Quotient of sum of exps

Percentage Accurate: 99.0% → 98.6%
Time: 8.6s
Alternatives: 11
Speedup: 1.0×

Specification

?
\[\begin{array}{l} \\ \frac{e^{a}}{e^{a} + e^{b}} \end{array} \]
(FPCore (a b) :precision binary64 (/ (exp a) (+ (exp a) (exp b))))
double code(double a, double b) {
	return exp(a) / (exp(a) + exp(b));
}
real(8) function code(a, b)
    real(8), intent (in) :: a
    real(8), intent (in) :: b
    code = exp(a) / (exp(a) + exp(b))
end function
public static double code(double a, double b) {
	return Math.exp(a) / (Math.exp(a) + Math.exp(b));
}
def code(a, b):
	return math.exp(a) / (math.exp(a) + math.exp(b))
function code(a, b)
	return Float64(exp(a) / Float64(exp(a) + exp(b)))
end
function tmp = code(a, b)
	tmp = exp(a) / (exp(a) + exp(b));
end
code[a_, b_] := N[(N[Exp[a], $MachinePrecision] / N[(N[Exp[a], $MachinePrecision] + N[Exp[b], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
\frac{e^{a}}{e^{a} + e^{b}}
\end{array}

Sampling outcomes in binary64 precision:

Local Percentage Accuracy vs ?

The average percentage accuracy by input value. Horizontal axis shows value of an input variable; the variable is choosen in the title. Vertical axis is accuracy; higher is better. Red represent the original program, while blue represents Herbie's suggestion. These can be toggled with buttons below the plot. The line is an average while dots represent individual samples.

Accuracy vs Speed?

Herbie found 11 alternatives:

AlternativeAccuracySpeedup
The accuracy (vertical axis) and speed (horizontal axis) of each alternatives. Up and to the right is better. The red square shows the initial program, and each blue circle shows an alternative.The line shows the best available speed-accuracy tradeoffs.

Initial Program: 99.0% accurate, 1.0× speedup?

\[\begin{array}{l} \\ \frac{e^{a}}{e^{a} + e^{b}} \end{array} \]
(FPCore (a b) :precision binary64 (/ (exp a) (+ (exp a) (exp b))))
double code(double a, double b) {
	return exp(a) / (exp(a) + exp(b));
}
real(8) function code(a, b)
    real(8), intent (in) :: a
    real(8), intent (in) :: b
    code = exp(a) / (exp(a) + exp(b))
end function
public static double code(double a, double b) {
	return Math.exp(a) / (Math.exp(a) + Math.exp(b));
}
def code(a, b):
	return math.exp(a) / (math.exp(a) + math.exp(b))
function code(a, b)
	return Float64(exp(a) / Float64(exp(a) + exp(b)))
end
function tmp = code(a, b)
	tmp = exp(a) / (exp(a) + exp(b));
end
code[a_, b_] := N[(N[Exp[a], $MachinePrecision] / N[(N[Exp[a], $MachinePrecision] + N[Exp[b], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
\frac{e^{a}}{e^{a} + e^{b}}
\end{array}

Alternative 1: 98.6% accurate, 1.0× speedup?

\[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;e^{a} \leq 0.995:\\ \;\;\;\;\frac{e^{a}}{e^{a} + 1}\\ \mathbf{else}:\\ \;\;\;\;\frac{1}{e^{b} + 1}\\ \end{array} \end{array} \]
(FPCore (a b)
 :precision binary64
 (if (<= (exp a) 0.995) (/ (exp a) (+ (exp a) 1.0)) (/ 1.0 (+ (exp b) 1.0))))
double code(double a, double b) {
	double tmp;
	if (exp(a) <= 0.995) {
		tmp = exp(a) / (exp(a) + 1.0);
	} else {
		tmp = 1.0 / (exp(b) + 1.0);
	}
	return tmp;
}
real(8) function code(a, b)
    real(8), intent (in) :: a
    real(8), intent (in) :: b
    real(8) :: tmp
    if (exp(a) <= 0.995d0) then
        tmp = exp(a) / (exp(a) + 1.0d0)
    else
        tmp = 1.0d0 / (exp(b) + 1.0d0)
    end if
    code = tmp
end function
public static double code(double a, double b) {
	double tmp;
	if (Math.exp(a) <= 0.995) {
		tmp = Math.exp(a) / (Math.exp(a) + 1.0);
	} else {
		tmp = 1.0 / (Math.exp(b) + 1.0);
	}
	return tmp;
}
def code(a, b):
	tmp = 0
	if math.exp(a) <= 0.995:
		tmp = math.exp(a) / (math.exp(a) + 1.0)
	else:
		tmp = 1.0 / (math.exp(b) + 1.0)
	return tmp
function code(a, b)
	tmp = 0.0
	if (exp(a) <= 0.995)
		tmp = Float64(exp(a) / Float64(exp(a) + 1.0));
	else
		tmp = Float64(1.0 / Float64(exp(b) + 1.0));
	end
	return tmp
end
function tmp_2 = code(a, b)
	tmp = 0.0;
	if (exp(a) <= 0.995)
		tmp = exp(a) / (exp(a) + 1.0);
	else
		tmp = 1.0 / (exp(b) + 1.0);
	end
	tmp_2 = tmp;
end
code[a_, b_] := If[LessEqual[N[Exp[a], $MachinePrecision], 0.995], N[(N[Exp[a], $MachinePrecision] / N[(N[Exp[a], $MachinePrecision] + 1.0), $MachinePrecision]), $MachinePrecision], N[(1.0 / N[(N[Exp[b], $MachinePrecision] + 1.0), $MachinePrecision]), $MachinePrecision]]
\begin{array}{l}

\\
\begin{array}{l}
\mathbf{if}\;e^{a} \leq 0.995:\\
\;\;\;\;\frac{e^{a}}{e^{a} + 1}\\

\mathbf{else}:\\
\;\;\;\;\frac{1}{e^{b} + 1}\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if (exp.f64 a) < 0.994999999999999996

    1. Initial program 100.0%

      \[\frac{e^{a}}{e^{a} + e^{b}} \]
    2. Add Preprocessing
    3. Taylor expanded in b around 0

      \[\leadsto \frac{e^{a}}{e^{a} + \color{blue}{1}} \]
    4. Step-by-step derivation
      1. Applied rewrites100.0%

        \[\leadsto \frac{e^{a}}{e^{a} + \color{blue}{1}} \]

      if 0.994999999999999996 < (exp.f64 a)

      1. Initial program 99.4%

        \[\frac{e^{a}}{e^{a} + e^{b}} \]
      2. Add Preprocessing
      3. Taylor expanded in a around 0

        \[\leadsto \color{blue}{\frac{1}{1 + e^{b}}} \]
      4. Step-by-step derivation
        1. lower-/.f64N/A

          \[\leadsto \color{blue}{\frac{1}{1 + e^{b}}} \]
        2. lower-+.f64N/A

          \[\leadsto \frac{1}{\color{blue}{1 + e^{b}}} \]
        3. lower-exp.f6499.8

          \[\leadsto \frac{1}{1 + \color{blue}{e^{b}}} \]
      5. Applied rewrites99.8%

        \[\leadsto \color{blue}{\frac{1}{1 + e^{b}}} \]
    5. Recombined 2 regimes into one program.
    6. Final simplification99.8%

      \[\leadsto \begin{array}{l} \mathbf{if}\;e^{a} \leq 0.995:\\ \;\;\;\;\frac{e^{a}}{e^{a} + 1}\\ \mathbf{else}:\\ \;\;\;\;\frac{1}{e^{b} + 1}\\ \end{array} \]
    7. Add Preprocessing

    Alternative 2: 99.0% accurate, 1.0× speedup?

