Data.Random.Distribution.Normal:normalF from random-fu-0.2.6.2

Percentage Accurate: 100.0% → 100.0%
Time: 19.9s
Alternatives: 16
Speedup: 1.0×

Specification

?
\[\begin{array}{l} \\ e^{\left(x \cdot y\right) \cdot y} \end{array} \]
(FPCore (x y) :precision binary64 (exp (* (* x y) y)))
double code(double x, double y) {
	return exp(((x * y) * y));
}
real(8) function code(x, y)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    code = exp(((x * y) * y))
end function
public static double code(double x, double y) {
	return Math.exp(((x * y) * y));
}
def code(x, y):
	return math.exp(((x * y) * y))
function code(x, y)
	return exp(Float64(Float64(x * y) * y))
end
function tmp = code(x, y)
	tmp = exp(((x * y) * y));
end
code[x_, y_] := N[Exp[N[(N[(x * y), $MachinePrecision] * y), $MachinePrecision]], $MachinePrecision]
\begin{array}{l}

\\
e^{\left(x \cdot y\right) \cdot y}
\end{array}

Sampling outcomes in binary64 precision:

Local Percentage Accuracy vs ?

The average percentage accuracy by input value. Horizontal axis shows value of an input variable; the variable is choosen in the title. Vertical axis is accuracy; higher is better. Red represent the original program, while blue represents Herbie's suggestion. These can be toggled with buttons below the plot. The line is an average while dots represent individual samples.

Accuracy vs Speed?

Herbie found 16 alternatives:

AlternativeAccuracySpeedup
The accuracy (vertical axis) and speed (horizontal axis) of each alternatives. Up and to the right is better. The red square shows the initial program, and each blue circle shows an alternative.The line shows the best available speed-accuracy tradeoffs.

Initial Program: 100.0% accurate, 1.0× speedup?

\[\begin{array}{l} \\ e^{\left(x \cdot y\right) \cdot y} \end{array} \]
(FPCore (x y) :precision binary64 (exp (* (* x y) y)))
double code(double x, double y) {
	return exp(((x * y) * y));
}
real(8) function code(x, y)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    code = exp(((x * y) * y))
end function
public static double code(double x, double y) {
	return Math.exp(((x * y) * y));
}
def code(x, y):
	return math.exp(((x * y) * y))
function code(x, y)
	return exp(Float64(Float64(x * y) * y))
end
function tmp = code(x, y)
	tmp = exp(((x * y) * y));
end
code[x_, y_] := N[Exp[N[(N[(x * y), $MachinePrecision] * y), $MachinePrecision]], $MachinePrecision]
\begin{array}{l}

\\
e^{\left(x \cdot y\right) \cdot y}
\end{array}

Alternative 1: 100.0% accurate, 1.0× speedup?

\[\begin{array}{l} \\ e^{y \cdot \left(x \cdot y\right)} \end{array} \]
(FPCore (x y) :precision binary64 (exp (* y (* x y))))
double code(double x, double y) {
	return exp((y * (x * y)));
}
real(8) function code(x, y)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    code = exp((y * (x * y)))
end function
public static double code(double x, double y) {
	return Math.exp((y * (x * y)));
}
def code(x, y):
	return math.exp((y * (x * y)))
function code(x, y)
	return exp(Float64(y * Float64(x * y)))
end
function tmp = code(x, y)
	tmp = exp((y * (x * y)));
end
code[x_, y_] := N[Exp[N[(y * N[(x * y), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]
\begin{array}{l}

\\
e^{y \cdot \left(x \cdot y\right)}
\end{array}
Derivation
  1. Initial program 100.0%

    \[e^{\left(x \cdot y\right) \cdot y} \]
  2. Add Preprocessing
  3. Final simplification100.0%

    \[\leadsto e^{y \cdot \left(x \cdot y\right)} \]
  4. Add Preprocessing

Alternative 2: 69.2% accurate, 0.8× speedup?

\[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;e^{y \cdot \left(x \cdot y\right)} \leq 5:\\ \;\;\;\;\mathsf{fma}\left(x \cdot y, y, 1\right)\\ \mathbf{else}:\\ \;\;\;\;\mathsf{fma}\left(x, \mathsf{fma}\left(x, 0.5 \cdot \left(y \cdot y\right), y\right), 1\right)\\ \end{array} \end{array} \]
(FPCore (x y)
 :precision binary64
 (if (<= (exp (* y (* x y))) 5.0)
   (fma (* x y) y 1.0)
   (fma x (fma x (* 0.5 (* y y)) y) 1.0)))
double code(double x, double y) {
	double tmp;
	if (exp((y * (x * y))) <= 5.0) {
		tmp = fma((x * y), y, 1.0);
	} else {
		tmp = fma(x, fma(x, (0.5 * (y * y)), y), 1.0);
	}
	return tmp;
}
function code(x, y)
	tmp = 0.0
	if (exp(Float64(y * Float64(x * y))) <= 5.0)
		tmp = fma(Float64(x * y), y, 1.0);
	else
		tmp = fma(x, fma(x, Float64(0.5 * Float64(y * y)), y), 1.0);
	end
	return tmp
end
code[x_, y_] := If[LessEqual[N[Exp[N[(y * N[(x * y), $MachinePrecision]), $MachinePrecision]], $MachinePrecision], 5.0], N[(N[(x * y), $MachinePrecision] * y + 1.0), $MachinePrecision], N[(x * N[(x * N[(0.5 * N[(y * y), $MachinePrecision]), $MachinePrecision] + y), $MachinePrecision] + 1.0), $MachinePrecision]]
\begin{array}{l}

\\
\begin{array}{l}
\mathbf{if}\;e^{y \cdot \left(x \cdot y\right)} \leq 5:\\
\;\;\;\;\mathsf{fma}\left(x \cdot y, y, 1\right)\\

\mathbf{else}:\\
\;\;\;\;\mathsf{fma}\left(x, \mathsf{fma}\left(x, 0.5 \cdot \left(y \cdot y\right), y\right), 1\right)\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if (exp.f64 (*.f64 (*.f64 x y) y)) < 5

    1. Initial program 100.0%

      \[e^{\left(x \cdot y\right) \cdot y} \]
    2. Add Preprocessing
    3. Taylor expanded in x around 0

      \[\leadsto \color{blue}{1 + x \cdot {y}^{2}} \]
    4. Step-by-step derivation
      1. +-commutativeN/A

        \[\leadsto \color{blue}{x \cdot {y}^{2} + 1} \]
      2. lower-fma.f64N/A

        \[\leadsto \color{blue}{\mathsf{fma}\left(x, {y}^{2}, 1\right)} \]
      3. unpow2N/A

        \[\leadsto \mathsf{fma}\left(x, \color{blue}{y \cdot y}, 1\right) \]
      4. lower-*.f6465.1

        \[\leadsto \mathsf{fma}\left(x, \color{blue}{y \cdot y}, 1\right) \]
    5. Applied rewrites65.1%

      \[\leadsto \color{blue}{\mathsf{fma}\left(x, y \cdot y, 1\right)} \]
    6. Step-by-step derivation
      1. Applied rewrites65.1%

        \[\leadsto \mathsf{fma}\left(x \cdot y, \color{blue}{y}, 1\right) \]

      if 5 < (exp.f64 (*.f64 (*.f64 x y) y))

      1. Initial program 100.0%

        \[e^{\left(x \cdot y\right) \cdot y} \]
      2. Add Preprocessing
      3. Applied rewrites58.2%

        \[\leadsto e^{\color{blue}{x} \cdot y} \]
      4. Taylor expanded in x around 0

        \[\leadsto \color{blue}{1 + x \cdot \left(y + \frac{1}{2} \cdot \left(x \cdot {y}^{2}\right)\right)} \]
      5. Step-by-step derivation
        1. +-commutativeN/A

          \[\leadsto \color{blue}{x \cdot \left(y + \frac{1}{2} \cdot \left(x \cdot {y}^{2}\right)\right) + 1} \]
        2. +-commutativeN/A

          \[\leadsto x \cdot \color{blue}{\left(\frac{1}{2} \cdot \left(x \cdot {y}^{2}\right) + y\right)} + 1 \]
        3. *-commutativeN/A

          \[\leadsto x \cdot \left(\frac{1}{2} \cdot \color{blue}{\left({y}^{2} \cdot x\right)} + y\right) + 1 \]
        4. associate-*r*N/A

          \[\leadsto x \cdot \left(\color{blue}{\left(\frac{1}{2} \cdot {y}^{2}\right) \cdot x} + y\right) + 1 \]
        5. lower-fma.f64N/A

          \[\leadsto \color{blue}{\mathsf{fma}\left(x, \left(\frac{1}{2} \cdot {y}^{2}\right) \cdot x + y, 1\right)} \]
        6. *-commutativeN/A

          \[\leadsto \mathsf{fma}\left(x, \color{blue}{x \cdot \left(\frac{1}{2} \cdot {y}^{2}\right)} + y, 1\right) \]
        7. lower-fma.f64N/A

          \[\leadsto \mathsf{fma}\left(x, \color{blue}{\mathsf{fma}\left(x, \frac{1}{2} \cdot {y}^{2}, y\right)}, 1\right) \]
        8. lower-*.f64N/A

          \[\leadsto \mathsf{fma}\left(x, \mathsf{fma}\left(x, \color{blue}{\frac{1}{2} \cdot {y}^{2}}, y\right), 1\right) \]
        9. unpow2N/A

          \[\leadsto \mathsf{fma}\left(x, \mathsf{fma}\left(x, \frac{1}{2} \cdot \color{blue}{\left(y \cdot y\right)}, y\right), 1\right) \]
        10. lower-*.f6484.6

          \[\leadsto \mathsf{fma}\left(x, \mathsf{fma}\left(x, 0.5 \cdot \color{blue}{\left(y \cdot y\right)}, y\right), 1\right) \]
      6. Applied rewrites84.6%

        \[\leadsto \color{blue}{\mathsf{fma}\left(x, \mathsf{fma}\left(x, 0.5 \cdot \left(y \cdot y\right), y\right), 1\right)} \]
    7. Recombined 2 regimes into one program.
    8. Final simplification69.7%

      \[\leadsto \begin{array}{l} \mathbf{if}\;e^{y \cdot \left(x \cdot y\right)} \leq 5:\\ \;\;\;\;\mathsf{fma}\left(x \cdot y, y, 1\right)\\ \mathbf{else}:\\ \;\;\;\;\mathsf{fma}\left(x, \mathsf{fma}\left(x, 0.5 \cdot \left(y \cdot y\right), y\right), 1\right)\\ \end{array} \]
    9. Add Preprocessing

    Alternative 3: 66.3% accurate, 0.9× speedup?

    \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;e^{y \cdot \left(x \cdot y\right)} \leq 2:\\ \;\;\;\;1\\ \mathbf{else}:\\ \;\;\;\;x \cdot \left(y \cdot y\right)\\ \end{array} \end{array} \]
    (FPCore (x y)
     :precision binary64
     (if (<= (exp (* y (* x y))) 2.0) 1.0 (* x (* y y))))
    double code(double x, double y) {
    	double tmp;
    	if (exp((y * (x * y))) <= 2.0) {
    		tmp = 1.0;
    	} else {
    		tmp = x * (y * y);
    	}
    	return tmp;
    }
    
    real(8) function code(x, y)
        real(8), intent (in) :: x
        real(8), intent (in) :: y
        real(8) :: tmp
        if (exp((y * (x * y))) <= 2.0d0) then
            tmp = 1.0d0
        else
            tmp = x * (y * y)
        end if
        code = tmp
    end function
    
    public static double code(double x, double y) {
    	double tmp;
    	if (Math.exp((y * (x * y))) <= 2.0) {
    		tmp = 1.0;
    	} else {
    		tmp = x * (y * y);
    	}
    	return tmp;
    }
    
    def code(x, y):
    	tmp = 0
    	if math.exp((y * (x * y))) <= 2.0:
    		tmp = 1.0
    	else:
    		tmp = x * (y * y)
    	return tmp
    
    function code(x, y)
    	tmp = 0.0
    	if (exp(Float64(y * Float64(x * y))) <= 2.0)
    		tmp = 1.0;
    	else
    		tmp = Float64(x * Float64(y * y));
    	end
    	return tmp
    end
    
    function tmp_2 = code(x, y)
    	tmp = 0.0;
    	if (exp((y * (x * y))) <= 2.0)
    		tmp = 1.0;
    	else
    		tmp = x * (y * y);
    	end
    	tmp_2 = tmp;
    end
    
    code[x_, y_] := If[LessEqual[N[Exp[N[(y * N[(x * y), $MachinePrecision]), $MachinePrecision]], $MachinePrecision], 2.0], 1.0, N[(x * N[(y * y), $MachinePrecision]), $MachinePrecision]]
    
    \begin{array}{l}
    
    \\
    \begin{array}{l}
    \mathbf{if}\;e^{y \cdot \left(x \cdot y\right)} \leq 2:\\
    \;\;\;\;1\\
    
    \mathbf{else}:\\
    \;\;\;\;x \cdot \left(y \cdot y\right)\\
    
    
    \end{array}
    \end{array}
    
    Derivation
    1. Split input into 2 regimes
    2. if (exp.f64 (*.f64 (*.f64 x y) y)) < 2

      1. Initial program 100.0%

        \[e^{\left(x \cdot y\right) \cdot y} \]
      2. Add Preprocessing
      3. Taylor expanded in x around 0

        \[\leadsto \color{blue}{1} \]
      4. Step-by-step derivation
        1. Applied rewrites65.0%

          \[\leadsto \color{blue}{1} \]

        if 2 < (exp.f64 (*.f64 (*.f64 x y) y))

