2nthrt (problem 3.4.6)

Percentage Accurate: 54.6% → 86.2%
Time: 27.0s
Alternatives: 17
Speedup: 1.9×

Specification

?
\[\begin{array}{l} \\ {\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \end{array} \]
(FPCore (x n)
 :precision binary64
 (- (pow (+ x 1.0) (/ 1.0 n)) (pow x (/ 1.0 n))))
double code(double x, double n) {
	return pow((x + 1.0), (1.0 / n)) - pow(x, (1.0 / n));
}
real(8) function code(x, n)
    real(8), intent (in) :: x
    real(8), intent (in) :: n
    code = ((x + 1.0d0) ** (1.0d0 / n)) - (x ** (1.0d0 / n))
end function
public static double code(double x, double n) {
	return Math.pow((x + 1.0), (1.0 / n)) - Math.pow(x, (1.0 / n));
}
def code(x, n):
	return math.pow((x + 1.0), (1.0 / n)) - math.pow(x, (1.0 / n))
function code(x, n)
	return Float64((Float64(x + 1.0) ^ Float64(1.0 / n)) - (x ^ Float64(1.0 / n)))
end
function tmp = code(x, n)
	tmp = ((x + 1.0) ^ (1.0 / n)) - (x ^ (1.0 / n));
end
code[x_, n_] := N[(N[Power[N[(x + 1.0), $MachinePrecision], N[(1.0 / n), $MachinePrecision]], $MachinePrecision] - N[Power[x, N[(1.0 / n), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)}
\end{array}

Sampling outcomes in binary64 precision:

Local Percentage Accuracy vs ?

The average percentage accuracy by input value. Horizontal axis shows value of an input variable; the variable is choosen in the title. Vertical axis is accuracy; higher is better. Red represent the original program, while blue represents Herbie's suggestion. These can be toggled with buttons below the plot. The line is an average while dots represent individual samples.

Accuracy vs Speed?

Herbie found 17 alternatives:

AlternativeAccuracySpeedup
The accuracy (vertical axis) and speed (horizontal axis) of each alternatives. Up and to the right is better. The red square shows the initial program, and each blue circle shows an alternative.The line shows the best available speed-accuracy tradeoffs.

Initial Program: 54.6% accurate, 1.0× speedup?

\[\begin{array}{l} \\ {\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \end{array} \]
(FPCore (x n)
 :precision binary64
 (- (pow (+ x 1.0) (/ 1.0 n)) (pow x (/ 1.0 n))))
double code(double x, double n) {
	return pow((x + 1.0), (1.0 / n)) - pow(x, (1.0 / n));
}
real(8) function code(x, n)
    real(8), intent (in) :: x
    real(8), intent (in) :: n
    code = ((x + 1.0d0) ** (1.0d0 / n)) - (x ** (1.0d0 / n))
end function
public static double code(double x, double n) {
	return Math.pow((x + 1.0), (1.0 / n)) - Math.pow(x, (1.0 / n));
}
def code(x, n):
	return math.pow((x + 1.0), (1.0 / n)) - math.pow(x, (1.0 / n))
function code(x, n)
	return Float64((Float64(x + 1.0) ^ Float64(1.0 / n)) - (x ^ Float64(1.0 / n)))
end
function tmp = code(x, n)
	tmp = ((x + 1.0) ^ (1.0 / n)) - (x ^ (1.0 / n));
end
code[x_, n_] := N[(N[Power[N[(x + 1.0), $MachinePrecision], N[(1.0 / n), $MachinePrecision]], $MachinePrecision] - N[Power[x, N[(1.0 / n), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)}
\end{array}

Alternative 1: 86.2% accurate, 0.6× speedup?

\[\begin{array}{l} \\ \begin{array}{l} t_0 := {x}^{\left(\frac{1}{n}\right)}\\ \mathbf{if}\;\frac{1}{n} \leq -4 \cdot 10^{-80}:\\ \;\;\;\;\frac{t\_0}{x \cdot n}\\ \mathbf{elif}\;\frac{1}{n} \leq 2 \cdot 10^{-64}:\\ \;\;\;\;\frac{\log \left(\frac{x + 1}{x}\right)}{n}\\ \mathbf{elif}\;\frac{1}{n} \leq 0.5:\\ \;\;\;\;\frac{\mathsf{fma}\left(\frac{t\_0}{x}, \left(\frac{0.5}{n \cdot n} + \frac{-0.5}{n}\right) + \frac{\frac{0.16666666666666666}{n \cdot \left(n \cdot n\right)} + \left(\frac{0.3333333333333333}{n} + \frac{-0.5}{n \cdot n}\right)}{x}, \frac{t\_0}{n}\right)}{x}\\ \mathbf{else}:\\ \;\;\;\;e^{\frac{x}{n}} - t\_0\\ \end{array} \end{array} \]
(FPCore (x n)
 :precision binary64
 (let* ((t_0 (pow x (/ 1.0 n))))
   (if (<= (/ 1.0 n) -4e-80)
     (/ t_0 (* x n))
     (if (<= (/ 1.0 n) 2e-64)
       (/ (log (/ (+ x 1.0) x)) n)
       (if (<= (/ 1.0 n) 0.5)
         (/
          (fma
           (/ t_0 x)
           (+
            (+ (/ 0.5 (* n n)) (/ -0.5 n))
            (/
             (+
              (/ 0.16666666666666666 (* n (* n n)))
              (+ (/ 0.3333333333333333 n) (/ -0.5 (* n n))))
             x))
           (/ t_0 n))
          x)
         (- (exp (/ x n)) t_0))))))
double code(double x, double n) {
	double t_0 = pow(x, (1.0 / n));
	double tmp;
	if ((1.0 / n) <= -4e-80) {
		tmp = t_0 / (x * n);
	} else if ((1.0 / n) <= 2e-64) {
		tmp = log(((x + 1.0) / x)) / n;
	} else if ((1.0 / n) <= 0.5) {
		tmp = fma((t_0 / x), (((0.5 / (n * n)) + (-0.5 / n)) + (((0.16666666666666666 / (n * (n * n))) + ((0.3333333333333333 / n) + (-0.5 / (n * n)))) / x)), (t_0 / n)) / x;
	} else {
		tmp = exp((x / n)) - t_0;
	}
	return tmp;
}
function code(x, n)
	t_0 = x ^ Float64(1.0 / n)
	tmp = 0.0
	if (Float64(1.0 / n) <= -4e-80)
		tmp = Float64(t_0 / Float64(x * n));
	elseif (Float64(1.0 / n) <= 2e-64)
		tmp = Float64(log(Float64(Float64(x + 1.0) / x)) / n);
	elseif (Float64(1.0 / n) <= 0.5)
		tmp = Float64(fma(Float64(t_0 / x), Float64(Float64(Float64(0.5 / Float64(n * n)) + Float64(-0.5 / n)) + Float64(Float64(Float64(0.16666666666666666 / Float64(n * Float64(n * n))) + Float64(Float64(0.3333333333333333 / n) + Float64(-0.5 / Float64(n * n)))) / x)), Float64(t_0 / n)) / x);
	else
		tmp = Float64(exp(Float64(x / n)) - t_0);
	end
	return tmp
end
code[x_, n_] := Block[{t$95$0 = N[Power[x, N[(1.0 / n), $MachinePrecision]], $MachinePrecision]}, If[LessEqual[N[(1.0 / n), $MachinePrecision], -4e-80], N[(t$95$0 / N[(x * n), $MachinePrecision]), $MachinePrecision], If[LessEqual[N[(1.0 / n), $MachinePrecision], 2e-64], N[(N[Log[N[(N[(x + 1.0), $MachinePrecision] / x), $MachinePrecision]], $MachinePrecision] / n), $MachinePrecision], If[LessEqual[N[(1.0 / n), $MachinePrecision], 0.5], N[(N[(N[(t$95$0 / x), $MachinePrecision] * N[(N[(N[(0.5 / N[(n * n), $MachinePrecision]), $MachinePrecision] + N[(-0.5 / n), $MachinePrecision]), $MachinePrecision] + N[(N[(N[(0.16666666666666666 / N[(n * N[(n * n), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] + N[(N[(0.3333333333333333 / n), $MachinePrecision] + N[(-0.5 / N[(n * n), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] / x), $MachinePrecision]), $MachinePrecision] + N[(t$95$0 / n), $MachinePrecision]), $MachinePrecision] / x), $MachinePrecision], N[(N[Exp[N[(x / n), $MachinePrecision]], $MachinePrecision] - t$95$0), $MachinePrecision]]]]]
\begin{array}{l}

\\
\begin{array}{l}
t_0 := {x}^{\left(\frac{1}{n}\right)}\\
\mathbf{if}\;\frac{1}{n} \leq -4 \cdot 10^{-80}:\\
\;\;\;\;\frac{t\_0}{x \cdot n}\\

\mathbf{elif}\;\frac{1}{n} \leq 2 \cdot 10^{-64}:\\
\;\;\;\;\frac{\log \left(\frac{x + 1}{x}\right)}{n}\\

\mathbf{elif}\;\frac{1}{n} \leq 0.5:\\
\;\;\;\;\frac{\mathsf{fma}\left(\frac{t\_0}{x}, \left(\frac{0.5}{n \cdot n} + \frac{-0.5}{n}\right) + \frac{\frac{0.16666666666666666}{n \cdot \left(n \cdot n\right)} + \left(\frac{0.3333333333333333}{n} + \frac{-0.5}{n \cdot n}\right)}{x}, \frac{t\_0}{n}\right)}{x}\\

\mathbf{else}:\\
\;\;\;\;e^{\frac{x}{n}} - t\_0\\


\end{array}
\end{array}
Derivation
  1. Split input into 4 regimes
  2. if (/.f64 #s(literal 1 binary64) n) < -3.99999999999999985e-80

    1. Initial program 78.0%

      \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
    2. Add Preprocessing
    3. Taylor expanded in x around inf

      \[\leadsto \color{blue}{\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{n \cdot x}} \]
    4. Step-by-step derivation
      1. lower-/.f64N/A

        \[\leadsto \color{blue}{\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{n \cdot x}} \]
      2. log-recN/A

        \[\leadsto \frac{e^{-1 \cdot \frac{\color{blue}{\mathsf{neg}\left(\log x\right)}}{n}}}{n \cdot x} \]
      3. mul-1-negN/A

        \[\leadsto \frac{e^{-1 \cdot \frac{\color{blue}{-1 \cdot \log x}}{n}}}{n \cdot x} \]
      4. associate-*r/N/A

        \[\leadsto \frac{e^{\color{blue}{\frac{-1 \cdot \left(-1 \cdot \log x\right)}{n}}}}{n \cdot x} \]
      5. associate-*r*N/A

        \[\leadsto \frac{e^{\frac{\color{blue}{\left(-1 \cdot -1\right) \cdot \log x}}{n}}}{n \cdot x} \]
      6. metadata-evalN/A

        \[\leadsto \frac{e^{\frac{\color{blue}{1} \cdot \log x}{n}}}{n \cdot x} \]
      7. *-commutativeN/A

        \[\leadsto \frac{e^{\frac{\color{blue}{\log x \cdot 1}}{n}}}{n \cdot x} \]
      8. associate-/l*N/A

        \[\leadsto \frac{e^{\color{blue}{\log x \cdot \frac{1}{n}}}}{n \cdot x} \]
      9. exp-to-powN/A

        \[\leadsto \frac{\color{blue}{{x}^{\left(\frac{1}{n}\right)}}}{n \cdot x} \]
      10. lower-pow.f64N/A

        \[\leadsto \frac{\color{blue}{{x}^{\left(\frac{1}{n}\right)}}}{n \cdot x} \]
      11. lower-/.f64N/A

        \[\leadsto \frac{{x}^{\color{blue}{\left(\frac{1}{n}\right)}}}{n \cdot x} \]
      12. *-commutativeN/A

        \[\leadsto \frac{{x}^{\left(\frac{1}{n}\right)}}{\color{blue}{x \cdot n}} \]
      13. lower-*.f6488.6

        \[\leadsto \frac{{x}^{\left(\frac{1}{n}\right)}}{\color{blue}{x \cdot n}} \]
    5. Applied rewrites88.6%

      \[\leadsto \color{blue}{\frac{{x}^{\left(\frac{1}{n}\right)}}{x \cdot n}} \]

    if -3.99999999999999985e-80 < (/.f64 #s(literal 1 binary64) n) < 1.99999999999999993e-64

    1. Initial program 36.4%

      \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
    2. Add Preprocessing
    3. Taylor expanded in n around -inf

      \[\leadsto \color{blue}{-1 \cdot \frac{\left(-1 \cdot \log \left(1 + x\right) + -1 \cdot \frac{\left(-1 \cdot \frac{\left(-1 \cdot \frac{\frac{1}{24} \cdot {\log \left(1 + x\right)}^{4} - \frac{1}{24} \cdot {\log x}^{4}}{n} + \frac{-1}{6} \cdot {\log \left(1 + x\right)}^{3}\right) - \frac{-1}{6} \cdot {\log x}^{3}}{n} + \frac{1}{2} \cdot {\log \left(1 + x\right)}^{2}\right) - \frac{1}{2} \cdot {\log x}^{2}}{n}\right) - -1 \cdot \log x}{n}} \]
    4. Applied rewrites80.9%

      \[\leadsto \color{blue}{\frac{\left(\log x - \mathsf{log1p}\left(x\right)\right) - \frac{0.5 \cdot \left({\left(\mathsf{log1p}\left(x\right)\right)}^{2} - {\log x}^{2}\right) - \frac{\mathsf{fma}\left(-0.041666666666666664, \frac{{\left(\mathsf{log1p}\left(x\right)\right)}^{4} - {\log x}^{4}}{n}, -0.16666666666666666 \cdot \left({\left(\mathsf{log1p}\left(x\right)\right)}^{3} - {\log x}^{3}\right)\right)}{n}}{n}}{-n}} \]
    5. Step-by-step derivation
      1. Applied rewrites81.2%

        \[\leadsto \frac{\left(-\log \left(\frac{x + 1}{x}\right)\right) - \frac{0.5 \cdot \left({\left(\mathsf{log1p}\left(x\right)\right)}^{2} - {\log x}^{2}\right) - \frac{\mathsf{fma}\left(-0.041666666666666664, \frac{{\left(\mathsf{log1p}\left(x\right)\right)}^{4} - {\log x}^{4}}{n}, -0.16666666666666666 \cdot \left({\left(\mathsf{log1p}\left(x\right)\right)}^{3} - {\log x}^{3}\right)\right)}{n}}{n}}{-n} \]
      2. Taylor expanded in n around inf

        \[\leadsto \frac{\log \left(\frac{1 + x}{x}\right)}{\color{blue}{n}} \]
      3. Step-by-step derivation
        1. Applied rewrites81.2%

          \[\leadsto \frac{\log \left(\frac{x + 1}{x}\right)}{\color{blue}{n}} \]

        if 1.99999999999999993e-64 < (/.f64 #s(literal 1 binary64) n) < 0.5

        1. Initial program 13.5%

          \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
        2. Add Preprocessing
        3. Taylor expanded in x around inf

          \[\leadsto \color{blue}{\frac{\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{n} + \left(\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}} \cdot \left(\frac{1}{2} \cdot \frac{1}{{n}^{2}} - \frac{1}{2} \cdot \frac{1}{n}\right)}{x} + \frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}} \cdot \left(\left(\frac{1}{6} \cdot \frac{1}{{n}^{3}} + \frac{1}{3} \cdot \frac{1}{n}\right) - \frac{1}{2} \cdot \frac{1}{{n}^{2}}\right)}{{x}^{2}}\right)}{x}} \]
        4. Applied rewrites79.4%

          \[\leadsto \color{blue}{\frac{\mathsf{fma}\left(\frac{{x}^{\left(\frac{1}{n}\right)}}{x}, \left(\frac{0.5}{n \cdot n} + \frac{-0.5}{n}\right) + \frac{\frac{0.16666666666666666}{n \cdot \left(n \cdot n\right)} + \left(\frac{0.3333333333333333}{n} + \frac{-0.5}{n \cdot n}\right)}{x}, \frac{{x}^{\left(\frac{1}{n}\right)}}{n}\right)}{x}} \]

        if 0.5 < (/.f64 #s(literal 1 binary64) n)

        1. Initial program 68.7%

          \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
        2. Add Preprocessing
        3. Step-by-step derivation
          1. lift-pow.f64N/A

            \[\leadsto \color{blue}{{\left(x + 1\right)}^{\left(\frac{1}{n}\right)}} - {x}^{\left(\frac{1}{n}\right)} \]
          2. pow-to-expN/A

            \[\leadsto \color{blue}{e^{\log \left(x + 1\right) \cdot \frac{1}{n}}} - {x}^{\left(\frac{1}{n}\right)} \]
          3. lower-exp.f64N/A

            \[\leadsto \color{blue}{e^{\log \left(x + 1\right) \cdot \frac{1}{n}}} - {x}^{\left(\frac{1}{n}\right)} \]
          4. lift-/.f64N/A

            \[\leadsto e^{\log \left(x + 1\right) \cdot \color{blue}{\frac{1}{n}}} - {x}^{\left(\frac{1}{n}\right)} \]
          5. un-div-invN/A

            \[\leadsto e^{\color{blue}{\frac{\log \left(x + 1\right)}{n}}} - {x}^{\left(\frac{1}{n}\right)} \]
          6. lower-/.f64N/A

            \[\leadsto e^{\color{blue}{\frac{\log \left(x + 1\right)}{n}}} - {x}^{\left(\frac{1}{n}\right)} \]
          7. lift-+.f64N/A

            \[\leadsto e^{\frac{\log \color{blue}{\left(x + 1\right)}}{n}} - {x}^{\left(\frac{1}{n}\right)} \]
          8. +-commutativeN/A

            \[\leadsto e^{\frac{\log \color{blue}{\left(1 + x\right)}}{n}} - {x}^{\left(\frac{1}{n}\right)} \]
          9. lower-log1p.f64100.0

            \[\leadsto e^{\frac{\color{blue}{\mathsf{log1p}\left(x\right)}}{n}} - {x}^{\left(\frac{1}{n}\right)} \]
        4. Applied rewrites100.0%

          \[\leadsto \color{blue}{e^{\frac{\mathsf{log1p}\left(x\right)}{n}}} - {x}^{\left(\frac{1}{n}\right)} \]
        5. Taylor expanded in x around 0

          \[\leadsto e^{\color{blue}{\frac{x}{n}}} - {x}^{\left(\frac{1}{n}\right)} \]
        6. Step-by-step derivation
          1. lower-/.f64100.0

            \[\leadsto e^{\color{blue}{\frac{x}{n}}} - {x}^{\left(\frac{1}{n}\right)} \]
        7. Applied rewrites100.0%

          \[\leadsto e^{\color{blue}{\frac{x}{n}}} - {x}^{\left(\frac{1}{n}\right)} \]
      4. Recombined 4 regimes into one program.
      5. Add Preprocessing

      Alternative 2: 80.2% accurate, 0.2× speedup?

      \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;x \leq 175:\\ \;\;\;\;\frac{\log \left(\frac{x + 1}{x}\right) + \frac{0.5 \cdot \left({\left(\mathsf{log1p}\left(x\right)\right)}^{2} - {\log x}^{2}\right) - \frac{\mathsf{fma}\left(-0.041666666666666664, \frac{{\left(\mathsf{log1p}\left(x\right)\right)}^{4} - {\log x}^{4}}{n}, -0.16666666666666666 \cdot \left({\left(\mathsf{log1p}\left(x\right)\right)}^{3} - {\log x}^{3}\right)\right)}{n}}{n}}{n}\\ \mathbf{else}:\\ \;\;\;\;\frac{{x}^{\left(\frac{1}{n}\right)}}{x \cdot n}\\ \end{array} \end{array} \]
      (FPCore (x n)
       :precision binary64
       (if (<= x 175.0)
         (/
          (+
           (log (/ (+ x 1.0) x))
           (/
            (-
             (* 0.5 (- (pow (log1p x) 2.0) (pow (log x) 2.0)))
             (/
              (fma
               -0.041666666666666664
               (/ (- (pow (log1p x) 4.0) (pow (log x) 4.0)) n)
               (* -0.16666666666666666 (- (pow (log1p x) 3.0) (pow (log x) 3.0))))
              n))
            n))
          n)
         (/ (pow x (/ 1.0 n)) (* x n))))
      double code(double x, double n) {
      	double tmp;
      	if (x <= 175.0) {
      		tmp = (log(((x + 1.0) / x)) + (((0.5 * (pow(log1p(x), 2.0) - pow(log(x), 2.0))) - (fma(-0.041666666666666664, ((pow(log1p(x), 4.0) - pow(log(x), 4.0)) / n), (-0.16666666666666666 * (pow(log1p(x), 3.0) - pow(log(x), 3.0)))) / n)) / n)) / n;
      	} else {
      		tmp = pow(x, (1.0 / n)) / (x * n);
      	}
      	return tmp;
      }
      
      function code(x, n)
      	tmp = 0.0
      	if (x <= 175.0)
      		tmp = Float64(Float64(log(Float64(Float64(x + 1.0) / x)) + Float64(Float64(Float64(0.5 * Float64((log1p(x) ^ 2.0) - (log(x) ^ 2.0))) - Float64(fma(-0.041666666666666664, Float64(Float64((log1p(x) ^ 4.0) - (log(x) ^ 4.0)) / n), Float64(-0.16666666666666666 * Float64((log1p(x) ^ 3.0) - (log(x) ^ 3.0)))) / n)) / n)) / n);
      	else
      		tmp = Float64((x ^ Float64(1.0 / n)) / Float64(x * n));
      	end
      	return tmp
      end
      
      code[x_, n_] := If[LessEqual[x, 175.0], N[(N[(N[Log[N[(N[(x + 1.0), $MachinePrecision] / x), $MachinePrecision]], $MachinePrecision] + N[(N[(N[(0.5 * N[(N[Power[N[Log[1 + x], $MachinePrecision], 2.0], $MachinePrecision] - N[Power[N[Log[x], $MachinePrecision], 2.0], $MachinePrecision]), $MachinePrecision]), $MachinePrecision] - N[(N[(-0.041666666666666664 * N[(N[(N[Power[N[Log[1 + x], $MachinePrecision], 4.0], $MachinePrecision] - N[Power[N[Log[x], $MachinePrecision], 4.0], $MachinePrecision]), $MachinePrecision] / n), $MachinePrecision] + N[(-0.16666666666666666 * N[(N[Power[N[Log[1 + x], $MachinePrecision], 3.0], $MachinePrecision] - N[Power[N[Log[x], $MachinePrecision], 3.0], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] / n), $MachinePrecision]), $MachinePrecision] / n), $MachinePrecision]), $MachinePrecision] / n), $MachinePrecision], N[(N[Power[x, N[(1.0 / n), $MachinePrecision]], $MachinePrecision] / N[(x * n), $MachinePrecision]), $MachinePrecision]]
      
      \begin{array}{l}
      
      \\
      \begin{array}{l}
      \mathbf{if}\;x \leq 175:\\
      \;\;\;\;\frac{\log \left(\frac{x + 1}{x}\right) + \frac{0.5 \cdot \left({\left(\mathsf{log1p}\left(x\right)\right)}^{2} - {\log x}^{2}\right) - \frac{\mathsf{fma}\left(-0.041666666666666664, \frac{{\left(\mathsf{log1p}\left(x\right)\right)}^{4} - {\log x}^{4}}{n}, -0.16666666666666666 \cdot \left({\left(\mathsf{log1p}\left(x\right)\right)}^{3} - {\log x}^{3}\right)\right)}{n}}{n}}{n}\\
      
      \mathbf{else}:\\
      \;\;\;\;\frac{{x}^{\left(\frac{1}{n}\right)}}{x \cdot n}\\
      
      
      \end{array}
      \end{array}
      
      Derivation
      1. Split input into 2 regimes
      2. if x < 175

        1. Initial program 48.9%

          \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
        2. Add Preprocessing
        3. Taylor expanded in n around -inf

          \[\leadsto \color{blue}{-1 \cdot \frac{\left(-1 \cdot \log \left(1 + x\right) + -1 \cdot \frac{\left(-1 \cdot \frac{\left(-1 \cdot \frac{\frac{1}{24} \cdot {\log \left(1 + x\right)}^{4} - \frac{1}{24} \cdot {\log x}^{4}}{n} + \frac{-1}{6} \cdot {\log \left(1 + x\right)}^{3}\right) - \frac{-1}{6} \cdot {\log x}^{3}}{n} + \frac{1}{2} \cdot {\log \left(1 + x\right)}^{2}\right) - \frac{1}{2} \cdot {\log x}^{2}}{n}\right) - -1 \cdot \log x}{n}} \]
        4. Applied rewrites71.5%

          \[\leadsto \color{blue}{\frac{\left(\log x - \mathsf{log1p}\left(x\right)\right) - \frac{0.5 \cdot \left({\left(\mathsf{log1p}\left(x\right)\right)}^{2} - {\log x}^{2}\right) - \frac{\mathsf{fma}\left(-0.041666666666666664, \frac{{\left(\mathsf{log1p}\left(x\right)\right)}^{4} - {\log x}^{4}}{n}, -0.16666666666666666 \cdot \left({\left(\mathsf{log1p}\left(x\right)\right)}^{3} - {\log x}^{3}\right)\right)}{n}}{n}}{-n}} \]
        5. Step-by-step derivation
          1. Applied rewrites71.6%

            \[\leadsto \frac{\left(-\log \left(\frac{x + 1}{x}\right)\right) - \frac{0.5 \cdot \left({\left(\mathsf{log1p}\left(x\right)\right)}^{2} - {\log x}^{2}\right) - \frac{\mathsf{fma}\left(-0.041666666666666664, \frac{{\left(\mathsf{log1p}\left(x\right)\right)}^{4} - {\log x}^{4}}{n}, -0.16666666666666666 \cdot \left({\left(\mathsf{log1p}\left(x\right)\right)}^{3} - {\log x}^{3}\right)\right)}{n}}{n}}{-n} \]

          if 175 < x

          1. Initial program 64.0%

            \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
          2. Add Preprocessing
          3. Taylor expanded in x around inf

            \[\leadsto \color{blue}{\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{n \cdot x}} \]
          4. Step-by-step derivation
            1. lower-/.f64N/A

              \[\leadsto \color{blue}{\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{n \cdot x}} \]
            2. log-recN/A

              \[\leadsto \frac{e^{-1 \cdot \frac{\color{blue}{\mathsf{neg}\left(\log x\right)}}{n}}}{n \cdot x} \]
            3. mul-1-negN/A

              \[\leadsto \frac{e^{-1 \cdot \frac{\color{blue}{-1 \cdot \log x}}{n}}}{n \cdot x} \]
            4. associate-*r/N/A

              \[\leadsto \frac{e^{\color{blue}{\frac{-1 \cdot \left(-1 \cdot \log x\right)}{n}}}}{n \cdot x} \]
            5. associate-*r*N/A

              \[\leadsto \frac{e^{\frac{\color{blue}{\left(-1 \cdot -1\right) \cdot \log x}}{n}}}{n \cdot x} \]
            6. metadata-evalN/A

              \[\leadsto \frac{e^{\frac{\color{blue}{1} \cdot \log x}{n}}}{n \cdot x} \]
            7. *-commutativeN/A

              \[\leadsto \frac{e^{\frac{\color{blue}{\log x \cdot 1}}{n}}}{n \cdot x} \]
            8. associate-/l*N/A

              \[\leadsto \frac{e^{\color{blue}{\log x \cdot \frac{1}{n}}}}{n \cdot x} \]
            9. exp-to-powN/A

              \[\leadsto \frac{\color{blue}{{x}^{\left(\frac{1}{n}\right)}}}{n \cdot x} \]
            10. lower-pow.f64N/A

              \[\leadsto \frac{\color{blue}{{x}^{\left(\frac{1}{n}\right)}}}{n \cdot x} \]
            11. lower-/.f64N/A

              \[\leadsto \frac{{x}^{\color{blue}{\left(\frac{1}{n}\right)}}}{n \cdot x} \]
            12. *-commutativeN/A

              \[\leadsto \frac{{x}^{\left(\frac{1}{n}\right)}}{\color{blue}{x \cdot n}} \]
            13. lower-*.f6498.0

              \[\leadsto \frac{{x}^{\left(\frac{1}{n}\right)}}{\color{blue}{x \cdot n}} \]
          5. Applied rewrites98.0%

            \[\leadsto \color{blue}{\frac{{x}^{\left(\frac{1}{n}\right)}}{x \cdot n}} \]
        6. Recombined 2 regimes into one program.
        7. Final simplification83.5%

          \[\leadsto \begin{array}{l} \mathbf{if}\;x \leq 175:\\ \;\;\;\;\frac{\log \left(\frac{x + 1}{x}\right) + \frac{0.5 \cdot \left({\left(\mathsf{log1p}\left(x\right)\right)}^{2} - {\log x}^{2}\right) - \frac{\mathsf{fma}\left(-0.041666666666666664, \frac{{\left(\mathsf{log1p}\left(x\right)\right)}^{4} - {\log x}^{4}}{n}, -0.16666666666666666 \cdot \left({\left(\mathsf{log1p}\left(x\right)\right)}^{3} - {\log x}^{3}\right)\right)}{n}}{n}}{n}\\ \mathbf{else}:\\ \;\;\;\;\frac{{x}^{\left(\frac{1}{n}\right)}}{x \cdot n}\\ \end{array} \]
        8. Add Preprocessing

        Alternative 3: 80.2% accurate, 0.2× speedup?

