Kahan p13 Example 3

Percentage Accurate: 100.0% → 100.0%
Time: 12.9s
Alternatives: 6
Speedup: N/A×

Specification

?
\[\begin{array}{l} \\ \begin{array}{l} t_1 := 2 - \frac{\frac{2}{t}}{1 + \frac{1}{t}}\\ 1 - \frac{1}{2 + t\_1 \cdot t\_1} \end{array} \end{array} \]
(FPCore (t)
 :precision binary64
 (let* ((t_1 (- 2.0 (/ (/ 2.0 t) (+ 1.0 (/ 1.0 t))))))
   (- 1.0 (/ 1.0 (+ 2.0 (* t_1 t_1))))))
double code(double t) {
	double t_1 = 2.0 - ((2.0 / t) / (1.0 + (1.0 / t)));
	return 1.0 - (1.0 / (2.0 + (t_1 * t_1)));
}
real(8) function code(t)
    real(8), intent (in) :: t
    real(8) :: t_1
    t_1 = 2.0d0 - ((2.0d0 / t) / (1.0d0 + (1.0d0 / t)))
    code = 1.0d0 - (1.0d0 / (2.0d0 + (t_1 * t_1)))
end function
public static double code(double t) {
	double t_1 = 2.0 - ((2.0 / t) / (1.0 + (1.0 / t)));
	return 1.0 - (1.0 / (2.0 + (t_1 * t_1)));
}
def code(t):
	t_1 = 2.0 - ((2.0 / t) / (1.0 + (1.0 / t)))
	return 1.0 - (1.0 / (2.0 + (t_1 * t_1)))
function code(t)
	t_1 = Float64(2.0 - Float64(Float64(2.0 / t) / Float64(1.0 + Float64(1.0 / t))))
	return Float64(1.0 - Float64(1.0 / Float64(2.0 + Float64(t_1 * t_1))))
end
function tmp = code(t)
	t_1 = 2.0 - ((2.0 / t) / (1.0 + (1.0 / t)));
	tmp = 1.0 - (1.0 / (2.0 + (t_1 * t_1)));
end
code[t_] := Block[{t$95$1 = N[(2.0 - N[(N[(2.0 / t), $MachinePrecision] / N[(1.0 + N[(1.0 / t), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]}, N[(1.0 - N[(1.0 / N[(2.0 + N[(t$95$1 * t$95$1), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]]
\begin{array}{l}

\\
\begin{array}{l}
t_1 := 2 - \frac{\frac{2}{t}}{1 + \frac{1}{t}}\\
1 - \frac{1}{2 + t\_1 \cdot t\_1}
\end{array}
\end{array}

Sampling outcomes in binary64 precision:

Local Percentage Accuracy vs ?

The average percentage accuracy by input value. Horizontal axis shows value of an input variable; the variable is choosen in the title. Vertical axis is accuracy; higher is better. Red represent the original program, while blue represents Herbie's suggestion. These can be toggled with buttons below the plot. The line is an average while dots represent individual samples.

Accuracy vs Speed?

Herbie found 6 alternatives:

AlternativeAccuracySpeedup
The accuracy (vertical axis) and speed (horizontal axis) of each alternatives. Up and to the right is better. The red square shows the initial program, and each blue circle shows an alternative.The line shows the best available speed-accuracy tradeoffs.

Initial Program: 100.0% accurate, 1.0× speedup?

\[\begin{array}{l} \\ \begin{array}{l} t_1 := 2 - \frac{\frac{2}{t}}{1 + \frac{1}{t}}\\ 1 - \frac{1}{2 + t\_1 \cdot t\_1} \end{array} \end{array} \]
(FPCore (t)
 :precision binary64
 (let* ((t_1 (- 2.0 (/ (/ 2.0 t) (+ 1.0 (/ 1.0 t))))))
   (- 1.0 (/ 1.0 (+ 2.0 (* t_1 t_1))))))
double code(double t) {
	double t_1 = 2.0 - ((2.0 / t) / (1.0 + (1.0 / t)));
	return 1.0 - (1.0 / (2.0 + (t_1 * t_1)));
}
real(8) function code(t)
    real(8), intent (in) :: t
    real(8) :: t_1
    t_1 = 2.0d0 - ((2.0d0 / t) / (1.0d0 + (1.0d0 / t)))
    code = 1.0d0 - (1.0d0 / (2.0d0 + (t_1 * t_1)))
end function
public static double code(double t) {
	double t_1 = 2.0 - ((2.0 / t) / (1.0 + (1.0 / t)));
	return 1.0 - (1.0 / (2.0 + (t_1 * t_1)));
}
def code(t):
	t_1 = 2.0 - ((2.0 / t) / (1.0 + (1.0 / t)))
	return 1.0 - (1.0 / (2.0 + (t_1 * t_1)))
function code(t)
	t_1 = Float64(2.0 - Float64(Float64(2.0 / t) / Float64(1.0 + Float64(1.0 / t))))
	return Float64(1.0 - Float64(1.0 / Float64(2.0 + Float64(t_1 * t_1))))
end
function tmp = code(t)
	t_1 = 2.0 - ((2.0 / t) / (1.0 + (1.0 / t)));
	tmp = 1.0 - (1.0 / (2.0 + (t_1 * t_1)));
end
code[t_] := Block[{t$95$1 = N[(2.0 - N[(N[(2.0 / t), $MachinePrecision] / N[(1.0 + N[(1.0 / t), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]}, N[(1.0 - N[(1.0 / N[(2.0 + N[(t$95$1 * t$95$1), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]]
\begin{array}{l}

