ABCF->ab-angle a

Percentage Accurate: 18.7% → 62.1%
Time: 19.9s
Alternatives: 22
Speedup: 16.9×

Specification

?
\[\begin{array}{l} \\ \begin{array}{l} t_0 := {B}^{2} - \left(4 \cdot A\right) \cdot C\\ \frac{-\sqrt{\left(2 \cdot \left(t\_0 \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{t\_0} \end{array} \end{array} \]
(FPCore (A B C F)
 :precision binary64
 (let* ((t_0 (- (pow B 2.0) (* (* 4.0 A) C))))
   (/
    (-
     (sqrt
      (*
       (* 2.0 (* t_0 F))
       (+ (+ A C) (sqrt (+ (pow (- A C) 2.0) (pow B 2.0)))))))
    t_0)))
double code(double A, double B, double C, double F) {
	double t_0 = pow(B, 2.0) - ((4.0 * A) * C);
	return -sqrt(((2.0 * (t_0 * F)) * ((A + C) + sqrt((pow((A - C), 2.0) + pow(B, 2.0)))))) / t_0;
}
real(8) function code(a, b, c, f)
    real(8), intent (in) :: a
    real(8), intent (in) :: b
    real(8), intent (in) :: c
    real(8), intent (in) :: f
    real(8) :: t_0
    t_0 = (b ** 2.0d0) - ((4.0d0 * a) * c)
    code = -sqrt(((2.0d0 * (t_0 * f)) * ((a + c) + sqrt((((a - c) ** 2.0d0) + (b ** 2.0d0)))))) / t_0
end function
public static double code(double A, double B, double C, double F) {
	double t_0 = Math.pow(B, 2.0) - ((4.0 * A) * C);
	return -Math.sqrt(((2.0 * (t_0 * F)) * ((A + C) + Math.sqrt((Math.pow((A - C), 2.0) + Math.pow(B, 2.0)))))) / t_0;
}
def code(A, B, C, F):
	t_0 = math.pow(B, 2.0) - ((4.0 * A) * C)
	return -math.sqrt(((2.0 * (t_0 * F)) * ((A + C) + math.sqrt((math.pow((A - C), 2.0) + math.pow(B, 2.0)))))) / t_0
function code(A, B, C, F)
	t_0 = Float64((B ^ 2.0) - Float64(Float64(4.0 * A) * C))
	return Float64(Float64(-sqrt(Float64(Float64(2.0 * Float64(t_0 * F)) * Float64(Float64(A + C) + sqrt(Float64((Float64(A - C) ^ 2.0) + (B ^ 2.0))))))) / t_0)
end
function tmp = code(A, B, C, F)
	t_0 = (B ^ 2.0) - ((4.0 * A) * C);
	tmp = -sqrt(((2.0 * (t_0 * F)) * ((A + C) + sqrt((((A - C) ^ 2.0) + (B ^ 2.0)))))) / t_0;
end
code[A_, B_, C_, F_] := Block[{t$95$0 = N[(N[Power[B, 2.0], $MachinePrecision] - N[(N[(4.0 * A), $MachinePrecision] * C), $MachinePrecision]), $MachinePrecision]}, N[((-N[Sqrt[N[(N[(2.0 * N[(t$95$0 * F), $MachinePrecision]), $MachinePrecision] * N[(N[(A + C), $MachinePrecision] + N[Sqrt[N[(N[Power[N[(A - C), $MachinePrecision], 2.0], $MachinePrecision] + N[Power[B, 2.0], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]) / t$95$0), $MachinePrecision]]
\begin{array}{l}

\\
\begin{array}{l}
t_0 := {B}^{2} - \left(4 \cdot A\right) \cdot C\\
\frac{-\sqrt{\left(2 \cdot \left(t\_0 \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{t\_0}
\end{array}
\end{array}

Sampling outcomes in binary64 precision:

Local Percentage Accuracy vs ?

The average percentage accuracy by input value. Horizontal axis shows value of an input variable; the variable is choosen in the title. Vertical axis is accuracy; higher is better. Red represent the original program, while blue represents Herbie's suggestion. These can be toggled with buttons below the plot. The line is an average while dots represent individual samples.

Accuracy vs Speed?

Herbie found 22 alternatives:

AlternativeAccuracySpeedup
The accuracy (vertical axis) and speed (horizontal axis) of each alternatives. Up and to the right is better. The red square shows the initial program, and each blue circle shows an alternative.The line shows the best available speed-accuracy tradeoffs.

Initial Program: 18.7% accurate, 1.0× speedup?

\[\begin{array}{l} \\ \begin{array}{l} t_0 := {B}^{2} - \left(4 \cdot A\right) \cdot C\\ \frac{-\sqrt{\left(2 \cdot \left(t\_0 \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{t\_0} \end{array} \end{array} \]
(FPCore (A B C F)
 :precision binary64
 (let* ((t_0 (- (pow B 2.0) (* (* 4.0 A) C))))
   (/
    (-
     (sqrt
      (*
       (* 2.0 (* t_0 F))
       (+ (+ A C) (sqrt (+ (pow (- A C) 2.0) (pow B 2.0)))))))
    t_0)))
double code(double A, double B, double C, double F) {
	double t_0 = pow(B, 2.0) - ((4.0 * A) * C);
	return -sqrt(((2.0 * (t_0 * F)) * ((A + C) + sqrt((pow((A - C), 2.0) + pow(B, 2.0)))))) / t_0;
}
real(8) function code(a, b, c, f)
    real(8), intent (in) :: a
    real(8), intent (in) :: b
    real(8), intent (in) :: c
    real(8), intent (in) :: f
    real(8) :: t_0
    t_0 = (b ** 2.0d0) - ((4.0d0 * a) * c)
    code = -sqrt(((2.0d0 * (t_0 * f)) * ((a + c) + sqrt((((a - c) ** 2.0d0) + (b ** 2.0d0)))))) / t_0
end function
public static double code(double A, double B, double C, double F) {
	double t_0 = Math.pow(B, 2.0) - ((4.0 * A) * C);
	return -Math.sqrt(((2.0 * (t_0 * F)) * ((A + C) + Math.sqrt((Math.pow((A - C), 2.0) + Math.pow(B, 2.0)))))) / t_0;
}
def code(A, B, C, F):
	t_0 = math.pow(B, 2.0) - ((4.0 * A) * C)
	return -math.sqrt(((2.0 * (t_0 * F)) * ((A + C) + math.sqrt((math.pow((A - C), 2.0) + math.pow(B, 2.0)))))) / t_0
function code(A, B, C, F)
	t_0 = Float64((B ^ 2.0) - Float64(Float64(4.0 * A) * C))
	return Float64(Float64(-sqrt(Float64(Float64(2.0 * Float64(t_0 * F)) * Float64(Float64(A + C) + sqrt(Float64((Float64(A - C) ^ 2.0) + (B ^ 2.0))))))) / t_0)
end
function tmp = code(A, B, C, F)
	t_0 = (B ^ 2.0) - ((4.0 * A) * C);
	tmp = -sqrt(((2.0 * (t_0 * F)) * ((A + C) + sqrt((((A - C) ^ 2.0) + (B ^ 2.0)))))) / t_0;
end
code[A_, B_, C_, F_] := Block[{t$95$0 = N[(N[Power[B, 2.0], $MachinePrecision] - N[(N[(4.0 * A), $MachinePrecision] * C), $MachinePrecision]), $MachinePrecision]}, N[((-N[Sqrt[N[(N[(2.0 * N[(t$95$0 * F), $MachinePrecision]), $MachinePrecision] * N[(N[(A + C), $MachinePrecision] + N[Sqrt[N[(N[Power[N[(A - C), $MachinePrecision], 2.0], $MachinePrecision] + N[Power[B, 2.0], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]) / t$95$0), $MachinePrecision]]
\begin{array}{l}

\\
\begin{array}{l}
t_0 := {B}^{2} - \left(4 \cdot A\right) \cdot C\\
\frac{-\sqrt{\left(2 \cdot \left(t\_0 \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{t\_0}
\end{array}
\end{array}

Alternative 1: 62.1% accurate, 0.2× speedup?

\[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} t_0 := \mathsf{fma}\left(B\_m, B\_m, -4 \cdot \left(A \cdot C\right)\right)\\ t_1 := \mathsf{fma}\left(2, C, \frac{\left(B\_m \cdot B\_m\right) \cdot -0.5}{A}\right)\\ t_2 := \left(4 \cdot A\right) \cdot C\\ t_3 := t\_2 - {B\_m}^{2}\\ t_4 := \frac{\sqrt{\left(2 \cdot \left(\left({B\_m}^{2} - t\_2\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{B\_m}^{2} + {\left(A - C\right)}^{2}}\right)}}{t\_3}\\ \mathbf{if}\;t\_4 \leq -5 \cdot 10^{+235}:\\ \;\;\;\;\frac{\sqrt{2 \cdot C} \cdot \left(\sqrt{2 \cdot \mathsf{fma}\left(C, A \cdot -4, B\_m \cdot B\_m\right)} \cdot \sqrt{F}\right)}{t\_3}\\ \mathbf{elif}\;t\_4 \leq -1 \cdot 10^{-220}:\\ \;\;\;\;\frac{\sqrt{t\_0 \cdot \left(2 \cdot F\right)}}{-1} \cdot \frac{\sqrt{\left(A + C\right) + \sqrt{\mathsf{fma}\left(A - C, A - C, B\_m \cdot B\_m\right)}}}{t\_0}\\ \mathbf{elif}\;t\_4 \leq 0:\\ \;\;\;\;\frac{\sqrt{F} \cdot \sqrt{t\_1 \cdot \mathsf{fma}\left(2, B\_m \cdot B\_m, \left(A \cdot C\right) \cdot -8\right)}}{t\_3}\\ \mathbf{elif}\;t\_4 \leq \infty:\\ \;\;\;\;\frac{\sqrt{\mathsf{fma}\left(B\_m, B\_m, A \cdot \left(C \cdot -4\right)\right) \cdot \left(2 \cdot F\right)} \cdot \sqrt{t\_1}}{t\_3}\\ \mathbf{else}:\\ \;\;\;\;\left(-\sqrt{F}\right) \cdot \sqrt{\frac{2}{B\_m}}\\ \end{array} \end{array} \]
B_m = (fabs.f64 B)
NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
(FPCore (A B_m C F)
 :precision binary64
 (let* ((t_0 (fma B_m B_m (* -4.0 (* A C))))
        (t_1 (fma 2.0 C (/ (* (* B_m B_m) -0.5) A)))
        (t_2 (* (* 4.0 A) C))
        (t_3 (- t_2 (pow B_m 2.0)))
        (t_4
         (/
          (sqrt
           (*
            (* 2.0 (* (- (pow B_m 2.0) t_2) F))
            (+ (+ A C) (sqrt (+ (pow B_m 2.0) (pow (- A C) 2.0))))))
          t_3)))
   (if (<= t_4 -5e+235)
     (/
      (*
       (sqrt (* 2.0 C))
       (* (sqrt (* 2.0 (fma C (* A -4.0) (* B_m B_m)))) (sqrt F)))
      t_3)
     (if (<= t_4 -1e-220)
       (*
        (/ (sqrt (* t_0 (* 2.0 F))) -1.0)
        (/ (sqrt (+ (+ A C) (sqrt (fma (- A C) (- A C) (* B_m B_m))))) t_0))
       (if (<= t_4 0.0)
         (/
          (* (sqrt F) (sqrt (* t_1 (fma 2.0 (* B_m B_m) (* (* A C) -8.0)))))
          t_3)
         (if (<= t_4 INFINITY)
           (/
            (* (sqrt (* (fma B_m B_m (* A (* C -4.0))) (* 2.0 F))) (sqrt t_1))
            t_3)
           (* (- (sqrt F)) (sqrt (/ 2.0 B_m)))))))))
B_m = fabs(B);
assert(A < B_m && B_m < C && C < F);
double code(double A, double B_m, double C, double F) {
	double t_0 = fma(B_m, B_m, (-4.0 * (A * C)));
	double t_1 = fma(2.0, C, (((B_m * B_m) * -0.5) / A));
	double t_2 = (4.0 * A) * C;
	double t_3 = t_2 - pow(B_m, 2.0);
	double t_4 = sqrt(((2.0 * ((pow(B_m, 2.0) - t_2) * F)) * ((A + C) + sqrt((pow(B_m, 2.0) + pow((A - C), 2.0)))))) / t_3;
	double tmp;
	if (t_4 <= -5e+235) {
		tmp = (sqrt((2.0 * C)) * (sqrt((2.0 * fma(C, (A * -4.0), (B_m * B_m)))) * sqrt(F))) / t_3;
	} else if (t_4 <= -1e-220) {
		tmp = (sqrt((t_0 * (2.0 * F))) / -1.0) * (sqrt(((A + C) + sqrt(fma((A - C), (A - C), (B_m * B_m))))) / t_0);
	} else if (t_4 <= 0.0) {
		tmp = (sqrt(F) * sqrt((t_1 * fma(2.0, (B_m * B_m), ((A * C) * -8.0))))) / t_3;
	} else if (t_4 <= ((double) INFINITY)) {
		tmp = (sqrt((fma(B_m, B_m, (A * (C * -4.0))) * (2.0 * F))) * sqrt(t_1)) / t_3;
	} else {
		tmp = -sqrt(F) * sqrt((2.0 / B_m));
	}
	return tmp;
}
B_m = abs(B)
A, B_m, C, F = sort([A, B_m, C, F])
function code(A, B_m, C, F)
	t_0 = fma(B_m, B_m, Float64(-4.0 * Float64(A * C)))
	t_1 = fma(2.0, C, Float64(Float64(Float64(B_m * B_m) * -0.5) / A))
	t_2 = Float64(Float64(4.0 * A) * C)
	t_3 = Float64(t_2 - (B_m ^ 2.0))
	t_4 = Float64(sqrt(Float64(Float64(2.0 * Float64(Float64((B_m ^ 2.0) - t_2) * F)) * Float64(Float64(A + C) + sqrt(Float64((B_m ^ 2.0) + (Float64(A - C) ^ 2.0)))))) / t_3)
	tmp = 0.0
	if (t_4 <= -5e+235)
		tmp = Float64(Float64(sqrt(Float64(2.0 * C)) * Float64(sqrt(Float64(2.0 * fma(C, Float64(A * -4.0), Float64(B_m * B_m)))) * sqrt(F))) / t_3);
	elseif (t_4 <= -1e-220)
		tmp = Float64(Float64(sqrt(Float64(t_0 * Float64(2.0 * F))) / -1.0) * Float64(sqrt(Float64(Float64(A + C) + sqrt(fma(Float64(A - C), Float64(A - C), Float64(B_m * B_m))))) / t_0));
	elseif (t_4 <= 0.0)
		tmp = Float64(Float64(sqrt(F) * sqrt(Float64(t_1 * fma(2.0, Float64(B_m * B_m), Float64(Float64(A * C) * -8.0))))) / t_3);
	elseif (t_4 <= Inf)
		tmp = Float64(Float64(sqrt(Float64(fma(B_m, B_m, Float64(A * Float64(C * -4.0))) * Float64(2.0 * F))) * sqrt(t_1)) / t_3);
	else
		tmp = Float64(Float64(-sqrt(F)) * sqrt(Float64(2.0 / B_m)));
	end
	return tmp
end
B_m = N[Abs[B], $MachinePrecision]
NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
code[A_, B$95$m_, C_, F_] := Block[{t$95$0 = N[(B$95$m * B$95$m + N[(-4.0 * N[(A * C), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$1 = N[(2.0 * C + N[(N[(N[(B$95$m * B$95$m), $MachinePrecision] * -0.5), $MachinePrecision] / A), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$2 = N[(N[(4.0 * A), $MachinePrecision] * C), $MachinePrecision]}, Block[{t$95$3 = N[(t$95$2 - N[Power[B$95$m, 2.0], $MachinePrecision]), $MachinePrecision]}, Block[{t$95$4 = N[(N[Sqrt[N[(N[(2.0 * N[(N[(N[Power[B$95$m, 2.0], $MachinePrecision] - t$95$2), $MachinePrecision] * F), $MachinePrecision]), $MachinePrecision] * N[(N[(A + C), $MachinePrecision] + N[Sqrt[N[(N[Power[B$95$m, 2.0], $MachinePrecision] + N[Power[N[(A - C), $MachinePrecision], 2.0], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / t$95$3), $MachinePrecision]}, If[LessEqual[t$95$4, -5e+235], N[(N[(N[Sqrt[N[(2.0 * C), $MachinePrecision]], $MachinePrecision] * N[(N[Sqrt[N[(2.0 * N[(C * N[(A * -4.0), $MachinePrecision] + N[(B$95$m * B$95$m), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] * N[Sqrt[F], $MachinePrecision]), $MachinePrecision]), $MachinePrecision] / t$95$3), $MachinePrecision], If[LessEqual[t$95$4, -1e-220], N[(N[(N[Sqrt[N[(t$95$0 * N[(2.0 * F), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / -1.0), $MachinePrecision] * N[(N[Sqrt[N[(N[(A + C), $MachinePrecision] + N[Sqrt[N[(N[(A - C), $MachinePrecision] * N[(A - C), $MachinePrecision] + N[(B$95$m * B$95$m), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / t$95$0), $MachinePrecision]), $MachinePrecision], If[LessEqual[t$95$4, 0.0], N[(N[(N[Sqrt[F], $MachinePrecision] * N[Sqrt[N[(t$95$1 * N[(2.0 * N[(B$95$m * B$95$m), $MachinePrecision] + N[(N[(A * C), $MachinePrecision] * -8.0), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] / t$95$3), $MachinePrecision], If[LessEqual[t$95$4, Infinity], N[(N[(N[Sqrt[N[(N[(B$95$m * B$95$m + N[(A * N[(C * -4.0), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] * N[(2.0 * F), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] * N[Sqrt[t$95$1], $MachinePrecision]), $MachinePrecision] / t$95$3), $MachinePrecision], N[((-N[Sqrt[F], $MachinePrecision]) * N[Sqrt[N[(2.0 / B$95$m), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]]]]]]]]]]
\begin{array}{l}
B_m = \left|B\right|
\\
[A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
\\
\begin{array}{l}
t_0 := \mathsf{fma}\left(B\_m, B\_m, -4 \cdot \left(A \cdot C\right)\right)\\
t_1 := \mathsf{fma}\left(2, C, \frac{\left(B\_m \cdot B\_m\right) \cdot -0.5}{A}\right)\\
t_2 := \left(4 \cdot A\right) \cdot C\\
t_3 := t\_2 - {B\_m}^{2}\\
t_4 := \frac{\sqrt{\left(2 \cdot \left(\left({B\_m}^{2} - t\_2\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{B\_m}^{2} + {\left(A - C\right)}^{2}}\right)}}{t\_3}\\
\mathbf{if}\;t\_4 \leq -5 \cdot 10^{+235}:\\
\;\;\;\;\frac{\sqrt{2 \cdot C} \cdot \left(\sqrt{2 \cdot \mathsf{fma}\left(C, A \cdot -4, B\_m \cdot B\_m\right)} \cdot \sqrt{F}\right)}{t\_3}\\

\mathbf{elif}\;t\_4 \leq -1 \cdot 10^{-220}:\\
\;\;\;\;\frac{\sqrt{t\_0 \cdot \left(2 \cdot F\right)}}{-1} \cdot \frac{\sqrt{\left(A + C\right) + \sqrt{\mathsf{fma}\left(A - C, A - C, B\_m \cdot B\_m\right)}}}{t\_0}\\

\mathbf{elif}\;t\_4 \leq 0:\\
\;\;\;\;\frac{\sqrt{F} \cdot \sqrt{t\_1 \cdot \mathsf{fma}\left(2, B\_m \cdot B\_m, \left(A \cdot C\right) \cdot -8\right)}}{t\_3}\\

\mathbf{elif}\;t\_4 \leq \infty:\\
\;\;\;\;\frac{\sqrt{\mathsf{fma}\left(B\_m, B\_m, A \cdot \left(C \cdot -4\right)\right) \cdot \left(2 \cdot F\right)} \cdot \sqrt{t\_1}}{t\_3}\\

\mathbf{else}:\\
\;\;\;\;\left(-\sqrt{F}\right) \cdot \sqrt{\frac{2}{B\_m}}\\


\end{array}
\end{array}
Derivation
  1. Split input into 5 regimes
  2. if (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C))) < -5.00000000000000027e235

    1. Initial program 6.0%

      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    2. Add Preprocessing
    3. Step-by-step derivation
      1. lift-sqrt.f64N/A

        \[\leadsto \frac{\mathsf{neg}\left(\color{blue}{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      2. lift-*.f64N/A

        \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\color{blue}{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      3. *-commutativeN/A

        \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\color{blue}{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right)}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      4. lift-*.f64N/A

        \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \color{blue}{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right)}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      5. lift-*.f64N/A

        \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \left(2 \cdot \color{blue}{\left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)}\right)}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      6. associate-*r*N/A

        \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \color{blue}{\left(\left(2 \cdot \left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)\right) \cdot F\right)}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      7. associate-*r*N/A

        \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\color{blue}{\left(\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \left(2 \cdot \left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)\right)\right) \cdot F}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      8. sqrt-prodN/A

        \[\leadsto \frac{\mathsf{neg}\left(\color{blue}{\sqrt{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \left(2 \cdot \left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)\right)} \cdot \sqrt{F}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      9. pow1/2N/A

        \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \left(2 \cdot \left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)\right)} \cdot \color{blue}{{F}^{\frac{1}{2}}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    4. Applied rewrites22.7%

      \[\leadsto \frac{-\color{blue}{\sqrt{\left(\sqrt{\mathsf{fma}\left(A - C, A - C, B \cdot B\right)} + \left(A + C\right)\right) \cdot \left(2 \cdot \mathsf{fma}\left(B, B, -4 \cdot \left(A \cdot C\right)\right)\right)} \cdot \sqrt{F}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    5. Taylor expanded in A around -inf

      \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\color{blue}{\left(2 \cdot C\right)} \cdot \left(2 \cdot \mathsf{fma}\left(B, B, -4 \cdot \left(A \cdot C\right)\right)\right)} \cdot \sqrt{F}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    6. Step-by-step derivation
      1. lower-*.f6414.2

        \[\leadsto \frac{-\sqrt{\color{blue}{\left(2 \cdot C\right)} \cdot \left(2 \cdot \mathsf{fma}\left(B, B, -4 \cdot \left(A \cdot C\right)\right)\right)} \cdot \sqrt{F}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    7. Applied rewrites14.2%

      \[\leadsto \frac{-\sqrt{\color{blue}{\left(2 \cdot C\right)} \cdot \left(2 \cdot \mathsf{fma}\left(B, B, -4 \cdot \left(A \cdot C\right)\right)\right)} \cdot \sqrt{F}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    8. Applied rewrites16.4%

      \[\leadsto \frac{\color{blue}{\sqrt{2 \cdot C} \cdot \left(\sqrt{2 \cdot \mathsf{fma}\left(C, A \cdot -4, B \cdot B\right)} \cdot \left(-\sqrt{F}\right)\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]

    if -5.00000000000000027e235 < (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C))) < -9.99999999999999992e-221

    1. Initial program 98.5%

      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    2. Add Preprocessing
    3. Applied rewrites98.8%

      \[\leadsto \color{blue}{\frac{\sqrt{\mathsf{fma}\left(B, B, -4 \cdot \left(A \cdot C\right)\right) \cdot \left(F \cdot 2\right)}}{-1} \cdot \frac{\sqrt{\sqrt{\mathsf{fma}\left(A - C, A - C, B \cdot B\right)} + \left(A + C\right)}}{\mathsf{fma}\left(B, B, -4 \cdot \left(A \cdot C\right)\right)}} \]

    if -9.99999999999999992e-221 < (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C))) < -0.0

    1. Initial program 3.8%

      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    2. Add Preprocessing
    3. Taylor expanded in A around -inf

      \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\left(\frac{-1}{2} \cdot \frac{{B}^{2}}{A} + 2 \cdot C\right)}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    4. Step-by-step derivation
      1. +-commutativeN/A

        \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\left(2 \cdot C + \frac{-1}{2} \cdot \frac{{B}^{2}}{A}\right)}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      2. lower-fma.f64N/A

        \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\mathsf{fma}\left(2, C, \frac{-1}{2} \cdot \frac{{B}^{2}}{A}\right)}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      3. associate-*r/N/A

        \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(2, C, \color{blue}{\frac{\frac{-1}{2} \cdot {B}^{2}}{A}}\right)}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      4. lower-/.f64N/A

        \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(2, C, \color{blue}{\frac{\frac{-1}{2} \cdot {B}^{2}}{A}}\right)}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      5. lower-*.f64N/A

        \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(2, C, \frac{\color{blue}{\frac{-1}{2} \cdot {B}^{2}}}{A}\right)}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      6. unpow2N/A

        \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(2, C, \frac{\frac{-1}{2} \cdot \color{blue}{\left(B \cdot B\right)}}{A}\right)}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      7. lower-*.f6422.3

        \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(2, C, \frac{-0.5 \cdot \color{blue}{\left(B \cdot B\right)}}{A}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    5. Applied rewrites22.3%

      \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\mathsf{fma}\left(2, C, \frac{-0.5 \cdot \left(B \cdot B\right)}{A}\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    6. Applied rewrites27.2%

      \[\leadsto \frac{-\color{blue}{\sqrt{\mathsf{fma}\left(2, C, \frac{\left(B \cdot B\right) \cdot -0.5}{A}\right) \cdot \mathsf{fma}\left(2, B \cdot B, \left(A \cdot C\right) \cdot -8\right)} \cdot \sqrt{F}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]

    if -0.0 < (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C))) < +inf.0

    1. Initial program 48.9%

      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    2. Add Preprocessing
    3. Taylor expanded in A around -inf

      \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\left(\frac{-1}{2} \cdot \frac{{B}^{2}}{A} + 2 \cdot C\right)}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    4. Step-by-step derivation
      1. +-commutativeN/A

        \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\left(2 \cdot C + \frac{-1}{2} \cdot \frac{{B}^{2}}{A}\right)}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      2. lower-fma.f64N/A

        \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\mathsf{fma}\left(2, C, \frac{-1}{2} \cdot \frac{{B}^{2}}{A}\right)}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      3. associate-*r/N/A

        \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(2, C, \color{blue}{\frac{\frac{-1}{2} \cdot {B}^{2}}{A}}\right)}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      4. lower-/.f64N/A

        \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(2, C, \color{blue}{\frac{\frac{-1}{2} \cdot {B}^{2}}{A}}\right)}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      5. lower-*.f64N/A

        \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(2, C, \frac{\color{blue}{\frac{-1}{2} \cdot {B}^{2}}}{A}\right)}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      6. unpow2N/A

        \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(2, C, \frac{\frac{-1}{2} \cdot \color{blue}{\left(B \cdot B\right)}}{A}\right)}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      7. lower-*.f6431.5

        \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(2, C, \frac{-0.5 \cdot \color{blue}{\left(B \cdot B\right)}}{A}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    5. Applied rewrites31.5%

      \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\mathsf{fma}\left(2, C, \frac{-0.5 \cdot \left(B \cdot B\right)}{A}\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    6. Step-by-step derivation
      1. lift-neg.f64N/A

        \[\leadsto \frac{\color{blue}{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(2, C, \frac{\frac{-1}{2} \cdot \left(B \cdot B\right)}{A}\right)}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      2. lift-sqrt.f64N/A

        \[\leadsto \frac{\mathsf{neg}\left(\color{blue}{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(2, C, \frac{\frac{-1}{2} \cdot \left(B \cdot B\right)}{A}\right)}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      3. pow1/2N/A

        \[\leadsto \frac{\mathsf{neg}\left(\color{blue}{{\left(\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(2, C, \frac{\frac{-1}{2} \cdot \left(B \cdot B\right)}{A}\right)\right)}^{\frac{1}{2}}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      4. lift-*.f64N/A

        \[\leadsto \frac{\mathsf{neg}\left({\color{blue}{\left(\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(2, C, \frac{\frac{-1}{2} \cdot \left(B \cdot B\right)}{A}\right)\right)}}^{\frac{1}{2}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      5. unpow-prod-downN/A

        \[\leadsto \frac{\mathsf{neg}\left(\color{blue}{{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right)}^{\frac{1}{2}} \cdot {\left(\mathsf{fma}\left(2, C, \frac{\frac{-1}{2} \cdot \left(B \cdot B\right)}{A}\right)\right)}^{\frac{1}{2}}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      6. distribute-rgt-neg-inN/A

        \[\leadsto \frac{\color{blue}{{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right)}^{\frac{1}{2}} \cdot \left(\mathsf{neg}\left({\left(\mathsf{fma}\left(2, C, \frac{\frac{-1}{2} \cdot \left(B \cdot B\right)}{A}\right)\right)}^{\frac{1}{2}}\right)\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    7. Applied rewrites37.1%

      \[\leadsto \frac{\color{blue}{\sqrt{\mathsf{fma}\left(B, B, \left(-4 \cdot C\right) \cdot A\right) \cdot \left(F \cdot 2\right)} \cdot \left(-\sqrt{\mathsf{fma}\left(2, C, \frac{\left(B \cdot B\right) \cdot -0.5}{A}\right)}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]

    if +inf.0 < (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)))

    1. Initial program 0.0%

      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    2. Add Preprocessing
    3. Taylor expanded in B around inf

      \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
    4. Step-by-step derivation
      1. mul-1-negN/A

        \[\leadsto \color{blue}{\mathsf{neg}\left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
      2. lower-neg.f64N/A

        \[\leadsto \color{blue}{\mathsf{neg}\left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
      3. *-commutativeN/A

        \[\leadsto \mathsf{neg}\left(\color{blue}{\sqrt{2} \cdot \sqrt{\frac{F}{B}}}\right) \]
      4. lower-*.f64N/A

        \[\leadsto \mathsf{neg}\left(\color{blue}{\sqrt{2} \cdot \sqrt{\frac{F}{B}}}\right) \]
      5. lower-sqrt.f64N/A

        \[\leadsto \mathsf{neg}\left(\color{blue}{\sqrt{2}} \cdot \sqrt{\frac{F}{B}}\right) \]
      6. lower-sqrt.f64N/A

        \[\leadsto \mathsf{neg}\left(\sqrt{2} \cdot \color{blue}{\sqrt{\frac{F}{B}}}\right) \]
      7. lower-/.f6420.0

        \[\leadsto -\sqrt{2} \cdot \sqrt{\color{blue}{\frac{F}{B}}} \]
    5. Applied rewrites20.0%

      \[\leadsto \color{blue}{-\sqrt{2} \cdot \sqrt{\frac{F}{B}}} \]
    6. Step-by-step derivation
      1. Applied rewrites29.6%

        \[\leadsto -\frac{\sqrt{F \cdot 2}}{\sqrt{B}} \]
      2. Step-by-step derivation
        1. Applied rewrites29.6%

          \[\leadsto -\sqrt{F} \cdot \sqrt{\frac{2}{B}} \]
      3. Recombined 5 regimes into one program.
      4. Final simplification36.6%

        \[\leadsto \begin{array}{l} \mathbf{if}\;\frac{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)}}{\left(4 \cdot A\right) \cdot C - {B}^{2}} \leq -5 \cdot 10^{+235}:\\ \;\;\;\;\frac{\sqrt{2 \cdot C} \cdot \left(\sqrt{2 \cdot \mathsf{fma}\left(C, A \cdot -4, B \cdot B\right)} \cdot \sqrt{F}\right)}{\left(4 \cdot A\right) \cdot C - {B}^{2}}\\ \mathbf{elif}\;\frac{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)}}{\left(4 \cdot A\right) \cdot C - {B}^{2}} \leq -1 \cdot 10^{-220}:\\ \;\;\;\;\frac{\sqrt{\mathsf{fma}\left(B, B, -4 \cdot \left(A \cdot C\right)\right) \cdot \left(2 \cdot F\right)}}{-1} \cdot \frac{\sqrt{\left(A + C\right) + \sqrt{\mathsf{fma}\left(A - C, A - C, B \cdot B\right)}}}{\mathsf{fma}\left(B, B, -4 \cdot \left(A \cdot C\right)\right)}\\ \mathbf{elif}\;\frac{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)}}{\left(4 \cdot A\right) \cdot C - {B}^{2}} \leq 0:\\ \;\;\;\;\frac{\sqrt{F} \cdot \sqrt{\mathsf{fma}\left(2, C, \frac{\left(B \cdot B\right) \cdot -0.5}{A}\right) \cdot \mathsf{fma}\left(2, B \cdot B, \left(A \cdot C\right) \cdot -8\right)}}{\left(4 \cdot A\right) \cdot C - {B}^{2}}\\ \mathbf{elif}\;\frac{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)}}{\left(4 \cdot A\right) \cdot C - {B}^{2}} \leq \infty:\\ \;\;\;\;\frac{\sqrt{\mathsf{fma}\left(B, B, A \cdot \left(C \cdot -4\right)\right) \cdot \left(2 \cdot F\right)} \cdot \sqrt{\mathsf{fma}\left(2, C, \frac{\left(B \cdot B\right) \cdot -0.5}{A}\right)}}{\left(4 \cdot A\right) \cdot C - {B}^{2}}\\ \mathbf{else}:\\ \;\;\;\;\left(-\sqrt{F}\right) \cdot \sqrt{\frac{2}{B}}\\ \end{array} \]
      5. Add Preprocessing

      Alternative 2: 62.1% accurate, 0.2× speedup?

      \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} t_0 := \mathsf{fma}\left(B\_m, B\_m, -4 \cdot \left(A \cdot C\right)\right)\\ t_1 := \mathsf{fma}\left(2, C, \frac{\left(B\_m \cdot B\_m\right) \cdot -0.5}{A}\right)\\ t_2 := \left(4 \cdot A\right) \cdot C\\ t_3 := t\_2 - {B\_m}^{2}\\ t_4 := \frac{\sqrt{\left(2 \cdot \left(\left({B\_m}^{2} - t\_2\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{B\_m}^{2} + {\left(A - C\right)}^{2}}\right)}}{t\_3}\\ \mathbf{if}\;t\_4 \leq -5 \cdot 10^{+235}:\\ \;\;\;\;\frac{\sqrt{2 \cdot C} \cdot \left(\sqrt{2 \cdot \mathsf{fma}\left(C, A \cdot -4, B\_m \cdot B\_m\right)} \cdot \sqrt{F}\right)}{t\_3}\\ \mathbf{elif}\;t\_4 \leq -1 \cdot 10^{-220}:\\ \;\;\;\;\frac{\sqrt{t\_0 \cdot \left(2 \cdot F\right)}}{-1} \cdot \frac{\sqrt{\left(A + C\right) + \sqrt{\mathsf{fma}\left(A - C, A - C, B\_m \cdot B\_m\right)}}}{t\_0}\\ \mathbf{elif}\;t\_4 \leq 0:\\ \;\;\;\;\frac{\sqrt{F} \cdot \sqrt{t\_1 \cdot \mathsf{fma}\left(2, B\_m \cdot B\_m, \left(A \cdot C\right) \cdot -8\right)}}{t\_3}\\ \mathbf{elif}\;t\_4 \leq \infty:\\ \;\;\;\;\frac{\sqrt{2 \cdot t\_1} \cdot \sqrt{F \cdot \mathsf{fma}\left(B\_m, B\_m, A \cdot \left(C \cdot -4\right)\right)}}{t\_3}\\ \mathbf{else}:\\ \;\;\;\;\left(-\sqrt{F}\right) \cdot \sqrt{\frac{2}{B\_m}}\\ \end{array} \end{array} \]
      B_m = (fabs.f64 B)
      NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
      (FPCore (A B_m C F)
       :precision binary64
       (let* ((t_0 (fma B_m B_m (* -4.0 (* A C))))
              (t_1 (fma 2.0 C (/ (* (* B_m B_m) -0.5) A)))
              (t_2 (* (* 4.0 A) C))
              (t_3 (- t_2 (pow B_m 2.0)))
              (t_4
               (/
                (sqrt
                 (*
                  (* 2.0 (* (- (pow B_m 2.0) t_2) F))
                  (+ (+ A C) (sqrt (+ (pow B_m 2.0) (pow (- A C) 2.0))))))
                t_3)))
         (if (<= t_4 -5e+235)
           (/
            (*
             (sqrt (* 2.0 C))
             (* (sqrt (* 2.0 (fma C (* A -4.0) (* B_m B_m)))) (sqrt F)))
            t_3)
           (if (<= t_4 -1e-220)
             (*
              (/ (sqrt (* t_0 (* 2.0 F))) -1.0)
              (/ (sqrt (+ (+ A C) (sqrt (fma (- A C) (- A C) (* B_m B_m))))) t_0))
             (if (<= t_4 0.0)
               (/
                (* (sqrt F) (sqrt (* t_1 (fma 2.0 (* B_m B_m) (* (* A C) -8.0)))))
                t_3)
               (if (<= t_4 INFINITY)
                 (/
                  (* (sqrt (* 2.0 t_1)) (sqrt (* F (fma B_m B_m (* A (* C -4.0))))))
                  t_3)
                 (* (- (sqrt F)) (sqrt (/ 2.0 B_m)))))))))
      B_m = fabs(B);
      assert(A < B_m && B_m < C && C < F);
      double code(double A, double B_m, double C, double F) {
      	double t_0 = fma(B_m, B_m, (-4.0 * (A * C)));
      	double t_1 = fma(2.0, C, (((B_m * B_m) * -0.5) / A));
      	double t_2 = (4.0 * A) * C;
      	double t_3 = t_2 - pow(B_m, 2.0);
      	double t_4 = sqrt(((2.0 * ((pow(B_m, 2.0) - t_2) * F)) * ((A + C) + sqrt((pow(B_m, 2.0) + pow((A - C), 2.0)))))) / t_3;
      	double tmp;
      	if (t_4 <= -5e+235) {
      		tmp = (sqrt((2.0 * C)) * (sqrt((2.0 * fma(C, (A * -4.0), (B_m * B_m)))) * sqrt(F))) / t_3;
      	} else if (t_4 <= -1e-220) {
      		tmp = (sqrt((t_0 * (2.0 * F))) / -1.0) * (sqrt(((A + C) + sqrt(fma((A - C), (A - C), (B_m * B_m))))) / t_0);
      	} else if (t_4 <= 0.0) {
      		tmp = (sqrt(F) * sqrt((t_1 * fma(2.0, (B_m * B_m), ((A * C) * -8.0))))) / t_3;
      	} else if (t_4 <= ((double) INFINITY)) {
      		tmp = (sqrt((2.0 * t_1)) * sqrt((F * fma(B_m, B_m, (A * (C * -4.0)))))) / t_3;
      	} else {
      		tmp = -sqrt(F) * sqrt((2.0 / B_m));
      	}
      	return tmp;
      }
      
      B_m = abs(B)
      A, B_m, C, F = sort([A, B_m, C, F])
      function code(A, B_m, C, F)
      	t_0 = fma(B_m, B_m, Float64(-4.0 * Float64(A * C)))
      	t_1 = fma(2.0, C, Float64(Float64(Float64(B_m * B_m) * -0.5) / A))
      	t_2 = Float64(Float64(4.0 * A) * C)
      	t_3 = Float64(t_2 - (B_m ^ 2.0))
      	t_4 = Float64(sqrt(Float64(Float64(2.0 * Float64(Float64((B_m ^ 2.0) - t_2) * F)) * Float64(Float64(A + C) + sqrt(Float64((B_m ^ 2.0) + (Float64(A - C) ^ 2.0)))))) / t_3)
      	tmp = 0.0
      	if (t_4 <= -5e+235)
      		tmp = Float64(Float64(sqrt(Float64(2.0 * C)) * Float64(sqrt(Float64(2.0 * fma(C, Float64(A * -4.0), Float64(B_m * B_m)))) * sqrt(F))) / t_3);
      	elseif (t_4 <= -1e-220)
      		tmp = Float64(Float64(sqrt(Float64(t_0 * Float64(2.0 * F))) / -1.0) * Float64(sqrt(Float64(Float64(A + C) + sqrt(fma(Float64(A - C), Float64(A - C), Float64(B_m * B_m))))) / t_0));
      	elseif (t_4 <= 0.0)
      		tmp = Float64(Float64(sqrt(F) * sqrt(Float64(t_1 * fma(2.0, Float64(B_m * B_m), Float64(Float64(A * C) * -8.0))))) / t_3);
      	elseif (t_4 <= Inf)
      		tmp = Float64(Float64(sqrt(Float64(2.0 * t_1)) * sqrt(Float64(F * fma(B_m, B_m, Float64(A * Float64(C * -4.0)))))) / t_3);
      	else
      		tmp = Float64(Float64(-sqrt(F)) * sqrt(Float64(2.0 / B_m)));
      	end
      	return tmp
      end
      
      B_m = N[Abs[B], $MachinePrecision]
      NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
      code[A_, B$95$m_, C_, F_] := Block[{t$95$0 = N[(B$95$m * B$95$m + N[(-4.0 * N[(A * C), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$1 = N[(2.0 * C + N[(N[(N[(B$95$m * B$95$m), $MachinePrecision] * -0.5), $MachinePrecision] / A), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$2 = N[(N[(4.0 * A), $MachinePrecision] * C), $MachinePrecision]}, Block[{t$95$3 = N[(t$95$2 - N[Power[B$95$m, 2.0], $MachinePrecision]), $MachinePrecision]}, Block[{t$95$4 = N[(N[Sqrt[N[(N[(2.0 * N[(N[(N[Power[B$95$m, 2.0], $MachinePrecision] - t$95$2), $MachinePrecision] * F), $MachinePrecision]), $MachinePrecision] * N[(N[(A + C), $MachinePrecision] + N[Sqrt[N[(N[Power[B$95$m, 2.0], $MachinePrecision] + N[Power[N[(A - C), $MachinePrecision], 2.0], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / t$95$3), $MachinePrecision]}, If[LessEqual[t$95$4, -5e+235], N[(N[(N[Sqrt[N[(2.0 * C), $MachinePrecision]], $MachinePrecision] * N[(N[Sqrt[N[(2.0 * N[(C * N[(A * -4.0), $MachinePrecision] + N[(B$95$m * B$95$m), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] * N[Sqrt[F], $MachinePrecision]), $MachinePrecision]), $MachinePrecision] / t$95$3), $MachinePrecision], If[LessEqual[t$95$4, -1e-220], N[(N[(N[Sqrt[N[(t$95$0 * N[(2.0 * F), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / -1.0), $MachinePrecision] * N[(N[Sqrt[N[(N[(A + C), $MachinePrecision] + N[Sqrt[N[(N[(A - C), $MachinePrecision] * N[(A - C), $MachinePrecision] + N[(B$95$m * B$95$m), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / t$95$0), $MachinePrecision]), $MachinePrecision], If[LessEqual[t$95$4, 0.0], N[(N[(N[Sqrt[F], $MachinePrecision] * N[Sqrt[N[(t$95$1 * N[(2.0 * N[(B$95$m * B$95$m), $MachinePrecision] + N[(N[(A * C), $MachinePrecision] * -8.0), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] / t$95$3), $MachinePrecision], If[LessEqual[t$95$4, Infinity], N[(N[(N[Sqrt[N[(2.0 * t$95$1), $MachinePrecision]], $MachinePrecision] * N[Sqrt[N[(F * N[(B$95$m * B$95$m + N[(A * N[(C * -4.0), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] / t$95$3), $MachinePrecision], N[((-N[Sqrt[F], $MachinePrecision]) * N[Sqrt[N[(2.0 / B$95$m), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]]]]]]]]]]
      
      \begin{array}{l}
      B_m = \left|B\right|
      \\
      [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
      \\
      \begin{array}{l}
      t_0 := \mathsf{fma}\left(B\_m, B\_m, -4 \cdot \left(A \cdot C\right)\right)\\
      t_1 := \mathsf{fma}\left(2, C, \frac{\left(B\_m \cdot B\_m\right) \cdot -0.5}{A}\right)\\
      t_2 := \left(4 \cdot A\right) \cdot C\\
      t_3 := t\_2 - {B\_m}^{2}\\
      t_4 := \frac{\sqrt{\left(2 \cdot \left(\left({B\_m}^{2} - t\_2\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{B\_m}^{2} + {\left(A - C\right)}^{2}}\right)}}{t\_3}\\
      \mathbf{if}\;t\_4 \leq -5 \cdot 10^{+235}:\\
      \;\;\;\;\frac{\sqrt{2 \cdot C} \cdot \left(\sqrt{2 \cdot \mathsf{fma}\left(C, A \cdot -4, B\_m \cdot B\_m\right)} \cdot \sqrt{F}\right)}{t\_3}\\
      
      \mathbf{elif}\;t\_4 \leq -1 \cdot 10^{-220}:\\
      \;\;\;\;\frac{\sqrt{t\_0 \cdot \left(2 \cdot F\right)}}{-1} \cdot \frac{\sqrt{\left(A + C\right) + \sqrt{\mathsf{fma}\left(A - C, A - C, B\_m \cdot B\_m\right)}}}{t\_0}\\
      
      \mathbf{elif}\;t\_4 \leq 0:\\
      \;\;\;\;\frac{\sqrt{F} \cdot \sqrt{t\_1 \cdot \mathsf{fma}\left(2, B\_m \cdot B\_m, \left(A \cdot C\right) \cdot -8\right)}}{t\_3}\\
      
      \mathbf{elif}\;t\_4 \leq \infty:\\
      \;\;\;\;\frac{\sqrt{2 \cdot t\_1} \cdot \sqrt{F \cdot \mathsf{fma}\left(B\_m, B\_m, A \cdot \left(C \cdot -4\right)\right)}}{t\_3}\\
      
      \mathbf{else}:\\
      \;\;\;\;\left(-\sqrt{F}\right) \cdot \sqrt{\frac{2}{B\_m}}\\
      
      
      \end{array}
      \end{array}
      
      Derivation
      1. Split input into 5 regimes
      2. if (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C))) < -5.00000000000000027e235

        1. Initial program 6.0%

          \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
        2. Add Preprocessing
        3. Step-by-step derivation
          1. lift-sqrt.f64N/A

            \[\leadsto \frac{\mathsf{neg}\left(\color{blue}{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
          2. lift-*.f64N/A

            \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\color{blue}{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
          3. *-commutativeN/A

            \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\color{blue}{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right)}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
          4. lift-*.f64N/A

            \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \color{blue}{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right)}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
          5. lift-*.f64N/A

            \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \left(2 \cdot \color{blue}{\left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)}\right)}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
          6. associate-*r*N/A

            \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \color{blue}{\left(\left(2 \cdot \left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)\right) \cdot F\right)}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
          7. associate-*r*N/A

            \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\color{blue}{\left(\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \left(2 \cdot \left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)\right)\right) \cdot F}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
          8. sqrt-prodN/A

            \[\leadsto \frac{\mathsf{neg}\left(\color{blue}{\sqrt{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \left(2 \cdot \left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)\right)} \cdot \sqrt{F}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
          9. pow1/2N/A

            \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \left(2 \cdot \left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)\right)} \cdot \color{blue}{{F}^{\frac{1}{2}}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
        4. Applied rewrites22.7%

          \[\leadsto \frac{-\color{blue}{\sqrt{\left(\sqrt{\mathsf{fma}\left(A - C, A - C, B \cdot B\right)} + \left(A + C\right)\right) \cdot \left(2 \cdot \mathsf{fma}\left(B, B, -4 \cdot \left(A \cdot C\right)\right)\right)} \cdot \sqrt{F}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
        5. Taylor expanded in A around -inf

          \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\color{blue}{\left(2 \cdot C\right)} \cdot \left(2 \cdot \mathsf{fma}\left(B, B, -4 \cdot \left(A \cdot C\right)\right)\right)} \cdot \sqrt{F}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
        6. Step-by-step derivation
          1. lower-*.f6414.2

            \[\leadsto \frac{-\sqrt{\color{blue}{\left(2 \cdot C\right)} \cdot \left(2 \cdot \mathsf{fma}\left(B, B, -4 \cdot \left(A \cdot C\right)\right)\right)} \cdot \sqrt{F}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
        7. Applied rewrites14.2%

          \[\leadsto \frac{-\sqrt{\color{blue}{\left(2 \cdot C\right)} \cdot \left(2 \cdot \mathsf{fma}\left(B, B, -4 \cdot \left(A \cdot C\right)\right)\right)} \cdot \sqrt{F}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
        8. Applied rewrites16.4%

          \[\leadsto \frac{\color{blue}{\sqrt{2 \cdot C} \cdot \left(\sqrt{2 \cdot \mathsf{fma}\left(C, A \cdot -4, B \cdot B\right)} \cdot \left(-\sqrt{F}\right)\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]

        if -5.00000000000000027e235 < (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C))) < -9.99999999999999992e-221

        1. Initial program 98.5%

          \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
        2. Add Preprocessing
        3. Applied rewrites98.8%

          \[\leadsto \color{blue}{\frac{\sqrt{\mathsf{fma}\left(B, B, -4 \cdot \left(A \cdot C\right)\right) \cdot \left(F \cdot 2\right)}}{-1} \cdot \frac{\sqrt{\sqrt{\mathsf{fma}\left(A - C, A - C, B \cdot B\right)} + \left(A + C\right)}}{\mathsf{fma}\left(B, B, -4 \cdot \left(A \cdot C\right)\right)}} \]

        if -9.99999999999999992e-221 < (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C))) < -0.0

        1. Initial program 3.8%

          \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
        2. Add Preprocessing
        3. Taylor expanded in A around -inf

          \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\left(\frac{-1}{2} \cdot \frac{{B}^{2}}{A} + 2 \cdot C\right)}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
        4. Step-by-step derivation
          1. +-commutativeN/A

            \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\left(2 \cdot C + \frac{-1}{2} \cdot \frac{{B}^{2}}{A}\right)}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
          2. lower-fma.f64N/A

            \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\mathsf{fma}\left(2, C, \frac{-1}{2} \cdot \frac{{B}^{2}}{A}\right)}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
          3. associate-*r/N/A

            \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(2, C, \color{blue}{\frac{\frac{-1}{2} \cdot {B}^{2}}{A}}\right)}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
          4. lower-/.f64N/A

            \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(2, C, \color{blue}{\frac{\frac{-1}{2} \cdot {B}^{2}}{A}}\right)}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
          5. lower-*.f64N/A

            \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(2, C, \frac{\color{blue}{\frac{-1}{2} \cdot {B}^{2}}}{A}\right)}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
          6. unpow2N/A

            \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(2, C, \frac{\frac{-1}{2} \cdot \color{blue}{\left(B \cdot B\right)}}{A}\right)}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
          7. lower-*.f6422.3

            \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(2, C, \frac{-0.5 \cdot \color{blue}{\left(B \cdot B\right)}}{A}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
        5. Applied rewrites22.3%

          \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\mathsf{fma}\left(2, C, \frac{-0.5 \cdot \left(B \cdot B\right)}{A}\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
        6. Applied rewrites27.2%

          \[\leadsto \frac{-\color{blue}{\sqrt{\mathsf{fma}\left(2, C, \frac{\left(B \cdot B\right) \cdot -0.5}{A}\right) \cdot \mathsf{fma}\left(2, B \cdot B, \left(A \cdot C\right) \cdot -8\right)} \cdot \sqrt{F}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]

        if -0.0 < (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C))) < +inf.0

        1. Initial program 48.9%

          \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
        2. Add Preprocessing
        3. Taylor expanded in A around -inf

          \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\left(\frac{-1}{2} \cdot \frac{{B}^{2}}{A} + 2 \cdot C\right)}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
        4. Step-by-step derivation
          1. +-commutativeN/A

            \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\left(2 \cdot C + \frac{-1}{2} \cdot \frac{{B}^{2}}{A}\right)}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
          2. lower-fma.f64N/A

            \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\mathsf{fma}\left(2, C, \frac{-1}{2} \cdot \frac{{B}^{2}}{A}\right)}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
          3. associate-*r/N/A

            \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(2, C, \color{blue}{\frac{\frac{-1}{2} \cdot {B}^{2}}{A}}\right)}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
          4. lower-/.f64N/A

            \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(2, C, \color{blue}{\frac{\frac{-1}{2} \cdot {B}^{2}}{A}}\right)}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
          5. lower-*.f64N/A

            \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(2, C, \frac{\color{blue}{\frac{-1}{2} \cdot {B}^{2}}}{A}\right)}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
          6. unpow2N/A

            \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(2, C, \frac{\frac{-1}{2} \cdot \color{blue}{\left(B \cdot B\right)}}{A}\right)}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
          7. lower-*.f6431.5

            \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(2, C, \frac{-0.5 \cdot \color{blue}{\left(B \cdot B\right)}}{A}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
        5. Applied rewrites31.5%

          \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\mathsf{fma}\left(2, C, \frac{-0.5 \cdot \left(B \cdot B\right)}{A}\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
        6. Applied rewrites37.1%

          \[\leadsto \frac{-\color{blue}{\sqrt{\mathsf{fma}\left(2, C, \frac{\left(B \cdot B\right) \cdot -0.5}{A}\right) \cdot 2} \cdot \sqrt{F \cdot \mathsf{fma}\left(B, B, \left(-4 \cdot C\right) \cdot A\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]

        if +inf.0 < (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)))

        1. Initial program 0.0%

          \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
        2. Add Preprocessing
        3. Taylor expanded in B around inf

          \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
        4. Step-by-step derivation
          1. mul-1-negN/A

            \[\leadsto \color{blue}{\mathsf{neg}\left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
          2. lower-neg.f64N/A

            \[\leadsto \color{blue}{\mathsf{neg}\left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
          3. *-commutativeN/A

            \[\leadsto \mathsf{neg}\left(\color{blue}{\sqrt{2} \cdot \sqrt{\frac{F}{B}}}\right) \]
          4. lower-*.f64N/A

            \[\leadsto \mathsf{neg}\left(\color{blue}{\sqrt{2} \cdot \sqrt{\frac{F}{B}}}\right) \]
          5. lower-sqrt.f64N/A

            \[\leadsto \mathsf{neg}\left(\color{blue}{\sqrt{2}} \cdot \sqrt{\frac{F}{B}}\right) \]
          6. lower-sqrt.f64N/A

            \[\leadsto \mathsf{neg}\left(\sqrt{2} \cdot \color{blue}{\sqrt{\frac{F}{B}}}\right) \]
          7. lower-/.f6420.0

            \[\leadsto -\sqrt{2} \cdot \sqrt{\color{blue}{\frac{F}{B}}} \]
        5. Applied rewrites20.0%

          \[\leadsto \color{blue}{-\sqrt{2} \cdot \sqrt{\frac{F}{B}}} \]
        6. Step-by-step derivation
          1. Applied rewrites29.6%

            \[\leadsto -\frac{\sqrt{F \cdot 2}}{\sqrt{B}} \]
          2. Step-by-step derivation
            1. Applied rewrites29.6%

              \[\leadsto -\sqrt{F} \cdot \sqrt{\frac{2}{B}} \]
          3. Recombined 5 regimes into one program.
          4. Final simplification36.6%

            \[\leadsto \begin{array}{l} \mathbf{if}\;\frac{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)}}{\left(4 \cdot A\right) \cdot C - {B}^{2}} \leq -5 \cdot 10^{+235}:\\ \;\;\;\;\frac{\sqrt{2 \cdot C} \cdot \left(\sqrt{2 \cdot \mathsf{fma}\left(C, A \cdot -4, B \cdot B\right)} \cdot \sqrt{F}\right)}{\left(4 \cdot A\right) \cdot C - {B}^{2}}\\ \mathbf{elif}\;\frac{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)}}{\left(4 \cdot A\right) \cdot C - {B}^{2}} \leq -1 \cdot 10^{-220}:\\ \;\;\;\;\frac{\sqrt{\mathsf{fma}\left(B, B, -4 \cdot \left(A \cdot C\right)\right) \cdot \left(2 \cdot F\right)}}{-1} \cdot \frac{\sqrt{\left(A + C\right) + \sqrt{\mathsf{fma}\left(A - C, A - C, B \cdot B\right)}}}{\mathsf{fma}\left(B, B, -4 \cdot \left(A \cdot C\right)\right)}\\ \mathbf{elif}\;\frac{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)}}{\left(4 \cdot A\right) \cdot C - {B}^{2}} \leq 0:\\ \;\;\;\;\frac{\sqrt{F} \cdot \sqrt{\mathsf{fma}\left(2, C, \frac{\left(B \cdot B\right) \cdot -0.5}{A}\right) \cdot \mathsf{fma}\left(2, B \cdot B, \left(A \cdot C\right) \cdot -8\right)}}{\left(4 \cdot A\right) \cdot C - {B}^{2}}\\ \mathbf{elif}\;\frac{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)}}{\left(4 \cdot A\right) \cdot C - {B}^{2}} \leq \infty:\\ \;\;\;\;\frac{\sqrt{2 \cdot \mathsf{fma}\left(2, C, \frac{\left(B \cdot B\right) \cdot -0.5}{A}\right)} \cdot \sqrt{F \cdot \mathsf{fma}\left(B, B, A \cdot \left(C \cdot -4\right)\right)}}{\left(4 \cdot A\right) \cdot C - {B}^{2}}\\ \mathbf{else}:\\ \;\;\;\;\left(-\sqrt{F}\right) \cdot \sqrt{\frac{2}{B}}\\ \end{array} \]
          5. Add Preprocessing

          Alternative 3: 62.1% accurate, 0.2× speedup?

