Data.Random.Distribution.Normal:normalF from random-fu-0.2.6.2

Percentage Accurate: 100.0% → 100.0%
Time: 28.3s
Alternatives: 14
Speedup: 1.0×

Specification

?
\[\begin{array}{l} \\ e^{\left(x \cdot y\right) \cdot y} \end{array} \]
(FPCore (x y) :precision binary64 (exp (* (* x y) y)))
double code(double x, double y) {
	return exp(((x * y) * y));
}
real(8) function code(x, y)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    code = exp(((x * y) * y))
end function
public static double code(double x, double y) {
	return Math.exp(((x * y) * y));
}
def code(x, y):
	return math.exp(((x * y) * y))
function code(x, y)
	return exp(Float64(Float64(x * y) * y))
end
function tmp = code(x, y)
	tmp = exp(((x * y) * y));
end
code[x_, y_] := N[Exp[N[(N[(x * y), $MachinePrecision] * y), $MachinePrecision]], $MachinePrecision]
\begin{array}{l}

\\
e^{\left(x \cdot y\right) \cdot y}
\end{array}

Sampling outcomes in binary64 precision:

Local Percentage Accuracy vs ?

The average percentage accuracy by input value. Horizontal axis shows value of an input variable; the variable is choosen in the title. Vertical axis is accuracy; higher is better. Red represent the original program, while blue represents Herbie's suggestion. These can be toggled with buttons below the plot. The line is an average while dots represent individual samples.

Accuracy vs Speed?

Herbie found 14 alternatives:

AlternativeAccuracySpeedup
The accuracy (vertical axis) and speed (horizontal axis) of each alternatives. Up and to the right is better. The red square shows the initial program, and each blue circle shows an alternative.The line shows the best available speed-accuracy tradeoffs.

Initial Program: 100.0% accurate, 1.0× speedup?

\[\begin{array}{l} \\ e^{\left(x \cdot y\right) \cdot y} \end{array} \]
(FPCore (x y) :precision binary64 (exp (* (* x y) y)))
double code(double x, double y) {
	return exp(((x * y) * y));
}
real(8) function code(x, y)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    code = exp(((x * y) * y))
end function
public static double code(double x, double y) {
	return Math.exp(((x * y) * y));
}
def code(x, y):
	return math.exp(((x * y) * y))
function code(x, y)
	return exp(Float64(Float64(x * y) * y))
end
function tmp = code(x, y)
	tmp = exp(((x * y) * y));
end
code[x_, y_] := N[Exp[N[(N[(x * y), $MachinePrecision] * y), $MachinePrecision]], $MachinePrecision]
\begin{array}{l}

\\
e^{\left(x \cdot y\right) \cdot y}
\end{array}

Alternative 1: 100.0% accurate, 1.0× speedup?

\[\begin{array}{l} \\ e^{y \cdot \left(x \cdot y\right)} \end{array} \]
(FPCore (x y) :precision binary64 (exp (* y (* x y))))
double code(double x, double y) {
	return exp((y * (x * y)));
}
real(8) function code(x, y)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    code = exp((y * (x * y)))
end function
public static double code(double x, double y) {
	return Math.exp((y * (x * y)));
}
def code(x, y):
	return math.exp((y * (x * y)))
function code(x, y)
	return exp(Float64(y * Float64(x * y)))
end
function tmp = code(x, y)
	tmp = exp((y * (x * y)));
end
code[x_, y_] := N[Exp[N[(y * N[(x * y), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]
\begin{array}{l}

\\
e^{y \cdot \left(x \cdot y\right)}
\end{array}
Derivation
  1. Initial program 100.0%

    \[e^{\left(x \cdot y\right) \cdot y} \]
  2. Add Preprocessing
  3. Final simplification100.0%

    \[\leadsto e^{y \cdot \left(x \cdot y\right)} \]
  4. Add Preprocessing

Alternative 2: 75.7% accurate, 0.7× speedup?

\[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;e^{y \cdot \left(x \cdot y\right)} \leq 10^{-127}:\\ \;\;\;\;y \cdot \left(y \cdot \left(y \cdot \left(y \cdot \left(0.5 \cdot \left(x \cdot x\right)\right)\right)\right)\right)\\ \mathbf{else}:\\ \;\;\;\;\mathsf{fma}\left(y \cdot y, \mathsf{fma}\left(x \cdot \left(x \cdot \left(y \cdot y\right)\right), \mathsf{fma}\left(x, \left(y \cdot y\right) \cdot 0.16666666666666666, 0.5\right), x\right), 1\right)\\ \end{array} \end{array} \]
(FPCore (x y)
 :precision binary64
 (if (<= (exp (* y (* x y))) 1e-127)
   (* y (* y (* y (* y (* 0.5 (* x x))))))
   (fma
    (* y y)
    (fma (* x (* x (* y y))) (fma x (* (* y y) 0.16666666666666666) 0.5) x)
    1.0)))
double code(double x, double y) {
	double tmp;
	if (exp((y * (x * y))) <= 1e-127) {
		tmp = y * (y * (y * (y * (0.5 * (x * x)))));
	} else {
		tmp = fma((y * y), fma((x * (x * (y * y))), fma(x, ((y * y) * 0.16666666666666666), 0.5), x), 1.0);
	}
	return tmp;
}
function code(x, y)
	tmp = 0.0
	if (exp(Float64(y * Float64(x * y))) <= 1e-127)
		tmp = Float64(y * Float64(y * Float64(y * Float64(y * Float64(0.5 * Float64(x * x))))));
	else
		tmp = fma(Float64(y * y), fma(Float64(x * Float64(x * Float64(y * y))), fma(x, Float64(Float64(y * y) * 0.16666666666666666), 0.5), x), 1.0);
	end
	return tmp
end
code[x_, y_] := If[LessEqual[N[Exp[N[(y * N[(x * y), $MachinePrecision]), $MachinePrecision]], $MachinePrecision], 1e-127], N[(y * N[(y * N[(y * N[(y * N[(0.5 * N[(x * x), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], N[(N[(y * y), $MachinePrecision] * N[(N[(x * N[(x * N[(y * y), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] * N[(x * N[(N[(y * y), $MachinePrecision] * 0.16666666666666666), $MachinePrecision] + 0.5), $MachinePrecision] + x), $MachinePrecision] + 1.0), $MachinePrecision]]
\begin{array}{l}

\\
\begin{array}{l}
\mathbf{if}\;e^{y \cdot \left(x \cdot y\right)} \leq 10^{-127}:\\
\;\;\;\;y \cdot \left(y \cdot \left(y \cdot \left(y \cdot \left(0.5 \cdot \left(x \cdot x\right)\right)\right)\right)\right)\\

\mathbf{else}:\\
\;\;\;\;\mathsf{fma}\left(y \cdot y, \mathsf{fma}\left(x \cdot \left(x \cdot \left(y \cdot y\right)\right), \mathsf{fma}\left(x, \left(y \cdot y\right) \cdot 0.16666666666666666, 0.5\right), x\right), 1\right)\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if (exp.f64 (*.f64 (*.f64 x y) y)) < 1e-127

    1. Initial program 99.8%

      \[e^{\left(x \cdot y\right) \cdot y} \]
    2. Add Preprocessing
    3. Taylor expanded in x around 0

      \[\leadsto \color{blue}{1 + x \cdot \left(\frac{1}{2} \cdot \left(x \cdot {y}^{4}\right) + {y}^{2}\right)} \]
    4. Step-by-step derivation
      1. +-commutativeN/A

        \[\leadsto \color{blue}{x \cdot \left(\frac{1}{2} \cdot \left(x \cdot {y}^{4}\right) + {y}^{2}\right) + 1} \]
    5. Applied rewrites1.8%

      \[\leadsto \color{blue}{\mathsf{fma}\left(y \cdot y, \mathsf{fma}\left(x, \left(x \cdot \left(y \cdot y\right)\right) \cdot 0.5, x\right), 1\right)} \]
    6. Taylor expanded in x around inf

      \[\leadsto {x}^{2} \cdot \color{blue}{\left(\frac{1}{2} \cdot {y}^{4} + \frac{{y}^{2}}{x}\right)} \]
    7. Step-by-step derivation
      1. Applied rewrites1.8%

        \[\leadsto y \cdot \color{blue}{\left(y \cdot \mathsf{fma}\left(0.5, x \cdot \left(x \cdot \left(y \cdot y\right)\right), x\right)\right)} \]
      2. Taylor expanded in y around inf

        \[\leadsto y \cdot \left(\frac{1}{2} \cdot \left({x}^{2} \cdot \color{blue}{{y}^{3}}\right)\right) \]
      3. Step-by-step derivation
        1. Applied rewrites3.4%

          \[\leadsto y \cdot \left(x \cdot \left(0.5 \cdot \color{blue}{\left(x \cdot \left(y \cdot \left(y \cdot y\right)\right)\right)}\right)\right) \]
        2. Taylor expanded in y around inf

          \[\leadsto y \cdot \left(\frac{1}{2} \cdot \left({x}^{2} \cdot \color{blue}{{y}^{3}}\right)\right) \]
        3. Step-by-step derivation
          1. Applied rewrites15.2%

            \[\leadsto y \cdot \left(y \cdot \left(y \cdot \color{blue}{\left(y \cdot \left(0.5 \cdot \left(x \cdot x\right)\right)\right)}\right)\right) \]

          if 1e-127 < (exp.f64 (*.f64 (*.f64 x y) y))

