Data.Random.Distribution.Normal:normalF from random-fu-0.2.6.2

Percentage Accurate: 100.0% → 100.0%
Time: 30.4s
Alternatives: 20
Speedup: 1.0×

Specification

?
\[\begin{array}{l} \\ e^{\left(x \cdot y\right) \cdot y} \end{array} \]
(FPCore (x y) :precision binary64 (exp (* (* x y) y)))
double code(double x, double y) {
	return exp(((x * y) * y));
}
real(8) function code(x, y)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    code = exp(((x * y) * y))
end function
public static double code(double x, double y) {
	return Math.exp(((x * y) * y));
}
def code(x, y):
	return math.exp(((x * y) * y))
function code(x, y)
	return exp(Float64(Float64(x * y) * y))
end
function tmp = code(x, y)
	tmp = exp(((x * y) * y));
end
code[x_, y_] := N[Exp[N[(N[(x * y), $MachinePrecision] * y), $MachinePrecision]], $MachinePrecision]
\begin{array}{l}

\\
e^{\left(x \cdot y\right) \cdot y}
\end{array}

Sampling outcomes in binary64 precision:

Local Percentage Accuracy vs ?

The average percentage accuracy by input value. Horizontal axis shows value of an input variable; the variable is choosen in the title. Vertical axis is accuracy; higher is better. Red represent the original program, while blue represents Herbie's suggestion. These can be toggled with buttons below the plot. The line is an average while dots represent individual samples.

Accuracy vs Speed?

Herbie found 20 alternatives:

AlternativeAccuracySpeedup
The accuracy (vertical axis) and speed (horizontal axis) of each alternatives. Up and to the right is better. The red square shows the initial program, and each blue circle shows an alternative.The line shows the best available speed-accuracy tradeoffs.

Initial Program: 100.0% accurate, 1.0× speedup?

\[\begin{array}{l} \\ e^{\left(x \cdot y\right) \cdot y} \end{array} \]
(FPCore (x y) :precision binary64 (exp (* (* x y) y)))
double code(double x, double y) {
	return exp(((x * y) * y));
}
real(8) function code(x, y)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    code = exp(((x * y) * y))
end function
public static double code(double x, double y) {
	return Math.exp(((x * y) * y));
}
def code(x, y):
	return math.exp(((x * y) * y))
function code(x, y)
	return exp(Float64(Float64(x * y) * y))
end
function tmp = code(x, y)
	tmp = exp(((x * y) * y));
end
code[x_, y_] := N[Exp[N[(N[(x * y), $MachinePrecision] * y), $MachinePrecision]], $MachinePrecision]
\begin{array}{l}

\\
e^{\left(x \cdot y\right) \cdot y}
\end{array}

Alternative 1: 100.0% accurate, 1.0× speedup?

\[\begin{array}{l} \\ e^{y \cdot \left(x \cdot y\right)} \end{array} \]
(FPCore (x y) :precision binary64 (exp (* y (* x y))))
double code(double x, double y) {
	return exp((y * (x * y)));
}
real(8) function code(x, y)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    code = exp((y * (x * y)))
end function
public static double code(double x, double y) {
	return Math.exp((y * (x * y)));
}
def code(x, y):
	return math.exp((y * (x * y)))
function code(x, y)
	return exp(Float64(y * Float64(x * y)))
end
function tmp = code(x, y)
	tmp = exp((y * (x * y)));
end
code[x_, y_] := N[Exp[N[(y * N[(x * y), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]
\begin{array}{l}

\\
e^{y \cdot \left(x \cdot y\right)}
\end{array}
Derivation
  1. Initial program 100.0%

    \[e^{\left(x \cdot y\right) \cdot y} \]
  2. Add Preprocessing
  3. Final simplification100.0%

    \[\leadsto e^{y \cdot \left(x \cdot y\right)} \]
  4. Add Preprocessing

Alternative 2: 82.4% accurate, 0.5× speedup?

\[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;e^{y \cdot \left(x \cdot y\right)} \leq 0:\\ \;\;\;\;e^{x \cdot y}\\ \mathbf{else}:\\ \;\;\;\;\mathsf{fma}\left(x, \left(y \cdot y\right) \cdot \left(\left(x \cdot y\right) \cdot \left(y \cdot \mathsf{fma}\left(x, \left(y \cdot y\right) \cdot 0.16666666666666666, 0.5\right)\right)\right), \mathsf{fma}\left(x \cdot y, y, 1\right)\right)\\ \end{array} \end{array} \]
(FPCore (x y)
 :precision binary64
 (if (<= (exp (* y (* x y))) 0.0)
   (exp (* x y))
   (fma
    x
    (* (* y y) (* (* x y) (* y (fma x (* (* y y) 0.16666666666666666) 0.5))))
    (fma (* x y) y 1.0))))
double code(double x, double y) {
	double tmp;
	if (exp((y * (x * y))) <= 0.0) {
		tmp = exp((x * y));
	} else {
		tmp = fma(x, ((y * y) * ((x * y) * (y * fma(x, ((y * y) * 0.16666666666666666), 0.5)))), fma((x * y), y, 1.0));
	}
	return tmp;
}
function code(x, y)
	tmp = 0.0
	if (exp(Float64(y * Float64(x * y))) <= 0.0)
		tmp = exp(Float64(x * y));
	else
		tmp = fma(x, Float64(Float64(y * y) * Float64(Float64(x * y) * Float64(y * fma(x, Float64(Float64(y * y) * 0.16666666666666666), 0.5)))), fma(Float64(x * y), y, 1.0));
	end
	return tmp
end
code[x_, y_] := If[LessEqual[N[Exp[N[(y * N[(x * y), $MachinePrecision]), $MachinePrecision]], $MachinePrecision], 0.0], N[Exp[N[(x * y), $MachinePrecision]], $MachinePrecision], N[(x * N[(N[(y * y), $MachinePrecision] * N[(N[(x * y), $MachinePrecision] * N[(y * N[(x * N[(N[(y * y), $MachinePrecision] * 0.16666666666666666), $MachinePrecision] + 0.5), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] + N[(N[(x * y), $MachinePrecision] * y + 1.0), $MachinePrecision]), $MachinePrecision]]
\begin{array}{l}

\\
\begin{array}{l}
\mathbf{if}\;e^{y \cdot \left(x \cdot y\right)} \leq 0:\\
\;\;\;\;e^{x \cdot y}\\

\mathbf{else}:\\
\;\;\;\;\mathsf{fma}\left(x, \left(y \cdot y\right) \cdot \left(\left(x \cdot y\right) \cdot \left(y \cdot \mathsf{fma}\left(x, \left(y \cdot y\right) \cdot 0.16666666666666666, 0.5\right)\right)\right), \mathsf{fma}\left(x \cdot y, y, 1\right)\right)\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if (exp.f64 (*.f64 (*.f64 x y) y)) < 0.0

    1. Initial program 100.0%

      \[e^{\left(x \cdot y\right) \cdot y} \]
    2. Add Preprocessing
    3. Applied rewrites43.6%

      \[\leadsto e^{\color{blue}{x} \cdot y} \]

    if 0.0 < (exp.f64 (*.f64 (*.f64 x y) y))

    1. Initial program 100.0%

      \[e^{\left(x \cdot y\right) \cdot y} \]
    2. Add Preprocessing
    3. Taylor expanded in x around 0

      \[\leadsto \color{blue}{1 + x \cdot \left(x \cdot \left(\frac{1}{6} \cdot \left(x \cdot {y}^{6}\right) + \frac{1}{2} \cdot {y}^{4}\right) + {y}^{2}\right)} \]
    4. Applied rewrites93.7%

      \[\leadsto \color{blue}{\mathsf{fma}\left(y \cdot y, \mathsf{fma}\left(x \cdot \left(x \cdot \left(y \cdot y\right)\right), \mathsf{fma}\left(x, \left(y \cdot y\right) \cdot 0.16666666666666666, 0.5\right), x\right), 1\right)} \]
    5. Step-by-step derivation
      1. Applied rewrites93.7%

        \[\leadsto \mathsf{fma}\left(x, \color{blue}{\left(\left(x \cdot y\right) \cdot \left(y \cdot \mathsf{fma}\left(x, \left(y \cdot y\right) \cdot 0.16666666666666666, 0.5\right)\right)\right) \cdot \left(y \cdot y\right)}, \mathsf{fma}\left(x, y \cdot y, 1\right)\right) \]
      2. Step-by-step derivation
        1. Applied rewrites93.7%

          \[\leadsto \mathsf{fma}\left(x, \left(\left(x \cdot y\right) \cdot \left(y \cdot \mathsf{fma}\left(x, \left(y \cdot y\right) \cdot 0.16666666666666666, 0.5\right)\right)\right) \cdot \left(y \cdot y\right), \mathsf{fma}\left(x \cdot y, y, 1\right)\right) \]
      3. Recombined 2 regimes into one program.
      4. Final simplification78.1%

        \[\leadsto \begin{array}{l} \mathbf{if}\;e^{y \cdot \left(x \cdot y\right)} \leq 0:\\ \;\;\;\;e^{x \cdot y}\\ \mathbf{else}:\\ \;\;\;\;\mathsf{fma}\left(x, \left(y \cdot y\right) \cdot \left(\left(x \cdot y\right) \cdot \left(y \cdot \mathsf{fma}\left(x, \left(y \cdot y\right) \cdot 0.16666666666666666, 0.5\right)\right)\right), \mathsf{fma}\left(x \cdot y, y, 1\right)\right)\\ \end{array} \]
      5. Add Preprocessing

      Alternative 3: 70.5% accurate, 0.8× speedup?

      \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;e^{y \cdot \left(x \cdot y\right)} \leq 2:\\ \;\;\;\;\mathsf{fma}\left(x \cdot y, y, 1\right)\\ \mathbf{else}:\\ \;\;\;\;\left(\left(x \cdot y\right) \cdot \left(x \cdot 0.5\right)\right) \cdot \left(y \cdot \left(y \cdot y\right)\right)\\ \end{array} \end{array} \]
      (FPCore (x y)
       :precision binary64
       (if (<= (exp (* y (* x y))) 2.0)
         (fma (* x y) y 1.0)
         (* (* (* x y) (* x 0.5)) (* y (* y y)))))
      double code(double x, double y) {
      	double tmp;
      	if (exp((y * (x * y))) <= 2.0) {
      		tmp = fma((x * y), y, 1.0);
      	} else {
      		tmp = ((x * y) * (x * 0.5)) * (y * (y * y));
      	}
      	return tmp;
      }
      
      function code(x, y)
      	tmp = 0.0
      	if (exp(Float64(y * Float64(x * y))) <= 2.0)
      		tmp = fma(Float64(x * y), y, 1.0);
      	else
      		tmp = Float64(Float64(Float64(x * y) * Float64(x * 0.5)) * Float64(y * Float64(y * y)));
      	end
      	return tmp
      end
      
      code[x_, y_] := If[LessEqual[N[Exp[N[(y * N[(x * y), $MachinePrecision]), $MachinePrecision]], $MachinePrecision], 2.0], N[(N[(x * y), $MachinePrecision] * y + 1.0), $MachinePrecision], N[(N[(N[(x * y), $MachinePrecision] * N[(x * 0.5), $MachinePrecision]), $MachinePrecision] * N[(y * N[(y * y), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]]
      
      \begin{array}{l}
      
      \\
      \begin{array}{l}
      \mathbf{if}\;e^{y \cdot \left(x \cdot y\right)} \leq 2:\\
      \;\;\;\;\mathsf{fma}\left(x \cdot y, y, 1\right)\\
      
      \mathbf{else}:\\
      \;\;\;\;\left(\left(x \cdot y\right) \cdot \left(x \cdot 0.5\right)\right) \cdot \left(y \cdot \left(y \cdot y\right)\right)\\
      
      
      \end{array}
      \end{array}
      
      Derivation
      1. Split input into 2 regimes
      2. if (exp.f64 (*.f64 (*.f64 x y) y)) < 2

        1. Initial program 100.0%

          \[e^{\left(x \cdot y\right) \cdot y} \]
        2. Add Preprocessing
        3. Taylor expanded in x around 0

          \[\leadsto \color{blue}{1 + x \cdot {y}^{2}} \]
        4. Step-by-step derivation
          1. +-commutativeN/A

            \[\leadsto \color{blue}{x \cdot {y}^{2} + 1} \]
          2. lower-fma.f64N/A

            \[\leadsto \color{blue}{\mathsf{fma}\left(x, {y}^{2}, 1\right)} \]
          3. unpow2N/A

            \[\leadsto \mathsf{fma}\left(x, \color{blue}{y \cdot y}, 1\right) \]
          4. lower-*.f6457.7

            \[\leadsto \mathsf{fma}\left(x, \color{blue}{y \cdot y}, 1\right) \]
        5. Applied rewrites57.7%

          \[\leadsto \color{blue}{\mathsf{fma}\left(x, y \cdot y, 1\right)} \]
        6. Step-by-step derivation
          1. Applied rewrites57.7%

            \[\leadsto \mathsf{fma}\left(x \cdot y, \color{blue}{y}, 1\right) \]

          if 2 < (exp.f64 (*.f64 (*.f64 x y) y))

          1. Initial program 100.0%

            \[e^{\left(x \cdot y\right) \cdot y} \]
          2. Add Preprocessing
          3. Taylor expanded in x around 0

            \[\leadsto \color{blue}{1 + x \cdot \left(\frac{1}{2} \cdot \left(x \cdot {y}^{4}\right) + {y}^{2}\right)} \]
          4. Step-by-step derivation
            1. +-commutativeN/A

              \[\leadsto \color{blue}{x \cdot \left(\frac{1}{2} \cdot \left(x \cdot {y}^{4}\right) + {y}^{2}\right) + 1} \]
          5. Applied rewrites80.9%

            \[\leadsto \color{blue}{\mathsf{fma}\left(y \cdot y, \mathsf{fma}\left(x, \left(x \cdot \left(y \cdot y\right)\right) \cdot 0.5, x\right), 1\right)} \]
          6. Step-by-step derivation
            1. Applied rewrites79.5%

              \[\leadsto \mathsf{fma}\left(\left(y \cdot y\right) \cdot \left(x \cdot \left(\left(y \cdot y\right) \cdot 0.5\right)\right), \color{blue}{x}, \mathsf{fma}\left(x, y \cdot y, 1\right)\right) \]
            2. Taylor expanded in y around inf

              \[\leadsto \frac{1}{2} \cdot \color{blue}{\left({x}^{2} \cdot {y}^{4}\right)} \]
            3. Step-by-step derivation
              1. Applied rewrites83.9%

                \[\leadsto y \cdot \color{blue}{\left(x \cdot \left(0.5 \cdot \left(x \cdot \left(y \cdot \left(y \cdot y\right)\right)\right)\right)\right)} \]
              2. Step-by-step derivation
                1. Applied rewrites86.8%

                  \[\leadsto \left(\left(x \cdot y\right) \cdot \left(x \cdot 0.5\right)\right) \cdot \left(y \cdot \color{blue}{\left(y \cdot y\right)}\right) \]
              3. Recombined 2 regimes into one program.
              4. Final simplification65.1%

                \[\leadsto \begin{array}{l} \mathbf{if}\;e^{y \cdot \left(x \cdot y\right)} \leq 2:\\ \;\;\;\;\mathsf{fma}\left(x \cdot y, y, 1\right)\\ \mathbf{else}:\\ \;\;\;\;\left(\left(x \cdot y\right) \cdot \left(x \cdot 0.5\right)\right) \cdot \left(y \cdot \left(y \cdot y\right)\right)\\ \end{array} \]
              5. Add Preprocessing

              Alternative 4: 70.6% accurate, 0.8× speedup?

