Data.HashTable.ST.Basic:computeOverhead from hashtables-1.2.0.2

Percentage Accurate: 86.3% → 99.1%
Time: 11.3s
Alternatives: 11
Speedup: 1.2×

Specification

?
\[\begin{array}{l} \\ \frac{x}{y} + \frac{2 + \left(z \cdot 2\right) \cdot \left(1 - t\right)}{t \cdot z} \end{array} \]
(FPCore (x y z t)
 :precision binary64
 (+ (/ x y) (/ (+ 2.0 (* (* z 2.0) (- 1.0 t))) (* t z))))
double code(double x, double y, double z, double t) {
	return (x / y) + ((2.0 + ((z * 2.0) * (1.0 - t))) / (t * z));
}
real(8) function code(x, y, z, t)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    real(8), intent (in) :: z
    real(8), intent (in) :: t
    code = (x / y) + ((2.0d0 + ((z * 2.0d0) * (1.0d0 - t))) / (t * z))
end function
public static double code(double x, double y, double z, double t) {
	return (x / y) + ((2.0 + ((z * 2.0) * (1.0 - t))) / (t * z));
}
def code(x, y, z, t):
	return (x / y) + ((2.0 + ((z * 2.0) * (1.0 - t))) / (t * z))
function code(x, y, z, t)
	return Float64(Float64(x / y) + Float64(Float64(2.0 + Float64(Float64(z * 2.0) * Float64(1.0 - t))) / Float64(t * z)))
end
function tmp = code(x, y, z, t)
	tmp = (x / y) + ((2.0 + ((z * 2.0) * (1.0 - t))) / (t * z));
end
code[x_, y_, z_, t_] := N[(N[(x / y), $MachinePrecision] + N[(N[(2.0 + N[(N[(z * 2.0), $MachinePrecision] * N[(1.0 - t), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] / N[(t * z), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
\frac{x}{y} + \frac{2 + \left(z \cdot 2\right) \cdot \left(1 - t\right)}{t \cdot z}
\end{array}

Sampling outcomes in binary64 precision:

Local Percentage Accuracy vs ?

The average percentage accuracy by input value. Horizontal axis shows value of an input variable; the variable is choosen in the title. Vertical axis is accuracy; higher is better. Red represent the original program, while blue represents Herbie's suggestion. These can be toggled with buttons below the plot. The line is an average while dots represent individual samples.

Accuracy vs Speed?

Herbie found 11 alternatives:

AlternativeAccuracySpeedup
The accuracy (vertical axis) and speed (horizontal axis) of each alternatives. Up and to the right is better. The red square shows the initial program, and each blue circle shows an alternative.The line shows the best available speed-accuracy tradeoffs.

Initial Program: 86.3% accurate, 1.0× speedup?

\[\begin{array}{l} \\ \frac{x}{y} + \frac{2 + \left(z \cdot 2\right) \cdot \left(1 - t\right)}{t \cdot z} \end{array} \]
(FPCore (x y z t)
 :precision binary64
 (+ (/ x y) (/ (+ 2.0 (* (* z 2.0) (- 1.0 t))) (* t z))))
double code(double x, double y, double z, double t) {
	return (x / y) + ((2.0 + ((z * 2.0) * (1.0 - t))) / (t * z));
}
real(8) function code(x, y, z, t)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    real(8), intent (in) :: z
    real(8), intent (in) :: t
    code = (x / y) + ((2.0d0 + ((z * 2.0d0) * (1.0d0 - t))) / (t * z))
end function
public static double code(double x, double y, double z, double t) {
	return (x / y) + ((2.0 + ((z * 2.0) * (1.0 - t))) / (t * z));
}
def code(x, y, z, t):
	return (x / y) + ((2.0 + ((z * 2.0) * (1.0 - t))) / (t * z))
function code(x, y, z, t)
	return Float64(Float64(x / y) + Float64(Float64(2.0 + Float64(Float64(z * 2.0) * Float64(1.0 - t))) / Float64(t * z)))
end
function tmp = code(x, y, z, t)
	tmp = (x / y) + ((2.0 + ((z * 2.0) * (1.0 - t))) / (t * z));
end
code[x_, y_, z_, t_] := N[(N[(x / y), $MachinePrecision] + N[(N[(2.0 + N[(N[(z * 2.0), $MachinePrecision] * N[(1.0 - t), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] / N[(t * z), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
\frac{x}{y} + \frac{2 + \left(z \cdot 2\right) \cdot \left(1 - t\right)}{t \cdot z}
\end{array}

Alternative 1: 99.1% accurate, 1.2× speedup?

\[\begin{array}{l} \\ \frac{x}{y} + \mathsf{fma}\left(\frac{2}{z \cdot t}, z + 1, -2\right) \end{array} \]
(FPCore (x y z t)
 :precision binary64
 (+ (/ x y) (fma (/ 2.0 (* z t)) (+ z 1.0) -2.0)))
double code(double x, double y, double z, double t) {
	return (x / y) + fma((2.0 / (z * t)), (z + 1.0), -2.0);
}
function code(x, y, z, t)
	return Float64(Float64(x / y) + fma(Float64(2.0 / Float64(z * t)), Float64(z + 1.0), -2.0))
end
code[x_, y_, z_, t_] := N[(N[(x / y), $MachinePrecision] + N[(N[(2.0 / N[(z * t), $MachinePrecision]), $MachinePrecision] * N[(z + 1.0), $MachinePrecision] + -2.0), $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
\frac{x}{y} + \mathsf{fma}\left(\frac{2}{z \cdot t}, z + 1, -2\right)
\end{array}
Derivation
  1. Initial program 86.6%

    \[\frac{x}{y} + \frac{2 + \left(z \cdot 2\right) \cdot \left(1 - t\right)}{t \cdot z} \]
  2. Add Preprocessing
  3. Taylor expanded in z around 0

    \[\leadsto \frac{x}{y} + \color{blue}{\frac{2 \cdot \frac{z \cdot \left(1 - t\right)}{t} + 2 \cdot \frac{1}{t}}{z}} \]
  4. Applied rewrites99.8%

    \[\leadsto \frac{x}{y} + \color{blue}{\mathsf{fma}\left(\frac{2}{t \cdot z}, z + 1, -2\right)} \]
  5. Final simplification99.8%

    \[\leadsto \frac{x}{y} + \mathsf{fma}\left(\frac{2}{z \cdot t}, z + 1, -2\right) \]
  6. Add Preprocessing

Alternative 2: 70.1% accurate, 0.2× speedup?

\[\begin{array}{l} \\ \begin{array}{l} t_1 := \frac{2}{z \cdot t}\\ t_2 := \frac{2 + \left(2 \cdot z\right) \cdot \left(1 - t\right)}{z \cdot t}\\ t_3 := \frac{x}{y} + -2\\ \mathbf{if}\;t\_2 \leq -\infty:\\ \;\;\;\;t\_1\\ \mathbf{elif}\;t\_2 \leq -1 \cdot 10^{+175}:\\ \;\;\;\;-2 + \frac{2}{t}\\ \mathbf{elif}\;t\_2 \leq 10^{+46}:\\ \;\;\;\;t\_3\\ \mathbf{elif}\;t\_2 \leq 4 \cdot 10^{+122}:\\ \;\;\;\;t\_1\\ \mathbf{elif}\;t\_2 \leq 10^{+294}:\\ \;\;\;\;\frac{2}{t}\\ \mathbf{elif}\;t\_2 \leq \infty:\\ \;\;\;\;\frac{\frac{2}{t}}{z}\\ \mathbf{else}:\\ \;\;\;\;t\_3\\ \end{array} \end{array} \]
(FPCore (x y z t)
 :precision binary64
 (let* ((t_1 (/ 2.0 (* z t)))
        (t_2 (/ (+ 2.0 (* (* 2.0 z) (- 1.0 t))) (* z t)))
        (t_3 (+ (/ x y) -2.0)))
   (if (<= t_2 (- INFINITY))
     t_1
     (if (<= t_2 -1e+175)
       (+ -2.0 (/ 2.0 t))
       (if (<= t_2 1e+46)
         t_3
         (if (<= t_2 4e+122)
           t_1
           (if (<= t_2 1e+294)
             (/ 2.0 t)
             (if (<= t_2 INFINITY) (/ (/ 2.0 t) z) t_3))))))))
double code(double x, double y, double z, double t) {
	double t_1 = 2.0 / (z * t);
	double t_2 = (2.0 + ((2.0 * z) * (1.0 - t))) / (z * t);
	double t_3 = (x / y) + -2.0;
	double tmp;
	if (t_2 <= -((double) INFINITY)) {
		tmp = t_1;
	} else if (t_2 <= -1e+175) {
		tmp = -2.0 + (2.0 / t);
	} else if (t_2 <= 1e+46) {
		tmp = t_3;
	} else if (t_2 <= 4e+122) {
		tmp = t_1;
	} else if (t_2 <= 1e+294) {
		tmp = 2.0 / t;
	} else if (t_2 <= ((double) INFINITY)) {
		tmp = (2.0 / t) / z;
	} else {
		tmp = t_3;
	}
	return tmp;
}
public static double code(double x, double y, double z, double t) {
	double t_1 = 2.0 / (z * t);
	double t_2 = (2.0 + ((2.0 * z) * (1.0 - t))) / (z * t);
	double t_3 = (x / y) + -2.0;
	double tmp;
	if (t_2 <= -Double.POSITIVE_INFINITY) {
		tmp = t_1;
	} else if (t_2 <= -1e+175) {
		tmp = -2.0 + (2.0 / t);
	} else if (t_2 <= 1e+46) {
		tmp = t_3;
	} else if (t_2 <= 4e+122) {
		tmp = t_1;
	} else if (t_2 <= 1e+294) {
		tmp = 2.0 / t;
	} else if (t_2 <= Double.POSITIVE_INFINITY) {
		tmp = (2.0 / t) / z;
	} else {
		tmp = t_3;
	}
	return tmp;
}
def code(x, y, z, t):
	t_1 = 2.0 / (z * t)
	t_2 = (2.0 + ((2.0 * z) * (1.0 - t))) / (z * t)
	t_3 = (x / y) + -2.0
	tmp = 0
	if t_2 <= -math.inf:
		tmp = t_1
	elif t_2 <= -1e+175:
		tmp = -2.0 + (2.0 / t)
	elif t_2 <= 1e+46:
		tmp = t_3
	elif t_2 <= 4e+122:
		tmp = t_1
	elif t_2 <= 1e+294:
		tmp = 2.0 / t
	elif t_2 <= math.inf:
		tmp = (2.0 / t) / z
	else:
		tmp = t_3
	return tmp
function code(x, y, z, t)
	t_1 = Float64(2.0 / Float64(z * t))
	t_2 = Float64(Float64(2.0 + Float64(Float64(2.0 * z) * Float64(1.0 - t))) / Float64(z * t))
	t_3 = Float64(Float64(x / y) + -2.0)
	tmp = 0.0
	if (t_2 <= Float64(-Inf))
		tmp = t_1;
	elseif (t_2 <= -1e+175)
		tmp = Float64(-2.0 + Float64(2.0 / t));
	elseif (t_2 <= 1e+46)
		tmp = t_3;
	elseif (t_2 <= 4e+122)
		tmp = t_1;
	elseif (t_2 <= 1e+294)
		tmp = Float64(2.0 / t);
	elseif (t_2 <= Inf)
		tmp = Float64(Float64(2.0 / t) / z);
	else
		tmp = t_3;
	end
	return tmp
end
function tmp_2 = code(x, y, z, t)
	t_1 = 2.0 / (z * t);
	t_2 = (2.0 + ((2.0 * z) * (1.0 - t))) / (z * t);
	t_3 = (x / y) + -2.0;
	tmp = 0.0;
	if (t_2 <= -Inf)
		tmp = t_1;
	elseif (t_2 <= -1e+175)
		tmp = -2.0 + (2.0 / t);
	elseif (t_2 <= 1e+46)
		tmp = t_3;
	elseif (t_2 <= 4e+122)
		tmp = t_1;
	elseif (t_2 <= 1e+294)
		tmp = 2.0 / t;
	elseif (t_2 <= Inf)
		tmp = (2.0 / t) / z;
	else
		tmp = t_3;
	end
	tmp_2 = tmp;
end
code[x_, y_, z_, t_] := Block[{t$95$1 = N[(2.0 / N[(z * t), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$2 = N[(N[(2.0 + N[(N[(2.0 * z), $MachinePrecision] * N[(1.0 - t), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] / N[(z * t), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$3 = N[(N[(x / y), $MachinePrecision] + -2.0), $MachinePrecision]}, If[LessEqual[t$95$2, (-Infinity)], t$95$1, If[LessEqual[t$95$2, -1e+175], N[(-2.0 + N[(2.0 / t), $MachinePrecision]), $MachinePrecision], If[LessEqual[t$95$2, 1e+46], t$95$3, If[LessEqual[t$95$2, 4e+122], t$95$1, If[LessEqual[t$95$2, 1e+294], N[(2.0 / t), $MachinePrecision], If[LessEqual[t$95$2, Infinity], N[(N[(2.0 / t), $MachinePrecision] / z), $MachinePrecision], t$95$3]]]]]]]]]
\begin{array}{l}