        1. Initial program 100.0%

          \[e^{\left(x \cdot y\right) \cdot y} \]
        2. Add Preprocessing
        3. Taylor expanded in x around 0

          \[\leadsto \color{blue}{1 + x \cdot {y}^{2}} \]
        4. Step-by-step derivation
          1. +-commutativeN/A

            \[\leadsto \color{blue}{x \cdot {y}^{2} + 1} \]
          2. lower-fma.f64N/A

            \[\leadsto \color{blue}{\mathsf{fma}\left(x, {y}^{2}, 1\right)} \]
          3. unpow2N/A

            \[\leadsto \mathsf{fma}\left(x, \color{blue}{y \cdot y}, 1\right) \]
          4. lower-*.f6474.2

            \[\leadsto \mathsf{fma}\left(x, \color{blue}{y \cdot y}, 1\right) \]
        5. Applied rewrites74.2%

          \[\leadsto \color{blue}{\mathsf{fma}\left(x, y \cdot y, 1\right)} \]
        6. Taylor expanded in x around inf

          \[\leadsto x \cdot \color{blue}{{y}^{2}} \]
        7. Step-by-step derivation
          1. Applied rewrites74.2%

            \[\leadsto x \cdot \color{blue}{\left(y \cdot y\right)} \]
        8. Recombined 2 regimes into one program.
        9. Final simplification67.2%

          \[\leadsto \begin{array}{l} \mathbf{if}\;e^{y \cdot \left(x \cdot y\right)} \leq 2:\\ \;\;\;\;1\\ \mathbf{else}:\\ \;\;\;\;x \cdot \left(y \cdot y\right)\\ \end{array} \]
        10. Add Preprocessing

        Alternative 4: 93.5% accurate, 1.0× speedup?

        \[\begin{array}{l} \\ \begin{array}{l} t_0 := y \cdot \left(x \cdot y\right)\\ \mathbf{if}\;t\_0 \leq -5 \cdot 10^{+138}:\\ \;\;\;\;\frac{1}{\mathsf{fma}\left(y \cdot y, x \cdot \mathsf{fma}\left(x, 0.5 \cdot \left(y \cdot y\right), -1\right), 1\right)}\\ \mathbf{elif}\;t\_0 \leq -2 \cdot 10^{+19}:\\ \;\;\;\;\frac{1}{\mathsf{fma}\left(y \cdot y, \mathsf{fma}\left(y \cdot y, \mathsf{fma}\left(x \cdot \left(x \cdot \left(x \cdot 0.16666666666666666\right)\right), y \cdot \left(-y\right), x \cdot \left(x \cdot 0.5\right)\right), -x\right), 1\right)}\\ \mathbf{else}:\\ \;\;\;\;\mathsf{fma}\left(y \cdot y, \mathsf{fma}\left(x \cdot \left(x \cdot \left(y \cdot y\right)\right), \mathsf{fma}\left(x, 0.16666666666666666 \cdot \left(y \cdot y\right), 0.5\right), x\right), 1\right)\\ \end{array} \end{array} \]
        (FPCore (x y)
         :precision binary64
         (let* ((t_0 (* y (* x y))))
           (if (<= t_0 -5e+138)
             (/ 1.0 (fma (* y y) (* x (fma x (* 0.5 (* y y)) -1.0)) 1.0))
             (if (<= t_0 -2e+19)
               (/
                1.0
                (fma
                 (* y y)
                 (fma
                  (* y y)
                  (fma
                   (* x (* x (* x 0.16666666666666666)))
                   (* y (- y))
                   (* x (* x 0.5)))
                  (- x))
                 1.0))
               (fma
                (* y y)
                (fma (* x (* x (* y y))) (fma x (* 0.16666666666666666 (* y y)) 0.5) x)
                1.0)))))
        double code(double x, double y) {
        	double t_0 = y * (x * y);
        	double tmp;
        	if (t_0 <= -5e+138) {
        		tmp = 1.0 / fma((y * y), (x * fma(x, (0.5 * (y * y)), -1.0)), 1.0);
        	} else if (t_0 <= -2e+19) {
        		tmp = 1.0 / fma((y * y), fma((y * y), fma((x * (x * (x * 0.16666666666666666))), (y * -y), (x * (x * 0.5))), -x), 1.0);
        	} else {
        		tmp = fma((y * y), fma((x * (x * (y * y))), fma(x, (0.16666666666666666 * (y * y)), 0.5), x), 1.0);
        	}
        	return tmp;
        }
        
        function code(x, y)
        	t_0 = Float64(y * Float64(x * y))
        	tmp = 0.0
        	if (t_0 <= -5e+138)
        		tmp = Float64(1.0 / fma(Float64(y * y), Float64(x * fma(x, Float64(0.5 * Float64(y * y)), -1.0)), 1.0));
        	elseif (t_0 <= -2e+19)
        		tmp = Float64(1.0 / fma(Float64(y * y), fma(Float64(y * y), fma(Float64(x * Float64(x * Float64(x * 0.16666666666666666))), Float64(y * Float64(-y)), Float64(x * Float64(x * 0.5))), Float64(-x)), 1.0));
        	else
        		tmp = fma(Float64(y * y), fma(Float64(x * Float64(x * Float64(y * y))), fma(x, Float64(0.16666666666666666 * Float64(y * y)), 0.5), x), 1.0);
        	end
        	return tmp
        end
        
        code[x_, y_] := Block[{t$95$0 = N[(y * N[(x * y), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[t$95$0, -5e+138], N[(1.0 / N[(N[(y * y), $MachinePrecision] * N[(x * N[(x * N[(0.5 * N[(y * y), $MachinePrecision]), $MachinePrecision] + -1.0), $MachinePrecision]), $MachinePrecision] + 1.0), $MachinePrecision]), $MachinePrecision], If[LessEqual[t$95$0, -2e+19], N[(1.0 / N[(N[(y * y), $MachinePrecision] * N[(N[(y * y), $MachinePrecision] * N[(N[(x * N[(x * N[(x * 0.16666666666666666), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] * N[(y * (-y)), $MachinePrecision] + N[(x * N[(x * 0.5), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] + (-x)), $MachinePrecision] + 1.0), $MachinePrecision]), $MachinePrecision], N[(N[(y * y), $MachinePrecision] * N[(N[(x * N[(x * N[(y * y), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] * N[(x * N[(0.16666666666666666 * N[(y * y), $MachinePrecision]), $MachinePrecision] + 0.5), $MachinePrecision] + x), $MachinePrecision] + 1.0), $MachinePrecision]]]]
        
        \begin{array}{l}
        
        \\
        \begin{array}{l}
        t_0 := y \cdot \left(x \cdot y\right)\\
        \mathbf{if}\;t\_0 \leq -5 \cdot 10^{+138}:\\
        \;\;\;\;\frac{1}{\mathsf{fma}\left(y \cdot y, x \cdot \mathsf{fma}\left(x, 0.5 \cdot \left(y \cdot y\right), -1\right), 1\right)}\\
        
        \mathbf{elif}\;t\_0 \leq -2 \cdot 10^{+19}:\\
        \;\;\;\;\frac{1}{\mathsf{fma}\left(y \cdot y, \mathsf{fma}\left(y \cdot y, \mathsf{fma}\left(x \cdot \left(x \cdot \left(x \cdot 0.16666666666666666\right)\right), y \cdot \left(-y\right), x \cdot \left(x \cdot 0.5\right)\right), -x\right), 1\right)}\\
        
        \mathbf{else}:\\
        \;\;\;\;\mathsf{fma}\left(y \cdot y, \mathsf{fma}\left(x \cdot \left(x \cdot \left(y \cdot y\right)\right), \mathsf{fma}\left(x, 0.16666666666666666 \cdot \left(y \cdot y\right), 0.5\right), x\right), 1\right)\\
        
        
        \end{array}
        \end{array}
        
        Derivation
        1. Split input into 3 regimes
        2. if (*.f64 (*.f64 x y) y) < -5.00000000000000016e138

          1. Initial program 100.0%

            \[e^{\left(x \cdot y\right) \cdot y} \]
          2. Add Preprocessing
          3. Taylor expanded in x around 0

            \[\leadsto \color{blue}{1 + x \cdot \left(x \cdot \left(\frac{1}{6} \cdot \left(x \cdot {y}^{6}\right) + \frac{1}{2} \cdot {y}^{4}\right) + {y}^{2}\right)} \]
          4. Applied rewrites1.6%

            \[\leadsto \color{blue}{\mathsf{fma}\left(y \cdot y, \mathsf{fma}\left(x \cdot \left(x \cdot \left(y \cdot y\right)\right), \mathsf{fma}\left(x, \left(y \cdot y\right) \cdot 0.16666666666666666, 0.5\right), x\right), 1\right)} \]
          5. Step-by-step derivation
            1. Applied rewrites1.6%

              \[\leadsto \frac{1}{\color{blue}{\frac{1}{\mathsf{fma}\left(y \cdot y, \mathsf{fma}\left(x \cdot \left(y \cdot y\right), x \cdot \mathsf{fma}\left(x, \left(y \cdot y\right) \cdot 0.16666666666666666, 0.5\right), x\right), 1\right)}}} \]
            2. Taylor expanded in y around 0

              \[\leadsto \frac{1}{1 + \color{blue}{{y}^{2} \cdot \left(-1 \cdot \left({y}^{2} \cdot \left(-1 \cdot {x}^{2} + \frac{1}{2} \cdot {x}^{2}\right)\right) - x\right)}} \]
            3. Step-by-step derivation
              1. Applied rewrites100.0%

                \[\leadsto \frac{1}{\mathsf{fma}\left(y \cdot y, \color{blue}{x \cdot \mathsf{fma}\left(x, \left(y \cdot y\right) \cdot 0.5, -1\right)}, 1\right)} \]

              if -5.00000000000000016e138 < (*.f64 (*.f64 x y) y) < -2e19

              1. Initial program 100.0%

                \[e^{\left(x \cdot y\right) \cdot y} \]
              2. Add Preprocessing
              3. Taylor expanded in x around 0

                \[\leadsto \color{blue}{1 + x \cdot \left(x \cdot \left(\frac{1}{6} \cdot \left(x \cdot {y}^{6}\right) + \frac{1}{2} \cdot {y}^{4}\right) + {y}^{2}\right)} \]
              4. Applied rewrites1.9%

                \[\leadsto \color{blue}{\mathsf{fma}\left(y \cdot y, \mathsf{fma}\left(x \cdot \left(x \cdot \left(y \cdot y\right)\right), \mathsf{fma}\left(x, \left(y \cdot y\right) \cdot 0.16666666666666666, 0.5\right), x\right), 1\right)} \]
              5. Step-by-step derivation
                1. Applied rewrites1.9%

                  \[\leadsto \frac{1}{\color{blue}{\frac{1}{\mathsf{fma}\left(y \cdot y, \mathsf{fma}\left(x \cdot \left(y \cdot y\right), x \cdot \mathsf{fma}\left(x, \left(y \cdot y\right) \cdot 0.16666666666666666, 0.5\right), x\right), 1\right)}}} \]
                2. Taylor expanded in y around 0

                  \[\leadsto \frac{1}{1 + \color{blue}{{y}^{2} \cdot \left({y}^{2} \cdot \left(-1 \cdot \left({y}^{2} \cdot \left(-1 \cdot \left(x \cdot \left(-1 \cdot {x}^{2} + \frac{1}{2} \cdot {x}^{2}\right)\right) + \left(\frac{-1}{2} \cdot {x}^{3} + \frac{1}{6} \cdot {x}^{3}\right)\right)\right) - \left(-1 \cdot {x}^{2} + \frac{1}{2} \cdot {x}^{2}\right)\right) - x\right)}} \]
                3. Applied rewrites56.3%

                  \[\leadsto \frac{1}{\mathsf{fma}\left(y \cdot y, \color{blue}{\mathsf{fma}\left(y \cdot y, \mathsf{fma}\left(x \cdot \left(x \cdot \left(x \cdot 0.16666666666666666\right)\right), y \cdot \left(-y\right), x \cdot \left(x \cdot 0.5\right)\right), -x\right)}, 1\right)} \]

                if -2e19 < (*.f64 (*.f64 x y) y)

                1. Initial program 100.0%

                  \[e^{\left(x \cdot y\right) \cdot y} \]
                2. Add Preprocessing
                3. Taylor expanded in x around 0

                  \[\leadsto \color{blue}{1 + x \cdot \left(x \cdot \left(\frac{1}{6} \cdot \left(x \cdot {y}^{6}\right) + \frac{1}{2} \cdot {y}^{4}\right) + {y}^{2}\right)} \]
                4. Applied rewrites97.9%

                  \[\leadsto \color{blue}{\mathsf{fma}\left(y \cdot y, \mathsf{fma}\left(x \cdot \left(x \cdot \left(y \cdot y\right)\right), \mathsf{fma}\left(x, \left(y \cdot y\right) \cdot 0.16666666666666666, 0.5\right), x\right), 1\right)} \]
              6. Recombined 3 regimes into one program.
              7. Final simplification96.3%

                \[\leadsto \begin{array}{l} \mathbf{if}\;y \cdot \left(x \cdot y\right) \leq -5 \cdot 10^{+138}:\\ \;\;\;\;\frac{1}{\mathsf{fma}\left(y \cdot y, x \cdot \mathsf{fma}\left(x, 0.5 \cdot \left(y \cdot y\right), -1\right), 1\right)}\\ \mathbf{elif}\;y \cdot \left(x \cdot y\right) \leq -2 \cdot 10^{+19}:\\ \;\;\;\;\frac{1}{\mathsf{fma}\left(y \cdot y, \mathsf{fma}\left(y \cdot y, \mathsf{fma}\left(x \cdot \left(x \cdot \left(x \cdot 0.16666666666666666\right)\right), y \cdot \left(-y\right), x \cdot \left(x \cdot 0.5\right)\right), -x\right), 1\right)}\\ \mathbf{else}:\\ \;\;\;\;\mathsf{fma}\left(y \cdot y, \mathsf{fma}\left(x \cdot \left(x \cdot \left(y \cdot y\right)\right), \mathsf{fma}\left(x, 0.16666666666666666 \cdot \left(y \cdot y\right), 0.5\right), x\right), 1\right)\\ \end{array} \]
              8. Add Preprocessing

              Alternative 5: 94.3% accurate, 1.2× speedup?