              \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;e^{y \cdot \left(x \cdot y\right)} \leq 2:\\ \;\;\;\;\mathsf{fma}\left(x \cdot y, y, 1\right)\\ \mathbf{else}:\\ \;\;\;\;y \cdot \left(x \cdot \left(0.5 \cdot \left(x \cdot \left(y \cdot \left(y \cdot y\right)\right)\right)\right)\right)\\ \end{array} \end{array} \]
              (FPCore (x y)
               :precision binary64
               (if (<= (exp (* y (* x y))) 2.0)
                 (fma (* x y) y 1.0)
                 (* y (* x (* 0.5 (* x (* y (* y y))))))))
              double code(double x, double y) {
              	double tmp;
              	if (exp((y * (x * y))) <= 2.0) {
              		tmp = fma((x * y), y, 1.0);
              	} else {
              		tmp = y * (x * (0.5 * (x * (y * (y * y)))));
              	}
              	return tmp;
              }
              
              function code(x, y)
              	tmp = 0.0
              	if (exp(Float64(y * Float64(x * y))) <= 2.0)
              		tmp = fma(Float64(x * y), y, 1.0);
              	else
              		tmp = Float64(y * Float64(x * Float64(0.5 * Float64(x * Float64(y * Float64(y * y))))));
              	end
              	return tmp
              end
              
              code[x_, y_] := If[LessEqual[N[Exp[N[(y * N[(x * y), $MachinePrecision]), $MachinePrecision]], $MachinePrecision], 2.0], N[(N[(x * y), $MachinePrecision] * y + 1.0), $MachinePrecision], N[(y * N[(x * N[(0.5 * N[(x * N[(y * N[(y * y), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]]
              
              \begin{array}{l}
              
              \\
              \begin{array}{l}
              \mathbf{if}\;e^{y \cdot \left(x \cdot y\right)} \leq 2:\\
              \;\;\;\;\mathsf{fma}\left(x \cdot y, y, 1\right)\\
              
              \mathbf{else}:\\
              \;\;\;\;y \cdot \left(x \cdot \left(0.5 \cdot \left(x \cdot \left(y \cdot \left(y \cdot y\right)\right)\right)\right)\right)\\
              
              
              \end{array}
              \end{array}
              
              Derivation
              1. Split input into 2 regimes
              2. if (exp.f64 (*.f64 (*.f64 x y) y)) < 2

                1. Initial program 100.0%

                  \[e^{\left(x \cdot y\right) \cdot y} \]
                2. Add Preprocessing
                3. Taylor expanded in x around 0

                  \[\leadsto \color{blue}{1 + x \cdot {y}^{2}} \]
                4. Step-by-step derivation
                  1. +-commutativeN/A

                    \[\leadsto \color{blue}{x \cdot {y}^{2} + 1} \]
                  2. lower-fma.f64N/A

                    \[\leadsto \color{blue}{\mathsf{fma}\left(x, {y}^{2}, 1\right)} \]
                  3. unpow2N/A

                    \[\leadsto \mathsf{fma}\left(x, \color{blue}{y \cdot y}, 1\right) \]
                  4. lower-*.f6457.7

                    \[\leadsto \mathsf{fma}\left(x, \color{blue}{y \cdot y}, 1\right) \]
                5. Applied rewrites57.7%

                  \[\leadsto \color{blue}{\mathsf{fma}\left(x, y \cdot y, 1\right)} \]
                6. Step-by-step derivation
                  1. Applied rewrites57.7%

                    \[\leadsto \mathsf{fma}\left(x \cdot y, \color{blue}{y}, 1\right) \]

                  if 2 < (exp.f64 (*.f64 (*.f64 x y) y))

                  1. Initial program 100.0%

                    \[e^{\left(x \cdot y\right) \cdot y} \]
                  2. Add Preprocessing
                  3. Taylor expanded in x around 0

                    \[\leadsto \color{blue}{1 + x \cdot \left(\frac{1}{2} \cdot \left(x \cdot {y}^{4}\right) + {y}^{2}\right)} \]
                  4. Step-by-step derivation
                    1. +-commutativeN/A

                      \[\leadsto \color{blue}{x \cdot \left(\frac{1}{2} \cdot \left(x \cdot {y}^{4}\right) + {y}^{2}\right) + 1} \]
                  5. Applied rewrites80.9%

                    \[\leadsto \color{blue}{\mathsf{fma}\left(y \cdot y, \mathsf{fma}\left(x, \left(x \cdot \left(y \cdot y\right)\right) \cdot 0.5, x\right), 1\right)} \]
                  6. Step-by-step derivation
                    1. Applied rewrites79.5%

                      \[\leadsto \mathsf{fma}\left(\left(y \cdot y\right) \cdot \left(x \cdot \left(\left(y \cdot y\right) \cdot 0.5\right)\right), \color{blue}{x}, \mathsf{fma}\left(x, y \cdot y, 1\right)\right) \]
                    2. Taylor expanded in y around inf

                      \[\leadsto \frac{1}{2} \cdot \color{blue}{\left({x}^{2} \cdot {y}^{4}\right)} \]
                    3. Step-by-step derivation
                      1. Applied rewrites83.9%

                        \[\leadsto y \cdot \color{blue}{\left(x \cdot \left(0.5 \cdot \left(x \cdot \left(y \cdot \left(y \cdot y\right)\right)\right)\right)\right)} \]
                    4. Recombined 2 regimes into one program.
                    5. Final simplification64.4%

                      \[\leadsto \begin{array}{l} \mathbf{if}\;e^{y \cdot \left(x \cdot y\right)} \leq 2:\\ \;\;\;\;\mathsf{fma}\left(x \cdot y, y, 1\right)\\ \mathbf{else}:\\ \;\;\;\;y \cdot \left(x \cdot \left(0.5 \cdot \left(x \cdot \left(y \cdot \left(y \cdot y\right)\right)\right)\right)\right)\\ \end{array} \]
                    6. Add Preprocessing

                    Alternative 5: 87.3% accurate, 0.9× speedup?

                    \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;y \cdot \left(x \cdot y\right) \leq -400000:\\ \;\;\;\;e^{x}\\ \mathbf{else}:\\ \;\;\;\;\mathsf{fma}\left(x, \left(y \cdot y\right) \cdot \left(\left(x \cdot y\right) \cdot \left(y \cdot \mathsf{fma}\left(x, \left(y \cdot y\right) \cdot 0.16666666666666666, 0.5\right)\right)\right), \mathsf{fma}\left(x \cdot y, y, 1\right)\right)\\ \end{array} \end{array} \]
                    (FPCore (x y)
                     :precision binary64
                     (if (<= (* y (* x y)) -400000.0)
                       (exp x)
                       (fma
                        x
                        (* (* y y) (* (* x y) (* y (fma x (* (* y y) 0.16666666666666666) 0.5))))
                        (fma (* x y) y 1.0))))
                    double code(double x, double y) {
                    	double tmp;
                    	if ((y * (x * y)) <= -400000.0) {
                    		tmp = exp(x);
                    	} else {
                    		tmp = fma(x, ((y * y) * ((x * y) * (y * fma(x, ((y * y) * 0.16666666666666666), 0.5)))), fma((x * y), y, 1.0));
                    	}
                    	return tmp;
                    }
                    
                    function code(x, y)
                    	tmp = 0.0
                    	if (Float64(y * Float64(x * y)) <= -400000.0)
                    		tmp = exp(x);
                    	else
                    		tmp = fma(x, Float64(Float64(y * y) * Float64(Float64(x * y) * Float64(y * fma(x, Float64(Float64(y * y) * 0.16666666666666666), 0.5)))), fma(Float64(x * y), y, 1.0));
                    	end
                    	return tmp
                    end
                    
                    code[x_, y_] := If[LessEqual[N[(y * N[(x * y), $MachinePrecision]), $MachinePrecision], -400000.0], N[Exp[x], $MachinePrecision], N[(x * N[(N[(y * y), $MachinePrecision] * N[(N[(x * y), $MachinePrecision] * N[(y * N[(x * N[(N[(y * y), $MachinePrecision] * 0.16666666666666666), $MachinePrecision] + 0.5), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] + N[(N[(x * y), $MachinePrecision] * y + 1.0), $MachinePrecision]), $MachinePrecision]]
                    
                    \begin{array}{l}
                    
                    \\
                    \begin{array}{l}
                    \mathbf{if}\;y \cdot \left(x \cdot y\right) \leq -400000:\\
                    \;\;\;\;e^{x}\\
                    
                    \mathbf{else}:\\
                    \;\;\;\;\mathsf{fma}\left(x, \left(y \cdot y\right) \cdot \left(\left(x \cdot y\right) \cdot \left(y \cdot \mathsf{fma}\left(x, \left(y \cdot y\right) \cdot 0.16666666666666666, 0.5\right)\right)\right), \mathsf{fma}\left(x \cdot y, y, 1\right)\right)\\
                    
                    
                    \end{array}
                    \end{array}
                    
                    Derivation
                    1. Split input into 2 regimes
                    2. if (*.f64 (*.f64 x y) y) < -4e5

                      1. Initial program 100.0%

                        \[e^{\left(x \cdot y\right) \cdot y} \]
                      2. Add Preprocessing
                      3. Applied rewrites67.3%

                        \[\leadsto e^{\color{blue}{x}} \]

                      if -4e5 < (*.f64 (*.f64 x y) y)

                      1. Initial program 100.0%

                        \[e^{\left(x \cdot y\right) \cdot y} \]
                      2. Add Preprocessing
                      3. Taylor expanded in x around 0

                        \[\leadsto \color{blue}{1 + x \cdot \left(x \cdot \left(\frac{1}{6} \cdot \left(x \cdot {y}^{6}\right) + \frac{1}{2} \cdot {y}^{4}\right) + {y}^{2}\right)} \]
                      4. Applied rewrites93.7%

                        \[\leadsto \color{blue}{\mathsf{fma}\left(y \cdot y, \mathsf{fma}\left(x \cdot \left(x \cdot \left(y \cdot y\right)\right), \mathsf{fma}\left(x, \left(y \cdot y\right) \cdot 0.16666666666666666, 0.5\right), x\right), 1\right)} \]
                      5. Step-by-step derivation
                        1. Applied rewrites93.7%

                          \[\leadsto \mathsf{fma}\left(x, \color{blue}{\left(\left(x \cdot y\right) \cdot \left(y \cdot \mathsf{fma}\left(x, \left(y \cdot y\right) \cdot 0.16666666666666666, 0.5\right)\right)\right) \cdot \left(y \cdot y\right)}, \mathsf{fma}\left(x, y \cdot y, 1\right)\right) \]
                        2. Step-by-step derivation
                          1. Applied rewrites93.7%

                            \[\leadsto \mathsf{fma}\left(x, \left(\left(x \cdot y\right) \cdot \left(y \cdot \mathsf{fma}\left(x, \left(y \cdot y\right) \cdot 0.16666666666666666, 0.5\right)\right)\right) \cdot \left(y \cdot y\right), \mathsf{fma}\left(x \cdot y, y, 1\right)\right) \]
                        3. Recombined 2 regimes into one program.
                        4. Final simplification85.5%

                          \[\leadsto \begin{array}{l} \mathbf{if}\;y \cdot \left(x \cdot y\right) \leq -400000:\\ \;\;\;\;e^{x}\\ \mathbf{else}:\\ \;\;\;\;\mathsf{fma}\left(x, \left(y \cdot y\right) \cdot \left(\left(x \cdot y\right) \cdot \left(y \cdot \mathsf{fma}\left(x, \left(y \cdot y\right) \cdot 0.16666666666666666, 0.5\right)\right)\right), \mathsf{fma}\left(x \cdot y, y, 1\right)\right)\\ \end{array} \]
                        5. Add Preprocessing

                        Alternative 6: 69.2% accurate, 1.8× speedup?