          1. Initial program 100.0%

            \[e^{\left(x \cdot y\right) \cdot y} \]
          2. Add Preprocessing
          3. Taylor expanded in x around 0

            \[\leadsto \color{blue}{1 + x \cdot \left(x \cdot \left(\frac{1}{6} \cdot \left(x \cdot {y}^{6}\right) + \frac{1}{2} \cdot {y}^{4}\right) + {y}^{2}\right)} \]
          4. Applied rewrites97.2%

            \[\leadsto \color{blue}{\mathsf{fma}\left(y \cdot y, \mathsf{fma}\left(x \cdot \left(x \cdot \left(y \cdot y\right)\right), \mathsf{fma}\left(x, \left(y \cdot y\right) \cdot 0.16666666666666666, 0.5\right), x\right), 1\right)} \]
        4. Recombined 2 regimes into one program.
        5. Final simplification78.6%

          \[\leadsto \begin{array}{l} \mathbf{if}\;e^{y \cdot \left(x \cdot y\right)} \leq 10^{-127}:\\ \;\;\;\;y \cdot \left(y \cdot \left(y \cdot \left(y \cdot \left(0.5 \cdot \left(x \cdot x\right)\right)\right)\right)\right)\\ \mathbf{else}:\\ \;\;\;\;\mathsf{fma}\left(y \cdot y, \mathsf{fma}\left(x \cdot \left(x \cdot \left(y \cdot y\right)\right), \mathsf{fma}\left(x, \left(y \cdot y\right) \cdot 0.16666666666666666, 0.5\right), x\right), 1\right)\\ \end{array} \]
        6. Add Preprocessing

        Alternative 3: 75.6% accurate, 0.7× speedup?

        \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;e^{y \cdot \left(x \cdot y\right)} \leq 0.5:\\ \;\;\;\;y \cdot \left(y \cdot \left(y \cdot \left(y \cdot \left(0.5 \cdot \left(x \cdot x\right)\right)\right)\right)\right)\\ \mathbf{else}:\\ \;\;\;\;\mathsf{fma}\left(y \cdot y, \mathsf{fma}\left(x \cdot \left(x \cdot \left(y \cdot y\right)\right), x \cdot \left(\left(y \cdot y\right) \cdot 0.16666666666666666\right), x\right), 1\right)\\ \end{array} \end{array} \]
        (FPCore (x y)
         :precision binary64
         (if (<= (exp (* y (* x y))) 0.5)
           (* y (* y (* y (* y (* 0.5 (* x x))))))
           (fma
            (* y y)
            (fma (* x (* x (* y y))) (* x (* (* y y) 0.16666666666666666)) x)
            1.0)))
        double code(double x, double y) {
        	double tmp;
        	if (exp((y * (x * y))) <= 0.5) {
        		tmp = y * (y * (y * (y * (0.5 * (x * x)))));
        	} else {
        		tmp = fma((y * y), fma((x * (x * (y * y))), (x * ((y * y) * 0.16666666666666666)), x), 1.0);
        	}
        	return tmp;
        }
        
        function code(x, y)
        	tmp = 0.0
        	if (exp(Float64(y * Float64(x * y))) <= 0.5)
        		tmp = Float64(y * Float64(y * Float64(y * Float64(y * Float64(0.5 * Float64(x * x))))));
        	else
        		tmp = fma(Float64(y * y), fma(Float64(x * Float64(x * Float64(y * y))), Float64(x * Float64(Float64(y * y) * 0.16666666666666666)), x), 1.0);
        	end
        	return tmp
        end
        
        code[x_, y_] := If[LessEqual[N[Exp[N[(y * N[(x * y), $MachinePrecision]), $MachinePrecision]], $MachinePrecision], 0.5], N[(y * N[(y * N[(y * N[(y * N[(0.5 * N[(x * x), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], N[(N[(y * y), $MachinePrecision] * N[(N[(x * N[(x * N[(y * y), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] * N[(x * N[(N[(y * y), $MachinePrecision] * 0.16666666666666666), $MachinePrecision]), $MachinePrecision] + x), $MachinePrecision] + 1.0), $MachinePrecision]]
        
        \begin{array}{l}
        
        \\
        \begin{array}{l}
        \mathbf{if}\;e^{y \cdot \left(x \cdot y\right)} \leq 0.5:\\
        \;\;\;\;y \cdot \left(y \cdot \left(y \cdot \left(y \cdot \left(0.5 \cdot \left(x \cdot x\right)\right)\right)\right)\right)\\
        
        \mathbf{else}:\\
        \;\;\;\;\mathsf{fma}\left(y \cdot y, \mathsf{fma}\left(x \cdot \left(x \cdot \left(y \cdot y\right)\right), x \cdot \left(\left(y \cdot y\right) \cdot 0.16666666666666666\right), x\right), 1\right)\\
        
        
        \end{array}
        \end{array}
        
        Derivation
        1. Split input into 2 regimes
        2. if (exp.f64 (*.f64 (*.f64 x y) y)) < 0.5

          1. Initial program 99.8%

            \[e^{\left(x \cdot y\right) \cdot y} \]
          2. Add Preprocessing
          3. Taylor expanded in x around 0

            \[\leadsto \color{blue}{1 + x \cdot \left(\frac{1}{2} \cdot \left(x \cdot {y}^{4}\right) + {y}^{2}\right)} \]
          4. Step-by-step derivation
            1. +-commutativeN/A

              \[\leadsto \color{blue}{x \cdot \left(\frac{1}{2} \cdot \left(x \cdot {y}^{4}\right) + {y}^{2}\right) + 1} \]
          5. Applied rewrites2.1%

            \[\leadsto \color{blue}{\mathsf{fma}\left(y \cdot y, \mathsf{fma}\left(x, \left(x \cdot \left(y \cdot y\right)\right) \cdot 0.5, x\right), 1\right)} \]
          6. Taylor expanded in x around inf

            \[\leadsto {x}^{2} \cdot \color{blue}{\left(\frac{1}{2} \cdot {y}^{4} + \frac{{y}^{2}}{x}\right)} \]
          7. Step-by-step derivation
            1. Applied rewrites1.7%

              \[\leadsto y \cdot \color{blue}{\left(y \cdot \mathsf{fma}\left(0.5, x \cdot \left(x \cdot \left(y \cdot y\right)\right), x\right)\right)} \]
            2. Taylor expanded in y around inf

              \[\leadsto y \cdot \left(\frac{1}{2} \cdot \left({x}^{2} \cdot \color{blue}{{y}^{3}}\right)\right) \]
            3. Step-by-step derivation
              1. Applied rewrites3.4%

                \[\leadsto y \cdot \left(x \cdot \left(0.5 \cdot \color{blue}{\left(x \cdot \left(y \cdot \left(y \cdot y\right)\right)\right)}\right)\right) \]
              2. Taylor expanded in y around inf

                \[\leadsto y \cdot \left(\frac{1}{2} \cdot \left({x}^{2} \cdot \color{blue}{{y}^{3}}\right)\right) \]
              3. Step-by-step derivation
                1. Applied rewrites15.0%

                  \[\leadsto y \cdot \left(y \cdot \left(y \cdot \color{blue}{\left(y \cdot \left(0.5 \cdot \left(x \cdot x\right)\right)\right)}\right)\right) \]

                if 0.5 < (exp.f64 (*.f64 (*.f64 x y) y))

                1. Initial program 100.0%

                  \[e^{\left(x \cdot y\right) \cdot y} \]
                2. Add Preprocessing
                3. Taylor expanded in x around 0

                  \[\leadsto \color{blue}{1 + x \cdot \left(x \cdot \left(\frac{1}{6} \cdot \left(x \cdot {y}^{6}\right) + \frac{1}{2} \cdot {y}^{4}\right) + {y}^{2}\right)} \]
                4. Applied rewrites97.6%

                  \[\leadsto \color{blue}{\mathsf{fma}\left(y \cdot y, \mathsf{fma}\left(x \cdot \left(x \cdot \left(y \cdot y\right)\right), \mathsf{fma}\left(x, \left(y \cdot y\right) \cdot 0.16666666666666666, 0.5\right), x\right), 1\right)} \]
                5. Taylor expanded in x around inf

                  \[\leadsto \mathsf{fma}\left(y \cdot y, \mathsf{fma}\left(x \cdot \left(x \cdot \left(y \cdot y\right)\right), \frac{1}{6} \cdot \color{blue}{\left(x \cdot {y}^{2}\right)}, x\right), 1\right) \]
                6. Step-by-step derivation
                  1. Applied rewrites97.4%

                    \[\leadsto \mathsf{fma}\left(y \cdot y, \mathsf{fma}\left(x \cdot \left(x \cdot \left(y \cdot y\right)\right), x \cdot \color{blue}{\left(\left(y \cdot y\right) \cdot 0.16666666666666666\right)}, x\right), 1\right) \]
                7. Recombined 2 regimes into one program.
                8. Final simplification78.4%

                  \[\leadsto \begin{array}{l} \mathbf{if}\;e^{y \cdot \left(x \cdot y\right)} \leq 0.5:\\ \;\;\;\;y \cdot \left(y \cdot \left(y \cdot \left(y \cdot \left(0.5 \cdot \left(x \cdot x\right)\right)\right)\right)\right)\\ \mathbf{else}:\\ \;\;\;\;\mathsf{fma}\left(y \cdot y, \mathsf{fma}\left(x \cdot \left(x \cdot \left(y \cdot y\right)\right), x \cdot \left(\left(y \cdot y\right) \cdot 0.16666666666666666\right), x\right), 1\right)\\ \end{array} \]
                9. Add Preprocessing

                Alternative 4: 74.6% accurate, 0.7× speedup?