          \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} t_0 := \mathsf{fma}\left(B\_m, B\_m, -4 \cdot \left(A \cdot C\right)\right)\\ t_1 := 2 \cdot \mathsf{fma}\left(2, C, \frac{\left(B\_m \cdot B\_m\right) \cdot -0.5}{A}\right)\\ t_2 := \left(4 \cdot A\right) \cdot C\\ t_3 := t\_2 - {B\_m}^{2}\\ t_4 := \frac{\sqrt{\left(2 \cdot \left(\left({B\_m}^{2} - t\_2\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{B\_m}^{2} + {\left(A - C\right)}^{2}}\right)}}{t\_3}\\ t_5 := \mathsf{fma}\left(B\_m, B\_m, A \cdot \left(C \cdot -4\right)\right)\\ \mathbf{if}\;t\_4 \leq -5 \cdot 10^{+235}:\\ \;\;\;\;\frac{\sqrt{2 \cdot C} \cdot \left(\sqrt{2 \cdot \mathsf{fma}\left(C, A \cdot -4, B\_m \cdot B\_m\right)} \cdot \sqrt{F}\right)}{t\_3}\\ \mathbf{elif}\;t\_4 \leq -1 \cdot 10^{-220}:\\ \;\;\;\;\frac{\sqrt{t\_0 \cdot \left(2 \cdot F\right)}}{-1} \cdot \frac{\sqrt{\left(A + C\right) + \sqrt{\mathsf{fma}\left(A - C, A - C, B\_m \cdot B\_m\right)}}}{t\_0}\\ \mathbf{elif}\;t\_4 \leq 0:\\ \;\;\;\;\frac{-1}{\frac{t\_5}{\sqrt{F} \cdot \sqrt{t\_1 \cdot \mathsf{fma}\left(-4, A \cdot C, B\_m \cdot B\_m\right)}}}\\ \mathbf{elif}\;t\_4 \leq \infty:\\ \;\;\;\;\frac{\sqrt{t\_1} \cdot \sqrt{F \cdot t\_5}}{t\_3}\\ \mathbf{else}:\\ \;\;\;\;\left(-\sqrt{F}\right) \cdot \sqrt{\frac{2}{B\_m}}\\ \end{array} \end{array} \]
          B_m = (fabs.f64 B)
          NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
          (FPCore (A B_m C F)
           :precision binary64
           (let* ((t_0 (fma B_m B_m (* -4.0 (* A C))))
                  (t_1 (* 2.0 (fma 2.0 C (/ (* (* B_m B_m) -0.5) A))))
                  (t_2 (* (* 4.0 A) C))
                  (t_3 (- t_2 (pow B_m 2.0)))
                  (t_4
                   (/
                    (sqrt
                     (*
                      (* 2.0 (* (- (pow B_m 2.0) t_2) F))
                      (+ (+ A C) (sqrt (+ (pow B_m 2.0) (pow (- A C) 2.0))))))
                    t_3))
                  (t_5 (fma B_m B_m (* A (* C -4.0)))))
             (if (<= t_4 -5e+235)
               (/
                (*
                 (sqrt (* 2.0 C))
                 (* (sqrt (* 2.0 (fma C (* A -4.0) (* B_m B_m)))) (sqrt F)))
                t_3)
               (if (<= t_4 -1e-220)
                 (*
                  (/ (sqrt (* t_0 (* 2.0 F))) -1.0)
                  (/ (sqrt (+ (+ A C) (sqrt (fma (- A C) (- A C) (* B_m B_m))))) t_0))
                 (if (<= t_4 0.0)
                   (/
                    -1.0
                    (/ t_5 (* (sqrt F) (sqrt (* t_1 (fma -4.0 (* A C) (* B_m B_m)))))))
                   (if (<= t_4 INFINITY)
                     (/ (* (sqrt t_1) (sqrt (* F t_5))) t_3)
                     (* (- (sqrt F)) (sqrt (/ 2.0 B_m)))))))))
          B_m = fabs(B);
          assert(A < B_m && B_m < C && C < F);
          double code(double A, double B_m, double C, double F) {
          	double t_0 = fma(B_m, B_m, (-4.0 * (A * C)));
          	double t_1 = 2.0 * fma(2.0, C, (((B_m * B_m) * -0.5) / A));
          	double t_2 = (4.0 * A) * C;
          	double t_3 = t_2 - pow(B_m, 2.0);
          	double t_4 = sqrt(((2.0 * ((pow(B_m, 2.0) - t_2) * F)) * ((A + C) + sqrt((pow(B_m, 2.0) + pow((A - C), 2.0)))))) / t_3;
          	double t_5 = fma(B_m, B_m, (A * (C * -4.0)));
          	double tmp;
          	if (t_4 <= -5e+235) {
          		tmp = (sqrt((2.0 * C)) * (sqrt((2.0 * fma(C, (A * -4.0), (B_m * B_m)))) * sqrt(F))) / t_3;
          	} else if (t_4 <= -1e-220) {
          		tmp = (sqrt((t_0 * (2.0 * F))) / -1.0) * (sqrt(((A + C) + sqrt(fma((A - C), (A - C), (B_m * B_m))))) / t_0);
          	} else if (t_4 <= 0.0) {
          		tmp = -1.0 / (t_5 / (sqrt(F) * sqrt((t_1 * fma(-4.0, (A * C), (B_m * B_m))))));
          	} else if (t_4 <= ((double) INFINITY)) {
          		tmp = (sqrt(t_1) * sqrt((F * t_5))) / t_3;
          	} else {
          		tmp = -sqrt(F) * sqrt((2.0 / B_m));
          	}
          	return tmp;
          }
          
          B_m = abs(B)
          A, B_m, C, F = sort([A, B_m, C, F])
          function code(A, B_m, C, F)
          	t_0 = fma(B_m, B_m, Float64(-4.0 * Float64(A * C)))
          	t_1 = Float64(2.0 * fma(2.0, C, Float64(Float64(Float64(B_m * B_m) * -0.5) / A)))
          	t_2 = Float64(Float64(4.0 * A) * C)
          	t_3 = Float64(t_2 - (B_m ^ 2.0))
          	t_4 = Float64(sqrt(Float64(Float64(2.0 * Float64(Float64((B_m ^ 2.0) - t_2) * F)) * Float64(Float64(A + C) + sqrt(Float64((B_m ^ 2.0) + (Float64(A - C) ^ 2.0)))))) / t_3)
          	t_5 = fma(B_m, B_m, Float64(A * Float64(C * -4.0)))
          	tmp = 0.0
          	if (t_4 <= -5e+235)
          		tmp = Float64(Float64(sqrt(Float64(2.0 * C)) * Float64(sqrt(Float64(2.0 * fma(C, Float64(A * -4.0), Float64(B_m * B_m)))) * sqrt(F))) / t_3);
          	elseif (t_4 <= -1e-220)
          		tmp = Float64(Float64(sqrt(Float64(t_0 * Float64(2.0 * F))) / -1.0) * Float64(sqrt(Float64(Float64(A + C) + sqrt(fma(Float64(A - C), Float64(A - C), Float64(B_m * B_m))))) / t_0));
          	elseif (t_4 <= 0.0)
          		tmp = Float64(-1.0 / Float64(t_5 / Float64(sqrt(F) * sqrt(Float64(t_1 * fma(-4.0, Float64(A * C), Float64(B_m * B_m)))))));
          	elseif (t_4 <= Inf)
          		tmp = Float64(Float64(sqrt(t_1) * sqrt(Float64(F * t_5))) / t_3);
          	else
          		tmp = Float64(Float64(-sqrt(F)) * sqrt(Float64(2.0 / B_m)));
          	end
          	return tmp
          end
          
          B_m = N[Abs[B], $MachinePrecision]
          NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
          code[A_, B$95$m_, C_, F_] := Block[{t$95$0 = N[(B$95$m * B$95$m + N[(-4.0 * N[(A * C), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$1 = N[(2.0 * N[(2.0 * C + N[(N[(N[(B$95$m * B$95$m), $MachinePrecision] * -0.5), $MachinePrecision] / A), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$2 = N[(N[(4.0 * A), $MachinePrecision] * C), $MachinePrecision]}, Block[{t$95$3 = N[(t$95$2 - N[Power[B$95$m, 2.0], $MachinePrecision]), $MachinePrecision]}, Block[{t$95$4 = N[(N[Sqrt[N[(N[(2.0 * N[(N[(N[Power[B$95$m, 2.0], $MachinePrecision] - t$95$2), $MachinePrecision] * F), $MachinePrecision]), $MachinePrecision] * N[(N[(A + C), $MachinePrecision] + N[Sqrt[N[(N[Power[B$95$m, 2.0], $MachinePrecision] + N[Power[N[(A - C), $MachinePrecision], 2.0], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / t$95$3), $MachinePrecision]}, Block[{t$95$5 = N[(B$95$m * B$95$m + N[(A * N[(C * -4.0), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[t$95$4, -5e+235], N[(N[(N[Sqrt[N[(2.0 * C), $MachinePrecision]], $MachinePrecision] * N[(N[Sqrt[N[(2.0 * N[(C * N[(A * -4.0), $MachinePrecision] + N[(B$95$m * B$95$m), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] * N[Sqrt[F], $MachinePrecision]), $MachinePrecision]), $MachinePrecision] / t$95$3), $MachinePrecision], If[LessEqual[t$95$4, -1e-220], N[(N[(N[Sqrt[N[(t$95$0 * N[(2.0 * F), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / -1.0), $MachinePrecision] * N[(N[Sqrt[N[(N[(A + C), $MachinePrecision] + N[Sqrt[N[(N[(A - C), $MachinePrecision] * N[(A - C), $MachinePrecision] + N[(B$95$m * B$95$m), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / t$95$0), $MachinePrecision]), $MachinePrecision], If[LessEqual[t$95$4, 0.0], N[(-1.0 / N[(t$95$5 / N[(N[Sqrt[F], $MachinePrecision] * N[Sqrt[N[(t$95$1 * N[(-4.0 * N[(A * C), $MachinePrecision] + N[(B$95$m * B$95$m), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], If[LessEqual[t$95$4, Infinity], N[(N[(N[Sqrt[t$95$1], $MachinePrecision] * N[Sqrt[N[(F * t$95$5), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] / t$95$3), $MachinePrecision], N[((-N[Sqrt[F], $MachinePrecision]) * N[Sqrt[N[(2.0 / B$95$m), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]]]]]]]]]]]
          
          \begin{array}{l}
          B_m = \left|B\right|
          \\
          [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
          \\
          \begin{array}{l}
          t_0 := \mathsf{fma}\left(B\_m, B\_m, -4 \cdot \left(A \cdot C\right)\right)\\
          t_1 := 2 \cdot \mathsf{fma}\left(2, C, \frac{\left(B\_m \cdot B\_m\right) \cdot -0.5}{A}\right)\\
          t_2 := \left(4 \cdot A\right) \cdot C\\
          t_3 := t\_2 - {B\_m}^{2}\\
          t_4 := \frac{\sqrt{\left(2 \cdot \left(\left({B\_m}^{2} - t\_2\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{B\_m}^{2} + {\left(A - C\right)}^{2}}\right)}}{t\_3}\\
          t_5 := \mathsf{fma}\left(B\_m, B\_m, A \cdot \left(C \cdot -4\right)\right)\\
          \mathbf{if}\;t\_4 \leq -5 \cdot 10^{+235}:\\
          \;\;\;\;\frac{\sqrt{2 \cdot C} \cdot \left(\sqrt{2 \cdot \mathsf{fma}\left(C, A \cdot -4, B\_m \cdot B\_m\right)} \cdot \sqrt{F}\right)}{t\_3}\\
          
          \mathbf{elif}\;t\_4 \leq -1 \cdot 10^{-220}:\\
          \;\;\;\;\frac{\sqrt{t\_0 \cdot \left(2 \cdot F\right)}}{-1} \cdot \frac{\sqrt{\left(A + C\right) + \sqrt{\mathsf{fma}\left(A - C, A - C, B\_m \cdot B\_m\right)}}}{t\_0}\\
          
          \mathbf{elif}\;t\_4 \leq 0:\\
          \;\;\;\;\frac{-1}{\frac{t\_5}{\sqrt{F} \cdot \sqrt{t\_1 \cdot \mathsf{fma}\left(-4, A \cdot C, B\_m \cdot B\_m\right)}}}\\
          
          \mathbf{elif}\;t\_4 \leq \infty:\\
          \;\;\;\;\frac{\sqrt{t\_1} \cdot \sqrt{F \cdot t\_5}}{t\_3}\\
          
          \mathbf{else}:\\
          \;\;\;\;\left(-\sqrt{F}\right) \cdot \sqrt{\frac{2}{B\_m}}\\
          
          
          \end{array}
          \end{array}
          
          Derivation
          1. Split input into 5 regimes
          2. if (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C))) < -5.00000000000000027e235

            1. Initial program 6.0%

              \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
            2. Add Preprocessing
            3. Step-by-step derivation
              1. lift-sqrt.f64N/A

                \[\leadsto \frac{\mathsf{neg}\left(\color{blue}{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
              2. lift-*.f64N/A

                \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\color{blue}{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
              3. *-commutativeN/A

                \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\color{blue}{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right)}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
              4. lift-*.f64N/A

                \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \color{blue}{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right)}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
              5. lift-*.f64N/A

                \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \left(2 \cdot \color{blue}{\left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)}\right)}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
              6. associate-*r*N/A

                \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \color{blue}{\left(\left(2 \cdot \left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)\right) \cdot F\right)}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
              7. associate-*r*N/A

                \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\color{blue}{\left(\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \left(2 \cdot \left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)\right)\right) \cdot F}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
              8. sqrt-prodN/A

                \[\leadsto \frac{\mathsf{neg}\left(\color{blue}{\sqrt{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \left(2 \cdot \left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)\right)} \cdot \sqrt{F}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
              9. pow1/2N/A

                \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \left(2 \cdot \left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)\right)} \cdot \color{blue}{{F}^{\frac{1}{2}}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
            4. Applied rewrites22.7%

              \[\leadsto \frac{-\color{blue}{\sqrt{\left(\sqrt{\mathsf{fma}\left(A - C, A - C, B \cdot B\right)} + \left(A + C\right)\right) \cdot \left(2 \cdot \mathsf{fma}\left(B, B, -4 \cdot \left(A \cdot C\right)\right)\right)} \cdot \sqrt{F}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
            5. Taylor expanded in A around -inf

              \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\color{blue}{\left(2 \cdot C\right)} \cdot \left(2 \cdot \mathsf{fma}\left(B, B, -4 \cdot \left(A \cdot C\right)\right)\right)} \cdot \sqrt{F}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
            6. Step-by-step derivation
              1. lower-*.f6414.2

                \[\leadsto \frac{-\sqrt{\color{blue}{\left(2 \cdot C\right)} \cdot \left(2 \cdot \mathsf{fma}\left(B, B, -4 \cdot \left(A \cdot C\right)\right)\right)} \cdot \sqrt{F}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
            7. Applied rewrites14.2%

              \[\leadsto \frac{-\sqrt{\color{blue}{\left(2 \cdot C\right)} \cdot \left(2 \cdot \mathsf{fma}\left(B, B, -4 \cdot \left(A \cdot C\right)\right)\right)} \cdot \sqrt{F}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
            8. Applied rewrites16.4%

              \[\leadsto \frac{\color{blue}{\sqrt{2 \cdot C} \cdot \left(\sqrt{2 \cdot \mathsf{fma}\left(C, A \cdot -4, B \cdot B\right)} \cdot \left(-\sqrt{F}\right)\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]

            if -5.00000000000000027e235 < (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C))) < -9.99999999999999992e-221

            1. Initial program 98.5%

              \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
            2. Add Preprocessing
            3. Applied rewrites98.8%

              \[\leadsto \color{blue}{\frac{\sqrt{\mathsf{fma}\left(B, B, -4 \cdot \left(A \cdot C\right)\right) \cdot \left(F \cdot 2\right)}}{-1} \cdot \frac{\sqrt{\sqrt{\mathsf{fma}\left(A - C, A - C, B \cdot B\right)} + \left(A + C\right)}}{\mathsf{fma}\left(B, B, -4 \cdot \left(A \cdot C\right)\right)}} \]

            if -9.99999999999999992e-221 < (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C))) < -0.0

            1. Initial program 3.8%

              \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
            2. Add Preprocessing
            3. Taylor expanded in A around -inf

              \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\left(\frac{-1}{2} \cdot \frac{{B}^{2}}{A} + 2 \cdot C\right)}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
            4. Step-by-step derivation
              1. +-commutativeN/A

                \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\left(2 \cdot C + \frac{-1}{2} \cdot \frac{{B}^{2}}{A}\right)}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
              2. lower-fma.f64N/A

                \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\mathsf{fma}\left(2, C, \frac{-1}{2} \cdot \frac{{B}^{2}}{A}\right)}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
              3. associate-*r/N/A

                \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(2, C, \color{blue}{\frac{\frac{-1}{2} \cdot {B}^{2}}{A}}\right)}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
              4. lower-/.f64N/A

                \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(2, C, \color{blue}{\frac{\frac{-1}{2} \cdot {B}^{2}}{A}}\right)}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
              5. lower-*.f64N/A

                \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(2, C, \frac{\color{blue}{\frac{-1}{2} \cdot {B}^{2}}}{A}\right)}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
              6. unpow2N/A

                \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(2, C, \frac{\frac{-1}{2} \cdot \color{blue}{\left(B \cdot B\right)}}{A}\right)}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
              7. lower-*.f6422.3

                \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(2, C, \frac{-0.5 \cdot \color{blue}{\left(B \cdot B\right)}}{A}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
            5. Applied rewrites22.3%

              \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\mathsf{fma}\left(2, C, \frac{-0.5 \cdot \left(B \cdot B\right)}{A}\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
            6. Applied rewrites22.2%

              \[\leadsto \color{blue}{\frac{1}{\frac{-\mathsf{fma}\left(B, B, \left(-4 \cdot C\right) \cdot A\right)}{\sqrt{\left(\mathsf{fma}\left(B, B, \left(-4 \cdot C\right) \cdot A\right) \cdot \left(F \cdot 2\right)\right) \cdot \mathsf{fma}\left(2, C, \frac{\left(B \cdot B\right) \cdot -0.5}{A}\right)}}}} \]
            7. Step-by-step derivation
              1. lift-sqrt.f64N/A

                \[\leadsto \frac{1}{\frac{\mathsf{neg}\left(\mathsf{fma}\left(B, B, \left(-4 \cdot C\right) \cdot A\right)\right)}{\color{blue}{\sqrt{\left(\mathsf{fma}\left(B, B, \left(-4 \cdot C\right) \cdot A\right) \cdot \left(F \cdot 2\right)\right) \cdot \mathsf{fma}\left(2, C, \frac{\left(B \cdot B\right) \cdot \frac{-1}{2}}{A}\right)}}}} \]
              2. lift-*.f64N/A

                \[\leadsto \frac{1}{\frac{\mathsf{neg}\left(\mathsf{fma}\left(B, B, \left(-4 \cdot C\right) \cdot A\right)\right)}{\sqrt{\color{blue}{\left(\mathsf{fma}\left(B, B, \left(-4 \cdot C\right) \cdot A\right) \cdot \left(F \cdot 2\right)\right) \cdot \mathsf{fma}\left(2, C, \frac{\left(B \cdot B\right) \cdot \frac{-1}{2}}{A}\right)}}}} \]
              3. lift-*.f64N/A

                \[\leadsto \frac{1}{\frac{\mathsf{neg}\left(\mathsf{fma}\left(B, B, \left(-4 \cdot C\right) \cdot A\right)\right)}{\sqrt{\color{blue}{\left(\mathsf{fma}\left(B, B, \left(-4 \cdot C\right) \cdot A\right) \cdot \left(F \cdot 2\right)\right)} \cdot \mathsf{fma}\left(2, C, \frac{\left(B \cdot B\right) \cdot \frac{-1}{2}}{A}\right)}}} \]
              4. lift-*.f64N/A

                \[\leadsto \frac{1}{\frac{\mathsf{neg}\left(\mathsf{fma}\left(B, B, \left(-4 \cdot C\right) \cdot A\right)\right)}{\sqrt{\left(\mathsf{fma}\left(B, B, \left(-4 \cdot C\right) \cdot A\right) \cdot \color{blue}{\left(F \cdot 2\right)}\right) \cdot \mathsf{fma}\left(2, C, \frac{\left(B \cdot B\right) \cdot \frac{-1}{2}}{A}\right)}}} \]
              5. associate-*r*N/A

                \[\leadsto \frac{1}{\frac{\mathsf{neg}\left(\mathsf{fma}\left(B, B, \left(-4 \cdot C\right) \cdot A\right)\right)}{\sqrt{\color{blue}{\left(\left(\mathsf{fma}\left(B, B, \left(-4 \cdot C\right) \cdot A\right) \cdot F\right) \cdot 2\right)} \cdot \mathsf{fma}\left(2, C, \frac{\left(B \cdot B\right) \cdot \frac{-1}{2}}{A}\right)}}} \]
              6. *-commutativeN/A

                \[\leadsto \frac{1}{\frac{\mathsf{neg}\left(\mathsf{fma}\left(B, B, \left(-4 \cdot C\right) \cdot A\right)\right)}{\sqrt{\left(\color{blue}{\left(F \cdot \mathsf{fma}\left(B, B, \left(-4 \cdot C\right) \cdot A\right)\right)} \cdot 2\right) \cdot \mathsf{fma}\left(2, C, \frac{\left(B \cdot B\right) \cdot \frac{-1}{2}}{A}\right)}}} \]
              7. lift-*.f64N/A

                \[\leadsto \frac{1}{\frac{\mathsf{neg}\left(\mathsf{fma}\left(B, B, \left(-4 \cdot C\right) \cdot A\right)\right)}{\sqrt{\left(\color{blue}{\left(F \cdot \mathsf{fma}\left(B, B, \left(-4 \cdot C\right) \cdot A\right)\right)} \cdot 2\right) \cdot \mathsf{fma}\left(2, C, \frac{\left(B \cdot B\right) \cdot \frac{-1}{2}}{A}\right)}}} \]
              8. associate-*l*N/A

                \[\leadsto \frac{1}{\frac{\mathsf{neg}\left(\mathsf{fma}\left(B, B, \left(-4 \cdot C\right) \cdot A\right)\right)}{\sqrt{\color{blue}{\left(F \cdot \mathsf{fma}\left(B, B, \left(-4 \cdot C\right) \cdot A\right)\right) \cdot \left(2 \cdot \mathsf{fma}\left(2, C, \frac{\left(B \cdot B\right) \cdot \frac{-1}{2}}{A}\right)\right)}}}} \]
              9. *-commutativeN/A

                \[\leadsto \frac{1}{\frac{\mathsf{neg}\left(\mathsf{fma}\left(B, B, \left(-4 \cdot C\right) \cdot A\right)\right)}{\sqrt{\left(F \cdot \mathsf{fma}\left(B, B, \left(-4 \cdot C\right) \cdot A\right)\right) \cdot \color{blue}{\left(\mathsf{fma}\left(2, C, \frac{\left(B \cdot B\right) \cdot \frac{-1}{2}}{A}\right) \cdot 2\right)}}}} \]
            8. Applied rewrites27.3%

              \[\leadsto \frac{1}{\frac{-\mathsf{fma}\left(B, B, \left(-4 \cdot C\right) \cdot A\right)}{\color{blue}{\sqrt{\left(2 \cdot \mathsf{fma}\left(2, C, \frac{\left(B \cdot B\right) \cdot -0.5}{A}\right)\right) \cdot \mathsf{fma}\left(-4, A \cdot C, B \cdot B\right)} \cdot \sqrt{F}}}} \]

            if -0.0 < (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C))) < +inf.0

            1. Initial program 48.9%

              \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
            2. Add Preprocessing
            3. Taylor expanded in A around -inf

              \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\left(\frac{-1}{2} \cdot \frac{{B}^{2}}{A} + 2 \cdot C\right)}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
            4. Step-by-step derivation
              1. +-commutativeN/A

                \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\left(2 \cdot C + \frac{-1}{2} \cdot \frac{{B}^{2}}{A}\right)}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
              2. lower-fma.f64N/A

                \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\mathsf{fma}\left(2, C, \frac{-1}{2} \cdot \frac{{B}^{2}}{A}\right)}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
              3. associate-*r/N/A

                \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(2, C, \color{blue}{\frac{\frac{-1}{2} \cdot {B}^{2}}{A}}\right)}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
              4. lower-/.f64N/A

                \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(2, C, \color{blue}{\frac{\frac{-1}{2} \cdot {B}^{2}}{A}}\right)}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
              5. lower-*.f64N/A

                \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(2, C, \frac{\color{blue}{\frac{-1}{2} \cdot {B}^{2}}}{A}\right)}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
              6. unpow2N/A

                \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(2, C, \frac{\frac{-1}{2} \cdot \color{blue}{\left(B \cdot B\right)}}{A}\right)}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
              7. lower-*.f6431.5

                \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(2, C, \frac{-0.5 \cdot \color{blue}{\left(B \cdot B\right)}}{A}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
            5. Applied rewrites31.5%

              \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\mathsf{fma}\left(2, C, \frac{-0.5 \cdot \left(B \cdot B\right)}{A}\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
            6. Applied rewrites37.1%

              \[\leadsto \frac{-\color{blue}{\sqrt{\mathsf{fma}\left(2, C, \frac{\left(B \cdot B\right) \cdot -0.5}{A}\right) \cdot 2} \cdot \sqrt{F \cdot \mathsf{fma}\left(B, B, \left(-4 \cdot C\right) \cdot A\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]

            if +inf.0 < (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)))

            1. Initial program 0.0%

              \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
            2. Add Preprocessing
            3. Taylor expanded in B around inf

              \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
            4. Step-by-step derivation
              1. mul-1-negN/A

                \[\leadsto \color{blue}{\mathsf{neg}\left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
              2. lower-neg.f64N/A

                \[\leadsto \color{blue}{\mathsf{neg}\left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
              3. *-commutativeN/A

                \[\leadsto \mathsf{neg}\left(\color{blue}{\sqrt{2} \cdot \sqrt{\frac{F}{B}}}\right) \]
              4. lower-*.f64N/A

                \[\leadsto \mathsf{neg}\left(\color{blue}{\sqrt{2} \cdot \sqrt{\frac{F}{B}}}\right) \]
              5. lower-sqrt.f64N/A

                \[\leadsto \mathsf{neg}\left(\color{blue}{\sqrt{2}} \cdot \sqrt{\frac{F}{B}}\right) \]
              6. lower-sqrt.f64N/A

                \[\leadsto \mathsf{neg}\left(\sqrt{2} \cdot \color{blue}{\sqrt{\frac{F}{B}}}\right) \]
              7. lower-/.f6420.0

                \[\leadsto -\sqrt{2} \cdot \sqrt{\color{blue}{\frac{F}{B}}} \]
            5. Applied rewrites20.0%

              \[\leadsto \color{blue}{-\sqrt{2} \cdot \sqrt{\frac{F}{B}}} \]
            6. Step-by-step derivation
              1. Applied rewrites29.6%

                \[\leadsto -\frac{\sqrt{F \cdot 2}}{\sqrt{B}} \]
              2. Step-by-step derivation
                1. Applied rewrites29.6%

                  \[\leadsto -\sqrt{F} \cdot \sqrt{\frac{2}{B}} \]
              3. Recombined 5 regimes into one program.
              4. Final simplification36.6%

                \[\leadsto \begin{array}{l} \mathbf{if}\;\frac{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)}}{\left(4 \cdot A\right) \cdot C - {B}^{2}} \leq -5 \cdot 10^{+235}:\\ \;\;\;\;\frac{\sqrt{2 \cdot C} \cdot \left(\sqrt{2 \cdot \mathsf{fma}\left(C, A \cdot -4, B \cdot B\right)} \cdot \sqrt{F}\right)}{\left(4 \cdot A\right) \cdot C - {B}^{2}}\\ \mathbf{elif}\;\frac{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)}}{\left(4 \cdot A\right) \cdot C - {B}^{2}} \leq -1 \cdot 10^{-220}:\\ \;\;\;\;\frac{\sqrt{\mathsf{fma}\left(B, B, -4 \cdot \left(A \cdot C\right)\right) \cdot \left(2 \cdot F\right)}}{-1} \cdot \frac{\sqrt{\left(A + C\right) + \sqrt{\mathsf{fma}\left(A - C, A - C, B \cdot B\right)}}}{\mathsf{fma}\left(B, B, -4 \cdot \left(A \cdot C\right)\right)}\\ \mathbf{elif}\;\frac{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)}}{\left(4 \cdot A\right) \cdot C - {B}^{2}} \leq 0:\\ \;\;\;\;\frac{-1}{\frac{\mathsf{fma}\left(B, B, A \cdot \left(C \cdot -4\right)\right)}{\sqrt{F} \cdot \sqrt{\left(2 \cdot \mathsf{fma}\left(2, C, \frac{\left(B \cdot B\right) \cdot -0.5}{A}\right)\right) \cdot \mathsf{fma}\left(-4, A \cdot C, B \cdot B\right)}}}\\ \mathbf{elif}\;\frac{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)}}{\left(4 \cdot A\right) \cdot C - {B}^{2}} \leq \infty:\\ \;\;\;\;\frac{\sqrt{2 \cdot \mathsf{fma}\left(2, C, \frac{\left(B \cdot B\right) \cdot -0.5}{A}\right)} \cdot \sqrt{F \cdot \mathsf{fma}\left(B, B, A \cdot \left(C \cdot -4\right)\right)}}{\left(4 \cdot A\right) \cdot C - {B}^{2}}\\ \mathbf{else}:\\ \;\;\;\;\left(-\sqrt{F}\right) \cdot \sqrt{\frac{2}{B}}\\ \end{array} \]
              5. Add Preprocessing

              Alternative 4: 62.1% accurate, 0.2× speedup?

              \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} t_0 := \mathsf{fma}\left(B\_m, B\_m, -4 \cdot \left(A \cdot C\right)\right)\\ t_1 := \mathsf{fma}\left(-4, A \cdot C, B\_m \cdot B\_m\right)\\ t_2 := \left(4 \cdot A\right) \cdot C\\ t_3 := t\_2 - {B\_m}^{2}\\ t_4 := \frac{\sqrt{\left(2 \cdot \left(\left({B\_m}^{2} - t\_2\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{B\_m}^{2} + {\left(A - C\right)}^{2}}\right)}}{t\_3}\\ t_5 := \mathsf{fma}\left(2, C, \frac{\left(B\_m \cdot B\_m\right) \cdot -0.5}{A}\right)\\ \mathbf{if}\;t\_4 \leq -5 \cdot 10^{+235}:\\ \;\;\;\;\frac{\sqrt{2 \cdot C} \cdot \left(\sqrt{2 \cdot \mathsf{fma}\left(C, A \cdot -4, B\_m \cdot B\_m\right)} \cdot \sqrt{F}\right)}{t\_3}\\ \mathbf{elif}\;t\_4 \leq -1 \cdot 10^{-220}:\\ \;\;\;\;\frac{\sqrt{t\_0 \cdot \left(2 \cdot F\right)}}{-1} \cdot \frac{\sqrt{\left(A + C\right) + \sqrt{\mathsf{fma}\left(A - C, A - C, B\_m \cdot B\_m\right)}}}{t\_0}\\ \mathbf{elif}\;t\_4 \leq 0:\\ \;\;\;\;\frac{-1}{\frac{\mathsf{fma}\left(B\_m, B\_m, A \cdot \left(C \cdot -4\right)\right)}{\sqrt{F} \cdot \sqrt{\left(2 \cdot t\_5\right) \cdot t\_1}}}\\ \mathbf{elif}\;t\_4 \leq \infty:\\ \;\;\;\;\sqrt{t\_1 \cdot \left(2 \cdot F\right)} \cdot \frac{\sqrt{t\_5}}{\mathsf{fma}\left(B\_m, -B\_m, 4 \cdot \left(A \cdot C\right)\right)}\\ \mathbf{else}:\\ \;\;\;\;\left(-\sqrt{F}\right) \cdot \sqrt{\frac{2}{B\_m}}\\ \end{array} \end{array} \]
              B_m = (fabs.f64 B)
              NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
              (FPCore (A B_m C F)
               :precision binary64
               (let* ((t_0 (fma B_m B_m (* -4.0 (* A C))))
                      (t_1 (fma -4.0 (* A C) (* B_m B_m)))
                      (t_2 (* (* 4.0 A) C))
                      (t_3 (- t_2 (pow B_m 2.0)))
                      (t_4
                       (/
                        (sqrt
                         (*
                          (* 2.0 (* (- (pow B_m 2.0) t_2) F))
                          (+ (+ A C) (sqrt (+ (pow B_m 2.0) (pow (- A C) 2.0))))))
                        t_3))
                      (t_5 (fma 2.0 C (/ (* (* B_m B_m) -0.5) A))))
                 (if (<= t_4 -5e+235)
                   (/
                    (*
                     (sqrt (* 2.0 C))
                     (* (sqrt (* 2.0 (fma C (* A -4.0) (* B_m B_m)))) (sqrt F)))
                    t_3)
                   (if (<= t_4 -1e-220)
                     (*
                      (/ (sqrt (* t_0 (* 2.0 F))) -1.0)
                      (/ (sqrt (+ (+ A C) (sqrt (fma (- A C) (- A C) (* B_m B_m))))) t_0))
                     (if (<= t_4 0.0)
                       (/
                        -1.0
                        (/
                         (fma B_m B_m (* A (* C -4.0)))
                         (* (sqrt F) (sqrt (* (* 2.0 t_5) t_1)))))
                       (if (<= t_4 INFINITY)
                         (*
                          (sqrt (* t_1 (* 2.0 F)))
                          (/ (sqrt t_5) (fma B_m (- B_m) (* 4.0 (* A C)))))
                         (* (- (sqrt F)) (sqrt (/ 2.0 B_m)))))))))
              B_m = fabs(B);
              assert(A < B_m && B_m < C && C < F);
              double code(double A, double B_m, double C, double F) {
              	double t_0 = fma(B_m, B_m, (-4.0 * (A * C)));
              	double t_1 = fma(-4.0, (A * C), (B_m * B_m));
              	double t_2 = (4.0 * A) * C;
              	double t_3 = t_2 - pow(B_m, 2.0);
              	double t_4 = sqrt(((2.0 * ((pow(B_m, 2.0) - t_2) * F)) * ((A + C) + sqrt((pow(B_m, 2.0) + pow((A - C), 2.0)))))) / t_3;
              	double t_5 = fma(2.0, C, (((B_m * B_m) * -0.5) / A));
              	double tmp;
              	if (t_4 <= -5e+235) {
              		tmp = (sqrt((2.0 * C)) * (sqrt((2.0 * fma(C, (A * -4.0), (B_m * B_m)))) * sqrt(F))) / t_3;
              	} else if (t_4 <= -1e-220) {
              		tmp = (sqrt((t_0 * (2.0 * F))) / -1.0) * (sqrt(((A + C) + sqrt(fma((A - C), (A - C), (B_m * B_m))))) / t_0);
              	} else if (t_4 <= 0.0) {
              		tmp = -1.0 / (fma(B_m, B_m, (A * (C * -4.0))) / (sqrt(F) * sqrt(((2.0 * t_5) * t_1))));
              	} else if (t_4 <= ((double) INFINITY)) {
              		tmp = sqrt((t_1 * (2.0 * F))) * (sqrt(t_5) / fma(B_m, -B_m, (4.0 * (A * C))));
              	} else {
              		tmp = -sqrt(F) * sqrt((2.0 / B_m));
              	}
              	return tmp;
              }
              
              B_m = abs(B)
              A, B_m, C, F = sort([A, B_m, C, F])
              function code(A, B_m, C, F)
              	t_0 = fma(B_m, B_m, Float64(-4.0 * Float64(A * C)))
              	t_1 = fma(-4.0, Float64(A * C), Float64(B_m * B_m))
              	t_2 = Float64(Float64(4.0 * A) * C)
              	t_3 = Float64(t_2 - (B_m ^ 2.0))
              	t_4 = Float64(sqrt(Float64(Float64(2.0 * Float64(Float64((B_m ^ 2.0) - t_2) * F)) * Float64(Float64(A + C) + sqrt(Float64((B_m ^ 2.0) + (Float64(A - C) ^ 2.0)))))) / t_3)
              	t_5 = fma(2.0, C, Float64(Float64(Float64(B_m * B_m) * -0.5) / A))
              	tmp = 0.0
              	if (t_4 <= -5e+235)
              		tmp = Float64(Float64(sqrt(Float64(2.0 * C)) * Float64(sqrt(Float64(2.0 * fma(C, Float64(A * -4.0), Float64(B_m * B_m)))) * sqrt(F))) / t_3);
              	elseif (t_4 <= -1e-220)
              		tmp = Float64(Float64(sqrt(Float64(t_0 * Float64(2.0 * F))) / -1.0) * Float64(sqrt(Float64(Float64(A + C) + sqrt(fma(Float64(A - C), Float64(A - C), Float64(B_m * B_m))))) / t_0));
              	elseif (t_4 <= 0.0)
              		tmp = Float64(-1.0 / Float64(fma(B_m, B_m, Float64(A * Float64(C * -4.0))) / Float64(sqrt(F) * sqrt(Float64(Float64(2.0 * t_5) * t_1)))));
              	elseif (t_4 <= Inf)
              		tmp = Float64(sqrt(Float64(t_1 * Float64(2.0 * F))) * Float64(sqrt(t_5) / fma(B_m, Float64(-B_m), Float64(4.0 * Float64(A * C)))));
              	else
              		tmp = Float64(Float64(-sqrt(F)) * sqrt(Float64(2.0 / B_m)));
              	end
              	return tmp
              end
              
              B_m = N[Abs[B], $MachinePrecision]
              NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
              code[A_, B$95$m_, C_, F_] := Block[{t$95$0 = N[(B$95$m * B$95$m + N[(-4.0 * N[(A * C), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$1 = N[(-4.0 * N[(A * C), $MachinePrecision] + N[(B$95$m * B$95$m), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$2 = N[(N[(4.0 * A), $MachinePrecision] * C), $MachinePrecision]}, Block[{t$95$3 = N[(t$95$2 - N[Power[B$95$m, 2.0], $MachinePrecision]), $MachinePrecision]}, Block[{t$95$4 = N[(N[Sqrt[N[(N[(2.0 * N[(N[(N[Power[B$95$m, 2.0], $MachinePrecision] - t$95$2), $MachinePrecision] * F), $MachinePrecision]), $MachinePrecision] * N[(N[(A + C), $MachinePrecision] + N[Sqrt[N[(N[Power[B$95$m, 2.0], $MachinePrecision] + N[Power[N[(A - C), $MachinePrecision], 2.0], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / t$95$3), $MachinePrecision]}, Block[{t$95$5 = N[(2.0 * C + N[(N[(N[(B$95$m * B$95$m), $MachinePrecision] * -0.5), $MachinePrecision] / A), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[t$95$4, -5e+235], N[(N[(N[Sqrt[N[(2.0 * C), $MachinePrecision]], $MachinePrecision] * N[(N[Sqrt[N[(2.0 * N[(C * N[(A * -4.0), $MachinePrecision] + N[(B$95$m * B$95$m), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] * N[Sqrt[F], $MachinePrecision]), $MachinePrecision]), $MachinePrecision] / t$95$3), $MachinePrecision], If[LessEqual[t$95$4, -1e-220], N[(N[(N[Sqrt[N[(t$95$0 * N[(2.0 * F), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / -1.0), $MachinePrecision] * N[(N[Sqrt[N[(N[(A + C), $MachinePrecision] + N[Sqrt[N[(N[(A - C), $MachinePrecision] * N[(A - C), $MachinePrecision] + N[(B$95$m * B$95$m), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / t$95$0), $MachinePrecision]), $MachinePrecision], If[LessEqual[t$95$4, 0.0], N[(-1.0 / N[(N[(B$95$m * B$95$m + N[(A * N[(C * -4.0), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] / N[(N[Sqrt[F], $MachinePrecision] * N[Sqrt[N[(N[(2.0 * t$95$5), $MachinePrecision] * t$95$1), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], If[LessEqual[t$95$4, Infinity], N[(N[Sqrt[N[(t$95$1 * N[(2.0 * F), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] * N[(N[Sqrt[t$95$5], $MachinePrecision] / N[(B$95$m * (-B$95$m) + N[(4.0 * N[(A * C), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], N[((-N[Sqrt[F], $MachinePrecision]) * N[Sqrt[N[(2.0 / B$95$m), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]]]]]]]]]]]
              
              \begin{array}{l}
              B_m = \left|B\right|
              \\
              [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
              \\
              \begin{array}{l}
              t_0 := \mathsf{fma}\left(B\_m, B\_m, -4 \cdot \left(A \cdot C\right)\right)\\
              t_1 := \mathsf{fma}\left(-4, A \cdot C, B\_m \cdot B\_m\right)\\
              t_2 := \left(4 \cdot A\right) \cdot C\\
              t_3 := t\_2 - {B\_m}^{2}\\
              t_4 := \frac{\sqrt{\left(2 \cdot \left(\left({B\_m}^{2} - t\_2\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{B\_m}^{2} + {\left(A - C\right)}^{2}}\right)}}{t\_3}\\
              t_5 := \mathsf{fma}\left(2, C, \frac{\left(B\_m \cdot B\_m\right) \cdot -0.5}{A}\right)\\
              \mathbf{if}\;t\_4 \leq -5 \cdot 10^{+235}:\\
              \;\;\;\;\frac{\sqrt{2 \cdot C} \cdot \left(\sqrt{2 \cdot \mathsf{fma}\left(C, A \cdot -4, B\_m \cdot B\_m\right)} \cdot \sqrt{F}\right)}{t\_3}\\
              
              \mathbf{elif}\;t\_4 \leq -1 \cdot 10^{-220}:\\
              \;\;\;\;\frac{\sqrt{t\_0 \cdot \left(2 \cdot F\right)}}{-1} \cdot \frac{\sqrt{\left(A + C\right) + \sqrt{\mathsf{fma}\left(A - C, A - C, B\_m \cdot B\_m\right)}}}{t\_0}\\
              
              \mathbf{elif}\;t\_4 \leq 0:\\
              \;\;\;\;\frac{-1}{\frac{\mathsf{fma}\left(B\_m, B\_m, A \cdot \left(C \cdot -4\right)\right)}{\sqrt{F} \cdot \sqrt{\left(2 \cdot t\_5\right) \cdot t\_1}}}\\
              
              \mathbf{elif}\;t\_4 \leq \infty:\\
              \;\;\;\;\sqrt{t\_1 \cdot \left(2 \cdot F\right)} \cdot \frac{\sqrt{t\_5}}{\mathsf{fma}\left(B\_m, -B\_m, 4 \cdot \left(A \cdot C\right)\right)}\\
              
              \mathbf{else}:\\
              \;\;\;\;\left(-\sqrt{F}\right) \cdot \sqrt{\frac{2}{B\_m}}\\
              
              
              \end{array}
              \end{array}
              
              Derivation
              1. Split input into 5 regimes
              2. if (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C))) < -5.00000000000000027e235

                1. Initial program 6.0%

                  \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                2. Add Preprocessing
                3. Step-by-step derivation
                  1. lift-sqrt.f64N/A

                    \[\leadsto \frac{\mathsf{neg}\left(\color{blue}{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                  2. lift-*.f64N/A

                    \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\color{blue}{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                  3. *-commutativeN/A

                    \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\color{blue}{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right)}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                  4. lift-*.f64N/A

                    \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \color{blue}{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right)}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                  5. lift-*.f64N/A

                    \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \left(2 \cdot \color{blue}{\left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)}\right)}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                  6. associate-*r*N/A

                    \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \color{blue}{\left(\left(2 \cdot \left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)\right) \cdot F\right)}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                  7. associate-*r*N/A

                    \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\color{blue}{\left(\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \left(2 \cdot \left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)\right)\right) \cdot F}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                  8. sqrt-prodN/A

                    \[\leadsto \frac{\mathsf{neg}\left(\color{blue}{\sqrt{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \left(2 \cdot \left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)\right)} \cdot \sqrt{F}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                  9. pow1/2N/A

                    \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \left(2 \cdot \left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)\right)} \cdot \color{blue}{{F}^{\frac{1}{2}}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                4. Applied rewrites22.7%

                  \[\leadsto \frac{-\color{blue}{\sqrt{\left(\sqrt{\mathsf{fma}\left(A - C, A - C, B \cdot B\right)} + \left(A + C\right)\right) \cdot \left(2 \cdot \mathsf{fma}\left(B, B, -4 \cdot \left(A \cdot C\right)\right)\right)} \cdot \sqrt{F}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                5. Taylor expanded in A around -inf

                  \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\color{blue}{\left(2 \cdot C\right)} \cdot \left(2 \cdot \mathsf{fma}\left(B, B, -4 \cdot \left(A \cdot C\right)\right)\right)} \cdot \sqrt{F}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                6. Step-by-step derivation
                  1. lower-*.f6414.2

                    \[\leadsto \frac{-\sqrt{\color{blue}{\left(2 \cdot C\right)} \cdot \left(2 \cdot \mathsf{fma}\left(B, B, -4 \cdot \left(A \cdot C\right)\right)\right)} \cdot \sqrt{F}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                7. Applied rewrites14.2%

                  \[\leadsto \frac{-\sqrt{\color{blue}{\left(2 \cdot C\right)} \cdot \left(2 \cdot \mathsf{fma}\left(B, B, -4 \cdot \left(A \cdot C\right)\right)\right)} \cdot \sqrt{F}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                8. Applied rewrites16.4%

                  \[\leadsto \frac{\color{blue}{\sqrt{2 \cdot C} \cdot \left(\sqrt{2 \cdot \mathsf{fma}\left(C, A \cdot -4, B \cdot B\right)} \cdot \left(-\sqrt{F}\right)\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]

                if -5.00000000000000027e235 < (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C))) < -9.99999999999999992e-221

                1. Initial program 98.5%

                  \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                2. Add Preprocessing
                3. Applied rewrites98.8%

                  \[\leadsto \color{blue}{\frac{\sqrt{\mathsf{fma}\left(B, B, -4 \cdot \left(A \cdot C\right)\right) \cdot \left(F \cdot 2\right)}}{-1} \cdot \frac{\sqrt{\sqrt{\mathsf{fma}\left(A - C, A - C, B \cdot B\right)} + \left(A + C\right)}}{\mathsf{fma}\left(B, B, -4 \cdot \left(A \cdot C\right)\right)}} \]

                if -9.99999999999999992e-221 < (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C))) < -0.0

                1. Initial program 3.8%

                  \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                2. Add Preprocessing
                3. Taylor expanded in A around -inf

                  \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\left(\frac{-1}{2} \cdot \frac{{B}^{2}}{A} + 2 \cdot C\right)}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                4. Step-by-step derivation
                  1. +-commutativeN/A

                    \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\left(2 \cdot C + \frac{-1}{2} \cdot \frac{{B}^{2}}{A}\right)}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                  2. lower-fma.f64N/A

                    \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\mathsf{fma}\left(2, C, \frac{-1}{2} \cdot \frac{{B}^{2}}{A}\right)}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                  3. associate-*r/N/A

                    \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(2, C, \color{blue}{\frac{\frac{-1}{2} \cdot {B}^{2}}{A}}\right)}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                  4. lower-/.f64N/A

                    \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(2, C, \color{blue}{\frac{\frac{-1}{2} \cdot {B}^{2}}{A}}\right)}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                  5. lower-*.f64N/A

                    \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(2, C, \frac{\color{blue}{\frac{-1}{2} \cdot {B}^{2}}}{A}\right)}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                  6. unpow2N/A

                    \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(2, C, \frac{\frac{-1}{2} \cdot \color{blue}{\left(B \cdot B\right)}}{A}\right)}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                  7. lower-*.f6422.3

                    \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(2, C, \frac{-0.5 \cdot \color{blue}{\left(B \cdot B\right)}}{A}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                5. Applied rewrites22.3%

                  \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\mathsf{fma}\left(2, C, \frac{-0.5 \cdot \left(B \cdot B\right)}{A}\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                6. Applied rewrites22.2%

                  \[\leadsto \color{blue}{\frac{1}{\frac{-\mathsf{fma}\left(B, B, \left(-4 \cdot C\right) \cdot A\right)}{\sqrt{\left(\mathsf{fma}\left(B, B, \left(-4 \cdot C\right) \cdot A\right) \cdot \left(F \cdot 2\right)\right) \cdot \mathsf{fma}\left(2, C, \frac{\left(B \cdot B\right) \cdot -0.5}{A}\right)}}}} \]
                7. Step-by-step derivation
                  1. lift-sqrt.f64N/A

                    \[\leadsto \frac{1}{\frac{\mathsf{neg}\left(\mathsf{fma}\left(B, B, \left(-4 \cdot C\right) \cdot A\right)\right)}{\color{blue}{\sqrt{\left(\mathsf{fma}\left(B, B, \left(-4 \cdot C\right) \cdot A\right) \cdot \left(F \cdot 2\right)\right) \cdot \mathsf{fma}\left(2, C, \frac{\left(B \cdot B\right) \cdot \frac{-1}{2}}{A}\right)}}}} \]
                  2. lift-*.f64N/A

                    \[\leadsto \frac{1}{\frac{\mathsf{neg}\left(\mathsf{fma}\left(B, B, \left(-4 \cdot C\right) \cdot A\right)\right)}{\sqrt{\color{blue}{\left(\mathsf{fma}\left(B, B, \left(-4 \cdot C\right) \cdot A\right) \cdot \left(F \cdot 2\right)\right) \cdot \mathsf{fma}\left(2, C, \frac{\left(B \cdot B\right) \cdot \frac{-1}{2}}{A}\right)}}}} \]
                  3. lift-*.f64N/A

                    \[\leadsto \frac{1}{\frac{\mathsf{neg}\left(\mathsf{fma}\left(B, B, \left(-4 \cdot C\right) \cdot A\right)\right)}{\sqrt{\color{blue}{\left(\mathsf{fma}\left(B, B, \left(-4 \cdot C\right) \cdot A\right) \cdot \left(F \cdot 2\right)\right)} \cdot \mathsf{fma}\left(2, C, \frac{\left(B \cdot B\right) \cdot \frac{-1}{2}}{A}\right)}}} \]
                  4. lift-*.f64N/A

                    \[\leadsto \frac{1}{\frac{\mathsf{neg}\left(\mathsf{fma}\left(B, B, \left(-4 \cdot C\right) \cdot A\right)\right)}{\sqrt{\left(\mathsf{fma}\left(B, B, \left(-4 \cdot C\right) \cdot A\right) \cdot \color{blue}{\left(F \cdot 2\right)}\right) \cdot \mathsf{fma}\left(2, C, \frac{\left(B \cdot B\right) \cdot \frac{-1}{2}}{A}\right)}}} \]
                  5. associate-*r*N/A

                    \[\leadsto \frac{1}{\frac{\mathsf{neg}\left(\mathsf{fma}\left(B, B, \left(-4 \cdot C\right) \cdot A\right)\right)}{\sqrt{\color{blue}{\left(\left(\mathsf{fma}\left(B, B, \left(-4 \cdot C\right) \cdot A\right) \cdot F\right) \cdot 2\right)} \cdot \mathsf{fma}\left(2, C, \frac{\left(B \cdot B\right) \cdot \frac{-1}{2}}{A}\right)}}} \]
                  6. *-commutativeN/A

                    \[\leadsto \frac{1}{\frac{\mathsf{neg}\left(\mathsf{fma}\left(B, B, \left(-4 \cdot C\right) \cdot A\right)\right)}{\sqrt{\left(\color{blue}{\left(F \cdot \mathsf{fma}\left(B, B, \left(-4 \cdot C\right) \cdot A\right)\right)} \cdot 2\right) \cdot \mathsf{fma}\left(2, C, \frac{\left(B \cdot B\right) \cdot \frac{-1}{2}}{A}\right)}}} \]
                  7. lift-*.f64N/A

                    \[\leadsto \frac{1}{\frac{\mathsf{neg}\left(\mathsf{fma}\left(B, B, \left(-4 \cdot C\right) \cdot A\right)\right)}{\sqrt{\left(\color{blue}{\left(F \cdot \mathsf{fma}\left(B, B, \left(-4 \cdot C\right) \cdot A\right)\right)} \cdot 2\right) \cdot \mathsf{fma}\left(2, C, \frac{\left(B \cdot B\right) \cdot \frac{-1}{2}}{A}\right)}}} \]
                  8. associate-*l*N/A

                    \[\leadsto \frac{1}{\frac{\mathsf{neg}\left(\mathsf{fma}\left(B, B, \left(-4 \cdot C\right) \cdot A\right)\right)}{\sqrt{\color{blue}{\left(F \cdot \mathsf{fma}\left(B, B, \left(-4 \cdot C\right) \cdot A\right)\right) \cdot \left(2 \cdot \mathsf{fma}\left(2, C, \frac{\left(B \cdot B\right) \cdot \frac{-1}{2}}{A}\right)\right)}}}} \]
                  9. *-commutativeN/A

                    \[\leadsto \frac{1}{\frac{\mathsf{neg}\left(\mathsf{fma}\left(B, B, \left(-4 \cdot C\right) \cdot A\right)\right)}{\sqrt{\left(F \cdot \mathsf{fma}\left(B, B, \left(-4 \cdot C\right) \cdot A\right)\right) \cdot \color{blue}{\left(\mathsf{fma}\left(2, C, \frac{\left(B \cdot B\right) \cdot \frac{-1}{2}}{A}\right) \cdot 2\right)}}}} \]
                8. Applied rewrites27.3%

                  \[\leadsto \frac{1}{\frac{-\mathsf{fma}\left(B, B, \left(-4 \cdot C\right) \cdot A\right)}{\color{blue}{\sqrt{\left(2 \cdot \mathsf{fma}\left(2, C, \frac{\left(B \cdot B\right) \cdot -0.5}{A}\right)\right) \cdot \mathsf{fma}\left(-4, A \cdot C, B \cdot B\right)} \cdot \sqrt{F}}}} \]

                if -0.0 < (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C))) < +inf.0

                1. Initial program 48.9%

                  \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                2. Add Preprocessing
                3. Taylor expanded in A around -inf

                  \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\left(\frac{-1}{2} \cdot \frac{{B}^{2}}{A} + 2 \cdot C\right)}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                4. Step-by-step derivation
                  1. +-commutativeN/A

                    \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\left(2 \cdot C + \frac{-1}{2} \cdot \frac{{B}^{2}}{A}\right)}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                  2. lower-fma.f64N/A

                    \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\mathsf{fma}\left(2, C, \frac{-1}{2} \cdot \frac{{B}^{2}}{A}\right)}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                  3. associate-*r/N/A

                    \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(2, C, \color{blue}{\frac{\frac{-1}{2} \cdot {B}^{2}}{A}}\right)}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                  4. lower-/.f64N/A

                    \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(2, C, \color{blue}{\frac{\frac{-1}{2} \cdot {B}^{2}}{A}}\right)}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                  5. lower-*.f64N/A

                    \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(2, C, \frac{\color{blue}{\frac{-1}{2} \cdot {B}^{2}}}{A}\right)}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                  6. unpow2N/A

                    \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(2, C, \frac{\frac{-1}{2} \cdot \color{blue}{\left(B \cdot B\right)}}{A}\right)}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                  7. lower-*.f6431.5

                    \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(2, C, \frac{-0.5 \cdot \color{blue}{\left(B \cdot B\right)}}{A}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                5. Applied rewrites31.5%

                  \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\mathsf{fma}\left(2, C, \frac{-0.5 \cdot \left(B \cdot B\right)}{A}\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                6. Applied rewrites31.4%

                  \[\leadsto \color{blue}{\frac{1}{\frac{-\mathsf{fma}\left(B, B, \left(-4 \cdot C\right) \cdot A\right)}{\sqrt{\left(\mathsf{fma}\left(B, B, \left(-4 \cdot C\right) \cdot A\right) \cdot \left(F \cdot 2\right)\right) \cdot \mathsf{fma}\left(2, C, \frac{\left(B \cdot B\right) \cdot -0.5}{A}\right)}}}} \]
                7. Applied rewrites37.0%

                  \[\leadsto \color{blue}{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, A \cdot C, B \cdot B\right)} \cdot \frac{\sqrt{\mathsf{fma}\left(2, C, \frac{\left(B \cdot B\right) \cdot -0.5}{A}\right)}}{\mathsf{fma}\left(B, -B, 4 \cdot \left(A \cdot C\right)\right)}} \]

                if +inf.0 < (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)))

                1. Initial program 0.0%

                  \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                2. Add Preprocessing
                3. Taylor expanded in B around inf

                  \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                4. Step-by-step derivation
                  1. mul-1-negN/A

                    \[\leadsto \color{blue}{\mathsf{neg}\left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                  2. lower-neg.f64N/A

                    \[\leadsto \color{blue}{\mathsf{neg}\left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                  3. *-commutativeN/A

                    \[\leadsto \mathsf{neg}\left(\color{blue}{\sqrt{2} \cdot \sqrt{\frac{F}{B}}}\right) \]
                  4. lower-*.f64N/A

                    \[\leadsto \mathsf{neg}\left(\color{blue}{\sqrt{2} \cdot \sqrt{\frac{F}{B}}}\right) \]
                  5. lower-sqrt.f64N/A

                    \[\leadsto \mathsf{neg}\left(\color{blue}{\sqrt{2}} \cdot \sqrt{\frac{F}{B}}\right) \]
                  6. lower-sqrt.f64N/A

                    \[\leadsto \mathsf{neg}\left(\sqrt{2} \cdot \color{blue}{\sqrt{\frac{F}{B}}}\right) \]
                  7. lower-/.f6420.0

                    \[\leadsto -\sqrt{2} \cdot \sqrt{\color{blue}{\frac{F}{B}}} \]
                5. Applied rewrites20.0%

                  \[\leadsto \color{blue}{-\sqrt{2} \cdot \sqrt{\frac{F}{B}}} \]
                6. Step-by-step derivation
                  1. Applied rewrites29.6%

                    \[\leadsto -\frac{\sqrt{F \cdot 2}}{\sqrt{B}} \]
                  2. Step-by-step derivation
                    1. Applied rewrites29.6%

                      \[\leadsto -\sqrt{F} \cdot \sqrt{\frac{2}{B}} \]
                  3. Recombined 5 regimes into one program.
                  4. Final simplification36.6%

                    \[\leadsto \begin{array}{l} \mathbf{if}\;\frac{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)}}{\left(4 \cdot A\right) \cdot C - {B}^{2}} \leq -5 \cdot 10^{+235}:\\ \;\;\;\;\frac{\sqrt{2 \cdot C} \cdot \left(\sqrt{2 \cdot \mathsf{fma}\left(C, A \cdot -4, B \cdot B\right)} \cdot \sqrt{F}\right)}{\left(4 \cdot A\right) \cdot C - {B}^{2}}\\ \mathbf{elif}\;\frac{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)}}{\left(4 \cdot A\right) \cdot C - {B}^{2}} \leq -1 \cdot 10^{-220}:\\ \;\;\;\;\frac{\sqrt{\mathsf{fma}\left(B, B, -4 \cdot \left(A \cdot C\right)\right) \cdot \left(2 \cdot F\right)}}{-1} \cdot \frac{\sqrt{\left(A + C\right) + \sqrt{\mathsf{fma}\left(A - C, A - C, B \cdot B\right)}}}{\mathsf{fma}\left(B, B, -4 \cdot \left(A \cdot C\right)\right)}\\ \mathbf{elif}\;\frac{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)}}{\left(4 \cdot A\right) \cdot C - {B}^{2}} \leq 0:\\ \;\;\;\;\frac{-1}{\frac{\mathsf{fma}\left(B, B, A \cdot \left(C \cdot -4\right)\right)}{\sqrt{F} \cdot \sqrt{\left(2 \cdot \mathsf{fma}\left(2, C, \frac{\left(B \cdot B\right) \cdot -0.5}{A}\right)\right) \cdot \mathsf{fma}\left(-4, A \cdot C, B \cdot B\right)}}}\\ \mathbf{elif}\;\frac{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)}}{\left(4 \cdot A\right) \cdot C - {B}^{2}} \leq \infty:\\ \;\;\;\;\sqrt{\mathsf{fma}\left(-4, A \cdot C, B \cdot B\right) \cdot \left(2 \cdot F\right)} \cdot \frac{\sqrt{\mathsf{fma}\left(2, C, \frac{\left(B \cdot B\right) \cdot -0.5}{A}\right)}}{\mathsf{fma}\left(B, -B, 4 \cdot \left(A \cdot C\right)\right)}\\ \mathbf{else}:\\ \;\;\;\;\left(-\sqrt{F}\right) \cdot \sqrt{\frac{2}{B}}\\ \end{array} \]
                  5. Add Preprocessing

                  Alternative 5: 58.2% accurate, 0.2× speedup?