    \[\begin{array}{l} \\ \frac{e^{a}}{e^{a} + e^{b}} \end{array} \]
    (FPCore (a b) :precision binary64 (/ (exp a) (+ (exp a) (exp b))))
    double code(double a, double b) {
    	return exp(a) / (exp(a) + exp(b));
    }
    
    real(8) function code(a, b)
        real(8), intent (in) :: a
        real(8), intent (in) :: b
        code = exp(a) / (exp(a) + exp(b))
    end function
    
    public static double code(double a, double b) {
    	return Math.exp(a) / (Math.exp(a) + Math.exp(b));
    }
    
    def code(a, b):
    	return math.exp(a) / (math.exp(a) + math.exp(b))
    
    function code(a, b)
    	return Float64(exp(a) / Float64(exp(a) + exp(b)))
    end
    
    function tmp = code(a, b)
    	tmp = exp(a) / (exp(a) + exp(b));
    end
    
    code[a_, b_] := N[(N[Exp[a], $MachinePrecision] / N[(N[Exp[a], $MachinePrecision] + N[Exp[b], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
    
    \begin{array}{l}
    
    \\
    \frac{e^{a}}{e^{a} + e^{b}}
    \end{array}
    
    Derivation
    1. Initial program 99.6%

      \[\frac{e^{a}}{e^{a} + e^{b}} \]
    2. Add Preprocessing
    3. Add Preprocessing

    Alternative 3: 98.6% accurate, 1.4× speedup?

    \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;e^{a} \leq 0.995:\\ \;\;\;\;\frac{1}{1 + e^{-a}}\\ \mathbf{else}:\\ \;\;\;\;\frac{1}{e^{b} + 1}\\ \end{array} \end{array} \]
    (FPCore (a b)
     :precision binary64
     (if (<= (exp a) 0.995) (/ 1.0 (+ 1.0 (exp (- a)))) (/ 1.0 (+ (exp b) 1.0))))
    double code(double a, double b) {
    	double tmp;
    	if (exp(a) <= 0.995) {
    		tmp = 1.0 / (1.0 + exp(-a));
    	} else {
    		tmp = 1.0 / (exp(b) + 1.0);
    	}
    	return tmp;
    }
    
    real(8) function code(a, b)
        real(8), intent (in) :: a
        real(8), intent (in) :: b
        real(8) :: tmp
        if (exp(a) <= 0.995d0) then
            tmp = 1.0d0 / (1.0d0 + exp(-a))
        else
            tmp = 1.0d0 / (exp(b) + 1.0d0)
        end if
        code = tmp
    end function
    
    public static double code(double a, double b) {
    	double tmp;
    	if (Math.exp(a) <= 0.995) {
    		tmp = 1.0 / (1.0 + Math.exp(-a));
    	} else {
    		tmp = 1.0 / (Math.exp(b) + 1.0);
    	}
    	return tmp;
    }
    
    def code(a, b):
    	tmp = 0
    	if math.exp(a) <= 0.995:
    		tmp = 1.0 / (1.0 + math.exp(-a))
    	else:
    		tmp = 1.0 / (math.exp(b) + 1.0)
    	return tmp
    
    function code(a, b)
    	tmp = 0.0
    	if (exp(a) <= 0.995)
    		tmp = Float64(1.0 / Float64(1.0 + exp(Float64(-a))));
    	else
    		tmp = Float64(1.0 / Float64(exp(b) + 1.0));
    	end
    	return tmp
    end
    
    function tmp_2 = code(a, b)
    	tmp = 0.0;
    	if (exp(a) <= 0.995)
    		tmp = 1.0 / (1.0 + exp(-a));
    	else
    		tmp = 1.0 / (exp(b) + 1.0);
    	end
    	tmp_2 = tmp;
    end
    
    code[a_, b_] := If[LessEqual[N[Exp[a], $MachinePrecision], 0.995], N[(1.0 / N[(1.0 + N[Exp[(-a)], $MachinePrecision]), $MachinePrecision]), $MachinePrecision], N[(1.0 / N[(N[Exp[b], $MachinePrecision] + 1.0), $MachinePrecision]), $MachinePrecision]]
    
    \begin{array}{l}
    
    \\
    \begin{array}{l}
    \mathbf{if}\;e^{a} \leq 0.995:\\
    \;\;\;\;\frac{1}{1 + e^{-a}}\\
    
    \mathbf{else}:\\
    \;\;\;\;\frac{1}{e^{b} + 1}\\
    
    
    \end{array}
    \end{array}
    
    Derivation
    1. Split input into 2 regimes
    2. if (exp.f64 a) < 0.994999999999999996

      1. Initial program 100.0%

        \[\frac{e^{a}}{e^{a} + e^{b}} \]
      2. Add Preprocessing
      3. Taylor expanded in b around 0

        \[\leadsto \frac{e^{a}}{e^{a} + \color{blue}{1}} \]
      4. Step-by-step derivation
        1. Applied rewrites100.0%

          \[\leadsto \frac{e^{a}}{e^{a} + \color{blue}{1}} \]
        2. Taylor expanded in a around 0

          \[\leadsto \frac{e^{a}}{\color{blue}{1} + 1} \]
        3. Step-by-step derivation
          1. Applied rewrites98.1%

            \[\leadsto \frac{e^{a}}{\color{blue}{1} + 1} \]
          2. Step-by-step derivation
            1. lift-/.f64N/A

              \[\leadsto \color{blue}{\frac{e^{a}}{1 + 1}} \]
            2. lift-exp.f64N/A

              \[\leadsto \frac{\color{blue}{e^{a}}}{1 + 1} \]
            3. clear-numN/A

              \[\leadsto \color{blue}{\frac{1}{\frac{1 + 1}{e^{a}}}} \]
            4. lower-/.f64N/A

              \[\leadsto \color{blue}{\frac{1}{\frac{1 + 1}{e^{a}}}} \]
            5. div-invN/A

              \[\leadsto \frac{1}{\color{blue}{\left(1 + 1\right) \cdot \frac{1}{e^{a}}}} \]
            6. lower-*.f64N/A

              \[\leadsto \frac{1}{\color{blue}{\left(1 + 1\right) \cdot \frac{1}{e^{a}}}} \]
            7. rec-expN/A

              \[\leadsto \frac{1}{\left(1 + 1\right) \cdot \color{blue}{e^{\mathsf{neg}\left(a\right)}}} \]
            8. lower-exp.f64N/A

              \[\leadsto \frac{1}{\left(1 + 1\right) \cdot \color{blue}{e^{\mathsf{neg}\left(a\right)}}} \]
            9. lower-neg.f6498.1

              \[\leadsto \frac{1}{\left(1 + 1\right) \cdot e^{\color{blue}{-a}}} \]
          3. Applied rewrites98.1%

            \[\leadsto \color{blue}{\frac{1}{\left(1 + 1\right) \cdot e^{-a}}} \]
          4. Taylor expanded in b around 0

            \[\leadsto \frac{1}{\color{blue}{e^{\mathsf{neg}\left(a\right)} \cdot \left(1 + e^{a}\right)}} \]
          5. Step-by-step derivation
            1. +-commutativeN/A

              \[\leadsto \frac{1}{e^{\mathsf{neg}\left(a\right)} \cdot \color{blue}{\left(e^{a} + 1\right)}} \]
            2. distribute-lft-inN/A

              \[\leadsto \frac{1}{\color{blue}{e^{\mathsf{neg}\left(a\right)} \cdot e^{a} + e^{\mathsf{neg}\left(a\right)} \cdot 1}} \]
            3. exp-negN/A

              \[\leadsto \frac{1}{\color{blue}{\frac{1}{e^{a}}} \cdot e^{a} + e^{\mathsf{neg}\left(a\right)} \cdot 1} \]
            4. lft-mult-inverseN/A

              \[\leadsto \frac{1}{\color{blue}{1} + e^{\mathsf{neg}\left(a\right)} \cdot 1} \]
            5. *-rgt-identityN/A

              \[\leadsto \frac{1}{1 + \color{blue}{e^{\mathsf{neg}\left(a\right)}}} \]
            6. lower-+.f64N/A

              \[\leadsto \frac{1}{\color{blue}{1 + e^{\mathsf{neg}\left(a\right)}}} \]
            7. lower-exp.f64N/A

              \[\leadsto \frac{1}{1 + \color{blue}{e^{\mathsf{neg}\left(a\right)}}} \]
            8. lower-neg.f64100.0

              \[\leadsto \frac{1}{1 + e^{\color{blue}{-a}}} \]
          6. Applied rewrites100.0%

            \[\leadsto \frac{1}{\color{blue}{1 + e^{-a}}} \]

          if 0.994999999999999996 < (exp.f64 a)

