ABCF->ab-angle angle

Percentage Accurate: 54.3% → 88.9%
Time: 12.8s
Alternatives: 13
Speedup: 2.6×

Specification

?
\[\begin{array}{l} \\ 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \end{array} \]
(FPCore (A B C)
 :precision binary64
 (*
  180.0
  (/
   (atan (* (/ 1.0 B) (- (- C A) (sqrt (+ (pow (- A C) 2.0) (pow B 2.0))))))
   PI)))
double code(double A, double B, double C) {
	return 180.0 * (atan(((1.0 / B) * ((C - A) - sqrt((pow((A - C), 2.0) + pow(B, 2.0)))))) / ((double) M_PI));
}
public static double code(double A, double B, double C) {
	return 180.0 * (Math.atan(((1.0 / B) * ((C - A) - Math.sqrt((Math.pow((A - C), 2.0) + Math.pow(B, 2.0)))))) / Math.PI);
}
def code(A, B, C):
	return 180.0 * (math.atan(((1.0 / B) * ((C - A) - math.sqrt((math.pow((A - C), 2.0) + math.pow(B, 2.0)))))) / math.pi)
function code(A, B, C)
	return Float64(180.0 * Float64(atan(Float64(Float64(1.0 / B) * Float64(Float64(C - A) - sqrt(Float64((Float64(A - C) ^ 2.0) + (B ^ 2.0)))))) / pi))
end
function tmp = code(A, B, C)
	tmp = 180.0 * (atan(((1.0 / B) * ((C - A) - sqrt((((A - C) ^ 2.0) + (B ^ 2.0)))))) / pi);
end
code[A_, B_, C_] := N[(180.0 * N[(N[ArcTan[N[(N[(1.0 / B), $MachinePrecision] * N[(N[(C - A), $MachinePrecision] - N[Sqrt[N[(N[Power[N[(A - C), $MachinePrecision], 2.0], $MachinePrecision] + N[Power[B, 2.0], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi}
\end{array}

Sampling outcomes in binary64 precision:

Local Percentage Accuracy vs ?

The average percentage accuracy by input value. Horizontal axis shows value of an input variable; the variable is choosen in the title. Vertical axis is accuracy; higher is better. Red represent the original program, while blue represents Herbie's suggestion. These can be toggled with buttons below the plot. The line is an average while dots represent individual samples.

Accuracy vs Speed?

Herbie found 13 alternatives:

AlternativeAccuracySpeedup
The accuracy (vertical axis) and speed (horizontal axis) of each alternatives. Up and to the right is better. The red square shows the initial program, and each blue circle shows an alternative.The line shows the best available speed-accuracy tradeoffs.

Initial Program: 54.3% accurate, 1.0× speedup?

\[\begin{array}{l} \\ 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \end{array} \]
(FPCore (A B C)
 :precision binary64
 (*
  180.0
  (/
   (atan (* (/ 1.0 B) (- (- C A) (sqrt (+ (pow (- A C) 2.0) (pow B 2.0))))))
   PI)))
double code(double A, double B, double C) {
	return 180.0 * (atan(((1.0 / B) * ((C - A) - sqrt((pow((A - C), 2.0) + pow(B, 2.0)))))) / ((double) M_PI));
}
public static double code(double A, double B, double C) {
	return 180.0 * (Math.atan(((1.0 / B) * ((C - A) - Math.sqrt((Math.pow((A - C), 2.0) + Math.pow(B, 2.0)))))) / Math.PI);
}
def code(A, B, C):
	return 180.0 * (math.atan(((1.0 / B) * ((C - A) - math.sqrt((math.pow((A - C), 2.0) + math.pow(B, 2.0)))))) / math.pi)
function code(A, B, C)
	return Float64(180.0 * Float64(atan(Float64(Float64(1.0 / B) * Float64(Float64(C - A) - sqrt(Float64((Float64(A - C) ^ 2.0) + (B ^ 2.0)))))) / pi))
end
function tmp = code(A, B, C)
	tmp = 180.0 * (atan(((1.0 / B) * ((C - A) - sqrt((((A - C) ^ 2.0) + (B ^ 2.0)))))) / pi);
end
code[A_, B_, C_] := N[(180.0 * N[(N[ArcTan[N[(N[(1.0 / B), $MachinePrecision] * N[(N[(C - A), $MachinePrecision] - N[Sqrt[N[(N[Power[N[(A - C), $MachinePrecision], 2.0], $MachinePrecision] + N[Power[B, 2.0], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi}
\end{array}

Alternative 1: 88.9% accurate, 0.5× speedup?