                  \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} t_0 := \mathsf{fma}\left(B\_m, B\_m, A \cdot \left(C \cdot -4\right)\right)\\ t_1 := \mathsf{fma}\left(-4, A \cdot C, B\_m \cdot B\_m\right)\\ t_2 := \left(4 \cdot A\right) \cdot C\\ t_3 := \frac{\sqrt{\left(2 \cdot \left(\left({B\_m}^{2} - t\_2\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{B\_m}^{2} + {\left(A - C\right)}^{2}}\right)}}{t\_2 - {B\_m}^{2}}\\ t_4 := \mathsf{fma}\left(2, C, \frac{\left(B\_m \cdot B\_m\right) \cdot -0.5}{A}\right)\\ t_5 := \mathsf{fma}\left(B\_m, B\_m, -4 \cdot \left(A \cdot C\right)\right)\\ \mathbf{if}\;t\_3 \leq -5 \cdot 10^{+235}:\\ \;\;\;\;\frac{-1}{\frac{t\_0}{\sqrt{t\_4 \cdot t\_1} \cdot \sqrt{2 \cdot F}}}\\ \mathbf{elif}\;t\_3 \leq -1 \cdot 10^{-220}:\\ \;\;\;\;\frac{\sqrt{t\_5 \cdot \left(2 \cdot F\right)}}{-1} \cdot \frac{\sqrt{\left(A + C\right) + \sqrt{\mathsf{fma}\left(A - C, A - C, B\_m \cdot B\_m\right)}}}{t\_5}\\ \mathbf{elif}\;t\_3 \leq 0:\\ \;\;\;\;\frac{-1}{\frac{t\_0}{\sqrt{F} \cdot \sqrt{\left(2 \cdot t\_4\right) \cdot t\_1}}}\\ \mathbf{elif}\;t\_3 \leq \infty:\\ \;\;\;\;\sqrt{t\_1 \cdot \left(2 \cdot F\right)} \cdot \frac{\sqrt{t\_4}}{\mathsf{fma}\left(B\_m, -B\_m, 4 \cdot \left(A \cdot C\right)\right)}\\ \mathbf{else}:\\ \;\;\;\;\left(-\sqrt{F}\right) \cdot \sqrt{\frac{2}{B\_m}}\\ \end{array} \end{array} \]
                  B_m = (fabs.f64 B)
                  NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                  (FPCore (A B_m C F)
                   :precision binary64
                   (let* ((t_0 (fma B_m B_m (* A (* C -4.0))))
                          (t_1 (fma -4.0 (* A C) (* B_m B_m)))
                          (t_2 (* (* 4.0 A) C))
                          (t_3
                           (/
                            (sqrt
                             (*
                              (* 2.0 (* (- (pow B_m 2.0) t_2) F))
                              (+ (+ A C) (sqrt (+ (pow B_m 2.0) (pow (- A C) 2.0))))))
                            (- t_2 (pow B_m 2.0))))
                          (t_4 (fma 2.0 C (/ (* (* B_m B_m) -0.5) A)))
                          (t_5 (fma B_m B_m (* -4.0 (* A C)))))
                     (if (<= t_3 -5e+235)
                       (/ -1.0 (/ t_0 (* (sqrt (* t_4 t_1)) (sqrt (* 2.0 F)))))
                       (if (<= t_3 -1e-220)
                         (*
                          (/ (sqrt (* t_5 (* 2.0 F))) -1.0)
                          (/ (sqrt (+ (+ A C) (sqrt (fma (- A C) (- A C) (* B_m B_m))))) t_5))
                         (if (<= t_3 0.0)
                           (/ -1.0 (/ t_0 (* (sqrt F) (sqrt (* (* 2.0 t_4) t_1)))))
                           (if (<= t_3 INFINITY)
                             (*
                              (sqrt (* t_1 (* 2.0 F)))
                              (/ (sqrt t_4) (fma B_m (- B_m) (* 4.0 (* A C)))))
                             (* (- (sqrt F)) (sqrt (/ 2.0 B_m)))))))))
                  B_m = fabs(B);
                  assert(A < B_m && B_m < C && C < F);
                  double code(double A, double B_m, double C, double F) {
                  	double t_0 = fma(B_m, B_m, (A * (C * -4.0)));
                  	double t_1 = fma(-4.0, (A * C), (B_m * B_m));
                  	double t_2 = (4.0 * A) * C;
                  	double t_3 = sqrt(((2.0 * ((pow(B_m, 2.0) - t_2) * F)) * ((A + C) + sqrt((pow(B_m, 2.0) + pow((A - C), 2.0)))))) / (t_2 - pow(B_m, 2.0));
                  	double t_4 = fma(2.0, C, (((B_m * B_m) * -0.5) / A));
                  	double t_5 = fma(B_m, B_m, (-4.0 * (A * C)));
                  	double tmp;
                  	if (t_3 <= -5e+235) {
                  		tmp = -1.0 / (t_0 / (sqrt((t_4 * t_1)) * sqrt((2.0 * F))));
                  	} else if (t_3 <= -1e-220) {
                  		tmp = (sqrt((t_5 * (2.0 * F))) / -1.0) * (sqrt(((A + C) + sqrt(fma((A - C), (A - C), (B_m * B_m))))) / t_5);
                  	} else if (t_3 <= 0.0) {
                  		tmp = -1.0 / (t_0 / (sqrt(F) * sqrt(((2.0 * t_4) * t_1))));
                  	} else if (t_3 <= ((double) INFINITY)) {
                  		tmp = sqrt((t_1 * (2.0 * F))) * (sqrt(t_4) / fma(B_m, -B_m, (4.0 * (A * C))));
                  	} else {
                  		tmp = -sqrt(F) * sqrt((2.0 / B_m));
                  	}
                  	return tmp;
                  }
                  
                  B_m = abs(B)
                  A, B_m, C, F = sort([A, B_m, C, F])
                  function code(A, B_m, C, F)
                  	t_0 = fma(B_m, B_m, Float64(A * Float64(C * -4.0)))
                  	t_1 = fma(-4.0, Float64(A * C), Float64(B_m * B_m))
                  	t_2 = Float64(Float64(4.0 * A) * C)
                  	t_3 = Float64(sqrt(Float64(Float64(2.0 * Float64(Float64((B_m ^ 2.0) - t_2) * F)) * Float64(Float64(A + C) + sqrt(Float64((B_m ^ 2.0) + (Float64(A - C) ^ 2.0)))))) / Float64(t_2 - (B_m ^ 2.0)))
                  	t_4 = fma(2.0, C, Float64(Float64(Float64(B_m * B_m) * -0.5) / A))
                  	t_5 = fma(B_m, B_m, Float64(-4.0 * Float64(A * C)))
                  	tmp = 0.0
                  	if (t_3 <= -5e+235)
                  		tmp = Float64(-1.0 / Float64(t_0 / Float64(sqrt(Float64(t_4 * t_1)) * sqrt(Float64(2.0 * F)))));
                  	elseif (t_3 <= -1e-220)
                  		tmp = Float64(Float64(sqrt(Float64(t_5 * Float64(2.0 * F))) / -1.0) * Float64(sqrt(Float64(Float64(A + C) + sqrt(fma(Float64(A - C), Float64(A - C), Float64(B_m * B_m))))) / t_5));
                  	elseif (t_3 <= 0.0)
                  		tmp = Float64(-1.0 / Float64(t_0 / Float64(sqrt(F) * sqrt(Float64(Float64(2.0 * t_4) * t_1)))));
                  	elseif (t_3 <= Inf)
                  		tmp = Float64(sqrt(Float64(t_1 * Float64(2.0 * F))) * Float64(sqrt(t_4) / fma(B_m, Float64(-B_m), Float64(4.0 * Float64(A * C)))));
                  	else
                  		tmp = Float64(Float64(-sqrt(F)) * sqrt(Float64(2.0 / B_m)));
                  	end
                  	return tmp
                  end
                  
                  B_m = N[Abs[B], $MachinePrecision]
                  NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                  code[A_, B$95$m_, C_, F_] := Block[{t$95$0 = N[(B$95$m * B$95$m + N[(A * N[(C * -4.0), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$1 = N[(-4.0 * N[(A * C), $MachinePrecision] + N[(B$95$m * B$95$m), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$2 = N[(N[(4.0 * A), $MachinePrecision] * C), $MachinePrecision]}, Block[{t$95$3 = N[(N[Sqrt[N[(N[(2.0 * N[(N[(N[Power[B$95$m, 2.0], $MachinePrecision] - t$95$2), $MachinePrecision] * F), $MachinePrecision]), $MachinePrecision] * N[(N[(A + C), $MachinePrecision] + N[Sqrt[N[(N[Power[B$95$m, 2.0], $MachinePrecision] + N[Power[N[(A - C), $MachinePrecision], 2.0], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / N[(t$95$2 - N[Power[B$95$m, 2.0], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$4 = N[(2.0 * C + N[(N[(N[(B$95$m * B$95$m), $MachinePrecision] * -0.5), $MachinePrecision] / A), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$5 = N[(B$95$m * B$95$m + N[(-4.0 * N[(A * C), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[t$95$3, -5e+235], N[(-1.0 / N[(t$95$0 / N[(N[Sqrt[N[(t$95$4 * t$95$1), $MachinePrecision]], $MachinePrecision] * N[Sqrt[N[(2.0 * F), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], If[LessEqual[t$95$3, -1e-220], N[(N[(N[Sqrt[N[(t$95$5 * N[(2.0 * F), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / -1.0), $MachinePrecision] * N[(N[Sqrt[N[(N[(A + C), $MachinePrecision] + N[Sqrt[N[(N[(A - C), $MachinePrecision] * N[(A - C), $MachinePrecision] + N[(B$95$m * B$95$m), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / t$95$5), $MachinePrecision]), $MachinePrecision], If[LessEqual[t$95$3, 0.0], N[(-1.0 / N[(t$95$0 / N[(N[Sqrt[F], $MachinePrecision] * N[Sqrt[N[(N[(2.0 * t$95$4), $MachinePrecision] * t$95$1), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], If[LessEqual[t$95$3, Infinity], N[(N[Sqrt[N[(t$95$1 * N[(2.0 * F), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] * N[(N[Sqrt[t$95$4], $MachinePrecision] / N[(B$95$m * (-B$95$m) + N[(4.0 * N[(A * C), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], N[((-N[Sqrt[F], $MachinePrecision]) * N[Sqrt[N[(2.0 / B$95$m), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]]]]]]]]]]]
                  
                  \begin{array}{l}
                  B_m = \left|B\right|
                  \\
                  [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
                  \\
                  \begin{array}{l}
                  t_0 := \mathsf{fma}\left(B\_m, B\_m, A \cdot \left(C \cdot -4\right)\right)\\
                  t_1 := \mathsf{fma}\left(-4, A \cdot C, B\_m \cdot B\_m\right)\\
                  t_2 := \left(4 \cdot A\right) \cdot C\\
                  t_3 := \frac{\sqrt{\left(2 \cdot \left(\left({B\_m}^{2} - t\_2\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{B\_m}^{2} + {\left(A - C\right)}^{2}}\right)}}{t\_2 - {B\_m}^{2}}\\
                  t_4 := \mathsf{fma}\left(2, C, \frac{\left(B\_m \cdot B\_m\right) \cdot -0.5}{A}\right)\\
                  t_5 := \mathsf{fma}\left(B\_m, B\_m, -4 \cdot \left(A \cdot C\right)\right)\\
                  \mathbf{if}\;t\_3 \leq -5 \cdot 10^{+235}:\\
                  \;\;\;\;\frac{-1}{\frac{t\_0}{\sqrt{t\_4 \cdot t\_1} \cdot \sqrt{2 \cdot F}}}\\
                  
                  \mathbf{elif}\;t\_3 \leq -1 \cdot 10^{-220}:\\
                  \;\;\;\;\frac{\sqrt{t\_5 \cdot \left(2 \cdot F\right)}}{-1} \cdot \frac{\sqrt{\left(A + C\right) + \sqrt{\mathsf{fma}\left(A - C, A - C, B\_m \cdot B\_m\right)}}}{t\_5}\\
                  
                  \mathbf{elif}\;t\_3 \leq 0:\\
                  \;\;\;\;\frac{-1}{\frac{t\_0}{\sqrt{F} \cdot \sqrt{\left(2 \cdot t\_4\right) \cdot t\_1}}}\\
                  
                  \mathbf{elif}\;t\_3 \leq \infty:\\
                  \;\;\;\;\sqrt{t\_1 \cdot \left(2 \cdot F\right)} \cdot \frac{\sqrt{t\_4}}{\mathsf{fma}\left(B\_m, -B\_m, 4 \cdot \left(A \cdot C\right)\right)}\\
                  
                  \mathbf{else}:\\
                  \;\;\;\;\left(-\sqrt{F}\right) \cdot \sqrt{\frac{2}{B\_m}}\\
                  
                  
                  \end{array}
                  \end{array}
                  
                  Derivation
                  1. Split input into 5 regimes
                  2. if (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C))) < -5.00000000000000027e235

                    1. Initial program 6.0%

                      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                    2. Add Preprocessing
                    3. Taylor expanded in A around -inf

                      \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\left(\frac{-1}{2} \cdot \frac{{B}^{2}}{A} + 2 \cdot C\right)}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                    4. Step-by-step derivation
                      1. +-commutativeN/A

                        \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\left(2 \cdot C + \frac{-1}{2} \cdot \frac{{B}^{2}}{A}\right)}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                      2. lower-fma.f64N/A

                        \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\mathsf{fma}\left(2, C, \frac{-1}{2} \cdot \frac{{B}^{2}}{A}\right)}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                      3. associate-*r/N/A

                        \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(2, C, \color{blue}{\frac{\frac{-1}{2} \cdot {B}^{2}}{A}}\right)}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                      4. lower-/.f64N/A

                        \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(2, C, \color{blue}{\frac{\frac{-1}{2} \cdot {B}^{2}}{A}}\right)}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                      5. lower-*.f64N/A

                        \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(2, C, \frac{\color{blue}{\frac{-1}{2} \cdot {B}^{2}}}{A}\right)}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                      6. unpow2N/A

                        \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(2, C, \frac{\frac{-1}{2} \cdot \color{blue}{\left(B \cdot B\right)}}{A}\right)}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                      7. lower-*.f648.5

                        \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(2, C, \frac{-0.5 \cdot \color{blue}{\left(B \cdot B\right)}}{A}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                    5. Applied rewrites8.5%

                      \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\mathsf{fma}\left(2, C, \frac{-0.5 \cdot \left(B \cdot B\right)}{A}\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                    6. Applied rewrites8.5%

                      \[\leadsto \color{blue}{\frac{1}{\frac{-\mathsf{fma}\left(B, B, \left(-4 \cdot C\right) \cdot A\right)}{\sqrt{\left(\mathsf{fma}\left(B, B, \left(-4 \cdot C\right) \cdot A\right) \cdot \left(F \cdot 2\right)\right) \cdot \mathsf{fma}\left(2, C, \frac{\left(B \cdot B\right) \cdot -0.5}{A}\right)}}}} \]
                    7. Step-by-step derivation
                      1. lift-sqrt.f64N/A

                        \[\leadsto \frac{1}{\frac{\mathsf{neg}\left(\mathsf{fma}\left(B, B, \left(-4 \cdot C\right) \cdot A\right)\right)}{\color{blue}{\sqrt{\left(\mathsf{fma}\left(B, B, \left(-4 \cdot C\right) \cdot A\right) \cdot \left(F \cdot 2\right)\right) \cdot \mathsf{fma}\left(2, C, \frac{\left(B \cdot B\right) \cdot \frac{-1}{2}}{A}\right)}}}} \]
                      2. lift-*.f64N/A

                        \[\leadsto \frac{1}{\frac{\mathsf{neg}\left(\mathsf{fma}\left(B, B, \left(-4 \cdot C\right) \cdot A\right)\right)}{\sqrt{\color{blue}{\left(\mathsf{fma}\left(B, B, \left(-4 \cdot C\right) \cdot A\right) \cdot \left(F \cdot 2\right)\right) \cdot \mathsf{fma}\left(2, C, \frac{\left(B \cdot B\right) \cdot \frac{-1}{2}}{A}\right)}}}} \]
                      3. *-commutativeN/A

                        \[\leadsto \frac{1}{\frac{\mathsf{neg}\left(\mathsf{fma}\left(B, B, \left(-4 \cdot C\right) \cdot A\right)\right)}{\sqrt{\color{blue}{\mathsf{fma}\left(2, C, \frac{\left(B \cdot B\right) \cdot \frac{-1}{2}}{A}\right) \cdot \left(\mathsf{fma}\left(B, B, \left(-4 \cdot C\right) \cdot A\right) \cdot \left(F \cdot 2\right)\right)}}}} \]
                      4. lift-*.f64N/A

                        \[\leadsto \frac{1}{\frac{\mathsf{neg}\left(\mathsf{fma}\left(B, B, \left(-4 \cdot C\right) \cdot A\right)\right)}{\sqrt{\mathsf{fma}\left(2, C, \frac{\left(B \cdot B\right) \cdot \frac{-1}{2}}{A}\right) \cdot \color{blue}{\left(\mathsf{fma}\left(B, B, \left(-4 \cdot C\right) \cdot A\right) \cdot \left(F \cdot 2\right)\right)}}}} \]
                      5. associate-*r*N/A

                        \[\leadsto \frac{1}{\frac{\mathsf{neg}\left(\mathsf{fma}\left(B, B, \left(-4 \cdot C\right) \cdot A\right)\right)}{\sqrt{\color{blue}{\left(\mathsf{fma}\left(2, C, \frac{\left(B \cdot B\right) \cdot \frac{-1}{2}}{A}\right) \cdot \mathsf{fma}\left(B, B, \left(-4 \cdot C\right) \cdot A\right)\right) \cdot \left(F \cdot 2\right)}}}} \]
                      6. sqrt-prodN/A

                        \[\leadsto \frac{1}{\frac{\mathsf{neg}\left(\mathsf{fma}\left(B, B, \left(-4 \cdot C\right) \cdot A\right)\right)}{\color{blue}{\sqrt{\mathsf{fma}\left(2, C, \frac{\left(B \cdot B\right) \cdot \frac{-1}{2}}{A}\right) \cdot \mathsf{fma}\left(B, B, \left(-4 \cdot C\right) \cdot A\right)} \cdot \sqrt{F \cdot 2}}}} \]
                    8. Applied rewrites17.7%

                      \[\leadsto \frac{1}{\frac{-\mathsf{fma}\left(B, B, \left(-4 \cdot C\right) \cdot A\right)}{\color{blue}{\sqrt{\mathsf{fma}\left(2, C, \frac{\left(B \cdot B\right) \cdot -0.5}{A}\right) \cdot \mathsf{fma}\left(-4, A \cdot C, B \cdot B\right)} \cdot \sqrt{2 \cdot F}}}} \]

                    if -5.00000000000000027e235 < (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C))) < -9.99999999999999992e-221

                    1. Initial program 98.5%

                      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                    2. Add Preprocessing
                    3. Applied rewrites98.8%

                      \[\leadsto \color{blue}{\frac{\sqrt{\mathsf{fma}\left(B, B, -4 \cdot \left(A \cdot C\right)\right) \cdot \left(F \cdot 2\right)}}{-1} \cdot \frac{\sqrt{\sqrt{\mathsf{fma}\left(A - C, A - C, B \cdot B\right)} + \left(A + C\right)}}{\mathsf{fma}\left(B, B, -4 \cdot \left(A \cdot C\right)\right)}} \]

                    if -9.99999999999999992e-221 < (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C))) < -0.0

                    1. Initial program 3.8%

                      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                    2. Add Preprocessing
                    3. Taylor expanded in A around -inf

                      \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\left(\frac{-1}{2} \cdot \frac{{B}^{2}}{A} + 2 \cdot C\right)}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                    4. Step-by-step derivation
                      1. +-commutativeN/A

                        \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\left(2 \cdot C + \frac{-1}{2} \cdot \frac{{B}^{2}}{A}\right)}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                      2. lower-fma.f64N/A

                        \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\mathsf{fma}\left(2, C, \frac{-1}{2} \cdot \frac{{B}^{2}}{A}\right)}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                      3. associate-*r/N/A

                        \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(2, C, \color{blue}{\frac{\frac{-1}{2} \cdot {B}^{2}}{A}}\right)}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                      4. lower-/.f64N/A

                        \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(2, C, \color{blue}{\frac{\frac{-1}{2} \cdot {B}^{2}}{A}}\right)}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                      5. lower-*.f64N/A

                        \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(2, C, \frac{\color{blue}{\frac{-1}{2} \cdot {B}^{2}}}{A}\right)}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                      6. unpow2N/A

                        \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(2, C, \frac{\frac{-1}{2} \cdot \color{blue}{\left(B \cdot B\right)}}{A}\right)}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                      7. lower-*.f6422.3

                        \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(2, C, \frac{-0.5 \cdot \color{blue}{\left(B \cdot B\right)}}{A}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                    5. Applied rewrites22.3%

                      \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\mathsf{fma}\left(2, C, \frac{-0.5 \cdot \left(B \cdot B\right)}{A}\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                    6. Applied rewrites22.2%

                      \[\leadsto \color{blue}{\frac{1}{\frac{-\mathsf{fma}\left(B, B, \left(-4 \cdot C\right) \cdot A\right)}{\sqrt{\left(\mathsf{fma}\left(B, B, \left(-4 \cdot C\right) \cdot A\right) \cdot \left(F \cdot 2\right)\right) \cdot \mathsf{fma}\left(2, C, \frac{\left(B \cdot B\right) \cdot -0.5}{A}\right)}}}} \]
                    7. Step-by-step derivation
                      1. lift-sqrt.f64N/A

                        \[\leadsto \frac{1}{\frac{\mathsf{neg}\left(\mathsf{fma}\left(B, B, \left(-4 \cdot C\right) \cdot A\right)\right)}{\color{blue}{\sqrt{\left(\mathsf{fma}\left(B, B, \left(-4 \cdot C\right) \cdot A\right) \cdot \left(F \cdot 2\right)\right) \cdot \mathsf{fma}\left(2, C, \frac{\left(B \cdot B\right) \cdot \frac{-1}{2}}{A}\right)}}}} \]
                      2. lift-*.f64N/A

                        \[\leadsto \frac{1}{\frac{\mathsf{neg}\left(\mathsf{fma}\left(B, B, \left(-4 \cdot C\right) \cdot A\right)\right)}{\sqrt{\color{blue}{\left(\mathsf{fma}\left(B, B, \left(-4 \cdot C\right) \cdot A\right) \cdot \left(F \cdot 2\right)\right) \cdot \mathsf{fma}\left(2, C, \frac{\left(B \cdot B\right) \cdot \frac{-1}{2}}{A}\right)}}}} \]
                      3. lift-*.f64N/A

                        \[\leadsto \frac{1}{\frac{\mathsf{neg}\left(\mathsf{fma}\left(B, B, \left(-4 \cdot C\right) \cdot A\right)\right)}{\sqrt{\color{blue}{\left(\mathsf{fma}\left(B, B, \left(-4 \cdot C\right) \cdot A\right) \cdot \left(F \cdot 2\right)\right)} \cdot \mathsf{fma}\left(2, C, \frac{\left(B \cdot B\right) \cdot \frac{-1}{2}}{A}\right)}}} \]
                      4. lift-*.f64N/A

                        \[\leadsto \frac{1}{\frac{\mathsf{neg}\left(\mathsf{fma}\left(B, B, \left(-4 \cdot C\right) \cdot A\right)\right)}{\sqrt{\left(\mathsf{fma}\left(B, B, \left(-4 \cdot C\right) \cdot A\right) \cdot \color{blue}{\left(F \cdot 2\right)}\right) \cdot \mathsf{fma}\left(2, C, \frac{\left(B \cdot B\right) \cdot \frac{-1}{2}}{A}\right)}}} \]
                      5. associate-*r*N/A

                        \[\leadsto \frac{1}{\frac{\mathsf{neg}\left(\mathsf{fma}\left(B, B, \left(-4 \cdot C\right) \cdot A\right)\right)}{\sqrt{\color{blue}{\left(\left(\mathsf{fma}\left(B, B, \left(-4 \cdot C\right) \cdot A\right) \cdot F\right) \cdot 2\right)} \cdot \mathsf{fma}\left(2, C, \frac{\left(B \cdot B\right) \cdot \frac{-1}{2}}{A}\right)}}} \]
                      6. *-commutativeN/A

                        \[\leadsto \frac{1}{\frac{\mathsf{neg}\left(\mathsf{fma}\left(B, B, \left(-4 \cdot C\right) \cdot A\right)\right)}{\sqrt{\left(\color{blue}{\left(F \cdot \mathsf{fma}\left(B, B, \left(-4 \cdot C\right) \cdot A\right)\right)} \cdot 2\right) \cdot \mathsf{fma}\left(2, C, \frac{\left(B \cdot B\right) \cdot \frac{-1}{2}}{A}\right)}}} \]
                      7. lift-*.f64N/A

                        \[\leadsto \frac{1}{\frac{\mathsf{neg}\left(\mathsf{fma}\left(B, B, \left(-4 \cdot C\right) \cdot A\right)\right)}{\sqrt{\left(\color{blue}{\left(F \cdot \mathsf{fma}\left(B, B, \left(-4 \cdot C\right) \cdot A\right)\right)} \cdot 2\right) \cdot \mathsf{fma}\left(2, C, \frac{\left(B \cdot B\right) \cdot \frac{-1}{2}}{A}\right)}}} \]
                      8. associate-*l*N/A

                        \[\leadsto \frac{1}{\frac{\mathsf{neg}\left(\mathsf{fma}\left(B, B, \left(-4 \cdot C\right) \cdot A\right)\right)}{\sqrt{\color{blue}{\left(F \cdot \mathsf{fma}\left(B, B, \left(-4 \cdot C\right) \cdot A\right)\right) \cdot \left(2 \cdot \mathsf{fma}\left(2, C, \frac{\left(B \cdot B\right) \cdot \frac{-1}{2}}{A}\right)\right)}}}} \]
                      9. *-commutativeN/A

                        \[\leadsto \frac{1}{\frac{\mathsf{neg}\left(\mathsf{fma}\left(B, B, \left(-4 \cdot C\right) \cdot A\right)\right)}{\sqrt{\left(F \cdot \mathsf{fma}\left(B, B, \left(-4 \cdot C\right) \cdot A\right)\right) \cdot \color{blue}{\left(\mathsf{fma}\left(2, C, \frac{\left(B \cdot B\right) \cdot \frac{-1}{2}}{A}\right) \cdot 2\right)}}}} \]
                    8. Applied rewrites27.3%

                      \[\leadsto \frac{1}{\frac{-\mathsf{fma}\left(B, B, \left(-4 \cdot C\right) \cdot A\right)}{\color{blue}{\sqrt{\left(2 \cdot \mathsf{fma}\left(2, C, \frac{\left(B \cdot B\right) \cdot -0.5}{A}\right)\right) \cdot \mathsf{fma}\left(-4, A \cdot C, B \cdot B\right)} \cdot \sqrt{F}}}} \]

                    if -0.0 < (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C))) < +inf.0

                    1. Initial program 48.9%

                      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                    2. Add Preprocessing
                    3. Taylor expanded in A around -inf

                      \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\left(\frac{-1}{2} \cdot \frac{{B}^{2}}{A} + 2 \cdot C\right)}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                    4. Step-by-step derivation
                      1. +-commutativeN/A

                        \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\left(2 \cdot C + \frac{-1}{2} \cdot \frac{{B}^{2}}{A}\right)}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                      2. lower-fma.f64N/A

                        \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\mathsf{fma}\left(2, C, \frac{-1}{2} \cdot \frac{{B}^{2}}{A}\right)}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                      3. associate-*r/N/A

                        \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(2, C, \color{blue}{\frac{\frac{-1}{2} \cdot {B}^{2}}{A}}\right)}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                      4. lower-/.f64N/A

                        \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(2, C, \color{blue}{\frac{\frac{-1}{2} \cdot {B}^{2}}{A}}\right)}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                      5. lower-*.f64N/A

                        \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(2, C, \frac{\color{blue}{\frac{-1}{2} \cdot {B}^{2}}}{A}\right)}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                      6. unpow2N/A

                        \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(2, C, \frac{\frac{-1}{2} \cdot \color{blue}{\left(B \cdot B\right)}}{A}\right)}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                      7. lower-*.f6431.5

                        \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(2, C, \frac{-0.5 \cdot \color{blue}{\left(B \cdot B\right)}}{A}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                    5. Applied rewrites31.5%

                      \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\mathsf{fma}\left(2, C, \frac{-0.5 \cdot \left(B \cdot B\right)}{A}\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                    6. Applied rewrites31.4%

                      \[\leadsto \color{blue}{\frac{1}{\frac{-\mathsf{fma}\left(B, B, \left(-4 \cdot C\right) \cdot A\right)}{\sqrt{\left(\mathsf{fma}\left(B, B, \left(-4 \cdot C\right) \cdot A\right) \cdot \left(F \cdot 2\right)\right) \cdot \mathsf{fma}\left(2, C, \frac{\left(B \cdot B\right) \cdot -0.5}{A}\right)}}}} \]
                    7. Applied rewrites37.0%

                      \[\leadsto \color{blue}{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, A \cdot C, B \cdot B\right)} \cdot \frac{\sqrt{\mathsf{fma}\left(2, C, \frac{\left(B \cdot B\right) \cdot -0.5}{A}\right)}}{\mathsf{fma}\left(B, -B, 4 \cdot \left(A \cdot C\right)\right)}} \]

                    if +inf.0 < (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)))

                    1. Initial program 0.0%

                      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                    2. Add Preprocessing
                    3. Taylor expanded in B around inf

                      \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                    4. Step-by-step derivation
                      1. mul-1-negN/A

                        \[\leadsto \color{blue}{\mathsf{neg}\left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                      2. lower-neg.f64N/A

                        \[\leadsto \color{blue}{\mathsf{neg}\left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                      3. *-commutativeN/A

                        \[\leadsto \mathsf{neg}\left(\color{blue}{\sqrt{2} \cdot \sqrt{\frac{F}{B}}}\right) \]
                      4. lower-*.f64N/A

                        \[\leadsto \mathsf{neg}\left(\color{blue}{\sqrt{2} \cdot \sqrt{\frac{F}{B}}}\right) \]
                      5. lower-sqrt.f64N/A

                        \[\leadsto \mathsf{neg}\left(\color{blue}{\sqrt{2}} \cdot \sqrt{\frac{F}{B}}\right) \]
                      6. lower-sqrt.f64N/A

                        \[\leadsto \mathsf{neg}\left(\sqrt{2} \cdot \color{blue}{\sqrt{\frac{F}{B}}}\right) \]
                      7. lower-/.f6420.0

                        \[\leadsto -\sqrt{2} \cdot \sqrt{\color{blue}{\frac{F}{B}}} \]
                    5. Applied rewrites20.0%

                      \[\leadsto \color{blue}{-\sqrt{2} \cdot \sqrt{\frac{F}{B}}} \]
                    6. Step-by-step derivation
                      1. Applied rewrites29.6%

                        \[\leadsto -\frac{\sqrt{F \cdot 2}}{\sqrt{B}} \]
                      2. Step-by-step derivation
                        1. Applied rewrites29.6%

                          \[\leadsto -\sqrt{F} \cdot \sqrt{\frac{2}{B}} \]
                      3. Recombined 5 regimes into one program.
                      4. Final simplification36.8%

                        \[\leadsto \begin{array}{l} \mathbf{if}\;\frac{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)}}{\left(4 \cdot A\right) \cdot C - {B}^{2}} \leq -5 \cdot 10^{+235}:\\ \;\;\;\;\frac{-1}{\frac{\mathsf{fma}\left(B, B, A \cdot \left(C \cdot -4\right)\right)}{\sqrt{\mathsf{fma}\left(2, C, \frac{\left(B \cdot B\right) \cdot -0.5}{A}\right) \cdot \mathsf{fma}\left(-4, A \cdot C, B \cdot B\right)} \cdot \sqrt{2 \cdot F}}}\\ \mathbf{elif}\;\frac{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)}}{\left(4 \cdot A\right) \cdot C - {B}^{2}} \leq -1 \cdot 10^{-220}:\\ \;\;\;\;\frac{\sqrt{\mathsf{fma}\left(B, B, -4 \cdot \left(A \cdot C\right)\right) \cdot \left(2 \cdot F\right)}}{-1} \cdot \frac{\sqrt{\left(A + C\right) + \sqrt{\mathsf{fma}\left(A - C, A - C, B \cdot B\right)}}}{\mathsf{fma}\left(B, B, -4 \cdot \left(A \cdot C\right)\right)}\\ \mathbf{elif}\;\frac{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)}}{\left(4 \cdot A\right) \cdot C - {B}^{2}} \leq 0:\\ \;\;\;\;\frac{-1}{\frac{\mathsf{fma}\left(B, B, A \cdot \left(C \cdot -4\right)\right)}{\sqrt{F} \cdot \sqrt{\left(2 \cdot \mathsf{fma}\left(2, C, \frac{\left(B \cdot B\right) \cdot -0.5}{A}\right)\right) \cdot \mathsf{fma}\left(-4, A \cdot C, B \cdot B\right)}}}\\ \mathbf{elif}\;\frac{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)}}{\left(4 \cdot A\right) \cdot C - {B}^{2}} \leq \infty:\\ \;\;\;\;\sqrt{\mathsf{fma}\left(-4, A \cdot C, B \cdot B\right) \cdot \left(2 \cdot F\right)} \cdot \frac{\sqrt{\mathsf{fma}\left(2, C, \frac{\left(B \cdot B\right) \cdot -0.5}{A}\right)}}{\mathsf{fma}\left(B, -B, 4 \cdot \left(A \cdot C\right)\right)}\\ \mathbf{else}:\\ \;\;\;\;\left(-\sqrt{F}\right) \cdot \sqrt{\frac{2}{B}}\\ \end{array} \]
                      5. Add Preprocessing

                      Alternative 6: 58.1% accurate, 0.2× speedup?

                      \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} t_0 := \mathsf{fma}\left(B\_m, B\_m, A \cdot \left(C \cdot -4\right)\right)\\ t_1 := \mathsf{fma}\left(-4, A \cdot C, B\_m \cdot B\_m\right)\\ t_2 := \left(4 \cdot A\right) \cdot C\\ t_3 := \frac{\sqrt{\left(2 \cdot \left(\left({B\_m}^{2} - t\_2\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{B\_m}^{2} + {\left(A - C\right)}^{2}}\right)}}{t\_2 - {B\_m}^{2}}\\ t_4 := \mathsf{fma}\left(2, C, \frac{\left(B\_m \cdot B\_m\right) \cdot -0.5}{A}\right)\\ t_5 := \mathsf{fma}\left(B\_m, B\_m, -4 \cdot \left(A \cdot C\right)\right)\\ \mathbf{if}\;t\_3 \leq -\infty:\\ \;\;\;\;\frac{-1}{\frac{t\_0}{\sqrt{t\_4 \cdot t\_1} \cdot \sqrt{2 \cdot F}}}\\ \mathbf{elif}\;t\_3 \leq -1 \cdot 10^{-220}:\\ \;\;\;\;\sqrt{\left(t\_5 \cdot \left(2 \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{\mathsf{fma}\left(A - C, A - C, B\_m \cdot B\_m\right)}\right)} \cdot \frac{-1}{t\_5}\\ \mathbf{elif}\;t\_3 \leq 0:\\ \;\;\;\;\frac{-1}{\frac{t\_0}{\sqrt{F} \cdot \sqrt{\left(2 \cdot t\_4\right) \cdot t\_1}}}\\ \mathbf{elif}\;t\_3 \leq \infty:\\ \;\;\;\;\sqrt{t\_1 \cdot \left(2 \cdot F\right)} \cdot \frac{\sqrt{t\_4}}{\mathsf{fma}\left(B\_m, -B\_m, 4 \cdot \left(A \cdot C\right)\right)}\\ \mathbf{else}:\\ \;\;\;\;\left(-\sqrt{F}\right) \cdot \sqrt{\frac{2}{B\_m}}\\ \end{array} \end{array} \]
                      B_m = (fabs.f64 B)
                      NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                      (FPCore (A B_m C F)
                       :precision binary64
                       (let* ((t_0 (fma B_m B_m (* A (* C -4.0))))
                              (t_1 (fma -4.0 (* A C) (* B_m B_m)))
                              (t_2 (* (* 4.0 A) C))
                              (t_3
                               (/
                                (sqrt
                                 (*
                                  (* 2.0 (* (- (pow B_m 2.0) t_2) F))
                                  (+ (+ A C) (sqrt (+ (pow B_m 2.0) (pow (- A C) 2.0))))))
                                (- t_2 (pow B_m 2.0))))
                              (t_4 (fma 2.0 C (/ (* (* B_m B_m) -0.5) A)))
                              (t_5 (fma B_m B_m (* -4.0 (* A C)))))
                         (if (<= t_3 (- INFINITY))
                           (/ -1.0 (/ t_0 (* (sqrt (* t_4 t_1)) (sqrt (* 2.0 F)))))
                           (if (<= t_3 -1e-220)
                             (*
                              (sqrt
                               (*
                                (* t_5 (* 2.0 F))
                                (+ (+ A C) (sqrt (fma (- A C) (- A C) (* B_m B_m))))))
                              (/ -1.0 t_5))
                             (if (<= t_3 0.0)
                               (/ -1.0 (/ t_0 (* (sqrt F) (sqrt (* (* 2.0 t_4) t_1)))))
                               (if (<= t_3 INFINITY)
                                 (*
                                  (sqrt (* t_1 (* 2.0 F)))
                                  (/ (sqrt t_4) (fma B_m (- B_m) (* 4.0 (* A C)))))
                                 (* (- (sqrt F)) (sqrt (/ 2.0 B_m)))))))))
                      B_m = fabs(B);
                      assert(A < B_m && B_m < C && C < F);
                      double code(double A, double B_m, double C, double F) {
                      	double t_0 = fma(B_m, B_m, (A * (C * -4.0)));
                      	double t_1 = fma(-4.0, (A * C), (B_m * B_m));
                      	double t_2 = (4.0 * A) * C;
                      	double t_3 = sqrt(((2.0 * ((pow(B_m, 2.0) - t_2) * F)) * ((A + C) + sqrt((pow(B_m, 2.0) + pow((A - C), 2.0)))))) / (t_2 - pow(B_m, 2.0));
                      	double t_4 = fma(2.0, C, (((B_m * B_m) * -0.5) / A));
                      	double t_5 = fma(B_m, B_m, (-4.0 * (A * C)));
                      	double tmp;
                      	if (t_3 <= -((double) INFINITY)) {
                      		tmp = -1.0 / (t_0 / (sqrt((t_4 * t_1)) * sqrt((2.0 * F))));
                      	} else if (t_3 <= -1e-220) {
                      		tmp = sqrt(((t_5 * (2.0 * F)) * ((A + C) + sqrt(fma((A - C), (A - C), (B_m * B_m)))))) * (-1.0 / t_5);
                      	} else if (t_3 <= 0.0) {
                      		tmp = -1.0 / (t_0 / (sqrt(F) * sqrt(((2.0 * t_4) * t_1))));
                      	} else if (t_3 <= ((double) INFINITY)) {
                      		tmp = sqrt((t_1 * (2.0 * F))) * (sqrt(t_4) / fma(B_m, -B_m, (4.0 * (A * C))));
                      	} else {
                      		tmp = -sqrt(F) * sqrt((2.0 / B_m));
                      	}
                      	return tmp;
                      }
                      
                      B_m = abs(B)
                      A, B_m, C, F = sort([A, B_m, C, F])
                      function code(A, B_m, C, F)
                      	t_0 = fma(B_m, B_m, Float64(A * Float64(C * -4.0)))
                      	t_1 = fma(-4.0, Float64(A * C), Float64(B_m * B_m))
                      	t_2 = Float64(Float64(4.0 * A) * C)
                      	t_3 = Float64(sqrt(Float64(Float64(2.0 * Float64(Float64((B_m ^ 2.0) - t_2) * F)) * Float64(Float64(A + C) + sqrt(Float64((B_m ^ 2.0) + (Float64(A - C) ^ 2.0)))))) / Float64(t_2 - (B_m ^ 2.0)))
                      	t_4 = fma(2.0, C, Float64(Float64(Float64(B_m * B_m) * -0.5) / A))
                      	t_5 = fma(B_m, B_m, Float64(-4.0 * Float64(A * C)))
                      	tmp = 0.0
                      	if (t_3 <= Float64(-Inf))
                      		tmp = Float64(-1.0 / Float64(t_0 / Float64(sqrt(Float64(t_4 * t_1)) * sqrt(Float64(2.0 * F)))));
                      	elseif (t_3 <= -1e-220)
                      		tmp = Float64(sqrt(Float64(Float64(t_5 * Float64(2.0 * F)) * Float64(Float64(A + C) + sqrt(fma(Float64(A - C), Float64(A - C), Float64(B_m * B_m)))))) * Float64(-1.0 / t_5));
                      	elseif (t_3 <= 0.0)
                      		tmp = Float64(-1.0 / Float64(t_0 / Float64(sqrt(F) * sqrt(Float64(Float64(2.0 * t_4) * t_1)))));
                      	elseif (t_3 <= Inf)
                      		tmp = Float64(sqrt(Float64(t_1 * Float64(2.0 * F))) * Float64(sqrt(t_4) / fma(B_m, Float64(-B_m), Float64(4.0 * Float64(A * C)))));
                      	else
                      		tmp = Float64(Float64(-sqrt(F)) * sqrt(Float64(2.0 / B_m)));
                      	end
                      	return tmp
                      end
                      
                      B_m = N[Abs[B], $MachinePrecision]
                      NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                      code[A_, B$95$m_, C_, F_] := Block[{t$95$0 = N[(B$95$m * B$95$m + N[(A * N[(C * -4.0), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$1 = N[(-4.0 * N[(A * C), $MachinePrecision] + N[(B$95$m * B$95$m), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$2 = N[(N[(4.0 * A), $MachinePrecision] * C), $MachinePrecision]}, Block[{t$95$3 = N[(N[Sqrt[N[(N[(2.0 * N[(N[(N[Power[B$95$m, 2.0], $MachinePrecision] - t$95$2), $MachinePrecision] * F), $MachinePrecision]), $MachinePrecision] * N[(N[(A + C), $MachinePrecision] + N[Sqrt[N[(N[Power[B$95$m, 2.0], $MachinePrecision] + N[Power[N[(A - C), $MachinePrecision], 2.0], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / N[(t$95$2 - N[Power[B$95$m, 2.0], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$4 = N[(2.0 * C + N[(N[(N[(B$95$m * B$95$m), $MachinePrecision] * -0.5), $MachinePrecision] / A), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$5 = N[(B$95$m * B$95$m + N[(-4.0 * N[(A * C), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[t$95$3, (-Infinity)], N[(-1.0 / N[(t$95$0 / N[(N[Sqrt[N[(t$95$4 * t$95$1), $MachinePrecision]], $MachinePrecision] * N[Sqrt[N[(2.0 * F), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], If[LessEqual[t$95$3, -1e-220], N[(N[Sqrt[N[(N[(t$95$5 * N[(2.0 * F), $MachinePrecision]), $MachinePrecision] * N[(N[(A + C), $MachinePrecision] + N[Sqrt[N[(N[(A - C), $MachinePrecision] * N[(A - C), $MachinePrecision] + N[(B$95$m * B$95$m), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] * N[(-1.0 / t$95$5), $MachinePrecision]), $MachinePrecision], If[LessEqual[t$95$3, 0.0], N[(-1.0 / N[(t$95$0 / N[(N[Sqrt[F], $MachinePrecision] * N[Sqrt[N[(N[(2.0 * t$95$4), $MachinePrecision] * t$95$1), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], If[LessEqual[t$95$3, Infinity], N[(N[Sqrt[N[(t$95$1 * N[(2.0 * F), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] * N[(N[Sqrt[t$95$4], $MachinePrecision] / N[(B$95$m * (-B$95$m) + N[(4.0 * N[(A * C), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], N[((-N[Sqrt[F], $MachinePrecision]) * N[Sqrt[N[(2.0 / B$95$m), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]]]]]]]]]]]
                      
                      \begin{array}{l}
                      B_m = \left|B\right|
                      \\
                      [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
                      \\
                      \begin{array}{l}
                      t_0 := \mathsf{fma}\left(B\_m, B\_m, A \cdot \left(C \cdot -4\right)\right)\\
                      t_1 := \mathsf{fma}\left(-4, A \cdot C, B\_m \cdot B\_m\right)\\
                      t_2 := \left(4 \cdot A\right) \cdot C\\
                      t_3 := \frac{\sqrt{\left(2 \cdot \left(\left({B\_m}^{2} - t\_2\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{B\_m}^{2} + {\left(A - C\right)}^{2}}\right)}}{t\_2 - {B\_m}^{2}}\\
                      t_4 := \mathsf{fma}\left(2, C, \frac{\left(B\_m \cdot B\_m\right) \cdot -0.5}{A}\right)\\
                      t_5 := \mathsf{fma}\left(B\_m, B\_m, -4 \cdot \left(A \cdot C\right)\right)\\
                      \mathbf{if}\;t\_3 \leq -\infty:\\
                      \;\;\;\;\frac{-1}{\frac{t\_0}{\sqrt{t\_4 \cdot t\_1} \cdot \sqrt{2 \cdot F}}}\\
                      
                      \mathbf{elif}\;t\_3 \leq -1 \cdot 10^{-220}:\\
                      \;\;\;\;\sqrt{\left(t\_5 \cdot \left(2 \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{\mathsf{fma}\left(A - C, A - C, B\_m \cdot B\_m\right)}\right)} \cdot \frac{-1}{t\_5}\\
                      
                      \mathbf{elif}\;t\_3 \leq 0:\\
                      \;\;\;\;\frac{-1}{\frac{t\_0}{\sqrt{F} \cdot \sqrt{\left(2 \cdot t\_4\right) \cdot t\_1}}}\\
                      
                      \mathbf{elif}\;t\_3 \leq \infty:\\
                      \;\;\;\;\sqrt{t\_1 \cdot \left(2 \cdot F\right)} \cdot \frac{\sqrt{t\_4}}{\mathsf{fma}\left(B\_m, -B\_m, 4 \cdot \left(A \cdot C\right)\right)}\\
                      
                      \mathbf{else}:\\
                      \;\;\;\;\left(-\sqrt{F}\right) \cdot \sqrt{\frac{2}{B\_m}}\\
                      
                      
                      \end{array}
                      \end{array}
                      
                      Derivation
                      1. Split input into 5 regimes
                      2. if (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C))) < -inf.0

                        1. Initial program 3.6%

                          \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                        2. Add Preprocessing
                        3. Taylor expanded in A around -inf

                          \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\left(\frac{-1}{2} \cdot \frac{{B}^{2}}{A} + 2 \cdot C\right)}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                        4. Step-by-step derivation
                          1. +-commutativeN/A

                            \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\left(2 \cdot C + \frac{-1}{2} \cdot \frac{{B}^{2}}{A}\right)}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                          2. lower-fma.f64N/A

                            \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\mathsf{fma}\left(2, C, \frac{-1}{2} \cdot \frac{{B}^{2}}{A}\right)}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                          3. associate-*r/N/A

                            \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(2, C, \color{blue}{\frac{\frac{-1}{2} \cdot {B}^{2}}{A}}\right)}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                          4. lower-/.f64N/A

                            \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(2, C, \color{blue}{\frac{\frac{-1}{2} \cdot {B}^{2}}{A}}\right)}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                          5. lower-*.f64N/A

                            \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(2, C, \frac{\color{blue}{\frac{-1}{2} \cdot {B}^{2}}}{A}\right)}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                          6. unpow2N/A

                            \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(2, C, \frac{\frac{-1}{2} \cdot \color{blue}{\left(B \cdot B\right)}}{A}\right)}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                          7. lower-*.f646.1

                            \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(2, C, \frac{-0.5 \cdot \color{blue}{\left(B \cdot B\right)}}{A}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                        5. Applied rewrites6.1%

                          \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\mathsf{fma}\left(2, C, \frac{-0.5 \cdot \left(B \cdot B\right)}{A}\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                        6. Applied rewrites6.1%

                          \[\leadsto \color{blue}{\frac{1}{\frac{-\mathsf{fma}\left(B, B, \left(-4 \cdot C\right) \cdot A\right)}{\sqrt{\left(\mathsf{fma}\left(B, B, \left(-4 \cdot C\right) \cdot A\right) \cdot \left(F \cdot 2\right)\right) \cdot \mathsf{fma}\left(2, C, \frac{\left(B \cdot B\right) \cdot -0.5}{A}\right)}}}} \]
                        7. Step-by-step derivation
                          1. lift-sqrt.f64N/A

                            \[\leadsto \frac{1}{\frac{\mathsf{neg}\left(\mathsf{fma}\left(B, B, \left(-4 \cdot C\right) \cdot A\right)\right)}{\color{blue}{\sqrt{\left(\mathsf{fma}\left(B, B, \left(-4 \cdot C\right) \cdot A\right) \cdot \left(F \cdot 2\right)\right) \cdot \mathsf{fma}\left(2, C, \frac{\left(B \cdot B\right) \cdot \frac{-1}{2}}{A}\right)}}}} \]
                          2. lift-*.f64N/A

                            \[\leadsto \frac{1}{\frac{\mathsf{neg}\left(\mathsf{fma}\left(B, B, \left(-4 \cdot C\right) \cdot A\right)\right)}{\sqrt{\color{blue}{\left(\mathsf{fma}\left(B, B, \left(-4 \cdot C\right) \cdot A\right) \cdot \left(F \cdot 2\right)\right) \cdot \mathsf{fma}\left(2, C, \frac{\left(B \cdot B\right) \cdot \frac{-1}{2}}{A}\right)}}}} \]
                          3. *-commutativeN/A

                            \[\leadsto \frac{1}{\frac{\mathsf{neg}\left(\mathsf{fma}\left(B, B, \left(-4 \cdot C\right) \cdot A\right)\right)}{\sqrt{\color{blue}{\mathsf{fma}\left(2, C, \frac{\left(B \cdot B\right) \cdot \frac{-1}{2}}{A}\right) \cdot \left(\mathsf{fma}\left(B, B, \left(-4 \cdot C\right) \cdot A\right) \cdot \left(F \cdot 2\right)\right)}}}} \]
                          4. lift-*.f64N/A

                            \[\leadsto \frac{1}{\frac{\mathsf{neg}\left(\mathsf{fma}\left(B, B, \left(-4 \cdot C\right) \cdot A\right)\right)}{\sqrt{\mathsf{fma}\left(2, C, \frac{\left(B \cdot B\right) \cdot \frac{-1}{2}}{A}\right) \cdot \color{blue}{\left(\mathsf{fma}\left(B, B, \left(-4 \cdot C\right) \cdot A\right) \cdot \left(F \cdot 2\right)\right)}}}} \]
                          5. associate-*r*N/A

                            \[\leadsto \frac{1}{\frac{\mathsf{neg}\left(\mathsf{fma}\left(B, B, \left(-4 \cdot C\right) \cdot A\right)\right)}{\sqrt{\color{blue}{\left(\mathsf{fma}\left(2, C, \frac{\left(B \cdot B\right) \cdot \frac{-1}{2}}{A}\right) \cdot \mathsf{fma}\left(B, B, \left(-4 \cdot C\right) \cdot A\right)\right) \cdot \left(F \cdot 2\right)}}}} \]
                          6. sqrt-prodN/A

                            \[\leadsto \frac{1}{\frac{\mathsf{neg}\left(\mathsf{fma}\left(B, B, \left(-4 \cdot C\right) \cdot A\right)\right)}{\color{blue}{\sqrt{\mathsf{fma}\left(2, C, \frac{\left(B \cdot B\right) \cdot \frac{-1}{2}}{A}\right) \cdot \mathsf{fma}\left(B, B, \left(-4 \cdot C\right) \cdot A\right)} \cdot \sqrt{F \cdot 2}}}} \]
                        8. Applied rewrites15.6%

                          \[\leadsto \frac{1}{\frac{-\mathsf{fma}\left(B, B, \left(-4 \cdot C\right) \cdot A\right)}{\color{blue}{\sqrt{\mathsf{fma}\left(2, C, \frac{\left(B \cdot B\right) \cdot -0.5}{A}\right) \cdot \mathsf{fma}\left(-4, A \cdot C, B \cdot B\right)} \cdot \sqrt{2 \cdot F}}}} \]

                        if -inf.0 < (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C))) < -9.99999999999999992e-221

                        1. Initial program 98.5%

                          \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                        2. Add Preprocessing
                        3. Applied rewrites98.8%

                          \[\leadsto \color{blue}{\sqrt{\left(\mathsf{fma}\left(B, B, -4 \cdot \left(A \cdot C\right)\right) \cdot \left(F \cdot 2\right)\right) \cdot \left(\sqrt{\mathsf{fma}\left(A - C, A - C, B \cdot B\right)} + \left(A + C\right)\right)} \cdot \frac{-1}{\mathsf{fma}\left(B, B, -4 \cdot \left(A \cdot C\right)\right)}} \]

                        if -9.99999999999999992e-221 < (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C))) < -0.0

                        1. Initial program 3.8%

                          \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                        2. Add Preprocessing
                        3. Taylor expanded in A around -inf

                          \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\left(\frac{-1}{2} \cdot \frac{{B}^{2}}{A} + 2 \cdot C\right)}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                        4. Step-by-step derivation
                          1. +-commutativeN/A

                            \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\left(2 \cdot C + \frac{-1}{2} \cdot \frac{{B}^{2}}{A}\right)}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                          2. lower-fma.f64N/A

                            \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\mathsf{fma}\left(2, C, \frac{-1}{2} \cdot \frac{{B}^{2}}{A}\right)}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                          3. associate-*r/N/A

                            \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(2, C, \color{blue}{\frac{\frac{-1}{2} \cdot {B}^{2}}{A}}\right)}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                          4. lower-/.f64N/A

                            \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(2, C, \color{blue}{\frac{\frac{-1}{2} \cdot {B}^{2}}{A}}\right)}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                          5. lower-*.f64N/A

                            \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(2, C, \frac{\color{blue}{\frac{-1}{2} \cdot {B}^{2}}}{A}\right)}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                          6. unpow2N/A

                            \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(2, C, \frac{\frac{-1}{2} \cdot \color{blue}{\left(B \cdot B\right)}}{A}\right)}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                          7. lower-*.f6422.3

                            \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(2, C, \frac{-0.5 \cdot \color{blue}{\left(B \cdot B\right)}}{A}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                        5. Applied rewrites22.3%

                          \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\mathsf{fma}\left(2, C, \frac{-0.5 \cdot \left(B \cdot B\right)}{A}\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                        6. Applied rewrites22.2%

                          \[\leadsto \color{blue}{\frac{1}{\frac{-\mathsf{fma}\left(B, B, \left(-4 \cdot C\right) \cdot A\right)}{\sqrt{\left(\mathsf{fma}\left(B, B, \left(-4 \cdot C\right) \cdot A\right) \cdot \left(F \cdot 2\right)\right) \cdot \mathsf{fma}\left(2, C, \frac{\left(B \cdot B\right) \cdot -0.5}{A}\right)}}}} \]
                        7. Step-by-step derivation
                          1. lift-sqrt.f64N/A

                            \[\leadsto \frac{1}{\frac{\mathsf{neg}\left(\mathsf{fma}\left(B, B, \left(-4 \cdot C\right) \cdot A\right)\right)}{\color{blue}{\sqrt{\left(\mathsf{fma}\left(B, B, \left(-4 \cdot C\right) \cdot A\right) \cdot \left(F \cdot 2\right)\right) \cdot \mathsf{fma}\left(2, C, \frac{\left(B \cdot B\right) \cdot \frac{-1}{2}}{A}\right)}}}} \]
                          2. lift-*.f64N/A

                            \[\leadsto \frac{1}{\frac{\mathsf{neg}\left(\mathsf{fma}\left(B, B, \left(-4 \cdot C\right) \cdot A\right)\right)}{\sqrt{\color{blue}{\left(\mathsf{fma}\left(B, B, \left(-4 \cdot C\right) \cdot A\right) \cdot \left(F \cdot 2\right)\right) \cdot \mathsf{fma}\left(2, C, \frac{\left(B \cdot B\right) \cdot \frac{-1}{2}}{A}\right)}}}} \]
                          3. lift-*.f64N/A

                            \[\leadsto \frac{1}{\frac{\mathsf{neg}\left(\mathsf{fma}\left(B, B, \left(-4 \cdot C\right) \cdot A\right)\right)}{\sqrt{\color{blue}{\left(\mathsf{fma}\left(B, B, \left(-4 \cdot C\right) \cdot A\right) \cdot \left(F \cdot 2\right)\right)} \cdot \mathsf{fma}\left(2, C, \frac{\left(B \cdot B\right) \cdot \frac{-1}{2}}{A}\right)}}} \]
                          4. lift-*.f64N/A

                            \[\leadsto \frac{1}{\frac{\mathsf{neg}\left(\mathsf{fma}\left(B, B, \left(-4 \cdot C\right) \cdot A\right)\right)}{\sqrt{\left(\mathsf{fma}\left(B, B, \left(-4 \cdot C\right) \cdot A\right) \cdot \color{blue}{\left(F \cdot 2\right)}\right) \cdot \mathsf{fma}\left(2, C, \frac{\left(B \cdot B\right) \cdot \frac{-1}{2}}{A}\right)}}} \]
                          5. associate-*r*N/A

                            \[\leadsto \frac{1}{\frac{\mathsf{neg}\left(\mathsf{fma}\left(B, B, \left(-4 \cdot C\right) \cdot A\right)\right)}{\sqrt{\color{blue}{\left(\left(\mathsf{fma}\left(B, B, \left(-4 \cdot C\right) \cdot A\right) \cdot F\right) \cdot 2\right)} \cdot \mathsf{fma}\left(2, C, \frac{\left(B \cdot B\right) \cdot \frac{-1}{2}}{A}\right)}}} \]
                          6. *-commutativeN/A

                            \[\leadsto \frac{1}{\frac{\mathsf{neg}\left(\mathsf{fma}\left(B, B, \left(-4 \cdot C\right) \cdot A\right)\right)}{\sqrt{\left(\color{blue}{\left(F \cdot \mathsf{fma}\left(B, B, \left(-4 \cdot C\right) \cdot A\right)\right)} \cdot 2\right) \cdot \mathsf{fma}\left(2, C, \frac{\left(B \cdot B\right) \cdot \frac{-1}{2}}{A}\right)}}} \]
                          7. lift-*.f64N/A

                            \[\leadsto \frac{1}{\frac{\mathsf{neg}\left(\mathsf{fma}\left(B, B, \left(-4 \cdot C\right) \cdot A\right)\right)}{\sqrt{\left(\color{blue}{\left(F \cdot \mathsf{fma}\left(B, B, \left(-4 \cdot C\right) \cdot A\right)\right)} \cdot 2\right) \cdot \mathsf{fma}\left(2, C, \frac{\left(B \cdot B\right) \cdot \frac{-1}{2}}{A}\right)}}} \]
                          8. associate-*l*N/A

                            \[\leadsto \frac{1}{\frac{\mathsf{neg}\left(\mathsf{fma}\left(B, B, \left(-4 \cdot C\right) \cdot A\right)\right)}{\sqrt{\color{blue}{\left(F \cdot \mathsf{fma}\left(B, B, \left(-4 \cdot C\right) \cdot A\right)\right) \cdot \left(2 \cdot \mathsf{fma}\left(2, C, \frac{\left(B \cdot B\right) \cdot \frac{-1}{2}}{A}\right)\right)}}}} \]
                          9. *-commutativeN/A

                            \[\leadsto \frac{1}{\frac{\mathsf{neg}\left(\mathsf{fma}\left(B, B, \left(-4 \cdot C\right) \cdot A\right)\right)}{\sqrt{\left(F \cdot \mathsf{fma}\left(B, B, \left(-4 \cdot C\right) \cdot A\right)\right) \cdot \color{blue}{\left(\mathsf{fma}\left(2, C, \frac{\left(B \cdot B\right) \cdot \frac{-1}{2}}{A}\right) \cdot 2\right)}}}} \]
                        8. Applied rewrites27.3%

                          \[\leadsto \frac{1}{\frac{-\mathsf{fma}\left(B, B, \left(-4 \cdot C\right) \cdot A\right)}{\color{blue}{\sqrt{\left(2 \cdot \mathsf{fma}\left(2, C, \frac{\left(B \cdot B\right) \cdot -0.5}{A}\right)\right) \cdot \mathsf{fma}\left(-4, A \cdot C, B \cdot B\right)} \cdot \sqrt{F}}}} \]

                        if -0.0 < (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C))) < +inf.0

                        1. Initial program 48.9%

                          \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                        2. Add Preprocessing
                        3. Taylor expanded in A around -inf

                          \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\left(\frac{-1}{2} \cdot \frac{{B}^{2}}{A} + 2 \cdot C\right)}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                        4. Step-by-step derivation
                          1. +-commutativeN/A

                            \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\left(2 \cdot C + \frac{-1}{2} \cdot \frac{{B}^{2}}{A}\right)}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                          2. lower-fma.f64N/A

                            \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\mathsf{fma}\left(2, C, \frac{-1}{2} \cdot \frac{{B}^{2}}{A}\right)}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                          3. associate-*r/N/A

                            \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(2, C, \color{blue}{\frac{\frac{-1}{2} \cdot {B}^{2}}{A}}\right)}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                          4. lower-/.f64N/A

                            \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(2, C, \color{blue}{\frac{\frac{-1}{2} \cdot {B}^{2}}{A}}\right)}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                          5. lower-*.f64N/A

                            \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(2, C, \frac{\color{blue}{\frac{-1}{2} \cdot {B}^{2}}}{A}\right)}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                          6. unpow2N/A

                            \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(2, C, \frac{\frac{-1}{2} \cdot \color{blue}{\left(B \cdot B\right)}}{A}\right)}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                          7. lower-*.f6431.5

                            \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(2, C, \frac{-0.5 \cdot \color{blue}{\left(B \cdot B\right)}}{A}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                        5. Applied rewrites31.5%

                          \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\mathsf{fma}\left(2, C, \frac{-0.5 \cdot \left(B \cdot B\right)}{A}\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                        6. Applied rewrites31.4%

                          \[\leadsto \color{blue}{\frac{1}{\frac{-\mathsf{fma}\left(B, B, \left(-4 \cdot C\right) \cdot A\right)}{\sqrt{\left(\mathsf{fma}\left(B, B, \left(-4 \cdot C\right) \cdot A\right) \cdot \left(F \cdot 2\right)\right) \cdot \mathsf{fma}\left(2, C, \frac{\left(B \cdot B\right) \cdot -0.5}{A}\right)}}}} \]
                        7. Applied rewrites37.0%

                          \[\leadsto \color{blue}{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, A \cdot C, B \cdot B\right)} \cdot \frac{\sqrt{\mathsf{fma}\left(2, C, \frac{\left(B \cdot B\right) \cdot -0.5}{A}\right)}}{\mathsf{fma}\left(B, -B, 4 \cdot \left(A \cdot C\right)\right)}} \]

                        if +inf.0 < (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)))

                        1. Initial program 0.0%

                          \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                        2. Add Preprocessing
                        3. Taylor expanded in B around inf

                          \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                        4. Step-by-step derivation
                          1. mul-1-negN/A

                            \[\leadsto \color{blue}{\mathsf{neg}\left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                          2. lower-neg.f64N/A

                            \[\leadsto \color{blue}{\mathsf{neg}\left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                          3. *-commutativeN/A

                            \[\leadsto \mathsf{neg}\left(\color{blue}{\sqrt{2} \cdot \sqrt{\frac{F}{B}}}\right) \]
                          4. lower-*.f64N/A

                            \[\leadsto \mathsf{neg}\left(\color{blue}{\sqrt{2} \cdot \sqrt{\frac{F}{B}}}\right) \]
                          5. lower-sqrt.f64N/A

                            \[\leadsto \mathsf{neg}\left(\color{blue}{\sqrt{2}} \cdot \sqrt{\frac{F}{B}}\right) \]
                          6. lower-sqrt.f64N/A

                            \[\leadsto \mathsf{neg}\left(\sqrt{2} \cdot \color{blue}{\sqrt{\frac{F}{B}}}\right) \]
                          7. lower-/.f6420.0

                            \[\leadsto -\sqrt{2} \cdot \sqrt{\color{blue}{\frac{F}{B}}} \]
                        5. Applied rewrites20.0%

                          \[\leadsto \color{blue}{-\sqrt{2} \cdot \sqrt{\frac{F}{B}}} \]
                        6. Step-by-step derivation
                          1. Applied rewrites29.6%

                            \[\leadsto -\frac{\sqrt{F \cdot 2}}{\sqrt{B}} \]
                          2. Step-by-step derivation
                            1. Applied rewrites29.6%

                              \[\leadsto -\sqrt{F} \cdot \sqrt{\frac{2}{B}} \]
                          3. Recombined 5 regimes into one program.
                          4. Final simplification36.8%

                            \[\leadsto \begin{array}{l} \mathbf{if}\;\frac{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)}}{\left(4 \cdot A\right) \cdot C - {B}^{2}} \leq -\infty:\\ \;\;\;\;\frac{-1}{\frac{\mathsf{fma}\left(B, B, A \cdot \left(C \cdot -4\right)\right)}{\sqrt{\mathsf{fma}\left(2, C, \frac{\left(B \cdot B\right) \cdot -0.5}{A}\right) \cdot \mathsf{fma}\left(-4, A \cdot C, B \cdot B\right)} \cdot \sqrt{2 \cdot F}}}\\ \mathbf{elif}\;\frac{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)}}{\left(4 \cdot A\right) \cdot C - {B}^{2}} \leq -1 \cdot 10^{-220}:\\ \;\;\;\;\sqrt{\left(\mathsf{fma}\left(B, B, -4 \cdot \left(A \cdot C\right)\right) \cdot \left(2 \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{\mathsf{fma}\left(A - C, A - C, B \cdot B\right)}\right)} \cdot \frac{-1}{\mathsf{fma}\left(B, B, -4 \cdot \left(A \cdot C\right)\right)}\\ \mathbf{elif}\;\frac{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)}}{\left(4 \cdot A\right) \cdot C - {B}^{2}} \leq 0:\\ \;\;\;\;\frac{-1}{\frac{\mathsf{fma}\left(B, B, A \cdot \left(C \cdot -4\right)\right)}{\sqrt{F} \cdot \sqrt{\left(2 \cdot \mathsf{fma}\left(2, C, \frac{\left(B \cdot B\right) \cdot -0.5}{A}\right)\right) \cdot \mathsf{fma}\left(-4, A \cdot C, B \cdot B\right)}}}\\ \mathbf{elif}\;\frac{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)}}{\left(4 \cdot A\right) \cdot C - {B}^{2}} \leq \infty:\\ \;\;\;\;\sqrt{\mathsf{fma}\left(-4, A \cdot C, B \cdot B\right) \cdot \left(2 \cdot F\right)} \cdot \frac{\sqrt{\mathsf{fma}\left(2, C, \frac{\left(B \cdot B\right) \cdot -0.5}{A}\right)}}{\mathsf{fma}\left(B, -B, 4 \cdot \left(A \cdot C\right)\right)}\\ \mathbf{else}:\\ \;\;\;\;\left(-\sqrt{F}\right) \cdot \sqrt{\frac{2}{B}}\\ \end{array} \]
                          5. Add Preprocessing

                          Alternative 7: 58.1% accurate, 0.2× speedup?

