expax (section 3.5)

Percentage Accurate: 54.0% → 100.0%
Time: 8.1s
Alternatives: 5
Speedup: 18.2×

Specification

?
\[710 > a \cdot x\]
\[\begin{array}{l} \\ e^{a \cdot x} - 1 \end{array} \]
(FPCore (a x) :precision binary64 (- (exp (* a x)) 1.0))
double code(double a, double x) {
	return exp((a * x)) - 1.0;
}
real(8) function code(a, x)
    real(8), intent (in) :: a
    real(8), intent (in) :: x
    code = exp((a * x)) - 1.0d0
end function
public static double code(double a, double x) {
	return Math.exp((a * x)) - 1.0;
}
def code(a, x):
	return math.exp((a * x)) - 1.0
function code(a, x)
	return Float64(exp(Float64(a * x)) - 1.0)
end
function tmp = code(a, x)
	tmp = exp((a * x)) - 1.0;
end
code[a_, x_] := N[(N[Exp[N[(a * x), $MachinePrecision]], $MachinePrecision] - 1.0), $MachinePrecision]
\begin{array}{l}

\\
e^{a \cdot x} - 1
\end{array}

Sampling outcomes in binary64 precision:

Local Percentage Accuracy vs ?

The average percentage accuracy by input value. Horizontal axis shows value of an input variable; the variable is choosen in the title. Vertical axis is accuracy; higher is better. Red represent the original program, while blue represents Herbie's suggestion. These can be toggled with buttons below the plot. The line is an average while dots represent individual samples.

Accuracy vs Speed?

Herbie found 5 alternatives:

AlternativeAccuracySpeedup
The accuracy (vertical axis) and speed (horizontal axis) of each alternatives. Up and to the right is better. The red square shows the initial program, and each blue circle shows an alternative.The line shows the best available speed-accuracy tradeoffs.

Initial Program: 54.0% accurate, 1.0× speedup?

\[\begin{array}{l} \\ e^{a \cdot x} - 1 \end{array} \]
(FPCore (a x) :precision binary64 (- (exp (* a x)) 1.0))
double code(double a, double x) {
	return exp((a * x)) - 1.0;
}
real(8) function code(a, x)
    real(8), intent (in) :: a
    real(8), intent (in) :: x
    code = exp((a * x)) - 1.0d0
end function
public static double code(double a, double x) {
	return Math.exp((a * x)) - 1.0;
}
def code(a, x):
	return math.exp((a * x)) - 1.0
function code(a, x)
	return Float64(exp(Float64(a * x)) - 1.0)
end
function tmp = code(a, x)
	tmp = exp((a * x)) - 1.0;
end
code[a_, x_] := N[(N[Exp[N[(a * x), $MachinePrecision]], $MachinePrecision] - 1.0), $MachinePrecision]
\begin{array}{l}

\\
e^{a \cdot x} - 1
\end{array}

Alternative 1: 100.0% accurate, 1.0× speedup?

\[\begin{array}{l} \\ \mathsf{expm1}\left(a \cdot x\right) \end{array} \]
(FPCore (a x) :precision binary64 (expm1 (* a x)))
double code(double a, double x) {
	return expm1((a * x));
}
public static double code(double a, double x) {
	return Math.expm1((a * x));
}
def code(a, x):
	return math.expm1((a * x))
function code(a, x)
	return expm1(Float64(a * x))
end
code[a_, x_] := N[(Exp[N[(a * x), $MachinePrecision]] - 1), $MachinePrecision]
\begin{array}{l}

\\
\mathsf{expm1}\left(a \cdot x\right)
\end{array}
Derivation
  1. Initial program 53.0%

    \[e^{a \cdot x} - 1 \]
  2. Add Preprocessing
  3. Step-by-step derivation
    1. lift--.f64N/A

      \[\leadsto \color{blue}{e^{a \cdot x} - 1} \]
    2. lift-exp.f64N/A

      \[\leadsto \color{blue}{e^{a \cdot x}} - 1 \]
    3. lower-expm1.f64100.0

      \[\leadsto \color{blue}{\mathsf{expm1}\left(a \cdot x\right)} \]
  4. Applied rewrites100.0%

    \[\leadsto \color{blue}{\mathsf{expm1}\left(a \cdot x\right)} \]
  5. Add Preprocessing

Alternative 2: 67.4% accurate, 3.3× speedup?

