Kahan's exp quotient

Percentage Accurate: 53.7% → 100.0%
Time: 9.6s
Alternatives: 14
Speedup: 8.8×

Specification

?
\[\begin{array}{l} \\ \frac{e^{x} - 1}{x} \end{array} \]
(FPCore (x) :precision binary64 (/ (- (exp x) 1.0) x))
double code(double x) {
	return (exp(x) - 1.0) / x;
}
real(8) function code(x)
    real(8), intent (in) :: x
    code = (exp(x) - 1.0d0) / x
end function
public static double code(double x) {
	return (Math.exp(x) - 1.0) / x;
}
def code(x):
	return (math.exp(x) - 1.0) / x
function code(x)
	return Float64(Float64(exp(x) - 1.0) / x)
end
function tmp = code(x)
	tmp = (exp(x) - 1.0) / x;
end
code[x_] := N[(N[(N[Exp[x], $MachinePrecision] - 1.0), $MachinePrecision] / x), $MachinePrecision]
\begin{array}{l}

\\
\frac{e^{x} - 1}{x}
\end{array}

Sampling outcomes in binary64 precision:

Local Percentage Accuracy vs ?

The average percentage accuracy by input value. Horizontal axis shows value of an input variable; the variable is choosen in the title. Vertical axis is accuracy; higher is better. Red represent the original program, while blue represents Herbie's suggestion. These can be toggled with buttons below the plot. The line is an average while dots represent individual samples.

Accuracy vs Speed?

Herbie found 14 alternatives:

AlternativeAccuracySpeedup
The accuracy (vertical axis) and speed (horizontal axis) of each alternatives. Up and to the right is better. The red square shows the initial program, and each blue circle shows an alternative.The line shows the best available speed-accuracy tradeoffs.

Initial Program: 53.7% accurate, 1.0× speedup?

\[\begin{array}{l} \\ \frac{e^{x} - 1}{x} \end{array} \]
(FPCore (x) :precision binary64 (/ (- (exp x) 1.0) x))
double code(double x) {
	return (exp(x) - 1.0) / x;
}
real(8) function code(x)
    real(8), intent (in) :: x
    code = (exp(x) - 1.0d0) / x
end function
public static double code(double x) {
	return (Math.exp(x) - 1.0) / x;
}
def code(x):
	return (math.exp(x) - 1.0) / x
function code(x)
	return Float64(Float64(exp(x) - 1.0) / x)
end
function tmp = code(x)
	tmp = (exp(x) - 1.0) / x;
end
code[x_] := N[(N[(N[Exp[x], $MachinePrecision] - 1.0), $MachinePrecision] / x), $MachinePrecision]
\begin{array}{l}

\\
\frac{e^{x} - 1}{x}
\end{array}

Alternative 1: 100.0% accurate, 1.0× speedup?

\[\begin{array}{l} \\ \frac{\mathsf{expm1}\left(x\right)}{x} \end{array} \]
(FPCore (x) :precision binary64 (/ (expm1 x) x))
double code(double x) {
	return expm1(x) / x;
}
public static double code(double x) {
	return Math.expm1(x) / x;
}
def code(x):
	return math.expm1(x) / x
function code(x)
	return Float64(expm1(x) / x)
end
code[x_] := N[(N[(Exp[x] - 1), $MachinePrecision] / x), $MachinePrecision]
\begin{array}{l}

\\
\frac{\mathsf{expm1}\left(x\right)}{x}
\end{array}
Derivation
  1. Initial program 60.6%

    \[\frac{e^{x} - 1}{x} \]
  2. Add Preprocessing
  3. Step-by-step derivation
    1. lift--.f64N/A

      \[\leadsto \frac{\color{blue}{e^{x} - 1}}{x} \]
    2. lift-exp.f64N/A

      \[\leadsto \frac{\color{blue}{e^{x}} - 1}{x} \]
    3. lower-expm1.f64100.0

      \[\leadsto \frac{\color{blue}{\mathsf{expm1}\left(x\right)}}{x} \]
  4. Applied rewrites100.0%

    \[\leadsto \frac{\color{blue}{\mathsf{expm1}\left(x\right)}}{x} \]
  5. Add Preprocessing

