(N[ArcTan[-1.0], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision]]
                                      
                                      \begin{array}{l}
                                      
                                      \\
                                      \begin{array}{l}
                                      \mathbf{if}\;B \leq 4.6 \cdot 10^{-238}:\\
                                      \;\;\;\;180 \cdot \frac{\tan^{-1} 0}{\pi}\\
                                      
                                      \mathbf{else}:\\
                                      \;\;\;\;180 \cdot \frac{\tan^{-1} -1}{\pi}\\
                                      
                                      
                                      \end{array}
                                      \end{array}
                                      
                                      Derivation
                                      1. Split input into 2 regimes
                                      2. if B < 4.60000000000000009e-238

                                        1. Initial program 55.0%

                                          \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
                                        2. Add Preprocessing
                                        3. Taylor expanded in C around inf

                                          \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(-1 \cdot \frac{A + -1 \cdot A}{B}\right)}}{\mathsf{PI}\left(\right)} \]
                                        4. Step-by-step derivation
                                          1. distribute-rgt1-inN/A

                                            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(-1 \cdot \frac{\color{blue}{\left(-1 + 1\right) \cdot A}}{B}\right)}{\mathsf{PI}\left(\right)} \]
                                          2. metadata-evalN/A

                                            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(-1 \cdot \frac{\color{blue}{0} \cdot A}{B}\right)}{\mathsf{PI}\left(\right)} \]
                                          3. mul0-lftN/A

                                            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(-1 \cdot \frac{\color{blue}{0}}{B}\right)}{\mathsf{PI}\left(\right)} \]
                                          4. div0N/A

                                            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(-1 \cdot \color{blue}{0}\right)}{\mathsf{PI}\left(\right)} \]
                                          5. metadata-eval16.8

                                            \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{0}}{\pi} \]
                                        5. Applied rewrites16.8%

                                          \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{0}}{\pi} \]

                                        if 4.60000000000000009e-238 < B

                                        1. Initial program 54.8%

                                          \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
                                        2. Add Preprocessing
                                        3. Taylor expanded in B around inf

                                          \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{-1}}{\mathsf{PI}\left(\right)} \]
                                        4. Step-by-step derivation
                                          1. Applied rewrites48.9%

                                            \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{-1}}{\pi} \]
                                        5. Recombined 2 regimes into one program.
                                        6. Add Preprocessing

                                        Alternative 15: 20.8% accurate, 3.1× speedup?

                                        \[\begin{array}{l} \\ 180 \cdot \frac{\tan^{-1} -1}{\pi} \end{array} \]
                                        (FPCore (A B C) :precision binary64 (* 180.0 (/ (atan -1.0) PI)))
                                        double code(double A, double B, double C) {
                                        	return 180.0 * (atan(-1.0) / ((double) M_PI));
                                        }
                                        
                                        public static double code(double A, double B, double C) {
                                        	return 180.0 * (Math.atan(-1.0) / Math.PI);
                                        }
                                        
                                        def code(A, B, C):
                                        	return 180.0 * (math.atan(-1.0) / math.pi)
                                        
                                        function code(A, B, C)
                                        	return Float64(180.0 * Float64(atan(-1.0) / pi))
                                        end
                                        
                                        function tmp = code(A, B, C)
                                        	tmp = 180.0 * (atan(-1.0) / pi);
                                        end
                                        
                                        code[A_, B_, C_] := N[(180.0 * N[(N[ArcTan[-1.0], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision]
                                        
                                        \begin{array}{l}
                                        
                                        \\
                                        180 \cdot \frac{\tan^{-1} -1}{\pi}
                                        \end{array}
                                        
                                        Derivation
                                        1. Initial program 54.9%

                                          \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
                                        2. Add Preprocessing
                                        3. Taylor expanded in B around inf

                                          \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{-1}}{\mathsf{PI}\left(\right)} \]
                                        4. Step-by-step derivation
                                          1. Applied rewrites22.8%

                                            \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{-1}}{\pi} \]
                                          2. Add Preprocessing

                                          Reproduce

                                          ?
                                          herbie shell --seed 2024233 
                                          (FPCore (A B C)
                                            :name "ABCF->ab-angle angle"
                                            :precision binary64
                                            (* 180.0 (/ (atan (* (/ 1.0 B) (- (- C A) (sqrt (+ (pow (- A C) 2.0) (pow B 2.0)))))) PI)))