Compound Interest

Percentage Accurate: 28.0% → 96.0%
Time: 16.3s
Alternatives: 18
Speedup: 24.3×

Specification

?
\[\begin{array}{l} \\ 100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}} \end{array} \]
(FPCore (i n)
 :precision binary64
 (* 100.0 (/ (- (pow (+ 1.0 (/ i n)) n) 1.0) (/ i n))))
double code(double i, double n) {
	return 100.0 * ((pow((1.0 + (i / n)), n) - 1.0) / (i / n));
}
real(8) function code(i, n)
    real(8), intent (in) :: i
    real(8), intent (in) :: n
    code = 100.0d0 * ((((1.0d0 + (i / n)) ** n) - 1.0d0) / (i / n))
end function
public static double code(double i, double n) {
	return 100.0 * ((Math.pow((1.0 + (i / n)), n) - 1.0) / (i / n));
}
def code(i, n):
	return 100.0 * ((math.pow((1.0 + (i / n)), n) - 1.0) / (i / n))
function code(i, n)
	return Float64(100.0 * Float64(Float64((Float64(1.0 + Float64(i / n)) ^ n) - 1.0) / Float64(i / n)))
end
function tmp = code(i, n)
	tmp = 100.0 * ((((1.0 + (i / n)) ^ n) - 1.0) / (i / n));
end
code[i_, n_] := N[(100.0 * N[(N[(N[Power[N[(1.0 + N[(i / n), $MachinePrecision]), $MachinePrecision], n], $MachinePrecision] - 1.0), $MachinePrecision] / N[(i / n), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}}
\end{array}

Sampling outcomes in binary64 precision:

Local Percentage Accuracy vs ?

The average percentage accuracy by input value. Horizontal axis shows value of an input variable; the variable is choosen in the title. Vertical axis is accuracy; higher is better. Red represent the original program, while blue represents Herbie's suggestion. These can be toggled with buttons below the plot. The line is an average while dots represent individual samples.

Accuracy vs Speed?

Herbie found 18 alternatives:

AlternativeAccuracySpeedup
The accuracy (vertical axis) and speed (horizontal axis) of each alternatives. Up and to the right is better. The red square shows the initial program, and each blue circle shows an alternative.The line shows the best available speed-accuracy tradeoffs.

Initial Program: 28.0% accurate, 1.0× speedup?

\[\begin{array}{l} \\ 100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}} \end{array} \]
(FPCore (i n)
 :precision binary64
 (* 100.0 (/ (- (pow (+ 1.0 (/ i n)) n) 1.0) (/ i n))))
double code(double i, double n) {
	return 100.0 * ((pow((1.0 + (i / n)), n) - 1.0) / (i / n));
}
real(8) function code(i, n)
    real(8), intent (in) :: i
    real(8), intent (in) :: n
    code = 100.0d0 * ((((1.0d0 + (i / n)) ** n) - 1.0d0) / (i / n))
end function
public static double code(double i, double n) {
	return 100.0 * ((Math.pow((1.0 + (i / n)), n) - 1.0) / (i / n));
}
def code(i, n):
	return 100.0 * ((math.pow((1.0 + (i / n)), n) - 1.0) / (i / n))
function code(i, n)
	return Float64(100.0 * Float64(Float64((Float64(1.0 + Float64(i / n)) ^ n) - 1.0) / Float64(i / n)))
end
function tmp = code(i, n)
	tmp = 100.0 * ((((1.0 + (i / n)) ^ n) - 1.0) / (i / n));
end
code[i_, n_] := N[(100.0 * N[(N[(N[Power[N[(1.0 + N[(i / n), $MachinePrecision]), $MachinePrecision], n], $MachinePrecision] - 1.0), $MachinePrecision] / N[(i / n), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}}
\end{array}

Alternative 1: 96.0% accurate, 0.3× speedup?

\[\begin{array}{l} \\ \begin{array}{l} t_0 := {\left(1 + \frac{i}{n}\right)}^{n}\\ t_1 := \mathsf{fma}\left(t\_0, 100, -100\right)\\ t_2 := \frac{t\_0 + -1}{\frac{i}{n}}\\ \mathbf{if}\;t\_2 \leq -2 \cdot 10^{-7}:\\ \;\;\;\;\frac{n \cdot t\_1}{i}\\ \mathbf{elif}\;t\_2 \leq 2 \cdot 10^{-289}:\\ \;\;\;\;100 \cdot \frac{\mathsf{expm1}\left(n \cdot \mathsf{log1p}\left(\frac{i}{n}\right)\right)}{\frac{i}{n}}\\ \mathbf{elif}\;t\_2 \leq \infty:\\ \;\;\;\;t\_1 \cdot \frac{n}{i}\\ \mathbf{else}:\\ \;\;\;\;n \cdot 100\\ \end{array} \end{array} \]
(FPCore (i n)
 :precision binary64
 (let* ((t_0 (pow (+ 1.0 (/ i n)) n))
        (t_1 (fma t_0 100.0 -100.0))
        (t_2 (/ (+ t_0 -1.0) (/ i n))))
   (if (<= t_2 -2e-7)
     (/ (* n t_1) i)
     (if (<= t_2 2e-289)
       (* 100.0 (/ (expm1 (* n (log1p (/ i n)))) (/ i n)))
       (if (<= t_2 INFINITY) (* t_1 (/ n i)) (* n 100.0))))))
double code(double i, double n) {
	double t_0 = pow((1.0 + (i / n)), n);
	double t_1 = fma(t_0, 100.0, -100.0);
	double t_2 = (t_0 + -1.0) / (i / n);
	double tmp;
	if (t_2 <= -2e-7) {
		tmp = (n * t_1) / i;
	} else if (t_2 <= 2e-289) {
		tmp = 100.0 * (expm1((n * log1p((i / n)))) / (i / n));
	} else if (t_2 <= ((double) INFINITY)) {
		tmp = t_1 * (n / i);
	} else {
		tmp = n * 100.0;
	}
	return tmp;
}
function code(i, n)
	t_0 = Float64(1.0 + Float64(i / n)) ^ n
	t_1 = fma(t_0, 100.0, -100.0)
	t_2 = Float64(Float64(t_0 + -1.0) / Float64(i / n))
	tmp = 0.0
	if (t_2 <= -2e-7)
		tmp = Float64(Float64(n * t_1) / i);
	elseif (t_2 <= 2e-289)
		tmp = Float64(100.0 * Float64(expm1(Float64(n * log1p(Float64(i / n)))) / Float64(i / n)));
	elseif (t_2 <= Inf)
		tmp = Float64(t_1 * Float64(n / i));
	else
		tmp = Float64(n * 100.0);
	end
	return tmp
end
code[i_, n_] := Block[{t$95$0 = N[Power[N[(1.0 + N[(i / n), $MachinePrecision]), $MachinePrecision], n], $MachinePrecision]}, Block[{t$95$1 = N[(t$95$0 * 100.0 + -100.0), $MachinePrecision]}, Block[{t$95$2 = N[(N[(t$95$0 + -1.0), $MachinePrecision] / N[(i / n), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[t$95$2, -2e-7], N[(N[(n * t$95$1), $MachinePrecision] / i), $MachinePrecision], If[LessEqual[t$95$2, 2e-289], N[(100.0 * N[(N[(Exp[N[(n * N[Log[1 + N[(i / n), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]] - 1), $MachinePrecision] / N[(i / n), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], If[LessEqual[t$95$2, Infinity], N[(t$95$1 * N[(n / i), $MachinePrecision]), $MachinePrecision], N[(n * 100.0), $MachinePrecision]]]]]]]
\begin{array}{l}

\\
\begin{array}{l}
t_0 := {\left(1 + \frac{i}{n}\right)}^{n}\\
t_1 := \mathsf{fma}\left(t\_0, 100, -100\right)\\
t_2 := \frac{t\_0 + -1}{\frac{i}{n}}\\
\mathbf{if}\;t\_2 \leq -2 \cdot 10^{-7}:\\
\;\;\;\;\frac{n \cdot t\_1}{i}\\

\mathbf{elif}\;t\_2 \leq 2 \cdot 10^{-289}:\\
\;\;\;\;100 \cdot \frac{\mathsf{expm1}\left(n \cdot \mathsf{log1p}\left(\frac{i}{n}\right)\right)}{\frac{i}{n}}\\

\mathbf{elif}\;t\_2 \leq \infty:\\
\;\;\;\;t\_1 \cdot \frac{n}{i}\\

\mathbf{else}:\\
\;\;\;\;n \cdot 100\\


\end{array}
\end{array}
Derivation
  1. Split input into 4 regimes
  2. if (/.f64 (-.f64 (pow.f64 (+.f64 #s(literal 1 binary64) (/.f64 i n)) n) #s(literal 1 binary64)) (/.f64 i n)) < -1.9999999999999999e-7

    1. Initial program 99.8%

      \[100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}} \]
    2. Add Preprocessing
    3. Step-by-step derivation
      1. lift-*.f64N/A

        \[\leadsto \color{blue}{100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}}} \]
      2. lift-/.f64N/A

        \[\leadsto 100 \cdot \color{blue}{\frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}}} \]
      3. associate-*r/N/A

        \[\leadsto \color{blue}{\frac{100 \cdot \left({\left(1 + \frac{i}{n}\right)}^{n} - 1\right)}{\frac{i}{n}}} \]
      4. lift-/.f64N/A

        \[\leadsto \frac{100 \cdot \left({\left(1 + \frac{i}{n}\right)}^{n} - 1\right)}{\color{blue}{\frac{i}{n}}} \]
      5. associate-/r/N/A

        \[\leadsto \color{blue}{\frac{100 \cdot \left({\left(1 + \frac{i}{n}\right)}^{n} - 1\right)}{i} \cdot n} \]
      6. associate-*l/N/A

        \[\leadsto \color{blue}{\frac{\left(100 \cdot \left({\left(1 + \frac{i}{n}\right)}^{n} - 1\right)\right) \cdot n}{i}} \]
      7. lower-/.f64N/A

        \[\leadsto \color{blue}{\frac{\left(100 \cdot \left({\left(1 + \frac{i}{n}\right)}^{n} - 1\right)\right) \cdot n}{i}} \]
      8. lower-*.f64N/A

        \[\leadsto \frac{\color{blue}{\left(100 \cdot \left({\left(1 + \frac{i}{n}\right)}^{n} - 1\right)\right) \cdot n}}{i} \]
      9. lift--.f64N/A

        \[\leadsto \frac{\left(100 \cdot \color{blue}{\left({\left(1 + \frac{i}{n}\right)}^{n} - 1\right)}\right) \cdot n}{i} \]
      10. sub-negN/A

        \[\leadsto \frac{\left(100 \cdot \color{blue}{\left({\left(1 + \frac{i}{n}\right)}^{n} + \left(\mathsf{neg}\left(1\right)\right)\right)}\right) \cdot n}{i} \]
      11. distribute-lft-inN/A

        \[\leadsto \frac{\color{blue}{\left(100 \cdot {\left(1 + \frac{i}{n}\right)}^{n} + 100 \cdot \left(\mathsf{neg}\left(1\right)\right)\right)} \cdot n}{i} \]
      12. *-commutativeN/A

        \[\leadsto \frac{\left(\color{blue}{{\left(1 + \frac{i}{n}\right)}^{n} \cdot 100} + 100 \cdot \left(\mathsf{neg}\left(1\right)\right)\right) \cdot n}{i} \]
      13. lower-fma.f64N/A

        \[\leadsto \frac{\color{blue}{\mathsf{fma}\left({\left(1 + \frac{i}{n}\right)}^{n}, 100, 100 \cdot \left(\mathsf{neg}\left(1\right)\right)\right)} \cdot n}{i} \]
      14. metadata-evalN/A

        \[\leadsto \frac{\mathsf{fma}\left({\left(1 + \frac{i}{n}\right)}^{n}, 100, 100 \cdot \color{blue}{-1}\right) \cdot n}{i} \]
      15. metadata-eval100.0

        \[\leadsto \frac{\mathsf{fma}\left({\left(1 + \frac{i}{n}\right)}^{n}, 100, \color{blue}{-100}\right) \cdot n}{i} \]
    4. Applied rewrites100.0%

      \[\leadsto \color{blue}{\frac{\mathsf{fma}\left({\left(1 + \frac{i}{n}\right)}^{n}, 100, -100\right) \cdot n}{i}} \]

    if -1.9999999999999999e-7 < (/.f64 (-.f64 (pow.f64 (+.f64 #s(literal 1 binary64) (/.f64 i n)) n) #s(literal 1 binary64)) (/.f64 i n)) < 2e-289

    1. Initial program 24.4%

      \[100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}} \]
    2. Add Preprocessing
    3. Step-by-step derivation
      1. lift--.f64N/A

        \[\leadsto 100 \cdot \frac{\color{blue}{{\left(1 + \frac{i}{n}\right)}^{n} - 1}}{\frac{i}{n}} \]
      2. lift-pow.f64N/A

        \[\leadsto 100 \cdot \frac{\color{blue}{{\left(1 + \frac{i}{n}\right)}^{n}} - 1}{\frac{i}{n}} \]
      3. pow-to-expN/A

        \[\leadsto 100 \cdot \frac{\color{blue}{e^{\log \left(1 + \frac{i}{n}\right) \cdot n}} - 1}{\frac{i}{n}} \]
      4. lower-expm1.f64N/A

        \[\leadsto 100 \cdot \frac{\color{blue}{\mathsf{expm1}\left(\log \left(1 + \frac{i}{n}\right) \cdot n\right)}}{\frac{i}{n}} \]
      5. *-commutativeN/A

        \[\leadsto 100 \cdot \frac{\mathsf{expm1}\left(\color{blue}{n \cdot \log \left(1 + \frac{i}{n}\right)}\right)}{\frac{i}{n}} \]
      6. lower-*.f64N/A

        \[\leadsto 100 \cdot \frac{\mathsf{expm1}\left(\color{blue}{n \cdot \log \left(1 + \frac{i}{n}\right)}\right)}{\frac{i}{n}} \]
      7. lift-+.f64N/A

        \[\leadsto 100 \cdot \frac{\mathsf{expm1}\left(n \cdot \log \color{blue}{\left(1 + \frac{i}{n}\right)}\right)}{\frac{i}{n}} \]
      8. lower-log1p.f6499.6

        \[\leadsto 100 \cdot \frac{\mathsf{expm1}\left(n \cdot \color{blue}{\mathsf{log1p}\left(\frac{i}{n}\right)}\right)}{\frac{i}{n}} \]
    4. Applied rewrites99.6%

      \[\leadsto 100 \cdot \frac{\color{blue}{\mathsf{expm1}\left(n \cdot \mathsf{log1p}\left(\frac{i}{n}\right)\right)}}{\frac{i}{n}} \]

    if 2e-289 < (/.f64 (-.f64 (pow.f64 (+.f64 #s(literal 1 binary64) (/.f64 i n)) n) #s(literal 1 binary64)) (/.f64 i n)) < +inf.0

    1. Initial program 99.8%

      \[100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}} \]
    2. Add Preprocessing
    3. Step-by-step derivation
      1. lift-*.f64N/A

        \[\leadsto \color{blue}{100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}}} \]
      2. lift-/.f64N/A

        \[\leadsto 100 \cdot \color{blue}{\frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}}} \]
      3. associate-*r/N/A

        \[\leadsto \color{blue}{\frac{100 \cdot \left({\left(1 + \frac{i}{n}\right)}^{n} - 1\right)}{\frac{i}{n}}} \]
      4. div-invN/A

        \[\leadsto \color{blue}{\left(100 \cdot \left({\left(1 + \frac{i}{n}\right)}^{n} - 1\right)\right) \cdot \frac{1}{\frac{i}{n}}} \]
      5. lift-/.f64N/A

        \[\leadsto \left(100 \cdot \left({\left(1 + \frac{i}{n}\right)}^{n} - 1\right)\right) \cdot \frac{1}{\color{blue}{\frac{i}{n}}} \]
      6. clear-numN/A

        \[\leadsto \left(100 \cdot \left({\left(1 + \frac{i}{n}\right)}^{n} - 1\right)\right) \cdot \color{blue}{\frac{n}{i}} \]
      7. lower-*.f64N/A

        \[\leadsto \color{blue}{\left(100 \cdot \left({\left(1 + \frac{i}{n}\right)}^{n} - 1\right)\right) \cdot \frac{n}{i}} \]
      8. lift--.f64N/A

        \[\leadsto \left(100 \cdot \color{blue}{\left({\left(1 + \frac{i}{n}\right)}^{n} - 1\right)}\right) \cdot \frac{n}{i} \]
      9. sub-negN/A

        \[\leadsto \left(100 \cdot \color{blue}{\left({\left(1 + \frac{i}{n}\right)}^{n} + \left(\mathsf{neg}\left(1\right)\right)\right)}\right) \cdot \frac{n}{i} \]
      10. distribute-lft-inN/A

        \[\leadsto \color{blue}{\left(100 \cdot {\left(1 + \frac{i}{n}\right)}^{n} + 100 \cdot \left(\mathsf{neg}\left(1\right)\right)\right)} \cdot \frac{n}{i} \]
      11. *-commutativeN/A

        \[\leadsto \left(\color{blue}{{\left(1 + \frac{i}{n}\right)}^{n} \cdot 100} + 100 \cdot \left(\mathsf{neg}\left(1\right)\right)\right) \cdot \frac{n}{i} \]
      12. lower-fma.f64N/A

        \[\leadsto \color{blue}{\mathsf{fma}\left({\left(1 + \frac{i}{n}\right)}^{n}, 100, 100 \cdot \left(\mathsf{neg}\left(1\right)\right)\right)} \cdot \frac{n}{i} \]
      13. metadata-evalN/A

        \[\leadsto \mathsf{fma}\left({\left(1 + \frac{i}{n}\right)}^{n}, 100, 100 \cdot \color{blue}{-1}\right) \cdot \frac{n}{i} \]
      14. metadata-evalN/A

        \[\leadsto \mathsf{fma}\left({\left(1 + \frac{i}{n}\right)}^{n}, 100, \color{blue}{-100}\right) \cdot \frac{n}{i} \]
      15. lower-/.f6499.9

        \[\leadsto \mathsf{fma}\left({\left(1 + \frac{i}{n}\right)}^{n}, 100, -100\right) \cdot \color{blue}{\frac{n}{i}} \]
    4. Applied rewrites99.9%

      \[\leadsto \color{blue}{\mathsf{fma}\left({\left(1 + \frac{i}{n}\right)}^{n}, 100, -100\right) \cdot \frac{n}{i}} \]

    if +inf.0 < (/.f64 (-.f64 (pow.f64 (+.f64 #s(literal 1 binary64) (/.f64 i n)) n) #s(literal 1 binary64)) (/.f64 i n))

    1. Initial program 0.0%

      \[100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}} \]
    2. Add Preprocessing
    3. Taylor expanded in i around 0

      \[\leadsto \color{blue}{100 \cdot n} \]
    4. Step-by-step derivation
      1. *-commutativeN/A

        \[\leadsto \color{blue}{n \cdot 100} \]
      2. lower-*.f6480.8

        \[\leadsto \color{blue}{n \cdot 100} \]
    5. Applied rewrites80.8%

      \[\leadsto \color{blue}{n \cdot 100} \]
  3. Recombined 4 regimes into one program.
  4. Final simplification96.4%

    \[\leadsto \begin{array}{l} \mathbf{if}\;\frac{{\left(1 + \frac{i}{n}\right)}^{n} + -1}{\frac{i}{n}} \leq -2 \cdot 10^{-7}:\\ \;\;\;\;\frac{n \cdot \mathsf{fma}\left({\left(1 + \frac{i}{n}\right)}^{n}, 100, -100\right)}{i}\\ \mathbf{elif}\;\frac{{\left(1 + \frac{i}{n}\right)}^{n} + -1}{\frac{i}{n}} \leq 2 \cdot 10^{-289}:\\ \;\;\;\;100 \cdot \frac{\mathsf{expm1}\left(n \cdot \mathsf{log1p}\left(\frac{i}{n}\right)\right)}{\frac{i}{n}}\\ \mathbf{elif}\;\frac{{\left(1 + \frac{i}{n}\right)}^{n} + -1}{\frac{i}{n}} \leq \infty:\\ \;\;\;\;\mathsf{fma}\left({\left(1 + \frac{i}{n}\right)}^{n}, 100, -100\right) \cdot \frac{n}{i}\\ \mathbf{else}:\\ \;\;\;\;n \cdot 100\\ \end{array} \]
  5. Add Preprocessing

Alternative 2: 80.6% accurate, 0.2× speedup?