                        \[\begin{array}{l} \\ \begin{array}{l} t_0 := y \cdot \left(x \cdot y\right)\\ \mathbf{if}\;t\_0 \leq 2 \cdot 10^{+15}:\\ \;\;\;\;\mathsf{fma}\left(x \cdot y, y, 1\right)\\ \mathbf{elif}\;t\_0 \leq 10^{+144}:\\ \;\;\;\;\left(y \cdot y\right) \cdot \left(y \cdot \left(0.16666666666666666 \cdot \left(x \cdot \left(x \cdot x\right)\right)\right)\right)\\ \mathbf{else}:\\ \;\;\;\;\left(x \cdot \left(x \cdot \left(y \cdot y\right)\right)\right) \cdot \left(\left(y \cdot y\right) \cdot 0.5\right)\\ \end{array} \end{array} \]
                        (FPCore (x y)
                         :precision binary64
                         (let* ((t_0 (* y (* x y))))
                           (if (<= t_0 2e+15)
                             (fma (* x y) y 1.0)
                             (if (<= t_0 1e+144)
                               (* (* y y) (* y (* 0.16666666666666666 (* x (* x x)))))
                               (* (* x (* x (* y y))) (* (* y y) 0.5))))))
                        double code(double x, double y) {
                        	double t_0 = y * (x * y);
                        	double tmp;
                        	if (t_0 <= 2e+15) {
                        		tmp = fma((x * y), y, 1.0);
                        	} else if (t_0 <= 1e+144) {
                        		tmp = (y * y) * (y * (0.16666666666666666 * (x * (x * x))));
                        	} else {
                        		tmp = (x * (x * (y * y))) * ((y * y) * 0.5);
                        	}
                        	return tmp;
                        }
                        
                        function code(x, y)
                        	t_0 = Float64(y * Float64(x * y))
                        	tmp = 0.0
                        	if (t_0 <= 2e+15)
                        		tmp = fma(Float64(x * y), y, 1.0);
                        	elseif (t_0 <= 1e+144)
                        		tmp = Float64(Float64(y * y) * Float64(y * Float64(0.16666666666666666 * Float64(x * Float64(x * x)))));
                        	else
                        		tmp = Float64(Float64(x * Float64(x * Float64(y * y))) * Float64(Float64(y * y) * 0.5));
                        	end
                        	return tmp
                        end
                        
                        code[x_, y_] := Block[{t$95$0 = N[(y * N[(x * y), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[t$95$0, 2e+15], N[(N[(x * y), $MachinePrecision] * y + 1.0), $MachinePrecision], If[LessEqual[t$95$0, 1e+144], N[(N[(y * y), $MachinePrecision] * N[(y * N[(0.16666666666666666 * N[(x * N[(x * x), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], N[(N[(x * N[(x * N[(y * y), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] * N[(N[(y * y), $MachinePrecision] * 0.5), $MachinePrecision]), $MachinePrecision]]]]
                        
                        \begin{array}{l}
                        
                        \\
                        \begin{array}{l}
                        t_0 := y \cdot \left(x \cdot y\right)\\
                        \mathbf{if}\;t\_0 \leq 2 \cdot 10^{+15}:\\
                        \;\;\;\;\mathsf{fma}\left(x \cdot y, y, 1\right)\\
                        
                        \mathbf{elif}\;t\_0 \leq 10^{+144}:\\
                        \;\;\;\;\left(y \cdot y\right) \cdot \left(y \cdot \left(0.16666666666666666 \cdot \left(x \cdot \left(x \cdot x\right)\right)\right)\right)\\
                        
                        \mathbf{else}:\\
                        \;\;\;\;\left(x \cdot \left(x \cdot \left(y \cdot y\right)\right)\right) \cdot \left(\left(y \cdot y\right) \cdot 0.5\right)\\
                        
                        
                        \end{array}
                        \end{array}
                        
                        Derivation
                        1. Split input into 3 regimes
                        2. if (*.f64 (*.f64 x y) y) < 2e15

                          1. Initial program 100.0%

                            \[e^{\left(x \cdot y\right) \cdot y} \]
                          2. Add Preprocessing
                          3. Taylor expanded in x around 0

                            \[\leadsto \color{blue}{1 + x \cdot {y}^{2}} \]
                          4. Step-by-step derivation
                            1. +-commutativeN/A

                              \[\leadsto \color{blue}{x \cdot {y}^{2} + 1} \]
                            2. lower-fma.f64N/A

                              \[\leadsto \color{blue}{\mathsf{fma}\left(x, {y}^{2}, 1\right)} \]
                            3. unpow2N/A

                              \[\leadsto \mathsf{fma}\left(x, \color{blue}{y \cdot y}, 1\right) \]
                            4. lower-*.f6457.4

                              \[\leadsto \mathsf{fma}\left(x, \color{blue}{y \cdot y}, 1\right) \]
                          5. Applied rewrites57.4%

                            \[\leadsto \color{blue}{\mathsf{fma}\left(x, y \cdot y, 1\right)} \]
                          6. Step-by-step derivation
                            1. Applied rewrites57.4%

                              \[\leadsto \mathsf{fma}\left(x \cdot y, \color{blue}{y}, 1\right) \]

                            if 2e15 < (*.f64 (*.f64 x y) y) < 1.00000000000000002e144

                            1. Initial program 100.0%

                              \[e^{\left(x \cdot y\right) \cdot y} \]
                            2. Add Preprocessing
                            3. Applied rewrites51.1%

                              \[\leadsto e^{\color{blue}{x} \cdot y} \]
                            4. Taylor expanded in x around 0

                              \[\leadsto \color{blue}{1 + x \cdot y} \]
                            5. Step-by-step derivation
                              1. +-commutativeN/A

                                \[\leadsto \color{blue}{x \cdot y + 1} \]
                              2. lower-fma.f642.9

                                \[\leadsto \color{blue}{\mathsf{fma}\left(x, y, 1\right)} \]
                            6. Applied rewrites2.9%

                              \[\leadsto \color{blue}{\mathsf{fma}\left(x, y, 1\right)} \]
                            7. Taylor expanded in x around 0

                              \[\leadsto \color{blue}{1 + x \cdot \left(y + x \cdot \left(\frac{1}{6} \cdot \left(x \cdot {y}^{3}\right) + \frac{1}{2} \cdot {y}^{2}\right)\right)} \]
                            8. Step-by-step derivation
                              1. +-commutativeN/A

                                \[\leadsto \color{blue}{x \cdot \left(y + x \cdot \left(\frac{1}{6} \cdot \left(x \cdot {y}^{3}\right) + \frac{1}{2} \cdot {y}^{2}\right)\right) + 1} \]
                              2. lower-fma.f64N/A

                                \[\leadsto \color{blue}{\mathsf{fma}\left(x, y + x \cdot \left(\frac{1}{6} \cdot \left(x \cdot {y}^{3}\right) + \frac{1}{2} \cdot {y}^{2}\right), 1\right)} \]
                              3. +-commutativeN/A

                                \[\leadsto \mathsf{fma}\left(x, \color{blue}{x \cdot \left(\frac{1}{6} \cdot \left(x \cdot {y}^{3}\right) + \frac{1}{2} \cdot {y}^{2}\right) + y}, 1\right) \]
                              4. lower-fma.f64N/A

                                \[\leadsto \mathsf{fma}\left(x, \color{blue}{\mathsf{fma}\left(x, \frac{1}{6} \cdot \left(x \cdot {y}^{3}\right) + \frac{1}{2} \cdot {y}^{2}, y\right)}, 1\right) \]
                              5. associate-*r*N/A

                                \[\leadsto \mathsf{fma}\left(x, \mathsf{fma}\left(x, \color{blue}{\left(\frac{1}{6} \cdot x\right) \cdot {y}^{3}} + \frac{1}{2} \cdot {y}^{2}, y\right), 1\right) \]
                              6. cube-multN/A

                                \[\leadsto \mathsf{fma}\left(x, \mathsf{fma}\left(x, \left(\frac{1}{6} \cdot x\right) \cdot \color{blue}{\left(y \cdot \left(y \cdot y\right)\right)} + \frac{1}{2} \cdot {y}^{2}, y\right), 1\right) \]
                              7. unpow2N/A

                                \[\leadsto \mathsf{fma}\left(x, \mathsf{fma}\left(x, \left(\frac{1}{6} \cdot x\right) \cdot \left(y \cdot \color{blue}{{y}^{2}}\right) + \frac{1}{2} \cdot {y}^{2}, y\right), 1\right) \]
                              8. associate-*r*N/A

                                \[\leadsto \mathsf{fma}\left(x, \mathsf{fma}\left(x, \color{blue}{\left(\left(\frac{1}{6} \cdot x\right) \cdot y\right) \cdot {y}^{2}} + \frac{1}{2} \cdot {y}^{2}, y\right), 1\right) \]
                              9. distribute-rgt-outN/A

                                \[\leadsto \mathsf{fma}\left(x, \mathsf{fma}\left(x, \color{blue}{{y}^{2} \cdot \left(\left(\frac{1}{6} \cdot x\right) \cdot y + \frac{1}{2}\right)}, y\right), 1\right) \]
                              10. lower-*.f64N/A

                                \[\leadsto \mathsf{fma}\left(x, \mathsf{fma}\left(x, \color{blue}{{y}^{2} \cdot \left(\left(\frac{1}{6} \cdot x\right) \cdot y + \frac{1}{2}\right)}, y\right), 1\right) \]
                              11. unpow2N/A

                                \[\leadsto \mathsf{fma}\left(x, \mathsf{fma}\left(x, \color{blue}{\left(y \cdot y\right)} \cdot \left(\left(\frac{1}{6} \cdot x\right) \cdot y + \frac{1}{2}\right), y\right), 1\right) \]
                              12. lower-*.f64N/A

                                \[\leadsto \mathsf{fma}\left(x, \mathsf{fma}\left(x, \color{blue}{\left(y \cdot y\right)} \cdot \left(\left(\frac{1}{6} \cdot x\right) \cdot y + \frac{1}{2}\right), y\right), 1\right) \]
                              13. lower-fma.f64N/A

                                \[\leadsto \mathsf{fma}\left(x, \mathsf{fma}\left(x, \left(y \cdot y\right) \cdot \color{blue}{\mathsf{fma}\left(\frac{1}{6} \cdot x, y, \frac{1}{2}\right)}, y\right), 1\right) \]
                              14. *-commutativeN/A

                                \[\leadsto \mathsf{fma}\left(x, \mathsf{fma}\left(x, \left(y \cdot y\right) \cdot \mathsf{fma}\left(\color{blue}{x \cdot \frac{1}{6}}, y, \frac{1}{2}\right), y\right), 1\right) \]
                              15. lower-*.f6424.6

                                \[\leadsto \mathsf{fma}\left(x, \mathsf{fma}\left(x, \left(y \cdot y\right) \cdot \mathsf{fma}\left(\color{blue}{x \cdot 0.16666666666666666}, y, 0.5\right), y\right), 1\right) \]
                            9. Applied rewrites24.6%

                              \[\leadsto \color{blue}{\mathsf{fma}\left(x, \mathsf{fma}\left(x, \left(y \cdot y\right) \cdot \mathsf{fma}\left(x \cdot 0.16666666666666666, y, 0.5\right), y\right), 1\right)} \]
                            10. Taylor expanded in x around inf

                              \[\leadsto \frac{1}{6} \cdot \color{blue}{\left({x}^{3} \cdot {y}^{3}\right)} \]
                            11. Step-by-step derivation
                              1. Applied rewrites36.6%

                                \[\leadsto \left(y \cdot y\right) \cdot \color{blue}{\left(y \cdot \left(0.16666666666666666 \cdot \left(x \cdot \left(x \cdot x\right)\right)\right)\right)} \]

                              if 1.00000000000000002e144 < (*.f64 (*.f64 x y) y)

                              1. Initial program 100.0%

                                \[e^{\left(x \cdot y\right) \cdot y} \]
                              2. Add Preprocessing
                              3. Taylor expanded in x around 0

                                \[\leadsto \color{blue}{1 + x \cdot \left(\frac{1}{2} \cdot \left(x \cdot {y}^{4}\right) + {y}^{2}\right)} \]
                              4. Step-by-step derivation
                                1. +-commutativeN/A

                                  \[\leadsto \color{blue}{x \cdot \left(\frac{1}{2} \cdot \left(x \cdot {y}^{4}\right) + {y}^{2}\right) + 1} \]
                              5. Applied rewrites100.0%

                                \[\leadsto \color{blue}{\mathsf{fma}\left(y \cdot y, \mathsf{fma}\left(x, \left(x \cdot \left(y \cdot y\right)\right) \cdot 0.5, x\right), 1\right)} \]
                              6. Taylor expanded in y around inf

                                \[\leadsto \frac{1}{2} \cdot \color{blue}{\left({x}^{2} \cdot {y}^{4}\right)} \]
                              7. Step-by-step derivation
                                1. Applied rewrites100.0%

                                  \[\leadsto \left(0.5 \cdot \left(y \cdot y\right)\right) \cdot \color{blue}{\left(x \cdot \left(x \cdot \left(y \cdot y\right)\right)\right)} \]
                              8. Recombined 3 regimes into one program.
                              9. Final simplification64.6%

                                \[\leadsto \begin{array}{l} \mathbf{if}\;y \cdot \left(x \cdot y\right) \leq 2 \cdot 10^{+15}:\\ \;\;\;\;\mathsf{fma}\left(x \cdot y, y, 1\right)\\ \mathbf{elif}\;y \cdot \left(x \cdot y\right) \leq 10^{+144}:\\ \;\;\;\;\left(y \cdot y\right) \cdot \left(y \cdot \left(0.16666666666666666 \cdot \left(x \cdot \left(x \cdot x\right)\right)\right)\right)\\ \mathbf{else}:\\ \;\;\;\;\left(x \cdot \left(x \cdot \left(y \cdot y\right)\right)\right) \cdot \left(\left(y \cdot y\right) \cdot 0.5\right)\\ \end{array} \]
                              10. Add Preprocessing

                              Alternative 7: 67.6% accurate, 1.8× speedup?