                \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;e^{y \cdot \left(x \cdot y\right)} \leq 0:\\ \;\;\;\;y \cdot \left(y \cdot \left(y \cdot \left(y \cdot \left(0.5 \cdot \left(x \cdot x\right)\right)\right)\right)\right)\\ \mathbf{else}:\\ \;\;\;\;\mathsf{fma}\left(y \cdot y, \mathsf{fma}\left(x, \left(x \cdot \left(y \cdot y\right)\right) \cdot 0.5, x\right), 1\right)\\ \end{array} \end{array} \]
                (FPCore (x y)
                 :precision binary64
                 (if (<= (exp (* y (* x y))) 0.0)
                   (* y (* y (* y (* y (* 0.5 (* x x))))))
                   (fma (* y y) (fma x (* (* x (* y y)) 0.5) x) 1.0)))
                double code(double x, double y) {
                	double tmp;
                	if (exp((y * (x * y))) <= 0.0) {
                		tmp = y * (y * (y * (y * (0.5 * (x * x)))));
                	} else {
                		tmp = fma((y * y), fma(x, ((x * (y * y)) * 0.5), x), 1.0);
                	}
                	return tmp;
                }
                
                function code(x, y)
                	tmp = 0.0
                	if (exp(Float64(y * Float64(x * y))) <= 0.0)
                		tmp = Float64(y * Float64(y * Float64(y * Float64(y * Float64(0.5 * Float64(x * x))))));
                	else
                		tmp = fma(Float64(y * y), fma(x, Float64(Float64(x * Float64(y * y)) * 0.5), x), 1.0);
                	end
                	return tmp
                end
                
                code[x_, y_] := If[LessEqual[N[Exp[N[(y * N[(x * y), $MachinePrecision]), $MachinePrecision]], $MachinePrecision], 0.0], N[(y * N[(y * N[(y * N[(y * N[(0.5 * N[(x * x), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], N[(N[(y * y), $MachinePrecision] * N[(x * N[(N[(x * N[(y * y), $MachinePrecision]), $MachinePrecision] * 0.5), $MachinePrecision] + x), $MachinePrecision] + 1.0), $MachinePrecision]]
                
                \begin{array}{l}
                
                \\
                \begin{array}{l}
                \mathbf{if}\;e^{y \cdot \left(x \cdot y\right)} \leq 0:\\
                \;\;\;\;y \cdot \left(y \cdot \left(y \cdot \left(y \cdot \left(0.5 \cdot \left(x \cdot x\right)\right)\right)\right)\right)\\
                
                \mathbf{else}:\\
                \;\;\;\;\mathsf{fma}\left(y \cdot y, \mathsf{fma}\left(x, \left(x \cdot \left(y \cdot y\right)\right) \cdot 0.5, x\right), 1\right)\\
                
                
                \end{array}
                \end{array}
                
                Derivation
                1. Split input into 2 regimes
                2. if (exp.f64 (*.f64 (*.f64 x y) y)) < 0.0

                  1. Initial program 100.0%

                    \[e^{\left(x \cdot y\right) \cdot y} \]
                  2. Add Preprocessing
                  3. Taylor expanded in x around 0

                    \[\leadsto \color{blue}{1 + x \cdot \left(\frac{1}{2} \cdot \left(x \cdot {y}^{4}\right) + {y}^{2}\right)} \]
                  4. Step-by-step derivation
                    1. +-commutativeN/A

                      \[\leadsto \color{blue}{x \cdot \left(\frac{1}{2} \cdot \left(x \cdot {y}^{4}\right) + {y}^{2}\right) + 1} \]
                  5. Applied rewrites1.7%

                    \[\leadsto \color{blue}{\mathsf{fma}\left(y \cdot y, \mathsf{fma}\left(x, \left(x \cdot \left(y \cdot y\right)\right) \cdot 0.5, x\right), 1\right)} \]
                  6. Taylor expanded in x around inf

                    \[\leadsto {x}^{2} \cdot \color{blue}{\left(\frac{1}{2} \cdot {y}^{4} + \frac{{y}^{2}}{x}\right)} \]
                  7. Step-by-step derivation
                    1. Applied rewrites1.7%

                      \[\leadsto y \cdot \color{blue}{\left(y \cdot \mathsf{fma}\left(0.5, x \cdot \left(x \cdot \left(y \cdot y\right)\right), x\right)\right)} \]
                    2. Taylor expanded in y around inf

                      \[\leadsto y \cdot \left(\frac{1}{2} \cdot \left({x}^{2} \cdot \color{blue}{{y}^{3}}\right)\right) \]
                    3. Step-by-step derivation
                      1. Applied rewrites3.4%

                        \[\leadsto y \cdot \left(x \cdot \left(0.5 \cdot \color{blue}{\left(x \cdot \left(y \cdot \left(y \cdot y\right)\right)\right)}\right)\right) \]
                      2. Taylor expanded in y around inf

                        \[\leadsto y \cdot \left(\frac{1}{2} \cdot \left({x}^{2} \cdot \color{blue}{{y}^{3}}\right)\right) \]
                      3. Step-by-step derivation
                        1. Applied rewrites15.5%

                          \[\leadsto y \cdot \left(y \cdot \left(y \cdot \color{blue}{\left(y \cdot \left(0.5 \cdot \left(x \cdot x\right)\right)\right)}\right)\right) \]

                        if 0.0 < (exp.f64 (*.f64 (*.f64 x y) y))

                        1. Initial program 99.9%

                          \[e^{\left(x \cdot y\right) \cdot y} \]
                        2. Add Preprocessing
                        3. Taylor expanded in x around 0

                          \[\leadsto \color{blue}{1 + x \cdot \left(\frac{1}{2} \cdot \left(x \cdot {y}^{4}\right) + {y}^{2}\right)} \]
                        4. Step-by-step derivation
                          1. +-commutativeN/A

                            \[\leadsto \color{blue}{x \cdot \left(\frac{1}{2} \cdot \left(x \cdot {y}^{4}\right) + {y}^{2}\right) + 1} \]
                        5. Applied rewrites96.2%

                          \[\leadsto \color{blue}{\mathsf{fma}\left(y \cdot y, \mathsf{fma}\left(x, \left(x \cdot \left(y \cdot y\right)\right) \cdot 0.5, x\right), 1\right)} \]
                      4. Recombined 2 regimes into one program.
                      5. Final simplification78.2%

                        \[\leadsto \begin{array}{l} \mathbf{if}\;e^{y \cdot \left(x \cdot y\right)} \leq 0:\\ \;\;\;\;y \cdot \left(y \cdot \left(y \cdot \left(y \cdot \left(0.5 \cdot \left(x \cdot x\right)\right)\right)\right)\right)\\ \mathbf{else}:\\ \;\;\;\;\mathsf{fma}\left(y \cdot y, \mathsf{fma}\left(x, \left(x \cdot \left(y \cdot y\right)\right) \cdot 0.5, x\right), 1\right)\\ \end{array} \]
                      6. Add Preprocessing

                      Alternative 5: 66.4% accurate, 0.9× speedup?

                      \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;e^{y \cdot \left(x \cdot y\right)} \leq 2:\\ \;\;\;\;1\\ \mathbf{else}:\\ \;\;\;\;x \cdot \left(y \cdot y\right)\\ \end{array} \end{array} \]
                      (FPCore (x y)
                       :precision binary64
                       (if (<= (exp (* y (* x y))) 2.0) 1.0 (* x (* y y))))
                      double code(double x, double y) {
                      	double tmp;
                      	if (exp((y * (x * y))) <= 2.0) {
                      		tmp = 1.0;
                      	} else {
                      		tmp = x * (y * y);
                      	}
                      	return tmp;
                      }
                      
                      real(8) function code(x, y)
                          real(8), intent (in) :: x
                          real(8), intent (in) :: y
                          real(8) :: tmp
                          if (exp((y * (x * y))) <= 2.0d0) then
                              tmp = 1.0d0
                          else
                              tmp = x * (y * y)
                          end if
                          code = tmp
                      end function
                      
                      public static double code(double x, double y) {
                      	double tmp;
                      	if (Math.exp((y * (x * y))) <= 2.0) {
                      		tmp = 1.0;
                      	} else {
                      		tmp = x * (y * y);
                      	}
                      	return tmp;
                      }
                      
                      def code(x, y):
                      	tmp = 0
                      	if math.exp((y * (x * y))) <= 2.0:
                      		tmp = 1.0
                      	else:
                      		tmp = x * (y * y)
                      	return tmp
                      
                      function code(x, y)
                      	tmp = 0.0
                      	if (exp(Float64(y * Float64(x * y))) <= 2.0)
                      		tmp = 1.0;
                      	else
                      		tmp = Float64(x * Float64(y * y));
                      	end
                      	return tmp
                      end
                      
                      function tmp_2 = code(x, y)
                      	tmp = 0.0;
                      	if (exp((y * (x * y))) <= 2.0)
                      		tmp = 1.0;
                      	else
                      		tmp = x * (y * y);
                      	end
                      	tmp_2 = tmp;
                      end
                      
                      code[x_, y_] := If[LessEqual[N[Exp[N[(y * N[(x * y), $MachinePrecision]), $MachinePrecision]], $MachinePrecision], 2.0], 1.0, N[(x * N[(y * y), $MachinePrecision]), $MachinePrecision]]
                      