\\
\begin{array}{l}
t_1 := 2 - \frac{\frac{2}{t}}{1 + \frac{1}{t}}\\
1 - \frac{1}{2 + t\_1 \cdot t\_1}
\end{array}
\end{array}

Alternative 1: 100.0% accurate, 2.1× speedup?

\[\begin{array}{l} \\ 1 + \frac{1}{\frac{\frac{4}{1 + t} - 8}{-1 - t} - 6} \end{array} \]
(FPCore (t)
 :precision binary64
 (+ 1.0 (/ 1.0 (- (/ (- (/ 4.0 (+ 1.0 t)) 8.0) (- -1.0 t)) 6.0))))
double code(double t) {
	return 1.0 + (1.0 / ((((4.0 / (1.0 + t)) - 8.0) / (-1.0 - t)) - 6.0));
}
real(8) function code(t)
    real(8), intent (in) :: t
    code = 1.0d0 + (1.0d0 / ((((4.0d0 / (1.0d0 + t)) - 8.0d0) / ((-1.0d0) - t)) - 6.0d0))
end function
public static double code(double t) {
	return 1.0 + (1.0 / ((((4.0 / (1.0 + t)) - 8.0) / (-1.0 - t)) - 6.0));
}
def code(t):
	return 1.0 + (1.0 / ((((4.0 / (1.0 + t)) - 8.0) / (-1.0 - t)) - 6.0))
function code(t)
	return Float64(1.0 + Float64(1.0 / Float64(Float64(Float64(Float64(4.0 / Float64(1.0 + t)) - 8.0) / Float64(-1.0 - t)) - 6.0)))
end
function tmp = code(t)
	tmp = 1.0 + (1.0 / ((((4.0 / (1.0 + t)) - 8.0) / (-1.0 - t)) - 6.0));
end
code[t_] := N[(1.0 + N[(1.0 / N[(N[(N[(N[(4.0 / N[(1.0 + t), $MachinePrecision]), $MachinePrecision] - 8.0), $MachinePrecision] / N[(-1.0 - t), $MachinePrecision]), $MachinePrecision] - 6.0), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
1 + \frac{1}{\frac{\frac{4}{1 + t} - 8}{-1 - t} - 6}
\end{array}
Derivation
  1. Initial program 100.0%

    \[1 - \frac{1}{2 + \left(2 - \frac{\frac{2}{t}}{1 + \frac{1}{t}}\right) \cdot \left(2 - \frac{\frac{2}{t}}{1 + \frac{1}{t}}\right)} \]
  2. Add Preprocessing
  3. Applied rewrites100.0%

    \[\leadsto 1 - \frac{1}{\color{blue}{\left(2 + \left(4 + \left(-\frac{4}{\mathsf{fma}\left(t, \frac{1}{t}, t\right)}\right)\right)\right) + \frac{\frac{4}{\mathsf{fma}\left(t, \frac{1}{t}, t\right)} - 4}{\mathsf{fma}\left(t, \frac{1}{t}, t\right)}}} \]
  4. Step-by-step derivation
    1. lift-+.f64N/A

      \[\leadsto 1 - \frac{1}{\color{blue}{\left(2 + \left(4 + \left(\mathsf{neg}\left(\frac{4}{\mathsf{fma}\left(t, \frac{1}{t}, t\right)}\right)\right)\right)\right) + \frac{\frac{4}{\mathsf{fma}\left(t, \frac{1}{t}, t\right)} - 4}{\mathsf{fma}\left(t, \frac{1}{t}, t\right)}}} \]
    2. lift-+.f64N/A

      \[\leadsto 1 - \frac{1}{\color{blue}{\left(2 + \left(4 + \left(\mathsf{neg}\left(\frac{4}{\mathsf{fma}\left(t, \frac{1}{t}, t\right)}\right)\right)\right)\right)} + \frac{\frac{4}{\mathsf{fma}\left(t, \frac{1}{t}, t\right)} - 4}{\mathsf{fma}\left(t, \frac{1}{t}, t\right)}} \]
    3. associate-+l+N/A

      \[\leadsto 1 - \frac{1}{\color{blue}{2 + \left(\left(4 + \left(\mathsf{neg}\left(\frac{4}{\mathsf{fma}\left(t, \frac{1}{t}, t\right)}\right)\right)\right) + \frac{\frac{4}{\mathsf{fma}\left(t, \frac{1}{t}, t\right)} - 4}{\mathsf{fma}\left(t, \frac{1}{t}, t\right)}\right)}} \]
    4. +-commutativeN/A

      \[\leadsto 1 - \frac{1}{\color{blue}{\left(\left(4 + \left(\mathsf{neg}\left(\frac{4}{\mathsf{fma}\left(t, \frac{1}{t}, t\right)}\right)\right)\right) + \frac{\frac{4}{\mathsf{fma}\left(t, \frac{1}{t}, t\right)} - 4}{\mathsf{fma}\left(t, \frac{1}{t}, t\right)}\right) + 2}} \]
    5. lower-+.f64N/A

      \[\leadsto 1 - \frac{1}{\color{blue}{\left(\left(4 + \left(\mathsf{neg}\left(\frac{4}{\mathsf{fma}\left(t, \frac{1}{t}, t\right)}\right)\right)\right) + \frac{\frac{4}{\mathsf{fma}\left(t, \frac{1}{t}, t\right)} - 4}{\mathsf{fma}\left(t, \frac{1}{t}, t\right)}\right) + 2}} \]
  5. Applied rewrites100.0%