                          \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} t_0 := \mathsf{fma}\left(-4, A \cdot C, B\_m \cdot B\_m\right)\\ t_1 := \left(4 \cdot A\right) \cdot C\\ t_2 := \frac{\sqrt{\left(2 \cdot \left(\left({B\_m}^{2} - t\_1\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{B\_m}^{2} + {\left(A - C\right)}^{2}}\right)}}{t\_1 - {B\_m}^{2}}\\ t_3 := \mathsf{fma}\left(2, C, \frac{\left(B\_m \cdot B\_m\right) \cdot -0.5}{A}\right)\\ t_4 := \frac{-1}{\frac{\mathsf{fma}\left(B\_m, B\_m, A \cdot \left(C \cdot -4\right)\right)}{\sqrt{t\_3 \cdot t\_0} \cdot \sqrt{2 \cdot F}}}\\ t_5 := \mathsf{fma}\left(B\_m, B\_m, -4 \cdot \left(A \cdot C\right)\right)\\ \mathbf{if}\;t\_2 \leq -\infty:\\ \;\;\;\;t\_4\\ \mathbf{elif}\;t\_2 \leq -1 \cdot 10^{-220}:\\ \;\;\;\;\sqrt{\left(t\_5 \cdot \left(2 \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{\mathsf{fma}\left(A - C, A - C, B\_m \cdot B\_m\right)}\right)} \cdot \frac{-1}{t\_5}\\ \mathbf{elif}\;t\_2 \leq 0:\\ \;\;\;\;t\_4\\ \mathbf{elif}\;t\_2 \leq \infty:\\ \;\;\;\;\sqrt{t\_0 \cdot \left(2 \cdot F\right)} \cdot \frac{\sqrt{t\_3}}{\mathsf{fma}\left(B\_m, -B\_m, 4 \cdot \left(A \cdot C\right)\right)}\\ \mathbf{else}:\\ \;\;\;\;\left(-\sqrt{F}\right) \cdot \sqrt{\frac{2}{B\_m}}\\ \end{array} \end{array} \]
                          B_m = (fabs.f64 B)
                          NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                          (FPCore (A B_m C F)
                           :precision binary64
                           (let* ((t_0 (fma -4.0 (* A C) (* B_m B_m)))
                                  (t_1 (* (* 4.0 A) C))
                                  (t_2
                                   (/
                                    (sqrt
                                     (*
                                      (* 2.0 (* (- (pow B_m 2.0) t_1) F))
                                      (+ (+ A C) (sqrt (+ (pow B_m 2.0) (pow (- A C) 2.0))))))
                                    (- t_1 (pow B_m 2.0))))
                                  (t_3 (fma 2.0 C (/ (* (* B_m B_m) -0.5) A)))
                                  (t_4
                                   (/
                                    -1.0
                                    (/
                                     (fma B_m B_m (* A (* C -4.0)))
                                     (* (sqrt (* t_3 t_0)) (sqrt (* 2.0 F))))))
                                  (t_5 (fma B_m B_m (* -4.0 (* A C)))))
                             (if (<= t_2 (- INFINITY))
                               t_4
                               (if (<= t_2 -1e-220)
                                 (*
                                  (sqrt
                                   (*
                                    (* t_5 (* 2.0 F))
                                    (+ (+ A C) (sqrt (fma (- A C) (- A C) (* B_m B_m))))))
                                  (/ -1.0 t_5))
                                 (if (<= t_2 0.0)
                                   t_4
                                   (if (<= t_2 INFINITY)
                                     (*
                                      (sqrt (* t_0 (* 2.0 F)))
                                      (/ (sqrt t_3) (fma B_m (- B_m) (* 4.0 (* A C)))))
                                     (* (- (sqrt F)) (sqrt (/ 2.0 B_m)))))))))
                          B_m = fabs(B);
                          assert(A < B_m && B_m < C && C < F);
                          double code(double A, double B_m, double C, double F) {
                          	double t_0 = fma(-4.0, (A * C), (B_m * B_m));
                          	double t_1 = (4.0 * A) * C;
                          	double t_2 = sqrt(((2.0 * ((pow(B_m, 2.0) - t_1) * F)) * ((A + C) + sqrt((pow(B_m, 2.0) + pow((A - C), 2.0)))))) / (t_1 - pow(B_m, 2.0));
                          	double t_3 = fma(2.0, C, (((B_m * B_m) * -0.5) / A));
                          	double t_4 = -1.0 / (fma(B_m, B_m, (A * (C * -4.0))) / (sqrt((t_3 * t_0)) * sqrt((2.0 * F))));
                          	double t_5 = fma(B_m, B_m, (-4.0 * (A * C)));
                          	double tmp;
                          	if (t_2 <= -((double) INFINITY)) {
                          		tmp = t_4;
                          	} else if (t_2 <= -1e-220) {
                          		tmp = sqrt(((t_5 * (2.0 * F)) * ((A + C) + sqrt(fma((A - C), (A - C), (B_m * B_m)))))) * (-1.0 / t_5);
                          	} else if (t_2 <= 0.0) {
                          		tmp = t_4;
                          	} else if (t_2 <= ((double) INFINITY)) {
                          		tmp = sqrt((t_0 * (2.0 * F))) * (sqrt(t_3) / fma(B_m, -B_m, (4.0 * (A * C))));
                          	} else {
                          		tmp = -sqrt(F) * sqrt((2.0 / B_m));
                          	}
                          	return tmp;
                          }
                          
                          B_m = abs(B)
                          A, B_m, C, F = sort([A, B_m, C, F])
                          function code(A, B_m, C, F)
                          	t_0 = fma(-4.0, Float64(A * C), Float64(B_m * B_m))
                          	t_1 = Float64(Float64(4.0 * A) * C)
                          	t_2 = Float64(sqrt(Float64(Float64(2.0 * Float64(Float64((B_m ^ 2.0) - t_1) * F)) * Float64(Float64(A + C) + sqrt(Float64((B_m ^ 2.0) + (Float64(A - C) ^ 2.0)))))) / Float64(t_1 - (B_m ^ 2.0)))
                          	t_3 = fma(2.0, C, Float64(Float64(Float64(B_m * B_m) * -0.5) / A))
                          	t_4 = Float64(-1.0 / Float64(fma(B_m, B_m, Float64(A * Float64(C * -4.0))) / Float64(sqrt(Float64(t_3 * t_0)) * sqrt(Float64(2.0 * F)))))
                          	t_5 = fma(B_m, B_m, Float64(-4.0 * Float64(A * C)))
                          	tmp = 0.0
                          	if (t_2 <= Float64(-Inf))
                          		tmp = t_4;
                          	elseif (t_2 <= -1e-220)
                          		tmp = Float64(sqrt(Float64(Float64(t_5 * Float64(2.0 * F)) * Float64(Float64(A + C) + sqrt(fma(Float64(A - C), Float64(A - C), Float64(B_m * B_m)))))) * Float64(-1.0 / t_5));
                          	elseif (t_2 <= 0.0)
                          		tmp = t_4;
                          	elseif (t_2 <= Inf)
                          		tmp = Float64(sqrt(Float64(t_0 * Float64(2.0 * F))) * Float64(sqrt(t_3) / fma(B_m, Float64(-B_m), Float64(4.0 * Float64(A * C)))));
                          	else
                          		tmp = Float64(Float64(-sqrt(F)) * sqrt(Float64(2.0 / B_m)));
                          	end
                          	return tmp
                          end
                          
                          B_m = N[Abs[B], $MachinePrecision]
                          NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                          code[A_, B$95$m_, C_, F_] := Block[{t$95$0 = N[(-4.0 * N[(A * C), $MachinePrecision] + N[(B$95$m * B$95$m), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$1 = N[(N[(4.0 * A), $MachinePrecision] * C), $MachinePrecision]}, Block[{t$95$2 = N[(N[Sqrt[N[(N[(2.0 * N[(N[(N[Power[B$95$m, 2.0], $MachinePrecision] - t$95$1), $MachinePrecision] * F), $MachinePrecision]), $MachinePrecision] * N[(N[(A + C), $MachinePrecision] + N[Sqrt[N[(N[Power[B$95$m, 2.0], $MachinePrecision] + N[Power[N[(A - C), $MachinePrecision], 2.0], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / N[(t$95$1 - N[Power[B$95$m, 2.0], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$3 = N[(2.0 * C + N[(N[(N[(B$95$m * B$95$m), $MachinePrecision] * -0.5), $MachinePrecision] / A), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$4 = N[(-1.0 / N[(N[(B$95$m * B$95$m + N[(A * N[(C * -4.0), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] / N[(N[Sqrt[N[(t$95$3 * t$95$0), $MachinePrecision]], $MachinePrecision] * N[Sqrt[N[(2.0 * F), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$5 = N[(B$95$m * B$95$m + N[(-4.0 * N[(A * C), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[t$95$2, (-Infinity)], t$95$4, If[LessEqual[t$95$2, -1e-220], N[(N[Sqrt[N[(N[(t$95$5 * N[(2.0 * F), $MachinePrecision]), $MachinePrecision] * N[(N[(A + C), $MachinePrecision] + N[Sqrt[N[(N[(A - C), $MachinePrecision] * N[(A - C), $MachinePrecision] + N[(B$95$m * B$95$m), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] * N[(-1.0 / t$95$5), $MachinePrecision]), $MachinePrecision], If[LessEqual[t$95$2, 0.0], t$95$4, If[LessEqual[t$95$2, Infinity], N[(N[Sqrt[N[(t$95$0 * N[(2.0 * F), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] * N[(N[Sqrt[t$95$3], $MachinePrecision] / N[(B$95$m * (-B$95$m) + N[(4.0 * N[(A * C), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], N[((-N[Sqrt[F], $MachinePrecision]) * N[Sqrt[N[(2.0 / B$95$m), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]]]]]]]]]]]
                          
                          \begin{array}{l}
                          B_m = \left|B\right|
                          \\
                          [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
                          \\
                          \begin{array}{l}
                          t_0 := \mathsf{fma}\left(-4, A \cdot C, B\_m \cdot B\_m\right)\\
                          t_1 := \left(4 \cdot A\right) \cdot C\\
                          t_2 := \frac{\sqrt{\left(2 \cdot \left(\left({B\_m}^{2} - t\_1\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{B\_m}^{2} + {\left(A - C\right)}^{2}}\right)}}{t\_1 - {B\_m}^{2}}\\
                          t_3 := \mathsf{fma}\left(2, C, \frac{\left(B\_m \cdot B\_m\right) \cdot -0.5}{A}\right)\\
                          t_4 := \frac{-1}{\frac{\mathsf{fma}\left(B\_m, B\_m, A \cdot \left(C \cdot -4\right)\right)}{\sqrt{t\_3 \cdot t\_0} \cdot \sqrt{2 \cdot F}}}\\
                          t_5 := \mathsf{fma}\left(B\_m, B\_m, -4 \cdot \left(A \cdot C\right)\right)\\
                          \mathbf{if}\;t\_2 \leq -\infty:\\
                          \;\;\;\;t\_4\\
                          
                          \mathbf{elif}\;t\_2 \leq -1 \cdot 10^{-220}:\\
                          \;\;\;\;\sqrt{\left(t\_5 \cdot \left(2 \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{\mathsf{fma}\left(A - C, A - C, B\_m \cdot B\_m\right)}\right)} \cdot \frac{-1}{t\_5}\\
                          
                          \mathbf{elif}\;t\_2 \leq 0:\\
                          \;\;\;\;t\_4\\
                          
                          \mathbf{elif}\;t\_2 \leq \infty:\\
                          \;\;\;\;\sqrt{t\_0 \cdot \left(2 \cdot F\right)} \cdot \frac{\sqrt{t\_3}}{\mathsf{fma}\left(B\_m, -B\_m, 4 \cdot \left(A \cdot C\right)\right)}\\
                          
                          \mathbf{else}:\\
                          \;\;\;\;\left(-\sqrt{F}\right) \cdot \sqrt{\frac{2}{B\_m}}\\
                          
                          
                          \end{array}
                          \end{array}
                          
                          Derivation
                          1. Split input into 4 regimes
                          2. if (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C))) < -inf.0 or -9.99999999999999992e-221 < (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C))) < -0.0

                            1. Initial program 3.7%

                              \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                            2. Add Preprocessing
                            3. Taylor expanded in A around -inf

                              \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\left(\frac{-1}{2} \cdot \frac{{B}^{2}}{A} + 2 \cdot C\right)}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                            4. Step-by-step derivation
                              1. +-commutativeN/A

                                \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\left(2 \cdot C + \frac{-1}{2} \cdot \frac{{B}^{2}}{A}\right)}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                              2. lower-fma.f64N/A

                                \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\mathsf{fma}\left(2, C, \frac{-1}{2} \cdot \frac{{B}^{2}}{A}\right)}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                              3. associate-*r/N/A

                                \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(2, C, \color{blue}{\frac{\frac{-1}{2} \cdot {B}^{2}}{A}}\right)}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                              4. lower-/.f64N/A

                                \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(2, C, \color{blue}{\frac{\frac{-1}{2} \cdot {B}^{2}}{A}}\right)}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                              5. lower-*.f64N/A

                                \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(2, C, \frac{\color{blue}{\frac{-1}{2} \cdot {B}^{2}}}{A}\right)}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                              6. unpow2N/A

                                \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(2, C, \frac{\frac{-1}{2} \cdot \color{blue}{\left(B \cdot B\right)}}{A}\right)}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                              7. lower-*.f6413.8

                                \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(2, C, \frac{-0.5 \cdot \color{blue}{\left(B \cdot B\right)}}{A}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                            5. Applied rewrites13.8%

                              \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\mathsf{fma}\left(2, C, \frac{-0.5 \cdot \left(B \cdot B\right)}{A}\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                            6. Applied rewrites13.7%

                              \[\leadsto \color{blue}{\frac{1}{\frac{-\mathsf{fma}\left(B, B, \left(-4 \cdot C\right) \cdot A\right)}{\sqrt{\left(\mathsf{fma}\left(B, B, \left(-4 \cdot C\right) \cdot A\right) \cdot \left(F \cdot 2\right)\right) \cdot \mathsf{fma}\left(2, C, \frac{\left(B \cdot B\right) \cdot -0.5}{A}\right)}}}} \]
                            7. Step-by-step derivation
                              1. lift-sqrt.f64N/A

                                \[\leadsto \frac{1}{\frac{\mathsf{neg}\left(\mathsf{fma}\left(B, B, \left(-4 \cdot C\right) \cdot A\right)\right)}{\color{blue}{\sqrt{\left(\mathsf{fma}\left(B, B, \left(-4 \cdot C\right) \cdot A\right) \cdot \left(F \cdot 2\right)\right) \cdot \mathsf{fma}\left(2, C, \frac{\left(B \cdot B\right) \cdot \frac{-1}{2}}{A}\right)}}}} \]
                              2. lift-*.f64N/A

                                \[\leadsto \frac{1}{\frac{\mathsf{neg}\left(\mathsf{fma}\left(B, B, \left(-4 \cdot C\right) \cdot A\right)\right)}{\sqrt{\color{blue}{\left(\mathsf{fma}\left(B, B, \left(-4 \cdot C\right) \cdot A\right) \cdot \left(F \cdot 2\right)\right) \cdot \mathsf{fma}\left(2, C, \frac{\left(B \cdot B\right) \cdot \frac{-1}{2}}{A}\right)}}}} \]
                              3. *-commutativeN/A

                                \[\leadsto \frac{1}{\frac{\mathsf{neg}\left(\mathsf{fma}\left(B, B, \left(-4 \cdot C\right) \cdot A\right)\right)}{\sqrt{\color{blue}{\mathsf{fma}\left(2, C, \frac{\left(B \cdot B\right) \cdot \frac{-1}{2}}{A}\right) \cdot \left(\mathsf{fma}\left(B, B, \left(-4 \cdot C\right) \cdot A\right) \cdot \left(F \cdot 2\right)\right)}}}} \]
                              4. lift-*.f64N/A

                                \[\leadsto \frac{1}{\frac{\mathsf{neg}\left(\mathsf{fma}\left(B, B, \left(-4 \cdot C\right) \cdot A\right)\right)}{\sqrt{\mathsf{fma}\left(2, C, \frac{\left(B \cdot B\right) \cdot \frac{-1}{2}}{A}\right) \cdot \color{blue}{\left(\mathsf{fma}\left(B, B, \left(-4 \cdot C\right) \cdot A\right) \cdot \left(F \cdot 2\right)\right)}}}} \]
                              5. associate-*r*N/A

                                \[\leadsto \frac{1}{\frac{\mathsf{neg}\left(\mathsf{fma}\left(B, B, \left(-4 \cdot C\right) \cdot A\right)\right)}{\sqrt{\color{blue}{\left(\mathsf{fma}\left(2, C, \frac{\left(B \cdot B\right) \cdot \frac{-1}{2}}{A}\right) \cdot \mathsf{fma}\left(B, B, \left(-4 \cdot C\right) \cdot A\right)\right) \cdot \left(F \cdot 2\right)}}}} \]
                              6. sqrt-prodN/A

                                \[\leadsto \frac{1}{\frac{\mathsf{neg}\left(\mathsf{fma}\left(B, B, \left(-4 \cdot C\right) \cdot A\right)\right)}{\color{blue}{\sqrt{\mathsf{fma}\left(2, C, \frac{\left(B \cdot B\right) \cdot \frac{-1}{2}}{A}\right) \cdot \mathsf{fma}\left(B, B, \left(-4 \cdot C\right) \cdot A\right)} \cdot \sqrt{F \cdot 2}}}} \]
                            8. Applied rewrites21.2%

                              \[\leadsto \frac{1}{\frac{-\mathsf{fma}\left(B, B, \left(-4 \cdot C\right) \cdot A\right)}{\color{blue}{\sqrt{\mathsf{fma}\left(2, C, \frac{\left(B \cdot B\right) \cdot -0.5}{A}\right) \cdot \mathsf{fma}\left(-4, A \cdot C, B \cdot B\right)} \cdot \sqrt{2 \cdot F}}}} \]

                            if -inf.0 < (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C))) < -9.99999999999999992e-221

                            1. Initial program 98.5%

                              \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                            2. Add Preprocessing
                            3. Applied rewrites98.8%

                              \[\leadsto \color{blue}{\sqrt{\left(\mathsf{fma}\left(B, B, -4 \cdot \left(A \cdot C\right)\right) \cdot \left(F \cdot 2\right)\right) \cdot \left(\sqrt{\mathsf{fma}\left(A - C, A - C, B \cdot B\right)} + \left(A + C\right)\right)} \cdot \frac{-1}{\mathsf{fma}\left(B, B, -4 \cdot \left(A \cdot C\right)\right)}} \]

                            if -0.0 < (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C))) < +inf.0

                            1. Initial program 48.9%

                              \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                            2. Add Preprocessing
                            3. Taylor expanded in A around -inf

                              \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\left(\frac{-1}{2} \cdot \frac{{B}^{2}}{A} + 2 \cdot C\right)}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                            4. Step-by-step derivation
                              1. +-commutativeN/A

                                \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\left(2 \cdot C + \frac{-1}{2} \cdot \frac{{B}^{2}}{A}\right)}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                              2. lower-fma.f64N/A

                                \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\mathsf{fma}\left(2, C, \frac{-1}{2} \cdot \frac{{B}^{2}}{A}\right)}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                              3. associate-*r/N/A

                                \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(2, C, \color{blue}{\frac{\frac{-1}{2} \cdot {B}^{2}}{A}}\right)}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                              4. lower-/.f64N/A

                                \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(2, C, \color{blue}{\frac{\frac{-1}{2} \cdot {B}^{2}}{A}}\right)}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                              5. lower-*.f64N/A

                                \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(2, C, \frac{\color{blue}{\frac{-1}{2} \cdot {B}^{2}}}{A}\right)}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                              6. unpow2N/A

                                \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(2, C, \frac{\frac{-1}{2} \cdot \color{blue}{\left(B \cdot B\right)}}{A}\right)}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                              7. lower-*.f6431.5

                                \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(2, C, \frac{-0.5 \cdot \color{blue}{\left(B \cdot B\right)}}{A}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                            5. Applied rewrites31.5%

                              \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\mathsf{fma}\left(2, C, \frac{-0.5 \cdot \left(B \cdot B\right)}{A}\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                            6. Applied rewrites31.4%

                              \[\leadsto \color{blue}{\frac{1}{\frac{-\mathsf{fma}\left(B, B, \left(-4 \cdot C\right) \cdot A\right)}{\sqrt{\left(\mathsf{fma}\left(B, B, \left(-4 \cdot C\right) \cdot A\right) \cdot \left(F \cdot 2\right)\right) \cdot \mathsf{fma}\left(2, C, \frac{\left(B \cdot B\right) \cdot -0.5}{A}\right)}}}} \]
                            7. Applied rewrites37.0%

                              \[\leadsto \color{blue}{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, A \cdot C, B \cdot B\right)} \cdot \frac{\sqrt{\mathsf{fma}\left(2, C, \frac{\left(B \cdot B\right) \cdot -0.5}{A}\right)}}{\mathsf{fma}\left(B, -B, 4 \cdot \left(A \cdot C\right)\right)}} \]

                            if +inf.0 < (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)))

                            1. Initial program 0.0%

                              \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                            2. Add Preprocessing
                            3. Taylor expanded in B around inf

                              \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                            4. Step-by-step derivation
                              1. mul-1-negN/A

                                \[\leadsto \color{blue}{\mathsf{neg}\left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                              2. lower-neg.f64N/A

                                \[\leadsto \color{blue}{\mathsf{neg}\left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                              3. *-commutativeN/A

                                \[\leadsto \mathsf{neg}\left(\color{blue}{\sqrt{2} \cdot \sqrt{\frac{F}{B}}}\right) \]
                              4. lower-*.f64N/A

                                \[\leadsto \mathsf{neg}\left(\color{blue}{\sqrt{2} \cdot \sqrt{\frac{F}{B}}}\right) \]
                              5. lower-sqrt.f64N/A

                                \[\leadsto \mathsf{neg}\left(\color{blue}{\sqrt{2}} \cdot \sqrt{\frac{F}{B}}\right) \]
                              6. lower-sqrt.f64N/A

                                \[\leadsto \mathsf{neg}\left(\sqrt{2} \cdot \color{blue}{\sqrt{\frac{F}{B}}}\right) \]
                              7. lower-/.f6420.0

                                \[\leadsto -\sqrt{2} \cdot \sqrt{\color{blue}{\frac{F}{B}}} \]
                            5. Applied rewrites20.0%

                              \[\leadsto \color{blue}{-\sqrt{2} \cdot \sqrt{\frac{F}{B}}} \]
                            6. Step-by-step derivation
                              1. Applied rewrites29.6%

                                \[\leadsto -\frac{\sqrt{F \cdot 2}}{\sqrt{B}} \]
                              2. Step-by-step derivation
                                1. Applied rewrites29.6%

                                  \[\leadsto -\sqrt{F} \cdot \sqrt{\frac{2}{B}} \]
                              3. Recombined 4 regimes into one program.
                              4. Final simplification36.8%

                                \[\leadsto \begin{array}{l} \mathbf{if}\;\frac{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)}}{\left(4 \cdot A\right) \cdot C - {B}^{2}} \leq -\infty:\\ \;\;\;\;\frac{-1}{\frac{\mathsf{fma}\left(B, B, A \cdot \left(C \cdot -4\right)\right)}{\sqrt{\mathsf{fma}\left(2, C, \frac{\left(B \cdot B\right) \cdot -0.5}{A}\right) \cdot \mathsf{fma}\left(-4, A \cdot C, B \cdot B\right)} \cdot \sqrt{2 \cdot F}}}\\ \mathbf{elif}\;\frac{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)}}{\left(4 \cdot A\right) \cdot C - {B}^{2}} \leq -1 \cdot 10^{-220}:\\ \;\;\;\;\sqrt{\left(\mathsf{fma}\left(B, B, -4 \cdot \left(A \cdot C\right)\right) \cdot \left(2 \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{\mathsf{fma}\left(A - C, A - C, B \cdot B\right)}\right)} \cdot \frac{-1}{\mathsf{fma}\left(B, B, -4 \cdot \left(A \cdot C\right)\right)}\\ \mathbf{elif}\;\frac{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)}}{\left(4 \cdot A\right) \cdot C - {B}^{2}} \leq 0:\\ \;\;\;\;\frac{-1}{\frac{\mathsf{fma}\left(B, B, A \cdot \left(C \cdot -4\right)\right)}{\sqrt{\mathsf{fma}\left(2, C, \frac{\left(B \cdot B\right) \cdot -0.5}{A}\right) \cdot \mathsf{fma}\left(-4, A \cdot C, B \cdot B\right)} \cdot \sqrt{2 \cdot F}}}\\ \mathbf{elif}\;\frac{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)}}{\left(4 \cdot A\right) \cdot C - {B}^{2}} \leq \infty:\\ \;\;\;\;\sqrt{\mathsf{fma}\left(-4, A \cdot C, B \cdot B\right) \cdot \left(2 \cdot F\right)} \cdot \frac{\sqrt{\mathsf{fma}\left(2, C, \frac{\left(B \cdot B\right) \cdot -0.5}{A}\right)}}{\mathsf{fma}\left(B, -B, 4 \cdot \left(A \cdot C\right)\right)}\\ \mathbf{else}:\\ \;\;\;\;\left(-\sqrt{F}\right) \cdot \sqrt{\frac{2}{B}}\\ \end{array} \]
                              5. Add Preprocessing

                              Alternative 8: 57.4% accurate, 0.3× speedup?

                              \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} t_0 := \sqrt{\mathsf{fma}\left(-4, A \cdot C, B\_m \cdot B\_m\right) \cdot \left(2 \cdot F\right)} \cdot \frac{\sqrt{\mathsf{fma}\left(2, C, \frac{\left(B\_m \cdot B\_m\right) \cdot -0.5}{A}\right)}}{\mathsf{fma}\left(B\_m, -B\_m, 4 \cdot \left(A \cdot C\right)\right)}\\ t_1 := \left(4 \cdot A\right) \cdot C\\ t_2 := \frac{\sqrt{\left(2 \cdot \left(\left({B\_m}^{2} - t\_1\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{B\_m}^{2} + {\left(A - C\right)}^{2}}\right)}}{t\_1 - {B\_m}^{2}}\\ t_3 := \mathsf{fma}\left(B\_m, B\_m, -4 \cdot \left(A \cdot C\right)\right)\\ \mathbf{if}\;t\_2 \leq -\infty:\\ \;\;\;\;t\_0\\ \mathbf{elif}\;t\_2 \leq -1 \cdot 10^{-220}:\\ \;\;\;\;\sqrt{\left(t\_3 \cdot \left(2 \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{\mathsf{fma}\left(A - C, A - C, B\_m \cdot B\_m\right)}\right)} \cdot \frac{-1}{t\_3}\\ \mathbf{elif}\;t\_2 \leq \infty:\\ \;\;\;\;t\_0\\ \mathbf{else}:\\ \;\;\;\;\left(-\sqrt{F}\right) \cdot \sqrt{\frac{2}{B\_m}}\\ \end{array} \end{array} \]
                              B_m = (fabs.f64 B)
                              NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                              (FPCore (A B_m C F)
                               :precision binary64
                               (let* ((t_0
                                       (*
                                        (sqrt (* (fma -4.0 (* A C) (* B_m B_m)) (* 2.0 F)))
                                        (/
                                         (sqrt (fma 2.0 C (/ (* (* B_m B_m) -0.5) A)))
                                         (fma B_m (- B_m) (* 4.0 (* A C))))))
                                      (t_1 (* (* 4.0 A) C))
                                      (t_2
                                       (/
                                        (sqrt
                                         (*
                                          (* 2.0 (* (- (pow B_m 2.0) t_1) F))
                                          (+ (+ A C) (sqrt (+ (pow B_m 2.0) (pow (- A C) 2.0))))))
                                        (- t_1 (pow B_m 2.0))))
                                      (t_3 (fma B_m B_m (* -4.0 (* A C)))))
                                 (if (<= t_2 (- INFINITY))
                                   t_0
                                   (if (<= t_2 -1e-220)
                                     (*
                                      (sqrt
                                       (*
                                        (* t_3 (* 2.0 F))
                                        (+ (+ A C) (sqrt (fma (- A C) (- A C) (* B_m B_m))))))
                                      (/ -1.0 t_3))
                                     (if (<= t_2 INFINITY) t_0 (* (- (sqrt F)) (sqrt (/ 2.0 B_m))))))))
                              B_m = fabs(B);
                              assert(A < B_m && B_m < C && C < F);
                              double code(double A, double B_m, double C, double F) {
                              	double t_0 = sqrt((fma(-4.0, (A * C), (B_m * B_m)) * (2.0 * F))) * (sqrt(fma(2.0, C, (((B_m * B_m) * -0.5) / A))) / fma(B_m, -B_m, (4.0 * (A * C))));
                              	double t_1 = (4.0 * A) * C;
                              	double t_2 = sqrt(((2.0 * ((pow(B_m, 2.0) - t_1) * F)) * ((A + C) + sqrt((pow(B_m, 2.0) + pow((A - C), 2.0)))))) / (t_1 - pow(B_m, 2.0));
                              	double t_3 = fma(B_m, B_m, (-4.0 * (A * C)));
                              	double tmp;
                              	if (t_2 <= -((double) INFINITY)) {
                              		tmp = t_0;
                              	} else if (t_2 <= -1e-220) {
                              		tmp = sqrt(((t_3 * (2.0 * F)) * ((A + C) + sqrt(fma((A - C), (A - C), (B_m * B_m)))))) * (-1.0 / t_3);
                              	} else if (t_2 <= ((double) INFINITY)) {
                              		tmp = t_0;
                              	} else {
                              		tmp = -sqrt(F) * sqrt((2.0 / B_m));
                              	}
                              	return tmp;
                              }
                              
                              B_m = abs(B)
                              A, B_m, C, F = sort([A, B_m, C, F])
                              function code(A, B_m, C, F)
                              	t_0 = Float64(sqrt(Float64(fma(-4.0, Float64(A * C), Float64(B_m * B_m)) * Float64(2.0 * F))) * Float64(sqrt(fma(2.0, C, Float64(Float64(Float64(B_m * B_m) * -0.5) / A))) / fma(B_m, Float64(-B_m), Float64(4.0 * Float64(A * C)))))
                              	t_1 = Float64(Float64(4.0 * A) * C)
                              	t_2 = Float64(sqrt(Float64(Float64(2.0 * Float64(Float64((B_m ^ 2.0) - t_1) * F)) * Float64(Float64(A + C) + sqrt(Float64((B_m ^ 2.0) + (Float64(A - C) ^ 2.0)))))) / Float64(t_1 - (B_m ^ 2.0)))
                              	t_3 = fma(B_m, B_m, Float64(-4.0 * Float64(A * C)))
                              	tmp = 0.0
                              	if (t_2 <= Float64(-Inf))
                              		tmp = t_0;
                              	elseif (t_2 <= -1e-220)
                              		tmp = Float64(sqrt(Float64(Float64(t_3 * Float64(2.0 * F)) * Float64(Float64(A + C) + sqrt(fma(Float64(A - C), Float64(A - C), Float64(B_m * B_m)))))) * Float64(-1.0 / t_3));
                              	elseif (t_2 <= Inf)
                              		tmp = t_0;
                              	else
                              		tmp = Float64(Float64(-sqrt(F)) * sqrt(Float64(2.0 / B_m)));
                              	end
                              	return tmp
                              end
                              
                              B_m = N[Abs[B], $MachinePrecision]
                              NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                              code[A_, B$95$m_, C_, F_] := Block[{t$95$0 = N[(N[Sqrt[N[(N[(-4.0 * N[(A * C), $MachinePrecision] + N[(B$95$m * B$95$m), $MachinePrecision]), $MachinePrecision] * N[(2.0 * F), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] * N[(N[Sqrt[N[(2.0 * C + N[(N[(N[(B$95$m * B$95$m), $MachinePrecision] * -0.5), $MachinePrecision] / A), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / N[(B$95$m * (-B$95$m) + N[(4.0 * N[(A * C), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$1 = N[(N[(4.0 * A), $MachinePrecision] * C), $MachinePrecision]}, Block[{t$95$2 = N[(N[Sqrt[N[(N[(2.0 * N[(N[(N[Power[B$95$m, 2.0], $MachinePrecision] - t$95$1), $MachinePrecision] * F), $MachinePrecision]), $MachinePrecision] * N[(N[(A + C), $MachinePrecision] + N[Sqrt[N[(N[Power[B$95$m, 2.0], $MachinePrecision] + N[Power[N[(A - C), $MachinePrecision], 2.0], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / N[(t$95$1 - N[Power[B$95$m, 2.0], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$3 = N[(B$95$m * B$95$m + N[(-4.0 * N[(A * C), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[t$95$2, (-Infinity)], t$95$0, If[LessEqual[t$95$2, -1e-220], N[(N[Sqrt[N[(N[(t$95$3 * N[(2.0 * F), $MachinePrecision]), $MachinePrecision] * N[(N[(A + C), $MachinePrecision] + N[Sqrt[N[(N[(A - C), $MachinePrecision] * N[(A - C), $MachinePrecision] + N[(B$95$m * B$95$m), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] * N[(-1.0 / t$95$3), $MachinePrecision]), $MachinePrecision], If[LessEqual[t$95$2, Infinity], t$95$0, N[((-N[Sqrt[F], $MachinePrecision]) * N[Sqrt[N[(2.0 / B$95$m), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]]]]]]]]
                              
                              \begin{array}{l}
                              B_m = \left|B\right|
                              \\
                              [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
                              \\
                              \begin{array}{l}
                              t_0 := \sqrt{\mathsf{fma}\left(-4, A \cdot C, B\_m \cdot B\_m\right) \cdot \left(2 \cdot F\right)} \cdot \frac{\sqrt{\mathsf{fma}\left(2, C, \frac{\left(B\_m \cdot B\_m\right) \cdot -0.5}{A}\right)}}{\mathsf{fma}\left(B\_m, -B\_m, 4 \cdot \left(A \cdot C\right)\right)}\\
                              t_1 := \left(4 \cdot A\right) \cdot C\\
                              t_2 := \frac{\sqrt{\left(2 \cdot \left(\left({B\_m}^{2} - t\_1\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{B\_m}^{2} + {\left(A - C\right)}^{2}}\right)}}{t\_1 - {B\_m}^{2}}\\
                              t_3 := \mathsf{fma}\left(B\_m, B\_m, -4 \cdot \left(A \cdot C\right)\right)\\
                              \mathbf{if}\;t\_2 \leq -\infty:\\
                              \;\;\;\;t\_0\\
                              
                              \mathbf{elif}\;t\_2 \leq -1 \cdot 10^{-220}:\\
                              \;\;\;\;\sqrt{\left(t\_3 \cdot \left(2 \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{\mathsf{fma}\left(A - C, A - C, B\_m \cdot B\_m\right)}\right)} \cdot \frac{-1}{t\_3}\\
                              
                              \mathbf{elif}\;t\_2 \leq \infty:\\
                              \;\;\;\;t\_0\\
                              
                              \mathbf{else}:\\
                              \;\;\;\;\left(-\sqrt{F}\right) \cdot \sqrt{\frac{2}{B\_m}}\\
                              
                              
                              \end{array}
                              \end{array}
                              
                              Derivation
                              1. Split input into 3 regimes
                              2. if (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C))) < -inf.0 or -9.99999999999999992e-221 < (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C))) < +inf.0

                                1. Initial program 12.2%

                                  \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                2. Add Preprocessing
                                3. Taylor expanded in A around -inf

                                  \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\left(\frac{-1}{2} \cdot \frac{{B}^{2}}{A} + 2 \cdot C\right)}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                4. Step-by-step derivation
                                  1. +-commutativeN/A

                                    \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\left(2 \cdot C + \frac{-1}{2} \cdot \frac{{B}^{2}}{A}\right)}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                  2. lower-fma.f64N/A

                                    \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\mathsf{fma}\left(2, C, \frac{-1}{2} \cdot \frac{{B}^{2}}{A}\right)}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                  3. associate-*r/N/A

                                    \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(2, C, \color{blue}{\frac{\frac{-1}{2} \cdot {B}^{2}}{A}}\right)}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                  4. lower-/.f64N/A

                                    \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(2, C, \color{blue}{\frac{\frac{-1}{2} \cdot {B}^{2}}{A}}\right)}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                  5. lower-*.f64N/A

                                    \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(2, C, \frac{\color{blue}{\frac{-1}{2} \cdot {B}^{2}}}{A}\right)}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                  6. unpow2N/A

                                    \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(2, C, \frac{\frac{-1}{2} \cdot \color{blue}{\left(B \cdot B\right)}}{A}\right)}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                  7. lower-*.f6417.1

                                    \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(2, C, \frac{-0.5 \cdot \color{blue}{\left(B \cdot B\right)}}{A}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                5. Applied rewrites17.1%

                                  \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\mathsf{fma}\left(2, C, \frac{-0.5 \cdot \left(B \cdot B\right)}{A}\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                6. Applied rewrites17.0%

                                  \[\leadsto \color{blue}{\frac{1}{\frac{-\mathsf{fma}\left(B, B, \left(-4 \cdot C\right) \cdot A\right)}{\sqrt{\left(\mathsf{fma}\left(B, B, \left(-4 \cdot C\right) \cdot A\right) \cdot \left(F \cdot 2\right)\right) \cdot \mathsf{fma}\left(2, C, \frac{\left(B \cdot B\right) \cdot -0.5}{A}\right)}}}} \]
                                7. Applied rewrites19.7%

                                  \[\leadsto \color{blue}{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, A \cdot C, B \cdot B\right)} \cdot \frac{\sqrt{\mathsf{fma}\left(2, C, \frac{\left(B \cdot B\right) \cdot -0.5}{A}\right)}}{\mathsf{fma}\left(B, -B, 4 \cdot \left(A \cdot C\right)\right)}} \]

                                if -inf.0 < (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C))) < -9.99999999999999992e-221

                                1. Initial program 98.5%

                                  \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                2. Add Preprocessing
                                3. Applied rewrites98.8%

                                  \[\leadsto \color{blue}{\sqrt{\left(\mathsf{fma}\left(B, B, -4 \cdot \left(A \cdot C\right)\right) \cdot \left(F \cdot 2\right)\right) \cdot \left(\sqrt{\mathsf{fma}\left(A - C, A - C, B \cdot B\right)} + \left(A + C\right)\right)} \cdot \frac{-1}{\mathsf{fma}\left(B, B, -4 \cdot \left(A \cdot C\right)\right)}} \]

                                if +inf.0 < (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)))

                                1. Initial program 0.0%

                                  \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                2. Add Preprocessing
                                3. Taylor expanded in B around inf

                                  \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                4. Step-by-step derivation
                                  1. mul-1-negN/A

                                    \[\leadsto \color{blue}{\mathsf{neg}\left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                  2. lower-neg.f64N/A

                                    \[\leadsto \color{blue}{\mathsf{neg}\left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                  3. *-commutativeN/A

                                    \[\leadsto \mathsf{neg}\left(\color{blue}{\sqrt{2} \cdot \sqrt{\frac{F}{B}}}\right) \]
                                  4. lower-*.f64N/A

                                    \[\leadsto \mathsf{neg}\left(\color{blue}{\sqrt{2} \cdot \sqrt{\frac{F}{B}}}\right) \]
                                  5. lower-sqrt.f64N/A

                                    \[\leadsto \mathsf{neg}\left(\color{blue}{\sqrt{2}} \cdot \sqrt{\frac{F}{B}}\right) \]
                                  6. lower-sqrt.f64N/A

                                    \[\leadsto \mathsf{neg}\left(\sqrt{2} \cdot \color{blue}{\sqrt{\frac{F}{B}}}\right) \]
                                  7. lower-/.f6420.0

                                    \[\leadsto -\sqrt{2} \cdot \sqrt{\color{blue}{\frac{F}{B}}} \]
                                5. Applied rewrites20.0%

                                  \[\leadsto \color{blue}{-\sqrt{2} \cdot \sqrt{\frac{F}{B}}} \]
                                6. Step-by-step derivation
                                  1. Applied rewrites29.6%

                                    \[\leadsto -\frac{\sqrt{F \cdot 2}}{\sqrt{B}} \]
                                  2. Step-by-step derivation
                                    1. Applied rewrites29.6%

                                      \[\leadsto -\sqrt{F} \cdot \sqrt{\frac{2}{B}} \]
                                  3. Recombined 3 regimes into one program.
                                  4. Final simplification35.2%

                                    \[\leadsto \begin{array}{l} \mathbf{if}\;\frac{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)}}{\left(4 \cdot A\right) \cdot C - {B}^{2}} \leq -\infty:\\ \;\;\;\;\sqrt{\mathsf{fma}\left(-4, A \cdot C, B \cdot B\right) \cdot \left(2 \cdot F\right)} \cdot \frac{\sqrt{\mathsf{fma}\left(2, C, \frac{\left(B \cdot B\right) \cdot -0.5}{A}\right)}}{\mathsf{fma}\left(B, -B, 4 \cdot \left(A \cdot C\right)\right)}\\ \mathbf{elif}\;\frac{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)}}{\left(4 \cdot A\right) \cdot C - {B}^{2}} \leq -1 \cdot 10^{-220}:\\ \;\;\;\;\sqrt{\left(\mathsf{fma}\left(B, B, -4 \cdot \left(A \cdot C\right)\right) \cdot \left(2 \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{\mathsf{fma}\left(A - C, A - C, B \cdot B\right)}\right)} \cdot \frac{-1}{\mathsf{fma}\left(B, B, -4 \cdot \left(A \cdot C\right)\right)}\\ \mathbf{elif}\;\frac{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)}}{\left(4 \cdot A\right) \cdot C - {B}^{2}} \leq \infty:\\ \;\;\;\;\sqrt{\mathsf{fma}\left(-4, A \cdot C, B \cdot B\right) \cdot \left(2 \cdot F\right)} \cdot \frac{\sqrt{\mathsf{fma}\left(2, C, \frac{\left(B \cdot B\right) \cdot -0.5}{A}\right)}}{\mathsf{fma}\left(B, -B, 4 \cdot \left(A \cdot C\right)\right)}\\ \mathbf{else}:\\ \;\;\;\;\left(-\sqrt{F}\right) \cdot \sqrt{\frac{2}{B}}\\ \end{array} \]
                                  5. Add Preprocessing

                                  Alternative 9: 53.7% accurate, 0.3× speedup?

                                  \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} t_0 := \mathsf{fma}\left(B\_m, B\_m, A \cdot \left(C \cdot -4\right)\right)\\ t_1 := \left(4 \cdot A\right) \cdot C\\ t_2 := \frac{\sqrt{\left(2 \cdot \left(\left({B\_m}^{2} - t\_1\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{B\_m}^{2} + {\left(A - C\right)}^{2}}\right)}}{t\_1 - {B\_m}^{2}}\\ t_3 := \mathsf{fma}\left(B\_m, B\_m, -4 \cdot \left(A \cdot C\right)\right)\\ \mathbf{if}\;t\_2 \leq -\infty:\\ \;\;\;\;\sqrt{F \cdot \left(-0.5 \cdot \frac{B\_m \cdot B\_m}{A}\right)} \cdot \frac{\sqrt{2}}{-B\_m}\\ \mathbf{elif}\;t\_2 \leq -1 \cdot 10^{-220}:\\ \;\;\;\;\sqrt{\left(t\_3 \cdot \left(2 \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{\mathsf{fma}\left(A - C, A - C, B\_m \cdot B\_m\right)}\right)} \cdot \frac{-1}{t\_3}\\ \mathbf{elif}\;t\_2 \leq \infty:\\ \;\;\;\;\frac{\sqrt{\mathsf{fma}\left(2, C, \frac{\left(B\_m \cdot B\_m\right) \cdot -0.5}{A}\right) \cdot \left(t\_0 \cdot \left(2 \cdot F\right)\right)}}{-t\_0}\\ \mathbf{else}:\\ \;\;\;\;\left(-\sqrt{F}\right) \cdot \sqrt{\frac{2}{B\_m}}\\ \end{array} \end{array} \]
                                  B_m = (fabs.f64 B)
                                  NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                  (FPCore (A B_m C F)
                                   :precision binary64
                                   (let* ((t_0 (fma B_m B_m (* A (* C -4.0))))
                                          (t_1 (* (* 4.0 A) C))
                                          (t_2
                                           (/
                                            (sqrt
                                             (*
                                              (* 2.0 (* (- (pow B_m 2.0) t_1) F))
                                              (+ (+ A C) (sqrt (+ (pow B_m 2.0) (pow (- A C) 2.0))))))
                                            (- t_1 (pow B_m 2.0))))
                                          (t_3 (fma B_m B_m (* -4.0 (* A C)))))
                                     (if (<= t_2 (- INFINITY))
                                       (* (sqrt (* F (* -0.5 (/ (* B_m B_m) A)))) (/ (sqrt 2.0) (- B_m)))
                                       (if (<= t_2 -1e-220)
                                         (*
                                          (sqrt
                                           (*
                                            (* t_3 (* 2.0 F))
                                            (+ (+ A C) (sqrt (fma (- A C) (- A C) (* B_m B_m))))))
                                          (/ -1.0 t_3))
                                         (if (<= t_2 INFINITY)
                                           (/
                                            (sqrt (* (fma 2.0 C (/ (* (* B_m B_m) -0.5) A)) (* t_0 (* 2.0 F))))
                                            (- t_0))
                                           (* (- (sqrt F)) (sqrt (/ 2.0 B_m))))))))
                                  B_m = fabs(B);
                                  assert(A < B_m && B_m < C && C < F);
                                  double code(double A, double B_m, double C, double F) {
                                  	double t_0 = fma(B_m, B_m, (A * (C * -4.0)));
                                  	double t_1 = (4.0 * A) * C;
                                  	double t_2 = sqrt(((2.0 * ((pow(B_m, 2.0) - t_1) * F)) * ((A + C) + sqrt((pow(B_m, 2.0) + pow((A - C), 2.0)))))) / (t_1 - pow(B_m, 2.0));
                                  	double t_3 = fma(B_m, B_m, (-4.0 * (A * C)));
                                  	double tmp;
                                  	if (t_2 <= -((double) INFINITY)) {
                                  		tmp = sqrt((F * (-0.5 * ((B_m * B_m) / A)))) * (sqrt(2.0) / -B_m);
                                  	} else if (t_2 <= -1e-220) {
                                  		tmp = sqrt(((t_3 * (2.0 * F)) * ((A + C) + sqrt(fma((A - C), (A - C), (B_m * B_m)))))) * (-1.0 / t_3);
                                  	} else if (t_2 <= ((double) INFINITY)) {
                                  		tmp = sqrt((fma(2.0, C, (((B_m * B_m) * -0.5) / A)) * (t_0 * (2.0 * F)))) / -t_0;
                                  	} else {
                                  		tmp = -sqrt(F) * sqrt((2.0 / B_m));
                                  	}
                                  	return tmp;
                                  }
                                  
                                  B_m = abs(B)
                                  A, B_m, C, F = sort([A, B_m, C, F])
                                  function code(A, B_m, C, F)
                                  	t_0 = fma(B_m, B_m, Float64(A * Float64(C * -4.0)))
                                  	t_1 = Float64(Float64(4.0 * A) * C)
                                  	t_2 = Float64(sqrt(Float64(Float64(2.0 * Float64(Float64((B_m ^ 2.0) - t_1) * F)) * Float64(Float64(A + C) + sqrt(Float64((B_m ^ 2.0) + (Float64(A - C) ^ 2.0)))))) / Float64(t_1 - (B_m ^ 2.0)))
                                  	t_3 = fma(B_m, B_m, Float64(-4.0 * Float64(A * C)))
                                  	tmp = 0.0
                                  	if (t_2 <= Float64(-Inf))
                                  		tmp = Float64(sqrt(Float64(F * Float64(-0.5 * Float64(Float64(B_m * B_m) / A)))) * Float64(sqrt(2.0) / Float64(-B_m)));
                                  	elseif (t_2 <= -1e-220)
                                  		tmp = Float64(sqrt(Float64(Float64(t_3 * Float64(2.0 * F)) * Float64(Float64(A + C) + sqrt(fma(Float64(A - C), Float64(A - C), Float64(B_m * B_m)))))) * Float64(-1.0 / t_3));
                                  	elseif (t_2 <= Inf)
                                  		tmp = Float64(sqrt(Float64(fma(2.0, C, Float64(Float64(Float64(B_m * B_m) * -0.5) / A)) * Float64(t_0 * Float64(2.0 * F)))) / Float64(-t_0));
                                  	else
                                  		tmp = Float64(Float64(-sqrt(F)) * sqrt(Float64(2.0 / B_m)));
                                  	end
                                  	return tmp
                                  end
                                  
                                  B_m = N[Abs[B], $MachinePrecision]
                                  NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                  code[A_, B$95$m_, C_, F_] := Block[{t$95$0 = N[(B$95$m * B$95$m + N[(A * N[(C * -4.0), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$1 = N[(N[(4.0 * A), $MachinePrecision] * C), $MachinePrecision]}, Block[{t$95$2 = N[(N[Sqrt[N[(N[(2.0 * N[(N[(N[Power[B$95$m, 2.0], $MachinePrecision] - t$95$1), $MachinePrecision] * F), $MachinePrecision]), $MachinePrecision] * N[(N[(A + C), $MachinePrecision] + N[Sqrt[N[(N[Power[B$95$m, 2.0], $MachinePrecision] + N[Power[N[(A - C), $MachinePrecision], 2.0], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / N[(t$95$1 - N[Power[B$95$m, 2.0], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$3 = N[(B$95$m * B$95$m + N[(-4.0 * N[(A * C), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[t$95$2, (-Infinity)], N[(N[Sqrt[N[(F * N[(-0.5 * N[(N[(B$95$m * B$95$m), $MachinePrecision] / A), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] * N[(N[Sqrt[2.0], $MachinePrecision] / (-B$95$m)), $MachinePrecision]), $MachinePrecision], If[LessEqual[t$95$2, -1e-220], N[(N[Sqrt[N[(N[(t$95$3 * N[(2.0 * F), $MachinePrecision]), $MachinePrecision] * N[(N[(A + C), $MachinePrecision] + N[Sqrt[N[(N[(A - C), $MachinePrecision] * N[(A - C), $MachinePrecision] + N[(B$95$m * B$95$m), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] * N[(-1.0 / t$95$3), $MachinePrecision]), $MachinePrecision], If[LessEqual[t$95$2, Infinity], N[(N[Sqrt[N[(N[(2.0 * C + N[(N[(N[(B$95$m * B$95$m), $MachinePrecision] * -0.5), $MachinePrecision] / A), $MachinePrecision]), $MachinePrecision] * N[(t$95$0 * N[(2.0 * F), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / (-t$95$0)), $MachinePrecision], N[((-N[Sqrt[F], $MachinePrecision]) * N[Sqrt[N[(2.0 / B$95$m), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]]]]]]]]
                                  
                                  \begin{array}{l}
                                  B_m = \left|B\right|
                                  \\
                                  [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
                                  \\
                                  \begin{array}{l}
                                  t_0 := \mathsf{fma}\left(B\_m, B\_m, A \cdot \left(C \cdot -4\right)\right)\\
                                  t_1 := \left(4 \cdot A\right) \cdot C\\
                                  t_2 := \frac{\sqrt{\left(2 \cdot \left(\left({B\_m}^{2} - t\_1\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{B\_m}^{2} + {\left(A - C\right)}^{2}}\right)}}{t\_1 - {B\_m}^{2}}\\
                                  t_3 := \mathsf{fma}\left(B\_m, B\_m, -4 \cdot \left(A \cdot C\right)\right)\\
                                  \mathbf{if}\;t\_2 \leq -\infty:\\
                                  \;\;\;\;\sqrt{F \cdot \left(-0.5 \cdot \frac{B\_m \cdot B\_m}{A}\right)} \cdot \frac{\sqrt{2}}{-B\_m}\\
                                  
                                  \mathbf{elif}\;t\_2 \leq -1 \cdot 10^{-220}:\\
                                  \;\;\;\;\sqrt{\left(t\_3 \cdot \left(2 \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{\mathsf{fma}\left(A - C, A - C, B\_m \cdot B\_m\right)}\right)} \cdot \frac{-1}{t\_3}\\
                                  
                                  \mathbf{elif}\;t\_2 \leq \infty:\\
                                  \;\;\;\;\frac{\sqrt{\mathsf{fma}\left(2, C, \frac{\left(B\_m \cdot B\_m\right) \cdot -0.5}{A}\right) \cdot \left(t\_0 \cdot \left(2 \cdot F\right)\right)}}{-t\_0}\\
                                  
                                  \mathbf{else}:\\
                                  \;\;\;\;\left(-\sqrt{F}\right) \cdot \sqrt{\frac{2}{B\_m}}\\
                                  
                                  
                                  \end{array}
                                  \end{array}
                                  
                                  Derivation
                                  1. Split input into 4 regimes
                                  2. if (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C))) < -inf.0

                                    1. Initial program 3.6%

                                      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                    2. Add Preprocessing
                                    3. Taylor expanded in C around 0

                                      \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A + \sqrt{{A}^{2} + {B}^{2}}\right)}\right)} \]
                                    4. Step-by-step derivation
                                      1. mul-1-negN/A

                                        \[\leadsto \color{blue}{\mathsf{neg}\left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A + \sqrt{{A}^{2} + {B}^{2}}\right)}\right)} \]
                                      2. *-commutativeN/A

                                        \[\leadsto \mathsf{neg}\left(\color{blue}{\sqrt{F \cdot \left(A + \sqrt{{A}^{2} + {B}^{2}}\right)} \cdot \frac{\sqrt{2}}{B}}\right) \]
                                      3. distribute-rgt-neg-inN/A

                                        \[\leadsto \color{blue}{\sqrt{F \cdot \left(A + \sqrt{{A}^{2} + {B}^{2}}\right)} \cdot \left(\mathsf{neg}\left(\frac{\sqrt{2}}{B}\right)\right)} \]
                                      4. mul-1-negN/A

                                        \[\leadsto \sqrt{F \cdot \left(A + \sqrt{{A}^{2} + {B}^{2}}\right)} \cdot \color{blue}{\left(-1 \cdot \frac{\sqrt{2}}{B}\right)} \]
                                      5. lower-*.f64N/A

                                        \[\leadsto \color{blue}{\sqrt{F \cdot \left(A + \sqrt{{A}^{2} + {B}^{2}}\right)} \cdot \left(-1 \cdot \frac{\sqrt{2}}{B}\right)} \]
                                    5. Applied rewrites5.4%

                                      \[\leadsto \color{blue}{\sqrt{F \cdot \left(A + \sqrt{\mathsf{fma}\left(B, B, A \cdot A\right)}\right)} \cdot \left(-\frac{\sqrt{2}}{B}\right)} \]
                                    6. Taylor expanded in A around -inf

                                      \[\leadsto \sqrt{F \cdot \left(\frac{-1}{2} \cdot \frac{{B}^{2}}{A}\right)} \cdot \left(\mathsf{neg}\left(\frac{\sqrt{2}}{B}\right)\right) \]
                                    7. Step-by-step derivation
                                      1. Applied rewrites8.4%

                                        \[\leadsto \sqrt{F \cdot \left(-0.5 \cdot \frac{B \cdot B}{A}\right)} \cdot \left(-\frac{\sqrt{2}}{B}\right) \]

                                      if -inf.0 < (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C))) < -9.99999999999999992e-221

                                      1. Initial program 98.5%

                                        \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                      2. Add Preprocessing
                                      3. Applied rewrites98.8%

                                        \[\leadsto \color{blue}{\sqrt{\left(\mathsf{fma}\left(B, B, -4 \cdot \left(A \cdot C\right)\right) \cdot \left(F \cdot 2\right)\right) \cdot \left(\sqrt{\mathsf{fma}\left(A - C, A - C, B \cdot B\right)} + \left(A + C\right)\right)} \cdot \frac{-1}{\mathsf{fma}\left(B, B, -4 \cdot \left(A \cdot C\right)\right)}} \]

                                      if -9.99999999999999992e-221 < (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C))) < +inf.0

                                      1. Initial program 18.5%

                                        \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                      2. Add Preprocessing
                                      3. Taylor expanded in A around -inf

                                        \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\left(\frac{-1}{2} \cdot \frac{{B}^{2}}{A} + 2 \cdot C\right)}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                      4. Step-by-step derivation
                                        1. +-commutativeN/A

                                          \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\left(2 \cdot C + \frac{-1}{2} \cdot \frac{{B}^{2}}{A}\right)}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                        2. lower-fma.f64N/A

                                          \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\mathsf{fma}\left(2, C, \frac{-1}{2} \cdot \frac{{B}^{2}}{A}\right)}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                        3. associate-*r/N/A

                                          \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(2, C, \color{blue}{\frac{\frac{-1}{2} \cdot {B}^{2}}{A}}\right)}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                        4. lower-/.f64N/A

                                          \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(2, C, \color{blue}{\frac{\frac{-1}{2} \cdot {B}^{2}}{A}}\right)}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                        5. lower-*.f64N/A

                                          \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(2, C, \frac{\color{blue}{\frac{-1}{2} \cdot {B}^{2}}}{A}\right)}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                        6. unpow2N/A

                                          \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(2, C, \frac{\frac{-1}{2} \cdot \color{blue}{\left(B \cdot B\right)}}{A}\right)}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                        7. lower-*.f6425.3

                                          \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(2, C, \frac{-0.5 \cdot \color{blue}{\left(B \cdot B\right)}}{A}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                      5. Applied rewrites25.3%

                                        \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\mathsf{fma}\left(2, C, \frac{-0.5 \cdot \left(B \cdot B\right)}{A}\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                      6. Applied rewrites25.3%

                                        \[\leadsto \color{blue}{\frac{\sqrt{\left(\mathsf{fma}\left(B, B, \left(-4 \cdot C\right) \cdot A\right) \cdot \left(F \cdot 2\right)\right) \cdot \mathsf{fma}\left(2, C, \frac{\left(B \cdot B\right) \cdot -0.5}{A}\right)}}{-\mathsf{fma}\left(B, B, \left(-4 \cdot C\right) \cdot A\right)}} \]

                                      if +inf.0 < (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)))

                                      1. Initial program 0.0%

                                        \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                      2. Add Preprocessing
                                      3. Taylor expanded in B around inf

                                        \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                      4. Step-by-step derivation
                                        1. mul-1-negN/A

                                          \[\leadsto \color{blue}{\mathsf{neg}\left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                        2. lower-neg.f64N/A

                                          \[\leadsto \color{blue}{\mathsf{neg}\left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                        3. *-commutativeN/A

                                          \[\leadsto \mathsf{neg}\left(\color{blue}{\sqrt{2} \cdot \sqrt{\frac{F}{B}}}\right) \]
                                        4. lower-*.f64N/A

                                          \[\leadsto \mathsf{neg}\left(\color{blue}{\sqrt{2} \cdot \sqrt{\frac{F}{B}}}\right) \]
                                        5. lower-sqrt.f64N/A

                                          \[\leadsto \mathsf{neg}\left(\color{blue}{\sqrt{2}} \cdot \sqrt{\frac{F}{B}}\right) \]
                                        6. lower-sqrt.f64N/A

                                          \[\leadsto \mathsf{neg}\left(\sqrt{2} \cdot \color{blue}{\sqrt{\frac{F}{B}}}\right) \]
                                        7. lower-/.f6420.0

                                          \[\leadsto -\sqrt{2} \cdot \sqrt{\color{blue}{\frac{F}{B}}} \]
                                      5. Applied rewrites20.0%

                                        \[\leadsto \color{blue}{-\sqrt{2} \cdot \sqrt{\frac{F}{B}}} \]
                                      6. Step-by-step derivation
                                        1. Applied rewrites29.6%

                                          \[\leadsto -\frac{\sqrt{F \cdot 2}}{\sqrt{B}} \]
                                        2. Step-by-step derivation
                                          1. Applied rewrites29.6%

                                            \[\leadsto -\sqrt{F} \cdot \sqrt{\frac{2}{B}} \]
                                        3. Recombined 4 regimes into one program.
                                        4. Final simplification34.7%

                                          \[\leadsto \begin{array}{l} \mathbf{if}\;\frac{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)}}{\left(4 \cdot A\right) \cdot C - {B}^{2}} \leq -\infty:\\ \;\;\;\;\sqrt{F \cdot \left(-0.5 \cdot \frac{B \cdot B}{A}\right)} \cdot \frac{\sqrt{2}}{-B}\\ \mathbf{elif}\;\frac{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)}}{\left(4 \cdot A\right) \cdot C - {B}^{2}} \leq -1 \cdot 10^{-220}:\\ \;\;\;\;\sqrt{\left(\mathsf{fma}\left(B, B, -4 \cdot \left(A \cdot C\right)\right) \cdot \left(2 \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{\mathsf{fma}\left(A - C, A - C, B \cdot B\right)}\right)} \cdot \frac{-1}{\mathsf{fma}\left(B, B, -4 \cdot \left(A \cdot C\right)\right)}\\ \mathbf{elif}\;\frac{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)}}{\left(4 \cdot A\right) \cdot C - {B}^{2}} \leq \infty:\\ \;\;\;\;\frac{\sqrt{\mathsf{fma}\left(2, C, \frac{\left(B \cdot B\right) \cdot -0.5}{A}\right) \cdot \left(\mathsf{fma}\left(B, B, A \cdot \left(C \cdot -4\right)\right) \cdot \left(2 \cdot F\right)\right)}}{-\mathsf{fma}\left(B, B, A \cdot \left(C \cdot -4\right)\right)}\\ \mathbf{else}:\\ \;\;\;\;\left(-\sqrt{F}\right) \cdot \sqrt{\frac{2}{B}}\\ \end{array} \]
                                        5. Add Preprocessing

                                        Alternative 10: 53.8% accurate, 0.3× speedup?