\\
\begin{array}{l}
t_1 := \frac{2}{z \cdot t}\\
t_2 := \frac{2 + \left(2 \cdot z\right) \cdot \left(1 - t\right)}{z \cdot t}\\
t_3 := \frac{x}{y} + -2\\
\mathbf{if}\;t\_2 \leq -\infty:\\
\;\;\;\;t\_1\\

\mathbf{elif}\;t\_2 \leq -1 \cdot 10^{+175}:\\
\;\;\;\;-2 + \frac{2}{t}\\

\mathbf{elif}\;t\_2 \leq 10^{+46}:\\
\;\;\;\;t\_3\\

\mathbf{elif}\;t\_2 \leq 4 \cdot 10^{+122}:\\
\;\;\;\;t\_1\\

\mathbf{elif}\;t\_2 \leq 10^{+294}:\\
\;\;\;\;\frac{2}{t}\\

\mathbf{elif}\;t\_2 \leq \infty:\\
\;\;\;\;\frac{\frac{2}{t}}{z}\\

\mathbf{else}:\\
\;\;\;\;t\_3\\


\end{array}
\end{array}
Derivation
  1. Split input into 5 regimes
  2. if (/.f64 (+.f64 #s(literal 2 binary64) (*.f64 (*.f64 z #s(literal 2 binary64)) (-.f64 #s(literal 1 binary64) t))) (*.f64 t z)) < -inf.0 or 9.9999999999999999e45 < (/.f64 (+.f64 #s(literal 2 binary64) (*.f64 (*.f64 z #s(literal 2 binary64)) (-.f64 #s(literal 1 binary64) t))) (*.f64 t z)) < 4.00000000000000006e122

    1. Initial program 94.7%

      \[\frac{x}{y} + \frac{2 + \left(z \cdot 2\right) \cdot \left(1 - t\right)}{t \cdot z} \]
    2. Add Preprocessing
    3. Taylor expanded in z around 0

      \[\leadsto \color{blue}{\frac{2}{t \cdot z}} \]
    4. Step-by-step derivation
      1. lower-/.f64N/A

        \[\leadsto \color{blue}{\frac{2}{t \cdot z}} \]
      2. lower-*.f6479.1

        \[\leadsto \frac{2}{\color{blue}{t \cdot z}} \]
    5. Applied rewrites79.1%

      \[\leadsto \color{blue}{\frac{2}{t \cdot z}} \]

    if -inf.0 < (/.f64 (+.f64 #s(literal 2 binary64) (*.f64 (*.f64 z #s(literal 2 binary64)) (-.f64 #s(literal 1 binary64) t))) (*.f64 t z)) < -9.9999999999999994e174

    1. Initial program 99.7%

      \[\frac{x}{y} + \frac{2 + \left(z \cdot 2\right) \cdot \left(1 - t\right)}{t \cdot z} \]
    2. Add Preprocessing
    3. Taylor expanded in x around 0

      \[\leadsto \color{blue}{2 \cdot \frac{1 - t}{t} + 2 \cdot \frac{1}{t \cdot z}} \]
    4. Applied rewrites80.6%

      \[\leadsto \color{blue}{\mathsf{fma}\left(\frac{2}{t \cdot z}, z + 1, -2\right)} \]
    5. Taylor expanded in z around inf

      \[\leadsto 2 \cdot \frac{1}{t} - \color{blue}{2} \]
    6. Step-by-step derivation
      1. Applied rewrites57.2%

        \[\leadsto \frac{2}{t} + \color{blue}{-2} \]

      if -9.9999999999999994e174 < (/.f64 (+.f64 #s(literal 2 binary64) (*.f64 (*.f64 z #s(literal 2 binary64)) (-.f64 #s(literal 1 binary64) t))) (*.f64 t z)) < 9.9999999999999999e45 or +inf.0 < (/.f64 (+.f64 #s(literal 2 binary64) (*.f64 (*.f64 z #s(literal 2 binary64)) (-.f64 #s(literal 1 binary64) t))) (*.f64 t z))

      1. Initial program 79.7%

        \[\frac{x}{y} + \frac{2 + \left(z \cdot 2\right) \cdot \left(1 - t\right)}{t \cdot z} \]
      2. Add Preprocessing
      3. Taylor expanded in t around inf

        \[\leadsto \frac{x}{y} + \color{blue}{-2} \]
      4. Step-by-step derivation
        1. Applied rewrites85.2%

          \[\leadsto \frac{x}{y} + \color{blue}{-2} \]

        if 4.00000000000000006e122 < (/.f64 (+.f64 #s(literal 2 binary64) (*.f64 (*.f64 z #s(literal 2 binary64)) (-.f64 #s(literal 1 binary64) t))) (*.f64 t z)) < 1.00000000000000007e294

        1. Initial program 99.7%

          \[\frac{x}{y} + \frac{2 + \left(z \cdot 2\right) \cdot \left(1 - t\right)}{t \cdot z} \]
        2. Add Preprocessing
        3. Taylor expanded in t around 0

          \[\leadsto \color{blue}{\frac{2 + 2 \cdot \frac{1}{z}}{t}} \]
        4. Applied rewrites86.8%

          \[\leadsto \color{blue}{\frac{\mathsf{fma}\left(2, z, 2\right)}{t \cdot z}} \]
        5. Taylor expanded in z around inf

          \[\leadsto \frac{2}{\color{blue}{t}} \]
        6. Step-by-step derivation
          1. Applied rewrites55.6%

            \[\leadsto \frac{2}{\color{blue}{t}} \]

          if 1.00000000000000007e294 < (/.f64 (+.f64 #s(literal 2 binary64) (*.f64 (*.f64 z #s(literal 2 binary64)) (-.f64 #s(literal 1 binary64) t))) (*.f64 t z)) < +inf.0

          1. Initial program 99.7%

            \[\frac{x}{y} + \frac{2 + \left(z \cdot 2\right) \cdot \left(1 - t\right)}{t \cdot z} \]
          2. Add Preprocessing
          3. Taylor expanded in z around 0

            \[\leadsto \color{blue}{\frac{2}{t \cdot z}} \]
          4. Step-by-step derivation
            1. lower-/.f64N/A

              \[\leadsto \color{blue}{\frac{2}{t \cdot z}} \]
            2. lower-*.f6493.3

              \[\leadsto \frac{2}{\color{blue}{t \cdot z}} \]
          5. Applied rewrites93.3%

            \[\leadsto \color{blue}{\frac{2}{t \cdot z}} \]
          6. Step-by-step derivation
            1. Applied rewrites93.5%

              \[\leadsto \frac{\frac{2}{t}}{\color{blue}{z}} \]
          7. Recombined 5 regimes into one program.
          8. Final simplification78.6%

            \[\leadsto \begin{array}{l} \mathbf{if}\;\frac{2 + \left(2 \cdot z\right) \cdot \left(1 - t\right)}{z \cdot t} \leq -\infty:\\ \;\;\;\;\frac{2}{z \cdot t}\\ \mathbf{elif}\;\frac{2 + \left(2 \cdot z\right) \cdot \left(1 - t\right)}{z \cdot t} \leq -1 \cdot 10^{+175}:\\ \;\;\;\;-2 + \frac{2}{t}\\ \mathbf{elif}\;\frac{2 + \left(2 \cdot z\right) \cdot \left(1 - t\right)}{z \cdot t} \leq 10^{+46}:\\ \;\;\;\;\frac{x}{y} + -2\\ \mathbf{elif}\;\frac{2 + \left(2 \cdot z\right) \cdot \left(1 - t\right)}{z \cdot t} \leq 4 \cdot 10^{+122}:\\ \;\;\;\;\frac{2}{z \cdot t}\\ \mathbf{elif}\;\frac{2 + \left(2 \cdot z\right) \cdot \left(1 - t\right)}{z \cdot t} \leq 10^{+294}:\\ \;\;\;\;\frac{2}{t}\\ \mathbf{elif}\;\frac{2 + \left(2 \cdot z\right) \cdot \left(1 - t\right)}{z \cdot t} \leq \infty:\\ \;\;\;\;\frac{\frac{2}{t}}{z}\\ \mathbf{else}:\\ \;\;\;\;\frac{x}{y} + -2\\ \end{array} \]
          9. Add Preprocessing