          1. Initial program 99.4%

            \[\frac{e^{a}}{e^{a} + e^{b}} \]
          2. Add Preprocessing
          3. Taylor expanded in a around 0

            \[\leadsto \color{blue}{\frac{1}{1 + e^{b}}} \]
          4. Step-by-step derivation
            1. lower-/.f64N/A

              \[\leadsto \color{blue}{\frac{1}{1 + e^{b}}} \]
            2. lower-+.f64N/A

              \[\leadsto \frac{1}{\color{blue}{1 + e^{b}}} \]
            3. lower-exp.f6499.8

              \[\leadsto \frac{1}{1 + \color{blue}{e^{b}}} \]
          5. Applied rewrites99.8%

            \[\leadsto \color{blue}{\frac{1}{1 + e^{b}}} \]
        4. Recombined 2 regimes into one program.
        5. Final simplification99.8%

          \[\leadsto \begin{array}{l} \mathbf{if}\;e^{a} \leq 0.995:\\ \;\;\;\;\frac{1}{1 + e^{-a}}\\ \mathbf{else}:\\ \;\;\;\;\frac{1}{e^{b} + 1}\\ \end{array} \]
        6. Add Preprocessing

        Alternative 4: 98.4% accurate, 1.4× speedup?

        \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;e^{a} \leq 0.995:\\ \;\;\;\;\frac{e^{a}}{1 + 1}\\ \mathbf{else}:\\ \;\;\;\;\frac{1}{e^{b} + 1}\\ \end{array} \end{array} \]
        (FPCore (a b)
         :precision binary64
         (if (<= (exp a) 0.995) (/ (exp a) (+ 1.0 1.0)) (/ 1.0 (+ (exp b) 1.0))))
        double code(double a, double b) {
        	double tmp;
        	if (exp(a) <= 0.995) {
        		tmp = exp(a) / (1.0 + 1.0);
        	} else {
        		tmp = 1.0 / (exp(b) + 1.0);
        	}
        	return tmp;
        }
        
        real(8) function code(a, b)
            real(8), intent (in) :: a
            real(8), intent (in) :: b
            real(8) :: tmp
            if (exp(a) <= 0.995d0) then
                tmp = exp(a) / (1.0d0 + 1.0d0)
            else
                tmp = 1.0d0 / (exp(b) + 1.0d0)
            end if
            code = tmp
        end function
        
        public static double code(double a, double b) {
        	double tmp;
        	if (Math.exp(a) <= 0.995) {
        		tmp = Math.exp(a) / (1.0 + 1.0);
        	} else {
        		tmp = 1.0 / (Math.exp(b) + 1.0);
        	}
        	return tmp;
        }
        
        def code(a, b):
        	tmp = 0
        	if math.exp(a) <= 0.995:
        		tmp = math.exp(a) / (1.0 + 1.0)
        	else:
        		tmp = 1.0 / (math.exp(b) + 1.0)
        	return tmp
        
        function code(a, b)
        	tmp = 0.0
        	if (exp(a) <= 0.995)
        		tmp = Float64(exp(a) / Float64(1.0 + 1.0));
        	else
        		tmp = Float64(1.0 / Float64(exp(b) + 1.0));
        	end
        	return tmp
        end
        
        function tmp_2 = code(a, b)
        	tmp = 0.0;
        	if (exp(a) <= 0.995)
        		tmp = exp(a) / (1.0 + 1.0);
        	else
        		tmp = 1.0 / (exp(b) + 1.0);
        	end
        	tmp_2 = tmp;
        end
        
        code[a_, b_] := If[LessEqual[N[Exp[a], $MachinePrecision], 0.995], N[(N[Exp[a], $MachinePrecision] / N[(1.0 + 1.0), $MachinePrecision]), $MachinePrecision], N[(1.0 / N[(N[Exp[b], $MachinePrecision] + 1.0), $MachinePrecision]), $MachinePrecision]]
        
        \begin{array}{l}
        
        \\
        \begin{array}{l}
        \mathbf{if}\;e^{a} \leq 0.995:\\
        \;\;\;\;\frac{e^{a}}{1 + 1}\\
        
        \mathbf{else}:\\
        \;\;\;\;\frac{1}{e^{b} + 1}\\
        
        
        \end{array}
        \end{array}
        
        Derivation
        1. Split input into 2 regimes
        2. if (exp.f64 a) < 0.994999999999999996

          1. Initial program 100.0%

            \[\frac{e^{a}}{e^{a} + e^{b}} \]
          2. Add Preprocessing
          3. Taylor expanded in b around 0

            \[\leadsto \frac{e^{a}}{e^{a} + \color{blue}{1}} \]
          4. Step-by-step derivation
            1. Applied rewrites100.0%

              \[\leadsto \frac{e^{a}}{e^{a} + \color{blue}{1}} \]
            2. Taylor expanded in a around 0

              \[\leadsto \frac{e^{a}}{\color{blue}{1} + 1} \]
            3. Step-by-step derivation
              1. Applied rewrites98.1%

                \[\leadsto \frac{e^{a}}{\color{blue}{1} + 1} \]

              if 0.994999999999999996 < (exp.f64 a)

              1. Initial program 99.4%

                \[\frac{e^{a}}{e^{a} + e^{b}} \]
              2. Add Preprocessing
              3. Taylor expanded in a around 0

                \[\leadsto \color{blue}{\frac{1}{1 + e^{b}}} \]
              4. Step-by-step derivation
                1. lower-/.f64N/A

                  \[\leadsto \color{blue}{\frac{1}{1 + e^{b}}} \]
                2. lower-+.f64N/A

                  \[\leadsto \frac{1}{\color{blue}{1 + e^{b}}} \]
                3. lower-exp.f6499.8

                  \[\leadsto \frac{1}{1 + \color{blue}{e^{b}}} \]
              5. Applied rewrites99.8%

                \[\leadsto \color{blue}{\frac{1}{1 + e^{b}}} \]
            4. Recombined 2 regimes into one program.
            5. Final simplification99.2%

              \[\leadsto \begin{array}{l} \mathbf{if}\;e^{a} \leq 0.995:\\ \;\;\;\;\frac{e^{a}}{1 + 1}\\ \mathbf{else}:\\ \;\;\;\;\frac{1}{e^{b} + 1}\\ \end{array} \]
            6. Add Preprocessing

            Alternative 5: 83.7% accurate, 1.4× speedup?