\[\begin{array}{l} \\ \begin{array}{l} t_0 := 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \mathsf{hypot}\left(C - A, B\right)\right)\right)}{\pi}\\ t_1 := \frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\\ \mathbf{if}\;t\_1 \leq -5 \cdot 10^{-102}:\\ \;\;\;\;t\_0\\ \mathbf{elif}\;t\_1 \leq 0:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(B \cdot \frac{-0.5}{C - A}\right)}{\pi}\\ \mathbf{else}:\\ \;\;\;\;t\_0\\ \end{array} \end{array} \]
(FPCore (A B C)
 :precision binary64
 (let* ((t_0
         (* 180.0 (/ (atan (* (/ 1.0 B) (- (- C A) (hypot (- C A) B)))) PI)))
        (t_1
         (* (/ 1.0 B) (- (- C A) (sqrt (+ (pow (- A C) 2.0) (pow B 2.0)))))))
   (if (<= t_1 -5e-102)
     t_0
     (if (<= t_1 0.0) (* 180.0 (/ (atan (* B (/ -0.5 (- C A)))) PI)) t_0))))
double code(double A, double B, double C) {
	double t_0 = 180.0 * (atan(((1.0 / B) * ((C - A) - hypot((C - A), B)))) / ((double) M_PI));
	double t_1 = (1.0 / B) * ((C - A) - sqrt((pow((A - C), 2.0) + pow(B, 2.0))));
	double tmp;
	if (t_1 <= -5e-102) {
		tmp = t_0;
	} else if (t_1 <= 0.0) {
		tmp = 180.0 * (atan((B * (-0.5 / (C - A)))) / ((double) M_PI));
	} else {
		tmp = t_0;
	}
	return tmp;
}
public static double code(double A, double B, double C) {
	double t_0 = 180.0 * (Math.atan(((1.0 / B) * ((C - A) - Math.hypot((C - A), B)))) / Math.PI);
	double t_1 = (1.0 / B) * ((C - A) - Math.sqrt((Math.pow((A - C), 2.0) + Math.pow(B, 2.0))));
	double tmp;
	if (t_1 <= -5e-102) {
		tmp = t_0;
	} else if (t_1 <= 0.0) {
		tmp = 180.0 * (Math.atan((B * (-0.5 / (C - A)))) / Math.PI);
	} else {
		tmp = t_0;
	}
	return tmp;
}
def code(A, B, C):
	t_0 = 180.0 * (math.atan(((1.0 / B) * ((C - A) - math.hypot((C - A), B)))) / math.pi)
	t_1 = (1.0 / B) * ((C - A) - math.sqrt((math.pow((A - C), 2.0) + math.pow(B, 2.0))))
	tmp = 0
	if t_1 <= -5e-102:
		tmp = t_0
	elif t_1 <= 0.0:
		tmp = 180.0 * (math.atan((B * (-0.5 / (C - A)))) / math.pi)
	else:
		tmp = t_0
	return tmp
function code(A, B, C)
	t_0 = Float64(180.0 * Float64(atan(Float64(Float64(1.0 / B) * Float64(Float64(C - A) - hypot(Float64(C - A), B)))) / pi))
	t_1 = Float64(Float64(1.0 / B) * Float64(Float64(C - A) - sqrt(Float64((Float64(A - C) ^ 2.0) + (B ^ 2.0)))))
	tmp = 0.0
	if (t_1 <= -5e-102)
		tmp = t_0;
	elseif (t_1 <= 0.0)
		tmp = Float64(180.0 * Float64(atan(Float64(B * Float64(-0.5 / Float64(C - A)))) / pi));
	else
		tmp = t_0;
	end
	return tmp
end
function tmp_2 = code(A, B, C)
	t_0 = 180.0 * (atan(((1.0 / B) * ((C - A) - hypot((C - A), B)))) / pi);
	t_1 = (1.0 / B) * ((C - A) - sqrt((((A - C) ^ 2.0) + (B ^ 2.0))));
	tmp = 0.0;
	if (t_1 <= -5e-102)
		tmp = t_0;
	elseif (t_1 <= 0.0)
		tmp = 180.0 * (atan((B * (-0.5 / (C - A)))) / pi);
	else
		tmp = t_0;
	end
	tmp_2 = tmp;
end
code[A_, B_, C_] := Block[{t$95$0 = N[(180.0 * N[(N[ArcTan[N[(N[(1.0 / B), $MachinePrecision] * N[(N[(C - A), $MachinePrecision] - N[Sqrt[N[(C - A), $MachinePrecision] ^ 2 + B ^ 2], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$1 = N[(N[(1.0 / B), $MachinePrecision] * N[(N[(C - A), $MachinePrecision] - N[Sqrt[N[(N[Power[N[(A - C), $MachinePrecision], 2.0], $MachinePrecision] + N[Power[B, 2.0], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[t$95$1, -5e-102], t$95$0, If[LessEqual[t$95$1, 0.0], N[(180.0 * N[(N[ArcTan[N[(B * N[(-0.5 / N[(C - A), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision], t$95$0]]]]
\begin{array}{l}

\\
\begin{array}{l}
t_0 := 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \mathsf{hypot}\left(C - A, B\right)\right)\right)}{\pi}\\
t_1 := \frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\\
\mathbf{if}\;t\_1 \leq -5 \cdot 10^{-102}:\\
\;\;\;\;t\_0\\

\mathbf{elif}\;t\_1 \leq 0:\\
\;\;\;\;180 \cdot \frac{\tan^{-1} \left(B \cdot \frac{-0.5}{C - A}\right)}{\pi}\\

\mathbf{else}:\\
\;\;\;\;t\_0\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if (*.f64 (/.f64 #s(literal 1 binary64) B) (-.f64 (-.f64 C A) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))) < -5.00000000000000026e-102 or 0.0 < (*.f64 (/.f64 #s(literal 1 binary64) B) (-.f64 (-.f64 C A) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64))))))

    1. Initial program 60.0%

      \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
    2. Add Preprocessing
    3. Step-by-step derivation
      1. Applied egg-rr88.7%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \color{blue}{\mathsf{hypot}\left(C - A, B\right)}\right)\right)}{\pi} \]

      if -5.00000000000000026e-102 < (*.f64 (/.f64 #s(literal 1 binary64) B) (-.f64 (-.f64 C A) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))) < 0.0