                      \begin{array}{l}
                      
                      \\
                      \begin{array}{l}
                      \mathbf{if}\;e^{y \cdot \left(x \cdot y\right)} \leq 2:\\
                      \;\;\;\;1\\
                      
                      \mathbf{else}:\\
                      \;\;\;\;x \cdot \left(y \cdot y\right)\\
                      
                      
                      \end{array}
                      \end{array}
                      
                      Derivation
                      1. Split input into 2 regimes
                      2. if (exp.f64 (*.f64 (*.f64 x y) y)) < 2

                        1. Initial program 99.9%

                          \[e^{\left(x \cdot y\right) \cdot y} \]
                        2. Add Preprocessing
                        3. Taylor expanded in x around 0

                          \[\leadsto \color{blue}{1} \]
                        4. Step-by-step derivation
                          1. Applied rewrites71.0%

                            \[\leadsto \color{blue}{1} \]

                          if 2 < (exp.f64 (*.f64 (*.f64 x y) y))

                          1. Initial program 100.0%

                            \[e^{\left(x \cdot y\right) \cdot y} \]
                          2. Add Preprocessing
                          3. Taylor expanded in x around 0

                            \[\leadsto \color{blue}{1 + x \cdot {y}^{2}} \]
                          4. Step-by-step derivation
                            1. +-commutativeN/A

                              \[\leadsto \color{blue}{x \cdot {y}^{2} + 1} \]
                            2. lower-fma.f64N/A

                              \[\leadsto \color{blue}{\mathsf{fma}\left(x, {y}^{2}, 1\right)} \]
                            3. unpow2N/A

                              \[\leadsto \mathsf{fma}\left(x, \color{blue}{y \cdot y}, 1\right) \]
                            4. lower-*.f6471.8

                              \[\leadsto \mathsf{fma}\left(x, \color{blue}{y \cdot y}, 1\right) \]
                          5. Applied rewrites71.8%

                            \[\leadsto \color{blue}{\mathsf{fma}\left(x, y \cdot y, 1\right)} \]
                          6. Taylor expanded in x around inf

                            \[\leadsto x \cdot \color{blue}{{y}^{2}} \]
                          7. Step-by-step derivation
                            1. Applied rewrites71.8%

                              \[\leadsto x \cdot \color{blue}{\left(y \cdot y\right)} \]
                          8. Recombined 2 regimes into one program.
                          9. Final simplification71.1%

                            \[\leadsto \begin{array}{l} \mathbf{if}\;e^{y \cdot \left(x \cdot y\right)} \leq 2:\\ \;\;\;\;1\\ \mathbf{else}:\\ \;\;\;\;x \cdot \left(y \cdot y\right)\\ \end{array} \]
                          10. Add Preprocessing

                          Alternative 6: 53.8% accurate, 0.9× speedup?

                          \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;e^{y \cdot \left(x \cdot y\right)} \leq 2:\\ \;\;\;\;1\\ \mathbf{else}:\\ \;\;\;\;\mathsf{fma}\left(x, y, 1\right)\\ \end{array} \end{array} \]
                          (FPCore (x y)
                           :precision binary64
                           (if (<= (exp (* y (* x y))) 2.0) 1.0 (fma x y 1.0)))
                          double code(double x, double y) {
                          	double tmp;
                          	if (exp((y * (x * y))) <= 2.0) {
                          		tmp = 1.0;
                          	} else {
                          		tmp = fma(x, y, 1.0);
                          	}
                          	return tmp;
                          }
                          
                          function code(x, y)
                          	tmp = 0.0
                          	if (exp(Float64(y * Float64(x * y))) <= 2.0)
                          		tmp = 1.0;
                          	else
                          		tmp = fma(x, y, 1.0);
                          	end
                          	return tmp
                          end
                          
                          code[x_, y_] := If[LessEqual[N[Exp[N[(y * N[(x * y), $MachinePrecision]), $MachinePrecision]], $MachinePrecision], 2.0], 1.0, N[(x * y + 1.0), $MachinePrecision]]
                          
                          \begin{array}{l}
                          
                          \\
                          \begin{array}{l}
                          \mathbf{if}\;e^{y \cdot \left(x \cdot y\right)} \leq 2:\\
                          \;\;\;\;1\\
                          
                          \mathbf{else}:\\
                          \;\;\;\;\mathsf{fma}\left(x, y, 1\right)\\
                          
                          
                          \end{array}
                          \end{array}
                          
                          Derivation
                          1. Split input into 2 regimes
                          2. if (exp.f64 (*.f64 (*.f64 x y) y)) < 2

                            1. Initial program 99.9%

                              \[e^{\left(x \cdot y\right) \cdot y} \]
                            2. Add Preprocessing
                            3. Taylor expanded in x around 0

                              \[\leadsto \color{blue}{1} \]
                            4. Step-by-step derivation
                              1. Applied rewrites71.0%

                                \[\leadsto \color{blue}{1} \]

                              if 2 < (exp.f64 (*.f64 (*.f64 x y) y))

                              1. Initial program 100.0%

                                \[e^{\left(x \cdot y\right) \cdot y} \]
                              2. Add Preprocessing
                              3. Applied rewrites48.4%

                                \[\leadsto e^{\color{blue}{x} \cdot y} \]
                              4. Taylor expanded in x around 0

                                \[\leadsto \color{blue}{1 + x \cdot y} \]
                              5. Step-by-step derivation
                                1. +-commutativeN/A

                                  \[\leadsto \color{blue}{x \cdot y + 1} \]
                                2. lower-fma.f6414.8

                                  \[\leadsto \color{blue}{\mathsf{fma}\left(x, y, 1\right)} \]
                              6. Applied rewrites14.8%

                                \[\leadsto \color{blue}{\mathsf{fma}\left(x, y, 1\right)} \]
                            5. Recombined 2 regimes into one program.
                            6. Final simplification58.5%

                              \[\leadsto \begin{array}{l} \mathbf{if}\;e^{y \cdot \left(x \cdot y\right)} \leq 2:\\ \;\;\;\;1\\ \mathbf{else}:\\ \;\;\;\;\mathsf{fma}\left(x, y, 1\right)\\ \end{array} \]
                            7. Add Preprocessing

                            Alternative 7: 82.8% accurate, 0.9× speedup?

                            \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;y \cdot \left(x \cdot y\right) \leq -200:\\ \;\;\;\;e^{x \cdot y}\\ \mathbf{else}:\\ \;\;\;\;\mathsf{fma}\left(y \cdot y, \mathsf{fma}\left(x \cdot \left(x \cdot \left(y \cdot y\right)\right), \mathsf{fma}\left(x, \left(y \cdot y\right) \cdot 0.16666666666666666, 0.5\right), x\right), 1\right)\\ \end{array} \end{array} \]
                            (FPCore (x y)
                             :precision binary64
                             (if (<= (* y (* x y)) -200.0)
                               (exp (* x y))
                               (fma
                                (* y y)
                                (fma (* x (* x (* y y))) (fma x (* (* y y) 0.16666666666666666) 0.5) x)
                                1.0)))
                            double code(double x, double y) {
                            	double tmp;
                            	if ((y * (x * y)) <= -200.0) {
                            		tmp = exp((x * y));
                            	} else {
                            		tmp = fma((y * y), fma((x * (x * (y * y))), fma(x, ((y * y) * 0.16666666666666666), 0.5), x), 1.0);
                            	}
                            	return tmp;
                            }
                            
                            function code(x, y)
                            	tmp = 0.0
                            	if (Float64(y * Float64(x * y)) <= -200.0)
                            		tmp = exp(Float64(x * y));
                            	else
                            		tmp = fma(Float64(y * y), fma(Float64(x * Float64(x * Float64(y * y))), fma(x, Float64(Float64(y * y) * 0.16666666666666666), 0.5), x), 1.0);
                            	end
                            	return tmp
                            end
                            
                            code[x_, y_] := If[LessEqual[N[(y * N[(x * y), $MachinePrecision]), $MachinePrecision], -200.0], N[Exp[N[(x * y), $MachinePrecision]], $MachinePrecision], N[(N[(y * y), $MachinePrecision] * N[(N[(x * N[(x * N[(y * y), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] * N[(x * N[(N[(y * y), $MachinePrecision] * 0.16666666666666666), $MachinePrecision] + 0.5), $MachinePrecision] + x), $MachinePrecision] + 1.0), $MachinePrecision]]
                            
                            \begin{array}{l}
                            
                            \\
                            \begin{array}{l}
                            \mathbf{if}\;y \cdot \left(x \cdot y\right) \leq -200:\\
                            \;\;\;\;e^{x \cdot y}\\
                            
                            \mathbf{else}:\\
                            \;\;\;\;\mathsf{fma}\left(y \cdot y, \mathsf{fma}\left(x \cdot \left(x \cdot \left(y \cdot y\right)\right), \mathsf{fma}\left(x, \left(y \cdot y\right) \cdot 0.16666666666666666, 0.5\right), x\right), 1\right)\\
                            
                            
                            \end{array}
                            \end{array}
                            
                            Derivation
                            1. Split input into 2 regimes
                            2. if (*.f64 (*.f64 x y) y) < -200

                              1. Initial program 99.8%

                                \[e^{\left(x \cdot y\right) \cdot y} \]
                              2. Add Preprocessing
                              3. Applied rewrites57.7%

                                \[\leadsto e^{\color{blue}{x} \cdot y} \]

                              if -200 < (*.f64 (*.f64 x y) y)

                              1. Initial program 100.0%

                                \[e^{\left(x \cdot y\right) \cdot y} \]
                              2. Add Preprocessing
                              3. Taylor expanded in x around 0