\[\begin{array}{l} \\ \left(a \cdot x\right) \cdot \mathsf{fma}\left(a \cdot x, \mathsf{fma}\left(a, x \cdot 0.16666666666666666, 0.5\right), 1\right) \end{array} \]
(FPCore (a x)
 :precision binary64
 (* (* a x) (fma (* a x) (fma a (* x 0.16666666666666666) 0.5) 1.0)))
double code(double a, double x) {
	return (a * x) * fma((a * x), fma(a, (x * 0.16666666666666666), 0.5), 1.0);
}
function code(a, x)
	return Float64(Float64(a * x) * fma(Float64(a * x), fma(a, Float64(x * 0.16666666666666666), 0.5), 1.0))
end
code[a_, x_] := N[(N[(a * x), $MachinePrecision] * N[(N[(a * x), $MachinePrecision] * N[(a * N[(x * 0.16666666666666666), $MachinePrecision] + 0.5), $MachinePrecision] + 1.0), $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
\left(a \cdot x\right) \cdot \mathsf{fma}\left(a \cdot x, \mathsf{fma}\left(a, x \cdot 0.16666666666666666, 0.5\right), 1\right)
\end{array}
Derivation
  1. Initial program 53.0%

    \[e^{a \cdot x} - 1 \]
  2. Add Preprocessing
  3. Taylor expanded in a around 0

    \[\leadsto \color{blue}{a \cdot \left(x + a \cdot \left(\frac{1}{2} \cdot {x}^{2} + a \cdot \left(\frac{1}{24} \cdot \left(a \cdot {x}^{4}\right) + \frac{1}{6} \cdot {x}^{3}\right)\right)\right)} \]
  4. Applied rewrites62.0%

    \[\leadsto \color{blue}{a \cdot \mathsf{fma}\left(a, x \cdot \left(x \cdot \mathsf{fma}\left(a \cdot x, \mathsf{fma}\left(a, x \cdot 0.041666666666666664, 0.16666666666666666\right), 0.5\right)\right), x\right)} \]
  5. Step-by-step derivation
    1. Applied rewrites68.3%

      \[\leadsto a \cdot \mathsf{fma}\left(\left(a \cdot x\right) \cdot \mathsf{fma}\left(a, x \cdot \mathsf{fma}\left(a \cdot x, 0.041666666666666664, 0.16666666666666666\right), 0.5\right), \color{blue}{x}, x\right) \]
    2. Taylor expanded in a around 0

      \[\leadsto a \cdot \mathsf{fma}\left(\left(a \cdot x\right) \cdot \left(\frac{1}{2} + \frac{1}{6} \cdot \left(a \cdot x\right)\right), x, x\right) \]
    3. Step-by-step derivation
      1. Applied rewrites69.1%

        \[\leadsto a \cdot \mathsf{fma}\left(\left(a \cdot x\right) \cdot \mathsf{fma}\left(a, x \cdot 0.16666666666666666, 0.5\right), x, x\right) \]
      2. Step-by-step derivation
        1. Applied rewrites69.2%

          \[\leadsto \mathsf{fma}\left(a \cdot x, \mathsf{fma}\left(a, x \cdot 0.16666666666666666, 0.5\right), 1\right) \cdot \color{blue}{\left(a \cdot x\right)} \]
        2. Final simplification69.2%

          \[\leadsto \left(a \cdot x\right) \cdot \mathsf{fma}\left(a \cdot x, \mathsf{fma}\left(a, x \cdot 0.16666666666666666, 0.5\right), 1\right) \]
        3. Add Preprocessing

        Alternative 3: 67.4% accurate, 3.3× speedup?

        \[\begin{array}{l} \\ a \cdot \mathsf{fma}\left(\left(a \cdot x\right) \cdot \mathsf{fma}\left(a, x \cdot 0.16666666666666666, 0.5\right), x, x\right) \end{array} \]
        (FPCore (a x)
         :precision binary64
         (* a (fma (* (* a x) (fma a (* x 0.16666666666666666) 0.5)) x x)))
        double code(double a, double x) {
        	return a * fma(((a * x) * fma(a, (x * 0.16666666666666666), 0.5)), x, x);
        }
        
        function code(a, x)
        	return Float64(a * fma(Float64(Float64(a * x) * fma(a, Float64(x * 0.16666666666666666), 0.5)), x, x))
        end
        
        code[a_, x_] := N[(a * N[(N[(N[(a * x), $MachinePrecision] * N[(a * N[(x * 0.16666666666666666), $MachinePrecision] + 0.5), $MachinePrecision]), $MachinePrecision] * x + x), $MachinePrecision]), $MachinePrecision]
        
        \begin{array}{l}
        
        \\
        a \cdot \mathsf{fma}\left(\left(a \cdot x\right) \cdot \mathsf{fma}\left(a, x \cdot 0.16666666666666666, 0.5\right), x, x\right)
        \end{array}
        