          Alternative 3: 70.1% accurate, 0.2× speedup?

          \[\begin{array}{l} \\ \begin{array}{l} t_1 := \frac{2}{z \cdot t}\\ t_2 := \frac{2 + \left(2 \cdot z\right) \cdot \left(1 - t\right)}{z \cdot t}\\ t_3 := \frac{x}{y} + -2\\ \mathbf{if}\;t\_2 \leq -\infty:\\ \;\;\;\;t\_1\\ \mathbf{elif}\;t\_2 \leq -1 \cdot 10^{+175}:\\ \;\;\;\;-2 + \frac{2}{t}\\ \mathbf{elif}\;t\_2 \leq 10^{+46}:\\ \;\;\;\;t\_3\\ \mathbf{elif}\;t\_2 \leq 4 \cdot 10^{+122}:\\ \;\;\;\;t\_1\\ \mathbf{elif}\;t\_2 \leq 10^{+294}:\\ \;\;\;\;\frac{2}{t}\\ \mathbf{elif}\;t\_2 \leq \infty:\\ \;\;\;\;t\_1\\ \mathbf{else}:\\ \;\;\;\;t\_3\\ \end{array} \end{array} \]
          (FPCore (x y z t)
           :precision binary64
           (let* ((t_1 (/ 2.0 (* z t)))
                  (t_2 (/ (+ 2.0 (* (* 2.0 z) (- 1.0 t))) (* z t)))
                  (t_3 (+ (/ x y) -2.0)))
             (if (<= t_2 (- INFINITY))
               t_1
               (if (<= t_2 -1e+175)
                 (+ -2.0 (/ 2.0 t))
                 (if (<= t_2 1e+46)
                   t_3
                   (if (<= t_2 4e+122)
                     t_1
                     (if (<= t_2 1e+294) (/ 2.0 t) (if (<= t_2 INFINITY) t_1 t_3))))))))
          double code(double x, double y, double z, double t) {
          	double t_1 = 2.0 / (z * t);
          	double t_2 = (2.0 + ((2.0 * z) * (1.0 - t))) / (z * t);
          	double t_3 = (x / y) + -2.0;
          	double tmp;
          	if (t_2 <= -((double) INFINITY)) {
          		tmp = t_1;
          	} else if (t_2 <= -1e+175) {
          		tmp = -2.0 + (2.0 / t);
          	} else if (t_2 <= 1e+46) {
          		tmp = t_3;
          	} else if (t_2 <= 4e+122) {
          		tmp = t_1;
          	} else if (t_2 <= 1e+294) {
          		tmp = 2.0 / t;
          	} else if (t_2 <= ((double) INFINITY)) {
          		tmp = t_1;
          	} else {
          		tmp = t_3;
          	}
          	return tmp;
          }
          
          public static double code(double x, double y, double z, double t) {
          	double t_1 = 2.0 / (z * t);
          	double t_2 = (2.0 + ((2.0 * z) * (1.0 - t))) / (z * t);
          	double t_3 = (x / y) + -2.0;
          	double tmp;
          	if (t_2 <= -Double.POSITIVE_INFINITY) {
          		tmp = t_1;
          	} else if (t_2 <= -1e+175) {
          		tmp = -2.0 + (2.0 / t);
          	} else if (t_2 <= 1e+46) {
          		tmp = t_3;
          	} else if (t_2 <= 4e+122) {
          		tmp = t_1;
          	} else if (t_2 <= 1e+294) {
          		tmp = 2.0 / t;
          	} else if (t_2 <= Double.POSITIVE_INFINITY) {
          		tmp = t_1;
          	} else {
          		tmp = t_3;
          	}
          	return tmp;
          }
          
          def code(x, y, z, t):
          	t_1 = 2.0 / (z * t)
          	t_2 = (2.0 + ((2.0 * z) * (1.0 - t))) / (z * t)
          	t_3 = (x / y) + -2.0
          	tmp = 0
          	if t_2 <= -math.inf:
          		tmp = t_1
          	elif t_2 <= -1e+175:
          		tmp = -2.0 + (2.0 / t)
          	elif t_2 <= 1e+46:
          		tmp = t_3
          	elif t_2 <= 4e+122:
          		tmp = t_1
          	elif t_2 <= 1e+294:
          		tmp = 2.0 / t
          	elif t_2 <= math.inf:
          		tmp = t_1
          	else:
          		tmp = t_3
          	return tmp
          
          function code(x, y, z, t)
          	t_1 = Float64(2.0 / Float64(z * t))
          	t_2 = Float64(Float64(2.0 + Float64(Float64(2.0 * z) * Float64(1.0 - t))) / Float64(z * t))
          	t_3 = Float64(Float64(x / y) + -2.0)
          	tmp = 0.0
          	if (t_2 <= Float64(-Inf))
          		tmp = t_1;
          	elseif (t_2 <= -1e+175)
          		tmp = Float64(-2.0 + Float64(2.0 / t));
          	elseif (t_2 <= 1e+46)
          		tmp = t_3;
          	elseif (t_2 <= 4e+122)
          		tmp = t_1;
          	elseif (t_2 <= 1e+294)
          		tmp = Float64(2.0 / t);
          	elseif (t_2 <= Inf)
          		tmp = t_1;
          	else
          		tmp = t_3;
          	end
          	return tmp
          end
          
          function tmp_2 = code(x, y, z, t)
          	t_1 = 2.0 / (z * t);
          	t_2 = (2.0 + ((2.0 * z) * (1.0 - t))) / (z * t);
          	t_3 = (x / y) + -2.0;
          	tmp = 0.0;
          	if (t_2 <= -Inf)
          		tmp = t_1;
          	elseif (t_2 <= -1e+175)
          		tmp = -2.0 + (2.0 / t);
          	elseif (t_2 <= 1e+46)
          		tmp = t_3;
          	elseif (t_2 <= 4e+122)
          		tmp = t_1;
          	elseif (t_2 <= 1e+294)
          		tmp = 2.0 / t;
          	elseif (t_2 <= Inf)
          		tmp = t_1;
          	else
          		tmp = t_3;
          	end
          	tmp_2 = tmp;
          end
          
          code[x_, y_, z_, t_] := Block[{t$95$1 = N[(2.0 / N[(z * t), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$2 = N[(N[(2.0 + N[(N[(2.0 * z), $MachinePrecision] * N[(1.0 - t), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] / N[(z * t), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$3 = N[(N[(x / y), $MachinePrecision] + -2.0), $MachinePrecision]}, If[LessEqual[t$95$2, (-Infinity)], t$95$1, If[LessEqual[t$95$2, -1e+175], N[(-2.0 + N[(2.0 / t), $MachinePrecision]), $MachinePrecision], If[LessEqual[t$95$2, 1e+46], t$95$3, If[LessEqual[t$95$2, 4e+122], t$95$1, If[LessEqual[t$95$2, 1e+294], N[(2.0 / t), $MachinePrecision], If[LessEqual[t$95$2, Infinity], t$95$1, t$95$3]]]]]]]]]
          
          \begin{array}{l}
          
          \\
          \begin{array}{l}
          t_1 := \frac{2}{z \cdot t}\\
          t_2 := \frac{2 + \left(2 \cdot z\right) \cdot \left(1 - t\right)}{z \cdot t}\\
          t_3 := \frac{x}{y} + -2\\
          \mathbf{if}\;t\_2 \leq -\infty:\\
          \;\;\;\;t\_1\\
          
          \mathbf{elif}\;t\_2 \leq -1 \cdot 10^{+175}:\\
          \;\;\;\;-2 + \frac{2}{t}\\
          
          \mathbf{elif}\;t\_2 \leq 10^{+46}:\\
          \;\;\;\;t\_3\\
          
          \mathbf{elif}\;t\_2 \leq 4 \cdot 10^{+122}:\\
          \;\;\;\;t\_1\\
          
          \mathbf{elif}\;t\_2 \leq 10^{+294}:\\
          \;\;\;\;\frac{2}{t}\\
          
          \mathbf{elif}\;t\_2 \leq \infty:\\
          \;\;\;\;t\_1\\
          
          \mathbf{else}:\\
          \;\;\;\;t\_3\\
          
          
          \end{array}
          \end{array}
          
          Derivation
          1. Split input into 4 regimes
          2. if (/.f64 (+.f64 #s(literal 2 binary64) (*.f64 (*.f64 z #s(literal 2 binary64)) (-.f64 #s(literal 1 binary64) t))) (*.f64 t z)) < -inf.0 or 9.9999999999999999e45 < (/.f64 (+.f64 #s(literal 2 binary64) (*.f64 (*.f64 z #s(literal 2 binary64)) (-.f64 #s(literal 1 binary64) t))) (*.f64 t z)) < 4.00000000000000006e122 or 1.00000000000000007e294 < (/.f64 (+.f64 #s(literal 2 binary64) (*.f64 (*.f64 z #s(literal 2 binary64)) (-.f64 #s(literal 1 binary64) t))) (*.f64 t z)) < +inf.0

            1. Initial program 96.9%

              \[\frac{x}{y} + \frac{2 + \left(z \cdot 2\right) \cdot \left(1 - t\right)}{t \cdot z} \]
            2. Add Preprocessing
            3. Taylor expanded in z around 0

              \[\leadsto \color{blue}{\frac{2}{t \cdot z}} \]
            4. Step-by-step derivation
              1. lower-/.f64N/A

                \[\leadsto \color{blue}{\frac{2}{t \cdot z}} \]
              2. lower-*.f6485.4

                \[\leadsto \frac{2}{\color{blue}{t \cdot z}} \]
            5. Applied rewrites85.4%

              \[\leadsto \color{blue}{\frac{2}{t \cdot z}} \]

            if -inf.0 < (/.f64 (+.f64 #s(literal 2 binary64) (*.f64 (*.f64 z #s(literal 2 binary64)) (-.f64 #s(literal 1 binary64) t))) (*.f64 t z)) < -9.9999999999999994e174