    \[\leadsto 1 - \frac{1}{\color{blue}{\left(4 - \frac{4 - \left(\frac{4}{t + 1} + -4\right)}{t + 1}\right) + 2}} \]
  6. Step-by-step derivation
    1. lift-+.f64N/A

      \[\leadsto 1 - \frac{1}{\color{blue}{\left(4 - \frac{4 - \left(\frac{4}{t + 1} + -4\right)}{t + 1}\right) + 2}} \]
    2. +-commutativeN/A

      \[\leadsto 1 - \frac{1}{\color{blue}{2 + \left(4 - \frac{4 - \left(\frac{4}{t + 1} + -4\right)}{t + 1}\right)}} \]
    3. lift--.f64N/A

      \[\leadsto 1 - \frac{1}{2 + \color{blue}{\left(4 - \frac{4 - \left(\frac{4}{t + 1} + -4\right)}{t + 1}\right)}} \]
    4. associate-+r-N/A

      \[\leadsto 1 - \frac{1}{\color{blue}{\left(2 + 4\right) - \frac{4 - \left(\frac{4}{t + 1} + -4\right)}{t + 1}}} \]
    5. metadata-evalN/A

      \[\leadsto 1 - \frac{1}{\color{blue}{6} - \frac{4 - \left(\frac{4}{t + 1} + -4\right)}{t + 1}} \]
    6. metadata-evalN/A

      \[\leadsto 1 - \frac{1}{\color{blue}{2 \cdot 3} - \frac{4 - \left(\frac{4}{t + 1} + -4\right)}{t + 1}} \]
    7. lower--.f64N/A

      \[\leadsto 1 - \frac{1}{\color{blue}{2 \cdot 3 - \frac{4 - \left(\frac{4}{t + 1} + -4\right)}{t + 1}}} \]
    8. metadata-eval100.0

      \[\leadsto 1 - \frac{1}{\color{blue}{6} - \frac{4 - \left(\frac{4}{t + 1} + -4\right)}{t + 1}} \]
    9. lift--.f64N/A

      \[\leadsto 1 - \frac{1}{6 - \frac{\color{blue}{4 - \left(\frac{4}{t + 1} + -4\right)}}{t + 1}} \]
    10. lift-+.f64N/A

      \[\leadsto 1 - \frac{1}{6 - \frac{4 - \color{blue}{\left(\frac{4}{t + 1} + -4\right)}}{t + 1}} \]
    11. +-commutativeN/A

      \[\leadsto 1 - \frac{1}{6 - \frac{4 - \color{blue}{\left(-4 + \frac{4}{t + 1}\right)}}{t + 1}} \]
    12. associate--r+N/A

      \[\leadsto 1 - \frac{1}{6 - \frac{\color{blue}{\left(4 - -4\right) - \frac{4}{t + 1}}}{t + 1}} \]
    13. metadata-evalN/A

      \[\leadsto 1 - \frac{1}{6 - \frac{\color{blue}{8} - \frac{4}{t + 1}}{t + 1}} \]
    14. metadata-evalN/A

      \[\leadsto 1 - \frac{1}{6 - \frac{\color{blue}{{2}^{3}} - \frac{4}{t + 1}}{t + 1}} \]
    15. lower--.f64N/A

      \[\leadsto 1 - \frac{1}{6 - \frac{\color{blue}{{2}^{3} - \frac{4}{t + 1}}}{t + 1}} \]
    16. metadata-eval100.0

      \[\leadsto 1 - \frac{1}{6 - \frac{\color{blue}{8} - \frac{4}{t + 1}}{t + 1}} \]
  7. Applied rewrites100.0%

    \[\leadsto 1 - \frac{1}{\color{blue}{6 - \frac{8 - \frac{4}{t + 1}}{t + 1}}} \]
  8. Final simplification100.0%

    \[\leadsto 1 + \frac{1}{\frac{\frac{4}{1 + t} - 8}{-1 - t} - 6} \]
  9. Add Preprocessing

Alternative 2: 98.1% accurate, 1.2× speedup?