\[\begin{array}{l} \\ \begin{array}{l} t_0 := {\left(1 + \frac{i}{n}\right)}^{n}\\ t_1 := \frac{t\_0 + -1}{\frac{i}{n}}\\ \mathbf{if}\;t\_1 \leq -5 \cdot 10^{-196}:\\ \;\;\;\;n \cdot \frac{\mathsf{fma}\left(t\_0, 100, -100\right)}{i}\\ \mathbf{elif}\;t\_1 \leq 0:\\ \;\;\;\;100 \cdot \frac{\mathsf{expm1}\left(i\right)}{\frac{i}{n}}\\ \mathbf{elif}\;t\_1 \leq \infty:\\ \;\;\;\;100 \cdot \left(t\_0 \cdot \frac{n}{i} - \frac{n}{i}\right)\\ \mathbf{else}:\\ \;\;\;\;n \cdot 100\\ \end{array} \end{array} \]
(FPCore (i n)
 :precision binary64
 (let* ((t_0 (pow (+ 1.0 (/ i n)) n)) (t_1 (/ (+ t_0 -1.0) (/ i n))))
   (if (<= t_1 -5e-196)
     (* n (/ (fma t_0 100.0 -100.0) i))
     (if (<= t_1 0.0)
       (* 100.0 (/ (expm1 i) (/ i n)))
       (if (<= t_1 INFINITY)
         (* 100.0 (- (* t_0 (/ n i)) (/ n i)))
         (* n 100.0))))))
double code(double i, double n) {
	double t_0 = pow((1.0 + (i / n)), n);
	double t_1 = (t_0 + -1.0) / (i / n);
	double tmp;
	if (t_1 <= -5e-196) {
		tmp = n * (fma(t_0, 100.0, -100.0) / i);
	} else if (t_1 <= 0.0) {
		tmp = 100.0 * (expm1(i) / (i / n));
	} else if (t_1 <= ((double) INFINITY)) {
		tmp = 100.0 * ((t_0 * (n / i)) - (n / i));
	} else {
		tmp = n * 100.0;
	}
	return tmp;
}
function code(i, n)
	t_0 = Float64(1.0 + Float64(i / n)) ^ n
	t_1 = Float64(Float64(t_0 + -1.0) / Float64(i / n))
	tmp = 0.0
	if (t_1 <= -5e-196)
		tmp = Float64(n * Float64(fma(t_0, 100.0, -100.0) / i));
	elseif (t_1 <= 0.0)
		tmp = Float64(100.0 * Float64(expm1(i) / Float64(i / n)));
	elseif (t_1 <= Inf)
		tmp = Float64(100.0 * Float64(Float64(t_0 * Float64(n / i)) - Float64(n / i)));
	else
		tmp = Float64(n * 100.0);
	end
	return tmp
end
code[i_, n_] := Block[{t$95$0 = N[Power[N[(1.0 + N[(i / n), $MachinePrecision]), $MachinePrecision], n], $MachinePrecision]}, Block[{t$95$1 = N[(N[(t$95$0 + -1.0), $MachinePrecision] / N[(i / n), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[t$95$1, -5e-196], N[(n * N[(N[(t$95$0 * 100.0 + -100.0), $MachinePrecision] / i), $MachinePrecision]), $MachinePrecision], If[LessEqual[t$95$1, 0.0], N[(100.0 * N[(N[(Exp[i] - 1), $MachinePrecision] / N[(i / n), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], If[LessEqual[t$95$1, Infinity], N[(100.0 * N[(N[(t$95$0 * N[(n / i), $MachinePrecision]), $MachinePrecision] - N[(n / i), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], N[(n * 100.0), $MachinePrecision]]]]]]
\begin{array}{l}

\\
\begin{array}{l}
t_0 := {\left(1 + \frac{i}{n}\right)}^{n}\\
t_1 := \frac{t\_0 + -1}{\frac{i}{n}}\\
\mathbf{if}\;t\_1 \leq -5 \cdot 10^{-196}:\\
\;\;\;\;n \cdot \frac{\mathsf{fma}\left(t\_0, 100, -100\right)}{i}\\

\mathbf{elif}\;t\_1 \leq 0:\\
\;\;\;\;100 \cdot \frac{\mathsf{expm1}\left(i\right)}{\frac{i}{n}}\\

\mathbf{elif}\;t\_1 \leq \infty:\\
\;\;\;\;100 \cdot \left(t\_0 \cdot \frac{n}{i} - \frac{n}{i}\right)\\

\mathbf{else}:\\
\;\;\;\;n \cdot 100\\


\end{array}
\end{array}
Derivation
  1. Split input into 4 regimes
  2. if (/.f64 (-.f64 (pow.f64 (+.f64 #s(literal 1 binary64) (/.f64 i n)) n) #s(literal 1 binary64)) (/.f64 i n)) < -5.0000000000000005e-196

    1. Initial program 90.9%

      \[100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}} \]
    2. Add Preprocessing
    3. Step-by-step derivation
      1. lift-*.f64N/A

        \[\leadsto \color{blue}{100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}}} \]
      2. lift-/.f64N/A

        \[\leadsto 100 \cdot \color{blue}{\frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}}} \]
      3. associate-*r/N/A

        \[\leadsto \color{blue}{\frac{100 \cdot \left({\left(1 + \frac{i}{n}\right)}^{n} - 1\right)}{\frac{i}{n}}} \]
      4. lift-/.f64N/A

        \[\leadsto \frac{100 \cdot \left({\left(1 + \frac{i}{n}\right)}^{n} - 1\right)}{\color{blue}{\frac{i}{n}}} \]
      5. associate-/r/N/A

        \[\leadsto \color{blue}{\frac{100 \cdot \left({\left(1 + \frac{i}{n}\right)}^{n} - 1\right)}{i} \cdot n} \]
      6. lower-*.f64N/A

        \[\leadsto \color{blue}{\frac{100 \cdot \left({\left(1 + \frac{i}{n}\right)}^{n} - 1\right)}{i} \cdot n} \]
      7. lower-/.f64N/A

        \[\leadsto \color{blue}{\frac{100 \cdot \left({\left(1 + \frac{i}{n}\right)}^{n} - 1\right)}{i}} \cdot n \]
      8. lift--.f64N/A

        \[\leadsto \frac{100 \cdot \color{blue}{\left({\left(1 + \frac{i}{n}\right)}^{n} - 1\right)}}{i} \cdot n \]
      9. sub-negN/A

        \[\leadsto \frac{100 \cdot \color{blue}{\left({\left(1 + \frac{i}{n}\right)}^{n} + \left(\mathsf{neg}\left(1\right)\right)\right)}}{i} \cdot n \]
      10. distribute-lft-inN/A

        \[\leadsto \frac{\color{blue}{100 \cdot {\left(1 + \frac{i}{n}\right)}^{n} + 100 \cdot \left(\mathsf{neg}\left(1\right)\right)}}{i} \cdot n \]
      11. *-commutativeN/A

        \[\leadsto \frac{\color{blue}{{\left(1 + \frac{i}{n}\right)}^{n} \cdot 100} + 100 \cdot \left(\mathsf{neg}\left(1\right)\right)}{i} \cdot n \]
      12. lower-fma.f64N/A

        \[\leadsto \frac{\color{blue}{\mathsf{fma}\left({\left(1 + \frac{i}{n}\right)}^{n}, 100, 100 \cdot \left(\mathsf{neg}\left(1\right)\right)\right)}}{i} \cdot n \]
      13. metadata-evalN/A

        \[\leadsto \frac{\mathsf{fma}\left({\left(1 + \frac{i}{n}\right)}^{n}, 100, 100 \cdot \color{blue}{-1}\right)}{i} \cdot n \]
      14. metadata-eval91.1

        \[\leadsto \frac{\mathsf{fma}\left({\left(1 + \frac{i}{n}\right)}^{n}, 100, \color{blue}{-100}\right)}{i} \cdot n \]
    4. Applied rewrites91.1%

      \[\leadsto \color{blue}{\frac{\mathsf{fma}\left({\left(1 + \frac{i}{n}\right)}^{n}, 100, -100\right)}{i} \cdot n} \]

    if -5.0000000000000005e-196 < (/.f64 (-.f64 (pow.f64 (+.f64 #s(literal 1 binary64) (/.f64 i n)) n) #s(literal 1 binary64)) (/.f64 i n)) < 0.0

    1. Initial program 18.4%

      \[100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}} \]
    2. Add Preprocessing
    3. Taylor expanded in n around inf

      \[\leadsto 100 \cdot \frac{\color{blue}{e^{i} - 1}}{\frac{i}{n}} \]
    4. Step-by-step derivation
      1. lower-expm1.f6475.7

        \[\leadsto 100 \cdot \frac{\color{blue}{\mathsf{expm1}\left(i\right)}}{\frac{i}{n}} \]
    5. Applied rewrites75.7%

      \[\leadsto 100 \cdot \frac{\color{blue}{\mathsf{expm1}\left(i\right)}}{\frac{i}{n}} \]

    if 0.0 < (/.f64 (-.f64 (pow.f64 (+.f64 #s(literal 1 binary64) (/.f64 i n)) n) #s(literal 1 binary64)) (/.f64 i n)) < +inf.0

    1. Initial program 95.8%

      \[100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}} \]
    2. Add Preprocessing
    3. Step-by-step derivation
      1. lift--.f64N/A

        \[\leadsto 100 \cdot \frac{\color{blue}{{\left(1 + \frac{i}{n}\right)}^{n} - 1}}{\frac{i}{n}} \]
      2. lift-pow.f64N/A

        \[\leadsto 100 \cdot \frac{\color{blue}{{\left(1 + \frac{i}{n}\right)}^{n}} - 1}{\frac{i}{n}} \]
      3. pow-to-expN/A

        \[\leadsto 100 \cdot \frac{\color{blue}{e^{\log \left(1 + \frac{i}{n}\right) \cdot n}} - 1}{\frac{i}{n}} \]
      4. lower-expm1.f64N/A

        \[\leadsto 100 \cdot \frac{\color{blue}{\mathsf{expm1}\left(\log \left(1 + \frac{i}{n}\right) \cdot n\right)}}{\frac{i}{n}} \]
      5. *-commutativeN/A

        \[\leadsto 100 \cdot \frac{\mathsf{expm1}\left(\color{blue}{n \cdot \log \left(1 + \frac{i}{n}\right)}\right)}{\frac{i}{n}} \]
      6. lower-*.f64N/A

        \[\leadsto 100 \cdot \frac{\mathsf{expm1}\left(\color{blue}{n \cdot \log \left(1 + \frac{i}{n}\right)}\right)}{\frac{i}{n}} \]
      7. lift-+.f64N/A

        \[\leadsto 100 \cdot \frac{\mathsf{expm1}\left(n \cdot \log \color{blue}{\left(1 + \frac{i}{n}\right)}\right)}{\frac{i}{n}} \]
      8. lower-log1p.f6451.8

        \[\leadsto 100 \cdot \frac{\mathsf{expm1}\left(n \cdot \color{blue}{\mathsf{log1p}\left(\frac{i}{n}\right)}\right)}{\frac{i}{n}} \]
    4. Applied rewrites51.8%

      \[\leadsto 100 \cdot \frac{\color{blue}{\mathsf{expm1}\left(n \cdot \mathsf{log1p}\left(\frac{i}{n}\right)\right)}}{\frac{i}{n}} \]
    5. Step-by-step derivation
      1. lift-/.f64N/A

        \[\leadsto 100 \cdot \color{blue}{\frac{\mathsf{expm1}\left(n \cdot \mathsf{log1p}\left(\frac{i}{n}\right)\right)}{\frac{i}{n}}} \]
      2. lift-expm1.f64N/A

        \[\leadsto 100 \cdot \frac{\color{blue}{e^{n \cdot \mathsf{log1p}\left(\frac{i}{n}\right)} - 1}}{\frac{i}{n}} \]
      3. div-subN/A

        \[\leadsto 100 \cdot \color{blue}{\left(\frac{e^{n \cdot \mathsf{log1p}\left(\frac{i}{n}\right)}}{\frac{i}{n}} - \frac{1}{\frac{i}{n}}\right)} \]
      4. lift-*.f64N/A

        \[\leadsto 100 \cdot \left(\frac{e^{\color{blue}{n \cdot \mathsf{log1p}\left(\frac{i}{n}\right)}}}{\frac{i}{n}} - \frac{1}{\frac{i}{n}}\right) \]
      5. *-commutativeN/A

        \[\leadsto 100 \cdot \left(\frac{e^{\color{blue}{\mathsf{log1p}\left(\frac{i}{n}\right) \cdot n}}}{\frac{i}{n}} - \frac{1}{\frac{i}{n}}\right) \]
      6. lift-log1p.f64N/A

        \[\leadsto 100 \cdot \left(\frac{e^{\color{blue}{\log \left(1 + \frac{i}{n}\right)} \cdot n}}{\frac{i}{n}} - \frac{1}{\frac{i}{n}}\right) \]
      7. lift-+.f64N/A

        \[\leadsto 100 \cdot \left(\frac{e^{\log \color{blue}{\left(1 + \frac{i}{n}\right)} \cdot n}}{\frac{i}{n}} - \frac{1}{\frac{i}{n}}\right) \]
      8. pow-to-expN/A

        \[\leadsto 100 \cdot \left(\frac{\color{blue}{{\left(1 + \frac{i}{n}\right)}^{n}}}{\frac{i}{n}} - \frac{1}{\frac{i}{n}}\right) \]
      9. lift-pow.f64N/A

        \[\leadsto 100 \cdot \left(\frac{\color{blue}{{\left(1 + \frac{i}{n}\right)}^{n}}}{\frac{i}{n}} - \frac{1}{\frac{i}{n}}\right) \]
      10. div-invN/A

        \[\leadsto 100 \cdot \left(\color{blue}{{\left(1 + \frac{i}{n}\right)}^{n} \cdot \frac{1}{\frac{i}{n}}} - \frac{1}{\frac{i}{n}}\right) \]
      11. lift-/.f64N/A

        \[\leadsto 100 \cdot \left({\left(1 + \frac{i}{n}\right)}^{n} \cdot \frac{1}{\color{blue}{\frac{i}{n}}} - \frac{1}{\frac{i}{n}}\right) \]
      12. clear-numN/A

        \[\leadsto 100 \cdot \left({\left(1 + \frac{i}{n}\right)}^{n} \cdot \color{blue}{\frac{n}{i}} - \frac{1}{\frac{i}{n}}\right) \]
      13. associate-/l*N/A

        \[\leadsto 100 \cdot \left(\color{blue}{\frac{{\left(1 + \frac{i}{n}\right)}^{n} \cdot n}{i}} - \frac{1}{\frac{i}{n}}\right) \]
      14. lift-*.f64N/A

        \[\leadsto 100 \cdot \left(\frac{\color{blue}{{\left(1 + \frac{i}{n}\right)}^{n} \cdot n}}{i} - \frac{1}{\frac{i}{n}}\right) \]
      15. lift-/.f64N/A

        \[\leadsto 100 \cdot \left(\color{blue}{\frac{{\left(1 + \frac{i}{n}\right)}^{n} \cdot n}{i}} - \frac{1}{\frac{i}{n}}\right) \]
      16. lift-/.f64N/A

        \[\leadsto 100 \cdot \left(\frac{{\left(1 + \frac{i}{n}\right)}^{n} \cdot n}{i} - \frac{1}{\color{blue}{\frac{i}{n}}}\right) \]
      17. clear-numN/A

        \[\leadsto 100 \cdot \left(\frac{{\left(1 + \frac{i}{n}\right)}^{n} \cdot n}{i} - \color{blue}{\frac{n}{i}}\right) \]
      18. lift-/.f64N/A

        \[\leadsto 100 \cdot \left(\frac{{\left(1 + \frac{i}{n}\right)}^{n} \cdot n}{i} - \color{blue}{\frac{n}{i}}\right) \]
    6. Applied rewrites96.0%

      \[\leadsto 100 \cdot \color{blue}{\left({\left(\frac{i}{n} + 1\right)}^{n} \cdot \frac{n}{i} - \frac{n}{i}\right)} \]

    if +inf.0 < (/.f64 (-.f64 (pow.f64 (+.f64 #s(literal 1 binary64) (/.f64 i n)) n) #s(literal 1 binary64)) (/.f64 i n))

    1. Initial program 0.0%

      \[100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}} \]
    2. Add Preprocessing
    3. Taylor expanded in i around 0

      \[\leadsto \color{blue}{100 \cdot n} \]
    4. Step-by-step derivation
      1. *-commutativeN/A

        \[\leadsto \color{blue}{n \cdot 100} \]
      2. lower-*.f6480.8

        \[\leadsto \color{blue}{n \cdot 100} \]
    5. Applied rewrites80.8%

      \[\leadsto \color{blue}{n \cdot 100} \]
  3. Recombined 4 regimes into one program.
  4. Final simplification80.1%

    \[\leadsto \begin{array}{l} \mathbf{if}\;\frac{{\left(1 + \frac{i}{n}\right)}^{n} + -1}{\frac{i}{n}} \leq -5 \cdot 10^{-196}:\\ \;\;\;\;n \cdot \frac{\mathsf{fma}\left({\left(1 + \frac{i}{n}\right)}^{n}, 100, -100\right)}{i}\\ \mathbf{elif}\;\frac{{\left(1 + \frac{i}{n}\right)}^{n} + -1}{\frac{i}{n}} \leq 0:\\ \;\;\;\;100 \cdot \frac{\mathsf{expm1}\left(i\right)}{\frac{i}{n}}\\ \mathbf{elif}\;\frac{{\left(1 + \frac{i}{n}\right)}^{n} + -1}{\frac{i}{n}} \leq \infty:\\ \;\;\;\;100 \cdot \left({\left(1 + \frac{i}{n}\right)}^{n} \cdot \frac{n}{i} - \frac{n}{i}\right)\\ \mathbf{else}:\\ \;\;\;\;n \cdot 100\\ \end{array} \]
  5. Add Preprocessing

Alternative 3: 80.6% accurate, 0.3× speedup?

\[\begin{array}{l} \\ \begin{array}{l} t_0 := {\left(1 + \frac{i}{n}\right)}^{n}\\ t_1 := \mathsf{fma}\left(t\_0, 100, -100\right)\\ t_2 := \frac{t\_0 + -1}{\frac{i}{n}}\\ \mathbf{if}\;t\_2 \leq -5 \cdot 10^{-196}:\\ \;\;\;\;n \cdot \frac{t\_1}{i}\\ \mathbf{elif}\;t\_2 \leq 0:\\ \;\;\;\;100 \cdot \frac{\mathsf{expm1}\left(i\right)}{\frac{i}{n}}\\ \mathbf{elif}\;t\_2 \leq \infty:\\ \;\;\;\;t\_1 \cdot \frac{n}{i}\\ \mathbf{else}:\\ \;\;\;\;n \cdot 100\\ \end{array} \end{array} \]
(FPCore (i n)
 :precision binary64
 (let* ((t_0 (pow (+ 1.0 (/ i n)) n))
        (t_1 (fma t_0 100.0 -100.0))
        (t_2 (/ (+ t_0 -1.0) (/ i n))))
   (if (<= t_2 -5e-196)
     (* n (/ t_1 i))
     (if (<= t_2 0.0)
       (* 100.0 (/ (expm1 i) (/ i n)))
       (if (<= t_2 INFINITY) (* t_1 (/ n i)) (* n 100.0))))))
double code(double i, double n) {
	double t_0 = pow((1.0 + (i / n)), n);
	double t_1 = fma(t_0, 100.0, -100.0);
	double t_2 = (t_0 + -1.0) / (i / n);
	double tmp;
	if (t_2 <= -5e-196) {
		tmp = n * (t_1 / i);
	} else if (t_2 <= 0.0) {
		tmp = 100.0 * (expm1(i) / (i / n));
	} else if (t_2 <= ((double) INFINITY)) {
		tmp = t_1 * (n / i);
	} else {
		tmp = n * 100.0;
	}
	return tmp;
}
function code(i, n)
	t_0 = Float64(1.0 + Float64(i / n)) ^ n
	t_1 = fma(t_0, 100.0, -100.0)
	t_2 = Float64(Float64(t_0 + -1.0) / Float64(i / n))
	tmp = 0.0
	if (t_2 <= -5e-196)
		tmp = Float64(n * Float64(t_1 / i));
	elseif (t_2 <= 0.0)
		tmp = Float64(100.0 * Float64(expm1(i) / Float64(i / n)));
	elseif (t_2 <= Inf)
		tmp = Float64(t_1 * Float64(n / i));
	else
		tmp = Float64(n * 100.0);
	end
	return tmp
end
code[i_, n_] := Block[{t$95$0 = N[Power[N[(1.0 + N[(i / n), $MachinePrecision]), $MachinePrecision], n], $MachinePrecision]}, Block[{t$95$1 = N[(t$95$0 * 100.0 + -100.0), $MachinePrecision]}, Block[{t$95$2 = N[(N[(t$95$0 + -1.0), $MachinePrecision] / N[(i / n), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[t$95$2, -5e-196], N[(n * N[(t$95$1 / i), $MachinePrecision]), $MachinePrecision], If[LessEqual[t$95$2, 0.0], N[(100.0 * N[(N[(Exp[i] - 1), $MachinePrecision] / N[(i / n), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], If[LessEqual[t$95$2, Infinity], N[(t$95$1 * N[(n / i), $MachinePrecision]), $MachinePrecision], N[(n * 100.0), $MachinePrecision]]]]]]]
\begin{array}{l}

\\
\begin{array}{l}
t_0 := {\left(1 + \frac{i}{n}\right)}^{n}\\
t_1 := \mathsf{fma}\left(t\_0, 100, -100\right)\\
t_2 := \frac{t\_0 + -1}{\frac{i}{n}}\\
\mathbf{if}\;t\_2 \leq -5 \cdot 10^{-196}:\\
\;\;\;\;n \cdot \frac{t\_1}{i}\\

\mathbf{elif}\;t\_2 \leq 0:\\
\;\;\;\;100 \cdot \frac{\mathsf{expm1}\left(i\right)}{\frac{i}{n}}\\

\mathbf{elif}\;t\_2 \leq \infty:\\
\;\;\;\;t\_1 \cdot \frac{n}{i}\\

\mathbf{else}:\\
\;\;\;\;n \cdot 100\\


\end{array}
\end{array}
Derivation
  1. Split input into 4 regimes
  2. if (/.f64 (-.f64 (pow.f64 (+.f64 #s(literal 1 binary64) (/.f64 i n)) n) #s(literal 1 binary64)) (/.f64 i n)) < -5.0000000000000005e-196