            1. Initial program 99.7%

              \[\frac{x}{y} + \frac{2 + \left(z \cdot 2\right) \cdot \left(1 - t\right)}{t \cdot z} \]
            2. Add Preprocessing
            3. Taylor expanded in x around 0

              \[\leadsto \color{blue}{2 \cdot \frac{1 - t}{t} + 2 \cdot \frac{1}{t \cdot z}} \]
            4. Applied rewrites80.6%

              \[\leadsto \color{blue}{\mathsf{fma}\left(\frac{2}{t \cdot z}, z + 1, -2\right)} \]
            5. Taylor expanded in z around inf

              \[\leadsto 2 \cdot \frac{1}{t} - \color{blue}{2} \]
            6. Step-by-step derivation
              1. Applied rewrites57.2%

                \[\leadsto \frac{2}{t} + \color{blue}{-2} \]

              if -9.9999999999999994e174 < (/.f64 (+.f64 #s(literal 2 binary64) (*.f64 (*.f64 z #s(literal 2 binary64)) (-.f64 #s(literal 1 binary64) t))) (*.f64 t z)) < 9.9999999999999999e45 or +inf.0 < (/.f64 (+.f64 #s(literal 2 binary64) (*.f64 (*.f64 z #s(literal 2 binary64)) (-.f64 #s(literal 1 binary64) t))) (*.f64 t z))

              1. Initial program 79.7%

                \[\frac{x}{y} + \frac{2 + \left(z \cdot 2\right) \cdot \left(1 - t\right)}{t \cdot z} \]
              2. Add Preprocessing
              3. Taylor expanded in t around inf

                \[\leadsto \frac{x}{y} + \color{blue}{-2} \]
              4. Step-by-step derivation
                1. Applied rewrites85.2%

                  \[\leadsto \frac{x}{y} + \color{blue}{-2} \]

                if 4.00000000000000006e122 < (/.f64 (+.f64 #s(literal 2 binary64) (*.f64 (*.f64 z #s(literal 2 binary64)) (-.f64 #s(literal 1 binary64) t))) (*.f64 t z)) < 1.00000000000000007e294

                1. Initial program 99.7%

                  \[\frac{x}{y} + \frac{2 + \left(z \cdot 2\right) \cdot \left(1 - t\right)}{t \cdot z} \]
                2. Add Preprocessing
                3. Taylor expanded in t around 0

                  \[\leadsto \color{blue}{\frac{2 + 2 \cdot \frac{1}{z}}{t}} \]
                4. Applied rewrites86.8%

                  \[\leadsto \color{blue}{\frac{\mathsf{fma}\left(2, z, 2\right)}{t \cdot z}} \]
                5. Taylor expanded in z around inf

                  \[\leadsto \frac{2}{\color{blue}{t}} \]
                6. Step-by-step derivation
                  1. Applied rewrites55.6%

                    \[\leadsto \frac{2}{\color{blue}{t}} \]
                7. Recombined 4 regimes into one program.
                8. Final simplification78.5%

                  \[\leadsto \begin{array}{l} \mathbf{if}\;\frac{2 + \left(2 \cdot z\right) \cdot \left(1 - t\right)}{z \cdot t} \leq -\infty:\\ \;\;\;\;\frac{2}{z \cdot t}\\ \mathbf{elif}\;\frac{2 + \left(2 \cdot z\right) \cdot \left(1 - t\right)}{z \cdot t} \leq -1 \cdot 10^{+175}:\\ \;\;\;\;-2 + \frac{2}{t}\\ \mathbf{elif}\;\frac{2 + \left(2 \cdot z\right) \cdot \left(1 - t\right)}{z \cdot t} \leq 10^{+46}:\\ \;\;\;\;\frac{x}{y} + -2\\ \mathbf{elif}\;\frac{2 + \left(2 \cdot z\right) \cdot \left(1 - t\right)}{z \cdot t} \leq 4 \cdot 10^{+122}:\\ \;\;\;\;\frac{2}{z \cdot t}\\ \mathbf{elif}\;\frac{2 + \left(2 \cdot z\right) \cdot \left(1 - t\right)}{z \cdot t} \leq 10^{+294}:\\ \;\;\;\;\frac{2}{t}\\ \mathbf{elif}\;\frac{2 + \left(2 \cdot z\right) \cdot \left(1 - t\right)}{z \cdot t} \leq \infty:\\ \;\;\;\;\frac{2}{z \cdot t}\\ \mathbf{else}:\\ \;\;\;\;\frac{x}{y} + -2\\ \end{array} \]
                9. Add Preprocessing

                Alternative 4: 84.2% accurate, 0.3× speedup?

                \[\begin{array}{l} \\ \begin{array}{l} t_1 := \frac{\mathsf{fma}\left(2, z, 2\right)}{z \cdot t}\\ t_2 := \frac{2 + \left(2 \cdot z\right) \cdot \left(1 - t\right)}{z \cdot t}\\ t_3 := \frac{x}{y} + -2\\ \mathbf{if}\;t\_2 \leq -2 \cdot 10^{+88}:\\ \;\;\;\;t\_1\\ \mathbf{elif}\;t\_2 \leq 10^{+46}:\\ \;\;\;\;t\_3\\ \mathbf{elif}\;t\_2 \leq \infty:\\ \;\;\;\;t\_1\\ \mathbf{else}:\\ \;\;\;\;t\_3\\ \end{array} \end{array} \]
                (FPCore (x y z t)
                 :precision binary64
                 (let* ((t_1 (/ (fma 2.0 z 2.0) (* z t)))
                        (t_2 (/ (+ 2.0 (* (* 2.0 z) (- 1.0 t))) (* z t)))
                        (t_3 (+ (/ x y) -2.0)))
                   (if (<= t_2 -2e+88)
                     t_1
                     (if (<= t_2 1e+46) t_3 (if (<= t_2 INFINITY) t_1 t_3)))))
                double code(double x, double y, double z, double t) {
                	double t_1 = fma(2.0, z, 2.0) / (z * t);
                	double t_2 = (2.0 + ((2.0 * z) * (1.0 - t))) / (z * t);
                	double t_3 = (x / y) + -2.0;
                	double tmp;
                	if (t_2 <= -2e+88) {
                		tmp = t_1;
                	} else if (t_2 <= 1e+46) {
                		tmp = t_3;
                	} else if (t_2 <= ((double) INFINITY)) {
                		tmp = t_1;
                	} else {
                		tmp = t_3;
                	}
                	return tmp;
                }
                
                function code(x, y, z, t)
                	t_1 = Float64(fma(2.0, z, 2.0) / Float64(z * t))
                	t_2 = Float64(Float64(2.0 + Float64(Float64(2.0 * z) * Float64(1.0 - t))) / Float64(z * t))
                	t_3 = Float64(Float64(x / y) + -2.0)
                	tmp = 0.0
                	if (t_2 <= -2e+88)
                		tmp = t_1;
                	elseif (t_2 <= 1e+46)
                		tmp = t_3;
                	elseif (t_2 <= Inf)
                		tmp = t_1;
                	else
                		tmp = t_3;
                	end
                	return tmp
                end
                
                code[x_, y_, z_, t_] := Block[{t$95$1 = N[(N[(2.0 * z + 2.0), $MachinePrecision] / N[(z * t), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$2 = N[(N[(2.0 + N[(N[(2.0 * z), $MachinePrecision] * N[(1.0 - t), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] / N[(z * t), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$3 = N[(N[(x / y), $MachinePrecision] + -2.0), $MachinePrecision]}, If[LessEqual[t$95$2, -2e+88], t$95$1, If[LessEqual[t$95$2, 1e+46], t$95$3, If[LessEqual[t$95$2, Infinity], t$95$1, t$95$3]]]]]]
                
                \begin{array}{l}
                
                \\
                \begin{array}{l}
                t_1 := \frac{\mathsf{fma}\left(2, z, 2\right)}{z \cdot t}\\
                t_2 := \frac{2 + \left(2 \cdot z\right) \cdot \left(1 - t\right)}{z \cdot t}\\
                t_3 := \frac{x}{y} + -2\\
                \mathbf{if}\;t\_2 \leq -2 \cdot 10^{+88}:\\
                \;\;\;\;t\_1\\
                
                \mathbf{elif}\;t\_2 \leq 10^{+46}:\\
                \;\;\;\;t\_3\\
                
                \mathbf{elif}\;t\_2 \leq \infty:\\
                \;\;\;\;t\_1\\
                
                \mathbf{else}:\\
                \;\;\;\;t\_3\\
                
                
                \end{array}
                \end{array}
                
                Derivation
                1. Split input into 2 regimes
                2. if (/.f64 (+.f64 #s(literal 2 binary64) (*.f64 (*.f64 z #s(literal 2 binary64)) (-.f64 #s(literal 1 binary64) t))) (*.f64 t z)) < -1.99999999999999992e88 or 9.9999999999999999e45 < (/.f64 (+.f64 #s(literal 2 binary64) (*.f64 (*.f64 z #s(literal 2 binary64)) (-.f64 #s(literal 1 binary64) t))) (*.f64 t z)) < +inf.0

                  1. Initial program 98.9%

                    \[\frac{x}{y} + \frac{2 + \left(z \cdot 2\right) \cdot \left(1 - t\right)}{t \cdot z} \]
                  2. Add Preprocessing
                  3. Taylor expanded in t around 0

                    \[\leadsto \color{blue}{\frac{2 + 2 \cdot \frac{1}{z}}{t}} \]
                  4. Applied rewrites80.8%

                    \[\leadsto \color{blue}{\frac{\mathsf{fma}\left(2, z, 2\right)}{t \cdot z}} \]

                  if -1.99999999999999992e88 < (/.f64 (+.f64 #s(literal 2 binary64) (*.f64 (*.f64 z #s(literal 2 binary64)) (-.f64 #s(literal 1 binary64) t))) (*.f64 t z)) < 9.9999999999999999e45 or +inf.0 < (/.f64 (+.f64 #s(literal 2 binary64) (*.f64 (*.f64 z #s(literal 2 binary64)) (-.f64 #s(literal 1 binary64) t))) (*.f64 t z))