Alternative 2: 70.7% accurate, 0.7× speedup?

\[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;\frac{e^{x} + -1}{x} \leq 2:\\ \;\;\;\;1 + \frac{x}{\mathsf{fma}\left(x, \mathsf{fma}\left(x, 0.05555555555555555, -0.6666666666666666\right), 2\right)}\\ \mathbf{else}:\\ \;\;\;\;\mathsf{fma}\left(x, \mathsf{fma}\left(x, \frac{7.233796296296296 \cdot 10^{-5} \cdot \left(x \cdot \left(x \cdot x\right)\right)}{0.027777777777777776}, 0.5\right), 1\right)\\ \end{array} \end{array} \]
(FPCore (x)
 :precision binary64
 (if (<= (/ (+ (exp x) -1.0) x) 2.0)
   (+ 1.0 (/ x (fma x (fma x 0.05555555555555555 -0.6666666666666666) 2.0)))
   (fma
    x
    (fma x (/ (* 7.233796296296296e-5 (* x (* x x))) 0.027777777777777776) 0.5)
    1.0)))
double code(double x) {
	double tmp;
	if (((exp(x) + -1.0) / x) <= 2.0) {
		tmp = 1.0 + (x / fma(x, fma(x, 0.05555555555555555, -0.6666666666666666), 2.0));
	} else {
		tmp = fma(x, fma(x, ((7.233796296296296e-5 * (x * (x * x))) / 0.027777777777777776), 0.5), 1.0);
	}
	return tmp;
}
function code(x)
	tmp = 0.0
	if (Float64(Float64(exp(x) + -1.0) / x) <= 2.0)
		tmp = Float64(1.0 + Float64(x / fma(x, fma(x, 0.05555555555555555, -0.6666666666666666), 2.0)));
	else
		tmp = fma(x, fma(x, Float64(Float64(7.233796296296296e-5 * Float64(x * Float64(x * x))) / 0.027777777777777776), 0.5), 1.0);
	end
	return tmp
end
code[x_] := If[LessEqual[N[(N[(N[Exp[x], $MachinePrecision] + -1.0), $MachinePrecision] / x), $MachinePrecision], 2.0], N[(1.0 + N[(x / N[(x * N[(x * 0.05555555555555555 + -0.6666666666666666), $MachinePrecision] + 2.0), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], N[(x * N[(x * N[(N[(7.233796296296296e-5 * N[(x * N[(x * x), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] / 0.027777777777777776), $MachinePrecision] + 0.5), $MachinePrecision] + 1.0), $MachinePrecision]]
\begin{array}{l}

\\
\begin{array}{l}
\mathbf{if}\;\frac{e^{x} + -1}{x} \leq 2:\\
\;\;\;\;1 + \frac{x}{\mathsf{fma}\left(x, \mathsf{fma}\left(x, 0.05555555555555555, -0.6666666666666666\right), 2\right)}\\

\mathbf{else}:\\
\;\;\;\;\mathsf{fma}\left(x, \mathsf{fma}\left(x, \frac{7.233796296296296 \cdot 10^{-5} \cdot \left(x \cdot \left(x \cdot x\right)\right)}{0.027777777777777776}, 0.5\right), 1\right)\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if (/.f64 (-.f64 (exp.f64 x) #s(literal 1 binary64)) x) < 2

