Harley's example

Percentage Accurate: 91.0% → 97.9%
Time: 52.8s
Alternatives: 10
Speedup: 896.0×

Specification

?
\[0 < c\_p \land 0 < c\_n\]
\[\begin{array}{l} \\ \begin{array}{l} t_1 := \frac{1}{1 + e^{-t}}\\ t_2 := \frac{1}{1 + e^{-s}}\\ \frac{{t\_2}^{c\_p} \cdot {\left(1 - t\_2\right)}^{c\_n}}{{t\_1}^{c\_p} \cdot {\left(1 - t\_1\right)}^{c\_n}} \end{array} \end{array} \]
(FPCore (c_p c_n t s)
 :precision binary64
 (let* ((t_1 (/ 1.0 (+ 1.0 (exp (- t))))) (t_2 (/ 1.0 (+ 1.0 (exp (- s))))))
   (/
    (* (pow t_2 c_p) (pow (- 1.0 t_2) c_n))
    (* (pow t_1 c_p) (pow (- 1.0 t_1) c_n)))))
double code(double c_p, double c_n, double t, double s) {
	double t_1 = 1.0 / (1.0 + exp(-t));
	double t_2 = 1.0 / (1.0 + exp(-s));
	return (pow(t_2, c_p) * pow((1.0 - t_2), c_n)) / (pow(t_1, c_p) * pow((1.0 - t_1), c_n));
}
real(8) function code(c_p, c_n, t, s)
    real(8), intent (in) :: c_p
    real(8), intent (in) :: c_n
    real(8), intent (in) :: t
    real(8), intent (in) :: s
    real(8) :: t_1
    real(8) :: t_2
    t_1 = 1.0d0 / (1.0d0 + exp(-t))
    t_2 = 1.0d0 / (1.0d0 + exp(-s))
    code = ((t_2 ** c_p) * ((1.0d0 - t_2) ** c_n)) / ((t_1 ** c_p) * ((1.0d0 - t_1) ** c_n))
end function
public static double code(double c_p, double c_n, double t, double s) {
	double t_1 = 1.0 / (1.0 + Math.exp(-t));
	double t_2 = 1.0 / (1.0 + Math.exp(-s));
	return (Math.pow(t_2, c_p) * Math.pow((1.0 - t_2), c_n)) / (Math.pow(t_1, c_p) * Math.pow((1.0 - t_1), c_n));
}
def code(c_p, c_n, t, s):
	t_1 = 1.0 / (1.0 + math.exp(-t))
	t_2 = 1.0 / (1.0 + math.exp(-s))
	return (math.pow(t_2, c_p) * math.pow((1.0 - t_2), c_n)) / (math.pow(t_1, c_p) * math.pow((1.0 - t_1), c_n))
function code(c_p, c_n, t, s)
	t_1 = Float64(1.0 / Float64(1.0 + exp(Float64(-t))))
	t_2 = Float64(1.0 / Float64(1.0 + exp(Float64(-s))))
	return Float64(Float64((t_2 ^ c_p) * (Float64(1.0 - t_2) ^ c_n)) / Float64((t_1 ^ c_p) * (Float64(1.0 - t_1) ^ c_n)))
end
function tmp = code(c_p, c_n, t, s)
	t_1 = 1.0 / (1.0 + exp(-t));
	t_2 = 1.0 / (1.0 + exp(-s));
	tmp = ((t_2 ^ c_p) * ((1.0 - t_2) ^ c_n)) / ((t_1 ^ c_p) * ((1.0 - t_1) ^ c_n));
end
code[c$95$p_, c$95$n_, t_, s_] := Block[{t$95$1 = N[(1.0 / N[(1.0 + N[Exp[(-t)], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$2 = N[(1.0 / N[(1.0 + N[Exp[(-s)], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]}, N[(N[(N[Power[t$95$2, c$95$p], $MachinePrecision] * N[Power[N[(1.0 - t$95$2), $MachinePrecision], c$95$n], $MachinePrecision]), $MachinePrecision] / N[(N[Power[t$95$1, c$95$p], $MachinePrecision] * N[Power[N[(1.0 - t$95$1), $MachinePrecision], c$95$n], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]]]
\begin{array}{l}

\\
\begin{array}{l}
t_1 := \frac{1}{1 + e^{-t}}\\
t_2 := \frac{1}{1 + e^{-s}}\\
\frac{{t\_2}^{c\_p} \cdot {\left(1 - t\_2\right)}^{c\_n}}{{t\_1}^{c\_p} \cdot {\left(1 - t\_1\right)}^{c\_n}}
\end{array}
\end{array}

Sampling outcomes in binary64 precision:

Local Percentage Accuracy vs ?

The average percentage accuracy by input value. Horizontal axis shows value of an input variable; the variable is choosen in the title. Vertical axis is accuracy; higher is better. Red represent the original program, while blue represents Herbie's suggestion. These can be toggled with buttons below the plot. The line is an average while dots represent individual samples.

Accuracy vs Speed?

Herbie found 10 alternatives:

AlternativeAccuracySpeedup
The accuracy (vertical axis) and speed (horizontal axis) of each alternatives. Up and to the right is better. The red square shows the initial program, and each blue circle shows an alternative.The line shows the best available speed-accuracy tradeoffs.