            \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;e^{a} \leq 0:\\ \;\;\;\;b \cdot \left(0.020833333333333332 \cdot \left(b \cdot b\right)\right)\\ \mathbf{else}:\\ \;\;\;\;\frac{1}{e^{b} + 1}\\ \end{array} \end{array} \]
            (FPCore (a b)
             :precision binary64
             (if (<= (exp a) 0.0)
               (* b (* 0.020833333333333332 (* b b)))
               (/ 1.0 (+ (exp b) 1.0))))
            double code(double a, double b) {
            	double tmp;
            	if (exp(a) <= 0.0) {
            		tmp = b * (0.020833333333333332 * (b * b));
            	} else {
            		tmp = 1.0 / (exp(b) + 1.0);
            	}
            	return tmp;
            }
            
            real(8) function code(a, b)
                real(8), intent (in) :: a
                real(8), intent (in) :: b
                real(8) :: tmp
                if (exp(a) <= 0.0d0) then
                    tmp = b * (0.020833333333333332d0 * (b * b))
                else
                    tmp = 1.0d0 / (exp(b) + 1.0d0)
                end if
                code = tmp
            end function
            
            public static double code(double a, double b) {
            	double tmp;
            	if (Math.exp(a) <= 0.0) {
            		tmp = b * (0.020833333333333332 * (b * b));
            	} else {
            		tmp = 1.0 / (Math.exp(b) + 1.0);
            	}
            	return tmp;
            }
            
            def code(a, b):
            	tmp = 0
            	if math.exp(a) <= 0.0:
            		tmp = b * (0.020833333333333332 * (b * b))
            	else:
            		tmp = 1.0 / (math.exp(b) + 1.0)
            	return tmp
            
            function code(a, b)
            	tmp = 0.0
            	if (exp(a) <= 0.0)
            		tmp = Float64(b * Float64(0.020833333333333332 * Float64(b * b)));
            	else
            		tmp = Float64(1.0 / Float64(exp(b) + 1.0));
            	end
            	return tmp
            end
            
            function tmp_2 = code(a, b)
            	tmp = 0.0;
            	if (exp(a) <= 0.0)
            		tmp = b * (0.020833333333333332 * (b * b));
            	else
            		tmp = 1.0 / (exp(b) + 1.0);
            	end
            	tmp_2 = tmp;
            end
            
            code[a_, b_] := If[LessEqual[N[Exp[a], $MachinePrecision], 0.0], N[(b * N[(0.020833333333333332 * N[(b * b), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], N[(1.0 / N[(N[Exp[b], $MachinePrecision] + 1.0), $MachinePrecision]), $MachinePrecision]]
            
            \begin{array}{l}
            
            \\
            \begin{array}{l}
            \mathbf{if}\;e^{a} \leq 0:\\
            \;\;\;\;b \cdot \left(0.020833333333333332 \cdot \left(b \cdot b\right)\right)\\
            
            \mathbf{else}:\\
            \;\;\;\;\frac{1}{e^{b} + 1}\\
            
            
            \end{array}
            \end{array}
            
            Derivation
            1. Split input into 2 regimes
            2. if (exp.f64 a) < 0.0

              1. Initial program 100.0%

                \[\frac{e^{a}}{e^{a} + e^{b}} \]
              2. Add Preprocessing
              3. Taylor expanded in a around 0

                \[\leadsto \color{blue}{\frac{1}{1 + e^{b}}} \]
              4. Step-by-step derivation
                1. lower-/.f64N/A

                  \[\leadsto \color{blue}{\frac{1}{1 + e^{b}}} \]
                2. lower-+.f64N/A

                  \[\leadsto \frac{1}{\color{blue}{1 + e^{b}}} \]
                3. lower-exp.f6433.7

                  \[\leadsto \frac{1}{1 + \color{blue}{e^{b}}} \]
              5. Applied rewrites33.7%

                \[\leadsto \color{blue}{\frac{1}{1 + e^{b}}} \]
              6. Taylor expanded in b around 0

                \[\leadsto \frac{1}{2} + \color{blue}{b \cdot \left(\frac{1}{48} \cdot {b}^{2} - \frac{1}{4}\right)} \]
              7. Step-by-step derivation
                1. Applied rewrites2.7%

                  \[\leadsto \mathsf{fma}\left(b, \color{blue}{\mathsf{fma}\left(b, b \cdot 0.020833333333333332, -0.25\right)}, 0.5\right) \]
                2. Taylor expanded in b around inf

                  \[\leadsto \frac{1}{48} \cdot {b}^{\color{blue}{3}} \]
                3. Step-by-step derivation
                  1. Applied rewrites50.4%

                    \[\leadsto b \cdot \left(0.020833333333333332 \cdot \color{blue}{\left(b \cdot b\right)}\right) \]

                  if 0.0 < (exp.f64 a)

                  1. Initial program 99.4%

                    \[\frac{e^{a}}{e^{a} + e^{b}} \]
                  2. Add Preprocessing
                  3. Taylor expanded in a around 0

                    \[\leadsto \color{blue}{\frac{1}{1 + e^{b}}} \]
                  4. Step-by-step derivation
                    1. lower-/.f64N/A

                      \[\leadsto \color{blue}{\frac{1}{1 + e^{b}}} \]
                    2. lower-+.f64N/A

                      \[\leadsto \frac{1}{\color{blue}{1 + e^{b}}} \]
                    3. lower-exp.f6498.9

                      \[\leadsto \frac{1}{1 + \color{blue}{e^{b}}} \]
                  5. Applied rewrites98.9%

                    \[\leadsto \color{blue}{\frac{1}{1 + e^{b}}} \]
                4. Recombined 2 regimes into one program.
                5. Final simplification84.5%

                  \[\leadsto \begin{array}{l} \mathbf{if}\;e^{a} \leq 0:\\ \;\;\;\;b \cdot \left(0.020833333333333332 \cdot \left(b \cdot b\right)\right)\\ \mathbf{else}:\\ \;\;\;\;\frac{1}{e^{b} + 1}\\ \end{array} \]
                6. Add Preprocessing

                Alternative 6: 59.4% accurate, 2.3× speedup?

                \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;e^{a} \leq 0:\\ \;\;\;\;b \cdot \left(0.020833333333333332 \cdot \left(b \cdot b\right)\right)\\ \mathbf{else}:\\ \;\;\;\;\frac{1}{\mathsf{fma}\left(b, \mathsf{fma}\left(b, \mathsf{fma}\left(b, 0.16666666666666666, 0.5\right), 1\right), 2\right)}\\ \end{array} \end{array} \]
                (FPCore (a b)
                 :precision binary64
                 (if (<= (exp a) 0.0)
                   (* b (* 0.020833333333333332 (* b b)))
                   (/ 1.0 (fma b (fma b (fma b 0.16666666666666666 0.5) 1.0) 2.0))))
                double code(double a, double b) {
                	double tmp;
                	if (exp(a) <= 0.0) {
                		tmp = b * (0.020833333333333332 * (b * b));
                	} else {
                		tmp = 1.0 / fma(b, fma(b, fma(b, 0.16666666666666666, 0.5), 1.0), 2.0);
                	}
                	return tmp;
                }
                
                function code(a, b)
                	tmp = 0.0
                	if (exp(a) <= 0.0)
                		tmp = Float64(b * Float64(0.020833333333333332 * Float64(b * b)));
                	else
                		tmp = Float64(1.0 / fma(b, fma(b, fma(b, 0.16666666666666666, 0.5), 1.0), 2.0));
                	end
                	return tmp
                end
                
                code[a_, b_] := If[LessEqual[N[Exp[a], $MachinePrecision], 0.0], N[(b * N[(0.020833333333333332 * N[(b * b), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], N[(1.0 / N[(b * N[(b * N[(b * 0.16666666666666666 + 0.5), $MachinePrecision] + 1.0), $MachinePrecision] + 2.0), $MachinePrecision]), $MachinePrecision]]
                
                \begin{array}{l}
                
                \\
                \begin{array}{l}
                \mathbf{if}\;e^{a} \leq 0:\\
                \;\;\;\;b \cdot \left(0.020833333333333332 \cdot \left(b \cdot b\right)\right)\\
                
                \mathbf{else}:\\
                \;\;\;\;\frac{1}{\mathsf{fma}\left(b, \mathsf{fma}\left(b, \mathsf{fma}\left(b, 0.16666666666666666, 0.5\right), 1\right), 2\right)}\\
                
                
                \end{array}
                \end{array}
                
                Derivation
                1. Split input into 2 regimes
                2. if (exp.f64 a) < 0.0