    1. Initial program 90.9%

      \[100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}} \]
    2. Add Preprocessing
    3. Step-by-step derivation
      1. lift-*.f64N/A

        \[\leadsto \color{blue}{100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}}} \]
      2. lift-/.f64N/A

        \[\leadsto 100 \cdot \color{blue}{\frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}}} \]
      3. associate-*r/N/A

        \[\leadsto \color{blue}{\frac{100 \cdot \left({\left(1 + \frac{i}{n}\right)}^{n} - 1\right)}{\frac{i}{n}}} \]
      4. lift-/.f64N/A

        \[\leadsto \frac{100 \cdot \left({\left(1 + \frac{i}{n}\right)}^{n} - 1\right)}{\color{blue}{\frac{i}{n}}} \]
      5. associate-/r/N/A

        \[\leadsto \color{blue}{\frac{100 \cdot \left({\left(1 + \frac{i}{n}\right)}^{n} - 1\right)}{i} \cdot n} \]
      6. lower-*.f64N/A

        \[\leadsto \color{blue}{\frac{100 \cdot \left({\left(1 + \frac{i}{n}\right)}^{n} - 1\right)}{i} \cdot n} \]
      7. lower-/.f64N/A

        \[\leadsto \color{blue}{\frac{100 \cdot \left({\left(1 + \frac{i}{n}\right)}^{n} - 1\right)}{i}} \cdot n \]
      8. lift--.f64N/A

        \[\leadsto \frac{100 \cdot \color{blue}{\left({\left(1 + \frac{i}{n}\right)}^{n} - 1\right)}}{i} \cdot n \]
      9. sub-negN/A

        \[\leadsto \frac{100 \cdot \color{blue}{\left({\left(1 + \frac{i}{n}\right)}^{n} + \left(\mathsf{neg}\left(1\right)\right)\right)}}{i} \cdot n \]
      10. distribute-lft-inN/A

        \[\leadsto \frac{\color{blue}{100 \cdot {\left(1 + \frac{i}{n}\right)}^{n} + 100 \cdot \left(\mathsf{neg}\left(1\right)\right)}}{i} \cdot n \]
      11. *-commutativeN/A

        \[\leadsto \frac{\color{blue}{{\left(1 + \frac{i}{n}\right)}^{n} \cdot 100} + 100 \cdot \left(\mathsf{neg}\left(1\right)\right)}{i} \cdot n \]
      12. lower-fma.f64N/A

        \[\leadsto \frac{\color{blue}{\mathsf{fma}\left({\left(1 + \frac{i}{n}\right)}^{n}, 100, 100 \cdot \left(\mathsf{neg}\left(1\right)\right)\right)}}{i} \cdot n \]
      13. metadata-evalN/A

        \[\leadsto \frac{\mathsf{fma}\left({\left(1 + \frac{i}{n}\right)}^{n}, 100, 100 \cdot \color{blue}{-1}\right)}{i} \cdot n \]
      14. metadata-eval91.1

        \[\leadsto \frac{\mathsf{fma}\left({\left(1 + \frac{i}{n}\right)}^{n}, 100, \color{blue}{-100}\right)}{i} \cdot n \]
    4. Applied rewrites91.1%

      \[\leadsto \color{blue}{\frac{\mathsf{fma}\left({\left(1 + \frac{i}{n}\right)}^{n}, 100, -100\right)}{i} \cdot n} \]

    if -5.0000000000000005e-196 < (/.f64 (-.f64 (pow.f64 (+.f64 #s(literal 1 binary64) (/.f64 i n)) n) #s(literal 1 binary64)) (/.f64 i n)) < 0.0

    1. Initial program 18.4%

      \[100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}} \]
    2. Add Preprocessing
    3. Taylor expanded in n around inf

      \[\leadsto 100 \cdot \frac{\color{blue}{e^{i} - 1}}{\frac{i}{n}} \]
    4. Step-by-step derivation
      1. lower-expm1.f6475.7

        \[\leadsto 100 \cdot \frac{\color{blue}{\mathsf{expm1}\left(i\right)}}{\frac{i}{n}} \]
    5. Applied rewrites75.7%

      \[\leadsto 100 \cdot \frac{\color{blue}{\mathsf{expm1}\left(i\right)}}{\frac{i}{n}} \]

    if 0.0 < (/.f64 (-.f64 (pow.f64 (+.f64 #s(literal 1 binary64) (/.f64 i n)) n) #s(literal 1 binary64)) (/.f64 i n)) < +inf.0

    1. Initial program 95.8%

      \[100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}} \]
    2. Add Preprocessing
    3. Step-by-step derivation
      1. lift-*.f64N/A

        \[\leadsto \color{blue}{100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}}} \]
      2. lift-/.f64N/A

        \[\leadsto 100 \cdot \color{blue}{\frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}}} \]
      3. associate-*r/N/A

        \[\leadsto \color{blue}{\frac{100 \cdot \left({\left(1 + \frac{i}{n}\right)}^{n} - 1\right)}{\frac{i}{n}}} \]
      4. div-invN/A

        \[\leadsto \color{blue}{\left(100 \cdot \left({\left(1 + \frac{i}{n}\right)}^{n} - 1\right)\right) \cdot \frac{1}{\frac{i}{n}}} \]
      5. lift-/.f64N/A

        \[\leadsto \left(100 \cdot \left({\left(1 + \frac{i}{n}\right)}^{n} - 1\right)\right) \cdot \frac{1}{\color{blue}{\frac{i}{n}}} \]
      6. clear-numN/A

        \[\leadsto \left(100 \cdot \left({\left(1 + \frac{i}{n}\right)}^{n} - 1\right)\right) \cdot \color{blue}{\frac{n}{i}} \]
      7. lower-*.f64N/A

        \[\leadsto \color{blue}{\left(100 \cdot \left({\left(1 + \frac{i}{n}\right)}^{n} - 1\right)\right) \cdot \frac{n}{i}} \]
      8. lift--.f64N/A

        \[\leadsto \left(100 \cdot \color{blue}{\left({\left(1 + \frac{i}{n}\right)}^{n} - 1\right)}\right) \cdot \frac{n}{i} \]
      9. sub-negN/A

        \[\leadsto \left(100 \cdot \color{blue}{\left({\left(1 + \frac{i}{n}\right)}^{n} + \left(\mathsf{neg}\left(1\right)\right)\right)}\right) \cdot \frac{n}{i} \]
      10. distribute-lft-inN/A

        \[\leadsto \color{blue}{\left(100 \cdot {\left(1 + \frac{i}{n}\right)}^{n} + 100 \cdot \left(\mathsf{neg}\left(1\right)\right)\right)} \cdot \frac{n}{i} \]
      11. *-commutativeN/A

        \[\leadsto \left(\color{blue}{{\left(1 + \frac{i}{n}\right)}^{n} \cdot 100} + 100 \cdot \left(\mathsf{neg}\left(1\right)\right)\right) \cdot \frac{n}{i} \]
      12. lower-fma.f64N/A

        \[\leadsto \color{blue}{\mathsf{fma}\left({\left(1 + \frac{i}{n}\right)}^{n}, 100, 100 \cdot \left(\mathsf{neg}\left(1\right)\right)\right)} \cdot \frac{n}{i} \]
      13. metadata-evalN/A

        \[\leadsto \mathsf{fma}\left({\left(1 + \frac{i}{n}\right)}^{n}, 100, 100 \cdot \color{blue}{-1}\right) \cdot \frac{n}{i} \]
      14. metadata-evalN/A

        \[\leadsto \mathsf{fma}\left({\left(1 + \frac{i}{n}\right)}^{n}, 100, \color{blue}{-100}\right) \cdot \frac{n}{i} \]
      15. lower-/.f6495.9

        \[\leadsto \mathsf{fma}\left({\left(1 + \frac{i}{n}\right)}^{n}, 100, -100\right) \cdot \color{blue}{\frac{n}{i}} \]
    4. Applied rewrites95.9%

      \[\leadsto \color{blue}{\mathsf{fma}\left({\left(1 + \frac{i}{n}\right)}^{n}, 100, -100\right) \cdot \frac{n}{i}} \]

    if +inf.0 < (/.f64 (-.f64 (pow.f64 (+.f64 #s(literal 1 binary64) (/.f64 i n)) n) #s(literal 1 binary64)) (/.f64 i n))

    1. Initial program 0.0%

      \[100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}} \]
    2. Add Preprocessing
    3. Taylor expanded in i around 0

      \[\leadsto \color{blue}{100 \cdot n} \]
    4. Step-by-step derivation
      1. *-commutativeN/A

        \[\leadsto \color{blue}{n \cdot 100} \]
      2. lower-*.f6480.8

        \[\leadsto \color{blue}{n \cdot 100} \]
    5. Applied rewrites80.8%

      \[\leadsto \color{blue}{n \cdot 100} \]
  3. Recombined 4 regimes into one program.
  4. Final simplification80.1%

    \[\leadsto \begin{array}{l} \mathbf{if}\;\frac{{\left(1 + \frac{i}{n}\right)}^{n} + -1}{\frac{i}{n}} \leq -5 \cdot 10^{-196}:\\ \;\;\;\;n \cdot \frac{\mathsf{fma}\left({\left(1 + \frac{i}{n}\right)}^{n}, 100, -100\right)}{i}\\ \mathbf{elif}\;\frac{{\left(1 + \frac{i}{n}\right)}^{n} + -1}{\frac{i}{n}} \leq 0:\\ \;\;\;\;100 \cdot \frac{\mathsf{expm1}\left(i\right)}{\frac{i}{n}}\\ \mathbf{elif}\;\frac{{\left(1 + \frac{i}{n}\right)}^{n} + -1}{\frac{i}{n}} \leq \infty:\\ \;\;\;\;\mathsf{fma}\left({\left(1 + \frac{i}{n}\right)}^{n}, 100, -100\right) \cdot \frac{n}{i}\\ \mathbf{else}:\\ \;\;\;\;n \cdot 100\\ \end{array} \]
  5. Add Preprocessing

Alternative 4: 80.6% accurate, 0.3× speedup?

\[\begin{array}{l} \\ \begin{array}{l} t_0 := {\left(1 + \frac{i}{n}\right)}^{n}\\ t_1 := \frac{t\_0 + -1}{\frac{i}{n}}\\ t_2 := n \cdot \frac{\mathsf{fma}\left(t\_0, 100, -100\right)}{i}\\ \mathbf{if}\;t\_1 \leq -5 \cdot 10^{-196}:\\ \;\;\;\;t\_2\\ \mathbf{elif}\;t\_1 \leq 0:\\ \;\;\;\;100 \cdot \frac{\mathsf{expm1}\left(i\right)}{\frac{i}{n}}\\ \mathbf{elif}\;t\_1 \leq \infty:\\ \;\;\;\;t\_2\\ \mathbf{else}:\\ \;\;\;\;n \cdot 100\\ \end{array} \end{array} \]
(FPCore (i n)
 :precision binary64
 (let* ((t_0 (pow (+ 1.0 (/ i n)) n))
        (t_1 (/ (+ t_0 -1.0) (/ i n)))
        (t_2 (* n (/ (fma t_0 100.0 -100.0) i))))
   (if (<= t_1 -5e-196)
     t_2
     (if (<= t_1 0.0)
       (* 100.0 (/ (expm1 i) (/ i n)))
       (if (<= t_1 INFINITY) t_2 (* n 100.0))))))
double code(double i, double n) {
	double t_0 = pow((1.0 + (i / n)), n);
	double t_1 = (t_0 + -1.0) / (i / n);
	double t_2 = n * (fma(t_0, 100.0, -100.0) / i);
	double tmp;
	if (t_1 <= -5e-196) {
		tmp = t_2;
	} else if (t_1 <= 0.0) {
		tmp = 100.0 * (expm1(i) / (i / n));
	} else if (t_1 <= ((double) INFINITY)) {
		tmp = t_2;
	} else {
		tmp = n * 100.0;
	}
	return tmp;
}
function code(i, n)
	t_0 = Float64(1.0 + Float64(i / n)) ^ n
	t_1 = Float64(Float64(t_0 + -1.0) / Float64(i / n))
	t_2 = Float64(n * Float64(fma(t_0, 100.0, -100.0) / i))
	tmp = 0.0
	if (t_1 <= -5e-196)
		tmp = t_2;
	elseif (t_1 <= 0.0)
		tmp = Float64(100.0 * Float64(expm1(i) / Float64(i / n)));
	elseif (t_1 <= Inf)
		tmp = t_2;
	else
		tmp = Float64(n * 100.0);
	end
	return tmp
end
code[i_, n_] := Block[{t$95$0 = N[Power[N[(1.0 + N[(i / n), $MachinePrecision]), $MachinePrecision], n], $MachinePrecision]}, Block[{t$95$1 = N[(N[(t$95$0 + -1.0), $MachinePrecision] / N[(i / n), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$2 = N[(n * N[(N[(t$95$0 * 100.0 + -100.0), $MachinePrecision] / i), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[t$95$1, -5e-196], t$95$2, If[LessEqual[t$95$1, 0.0], N[(100.0 * N[(N[(Exp[i] - 1), $MachinePrecision] / N[(i / n), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], If[LessEqual[t$95$1, Infinity], t$95$2, N[(n * 100.0), $MachinePrecision]]]]]]]
\begin{array}{l}

\\
\begin{array}{l}
t_0 := {\left(1 + \frac{i}{n}\right)}^{n}\\
t_1 := \frac{t\_0 + -1}{\frac{i}{n}}\\
t_2 := n \cdot \frac{\mathsf{fma}\left(t\_0, 100, -100\right)}{i}\\
\mathbf{if}\;t\_1 \leq -5 \cdot 10^{-196}:\\
\;\;\;\;t\_2\\

\mathbf{elif}\;t\_1 \leq 0:\\
\;\;\;\;100 \cdot \frac{\mathsf{expm1}\left(i\right)}{\frac{i}{n}}\\

\mathbf{elif}\;t\_1 \leq \infty:\\
\;\;\;\;t\_2\\

\mathbf{else}:\\
\;\;\;\;n \cdot 100\\


\end{array}
\end{array}
Derivation
  1. Split input into 3 regimes
  2. if (/.f64 (-.f64 (pow.f64 (+.f64 #s(literal 1 binary64) (/.f64 i n)) n) #s(literal 1 binary64)) (/.f64 i n)) < -5.0000000000000005e-196 or 0.0 < (/.f64 (-.f64 (pow.f64 (+.f64 #s(literal 1 binary64) (/.f64 i n)) n) #s(literal 1 binary64)) (/.f64 i n)) < +inf.0

    1. Initial program 93.5%

      \[100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}} \]
    2. Add Preprocessing
    3. Step-by-step derivation
      1. lift-*.f64N/A

        \[\leadsto \color{blue}{100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}}} \]
      2. lift-/.f64N/A

        \[\leadsto 100 \cdot \color{blue}{\frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}}} \]
      3. associate-*r/N/A

        \[\leadsto \color{blue}{\frac{100 \cdot \left({\left(1 + \frac{i}{n}\right)}^{n} - 1\right)}{\frac{i}{n}}} \]
      4. lift-/.f64N/A

        \[\leadsto \frac{100 \cdot \left({\left(1 + \frac{i}{n}\right)}^{n} - 1\right)}{\color{blue}{\frac{i}{n}}} \]
      5. associate-/r/N/A

        \[\leadsto \color{blue}{\frac{100 \cdot \left({\left(1 + \frac{i}{n}\right)}^{n} - 1\right)}{i} \cdot n} \]
      6. lower-*.f64N/A

        \[\leadsto \color{blue}{\frac{100 \cdot \left({\left(1 + \frac{i}{n}\right)}^{n} - 1\right)}{i} \cdot n} \]
      7. lower-/.f64N/A

        \[\leadsto \color{blue}{\frac{100 \cdot \left({\left(1 + \frac{i}{n}\right)}^{n} - 1\right)}{i}} \cdot n \]
      8. lift--.f64N/A

        \[\leadsto \frac{100 \cdot \color{blue}{\left({\left(1 + \frac{i}{n}\right)}^{n} - 1\right)}}{i} \cdot n \]
      9. sub-negN/A

        \[\leadsto \frac{100 \cdot \color{blue}{\left({\left(1 + \frac{i}{n}\right)}^{n} + \left(\mathsf{neg}\left(1\right)\right)\right)}}{i} \cdot n \]
      10. distribute-lft-inN/A

        \[\leadsto \frac{\color{blue}{100 \cdot {\left(1 + \frac{i}{n}\right)}^{n} + 100 \cdot \left(\mathsf{neg}\left(1\right)\right)}}{i} \cdot n \]
      11. *-commutativeN/A

        \[\leadsto \frac{\color{blue}{{\left(1 + \frac{i}{n}\right)}^{n} \cdot 100} + 100 \cdot \left(\mathsf{neg}\left(1\right)\right)}{i} \cdot n \]
      12. lower-fma.f64N/A

        \[\leadsto \frac{\color{blue}{\mathsf{fma}\left({\left(1 + \frac{i}{n}\right)}^{n}, 100, 100 \cdot \left(\mathsf{neg}\left(1\right)\right)\right)}}{i} \cdot n \]
      13. metadata-evalN/A

        \[\leadsto \frac{\mathsf{fma}\left({\left(1 + \frac{i}{n}\right)}^{n}, 100, 100 \cdot \color{blue}{-1}\right)}{i} \cdot n \]
      14. metadata-eval93.5

        \[\leadsto \frac{\mathsf{fma}\left({\left(1 + \frac{i}{n}\right)}^{n}, 100, \color{blue}{-100}\right)}{i} \cdot n \]
    4. Applied rewrites93.5%

      \[\leadsto \color{blue}{\frac{\mathsf{fma}\left({\left(1 + \frac{i}{n}\right)}^{n}, 100, -100\right)}{i} \cdot n} \]

    if -5.0000000000000005e-196 < (/.f64 (-.f64 (pow.f64 (+.f64 #s(literal 1 binary64) (/.f64 i n)) n) #s(literal 1 binary64)) (/.f64 i n)) < 0.0

    1. Initial program 18.4%

      \[100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}} \]
    2. Add Preprocessing
    3. Taylor expanded in n around inf

      \[\leadsto 100 \cdot \frac{\color{blue}{e^{i} - 1}}{\frac{i}{n}} \]
    4. Step-by-step derivation
      1. lower-expm1.f6475.7

        \[\leadsto 100 \cdot \frac{\color{blue}{\mathsf{expm1}\left(i\right)}}{\frac{i}{n}} \]
    5. Applied rewrites75.7%

      \[\leadsto 100 \cdot \frac{\color{blue}{\mathsf{expm1}\left(i\right)}}{\frac{i}{n}} \]

    if +inf.0 < (/.f64 (-.f64 (pow.f64 (+.f64 #s(literal 1 binary64) (/.f64 i n)) n) #s(literal 1 binary64)) (/.f64 i n))

    1. Initial program 0.0%

      \[100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}} \]
    2. Add Preprocessing
    3. Taylor expanded in i around 0

      \[\leadsto \color{blue}{100 \cdot n} \]
    4. Step-by-step derivation
      1. *-commutativeN/A

        \[\leadsto \color{blue}{n \cdot 100} \]
      2. lower-*.f6480.8

        \[\leadsto \color{blue}{n \cdot 100} \]
    5. Applied rewrites80.8%

      \[\leadsto \color{blue}{n \cdot 100} \]
  3. Recombined 3 regimes into one program.
  4. Final simplification80.1%

    \[\leadsto \begin{array}{l} \mathbf{if}\;\frac{{\left(1 + \frac{i}{n}\right)}^{n} + -1}{\frac{i}{n}} \leq -5 \cdot 10^{-196}:\\ \;\;\;\;n \cdot \frac{\mathsf{fma}\left({\left(1 + \frac{i}{n}\right)}^{n}, 100, -100\right)}{i}\\ \mathbf{elif}\;\frac{{\left(1 + \frac{i}{n}\right)}^{n} + -1}{\frac{i}{n}} \leq 0:\\ \;\;\;\;100 \cdot \frac{\mathsf{expm1}\left(i\right)}{\frac{i}{n}}\\ \mathbf{elif}\;\frac{{\left(1 + \frac{i}{n}\right)}^{n} + -1}{\frac{i}{n}} \leq \infty:\\ \;\;\;\;n \cdot \frac{\mathsf{fma}\left({\left(1 + \frac{i}{n}\right)}^{n}, 100, -100\right)}{i}\\ \mathbf{else}:\\ \;\;\;\;n \cdot 100\\ \end{array} \]
  5. Add Preprocessing

Alternative 5: 77.4% accurate, 0.6× speedup?

\[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;i \leq 1.35 \cdot 10^{-180}:\\ \;\;\;\;n \cdot \mathsf{fma}\left(\frac{i \cdot e^{i}}{n}, -50, 100 \cdot \frac{\mathsf{expm1}\left(i\right)}{i}\right)\\ \mathbf{elif}\;i \leq 4.5 \cdot 10^{+63}:\\ \;\;\;\;100 \cdot \frac{n \cdot \mathsf{expm1}\left(i\right)}{i}\\ \mathbf{else}:\\ \;\;\;\;100 \cdot \frac{\frac{i}{n} \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n}}{i} + \frac{-1}{n}}{\frac{\frac{i}{n}}{n}}\\ \end{array} \end{array} \]
(FPCore (i n)
 :precision binary64
 (if (<= i 1.35e-180)
   (* n (fma (/ (* i (exp i)) n) -50.0 (* 100.0 (/ (expm1 i) i))))
   (if (<= i 4.5e+63)
     (* 100.0 (/ (* n (expm1 i)) i))
     (*
      100.0
      (/
       (+ (* (/ i n) (/ (pow (+ 1.0 (/ i n)) n) i)) (/ -1.0 n))
       (/ (/ i n) n))))))
double code(double i, double n) {
	double tmp;
	if (i <= 1.35e-180) {
		tmp = n * fma(((i * exp(i)) / n), -50.0, (100.0 * (expm1(i) / i)));
	} else if (i <= 4.5e+63) {
		tmp = 100.0 * ((n * expm1(i)) / i);
	} else {
		tmp = 100.0 * ((((i / n) * (pow((1.0 + (i / n)), n) / i)) + (-1.0 / n)) / ((i / n) / n));
	}
	return tmp;
}
function code(i, n)
	tmp = 0.0
	if (i <= 1.35e-180)
		tmp = Float64(n * fma(Float64(Float64(i * exp(i)) / n), -50.0, Float64(100.0 * Float64(expm1(i) / i))));
	elseif (i <= 4.5e+63)
		tmp = Float64(100.0 * Float64(Float64(n * expm1(i)) / i));
	else
		tmp = Float64(100.0 * Float64(Float64(Float64(Float64(i / n) * Float64((Float64(1.0 + Float64(i / n)) ^ n) / i)) + Float64(-1.0 / n)) / Float64(Float64(i / n) / n)));
	end
	return tmp
end
code[i_, n_] := If[LessEqual[i, 1.35e-180], N[(n * N[(N[(N[(i * N[Exp[i], $MachinePrecision]), $MachinePrecision] / n), $MachinePrecision] * -50.0 + N[(100.0 * N[(N[(Exp[i] - 1), $MachinePrecision] / i), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], If[LessEqual[i, 4.5e+63], N[(100.0 * N[(N[(n * N[(Exp[i] - 1), $MachinePrecision]), $MachinePrecision] / i), $MachinePrecision]), $MachinePrecision], N[(100.0 * N[(N[(N[(N[(i / n), $MachinePrecision] * N[(N[Power[N[(1.0 + N[(i / n), $MachinePrecision]), $MachinePrecision], n], $MachinePrecision] / i), $MachinePrecision]), $MachinePrecision] + N[(-1.0 / n), $MachinePrecision]), $MachinePrecision] / N[(N[(i / n), $MachinePrecision] / n), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]]]
\begin{array}{l}

