Diagrams.TwoD.Apollonian:descartes from diagrams-contrib-1.3.0.5

Percentage Accurate: 70.1% → 94.0%
Time: 11.3s
Alternatives: 7
Speedup: 1.2×

Specification

?
\[\begin{array}{l} \\ 2 \cdot \sqrt{\left(x \cdot y + x \cdot z\right) + y \cdot z} \end{array} \]
(FPCore (x y z)
 :precision binary64
 (* 2.0 (sqrt (+ (+ (* x y) (* x z)) (* y z)))))
double code(double x, double y, double z) {
	return 2.0 * sqrt((((x * y) + (x * z)) + (y * z)));
}
real(8) function code(x, y, z)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    real(8), intent (in) :: z
    code = 2.0d0 * sqrt((((x * y) + (x * z)) + (y * z)))
end function
public static double code(double x, double y, double z) {
	return 2.0 * Math.sqrt((((x * y) + (x * z)) + (y * z)));
}
def code(x, y, z):
	return 2.0 * math.sqrt((((x * y) + (x * z)) + (y * z)))
function code(x, y, z)
	return Float64(2.0 * sqrt(Float64(Float64(Float64(x * y) + Float64(x * z)) + Float64(y * z))))
end
function tmp = code(x, y, z)
	tmp = 2.0 * sqrt((((x * y) + (x * z)) + (y * z)));
end
code[x_, y_, z_] := N[(2.0 * N[Sqrt[N[(N[(N[(x * y), $MachinePrecision] + N[(x * z), $MachinePrecision]), $MachinePrecision] + N[(y * z), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
2 \cdot \sqrt{\left(x \cdot y + x \cdot z\right) + y \cdot z}
\end{array}

Sampling outcomes in binary64 precision:

Local Percentage Accuracy vs ?

The average percentage accuracy by input value. Horizontal axis shows value of an input variable; the variable is choosen in the title. Vertical axis is accuracy; higher is better. Red represent the original program, while blue represents Herbie's suggestion. These can be toggled with buttons below the plot. The line is an average while dots represent individual samples.

Accuracy vs Speed?

Herbie found 7 alternatives:

AlternativeAccuracySpeedup
The accuracy (vertical axis) and speed (horizontal axis) of each alternatives. Up and to the right is better. The red square shows the initial program, and each blue circle shows an alternative.The line shows the best available speed-accuracy tradeoffs.

Initial Program: 70.1% accurate, 1.0× speedup?

\[\begin{array}{l} \\ 2 \cdot \sqrt{\left(x \cdot y + x \cdot z\right) + y \cdot z} \end{array} \]
(FPCore (x y z)
 :precision binary64
 (* 2.0 (sqrt (+ (+ (* x y) (* x z)) (* y z)))))
double code(double x, double y, double z) {
	return 2.0 * sqrt((((x * y) + (x * z)) + (y * z)));
}
real(8) function code(x, y, z)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    real(8), intent (in) :: z
    code = 2.0d0 * sqrt((((x * y) + (x * z)) + (y * z)))
end function
public static double code(double x, double y, double z) {
	return 2.0 * Math.sqrt((((x * y) + (x * z)) + (y * z)));
}
def code(x, y, z):
	return 2.0 * math.sqrt((((x * y) + (x * z)) + (y * z)))
function code(x, y, z)
	return Float64(2.0 * sqrt(Float64(Float64(Float64(x * y) + Float64(x * z)) + Float64(y * z))))
end
function tmp = code(x, y, z)
	tmp = 2.0 * sqrt((((x * y) + (x * z)) + (y * z)));
end
code[x_, y_, z_] := N[(2.0 * N[Sqrt[N[(N[(N[(x * y), $MachinePrecision] + N[(x * z), $MachinePrecision]), $MachinePrecision] + N[(y * z), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
2 \cdot \sqrt{\left(x \cdot y + x \cdot z\right) + y \cdot z}
\end{array}

Alternative 1: 94.0% accurate, 0.1× speedup?

\[\begin{array}{l} [x, y, z] = \mathsf{sort}([x, y, z])\\ \\ \begin{array}{l} \mathbf{if}\;y \leq -7.3 \cdot 10^{+49}:\\ \;\;\;\;2 \cdot {\left(e^{0.25 \cdot \left(\log \left(\left(-z\right) - y\right) - \log \left(\frac{-1}{x}\right)\right)}\right)}^{2}\\ \mathbf{elif}\;y \leq 5 \cdot 10^{+62}:\\ \;\;\;\;2 \cdot \sqrt{\left(y \cdot x + x \cdot z\right) + y \cdot z}\\ \mathbf{else}:\\ \;\;\;\;\mathsf{fma}\left(2 \cdot \sqrt{y}, \sqrt{z}, x \cdot \sqrt{\frac{z}{y}}\right)\\ \end{array} \end{array} \]
NOTE: x, y, and z should be sorted in increasing order before calling this function.
(FPCore (x y z)
 :precision binary64
 (if (<= y -7.3e+49)
   (* 2.0 (pow (exp (* 0.25 (- (log (- (- z) y)) (log (/ -1.0 x))))) 2.0))
   (if (<= y 5e+62)
     (* 2.0 (sqrt (+ (+ (* y x) (* x z)) (* y z))))
     (fma (* 2.0 (sqrt y)) (sqrt z) (* x (sqrt (/ z y)))))))
assert(x < y && y < z);
double code(double x, double y, double z) {
	double tmp;
	if (y <= -7.3e+49) {
		tmp = 2.0 * pow(exp((0.25 * (log((-z - y)) - log((-1.0 / x))))), 2.0);
	} else if (y <= 5e+62) {
		tmp = 2.0 * sqrt((((y * x) + (x * z)) + (y * z)));
	} else {
		tmp = fma((2.0 * sqrt(y)), sqrt(z), (x * sqrt((z / y))));
	}
	return tmp;
}
x, y, z = sort([x, y, z])
function code(x, y, z)
	tmp = 0.0
	if (y <= -7.3e+49)
		tmp = Float64(2.0 * (exp(Float64(0.25 * Float64(log(Float64(Float64(-z) - y)) - log(Float64(-1.0 / x))))) ^ 2.0));
	elseif (y <= 5e+62)
		tmp = Float64(2.0 * sqrt(Float64(Float64(Float64(y * x) + Float64(x * z)) + Float64(y * z))));
	else
		tmp = fma(Float64(2.0 * sqrt(y)), sqrt(z), Float64(x * sqrt(Float64(z / y))));
	end
	return tmp
end
NOTE: x, y, and z should be sorted in increasing order before calling this function.
code[x_, y_, z_] := If[LessEqual[y, -7.3e+49], N[(2.0 * N[Power[N[Exp[N[(0.25 * N[(N[Log[N[((-z) - y), $MachinePrecision]], $MachinePrecision] - N[Log[N[(-1.0 / x), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision], 2.0], $MachinePrecision]), $MachinePrecision], If[LessEqual[y, 5e+62], N[(2.0 * N[Sqrt[N[(N[(N[(y * x), $MachinePrecision] + N[(x * z), $MachinePrecision]), $MachinePrecision] + N[(y * z), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision], N[(N[(2.0 * N[Sqrt[y], $MachinePrecision]), $MachinePrecision] * N[Sqrt[z], $MachinePrecision] + N[(x * N[Sqrt[N[(z / y), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]]]
\begin{array}{l}
[x, y, z] = \mathsf{sort}([x, y, z])\\
\\
\begin{array}{l}
\mathbf{if}\;y \leq -7.3 \cdot 10^{+49}:\\
\;\;\;\;2 \cdot {\left(e^{0.25 \cdot \left(\log \left(\left(-z\right) - y\right) - \log \left(\frac{-1}{x}\right)\right)}\right)}^{2}\\