Initial Program: 91.0% accurate, 1.0× speedup?

\[\begin{array}{l} \\ \begin{array}{l} t_1 := \frac{1}{1 + e^{-t}}\\ t_2 := \frac{1}{1 + e^{-s}}\\ \frac{{t\_2}^{c\_p} \cdot {\left(1 - t\_2\right)}^{c\_n}}{{t\_1}^{c\_p} \cdot {\left(1 - t\_1\right)}^{c\_n}} \end{array} \end{array} \]
(FPCore (c_p c_n t s)
 :precision binary64
 (let* ((t_1 (/ 1.0 (+ 1.0 (exp (- t))))) (t_2 (/ 1.0 (+ 1.0 (exp (- s))))))
   (/
    (* (pow t_2 c_p) (pow (- 1.0 t_2) c_n))
    (* (pow t_1 c_p) (pow (- 1.0 t_1) c_n)))))
double code(double c_p, double c_n, double t, double s) {
	double t_1 = 1.0 / (1.0 + exp(-t));
	double t_2 = 1.0 / (1.0 + exp(-s));
	return (pow(t_2, c_p) * pow((1.0 - t_2), c_n)) / (pow(t_1, c_p) * pow((1.0 - t_1), c_n));
}
real(8) function code(c_p, c_n, t, s)
    real(8), intent (in) :: c_p
    real(8), intent (in) :: c_n
    real(8), intent (in) :: t
    real(8), intent (in) :: s
    real(8) :: t_1
    real(8) :: t_2
    t_1 = 1.0d0 / (1.0d0 + exp(-t))
    t_2 = 1.0d0 / (1.0d0 + exp(-s))
    code = ((t_2 ** c_p) * ((1.0d0 - t_2) ** c_n)) / ((t_1 ** c_p) * ((1.0d0 - t_1) ** c_n))
end function
public static double code(double c_p, double c_n, double t, double s) {
	double t_1 = 1.0 / (1.0 + Math.exp(-t));
	double t_2 = 1.0 / (1.0 + Math.exp(-s));
	return (Math.pow(t_2, c_p) * Math.pow((1.0 - t_2), c_n)) / (Math.pow(t_1, c_p) * Math.pow((1.0 - t_1), c_n));
}
def code(c_p, c_n, t, s):
	t_1 = 1.0 / (1.0 + math.exp(-t))
	t_2 = 1.0 / (1.0 + math.exp(-s))
	return (math.pow(t_2, c_p) * math.pow((1.0 - t_2), c_n)) / (math.pow(t_1, c_p) * math.pow((1.0 - t_1), c_n))
function code(c_p, c_n, t, s)
	t_1 = Float64(1.0 / Float64(1.0 + exp(Float64(-t))))
	t_2 = Float64(1.0 / Float64(1.0 + exp(Float64(-s))))
	return Float64(Float64((t_2 ^ c_p) * (Float64(1.0 - t_2) ^ c_n)) / Float64((t_1 ^ c_p) * (Float64(1.0 - t_1) ^ c_n)))
end
function tmp = code(c_p, c_n, t, s)
	t_1 = 1.0 / (1.0 + exp(-t));
	t_2 = 1.0 / (1.0 + exp(-s));
	tmp = ((t_2 ^ c_p) * ((1.0 - t_2) ^ c_n)) / ((t_1 ^ c_p) * ((1.0 - t_1) ^ c_n));
end
code[c$95$p_, c$95$n_, t_, s_] := Block[{t$95$1 = N[(1.0 / N[(1.0 + N[Exp[(-t)], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$2 = N[(1.0 / N[(1.0 + N[Exp[(-s)], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]}, N[(N[(N[Power[t$95$2, c$95$p], $MachinePrecision] * N[Power[N[(1.0 - t$95$2), $MachinePrecision], c$95$n], $MachinePrecision]), $MachinePrecision] / N[(N[Power[t$95$1, c$95$p], $MachinePrecision] * N[Power[N[(1.0 - t$95$1), $MachinePrecision], c$95$n], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]]]
\begin{array}{l}

\\
\begin{array}{l}
t_1 := \frac{1}{1 + e^{-t}}\\
t_2 := \frac{1}{1 + e^{-s}}\\
\frac{{t\_2}^{c\_p} \cdot {\left(1 - t\_2\right)}^{c\_n}}{{t\_1}^{c\_p} \cdot {\left(1 - t\_1\right)}^{c\_n}}
\end{array}
\end{array}

Alternative 1: 97.9% accurate, 0.9× speedup?