                              \[\begin{array}{l} \\ \begin{array}{l} t_0 := y \cdot \left(x \cdot y\right)\\ \mathbf{if}\;t\_0 \leq 2 \cdot 10^{+15}:\\ \;\;\;\;\mathsf{fma}\left(x \cdot y, y, 1\right)\\ \mathbf{elif}\;t\_0 \leq 10^{+144}:\\ \;\;\;\;\left(y \cdot y\right) \cdot \left(y \cdot \left(0.16666666666666666 \cdot \left(x \cdot \left(x \cdot x\right)\right)\right)\right)\\ \mathbf{else}:\\ \;\;\;\;\mathsf{fma}\left(x, \mathsf{fma}\left(x, \left(y \cdot y\right) \cdot 0.5, y\right), 1\right)\\ \end{array} \end{array} \]
                              (FPCore (x y)
                               :precision binary64
                               (let* ((t_0 (* y (* x y))))
                                 (if (<= t_0 2e+15)
                                   (fma (* x y) y 1.0)
                                   (if (<= t_0 1e+144)
                                     (* (* y y) (* y (* 0.16666666666666666 (* x (* x x)))))
                                     (fma x (fma x (* (* y y) 0.5) y) 1.0)))))
                              double code(double x, double y) {
                              	double t_0 = y * (x * y);
                              	double tmp;
                              	if (t_0 <= 2e+15) {
                              		tmp = fma((x * y), y, 1.0);
                              	} else if (t_0 <= 1e+144) {
                              		tmp = (y * y) * (y * (0.16666666666666666 * (x * (x * x))));
                              	} else {
                              		tmp = fma(x, fma(x, ((y * y) * 0.5), y), 1.0);
                              	}
                              	return tmp;
                              }
                              
                              function code(x, y)
                              	t_0 = Float64(y * Float64(x * y))
                              	tmp = 0.0
                              	if (t_0 <= 2e+15)
                              		tmp = fma(Float64(x * y), y, 1.0);
                              	elseif (t_0 <= 1e+144)
                              		tmp = Float64(Float64(y * y) * Float64(y * Float64(0.16666666666666666 * Float64(x * Float64(x * x)))));
                              	else
                              		tmp = fma(x, fma(x, Float64(Float64(y * y) * 0.5), y), 1.0);
                              	end
                              	return tmp
                              end
                              
                              code[x_, y_] := Block[{t$95$0 = N[(y * N[(x * y), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[t$95$0, 2e+15], N[(N[(x * y), $MachinePrecision] * y + 1.0), $MachinePrecision], If[LessEqual[t$95$0, 1e+144], N[(N[(y * y), $MachinePrecision] * N[(y * N[(0.16666666666666666 * N[(x * N[(x * x), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], N[(x * N[(x * N[(N[(y * y), $MachinePrecision] * 0.5), $MachinePrecision] + y), $MachinePrecision] + 1.0), $MachinePrecision]]]]
                              
                              \begin{array}{l}
                              
                              \\
                              \begin{array}{l}
                              t_0 := y \cdot \left(x \cdot y\right)\\
                              \mathbf{if}\;t\_0 \leq 2 \cdot 10^{+15}:\\
                              \;\;\;\;\mathsf{fma}\left(x \cdot y, y, 1\right)\\
                              
                              \mathbf{elif}\;t\_0 \leq 10^{+144}:\\
                              \;\;\;\;\left(y \cdot y\right) \cdot \left(y \cdot \left(0.16666666666666666 \cdot \left(x \cdot \left(x \cdot x\right)\right)\right)\right)\\
                              
                              \mathbf{else}:\\
                              \;\;\;\;\mathsf{fma}\left(x, \mathsf{fma}\left(x, \left(y \cdot y\right) \cdot 0.5, y\right), 1\right)\\
                              
                              
                              \end{array}
                              \end{array}
                              
                              Derivation
                              1. Split input into 3 regimes
                              2. if (*.f64 (*.f64 x y) y) < 2e15

                                1. Initial program 100.0%

                                  \[e^{\left(x \cdot y\right) \cdot y} \]
                                2. Add Preprocessing
                                3. Taylor expanded in x around 0

                                  \[\leadsto \color{blue}{1 + x \cdot {y}^{2}} \]
                                4. Step-by-step derivation
                                  1. +-commutativeN/A

                                    \[\leadsto \color{blue}{x \cdot {y}^{2} + 1} \]
                                  2. lower-fma.f64N/A

                                    \[\leadsto \color{blue}{\mathsf{fma}\left(x, {y}^{2}, 1\right)} \]
                                  3. unpow2N/A

                                    \[\leadsto \mathsf{fma}\left(x, \color{blue}{y \cdot y}, 1\right) \]
                                  4. lower-*.f6457.4

                                    \[\leadsto \mathsf{fma}\left(x, \color{blue}{y \cdot y}, 1\right) \]
                                5. Applied rewrites57.4%

                                  \[\leadsto \color{blue}{\mathsf{fma}\left(x, y \cdot y, 1\right)} \]
                                6. Step-by-step derivation
                                  1. Applied rewrites57.4%

                                    \[\leadsto \mathsf{fma}\left(x \cdot y, \color{blue}{y}, 1\right) \]

                                  if 2e15 < (*.f64 (*.f64 x y) y) < 1.00000000000000002e144

                                  1. Initial program 100.0%

                                    \[e^{\left(x \cdot y\right) \cdot y} \]
                                  2. Add Preprocessing
                                  3. Applied rewrites51.1%

                                    \[\leadsto e^{\color{blue}{x} \cdot y} \]
                                  4. Taylor expanded in x around 0

                                    \[\leadsto \color{blue}{1 + x \cdot y} \]
                                  5. Step-by-step derivation
                                    1. +-commutativeN/A

                                      \[\leadsto \color{blue}{x \cdot y + 1} \]
                                    2. lower-fma.f642.9

                                      \[\leadsto \color{blue}{\mathsf{fma}\left(x, y, 1\right)} \]
                                  6. Applied rewrites2.9%

                                    \[\leadsto \color{blue}{\mathsf{fma}\left(x, y, 1\right)} \]
                                  7. Taylor expanded in x around 0

                                    \[\leadsto \color{blue}{1 + x \cdot \left(y + x \cdot \left(\frac{1}{6} \cdot \left(x \cdot {y}^{3}\right) + \frac{1}{2} \cdot {y}^{2}\right)\right)} \]
                                  8. Step-by-step derivation
                                    1. +-commutativeN/A

                                      \[\leadsto \color{blue}{x \cdot \left(y + x \cdot \left(\frac{1}{6} \cdot \left(x \cdot {y}^{3}\right) + \frac{1}{2} \cdot {y}^{2}\right)\right) + 1} \]
                                    2. lower-fma.f64N/A

                                      \[\leadsto \color{blue}{\mathsf{fma}\left(x, y + x \cdot \left(\frac{1}{6} \cdot \left(x \cdot {y}^{3}\right) + \frac{1}{2} \cdot {y}^{2}\right), 1\right)} \]
                                    3. +-commutativeN/A

                                      \[\leadsto \mathsf{fma}\left(x, \color{blue}{x \cdot \left(\frac{1}{6} \cdot \left(x \cdot {y}^{3}\right) + \frac{1}{2} \cdot {y}^{2}\right) + y}, 1\right) \]
                                    4. lower-fma.f64N/A

                                      \[\leadsto \mathsf{fma}\left(x, \color{blue}{\mathsf{fma}\left(x, \frac{1}{6} \cdot \left(x \cdot {y}^{3}\right) + \frac{1}{2} \cdot {y}^{2}, y\right)}, 1\right) \]
                                    5. associate-*r*N/A

                                      \[\leadsto \mathsf{fma}\left(x, \mathsf{fma}\left(x, \color{blue}{\left(\frac{1}{6} \cdot x\right) \cdot {y}^{3}} + \frac{1}{2} \cdot {y}^{2}, y\right), 1\right) \]
                                    6. cube-multN/A

                                      \[\leadsto \mathsf{fma}\left(x, \mathsf{fma}\left(x, \left(\frac{1}{6} \cdot x\right) \cdot \color{blue}{\left(y \cdot \left(y \cdot y\right)\right)} + \frac{1}{2} \cdot {y}^{2}, y\right), 1\right) \]
                                    7. unpow2N/A

                                      \[\leadsto \mathsf{fma}\left(x, \mathsf{fma}\left(x, \left(\frac{1}{6} \cdot x\right) \cdot \left(y \cdot \color{blue}{{y}^{2}}\right) + \frac{1}{2} \cdot {y}^{2}, y\right), 1\right) \]
                                    8. associate-*r*N/A

                                      \[\leadsto \mathsf{fma}\left(x, \mathsf{fma}\left(x, \color{blue}{\left(\left(\frac{1}{6} \cdot x\right) \cdot y\right) \cdot {y}^{2}} + \frac{1}{2} \cdot {y}^{2}, y\right), 1\right) \]
                                    9. distribute-rgt-outN/A

                                      \[\leadsto \mathsf{fma}\left(x, \mathsf{fma}\left(x, \color{blue}{{y}^{2} \cdot \left(\left(\frac{1}{6} \cdot x\right) \cdot y + \frac{1}{2}\right)}, y\right), 1\right) \]
                                    10. lower-*.f64N/A

                                      \[\leadsto \mathsf{fma}\left(x, \mathsf{fma}\left(x, \color{blue}{{y}^{2} \cdot \left(\left(\frac{1}{6} \cdot x\right) \cdot y + \frac{1}{2}\right)}, y\right), 1\right) \]
                                    11. unpow2N/A

                                      \[\leadsto \mathsf{fma}\left(x, \mathsf{fma}\left(x, \color{blue}{\left(y \cdot y\right)} \cdot \left(\left(\frac{1}{6} \cdot x\right) \cdot y + \frac{1}{2}\right), y\right), 1\right) \]
                                    12. lower-*.f64N/A

                                      \[\leadsto \mathsf{fma}\left(x, \mathsf{fma}\left(x, \color{blue}{\left(y \cdot y\right)} \cdot \left(\left(\frac{1}{6} \cdot x\right) \cdot y + \frac{1}{2}\right), y\right), 1\right) \]
                                    13. lower-fma.f64N/A

                                      \[\leadsto \mathsf{fma}\left(x, \mathsf{fma}\left(x, \left(y \cdot y\right) \cdot \color{blue}{\mathsf{fma}\left(\frac{1}{6} \cdot x, y, \frac{1}{2}\right)}, y\right), 1\right) \]
                                    14. *-commutativeN/A

                                      \[\leadsto \mathsf{fma}\left(x, \mathsf{fma}\left(x, \left(y \cdot y\right) \cdot \mathsf{fma}\left(\color{blue}{x \cdot \frac{1}{6}}, y, \frac{1}{2}\right), y\right), 1\right) \]
                                    15. lower-*.f6424.6

                                      \[\leadsto \mathsf{fma}\left(x, \mathsf{fma}\left(x, \left(y \cdot y\right) \cdot \mathsf{fma}\left(\color{blue}{x \cdot 0.16666666666666666}, y, 0.5\right), y\right), 1\right) \]
                                  9. Applied rewrites24.6%

                                    \[\leadsto \color{blue}{\mathsf{fma}\left(x, \mathsf{fma}\left(x, \left(y \cdot y\right) \cdot \mathsf{fma}\left(x \cdot 0.16666666666666666, y, 0.5\right), y\right), 1\right)} \]
                                  10. Taylor expanded in x around inf

                                    \[\leadsto \frac{1}{6} \cdot \color{blue}{\left({x}^{3} \cdot {y}^{3}\right)} \]
                                  11. Step-by-step derivation
                                    1. Applied rewrites36.6%

                                      \[\leadsto \left(y \cdot y\right) \cdot \color{blue}{\left(y \cdot \left(0.16666666666666666 \cdot \left(x \cdot \left(x \cdot x\right)\right)\right)\right)} \]

                                    if 1.00000000000000002e144 < (*.f64 (*.f64 x y) y)

                                    1. Initial program 100.0%

                                      \[e^{\left(x \cdot y\right) \cdot y} \]
                                    2. Add Preprocessing
                                    3. Applied rewrites52.8%

                                      \[\leadsto e^{\color{blue}{x} \cdot y} \]
                                    4. Taylor expanded in x around 0

                                      \[\leadsto \color{blue}{1 + x \cdot \left(y + \frac{1}{2} \cdot \left(x \cdot {y}^{2}\right)\right)} \]
                                    5. Step-by-step derivation
                                      1. +-commutativeN/A

                                        \[\leadsto \color{blue}{x \cdot \left(y + \frac{1}{2} \cdot \left(x \cdot {y}^{2}\right)\right) + 1} \]
                                      2. +-commutativeN/A

                                        \[\leadsto x \cdot \color{blue}{\left(\frac{1}{2} \cdot \left(x \cdot {y}^{2}\right) + y\right)} + 1 \]
                                      3. *-commutativeN/A

                                        \[\leadsto x \cdot \left(\frac{1}{2} \cdot \color{blue}{\left({y}^{2} \cdot x\right)} + y\right) + 1 \]
                                      4. associate-*r*N/A