\mathbf{elif}\;y \leq 5 \cdot 10^{+62}:\\
\;\;\;\;2 \cdot \sqrt{\left(y \cdot x + x \cdot z\right) + y \cdot z}\\

\mathbf{else}:\\
\;\;\;\;\mathsf{fma}\left(2 \cdot \sqrt{y}, \sqrt{z}, x \cdot \sqrt{\frac{z}{y}}\right)\\


\end{array}
\end{array}
Derivation
  1. Split input into 3 regimes
  2. if y < -7.30000000000000014e49

    1. Initial program 58.9%

      \[2 \cdot \sqrt{\left(x \cdot y + x \cdot z\right) + y \cdot z} \]
    2. Add Preprocessing
    3. Step-by-step derivation
      1. lift-sqrt.f64N/A

        \[\leadsto 2 \cdot \color{blue}{\sqrt{\left(x \cdot y + x \cdot z\right) + y \cdot z}} \]
      2. pow1/2N/A

        \[\leadsto 2 \cdot \color{blue}{{\left(\left(x \cdot y + x \cdot z\right) + y \cdot z\right)}^{\frac{1}{2}}} \]
      3. sqr-powN/A

        \[\leadsto 2 \cdot \color{blue}{\left({\left(\left(x \cdot y + x \cdot z\right) + y \cdot z\right)}^{\left(\frac{\frac{1}{2}}{2}\right)} \cdot {\left(\left(x \cdot y + x \cdot z\right) + y \cdot z\right)}^{\left(\frac{\frac{1}{2}}{2}\right)}\right)} \]
      4. pow2N/A

        \[\leadsto 2 \cdot \color{blue}{{\left({\left(\left(x \cdot y + x \cdot z\right) + y \cdot z\right)}^{\left(\frac{\frac{1}{2}}{2}\right)}\right)}^{2}} \]
      5. lower-pow.f64N/A

        \[\leadsto 2 \cdot \color{blue}{{\left({\left(\left(x \cdot y + x \cdot z\right) + y \cdot z\right)}^{\left(\frac{\frac{1}{2}}{2}\right)}\right)}^{2}} \]
      6. lower-pow.f64N/A

        \[\leadsto 2 \cdot {\color{blue}{\left({\left(\left(x \cdot y + x \cdot z\right) + y \cdot z\right)}^{\left(\frac{\frac{1}{2}}{2}\right)}\right)}}^{2} \]
      7. lift-+.f64N/A

        \[\leadsto 2 \cdot {\left({\color{blue}{\left(\left(x \cdot y + x \cdot z\right) + y \cdot z\right)}}^{\left(\frac{\frac{1}{2}}{2}\right)}\right)}^{2} \]
      8. lift-+.f64N/A

        \[\leadsto 2 \cdot {\left({\left(\color{blue}{\left(x \cdot y + x \cdot z\right)} + y \cdot z\right)}^{\left(\frac{\frac{1}{2}}{2}\right)}\right)}^{2} \]
      9. lift-*.f64N/A

        \[\leadsto 2 \cdot {\left({\left(\left(\color{blue}{x \cdot y} + x \cdot z\right) + y \cdot z\right)}^{\left(\frac{\frac{1}{2}}{2}\right)}\right)}^{2} \]
      10. lift-*.f64N/A

        \[\leadsto 2 \cdot {\left({\left(\left(x \cdot y + \color{blue}{x \cdot z}\right) + y \cdot z\right)}^{\left(\frac{\frac{1}{2}}{2}\right)}\right)}^{2} \]
      11. distribute-lft-outN/A

        \[\leadsto 2 \cdot {\left({\left(\color{blue}{x \cdot \left(y + z\right)} + y \cdot z\right)}^{\left(\frac{\frac{1}{2}}{2}\right)}\right)}^{2} \]
      12. lower-fma.f64N/A

        \[\leadsto 2 \cdot {\left({\color{blue}{\left(\mathsf{fma}\left(x, y + z, y \cdot z\right)\right)}}^{\left(\frac{\frac{1}{2}}{2}\right)}\right)}^{2} \]
      13. lower-+.f64N/A

        \[\leadsto 2 \cdot {\left({\left(\mathsf{fma}\left(x, \color{blue}{y + z}, y \cdot z\right)\right)}^{\left(\frac{\frac{1}{2}}{2}\right)}\right)}^{2} \]
      14. metadata-eval59.0

        \[\leadsto 2 \cdot {\left({\left(\mathsf{fma}\left(x, y + z, y \cdot z\right)\right)}^{\color{blue}{0.25}}\right)}^{2} \]
    4. Applied rewrites59.0%

      \[\leadsto 2 \cdot \color{blue}{{\left({\left(\mathsf{fma}\left(x, y + z, y \cdot z\right)\right)}^{0.25}\right)}^{2}} \]
    5. Taylor expanded in x around -inf

      \[\leadsto 2 \cdot {\color{blue}{\left(e^{\frac{1}{4} \cdot \left(\log \left(-1 \cdot \left(y + z\right)\right) + -1 \cdot \log \left(\frac{-1}{x}\right)\right)}\right)}}^{2} \]
    6. Step-by-step derivation
      1. lower-exp.f64N/A

        \[\leadsto 2 \cdot {\color{blue}{\left(e^{\frac{1}{4} \cdot \left(\log \left(-1 \cdot \left(y + z\right)\right) + -1 \cdot \log \left(\frac{-1}{x}\right)\right)}\right)}}^{2} \]
      2. lower-*.f64N/A

        \[\leadsto 2 \cdot {\left(e^{\color{blue}{\frac{1}{4} \cdot \left(\log \left(-1 \cdot \left(y + z\right)\right) + -1 \cdot \log \left(\frac{-1}{x}\right)\right)}}\right)}^{2} \]
      3. mul-1-negN/A

        \[\leadsto 2 \cdot {\left(e^{\frac{1}{4} \cdot \left(\log \left(-1 \cdot \left(y + z\right)\right) + \color{blue}{\left(\mathsf{neg}\left(\log \left(\frac{-1}{x}\right)\right)\right)}\right)}\right)}^{2} \]
      4. unsub-negN/A

        \[\leadsto 2 \cdot {\left(e^{\frac{1}{4} \cdot \color{blue}{\left(\log \left(-1 \cdot \left(y + z\right)\right) - \log \left(\frac{-1}{x}\right)\right)}}\right)}^{2} \]
      5. lower--.f64N/A

        \[\leadsto 2 \cdot {\left(e^{\frac{1}{4} \cdot \color{blue}{\left(\log \left(-1 \cdot \left(y + z\right)\right) - \log \left(\frac{-1}{x}\right)\right)}}\right)}^{2} \]
      6. distribute-lft-inN/A

        \[\leadsto 2 \cdot {\left(e^{\frac{1}{4} \cdot \left(\log \color{blue}{\left(-1 \cdot y + -1 \cdot z\right)} - \log \left(\frac{-1}{x}\right)\right)}\right)}^{2} \]
      7. lower-log.f64N/A

        \[\leadsto 2 \cdot {\left(e^{\frac{1}{4} \cdot \left(\color{blue}{\log \left(-1 \cdot y + -1 \cdot z\right)} - \log \left(\frac{-1}{x}\right)\right)}\right)}^{2} \]
      8. +-commutativeN/A