              \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;y \cdot \left(x \cdot y\right) \leq -2 \cdot 10^{+19}:\\ \;\;\;\;\frac{1}{\mathsf{fma}\left(y \cdot y, \mathsf{fma}\left(y, \mathsf{fma}\left(0.16666666666666666, y \cdot \left(y \cdot \left(x \cdot \left(x \cdot x\right)\right)\right), \left(x \cdot x\right) \cdot -0.5\right) \cdot \left(-y\right), -x\right), 1\right)}\\ \mathbf{else}:\\ \;\;\;\;\mathsf{fma}\left(y \cdot y, \mathsf{fma}\left(x \cdot \left(x \cdot \left(y \cdot y\right)\right), \mathsf{fma}\left(x, 0.16666666666666666 \cdot \left(y \cdot y\right), 0.5\right), x\right), 1\right)\\ \end{array} \end{array} \]
              (FPCore (x y)
               :precision binary64
               (if (<= (* y (* x y)) -2e+19)
                 (/
                  1.0
                  (fma
                   (* y y)
                   (fma
                    y
                    (*
                     (fma 0.16666666666666666 (* y (* y (* x (* x x)))) (* (* x x) -0.5))
                     (- y))
                    (- x))
                   1.0))
                 (fma
                  (* y y)
                  (fma (* x (* x (* y y))) (fma x (* 0.16666666666666666 (* y y)) 0.5) x)
                  1.0)))
              double code(double x, double y) {
              	double tmp;
              	if ((y * (x * y)) <= -2e+19) {
              		tmp = 1.0 / fma((y * y), fma(y, (fma(0.16666666666666666, (y * (y * (x * (x * x)))), ((x * x) * -0.5)) * -y), -x), 1.0);
              	} else {
              		tmp = fma((y * y), fma((x * (x * (y * y))), fma(x, (0.16666666666666666 * (y * y)), 0.5), x), 1.0);
              	}
              	return tmp;
              }
              
              function code(x, y)
              	tmp = 0.0
              	if (Float64(y * Float64(x * y)) <= -2e+19)
              		tmp = Float64(1.0 / fma(Float64(y * y), fma(y, Float64(fma(0.16666666666666666, Float64(y * Float64(y * Float64(x * Float64(x * x)))), Float64(Float64(x * x) * -0.5)) * Float64(-y)), Float64(-x)), 1.0));
              	else
              		tmp = fma(Float64(y * y), fma(Float64(x * Float64(x * Float64(y * y))), fma(x, Float64(0.16666666666666666 * Float64(y * y)), 0.5), x), 1.0);
              	end
              	return tmp
              end
              
              code[x_, y_] := If[LessEqual[N[(y * N[(x * y), $MachinePrecision]), $MachinePrecision], -2e+19], N[(1.0 / N[(N[(y * y), $MachinePrecision] * N[(y * N[(N[(0.16666666666666666 * N[(y * N[(y * N[(x * N[(x * x), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] + N[(N[(x * x), $MachinePrecision] * -0.5), $MachinePrecision]), $MachinePrecision] * (-y)), $MachinePrecision] + (-x)), $MachinePrecision] + 1.0), $MachinePrecision]), $MachinePrecision], N[(N[(y * y), $MachinePrecision] * N[(N[(x * N[(x * N[(y * y), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] * N[(x * N[(0.16666666666666666 * N[(y * y), $MachinePrecision]), $MachinePrecision] + 0.5), $MachinePrecision] + x), $MachinePrecision] + 1.0), $MachinePrecision]]
              
              \begin{array}{l}
              
              \\
              \begin{array}{l}
              \mathbf{if}\;y \cdot \left(x \cdot y\right) \leq -2 \cdot 10^{+19}:\\
              \;\;\;\;\frac{1}{\mathsf{fma}\left(y \cdot y, \mathsf{fma}\left(y, \mathsf{fma}\left(0.16666666666666666, y \cdot \left(y \cdot \left(x \cdot \left(x \cdot x\right)\right)\right), \left(x \cdot x\right) \cdot -0.5\right) \cdot \left(-y\right), -x\right), 1\right)}\\
              
              \mathbf{else}:\\
              \;\;\;\;\mathsf{fma}\left(y \cdot y, \mathsf{fma}\left(x \cdot \left(x \cdot \left(y \cdot y\right)\right), \mathsf{fma}\left(x, 0.16666666666666666 \cdot \left(y \cdot y\right), 0.5\right), x\right), 1\right)\\
              
              
              \end{array}
              \end{array}
              
              Derivation
              1. Split input into 2 regimes
              2. if (*.f64 (*.f64 x y) y) < -2e19

                1. Initial program 100.0%

                  \[e^{\left(x \cdot y\right) \cdot y} \]
                2. Add Preprocessing
                3. Taylor expanded in x around 0

                  \[\leadsto \color{blue}{1 + x \cdot \left(x \cdot \left(\frac{1}{6} \cdot \left(x \cdot {y}^{6}\right) + \frac{1}{2} \cdot {y}^{4}\right) + {y}^{2}\right)} \]
                4. Applied rewrites1.6%

                  \[\leadsto \color{blue}{\mathsf{fma}\left(y \cdot y, \mathsf{fma}\left(x \cdot \left(x \cdot \left(y \cdot y\right)\right), \mathsf{fma}\left(x, \left(y \cdot y\right) \cdot 0.16666666666666666, 0.5\right), x\right), 1\right)} \]
                5. Step-by-step derivation
                  1. Applied rewrites1.6%

                    \[\leadsto \frac{1}{\color{blue}{\frac{1}{\mathsf{fma}\left(y \cdot y, \mathsf{fma}\left(x \cdot \left(y \cdot y\right), x \cdot \mathsf{fma}\left(x, \left(y \cdot y\right) \cdot 0.16666666666666666, 0.5\right), x\right), 1\right)}}} \]
                  2. Step-by-step derivation
                    1. Applied rewrites1.6%

                      \[\leadsto \frac{1}{\frac{1}{\mathsf{fma}\left(y \cdot y, \mathsf{fma}\left(x \cdot \left(y \cdot y\right), x \cdot \mathsf{fma}\left(y \cdot \left(y \cdot 0.16666666666666666\right), \color{blue}{x}, 0.5\right), x\right), 1\right)}} \]
                    2. Taylor expanded in y around 0

                      \[\leadsto \frac{1}{1 + \color{blue}{{y}^{2} \cdot \left({y}^{2} \cdot \left(-1 \cdot \left({y}^{2} \cdot \left(-1 \cdot \left(x \cdot \left(-1 \cdot {x}^{2} + \frac{1}{2} \cdot {x}^{2}\right)\right) + \left(\frac{-1}{2} \cdot {x}^{3} + \frac{1}{6} \cdot {x}^{3}\right)\right)\right) - \left(-1 \cdot {x}^{2} + \frac{1}{2} \cdot {x}^{2}\right)\right) - x\right)}} \]
                    3. Applied rewrites93.1%

                      \[\leadsto \frac{1}{\mathsf{fma}\left(y \cdot y, \color{blue}{\mathsf{fma}\left(y, -y \cdot \mathsf{fma}\left(0.16666666666666666, y \cdot \left(y \cdot \left(x \cdot \left(x \cdot x\right)\right)\right), \left(x \cdot x\right) \cdot -0.5\right), -x\right)}, 1\right)} \]

                    if -2e19 < (*.f64 (*.f64 x y) y)

                    1. Initial program 100.0%

                      \[e^{\left(x \cdot y\right) \cdot y} \]
                    2. Add Preprocessing
                    3. Taylor expanded in x around 0

                      \[\leadsto \color{blue}{1 + x \cdot \left(x \cdot \left(\frac{1}{6} \cdot \left(x \cdot {y}^{6}\right) + \frac{1}{2} \cdot {y}^{4}\right) + {y}^{2}\right)} \]
                    4. Applied rewrites97.9%

                      \[\leadsto \color{blue}{\mathsf{fma}\left(y \cdot y, \mathsf{fma}\left(x \cdot \left(x \cdot \left(y \cdot y\right)\right), \mathsf{fma}\left(x, \left(y \cdot y\right) \cdot 0.16666666666666666, 0.5\right), x\right), 1\right)} \]
                  3. Recombined 2 regimes into one program.
                  4. Final simplification96.7%

                    \[\leadsto \begin{array}{l} \mathbf{if}\;y \cdot \left(x \cdot y\right) \leq -2 \cdot 10^{+19}:\\ \;\;\;\;\frac{1}{\mathsf{fma}\left(y \cdot y, \mathsf{fma}\left(y, \mathsf{fma}\left(0.16666666666666666, y \cdot \left(y \cdot \left(x \cdot \left(x \cdot x\right)\right)\right), \left(x \cdot x\right) \cdot -0.5\right) \cdot \left(-y\right), -x\right), 1\right)}\\ \mathbf{else}:\\ \;\;\;\;\mathsf{fma}\left(y \cdot y, \mathsf{fma}\left(x \cdot \left(x \cdot \left(y \cdot y\right)\right), \mathsf{fma}\left(x, 0.16666666666666666 \cdot \left(y \cdot y\right), 0.5\right), x\right), 1\right)\\ \end{array} \]
                  5. Add Preprocessing

                  Alternative 6: 91.6% accurate, 1.7× speedup?

                  \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;y \cdot \left(x \cdot y\right) \leq 2 \cdot 10^{-202}:\\ \;\;\;\;\frac{1}{\mathsf{fma}\left(y \cdot y, x \cdot \mathsf{fma}\left(x, 0.5 \cdot \left(y \cdot y\right), -1\right), 1\right)}\\ \mathbf{else}:\\ \;\;\;\;\mathsf{fma}\left(y \cdot y, \mathsf{fma}\left(y \cdot \left(x \cdot \left(x \cdot y\right)\right), \mathsf{fma}\left(x, 0.16666666666666666 \cdot \left(y \cdot y\right), 0.5\right), x\right), 1\right)\\ \end{array} \end{array} \]
                  (FPCore (x y)
                   :precision binary64
                   (if (<= (* y (* x y)) 2e-202)
                     (/ 1.0 (fma (* y y) (* x (fma x (* 0.5 (* y y)) -1.0)) 1.0))
                     (fma
                      (* y y)
                      (fma (* y (* x (* x y))) (fma x (* 0.16666666666666666 (* y y)) 0.5) x)
                      1.0)))
                  double code(double x, double y) {
                  	double tmp;
                  	if ((y * (x * y)) <= 2e-202) {
                  		tmp = 1.0 / fma((y * y), (x * fma(x, (0.5 * (y * y)), -1.0)), 1.0);
                  	} else {
                  		tmp = fma((y * y), fma((y * (x * (x * y))), fma(x, (0.16666666666666666 * (y * y)), 0.5), x), 1.0);
                  	}
                  	return tmp;
                  }
                  
                  function code(x, y)
                  	tmp = 0.0
                  	if (Float64(y * Float64(x * y)) <= 2e-202)
                  		tmp = Float64(1.0 / fma(Float64(y * y), Float64(x * fma(x, Float64(0.5 * Float64(y * y)), -1.0)), 1.0));
                  	else
                  		tmp = fma(Float64(y * y), fma(Float64(y * Float64(x * Float64(x * y))), fma(x, Float64(0.16666666666666666 * Float64(y * y)), 0.5), x), 1.0);
                  	end
                  	return tmp
                  end
                  
                  code[x_, y_] := If[LessEqual[N[(y * N[(x * y), $MachinePrecision]), $MachinePrecision], 2e-202], N[(1.0 / N[(N[(y * y), $MachinePrecision] * N[(x * N[(x * N[(0.5 * N[(y * y), $MachinePrecision]), $MachinePrecision] + -1.0), $MachinePrecision]), $MachinePrecision] + 1.0), $MachinePrecision]), $MachinePrecision], N[(N[(y * y), $MachinePrecision] * N[(N[(y * N[(x * N[(x * y), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] * N[(x * N[(0.16666666666666666 * N[(y * y), $MachinePrecision]), $MachinePrecision] + 0.5), $MachinePrecision] + x), $MachinePrecision] + 1.0), $MachinePrecision]]
                  
                  \begin{array}{l}
                  
                  \\
                  \begin{array}{l}
                  \mathbf{if}\;y \cdot \left(x \cdot y\right) \leq 2 \cdot 10^{-202}:\\
                  \;\;\;\;\frac{1}{\mathsf{fma}\left(y \cdot y, x \cdot \mathsf{fma}\left(x, 0.5 \cdot \left(y \cdot y\right), -1\right), 1\right)}\\
                  
                  \mathbf{else}:\\
                  \;\;\;\;\mathsf{fma}\left(y \cdot y, \mathsf{fma}\left(y \cdot \left(x \cdot \left(x \cdot y\right)\right), \mathsf{fma}\left(x, 0.16666666666666666 \cdot \left(y \cdot y\right), 0.5\right), x\right), 1\right)\\
                  
                  
                  \end{array}
                  \end{array}
                  
                  Derivation
                  1. Split input into 2 regimes
                  2. if (*.f64 (*.f64 x y) y) < 2.0000000000000001e-202

                    1. Initial program 100.0%

                      \[e^{\left(x \cdot y\right) \cdot y} \]
                    2. Add Preprocessing
                    3. Taylor expanded in x around 0

                      \[\leadsto \color{blue}{1 + x \cdot \left(x \cdot \left(\frac{1}{6} \cdot \left(x \cdot {y}^{6}\right) + \frac{1}{2} \cdot {y}^{4}\right) + {y}^{2}\right)} \]
                    4. Applied rewrites62.3%

                      \[\leadsto \color{blue}{\mathsf{fma}\left(y \cdot y, \mathsf{fma}\left(x \cdot \left(x \cdot \left(y \cdot y\right)\right), \mathsf{fma}\left(x, \left(y \cdot y\right) \cdot 0.16666666666666666, 0.5\right), x\right), 1\right)} \]
                    5. Step-by-step derivation
                      1. Applied rewrites62.3%

                        \[\leadsto \frac{1}{\color{blue}{\frac{1}{\mathsf{fma}\left(y \cdot y, \mathsf{fma}\left(x \cdot \left(y \cdot y\right), x \cdot \mathsf{fma}\left(x, \left(y \cdot y\right) \cdot 0.16666666666666666, 0.5\right), x\right), 1\right)}}} \]
                      2. Taylor expanded in y around 0

                        \[\leadsto \frac{1}{1 + \color{blue}{{y}^{2} \cdot \left(-1 \cdot \left({y}^{2} \cdot \left(-1 \cdot {x}^{2} + \frac{1}{2} \cdot {x}^{2}\right)\right) - x\right)}} \]
                      3. Step-by-step derivation
                        1. Applied rewrites93.9%

