Jmat.Real.erfi, branch x greater than or equal to 5

Percentage Accurate: 100.0% → 100.0%
Time: 14.0s
Alternatives: 14
Speedup: 1.9×

Specification

?
\[x \geq 0.5\]
\[\begin{array}{l} \\ \begin{array}{l} t_0 := \frac{1}{\left|x\right|}\\ t_1 := \left(t\_0 \cdot t\_0\right) \cdot t\_0\\ t_2 := \left(t\_1 \cdot t\_0\right) \cdot t\_0\\ \left(\frac{1}{\sqrt{\pi}} \cdot e^{\left|x\right| \cdot \left|x\right|}\right) \cdot \left(\left(\left(t\_0 + \frac{1}{2} \cdot t\_1\right) + \frac{3}{4} \cdot t\_2\right) + \frac{15}{8} \cdot \left(\left(t\_2 \cdot t\_0\right) \cdot t\_0\right)\right) \end{array} \end{array} \]
(FPCore (x)
 :precision binary64
 (let* ((t_0 (/ 1.0 (fabs x)))
        (t_1 (* (* t_0 t_0) t_0))
        (t_2 (* (* t_1 t_0) t_0)))
   (*
    (* (/ 1.0 (sqrt PI)) (exp (* (fabs x) (fabs x))))
    (+
     (+ (+ t_0 (* (/ 1.0 2.0) t_1)) (* (/ 3.0 4.0) t_2))
     (* (/ 15.0 8.0) (* (* t_2 t_0) t_0))))))
double code(double x) {
	double t_0 = 1.0 / fabs(x);
	double t_1 = (t_0 * t_0) * t_0;
	double t_2 = (t_1 * t_0) * t_0;
	return ((1.0 / sqrt(((double) M_PI))) * exp((fabs(x) * fabs(x)))) * (((t_0 + ((1.0 / 2.0) * t_1)) + ((3.0 / 4.0) * t_2)) + ((15.0 / 8.0) * ((t_2 * t_0) * t_0)));
}
public static double code(double x) {
	double t_0 = 1.0 / Math.abs(x);
	double t_1 = (t_0 * t_0) * t_0;
	double t_2 = (t_1 * t_0) * t_0;
	return ((1.0 / Math.sqrt(Math.PI)) * Math.exp((Math.abs(x) * Math.abs(x)))) * (((t_0 + ((1.0 / 2.0) * t_1)) + ((3.0 / 4.0) * t_2)) + ((15.0 / 8.0) * ((t_2 * t_0) * t_0)));
}
def code(x):
	t_0 = 1.0 / math.fabs(x)
	t_1 = (t_0 * t_0) * t_0
	t_2 = (t_1 * t_0) * t_0
	return ((1.0 / math.sqrt(math.pi)) * math.exp((math.fabs(x) * math.fabs(x)))) * (((t_0 + ((1.0 / 2.0) * t_1)) + ((3.0 / 4.0) * t_2)) + ((15.0 / 8.0) * ((t_2 * t_0) * t_0)))
function code(x)
	t_0 = Float64(1.0 / abs(x))
	t_1 = Float64(Float64(t_0 * t_0) * t_0)
	t_2 = Float64(Float64(t_1 * t_0) * t_0)
	return Float64(Float64(Float64(1.0 / sqrt(pi)) * exp(Float64(abs(x) * abs(x)))) * Float64(Float64(Float64(t_0 + Float64(Float64(1.0 / 2.0) * t_1)) + Float64(Float64(3.0 / 4.0) * t_2)) + Float64(Float64(15.0 / 8.0) * Float64(Float64(t_2 * t_0) * t_0))))
end
function tmp = code(x)
	t_0 = 1.0 / abs(x);
	t_1 = (t_0 * t_0) * t_0;
	t_2 = (t_1 * t_0) * t_0;
	tmp = ((1.0 / sqrt(pi)) * exp((abs(x) * abs(x)))) * (((t_0 + ((1.0 / 2.0) * t_1)) + ((3.0 / 4.0) * t_2)) + ((15.0 / 8.0) * ((t_2 * t_0) * t_0)));
end
code[x_] := Block[{t$95$0 = N[(1.0 / N[Abs[x], $MachinePrecision]), $MachinePrecision]}, Block[{t$95$1 = N[(N[(t$95$0 * t$95$0), $MachinePrecision] * t$95$0), $MachinePrecision]}, Block[{t$95$2 = N[(N[(t$95$1 * t$95$0), $MachinePrecision] * t$95$0), $MachinePrecision]}, N[(N[(N[(1.0 / N[Sqrt[Pi], $MachinePrecision]), $MachinePrecision] * N[Exp[N[(N[Abs[x], $MachinePrecision] * N[Abs[x], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] * N[(N[(N[(t$95$0 + N[(N[(1.0 / 2.0), $MachinePrecision] * t$95$1), $MachinePrecision]), $MachinePrecision] + N[(N[(3.0 / 4.0), $MachinePrecision] * t$95$2), $MachinePrecision]), $MachinePrecision] + N[(N[(15.0 / 8.0), $MachinePrecision] * N[(N[(t$95$2 * t$95$0), $MachinePrecision] * t$95$0), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]]]]
\begin{array}{l}

\\
\begin{array}{l}
t_0 := \frac{1}{\left|x\right|}\\
t_1 := \left(t\_0 \cdot t\_0\right) \cdot t\_0\\
t_2 := \left(t\_1 \cdot t\_0\right) \cdot t\_0\\
\left(\frac{1}{\sqrt{\pi}} \cdot e^{\left|x\right| \cdot \left|x\right|}\right) \cdot \left(\left(\left(t\_0 + \frac{1}{2} \cdot t\_1\right) + \frac{3}{4} \cdot t\_2\right) + \frac{15}{8} \cdot \left(\left(t\_2 \cdot t\_0\right) \cdot t\_0\right)\right)
\end{array}
\end{array}

Sampling outcomes in binary64 precision:

Local Percentage Accuracy vs ?

The average percentage accuracy by input value. Horizontal axis shows value of an input variable; the variable is choosen in the title. Vertical axis is accuracy; higher is better. Red represent the original program, while blue represents Herbie's suggestion. These can be toggled with buttons below the plot. The line is an average while dots represent individual samples.

Accuracy vs Speed?

Herbie found 14 alternatives:

AlternativeAccuracySpeedup
The accuracy (vertical axis) and speed (horizontal axis) of each alternatives. Up and to the right is better. The red square shows the initial program, and each blue circle shows an alternative.The line shows the best available speed-accuracy tradeoffs.

Initial Program: 100.0% accurate, 1.0× speedup?

\[\begin{array}{l} \\ \begin{array}{l} t_0 := \frac{1}{\left|x\right|}\\ t_1 := \left(t\_0 \cdot t\_0\right) \cdot t\_0\\ t_2 := \left(t\_1 \cdot t\_0\right) \cdot t\_0\\ \left(\frac{1}{\sqrt{\pi}} \cdot e^{\left|x\right| \cdot \left|x\right|}\right) \cdot \left(\left(\left(t\_0 + \frac{1}{2} \cdot t\_1\right) + \frac{3}{4} \cdot t\_2\right) + \frac{15}{8} \cdot \left(\left(t\_2 \cdot t\_0\right) \cdot t\_0\right)\right) \end{array} \end{array} \]
(FPCore (x)
 :precision binary64
 (let* ((t_0 (/ 1.0 (fabs x)))
        (t_1 (* (* t_0 t_0) t_0))
        (t_2 (* (* t_1 t_0) t_0)))
   (*
    (* (/ 1.0 (sqrt PI)) (exp (* (fabs x) (fabs x))))
    (+
     (+ (+ t_0 (* (/ 1.0 2.0) t_1)) (* (/ 3.0 4.0) t_2))
     (* (/ 15.0 8.0) (* (* t_2 t_0) t_0))))))
double code(double x) {
	double t_0 = 1.0 / fabs(x);
	double t_1 = (t_0 * t_0) * t_0;
	double t_2 = (t_1 * t_0) * t_0;
	return ((1.0 / sqrt(((double) M_PI))) * exp((fabs(x) * fabs(x)))) * (((t_0 + ((1.0 / 2.0) * t_1)) + ((3.0 / 4.0) * t_2)) + ((15.0 / 8.0) * ((t_2 * t_0) * t_0)));
}
public static double code(double x) {
	double t_0 = 1.0 / Math.abs(x);
	double t_1 = (t_0 * t_0) * t_0;
	double t_2 = (t_1 * t_0) * t_0;
	return ((1.0 / Math.sqrt(Math.PI)) * Math.exp((Math.abs(x) * Math.abs(x)))) * (((t_0 + ((1.0 / 2.0) * t_1)) + ((3.0 / 4.0) * t_2)) + ((15.0 / 8.0) * ((t_2 * t_0) * t_0)));
}
def code(x):
	t_0 = 1.0 / math.fabs(x)
	t_1 = (t_0 * t_0) * t_0
	t_2 = (t_1 * t_0) * t_0
	return ((1.0 / math.sqrt(math.pi)) * math.exp((math.fabs(x) * math.fabs(x)))) * (((t_0 + ((1.0 / 2.0) * t_1)) + ((3.0 / 4.0) * t_2)) + ((15.0 / 8.0) * ((t_2 * t_0) * t_0)))
function code(x)
	t_0 = Float64(1.0 / abs(x))
	t_1 = Float64(Float64(t_0 * t_0) * t_0)
	t_2 = Float64(Float64(t_1 * t_0) * t_0)
	return Float64(Float64(Float64(1.0 / sqrt(pi)) * exp(Float64(abs(x) * abs(x)))) * Float64(Float64(Float64(t_0 + Float64(Float64(1.0 / 2.0) * t_1)) + Float64(Float64(3.0 / 4.0) * t_2)) + Float64(Float64(15.0 / 8.0) * Float64(Float64(t_2 * t_0) * t_0))))
end
function tmp = code(x)
	t_0 = 1.0 / abs(x);
	t_1 = (t_0 * t_0) * t_0;
	t_2 = (t_1 * t_0) * t_0;
	tmp = ((1.0 / sqrt(pi)) * exp((abs(x) * abs(x)))) * (((t_0 + ((1.0 / 2.0) * t_1)) + ((3.0 / 4.0) * t_2)) + ((15.0 / 8.0) * ((t_2 * t_0) * t_0)));
end
code[x_] := Block[{t$95$0 = N[(1.0 / N[Abs[x], $MachinePrecision]), $MachinePrecision]}, Block[{t$95$1 = N[(N[(t$95$0 * t$95$0), $MachinePrecision] * t$95$0), $MachinePrecision]}, Block[{t$95$2 = N[(N[(t$95$1 * t$95$0), $MachinePrecision] * t$95$0), $MachinePrecision]}, N[(N[(N[(1.0 / N[Sqrt[Pi], $MachinePrecision]), $MachinePrecision] * N[Exp[N[(N[Abs[x], $MachinePrecision] * N[Abs[x], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] * N[(N[(N[(t$95$0 + N[(N[(1.0 / 2.0), $MachinePrecision] * t$95$1), $MachinePrecision]), $MachinePrecision] + N[(N[(3.0 / 4.0), $MachinePrecision] * t$95$2), $MachinePrecision]), $MachinePrecision] + N[(N[(15.0 / 8.0), $MachinePrecision] * N[(N[(t$95$2 * t$95$0), $MachinePrecision] * t$95$0), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]]]]
\begin{array}{l}

\\
\begin{array}{l}
t_0 := \frac{1}{\left|x\right|}\\
t_1 := \left(t\_0 \cdot t\_0\right) \cdot t\_0\\
t_2 := \left(t\_1 \cdot t\_0\right) \cdot t\_0\\
\left(\frac{1}{\sqrt{\pi}} \cdot e^{\left|x\right| \cdot \left|x\right|}\right) \cdot \left(\left(\left(t\_0 + \frac{1}{2} \cdot t\_1\right) + \frac{3}{4} \cdot t\_2\right) + \frac{15}{8} \cdot \left(\left(t\_2 \cdot t\_0\right) \cdot t\_0\right)\right)
\end{array}
\end{array}

Alternative 1: 100.0% accurate, 1.4× speedup?

\[\begin{array}{l} \\ \begin{array}{l} t_0 := x \cdot \left(\left(x \cdot x\right) \cdot \left(x \cdot x\right)\right)\\ \frac{{\left(e^{x}\right)}^{x}}{\sqrt{\pi}} \cdot \left(\frac{\frac{0.5}{x \cdot x} + 1}{\left|x\right|} + \left(\frac{0.75}{t\_0} + \frac{1.875}{\left(x \cdot x\right) \cdot t\_0}\right)\right) \end{array} \end{array} \]
(FPCore (x)
 :precision binary64
 (let* ((t_0 (* x (* (* x x) (* x x)))))
   (*
    (/ (pow (exp x) x) (sqrt PI))
    (+
     (/ (+ (/ 0.5 (* x x)) 1.0) (fabs x))
     (+ (/ 0.75 t_0) (/ 1.875 (* (* x x) t_0)))))))
double code(double x) {
	double t_0 = x * ((x * x) * (x * x));
	return (pow(exp(x), x) / sqrt(((double) M_PI))) * ((((0.5 / (x * x)) + 1.0) / fabs(x)) + ((0.75 / t_0) + (1.875 / ((x * x) * t_0))));
}
public static double code(double x) {
	double t_0 = x * ((x * x) * (x * x));
	return (Math.pow(Math.exp(x), x) / Math.sqrt(Math.PI)) * ((((0.5 / (x * x)) + 1.0) / Math.abs(x)) + ((0.75 / t_0) + (1.875 / ((x * x) * t_0))));
}
def code(x):
	t_0 = x * ((x * x) * (x * x))
	return (math.pow(math.exp(x), x) / math.sqrt(math.pi)) * ((((0.5 / (x * x)) + 1.0) / math.fabs(x)) + ((0.75 / t_0) + (1.875 / ((x * x) * t_0))))
function code(x)
	t_0 = Float64(x * Float64(Float64(x * x) * Float64(x * x)))
	return Float64(Float64((exp(x) ^ x) / sqrt(pi)) * Float64(Float64(Float64(Float64(0.5 / Float64(x * x)) + 1.0) / abs(x)) + Float64(Float64(0.75 / t_0) + Float64(1.875 / Float64(Float64(x * x) * t_0)))))
end
function tmp = code(x)
	t_0 = x * ((x * x) * (x * x));
	tmp = ((exp(x) ^ x) / sqrt(pi)) * ((((0.5 / (x * x)) + 1.0) / abs(x)) + ((0.75 / t_0) + (1.875 / ((x * x) * t_0))));
end
code[x_] := Block[{t$95$0 = N[(x * N[(N[(x * x), $MachinePrecision] * N[(x * x), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]}, N[(N[(N[Power[N[Exp[x], $MachinePrecision], x], $MachinePrecision] / N[Sqrt[Pi], $MachinePrecision]), $MachinePrecision] * N[(N[(N[(N[(0.5 / N[(x * x), $MachinePrecision]), $MachinePrecision] + 1.0), $MachinePrecision] / N[Abs[x], $MachinePrecision]), $MachinePrecision] + N[(N[(0.75 / t$95$0), $MachinePrecision] + N[(1.875 / N[(N[(x * x), $MachinePrecision] * t$95$0), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]]
\begin{array}{l}

