Kahan's exp quotient

Percentage Accurate: 52.8% → 100.0%
Time: 10.0s
Alternatives: 14
Speedup: 8.8×

Specification

?
\[\begin{array}{l} \\ \frac{e^{x} - 1}{x} \end{array} \]
(FPCore (x) :precision binary64 (/ (- (exp x) 1.0) x))
double code(double x) {
	return (exp(x) - 1.0) / x;
}
real(8) function code(x)
    real(8), intent (in) :: x
    code = (exp(x) - 1.0d0) / x
end function
public static double code(double x) {
	return (Math.exp(x) - 1.0) / x;
}
def code(x):
	return (math.exp(x) - 1.0) / x
function code(x)
	return Float64(Float64(exp(x) - 1.0) / x)
end
function tmp = code(x)
	tmp = (exp(x) - 1.0) / x;
end
code[x_] := N[(N[(N[Exp[x], $MachinePrecision] - 1.0), $MachinePrecision] / x), $MachinePrecision]
\begin{array}{l}

\\
\frac{e^{x} - 1}{x}
\end{array}

Sampling outcomes in binary64 precision:

Local Percentage Accuracy vs ?

The average percentage accuracy by input value. Horizontal axis shows value of an input variable; the variable is choosen in the title. Vertical axis is accuracy; higher is better. Red represent the original program, while blue represents Herbie's suggestion. These can be toggled with buttons below the plot. The line is an average while dots represent individual samples.

Accuracy vs Speed?

Herbie found 14 alternatives:

AlternativeAccuracySpeedup
The accuracy (vertical axis) and speed (horizontal axis) of each alternatives. Up and to the right is better. The red square shows the initial program, and each blue circle shows an alternative.The line shows the best available speed-accuracy tradeoffs.

Initial Program: 52.8% accurate, 1.0× speedup?

\[\begin{array}{l} \\ \frac{e^{x} - 1}{x} \end{array} \]
(FPCore (x) :precision binary64 (/ (- (exp x) 1.0) x))
double code(double x) {
	return (exp(x) - 1.0) / x;
}
real(8) function code(x)
    real(8), intent (in) :: x
    code = (exp(x) - 1.0d0) / x
end function
public static double code(double x) {
	return (Math.exp(x) - 1.0) / x;
}
def code(x):
	return (math.exp(x) - 1.0) / x
function code(x)
	return Float64(Float64(exp(x) - 1.0) / x)
end
function tmp = code(x)
	tmp = (exp(x) - 1.0) / x;
end
code[x_] := N[(N[(N[Exp[x], $MachinePrecision] - 1.0), $MachinePrecision] / x), $MachinePrecision]
\begin{array}{l}

\\
\frac{e^{x} - 1}{x}
\end{array}

Alternative 1: 100.0% accurate, 1.0× speedup?

\[\begin{array}{l} \\ \frac{\mathsf{expm1}\left(x\right)}{x} \end{array} \]
(FPCore (x) :precision binary64 (/ (expm1 x) x))
double code(double x) {
	return expm1(x) / x;
}
public static double code(double x) {
	return Math.expm1(x) / x;
}
def code(x):
	return math.expm1(x) / x
function code(x)
	return Float64(expm1(x) / x)
end
code[x_] := N[(N[(Exp[x] - 1), $MachinePrecision] / x), $MachinePrecision]
\begin{array}{l}

\\
\frac{\mathsf{expm1}\left(x\right)}{x}
\end{array}
Derivation
  1. Initial program 53.5%

    \[\frac{e^{x} - 1}{x} \]
  2. Add Preprocessing
  3. Step-by-step derivation
    1. lift--.f64N/A

      \[\leadsto \frac{\color{blue}{e^{x} - 1}}{x} \]
    2. lift-exp.f64N/A

      \[\leadsto \frac{\color{blue}{e^{x}} - 1}{x} \]
    3. lower-expm1.f64100.0

      \[\leadsto \frac{\color{blue}{\mathsf{expm1}\left(x\right)}}{x} \]
  4. Applied rewrites100.0%

    \[\leadsto \frac{\color{blue}{\mathsf{expm1}\left(x\right)}}{x} \]
  5. Add Preprocessing