                          \[\leadsto \frac{1}{\mathsf{fma}\left(y \cdot y, \color{blue}{x \cdot \mathsf{fma}\left(x, \left(y \cdot y\right) \cdot 0.5, -1\right)}, 1\right)} \]

                        if 2.0000000000000001e-202 < (*.f64 (*.f64 x y) y)

                        1. Initial program 100.0%

                          \[e^{\left(x \cdot y\right) \cdot y} \]
                        2. Add Preprocessing
                        3. Taylor expanded in x around 0

                          \[\leadsto \color{blue}{1 + x \cdot \left(x \cdot \left(\frac{1}{6} \cdot \left(x \cdot {y}^{6}\right) + \frac{1}{2} \cdot {y}^{4}\right) + {y}^{2}\right)} \]
                        4. Applied rewrites95.3%

                          \[\leadsto \color{blue}{\mathsf{fma}\left(y \cdot y, \mathsf{fma}\left(x \cdot \left(x \cdot \left(y \cdot y\right)\right), \mathsf{fma}\left(x, \left(y \cdot y\right) \cdot 0.16666666666666666, 0.5\right), x\right), 1\right)} \]
                        5. Step-by-step derivation
                          1. Applied rewrites96.6%

                            \[\leadsto \mathsf{fma}\left(y \cdot y, \mathsf{fma}\left(\left(x \cdot \left(x \cdot y\right)\right) \cdot y, \mathsf{fma}\left(\color{blue}{x}, \left(y \cdot y\right) \cdot 0.16666666666666666, 0.5\right), x\right), 1\right) \]
                        6. Recombined 2 regimes into one program.
                        7. Final simplification94.7%

                          \[\leadsto \begin{array}{l} \mathbf{if}\;y \cdot \left(x \cdot y\right) \leq 2 \cdot 10^{-202}:\\ \;\;\;\;\frac{1}{\mathsf{fma}\left(y \cdot y, x \cdot \mathsf{fma}\left(x, 0.5 \cdot \left(y \cdot y\right), -1\right), 1\right)}\\ \mathbf{else}:\\ \;\;\;\;\mathsf{fma}\left(y \cdot y, \mathsf{fma}\left(y \cdot \left(x \cdot \left(x \cdot y\right)\right), \mathsf{fma}\left(x, 0.16666666666666666 \cdot \left(y \cdot y\right), 0.5\right), x\right), 1\right)\\ \end{array} \]
                        8. Add Preprocessing

                        Alternative 7: 93.0% accurate, 1.8× speedup?

                        \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;y \cdot \left(x \cdot y\right) \leq 2:\\ \;\;\;\;\frac{1}{\mathsf{fma}\left(y \cdot y, x \cdot \mathsf{fma}\left(x, 0.5 \cdot \left(y \cdot y\right), -1\right), 1\right)}\\ \mathbf{else}:\\ \;\;\;\;\mathsf{fma}\left(y \cdot y, \left(y \cdot y\right) \cdot \left(0.16666666666666666 \cdot \left(x \cdot \left(x \cdot \left(x \cdot \left(y \cdot y\right)\right)\right)\right)\right), 1\right)\\ \end{array} \end{array} \]
                        (FPCore (x y)
                         :precision binary64
                         (if (<= (* y (* x y)) 2.0)
                           (/ 1.0 (fma (* y y) (* x (fma x (* 0.5 (* y y)) -1.0)) 1.0))
                           (fma
                            (* y y)
                            (* (* y y) (* 0.16666666666666666 (* x (* x (* x (* y y))))))
                            1.0)))
                        double code(double x, double y) {
                        	double tmp;
                        	if ((y * (x * y)) <= 2.0) {
                        		tmp = 1.0 / fma((y * y), (x * fma(x, (0.5 * (y * y)), -1.0)), 1.0);
                        	} else {
                        		tmp = fma((y * y), ((y * y) * (0.16666666666666666 * (x * (x * (x * (y * y)))))), 1.0);
                        	}
                        	return tmp;
                        }
                        
                        function code(x, y)
                        	tmp = 0.0
                        	if (Float64(y * Float64(x * y)) <= 2.0)
                        		tmp = Float64(1.0 / fma(Float64(y * y), Float64(x * fma(x, Float64(0.5 * Float64(y * y)), -1.0)), 1.0));
                        	else
                        		tmp = fma(Float64(y * y), Float64(Float64(y * y) * Float64(0.16666666666666666 * Float64(x * Float64(x * Float64(x * Float64(y * y)))))), 1.0);
                        	end
                        	return tmp
                        end
                        
                        code[x_, y_] := If[LessEqual[N[(y * N[(x * y), $MachinePrecision]), $MachinePrecision], 2.0], N[(1.0 / N[(N[(y * y), $MachinePrecision] * N[(x * N[(x * N[(0.5 * N[(y * y), $MachinePrecision]), $MachinePrecision] + -1.0), $MachinePrecision]), $MachinePrecision] + 1.0), $MachinePrecision]), $MachinePrecision], N[(N[(y * y), $MachinePrecision] * N[(N[(y * y), $MachinePrecision] * N[(0.16666666666666666 * N[(x * N[(x * N[(x * N[(y * y), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] + 1.0), $MachinePrecision]]
                        
                        \begin{array}{l}
                        
                        \\
                        \begin{array}{l}
                        \mathbf{if}\;y \cdot \left(x \cdot y\right) \leq 2:\\
                        \;\;\;\;\frac{1}{\mathsf{fma}\left(y \cdot y, x \cdot \mathsf{fma}\left(x, 0.5 \cdot \left(y \cdot y\right), -1\right), 1\right)}\\
                        
                        \mathbf{else}:\\
                        \;\;\;\;\mathsf{fma}\left(y \cdot y, \left(y \cdot y\right) \cdot \left(0.16666666666666666 \cdot \left(x \cdot \left(x \cdot \left(x \cdot \left(y \cdot y\right)\right)\right)\right)\right), 1\right)\\
                        
                        
                        \end{array}
                        \end{array}
                        
                        Derivation
                        1. Split input into 2 regimes
                        2. if (*.f64 (*.f64 x y) y) < 2

                          1. Initial program 100.0%

                            \[e^{\left(x \cdot y\right) \cdot y} \]
                          2. Add Preprocessing
                          3. Taylor expanded in x around 0

                            \[\leadsto \color{blue}{1 + x \cdot \left(x \cdot \left(\frac{1}{6} \cdot \left(x \cdot {y}^{6}\right) + \frac{1}{2} \cdot {y}^{4}\right) + {y}^{2}\right)} \]
                          4. Applied rewrites65.2%

                            \[\leadsto \color{blue}{\mathsf{fma}\left(y \cdot y, \mathsf{fma}\left(x \cdot \left(x \cdot \left(y \cdot y\right)\right), \mathsf{fma}\left(x, \left(y \cdot y\right) \cdot 0.16666666666666666, 0.5\right), x\right), 1\right)} \]
                          5. Step-by-step derivation
                            1. Applied rewrites65.2%

                              \[\leadsto \frac{1}{\color{blue}{\frac{1}{\mathsf{fma}\left(y \cdot y, \mathsf{fma}\left(x \cdot \left(y \cdot y\right), x \cdot \mathsf{fma}\left(x, \left(y \cdot y\right) \cdot 0.16666666666666666, 0.5\right), x\right), 1\right)}}} \]
                            2. Taylor expanded in y around 0

                              \[\leadsto \frac{1}{1 + \color{blue}{{y}^{2} \cdot \left(-1 \cdot \left({y}^{2} \cdot \left(-1 \cdot {x}^{2} + \frac{1}{2} \cdot {x}^{2}\right)\right) - x\right)}} \]
                            3. Step-by-step derivation
                              1. Applied rewrites94.0%

                                \[\leadsto \frac{1}{\mathsf{fma}\left(y \cdot y, \color{blue}{x \cdot \mathsf{fma}\left(x, \left(y \cdot y\right) \cdot 0.5, -1\right)}, 1\right)} \]

                              if 2 < (*.f64 (*.f64 x y) y)

                              1. Initial program 100.0%

                                \[e^{\left(x \cdot y\right) \cdot y} \]
                              2. Add Preprocessing
                              3. Taylor expanded in x around 0

                                \[\leadsto \color{blue}{1 + x \cdot \left(x \cdot \left(\frac{1}{6} \cdot \left(x \cdot {y}^{6}\right) + \frac{1}{2} \cdot {y}^{4}\right) + {y}^{2}\right)} \]
                              4. Applied rewrites95.3%

                                \[\leadsto \color{blue}{\mathsf{fma}\left(y \cdot y, \mathsf{fma}\left(x \cdot \left(x \cdot \left(y \cdot y\right)\right), \mathsf{fma}\left(x, \left(y \cdot y\right) \cdot 0.16666666666666666, 0.5\right), x\right), 1\right)} \]
                              5. Taylor expanded in x around inf

                                \[\leadsto \mathsf{fma}\left(y \cdot y, \frac{1}{6} \cdot \color{blue}{\left({x}^{3} \cdot {y}^{4}\right)}, 1\right) \]
                              6. Step-by-step derivation
                                1. Applied rewrites96.8%

                                  \[\leadsto \mathsf{fma}\left(y \cdot y, \left(y \cdot y\right) \cdot \color{blue}{\left(0.16666666666666666 \cdot \left(x \cdot \left(x \cdot \left(x \cdot \left(y \cdot y\right)\right)\right)\right)\right)}, 1\right) \]
                              7. Recombined 2 regimes into one program.
                              8. Final simplification94.7%

                                \[\leadsto \begin{array}{l} \mathbf{if}\;y \cdot \left(x \cdot y\right) \leq 2:\\ \;\;\;\;\frac{1}{\mathsf{fma}\left(y \cdot y, x \cdot \mathsf{fma}\left(x, 0.5 \cdot \left(y \cdot y\right), -1\right), 1\right)}\\ \mathbf{else}:\\ \;\;\;\;\mathsf{fma}\left(y \cdot y, \left(y \cdot y\right) \cdot \left(0.16666666666666666 \cdot \left(x \cdot \left(x \cdot \left(x \cdot \left(y \cdot y\right)\right)\right)\right)\right), 1\right)\\ \end{array} \]
                              9. Add Preprocessing

                              Alternative 8: 91.5% accurate, 1.8× speedup?

                              \[\begin{array}{l} \\ \begin{array}{l} t_0 := 0.5 \cdot \left(y \cdot y\right)\\ \mathbf{if}\;y \cdot \left(x \cdot y\right) \leq 50000:\\ \;\;\;\;\frac{1}{\mathsf{fma}\left(y \cdot y, x \cdot \mathsf{fma}\left(x, t\_0, -1\right), 1\right)}\\ \mathbf{else}:\\ \;\;\;\;\left(x \cdot \left(x \cdot y\right)\right) \cdot \left(y \cdot t\_0\right)\\ \end{array} \end{array} \]
                              (FPCore (x y)
                               :precision binary64
                               (let* ((t_0 (* 0.5 (* y y))))
                                 (if (<= (* y (* x y)) 50000.0)
                                   (/ 1.0 (fma (* y y) (* x (fma x t_0 -1.0)) 1.0))
                                   (* (* x (* x y)) (* y t_0)))))
                              double code(double x, double y) {
                              	double t_0 = 0.5 * (y * y);
                              	double tmp;
                              	if ((y * (x * y)) <= 50000.0) {
                              		tmp = 1.0 / fma((y * y), (x * fma(x, t_0, -1.0)), 1.0);
                              	} else {
                              		tmp = (x * (x * y)) * (y * t_0);
                              	}
                              	return tmp;
                              }
                              
                              function code(x, y)
                              	t_0 = Float64(0.5 * Float64(y * y))
                              	tmp = 0.0
                              	if (Float64(y * Float64(x * y)) <= 50000.0)
                              		tmp = Float64(1.0 / fma(Float64(y * y), Float64(x * fma(x, t_0, -1.0)), 1.0));
                              	else
                              		tmp = Float64(Float64(x * Float64(x * y)) * Float64(y * t_0));
                              	end
                              	return tmp
                              end
                              
                              code[x_, y_] := Block[{t$95$0 = N[(0.5 * N[(y * y), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[N[(y * N[(x * y), $MachinePrecision]), $MachinePrecision], 50000.0], N[(1.0 / N[(N[(y * y), $MachinePrecision] * N[(x * N[(x * t$95$0 + -1.0), $MachinePrecision]), $MachinePrecision] + 1.0), $MachinePrecision]), $MachinePrecision], N[(N[(x * N[(x * y), $MachinePrecision]), $MachinePrecision] * N[(y * t$95$0), $MachinePrecision]), $MachinePrecision]]]
                              
                              \begin{array}{l}
                              
                              \\
                              \begin{array}{l}
                              t_0 := 0.5 \cdot \left(y \cdot y\right)\\
                              \mathbf{if}\;y \cdot \left(x \cdot y\right) \leq 50000:\\
                              \;\;\;\;\frac{1}{\mathsf{fma}\left(y \cdot y, x \cdot \mathsf{fma}\left(x, t\_0, -1\right), 1\right)}\\
                              
                              \mathbf{else}:\\
                              \;\;\;\;\left(x \cdot \left(x \cdot y\right)\right) \cdot \left(y \cdot t\_0\right)\\
                              
                              
                              \end{array}
                              \end{array}
                              
                              Derivation
                              1. Split input into 2 regimes
                              2. if (*.f64 (*.f64 x y) y) < 5e4

                                1. Initial program 100.0%

                                  \[e^{\left(x \cdot y\right) \cdot y} \]
                                2. Add Preprocessing
                                3. Taylor expanded in x around 0

                                  \[\leadsto \color{blue}{1 + x \cdot \left(x \cdot \left(\frac{1}{6} \cdot \left(x \cdot {y}^{6}\right) + \frac{1}{2} \cdot {y}^{4}\right) + {y}^{2}\right)} \]
                                4. Applied rewrites64.9%

                                  \[\leadsto \color{blue}{\mathsf{fma}\left(y \cdot y, \mathsf{fma}\left(x \cdot \left(x \cdot \left(y \cdot y\right)\right), \mathsf{fma}\left(x, \left(y \cdot y\right) \cdot 0.16666666666666666, 0.5\right), x\right), 1\right)} \]
                                5. Step-by-step derivation
                                  1. Applied rewrites64.9%