\\
\begin{array}{l}
t_0 := x \cdot \left(\left(x \cdot x\right) \cdot \left(x \cdot x\right)\right)\\
\frac{{\left(e^{x}\right)}^{x}}{\sqrt{\pi}} \cdot \left(\frac{\frac{0.5}{x \cdot x} + 1}{\left|x\right|} + \left(\frac{0.75}{t\_0} + \frac{1.875}{\left(x \cdot x\right) \cdot t\_0}\right)\right)
\end{array}
\end{array}
Derivation
  1. Initial program 100.0%

    \[\left(\frac{1}{\sqrt{\pi}} \cdot e^{\left|x\right| \cdot \left|x\right|}\right) \cdot \left(\left(\left(\frac{1}{\left|x\right|} + \frac{1}{2} \cdot \left(\left(\frac{1}{\left|x\right|} \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right)\right) + \frac{3}{4} \cdot \left(\left(\left(\left(\frac{1}{\left|x\right|} \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right)\right) + \frac{15}{8} \cdot \left(\left(\left(\left(\left(\left(\frac{1}{\left|x\right|} \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right)\right) \]
  2. Add Preprocessing
  3. Applied rewrites100.0%

    \[\leadsto \left(\frac{1}{\sqrt{\pi}} \cdot e^{\left|x\right| \cdot \left|x\right|}\right) \cdot \color{blue}{\left(\frac{\frac{0.5}{x \cdot x} + 1}{\left|x\right|} + \left(\frac{0.75}{\left|x\right| \cdot \left(\left(x \cdot x\right) \cdot \left(x \cdot x\right)\right)} + \frac{1.875}{\left(x \cdot x\right) \cdot \left(\left|x\right| \cdot \left(\left(x \cdot x\right) \cdot \left(x \cdot x\right)\right)\right)}\right)\right)} \]
  4. Applied rewrites100.0%

    \[\leadsto \color{blue}{\frac{e^{x \cdot x}}{\sqrt{\pi}} \cdot \left(\frac{1 + \frac{0.5}{x \cdot x}}{\left|x\right|} + \left(\frac{0.75}{x \cdot \left(\left(x \cdot x\right) \cdot \left(x \cdot x\right)\right)} + \frac{1.875}{\left(x \cdot x\right) \cdot \left(x \cdot \left(\left(x \cdot x\right) \cdot \left(x \cdot x\right)\right)\right)}\right)\right)} \]
  5. Step-by-step derivation
    1. lift-exp.f64N/A

      \[\leadsto \frac{\color{blue}{e^{x \cdot x}}}{\sqrt{\mathsf{PI}\left(\right)}} \cdot \left(\frac{1 + \frac{\frac{1}{2}}{x \cdot x}}{\left|x\right|} + \left(\frac{\frac{3}{4}}{x \cdot \left(\left(x \cdot x\right) \cdot \left(x \cdot x\right)\right)} + \frac{\frac{15}{8}}{\left(x \cdot x\right) \cdot \left(x \cdot \left(\left(x \cdot x\right) \cdot \left(x \cdot x\right)\right)\right)}\right)\right) \]
    2. lift-*.f64N/A

      \[\leadsto \frac{e^{\color{blue}{x \cdot x}}}{\sqrt{\mathsf{PI}\left(\right)}} \cdot \left(\frac{1 + \frac{\frac{1}{2}}{x \cdot x}}{\left|x\right|} + \left(\frac{\frac{3}{4}}{x \cdot \left(\left(x \cdot x\right) \cdot \left(x \cdot x\right)\right)} + \frac{\frac{15}{8}}{\left(x \cdot x\right) \cdot \left(x \cdot \left(\left(x \cdot x\right) \cdot \left(x \cdot x\right)\right)\right)}\right)\right) \]
    3. exp-prodN/A

      \[\leadsto \frac{\color{blue}{{\left(e^{x}\right)}^{x}}}{\sqrt{\mathsf{PI}\left(\right)}} \cdot \left(\frac{1 + \frac{\frac{1}{2}}{x \cdot x}}{\left|x\right|} + \left(\frac{\frac{3}{4}}{x \cdot \left(\left(x \cdot x\right) \cdot \left(x \cdot x\right)\right)} + \frac{\frac{15}{8}}{\left(x \cdot x\right) \cdot \left(x \cdot \left(\left(x \cdot x\right) \cdot \left(x \cdot x\right)\right)\right)}\right)\right) \]
    4. lower-pow.f64N/A

      \[\leadsto \frac{\color{blue}{{\left(e^{x}\right)}^{x}}}{\sqrt{\mathsf{PI}\left(\right)}} \cdot \left(\frac{1 + \frac{\frac{1}{2}}{x \cdot x}}{\left|x\right|} + \left(\frac{\frac{3}{4}}{x \cdot \left(\left(x \cdot x\right) \cdot \left(x \cdot x\right)\right)} + \frac{\frac{15}{8}}{\left(x \cdot x\right) \cdot \left(x \cdot \left(\left(x \cdot x\right) \cdot \left(x \cdot x\right)\right)\right)}\right)\right) \]
    5. lower-exp.f64100.0

      \[\leadsto \frac{{\color{blue}{\left(e^{x}\right)}}^{x}}{\sqrt{\pi}} \cdot \left(\frac{1 + \frac{0.5}{x \cdot x}}{\left|x\right|} + \left(\frac{0.75}{x \cdot \left(\left(x \cdot x\right) \cdot \left(x \cdot x\right)\right)} + \frac{1.875}{\left(x \cdot x\right) \cdot \left(x \cdot \left(\left(x \cdot x\right) \cdot \left(x \cdot x\right)\right)\right)}\right)\right) \]
  6. Applied rewrites100.0%

    \[\leadsto \frac{\color{blue}{{\left(e^{x}\right)}^{x}}}{\sqrt{\pi}} \cdot \left(\frac{1 + \frac{0.5}{x \cdot x}}{\left|x\right|} + \left(\frac{0.75}{x \cdot \left(\left(x \cdot x\right) \cdot \left(x \cdot x\right)\right)} + \frac{1.875}{\left(x \cdot x\right) \cdot \left(x \cdot \left(\left(x \cdot x\right) \cdot \left(x \cdot x\right)\right)\right)}\right)\right) \]
  7. Final simplification100.0%

    \[\leadsto \frac{{\left(e^{x}\right)}^{x}}{\sqrt{\pi}} \cdot \left(\frac{\frac{0.5}{x \cdot x} + 1}{\left|x\right|} + \left(\frac{0.75}{x \cdot \left(\left(x \cdot x\right) \cdot \left(x \cdot x\right)\right)} + \frac{1.875}{\left(x \cdot x\right) \cdot \left(x \cdot \left(\left(x \cdot x\right) \cdot \left(x \cdot x\right)\right)\right)}\right)\right) \]
  8. Add Preprocessing

Alternative 2: 100.0% accurate, 1.9× speedup?

\[\begin{array}{l} \\ \begin{array}{l} t_0 := x \cdot \left(\left(x \cdot x\right) \cdot \left(x \cdot x\right)\right)\\ \left(\left(\frac{\frac{0.5}{x \cdot x} + 1}{\left|x\right|} + \left(\frac{0.75}{t\_0} + \frac{1.875}{\left(x \cdot x\right) \cdot t\_0}\right)\right) \cdot \frac{1}{\sqrt{\pi}}\right) \cdot e^{x \cdot x} \end{array} \end{array} \]
(FPCore (x)
 :precision binary64
 (let* ((t_0 (* x (* (* x x) (* x x)))))
   (*
    (*
     (+
      (/ (+ (/ 0.5 (* x x)) 1.0) (fabs x))
      (+ (/ 0.75 t_0) (/ 1.875 (* (* x x) t_0))))
     (/ 1.0 (sqrt PI)))
    (exp (* x x)))))
double code(double x) {
	double t_0 = x * ((x * x) * (x * x));
	return (((((0.5 / (x * x)) + 1.0) / fabs(x)) + ((0.75 / t_0) + (1.875 / ((x * x) * t_0)))) * (1.0 / sqrt(((double) M_PI)))) * exp((x * x));
}
public static double code(double x) {
	double t_0 = x * ((x * x) * (x * x));
	return (((((0.5 / (x * x)) + 1.0) / Math.abs(x)) + ((0.75 / t_0) + (1.875 / ((x * x) * t_0)))) * (1.0 / Math.sqrt(Math.PI))) * Math.exp((x * x));
}
def code(x):
	t_0 = x * ((x * x) * (x * x))
	return (((((0.5 / (x * x)) + 1.0) / math.fabs(x)) + ((0.75 / t_0) + (1.875 / ((x * x) * t_0)))) * (1.0 / math.sqrt(math.pi))) * math.exp((x * x))
function code(x)
	t_0 = Float64(x * Float64(Float64(x * x) * Float64(x * x)))
	return Float64(Float64(Float64(Float64(Float64(Float64(0.5 / Float64(x * x)) + 1.0) / abs(x)) + Float64(Float64(0.75 / t_0) + Float64(1.875 / Float64(Float64(x * x) * t_0)))) * Float64(1.0 / sqrt(pi))) * exp(Float64(x * x)))
end
function tmp = code(x)
	t_0 = x * ((x * x) * (x * x));
	tmp = (((((0.5 / (x * x)) + 1.0) / abs(x)) + ((0.75 / t_0) + (1.875 / ((x * x) * t_0)))) * (1.0 / sqrt(pi))) * exp((x * x));
end
code[x_] := Block[{t$95$0 = N[(x * N[(N[(x * x), $MachinePrecision] * N[(x * x), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]}, N[(N[(N[(N[(N[(N[(0.5 / N[(x * x), $MachinePrecision]), $MachinePrecision] + 1.0), $MachinePrecision] / N[Abs[x], $MachinePrecision]), $MachinePrecision] + N[(N[(0.75 / t$95$0), $MachinePrecision] + N[(1.875 / N[(N[(x * x), $MachinePrecision] * t$95$0), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] * N[(1.0 / N[Sqrt[Pi], $MachinePrecision]), $MachinePrecision]), $MachinePrecision] * N[Exp[N[(x * x), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]]
\begin{array}{l}

\\
\begin{array}{l}
t_0 := x \cdot \left(\left(x \cdot x\right) \cdot \left(x \cdot x\right)\right)\\
\left(\left(\frac{\frac{0.5}{x \cdot x} + 1}{\left|x\right|} + \left(\frac{0.75}{t\_0} + \frac{1.875}{\left(x \cdot x\right) \cdot t\_0}\right)\right) \cdot \frac{1}{\sqrt{\pi}}\right) \cdot e^{x \cdot x}
\end{array}
\end{array}
Derivation
  1. Initial program 100.0%

    \[\left(\frac{1}{\sqrt{\pi}} \cdot e^{\left|x\right| \cdot \left|x\right|}\right) \cdot \left(\left(\left(\frac{1}{\left|x\right|} + \frac{1}{2} \cdot \left(\left(\frac{1}{\left|x\right|} \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right)\right) + \frac{3}{4} \cdot \left(\left(\left(\left(\frac{1}{\left|x\right|} \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right)\right) + \frac{15}{8} \cdot \left(\left(\left(\left(\left(\left(\frac{1}{\left|x\right|} \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right)\right) \]
  2. Add Preprocessing
  3. Applied rewrites100.0%

    \[\leadsto \left(\frac{1}{\sqrt{\pi}} \cdot e^{\left|x\right| \cdot \left|x\right|}\right) \cdot \color{blue}{\left(\frac{\frac{0.5}{x \cdot x} + 1}{\left|x\right|} + \left(\frac{0.75}{\left|x\right| \cdot \left(\left(x \cdot x\right) \cdot \left(x \cdot x\right)\right)} + \frac{1.875}{\left(x \cdot x\right) \cdot \left(\left|x\right| \cdot \left(\left(x \cdot x\right) \cdot \left(x \cdot x\right)\right)\right)}\right)\right)} \]
  4. Applied rewrites100.0%

    \[\leadsto \color{blue}{\left(\left(\frac{1 + \frac{0.5}{x \cdot x}}{\left|x\right|} + \left(\frac{0.75}{x \cdot \left(\left(x \cdot x\right) \cdot \left(x \cdot x\right)\right)} + \frac{1.875}{\left(x \cdot x\right) \cdot \left(x \cdot \left(\left(x \cdot x\right) \cdot \left(x \cdot x\right)\right)\right)}\right)\right) \cdot \frac{1}{\sqrt{\pi}}\right) \cdot e^{x \cdot x}} \]
  5. Final simplification100.0%

    \[\leadsto \left(\left(\frac{\frac{0.5}{x \cdot x} + 1}{\left|x\right|} + \left(\frac{0.75}{x \cdot \left(\left(x \cdot x\right) \cdot \left(x \cdot x\right)\right)} + \frac{1.875}{\left(x \cdot x\right) \cdot \left(x \cdot \left(\left(x \cdot x\right) \cdot \left(x \cdot x\right)\right)\right)}\right)\right) \cdot \frac{1}{\sqrt{\pi}}\right) \cdot e^{x \cdot x} \]
  6. Add Preprocessing

Alternative 3: 100.0% accurate, 1.9× speedup?

\[\begin{array}{l} \\ \begin{array}{l} t_0 := x \cdot \left(\left(x \cdot x\right) \cdot \left(x \cdot x\right)\right)\\ \left(\frac{\frac{0.5}{x \cdot x} + 1}{\left|x\right|} + \left(\frac{0.75}{t\_0} + \frac{1.875}{\left(x \cdot x\right) \cdot t\_0}\right)\right) \cdot \frac{e^{x \cdot x}}{\sqrt{\pi}} \end{array} \end{array} \]
(FPCore (x)
 :precision binary64
 (let* ((t_0 (* x (* (* x x) (* x x)))))
   (*
    (+
     (/ (+ (/ 0.5 (* x x)) 1.0) (fabs x))
     (+ (/ 0.75 t_0) (/ 1.875 (* (* x x) t_0))))
    (/ (exp (* x x)) (sqrt PI)))))
double code(double x) {
	double t_0 = x * ((x * x) * (x * x));
	return ((((0.5 / (x * x)) + 1.0) / fabs(x)) + ((0.75 / t_0) + (1.875 / ((x * x) * t_0)))) * (exp((x * x)) / sqrt(((double) M_PI)));
}
public static double code(double x) {
	double t_0 = x * ((x * x) * (x * x));
	return ((((0.5 / (x * x)) + 1.0) / Math.abs(x)) + ((0.75 / t_0) + (1.875 / ((x * x) * t_0)))) * (Math.exp((x * x)) / Math.sqrt(Math.PI));
}
def code(x):
	t_0 = x * ((x * x) * (x * x))
	return ((((0.5 / (x * x)) + 1.0) / math.fabs(x)) + ((0.75 / t_0) + (1.875 / ((x * x) * t_0)))) * (math.exp((x * x)) / math.sqrt(math.pi))
function code(x)
	t_0 = Float64(x * Float64(Float64(x * x) * Float64(x * x)))
	return Float64(Float64(Float64(Float64(Float64(0.5 / Float64(x * x)) + 1.0) / abs(x)) + Float64(Float64(0.75 / t_0) + Float64(1.875 / Float64(Float64(x * x) * t_0)))) * Float64(exp(Float64(x * x)) / sqrt(pi)))
end
function tmp = code(x)
	t_0 = x * ((x * x) * (x * x));
	tmp = ((((0.5 / (x * x)) + 1.0) / abs(x)) + ((0.75 / t_0) + (1.875 / ((x * x) * t_0)))) * (exp((x * x)) / sqrt(pi));
end
code[x_] := Block[{t$95$0 = N[(x * N[(N[(x * x), $MachinePrecision] * N[(x * x), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]}, N[(N[(N[(N[(N[(0.5 / N[(x * x), $MachinePrecision]), $MachinePrecision] + 1.0), $MachinePrecision] / N[Abs[x], $MachinePrecision]), $MachinePrecision] + N[(N[(0.75 / t$95$0), $MachinePrecision] + N[(1.875 / N[(N[(x * x), $MachinePrecision] * t$95$0), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] * N[(N[Exp[N[(x * x), $MachinePrecision]], $MachinePrecision] / N[Sqrt[Pi], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]]
\begin{array}{l}