                                \[\leadsto \color{blue}{1 + x \cdot \left(x \cdot \left(\frac{1}{6} \cdot \left(x \cdot {y}^{6}\right) + \frac{1}{2} \cdot {y}^{4}\right) + {y}^{2}\right)} \]
                              4. Applied rewrites97.2%

                                \[\leadsto \color{blue}{\mathsf{fma}\left(y \cdot y, \mathsf{fma}\left(x \cdot \left(x \cdot \left(y \cdot y\right)\right), \mathsf{fma}\left(x, \left(y \cdot y\right) \cdot 0.16666666666666666, 0.5\right), x\right), 1\right)} \]
                            3. Recombined 2 regimes into one program.
                            4. Final simplification88.2%

                              \[\leadsto \begin{array}{l} \mathbf{if}\;y \cdot \left(x \cdot y\right) \leq -200:\\ \;\;\;\;e^{x \cdot y}\\ \mathbf{else}:\\ \;\;\;\;\mathsf{fma}\left(y \cdot y, \mathsf{fma}\left(x \cdot \left(x \cdot \left(y \cdot y\right)\right), \mathsf{fma}\left(x, \left(y \cdot y\right) \cdot 0.16666666666666666, 0.5\right), x\right), 1\right)\\ \end{array} \]
                            5. Add Preprocessing

                            Alternative 8: 87.5% accurate, 0.9× speedup?

                            \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;y \cdot \left(x \cdot y\right) \leq -200:\\ \;\;\;\;e^{x}\\ \mathbf{else}:\\ \;\;\;\;\mathsf{fma}\left(y \cdot y, \mathsf{fma}\left(x \cdot \left(x \cdot \left(y \cdot y\right)\right), \mathsf{fma}\left(x, \left(y \cdot y\right) \cdot 0.16666666666666666, 0.5\right), x\right), 1\right)\\ \end{array} \end{array} \]
                            (FPCore (x y)
                             :precision binary64
                             (if (<= (* y (* x y)) -200.0)
                               (exp x)
                               (fma
                                (* y y)
                                (fma (* x (* x (* y y))) (fma x (* (* y y) 0.16666666666666666) 0.5) x)
                                1.0)))
                            double code(double x, double y) {
                            	double tmp;
                            	if ((y * (x * y)) <= -200.0) {
                            		tmp = exp(x);
                            	} else {
                            		tmp = fma((y * y), fma((x * (x * (y * y))), fma(x, ((y * y) * 0.16666666666666666), 0.5), x), 1.0);
                            	}
                            	return tmp;
                            }
                            
                            function code(x, y)
                            	tmp = 0.0
                            	if (Float64(y * Float64(x * y)) <= -200.0)
                            		tmp = exp(x);
                            	else
                            		tmp = fma(Float64(y * y), fma(Float64(x * Float64(x * Float64(y * y))), fma(x, Float64(Float64(y * y) * 0.16666666666666666), 0.5), x), 1.0);
                            	end
                            	return tmp
                            end
                            
                            code[x_, y_] := If[LessEqual[N[(y * N[(x * y), $MachinePrecision]), $MachinePrecision], -200.0], N[Exp[x], $MachinePrecision], N[(N[(y * y), $MachinePrecision] * N[(N[(x * N[(x * N[(y * y), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] * N[(x * N[(N[(y * y), $MachinePrecision] * 0.16666666666666666), $MachinePrecision] + 0.5), $MachinePrecision] + x), $MachinePrecision] + 1.0), $MachinePrecision]]
                            
                            \begin{array}{l}
                            
                            \\
                            \begin{array}{l}
                            \mathbf{if}\;y \cdot \left(x \cdot y\right) \leq -200:\\
                            \;\;\;\;e^{x}\\
                            
                            \mathbf{else}:\\
                            \;\;\;\;\mathsf{fma}\left(y \cdot y, \mathsf{fma}\left(x \cdot \left(x \cdot \left(y \cdot y\right)\right), \mathsf{fma}\left(x, \left(y \cdot y\right) \cdot 0.16666666666666666, 0.5\right), x\right), 1\right)\\
                            
                            
                            \end{array}
                            \end{array}
                            
                            Derivation
                            1. Split input into 2 regimes
                            2. if (*.f64 (*.f64 x y) y) < -200

                              1. Initial program 99.8%

                                \[e^{\left(x \cdot y\right) \cdot y} \]
                              2. Add Preprocessing
                              3. Applied rewrites63.3%

                                \[\leadsto e^{\color{blue}{x}} \]

                              if -200 < (*.f64 (*.f64 x y) y)

                              1. Initial program 100.0%

                                \[e^{\left(x \cdot y\right) \cdot y} \]
                              2. Add Preprocessing
                              3. Taylor expanded in x around 0

                                \[\leadsto \color{blue}{1 + x \cdot \left(x \cdot \left(\frac{1}{6} \cdot \left(x \cdot {y}^{6}\right) + \frac{1}{2} \cdot {y}^{4}\right) + {y}^{2}\right)} \]
                              4. Applied rewrites97.2%

                                \[\leadsto \color{blue}{\mathsf{fma}\left(y \cdot y, \mathsf{fma}\left(x \cdot \left(x \cdot \left(y \cdot y\right)\right), \mathsf{fma}\left(x, \left(y \cdot y\right) \cdot 0.16666666666666666, 0.5\right), x\right), 1\right)} \]
                            3. Recombined 2 regimes into one program.
                            4. Final simplification89.5%

                              \[\leadsto \begin{array}{l} \mathbf{if}\;y \cdot \left(x \cdot y\right) \leq -200:\\ \;\;\;\;e^{x}\\ \mathbf{else}:\\ \;\;\;\;\mathsf{fma}\left(y \cdot y, \mathsf{fma}\left(x \cdot \left(x \cdot \left(y \cdot y\right)\right), \mathsf{fma}\left(x, \left(y \cdot y\right) \cdot 0.16666666666666666, 0.5\right), x\right), 1\right)\\ \end{array} \]
                            5. Add Preprocessing

                            Alternative 9: 74.7% accurate, 1.8× speedup?

                            \[\begin{array}{l} \\ \begin{array}{l} t_0 := y \cdot \left(x \cdot y\right)\\ \mathbf{if}\;t\_0 \leq -1:\\ \;\;\;\;y \cdot \left(y \cdot \left(y \cdot \left(y \cdot \left(0.5 \cdot \left(x \cdot x\right)\right)\right)\right)\right)\\ \mathbf{elif}\;t\_0 \leq 20000000000000:\\ \;\;\;\;\mathsf{fma}\left(x \cdot y, y, 1\right)\\ \mathbf{else}:\\ \;\;\;\;y \cdot \left(x \cdot \left(0.5 \cdot \left(x \cdot \left(y \cdot \left(y \cdot y\right)\right)\right)\right)\right)\\ \end{array} \end{array} \]
                            (FPCore (x y)
                             :precision binary64
                             (let* ((t_0 (* y (* x y))))
                               (if (<= t_0 -1.0)
                                 (* y (* y (* y (* y (* 0.5 (* x x))))))
                                 (if (<= t_0 20000000000000.0)
                                   (fma (* x y) y 1.0)
                                   (* y (* x (* 0.5 (* x (* y (* y y))))))))))
                            double code(double x, double y) {
                            	double t_0 = y * (x * y);
                            	double tmp;
                            	if (t_0 <= -1.0) {
                            		tmp = y * (y * (y * (y * (0.5 * (x * x)))));
                            	} else if (t_0 <= 20000000000000.0) {
                            		tmp = fma((x * y), y, 1.0);
                            	} else {
                            		tmp = y * (x * (0.5 * (x * (y * (y * y)))));
                            	}
                            	return tmp;
                            }
                            
                            function code(x, y)
                            	t_0 = Float64(y * Float64(x * y))
                            	tmp = 0.0
                            	if (t_0 <= -1.0)
                            		tmp = Float64(y * Float64(y * Float64(y * Float64(y * Float64(0.5 * Float64(x * x))))));
                            	elseif (t_0 <= 20000000000000.0)
                            		tmp = fma(Float64(x * y), y, 1.0);
                            	else
                            		tmp = Float64(y * Float64(x * Float64(0.5 * Float64(x * Float64(y * Float64(y * y))))));
                            	end
                            	return tmp
                            end
                            
                            code[x_, y_] := Block[{t$95$0 = N[(y * N[(x * y), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[t$95$0, -1.0], N[(y * N[(y * N[(y * N[(y * N[(0.5 * N[(x * x), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], If[LessEqual[t$95$0, 20000000000000.0], N[(N[(x * y), $MachinePrecision] * y + 1.0), $MachinePrecision], N[(y * N[(x * N[(0.5 * N[(x * N[(y * N[(y * y), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]]]]
                            
                            \begin{array}{l}
                            
                            \\
                            \begin{array}{l}
                            t_0 := y \cdot \left(x \cdot y\right)\\
                            \mathbf{if}\;t\_0 \leq -1:\\
                            \;\;\;\;y \cdot \left(y \cdot \left(y \cdot \left(y \cdot \left(0.5 \cdot \left(x \cdot x\right)\right)\right)\right)\right)\\
                            
                            \mathbf{elif}\;t\_0 \leq 20000000000000:\\
                            \;\;\;\;\mathsf{fma}\left(x \cdot y, y, 1\right)\\
                            