                                    \[\leadsto \frac{1}{\color{blue}{\frac{1}{\mathsf{fma}\left(y \cdot y, \mathsf{fma}\left(x \cdot \left(y \cdot y\right), x \cdot \mathsf{fma}\left(x, \left(y \cdot y\right) \cdot 0.16666666666666666, 0.5\right), x\right), 1\right)}}} \]
                                  2. Taylor expanded in y around 0

                                    \[\leadsto \frac{1}{1 + \color{blue}{{y}^{2} \cdot \left(-1 \cdot \left({y}^{2} \cdot \left(-1 \cdot {x}^{2} + \frac{1}{2} \cdot {x}^{2}\right)\right) - x\right)}} \]
                                  3. Step-by-step derivation
                                    1. Applied rewrites93.5%

                                      \[\leadsto \frac{1}{\mathsf{fma}\left(y \cdot y, \color{blue}{x \cdot \mathsf{fma}\left(x, \left(y \cdot y\right) \cdot 0.5, -1\right)}, 1\right)} \]

                                    if 5e4 < (*.f64 (*.f64 x y) y)

                                    1. Initial program 100.0%

                                      \[e^{\left(x \cdot y\right) \cdot y} \]
                                    2. Add Preprocessing
                                    3. Taylor expanded in x around 0

                                      \[\leadsto \color{blue}{1 + x \cdot \left(\frac{1}{2} \cdot \left(x \cdot {y}^{4}\right) + {y}^{2}\right)} \]
                                    4. Step-by-step derivation
                                      1. +-commutativeN/A

                                        \[\leadsto \color{blue}{x \cdot \left(\frac{1}{2} \cdot \left(x \cdot {y}^{4}\right) + {y}^{2}\right) + 1} \]
                                    5. Applied rewrites88.9%

                                      \[\leadsto \color{blue}{\mathsf{fma}\left(y \cdot y, \mathsf{fma}\left(x, \left(x \cdot \left(y \cdot y\right)\right) \cdot 0.5, x\right), 1\right)} \]
                                    6. Taylor expanded in y around inf

                                      \[\leadsto \frac{1}{2} \cdot \color{blue}{\left({x}^{2} \cdot {y}^{4}\right)} \]
                                    7. Step-by-step derivation
                                      1. Applied rewrites88.9%

                                        \[\leadsto \left(0.5 \cdot \left(y \cdot y\right)\right) \cdot \color{blue}{\left(x \cdot \left(x \cdot \left(y \cdot y\right)\right)\right)} \]
                                      2. Step-by-step derivation
                                        1. Applied rewrites95.2%

                                          \[\leadsto \left(\left(\left(y \cdot y\right) \cdot 0.5\right) \cdot y\right) \cdot \left(x \cdot \color{blue}{\left(y \cdot x\right)}\right) \]
                                      3. Recombined 2 regimes into one program.
                                      4. Final simplification93.9%

                                        \[\leadsto \begin{array}{l} \mathbf{if}\;y \cdot \left(x \cdot y\right) \leq 50000:\\ \;\;\;\;\frac{1}{\mathsf{fma}\left(y \cdot y, x \cdot \mathsf{fma}\left(x, 0.5 \cdot \left(y \cdot y\right), -1\right), 1\right)}\\ \mathbf{else}:\\ \;\;\;\;\left(x \cdot \left(x \cdot y\right)\right) \cdot \left(y \cdot \left(0.5 \cdot \left(y \cdot y\right)\right)\right)\\ \end{array} \]
                                      5. Add Preprocessing

                                      Alternative 9: 84.8% accurate, 2.0× speedup?

                                      \[\begin{array}{l} \\ \begin{array}{l} t_0 := y \cdot \left(x \cdot y\right)\\ \mathbf{if}\;t\_0 \leq -2 \cdot 10^{+19}:\\ \;\;\;\;\frac{1}{-x \cdot \left(y \cdot y\right)}\\ \mathbf{elif}\;t\_0 \leq 2:\\ \;\;\;\;\mathsf{fma}\left(x, y \cdot y, 1\right)\\ \mathbf{else}:\\ \;\;\;\;\mathsf{fma}\left(x, \mathsf{fma}\left(x, 0.5 \cdot \left(y \cdot y\right), y\right), 1\right)\\ \end{array} \end{array} \]
                                      (FPCore (x y)
                                       :precision binary64
                                       (let* ((t_0 (* y (* x y))))
                                         (if (<= t_0 -2e+19)
                                           (/ 1.0 (- (* x (* y y))))
                                           (if (<= t_0 2.0)
                                             (fma x (* y y) 1.0)
                                             (fma x (fma x (* 0.5 (* y y)) y) 1.0)))))
                                      double code(double x, double y) {
                                      	double t_0 = y * (x * y);
                                      	double tmp;
                                      	if (t_0 <= -2e+19) {
                                      		tmp = 1.0 / -(x * (y * y));
                                      	} else if (t_0 <= 2.0) {
                                      		tmp = fma(x, (y * y), 1.0);
                                      	} else {
                                      		tmp = fma(x, fma(x, (0.5 * (y * y)), y), 1.0);
                                      	}
                                      	return tmp;
                                      }
                                      
                                      function code(x, y)
                                      	t_0 = Float64(y * Float64(x * y))
                                      	tmp = 0.0
                                      	if (t_0 <= -2e+19)
                                      		tmp = Float64(1.0 / Float64(-Float64(x * Float64(y * y))));
                                      	elseif (t_0 <= 2.0)
                                      		tmp = fma(x, Float64(y * y), 1.0);
                                      	else
                                      		tmp = fma(x, fma(x, Float64(0.5 * Float64(y * y)), y), 1.0);
                                      	end
                                      	return tmp
                                      end
                                      
                                      code[x_, y_] := Block[{t$95$0 = N[(y * N[(x * y), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[t$95$0, -2e+19], N[(1.0 / (-N[(x * N[(y * y), $MachinePrecision]), $MachinePrecision])), $MachinePrecision], If[LessEqual[t$95$0, 2.0], N[(x * N[(y * y), $MachinePrecision] + 1.0), $MachinePrecision], N[(x * N[(x * N[(0.5 * N[(y * y), $MachinePrecision]), $MachinePrecision] + y), $MachinePrecision] + 1.0), $MachinePrecision]]]]
                                      
                                      \begin{array}{l}
                                      
                                      \\
                                      \begin{array}{l}
                                      t_0 := y \cdot \left(x \cdot y\right)\\
                                      \mathbf{if}\;t\_0 \leq -2 \cdot 10^{+19}:\\
                                      \;\;\;\;\frac{1}{-x \cdot \left(y \cdot y\right)}\\
                                      
                                      \mathbf{elif}\;t\_0 \leq 2:\\
                                      \;\;\;\;\mathsf{fma}\left(x, y \cdot y, 1\right)\\
                                      
                                      \mathbf{else}:\\
                                      \;\;\;\;\mathsf{fma}\left(x, \mathsf{fma}\left(x, 0.5 \cdot \left(y \cdot y\right), y\right), 1\right)\\
                                      
                                      
                                      \end{array}
                                      \end{array}
                                      
                                      Derivation
                                      1. Split input into 3 regimes
                                      2. if (*.f64 (*.f64 x y) y) < -2e19

                                        1. Initial program 100.0%

                                          \[e^{\left(x \cdot y\right) \cdot y} \]
                                        2. Add Preprocessing
                                        3. Taylor expanded in x around 0

                                          \[\leadsto \color{blue}{1 + x \cdot \left(x \cdot \left(\frac{1}{6} \cdot \left(x \cdot {y}^{6}\right) + \frac{1}{2} \cdot {y}^{4}\right) + {y}^{2}\right)} \]
                                        4. Applied rewrites1.6%

                                          \[\leadsto \color{blue}{\mathsf{fma}\left(y \cdot y, \mathsf{fma}\left(x \cdot \left(x \cdot \left(y \cdot y\right)\right), \mathsf{fma}\left(x, \left(y \cdot y\right) \cdot 0.16666666666666666, 0.5\right), x\right), 1\right)} \]
                                        5. Step-by-step derivation
                                          1. Applied rewrites1.6%

                                            \[\leadsto \frac{1}{\color{blue}{\frac{1}{\mathsf{fma}\left(y \cdot y, \mathsf{fma}\left(x \cdot \left(y \cdot y\right), x \cdot \mathsf{fma}\left(x, \left(y \cdot y\right) \cdot 0.16666666666666666, 0.5\right), x\right), 1\right)}}} \]
                                          2. Taylor expanded in y around 0

                                            \[\leadsto \frac{1}{1 + \color{blue}{-1 \cdot \left(x \cdot {y}^{2}\right)}} \]
                                          3. Step-by-step derivation
                                            1. Applied rewrites67.8%

                                              \[\leadsto \frac{1}{1 - \color{blue}{x \cdot \left(y \cdot y\right)}} \]
                                            2. Taylor expanded in x around inf

                                              \[\leadsto \frac{1}{-1 \cdot \left(x \cdot \color{blue}{{y}^{2}}\right)} \]
                                            3. Step-by-step derivation
                                              1. Applied rewrites67.8%

                                                \[\leadsto \frac{1}{-x \cdot \left(y \cdot y\right)} \]

                                              if -2e19 < (*.f64 (*.f64 x y) y) < 2

                                              1. Initial program 100.0%

                                                \[e^{\left(x \cdot y\right) \cdot y} \]
                                              2. Add Preprocessing
                                              3. Taylor expanded in x around 0

                                                \[\leadsto \color{blue}{1 + x \cdot {y}^{2}} \]
                                              4. Step-by-step derivation
                                                1. +-commutativeN/A

                                                  \[\leadsto \color{blue}{x \cdot {y}^{2} + 1} \]
                                                2. lower-fma.f64N/A

                                                  \[\leadsto \color{blue}{\mathsf{fma}\left(x, {y}^{2}, 1\right)} \]
                                                3. unpow2N/A

                                                  \[\leadsto \mathsf{fma}\left(x, \color{blue}{y \cdot y}, 1\right) \]
                                                4. lower-*.f6498.9

                                                  \[\leadsto \mathsf{fma}\left(x, \color{blue}{y \cdot y}, 1\right) \]
                                              5. Applied rewrites98.9%

                                                \[\leadsto \color{blue}{\mathsf{fma}\left(x, y \cdot y, 1\right)} \]

                                              if 2 < (*.f64 (*.f64 x y) y)

                                              1. Initial program 100.0%

                                                \[e^{\left(x \cdot y\right) \cdot y} \]
                                              2. Add Preprocessing
                                              3. Applied rewrites58.2%

                                                \[\leadsto e^{\color{blue}{x} \cdot y} \]
                                              4. Taylor expanded in x around 0

                                                \[\leadsto \color{blue}{1 + x \cdot \left(y + \frac{1}{2} \cdot \left(x \cdot {y}^{2}\right)\right)} \]
                                              5. Step-by-step derivation
                                                1. +-commutativeN/A

                                                  \[\leadsto \color{blue}{x \cdot \left(y + \frac{1}{2} \cdot \left(x \cdot {y}^{2}\right)\right) + 1} \]
                                                2. +-commutativeN/A

                                                  \[\leadsto x \cdot \color{blue}{\left(\frac{1}{2} \cdot \left(x \cdot {y}^{2}\right) + y\right)} + 1 \]
                                                3. *-commutativeN/A

                                                  \[\leadsto x \cdot \left(\frac{1}{2} \cdot \color{blue}{\left({y}^{2} \cdot x\right)} + y\right) + 1 \]
                                                4. associate-*r*N/A

                                                  \[\leadsto x \cdot \left(\color{blue}{\left(\frac{1}{2} \cdot {y}^{2}\right) \cdot x} + y\right) + 1 \]
                                                5. lower-fma.f64N/A

                                                  \[\leadsto \color{blue}{\mathsf{fma}\left(x, \left(\frac{1}{2} \cdot {y}^{2}\right) \cdot x + y, 1\right)} \]
                                                6. *-commutativeN/A

                                                  \[\leadsto \mathsf{fma}\left(x, \color{blue}{x \cdot \left(\frac{1}{2} \cdot {y}^{2}\right)} + y, 1\right) \]
                                                7. lower-fma.f64N/A

                                                  \[\leadsto \mathsf{fma}\left(x, \color{blue}{\mathsf{fma}\left(x, \frac{1}{2} \cdot {y}^{2}, y\right)}, 1\right) \]
                                                8. lower-*.f64N/A

                                                  \[\leadsto \mathsf{fma}\left(x, \mathsf{fma}\left(x, \color{blue}{\frac{1}{2} \cdot {y}^{2}}, y\right), 1\right) \]
                                                9. unpow2N/A

                                                  \[\leadsto \mathsf{fma}\left(x, \mathsf{fma}\left(x, \frac{1}{2} \cdot \color{blue}{\left(y \cdot y\right)}, y\right), 1\right) \]
                                                10. lower-*.f6484.6

                                                  \[\leadsto \mathsf{fma}\left(x, \mathsf{fma}\left(x, 0.5 \cdot \color{blue}{\left(y \cdot y\right)}, y\right), 1\right) \]
                                              6. Applied rewrites84.6%

                                                \[\leadsto \color{blue}{\mathsf{fma}\left(x, \mathsf{fma}\left(x, 0.5 \cdot \left(y \cdot y\right), y\right), 1\right)} \]
                                            4. Recombined 3 regimes into one program.
                                            5. Final simplification87.2%

                                              \[\leadsto \begin{array}{l} \mathbf{if}\;y \cdot \left(x \cdot y\right) \leq -2 \cdot 10^{+19}:\\ \;\;\;\;\frac{1}{-x \cdot \left(y \cdot y\right)}\\ \mathbf{elif}\;y \cdot \left(x \cdot y\right) \leq 2:\\ \;\;\;\;\mathsf{fma}\left(x, y \cdot y, 1\right)\\ \mathbf{else}:\\ \;\;\;\;\mathsf{fma}\left(x, \mathsf{fma}\left(x, 0.5 \cdot \left(y \cdot y\right), y\right), 1\right)\\ \end{array} \]
                                            6. Add Preprocessing

                                            Alternative 10: 86.6% accurate, 2.4× speedup?