\[\begin{array}{l} \\ \begin{array}{l} t_1 := e^{-t}\\ t_2 := e^{-s}\\ \mathbf{if}\;-t \leq 4 \cdot 10^{-5}:\\ \;\;\;\;e^{\mathsf{fma}\left(c\_p, -\mathsf{log1p}\left(t\_2\right), c\_n \cdot \mathsf{log1p}\left(\frac{1}{-1 - t\_2}\right)\right) - \mathsf{fma}\left(c\_p, -\mathsf{log1p}\left(t\_1\right), c\_n \cdot \mathsf{log1p}\left(\frac{1}{-1 - t\_1}\right)\right)}\\ \mathbf{else}:\\ \;\;\;\;e^{\mathsf{fma}\left(c\_n, t \cdot 0.5, s \cdot \left(c\_n \cdot -0.5\right)\right)}\\ \end{array} \end{array} \]
(FPCore (c_p c_n t s)
 :precision binary64
 (let* ((t_1 (exp (- t))) (t_2 (exp (- s))))
   (if (<= (- t) 4e-5)
     (exp
      (-
       (fma c_p (- (log1p t_2)) (* c_n (log1p (/ 1.0 (- -1.0 t_2)))))
       (fma c_p (- (log1p t_1)) (* c_n (log1p (/ 1.0 (- -1.0 t_1)))))))
     (exp (fma c_n (* t 0.5) (* s (* c_n -0.5)))))))
double code(double c_p, double c_n, double t, double s) {
	double t_1 = exp(-t);
	double t_2 = exp(-s);
	double tmp;
	if (-t <= 4e-5) {
		tmp = exp((fma(c_p, -log1p(t_2), (c_n * log1p((1.0 / (-1.0 - t_2))))) - fma(c_p, -log1p(t_1), (c_n * log1p((1.0 / (-1.0 - t_1)))))));
	} else {
		tmp = exp(fma(c_n, (t * 0.5), (s * (c_n * -0.5))));
	}
	return tmp;
}
function code(c_p, c_n, t, s)
	t_1 = exp(Float64(-t))
	t_2 = exp(Float64(-s))
	tmp = 0.0
	if (Float64(-t) <= 4e-5)
		tmp = exp(Float64(fma(c_p, Float64(-log1p(t_2)), Float64(c_n * log1p(Float64(1.0 / Float64(-1.0 - t_2))))) - fma(c_p, Float64(-log1p(t_1)), Float64(c_n * log1p(Float64(1.0 / Float64(-1.0 - t_1)))))));
	else
		tmp = exp(fma(c_n, Float64(t * 0.5), Float64(s * Float64(c_n * -0.5))));
	end
	return tmp
end
code[c$95$p_, c$95$n_, t_, s_] := Block[{t$95$1 = N[Exp[(-t)], $MachinePrecision]}, Block[{t$95$2 = N[Exp[(-s)], $MachinePrecision]}, If[LessEqual[(-t), 4e-5], N[Exp[N[(N[(c$95$p * (-N[Log[1 + t$95$2], $MachinePrecision]) + N[(c$95$n * N[Log[1 + N[(1.0 / N[(-1.0 - t$95$2), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision] - N[(c$95$p * (-N[Log[1 + t$95$1], $MachinePrecision]) + N[(c$95$n * N[Log[1 + N[(1.0 / N[(-1.0 - t$95$1), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision], N[Exp[N[(c$95$n * N[(t * 0.5), $MachinePrecision] + N[(s * N[(c$95$n * -0.5), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]]]]
\begin{array}{l}

\\
\begin{array}{l}
t_1 := e^{-t}\\
t_2 := e^{-s}\\
\mathbf{if}\;-t \leq 4 \cdot 10^{-5}:\\
\;\;\;\;e^{\mathsf{fma}\left(c\_p, -\mathsf{log1p}\left(t\_2\right), c\_n \cdot \mathsf{log1p}\left(\frac{1}{-1 - t\_2}\right)\right) - \mathsf{fma}\left(c\_p, -\mathsf{log1p}\left(t\_1\right), c\_n \cdot \mathsf{log1p}\left(\frac{1}{-1 - t\_1}\right)\right)}\\

\mathbf{else}:\\
\;\;\;\;e^{\mathsf{fma}\left(c\_n, t \cdot 0.5, s \cdot \left(c\_n \cdot -0.5\right)\right)}\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if (neg.f64 t) < 4.00000000000000033e-5

    1. Initial program 93.1%

      \[\frac{{\left(\frac{1}{1 + e^{-s}}\right)}^{c\_p} \cdot {\left(1 - \frac{1}{1 + e^{-s}}\right)}^{c\_n}}{{\left(\frac{1}{1 + e^{-t}}\right)}^{c\_p} \cdot {\left(1 - \frac{1}{1 + e^{-t}}\right)}^{c\_n}} \]
    2. Add Preprocessing
    3. Applied rewrites99.9%

      \[\leadsto \color{blue}{e^{\mathsf{fma}\left(c\_p, -\mathsf{log1p}\left(e^{-s}\right), c\_n \cdot \mathsf{log1p}\left(\frac{1}{-1 - e^{-s}}\right)\right) - \mathsf{fma}\left(c\_p, -\mathsf{log1p}\left(e^{-t}\right), c\_n \cdot \mathsf{log1p}\left(\frac{-1}{1 + e^{-t}}\right)\right)}} \]

    if 4.00000000000000033e-5 < (neg.f64 t)