\\
\begin{array}{l}
\mathbf{if}\;i \leq 1.35 \cdot 10^{-180}:\\
\;\;\;\;n \cdot \mathsf{fma}\left(\frac{i \cdot e^{i}}{n}, -50, 100 \cdot \frac{\mathsf{expm1}\left(i\right)}{i}\right)\\

\mathbf{elif}\;i \leq 4.5 \cdot 10^{+63}:\\
\;\;\;\;100 \cdot \frac{n \cdot \mathsf{expm1}\left(i\right)}{i}\\

\mathbf{else}:\\
\;\;\;\;100 \cdot \frac{\frac{i}{n} \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n}}{i} + \frac{-1}{n}}{\frac{\frac{i}{n}}{n}}\\


\end{array}
\end{array}
Derivation
  1. Split input into 3 regimes
  2. if i < 1.35000000000000007e-180

    1. Initial program 24.1%

      \[100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}} \]
    2. Add Preprocessing
    3. Taylor expanded in n around inf

      \[\leadsto \color{blue}{n \cdot \left(-50 \cdot \frac{i \cdot e^{i}}{n} + 100 \cdot \frac{e^{i} - 1}{i}\right)} \]
    4. Step-by-step derivation
      1. lower-*.f64N/A

        \[\leadsto \color{blue}{n \cdot \left(-50 \cdot \frac{i \cdot e^{i}}{n} + 100 \cdot \frac{e^{i} - 1}{i}\right)} \]
      2. *-commutativeN/A

        \[\leadsto n \cdot \left(\color{blue}{\frac{i \cdot e^{i}}{n} \cdot -50} + 100 \cdot \frac{e^{i} - 1}{i}\right) \]
      3. lower-fma.f64N/A

        \[\leadsto n \cdot \color{blue}{\mathsf{fma}\left(\frac{i \cdot e^{i}}{n}, -50, 100 \cdot \frac{e^{i} - 1}{i}\right)} \]
      4. lower-/.f64N/A

        \[\leadsto n \cdot \mathsf{fma}\left(\color{blue}{\frac{i \cdot e^{i}}{n}}, -50, 100 \cdot \frac{e^{i} - 1}{i}\right) \]
      5. lower-*.f64N/A

        \[\leadsto n \cdot \mathsf{fma}\left(\frac{\color{blue}{i \cdot e^{i}}}{n}, -50, 100 \cdot \frac{e^{i} - 1}{i}\right) \]
      6. lower-exp.f64N/A

        \[\leadsto n \cdot \mathsf{fma}\left(\frac{i \cdot \color{blue}{e^{i}}}{n}, -50, 100 \cdot \frac{e^{i} - 1}{i}\right) \]
      7. *-commutativeN/A

        \[\leadsto n \cdot \mathsf{fma}\left(\frac{i \cdot e^{i}}{n}, -50, \color{blue}{\frac{e^{i} - 1}{i} \cdot 100}\right) \]
      8. lower-*.f64N/A

        \[\leadsto n \cdot \mathsf{fma}\left(\frac{i \cdot e^{i}}{n}, -50, \color{blue}{\frac{e^{i} - 1}{i} \cdot 100}\right) \]
      9. lower-/.f64N/A

        \[\leadsto n \cdot \mathsf{fma}\left(\frac{i \cdot e^{i}}{n}, -50, \color{blue}{\frac{e^{i} - 1}{i}} \cdot 100\right) \]
      10. lower-expm1.f6482.9

        \[\leadsto n \cdot \mathsf{fma}\left(\frac{i \cdot e^{i}}{n}, -50, \frac{\color{blue}{\mathsf{expm1}\left(i\right)}}{i} \cdot 100\right) \]
    5. Applied rewrites82.9%

      \[\leadsto \color{blue}{n \cdot \mathsf{fma}\left(\frac{i \cdot e^{i}}{n}, -50, \frac{\mathsf{expm1}\left(i\right)}{i} \cdot 100\right)} \]

    if 1.35000000000000007e-180 < i < 4.50000000000000017e63

    1. Initial program 21.4%

      \[100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}} \]
    2. Add Preprocessing
    3. Taylor expanded in n around inf

      \[\leadsto 100 \cdot \color{blue}{\frac{n \cdot \left(e^{i} - 1\right)}{i}} \]
    4. Step-by-step derivation
      1. lower-/.f64N/A

        \[\leadsto 100 \cdot \color{blue}{\frac{n \cdot \left(e^{i} - 1\right)}{i}} \]
      2. lower-*.f64N/A

        \[\leadsto 100 \cdot \frac{\color{blue}{n \cdot \left(e^{i} - 1\right)}}{i} \]
      3. lower-expm1.f6480.3

        \[\leadsto 100 \cdot \frac{n \cdot \color{blue}{\mathsf{expm1}\left(i\right)}}{i} \]
    5. Applied rewrites80.3%

      \[\leadsto 100 \cdot \color{blue}{\frac{n \cdot \mathsf{expm1}\left(i\right)}{i}} \]

    if 4.50000000000000017e63 < i

    1. Initial program 60.5%

      \[100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}} \]
    2. Add Preprocessing
    3. Step-by-step derivation
      1. lift-/.f64N/A

        \[\leadsto 100 \cdot \color{blue}{\frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}}} \]
      2. lift--.f64N/A

        \[\leadsto 100 \cdot \frac{\color{blue}{{\left(1 + \frac{i}{n}\right)}^{n} - 1}}{\frac{i}{n}} \]
      3. div-subN/A

        \[\leadsto 100 \cdot \color{blue}{\left(\frac{{\left(1 + \frac{i}{n}\right)}^{n}}{\frac{i}{n}} - \frac{1}{\frac{i}{n}}\right)} \]
      4. lift-/.f64N/A

        \[\leadsto 100 \cdot \left(\frac{{\left(1 + \frac{i}{n}\right)}^{n}}{\color{blue}{\frac{i}{n}}} - \frac{1}{\frac{i}{n}}\right) \]
      5. div-invN/A

        \[\leadsto 100 \cdot \left(\frac{{\left(1 + \frac{i}{n}\right)}^{n}}{\color{blue}{i \cdot \frac{1}{n}}} - \frac{1}{\frac{i}{n}}\right) \]
      6. associate-/r*N/A

        \[\leadsto 100 \cdot \left(\color{blue}{\frac{\frac{{\left(1 + \frac{i}{n}\right)}^{n}}{i}}{\frac{1}{n}}} - \frac{1}{\frac{i}{n}}\right) \]
      7. frac-subN/A

        \[\leadsto 100 \cdot \color{blue}{\frac{\frac{{\left(1 + \frac{i}{n}\right)}^{n}}{i} \cdot \frac{i}{n} - \frac{1}{n} \cdot 1}{\frac{1}{n} \cdot \frac{i}{n}}} \]
      8. lower-/.f64N/A

        \[\leadsto 100 \cdot \color{blue}{\frac{\frac{{\left(1 + \frac{i}{n}\right)}^{n}}{i} \cdot \frac{i}{n} - \frac{1}{n} \cdot 1}{\frac{1}{n} \cdot \frac{i}{n}}} \]
      9. associate-/r/N/A

        \[\leadsto 100 \cdot \frac{\frac{{\left(1 + \frac{i}{n}\right)}^{n}}{i} \cdot \frac{i}{n} - \color{blue}{\frac{1}{\frac{n}{1}}}}{\frac{1}{n} \cdot \frac{i}{n}} \]
      10. clear-numN/A

        \[\leadsto 100 \cdot \frac{\frac{{\left(1 + \frac{i}{n}\right)}^{n}}{i} \cdot \frac{i}{n} - \color{blue}{\frac{1}{n}}}{\frac{1}{n} \cdot \frac{i}{n}} \]
      11. lower--.f64N/A

        \[\leadsto 100 \cdot \frac{\color{blue}{\frac{{\left(1 + \frac{i}{n}\right)}^{n}}{i} \cdot \frac{i}{n} - \frac{1}{n}}}{\frac{1}{n} \cdot \frac{i}{n}} \]
      12. lower-*.f64N/A

        \[\leadsto 100 \cdot \frac{\color{blue}{\frac{{\left(1 + \frac{i}{n}\right)}^{n}}{i} \cdot \frac{i}{n}} - \frac{1}{n}}{\frac{1}{n} \cdot \frac{i}{n}} \]
      13. lower-/.f64N/A

        \[\leadsto 100 \cdot \frac{\color{blue}{\frac{{\left(1 + \frac{i}{n}\right)}^{n}}{i}} \cdot \frac{i}{n} - \frac{1}{n}}{\frac{1}{n} \cdot \frac{i}{n}} \]
      14. lower-/.f64N/A

        \[\leadsto 100 \cdot \frac{\frac{{\left(1 + \frac{i}{n}\right)}^{n}}{i} \cdot \frac{i}{n} - \color{blue}{\frac{1}{n}}}{\frac{1}{n} \cdot \frac{i}{n}} \]
      15. lift-/.f64N/A

        \[\leadsto 100 \cdot \frac{\frac{{\left(1 + \frac{i}{n}\right)}^{n}}{i} \cdot \frac{i}{n} - \frac{1}{n}}{\frac{1}{n} \cdot \color{blue}{\frac{i}{n}}} \]
      16. associate-*r/N/A

        \[\leadsto 100 \cdot \frac{\frac{{\left(1 + \frac{i}{n}\right)}^{n}}{i} \cdot \frac{i}{n} - \frac{1}{n}}{\color{blue}{\frac{\frac{1}{n} \cdot i}{n}}} \]
    4. Applied rewrites62.6%

      \[\leadsto 100 \cdot \color{blue}{\frac{\frac{{\left(1 + \frac{i}{n}\right)}^{n}}{i} \cdot \frac{i}{n} - \frac{1}{n}}{\frac{\frac{i}{n}}{n}}} \]
  3. Recombined 3 regimes into one program.
  4. Final simplification78.8%

    \[\leadsto \begin{array}{l} \mathbf{if}\;i \leq 1.35 \cdot 10^{-180}:\\ \;\;\;\;n \cdot \mathsf{fma}\left(\frac{i \cdot e^{i}}{n}, -50, 100 \cdot \frac{\mathsf{expm1}\left(i\right)}{i}\right)\\ \mathbf{elif}\;i \leq 4.5 \cdot 10^{+63}:\\ \;\;\;\;100 \cdot \frac{n \cdot \mathsf{expm1}\left(i\right)}{i}\\ \mathbf{else}:\\ \;\;\;\;100 \cdot \frac{\frac{i}{n} \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n}}{i} + \frac{-1}{n}}{\frac{\frac{i}{n}}{n}}\\ \end{array} \]
  5. Add Preprocessing

Alternative 6: 79.7% accurate, 1.0× speedup?

\[\begin{array}{l} \\ \begin{array}{l} t_0 := 100 \cdot \frac{n \cdot \mathsf{expm1}\left(i\right)}{i}\\ \mathbf{if}\;n \leq -2.6 \cdot 10^{+76}:\\ \;\;\;\;t\_0\\ \mathbf{elif}\;n \leq -6.6 \cdot 10^{-208}:\\ \;\;\;\;100 \cdot \frac{\mathsf{expm1}\left(i\right)}{\frac{i}{n}}\\ \mathbf{elif}\;n \leq 0.0013:\\ \;\;\;\;100 \cdot \frac{\frac{1}{n}}{\frac{\frac{1}{n}}{n}}\\ \mathbf{else}:\\ \;\;\;\;t\_0\\ \end{array} \end{array} \]
(FPCore (i n)
 :precision binary64
 (let* ((t_0 (* 100.0 (/ (* n (expm1 i)) i))))
   (if (<= n -2.6e+76)
     t_0
     (if (<= n -6.6e-208)
       (* 100.0 (/ (expm1 i) (/ i n)))
       (if (<= n 0.0013) (* 100.0 (/ (/ 1.0 n) (/ (/ 1.0 n) n))) t_0)))))
double code(double i, double n) {
	double t_0 = 100.0 * ((n * expm1(i)) / i);
	double tmp;
	if (n <= -2.6e+76) {
		tmp = t_0;
	} else if (n <= -6.6e-208) {
		tmp = 100.0 * (expm1(i) / (i / n));
	} else if (n <= 0.0013) {
		tmp = 100.0 * ((1.0 / n) / ((1.0 / n) / n));
	} else {
		tmp = t_0;
	}
	return tmp;
}
public static double code(double i, double n) {
	double t_0 = 100.0 * ((n * Math.expm1(i)) / i);
	double tmp;
	if (n <= -2.6e+76) {
		tmp = t_0;
	} else if (n <= -6.6e-208) {
		tmp = 100.0 * (Math.expm1(i) / (i / n));
	} else if (n <= 0.0013) {
		tmp = 100.0 * ((1.0 / n) / ((1.0 / n) / n));
	} else {
		tmp = t_0;
	}
	return tmp;
}
def code(i, n):
	t_0 = 100.0 * ((n * math.expm1(i)) / i)
	tmp = 0
	if n <= -2.6e+76:
		tmp = t_0
	elif n <= -6.6e-208:
		tmp = 100.0 * (math.expm1(i) / (i / n))
	elif n <= 0.0013:
		tmp = 100.0 * ((1.0 / n) / ((1.0 / n) / n))
	else:
		tmp = t_0
	return tmp
function code(i, n)
	t_0 = Float64(100.0 * Float64(Float64(n * expm1(i)) / i))
	tmp = 0.0
	if (n <= -2.6e+76)
		tmp = t_0;
	elseif (n <= -6.6e-208)
		tmp = Float64(100.0 * Float64(expm1(i) / Float64(i / n)));
	elseif (n <= 0.0013)
		tmp = Float64(100.0 * Float64(Float64(1.0 / n) / Float64(Float64(1.0 / n) / n)));
	else
		tmp = t_0;
	end
	return tmp
end
code[i_, n_] := Block[{t$95$0 = N[(100.0 * N[(N[(n * N[(Exp[i] - 1), $MachinePrecision]), $MachinePrecision] / i), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[n, -2.6e+76], t$95$0, If[LessEqual[n, -6.6e-208], N[(100.0 * N[(N[(Exp[i] - 1), $MachinePrecision] / N[(i / n), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], If[LessEqual[n, 0.0013], N[(100.0 * N[(N[(1.0 / n), $MachinePrecision] / N[(N[(1.0 / n), $MachinePrecision] / n), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], t$95$0]]]]
\begin{array}{l}

\\
\begin{array}{l}
t_0 := 100 \cdot \frac{n \cdot \mathsf{expm1}\left(i\right)}{i}\\
\mathbf{if}\;n \leq -2.6 \cdot 10^{+76}:\\
\;\;\;\;t\_0\\

\mathbf{elif}\;n \leq -6.6 \cdot 10^{-208}:\\
\;\;\;\;100 \cdot \frac{\mathsf{expm1}\left(i\right)}{\frac{i}{n}}\\

\mathbf{elif}\;n \leq 0.0013:\\
\;\;\;\;100 \cdot \frac{\frac{1}{n}}{\frac{\frac{1}{n}}{n}}\\

\mathbf{else}:\\
\;\;\;\;t\_0\\


\end{array}
\end{array}
Derivation
  1. Split input into 3 regimes
  2. if n < -2.5999999999999999e76 or 0.0012999999999999999 < n

    1. Initial program 27.0%

      \[100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}} \]
    2. Add Preprocessing
    3. Taylor expanded in n around inf

      \[\leadsto 100 \cdot \color{blue}{\frac{n \cdot \left(e^{i} - 1\right)}{i}} \]
    4. Step-by-step derivation
      1. lower-/.f64N/A

        \[\leadsto 100 \cdot \color{blue}{\frac{n \cdot \left(e^{i} - 1\right)}{i}} \]
      2. lower-*.f64N/A

        \[\leadsto 100 \cdot \frac{\color{blue}{n \cdot \left(e^{i} - 1\right)}}{i} \]
      3. lower-expm1.f6491.2

        \[\leadsto 100 \cdot \frac{n \cdot \color{blue}{\mathsf{expm1}\left(i\right)}}{i} \]
    5. Applied rewrites91.2%

      \[\leadsto 100 \cdot \color{blue}{\frac{n \cdot \mathsf{expm1}\left(i\right)}{i}} \]

    if -2.5999999999999999e76 < n < -6.60000000000000013e-208

    1. Initial program 31.9%

      \[100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}} \]
    2. Add Preprocessing
    3. Taylor expanded in n around inf

      \[\leadsto 100 \cdot \frac{\color{blue}{e^{i} - 1}}{\frac{i}{n}} \]
    4. Step-by-step derivation
      1. lower-expm1.f6466.7

        \[\leadsto 100 \cdot \frac{\color{blue}{\mathsf{expm1}\left(i\right)}}{\frac{i}{n}} \]
    5. Applied rewrites66.7%

      \[\leadsto 100 \cdot \frac{\color{blue}{\mathsf{expm1}\left(i\right)}}{\frac{i}{n}} \]

    if -6.60000000000000013e-208 < n < 0.0012999999999999999

    1. Initial program 33.8%

      \[100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}} \]
    2. Add Preprocessing
    3. Step-by-step derivation
      1. lift-/.f64N/A

        \[\leadsto 100 \cdot \color{blue}{\frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}}} \]
      2. lift-/.f64N/A

        \[\leadsto 100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\color{blue}{\frac{i}{n}}} \]
      3. div-invN/A

        \[\leadsto 100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\color{blue}{i \cdot \frac{1}{n}}} \]
      4. associate-/r*N/A

        \[\leadsto 100 \cdot \color{blue}{\frac{\frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{i}}{\frac{1}{n}}} \]
      5. lift--.f64N/A

        \[\leadsto 100 \cdot \frac{\frac{\color{blue}{{\left(1 + \frac{i}{n}\right)}^{n} - 1}}{i}}{\frac{1}{n}} \]
      6. div-subN/A

        \[\leadsto 100 \cdot \frac{\color{blue}{\frac{{\left(1 + \frac{i}{n}\right)}^{n}}{i} - \frac{1}{i}}}{\frac{1}{n}} \]
      7. sub-divN/A

        \[\leadsto 100 \cdot \color{blue}{\left(\frac{\frac{{\left(1 + \frac{i}{n}\right)}^{n}}{i}}{\frac{1}{n}} - \frac{\frac{1}{i}}{\frac{1}{n}}\right)} \]
      8. frac-subN/A

        \[\leadsto 100 \cdot \color{blue}{\frac{\frac{{\left(1 + \frac{i}{n}\right)}^{n}}{i} \cdot \frac{1}{n} - \frac{1}{n} \cdot \frac{1}{i}}{\frac{1}{n} \cdot \frac{1}{n}}} \]
      9. pow2N/A

        \[\leadsto 100 \cdot \frac{\frac{{\left(1 + \frac{i}{n}\right)}^{n}}{i} \cdot \frac{1}{n} - \frac{1}{n} \cdot \frac{1}{i}}{\color{blue}{{\left(\frac{1}{n}\right)}^{2}}} \]
      10. lower-/.f64N/A

        \[\leadsto 100 \cdot \color{blue}{\frac{\frac{{\left(1 + \frac{i}{n}\right)}^{n}}{i} \cdot \frac{1}{n} - \frac{1}{n} \cdot \frac{1}{i}}{{\left(\frac{1}{n}\right)}^{2}}} \]
    4. Applied rewrites23.6%

      \[\leadsto 100 \cdot \color{blue}{\frac{\frac{{\left(1 + \frac{i}{n}\right)}^{n}}{i} \cdot \frac{1}{n} - \frac{1}{n} \cdot \frac{1}{i}}{\frac{\frac{1}{n}}{n}}} \]
    5. Taylor expanded in i around 0

      \[\leadsto 100 \cdot \frac{\color{blue}{\frac{1}{n}}}{\frac{\frac{1}{n}}{n}} \]
    6. Step-by-step derivation
      1. lower-/.f6463.5

        \[\leadsto 100 \cdot \frac{\color{blue}{\frac{1}{n}}}{\frac{\frac{1}{n}}{n}} \]
    7. Applied rewrites63.5%

      \[\leadsto 100 \cdot \frac{\color{blue}{\frac{1}{n}}}{\frac{\frac{1}{n}}{n}} \]
  3. Recombined 3 regimes into one program.
  4. Add Preprocessing

Alternative 7: 78.7% accurate, 1.1× speedup?