        \[\leadsto 2 \cdot {\left(e^{\frac{1}{4} \cdot \left(\log \color{blue}{\left(-1 \cdot z + -1 \cdot y\right)} - \log \left(\frac{-1}{x}\right)\right)}\right)}^{2} \]
      9. mul-1-negN/A

        \[\leadsto 2 \cdot {\left(e^{\frac{1}{4} \cdot \left(\log \left(-1 \cdot z + \color{blue}{\left(\mathsf{neg}\left(y\right)\right)}\right) - \log \left(\frac{-1}{x}\right)\right)}\right)}^{2} \]
      10. unsub-negN/A

        \[\leadsto 2 \cdot {\left(e^{\frac{1}{4} \cdot \left(\log \color{blue}{\left(-1 \cdot z - y\right)} - \log \left(\frac{-1}{x}\right)\right)}\right)}^{2} \]
      11. lower--.f64N/A

        \[\leadsto 2 \cdot {\left(e^{\frac{1}{4} \cdot \left(\log \color{blue}{\left(-1 \cdot z - y\right)} - \log \left(\frac{-1}{x}\right)\right)}\right)}^{2} \]
      12. mul-1-negN/A

        \[\leadsto 2 \cdot {\left(e^{\frac{1}{4} \cdot \left(\log \left(\color{blue}{\left(\mathsf{neg}\left(z\right)\right)} - y\right) - \log \left(\frac{-1}{x}\right)\right)}\right)}^{2} \]
      13. lower-neg.f64N/A

        \[\leadsto 2 \cdot {\left(e^{\frac{1}{4} \cdot \left(\log \left(\color{blue}{\left(\mathsf{neg}\left(z\right)\right)} - y\right) - \log \left(\frac{-1}{x}\right)\right)}\right)}^{2} \]
      14. lower-log.f64N/A

        \[\leadsto 2 \cdot {\left(e^{\frac{1}{4} \cdot \left(\log \left(\left(\mathsf{neg}\left(z\right)\right) - y\right) - \color{blue}{\log \left(\frac{-1}{x}\right)}\right)}\right)}^{2} \]
      15. lower-/.f6444.4

        \[\leadsto 2 \cdot {\left(e^{0.25 \cdot \left(\log \left(\left(-z\right) - y\right) - \log \color{blue}{\left(\frac{-1}{x}\right)}\right)}\right)}^{2} \]
    7. Applied rewrites44.4%

      \[\leadsto 2 \cdot {\color{blue}{\left(e^{0.25 \cdot \left(\log \left(\left(-z\right) - y\right) - \log \left(\frac{-1}{x}\right)\right)}\right)}}^{2} \]

    if -7.30000000000000014e49 < y < 5.00000000000000029e62

    1. Initial program 83.8%

      \[2 \cdot \sqrt{\left(x \cdot y + x \cdot z\right) + y \cdot z} \]
    2. Add Preprocessing

    if 5.00000000000000029e62 < y

    1. Initial program 62.1%

      \[2 \cdot \sqrt{\left(x \cdot y + x \cdot z\right) + y \cdot z} \]
    2. Add Preprocessing
    3. Taylor expanded in x around 0

      \[\leadsto \color{blue}{2 \cdot \sqrt{y \cdot z} + \left(x \cdot \left(y + z\right)\right) \cdot \sqrt{\frac{1}{y \cdot z}}} \]
    4. Step-by-step derivation
      1. +-commutativeN/A

        \[\leadsto \color{blue}{\left(x \cdot \left(y + z\right)\right) \cdot \sqrt{\frac{1}{y \cdot z}} + 2 \cdot \sqrt{y \cdot z}} \]
      2. associate-*l*N/A

        \[\leadsto \color{blue}{x \cdot \left(\left(y + z\right) \cdot \sqrt{\frac{1}{y \cdot z}}\right)} + 2 \cdot \sqrt{y \cdot z} \]
      3. *-commutativeN/A

        \[\leadsto x \cdot \color{blue}{\left(\sqrt{\frac{1}{y \cdot z}} \cdot \left(y + z\right)\right)} + 2 \cdot \sqrt{y \cdot z} \]
      4. lower-fma.f64N/A

        \[\leadsto \color{blue}{\mathsf{fma}\left(x, \sqrt{\frac{1}{y \cdot z}} \cdot \left(y + z\right), 2 \cdot \sqrt{y \cdot z}\right)} \]
      5. *-commutativeN/A

        \[\leadsto \mathsf{fma}\left(x, \color{blue}{\left(y + z\right) \cdot \sqrt{\frac{1}{y \cdot z}}}, 2 \cdot \sqrt{y \cdot z}\right) \]
      6. lower-*.f64N/A

        \[\leadsto \mathsf{fma}\left(x, \color{blue}{\left(y + z\right) \cdot \sqrt{\frac{1}{y \cdot z}}}, 2 \cdot \sqrt{y \cdot z}\right) \]
      7. lower-+.f64N/A

        \[\leadsto \mathsf{fma}\left(x, \color{blue}{\left(y + z\right)} \cdot \sqrt{\frac{1}{y \cdot z}}, 2 \cdot \sqrt{y \cdot z}\right) \]
      8. lower-sqrt.f64N/A

        \[\leadsto \mathsf{fma}\left(x, \left(y + z\right) \cdot \color{blue}{\sqrt{\frac{1}{y \cdot z}}}, 2 \cdot \sqrt{y \cdot z}\right) \]
      9. lower-/.f64N/A

        \[\leadsto \mathsf{fma}\left(x, \left(y + z\right) \cdot \sqrt{\color{blue}{\frac{1}{y \cdot z}}}, 2 \cdot \sqrt{y \cdot z}\right) \]
      10. lower-*.f64N/A

        \[\leadsto \mathsf{fma}\left(x, \left(y + z\right) \cdot \sqrt{\frac{1}{\color{blue}{y \cdot z}}}, 2 \cdot \sqrt{y \cdot z}\right) \]
      11. lower-*.f64N/A

        \[\leadsto \mathsf{fma}\left(x, \left(y + z\right) \cdot \sqrt{\frac{1}{y \cdot z}}, \color{blue}{2 \cdot \sqrt{y \cdot z}}\right) \]
      12. lower-sqrt.f64N/A

        \[\leadsto \mathsf{fma}\left(x, \left(y + z\right) \cdot \sqrt{\frac{1}{y \cdot z}}, 2 \cdot \color{blue}{\sqrt{y \cdot z}}\right) \]
      13. lower-*.f6425.7

        \[\leadsto \mathsf{fma}\left(x, \left(y + z\right) \cdot \sqrt{\frac{1}{y \cdot z}}, 2 \cdot \sqrt{\color{blue}{y \cdot z}}\right) \]
    5. Applied rewrites25.7%

      \[\leadsto \color{blue}{\mathsf{fma}\left(x, \left(y + z\right) \cdot \sqrt{\frac{1}{y \cdot z}}, 2 \cdot \sqrt{y \cdot z}\right)} \]
    6. Step-by-step derivation
      1. Applied rewrites30.2%

        \[\leadsto \mathsf{fma}\left(2 \cdot \sqrt{y}, \color{blue}{\sqrt{z}}, \frac{x \cdot \left(y + z\right)}{\sqrt{y \cdot z}}\right) \]
      2. Taylor expanded in y around 0

        \[\leadsto \mathsf{fma}\left(2 \cdot \sqrt{y}, \sqrt{z}, x \cdot \sqrt{\frac{z}{y}}\right) \]
      3. Step-by-step derivation
        1. Applied rewrites33.2%

          \[\leadsto \mathsf{fma}\left(2 \cdot \sqrt{y}, \sqrt{z}, x \cdot \sqrt{\frac{z}{y}}\right) \]
      4. Recombined 3 regimes into one program.
      5. Final simplification67.4%

        \[\leadsto \begin{array}{l} \mathbf{if}\;y \leq -7.3 \cdot 10^{+49}:\\ \;\;\;\;2 \cdot {\left(e^{0.25 \cdot \left(\log \left(\left(-z\right) - y\right) - \log \left(\frac{-1}{x}\right)\right)}\right)}^{2}\\ \mathbf{elif}\;y \leq 5 \cdot 10^{+62}:\\ \;\;\;\;2 \cdot \sqrt{\left(y \cdot x + x \cdot z\right) + y \cdot z}\\ \mathbf{else}:\\ \;\;\;\;\mathsf{fma}\left(2 \cdot \sqrt{y}, \sqrt{z}, x \cdot \sqrt{\frac{z}{y}}\right)\\ \end{array} \]
      6. Add Preprocessing