                                        \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} t_0 := \mathsf{fma}\left(B\_m, B\_m, A \cdot \left(C \cdot -4\right)\right)\\ t_1 := \left(4 \cdot A\right) \cdot C\\ t_2 := \frac{\sqrt{\left(2 \cdot \left(\left({B\_m}^{2} - t\_1\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{B\_m}^{2} + {\left(A - C\right)}^{2}}\right)}}{t\_1 - {B\_m}^{2}}\\ t_3 := \mathsf{fma}\left(B\_m, B\_m, -4 \cdot \left(A \cdot C\right)\right)\\ \mathbf{if}\;t\_2 \leq -\infty:\\ \;\;\;\;\sqrt{F \cdot \left(-0.5 \cdot \frac{B\_m \cdot B\_m}{A}\right)} \cdot \frac{\sqrt{2}}{-B\_m}\\ \mathbf{elif}\;t\_2 \leq -1 \cdot 10^{-220}:\\ \;\;\;\;\frac{\sqrt{\left(t\_3 \cdot \left(2 \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{\mathsf{fma}\left(A - C, A - C, B\_m \cdot B\_m\right)}\right)}}{-t\_3}\\ \mathbf{elif}\;t\_2 \leq \infty:\\ \;\;\;\;\frac{\sqrt{\mathsf{fma}\left(2, C, \frac{\left(B\_m \cdot B\_m\right) \cdot -0.5}{A}\right) \cdot \left(t\_0 \cdot \left(2 \cdot F\right)\right)}}{-t\_0}\\ \mathbf{else}:\\ \;\;\;\;\left(-\sqrt{F}\right) \cdot \sqrt{\frac{2}{B\_m}}\\ \end{array} \end{array} \]
                                        B_m = (fabs.f64 B)
                                        NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                        (FPCore (A B_m C F)
                                         :precision binary64
                                         (let* ((t_0 (fma B_m B_m (* A (* C -4.0))))
                                                (t_1 (* (* 4.0 A) C))
                                                (t_2
                                                 (/
                                                  (sqrt
                                                   (*
                                                    (* 2.0 (* (- (pow B_m 2.0) t_1) F))
                                                    (+ (+ A C) (sqrt (+ (pow B_m 2.0) (pow (- A C) 2.0))))))
                                                  (- t_1 (pow B_m 2.0))))
                                                (t_3 (fma B_m B_m (* -4.0 (* A C)))))
                                           (if (<= t_2 (- INFINITY))
                                             (* (sqrt (* F (* -0.5 (/ (* B_m B_m) A)))) (/ (sqrt 2.0) (- B_m)))
                                             (if (<= t_2 -1e-220)
                                               (/
                                                (sqrt
                                                 (*
                                                  (* t_3 (* 2.0 F))
                                                  (+ (+ A C) (sqrt (fma (- A C) (- A C) (* B_m B_m))))))
                                                (- t_3))
                                               (if (<= t_2 INFINITY)
                                                 (/
                                                  (sqrt (* (fma 2.0 C (/ (* (* B_m B_m) -0.5) A)) (* t_0 (* 2.0 F))))
                                                  (- t_0))
                                                 (* (- (sqrt F)) (sqrt (/ 2.0 B_m))))))))
                                        B_m = fabs(B);
                                        assert(A < B_m && B_m < C && C < F);
                                        double code(double A, double B_m, double C, double F) {
                                        	double t_0 = fma(B_m, B_m, (A * (C * -4.0)));
                                        	double t_1 = (4.0 * A) * C;
                                        	double t_2 = sqrt(((2.0 * ((pow(B_m, 2.0) - t_1) * F)) * ((A + C) + sqrt((pow(B_m, 2.0) + pow((A - C), 2.0)))))) / (t_1 - pow(B_m, 2.0));
                                        	double t_3 = fma(B_m, B_m, (-4.0 * (A * C)));
                                        	double tmp;
                                        	if (t_2 <= -((double) INFINITY)) {
                                        		tmp = sqrt((F * (-0.5 * ((B_m * B_m) / A)))) * (sqrt(2.0) / -B_m);
                                        	} else if (t_2 <= -1e-220) {
                                        		tmp = sqrt(((t_3 * (2.0 * F)) * ((A + C) + sqrt(fma((A - C), (A - C), (B_m * B_m)))))) / -t_3;
                                        	} else if (t_2 <= ((double) INFINITY)) {
                                        		tmp = sqrt((fma(2.0, C, (((B_m * B_m) * -0.5) / A)) * (t_0 * (2.0 * F)))) / -t_0;
                                        	} else {
                                        		tmp = -sqrt(F) * sqrt((2.0 / B_m));
                                        	}
                                        	return tmp;
                                        }
                                        
                                        B_m = abs(B)
                                        A, B_m, C, F = sort([A, B_m, C, F])
                                        function code(A, B_m, C, F)
                                        	t_0 = fma(B_m, B_m, Float64(A * Float64(C * -4.0)))
                                        	t_1 = Float64(Float64(4.0 * A) * C)
                                        	t_2 = Float64(sqrt(Float64(Float64(2.0 * Float64(Float64((B_m ^ 2.0) - t_1) * F)) * Float64(Float64(A + C) + sqrt(Float64((B_m ^ 2.0) + (Float64(A - C) ^ 2.0)))))) / Float64(t_1 - (B_m ^ 2.0)))
                                        	t_3 = fma(B_m, B_m, Float64(-4.0 * Float64(A * C)))
                                        	tmp = 0.0
                                        	if (t_2 <= Float64(-Inf))
                                        		tmp = Float64(sqrt(Float64(F * Float64(-0.5 * Float64(Float64(B_m * B_m) / A)))) * Float64(sqrt(2.0) / Float64(-B_m)));
                                        	elseif (t_2 <= -1e-220)
                                        		tmp = Float64(sqrt(Float64(Float64(t_3 * Float64(2.0 * F)) * Float64(Float64(A + C) + sqrt(fma(Float64(A - C), Float64(A - C), Float64(B_m * B_m)))))) / Float64(-t_3));
                                        	elseif (t_2 <= Inf)
                                        		tmp = Float64(sqrt(Float64(fma(2.0, C, Float64(Float64(Float64(B_m * B_m) * -0.5) / A)) * Float64(t_0 * Float64(2.0 * F)))) / Float64(-t_0));
                                        	else
                                        		tmp = Float64(Float64(-sqrt(F)) * sqrt(Float64(2.0 / B_m)));
                                        	end
                                        	return tmp
                                        end
                                        
                                        B_m = N[Abs[B], $MachinePrecision]
                                        NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                        code[A_, B$95$m_, C_, F_] := Block[{t$95$0 = N[(B$95$m * B$95$m + N[(A * N[(C * -4.0), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$1 = N[(N[(4.0 * A), $MachinePrecision] * C), $MachinePrecision]}, Block[{t$95$2 = N[(N[Sqrt[N[(N[(2.0 * N[(N[(N[Power[B$95$m, 2.0], $MachinePrecision] - t$95$1), $MachinePrecision] * F), $MachinePrecision]), $MachinePrecision] * N[(N[(A + C), $MachinePrecision] + N[Sqrt[N[(N[Power[B$95$m, 2.0], $MachinePrecision] + N[Power[N[(A - C), $MachinePrecision], 2.0], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / N[(t$95$1 - N[Power[B$95$m, 2.0], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$3 = N[(B$95$m * B$95$m + N[(-4.0 * N[(A * C), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[t$95$2, (-Infinity)], N[(N[Sqrt[N[(F * N[(-0.5 * N[(N[(B$95$m * B$95$m), $MachinePrecision] / A), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] * N[(N[Sqrt[2.0], $MachinePrecision] / (-B$95$m)), $MachinePrecision]), $MachinePrecision], If[LessEqual[t$95$2, -1e-220], N[(N[Sqrt[N[(N[(t$95$3 * N[(2.0 * F), $MachinePrecision]), $MachinePrecision] * N[(N[(A + C), $MachinePrecision] + N[Sqrt[N[(N[(A - C), $MachinePrecision] * N[(A - C), $MachinePrecision] + N[(B$95$m * B$95$m), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / (-t$95$3)), $MachinePrecision], If[LessEqual[t$95$2, Infinity], N[(N[Sqrt[N[(N[(2.0 * C + N[(N[(N[(B$95$m * B$95$m), $MachinePrecision] * -0.5), $MachinePrecision] / A), $MachinePrecision]), $MachinePrecision] * N[(t$95$0 * N[(2.0 * F), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / (-t$95$0)), $MachinePrecision], N[((-N[Sqrt[F], $MachinePrecision]) * N[Sqrt[N[(2.0 / B$95$m), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]]]]]]]]
                                        
                                        \begin{array}{l}
                                        B_m = \left|B\right|
                                        \\
                                        [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
                                        \\
                                        \begin{array}{l}
                                        t_0 := \mathsf{fma}\left(B\_m, B\_m, A \cdot \left(C \cdot -4\right)\right)\\
                                        t_1 := \left(4 \cdot A\right) \cdot C\\
                                        t_2 := \frac{\sqrt{\left(2 \cdot \left(\left({B\_m}^{2} - t\_1\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{B\_m}^{2} + {\left(A - C\right)}^{2}}\right)}}{t\_1 - {B\_m}^{2}}\\
                                        t_3 := \mathsf{fma}\left(B\_m, B\_m, -4 \cdot \left(A \cdot C\right)\right)\\
                                        \mathbf{if}\;t\_2 \leq -\infty:\\
                                        \;\;\;\;\sqrt{F \cdot \left(-0.5 \cdot \frac{B\_m \cdot B\_m}{A}\right)} \cdot \frac{\sqrt{2}}{-B\_m}\\
                                        
                                        \mathbf{elif}\;t\_2 \leq -1 \cdot 10^{-220}:\\
                                        \;\;\;\;\frac{\sqrt{\left(t\_3 \cdot \left(2 \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{\mathsf{fma}\left(A - C, A - C, B\_m \cdot B\_m\right)}\right)}}{-t\_3}\\
                                        
                                        \mathbf{elif}\;t\_2 \leq \infty:\\
                                        \;\;\;\;\frac{\sqrt{\mathsf{fma}\left(2, C, \frac{\left(B\_m \cdot B\_m\right) \cdot -0.5}{A}\right) \cdot \left(t\_0 \cdot \left(2 \cdot F\right)\right)}}{-t\_0}\\
                                        
                                        \mathbf{else}:\\
                                        \;\;\;\;\left(-\sqrt{F}\right) \cdot \sqrt{\frac{2}{B\_m}}\\
                                        
                                        
                                        \end{array}
                                        \end{array}
                                        
                                        Derivation
                                        1. Split input into 4 regimes
                                        2. if (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C))) < -inf.0

                                          1. Initial program 3.6%

                                            \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                          2. Add Preprocessing
                                          3. Taylor expanded in C around 0

                                            \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A + \sqrt{{A}^{2} + {B}^{2}}\right)}\right)} \]
                                          4. Step-by-step derivation
                                            1. mul-1-negN/A

                                              \[\leadsto \color{blue}{\mathsf{neg}\left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A + \sqrt{{A}^{2} + {B}^{2}}\right)}\right)} \]
                                            2. *-commutativeN/A

                                              \[\leadsto \mathsf{neg}\left(\color{blue}{\sqrt{F \cdot \left(A + \sqrt{{A}^{2} + {B}^{2}}\right)} \cdot \frac{\sqrt{2}}{B}}\right) \]
                                            3. distribute-rgt-neg-inN/A

                                              \[\leadsto \color{blue}{\sqrt{F \cdot \left(A + \sqrt{{A}^{2} + {B}^{2}}\right)} \cdot \left(\mathsf{neg}\left(\frac{\sqrt{2}}{B}\right)\right)} \]
                                            4. mul-1-negN/A

                                              \[\leadsto \sqrt{F \cdot \left(A + \sqrt{{A}^{2} + {B}^{2}}\right)} \cdot \color{blue}{\left(-1 \cdot \frac{\sqrt{2}}{B}\right)} \]
                                            5. lower-*.f64N/A

                                              \[\leadsto \color{blue}{\sqrt{F \cdot \left(A + \sqrt{{A}^{2} + {B}^{2}}\right)} \cdot \left(-1 \cdot \frac{\sqrt{2}}{B}\right)} \]
                                          5. Applied rewrites5.4%

                                            \[\leadsto \color{blue}{\sqrt{F \cdot \left(A + \sqrt{\mathsf{fma}\left(B, B, A \cdot A\right)}\right)} \cdot \left(-\frac{\sqrt{2}}{B}\right)} \]
                                          6. Taylor expanded in A around -inf

                                            \[\leadsto \sqrt{F \cdot \left(\frac{-1}{2} \cdot \frac{{B}^{2}}{A}\right)} \cdot \left(\mathsf{neg}\left(\frac{\sqrt{2}}{B}\right)\right) \]
                                          7. Step-by-step derivation
                                            1. Applied rewrites8.4%

                                              \[\leadsto \sqrt{F \cdot \left(-0.5 \cdot \frac{B \cdot B}{A}\right)} \cdot \left(-\frac{\sqrt{2}}{B}\right) \]

                                            if -inf.0 < (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C))) < -9.99999999999999992e-221

                                            1. Initial program 98.5%

                                              \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                            2. Add Preprocessing
                                            3. Step-by-step derivation
                                              1. lift-/.f64N/A

                                                \[\leadsto \color{blue}{\frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C}} \]
                                              2. frac-2negN/A

                                                \[\leadsto \color{blue}{\frac{\mathsf{neg}\left(\left(\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}\right)\right)\right)}{\mathsf{neg}\left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)\right)}} \]
                                              3. lift-neg.f64N/A

                                                \[\leadsto \frac{\mathsf{neg}\left(\color{blue}{\left(\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}\right)\right)}\right)}{\mathsf{neg}\left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)\right)} \]
                                              4. remove-double-negN/A

                                                \[\leadsto \frac{\color{blue}{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}}{\mathsf{neg}\left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)\right)} \]
                                              5. lower-/.f64N/A

                                                \[\leadsto \color{blue}{\frac{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{\mathsf{neg}\left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)\right)}} \]
                                            4. Applied rewrites98.5%

                                              \[\leadsto \color{blue}{\frac{\sqrt{\left(\mathsf{fma}\left(B, B, -4 \cdot \left(A \cdot C\right)\right) \cdot \left(F \cdot 2\right)\right) \cdot \left(\sqrt{\mathsf{fma}\left(A - C, A - C, B \cdot B\right)} + \left(A + C\right)\right)}}{-\mathsf{fma}\left(B, B, -4 \cdot \left(A \cdot C\right)\right)}} \]

                                            if -9.99999999999999992e-221 < (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C))) < +inf.0

                                            1. Initial program 18.5%

                                              \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                            2. Add Preprocessing
                                            3. Taylor expanded in A around -inf

                                              \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\left(\frac{-1}{2} \cdot \frac{{B}^{2}}{A} + 2 \cdot C\right)}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                            4. Step-by-step derivation
                                              1. +-commutativeN/A

                                                \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\left(2 \cdot C + \frac{-1}{2} \cdot \frac{{B}^{2}}{A}\right)}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                              2. lower-fma.f64N/A

                                                \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\mathsf{fma}\left(2, C, \frac{-1}{2} \cdot \frac{{B}^{2}}{A}\right)}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                              3. associate-*r/N/A

                                                \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(2, C, \color{blue}{\frac{\frac{-1}{2} \cdot {B}^{2}}{A}}\right)}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                              4. lower-/.f64N/A

                                                \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(2, C, \color{blue}{\frac{\frac{-1}{2} \cdot {B}^{2}}{A}}\right)}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                              5. lower-*.f64N/A

                                                \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(2, C, \frac{\color{blue}{\frac{-1}{2} \cdot {B}^{2}}}{A}\right)}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                              6. unpow2N/A

                                                \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(2, C, \frac{\frac{-1}{2} \cdot \color{blue}{\left(B \cdot B\right)}}{A}\right)}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                              7. lower-*.f6425.3

                                                \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(2, C, \frac{-0.5 \cdot \color{blue}{\left(B \cdot B\right)}}{A}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                            5. Applied rewrites25.3%

                                              \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\mathsf{fma}\left(2, C, \frac{-0.5 \cdot \left(B \cdot B\right)}{A}\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                            6. Applied rewrites25.3%

                                              \[\leadsto \color{blue}{\frac{\sqrt{\left(\mathsf{fma}\left(B, B, \left(-4 \cdot C\right) \cdot A\right) \cdot \left(F \cdot 2\right)\right) \cdot \mathsf{fma}\left(2, C, \frac{\left(B \cdot B\right) \cdot -0.5}{A}\right)}}{-\mathsf{fma}\left(B, B, \left(-4 \cdot C\right) \cdot A\right)}} \]

                                            if +inf.0 < (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)))

                                            1. Initial program 0.0%

                                              \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                            2. Add Preprocessing
                                            3. Taylor expanded in B around inf

                                              \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                            4. Step-by-step derivation
                                              1. mul-1-negN/A

                                                \[\leadsto \color{blue}{\mathsf{neg}\left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                              2. lower-neg.f64N/A

                                                \[\leadsto \color{blue}{\mathsf{neg}\left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                              3. *-commutativeN/A

                                                \[\leadsto \mathsf{neg}\left(\color{blue}{\sqrt{2} \cdot \sqrt{\frac{F}{B}}}\right) \]
                                              4. lower-*.f64N/A

                                                \[\leadsto \mathsf{neg}\left(\color{blue}{\sqrt{2} \cdot \sqrt{\frac{F}{B}}}\right) \]
                                              5. lower-sqrt.f64N/A

                                                \[\leadsto \mathsf{neg}\left(\color{blue}{\sqrt{2}} \cdot \sqrt{\frac{F}{B}}\right) \]
                                              6. lower-sqrt.f64N/A

                                                \[\leadsto \mathsf{neg}\left(\sqrt{2} \cdot \color{blue}{\sqrt{\frac{F}{B}}}\right) \]
                                              7. lower-/.f6420.0

                                                \[\leadsto -\sqrt{2} \cdot \sqrt{\color{blue}{\frac{F}{B}}} \]
                                            5. Applied rewrites20.0%

                                              \[\leadsto \color{blue}{-\sqrt{2} \cdot \sqrt{\frac{F}{B}}} \]
                                            6. Step-by-step derivation
                                              1. Applied rewrites29.6%

                                                \[\leadsto -\frac{\sqrt{F \cdot 2}}{\sqrt{B}} \]
                                              2. Step-by-step derivation
                                                1. Applied rewrites29.6%

                                                  \[\leadsto -\sqrt{F} \cdot \sqrt{\frac{2}{B}} \]
                                              3. Recombined 4 regimes into one program.
                                              4. Final simplification34.6%

                                                \[\leadsto \begin{array}{l} \mathbf{if}\;\frac{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)}}{\left(4 \cdot A\right) \cdot C - {B}^{2}} \leq -\infty:\\ \;\;\;\;\sqrt{F \cdot \left(-0.5 \cdot \frac{B \cdot B}{A}\right)} \cdot \frac{\sqrt{2}}{-B}\\ \mathbf{elif}\;\frac{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)}}{\left(4 \cdot A\right) \cdot C - {B}^{2}} \leq -1 \cdot 10^{-220}:\\ \;\;\;\;\frac{\sqrt{\left(\mathsf{fma}\left(B, B, -4 \cdot \left(A \cdot C\right)\right) \cdot \left(2 \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{\mathsf{fma}\left(A - C, A - C, B \cdot B\right)}\right)}}{-\mathsf{fma}\left(B, B, -4 \cdot \left(A \cdot C\right)\right)}\\ \mathbf{elif}\;\frac{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)}}{\left(4 \cdot A\right) \cdot C - {B}^{2}} \leq \infty:\\ \;\;\;\;\frac{\sqrt{\mathsf{fma}\left(2, C, \frac{\left(B \cdot B\right) \cdot -0.5}{A}\right) \cdot \left(\mathsf{fma}\left(B, B, A \cdot \left(C \cdot -4\right)\right) \cdot \left(2 \cdot F\right)\right)}}{-\mathsf{fma}\left(B, B, A \cdot \left(C \cdot -4\right)\right)}\\ \mathbf{else}:\\ \;\;\;\;\left(-\sqrt{F}\right) \cdot \sqrt{\frac{2}{B}}\\ \end{array} \]
                                              5. Add Preprocessing

                                              Alternative 11: 41.1% accurate, 0.3× speedup?

                                              \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} t_0 := \frac{\sqrt{2}}{-B\_m}\\ t_1 := \left(4 \cdot A\right) \cdot C\\ t_2 := \frac{\sqrt{\left(2 \cdot \left(\left({B\_m}^{2} - t\_1\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{B\_m}^{2} + {\left(A - C\right)}^{2}}\right)}}{t\_1 - {B\_m}^{2}}\\ \mathbf{if}\;t\_2 \leq -\infty:\\ \;\;\;\;\sqrt{F \cdot \left(-0.5 \cdot \frac{B\_m \cdot B\_m}{A}\right)} \cdot t\_0\\ \mathbf{elif}\;t\_2 \leq -1 \cdot 10^{-220}:\\ \;\;\;\;\frac{-1}{\frac{B\_m}{\sqrt{2 \cdot \left(F \cdot \left(C + \sqrt{\mathsf{fma}\left(B\_m, B\_m, C \cdot C\right)}\right)\right)}}}\\ \mathbf{elif}\;t\_2 \leq \infty:\\ \;\;\;\;t\_0 \cdot \sqrt{\frac{-0.5 \cdot \left(F \cdot \left(B\_m \cdot B\_m\right)\right)}{A}}\\ \mathbf{else}:\\ \;\;\;\;\left(-\sqrt{F}\right) \cdot \sqrt{\frac{2}{B\_m}}\\ \end{array} \end{array} \]
                                              B_m = (fabs.f64 B)
                                              NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                              (FPCore (A B_m C F)
                                               :precision binary64
                                               (let* ((t_0 (/ (sqrt 2.0) (- B_m)))
                                                      (t_1 (* (* 4.0 A) C))
                                                      (t_2
                                                       (/
                                                        (sqrt
                                                         (*
                                                          (* 2.0 (* (- (pow B_m 2.0) t_1) F))
                                                          (+ (+ A C) (sqrt (+ (pow B_m 2.0) (pow (- A C) 2.0))))))
                                                        (- t_1 (pow B_m 2.0)))))
                                                 (if (<= t_2 (- INFINITY))
                                                   (* (sqrt (* F (* -0.5 (/ (* B_m B_m) A)))) t_0)
                                                   (if (<= t_2 -1e-220)
                                                     (/ -1.0 (/ B_m (sqrt (* 2.0 (* F (+ C (sqrt (fma B_m B_m (* C C)))))))))
                                                     (if (<= t_2 INFINITY)
                                                       (* t_0 (sqrt (/ (* -0.5 (* F (* B_m B_m))) A)))
                                                       (* (- (sqrt F)) (sqrt (/ 2.0 B_m))))))))
                                              B_m = fabs(B);
                                              assert(A < B_m && B_m < C && C < F);
                                              double code(double A, double B_m, double C, double F) {
                                              	double t_0 = sqrt(2.0) / -B_m;
                                              	double t_1 = (4.0 * A) * C;
                                              	double t_2 = sqrt(((2.0 * ((pow(B_m, 2.0) - t_1) * F)) * ((A + C) + sqrt((pow(B_m, 2.0) + pow((A - C), 2.0)))))) / (t_1 - pow(B_m, 2.0));
                                              	double tmp;
                                              	if (t_2 <= -((double) INFINITY)) {
                                              		tmp = sqrt((F * (-0.5 * ((B_m * B_m) / A)))) * t_0;
                                              	} else if (t_2 <= -1e-220) {
                                              		tmp = -1.0 / (B_m / sqrt((2.0 * (F * (C + sqrt(fma(B_m, B_m, (C * C))))))));
                                              	} else if (t_2 <= ((double) INFINITY)) {
                                              		tmp = t_0 * sqrt(((-0.5 * (F * (B_m * B_m))) / A));
                                              	} else {
                                              		tmp = -sqrt(F) * sqrt((2.0 / B_m));
                                              	}
                                              	return tmp;
                                              }
                                              
                                              B_m = abs(B)
                                              A, B_m, C, F = sort([A, B_m, C, F])
                                              function code(A, B_m, C, F)
                                              	t_0 = Float64(sqrt(2.0) / Float64(-B_m))
                                              	t_1 = Float64(Float64(4.0 * A) * C)
                                              	t_2 = Float64(sqrt(Float64(Float64(2.0 * Float64(Float64((B_m ^ 2.0) - t_1) * F)) * Float64(Float64(A + C) + sqrt(Float64((B_m ^ 2.0) + (Float64(A - C) ^ 2.0)))))) / Float64(t_1 - (B_m ^ 2.0)))
                                              	tmp = 0.0
                                              	if (t_2 <= Float64(-Inf))
                                              		tmp = Float64(sqrt(Float64(F * Float64(-0.5 * Float64(Float64(B_m * B_m) / A)))) * t_0);
                                              	elseif (t_2 <= -1e-220)
                                              		tmp = Float64(-1.0 / Float64(B_m / sqrt(Float64(2.0 * Float64(F * Float64(C + sqrt(fma(B_m, B_m, Float64(C * C)))))))));
                                              	elseif (t_2 <= Inf)
                                              		tmp = Float64(t_0 * sqrt(Float64(Float64(-0.5 * Float64(F * Float64(B_m * B_m))) / A)));
                                              	else
                                              		tmp = Float64(Float64(-sqrt(F)) * sqrt(Float64(2.0 / B_m)));
                                              	end
                                              	return tmp
                                              end
                                              
                                              B_m = N[Abs[B], $MachinePrecision]
                                              NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                              code[A_, B$95$m_, C_, F_] := Block[{t$95$0 = N[(N[Sqrt[2.0], $MachinePrecision] / (-B$95$m)), $MachinePrecision]}, Block[{t$95$1 = N[(N[(4.0 * A), $MachinePrecision] * C), $MachinePrecision]}, Block[{t$95$2 = N[(N[Sqrt[N[(N[(2.0 * N[(N[(N[Power[B$95$m, 2.0], $MachinePrecision] - t$95$1), $MachinePrecision] * F), $MachinePrecision]), $MachinePrecision] * N[(N[(A + C), $MachinePrecision] + N[Sqrt[N[(N[Power[B$95$m, 2.0], $MachinePrecision] + N[Power[N[(A - C), $MachinePrecision], 2.0], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / N[(t$95$1 - N[Power[B$95$m, 2.0], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[t$95$2, (-Infinity)], N[(N[Sqrt[N[(F * N[(-0.5 * N[(N[(B$95$m * B$95$m), $MachinePrecision] / A), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] * t$95$0), $MachinePrecision], If[LessEqual[t$95$2, -1e-220], N[(-1.0 / N[(B$95$m / N[Sqrt[N[(2.0 * N[(F * N[(C + N[Sqrt[N[(B$95$m * B$95$m + N[(C * C), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision], If[LessEqual[t$95$2, Infinity], N[(t$95$0 * N[Sqrt[N[(N[(-0.5 * N[(F * N[(B$95$m * B$95$m), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] / A), $MachinePrecision]], $MachinePrecision]), $MachinePrecision], N[((-N[Sqrt[F], $MachinePrecision]) * N[Sqrt[N[(2.0 / B$95$m), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]]]]]]]
                                              
                                              \begin{array}{l}
                                              B_m = \left|B\right|
                                              \\
                                              [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
                                              \\
                                              \begin{array}{l}
                                              t_0 := \frac{\sqrt{2}}{-B\_m}\\
                                              t_1 := \left(4 \cdot A\right) \cdot C\\
                                              t_2 := \frac{\sqrt{\left(2 \cdot \left(\left({B\_m}^{2} - t\_1\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{B\_m}^{2} + {\left(A - C\right)}^{2}}\right)}}{t\_1 - {B\_m}^{2}}\\
                                              \mathbf{if}\;t\_2 \leq -\infty:\\
                                              \;\;\;\;\sqrt{F \cdot \left(-0.5 \cdot \frac{B\_m \cdot B\_m}{A}\right)} \cdot t\_0\\
                                              
                                              \mathbf{elif}\;t\_2 \leq -1 \cdot 10^{-220}:\\
                                              \;\;\;\;\frac{-1}{\frac{B\_m}{\sqrt{2 \cdot \left(F \cdot \left(C + \sqrt{\mathsf{fma}\left(B\_m, B\_m, C \cdot C\right)}\right)\right)}}}\\
                                              
                                              \mathbf{elif}\;t\_2 \leq \infty:\\
                                              \;\;\;\;t\_0 \cdot \sqrt{\frac{-0.5 \cdot \left(F \cdot \left(B\_m \cdot B\_m\right)\right)}{A}}\\
                                              
                                              \mathbf{else}:\\
                                              \;\;\;\;\left(-\sqrt{F}\right) \cdot \sqrt{\frac{2}{B\_m}}\\
                                              
                                              
                                              \end{array}
                                              \end{array}
                                              
                                              Derivation
                                              1. Split input into 4 regimes
                                              2. if (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C))) < -inf.0

                                                1. Initial program 3.6%

                                                  \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                2. Add Preprocessing
                                                3. Taylor expanded in C around 0

                                                  \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A + \sqrt{{A}^{2} + {B}^{2}}\right)}\right)} \]
                                                4. Step-by-step derivation
                                                  1. mul-1-negN/A

                                                    \[\leadsto \color{blue}{\mathsf{neg}\left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A + \sqrt{{A}^{2} + {B}^{2}}\right)}\right)} \]
                                                  2. *-commutativeN/A

                                                    \[\leadsto \mathsf{neg}\left(\color{blue}{\sqrt{F \cdot \left(A + \sqrt{{A}^{2} + {B}^{2}}\right)} \cdot \frac{\sqrt{2}}{B}}\right) \]
                                                  3. distribute-rgt-neg-inN/A

                                                    \[\leadsto \color{blue}{\sqrt{F \cdot \left(A + \sqrt{{A}^{2} + {B}^{2}}\right)} \cdot \left(\mathsf{neg}\left(\frac{\sqrt{2}}{B}\right)\right)} \]
                                                  4. mul-1-negN/A

                                                    \[\leadsto \sqrt{F \cdot \left(A + \sqrt{{A}^{2} + {B}^{2}}\right)} \cdot \color{blue}{\left(-1 \cdot \frac{\sqrt{2}}{B}\right)} \]
                                                  5. lower-*.f64N/A

                                                    \[\leadsto \color{blue}{\sqrt{F \cdot \left(A + \sqrt{{A}^{2} + {B}^{2}}\right)} \cdot \left(-1 \cdot \frac{\sqrt{2}}{B}\right)} \]
                                                5. Applied rewrites5.4%

                                                  \[\leadsto \color{blue}{\sqrt{F \cdot \left(A + \sqrt{\mathsf{fma}\left(B, B, A \cdot A\right)}\right)} \cdot \left(-\frac{\sqrt{2}}{B}\right)} \]
                                                6. Taylor expanded in A around -inf

                                                  \[\leadsto \sqrt{F \cdot \left(\frac{-1}{2} \cdot \frac{{B}^{2}}{A}\right)} \cdot \left(\mathsf{neg}\left(\frac{\sqrt{2}}{B}\right)\right) \]
                                                7. Step-by-step derivation
                                                  1. Applied rewrites8.4%

                                                    \[\leadsto \sqrt{F \cdot \left(-0.5 \cdot \frac{B \cdot B}{A}\right)} \cdot \left(-\frac{\sqrt{2}}{B}\right) \]

                                                  if -inf.0 < (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C))) < -9.99999999999999992e-221

                                                  1. Initial program 98.5%

                                                    \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                  2. Add Preprocessing
                                                  3. Taylor expanded in A around -inf

                                                    \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\left(\frac{-1}{2} \cdot \frac{{B}^{2}}{A} + 2 \cdot C\right)}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                  4. Step-by-step derivation
                                                    1. +-commutativeN/A

                                                      \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\left(2 \cdot C + \frac{-1}{2} \cdot \frac{{B}^{2}}{A}\right)}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                    2. lower-fma.f64N/A

                                                      \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\mathsf{fma}\left(2, C, \frac{-1}{2} \cdot \frac{{B}^{2}}{A}\right)}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                    3. associate-*r/N/A

                                                      \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(2, C, \color{blue}{\frac{\frac{-1}{2} \cdot {B}^{2}}{A}}\right)}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                    4. lower-/.f64N/A

                                                      \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(2, C, \color{blue}{\frac{\frac{-1}{2} \cdot {B}^{2}}{A}}\right)}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                    5. lower-*.f64N/A

                                                      \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(2, C, \frac{\color{blue}{\frac{-1}{2} \cdot {B}^{2}}}{A}\right)}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                    6. unpow2N/A

                                                      \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(2, C, \frac{\frac{-1}{2} \cdot \color{blue}{\left(B \cdot B\right)}}{A}\right)}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                    7. lower-*.f6420.9

                                                      \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(2, C, \frac{-0.5 \cdot \color{blue}{\left(B \cdot B\right)}}{A}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                  5. Applied rewrites20.9%

                                                    \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\mathsf{fma}\left(2, C, \frac{-0.5 \cdot \left(B \cdot B\right)}{A}\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                  6. Applied rewrites20.8%

                                                    \[\leadsto \frac{-\color{blue}{\sqrt{\mathsf{fma}\left(2, C, \frac{\left(B \cdot B\right) \cdot -0.5}{A}\right) \cdot 2} \cdot \sqrt{F \cdot \mathsf{fma}\left(B, B, \left(-4 \cdot C\right) \cdot A\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                  7. Taylor expanded in A around 0

                                                    \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right)} \]
                                                  8. Step-by-step derivation
                                                    1. mul-1-negN/A

                                                      \[\leadsto \color{blue}{\mathsf{neg}\left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right)} \]
                                                    2. lower-neg.f64N/A

                                                      \[\leadsto \color{blue}{\mathsf{neg}\left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right)} \]
                                                    3. lower-*.f64N/A

                                                      \[\leadsto \mathsf{neg}\left(\color{blue}{\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}}\right) \]
                                                    4. lower-/.f64N/A

                                                      \[\leadsto \mathsf{neg}\left(\color{blue}{\frac{\sqrt{2}}{B}} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right) \]
                                                    5. lower-sqrt.f64N/A

                                                      \[\leadsto \mathsf{neg}\left(\frac{\color{blue}{\sqrt{2}}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right) \]
                                                    6. lower-sqrt.f64N/A

                                                      \[\leadsto \mathsf{neg}\left(\frac{\sqrt{2}}{B} \cdot \color{blue}{\sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}}\right) \]
                                                    7. lower-*.f64N/A

                                                      \[\leadsto \mathsf{neg}\left(\frac{\sqrt{2}}{B} \cdot \sqrt{\color{blue}{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}}\right) \]
                                                    8. lower-+.f64N/A

                                                      \[\leadsto \mathsf{neg}\left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}}\right) \]
                                                    9. lower-sqrt.f64N/A

                                                      \[\leadsto \mathsf{neg}\left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \color{blue}{\sqrt{{B}^{2} + {C}^{2}}}\right)}\right) \]
                                                    10. unpow2N/A

                                                      \[\leadsto \mathsf{neg}\left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{\color{blue}{B \cdot B} + {C}^{2}}\right)}\right) \]
                                                    11. lower-fma.f64N/A

                                                      \[\leadsto \mathsf{neg}\left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{\color{blue}{\mathsf{fma}\left(B, B, {C}^{2}\right)}}\right)}\right) \]
                                                    12. unpow2N/A

                                                      \[\leadsto \mathsf{neg}\left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{\mathsf{fma}\left(B, B, \color{blue}{C \cdot C}\right)}\right)}\right) \]
                                                    13. lower-*.f6445.6

                                                      \[\leadsto -\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{\mathsf{fma}\left(B, B, \color{blue}{C \cdot C}\right)}\right)} \]
                                                  9. Applied rewrites45.6%

                                                    \[\leadsto \color{blue}{-\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{\mathsf{fma}\left(B, B, C \cdot C\right)}\right)}} \]
                                                  10. Step-by-step derivation
                                                    1. Applied rewrites45.8%

                                                      \[\leadsto -\frac{1}{\frac{B}{\sqrt{2 \cdot \left(F \cdot \left(C + \sqrt{\mathsf{fma}\left(B, B, C \cdot C\right)}\right)\right)}}} \]

                                                    if -9.99999999999999992e-221 < (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C))) < +inf.0

                                                    1. Initial program 18.5%

                                                      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                    2. Add Preprocessing
                                                    3. Taylor expanded in C around 0

                                                      \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A + \sqrt{{A}^{2} + {B}^{2}}\right)}\right)} \]
                                                    4. Step-by-step derivation
                                                      1. mul-1-negN/A

                                                        \[\leadsto \color{blue}{\mathsf{neg}\left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A + \sqrt{{A}^{2} + {B}^{2}}\right)}\right)} \]
                                                      2. *-commutativeN/A

                                                        \[\leadsto \mathsf{neg}\left(\color{blue}{\sqrt{F \cdot \left(A + \sqrt{{A}^{2} + {B}^{2}}\right)} \cdot \frac{\sqrt{2}}{B}}\right) \]
                                                      3. distribute-rgt-neg-inN/A

                                                        \[\leadsto \color{blue}{\sqrt{F \cdot \left(A + \sqrt{{A}^{2} + {B}^{2}}\right)} \cdot \left(\mathsf{neg}\left(\frac{\sqrt{2}}{B}\right)\right)} \]
                                                      4. mul-1-negN/A

                                                        \[\leadsto \sqrt{F \cdot \left(A + \sqrt{{A}^{2} + {B}^{2}}\right)} \cdot \color{blue}{\left(-1 \cdot \frac{\sqrt{2}}{B}\right)} \]
                                                      5. lower-*.f64N/A

                                                        \[\leadsto \color{blue}{\sqrt{F \cdot \left(A + \sqrt{{A}^{2} + {B}^{2}}\right)} \cdot \left(-1 \cdot \frac{\sqrt{2}}{B}\right)} \]
                                                    5. Applied rewrites4.6%

                                                      \[\leadsto \color{blue}{\sqrt{F \cdot \left(A + \sqrt{\mathsf{fma}\left(B, B, A \cdot A\right)}\right)} \cdot \left(-\frac{\sqrt{2}}{B}\right)} \]
                                                    6. Taylor expanded in A around -inf

                                                      \[\leadsto \sqrt{\frac{-1}{2} \cdot \frac{{B}^{2} \cdot F}{A}} \cdot \left(\mathsf{neg}\left(\frac{\color{blue}{\sqrt{2}}}{B}\right)\right) \]
                                                    7. Step-by-step derivation
                                                      1. Applied rewrites6.6%

                                                        \[\leadsto \sqrt{\frac{-0.5 \cdot \left(\left(B \cdot B\right) \cdot F\right)}{A}} \cdot \left(-\frac{\color{blue}{\sqrt{2}}}{B}\right) \]

                                                      if +inf.0 < (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)))

                                                      1. Initial program 0.0%

                                                        \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                      2. Add Preprocessing
                                                      3. Taylor expanded in B around inf

                                                        \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                                      4. Step-by-step derivation
                                                        1. mul-1-negN/A

                                                          \[\leadsto \color{blue}{\mathsf{neg}\left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                                        2. lower-neg.f64N/A

                                                          \[\leadsto \color{blue}{\mathsf{neg}\left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                                        3. *-commutativeN/A

                                                          \[\leadsto \mathsf{neg}\left(\color{blue}{\sqrt{2} \cdot \sqrt{\frac{F}{B}}}\right) \]
                                                        4. lower-*.f64N/A

                                                          \[\leadsto \mathsf{neg}\left(\color{blue}{\sqrt{2} \cdot \sqrt{\frac{F}{B}}}\right) \]
                                                        5. lower-sqrt.f64N/A

                                                          \[\leadsto \mathsf{neg}\left(\color{blue}{\sqrt{2}} \cdot \sqrt{\frac{F}{B}}\right) \]
                                                        6. lower-sqrt.f64N/A

                                                          \[\leadsto \mathsf{neg}\left(\sqrt{2} \cdot \color{blue}{\sqrt{\frac{F}{B}}}\right) \]
                                                        7. lower-/.f6420.0

                                                          \[\leadsto -\sqrt{2} \cdot \sqrt{\color{blue}{\frac{F}{B}}} \]
                                                      5. Applied rewrites20.0%

                                                        \[\leadsto \color{blue}{-\sqrt{2} \cdot \sqrt{\frac{F}{B}}} \]
                                                      6. Step-by-step derivation
                                                        1. Applied rewrites29.6%

                                                          \[\leadsto -\frac{\sqrt{F \cdot 2}}{\sqrt{B}} \]
                                                        2. Step-by-step derivation
                                                          1. Applied rewrites29.6%

                                                            \[\leadsto -\sqrt{F} \cdot \sqrt{\frac{2}{B}} \]
                                                        3. Recombined 4 regimes into one program.
                                                        4. Final simplification23.9%

                                                          \[\leadsto \begin{array}{l} \mathbf{if}\;\frac{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)}}{\left(4 \cdot A\right) \cdot C - {B}^{2}} \leq -\infty:\\ \;\;\;\;\sqrt{F \cdot \left(-0.5 \cdot \frac{B \cdot B}{A}\right)} \cdot \frac{\sqrt{2}}{-B}\\ \mathbf{elif}\;\frac{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)}}{\left(4 \cdot A\right) \cdot C - {B}^{2}} \leq -1 \cdot 10^{-220}:\\ \;\;\;\;\frac{-1}{\frac{B}{\sqrt{2 \cdot \left(F \cdot \left(C + \sqrt{\mathsf{fma}\left(B, B, C \cdot C\right)}\right)\right)}}}\\ \mathbf{elif}\;\frac{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)}}{\left(4 \cdot A\right) \cdot C - {B}^{2}} \leq \infty:\\ \;\;\;\;\frac{\sqrt{2}}{-B} \cdot \sqrt{\frac{-0.5 \cdot \left(F \cdot \left(B \cdot B\right)\right)}{A}}\\ \mathbf{else}:\\ \;\;\;\;\left(-\sqrt{F}\right) \cdot \sqrt{\frac{2}{B}}\\ \end{array} \]
                                                        5. Add Preprocessing

                                                        Alternative 12: 41.1% accurate, 0.3× speedup?

                                                        \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} t_0 := \frac{\sqrt{2}}{-B\_m}\\ t_1 := \left(4 \cdot A\right) \cdot C\\ t_2 := \frac{\sqrt{\left(2 \cdot \left(\left({B\_m}^{2} - t\_1\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{B\_m}^{2} + {\left(A - C\right)}^{2}}\right)}}{t\_1 - {B\_m}^{2}}\\ \mathbf{if}\;t\_2 \leq -\infty:\\ \;\;\;\;\sqrt{F \cdot \left(-0.5 \cdot \frac{B\_m \cdot B\_m}{A}\right)} \cdot t\_0\\ \mathbf{elif}\;t\_2 \leq -1 \cdot 10^{-220}:\\ \;\;\;\;\frac{\sqrt{2 \cdot \left(F \cdot \left(C + \sqrt{\mathsf{fma}\left(B\_m, B\_m, C \cdot C\right)}\right)\right)}}{-B\_m}\\ \mathbf{elif}\;t\_2 \leq \infty:\\ \;\;\;\;t\_0 \cdot \sqrt{\frac{-0.5 \cdot \left(F \cdot \left(B\_m \cdot B\_m\right)\right)}{A}}\\ \mathbf{else}:\\ \;\;\;\;\left(-\sqrt{F}\right) \cdot \sqrt{\frac{2}{B\_m}}\\ \end{array} \end{array} \]
                                                        B_m = (fabs.f64 B)
                                                        NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                        (FPCore (A B_m C F)
                                                         :precision binary64
                                                         (let* ((t_0 (/ (sqrt 2.0) (- B_m)))
                                                                (t_1 (* (* 4.0 A) C))
                                                                (t_2
                                                                 (/
                                                                  (sqrt
                                                                   (*
                                                                    (* 2.0 (* (- (pow B_m 2.0) t_1) F))
                                                                    (+ (+ A C) (sqrt (+ (pow B_m 2.0) (pow (- A C) 2.0))))))
                                                                  (- t_1 (pow B_m 2.0)))))
                                                           (if (<= t_2 (- INFINITY))
                                                             (* (sqrt (* F (* -0.5 (/ (* B_m B_m) A)))) t_0)
                                                             (if (<= t_2 -1e-220)
                                                               (/ (sqrt (* 2.0 (* F (+ C (sqrt (fma B_m B_m (* C C))))))) (- B_m))
                                                               (if (<= t_2 INFINITY)
                                                                 (* t_0 (sqrt (/ (* -0.5 (* F (* B_m B_m))) A)))
                                                                 (* (- (sqrt F)) (sqrt (/ 2.0 B_m))))))))
                                                        B_m = fabs(B);
                                                        assert(A < B_m && B_m < C && C < F);
                                                        double code(double A, double B_m, double C, double F) {
                                                        	double t_0 = sqrt(2.0) / -B_m;
                                                        	double t_1 = (4.0 * A) * C;
                                                        	double t_2 = sqrt(((2.0 * ((pow(B_m, 2.0) - t_1) * F)) * ((A + C) + sqrt((pow(B_m, 2.0) + pow((A - C), 2.0)))))) / (t_1 - pow(B_m, 2.0));
                                                        	double tmp;
                                                        	if (t_2 <= -((double) INFINITY)) {
                                                        		tmp = sqrt((F * (-0.5 * ((B_m * B_m) / A)))) * t_0;
                                                        	} else if (t_2 <= -1e-220) {
                                                        		tmp = sqrt((2.0 * (F * (C + sqrt(fma(B_m, B_m, (C * C))))))) / -B_m;
                                                        	} else if (t_2 <= ((double) INFINITY)) {
                                                        		tmp = t_0 * sqrt(((-0.5 * (F * (B_m * B_m))) / A));
                                                        	} else {
                                                        		tmp = -sqrt(F) * sqrt((2.0 / B_m));
                                                        	}
                                                        	return tmp;
                                                        }
                                                        
                                                        B_m = abs(B)
                                                        A, B_m, C, F = sort([A, B_m, C, F])
                                                        function code(A, B_m, C, F)
                                                        	t_0 = Float64(sqrt(2.0) / Float64(-B_m))
                                                        	t_1 = Float64(Float64(4.0 * A) * C)
                                                        	t_2 = Float64(sqrt(Float64(Float64(2.0 * Float64(Float64((B_m ^ 2.0) - t_1) * F)) * Float64(Float64(A + C) + sqrt(Float64((B_m ^ 2.0) + (Float64(A - C) ^ 2.0)))))) / Float64(t_1 - (B_m ^ 2.0)))
                                                        	tmp = 0.0
                                                        	if (t_2 <= Float64(-Inf))
                                                        		tmp = Float64(sqrt(Float64(F * Float64(-0.5 * Float64(Float64(B_m * B_m) / A)))) * t_0);
                                                        	elseif (t_2 <= -1e-220)
                                                        		tmp = Float64(sqrt(Float64(2.0 * Float64(F * Float64(C + sqrt(fma(B_m, B_m, Float64(C * C))))))) / Float64(-B_m));
                                                        	elseif (t_2 <= Inf)
                                                        		tmp = Float64(t_0 * sqrt(Float64(Float64(-0.5 * Float64(F * Float64(B_m * B_m))) / A)));
                                                        	else
                                                        		tmp = Float64(Float64(-sqrt(F)) * sqrt(Float64(2.0 / B_m)));
                                                        	end
                                                        	return tmp
                                                        end
                                                        
                                                        B_m = N[Abs[B], $MachinePrecision]
                                                        NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                        code[A_, B$95$m_, C_, F_] := Block[{t$95$0 = N[(N[Sqrt[2.0], $MachinePrecision] / (-B$95$m)), $MachinePrecision]}, Block[{t$95$1 = N[(N[(4.0 * A), $MachinePrecision] * C), $MachinePrecision]}, Block[{t$95$2 = N[(N[Sqrt[N[(N[(2.0 * N[(N[(N[Power[B$95$m, 2.0], $MachinePrecision] - t$95$1), $MachinePrecision] * F), $MachinePrecision]), $MachinePrecision] * N[(N[(A + C), $MachinePrecision] + N[Sqrt[N[(N[Power[B$95$m, 2.0], $MachinePrecision] + N[Power[N[(A - C), $MachinePrecision], 2.0], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / N[(t$95$1 - N[Power[B$95$m, 2.0], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[t$95$2, (-Infinity)], N[(N[Sqrt[N[(F * N[(-0.5 * N[(N[(B$95$m * B$95$m), $MachinePrecision] / A), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] * t$95$0), $MachinePrecision], If[LessEqual[t$95$2, -1e-220], N[(N[Sqrt[N[(2.0 * N[(F * N[(C + N[Sqrt[N[(B$95$m * B$95$m + N[(C * C), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / (-B$95$m)), $MachinePrecision], If[LessEqual[t$95$2, Infinity], N[(t$95$0 * N[Sqrt[N[(N[(-0.5 * N[(F * N[(B$95$m * B$95$m), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] / A), $MachinePrecision]], $MachinePrecision]), $MachinePrecision], N[((-N[Sqrt[F], $MachinePrecision]) * N[Sqrt[N[(2.0 / B$95$m), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]]]]]]]
                                                        
                                                        \begin{array}{l}
                                                        B_m = \left|B\right|
                                                        \\
                                                        [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
                                                        \\
                                                        \begin{array}{l}
                                                        t_0 := \frac{\sqrt{2}}{-B\_m}\\
                                                        t_1 := \left(4 \cdot A\right) \cdot C\\
                                                        t_2 := \frac{\sqrt{\left(2 \cdot \left(\left({B\_m}^{2} - t\_1\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{B\_m}^{2} + {\left(A - C\right)}^{2}}\right)}}{t\_1 - {B\_m}^{2}}\\
                                                        \mathbf{if}\;t\_2 \leq -\infty:\\
                                                        \;\;\;\;\sqrt{F \cdot \left(-0.5 \cdot \frac{B\_m \cdot B\_m}{A}\right)} \cdot t\_0\\
                                                        
                                                        \mathbf{elif}\;t\_2 \leq -1 \cdot 10^{-220}:\\
                                                        \;\;\;\;\frac{\sqrt{2 \cdot \left(F \cdot \left(C + \sqrt{\mathsf{fma}\left(B\_m, B\_m, C \cdot C\right)}\right)\right)}}{-B\_m}\\
                                                        
                                                        \mathbf{elif}\;t\_2 \leq \infty:\\
                                                        \;\;\;\;t\_0 \cdot \sqrt{\frac{-0.5 \cdot \left(F \cdot \left(B\_m \cdot B\_m\right)\right)}{A}}\\
                                                        
                                                        \mathbf{else}:\\
                                                        \;\;\;\;\left(-\sqrt{F}\right) \cdot \sqrt{\frac{2}{B\_m}}\\
                                                        
                                                        
                                                        \end{array}
                                                        \end{array}
                                                        
                                                        Derivation
                                                        1. Split input into 4 regimes
                                                        2. if (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C))) < -inf.0

                                                          1. Initial program 3.6%

                                                            \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                          2. Add Preprocessing
                                                          3. Taylor expanded in C around 0

                                                            \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A + \sqrt{{A}^{2} + {B}^{2}}\right)}\right)} \]
                                                          4. Step-by-step derivation
                                                            1. mul-1-negN/A

                                                              \[\leadsto \color{blue}{\mathsf{neg}\left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A + \sqrt{{A}^{2} + {B}^{2}}\right)}\right)} \]
                                                            2. *-commutativeN/A

                                                              \[\leadsto \mathsf{neg}\left(\color{blue}{\sqrt{F \cdot \left(A + \sqrt{{A}^{2} + {B}^{2}}\right)} \cdot \frac{\sqrt{2}}{B}}\right) \]
                                                            3. distribute-rgt-neg-inN/A

                                                              \[\leadsto \color{blue}{\sqrt{F \cdot \left(A + \sqrt{{A}^{2} + {B}^{2}}\right)} \cdot \left(\mathsf{neg}\left(\frac{\sqrt{2}}{B}\right)\right)} \]
                                                            4. mul-1-negN/A

                                                              \[\leadsto \sqrt{F \cdot \left(A + \sqrt{{A}^{2} + {B}^{2}}\right)} \cdot \color{blue}{\left(-1 \cdot \frac{\sqrt{2}}{B}\right)} \]
                                                            5. lower-*.f64N/A

                                                              \[\leadsto \color{blue}{\sqrt{F \cdot \left(A + \sqrt{{A}^{2} + {B}^{2}}\right)} \cdot \left(-1 \cdot \frac{\sqrt{2}}{B}\right)} \]
                                                          5. Applied rewrites5.4%

                                                            \[\leadsto \color{blue}{\sqrt{F \cdot \left(A + \sqrt{\mathsf{fma}\left(B, B, A \cdot A\right)}\right)} \cdot \left(-\frac{\sqrt{2}}{B}\right)} \]
                                                          6. Taylor expanded in A around -inf

                                                            \[\leadsto \sqrt{F \cdot \left(\frac{-1}{2} \cdot \frac{{B}^{2}}{A}\right)} \cdot \left(\mathsf{neg}\left(\frac{\sqrt{2}}{B}\right)\right) \]
                                                          7. Step-by-step derivation
                                                            1. Applied rewrites8.4%

                                                              \[\leadsto \sqrt{F \cdot \left(-0.5 \cdot \frac{B \cdot B}{A}\right)} \cdot \left(-\frac{\sqrt{2}}{B}\right) \]

                                                            if -inf.0 < (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C))) < -9.99999999999999992e-221

                                                            1. Initial program 98.5%

                                                              \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                            2. Add Preprocessing
                                                            3. Taylor expanded in A around -inf

                                                              \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\left(\frac{-1}{2} \cdot \frac{{B}^{2}}{A} + 2 \cdot C\right)}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                            4. Step-by-step derivation
                                                              1. +-commutativeN/A