Alternative 2: 69.2% accurate, 0.8× speedup?

\[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;\frac{e^{x} + -1}{x} \leq 2:\\ \;\;\;\;1\\ \mathbf{else}:\\ \;\;\;\;\frac{0.041666666666666664 \cdot \left(x \cdot \left(x \cdot \left(x \cdot x\right)\right)\right)}{x}\\ \end{array} \end{array} \]
(FPCore (x)
 :precision binary64
 (if (<= (/ (+ (exp x) -1.0) x) 2.0)
   1.0
   (/ (* 0.041666666666666664 (* x (* x (* x x)))) x)))
double code(double x) {
	double tmp;
	if (((exp(x) + -1.0) / x) <= 2.0) {
		tmp = 1.0;
	} else {
		tmp = (0.041666666666666664 * (x * (x * (x * x)))) / x;
	}
	return tmp;
}
real(8) function code(x)
    real(8), intent (in) :: x
    real(8) :: tmp
    if (((exp(x) + (-1.0d0)) / x) <= 2.0d0) then
        tmp = 1.0d0
    else
        tmp = (0.041666666666666664d0 * (x * (x * (x * x)))) / x
    end if
    code = tmp
end function
public static double code(double x) {
	double tmp;
	if (((Math.exp(x) + -1.0) / x) <= 2.0) {
		tmp = 1.0;
	} else {
		tmp = (0.041666666666666664 * (x * (x * (x * x)))) / x;
	}
	return tmp;
}
def code(x):
	tmp = 0
	if ((math.exp(x) + -1.0) / x) <= 2.0:
		tmp = 1.0
	else:
		tmp = (0.041666666666666664 * (x * (x * (x * x)))) / x
	return tmp
function code(x)
	tmp = 0.0
	if (Float64(Float64(exp(x) + -1.0) / x) <= 2.0)
		tmp = 1.0;
	else
		tmp = Float64(Float64(0.041666666666666664 * Float64(x * Float64(x * Float64(x * x)))) / x);
	end
	return tmp
end
function tmp_2 = code(x)
	tmp = 0.0;
	if (((exp(x) + -1.0) / x) <= 2.0)
		tmp = 1.0;
	else
		tmp = (0.041666666666666664 * (x * (x * (x * x)))) / x;
	end
	tmp_2 = tmp;
end
code[x_] := If[LessEqual[N[(N[(N[Exp[x], $MachinePrecision] + -1.0), $MachinePrecision] / x), $MachinePrecision], 2.0], 1.0, N[(N[(0.041666666666666664 * N[(x * N[(x * N[(x * x), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] / x), $MachinePrecision]]
\begin{array}{l}

\\
\begin{array}{l}
\mathbf{if}\;\frac{e^{x} + -1}{x} \leq 2:\\
\;\;\;\;1\\

\mathbf{else}:\\
\;\;\;\;\frac{0.041666666666666664 \cdot \left(x \cdot \left(x \cdot \left(x \cdot x\right)\right)\right)}{x}\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if (/.f64 (-.f64 (exp.f64 x) #s(literal 1 binary64)) x) < 2

    1. Initial program 37.5%

      \[\frac{e^{x} - 1}{x} \]
    2. Add Preprocessing
    3. Taylor expanded in x around 0

      \[\leadsto \color{blue}{1} \]
    4. Step-by-step derivation
      1. Applied rewrites67.2%

        \[\leadsto \color{blue}{1} \]

      if 2 < (/.f64 (-.f64 (exp.f64 x) #s(literal 1 binary64)) x)