    1. Initial program 38.3%

      \[\frac{e^{x} - 1}{x} \]
    2. Add Preprocessing
    3. Taylor expanded in x around 0

      \[\leadsto \color{blue}{1 + x \cdot \left(\frac{1}{2} + x \cdot \left(\frac{1}{6} + \frac{1}{24} \cdot x\right)\right)} \]
    4. Step-by-step derivation
      1. +-commutativeN/A

        \[\leadsto \color{blue}{x \cdot \left(\frac{1}{2} + x \cdot \left(\frac{1}{6} + \frac{1}{24} \cdot x\right)\right) + 1} \]
      2. lower-fma.f64N/A

        \[\leadsto \color{blue}{\mathsf{fma}\left(x, \frac{1}{2} + x \cdot \left(\frac{1}{6} + \frac{1}{24} \cdot x\right), 1\right)} \]
      3. +-commutativeN/A

        \[\leadsto \mathsf{fma}\left(x, \color{blue}{x \cdot \left(\frac{1}{6} + \frac{1}{24} \cdot x\right) + \frac{1}{2}}, 1\right) \]
      4. lower-fma.f64N/A

        \[\leadsto \mathsf{fma}\left(x, \color{blue}{\mathsf{fma}\left(x, \frac{1}{6} + \frac{1}{24} \cdot x, \frac{1}{2}\right)}, 1\right) \]
      5. +-commutativeN/A

        \[\leadsto \mathsf{fma}\left(x, \mathsf{fma}\left(x, \color{blue}{\frac{1}{24} \cdot x + \frac{1}{6}}, \frac{1}{2}\right), 1\right) \]
      6. *-commutativeN/A

        \[\leadsto \mathsf{fma}\left(x, \mathsf{fma}\left(x, \color{blue}{x \cdot \frac{1}{24}} + \frac{1}{6}, \frac{1}{2}\right), 1\right) \]
      7. lower-fma.f6465.9

        \[\leadsto \mathsf{fma}\left(x, \mathsf{fma}\left(x, \color{blue}{\mathsf{fma}\left(x, 0.041666666666666664, 0.16666666666666666\right)}, 0.5\right), 1\right) \]
    5. Applied rewrites65.9%

      \[\leadsto \color{blue}{\mathsf{fma}\left(x, \mathsf{fma}\left(x, \mathsf{fma}\left(x, 0.041666666666666664, 0.16666666666666666\right), 0.5\right), 1\right)} \]
    6. Step-by-step derivation
      1. Applied rewrites65.9%

        \[\leadsto \mathsf{fma}\left(x, \frac{1}{\color{blue}{\frac{1}{\mathsf{fma}\left(x, \mathsf{fma}\left(x, 0.041666666666666664, 0.16666666666666666\right), 0.5\right)}}}, 1\right) \]
      2. Taylor expanded in x around 0

        \[\leadsto \mathsf{fma}\left(x, \frac{1}{2 + \color{blue}{x \cdot \left(\frac{1}{18} \cdot x - \frac{2}{3}\right)}}, 1\right) \]
      3. Step-by-step derivation
        1. Applied rewrites67.3%

          \[\leadsto \mathsf{fma}\left(x, \frac{1}{\mathsf{fma}\left(x, \color{blue}{\mathsf{fma}\left(x, 0.05555555555555555, -0.6666666666666666\right)}, 2\right)}, 1\right) \]
        2. Step-by-step derivation
          1. Applied rewrites67.3%

            \[\leadsto \frac{x}{\mathsf{fma}\left(x, \mathsf{fma}\left(x, 0.05555555555555555, -0.6666666666666666\right), 2\right)} + \color{blue}{1} \]

          if 2 < (/.f64 (-.f64 (exp.f64 x) #s(literal 1 binary64)) x)

          1. Initial program 100.0%

            \[\frac{e^{x} - 1}{x} \]
          2. Add Preprocessing
          3. Taylor expanded in x around 0

            \[\leadsto \color{blue}{1 + x \cdot \left(\frac{1}{2} + x \cdot \left(\frac{1}{6} + \frac{1}{24} \cdot x\right)\right)} \]
          4. Step-by-step derivation
            1. +-commutativeN/A

              \[\leadsto \color{blue}{x \cdot \left(\frac{1}{2} + x \cdot \left(\frac{1}{6} + \frac{1}{24} \cdot x\right)\right) + 1} \]
            2. lower-fma.f64N/A

              \[\leadsto \color{blue}{\mathsf{fma}\left(x, \frac{1}{2} + x \cdot \left(\frac{1}{6} + \frac{1}{24} \cdot x\right), 1\right)} \]
            3. +-commutativeN/A