                                        \[\leadsto x \cdot \left(\color{blue}{\left(\frac{1}{2} \cdot {y}^{2}\right) \cdot x} + y\right) + 1 \]
                                      5. lower-fma.f64N/A

                                        \[\leadsto \color{blue}{\mathsf{fma}\left(x, \left(\frac{1}{2} \cdot {y}^{2}\right) \cdot x + y, 1\right)} \]
                                      6. *-commutativeN/A

                                        \[\leadsto \mathsf{fma}\left(x, \color{blue}{x \cdot \left(\frac{1}{2} \cdot {y}^{2}\right)} + y, 1\right) \]
                                      7. lower-fma.f64N/A

                                        \[\leadsto \mathsf{fma}\left(x, \color{blue}{\mathsf{fma}\left(x, \frac{1}{2} \cdot {y}^{2}, y\right)}, 1\right) \]
                                      8. lower-*.f64N/A

                                        \[\leadsto \mathsf{fma}\left(x, \mathsf{fma}\left(x, \color{blue}{\frac{1}{2} \cdot {y}^{2}}, y\right), 1\right) \]
                                      9. unpow2N/A

                                        \[\leadsto \mathsf{fma}\left(x, \mathsf{fma}\left(x, \frac{1}{2} \cdot \color{blue}{\left(y \cdot y\right)}, y\right), 1\right) \]
                                      10. lower-*.f6494.4

                                        \[\leadsto \mathsf{fma}\left(x, \mathsf{fma}\left(x, 0.5 \cdot \color{blue}{\left(y \cdot y\right)}, y\right), 1\right) \]
                                    6. Applied rewrites94.4%

                                      \[\leadsto \color{blue}{\mathsf{fma}\left(x, \mathsf{fma}\left(x, 0.5 \cdot \left(y \cdot y\right), y\right), 1\right)} \]
                                  12. Recombined 3 regimes into one program.
                                  13. Final simplification63.5%

                                    \[\leadsto \begin{array}{l} \mathbf{if}\;y \cdot \left(x \cdot y\right) \leq 2 \cdot 10^{+15}:\\ \;\;\;\;\mathsf{fma}\left(x \cdot y, y, 1\right)\\ \mathbf{elif}\;y \cdot \left(x \cdot y\right) \leq 10^{+144}:\\ \;\;\;\;\left(y \cdot y\right) \cdot \left(y \cdot \left(0.16666666666666666 \cdot \left(x \cdot \left(x \cdot x\right)\right)\right)\right)\\ \mathbf{else}:\\ \;\;\;\;\mathsf{fma}\left(x, \mathsf{fma}\left(x, \left(y \cdot y\right) \cdot 0.5, y\right), 1\right)\\ \end{array} \]
                                  14. Add Preprocessing

                                  Alternative 8: 71.8% accurate, 1.8× speedup?

                                  \[\begin{array}{l} \\ \begin{array}{l} t_0 := x \cdot \left(y \cdot y\right)\\ \mathbf{if}\;y \cdot \left(x \cdot y\right) \leq 2 \cdot 10^{+15}:\\ \;\;\;\;\mathsf{fma}\left(y \cdot y, \mathsf{fma}\left(x, 0.5 \cdot t\_0, x\right), 1\right)\\ \mathbf{else}:\\ \;\;\;\;\mathsf{fma}\left(y \cdot y, \left(y \cdot y\right) \cdot \left(0.16666666666666666 \cdot \left(x \cdot \left(x \cdot t\_0\right)\right)\right), 1\right)\\ \end{array} \end{array} \]
                                  (FPCore (x y)
                                   :precision binary64
                                   (let* ((t_0 (* x (* y y))))
                                     (if (<= (* y (* x y)) 2e+15)
                                       (fma (* y y) (fma x (* 0.5 t_0) x) 1.0)
                                       (fma (* y y) (* (* y y) (* 0.16666666666666666 (* x (* x t_0)))) 1.0))))
                                  double code(double x, double y) {
                                  	double t_0 = x * (y * y);
                                  	double tmp;
                                  	if ((y * (x * y)) <= 2e+15) {
                                  		tmp = fma((y * y), fma(x, (0.5 * t_0), x), 1.0);
                                  	} else {
                                  		tmp = fma((y * y), ((y * y) * (0.16666666666666666 * (x * (x * t_0)))), 1.0);
                                  	}
                                  	return tmp;
                                  }
                                  
                                  function code(x, y)
                                  	t_0 = Float64(x * Float64(y * y))
                                  	tmp = 0.0
                                  	if (Float64(y * Float64(x * y)) <= 2e+15)
                                  		tmp = fma(Float64(y * y), fma(x, Float64(0.5 * t_0), x), 1.0);
                                  	else
                                  		tmp = fma(Float64(y * y), Float64(Float64(y * y) * Float64(0.16666666666666666 * Float64(x * Float64(x * t_0)))), 1.0);
                                  	end
                                  	return tmp
                                  end
                                  
                                  code[x_, y_] := Block[{t$95$0 = N[(x * N[(y * y), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[N[(y * N[(x * y), $MachinePrecision]), $MachinePrecision], 2e+15], N[(N[(y * y), $MachinePrecision] * N[(x * N[(0.5 * t$95$0), $MachinePrecision] + x), $MachinePrecision] + 1.0), $MachinePrecision], N[(N[(y * y), $MachinePrecision] * N[(N[(y * y), $MachinePrecision] * N[(0.16666666666666666 * N[(x * N[(x * t$95$0), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] + 1.0), $MachinePrecision]]]
                                  
                                  \begin{array}{l}
                                  
                                  \\
                                  \begin{array}{l}
                                  t_0 := x \cdot \left(y \cdot y\right)\\
                                  \mathbf{if}\;y \cdot \left(x \cdot y\right) \leq 2 \cdot 10^{+15}:\\
                                  \;\;\;\;\mathsf{fma}\left(y \cdot y, \mathsf{fma}\left(x, 0.5 \cdot t\_0, x\right), 1\right)\\
                                  
                                  \mathbf{else}:\\
                                  \;\;\;\;\mathsf{fma}\left(y \cdot y, \left(y \cdot y\right) \cdot \left(0.16666666666666666 \cdot \left(x \cdot \left(x \cdot t\_0\right)\right)\right), 1\right)\\
                                  
                                  
                                  \end{array}
                                  \end{array}
                                  
                                  Derivation
                                  1. Split input into 2 regimes
                                  2. if (*.f64 (*.f64 x y) y) < 2e15

                                    1. Initial program 100.0%

                                      \[e^{\left(x \cdot y\right) \cdot y} \]
                                    2. Add Preprocessing
                                    3. Taylor expanded in x around 0

                                      \[\leadsto \color{blue}{1 + x \cdot \left(\frac{1}{2} \cdot \left(x \cdot {y}^{4}\right) + {y}^{2}\right)} \]
                                    4. Step-by-step derivation
                                      1. +-commutativeN/A

                                        \[\leadsto \color{blue}{x \cdot \left(\frac{1}{2} \cdot \left(x \cdot {y}^{4}\right) + {y}^{2}\right) + 1} \]
                                    5. Applied rewrites57.6%

                                      \[\leadsto \color{blue}{\mathsf{fma}\left(y \cdot y, \mathsf{fma}\left(x, \left(x \cdot \left(y \cdot y\right)\right) \cdot 0.5, x\right), 1\right)} \]

                                    if 2e15 < (*.f64 (*.f64 x y) y)

                                    1. Initial program 100.0%

                                      \[e^{\left(x \cdot y\right) \cdot y} \]
                                    2. Add Preprocessing
                                    3. Taylor expanded in x around 0

                                      \[\leadsto \color{blue}{1 + x \cdot \left(x \cdot \left(\frac{1}{6} \cdot \left(x \cdot {y}^{6}\right) + \frac{1}{2} \cdot {y}^{4}\right) + {y}^{2}\right)} \]
                                    4. Applied rewrites86.6%

                                      \[\leadsto \color{blue}{\mathsf{fma}\left(y \cdot y, \mathsf{fma}\left(x \cdot \left(x \cdot \left(y \cdot y\right)\right), \mathsf{fma}\left(x, \left(y \cdot y\right) \cdot 0.16666666666666666, 0.5\right), x\right), 1\right)} \]
                                    5. Taylor expanded in x around inf

                                      \[\leadsto \mathsf{fma}\left(y \cdot y, \frac{1}{6} \cdot \color{blue}{\left({x}^{3} \cdot {y}^{4}\right)}, 1\right) \]
                                    6. Step-by-step derivation
                                      1. Applied rewrites91.1%

                                        \[\leadsto \mathsf{fma}\left(y \cdot y, \left(y \cdot y\right) \cdot \color{blue}{\left(0.16666666666666666 \cdot \left(x \cdot \left(x \cdot \left(x \cdot \left(y \cdot y\right)\right)\right)\right)\right)}, 1\right) \]
                                    7. Recombined 2 regimes into one program.
                                    8. Final simplification66.0%

                                      \[\leadsto \begin{array}{l} \mathbf{if}\;y \cdot \left(x \cdot y\right) \leq 2 \cdot 10^{+15}:\\ \;\;\;\;\mathsf{fma}\left(y \cdot y, \mathsf{fma}\left(x, 0.5 \cdot \left(x \cdot \left(y \cdot y\right)\right), x\right), 1\right)\\ \mathbf{else}:\\ \;\;\;\;\mathsf{fma}\left(y \cdot y, \left(y \cdot y\right) \cdot \left(0.16666666666666666 \cdot \left(x \cdot \left(x \cdot \left(x \cdot \left(y \cdot y\right)\right)\right)\right)\right), 1\right)\\ \end{array} \]
                                    9. Add Preprocessing

                                    Alternative 9: 71.6% accurate, 1.9× speedup?

                                    \[\begin{array}{l} \\ \mathsf{fma}\left(x, \left(y \cdot y\right) \cdot \left(\left(x \cdot y\right) \cdot \left(y \cdot \mathsf{fma}\left(x, \left(y \cdot y\right) \cdot 0.16666666666666666, 0.5\right)\right)\right), \mathsf{fma}\left(x \cdot y, y, 1\right)\right) \end{array} \]
                                    (FPCore (x y)
                                     :precision binary64
                                     (fma
                                      x
                                      (* (* y y) (* (* x y) (* y (fma x (* (* y y) 0.16666666666666666) 0.5))))
                                      (fma (* x y) y 1.0)))
                                    double code(double x, double y) {
                                    	return fma(x, ((y * y) * ((x * y) * (y * fma(x, ((y * y) * 0.16666666666666666), 0.5)))), fma((x * y), y, 1.0));
                                    }
                                    
                                    function code(x, y)
                                    	return fma(x, Float64(Float64(y * y) * Float64(Float64(x * y) * Float64(y * fma(x, Float64(Float64(y * y) * 0.16666666666666666), 0.5)))), fma(Float64(x * y), y, 1.0))
                                    end
                                    
                                    code[x_, y_] := N[(x * N[(N[(y * y), $MachinePrecision] * N[(N[(x * y), $MachinePrecision] * N[(y * N[(x * N[(N[(y * y), $MachinePrecision] * 0.16666666666666666), $MachinePrecision] + 0.5), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] + N[(N[(x * y), $MachinePrecision] * y + 1.0), $MachinePrecision]), $MachinePrecision]
                                    
                                    \begin{array}{l}
                                    
                                    \\
                                    \mathsf{fma}\left(x, \left(y \cdot y\right) \cdot \left(\left(x \cdot y\right) \cdot \left(y \cdot \mathsf{fma}\left(x, \left(y \cdot y\right) \cdot 0.16666666666666666, 0.5\right)\right)\right), \mathsf{fma}\left(x \cdot y, y, 1\right)\right)
                                    \end{array}
                                    
                                    Derivation
                                    1. Initial program 100.0%

                                      \[e^{\left(x \cdot y\right) \cdot y} \]
                                    2. Add Preprocessing
                                    3. Taylor expanded in x around 0

                                      \[\leadsto \color{blue}{1 + x \cdot \left(x \cdot \left(\frac{1}{6} \cdot \left(x \cdot {y}^{6}\right) + \frac{1}{2} \cdot {y}^{4}\right) + {y}^{2}\right)} \]
                                    4. Applied rewrites65.0%

                                      \[\leadsto \color{blue}{\mathsf{fma}\left(y \cdot y, \mathsf{fma}\left(x \cdot \left(x \cdot \left(y \cdot y\right)\right), \mathsf{fma}\left(x, \left(y \cdot y\right) \cdot 0.16666666666666666, 0.5\right), x\right), 1\right)} \]
                                    5. Step-by-step derivation
                                      1. Applied rewrites65.0%

                                        \[\leadsto \mathsf{fma}\left(x, \color{blue}{\left(\left(x \cdot y\right) \cdot \left(y \cdot \mathsf{fma}\left(x, \left(y \cdot y\right) \cdot 0.16666666666666666, 0.5\right)\right)\right) \cdot \left(y \cdot y\right)}, \mathsf{fma}\left(x, y \cdot y, 1\right)\right) \]
                                      2. Step-by-step derivation
                                        1. Applied rewrites65.0%

                                          \[\leadsto \mathsf{fma}\left(x, \left(\left(x \cdot y\right) \cdot \left(y \cdot \mathsf{fma}\left(x, \left(y \cdot y\right) \cdot 0.16666666666666666, 0.5\right)\right)\right) \cdot \left(y \cdot y\right), \mathsf{fma}\left(x \cdot y, y, 1\right)\right) \]
                                        2. Final simplification65.0%

                                          \[\leadsto \mathsf{fma}\left(x, \left(y \cdot y\right) \cdot \left(\left(x \cdot y\right) \cdot \left(y \cdot \mathsf{fma}\left(x, \left(y \cdot y\right) \cdot 0.16666666666666666, 0.5\right)\right)\right), \mathsf{fma}\left(x \cdot y, y, 1\right)\right) \]
                                        3. Add Preprocessing

                                        Alternative 10: 71.6% accurate, 1.9× speedup?