      1. Initial program 100.0%

        \[\frac{e^{x} - 1}{x} \]
      2. Add Preprocessing
      3. Taylor expanded in x around 0

        \[\leadsto \frac{\color{blue}{x \cdot \left(1 + x \cdot \left(\frac{1}{2} + x \cdot \left(\frac{1}{6} + \frac{1}{24} \cdot x\right)\right)\right)}}{x} \]
      4. Step-by-step derivation
        1. +-commutativeN/A

          \[\leadsto \frac{x \cdot \color{blue}{\left(x \cdot \left(\frac{1}{2} + x \cdot \left(\frac{1}{6} + \frac{1}{24} \cdot x\right)\right) + 1\right)}}{x} \]
        2. distribute-lft-inN/A

          \[\leadsto \frac{\color{blue}{x \cdot \left(x \cdot \left(\frac{1}{2} + x \cdot \left(\frac{1}{6} + \frac{1}{24} \cdot x\right)\right)\right) + x \cdot 1}}{x} \]
        3. *-rgt-identityN/A

          \[\leadsto \frac{x \cdot \left(x \cdot \left(\frac{1}{2} + x \cdot \left(\frac{1}{6} + \frac{1}{24} \cdot x\right)\right)\right) + \color{blue}{x}}{x} \]
        4. lower-fma.f64N/A

          \[\leadsto \frac{\color{blue}{\mathsf{fma}\left(x, x \cdot \left(\frac{1}{2} + x \cdot \left(\frac{1}{6} + \frac{1}{24} \cdot x\right)\right), x\right)}}{x} \]
        5. lower-*.f64N/A

          \[\leadsto \frac{\mathsf{fma}\left(x, \color{blue}{x \cdot \left(\frac{1}{2} + x \cdot \left(\frac{1}{6} + \frac{1}{24} \cdot x\right)\right)}, x\right)}{x} \]
        6. +-commutativeN/A

          \[\leadsto \frac{\mathsf{fma}\left(x, x \cdot \color{blue}{\left(x \cdot \left(\frac{1}{6} + \frac{1}{24} \cdot x\right) + \frac{1}{2}\right)}, x\right)}{x} \]
        7. lower-fma.f64N/A

          \[\leadsto \frac{\mathsf{fma}\left(x, x \cdot \color{blue}{\mathsf{fma}\left(x, \frac{1}{6} + \frac{1}{24} \cdot x, \frac{1}{2}\right)}, x\right)}{x} \]
        8. +-commutativeN/A

          \[\leadsto \frac{\mathsf{fma}\left(x, x \cdot \mathsf{fma}\left(x, \color{blue}{\frac{1}{24} \cdot x + \frac{1}{6}}, \frac{1}{2}\right), x\right)}{x} \]
        9. *-commutativeN/A

          \[\leadsto \frac{\mathsf{fma}\left(x, x \cdot \mathsf{fma}\left(x, \color{blue}{x \cdot \frac{1}{24}} + \frac{1}{6}, \frac{1}{2}\right), x\right)}{x} \]
        10. lower-fma.f6475.2

          \[\leadsto \frac{\mathsf{fma}\left(x, x \cdot \mathsf{fma}\left(x, \color{blue}{\mathsf{fma}\left(x, 0.041666666666666664, 0.16666666666666666\right)}, 0.5\right), x\right)}{x} \]
      5. Applied rewrites75.2%

        \[\leadsto \frac{\color{blue}{\mathsf{fma}\left(x, x \cdot \mathsf{fma}\left(x, \mathsf{fma}\left(x, 0.041666666666666664, 0.16666666666666666\right), 0.5\right), x\right)}}{x} \]
      6. Taylor expanded in x around inf

        \[\leadsto \frac{\frac{1}{24} \cdot \color{blue}{{x}^{4}}}{x} \]
      7. Step-by-step derivation
        1. Applied rewrites75.3%

          \[\leadsto \frac{0.041666666666666664 \cdot \color{blue}{\left(x \cdot \left(x \cdot \left(x \cdot x\right)\right)\right)}}{x} \]
      8. Recombined 2 regimes into one program.
      9. Final simplification69.2%

        \[\leadsto \begin{array}{l} \mathbf{if}\;\frac{e^{x} + -1}{x} \leq 2:\\ \;\;\;\;1\\ \mathbf{else}:\\ \;\;\;\;\frac{0.041666666666666664 \cdot \left(x \cdot \left(x \cdot \left(x \cdot x\right)\right)\right)}{x}\\ \end{array} \]
      10. Add Preprocessing