    1. Initial program 45.5%

      \[\frac{{\left(\frac{1}{1 + e^{-s}}\right)}^{c\_p} \cdot {\left(1 - \frac{1}{1 + e^{-s}}\right)}^{c\_n}}{{\left(\frac{1}{1 + e^{-t}}\right)}^{c\_p} \cdot {\left(1 - \frac{1}{1 + e^{-t}}\right)}^{c\_n}} \]
    2. Add Preprocessing
    3. Applied rewrites46.2%

      \[\leadsto \color{blue}{e^{\mathsf{fma}\left(c\_p, -\mathsf{log1p}\left(e^{-s}\right), c\_n \cdot \mathsf{log1p}\left(\frac{1}{-1 - e^{-s}}\right)\right) - \mathsf{fma}\left(c\_p, -\mathsf{log1p}\left(e^{-t}\right), c\_n \cdot \mathsf{log1p}\left(\frac{-1}{1 + e^{-t}}\right)\right)}} \]
    4. Taylor expanded in c_p around 0

      \[\leadsto e^{\color{blue}{c\_n \cdot \log \left(1 - \frac{1}{1 + e^{\mathsf{neg}\left(s\right)}}\right) - c\_n \cdot \log \left(1 - \frac{1}{1 + e^{\mathsf{neg}\left(t\right)}}\right)}} \]
    5. Step-by-step derivation
      1. distribute-lft-out--N/A

        \[\leadsto e^{\color{blue}{c\_n \cdot \left(\log \left(1 - \frac{1}{1 + e^{\mathsf{neg}\left(s\right)}}\right) - \log \left(1 - \frac{1}{1 + e^{\mathsf{neg}\left(t\right)}}\right)\right)}} \]
      2. lower-*.f64N/A

        \[\leadsto e^{\color{blue}{c\_n \cdot \left(\log \left(1 - \frac{1}{1 + e^{\mathsf{neg}\left(s\right)}}\right) - \log \left(1 - \frac{1}{1 + e^{\mathsf{neg}\left(t\right)}}\right)\right)}} \]
      3. lower--.f64N/A

        \[\leadsto e^{c\_n \cdot \color{blue}{\left(\log \left(1 - \frac{1}{1 + e^{\mathsf{neg}\left(s\right)}}\right) - \log \left(1 - \frac{1}{1 + e^{\mathsf{neg}\left(t\right)}}\right)\right)}} \]
      4. sub-negN/A

        \[\leadsto e^{c\_n \cdot \left(\log \color{blue}{\left(1 + \left(\mathsf{neg}\left(\frac{1}{1 + e^{\mathsf{neg}\left(s\right)}}\right)\right)\right)} - \log \left(1 - \frac{1}{1 + e^{\mathsf{neg}\left(t\right)}}\right)\right)} \]
      5. lower-log1p.f64N/A

        \[\leadsto e^{c\_n \cdot \left(\color{blue}{\mathsf{log1p}\left(\mathsf{neg}\left(\frac{1}{1 + e^{\mathsf{neg}\left(s\right)}}\right)\right)} - \log \left(1 - \frac{1}{1 + e^{\mathsf{neg}\left(t\right)}}\right)\right)} \]
      6. distribute-neg-fracN/A

        \[\leadsto e^{c\_n \cdot \left(\mathsf{log1p}\left(\color{blue}{\frac{\mathsf{neg}\left(1\right)}{1 + e^{\mathsf{neg}\left(s\right)}}}\right) - \log \left(1 - \frac{1}{1 + e^{\mathsf{neg}\left(t\right)}}\right)\right)} \]
      7. metadata-evalN/A

        \[\leadsto e^{c\_n \cdot \left(\mathsf{log1p}\left(\frac{\color{blue}{-1}}{1 + e^{\mathsf{neg}\left(s\right)}}\right) - \log \left(1 - \frac{1}{1 + e^{\mathsf{neg}\left(t\right)}}\right)\right)} \]
      8. lower-/.f64N/A

        \[\leadsto e^{c\_n \cdot \left(\mathsf{log1p}\left(\color{blue}{\frac{-1}{1 + e^{\mathsf{neg}\left(s\right)}}}\right) - \log \left(1 - \frac{1}{1 + e^{\mathsf{neg}\left(t\right)}}\right)\right)} \]
      9. lower-+.f64N/A

        \[\leadsto e^{c\_n \cdot \left(\mathsf{log1p}\left(\frac{-1}{\color{blue}{1 + e^{\mathsf{neg}\left(s\right)}}}\right) - \log \left(1 - \frac{1}{1 + e^{\mathsf{neg}\left(t\right)}}\right)\right)} \]
      10. lower-exp.f64N/A

        \[\leadsto e^{c\_n \cdot \left(\mathsf{log1p}\left(\frac{-1}{1 + \color{blue}{e^{\mathsf{neg}\left(s\right)}}}\right) - \log \left(1 - \frac{1}{1 + e^{\mathsf{neg}\left(t\right)}}\right)\right)} \]
      11. lower-neg.f64N/A

        \[\leadsto e^{c\_n \cdot \left(\mathsf{log1p}\left(\frac{-1}{1 + e^{\color{blue}{\mathsf{neg}\left(s\right)}}}\right) - \log \left(1 - \frac{1}{1 + e^{\mathsf{neg}\left(t\right)}}\right)\right)} \]
      12. sub-negN/A

        \[\leadsto e^{c\_n \cdot \left(\mathsf{log1p}\left(\frac{-1}{1 + e^{\mathsf{neg}\left(s\right)}}\right) - \log \color{blue}{\left(1 + \left(\mathsf{neg}\left(\frac{1}{1 + e^{\mathsf{neg}\left(t\right)}}\right)\right)\right)}\right)} \]
      13. lower-log1p.f64N/A