\\
\begin{array}{l}
t_0 := x \cdot \left(\left(x \cdot x\right) \cdot \left(x \cdot x\right)\right)\\
\left(\frac{\frac{0.5}{x \cdot x} + 1}{\left|x\right|} + \left(\frac{0.75}{t\_0} + \frac{1.875}{\left(x \cdot x\right) \cdot t\_0}\right)\right) \cdot \frac{e^{x \cdot x}}{\sqrt{\pi}}
\end{array}
\end{array}
Derivation
  1. Initial program 100.0%

    \[\left(\frac{1}{\sqrt{\pi}} \cdot e^{\left|x\right| \cdot \left|x\right|}\right) \cdot \left(\left(\left(\frac{1}{\left|x\right|} + \frac{1}{2} \cdot \left(\left(\frac{1}{\left|x\right|} \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right)\right) + \frac{3}{4} \cdot \left(\left(\left(\left(\frac{1}{\left|x\right|} \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right)\right) + \frac{15}{8} \cdot \left(\left(\left(\left(\left(\left(\frac{1}{\left|x\right|} \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right)\right) \]
  2. Add Preprocessing
  3. Applied rewrites100.0%

    \[\leadsto \left(\frac{1}{\sqrt{\pi}} \cdot e^{\left|x\right| \cdot \left|x\right|}\right) \cdot \color{blue}{\left(\frac{\frac{0.5}{x \cdot x} + 1}{\left|x\right|} + \left(\frac{0.75}{\left|x\right| \cdot \left(\left(x \cdot x\right) \cdot \left(x \cdot x\right)\right)} + \frac{1.875}{\left(x \cdot x\right) \cdot \left(\left|x\right| \cdot \left(\left(x \cdot x\right) \cdot \left(x \cdot x\right)\right)\right)}\right)\right)} \]
  4. Applied rewrites100.0%

    \[\leadsto \color{blue}{\frac{e^{x \cdot x}}{\sqrt{\pi}} \cdot \left(\frac{1 + \frac{0.5}{x \cdot x}}{\left|x\right|} + \left(\frac{0.75}{x \cdot \left(\left(x \cdot x\right) \cdot \left(x \cdot x\right)\right)} + \frac{1.875}{\left(x \cdot x\right) \cdot \left(x \cdot \left(\left(x \cdot x\right) \cdot \left(x \cdot x\right)\right)\right)}\right)\right)} \]
  5. Final simplification100.0%

    \[\leadsto \left(\frac{\frac{0.5}{x \cdot x} + 1}{\left|x\right|} + \left(\frac{0.75}{x \cdot \left(\left(x \cdot x\right) \cdot \left(x \cdot x\right)\right)} + \frac{1.875}{\left(x \cdot x\right) \cdot \left(x \cdot \left(\left(x \cdot x\right) \cdot \left(x \cdot x\right)\right)\right)}\right)\right) \cdot \frac{e^{x \cdot x}}{\sqrt{\pi}} \]
  6. Add Preprocessing

Alternative 4: 99.5% accurate, 2.4× speedup?

\[\begin{array}{l} \\ \frac{e^{x \cdot x} \cdot \sqrt{\frac{1}{\pi}}}{\left|x\right|} \cdot \left(\left(\frac{0.5}{x \cdot x} + 1\right) + \frac{0.75}{\left(x \cdot x\right) \cdot \left(x \cdot x\right)}\right) \end{array} \]
(FPCore (x)
 :precision binary64
 (*
  (/ (* (exp (* x x)) (sqrt (/ 1.0 PI))) (fabs x))
  (+ (+ (/ 0.5 (* x x)) 1.0) (/ 0.75 (* (* x x) (* x x))))))
double code(double x) {
	return ((exp((x * x)) * sqrt((1.0 / ((double) M_PI)))) / fabs(x)) * (((0.5 / (x * x)) + 1.0) + (0.75 / ((x * x) * (x * x))));
}
public static double code(double x) {
	return ((Math.exp((x * x)) * Math.sqrt((1.0 / Math.PI))) / Math.abs(x)) * (((0.5 / (x * x)) + 1.0) + (0.75 / ((x * x) * (x * x))));
}
def code(x):
	return ((math.exp((x * x)) * math.sqrt((1.0 / math.pi))) / math.fabs(x)) * (((0.5 / (x * x)) + 1.0) + (0.75 / ((x * x) * (x * x))))
function code(x)
	return Float64(Float64(Float64(exp(Float64(x * x)) * sqrt(Float64(1.0 / pi))) / abs(x)) * Float64(Float64(Float64(0.5 / Float64(x * x)) + 1.0) + Float64(0.75 / Float64(Float64(x * x) * Float64(x * x)))))
end
function tmp = code(x)
	tmp = ((exp((x * x)) * sqrt((1.0 / pi))) / abs(x)) * (((0.5 / (x * x)) + 1.0) + (0.75 / ((x * x) * (x * x))));
end
code[x_] := N[(N[(N[(N[Exp[N[(x * x), $MachinePrecision]], $MachinePrecision] * N[Sqrt[N[(1.0 / Pi), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] / N[Abs[x], $MachinePrecision]), $MachinePrecision] * N[(N[(N[(0.5 / N[(x * x), $MachinePrecision]), $MachinePrecision] + 1.0), $MachinePrecision] + N[(0.75 / N[(N[(x * x), $MachinePrecision] * N[(x * x), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
\frac{e^{x \cdot x} \cdot \sqrt{\frac{1}{\pi}}}{\left|x\right|} \cdot \left(\left(\frac{0.5}{x \cdot x} + 1\right) + \frac{0.75}{\left(x \cdot x\right) \cdot \left(x \cdot x\right)}\right)
\end{array}
Derivation
  1. Initial program 100.0%

    \[\left(\frac{1}{\sqrt{\pi}} \cdot e^{\left|x\right| \cdot \left|x\right|}\right) \cdot \left(\left(\left(\frac{1}{\left|x\right|} + \frac{1}{2} \cdot \left(\left(\frac{1}{\left|x\right|} \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right)\right) + \frac{3}{4} \cdot \left(\left(\left(\left(\frac{1}{\left|x\right|} \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right)\right) + \frac{15}{8} \cdot \left(\left(\left(\left(\left(\left(\frac{1}{\left|x\right|} \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right)\right) \]
  2. Add Preprocessing
  3. Applied rewrites100.0%

    \[\leadsto \left(\frac{1}{\sqrt{\pi}} \cdot e^{\left|x\right| \cdot \left|x\right|}\right) \cdot \color{blue}{\left(\frac{\frac{0.5}{x \cdot x} + 1}{\left|x\right|} + \left(\frac{0.75}{\left|x\right| \cdot \left(\left(x \cdot x\right) \cdot \left(x \cdot x\right)\right)} + \frac{1.875}{\left(x \cdot x\right) \cdot \left(\left|x\right| \cdot \left(\left(x \cdot x\right) \cdot \left(x \cdot x\right)\right)\right)}\right)\right)} \]
  4. Taylor expanded in x around inf

    \[\leadsto \color{blue}{\sqrt{\frac{1}{\mathsf{PI}\left(\right)}} \cdot \frac{e^{{\left(\left|x\right|\right)}^{2}}}{\left|x\right|}} \]
  5. Step-by-step derivation
    1. lower-*.f64N/A

      \[\leadsto \color{blue}{\sqrt{\frac{1}{\mathsf{PI}\left(\right)}} \cdot \frac{e^{{\left(\left|x\right|\right)}^{2}}}{\left|x\right|}} \]
    2. lower-sqrt.f64N/A

      \[\leadsto \color{blue}{\sqrt{\frac{1}{\mathsf{PI}\left(\right)}}} \cdot \frac{e^{{\left(\left|x\right|\right)}^{2}}}{\left|x\right|} \]
    3. lower-/.f64N/A

      \[\leadsto \sqrt{\color{blue}{\frac{1}{\mathsf{PI}\left(\right)}}} \cdot \frac{e^{{\left(\left|x\right|\right)}^{2}}}{\left|x\right|} \]
    4. lower-PI.f64N/A

      \[\leadsto \sqrt{\frac{1}{\color{blue}{\mathsf{PI}\left(\right)}}} \cdot \frac{e^{{\left(\left|x\right|\right)}^{2}}}{\left|x\right|} \]
    5. lower-/.f64N/A

      \[\leadsto \sqrt{\frac{1}{\mathsf{PI}\left(\right)}} \cdot \color{blue}{\frac{e^{{\left(\left|x\right|\right)}^{2}}}{\left|x\right|}} \]
    6. unpow2N/A

      \[\leadsto \sqrt{\frac{1}{\mathsf{PI}\left(\right)}} \cdot \frac{e^{\color{blue}{\left|x\right| \cdot \left|x\right|}}}{\left|x\right|} \]
    7. sqr-absN/A

      \[\leadsto \sqrt{\frac{1}{\mathsf{PI}\left(\right)}} \cdot \frac{e^{\color{blue}{x \cdot x}}}{\left|x\right|} \]
    8. unpow2N/A

      \[\leadsto \sqrt{\frac{1}{\mathsf{PI}\left(\right)}} \cdot \frac{e^{\color{blue}{{x}^{2}}}}{\left|x\right|} \]
    9. lower-exp.f64N/A

      \[\leadsto \sqrt{\frac{1}{\mathsf{PI}\left(\right)}} \cdot \frac{\color{blue}{e^{{x}^{2}}}}{\left|x\right|} \]
    10. unpow2N/A

      \[\leadsto \sqrt{\frac{1}{\mathsf{PI}\left(\right)}} \cdot \frac{e^{\color{blue}{x \cdot x}}}{\left|x\right|} \]
    11. lower-*.f64N/A

      \[\leadsto \sqrt{\frac{1}{\mathsf{PI}\left(\right)}} \cdot \frac{e^{\color{blue}{x \cdot x}}}{\left|x\right|} \]
    12. lower-fabs.f6499.4

      \[\leadsto \sqrt{\frac{1}{\pi}} \cdot \frac{e^{x \cdot x}}{\color{blue}{\left|x\right|}} \]
  6. Applied rewrites99.4%

    \[\leadsto \color{blue}{\sqrt{\frac{1}{\pi}} \cdot \frac{e^{x \cdot x}}{\left|x\right|}} \]
  7. Taylor expanded in x around 0

    \[\leadsto \sqrt{\frac{1}{\mathsf{PI}\left(\right)}} \cdot \color{blue}{\frac{1}{\left|x\right|}} \]
  8. Step-by-step derivation
    1. Applied rewrites2.3%

      \[\leadsto \frac{\sqrt{\frac{1}{\pi}}}{\color{blue}{\left|x\right|}} \]
    2. Taylor expanded in x around inf

      \[\leadsto \color{blue}{\frac{1}{2} \cdot \left(\frac{e^{{\left(\left|x\right|\right)}^{2}}}{{x}^{2} \cdot \left|x\right|} \cdot \sqrt{\frac{1}{\mathsf{PI}\left(\right)}}\right) + \left(\frac{3}{4} \cdot \left(\frac{e^{{\left(\left|x\right|\right)}^{2}}}{{x}^{4} \cdot \left|x\right|} \cdot \sqrt{\frac{1}{\mathsf{PI}\left(\right)}}\right) + \sqrt{\frac{1}{\mathsf{PI}\left(\right)}} \cdot \frac{e^{{\left(\left|x\right|\right)}^{2}}}{\left|x\right|}\right)} \]
    3. Applied rewrites99.6%

      \[\leadsto \color{blue}{\frac{\sqrt{\frac{1}{\pi}} \cdot e^{x \cdot x}}{\left|x\right|} \cdot \left(\frac{0.75}{\left(x \cdot x\right) \cdot \left(x \cdot x\right)} + \left(\frac{0.5}{x \cdot x} + 1\right)\right)} \]
    4. Final simplification99.6%

      \[\leadsto \frac{e^{x \cdot x} \cdot \sqrt{\frac{1}{\pi}}}{\left|x\right|} \cdot \left(\left(\frac{0.5}{x \cdot x} + 1\right) + \frac{0.75}{\left(x \cdot x\right) \cdot \left(x \cdot x\right)}\right) \]
    5. Add Preprocessing

    Alternative 5: 99.5% accurate, 2.7× speedup?

    \[\begin{array}{l} \\ \frac{e^{x \cdot x}}{\sqrt{\pi}} \cdot \left(\frac{1}{\left|x\right|} + \frac{0.5}{x \cdot \left(x \cdot \left|x\right|\right)}\right) \end{array} \]
    (FPCore (x)
     :precision binary64
     (*
      (/ (exp (* x x)) (sqrt PI))
      (+ (/ 1.0 (fabs x)) (/ 0.5 (* x (* x (fabs x)))))))
    double code(double x) {
    	return (exp((x * x)) / sqrt(((double) M_PI))) * ((1.0 / fabs(x)) + (0.5 / (x * (x * fabs(x)))));
    }
    
    public static double code(double x) {
    	return (Math.exp((x * x)) / Math.sqrt(Math.PI)) * ((1.0 / Math.abs(x)) + (0.5 / (x * (x * Math.abs(x)))));
    }
    
    def code(x):
    	return (math.exp((x * x)) / math.sqrt(math.pi)) * ((1.0 / math.fabs(x)) + (0.5 / (x * (x * math.fabs(x)))))
    
    function code(x)
    	return Float64(Float64(exp(Float64(x * x)) / sqrt(pi)) * Float64(Float64(1.0 / abs(x)) + Float64(0.5 / Float64(x * Float64(x * abs(x))))))
    end
    
    function tmp = code(x)
    	tmp = (exp((x * x)) / sqrt(pi)) * ((1.0 / abs(x)) + (0.5 / (x * (x * abs(x)))));
    end
    
    code[x_] := N[(N[(N[Exp[N[(x * x), $MachinePrecision]], $MachinePrecision] / N[Sqrt[Pi], $MachinePrecision]), $MachinePrecision] * N[(N[(1.0 / N[Abs[x], $MachinePrecision]), $MachinePrecision] + N[(0.5 / N[(x * N[(x * N[Abs[x], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
    
    \begin{array}{l}
    
    \\
    \frac{e^{x \cdot x}}{\sqrt{\pi}} \cdot \left(\frac{1}{\left|x\right|} + \frac{0.5}{x \cdot \left(x \cdot \left|x\right|\right)}\right)
    \end{array}
    