                                            \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;y \cdot \left(x \cdot y\right) \leq 10^{-8}:\\ \;\;\;\;\frac{1}{1 - x \cdot \left(y \cdot y\right)}\\ \mathbf{else}:\\ \;\;\;\;\left(x \cdot \left(x \cdot y\right)\right) \cdot \left(y \cdot \left(0.5 \cdot \left(y \cdot y\right)\right)\right)\\ \end{array} \end{array} \]
                                            (FPCore (x y)
                                             :precision binary64
                                             (if (<= (* y (* x y)) 1e-8)
                                               (/ 1.0 (- 1.0 (* x (* y y))))
                                               (* (* x (* x y)) (* y (* 0.5 (* y y))))))
                                            double code(double x, double y) {
                                            	double tmp;
                                            	if ((y * (x * y)) <= 1e-8) {
                                            		tmp = 1.0 / (1.0 - (x * (y * y)));
                                            	} else {
                                            		tmp = (x * (x * y)) * (y * (0.5 * (y * y)));
                                            	}
                                            	return tmp;
                                            }
                                            
                                            real(8) function code(x, y)
                                                real(8), intent (in) :: x
                                                real(8), intent (in) :: y
                                                real(8) :: tmp
                                                if ((y * (x * y)) <= 1d-8) then
                                                    tmp = 1.0d0 / (1.0d0 - (x * (y * y)))
                                                else
                                                    tmp = (x * (x * y)) * (y * (0.5d0 * (y * y)))
                                                end if
                                                code = tmp
                                            end function
                                            
                                            public static double code(double x, double y) {
                                            	double tmp;
                                            	if ((y * (x * y)) <= 1e-8) {
                                            		tmp = 1.0 / (1.0 - (x * (y * y)));
                                            	} else {
                                            		tmp = (x * (x * y)) * (y * (0.5 * (y * y)));
                                            	}
                                            	return tmp;
                                            }
                                            
                                            def code(x, y):
                                            	tmp = 0
                                            	if (y * (x * y)) <= 1e-8:
                                            		tmp = 1.0 / (1.0 - (x * (y * y)))
                                            	else:
                                            		tmp = (x * (x * y)) * (y * (0.5 * (y * y)))
                                            	return tmp
                                            
                                            function code(x, y)
                                            	tmp = 0.0
                                            	if (Float64(y * Float64(x * y)) <= 1e-8)
                                            		tmp = Float64(1.0 / Float64(1.0 - Float64(x * Float64(y * y))));
                                            	else
                                            		tmp = Float64(Float64(x * Float64(x * y)) * Float64(y * Float64(0.5 * Float64(y * y))));
                                            	end
                                            	return tmp
                                            end
                                            
                                            function tmp_2 = code(x, y)
                                            	tmp = 0.0;
                                            	if ((y * (x * y)) <= 1e-8)
                                            		tmp = 1.0 / (1.0 - (x * (y * y)));
                                            	else
                                            		tmp = (x * (x * y)) * (y * (0.5 * (y * y)));
                                            	end
                                            	tmp_2 = tmp;
                                            end
                                            
                                            code[x_, y_] := If[LessEqual[N[(y * N[(x * y), $MachinePrecision]), $MachinePrecision], 1e-8], N[(1.0 / N[(1.0 - N[(x * N[(y * y), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], N[(N[(x * N[(x * y), $MachinePrecision]), $MachinePrecision] * N[(y * N[(0.5 * N[(y * y), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]]
                                            
                                            \begin{array}{l}
                                            
                                            \\
                                            \begin{array}{l}
                                            \mathbf{if}\;y \cdot \left(x \cdot y\right) \leq 10^{-8}:\\
                                            \;\;\;\;\frac{1}{1 - x \cdot \left(y \cdot y\right)}\\
                                            
                                            \mathbf{else}:\\
                                            \;\;\;\;\left(x \cdot \left(x \cdot y\right)\right) \cdot \left(y \cdot \left(0.5 \cdot \left(y \cdot y\right)\right)\right)\\
                                            
                                            
                                            \end{array}
                                            \end{array}
                                            
                                            Derivation
                                            1. Split input into 2 regimes
                                            2. if (*.f64 (*.f64 x y) y) < 1e-8

                                              1. Initial program 100.0%

                                                \[e^{\left(x \cdot y\right) \cdot y} \]
                                              2. Add Preprocessing
                                              3. Taylor expanded in x around 0

                                                \[\leadsto \color{blue}{1 + x \cdot \left(x \cdot \left(\frac{1}{6} \cdot \left(x \cdot {y}^{6}\right) + \frac{1}{2} \cdot {y}^{4}\right) + {y}^{2}\right)} \]
                                              4. Applied rewrites65.4%

                                                \[\leadsto \color{blue}{\mathsf{fma}\left(y \cdot y, \mathsf{fma}\left(x \cdot \left(x \cdot \left(y \cdot y\right)\right), \mathsf{fma}\left(x, \left(y \cdot y\right) \cdot 0.16666666666666666, 0.5\right), x\right), 1\right)} \]
                                              5. Step-by-step derivation
                                                1. Applied rewrites65.4%

                                                  \[\leadsto \frac{1}{\color{blue}{\frac{1}{\mathsf{fma}\left(y \cdot y, \mathsf{fma}\left(x \cdot \left(y \cdot y\right), x \cdot \mathsf{fma}\left(x, \left(y \cdot y\right) \cdot 0.16666666666666666, 0.5\right), x\right), 1\right)}}} \]
                                                2. Taylor expanded in y around 0

                                                  \[\leadsto \frac{1}{1 + \color{blue}{-1 \cdot \left(x \cdot {y}^{2}\right)}} \]
                                                3. Step-by-step derivation
                                                  1. Applied rewrites88.4%

                                                    \[\leadsto \frac{1}{1 - \color{blue}{x \cdot \left(y \cdot y\right)}} \]

                                                  if 1e-8 < (*.f64 (*.f64 x y) y)

                                                  1. Initial program 100.0%

                                                    \[e^{\left(x \cdot y\right) \cdot y} \]
                                                  2. Add Preprocessing
                                                  3. Taylor expanded in x around 0

                                                    \[\leadsto \color{blue}{1 + x \cdot \left(\frac{1}{2} \cdot \left(x \cdot {y}^{4}\right) + {y}^{2}\right)} \]
                                                  4. Step-by-step derivation
                                                    1. +-commutativeN/A

                                                      \[\leadsto \color{blue}{x \cdot \left(\frac{1}{2} \cdot \left(x \cdot {y}^{4}\right) + {y}^{2}\right) + 1} \]
                                                  5. Applied rewrites86.4%

                                                    \[\leadsto \color{blue}{\mathsf{fma}\left(y \cdot y, \mathsf{fma}\left(x, \left(x \cdot \left(y \cdot y\right)\right) \cdot 0.5, x\right), 1\right)} \]
                                                  6. Taylor expanded in y around inf

                                                    \[\leadsto \frac{1}{2} \cdot \color{blue}{\left({x}^{2} \cdot {y}^{4}\right)} \]
                                                  7. Step-by-step derivation
                                                    1. Applied rewrites86.4%

                                                      \[\leadsto \left(0.5 \cdot \left(y \cdot y\right)\right) \cdot \color{blue}{\left(x \cdot \left(x \cdot \left(y \cdot y\right)\right)\right)} \]
                                                    2. Step-by-step derivation
                                                      1. Applied rewrites92.4%

                                                        \[\leadsto \left(\left(\left(y \cdot y\right) \cdot 0.5\right) \cdot y\right) \cdot \left(x \cdot \color{blue}{\left(y \cdot x\right)}\right) \]
                                                    3. Recombined 2 regimes into one program.
                                                    4. Final simplification89.4%

                                                      \[\leadsto \begin{array}{l} \mathbf{if}\;y \cdot \left(x \cdot y\right) \leq 10^{-8}:\\ \;\;\;\;\frac{1}{1 - x \cdot \left(y \cdot y\right)}\\ \mathbf{else}:\\ \;\;\;\;\left(x \cdot \left(x \cdot y\right)\right) \cdot \left(y \cdot \left(0.5 \cdot \left(y \cdot y\right)\right)\right)\\ \end{array} \]
                                                    5. Add Preprocessing

                                                    Alternative 11: 75.7% accurate, 2.4× speedup?

                                                    \[\begin{array}{l} \\ \begin{array}{l} t_0 := x \cdot \left(y \cdot y\right)\\ \mathbf{if}\;y \cdot \left(x \cdot y\right) \leq 10^{-8}:\\ \;\;\;\;\frac{1}{1 - t\_0}\\ \mathbf{else}:\\ \;\;\;\;x \cdot \left(x \cdot \left(0.16666666666666666 \cdot \left(y \cdot t\_0\right)\right)\right)\\ \end{array} \end{array} \]
                                                    (FPCore (x y)
                                                     :precision binary64
                                                     (let* ((t_0 (* x (* y y))))
                                                       (if (<= (* y (* x y)) 1e-8)
                                                         (/ 1.0 (- 1.0 t_0))
                                                         (* x (* x (* 0.16666666666666666 (* y t_0)))))))
                                                    double code(double x, double y) {
                                                    	double t_0 = x * (y * y);
                                                    	double tmp;
                                                    	if ((y * (x * y)) <= 1e-8) {
                                                    		tmp = 1.0 / (1.0 - t_0);
                                                    	} else {
                                                    		tmp = x * (x * (0.16666666666666666 * (y * t_0)));
                                                    	}
                                                    	return tmp;
                                                    }
                                                    
                                                    real(8) function code(x, y)
                                                        real(8), intent (in) :: x
                                                        real(8), intent (in) :: y
                                                        real(8) :: t_0
                                                        real(8) :: tmp
                                                        t_0 = x * (y * y)
                                                        if ((y * (x * y)) <= 1d-8) then
                                                            tmp = 1.0d0 / (1.0d0 - t_0)
                                                        else
                                                            tmp = x * (x * (0.16666666666666666d0 * (y * t_0)))
                                                        end if
                                                        code = tmp
                                                    end function
                                                    
                                                    public static double code(double x, double y) {
                                                    	double t_0 = x * (y * y);
                                                    	double tmp;
                                                    	if ((y * (x * y)) <= 1e-8) {
                                                    		tmp = 1.0 / (1.0 - t_0);
                                                    	} else {
                                                    		tmp = x * (x * (0.16666666666666666 * (y * t_0)));
                                                    	}
                                                    	return tmp;
                                                    }
                                                    
                                                    def code(x, y):
                                                    	t_0 = x * (y * y)
                                                    	tmp = 0
                                                    	if (y * (x * y)) <= 1e-8:
                                                    		tmp = 1.0 / (1.0 - t_0)
                                                    	else:
                                                    		tmp = x * (x * (0.16666666666666666 * (y * t_0)))
                                                    	return tmp
                                                    
                                                    function code(x, y)
                                                    	t_0 = Float64(x * Float64(y * y))
                                                    	tmp = 0.0
                                                    	if (Float64(y * Float64(x * y)) <= 1e-8)
                                                    		tmp = Float64(1.0 / Float64(1.0 - t_0));
                                                    	else
                                                    		tmp = Float64(x * Float64(x * Float64(0.16666666666666666 * Float64(y * t_0))));
                                                    	end
                                                    	return tmp
                                                    end
                                                    
                                                    function tmp_2 = code(x, y)
                                                    	t_0 = x * (y * y);
                                                    	tmp = 0.0;
                                                    	if ((y * (x * y)) <= 1e-8)
                                                    		tmp = 1.0 / (1.0 - t_0);
                                                    	else
                                                    		tmp = x * (x * (0.16666666666666666 * (y * t_0)));
                                                    	end
                                                    	tmp_2 = tmp;
                                                    end
                                                    
                                                    code[x_, y_] := Block[{t$95$0 = N[(x * N[(y * y), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[N[(y * N[(x * y), $MachinePrecision]), $MachinePrecision], 1e-8], N[(1.0 / N[(1.0 - t$95$0), $MachinePrecision]), $MachinePrecision], N[(x * N[(x * N[(0.16666666666666666 * N[(y * t$95$0), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]]]
                                                    
                                                    \begin{array}{l}
                                                    
                                                    \\
                                                    \begin{array}{l}
                                                    t_0 := x \cdot \left(y \cdot y\right)\\
                                                    \mathbf{if}\;y \cdot \left(x \cdot y\right) \leq 10^{-8}:\\
                                                    \;\;\;\;\frac{1}{1 - t\_0}\\
                                                    
                                                    \mathbf{else}:\\
                                                    \;\;\;\;x \cdot \left(x \cdot \left(0.16666666666666666 \cdot \left(y \cdot t\_0\right)\right)\right)\\
                                                    
                                                    
                                                    \end{array}
                                                    \end{array}
                                                    
                                                    Derivation
                                                    1. Split input into 2 regimes
                                                    2. if (*.f64 (*.f64 x y) y) < 1e-8

                                                      1. Initial program 100.0%

                                                        \[e^{\left(x \cdot y\right) \cdot y} \]
                                                      2. Add Preprocessing
                                                      3. Taylor expanded in x around 0

                                                        \[\leadsto \color{blue}{1 + x \cdot \left(x \cdot \left(\frac{1}{6} \cdot \left(x \cdot {y}^{6}\right) + \frac{1}{2} \cdot {y}^{4}\right) + {y}^{2}\right)} \]
                                                      4. Applied rewrites65.4%

                                                        \[\leadsto \color{blue}{\mathsf{fma}\left(y \cdot y, \mathsf{fma}\left(x \cdot \left(x \cdot \left(y \cdot y\right)\right), \mathsf{fma}\left(x, \left(y \cdot y\right) \cdot 0.16666666666666666, 0.5\right), x\right), 1\right)} \]
                                                      5. Step-by-step derivation
                                                        1. Applied rewrites65.4%

                                                          \[\leadsto \frac{1}{\color{blue}{\frac{1}{\mathsf{fma}\left(y \cdot y, \mathsf{fma}\left(x \cdot \left(y \cdot y\right), x \cdot \mathsf{fma}\left(x, \left(y \cdot y\right) \cdot 0.16666666666666666, 0.5\right), x\right), 1\right)}}} \]
                                                        2. Taylor expanded in y around 0