        \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;x \leq 175:\\ \;\;\;\;\frac{\frac{0.5 \cdot \left(\log \left(\frac{x + 1}{x}\right) \cdot \log \left(\mathsf{fma}\left(x, x, x\right)\right)\right) - \frac{\mathsf{fma}\left(-0.041666666666666664, \frac{{\left(\mathsf{log1p}\left(x\right)\right)}^{4} - {\log x}^{4}}{n}, -0.16666666666666666 \cdot \left({\left(\mathsf{log1p}\left(x\right)\right)}^{3} - {\log x}^{3}\right)\right)}{n}}{n} - \log \left(\frac{x}{x + 1}\right)}{n}\\ \mathbf{else}:\\ \;\;\;\;\frac{{x}^{\left(\frac{1}{n}\right)}}{x \cdot n}\\ \end{array} \end{array} \]
        (FPCore (x n)
         :precision binary64
         (if (<= x 175.0)
           (/
            (-
             (/
              (-
               (* 0.5 (* (log (/ (+ x 1.0) x)) (log (fma x x x))))
               (/
                (fma
                 -0.041666666666666664
                 (/ (- (pow (log1p x) 4.0) (pow (log x) 4.0)) n)
                 (* -0.16666666666666666 (- (pow (log1p x) 3.0) (pow (log x) 3.0))))
                n))
              n)
             (log (/ x (+ x 1.0))))
            n)
           (/ (pow x (/ 1.0 n)) (* x n))))
        double code(double x, double n) {
        	double tmp;
        	if (x <= 175.0) {
        		tmp = ((((0.5 * (log(((x + 1.0) / x)) * log(fma(x, x, x)))) - (fma(-0.041666666666666664, ((pow(log1p(x), 4.0) - pow(log(x), 4.0)) / n), (-0.16666666666666666 * (pow(log1p(x), 3.0) - pow(log(x), 3.0)))) / n)) / n) - log((x / (x + 1.0)))) / n;
        	} else {
        		tmp = pow(x, (1.0 / n)) / (x * n);
        	}
        	return tmp;
        }
        
        function code(x, n)
        	tmp = 0.0
        	if (x <= 175.0)
        		tmp = Float64(Float64(Float64(Float64(Float64(0.5 * Float64(log(Float64(Float64(x + 1.0) / x)) * log(fma(x, x, x)))) - Float64(fma(-0.041666666666666664, Float64(Float64((log1p(x) ^ 4.0) - (log(x) ^ 4.0)) / n), Float64(-0.16666666666666666 * Float64((log1p(x) ^ 3.0) - (log(x) ^ 3.0)))) / n)) / n) - log(Float64(x / Float64(x + 1.0)))) / n);
        	else
        		tmp = Float64((x ^ Float64(1.0 / n)) / Float64(x * n));
        	end
        	return tmp
        end
        
        code[x_, n_] := If[LessEqual[x, 175.0], N[(N[(N[(N[(N[(0.5 * N[(N[Log[N[(N[(x + 1.0), $MachinePrecision] / x), $MachinePrecision]], $MachinePrecision] * N[Log[N[(x * x + x), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision] - N[(N[(-0.041666666666666664 * N[(N[(N[Power[N[Log[1 + x], $MachinePrecision], 4.0], $MachinePrecision] - N[Power[N[Log[x], $MachinePrecision], 4.0], $MachinePrecision]), $MachinePrecision] / n), $MachinePrecision] + N[(-0.16666666666666666 * N[(N[Power[N[Log[1 + x], $MachinePrecision], 3.0], $MachinePrecision] - N[Power[N[Log[x], $MachinePrecision], 3.0], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] / n), $MachinePrecision]), $MachinePrecision] / n), $MachinePrecision] - N[Log[N[(x / N[(x + 1.0), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] / n), $MachinePrecision], N[(N[Power[x, N[(1.0 / n), $MachinePrecision]], $MachinePrecision] / N[(x * n), $MachinePrecision]), $MachinePrecision]]
        
        \begin{array}{l}
        
        \\
        \begin{array}{l}
        \mathbf{if}\;x \leq 175:\\
        \;\;\;\;\frac{\frac{0.5 \cdot \left(\log \left(\frac{x + 1}{x}\right) \cdot \log \left(\mathsf{fma}\left(x, x, x\right)\right)\right) - \frac{\mathsf{fma}\left(-0.041666666666666664, \frac{{\left(\mathsf{log1p}\left(x\right)\right)}^{4} - {\log x}^{4}}{n}, -0.16666666666666666 \cdot \left({\left(\mathsf{log1p}\left(x\right)\right)}^{3} - {\log x}^{3}\right)\right)}{n}}{n} - \log \left(\frac{x}{x + 1}\right)}{n}\\
        
        \mathbf{else}:\\
        \;\;\;\;\frac{{x}^{\left(\frac{1}{n}\right)}}{x \cdot n}\\
        
        
        \end{array}
        \end{array}
        
        Derivation
        1. Split input into 2 regimes
        2. if x < 175

          1. Initial program 48.9%

            \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
          2. Add Preprocessing
          3. Taylor expanded in n around -inf

            \[\leadsto \color{blue}{-1 \cdot \frac{\left(-1 \cdot \log \left(1 + x\right) + -1 \cdot \frac{\left(-1 \cdot \frac{\left(-1 \cdot \frac{\frac{1}{24} \cdot {\log \left(1 + x\right)}^{4} - \frac{1}{24} \cdot {\log x}^{4}}{n} + \frac{-1}{6} \cdot {\log \left(1 + x\right)}^{3}\right) - \frac{-1}{6} \cdot {\log x}^{3}}{n} + \frac{1}{2} \cdot {\log \left(1 + x\right)}^{2}\right) - \frac{1}{2} \cdot {\log x}^{2}}{n}\right) - -1 \cdot \log x}{n}} \]
          4. Applied rewrites71.5%

            \[\leadsto \color{blue}{\frac{\left(\log x - \mathsf{log1p}\left(x\right)\right) - \frac{0.5 \cdot \left({\left(\mathsf{log1p}\left(x\right)\right)}^{2} - {\log x}^{2}\right) - \frac{\mathsf{fma}\left(-0.041666666666666664, \frac{{\left(\mathsf{log1p}\left(x\right)\right)}^{4} - {\log x}^{4}}{n}, -0.16666666666666666 \cdot \left({\left(\mathsf{log1p}\left(x\right)\right)}^{3} - {\log x}^{3}\right)\right)}{n}}{n}}{-n}} \]
          5. Step-by-step derivation
            1. Applied rewrites71.3%

              \[\leadsto \frac{\frac{1}{\frac{\mathsf{fma}\left(\log x, \log \left(x \cdot \left(x + 1\right)\right), {\left(\mathsf{log1p}\left(x\right)\right)}^{2}\right)}{{\log x}^{3} - {\left(\mathsf{log1p}\left(x\right)\right)}^{3}}} - \frac{0.5 \cdot \left({\left(\mathsf{log1p}\left(x\right)\right)}^{2} - {\log x}^{2}\right) - \frac{\mathsf{fma}\left(-0.041666666666666664, \frac{{\left(\mathsf{log1p}\left(x\right)\right)}^{4} - {\log x}^{4}}{n}, -0.16666666666666666 \cdot \left({\left(\mathsf{log1p}\left(x\right)\right)}^{3} - {\log x}^{3}\right)\right)}{n}}{n}}{-n} \]
            2. Applied rewrites71.5%

              \[\leadsto \frac{\log \left(\frac{x}{1 + x}\right) - \frac{0.5 \cdot \left(\log \left(\mathsf{fma}\left(x, x, x\right)\right) \cdot \log \left(\frac{1 + x}{x}\right)\right) - \frac{\mathsf{fma}\left(-0.041666666666666664, \frac{{\left(\mathsf{log1p}\left(x\right)\right)}^{4} - {\log x}^{4}}{n}, -0.16666666666666666 \cdot \left({\left(\mathsf{log1p}\left(x\right)\right)}^{3} - {\log x}^{3}\right)\right)}{n}}{n}}{\color{blue}{-n}} \]

            if 175 < x

            1. Initial program 64.0%

              \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
            2. Add Preprocessing
            3. Taylor expanded in x around inf

              \[\leadsto \color{blue}{\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{n \cdot x}} \]
            4. Step-by-step derivation
              1. lower-/.f64N/A

                \[\leadsto \color{blue}{\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{n \cdot x}} \]
              2. log-recN/A

                \[\leadsto \frac{e^{-1 \cdot \frac{\color{blue}{\mathsf{neg}\left(\log x\right)}}{n}}}{n \cdot x} \]
              3. mul-1-negN/A

                \[\leadsto \frac{e^{-1 \cdot \frac{\color{blue}{-1 \cdot \log x}}{n}}}{n \cdot x} \]
              4. associate-*r/N/A

                \[\leadsto \frac{e^{\color{blue}{\frac{-1 \cdot \left(-1 \cdot \log x\right)}{n}}}}{n \cdot x} \]
              5. associate-*r*N/A

                \[\leadsto \frac{e^{\frac{\color{blue}{\left(-1 \cdot -1\right) \cdot \log x}}{n}}}{n \cdot x} \]
              6. metadata-evalN/A

                \[\leadsto \frac{e^{\frac{\color{blue}{1} \cdot \log x}{n}}}{n \cdot x} \]
              7. *-commutativeN/A

                \[\leadsto \frac{e^{\frac{\color{blue}{\log x \cdot 1}}{n}}}{n \cdot x} \]
              8. associate-/l*N/A

                \[\leadsto \frac{e^{\color{blue}{\log x \cdot \frac{1}{n}}}}{n \cdot x} \]
              9. exp-to-powN/A

                \[\leadsto \frac{\color{blue}{{x}^{\left(\frac{1}{n}\right)}}}{n \cdot x} \]
              10. lower-pow.f64N/A

                \[\leadsto \frac{\color{blue}{{x}^{\left(\frac{1}{n}\right)}}}{n \cdot x} \]
              11. lower-/.f64N/A

                \[\leadsto \frac{{x}^{\color{blue}{\left(\frac{1}{n}\right)}}}{n \cdot x} \]
              12. *-commutativeN/A

                \[\leadsto \frac{{x}^{\left(\frac{1}{n}\right)}}{\color{blue}{x \cdot n}} \]
              13. lower-*.f6498.0

                \[\leadsto \frac{{x}^{\left(\frac{1}{n}\right)}}{\color{blue}{x \cdot n}} \]
            5. Applied rewrites98.0%

              \[\leadsto \color{blue}{\frac{{x}^{\left(\frac{1}{n}\right)}}{x \cdot n}} \]
          6. Recombined 2 regimes into one program.
          7. Final simplification83.5%

            \[\leadsto \begin{array}{l} \mathbf{if}\;x \leq 175:\\ \;\;\;\;\frac{\frac{0.5 \cdot \left(\log \left(\frac{x + 1}{x}\right) \cdot \log \left(\mathsf{fma}\left(x, x, x\right)\right)\right) - \frac{\mathsf{fma}\left(-0.041666666666666664, \frac{{\left(\mathsf{log1p}\left(x\right)\right)}^{4} - {\log x}^{4}}{n}, -0.16666666666666666 \cdot \left({\left(\mathsf{log1p}\left(x\right)\right)}^{3} - {\log x}^{3}\right)\right)}{n}}{n} - \log \left(\frac{x}{x + 1}\right)}{n}\\ \mathbf{else}:\\ \;\;\;\;\frac{{x}^{\left(\frac{1}{n}\right)}}{x \cdot n}\\ \end{array} \]
          8. Add Preprocessing

          Alternative 4: 78.1% accurate, 0.4× speedup?

          \[\begin{array}{l} \\ \begin{array}{l} t_0 := {x}^{\left(\frac{1}{n}\right)}\\ t_1 := {\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - t\_0\\ t_2 := 1 - t\_0\\ \mathbf{if}\;t\_1 \leq -1 \cdot 10^{+21}:\\ \;\;\;\;t\_2\\ \mathbf{elif}\;t\_1 \leq 0:\\ \;\;\;\;\frac{\log \left(\frac{x + 1}{x}\right)}{n}\\ \mathbf{else}:\\ \;\;\;\;t\_2\\ \end{array} \end{array} \]
          (FPCore (x n)
           :precision binary64
           (let* ((t_0 (pow x (/ 1.0 n)))
                  (t_1 (- (pow (+ x 1.0) (/ 1.0 n)) t_0))
                  (t_2 (- 1.0 t_0)))
             (if (<= t_1 -1e+21) t_2 (if (<= t_1 0.0) (/ (log (/ (+ x 1.0) x)) n) t_2))))
          double code(double x, double n) {
          	double t_0 = pow(x, (1.0 / n));
          	double t_1 = pow((x + 1.0), (1.0 / n)) - t_0;
          	double t_2 = 1.0 - t_0;
          	double tmp;
          	if (t_1 <= -1e+21) {
          		tmp = t_2;
          	} else if (t_1 <= 0.0) {
          		tmp = log(((x + 1.0) / x)) / n;
          	} else {
          		tmp = t_2;
          	}
          	return tmp;
          }
          
          real(8) function code(x, n)
              real(8), intent (in) :: x
              real(8), intent (in) :: n
              real(8) :: t_0
              real(8) :: t_1
              real(8) :: t_2
              real(8) :: tmp
              t_0 = x ** (1.0d0 / n)
              t_1 = ((x + 1.0d0) ** (1.0d0 / n)) - t_0
              t_2 = 1.0d0 - t_0
              if (t_1 <= (-1d+21)) then
                  tmp = t_2
              else if (t_1 <= 0.0d0) then
                  tmp = log(((x + 1.0d0) / x)) / n
              else
                  tmp = t_2
              end if
              code = tmp
          end function
          
          public static double code(double x, double n) {
          	double t_0 = Math.pow(x, (1.0 / n));
          	double t_1 = Math.pow((x + 1.0), (1.0 / n)) - t_0;
          	double t_2 = 1.0 - t_0;
          	double tmp;
          	if (t_1 <= -1e+21) {
          		tmp = t_2;
          	} else if (t_1 <= 0.0) {
          		tmp = Math.log(((x + 1.0) / x)) / n;
          	} else {
          		tmp = t_2;
          	}
          	return tmp;
          }
          
          def code(x, n):
          	t_0 = math.pow(x, (1.0 / n))
          	t_1 = math.pow((x + 1.0), (1.0 / n)) - t_0
          	t_2 = 1.0 - t_0
          	tmp = 0
          	if t_1 <= -1e+21:
          		tmp = t_2
          	elif t_1 <= 0.0:
          		tmp = math.log(((x + 1.0) / x)) / n
          	else:
          		tmp = t_2
          	return tmp
          
          function code(x, n)
          	t_0 = x ^ Float64(1.0 / n)
          	t_1 = Float64((Float64(x + 1.0) ^ Float64(1.0 / n)) - t_0)
          	t_2 = Float64(1.0 - t_0)
          	tmp = 0.0
          	if (t_1 <= -1e+21)
          		tmp = t_2;
          	elseif (t_1 <= 0.0)
          		tmp = Float64(log(Float64(Float64(x + 1.0) / x)) / n);
          	else
          		tmp = t_2;
          	end
          	return tmp
          end
          
          function tmp_2 = code(x, n)
          	t_0 = x ^ (1.0 / n);
          	t_1 = ((x + 1.0) ^ (1.0 / n)) - t_0;
          	t_2 = 1.0 - t_0;
          	tmp = 0.0;
          	if (t_1 <= -1e+21)
          		tmp = t_2;
          	elseif (t_1 <= 0.0)
          		tmp = log(((x + 1.0) / x)) / n;
          	else
          		tmp = t_2;
          	end
          	tmp_2 = tmp;
          end
          
          code[x_, n_] := Block[{t$95$0 = N[Power[x, N[(1.0 / n), $MachinePrecision]], $MachinePrecision]}, Block[{t$95$1 = N[(N[Power[N[(x + 1.0), $MachinePrecision], N[(1.0 / n), $MachinePrecision]], $MachinePrecision] - t$95$0), $MachinePrecision]}, Block[{t$95$2 = N[(1.0 - t$95$0), $MachinePrecision]}, If[LessEqual[t$95$1, -1e+21], t$95$2, If[LessEqual[t$95$1, 0.0], N[(N[Log[N[(N[(x + 1.0), $MachinePrecision] / x), $MachinePrecision]], $MachinePrecision] / n), $MachinePrecision], t$95$2]]]]]
          
          \begin{array}{l}
          
          \\
          \begin{array}{l}
          t_0 := {x}^{\left(\frac{1}{n}\right)}\\
          t_1 := {\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - t\_0\\
          t_2 := 1 - t\_0\\
          \mathbf{if}\;t\_1 \leq -1 \cdot 10^{+21}:\\
          \;\;\;\;t\_2\\
          
          \mathbf{elif}\;t\_1 \leq 0:\\
          \;\;\;\;\frac{\log \left(\frac{x + 1}{x}\right)}{n}\\
          
          \mathbf{else}:\\
          \;\;\;\;t\_2\\
          
          
          \end{array}
          \end{array}
          
          Derivation
          1. Split input into 2 regimes
          2. if (-.f64 (pow.f64 (+.f64 x #s(literal 1 binary64)) (/.f64 #s(literal 1 binary64) n)) (pow.f64 x (/.f64 #s(literal 1 binary64) n))) < -1e21 or 0.0 < (-.f64 (pow.f64 (+.f64 x #s(literal 1 binary64)) (/.f64 #s(literal 1 binary64) n)) (pow.f64 x (/.f64 #s(literal 1 binary64) n)))

            1. Initial program 85.8%

              \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
            2. Add Preprocessing
            3. Taylor expanded in x around 0

              \[\leadsto \color{blue}{1} - {x}^{\left(\frac{1}{n}\right)} \]
            4. Step-by-step derivation
              1. Applied rewrites84.5%

                \[\leadsto \color{blue}{1} - {x}^{\left(\frac{1}{n}\right)} \]

              if -1e21 < (-.f64 (pow.f64 (+.f64 x #s(literal 1 binary64)) (/.f64 #s(literal 1 binary64) n)) (pow.f64 x (/.f64 #s(literal 1 binary64) n))) < 0.0

              1. Initial program 43.1%

                \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
              2. Add Preprocessing
              3. Taylor expanded in n around -inf

                \[\leadsto \color{blue}{-1 \cdot \frac{\left(-1 \cdot \log \left(1 + x\right) + -1 \cdot \frac{\left(-1 \cdot \frac{\left(-1 \cdot \frac{\frac{1}{24} \cdot {\log \left(1 + x\right)}^{4} - \frac{1}{24} \cdot {\log x}^{4}}{n} + \frac{-1}{6} \cdot {\log \left(1 + x\right)}^{3}\right) - \frac{-1}{6} \cdot {\log x}^{3}}{n} + \frac{1}{2} \cdot {\log \left(1 + x\right)}^{2}\right) - \frac{1}{2} \cdot {\log x}^{2}}{n}\right) - -1 \cdot \log x}{n}} \]
              4. Applied rewrites76.8%

                \[\leadsto \color{blue}{\frac{\left(\log x - \mathsf{log1p}\left(x\right)\right) - \frac{0.5 \cdot \left({\left(\mathsf{log1p}\left(x\right)\right)}^{2} - {\log x}^{2}\right) - \frac{\mathsf{fma}\left(-0.041666666666666664, \frac{{\left(\mathsf{log1p}\left(x\right)\right)}^{4} - {\log x}^{4}}{n}, -0.16666666666666666 \cdot \left({\left(\mathsf{log1p}\left(x\right)\right)}^{3} - {\log x}^{3}\right)\right)}{n}}{n}}{-n}} \]
              5. Step-by-step derivation
                1. Applied rewrites76.5%

                  \[\leadsto \frac{\left(-\log \left(\frac{x + 1}{x}\right)\right) - \frac{0.5 \cdot \left({\left(\mathsf{log1p}\left(x\right)\right)}^{2} - {\log x}^{2}\right) - \frac{\mathsf{fma}\left(-0.041666666666666664, \frac{{\left(\mathsf{log1p}\left(x\right)\right)}^{4} - {\log x}^{4}}{n}, -0.16666666666666666 \cdot \left({\left(\mathsf{log1p}\left(x\right)\right)}^{3} - {\log x}^{3}\right)\right)}{n}}{n}}{-n} \]
                2. Taylor expanded in n around inf

                  \[\leadsto \frac{\log \left(\frac{1 + x}{x}\right)}{\color{blue}{n}} \]
                3. Step-by-step derivation
                  1. Applied rewrites76.5%

                    \[\leadsto \frac{\log \left(\frac{x + 1}{x}\right)}{\color{blue}{n}} \]
                4. Recombined 2 regimes into one program.
                5. Add Preprocessing

                Alternative 5: 86.1% accurate, 0.8× speedup?

                \[\begin{array}{l} \\ \begin{array}{l} t_0 := {x}^{\left(\frac{1}{n}\right)}\\ \mathbf{if}\;\frac{1}{n} \leq -4 \cdot 10^{-80}:\\ \;\;\;\;\frac{t\_0}{x \cdot n}\\ \mathbf{elif}\;\frac{1}{n} \leq 2 \cdot 10^{-64}:\\ \;\;\;\;\frac{\log \left(\frac{x + 1}{x}\right)}{n}\\ \mathbf{elif}\;\frac{1}{n} \leq 0.5:\\ \;\;\;\;\frac{1}{x} \cdot \left(\left(\frac{1}{n} + \left(\frac{0.5}{x \cdot \left(n \cdot n\right)} + \frac{-0.5}{x \cdot n}\right)\right) \cdot t\_0\right)\\ \mathbf{else}:\\ \;\;\;\;e^{\frac{x}{n}} - t\_0\\ \end{array} \end{array} \]
                (FPCore (x n)
                 :precision binary64
                 (let* ((t_0 (pow x (/ 1.0 n))))
                   (if (<= (/ 1.0 n) -4e-80)
                     (/ t_0 (* x n))
                     (if (<= (/ 1.0 n) 2e-64)
                       (/ (log (/ (+ x 1.0) x)) n)
                       (if (<= (/ 1.0 n) 0.5)
                         (*
                          (/ 1.0 x)
                          (* (+ (/ 1.0 n) (+ (/ 0.5 (* x (* n n))) (/ -0.5 (* x n)))) t_0))
                         (- (exp (/ x n)) t_0))))))
                double code(double x, double n) {
                	double t_0 = pow(x, (1.0 / n));
                	double tmp;
                	if ((1.0 / n) <= -4e-80) {
                		tmp = t_0 / (x * n);
                	} else if ((1.0 / n) <= 2e-64) {
                		tmp = log(((x + 1.0) / x)) / n;
                	} else if ((1.0 / n) <= 0.5) {
                		tmp = (1.0 / x) * (((1.0 / n) + ((0.5 / (x * (n * n))) + (-0.5 / (x * n)))) * t_0);
                	} else {
                		tmp = exp((x / n)) - t_0;
                	}
                	return tmp;
                }
                
                real(8) function code(x, n)
                    real(8), intent (in) :: x
                    real(8), intent (in) :: n
                    real(8) :: t_0
                    real(8) :: tmp
                    t_0 = x ** (1.0d0 / n)
                    if ((1.0d0 / n) <= (-4d-80)) then
                        tmp = t_0 / (x * n)
                    else if ((1.0d0 / n) <= 2d-64) then
                        tmp = log(((x + 1.0d0) / x)) / n
                    else if ((1.0d0 / n) <= 0.5d0) then
                        tmp = (1.0d0 / x) * (((1.0d0 / n) + ((0.5d0 / (x * (n * n))) + ((-0.5d0) / (x * n)))) * t_0)
                    else
                        tmp = exp((x / n)) - t_0
                    end if
                    code = tmp
                end function
                
                public static double code(double x, double n) {
                	double t_0 = Math.pow(x, (1.0 / n));
                	double tmp;
                	if ((1.0 / n) <= -4e-80) {
                		tmp = t_0 / (x * n);
                	} else if ((1.0 / n) <= 2e-64) {
                		tmp = Math.log(((x + 1.0) / x)) / n;
                	} else if ((1.0 / n) <= 0.5) {
                		tmp = (1.0 / x) * (((1.0 / n) + ((0.5 / (x * (n * n))) + (-0.5 / (x * n)))) * t_0);
                	} else {
                		tmp = Math.exp((x / n)) - t_0;
                	}
                	return tmp;
                }
                
                def code(x, n):
                	t_0 = math.pow(x, (1.0 / n))
                	tmp = 0
                	if (1.0 / n) <= -4e-80:
                		tmp = t_0 / (x * n)
                	elif (1.0 / n) <= 2e-64:
                		tmp = math.log(((x + 1.0) / x)) / n
                	elif (1.0 / n) <= 0.5:
                		tmp = (1.0 / x) * (((1.0 / n) + ((0.5 / (x * (n * n))) + (-0.5 / (x * n)))) * t_0)
                	else:
                		tmp = math.exp((x / n)) - t_0
                	return tmp
                
                function code(x, n)
                	t_0 = x ^ Float64(1.0 / n)
                	tmp = 0.0
                	if (Float64(1.0 / n) <= -4e-80)
                		tmp = Float64(t_0 / Float64(x * n));
                	elseif (Float64(1.0 / n) <= 2e-64)
                		tmp = Float64(log(Float64(Float64(x + 1.0) / x)) / n);
                	elseif (Float64(1.0 / n) <= 0.5)
                		tmp = Float64(Float64(1.0 / x) * Float64(Float64(Float64(1.0 / n) + Float64(Float64(0.5 / Float64(x * Float64(n * n))) + Float64(-0.5 / Float64(x * n)))) * t_0));
                	else
                		tmp = Float64(exp(Float64(x / n)) - t_0);
                	end
                	return tmp
                end
                
                function tmp_2 = code(x, n)
                	t_0 = x ^ (1.0 / n);
                	tmp = 0.0;
                	if ((1.0 / n) <= -4e-80)
                		tmp = t_0 / (x * n);
                	elseif ((1.0 / n) <= 2e-64)
                		tmp = log(((x + 1.0) / x)) / n;
                	elseif ((1.0 / n) <= 0.5)
                		tmp = (1.0 / x) * (((1.0 / n) + ((0.5 / (x * (n * n))) + (-0.5 / (x * n)))) * t_0);
                	else
                		tmp = exp((x / n)) - t_0;
                	end
                	tmp_2 = tmp;
                end
                
                code[x_, n_] := Block[{t$95$0 = N[Power[x, N[(1.0 / n), $MachinePrecision]], $MachinePrecision]}, If[LessEqual[N[(1.0 / n), $MachinePrecision], -4e-80], N[(t$95$0 / N[(x * n), $MachinePrecision]), $MachinePrecision], If[LessEqual[N[(1.0 / n), $MachinePrecision], 2e-64], N[(N[Log[N[(N[(x + 1.0), $MachinePrecision] / x), $MachinePrecision]], $MachinePrecision] / n), $MachinePrecision], If[LessEqual[N[(1.0 / n), $MachinePrecision], 0.5], N[(N[(1.0 / x), $MachinePrecision] * N[(N[(N[(1.0 / n), $MachinePrecision] + N[(N[(0.5 / N[(x * N[(n * n), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] + N[(-0.5 / N[(x * n), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] * t$95$0), $MachinePrecision]), $MachinePrecision], N[(N[Exp[N[(x / n), $MachinePrecision]], $MachinePrecision] - t$95$0), $MachinePrecision]]]]]
                
                \begin{array}{l}
                
                \\
                \begin{array}{l}
                t_0 := {x}^{\left(\frac{1}{n}\right)}\\
                \mathbf{if}\;\frac{1}{n} \leq -4 \cdot 10^{-80}:\\
                \;\;\;\;\frac{t\_0}{x \cdot n}\\
                