    Derivation
    1. Initial program 100.0%

      \[\left(\frac{1}{\sqrt{\pi}} \cdot e^{\left|x\right| \cdot \left|x\right|}\right) \cdot \left(\left(\left(\frac{1}{\left|x\right|} + \frac{1}{2} \cdot \left(\left(\frac{1}{\left|x\right|} \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right)\right) + \frac{3}{4} \cdot \left(\left(\left(\left(\frac{1}{\left|x\right|} \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right)\right) + \frac{15}{8} \cdot \left(\left(\left(\left(\left(\left(\frac{1}{\left|x\right|} \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right)\right) \]
    2. Add Preprocessing
    3. Applied rewrites100.0%

      \[\leadsto \left(\frac{1}{\sqrt{\pi}} \cdot e^{\left|x\right| \cdot \left|x\right|}\right) \cdot \color{blue}{\left(\frac{\frac{0.5}{x \cdot x} + 1}{\left|x\right|} + \left(\frac{0.75}{\left|x\right| \cdot \left(\left(x \cdot x\right) \cdot \left(x \cdot x\right)\right)} + \frac{1.875}{\left(x \cdot x\right) \cdot \left(\left|x\right| \cdot \left(\left(x \cdot x\right) \cdot \left(x \cdot x\right)\right)\right)}\right)\right)} \]
    4. Applied rewrites100.0%

      \[\leadsto \color{blue}{\frac{e^{x \cdot x}}{\sqrt{\pi}} \cdot \left(\frac{1 + \frac{0.5}{x \cdot x}}{\left|x\right|} + \left(\frac{0.75}{x \cdot \left(\left(x \cdot x\right) \cdot \left(x \cdot x\right)\right)} + \frac{1.875}{\left(x \cdot x\right) \cdot \left(x \cdot \left(\left(x \cdot x\right) \cdot \left(x \cdot x\right)\right)\right)}\right)\right)} \]
    5. Taylor expanded in x around inf

      \[\leadsto \frac{e^{x \cdot x}}{\sqrt{\mathsf{PI}\left(\right)}} \cdot \color{blue}{\left(\frac{1}{\left|x\right|} + \frac{1}{2} \cdot \frac{1}{{x}^{2} \cdot \left|x\right|}\right)} \]
    6. Step-by-step derivation
      1. associate-*r/N/A

        \[\leadsto \frac{e^{x \cdot x}}{\sqrt{\mathsf{PI}\left(\right)}} \cdot \left(\frac{1}{\left|x\right|} + \color{blue}{\frac{\frac{1}{2} \cdot 1}{{x}^{2} \cdot \left|x\right|}}\right) \]
      2. metadata-evalN/A

        \[\leadsto \frac{e^{x \cdot x}}{\sqrt{\mathsf{PI}\left(\right)}} \cdot \left(\frac{1}{\left|x\right|} + \frac{\color{blue}{\frac{1}{2}}}{{x}^{2} \cdot \left|x\right|}\right) \]
      3. lower-+.f64N/A

        \[\leadsto \frac{e^{x \cdot x}}{\sqrt{\mathsf{PI}\left(\right)}} \cdot \color{blue}{\left(\frac{1}{\left|x\right|} + \frac{\frac{1}{2}}{{x}^{2} \cdot \left|x\right|}\right)} \]
      4. lower-/.f64N/A

        \[\leadsto \frac{e^{x \cdot x}}{\sqrt{\mathsf{PI}\left(\right)}} \cdot \left(\color{blue}{\frac{1}{\left|x\right|}} + \frac{\frac{1}{2}}{{x}^{2} \cdot \left|x\right|}\right) \]
      5. lower-fabs.f64N/A

        \[\leadsto \frac{e^{x \cdot x}}{\sqrt{\mathsf{PI}\left(\right)}} \cdot \left(\frac{1}{\color{blue}{\left|x\right|}} + \frac{\frac{1}{2}}{{x}^{2} \cdot \left|x\right|}\right) \]
      6. lower-/.f64N/A

        \[\leadsto \frac{e^{x \cdot x}}{\sqrt{\mathsf{PI}\left(\right)}} \cdot \left(\frac{1}{\left|x\right|} + \color{blue}{\frac{\frac{1}{2}}{{x}^{2} \cdot \left|x\right|}}\right) \]
      7. unpow2N/A

        \[\leadsto \frac{e^{x \cdot x}}{\sqrt{\mathsf{PI}\left(\right)}} \cdot \left(\frac{1}{\left|x\right|} + \frac{\frac{1}{2}}{\color{blue}{\left(x \cdot x\right)} \cdot \left|x\right|}\right) \]
      8. associate-*l*N/A

        \[\leadsto \frac{e^{x \cdot x}}{\sqrt{\mathsf{PI}\left(\right)}} \cdot \left(\frac{1}{\left|x\right|} + \frac{\frac{1}{2}}{\color{blue}{x \cdot \left(x \cdot \left|x\right|\right)}}\right) \]
      9. lower-*.f64N/A

        \[\leadsto \frac{e^{x \cdot x}}{\sqrt{\mathsf{PI}\left(\right)}} \cdot \left(\frac{1}{\left|x\right|} + \frac{\frac{1}{2}}{\color{blue}{x \cdot \left(x \cdot \left|x\right|\right)}}\right) \]
      10. lower-*.f64N/A

        \[\leadsto \frac{e^{x \cdot x}}{\sqrt{\mathsf{PI}\left(\right)}} \cdot \left(\frac{1}{\left|x\right|} + \frac{\frac{1}{2}}{x \cdot \color{blue}{\left(x \cdot \left|x\right|\right)}}\right) \]
      11. lower-fabs.f6499.5

        \[\leadsto \frac{e^{x \cdot x}}{\sqrt{\pi}} \cdot \left(\frac{1}{\left|x\right|} + \frac{0.5}{x \cdot \left(x \cdot \color{blue}{\left|x\right|}\right)}\right) \]
    7. Applied rewrites99.5%

      \[\leadsto \frac{e^{x \cdot x}}{\sqrt{\pi}} \cdot \color{blue}{\left(\frac{1}{\left|x\right|} + \frac{0.5}{x \cdot \left(x \cdot \left|x\right|\right)}\right)} \]
    8. Add Preprocessing

    Alternative 6: 99.4% accurate, 2.9× speedup?

    \[\begin{array}{l} \\ \frac{\left(\frac{0.5}{x \cdot x} + 1\right) \cdot e^{x \cdot x}}{\sqrt{\pi} \cdot \left|x\right|} \end{array} \]
    (FPCore (x)
     :precision binary64
     (/ (* (+ (/ 0.5 (* x x)) 1.0) (exp (* x x))) (* (sqrt PI) (fabs x))))
    double code(double x) {
    	return (((0.5 / (x * x)) + 1.0) * exp((x * x))) / (sqrt(((double) M_PI)) * fabs(x));
    }
    
    public static double code(double x) {
    	return (((0.5 / (x * x)) + 1.0) * Math.exp((x * x))) / (Math.sqrt(Math.PI) * Math.abs(x));
    }
    
    def code(x):
    	return (((0.5 / (x * x)) + 1.0) * math.exp((x * x))) / (math.sqrt(math.pi) * math.fabs(x))
    
    function code(x)
    	return Float64(Float64(Float64(Float64(0.5 / Float64(x * x)) + 1.0) * exp(Float64(x * x))) / Float64(sqrt(pi) * abs(x)))
    end
    
    function tmp = code(x)
    	tmp = (((0.5 / (x * x)) + 1.0) * exp((x * x))) / (sqrt(pi) * abs(x));
    end
    
    code[x_] := N[(N[(N[(N[(0.5 / N[(x * x), $MachinePrecision]), $MachinePrecision] + 1.0), $MachinePrecision] * N[Exp[N[(x * x), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] / N[(N[Sqrt[Pi], $MachinePrecision] * N[Abs[x], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
    
    \begin{array}{l}
    
    \\
    \frac{\left(\frac{0.5}{x \cdot x} + 1\right) \cdot e^{x \cdot x}}{\sqrt{\pi} \cdot \left|x\right|}
    \end{array}
    
    Derivation
    1. Initial program 100.0%

      \[\left(\frac{1}{\sqrt{\pi}} \cdot e^{\left|x\right| \cdot \left|x\right|}\right) \cdot \left(\left(\left(\frac{1}{\left|x\right|} + \frac{1}{2} \cdot \left(\left(\frac{1}{\left|x\right|} \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right)\right) + \frac{3}{4} \cdot \left(\left(\left(\left(\frac{1}{\left|x\right|} \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right)\right) + \frac{15}{8} \cdot \left(\left(\left(\left(\left(\left(\frac{1}{\left|x\right|} \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right)\right) \]
    2. Add Preprocessing
    3. Applied rewrites100.0%

      \[\leadsto \left(\frac{1}{\sqrt{\pi}} \cdot e^{\left|x\right| \cdot \left|x\right|}\right) \cdot \color{blue}{\left(\frac{\frac{0.5}{x \cdot x} + 1}{\left|x\right|} + \left(\frac{0.75}{\left|x\right| \cdot \left(\left(x \cdot x\right) \cdot \left(x \cdot x\right)\right)} + \frac{1.875}{\left(x \cdot x\right) \cdot \left(\left|x\right| \cdot \left(\left(x \cdot x\right) \cdot \left(x \cdot x\right)\right)\right)}\right)\right)} \]
    4. Taylor expanded in x around inf

      \[\leadsto \color{blue}{\frac{1}{2} \cdot \left(\frac{e^{{\left(\left|x\right|\right)}^{2}}}{{x}^{2} \cdot \left|x\right|} \cdot \sqrt{\frac{1}{\mathsf{PI}\left(\right)}}\right) + \sqrt{\frac{1}{\mathsf{PI}\left(\right)}} \cdot \frac{e^{{\left(\left|x\right|\right)}^{2}}}{\left|x\right|}} \]
    5. Step-by-step derivation
      1. associate-*r*N/A

        \[\leadsto \color{blue}{\left(\frac{1}{2} \cdot \frac{e^{{\left(\left|x\right|\right)}^{2}}}{{x}^{2} \cdot \left|x\right|}\right) \cdot \sqrt{\frac{1}{\mathsf{PI}\left(\right)}}} + \sqrt{\frac{1}{\mathsf{PI}\left(\right)}} \cdot \frac{e^{{\left(\left|x\right|\right)}^{2}}}{\left|x\right|} \]
      2. *-commutativeN/A

        \[\leadsto \left(\frac{1}{2} \cdot \frac{e^{{\left(\left|x\right|\right)}^{2}}}{{x}^{2} \cdot \left|x\right|}\right) \cdot \sqrt{\frac{1}{\mathsf{PI}\left(\right)}} + \color{blue}{\frac{e^{{\left(\left|x\right|\right)}^{2}}}{\left|x\right|} \cdot \sqrt{\frac{1}{\mathsf{PI}\left(\right)}}} \]
      3. distribute-rgt-outN/A

        \[\leadsto \color{blue}{\sqrt{\frac{1}{\mathsf{PI}\left(\right)}} \cdot \left(\frac{1}{2} \cdot \frac{e^{{\left(\left|x\right|\right)}^{2}}}{{x}^{2} \cdot \left|x\right|} + \frac{e^{{\left(\left|x\right|\right)}^{2}}}{\left|x\right|}\right)} \]
      4. lower-*.f64N/A

        \[\leadsto \color{blue}{\sqrt{\frac{1}{\mathsf{PI}\left(\right)}} \cdot \left(\frac{1}{2} \cdot \frac{e^{{\left(\left|x\right|\right)}^{2}}}{{x}^{2} \cdot \left|x\right|} + \frac{e^{{\left(\left|x\right|\right)}^{2}}}{\left|x\right|}\right)} \]
      5. lower-sqrt.f64N/A

        \[\leadsto \color{blue}{\sqrt{\frac{1}{\mathsf{PI}\left(\right)}}} \cdot \left(\frac{1}{2} \cdot \frac{e^{{\left(\left|x\right|\right)}^{2}}}{{x}^{2} \cdot \left|x\right|} + \frac{e^{{\left(\left|x\right|\right)}^{2}}}{\left|x\right|}\right) \]
      6. lower-/.f64N/A

        \[\leadsto \sqrt{\color{blue}{\frac{1}{\mathsf{PI}\left(\right)}}} \cdot \left(\frac{1}{2} \cdot \frac{e^{{\left(\left|x\right|\right)}^{2}}}{{x}^{2} \cdot \left|x\right|} + \frac{e^{{\left(\left|x\right|\right)}^{2}}}{\left|x\right|}\right) \]
      7. lower-PI.f64N/A

        \[\leadsto \sqrt{\frac{1}{\color{blue}{\mathsf{PI}\left(\right)}}} \cdot \left(\frac{1}{2} \cdot \frac{e^{{\left(\left|x\right|\right)}^{2}}}{{x}^{2} \cdot \left|x\right|} + \frac{e^{{\left(\left|x\right|\right)}^{2}}}{\left|x\right|}\right) \]
    6. Applied rewrites99.5%

      \[\leadsto \color{blue}{\sqrt{\frac{1}{\pi}} \cdot \left(\left(\frac{0.5}{x \cdot x} + 1\right) \cdot \frac{e^{x \cdot x}}{\left|x\right|}\right)} \]
    7. Step-by-step derivation
      1. Applied rewrites99.5%

        \[\leadsto \color{blue}{\frac{e^{x \cdot x} \cdot \left(1 + \frac{0.5}{x \cdot x}\right)}{\sqrt{\pi} \cdot \left|x\right|}} \]
      2. Final simplification99.5%

        \[\leadsto \frac{\left(\frac{0.5}{x \cdot x} + 1\right) \cdot e^{x \cdot x}}{\sqrt{\pi} \cdot \left|x\right|} \]
      3. Add Preprocessing

      Alternative 7: 88.0% accurate, 3.3× speedup?

      \[\begin{array}{l} \\ \begin{array}{l} t_0 := x \cdot \mathsf{fma}\left(x \cdot x, 0.16666666666666666, 0.5\right)\\ t_1 := \sqrt{\frac{1}{\pi}}\\ \mathbf{if}\;\left|x\right| \leq 10^{+77}:\\ \;\;\;\;t\_1 \cdot \frac{\mathsf{fma}\left(x \cdot x, \frac{\mathsf{fma}\left(x \cdot x, t\_0 \cdot t\_0, -1\right)}{\mathsf{fma}\left(x, t\_0, -1\right)}, 1\right)}{\left|x\right|}\\ \mathbf{else}:\\ \;\;\;\;t\_1 \cdot \frac{\mathsf{fma}\left(x, \mathsf{fma}\left(x, 0.5 \cdot \left(x \cdot x\right), x\right), 1\right)}{\left|x\right|}\\ \end{array} \end{array} \]
      (FPCore (x)
       :precision binary64
       (let* ((t_0 (* x (fma (* x x) 0.16666666666666666 0.5)))
              (t_1 (sqrt (/ 1.0 PI))))
         (if (<= (fabs x) 1e+77)
           (*
            t_1
            (/
             (fma (* x x) (/ (fma (* x x) (* t_0 t_0) -1.0) (fma x t_0 -1.0)) 1.0)
             (fabs x)))
           (* t_1 (/ (fma x (fma x (* 0.5 (* x x)) x) 1.0) (fabs x))))))
      double code(double x) {
      	double t_0 = x * fma((x * x), 0.16666666666666666, 0.5);
      	double t_1 = sqrt((1.0 / ((double) M_PI)));
      	double tmp;
      	if (fabs(x) <= 1e+77) {
      		tmp = t_1 * (fma((x * x), (fma((x * x), (t_0 * t_0), -1.0) / fma(x, t_0, -1.0)), 1.0) / fabs(x));
      	} else {
      		tmp = t_1 * (fma(x, fma(x, (0.5 * (x * x)), x), 1.0) / fabs(x));
      	}
      	return tmp;
      }
      
      function code(x)
      	t_0 = Float64(x * fma(Float64(x * x), 0.16666666666666666, 0.5))
      	t_1 = sqrt(Float64(1.0 / pi))
      	tmp = 0.0
      	if (abs(x) <= 1e+77)
      		tmp = Float64(t_1 * Float64(fma(Float64(x * x), Float64(fma(Float64(x * x), Float64(t_0 * t_0), -1.0) / fma(x, t_0, -1.0)), 1.0) / abs(x)));
      	else
      		tmp = Float64(t_1 * Float64(fma(x, fma(x, Float64(0.5 * Float64(x * x)), x), 1.0) / abs(x)));
      	end
      	return tmp
      end
      
      code[x_] := Block[{t$95$0 = N[(x * N[(N[(x * x), $MachinePrecision] * 0.16666666666666666 + 0.5), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$1 = N[Sqrt[N[(1.0 / Pi), $MachinePrecision]], $MachinePrecision]}, If[LessEqual[N[Abs[x], $MachinePrecision], 1e+77], N[(t$95$1 * N[(N[(N[(x * x), $MachinePrecision] * N[(N[(N[(x * x), $MachinePrecision] * N[(t$95$0 * t$95$0), $MachinePrecision] + -1.0), $MachinePrecision] / N[(x * t$95$0 + -1.0), $MachinePrecision]), $MachinePrecision] + 1.0), $MachinePrecision] / N[Abs[x], $MachinePrecision]), $MachinePrecision]), $MachinePrecision], N[(t$95$1 * N[(N[(x * N[(x * N[(0.5 * N[(x * x), $MachinePrecision]), $MachinePrecision] + x), $MachinePrecision] + 1.0), $MachinePrecision] / N[Abs[x], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]]]]
      
      \begin{array}{l}
      
      \\
      \begin{array}{l}
      t_0 := x \cdot \mathsf{fma}\left(x \cdot x, 0.16666666666666666, 0.5\right)\\
      t_1 := \sqrt{\frac{1}{\pi}}\\
      \mathbf{if}\;\left|x\right| \leq 10^{+77}:\\
      \;\;\;\;t\_1 \cdot \frac{\mathsf{fma}\left(x \cdot x, \frac{\mathsf{fma}\left(x \cdot x, t\_0 \cdot t\_0, -1\right)}{\mathsf{fma}\left(x, t\_0, -1\right)}, 1\right)}{\left|x\right|}\\
      
      \mathbf{else}:\\
      \;\;\;\;t\_1 \cdot \frac{\mathsf{fma}\left(x, \mathsf{fma}\left(x, 0.5 \cdot \left(x \cdot x\right), x\right), 1\right)}{\left|x\right|}\\
      