      1. Initial program 19.5%

        \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
      2. Add Preprocessing
      3. Step-by-step derivation
        1. Applied egg-rr19.5%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \color{blue}{\mathsf{hypot}\left(C - A, B\right)}\right)\right)}{\pi} \]
        2. Taylor expanded in B around 0

          \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{-1}{2} \cdot \frac{B}{C - A}\right)}}{\mathsf{PI}\left(\right)} \]
        3. Step-by-step derivation
          1. associate-*r/N/A

            \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{\frac{-1}{2} \cdot B}{C - A}\right)}}{\mathsf{PI}\left(\right)} \]
          2. *-commutativeN/A

            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\color{blue}{B \cdot \frac{-1}{2}}}{C - A}\right)}{\mathsf{PI}\left(\right)} \]
          3. associate-/l*N/A

            \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(B \cdot \frac{\frac{-1}{2}}{C - A}\right)}}{\mathsf{PI}\left(\right)} \]
          4. metadata-evalN/A

            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(B \cdot \frac{\color{blue}{\mathsf{neg}\left(\frac{1}{2}\right)}}{C - A}\right)}{\mathsf{PI}\left(\right)} \]
          5. distribute-neg-fracN/A

            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(B \cdot \color{blue}{\left(\mathsf{neg}\left(\frac{\frac{1}{2}}{C - A}\right)\right)}\right)}{\mathsf{PI}\left(\right)} \]
          6. metadata-evalN/A

            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(B \cdot \left(\mathsf{neg}\left(\frac{\color{blue}{\frac{1}{2} \cdot 1}}{C - A}\right)\right)\right)}{\mathsf{PI}\left(\right)} \]
          7. associate-*r/N/A

            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(B \cdot \left(\mathsf{neg}\left(\color{blue}{\frac{1}{2} \cdot \frac{1}{C - A}}\right)\right)\right)}{\mathsf{PI}\left(\right)} \]
          8. lower-*.f64N/A

            \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(B \cdot \left(\mathsf{neg}\left(\frac{1}{2} \cdot \frac{1}{C - A}\right)\right)\right)}}{\mathsf{PI}\left(\right)} \]
          9. associate-*r/N/A

            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(B \cdot \left(\mathsf{neg}\left(\color{blue}{\frac{\frac{1}{2} \cdot 1}{C - A}}\right)\right)\right)}{\mathsf{PI}\left(\right)} \]
          10. metadata-evalN/A

            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(B \cdot \left(\mathsf{neg}\left(\frac{\color{blue}{\frac{1}{2}}}{C - A}\right)\right)\right)}{\mathsf{PI}\left(\right)} \]
          11. distribute-neg-fracN/A

            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(B \cdot \color{blue}{\frac{\mathsf{neg}\left(\frac{1}{2}\right)}{C - A}}\right)}{\mathsf{PI}\left(\right)} \]
          12. metadata-evalN/A

            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(B \cdot \frac{\color{blue}{\frac{-1}{2}}}{C - A}\right)}{\mathsf{PI}\left(\right)} \]
          13. lower-/.f64N/A

            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(B \cdot \color{blue}{\frac{\frac{-1}{2}}{C - A}}\right)}{\mathsf{PI}\left(\right)} \]
          14. lower--.f6499.1

            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(B \cdot \frac{-0.5}{\color{blue}{C - A}}\right)}{\pi} \]
        4. Simplified99.1%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(B \cdot \frac{-0.5}{C - A}\right)}}{\pi} \]
      4. Recombined 2 regimes into one program.
      5. Add Preprocessing

      Alternative 2: 67.5% accurate, 0.4× speedup?

      \[\begin{array}{l} \\ \begin{array}{l} t_0 := \tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)\\ \mathbf{if}\;t\_0 \leq -0.5:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(-1 - \frac{A}{B}\right)}{\pi}\\ \mathbf{elif}\;t\_0 \leq 0:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{B \cdot 0.5}{A}\right)}{\pi}\\ \mathbf{else}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(1 + \frac{C - A}{B}\right)}{\pi}\\ \end{array} \end{array} \]
      (FPCore (A B C)
       :precision binary64
       (let* ((t_0
               (atan
                (* (/ 1.0 B) (- (- C A) (sqrt (+ (pow (- A C) 2.0) (pow B 2.0))))))))
         (if (<= t_0 -0.5)
           (* 180.0 (/ (atan (- -1.0 (/ A B))) PI))
           (if (<= t_0 0.0)
             (* 180.0 (/ (atan (/ (* B 0.5) A)) PI))
             (* 180.0 (/ (atan (+ 1.0 (/ (- C A) B))) PI))))))
      double code(double A, double B, double C) {
      	double t_0 = atan(((1.0 / B) * ((C - A) - sqrt((pow((A - C), 2.0) + pow(B, 2.0))))));
      	double tmp;
      	if (t_0 <= -0.5) {
      		tmp = 180.0 * (atan((-1.0 - (A / B))) / ((double) M_PI));
      	} else if (t_0 <= 0.0) {
      		tmp = 180.0 * (atan(((B * 0.5) / A)) / ((double) M_PI));
      	} else {
      		tmp = 180.0 * (atan((1.0 + ((C - A) / B))) / ((double) M_PI));
      	}
      	return tmp;
      }
      
      public static double code(double A, double B, double C) {
      	double t_0 = Math.atan(((1.0 / B) * ((C - A) - Math.sqrt((Math.pow((A - C), 2.0) + Math.pow(B, 2.0))))));
      	double tmp;
      	if (t_0 <= -0.5) {
      		tmp = 180.0 * (Math.atan((-1.0 - (A / B))) / Math.PI);
      	} else if (t_0 <= 0.0) {
      		tmp = 180.0 * (Math.atan(((B * 0.5) / A)) / Math.PI);
      	} else {
      		tmp = 180.0 * (Math.atan((1.0 + ((C - A) / B))) / Math.PI);
      	}
      	return tmp;
      }
      