                \mathbf{elif}\;\frac{1}{n} \leq 2 \cdot 10^{-64}:\\
                \;\;\;\;\frac{\log \left(\frac{x + 1}{x}\right)}{n}\\
                
                \mathbf{elif}\;\frac{1}{n} \leq 0.5:\\
                \;\;\;\;\frac{1}{x} \cdot \left(\left(\frac{1}{n} + \left(\frac{0.5}{x \cdot \left(n \cdot n\right)} + \frac{-0.5}{x \cdot n}\right)\right) \cdot t\_0\right)\\
                
                \mathbf{else}:\\
                \;\;\;\;e^{\frac{x}{n}} - t\_0\\
                
                
                \end{array}
                \end{array}
                
                Derivation
                1. Split input into 4 regimes
                2. if (/.f64 #s(literal 1 binary64) n) < -3.99999999999999985e-80

                  1. Initial program 78.0%

                    \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                  2. Add Preprocessing
                  3. Taylor expanded in x around inf

                    \[\leadsto \color{blue}{\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{n \cdot x}} \]
                  4. Step-by-step derivation
                    1. lower-/.f64N/A

                      \[\leadsto \color{blue}{\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{n \cdot x}} \]
                    2. log-recN/A

                      \[\leadsto \frac{e^{-1 \cdot \frac{\color{blue}{\mathsf{neg}\left(\log x\right)}}{n}}}{n \cdot x} \]
                    3. mul-1-negN/A

                      \[\leadsto \frac{e^{-1 \cdot \frac{\color{blue}{-1 \cdot \log x}}{n}}}{n \cdot x} \]
                    4. associate-*r/N/A

                      \[\leadsto \frac{e^{\color{blue}{\frac{-1 \cdot \left(-1 \cdot \log x\right)}{n}}}}{n \cdot x} \]
                    5. associate-*r*N/A

                      \[\leadsto \frac{e^{\frac{\color{blue}{\left(-1 \cdot -1\right) \cdot \log x}}{n}}}{n \cdot x} \]
                    6. metadata-evalN/A

                      \[\leadsto \frac{e^{\frac{\color{blue}{1} \cdot \log x}{n}}}{n \cdot x} \]
                    7. *-commutativeN/A

                      \[\leadsto \frac{e^{\frac{\color{blue}{\log x \cdot 1}}{n}}}{n \cdot x} \]
                    8. associate-/l*N/A

                      \[\leadsto \frac{e^{\color{blue}{\log x \cdot \frac{1}{n}}}}{n \cdot x} \]
                    9. exp-to-powN/A

                      \[\leadsto \frac{\color{blue}{{x}^{\left(\frac{1}{n}\right)}}}{n \cdot x} \]
                    10. lower-pow.f64N/A

                      \[\leadsto \frac{\color{blue}{{x}^{\left(\frac{1}{n}\right)}}}{n \cdot x} \]
                    11. lower-/.f64N/A

                      \[\leadsto \frac{{x}^{\color{blue}{\left(\frac{1}{n}\right)}}}{n \cdot x} \]
                    12. *-commutativeN/A

                      \[\leadsto \frac{{x}^{\left(\frac{1}{n}\right)}}{\color{blue}{x \cdot n}} \]
                    13. lower-*.f6488.6

                      \[\leadsto \frac{{x}^{\left(\frac{1}{n}\right)}}{\color{blue}{x \cdot n}} \]
                  5. Applied rewrites88.6%

                    \[\leadsto \color{blue}{\frac{{x}^{\left(\frac{1}{n}\right)}}{x \cdot n}} \]

                  if -3.99999999999999985e-80 < (/.f64 #s(literal 1 binary64) n) < 1.99999999999999993e-64

                  1. Initial program 36.4%

                    \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                  2. Add Preprocessing
                  3. Taylor expanded in n around -inf

                    \[\leadsto \color{blue}{-1 \cdot \frac{\left(-1 \cdot \log \left(1 + x\right) + -1 \cdot \frac{\left(-1 \cdot \frac{\left(-1 \cdot \frac{\frac{1}{24} \cdot {\log \left(1 + x\right)}^{4} - \frac{1}{24} \cdot {\log x}^{4}}{n} + \frac{-1}{6} \cdot {\log \left(1 + x\right)}^{3}\right) - \frac{-1}{6} \cdot {\log x}^{3}}{n} + \frac{1}{2} \cdot {\log \left(1 + x\right)}^{2}\right) - \frac{1}{2} \cdot {\log x}^{2}}{n}\right) - -1 \cdot \log x}{n}} \]
                  4. Applied rewrites80.9%

                    \[\leadsto \color{blue}{\frac{\left(\log x - \mathsf{log1p}\left(x\right)\right) - \frac{0.5 \cdot \left({\left(\mathsf{log1p}\left(x\right)\right)}^{2} - {\log x}^{2}\right) - \frac{\mathsf{fma}\left(-0.041666666666666664, \frac{{\left(\mathsf{log1p}\left(x\right)\right)}^{4} - {\log x}^{4}}{n}, -0.16666666666666666 \cdot \left({\left(\mathsf{log1p}\left(x\right)\right)}^{3} - {\log x}^{3}\right)\right)}{n}}{n}}{-n}} \]
                  5. Step-by-step derivation
                    1. Applied rewrites81.2%

                      \[\leadsto \frac{\left(-\log \left(\frac{x + 1}{x}\right)\right) - \frac{0.5 \cdot \left({\left(\mathsf{log1p}\left(x\right)\right)}^{2} - {\log x}^{2}\right) - \frac{\mathsf{fma}\left(-0.041666666666666664, \frac{{\left(\mathsf{log1p}\left(x\right)\right)}^{4} - {\log x}^{4}}{n}, -0.16666666666666666 \cdot \left({\left(\mathsf{log1p}\left(x\right)\right)}^{3} - {\log x}^{3}\right)\right)}{n}}{n}}{-n} \]
                    2. Taylor expanded in n around inf

                      \[\leadsto \frac{\log \left(\frac{1 + x}{x}\right)}{\color{blue}{n}} \]
                    3. Step-by-step derivation
                      1. Applied rewrites81.2%

                        \[\leadsto \frac{\log \left(\frac{x + 1}{x}\right)}{\color{blue}{n}} \]

                      if 1.99999999999999993e-64 < (/.f64 #s(literal 1 binary64) n) < 0.5

                      1. Initial program 13.5%

                        \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                      2. Add Preprocessing
                      3. Taylor expanded in x around inf

                        \[\leadsto \color{blue}{\frac{\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{n} + \frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}} \cdot \left(\frac{1}{2} \cdot \frac{1}{{n}^{2}} - \frac{1}{2} \cdot \frac{1}{n}\right)}{x}}{x}} \]
                      4. Step-by-step derivation
                        1. lower-/.f64N/A

                          \[\leadsto \color{blue}{\frac{\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{n} + \frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}} \cdot \left(\frac{1}{2} \cdot \frac{1}{{n}^{2}} - \frac{1}{2} \cdot \frac{1}{n}\right)}{x}}{x}} \]
                      5. Applied rewrites78.9%

                        \[\leadsto \color{blue}{\frac{\mathsf{fma}\left({x}^{\left(\frac{1}{n}\right)}, \frac{0.5}{x \cdot \left(n \cdot n\right)} - \frac{0.5}{x \cdot n}, \frac{{x}^{\left(\frac{1}{n}\right)}}{n}\right)}{x}} \]
                      6. Step-by-step derivation
                        1. Applied rewrites79.0%

                          \[\leadsto \frac{1}{x} \cdot \color{blue}{\left({x}^{\left(\frac{1}{n}\right)} \cdot \left(\frac{1}{n} + \left(\frac{0.5}{x \cdot \left(n \cdot n\right)} + \frac{-0.5}{x \cdot n}\right)\right)\right)} \]

                        if 0.5 < (/.f64 #s(literal 1 binary64) n)

                        1. Initial program 68.7%

                          \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                        2. Add Preprocessing
                        3. Step-by-step derivation
                          1. lift-pow.f64N/A

                            \[\leadsto \color{blue}{{\left(x + 1\right)}^{\left(\frac{1}{n}\right)}} - {x}^{\left(\frac{1}{n}\right)} \]
                          2. pow-to-expN/A

                            \[\leadsto \color{blue}{e^{\log \left(x + 1\right) \cdot \frac{1}{n}}} - {x}^{\left(\frac{1}{n}\right)} \]
                          3. lower-exp.f64N/A

                            \[\leadsto \color{blue}{e^{\log \left(x + 1\right) \cdot \frac{1}{n}}} - {x}^{\left(\frac{1}{n}\right)} \]
                          4. lift-/.f64N/A

                            \[\leadsto e^{\log \left(x + 1\right) \cdot \color{blue}{\frac{1}{n}}} - {x}^{\left(\frac{1}{n}\right)} \]
                          5. un-div-invN/A

                            \[\leadsto e^{\color{blue}{\frac{\log \left(x + 1\right)}{n}}} - {x}^{\left(\frac{1}{n}\right)} \]
                          6. lower-/.f64N/A

                            \[\leadsto e^{\color{blue}{\frac{\log \left(x + 1\right)}{n}}} - {x}^{\left(\frac{1}{n}\right)} \]
                          7. lift-+.f64N/A

                            \[\leadsto e^{\frac{\log \color{blue}{\left(x + 1\right)}}{n}} - {x}^{\left(\frac{1}{n}\right)} \]
                          8. +-commutativeN/A

                            \[\leadsto e^{\frac{\log \color{blue}{\left(1 + x\right)}}{n}} - {x}^{\left(\frac{1}{n}\right)} \]
                          9. lower-log1p.f64100.0

                            \[\leadsto e^{\frac{\color{blue}{\mathsf{log1p}\left(x\right)}}{n}} - {x}^{\left(\frac{1}{n}\right)} \]
                        4. Applied rewrites100.0%

                          \[\leadsto \color{blue}{e^{\frac{\mathsf{log1p}\left(x\right)}{n}}} - {x}^{\left(\frac{1}{n}\right)} \]
                        5. Taylor expanded in x around 0

                          \[\leadsto e^{\color{blue}{\frac{x}{n}}} - {x}^{\left(\frac{1}{n}\right)} \]
                        6. Step-by-step derivation
                          1. lower-/.f64100.0

                            \[\leadsto e^{\color{blue}{\frac{x}{n}}} - {x}^{\left(\frac{1}{n}\right)} \]
                        7. Applied rewrites100.0%

                          \[\leadsto e^{\color{blue}{\frac{x}{n}}} - {x}^{\left(\frac{1}{n}\right)} \]
                      7. Recombined 4 regimes into one program.
                      8. Final simplification86.4%

                        \[\leadsto \begin{array}{l} \mathbf{if}\;\frac{1}{n} \leq -4 \cdot 10^{-80}:\\ \;\;\;\;\frac{{x}^{\left(\frac{1}{n}\right)}}{x \cdot n}\\ \mathbf{elif}\;\frac{1}{n} \leq 2 \cdot 10^{-64}:\\ \;\;\;\;\frac{\log \left(\frac{x + 1}{x}\right)}{n}\\ \mathbf{elif}\;\frac{1}{n} \leq 0.5:\\ \;\;\;\;\frac{1}{x} \cdot \left(\left(\frac{1}{n} + \left(\frac{0.5}{x \cdot \left(n \cdot n\right)} + \frac{-0.5}{x \cdot n}\right)\right) \cdot {x}^{\left(\frac{1}{n}\right)}\right)\\ \mathbf{else}:\\ \;\;\;\;e^{\frac{x}{n}} - {x}^{\left(\frac{1}{n}\right)}\\ \end{array} \]
                      9. Add Preprocessing

                      Alternative 6: 82.4% accurate, 1.0× speedup?

                      \[\begin{array}{l} \\ \begin{array}{l} t_0 := {x}^{\left(\frac{1}{n}\right)}\\ \mathbf{if}\;\frac{1}{n} \leq -4 \cdot 10^{-80}:\\ \;\;\;\;\frac{t\_0}{x \cdot n}\\ \mathbf{elif}\;\frac{1}{n} \leq 2 \cdot 10^{-64}:\\ \;\;\;\;\frac{\log \left(\frac{x + 1}{x}\right)}{n}\\ \mathbf{elif}\;\frac{1}{n} \leq 0.5:\\ \;\;\;\;\frac{1}{x} \cdot \left(\left(\frac{1}{n} + \left(\frac{0.5}{x \cdot \left(n \cdot n\right)} + \frac{-0.5}{x \cdot n}\right)\right) \cdot t\_0\right)\\ \mathbf{else}:\\ \;\;\;\;\mathsf{fma}\left(x, \mathsf{fma}\left(x, \frac{0.5}{n \cdot n} + \frac{-0.5}{n}, \frac{1}{n}\right), 1\right) - t\_0\\ \end{array} \end{array} \]
                      (FPCore (x n)
                       :precision binary64
                       (let* ((t_0 (pow x (/ 1.0 n))))
                         (if (<= (/ 1.0 n) -4e-80)
                           (/ t_0 (* x n))
                           (if (<= (/ 1.0 n) 2e-64)
                             (/ (log (/ (+ x 1.0) x)) n)
                             (if (<= (/ 1.0 n) 0.5)
                               (*
                                (/ 1.0 x)
                                (* (+ (/ 1.0 n) (+ (/ 0.5 (* x (* n n))) (/ -0.5 (* x n)))) t_0))
                               (-
                                (fma x (fma x (+ (/ 0.5 (* n n)) (/ -0.5 n)) (/ 1.0 n)) 1.0)
                                t_0))))))
                      double code(double x, double n) {
                      	double t_0 = pow(x, (1.0 / n));
                      	double tmp;
                      	if ((1.0 / n) <= -4e-80) {
                      		tmp = t_0 / (x * n);
                      	} else if ((1.0 / n) <= 2e-64) {
                      		tmp = log(((x + 1.0) / x)) / n;
                      	} else if ((1.0 / n) <= 0.5) {
                      		tmp = (1.0 / x) * (((1.0 / n) + ((0.5 / (x * (n * n))) + (-0.5 / (x * n)))) * t_0);
                      	} else {
                      		tmp = fma(x, fma(x, ((0.5 / (n * n)) + (-0.5 / n)), (1.0 / n)), 1.0) - t_0;
                      	}
                      	return tmp;
                      }
                      
                      function code(x, n)
                      	t_0 = x ^ Float64(1.0 / n)
                      	tmp = 0.0
                      	if (Float64(1.0 / n) <= -4e-80)
                      		tmp = Float64(t_0 / Float64(x * n));
                      	elseif (Float64(1.0 / n) <= 2e-64)
                      		tmp = Float64(log(Float64(Float64(x + 1.0) / x)) / n);
                      	elseif (Float64(1.0 / n) <= 0.5)
                      		tmp = Float64(Float64(1.0 / x) * Float64(Float64(Float64(1.0 / n) + Float64(Float64(0.5 / Float64(x * Float64(n * n))) + Float64(-0.5 / Float64(x * n)))) * t_0));
                      	else
                      		tmp = Float64(fma(x, fma(x, Float64(Float64(0.5 / Float64(n * n)) + Float64(-0.5 / n)), Float64(1.0 / n)), 1.0) - t_0);
                      	end
                      	return tmp
                      end
                      
                      code[x_, n_] := Block[{t$95$0 = N[Power[x, N[(1.0 / n), $MachinePrecision]], $MachinePrecision]}, If[LessEqual[N[(1.0 / n), $MachinePrecision], -4e-80], N[(t$95$0 / N[(x * n), $MachinePrecision]), $MachinePrecision], If[LessEqual[N[(1.0 / n), $MachinePrecision], 2e-64], N[(N[Log[N[(N[(x + 1.0), $MachinePrecision] / x), $MachinePrecision]], $MachinePrecision] / n), $MachinePrecision], If[LessEqual[N[(1.0 / n), $MachinePrecision], 0.5], N[(N[(1.0 / x), $MachinePrecision] * N[(N[(N[(1.0 / n), $MachinePrecision] + N[(N[(0.5 / N[(x * N[(n * n), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] + N[(-0.5 / N[(x * n), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] * t$95$0), $MachinePrecision]), $MachinePrecision], N[(N[(x * N[(x * N[(N[(0.5 / N[(n * n), $MachinePrecision]), $MachinePrecision] + N[(-0.5 / n), $MachinePrecision]), $MachinePrecision] + N[(1.0 / n), $MachinePrecision]), $MachinePrecision] + 1.0), $MachinePrecision] - t$95$0), $MachinePrecision]]]]]
                      
                      \begin{array}{l}
                      
                      \\
                      \begin{array}{l}
                      t_0 := {x}^{\left(\frac{1}{n}\right)}\\
                      \mathbf{if}\;\frac{1}{n} \leq -4 \cdot 10^{-80}:\\
                      \;\;\;\;\frac{t\_0}{x \cdot n}\\
                      
                      \mathbf{elif}\;\frac{1}{n} \leq 2 \cdot 10^{-64}:\\
                      \;\;\;\;\frac{\log \left(\frac{x + 1}{x}\right)}{n}\\
                      
                      \mathbf{elif}\;\frac{1}{n} \leq 0.5:\\
                      \;\;\;\;\frac{1}{x} \cdot \left(\left(\frac{1}{n} + \left(\frac{0.5}{x \cdot \left(n \cdot n\right)} + \frac{-0.5}{x \cdot n}\right)\right) \cdot t\_0\right)\\
                      
                      \mathbf{else}:\\
                      \;\;\;\;\mathsf{fma}\left(x, \mathsf{fma}\left(x, \frac{0.5}{n \cdot n} + \frac{-0.5}{n}, \frac{1}{n}\right), 1\right) - t\_0\\
                      
                      
                      \end{array}
                      \end{array}
                      
                      Derivation
                      1. Split input into 4 regimes
                      2. if (/.f64 #s(literal 1 binary64) n) < -3.99999999999999985e-80

                        1. Initial program 78.0%

                          \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                        2. Add Preprocessing
                        3. Taylor expanded in x around inf

                          \[\leadsto \color{blue}{\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{n \cdot x}} \]
                        4. Step-by-step derivation
                          1. lower-/.f64N/A

                            \[\leadsto \color{blue}{\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{n \cdot x}} \]
                          2. log-recN/A

                            \[\leadsto \frac{e^{-1 \cdot \frac{\color{blue}{\mathsf{neg}\left(\log x\right)}}{n}}}{n \cdot x} \]
                          3. mul-1-negN/A

                            \[\leadsto \frac{e^{-1 \cdot \frac{\color{blue}{-1 \cdot \log x}}{n}}}{n \cdot x} \]
                          4. associate-*r/N/A

                            \[\leadsto \frac{e^{\color{blue}{\frac{-1 \cdot \left(-1 \cdot \log x\right)}{n}}}}{n \cdot x} \]
                          5. associate-*r*N/A

                            \[\leadsto \frac{e^{\frac{\color{blue}{\left(-1 \cdot -1\right) \cdot \log x}}{n}}}{n \cdot x} \]
                          6. metadata-evalN/A

                            \[\leadsto \frac{e^{\frac{\color{blue}{1} \cdot \log x}{n}}}{n \cdot x} \]
                          7. *-commutativeN/A

                            \[\leadsto \frac{e^{\frac{\color{blue}{\log x \cdot 1}}{n}}}{n \cdot x} \]
                          8. associate-/l*N/A

                            \[\leadsto \frac{e^{\color{blue}{\log x \cdot \frac{1}{n}}}}{n \cdot x} \]
                          9. exp-to-powN/A

                            \[\leadsto \frac{\color{blue}{{x}^{\left(\frac{1}{n}\right)}}}{n \cdot x} \]
                          10. lower-pow.f64N/A

                            \[\leadsto \frac{\color{blue}{{x}^{\left(\frac{1}{n}\right)}}}{n \cdot x} \]
                          11. lower-/.f64N/A

                            \[\leadsto \frac{{x}^{\color{blue}{\left(\frac{1}{n}\right)}}}{n \cdot x} \]
                          12. *-commutativeN/A

                            \[\leadsto \frac{{x}^{\left(\frac{1}{n}\right)}}{\color{blue}{x \cdot n}} \]
                          13. lower-*.f6488.6

                            \[\leadsto \frac{{x}^{\left(\frac{1}{n}\right)}}{\color{blue}{x \cdot n}} \]
                        5. Applied rewrites88.6%

                          \[\leadsto \color{blue}{\frac{{x}^{\left(\frac{1}{n}\right)}}{x \cdot n}} \]

                        if -3.99999999999999985e-80 < (/.f64 #s(literal 1 binary64) n) < 1.99999999999999993e-64

                        1. Initial program 36.4%

                          \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                        2. Add Preprocessing
                        3. Taylor expanded in n around -inf

                          \[\leadsto \color{blue}{-1 \cdot \frac{\left(-1 \cdot \log \left(1 + x\right) + -1 \cdot \frac{\left(-1 \cdot \frac{\left(-1 \cdot \frac{\frac{1}{24} \cdot {\log \left(1 + x\right)}^{4} - \frac{1}{24} \cdot {\log x}^{4}}{n} + \frac{-1}{6} \cdot {\log \left(1 + x\right)}^{3}\right) - \frac{-1}{6} \cdot {\log x}^{3}}{n} + \frac{1}{2} \cdot {\log \left(1 + x\right)}^{2}\right) - \frac{1}{2} \cdot {\log x}^{2}}{n}\right) - -1 \cdot \log x}{n}} \]
                        4. Applied rewrites80.9%

                          \[\leadsto \color{blue}{\frac{\left(\log x - \mathsf{log1p}\left(x\right)\right) - \frac{0.5 \cdot \left({\left(\mathsf{log1p}\left(x\right)\right)}^{2} - {\log x}^{2}\right) - \frac{\mathsf{fma}\left(-0.041666666666666664, \frac{{\left(\mathsf{log1p}\left(x\right)\right)}^{4} - {\log x}^{4}}{n}, -0.16666666666666666 \cdot \left({\left(\mathsf{log1p}\left(x\right)\right)}^{3} - {\log x}^{3}\right)\right)}{n}}{n}}{-n}} \]
                        5. Step-by-step derivation
                          1. Applied rewrites81.2%

                            \[\leadsto \frac{\left(-\log \left(\frac{x + 1}{x}\right)\right) - \frac{0.5 \cdot \left({\left(\mathsf{log1p}\left(x\right)\right)}^{2} - {\log x}^{2}\right) - \frac{\mathsf{fma}\left(-0.041666666666666664, \frac{{\left(\mathsf{log1p}\left(x\right)\right)}^{4} - {\log x}^{4}}{n}, -0.16666666666666666 \cdot \left({\left(\mathsf{log1p}\left(x\right)\right)}^{3} - {\log x}^{3}\right)\right)}{n}}{n}}{-n} \]
                          2. Taylor expanded in n around inf

                            \[\leadsto \frac{\log \left(\frac{1 + x}{x}\right)}{\color{blue}{n}} \]
                          3. Step-by-step derivation
                            1. Applied rewrites81.2%

                              \[\leadsto \frac{\log \left(\frac{x + 1}{x}\right)}{\color{blue}{n}} \]

                            if 1.99999999999999993e-64 < (/.f64 #s(literal 1 binary64) n) < 0.5

                            1. Initial program 13.5%

                              \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                            2. Add Preprocessing
                            3. Taylor expanded in x around inf

                              \[\leadsto \color{blue}{\frac{\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{n} + \frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}} \cdot \left(\frac{1}{2} \cdot \frac{1}{{n}^{2}} - \frac{1}{2} \cdot \frac{1}{n}\right)}{x}}{x}} \]
                            4. Step-by-step derivation
                              1. lower-/.f64N/A

                                \[\leadsto \color{blue}{\frac{\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{n} + \frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}} \cdot \left(\frac{1}{2} \cdot \frac{1}{{n}^{2}} - \frac{1}{2} \cdot \frac{1}{n}\right)}{x}}{x}} \]
                            5. Applied rewrites78.9%

                              \[\leadsto \color{blue}{\frac{\mathsf{fma}\left({x}^{\left(\frac{1}{n}\right)}, \frac{0.5}{x \cdot \left(n \cdot n\right)} - \frac{0.5}{x \cdot n}, \frac{{x}^{\left(\frac{1}{n}\right)}}{n}\right)}{x}} \]
                            6. Step-by-step derivation
                              1. Applied rewrites79.0%

                                \[\leadsto \frac{1}{x} \cdot \color{blue}{\left({x}^{\left(\frac{1}{n}\right)} \cdot \left(\frac{1}{n} + \left(\frac{0.5}{x \cdot \left(n \cdot n\right)} + \frac{-0.5}{x \cdot n}\right)\right)\right)} \]

                              if 0.5 < (/.f64 #s(literal 1 binary64) n)

                              1. Initial program 68.7%

                                \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                              2. Add Preprocessing
                              3. Taylor expanded in x around 0

                                \[\leadsto \color{blue}{\left(1 + x \cdot \left(x \cdot \left(\frac{1}{2} \cdot \frac{1}{{n}^{2}} - \frac{1}{2} \cdot \frac{1}{n}\right) + \frac{1}{n}\right)\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                              4. Step-by-step derivation
                                1. +-commutativeN/A

                                  \[\leadsto \color{blue}{\left(x \cdot \left(x \cdot \left(\frac{1}{2} \cdot \frac{1}{{n}^{2}} - \frac{1}{2} \cdot \frac{1}{n}\right) + \frac{1}{n}\right) + 1\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                                2. lower-fma.f64N/A

                                  \[\leadsto \color{blue}{\mathsf{fma}\left(x, x \cdot \left(\frac{1}{2} \cdot \frac{1}{{n}^{2}} - \frac{1}{2} \cdot \frac{1}{n}\right) + \frac{1}{n}, 1\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                                3. lower-fma.f64N/A

                                  \[\leadsto \mathsf{fma}\left(x, \color{blue}{\mathsf{fma}\left(x, \frac{1}{2} \cdot \frac{1}{{n}^{2}} - \frac{1}{2} \cdot \frac{1}{n}, \frac{1}{n}\right)}, 1\right) - {x}^{\left(\frac{1}{n}\right)} \]
                                4. sub-negN/A

                                  \[\leadsto \mathsf{fma}\left(x, \mathsf{fma}\left(x, \color{blue}{\frac{1}{2} \cdot \frac{1}{{n}^{2}} + \left(\mathsf{neg}\left(\frac{1}{2} \cdot \frac{1}{n}\right)\right)}, \frac{1}{n}\right), 1\right) - {x}^{\left(\frac{1}{n}\right)} \]
                                5. lower-+.f64N/A

                                  \[\leadsto \mathsf{fma}\left(x, \mathsf{fma}\left(x, \color{blue}{\frac{1}{2} \cdot \frac{1}{{n}^{2}} + \left(\mathsf{neg}\left(\frac{1}{2} \cdot \frac{1}{n}\right)\right)}, \frac{1}{n}\right), 1\right) - {x}^{\left(\frac{1}{n}\right)} \]
                                6. associate-*r/N/A

                                  \[\leadsto \mathsf{fma}\left(x, \mathsf{fma}\left(x, \color{blue}{\frac{\frac{1}{2} \cdot 1}{{n}^{2}}} + \left(\mathsf{neg}\left(\frac{1}{2} \cdot \frac{1}{n}\right)\right), \frac{1}{n}\right), 1\right) - {x}^{\left(\frac{1}{n}\right)} \]
                                7. metadata-evalN/A

                                  \[\leadsto \mathsf{fma}\left(x, \mathsf{fma}\left(x, \frac{\color{blue}{\frac{1}{2}}}{{n}^{2}} + \left(\mathsf{neg}\left(\frac{1}{2} \cdot \frac{1}{n}\right)\right), \frac{1}{n}\right), 1\right) - {x}^{\left(\frac{1}{n}\right)} \]
                                8. lower-/.f64N/A