                  1. Initial program 100.0%

                    \[\frac{e^{a}}{e^{a} + e^{b}} \]
                  2. Add Preprocessing
                  3. Taylor expanded in a around 0

                    \[\leadsto \color{blue}{\frac{1}{1 + e^{b}}} \]
                  4. Step-by-step derivation
                    1. lower-/.f64N/A

                      \[\leadsto \color{blue}{\frac{1}{1 + e^{b}}} \]
                    2. lower-+.f64N/A

                      \[\leadsto \frac{1}{\color{blue}{1 + e^{b}}} \]
                    3. lower-exp.f6433.7

                      \[\leadsto \frac{1}{1 + \color{blue}{e^{b}}} \]
                  5. Applied rewrites33.7%

                    \[\leadsto \color{blue}{\frac{1}{1 + e^{b}}} \]
                  6. Taylor expanded in b around 0

                    \[\leadsto \frac{1}{2} + \color{blue}{b \cdot \left(\frac{1}{48} \cdot {b}^{2} - \frac{1}{4}\right)} \]
                  7. Step-by-step derivation
                    1. Applied rewrites2.7%

                      \[\leadsto \mathsf{fma}\left(b, \color{blue}{\mathsf{fma}\left(b, b \cdot 0.020833333333333332, -0.25\right)}, 0.5\right) \]
                    2. Taylor expanded in b around inf

                      \[\leadsto \frac{1}{48} \cdot {b}^{\color{blue}{3}} \]
                    3. Step-by-step derivation
                      1. Applied rewrites50.4%

                        \[\leadsto b \cdot \left(0.020833333333333332 \cdot \color{blue}{\left(b \cdot b\right)}\right) \]

                      if 0.0 < (exp.f64 a)

                      1. Initial program 99.4%

                        \[\frac{e^{a}}{e^{a} + e^{b}} \]
                      2. Add Preprocessing
                      3. Taylor expanded in a around 0

                        \[\leadsto \color{blue}{\frac{1}{1 + e^{b}}} \]
                      4. Step-by-step derivation
                        1. lower-/.f64N/A

                          \[\leadsto \color{blue}{\frac{1}{1 + e^{b}}} \]
                        2. lower-+.f64N/A

                          \[\leadsto \frac{1}{\color{blue}{1 + e^{b}}} \]
                        3. lower-exp.f6498.9

                          \[\leadsto \frac{1}{1 + \color{blue}{e^{b}}} \]
                      5. Applied rewrites98.9%

                        \[\leadsto \color{blue}{\frac{1}{1 + e^{b}}} \]
                      6. Taylor expanded in b around 0

                        \[\leadsto \frac{1}{2 + \color{blue}{b \cdot \left(1 + b \cdot \left(\frac{1}{2} + \frac{1}{6} \cdot b\right)\right)}} \]
                      7. Step-by-step derivation
                        1. Applied rewrites66.8%

                          \[\leadsto \frac{1}{\mathsf{fma}\left(b, \color{blue}{\mathsf{fma}\left(b, \mathsf{fma}\left(b, 0.16666666666666666, 0.5\right), 1\right)}, 2\right)} \]
                      8. Recombined 2 regimes into one program.
                      9. Add Preprocessing

                      Alternative 7: 59.2% accurate, 2.3× speedup?

                      \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;e^{a} \leq 0:\\ \;\;\;\;b \cdot \left(0.020833333333333332 \cdot \left(b \cdot b\right)\right)\\ \mathbf{else}:\\ \;\;\;\;\frac{1}{\mathsf{fma}\left(b, \mathsf{fma}\left(b, b \cdot 0.16666666666666666, 1\right), 2\right)}\\ \end{array} \end{array} \]
                      (FPCore (a b)
                       :precision binary64
                       (if (<= (exp a) 0.0)
                         (* b (* 0.020833333333333332 (* b b)))
                         (/ 1.0 (fma b (fma b (* b 0.16666666666666666) 1.0) 2.0))))
                      double code(double a, double b) {
                      	double tmp;
                      	if (exp(a) <= 0.0) {
                      		tmp = b * (0.020833333333333332 * (b * b));
                      	} else {
                      		tmp = 1.0 / fma(b, fma(b, (b * 0.16666666666666666), 1.0), 2.0);
                      	}
                      	return tmp;
                      }
                      
                      function code(a, b)
                      	tmp = 0.0
                      	if (exp(a) <= 0.0)
                      		tmp = Float64(b * Float64(0.020833333333333332 * Float64(b * b)));
                      	else
                      		tmp = Float64(1.0 / fma(b, fma(b, Float64(b * 0.16666666666666666), 1.0), 2.0));
                      	end
                      	return tmp
                      end
                      
                      code[a_, b_] := If[LessEqual[N[Exp[a], $MachinePrecision], 0.0], N[(b * N[(0.020833333333333332 * N[(b * b), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], N[(1.0 / N[(b * N[(b * N[(b * 0.16666666666666666), $MachinePrecision] + 1.0), $MachinePrecision] + 2.0), $MachinePrecision]), $MachinePrecision]]
                      
                      \begin{array}{l}
                      
                      \\
                      \begin{array}{l}
                      \mathbf{if}\;e^{a} \leq 0:\\
                      \;\;\;\;b \cdot \left(0.020833333333333332 \cdot \left(b \cdot b\right)\right)\\
                      
                      \mathbf{else}:\\
                      \;\;\;\;\frac{1}{\mathsf{fma}\left(b, \mathsf{fma}\left(b, b \cdot 0.16666666666666666, 1\right), 2\right)}\\
                      
                      
                      \end{array}
                      \end{array}
                      
                      Derivation
                      1. Split input into 2 regimes
                      2. if (exp.f64 a) < 0.0

                        1. Initial program 100.0%

                          \[\frac{e^{a}}{e^{a} + e^{b}} \]
                        2. Add Preprocessing
                        3. Taylor expanded in a around 0

                          \[\leadsto \color{blue}{\frac{1}{1 + e^{b}}} \]
                        4. Step-by-step derivation
                          1. lower-/.f64N/A

                            \[\leadsto \color{blue}{\frac{1}{1 + e^{b}}} \]
                          2. lower-+.f64N/A

                            \[\leadsto \frac{1}{\color{blue}{1 + e^{b}}} \]
                          3. lower-exp.f6433.7

                            \[\leadsto \frac{1}{1 + \color{blue}{e^{b}}} \]
                        5. Applied rewrites33.7%

                          \[\leadsto \color{blue}{\frac{1}{1 + e^{b}}} \]
                        6. Taylor expanded in b around 0

                          \[\leadsto \frac{1}{2} + \color{blue}{b \cdot \left(\frac{1}{48} \cdot {b}^{2} - \frac{1}{4}\right)} \]
                        7. Step-by-step derivation
                          1. Applied rewrites2.7%

                            \[\leadsto \mathsf{fma}\left(b, \color{blue}{\mathsf{fma}\left(b, b \cdot 0.020833333333333332, -0.25\right)}, 0.5\right) \]
                          2. Taylor expanded in b around inf

                            \[\leadsto \frac{1}{48} \cdot {b}^{\color{blue}{3}} \]
                          3. Step-by-step derivation
                            1. Applied rewrites50.4%

                              \[\leadsto b \cdot \left(0.020833333333333332 \cdot \color{blue}{\left(b \cdot b\right)}\right) \]

                            if 0.0 < (exp.f64 a)

                            1. Initial program 99.4%

                              \[\frac{e^{a}}{e^{a} + e^{b}} \]
                            2. Add Preprocessing
                            3. Taylor expanded in a around 0

                              \[\leadsto \color{blue}{\frac{1}{1 + e^{b}}} \]
                            4. Step-by-step derivation
                              1. lower-/.f64N/A

                                \[\leadsto \color{blue}{\frac{1}{1 + e^{b}}} \]
                              2. lower-+.f64N/A

                                \[\leadsto \frac{1}{\color{blue}{1 + e^{b}}} \]
                              3. lower-exp.f6498.9

                                \[\leadsto \frac{1}{1 + \color{blue}{e^{b}}} \]
                            5. Applied rewrites98.9%

                              \[\leadsto \color{blue}{\frac{1}{1 + e^{b}}} \]
                            6. Taylor expanded in b around 0

                              \[\leadsto \frac{1}{2 + \color{blue}{b \cdot \left(1 + b \cdot \left(\frac{1}{2} + \frac{1}{6} \cdot b\right)\right)}} \]
                            7. Step-by-step derivation
                              1. Applied rewrites66.8%

                                \[\leadsto \frac{1}{\mathsf{fma}\left(b, \color{blue}{\mathsf{fma}\left(b, \mathsf{fma}\left(b, 0.16666666666666666, 0.5\right), 1\right)}, 2\right)} \]
                              2. Taylor expanded in b around inf

                                \[\leadsto \frac{1}{\mathsf{fma}\left(b, \mathsf{fma}\left(b, \frac{1}{6} \cdot b, 1\right), 2\right)} \]
                              3. Step-by-step derivation
                                1. Applied rewrites66.5%

                                  \[\leadsto \frac{1}{\mathsf{fma}\left(b, \mathsf{fma}\left(b, b \cdot 0.16666666666666666, 1\right), 2\right)} \]
                              4. Recombined 2 regimes into one program.
                              5. Add Preprocessing

                              Alternative 8: 56.8% accurate, 2.4× speedup?