      def code(A, B, C):
      	t_0 = math.atan(((1.0 / B) * ((C - A) - math.sqrt((math.pow((A - C), 2.0) + math.pow(B, 2.0))))))
      	tmp = 0
      	if t_0 <= -0.5:
      		tmp = 180.0 * (math.atan((-1.0 - (A / B))) / math.pi)
      	elif t_0 <= 0.0:
      		tmp = 180.0 * (math.atan(((B * 0.5) / A)) / math.pi)
      	else:
      		tmp = 180.0 * (math.atan((1.0 + ((C - A) / B))) / math.pi)
      	return tmp
      
      function code(A, B, C)
      	t_0 = atan(Float64(Float64(1.0 / B) * Float64(Float64(C - A) - sqrt(Float64((Float64(A - C) ^ 2.0) + (B ^ 2.0))))))
      	tmp = 0.0
      	if (t_0 <= -0.5)
      		tmp = Float64(180.0 * Float64(atan(Float64(-1.0 - Float64(A / B))) / pi));
      	elseif (t_0 <= 0.0)
      		tmp = Float64(180.0 * Float64(atan(Float64(Float64(B * 0.5) / A)) / pi));
      	else
      		tmp = Float64(180.0 * Float64(atan(Float64(1.0 + Float64(Float64(C - A) / B))) / pi));
      	end
      	return tmp
      end
      
      function tmp_2 = code(A, B, C)
      	t_0 = atan(((1.0 / B) * ((C - A) - sqrt((((A - C) ^ 2.0) + (B ^ 2.0))))));
      	tmp = 0.0;
      	if (t_0 <= -0.5)
      		tmp = 180.0 * (atan((-1.0 - (A / B))) / pi);
      	elseif (t_0 <= 0.0)
      		tmp = 180.0 * (atan(((B * 0.5) / A)) / pi);
      	else
      		tmp = 180.0 * (atan((1.0 + ((C - A) / B))) / pi);
      	end
      	tmp_2 = tmp;
      end
      
      code[A_, B_, C_] := Block[{t$95$0 = N[ArcTan[N[(N[(1.0 / B), $MachinePrecision] * N[(N[(C - A), $MachinePrecision] - N[Sqrt[N[(N[Power[N[(A - C), $MachinePrecision], 2.0], $MachinePrecision] + N[Power[B, 2.0], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]}, If[LessEqual[t$95$0, -0.5], N[(180.0 * N[(N[ArcTan[N[(-1.0 - N[(A / B), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision], If[LessEqual[t$95$0, 0.0], N[(180.0 * N[(N[ArcTan[N[(N[(B * 0.5), $MachinePrecision] / A), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision], N[(180.0 * N[(N[ArcTan[N[(1.0 + N[(N[(C - A), $MachinePrecision] / B), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision]]]]
      
      \begin{array}{l}
      
      \\
      \begin{array}{l}
      t_0 := \tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)\\
      \mathbf{if}\;t\_0 \leq -0.5:\\
      \;\;\;\;180 \cdot \frac{\tan^{-1} \left(-1 - \frac{A}{B}\right)}{\pi}\\
      
      \mathbf{elif}\;t\_0 \leq 0:\\
      \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{B \cdot 0.5}{A}\right)}{\pi}\\
      
      \mathbf{else}:\\
      \;\;\;\;180 \cdot \frac{\tan^{-1} \left(1 + \frac{C - A}{B}\right)}{\pi}\\
      
      
      \end{array}
      \end{array}
      
      Derivation
      1. Split input into 3 regimes
      2. if (atan.f64 (*.f64 (/.f64 #s(literal 1 binary64) B) (-.f64 (-.f64 C A) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64))))))) < -0.5

        1. Initial program 63.3%

          \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
        2. Add Preprocessing
        3. Step-by-step derivation
          1. lift--.f64N/A

            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\color{blue}{\left(C - A\right)} - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\mathsf{PI}\left(\right)} \]
          2. lift--.f64N/A

            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\color{blue}{\left(A - C\right)}}^{2} + {B}^{2}}\right)\right)}{\mathsf{PI}\left(\right)} \]
          3. lift-pow.f64N/A

            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{\color{blue}{{\left(A - C\right)}^{2}} + {B}^{2}}\right)\right)}{\mathsf{PI}\left(\right)} \]
          4. lift-pow.f64N/A

            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + \color{blue}{{B}^{2}}}\right)\right)}{\mathsf{PI}\left(\right)} \]
          5. lift-+.f64N/A

            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{\color{blue}{{\left(A - C\right)}^{2} + {B}^{2}}}\right)\right)}{\mathsf{PI}\left(\right)} \]
          6. lift-sqrt.f64N/A

            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \color{blue}{\sqrt{{\left(A - C\right)}^{2} + {B}^{2}}}\right)\right)}{\mathsf{PI}\left(\right)} \]
          7. lift--.f64N/A

            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \color{blue}{\left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}\right)}{\mathsf{PI}\left(\right)} \]
          8. associate-*l/N/A

            \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{1 \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}{B}\right)}}{\mathsf{PI}\left(\right)} \]
          9. *-lft-identityN/A