                                  \[\leadsto \mathsf{fma}\left(x, \mathsf{fma}\left(x, \color{blue}{\frac{\frac{1}{2}}{{n}^{2}}} + \left(\mathsf{neg}\left(\frac{1}{2} \cdot \frac{1}{n}\right)\right), \frac{1}{n}\right), 1\right) - {x}^{\left(\frac{1}{n}\right)} \]
                                9. unpow2N/A

                                  \[\leadsto \mathsf{fma}\left(x, \mathsf{fma}\left(x, \frac{\frac{1}{2}}{\color{blue}{n \cdot n}} + \left(\mathsf{neg}\left(\frac{1}{2} \cdot \frac{1}{n}\right)\right), \frac{1}{n}\right), 1\right) - {x}^{\left(\frac{1}{n}\right)} \]
                                10. lower-*.f64N/A

                                  \[\leadsto \mathsf{fma}\left(x, \mathsf{fma}\left(x, \frac{\frac{1}{2}}{\color{blue}{n \cdot n}} + \left(\mathsf{neg}\left(\frac{1}{2} \cdot \frac{1}{n}\right)\right), \frac{1}{n}\right), 1\right) - {x}^{\left(\frac{1}{n}\right)} \]
                                11. associate-*r/N/A

                                  \[\leadsto \mathsf{fma}\left(x, \mathsf{fma}\left(x, \frac{\frac{1}{2}}{n \cdot n} + \left(\mathsf{neg}\left(\color{blue}{\frac{\frac{1}{2} \cdot 1}{n}}\right)\right), \frac{1}{n}\right), 1\right) - {x}^{\left(\frac{1}{n}\right)} \]
                                12. metadata-evalN/A

                                  \[\leadsto \mathsf{fma}\left(x, \mathsf{fma}\left(x, \frac{\frac{1}{2}}{n \cdot n} + \left(\mathsf{neg}\left(\frac{\color{blue}{\frac{1}{2}}}{n}\right)\right), \frac{1}{n}\right), 1\right) - {x}^{\left(\frac{1}{n}\right)} \]
                                13. distribute-neg-fracN/A

                                  \[\leadsto \mathsf{fma}\left(x, \mathsf{fma}\left(x, \frac{\frac{1}{2}}{n \cdot n} + \color{blue}{\frac{\mathsf{neg}\left(\frac{1}{2}\right)}{n}}, \frac{1}{n}\right), 1\right) - {x}^{\left(\frac{1}{n}\right)} \]
                                14. metadata-evalN/A

                                  \[\leadsto \mathsf{fma}\left(x, \mathsf{fma}\left(x, \frac{\frac{1}{2}}{n \cdot n} + \frac{\color{blue}{\frac{-1}{2}}}{n}, \frac{1}{n}\right), 1\right) - {x}^{\left(\frac{1}{n}\right)} \]
                                15. lower-/.f64N/A

                                  \[\leadsto \mathsf{fma}\left(x, \mathsf{fma}\left(x, \frac{\frac{1}{2}}{n \cdot n} + \color{blue}{\frac{\frac{-1}{2}}{n}}, \frac{1}{n}\right), 1\right) - {x}^{\left(\frac{1}{n}\right)} \]
                                16. lower-/.f6484.6

                                  \[\leadsto \mathsf{fma}\left(x, \mathsf{fma}\left(x, \frac{0.5}{n \cdot n} + \frac{-0.5}{n}, \color{blue}{\frac{1}{n}}\right), 1\right) - {x}^{\left(\frac{1}{n}\right)} \]
                              5. Applied rewrites84.6%

                                \[\leadsto \color{blue}{\mathsf{fma}\left(x, \mathsf{fma}\left(x, \frac{0.5}{n \cdot n} + \frac{-0.5}{n}, \frac{1}{n}\right), 1\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                            7. Recombined 4 regimes into one program.
                            8. Final simplification84.4%

                              \[\leadsto \begin{array}{l} \mathbf{if}\;\frac{1}{n} \leq -4 \cdot 10^{-80}:\\ \;\;\;\;\frac{{x}^{\left(\frac{1}{n}\right)}}{x \cdot n}\\ \mathbf{elif}\;\frac{1}{n} \leq 2 \cdot 10^{-64}:\\ \;\;\;\;\frac{\log \left(\frac{x + 1}{x}\right)}{n}\\ \mathbf{elif}\;\frac{1}{n} \leq 0.5:\\ \;\;\;\;\frac{1}{x} \cdot \left(\left(\frac{1}{n} + \left(\frac{0.5}{x \cdot \left(n \cdot n\right)} + \frac{-0.5}{x \cdot n}\right)\right) \cdot {x}^{\left(\frac{1}{n}\right)}\right)\\ \mathbf{else}:\\ \;\;\;\;\mathsf{fma}\left(x, \mathsf{fma}\left(x, \frac{0.5}{n \cdot n} + \frac{-0.5}{n}, \frac{1}{n}\right), 1\right) - {x}^{\left(\frac{1}{n}\right)}\\ \end{array} \]
                            9. Add Preprocessing

                            Alternative 7: 82.4% accurate, 1.0× speedup?

                            \[\begin{array}{l} \\ \begin{array}{l} t_0 := {x}^{\left(\frac{1}{n}\right)}\\ t_1 := \frac{t\_0}{x \cdot n}\\ \mathbf{if}\;\frac{1}{n} \leq -4 \cdot 10^{-80}:\\ \;\;\;\;t\_1\\ \mathbf{elif}\;\frac{1}{n} \leq 2 \cdot 10^{-64}:\\ \;\;\;\;\frac{\log \left(\frac{x + 1}{x}\right)}{n}\\ \mathbf{elif}\;\frac{1}{n} \leq 0.5:\\ \;\;\;\;t\_1\\ \mathbf{else}:\\ \;\;\;\;\mathsf{fma}\left(x, \mathsf{fma}\left(x, \frac{0.5}{n \cdot n} + \frac{-0.5}{n}, \frac{1}{n}\right), 1\right) - t\_0\\ \end{array} \end{array} \]
                            (FPCore (x n)
                             :precision binary64
                             (let* ((t_0 (pow x (/ 1.0 n))) (t_1 (/ t_0 (* x n))))
                               (if (<= (/ 1.0 n) -4e-80)
                                 t_1
                                 (if (<= (/ 1.0 n) 2e-64)
                                   (/ (log (/ (+ x 1.0) x)) n)
                                   (if (<= (/ 1.0 n) 0.5)
                                     t_1
                                     (-
                                      (fma x (fma x (+ (/ 0.5 (* n n)) (/ -0.5 n)) (/ 1.0 n)) 1.0)
                                      t_0))))))
                            double code(double x, double n) {
                            	double t_0 = pow(x, (1.0 / n));
                            	double t_1 = t_0 / (x * n);
                            	double tmp;
                            	if ((1.0 / n) <= -4e-80) {
                            		tmp = t_1;
                            	} else if ((1.0 / n) <= 2e-64) {
                            		tmp = log(((x + 1.0) / x)) / n;
                            	} else if ((1.0 / n) <= 0.5) {
                            		tmp = t_1;
                            	} else {
                            		tmp = fma(x, fma(x, ((0.5 / (n * n)) + (-0.5 / n)), (1.0 / n)), 1.0) - t_0;
                            	}
                            	return tmp;
                            }
                            
                            function code(x, n)
                            	t_0 = x ^ Float64(1.0 / n)
                            	t_1 = Float64(t_0 / Float64(x * n))
                            	tmp = 0.0
                            	if (Float64(1.0 / n) <= -4e-80)
                            		tmp = t_1;
                            	elseif (Float64(1.0 / n) <= 2e-64)
                            		tmp = Float64(log(Float64(Float64(x + 1.0) / x)) / n);
                            	elseif (Float64(1.0 / n) <= 0.5)
                            		tmp = t_1;
                            	else
                            		tmp = Float64(fma(x, fma(x, Float64(Float64(0.5 / Float64(n * n)) + Float64(-0.5 / n)), Float64(1.0 / n)), 1.0) - t_0);
                            	end
                            	return tmp
                            end
                            
                            code[x_, n_] := Block[{t$95$0 = N[Power[x, N[(1.0 / n), $MachinePrecision]], $MachinePrecision]}, Block[{t$95$1 = N[(t$95$0 / N[(x * n), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[N[(1.0 / n), $MachinePrecision], -4e-80], t$95$1, If[LessEqual[N[(1.0 / n), $MachinePrecision], 2e-64], N[(N[Log[N[(N[(x + 1.0), $MachinePrecision] / x), $MachinePrecision]], $MachinePrecision] / n), $MachinePrecision], If[LessEqual[N[(1.0 / n), $MachinePrecision], 0.5], t$95$1, N[(N[(x * N[(x * N[(N[(0.5 / N[(n * n), $MachinePrecision]), $MachinePrecision] + N[(-0.5 / n), $MachinePrecision]), $MachinePrecision] + N[(1.0 / n), $MachinePrecision]), $MachinePrecision] + 1.0), $MachinePrecision] - t$95$0), $MachinePrecision]]]]]]
                            
                            \begin{array}{l}
                            
                            \\
                            \begin{array}{l}
                            t_0 := {x}^{\left(\frac{1}{n}\right)}\\
                            t_1 := \frac{t\_0}{x \cdot n}\\
                            \mathbf{if}\;\frac{1}{n} \leq -4 \cdot 10^{-80}:\\
                            \;\;\;\;t\_1\\
                            
                            \mathbf{elif}\;\frac{1}{n} \leq 2 \cdot 10^{-64}:\\
                            \;\;\;\;\frac{\log \left(\frac{x + 1}{x}\right)}{n}\\
                            
                            \mathbf{elif}\;\frac{1}{n} \leq 0.5:\\
                            \;\;\;\;t\_1\\
                            
                            \mathbf{else}:\\
                            \;\;\;\;\mathsf{fma}\left(x, \mathsf{fma}\left(x, \frac{0.5}{n \cdot n} + \frac{-0.5}{n}, \frac{1}{n}\right), 1\right) - t\_0\\
                            
                            
                            \end{array}
                            \end{array}
                            
                            Derivation
                            1. Split input into 3 regimes
                            2. if (/.f64 #s(literal 1 binary64) n) < -3.99999999999999985e-80 or 1.99999999999999993e-64 < (/.f64 #s(literal 1 binary64) n) < 0.5

                              1. Initial program 72.1%

                                \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                              2. Add Preprocessing
                              3. Taylor expanded in x around inf

                                \[\leadsto \color{blue}{\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{n \cdot x}} \]
                              4. Step-by-step derivation
                                1. lower-/.f64N/A

                                  \[\leadsto \color{blue}{\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{n \cdot x}} \]
                                2. log-recN/A

                                  \[\leadsto \frac{e^{-1 \cdot \frac{\color{blue}{\mathsf{neg}\left(\log x\right)}}{n}}}{n \cdot x} \]
                                3. mul-1-negN/A

                                  \[\leadsto \frac{e^{-1 \cdot \frac{\color{blue}{-1 \cdot \log x}}{n}}}{n \cdot x} \]
                                4. associate-*r/N/A

                                  \[\leadsto \frac{e^{\color{blue}{\frac{-1 \cdot \left(-1 \cdot \log x\right)}{n}}}}{n \cdot x} \]
                                5. associate-*r*N/A

                                  \[\leadsto \frac{e^{\frac{\color{blue}{\left(-1 \cdot -1\right) \cdot \log x}}{n}}}{n \cdot x} \]
                                6. metadata-evalN/A

                                  \[\leadsto \frac{e^{\frac{\color{blue}{1} \cdot \log x}{n}}}{n \cdot x} \]
                                7. *-commutativeN/A

                                  \[\leadsto \frac{e^{\frac{\color{blue}{\log x \cdot 1}}{n}}}{n \cdot x} \]
                                8. associate-/l*N/A

                                  \[\leadsto \frac{e^{\color{blue}{\log x \cdot \frac{1}{n}}}}{n \cdot x} \]
                                9. exp-to-powN/A

                                  \[\leadsto \frac{\color{blue}{{x}^{\left(\frac{1}{n}\right)}}}{n \cdot x} \]
                                10. lower-pow.f64N/A

                                  \[\leadsto \frac{\color{blue}{{x}^{\left(\frac{1}{n}\right)}}}{n \cdot x} \]
                                11. lower-/.f64N/A

                                  \[\leadsto \frac{{x}^{\color{blue}{\left(\frac{1}{n}\right)}}}{n \cdot x} \]
                                12. *-commutativeN/A

                                  \[\leadsto \frac{{x}^{\left(\frac{1}{n}\right)}}{\color{blue}{x \cdot n}} \]
                                13. lower-*.f6487.5

                                  \[\leadsto \frac{{x}^{\left(\frac{1}{n}\right)}}{\color{blue}{x \cdot n}} \]
                              5. Applied rewrites87.5%

                                \[\leadsto \color{blue}{\frac{{x}^{\left(\frac{1}{n}\right)}}{x \cdot n}} \]

                              if -3.99999999999999985e-80 < (/.f64 #s(literal 1 binary64) n) < 1.99999999999999993e-64

                              1. Initial program 36.4%

                                \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                              2. Add Preprocessing
                              3. Taylor expanded in n around -inf

                                \[\leadsto \color{blue}{-1 \cdot \frac{\left(-1 \cdot \log \left(1 + x\right) + -1 \cdot \frac{\left(-1 \cdot \frac{\left(-1 \cdot \frac{\frac{1}{24} \cdot {\log \left(1 + x\right)}^{4} - \frac{1}{24} \cdot {\log x}^{4}}{n} + \frac{-1}{6} \cdot {\log \left(1 + x\right)}^{3}\right) - \frac{-1}{6} \cdot {\log x}^{3}}{n} + \frac{1}{2} \cdot {\log \left(1 + x\right)}^{2}\right) - \frac{1}{2} \cdot {\log x}^{2}}{n}\right) - -1 \cdot \log x}{n}} \]
                              4. Applied rewrites80.9%

                                \[\leadsto \color{blue}{\frac{\left(\log x - \mathsf{log1p}\left(x\right)\right) - \frac{0.5 \cdot \left({\left(\mathsf{log1p}\left(x\right)\right)}^{2} - {\log x}^{2}\right) - \frac{\mathsf{fma}\left(-0.041666666666666664, \frac{{\left(\mathsf{log1p}\left(x\right)\right)}^{4} - {\log x}^{4}}{n}, -0.16666666666666666 \cdot \left({\left(\mathsf{log1p}\left(x\right)\right)}^{3} - {\log x}^{3}\right)\right)}{n}}{n}}{-n}} \]
                              5. Step-by-step derivation
                                1. Applied rewrites81.2%

                                  \[\leadsto \frac{\left(-\log \left(\frac{x + 1}{x}\right)\right) - \frac{0.5 \cdot \left({\left(\mathsf{log1p}\left(x\right)\right)}^{2} - {\log x}^{2}\right) - \frac{\mathsf{fma}\left(-0.041666666666666664, \frac{{\left(\mathsf{log1p}\left(x\right)\right)}^{4} - {\log x}^{4}}{n}, -0.16666666666666666 \cdot \left({\left(\mathsf{log1p}\left(x\right)\right)}^{3} - {\log x}^{3}\right)\right)}{n}}{n}}{-n} \]
                                2. Taylor expanded in n around inf

                                  \[\leadsto \frac{\log \left(\frac{1 + x}{x}\right)}{\color{blue}{n}} \]
                                3. Step-by-step derivation
                                  1. Applied rewrites81.2%

                                    \[\leadsto \frac{\log \left(\frac{x + 1}{x}\right)}{\color{blue}{n}} \]

                                  if 0.5 < (/.f64 #s(literal 1 binary64) n)

                                  1. Initial program 68.7%

                                    \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                                  2. Add Preprocessing
                                  3. Taylor expanded in x around 0

                                    \[\leadsto \color{blue}{\left(1 + x \cdot \left(x \cdot \left(\frac{1}{2} \cdot \frac{1}{{n}^{2}} - \frac{1}{2} \cdot \frac{1}{n}\right) + \frac{1}{n}\right)\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                                  4. Step-by-step derivation
                                    1. +-commutativeN/A

                                      \[\leadsto \color{blue}{\left(x \cdot \left(x \cdot \left(\frac{1}{2} \cdot \frac{1}{{n}^{2}} - \frac{1}{2} \cdot \frac{1}{n}\right) + \frac{1}{n}\right) + 1\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                                    2. lower-fma.f64N/A

                                      \[\leadsto \color{blue}{\mathsf{fma}\left(x, x \cdot \left(\frac{1}{2} \cdot \frac{1}{{n}^{2}} - \frac{1}{2} \cdot \frac{1}{n}\right) + \frac{1}{n}, 1\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                                    3. lower-fma.f64N/A

                                      \[\leadsto \mathsf{fma}\left(x, \color{blue}{\mathsf{fma}\left(x, \frac{1}{2} \cdot \frac{1}{{n}^{2}} - \frac{1}{2} \cdot \frac{1}{n}, \frac{1}{n}\right)}, 1\right) - {x}^{\left(\frac{1}{n}\right)} \]
                                    4. sub-negN/A

                                      \[\leadsto \mathsf{fma}\left(x, \mathsf{fma}\left(x, \color{blue}{\frac{1}{2} \cdot \frac{1}{{n}^{2}} + \left(\mathsf{neg}\left(\frac{1}{2} \cdot \frac{1}{n}\right)\right)}, \frac{1}{n}\right), 1\right) - {x}^{\left(\frac{1}{n}\right)} \]
                                    5. lower-+.f64N/A

                                      \[\leadsto \mathsf{fma}\left(x, \mathsf{fma}\left(x, \color{blue}{\frac{1}{2} \cdot \frac{1}{{n}^{2}} + \left(\mathsf{neg}\left(\frac{1}{2} \cdot \frac{1}{n}\right)\right)}, \frac{1}{n}\right), 1\right) - {x}^{\left(\frac{1}{n}\right)} \]
                                    6. associate-*r/N/A

                                      \[\leadsto \mathsf{fma}\left(x, \mathsf{fma}\left(x, \color{blue}{\frac{\frac{1}{2} \cdot 1}{{n}^{2}}} + \left(\mathsf{neg}\left(\frac{1}{2} \cdot \frac{1}{n}\right)\right), \frac{1}{n}\right), 1\right) - {x}^{\left(\frac{1}{n}\right)} \]
                                    7. metadata-evalN/A

                                      \[\leadsto \mathsf{fma}\left(x, \mathsf{fma}\left(x, \frac{\color{blue}{\frac{1}{2}}}{{n}^{2}} + \left(\mathsf{neg}\left(\frac{1}{2} \cdot \frac{1}{n}\right)\right), \frac{1}{n}\right), 1\right) - {x}^{\left(\frac{1}{n}\right)} \]
                                    8. lower-/.f64N/A

                                      \[\leadsto \mathsf{fma}\left(x, \mathsf{fma}\left(x, \color{blue}{\frac{\frac{1}{2}}{{n}^{2}}} + \left(\mathsf{neg}\left(\frac{1}{2} \cdot \frac{1}{n}\right)\right), \frac{1}{n}\right), 1\right) - {x}^{\left(\frac{1}{n}\right)} \]
                                    9. unpow2N/A

                                      \[\leadsto \mathsf{fma}\left(x, \mathsf{fma}\left(x, \frac{\frac{1}{2}}{\color{blue}{n \cdot n}} + \left(\mathsf{neg}\left(\frac{1}{2} \cdot \frac{1}{n}\right)\right), \frac{1}{n}\right), 1\right) - {x}^{\left(\frac{1}{n}\right)} \]
                                    10. lower-*.f64N/A

                                      \[\leadsto \mathsf{fma}\left(x, \mathsf{fma}\left(x, \frac{\frac{1}{2}}{\color{blue}{n \cdot n}} + \left(\mathsf{neg}\left(\frac{1}{2} \cdot \frac{1}{n}\right)\right), \frac{1}{n}\right), 1\right) - {x}^{\left(\frac{1}{n}\right)} \]
                                    11. associate-*r/N/A

                                      \[\leadsto \mathsf{fma}\left(x, \mathsf{fma}\left(x, \frac{\frac{1}{2}}{n \cdot n} + \left(\mathsf{neg}\left(\color{blue}{\frac{\frac{1}{2} \cdot 1}{n}}\right)\right), \frac{1}{n}\right), 1\right) - {x}^{\left(\frac{1}{n}\right)} \]
                                    12. metadata-evalN/A

                                      \[\leadsto \mathsf{fma}\left(x, \mathsf{fma}\left(x, \frac{\frac{1}{2}}{n \cdot n} + \left(\mathsf{neg}\left(\frac{\color{blue}{\frac{1}{2}}}{n}\right)\right), \frac{1}{n}\right), 1\right) - {x}^{\left(\frac{1}{n}\right)} \]
                                    13. distribute-neg-fracN/A

                                      \[\leadsto \mathsf{fma}\left(x, \mathsf{fma}\left(x, \frac{\frac{1}{2}}{n \cdot n} + \color{blue}{\frac{\mathsf{neg}\left(\frac{1}{2}\right)}{n}}, \frac{1}{n}\right), 1\right) - {x}^{\left(\frac{1}{n}\right)} \]
                                    14. metadata-evalN/A

                                      \[\leadsto \mathsf{fma}\left(x, \mathsf{fma}\left(x, \frac{\frac{1}{2}}{n \cdot n} + \frac{\color{blue}{\frac{-1}{2}}}{n}, \frac{1}{n}\right), 1\right) - {x}^{\left(\frac{1}{n}\right)} \]
                                    15. lower-/.f64N/A

                                      \[\leadsto \mathsf{fma}\left(x, \mathsf{fma}\left(x, \frac{\frac{1}{2}}{n \cdot n} + \color{blue}{\frac{\frac{-1}{2}}{n}}, \frac{1}{n}\right), 1\right) - {x}^{\left(\frac{1}{n}\right)} \]
                                    16. lower-/.f6484.6

                                      \[\leadsto \mathsf{fma}\left(x, \mathsf{fma}\left(x, \frac{0.5}{n \cdot n} + \frac{-0.5}{n}, \color{blue}{\frac{1}{n}}\right), 1\right) - {x}^{\left(\frac{1}{n}\right)} \]
                                  5. Applied rewrites84.6%

                                    \[\leadsto \color{blue}{\mathsf{fma}\left(x, \mathsf{fma}\left(x, \frac{0.5}{n \cdot n} + \frac{-0.5}{n}, \frac{1}{n}\right), 1\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                                4. Recombined 3 regimes into one program.
                                5. Add Preprocessing

                                Alternative 8: 82.4% accurate, 1.1× speedup?

                                \[\begin{array}{l} \\ \begin{array}{l} t_0 := {x}^{\left(\frac{1}{n}\right)}\\ t_1 := \frac{t\_0}{x \cdot n}\\ \mathbf{if}\;\frac{1}{n} \leq -4 \cdot 10^{-80}:\\ \;\;\;\;t\_1\\ \mathbf{elif}\;\frac{1}{n} \leq 2 \cdot 10^{-64}:\\ \;\;\;\;\frac{\log \left(\frac{x + 1}{x}\right)}{n}\\ \mathbf{elif}\;\frac{1}{n} \leq 0.5:\\ \;\;\;\;t\_1\\ \mathbf{else}:\\ \;\;\;\;\mathsf{fma}\left(x, \frac{\mathsf{fma}\left(x, 0.5, n \cdot \mathsf{fma}\left(x, -0.5, 1\right)\right)}{n \cdot n}, 1\right) - t\_0\\ \end{array} \end{array} \]
                                (FPCore (x n)
                                 :precision binary64
                                 (let* ((t_0 (pow x (/ 1.0 n))) (t_1 (/ t_0 (* x n))))
                                   (if (<= (/ 1.0 n) -4e-80)
                                     t_1
                                     (if (<= (/ 1.0 n) 2e-64)
                                       (/ (log (/ (+ x 1.0) x)) n)
                                       (if (<= (/ 1.0 n) 0.5)
                                         t_1
                                         (-
                                          (fma x (/ (fma x 0.5 (* n (fma x -0.5 1.0))) (* n n)) 1.0)
                                          t_0))))))
                                double code(double x, double n) {
                                	double t_0 = pow(x, (1.0 / n));
                                	double t_1 = t_0 / (x * n);
                                	double tmp;
                                	if ((1.0 / n) <= -4e-80) {
                                		tmp = t_1;
                                	} else if ((1.0 / n) <= 2e-64) {
                                		tmp = log(((x + 1.0) / x)) / n;
                                	} else if ((1.0 / n) <= 0.5) {
                                		tmp = t_1;
                                	} else {
                                		tmp = fma(x, (fma(x, 0.5, (n * fma(x, -0.5, 1.0))) / (n * n)), 1.0) - t_0;
                                	}
                                	return tmp;
                                }
                                
                                function code(x, n)
                                	t_0 = x ^ Float64(1.0 / n)
                                	t_1 = Float64(t_0 / Float64(x * n))
                                	tmp = 0.0
                                	if (Float64(1.0 / n) <= -4e-80)
                                		tmp = t_1;
                                	elseif (Float64(1.0 / n) <= 2e-64)
                                		tmp = Float64(log(Float64(Float64(x + 1.0) / x)) / n);
                                	elseif (Float64(1.0 / n) <= 0.5)
                                		tmp = t_1;
                                	else
                                		tmp = Float64(fma(x, Float64(fma(x, 0.5, Float64(n * fma(x, -0.5, 1.0))) / Float64(n * n)), 1.0) - t_0);
                                	end
                                	return tmp
                                end
                                
                                code[x_, n_] := Block[{t$95$0 = N[Power[x, N[(1.0 / n), $MachinePrecision]], $MachinePrecision]}, Block[{t$95$1 = N[(t$95$0 / N[(x * n), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[N[(1.0 / n), $MachinePrecision], -4e-80], t$95$1, If[LessEqual[N[(1.0 / n), $MachinePrecision], 2e-64], N[(N[Log[N[(N[(x + 1.0), $MachinePrecision] / x), $MachinePrecision]], $MachinePrecision] / n), $MachinePrecision], If[LessEqual[N[(1.0 / n), $MachinePrecision], 0.5], t$95$1, N[(N[(x * N[(N[(x * 0.5 + N[(n * N[(x * -0.5 + 1.0), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] / N[(n * n), $MachinePrecision]), $MachinePrecision] + 1.0), $MachinePrecision] - t$95$0), $MachinePrecision]]]]]]
                                
                                \begin{array}{l}
                                
                                \\
                                \begin{array}{l}
                                t_0 := {x}^{\left(\frac{1}{n}\right)}\\
                                t_1 := \frac{t\_0}{x \cdot n}\\
                                \mathbf{if}\;\frac{1}{n} \leq -4 \cdot 10^{-80}:\\
                                \;\;\;\;t\_1\\
                                
                                \mathbf{elif}\;\frac{1}{n} \leq 2 \cdot 10^{-64}:\\
                                \;\;\;\;\frac{\log \left(\frac{x + 1}{x}\right)}{n}\\
                                
                                \mathbf{elif}\;\frac{1}{n} \leq 0.5:\\
                                \;\;\;\;t\_1\\
                                
                                \mathbf{else}:\\
                                \;\;\;\;\mathsf{fma}\left(x, \frac{\mathsf{fma}\left(x, 0.5, n \cdot \mathsf{fma}\left(x, -0.5, 1\right)\right)}{n \cdot n}, 1\right) - t\_0\\
                                
                                
                                \end{array}
                                \end{array}
                                
                                Derivation
                                1. Split input into 3 regimes
                                2. if (/.f64 #s(literal 1 binary64) n) < -3.99999999999999985e-80 or 1.99999999999999993e-64 < (/.f64 #s(literal 1 binary64) n) < 0.5

                                  1. Initial program 72.1%

                                    \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                                  2. Add Preprocessing
                                  3. Taylor expanded in x around inf

                                    \[\leadsto \color{blue}{\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{n \cdot x}} \]
                                  4. Step-by-step derivation
                                    1. lower-/.f64N/A

                                      \[\leadsto \color{blue}{\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{n \cdot x}} \]
                                    2. log-recN/A

                                      \[\leadsto \frac{e^{-1 \cdot \frac{\color{blue}{\mathsf{neg}\left(\log x\right)}}{n}}}{n \cdot x} \]
                                    3. mul-1-negN/A

                                      \[\leadsto \frac{e^{-1 \cdot \frac{\color{blue}{-1 \cdot \log x}}{n}}}{n \cdot x} \]
                                    4. associate-*r/N/A