\[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;\frac{\frac{2}{t}}{1 + \frac{1}{t}} \leq 5 \cdot 10^{-17}:\\ \;\;\;\;0.8333333333333334 + \frac{\frac{0.037037037037037035 + \frac{0.04938271604938271}{t}}{t} + -0.2222222222222222}{t}\\ \mathbf{else}:\\ \;\;\;\;0.5\\ \end{array} \end{array} \]
(FPCore (t)
 :precision binary64
 (if (<= (/ (/ 2.0 t) (+ 1.0 (/ 1.0 t))) 5e-17)
   (+
    0.8333333333333334
    (/
     (+
      (/ (+ 0.037037037037037035 (/ 0.04938271604938271 t)) t)
      -0.2222222222222222)
     t))
   0.5))
double code(double t) {
	double tmp;
	if (((2.0 / t) / (1.0 + (1.0 / t))) <= 5e-17) {
		tmp = 0.8333333333333334 + ((((0.037037037037037035 + (0.04938271604938271 / t)) / t) + -0.2222222222222222) / t);
	} else {
		tmp = 0.5;
	}
	return tmp;
}
real(8) function code(t)
    real(8), intent (in) :: t
    real(8) :: tmp
    if (((2.0d0 / t) / (1.0d0 + (1.0d0 / t))) <= 5d-17) then
        tmp = 0.8333333333333334d0 + ((((0.037037037037037035d0 + (0.04938271604938271d0 / t)) / t) + (-0.2222222222222222d0)) / t)
    else
        tmp = 0.5d0
    end if
    code = tmp
end function
public static double code(double t) {
	double tmp;
	if (((2.0 / t) / (1.0 + (1.0 / t))) <= 5e-17) {
		tmp = 0.8333333333333334 + ((((0.037037037037037035 + (0.04938271604938271 / t)) / t) + -0.2222222222222222) / t);
	} else {
		tmp = 0.5;
	}
	return tmp;
}
def code(t):
	tmp = 0
	if ((2.0 / t) / (1.0 + (1.0 / t))) <= 5e-17:
		tmp = 0.8333333333333334 + ((((0.037037037037037035 + (0.04938271604938271 / t)) / t) + -0.2222222222222222) / t)
	else:
		tmp = 0.5
	return tmp
function code(t)
	tmp = 0.0
	if (Float64(Float64(2.0 / t) / Float64(1.0 + Float64(1.0 / t))) <= 5e-17)
		tmp = Float64(0.8333333333333334 + Float64(Float64(Float64(Float64(0.037037037037037035 + Float64(0.04938271604938271 / t)) / t) + -0.2222222222222222) / t));
	else
		tmp = 0.5;
	end
	return tmp
end
function tmp_2 = code(t)
	tmp = 0.0;
	if (((2.0 / t) / (1.0 + (1.0 / t))) <= 5e-17)
		tmp = 0.8333333333333334 + ((((0.037037037037037035 + (0.04938271604938271 / t)) / t) + -0.2222222222222222) / t);
	else
		tmp = 0.5;
	end
	tmp_2 = tmp;
end
code[t_] := If[LessEqual[N[(N[(2.0 / t), $MachinePrecision] / N[(1.0 + N[(1.0 / t), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], 5e-17], N[(0.8333333333333334 + N[(N[(N[(N[(0.037037037037037035 + N[(0.04938271604938271 / t), $MachinePrecision]), $MachinePrecision] / t), $MachinePrecision] + -0.2222222222222222), $MachinePrecision] / t), $MachinePrecision]), $MachinePrecision], 0.5]
\begin{array}{l}

\\
\begin{array}{l}
\mathbf{if}\;\frac{\frac{2}{t}}{1 + \frac{1}{t}} \leq 5 \cdot 10^{-17}:\\
\;\;\;\;0.8333333333333334 + \frac{\frac{0.037037037037037035 + \frac{0.04938271604938271}{t}}{t} + -0.2222222222222222}{t}\\

\mathbf{else}:\\
\;\;\;\;0.5\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if (/.f64 (/.f64 #s(literal 2 binary64) t) (+.f64 #s(literal 1 binary64) (/.f64 #s(literal 1 binary64) t))) < 4.9999999999999999e-17

    1. Initial program 100.0%

      \[1 - \frac{1}{2 + \left(2 - \frac{\frac{2}{t}}{1 + \frac{1}{t}}\right) \cdot \left(2 - \frac{\frac{2}{t}}{1 + \frac{1}{t}}\right)} \]
    2. Add Preprocessing
    3. Taylor expanded in t around -inf

      \[\leadsto \color{blue}{\frac{5}{6} + -1 \cdot \frac{\frac{2}{9} + -1 \cdot \frac{\frac{1}{27} + \frac{4}{81} \cdot \frac{1}{t}}{t}}{t}} \]
    4. Step-by-step derivation
      1. lower-+.f64N/A

        \[\leadsto \color{blue}{\frac{5}{6} + -1 \cdot \frac{\frac{2}{9} + -1 \cdot \frac{\frac{1}{27} + \frac{4}{81} \cdot \frac{1}{t}}{t}}{t}} \]
      2. mul-1-negN/A

        \[\leadsto \frac{5}{6} + \color{blue}{\left(\mathsf{neg}\left(\frac{\frac{2}{9} + -1 \cdot \frac{\frac{1}{27} + \frac{4}{81} \cdot \frac{1}{t}}{t}}{t}\right)\right)} \]
      3. distribute-neg-fracN/A

        \[\leadsto \frac{5}{6} + \color{blue}{\frac{\mathsf{neg}\left(\left(\frac{2}{9} + -1 \cdot \frac{\frac{1}{27} + \frac{4}{81} \cdot \frac{1}{t}}{t}\right)\right)}{t}} \]
      4. distribute-neg-inN/A

        \[\leadsto \frac{5}{6} + \frac{\color{blue}{\left(\mathsf{neg}\left(\frac{2}{9}\right)\right) + \left(\mathsf{neg}\left(-1 \cdot \frac{\frac{1}{27} + \frac{4}{81} \cdot \frac{1}{t}}{t}\right)\right)}}{t} \]
      5. mul-1-negN/A

        \[\leadsto \frac{5}{6} + \frac{\left(\mathsf{neg}\left(\frac{2}{9}\right)\right) + \left(\mathsf{neg}\left(\color{blue}{\left(\mathsf{neg}\left(\frac{\frac{1}{27} + \frac{4}{81} \cdot \frac{1}{t}}{t}\right)\right)}\right)\right)}{t} \]
      6. remove-double-negN/A

        \[\leadsto \frac{5}{6} + \frac{\left(\mathsf{neg}\left(\frac{2}{9}\right)\right) + \color{blue}{\frac{\frac{1}{27} + \frac{4}{81} \cdot \frac{1}{t}}{t}}}{t} \]
      7. +-commutativeN/A