\[\begin{array}{l} \\ \begin{array}{l} t_0 := n \cdot \mathsf{expm1}\left(i\right)\\ \mathbf{if}\;n \leq -2.65 \cdot 10^{-34}:\\ \;\;\;\;\frac{1}{\frac{i \cdot 0.01}{t\_0}}\\ \mathbf{elif}\;n \leq 0.0013:\\ \;\;\;\;100 \cdot \frac{\frac{1}{n}}{\frac{\frac{1}{n}}{n}}\\ \mathbf{else}:\\ \;\;\;\;100 \cdot \frac{t\_0}{i}\\ \end{array} \end{array} \]
(FPCore (i n)
 :precision binary64
 (let* ((t_0 (* n (expm1 i))))
   (if (<= n -2.65e-34)
     (/ 1.0 (/ (* i 0.01) t_0))
     (if (<= n 0.0013)
       (* 100.0 (/ (/ 1.0 n) (/ (/ 1.0 n) n)))
       (* 100.0 (/ t_0 i))))))
double code(double i, double n) {
	double t_0 = n * expm1(i);
	double tmp;
	if (n <= -2.65e-34) {
		tmp = 1.0 / ((i * 0.01) / t_0);
	} else if (n <= 0.0013) {
		tmp = 100.0 * ((1.0 / n) / ((1.0 / n) / n));
	} else {
		tmp = 100.0 * (t_0 / i);
	}
	return tmp;
}
public static double code(double i, double n) {
	double t_0 = n * Math.expm1(i);
	double tmp;
	if (n <= -2.65e-34) {
		tmp = 1.0 / ((i * 0.01) / t_0);
	} else if (n <= 0.0013) {
		tmp = 100.0 * ((1.0 / n) / ((1.0 / n) / n));
	} else {
		tmp = 100.0 * (t_0 / i);
	}
	return tmp;
}
def code(i, n):
	t_0 = n * math.expm1(i)
	tmp = 0
	if n <= -2.65e-34:
		tmp = 1.0 / ((i * 0.01) / t_0)
	elif n <= 0.0013:
		tmp = 100.0 * ((1.0 / n) / ((1.0 / n) / n))
	else:
		tmp = 100.0 * (t_0 / i)
	return tmp
function code(i, n)
	t_0 = Float64(n * expm1(i))
	tmp = 0.0
	if (n <= -2.65e-34)
		tmp = Float64(1.0 / Float64(Float64(i * 0.01) / t_0));
	elseif (n <= 0.0013)
		tmp = Float64(100.0 * Float64(Float64(1.0 / n) / Float64(Float64(1.0 / n) / n)));
	else
		tmp = Float64(100.0 * Float64(t_0 / i));
	end
	return tmp
end
code[i_, n_] := Block[{t$95$0 = N[(n * N[(Exp[i] - 1), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[n, -2.65e-34], N[(1.0 / N[(N[(i * 0.01), $MachinePrecision] / t$95$0), $MachinePrecision]), $MachinePrecision], If[LessEqual[n, 0.0013], N[(100.0 * N[(N[(1.0 / n), $MachinePrecision] / N[(N[(1.0 / n), $MachinePrecision] / n), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], N[(100.0 * N[(t$95$0 / i), $MachinePrecision]), $MachinePrecision]]]]
\begin{array}{l}

\\
\begin{array}{l}
t_0 := n \cdot \mathsf{expm1}\left(i\right)\\
\mathbf{if}\;n \leq -2.65 \cdot 10^{-34}:\\
\;\;\;\;\frac{1}{\frac{i \cdot 0.01}{t\_0}}\\

\mathbf{elif}\;n \leq 0.0013:\\
\;\;\;\;100 \cdot \frac{\frac{1}{n}}{\frac{\frac{1}{n}}{n}}\\

\mathbf{else}:\\
\;\;\;\;100 \cdot \frac{t\_0}{i}\\


\end{array}
\end{array}
Derivation
  1. Split input into 3 regimes
  2. if n < -2.6499999999999998e-34

    1. Initial program 35.5%

      \[100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}} \]
    2. Add Preprocessing
    3. Taylor expanded in n around inf

      \[\leadsto \color{blue}{100 \cdot \frac{n \cdot \left(e^{i} - 1\right)}{i}} \]
    4. Step-by-step derivation
      1. associate-*r/N/A

        \[\leadsto \color{blue}{\frac{100 \cdot \left(n \cdot \left(e^{i} - 1\right)\right)}{i}} \]
      2. lower-/.f64N/A

        \[\leadsto \color{blue}{\frac{100 \cdot \left(n \cdot \left(e^{i} - 1\right)\right)}{i}} \]
      3. *-commutativeN/A

        \[\leadsto \frac{\color{blue}{\left(n \cdot \left(e^{i} - 1\right)\right) \cdot 100}}{i} \]
      4. lower-*.f64N/A

        \[\leadsto \frac{\color{blue}{\left(n \cdot \left(e^{i} - 1\right)\right) \cdot 100}}{i} \]
      5. lower-*.f64N/A

        \[\leadsto \frac{\color{blue}{\left(n \cdot \left(e^{i} - 1\right)\right)} \cdot 100}{i} \]
      6. lower-expm1.f6480.0

        \[\leadsto \frac{\left(n \cdot \color{blue}{\mathsf{expm1}\left(i\right)}\right) \cdot 100}{i} \]
    5. Applied rewrites80.0%

      \[\leadsto \color{blue}{\frac{\left(n \cdot \mathsf{expm1}\left(i\right)\right) \cdot 100}{i}} \]
    6. Step-by-step derivation
      1. Applied rewrites80.0%

        \[\leadsto \frac{100}{i} \cdot \color{blue}{\left(n \cdot \mathsf{expm1}\left(i\right)\right)} \]
      2. Step-by-step derivation
        1. Applied rewrites80.5%

          \[\leadsto \frac{1}{\color{blue}{\frac{i \cdot 0.01}{n \cdot \mathsf{expm1}\left(i\right)}}} \]

        if -2.6499999999999998e-34 < n < 0.0012999999999999999

        1. Initial program 30.4%

          \[100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}} \]
        2. Add Preprocessing
        3. Step-by-step derivation
          1. lift-/.f64N/A

            \[\leadsto 100 \cdot \color{blue}{\frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}}} \]
          2. lift-/.f64N/A

            \[\leadsto 100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\color{blue}{\frac{i}{n}}} \]
          3. div-invN/A

            \[\leadsto 100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\color{blue}{i \cdot \frac{1}{n}}} \]
          4. associate-/r*N/A

            \[\leadsto 100 \cdot \color{blue}{\frac{\frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{i}}{\frac{1}{n}}} \]
          5. lift--.f64N/A

            \[\leadsto 100 \cdot \frac{\frac{\color{blue}{{\left(1 + \frac{i}{n}\right)}^{n} - 1}}{i}}{\frac{1}{n}} \]
          6. div-subN/A

            \[\leadsto 100 \cdot \frac{\color{blue}{\frac{{\left(1 + \frac{i}{n}\right)}^{n}}{i} - \frac{1}{i}}}{\frac{1}{n}} \]
          7. sub-divN/A

            \[\leadsto 100 \cdot \color{blue}{\left(\frac{\frac{{\left(1 + \frac{i}{n}\right)}^{n}}{i}}{\frac{1}{n}} - \frac{\frac{1}{i}}{\frac{1}{n}}\right)} \]
          8. frac-subN/A

            \[\leadsto 100 \cdot \color{blue}{\frac{\frac{{\left(1 + \frac{i}{n}\right)}^{n}}{i} \cdot \frac{1}{n} - \frac{1}{n} \cdot \frac{1}{i}}{\frac{1}{n} \cdot \frac{1}{n}}} \]
          9. pow2N/A

            \[\leadsto 100 \cdot \frac{\frac{{\left(1 + \frac{i}{n}\right)}^{n}}{i} \cdot \frac{1}{n} - \frac{1}{n} \cdot \frac{1}{i}}{\color{blue}{{\left(\frac{1}{n}\right)}^{2}}} \]
          10. lower-/.f64N/A

            \[\leadsto 100 \cdot \color{blue}{\frac{\frac{{\left(1 + \frac{i}{n}\right)}^{n}}{i} \cdot \frac{1}{n} - \frac{1}{n} \cdot \frac{1}{i}}{{\left(\frac{1}{n}\right)}^{2}}} \]
        4. Applied rewrites23.0%

          \[\leadsto 100 \cdot \color{blue}{\frac{\frac{{\left(1 + \frac{i}{n}\right)}^{n}}{i} \cdot \frac{1}{n} - \frac{1}{n} \cdot \frac{1}{i}}{\frac{\frac{1}{n}}{n}}} \]
        5. Taylor expanded in i around 0

          \[\leadsto 100 \cdot \frac{\color{blue}{\frac{1}{n}}}{\frac{\frac{1}{n}}{n}} \]
        6. Step-by-step derivation
          1. lower-/.f6459.5

            \[\leadsto 100 \cdot \frac{\color{blue}{\frac{1}{n}}}{\frac{\frac{1}{n}}{n}} \]
        7. Applied rewrites59.5%

          \[\leadsto 100 \cdot \frac{\color{blue}{\frac{1}{n}}}{\frac{\frac{1}{n}}{n}} \]

        if 0.0012999999999999999 < n

        1. Initial program 22.3%

          \[100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}} \]
        2. Add Preprocessing
        3. Taylor expanded in n around inf

          \[\leadsto 100 \cdot \color{blue}{\frac{n \cdot \left(e^{i} - 1\right)}{i}} \]
        4. Step-by-step derivation
          1. lower-/.f64N/A

            \[\leadsto 100 \cdot \color{blue}{\frac{n \cdot \left(e^{i} - 1\right)}{i}} \]
          2. lower-*.f64N/A

            \[\leadsto 100 \cdot \frac{\color{blue}{n \cdot \left(e^{i} - 1\right)}}{i} \]
          3. lower-expm1.f6494.2

            \[\leadsto 100 \cdot \frac{n \cdot \color{blue}{\mathsf{expm1}\left(i\right)}}{i} \]
        5. Applied rewrites94.2%

          \[\leadsto 100 \cdot \color{blue}{\frac{n \cdot \mathsf{expm1}\left(i\right)}{i}} \]
      3. Recombined 3 regimes into one program.
      4. Add Preprocessing

      Alternative 8: 78.8% accurate, 1.1× speedup?

      \[\begin{array}{l} \\ \begin{array}{l} t_0 := 100 \cdot \frac{n \cdot \mathsf{expm1}\left(i\right)}{i}\\ \mathbf{if}\;n \leq -3.2 \cdot 10^{-18}:\\ \;\;\;\;t\_0\\ \mathbf{elif}\;n \leq 0.0013:\\ \;\;\;\;100 \cdot \frac{\frac{1}{n}}{\frac{\frac{1}{n}}{n}}\\ \mathbf{else}:\\ \;\;\;\;t\_0\\ \end{array} \end{array} \]
      (FPCore (i n)
       :precision binary64
       (let* ((t_0 (* 100.0 (/ (* n (expm1 i)) i))))
         (if (<= n -3.2e-18)
           t_0
           (if (<= n 0.0013) (* 100.0 (/ (/ 1.0 n) (/ (/ 1.0 n) n))) t_0))))
      double code(double i, double n) {
      	double t_0 = 100.0 * ((n * expm1(i)) / i);
      	double tmp;
      	if (n <= -3.2e-18) {
      		tmp = t_0;
      	} else if (n <= 0.0013) {
      		tmp = 100.0 * ((1.0 / n) / ((1.0 / n) / n));
      	} else {
      		tmp = t_0;
      	}
      	return tmp;
      }
      
      public static double code(double i, double n) {
      	double t_0 = 100.0 * ((n * Math.expm1(i)) / i);
      	double tmp;
      	if (n <= -3.2e-18) {
      		tmp = t_0;
      	} else if (n <= 0.0013) {
      		tmp = 100.0 * ((1.0 / n) / ((1.0 / n) / n));
      	} else {
      		tmp = t_0;
      	}
      	return tmp;
      }
      
      def code(i, n):
      	t_0 = 100.0 * ((n * math.expm1(i)) / i)
      	tmp = 0
      	if n <= -3.2e-18:
      		tmp = t_0
      	elif n <= 0.0013:
      		tmp = 100.0 * ((1.0 / n) / ((1.0 / n) / n))
      	else:
      		tmp = t_0
      	return tmp
      
      function code(i, n)
      	t_0 = Float64(100.0 * Float64(Float64(n * expm1(i)) / i))
      	tmp = 0.0
      	if (n <= -3.2e-18)
      		tmp = t_0;
      	elseif (n <= 0.0013)
      		tmp = Float64(100.0 * Float64(Float64(1.0 / n) / Float64(Float64(1.0 / n) / n)));
      	else
      		tmp = t_0;
      	end
      	return tmp
      end
      
      code[i_, n_] := Block[{t$95$0 = N[(100.0 * N[(N[(n * N[(Exp[i] - 1), $MachinePrecision]), $MachinePrecision] / i), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[n, -3.2e-18], t$95$0, If[LessEqual[n, 0.0013], N[(100.0 * N[(N[(1.0 / n), $MachinePrecision] / N[(N[(1.0 / n), $MachinePrecision] / n), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], t$95$0]]]
      
      \begin{array}{l}
      
      \\
      \begin{array}{l}
      t_0 := 100 \cdot \frac{n \cdot \mathsf{expm1}\left(i\right)}{i}\\
      \mathbf{if}\;n \leq -3.2 \cdot 10^{-18}:\\
      \;\;\;\;t\_0\\
      
      \mathbf{elif}\;n \leq 0.0013:\\
      \;\;\;\;100 \cdot \frac{\frac{1}{n}}{\frac{\frac{1}{n}}{n}}\\
      
      \mathbf{else}:\\
      \;\;\;\;t\_0\\
      
      
      \end{array}
      \end{array}
      
      Derivation
      1. Split input into 2 regimes
      2. if n < -3.1999999999999999e-18 or 0.0012999999999999999 < n

        1. Initial program 29.4%

          \[100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}} \]
        2. Add Preprocessing
        3. Taylor expanded in n around inf

          \[\leadsto 100 \cdot \color{blue}{\frac{n \cdot \left(e^{i} - 1\right)}{i}} \]
        4. Step-by-step derivation
          1. lower-/.f64N/A

            \[\leadsto 100 \cdot \color{blue}{\frac{n \cdot \left(e^{i} - 1\right)}{i}} \]
          2. lower-*.f64N/A

            \[\leadsto 100 \cdot \frac{\color{blue}{n \cdot \left(e^{i} - 1\right)}}{i} \]
          3. lower-expm1.f6486.9

            \[\leadsto 100 \cdot \frac{n \cdot \color{blue}{\mathsf{expm1}\left(i\right)}}{i} \]
        5. Applied rewrites86.9%

          \[\leadsto 100 \cdot \color{blue}{\frac{n \cdot \mathsf{expm1}\left(i\right)}{i}} \]

        if -3.1999999999999999e-18 < n < 0.0012999999999999999

        1. Initial program 30.8%

          \[100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}} \]
        2. Add Preprocessing
        3. Step-by-step derivation
          1. lift-/.f64N/A

            \[\leadsto 100 \cdot \color{blue}{\frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}}} \]
          2. lift-/.f64N/A

            \[\leadsto 100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\color{blue}{\frac{i}{n}}} \]
          3. div-invN/A

            \[\leadsto 100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\color{blue}{i \cdot \frac{1}{n}}} \]
          4. associate-/r*N/A

            \[\leadsto 100 \cdot \color{blue}{\frac{\frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{i}}{\frac{1}{n}}} \]
          5. lift--.f64N/A

            \[\leadsto 100 \cdot \frac{\frac{\color{blue}{{\left(1 + \frac{i}{n}\right)}^{n} - 1}}{i}}{\frac{1}{n}} \]
          6. div-subN/A

            \[\leadsto 100 \cdot \frac{\color{blue}{\frac{{\left(1 + \frac{i}{n}\right)}^{n}}{i} - \frac{1}{i}}}{\frac{1}{n}} \]
          7. sub-divN/A

            \[\leadsto 100 \cdot \color{blue}{\left(\frac{\frac{{\left(1 + \frac{i}{n}\right)}^{n}}{i}}{\frac{1}{n}} - \frac{\frac{1}{i}}{\frac{1}{n}}\right)} \]
          8. frac-subN/A

            \[\leadsto 100 \cdot \color{blue}{\frac{\frac{{\left(1 + \frac{i}{n}\right)}^{n}}{i} \cdot \frac{1}{n} - \frac{1}{n} \cdot \frac{1}{i}}{\frac{1}{n} \cdot \frac{1}{n}}} \]
          9. pow2N/A

            \[\leadsto 100 \cdot \frac{\frac{{\left(1 + \frac{i}{n}\right)}^{n}}{i} \cdot \frac{1}{n} - \frac{1}{n} \cdot \frac{1}{i}}{\color{blue}{{\left(\frac{1}{n}\right)}^{2}}} \]
          10. lower-/.f64N/A

            \[\leadsto 100 \cdot \color{blue}{\frac{\frac{{\left(1 + \frac{i}{n}\right)}^{n}}{i} \cdot \frac{1}{n} - \frac{1}{n} \cdot \frac{1}{i}}{{\left(\frac{1}{n}\right)}^{2}}} \]
        4. Applied rewrites23.1%

          \[\leadsto 100 \cdot \color{blue}{\frac{\frac{{\left(1 + \frac{i}{n}\right)}^{n}}{i} \cdot \frac{1}{n} - \frac{1}{n} \cdot \frac{1}{i}}{\frac{\frac{1}{n}}{n}}} \]
        5. Taylor expanded in i around 0

          \[\leadsto 100 \cdot \frac{\color{blue}{\frac{1}{n}}}{\frac{\frac{1}{n}}{n}} \]
        6. Step-by-step derivation
          1. lower-/.f6459.3

            \[\leadsto 100 \cdot \frac{\color{blue}{\frac{1}{n}}}{\frac{\frac{1}{n}}{n}} \]
        7. Applied rewrites59.3%

          \[\leadsto 100 \cdot \frac{\color{blue}{\frac{1}{n}}}{\frac{\frac{1}{n}}{n}} \]
      3. Recombined 2 regimes into one program.
      4. Add Preprocessing

      Alternative 9: 78.6% accurate, 1.1× speedup?

      \[\begin{array}{l} \\ \begin{array}{l} t_0 := n \cdot \mathsf{expm1}\left(i\right)\\ \mathbf{if}\;n \leq -3.2 \cdot 10^{-18}:\\ \;\;\;\;t\_0 \cdot \frac{100}{i}\\ \mathbf{elif}\;n \leq 0.0013:\\ \;\;\;\;100 \cdot \frac{\frac{1}{n}}{\frac{\frac{1}{n}}{n}}\\ \mathbf{else}:\\ \;\;\;\;\frac{100 \cdot t\_0}{i}\\ \end{array} \end{array} \]
      (FPCore (i n)
       :precision binary64
       (let* ((t_0 (* n (expm1 i))))
         (if (<= n -3.2e-18)
           (* t_0 (/ 100.0 i))
           (if (<= n 0.0013)
             (* 100.0 (/ (/ 1.0 n) (/ (/ 1.0 n) n)))
             (/ (* 100.0 t_0) i)))))
      double code(double i, double n) {
      	double t_0 = n * expm1(i);
      	double tmp;
      	if (n <= -3.2e-18) {
      		tmp = t_0 * (100.0 / i);
      	} else if (n <= 0.0013) {
      		tmp = 100.0 * ((1.0 / n) / ((1.0 / n) / n));
      	} else {
      		tmp = (100.0 * t_0) / i;
      	}
      	return tmp;
      }
      
      public static double code(double i, double n) {
      	double t_0 = n * Math.expm1(i);
      	double tmp;
      	if (n <= -3.2e-18) {
      		tmp = t_0 * (100.0 / i);
      	} else if (n <= 0.0013) {
      		tmp = 100.0 * ((1.0 / n) / ((1.0 / n) / n));
      	} else {
      		tmp = (100.0 * t_0) / i;
      	}
      	return tmp;
      }
      
      def code(i, n):
      	t_0 = n * math.expm1(i)
      	tmp = 0
      	if n <= -3.2e-18:
      		tmp = t_0 * (100.0 / i)
      	elif n <= 0.0013:
      		tmp = 100.0 * ((1.0 / n) / ((1.0 / n) / n))
      	else:
      		tmp = (100.0 * t_0) / i
      	return tmp
      
      function code(i, n)
      	t_0 = Float64(n * expm1(i))
      	tmp = 0.0
      	if (n <= -3.2e-18)
      		tmp = Float64(t_0 * Float64(100.0 / i));
      	elseif (n <= 0.0013)
      		tmp = Float64(100.0 * Float64(Float64(1.0 / n) / Float64(Float64(1.0 / n) / n)));
      	else
      		tmp = Float64(Float64(100.0 * t_0) / i);
      	end
      	return tmp
      end
      
      code[i_, n_] := Block[{t$95$0 = N[(n * N[(Exp[i] - 1), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[n, -3.2e-18], N[(t$95$0 * N[(100.0 / i), $MachinePrecision]), $MachinePrecision], If[LessEqual[n, 0.0013], N[(100.0 * N[(N[(1.0 / n), $MachinePrecision] / N[(N[(1.0 / n), $MachinePrecision] / n), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], N[(N[(100.0 * t$95$0), $MachinePrecision] / i), $MachinePrecision]]]]
      
      \begin{array}{l}
      
      \\
      \begin{array}{l}
      t_0 := n \cdot \mathsf{expm1}\left(i\right)\\
      \mathbf{if}\;n \leq -3.2 \cdot 10^{-18}:\\
      \;\;\;\;t\_0 \cdot \frac{100}{i}\\
      
      \mathbf{elif}\;n \leq 0.0013:\\
      \;\;\;\;100 \cdot \frac{\frac{1}{n}}{\frac{\frac{1}{n}}{n}}\\
      
      \mathbf{else}:\\
      \;\;\;\;\frac{100 \cdot t\_0}{i}\\
      
      
      \end{array}
      \end{array}
      
      Derivation
      1. Split input into 3 regimes
      2. if n < -3.1999999999999999e-18