                                      \[\leadsto \frac{e^{\color{blue}{\frac{-1 \cdot \left(-1 \cdot \log x\right)}{n}}}}{n \cdot x} \]
                                    5. associate-*r*N/A

                                      \[\leadsto \frac{e^{\frac{\color{blue}{\left(-1 \cdot -1\right) \cdot \log x}}{n}}}{n \cdot x} \]
                                    6. metadata-evalN/A

                                      \[\leadsto \frac{e^{\frac{\color{blue}{1} \cdot \log x}{n}}}{n \cdot x} \]
                                    7. *-commutativeN/A

                                      \[\leadsto \frac{e^{\frac{\color{blue}{\log x \cdot 1}}{n}}}{n \cdot x} \]
                                    8. associate-/l*N/A

                                      \[\leadsto \frac{e^{\color{blue}{\log x \cdot \frac{1}{n}}}}{n \cdot x} \]
                                    9. exp-to-powN/A

                                      \[\leadsto \frac{\color{blue}{{x}^{\left(\frac{1}{n}\right)}}}{n \cdot x} \]
                                    10. lower-pow.f64N/A

                                      \[\leadsto \frac{\color{blue}{{x}^{\left(\frac{1}{n}\right)}}}{n \cdot x} \]
                                    11. lower-/.f64N/A

                                      \[\leadsto \frac{{x}^{\color{blue}{\left(\frac{1}{n}\right)}}}{n \cdot x} \]
                                    12. *-commutativeN/A

                                      \[\leadsto \frac{{x}^{\left(\frac{1}{n}\right)}}{\color{blue}{x \cdot n}} \]
                                    13. lower-*.f6487.5

                                      \[\leadsto \frac{{x}^{\left(\frac{1}{n}\right)}}{\color{blue}{x \cdot n}} \]
                                  5. Applied rewrites87.5%

                                    \[\leadsto \color{blue}{\frac{{x}^{\left(\frac{1}{n}\right)}}{x \cdot n}} \]

                                  if -3.99999999999999985e-80 < (/.f64 #s(literal 1 binary64) n) < 1.99999999999999993e-64

                                  1. Initial program 36.4%

                                    \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                                  2. Add Preprocessing
                                  3. Taylor expanded in n around -inf

                                    \[\leadsto \color{blue}{-1 \cdot \frac{\left(-1 \cdot \log \left(1 + x\right) + -1 \cdot \frac{\left(-1 \cdot \frac{\left(-1 \cdot \frac{\frac{1}{24} \cdot {\log \left(1 + x\right)}^{4} - \frac{1}{24} \cdot {\log x}^{4}}{n} + \frac{-1}{6} \cdot {\log \left(1 + x\right)}^{3}\right) - \frac{-1}{6} \cdot {\log x}^{3}}{n} + \frac{1}{2} \cdot {\log \left(1 + x\right)}^{2}\right) - \frac{1}{2} \cdot {\log x}^{2}}{n}\right) - -1 \cdot \log x}{n}} \]
                                  4. Applied rewrites80.9%

                                    \[\leadsto \color{blue}{\frac{\left(\log x - \mathsf{log1p}\left(x\right)\right) - \frac{0.5 \cdot \left({\left(\mathsf{log1p}\left(x\right)\right)}^{2} - {\log x}^{2}\right) - \frac{\mathsf{fma}\left(-0.041666666666666664, \frac{{\left(\mathsf{log1p}\left(x\right)\right)}^{4} - {\log x}^{4}}{n}, -0.16666666666666666 \cdot \left({\left(\mathsf{log1p}\left(x\right)\right)}^{3} - {\log x}^{3}\right)\right)}{n}}{n}}{-n}} \]
                                  5. Step-by-step derivation
                                    1. Applied rewrites81.2%

                                      \[\leadsto \frac{\left(-\log \left(\frac{x + 1}{x}\right)\right) - \frac{0.5 \cdot \left({\left(\mathsf{log1p}\left(x\right)\right)}^{2} - {\log x}^{2}\right) - \frac{\mathsf{fma}\left(-0.041666666666666664, \frac{{\left(\mathsf{log1p}\left(x\right)\right)}^{4} - {\log x}^{4}}{n}, -0.16666666666666666 \cdot \left({\left(\mathsf{log1p}\left(x\right)\right)}^{3} - {\log x}^{3}\right)\right)}{n}}{n}}{-n} \]
                                    2. Taylor expanded in n around inf

                                      \[\leadsto \frac{\log \left(\frac{1 + x}{x}\right)}{\color{blue}{n}} \]
                                    3. Step-by-step derivation
                                      1. Applied rewrites81.2%

                                        \[\leadsto \frac{\log \left(\frac{x + 1}{x}\right)}{\color{blue}{n}} \]

                                      if 0.5 < (/.f64 #s(literal 1 binary64) n)

                                      1. Initial program 68.7%

                                        \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                                      2. Add Preprocessing
                                      3. Taylor expanded in x around 0

                                        \[\leadsto \color{blue}{\left(1 + x \cdot \left(x \cdot \left(\left(\frac{1}{2} \cdot \frac{1}{{n}^{2}} + x \cdot \left(\left(\frac{1}{6} \cdot \frac{1}{{n}^{3}} + \frac{1}{3} \cdot \frac{1}{n}\right) - \frac{1}{2} \cdot \frac{1}{{n}^{2}}\right)\right) - \frac{1}{2} \cdot \frac{1}{n}\right) + \frac{1}{n}\right)\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                                      4. Step-by-step derivation
                                        1. +-commutativeN/A

                                          \[\leadsto \color{blue}{\left(x \cdot \left(x \cdot \left(\left(\frac{1}{2} \cdot \frac{1}{{n}^{2}} + x \cdot \left(\left(\frac{1}{6} \cdot \frac{1}{{n}^{3}} + \frac{1}{3} \cdot \frac{1}{n}\right) - \frac{1}{2} \cdot \frac{1}{{n}^{2}}\right)\right) - \frac{1}{2} \cdot \frac{1}{n}\right) + \frac{1}{n}\right) + 1\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                                        2. lower-fma.f64N/A

                                          \[\leadsto \color{blue}{\mathsf{fma}\left(x, x \cdot \left(\left(\frac{1}{2} \cdot \frac{1}{{n}^{2}} + x \cdot \left(\left(\frac{1}{6} \cdot \frac{1}{{n}^{3}} + \frac{1}{3} \cdot \frac{1}{n}\right) - \frac{1}{2} \cdot \frac{1}{{n}^{2}}\right)\right) - \frac{1}{2} \cdot \frac{1}{n}\right) + \frac{1}{n}, 1\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                                      5. Applied rewrites40.8%

                                        \[\leadsto \color{blue}{\mathsf{fma}\left(x, \mathsf{fma}\left(x, \mathsf{fma}\left(x, \frac{0.16666666666666666}{n \cdot \left(n \cdot n\right)} + \left(\frac{0.3333333333333333}{n} + \frac{-0.5}{n \cdot n}\right), \frac{0.5}{n \cdot n} + \frac{-0.5}{n}\right), \frac{1}{n}\right), 1\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                                      6. Taylor expanded in n around 0

                                        \[\leadsto \mathsf{fma}\left(x, \frac{1}{6} \cdot \color{blue}{\frac{{x}^{2}}{{n}^{3}}}, 1\right) - {x}^{\left(\frac{1}{n}\right)} \]
                                      7. Step-by-step derivation
                                        1. Applied rewrites56.1%

                                          \[\leadsto \mathsf{fma}\left(x, \frac{0.16666666666666666 \cdot \left(x \cdot x\right)}{\color{blue}{n \cdot \left(n \cdot n\right)}}, 1\right) - {x}^{\left(\frac{1}{n}\right)} \]
                                        2. Taylor expanded in x around 0

                                          \[\leadsto \color{blue}{\left(1 + x \cdot \left(x \cdot \left(\frac{1}{2} \cdot \frac{1}{{n}^{2}} - \frac{1}{2} \cdot \frac{1}{n}\right) + \frac{1}{n}\right)\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                                        3. Step-by-step derivation
                                          1. +-commutativeN/A

                                            \[\leadsto \color{blue}{\left(x \cdot \left(x \cdot \left(\frac{1}{2} \cdot \frac{1}{{n}^{2}} - \frac{1}{2} \cdot \frac{1}{n}\right) + \frac{1}{n}\right) + 1\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                                          2. lower-fma.f64N/A

                                            \[\leadsto \color{blue}{\mathsf{fma}\left(x, x \cdot \left(\frac{1}{2} \cdot \frac{1}{{n}^{2}} - \frac{1}{2} \cdot \frac{1}{n}\right) + \frac{1}{n}, 1\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                                          3. lower-fma.f64N/A

                                            \[\leadsto \mathsf{fma}\left(x, \color{blue}{\mathsf{fma}\left(x, \frac{1}{2} \cdot \frac{1}{{n}^{2}} - \frac{1}{2} \cdot \frac{1}{n}, \frac{1}{n}\right)}, 1\right) - {x}^{\left(\frac{1}{n}\right)} \]
                                          4. lower--.f64N/A

                                            \[\leadsto \mathsf{fma}\left(x, \mathsf{fma}\left(x, \color{blue}{\frac{1}{2} \cdot \frac{1}{{n}^{2}} - \frac{1}{2} \cdot \frac{1}{n}}, \frac{1}{n}\right), 1\right) - {x}^{\left(\frac{1}{n}\right)} \]
                                          5. associate-*r/N/A

                                            \[\leadsto \mathsf{fma}\left(x, \mathsf{fma}\left(x, \color{blue}{\frac{\frac{1}{2} \cdot 1}{{n}^{2}}} - \frac{1}{2} \cdot \frac{1}{n}, \frac{1}{n}\right), 1\right) - {x}^{\left(\frac{1}{n}\right)} \]
                                          6. metadata-evalN/A

                                            \[\leadsto \mathsf{fma}\left(x, \mathsf{fma}\left(x, \frac{\color{blue}{\frac{1}{2}}}{{n}^{2}} - \frac{1}{2} \cdot \frac{1}{n}, \frac{1}{n}\right), 1\right) - {x}^{\left(\frac{1}{n}\right)} \]
                                          7. lower-/.f64N/A

                                            \[\leadsto \mathsf{fma}\left(x, \mathsf{fma}\left(x, \color{blue}{\frac{\frac{1}{2}}{{n}^{2}}} - \frac{1}{2} \cdot \frac{1}{n}, \frac{1}{n}\right), 1\right) - {x}^{\left(\frac{1}{n}\right)} \]
                                          8. unpow2N/A

                                            \[\leadsto \mathsf{fma}\left(x, \mathsf{fma}\left(x, \frac{\frac{1}{2}}{\color{blue}{n \cdot n}} - \frac{1}{2} \cdot \frac{1}{n}, \frac{1}{n}\right), 1\right) - {x}^{\left(\frac{1}{n}\right)} \]
                                          9. lower-*.f64N/A

                                            \[\leadsto \mathsf{fma}\left(x, \mathsf{fma}\left(x, \frac{\frac{1}{2}}{\color{blue}{n \cdot n}} - \frac{1}{2} \cdot \frac{1}{n}, \frac{1}{n}\right), 1\right) - {x}^{\left(\frac{1}{n}\right)} \]
                                          10. associate-*r/N/A

                                            \[\leadsto \mathsf{fma}\left(x, \mathsf{fma}\left(x, \frac{\frac{1}{2}}{n \cdot n} - \color{blue}{\frac{\frac{1}{2} \cdot 1}{n}}, \frac{1}{n}\right), 1\right) - {x}^{\left(\frac{1}{n}\right)} \]
                                          11. metadata-evalN/A

                                            \[\leadsto \mathsf{fma}\left(x, \mathsf{fma}\left(x, \frac{\frac{1}{2}}{n \cdot n} - \frac{\color{blue}{\frac{1}{2}}}{n}, \frac{1}{n}\right), 1\right) - {x}^{\left(\frac{1}{n}\right)} \]
                                          12. lower-/.f64N/A

                                            \[\leadsto \mathsf{fma}\left(x, \mathsf{fma}\left(x, \frac{\frac{1}{2}}{n \cdot n} - \color{blue}{\frac{\frac{1}{2}}{n}}, \frac{1}{n}\right), 1\right) - {x}^{\left(\frac{1}{n}\right)} \]
                                          13. lower-/.f6484.6

                                            \[\leadsto \mathsf{fma}\left(x, \mathsf{fma}\left(x, \frac{0.5}{n \cdot n} - \frac{0.5}{n}, \color{blue}{\frac{1}{n}}\right), 1\right) - {x}^{\left(\frac{1}{n}\right)} \]
                                        4. Applied rewrites84.6%

                                          \[\leadsto \color{blue}{\mathsf{fma}\left(x, \mathsf{fma}\left(x, \frac{0.5}{n \cdot n} - \frac{0.5}{n}, \frac{1}{n}\right), 1\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                                        5. Taylor expanded in n around 0

                                          \[\leadsto \mathsf{fma}\left(x, \frac{\frac{1}{2} \cdot x + n \cdot \left(1 + \frac{-1}{2} \cdot x\right)}{\color{blue}{{n}^{2}}}, 1\right) - {x}^{\left(\frac{1}{n}\right)} \]
                                        6. Step-by-step derivation
                                          1. Applied rewrites81.7%

                                            \[\leadsto \mathsf{fma}\left(x, \frac{\mathsf{fma}\left(x, 0.5, n \cdot \mathsf{fma}\left(x, -0.5, 1\right)\right)}{\color{blue}{n \cdot n}}, 1\right) - {x}^{\left(\frac{1}{n}\right)} \]
                                        7. Recombined 3 regimes into one program.
                                        8. Add Preprocessing

                                        Alternative 9: 81.6% accurate, 1.2× speedup?

                                        \[\begin{array}{l} \\ \begin{array}{l} t_0 := {x}^{\left(\frac{1}{n}\right)}\\ t_1 := \frac{t\_0}{x \cdot n}\\ \mathbf{if}\;\frac{1}{n} \leq -4 \cdot 10^{-80}:\\ \;\;\;\;t\_1\\ \mathbf{elif}\;\frac{1}{n} \leq 2 \cdot 10^{-64}:\\ \;\;\;\;\frac{\log \left(\frac{x + 1}{x}\right)}{n}\\ \mathbf{elif}\;\frac{1}{n} \leq 0.5:\\ \;\;\;\;t\_1\\ \mathbf{elif}\;\frac{1}{n} \leq 5 \cdot 10^{+214}:\\ \;\;\;\;\left(\frac{x}{n} + 1\right) - t\_0\\ \mathbf{else}:\\ \;\;\;\;\mathsf{fma}\left(x, \mathsf{fma}\left(x, \frac{0.5}{n \cdot n} - \frac{0.5}{n}, \frac{1}{n}\right), 1\right) - 1\\ \end{array} \end{array} \]
                                        (FPCore (x n)
                                         :precision binary64
                                         (let* ((t_0 (pow x (/ 1.0 n))) (t_1 (/ t_0 (* x n))))
                                           (if (<= (/ 1.0 n) -4e-80)
                                             t_1
                                             (if (<= (/ 1.0 n) 2e-64)
                                               (/ (log (/ (+ x 1.0) x)) n)
                                               (if (<= (/ 1.0 n) 0.5)
                                                 t_1
                                                 (if (<= (/ 1.0 n) 5e+214)
                                                   (- (+ (/ x n) 1.0) t_0)
                                                   (-
                                                    (fma x (fma x (- (/ 0.5 (* n n)) (/ 0.5 n)) (/ 1.0 n)) 1.0)
                                                    1.0)))))))
                                        double code(double x, double n) {
                                        	double t_0 = pow(x, (1.0 / n));
                                        	double t_1 = t_0 / (x * n);
                                        	double tmp;
                                        	if ((1.0 / n) <= -4e-80) {
                                        		tmp = t_1;
                                        	} else if ((1.0 / n) <= 2e-64) {
                                        		tmp = log(((x + 1.0) / x)) / n;
                                        	} else if ((1.0 / n) <= 0.5) {
                                        		tmp = t_1;
                                        	} else if ((1.0 / n) <= 5e+214) {
                                        		tmp = ((x / n) + 1.0) - t_0;
                                        	} else {
                                        		tmp = fma(x, fma(x, ((0.5 / (n * n)) - (0.5 / n)), (1.0 / n)), 1.0) - 1.0;
                                        	}
                                        	return tmp;
                                        }
                                        
                                        function code(x, n)
                                        	t_0 = x ^ Float64(1.0 / n)
                                        	t_1 = Float64(t_0 / Float64(x * n))
                                        	tmp = 0.0
                                        	if (Float64(1.0 / n) <= -4e-80)
                                        		tmp = t_1;
                                        	elseif (Float64(1.0 / n) <= 2e-64)
                                        		tmp = Float64(log(Float64(Float64(x + 1.0) / x)) / n);
                                        	elseif (Float64(1.0 / n) <= 0.5)
                                        		tmp = t_1;
                                        	elseif (Float64(1.0 / n) <= 5e+214)
                                        		tmp = Float64(Float64(Float64(x / n) + 1.0) - t_0);
                                        	else
                                        		tmp = Float64(fma(x, fma(x, Float64(Float64(0.5 / Float64(n * n)) - Float64(0.5 / n)), Float64(1.0 / n)), 1.0) - 1.0);
                                        	end
                                        	return tmp
                                        end
                                        
                                        code[x_, n_] := Block[{t$95$0 = N[Power[x, N[(1.0 / n), $MachinePrecision]], $MachinePrecision]}, Block[{t$95$1 = N[(t$95$0 / N[(x * n), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[N[(1.0 / n), $MachinePrecision], -4e-80], t$95$1, If[LessEqual[N[(1.0 / n), $MachinePrecision], 2e-64], N[(N[Log[N[(N[(x + 1.0), $MachinePrecision] / x), $MachinePrecision]], $MachinePrecision] / n), $MachinePrecision], If[LessEqual[N[(1.0 / n), $MachinePrecision], 0.5], t$95$1, If[LessEqual[N[(1.0 / n), $MachinePrecision], 5e+214], N[(N[(N[(x / n), $MachinePrecision] + 1.0), $MachinePrecision] - t$95$0), $MachinePrecision], N[(N[(x * N[(x * N[(N[(0.5 / N[(n * n), $MachinePrecision]), $MachinePrecision] - N[(0.5 / n), $MachinePrecision]), $MachinePrecision] + N[(1.0 / n), $MachinePrecision]), $MachinePrecision] + 1.0), $MachinePrecision] - 1.0), $MachinePrecision]]]]]]]
                                        
                                        \begin{array}{l}
                                        
                                        \\
                                        \begin{array}{l}
                                        t_0 := {x}^{\left(\frac{1}{n}\right)}\\
                                        t_1 := \frac{t\_0}{x \cdot n}\\
                                        \mathbf{if}\;\frac{1}{n} \leq -4 \cdot 10^{-80}:\\
                                        \;\;\;\;t\_1\\
                                        
                                        \mathbf{elif}\;\frac{1}{n} \leq 2 \cdot 10^{-64}:\\
                                        \;\;\;\;\frac{\log \left(\frac{x + 1}{x}\right)}{n}\\
                                        
                                        \mathbf{elif}\;\frac{1}{n} \leq 0.5:\\
                                        \;\;\;\;t\_1\\
                                        
                                        \mathbf{elif}\;\frac{1}{n} \leq 5 \cdot 10^{+214}:\\
                                        \;\;\;\;\left(\frac{x}{n} + 1\right) - t\_0\\
                                        
                                        \mathbf{else}:\\
                                        \;\;\;\;\mathsf{fma}\left(x, \mathsf{fma}\left(x, \frac{0.5}{n \cdot n} - \frac{0.5}{n}, \frac{1}{n}\right), 1\right) - 1\\
                                        
                                        
                                        \end{array}
                                        \end{array}
                                        
                                        Derivation
                                        1. Split input into 4 regimes
                                        2. if (/.f64 #s(literal 1 binary64) n) < -3.99999999999999985e-80 or 1.99999999999999993e-64 < (/.f64 #s(literal 1 binary64) n) < 0.5

                                          1. Initial program 72.1%

                                            \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                                          2. Add Preprocessing
                                          3. Taylor expanded in x around inf

                                            \[\leadsto \color{blue}{\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{n \cdot x}} \]
                                          4. Step-by-step derivation
                                            1. lower-/.f64N/A

                                              \[\leadsto \color{blue}{\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{n \cdot x}} \]
                                            2. log-recN/A

                                              \[\leadsto \frac{e^{-1 \cdot \frac{\color{blue}{\mathsf{neg}\left(\log x\right)}}{n}}}{n \cdot x} \]
                                            3. mul-1-negN/A

                                              \[\leadsto \frac{e^{-1 \cdot \frac{\color{blue}{-1 \cdot \log x}}{n}}}{n \cdot x} \]
                                            4. associate-*r/N/A

                                              \[\leadsto \frac{e^{\color{blue}{\frac{-1 \cdot \left(-1 \cdot \log x\right)}{n}}}}{n \cdot x} \]
                                            5. associate-*r*N/A

                                              \[\leadsto \frac{e^{\frac{\color{blue}{\left(-1 \cdot -1\right) \cdot \log x}}{n}}}{n \cdot x} \]
                                            6. metadata-evalN/A

                                              \[\leadsto \frac{e^{\frac{\color{blue}{1} \cdot \log x}{n}}}{n \cdot x} \]
                                            7. *-commutativeN/A

                                              \[\leadsto \frac{e^{\frac{\color{blue}{\log x \cdot 1}}{n}}}{n \cdot x} \]
                                            8. associate-/l*N/A

                                              \[\leadsto \frac{e^{\color{blue}{\log x \cdot \frac{1}{n}}}}{n \cdot x} \]
                                            9. exp-to-powN/A

                                              \[\leadsto \frac{\color{blue}{{x}^{\left(\frac{1}{n}\right)}}}{n \cdot x} \]
                                            10. lower-pow.f64N/A

                                              \[\leadsto \frac{\color{blue}{{x}^{\left(\frac{1}{n}\right)}}}{n \cdot x} \]
                                            11. lower-/.f64N/A

                                              \[\leadsto \frac{{x}^{\color{blue}{\left(\frac{1}{n}\right)}}}{n \cdot x} \]
                                            12. *-commutativeN/A

                                              \[\leadsto \frac{{x}^{\left(\frac{1}{n}\right)}}{\color{blue}{x \cdot n}} \]
                                            13. lower-*.f6487.5

                                              \[\leadsto \frac{{x}^{\left(\frac{1}{n}\right)}}{\color{blue}{x \cdot n}} \]
                                          5. Applied rewrites87.5%

                                            \[\leadsto \color{blue}{\frac{{x}^{\left(\frac{1}{n}\right)}}{x \cdot n}} \]

                                          if -3.99999999999999985e-80 < (/.f64 #s(literal 1 binary64) n) < 1.99999999999999993e-64

                                          1. Initial program 36.4%

                                            \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                                          2. Add Preprocessing
                                          3. Taylor expanded in n around -inf

                                            \[\leadsto \color{blue}{-1 \cdot \frac{\left(-1 \cdot \log \left(1 + x\right) + -1 \cdot \frac{\left(-1 \cdot \frac{\left(-1 \cdot \frac{\frac{1}{24} \cdot {\log \left(1 + x\right)}^{4} - \frac{1}{24} \cdot {\log x}^{4}}{n} + \frac{-1}{6} \cdot {\log \left(1 + x\right)}^{3}\right) - \frac{-1}{6} \cdot {\log x}^{3}}{n} + \frac{1}{2} \cdot {\log \left(1 + x\right)}^{2}\right) - \frac{1}{2} \cdot {\log x}^{2}}{n}\right) - -1 \cdot \log x}{n}} \]
                                          4. Applied rewrites80.9%

                                            \[\leadsto \color{blue}{\frac{\left(\log x - \mathsf{log1p}\left(x\right)\right) - \frac{0.5 \cdot \left({\left(\mathsf{log1p}\left(x\right)\right)}^{2} - {\log x}^{2}\right) - \frac{\mathsf{fma}\left(-0.041666666666666664, \frac{{\left(\mathsf{log1p}\left(x\right)\right)}^{4} - {\log x}^{4}}{n}, -0.16666666666666666 \cdot \left({\left(\mathsf{log1p}\left(x\right)\right)}^{3} - {\log x}^{3}\right)\right)}{n}}{n}}{-n}} \]
                                          5. Step-by-step derivation
                                            1. Applied rewrites81.2%

                                              \[\leadsto \frac{\left(-\log \left(\frac{x + 1}{x}\right)\right) - \frac{0.5 \cdot \left({\left(\mathsf{log1p}\left(x\right)\right)}^{2} - {\log x}^{2}\right) - \frac{\mathsf{fma}\left(-0.041666666666666664, \frac{{\left(\mathsf{log1p}\left(x\right)\right)}^{4} - {\log x}^{4}}{n}, -0.16666666666666666 \cdot \left({\left(\mathsf{log1p}\left(x\right)\right)}^{3} - {\log x}^{3}\right)\right)}{n}}{n}}{-n} \]
                                            2. Taylor expanded in n around inf

                                              \[\leadsto \frac{\log \left(\frac{1 + x}{x}\right)}{\color{blue}{n}} \]
                                            3. Step-by-step derivation
                                              1. Applied rewrites81.2%

                                                \[\leadsto \frac{\log \left(\frac{x + 1}{x}\right)}{\color{blue}{n}} \]

                                              if 0.5 < (/.f64 #s(literal 1 binary64) n) < 4.99999999999999953e214

                                              1. Initial program 84.6%

                                                \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                                              2. Add Preprocessing
                                              3. Taylor expanded in x around 0

                                                \[\leadsto \color{blue}{\left(1 + \frac{x}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                                              4. Step-by-step derivation
                                                1. *-rgt-identityN/A

                                                  \[\leadsto \left(1 + \frac{\color{blue}{x \cdot 1}}{n}\right) - {x}^{\left(\frac{1}{n}\right)} \]
                                                2. associate-*r/N/A

                                                  \[\leadsto \left(1 + \color{blue}{x \cdot \frac{1}{n}}\right) - {x}^{\left(\frac{1}{n}\right)} \]
                                                3. lower-+.f64N/A

                                                  \[\leadsto \color{blue}{\left(1 + x \cdot \frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                                                4. associate-*r/N/A

                                                  \[\leadsto \left(1 + \color{blue}{\frac{x \cdot 1}{n}}\right) - {x}^{\left(\frac{1}{n}\right)} \]
                                                5. *-rgt-identityN/A

                                                  \[\leadsto \left(1 + \frac{\color{blue}{x}}{n}\right) - {x}^{\left(\frac{1}{n}\right)} \]
                                                6. lower-/.f6486.2

                                                  \[\leadsto \left(1 + \color{blue}{\frac{x}{n}}\right) - {x}^{\left(\frac{1}{n}\right)} \]
                                              5. Applied rewrites86.2%

                                                \[\leadsto \color{blue}{\left(1 + \frac{x}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]

                                              if 4.99999999999999953e214 < (/.f64 #s(literal 1 binary64) n)

                                              1. Initial program 24.7%

                                                \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                                              2. Add Preprocessing
                                              3. Taylor expanded in x around 0

                                                \[\leadsto \color{blue}{1} - {x}^{\left(\frac{1}{n}\right)} \]
                                              4. Step-by-step derivation
                                                1. Applied rewrites13.9%

                                                  \[\leadsto \color{blue}{1} - {x}^{\left(\frac{1}{n}\right)} \]
                                                2. Taylor expanded in n around inf

                                                  \[\leadsto 1 - \color{blue}{1} \]
                                                3. Step-by-step derivation
                                                  1. Applied rewrites1.7%

                                                    \[\leadsto 1 - \color{blue}{1} \]
                                                  2. Taylor expanded in x around 0

                                                    \[\leadsto \color{blue}{\left(1 + x \cdot \left(x \cdot \left(\frac{1}{2} \cdot \frac{1}{{n}^{2}} - \frac{1}{2} \cdot \frac{1}{n}\right) + \frac{1}{n}\right)\right)} - 1 \]
                                                  3. Step-by-step derivation
                                                    1. +-commutativeN/A

                                                      \[\leadsto \color{blue}{\left(x \cdot \left(x \cdot \left(\frac{1}{2} \cdot \frac{1}{{n}^{2}} - \frac{1}{2} \cdot \frac{1}{n}\right) + \frac{1}{n}\right) + 1\right)} - 1 \]
                                                    2. lower-fma.f64N/A