                                        \[\begin{array}{l} \\ \mathsf{fma}\left(x, \left(y \cdot y\right) \cdot \left(\left(x \cdot y\right) \cdot \left(y \cdot \mathsf{fma}\left(x, \left(y \cdot y\right) \cdot 0.16666666666666666, 0.5\right)\right)\right), \mathsf{fma}\left(x, y \cdot y, 1\right)\right) \end{array} \]
                                        (FPCore (x y)
                                         :precision binary64
                                         (fma
                                          x
                                          (* (* y y) (* (* x y) (* y (fma x (* (* y y) 0.16666666666666666) 0.5))))
                                          (fma x (* y y) 1.0)))
                                        double code(double x, double y) {
                                        	return fma(x, ((y * y) * ((x * y) * (y * fma(x, ((y * y) * 0.16666666666666666), 0.5)))), fma(x, (y * y), 1.0));
                                        }
                                        
                                        function code(x, y)
                                        	return fma(x, Float64(Float64(y * y) * Float64(Float64(x * y) * Float64(y * fma(x, Float64(Float64(y * y) * 0.16666666666666666), 0.5)))), fma(x, Float64(y * y), 1.0))
                                        end
                                        
                                        code[x_, y_] := N[(x * N[(N[(y * y), $MachinePrecision] * N[(N[(x * y), $MachinePrecision] * N[(y * N[(x * N[(N[(y * y), $MachinePrecision] * 0.16666666666666666), $MachinePrecision] + 0.5), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] + N[(x * N[(y * y), $MachinePrecision] + 1.0), $MachinePrecision]), $MachinePrecision]
                                        
                                        \begin{array}{l}
                                        
                                        \\
                                        \mathsf{fma}\left(x, \left(y \cdot y\right) \cdot \left(\left(x \cdot y\right) \cdot \left(y \cdot \mathsf{fma}\left(x, \left(y \cdot y\right) \cdot 0.16666666666666666, 0.5\right)\right)\right), \mathsf{fma}\left(x, y \cdot y, 1\right)\right)
                                        \end{array}
                                        
                                        Derivation
                                        1. Initial program 100.0%

                                          \[e^{\left(x \cdot y\right) \cdot y} \]
                                        2. Add Preprocessing
                                        3. Taylor expanded in x around 0

                                          \[\leadsto \color{blue}{1 + x \cdot \left(x \cdot \left(\frac{1}{6} \cdot \left(x \cdot {y}^{6}\right) + \frac{1}{2} \cdot {y}^{4}\right) + {y}^{2}\right)} \]
                                        4. Applied rewrites65.0%

                                          \[\leadsto \color{blue}{\mathsf{fma}\left(y \cdot y, \mathsf{fma}\left(x \cdot \left(x \cdot \left(y \cdot y\right)\right), \mathsf{fma}\left(x, \left(y \cdot y\right) \cdot 0.16666666666666666, 0.5\right), x\right), 1\right)} \]
                                        5. Step-by-step derivation
                                          1. Applied rewrites65.0%

                                            \[\leadsto \mathsf{fma}\left(x, \color{blue}{\left(\left(x \cdot y\right) \cdot \left(y \cdot \mathsf{fma}\left(x, \left(y \cdot y\right) \cdot 0.16666666666666666, 0.5\right)\right)\right) \cdot \left(y \cdot y\right)}, \mathsf{fma}\left(x, y \cdot y, 1\right)\right) \]
                                          2. Final simplification65.0%

                                            \[\leadsto \mathsf{fma}\left(x, \left(y \cdot y\right) \cdot \left(\left(x \cdot y\right) \cdot \left(y \cdot \mathsf{fma}\left(x, \left(y \cdot y\right) \cdot 0.16666666666666666, 0.5\right)\right)\right), \mathsf{fma}\left(x, y \cdot y, 1\right)\right) \]
                                          3. Add Preprocessing

                                          Alternative 11: 71.4% accurate, 2.3× speedup?

                                          \[\begin{array}{l} \\ \mathsf{fma}\left(y \cdot \mathsf{fma}\left(x \cdot \left(y \cdot y\right), x \cdot \mathsf{fma}\left(x, \left(y \cdot y\right) \cdot 0.16666666666666666, 0.5\right), x\right), y, 1\right) \end{array} \]
                                          (FPCore (x y)
                                           :precision binary64
                                           (fma
                                            (* y (fma (* x (* y y)) (* x (fma x (* (* y y) 0.16666666666666666) 0.5)) x))
                                            y
                                            1.0))
                                          double code(double x, double y) {
                                          	return fma((y * fma((x * (y * y)), (x * fma(x, ((y * y) * 0.16666666666666666), 0.5)), x)), y, 1.0);
                                          }
                                          
                                          function code(x, y)
                                          	return fma(Float64(y * fma(Float64(x * Float64(y * y)), Float64(x * fma(x, Float64(Float64(y * y) * 0.16666666666666666), 0.5)), x)), y, 1.0)
                                          end
                                          
                                          code[x_, y_] := N[(N[(y * N[(N[(x * N[(y * y), $MachinePrecision]), $MachinePrecision] * N[(x * N[(x * N[(N[(y * y), $MachinePrecision] * 0.16666666666666666), $MachinePrecision] + 0.5), $MachinePrecision]), $MachinePrecision] + x), $MachinePrecision]), $MachinePrecision] * y + 1.0), $MachinePrecision]
                                          
                                          \begin{array}{l}
                                          
                                          \\
                                          \mathsf{fma}\left(y \cdot \mathsf{fma}\left(x \cdot \left(y \cdot y\right), x \cdot \mathsf{fma}\left(x, \left(y \cdot y\right) \cdot 0.16666666666666666, 0.5\right), x\right), y, 1\right)
                                          \end{array}
                                          
                                          Derivation
                                          1. Initial program 100.0%

                                            \[e^{\left(x \cdot y\right) \cdot y} \]
                                          2. Add Preprocessing
                                          3. Taylor expanded in x around 0

                                            \[\leadsto \color{blue}{1 + x \cdot \left(x \cdot \left(\frac{1}{6} \cdot \left(x \cdot {y}^{6}\right) + \frac{1}{2} \cdot {y}^{4}\right) + {y}^{2}\right)} \]
                                          4. Applied rewrites65.0%

                                            \[\leadsto \color{blue}{\mathsf{fma}\left(y \cdot y, \mathsf{fma}\left(x \cdot \left(x \cdot \left(y \cdot y\right)\right), \mathsf{fma}\left(x, \left(y \cdot y\right) \cdot 0.16666666666666666, 0.5\right), x\right), 1\right)} \]
                                          5. Step-by-step derivation
                                            1. Applied rewrites65.0%

                                              \[\leadsto \mathsf{fma}\left(y \cdot \mathsf{fma}\left(x \cdot \left(y \cdot y\right), x \cdot \mathsf{fma}\left(x, \left(y \cdot y\right) \cdot 0.16666666666666666, 0.5\right), x\right), \color{blue}{y}, 1\right) \]
                                            2. Add Preprocessing

                                            Alternative 12: 71.4% accurate, 2.3× speedup?

                                            \[\begin{array}{l} \\ \mathsf{fma}\left(y \cdot y, \mathsf{fma}\left(x \cdot \left(x \cdot \left(y \cdot y\right)\right), \mathsf{fma}\left(x, \left(y \cdot y\right) \cdot 0.16666666666666666, 0.5\right), x\right), 1\right) \end{array} \]
                                            (FPCore (x y)
                                             :precision binary64
                                             (fma
                                              (* y y)
                                              (fma (* x (* x (* y y))) (fma x (* (* y y) 0.16666666666666666) 0.5) x)
                                              1.0))
                                            double code(double x, double y) {
                                            	return fma((y * y), fma((x * (x * (y * y))), fma(x, ((y * y) * 0.16666666666666666), 0.5), x), 1.0);
                                            }
                                            
                                            function code(x, y)
                                            	return fma(Float64(y * y), fma(Float64(x * Float64(x * Float64(y * y))), fma(x, Float64(Float64(y * y) * 0.16666666666666666), 0.5), x), 1.0)
                                            end
                                            
                                            code[x_, y_] := N[(N[(y * y), $MachinePrecision] * N[(N[(x * N[(x * N[(y * y), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] * N[(x * N[(N[(y * y), $MachinePrecision] * 0.16666666666666666), $MachinePrecision] + 0.5), $MachinePrecision] + x), $MachinePrecision] + 1.0), $MachinePrecision]
                                            
                                            \begin{array}{l}
                                            
                                            \\
                                            \mathsf{fma}\left(y \cdot y, \mathsf{fma}\left(x \cdot \left(x \cdot \left(y \cdot y\right)\right), \mathsf{fma}\left(x, \left(y \cdot y\right) \cdot 0.16666666666666666, 0.5\right), x\right), 1\right)
                                            \end{array}
                                            
                                            Derivation
                                            1. Initial program 100.0%

                                              \[e^{\left(x \cdot y\right) \cdot y} \]
                                            2. Add Preprocessing
                                            3. Taylor expanded in x around 0

                                              \[\leadsto \color{blue}{1 + x \cdot \left(x \cdot \left(\frac{1}{6} \cdot \left(x \cdot {y}^{6}\right) + \frac{1}{2} \cdot {y}^{4}\right) + {y}^{2}\right)} \]
                                            4. Applied rewrites65.0%

                                              \[\leadsto \color{blue}{\mathsf{fma}\left(y \cdot y, \mathsf{fma}\left(x \cdot \left(x \cdot \left(y \cdot y\right)\right), \mathsf{fma}\left(x, \left(y \cdot y\right) \cdot 0.16666666666666666, 0.5\right), x\right), 1\right)} \]
                                            5. Add Preprocessing

                                            Alternative 13: 71.3% accurate, 2.3× speedup?

                                            \[\begin{array}{l} \\ \mathsf{fma}\left(y \cdot y, \mathsf{fma}\left(x \cdot \left(x \cdot \left(y \cdot y\right)\right), x \cdot \left(\left(y \cdot y\right) \cdot 0.16666666666666666\right), x\right), 1\right) \end{array} \]
                                            (FPCore (x y)
                                             :precision binary64
                                             (fma
                                              (* y y)
                                              (fma (* x (* x (* y y))) (* x (* (* y y) 0.16666666666666666)) x)
                                              1.0))
                                            double code(double x, double y) {
                                            	return fma((y * y), fma((x * (x * (y * y))), (x * ((y * y) * 0.16666666666666666)), x), 1.0);
                                            }
                                            
                                            function code(x, y)
                                            	return fma(Float64(y * y), fma(Float64(x * Float64(x * Float64(y * y))), Float64(x * Float64(Float64(y * y) * 0.16666666666666666)), x), 1.0)
                                            end
                                            
                                            code[x_, y_] := N[(N[(y * y), $MachinePrecision] * N[(N[(x * N[(x * N[(y * y), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] * N[(x * N[(N[(y * y), $MachinePrecision] * 0.16666666666666666), $MachinePrecision]), $MachinePrecision] + x), $MachinePrecision] + 1.0), $MachinePrecision]
                                            
                                            \begin{array}{l}
                                            
                                            \\
                                            \mathsf{fma}\left(y \cdot y, \mathsf{fma}\left(x \cdot \left(x \cdot \left(y \cdot y\right)\right), x \cdot \left(\left(y \cdot y\right) \cdot 0.16666666666666666\right), x\right), 1\right)
                                            \end{array}
                                            
                                            Derivation
                                            1. Initial program 100.0%

                                              \[e^{\left(x \cdot y\right) \cdot y} \]
                                            2. Add Preprocessing
                                            3. Taylor expanded in x around 0

                                              \[\leadsto \color{blue}{1 + x \cdot \left(x \cdot \left(\frac{1}{6} \cdot \left(x \cdot {y}^{6}\right) + \frac{1}{2} \cdot {y}^{4}\right) + {y}^{2}\right)} \]
                                            4. Applied rewrites65.0%

                                              \[\leadsto \color{blue}{\mathsf{fma}\left(y \cdot y, \mathsf{fma}\left(x \cdot \left(x \cdot \left(y \cdot y\right)\right), \mathsf{fma}\left(x, \left(y \cdot y\right) \cdot 0.16666666666666666, 0.5\right), x\right), 1\right)} \]
                                            5. Taylor expanded in x around inf

                                              \[\leadsto \mathsf{fma}\left(y \cdot y, \mathsf{fma}\left(x \cdot \left(x \cdot \left(y \cdot y\right)\right), \frac{1}{6} \cdot \color{blue}{\left(x \cdot {y}^{2}\right)}, x\right), 1\right) \]
                                            6. Step-by-step derivation
                                              1. Applied rewrites64.6%

                                                \[\leadsto \mathsf{fma}\left(y \cdot y, \mathsf{fma}\left(x \cdot \left(x \cdot \left(y \cdot y\right)\right), x \cdot \color{blue}{\left(\left(y \cdot y\right) \cdot 0.16666666666666666\right)}, x\right), 1\right) \]
                                              2. Add Preprocessing

                                              Alternative 14: 68.4% accurate, 2.8× speedup?