        \[\leadsto \frac{5}{6} + \frac{\color{blue}{\frac{\frac{1}{27} + \frac{4}{81} \cdot \frac{1}{t}}{t} + \left(\mathsf{neg}\left(\frac{2}{9}\right)\right)}}{t} \]
      8. sub-negN/A

        \[\leadsto \frac{5}{6} + \frac{\color{blue}{\frac{\frac{1}{27} + \frac{4}{81} \cdot \frac{1}{t}}{t} - \frac{2}{9}}}{t} \]
      9. lower-/.f64N/A

        \[\leadsto \frac{5}{6} + \color{blue}{\frac{\frac{\frac{1}{27} + \frac{4}{81} \cdot \frac{1}{t}}{t} - \frac{2}{9}}{t}} \]
    5. Applied rewrites99.2%

      \[\leadsto \color{blue}{0.8333333333333334 + \frac{\frac{0.037037037037037035 + \frac{0.04938271604938271}{t}}{t} + -0.2222222222222222}{t}} \]

    if 4.9999999999999999e-17 < (/.f64 (/.f64 #s(literal 2 binary64) t) (+.f64 #s(literal 1 binary64) (/.f64 #s(literal 1 binary64) t)))

    1. Initial program 100.0%

      \[1 - \frac{1}{2 + \left(2 - \frac{\frac{2}{t}}{1 + \frac{1}{t}}\right) \cdot \left(2 - \frac{\frac{2}{t}}{1 + \frac{1}{t}}\right)} \]
    2. Add Preprocessing
    3. Taylor expanded in t around 0

      \[\leadsto \color{blue}{\frac{1}{2}} \]
    4. Step-by-step derivation
      1. Applied rewrites100.0%

        \[\leadsto \color{blue}{0.5} \]
    5. Recombined 2 regimes into one program.
    6. Add Preprocessing

    Alternative 3: 98.1% accurate, 1.5× speedup?

    \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;\frac{\frac{2}{t}}{1 + \frac{1}{t}} \leq 5 \cdot 10^{-17}:\\ \;\;\;\;0.8333333333333334 + \frac{\mathsf{fma}\left(t, -0.2222222222222222, 0.037037037037037035\right)}{t \cdot t}\\ \mathbf{else}:\\ \;\;\;\;0.5\\ \end{array} \end{array} \]
    (FPCore (t)
     :precision binary64
     (if (<= (/ (/ 2.0 t) (+ 1.0 (/ 1.0 t))) 5e-17)
       (+
        0.8333333333333334
        (/ (fma t -0.2222222222222222 0.037037037037037035) (* t t)))
       0.5))
    double code(double t) {
    	double tmp;
    	if (((2.0 / t) / (1.0 + (1.0 / t))) <= 5e-17) {
    		tmp = 0.8333333333333334 + (fma(t, -0.2222222222222222, 0.037037037037037035) / (t * t));
    	} else {
    		tmp = 0.5;
    	}
    	return tmp;
    }
    
    function code(t)
    	tmp = 0.0
    	if (Float64(Float64(2.0 / t) / Float64(1.0 + Float64(1.0 / t))) <= 5e-17)
    		tmp = Float64(0.8333333333333334 + Float64(fma(t, -0.2222222222222222, 0.037037037037037035) / Float64(t * t)));
    	else
    		tmp = 0.5;
    	end
    	return tmp
    end
    
    code[t_] := If[LessEqual[N[(N[(2.0 / t), $MachinePrecision] / N[(1.0 + N[(1.0 / t), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], 5e-17], N[(0.8333333333333334 + N[(N[(t * -0.2222222222222222 + 0.037037037037037035), $MachinePrecision] / N[(t * t), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], 0.5]
    
    \begin{array}{l}
    
    \\
    \begin{array}{l}
    \mathbf{if}\;\frac{\frac{2}{t}}{1 + \frac{1}{t}} \leq 5 \cdot 10^{-17}:\\
    \;\;\;\;0.8333333333333334 + \frac{\mathsf{fma}\left(t, -0.2222222222222222, 0.037037037037037035\right)}{t \cdot t}\\
    
    \mathbf{else}:\\
    \;\;\;\;0.5\\
    
    
    \end{array}
    \end{array}
    
    Derivation
    1. Split input into 2 regimes
    2. if (/.f64 (/.f64 #s(literal 2 binary64) t) (+.f64 #s(literal 1 binary64) (/.f64 #s(literal 1 binary64) t))) < 4.9999999999999999e-17

      1. Initial program 100.0%

        \[1 - \frac{1}{2 + \left(2 - \frac{\frac{2}{t}}{1 + \frac{1}{t}}\right) \cdot \left(2 - \frac{\frac{2}{t}}{1 + \frac{1}{t}}\right)} \]
      2. Add Preprocessing
      3. Applied rewrites100.0%

        \[\leadsto 1 - \frac{1}{\color{blue}{\left(2 + \left(4 + \left(-\frac{4}{\mathsf{fma}\left(t, \frac{1}{t}, t\right)}\right)\right)\right) + \frac{\frac{4}{\mathsf{fma}\left(t, \frac{1}{t}, t\right)} - 4}{\mathsf{fma}\left(t, \frac{1}{t}, t\right)}}} \]
      4. Step-by-step derivation
        1. lift-+.f64N/A