                                                      \[\leadsto \color{blue}{\mathsf{fma}\left(x, x \cdot \left(\frac{1}{2} \cdot \frac{1}{{n}^{2}} - \frac{1}{2} \cdot \frac{1}{n}\right) + \frac{1}{n}, 1\right)} - 1 \]
                                                    3. lower-fma.f64N/A

                                                      \[\leadsto \mathsf{fma}\left(x, \color{blue}{\mathsf{fma}\left(x, \frac{1}{2} \cdot \frac{1}{{n}^{2}} - \frac{1}{2} \cdot \frac{1}{n}, \frac{1}{n}\right)}, 1\right) - 1 \]
                                                    4. lower--.f64N/A

                                                      \[\leadsto \mathsf{fma}\left(x, \mathsf{fma}\left(x, \color{blue}{\frac{1}{2} \cdot \frac{1}{{n}^{2}} - \frac{1}{2} \cdot \frac{1}{n}}, \frac{1}{n}\right), 1\right) - 1 \]
                                                    5. associate-*r/N/A

                                                      \[\leadsto \mathsf{fma}\left(x, \mathsf{fma}\left(x, \color{blue}{\frac{\frac{1}{2} \cdot 1}{{n}^{2}}} - \frac{1}{2} \cdot \frac{1}{n}, \frac{1}{n}\right), 1\right) - 1 \]
                                                    6. metadata-evalN/A

                                                      \[\leadsto \mathsf{fma}\left(x, \mathsf{fma}\left(x, \frac{\color{blue}{\frac{1}{2}}}{{n}^{2}} - \frac{1}{2} \cdot \frac{1}{n}, \frac{1}{n}\right), 1\right) - 1 \]
                                                    7. lower-/.f64N/A

                                                      \[\leadsto \mathsf{fma}\left(x, \mathsf{fma}\left(x, \color{blue}{\frac{\frac{1}{2}}{{n}^{2}}} - \frac{1}{2} \cdot \frac{1}{n}, \frac{1}{n}\right), 1\right) - 1 \]
                                                    8. unpow2N/A

                                                      \[\leadsto \mathsf{fma}\left(x, \mathsf{fma}\left(x, \frac{\frac{1}{2}}{\color{blue}{n \cdot n}} - \frac{1}{2} \cdot \frac{1}{n}, \frac{1}{n}\right), 1\right) - 1 \]
                                                    9. lower-*.f64N/A

                                                      \[\leadsto \mathsf{fma}\left(x, \mathsf{fma}\left(x, \frac{\frac{1}{2}}{\color{blue}{n \cdot n}} - \frac{1}{2} \cdot \frac{1}{n}, \frac{1}{n}\right), 1\right) - 1 \]
                                                    10. associate-*r/N/A

                                                      \[\leadsto \mathsf{fma}\left(x, \mathsf{fma}\left(x, \frac{\frac{1}{2}}{n \cdot n} - \color{blue}{\frac{\frac{1}{2} \cdot 1}{n}}, \frac{1}{n}\right), 1\right) - 1 \]
                                                    11. metadata-evalN/A

                                                      \[\leadsto \mathsf{fma}\left(x, \mathsf{fma}\left(x, \frac{\frac{1}{2}}{n \cdot n} - \frac{\color{blue}{\frac{1}{2}}}{n}, \frac{1}{n}\right), 1\right) - 1 \]
                                                    12. lower-/.f64N/A

                                                      \[\leadsto \mathsf{fma}\left(x, \mathsf{fma}\left(x, \frac{\frac{1}{2}}{n \cdot n} - \color{blue}{\frac{\frac{1}{2}}{n}}, \frac{1}{n}\right), 1\right) - 1 \]
                                                    13. lower-/.f6489.2

                                                      \[\leadsto \mathsf{fma}\left(x, \mathsf{fma}\left(x, \frac{0.5}{n \cdot n} - \frac{0.5}{n}, \color{blue}{\frac{1}{n}}\right), 1\right) - 1 \]
                                                  4. Applied rewrites89.2%

                                                    \[\leadsto \color{blue}{\mathsf{fma}\left(x, \mathsf{fma}\left(x, \frac{0.5}{n \cdot n} - \frac{0.5}{n}, \frac{1}{n}\right), 1\right)} - 1 \]
                                                4. Recombined 4 regimes into one program.
                                                5. Final simplification84.7%

                                                  \[\leadsto \begin{array}{l} \mathbf{if}\;\frac{1}{n} \leq -4 \cdot 10^{-80}:\\ \;\;\;\;\frac{{x}^{\left(\frac{1}{n}\right)}}{x \cdot n}\\ \mathbf{elif}\;\frac{1}{n} \leq 2 \cdot 10^{-64}:\\ \;\;\;\;\frac{\log \left(\frac{x + 1}{x}\right)}{n}\\ \mathbf{elif}\;\frac{1}{n} \leq 0.5:\\ \;\;\;\;\frac{{x}^{\left(\frac{1}{n}\right)}}{x \cdot n}\\ \mathbf{elif}\;\frac{1}{n} \leq 5 \cdot 10^{+214}:\\ \;\;\;\;\left(\frac{x}{n} + 1\right) - {x}^{\left(\frac{1}{n}\right)}\\ \mathbf{else}:\\ \;\;\;\;\mathsf{fma}\left(x, \mathsf{fma}\left(x, \frac{0.5}{n \cdot n} - \frac{0.5}{n}, \frac{1}{n}\right), 1\right) - 1\\ \end{array} \]
                                                6. Add Preprocessing

                                                Alternative 10: 81.5% accurate, 1.3× speedup?

                                                \[\begin{array}{l} \\ \begin{array}{l} t_0 := {x}^{\left(\frac{1}{n}\right)}\\ t_1 := \frac{t\_0}{x \cdot n}\\ \mathbf{if}\;\frac{1}{n} \leq -4 \cdot 10^{-80}:\\ \;\;\;\;t\_1\\ \mathbf{elif}\;\frac{1}{n} \leq 2 \cdot 10^{-64}:\\ \;\;\;\;\frac{\log \left(\frac{x + 1}{x}\right)}{n}\\ \mathbf{elif}\;\frac{1}{n} \leq 0.5:\\ \;\;\;\;t\_1\\ \mathbf{elif}\;\frac{1}{n} \leq 5 \cdot 10^{+214}:\\ \;\;\;\;1 - t\_0\\ \mathbf{else}:\\ \;\;\;\;\mathsf{fma}\left(x, \mathsf{fma}\left(x, \frac{0.5}{n \cdot n} - \frac{0.5}{n}, \frac{1}{n}\right), 1\right) - 1\\ \end{array} \end{array} \]
                                                (FPCore (x n)
                                                 :precision binary64
                                                 (let* ((t_0 (pow x (/ 1.0 n))) (t_1 (/ t_0 (* x n))))
                                                   (if (<= (/ 1.0 n) -4e-80)
                                                     t_1
                                                     (if (<= (/ 1.0 n) 2e-64)
                                                       (/ (log (/ (+ x 1.0) x)) n)
                                                       (if (<= (/ 1.0 n) 0.5)
                                                         t_1
                                                         (if (<= (/ 1.0 n) 5e+214)
                                                           (- 1.0 t_0)
                                                           (-
                                                            (fma x (fma x (- (/ 0.5 (* n n)) (/ 0.5 n)) (/ 1.0 n)) 1.0)
                                                            1.0)))))))
                                                double code(double x, double n) {
                                                	double t_0 = pow(x, (1.0 / n));
                                                	double t_1 = t_0 / (x * n);
                                                	double tmp;
                                                	if ((1.0 / n) <= -4e-80) {
                                                		tmp = t_1;
                                                	} else if ((1.0 / n) <= 2e-64) {
                                                		tmp = log(((x + 1.0) / x)) / n;
                                                	} else if ((1.0 / n) <= 0.5) {
                                                		tmp = t_1;
                                                	} else if ((1.0 / n) <= 5e+214) {
                                                		tmp = 1.0 - t_0;
                                                	} else {
                                                		tmp = fma(x, fma(x, ((0.5 / (n * n)) - (0.5 / n)), (1.0 / n)), 1.0) - 1.0;
                                                	}
                                                	return tmp;
                                                }
                                                
                                                function code(x, n)
                                                	t_0 = x ^ Float64(1.0 / n)
                                                	t_1 = Float64(t_0 / Float64(x * n))
                                                	tmp = 0.0
                                                	if (Float64(1.0 / n) <= -4e-80)
                                                		tmp = t_1;
                                                	elseif (Float64(1.0 / n) <= 2e-64)
                                                		tmp = Float64(log(Float64(Float64(x + 1.0) / x)) / n);
                                                	elseif (Float64(1.0 / n) <= 0.5)
                                                		tmp = t_1;
                                                	elseif (Float64(1.0 / n) <= 5e+214)
                                                		tmp = Float64(1.0 - t_0);
                                                	else
                                                		tmp = Float64(fma(x, fma(x, Float64(Float64(0.5 / Float64(n * n)) - Float64(0.5 / n)), Float64(1.0 / n)), 1.0) - 1.0);
                                                	end
                                                	return tmp
                                                end
                                                
                                                code[x_, n_] := Block[{t$95$0 = N[Power[x, N[(1.0 / n), $MachinePrecision]], $MachinePrecision]}, Block[{t$95$1 = N[(t$95$0 / N[(x * n), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[N[(1.0 / n), $MachinePrecision], -4e-80], t$95$1, If[LessEqual[N[(1.0 / n), $MachinePrecision], 2e-64], N[(N[Log[N[(N[(x + 1.0), $MachinePrecision] / x), $MachinePrecision]], $MachinePrecision] / n), $MachinePrecision], If[LessEqual[N[(1.0 / n), $MachinePrecision], 0.5], t$95$1, If[LessEqual[N[(1.0 / n), $MachinePrecision], 5e+214], N[(1.0 - t$95$0), $MachinePrecision], N[(N[(x * N[(x * N[(N[(0.5 / N[(n * n), $MachinePrecision]), $MachinePrecision] - N[(0.5 / n), $MachinePrecision]), $MachinePrecision] + N[(1.0 / n), $MachinePrecision]), $MachinePrecision] + 1.0), $MachinePrecision] - 1.0), $MachinePrecision]]]]]]]
                                                
                                                \begin{array}{l}
                                                
                                                \\
                                                \begin{array}{l}
                                                t_0 := {x}^{\left(\frac{1}{n}\right)}\\
                                                t_1 := \frac{t\_0}{x \cdot n}\\
                                                \mathbf{if}\;\frac{1}{n} \leq -4 \cdot 10^{-80}:\\
                                                \;\;\;\;t\_1\\
                                                
                                                \mathbf{elif}\;\frac{1}{n} \leq 2 \cdot 10^{-64}:\\
                                                \;\;\;\;\frac{\log \left(\frac{x + 1}{x}\right)}{n}\\
                                                
                                                \mathbf{elif}\;\frac{1}{n} \leq 0.5:\\
                                                \;\;\;\;t\_1\\
                                                
                                                \mathbf{elif}\;\frac{1}{n} \leq 5 \cdot 10^{+214}:\\
                                                \;\;\;\;1 - t\_0\\
                                                
                                                \mathbf{else}:\\
                                                \;\;\;\;\mathsf{fma}\left(x, \mathsf{fma}\left(x, \frac{0.5}{n \cdot n} - \frac{0.5}{n}, \frac{1}{n}\right), 1\right) - 1\\
                                                
                                                
                                                \end{array}
                                                \end{array}
                                                
                                                Derivation
                                                1. Split input into 4 regimes
                                                2. if (/.f64 #s(literal 1 binary64) n) < -3.99999999999999985e-80 or 1.99999999999999993e-64 < (/.f64 #s(literal 1 binary64) n) < 0.5

                                                  1. Initial program 72.1%

                                                    \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                                                  2. Add Preprocessing
                                                  3. Taylor expanded in x around inf

                                                    \[\leadsto \color{blue}{\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{n \cdot x}} \]
                                                  4. Step-by-step derivation
                                                    1. lower-/.f64N/A

                                                      \[\leadsto \color{blue}{\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{n \cdot x}} \]
                                                    2. log-recN/A

                                                      \[\leadsto \frac{e^{-1 \cdot \frac{\color{blue}{\mathsf{neg}\left(\log x\right)}}{n}}}{n \cdot x} \]
                                                    3. mul-1-negN/A

                                                      \[\leadsto \frac{e^{-1 \cdot \frac{\color{blue}{-1 \cdot \log x}}{n}}}{n \cdot x} \]
                                                    4. associate-*r/N/A

                                                      \[\leadsto \frac{e^{\color{blue}{\frac{-1 \cdot \left(-1 \cdot \log x\right)}{n}}}}{n \cdot x} \]
                                                    5. associate-*r*N/A

                                                      \[\leadsto \frac{e^{\frac{\color{blue}{\left(-1 \cdot -1\right) \cdot \log x}}{n}}}{n \cdot x} \]
                                                    6. metadata-evalN/A

                                                      \[\leadsto \frac{e^{\frac{\color{blue}{1} \cdot \log x}{n}}}{n \cdot x} \]
                                                    7. *-commutativeN/A

                                                      \[\leadsto \frac{e^{\frac{\color{blue}{\log x \cdot 1}}{n}}}{n \cdot x} \]
                                                    8. associate-/l*N/A

                                                      \[\leadsto \frac{e^{\color{blue}{\log x \cdot \frac{1}{n}}}}{n \cdot x} \]
                                                    9. exp-to-powN/A

                                                      \[\leadsto \frac{\color{blue}{{x}^{\left(\frac{1}{n}\right)}}}{n \cdot x} \]
                                                    10. lower-pow.f64N/A

                                                      \[\leadsto \frac{\color{blue}{{x}^{\left(\frac{1}{n}\right)}}}{n \cdot x} \]
                                                    11. lower-/.f64N/A

                                                      \[\leadsto \frac{{x}^{\color{blue}{\left(\frac{1}{n}\right)}}}{n \cdot x} \]
                                                    12. *-commutativeN/A

                                                      \[\leadsto \frac{{x}^{\left(\frac{1}{n}\right)}}{\color{blue}{x \cdot n}} \]
                                                    13. lower-*.f6487.5

                                                      \[\leadsto \frac{{x}^{\left(\frac{1}{n}\right)}}{\color{blue}{x \cdot n}} \]
                                                  5. Applied rewrites87.5%

                                                    \[\leadsto \color{blue}{\frac{{x}^{\left(\frac{1}{n}\right)}}{x \cdot n}} \]

                                                  if -3.99999999999999985e-80 < (/.f64 #s(literal 1 binary64) n) < 1.99999999999999993e-64

                                                  1. Initial program 36.4%

                                                    \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                                                  2. Add Preprocessing
                                                  3. Taylor expanded in n around -inf

                                                    \[\leadsto \color{blue}{-1 \cdot \frac{\left(-1 \cdot \log \left(1 + x\right) + -1 \cdot \frac{\left(-1 \cdot \frac{\left(-1 \cdot \frac{\frac{1}{24} \cdot {\log \left(1 + x\right)}^{4} - \frac{1}{24} \cdot {\log x}^{4}}{n} + \frac{-1}{6} \cdot {\log \left(1 + x\right)}^{3}\right) - \frac{-1}{6} \cdot {\log x}^{3}}{n} + \frac{1}{2} \cdot {\log \left(1 + x\right)}^{2}\right) - \frac{1}{2} \cdot {\log x}^{2}}{n}\right) - -1 \cdot \log x}{n}} \]
                                                  4. Applied rewrites80.9%

                                                    \[\leadsto \color{blue}{\frac{\left(\log x - \mathsf{log1p}\left(x\right)\right) - \frac{0.5 \cdot \left({\left(\mathsf{log1p}\left(x\right)\right)}^{2} - {\log x}^{2}\right) - \frac{\mathsf{fma}\left(-0.041666666666666664, \frac{{\left(\mathsf{log1p}\left(x\right)\right)}^{4} - {\log x}^{4}}{n}, -0.16666666666666666 \cdot \left({\left(\mathsf{log1p}\left(x\right)\right)}^{3} - {\log x}^{3}\right)\right)}{n}}{n}}{-n}} \]
                                                  5. Step-by-step derivation
                                                    1. Applied rewrites81.2%

                                                      \[\leadsto \frac{\left(-\log \left(\frac{x + 1}{x}\right)\right) - \frac{0.5 \cdot \left({\left(\mathsf{log1p}\left(x\right)\right)}^{2} - {\log x}^{2}\right) - \frac{\mathsf{fma}\left(-0.041666666666666664, \frac{{\left(\mathsf{log1p}\left(x\right)\right)}^{4} - {\log x}^{4}}{n}, -0.16666666666666666 \cdot \left({\left(\mathsf{log1p}\left(x\right)\right)}^{3} - {\log x}^{3}\right)\right)}{n}}{n}}{-n} \]
                                                    2. Taylor expanded in n around inf

                                                      \[\leadsto \frac{\log \left(\frac{1 + x}{x}\right)}{\color{blue}{n}} \]
                                                    3. Step-by-step derivation
                                                      1. Applied rewrites81.2%

                                                        \[\leadsto \frac{\log \left(\frac{x + 1}{x}\right)}{\color{blue}{n}} \]

                                                      if 0.5 < (/.f64 #s(literal 1 binary64) n) < 4.99999999999999953e214

                                                      1. Initial program 84.6%

                                                        \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                                                      2. Add Preprocessing
                                                      3. Taylor expanded in x around 0

                                                        \[\leadsto \color{blue}{1} - {x}^{\left(\frac{1}{n}\right)} \]
                                                      4. Step-by-step derivation
                                                        1. Applied rewrites84.6%

                                                          \[\leadsto \color{blue}{1} - {x}^{\left(\frac{1}{n}\right)} \]

                                                        if 4.99999999999999953e214 < (/.f64 #s(literal 1 binary64) n)

                                                        1. Initial program 24.7%

                                                          \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                                                        2. Add Preprocessing
                                                        3. Taylor expanded in x around 0

                                                          \[\leadsto \color{blue}{1} - {x}^{\left(\frac{1}{n}\right)} \]
                                                        4. Step-by-step derivation
                                                          1. Applied rewrites13.9%

                                                            \[\leadsto \color{blue}{1} - {x}^{\left(\frac{1}{n}\right)} \]
                                                          2. Taylor expanded in n around inf

                                                            \[\leadsto 1 - \color{blue}{1} \]
                                                          3. Step-by-step derivation
                                                            1. Applied rewrites1.7%

                                                              \[\leadsto 1 - \color{blue}{1} \]
                                                            2. Taylor expanded in x around 0

                                                              \[\leadsto \color{blue}{\left(1 + x \cdot \left(x \cdot \left(\frac{1}{2} \cdot \frac{1}{{n}^{2}} - \frac{1}{2} \cdot \frac{1}{n}\right) + \frac{1}{n}\right)\right)} - 1 \]
                                                            3. Step-by-step derivation
                                                              1. +-commutativeN/A

                                                                \[\leadsto \color{blue}{\left(x \cdot \left(x \cdot \left(\frac{1}{2} \cdot \frac{1}{{n}^{2}} - \frac{1}{2} \cdot \frac{1}{n}\right) + \frac{1}{n}\right) + 1\right)} - 1 \]
                                                              2. lower-fma.f64N/A

                                                                \[\leadsto \color{blue}{\mathsf{fma}\left(x, x \cdot \left(\frac{1}{2} \cdot \frac{1}{{n}^{2}} - \frac{1}{2} \cdot \frac{1}{n}\right) + \frac{1}{n}, 1\right)} - 1 \]
                                                              3. lower-fma.f64N/A

                                                                \[\leadsto \mathsf{fma}\left(x, \color{blue}{\mathsf{fma}\left(x, \frac{1}{2} \cdot \frac{1}{{n}^{2}} - \frac{1}{2} \cdot \frac{1}{n}, \frac{1}{n}\right)}, 1\right) - 1 \]
                                                              4. lower--.f64N/A

                                                                \[\leadsto \mathsf{fma}\left(x, \mathsf{fma}\left(x, \color{blue}{\frac{1}{2} \cdot \frac{1}{{n}^{2}} - \frac{1}{2} \cdot \frac{1}{n}}, \frac{1}{n}\right), 1\right) - 1 \]
                                                              5. associate-*r/N/A

                                                                \[\leadsto \mathsf{fma}\left(x, \mathsf{fma}\left(x, \color{blue}{\frac{\frac{1}{2} \cdot 1}{{n}^{2}}} - \frac{1}{2} \cdot \frac{1}{n}, \frac{1}{n}\right), 1\right) - 1 \]
                                                              6. metadata-evalN/A

                                                                \[\leadsto \mathsf{fma}\left(x, \mathsf{fma}\left(x, \frac{\color{blue}{\frac{1}{2}}}{{n}^{2}} - \frac{1}{2} \cdot \frac{1}{n}, \frac{1}{n}\right), 1\right) - 1 \]
                                                              7. lower-/.f64N/A

                                                                \[\leadsto \mathsf{fma}\left(x, \mathsf{fma}\left(x, \color{blue}{\frac{\frac{1}{2}}{{n}^{2}}} - \frac{1}{2} \cdot \frac{1}{n}, \frac{1}{n}\right), 1\right) - 1 \]
                                                              8. unpow2N/A

                                                                \[\leadsto \mathsf{fma}\left(x, \mathsf{fma}\left(x, \frac{\frac{1}{2}}{\color{blue}{n \cdot n}} - \frac{1}{2} \cdot \frac{1}{n}, \frac{1}{n}\right), 1\right) - 1 \]
                                                              9. lower-*.f64N/A

                                                                \[\leadsto \mathsf{fma}\left(x, \mathsf{fma}\left(x, \frac{\frac{1}{2}}{\color{blue}{n \cdot n}} - \frac{1}{2} \cdot \frac{1}{n}, \frac{1}{n}\right), 1\right) - 1 \]
                                                              10. associate-*r/N/A

                                                                \[\leadsto \mathsf{fma}\left(x, \mathsf{fma}\left(x, \frac{\frac{1}{2}}{n \cdot n} - \color{blue}{\frac{\frac{1}{2} \cdot 1}{n}}, \frac{1}{n}\right), 1\right) - 1 \]
                                                              11. metadata-evalN/A

                                                                \[\leadsto \mathsf{fma}\left(x, \mathsf{fma}\left(x, \frac{\frac{1}{2}}{n \cdot n} - \frac{\color{blue}{\frac{1}{2}}}{n}, \frac{1}{n}\right), 1\right) - 1 \]
                                                              12. lower-/.f64N/A

                                                                \[\leadsto \mathsf{fma}\left(x, \mathsf{fma}\left(x, \frac{\frac{1}{2}}{n \cdot n} - \color{blue}{\frac{\frac{1}{2}}{n}}, \frac{1}{n}\right), 1\right) - 1 \]
                                                              13. lower-/.f6489.2

                                                                \[\leadsto \mathsf{fma}\left(x, \mathsf{fma}\left(x, \frac{0.5}{n \cdot n} - \frac{0.5}{n}, \color{blue}{\frac{1}{n}}\right), 1\right) - 1 \]
                                                            4. Applied rewrites89.2%

                                                              \[\leadsto \color{blue}{\mathsf{fma}\left(x, \mathsf{fma}\left(x, \frac{0.5}{n \cdot n} - \frac{0.5}{n}, \frac{1}{n}\right), 1\right)} - 1 \]
                                                          4. Recombined 4 regimes into one program.
                                                          5. Add Preprocessing

                                                          Alternative 11: 59.9% accurate, 1.8× speedup?

                                                          \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;x \leq 8 \cdot 10^{-150}:\\ \;\;\;\;1 - {x}^{\left(\frac{1}{n}\right)}\\ \mathbf{elif}\;x \leq 0.7:\\ \;\;\;\;\frac{\log x}{-n}\\ \mathbf{elif}\;x \leq 5.9 \cdot 10^{+166}:\\ \;\;\;\;\frac{\frac{1 - \frac{0.5}{x}}{n}}{x}\\ \mathbf{else}:\\ \;\;\;\;1 - 1\\ \end{array} \end{array} \]
                                                          (FPCore (x n)
                                                           :precision binary64
                                                           (if (<= x 8e-150)
                                                             (- 1.0 (pow x (/ 1.0 n)))
                                                             (if (<= x 0.7)
                                                               (/ (log x) (- n))
                                                               (if (<= x 5.9e+166) (/ (/ (- 1.0 (/ 0.5 x)) n) x) (- 1.0 1.0)))))
                                                          double code(double x, double n) {
                                                          	double tmp;
                                                          	if (x <= 8e-150) {
                                                          		tmp = 1.0 - pow(x, (1.0 / n));
                                                          	} else if (x <= 0.7) {
                                                          		tmp = log(x) / -n;
                                                          	} else if (x <= 5.9e+166) {
                                                          		tmp = ((1.0 - (0.5 / x)) / n) / x;
                                                          	} else {
                                                          		tmp = 1.0 - 1.0;
                                                          	}
                                                          	return tmp;
                                                          }
                                                          
                                                          real(8) function code(x, n)
                                                              real(8), intent (in) :: x
                                                              real(8), intent (in) :: n
                                                              real(8) :: tmp
                                                              if (x <= 8d-150) then
                                                                  tmp = 1.0d0 - (x ** (1.0d0 / n))
                                                              else if (x <= 0.7d0) then
                                                                  tmp = log(x) / -n
                                                              else if (x <= 5.9d+166) then
                                                                  tmp = ((1.0d0 - (0.5d0 / x)) / n) / x
                                                              else
                                                                  tmp = 1.0d0 - 1.0d0
                                                              end if
                                                              code = tmp
                                                          end function
                                                          
                                                          public static double code(double x, double n) {
                                                          	double tmp;
                                                          	if (x <= 8e-150) {
                                                          		tmp = 1.0 - Math.pow(x, (1.0 / n));
                                                          	} else if (x <= 0.7) {
                                                          		tmp = Math.log(x) / -n;
                                                          	} else if (x <= 5.9e+166) {
                                                          		tmp = ((1.0 - (0.5 / x)) / n) / x;
                                                          	} else {
                                                          		tmp = 1.0 - 1.0;
                                                          	}
                                                          	return tmp;
                                                          }
                                                          
                                                          def code(x, n):
                                                          	tmp = 0
                                                          	if x <= 8e-150:
                                                          		tmp = 1.0 - math.pow(x, (1.0 / n))
                                                          	elif x <= 0.7:
                                                          		tmp = math.log(x) / -n
                                                          	elif x <= 5.9e+166:
                                                          		tmp = ((1.0 - (0.5 / x)) / n) / x
                                                          	else:
                                                          		tmp = 1.0 - 1.0
                                                          	return tmp
                                                          
                                                          function code(x, n)
                                                          	tmp = 0.0
                                                          	if (x <= 8e-150)
                                                          		tmp = Float64(1.0 - (x ^ Float64(1.0 / n)));
                                                          	elseif (x <= 0.7)
                                                          		tmp = Float64(log(x) / Float64(-n));
                                                          	elseif (x <= 5.9e+166)
                                                          		tmp = Float64(Float64(Float64(1.0 - Float64(0.5 / x)) / n) / x);
                                                          	else
                                                          		tmp = Float64(1.0 - 1.0);
                                                          	end
                                                          	return tmp
                                                          end
                                                          
                                                          function tmp_2 = code(x, n)
                                                          	tmp = 0.0;
                                                          	if (x <= 8e-150)
                                                          		tmp = 1.0 - (x ^ (1.0 / n));
                                                          	elseif (x <= 0.7)
                                                          		tmp = log(x) / -n;
                                                          	elseif (x <= 5.9e+166)
                                                          		tmp = ((1.0 - (0.5 / x)) / n) / x;
                                                          	else
                                                          		tmp = 1.0 - 1.0;
                                                          	end
                                                          	tmp_2 = tmp;
                                                          end
                                                          
                                                          code[x_, n_] := If[LessEqual[x, 8e-150], N[(1.0 - N[Power[x, N[(1.0 / n), $MachinePrecision]], $MachinePrecision]), $MachinePrecision], If[LessEqual[x, 0.7], N[(N[Log[x], $MachinePrecision] / (-n)), $MachinePrecision], If[LessEqual[x, 5.9e+166], N[(N[(N[(1.0 - N[(0.5 / x), $MachinePrecision]), $MachinePrecision] / n), $MachinePrecision] / x), $MachinePrecision], N[(1.0 - 1.0), $MachinePrecision]]]]
                                                          