      Alternative 2: 82.4% accurate, 0.6× speedup?

      \[\begin{array}{l} [x, y, z] = \mathsf{sort}([x, y, z])\\ \\ \begin{array}{l} \mathbf{if}\;y \leq 5 \cdot 10^{+62}:\\ \;\;\;\;2 \cdot \sqrt{\left(y \cdot x + x \cdot z\right) + y \cdot z}\\ \mathbf{else}:\\ \;\;\;\;\mathsf{fma}\left(2 \cdot \sqrt{y}, \sqrt{z}, x \cdot \sqrt{\frac{z}{y}}\right)\\ \end{array} \end{array} \]
      NOTE: x, y, and z should be sorted in increasing order before calling this function.
      (FPCore (x y z)
       :precision binary64
       (if (<= y 5e+62)
         (* 2.0 (sqrt (+ (+ (* y x) (* x z)) (* y z))))
         (fma (* 2.0 (sqrt y)) (sqrt z) (* x (sqrt (/ z y))))))
      assert(x < y && y < z);
      double code(double x, double y, double z) {
      	double tmp;
      	if (y <= 5e+62) {
      		tmp = 2.0 * sqrt((((y * x) + (x * z)) + (y * z)));
      	} else {
      		tmp = fma((2.0 * sqrt(y)), sqrt(z), (x * sqrt((z / y))));
      	}
      	return tmp;
      }
      
      x, y, z = sort([x, y, z])
      function code(x, y, z)
      	tmp = 0.0
      	if (y <= 5e+62)
      		tmp = Float64(2.0 * sqrt(Float64(Float64(Float64(y * x) + Float64(x * z)) + Float64(y * z))));
      	else
      		tmp = fma(Float64(2.0 * sqrt(y)), sqrt(z), Float64(x * sqrt(Float64(z / y))));
      	end
      	return tmp
      end
      
      NOTE: x, y, and z should be sorted in increasing order before calling this function.
      code[x_, y_, z_] := If[LessEqual[y, 5e+62], N[(2.0 * N[Sqrt[N[(N[(N[(y * x), $MachinePrecision] + N[(x * z), $MachinePrecision]), $MachinePrecision] + N[(y * z), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision], N[(N[(2.0 * N[Sqrt[y], $MachinePrecision]), $MachinePrecision] * N[Sqrt[z], $MachinePrecision] + N[(x * N[Sqrt[N[(z / y), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]]
      
      \begin{array}{l}
      [x, y, z] = \mathsf{sort}([x, y, z])\\
      \\
      \begin{array}{l}
      \mathbf{if}\;y \leq 5 \cdot 10^{+62}:\\
      \;\;\;\;2 \cdot \sqrt{\left(y \cdot x + x \cdot z\right) + y \cdot z}\\
      
      \mathbf{else}:\\
      \;\;\;\;\mathsf{fma}\left(2 \cdot \sqrt{y}, \sqrt{z}, x \cdot \sqrt{\frac{z}{y}}\right)\\
      
      
      \end{array}
      \end{array}
      
      Derivation
      1. Split input into 2 regimes
      2. if y < 5.00000000000000029e62

        1. Initial program 77.2%

          \[2 \cdot \sqrt{\left(x \cdot y + x \cdot z\right) + y \cdot z} \]
        2. Add Preprocessing

        if 5.00000000000000029e62 < y

        1. Initial program 62.1%

          \[2 \cdot \sqrt{\left(x \cdot y + x \cdot z\right) + y \cdot z} \]
        2. Add Preprocessing
        3. Taylor expanded in x around 0

          \[\leadsto \color{blue}{2 \cdot \sqrt{y \cdot z} + \left(x \cdot \left(y + z\right)\right) \cdot \sqrt{\frac{1}{y \cdot z}}} \]
        4. Step-by-step derivation
          1. +-commutativeN/A

            \[\leadsto \color{blue}{\left(x \cdot \left(y + z\right)\right) \cdot \sqrt{\frac{1}{y \cdot z}} + 2 \cdot \sqrt{y \cdot z}} \]
          2. associate-*l*N/A

            \[\leadsto \color{blue}{x \cdot \left(\left(y + z\right) \cdot \sqrt{\frac{1}{y \cdot z}}\right)} + 2 \cdot \sqrt{y \cdot z} \]
          3. *-commutativeN/A

            \[\leadsto x \cdot \color{blue}{\left(\sqrt{\frac{1}{y \cdot z}} \cdot \left(y + z\right)\right)} + 2 \cdot \sqrt{y \cdot z} \]
          4. lower-fma.f64N/A

            \[\leadsto \color{blue}{\mathsf{fma}\left(x, \sqrt{\frac{1}{y \cdot z}} \cdot \left(y + z\right), 2 \cdot \sqrt{y \cdot z}\right)} \]
          5. *-commutativeN/A

            \[\leadsto \mathsf{fma}\left(x, \color{blue}{\left(y + z\right) \cdot \sqrt{\frac{1}{y \cdot z}}}, 2 \cdot \sqrt{y \cdot z}\right) \]
          6. lower-*.f64N/A

            \[\leadsto \mathsf{fma}\left(x, \color{blue}{\left(y + z\right) \cdot \sqrt{\frac{1}{y \cdot z}}}, 2 \cdot \sqrt{y \cdot z}\right) \]
          7. lower-+.f64N/A

            \[\leadsto \mathsf{fma}\left(x, \color{blue}{\left(y + z\right)} \cdot \sqrt{\frac{1}{y \cdot z}}, 2 \cdot \sqrt{y \cdot z}\right) \]
          8. lower-sqrt.f64N/A

            \[\leadsto \mathsf{fma}\left(x, \left(y + z\right) \cdot \color{blue}{\sqrt{\frac{1}{y \cdot z}}}, 2 \cdot \sqrt{y \cdot z}\right) \]
          9. lower-/.f64N/A

            \[\leadsto \mathsf{fma}\left(x, \left(y + z\right) \cdot \sqrt{\color{blue}{\frac{1}{y \cdot z}}}, 2 \cdot \sqrt{y \cdot z}\right) \]
          10. lower-*.f64N/A

            \[\leadsto \mathsf{fma}\left(x, \left(y + z\right) \cdot \sqrt{\frac{1}{\color{blue}{y \cdot z}}}, 2 \cdot \sqrt{y \cdot z}\right) \]
          11. lower-*.f64N/A

            \[\leadsto \mathsf{fma}\left(x, \left(y + z\right) \cdot \sqrt{\frac{1}{y \cdot z}}, \color{blue}{2 \cdot \sqrt{y \cdot z}}\right) \]
          12. lower-sqrt.f64N/A