                            \mathbf{else}:\\
                            \;\;\;\;y \cdot \left(x \cdot \left(0.5 \cdot \left(x \cdot \left(y \cdot \left(y \cdot y\right)\right)\right)\right)\right)\\
                            
                            
                            \end{array}
                            \end{array}
                            
                            Derivation
                            1. Split input into 3 regimes
                            2. if (*.f64 (*.f64 x y) y) < -1

                              1. Initial program 99.8%

                                \[e^{\left(x \cdot y\right) \cdot y} \]
                              2. Add Preprocessing
                              3. Taylor expanded in x around 0

                                \[\leadsto \color{blue}{1 + x \cdot \left(\frac{1}{2} \cdot \left(x \cdot {y}^{4}\right) + {y}^{2}\right)} \]
                              4. Step-by-step derivation
                                1. +-commutativeN/A

                                  \[\leadsto \color{blue}{x \cdot \left(\frac{1}{2} \cdot \left(x \cdot {y}^{4}\right) + {y}^{2}\right) + 1} \]
                              5. Applied rewrites2.1%

                                \[\leadsto \color{blue}{\mathsf{fma}\left(y \cdot y, \mathsf{fma}\left(x, \left(x \cdot \left(y \cdot y\right)\right) \cdot 0.5, x\right), 1\right)} \]
                              6. Taylor expanded in x around inf

                                \[\leadsto {x}^{2} \cdot \color{blue}{\left(\frac{1}{2} \cdot {y}^{4} + \frac{{y}^{2}}{x}\right)} \]
                              7. Step-by-step derivation
                                1. Applied rewrites1.7%

                                  \[\leadsto y \cdot \color{blue}{\left(y \cdot \mathsf{fma}\left(0.5, x \cdot \left(x \cdot \left(y \cdot y\right)\right), x\right)\right)} \]
                                2. Taylor expanded in y around inf

                                  \[\leadsto y \cdot \left(\frac{1}{2} \cdot \left({x}^{2} \cdot \color{blue}{{y}^{3}}\right)\right) \]
                                3. Step-by-step derivation
                                  1. Applied rewrites3.4%

                                    \[\leadsto y \cdot \left(x \cdot \left(0.5 \cdot \color{blue}{\left(x \cdot \left(y \cdot \left(y \cdot y\right)\right)\right)}\right)\right) \]
                                  2. Taylor expanded in y around inf

                                    \[\leadsto y \cdot \left(\frac{1}{2} \cdot \left({x}^{2} \cdot \color{blue}{{y}^{3}}\right)\right) \]
                                  3. Step-by-step derivation
                                    1. Applied rewrites15.0%

                                      \[\leadsto y \cdot \left(y \cdot \left(y \cdot \color{blue}{\left(y \cdot \left(0.5 \cdot \left(x \cdot x\right)\right)\right)}\right)\right) \]

                                    if -1 < (*.f64 (*.f64 x y) y) < 2e13

                                    1. Initial program 100.0%

                                      \[e^{\left(x \cdot y\right) \cdot y} \]
                                    2. Add Preprocessing
                                    3. Taylor expanded in x around 0

                                      \[\leadsto \color{blue}{1 + x \cdot {y}^{2}} \]
                                    4. Step-by-step derivation
                                      1. +-commutativeN/A

                                        \[\leadsto \color{blue}{x \cdot {y}^{2} + 1} \]
                                      2. lower-fma.f64N/A

                                        \[\leadsto \color{blue}{\mathsf{fma}\left(x, {y}^{2}, 1\right)} \]
                                      3. unpow2N/A

                                        \[\leadsto \mathsf{fma}\left(x, \color{blue}{y \cdot y}, 1\right) \]
                                      4. lower-*.f6498.4

                                        \[\leadsto \mathsf{fma}\left(x, \color{blue}{y \cdot y}, 1\right) \]
                                    5. Applied rewrites98.4%

                                      \[\leadsto \color{blue}{\mathsf{fma}\left(x, y \cdot y, 1\right)} \]
                                    6. Step-by-step derivation
                                      1. Applied rewrites98.4%

                                        \[\leadsto \mathsf{fma}\left(x \cdot y, \color{blue}{y}, 1\right) \]

                                      if 2e13 < (*.f64 (*.f64 x y) y)

                                      1. Initial program 100.0%

                                        \[e^{\left(x \cdot y\right) \cdot y} \]
                                      2. Add Preprocessing
                                      3. Taylor expanded in x around 0

                                        \[\leadsto \color{blue}{1 + x \cdot \left(\frac{1}{2} \cdot \left(x \cdot {y}^{4}\right) + {y}^{2}\right)} \]
                                      4. Step-by-step derivation
                                        1. +-commutativeN/A

                                          \[\leadsto \color{blue}{x \cdot \left(\frac{1}{2} \cdot \left(x \cdot {y}^{4}\right) + {y}^{2}\right) + 1} \]
                                      5. Applied rewrites91.3%

                                        \[\leadsto \color{blue}{\mathsf{fma}\left(y \cdot y, \mathsf{fma}\left(x, \left(x \cdot \left(y \cdot y\right)\right) \cdot 0.5, x\right), 1\right)} \]
                                      6. Taylor expanded in x around inf

                                        \[\leadsto {x}^{2} \cdot \color{blue}{\left(\frac{1}{2} \cdot {y}^{4} + \frac{{y}^{2}}{x}\right)} \]
                                      7. Step-by-step derivation
                                        1. Applied rewrites91.3%

                                          \[\leadsto y \cdot \color{blue}{\left(y \cdot \mathsf{fma}\left(0.5, x \cdot \left(x \cdot \left(y \cdot y\right)\right), x\right)\right)} \]
                                        2. Taylor expanded in y around inf

                                          \[\leadsto y \cdot \left(\frac{1}{2} \cdot \left({x}^{2} \cdot \color{blue}{{y}^{3}}\right)\right) \]
                                        3. Step-by-step derivation
                                          1. Applied rewrites94.8%

                                            \[\leadsto y \cdot \left(x \cdot \left(0.5 \cdot \color{blue}{\left(x \cdot \left(y \cdot \left(y \cdot y\right)\right)\right)}\right)\right) \]
                                        4. Recombined 3 regimes into one program.
                                        5. Final simplification78.4%

                                          \[\leadsto \begin{array}{l} \mathbf{if}\;y \cdot \left(x \cdot y\right) \leq -1:\\ \;\;\;\;y \cdot \left(y \cdot \left(y \cdot \left(y \cdot \left(0.5 \cdot \left(x \cdot x\right)\right)\right)\right)\right)\\ \mathbf{elif}\;y \cdot \left(x \cdot y\right) \leq 20000000000000:\\ \;\;\;\;\mathsf{fma}\left(x \cdot y, y, 1\right)\\ \mathbf{else}:\\ \;\;\;\;y \cdot \left(x \cdot \left(0.5 \cdot \left(x \cdot \left(y \cdot \left(y \cdot y\right)\right)\right)\right)\right)\\ \end{array} \]
                                        6. Add Preprocessing

                                        Alternative 10: 71.1% accurate, 2.4× speedup?

                                        \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;y \cdot \left(x \cdot y\right) \leq 20000000000000:\\ \;\;\;\;1\\ \mathbf{else}:\\ \;\;\;\;y \cdot \left(x \cdot \left(0.5 \cdot \left(x \cdot \left(y \cdot \left(y \cdot y\right)\right)\right)\right)\right)\\ \end{array} \end{array} \]
                                        (FPCore (x y)
                                         :precision binary64
                                         (if (<= (* y (* x y)) 20000000000000.0)
                                           1.0
                                           (* y (* x (* 0.5 (* x (* y (* y y))))))))
                                        double code(double x, double y) {
                                        	double tmp;
                                        	if ((y * (x * y)) <= 20000000000000.0) {
                                        		tmp = 1.0;
                                        	} else {
                                        		tmp = y * (x * (0.5 * (x * (y * (y * y)))));
                                        	}
                                        	return tmp;
                                        }
                                        
                                        real(8) function code(x, y)
                                            real(8), intent (in) :: x
                                            real(8), intent (in) :: y
                                            real(8) :: tmp
                                            if ((y * (x * y)) <= 20000000000000.0d0) then
                                                tmp = 1.0d0
                                            else
                                                tmp = y * (x * (0.5d0 * (x * (y * (y * y)))))
                                            end if
                                            code = tmp
                                        end function
                                        
                                        public static double code(double x, double y) {
                                        	double tmp;
                                        	if ((y * (x * y)) <= 20000000000000.0) {
                                        		tmp = 1.0;
                                        	} else {
                                        		tmp = y * (x * (0.5 * (x * (y * (y * y)))));
                                        	}
                                        	return tmp;
                                        }
                                        
                                        def code(x, y):
                                        	tmp = 0
                                        	if (y * (x * y)) <= 20000000000000.0:
                                        		tmp = 1.0
                                        	else:
                                        		tmp = y * (x * (0.5 * (x * (y * (y * y)))))
                                        	return tmp
                                        
                                        function code(x, y)
                                        	tmp = 0.0
                                        	if (Float64(y * Float64(x * y)) <= 20000000000000.0)
                                        		tmp = 1.0;
                                        	else
                                        		tmp = Float64(y * Float64(x * Float64(0.5 * Float64(x * Float64(y * Float64(y * y))))));
                                        	end
                                        	return tmp
                                        end
                                        
                                        function tmp_2 = code(x, y)
                                        	tmp = 0.0;
                                        	if ((y * (x * y)) <= 20000000000000.0)
                                        		tmp = 1.0;
                                        	else
                                        		tmp = y * (x * (0.5 * (x * (y * (y * y)))));
                                        	end
                                        	tmp_2 = tmp;
                                        end
                                        