      
      \end{array}
      \end{array}
      
      Derivation
      1. Split input into 2 regimes
      2. if (fabs.f64 x) < 9.99999999999999983e76

        1. Initial program 99.8%

          \[\left(\frac{1}{\sqrt{\pi}} \cdot e^{\left|x\right| \cdot \left|x\right|}\right) \cdot \left(\left(\left(\frac{1}{\left|x\right|} + \frac{1}{2} \cdot \left(\left(\frac{1}{\left|x\right|} \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right)\right) + \frac{3}{4} \cdot \left(\left(\left(\left(\frac{1}{\left|x\right|} \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right)\right) + \frac{15}{8} \cdot \left(\left(\left(\left(\left(\left(\frac{1}{\left|x\right|} \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right)\right) \]
        2. Add Preprocessing
        3. Applied rewrites99.9%

          \[\leadsto \left(\frac{1}{\sqrt{\pi}} \cdot e^{\left|x\right| \cdot \left|x\right|}\right) \cdot \color{blue}{\left(\frac{\frac{0.5}{x \cdot x} + 1}{\left|x\right|} + \left(\frac{0.75}{\left|x\right| \cdot \left(\left(x \cdot x\right) \cdot \left(x \cdot x\right)\right)} + \frac{1.875}{\left(x \cdot x\right) \cdot \left(\left|x\right| \cdot \left(\left(x \cdot x\right) \cdot \left(x \cdot x\right)\right)\right)}\right)\right)} \]
        4. Taylor expanded in x around inf

          \[\leadsto \color{blue}{\sqrt{\frac{1}{\mathsf{PI}\left(\right)}} \cdot \frac{e^{{\left(\left|x\right|\right)}^{2}}}{\left|x\right|}} \]
        5. Step-by-step derivation
          1. lower-*.f64N/A

            \[\leadsto \color{blue}{\sqrt{\frac{1}{\mathsf{PI}\left(\right)}} \cdot \frac{e^{{\left(\left|x\right|\right)}^{2}}}{\left|x\right|}} \]
          2. lower-sqrt.f64N/A

            \[\leadsto \color{blue}{\sqrt{\frac{1}{\mathsf{PI}\left(\right)}}} \cdot \frac{e^{{\left(\left|x\right|\right)}^{2}}}{\left|x\right|} \]
          3. lower-/.f64N/A

            \[\leadsto \sqrt{\color{blue}{\frac{1}{\mathsf{PI}\left(\right)}}} \cdot \frac{e^{{\left(\left|x\right|\right)}^{2}}}{\left|x\right|} \]
          4. lower-PI.f64N/A

            \[\leadsto \sqrt{\frac{1}{\color{blue}{\mathsf{PI}\left(\right)}}} \cdot \frac{e^{{\left(\left|x\right|\right)}^{2}}}{\left|x\right|} \]
          5. lower-/.f64N/A

            \[\leadsto \sqrt{\frac{1}{\mathsf{PI}\left(\right)}} \cdot \color{blue}{\frac{e^{{\left(\left|x\right|\right)}^{2}}}{\left|x\right|}} \]
          6. unpow2N/A

            \[\leadsto \sqrt{\frac{1}{\mathsf{PI}\left(\right)}} \cdot \frac{e^{\color{blue}{\left|x\right| \cdot \left|x\right|}}}{\left|x\right|} \]
          7. sqr-absN/A

            \[\leadsto \sqrt{\frac{1}{\mathsf{PI}\left(\right)}} \cdot \frac{e^{\color{blue}{x \cdot x}}}{\left|x\right|} \]
          8. unpow2N/A

            \[\leadsto \sqrt{\frac{1}{\mathsf{PI}\left(\right)}} \cdot \frac{e^{\color{blue}{{x}^{2}}}}{\left|x\right|} \]
          9. lower-exp.f64N/A

            \[\leadsto \sqrt{\frac{1}{\mathsf{PI}\left(\right)}} \cdot \frac{\color{blue}{e^{{x}^{2}}}}{\left|x\right|} \]
          10. unpow2N/A

            \[\leadsto \sqrt{\frac{1}{\mathsf{PI}\left(\right)}} \cdot \frac{e^{\color{blue}{x \cdot x}}}{\left|x\right|} \]
          11. lower-*.f64N/A

            \[\leadsto \sqrt{\frac{1}{\mathsf{PI}\left(\right)}} \cdot \frac{e^{\color{blue}{x \cdot x}}}{\left|x\right|} \]
          12. lower-fabs.f6498.1

            \[\leadsto \sqrt{\frac{1}{\pi}} \cdot \frac{e^{x \cdot x}}{\color{blue}{\left|x\right|}} \]
        6. Applied rewrites98.1%

          \[\leadsto \color{blue}{\sqrt{\frac{1}{\pi}} \cdot \frac{e^{x \cdot x}}{\left|x\right|}} \]
        7. Taylor expanded in x around 0

          \[\leadsto \sqrt{\frac{1}{\mathsf{PI}\left(\right)}} \cdot \frac{1 + {x}^{2} \cdot \left(1 + {x}^{2} \cdot \left(\frac{1}{2} + \frac{1}{6} \cdot {x}^{2}\right)\right)}{\left|\color{blue}{x}\right|} \]
        8. Step-by-step derivation
          1. Applied rewrites32.1%

            \[\leadsto \sqrt{\frac{1}{\pi}} \cdot \frac{\mathsf{fma}\left(x \cdot x, \mathsf{fma}\left(x \cdot x, \mathsf{fma}\left(x \cdot x, 0.16666666666666666, 0.5\right), 1\right), 1\right)}{\left|\color{blue}{x}\right|} \]
          2. Step-by-step derivation
            1. Applied rewrites45.0%

              \[\leadsto \sqrt{\frac{1}{\pi}} \cdot \frac{\mathsf{fma}\left(x \cdot x, \frac{\mathsf{fma}\left(x \cdot x, \left(x \cdot \mathsf{fma}\left(x \cdot x, 0.16666666666666666, 0.5\right)\right) \cdot \left(x \cdot \mathsf{fma}\left(x \cdot x, 0.16666666666666666, 0.5\right)\right), -1\right)}{\mathsf{fma}\left(x, x \cdot \mathsf{fma}\left(x \cdot x, 0.16666666666666666, 0.5\right), -1\right)}, 1\right)}{\left|x\right|} \]

            if 9.99999999999999983e76 < (fabs.f64 x)

            1. Initial program 100.0%

              \[\left(\frac{1}{\sqrt{\pi}} \cdot e^{\left|x\right| \cdot \left|x\right|}\right) \cdot \left(\left(\left(\frac{1}{\left|x\right|} + \frac{1}{2} \cdot \left(\left(\frac{1}{\left|x\right|} \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right)\right) + \frac{3}{4} \cdot \left(\left(\left(\left(\frac{1}{\left|x\right|} \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right)\right) + \frac{15}{8} \cdot \left(\left(\left(\left(\left(\left(\frac{1}{\left|x\right|} \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right)\right) \]
            2. Add Preprocessing
            3. Applied rewrites100.0%

              \[\leadsto \left(\frac{1}{\sqrt{\pi}} \cdot e^{\left|x\right| \cdot \left|x\right|}\right) \cdot \color{blue}{\left(\frac{\frac{0.5}{x \cdot x} + 1}{\left|x\right|} + \left(\frac{0.75}{\left|x\right| \cdot \left(\left(x \cdot x\right) \cdot \left(x \cdot x\right)\right)} + \frac{1.875}{\left(x \cdot x\right) \cdot \left(\left|x\right| \cdot \left(\left(x \cdot x\right) \cdot \left(x \cdot x\right)\right)\right)}\right)\right)} \]
            4. Taylor expanded in x around inf

              \[\leadsto \color{blue}{\sqrt{\frac{1}{\mathsf{PI}\left(\right)}} \cdot \frac{e^{{\left(\left|x\right|\right)}^{2}}}{\left|x\right|}} \]
            5. Step-by-step derivation
              1. lower-*.f64N/A

                \[\leadsto \color{blue}{\sqrt{\frac{1}{\mathsf{PI}\left(\right)}} \cdot \frac{e^{{\left(\left|x\right|\right)}^{2}}}{\left|x\right|}} \]
              2. lower-sqrt.f64N/A

                \[\leadsto \color{blue}{\sqrt{\frac{1}{\mathsf{PI}\left(\right)}}} \cdot \frac{e^{{\left(\left|x\right|\right)}^{2}}}{\left|x\right|} \]
              3. lower-/.f64N/A

                \[\leadsto \sqrt{\color{blue}{\frac{1}{\mathsf{PI}\left(\right)}}} \cdot \frac{e^{{\left(\left|x\right|\right)}^{2}}}{\left|x\right|} \]
              4. lower-PI.f64N/A

                \[\leadsto \sqrt{\frac{1}{\color{blue}{\mathsf{PI}\left(\right)}}} \cdot \frac{e^{{\left(\left|x\right|\right)}^{2}}}{\left|x\right|} \]
              5. lower-/.f64N/A

                \[\leadsto \sqrt{\frac{1}{\mathsf{PI}\left(\right)}} \cdot \color{blue}{\frac{e^{{\left(\left|x\right|\right)}^{2}}}{\left|x\right|}} \]
              6. unpow2N/A

                \[\leadsto \sqrt{\frac{1}{\mathsf{PI}\left(\right)}} \cdot \frac{e^{\color{blue}{\left|x\right| \cdot \left|x\right|}}}{\left|x\right|} \]
              7. sqr-absN/A

                \[\leadsto \sqrt{\frac{1}{\mathsf{PI}\left(\right)}} \cdot \frac{e^{\color{blue}{x \cdot x}}}{\left|x\right|} \]
              8. unpow2N/A

                \[\leadsto \sqrt{\frac{1}{\mathsf{PI}\left(\right)}} \cdot \frac{e^{\color{blue}{{x}^{2}}}}{\left|x\right|} \]
              9. lower-exp.f64N/A

                \[\leadsto \sqrt{\frac{1}{\mathsf{PI}\left(\right)}} \cdot \frac{\color{blue}{e^{{x}^{2}}}}{\left|x\right|} \]
              10. unpow2N/A

                \[\leadsto \sqrt{\frac{1}{\mathsf{PI}\left(\right)}} \cdot \frac{e^{\color{blue}{x \cdot x}}}{\left|x\right|} \]
              11. lower-*.f64N/A

                \[\leadsto \sqrt{\frac{1}{\mathsf{PI}\left(\right)}} \cdot \frac{e^{\color{blue}{x \cdot x}}}{\left|x\right|} \]
              12. lower-fabs.f64100.0

                \[\leadsto \sqrt{\frac{1}{\pi}} \cdot \frac{e^{x \cdot x}}{\color{blue}{\left|x\right|}} \]
            6. Applied rewrites100.0%

              \[\leadsto \color{blue}{\sqrt{\frac{1}{\pi}} \cdot \frac{e^{x \cdot x}}{\left|x\right|}} \]
            7. Taylor expanded in x around 0

              \[\leadsto \sqrt{\frac{1}{\mathsf{PI}\left(\right)}} \cdot \frac{1 + {x}^{2} \cdot \left(1 + \frac{1}{2} \cdot {x}^{2}\right)}{\left|\color{blue}{x}\right|} \]
            8. Step-by-step derivation
              1. Applied rewrites100.0%

                \[\leadsto \sqrt{\frac{1}{\pi}} \cdot \frac{\mathsf{fma}\left(x, \mathsf{fma}\left(x, \left(x \cdot x\right) \cdot 0.5, x\right), 1\right)}{\left|\color{blue}{x}\right|} \]
            9. Recombined 2 regimes into one program.
            10. Final simplification84.3%

              \[\leadsto \begin{array}{l} \mathbf{if}\;\left|x\right| \leq 10^{+77}:\\ \;\;\;\;\sqrt{\frac{1}{\pi}} \cdot \frac{\mathsf{fma}\left(x \cdot x, \frac{\mathsf{fma}\left(x \cdot x, \left(x \cdot \mathsf{fma}\left(x \cdot x, 0.16666666666666666, 0.5\right)\right) \cdot \left(x \cdot \mathsf{fma}\left(x \cdot x, 0.16666666666666666, 0.5\right)\right), -1\right)}{\mathsf{fma}\left(x, x \cdot \mathsf{fma}\left(x \cdot x, 0.16666666666666666, 0.5\right), -1\right)}, 1\right)}{\left|x\right|}\\ \mathbf{else}:\\ \;\;\;\;\sqrt{\frac{1}{\pi}} \cdot \frac{\mathsf{fma}\left(x, \mathsf{fma}\left(x, 0.5 \cdot \left(x \cdot x\right), x\right), 1\right)}{\left|x\right|}\\ \end{array} \]
            11. Add Preprocessing

            Alternative 8: 99.4% accurate, 3.5× speedup?

            \[\begin{array}{l} \\ \frac{e^{x \cdot x}}{\sqrt{\pi} \cdot \left|x\right|} \end{array} \]
            (FPCore (x) :precision binary64 (/ (exp (* x x)) (* (sqrt PI) (fabs x))))
            double code(double x) {
            	return exp((x * x)) / (sqrt(((double) M_PI)) * fabs(x));
            }
            
            public static double code(double x) {
            	return Math.exp((x * x)) / (Math.sqrt(Math.PI) * Math.abs(x));
            }
            
            def code(x):
            	return math.exp((x * x)) / (math.sqrt(math.pi) * math.fabs(x))
            
            function code(x)
            	return Float64(exp(Float64(x * x)) / Float64(sqrt(pi) * abs(x)))
            end
            
            function tmp = code(x)
            	tmp = exp((x * x)) / (sqrt(pi) * abs(x));
            end
            
            code[x_] := N[(N[Exp[N[(x * x), $MachinePrecision]], $MachinePrecision] / N[(N[Sqrt[Pi], $MachinePrecision] * N[Abs[x], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
            
            \begin{array}{l}
            
            \\
            \frac{e^{x \cdot x}}{\sqrt{\pi} \cdot \left|x\right|}
            \end{array}
            