                                                          \[\leadsto \frac{1}{1 + \color{blue}{-1 \cdot \left(x \cdot {y}^{2}\right)}} \]
                                                        3. Step-by-step derivation
                                                          1. Applied rewrites88.4%

                                                            \[\leadsto \frac{1}{1 - \color{blue}{x \cdot \left(y \cdot y\right)}} \]

                                                          if 1e-8 < (*.f64 (*.f64 x y) y)

                                                          1. Initial program 100.0%

                                                            \[e^{\left(x \cdot y\right) \cdot y} \]
                                                          2. Add Preprocessing
                                                          3. Applied rewrites57.3%

                                                            \[\leadsto e^{\color{blue}{x} \cdot y} \]
                                                          4. Taylor expanded in x around 0

                                                            \[\leadsto \color{blue}{1 + x \cdot \left(y + x \cdot \left(\frac{1}{6} \cdot \left(x \cdot {y}^{3}\right) + \frac{1}{2} \cdot {y}^{2}\right)\right)} \]
                                                          5. Step-by-step derivation
                                                            1. +-commutativeN/A

                                                              \[\leadsto \color{blue}{x \cdot \left(y + x \cdot \left(\frac{1}{6} \cdot \left(x \cdot {y}^{3}\right) + \frac{1}{2} \cdot {y}^{2}\right)\right) + 1} \]
                                                            2. lower-fma.f64N/A

                                                              \[\leadsto \color{blue}{\mathsf{fma}\left(x, y + x \cdot \left(\frac{1}{6} \cdot \left(x \cdot {y}^{3}\right) + \frac{1}{2} \cdot {y}^{2}\right), 1\right)} \]
                                                            3. +-commutativeN/A

                                                              \[\leadsto \mathsf{fma}\left(x, \color{blue}{x \cdot \left(\frac{1}{6} \cdot \left(x \cdot {y}^{3}\right) + \frac{1}{2} \cdot {y}^{2}\right) + y}, 1\right) \]
                                                            4. lower-fma.f64N/A

                                                              \[\leadsto \mathsf{fma}\left(x, \color{blue}{\mathsf{fma}\left(x, \frac{1}{6} \cdot \left(x \cdot {y}^{3}\right) + \frac{1}{2} \cdot {y}^{2}, y\right)}, 1\right) \]
                                                            5. associate-*r*N/A

                                                              \[\leadsto \mathsf{fma}\left(x, \mathsf{fma}\left(x, \color{blue}{\left(\frac{1}{6} \cdot x\right) \cdot {y}^{3}} + \frac{1}{2} \cdot {y}^{2}, y\right), 1\right) \]
                                                            6. cube-multN/A

                                                              \[\leadsto \mathsf{fma}\left(x, \mathsf{fma}\left(x, \left(\frac{1}{6} \cdot x\right) \cdot \color{blue}{\left(y \cdot \left(y \cdot y\right)\right)} + \frac{1}{2} \cdot {y}^{2}, y\right), 1\right) \]
                                                            7. unpow2N/A

                                                              \[\leadsto \mathsf{fma}\left(x, \mathsf{fma}\left(x, \left(\frac{1}{6} \cdot x\right) \cdot \left(y \cdot \color{blue}{{y}^{2}}\right) + \frac{1}{2} \cdot {y}^{2}, y\right), 1\right) \]
                                                            8. associate-*r*N/A

                                                              \[\leadsto \mathsf{fma}\left(x, \mathsf{fma}\left(x, \color{blue}{\left(\left(\frac{1}{6} \cdot x\right) \cdot y\right) \cdot {y}^{2}} + \frac{1}{2} \cdot {y}^{2}, y\right), 1\right) \]
                                                            9. distribute-rgt-outN/A

                                                              \[\leadsto \mathsf{fma}\left(x, \mathsf{fma}\left(x, \color{blue}{{y}^{2} \cdot \left(\left(\frac{1}{6} \cdot x\right) \cdot y + \frac{1}{2}\right)}, y\right), 1\right) \]
                                                            10. lower-*.f64N/A

                                                              \[\leadsto \mathsf{fma}\left(x, \mathsf{fma}\left(x, \color{blue}{{y}^{2} \cdot \left(\left(\frac{1}{6} \cdot x\right) \cdot y + \frac{1}{2}\right)}, y\right), 1\right) \]
                                                            11. unpow2N/A

                                                              \[\leadsto \mathsf{fma}\left(x, \mathsf{fma}\left(x, \color{blue}{\left(y \cdot y\right)} \cdot \left(\left(\frac{1}{6} \cdot x\right) \cdot y + \frac{1}{2}\right), y\right), 1\right) \]
                                                            12. lower-*.f64N/A

                                                              \[\leadsto \mathsf{fma}\left(x, \mathsf{fma}\left(x, \color{blue}{\left(y \cdot y\right)} \cdot \left(\left(\frac{1}{6} \cdot x\right) \cdot y + \frac{1}{2}\right), y\right), 1\right) \]
                                                            13. *-commutativeN/A

                                                              \[\leadsto \mathsf{fma}\left(x, \mathsf{fma}\left(x, \left(y \cdot y\right) \cdot \left(\color{blue}{y \cdot \left(\frac{1}{6} \cdot x\right)} + \frac{1}{2}\right), y\right), 1\right) \]
                                                            14. lower-fma.f64N/A

                                                              \[\leadsto \mathsf{fma}\left(x, \mathsf{fma}\left(x, \left(y \cdot y\right) \cdot \color{blue}{\mathsf{fma}\left(y, \frac{1}{6} \cdot x, \frac{1}{2}\right)}, y\right), 1\right) \]
                                                            15. *-commutativeN/A

                                                              \[\leadsto \mathsf{fma}\left(x, \mathsf{fma}\left(x, \left(y \cdot y\right) \cdot \mathsf{fma}\left(y, \color{blue}{x \cdot \frac{1}{6}}, \frac{1}{2}\right), y\right), 1\right) \]
                                                            16. lower-*.f6459.9

                                                              \[\leadsto \mathsf{fma}\left(x, \mathsf{fma}\left(x, \left(y \cdot y\right) \cdot \mathsf{fma}\left(y, \color{blue}{x \cdot 0.16666666666666666}, 0.5\right), y\right), 1\right) \]
                                                          6. Applied rewrites59.9%

                                                            \[\leadsto \color{blue}{\mathsf{fma}\left(x, \mathsf{fma}\left(x, \left(y \cdot y\right) \cdot \mathsf{fma}\left(y, x \cdot 0.16666666666666666, 0.5\right), y\right), 1\right)} \]
                                                          7. Taylor expanded in x around inf

                                                            \[\leadsto \frac{1}{6} \cdot \color{blue}{\left({x}^{3} \cdot {y}^{3}\right)} \]
                                                          8. Step-by-step derivation
                                                            1. Applied rewrites58.3%

                                                              \[\leadsto x \cdot \color{blue}{\left(x \cdot \left(0.16666666666666666 \cdot \left(y \cdot \left(x \cdot \left(y \cdot y\right)\right)\right)\right)\right)} \]
                                                          9. Recombined 2 regimes into one program.
                                                          10. Final simplification81.1%

                                                            \[\leadsto \begin{array}{l} \mathbf{if}\;y \cdot \left(x \cdot y\right) \leq 10^{-8}:\\ \;\;\;\;\frac{1}{1 - x \cdot \left(y \cdot y\right)}\\ \mathbf{else}:\\ \;\;\;\;x \cdot \left(x \cdot \left(0.16666666666666666 \cdot \left(y \cdot \left(x \cdot \left(y \cdot y\right)\right)\right)\right)\right)\\ \end{array} \]
                                                          11. Add Preprocessing

                                                          Alternative 12: 84.6% accurate, 2.7× speedup?

                                                          \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;y \cdot \left(x \cdot y\right) \leq 10^{-8}:\\ \;\;\;\;\frac{1}{1 - x \cdot \left(y \cdot y\right)}\\ \mathbf{else}:\\ \;\;\;\;\mathsf{fma}\left(x, \mathsf{fma}\left(x, 0.5 \cdot \left(y \cdot y\right), y\right), 1\right)\\ \end{array} \end{array} \]
                                                          (FPCore (x y)
                                                           :precision binary64
                                                           (if (<= (* y (* x y)) 1e-8)
                                                             (/ 1.0 (- 1.0 (* x (* y y))))
                                                             (fma x (fma x (* 0.5 (* y y)) y) 1.0)))
                                                          double code(double x, double y) {
                                                          	double tmp;
                                                          	if ((y * (x * y)) <= 1e-8) {
                                                          		tmp = 1.0 / (1.0 - (x * (y * y)));
                                                          	} else {
                                                          		tmp = fma(x, fma(x, (0.5 * (y * y)), y), 1.0);
                                                          	}
                                                          	return tmp;
                                                          }
                                                          
                                                          function code(x, y)
                                                          	tmp = 0.0
                                                          	if (Float64(y * Float64(x * y)) <= 1e-8)
                                                          		tmp = Float64(1.0 / Float64(1.0 - Float64(x * Float64(y * y))));
                                                          	else
                                                          		tmp = fma(x, fma(x, Float64(0.5 * Float64(y * y)), y), 1.0);
                                                          	end
                                                          	return tmp
                                                          end
                                                          
                                                          code[x_, y_] := If[LessEqual[N[(y * N[(x * y), $MachinePrecision]), $MachinePrecision], 1e-8], N[(1.0 / N[(1.0 - N[(x * N[(y * y), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], N[(x * N[(x * N[(0.5 * N[(y * y), $MachinePrecision]), $MachinePrecision] + y), $MachinePrecision] + 1.0), $MachinePrecision]]
                                                          
                                                          \begin{array}{l}
                                                          
                                                          \\
                                                          \begin{array}{l}
                                                          \mathbf{if}\;y \cdot \left(x \cdot y\right) \leq 10^{-8}:\\
                                                          \;\;\;\;\frac{1}{1 - x \cdot \left(y \cdot y\right)}\\
                                                          
                                                          \mathbf{else}:\\
                                                          \;\;\;\;\mathsf{fma}\left(x, \mathsf{fma}\left(x, 0.5 \cdot \left(y \cdot y\right), y\right), 1\right)\\
                                                          
                                                          
                                                          \end{array}
                                                          \end{array}
                                                          
                                                          Derivation
                                                          1. Split input into 2 regimes
                                                          2. if (*.f64 (*.f64 x y) y) < 1e-8

                                                            1. Initial program 100.0%

                                                              \[e^{\left(x \cdot y\right) \cdot y} \]
                                                            2. Add Preprocessing
                                                            3. Taylor expanded in x around 0

                                                              \[\leadsto \color{blue}{1 + x \cdot \left(x \cdot \left(\frac{1}{6} \cdot \left(x \cdot {y}^{6}\right) + \frac{1}{2} \cdot {y}^{4}\right) + {y}^{2}\right)} \]
                                                            4. Applied rewrites65.4%

                                                              \[\leadsto \color{blue}{\mathsf{fma}\left(y \cdot y, \mathsf{fma}\left(x \cdot \left(x \cdot \left(y \cdot y\right)\right), \mathsf{fma}\left(x, \left(y \cdot y\right) \cdot 0.16666666666666666, 0.5\right), x\right), 1\right)} \]
                                                            5. Step-by-step derivation
                                                              1. Applied rewrites65.4%

                                                                \[\leadsto \frac{1}{\color{blue}{\frac{1}{\mathsf{fma}\left(y \cdot y, \mathsf{fma}\left(x \cdot \left(y \cdot y\right), x \cdot \mathsf{fma}\left(x, \left(y \cdot y\right) \cdot 0.16666666666666666, 0.5\right), x\right), 1\right)}}} \]
                                                              2. Taylor expanded in y around 0

                                                                \[\leadsto \frac{1}{1 + \color{blue}{-1 \cdot \left(x \cdot {y}^{2}\right)}} \]
                                                              3. Step-by-step derivation
                                                                1. Applied rewrites88.4%

                                                                  \[\leadsto \frac{1}{1 - \color{blue}{x \cdot \left(y \cdot y\right)}} \]

                                                                if 1e-8 < (*.f64 (*.f64 x y) y)

                                                                1. Initial program 100.0%

                                                                  \[e^{\left(x \cdot y\right) \cdot y} \]
                                                                2. Add Preprocessing
                                                                3. Applied rewrites57.3%

                                                                  \[\leadsto e^{\color{blue}{x} \cdot y} \]
                                                                4. Taylor expanded in x around 0

                                                                  \[\leadsto \color{blue}{1 + x \cdot \left(y + \frac{1}{2} \cdot \left(x \cdot {y}^{2}\right)\right)} \]
                                                                5. Step-by-step derivation
                                                                  1. +-commutativeN/A

                                                                    \[\leadsto \color{blue}{x \cdot \left(y + \frac{1}{2} \cdot \left(x \cdot {y}^{2}\right)\right) + 1} \]
                                                                  2. +-commutativeN/A

                                                                    \[\leadsto x \cdot \color{blue}{\left(\frac{1}{2} \cdot \left(x \cdot {y}^{2}\right) + y\right)} + 1 \]
                                                                  3. *-commutativeN/A

                                                                    \[\leadsto x \cdot \left(\frac{1}{2} \cdot \color{blue}{\left({y}^{2} \cdot x\right)} + y\right) + 1 \]
                                                                  4. associate-*r*N/A

                                                                    \[\leadsto x \cdot \left(\color{blue}{\left(\frac{1}{2} \cdot {y}^{2}\right) \cdot x} + y\right) + 1 \]
                                                                  5. lower-fma.f64N/A

                                                                    \[\leadsto \color{blue}{\mathsf{fma}\left(x, \left(\frac{1}{2} \cdot {y}^{2}\right) \cdot x + y, 1\right)} \]
                                                                  6. *-commutativeN/A

                                                                    \[\leadsto \mathsf{fma}\left(x, \color{blue}{x \cdot \left(\frac{1}{2} \cdot {y}^{2}\right)} + y, 1\right) \]
                                                                  7. lower-fma.f64N/A

                                                                    \[\leadsto \mathsf{fma}\left(x, \color{blue}{\mathsf{fma}\left(x, \frac{1}{2} \cdot {y}^{2}, y\right)}, 1\right) \]
                                                                  8. lower-*.f64N/A

                                                                    \[\leadsto \mathsf{fma}\left(x, \mathsf{fma}\left(x, \color{blue}{\frac{1}{2} \cdot {y}^{2}}, y\right), 1\right) \]
                                                                  9. unpow2N/A

                                                                    \[\leadsto \mathsf{fma}\left(x, \mathsf{fma}\left(x, \frac{1}{2} \cdot \color{blue}{\left(y \cdot y\right)}, y\right), 1\right) \]
                                                                  10. lower-*.f6483.3

                                                                    \[\leadsto \mathsf{fma}\left(x, \mathsf{fma}\left(x, 0.5 \cdot \color{blue}{\left(y \cdot y\right)}, y\right), 1\right) \]
                                                                6. Applied rewrites83.3%

                                                                  \[\leadsto \color{blue}{\mathsf{fma}\left(x, \mathsf{fma}\left(x, 0.5 \cdot \left(y \cdot y\right), y\right), 1\right)} \]
                                                              4. Recombined 2 regimes into one program.
                                                              5. Final simplification87.2%

                                                                \[\leadsto \begin{array}{l} \mathbf{if}\;y \cdot \left(x \cdot y\right) \leq 10^{-8}:\\ \;\;\;\;\frac{1}{1 - x \cdot \left(y \cdot y\right)}\\ \mathbf{else}:\\ \;\;\;\;\mathsf{fma}\left(x, \mathsf{fma}\left(x, 0.5 \cdot \left(y \cdot y\right), y\right), 1\right)\\ \end{array} \]
                                                              6. Add Preprocessing

                                                              Alternative 13: 53.8% accurate, 4.8× speedup?