        \[\leadsto e^{c\_n \cdot \left(\mathsf{log1p}\left(\frac{-1}{1 + e^{\mathsf{neg}\left(s\right)}}\right) - \color{blue}{\mathsf{log1p}\left(\mathsf{neg}\left(\frac{1}{1 + e^{\mathsf{neg}\left(t\right)}}\right)\right)}\right)} \]
    6. Applied rewrites100.0%

      \[\leadsto e^{\color{blue}{c\_n \cdot \left(\mathsf{log1p}\left(\frac{-1}{1 + e^{-s}}\right) - \mathsf{log1p}\left(\frac{-1}{1 + e^{-t}}\right)\right)}} \]
    7. Taylor expanded in s around 0

      \[\leadsto e^{\frac{-1}{2} \cdot \left(c\_n \cdot s\right) + \color{blue}{c\_n \cdot \left(\log \frac{1}{2} - \log \left(1 - \frac{1}{1 + e^{\mathsf{neg}\left(t\right)}}\right)\right)}} \]
    8. Step-by-step derivation
      1. Applied rewrites100.0%

        \[\leadsto e^{\mathsf{fma}\left(c\_n, \color{blue}{\log 0.5 - \mathsf{log1p}\left(\frac{-1}{1 + e^{-t}}\right)}, s \cdot \left(c\_n \cdot -0.5\right)\right)} \]
      2. Taylor expanded in t around 0

        \[\leadsto e^{\mathsf{fma}\left(c\_n, \frac{1}{2} \cdot t, s \cdot \left(c\_n \cdot \frac{-1}{2}\right)\right)} \]
      3. Step-by-step derivation
        1. Applied rewrites100.0%

          \[\leadsto e^{\mathsf{fma}\left(c\_n, 0.5 \cdot t, s \cdot \left(c\_n \cdot -0.5\right)\right)} \]
      4. Recombined 2 regimes into one program.
      5. Final simplification99.9%

        \[\leadsto \begin{array}{l} \mathbf{if}\;-t \leq 4 \cdot 10^{-5}:\\ \;\;\;\;e^{\mathsf{fma}\left(c\_p, -\mathsf{log1p}\left(e^{-s}\right), c\_n \cdot \mathsf{log1p}\left(\frac{1}{-1 - e^{-s}}\right)\right) - \mathsf{fma}\left(c\_p, -\mathsf{log1p}\left(e^{-t}\right), c\_n \cdot \mathsf{log1p}\left(\frac{1}{-1 - e^{-t}}\right)\right)}\\ \mathbf{else}:\\ \;\;\;\;e^{\mathsf{fma}\left(c\_n, t \cdot 0.5, s \cdot \left(c\_n \cdot -0.5\right)\right)}\\ \end{array} \]
      6. Add Preprocessing

      Alternative 2: 97.6% accurate, 0.9× speedup?

      \[\begin{array}{l} \\ \begin{array}{l} t_1 := e^{-s}\\ t_2 := e^{-t}\\ t_3 := \mathsf{log1p}\left(\frac{1}{-1 - t\_2}\right)\\ \mathbf{if}\;-t \leq 4 \cdot 10^{-163}:\\ \;\;\;\;e^{\mathsf{fma}\left(c\_p, \mathsf{log1p}\left(t\_2\right) - \mathsf{log1p}\left(t\_1\right), c\_n \cdot \left(\mathsf{log1p}\left(\frac{1}{-1 - t\_1}\right) - t\_3\right)\right)}\\ \mathbf{else}:\\ \;\;\;\;e^{\mathsf{fma}\left(c\_n, \log 0.5 - t\_3, s \cdot \left(c\_n \cdot -0.5\right)\right)}\\ \end{array} \end{array} \]
      (FPCore (c_p c_n t s)
       :precision binary64
       (let* ((t_1 (exp (- s))) (t_2 (exp (- t))) (t_3 (log1p (/ 1.0 (- -1.0 t_2)))))
         (if (<= (- t) 4e-163)
           (exp
            (fma
             c_p
             (- (log1p t_2) (log1p t_1))
             (* c_n (- (log1p (/ 1.0 (- -1.0 t_1))) t_3))))
           (exp (fma c_n (- (log 0.5) t_3) (* s (* c_n -0.5)))))))
      double code(double c_p, double c_n, double t, double s) {
      	double t_1 = exp(-s);
      	double t_2 = exp(-t);
      	double t_3 = log1p((1.0 / (-1.0 - t_2)));
      	double tmp;
      	if (-t <= 4e-163) {
      		tmp = exp(fma(c_p, (log1p(t_2) - log1p(t_1)), (c_n * (log1p((1.0 / (-1.0 - t_1))) - t_3))));
      	} else {
      		tmp = exp(fma(c_n, (log(0.5) - t_3), (s * (c_n * -0.5))));
      	}
      	return tmp;
      }
      