          \[\leadsto 1 - \frac{1}{\color{blue}{\left(2 + \left(4 + \left(\mathsf{neg}\left(\frac{4}{\mathsf{fma}\left(t, \frac{1}{t}, t\right)}\right)\right)\right)\right) + \frac{\frac{4}{\mathsf{fma}\left(t, \frac{1}{t}, t\right)} - 4}{\mathsf{fma}\left(t, \frac{1}{t}, t\right)}}} \]
        2. lift-+.f64N/A

          \[\leadsto 1 - \frac{1}{\color{blue}{\left(2 + \left(4 + \left(\mathsf{neg}\left(\frac{4}{\mathsf{fma}\left(t, \frac{1}{t}, t\right)}\right)\right)\right)\right)} + \frac{\frac{4}{\mathsf{fma}\left(t, \frac{1}{t}, t\right)} - 4}{\mathsf{fma}\left(t, \frac{1}{t}, t\right)}} \]
        3. associate-+l+N/A

          \[\leadsto 1 - \frac{1}{\color{blue}{2 + \left(\left(4 + \left(\mathsf{neg}\left(\frac{4}{\mathsf{fma}\left(t, \frac{1}{t}, t\right)}\right)\right)\right) + \frac{\frac{4}{\mathsf{fma}\left(t, \frac{1}{t}, t\right)} - 4}{\mathsf{fma}\left(t, \frac{1}{t}, t\right)}\right)}} \]
        4. +-commutativeN/A

          \[\leadsto 1 - \frac{1}{\color{blue}{\left(\left(4 + \left(\mathsf{neg}\left(\frac{4}{\mathsf{fma}\left(t, \frac{1}{t}, t\right)}\right)\right)\right) + \frac{\frac{4}{\mathsf{fma}\left(t, \frac{1}{t}, t\right)} - 4}{\mathsf{fma}\left(t, \frac{1}{t}, t\right)}\right) + 2}} \]
        5. lower-+.f64N/A

          \[\leadsto 1 - \frac{1}{\color{blue}{\left(\left(4 + \left(\mathsf{neg}\left(\frac{4}{\mathsf{fma}\left(t, \frac{1}{t}, t\right)}\right)\right)\right) + \frac{\frac{4}{\mathsf{fma}\left(t, \frac{1}{t}, t\right)} - 4}{\mathsf{fma}\left(t, \frac{1}{t}, t\right)}\right) + 2}} \]
      5. Applied rewrites100.0%

        \[\leadsto 1 - \frac{1}{\color{blue}{\left(4 - \frac{4 - \left(\frac{4}{t + 1} + -4\right)}{t + 1}\right) + 2}} \]
      6. Taylor expanded in t around inf

        \[\leadsto \color{blue}{\left(\frac{5}{6} + \frac{\frac{1}{27}}{{t}^{2}}\right) - \frac{2}{9} \cdot \frac{1}{t}} \]
      7. Applied rewrites99.0%

        \[\leadsto \color{blue}{0.8333333333333334 + \frac{\mathsf{fma}\left(t, -0.2222222222222222, 0.037037037037037035\right)}{t \cdot t}} \]

      if 4.9999999999999999e-17 < (/.f64 (/.f64 #s(literal 2 binary64) t) (+.f64 #s(literal 1 binary64) (/.f64 #s(literal 1 binary64) t)))

      1. Initial program 100.0%

        \[1 - \frac{1}{2 + \left(2 - \frac{\frac{2}{t}}{1 + \frac{1}{t}}\right) \cdot \left(2 - \frac{\frac{2}{t}}{1 + \frac{1}{t}}\right)} \]
      2. Add Preprocessing
      3. Taylor expanded in t around 0

        \[\leadsto \color{blue}{\frac{1}{2}} \]
      4. Step-by-step derivation
        1. Applied rewrites100.0%

          \[\leadsto \color{blue}{0.5} \]
      5. Recombined 2 regimes into one program.
      6. Add Preprocessing

      Alternative 4: 98.0% accurate, 1.8× speedup?

      \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;\frac{\frac{2}{t}}{1 + \frac{1}{t}} \leq 5 \cdot 10^{-17}:\\ \;\;\;\;0.8333333333333334 + \frac{-0.2222222222222222}{t}\\ \mathbf{else}:\\ \;\;\;\;0.5\\ \end{array} \end{array} \]
      (FPCore (t)
       :precision binary64
       (if (<= (/ (/ 2.0 t) (+ 1.0 (/ 1.0 t))) 5e-17)
         (+ 0.8333333333333334 (/ -0.2222222222222222 t))
         0.5))
      double code(double t) {
      	double tmp;
      	if (((2.0 / t) / (1.0 + (1.0 / t))) <= 5e-17) {
      		tmp = 0.8333333333333334 + (-0.2222222222222222 / t);
      	} else {
      		tmp = 0.5;
      	}
      	return tmp;
      }
      
      real(8) function code(t)
          real(8), intent (in) :: t
          real(8) :: tmp
          if (((2.0d0 / t) / (1.0d0 + (1.0d0 / t))) <= 5d-17) then
              tmp = 0.8333333333333334d0 + ((-0.2222222222222222d0) / t)
          else
              tmp = 0.5d0
          end if
          code = tmp
      end function
      
      public static double code(double t) {
      	double tmp;
      	if (((2.0 / t) / (1.0 + (1.0 / t))) <= 5e-17) {
      		tmp = 0.8333333333333334 + (-0.2222222222222222 / t);
      	} else {
      		tmp = 0.5;
      	}
      	return tmp;
      }
      