            \[\leadsto \mathsf{fma}\left(x, \left(y + z\right) \cdot \sqrt{\frac{1}{y \cdot z}}, 2 \cdot \color{blue}{\sqrt{y \cdot z}}\right) \]
          13. lower-*.f6425.7

            \[\leadsto \mathsf{fma}\left(x, \left(y + z\right) \cdot \sqrt{\frac{1}{y \cdot z}}, 2 \cdot \sqrt{\color{blue}{y \cdot z}}\right) \]
        5. Applied rewrites25.7%

          \[\leadsto \color{blue}{\mathsf{fma}\left(x, \left(y + z\right) \cdot \sqrt{\frac{1}{y \cdot z}}, 2 \cdot \sqrt{y \cdot z}\right)} \]
        6. Step-by-step derivation
          1. Applied rewrites30.2%

            \[\leadsto \mathsf{fma}\left(2 \cdot \sqrt{y}, \color{blue}{\sqrt{z}}, \frac{x \cdot \left(y + z\right)}{\sqrt{y \cdot z}}\right) \]
          2. Taylor expanded in y around 0

            \[\leadsto \mathsf{fma}\left(2 \cdot \sqrt{y}, \sqrt{z}, x \cdot \sqrt{\frac{z}{y}}\right) \]
          3. Step-by-step derivation
            1. Applied rewrites33.2%

              \[\leadsto \mathsf{fma}\left(2 \cdot \sqrt{y}, \sqrt{z}, x \cdot \sqrt{\frac{z}{y}}\right) \]
          4. Recombined 2 regimes into one program.
          5. Final simplification70.7%

            \[\leadsto \begin{array}{l} \mathbf{if}\;y \leq 5 \cdot 10^{+62}:\\ \;\;\;\;2 \cdot \sqrt{\left(y \cdot x + x \cdot z\right) + y \cdot z}\\ \mathbf{else}:\\ \;\;\;\;\mathsf{fma}\left(2 \cdot \sqrt{y}, \sqrt{z}, x \cdot \sqrt{\frac{z}{y}}\right)\\ \end{array} \]
          6. Add Preprocessing

          Alternative 3: 70.1% accurate, 1.0× speedup?

          \[\begin{array}{l} [x, y, z] = \mathsf{sort}([x, y, z])\\ \\ 2 \cdot \sqrt{\left(y \cdot x + x \cdot z\right) + y \cdot z} \end{array} \]
          NOTE: x, y, and z should be sorted in increasing order before calling this function.
          (FPCore (x y z)
           :precision binary64
           (* 2.0 (sqrt (+ (+ (* y x) (* x z)) (* y z)))))
          assert(x < y && y < z);
          double code(double x, double y, double z) {
          	return 2.0 * sqrt((((y * x) + (x * z)) + (y * z)));
          }
          
          NOTE: x, y, and z should be sorted in increasing order before calling this function.
          real(8) function code(x, y, z)
              real(8), intent (in) :: x
              real(8), intent (in) :: y
              real(8), intent (in) :: z
              code = 2.0d0 * sqrt((((y * x) + (x * z)) + (y * z)))
          end function
          
          assert x < y && y < z;
          public static double code(double x, double y, double z) {
          	return 2.0 * Math.sqrt((((y * x) + (x * z)) + (y * z)));
          }
          
          [x, y, z] = sort([x, y, z])
          def code(x, y, z):
          	return 2.0 * math.sqrt((((y * x) + (x * z)) + (y * z)))
          
          x, y, z = sort([x, y, z])
          function code(x, y, z)
          	return Float64(2.0 * sqrt(Float64(Float64(Float64(y * x) + Float64(x * z)) + Float64(y * z))))
          end
          
          x, y, z = num2cell(sort([x, y, z])){:}
          function tmp = code(x, y, z)
          	tmp = 2.0 * sqrt((((y * x) + (x * z)) + (y * z)));
          end
          
          NOTE: x, y, and z should be sorted in increasing order before calling this function.
          code[x_, y_, z_] := N[(2.0 * N[Sqrt[N[(N[(N[(y * x), $MachinePrecision] + N[(x * z), $MachinePrecision]), $MachinePrecision] + N[(y * z), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]
          
          \begin{array}{l}
          [x, y, z] = \mathsf{sort}([x, y, z])\\
          \\
          2 \cdot \sqrt{\left(y \cdot x + x \cdot z\right) + y \cdot z}
          \end{array}
          
          Derivation
          1. Initial program 75.0%

            \[2 \cdot \sqrt{\left(x \cdot y + x \cdot z\right) + y \cdot z} \]
          2. Add Preprocessing
          3. Final simplification75.0%

            \[\leadsto 2 \cdot \sqrt{\left(y \cdot x + x \cdot z\right) + y \cdot z} \]
          4. Add Preprocessing

          Alternative 4: 70.3% accurate, 1.2× speedup?

          \[\begin{array}{l} [x, y, z] = \mathsf{sort}([x, y, z])\\ \\ \begin{array}{l} \mathbf{if}\;y \leq -4 \cdot 10^{-303}:\\ \;\;\;\;2 \cdot \sqrt{x \cdot \left(y + z\right)}\\ \mathbf{else}:\\ \;\;\;\;2 \cdot \sqrt{z \cdot \left(y + x\right)}\\ \end{array} \end{array} \]
          NOTE: x, y, and z should be sorted in increasing order before calling this function.
          (FPCore (x y z)
           :precision binary64
           (if (<= y -4e-303) (* 2.0 (sqrt (* x (+ y z)))) (* 2.0 (sqrt (* z (+ y x))))))
          assert(x < y && y < z);
          double code(double x, double y, double z) {
          	double tmp;
          	if (y <= -4e-303) {
          		tmp = 2.0 * sqrt((x * (y + z)));
          	} else {
          		tmp = 2.0 * sqrt((z * (y + x)));
          	}
          	return tmp;
          }
          
          NOTE: x, y, and z should be sorted in increasing order before calling this function.
          real(8) function code(x, y, z)
              real(8), intent (in) :: x
              real(8), intent (in) :: y
              real(8), intent (in) :: z
              real(8) :: tmp
              if (y <= (-4d-303)) then
                  tmp = 2.0d0 * sqrt((x * (y + z)))
              else
                  tmp = 2.0d0 * sqrt((z * (y + x)))
              end if
              code = tmp
          end function
          
          assert x < y && y < z;
          public static double code(double x, double y, double z) {
          	double tmp;
          	if (y <= -4e-303) {
          		tmp = 2.0 * Math.sqrt((x * (y + z)));
          	} else {
          		tmp = 2.0 * Math.sqrt((z * (y + x)));
          	}
          	return tmp;
          }
          
          [x, y, z] = sort([x, y, z])
          def code(x, y, z):
          	tmp = 0
          	if y <= -4e-303:
          		tmp = 2.0 * math.sqrt((x * (y + z)))
          	else:
          		tmp = 2.0 * math.sqrt((z * (y + x)))
          	return tmp
          
          x, y, z = sort([x, y, z])
          function code(x, y, z)
          	tmp = 0.0
          	if (y <= -4e-303)
          		tmp = Float64(2.0 * sqrt(Float64(x * Float64(y + z))));
          	else
          		tmp = Float64(2.0 * sqrt(Float64(z * Float64(y + x))));
          	end
          	return tmp
          end
          
          x, y, z = num2cell(sort([x, y, z])){:}
          function tmp_2 = code(x, y, z)
          	tmp = 0.0;
          	if (y <= -4e-303)
          		tmp = 2.0 * sqrt((x * (y + z)));
          	else
          		tmp = 2.0 * sqrt((z * (y + x)));
          	end
          	tmp_2 = tmp;
          end
          