                                                              \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;y \cdot \left(x \cdot y\right) \leq 2:\\ \;\;\;\;1\\ \mathbf{else}:\\ \;\;\;\;\mathsf{fma}\left(x, y, 1\right)\\ \end{array} \end{array} \]
                                                              (FPCore (x y)
                                                               :precision binary64
                                                               (if (<= (* y (* x y)) 2.0) 1.0 (fma x y 1.0)))
                                                              double code(double x, double y) {
                                                              	double tmp;
                                                              	if ((y * (x * y)) <= 2.0) {
                                                              		tmp = 1.0;
                                                              	} else {
                                                              		tmp = fma(x, y, 1.0);
                                                              	}
                                                              	return tmp;
                                                              }
                                                              
                                                              function code(x, y)
                                                              	tmp = 0.0
                                                              	if (Float64(y * Float64(x * y)) <= 2.0)
                                                              		tmp = 1.0;
                                                              	else
                                                              		tmp = fma(x, y, 1.0);
                                                              	end
                                                              	return tmp
                                                              end
                                                              
                                                              code[x_, y_] := If[LessEqual[N[(y * N[(x * y), $MachinePrecision]), $MachinePrecision], 2.0], 1.0, N[(x * y + 1.0), $MachinePrecision]]
                                                              
                                                              \begin{array}{l}
                                                              
                                                              \\
                                                              \begin{array}{l}
                                                              \mathbf{if}\;y \cdot \left(x \cdot y\right) \leq 2:\\
                                                              \;\;\;\;1\\
                                                              
                                                              \mathbf{else}:\\
                                                              \;\;\;\;\mathsf{fma}\left(x, y, 1\right)\\
                                                              
                                                              
                                                              \end{array}
                                                              \end{array}
                                                              
                                                              Derivation
                                                              1. Split input into 2 regimes
                                                              2. if (*.f64 (*.f64 x y) y) < 2

                                                                1. Initial program 100.0%

                                                                  \[e^{\left(x \cdot y\right) \cdot y} \]
                                                                2. Add Preprocessing
                                                                3. Taylor expanded in x around 0

                                                                  \[\leadsto \color{blue}{1} \]
                                                                4. Step-by-step derivation
                                                                  1. Applied rewrites64.7%

                                                                    \[\leadsto \color{blue}{1} \]

                                                                  if 2 < (*.f64 (*.f64 x y) y)

                                                                  1. Initial program 100.0%

                                                                    \[e^{\left(x \cdot y\right) \cdot y} \]
                                                                  2. Add Preprocessing
                                                                  3. Applied rewrites58.2%

                                                                    \[\leadsto e^{\color{blue}{x} \cdot y} \]
                                                                  4. Taylor expanded in x around 0

                                                                    \[\leadsto \color{blue}{1 + x \cdot y} \]
                                                                  5. Step-by-step derivation
                                                                    1. +-commutativeN/A

                                                                      \[\leadsto \color{blue}{x \cdot y + 1} \]
                                                                    2. lower-fma.f6419.0

                                                                      \[\leadsto \color{blue}{\mathsf{fma}\left(x, y, 1\right)} \]
                                                                  6. Applied rewrites19.0%

                                                                    \[\leadsto \color{blue}{\mathsf{fma}\left(x, y, 1\right)} \]
                                                                5. Recombined 2 regimes into one program.
                                                                6. Final simplification53.8%

                                                                  \[\leadsto \begin{array}{l} \mathbf{if}\;y \cdot \left(x \cdot y\right) \leq 2:\\ \;\;\;\;1\\ \mathbf{else}:\\ \;\;\;\;\mathsf{fma}\left(x, y, 1\right)\\ \end{array} \]
                                                                7. Add Preprocessing

                                                                Alternative 14: 53.7% accurate, 5.0× speedup?

                                                                \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;y \cdot \left(x \cdot y\right) \leq 2:\\ \;\;\;\;1\\ \mathbf{else}:\\ \;\;\;\;x \cdot y\\ \end{array} \end{array} \]
                                                                (FPCore (x y) :precision binary64 (if (<= (* y (* x y)) 2.0) 1.0 (* x y)))
                                                                double code(double x, double y) {
                                                                	double tmp;
                                                                	if ((y * (x * y)) <= 2.0) {
                                                                		tmp = 1.0;
                                                                	} else {
                                                                		tmp = x * y;
                                                                	}
                                                                	return tmp;
                                                                }
                                                                
                                                                real(8) function code(x, y)
                                                                    real(8), intent (in) :: x
                                                                    real(8), intent (in) :: y
                                                                    real(8) :: tmp
                                                                    if ((y * (x * y)) <= 2.0d0) then
                                                                        tmp = 1.0d0
                                                                    else
                                                                        tmp = x * y
                                                                    end if
                                                                    code = tmp
                                                                end function
                                                                
                                                                public static double code(double x, double y) {
                                                                	double tmp;
                                                                	if ((y * (x * y)) <= 2.0) {
                                                                		tmp = 1.0;
                                                                	} else {
                                                                		tmp = x * y;
                                                                	}
                                                                	return tmp;
                                                                }
                                                                
                                                                def code(x, y):
                                                                	tmp = 0
                                                                	if (y * (x * y)) <= 2.0:
                                                                		tmp = 1.0
                                                                	else:
                                                                		tmp = x * y
                                                                	return tmp
                                                                
                                                                function code(x, y)
                                                                	tmp = 0.0
                                                                	if (Float64(y * Float64(x * y)) <= 2.0)
                                                                		tmp = 1.0;
                                                                	else
                                                                		tmp = Float64(x * y);
                                                                	end
                                                                	return tmp
                                                                end
                                                                
                                                                function tmp_2 = code(x, y)
                                                                	tmp = 0.0;
                                                                	if ((y * (x * y)) <= 2.0)
                                                                		tmp = 1.0;
                                                                	else
                                                                		tmp = x * y;
                                                                	end
                                                                	tmp_2 = tmp;
                                                                end
                                                                
                                                                code[x_, y_] := If[LessEqual[N[(y * N[(x * y), $MachinePrecision]), $MachinePrecision], 2.0], 1.0, N[(x * y), $MachinePrecision]]
                                                                
                                                                \begin{array}{l}
                                                                
                                                                \\
                                                                \begin{array}{l}
                                                                \mathbf{if}\;y \cdot \left(x \cdot y\right) \leq 2:\\
                                                                \;\;\;\;1\\
                                                                
                                                                \mathbf{else}:\\
                                                                \;\;\;\;x \cdot y\\
                                                                
                                                                
                                                                \end{array}
                                                                \end{array}
                                                                
                                                                Derivation
                                                                1. Split input into 2 regimes
                                                                2. if (*.f64 (*.f64 x y) y) < 2

                                                                  1. Initial program 100.0%

                                                                    \[e^{\left(x \cdot y\right) \cdot y} \]
                                                                  2. Add Preprocessing
                                                                  3. Taylor expanded in x around 0

                                                                    \[\leadsto \color{blue}{1} \]
                                                                  4. Step-by-step derivation
                                                                    1. Applied rewrites64.7%

                                                                      \[\leadsto \color{blue}{1} \]

                                                                    if 2 < (*.f64 (*.f64 x y) y)

                                                                    1. Initial program 100.0%

                                                                      \[e^{\left(x \cdot y\right) \cdot y} \]
                                                                    2. Add Preprocessing
                                                                    3. Applied rewrites58.2%

                                                                      \[\leadsto e^{\color{blue}{x} \cdot y} \]
                                                                    4. Taylor expanded in x around 0

                                                                      \[\leadsto \color{blue}{1 + x \cdot y} \]
                                                                    5. Step-by-step derivation
                                                                      1. +-commutativeN/A

                                                                        \[\leadsto \color{blue}{x \cdot y + 1} \]
                                                                      2. lower-fma.f6419.0

                                                                        \[\leadsto \color{blue}{\mathsf{fma}\left(x, y, 1\right)} \]
                                                                    6. Applied rewrites19.0%

                                                                      \[\leadsto \color{blue}{\mathsf{fma}\left(x, y, 1\right)} \]
                                                                    7. Taylor expanded in x around inf

                                                                      \[\leadsto x \cdot \color{blue}{y} \]
                                                                    8. Step-by-step derivation
                                                                      1. Applied rewrites19.0%

                                                                        \[\leadsto x \cdot \color{blue}{y} \]
                                                                    9. Recombined 2 regimes into one program.
                                                                    10. Final simplification53.8%

                                                                      \[\leadsto \begin{array}{l} \mathbf{if}\;y \cdot \left(x \cdot y\right) \leq 2:\\ \;\;\;\;1\\ \mathbf{else}:\\ \;\;\;\;x \cdot y\\ \end{array} \]
                                                                    11. Add Preprocessing

                                                                    Alternative 15: 66.2% accurate, 9.3× speedup?

                                                                    \[\begin{array}{l} \\ \mathsf{fma}\left(x, y \cdot y, 1\right) \end{array} \]
                                                                    (FPCore (x y) :precision binary64 (fma x (* y y) 1.0))
                                                                    double code(double x, double y) {
                                                                    	return fma(x, (y * y), 1.0);
                                                                    }
                                                                    
                                                                    function code(x, y)
                                                                    	return fma(x, Float64(y * y), 1.0)
                                                                    end
                                                                    
                                                                    code[x_, y_] := N[(x * N[(y * y), $MachinePrecision] + 1.0), $MachinePrecision]
                                                                    
                                                                    \begin{array}{l}
                                                                    
                                                                    \\
                                                                    \mathsf{fma}\left(x, y \cdot y, 1\right)
                                                                    \end{array}
                                                                    
                                                                    Derivation
                                                                    1. Initial program 100.0%

                                                                      \[e^{\left(x \cdot y\right) \cdot y} \]
                                                                    2. Add Preprocessing
                                                                    3. Taylor expanded in x around 0

                                                                      \[\leadsto \color{blue}{1 + x \cdot {y}^{2}} \]
                                                                    4. Step-by-step derivation
                                                                      1. +-commutativeN/A

                                                                        \[\leadsto \color{blue}{x \cdot {y}^{2} + 1} \]
                                                                      2. lower-fma.f64N/A

                                                                        \[\leadsto \color{blue}{\mathsf{fma}\left(x, {y}^{2}, 1\right)} \]
                                                                      3. unpow2N/A

                                                                        \[\leadsto \mathsf{fma}\left(x, \color{blue}{y \cdot y}, 1\right) \]
                                                                      4. lower-*.f6467.5

                                                                        \[\leadsto \mathsf{fma}\left(x, \color{blue}{y \cdot y}, 1\right) \]
                                                                    5. Applied rewrites67.5%

                                                                      \[\leadsto \color{blue}{\mathsf{fma}\left(x, y \cdot y, 1\right)} \]
                                                                    6. Add Preprocessing

                                                                    Alternative 16: 50.6% accurate, 111.0× speedup?

                                                                    \[\begin{array}{l} \\ 1 \end{array} \]
                                                                    (FPCore (x y) :precision binary64 1.0)
                                                                    double code(double x, double y) {
                                                                    	return 1.0;
                                                                    }
                                                                    
                                                                    real(8) function code(x, y)
                                                                        real(8), intent (in) :: x
                                                                        real(8), intent (in) :: y
                                                                        code = 1.0d0
                                                                    end function
                                                                    
                                                                    public static double code(double x, double y) {
                                                                    	return 1.0;
                                                                    }
                                                                    
                                                                    def code(x, y):
                                                                    	return 1.0
                                                                    
                                                                    function code(x, y)
                                                                    	return 1.0
                                                                    end
                                                                    
                                                                    function tmp = code(x, y)
                                                                    	tmp = 1.0;
                                                                    end
                                                                    
                                                                    code[x_, y_] := 1.0
                                                                    
                                                                    \begin{array}{l}
                                                                    
                                                                    \\
                                                                    1
                                                                    \end{array}
                                                                    
                                                                    Derivation
                                                                    1. Initial program 100.0%

                                                                      \[e^{\left(x \cdot y\right) \cdot y} \]
                                                                    2. Add Preprocessing
                                                                    3. Taylor expanded in x around 0

                                                                      \[\leadsto \color{blue}{1} \]
                                                                    4. Step-by-step derivation
                                                                      1. Applied rewrites50.0%

                                                                        \[\leadsto \color{blue}{1} \]
                                                                      2. Add Preprocessing

                                                                      Reproduce

                                                                      ?
                                                                      herbie shell --seed 2024222 
                                                                      (FPCore (x y)
                                                                        :name "Data.Random.Distribution.Normal:normalF from random-fu-0.2.6.2"
                                                                        :precision binary64
                                                                        (exp (* (* x y) y)))