                                                                \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\left(2 \cdot C + \frac{-1}{2} \cdot \frac{{B}^{2}}{A}\right)}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                              2. lower-fma.f64N/A

                                                                \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\mathsf{fma}\left(2, C, \frac{-1}{2} \cdot \frac{{B}^{2}}{A}\right)}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                              3. associate-*r/N/A

                                                                \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(2, C, \color{blue}{\frac{\frac{-1}{2} \cdot {B}^{2}}{A}}\right)}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                              4. lower-/.f64N/A

                                                                \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(2, C, \color{blue}{\frac{\frac{-1}{2} \cdot {B}^{2}}{A}}\right)}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                              5. lower-*.f64N/A

                                                                \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(2, C, \frac{\color{blue}{\frac{-1}{2} \cdot {B}^{2}}}{A}\right)}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                              6. unpow2N/A

                                                                \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(2, C, \frac{\frac{-1}{2} \cdot \color{blue}{\left(B \cdot B\right)}}{A}\right)}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                              7. lower-*.f6420.9

                                                                \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(2, C, \frac{-0.5 \cdot \color{blue}{\left(B \cdot B\right)}}{A}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                            5. Applied rewrites20.9%

                                                              \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\mathsf{fma}\left(2, C, \frac{-0.5 \cdot \left(B \cdot B\right)}{A}\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                            6. Applied rewrites20.8%

                                                              \[\leadsto \frac{-\color{blue}{\sqrt{\mathsf{fma}\left(2, C, \frac{\left(B \cdot B\right) \cdot -0.5}{A}\right) \cdot 2} \cdot \sqrt{F \cdot \mathsf{fma}\left(B, B, \left(-4 \cdot C\right) \cdot A\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                            7. Taylor expanded in A around 0

                                                              \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right)} \]
                                                            8. Step-by-step derivation
                                                              1. mul-1-negN/A

                                                                \[\leadsto \color{blue}{\mathsf{neg}\left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right)} \]
                                                              2. lower-neg.f64N/A

                                                                \[\leadsto \color{blue}{\mathsf{neg}\left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right)} \]
                                                              3. lower-*.f64N/A

                                                                \[\leadsto \mathsf{neg}\left(\color{blue}{\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}}\right) \]
                                                              4. lower-/.f64N/A

                                                                \[\leadsto \mathsf{neg}\left(\color{blue}{\frac{\sqrt{2}}{B}} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right) \]
                                                              5. lower-sqrt.f64N/A

                                                                \[\leadsto \mathsf{neg}\left(\frac{\color{blue}{\sqrt{2}}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right) \]
                                                              6. lower-sqrt.f64N/A

                                                                \[\leadsto \mathsf{neg}\left(\frac{\sqrt{2}}{B} \cdot \color{blue}{\sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}}\right) \]
                                                              7. lower-*.f64N/A

                                                                \[\leadsto \mathsf{neg}\left(\frac{\sqrt{2}}{B} \cdot \sqrt{\color{blue}{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}}\right) \]
                                                              8. lower-+.f64N/A

                                                                \[\leadsto \mathsf{neg}\left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}}\right) \]
                                                              9. lower-sqrt.f64N/A

                                                                \[\leadsto \mathsf{neg}\left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \color{blue}{\sqrt{{B}^{2} + {C}^{2}}}\right)}\right) \]
                                                              10. unpow2N/A

                                                                \[\leadsto \mathsf{neg}\left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{\color{blue}{B \cdot B} + {C}^{2}}\right)}\right) \]
                                                              11. lower-fma.f64N/A

                                                                \[\leadsto \mathsf{neg}\left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{\color{blue}{\mathsf{fma}\left(B, B, {C}^{2}\right)}}\right)}\right) \]
                                                              12. unpow2N/A

                                                                \[\leadsto \mathsf{neg}\left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{\mathsf{fma}\left(B, B, \color{blue}{C \cdot C}\right)}\right)}\right) \]
                                                              13. lower-*.f6445.6

                                                                \[\leadsto -\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{\mathsf{fma}\left(B, B, \color{blue}{C \cdot C}\right)}\right)} \]
                                                            9. Applied rewrites45.6%

                                                              \[\leadsto \color{blue}{-\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{\mathsf{fma}\left(B, B, C \cdot C\right)}\right)}} \]
                                                            10. Step-by-step derivation
                                                              1. Applied rewrites45.9%

                                                                \[\leadsto \frac{\sqrt{2 \cdot \left(F \cdot \left(C + \sqrt{\mathsf{fma}\left(B, B, C \cdot C\right)}\right)\right)}}{\color{blue}{-B}} \]

                                                              if -9.99999999999999992e-221 < (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C))) < +inf.0

                                                              1. Initial program 18.5%

                                                                \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                              2. Add Preprocessing
                                                              3. Taylor expanded in C around 0

                                                                \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A + \sqrt{{A}^{2} + {B}^{2}}\right)}\right)} \]
                                                              4. Step-by-step derivation
                                                                1. mul-1-negN/A

                                                                  \[\leadsto \color{blue}{\mathsf{neg}\left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A + \sqrt{{A}^{2} + {B}^{2}}\right)}\right)} \]
                                                                2. *-commutativeN/A

                                                                  \[\leadsto \mathsf{neg}\left(\color{blue}{\sqrt{F \cdot \left(A + \sqrt{{A}^{2} + {B}^{2}}\right)} \cdot \frac{\sqrt{2}}{B}}\right) \]
                                                                3. distribute-rgt-neg-inN/A

                                                                  \[\leadsto \color{blue}{\sqrt{F \cdot \left(A + \sqrt{{A}^{2} + {B}^{2}}\right)} \cdot \left(\mathsf{neg}\left(\frac{\sqrt{2}}{B}\right)\right)} \]
                                                                4. mul-1-negN/A

                                                                  \[\leadsto \sqrt{F \cdot \left(A + \sqrt{{A}^{2} + {B}^{2}}\right)} \cdot \color{blue}{\left(-1 \cdot \frac{\sqrt{2}}{B}\right)} \]
                                                                5. lower-*.f64N/A

                                                                  \[\leadsto \color{blue}{\sqrt{F \cdot \left(A + \sqrt{{A}^{2} + {B}^{2}}\right)} \cdot \left(-1 \cdot \frac{\sqrt{2}}{B}\right)} \]
                                                              5. Applied rewrites4.6%

                                                                \[\leadsto \color{blue}{\sqrt{F \cdot \left(A + \sqrt{\mathsf{fma}\left(B, B, A \cdot A\right)}\right)} \cdot \left(-\frac{\sqrt{2}}{B}\right)} \]
                                                              6. Taylor expanded in A around -inf

                                                                \[\leadsto \sqrt{\frac{-1}{2} \cdot \frac{{B}^{2} \cdot F}{A}} \cdot \left(\mathsf{neg}\left(\frac{\color{blue}{\sqrt{2}}}{B}\right)\right) \]
                                                              7. Step-by-step derivation
                                                                1. Applied rewrites6.6%

                                                                  \[\leadsto \sqrt{\frac{-0.5 \cdot \left(\left(B \cdot B\right) \cdot F\right)}{A}} \cdot \left(-\frac{\color{blue}{\sqrt{2}}}{B}\right) \]

                                                                if +inf.0 < (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)))

                                                                1. Initial program 0.0%

                                                                  \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                2. Add Preprocessing
                                                                3. Taylor expanded in B around inf

                                                                  \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                                                4. Step-by-step derivation
                                                                  1. mul-1-negN/A

                                                                    \[\leadsto \color{blue}{\mathsf{neg}\left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                                                  2. lower-neg.f64N/A

                                                                    \[\leadsto \color{blue}{\mathsf{neg}\left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                                                  3. *-commutativeN/A

                                                                    \[\leadsto \mathsf{neg}\left(\color{blue}{\sqrt{2} \cdot \sqrt{\frac{F}{B}}}\right) \]
                                                                  4. lower-*.f64N/A

                                                                    \[\leadsto \mathsf{neg}\left(\color{blue}{\sqrt{2} \cdot \sqrt{\frac{F}{B}}}\right) \]
                                                                  5. lower-sqrt.f64N/A

                                                                    \[\leadsto \mathsf{neg}\left(\color{blue}{\sqrt{2}} \cdot \sqrt{\frac{F}{B}}\right) \]
                                                                  6. lower-sqrt.f64N/A

                                                                    \[\leadsto \mathsf{neg}\left(\sqrt{2} \cdot \color{blue}{\sqrt{\frac{F}{B}}}\right) \]
                                                                  7. lower-/.f6420.0

                                                                    \[\leadsto -\sqrt{2} \cdot \sqrt{\color{blue}{\frac{F}{B}}} \]
                                                                5. Applied rewrites20.0%

                                                                  \[\leadsto \color{blue}{-\sqrt{2} \cdot \sqrt{\frac{F}{B}}} \]
                                                                6. Step-by-step derivation
                                                                  1. Applied rewrites29.6%

                                                                    \[\leadsto -\frac{\sqrt{F \cdot 2}}{\sqrt{B}} \]
                                                                  2. Step-by-step derivation
                                                                    1. Applied rewrites29.6%

                                                                      \[\leadsto -\sqrt{F} \cdot \sqrt{\frac{2}{B}} \]
                                                                  3. Recombined 4 regimes into one program.
                                                                  4. Final simplification23.9%

                                                                    \[\leadsto \begin{array}{l} \mathbf{if}\;\frac{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)}}{\left(4 \cdot A\right) \cdot C - {B}^{2}} \leq -\infty:\\ \;\;\;\;\sqrt{F \cdot \left(-0.5 \cdot \frac{B \cdot B}{A}\right)} \cdot \frac{\sqrt{2}}{-B}\\ \mathbf{elif}\;\frac{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)}}{\left(4 \cdot A\right) \cdot C - {B}^{2}} \leq -1 \cdot 10^{-220}:\\ \;\;\;\;\frac{\sqrt{2 \cdot \left(F \cdot \left(C + \sqrt{\mathsf{fma}\left(B, B, C \cdot C\right)}\right)\right)}}{-B}\\ \mathbf{elif}\;\frac{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)}}{\left(4 \cdot A\right) \cdot C - {B}^{2}} \leq \infty:\\ \;\;\;\;\frac{\sqrt{2}}{-B} \cdot \sqrt{\frac{-0.5 \cdot \left(F \cdot \left(B \cdot B\right)\right)}{A}}\\ \mathbf{else}:\\ \;\;\;\;\left(-\sqrt{F}\right) \cdot \sqrt{\frac{2}{B}}\\ \end{array} \]
                                                                  5. Add Preprocessing

                                                                  Alternative 13: 40.6% accurate, 0.3× speedup?

                                                                  \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} t_0 := \frac{\sqrt{2}}{-B\_m} \cdot \sqrt{\frac{-0.5 \cdot \left(F \cdot \left(B\_m \cdot B\_m\right)\right)}{A}}\\ t_1 := \left(4 \cdot A\right) \cdot C\\ t_2 := \frac{\sqrt{\left(2 \cdot \left(\left({B\_m}^{2} - t\_1\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{B\_m}^{2} + {\left(A - C\right)}^{2}}\right)}}{t\_1 - {B\_m}^{2}}\\ \mathbf{if}\;t\_2 \leq -\infty:\\ \;\;\;\;t\_0\\ \mathbf{elif}\;t\_2 \leq -1 \cdot 10^{-220}:\\ \;\;\;\;\frac{\sqrt{2 \cdot \left(F \cdot \left(C + \sqrt{\mathsf{fma}\left(B\_m, B\_m, C \cdot C\right)}\right)\right)}}{-B\_m}\\ \mathbf{elif}\;t\_2 \leq \infty:\\ \;\;\;\;t\_0\\ \mathbf{else}:\\ \;\;\;\;\left(-\sqrt{F}\right) \cdot \sqrt{\frac{2}{B\_m}}\\ \end{array} \end{array} \]
                                                                  B_m = (fabs.f64 B)
                                                                  NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                                  (FPCore (A B_m C F)
                                                                   :precision binary64
                                                                   (let* ((t_0
                                                                           (* (/ (sqrt 2.0) (- B_m)) (sqrt (/ (* -0.5 (* F (* B_m B_m))) A))))
                                                                          (t_1 (* (* 4.0 A) C))
                                                                          (t_2
                                                                           (/
                                                                            (sqrt
                                                                             (*
                                                                              (* 2.0 (* (- (pow B_m 2.0) t_1) F))
                                                                              (+ (+ A C) (sqrt (+ (pow B_m 2.0) (pow (- A C) 2.0))))))
                                                                            (- t_1 (pow B_m 2.0)))))
                                                                     (if (<= t_2 (- INFINITY))
                                                                       t_0
                                                                       (if (<= t_2 -1e-220)
                                                                         (/ (sqrt (* 2.0 (* F (+ C (sqrt (fma B_m B_m (* C C))))))) (- B_m))
                                                                         (if (<= t_2 INFINITY) t_0 (* (- (sqrt F)) (sqrt (/ 2.0 B_m))))))))
                                                                  B_m = fabs(B);
                                                                  assert(A < B_m && B_m < C && C < F);
                                                                  double code(double A, double B_m, double C, double F) {
                                                                  	double t_0 = (sqrt(2.0) / -B_m) * sqrt(((-0.5 * (F * (B_m * B_m))) / A));
                                                                  	double t_1 = (4.0 * A) * C;
                                                                  	double t_2 = sqrt(((2.0 * ((pow(B_m, 2.0) - t_1) * F)) * ((A + C) + sqrt((pow(B_m, 2.0) + pow((A - C), 2.0)))))) / (t_1 - pow(B_m, 2.0));
                                                                  	double tmp;
                                                                  	if (t_2 <= -((double) INFINITY)) {
                                                                  		tmp = t_0;
                                                                  	} else if (t_2 <= -1e-220) {
                                                                  		tmp = sqrt((2.0 * (F * (C + sqrt(fma(B_m, B_m, (C * C))))))) / -B_m;
                                                                  	} else if (t_2 <= ((double) INFINITY)) {
                                                                  		tmp = t_0;
                                                                  	} else {
                                                                  		tmp = -sqrt(F) * sqrt((2.0 / B_m));
                                                                  	}
                                                                  	return tmp;
                                                                  }
                                                                  
                                                                  B_m = abs(B)
                                                                  A, B_m, C, F = sort([A, B_m, C, F])
                                                                  function code(A, B_m, C, F)
                                                                  	t_0 = Float64(Float64(sqrt(2.0) / Float64(-B_m)) * sqrt(Float64(Float64(-0.5 * Float64(F * Float64(B_m * B_m))) / A)))
                                                                  	t_1 = Float64(Float64(4.0 * A) * C)
                                                                  	t_2 = Float64(sqrt(Float64(Float64(2.0 * Float64(Float64((B_m ^ 2.0) - t_1) * F)) * Float64(Float64(A + C) + sqrt(Float64((B_m ^ 2.0) + (Float64(A - C) ^ 2.0)))))) / Float64(t_1 - (B_m ^ 2.0)))
                                                                  	tmp = 0.0
                                                                  	if (t_2 <= Float64(-Inf))
                                                                  		tmp = t_0;
                                                                  	elseif (t_2 <= -1e-220)
                                                                  		tmp = Float64(sqrt(Float64(2.0 * Float64(F * Float64(C + sqrt(fma(B_m, B_m, Float64(C * C))))))) / Float64(-B_m));
                                                                  	elseif (t_2 <= Inf)
                                                                  		tmp = t_0;
                                                                  	else
                                                                  		tmp = Float64(Float64(-sqrt(F)) * sqrt(Float64(2.0 / B_m)));
                                                                  	end
                                                                  	return tmp
                                                                  end
                                                                  
                                                                  B_m = N[Abs[B], $MachinePrecision]
                                                                  NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                                  code[A_, B$95$m_, C_, F_] := Block[{t$95$0 = N[(N[(N[Sqrt[2.0], $MachinePrecision] / (-B$95$m)), $MachinePrecision] * N[Sqrt[N[(N[(-0.5 * N[(F * N[(B$95$m * B$95$m), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] / A), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]}, Block[{t$95$1 = N[(N[(4.0 * A), $MachinePrecision] * C), $MachinePrecision]}, Block[{t$95$2 = N[(N[Sqrt[N[(N[(2.0 * N[(N[(N[Power[B$95$m, 2.0], $MachinePrecision] - t$95$1), $MachinePrecision] * F), $MachinePrecision]), $MachinePrecision] * N[(N[(A + C), $MachinePrecision] + N[Sqrt[N[(N[Power[B$95$m, 2.0], $MachinePrecision] + N[Power[N[(A - C), $MachinePrecision], 2.0], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / N[(t$95$1 - N[Power[B$95$m, 2.0], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[t$95$2, (-Infinity)], t$95$0, If[LessEqual[t$95$2, -1e-220], N[(N[Sqrt[N[(2.0 * N[(F * N[(C + N[Sqrt[N[(B$95$m * B$95$m + N[(C * C), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / (-B$95$m)), $MachinePrecision], If[LessEqual[t$95$2, Infinity], t$95$0, N[((-N[Sqrt[F], $MachinePrecision]) * N[Sqrt[N[(2.0 / B$95$m), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]]]]]]]
                                                                  
                                                                  \begin{array}{l}
                                                                  B_m = \left|B\right|
                                                                  \\
                                                                  [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
                                                                  \\
                                                                  \begin{array}{l}
                                                                  t_0 := \frac{\sqrt{2}}{-B\_m} \cdot \sqrt{\frac{-0.5 \cdot \left(F \cdot \left(B\_m \cdot B\_m\right)\right)}{A}}\\
                                                                  t_1 := \left(4 \cdot A\right) \cdot C\\
                                                                  t_2 := \frac{\sqrt{\left(2 \cdot \left(\left({B\_m}^{2} - t\_1\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{B\_m}^{2} + {\left(A - C\right)}^{2}}\right)}}{t\_1 - {B\_m}^{2}}\\
                                                                  \mathbf{if}\;t\_2 \leq -\infty:\\
                                                                  \;\;\;\;t\_0\\
                                                                  
                                                                  \mathbf{elif}\;t\_2 \leq -1 \cdot 10^{-220}:\\
                                                                  \;\;\;\;\frac{\sqrt{2 \cdot \left(F \cdot \left(C + \sqrt{\mathsf{fma}\left(B\_m, B\_m, C \cdot C\right)}\right)\right)}}{-B\_m}\\
                                                                  
                                                                  \mathbf{elif}\;t\_2 \leq \infty:\\
                                                                  \;\;\;\;t\_0\\
                                                                  
                                                                  \mathbf{else}:\\
                                                                  \;\;\;\;\left(-\sqrt{F}\right) \cdot \sqrt{\frac{2}{B\_m}}\\
                                                                  
                                                                  
                                                                  \end{array}
                                                                  \end{array}
                                                                  
                                                                  Derivation
                                                                  1. Split input into 3 regimes
                                                                  2. if (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C))) < -inf.0 or -9.99999999999999992e-221 < (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C))) < +inf.0

                                                                    1. Initial program 12.2%

                                                                      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                    2. Add Preprocessing
                                                                    3. Taylor expanded in C around 0

                                                                      \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A + \sqrt{{A}^{2} + {B}^{2}}\right)}\right)} \]
                                                                    4. Step-by-step derivation
                                                                      1. mul-1-negN/A

                                                                        \[\leadsto \color{blue}{\mathsf{neg}\left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A + \sqrt{{A}^{2} + {B}^{2}}\right)}\right)} \]
                                                                      2. *-commutativeN/A

                                                                        \[\leadsto \mathsf{neg}\left(\color{blue}{\sqrt{F \cdot \left(A + \sqrt{{A}^{2} + {B}^{2}}\right)} \cdot \frac{\sqrt{2}}{B}}\right) \]
                                                                      3. distribute-rgt-neg-inN/A

                                                                        \[\leadsto \color{blue}{\sqrt{F \cdot \left(A + \sqrt{{A}^{2} + {B}^{2}}\right)} \cdot \left(\mathsf{neg}\left(\frac{\sqrt{2}}{B}\right)\right)} \]
                                                                      4. mul-1-negN/A

                                                                        \[\leadsto \sqrt{F \cdot \left(A + \sqrt{{A}^{2} + {B}^{2}}\right)} \cdot \color{blue}{\left(-1 \cdot \frac{\sqrt{2}}{B}\right)} \]
                                                                      5. lower-*.f64N/A

                                                                        \[\leadsto \color{blue}{\sqrt{F \cdot \left(A + \sqrt{{A}^{2} + {B}^{2}}\right)} \cdot \left(-1 \cdot \frac{\sqrt{2}}{B}\right)} \]
                                                                    5. Applied rewrites4.9%

                                                                      \[\leadsto \color{blue}{\sqrt{F \cdot \left(A + \sqrt{\mathsf{fma}\left(B, B, A \cdot A\right)}\right)} \cdot \left(-\frac{\sqrt{2}}{B}\right)} \]
                                                                    6. Taylor expanded in A around -inf

                                                                      \[\leadsto \sqrt{\frac{-1}{2} \cdot \frac{{B}^{2} \cdot F}{A}} \cdot \left(\mathsf{neg}\left(\frac{\color{blue}{\sqrt{2}}}{B}\right)\right) \]
                                                                    7. Step-by-step derivation
                                                                      1. Applied rewrites6.4%

                                                                        \[\leadsto \sqrt{\frac{-0.5 \cdot \left(\left(B \cdot B\right) \cdot F\right)}{A}} \cdot \left(-\frac{\color{blue}{\sqrt{2}}}{B}\right) \]

                                                                      if -inf.0 < (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C))) < -9.99999999999999992e-221

                                                                      1. Initial program 98.5%

                                                                        \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                      2. Add Preprocessing
                                                                      3. Taylor expanded in A around -inf

                                                                        \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\left(\frac{-1}{2} \cdot \frac{{B}^{2}}{A} + 2 \cdot C\right)}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                      4. Step-by-step derivation
                                                                        1. +-commutativeN/A

                                                                          \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\left(2 \cdot C + \frac{-1}{2} \cdot \frac{{B}^{2}}{A}\right)}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                        2. lower-fma.f64N/A

                                                                          \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\mathsf{fma}\left(2, C, \frac{-1}{2} \cdot \frac{{B}^{2}}{A}\right)}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                        3. associate-*r/N/A

                                                                          \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(2, C, \color{blue}{\frac{\frac{-1}{2} \cdot {B}^{2}}{A}}\right)}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                        4. lower-/.f64N/A

                                                                          \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(2, C, \color{blue}{\frac{\frac{-1}{2} \cdot {B}^{2}}{A}}\right)}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                        5. lower-*.f64N/A

                                                                          \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(2, C, \frac{\color{blue}{\frac{-1}{2} \cdot {B}^{2}}}{A}\right)}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                        6. unpow2N/A

                                                                          \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(2, C, \frac{\frac{-1}{2} \cdot \color{blue}{\left(B \cdot B\right)}}{A}\right)}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                        7. lower-*.f6420.9

                                                                          \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(2, C, \frac{-0.5 \cdot \color{blue}{\left(B \cdot B\right)}}{A}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                      5. Applied rewrites20.9%

                                                                        \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\mathsf{fma}\left(2, C, \frac{-0.5 \cdot \left(B \cdot B\right)}{A}\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                      6. Applied rewrites20.8%

                                                                        \[\leadsto \frac{-\color{blue}{\sqrt{\mathsf{fma}\left(2, C, \frac{\left(B \cdot B\right) \cdot -0.5}{A}\right) \cdot 2} \cdot \sqrt{F \cdot \mathsf{fma}\left(B, B, \left(-4 \cdot C\right) \cdot A\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                      7. Taylor expanded in A around 0

                                                                        \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right)} \]
                                                                      8. Step-by-step derivation
                                                                        1. mul-1-negN/A

                                                                          \[\leadsto \color{blue}{\mathsf{neg}\left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right)} \]
                                                                        2. lower-neg.f64N/A

                                                                          \[\leadsto \color{blue}{\mathsf{neg}\left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right)} \]
                                                                        3. lower-*.f64N/A

                                                                          \[\leadsto \mathsf{neg}\left(\color{blue}{\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}}\right) \]
                                                                        4. lower-/.f64N/A

                                                                          \[\leadsto \mathsf{neg}\left(\color{blue}{\frac{\sqrt{2}}{B}} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right) \]
                                                                        5. lower-sqrt.f64N/A

                                                                          \[\leadsto \mathsf{neg}\left(\frac{\color{blue}{\sqrt{2}}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right) \]
                                                                        6. lower-sqrt.f64N/A

                                                                          \[\leadsto \mathsf{neg}\left(\frac{\sqrt{2}}{B} \cdot \color{blue}{\sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}}\right) \]
                                                                        7. lower-*.f64N/A

                                                                          \[\leadsto \mathsf{neg}\left(\frac{\sqrt{2}}{B} \cdot \sqrt{\color{blue}{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}}\right) \]
                                                                        8. lower-+.f64N/A

                                                                          \[\leadsto \mathsf{neg}\left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}}\right) \]
                                                                        9. lower-sqrt.f64N/A

                                                                          \[\leadsto \mathsf{neg}\left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \color{blue}{\sqrt{{B}^{2} + {C}^{2}}}\right)}\right) \]
                                                                        10. unpow2N/A

                                                                          \[\leadsto \mathsf{neg}\left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{\color{blue}{B \cdot B} + {C}^{2}}\right)}\right) \]
                                                                        11. lower-fma.f64N/A

                                                                          \[\leadsto \mathsf{neg}\left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{\color{blue}{\mathsf{fma}\left(B, B, {C}^{2}\right)}}\right)}\right) \]
                                                                        12. unpow2N/A

                                                                          \[\leadsto \mathsf{neg}\left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{\mathsf{fma}\left(B, B, \color{blue}{C \cdot C}\right)}\right)}\right) \]
                                                                        13. lower-*.f6445.6

                                                                          \[\leadsto -\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{\mathsf{fma}\left(B, B, \color{blue}{C \cdot C}\right)}\right)} \]
                                                                      9. Applied rewrites45.6%

                                                                        \[\leadsto \color{blue}{-\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{\mathsf{fma}\left(B, B, C \cdot C\right)}\right)}} \]
                                                                      10. Step-by-step derivation
                                                                        1. Applied rewrites45.9%

                                                                          \[\leadsto \frac{\sqrt{2 \cdot \left(F \cdot \left(C + \sqrt{\mathsf{fma}\left(B, B, C \cdot C\right)}\right)\right)}}{\color{blue}{-B}} \]

                                                                        if +inf.0 < (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)))

                                                                        1. Initial program 0.0%

                                                                          \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                        2. Add Preprocessing
                                                                        3. Taylor expanded in B around inf

                                                                          \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                                                        4. Step-by-step derivation
                                                                          1. mul-1-negN/A

                                                                            \[\leadsto \color{blue}{\mathsf{neg}\left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                                                          2. lower-neg.f64N/A

                                                                            \[\leadsto \color{blue}{\mathsf{neg}\left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                                                          3. *-commutativeN/A

                                                                            \[\leadsto \mathsf{neg}\left(\color{blue}{\sqrt{2} \cdot \sqrt{\frac{F}{B}}}\right) \]
                                                                          4. lower-*.f64N/A

                                                                            \[\leadsto \mathsf{neg}\left(\color{blue}{\sqrt{2} \cdot \sqrt{\frac{F}{B}}}\right) \]
                                                                          5. lower-sqrt.f64N/A

                                                                            \[\leadsto \mathsf{neg}\left(\color{blue}{\sqrt{2}} \cdot \sqrt{\frac{F}{B}}\right) \]
                                                                          6. lower-sqrt.f64N/A

                                                                            \[\leadsto \mathsf{neg}\left(\sqrt{2} \cdot \color{blue}{\sqrt{\frac{F}{B}}}\right) \]
                                                                          7. lower-/.f6420.0

                                                                            \[\leadsto -\sqrt{2} \cdot \sqrt{\color{blue}{\frac{F}{B}}} \]
                                                                        5. Applied rewrites20.0%

                                                                          \[\leadsto \color{blue}{-\sqrt{2} \cdot \sqrt{\frac{F}{B}}} \]
                                                                        6. Step-by-step derivation
                                                                          1. Applied rewrites29.6%

                                                                            \[\leadsto -\frac{\sqrt{F \cdot 2}}{\sqrt{B}} \]
                                                                          2. Step-by-step derivation
                                                                            1. Applied rewrites29.6%

                                                                              \[\leadsto -\sqrt{F} \cdot \sqrt{\frac{2}{B}} \]
                                                                          3. Recombined 3 regimes into one program.
                                                                          4. Final simplification23.5%

                                                                            \[\leadsto \begin{array}{l} \mathbf{if}\;\frac{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)}}{\left(4 \cdot A\right) \cdot C - {B}^{2}} \leq -\infty:\\ \;\;\;\;\frac{\sqrt{2}}{-B} \cdot \sqrt{\frac{-0.5 \cdot \left(F \cdot \left(B \cdot B\right)\right)}{A}}\\ \mathbf{elif}\;\frac{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)}}{\left(4 \cdot A\right) \cdot C - {B}^{2}} \leq -1 \cdot 10^{-220}:\\ \;\;\;\;\frac{\sqrt{2 \cdot \left(F \cdot \left(C + \sqrt{\mathsf{fma}\left(B, B, C \cdot C\right)}\right)\right)}}{-B}\\ \mathbf{elif}\;\frac{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)}}{\left(4 \cdot A\right) \cdot C - {B}^{2}} \leq \infty:\\ \;\;\;\;\frac{\sqrt{2}}{-B} \cdot \sqrt{\frac{-0.5 \cdot \left(F \cdot \left(B \cdot B\right)\right)}{A}}\\ \mathbf{else}:\\ \;\;\;\;\left(-\sqrt{F}\right) \cdot \sqrt{\frac{2}{B}}\\ \end{array} \]
                                                                          5. Add Preprocessing

                                                                          Alternative 14: 48.1% accurate, 1.3× speedup?

                                                                          \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} t_0 := \mathsf{fma}\left(C, A \cdot -4, B\_m \cdot B\_m\right)\\ \mathbf{if}\;{B\_m}^{2} \leq 10^{-120}:\\ \;\;\;\;\sqrt{2 \cdot \left(\left(2 \cdot C\right) \cdot t\_0\right)} \cdot \frac{-\sqrt{F}}{t\_0}\\ \mathbf{elif}\;{B\_m}^{2} \leq 5 \cdot 10^{-14}:\\ \;\;\;\;\frac{\sqrt{F} \cdot \sqrt{\left(\left(A + C\right) + \sqrt{\mathsf{fma}\left(A - C, A - C, B\_m \cdot B\_m\right)}\right) \cdot \left(2 \cdot \mathsf{fma}\left(B\_m, B\_m, -4 \cdot \left(A \cdot C\right)\right)\right)}}{-B\_m \cdot B\_m}\\ \mathbf{elif}\;{B\_m}^{2} \leq 10^{+167}:\\ \;\;\;\;\sqrt{F \cdot \left(-0.5 \cdot \frac{B\_m \cdot B\_m}{A}\right)} \cdot \frac{\sqrt{2}}{-B\_m}\\ \mathbf{else}:\\ \;\;\;\;-\frac{\sqrt{F}}{\sqrt{B\_m \cdot 0.5}}\\ \end{array} \end{array} \]
                                                                          B_m = (fabs.f64 B)
                                                                          NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                                          (FPCore (A B_m C F)
                                                                           :precision binary64
                                                                           (let* ((t_0 (fma C (* A -4.0) (* B_m B_m))))
                                                                             (if (<= (pow B_m 2.0) 1e-120)
                                                                               (* (sqrt (* 2.0 (* (* 2.0 C) t_0))) (/ (- (sqrt F)) t_0))
                                                                               (if (<= (pow B_m 2.0) 5e-14)
                                                                                 (/
                                                                                  (*
                                                                                   (sqrt F)
                                                                                   (sqrt
                                                                                    (*
                                                                                     (+ (+ A C) (sqrt (fma (- A C) (- A C) (* B_m B_m))))
                                                                                     (* 2.0 (fma B_m B_m (* -4.0 (* A C)))))))
                                                                                  (- (* B_m B_m)))
                                                                                 (if (<= (pow B_m 2.0) 1e+167)
                                                                                   (* (sqrt (* F (* -0.5 (/ (* B_m B_m) A)))) (/ (sqrt 2.0) (- B_m)))
                                                                                   (- (/ (sqrt F) (sqrt (* B_m 0.5)))))))))
                                                                          B_m = fabs(B);
                                                                          assert(A < B_m && B_m < C && C < F);
                                                                          double code(double A, double B_m, double C, double F) {
                                                                          	double t_0 = fma(C, (A * -4.0), (B_m * B_m));
                                                                          	double tmp;
                                                                          	if (pow(B_m, 2.0) <= 1e-120) {
                                                                          		tmp = sqrt((2.0 * ((2.0 * C) * t_0))) * (-sqrt(F) / t_0);
                                                                          	} else if (pow(B_m, 2.0) <= 5e-14) {
                                                                          		tmp = (sqrt(F) * sqrt((((A + C) + sqrt(fma((A - C), (A - C), (B_m * B_m)))) * (2.0 * fma(B_m, B_m, (-4.0 * (A * C))))))) / -(B_m * B_m);
                                                                          	} else if (pow(B_m, 2.0) <= 1e+167) {
                                                                          		tmp = sqrt((F * (-0.5 * ((B_m * B_m) / A)))) * (sqrt(2.0) / -B_m);
                                                                          	} else {
                                                                          		tmp = -(sqrt(F) / sqrt((B_m * 0.5)));
                                                                          	}
                                                                          	return tmp;
                                                                          }
                                                                          
                                                                          B_m = abs(B)
                                                                          A, B_m, C, F = sort([A, B_m, C, F])
                                                                          function code(A, B_m, C, F)
                                                                          	t_0 = fma(C, Float64(A * -4.0), Float64(B_m * B_m))
                                                                          	tmp = 0.0
                                                                          	if ((B_m ^ 2.0) <= 1e-120)
                                                                          		tmp = Float64(sqrt(Float64(2.0 * Float64(Float64(2.0 * C) * t_0))) * Float64(Float64(-sqrt(F)) / t_0));
                                                                          	elseif ((B_m ^ 2.0) <= 5e-14)
                                                                          		tmp = Float64(Float64(sqrt(F) * sqrt(Float64(Float64(Float64(A + C) + sqrt(fma(Float64(A - C), Float64(A - C), Float64(B_m * B_m)))) * Float64(2.0 * fma(B_m, B_m, Float64(-4.0 * Float64(A * C))))))) / Float64(-Float64(B_m * B_m)));
                                                                          	elseif ((B_m ^ 2.0) <= 1e+167)
                                                                          		tmp = Float64(sqrt(Float64(F * Float64(-0.5 * Float64(Float64(B_m * B_m) / A)))) * Float64(sqrt(2.0) / Float64(-B_m)));
                                                                          	else
                                                                          		tmp = Float64(-Float64(sqrt(F) / sqrt(Float64(B_m * 0.5))));
                                                                          	end
                                                                          	return tmp
                                                                          end
                                                                          
                                                                          B_m = N[Abs[B], $MachinePrecision]
                                                                          NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                                          code[A_, B$95$m_, C_, F_] := Block[{t$95$0 = N[(C * N[(A * -4.0), $MachinePrecision] + N[(B$95$m * B$95$m), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[N[Power[B$95$m, 2.0], $MachinePrecision], 1e-120], N[(N[Sqrt[N[(2.0 * N[(N[(2.0 * C), $MachinePrecision] * t$95$0), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] * N[((-N[Sqrt[F], $MachinePrecision]) / t$95$0), $MachinePrecision]), $MachinePrecision], If[LessEqual[N[Power[B$95$m, 2.0], $MachinePrecision], 5e-14], N[(N[(N[Sqrt[F], $MachinePrecision] * N[Sqrt[N[(N[(N[(A + C), $MachinePrecision] + N[Sqrt[N[(N[(A - C), $MachinePrecision] * N[(A - C), $MachinePrecision] + N[(B$95$m * B$95$m), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] * N[(2.0 * N[(B$95$m * B$95$m + N[(-4.0 * N[(A * C), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] / (-N[(B$95$m * B$95$m), $MachinePrecision])), $MachinePrecision], If[LessEqual[N[Power[B$95$m, 2.0], $MachinePrecision], 1e+167], N[(N[Sqrt[N[(F * N[(-0.5 * N[(N[(B$95$m * B$95$m), $MachinePrecision] / A), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] * N[(N[Sqrt[2.0], $MachinePrecision] / (-B$95$m)), $MachinePrecision]), $MachinePrecision], (-N[(N[Sqrt[F], $MachinePrecision] / N[Sqrt[N[(B$95$m * 0.5), $MachinePrecision]], $MachinePrecision]), $MachinePrecision])]]]]
                                                                          
                                                                          \begin{array}{l}
                                                                          B_m = \left|B\right|
                                                                          \\
                                                                          [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
                                                                          \\
                                                                          \begin{array}{l}
                                                                          t_0 := \mathsf{fma}\left(C, A \cdot -4, B\_m \cdot B\_m\right)\\
                                                                          \mathbf{if}\;{B\_m}^{2} \leq 10^{-120}:\\
                                                                          \;\;\;\;\sqrt{2 \cdot \left(\left(2 \cdot C\right) \cdot t\_0\right)} \cdot \frac{-\sqrt{F}}{t\_0}\\
                                                                          
                                                                          \mathbf{elif}\;{B\_m}^{2} \leq 5 \cdot 10^{-14}:\\
                                                                          \;\;\;\;\frac{\sqrt{F} \cdot \sqrt{\left(\left(A + C\right) + \sqrt{\mathsf{fma}\left(A - C, A - C, B\_m \cdot B\_m\right)}\right) \cdot \left(2 \cdot \mathsf{fma}\left(B\_m, B\_m, -4 \cdot \left(A \cdot C\right)\right)\right)}}{-B\_m \cdot B\_m}\\
                                                                          
                                                                          \mathbf{elif}\;{B\_m}^{2} \leq 10^{+167}:\\
                                                                          \;\;\;\;\sqrt{F \cdot \left(-0.5 \cdot \frac{B\_m \cdot B\_m}{A}\right)} \cdot \frac{\sqrt{2}}{-B\_m}\\
                                                                          
                                                                          \mathbf{else}:\\
                                                                          \;\;\;\;-\frac{\sqrt{F}}{\sqrt{B\_m \cdot 0.5}}\\
                                                                          
                                                                          
                                                                          \end{array}
                                                                          \end{array}
                                                                          
                                                                          Derivation
                                                                          1. Split input into 4 regimes
                                                                          2. if (pow.f64 B #s(literal 2 binary64)) < 9.99999999999999979e-121

                                                                            1. Initial program 23.0%

                                                                              \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                            2. Add Preprocessing
                                                                            3. Step-by-step derivation
                                                                              1. lift-sqrt.f64N/A

                                                                                \[\leadsto \frac{\mathsf{neg}\left(\color{blue}{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                              2. lift-*.f64N/A

                                                                                \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\color{blue}{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                              3. *-commutativeN/A

                                                                                \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\color{blue}{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right)}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                              4. lift-*.f64N/A

                                                                                \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \color{blue}{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right)}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                              5. lift-*.f64N/A

                                                                                \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \left(2 \cdot \color{blue}{\left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)}\right)}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                              6. associate-*r*N/A

                                                                                \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \color{blue}{\left(\left(2 \cdot \left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)\right) \cdot F\right)}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                              7. associate-*r*N/A

                                                                                \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\color{blue}{\left(\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \left(2 \cdot \left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)\right)\right) \cdot F}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                              8. sqrt-prodN/A

                                                                                \[\leadsto \frac{\mathsf{neg}\left(\color{blue}{\sqrt{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \left(2 \cdot \left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)\right)} \cdot \sqrt{F}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                              9. pow1/2N/A

                                                                                \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \left(2 \cdot \left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)\right)} \cdot \color{blue}{{F}^{\frac{1}{2}}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                            4. Applied rewrites13.7%

                                                                              \[\leadsto \frac{-\color{blue}{\sqrt{\left(\sqrt{\mathsf{fma}\left(A - C, A - C, B \cdot B\right)} + \left(A + C\right)\right) \cdot \left(2 \cdot \mathsf{fma}\left(B, B, -4 \cdot \left(A \cdot C\right)\right)\right)} \cdot \sqrt{F}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                            5. Taylor expanded in A around -inf

                                                                              \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\color{blue}{\left(2 \cdot C\right)} \cdot \left(2 \cdot \mathsf{fma}\left(B, B, -4 \cdot \left(A \cdot C\right)\right)\right)} \cdot \sqrt{F}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                            6. Step-by-step derivation
                                                                              1. lower-*.f6415.1

                                                                                \[\leadsto \frac{-\sqrt{\color{blue}{\left(2 \cdot C\right)} \cdot \left(2 \cdot \mathsf{fma}\left(B, B, -4 \cdot \left(A \cdot C\right)\right)\right)} \cdot \sqrt{F}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                            7. Applied rewrites15.1%

                                                                              \[\leadsto \frac{-\sqrt{\color{blue}{\left(2 \cdot C\right)} \cdot \left(2 \cdot \mathsf{fma}\left(B, B, -4 \cdot \left(A \cdot C\right)\right)\right)} \cdot \sqrt{F}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                            8. Applied rewrites15.1%

                                                                              \[\leadsto \color{blue}{\sqrt{2 \cdot \left(\mathsf{fma}\left(C, A \cdot -4, B \cdot B\right) \cdot \left(2 \cdot C\right)\right)} \cdot \frac{-\sqrt{F}}{\mathsf{fma}\left(C, A \cdot -4, B \cdot B\right)}} \]

                                                                            if 9.99999999999999979e-121 < (pow.f64 B #s(literal 2 binary64)) < 5.0000000000000002e-14

                                                                            1. Initial program 48.3%

                                                                              \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                            2. Add Preprocessing
                                                                            3. Step-by-step derivation
                                                                              1. lift-sqrt.f64N/A

                                                                                \[\leadsto \frac{\mathsf{neg}\left(\color{blue}{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                              2. lift-*.f64N/A

                                                                                \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\color{blue}{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                              3. *-commutativeN/A

                                                                                \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\color{blue}{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right)}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                              4. lift-*.f64N/A

                                                                                \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \color{blue}{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right)}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                              5. lift-*.f64N/A

                                                                                \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \left(2 \cdot \color{blue}{\left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)}\right)}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                              6. associate-*r*N/A

                                                                                \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \color{blue}{\left(\left(2 \cdot \left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)\right) \cdot F\right)}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                              7. associate-*r*N/A

                                                                                \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\color{blue}{\left(\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \left(2 \cdot \left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)\right)\right) \cdot F}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                              8. sqrt-prodN/A

                                                                                \[\leadsto \frac{\mathsf{neg}\left(\color{blue}{\sqrt{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \left(2 \cdot \left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)\right)} \cdot \sqrt{F}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                              9. pow1/2N/A

                                                                                \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \left(2 \cdot \left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)\right)} \cdot \color{blue}{{F}^{\frac{1}{2}}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                            4. Applied rewrites52.3%

                                                                              \[\leadsto \frac{-\color{blue}{\sqrt{\left(\sqrt{\mathsf{fma}\left(A - C, A - C, B \cdot B\right)} + \left(A + C\right)\right) \cdot \left(2 \cdot \mathsf{fma}\left(B, B, -4 \cdot \left(A \cdot C\right)\right)\right)} \cdot \sqrt{F}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                            5. Taylor expanded in B around inf

                                                                              \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(\sqrt{\mathsf{fma}\left(A - C, A - C, B \cdot B\right)} + \left(A + C\right)\right) \cdot \left(2 \cdot \mathsf{fma}\left(B, B, -4 \cdot \left(A \cdot C\right)\right)\right)} \cdot \sqrt{F}\right)}{\color{blue}{{B}^{2}}} \]
                                                                            6. Step-by-step derivation
                                                                              1. unpow2N/A

                                                                                \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(\sqrt{\mathsf{fma}\left(A - C, A - C, B \cdot B\right)} + \left(A + C\right)\right) \cdot \left(2 \cdot \mathsf{fma}\left(B, B, -4 \cdot \left(A \cdot C\right)\right)\right)} \cdot \sqrt{F}\right)}{\color{blue}{B \cdot B}} \]
                                                                              2. lower-*.f6452.5

                                                                                \[\leadsto \frac{-\sqrt{\left(\sqrt{\mathsf{fma}\left(A - C, A - C, B \cdot B\right)} + \left(A + C\right)\right) \cdot \left(2 \cdot \mathsf{fma}\left(B, B, -4 \cdot \left(A \cdot C\right)\right)\right)} \cdot \sqrt{F}}{\color{blue}{B \cdot B}} \]
                                                                            7. Applied rewrites52.5%

                                                                              \[\leadsto \frac{-\sqrt{\left(\sqrt{\mathsf{fma}\left(A - C, A - C, B \cdot B\right)} + \left(A + C\right)\right) \cdot \left(2 \cdot \mathsf{fma}\left(B, B, -4 \cdot \left(A \cdot C\right)\right)\right)} \cdot \sqrt{F}}{\color{blue}{B \cdot B}} \]

                                                                            if 5.0000000000000002e-14 < (pow.f64 B #s(literal 2 binary64)) < 1e167

                                                                            1. Initial program 15.1%

                                                                              \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                            2. Add Preprocessing
                                                                            3. Taylor expanded in C around 0

                                                                              \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A + \sqrt{{A}^{2} + {B}^{2}}\right)}\right)} \]
                                                                            4. Step-by-step derivation
                                                                              1. mul-1-negN/A

                                                                                \[\leadsto \color{blue}{\mathsf{neg}\left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A + \sqrt{{A}^{2} + {B}^{2}}\right)}\right)} \]
                                                                              2. *-commutativeN/A

                                                                                \[\leadsto \mathsf{neg}\left(\color{blue}{\sqrt{F \cdot \left(A + \sqrt{{A}^{2} + {B}^{2}}\right)} \cdot \frac{\sqrt{2}}{B}}\right) \]
                                                                              3. distribute-rgt-neg-inN/A

                                                                                \[\leadsto \color{blue}{\sqrt{F \cdot \left(A + \sqrt{{A}^{2} + {B}^{2}}\right)} \cdot \left(\mathsf{neg}\left(\frac{\sqrt{2}}{B}\right)\right)} \]
                                                                              4. mul-1-negN/A

                                                                                \[\leadsto \sqrt{F \cdot \left(A + \sqrt{{A}^{2} + {B}^{2}}\right)} \cdot \color{blue}{\left(-1 \cdot \frac{\sqrt{2}}{B}\right)} \]
                                                                              5. lower-*.f64N/A

                                                                                \[\leadsto \color{blue}{\sqrt{F \cdot \left(A + \sqrt{{A}^{2} + {B}^{2}}\right)} \cdot \left(-1 \cdot \frac{\sqrt{2}}{B}\right)} \]
                                                                            5. Applied rewrites10.8%

                                                                              \[\leadsto \color{blue}{\sqrt{F \cdot \left(A + \sqrt{\mathsf{fma}\left(B, B, A \cdot A\right)}\right)} \cdot \left(-\frac{\sqrt{2}}{B}\right)} \]
                                                                            6. Taylor expanded in A around -inf

                                                                              \[\leadsto \sqrt{F \cdot \left(\frac{-1}{2} \cdot \frac{{B}^{2}}{A}\right)} \cdot \left(\mathsf{neg}\left(\frac{\sqrt{2}}{B}\right)\right) \]
                                                                            7. Step-by-step derivation
                                                                              1. Applied rewrites9.1%

                                                                                \[\leadsto \sqrt{F \cdot \left(-0.5 \cdot \frac{B \cdot B}{A}\right)} \cdot \left(-\frac{\sqrt{2}}{B}\right) \]

                                                                              if 1e167 < (pow.f64 B #s(literal 2 binary64))

                                                                              1. Initial program 6.2%

                                                                                \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                              2. Add Preprocessing
                                                                              3. Taylor expanded in B around inf

                                                                                \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                                                              4. Step-by-step derivation
                                                                                1. mul-1-negN/A

                                                                                  \[\leadsto \color{blue}{\mathsf{neg}\left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                                                                2. lower-neg.f64N/A

                                                                                  \[\leadsto \color{blue}{\mathsf{neg}\left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                                                                3. *-commutativeN/A

                                                                                  \[\leadsto \mathsf{neg}\left(\color{blue}{\sqrt{2} \cdot \sqrt{\frac{F}{B}}}\right) \]
                                                                                4. lower-*.f64N/A

                                                                                  \[\leadsto \mathsf{neg}\left(\color{blue}{\sqrt{2} \cdot \sqrt{\frac{F}{B}}}\right) \]
                                                                                5. lower-sqrt.f64N/A

                                                                                  \[\leadsto \mathsf{neg}\left(\color{blue}{\sqrt{2}} \cdot \sqrt{\frac{F}{B}}\right) \]
                                                                                6. lower-sqrt.f64N/A

                                                                                  \[\leadsto \mathsf{neg}\left(\sqrt{2} \cdot \color{blue}{\sqrt{\frac{F}{B}}}\right) \]
                                                                                7. lower-/.f6432.2

                                                                                  \[\leadsto -\sqrt{2} \cdot \sqrt{\color{blue}{\frac{F}{B}}} \]
                                                                              5. Applied rewrites32.2%

                                                                                \[\leadsto \color{blue}{-\sqrt{2} \cdot \sqrt{\frac{F}{B}}} \]
                                                                              6. Step-by-step derivation
                                                                                1. Applied rewrites45.8%

                                                                                  \[\leadsto -\frac{\sqrt{F \cdot 2}}{\sqrt{B}} \]
                                                                                2. Step-by-step derivation
                                                                                  1. Applied rewrites45.8%

                                                                                    \[\leadsto -\sqrt{F} \cdot \sqrt{\frac{2}{B}} \]
                                                                                  2. Step-by-step derivation
                                                                                    1. Applied rewrites45.9%

                                                                                      \[\leadsto -\frac{\sqrt{F}}{\sqrt{B \cdot 0.5}} \]
                                                                                  3. Recombined 4 regimes into one program.
                                                                                  4. Final simplification29.8%

                                                                                    \[\leadsto \begin{array}{l} \mathbf{if}\;{B}^{2} \leq 10^{-120}:\\ \;\;\;\;\sqrt{2 \cdot \left(\left(2 \cdot C\right) \cdot \mathsf{fma}\left(C, A \cdot -4, B \cdot B\right)\right)} \cdot \frac{-\sqrt{F}}{\mathsf{fma}\left(C, A \cdot -4, B \cdot B\right)}\\ \mathbf{elif}\;{B}^{2} \leq 5 \cdot 10^{-14}:\\ \;\;\;\;\frac{\sqrt{F} \cdot \sqrt{\left(\left(A + C\right) + \sqrt{\mathsf{fma}\left(A - C, A - C, B \cdot B\right)}\right) \cdot \left(2 \cdot \mathsf{fma}\left(B, B, -4 \cdot \left(A \cdot C\right)\right)\right)}}{-B \cdot B}\\ \mathbf{elif}\;{B}^{2} \leq 10^{+167}:\\ \;\;\;\;\sqrt{F \cdot \left(-0.5 \cdot \frac{B \cdot B}{A}\right)} \cdot \frac{\sqrt{2}}{-B}\\ \mathbf{else}:\\ \;\;\;\;-\frac{\sqrt{F}}{\sqrt{B \cdot 0.5}}\\ \end{array} \]
                                                                                  5. Add Preprocessing

                                                                                  Alternative 15: 48.0% accurate, 1.3× speedup?