                              \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;e^{a} \leq 0:\\ \;\;\;\;b \cdot \left(0.020833333333333332 \cdot \left(b \cdot b\right)\right)\\ \mathbf{else}:\\ \;\;\;\;\frac{1}{\mathsf{fma}\left(b, \mathsf{fma}\left(b, 0.5, 1\right), 2\right)}\\ \end{array} \end{array} \]
                              (FPCore (a b)
                               :precision binary64
                               (if (<= (exp a) 0.0)
                                 (* b (* 0.020833333333333332 (* b b)))
                                 (/ 1.0 (fma b (fma b 0.5 1.0) 2.0))))
                              double code(double a, double b) {
                              	double tmp;
                              	if (exp(a) <= 0.0) {
                              		tmp = b * (0.020833333333333332 * (b * b));
                              	} else {
                              		tmp = 1.0 / fma(b, fma(b, 0.5, 1.0), 2.0);
                              	}
                              	return tmp;
                              }
                              
                              function code(a, b)
                              	tmp = 0.0
                              	if (exp(a) <= 0.0)
                              		tmp = Float64(b * Float64(0.020833333333333332 * Float64(b * b)));
                              	else
                              		tmp = Float64(1.0 / fma(b, fma(b, 0.5, 1.0), 2.0));
                              	end
                              	return tmp
                              end
                              
                              code[a_, b_] := If[LessEqual[N[Exp[a], $MachinePrecision], 0.0], N[(b * N[(0.020833333333333332 * N[(b * b), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], N[(1.0 / N[(b * N[(b * 0.5 + 1.0), $MachinePrecision] + 2.0), $MachinePrecision]), $MachinePrecision]]
                              
                              \begin{array}{l}
                              
                              \\
                              \begin{array}{l}
                              \mathbf{if}\;e^{a} \leq 0:\\
                              \;\;\;\;b \cdot \left(0.020833333333333332 \cdot \left(b \cdot b\right)\right)\\
                              
                              \mathbf{else}:\\
                              \;\;\;\;\frac{1}{\mathsf{fma}\left(b, \mathsf{fma}\left(b, 0.5, 1\right), 2\right)}\\
                              
                              
                              \end{array}
                              \end{array}
                              
                              Derivation
                              1. Split input into 2 regimes
                              2. if (exp.f64 a) < 0.0

                                1. Initial program 100.0%

                                  \[\frac{e^{a}}{e^{a} + e^{b}} \]
                                2. Add Preprocessing
                                3. Taylor expanded in a around 0

                                  \[\leadsto \color{blue}{\frac{1}{1 + e^{b}}} \]
                                4. Step-by-step derivation
                                  1. lower-/.f64N/A

                                    \[\leadsto \color{blue}{\frac{1}{1 + e^{b}}} \]
                                  2. lower-+.f64N/A

                                    \[\leadsto \frac{1}{\color{blue}{1 + e^{b}}} \]
                                  3. lower-exp.f6433.7

                                    \[\leadsto \frac{1}{1 + \color{blue}{e^{b}}} \]
                                5. Applied rewrites33.7%

                                  \[\leadsto \color{blue}{\frac{1}{1 + e^{b}}} \]
                                6. Taylor expanded in b around 0

                                  \[\leadsto \frac{1}{2} + \color{blue}{b \cdot \left(\frac{1}{48} \cdot {b}^{2} - \frac{1}{4}\right)} \]
                                7. Step-by-step derivation
                                  1. Applied rewrites2.7%

                                    \[\leadsto \mathsf{fma}\left(b, \color{blue}{\mathsf{fma}\left(b, b \cdot 0.020833333333333332, -0.25\right)}, 0.5\right) \]
                                  2. Taylor expanded in b around inf

                                    \[\leadsto \frac{1}{48} \cdot {b}^{\color{blue}{3}} \]
                                  3. Step-by-step derivation
                                    1. Applied rewrites50.4%

                                      \[\leadsto b \cdot \left(0.020833333333333332 \cdot \color{blue}{\left(b \cdot b\right)}\right) \]

                                    if 0.0 < (exp.f64 a)

                                    1. Initial program 99.4%

                                      \[\frac{e^{a}}{e^{a} + e^{b}} \]
                                    2. Add Preprocessing
                                    3. Taylor expanded in a around 0

                                      \[\leadsto \color{blue}{\frac{1}{1 + e^{b}}} \]
                                    4. Step-by-step derivation
                                      1. lower-/.f64N/A

                                        \[\leadsto \color{blue}{\frac{1}{1 + e^{b}}} \]
                                      2. lower-+.f64N/A

                                        \[\leadsto \frac{1}{\color{blue}{1 + e^{b}}} \]
                                      3. lower-exp.f6498.9

                                        \[\leadsto \frac{1}{1 + \color{blue}{e^{b}}} \]
                                    5. Applied rewrites98.9%

                                      \[\leadsto \color{blue}{\frac{1}{1 + e^{b}}} \]
                                    6. Taylor expanded in b around 0

                                      \[\leadsto \frac{1}{2 + \color{blue}{b \cdot \left(1 + \frac{1}{2} \cdot b\right)}} \]
                                    7. Step-by-step derivation
                                      1. Applied rewrites64.3%

                                        \[\leadsto \frac{1}{\mathsf{fma}\left(b, \color{blue}{\mathsf{fma}\left(b, 0.5, 1\right)}, 2\right)} \]
                                    8. Recombined 2 regimes into one program.
                                    9. Add Preprocessing

                                    Alternative 9: 56.3% accurate, 2.4× speedup?

                                    \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;e^{a} \leq 0:\\ \;\;\;\;b \cdot \left(0.020833333333333332 \cdot \left(b \cdot b\right)\right)\\ \mathbf{else}:\\ \;\;\;\;\frac{1}{\mathsf{fma}\left(b, b \cdot 0.5, 2\right)}\\ \end{array} \end{array} \]
                                    (FPCore (a b)
                                     :precision binary64
                                     (if (<= (exp a) 0.0)
                                       (* b (* 0.020833333333333332 (* b b)))
                                       (/ 1.0 (fma b (* b 0.5) 2.0))))
                                    double code(double a, double b) {
                                    	double tmp;
                                    	if (exp(a) <= 0.0) {
                                    		tmp = b * (0.020833333333333332 * (b * b));
                                    	} else {
                                    		tmp = 1.0 / fma(b, (b * 0.5), 2.0);
                                    	}
                                    	return tmp;
                                    }
                                    
                                    function code(a, b)
                                    	tmp = 0.0
                                    	if (exp(a) <= 0.0)
                                    		tmp = Float64(b * Float64(0.020833333333333332 * Float64(b * b)));
                                    	else
                                    		tmp = Float64(1.0 / fma(b, Float64(b * 0.5), 2.0));
                                    	end
                                    	return tmp
                                    end
                                    