                                        code[x_, y_] := If[LessEqual[N[(y * N[(x * y), $MachinePrecision]), $MachinePrecision], 20000000000000.0], 1.0, N[(y * N[(x * N[(0.5 * N[(x * N[(y * N[(y * y), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]]
                                        
                                        \begin{array}{l}
                                        
                                        \\
                                        \begin{array}{l}
                                        \mathbf{if}\;y \cdot \left(x \cdot y\right) \leq 20000000000000:\\
                                        \;\;\;\;1\\
                                        
                                        \mathbf{else}:\\
                                        \;\;\;\;y \cdot \left(x \cdot \left(0.5 \cdot \left(x \cdot \left(y \cdot \left(y \cdot y\right)\right)\right)\right)\right)\\
                                        
                                        
                                        \end{array}
                                        \end{array}
                                        
                                        Derivation
                                        1. Split input into 2 regimes
                                        2. if (*.f64 (*.f64 x y) y) < 2e13

                                          1. Initial program 99.9%

                                            \[e^{\left(x \cdot y\right) \cdot y} \]
                                          2. Add Preprocessing
                                          3. Taylor expanded in x around 0

                                            \[\leadsto \color{blue}{1} \]
                                          4. Step-by-step derivation
                                            1. Applied rewrites70.3%

                                              \[\leadsto \color{blue}{1} \]

                                            if 2e13 < (*.f64 (*.f64 x y) y)

                                            1. Initial program 100.0%

                                              \[e^{\left(x \cdot y\right) \cdot y} \]
                                            2. Add Preprocessing
                                            3. Taylor expanded in x around 0

                                              \[\leadsto \color{blue}{1 + x \cdot \left(\frac{1}{2} \cdot \left(x \cdot {y}^{4}\right) + {y}^{2}\right)} \]
                                            4. Step-by-step derivation
                                              1. +-commutativeN/A

                                                \[\leadsto \color{blue}{x \cdot \left(\frac{1}{2} \cdot \left(x \cdot {y}^{4}\right) + {y}^{2}\right) + 1} \]
                                            5. Applied rewrites91.3%

                                              \[\leadsto \color{blue}{\mathsf{fma}\left(y \cdot y, \mathsf{fma}\left(x, \left(x \cdot \left(y \cdot y\right)\right) \cdot 0.5, x\right), 1\right)} \]
                                            6. Taylor expanded in x around inf

                                              \[\leadsto {x}^{2} \cdot \color{blue}{\left(\frac{1}{2} \cdot {y}^{4} + \frac{{y}^{2}}{x}\right)} \]
                                            7. Step-by-step derivation
                                              1. Applied rewrites91.3%

                                                \[\leadsto y \cdot \color{blue}{\left(y \cdot \mathsf{fma}\left(0.5, x \cdot \left(x \cdot \left(y \cdot y\right)\right), x\right)\right)} \]
                                              2. Taylor expanded in y around inf

                                                \[\leadsto y \cdot \left(\frac{1}{2} \cdot \left({x}^{2} \cdot \color{blue}{{y}^{3}}\right)\right) \]
                                              3. Step-by-step derivation
                                                1. Applied rewrites94.8%

                                                  \[\leadsto y \cdot \left(x \cdot \left(0.5 \cdot \color{blue}{\left(x \cdot \left(y \cdot \left(y \cdot y\right)\right)\right)}\right)\right) \]
                                              4. Recombined 2 regimes into one program.
                                              5. Final simplification75.6%

                                                \[\leadsto \begin{array}{l} \mathbf{if}\;y \cdot \left(x \cdot y\right) \leq 20000000000000:\\ \;\;\;\;1\\ \mathbf{else}:\\ \;\;\;\;y \cdot \left(x \cdot \left(0.5 \cdot \left(x \cdot \left(y \cdot \left(y \cdot y\right)\right)\right)\right)\right)\\ \end{array} \]
                                              6. Add Preprocessing

                                              Alternative 11: 69.2% accurate, 2.8× speedup?

                                              \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;y \cdot \left(x \cdot y\right) \leq 0.0001:\\ \;\;\;\;1\\ \mathbf{else}:\\ \;\;\;\;\mathsf{fma}\left(x, \mathsf{fma}\left(x, \left(y \cdot y\right) \cdot 0.5, y\right), 1\right)\\ \end{array} \end{array} \]
                                              (FPCore (x y)
                                               :precision binary64
                                               (if (<= (* y (* x y)) 0.0001) 1.0 (fma x (fma x (* (* y y) 0.5) y) 1.0)))
                                              double code(double x, double y) {
                                              	double tmp;
                                              	if ((y * (x * y)) <= 0.0001) {
                                              		tmp = 1.0;
                                              	} else {
                                              		tmp = fma(x, fma(x, ((y * y) * 0.5), y), 1.0);
                                              	}
                                              	return tmp;
                                              }
                                              
                                              function code(x, y)
                                              	tmp = 0.0
                                              	if (Float64(y * Float64(x * y)) <= 0.0001)
                                              		tmp = 1.0;
                                              	else
                                              		tmp = fma(x, fma(x, Float64(Float64(y * y) * 0.5), y), 1.0);
                                              	end
                                              	return tmp
                                              end
                                              
                                              code[x_, y_] := If[LessEqual[N[(y * N[(x * y), $MachinePrecision]), $MachinePrecision], 0.0001], 1.0, N[(x * N[(x * N[(N[(y * y), $MachinePrecision] * 0.5), $MachinePrecision] + y), $MachinePrecision] + 1.0), $MachinePrecision]]
                                              
                                              \begin{array}{l}
                                              
                                              \\
                                              \begin{array}{l}
                                              \mathbf{if}\;y \cdot \left(x \cdot y\right) \leq 0.0001:\\
                                              \;\;\;\;1\\
                                              
                                              \mathbf{else}:\\
                                              \;\;\;\;\mathsf{fma}\left(x, \mathsf{fma}\left(x, \left(y \cdot y\right) \cdot 0.5, y\right), 1\right)\\
                                              
                                              
                                              \end{array}
                                              \end{array}
                                              
                                              Derivation
                                              1. Split input into 2 regimes
                                              2. if (*.f64 (*.f64 x y) y) < 1.00000000000000005e-4

                                                1. Initial program 99.9%

                                                  \[e^{\left(x \cdot y\right) \cdot y} \]
                                                2. Add Preprocessing
                                                3. Taylor expanded in x around 0

                                                  \[\leadsto \color{blue}{1} \]
                                                4. Step-by-step derivation
                                                  1. Applied rewrites71.0%

                                                    \[\leadsto \color{blue}{1} \]

                                                  if 1.00000000000000005e-4 < (*.f64 (*.f64 x y) y)

                                                  1. Initial program 100.0%

                                                    \[e^{\left(x \cdot y\right) \cdot y} \]
                                                  2. Add Preprocessing
                                                  3. Applied rewrites48.4%

                                                    \[\leadsto e^{\color{blue}{x} \cdot y} \]
                                                  4. Taylor expanded in x around 0

                                                    \[\leadsto \color{blue}{1 + x \cdot \left(y + \frac{1}{2} \cdot \left(x \cdot {y}^{2}\right)\right)} \]
                                                  5. Step-by-step derivation
                                                    1. +-commutativeN/A

                                                      \[\leadsto \color{blue}{x \cdot \left(y + \frac{1}{2} \cdot \left(x \cdot {y}^{2}\right)\right) + 1} \]
                                                    2. +-commutativeN/A

                                                      \[\leadsto x \cdot \color{blue}{\left(\frac{1}{2} \cdot \left(x \cdot {y}^{2}\right) + y\right)} + 1 \]
                                                    3. *-commutativeN/A

                                                      \[\leadsto x \cdot \left(\frac{1}{2} \cdot \color{blue}{\left({y}^{2} \cdot x\right)} + y\right) + 1 \]
                                                    4. associate-*r*N/A

                                                      \[\leadsto x \cdot \left(\color{blue}{\left(\frac{1}{2} \cdot {y}^{2}\right) \cdot x} + y\right) + 1 \]
                                                    5. lower-fma.f64N/A

                                                      \[\leadsto \color{blue}{\mathsf{fma}\left(x, \left(\frac{1}{2} \cdot {y}^{2}\right) \cdot x + y, 1\right)} \]
                                                    6. *-commutativeN/A

                                                      \[\leadsto \mathsf{fma}\left(x, \color{blue}{x \cdot \left(\frac{1}{2} \cdot {y}^{2}\right)} + y, 1\right) \]
                                                    7. lower-fma.f64N/A

                                                      \[\leadsto \mathsf{fma}\left(x, \color{blue}{\mathsf{fma}\left(x, \frac{1}{2} \cdot {y}^{2}, y\right)}, 1\right) \]
                                                    8. lower-*.f64N/A

                                                      \[\leadsto \mathsf{fma}\left(x, \mathsf{fma}\left(x, \color{blue}{\frac{1}{2} \cdot {y}^{2}}, y\right), 1\right) \]
                                                    9. unpow2N/A

                                                      \[\leadsto \mathsf{fma}\left(x, \mathsf{fma}\left(x, \frac{1}{2} \cdot \color{blue}{\left(y \cdot y\right)}, y\right), 1\right) \]
                                                    10. lower-*.f6485.1

                                                      \[\leadsto \mathsf{fma}\left(x, \mathsf{fma}\left(x, 0.5 \cdot \color{blue}{\left(y \cdot y\right)}, y\right), 1\right) \]
                                                  6. Applied rewrites85.1%

                                                    \[\leadsto \color{blue}{\mathsf{fma}\left(x, \mathsf{fma}\left(x, 0.5 \cdot \left(y \cdot y\right), y\right), 1\right)} \]
                                                5. Recombined 2 regimes into one program.
                                                6. Final simplification74.1%

                                                  \[\leadsto \begin{array}{l} \mathbf{if}\;y \cdot \left(x \cdot y\right) \leq 0.0001:\\ \;\;\;\;1\\ \mathbf{else}:\\ \;\;\;\;\mathsf{fma}\left(x, \mathsf{fma}\left(x, \left(y \cdot y\right) \cdot 0.5, y\right), 1\right)\\ \end{array} \]
                                                7. Add Preprocessing

                                                Alternative 12: 53.8% accurate, 5.0× speedup?