      def code(t):
      	tmp = 0
      	if ((2.0 / t) / (1.0 + (1.0 / t))) <= 5e-17:
      		tmp = 0.8333333333333334 + (-0.2222222222222222 / t)
      	else:
      		tmp = 0.5
      	return tmp
      
      function code(t)
      	tmp = 0.0
      	if (Float64(Float64(2.0 / t) / Float64(1.0 + Float64(1.0 / t))) <= 5e-17)
      		tmp = Float64(0.8333333333333334 + Float64(-0.2222222222222222 / t));
      	else
      		tmp = 0.5;
      	end
      	return tmp
      end
      
      function tmp_2 = code(t)
      	tmp = 0.0;
      	if (((2.0 / t) / (1.0 + (1.0 / t))) <= 5e-17)
      		tmp = 0.8333333333333334 + (-0.2222222222222222 / t);
      	else
      		tmp = 0.5;
      	end
      	tmp_2 = tmp;
      end
      
      code[t_] := If[LessEqual[N[(N[(2.0 / t), $MachinePrecision] / N[(1.0 + N[(1.0 / t), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], 5e-17], N[(0.8333333333333334 + N[(-0.2222222222222222 / t), $MachinePrecision]), $MachinePrecision], 0.5]
      
      \begin{array}{l}
      
      \\
      \begin{array}{l}
      \mathbf{if}\;\frac{\frac{2}{t}}{1 + \frac{1}{t}} \leq 5 \cdot 10^{-17}:\\
      \;\;\;\;0.8333333333333334 + \frac{-0.2222222222222222}{t}\\
      
      \mathbf{else}:\\
      \;\;\;\;0.5\\
      
      
      \end{array}
      \end{array}
      
      Derivation
      1. Split input into 2 regimes
      2. if (/.f64 (/.f64 #s(literal 2 binary64) t) (+.f64 #s(literal 1 binary64) (/.f64 #s(literal 1 binary64) t))) < 4.9999999999999999e-17

        1. Initial program 100.0%

          \[1 - \frac{1}{2 + \left(2 - \frac{\frac{2}{t}}{1 + \frac{1}{t}}\right) \cdot \left(2 - \frac{\frac{2}{t}}{1 + \frac{1}{t}}\right)} \]
        2. Add Preprocessing
        3. Taylor expanded in t around inf

          \[\leadsto \color{blue}{\frac{5}{6} - \frac{2}{9} \cdot \frac{1}{t}} \]
        4. Step-by-step derivation
          1. sub-negN/A

            \[\leadsto \color{blue}{\frac{5}{6} + \left(\mathsf{neg}\left(\frac{2}{9} \cdot \frac{1}{t}\right)\right)} \]
          2. lower-+.f64N/A

            \[\leadsto \color{blue}{\frac{5}{6} + \left(\mathsf{neg}\left(\frac{2}{9} \cdot \frac{1}{t}\right)\right)} \]
          3. associate-*r/N/A

            \[\leadsto \frac{5}{6} + \left(\mathsf{neg}\left(\color{blue}{\frac{\frac{2}{9} \cdot 1}{t}}\right)\right) \]
          4. metadata-evalN/A

            \[\leadsto \frac{5}{6} + \left(\mathsf{neg}\left(\frac{\color{blue}{\frac{2}{9}}}{t}\right)\right) \]
          5. distribute-neg-fracN/A

            \[\leadsto \frac{5}{6} + \color{blue}{\frac{\mathsf{neg}\left(\frac{2}{9}\right)}{t}} \]
          6. lower-/.f64N/A

            \[\leadsto \frac{5}{6} + \color{blue}{\frac{\mathsf{neg}\left(\frac{2}{9}\right)}{t}} \]
          7. metadata-eval98.4

            \[\leadsto 0.8333333333333334 + \frac{\color{blue}{-0.2222222222222222}}{t} \]
        5. Applied rewrites98.4%

          \[\leadsto \color{blue}{0.8333333333333334 + \frac{-0.2222222222222222}{t}} \]

        if 4.9999999999999999e-17 < (/.f64 (/.f64 #s(literal 2 binary64) t) (+.f64 #s(literal 1 binary64) (/.f64 #s(literal 1 binary64) t)))

        1. Initial program 100.0%

          \[1 - \frac{1}{2 + \left(2 - \frac{\frac{2}{t}}{1 + \frac{1}{t}}\right) \cdot \left(2 - \frac{\frac{2}{t}}{1 + \frac{1}{t}}\right)} \]
        2. Add Preprocessing
        3. Taylor expanded in t around 0

          \[\leadsto \color{blue}{\frac{1}{2}} \]
        4. Step-by-step derivation
          1. Applied rewrites100.0%

            \[\leadsto \color{blue}{0.5} \]
        5. Recombined 2 regimes into one program.
        6. Add Preprocessing

        Alternative 5: 98.4% accurate, 2.3× speedup?