      Developer Target 1: 52.6% accurate, 0.4× speedup?

      \[\begin{array}{l} \\ \begin{array}{l} t_0 := e^{x} - 1\\ \mathbf{if}\;x < 1 \land x > -1:\\ \;\;\;\;\frac{t\_0}{\log \left(e^{x}\right)}\\ \mathbf{else}:\\ \;\;\;\;\frac{t\_0}{x}\\ \end{array} \end{array} \]
      (FPCore (x)
       :precision binary64
       (let* ((t_0 (- (exp x) 1.0)))
         (if (and (< x 1.0) (> x -1.0)) (/ t_0 (log (exp x))) (/ t_0 x))))
      double code(double x) {
      	double t_0 = exp(x) - 1.0;
      	double tmp;
      	if ((x < 1.0) && (x > -1.0)) {
      		tmp = t_0 / log(exp(x));
      	} else {
      		tmp = t_0 / x;
      	}
      	return tmp;
      }
      
      real(8) function code(x)
          real(8), intent (in) :: x
          real(8) :: t_0
          real(8) :: tmp
          t_0 = exp(x) - 1.0d0
          if ((x < 1.0d0) .and. (x > (-1.0d0))) then
              tmp = t_0 / log(exp(x))
          else
              tmp = t_0 / x
          end if
          code = tmp
      end function
      
      public static double code(double x) {
      	double t_0 = Math.exp(x) - 1.0;
      	double tmp;
      	if ((x < 1.0) && (x > -1.0)) {
      		tmp = t_0 / Math.log(Math.exp(x));
      	} else {
      		tmp = t_0 / x;
      	}
      	return tmp;
      }
      
      def code(x):
      	t_0 = math.exp(x) - 1.0
      	tmp = 0
      	if (x < 1.0) and (x > -1.0):
      		tmp = t_0 / math.log(math.exp(x))
      	else:
      		tmp = t_0 / x
      	return tmp
      
      function code(x)
      	t_0 = Float64(exp(x) - 1.0)
      	tmp = 0.0
      	if ((x < 1.0) && (x > -1.0))
      		tmp = Float64(t_0 / log(exp(x)));
      	else
      		tmp = Float64(t_0 / x);
      	end
      	return tmp
      end
      
      function tmp_2 = code(x)
      	t_0 = exp(x) - 1.0;
      	tmp = 0.0;
      	if ((x < 1.0) && (x > -1.0))
      		tmp = t_0 / log(exp(x));
      	else
      		tmp = t_0 / x;
      	end
      	tmp_2 = tmp;
      end
      
      code[x_] := Block[{t$95$0 = N[(N[Exp[x], $MachinePrecision] - 1.0), $MachinePrecision]}, If[And[Less[x, 1.0], Greater[x, -1.0]], N[(t$95$0 / N[Log[N[Exp[x], $MachinePrecision]], $MachinePrecision]), $MachinePrecision], N[(t$95$0 / x), $MachinePrecision]]]
      
      \begin{array}{l}
      
      \\
      \begin{array}{l}
      t_0 := e^{x} - 1\\
      \mathbf{if}\;x < 1 \land x > -1:\\
      \;\;\;\;\frac{t\_0}{\log \left(e^{x}\right)}\\
      
      \mathbf{else}:\\
      \;\;\;\;\frac{t\_0}{x}\\
      
      
      \end{array}
      \end{array}
      

      Reproduce

      ?
      herbie shell --seed 2024228 
      (FPCore (x)
        :name "Kahan's exp quotient"
        :precision binary64
      
        :alt
        (! :herbie-platform default (if (and (< x 1) (> x -1)) (/ (- (exp x) 1) (log (exp x))) (/ (- (exp x) 1) x)))
      
        (/ (- (exp x) 1.0) x))