            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\color{blue}{\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}}}{B}\right)}{\mathsf{PI}\left(\right)} \]
          10. lift--.f64N/A

            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\color{blue}{\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}}}{B}\right)}{\mathsf{PI}\left(\right)} \]
          11. div-subN/A

            \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{C - A}{B} - \frac{\sqrt{{\left(A - C\right)}^{2} + {B}^{2}}}{B}\right)}}{\mathsf{PI}\left(\right)} \]
          12. un-div-invN/A

            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\color{blue}{\left(C - A\right) \cdot \frac{1}{B}} - \frac{\sqrt{{\left(A - C\right)}^{2} + {B}^{2}}}{B}\right)}{\mathsf{PI}\left(\right)} \]
          13. lift-/.f64N/A

            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\left(C - A\right) \cdot \color{blue}{\frac{1}{B}} - \frac{\sqrt{{\left(A - C\right)}^{2} + {B}^{2}}}{B}\right)}{\mathsf{PI}\left(\right)} \]
          14. lower--.f64N/A

            \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\left(C - A\right) \cdot \frac{1}{B} - \frac{\sqrt{{\left(A - C\right)}^{2} + {B}^{2}}}{B}\right)}}{\mathsf{PI}\left(\right)} \]
        4. Applied egg-rr63.0%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{C - A}{B} - \frac{\sqrt{\mathsf{fma}\left(A - C, A - C, B \cdot B\right)}}{B}\right)}}{\pi} \]
        5. Taylor expanded in A around 0

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{C - A}{B} - \frac{\color{blue}{\sqrt{{B}^{2} + {C}^{2}}}}{B}\right)}{\mathsf{PI}\left(\right)} \]
        6. Step-by-step derivation
          1. lower-sqrt.f64N/A

            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{C - A}{B} - \frac{\color{blue}{\sqrt{{B}^{2} + {C}^{2}}}}{B}\right)}{\mathsf{PI}\left(\right)} \]
          2. unpow2N/A

            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{C - A}{B} - \frac{\sqrt{\color{blue}{B \cdot B} + {C}^{2}}}{B}\right)}{\mathsf{PI}\left(\right)} \]
          3. lower-fma.f64N/A

            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{C - A}{B} - \frac{\sqrt{\color{blue}{\mathsf{fma}\left(B, B, {C}^{2}\right)}}}{B}\right)}{\mathsf{PI}\left(\right)} \]
          4. unpow2N/A

            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{C - A}{B} - \frac{\sqrt{\mathsf{fma}\left(B, B, \color{blue}{C \cdot C}\right)}}{B}\right)}{\mathsf{PI}\left(\right)} \]
          5. lower-*.f6462.8

            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{C - A}{B} - \frac{\sqrt{\mathsf{fma}\left(B, B, \color{blue}{C \cdot C}\right)}}{B}\right)}{\pi} \]
        7. Simplified62.8%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{C - A}{B} - \frac{\color{blue}{\sqrt{\mathsf{fma}\left(B, B, C \cdot C\right)}}}{B}\right)}{\pi} \]
        8. Taylor expanded in C around 0

          \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(-1 \cdot \left(1 + \frac{A}{B}\right)\right)}}{\mathsf{PI}\left(\right)} \]
        9. Step-by-step derivation
          1. distribute-lft-inN/A

            \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(-1 \cdot 1 + -1 \cdot \frac{A}{B}\right)}}{\mathsf{PI}\left(\right)} \]
          2. metadata-evalN/A

            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\color{blue}{-1} + -1 \cdot \frac{A}{B}\right)}{\mathsf{PI}\left(\right)} \]
          3. mul-1-negN/A

            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(-1 + \color{blue}{\left(\mathsf{neg}\left(\frac{A}{B}\right)\right)}\right)}{\mathsf{PI}\left(\right)} \]
          4. unsub-negN/A

            \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(-1 - \frac{A}{B}\right)}}{\mathsf{PI}\left(\right)} \]
          5. lower--.f64N/A

            \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(-1 - \frac{A}{B}\right)}}{\mathsf{PI}\left(\right)} \]
          6. lower-/.f6468.8

            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(-1 - \color{blue}{\frac{A}{B}}\right)}{\pi} \]
        10. Simplified68.8%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(-1 - \frac{A}{B}\right)}}{\pi} \]

        if -0.5 < (atan.f64 (*.f64 (/.f64 #s(literal 1 binary64) B) (-.f64 (-.f64 C A) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64))))))) < 0.0

        1. Initial program 19.1%

          \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
        2. Add Preprocessing
        3. Taylor expanded in A around -inf

          \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{1}{2} \cdot \frac{B}{A}\right)}}{\mathsf{PI}\left(\right)} \]
        4. Step-by-step derivation
          1. associate-*r/N/A

            \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{\frac{1}{2} \cdot B}{A}\right)}}{\mathsf{PI}\left(\right)} \]
          2. lower-/.f64N/A

            \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{\frac{1}{2} \cdot B}{A}\right)}}{\mathsf{PI}\left(\right)} \]
          3. *-commutativeN/A

            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\color{blue}{B \cdot \frac{1}{2}}}{A}\right)}{\mathsf{PI}\left(\right)} \]
          4. lower-*.f6453.2

            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\color{blue}{B \cdot 0.5}}{A}\right)}{\pi} \]
        5. Simplified53.2%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{B \cdot 0.5}{A}\right)}}{\pi} \]

        if 0.0 < (atan.f64 (*.f64 (/.f64 #s(literal 1 binary64) B) (-.f64 (-.f64 C A) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))