        1. Initial program 35.1%

          \[100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}} \]
        2. Add Preprocessing
        3. Taylor expanded in n around inf

          \[\leadsto \color{blue}{100 \cdot \frac{n \cdot \left(e^{i} - 1\right)}{i}} \]
        4. Step-by-step derivation
          1. associate-*r/N/A

            \[\leadsto \color{blue}{\frac{100 \cdot \left(n \cdot \left(e^{i} - 1\right)\right)}{i}} \]
          2. lower-/.f64N/A

            \[\leadsto \color{blue}{\frac{100 \cdot \left(n \cdot \left(e^{i} - 1\right)\right)}{i}} \]
          3. *-commutativeN/A

            \[\leadsto \frac{\color{blue}{\left(n \cdot \left(e^{i} - 1\right)\right) \cdot 100}}{i} \]
          4. lower-*.f64N/A

            \[\leadsto \frac{\color{blue}{\left(n \cdot \left(e^{i} - 1\right)\right) \cdot 100}}{i} \]
          5. lower-*.f64N/A

            \[\leadsto \frac{\color{blue}{\left(n \cdot \left(e^{i} - 1\right)\right)} \cdot 100}{i} \]
          6. lower-expm1.f6480.9

            \[\leadsto \frac{\left(n \cdot \color{blue}{\mathsf{expm1}\left(i\right)}\right) \cdot 100}{i} \]
        5. Applied rewrites80.9%

          \[\leadsto \color{blue}{\frac{\left(n \cdot \mathsf{expm1}\left(i\right)\right) \cdot 100}{i}} \]
        6. Step-by-step derivation
          1. Applied rewrites80.9%

            \[\leadsto \frac{100}{i} \cdot \color{blue}{\left(n \cdot \mathsf{expm1}\left(i\right)\right)} \]

          if -3.1999999999999999e-18 < n < 0.0012999999999999999

          1. Initial program 30.8%

            \[100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}} \]
          2. Add Preprocessing
          3. Step-by-step derivation
            1. lift-/.f64N/A

              \[\leadsto 100 \cdot \color{blue}{\frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}}} \]
            2. lift-/.f64N/A

              \[\leadsto 100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\color{blue}{\frac{i}{n}}} \]
            3. div-invN/A

              \[\leadsto 100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\color{blue}{i \cdot \frac{1}{n}}} \]
            4. associate-/r*N/A

              \[\leadsto 100 \cdot \color{blue}{\frac{\frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{i}}{\frac{1}{n}}} \]
            5. lift--.f64N/A

              \[\leadsto 100 \cdot \frac{\frac{\color{blue}{{\left(1 + \frac{i}{n}\right)}^{n} - 1}}{i}}{\frac{1}{n}} \]
            6. div-subN/A

              \[\leadsto 100 \cdot \frac{\color{blue}{\frac{{\left(1 + \frac{i}{n}\right)}^{n}}{i} - \frac{1}{i}}}{\frac{1}{n}} \]
            7. sub-divN/A

              \[\leadsto 100 \cdot \color{blue}{\left(\frac{\frac{{\left(1 + \frac{i}{n}\right)}^{n}}{i}}{\frac{1}{n}} - \frac{\frac{1}{i}}{\frac{1}{n}}\right)} \]
            8. frac-subN/A

              \[\leadsto 100 \cdot \color{blue}{\frac{\frac{{\left(1 + \frac{i}{n}\right)}^{n}}{i} \cdot \frac{1}{n} - \frac{1}{n} \cdot \frac{1}{i}}{\frac{1}{n} \cdot \frac{1}{n}}} \]
            9. pow2N/A

              \[\leadsto 100 \cdot \frac{\frac{{\left(1 + \frac{i}{n}\right)}^{n}}{i} \cdot \frac{1}{n} - \frac{1}{n} \cdot \frac{1}{i}}{\color{blue}{{\left(\frac{1}{n}\right)}^{2}}} \]
            10. lower-/.f64N/A

              \[\leadsto 100 \cdot \color{blue}{\frac{\frac{{\left(1 + \frac{i}{n}\right)}^{n}}{i} \cdot \frac{1}{n} - \frac{1}{n} \cdot \frac{1}{i}}{{\left(\frac{1}{n}\right)}^{2}}} \]
          4. Applied rewrites23.1%

            \[\leadsto 100 \cdot \color{blue}{\frac{\frac{{\left(1 + \frac{i}{n}\right)}^{n}}{i} \cdot \frac{1}{n} - \frac{1}{n} \cdot \frac{1}{i}}{\frac{\frac{1}{n}}{n}}} \]
          5. Taylor expanded in i around 0

            \[\leadsto 100 \cdot \frac{\color{blue}{\frac{1}{n}}}{\frac{\frac{1}{n}}{n}} \]
          6. Step-by-step derivation
            1. lower-/.f6459.3

              \[\leadsto 100 \cdot \frac{\color{blue}{\frac{1}{n}}}{\frac{\frac{1}{n}}{n}} \]
          7. Applied rewrites59.3%

            \[\leadsto 100 \cdot \frac{\color{blue}{\frac{1}{n}}}{\frac{\frac{1}{n}}{n}} \]

          if 0.0012999999999999999 < n

          1. Initial program 22.3%

            \[100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}} \]
          2. Add Preprocessing
          3. Taylor expanded in n around inf

            \[\leadsto \color{blue}{100 \cdot \frac{n \cdot \left(e^{i} - 1\right)}{i}} \]
          4. Step-by-step derivation
            1. associate-*r/N/A

              \[\leadsto \color{blue}{\frac{100 \cdot \left(n \cdot \left(e^{i} - 1\right)\right)}{i}} \]
            2. lower-/.f64N/A

              \[\leadsto \color{blue}{\frac{100 \cdot \left(n \cdot \left(e^{i} - 1\right)\right)}{i}} \]
            3. *-commutativeN/A

              \[\leadsto \frac{\color{blue}{\left(n \cdot \left(e^{i} - 1\right)\right) \cdot 100}}{i} \]
            4. lower-*.f64N/A

              \[\leadsto \frac{\color{blue}{\left(n \cdot \left(e^{i} - 1\right)\right) \cdot 100}}{i} \]
            5. lower-*.f64N/A

              \[\leadsto \frac{\color{blue}{\left(n \cdot \left(e^{i} - 1\right)\right)} \cdot 100}{i} \]
            6. lower-expm1.f6494.1

              \[\leadsto \frac{\left(n \cdot \color{blue}{\mathsf{expm1}\left(i\right)}\right) \cdot 100}{i} \]
          5. Applied rewrites94.1%

            \[\leadsto \color{blue}{\frac{\left(n \cdot \mathsf{expm1}\left(i\right)\right) \cdot 100}{i}} \]
        7. Recombined 3 regimes into one program.
        8. Final simplification76.4%

          \[\leadsto \begin{array}{l} \mathbf{if}\;n \leq -3.2 \cdot 10^{-18}:\\ \;\;\;\;\left(n \cdot \mathsf{expm1}\left(i\right)\right) \cdot \frac{100}{i}\\ \mathbf{elif}\;n \leq 0.0013:\\ \;\;\;\;100 \cdot \frac{\frac{1}{n}}{\frac{\frac{1}{n}}{n}}\\ \mathbf{else}:\\ \;\;\;\;\frac{100 \cdot \left(n \cdot \mathsf{expm1}\left(i\right)\right)}{i}\\ \end{array} \]
        9. Add Preprocessing

        Alternative 10: 78.5% accurate, 1.1× speedup?

        \[\begin{array}{l} \\ \begin{array}{l} t_0 := \left(n \cdot \mathsf{expm1}\left(i\right)\right) \cdot \frac{100}{i}\\ \mathbf{if}\;n \leq -3.2 \cdot 10^{-18}:\\ \;\;\;\;t\_0\\ \mathbf{elif}\;n \leq 0.0013:\\ \;\;\;\;100 \cdot \frac{\frac{1}{n}}{\frac{\frac{1}{n}}{n}}\\ \mathbf{else}:\\ \;\;\;\;t\_0\\ \end{array} \end{array} \]
        (FPCore (i n)
         :precision binary64
         (let* ((t_0 (* (* n (expm1 i)) (/ 100.0 i))))
           (if (<= n -3.2e-18)
             t_0
             (if (<= n 0.0013) (* 100.0 (/ (/ 1.0 n) (/ (/ 1.0 n) n))) t_0))))
        double code(double i, double n) {
        	double t_0 = (n * expm1(i)) * (100.0 / i);
        	double tmp;
        	if (n <= -3.2e-18) {
        		tmp = t_0;
        	} else if (n <= 0.0013) {
        		tmp = 100.0 * ((1.0 / n) / ((1.0 / n) / n));
        	} else {
        		tmp = t_0;
        	}
        	return tmp;
        }
        
        public static double code(double i, double n) {
        	double t_0 = (n * Math.expm1(i)) * (100.0 / i);
        	double tmp;
        	if (n <= -3.2e-18) {
        		tmp = t_0;
        	} else if (n <= 0.0013) {
        		tmp = 100.0 * ((1.0 / n) / ((1.0 / n) / n));
        	} else {
        		tmp = t_0;
        	}
        	return tmp;
        }
        
        def code(i, n):
        	t_0 = (n * math.expm1(i)) * (100.0 / i)
        	tmp = 0
        	if n <= -3.2e-18:
        		tmp = t_0
        	elif n <= 0.0013:
        		tmp = 100.0 * ((1.0 / n) / ((1.0 / n) / n))
        	else:
        		tmp = t_0
        	return tmp
        
        function code(i, n)
        	t_0 = Float64(Float64(n * expm1(i)) * Float64(100.0 / i))
        	tmp = 0.0
        	if (n <= -3.2e-18)
        		tmp = t_0;
        	elseif (n <= 0.0013)
        		tmp = Float64(100.0 * Float64(Float64(1.0 / n) / Float64(Float64(1.0 / n) / n)));
        	else
        		tmp = t_0;
        	end
        	return tmp
        end
        
        code[i_, n_] := Block[{t$95$0 = N[(N[(n * N[(Exp[i] - 1), $MachinePrecision]), $MachinePrecision] * N[(100.0 / i), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[n, -3.2e-18], t$95$0, If[LessEqual[n, 0.0013], N[(100.0 * N[(N[(1.0 / n), $MachinePrecision] / N[(N[(1.0 / n), $MachinePrecision] / n), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], t$95$0]]]
        
        \begin{array}{l}
        
        \\
        \begin{array}{l}
        t_0 := \left(n \cdot \mathsf{expm1}\left(i\right)\right) \cdot \frac{100}{i}\\
        \mathbf{if}\;n \leq -3.2 \cdot 10^{-18}:\\
        \;\;\;\;t\_0\\
        
        \mathbf{elif}\;n \leq 0.0013:\\
        \;\;\;\;100 \cdot \frac{\frac{1}{n}}{\frac{\frac{1}{n}}{n}}\\
        
        \mathbf{else}:\\
        \;\;\;\;t\_0\\
        
        
        \end{array}
        \end{array}
        
        Derivation
        1. Split input into 2 regimes
        2. if n < -3.1999999999999999e-18 or 0.0012999999999999999 < n

          1. Initial program 29.4%

            \[100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}} \]
          2. Add Preprocessing
          3. Taylor expanded in n around inf

            \[\leadsto \color{blue}{100 \cdot \frac{n \cdot \left(e^{i} - 1\right)}{i}} \]
          4. Step-by-step derivation
            1. associate-*r/N/A

              \[\leadsto \color{blue}{\frac{100 \cdot \left(n \cdot \left(e^{i} - 1\right)\right)}{i}} \]
            2. lower-/.f64N/A

              \[\leadsto \color{blue}{\frac{100 \cdot \left(n \cdot \left(e^{i} - 1\right)\right)}{i}} \]
            3. *-commutativeN/A

              \[\leadsto \frac{\color{blue}{\left(n \cdot \left(e^{i} - 1\right)\right) \cdot 100}}{i} \]
            4. lower-*.f64N/A

              \[\leadsto \frac{\color{blue}{\left(n \cdot \left(e^{i} - 1\right)\right) \cdot 100}}{i} \]
            5. lower-*.f64N/A

              \[\leadsto \frac{\color{blue}{\left(n \cdot \left(e^{i} - 1\right)\right)} \cdot 100}{i} \]
            6. lower-expm1.f6486.8

              \[\leadsto \frac{\left(n \cdot \color{blue}{\mathsf{expm1}\left(i\right)}\right) \cdot 100}{i} \]
          5. Applied rewrites86.8%

            \[\leadsto \color{blue}{\frac{\left(n \cdot \mathsf{expm1}\left(i\right)\right) \cdot 100}{i}} \]
          6. Step-by-step derivation
            1. Applied rewrites86.8%

              \[\leadsto \frac{100}{i} \cdot \color{blue}{\left(n \cdot \mathsf{expm1}\left(i\right)\right)} \]

            if -3.1999999999999999e-18 < n < 0.0012999999999999999

            1. Initial program 30.8%

              \[100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}} \]
            2. Add Preprocessing
            3. Step-by-step derivation
              1. lift-/.f64N/A

                \[\leadsto 100 \cdot \color{blue}{\frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}}} \]
              2. lift-/.f64N/A

                \[\leadsto 100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\color{blue}{\frac{i}{n}}} \]
              3. div-invN/A

                \[\leadsto 100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\color{blue}{i \cdot \frac{1}{n}}} \]
              4. associate-/r*N/A

                \[\leadsto 100 \cdot \color{blue}{\frac{\frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{i}}{\frac{1}{n}}} \]
              5. lift--.f64N/A

                \[\leadsto 100 \cdot \frac{\frac{\color{blue}{{\left(1 + \frac{i}{n}\right)}^{n} - 1}}{i}}{\frac{1}{n}} \]
              6. div-subN/A

                \[\leadsto 100 \cdot \frac{\color{blue}{\frac{{\left(1 + \frac{i}{n}\right)}^{n}}{i} - \frac{1}{i}}}{\frac{1}{n}} \]
              7. sub-divN/A

                \[\leadsto 100 \cdot \color{blue}{\left(\frac{\frac{{\left(1 + \frac{i}{n}\right)}^{n}}{i}}{\frac{1}{n}} - \frac{\frac{1}{i}}{\frac{1}{n}}\right)} \]
              8. frac-subN/A

                \[\leadsto 100 \cdot \color{blue}{\frac{\frac{{\left(1 + \frac{i}{n}\right)}^{n}}{i} \cdot \frac{1}{n} - \frac{1}{n} \cdot \frac{1}{i}}{\frac{1}{n} \cdot \frac{1}{n}}} \]
              9. pow2N/A

                \[\leadsto 100 \cdot \frac{\frac{{\left(1 + \frac{i}{n}\right)}^{n}}{i} \cdot \frac{1}{n} - \frac{1}{n} \cdot \frac{1}{i}}{\color{blue}{{\left(\frac{1}{n}\right)}^{2}}} \]
              10. lower-/.f64N/A

                \[\leadsto 100 \cdot \color{blue}{\frac{\frac{{\left(1 + \frac{i}{n}\right)}^{n}}{i} \cdot \frac{1}{n} - \frac{1}{n} \cdot \frac{1}{i}}{{\left(\frac{1}{n}\right)}^{2}}} \]
            4. Applied rewrites23.1%

              \[\leadsto 100 \cdot \color{blue}{\frac{\frac{{\left(1 + \frac{i}{n}\right)}^{n}}{i} \cdot \frac{1}{n} - \frac{1}{n} \cdot \frac{1}{i}}{\frac{\frac{1}{n}}{n}}} \]
            5. Taylor expanded in i around 0

              \[\leadsto 100 \cdot \frac{\color{blue}{\frac{1}{n}}}{\frac{\frac{1}{n}}{n}} \]
            6. Step-by-step derivation
              1. lower-/.f6459.3

                \[\leadsto 100 \cdot \frac{\color{blue}{\frac{1}{n}}}{\frac{\frac{1}{n}}{n}} \]
            7. Applied rewrites59.3%

              \[\leadsto 100 \cdot \frac{\color{blue}{\frac{1}{n}}}{\frac{\frac{1}{n}}{n}} \]
          7. Recombined 2 regimes into one program.
          8. Final simplification76.4%

            \[\leadsto \begin{array}{l} \mathbf{if}\;n \leq -3.2 \cdot 10^{-18}:\\ \;\;\;\;\left(n \cdot \mathsf{expm1}\left(i\right)\right) \cdot \frac{100}{i}\\ \mathbf{elif}\;n \leq 0.0013:\\ \;\;\;\;100 \cdot \frac{\frac{1}{n}}{\frac{\frac{1}{n}}{n}}\\ \mathbf{else}:\\ \;\;\;\;\left(n \cdot \mathsf{expm1}\left(i\right)\right) \cdot \frac{100}{i}\\ \end{array} \]
          9. Add Preprocessing

          Alternative 11: 65.4% accurate, 3.6× speedup?

          \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;n \leq -1.6 \cdot 10^{-131}:\\ \;\;\;\;\mathsf{fma}\left(i, n \cdot \mathsf{fma}\left(16.666666666666668, i, 50\right), n \cdot 100\right)\\ \mathbf{elif}\;n \leq 7.2 \cdot 10^{-130}:\\ \;\;\;\;100 \cdot \frac{n \cdot 1 - n}{i}\\ \mathbf{else}:\\ \;\;\;\;100 \cdot \mathsf{fma}\left(i, n \cdot \mathsf{fma}\left(i, \mathsf{fma}\left(i, 0.041666666666666664, 0.16666666666666666\right), 0.5\right), n\right)\\ \end{array} \end{array} \]
          (FPCore (i n)
           :precision binary64
           (if (<= n -1.6e-131)
             (fma i (* n (fma 16.666666666666668 i 50.0)) (* n 100.0))
             (if (<= n 7.2e-130)
               (* 100.0 (/ (- (* n 1.0) n) i))
               (*
                100.0
                (fma
                 i
                 (* n (fma i (fma i 0.041666666666666664 0.16666666666666666) 0.5))
                 n)))))
          double code(double i, double n) {
          	double tmp;
          	if (n <= -1.6e-131) {
          		tmp = fma(i, (n * fma(16.666666666666668, i, 50.0)), (n * 100.0));
          	} else if (n <= 7.2e-130) {
          		tmp = 100.0 * (((n * 1.0) - n) / i);
          	} else {
          		tmp = 100.0 * fma(i, (n * fma(i, fma(i, 0.041666666666666664, 0.16666666666666666), 0.5)), n);
          	}
          	return tmp;
          }
          
          function code(i, n)
          	tmp = 0.0
          	if (n <= -1.6e-131)
          		tmp = fma(i, Float64(n * fma(16.666666666666668, i, 50.0)), Float64(n * 100.0));
          	elseif (n <= 7.2e-130)
          		tmp = Float64(100.0 * Float64(Float64(Float64(n * 1.0) - n) / i));
          	else
          		tmp = Float64(100.0 * fma(i, Float64(n * fma(i, fma(i, 0.041666666666666664, 0.16666666666666666), 0.5)), n));
          	end
          	return tmp
          end
          
          code[i_, n_] := If[LessEqual[n, -1.6e-131], N[(i * N[(n * N[(16.666666666666668 * i + 50.0), $MachinePrecision]), $MachinePrecision] + N[(n * 100.0), $MachinePrecision]), $MachinePrecision], If[LessEqual[n, 7.2e-130], N[(100.0 * N[(N[(N[(n * 1.0), $MachinePrecision] - n), $MachinePrecision] / i), $MachinePrecision]), $MachinePrecision], N[(100.0 * N[(i * N[(n * N[(i * N[(i * 0.041666666666666664 + 0.16666666666666666), $MachinePrecision] + 0.5), $MachinePrecision]), $MachinePrecision] + n), $MachinePrecision]), $MachinePrecision]]]
          
          \begin{array}{l}
          
          \\
          \begin{array}{l}
          \mathbf{if}\;n \leq -1.6 \cdot 10^{-131}:\\
          \;\;\;\;\mathsf{fma}\left(i, n \cdot \mathsf{fma}\left(16.666666666666668, i, 50\right), n \cdot 100\right)\\
          
          \mathbf{elif}\;n \leq 7.2 \cdot 10^{-130}:\\
          \;\;\;\;100 \cdot \frac{n \cdot 1 - n}{i}\\
          
          \mathbf{else}:\\
          \;\;\;\;100 \cdot \mathsf{fma}\left(i, n \cdot \mathsf{fma}\left(i, \mathsf{fma}\left(i, 0.041666666666666664, 0.16666666666666666\right), 0.5\right), n\right)\\
          