          NOTE: x, y, and z should be sorted in increasing order before calling this function.
          code[x_, y_, z_] := If[LessEqual[y, -4e-303], N[(2.0 * N[Sqrt[N[(x * N[(y + z), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision], N[(2.0 * N[Sqrt[N[(z * N[(y + x), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]]
          
          \begin{array}{l}
          [x, y, z] = \mathsf{sort}([x, y, z])\\
          \\
          \begin{array}{l}
          \mathbf{if}\;y \leq -4 \cdot 10^{-303}:\\
          \;\;\;\;2 \cdot \sqrt{x \cdot \left(y + z\right)}\\
          
          \mathbf{else}:\\
          \;\;\;\;2 \cdot \sqrt{z \cdot \left(y + x\right)}\\
          
          
          \end{array}
          \end{array}
          
          Derivation
          1. Split input into 2 regimes
          2. if y < -3.99999999999999972e-303

            1. Initial program 74.0%

              \[2 \cdot \sqrt{\left(x \cdot y + x \cdot z\right) + y \cdot z} \]
            2. Add Preprocessing
            3. Taylor expanded in x around inf

              \[\leadsto 2 \cdot \sqrt{\color{blue}{x \cdot \left(y + z\right)}} \]
            4. Step-by-step derivation
              1. lower-*.f64N/A

                \[\leadsto 2 \cdot \sqrt{\color{blue}{x \cdot \left(y + z\right)}} \]
              2. lower-+.f6446.1

                \[\leadsto 2 \cdot \sqrt{x \cdot \color{blue}{\left(y + z\right)}} \]
            5. Applied rewrites46.1%

              \[\leadsto 2 \cdot \sqrt{\color{blue}{x \cdot \left(y + z\right)}} \]

            if -3.99999999999999972e-303 < y

            1. Initial program 75.9%

              \[2 \cdot \sqrt{\left(x \cdot y + x \cdot z\right) + y \cdot z} \]
            2. Add Preprocessing
            3. Taylor expanded in z around inf

              \[\leadsto 2 \cdot \sqrt{\color{blue}{z \cdot \left(x + y\right)}} \]
            4. Step-by-step derivation
              1. lower-*.f64N/A

                \[\leadsto 2 \cdot \sqrt{\color{blue}{z \cdot \left(x + y\right)}} \]
              2. lower-+.f6449.0

                \[\leadsto 2 \cdot \sqrt{z \cdot \color{blue}{\left(x + y\right)}} \]
            5. Applied rewrites49.0%

              \[\leadsto 2 \cdot \sqrt{\color{blue}{z \cdot \left(x + y\right)}} \]
          3. Recombined 2 regimes into one program.
          4. Final simplification47.5%

            \[\leadsto \begin{array}{l} \mathbf{if}\;y \leq -4 \cdot 10^{-303}:\\ \;\;\;\;2 \cdot \sqrt{x \cdot \left(y + z\right)}\\ \mathbf{else}:\\ \;\;\;\;2 \cdot \sqrt{z \cdot \left(y + x\right)}\\ \end{array} \]
          5. Add Preprocessing

          Alternative 5: 69.1% accurate, 1.2× speedup?

          \[\begin{array}{l} [x, y, z] = \mathsf{sort}([x, y, z])\\ \\ \begin{array}{l} \mathbf{if}\;y \leq 2.6 \cdot 10^{-273}:\\ \;\;\;\;2 \cdot \sqrt{x \cdot \left(y + z\right)}\\ \mathbf{else}:\\ \;\;\;\;2 \cdot \sqrt{y \cdot z}\\ \end{array} \end{array} \]
          NOTE: x, y, and z should be sorted in increasing order before calling this function.
          (FPCore (x y z)
           :precision binary64
           (if (<= y 2.6e-273) (* 2.0 (sqrt (* x (+ y z)))) (* 2.0 (sqrt (* y z)))))
          assert(x < y && y < z);
          double code(double x, double y, double z) {
          	double tmp;
          	if (y <= 2.6e-273) {
          		tmp = 2.0 * sqrt((x * (y + z)));
          	} else {
          		tmp = 2.0 * sqrt((y * z));
          	}
          	return tmp;
          }
          
          NOTE: x, y, and z should be sorted in increasing order before calling this function.
          real(8) function code(x, y, z)
              real(8), intent (in) :: x
              real(8), intent (in) :: y
              real(8), intent (in) :: z
              real(8) :: tmp
              if (y <= 2.6d-273) then
                  tmp = 2.0d0 * sqrt((x * (y + z)))
              else
                  tmp = 2.0d0 * sqrt((y * z))
              end if
              code = tmp
          end function
          
          assert x < y && y < z;
          public static double code(double x, double y, double z) {
          	double tmp;
          	if (y <= 2.6e-273) {
          		tmp = 2.0 * Math.sqrt((x * (y + z)));
          	} else {
          		tmp = 2.0 * Math.sqrt((y * z));
          	}
          	return tmp;
          }
          
          [x, y, z] = sort([x, y, z])
          def code(x, y, z):
          	tmp = 0
          	if y <= 2.6e-273:
          		tmp = 2.0 * math.sqrt((x * (y + z)))
          	else:
          		tmp = 2.0 * math.sqrt((y * z))
          	return tmp
          
          x, y, z = sort([x, y, z])
          function code(x, y, z)
          	tmp = 0.0
          	if (y <= 2.6e-273)
          		tmp = Float64(2.0 * sqrt(Float64(x * Float64(y + z))));
          	else
          		tmp = Float64(2.0 * sqrt(Float64(y * z)));
          	end
          	return tmp
          end
          
          x, y, z = num2cell(sort([x, y, z])){:}
          function tmp_2 = code(x, y, z)
          	tmp = 0.0;
          	if (y <= 2.6e-273)
          		tmp = 2.0 * sqrt((x * (y + z)));
          	else
          		tmp = 2.0 * sqrt((y * z));
          	end
          	tmp_2 = tmp;
          end
          
          NOTE: x, y, and z should be sorted in increasing order before calling this function.
          code[x_, y_, z_] := If[LessEqual[y, 2.6e-273], N[(2.0 * N[Sqrt[N[(x * N[(y + z), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision], N[(2.0 * N[Sqrt[N[(y * z), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]]
          
          \begin{array}{l}
          [x, y, z] = \mathsf{sort}([x, y, z])\\
          \\
          \begin{array}{l}
          \mathbf{if}\;y \leq 2.6 \cdot 10^{-273}:\\
          \;\;\;\;2 \cdot \sqrt{x \cdot \left(y + z\right)}\\
          
          \mathbf{else}:\\
          \;\;\;\;2 \cdot \sqrt{y \cdot z}\\
          
          
          \end{array}
          \end{array}
          
          Derivation
          1. Split input into 2 regimes
          2. if y < 2.59999999999999983e-273

            1. Initial program 75.7%

              \[2 \cdot \sqrt{\left(x \cdot y + x \cdot z\right) + y \cdot z} \]
            2. Add Preprocessing
            3. Taylor expanded in x around inf

              \[\leadsto 2 \cdot \sqrt{\color{blue}{x \cdot \left(y + z\right)}} \]
            4. Step-by-step derivation
              1. lower-*.f64N/A

                \[\leadsto 2 \cdot \sqrt{\color{blue}{x \cdot \left(y + z\right)}} \]
              2. lower-+.f6449.7

                \[\leadsto 2 \cdot \sqrt{x \cdot \color{blue}{\left(y + z\right)}} \]
            5. Applied rewrites49.7%

              \[\leadsto 2 \cdot \sqrt{\color{blue}{x \cdot \left(y + z\right)}} \]

            if 2.59999999999999983e-273 < y

            1. Initial program 74.1%

              \[2 \cdot \sqrt{\left(x \cdot y + x \cdot z\right) + y \cdot z} \]
            2. Add Preprocessing
            3. Taylor expanded in x around 0

              \[\leadsto 2 \cdot \sqrt{\color{blue}{y \cdot z}} \]
            4. Step-by-step derivation
              1. lower-*.f6425.5

                \[\leadsto 2 \cdot \sqrt{\color{blue}{y \cdot z}} \]
            5. Applied rewrites25.5%

              \[\leadsto 2 \cdot \sqrt{\color{blue}{y \cdot z}} \]
          3. Recombined 2 regimes into one program.
          4. Add Preprocessing