                                                                                  \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} t_0 := \mathsf{fma}\left(C, A \cdot -4, B\_m \cdot B\_m\right)\\ t_1 := -\sqrt{F}\\ \mathbf{if}\;{B\_m}^{2} \leq 10^{-120}:\\ \;\;\;\;\sqrt{2 \cdot \left(\left(2 \cdot C\right) \cdot t\_0\right)} \cdot \frac{t\_1}{t\_0}\\ \mathbf{elif}\;{B\_m}^{2} \leq 5 \cdot 10^{-31}:\\ \;\;\;\;\frac{\sqrt{2}}{B\_m} \cdot \left(t\_1 \cdot \sqrt{C + \sqrt{\mathsf{fma}\left(B\_m, B\_m, C \cdot C\right)}}\right)\\ \mathbf{elif}\;{B\_m}^{2} \leq 10^{+167}:\\ \;\;\;\;\sqrt{F \cdot \left(-0.5 \cdot \frac{B\_m \cdot B\_m}{A}\right)} \cdot \frac{\sqrt{2}}{-B\_m}\\ \mathbf{else}:\\ \;\;\;\;-\frac{\sqrt{F}}{\sqrt{B\_m \cdot 0.5}}\\ \end{array} \end{array} \]
                                                                                  B_m = (fabs.f64 B)
                                                                                  NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                                                  (FPCore (A B_m C F)
                                                                                   :precision binary64
                                                                                   (let* ((t_0 (fma C (* A -4.0) (* B_m B_m))) (t_1 (- (sqrt F))))
                                                                                     (if (<= (pow B_m 2.0) 1e-120)
                                                                                       (* (sqrt (* 2.0 (* (* 2.0 C) t_0))) (/ t_1 t_0))
                                                                                       (if (<= (pow B_m 2.0) 5e-31)
                                                                                         (* (/ (sqrt 2.0) B_m) (* t_1 (sqrt (+ C (sqrt (fma B_m B_m (* C C)))))))
                                                                                         (if (<= (pow B_m 2.0) 1e+167)
                                                                                           (* (sqrt (* F (* -0.5 (/ (* B_m B_m) A)))) (/ (sqrt 2.0) (- B_m)))
                                                                                           (- (/ (sqrt F) (sqrt (* B_m 0.5)))))))))
                                                                                  B_m = fabs(B);
                                                                                  assert(A < B_m && B_m < C && C < F);
                                                                                  double code(double A, double B_m, double C, double F) {
                                                                                  	double t_0 = fma(C, (A * -4.0), (B_m * B_m));
                                                                                  	double t_1 = -sqrt(F);
                                                                                  	double tmp;
                                                                                  	if (pow(B_m, 2.0) <= 1e-120) {
                                                                                  		tmp = sqrt((2.0 * ((2.0 * C) * t_0))) * (t_1 / t_0);
                                                                                  	} else if (pow(B_m, 2.0) <= 5e-31) {
                                                                                  		tmp = (sqrt(2.0) / B_m) * (t_1 * sqrt((C + sqrt(fma(B_m, B_m, (C * C))))));
                                                                                  	} else if (pow(B_m, 2.0) <= 1e+167) {
                                                                                  		tmp = sqrt((F * (-0.5 * ((B_m * B_m) / A)))) * (sqrt(2.0) / -B_m);
                                                                                  	} else {
                                                                                  		tmp = -(sqrt(F) / sqrt((B_m * 0.5)));
                                                                                  	}
                                                                                  	return tmp;
                                                                                  }
                                                                                  
                                                                                  B_m = abs(B)
                                                                                  A, B_m, C, F = sort([A, B_m, C, F])
                                                                                  function code(A, B_m, C, F)
                                                                                  	t_0 = fma(C, Float64(A * -4.0), Float64(B_m * B_m))
                                                                                  	t_1 = Float64(-sqrt(F))
                                                                                  	tmp = 0.0
                                                                                  	if ((B_m ^ 2.0) <= 1e-120)
                                                                                  		tmp = Float64(sqrt(Float64(2.0 * Float64(Float64(2.0 * C) * t_0))) * Float64(t_1 / t_0));
                                                                                  	elseif ((B_m ^ 2.0) <= 5e-31)
                                                                                  		tmp = Float64(Float64(sqrt(2.0) / B_m) * Float64(t_1 * sqrt(Float64(C + sqrt(fma(B_m, B_m, Float64(C * C)))))));
                                                                                  	elseif ((B_m ^ 2.0) <= 1e+167)
                                                                                  		tmp = Float64(sqrt(Float64(F * Float64(-0.5 * Float64(Float64(B_m * B_m) / A)))) * Float64(sqrt(2.0) / Float64(-B_m)));
                                                                                  	else
                                                                                  		tmp = Float64(-Float64(sqrt(F) / sqrt(Float64(B_m * 0.5))));
                                                                                  	end
                                                                                  	return tmp
                                                                                  end
                                                                                  
                                                                                  B_m = N[Abs[B], $MachinePrecision]
                                                                                  NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                                                  code[A_, B$95$m_, C_, F_] := Block[{t$95$0 = N[(C * N[(A * -4.0), $MachinePrecision] + N[(B$95$m * B$95$m), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$1 = (-N[Sqrt[F], $MachinePrecision])}, If[LessEqual[N[Power[B$95$m, 2.0], $MachinePrecision], 1e-120], N[(N[Sqrt[N[(2.0 * N[(N[(2.0 * C), $MachinePrecision] * t$95$0), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] * N[(t$95$1 / t$95$0), $MachinePrecision]), $MachinePrecision], If[LessEqual[N[Power[B$95$m, 2.0], $MachinePrecision], 5e-31], N[(N[(N[Sqrt[2.0], $MachinePrecision] / B$95$m), $MachinePrecision] * N[(t$95$1 * N[Sqrt[N[(C + N[Sqrt[N[(B$95$m * B$95$m + N[(C * C), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision], If[LessEqual[N[Power[B$95$m, 2.0], $MachinePrecision], 1e+167], N[(N[Sqrt[N[(F * N[(-0.5 * N[(N[(B$95$m * B$95$m), $MachinePrecision] / A), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] * N[(N[Sqrt[2.0], $MachinePrecision] / (-B$95$m)), $MachinePrecision]), $MachinePrecision], (-N[(N[Sqrt[F], $MachinePrecision] / N[Sqrt[N[(B$95$m * 0.5), $MachinePrecision]], $MachinePrecision]), $MachinePrecision])]]]]]
                                                                                  
                                                                                  \begin{array}{l}
                                                                                  B_m = \left|B\right|
                                                                                  \\
                                                                                  [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
                                                                                  \\
                                                                                  \begin{array}{l}
                                                                                  t_0 := \mathsf{fma}\left(C, A \cdot -4, B\_m \cdot B\_m\right)\\
                                                                                  t_1 := -\sqrt{F}\\
                                                                                  \mathbf{if}\;{B\_m}^{2} \leq 10^{-120}:\\
                                                                                  \;\;\;\;\sqrt{2 \cdot \left(\left(2 \cdot C\right) \cdot t\_0\right)} \cdot \frac{t\_1}{t\_0}\\
                                                                                  
                                                                                  \mathbf{elif}\;{B\_m}^{2} \leq 5 \cdot 10^{-31}:\\
                                                                                  \;\;\;\;\frac{\sqrt{2}}{B\_m} \cdot \left(t\_1 \cdot \sqrt{C + \sqrt{\mathsf{fma}\left(B\_m, B\_m, C \cdot C\right)}}\right)\\
                                                                                  
                                                                                  \mathbf{elif}\;{B\_m}^{2} \leq 10^{+167}:\\
                                                                                  \;\;\;\;\sqrt{F \cdot \left(-0.5 \cdot \frac{B\_m \cdot B\_m}{A}\right)} \cdot \frac{\sqrt{2}}{-B\_m}\\
                                                                                  
                                                                                  \mathbf{else}:\\
                                                                                  \;\;\;\;-\frac{\sqrt{F}}{\sqrt{B\_m \cdot 0.5}}\\
                                                                                  
                                                                                  
                                                                                  \end{array}
                                                                                  \end{array}
                                                                                  
                                                                                  Derivation
                                                                                  1. Split input into 4 regimes
                                                                                  2. if (pow.f64 B #s(literal 2 binary64)) < 9.99999999999999979e-121

                                                                                    1. Initial program 23.0%

                                                                                      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                                    2. Add Preprocessing
                                                                                    3. Step-by-step derivation
                                                                                      1. lift-sqrt.f64N/A

                                                                                        \[\leadsto \frac{\mathsf{neg}\left(\color{blue}{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                                      2. lift-*.f64N/A

                                                                                        \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\color{blue}{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                                      3. *-commutativeN/A

                                                                                        \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\color{blue}{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right)}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                                      4. lift-*.f64N/A

                                                                                        \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \color{blue}{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right)}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                                      5. lift-*.f64N/A

                                                                                        \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \left(2 \cdot \color{blue}{\left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)}\right)}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                                      6. associate-*r*N/A

                                                                                        \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \color{blue}{\left(\left(2 \cdot \left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)\right) \cdot F\right)}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                                      7. associate-*r*N/A

                                                                                        \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\color{blue}{\left(\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \left(2 \cdot \left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)\right)\right) \cdot F}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                                      8. sqrt-prodN/A

                                                                                        \[\leadsto \frac{\mathsf{neg}\left(\color{blue}{\sqrt{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \left(2 \cdot \left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)\right)} \cdot \sqrt{F}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                                      9. pow1/2N/A

                                                                                        \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \left(2 \cdot \left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)\right)} \cdot \color{blue}{{F}^{\frac{1}{2}}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                                    4. Applied rewrites13.7%

                                                                                      \[\leadsto \frac{-\color{blue}{\sqrt{\left(\sqrt{\mathsf{fma}\left(A - C, A - C, B \cdot B\right)} + \left(A + C\right)\right) \cdot \left(2 \cdot \mathsf{fma}\left(B, B, -4 \cdot \left(A \cdot C\right)\right)\right)} \cdot \sqrt{F}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                                    5. Taylor expanded in A around -inf

                                                                                      \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\color{blue}{\left(2 \cdot C\right)} \cdot \left(2 \cdot \mathsf{fma}\left(B, B, -4 \cdot \left(A \cdot C\right)\right)\right)} \cdot \sqrt{F}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                                    6. Step-by-step derivation
                                                                                      1. lower-*.f6415.1

                                                                                        \[\leadsto \frac{-\sqrt{\color{blue}{\left(2 \cdot C\right)} \cdot \left(2 \cdot \mathsf{fma}\left(B, B, -4 \cdot \left(A \cdot C\right)\right)\right)} \cdot \sqrt{F}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                                    7. Applied rewrites15.1%

                                                                                      \[\leadsto \frac{-\sqrt{\color{blue}{\left(2 \cdot C\right)} \cdot \left(2 \cdot \mathsf{fma}\left(B, B, -4 \cdot \left(A \cdot C\right)\right)\right)} \cdot \sqrt{F}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                                    8. Applied rewrites15.1%

                                                                                      \[\leadsto \color{blue}{\sqrt{2 \cdot \left(\mathsf{fma}\left(C, A \cdot -4, B \cdot B\right) \cdot \left(2 \cdot C\right)\right)} \cdot \frac{-\sqrt{F}}{\mathsf{fma}\left(C, A \cdot -4, B \cdot B\right)}} \]

                                                                                    if 9.99999999999999979e-121 < (pow.f64 B #s(literal 2 binary64)) < 5e-31

                                                                                    1. Initial program 54.5%

                                                                                      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                                    2. Add Preprocessing
                                                                                    3. Taylor expanded in A around -inf

                                                                                      \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\left(\frac{-1}{2} \cdot \frac{{B}^{2}}{A} + 2 \cdot C\right)}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                                    4. Step-by-step derivation
                                                                                      1. +-commutativeN/A

                                                                                        \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\left(2 \cdot C + \frac{-1}{2} \cdot \frac{{B}^{2}}{A}\right)}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                                      2. lower-fma.f64N/A

                                                                                        \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\mathsf{fma}\left(2, C, \frac{-1}{2} \cdot \frac{{B}^{2}}{A}\right)}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                                      3. associate-*r/N/A

                                                                                        \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(2, C, \color{blue}{\frac{\frac{-1}{2} \cdot {B}^{2}}{A}}\right)}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                                      4. lower-/.f64N/A

                                                                                        \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(2, C, \color{blue}{\frac{\frac{-1}{2} \cdot {B}^{2}}{A}}\right)}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                                      5. lower-*.f64N/A

                                                                                        \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(2, C, \frac{\color{blue}{\frac{-1}{2} \cdot {B}^{2}}}{A}\right)}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                                      6. unpow2N/A

                                                                                        \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(2, C, \frac{\frac{-1}{2} \cdot \color{blue}{\left(B \cdot B\right)}}{A}\right)}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                                      7. lower-*.f643.2

                                                                                        \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(2, C, \frac{-0.5 \cdot \color{blue}{\left(B \cdot B\right)}}{A}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                                    5. Applied rewrites3.2%

                                                                                      \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\mathsf{fma}\left(2, C, \frac{-0.5 \cdot \left(B \cdot B\right)}{A}\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                                    6. Applied rewrites8.9%

                                                                                      \[\leadsto \frac{-\color{blue}{\sqrt{\mathsf{fma}\left(2, C, \frac{\left(B \cdot B\right) \cdot -0.5}{A}\right) \cdot 2} \cdot \sqrt{F \cdot \mathsf{fma}\left(B, B, \left(-4 \cdot C\right) \cdot A\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                                    7. Taylor expanded in A around 0

                                                                                      \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right)} \]
                                                                                    8. Step-by-step derivation
                                                                                      1. mul-1-negN/A

                                                                                        \[\leadsto \color{blue}{\mathsf{neg}\left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right)} \]
                                                                                      2. lower-neg.f64N/A

                                                                                        \[\leadsto \color{blue}{\mathsf{neg}\left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right)} \]
                                                                                      3. lower-*.f64N/A

                                                                                        \[\leadsto \mathsf{neg}\left(\color{blue}{\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}}\right) \]
                                                                                      4. lower-/.f64N/A

                                                                                        \[\leadsto \mathsf{neg}\left(\color{blue}{\frac{\sqrt{2}}{B}} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right) \]
                                                                                      5. lower-sqrt.f64N/A

                                                                                        \[\leadsto \mathsf{neg}\left(\frac{\color{blue}{\sqrt{2}}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right) \]
                                                                                      6. lower-sqrt.f64N/A

                                                                                        \[\leadsto \mathsf{neg}\left(\frac{\sqrt{2}}{B} \cdot \color{blue}{\sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}}\right) \]
                                                                                      7. lower-*.f64N/A

                                                                                        \[\leadsto \mathsf{neg}\left(\frac{\sqrt{2}}{B} \cdot \sqrt{\color{blue}{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}}\right) \]
                                                                                      8. lower-+.f64N/A

                                                                                        \[\leadsto \mathsf{neg}\left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}}\right) \]
                                                                                      9. lower-sqrt.f64N/A

                                                                                        \[\leadsto \mathsf{neg}\left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \color{blue}{\sqrt{{B}^{2} + {C}^{2}}}\right)}\right) \]
                                                                                      10. unpow2N/A

                                                                                        \[\leadsto \mathsf{neg}\left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{\color{blue}{B \cdot B} + {C}^{2}}\right)}\right) \]
                                                                                      11. lower-fma.f64N/A

                                                                                        \[\leadsto \mathsf{neg}\left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{\color{blue}{\mathsf{fma}\left(B, B, {C}^{2}\right)}}\right)}\right) \]
                                                                                      12. unpow2N/A

                                                                                        \[\leadsto \mathsf{neg}\left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{\mathsf{fma}\left(B, B, \color{blue}{C \cdot C}\right)}\right)}\right) \]
                                                                                      13. lower-*.f6428.8

                                                                                        \[\leadsto -\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{\mathsf{fma}\left(B, B, \color{blue}{C \cdot C}\right)}\right)} \]
                                                                                    9. Applied rewrites28.8%

                                                                                      \[\leadsto \color{blue}{-\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{\mathsf{fma}\left(B, B, C \cdot C\right)}\right)}} \]
                                                                                    10. Step-by-step derivation
                                                                                      1. Applied rewrites35.2%

                                                                                        \[\leadsto -\frac{\sqrt{2}}{B} \cdot \left(\sqrt{C + \sqrt{\mathsf{fma}\left(B, B, C \cdot C\right)}} \cdot \sqrt{F}\right) \]

                                                                                      if 5e-31 < (pow.f64 B #s(literal 2 binary64)) < 1e167

                                                                                      1. Initial program 18.8%

                                                                                        \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                                      2. Add Preprocessing
                                                                                      3. Taylor expanded in C around 0

                                                                                        \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A + \sqrt{{A}^{2} + {B}^{2}}\right)}\right)} \]
                                                                                      4. Step-by-step derivation
                                                                                        1. mul-1-negN/A

                                                                                          \[\leadsto \color{blue}{\mathsf{neg}\left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A + \sqrt{{A}^{2} + {B}^{2}}\right)}\right)} \]
                                                                                        2. *-commutativeN/A

                                                                                          \[\leadsto \mathsf{neg}\left(\color{blue}{\sqrt{F \cdot \left(A + \sqrt{{A}^{2} + {B}^{2}}\right)} \cdot \frac{\sqrt{2}}{B}}\right) \]
                                                                                        3. distribute-rgt-neg-inN/A

                                                                                          \[\leadsto \color{blue}{\sqrt{F \cdot \left(A + \sqrt{{A}^{2} + {B}^{2}}\right)} \cdot \left(\mathsf{neg}\left(\frac{\sqrt{2}}{B}\right)\right)} \]
                                                                                        4. mul-1-negN/A

                                                                                          \[\leadsto \sqrt{F \cdot \left(A + \sqrt{{A}^{2} + {B}^{2}}\right)} \cdot \color{blue}{\left(-1 \cdot \frac{\sqrt{2}}{B}\right)} \]
                                                                                        5. lower-*.f64N/A

                                                                                          \[\leadsto \color{blue}{\sqrt{F \cdot \left(A + \sqrt{{A}^{2} + {B}^{2}}\right)} \cdot \left(-1 \cdot \frac{\sqrt{2}}{B}\right)} \]
                                                                                      5. Applied rewrites13.1%

                                                                                        \[\leadsto \color{blue}{\sqrt{F \cdot \left(A + \sqrt{\mathsf{fma}\left(B, B, A \cdot A\right)}\right)} \cdot \left(-\frac{\sqrt{2}}{B}\right)} \]
                                                                                      6. Taylor expanded in A around -inf

                                                                                        \[\leadsto \sqrt{F \cdot \left(\frac{-1}{2} \cdot \frac{{B}^{2}}{A}\right)} \cdot \left(\mathsf{neg}\left(\frac{\sqrt{2}}{B}\right)\right) \]
                                                                                      7. Step-by-step derivation
                                                                                        1. Applied rewrites9.9%

                                                                                          \[\leadsto \sqrt{F \cdot \left(-0.5 \cdot \frac{B \cdot B}{A}\right)} \cdot \left(-\frac{\sqrt{2}}{B}\right) \]

                                                                                        if 1e167 < (pow.f64 B #s(literal 2 binary64))

                                                                                        1. Initial program 6.2%

                                                                                          \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                                        2. Add Preprocessing
                                                                                        3. Taylor expanded in B around inf

                                                                                          \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                                                                        4. Step-by-step derivation
                                                                                          1. mul-1-negN/A

                                                                                            \[\leadsto \color{blue}{\mathsf{neg}\left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                                                                          2. lower-neg.f64N/A

                                                                                            \[\leadsto \color{blue}{\mathsf{neg}\left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                                                                          3. *-commutativeN/A

                                                                                            \[\leadsto \mathsf{neg}\left(\color{blue}{\sqrt{2} \cdot \sqrt{\frac{F}{B}}}\right) \]
                                                                                          4. lower-*.f64N/A

                                                                                            \[\leadsto \mathsf{neg}\left(\color{blue}{\sqrt{2} \cdot \sqrt{\frac{F}{B}}}\right) \]
                                                                                          5. lower-sqrt.f64N/A

                                                                                            \[\leadsto \mathsf{neg}\left(\color{blue}{\sqrt{2}} \cdot \sqrt{\frac{F}{B}}\right) \]
                                                                                          6. lower-sqrt.f64N/A

                                                                                            \[\leadsto \mathsf{neg}\left(\sqrt{2} \cdot \color{blue}{\sqrt{\frac{F}{B}}}\right) \]
                                                                                          7. lower-/.f6432.2

                                                                                            \[\leadsto -\sqrt{2} \cdot \sqrt{\color{blue}{\frac{F}{B}}} \]
                                                                                        5. Applied rewrites32.2%

                                                                                          \[\leadsto \color{blue}{-\sqrt{2} \cdot \sqrt{\frac{F}{B}}} \]
                                                                                        6. Step-by-step derivation
                                                                                          1. Applied rewrites45.8%

                                                                                            \[\leadsto -\frac{\sqrt{F \cdot 2}}{\sqrt{B}} \]
                                                                                          2. Step-by-step derivation
                                                                                            1. Applied rewrites45.8%

                                                                                              \[\leadsto -\sqrt{F} \cdot \sqrt{\frac{2}{B}} \]
                                                                                            2. Step-by-step derivation
                                                                                              1. Applied rewrites45.9%

                                                                                                \[\leadsto -\frac{\sqrt{F}}{\sqrt{B \cdot 0.5}} \]
                                                                                            3. Recombined 4 regimes into one program.
                                                                                            4. Final simplification27.6%

                                                                                              \[\leadsto \begin{array}{l} \mathbf{if}\;{B}^{2} \leq 10^{-120}:\\ \;\;\;\;\sqrt{2 \cdot \left(\left(2 \cdot C\right) \cdot \mathsf{fma}\left(C, A \cdot -4, B \cdot B\right)\right)} \cdot \frac{-\sqrt{F}}{\mathsf{fma}\left(C, A \cdot -4, B \cdot B\right)}\\ \mathbf{elif}\;{B}^{2} \leq 5 \cdot 10^{-31}:\\ \;\;\;\;\frac{\sqrt{2}}{B} \cdot \left(\left(-\sqrt{F}\right) \cdot \sqrt{C + \sqrt{\mathsf{fma}\left(B, B, C \cdot C\right)}}\right)\\ \mathbf{elif}\;{B}^{2} \leq 10^{+167}:\\ \;\;\;\;\sqrt{F \cdot \left(-0.5 \cdot \frac{B \cdot B}{A}\right)} \cdot \frac{\sqrt{2}}{-B}\\ \mathbf{else}:\\ \;\;\;\;-\frac{\sqrt{F}}{\sqrt{B \cdot 0.5}}\\ \end{array} \]
                                                                                            5. Add Preprocessing

                                                                                            Alternative 16: 50.2% accurate, 1.3× speedup?

                                                                                            \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} t_0 := \mathsf{fma}\left(C, A \cdot -4, B\_m \cdot B\_m\right)\\ \mathbf{if}\;{B\_m}^{2} \leq 10^{-132}:\\ \;\;\;\;\sqrt{\left(2 \cdot C\right) \cdot \left(2 \cdot \left(F \cdot t\_0\right)\right)} \cdot \frac{-1}{t\_0}\\ \mathbf{elif}\;{B\_m}^{2} \leq 5 \cdot 10^{-31}:\\ \;\;\;\;\frac{\sqrt{2}}{B\_m} \cdot \left(\left(-\sqrt{F}\right) \cdot \sqrt{C + \sqrt{\mathsf{fma}\left(B\_m, B\_m, C \cdot C\right)}}\right)\\ \mathbf{elif}\;{B\_m}^{2} \leq 10^{+167}:\\ \;\;\;\;\sqrt{F \cdot \left(-0.5 \cdot \frac{B\_m \cdot B\_m}{A}\right)} \cdot \frac{\sqrt{2}}{-B\_m}\\ \mathbf{else}:\\ \;\;\;\;-\frac{\sqrt{F}}{\sqrt{B\_m \cdot 0.5}}\\ \end{array} \end{array} \]
                                                                                            B_m = (fabs.f64 B)
                                                                                            NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                                                            (FPCore (A B_m C F)
                                                                                             :precision binary64
                                                                                             (let* ((t_0 (fma C (* A -4.0) (* B_m B_m))))
                                                                                               (if (<= (pow B_m 2.0) 1e-132)
                                                                                                 (* (sqrt (* (* 2.0 C) (* 2.0 (* F t_0)))) (/ -1.0 t_0))
                                                                                                 (if (<= (pow B_m 2.0) 5e-31)
                                                                                                   (*
                                                                                                    (/ (sqrt 2.0) B_m)
                                                                                                    (* (- (sqrt F)) (sqrt (+ C (sqrt (fma B_m B_m (* C C)))))))
                                                                                                   (if (<= (pow B_m 2.0) 1e+167)
                                                                                                     (* (sqrt (* F (* -0.5 (/ (* B_m B_m) A)))) (/ (sqrt 2.0) (- B_m)))
                                                                                                     (- (/ (sqrt F) (sqrt (* B_m 0.5)))))))))
                                                                                            B_m = fabs(B);
                                                                                            assert(A < B_m && B_m < C && C < F);
                                                                                            double code(double A, double B_m, double C, double F) {
                                                                                            	double t_0 = fma(C, (A * -4.0), (B_m * B_m));
                                                                                            	double tmp;
                                                                                            	if (pow(B_m, 2.0) <= 1e-132) {
                                                                                            		tmp = sqrt(((2.0 * C) * (2.0 * (F * t_0)))) * (-1.0 / t_0);
                                                                                            	} else if (pow(B_m, 2.0) <= 5e-31) {
                                                                                            		tmp = (sqrt(2.0) / B_m) * (-sqrt(F) * sqrt((C + sqrt(fma(B_m, B_m, (C * C))))));
                                                                                            	} else if (pow(B_m, 2.0) <= 1e+167) {
                                                                                            		tmp = sqrt((F * (-0.5 * ((B_m * B_m) / A)))) * (sqrt(2.0) / -B_m);
                                                                                            	} else {
                                                                                            		tmp = -(sqrt(F) / sqrt((B_m * 0.5)));
                                                                                            	}
                                                                                            	return tmp;
                                                                                            }
                                                                                            
                                                                                            B_m = abs(B)
                                                                                            A, B_m, C, F = sort([A, B_m, C, F])
                                                                                            function code(A, B_m, C, F)
                                                                                            	t_0 = fma(C, Float64(A * -4.0), Float64(B_m * B_m))
                                                                                            	tmp = 0.0
                                                                                            	if ((B_m ^ 2.0) <= 1e-132)
                                                                                            		tmp = Float64(sqrt(Float64(Float64(2.0 * C) * Float64(2.0 * Float64(F * t_0)))) * Float64(-1.0 / t_0));
                                                                                            	elseif ((B_m ^ 2.0) <= 5e-31)
                                                                                            		tmp = Float64(Float64(sqrt(2.0) / B_m) * Float64(Float64(-sqrt(F)) * sqrt(Float64(C + sqrt(fma(B_m, B_m, Float64(C * C)))))));
                                                                                            	elseif ((B_m ^ 2.0) <= 1e+167)
                                                                                            		tmp = Float64(sqrt(Float64(F * Float64(-0.5 * Float64(Float64(B_m * B_m) / A)))) * Float64(sqrt(2.0) / Float64(-B_m)));
                                                                                            	else
                                                                                            		tmp = Float64(-Float64(sqrt(F) / sqrt(Float64(B_m * 0.5))));
                                                                                            	end
                                                                                            	return tmp
                                                                                            end
                                                                                            
                                                                                            B_m = N[Abs[B], $MachinePrecision]
                                                                                            NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                                                            code[A_, B$95$m_, C_, F_] := Block[{t$95$0 = N[(C * N[(A * -4.0), $MachinePrecision] + N[(B$95$m * B$95$m), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[N[Power[B$95$m, 2.0], $MachinePrecision], 1e-132], N[(N[Sqrt[N[(N[(2.0 * C), $MachinePrecision] * N[(2.0 * N[(F * t$95$0), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] * N[(-1.0 / t$95$0), $MachinePrecision]), $MachinePrecision], If[LessEqual[N[Power[B$95$m, 2.0], $MachinePrecision], 5e-31], N[(N[(N[Sqrt[2.0], $MachinePrecision] / B$95$m), $MachinePrecision] * N[((-N[Sqrt[F], $MachinePrecision]) * N[Sqrt[N[(C + N[Sqrt[N[(B$95$m * B$95$m + N[(C * C), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision], If[LessEqual[N[Power[B$95$m, 2.0], $MachinePrecision], 1e+167], N[(N[Sqrt[N[(F * N[(-0.5 * N[(N[(B$95$m * B$95$m), $MachinePrecision] / A), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] * N[(N[Sqrt[2.0], $MachinePrecision] / (-B$95$m)), $MachinePrecision]), $MachinePrecision], (-N[(N[Sqrt[F], $MachinePrecision] / N[Sqrt[N[(B$95$m * 0.5), $MachinePrecision]], $MachinePrecision]), $MachinePrecision])]]]]
                                                                                            
                                                                                            \begin{array}{l}
                                                                                            B_m = \left|B\right|
                                                                                            \\
                                                                                            [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
                                                                                            \\
                                                                                            \begin{array}{l}
                                                                                            t_0 := \mathsf{fma}\left(C, A \cdot -4, B\_m \cdot B\_m\right)\\
                                                                                            \mathbf{if}\;{B\_m}^{2} \leq 10^{-132}:\\
                                                                                            \;\;\;\;\sqrt{\left(2 \cdot C\right) \cdot \left(2 \cdot \left(F \cdot t\_0\right)\right)} \cdot \frac{-1}{t\_0}\\
                                                                                            
                                                                                            \mathbf{elif}\;{B\_m}^{2} \leq 5 \cdot 10^{-31}:\\
                                                                                            \;\;\;\;\frac{\sqrt{2}}{B\_m} \cdot \left(\left(-\sqrt{F}\right) \cdot \sqrt{C + \sqrt{\mathsf{fma}\left(B\_m, B\_m, C \cdot C\right)}}\right)\\
                                                                                            
                                                                                            \mathbf{elif}\;{B\_m}^{2} \leq 10^{+167}:\\
                                                                                            \;\;\;\;\sqrt{F \cdot \left(-0.5 \cdot \frac{B\_m \cdot B\_m}{A}\right)} \cdot \frac{\sqrt{2}}{-B\_m}\\
                                                                                            
                                                                                            \mathbf{else}:\\
                                                                                            \;\;\;\;-\frac{\sqrt{F}}{\sqrt{B\_m \cdot 0.5}}\\
                                                                                            
                                                                                            
                                                                                            \end{array}
                                                                                            \end{array}
                                                                                            
                                                                                            Derivation
                                                                                            1. Split input into 4 regimes
                                                                                            2. if (pow.f64 B #s(literal 2 binary64)) < 9.9999999999999999e-133

                                                                                              1. Initial program 22.9%

                                                                                                \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                                              2. Add Preprocessing
                                                                                              3. Step-by-step derivation
                                                                                                1. lift-sqrt.f64N/A

                                                                                                  \[\leadsto \frac{\mathsf{neg}\left(\color{blue}{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                                                2. lift-*.f64N/A

                                                                                                  \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\color{blue}{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                                                3. *-commutativeN/A

                                                                                                  \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\color{blue}{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right)}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                                                4. lift-*.f64N/A

                                                                                                  \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \color{blue}{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right)}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                                                5. lift-*.f64N/A

                                                                                                  \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \left(2 \cdot \color{blue}{\left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)}\right)}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                                                6. associate-*r*N/A

                                                                                                  \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \color{blue}{\left(\left(2 \cdot \left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)\right) \cdot F\right)}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                                                7. associate-*r*N/A

                                                                                                  \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\color{blue}{\left(\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \left(2 \cdot \left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)\right)\right) \cdot F}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                                                8. sqrt-prodN/A

                                                                                                  \[\leadsto \frac{\mathsf{neg}\left(\color{blue}{\sqrt{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \left(2 \cdot \left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)\right)} \cdot \sqrt{F}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                                                9. pow1/2N/A

                                                                                                  \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \left(2 \cdot \left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)\right)} \cdot \color{blue}{{F}^{\frac{1}{2}}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                                              4. Applied rewrites13.2%

                                                                                                \[\leadsto \frac{-\color{blue}{\sqrt{\left(\sqrt{\mathsf{fma}\left(A - C, A - C, B \cdot B\right)} + \left(A + C\right)\right) \cdot \left(2 \cdot \mathsf{fma}\left(B, B, -4 \cdot \left(A \cdot C\right)\right)\right)} \cdot \sqrt{F}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                                              5. Taylor expanded in A around -inf

                                                                                                \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\color{blue}{\left(2 \cdot C\right)} \cdot \left(2 \cdot \mathsf{fma}\left(B, B, -4 \cdot \left(A \cdot C\right)\right)\right)} \cdot \sqrt{F}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                                              6. Step-by-step derivation
                                                                                                1. lower-*.f6414.5

                                                                                                  \[\leadsto \frac{-\sqrt{\color{blue}{\left(2 \cdot C\right)} \cdot \left(2 \cdot \mathsf{fma}\left(B, B, -4 \cdot \left(A \cdot C\right)\right)\right)} \cdot \sqrt{F}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                                              7. Applied rewrites14.5%

                                                                                                \[\leadsto \frac{-\sqrt{\color{blue}{\left(2 \cdot C\right)} \cdot \left(2 \cdot \mathsf{fma}\left(B, B, -4 \cdot \left(A \cdot C\right)\right)\right)} \cdot \sqrt{F}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                                              8. Applied rewrites17.7%

                                                                                                \[\leadsto \color{blue}{\sqrt{\left(2 \cdot C\right) \cdot \left(2 \cdot \left(F \cdot \mathsf{fma}\left(C, A \cdot -4, B \cdot B\right)\right)\right)} \cdot \frac{-1}{\mathsf{fma}\left(C, A \cdot -4, B \cdot B\right)}} \]

                                                                                              if 9.9999999999999999e-133 < (pow.f64 B #s(literal 2 binary64)) < 5e-31

                                                                                              1. Initial program 48.3%

                                                                                                \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                                              2. Add Preprocessing
                                                                                              3. Taylor expanded in A around -inf

                                                                                                \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\left(\frac{-1}{2} \cdot \frac{{B}^{2}}{A} + 2 \cdot C\right)}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                                              4. Step-by-step derivation
                                                                                                1. +-commutativeN/A

                                                                                                  \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\left(2 \cdot C + \frac{-1}{2} \cdot \frac{{B}^{2}}{A}\right)}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                                                2. lower-fma.f64N/A

                                                                                                  \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\mathsf{fma}\left(2, C, \frac{-1}{2} \cdot \frac{{B}^{2}}{A}\right)}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                                                3. associate-*r/N/A

                                                                                                  \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(2, C, \color{blue}{\frac{\frac{-1}{2} \cdot {B}^{2}}{A}}\right)}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                                                4. lower-/.f64N/A

                                                                                                  \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(2, C, \color{blue}{\frac{\frac{-1}{2} \cdot {B}^{2}}{A}}\right)}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                                                5. lower-*.f64N/A

                                                                                                  \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(2, C, \frac{\color{blue}{\frac{-1}{2} \cdot {B}^{2}}}{A}\right)}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                                                6. unpow2N/A

                                                                                                  \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(2, C, \frac{\frac{-1}{2} \cdot \color{blue}{\left(B \cdot B\right)}}{A}\right)}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                                                7. lower-*.f648.1

                                                                                                  \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(2, C, \frac{-0.5 \cdot \color{blue}{\left(B \cdot B\right)}}{A}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                                              5. Applied rewrites8.1%

                                                                                                \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\mathsf{fma}\left(2, C, \frac{-0.5 \cdot \left(B \cdot B\right)}{A}\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                                              6. Applied rewrites12.3%

                                                                                                \[\leadsto \frac{-\color{blue}{\sqrt{\mathsf{fma}\left(2, C, \frac{\left(B \cdot B\right) \cdot -0.5}{A}\right) \cdot 2} \cdot \sqrt{F \cdot \mathsf{fma}\left(B, B, \left(-4 \cdot C\right) \cdot A\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                                              7. Taylor expanded in A around 0

                                                                                                \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right)} \]
                                                                                              8. Step-by-step derivation
                                                                                                1. mul-1-negN/A

                                                                                                  \[\leadsto \color{blue}{\mathsf{neg}\left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right)} \]
                                                                                                2. lower-neg.f64N/A

                                                                                                  \[\leadsto \color{blue}{\mathsf{neg}\left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right)} \]
                                                                                                3. lower-*.f64N/A

                                                                                                  \[\leadsto \mathsf{neg}\left(\color{blue}{\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}}\right) \]
                                                                                                4. lower-/.f64N/A

                                                                                                  \[\leadsto \mathsf{neg}\left(\color{blue}{\frac{\sqrt{2}}{B}} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right) \]
                                                                                                5. lower-sqrt.f64N/A

                                                                                                  \[\leadsto \mathsf{neg}\left(\frac{\color{blue}{\sqrt{2}}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right) \]
                                                                                                6. lower-sqrt.f64N/A

                                                                                                  \[\leadsto \mathsf{neg}\left(\frac{\sqrt{2}}{B} \cdot \color{blue}{\sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}}\right) \]
                                                                                                7. lower-*.f64N/A

                                                                                                  \[\leadsto \mathsf{neg}\left(\frac{\sqrt{2}}{B} \cdot \sqrt{\color{blue}{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}}\right) \]
                                                                                                8. lower-+.f64N/A

                                                                                                  \[\leadsto \mathsf{neg}\left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}}\right) \]
                                                                                                9. lower-sqrt.f64N/A

                                                                                                  \[\leadsto \mathsf{neg}\left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \color{blue}{\sqrt{{B}^{2} + {C}^{2}}}\right)}\right) \]
                                                                                                10. unpow2N/A

                                                                                                  \[\leadsto \mathsf{neg}\left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{\color{blue}{B \cdot B} + {C}^{2}}\right)}\right) \]
                                                                                                11. lower-fma.f64N/A

                                                                                                  \[\leadsto \mathsf{neg}\left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{\color{blue}{\mathsf{fma}\left(B, B, {C}^{2}\right)}}\right)}\right) \]
                                                                                                12. unpow2N/A

                                                                                                  \[\leadsto \mathsf{neg}\left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{\mathsf{fma}\left(B, B, \color{blue}{C \cdot C}\right)}\right)}\right) \]
                                                                                                13. lower-*.f6423.1

                                                                                                  \[\leadsto -\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{\mathsf{fma}\left(B, B, \color{blue}{C \cdot C}\right)}\right)} \]
                                                                                              9. Applied rewrites23.1%

                                                                                                \[\leadsto \color{blue}{-\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{\mathsf{fma}\left(B, B, C \cdot C\right)}\right)}} \]
                                                                                              10. Step-by-step derivation
                                                                                                1. Applied rewrites28.1%

                                                                                                  \[\leadsto -\frac{\sqrt{2}}{B} \cdot \left(\sqrt{C + \sqrt{\mathsf{fma}\left(B, B, C \cdot C\right)}} \cdot \sqrt{F}\right) \]

                                                                                                if 5e-31 < (pow.f64 B #s(literal 2 binary64)) < 1e167

                                                                                                1. Initial program 18.8%

                                                                                                  \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                                                2. Add Preprocessing
                                                                                                3. Taylor expanded in C around 0

                                                                                                  \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A + \sqrt{{A}^{2} + {B}^{2}}\right)}\right)} \]
                                                                                                4. Step-by-step derivation
                                                                                                  1. mul-1-negN/A

                                                                                                    \[\leadsto \color{blue}{\mathsf{neg}\left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A + \sqrt{{A}^{2} + {B}^{2}}\right)}\right)} \]
                                                                                                  2. *-commutativeN/A

                                                                                                    \[\leadsto \mathsf{neg}\left(\color{blue}{\sqrt{F \cdot \left(A + \sqrt{{A}^{2} + {B}^{2}}\right)} \cdot \frac{\sqrt{2}}{B}}\right) \]
                                                                                                  3. distribute-rgt-neg-inN/A

                                                                                                    \[\leadsto \color{blue}{\sqrt{F \cdot \left(A + \sqrt{{A}^{2} + {B}^{2}}\right)} \cdot \left(\mathsf{neg}\left(\frac{\sqrt{2}}{B}\right)\right)} \]
                                                                                                  4. mul-1-negN/A

                                                                                                    \[\leadsto \sqrt{F \cdot \left(A + \sqrt{{A}^{2} + {B}^{2}}\right)} \cdot \color{blue}{\left(-1 \cdot \frac{\sqrt{2}}{B}\right)} \]
                                                                                                  5. lower-*.f64N/A

                                                                                                    \[\leadsto \color{blue}{\sqrt{F \cdot \left(A + \sqrt{{A}^{2} + {B}^{2}}\right)} \cdot \left(-1 \cdot \frac{\sqrt{2}}{B}\right)} \]
                                                                                                5. Applied rewrites13.1%

                                                                                                  \[\leadsto \color{blue}{\sqrt{F \cdot \left(A + \sqrt{\mathsf{fma}\left(B, B, A \cdot A\right)}\right)} \cdot \left(-\frac{\sqrt{2}}{B}\right)} \]
                                                                                                6. Taylor expanded in A around -inf

                                                                                                  \[\leadsto \sqrt{F \cdot \left(\frac{-1}{2} \cdot \frac{{B}^{2}}{A}\right)} \cdot \left(\mathsf{neg}\left(\frac{\sqrt{2}}{B}\right)\right) \]
                                                                                                7. Step-by-step derivation
                                                                                                  1. Applied rewrites9.9%

                                                                                                    \[\leadsto \sqrt{F \cdot \left(-0.5 \cdot \frac{B \cdot B}{A}\right)} \cdot \left(-\frac{\sqrt{2}}{B}\right) \]

                                                                                                  if 1e167 < (pow.f64 B #s(literal 2 binary64))

                                                                                                  1. Initial program 6.2%

                                                                                                    \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                                                  2. Add Preprocessing
                                                                                                  3. Taylor expanded in B around inf

                                                                                                    \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                                                                                  4. Step-by-step derivation
                                                                                                    1. mul-1-negN/A

                                                                                                      \[\leadsto \color{blue}{\mathsf{neg}\left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                                                                                    2. lower-neg.f64N/A

                                                                                                      \[\leadsto \color{blue}{\mathsf{neg}\left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                                                                                    3. *-commutativeN/A

                                                                                                      \[\leadsto \mathsf{neg}\left(\color{blue}{\sqrt{2} \cdot \sqrt{\frac{F}{B}}}\right) \]
                                                                                                    4. lower-*.f64N/A

                                                                                                      \[\leadsto \mathsf{neg}\left(\color{blue}{\sqrt{2} \cdot \sqrt{\frac{F}{B}}}\right) \]
                                                                                                    5. lower-sqrt.f64N/A

                                                                                                      \[\leadsto \mathsf{neg}\left(\color{blue}{\sqrt{2}} \cdot \sqrt{\frac{F}{B}}\right) \]
                                                                                                    6. lower-sqrt.f64N/A

                                                                                                      \[\leadsto \mathsf{neg}\left(\sqrt{2} \cdot \color{blue}{\sqrt{\frac{F}{B}}}\right) \]
                                                                                                    7. lower-/.f6432.2

                                                                                                      \[\leadsto -\sqrt{2} \cdot \sqrt{\color{blue}{\frac{F}{B}}} \]
                                                                                                  5. Applied rewrites32.2%

                                                                                                    \[\leadsto \color{blue}{-\sqrt{2} \cdot \sqrt{\frac{F}{B}}} \]
                                                                                                  6. Step-by-step derivation
                                                                                                    1. Applied rewrites45.8%

                                                                                                      \[\leadsto -\frac{\sqrt{F \cdot 2}}{\sqrt{B}} \]
                                                                                                    2. Step-by-step derivation
                                                                                                      1. Applied rewrites45.8%

                                                                                                        \[\leadsto -\sqrt{F} \cdot \sqrt{\frac{2}{B}} \]
                                                                                                      2. Step-by-step derivation
                                                                                                        1. Applied rewrites45.9%

                                                                                                          \[\leadsto -\frac{\sqrt{F}}{\sqrt{B \cdot 0.5}} \]
                                                                                                      3. Recombined 4 regimes into one program.
                                                                                                      4. Final simplification28.3%

                                                                                                        \[\leadsto \begin{array}{l} \mathbf{if}\;{B}^{2} \leq 10^{-132}:\\ \;\;\;\;\sqrt{\left(2 \cdot C\right) \cdot \left(2 \cdot \left(F \cdot \mathsf{fma}\left(C, A \cdot -4, B \cdot B\right)\right)\right)} \cdot \frac{-1}{\mathsf{fma}\left(C, A \cdot -4, B \cdot B\right)}\\ \mathbf{elif}\;{B}^{2} \leq 5 \cdot 10^{-31}:\\ \;\;\;\;\frac{\sqrt{2}}{B} \cdot \left(\left(-\sqrt{F}\right) \cdot \sqrt{C + \sqrt{\mathsf{fma}\left(B, B, C \cdot C\right)}}\right)\\ \mathbf{elif}\;{B}^{2} \leq 10^{+167}:\\ \;\;\;\;\sqrt{F \cdot \left(-0.5 \cdot \frac{B \cdot B}{A}\right)} \cdot \frac{\sqrt{2}}{-B}\\ \mathbf{else}:\\ \;\;\;\;-\frac{\sqrt{F}}{\sqrt{B \cdot 0.5}}\\ \end{array} \]
                                                                                                      5. Add Preprocessing

                                                                                                      Alternative 17: 50.3% accurate, 1.3× speedup?

                                                                                                      \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} \mathbf{if}\;{B\_m}^{2} \leq 10^{-132}:\\ \;\;\;\;\frac{\sqrt{\left(2 \cdot C\right) \cdot \left(2 \cdot \left(F \cdot \mathsf{fma}\left(C, A \cdot -4, B\_m \cdot B\_m\right)\right)\right)}}{4 \cdot \left(A \cdot C\right) - B\_m \cdot B\_m}\\ \mathbf{elif}\;{B\_m}^{2} \leq 5 \cdot 10^{-31}:\\ \;\;\;\;\frac{\sqrt{2}}{B\_m} \cdot \left(\left(-\sqrt{F}\right) \cdot \sqrt{C + \sqrt{\mathsf{fma}\left(B\_m, B\_m, C \cdot C\right)}}\right)\\ \mathbf{elif}\;{B\_m}^{2} \leq 10^{+167}:\\ \;\;\;\;\sqrt{F \cdot \left(-0.5 \cdot \frac{B\_m \cdot B\_m}{A}\right)} \cdot \frac{\sqrt{2}}{-B\_m}\\ \mathbf{else}:\\ \;\;\;\;-\frac{\sqrt{F}}{\sqrt{B\_m \cdot 0.5}}\\ \end{array} \end{array} \]
                                                                                                      B_m = (fabs.f64 B)
                                                                                                      NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                                                                      (FPCore (A B_m C F)
                                                                                                       :precision binary64
                                                                                                       (if (<= (pow B_m 2.0) 1e-132)
                                                                                                         (/
                                                                                                          (sqrt (* (* 2.0 C) (* 2.0 (* F (fma C (* A -4.0) (* B_m B_m))))))
                                                                                                          (- (* 4.0 (* A C)) (* B_m B_m)))
                                                                                                         (if (<= (pow B_m 2.0) 5e-31)
                                                                                                           (*
                                                                                                            (/ (sqrt 2.0) B_m)
                                                                                                            (* (- (sqrt F)) (sqrt (+ C (sqrt (fma B_m B_m (* C C)))))))
                                                                                                           (if (<= (pow B_m 2.0) 1e+167)
                                                                                                             (* (sqrt (* F (* -0.5 (/ (* B_m B_m) A)))) (/ (sqrt 2.0) (- B_m)))
                                                                                                             (- (/ (sqrt F) (sqrt (* B_m 0.5))))))))
                                                                                                      B_m = fabs(B);
                                                                                                      assert(A < B_m && B_m < C && C < F);
                                                                                                      double code(double A, double B_m, double C, double F) {
                                                                                                      	double tmp;
                                                                                                      	if (pow(B_m, 2.0) <= 1e-132) {
                                                                                                      		tmp = sqrt(((2.0 * C) * (2.0 * (F * fma(C, (A * -4.0), (B_m * B_m)))))) / ((4.0 * (A * C)) - (B_m * B_m));
                                                                                                      	} else if (pow(B_m, 2.0) <= 5e-31) {
                                                                                                      		tmp = (sqrt(2.0) / B_m) * (-sqrt(F) * sqrt((C + sqrt(fma(B_m, B_m, (C * C))))));
                                                                                                      	} else if (pow(B_m, 2.0) <= 1e+167) {
                                                                                                      		tmp = sqrt((F * (-0.5 * ((B_m * B_m) / A)))) * (sqrt(2.0) / -B_m);
                                                                                                      	} else {
                                                                                                      		tmp = -(sqrt(F) / sqrt((B_m * 0.5)));
                                                                                                      	}
                                                                                                      	return tmp;
                                                                                                      }
                                                                                                      
                                                                                                      B_m = abs(B)
                                                                                                      A, B_m, C, F = sort([A, B_m, C, F])
                                                                                                      function code(A, B_m, C, F)
                                                                                                      	tmp = 0.0
                                                                                                      	if ((B_m ^ 2.0) <= 1e-132)
                                                                                                      		tmp = Float64(sqrt(Float64(Float64(2.0 * C) * Float64(2.0 * Float64(F * fma(C, Float64(A * -4.0), Float64(B_m * B_m)))))) / Float64(Float64(4.0 * Float64(A * C)) - Float64(B_m * B_m)));
                                                                                                      	elseif ((B_m ^ 2.0) <= 5e-31)
                                                                                                      		tmp = Float64(Float64(sqrt(2.0) / B_m) * Float64(Float64(-sqrt(F)) * sqrt(Float64(C + sqrt(fma(B_m, B_m, Float64(C * C)))))));
                                                                                                      	elseif ((B_m ^ 2.0) <= 1e+167)
                                                                                                      		tmp = Float64(sqrt(Float64(F * Float64(-0.5 * Float64(Float64(B_m * B_m) / A)))) * Float64(sqrt(2.0) / Float64(-B_m)));
                                                                                                      	else
                                                                                                      		tmp = Float64(-Float64(sqrt(F) / sqrt(Float64(B_m * 0.5))));
                                                                                                      	end
                                                                                                      	return tmp
                                                                                                      end
                                                                                                      
                                                                                                      B_m = N[Abs[B], $MachinePrecision]
                                                                                                      NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                                                                      code[A_, B$95$m_, C_, F_] := If[LessEqual[N[Power[B$95$m, 2.0], $MachinePrecision], 1e-132], N[(N[Sqrt[N[(N[(2.0 * C), $MachinePrecision] * N[(2.0 * N[(F * N[(C * N[(A * -4.0), $MachinePrecision] + N[(B$95$m * B$95$m), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / N[(N[(4.0 * N[(A * C), $MachinePrecision]), $MachinePrecision] - N[(B$95$m * B$95$m), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], If[LessEqual[N[Power[B$95$m, 2.0], $MachinePrecision], 5e-31], N[(N[(N[Sqrt[2.0], $MachinePrecision] / B$95$m), $MachinePrecision] * N[((-N[Sqrt[F], $MachinePrecision]) * N[Sqrt[N[(C + N[Sqrt[N[(B$95$m * B$95$m + N[(C * C), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision], If[LessEqual[N[Power[B$95$m, 2.0], $MachinePrecision], 1e+167], N[(N[Sqrt[N[(F * N[(-0.5 * N[(N[(B$95$m * B$95$m), $MachinePrecision] / A), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] * N[(N[Sqrt[2.0], $MachinePrecision] / (-B$95$m)), $MachinePrecision]), $MachinePrecision], (-N[(N[Sqrt[F], $MachinePrecision] / N[Sqrt[N[(B$95$m * 0.5), $MachinePrecision]], $MachinePrecision]), $MachinePrecision])]]]
                                                                                                      
                                                                                                      \begin{array}{l}
                                                                                                      B_m = \left|B\right|
                                                                                                      \\
                                                                                                      [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
                                                                                                      \\
                                                                                                      \begin{array}{l}
                                                                                                      \mathbf{if}\;{B\_m}^{2} \leq 10^{-132}:\\
                                                                                                      \;\;\;\;\frac{\sqrt{\left(2 \cdot C\right) \cdot \left(2 \cdot \left(F \cdot \mathsf{fma}\left(C, A \cdot -4, B\_m \cdot B\_m\right)\right)\right)}}{4 \cdot \left(A \cdot C\right) - B\_m \cdot B\_m}\\
                                                                                                      
                                                                                                      \mathbf{elif}\;{B\_m}^{2} \leq 5 \cdot 10^{-31}:\\
                                                                                                      \;\;\;\;\frac{\sqrt{2}}{B\_m} \cdot \left(\left(-\sqrt{F}\right) \cdot \sqrt{C + \sqrt{\mathsf{fma}\left(B\_m, B\_m, C \cdot C\right)}}\right)\\
                                                                                                      
                                                                                                      \mathbf{elif}\;{B\_m}^{2} \leq 10^{+167}:\\
                                                                                                      \;\;\;\;\sqrt{F \cdot \left(-0.5 \cdot \frac{B\_m \cdot B\_m}{A}\right)} \cdot \frac{\sqrt{2}}{-B\_m}\\
                                                                                                      
                                                                                                      \mathbf{else}:\\
                                                                                                      \;\;\;\;-\frac{\sqrt{F}}{\sqrt{B\_m \cdot 0.5}}\\
                                                                                                      
                                                                                                      
                                                                                                      \end{array}
                                                                                                      \end{array}
                                                                                                      
                                                                                                      Derivation
                                                                                                      1. Split input into 4 regimes
                                                                                                      2. if (pow.f64 B #s(literal 2 binary64)) < 9.9999999999999999e-133

                                                                                                        1. Initial program 22.9%

                                                                                                          \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                                                        2. Add Preprocessing
                                                                                                        3. Step-by-step derivation
                                                                                                          1. lift-sqrt.f64N/A

                                                                                                            \[\leadsto \frac{\mathsf{neg}\left(\color{blue}{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                                                          2. lift-*.f64N/A

                                                                                                            \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\color{blue}{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                                                          3. *-commutativeN/A

                                                                                                            \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\color{blue}{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right)}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                                                          4. lift-*.f64N/A

                                                                                                            \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \color{blue}{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right)}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                                                          5. lift-*.f64N/A

                                                                                                            \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \left(2 \cdot \color{blue}{\left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)}\right)}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                                                          6. associate-*r*N/A

                                                                                                            \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \color{blue}{\left(\left(2 \cdot \left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)\right) \cdot F\right)}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                                                          7. associate-*r*N/A

                                                                                                            \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\color{blue}{\left(\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \left(2 \cdot \left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)\right)\right) \cdot F}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                                                          8. sqrt-prodN/A

                                                                                                            \[\leadsto \frac{\mathsf{neg}\left(\color{blue}{\sqrt{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \left(2 \cdot \left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)\right)} \cdot \sqrt{F}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                                                          9. pow1/2N/A

                                                                                                            \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \left(2 \cdot \left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)\right)} \cdot \color{blue}{{F}^{\frac{1}{2}}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                                                        4. Applied rewrites13.2%

                                                                                                          \[\leadsto \frac{-\color{blue}{\sqrt{\left(\sqrt{\mathsf{fma}\left(A - C, A - C, B \cdot B\right)} + \left(A + C\right)\right) \cdot \left(2 \cdot \mathsf{fma}\left(B, B, -4 \cdot \left(A \cdot C\right)\right)\right)} \cdot \sqrt{F}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                                                        5. Taylor expanded in A around -inf

                                                                                                          \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\color{blue}{\left(2 \cdot C\right)} \cdot \left(2 \cdot \mathsf{fma}\left(B, B, -4 \cdot \left(A \cdot C\right)\right)\right)} \cdot \sqrt{F}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                                                        6. Step-by-step derivation
                                                                                                          1. lower-*.f6414.5

                                                                                                            \[\leadsto \frac{-\sqrt{\color{blue}{\left(2 \cdot C\right)} \cdot \left(2 \cdot \mathsf{fma}\left(B, B, -4 \cdot \left(A \cdot C\right)\right)\right)} \cdot \sqrt{F}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                                                        7. Applied rewrites14.5%

                                                                                                          \[\leadsto \frac{-\sqrt{\color{blue}{\left(2 \cdot C\right)} \cdot \left(2 \cdot \mathsf{fma}\left(B, B, -4 \cdot \left(A \cdot C\right)\right)\right)} \cdot \sqrt{F}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                                                        8. Applied rewrites17.7%

                                                                                                          \[\leadsto \color{blue}{\frac{\sqrt{\left(2 \cdot C\right) \cdot \left(2 \cdot \left(F \cdot \mathsf{fma}\left(C, A \cdot -4, B \cdot B\right)\right)\right)}}{4 \cdot \left(A \cdot C\right) - B \cdot B}} \]

                                                                                                        if 9.9999999999999999e-133 < (pow.f64 B #s(literal 2 binary64)) < 5e-31

                                                                                                        1. Initial program 48.3%

                                                                                                          \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                                                        2. Add Preprocessing
                                                                                                        3. Taylor expanded in A around -inf

                                                                                                          \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\left(\frac{-1}{2} \cdot \frac{{B}^{2}}{A} + 2 \cdot C\right)}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                                                        4. Step-by-step derivation
                                                                                                          1. +-commutativeN/A

                                                                                                            \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\left(2 \cdot C + \frac{-1}{2} \cdot \frac{{B}^{2}}{A}\right)}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                                                          2. lower-fma.f64N/A

                                                                                                            \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\mathsf{fma}\left(2, C, \frac{-1}{2} \cdot \frac{{B}^{2}}{A}\right)}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                                                          3. associate-*r/N/A

                                                                                                            \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(2, C, \color{blue}{\frac{\frac{-1}{2} \cdot {B}^{2}}{A}}\right)}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                                                          4. lower-/.f64N/A

                                                                                                            \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(2, C, \color{blue}{\frac{\frac{-1}{2} \cdot {B}^{2}}{A}}\right)}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                                                          5. lower-*.f64N/A

                                                                                                            \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(2, C, \frac{\color{blue}{\frac{-1}{2} \cdot {B}^{2}}}{A}\right)}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                                                          6. unpow2N/A

                                                                                                            \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(2, C, \frac{\frac{-1}{2} \cdot \color{blue}{\left(B \cdot B\right)}}{A}\right)}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                                                          7. lower-*.f648.1

                                                                                                            \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(2, C, \frac{-0.5 \cdot \color{blue}{\left(B \cdot B\right)}}{A}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                                                        5. Applied rewrites8.1%

                                                                                                          \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\mathsf{fma}\left(2, C, \frac{-0.5 \cdot \left(B \cdot B\right)}{A}\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                                                        6. Applied rewrites12.3%

                                                                                                          \[\leadsto \frac{-\color{blue}{\sqrt{\mathsf{fma}\left(2, C, \frac{\left(B \cdot B\right) \cdot -0.5}{A}\right) \cdot 2} \cdot \sqrt{F \cdot \mathsf{fma}\left(B, B, \left(-4 \cdot C\right) \cdot A\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                                                        7. Taylor expanded in A around 0

                                                                                                          \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right)} \]
                                                                                                        8. Step-by-step derivation
                                                                                                          1. mul-1-negN/A

                                                                                                            \[\leadsto \color{blue}{\mathsf{neg}\left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right)} \]
                                                                                                          2. lower-neg.f64N/A

                                                                                                            \[\leadsto \color{blue}{\mathsf{neg}\left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right)} \]
                                                                                                          3. lower-*.f64N/A

                                                                                                            \[\leadsto \mathsf{neg}\left(\color{blue}{\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}}\right) \]
                                                                                                          4. lower-/.f64N/A

                                                                                                            \[\leadsto \mathsf{neg}\left(\color{blue}{\frac{\sqrt{2}}{B}} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right) \]
                                                                                                          5. lower-sqrt.f64N/A

                                                                                                            \[\leadsto \mathsf{neg}\left(\frac{\color{blue}{\sqrt{2}}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right) \]
                                                                                                          6. lower-sqrt.f64N/A

                                                                                                            \[\leadsto \mathsf{neg}\left(\frac{\sqrt{2}}{B} \cdot \color{blue}{\sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}}\right) \]
                                                                                                          7. lower-*.f64N/A

                                                                                                            \[\leadsto \mathsf{neg}\left(\frac{\sqrt{2}}{B} \cdot \sqrt{\color{blue}{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}}\right) \]
                                                                                                          8. lower-+.f64N/A

                                                                                                            \[\leadsto \mathsf{neg}\left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}}\right) \]
                                                                                                          9. lower-sqrt.f64N/A

                                                                                                            \[\leadsto \mathsf{neg}\left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \color{blue}{\sqrt{{B}^{2} + {C}^{2}}}\right)}\right) \]
                                                                                                          10. unpow2N/A

                                                                                                            \[\leadsto \mathsf{neg}\left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{\color{blue}{B \cdot B} + {C}^{2}}\right)}\right) \]
                                                                                                          11. lower-fma.f64N/A

                                                                                                            \[\leadsto \mathsf{neg}\left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{\color{blue}{\mathsf{fma}\left(B, B, {C}^{2}\right)}}\right)}\right) \]
                                                                                                          12. unpow2N/A

                                                                                                            \[\leadsto \mathsf{neg}\left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{\mathsf{fma}\left(B, B, \color{blue}{C \cdot C}\right)}\right)}\right) \]
                                                                                                          13. lower-*.f6423.1

                                                                                                            \[\leadsto -\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{\mathsf{fma}\left(B, B, \color{blue}{C \cdot C}\right)}\right)} \]
                                                                                                        9. Applied rewrites23.1%

                                                                                                          \[\leadsto \color{blue}{-\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{\mathsf{fma}\left(B, B, C \cdot C\right)}\right)}} \]
                                                                                                        10. Step-by-step derivation
                                                                                                          1. Applied rewrites28.1%

                                                                                                            \[\leadsto -\frac{\sqrt{2}}{B} \cdot \left(\sqrt{C + \sqrt{\mathsf{fma}\left(B, B, C \cdot C\right)}} \cdot \sqrt{F}\right) \]

                                                                                                          if 5e-31 < (pow.f64 B #s(literal 2 binary64)) < 1e167

                                                                                                          1. Initial program 18.8%

                                                                                                            \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                                                          2. Add Preprocessing
                                                                                                          3. Taylor expanded in C around 0

                                                                                                            \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A + \sqrt{{A}^{2} + {B}^{2}}\right)}\right)} \]
                                                                                                          4. Step-by-step derivation
                                                                                                            1. mul-1-negN/A

                                                                                                              \[\leadsto \color{blue}{\mathsf{neg}\left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A + \sqrt{{A}^{2} + {B}^{2}}\right)}\right)} \]
                                                                                                            2. *-commutativeN/A

                                                                                                              \[\leadsto \mathsf{neg}\left(\color{blue}{\sqrt{F \cdot \left(A + \sqrt{{A}^{2} + {B}^{2}}\right)} \cdot \frac{\sqrt{2}}{B}}\right) \]
                                                                                                            3. distribute-rgt-neg-inN/A

                                                                                                              \[\leadsto \color{blue}{\sqrt{F \cdot \left(A + \sqrt{{A}^{2} + {B}^{2}}\right)} \cdot \left(\mathsf{neg}\left(\frac{\sqrt{2}}{B}\right)\right)} \]
                                                                                                            4. mul-1-negN/A

                                                                                                              \[\leadsto \sqrt{F \cdot \left(A + \sqrt{{A}^{2} + {B}^{2}}\right)} \cdot \color{blue}{\left(-1 \cdot \frac{\sqrt{2}}{B}\right)} \]
                                                                                                            5. lower-*.f64N/A

                                                                                                              \[\leadsto \color{blue}{\sqrt{F \cdot \left(A + \sqrt{{A}^{2} + {B}^{2}}\right)} \cdot \left(-1 \cdot \frac{\sqrt{2}}{B}\right)} \]
                                                                                                          5. Applied rewrites13.1%

                                                                                                            \[\leadsto \color{blue}{\sqrt{F \cdot \left(A + \sqrt{\mathsf{fma}\left(B, B, A \cdot A\right)}\right)} \cdot \left(-\frac{\sqrt{2}}{B}\right)} \]
                                                                                                          6. Taylor expanded in A around -inf

                                                                                                            \[\leadsto \sqrt{F \cdot \left(\frac{-1}{2} \cdot \frac{{B}^{2}}{A}\right)} \cdot \left(\mathsf{neg}\left(\frac{\sqrt{2}}{B}\right)\right) \]
                                                                                                          7. Step-by-step derivation
                                                                                                            1. Applied rewrites9.9%

                                                                                                              \[\leadsto \sqrt{F \cdot \left(-0.5 \cdot \frac{B \cdot B}{A}\right)} \cdot \left(-\frac{\sqrt{2}}{B}\right) \]

                                                                                                            if 1e167 < (pow.f64 B #s(literal 2 binary64))

                                                                                                            1. Initial program 6.2%

                                                                                                              \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                                                            2. Add Preprocessing
                                                                                                            3. Taylor expanded in B around inf

                                                                                                              \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                                                                                            4. Step-by-step derivation
                                                                                                              1. mul-1-negN/A

                                                                                                                \[\leadsto \color{blue}{\mathsf{neg}\left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                                                                                              2. lower-neg.f64N/A

                                                                                                                \[\leadsto \color{blue}{\mathsf{neg}\left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                                                                                              3. *-commutativeN/A

                                                                                                                \[\leadsto \mathsf{neg}\left(\color{blue}{\sqrt{2} \cdot \sqrt{\frac{F}{B}}}\right) \]
                                                                                                              4. lower-*.f64N/A

                                                                                                                \[\leadsto \mathsf{neg}\left(\color{blue}{\sqrt{2} \cdot \sqrt{\frac{F}{B}}}\right) \]
                                                                                                              5. lower-sqrt.f64N/A

                                                                                                                \[\leadsto \mathsf{neg}\left(\color{blue}{\sqrt{2}} \cdot \sqrt{\frac{F}{B}}\right) \]
                                                                                                              6. lower-sqrt.f64N/A

                                                                                                                \[\leadsto \mathsf{neg}\left(\sqrt{2} \cdot \color{blue}{\sqrt{\frac{F}{B}}}\right) \]
                                                                                                              7. lower-/.f6432.2

                                                                                                                \[\leadsto -\sqrt{2} \cdot \sqrt{\color{blue}{\frac{F}{B}}} \]
                                                                                                            5. Applied rewrites32.2%

                                                                                                              \[\leadsto \color{blue}{-\sqrt{2} \cdot \sqrt{\frac{F}{B}}} \]
                                                                                                            6. Step-by-step derivation
                                                                                                              1. Applied rewrites45.8%

                                                                                                                \[\leadsto -\frac{\sqrt{F \cdot 2}}{\sqrt{B}} \]
                                                                                                              2. Step-by-step derivation
                                                                                                                1. Applied rewrites45.8%

                                                                                                                  \[\leadsto -\sqrt{F} \cdot \sqrt{\frac{2}{B}} \]
                                                                                                                2. Step-by-step derivation
                                                                                                                  1. Applied rewrites45.9%

                                                                                                                    \[\leadsto -\frac{\sqrt{F}}{\sqrt{B \cdot 0.5}} \]
                                                                                                                3. Recombined 4 regimes into one program.
                                                                                                                4. Final simplification28.3%

                                                                                                                  \[\leadsto \begin{array}{l} \mathbf{if}\;{B}^{2} \leq 10^{-132}:\\ \;\;\;\;\frac{\sqrt{\left(2 \cdot C\right) \cdot \left(2 \cdot \left(F \cdot \mathsf{fma}\left(C, A \cdot -4, B \cdot B\right)\right)\right)}}{4 \cdot \left(A \cdot C\right) - B \cdot B}\\ \mathbf{elif}\;{B}^{2} \leq 5 \cdot 10^{-31}:\\ \;\;\;\;\frac{\sqrt{2}}{B} \cdot \left(\left(-\sqrt{F}\right) \cdot \sqrt{C + \sqrt{\mathsf{fma}\left(B, B, C \cdot C\right)}}\right)\\ \mathbf{elif}\;{B}^{2} \leq 10^{+167}:\\ \;\;\;\;\sqrt{F \cdot \left(-0.5 \cdot \frac{B \cdot B}{A}\right)} \cdot \frac{\sqrt{2}}{-B}\\ \mathbf{else}:\\ \;\;\;\;-\frac{\sqrt{F}}{\sqrt{B \cdot 0.5}}\\ \end{array} \]
                                                                                                                5. Add Preprocessing

                                                                                                                Alternative 18: 50.1% accurate, 1.3× speedup?