                  1. Initial program 76.7%

                    \[\frac{x}{y} + \frac{2 + \left(z \cdot 2\right) \cdot \left(1 - t\right)}{t \cdot z} \]
                  2. Add Preprocessing
                  3. Taylor expanded in t around inf

                    \[\leadsto \frac{x}{y} + \color{blue}{-2} \]
                  4. Step-by-step derivation
                    1. Applied rewrites91.0%

                      \[\leadsto \frac{x}{y} + \color{blue}{-2} \]
                  5. Recombined 2 regimes into one program.
                  6. Final simplification86.5%

                    \[\leadsto \begin{array}{l} \mathbf{if}\;\frac{2 + \left(2 \cdot z\right) \cdot \left(1 - t\right)}{z \cdot t} \leq -2 \cdot 10^{+88}:\\ \;\;\;\;\frac{\mathsf{fma}\left(2, z, 2\right)}{z \cdot t}\\ \mathbf{elif}\;\frac{2 + \left(2 \cdot z\right) \cdot \left(1 - t\right)}{z \cdot t} \leq 10^{+46}:\\ \;\;\;\;\frac{x}{y} + -2\\ \mathbf{elif}\;\frac{2 + \left(2 \cdot z\right) \cdot \left(1 - t\right)}{z \cdot t} \leq \infty:\\ \;\;\;\;\frac{\mathsf{fma}\left(2, z, 2\right)}{z \cdot t}\\ \mathbf{else}:\\ \;\;\;\;\frac{x}{y} + -2\\ \end{array} \]
                  7. Add Preprocessing

                  Alternative 5: 89.0% accurate, 0.8× speedup?

                  \[\begin{array}{l} \\ \begin{array}{l} t_1 := \frac{x}{y} + \frac{2}{t}\\ \mathbf{if}\;\frac{x}{y} \leq -2 \cdot 10^{+18}:\\ \;\;\;\;t\_1\\ \mathbf{elif}\;\frac{x}{y} \leq 20000000000000:\\ \;\;\;\;\mathsf{fma}\left(\frac{2}{z \cdot t}, z + 1, -2\right)\\ \mathbf{else}:\\ \;\;\;\;t\_1\\ \end{array} \end{array} \]
                  (FPCore (x y z t)
                   :precision binary64
                   (let* ((t_1 (+ (/ x y) (/ 2.0 t))))
                     (if (<= (/ x y) -2e+18)
                       t_1
                       (if (<= (/ x y) 20000000000000.0)
                         (fma (/ 2.0 (* z t)) (+ z 1.0) -2.0)
                         t_1))))
                  double code(double x, double y, double z, double t) {
                  	double t_1 = (x / y) + (2.0 / t);
                  	double tmp;
                  	if ((x / y) <= -2e+18) {
                  		tmp = t_1;
                  	} else if ((x / y) <= 20000000000000.0) {
                  		tmp = fma((2.0 / (z * t)), (z + 1.0), -2.0);
                  	} else {
                  		tmp = t_1;
                  	}
                  	return tmp;
                  }
                  
                  function code(x, y, z, t)
                  	t_1 = Float64(Float64(x / y) + Float64(2.0 / t))
                  	tmp = 0.0
                  	if (Float64(x / y) <= -2e+18)
                  		tmp = t_1;
                  	elseif (Float64(x / y) <= 20000000000000.0)
                  		tmp = fma(Float64(2.0 / Float64(z * t)), Float64(z + 1.0), -2.0);
                  	else
                  		tmp = t_1;
                  	end
                  	return tmp
                  end
                  
                  code[x_, y_, z_, t_] := Block[{t$95$1 = N[(N[(x / y), $MachinePrecision] + N[(2.0 / t), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[N[(x / y), $MachinePrecision], -2e+18], t$95$1, If[LessEqual[N[(x / y), $MachinePrecision], 20000000000000.0], N[(N[(2.0 / N[(z * t), $MachinePrecision]), $MachinePrecision] * N[(z + 1.0), $MachinePrecision] + -2.0), $MachinePrecision], t$95$1]]]
                  
                  \begin{array}{l}
                  
                  \\
                  \begin{array}{l}
                  t_1 := \frac{x}{y} + \frac{2}{t}\\
                  \mathbf{if}\;\frac{x}{y} \leq -2 \cdot 10^{+18}:\\
                  \;\;\;\;t\_1\\
                  
                  \mathbf{elif}\;\frac{x}{y} \leq 20000000000000:\\
                  \;\;\;\;\mathsf{fma}\left(\frac{2}{z \cdot t}, z + 1, -2\right)\\
                  
                  \mathbf{else}:\\
                  \;\;\;\;t\_1\\
                  
                  
                  \end{array}
                  \end{array}
                  
                  Derivation
                  1. Split input into 2 regimes
                  2. if (/.f64 x y) < -2e18 or 2e13 < (/.f64 x y)

                    1. Initial program 82.6%

                      \[\frac{x}{y} + \frac{2 + \left(z \cdot 2\right) \cdot \left(1 - t\right)}{t \cdot z} \]
                    2. Add Preprocessing
                    3. Taylor expanded in z around inf

                      \[\leadsto \frac{x}{y} + \color{blue}{2 \cdot \frac{1 - t}{t}} \]
                    4. Step-by-step derivation
                      1. div-subN/A

                        \[\leadsto \frac{x}{y} + 2 \cdot \color{blue}{\left(\frac{1}{t} - \frac{t}{t}\right)} \]
                      2. sub-negN/A

                        \[\leadsto \frac{x}{y} + 2 \cdot \color{blue}{\left(\frac{1}{t} + \left(\mathsf{neg}\left(\frac{t}{t}\right)\right)\right)} \]
                      3. *-inversesN/A

                        \[\leadsto \frac{x}{y} + 2 \cdot \left(\frac{1}{t} + \left(\mathsf{neg}\left(\color{blue}{1}\right)\right)\right) \]
                      4. metadata-evalN/A

                        \[\leadsto \frac{x}{y} + 2 \cdot \left(\frac{1}{t} + \color{blue}{-1}\right) \]
                      5. distribute-lft-inN/A

                        \[\leadsto \frac{x}{y} + \color{blue}{\left(2 \cdot \frac{1}{t} + 2 \cdot -1\right)} \]
                      6. metadata-evalN/A

                        \[\leadsto \frac{x}{y} + \left(2 \cdot \frac{1}{t} + \color{blue}{-2}\right) \]
                      7. lower-+.f64N/A

                        \[\leadsto \frac{x}{y} + \color{blue}{\left(2 \cdot \frac{1}{t} + -2\right)} \]
                      8. associate-*r/N/A

                        \[\leadsto \frac{x}{y} + \left(\color{blue}{\frac{2 \cdot 1}{t}} + -2\right) \]
                      9. metadata-evalN/A

                        \[\leadsto \frac{x}{y} + \left(\frac{\color{blue}{2}}{t} + -2\right) \]
                      10. lower-/.f6487.0

                        \[\leadsto \frac{x}{y} + \left(\color{blue}{\frac{2}{t}} + -2\right) \]
                    5. Applied rewrites87.0%

                      \[\leadsto \frac{x}{y} + \color{blue}{\left(\frac{2}{t} + -2\right)} \]
                    6. Taylor expanded in t around 0

                      \[\leadsto \frac{x}{y} + \frac{2}{\color{blue}{t}} \]
                    7. Step-by-step derivation
                      1. Applied rewrites87.0%

                        \[\leadsto \frac{x}{y} + \frac{2}{\color{blue}{t}} \]

                      if -2e18 < (/.f64 x y) < 2e13

                      1. Initial program 90.8%

                        \[\frac{x}{y} + \frac{2 + \left(z \cdot 2\right) \cdot \left(1 - t\right)}{t \cdot z} \]
                      2. Add Preprocessing
                      3. Taylor expanded in x around 0

                        \[\leadsto \color{blue}{2 \cdot \frac{1 - t}{t} + 2 \cdot \frac{1}{t \cdot z}} \]
                      4. Applied rewrites97.7%

                        \[\leadsto \color{blue}{\mathsf{fma}\left(\frac{2}{t \cdot z}, z + 1, -2\right)} \]
                    8. Recombined 2 regimes into one program.
                    9. Final simplification92.2%

                      \[\leadsto \begin{array}{l} \mathbf{if}\;\frac{x}{y} \leq -2 \cdot 10^{+18}:\\ \;\;\;\;\frac{x}{y} + \frac{2}{t}\\ \mathbf{elif}\;\frac{x}{y} \leq 20000000000000:\\ \;\;\;\;\mathsf{fma}\left(\frac{2}{z \cdot t}, z + 1, -2\right)\\ \mathbf{else}:\\ \;\;\;\;\frac{x}{y} + \frac{2}{t}\\ \end{array} \]
                    10. Add Preprocessing

                    Alternative 6: 84.4% accurate, 0.8× speedup?

                    \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;\frac{x}{y} \leq -2.6 \cdot 10^{+17}:\\ \;\;\;\;\frac{x}{y}\\ \mathbf{elif}\;\frac{x}{y} \leq 1.05 \cdot 10^{+158}:\\ \;\;\;\;\mathsf{fma}\left(\frac{2}{z \cdot t}, z + 1, -2\right)\\ \mathbf{else}:\\ \;\;\;\;\frac{x}{y}\\ \end{array} \end{array} \]
                    (FPCore (x y z t)
                     :precision binary64
                     (if (<= (/ x y) -2.6e+17)
                       (/ x y)
                       (if (<= (/ x y) 1.05e+158) (fma (/ 2.0 (* z t)) (+ z 1.0) -2.0) (/ x y))))
                    double code(double x, double y, double z, double t) {
                    	double tmp;
                    	if ((x / y) <= -2.6e+17) {
                    		tmp = x / y;
                    	} else if ((x / y) <= 1.05e+158) {
                    		tmp = fma((2.0 / (z * t)), (z + 1.0), -2.0);
                    	} else {
                    		tmp = x / y;
                    	}
                    	return tmp;
                    }
                    
                    function code(x, y, z, t)
                    	tmp = 0.0
                    	if (Float64(x / y) <= -2.6e+17)
                    		tmp = Float64(x / y);
                    	elseif (Float64(x / y) <= 1.05e+158)
                    		tmp = fma(Float64(2.0 / Float64(z * t)), Float64(z + 1.0), -2.0);
                    	else
                    		tmp = Float64(x / y);
                    	end
                    	return tmp
                    end
                    
                    code[x_, y_, z_, t_] := If[LessEqual[N[(x / y), $MachinePrecision], -2.6e+17], N[(x / y), $MachinePrecision], If[LessEqual[N[(x / y), $MachinePrecision], 1.05e+158], N[(N[(2.0 / N[(z * t), $MachinePrecision]), $MachinePrecision] * N[(z + 1.0), $MachinePrecision] + -2.0), $MachinePrecision], N[(x / y), $MachinePrecision]]]
                    
                    \begin{array}{l}
                    
                    \\
                    \begin{array}{l}
                    \mathbf{if}\;\frac{x}{y} \leq -2.6 \cdot 10^{+17}:\\
                    \;\;\;\;\frac{x}{y}\\
                    