      function code(c_p, c_n, t, s)
      	t_1 = exp(Float64(-s))
      	t_2 = exp(Float64(-t))
      	t_3 = log1p(Float64(1.0 / Float64(-1.0 - t_2)))
      	tmp = 0.0
      	if (Float64(-t) <= 4e-163)
      		tmp = exp(fma(c_p, Float64(log1p(t_2) - log1p(t_1)), Float64(c_n * Float64(log1p(Float64(1.0 / Float64(-1.0 - t_1))) - t_3))));
      	else
      		tmp = exp(fma(c_n, Float64(log(0.5) - t_3), Float64(s * Float64(c_n * -0.5))));
      	end
      	return tmp
      end
      
      code[c$95$p_, c$95$n_, t_, s_] := Block[{t$95$1 = N[Exp[(-s)], $MachinePrecision]}, Block[{t$95$2 = N[Exp[(-t)], $MachinePrecision]}, Block[{t$95$3 = N[Log[1 + N[(1.0 / N[(-1.0 - t$95$2), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]}, If[LessEqual[(-t), 4e-163], N[Exp[N[(c$95$p * N[(N[Log[1 + t$95$2], $MachinePrecision] - N[Log[1 + t$95$1], $MachinePrecision]), $MachinePrecision] + N[(c$95$n * N[(N[Log[1 + N[(1.0 / N[(-1.0 - t$95$1), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] - t$95$3), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision], N[Exp[N[(c$95$n * N[(N[Log[0.5], $MachinePrecision] - t$95$3), $MachinePrecision] + N[(s * N[(c$95$n * -0.5), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]]]]]
      
      \begin{array}{l}
      
      \\
      \begin{array}{l}
      t_1 := e^{-s}\\
      t_2 := e^{-t}\\
      t_3 := \mathsf{log1p}\left(\frac{1}{-1 - t\_2}\right)\\
      \mathbf{if}\;-t \leq 4 \cdot 10^{-163}:\\
      \;\;\;\;e^{\mathsf{fma}\left(c\_p, \mathsf{log1p}\left(t\_2\right) - \mathsf{log1p}\left(t\_1\right), c\_n \cdot \left(\mathsf{log1p}\left(\frac{1}{-1 - t\_1}\right) - t\_3\right)\right)}\\
      
      \mathbf{else}:\\
      \;\;\;\;e^{\mathsf{fma}\left(c\_n, \log 0.5 - t\_3, s \cdot \left(c\_n \cdot -0.5\right)\right)}\\
      
      
      \end{array}
      \end{array}
      
      Derivation
      1. Split input into 2 regimes
      2. if (neg.f64 t) < 3.99999999999999969e-163

        1. Initial program 92.7%

          \[\frac{{\left(\frac{1}{1 + e^{-s}}\right)}^{c\_p} \cdot {\left(1 - \frac{1}{1 + e^{-s}}\right)}^{c\_n}}{{\left(\frac{1}{1 + e^{-t}}\right)}^{c\_p} \cdot {\left(1 - \frac{1}{1 + e^{-t}}\right)}^{c\_n}} \]
        2. Add Preprocessing
        3. Applied rewrites97.9%

          \[\leadsto \color{blue}{e^{\mathsf{fma}\left(c\_p, \left(-\mathsf{log1p}\left(e^{-s}\right)\right) - \left(-\mathsf{log1p}\left(e^{-t}\right)\right), c\_n \cdot \left(\mathsf{log1p}\left(\frac{1}{-1 - e^{-s}}\right) - \mathsf{log1p}\left(\frac{-1}{1 + e^{-t}}\right)\right)\right)}} \]

        if 3.99999999999999969e-163 < (neg.f64 t)

        1. Initial program 86.9%

          \[\frac{{\left(\frac{1}{1 + e^{-s}}\right)}^{c\_p} \cdot {\left(1 - \frac{1}{1 + e^{-s}}\right)}^{c\_n}}{{\left(\frac{1}{1 + e^{-t}}\right)}^{c\_p} \cdot {\left(1 - \frac{1}{1 + e^{-t}}\right)}^{c\_n}} \]
        2. Add Preprocessing
        3. Applied rewrites91.4%

          \[\leadsto \color{blue}{e^{\mathsf{fma}\left(c\_p, -\mathsf{log1p}\left(e^{-s}\right), c\_n \cdot \mathsf{log1p}\left(\frac{1}{-1 - e^{-s}}\right)\right) - \mathsf{fma}\left(c\_p, -\mathsf{log1p}\left(e^{-t}\right), c\_n \cdot \mathsf{log1p}\left(\frac{-1}{1 + e^{-t}}\right)\right)}} \]
        4. Taylor expanded in c_p around 0

          \[\leadsto e^{\color{blue}{c\_n \cdot \log \left(1 - \frac{1}{1 + e^{\mathsf{neg}\left(s\right)}}\right) - c\_n \cdot \log \left(1 - \frac{1}{1 + e^{\mathsf{neg}\left(t\right)}}\right)}} \]
        5. Step-by-step derivation
          1. distribute-lft-out--N/A

            \[\leadsto e^{\color{blue}{c\_n \cdot \left(\log \left(1 - \frac{1}{1 + e^{\mathsf{neg}\left(s\right)}}\right) - \log \left(1 - \frac{1}{1 + e^{\mathsf{neg}\left(t\right)}}\right)\right)}} \]
          2. lower-*.f64N/A