              \[\leadsto \mathsf{fma}\left(x, \color{blue}{x \cdot \left(\frac{1}{6} + \frac{1}{24} \cdot x\right) + \frac{1}{2}}, 1\right) \]
            4. lower-fma.f64N/A

              \[\leadsto \mathsf{fma}\left(x, \color{blue}{\mathsf{fma}\left(x, \frac{1}{6} + \frac{1}{24} \cdot x, \frac{1}{2}\right)}, 1\right) \]
            5. +-commutativeN/A

              \[\leadsto \mathsf{fma}\left(x, \mathsf{fma}\left(x, \color{blue}{\frac{1}{24} \cdot x + \frac{1}{6}}, \frac{1}{2}\right), 1\right) \]
            6. *-commutativeN/A

              \[\leadsto \mathsf{fma}\left(x, \mathsf{fma}\left(x, \color{blue}{x \cdot \frac{1}{24}} + \frac{1}{6}, \frac{1}{2}\right), 1\right) \]
            7. lower-fma.f6467.4

              \[\leadsto \mathsf{fma}\left(x, \mathsf{fma}\left(x, \color{blue}{\mathsf{fma}\left(x, 0.041666666666666664, 0.16666666666666666\right)}, 0.5\right), 1\right) \]
          5. Applied rewrites67.4%

            \[\leadsto \color{blue}{\mathsf{fma}\left(x, \mathsf{fma}\left(x, \mathsf{fma}\left(x, 0.041666666666666664, 0.16666666666666666\right), 0.5\right), 1\right)} \]
          6. Step-by-step derivation
            1. Applied rewrites18.9%

              \[\leadsto \mathsf{fma}\left(x, \mathsf{fma}\left(x, \frac{\mathsf{fma}\left(x \cdot \left(x \cdot x\right), 7.233796296296296 \cdot 10^{-5}, 0.004629629629629629\right)}{\color{blue}{0.027777777777777776 + \mathsf{fma}\left(x, -0.006944444444444444, \left(x \cdot x\right) \cdot 0.001736111111111111\right)}}, 0.5\right), 1\right) \]
            2. Taylor expanded in x around 0

              \[\leadsto \mathsf{fma}\left(x, \mathsf{fma}\left(x, \frac{\mathsf{fma}\left(x \cdot \left(x \cdot x\right), \frac{1}{13824}, \frac{1}{216}\right)}{\frac{1}{36}}, \frac{1}{2}\right), 1\right) \]
            3. Step-by-step derivation
              1. Applied rewrites80.9%

                \[\leadsto \mathsf{fma}\left(x, \mathsf{fma}\left(x, \frac{\mathsf{fma}\left(x \cdot \left(x \cdot x\right), 7.233796296296296 \cdot 10^{-5}, 0.004629629629629629\right)}{0.027777777777777776}, 0.5\right), 1\right) \]
              2. Taylor expanded in x around inf

                \[\leadsto \mathsf{fma}\left(x, \mathsf{fma}\left(x, \frac{\frac{1}{13824} \cdot {x}^{3}}{\frac{1}{36}}, \frac{1}{2}\right), 1\right) \]
              3. Step-by-step derivation
                1. Applied rewrites80.9%

                  \[\leadsto \mathsf{fma}\left(x, \mathsf{fma}\left(x, \frac{\left(x \cdot \left(x \cdot x\right)\right) \cdot 7.233796296296296 \cdot 10^{-5}}{0.027777777777777776}, 0.5\right), 1\right) \]
              4. Recombined 2 regimes into one program.
              5. Final simplification70.7%

                \[\leadsto \begin{array}{l} \mathbf{if}\;\frac{e^{x} + -1}{x} \leq 2:\\ \;\;\;\;1 + \frac{x}{\mathsf{fma}\left(x, \mathsf{fma}\left(x, 0.05555555555555555, -0.6666666666666666\right), 2\right)}\\ \mathbf{else}:\\ \;\;\;\;\mathsf{fma}\left(x, \mathsf{fma}\left(x, \frac{7.233796296296296 \cdot 10^{-5} \cdot \left(x \cdot \left(x \cdot x\right)\right)}{0.027777777777777776}, 0.5\right), 1\right)\\ \end{array} \]
              6. Add Preprocessing