                    \mathbf{elif}\;\frac{x}{y} \leq 1.05 \cdot 10^{+158}:\\
                    \;\;\;\;\mathsf{fma}\left(\frac{2}{z \cdot t}, z + 1, -2\right)\\
                    
                    \mathbf{else}:\\
                    \;\;\;\;\frac{x}{y}\\
                    
                    
                    \end{array}
                    \end{array}
                    
                    Derivation
                    1. Split input into 2 regimes
                    2. if (/.f64 x y) < -2.6e17 or 1.0499999999999999e158 < (/.f64 x y)

                      1. Initial program 82.4%

                        \[\frac{x}{y} + \frac{2 + \left(z \cdot 2\right) \cdot \left(1 - t\right)}{t \cdot z} \]
                      2. Add Preprocessing
                      3. Taylor expanded in x around inf

                        \[\leadsto \color{blue}{\frac{x}{y}} \]
                      4. Step-by-step derivation
                        1. lower-/.f6482.3

                          \[\leadsto \color{blue}{\frac{x}{y}} \]
                      5. Applied rewrites82.3%

                        \[\leadsto \color{blue}{\frac{x}{y}} \]

                      if -2.6e17 < (/.f64 x y) < 1.0499999999999999e158

                      1. Initial program 89.6%

                        \[\frac{x}{y} + \frac{2 + \left(z \cdot 2\right) \cdot \left(1 - t\right)}{t \cdot z} \]
                      2. Add Preprocessing
                      3. Taylor expanded in x around 0

                        \[\leadsto \color{blue}{2 \cdot \frac{1 - t}{t} + 2 \cdot \frac{1}{t \cdot z}} \]
                      4. Applied rewrites89.7%

                        \[\leadsto \color{blue}{\mathsf{fma}\left(\frac{2}{t \cdot z}, z + 1, -2\right)} \]
                    3. Recombined 2 regimes into one program.
                    4. Final simplification86.6%

                      \[\leadsto \begin{array}{l} \mathbf{if}\;\frac{x}{y} \leq -2.6 \cdot 10^{+17}:\\ \;\;\;\;\frac{x}{y}\\ \mathbf{elif}\;\frac{x}{y} \leq 1.05 \cdot 10^{+158}:\\ \;\;\;\;\mathsf{fma}\left(\frac{2}{z \cdot t}, z + 1, -2\right)\\ \mathbf{else}:\\ \;\;\;\;\frac{x}{y}\\ \end{array} \]
                    5. Add Preprocessing

                    Alternative 7: 65.7% accurate, 1.0× speedup?

                    \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;\frac{x}{y} \leq -4.4 \cdot 10^{+15}:\\ \;\;\;\;\frac{x}{y}\\ \mathbf{elif}\;\frac{x}{y} \leq 4800000:\\ \;\;\;\;-2 + \frac{2}{t}\\ \mathbf{else}:\\ \;\;\;\;\frac{x}{y}\\ \end{array} \end{array} \]
                    (FPCore (x y z t)
                     :precision binary64
                     (if (<= (/ x y) -4.4e+15)
                       (/ x y)
                       (if (<= (/ x y) 4800000.0) (+ -2.0 (/ 2.0 t)) (/ x y))))
                    double code(double x, double y, double z, double t) {
                    	double tmp;
                    	if ((x / y) <= -4.4e+15) {
                    		tmp = x / y;
                    	} else if ((x / y) <= 4800000.0) {
                    		tmp = -2.0 + (2.0 / t);
                    	} else {
                    		tmp = x / y;
                    	}
                    	return tmp;
                    }
                    
                    real(8) function code(x, y, z, t)
                        real(8), intent (in) :: x
                        real(8), intent (in) :: y
                        real(8), intent (in) :: z
                        real(8), intent (in) :: t
                        real(8) :: tmp
                        if ((x / y) <= (-4.4d+15)) then
                            tmp = x / y
                        else if ((x / y) <= 4800000.0d0) then
                            tmp = (-2.0d0) + (2.0d0 / t)
                        else
                            tmp = x / y
                        end if
                        code = tmp
                    end function
                    
                    public static double code(double x, double y, double z, double t) {
                    	double tmp;
                    	if ((x / y) <= -4.4e+15) {
                    		tmp = x / y;
                    	} else if ((x / y) <= 4800000.0) {
                    		tmp = -2.0 + (2.0 / t);
                    	} else {
                    		tmp = x / y;
                    	}
                    	return tmp;
                    }
                    
                    def code(x, y, z, t):
                    	tmp = 0
                    	if (x / y) <= -4.4e+15:
                    		tmp = x / y
                    	elif (x / y) <= 4800000.0:
                    		tmp = -2.0 + (2.0 / t)
                    	else:
                    		tmp = x / y
                    	return tmp
                    
                    function code(x, y, z, t)
                    	tmp = 0.0
                    	if (Float64(x / y) <= -4.4e+15)
                    		tmp = Float64(x / y);
                    	elseif (Float64(x / y) <= 4800000.0)
                    		tmp = Float64(-2.0 + Float64(2.0 / t));
                    	else
                    		tmp = Float64(x / y);
                    	end
                    	return tmp
                    end
                    
                    function tmp_2 = code(x, y, z, t)
                    	tmp = 0.0;
                    	if ((x / y) <= -4.4e+15)
                    		tmp = x / y;
                    	elseif ((x / y) <= 4800000.0)
                    		tmp = -2.0 + (2.0 / t);
                    	else
                    		tmp = x / y;
                    	end
                    	tmp_2 = tmp;
                    end
                    
                    code[x_, y_, z_, t_] := If[LessEqual[N[(x / y), $MachinePrecision], -4.4e+15], N[(x / y), $MachinePrecision], If[LessEqual[N[(x / y), $MachinePrecision], 4800000.0], N[(-2.0 + N[(2.0 / t), $MachinePrecision]), $MachinePrecision], N[(x / y), $MachinePrecision]]]
                    
                    \begin{array}{l}
                    
                    \\
                    \begin{array}{l}
                    \mathbf{if}\;\frac{x}{y} \leq -4.4 \cdot 10^{+15}:\\
                    \;\;\;\;\frac{x}{y}\\
                    
                    \mathbf{elif}\;\frac{x}{y} \leq 4800000:\\
                    \;\;\;\;-2 + \frac{2}{t}\\
                    
                    \mathbf{else}:\\
                    \;\;\;\;\frac{x}{y}\\
                    
                    
                    \end{array}
                    \end{array}
                    
                    Derivation
                    1. Split input into 2 regimes
                    2. if (/.f64 x y) < -4.4e15 or 4.8e6 < (/.f64 x y)

                      1. Initial program 82.8%

                        \[\frac{x}{y} + \frac{2 + \left(z \cdot 2\right) \cdot \left(1 - t\right)}{t \cdot z} \]
                      2. Add Preprocessing
                      3. Taylor expanded in x around inf

                        \[\leadsto \color{blue}{\frac{x}{y}} \]
                      4. Step-by-step derivation
                        1. lower-/.f6475.6

                          \[\leadsto \color{blue}{\frac{x}{y}} \]
                      5. Applied rewrites75.6%

                        \[\leadsto \color{blue}{\frac{x}{y}} \]

                      if -4.4e15 < (/.f64 x y) < 4.8e6

                      1. Initial program 90.7%

                        \[\frac{x}{y} + \frac{2 + \left(z \cdot 2\right) \cdot \left(1 - t\right)}{t \cdot z} \]
                      2. Add Preprocessing
                      3. Taylor expanded in x around 0

                        \[\leadsto \color{blue}{2 \cdot \frac{1 - t}{t} + 2 \cdot \frac{1}{t \cdot z}} \]
                      4. Applied rewrites97.7%

                        \[\leadsto \color{blue}{\mathsf{fma}\left(\frac{2}{t \cdot z}, z + 1, -2\right)} \]
                      5. Taylor expanded in z around inf

                        \[\leadsto 2 \cdot \frac{1}{t} - \color{blue}{2} \]
                      6. Step-by-step derivation
                        1. Applied rewrites66.3%

                          \[\leadsto \frac{2}{t} + \color{blue}{-2} \]
                      7. Recombined 2 regimes into one program.
                      8. Final simplification71.2%

                        \[\leadsto \begin{array}{l} \mathbf{if}\;\frac{x}{y} \leq -4.4 \cdot 10^{+15}:\\ \;\;\;\;\frac{x}{y}\\ \mathbf{elif}\;\frac{x}{y} \leq 4800000:\\ \;\;\;\;-2 + \frac{2}{t}\\ \mathbf{else}:\\ \;\;\;\;\frac{x}{y}\\ \end{array} \]
                      9. Add Preprocessing

                      Alternative 8: 52.8% accurate, 1.0× speedup?

                      \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;\frac{x}{y} \leq -4.1 \cdot 10^{+15}:\\ \;\;\;\;\frac{x}{y}\\ \mathbf{elif}\;\frac{x}{y} \leq 2.5 \cdot 10^{-7}:\\ \;\;\;\;-2\\ \mathbf{else}:\\ \;\;\;\;\frac{x}{y}\\ \end{array} \end{array} \]
                      (FPCore (x y z t)
                       :precision binary64
                       (if (<= (/ x y) -4.1e+15) (/ x y) (if (<= (/ x y) 2.5e-7) -2.0 (/ x y))))
                      double code(double x, double y, double z, double t) {
                      	double tmp;
                      	if ((x / y) <= -4.1e+15) {
                      		tmp = x / y;
                      	} else if ((x / y) <= 2.5e-7) {
                      		tmp = -2.0;
                      	} else {
                      		tmp = x / y;
                      	}
                      	return tmp;
                      }
                      
                      real(8) function code(x, y, z, t)
                          real(8), intent (in) :: x
                          real(8), intent (in) :: y
                          real(8), intent (in) :: z
                          real(8), intent (in) :: t
                          real(8) :: tmp
                          if ((x / y) <= (-4.1d+15)) then
                              tmp = x / y
                          else if ((x / y) <= 2.5d-7) then
                              tmp = -2.0d0
                          else
                              tmp = x / y
                          end if
                          code = tmp
                      end function
                      
                      public static double code(double x, double y, double z, double t) {
                      	double tmp;
                      	if ((x / y) <= -4.1e+15) {
                      		tmp = x / y;
                      	} else if ((x / y) <= 2.5e-7) {
                      		tmp = -2.0;
                      	} else {
                      		tmp = x / y;
                      	}
                      	return tmp;
                      }
                      
                      def code(x, y, z, t):
                      	tmp = 0
                      	if (x / y) <= -4.1e+15:
                      		tmp = x / y
                      	elif (x / y) <= 2.5e-7:
                      		tmp = -2.0
                      	else:
                      		tmp = x / y
                      	return tmp
                      
                      function code(x, y, z, t)
                      	tmp = 0.0
                      	if (Float64(x / y) <= -4.1e+15)
                      		tmp = Float64(x / y);
                      	elseif (Float64(x / y) <= 2.5e-7)
                      		tmp = -2.0;
                      	else
                      		tmp = Float64(x / y);
                      	end
                      	return tmp
                      end
                      
                      function tmp_2 = code(x, y, z, t)
                      	tmp = 0.0;
                      	if ((x / y) <= -4.1e+15)
                      		tmp = x / y;
                      	elseif ((x / y) <= 2.5e-7)
                      		tmp = -2.0;
                      	else
                      		tmp = x / y;
                      	end
                      	tmp_2 = tmp;
                      end
                      
                      code[x_, y_, z_, t_] := If[LessEqual[N[(x / y), $MachinePrecision], -4.1e+15], N[(x / y), $MachinePrecision], If[LessEqual[N[(x / y), $MachinePrecision], 2.5e-7], -2.0, N[(x / y), $MachinePrecision]]]
                      