            Derivation
            1. Initial program 100.0%

              \[\left(\frac{1}{\sqrt{\pi}} \cdot e^{\left|x\right| \cdot \left|x\right|}\right) \cdot \left(\left(\left(\frac{1}{\left|x\right|} + \frac{1}{2} \cdot \left(\left(\frac{1}{\left|x\right|} \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right)\right) + \frac{3}{4} \cdot \left(\left(\left(\left(\frac{1}{\left|x\right|} \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right)\right) + \frac{15}{8} \cdot \left(\left(\left(\left(\left(\left(\frac{1}{\left|x\right|} \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right)\right) \]
            2. Add Preprocessing
            3. Applied rewrites100.0%

              \[\leadsto \left(\frac{1}{\sqrt{\pi}} \cdot e^{\left|x\right| \cdot \left|x\right|}\right) \cdot \color{blue}{\left(\frac{\frac{0.5}{x \cdot x} + 1}{\left|x\right|} + \left(\frac{0.75}{\left|x\right| \cdot \left(\left(x \cdot x\right) \cdot \left(x \cdot x\right)\right)} + \frac{1.875}{\left(x \cdot x\right) \cdot \left(\left|x\right| \cdot \left(\left(x \cdot x\right) \cdot \left(x \cdot x\right)\right)\right)}\right)\right)} \]
            4. Taylor expanded in x around inf

              \[\leadsto \color{blue}{\sqrt{\frac{1}{\mathsf{PI}\left(\right)}} \cdot \frac{e^{{\left(\left|x\right|\right)}^{2}}}{\left|x\right|}} \]
            5. Step-by-step derivation
              1. lower-*.f64N/A

                \[\leadsto \color{blue}{\sqrt{\frac{1}{\mathsf{PI}\left(\right)}} \cdot \frac{e^{{\left(\left|x\right|\right)}^{2}}}{\left|x\right|}} \]
              2. lower-sqrt.f64N/A

                \[\leadsto \color{blue}{\sqrt{\frac{1}{\mathsf{PI}\left(\right)}}} \cdot \frac{e^{{\left(\left|x\right|\right)}^{2}}}{\left|x\right|} \]
              3. lower-/.f64N/A

                \[\leadsto \sqrt{\color{blue}{\frac{1}{\mathsf{PI}\left(\right)}}} \cdot \frac{e^{{\left(\left|x\right|\right)}^{2}}}{\left|x\right|} \]
              4. lower-PI.f64N/A

                \[\leadsto \sqrt{\frac{1}{\color{blue}{\mathsf{PI}\left(\right)}}} \cdot \frac{e^{{\left(\left|x\right|\right)}^{2}}}{\left|x\right|} \]
              5. lower-/.f64N/A

                \[\leadsto \sqrt{\frac{1}{\mathsf{PI}\left(\right)}} \cdot \color{blue}{\frac{e^{{\left(\left|x\right|\right)}^{2}}}{\left|x\right|}} \]
              6. unpow2N/A

                \[\leadsto \sqrt{\frac{1}{\mathsf{PI}\left(\right)}} \cdot \frac{e^{\color{blue}{\left|x\right| \cdot \left|x\right|}}}{\left|x\right|} \]
              7. sqr-absN/A

                \[\leadsto \sqrt{\frac{1}{\mathsf{PI}\left(\right)}} \cdot \frac{e^{\color{blue}{x \cdot x}}}{\left|x\right|} \]
              8. unpow2N/A

                \[\leadsto \sqrt{\frac{1}{\mathsf{PI}\left(\right)}} \cdot \frac{e^{\color{blue}{{x}^{2}}}}{\left|x\right|} \]
              9. lower-exp.f64N/A

                \[\leadsto \sqrt{\frac{1}{\mathsf{PI}\left(\right)}} \cdot \frac{\color{blue}{e^{{x}^{2}}}}{\left|x\right|} \]
              10. unpow2N/A

                \[\leadsto \sqrt{\frac{1}{\mathsf{PI}\left(\right)}} \cdot \frac{e^{\color{blue}{x \cdot x}}}{\left|x\right|} \]
              11. lower-*.f64N/A

                \[\leadsto \sqrt{\frac{1}{\mathsf{PI}\left(\right)}} \cdot \frac{e^{\color{blue}{x \cdot x}}}{\left|x\right|} \]
              12. lower-fabs.f6499.4

                \[\leadsto \sqrt{\frac{1}{\pi}} \cdot \frac{e^{x \cdot x}}{\color{blue}{\left|x\right|}} \]
            6. Applied rewrites99.4%

              \[\leadsto \color{blue}{\sqrt{\frac{1}{\pi}} \cdot \frac{e^{x \cdot x}}{\left|x\right|}} \]
            7. Step-by-step derivation
              1. Applied rewrites99.4%

                \[\leadsto \color{blue}{\frac{e^{x \cdot x}}{\sqrt{\pi} \cdot \left|x\right|}} \]
              2. Add Preprocessing

              Alternative 9: 84.2% accurate, 4.8× speedup?

              \[\begin{array}{l} \\ \sqrt{\frac{1}{\pi}} \cdot \left(\left(\frac{0.5}{x \cdot x} + 1\right) \cdot \frac{\mathsf{fma}\left(x \cdot x, \mathsf{fma}\left(x \cdot x, \mathsf{fma}\left(x \cdot x, 0.16666666666666666, 0.5\right), 1\right), 1\right)}{\left|x\right|}\right) \end{array} \]
              (FPCore (x)
               :precision binary64
               (*
                (sqrt (/ 1.0 PI))
                (*
                 (+ (/ 0.5 (* x x)) 1.0)
                 (/
                  (fma (* x x) (fma (* x x) (fma (* x x) 0.16666666666666666 0.5) 1.0) 1.0)
                  (fabs x)))))
              double code(double x) {
              	return sqrt((1.0 / ((double) M_PI))) * (((0.5 / (x * x)) + 1.0) * (fma((x * x), fma((x * x), fma((x * x), 0.16666666666666666, 0.5), 1.0), 1.0) / fabs(x)));
              }
              
              function code(x)
              	return Float64(sqrt(Float64(1.0 / pi)) * Float64(Float64(Float64(0.5 / Float64(x * x)) + 1.0) * Float64(fma(Float64(x * x), fma(Float64(x * x), fma(Float64(x * x), 0.16666666666666666, 0.5), 1.0), 1.0) / abs(x))))
              end
              
              code[x_] := N[(N[Sqrt[N[(1.0 / Pi), $MachinePrecision]], $MachinePrecision] * N[(N[(N[(0.5 / N[(x * x), $MachinePrecision]), $MachinePrecision] + 1.0), $MachinePrecision] * N[(N[(N[(x * x), $MachinePrecision] * N[(N[(x * x), $MachinePrecision] * N[(N[(x * x), $MachinePrecision] * 0.16666666666666666 + 0.5), $MachinePrecision] + 1.0), $MachinePrecision] + 1.0), $MachinePrecision] / N[Abs[x], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
              
              \begin{array}{l}
              
              \\
              \sqrt{\frac{1}{\pi}} \cdot \left(\left(\frac{0.5}{x \cdot x} + 1\right) \cdot \frac{\mathsf{fma}\left(x \cdot x, \mathsf{fma}\left(x \cdot x, \mathsf{fma}\left(x \cdot x, 0.16666666666666666, 0.5\right), 1\right), 1\right)}{\left|x\right|}\right)
              \end{array}
              
              Derivation
              1. Initial program 100.0%

                \[\left(\frac{1}{\sqrt{\pi}} \cdot e^{\left|x\right| \cdot \left|x\right|}\right) \cdot \left(\left(\left(\frac{1}{\left|x\right|} + \frac{1}{2} \cdot \left(\left(\frac{1}{\left|x\right|} \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right)\right) + \frac{3}{4} \cdot \left(\left(\left(\left(\frac{1}{\left|x\right|} \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right)\right) + \frac{15}{8} \cdot \left(\left(\left(\left(\left(\left(\frac{1}{\left|x\right|} \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right)\right) \]
              2. Add Preprocessing
              3. Applied rewrites100.0%

                \[\leadsto \left(\frac{1}{\sqrt{\pi}} \cdot e^{\left|x\right| \cdot \left|x\right|}\right) \cdot \color{blue}{\left(\frac{\frac{0.5}{x \cdot x} + 1}{\left|x\right|} + \left(\frac{0.75}{\left|x\right| \cdot \left(\left(x \cdot x\right) \cdot \left(x \cdot x\right)\right)} + \frac{1.875}{\left(x \cdot x\right) \cdot \left(\left|x\right| \cdot \left(\left(x \cdot x\right) \cdot \left(x \cdot x\right)\right)\right)}\right)\right)} \]
              4. Taylor expanded in x around inf

                \[\leadsto \color{blue}{\frac{1}{2} \cdot \left(\frac{e^{{\left(\left|x\right|\right)}^{2}}}{{x}^{2} \cdot \left|x\right|} \cdot \sqrt{\frac{1}{\mathsf{PI}\left(\right)}}\right) + \sqrt{\frac{1}{\mathsf{PI}\left(\right)}} \cdot \frac{e^{{\left(\left|x\right|\right)}^{2}}}{\left|x\right|}} \]
              5. Step-by-step derivation
                1. associate-*r*N/A

                  \[\leadsto \color{blue}{\left(\frac{1}{2} \cdot \frac{e^{{\left(\left|x\right|\right)}^{2}}}{{x}^{2} \cdot \left|x\right|}\right) \cdot \sqrt{\frac{1}{\mathsf{PI}\left(\right)}}} + \sqrt{\frac{1}{\mathsf{PI}\left(\right)}} \cdot \frac{e^{{\left(\left|x\right|\right)}^{2}}}{\left|x\right|} \]
                2. *-commutativeN/A

                  \[\leadsto \left(\frac{1}{2} \cdot \frac{e^{{\left(\left|x\right|\right)}^{2}}}{{x}^{2} \cdot \left|x\right|}\right) \cdot \sqrt{\frac{1}{\mathsf{PI}\left(\right)}} + \color{blue}{\frac{e^{{\left(\left|x\right|\right)}^{2}}}{\left|x\right|} \cdot \sqrt{\frac{1}{\mathsf{PI}\left(\right)}}} \]
                3. distribute-rgt-outN/A

                  \[\leadsto \color{blue}{\sqrt{\frac{1}{\mathsf{PI}\left(\right)}} \cdot \left(\frac{1}{2} \cdot \frac{e^{{\left(\left|x\right|\right)}^{2}}}{{x}^{2} \cdot \left|x\right|} + \frac{e^{{\left(\left|x\right|\right)}^{2}}}{\left|x\right|}\right)} \]
                4. lower-*.f64N/A

                  \[\leadsto \color{blue}{\sqrt{\frac{1}{\mathsf{PI}\left(\right)}} \cdot \left(\frac{1}{2} \cdot \frac{e^{{\left(\left|x\right|\right)}^{2}}}{{x}^{2} \cdot \left|x\right|} + \frac{e^{{\left(\left|x\right|\right)}^{2}}}{\left|x\right|}\right)} \]
                5. lower-sqrt.f64N/A

                  \[\leadsto \color{blue}{\sqrt{\frac{1}{\mathsf{PI}\left(\right)}}} \cdot \left(\frac{1}{2} \cdot \frac{e^{{\left(\left|x\right|\right)}^{2}}}{{x}^{2} \cdot \left|x\right|} + \frac{e^{{\left(\left|x\right|\right)}^{2}}}{\left|x\right|}\right) \]
                6. lower-/.f64N/A

                  \[\leadsto \sqrt{\color{blue}{\frac{1}{\mathsf{PI}\left(\right)}}} \cdot \left(\frac{1}{2} \cdot \frac{e^{{\left(\left|x\right|\right)}^{2}}}{{x}^{2} \cdot \left|x\right|} + \frac{e^{{\left(\left|x\right|\right)}^{2}}}{\left|x\right|}\right) \]
                7. lower-PI.f64N/A

                  \[\leadsto \sqrt{\frac{1}{\color{blue}{\mathsf{PI}\left(\right)}}} \cdot \left(\frac{1}{2} \cdot \frac{e^{{\left(\left|x\right|\right)}^{2}}}{{x}^{2} \cdot \left|x\right|} + \frac{e^{{\left(\left|x\right|\right)}^{2}}}{\left|x\right|}\right) \]
              6. Applied rewrites99.5%

                \[\leadsto \color{blue}{\sqrt{\frac{1}{\pi}} \cdot \left(\left(\frac{0.5}{x \cdot x} + 1\right) \cdot \frac{e^{x \cdot x}}{\left|x\right|}\right)} \]
              7. Taylor expanded in x around 0

                \[\leadsto \sqrt{\frac{1}{\mathsf{PI}\left(\right)}} \cdot \left(\left(\frac{\frac{1}{2}}{x \cdot x} + 1\right) \cdot \frac{1 + {x}^{2} \cdot \left(1 + {x}^{2} \cdot \left(\frac{1}{2} + \frac{1}{6} \cdot {x}^{2}\right)\right)}{\left|\color{blue}{x}\right|}\right) \]
              8. Step-by-step derivation
                1. Applied rewrites80.6%

                  \[\leadsto \sqrt{\frac{1}{\pi}} \cdot \left(\left(\frac{0.5}{x \cdot x} + 1\right) \cdot \frac{\mathsf{fma}\left(x \cdot x, \mathsf{fma}\left(x \cdot x, \mathsf{fma}\left(x \cdot x, 0.16666666666666666, 0.5\right), 1\right), 1\right)}{\left|\color{blue}{x}\right|}\right) \]
                2. Add Preprocessing

                Alternative 10: 84.1% accurate, 7.5× speedup?

                \[\begin{array}{l} \\ \frac{\mathsf{fma}\left(x \cdot x, \mathsf{fma}\left(x, x \cdot \mathsf{fma}\left(x \cdot x, 0.16666666666666666, 0.5\right), 1\right), 1\right)}{\sqrt{\pi} \cdot \left|x\right|} \end{array} \]
                (FPCore (x)
                 :precision binary64
                 (/
                  (fma (* x x) (fma x (* x (fma (* x x) 0.16666666666666666 0.5)) 1.0) 1.0)
                  (* (sqrt PI) (fabs x))))
                double code(double x) {
                	return fma((x * x), fma(x, (x * fma((x * x), 0.16666666666666666, 0.5)), 1.0), 1.0) / (sqrt(((double) M_PI)) * fabs(x));
                }
                
                function code(x)
                	return Float64(fma(Float64(x * x), fma(x, Float64(x * fma(Float64(x * x), 0.16666666666666666, 0.5)), 1.0), 1.0) / Float64(sqrt(pi) * abs(x)))
                end
                
                code[x_] := N[(N[(N[(x * x), $MachinePrecision] * N[(x * N[(x * N[(N[(x * x), $MachinePrecision] * 0.16666666666666666 + 0.5), $MachinePrecision]), $MachinePrecision] + 1.0), $MachinePrecision] + 1.0), $MachinePrecision] / N[(N[Sqrt[Pi], $MachinePrecision] * N[Abs[x], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
                
                \begin{array}{l}
                
                \\
                \frac{\mathsf{fma}\left(x \cdot x, \mathsf{fma}\left(x, x \cdot \mathsf{fma}\left(x \cdot x, 0.16666666666666666, 0.5\right), 1\right), 1\right)}{\sqrt{\pi} \cdot \left|x\right|}
                \end{array}
                
                Derivation
                1. Initial program 100.0%

                  \[\left(\frac{1}{\sqrt{\pi}} \cdot e^{\left|x\right| \cdot \left|x\right|}\right) \cdot \left(\left(\left(\frac{1}{\left|x\right|} + \frac{1}{2} \cdot \left(\left(\frac{1}{\left|x\right|} \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right)\right) + \frac{3}{4} \cdot \left(\left(\left(\left(\frac{1}{\left|x\right|} \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right)\right) + \frac{15}{8} \cdot \left(\left(\left(\left(\left(\left(\frac{1}{\left|x\right|} \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right)\right) \]
                2. Add Preprocessing
                3. Applied rewrites100.0%

                  \[\leadsto \left(\frac{1}{\sqrt{\pi}} \cdot e^{\left|x\right| \cdot \left|x\right|}\right) \cdot \color{blue}{\left(\frac{\frac{0.5}{x \cdot x} + 1}{\left|x\right|} + \left(\frac{0.75}{\left|x\right| \cdot \left(\left(x \cdot x\right) \cdot \left(x \cdot x\right)\right)} + \frac{1.875}{\left(x \cdot x\right) \cdot \left(\left|x\right| \cdot \left(\left(x \cdot x\right) \cdot \left(x \cdot x\right)\right)\right)}\right)\right)} \]
                4. Taylor expanded in x around inf

                  \[\leadsto \color{blue}{\sqrt{\frac{1}{\mathsf{PI}\left(\right)}} \cdot \frac{e^{{\left(\left|x\right|\right)}^{2}}}{\left|x\right|}} \]
                5. Step-by-step derivation
                  1. lower-*.f64N/A

                    \[\leadsto \color{blue}{\sqrt{\frac{1}{\mathsf{PI}\left(\right)}} \cdot \frac{e^{{\left(\left|x\right|\right)}^{2}}}{\left|x\right|}} \]
                  2. lower-sqrt.f64N/A

                    \[\leadsto \color{blue}{\sqrt{\frac{1}{\mathsf{PI}\left(\right)}}} \cdot \frac{e^{{\left(\left|x\right|\right)}^{2}}}{\left|x\right|} \]
                  3. lower-/.f64N/A

                    \[\leadsto \sqrt{\color{blue}{\frac{1}{\mathsf{PI}\left(\right)}}} \cdot \frac{e^{{\left(\left|x\right|\right)}^{2}}}{\left|x\right|} \]
                  4. lower-PI.f64N/A

                    \[\leadsto \sqrt{\frac{1}{\color{blue}{\mathsf{PI}\left(\right)}}} \cdot \frac{e^{{\left(\left|x\right|\right)}^{2}}}{\left|x\right|} \]
                  5. lower-/.f64N/A