              Developer Target 1: 53.2% accurate, 0.4× speedup?

              \[\begin{array}{l} \\ \begin{array}{l} t_0 := e^{x} - 1\\ \mathbf{if}\;x < 1 \land x > -1:\\ \;\;\;\;\frac{t\_0}{\log \left(e^{x}\right)}\\ \mathbf{else}:\\ \;\;\;\;\frac{t\_0}{x}\\ \end{array} \end{array} \]
              (FPCore (x)
               :precision binary64
               (let* ((t_0 (- (exp x) 1.0)))
                 (if (and (< x 1.0) (> x -1.0)) (/ t_0 (log (exp x))) (/ t_0 x))))
              double code(double x) {
              	double t_0 = exp(x) - 1.0;
              	double tmp;
              	if ((x < 1.0) && (x > -1.0)) {
              		tmp = t_0 / log(exp(x));
              	} else {
              		tmp = t_0 / x;
              	}
              	return tmp;
              }
              
              real(8) function code(x)
                  real(8), intent (in) :: x
                  real(8) :: t_0
                  real(8) :: tmp
                  t_0 = exp(x) - 1.0d0
                  if ((x < 1.0d0) .and. (x > (-1.0d0))) then
                      tmp = t_0 / log(exp(x))
                  else
                      tmp = t_0 / x
                  end if
                  code = tmp
              end function
              
              public static double code(double x) {
              	double t_0 = Math.exp(x) - 1.0;
              	double tmp;
              	if ((x < 1.0) && (x > -1.0)) {
              		tmp = t_0 / Math.log(Math.exp(x));
              	} else {
              		tmp = t_0 / x;
              	}
              	return tmp;
              }
              
              def code(x):
              	t_0 = math.exp(x) - 1.0
              	tmp = 0
              	if (x < 1.0) and (x > -1.0):
              		tmp = t_0 / math.log(math.exp(x))
              	else:
              		tmp = t_0 / x
              	return tmp
              
              function code(x)
              	t_0 = Float64(exp(x) - 1.0)
              	tmp = 0.0
              	if ((x < 1.0) && (x > -1.0))
              		tmp = Float64(t_0 / log(exp(x)));
              	else
              		tmp = Float64(t_0 / x);
              	end
              	return tmp
              end
              
              function tmp_2 = code(x)
              	t_0 = exp(x) - 1.0;
              	tmp = 0.0;
              	if ((x < 1.0) && (x > -1.0))
              		tmp = t_0 / log(exp(x));
              	else
              		tmp = t_0 / x;
              	end
              	tmp_2 = tmp;
              end
              
              code[x_] := Block[{t$95$0 = N[(N[Exp[x], $MachinePrecision] - 1.0), $MachinePrecision]}, If[And[Less[x, 1.0], Greater[x, -1.0]], N[(t$95$0 / N[Log[N[Exp[x], $MachinePrecision]], $MachinePrecision]), $MachinePrecision], N[(t$95$0 / x), $MachinePrecision]]]
              
              \begin{array}{l}
              
              \\
              \begin{array}{l}
              t_0 := e^{x} - 1\\
              \mathbf{if}\;x < 1 \land x > -1:\\
              \;\;\;\;\frac{t\_0}{\log \left(e^{x}\right)}\\
              
              \mathbf{else}:\\
              \;\;\;\;\frac{t\_0}{x}\\
              
              
              \end{array}
              \end{array}
              

              Reproduce

              ?
              herbie shell --seed 2024227 
              (FPCore (x)
                :name "Kahan's exp quotient"
                :precision binary64
              
                :alt
                (! :herbie-platform default (if (and (< x 1) (> x -1)) (/ (- (exp x) 1) (log (exp x))) (/ (- (exp x) 1) x)))
              
                (/ (- (exp x) 1.0) x))