        1. Initial program 57.6%

          \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
        2. Add Preprocessing
        3. Taylor expanded in B around -inf

          \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\left(1 + \frac{C}{B}\right) - \frac{A}{B}\right)}}{\mathsf{PI}\left(\right)} \]
        4. Step-by-step derivation
          1. associate--l+N/A

            \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(1 + \left(\frac{C}{B} - \frac{A}{B}\right)\right)}}{\mathsf{PI}\left(\right)} \]
          2. div-subN/A

            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \color{blue}{\frac{C - A}{B}}\right)}{\mathsf{PI}\left(\right)} \]
          3. lower-+.f64N/A

            \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(1 + \frac{C - A}{B}\right)}}{\mathsf{PI}\left(\right)} \]
          4. lower-/.f64N/A

            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \color{blue}{\frac{C - A}{B}}\right)}{\mathsf{PI}\left(\right)} \]
          5. lower--.f6479.1

            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \frac{\color{blue}{C - A}}{B}\right)}{\pi} \]
        5. Simplified79.1%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(1 + \frac{C - A}{B}\right)}}{\pi} \]
      3. Recombined 3 regimes into one program.
      4. Add Preprocessing

      Alternative 3: 62.5% accurate, 0.4× speedup?

      \[\begin{array}{l} \\ \begin{array}{l} t_0 := \tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)\\ \mathbf{if}\;t\_0 \leq -0.5:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(-1 - \frac{A}{B}\right)}{\pi}\\ \mathbf{elif}\;t\_0 \leq 0:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{B \cdot 0.5}{A}\right)}{\pi}\\ \mathbf{else}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(1 - \frac{A}{B}\right)}{\pi}\\ \end{array} \end{array} \]
      (FPCore (A B C)
       :precision binary64
       (let* ((t_0
               (atan
                (* (/ 1.0 B) (- (- C A) (sqrt (+ (pow (- A C) 2.0) (pow B 2.0))))))))
         (if (<= t_0 -0.5)
           (* 180.0 (/ (atan (- -1.0 (/ A B))) PI))
           (if (<= t_0 0.0)
             (* 180.0 (/ (atan (/ (* B 0.5) A)) PI))
             (* 180.0 (/ (atan (- 1.0 (/ A B))) PI))))))
      double code(double A, double B, double C) {
      	double t_0 = atan(((1.0 / B) * ((C - A) - sqrt((pow((A - C), 2.0) + pow(B, 2.0))))));
      	double tmp;
      	if (t_0 <= -0.5) {
      		tmp = 180.0 * (atan((-1.0 - (A / B))) / ((double) M_PI));
      	} else if (t_0 <= 0.0) {
      		tmp = 180.0 * (atan(((B * 0.5) / A)) / ((double) M_PI));
      	} else {
      		tmp = 180.0 * (atan((1.0 - (A / B))) / ((double) M_PI));
      	}
      	return tmp;
      }
      
      public static double code(double A, double B, double C) {
      	double t_0 = Math.atan(((1.0 / B) * ((C - A) - Math.sqrt((Math.pow((A - C), 2.0) + Math.pow(B, 2.0))))));
      	double tmp;
      	if (t_0 <= -0.5) {
      		tmp = 180.0 * (Math.atan((-1.0 - (A / B))) / Math.PI);
      	} else if (t_0 <= 0.0) {
      		tmp = 180.0 * (Math.atan(((B * 0.5) / A)) / Math.PI);
      	} else {
      		tmp = 180.0 * (Math.atan((1.0 - (A / B))) / Math.PI);
      	}
      	return tmp;
      }
      
      def code(A, B, C):
      	t_0 = math.atan(((1.0 / B) * ((C - A) - math.sqrt((math.pow((A - C), 2.0) + math.pow(B, 2.0))))))
      	tmp = 0
      	if t_0 <= -0.5:
      		tmp = 180.0 * (math.atan((-1.0 - (A / B))) / math.pi)
      	elif t_0 <= 0.0:
      		tmp = 180.0 * (math.atan(((B * 0.5) / A)) / math.pi)
      	else:
      		tmp = 180.0 * (math.atan((1.0 - (A / B))) / math.pi)
      	return tmp
      
      function code(A, B, C)
      	t_0 = atan(Float64(Float64(1.0 / B) * Float64(Float64(C - A) - sqrt(Float64((Float64(A - C) ^ 2.0) + (B ^ 2.0))))))
      	tmp = 0.0
      	if (t_0 <= -0.5)
      		tmp = Float64(180.0 * Float64(atan(Float64(-1.0 - Float64(A / B))) / pi));
      	elseif (t_0 <= 0.0)
      		tmp = Float64(180.0 * Float64(atan(Float64(Float64(B * 0.5) / A)) / pi));
      	else
      		tmp = Float64(180.0 * Float64(atan(Float64(1.0 - Float64(A / B))) / pi));
      	end
      	return tmp
      end
      
      function tmp_2 = code(A, B, C)
      	t_0 = atan(((1.0 / B) * ((C - A) - sqrt((((A - C) ^ 2.0) + (B ^ 2.0))))));
      	tmp = 0.0;
      	if (t_0 <= -0.5)
      		tmp = 180.0 * (atan((-1.0 - (A / B))) / pi);
      	elseif (t_0 <= 0.0)
      		tmp = 180.0 * (atan(((B * 0.5) / A)) / pi);
      	else
      		tmp = 180.0 * (atan((1.0 - (A / B))) / pi);
      	end
      	tmp_2 = tmp;
      end
      