                                                                                                                \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} \mathbf{if}\;{B\_m}^{2} \leq 10^{-132}:\\ \;\;\;\;\frac{\sqrt{\left(2 \cdot C\right) \cdot \left(2 \cdot \left(F \cdot \mathsf{fma}\left(C, A \cdot -4, B\_m \cdot B\_m\right)\right)\right)}}{4 \cdot \left(A \cdot C\right) - B\_m \cdot B\_m}\\ \mathbf{elif}\;{B\_m}^{2} \leq 5 \cdot 10^{-31}:\\ \;\;\;\;\sqrt{2 \cdot \left(F \cdot \left(C + \sqrt{\mathsf{fma}\left(B\_m, B\_m, C \cdot C\right)}\right)\right)} \cdot \frac{-1}{B\_m}\\ \mathbf{elif}\;{B\_m}^{2} \leq 10^{+167}:\\ \;\;\;\;\sqrt{F \cdot \left(-0.5 \cdot \frac{B\_m \cdot B\_m}{A}\right)} \cdot \frac{\sqrt{2}}{-B\_m}\\ \mathbf{else}:\\ \;\;\;\;-\frac{\sqrt{F}}{\sqrt{B\_m \cdot 0.5}}\\ \end{array} \end{array} \]
                                                                                                                B_m = (fabs.f64 B)
                                                                                                                NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                                                                                (FPCore (A B_m C F)
                                                                                                                 :precision binary64
                                                                                                                 (if (<= (pow B_m 2.0) 1e-132)
                                                                                                                   (/
                                                                                                                    (sqrt (* (* 2.0 C) (* 2.0 (* F (fma C (* A -4.0) (* B_m B_m))))))
                                                                                                                    (- (* 4.0 (* A C)) (* B_m B_m)))
                                                                                                                   (if (<= (pow B_m 2.0) 5e-31)
                                                                                                                     (* (sqrt (* 2.0 (* F (+ C (sqrt (fma B_m B_m (* C C))))))) (/ -1.0 B_m))
                                                                                                                     (if (<= (pow B_m 2.0) 1e+167)
                                                                                                                       (* (sqrt (* F (* -0.5 (/ (* B_m B_m) A)))) (/ (sqrt 2.0) (- B_m)))
                                                                                                                       (- (/ (sqrt F) (sqrt (* B_m 0.5))))))))
                                                                                                                B_m = fabs(B);
                                                                                                                assert(A < B_m && B_m < C && C < F);
                                                                                                                double code(double A, double B_m, double C, double F) {
                                                                                                                	double tmp;
                                                                                                                	if (pow(B_m, 2.0) <= 1e-132) {
                                                                                                                		tmp = sqrt(((2.0 * C) * (2.0 * (F * fma(C, (A * -4.0), (B_m * B_m)))))) / ((4.0 * (A * C)) - (B_m * B_m));
                                                                                                                	} else if (pow(B_m, 2.0) <= 5e-31) {
                                                                                                                		tmp = sqrt((2.0 * (F * (C + sqrt(fma(B_m, B_m, (C * C))))))) * (-1.0 / B_m);
                                                                                                                	} else if (pow(B_m, 2.0) <= 1e+167) {
                                                                                                                		tmp = sqrt((F * (-0.5 * ((B_m * B_m) / A)))) * (sqrt(2.0) / -B_m);
                                                                                                                	} else {
                                                                                                                		tmp = -(sqrt(F) / sqrt((B_m * 0.5)));
                                                                                                                	}
                                                                                                                	return tmp;
                                                                                                                }
                                                                                                                
                                                                                                                B_m = abs(B)
                                                                                                                A, B_m, C, F = sort([A, B_m, C, F])
                                                                                                                function code(A, B_m, C, F)
                                                                                                                	tmp = 0.0
                                                                                                                	if ((B_m ^ 2.0) <= 1e-132)
                                                                                                                		tmp = Float64(sqrt(Float64(Float64(2.0 * C) * Float64(2.0 * Float64(F * fma(C, Float64(A * -4.0), Float64(B_m * B_m)))))) / Float64(Float64(4.0 * Float64(A * C)) - Float64(B_m * B_m)));
                                                                                                                	elseif ((B_m ^ 2.0) <= 5e-31)
                                                                                                                		tmp = Float64(sqrt(Float64(2.0 * Float64(F * Float64(C + sqrt(fma(B_m, B_m, Float64(C * C))))))) * Float64(-1.0 / B_m));
                                                                                                                	elseif ((B_m ^ 2.0) <= 1e+167)
                                                                                                                		tmp = Float64(sqrt(Float64(F * Float64(-0.5 * Float64(Float64(B_m * B_m) / A)))) * Float64(sqrt(2.0) / Float64(-B_m)));
                                                                                                                	else
                                                                                                                		tmp = Float64(-Float64(sqrt(F) / sqrt(Float64(B_m * 0.5))));
                                                                                                                	end
                                                                                                                	return tmp
                                                                                                                end
                                                                                                                
                                                                                                                B_m = N[Abs[B], $MachinePrecision]
                                                                                                                NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                                                                                code[A_, B$95$m_, C_, F_] := If[LessEqual[N[Power[B$95$m, 2.0], $MachinePrecision], 1e-132], N[(N[Sqrt[N[(N[(2.0 * C), $MachinePrecision] * N[(2.0 * N[(F * N[(C * N[(A * -4.0), $MachinePrecision] + N[(B$95$m * B$95$m), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / N[(N[(4.0 * N[(A * C), $MachinePrecision]), $MachinePrecision] - N[(B$95$m * B$95$m), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], If[LessEqual[N[Power[B$95$m, 2.0], $MachinePrecision], 5e-31], N[(N[Sqrt[N[(2.0 * N[(F * N[(C + N[Sqrt[N[(B$95$m * B$95$m + N[(C * C), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] * N[(-1.0 / B$95$m), $MachinePrecision]), $MachinePrecision], If[LessEqual[N[Power[B$95$m, 2.0], $MachinePrecision], 1e+167], N[(N[Sqrt[N[(F * N[(-0.5 * N[(N[(B$95$m * B$95$m), $MachinePrecision] / A), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] * N[(N[Sqrt[2.0], $MachinePrecision] / (-B$95$m)), $MachinePrecision]), $MachinePrecision], (-N[(N[Sqrt[F], $MachinePrecision] / N[Sqrt[N[(B$95$m * 0.5), $MachinePrecision]], $MachinePrecision]), $MachinePrecision])]]]
                                                                                                                
                                                                                                                \begin{array}{l}
                                                                                                                B_m = \left|B\right|
                                                                                                                \\
                                                                                                                [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
                                                                                                                \\
                                                                                                                \begin{array}{l}
                                                                                                                \mathbf{if}\;{B\_m}^{2} \leq 10^{-132}:\\
                                                                                                                \;\;\;\;\frac{\sqrt{\left(2 \cdot C\right) \cdot \left(2 \cdot \left(F \cdot \mathsf{fma}\left(C, A \cdot -4, B\_m \cdot B\_m\right)\right)\right)}}{4 \cdot \left(A \cdot C\right) - B\_m \cdot B\_m}\\
                                                                                                                
                                                                                                                \mathbf{elif}\;{B\_m}^{2} \leq 5 \cdot 10^{-31}:\\
                                                                                                                \;\;\;\;\sqrt{2 \cdot \left(F \cdot \left(C + \sqrt{\mathsf{fma}\left(B\_m, B\_m, C \cdot C\right)}\right)\right)} \cdot \frac{-1}{B\_m}\\
                                                                                                                
                                                                                                                \mathbf{elif}\;{B\_m}^{2} \leq 10^{+167}:\\
                                                                                                                \;\;\;\;\sqrt{F \cdot \left(-0.5 \cdot \frac{B\_m \cdot B\_m}{A}\right)} \cdot \frac{\sqrt{2}}{-B\_m}\\
                                                                                                                
                                                                                                                \mathbf{else}:\\
                                                                                                                \;\;\;\;-\frac{\sqrt{F}}{\sqrt{B\_m \cdot 0.5}}\\
                                                                                                                
                                                                                                                
                                                                                                                \end{array}
                                                                                                                \end{array}
                                                                                                                
                                                                                                                Derivation
                                                                                                                1. Split input into 4 regimes
                                                                                                                2. if (pow.f64 B #s(literal 2 binary64)) < 9.9999999999999999e-133

                                                                                                                  1. Initial program 22.9%

                                                                                                                    \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                                                                  2. Add Preprocessing
                                                                                                                  3. Step-by-step derivation
                                                                                                                    1. lift-sqrt.f64N/A

                                                                                                                      \[\leadsto \frac{\mathsf{neg}\left(\color{blue}{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                                                                    2. lift-*.f64N/A

                                                                                                                      \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\color{blue}{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                                                                    3. *-commutativeN/A

                                                                                                                      \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\color{blue}{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right)}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                                                                    4. lift-*.f64N/A

                                                                                                                      \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \color{blue}{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right)}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                                                                    5. lift-*.f64N/A

                                                                                                                      \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \left(2 \cdot \color{blue}{\left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)}\right)}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                                                                    6. associate-*r*N/A

                                                                                                                      \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \color{blue}{\left(\left(2 \cdot \left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)\right) \cdot F\right)}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                                                                    7. associate-*r*N/A

                                                                                                                      \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\color{blue}{\left(\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \left(2 \cdot \left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)\right)\right) \cdot F}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                                                                    8. sqrt-prodN/A

                                                                                                                      \[\leadsto \frac{\mathsf{neg}\left(\color{blue}{\sqrt{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \left(2 \cdot \left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)\right)} \cdot \sqrt{F}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                                                                    9. pow1/2N/A

                                                                                                                      \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \left(2 \cdot \left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)\right)} \cdot \color{blue}{{F}^{\frac{1}{2}}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                                                                  4. Applied rewrites13.2%

                                                                                                                    \[\leadsto \frac{-\color{blue}{\sqrt{\left(\sqrt{\mathsf{fma}\left(A - C, A - C, B \cdot B\right)} + \left(A + C\right)\right) \cdot \left(2 \cdot \mathsf{fma}\left(B, B, -4 \cdot \left(A \cdot C\right)\right)\right)} \cdot \sqrt{F}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                                                                  5. Taylor expanded in A around -inf

                                                                                                                    \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\color{blue}{\left(2 \cdot C\right)} \cdot \left(2 \cdot \mathsf{fma}\left(B, B, -4 \cdot \left(A \cdot C\right)\right)\right)} \cdot \sqrt{F}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                                                                  6. Step-by-step derivation
                                                                                                                    1. lower-*.f6414.5

                                                                                                                      \[\leadsto \frac{-\sqrt{\color{blue}{\left(2 \cdot C\right)} \cdot \left(2 \cdot \mathsf{fma}\left(B, B, -4 \cdot \left(A \cdot C\right)\right)\right)} \cdot \sqrt{F}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                                                                  7. Applied rewrites14.5%

                                                                                                                    \[\leadsto \frac{-\sqrt{\color{blue}{\left(2 \cdot C\right)} \cdot \left(2 \cdot \mathsf{fma}\left(B, B, -4 \cdot \left(A \cdot C\right)\right)\right)} \cdot \sqrt{F}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                                                                  8. Applied rewrites17.7%

                                                                                                                    \[\leadsto \color{blue}{\frac{\sqrt{\left(2 \cdot C\right) \cdot \left(2 \cdot \left(F \cdot \mathsf{fma}\left(C, A \cdot -4, B \cdot B\right)\right)\right)}}{4 \cdot \left(A \cdot C\right) - B \cdot B}} \]

                                                                                                                  if 9.9999999999999999e-133 < (pow.f64 B #s(literal 2 binary64)) < 5e-31

                                                                                                                  1. Initial program 48.3%

                                                                                                                    \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                                                                  2. Add Preprocessing
                                                                                                                  3. Taylor expanded in A around -inf

                                                                                                                    \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\left(\frac{-1}{2} \cdot \frac{{B}^{2}}{A} + 2 \cdot C\right)}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                                                                  4. Step-by-step derivation
                                                                                                                    1. +-commutativeN/A

                                                                                                                      \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\left(2 \cdot C + \frac{-1}{2} \cdot \frac{{B}^{2}}{A}\right)}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                                                                    2. lower-fma.f64N/A

                                                                                                                      \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\mathsf{fma}\left(2, C, \frac{-1}{2} \cdot \frac{{B}^{2}}{A}\right)}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                                                                    3. associate-*r/N/A

                                                                                                                      \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(2, C, \color{blue}{\frac{\frac{-1}{2} \cdot {B}^{2}}{A}}\right)}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                                                                    4. lower-/.f64N/A

                                                                                                                      \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(2, C, \color{blue}{\frac{\frac{-1}{2} \cdot {B}^{2}}{A}}\right)}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                                                                    5. lower-*.f64N/A

                                                                                                                      \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(2, C, \frac{\color{blue}{\frac{-1}{2} \cdot {B}^{2}}}{A}\right)}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                                                                    6. unpow2N/A

                                                                                                                      \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(2, C, \frac{\frac{-1}{2} \cdot \color{blue}{\left(B \cdot B\right)}}{A}\right)}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                                                                    7. lower-*.f648.1

                                                                                                                      \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(2, C, \frac{-0.5 \cdot \color{blue}{\left(B \cdot B\right)}}{A}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                                                                  5. Applied rewrites8.1%

                                                                                                                    \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\mathsf{fma}\left(2, C, \frac{-0.5 \cdot \left(B \cdot B\right)}{A}\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                                                                  6. Applied rewrites12.3%

                                                                                                                    \[\leadsto \frac{-\color{blue}{\sqrt{\mathsf{fma}\left(2, C, \frac{\left(B \cdot B\right) \cdot -0.5}{A}\right) \cdot 2} \cdot \sqrt{F \cdot \mathsf{fma}\left(B, B, \left(-4 \cdot C\right) \cdot A\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                                                                  7. Taylor expanded in A around 0

                                                                                                                    \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right)} \]
                                                                                                                  8. Step-by-step derivation
                                                                                                                    1. mul-1-negN/A

                                                                                                                      \[\leadsto \color{blue}{\mathsf{neg}\left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right)} \]
                                                                                                                    2. lower-neg.f64N/A

                                                                                                                      \[\leadsto \color{blue}{\mathsf{neg}\left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right)} \]
                                                                                                                    3. lower-*.f64N/A

                                                                                                                      \[\leadsto \mathsf{neg}\left(\color{blue}{\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}}\right) \]
                                                                                                                    4. lower-/.f64N/A

                                                                                                                      \[\leadsto \mathsf{neg}\left(\color{blue}{\frac{\sqrt{2}}{B}} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right) \]
                                                                                                                    5. lower-sqrt.f64N/A

                                                                                                                      \[\leadsto \mathsf{neg}\left(\frac{\color{blue}{\sqrt{2}}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right) \]
                                                                                                                    6. lower-sqrt.f64N/A

                                                                                                                      \[\leadsto \mathsf{neg}\left(\frac{\sqrt{2}}{B} \cdot \color{blue}{\sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}}\right) \]
                                                                                                                    7. lower-*.f64N/A

                                                                                                                      \[\leadsto \mathsf{neg}\left(\frac{\sqrt{2}}{B} \cdot \sqrt{\color{blue}{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}}\right) \]
                                                                                                                    8. lower-+.f64N/A

                                                                                                                      \[\leadsto \mathsf{neg}\left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}}\right) \]
                                                                                                                    9. lower-sqrt.f64N/A

                                                                                                                      \[\leadsto \mathsf{neg}\left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \color{blue}{\sqrt{{B}^{2} + {C}^{2}}}\right)}\right) \]
                                                                                                                    10. unpow2N/A

                                                                                                                      \[\leadsto \mathsf{neg}\left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{\color{blue}{B \cdot B} + {C}^{2}}\right)}\right) \]
                                                                                                                    11. lower-fma.f64N/A

                                                                                                                      \[\leadsto \mathsf{neg}\left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{\color{blue}{\mathsf{fma}\left(B, B, {C}^{2}\right)}}\right)}\right) \]
                                                                                                                    12. unpow2N/A

                                                                                                                      \[\leadsto \mathsf{neg}\left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{\mathsf{fma}\left(B, B, \color{blue}{C \cdot C}\right)}\right)}\right) \]
                                                                                                                    13. lower-*.f6423.1

                                                                                                                      \[\leadsto -\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{\mathsf{fma}\left(B, B, \color{blue}{C \cdot C}\right)}\right)} \]
                                                                                                                  9. Applied rewrites23.1%

                                                                                                                    \[\leadsto \color{blue}{-\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{\mathsf{fma}\left(B, B, C \cdot C\right)}\right)}} \]
                                                                                                                  10. Step-by-step derivation
                                                                                                                    1. Applied rewrites23.4%

                                                                                                                      \[\leadsto -\sqrt{2 \cdot \left(F \cdot \left(C + \sqrt{\mathsf{fma}\left(B, B, C \cdot C\right)}\right)\right)} \cdot \frac{1}{B} \]

                                                                                                                    if 5e-31 < (pow.f64 B #s(literal 2 binary64)) < 1e167

                                                                                                                    1. Initial program 18.8%

                                                                                                                      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                                                                    2. Add Preprocessing
                                                                                                                    3. Taylor expanded in C around 0

                                                                                                                      \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A + \sqrt{{A}^{2} + {B}^{2}}\right)}\right)} \]
                                                                                                                    4. Step-by-step derivation
                                                                                                                      1. mul-1-negN/A

                                                                                                                        \[\leadsto \color{blue}{\mathsf{neg}\left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A + \sqrt{{A}^{2} + {B}^{2}}\right)}\right)} \]
                                                                                                                      2. *-commutativeN/A

                                                                                                                        \[\leadsto \mathsf{neg}\left(\color{blue}{\sqrt{F \cdot \left(A + \sqrt{{A}^{2} + {B}^{2}}\right)} \cdot \frac{\sqrt{2}}{B}}\right) \]
                                                                                                                      3. distribute-rgt-neg-inN/A

                                                                                                                        \[\leadsto \color{blue}{\sqrt{F \cdot \left(A + \sqrt{{A}^{2} + {B}^{2}}\right)} \cdot \left(\mathsf{neg}\left(\frac{\sqrt{2}}{B}\right)\right)} \]
                                                                                                                      4. mul-1-negN/A

                                                                                                                        \[\leadsto \sqrt{F \cdot \left(A + \sqrt{{A}^{2} + {B}^{2}}\right)} \cdot \color{blue}{\left(-1 \cdot \frac{\sqrt{2}}{B}\right)} \]
                                                                                                                      5. lower-*.f64N/A

                                                                                                                        \[\leadsto \color{blue}{\sqrt{F \cdot \left(A + \sqrt{{A}^{2} + {B}^{2}}\right)} \cdot \left(-1 \cdot \frac{\sqrt{2}}{B}\right)} \]
                                                                                                                    5. Applied rewrites13.1%

                                                                                                                      \[\leadsto \color{blue}{\sqrt{F \cdot \left(A + \sqrt{\mathsf{fma}\left(B, B, A \cdot A\right)}\right)} \cdot \left(-\frac{\sqrt{2}}{B}\right)} \]
                                                                                                                    6. Taylor expanded in A around -inf

                                                                                                                      \[\leadsto \sqrt{F \cdot \left(\frac{-1}{2} \cdot \frac{{B}^{2}}{A}\right)} \cdot \left(\mathsf{neg}\left(\frac{\sqrt{2}}{B}\right)\right) \]
                                                                                                                    7. Step-by-step derivation
                                                                                                                      1. Applied rewrites9.9%

                                                                                                                        \[\leadsto \sqrt{F \cdot \left(-0.5 \cdot \frac{B \cdot B}{A}\right)} \cdot \left(-\frac{\sqrt{2}}{B}\right) \]

                                                                                                                      if 1e167 < (pow.f64 B #s(literal 2 binary64))

                                                                                                                      1. Initial program 6.2%

                                                                                                                        \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                                                                      2. Add Preprocessing
                                                                                                                      3. Taylor expanded in B around inf

                                                                                                                        \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                                                                                                      4. Step-by-step derivation
                                                                                                                        1. mul-1-negN/A

                                                                                                                          \[\leadsto \color{blue}{\mathsf{neg}\left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                                                                                                        2. lower-neg.f64N/A

                                                                                                                          \[\leadsto \color{blue}{\mathsf{neg}\left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                                                                                                        3. *-commutativeN/A

                                                                                                                          \[\leadsto \mathsf{neg}\left(\color{blue}{\sqrt{2} \cdot \sqrt{\frac{F}{B}}}\right) \]
                                                                                                                        4. lower-*.f64N/A

                                                                                                                          \[\leadsto \mathsf{neg}\left(\color{blue}{\sqrt{2} \cdot \sqrt{\frac{F}{B}}}\right) \]
                                                                                                                        5. lower-sqrt.f64N/A

                                                                                                                          \[\leadsto \mathsf{neg}\left(\color{blue}{\sqrt{2}} \cdot \sqrt{\frac{F}{B}}\right) \]
                                                                                                                        6. lower-sqrt.f64N/A

                                                                                                                          \[\leadsto \mathsf{neg}\left(\sqrt{2} \cdot \color{blue}{\sqrt{\frac{F}{B}}}\right) \]
                                                                                                                        7. lower-/.f6432.2

                                                                                                                          \[\leadsto -\sqrt{2} \cdot \sqrt{\color{blue}{\frac{F}{B}}} \]
                                                                                                                      5. Applied rewrites32.2%

                                                                                                                        \[\leadsto \color{blue}{-\sqrt{2} \cdot \sqrt{\frac{F}{B}}} \]
                                                                                                                      6. Step-by-step derivation
                                                                                                                        1. Applied rewrites45.8%

                                                                                                                          \[\leadsto -\frac{\sqrt{F \cdot 2}}{\sqrt{B}} \]
                                                                                                                        2. Step-by-step derivation
                                                                                                                          1. Applied rewrites45.8%

                                                                                                                            \[\leadsto -\sqrt{F} \cdot \sqrt{\frac{2}{B}} \]
                                                                                                                          2. Step-by-step derivation
                                                                                                                            1. Applied rewrites45.9%

                                                                                                                              \[\leadsto -\frac{\sqrt{F}}{\sqrt{B \cdot 0.5}} \]
                                                                                                                          3. Recombined 4 regimes into one program.
                                                                                                                          4. Final simplification27.9%

                                                                                                                            \[\leadsto \begin{array}{l} \mathbf{if}\;{B}^{2} \leq 10^{-132}:\\ \;\;\;\;\frac{\sqrt{\left(2 \cdot C\right) \cdot \left(2 \cdot \left(F \cdot \mathsf{fma}\left(C, A \cdot -4, B \cdot B\right)\right)\right)}}{4 \cdot \left(A \cdot C\right) - B \cdot B}\\ \mathbf{elif}\;{B}^{2} \leq 5 \cdot 10^{-31}:\\ \;\;\;\;\sqrt{2 \cdot \left(F \cdot \left(C + \sqrt{\mathsf{fma}\left(B, B, C \cdot C\right)}\right)\right)} \cdot \frac{-1}{B}\\ \mathbf{elif}\;{B}^{2} \leq 10^{+167}:\\ \;\;\;\;\sqrt{F \cdot \left(-0.5 \cdot \frac{B \cdot B}{A}\right)} \cdot \frac{\sqrt{2}}{-B}\\ \mathbf{else}:\\ \;\;\;\;-\frac{\sqrt{F}}{\sqrt{B \cdot 0.5}}\\ \end{array} \]
                                                                                                                          5. Add Preprocessing

                                                                                                                          Alternative 19: 36.8% accurate, 2.9× speedup?

                                                                                                                          \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} \mathbf{if}\;{B\_m}^{2} \leq 5 \cdot 10^{+79}:\\ \;\;\;\;\sqrt{2 \cdot \left(F \cdot \left(C + \sqrt{\mathsf{fma}\left(B\_m, B\_m, C \cdot C\right)}\right)\right)} \cdot \frac{-1}{B\_m}\\ \mathbf{else}:\\ \;\;\;\;-\frac{\sqrt{F}}{\sqrt{B\_m \cdot 0.5}}\\ \end{array} \end{array} \]
                                                                                                                          B_m = (fabs.f64 B)
                                                                                                                          NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                                                                                          (FPCore (A B_m C F)
                                                                                                                           :precision binary64
                                                                                                                           (if (<= (pow B_m 2.0) 5e+79)
                                                                                                                             (* (sqrt (* 2.0 (* F (+ C (sqrt (fma B_m B_m (* C C))))))) (/ -1.0 B_m))
                                                                                                                             (- (/ (sqrt F) (sqrt (* B_m 0.5))))))
                                                                                                                          B_m = fabs(B);
                                                                                                                          assert(A < B_m && B_m < C && C < F);
                                                                                                                          double code(double A, double B_m, double C, double F) {
                                                                                                                          	double tmp;
                                                                                                                          	if (pow(B_m, 2.0) <= 5e+79) {
                                                                                                                          		tmp = sqrt((2.0 * (F * (C + sqrt(fma(B_m, B_m, (C * C))))))) * (-1.0 / B_m);
                                                                                                                          	} else {
                                                                                                                          		tmp = -(sqrt(F) / sqrt((B_m * 0.5)));
                                                                                                                          	}
                                                                                                                          	return tmp;
                                                                                                                          }
                                                                                                                          
                                                                                                                          B_m = abs(B)
                                                                                                                          A, B_m, C, F = sort([A, B_m, C, F])
                                                                                                                          function code(A, B_m, C, F)
                                                                                                                          	tmp = 0.0
                                                                                                                          	if ((B_m ^ 2.0) <= 5e+79)
                                                                                                                          		tmp = Float64(sqrt(Float64(2.0 * Float64(F * Float64(C + sqrt(fma(B_m, B_m, Float64(C * C))))))) * Float64(-1.0 / B_m));
                                                                                                                          	else
                                                                                                                          		tmp = Float64(-Float64(sqrt(F) / sqrt(Float64(B_m * 0.5))));
                                                                                                                          	end
                                                                                                                          	return tmp
                                                                                                                          end
                                                                                                                          
                                                                                                                          B_m = N[Abs[B], $MachinePrecision]
                                                                                                                          NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                                                                                          code[A_, B$95$m_, C_, F_] := If[LessEqual[N[Power[B$95$m, 2.0], $MachinePrecision], 5e+79], N[(N[Sqrt[N[(2.0 * N[(F * N[(C + N[Sqrt[N[(B$95$m * B$95$m + N[(C * C), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] * N[(-1.0 / B$95$m), $MachinePrecision]), $MachinePrecision], (-N[(N[Sqrt[F], $MachinePrecision] / N[Sqrt[N[(B$95$m * 0.5), $MachinePrecision]], $MachinePrecision]), $MachinePrecision])]
                                                                                                                          
                                                                                                                          \begin{array}{l}
                                                                                                                          B_m = \left|B\right|
                                                                                                                          \\
                                                                                                                          [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
                                                                                                                          \\
                                                                                                                          \begin{array}{l}
                                                                                                                          \mathbf{if}\;{B\_m}^{2} \leq 5 \cdot 10^{+79}:\\
                                                                                                                          \;\;\;\;\sqrt{2 \cdot \left(F \cdot \left(C + \sqrt{\mathsf{fma}\left(B\_m, B\_m, C \cdot C\right)}\right)\right)} \cdot \frac{-1}{B\_m}\\
                                                                                                                          
                                                                                                                          \mathbf{else}:\\
                                                                                                                          \;\;\;\;-\frac{\sqrt{F}}{\sqrt{B\_m \cdot 0.5}}\\
                                                                                                                          
                                                                                                                          
                                                                                                                          \end{array}
                                                                                                                          \end{array}
                                                                                                                          
                                                                                                                          Derivation
                                                                                                                          1. Split input into 2 regimes
                                                                                                                          2. if (pow.f64 B #s(literal 2 binary64)) < 5e79

                                                                                                                            1. Initial program 27.4%

                                                                                                                              \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                                                                            2. Add Preprocessing
                                                                                                                            3. Taylor expanded in A around -inf

                                                                                                                              \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\left(\frac{-1}{2} \cdot \frac{{B}^{2}}{A} + 2 \cdot C\right)}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                                                                            4. Step-by-step derivation
                                                                                                                              1. +-commutativeN/A

                                                                                                                                \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\left(2 \cdot C + \frac{-1}{2} \cdot \frac{{B}^{2}}{A}\right)}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                                                                              2. lower-fma.f64N/A

                                                                                                                                \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\mathsf{fma}\left(2, C, \frac{-1}{2} \cdot \frac{{B}^{2}}{A}\right)}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                                                                              3. associate-*r/N/A

                                                                                                                                \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(2, C, \color{blue}{\frac{\frac{-1}{2} \cdot {B}^{2}}{A}}\right)}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                                                                              4. lower-/.f64N/A

                                                                                                                                \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(2, C, \color{blue}{\frac{\frac{-1}{2} \cdot {B}^{2}}{A}}\right)}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                                                                              5. lower-*.f64N/A

                                                                                                                                \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(2, C, \frac{\color{blue}{\frac{-1}{2} \cdot {B}^{2}}}{A}\right)}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                                                                              6. unpow2N/A

                                                                                                                                \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(2, C, \frac{\frac{-1}{2} \cdot \color{blue}{\left(B \cdot B\right)}}{A}\right)}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                                                                              7. lower-*.f6416.9

                                                                                                                                \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(2, C, \frac{-0.5 \cdot \color{blue}{\left(B \cdot B\right)}}{A}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                                                                            5. Applied rewrites16.9%

                                                                                                                              \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\mathsf{fma}\left(2, C, \frac{-0.5 \cdot \left(B \cdot B\right)}{A}\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                                                                            6. Applied rewrites16.0%

                                                                                                                              \[\leadsto \frac{-\color{blue}{\sqrt{\mathsf{fma}\left(2, C, \frac{\left(B \cdot B\right) \cdot -0.5}{A}\right) \cdot 2} \cdot \sqrt{F \cdot \mathsf{fma}\left(B, B, \left(-4 \cdot C\right) \cdot A\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                                                                            7. Taylor expanded in A around 0

                                                                                                                              \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right)} \]
                                                                                                                            8. Step-by-step derivation
                                                                                                                              1. mul-1-negN/A

                                                                                                                                \[\leadsto \color{blue}{\mathsf{neg}\left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right)} \]
                                                                                                                              2. lower-neg.f64N/A

                                                                                                                                \[\leadsto \color{blue}{\mathsf{neg}\left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right)} \]
                                                                                                                              3. lower-*.f64N/A

                                                                                                                                \[\leadsto \mathsf{neg}\left(\color{blue}{\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}}\right) \]
                                                                                                                              4. lower-/.f64N/A

                                                                                                                                \[\leadsto \mathsf{neg}\left(\color{blue}{\frac{\sqrt{2}}{B}} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right) \]
                                                                                                                              5. lower-sqrt.f64N/A

                                                                                                                                \[\leadsto \mathsf{neg}\left(\frac{\color{blue}{\sqrt{2}}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right) \]
                                                                                                                              6. lower-sqrt.f64N/A

                                                                                                                                \[\leadsto \mathsf{neg}\left(\frac{\sqrt{2}}{B} \cdot \color{blue}{\sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}}\right) \]
                                                                                                                              7. lower-*.f64N/A

                                                                                                                                \[\leadsto \mathsf{neg}\left(\frac{\sqrt{2}}{B} \cdot \sqrt{\color{blue}{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}}\right) \]
                                                                                                                              8. lower-+.f64N/A

                                                                                                                                \[\leadsto \mathsf{neg}\left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}}\right) \]
                                                                                                                              9. lower-sqrt.f64N/A

                                                                                                                                \[\leadsto \mathsf{neg}\left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \color{blue}{\sqrt{{B}^{2} + {C}^{2}}}\right)}\right) \]
                                                                                                                              10. unpow2N/A

                                                                                                                                \[\leadsto \mathsf{neg}\left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{\color{blue}{B \cdot B} + {C}^{2}}\right)}\right) \]
                                                                                                                              11. lower-fma.f64N/A

                                                                                                                                \[\leadsto \mathsf{neg}\left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{\color{blue}{\mathsf{fma}\left(B, B, {C}^{2}\right)}}\right)}\right) \]
                                                                                                                              12. unpow2N/A

                                                                                                                                \[\leadsto \mathsf{neg}\left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{\mathsf{fma}\left(B, B, \color{blue}{C \cdot C}\right)}\right)}\right) \]
                                                                                                                              13. lower-*.f6410.0

                                                                                                                                \[\leadsto -\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{\mathsf{fma}\left(B, B, \color{blue}{C \cdot C}\right)}\right)} \]
                                                                                                                            9. Applied rewrites10.0%

                                                                                                                              \[\leadsto \color{blue}{-\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{\mathsf{fma}\left(B, B, C \cdot C\right)}\right)}} \]
                                                                                                                            10. Step-by-step derivation
                                                                                                                              1. Applied rewrites10.0%

                                                                                                                                \[\leadsto -\sqrt{2 \cdot \left(F \cdot \left(C + \sqrt{\mathsf{fma}\left(B, B, C \cdot C\right)}\right)\right)} \cdot \frac{1}{B} \]

                                                                                                                              if 5e79 < (pow.f64 B #s(literal 2 binary64))

                                                                                                                              1. Initial program 6.4%

                                                                                                                                \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                                                                              2. Add Preprocessing
                                                                                                                              3. Taylor expanded in B around inf

                                                                                                                                \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                                                                                                              4. Step-by-step derivation
                                                                                                                                1. mul-1-negN/A

                                                                                                                                  \[\leadsto \color{blue}{\mathsf{neg}\left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                                                                                                                2. lower-neg.f64N/A

                                                                                                                                  \[\leadsto \color{blue}{\mathsf{neg}\left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                                                                                                                3. *-commutativeN/A

                                                                                                                                  \[\leadsto \mathsf{neg}\left(\color{blue}{\sqrt{2} \cdot \sqrt{\frac{F}{B}}}\right) \]
                                                                                                                                4. lower-*.f64N/A

                                                                                                                                  \[\leadsto \mathsf{neg}\left(\color{blue}{\sqrt{2} \cdot \sqrt{\frac{F}{B}}}\right) \]
                                                                                                                                5. lower-sqrt.f64N/A

                                                                                                                                  \[\leadsto \mathsf{neg}\left(\color{blue}{\sqrt{2}} \cdot \sqrt{\frac{F}{B}}\right) \]
                                                                                                                                6. lower-sqrt.f64N/A

                                                                                                                                  \[\leadsto \mathsf{neg}\left(\sqrt{2} \cdot \color{blue}{\sqrt{\frac{F}{B}}}\right) \]
                                                                                                                                7. lower-/.f6428.9

                                                                                                                                  \[\leadsto -\sqrt{2} \cdot \sqrt{\color{blue}{\frac{F}{B}}} \]
                                                                                                                              5. Applied rewrites28.9%

                                                                                                                                \[\leadsto \color{blue}{-\sqrt{2} \cdot \sqrt{\frac{F}{B}}} \]
                                                                                                                              6. Step-by-step derivation
                                                                                                                                1. Applied rewrites40.1%

                                                                                                                                  \[\leadsto -\frac{\sqrt{F \cdot 2}}{\sqrt{B}} \]
                                                                                                                                2. Step-by-step derivation
                                                                                                                                  1. Applied rewrites40.1%

                                                                                                                                    \[\leadsto -\sqrt{F} \cdot \sqrt{\frac{2}{B}} \]
                                                                                                                                  2. Step-by-step derivation
                                                                                                                                    1. Applied rewrites40.2%

                                                                                                                                      \[\leadsto -\frac{\sqrt{F}}{\sqrt{B \cdot 0.5}} \]
                                                                                                                                  3. Recombined 2 regimes into one program.
                                                                                                                                  4. Final simplification24.4%

                                                                                                                                    \[\leadsto \begin{array}{l} \mathbf{if}\;{B}^{2} \leq 5 \cdot 10^{+79}:\\ \;\;\;\;\sqrt{2 \cdot \left(F \cdot \left(C + \sqrt{\mathsf{fma}\left(B, B, C \cdot C\right)}\right)\right)} \cdot \frac{-1}{B}\\ \mathbf{else}:\\ \;\;\;\;-\frac{\sqrt{F}}{\sqrt{B \cdot 0.5}}\\ \end{array} \]
                                                                                                                                  5. Add Preprocessing

                                                                                                                                  Alternative 20: 37.0% accurate, 3.0× speedup?

                                                                                                                                  \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} \mathbf{if}\;{B\_m}^{2} \leq 10^{+114}:\\ \;\;\;\;\frac{\sqrt{2 \cdot \left(F \cdot \left(C + \sqrt{\mathsf{fma}\left(B\_m, B\_m, C \cdot C\right)}\right)\right)}}{-B\_m}\\ \mathbf{else}:\\ \;\;\;\;-\frac{\sqrt{F}}{\sqrt{B\_m \cdot 0.5}}\\ \end{array} \end{array} \]
                                                                                                                                  B_m = (fabs.f64 B)
                                                                                                                                  NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                                                                                                  (FPCore (A B_m C F)
                                                                                                                                   :precision binary64
                                                                                                                                   (if (<= (pow B_m 2.0) 1e+114)
                                                                                                                                     (/ (sqrt (* 2.0 (* F (+ C (sqrt (fma B_m B_m (* C C))))))) (- B_m))
                                                                                                                                     (- (/ (sqrt F) (sqrt (* B_m 0.5))))))
                                                                                                                                  B_m = fabs(B);
                                                                                                                                  assert(A < B_m && B_m < C && C < F);
                                                                                                                                  double code(double A, double B_m, double C, double F) {
                                                                                                                                  	double tmp;
                                                                                                                                  	if (pow(B_m, 2.0) <= 1e+114) {
                                                                                                                                  		tmp = sqrt((2.0 * (F * (C + sqrt(fma(B_m, B_m, (C * C))))))) / -B_m;
                                                                                                                                  	} else {
                                                                                                                                  		tmp = -(sqrt(F) / sqrt((B_m * 0.5)));
                                                                                                                                  	}
                                                                                                                                  	return tmp;
                                                                                                                                  }
                                                                                                                                  
                                                                                                                                  B_m = abs(B)
                                                                                                                                  A, B_m, C, F = sort([A, B_m, C, F])
                                                                                                                                  function code(A, B_m, C, F)
                                                                                                                                  	tmp = 0.0
                                                                                                                                  	if ((B_m ^ 2.0) <= 1e+114)
                                                                                                                                  		tmp = Float64(sqrt(Float64(2.0 * Float64(F * Float64(C + sqrt(fma(B_m, B_m, Float64(C * C))))))) / Float64(-B_m));
                                                                                                                                  	else
                                                                                                                                  		tmp = Float64(-Float64(sqrt(F) / sqrt(Float64(B_m * 0.5))));
                                                                                                                                  	end
                                                                                                                                  	return tmp
                                                                                                                                  end
                                                                                                                                  
                                                                                                                                  B_m = N[Abs[B], $MachinePrecision]
                                                                                                                                  NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                                                                                                  code[A_, B$95$m_, C_, F_] := If[LessEqual[N[Power[B$95$m, 2.0], $MachinePrecision], 1e+114], N[(N[Sqrt[N[(2.0 * N[(F * N[(C + N[Sqrt[N[(B$95$m * B$95$m + N[(C * C), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / (-B$95$m)), $MachinePrecision], (-N[(N[Sqrt[F], $MachinePrecision] / N[Sqrt[N[(B$95$m * 0.5), $MachinePrecision]], $MachinePrecision]), $MachinePrecision])]
                                                                                                                                  
                                                                                                                                  \begin{array}{l}
                                                                                                                                  B_m = \left|B\right|
                                                                                                                                  \\
                                                                                                                                  [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
                                                                                                                                  \\
                                                                                                                                  \begin{array}{l}
                                                                                                                                  \mathbf{if}\;{B\_m}^{2} \leq 10^{+114}:\\
                                                                                                                                  \;\;\;\;\frac{\sqrt{2 \cdot \left(F \cdot \left(C + \sqrt{\mathsf{fma}\left(B\_m, B\_m, C \cdot C\right)}\right)\right)}}{-B\_m}\\
                                                                                                                                  
                                                                                                                                  \mathbf{else}:\\
                                                                                                                                  \;\;\;\;-\frac{\sqrt{F}}{\sqrt{B\_m \cdot 0.5}}\\
                                                                                                                                  
                                                                                                                                  
                                                                                                                                  \end{array}
                                                                                                                                  \end{array}
                                                                                                                                  
                                                                                                                                  Derivation
                                                                                                                                  1. Split input into 2 regimes
                                                                                                                                  2. if (pow.f64 B #s(literal 2 binary64)) < 1e114

                                                                                                                                    1. Initial program 26.5%

                                                                                                                                      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                                                                                    2. Add Preprocessing
                                                                                                                                    3. Taylor expanded in A around -inf

                                                                                                                                      \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\left(\frac{-1}{2} \cdot \frac{{B}^{2}}{A} + 2 \cdot C\right)}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                                                                                    4. Step-by-step derivation
                                                                                                                                      1. +-commutativeN/A

                                                                                                                                        \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\left(2 \cdot C + \frac{-1}{2} \cdot \frac{{B}^{2}}{A}\right)}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                                                                                      2. lower-fma.f64N/A

                                                                                                                                        \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\mathsf{fma}\left(2, C, \frac{-1}{2} \cdot \frac{{B}^{2}}{A}\right)}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                                                                                      3. associate-*r/N/A

                                                                                                                                        \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(2, C, \color{blue}{\frac{\frac{-1}{2} \cdot {B}^{2}}{A}}\right)}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                                                                                      4. lower-/.f64N/A

                                                                                                                                        \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(2, C, \color{blue}{\frac{\frac{-1}{2} \cdot {B}^{2}}{A}}\right)}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                                                                                      5. lower-*.f64N/A

                                                                                                                                        \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(2, C, \frac{\color{blue}{\frac{-1}{2} \cdot {B}^{2}}}{A}\right)}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                                                                                      6. unpow2N/A

                                                                                                                                        \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(2, C, \frac{\frac{-1}{2} \cdot \color{blue}{\left(B \cdot B\right)}}{A}\right)}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                                                                                      7. lower-*.f6417.5

                                                                                                                                        \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(2, C, \frac{-0.5 \cdot \color{blue}{\left(B \cdot B\right)}}{A}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                                                                                    5. Applied rewrites17.5%

                                                                                                                                      \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\mathsf{fma}\left(2, C, \frac{-0.5 \cdot \left(B \cdot B\right)}{A}\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                                                                                    6. Applied rewrites16.6%

                                                                                                                                      \[\leadsto \frac{-\color{blue}{\sqrt{\mathsf{fma}\left(2, C, \frac{\left(B \cdot B\right) \cdot -0.5}{A}\right) \cdot 2} \cdot \sqrt{F \cdot \mathsf{fma}\left(B, B, \left(-4 \cdot C\right) \cdot A\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                                                                                    7. Taylor expanded in A around 0

                                                                                                                                      \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right)} \]
                                                                                                                                    8. Step-by-step derivation
                                                                                                                                      1. mul-1-negN/A

                                                                                                                                        \[\leadsto \color{blue}{\mathsf{neg}\left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right)} \]
                                                                                                                                      2. lower-neg.f64N/A

                                                                                                                                        \[\leadsto \color{blue}{\mathsf{neg}\left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right)} \]
                                                                                                                                      3. lower-*.f64N/A

                                                                                                                                        \[\leadsto \mathsf{neg}\left(\color{blue}{\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}}\right) \]
                                                                                                                                      4. lower-/.f64N/A

                                                                                                                                        \[\leadsto \mathsf{neg}\left(\color{blue}{\frac{\sqrt{2}}{B}} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right) \]
                                                                                                                                      5. lower-sqrt.f64N/A

                                                                                                                                        \[\leadsto \mathsf{neg}\left(\frac{\color{blue}{\sqrt{2}}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right) \]
                                                                                                                                      6. lower-sqrt.f64N/A

                                                                                                                                        \[\leadsto \mathsf{neg}\left(\frac{\sqrt{2}}{B} \cdot \color{blue}{\sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}}\right) \]
                                                                                                                                      7. lower-*.f64N/A

                                                                                                                                        \[\leadsto \mathsf{neg}\left(\frac{\sqrt{2}}{B} \cdot \sqrt{\color{blue}{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}}\right) \]
                                                                                                                                      8. lower-+.f64N/A

                                                                                                                                        \[\leadsto \mathsf{neg}\left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}}\right) \]
                                                                                                                                      9. lower-sqrt.f64N/A

                                                                                                                                        \[\leadsto \mathsf{neg}\left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \color{blue}{\sqrt{{B}^{2} + {C}^{2}}}\right)}\right) \]
                                                                                                                                      10. unpow2N/A

                                                                                                                                        \[\leadsto \mathsf{neg}\left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{\color{blue}{B \cdot B} + {C}^{2}}\right)}\right) \]
                                                                                                                                      11. lower-fma.f64N/A

                                                                                                                                        \[\leadsto \mathsf{neg}\left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{\color{blue}{\mathsf{fma}\left(B, B, {C}^{2}\right)}}\right)}\right) \]
                                                                                                                                      12. unpow2N/A

                                                                                                                                        \[\leadsto \mathsf{neg}\left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{\mathsf{fma}\left(B, B, \color{blue}{C \cdot C}\right)}\right)}\right) \]
                                                                                                                                      13. lower-*.f6410.2

                                                                                                                                        \[\leadsto -\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{\mathsf{fma}\left(B, B, \color{blue}{C \cdot C}\right)}\right)} \]
                                                                                                                                    9. Applied rewrites10.2%

                                                                                                                                      \[\leadsto \color{blue}{-\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{\mathsf{fma}\left(B, B, C \cdot C\right)}\right)}} \]
                                                                                                                                    10. Step-by-step derivation
                                                                                                                                      1. Applied rewrites10.2%

                                                                                                                                        \[\leadsto \frac{\sqrt{2 \cdot \left(F \cdot \left(C + \sqrt{\mathsf{fma}\left(B, B, C \cdot C\right)}\right)\right)}}{\color{blue}{-B}} \]

                                                                                                                                      if 1e114 < (pow.f64 B #s(literal 2 binary64))

                                                                                                                                      1. Initial program 5.9%

                                                                                                                                        \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                                                                                      2. Add Preprocessing
                                                                                                                                      3. Taylor expanded in B around inf

                                                                                                                                        \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                                                                                                                      4. Step-by-step derivation
                                                                                                                                        1. mul-1-negN/A

                                                                                                                                          \[\leadsto \color{blue}{\mathsf{neg}\left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                                                                                                                        2. lower-neg.f64N/A

                                                                                                                                          \[\leadsto \color{blue}{\mathsf{neg}\left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                                                                                                                        3. *-commutativeN/A

                                                                                                                                          \[\leadsto \mathsf{neg}\left(\color{blue}{\sqrt{2} \cdot \sqrt{\frac{F}{B}}}\right) \]
                                                                                                                                        4. lower-*.f64N/A

                                                                                                                                          \[\leadsto \mathsf{neg}\left(\color{blue}{\sqrt{2} \cdot \sqrt{\frac{F}{B}}}\right) \]
                                                                                                                                        5. lower-sqrt.f64N/A

                                                                                                                                          \[\leadsto \mathsf{neg}\left(\color{blue}{\sqrt{2}} \cdot \sqrt{\frac{F}{B}}\right) \]
                                                                                                                                        6. lower-sqrt.f64N/A

                                                                                                                                          \[\leadsto \mathsf{neg}\left(\sqrt{2} \cdot \color{blue}{\sqrt{\frac{F}{B}}}\right) \]
                                                                                                                                        7. lower-/.f6430.2

                                                                                                                                          \[\leadsto -\sqrt{2} \cdot \sqrt{\color{blue}{\frac{F}{B}}} \]
                                                                                                                                      5. Applied rewrites30.2%

                                                                                                                                        \[\leadsto \color{blue}{-\sqrt{2} \cdot \sqrt{\frac{F}{B}}} \]
                                                                                                                                      6. Step-by-step derivation
                                                                                                                                        1. Applied rewrites42.3%

                                                                                                                                          \[\leadsto -\frac{\sqrt{F \cdot 2}}{\sqrt{B}} \]
                                                                                                                                        2. Step-by-step derivation
                                                                                                                                          1. Applied rewrites42.3%

                                                                                                                                            \[\leadsto -\sqrt{F} \cdot \sqrt{\frac{2}{B}} \]
                                                                                                                                          2. Step-by-step derivation
                                                                                                                                            1. Applied rewrites42.3%

                                                                                                                                              \[\leadsto -\frac{\sqrt{F}}{\sqrt{B \cdot 0.5}} \]
                                                                                                                                          3. Recombined 2 regimes into one program.
                                                                                                                                          4. Add Preprocessing

                                                                                                                                          Alternative 21: 35.8% accurate, 12.6× speedup?

                                                                                                                                          \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \left(-\sqrt{F}\right) \cdot \sqrt{\frac{2}{B\_m}} \end{array} \]
                                                                                                                                          B_m = (fabs.f64 B)
                                                                                                                                          NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                                                                                                          (FPCore (A B_m C F) :precision binary64 (* (- (sqrt F)) (sqrt (/ 2.0 B_m))))
                                                                                                                                          B_m = fabs(B);
                                                                                                                                          assert(A < B_m && B_m < C && C < F);
                                                                                                                                          double code(double A, double B_m, double C, double F) {
                                                                                                                                          	return -sqrt(F) * sqrt((2.0 / B_m));
                                                                                                                                          }
                                                                                                                                          
                                                                                                                                          B_m = abs(b)
                                                                                                                                          NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                                                                                                          real(8) function code(a, b_m, c, f)
                                                                                                                                              real(8), intent (in) :: a
                                                                                                                                              real(8), intent (in) :: b_m
                                                                                                                                              real(8), intent (in) :: c
                                                                                                                                              real(8), intent (in) :: f
                                                                                                                                              code = -sqrt(f) * sqrt((2.0d0 / b_m))
                                                                                                                                          end function
                                                                                                                                          
                                                                                                                                          B_m = Math.abs(B);
                                                                                                                                          assert A < B_m && B_m < C && C < F;
                                                                                                                                          public static double code(double A, double B_m, double C, double F) {
                                                                                                                                          	return -Math.sqrt(F) * Math.sqrt((2.0 / B_m));
                                                                                                                                          }
                                                                                                                                          
                                                                                                                                          B_m = math.fabs(B)
                                                                                                                                          [A, B_m, C, F] = sort([A, B_m, C, F])
                                                                                                                                          def code(A, B_m, C, F):
                                                                                                                                          	return -math.sqrt(F) * math.sqrt((2.0 / B_m))
                                                                                                                                          
                                                                                                                                          B_m = abs(B)
                                                                                                                                          A, B_m, C, F = sort([A, B_m, C, F])
                                                                                                                                          function code(A, B_m, C, F)
                                                                                                                                          	return Float64(Float64(-sqrt(F)) * sqrt(Float64(2.0 / B_m)))
                                                                                                                                          end
                                                                                                                                          
                                                                                                                                          B_m = abs(B);
                                                                                                                                          A, B_m, C, F = num2cell(sort([A, B_m, C, F])){:}
                                                                                                                                          function tmp = code(A, B_m, C, F)
                                                                                                                                          	tmp = -sqrt(F) * sqrt((2.0 / B_m));
                                                                                                                                          end
                                                                                                                                          
                                                                                                                                          B_m = N[Abs[B], $MachinePrecision]
                                                                                                                                          NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                                                                                                          code[A_, B$95$m_, C_, F_] := N[((-N[Sqrt[F], $MachinePrecision]) * N[Sqrt[N[(2.0 / B$95$m), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]
                                                                                                                                          
                                                                                                                                          \begin{array}{l}
                                                                                                                                          B_m = \left|B\right|
                                                                                                                                          \\
                                                                                                                                          [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
                                                                                                                                          \\
                                                                                                                                          \left(-\sqrt{F}\right) \cdot \sqrt{\frac{2}{B\_m}}
                                                                                                                                          \end{array}
                                                                                                                                          
                                                                                                                                          Derivation
                                                                                                                                          1. Initial program 17.4%

                                                                                                                                            \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                                                                                          2. Add Preprocessing
                                                                                                                                          3. Taylor expanded in B around inf

                                                                                                                                            \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                                                                                                                          4. Step-by-step derivation
                                                                                                                                            1. mul-1-negN/A

                                                                                                                                              \[\leadsto \color{blue}{\mathsf{neg}\left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                                                                                                                            2. lower-neg.f64N/A

                                                                                                                                              \[\leadsto \color{blue}{\mathsf{neg}\left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                                                                                                                            3. *-commutativeN/A

                                                                                                                                              \[\leadsto \mathsf{neg}\left(\color{blue}{\sqrt{2} \cdot \sqrt{\frac{F}{B}}}\right) \]
                                                                                                                                            4. lower-*.f64N/A

                                                                                                                                              \[\leadsto \mathsf{neg}\left(\color{blue}{\sqrt{2} \cdot \sqrt{\frac{F}{B}}}\right) \]
                                                                                                                                            5. lower-sqrt.f64N/A

                                                                                                                                              \[\leadsto \mathsf{neg}\left(\color{blue}{\sqrt{2}} \cdot \sqrt{\frac{F}{B}}\right) \]
                                                                                                                                            6. lower-sqrt.f64N/A

                                                                                                                                              \[\leadsto \mathsf{neg}\left(\sqrt{2} \cdot \color{blue}{\sqrt{\frac{F}{B}}}\right) \]
                                                                                                                                            7. lower-/.f6418.4

                                                                                                                                              \[\leadsto -\sqrt{2} \cdot \sqrt{\color{blue}{\frac{F}{B}}} \]
                                                                                                                                          5. Applied rewrites18.4%

                                                                                                                                            \[\leadsto \color{blue}{-\sqrt{2} \cdot \sqrt{\frac{F}{B}}} \]
                                                                                                                                          6. Step-by-step derivation
                                                                                                                                            1. Applied rewrites24.1%

                                                                                                                                              \[\leadsto -\frac{\sqrt{F \cdot 2}}{\sqrt{B}} \]
                                                                                                                                            2. Step-by-step derivation
                                                                                                                                              1. Applied rewrites24.1%

                                                                                                                                                \[\leadsto -\sqrt{F} \cdot \sqrt{\frac{2}{B}} \]
                                                                                                                                              2. Final simplification24.1%

                                                                                                                                                \[\leadsto \left(-\sqrt{F}\right) \cdot \sqrt{\frac{2}{B}} \]
                                                                                                                                              3. Add Preprocessing

                                                                                                                                              Alternative 22: 27.5% accurate, 16.9× speedup?

                                                                                                                                              \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ -\sqrt{F \cdot \frac{2}{B\_m}} \end{array} \]
                                                                                                                                              B_m = (fabs.f64 B)
                                                                                                                                              NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                                                                                                              (FPCore (A B_m C F) :precision binary64 (- (sqrt (* F (/ 2.0 B_m)))))
                                                                                                                                              B_m = fabs(B);
                                                                                                                                              assert(A < B_m && B_m < C && C < F);
                                                                                                                                              double code(double A, double B_m, double C, double F) {
                                                                                                                                              	return -sqrt((F * (2.0 / B_m)));
                                                                                                                                              }
                                                                                                                                              
                                                                                                                                              B_m = abs(b)
                                                                                                                                              NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                                                                                                              real(8) function code(a, b_m, c, f)
                                                                                                                                                  real(8), intent (in) :: a
                                                                                                                                                  real(8), intent (in) :: b_m
                                                                                                                                                  real(8), intent (in) :: c
                                                                                                                                                  real(8), intent (in) :: f
                                                                                                                                                  code = -sqrt((f * (2.0d0 / b_m)))
                                                                                                                                              end function
                                                                                                                                              
                                                                                                                                              B_m = Math.abs(B);
                                                                                                                                              assert A < B_m && B_m < C && C < F;
                                                                                                                                              public static double code(double A, double B_m, double C, double F) {
                                                                                                                                              	return -Math.sqrt((F * (2.0 / B_m)));
                                                                                                                                              }
                                                                                                                                              
                                                                                                                                              B_m = math.fabs(B)
                                                                                                                                              [A, B_m, C, F] = sort([A, B_m, C, F])
                                                                                                                                              def code(A, B_m, C, F):
                                                                                                                                              	return -math.sqrt((F * (2.0 / B_m)))
                                                                                                                                              
                                                                                                                                              B_m = abs(B)
                                                                                                                                              A, B_m, C, F = sort([A, B_m, C, F])
                                                                                                                                              function code(A, B_m, C, F)
                                                                                                                                              	return Float64(-sqrt(Float64(F * Float64(2.0 / B_m))))
                                                                                                                                              end
                                                                                                                                              
                                                                                                                                              B_m = abs(B);
                                                                                                                                              A, B_m, C, F = num2cell(sort([A, B_m, C, F])){:}
                                                                                                                                              function tmp = code(A, B_m, C, F)
                                                                                                                                              	tmp = -sqrt((F * (2.0 / B_m)));
                                                                                                                                              end
                                                                                                                                              
                                                                                                                                              B_m = N[Abs[B], $MachinePrecision]
                                                                                                                                              NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                                                                                                              code[A_, B$95$m_, C_, F_] := (-N[Sqrt[N[(F * N[(2.0 / B$95$m), $MachinePrecision]), $MachinePrecision]], $MachinePrecision])
                                                                                                                                              
                                                                                                                                              \begin{array}{l}
                                                                                                                                              B_m = \left|B\right|
                                                                                                                                              \\
                                                                                                                                              [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
                                                                                                                                              \\
                                                                                                                                              -\sqrt{F \cdot \frac{2}{B\_m}}
                                                                                                                                              \end{array}
                                                                                                                                              
                                                                                                                                              Derivation
                                                                                                                                              1. Initial program 17.4%

                                                                                                                                                \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                                                                                              2. Add Preprocessing
                                                                                                                                              3. Taylor expanded in B around inf

                                                                                                                                                \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                                                                                                                              4. Step-by-step derivation
                                                                                                                                                1. mul-1-negN/A

                                                                                                                                                  \[\leadsto \color{blue}{\mathsf{neg}\left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                                                                                                                                2. lower-neg.f64N/A

                                                                                                                                                  \[\leadsto \color{blue}{\mathsf{neg}\left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                                                                                                                                3. *-commutativeN/A

                                                                                                                                                  \[\leadsto \mathsf{neg}\left(\color{blue}{\sqrt{2} \cdot \sqrt{\frac{F}{B}}}\right) \]
                                                                                                                                                4. lower-*.f64N/A

                                                                                                                                                  \[\leadsto \mathsf{neg}\left(\color{blue}{\sqrt{2} \cdot \sqrt{\frac{F}{B}}}\right) \]
                                                                                                                                                5. lower-sqrt.f64N/A

                                                                                                                                                  \[\leadsto \mathsf{neg}\left(\color{blue}{\sqrt{2}} \cdot \sqrt{\frac{F}{B}}\right) \]
                                                                                                                                                6. lower-sqrt.f64N/A

                                                                                                                                                  \[\leadsto \mathsf{neg}\left(\sqrt{2} \cdot \color{blue}{\sqrt{\frac{F}{B}}}\right) \]
                                                                                                                                                7. lower-/.f6418.4

                                                                                                                                                  \[\leadsto -\sqrt{2} \cdot \sqrt{\color{blue}{\frac{F}{B}}} \]
                                                                                                                                              5. Applied rewrites18.4%

                                                                                                                                                \[\leadsto \color{blue}{-\sqrt{2} \cdot \sqrt{\frac{F}{B}}} \]
                                                                                                                                              6. Step-by-step derivation
                                                                                                                                                1. Applied rewrites18.5%

                                                                                                                                                  \[\leadsto \color{blue}{-\sqrt{\frac{2 \cdot F}{B}}} \]
                                                                                                                                                2. Step-by-step derivation
                                                                                                                                                  1. Applied rewrites18.5%

                                                                                                                                                    \[\leadsto -\sqrt{F \cdot \frac{2}{B}} \]
                                                                                                                                                  2. Add Preprocessing

                                                                                                                                                  Reproduce

                                                                                                                                                  ?
                                                                                                                                                  herbie shell --seed 2024227 
                                                                                                                                                  (FPCore (A B C F)
                                                                                                                                                    :name "ABCF->ab-angle a"
                                                                                                                                                    :precision binary64
                                                                                                                                                    (/ (- (sqrt (* (* 2.0 (* (- (pow B 2.0) (* (* 4.0 A) C)) F)) (+ (+ A C) (sqrt (+ (pow (- A C) 2.0) (pow B 2.0))))))) (- (pow B 2.0) (* (* 4.0 A) C))))