                                    code[a_, b_] := If[LessEqual[N[Exp[a], $MachinePrecision], 0.0], N[(b * N[(0.020833333333333332 * N[(b * b), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], N[(1.0 / N[(b * N[(b * 0.5), $MachinePrecision] + 2.0), $MachinePrecision]), $MachinePrecision]]
                                    
                                    \begin{array}{l}
                                    
                                    \\
                                    \begin{array}{l}
                                    \mathbf{if}\;e^{a} \leq 0:\\
                                    \;\;\;\;b \cdot \left(0.020833333333333332 \cdot \left(b \cdot b\right)\right)\\
                                    
                                    \mathbf{else}:\\
                                    \;\;\;\;\frac{1}{\mathsf{fma}\left(b, b \cdot 0.5, 2\right)}\\
                                    
                                    
                                    \end{array}
                                    \end{array}
                                    
                                    Derivation
                                    1. Split input into 2 regimes
                                    2. if (exp.f64 a) < 0.0

                                      1. Initial program 100.0%

                                        \[\frac{e^{a}}{e^{a} + e^{b}} \]
                                      2. Add Preprocessing
                                      3. Taylor expanded in a around 0

                                        \[\leadsto \color{blue}{\frac{1}{1 + e^{b}}} \]
                                      4. Step-by-step derivation
                                        1. lower-/.f64N/A

                                          \[\leadsto \color{blue}{\frac{1}{1 + e^{b}}} \]
                                        2. lower-+.f64N/A

                                          \[\leadsto \frac{1}{\color{blue}{1 + e^{b}}} \]
                                        3. lower-exp.f6433.7

                                          \[\leadsto \frac{1}{1 + \color{blue}{e^{b}}} \]
                                      5. Applied rewrites33.7%

                                        \[\leadsto \color{blue}{\frac{1}{1 + e^{b}}} \]
                                      6. Taylor expanded in b around 0

                                        \[\leadsto \frac{1}{2} + \color{blue}{b \cdot \left(\frac{1}{48} \cdot {b}^{2} - \frac{1}{4}\right)} \]
                                      7. Step-by-step derivation
                                        1. Applied rewrites2.7%

                                          \[\leadsto \mathsf{fma}\left(b, \color{blue}{\mathsf{fma}\left(b, b \cdot 0.020833333333333332, -0.25\right)}, 0.5\right) \]
                                        2. Taylor expanded in b around inf

                                          \[\leadsto \frac{1}{48} \cdot {b}^{\color{blue}{3}} \]
                                        3. Step-by-step derivation
                                          1. Applied rewrites50.4%

                                            \[\leadsto b \cdot \left(0.020833333333333332 \cdot \color{blue}{\left(b \cdot b\right)}\right) \]

                                          if 0.0 < (exp.f64 a)

                                          1. Initial program 99.4%

                                            \[\frac{e^{a}}{e^{a} + e^{b}} \]
                                          2. Add Preprocessing
                                          3. Taylor expanded in a around 0

                                            \[\leadsto \color{blue}{\frac{1}{1 + e^{b}}} \]
                                          4. Step-by-step derivation
                                            1. lower-/.f64N/A

                                              \[\leadsto \color{blue}{\frac{1}{1 + e^{b}}} \]
                                            2. lower-+.f64N/A

                                              \[\leadsto \frac{1}{\color{blue}{1 + e^{b}}} \]
                                            3. lower-exp.f6498.9

                                              \[\leadsto \frac{1}{1 + \color{blue}{e^{b}}} \]
                                          5. Applied rewrites98.9%

                                            \[\leadsto \color{blue}{\frac{1}{1 + e^{b}}} \]
                                          6. Taylor expanded in b around 0

                                            \[\leadsto \frac{1}{2 + \color{blue}{b \cdot \left(1 + \frac{1}{2} \cdot b\right)}} \]
                                          7. Step-by-step derivation
                                            1. Applied rewrites64.3%

                                              \[\leadsto \frac{1}{\mathsf{fma}\left(b, \color{blue}{\mathsf{fma}\left(b, 0.5, 1\right)}, 2\right)} \]
                                            2. Taylor expanded in b around inf

                                              \[\leadsto \frac{1}{\mathsf{fma}\left(b, \frac{1}{2} \cdot b, 2\right)} \]
                                            3. Step-by-step derivation
                                              1. Applied rewrites63.2%

                                                \[\leadsto \frac{1}{\mathsf{fma}\left(b, b \cdot 0.5, 2\right)} \]
                                            4. Recombined 2 regimes into one program.
                                            5. Add Preprocessing

                                            Alternative 10: 50.8% accurate, 2.6× speedup?

                                            \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;e^{a} \leq 10^{-22}:\\ \;\;\;\;b \cdot \left(0.020833333333333332 \cdot \left(b \cdot b\right)\right)\\ \mathbf{else}:\\ \;\;\;\;\mathsf{fma}\left(a, 0.25, 0.5\right)\\ \end{array} \end{array} \]
                                            (FPCore (a b)
                                             :precision binary64
                                             (if (<= (exp a) 1e-22)
                                               (* b (* 0.020833333333333332 (* b b)))
                                               (fma a 0.25 0.5)))
                                            double code(double a, double b) {
                                            	double tmp;
                                            	if (exp(a) <= 1e-22) {
                                            		tmp = b * (0.020833333333333332 * (b * b));
                                            	} else {
                                            		tmp = fma(a, 0.25, 0.5);
                                            	}
                                            	return tmp;
                                            }
                                            
                                            function code(a, b)
                                            	tmp = 0.0
                                            	if (exp(a) <= 1e-22)
                                            		tmp = Float64(b * Float64(0.020833333333333332 * Float64(b * b)));
                                            	else
                                            		tmp = fma(a, 0.25, 0.5);
                                            	end
                                            	return tmp
                                            end
                                            
                                            code[a_, b_] := If[LessEqual[N[Exp[a], $MachinePrecision], 1e-22], N[(b * N[(0.020833333333333332 * N[(b * b), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], N[(a * 0.25 + 0.5), $MachinePrecision]]
                                            
                                            \begin{array}{l}
                                            
                                            \\
                                            \begin{array}{l}
                                            \mathbf{if}\;e^{a} \leq 10^{-22}:\\
                                            \;\;\;\;b \cdot \left(0.020833333333333332 \cdot \left(b \cdot b\right)\right)\\
                                            
                                            \mathbf{else}:\\
                                            \;\;\;\;\mathsf{fma}\left(a, 0.25, 0.5\right)\\
                                            
                                            
                                            \end{array}
                                            \end{array}
                                            
                                            Derivation
                                            1. Split input into 2 regimes
                                            2. if (exp.f64 a) < 1e-22

                                              1. Initial program 100.0%

                                                \[\frac{e^{a}}{e^{a} + e^{b}} \]
                                              2. Add Preprocessing
                                              3. Taylor expanded in a around 0

                                                \[\leadsto \color{blue}{\frac{1}{1 + e^{b}}} \]
                                              4. Step-by-step derivation
                                                1. lower-/.f64N/A

                                                  \[\leadsto \color{blue}{\frac{1}{1 + e^{b}}} \]
                                                2. lower-+.f64N/A

                                                  \[\leadsto \frac{1}{\color{blue}{1 + e^{b}}} \]
                                                3. lower-exp.f6433.4

                                                  \[\leadsto \frac{1}{1 + \color{blue}{e^{b}}} \]
                                              5. Applied rewrites33.4%

                                                \[\leadsto \color{blue}{\frac{1}{1 + e^{b}}} \]
                                              6. Taylor expanded in b around 0

                                                \[\leadsto \frac{1}{2} + \color{blue}{b \cdot \left(\frac{1}{48} \cdot {b}^{2} - \frac{1}{4}\right)} \]
                                              7. Step-by-step derivation
                                                1. Applied rewrites2.8%

                                                  \[\leadsto \mathsf{fma}\left(b, \color{blue}{\mathsf{fma}\left(b, b \cdot 0.020833333333333332, -0.25\right)}, 0.5\right) \]
                                                2. Taylor expanded in b around inf