                                              \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;y \cdot \left(x \cdot y\right) \leq 2 \cdot 10^{+15}:\\ \;\;\;\;\mathsf{fma}\left(x \cdot y, y, 1\right)\\ \mathbf{else}:\\ \;\;\;\;\mathsf{fma}\left(x, \mathsf{fma}\left(x, \left(y \cdot y\right) \cdot 0.5, y\right), 1\right)\\ \end{array} \end{array} \]
                                              (FPCore (x y)
                                               :precision binary64
                                               (if (<= (* y (* x y)) 2e+15)
                                                 (fma (* x y) y 1.0)
                                                 (fma x (fma x (* (* y y) 0.5) y) 1.0)))
                                              double code(double x, double y) {
                                              	double tmp;
                                              	if ((y * (x * y)) <= 2e+15) {
                                              		tmp = fma((x * y), y, 1.0);
                                              	} else {
                                              		tmp = fma(x, fma(x, ((y * y) * 0.5), y), 1.0);
                                              	}
                                              	return tmp;
                                              }
                                              
                                              function code(x, y)
                                              	tmp = 0.0
                                              	if (Float64(y * Float64(x * y)) <= 2e+15)
                                              		tmp = fma(Float64(x * y), y, 1.0);
                                              	else
                                              		tmp = fma(x, fma(x, Float64(Float64(y * y) * 0.5), y), 1.0);
                                              	end
                                              	return tmp
                                              end
                                              
                                              code[x_, y_] := If[LessEqual[N[(y * N[(x * y), $MachinePrecision]), $MachinePrecision], 2e+15], N[(N[(x * y), $MachinePrecision] * y + 1.0), $MachinePrecision], N[(x * N[(x * N[(N[(y * y), $MachinePrecision] * 0.5), $MachinePrecision] + y), $MachinePrecision] + 1.0), $MachinePrecision]]
                                              
                                              \begin{array}{l}
                                              
                                              \\
                                              \begin{array}{l}
                                              \mathbf{if}\;y \cdot \left(x \cdot y\right) \leq 2 \cdot 10^{+15}:\\
                                              \;\;\;\;\mathsf{fma}\left(x \cdot y, y, 1\right)\\
                                              
                                              \mathbf{else}:\\
                                              \;\;\;\;\mathsf{fma}\left(x, \mathsf{fma}\left(x, \left(y \cdot y\right) \cdot 0.5, y\right), 1\right)\\
                                              
                                              
                                              \end{array}
                                              \end{array}
                                              
                                              Derivation
                                              1. Split input into 2 regimes
                                              2. if (*.f64 (*.f64 x y) y) < 2e15

                                                1. Initial program 100.0%

                                                  \[e^{\left(x \cdot y\right) \cdot y} \]
                                                2. Add Preprocessing
                                                3. Taylor expanded in x around 0

                                                  \[\leadsto \color{blue}{1 + x \cdot {y}^{2}} \]
                                                4. Step-by-step derivation
                                                  1. +-commutativeN/A

                                                    \[\leadsto \color{blue}{x \cdot {y}^{2} + 1} \]
                                                  2. lower-fma.f64N/A

                                                    \[\leadsto \color{blue}{\mathsf{fma}\left(x, {y}^{2}, 1\right)} \]
                                                  3. unpow2N/A

                                                    \[\leadsto \mathsf{fma}\left(x, \color{blue}{y \cdot y}, 1\right) \]
                                                  4. lower-*.f6457.4

                                                    \[\leadsto \mathsf{fma}\left(x, \color{blue}{y \cdot y}, 1\right) \]
                                                5. Applied rewrites57.4%

                                                  \[\leadsto \color{blue}{\mathsf{fma}\left(x, y \cdot y, 1\right)} \]
                                                6. Step-by-step derivation
                                                  1. Applied rewrites57.4%

                                                    \[\leadsto \mathsf{fma}\left(x \cdot y, \color{blue}{y}, 1\right) \]

                                                  if 2e15 < (*.f64 (*.f64 x y) y)

                                                  1. Initial program 100.0%

                                                    \[e^{\left(x \cdot y\right) \cdot y} \]
                                                  2. Add Preprocessing
                                                  3. Applied rewrites52.4%

                                                    \[\leadsto e^{\color{blue}{x} \cdot y} \]
                                                  4. Taylor expanded in x around 0

                                                    \[\leadsto \color{blue}{1 + x \cdot \left(y + \frac{1}{2} \cdot \left(x \cdot {y}^{2}\right)\right)} \]
                                                  5. Step-by-step derivation
                                                    1. +-commutativeN/A

                                                      \[\leadsto \color{blue}{x \cdot \left(y + \frac{1}{2} \cdot \left(x \cdot {y}^{2}\right)\right) + 1} \]
                                                    2. +-commutativeN/A

                                                      \[\leadsto x \cdot \color{blue}{\left(\frac{1}{2} \cdot \left(x \cdot {y}^{2}\right) + y\right)} + 1 \]
                                                    3. *-commutativeN/A

                                                      \[\leadsto x \cdot \left(\frac{1}{2} \cdot \color{blue}{\left({y}^{2} \cdot x\right)} + y\right) + 1 \]
                                                    4. associate-*r*N/A

                                                      \[\leadsto x \cdot \left(\color{blue}{\left(\frac{1}{2} \cdot {y}^{2}\right) \cdot x} + y\right) + 1 \]
                                                    5. lower-fma.f64N/A

                                                      \[\leadsto \color{blue}{\mathsf{fma}\left(x, \left(\frac{1}{2} \cdot {y}^{2}\right) \cdot x + y, 1\right)} \]
                                                    6. *-commutativeN/A

                                                      \[\leadsto \mathsf{fma}\left(x, \color{blue}{x \cdot \left(\frac{1}{2} \cdot {y}^{2}\right)} + y, 1\right) \]
                                                    7. lower-fma.f64N/A

                                                      \[\leadsto \mathsf{fma}\left(x, \color{blue}{\mathsf{fma}\left(x, \frac{1}{2} \cdot {y}^{2}, y\right)}, 1\right) \]
                                                    8. lower-*.f64N/A

                                                      \[\leadsto \mathsf{fma}\left(x, \mathsf{fma}\left(x, \color{blue}{\frac{1}{2} \cdot {y}^{2}}, y\right), 1\right) \]
                                                    9. unpow2N/A

                                                      \[\leadsto \mathsf{fma}\left(x, \mathsf{fma}\left(x, \frac{1}{2} \cdot \color{blue}{\left(y \cdot y\right)}, y\right), 1\right) \]
                                                    10. lower-*.f6477.8

                                                      \[\leadsto \mathsf{fma}\left(x, \mathsf{fma}\left(x, 0.5 \cdot \color{blue}{\left(y \cdot y\right)}, y\right), 1\right) \]
                                                  6. Applied rewrites77.8%

                                                    \[\leadsto \color{blue}{\mathsf{fma}\left(x, \mathsf{fma}\left(x, 0.5 \cdot \left(y \cdot y\right), y\right), 1\right)} \]
                                                7. Recombined 2 regimes into one program.
                                                8. Final simplification62.5%

                                                  \[\leadsto \begin{array}{l} \mathbf{if}\;y \cdot \left(x \cdot y\right) \leq 2 \cdot 10^{+15}:\\ \;\;\;\;\mathsf{fma}\left(x \cdot y, y, 1\right)\\ \mathbf{else}:\\ \;\;\;\;\mathsf{fma}\left(x, \mathsf{fma}\left(x, \left(y \cdot y\right) \cdot 0.5, y\right), 1\right)\\ \end{array} \]
                                                9. Add Preprocessing

                                                Alternative 15: 70.0% accurate, 3.4× speedup?

                                                \[\begin{array}{l} \\ \mathsf{fma}\left(y \cdot y, \mathsf{fma}\left(x, 0.5 \cdot \left(x \cdot \left(y \cdot y\right)\right), x\right), 1\right) \end{array} \]
                                                (FPCore (x y)
                                                 :precision binary64
                                                 (fma (* y y) (fma x (* 0.5 (* x (* y y))) x) 1.0))
                                                double code(double x, double y) {
                                                	return fma((y * y), fma(x, (0.5 * (x * (y * y))), x), 1.0);
                                                }
                                                
                                                function code(x, y)
                                                	return fma(Float64(y * y), fma(x, Float64(0.5 * Float64(x * Float64(y * y))), x), 1.0)
                                                end
                                                
                                                code[x_, y_] := N[(N[(y * y), $MachinePrecision] * N[(x * N[(0.5 * N[(x * N[(y * y), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] + x), $MachinePrecision] + 1.0), $MachinePrecision]
                                                
                                                \begin{array}{l}
                                                
                                                \\
                                                \mathsf{fma}\left(y \cdot y, \mathsf{fma}\left(x, 0.5 \cdot \left(x \cdot \left(y \cdot y\right)\right), x\right), 1\right)
                                                \end{array}
                                                
                                                Derivation
                                                1. Initial program 100.0%

                                                  \[e^{\left(x \cdot y\right) \cdot y} \]
                                                2. Add Preprocessing
                                                3. Taylor expanded in x around 0

                                                  \[\leadsto \color{blue}{1 + x \cdot \left(\frac{1}{2} \cdot \left(x \cdot {y}^{4}\right) + {y}^{2}\right)} \]
                                                4. Step-by-step derivation
                                                  1. +-commutativeN/A

                                                    \[\leadsto \color{blue}{x \cdot \left(\frac{1}{2} \cdot \left(x \cdot {y}^{4}\right) + {y}^{2}\right) + 1} \]
                                                5. Applied rewrites63.7%

                                                  \[\leadsto \color{blue}{\mathsf{fma}\left(y \cdot y, \mathsf{fma}\left(x, \left(x \cdot \left(y \cdot y\right)\right) \cdot 0.5, x\right), 1\right)} \]
                                                6. Final simplification63.7%

                                                  \[\leadsto \mathsf{fma}\left(y \cdot y, \mathsf{fma}\left(x, 0.5 \cdot \left(x \cdot \left(y \cdot y\right)\right), x\right), 1\right) \]
                                                7. Add Preprocessing

                                                Alternative 16: 65.9% accurate, 4.1× speedup?

                                                \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;y \cdot \left(x \cdot y\right) \leq 0.1:\\ \;\;\;\;1\\ \mathbf{else}:\\ \;\;\;\;x \cdot \left(y \cdot y\right)\\ \end{array} \end{array} \]
                                                (FPCore (x y)
                                                 :precision binary64
                                                 (if (<= (* y (* x y)) 0.1) 1.0 (* x (* y y))))
                                                double code(double x, double y) {
                                                	double tmp;
                                                	if ((y * (x * y)) <= 0.1) {
                                                		tmp = 1.0;
                                                	} else {
                                                		tmp = x * (y * y);
                                                	}
                                                	return tmp;
                                                }
                                                
                                                real(8) function code(x, y)
                                                    real(8), intent (in) :: x
                                                    real(8), intent (in) :: y
                                                    real(8) :: tmp
                                                    if ((y * (x * y)) <= 0.1d0) then
                                                        tmp = 1.0d0
                                                    else
                                                        tmp = x * (y * y)
                                                    end if
                                                    code = tmp
                                                end function
                                                
                                                public static double code(double x, double y) {
                                                	double tmp;
                                                	if ((y * (x * y)) <= 0.1) {
                                                		tmp = 1.0;
                                                	} else {
                                                		tmp = x * (y * y);
                                                	}
                                                	return tmp;
                                                }
                                                
                                                def code(x, y):
                                                	tmp = 0
                                                	if (y * (x * y)) <= 0.1:
                                                		tmp = 1.0
                                                	else:
                                                		tmp = x * (y * y)
                                                	return tmp
                                                
                                                function code(x, y)
                                                	tmp = 0.0
                                                	if (Float64(y * Float64(x * y)) <= 0.1)
                                                		tmp = 1.0;
                                                	else
                                                		tmp = Float64(x * Float64(y * y));
                                                	end
                                                	return tmp
                                                end
                                                
                                                function tmp_2 = code(x, y)
                                                	tmp = 0.0;
                                                	if ((y * (x * y)) <= 0.1)
                                                		tmp = 1.0;
                                                	else
                                                		tmp = x * (y * y);
                                                	end
                                                	tmp_2 = tmp;
                                                end
                                                
                                                code[x_, y_] := If[LessEqual[N[(y * N[(x * y), $MachinePrecision]), $MachinePrecision], 0.1], 1.0, N[(x * N[(y * y), $MachinePrecision]), $MachinePrecision]]
                                                
                                                \begin{array}{l}
                                                
                                                \\
                                                \begin{array}{l}
                                                \mathbf{if}\;y \cdot \left(x \cdot y\right) \leq 0.1:\\
                                                \;\;\;\;1\\
                                                
                                                \mathbf{else}:\\
                                                \;\;\;\;x \cdot \left(y \cdot y\right)\\
                                                
                                                
                                                \end{array}
                                                \end{array}
                                                
                                                Derivation
                                                1. Split input into 2 regimes
                                                2. if (*.f64 (*.f64 x y) y) < 0.10000000000000001

                                                  1. Initial program 100.0%

                                                    \[e^{\left(x \cdot y\right) \cdot y} \]
                                                  2. Add Preprocessing
                                                  3. Taylor expanded in x around 0

                                                    \[\leadsto \color{blue}{1} \]
                                                  4. Step-by-step derivation
                                                    1. Applied rewrites57.5%

                                                      \[\leadsto \color{blue}{1} \]

                                                    if 0.10000000000000001 < (*.f64 (*.f64 x y) y)

                                                    1. Initial program 100.0%

                                                      \[e^{\left(x \cdot y\right) \cdot y} \]
                                                    2. Add Preprocessing
                                                    3. Taylor expanded in x around 0

                                                      \[\leadsto \color{blue}{1 + x \cdot {y}^{2}} \]
                                                    4. Step-by-step derivation
                                                      1. +-commutativeN/A

                                                        \[\leadsto \color{blue}{x \cdot {y}^{2} + 1} \]
                                                      2. lower-fma.f64N/A

                                                        \[\leadsto \color{blue}{\mathsf{fma}\left(x, {y}^{2}, 1\right)} \]
                                                      3. unpow2N/A

                                                        \[\leadsto \mathsf{fma}\left(x, \color{blue}{y \cdot y}, 1\right) \]
                                                      4. lower-*.f6463.5

                                                        \[\leadsto \mathsf{fma}\left(x, \color{blue}{y \cdot y}, 1\right) \]
                                                    5. Applied rewrites63.5%

                                                      \[\leadsto \color{blue}{\mathsf{fma}\left(x, y \cdot y, 1\right)} \]
                                                    6. Taylor expanded in x around inf

                                                      \[\leadsto x \cdot \color{blue}{{y}^{2}} \]
                                                    7. Step-by-step derivation
                                                      1. Applied rewrites63.5%

                                                        \[\leadsto x \cdot \color{blue}{\left(y \cdot y\right)} \]
                                                    8. Recombined 2 regimes into one program.
                                                    9. Final simplification59.0%

                                                      \[\leadsto \begin{array}{l} \mathbf{if}\;y \cdot \left(x \cdot y\right) \leq 0.1:\\ \;\;\;\;1\\ \mathbf{else}:\\ \;\;\;\;x \cdot \left(y \cdot y\right)\\ \end{array} \]
                                                    10. Add Preprocessing

                                                    Alternative 17: 53.4% accurate, 4.8× speedup?