      code[A_, B_, C_] := Block[{t$95$0 = N[ArcTan[N[(N[(1.0 / B), $MachinePrecision] * N[(N[(C - A), $MachinePrecision] - N[Sqrt[N[(N[Power[N[(A - C), $MachinePrecision], 2.0], $MachinePrecision] + N[Power[B, 2.0], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]}, If[LessEqual[t$95$0, -0.5], N[(180.0 * N[(N[ArcTan[N[(-1.0 - N[(A / B), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision], If[LessEqual[t$95$0, 0.0], N[(180.0 * N[(N[ArcTan[N[(N[(B * 0.5), $MachinePrecision] / A), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision], N[(180.0 * N[(N[ArcTan[N[(1.0 - N[(A / B), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision]]]]
      
      \begin{array}{l}
      
      \\
      \begin{array}{l}
      t_0 := \tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)\\
      \mathbf{if}\;t\_0 \leq -0.5:\\
      \;\;\;\;180 \cdot \frac{\tan^{-1} \left(-1 - \frac{A}{B}\right)}{\pi}\\
      
      \mathbf{elif}\;t\_0 \leq 0:\\
      \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{B \cdot 0.5}{A}\right)}{\pi}\\
      
      \mathbf{else}:\\
      \;\;\;\;180 \cdot \frac{\tan^{-1} \left(1 - \frac{A}{B}\right)}{\pi}\\
      
      
      \end{array}
      \end{array}
      
      Derivation
      1. Split input into 3 regimes
      2. if (atan.f64 (*.f64 (/.f64 #s(literal 1 binary64) B) (-.f64 (-.f64 C A) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64))))))) < -0.5

        1. Initial program 63.3%

          \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
        2. Add Preprocessing
        3. Step-by-step derivation
          1. lift--.f64N/A

            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\color{blue}{\left(C - A\right)} - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\mathsf{PI}\left(\right)} \]
          2. lift--.f64N/A

            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\color{blue}{\left(A - C\right)}}^{2} + {B}^{2}}\right)\right)}{\mathsf{PI}\left(\right)} \]
          3. lift-pow.f64N/A

            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{\color{blue}{{\left(A - C\right)}^{2}} + {B}^{2}}\right)\right)}{\mathsf{PI}\left(\right)} \]
          4. lift-pow.f64N/A

            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + \color{blue}{{B}^{2}}}\right)\right)}{\mathsf{PI}\left(\right)} \]
          5. lift-+.f64N/A

            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{\color{blue}{{\left(A - C\right)}^{2} + {B}^{2}}}\right)\right)}{\mathsf{PI}\left(\right)} \]
          6. lift-sqrt.f64N/A

            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \color{blue}{\sqrt{{\left(A - C\right)}^{2} + {B}^{2}}}\right)\right)}{\mathsf{PI}\left(\right)} \]
          7. lift--.f64N/A

            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \color{blue}{\left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}\right)}{\mathsf{PI}\left(\right)} \]
          8. associate-*l/N/A

            \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{1 \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}{B}\right)}}{\mathsf{PI}\left(\right)} \]
          9. *-lft-identityN/A

            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\color{blue}{\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}}}{B}\right)}{\mathsf{PI}\left(\right)} \]
          10. lift--.f64N/A

            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\color{blue}{\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}}}{B}\right)}{\mathsf{PI}\left(\right)} \]
          11. div-subN/A

            \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{C - A}{B} - \frac{\sqrt{{\left(A - C\right)}^{2} + {B}^{2}}}{B}\right)}}{\mathsf{PI}\left(\right)} \]
          12. un-div-invN/A

            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\color{blue}{\left(C - A\right) \cdot \frac{1}{B}} - \frac{\sqrt{{\left(A - C\right)}^{2} + {B}^{2}}}{B}\right)}{\mathsf{PI}\left(\right)} \]
          13. lift-/.f64N/A

            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\left(C - A\right) \cdot \color{blue}{\frac{1}{B}} - \frac{\sqrt{{\left(A - C\right)}^{2} + {B}^{2}}}{B}\right)}{\mathsf{PI}\left(\right)} \]
          14. lower--.f64N/A

            \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\left(C - A\right) \cdot \frac{1}{B} - \frac{\sqrt{{\left(A - C\right)}^{2} + {B}^{2}}}{B}\right)}}{\mathsf{PI}\left(\right)} \]
        4. Applied egg-rr63.0%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{C - A}{B} - \frac{\sqrt{\mathsf{fma}\left(A - C, A - C, B \cdot B\right)}}{B}\right)}}{\pi} \]
        5. Taylor expanded in A around 0

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{C - A}{B} - \frac{\color{blue}{\sqrt{{B}^{2} + {C}^{2}}}}{B}\right)}{\mathsf{PI}\left(\right)} \]
        6. Step-by-step derivation
          1. lower-sqrt.f64N/A

            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{C - A}{B} - \frac{\color{blue}{\sqrt{{B}^{2} + {C}^{2}}}}{B}\right)}{\mathsf{PI}\left(\right)} \]
          2. unpow2N/A

            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{C - A}{B} - \frac{\sqrt{\color{blue}{B \cdot B} + {C}^{2}}}{B}\right)}{\mathsf{PI}\left(\right)} \]
          3. lower-fma.f64N/A

            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{C - A}{B} - \frac{\sqrt{\color{blue}{\mathsf{fma}\left(B, B, {C}^{2}\right)}}}{B}\right)}{\mathsf{PI}\left(\right)} \]
          4. unpow2N/A