                                                \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;y \cdot \left(x \cdot y\right) \leq 100000000:\\ \;\;\;\;1\\ \mathbf{else}:\\ \;\;\;\;x \cdot y\\ \end{array} \end{array} \]
                                                (FPCore (x y)
                                                 :precision binary64
                                                 (if (<= (* y (* x y)) 100000000.0) 1.0 (* x y)))
                                                double code(double x, double y) {
                                                	double tmp;
                                                	if ((y * (x * y)) <= 100000000.0) {
                                                		tmp = 1.0;
                                                	} else {
                                                		tmp = x * y;
                                                	}
                                                	return tmp;
                                                }
                                                
                                                real(8) function code(x, y)
                                                    real(8), intent (in) :: x
                                                    real(8), intent (in) :: y
                                                    real(8) :: tmp
                                                    if ((y * (x * y)) <= 100000000.0d0) then
                                                        tmp = 1.0d0
                                                    else
                                                        tmp = x * y
                                                    end if
                                                    code = tmp
                                                end function
                                                
                                                public static double code(double x, double y) {
                                                	double tmp;
                                                	if ((y * (x * y)) <= 100000000.0) {
                                                		tmp = 1.0;
                                                	} else {
                                                		tmp = x * y;
                                                	}
                                                	return tmp;
                                                }
                                                
                                                def code(x, y):
                                                	tmp = 0
                                                	if (y * (x * y)) <= 100000000.0:
                                                		tmp = 1.0
                                                	else:
                                                		tmp = x * y
                                                	return tmp
                                                
                                                function code(x, y)
                                                	tmp = 0.0
                                                	if (Float64(y * Float64(x * y)) <= 100000000.0)
                                                		tmp = 1.0;
                                                	else
                                                		tmp = Float64(x * y);
                                                	end
                                                	return tmp
                                                end
                                                
                                                function tmp_2 = code(x, y)
                                                	tmp = 0.0;
                                                	if ((y * (x * y)) <= 100000000.0)
                                                		tmp = 1.0;
                                                	else
                                                		tmp = x * y;
                                                	end
                                                	tmp_2 = tmp;
                                                end
                                                
                                                code[x_, y_] := If[LessEqual[N[(y * N[(x * y), $MachinePrecision]), $MachinePrecision], 100000000.0], 1.0, N[(x * y), $MachinePrecision]]
                                                
                                                \begin{array}{l}
                                                
                                                \\
                                                \begin{array}{l}
                                                \mathbf{if}\;y \cdot \left(x \cdot y\right) \leq 100000000:\\
                                                \;\;\;\;1\\
                                                
                                                \mathbf{else}:\\
                                                \;\;\;\;x \cdot y\\
                                                
                                                
                                                \end{array}
                                                \end{array}
                                                
                                                Derivation
                                                1. Split input into 2 regimes
                                                2. if (*.f64 (*.f64 x y) y) < 1e8

                                                  1. Initial program 99.9%

                                                    \[e^{\left(x \cdot y\right) \cdot y} \]
                                                  2. Add Preprocessing
                                                  3. Taylor expanded in x around 0

                                                    \[\leadsto \color{blue}{1} \]
                                                  4. Step-by-step derivation
                                                    1. Applied rewrites70.6%

                                                      \[\leadsto \color{blue}{1} \]

                                                    if 1e8 < (*.f64 (*.f64 x y) y)

                                                    1. Initial program 100.0%

                                                      \[e^{\left(x \cdot y\right) \cdot y} \]
                                                    2. Add Preprocessing
                                                    3. Applied rewrites49.2%

                                                      \[\leadsto e^{\color{blue}{x} \cdot y} \]
                                                    4. Taylor expanded in x around 0

                                                      \[\leadsto \color{blue}{1 + x \cdot y} \]
                                                    5. Step-by-step derivation
                                                      1. +-commutativeN/A

                                                        \[\leadsto \color{blue}{x \cdot y + 1} \]
                                                      2. lower-fma.f6415.0

                                                        \[\leadsto \color{blue}{\mathsf{fma}\left(x, y, 1\right)} \]
                                                    6. Applied rewrites15.0%

                                                      \[\leadsto \color{blue}{\mathsf{fma}\left(x, y, 1\right)} \]
                                                    7. Taylor expanded in x around inf

                                                      \[\leadsto x \cdot \color{blue}{y} \]
                                                    8. Step-by-step derivation
                                                      1. Applied rewrites14.9%

                                                        \[\leadsto x \cdot \color{blue}{y} \]
                                                    9. Recombined 2 regimes into one program.
                                                    10. Final simplification58.4%

                                                      \[\leadsto \begin{array}{l} \mathbf{if}\;y \cdot \left(x \cdot y\right) \leq 100000000:\\ \;\;\;\;1\\ \mathbf{else}:\\ \;\;\;\;x \cdot y\\ \end{array} \]
                                                    11. Add Preprocessing

                                                    Alternative 13: 66.4% accurate, 9.3× speedup?

                                                    \[\begin{array}{l} \\ \mathsf{fma}\left(x, y \cdot y, 1\right) \end{array} \]
                                                    (FPCore (x y) :precision binary64 (fma x (* y y) 1.0))
                                                    double code(double x, double y) {
                                                    	return fma(x, (y * y), 1.0);
                                                    }
                                                    
                                                    function code(x, y)
                                                    	return fma(x, Float64(y * y), 1.0)
                                                    end
                                                    
                                                    code[x_, y_] := N[(x * N[(y * y), $MachinePrecision] + 1.0), $MachinePrecision]
                                                    
                                                    \begin{array}{l}
                                                    
                                                    \\
                                                    \mathsf{fma}\left(x, y \cdot y, 1\right)
                                                    \end{array}
                                                    
                                                    Derivation
                                                    1. Initial program 100.0%

                                                      \[e^{\left(x \cdot y\right) \cdot y} \]
                                                    2. Add Preprocessing
                                                    3. Taylor expanded in x around 0

                                                      \[\leadsto \color{blue}{1 + x \cdot {y}^{2}} \]
                                                    4. Step-by-step derivation
                                                      1. +-commutativeN/A

                                                        \[\leadsto \color{blue}{x \cdot {y}^{2} + 1} \]
                                                      2. lower-fma.f64N/A

                                                        \[\leadsto \color{blue}{\mathsf{fma}\left(x, {y}^{2}, 1\right)} \]
                                                      3. unpow2N/A

                                                        \[\leadsto \mathsf{fma}\left(x, \color{blue}{y \cdot y}, 1\right) \]
                                                      4. lower-*.f6470.9

                                                        \[\leadsto \mathsf{fma}\left(x, \color{blue}{y \cdot y}, 1\right) \]
                                                    5. Applied rewrites70.9%

                                                      \[\leadsto \color{blue}{\mathsf{fma}\left(x, y \cdot y, 1\right)} \]
                                                    6. Add Preprocessing

                                                    Alternative 14: 51.1% accurate, 111.0× speedup?

                                                    \[\begin{array}{l} \\ 1 \end{array} \]
                                                    (FPCore (x y) :precision binary64 1.0)
                                                    double code(double x, double y) {
                                                    	return 1.0;
                                                    }
                                                    
                                                    real(8) function code(x, y)
                                                        real(8), intent (in) :: x
                                                        real(8), intent (in) :: y
                                                        code = 1.0d0
                                                    end function
                                                    
                                                    public static double code(double x, double y) {
                                                    	return 1.0;
                                                    }
                                                    
                                                    def code(x, y):
                                                    	return 1.0
                                                    
                                                    function code(x, y)
                                                    	return 1.0
                                                    end
                                                    
                                                    function tmp = code(x, y)
                                                    	tmp = 1.0;
                                                    end
                                                    
                                                    code[x_, y_] := 1.0
                                                    
                                                    \begin{array}{l}
                                                    
                                                    \\
                                                    1
                                                    \end{array}
                                                    
                                                    Derivation
                                                    1. Initial program 100.0%

                                                      \[e^{\left(x \cdot y\right) \cdot y} \]
                                                    2. Add Preprocessing
                                                    3. Taylor expanded in x around 0

                                                      \[\leadsto \color{blue}{1} \]
                                                    4. Step-by-step derivation
                                                      1. Applied rewrites55.9%

                                                        \[\leadsto \color{blue}{1} \]
                                                      2. Add Preprocessing

                                                      Reproduce

                                                      ?
                                                      herbie shell --seed 2024219 
                                                      (FPCore (x y)
                                                        :name "Data.Random.Distribution.Normal:normalF from random-fu-0.2.6.2"
                                                        :precision binary64
                                                        (exp (* (* x y) y)))