                      \begin{array}{l}
                      
                      \\
                      \begin{array}{l}
                      \mathbf{if}\;\frac{x}{y} \leq -4.1 \cdot 10^{+15}:\\
                      \;\;\;\;\frac{x}{y}\\
                      
                      \mathbf{elif}\;\frac{x}{y} \leq 2.5 \cdot 10^{-7}:\\
                      \;\;\;\;-2\\
                      
                      \mathbf{else}:\\
                      \;\;\;\;\frac{x}{y}\\
                      
                      
                      \end{array}
                      \end{array}
                      
                      Derivation
                      1. Split input into 2 regimes
                      2. if (/.f64 x y) < -4.1e15 or 2.49999999999999989e-7 < (/.f64 x y)

                        1. Initial program 83.1%

                          \[\frac{x}{y} + \frac{2 + \left(z \cdot 2\right) \cdot \left(1 - t\right)}{t \cdot z} \]
                        2. Add Preprocessing
                        3. Taylor expanded in x around inf

                          \[\leadsto \color{blue}{\frac{x}{y}} \]
                        4. Step-by-step derivation
                          1. lower-/.f6474.1

                            \[\leadsto \color{blue}{\frac{x}{y}} \]
                        5. Applied rewrites74.1%

                          \[\leadsto \color{blue}{\frac{x}{y}} \]

                        if -4.1e15 < (/.f64 x y) < 2.49999999999999989e-7

                        1. Initial program 90.5%

                          \[\frac{x}{y} + \frac{2 + \left(z \cdot 2\right) \cdot \left(1 - t\right)}{t \cdot z} \]
                        2. Add Preprocessing
                        3. Taylor expanded in x around 0

                          \[\leadsto \color{blue}{2 \cdot \frac{1 - t}{t} + 2 \cdot \frac{1}{t \cdot z}} \]
                        4. Applied rewrites98.1%

                          \[\leadsto \color{blue}{\mathsf{fma}\left(\frac{2}{t \cdot z}, z + 1, -2\right)} \]
                        5. Taylor expanded in t around inf

                          \[\leadsto -2 \]
                        6. Step-by-step derivation
                          1. Applied rewrites42.0%

                            \[\leadsto -2 \]
                        7. Recombined 2 regimes into one program.
                        8. Add Preprocessing

                        Alternative 9: 92.1% accurate, 1.1× speedup?

                        \[\begin{array}{l} \\ \begin{array}{l} t_1 := \frac{x}{y} + \left(-2 + \frac{2}{t}\right)\\ \mathbf{if}\;z \leq -1.3 \cdot 10^{-28}:\\ \;\;\;\;t\_1\\ \mathbf{elif}\;z \leq 1.3 \cdot 10^{-10}:\\ \;\;\;\;\frac{x}{y} + \frac{2}{z \cdot t}\\ \mathbf{else}:\\ \;\;\;\;t\_1\\ \end{array} \end{array} \]
                        (FPCore (x y z t)
                         :precision binary64
                         (let* ((t_1 (+ (/ x y) (+ -2.0 (/ 2.0 t)))))
                           (if (<= z -1.3e-28)
                             t_1
                             (if (<= z 1.3e-10) (+ (/ x y) (/ 2.0 (* z t))) t_1))))
                        double code(double x, double y, double z, double t) {
                        	double t_1 = (x / y) + (-2.0 + (2.0 / t));
                        	double tmp;
                        	if (z <= -1.3e-28) {
                        		tmp = t_1;
                        	} else if (z <= 1.3e-10) {
                        		tmp = (x / y) + (2.0 / (z * t));
                        	} else {
                        		tmp = t_1;
                        	}
                        	return tmp;
                        }
                        
                        real(8) function code(x, y, z, t)
                            real(8), intent (in) :: x
                            real(8), intent (in) :: y
                            real(8), intent (in) :: z
                            real(8), intent (in) :: t
                            real(8) :: t_1
                            real(8) :: tmp
                            t_1 = (x / y) + ((-2.0d0) + (2.0d0 / t))
                            if (z <= (-1.3d-28)) then
                                tmp = t_1
                            else if (z <= 1.3d-10) then
                                tmp = (x / y) + (2.0d0 / (z * t))
                            else
                                tmp = t_1
                            end if
                            code = tmp
                        end function
                        
                        public static double code(double x, double y, double z, double t) {
                        	double t_1 = (x / y) + (-2.0 + (2.0 / t));
                        	double tmp;
                        	if (z <= -1.3e-28) {
                        		tmp = t_1;
                        	} else if (z <= 1.3e-10) {
                        		tmp = (x / y) + (2.0 / (z * t));
                        	} else {
                        		tmp = t_1;
                        	}
                        	return tmp;
                        }
                        
                        def code(x, y, z, t):
                        	t_1 = (x / y) + (-2.0 + (2.0 / t))
                        	tmp = 0
                        	if z <= -1.3e-28:
                        		tmp = t_1
                        	elif z <= 1.3e-10:
                        		tmp = (x / y) + (2.0 / (z * t))
                        	else:
                        		tmp = t_1
                        	return tmp
                        
                        function code(x, y, z, t)
                        	t_1 = Float64(Float64(x / y) + Float64(-2.0 + Float64(2.0 / t)))
                        	tmp = 0.0
                        	if (z <= -1.3e-28)
                        		tmp = t_1;
                        	elseif (z <= 1.3e-10)
                        		tmp = Float64(Float64(x / y) + Float64(2.0 / Float64(z * t)));
                        	else
                        		tmp = t_1;
                        	end
                        	return tmp
                        end
                        
                        function tmp_2 = code(x, y, z, t)
                        	t_1 = (x / y) + (-2.0 + (2.0 / t));
                        	tmp = 0.0;
                        	if (z <= -1.3e-28)
                        		tmp = t_1;
                        	elseif (z <= 1.3e-10)
                        		tmp = (x / y) + (2.0 / (z * t));
                        	else
                        		tmp = t_1;
                        	end
                        	tmp_2 = tmp;
                        end
                        
                        code[x_, y_, z_, t_] := Block[{t$95$1 = N[(N[(x / y), $MachinePrecision] + N[(-2.0 + N[(2.0 / t), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[z, -1.3e-28], t$95$1, If[LessEqual[z, 1.3e-10], N[(N[(x / y), $MachinePrecision] + N[(2.0 / N[(z * t), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], t$95$1]]]
                        
                        \begin{array}{l}
                        
                        \\
                        \begin{array}{l}
                        t_1 := \frac{x}{y} + \left(-2 + \frac{2}{t}\right)\\
                        \mathbf{if}\;z \leq -1.3 \cdot 10^{-28}:\\
                        \;\;\;\;t\_1\\
                        
                        \mathbf{elif}\;z \leq 1.3 \cdot 10^{-10}:\\
                        \;\;\;\;\frac{x}{y} + \frac{2}{z \cdot t}\\
                        
                        \mathbf{else}:\\
                        \;\;\;\;t\_1\\
                        
                        
                        \end{array}
                        \end{array}
                        
                        Derivation
                        1. Split input into 2 regimes
                        2. if z < -1.3e-28 or 1.29999999999999991e-10 < z

                          1. Initial program 78.9%

                            \[\frac{x}{y} + \frac{2 + \left(z \cdot 2\right) \cdot \left(1 - t\right)}{t \cdot z} \]
                          2. Add Preprocessing
                          3. Taylor expanded in z around inf

                            \[\leadsto \frac{x}{y} + \color{blue}{2 \cdot \frac{1 - t}{t}} \]
                          4. Step-by-step derivation
                            1. div-subN/A

                              \[\leadsto \frac{x}{y} + 2 \cdot \color{blue}{\left(\frac{1}{t} - \frac{t}{t}\right)} \]
                            2. sub-negN/A

                              \[\leadsto \frac{x}{y} + 2 \cdot \color{blue}{\left(\frac{1}{t} + \left(\mathsf{neg}\left(\frac{t}{t}\right)\right)\right)} \]
                            3. *-inversesN/A

                              \[\leadsto \frac{x}{y} + 2 \cdot \left(\frac{1}{t} + \left(\mathsf{neg}\left(\color{blue}{1}\right)\right)\right) \]
                            4. metadata-evalN/A

                              \[\leadsto \frac{x}{y} + 2 \cdot \left(\frac{1}{t} + \color{blue}{-1}\right) \]
                            5. distribute-lft-inN/A

                              \[\leadsto \frac{x}{y} + \color{blue}{\left(2 \cdot \frac{1}{t} + 2 \cdot -1\right)} \]
                            6. metadata-evalN/A

                              \[\leadsto \frac{x}{y} + \left(2 \cdot \frac{1}{t} + \color{blue}{-2}\right) \]
                            7. lower-+.f64N/A

                              \[\leadsto \frac{x}{y} + \color{blue}{\left(2 \cdot \frac{1}{t} + -2\right)} \]
                            8. associate-*r/N/A

                              \[\leadsto \frac{x}{y} + \left(\color{blue}{\frac{2 \cdot 1}{t}} + -2\right) \]
                            9. metadata-evalN/A

                              \[\leadsto \frac{x}{y} + \left(\frac{\color{blue}{2}}{t} + -2\right) \]
                            10. lower-/.f6497.6

                              \[\leadsto \frac{x}{y} + \left(\color{blue}{\frac{2}{t}} + -2\right) \]
                          5. Applied rewrites97.6%

                            \[\leadsto \frac{x}{y} + \color{blue}{\left(\frac{2}{t} + -2\right)} \]

                          if -1.3e-28 < z < 1.29999999999999991e-10

                          1. Initial program 99.8%

                            \[\frac{x}{y} + \frac{2 + \left(z \cdot 2\right) \cdot \left(1 - t\right)}{t \cdot z} \]
                          2. Add Preprocessing
                          3. Taylor expanded in z around 0

                            \[\leadsto \frac{x}{y} + \frac{\color{blue}{2}}{t \cdot z} \]
                          4. Step-by-step derivation
                            1. Applied rewrites87.2%

                              \[\leadsto \frac{x}{y} + \frac{\color{blue}{2}}{t \cdot z} \]
                          5. Recombined 2 regimes into one program.
                          6. Final simplification93.8%

                            \[\leadsto \begin{array}{l} \mathbf{if}\;z \leq -1.3 \cdot 10^{-28}:\\ \;\;\;\;\frac{x}{y} + \left(-2 + \frac{2}{t}\right)\\ \mathbf{elif}\;z \leq 1.3 \cdot 10^{-10}:\\ \;\;\;\;\frac{x}{y} + \frac{2}{z \cdot t}\\ \mathbf{else}:\\ \;\;\;\;\frac{x}{y} + \left(-2 + \frac{2}{t}\right)\\ \end{array} \]
                          7. Add Preprocessing

                          Alternative 10: 37.2% accurate, 2.0× speedup?