        \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;\frac{\frac{2}{t}}{1 + \frac{1}{t}} \leq 1:\\ \;\;\;\;0.8333333333333334\\ \mathbf{else}:\\ \;\;\;\;0.5\\ \end{array} \end{array} \]
        (FPCore (t)
         :precision binary64
         (if (<= (/ (/ 2.0 t) (+ 1.0 (/ 1.0 t))) 1.0) 0.8333333333333334 0.5))
        double code(double t) {
        	double tmp;
        	if (((2.0 / t) / (1.0 + (1.0 / t))) <= 1.0) {
        		tmp = 0.8333333333333334;
        	} else {
        		tmp = 0.5;
        	}
        	return tmp;
        }
        
        real(8) function code(t)
            real(8), intent (in) :: t
            real(8) :: tmp
            if (((2.0d0 / t) / (1.0d0 + (1.0d0 / t))) <= 1.0d0) then
                tmp = 0.8333333333333334d0
            else
                tmp = 0.5d0
            end if
            code = tmp
        end function
        
        public static double code(double t) {
        	double tmp;
        	if (((2.0 / t) / (1.0 + (1.0 / t))) <= 1.0) {
        		tmp = 0.8333333333333334;
        	} else {
        		tmp = 0.5;
        	}
        	return tmp;
        }
        
        def code(t):
        	tmp = 0
        	if ((2.0 / t) / (1.0 + (1.0 / t))) <= 1.0:
        		tmp = 0.8333333333333334
        	else:
        		tmp = 0.5
        	return tmp
        
        function code(t)
        	tmp = 0.0
        	if (Float64(Float64(2.0 / t) / Float64(1.0 + Float64(1.0 / t))) <= 1.0)
        		tmp = 0.8333333333333334;
        	else
        		tmp = 0.5;
        	end
        	return tmp
        end
        
        function tmp_2 = code(t)
        	tmp = 0.0;
        	if (((2.0 / t) / (1.0 + (1.0 / t))) <= 1.0)
        		tmp = 0.8333333333333334;
        	else
        		tmp = 0.5;
        	end
        	tmp_2 = tmp;
        end
        
        code[t_] := If[LessEqual[N[(N[(2.0 / t), $MachinePrecision] / N[(1.0 + N[(1.0 / t), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], 1.0], 0.8333333333333334, 0.5]
        
        \begin{array}{l}
        
        \\
        \begin{array}{l}
        \mathbf{if}\;\frac{\frac{2}{t}}{1 + \frac{1}{t}} \leq 1:\\
        \;\;\;\;0.8333333333333334\\
        
        \mathbf{else}:\\
        \;\;\;\;0.5\\
        
        
        \end{array}
        \end{array}
        
        Derivation
        1. Split input into 2 regimes
        2. if (/.f64 (/.f64 #s(literal 2 binary64) t) (+.f64 #s(literal 1 binary64) (/.f64 #s(literal 1 binary64) t))) < 1

          1. Initial program 100.0%

            \[1 - \frac{1}{2 + \left(2 - \frac{\frac{2}{t}}{1 + \frac{1}{t}}\right) \cdot \left(2 - \frac{\frac{2}{t}}{1 + \frac{1}{t}}\right)} \]
          2. Add Preprocessing
          3. Taylor expanded in t around inf

            \[\leadsto \color{blue}{\frac{5}{6}} \]
          4. Step-by-step derivation
            1. Applied rewrites97.2%

              \[\leadsto \color{blue}{0.8333333333333334} \]

            if 1 < (/.f64 (/.f64 #s(literal 2 binary64) t) (+.f64 #s(literal 1 binary64) (/.f64 #s(literal 1 binary64) t)))

            1. Initial program 100.0%

              \[1 - \frac{1}{2 + \left(2 - \frac{\frac{2}{t}}{1 + \frac{1}{t}}\right) \cdot \left(2 - \frac{\frac{2}{t}}{1 + \frac{1}{t}}\right)} \]
            2. Add Preprocessing
            3. Taylor expanded in t around 0

              \[\leadsto \color{blue}{\frac{1}{2}} \]
            4. Step-by-step derivation
              1. Applied rewrites100.0%

                \[\leadsto \color{blue}{0.5} \]
            5. Recombined 2 regimes into one program.
            6. Add Preprocessing

            Alternative 6: 59.2% accurate, 101.0× speedup?

            \[\begin{array}{l} \\ 0.5 \end{array} \]
            (FPCore (t) :precision binary64 0.5)
            double code(double t) {
            	return 0.5;
            }
            
            real(8) function code(t)
                real(8), intent (in) :: t
                code = 0.5d0
            end function
            
            public static double code(double t) {
            	return 0.5;
            }
            
            def code(t):
            	return 0.5
            
            function code(t)
            	return 0.5
            end
            
            function tmp = code(t)
            	tmp = 0.5;
            end
            
            code[t_] := 0.5
            
            \begin{array}{l}
            
            \\
            0.5
            \end{array}
            
            Derivation
            1. Initial program 100.0%

              \[1 - \frac{1}{2 + \left(2 - \frac{\frac{2}{t}}{1 + \frac{1}{t}}\right) \cdot \left(2 - \frac{\frac{2}{t}}{1 + \frac{1}{t}}\right)} \]
            2. Add Preprocessing
            3. Taylor expanded in t around 0

              \[\leadsto \color{blue}{\frac{1}{2}} \]
            4. Step-by-step derivation
              1. Applied rewrites61.1%

                \[\leadsto \color{blue}{0.5} \]
              2. Add Preprocessing

              Reproduce

              ?
              herbie shell --seed 2024221 
              (FPCore (t)
                :name "Kahan p13 Example 3"
                :precision binary64
                (- 1.0 (/ 1.0 (+ 2.0 (* (- 2.0 (/ (/ 2.0 t) (+ 1.0 (/ 1.0 t)))) (- 2.0 (/ (/ 2.0 t) (+ 1.0 (/ 1.0 t)))))))))