                    \[\leadsto \sqrt{\frac{1}{\mathsf{PI}\left(\right)}} \cdot \color{blue}{\frac{e^{{\left(\left|x\right|\right)}^{2}}}{\left|x\right|}} \]
                  6. unpow2N/A

                    \[\leadsto \sqrt{\frac{1}{\mathsf{PI}\left(\right)}} \cdot \frac{e^{\color{blue}{\left|x\right| \cdot \left|x\right|}}}{\left|x\right|} \]
                  7. sqr-absN/A

                    \[\leadsto \sqrt{\frac{1}{\mathsf{PI}\left(\right)}} \cdot \frac{e^{\color{blue}{x \cdot x}}}{\left|x\right|} \]
                  8. unpow2N/A

                    \[\leadsto \sqrt{\frac{1}{\mathsf{PI}\left(\right)}} \cdot \frac{e^{\color{blue}{{x}^{2}}}}{\left|x\right|} \]
                  9. lower-exp.f64N/A

                    \[\leadsto \sqrt{\frac{1}{\mathsf{PI}\left(\right)}} \cdot \frac{\color{blue}{e^{{x}^{2}}}}{\left|x\right|} \]
                  10. unpow2N/A

                    \[\leadsto \sqrt{\frac{1}{\mathsf{PI}\left(\right)}} \cdot \frac{e^{\color{blue}{x \cdot x}}}{\left|x\right|} \]
                  11. lower-*.f64N/A

                    \[\leadsto \sqrt{\frac{1}{\mathsf{PI}\left(\right)}} \cdot \frac{e^{\color{blue}{x \cdot x}}}{\left|x\right|} \]
                  12. lower-fabs.f6499.4

                    \[\leadsto \sqrt{\frac{1}{\pi}} \cdot \frac{e^{x \cdot x}}{\color{blue}{\left|x\right|}} \]
                6. Applied rewrites99.4%

                  \[\leadsto \color{blue}{\sqrt{\frac{1}{\pi}} \cdot \frac{e^{x \cdot x}}{\left|x\right|}} \]
                7. Taylor expanded in x around 0

                  \[\leadsto \sqrt{\frac{1}{\mathsf{PI}\left(\right)}} \cdot \frac{1 + {x}^{2} \cdot \left(1 + {x}^{2} \cdot \left(\frac{1}{2} + \frac{1}{6} \cdot {x}^{2}\right)\right)}{\left|\color{blue}{x}\right|} \]
                8. Step-by-step derivation
                  1. Applied rewrites80.6%

                    \[\leadsto \sqrt{\frac{1}{\pi}} \cdot \frac{\mathsf{fma}\left(x \cdot x, \mathsf{fma}\left(x \cdot x, \mathsf{fma}\left(x \cdot x, 0.16666666666666666, 0.5\right), 1\right), 1\right)}{\left|\color{blue}{x}\right|} \]
                  2. Step-by-step derivation
                    1. Applied rewrites80.6%

                      \[\leadsto \color{blue}{\frac{-\mathsf{fma}\left(x \cdot x, \mathsf{fma}\left(x, x \cdot \mathsf{fma}\left(x \cdot x, 0.16666666666666666, 0.5\right), 1\right), 1\right)}{\left(-\sqrt{\pi}\right) \cdot \left|x\right|}} \]
                    2. Final simplification80.6%

                      \[\leadsto \frac{\mathsf{fma}\left(x \cdot x, \mathsf{fma}\left(x, x \cdot \mathsf{fma}\left(x \cdot x, 0.16666666666666666, 0.5\right), 1\right), 1\right)}{\sqrt{\pi} \cdot \left|x\right|} \]
                    3. Add Preprocessing

                    Alternative 11: 76.1% accurate, 7.5× speedup?

                    \[\begin{array}{l} \\ \sqrt{\frac{1}{\pi}} \cdot \frac{\mathsf{fma}\left(x, \mathsf{fma}\left(x, 0.5 \cdot \left(x \cdot x\right), x\right), 1\right)}{\left|x\right|} \end{array} \]
                    (FPCore (x)
                     :precision binary64
                     (* (sqrt (/ 1.0 PI)) (/ (fma x (fma x (* 0.5 (* x x)) x) 1.0) (fabs x))))
                    double code(double x) {
                    	return sqrt((1.0 / ((double) M_PI))) * (fma(x, fma(x, (0.5 * (x * x)), x), 1.0) / fabs(x));
                    }
                    
                    function code(x)
                    	return Float64(sqrt(Float64(1.0 / pi)) * Float64(fma(x, fma(x, Float64(0.5 * Float64(x * x)), x), 1.0) / abs(x)))
                    end
                    
                    code[x_] := N[(N[Sqrt[N[(1.0 / Pi), $MachinePrecision]], $MachinePrecision] * N[(N[(x * N[(x * N[(0.5 * N[(x * x), $MachinePrecision]), $MachinePrecision] + x), $MachinePrecision] + 1.0), $MachinePrecision] / N[Abs[x], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
                    
                    \begin{array}{l}
                    
                    \\
                    \sqrt{\frac{1}{\pi}} \cdot \frac{\mathsf{fma}\left(x, \mathsf{fma}\left(x, 0.5 \cdot \left(x \cdot x\right), x\right), 1\right)}{\left|x\right|}
                    \end{array}
                    
                    Derivation
                    1. Initial program 100.0%

                      \[\left(\frac{1}{\sqrt{\pi}} \cdot e^{\left|x\right| \cdot \left|x\right|}\right) \cdot \left(\left(\left(\frac{1}{\left|x\right|} + \frac{1}{2} \cdot \left(\left(\frac{1}{\left|x\right|} \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right)\right) + \frac{3}{4} \cdot \left(\left(\left(\left(\frac{1}{\left|x\right|} \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right)\right) + \frac{15}{8} \cdot \left(\left(\left(\left(\left(\left(\frac{1}{\left|x\right|} \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right)\right) \]
                    2. Add Preprocessing
                    3. Applied rewrites100.0%

                      \[\leadsto \left(\frac{1}{\sqrt{\pi}} \cdot e^{\left|x\right| \cdot \left|x\right|}\right) \cdot \color{blue}{\left(\frac{\frac{0.5}{x \cdot x} + 1}{\left|x\right|} + \left(\frac{0.75}{\left|x\right| \cdot \left(\left(x \cdot x\right) \cdot \left(x \cdot x\right)\right)} + \frac{1.875}{\left(x \cdot x\right) \cdot \left(\left|x\right| \cdot \left(\left(x \cdot x\right) \cdot \left(x \cdot x\right)\right)\right)}\right)\right)} \]
                    4. Taylor expanded in x around inf

                      \[\leadsto \color{blue}{\sqrt{\frac{1}{\mathsf{PI}\left(\right)}} \cdot \frac{e^{{\left(\left|x\right|\right)}^{2}}}{\left|x\right|}} \]
                    5. Step-by-step derivation
                      1. lower-*.f64N/A

                        \[\leadsto \color{blue}{\sqrt{\frac{1}{\mathsf{PI}\left(\right)}} \cdot \frac{e^{{\left(\left|x\right|\right)}^{2}}}{\left|x\right|}} \]
                      2. lower-sqrt.f64N/A

                        \[\leadsto \color{blue}{\sqrt{\frac{1}{\mathsf{PI}\left(\right)}}} \cdot \frac{e^{{\left(\left|x\right|\right)}^{2}}}{\left|x\right|} \]
                      3. lower-/.f64N/A

                        \[\leadsto \sqrt{\color{blue}{\frac{1}{\mathsf{PI}\left(\right)}}} \cdot \frac{e^{{\left(\left|x\right|\right)}^{2}}}{\left|x\right|} \]
                      4. lower-PI.f64N/A

                        \[\leadsto \sqrt{\frac{1}{\color{blue}{\mathsf{PI}\left(\right)}}} \cdot \frac{e^{{\left(\left|x\right|\right)}^{2}}}{\left|x\right|} \]
                      5. lower-/.f64N/A

                        \[\leadsto \sqrt{\frac{1}{\mathsf{PI}\left(\right)}} \cdot \color{blue}{\frac{e^{{\left(\left|x\right|\right)}^{2}}}{\left|x\right|}} \]
                      6. unpow2N/A

                        \[\leadsto \sqrt{\frac{1}{\mathsf{PI}\left(\right)}} \cdot \frac{e^{\color{blue}{\left|x\right| \cdot \left|x\right|}}}{\left|x\right|} \]
                      7. sqr-absN/A

                        \[\leadsto \sqrt{\frac{1}{\mathsf{PI}\left(\right)}} \cdot \frac{e^{\color{blue}{x \cdot x}}}{\left|x\right|} \]
                      8. unpow2N/A

                        \[\leadsto \sqrt{\frac{1}{\mathsf{PI}\left(\right)}} \cdot \frac{e^{\color{blue}{{x}^{2}}}}{\left|x\right|} \]
                      9. lower-exp.f64N/A

                        \[\leadsto \sqrt{\frac{1}{\mathsf{PI}\left(\right)}} \cdot \frac{\color{blue}{e^{{x}^{2}}}}{\left|x\right|} \]
                      10. unpow2N/A

                        \[\leadsto \sqrt{\frac{1}{\mathsf{PI}\left(\right)}} \cdot \frac{e^{\color{blue}{x \cdot x}}}{\left|x\right|} \]
                      11. lower-*.f64N/A

                        \[\leadsto \sqrt{\frac{1}{\mathsf{PI}\left(\right)}} \cdot \frac{e^{\color{blue}{x \cdot x}}}{\left|x\right|} \]
                      12. lower-fabs.f6499.4

                        \[\leadsto \sqrt{\frac{1}{\pi}} \cdot \frac{e^{x \cdot x}}{\color{blue}{\left|x\right|}} \]
                    6. Applied rewrites99.4%

                      \[\leadsto \color{blue}{\sqrt{\frac{1}{\pi}} \cdot \frac{e^{x \cdot x}}{\left|x\right|}} \]
                    7. Taylor expanded in x around 0

                      \[\leadsto \sqrt{\frac{1}{\mathsf{PI}\left(\right)}} \cdot \frac{1 + {x}^{2} \cdot \left(1 + \frac{1}{2} \cdot {x}^{2}\right)}{\left|\color{blue}{x}\right|} \]
                    8. Step-by-step derivation
                      1. Applied rewrites72.7%

                        \[\leadsto \sqrt{\frac{1}{\pi}} \cdot \frac{\mathsf{fma}\left(x, \mathsf{fma}\left(x, \left(x \cdot x\right) \cdot 0.5, x\right), 1\right)}{\left|\color{blue}{x}\right|} \]
                      2. Final simplification72.7%

                        \[\leadsto \sqrt{\frac{1}{\pi}} \cdot \frac{\mathsf{fma}\left(x, \mathsf{fma}\left(x, 0.5 \cdot \left(x \cdot x\right), x\right), 1\right)}{\left|x\right|} \]
                      3. Add Preprocessing

                      Alternative 12: 68.0% accurate, 7.9× speedup?

                      \[\begin{array}{l} \\ \sqrt{\frac{1}{\pi}} \cdot \mathsf{fma}\left(\left|x\right|, \mathsf{fma}\left(x, x \cdot 0.5, 1\right), \frac{1}{\left|x\right|}\right) \end{array} \]
                      (FPCore (x)
                       :precision binary64
                       (* (sqrt (/ 1.0 PI)) (fma (fabs x) (fma x (* x 0.5) 1.0) (/ 1.0 (fabs x)))))
                      double code(double x) {
                      	return sqrt((1.0 / ((double) M_PI))) * fma(fabs(x), fma(x, (x * 0.5), 1.0), (1.0 / fabs(x)));
                      }
                      
                      function code(x)
                      	return Float64(sqrt(Float64(1.0 / pi)) * fma(abs(x), fma(x, Float64(x * 0.5), 1.0), Float64(1.0 / abs(x))))
                      end
                      
                      code[x_] := N[(N[Sqrt[N[(1.0 / Pi), $MachinePrecision]], $MachinePrecision] * N[(N[Abs[x], $MachinePrecision] * N[(x * N[(x * 0.5), $MachinePrecision] + 1.0), $MachinePrecision] + N[(1.0 / N[Abs[x], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
                      
                      \begin{array}{l}
                      
                      \\
                      \sqrt{\frac{1}{\pi}} \cdot \mathsf{fma}\left(\left|x\right|, \mathsf{fma}\left(x, x \cdot 0.5, 1\right), \frac{1}{\left|x\right|}\right)
                      \end{array}
                      
                      Derivation
                      1. Initial program 100.0%

                        \[\left(\frac{1}{\sqrt{\pi}} \cdot e^{\left|x\right| \cdot \left|x\right|}\right) \cdot \left(\left(\left(\frac{1}{\left|x\right|} + \frac{1}{2} \cdot \left(\left(\frac{1}{\left|x\right|} \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right)\right) + \frac{3}{4} \cdot \left(\left(\left(\left(\frac{1}{\left|x\right|} \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right)\right) + \frac{15}{8} \cdot \left(\left(\left(\left(\left(\left(\frac{1}{\left|x\right|} \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right)\right) \]
                      2. Add Preprocessing
                      3. Applied rewrites100.0%

                        \[\leadsto \left(\frac{1}{\sqrt{\pi}} \cdot e^{\left|x\right| \cdot \left|x\right|}\right) \cdot \color{blue}{\left(\frac{\frac{0.5}{x \cdot x} + 1}{\left|x\right|} + \left(\frac{0.75}{\left|x\right| \cdot \left(\left(x \cdot x\right) \cdot \left(x \cdot x\right)\right)} + \frac{1.875}{\left(x \cdot x\right) \cdot \left(\left|x\right| \cdot \left(\left(x \cdot x\right) \cdot \left(x \cdot x\right)\right)\right)}\right)\right)} \]
                      4. Taylor expanded in x around inf

                        \[\leadsto \color{blue}{\sqrt{\frac{1}{\mathsf{PI}\left(\right)}} \cdot \frac{e^{{\left(\left|x\right|\right)}^{2}}}{\left|x\right|}} \]
                      5. Step-by-step derivation
                        1. lower-*.f64N/A

                          \[\leadsto \color{blue}{\sqrt{\frac{1}{\mathsf{PI}\left(\right)}} \cdot \frac{e^{{\left(\left|x\right|\right)}^{2}}}{\left|x\right|}} \]
                        2. lower-sqrt.f64N/A

                          \[\leadsto \color{blue}{\sqrt{\frac{1}{\mathsf{PI}\left(\right)}}} \cdot \frac{e^{{\left(\left|x\right|\right)}^{2}}}{\left|x\right|} \]
                        3. lower-/.f64N/A

                          \[\leadsto \sqrt{\color{blue}{\frac{1}{\mathsf{PI}\left(\right)}}} \cdot \frac{e^{{\left(\left|x\right|\right)}^{2}}}{\left|x\right|} \]
                        4. lower-PI.f64N/A

                          \[\leadsto \sqrt{\frac{1}{\color{blue}{\mathsf{PI}\left(\right)}}} \cdot \frac{e^{{\left(\left|x\right|\right)}^{2}}}{\left|x\right|} \]
                        5. lower-/.f64N/A

                          \[\leadsto \sqrt{\frac{1}{\mathsf{PI}\left(\right)}} \cdot \color{blue}{\frac{e^{{\left(\left|x\right|\right)}^{2}}}{\left|x\right|}} \]
                        6. unpow2N/A

                          \[\leadsto \sqrt{\frac{1}{\mathsf{PI}\left(\right)}} \cdot \frac{e^{\color{blue}{\left|x\right| \cdot \left|x\right|}}}{\left|x\right|} \]
                        7. sqr-absN/A

                          \[\leadsto \sqrt{\frac{1}{\mathsf{PI}\left(\right)}} \cdot \frac{e^{\color{blue}{x \cdot x}}}{\left|x\right|} \]
                        8. unpow2N/A

                          \[\leadsto \sqrt{\frac{1}{\mathsf{PI}\left(\right)}} \cdot \frac{e^{\color{blue}{{x}^{2}}}}{\left|x\right|} \]
                        9. lower-exp.f64N/A

                          \[\leadsto \sqrt{\frac{1}{\mathsf{PI}\left(\right)}} \cdot \frac{\color{blue}{e^{{x}^{2}}}}{\left|x\right|} \]
                        10. unpow2N/A

                          \[\leadsto \sqrt{\frac{1}{\mathsf{PI}\left(\right)}} \cdot \frac{e^{\color{blue}{x \cdot x}}}{\left|x\right|} \]
                        11. lower-*.f64N/A

                          \[\leadsto \sqrt{\frac{1}{\mathsf{PI}\left(\right)}} \cdot \frac{e^{\color{blue}{x \cdot x}}}{\left|x\right|} \]
                        12. lower-fabs.f6499.4

                          \[\leadsto \sqrt{\frac{1}{\pi}} \cdot \frac{e^{x \cdot x}}{\color{blue}{\left|x\right|}} \]
                      6. Applied rewrites99.4%

                        \[\leadsto \color{blue}{\sqrt{\frac{1}{\pi}} \cdot \frac{e^{x \cdot x}}{\left|x\right|}} \]
                      7. Taylor expanded in x around 0

                        \[\leadsto \sqrt{\frac{1}{\mathsf{PI}\left(\right)}} \cdot \left({x}^{2} \cdot \left(\frac{1}{2} \cdot \frac{{x}^{2}}{\left|x\right|} + \frac{1}{\left|x\right|}\right) + \color{blue}{\frac{1}{\left|x\right|}}\right) \]
                      8. Step-by-step derivation
                        1. Applied rewrites67.0%

                          \[\leadsto \sqrt{\frac{1}{\pi}} \cdot \mathsf{fma}\left(\left|x\right|, \color{blue}{\mathsf{fma}\left(x, x \cdot 0.5, 1\right)}, \frac{1}{\left|x\right|}\right) \]
                        2. Add Preprocessing

                        Alternative 13: 50.9% accurate, 13.3× speedup?