                                                          \begin{array}{l}
                                                          
                                                          \\
                                                          \begin{array}{l}
                                                          \mathbf{if}\;x \leq 8 \cdot 10^{-150}:\\
                                                          \;\;\;\;1 - {x}^{\left(\frac{1}{n}\right)}\\
                                                          
                                                          \mathbf{elif}\;x \leq 0.7:\\
                                                          \;\;\;\;\frac{\log x}{-n}\\
                                                          
                                                          \mathbf{elif}\;x \leq 5.9 \cdot 10^{+166}:\\
                                                          \;\;\;\;\frac{\frac{1 - \frac{0.5}{x}}{n}}{x}\\
                                                          
                                                          \mathbf{else}:\\
                                                          \;\;\;\;1 - 1\\
                                                          
                                                          
                                                          \end{array}
                                                          \end{array}
                                                          
                                                          Derivation
                                                          1. Split input into 4 regimes
                                                          2. if x < 8.00000000000000005e-150

                                                            1. Initial program 58.3%

                                                              \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                                                            2. Add Preprocessing
                                                            3. Taylor expanded in x around 0

                                                              \[\leadsto \color{blue}{1} - {x}^{\left(\frac{1}{n}\right)} \]
                                                            4. Step-by-step derivation
                                                              1. Applied rewrites58.3%

                                                                \[\leadsto \color{blue}{1} - {x}^{\left(\frac{1}{n}\right)} \]

                                                              if 8.00000000000000005e-150 < x < 0.69999999999999996

                                                              1. Initial program 39.2%

                                                                \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                                                              2. Add Preprocessing
                                                              3. Taylor expanded in n around -inf

                                                                \[\leadsto \color{blue}{-1 \cdot \frac{\left(-1 \cdot \log \left(1 + x\right) + -1 \cdot \frac{\left(-1 \cdot \frac{\left(-1 \cdot \frac{\frac{1}{24} \cdot {\log \left(1 + x\right)}^{4} - \frac{1}{24} \cdot {\log x}^{4}}{n} + \frac{-1}{6} \cdot {\log \left(1 + x\right)}^{3}\right) - \frac{-1}{6} \cdot {\log x}^{3}}{n} + \frac{1}{2} \cdot {\log \left(1 + x\right)}^{2}\right) - \frac{1}{2} \cdot {\log x}^{2}}{n}\right) - -1 \cdot \log x}{n}} \]
                                                              4. Applied rewrites77.2%

                                                                \[\leadsto \color{blue}{\frac{\left(\log x - \mathsf{log1p}\left(x\right)\right) - \frac{0.5 \cdot \left({\left(\mathsf{log1p}\left(x\right)\right)}^{2} - {\log x}^{2}\right) - \frac{\mathsf{fma}\left(-0.041666666666666664, \frac{{\left(\mathsf{log1p}\left(x\right)\right)}^{4} - {\log x}^{4}}{n}, -0.16666666666666666 \cdot \left({\left(\mathsf{log1p}\left(x\right)\right)}^{3} - {\log x}^{3}\right)\right)}{n}}{n}}{-n}} \]
                                                              5. Taylor expanded in x around 0

                                                                \[\leadsto \frac{\left(\log x + \left(\frac{1}{24} \cdot \frac{{\log x}^{4}}{{n}^{3}} + \frac{1}{6} \cdot \frac{{\log x}^{3}}{{n}^{2}}\right)\right) - \frac{-1}{2} \cdot \frac{{\log x}^{2}}{n}}{\mathsf{neg}\left(\color{blue}{n}\right)} \]
                                                              6. Step-by-step derivation
                                                                1. Applied rewrites77.2%

                                                                  \[\leadsto \frac{\log x + \mathsf{fma}\left(0.041666666666666664, \frac{{\log x}^{4}}{n \cdot \left(n \cdot n\right)}, \mathsf{fma}\left(0.16666666666666666, \frac{{\log x}^{3}}{n \cdot n}, \frac{0.5 \cdot {\log x}^{2}}{n}\right)\right)}{-\color{blue}{n}} \]
                                                                2. Taylor expanded in n around inf

                                                                  \[\leadsto \frac{\log x}{\mathsf{neg}\left(n\right)} \]
                                                                3. Step-by-step derivation
                                                                  1. Applied rewrites57.7%

                                                                    \[\leadsto \frac{\log x}{-n} \]

                                                                  if 0.69999999999999996 < x < 5.90000000000000012e166

                                                                  1. Initial program 52.6%

                                                                    \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                                                                  2. Add Preprocessing
                                                                  3. Taylor expanded in x around inf

                                                                    \[\leadsto \color{blue}{\frac{\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{n} + \frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}} \cdot \left(\frac{1}{2} \cdot \frac{1}{{n}^{2}} - \frac{1}{2} \cdot \frac{1}{n}\right)}{x}}{x}} \]
                                                                  4. Step-by-step derivation
                                                                    1. lower-/.f64N/A

                                                                      \[\leadsto \color{blue}{\frac{\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{n} + \frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}} \cdot \left(\frac{1}{2} \cdot \frac{1}{{n}^{2}} - \frac{1}{2} \cdot \frac{1}{n}\right)}{x}}{x}} \]
                                                                  5. Applied rewrites85.7%

                                                                    \[\leadsto \color{blue}{\frac{\mathsf{fma}\left({x}^{\left(\frac{1}{n}\right)}, \frac{0.5}{x \cdot \left(n \cdot n\right)} - \frac{0.5}{x \cdot n}, \frac{{x}^{\left(\frac{1}{n}\right)}}{n}\right)}{x}} \]
                                                                  6. Taylor expanded in n around inf

                                                                    \[\leadsto \frac{\frac{1 - \frac{1}{2} \cdot \frac{1}{x}}{n}}{x} \]
                                                                  7. Step-by-step derivation
                                                                    1. Applied rewrites70.0%

                                                                      \[\leadsto \frac{\frac{1 - \frac{0.5}{x}}{n}}{x} \]

                                                                    if 5.90000000000000012e166 < x

                                                                    1. Initial program 79.1%

                                                                      \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                                                                    2. Add Preprocessing
                                                                    3. Taylor expanded in x around 0

                                                                      \[\leadsto \color{blue}{1} - {x}^{\left(\frac{1}{n}\right)} \]
                                                                    4. Step-by-step derivation
                                                                      1. Applied rewrites50.7%

                                                                        \[\leadsto \color{blue}{1} - {x}^{\left(\frac{1}{n}\right)} \]
                                                                      2. Taylor expanded in n around inf

                                                                        \[\leadsto 1 - \color{blue}{1} \]
                                                                      3. Step-by-step derivation
                                                                        1. Applied rewrites79.1%

                                                                          \[\leadsto 1 - \color{blue}{1} \]
                                                                      4. Recombined 4 regimes into one program.
                                                                      5. Add Preprocessing

                                                                      Alternative 12: 60.4% accurate, 1.9× speedup?

                                                                      \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;x \leq 0.7:\\ \;\;\;\;\frac{\log x}{-n}\\ \mathbf{elif}\;x \leq 5.9 \cdot 10^{+166}:\\ \;\;\;\;\frac{\frac{1 - \frac{0.5}{x}}{n}}{x}\\ \mathbf{else}:\\ \;\;\;\;1 - 1\\ \end{array} \end{array} \]
                                                                      (FPCore (x n)
                                                                       :precision binary64
                                                                       (if (<= x 0.7)
                                                                         (/ (log x) (- n))
                                                                         (if (<= x 5.9e+166) (/ (/ (- 1.0 (/ 0.5 x)) n) x) (- 1.0 1.0))))
                                                                      double code(double x, double n) {
                                                                      	double tmp;
                                                                      	if (x <= 0.7) {
                                                                      		tmp = log(x) / -n;
                                                                      	} else if (x <= 5.9e+166) {
                                                                      		tmp = ((1.0 - (0.5 / x)) / n) / x;
                                                                      	} else {
                                                                      		tmp = 1.0 - 1.0;
                                                                      	}
                                                                      	return tmp;
                                                                      }
                                                                      
                                                                      real(8) function code(x, n)
                                                                          real(8), intent (in) :: x
                                                                          real(8), intent (in) :: n
                                                                          real(8) :: tmp
                                                                          if (x <= 0.7d0) then
                                                                              tmp = log(x) / -n
                                                                          else if (x <= 5.9d+166) then
                                                                              tmp = ((1.0d0 - (0.5d0 / x)) / n) / x
                                                                          else
                                                                              tmp = 1.0d0 - 1.0d0
                                                                          end if
                                                                          code = tmp
                                                                      end function
                                                                      
                                                                      public static double code(double x, double n) {
                                                                      	double tmp;
                                                                      	if (x <= 0.7) {
                                                                      		tmp = Math.log(x) / -n;
                                                                      	} else if (x <= 5.9e+166) {
                                                                      		tmp = ((1.0 - (0.5 / x)) / n) / x;
                                                                      	} else {
                                                                      		tmp = 1.0 - 1.0;
                                                                      	}
                                                                      	return tmp;
                                                                      }
                                                                      
                                                                      def code(x, n):
                                                                      	tmp = 0
                                                                      	if x <= 0.7:
                                                                      		tmp = math.log(x) / -n
                                                                      	elif x <= 5.9e+166:
                                                                      		tmp = ((1.0 - (0.5 / x)) / n) / x
                                                                      	else:
                                                                      		tmp = 1.0 - 1.0
                                                                      	return tmp
                                                                      
                                                                      function code(x, n)
                                                                      	tmp = 0.0
                                                                      	if (x <= 0.7)
                                                                      		tmp = Float64(log(x) / Float64(-n));
                                                                      	elseif (x <= 5.9e+166)
                                                                      		tmp = Float64(Float64(Float64(1.0 - Float64(0.5 / x)) / n) / x);
                                                                      	else
                                                                      		tmp = Float64(1.0 - 1.0);
                                                                      	end
                                                                      	return tmp
                                                                      end
                                                                      
                                                                      function tmp_2 = code(x, n)
                                                                      	tmp = 0.0;
                                                                      	if (x <= 0.7)
                                                                      		tmp = log(x) / -n;
                                                                      	elseif (x <= 5.9e+166)
                                                                      		tmp = ((1.0 - (0.5 / x)) / n) / x;
                                                                      	else
                                                                      		tmp = 1.0 - 1.0;
                                                                      	end
                                                                      	tmp_2 = tmp;
                                                                      end
                                                                      
                                                                      code[x_, n_] := If[LessEqual[x, 0.7], N[(N[Log[x], $MachinePrecision] / (-n)), $MachinePrecision], If[LessEqual[x, 5.9e+166], N[(N[(N[(1.0 - N[(0.5 / x), $MachinePrecision]), $MachinePrecision] / n), $MachinePrecision] / x), $MachinePrecision], N[(1.0 - 1.0), $MachinePrecision]]]
                                                                      
                                                                      \begin{array}{l}
                                                                      
                                                                      \\
                                                                      \begin{array}{l}
                                                                      \mathbf{if}\;x \leq 0.7:\\
                                                                      \;\;\;\;\frac{\log x}{-n}\\
                                                                      
                                                                      \mathbf{elif}\;x \leq 5.9 \cdot 10^{+166}:\\
                                                                      \;\;\;\;\frac{\frac{1 - \frac{0.5}{x}}{n}}{x}\\
                                                                      
                                                                      \mathbf{else}:\\
                                                                      \;\;\;\;1 - 1\\
                                                                      
                                                                      
                                                                      \end{array}
                                                                      \end{array}
                                                                      
                                                                      Derivation
                                                                      1. Split input into 3 regimes
                                                                      2. if x < 0.69999999999999996

                                                                        1. Initial program 49.2%

                                                                          \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                                                                        2. Add Preprocessing
                                                                        3. Taylor expanded in n around -inf

                                                                          \[\leadsto \color{blue}{-1 \cdot \frac{\left(-1 \cdot \log \left(1 + x\right) + -1 \cdot \frac{\left(-1 \cdot \frac{\left(-1 \cdot \frac{\frac{1}{24} \cdot {\log \left(1 + x\right)}^{4} - \frac{1}{24} \cdot {\log x}^{4}}{n} + \frac{-1}{6} \cdot {\log \left(1 + x\right)}^{3}\right) - \frac{-1}{6} \cdot {\log x}^{3}}{n} + \frac{1}{2} \cdot {\log \left(1 + x\right)}^{2}\right) - \frac{1}{2} \cdot {\log x}^{2}}{n}\right) - -1 \cdot \log x}{n}} \]
                                                                        4. Applied rewrites71.4%

                                                                          \[\leadsto \color{blue}{\frac{\left(\log x - \mathsf{log1p}\left(x\right)\right) - \frac{0.5 \cdot \left({\left(\mathsf{log1p}\left(x\right)\right)}^{2} - {\log x}^{2}\right) - \frac{\mathsf{fma}\left(-0.041666666666666664, \frac{{\left(\mathsf{log1p}\left(x\right)\right)}^{4} - {\log x}^{4}}{n}, -0.16666666666666666 \cdot \left({\left(\mathsf{log1p}\left(x\right)\right)}^{3} - {\log x}^{3}\right)\right)}{n}}{n}}{-n}} \]
                                                                        5. Taylor expanded in x around 0

                                                                          \[\leadsto \frac{\left(\log x + \left(\frac{1}{24} \cdot \frac{{\log x}^{4}}{{n}^{3}} + \frac{1}{6} \cdot \frac{{\log x}^{3}}{{n}^{2}}\right)\right) - \frac{-1}{2} \cdot \frac{{\log x}^{2}}{n}}{\mathsf{neg}\left(\color{blue}{n}\right)} \]
                                                                        6. Step-by-step derivation
                                                                          1. Applied rewrites71.4%

                                                                            \[\leadsto \frac{\log x + \mathsf{fma}\left(0.041666666666666664, \frac{{\log x}^{4}}{n \cdot \left(n \cdot n\right)}, \mathsf{fma}\left(0.16666666666666666, \frac{{\log x}^{3}}{n \cdot n}, \frac{0.5 \cdot {\log x}^{2}}{n}\right)\right)}{-\color{blue}{n}} \]
                                                                          2. Taylor expanded in n around inf

                                                                            \[\leadsto \frac{\log x}{\mathsf{neg}\left(n\right)} \]
                                                                          3. Step-by-step derivation
                                                                            1. Applied rewrites48.8%

                                                                              \[\leadsto \frac{\log x}{-n} \]

                                                                            if 0.69999999999999996 < x < 5.90000000000000012e166

                                                                            1. Initial program 52.6%

                                                                              \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                                                                            2. Add Preprocessing
                                                                            3. Taylor expanded in x around inf

                                                                              \[\leadsto \color{blue}{\frac{\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{n} + \frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}} \cdot \left(\frac{1}{2} \cdot \frac{1}{{n}^{2}} - \frac{1}{2} \cdot \frac{1}{n}\right)}{x}}{x}} \]
                                                                            4. Step-by-step derivation
                                                                              1. lower-/.f64N/A

                                                                                \[\leadsto \color{blue}{\frac{\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{n} + \frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}} \cdot \left(\frac{1}{2} \cdot \frac{1}{{n}^{2}} - \frac{1}{2} \cdot \frac{1}{n}\right)}{x}}{x}} \]
                                                                            5. Applied rewrites85.7%

                                                                              \[\leadsto \color{blue}{\frac{\mathsf{fma}\left({x}^{\left(\frac{1}{n}\right)}, \frac{0.5}{x \cdot \left(n \cdot n\right)} - \frac{0.5}{x \cdot n}, \frac{{x}^{\left(\frac{1}{n}\right)}}{n}\right)}{x}} \]
                                                                            6. Taylor expanded in n around inf

                                                                              \[\leadsto \frac{\frac{1 - \frac{1}{2} \cdot \frac{1}{x}}{n}}{x} \]
                                                                            7. Step-by-step derivation
                                                                              1. Applied rewrites70.0%

                                                                                \[\leadsto \frac{\frac{1 - \frac{0.5}{x}}{n}}{x} \]

                                                                              if 5.90000000000000012e166 < x

                                                                              1. Initial program 79.1%

                                                                                \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                                                                              2. Add Preprocessing
                                                                              3. Taylor expanded in x around 0

                                                                                \[\leadsto \color{blue}{1} - {x}^{\left(\frac{1}{n}\right)} \]
                                                                              4. Step-by-step derivation
                                                                                1. Applied rewrites50.7%

                                                                                  \[\leadsto \color{blue}{1} - {x}^{\left(\frac{1}{n}\right)} \]
                                                                                2. Taylor expanded in n around inf

                                                                                  \[\leadsto 1 - \color{blue}{1} \]
                                                                                3. Step-by-step derivation
                                                                                  1. Applied rewrites79.1%

                                                                                    \[\leadsto 1 - \color{blue}{1} \]
                                                                                4. Recombined 3 regimes into one program.
                                                                                5. Add Preprocessing

                                                                                Alternative 13: 48.4% accurate, 2.5× speedup?

                                                                                \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;\frac{1}{n} \leq -1 \cdot 10^{-19}:\\ \;\;\;\;1 - 1\\ \mathbf{elif}\;\frac{1}{n} \leq 0.5:\\ \;\;\;\;\frac{\frac{1 - \frac{0.5}{x}}{n}}{x}\\ \mathbf{else}:\\ \;\;\;\;\mathsf{fma}\left(x, \mathsf{fma}\left(x, \frac{0.5}{n \cdot n} - \frac{0.5}{n}, \frac{1}{n}\right), 1\right) - 1\\ \end{array} \end{array} \]
                                                                                (FPCore (x n)
                                                                                 :precision binary64
                                                                                 (if (<= (/ 1.0 n) -1e-19)
                                                                                   (- 1.0 1.0)
                                                                                   (if (<= (/ 1.0 n) 0.5)
                                                                                     (/ (/ (- 1.0 (/ 0.5 x)) n) x)
                                                                                     (- (fma x (fma x (- (/ 0.5 (* n n)) (/ 0.5 n)) (/ 1.0 n)) 1.0) 1.0))))
                                                                                double code(double x, double n) {
                                                                                	double tmp;
                                                                                	if ((1.0 / n) <= -1e-19) {
                                                                                		tmp = 1.0 - 1.0;
                                                                                	} else if ((1.0 / n) <= 0.5) {
                                                                                		tmp = ((1.0 - (0.5 / x)) / n) / x;
                                                                                	} else {
                                                                                		tmp = fma(x, fma(x, ((0.5 / (n * n)) - (0.5 / n)), (1.0 / n)), 1.0) - 1.0;
                                                                                	}
                                                                                	return tmp;
                                                                                }
                                                                                
                                                                                function code(x, n)
                                                                                	tmp = 0.0
                                                                                	if (Float64(1.0 / n) <= -1e-19)
                                                                                		tmp = Float64(1.0 - 1.0);
                                                                                	elseif (Float64(1.0 / n) <= 0.5)
                                                                                		tmp = Float64(Float64(Float64(1.0 - Float64(0.5 / x)) / n) / x);
                                                                                	else
                                                                                		tmp = Float64(fma(x, fma(x, Float64(Float64(0.5 / Float64(n * n)) - Float64(0.5 / n)), Float64(1.0 / n)), 1.0) - 1.0);
                                                                                	end
                                                                                	return tmp
                                                                                end
                                                                                
                                                                                code[x_, n_] := If[LessEqual[N[(1.0 / n), $MachinePrecision], -1e-19], N[(1.0 - 1.0), $MachinePrecision], If[LessEqual[N[(1.0 / n), $MachinePrecision], 0.5], N[(N[(N[(1.0 - N[(0.5 / x), $MachinePrecision]), $MachinePrecision] / n), $MachinePrecision] / x), $MachinePrecision], N[(N[(x * N[(x * N[(N[(0.5 / N[(n * n), $MachinePrecision]), $MachinePrecision] - N[(0.5 / n), $MachinePrecision]), $MachinePrecision] + N[(1.0 / n), $MachinePrecision]), $MachinePrecision] + 1.0), $MachinePrecision] - 1.0), $MachinePrecision]]]
                                                                                
                                                                                \begin{array}{l}
                                                                                
                                                                                \\
                                                                                \begin{array}{l}
                                                                                \mathbf{if}\;\frac{1}{n} \leq -1 \cdot 10^{-19}:\\
                                                                                \;\;\;\;1 - 1\\
                                                                                
                                                                                \mathbf{elif}\;\frac{1}{n} \leq 0.5:\\
                                                                                \;\;\;\;\frac{\frac{1 - \frac{0.5}{x}}{n}}{x}\\
                                                                                
                                                                                \mathbf{else}:\\
                                                                                \;\;\;\;\mathsf{fma}\left(x, \mathsf{fma}\left(x, \frac{0.5}{n \cdot n} - \frac{0.5}{n}, \frac{1}{n}\right), 1\right) - 1\\
                                                                                
                                                                                
                                                                                \end{array}
                                                                                \end{array}
                                                                                
                                                                                Derivation
                                                                                1. Split input into 3 regimes
                                                                                2. if (/.f64 #s(literal 1 binary64) n) < -9.9999999999999998e-20

                                                                                  1. Initial program 97.5%

                                                                                    \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                                                                                  2. Add Preprocessing
                                                                                  3. Taylor expanded in x around 0

                                                                                    \[\leadsto \color{blue}{1} - {x}^{\left(\frac{1}{n}\right)} \]
                                                                                  4. Step-by-step derivation
                                                                                    1. Applied rewrites54.6%

                                                                                      \[\leadsto \color{blue}{1} - {x}^{\left(\frac{1}{n}\right)} \]
                                                                                    2. Taylor expanded in n around inf

                                                                                      \[\leadsto 1 - \color{blue}{1} \]
                                                                                    3. Step-by-step derivation
                                                                                      1. Applied rewrites45.1%

                                                                                        \[\leadsto 1 - \color{blue}{1} \]

                                                                                      if -9.9999999999999998e-20 < (/.f64 #s(literal 1 binary64) n) < 0.5

                                                                                      1. Initial program 30.6%

                                                                                        \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                                                                                      2. Add Preprocessing
                                                                                      3. Taylor expanded in x around inf

                                                                                        \[\leadsto \color{blue}{\frac{\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{n} + \frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}} \cdot \left(\frac{1}{2} \cdot \frac{1}{{n}^{2}} - \frac{1}{2} \cdot \frac{1}{n}\right)}{x}}{x}} \]
                                                                                      4. Step-by-step derivation
                                                                                        1. lower-/.f64N/A

                                                                                          \[\leadsto \color{blue}{\frac{\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{n} + \frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}} \cdot \left(\frac{1}{2} \cdot \frac{1}{{n}^{2}} - \frac{1}{2} \cdot \frac{1}{n}\right)}{x}}{x}} \]
                                                                                      5. Applied rewrites56.7%

                                                                                        \[\leadsto \color{blue}{\frac{\mathsf{fma}\left({x}^{\left(\frac{1}{n}\right)}, \frac{0.5}{x \cdot \left(n \cdot n\right)} - \frac{0.5}{x \cdot n}, \frac{{x}^{\left(\frac{1}{n}\right)}}{n}\right)}{x}} \]
                                                                                      6. Taylor expanded in n around inf

                                                                                        \[\leadsto \frac{\frac{1 - \frac{1}{2} \cdot \frac{1}{x}}{n}}{x} \]
                                                                                      7. Step-by-step derivation
                                                                                        1. Applied rewrites55.8%

                                                                                          \[\leadsto \frac{\frac{1 - \frac{0.5}{x}}{n}}{x} \]

                                                                                        if 0.5 < (/.f64 #s(literal 1 binary64) n)

                                                                                        1. Initial program 68.7%

                                                                                          \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                                                                                        2. Add Preprocessing
                                                                                        3. Taylor expanded in x around 0

                                                                                          \[\leadsto \color{blue}{1} - {x}^{\left(\frac{1}{n}\right)} \]
                                                                                        4. Step-by-step derivation
                                                                                          1. Applied rewrites65.9%

                                                                                            \[\leadsto \color{blue}{1} - {x}^{\left(\frac{1}{n}\right)} \]
                                                                                          2. Taylor expanded in n around inf

                                                                                            \[\leadsto 1 - \color{blue}{1} \]
                                                                                          3. Step-by-step derivation
                                                                                            1. Applied rewrites2.6%

                                                                                              \[\leadsto 1 - \color{blue}{1} \]
                                                                                            2. Taylor expanded in x around 0

                                                                                              \[\leadsto \color{blue}{\left(1 + x \cdot \left(x \cdot \left(\frac{1}{2} \cdot \frac{1}{{n}^{2}} - \frac{1}{2} \cdot \frac{1}{n}\right) + \frac{1}{n}\right)\right)} - 1 \]
                                                                                            3. Step-by-step derivation
                                                                                              1. +-commutativeN/A

                                                                                                \[\leadsto \color{blue}{\left(x \cdot \left(x \cdot \left(\frac{1}{2} \cdot \frac{1}{{n}^{2}} - \frac{1}{2} \cdot \frac{1}{n}\right) + \frac{1}{n}\right) + 1\right)} - 1 \]
                                                                                              2. lower-fma.f64N/A

                                                                                                \[\leadsto \color{blue}{\mathsf{fma}\left(x, x \cdot \left(\frac{1}{2} \cdot \frac{1}{{n}^{2}} - \frac{1}{2} \cdot \frac{1}{n}\right) + \frac{1}{n}, 1\right)} - 1 \]
                                                                                              3. lower-fma.f64N/A

                                                                                                \[\leadsto \mathsf{fma}\left(x, \color{blue}{\mathsf{fma}\left(x, \frac{1}{2} \cdot \frac{1}{{n}^{2}} - \frac{1}{2} \cdot \frac{1}{n}, \frac{1}{n}\right)}, 1\right) - 1 \]
                                                                                              4. lower--.f64N/A

                                                                                                \[\leadsto \mathsf{fma}\left(x, \mathsf{fma}\left(x, \color{blue}{\frac{1}{2} \cdot \frac{1}{{n}^{2}} - \frac{1}{2} \cdot \frac{1}{n}}, \frac{1}{n}\right), 1\right) - 1 \]
                                                                                              5. associate-*r/N/A

                                                                                                \[\leadsto \mathsf{fma}\left(x, \mathsf{fma}\left(x, \color{blue}{\frac{\frac{1}{2} \cdot 1}{{n}^{2}}} - \frac{1}{2} \cdot \frac{1}{n}, \frac{1}{n}\right), 1\right) - 1 \]
                                                                                              6. metadata-evalN/A

                                                                                                \[\leadsto \mathsf{fma}\left(x, \mathsf{fma}\left(x, \frac{\color{blue}{\frac{1}{2}}}{{n}^{2}} - \frac{1}{2} \cdot \frac{1}{n}, \frac{1}{n}\right), 1\right) - 1 \]
                                                                                              7. lower-/.f64N/A

                                                                                                \[\leadsto \mathsf{fma}\left(x, \mathsf{fma}\left(x, \color{blue}{\frac{\frac{1}{2}}{{n}^{2}}} - \frac{1}{2} \cdot \frac{1}{n}, \frac{1}{n}\right), 1\right) - 1 \]
                                                                                              8. unpow2N/A

                                                                                                \[\leadsto \mathsf{fma}\left(x, \mathsf{fma}\left(x, \frac{\frac{1}{2}}{\color{blue}{n \cdot n}} - \frac{1}{2} \cdot \frac{1}{n}, \frac{1}{n}\right), 1\right) - 1 \]
                                                                                              9. lower-*.f64N/A

                                                                                                \[\leadsto \mathsf{fma}\left(x, \mathsf{fma}\left(x, \frac{\frac{1}{2}}{\color{blue}{n \cdot n}} - \frac{1}{2} \cdot \frac{1}{n}, \frac{1}{n}\right), 1\right) - 1 \]
                                                                                              10. associate-*r/N/A

                                                                                                \[\leadsto \mathsf{fma}\left(x, \mathsf{fma}\left(x, \frac{\frac{1}{2}}{n \cdot n} - \color{blue}{\frac{\frac{1}{2} \cdot 1}{n}}, \frac{1}{n}\right), 1\right) - 1 \]
                                                                                              11. metadata-evalN/A

                                                                                                \[\leadsto \mathsf{fma}\left(x, \mathsf{fma}\left(x, \frac{\frac{1}{2}}{n \cdot n} - \frac{\color{blue}{\frac{1}{2}}}{n}, \frac{1}{n}\right), 1\right) - 1 \]
                                                                                              12. lower-/.f64N/A

                                                                                                \[\leadsto \mathsf{fma}\left(x, \mathsf{fma}\left(x, \frac{\frac{1}{2}}{n \cdot n} - \color{blue}{\frac{\frac{1}{2}}{n}}, \frac{1}{n}\right), 1\right) - 1 \]
                                                                                              13. lower-/.f6435.0

                                                                                                \[\leadsto \mathsf{fma}\left(x, \mathsf{fma}\left(x, \frac{0.5}{n \cdot n} - \frac{0.5}{n}, \color{blue}{\frac{1}{n}}\right), 1\right) - 1 \]
                                                                                            4. Applied rewrites35.0%

                                                                                              \[\leadsto \color{blue}{\mathsf{fma}\left(x, \mathsf{fma}\left(x, \frac{0.5}{n \cdot n} - \frac{0.5}{n}, \frac{1}{n}\right), 1\right)} - 1 \]
                                                                                          4. Recombined 3 regimes into one program.
                                                                                          5. Add Preprocessing

                                                                                          Alternative 14: 47.9% accurate, 3.1× speedup?