            \[\leadsto e^{\color{blue}{c\_n \cdot \left(\log \left(1 - \frac{1}{1 + e^{\mathsf{neg}\left(s\right)}}\right) - \log \left(1 - \frac{1}{1 + e^{\mathsf{neg}\left(t\right)}}\right)\right)}} \]
          3. lower--.f64N/A

            \[\leadsto e^{c\_n \cdot \color{blue}{\left(\log \left(1 - \frac{1}{1 + e^{\mathsf{neg}\left(s\right)}}\right) - \log \left(1 - \frac{1}{1 + e^{\mathsf{neg}\left(t\right)}}\right)\right)}} \]
          4. sub-negN/A

            \[\leadsto e^{c\_n \cdot \left(\log \color{blue}{\left(1 + \left(\mathsf{neg}\left(\frac{1}{1 + e^{\mathsf{neg}\left(s\right)}}\right)\right)\right)} - \log \left(1 - \frac{1}{1 + e^{\mathsf{neg}\left(t\right)}}\right)\right)} \]
          5. lower-log1p.f64N/A

            \[\leadsto e^{c\_n \cdot \left(\color{blue}{\mathsf{log1p}\left(\mathsf{neg}\left(\frac{1}{1 + e^{\mathsf{neg}\left(s\right)}}\right)\right)} - \log \left(1 - \frac{1}{1 + e^{\mathsf{neg}\left(t\right)}}\right)\right)} \]
          6. distribute-neg-fracN/A

            \[\leadsto e^{c\_n \cdot \left(\mathsf{log1p}\left(\color{blue}{\frac{\mathsf{neg}\left(1\right)}{1 + e^{\mathsf{neg}\left(s\right)}}}\right) - \log \left(1 - \frac{1}{1 + e^{\mathsf{neg}\left(t\right)}}\right)\right)} \]
          7. metadata-evalN/A

            \[\leadsto e^{c\_n \cdot \left(\mathsf{log1p}\left(\frac{\color{blue}{-1}}{1 + e^{\mathsf{neg}\left(s\right)}}\right) - \log \left(1 - \frac{1}{1 + e^{\mathsf{neg}\left(t\right)}}\right)\right)} \]
          8. lower-/.f64N/A

            \[\leadsto e^{c\_n \cdot \left(\mathsf{log1p}\left(\color{blue}{\frac{-1}{1 + e^{\mathsf{neg}\left(s\right)}}}\right) - \log \left(1 - \frac{1}{1 + e^{\mathsf{neg}\left(t\right)}}\right)\right)} \]
          9. lower-+.f64N/A

            \[\leadsto e^{c\_n \cdot \left(\mathsf{log1p}\left(\frac{-1}{\color{blue}{1 + e^{\mathsf{neg}\left(s\right)}}}\right) - \log \left(1 - \frac{1}{1 + e^{\mathsf{neg}\left(t\right)}}\right)\right)} \]
          10. lower-exp.f64N/A

            \[\leadsto e^{c\_n \cdot \left(\mathsf{log1p}\left(\frac{-1}{1 + \color{blue}{e^{\mathsf{neg}\left(s\right)}}}\right) - \log \left(1 - \frac{1}{1 + e^{\mathsf{neg}\left(t\right)}}\right)\right)} \]
          11. lower-neg.f64N/A

            \[\leadsto e^{c\_n \cdot \left(\mathsf{log1p}\left(\frac{-1}{1 + e^{\color{blue}{\mathsf{neg}\left(s\right)}}}\right) - \log \left(1 - \frac{1}{1 + e^{\mathsf{neg}\left(t\right)}}\right)\right)} \]
          12. sub-negN/A

            \[\leadsto e^{c\_n \cdot \left(\mathsf{log1p}\left(\frac{-1}{1 + e^{\mathsf{neg}\left(s\right)}}\right) - \log \color{blue}{\left(1 + \left(\mathsf{neg}\left(\frac{1}{1 + e^{\mathsf{neg}\left(t\right)}}\right)\right)\right)}\right)} \]
          13. lower-log1p.f64N/A

            \[\leadsto e^{c\_n \cdot \left(\mathsf{log1p}\left(\frac{-1}{1 + e^{\mathsf{neg}\left(s\right)}}\right) - \color{blue}{\mathsf{log1p}\left(\mathsf{neg}\left(\frac{1}{1 + e^{\mathsf{neg}\left(t\right)}}\right)\right)}\right)} \]
        6. Applied rewrites96.7%

          \[\leadsto e^{\color{blue}{c\_n \cdot \left(\mathsf{log1p}\left(\frac{-1}{1 + e^{-s}}\right) - \mathsf{log1p}\left(\frac{-1}{1 + e^{-t}}\right)\right)}} \]
        7. Taylor expanded in s around 0

          \[\leadsto e^{\frac{-1}{2} \cdot \left(c\_n \cdot s\right) + \color{blue}{c\_n \cdot \left(\log \frac{1}{2} - \log \left(1 - \frac{1}{1 + e^{\mathsf{neg}\left(t\right)}}\right)\right)}} \]
        8. Step-by-step derivation
          1. Applied rewrites97.0%