                        \[\begin{array}{l} \\ \frac{\mathsf{fma}\left(x, x, 1\right)}{\sqrt{\pi} \cdot \left|x\right|} \end{array} \]
                        (FPCore (x) :precision binary64 (/ (fma x x 1.0) (* (sqrt PI) (fabs x))))
                        double code(double x) {
                        	return fma(x, x, 1.0) / (sqrt(((double) M_PI)) * fabs(x));
                        }
                        
                        function code(x)
                        	return Float64(fma(x, x, 1.0) / Float64(sqrt(pi) * abs(x)))
                        end
                        
                        code[x_] := N[(N[(x * x + 1.0), $MachinePrecision] / N[(N[Sqrt[Pi], $MachinePrecision] * N[Abs[x], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
                        
                        \begin{array}{l}
                        
                        \\
                        \frac{\mathsf{fma}\left(x, x, 1\right)}{\sqrt{\pi} \cdot \left|x\right|}
                        \end{array}
                        
                        Derivation
                        1. Initial program 100.0%

                          \[\left(\frac{1}{\sqrt{\pi}} \cdot e^{\left|x\right| \cdot \left|x\right|}\right) \cdot \left(\left(\left(\frac{1}{\left|x\right|} + \frac{1}{2} \cdot \left(\left(\frac{1}{\left|x\right|} \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right)\right) + \frac{3}{4} \cdot \left(\left(\left(\left(\frac{1}{\left|x\right|} \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right)\right) + \frac{15}{8} \cdot \left(\left(\left(\left(\left(\left(\frac{1}{\left|x\right|} \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right)\right) \]
                        2. Add Preprocessing
                        3. Applied rewrites100.0%

                          \[\leadsto \left(\frac{1}{\sqrt{\pi}} \cdot e^{\left|x\right| \cdot \left|x\right|}\right) \cdot \color{blue}{\left(\frac{\frac{0.5}{x \cdot x} + 1}{\left|x\right|} + \left(\frac{0.75}{\left|x\right| \cdot \left(\left(x \cdot x\right) \cdot \left(x \cdot x\right)\right)} + \frac{1.875}{\left(x \cdot x\right) \cdot \left(\left|x\right| \cdot \left(\left(x \cdot x\right) \cdot \left(x \cdot x\right)\right)\right)}\right)\right)} \]
                        4. Taylor expanded in x around inf

                          \[\leadsto \color{blue}{\sqrt{\frac{1}{\mathsf{PI}\left(\right)}} \cdot \frac{e^{{\left(\left|x\right|\right)}^{2}}}{\left|x\right|}} \]
                        5. Step-by-step derivation
                          1. lower-*.f64N/A

                            \[\leadsto \color{blue}{\sqrt{\frac{1}{\mathsf{PI}\left(\right)}} \cdot \frac{e^{{\left(\left|x\right|\right)}^{2}}}{\left|x\right|}} \]
                          2. lower-sqrt.f64N/A

                            \[\leadsto \color{blue}{\sqrt{\frac{1}{\mathsf{PI}\left(\right)}}} \cdot \frac{e^{{\left(\left|x\right|\right)}^{2}}}{\left|x\right|} \]
                          3. lower-/.f64N/A

                            \[\leadsto \sqrt{\color{blue}{\frac{1}{\mathsf{PI}\left(\right)}}} \cdot \frac{e^{{\left(\left|x\right|\right)}^{2}}}{\left|x\right|} \]
                          4. lower-PI.f64N/A

                            \[\leadsto \sqrt{\frac{1}{\color{blue}{\mathsf{PI}\left(\right)}}} \cdot \frac{e^{{\left(\left|x\right|\right)}^{2}}}{\left|x\right|} \]
                          5. lower-/.f64N/A

                            \[\leadsto \sqrt{\frac{1}{\mathsf{PI}\left(\right)}} \cdot \color{blue}{\frac{e^{{\left(\left|x\right|\right)}^{2}}}{\left|x\right|}} \]
                          6. unpow2N/A

                            \[\leadsto \sqrt{\frac{1}{\mathsf{PI}\left(\right)}} \cdot \frac{e^{\color{blue}{\left|x\right| \cdot \left|x\right|}}}{\left|x\right|} \]
                          7. sqr-absN/A

                            \[\leadsto \sqrt{\frac{1}{\mathsf{PI}\left(\right)}} \cdot \frac{e^{\color{blue}{x \cdot x}}}{\left|x\right|} \]
                          8. unpow2N/A

                            \[\leadsto \sqrt{\frac{1}{\mathsf{PI}\left(\right)}} \cdot \frac{e^{\color{blue}{{x}^{2}}}}{\left|x\right|} \]
                          9. lower-exp.f64N/A

                            \[\leadsto \sqrt{\frac{1}{\mathsf{PI}\left(\right)}} \cdot \frac{\color{blue}{e^{{x}^{2}}}}{\left|x\right|} \]
                          10. unpow2N/A

                            \[\leadsto \sqrt{\frac{1}{\mathsf{PI}\left(\right)}} \cdot \frac{e^{\color{blue}{x \cdot x}}}{\left|x\right|} \]
                          11. lower-*.f64N/A

                            \[\leadsto \sqrt{\frac{1}{\mathsf{PI}\left(\right)}} \cdot \frac{e^{\color{blue}{x \cdot x}}}{\left|x\right|} \]
                          12. lower-fabs.f6499.4

                            \[\leadsto \sqrt{\frac{1}{\pi}} \cdot \frac{e^{x \cdot x}}{\color{blue}{\left|x\right|}} \]
                        6. Applied rewrites99.4%

                          \[\leadsto \color{blue}{\sqrt{\frac{1}{\pi}} \cdot \frac{e^{x \cdot x}}{\left|x\right|}} \]
                        7. Taylor expanded in x around 0

                          \[\leadsto \sqrt{\frac{1}{\mathsf{PI}\left(\right)}} \cdot \frac{1 + {x}^{2}}{\left|\color{blue}{x}\right|} \]
                        8. Step-by-step derivation
                          1. Applied rewrites53.8%

                            \[\leadsto \sqrt{\frac{1}{\pi}} \cdot \frac{\mathsf{fma}\left(x, x, 1\right)}{\left|\color{blue}{x}\right|} \]
                          2. Step-by-step derivation
                            1. Applied rewrites53.8%

                              \[\leadsto \color{blue}{\frac{-\mathsf{fma}\left(x, x, 1\right)}{\left(-\sqrt{\pi}\right) \cdot \left|x\right|}} \]
                            2. Final simplification53.8%

                              \[\leadsto \frac{\mathsf{fma}\left(x, x, 1\right)}{\sqrt{\pi} \cdot \left|x\right|} \]
                            3. Add Preprocessing

                            Alternative 14: 2.3% accurate, 16.1× speedup?

                            \[\begin{array}{l} \\ \frac{1}{\sqrt{\pi} \cdot \left|x\right|} \end{array} \]
                            (FPCore (x) :precision binary64 (/ 1.0 (* (sqrt PI) (fabs x))))
                            double code(double x) {
                            	return 1.0 / (sqrt(((double) M_PI)) * fabs(x));
                            }
                            
                            public static double code(double x) {
                            	return 1.0 / (Math.sqrt(Math.PI) * Math.abs(x));
                            }
                            
                            def code(x):
                            	return 1.0 / (math.sqrt(math.pi) * math.fabs(x))
                            
                            function code(x)
                            	return Float64(1.0 / Float64(sqrt(pi) * abs(x)))
                            end
                            
                            function tmp = code(x)
                            	tmp = 1.0 / (sqrt(pi) * abs(x));
                            end
                            
                            code[x_] := N[(1.0 / N[(N[Sqrt[Pi], $MachinePrecision] * N[Abs[x], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
                            
                            \begin{array}{l}
                            
                            \\
                            \frac{1}{\sqrt{\pi} \cdot \left|x\right|}
                            \end{array}
                            
                            Derivation
                            1. Initial program 100.0%

                              \[\left(\frac{1}{\sqrt{\pi}} \cdot e^{\left|x\right| \cdot \left|x\right|}\right) \cdot \left(\left(\left(\frac{1}{\left|x\right|} + \frac{1}{2} \cdot \left(\left(\frac{1}{\left|x\right|} \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right)\right) + \frac{3}{4} \cdot \left(\left(\left(\left(\frac{1}{\left|x\right|} \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right)\right) + \frac{15}{8} \cdot \left(\left(\left(\left(\left(\left(\frac{1}{\left|x\right|} \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right)\right) \]
                            2. Add Preprocessing
                            3. Applied rewrites100.0%

                              \[\leadsto \left(\frac{1}{\sqrt{\pi}} \cdot e^{\left|x\right| \cdot \left|x\right|}\right) \cdot \color{blue}{\left(\frac{\frac{0.5}{x \cdot x} + 1}{\left|x\right|} + \left(\frac{0.75}{\left|x\right| \cdot \left(\left(x \cdot x\right) \cdot \left(x \cdot x\right)\right)} + \frac{1.875}{\left(x \cdot x\right) \cdot \left(\left|x\right| \cdot \left(\left(x \cdot x\right) \cdot \left(x \cdot x\right)\right)\right)}\right)\right)} \]
                            4. Taylor expanded in x around inf

                              \[\leadsto \color{blue}{\sqrt{\frac{1}{\mathsf{PI}\left(\right)}} \cdot \frac{e^{{\left(\left|x\right|\right)}^{2}}}{\left|x\right|}} \]
                            5. Step-by-step derivation
                              1. lower-*.f64N/A

                                \[\leadsto \color{blue}{\sqrt{\frac{1}{\mathsf{PI}\left(\right)}} \cdot \frac{e^{{\left(\left|x\right|\right)}^{2}}}{\left|x\right|}} \]
                              2. lower-sqrt.f64N/A

                                \[\leadsto \color{blue}{\sqrt{\frac{1}{\mathsf{PI}\left(\right)}}} \cdot \frac{e^{{\left(\left|x\right|\right)}^{2}}}{\left|x\right|} \]
                              3. lower-/.f64N/A

                                \[\leadsto \sqrt{\color{blue}{\frac{1}{\mathsf{PI}\left(\right)}}} \cdot \frac{e^{{\left(\left|x\right|\right)}^{2}}}{\left|x\right|} \]
                              4. lower-PI.f64N/A

                                \[\leadsto \sqrt{\frac{1}{\color{blue}{\mathsf{PI}\left(\right)}}} \cdot \frac{e^{{\left(\left|x\right|\right)}^{2}}}{\left|x\right|} \]
                              5. lower-/.f64N/A

                                \[\leadsto \sqrt{\frac{1}{\mathsf{PI}\left(\right)}} \cdot \color{blue}{\frac{e^{{\left(\left|x\right|\right)}^{2}}}{\left|x\right|}} \]
                              6. unpow2N/A

                                \[\leadsto \sqrt{\frac{1}{\mathsf{PI}\left(\right)}} \cdot \frac{e^{\color{blue}{\left|x\right| \cdot \left|x\right|}}}{\left|x\right|} \]
                              7. sqr-absN/A

                                \[\leadsto \sqrt{\frac{1}{\mathsf{PI}\left(\right)}} \cdot \frac{e^{\color{blue}{x \cdot x}}}{\left|x\right|} \]
                              8. unpow2N/A

                                \[\leadsto \sqrt{\frac{1}{\mathsf{PI}\left(\right)}} \cdot \frac{e^{\color{blue}{{x}^{2}}}}{\left|x\right|} \]
                              9. lower-exp.f64N/A

                                \[\leadsto \sqrt{\frac{1}{\mathsf{PI}\left(\right)}} \cdot \frac{\color{blue}{e^{{x}^{2}}}}{\left|x\right|} \]
                              10. unpow2N/A

                                \[\leadsto \sqrt{\frac{1}{\mathsf{PI}\left(\right)}} \cdot \frac{e^{\color{blue}{x \cdot x}}}{\left|x\right|} \]
                              11. lower-*.f64N/A

                                \[\leadsto \sqrt{\frac{1}{\mathsf{PI}\left(\right)}} \cdot \frac{e^{\color{blue}{x \cdot x}}}{\left|x\right|} \]
                              12. lower-fabs.f6499.4

                                \[\leadsto \sqrt{\frac{1}{\pi}} \cdot \frac{e^{x \cdot x}}{\color{blue}{\left|x\right|}} \]
                            6. Applied rewrites99.4%

                              \[\leadsto \color{blue}{\sqrt{\frac{1}{\pi}} \cdot \frac{e^{x \cdot x}}{\left|x\right|}} \]
                            7. Taylor expanded in x around 0

                              \[\leadsto \sqrt{\frac{1}{\mathsf{PI}\left(\right)}} \cdot \color{blue}{\frac{1}{\left|x\right|}} \]
                            8. Step-by-step derivation
                              1. Applied rewrites2.3%

                                \[\leadsto \frac{\sqrt{\frac{1}{\pi}}}{\color{blue}{\left|x\right|}} \]
                              2. Step-by-step derivation
                                1. Applied rewrites2.3%

                                  \[\leadsto \frac{1}{\sqrt{\pi} \cdot \color{blue}{\left|x\right|}} \]
                                2. Add Preprocessing

                                Reproduce

                                ?
                                herbie shell --seed 2024222 
                                (FPCore (x)
                                  :name "Jmat.Real.erfi, branch x greater than or equal to 5"
                                  :precision binary64
                                  :pre (>= x 0.5)
                                  (* (* (/ 1.0 (sqrt PI)) (exp (* (fabs x) (fabs x)))) (+ (+ (+ (/ 1.0 (fabs x)) (* (/ 1.0 2.0) (* (* (/ 1.0 (fabs x)) (/ 1.0 (fabs x))) (/ 1.0 (fabs x))))) (* (/ 3.0 4.0) (* (* (* (* (/ 1.0 (fabs x)) (/ 1.0 (fabs x))) (/ 1.0 (fabs x))) (/ 1.0 (fabs x))) (/ 1.0 (fabs x))))) (* (/ 15.0 8.0) (* (* (* (* (* (* (/ 1.0 (fabs x)) (/ 1.0 (fabs x))) (/ 1.0 (fabs x))) (/ 1.0 (fabs x))) (/ 1.0 (fabs x))) (/ 1.0 (fabs x))) (/ 1.0 (fabs x)))))))