                                                                                          \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;\frac{1}{n} \leq -1 \cdot 10^{-19}:\\ \;\;\;\;1 - 1\\ \mathbf{elif}\;\frac{1}{n} \leq 0.5:\\ \;\;\;\;\frac{\frac{1 - \frac{0.5}{x}}{n}}{x}\\ \mathbf{else}:\\ \;\;\;\;\mathsf{fma}\left(x, \frac{0.16666666666666666 \cdot \left(x \cdot x\right)}{n \cdot \left(n \cdot n\right)}, 1\right) - 1\\ \end{array} \end{array} \]
                                                                                          (FPCore (x n)
                                                                                           :precision binary64
                                                                                           (if (<= (/ 1.0 n) -1e-19)
                                                                                             (- 1.0 1.0)
                                                                                             (if (<= (/ 1.0 n) 0.5)
                                                                                               (/ (/ (- 1.0 (/ 0.5 x)) n) x)
                                                                                               (- (fma x (/ (* 0.16666666666666666 (* x x)) (* n (* n n))) 1.0) 1.0))))
                                                                                          double code(double x, double n) {
                                                                                          	double tmp;
                                                                                          	if ((1.0 / n) <= -1e-19) {
                                                                                          		tmp = 1.0 - 1.0;
                                                                                          	} else if ((1.0 / n) <= 0.5) {
                                                                                          		tmp = ((1.0 - (0.5 / x)) / n) / x;
                                                                                          	} else {
                                                                                          		tmp = fma(x, ((0.16666666666666666 * (x * x)) / (n * (n * n))), 1.0) - 1.0;
                                                                                          	}
                                                                                          	return tmp;
                                                                                          }
                                                                                          
                                                                                          function code(x, n)
                                                                                          	tmp = 0.0
                                                                                          	if (Float64(1.0 / n) <= -1e-19)
                                                                                          		tmp = Float64(1.0 - 1.0);
                                                                                          	elseif (Float64(1.0 / n) <= 0.5)
                                                                                          		tmp = Float64(Float64(Float64(1.0 - Float64(0.5 / x)) / n) / x);
                                                                                          	else
                                                                                          		tmp = Float64(fma(x, Float64(Float64(0.16666666666666666 * Float64(x * x)) / Float64(n * Float64(n * n))), 1.0) - 1.0);
                                                                                          	end
                                                                                          	return tmp
                                                                                          end
                                                                                          
                                                                                          code[x_, n_] := If[LessEqual[N[(1.0 / n), $MachinePrecision], -1e-19], N[(1.0 - 1.0), $MachinePrecision], If[LessEqual[N[(1.0 / n), $MachinePrecision], 0.5], N[(N[(N[(1.0 - N[(0.5 / x), $MachinePrecision]), $MachinePrecision] / n), $MachinePrecision] / x), $MachinePrecision], N[(N[(x * N[(N[(0.16666666666666666 * N[(x * x), $MachinePrecision]), $MachinePrecision] / N[(n * N[(n * n), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] + 1.0), $MachinePrecision] - 1.0), $MachinePrecision]]]
                                                                                          
                                                                                          \begin{array}{l}
                                                                                          
                                                                                          \\
                                                                                          \begin{array}{l}
                                                                                          \mathbf{if}\;\frac{1}{n} \leq -1 \cdot 10^{-19}:\\
                                                                                          \;\;\;\;1 - 1\\
                                                                                          
                                                                                          \mathbf{elif}\;\frac{1}{n} \leq 0.5:\\
                                                                                          \;\;\;\;\frac{\frac{1 - \frac{0.5}{x}}{n}}{x}\\
                                                                                          
                                                                                          \mathbf{else}:\\
                                                                                          \;\;\;\;\mathsf{fma}\left(x, \frac{0.16666666666666666 \cdot \left(x \cdot x\right)}{n \cdot \left(n \cdot n\right)}, 1\right) - 1\\
                                                                                          
                                                                                          
                                                                                          \end{array}
                                                                                          \end{array}
                                                                                          
                                                                                          Derivation
                                                                                          1. Split input into 3 regimes
                                                                                          2. if (/.f64 #s(literal 1 binary64) n) < -9.9999999999999998e-20

                                                                                            1. Initial program 97.5%

                                                                                              \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                                                                                            2. Add Preprocessing
                                                                                            3. Taylor expanded in x around 0

                                                                                              \[\leadsto \color{blue}{1} - {x}^{\left(\frac{1}{n}\right)} \]
                                                                                            4. Step-by-step derivation
                                                                                              1. Applied rewrites54.6%

                                                                                                \[\leadsto \color{blue}{1} - {x}^{\left(\frac{1}{n}\right)} \]
                                                                                              2. Taylor expanded in n around inf

                                                                                                \[\leadsto 1 - \color{blue}{1} \]
                                                                                              3. Step-by-step derivation
                                                                                                1. Applied rewrites45.1%

                                                                                                  \[\leadsto 1 - \color{blue}{1} \]

                                                                                                if -9.9999999999999998e-20 < (/.f64 #s(literal 1 binary64) n) < 0.5

                                                                                                1. Initial program 30.6%

                                                                                                  \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                                                                                                2. Add Preprocessing
                                                                                                3. Taylor expanded in x around inf

                                                                                                  \[\leadsto \color{blue}{\frac{\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{n} + \frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}} \cdot \left(\frac{1}{2} \cdot \frac{1}{{n}^{2}} - \frac{1}{2} \cdot \frac{1}{n}\right)}{x}}{x}} \]
                                                                                                4. Step-by-step derivation
                                                                                                  1. lower-/.f64N/A

                                                                                                    \[\leadsto \color{blue}{\frac{\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{n} + \frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}} \cdot \left(\frac{1}{2} \cdot \frac{1}{{n}^{2}} - \frac{1}{2} \cdot \frac{1}{n}\right)}{x}}{x}} \]
                                                                                                5. Applied rewrites56.7%

                                                                                                  \[\leadsto \color{blue}{\frac{\mathsf{fma}\left({x}^{\left(\frac{1}{n}\right)}, \frac{0.5}{x \cdot \left(n \cdot n\right)} - \frac{0.5}{x \cdot n}, \frac{{x}^{\left(\frac{1}{n}\right)}}{n}\right)}{x}} \]
                                                                                                6. Taylor expanded in n around inf

                                                                                                  \[\leadsto \frac{\frac{1 - \frac{1}{2} \cdot \frac{1}{x}}{n}}{x} \]
                                                                                                7. Step-by-step derivation
                                                                                                  1. Applied rewrites55.8%

                                                                                                    \[\leadsto \frac{\frac{1 - \frac{0.5}{x}}{n}}{x} \]

                                                                                                  if 0.5 < (/.f64 #s(literal 1 binary64) n)

                                                                                                  1. Initial program 68.7%

                                                                                                    \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                                                                                                  2. Add Preprocessing
                                                                                                  3. Taylor expanded in x around 0

                                                                                                    \[\leadsto \color{blue}{\left(1 + x \cdot \left(x \cdot \left(\left(\frac{1}{2} \cdot \frac{1}{{n}^{2}} + x \cdot \left(\left(\frac{1}{6} \cdot \frac{1}{{n}^{3}} + \frac{1}{3} \cdot \frac{1}{n}\right) - \frac{1}{2} \cdot \frac{1}{{n}^{2}}\right)\right) - \frac{1}{2} \cdot \frac{1}{n}\right) + \frac{1}{n}\right)\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                                                                                                  4. Step-by-step derivation
                                                                                                    1. +-commutativeN/A

                                                                                                      \[\leadsto \color{blue}{\left(x \cdot \left(x \cdot \left(\left(\frac{1}{2} \cdot \frac{1}{{n}^{2}} + x \cdot \left(\left(\frac{1}{6} \cdot \frac{1}{{n}^{3}} + \frac{1}{3} \cdot \frac{1}{n}\right) - \frac{1}{2} \cdot \frac{1}{{n}^{2}}\right)\right) - \frac{1}{2} \cdot \frac{1}{n}\right) + \frac{1}{n}\right) + 1\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                                                                                                    2. lower-fma.f64N/A

                                                                                                      \[\leadsto \color{blue}{\mathsf{fma}\left(x, x \cdot \left(\left(\frac{1}{2} \cdot \frac{1}{{n}^{2}} + x \cdot \left(\left(\frac{1}{6} \cdot \frac{1}{{n}^{3}} + \frac{1}{3} \cdot \frac{1}{n}\right) - \frac{1}{2} \cdot \frac{1}{{n}^{2}}\right)\right) - \frac{1}{2} \cdot \frac{1}{n}\right) + \frac{1}{n}, 1\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                                                                                                  5. Applied rewrites40.8%

                                                                                                    \[\leadsto \color{blue}{\mathsf{fma}\left(x, \mathsf{fma}\left(x, \mathsf{fma}\left(x, \frac{0.16666666666666666}{n \cdot \left(n \cdot n\right)} + \left(\frac{0.3333333333333333}{n} + \frac{-0.5}{n \cdot n}\right), \frac{0.5}{n \cdot n} + \frac{-0.5}{n}\right), \frac{1}{n}\right), 1\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                                                                                                  6. Taylor expanded in n around 0

                                                                                                    \[\leadsto \mathsf{fma}\left(x, \frac{1}{6} \cdot \color{blue}{\frac{{x}^{2}}{{n}^{3}}}, 1\right) - {x}^{\left(\frac{1}{n}\right)} \]
                                                                                                  7. Step-by-step derivation
                                                                                                    1. Applied rewrites56.1%

                                                                                                      \[\leadsto \mathsf{fma}\left(x, \frac{0.16666666666666666 \cdot \left(x \cdot x\right)}{\color{blue}{n \cdot \left(n \cdot n\right)}}, 1\right) - {x}^{\left(\frac{1}{n}\right)} \]
                                                                                                    2. Taylor expanded in n around inf

                                                                                                      \[\leadsto \mathsf{fma}\left(x, \frac{\frac{1}{6} \cdot \left(x \cdot x\right)}{n \cdot \left(n \cdot n\right)}, 1\right) - \color{blue}{1} \]
                                                                                                    3. Step-by-step derivation
                                                                                                      1. Applied rewrites19.3%

                                                                                                        \[\leadsto \mathsf{fma}\left(x, \frac{0.16666666666666666 \cdot \left(x \cdot x\right)}{n \cdot \left(n \cdot n\right)}, 1\right) - \color{blue}{1} \]
                                                                                                    4. Recombined 3 regimes into one program.
                                                                                                    5. Add Preprocessing

                                                                                                    Alternative 15: 42.8% accurate, 4.3× speedup?

                                                                                                    \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;\frac{1}{n} \leq -1 \cdot 10^{-19}:\\ \;\;\;\;1 - 1\\ \mathbf{else}:\\ \;\;\;\;\frac{\frac{1 - \frac{0.5}{x}}{n}}{x}\\ \end{array} \end{array} \]
                                                                                                    (FPCore (x n)
                                                                                                     :precision binary64
                                                                                                     (if (<= (/ 1.0 n) -1e-19) (- 1.0 1.0) (/ (/ (- 1.0 (/ 0.5 x)) n) x)))
                                                                                                    double code(double x, double n) {
                                                                                                    	double tmp;
                                                                                                    	if ((1.0 / n) <= -1e-19) {
                                                                                                    		tmp = 1.0 - 1.0;
                                                                                                    	} else {
                                                                                                    		tmp = ((1.0 - (0.5 / x)) / n) / x;
                                                                                                    	}
                                                                                                    	return tmp;
                                                                                                    }
                                                                                                    
                                                                                                    real(8) function code(x, n)
                                                                                                        real(8), intent (in) :: x
                                                                                                        real(8), intent (in) :: n
                                                                                                        real(8) :: tmp
                                                                                                        if ((1.0d0 / n) <= (-1d-19)) then
                                                                                                            tmp = 1.0d0 - 1.0d0
                                                                                                        else
                                                                                                            tmp = ((1.0d0 - (0.5d0 / x)) / n) / x
                                                                                                        end if
                                                                                                        code = tmp
                                                                                                    end function
                                                                                                    
                                                                                                    public static double code(double x, double n) {
                                                                                                    	double tmp;
                                                                                                    	if ((1.0 / n) <= -1e-19) {
                                                                                                    		tmp = 1.0 - 1.0;
                                                                                                    	} else {
                                                                                                    		tmp = ((1.0 - (0.5 / x)) / n) / x;
                                                                                                    	}
                                                                                                    	return tmp;
                                                                                                    }
                                                                                                    
                                                                                                    def code(x, n):
                                                                                                    	tmp = 0
                                                                                                    	if (1.0 / n) <= -1e-19:
                                                                                                    		tmp = 1.0 - 1.0
                                                                                                    	else:
                                                                                                    		tmp = ((1.0 - (0.5 / x)) / n) / x
                                                                                                    	return tmp
                                                                                                    
                                                                                                    function code(x, n)
                                                                                                    	tmp = 0.0
                                                                                                    	if (Float64(1.0 / n) <= -1e-19)
                                                                                                    		tmp = Float64(1.0 - 1.0);
                                                                                                    	else
                                                                                                    		tmp = Float64(Float64(Float64(1.0 - Float64(0.5 / x)) / n) / x);
                                                                                                    	end
                                                                                                    	return tmp
                                                                                                    end
                                                                                                    
                                                                                                    function tmp_2 = code(x, n)
                                                                                                    	tmp = 0.0;
                                                                                                    	if ((1.0 / n) <= -1e-19)
                                                                                                    		tmp = 1.0 - 1.0;
                                                                                                    	else
                                                                                                    		tmp = ((1.0 - (0.5 / x)) / n) / x;
                                                                                                    	end
                                                                                                    	tmp_2 = tmp;
                                                                                                    end
                                                                                                    
                                                                                                    code[x_, n_] := If[LessEqual[N[(1.0 / n), $MachinePrecision], -1e-19], N[(1.0 - 1.0), $MachinePrecision], N[(N[(N[(1.0 - N[(0.5 / x), $MachinePrecision]), $MachinePrecision] / n), $MachinePrecision] / x), $MachinePrecision]]
                                                                                                    
                                                                                                    \begin{array}{l}
                                                                                                    
                                                                                                    \\
                                                                                                    \begin{array}{l}
                                                                                                    \mathbf{if}\;\frac{1}{n} \leq -1 \cdot 10^{-19}:\\
                                                                                                    \;\;\;\;1 - 1\\
                                                                                                    
                                                                                                    \mathbf{else}:\\
                                                                                                    \;\;\;\;\frac{\frac{1 - \frac{0.5}{x}}{n}}{x}\\
                                                                                                    
                                                                                                    
                                                                                                    \end{array}
                                                                                                    \end{array}
                                                                                                    
                                                                                                    Derivation
                                                                                                    1. Split input into 2 regimes
                                                                                                    2. if (/.f64 #s(literal 1 binary64) n) < -9.9999999999999998e-20

                                                                                                      1. Initial program 97.5%

                                                                                                        \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                                                                                                      2. Add Preprocessing
                                                                                                      3. Taylor expanded in x around 0

                                                                                                        \[\leadsto \color{blue}{1} - {x}^{\left(\frac{1}{n}\right)} \]
                                                                                                      4. Step-by-step derivation
                                                                                                        1. Applied rewrites54.6%

                                                                                                          \[\leadsto \color{blue}{1} - {x}^{\left(\frac{1}{n}\right)} \]
                                                                                                        2. Taylor expanded in n around inf

                                                                                                          \[\leadsto 1 - \color{blue}{1} \]
                                                                                                        3. Step-by-step derivation
                                                                                                          1. Applied rewrites45.1%

                                                                                                            \[\leadsto 1 - \color{blue}{1} \]

                                                                                                          if -9.9999999999999998e-20 < (/.f64 #s(literal 1 binary64) n)

                                                                                                          1. Initial program 37.8%

                                                                                                            \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                                                                                                          2. Add Preprocessing
                                                                                                          3. Taylor expanded in x around inf

                                                                                                            \[\leadsto \color{blue}{\frac{\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{n} + \frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}} \cdot \left(\frac{1}{2} \cdot \frac{1}{{n}^{2}} - \frac{1}{2} \cdot \frac{1}{n}\right)}{x}}{x}} \]
                                                                                                          4. Step-by-step derivation
                                                                                                            1. lower-/.f64N/A

                                                                                                              \[\leadsto \color{blue}{\frac{\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{n} + \frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}} \cdot \left(\frac{1}{2} \cdot \frac{1}{{n}^{2}} - \frac{1}{2} \cdot \frac{1}{n}\right)}{x}}{x}} \]
                                                                                                          5. Applied rewrites46.0%

                                                                                                            \[\leadsto \color{blue}{\frac{\mathsf{fma}\left({x}^{\left(\frac{1}{n}\right)}, \frac{0.5}{x \cdot \left(n \cdot n\right)} - \frac{0.5}{x \cdot n}, \frac{{x}^{\left(\frac{1}{n}\right)}}{n}\right)}{x}} \]
                                                                                                          6. Taylor expanded in n around inf

                                                                                                            \[\leadsto \frac{\frac{1 - \frac{1}{2} \cdot \frac{1}{x}}{n}}{x} \]
                                                                                                          7. Step-by-step derivation
                                                                                                            1. Applied rewrites45.3%

                                                                                                              \[\leadsto \frac{\frac{1 - \frac{0.5}{x}}{n}}{x} \]
                                                                                                          8. Recombined 2 regimes into one program.
                                                                                                          9. Add Preprocessing

                                                                                                          Alternative 16: 42.2% accurate, 4.8× speedup?

                                                                                                          \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;\frac{1}{n} \leq -1 \cdot 10^{-19}:\\ \;\;\;\;1 - 1\\ \mathbf{else}:\\ \;\;\;\;\frac{1 - \frac{0.5}{x}}{x \cdot n}\\ \end{array} \end{array} \]
                                                                                                          (FPCore (x n)
                                                                                                           :precision binary64
                                                                                                           (if (<= (/ 1.0 n) -1e-19) (- 1.0 1.0) (/ (- 1.0 (/ 0.5 x)) (* x n))))
                                                                                                          double code(double x, double n) {
                                                                                                          	double tmp;
                                                                                                          	if ((1.0 / n) <= -1e-19) {
                                                                                                          		tmp = 1.0 - 1.0;
                                                                                                          	} else {
                                                                                                          		tmp = (1.0 - (0.5 / x)) / (x * n);
                                                                                                          	}
                                                                                                          	return tmp;
                                                                                                          }
                                                                                                          
                                                                                                          real(8) function code(x, n)
                                                                                                              real(8), intent (in) :: x
                                                                                                              real(8), intent (in) :: n
                                                                                                              real(8) :: tmp
                                                                                                              if ((1.0d0 / n) <= (-1d-19)) then
                                                                                                                  tmp = 1.0d0 - 1.0d0
                                                                                                              else
                                                                                                                  tmp = (1.0d0 - (0.5d0 / x)) / (x * n)
                                                                                                              end if
                                                                                                              code = tmp
                                                                                                          end function
                                                                                                          
                                                                                                          public static double code(double x, double n) {
                                                                                                          	double tmp;
                                                                                                          	if ((1.0 / n) <= -1e-19) {
                                                                                                          		tmp = 1.0 - 1.0;
                                                                                                          	} else {
                                                                                                          		tmp = (1.0 - (0.5 / x)) / (x * n);
                                                                                                          	}
                                                                                                          	return tmp;
                                                                                                          }
                                                                                                          
                                                                                                          def code(x, n):
                                                                                                          	tmp = 0
                                                                                                          	if (1.0 / n) <= -1e-19:
                                                                                                          		tmp = 1.0 - 1.0
                                                                                                          	else:
                                                                                                          		tmp = (1.0 - (0.5 / x)) / (x * n)
                                                                                                          	return tmp
                                                                                                          
                                                                                                          function code(x, n)
                                                                                                          	tmp = 0.0
                                                                                                          	if (Float64(1.0 / n) <= -1e-19)
                                                                                                          		tmp = Float64(1.0 - 1.0);
                                                                                                          	else
                                                                                                          		tmp = Float64(Float64(1.0 - Float64(0.5 / x)) / Float64(x * n));
                                                                                                          	end
                                                                                                          	return tmp
                                                                                                          end
                                                                                                          
                                                                                                          function tmp_2 = code(x, n)
                                                                                                          	tmp = 0.0;
                                                                                                          	if ((1.0 / n) <= -1e-19)
                                                                                                          		tmp = 1.0 - 1.0;
                                                                                                          	else
                                                                                                          		tmp = (1.0 - (0.5 / x)) / (x * n);
                                                                                                          	end
                                                                                                          	tmp_2 = tmp;
                                                                                                          end
                                                                                                          
                                                                                                          code[x_, n_] := If[LessEqual[N[(1.0 / n), $MachinePrecision], -1e-19], N[(1.0 - 1.0), $MachinePrecision], N[(N[(1.0 - N[(0.5 / x), $MachinePrecision]), $MachinePrecision] / N[(x * n), $MachinePrecision]), $MachinePrecision]]
                                                                                                          
                                                                                                          \begin{array}{l}
                                                                                                          
                                                                                                          \\
                                                                                                          \begin{array}{l}
                                                                                                          \mathbf{if}\;\frac{1}{n} \leq -1 \cdot 10^{-19}:\\
                                                                                                          \;\;\;\;1 - 1\\
                                                                                                          
                                                                                                          \mathbf{else}:\\
                                                                                                          \;\;\;\;\frac{1 - \frac{0.5}{x}}{x \cdot n}\\
                                                                                                          
                                                                                                          
                                                                                                          \end{array}
                                                                                                          \end{array}
                                                                                                          
                                                                                                          Derivation
                                                                                                          1. Split input into 2 regimes
                                                                                                          2. if (/.f64 #s(literal 1 binary64) n) < -9.9999999999999998e-20

                                                                                                            1. Initial program 97.5%

                                                                                                              \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                                                                                                            2. Add Preprocessing
                                                                                                            3. Taylor expanded in x around 0

                                                                                                              \[\leadsto \color{blue}{1} - {x}^{\left(\frac{1}{n}\right)} \]
                                                                                                            4. Step-by-step derivation
                                                                                                              1. Applied rewrites54.6%

                                                                                                                \[\leadsto \color{blue}{1} - {x}^{\left(\frac{1}{n}\right)} \]
                                                                                                              2. Taylor expanded in n around inf

                                                                                                                \[\leadsto 1 - \color{blue}{1} \]
                                                                                                              3. Step-by-step derivation
                                                                                                                1. Applied rewrites45.1%

                                                                                                                  \[\leadsto 1 - \color{blue}{1} \]

                                                                                                                if -9.9999999999999998e-20 < (/.f64 #s(literal 1 binary64) n)

                                                                                                                1. Initial program 37.8%

                                                                                                                  \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                                                                                                                2. Add Preprocessing
                                                                                                                3. Taylor expanded in x around inf

                                                                                                                  \[\leadsto \color{blue}{\frac{\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{n} + \frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}} \cdot \left(\frac{1}{2} \cdot \frac{1}{{n}^{2}} - \frac{1}{2} \cdot \frac{1}{n}\right)}{x}}{x}} \]
                                                                                                                4. Step-by-step derivation
                                                                                                                  1. lower-/.f64N/A

                                                                                                                    \[\leadsto \color{blue}{\frac{\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{n} + \frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}} \cdot \left(\frac{1}{2} \cdot \frac{1}{{n}^{2}} - \frac{1}{2} \cdot \frac{1}{n}\right)}{x}}{x}} \]
                                                                                                                5. Applied rewrites46.0%

                                                                                                                  \[\leadsto \color{blue}{\frac{\mathsf{fma}\left({x}^{\left(\frac{1}{n}\right)}, \frac{0.5}{x \cdot \left(n \cdot n\right)} - \frac{0.5}{x \cdot n}, \frac{{x}^{\left(\frac{1}{n}\right)}}{n}\right)}{x}} \]
                                                                                                                6. Taylor expanded in n around inf

                                                                                                                  \[\leadsto \frac{1 - \frac{1}{2} \cdot \frac{1}{x}}{\color{blue}{n \cdot x}} \]
                                                                                                                7. Step-by-step derivation
                                                                                                                  1. Applied rewrites44.7%

                                                                                                                    \[\leadsto \frac{1 - \frac{0.5}{x}}{\color{blue}{x \cdot n}} \]
                                                                                                                8. Recombined 2 regimes into one program.
                                                                                                                9. Add Preprocessing

                                                                                                                Alternative 17: 32.0% accurate, 57.8× speedup?

                                                                                                                \[\begin{array}{l} \\ 1 - 1 \end{array} \]
                                                                                                                (FPCore (x n) :precision binary64 (- 1.0 1.0))
                                                                                                                double code(double x, double n) {
                                                                                                                	return 1.0 - 1.0;
                                                                                                                }
                                                                                                                
                                                                                                                real(8) function code(x, n)
                                                                                                                    real(8), intent (in) :: x
                                                                                                                    real(8), intent (in) :: n
                                                                                                                    code = 1.0d0 - 1.0d0
                                                                                                                end function
                                                                                                                
                                                                                                                public static double code(double x, double n) {
                                                                                                                	return 1.0 - 1.0;
                                                                                                                }
                                                                                                                
                                                                                                                def code(x, n):
                                                                                                                	return 1.0 - 1.0
                                                                                                                
                                                                                                                function code(x, n)
                                                                                                                	return Float64(1.0 - 1.0)
                                                                                                                end
                                                                                                                
                                                                                                                function tmp = code(x, n)
                                                                                                                	tmp = 1.0 - 1.0;
                                                                                                                end
                                                                                                                
                                                                                                                code[x_, n_] := N[(1.0 - 1.0), $MachinePrecision]
                                                                                                                
                                                                                                                \begin{array}{l}
                                                                                                                
                                                                                                                \\
                                                                                                                1 - 1
                                                                                                                \end{array}
                                                                                                                
                                                                                                                Derivation
                                                                                                                1. Initial program 55.8%

                                                                                                                  \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                                                                                                                2. Add Preprocessing
                                                                                                                3. Taylor expanded in x around 0

                                                                                                                  \[\leadsto \color{blue}{1} - {x}^{\left(\frac{1}{n}\right)} \]
                                                                                                                4. Step-by-step derivation
                                                                                                                  1. Applied rewrites42.5%

                                                                                                                    \[\leadsto \color{blue}{1} - {x}^{\left(\frac{1}{n}\right)} \]
                                                                                                                  2. Taylor expanded in n around inf

                                                                                                                    \[\leadsto 1 - \color{blue}{1} \]
                                                                                                                  3. Step-by-step derivation
                                                                                                                    1. Applied rewrites30.9%

                                                                                                                      \[\leadsto 1 - \color{blue}{1} \]
                                                                                                                    2. Add Preprocessing

                                                                                                                    Reproduce

                                                                                                                    ?
                                                                                                                    herbie shell --seed 2024233 
                                                                                                                    (FPCore (x n)
                                                                                                                      :name "2nthrt (problem 3.4.6)"
                                                                                                                      :precision binary64
                                                                                                                      (- (pow (+ x 1.0) (/ 1.0 n)) (pow x (/ 1.0 n))))