                                                    \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;y \cdot \left(x \cdot y\right) \leq 0.1:\\ \;\;\;\;1\\ \mathbf{else}:\\ \;\;\;\;\mathsf{fma}\left(x, y, 1\right)\\ \end{array} \end{array} \]
                                                    (FPCore (x y)
                                                     :precision binary64
                                                     (if (<= (* y (* x y)) 0.1) 1.0 (fma x y 1.0)))
                                                    double code(double x, double y) {
                                                    	double tmp;
                                                    	if ((y * (x * y)) <= 0.1) {
                                                    		tmp = 1.0;
                                                    	} else {
                                                    		tmp = fma(x, y, 1.0);
                                                    	}
                                                    	return tmp;
                                                    }
                                                    
                                                    function code(x, y)
                                                    	tmp = 0.0
                                                    	if (Float64(y * Float64(x * y)) <= 0.1)
                                                    		tmp = 1.0;
                                                    	else
                                                    		tmp = fma(x, y, 1.0);
                                                    	end
                                                    	return tmp
                                                    end
                                                    
                                                    code[x_, y_] := If[LessEqual[N[(y * N[(x * y), $MachinePrecision]), $MachinePrecision], 0.1], 1.0, N[(x * y + 1.0), $MachinePrecision]]
                                                    
                                                    \begin{array}{l}
                                                    
                                                    \\
                                                    \begin{array}{l}
                                                    \mathbf{if}\;y \cdot \left(x \cdot y\right) \leq 0.1:\\
                                                    \;\;\;\;1\\
                                                    
                                                    \mathbf{else}:\\
                                                    \;\;\;\;\mathsf{fma}\left(x, y, 1\right)\\
                                                    
                                                    
                                                    \end{array}
                                                    \end{array}
                                                    
                                                    Derivation
                                                    1. Split input into 2 regimes
                                                    2. if (*.f64 (*.f64 x y) y) < 0.10000000000000001

                                                      1. Initial program 100.0%

                                                        \[e^{\left(x \cdot y\right) \cdot y} \]
                                                      2. Add Preprocessing
                                                      3. Taylor expanded in x around 0

                                                        \[\leadsto \color{blue}{1} \]
                                                      4. Step-by-step derivation
                                                        1. Applied rewrites57.5%

                                                          \[\leadsto \color{blue}{1} \]

                                                        if 0.10000000000000001 < (*.f64 (*.f64 x y) y)

                                                        1. Initial program 100.0%

                                                          \[e^{\left(x \cdot y\right) \cdot y} \]
                                                        2. Add Preprocessing
                                                        3. Applied rewrites51.7%

                                                          \[\leadsto e^{\color{blue}{x} \cdot y} \]
                                                        4. Taylor expanded in x around 0

                                                          \[\leadsto \color{blue}{1 + x \cdot y} \]
                                                        5. Step-by-step derivation
                                                          1. +-commutativeN/A

                                                            \[\leadsto \color{blue}{x \cdot y + 1} \]
                                                          2. lower-fma.f6414.7

                                                            \[\leadsto \color{blue}{\mathsf{fma}\left(x, y, 1\right)} \]
                                                        6. Applied rewrites14.7%

                                                          \[\leadsto \color{blue}{\mathsf{fma}\left(x, y, 1\right)} \]
                                                      5. Recombined 2 regimes into one program.
                                                      6. Final simplification46.7%

                                                        \[\leadsto \begin{array}{l} \mathbf{if}\;y \cdot \left(x \cdot y\right) \leq 0.1:\\ \;\;\;\;1\\ \mathbf{else}:\\ \;\;\;\;\mathsf{fma}\left(x, y, 1\right)\\ \end{array} \]
                                                      7. Add Preprocessing

                                                      Alternative 18: 53.3% accurate, 5.0× speedup?

                                                      \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;y \cdot \left(x \cdot y\right) \leq 2 \cdot 10^{+15}:\\ \;\;\;\;1\\ \mathbf{else}:\\ \;\;\;\;x \cdot y\\ \end{array} \end{array} \]
                                                      (FPCore (x y) :precision binary64 (if (<= (* y (* x y)) 2e+15) 1.0 (* x y)))
                                                      double code(double x, double y) {
                                                      	double tmp;
                                                      	if ((y * (x * y)) <= 2e+15) {
                                                      		tmp = 1.0;
                                                      	} else {
                                                      		tmp = x * y;
                                                      	}
                                                      	return tmp;
                                                      }
                                                      
                                                      real(8) function code(x, y)
                                                          real(8), intent (in) :: x
                                                          real(8), intent (in) :: y
                                                          real(8) :: tmp
                                                          if ((y * (x * y)) <= 2d+15) then
                                                              tmp = 1.0d0
                                                          else
                                                              tmp = x * y
                                                          end if
                                                          code = tmp
                                                      end function
                                                      
                                                      public static double code(double x, double y) {
                                                      	double tmp;
                                                      	if ((y * (x * y)) <= 2e+15) {
                                                      		tmp = 1.0;
                                                      	} else {
                                                      		tmp = x * y;
                                                      	}
                                                      	return tmp;
                                                      }
                                                      
                                                      def code(x, y):
                                                      	tmp = 0
                                                      	if (y * (x * y)) <= 2e+15:
                                                      		tmp = 1.0
                                                      	else:
                                                      		tmp = x * y
                                                      	return tmp
                                                      
                                                      function code(x, y)
                                                      	tmp = 0.0
                                                      	if (Float64(y * Float64(x * y)) <= 2e+15)
                                                      		tmp = 1.0;
                                                      	else
                                                      		tmp = Float64(x * y);
                                                      	end
                                                      	return tmp
                                                      end
                                                      
                                                      function tmp_2 = code(x, y)
                                                      	tmp = 0.0;
                                                      	if ((y * (x * y)) <= 2e+15)
                                                      		tmp = 1.0;
                                                      	else
                                                      		tmp = x * y;
                                                      	end
                                                      	tmp_2 = tmp;
                                                      end
                                                      
                                                      code[x_, y_] := If[LessEqual[N[(y * N[(x * y), $MachinePrecision]), $MachinePrecision], 2e+15], 1.0, N[(x * y), $MachinePrecision]]
                                                      
                                                      \begin{array}{l}
                                                      
                                                      \\
                                                      \begin{array}{l}
                                                      \mathbf{if}\;y \cdot \left(x \cdot y\right) \leq 2 \cdot 10^{+15}:\\
                                                      \;\;\;\;1\\
                                                      
                                                      \mathbf{else}:\\
                                                      \;\;\;\;x \cdot y\\
                                                      
                                                      
                                                      \end{array}
                                                      \end{array}
                                                      
                                                      Derivation
                                                      1. Split input into 2 regimes
                                                      2. if (*.f64 (*.f64 x y) y) < 2e15

                                                        1. Initial program 100.0%

                                                          \[e^{\left(x \cdot y\right) \cdot y} \]
                                                        2. Add Preprocessing
                                                        3. Taylor expanded in x around 0

                                                          \[\leadsto \color{blue}{1} \]
                                                        4. Step-by-step derivation
                                                          1. Applied rewrites57.3%

                                                            \[\leadsto \color{blue}{1} \]

                                                          if 2e15 < (*.f64 (*.f64 x y) y)

                                                          1. Initial program 100.0%

                                                            \[e^{\left(x \cdot y\right) \cdot y} \]
                                                          2. Add Preprocessing
                                                          3. Applied rewrites52.4%

                                                            \[\leadsto e^{\color{blue}{x} \cdot y} \]
                                                          4. Taylor expanded in x around 0

                                                            \[\leadsto \color{blue}{1 + x \cdot y} \]
                                                          5. Step-by-step derivation
                                                            1. +-commutativeN/A

                                                              \[\leadsto \color{blue}{x \cdot y + 1} \]
                                                            2. lower-fma.f6414.9

                                                              \[\leadsto \color{blue}{\mathsf{fma}\left(x, y, 1\right)} \]
                                                          6. Applied rewrites14.9%

                                                            \[\leadsto \color{blue}{\mathsf{fma}\left(x, y, 1\right)} \]
                                                          7. Taylor expanded in x around inf

                                                            \[\leadsto x \cdot \color{blue}{y} \]
                                                          8. Step-by-step derivation
                                                            1. Applied rewrites14.7%

                                                              \[\leadsto x \cdot \color{blue}{y} \]
                                                          9. Recombined 2 regimes into one program.
                                                          10. Final simplification46.6%

                                                            \[\leadsto \begin{array}{l} \mathbf{if}\;y \cdot \left(x \cdot y\right) \leq 2 \cdot 10^{+15}:\\ \;\;\;\;1\\ \mathbf{else}:\\ \;\;\;\;x \cdot y\\ \end{array} \]
                                                          11. Add Preprocessing

                                                          Alternative 19: 65.8% accurate, 9.3× speedup?

                                                          \[\begin{array}{l} \\ \mathsf{fma}\left(x, y \cdot y, 1\right) \end{array} \]
                                                          (FPCore (x y) :precision binary64 (fma x (* y y) 1.0))
                                                          double code(double x, double y) {
                                                          	return fma(x, (y * y), 1.0);
                                                          }
                                                          
                                                          function code(x, y)
                                                          	return fma(x, Float64(y * y), 1.0)
                                                          end
                                                          
                                                          code[x_, y_] := N[(x * N[(y * y), $MachinePrecision] + 1.0), $MachinePrecision]
                                                          
                                                          \begin{array}{l}
                                                          
                                                          \\
                                                          \mathsf{fma}\left(x, y \cdot y, 1\right)
                                                          \end{array}
                                                          
                                                          Derivation
                                                          1. Initial program 100.0%

                                                            \[e^{\left(x \cdot y\right) \cdot y} \]
                                                          2. Add Preprocessing
                                                          3. Taylor expanded in x around 0

                                                            \[\leadsto \color{blue}{1 + x \cdot {y}^{2}} \]
                                                          4. Step-by-step derivation
                                                            1. +-commutativeN/A

                                                              \[\leadsto \color{blue}{x \cdot {y}^{2} + 1} \]
                                                            2. lower-fma.f64N/A

                                                              \[\leadsto \color{blue}{\mathsf{fma}\left(x, {y}^{2}, 1\right)} \]
                                                            3. unpow2N/A

                                                              \[\leadsto \mathsf{fma}\left(x, \color{blue}{y \cdot y}, 1\right) \]
                                                            4. lower-*.f6459.1

                                                              \[\leadsto \mathsf{fma}\left(x, \color{blue}{y \cdot y}, 1\right) \]
                                                          5. Applied rewrites59.1%

                                                            \[\leadsto \color{blue}{\mathsf{fma}\left(x, y \cdot y, 1\right)} \]
                                                          6. Add Preprocessing

                                                          Alternative 20: 50.6% accurate, 111.0× speedup?

                                                          \[\begin{array}{l} \\ 1 \end{array} \]
                                                          (FPCore (x y) :precision binary64 1.0)
                                                          double code(double x, double y) {
                                                          	return 1.0;
                                                          }
                                                          
                                                          real(8) function code(x, y)
                                                              real(8), intent (in) :: x
                                                              real(8), intent (in) :: y
                                                              code = 1.0d0
                                                          end function
                                                          
                                                          public static double code(double x, double y) {
                                                          	return 1.0;
                                                          }
                                                          
                                                          def code(x, y):
                                                          	return 1.0
                                                          
                                                          function code(x, y)
                                                          	return 1.0
                                                          end
                                                          
                                                          function tmp = code(x, y)
                                                          	tmp = 1.0;
                                                          end
                                                          
                                                          code[x_, y_] := 1.0
                                                          
                                                          \begin{array}{l}
                                                          
                                                          \\
                                                          1
                                                          \end{array}
                                                          
                                                          Derivation
                                                          1. Initial program 100.0%

                                                            \[e^{\left(x \cdot y\right) \cdot y} \]
                                                          2. Add Preprocessing
                                                          3. Taylor expanded in x around 0

                                                            \[\leadsto \color{blue}{1} \]
                                                          4. Step-by-step derivation
                                                            1. Applied rewrites43.7%

                                                              \[\leadsto \color{blue}{1} \]
                                                            2. Add Preprocessing

                                                            Reproduce

                                                            ?
                                                            herbie shell --seed 2024220 
                                                            (FPCore (x y)
                                                              :name "Data.Random.Distribution.Normal:normalF from random-fu-0.2.6.2"
                                                              :precision binary64
                                                              (exp (* (* x y) y)))