                          \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;t \leq -1:\\ \;\;\;\;-2\\ \mathbf{elif}\;t \leq 1:\\ \;\;\;\;\frac{2}{t}\\ \mathbf{else}:\\ \;\;\;\;-2\\ \end{array} \end{array} \]
                          (FPCore (x y z t)
                           :precision binary64
                           (if (<= t -1.0) -2.0 (if (<= t 1.0) (/ 2.0 t) -2.0)))
                          double code(double x, double y, double z, double t) {
                          	double tmp;
                          	if (t <= -1.0) {
                          		tmp = -2.0;
                          	} else if (t <= 1.0) {
                          		tmp = 2.0 / t;
                          	} else {
                          		tmp = -2.0;
                          	}
                          	return tmp;
                          }
                          
                          real(8) function code(x, y, z, t)
                              real(8), intent (in) :: x
                              real(8), intent (in) :: y
                              real(8), intent (in) :: z
                              real(8), intent (in) :: t
                              real(8) :: tmp
                              if (t <= (-1.0d0)) then
                                  tmp = -2.0d0
                              else if (t <= 1.0d0) then
                                  tmp = 2.0d0 / t
                              else
                                  tmp = -2.0d0
                              end if
                              code = tmp
                          end function
                          
                          public static double code(double x, double y, double z, double t) {
                          	double tmp;
                          	if (t <= -1.0) {
                          		tmp = -2.0;
                          	} else if (t <= 1.0) {
                          		tmp = 2.0 / t;
                          	} else {
                          		tmp = -2.0;
                          	}
                          	return tmp;
                          }
                          
                          def code(x, y, z, t):
                          	tmp = 0
                          	if t <= -1.0:
                          		tmp = -2.0
                          	elif t <= 1.0:
                          		tmp = 2.0 / t
                          	else:
                          		tmp = -2.0
                          	return tmp
                          
                          function code(x, y, z, t)
                          	tmp = 0.0
                          	if (t <= -1.0)
                          		tmp = -2.0;
                          	elseif (t <= 1.0)
                          		tmp = Float64(2.0 / t);
                          	else
                          		tmp = -2.0;
                          	end
                          	return tmp
                          end
                          
                          function tmp_2 = code(x, y, z, t)
                          	tmp = 0.0;
                          	if (t <= -1.0)
                          		tmp = -2.0;
                          	elseif (t <= 1.0)
                          		tmp = 2.0 / t;
                          	else
                          		tmp = -2.0;
                          	end
                          	tmp_2 = tmp;
                          end
                          
                          code[x_, y_, z_, t_] := If[LessEqual[t, -1.0], -2.0, If[LessEqual[t, 1.0], N[(2.0 / t), $MachinePrecision], -2.0]]
                          
                          \begin{array}{l}
                          
                          \\
                          \begin{array}{l}
                          \mathbf{if}\;t \leq -1:\\
                          \;\;\;\;-2\\
                          
                          \mathbf{elif}\;t \leq 1:\\
                          \;\;\;\;\frac{2}{t}\\
                          
                          \mathbf{else}:\\
                          \;\;\;\;-2\\
                          
                          
                          \end{array}
                          \end{array}
                          
                          Derivation
                          1. Split input into 2 regimes
                          2. if t < -1 or 1 < t

                            1. Initial program 75.8%

                              \[\frac{x}{y} + \frac{2 + \left(z \cdot 2\right) \cdot \left(1 - t\right)}{t \cdot z} \]
                            2. Add Preprocessing
                            3. Taylor expanded in x around 0

                              \[\leadsto \color{blue}{2 \cdot \frac{1 - t}{t} + 2 \cdot \frac{1}{t \cdot z}} \]
                            4. Applied rewrites50.3%

                              \[\leadsto \color{blue}{\mathsf{fma}\left(\frac{2}{t \cdot z}, z + 1, -2\right)} \]
                            5. Taylor expanded in t around inf

                              \[\leadsto -2 \]
                            6. Step-by-step derivation
                              1. Applied rewrites36.0%

                                \[\leadsto -2 \]

                              if -1 < t < 1

                              1. Initial program 99.8%

                                \[\frac{x}{y} + \frac{2 + \left(z \cdot 2\right) \cdot \left(1 - t\right)}{t \cdot z} \]
                              2. Add Preprocessing
                              3. Taylor expanded in t around 0

                                \[\leadsto \color{blue}{\frac{2 + 2 \cdot \frac{1}{z}}{t}} \]
                              4. Applied rewrites72.1%

                                \[\leadsto \color{blue}{\frac{\mathsf{fma}\left(2, z, 2\right)}{t \cdot z}} \]
                              5. Taylor expanded in z around inf

                                \[\leadsto \frac{2}{\color{blue}{t}} \]
                              6. Step-by-step derivation
                                1. Applied rewrites38.2%

                                  \[\leadsto \frac{2}{\color{blue}{t}} \]
                              7. Recombined 2 regimes into one program.
                              8. Add Preprocessing

                              Alternative 11: 20.4% accurate, 47.0× speedup?

                              \[\begin{array}{l} \\ -2 \end{array} \]
                              (FPCore (x y z t) :precision binary64 -2.0)
                              double code(double x, double y, double z, double t) {
                              	return -2.0;
                              }
                              
                              real(8) function code(x, y, z, t)
                                  real(8), intent (in) :: x
                                  real(8), intent (in) :: y
                                  real(8), intent (in) :: z
                                  real(8), intent (in) :: t
                                  code = -2.0d0
                              end function
                              
                              public static double code(double x, double y, double z, double t) {
                              	return -2.0;
                              }
                              
                              def code(x, y, z, t):
                              	return -2.0
                              
                              function code(x, y, z, t)
                              	return -2.0
                              end
                              
                              function tmp = code(x, y, z, t)
                              	tmp = -2.0;
                              end
                              
                              code[x_, y_, z_, t_] := -2.0
                              
                              \begin{array}{l}
                              
                              \\
                              -2
                              \end{array}
                              
                              Derivation
                              1. Initial program 86.6%

                                \[\frac{x}{y} + \frac{2 + \left(z \cdot 2\right) \cdot \left(1 - t\right)}{t \cdot z} \]
                              2. Add Preprocessing
                              3. Taylor expanded in x around 0

                                \[\leadsto \color{blue}{2 \cdot \frac{1 - t}{t} + 2 \cdot \frac{1}{t \cdot z}} \]
                              4. Applied rewrites60.5%

                                \[\leadsto \color{blue}{\mathsf{fma}\left(\frac{2}{t \cdot z}, z + 1, -2\right)} \]
                              5. Taylor expanded in t around inf

                                \[\leadsto -2 \]
                              6. Step-by-step derivation
                                1. Applied rewrites20.9%

                                  \[\leadsto -2 \]
                                2. Add Preprocessing

                                Developer Target 1: 99.2% accurate, 1.1× speedup?

                                \[\begin{array}{l} \\ \frac{\frac{2}{z} + 2}{t} - \left(2 - \frac{x}{y}\right) \end{array} \]
                                (FPCore (x y z t)
                                 :precision binary64
                                 (- (/ (+ (/ 2.0 z) 2.0) t) (- 2.0 (/ x y))))
                                double code(double x, double y, double z, double t) {
                                	return (((2.0 / z) + 2.0) / t) - (2.0 - (x / y));
                                }
                                
                                real(8) function code(x, y, z, t)
                                    real(8), intent (in) :: x
                                    real(8), intent (in) :: y
                                    real(8), intent (in) :: z
                                    real(8), intent (in) :: t
                                    code = (((2.0d0 / z) + 2.0d0) / t) - (2.0d0 - (x / y))
                                end function
                                
                                public static double code(double x, double y, double z, double t) {
                                	return (((2.0 / z) + 2.0) / t) - (2.0 - (x / y));
                                }
                                
                                def code(x, y, z, t):
                                	return (((2.0 / z) + 2.0) / t) - (2.0 - (x / y))
                                
                                function code(x, y, z, t)
                                	return Float64(Float64(Float64(Float64(2.0 / z) + 2.0) / t) - Float64(2.0 - Float64(x / y)))
                                end
                                
                                function tmp = code(x, y, z, t)
                                	tmp = (((2.0 / z) + 2.0) / t) - (2.0 - (x / y));
                                end
                                
                                code[x_, y_, z_, t_] := N[(N[(N[(N[(2.0 / z), $MachinePrecision] + 2.0), $MachinePrecision] / t), $MachinePrecision] - N[(2.0 - N[(x / y), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
                                
                                \begin{array}{l}
                                
                                \\
                                \frac{\frac{2}{z} + 2}{t} - \left(2 - \frac{x}{y}\right)
                                \end{array}
                                

                                Reproduce

                                ?
                                herbie shell --seed 2024233 
                                (FPCore (x y z t)
                                  :name "Data.HashTable.ST.Basic:computeOverhead from hashtables-1.2.0.2"
                                  :precision binary64
                                
                                  :alt
                                  (! :herbie-platform default (- (/ (+ (/ 2 z) 2) t) (- 2 (/ x y))))
                                
                                  (+ (/ x y) (/ (+ 2.0 (* (* z 2.0) (- 1.0 t))) (* t z))))