          
          \end{array}
          \end{array}
          
          Derivation
          1. Split input into 3 regimes
          2. if n < -1.6e-131

            1. Initial program 31.1%

              \[100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}} \]
            2. Add Preprocessing
            3. Taylor expanded in n around inf

              \[\leadsto \color{blue}{100 \cdot \frac{n \cdot \left(e^{i} - 1\right)}{i}} \]
            4. Step-by-step derivation
              1. associate-*r/N/A

                \[\leadsto \color{blue}{\frac{100 \cdot \left(n \cdot \left(e^{i} - 1\right)\right)}{i}} \]
              2. lower-/.f64N/A

                \[\leadsto \color{blue}{\frac{100 \cdot \left(n \cdot \left(e^{i} - 1\right)\right)}{i}} \]
              3. *-commutativeN/A

                \[\leadsto \frac{\color{blue}{\left(n \cdot \left(e^{i} - 1\right)\right) \cdot 100}}{i} \]
              4. lower-*.f64N/A

                \[\leadsto \frac{\color{blue}{\left(n \cdot \left(e^{i} - 1\right)\right) \cdot 100}}{i} \]
              5. lower-*.f64N/A

                \[\leadsto \frac{\color{blue}{\left(n \cdot \left(e^{i} - 1\right)\right)} \cdot 100}{i} \]
              6. lower-expm1.f6476.5

                \[\leadsto \frac{\left(n \cdot \color{blue}{\mathsf{expm1}\left(i\right)}\right) \cdot 100}{i} \]
            5. Applied rewrites76.5%

              \[\leadsto \color{blue}{\frac{\left(n \cdot \mathsf{expm1}\left(i\right)\right) \cdot 100}{i}} \]
            6. Taylor expanded in i around 0

              \[\leadsto 100 \cdot n + \color{blue}{i \cdot \left(\frac{50}{3} \cdot \left(i \cdot n\right) + 50 \cdot n\right)} \]
            7. Step-by-step derivation
              1. Applied rewrites54.3%

                \[\leadsto \mathsf{fma}\left(i, \color{blue}{n \cdot \mathsf{fma}\left(16.666666666666668, i, 50\right)}, n \cdot 100\right) \]

              if -1.6e-131 < n < 7.2000000000000003e-130

              1. Initial program 47.5%

                \[100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}} \]
              2. Add Preprocessing
              3. Step-by-step derivation
                1. lift--.f64N/A

                  \[\leadsto 100 \cdot \frac{\color{blue}{{\left(1 + \frac{i}{n}\right)}^{n} - 1}}{\frac{i}{n}} \]
                2. lift-pow.f64N/A

                  \[\leadsto 100 \cdot \frac{\color{blue}{{\left(1 + \frac{i}{n}\right)}^{n}} - 1}{\frac{i}{n}} \]
                3. pow-to-expN/A

                  \[\leadsto 100 \cdot \frac{\color{blue}{e^{\log \left(1 + \frac{i}{n}\right) \cdot n}} - 1}{\frac{i}{n}} \]
                4. lower-expm1.f64N/A

                  \[\leadsto 100 \cdot \frac{\color{blue}{\mathsf{expm1}\left(\log \left(1 + \frac{i}{n}\right) \cdot n\right)}}{\frac{i}{n}} \]
                5. *-commutativeN/A

                  \[\leadsto 100 \cdot \frac{\mathsf{expm1}\left(\color{blue}{n \cdot \log \left(1 + \frac{i}{n}\right)}\right)}{\frac{i}{n}} \]
                6. lower-*.f64N/A

                  \[\leadsto 100 \cdot \frac{\mathsf{expm1}\left(\color{blue}{n \cdot \log \left(1 + \frac{i}{n}\right)}\right)}{\frac{i}{n}} \]
                7. lift-+.f64N/A

                  \[\leadsto 100 \cdot \frac{\mathsf{expm1}\left(n \cdot \log \color{blue}{\left(1 + \frac{i}{n}\right)}\right)}{\frac{i}{n}} \]
                8. lower-log1p.f6485.7

                  \[\leadsto 100 \cdot \frac{\mathsf{expm1}\left(n \cdot \color{blue}{\mathsf{log1p}\left(\frac{i}{n}\right)}\right)}{\frac{i}{n}} \]
              4. Applied rewrites85.7%

                \[\leadsto 100 \cdot \frac{\color{blue}{\mathsf{expm1}\left(n \cdot \mathsf{log1p}\left(\frac{i}{n}\right)\right)}}{\frac{i}{n}} \]
              5. Step-by-step derivation
                1. lift-/.f64N/A

                  \[\leadsto 100 \cdot \color{blue}{\frac{\mathsf{expm1}\left(n \cdot \mathsf{log1p}\left(\frac{i}{n}\right)\right)}{\frac{i}{n}}} \]
                2. lift-expm1.f64N/A

                  \[\leadsto 100 \cdot \frac{\color{blue}{e^{n \cdot \mathsf{log1p}\left(\frac{i}{n}\right)} - 1}}{\frac{i}{n}} \]
                3. div-subN/A

                  \[\leadsto 100 \cdot \color{blue}{\left(\frac{e^{n \cdot \mathsf{log1p}\left(\frac{i}{n}\right)}}{\frac{i}{n}} - \frac{1}{\frac{i}{n}}\right)} \]
                4. lift-*.f64N/A

                  \[\leadsto 100 \cdot \left(\frac{e^{\color{blue}{n \cdot \mathsf{log1p}\left(\frac{i}{n}\right)}}}{\frac{i}{n}} - \frac{1}{\frac{i}{n}}\right) \]
                5. *-commutativeN/A

                  \[\leadsto 100 \cdot \left(\frac{e^{\color{blue}{\mathsf{log1p}\left(\frac{i}{n}\right) \cdot n}}}{\frac{i}{n}} - \frac{1}{\frac{i}{n}}\right) \]
                6. lift-log1p.f64N/A

                  \[\leadsto 100 \cdot \left(\frac{e^{\color{blue}{\log \left(1 + \frac{i}{n}\right)} \cdot n}}{\frac{i}{n}} - \frac{1}{\frac{i}{n}}\right) \]
                7. lift-+.f64N/A

                  \[\leadsto 100 \cdot \left(\frac{e^{\log \color{blue}{\left(1 + \frac{i}{n}\right)} \cdot n}}{\frac{i}{n}} - \frac{1}{\frac{i}{n}}\right) \]
                8. pow-to-expN/A

                  \[\leadsto 100 \cdot \left(\frac{\color{blue}{{\left(1 + \frac{i}{n}\right)}^{n}}}{\frac{i}{n}} - \frac{1}{\frac{i}{n}}\right) \]
                9. lift-pow.f64N/A

                  \[\leadsto 100 \cdot \left(\frac{\color{blue}{{\left(1 + \frac{i}{n}\right)}^{n}}}{\frac{i}{n}} - \frac{1}{\frac{i}{n}}\right) \]
                10. div-invN/A

                  \[\leadsto 100 \cdot \left(\color{blue}{{\left(1 + \frac{i}{n}\right)}^{n} \cdot \frac{1}{\frac{i}{n}}} - \frac{1}{\frac{i}{n}}\right) \]
                11. lift-/.f64N/A

                  \[\leadsto 100 \cdot \left({\left(1 + \frac{i}{n}\right)}^{n} \cdot \frac{1}{\color{blue}{\frac{i}{n}}} - \frac{1}{\frac{i}{n}}\right) \]
                12. clear-numN/A

                  \[\leadsto 100 \cdot \left({\left(1 + \frac{i}{n}\right)}^{n} \cdot \color{blue}{\frac{n}{i}} - \frac{1}{\frac{i}{n}}\right) \]
                13. associate-/l*N/A

                  \[\leadsto 100 \cdot \left(\color{blue}{\frac{{\left(1 + \frac{i}{n}\right)}^{n} \cdot n}{i}} - \frac{1}{\frac{i}{n}}\right) \]
                14. lift-*.f64N/A

                  \[\leadsto 100 \cdot \left(\frac{\color{blue}{{\left(1 + \frac{i}{n}\right)}^{n} \cdot n}}{i} - \frac{1}{\frac{i}{n}}\right) \]
                15. div-invN/A

                  \[\leadsto 100 \cdot \left(\color{blue}{\left({\left(1 + \frac{i}{n}\right)}^{n} \cdot n\right) \cdot \frac{1}{i}} - \frac{1}{\frac{i}{n}}\right) \]
                16. associate-*r/N/A

                  \[\leadsto 100 \cdot \left(\color{blue}{\frac{\left({\left(1 + \frac{i}{n}\right)}^{n} \cdot n\right) \cdot 1}{i}} - \frac{1}{\frac{i}{n}}\right) \]
                17. lift-/.f64N/A

                  \[\leadsto 100 \cdot \left(\frac{\left({\left(1 + \frac{i}{n}\right)}^{n} \cdot n\right) \cdot 1}{i} - \frac{1}{\color{blue}{\frac{i}{n}}}\right) \]
                18. clear-numN/A

                  \[\leadsto 100 \cdot \left(\frac{\left({\left(1 + \frac{i}{n}\right)}^{n} \cdot n\right) \cdot 1}{i} - \color{blue}{\frac{n}{i}}\right) \]
              6. Applied rewrites45.9%

                \[\leadsto 100 \cdot \color{blue}{\frac{\left(n \cdot {\left(\frac{i}{n} + 1\right)}^{n}\right) \cdot 1 - n}{i}} \]
              7. Taylor expanded in i around 0

                \[\leadsto 100 \cdot \frac{\left(n \cdot \color{blue}{1}\right) \cdot 1 - n}{i} \]
              8. Step-by-step derivation
                1. Applied rewrites61.3%

                  \[\leadsto 100 \cdot \frac{\left(n \cdot \color{blue}{1}\right) \cdot 1 - n}{i} \]

                if 7.2000000000000003e-130 < n

                1. Initial program 19.8%

                  \[100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}} \]
                2. Add Preprocessing
                3. Taylor expanded in n around inf

                  \[\leadsto 100 \cdot \color{blue}{\frac{n \cdot \left(e^{i} - 1\right)}{i}} \]
                4. Step-by-step derivation
                  1. lower-/.f64N/A

                    \[\leadsto 100 \cdot \color{blue}{\frac{n \cdot \left(e^{i} - 1\right)}{i}} \]
                  2. lower-*.f64N/A

                    \[\leadsto 100 \cdot \frac{\color{blue}{n \cdot \left(e^{i} - 1\right)}}{i} \]
                  3. lower-expm1.f6479.2

                    \[\leadsto 100 \cdot \frac{n \cdot \color{blue}{\mathsf{expm1}\left(i\right)}}{i} \]
                5. Applied rewrites79.2%

                  \[\leadsto 100 \cdot \color{blue}{\frac{n \cdot \mathsf{expm1}\left(i\right)}{i}} \]
                6. Taylor expanded in i around 0

                  \[\leadsto 100 \cdot \left(n + \color{blue}{i \cdot \left(\frac{1}{2} \cdot n + i \cdot \left(\frac{1}{24} \cdot \left(i \cdot n\right) + \frac{1}{6} \cdot n\right)\right)}\right) \]
                7. Step-by-step derivation
                  1. Applied rewrites72.1%

                    \[\leadsto 100 \cdot \mathsf{fma}\left(i, \color{blue}{\mathsf{fma}\left(n, 0.5, i \cdot \mathsf{fma}\left(n, 0.16666666666666666, 0.041666666666666664 \cdot \left(n \cdot i\right)\right)\right)}, n\right) \]
                  2. Taylor expanded in i around 0

                    \[\leadsto 100 \cdot \left(n + \color{blue}{i \cdot \left(\frac{1}{2} \cdot n + i \cdot \left(\frac{1}{24} \cdot \left(i \cdot n\right) + \frac{1}{6} \cdot n\right)\right)}\right) \]
                  3. Step-by-step derivation
                    1. Applied rewrites72.1%

                      \[\leadsto 100 \cdot \mathsf{fma}\left(i, \color{blue}{n \cdot \mathsf{fma}\left(i, \mathsf{fma}\left(i, 0.041666666666666664, 0.16666666666666666\right), 0.5\right)}, n\right) \]
                  4. Recombined 3 regimes into one program.
                  5. Final simplification62.6%

                    \[\leadsto \begin{array}{l} \mathbf{if}\;n \leq -1.6 \cdot 10^{-131}:\\ \;\;\;\;\mathsf{fma}\left(i, n \cdot \mathsf{fma}\left(16.666666666666668, i, 50\right), n \cdot 100\right)\\ \mathbf{elif}\;n \leq 7.2 \cdot 10^{-130}:\\ \;\;\;\;100 \cdot \frac{n \cdot 1 - n}{i}\\ \mathbf{else}:\\ \;\;\;\;100 \cdot \mathsf{fma}\left(i, n \cdot \mathsf{fma}\left(i, \mathsf{fma}\left(i, 0.041666666666666664, 0.16666666666666666\right), 0.5\right), n\right)\\ \end{array} \]
                  6. Add Preprocessing

                  Alternative 12: 58.7% accurate, 5.0× speedup?

                  \[\begin{array}{l} \\ 100 \cdot \mathsf{fma}\left(i, n \cdot \mathsf{fma}\left(i, \mathsf{fma}\left(i, 0.041666666666666664, 0.16666666666666666\right), 0.5\right), n\right) \end{array} \]
                  (FPCore (i n)
                   :precision binary64
                   (*
                    100.0
                    (fma
                     i
                     (* n (fma i (fma i 0.041666666666666664 0.16666666666666666) 0.5))
                     n)))
                  double code(double i, double n) {
                  	return 100.0 * fma(i, (n * fma(i, fma(i, 0.041666666666666664, 0.16666666666666666), 0.5)), n);
                  }
                  
                  function code(i, n)
                  	return Float64(100.0 * fma(i, Float64(n * fma(i, fma(i, 0.041666666666666664, 0.16666666666666666), 0.5)), n))
                  end
                  
                  code[i_, n_] := N[(100.0 * N[(i * N[(n * N[(i * N[(i * 0.041666666666666664 + 0.16666666666666666), $MachinePrecision] + 0.5), $MachinePrecision]), $MachinePrecision] + n), $MachinePrecision]), $MachinePrecision]
                  
                  \begin{array}{l}
                  
                  \\
                  100 \cdot \mathsf{fma}\left(i, n \cdot \mathsf{fma}\left(i, \mathsf{fma}\left(i, 0.041666666666666664, 0.16666666666666666\right), 0.5\right), n\right)
                  \end{array}
                  
                  Derivation
                  1. Initial program 29.9%

                    \[100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}} \]
                  2. Add Preprocessing
                  3. Taylor expanded in n around inf

                    \[\leadsto 100 \cdot \color{blue}{\frac{n \cdot \left(e^{i} - 1\right)}{i}} \]
                  4. Step-by-step derivation
                    1. lower-/.f64N/A

                      \[\leadsto 100 \cdot \color{blue}{\frac{n \cdot \left(e^{i} - 1\right)}{i}} \]
                    2. lower-*.f64N/A

                      \[\leadsto 100 \cdot \frac{\color{blue}{n \cdot \left(e^{i} - 1\right)}}{i} \]
                    3. lower-expm1.f6468.5

                      \[\leadsto 100 \cdot \frac{n \cdot \color{blue}{\mathsf{expm1}\left(i\right)}}{i} \]
                  5. Applied rewrites68.5%

                    \[\leadsto 100 \cdot \color{blue}{\frac{n \cdot \mathsf{expm1}\left(i\right)}{i}} \]
                  6. Taylor expanded in i around 0

                    \[\leadsto 100 \cdot \left(n + \color{blue}{i \cdot \left(\frac{1}{2} \cdot n + i \cdot \left(\frac{1}{24} \cdot \left(i \cdot n\right) + \frac{1}{6} \cdot n\right)\right)}\right) \]
                  7. Step-by-step derivation
                    1. Applied rewrites54.0%

                      \[\leadsto 100 \cdot \mathsf{fma}\left(i, \color{blue}{\mathsf{fma}\left(n, 0.5, i \cdot \mathsf{fma}\left(n, 0.16666666666666666, 0.041666666666666664 \cdot \left(n \cdot i\right)\right)\right)}, n\right) \]
                    2. Taylor expanded in i around 0

                      \[\leadsto 100 \cdot \left(n + \color{blue}{i \cdot \left(\frac{1}{2} \cdot n + i \cdot \left(\frac{1}{24} \cdot \left(i \cdot n\right) + \frac{1}{6} \cdot n\right)\right)}\right) \]
                    3. Step-by-step derivation
                      1. Applied rewrites54.0%

                        \[\leadsto 100 \cdot \mathsf{fma}\left(i, \color{blue}{n \cdot \mathsf{fma}\left(i, \mathsf{fma}\left(i, 0.041666666666666664, 0.16666666666666666\right), 0.5\right)}, n\right) \]
                      2. Add Preprocessing

                      Alternative 13: 55.5% accurate, 5.2× speedup?

                      \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;i \leq 1.04 \cdot 10^{-128}:\\ \;\;\;\;n \cdot \mathsf{fma}\left(50, i, 100\right)\\ \mathbf{else}:\\ \;\;\;\;\frac{100}{i} \cdot \left(i \cdot n\right)\\ \end{array} \end{array} \]
                      (FPCore (i n)
                       :precision binary64
                       (if (<= i 1.04e-128) (* n (fma 50.0 i 100.0)) (* (/ 100.0 i) (* i n))))
                      double code(double i, double n) {
                      	double tmp;
                      	if (i <= 1.04e-128) {
                      		tmp = n * fma(50.0, i, 100.0);
                      	} else {
                      		tmp = (100.0 / i) * (i * n);
                      	}
                      	return tmp;
                      }
                      
                      function code(i, n)
                      	tmp = 0.0
                      	if (i <= 1.04e-128)
                      		tmp = Float64(n * fma(50.0, i, 100.0));
                      	else
                      		tmp = Float64(Float64(100.0 / i) * Float64(i * n));
                      	end
                      	return tmp
                      end
                      
                      code[i_, n_] := If[LessEqual[i, 1.04e-128], N[(n * N[(50.0 * i + 100.0), $MachinePrecision]), $MachinePrecision], N[(N[(100.0 / i), $MachinePrecision] * N[(i * n), $MachinePrecision]), $MachinePrecision]]
                      
                      \begin{array}{l}
                      
                      \\
                      \begin{array}{l}
                      \mathbf{if}\;i \leq 1.04 \cdot 10^{-128}:\\
                      \;\;\;\;n \cdot \mathsf{fma}\left(50, i, 100\right)\\
                      
                      \mathbf{else}:\\
                      \;\;\;\;\frac{100}{i} \cdot \left(i \cdot n\right)\\
                      
                      
                      \end{array}
                      \end{array}
                      
                      Derivation
                      1. Split input into 2 regimes
                      2. if i < 1.04e-128

                        1. Initial program 22.4%

                          \[100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}} \]
                        2. Add Preprocessing
                        3. Taylor expanded in n around inf

                          \[\leadsto \color{blue}{100 \cdot \frac{n \cdot \left(e^{i} - 1\right)}{i}} \]
                        4. Step-by-step derivation
                          1. associate-*r/N/A

                            \[\leadsto \color{blue}{\frac{100 \cdot \left(n \cdot \left(e^{i} - 1\right)\right)}{i}} \]
                          2. lower-/.f64N/A

                            \[\leadsto \color{blue}{\frac{100 \cdot \left(n \cdot \left(e^{i} - 1\right)\right)}{i}} \]
                          3. *-commutativeN/A

                            \[\leadsto \frac{\color{blue}{\left(n \cdot \left(e^{i} - 1\right)\right) \cdot 100}}{i} \]
                          4. lower-*.f64N/A

                            \[\leadsto \frac{\color{blue}{\left(n \cdot \left(e^{i} - 1\right)\right) \cdot 100}}{i} \]
                          5. lower-*.f64N/A

                            \[\leadsto \frac{\color{blue}{\left(n \cdot \left(e^{i} - 1\right)\right)} \cdot 100}{i} \]
                          6. lower-expm1.f6476.1

                            \[\leadsto \frac{\left(n \cdot \color{blue}{\mathsf{expm1}\left(i\right)}\right) \cdot 100}{i} \]
                        5. Applied rewrites76.1%

                          \[\leadsto \color{blue}{\frac{\left(n \cdot \mathsf{expm1}\left(i\right)\right) \cdot 100}{i}} \]
                        6. Taylor expanded in i around 0

                          \[\leadsto 50 \cdot \left(i \cdot n\right) + \color{blue}{100 \cdot n} \]
                        7. Step-by-step derivation
                          1. Applied rewrites60.1%

                            \[\leadsto n \cdot \color{blue}{\mathsf{fma}\left(50, i, 100\right)} \]

                          if 1.04e-128 < i

                          1. Initial program 44.5%

                            \[100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}} \]
                          2. Add Preprocessing
                          3. Taylor expanded in n around inf

                            \[\leadsto \color{blue}{100 \cdot \frac{n \cdot \left(e^{i} - 1\right)}{i}} \]
                          4. Step-by-step derivation
                            1. associate-*r/N/A

                              \[\leadsto \color{blue}{\frac{100 \cdot \left(n \cdot \left(e^{i} - 1\right)\right)}{i}} \]
                            2. lower-/.f64N/A

                              \[\leadsto \color{blue}{\frac{100 \cdot \left(n \cdot \left(e^{i} - 1\right)\right)}{i}} \]
                            3. *-commutativeN/A

                              \[\leadsto \frac{\color{blue}{\left(n \cdot \left(e^{i} - 1\right)\right) \cdot 100}}{i} \]
                            4. lower-*.f64N/A

                              \[\leadsto \frac{\color{blue}{\left(n \cdot \left(e^{i} - 1\right)\right) \cdot 100}}{i} \]
                            5. lower-*.f64N/A

                              \[\leadsto \frac{\color{blue}{\left(n \cdot \left(e^{i} - 1\right)\right)} \cdot 100}{i} \]
                            6. lower-expm1.f6453.4

                              \[\leadsto \frac{\left(n \cdot \color{blue}{\mathsf{expm1}\left(i\right)}\right) \cdot 100}{i} \]
                          5. Applied rewrites53.4%

                            \[\leadsto \color{blue}{\frac{\left(n \cdot \mathsf{expm1}\left(i\right)\right) \cdot 100}{i}} \]
                          6. Step-by-step derivation
                            1. Applied rewrites53.4%

                              \[\leadsto \frac{100}{i} \cdot \color{blue}{\left(n \cdot \mathsf{expm1}\left(i\right)\right)} \]
                            2. Taylor expanded in i around 0

                              \[\leadsto \frac{100}{i} \cdot \left(i \cdot \color{blue}{n}\right) \]
                            3. Step-by-step derivation
                              1. Applied rewrites40.1%

                                \[\leadsto \frac{100}{i} \cdot \left(n \cdot \color{blue}{i}\right) \]
                            4. Recombined 2 regimes into one program.
                            5. Final simplification53.3%

                              \[\leadsto \begin{array}{l} \mathbf{if}\;i \leq 1.04 \cdot 10^{-128}:\\ \;\;\;\;n \cdot \mathsf{fma}\left(50, i, 100\right)\\ \mathbf{else}:\\ \;\;\;\;\frac{100}{i} \cdot \left(i \cdot n\right)\\ \end{array} \]
                            6. Add Preprocessing

                            Alternative 14: 58.2% accurate, 5.4× speedup?