          Alternative 6: 68.1% accurate, 1.4× speedup?

          \[\begin{array}{l} [x, y, z] = \mathsf{sort}([x, y, z])\\ \\ \begin{array}{l} \mathbf{if}\;y \leq -1 \cdot 10^{-310}:\\ \;\;\;\;2 \cdot \sqrt{y \cdot x}\\ \mathbf{else}:\\ \;\;\;\;2 \cdot \sqrt{y \cdot z}\\ \end{array} \end{array} \]
          NOTE: x, y, and z should be sorted in increasing order before calling this function.
          (FPCore (x y z)
           :precision binary64
           (if (<= y -1e-310) (* 2.0 (sqrt (* y x))) (* 2.0 (sqrt (* y z)))))
          assert(x < y && y < z);
          double code(double x, double y, double z) {
          	double tmp;
          	if (y <= -1e-310) {
          		tmp = 2.0 * sqrt((y * x));
          	} else {
          		tmp = 2.0 * sqrt((y * z));
          	}
          	return tmp;
          }
          
          NOTE: x, y, and z should be sorted in increasing order before calling this function.
          real(8) function code(x, y, z)
              real(8), intent (in) :: x
              real(8), intent (in) :: y
              real(8), intent (in) :: z
              real(8) :: tmp
              if (y <= (-1d-310)) then
                  tmp = 2.0d0 * sqrt((y * x))
              else
                  tmp = 2.0d0 * sqrt((y * z))
              end if
              code = tmp
          end function
          
          assert x < y && y < z;
          public static double code(double x, double y, double z) {
          	double tmp;
          	if (y <= -1e-310) {
          		tmp = 2.0 * Math.sqrt((y * x));
          	} else {
          		tmp = 2.0 * Math.sqrt((y * z));
          	}
          	return tmp;
          }
          
          [x, y, z] = sort([x, y, z])
          def code(x, y, z):
          	tmp = 0
          	if y <= -1e-310:
          		tmp = 2.0 * math.sqrt((y * x))
          	else:
          		tmp = 2.0 * math.sqrt((y * z))
          	return tmp
          
          x, y, z = sort([x, y, z])
          function code(x, y, z)
          	tmp = 0.0
          	if (y <= -1e-310)
          		tmp = Float64(2.0 * sqrt(Float64(y * x)));
          	else
          		tmp = Float64(2.0 * sqrt(Float64(y * z)));
          	end
          	return tmp
          end
          
          x, y, z = num2cell(sort([x, y, z])){:}
          function tmp_2 = code(x, y, z)
          	tmp = 0.0;
          	if (y <= -1e-310)
          		tmp = 2.0 * sqrt((y * x));
          	else
          		tmp = 2.0 * sqrt((y * z));
          	end
          	tmp_2 = tmp;
          end
          
          NOTE: x, y, and z should be sorted in increasing order before calling this function.
          code[x_, y_, z_] := If[LessEqual[y, -1e-310], N[(2.0 * N[Sqrt[N[(y * x), $MachinePrecision]], $MachinePrecision]), $MachinePrecision], N[(2.0 * N[Sqrt[N[(y * z), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]]
          
          \begin{array}{l}
          [x, y, z] = \mathsf{sort}([x, y, z])\\
          \\
          \begin{array}{l}
          \mathbf{if}\;y \leq -1 \cdot 10^{-310}:\\
          \;\;\;\;2 \cdot \sqrt{y \cdot x}\\
          
          \mathbf{else}:\\
          \;\;\;\;2 \cdot \sqrt{y \cdot z}\\
          
          
          \end{array}
          \end{array}
          
          Derivation
          1. Split input into 2 regimes
          2. if y < -9.999999999999969e-311

            1. Initial program 74.2%

              \[2 \cdot \sqrt{\left(x \cdot y + x \cdot z\right) + y \cdot z} \]
            2. Add Preprocessing
            3. Taylor expanded in z around 0

              \[\leadsto 2 \cdot \sqrt{\color{blue}{x \cdot y}} \]
            4. Step-by-step derivation
              1. lower-*.f6425.2

                \[\leadsto 2 \cdot \sqrt{\color{blue}{x \cdot y}} \]
            5. Applied rewrites25.2%

              \[\leadsto 2 \cdot \sqrt{\color{blue}{x \cdot y}} \]

            if -9.999999999999969e-311 < y

            1. Initial program 75.7%

              \[2 \cdot \sqrt{\left(x \cdot y + x \cdot z\right) + y \cdot z} \]
            2. Add Preprocessing
            3. Taylor expanded in x around 0

              \[\leadsto 2 \cdot \sqrt{\color{blue}{y \cdot z}} \]
            4. Step-by-step derivation
              1. lower-*.f6423.9

                \[\leadsto 2 \cdot \sqrt{\color{blue}{y \cdot z}} \]
            5. Applied rewrites23.9%

              \[\leadsto 2 \cdot \sqrt{\color{blue}{y \cdot z}} \]
          3. Recombined 2 regimes into one program.
          4. Final simplification24.6%

            \[\leadsto \begin{array}{l} \mathbf{if}\;y \leq -1 \cdot 10^{-310}:\\ \;\;\;\;2 \cdot \sqrt{y \cdot x}\\ \mathbf{else}:\\ \;\;\;\;2 \cdot \sqrt{y \cdot z}\\ \end{array} \]
          5. Add Preprocessing

          Alternative 7: 35.2% accurate, 1.8× speedup?

          \[\begin{array}{l} [x, y, z] = \mathsf{sort}([x, y, z])\\ \\ 2 \cdot \sqrt{y \cdot x} \end{array} \]
          NOTE: x, y, and z should be sorted in increasing order before calling this function.
          (FPCore (x y z) :precision binary64 (* 2.0 (sqrt (* y x))))
          assert(x < y && y < z);
          double code(double x, double y, double z) {
          	return 2.0 * sqrt((y * x));
          }
          
          NOTE: x, y, and z should be sorted in increasing order before calling this function.
          real(8) function code(x, y, z)
              real(8), intent (in) :: x
              real(8), intent (in) :: y
              real(8), intent (in) :: z
              code = 2.0d0 * sqrt((y * x))
          end function
          
          assert x < y && y < z;
          public static double code(double x, double y, double z) {
          	return 2.0 * Math.sqrt((y * x));
          }
          
          [x, y, z] = sort([x, y, z])
          def code(x, y, z):
          	return 2.0 * math.sqrt((y * x))
          
          x, y, z = sort([x, y, z])
          function code(x, y, z)
          	return Float64(2.0 * sqrt(Float64(y * x)))
          end
          
          x, y, z = num2cell(sort([x, y, z])){:}
          function tmp = code(x, y, z)
          	tmp = 2.0 * sqrt((y * x));
          end
          