        Derivation
        1. Initial program 53.0%

          \[e^{a \cdot x} - 1 \]
        2. Add Preprocessing
        3. Taylor expanded in a around 0

          \[\leadsto \color{blue}{a \cdot \left(x + a \cdot \left(\frac{1}{2} \cdot {x}^{2} + a \cdot \left(\frac{1}{24} \cdot \left(a \cdot {x}^{4}\right) + \frac{1}{6} \cdot {x}^{3}\right)\right)\right)} \]
        4. Applied rewrites62.0%

          \[\leadsto \color{blue}{a \cdot \mathsf{fma}\left(a, x \cdot \left(x \cdot \mathsf{fma}\left(a \cdot x, \mathsf{fma}\left(a, x \cdot 0.041666666666666664, 0.16666666666666666\right), 0.5\right)\right), x\right)} \]
        5. Step-by-step derivation
          1. Applied rewrites68.3%

            \[\leadsto a \cdot \mathsf{fma}\left(\left(a \cdot x\right) \cdot \mathsf{fma}\left(a, x \cdot \mathsf{fma}\left(a \cdot x, 0.041666666666666664, 0.16666666666666666\right), 0.5\right), \color{blue}{x}, x\right) \]
          2. Taylor expanded in a around 0

            \[\leadsto a \cdot \mathsf{fma}\left(\left(a \cdot x\right) \cdot \left(\frac{1}{2} + \frac{1}{6} \cdot \left(a \cdot x\right)\right), x, x\right) \]
          3. Step-by-step derivation
            1. Applied rewrites69.1%

              \[\leadsto a \cdot \mathsf{fma}\left(\left(a \cdot x\right) \cdot \mathsf{fma}\left(a, x \cdot 0.16666666666666666, 0.5\right), x, x\right) \]
            2. Add Preprocessing

            Alternative 4: 66.7% accurate, 18.2× speedup?

            \[\begin{array}{l} \\ a \cdot x \end{array} \]
            (FPCore (a x) :precision binary64 (* a x))
            double code(double a, double x) {
            	return a * x;
            }
            
            real(8) function code(a, x)
                real(8), intent (in) :: a
                real(8), intent (in) :: x
                code = a * x
            end function
            
            public static double code(double a, double x) {
            	return a * x;
            }
            
            def code(a, x):
            	return a * x
            
            function code(a, x)
            	return Float64(a * x)
            end
            
            function tmp = code(a, x)
            	tmp = a * x;
            end
            
            code[a_, x_] := N[(a * x), $MachinePrecision]
            
            \begin{array}{l}
            
            \\
            a \cdot x
            \end{array}
            
            Derivation
            1. Initial program 53.0%

              \[e^{a \cdot x} - 1 \]
            2. Add Preprocessing
            3. Taylor expanded in a around 0

              \[\leadsto \color{blue}{a \cdot x} \]
            4. Step-by-step derivation
              1. lower-*.f6468.9

                \[\leadsto \color{blue}{a \cdot x} \]
            5. Applied rewrites68.9%

              \[\leadsto \color{blue}{a \cdot x} \]
            6. Add Preprocessing

            Alternative 5: 19.3% accurate, 27.3× speedup?

            \[\begin{array}{l} \\ 1 + -1 \end{array} \]
            (FPCore (a x) :precision binary64 (+ 1.0 -1.0))
            double code(double a, double x) {
            	return 1.0 + -1.0;
            }
            
            real(8) function code(a, x)
                real(8), intent (in) :: a
                real(8), intent (in) :: x
                code = 1.0d0 + (-1.0d0)
            end function
            
            public static double code(double a, double x) {
            	return 1.0 + -1.0;
            }
            
            def code(a, x):
            	return 1.0 + -1.0
            
            function code(a, x)
            	return Float64(1.0 + -1.0)
            end
            
            function tmp = code(a, x)
            	tmp = 1.0 + -1.0;
            end
            
            code[a_, x_] := N[(1.0 + -1.0), $MachinePrecision]
            
            \begin{array}{l}
            
            \\
            1 + -1
            \end{array}
            
            Derivation
            1. Initial program 53.0%

              \[e^{a \cdot x} - 1 \]
            2. Add Preprocessing
            3. Taylor expanded in a around 0

              \[\leadsto \color{blue}{1} - 1 \]
            4. Step-by-step derivation
              1. Applied rewrites20.5%

                \[\leadsto \color{blue}{1} - 1 \]
              2. Final simplification20.5%

                \[\leadsto 1 + -1 \]
              3. Add Preprocessing

              Developer Target 1: 100.0% accurate, 1.0× speedup?

              \[\begin{array}{l} \\ \mathsf{expm1}\left(a \cdot x\right) \end{array} \]
              (FPCore (a x) :precision binary64 (expm1 (* a x)))
              double code(double a, double x) {
              	return expm1((a * x));
              }
              
              public static double code(double a, double x) {
              	return Math.expm1((a * x));
              }
              
              def code(a, x):
              	return math.expm1((a * x))
              
              function code(a, x)
              	return expm1(Float64(a * x))
              end
              
              code[a_, x_] := N[(Exp[N[(a * x), $MachinePrecision]] - 1), $MachinePrecision]
              
              \begin{array}{l}
              
              \\
              \mathsf{expm1}\left(a \cdot x\right)
              \end{array}
              

              Reproduce

              ?
              herbie shell --seed 2024227 
              (FPCore (a x)
                :name "expax (section 3.5)"
                :precision binary64
                :pre (> 710.0 (* a x))
              
                :alt
                (! :herbie-platform default (expm1 (* a x)))
              
                (- (exp (* a x)) 1.0))