                                                  \[\leadsto \frac{1}{48} \cdot {b}^{\color{blue}{3}} \]
                                                3. Step-by-step derivation
                                                  1. Applied rewrites49.8%

                                                    \[\leadsto b \cdot \left(0.020833333333333332 \cdot \color{blue}{\left(b \cdot b\right)}\right) \]

                                                  if 1e-22 < (exp.f64 a)

                                                  1. Initial program 99.4%

                                                    \[\frac{e^{a}}{e^{a} + e^{b}} \]
                                                  2. Add Preprocessing
                                                  3. Taylor expanded in b around 0

                                                    \[\leadsto \color{blue}{-1 \cdot \frac{b \cdot e^{a}}{{\left(1 + e^{a}\right)}^{2}} + \frac{e^{a}}{1 + e^{a}}} \]
                                                  4. Step-by-step derivation
                                                    1. associate-*r/N/A

                                                      \[\leadsto \color{blue}{\frac{-1 \cdot \left(b \cdot e^{a}\right)}{{\left(1 + e^{a}\right)}^{2}}} + \frac{e^{a}}{1 + e^{a}} \]
                                                    2. unpow2N/A

                                                      \[\leadsto \frac{-1 \cdot \left(b \cdot e^{a}\right)}{\color{blue}{\left(1 + e^{a}\right) \cdot \left(1 + e^{a}\right)}} + \frac{e^{a}}{1 + e^{a}} \]
                                                    3. associate-*r*N/A

                                                      \[\leadsto \frac{\color{blue}{\left(-1 \cdot b\right) \cdot e^{a}}}{\left(1 + e^{a}\right) \cdot \left(1 + e^{a}\right)} + \frac{e^{a}}{1 + e^{a}} \]
                                                    4. times-fracN/A

                                                      \[\leadsto \color{blue}{\frac{-1 \cdot b}{1 + e^{a}} \cdot \frac{e^{a}}{1 + e^{a}}} + \frac{e^{a}}{1 + e^{a}} \]
                                                    5. distribute-lft1-inN/A

                                                      \[\leadsto \color{blue}{\left(\frac{-1 \cdot b}{1 + e^{a}} + 1\right) \cdot \frac{e^{a}}{1 + e^{a}}} \]
                                                    6. lower-*.f64N/A

                                                      \[\leadsto \color{blue}{\left(\frac{-1 \cdot b}{1 + e^{a}} + 1\right) \cdot \frac{e^{a}}{1 + e^{a}}} \]
                                                  5. Applied rewrites53.7%

                                                    \[\leadsto \color{blue}{\left(\frac{b}{-1 - e^{a}} + 1\right) \cdot \frac{e^{a}}{1 + e^{a}}} \]
                                                  6. Taylor expanded in a around 0

                                                    \[\leadsto \frac{1}{2} \cdot \left(1 + \frac{-1}{2} \cdot b\right) + \color{blue}{a \cdot \left(\frac{1}{2} \cdot \left(1 + \left(\frac{-1}{2} \cdot b + \frac{1}{4} \cdot b\right)\right) - \frac{1}{4} \cdot \left(1 + \frac{-1}{2} \cdot b\right)\right)} \]
                                                  7. Applied rewrites53.5%

                                                    \[\leadsto \mathsf{fma}\left(a, \color{blue}{0.25}, \mathsf{fma}\left(b, -0.25, 0.5\right)\right) \]
                                                  8. Taylor expanded in b around 0

                                                    \[\leadsto \mathsf{fma}\left(a, \frac{1}{4}, \frac{1}{2}\right) \]
                                                  9. Step-by-step derivation
                                                    1. Applied rewrites55.8%

                                                      \[\leadsto \mathsf{fma}\left(a, 0.25, 0.5\right) \]
                                                  10. Recombined 2 regimes into one program.
                                                  11. Add Preprocessing

                                                  Alternative 11: 38.2% accurate, 315.0× speedup?

                                                  \[\begin{array}{l} \\ 0.5 \end{array} \]
                                                  (FPCore (a b) :precision binary64 0.5)
                                                  double code(double a, double b) {
                                                  	return 0.5;
                                                  }
                                                  
                                                  real(8) function code(a, b)
                                                      real(8), intent (in) :: a
                                                      real(8), intent (in) :: b
                                                      code = 0.5d0
                                                  end function
                                                  
                                                  public static double code(double a, double b) {
                                                  	return 0.5;
                                                  }
                                                  
                                                  def code(a, b):
                                                  	return 0.5
                                                  
                                                  function code(a, b)
                                                  	return 0.5
                                                  end
                                                  
                                                  function tmp = code(a, b)
                                                  	tmp = 0.5;
                                                  end
                                                  
                                                  code[a_, b_] := 0.5
                                                  
                                                  \begin{array}{l}
                                                  
                                                  \\
                                                  0.5
                                                  \end{array}
                                                  
                                                  Derivation
                                                  1. Initial program 99.6%

                                                    \[\frac{e^{a}}{e^{a} + e^{b}} \]
                                                  2. Add Preprocessing
                                                  3. Taylor expanded in a around 0

                                                    \[\leadsto \color{blue}{\frac{1}{1 + e^{b}}} \]
                                                  4. Step-by-step derivation
                                                    1. lower-/.f64N/A

                                                      \[\leadsto \color{blue}{\frac{1}{1 + e^{b}}} \]
                                                    2. lower-+.f64N/A

                                                      \[\leadsto \frac{1}{\color{blue}{1 + e^{b}}} \]
                                                    3. lower-exp.f6479.5

                                                      \[\leadsto \frac{1}{1 + \color{blue}{e^{b}}} \]
                                                  5. Applied rewrites79.5%

                                                    \[\leadsto \color{blue}{\frac{1}{1 + e^{b}}} \]
                                                  6. Taylor expanded in b around 0

                                                    \[\leadsto \frac{1}{2} \]
                                                  7. Step-by-step derivation
                                                    1. Applied rewrites39.7%

                                                      \[\leadsto 0.5 \]
                                                    2. Add Preprocessing

                                                    Developer Target 1: 100.0% accurate, 2.7× speedup?

                                                    \[\begin{array}{l} \\ \frac{1}{1 + e^{b - a}} \end{array} \]
                                                    (FPCore (a b) :precision binary64 (/ 1.0 (+ 1.0 (exp (- b a)))))
                                                    double code(double a, double b) {
                                                    	return 1.0 / (1.0 + exp((b - a)));
                                                    }
                                                    
                                                    real(8) function code(a, b)
                                                        real(8), intent (in) :: a
                                                        real(8), intent (in) :: b
                                                        code = 1.0d0 / (1.0d0 + exp((b - a)))
                                                    end function
                                                    
                                                    public static double code(double a, double b) {
                                                    	return 1.0 / (1.0 + Math.exp((b - a)));
                                                    }
                                                    
                                                    def code(a, b):
                                                    	return 1.0 / (1.0 + math.exp((b - a)))
                                                    
                                                    function code(a, b)
                                                    	return Float64(1.0 / Float64(1.0 + exp(Float64(b - a))))
                                                    end
                                                    
                                                    function tmp = code(a, b)
                                                    	tmp = 1.0 / (1.0 + exp((b - a)));
                                                    end
                                                    
                                                    code[a_, b_] := N[(1.0 / N[(1.0 + N[Exp[N[(b - a), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
                                                    
                                                    \begin{array}{l}
                                                    
                                                    \\
                                                    \frac{1}{1 + e^{b - a}}
                                                    \end{array}
                                                    

                                                    Reproduce

                                                    ?
                                                    herbie shell --seed 2024221 
                                                    (FPCore (a b)
                                                      :name "Quotient of sum of exps"
                                                      :precision binary64
                                                    
                                                      :alt
                                                      (! :herbie-platform default (/ 1 (+ 1 (exp (- b a)))))
                                                    
                                                      (/ (exp a) (+ (exp a) (exp b))))