            \[\leadsto e^{\mathsf{fma}\left(c\_n, \color{blue}{\log 0.5 - \mathsf{log1p}\left(\frac{-1}{1 + e^{-t}}\right)}, s \cdot \left(c\_n \cdot -0.5\right)\right)} \]
        9. Recombined 2 regimes into one program.
        10. Final simplification97.6%

          \[\leadsto \begin{array}{l} \mathbf{if}\;-t \leq 4 \cdot 10^{-163}:\\ \;\;\;\;e^{\mathsf{fma}\left(c\_p, \mathsf{log1p}\left(e^{-t}\right) - \mathsf{log1p}\left(e^{-s}\right), c\_n \cdot \left(\mathsf{log1p}\left(\frac{1}{-1 - e^{-s}}\right) - \mathsf{log1p}\left(\frac{1}{-1 - e^{-t}}\right)\right)\right)}\\ \mathbf{else}:\\ \;\;\;\;e^{\mathsf{fma}\left(c\_n, \log 0.5 - \mathsf{log1p}\left(\frac{1}{-1 - e^{-t}}\right), s \cdot \left(c\_n \cdot -0.5\right)\right)}\\ \end{array} \]
        11. Add Preprocessing

        Developer Target 1: 96.5% accurate, 1.4× speedup?

        \[\begin{array}{l} \\ {\left(\frac{1 + e^{-t}}{1 + e^{-s}}\right)}^{c\_p} \cdot {\left(\frac{1 + e^{t}}{1 + e^{s}}\right)}^{c\_n} \end{array} \]
        (FPCore (c_p c_n t s)
         :precision binary64
         (*
          (pow (/ (+ 1.0 (exp (- t))) (+ 1.0 (exp (- s)))) c_p)
          (pow (/ (+ 1.0 (exp t)) (+ 1.0 (exp s))) c_n)))
        double code(double c_p, double c_n, double t, double s) {
        	return pow(((1.0 + exp(-t)) / (1.0 + exp(-s))), c_p) * pow(((1.0 + exp(t)) / (1.0 + exp(s))), c_n);
        }
        
        real(8) function code(c_p, c_n, t, s)
            real(8), intent (in) :: c_p
            real(8), intent (in) :: c_n
            real(8), intent (in) :: t
            real(8), intent (in) :: s
            code = (((1.0d0 + exp(-t)) / (1.0d0 + exp(-s))) ** c_p) * (((1.0d0 + exp(t)) / (1.0d0 + exp(s))) ** c_n)
        end function
        
        public static double code(double c_p, double c_n, double t, double s) {
        	return Math.pow(((1.0 + Math.exp(-t)) / (1.0 + Math.exp(-s))), c_p) * Math.pow(((1.0 + Math.exp(t)) / (1.0 + Math.exp(s))), c_n);
        }
        
        def code(c_p, c_n, t, s):
        	return math.pow(((1.0 + math.exp(-t)) / (1.0 + math.exp(-s))), c_p) * math.pow(((1.0 + math.exp(t)) / (1.0 + math.exp(s))), c_n)
        
        function code(c_p, c_n, t, s)
        	return Float64((Float64(Float64(1.0 + exp(Float64(-t))) / Float64(1.0 + exp(Float64(-s)))) ^ c_p) * (Float64(Float64(1.0 + exp(t)) / Float64(1.0 + exp(s))) ^ c_n))
        end
        
        function tmp = code(c_p, c_n, t, s)
        	tmp = (((1.0 + exp(-t)) / (1.0 + exp(-s))) ^ c_p) * (((1.0 + exp(t)) / (1.0 + exp(s))) ^ c_n);
        end
        
        code[c$95$p_, c$95$n_, t_, s_] := N[(N[Power[N[(N[(1.0 + N[Exp[(-t)], $MachinePrecision]), $MachinePrecision] / N[(1.0 + N[Exp[(-s)], $MachinePrecision]), $MachinePrecision]), $MachinePrecision], c$95$p], $MachinePrecision] * N[Power[N[(N[(1.0 + N[Exp[t], $MachinePrecision]), $MachinePrecision] / N[(1.0 + N[Exp[s], $MachinePrecision]), $MachinePrecision]), $MachinePrecision], c$95$n], $MachinePrecision]), $MachinePrecision]
        
        \begin{array}{l}
        
        \\
        {\left(\frac{1 + e^{-t}}{1 + e^{-s}}\right)}^{c\_p} \cdot {\left(\frac{1 + e^{t}}{1 + e^{s}}\right)}^{c\_n}
        \end{array}
        

        Reproduce

        ?
        herbie shell --seed 2024219 
        (FPCore (c_p c_n t s)
          :name "Harley's example"
          :precision binary64
          :pre (and (< 0.0 c_p) (< 0.0 c_n))
        
          :alt
          (! :herbie-platform default (* (pow (/ (+ 1 (exp (- t))) (+ 1 (exp (- s)))) c_p) (pow (/ (+ 1 (exp t)) (+ 1 (exp s))) c_n)))
        
          (/ (* (pow (/ 1.0 (+ 1.0 (exp (- s)))) c_p) (pow (- 1.0 (/ 1.0 (+ 1.0 (exp (- s))))) c_n)) (* (pow (/ 1.0 (+ 1.0 (exp (- t)))) c_p) (pow (- 1.0 (/ 1.0 (+ 1.0 (exp (- t))))) c_n))))