                            \[\begin{array}{l} \\ 100 \cdot \mathsf{fma}\left(i, n \cdot \left(0.041666666666666664 \cdot \left(i \cdot i\right)\right), n\right) \end{array} \]
                            (FPCore (i n)
                             :precision binary64
                             (* 100.0 (fma i (* n (* 0.041666666666666664 (* i i))) n)))
                            double code(double i, double n) {
                            	return 100.0 * fma(i, (n * (0.041666666666666664 * (i * i))), n);
                            }
                            
                            function code(i, n)
                            	return Float64(100.0 * fma(i, Float64(n * Float64(0.041666666666666664 * Float64(i * i))), n))
                            end
                            
                            code[i_, n_] := N[(100.0 * N[(i * N[(n * N[(0.041666666666666664 * N[(i * i), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] + n), $MachinePrecision]), $MachinePrecision]
                            
                            \begin{array}{l}
                            
                            \\
                            100 \cdot \mathsf{fma}\left(i, n \cdot \left(0.041666666666666664 \cdot \left(i \cdot i\right)\right), n\right)
                            \end{array}
                            
                            Derivation
                            1. Initial program 29.9%

                              \[100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}} \]
                            2. Add Preprocessing
                            3. Taylor expanded in n around inf

                              \[\leadsto 100 \cdot \color{blue}{\frac{n \cdot \left(e^{i} - 1\right)}{i}} \]
                            4. Step-by-step derivation
                              1. lower-/.f64N/A

                                \[\leadsto 100 \cdot \color{blue}{\frac{n \cdot \left(e^{i} - 1\right)}{i}} \]
                              2. lower-*.f64N/A

                                \[\leadsto 100 \cdot \frac{\color{blue}{n \cdot \left(e^{i} - 1\right)}}{i} \]
                              3. lower-expm1.f6468.5

                                \[\leadsto 100 \cdot \frac{n \cdot \color{blue}{\mathsf{expm1}\left(i\right)}}{i} \]
                            5. Applied rewrites68.5%

                              \[\leadsto 100 \cdot \color{blue}{\frac{n \cdot \mathsf{expm1}\left(i\right)}{i}} \]
                            6. Taylor expanded in i around 0

                              \[\leadsto 100 \cdot \left(n + \color{blue}{i \cdot \left(\frac{1}{2} \cdot n + i \cdot \left(\frac{1}{24} \cdot \left(i \cdot n\right) + \frac{1}{6} \cdot n\right)\right)}\right) \]
                            7. Step-by-step derivation
                              1. Applied rewrites54.0%

                                \[\leadsto 100 \cdot \mathsf{fma}\left(i, \color{blue}{\mathsf{fma}\left(n, 0.5, i \cdot \mathsf{fma}\left(n, 0.16666666666666666, 0.041666666666666664 \cdot \left(n \cdot i\right)\right)\right)}, n\right) \]
                              2. Taylor expanded in i around inf

                                \[\leadsto 100 \cdot \mathsf{fma}\left(i, \frac{1}{24} \cdot \left({i}^{2} \cdot \color{blue}{n}\right), n\right) \]
                              3. Step-by-step derivation
                                1. Applied rewrites53.9%

                                  \[\leadsto 100 \cdot \mathsf{fma}\left(i, n \cdot \left(0.041666666666666664 \cdot \color{blue}{\left(i \cdot i\right)}\right), n\right) \]
                                2. Add Preprocessing

                                Alternative 15: 57.2% accurate, 6.3× speedup?

                                \[\begin{array}{l} \\ \mathsf{fma}\left(i, n \cdot \mathsf{fma}\left(16.666666666666668, i, 50\right), n \cdot 100\right) \end{array} \]
                                (FPCore (i n)
                                 :precision binary64
                                 (fma i (* n (fma 16.666666666666668 i 50.0)) (* n 100.0)))
                                double code(double i, double n) {
                                	return fma(i, (n * fma(16.666666666666668, i, 50.0)), (n * 100.0));
                                }
                                
                                function code(i, n)
                                	return fma(i, Float64(n * fma(16.666666666666668, i, 50.0)), Float64(n * 100.0))
                                end
                                
                                code[i_, n_] := N[(i * N[(n * N[(16.666666666666668 * i + 50.0), $MachinePrecision]), $MachinePrecision] + N[(n * 100.0), $MachinePrecision]), $MachinePrecision]
                                
                                \begin{array}{l}
                                
                                \\
                                \mathsf{fma}\left(i, n \cdot \mathsf{fma}\left(16.666666666666668, i, 50\right), n \cdot 100\right)
                                \end{array}
                                
                                Derivation
                                1. Initial program 29.9%

                                  \[100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}} \]
                                2. Add Preprocessing
                                3. Taylor expanded in n around inf

                                  \[\leadsto \color{blue}{100 \cdot \frac{n \cdot \left(e^{i} - 1\right)}{i}} \]
                                4. Step-by-step derivation
                                  1. associate-*r/N/A

                                    \[\leadsto \color{blue}{\frac{100 \cdot \left(n \cdot \left(e^{i} - 1\right)\right)}{i}} \]
                                  2. lower-/.f64N/A

                                    \[\leadsto \color{blue}{\frac{100 \cdot \left(n \cdot \left(e^{i} - 1\right)\right)}{i}} \]
                                  3. *-commutativeN/A

                                    \[\leadsto \frac{\color{blue}{\left(n \cdot \left(e^{i} - 1\right)\right) \cdot 100}}{i} \]
                                  4. lower-*.f64N/A

                                    \[\leadsto \frac{\color{blue}{\left(n \cdot \left(e^{i} - 1\right)\right) \cdot 100}}{i} \]
                                  5. lower-*.f64N/A

                                    \[\leadsto \frac{\color{blue}{\left(n \cdot \left(e^{i} - 1\right)\right)} \cdot 100}{i} \]
                                  6. lower-expm1.f6468.4

                                    \[\leadsto \frac{\left(n \cdot \color{blue}{\mathsf{expm1}\left(i\right)}\right) \cdot 100}{i} \]
                                5. Applied rewrites68.4%

                                  \[\leadsto \color{blue}{\frac{\left(n \cdot \mathsf{expm1}\left(i\right)\right) \cdot 100}{i}} \]
                                6. Taylor expanded in i around 0

                                  \[\leadsto 100 \cdot n + \color{blue}{i \cdot \left(\frac{50}{3} \cdot \left(i \cdot n\right) + 50 \cdot n\right)} \]
                                7. Step-by-step derivation
                                  1. Applied rewrites52.0%

                                    \[\leadsto \mathsf{fma}\left(i, \color{blue}{n \cdot \mathsf{fma}\left(16.666666666666668, i, 50\right)}, n \cdot 100\right) \]
                                  2. Add Preprocessing

                                  Alternative 16: 53.2% accurate, 8.6× speedup?

                                  \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;i \leq 6.6 \cdot 10^{-46}:\\ \;\;\;\;n \cdot 100\\ \mathbf{else}:\\ \;\;\;\;50 \cdot \left(i \cdot n\right)\\ \end{array} \end{array} \]
                                  (FPCore (i n)
                                   :precision binary64
                                   (if (<= i 6.6e-46) (* n 100.0) (* 50.0 (* i n))))
                                  double code(double i, double n) {
                                  	double tmp;
                                  	if (i <= 6.6e-46) {
                                  		tmp = n * 100.0;
                                  	} else {
                                  		tmp = 50.0 * (i * n);
                                  	}
                                  	return tmp;
                                  }
                                  
                                  real(8) function code(i, n)
                                      real(8), intent (in) :: i
                                      real(8), intent (in) :: n
                                      real(8) :: tmp
                                      if (i <= 6.6d-46) then
                                          tmp = n * 100.0d0
                                      else
                                          tmp = 50.0d0 * (i * n)
                                      end if
                                      code = tmp
                                  end function
                                  
                                  public static double code(double i, double n) {
                                  	double tmp;
                                  	if (i <= 6.6e-46) {
                                  		tmp = n * 100.0;
                                  	} else {
                                  		tmp = 50.0 * (i * n);
                                  	}
                                  	return tmp;
                                  }
                                  
                                  def code(i, n):
                                  	tmp = 0
                                  	if i <= 6.6e-46:
                                  		tmp = n * 100.0
                                  	else:
                                  		tmp = 50.0 * (i * n)
                                  	return tmp
                                  
                                  function code(i, n)
                                  	tmp = 0.0
                                  	if (i <= 6.6e-46)
                                  		tmp = Float64(n * 100.0);
                                  	else
                                  		tmp = Float64(50.0 * Float64(i * n));
                                  	end
                                  	return tmp
                                  end
                                  
                                  function tmp_2 = code(i, n)
                                  	tmp = 0.0;
                                  	if (i <= 6.6e-46)
                                  		tmp = n * 100.0;
                                  	else
                                  		tmp = 50.0 * (i * n);
                                  	end
                                  	tmp_2 = tmp;
                                  end
                                  
                                  code[i_, n_] := If[LessEqual[i, 6.6e-46], N[(n * 100.0), $MachinePrecision], N[(50.0 * N[(i * n), $MachinePrecision]), $MachinePrecision]]
                                  
                                  \begin{array}{l}
                                  
                                  \\
                                  \begin{array}{l}
                                  \mathbf{if}\;i \leq 6.6 \cdot 10^{-46}:\\
                                  \;\;\;\;n \cdot 100\\
                                  
                                  \mathbf{else}:\\
                                  \;\;\;\;50 \cdot \left(i \cdot n\right)\\
                                  
                                  
                                  \end{array}
                                  \end{array}
                                  
                                  Derivation
                                  1. Split input into 2 regimes
                                  2. if i < 6.60000000000000027e-46

                                    1. Initial program 21.9%

                                      \[100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}} \]
                                    2. Add Preprocessing
                                    3. Taylor expanded in i around 0

                                      \[\leadsto \color{blue}{100 \cdot n} \]
                                    4. Step-by-step derivation
                                      1. *-commutativeN/A

                                        \[\leadsto \color{blue}{n \cdot 100} \]
                                      2. lower-*.f6461.0

                                        \[\leadsto \color{blue}{n \cdot 100} \]
                                    5. Applied rewrites61.0%

                                      \[\leadsto \color{blue}{n \cdot 100} \]

                                    if 6.60000000000000027e-46 < i

                                    1. Initial program 53.9%

                                      \[100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}} \]
                                    2. Add Preprocessing
                                    3. Taylor expanded in n around inf

                                      \[\leadsto \color{blue}{100 \cdot \frac{n \cdot \left(e^{i} - 1\right)}{i}} \]
                                    4. Step-by-step derivation
                                      1. associate-*r/N/A

                                        \[\leadsto \color{blue}{\frac{100 \cdot \left(n \cdot \left(e^{i} - 1\right)\right)}{i}} \]
                                      2. lower-/.f64N/A

                                        \[\leadsto \color{blue}{\frac{100 \cdot \left(n \cdot \left(e^{i} - 1\right)\right)}{i}} \]
                                      3. *-commutativeN/A

                                        \[\leadsto \frac{\color{blue}{\left(n \cdot \left(e^{i} - 1\right)\right) \cdot 100}}{i} \]
                                      4. lower-*.f64N/A

                                        \[\leadsto \frac{\color{blue}{\left(n \cdot \left(e^{i} - 1\right)\right) \cdot 100}}{i} \]
                                      5. lower-*.f64N/A

                                        \[\leadsto \frac{\color{blue}{\left(n \cdot \left(e^{i} - 1\right)\right)} \cdot 100}{i} \]
                                      6. lower-expm1.f6443.2

                                        \[\leadsto \frac{\left(n \cdot \color{blue}{\mathsf{expm1}\left(i\right)}\right) \cdot 100}{i} \]
                                    5. Applied rewrites43.2%

                                      \[\leadsto \color{blue}{\frac{\left(n \cdot \mathsf{expm1}\left(i\right)\right) \cdot 100}{i}} \]
                                    6. Taylor expanded in i around 0

                                      \[\leadsto 50 \cdot \left(i \cdot n\right) + \color{blue}{100 \cdot n} \]
                                    7. Step-by-step derivation
                                      1. Applied rewrites23.3%

                                        \[\leadsto n \cdot \color{blue}{\mathsf{fma}\left(50, i, 100\right)} \]
                                      2. Taylor expanded in i around inf

                                        \[\leadsto 50 \cdot \left(i \cdot \color{blue}{n}\right) \]
                                      3. Step-by-step derivation
                                        1. Applied rewrites23.3%

                                          \[\leadsto 50 \cdot \left(n \cdot \color{blue}{i}\right) \]
                                      4. Recombined 2 regimes into one program.
                                      5. Final simplification51.6%

                                        \[\leadsto \begin{array}{l} \mathbf{if}\;i \leq 6.6 \cdot 10^{-46}:\\ \;\;\;\;n \cdot 100\\ \mathbf{else}:\\ \;\;\;\;50 \cdot \left(i \cdot n\right)\\ \end{array} \]
                                      6. Add Preprocessing

                                      Alternative 17: 55.2% accurate, 12.2× speedup?

                                      \[\begin{array}{l} \\ n \cdot \mathsf{fma}\left(50, i, 100\right) \end{array} \]
                                      (FPCore (i n) :precision binary64 (* n (fma 50.0 i 100.0)))
                                      double code(double i, double n) {
                                      	return n * fma(50.0, i, 100.0);
                                      }
                                      
                                      function code(i, n)
                                      	return Float64(n * fma(50.0, i, 100.0))
                                      end
                                      
                                      code[i_, n_] := N[(n * N[(50.0 * i + 100.0), $MachinePrecision]), $MachinePrecision]
                                      
                                      \begin{array}{l}
                                      
                                      \\
                                      n \cdot \mathsf{fma}\left(50, i, 100\right)
                                      \end{array}
                                      
                                      Derivation
                                      1. Initial program 29.9%

                                        \[100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}} \]
                                      2. Add Preprocessing
                                      3. Taylor expanded in n around inf

                                        \[\leadsto \color{blue}{100 \cdot \frac{n \cdot \left(e^{i} - 1\right)}{i}} \]
                                      4. Step-by-step derivation
                                        1. associate-*r/N/A

                                          \[\leadsto \color{blue}{\frac{100 \cdot \left(n \cdot \left(e^{i} - 1\right)\right)}{i}} \]
                                        2. lower-/.f64N/A

                                          \[\leadsto \color{blue}{\frac{100 \cdot \left(n \cdot \left(e^{i} - 1\right)\right)}{i}} \]
                                        3. *-commutativeN/A

                                          \[\leadsto \frac{\color{blue}{\left(n \cdot \left(e^{i} - 1\right)\right) \cdot 100}}{i} \]
                                        4. lower-*.f64N/A

                                          \[\leadsto \frac{\color{blue}{\left(n \cdot \left(e^{i} - 1\right)\right) \cdot 100}}{i} \]
                                        5. lower-*.f64N/A

                                          \[\leadsto \frac{\color{blue}{\left(n \cdot \left(e^{i} - 1\right)\right)} \cdot 100}{i} \]
                                        6. lower-expm1.f6468.4

                                          \[\leadsto \frac{\left(n \cdot \color{blue}{\mathsf{expm1}\left(i\right)}\right) \cdot 100}{i} \]
                                      5. Applied rewrites68.4%

                                        \[\leadsto \color{blue}{\frac{\left(n \cdot \mathsf{expm1}\left(i\right)\right) \cdot 100}{i}} \]
                                      6. Taylor expanded in i around 0

                                        \[\leadsto 50 \cdot \left(i \cdot n\right) + \color{blue}{100 \cdot n} \]
                                      7. Step-by-step derivation
                                        1. Applied rewrites51.6%

                                          \[\leadsto n \cdot \color{blue}{\mathsf{fma}\left(50, i, 100\right)} \]
                                        2. Add Preprocessing

                                        Alternative 18: 49.4% accurate, 24.3× speedup?

                                        \[\begin{array}{l} \\ n \cdot 100 \end{array} \]
                                        (FPCore (i n) :precision binary64 (* n 100.0))
                                        double code(double i, double n) {
                                        	return n * 100.0;
                                        }
                                        
                                        real(8) function code(i, n)
                                            real(8), intent (in) :: i
                                            real(8), intent (in) :: n
                                            code = n * 100.0d0
                                        end function
                                        
                                        public static double code(double i, double n) {
                                        	return n * 100.0;
                                        }
                                        
                                        def code(i, n):
                                        	return n * 100.0
                                        
                                        function code(i, n)
                                        	return Float64(n * 100.0)
                                        end
                                        
                                        function tmp = code(i, n)
                                        	tmp = n * 100.0;
                                        end
                                        
                                        code[i_, n_] := N[(n * 100.0), $MachinePrecision]
                                        
                                        \begin{array}{l}
                                        
                                        \\
                                        n \cdot 100
                                        \end{array}
                                        
                                        Derivation
                                        1. Initial program 29.9%

                                          \[100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}} \]
                                        2. Add Preprocessing
                                        3. Taylor expanded in i around 0

                                          \[\leadsto \color{blue}{100 \cdot n} \]
                                        4. Step-by-step derivation
                                          1. *-commutativeN/A

                                            \[\leadsto \color{blue}{n \cdot 100} \]
                                          2. lower-*.f6447.3

                                            \[\leadsto \color{blue}{n \cdot 100} \]
                                        5. Applied rewrites47.3%

                                          \[\leadsto \color{blue}{n \cdot 100} \]
                                        6. Add Preprocessing

                                        Developer Target 1: 34.3% accurate, 0.5× speedup?

                                        \[\begin{array}{l} \\ \begin{array}{l} t_0 := 1 + \frac{i}{n}\\ 100 \cdot \frac{e^{n \cdot \begin{array}{l} \mathbf{if}\;t\_0 = 1:\\ \;\;\;\;\frac{i}{n}\\ \mathbf{else}:\\ \;\;\;\;\frac{\frac{i}{n} \cdot \log t\_0}{\left(\frac{i}{n} + 1\right) - 1}\\ \end{array}} - 1}{\frac{i}{n}} \end{array} \end{array} \]
                                        (FPCore (i n)
                                         :precision binary64
                                         (let* ((t_0 (+ 1.0 (/ i n))))
                                           (*
                                            100.0
                                            (/
                                             (-
                                              (exp
                                               (*
                                                n
                                                (if (== t_0 1.0)
                                                  (/ i n)
                                                  (/ (* (/ i n) (log t_0)) (- (+ (/ i n) 1.0) 1.0)))))
                                              1.0)
                                             (/ i n)))))
                                        double code(double i, double n) {
                                        	double t_0 = 1.0 + (i / n);
                                        	double tmp;
                                        	if (t_0 == 1.0) {
                                        		tmp = i / n;
                                        	} else {
                                        		tmp = ((i / n) * log(t_0)) / (((i / n) + 1.0) - 1.0);
                                        	}
                                        	return 100.0 * ((exp((n * tmp)) - 1.0) / (i / n));
                                        }
                                        
                                        real(8) function code(i, n)
                                            real(8), intent (in) :: i
                                            real(8), intent (in) :: n
                                            real(8) :: t_0
                                            real(8) :: tmp
                                            t_0 = 1.0d0 + (i / n)
                                            if (t_0 == 1.0d0) then
                                                tmp = i / n
                                            else
                                                tmp = ((i / n) * log(t_0)) / (((i / n) + 1.0d0) - 1.0d0)
                                            end if
                                            code = 100.0d0 * ((exp((n * tmp)) - 1.0d0) / (i / n))
                                        end function
                                        
                                        public static double code(double i, double n) {
                                        	double t_0 = 1.0 + (i / n);
                                        	double tmp;
                                        	if (t_0 == 1.0) {
                                        		tmp = i / n;
                                        	} else {
                                        		tmp = ((i / n) * Math.log(t_0)) / (((i / n) + 1.0) - 1.0);
                                        	}
                                        	return 100.0 * ((Math.exp((n * tmp)) - 1.0) / (i / n));
                                        }
                                        
                                        def code(i, n):
                                        	t_0 = 1.0 + (i / n)
                                        	tmp = 0
                                        	if t_0 == 1.0:
                                        		tmp = i / n
                                        	else:
                                        		tmp = ((i / n) * math.log(t_0)) / (((i / n) + 1.0) - 1.0)
                                        	return 100.0 * ((math.exp((n * tmp)) - 1.0) / (i / n))
                                        
                                        function code(i, n)
                                        	t_0 = Float64(1.0 + Float64(i / n))
                                        	tmp = 0.0
                                        	if (t_0 == 1.0)
                                        		tmp = Float64(i / n);
                                        	else
                                        		tmp = Float64(Float64(Float64(i / n) * log(t_0)) / Float64(Float64(Float64(i / n) + 1.0) - 1.0));
                                        	end
                                        	return Float64(100.0 * Float64(Float64(exp(Float64(n * tmp)) - 1.0) / Float64(i / n)))
                                        end
                                        
                                        function tmp_2 = code(i, n)
                                        	t_0 = 1.0 + (i / n);
                                        	tmp = 0.0;
                                        	if (t_0 == 1.0)
                                        		tmp = i / n;
                                        	else
                                        		tmp = ((i / n) * log(t_0)) / (((i / n) + 1.0) - 1.0);
                                        	end
                                        	tmp_2 = 100.0 * ((exp((n * tmp)) - 1.0) / (i / n));
                                        end
                                        
                                        code[i_, n_] := Block[{t$95$0 = N[(1.0 + N[(i / n), $MachinePrecision]), $MachinePrecision]}, N[(100.0 * N[(N[(N[Exp[N[(n * If[Equal[t$95$0, 1.0], N[(i / n), $MachinePrecision], N[(N[(N[(i / n), $MachinePrecision] * N[Log[t$95$0], $MachinePrecision]), $MachinePrecision] / N[(N[(N[(i / n), $MachinePrecision] + 1.0), $MachinePrecision] - 1.0), $MachinePrecision]), $MachinePrecision]]), $MachinePrecision]], $MachinePrecision] - 1.0), $MachinePrecision] / N[(i / n), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]]
                                        
                                        \begin{array}{l}
                                        
                                        \\
                                        \begin{array}{l}
                                        t_0 := 1 + \frac{i}{n}\\
                                        100 \cdot \frac{e^{n \cdot \begin{array}{l}
                                        \mathbf{if}\;t\_0 = 1:\\
                                        \;\;\;\;\frac{i}{n}\\
                                        
                                        \mathbf{else}:\\
                                        \;\;\;\;\frac{\frac{i}{n} \cdot \log t\_0}{\left(\frac{i}{n} + 1\right) - 1}\\
                                        
                                        
                                        \end{array}} - 1}{\frac{i}{n}}
                                        \end{array}
                                        \end{array}
                                        

                                        Reproduce

                                        ?
                                        herbie shell --seed 2024219 
                                        (FPCore (i n)
                                          :name "Compound Interest"
                                          :precision binary64
                                        
                                          :alt
                                          (! :herbie-platform default (let ((lnbase (if (== (+ 1 (/ i n)) 1) (/ i n) (/ (* (/ i n) (log (+ 1 (/ i n)))) (- (+ (/ i n) 1) 1))))) (* 100 (/ (- (exp (* n lnbase)) 1) (/ i n)))))
                                        
                                          (* 100.0 (/ (- (pow (+ 1.0 (/ i n)) n) 1.0) (/ i n))))