          NOTE: x, y, and z should be sorted in increasing order before calling this function.
          code[x_, y_, z_] := N[(2.0 * N[Sqrt[N[(y * x), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]
          
          \begin{array}{l}
          [x, y, z] = \mathsf{sort}([x, y, z])\\
          \\
          2 \cdot \sqrt{y \cdot x}
          \end{array}
          
          Derivation
          1. Initial program 75.0%

            \[2 \cdot \sqrt{\left(x \cdot y + x \cdot z\right) + y \cdot z} \]
          2. Add Preprocessing
          3. Taylor expanded in z around 0

            \[\leadsto 2 \cdot \sqrt{\color{blue}{x \cdot y}} \]
          4. Step-by-step derivation
            1. lower-*.f6427.4

              \[\leadsto 2 \cdot \sqrt{\color{blue}{x \cdot y}} \]
          5. Applied rewrites27.4%

            \[\leadsto 2 \cdot \sqrt{\color{blue}{x \cdot y}} \]
          6. Final simplification27.4%

            \[\leadsto 2 \cdot \sqrt{y \cdot x} \]
          7. Add Preprocessing

          Developer Target 1: 82.3% accurate, 0.0× speedup?

          \[\begin{array}{l} \\ \begin{array}{l} t_0 := 0.25 \cdot \left(\left({y}^{-0.75} \cdot \left({z}^{-0.75} \cdot x\right)\right) \cdot \left(y + z\right)\right) + {z}^{0.25} \cdot {y}^{0.25}\\ \mathbf{if}\;z < 7.636950090573675 \cdot 10^{+176}:\\ \;\;\;\;2 \cdot \sqrt{\left(x + y\right) \cdot z + x \cdot y}\\ \mathbf{else}:\\ \;\;\;\;\left(t\_0 \cdot t\_0\right) \cdot 2\\ \end{array} \end{array} \]
          (FPCore (x y z)
           :precision binary64
           (let* ((t_0
                   (+
                    (* 0.25 (* (* (pow y -0.75) (* (pow z -0.75) x)) (+ y z)))
                    (* (pow z 0.25) (pow y 0.25)))))
             (if (< z 7.636950090573675e+176)
               (* 2.0 (sqrt (+ (* (+ x y) z) (* x y))))
               (* (* t_0 t_0) 2.0))))
          double code(double x, double y, double z) {
          	double t_0 = (0.25 * ((pow(y, -0.75) * (pow(z, -0.75) * x)) * (y + z))) + (pow(z, 0.25) * pow(y, 0.25));
          	double tmp;
          	if (z < 7.636950090573675e+176) {
          		tmp = 2.0 * sqrt((((x + y) * z) + (x * y)));
          	} else {
          		tmp = (t_0 * t_0) * 2.0;
          	}
          	return tmp;
          }
          
          real(8) function code(x, y, z)
              real(8), intent (in) :: x
              real(8), intent (in) :: y
              real(8), intent (in) :: z
              real(8) :: t_0
              real(8) :: tmp
              t_0 = (0.25d0 * (((y ** (-0.75d0)) * ((z ** (-0.75d0)) * x)) * (y + z))) + ((z ** 0.25d0) * (y ** 0.25d0))
              if (z < 7.636950090573675d+176) then
                  tmp = 2.0d0 * sqrt((((x + y) * z) + (x * y)))
              else
                  tmp = (t_0 * t_0) * 2.0d0
              end if
              code = tmp
          end function
          
          public static double code(double x, double y, double z) {
          	double t_0 = (0.25 * ((Math.pow(y, -0.75) * (Math.pow(z, -0.75) * x)) * (y + z))) + (Math.pow(z, 0.25) * Math.pow(y, 0.25));
          	double tmp;
          	if (z < 7.636950090573675e+176) {
          		tmp = 2.0 * Math.sqrt((((x + y) * z) + (x * y)));
          	} else {
          		tmp = (t_0 * t_0) * 2.0;
          	}
          	return tmp;
          }
          
          def code(x, y, z):
          	t_0 = (0.25 * ((math.pow(y, -0.75) * (math.pow(z, -0.75) * x)) * (y + z))) + (math.pow(z, 0.25) * math.pow(y, 0.25))
          	tmp = 0
          	if z < 7.636950090573675e+176:
          		tmp = 2.0 * math.sqrt((((x + y) * z) + (x * y)))
          	else:
          		tmp = (t_0 * t_0) * 2.0
          	return tmp
          
          function code(x, y, z)
          	t_0 = Float64(Float64(0.25 * Float64(Float64((y ^ -0.75) * Float64((z ^ -0.75) * x)) * Float64(y + z))) + Float64((z ^ 0.25) * (y ^ 0.25)))
          	tmp = 0.0
          	if (z < 7.636950090573675e+176)
          		tmp = Float64(2.0 * sqrt(Float64(Float64(Float64(x + y) * z) + Float64(x * y))));
          	else
          		tmp = Float64(Float64(t_0 * t_0) * 2.0);
          	end
          	return tmp
          end
          
          function tmp_2 = code(x, y, z)
          	t_0 = (0.25 * (((y ^ -0.75) * ((z ^ -0.75) * x)) * (y + z))) + ((z ^ 0.25) * (y ^ 0.25));
          	tmp = 0.0;
          	if (z < 7.636950090573675e+176)
          		tmp = 2.0 * sqrt((((x + y) * z) + (x * y)));
          	else
          		tmp = (t_0 * t_0) * 2.0;
          	end
          	tmp_2 = tmp;
          end
          
          code[x_, y_, z_] := Block[{t$95$0 = N[(N[(0.25 * N[(N[(N[Power[y, -0.75], $MachinePrecision] * N[(N[Power[z, -0.75], $MachinePrecision] * x), $MachinePrecision]), $MachinePrecision] * N[(y + z), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] + N[(N[Power[z, 0.25], $MachinePrecision] * N[Power[y, 0.25], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]}, If[Less[z, 7.636950090573675e+176], N[(2.0 * N[Sqrt[N[(N[(N[(x + y), $MachinePrecision] * z), $MachinePrecision] + N[(x * y), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision], N[(N[(t$95$0 * t$95$0), $MachinePrecision] * 2.0), $MachinePrecision]]]
          
          \begin{array}{l}
          
          \\
          \begin{array}{l}
          t_0 := 0.25 \cdot \left(\left({y}^{-0.75} \cdot \left({z}^{-0.75} \cdot x\right)\right) \cdot \left(y + z\right)\right) + {z}^{0.25} \cdot {y}^{0.25}\\
          \mathbf{if}\;z < 7.636950090573675 \cdot 10^{+176}:\\
          \;\;\;\;2 \cdot \sqrt{\left(x + y\right) \cdot z + x \cdot y}\\
          
          \mathbf{else}:\\
          \;\;\;\;\left(t\_0 \cdot t\_0\right) \cdot 2\\
          
          
          \end{array}
          \end{array}
          

          Reproduce

          ?
          herbie shell --seed 2024233 
          (FPCore (x y z)
            :name "Diagrams.TwoD.Apollonian:descartes from diagrams-contrib-1.3.0.5"
            :precision binary64
          
            :alt
            (! :herbie-platform default (if (< z 763695009057367500000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000) (* 2 (sqrt (+ (* (+ x y) z) (* x y)))) (* (* (+ (* 1/4 (* (* (pow y -3/4) (* (pow z -3/4) x)) (+ y z))) (* (pow z 1/4) (pow y 1/4))) (+ (* 1/4 (* (* (pow y -3/4) (* (pow z -3/4) x)) (+ y z))) (* (pow z 1/4) (pow y 1/4)))) 2)))
          
            (* 2.0 (sqrt (+ (+ (* x y) (* x z)) (* y z)))))