            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{C - A}{B} - \frac{\sqrt{\mathsf{fma}\left(B, B, \color{blue}{C \cdot C}\right)}}{B}\right)}{\mathsf{PI}\left(\right)} \]
          5. lower-*.f6462.8

            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{C - A}{B} - \frac{\sqrt{\mathsf{fma}\left(B, B, \color{blue}{C \cdot C}\right)}}{B}\right)}{\pi} \]
        7. Simplified62.8%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{C - A}{B} - \frac{\color{blue}{\sqrt{\mathsf{fma}\left(B, B, C \cdot C\right)}}}{B}\right)}{\pi} \]
        8. Taylor expanded in C around 0

          \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(-1 \cdot \left(1 + \frac{A}{B}\right)\right)}}{\mathsf{PI}\left(\right)} \]
        9. Step-by-step derivation
          1. distribute-lft-inN/A

            \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(-1 \cdot 1 + -1 \cdot \frac{A}{B}\right)}}{\mathsf{PI}\left(\right)} \]
          2. metadata-evalN/A

            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\color{blue}{-1} + -1 \cdot \frac{A}{B}\right)}{\mathsf{PI}\left(\right)} \]
          3. mul-1-negN/A

            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(-1 + \color{blue}{\left(\mathsf{neg}\left(\frac{A}{B}\right)\right)}\right)}{\mathsf{PI}\left(\right)} \]
          4. unsub-negN/A

            \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(-1 - \frac{A}{B}\right)}}{\mathsf{PI}\left(\right)} \]
          5. lower--.f64N/A

            \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(-1 - \frac{A}{B}\right)}}{\mathsf{PI}\left(\right)} \]
          6. lower-/.f6468.8

            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(-1 - \color{blue}{\frac{A}{B}}\right)}{\pi} \]
        10. Simplified68.8%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(-1 - \frac{A}{B}\right)}}{\pi} \]

        if -0.5 < (atan.f64 (*.f64 (/.f64 #s(literal 1 binary64) B) (-.f64 (-.f64 C A) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64))))))) < 0.0

        1. Initial program 19.1%

          \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
        2. Add Preprocessing
        3. Taylor expanded in A around -inf

          \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{1}{2} \cdot \frac{B}{A}\right)}}{\mathsf{PI}\left(\right)} \]
        4. Step-by-step derivation
          1. associate-*r/N/A

            \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{\frac{1}{2} \cdot B}{A}\right)}}{\mathsf{PI}\left(\right)} \]
          2. lower-/.f64N/A

            \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{\frac{1}{2} \cdot B}{A}\right)}}{\mathsf{PI}\left(\right)} \]
          3. *-commutativeN/A

            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\color{blue}{B \cdot \frac{1}{2}}}{A}\right)}{\mathsf{PI}\left(\right)} \]
          4. lower-*.f6453.2

            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\color{blue}{B \cdot 0.5}}{A}\right)}{\pi} \]
        5. Simplified53.2%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{B \cdot 0.5}{A}\right)}}{\pi} \]

        if 0.0 < (atan.f64 (*.f64 (/.f64 #s(literal 1 binary64) B) (-.f64 (-.f64 C A) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))

        1. Initial program 57.6%

          \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
        2. Add Preprocessing
        3. Taylor expanded in B around -inf

          \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\left(1 + \frac{C}{B}\right) - \frac{A}{B}\right)}}{\mathsf{PI}\left(\right)} \]
        4. Step-by-step derivation
          1. associate--l+N/A

            \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(1 + \left(\frac{C}{B} - \frac{A}{B}\right)\right)}}{\mathsf{PI}\left(\right)} \]
          2. div-subN/A

            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \color{blue}{\frac{C - A}{B}}\right)}{\mathsf{PI}\left(\right)} \]
          3. lower-+.f64N/A

            \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(1 + \frac{C - A}{B}\right)}}{\mathsf{PI}\left(\right)} \]
          4. lower-/.f64N/A

            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \color{blue}{\frac{C - A}{B}}\right)}{\mathsf{PI}\left(\right)} \]
          5. lower--.f6479.1

            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \frac{\color{blue}{C - A}}{B}\right)}{\pi} \]
        5. Simplified79.1%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(1 + \frac{C - A}{B}\right)}}{\pi} \]
        6. Taylor expanded in C around 0

          \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(1 - \frac{A}{B}\right)}}{\mathsf{PI}\left(\right)} \]
        7. Step-by-step derivation
          1. lower--.f64N/A

            \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(1 - \frac{A}{B}\right)}}{\mathsf{PI}\left(\right)} \]
          2. lower-/.f6469.4

            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 - \color{blue}{\frac{A}{B}}\right)}{\pi} \]
        8. Simplified69.4%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(1 - \frac{A}{B}\right)}}{\pi} \]
      3. Recombined 3 regimes into one program.
      4. Add Preprocessing

      Alternative 4: 63.0% accurate, 0.4× speedup?

      \[\begin{array}{l} \\ \begin{array}{l} t_0 := \tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)\\ \mathbf{if}\;t\_0 \leq -5 \cdot 10^{-102}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(-1 - \frac{A}{B}\right)}{\pi}\\ \mathbf{elif}\;t\_0 \leq 0:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(B \cdot \frac{-0.5}{C}\right)}{\pi}\\ \mathbf{else}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(1 - \frac{A}{B}\right)}{\pi}\\ \end{array} \end{array} \]
      (FPCore (A B C)
       :precision binary64
       (let* ((t_0
               (atan
                (* (/ 1.0 B) (- (- C A) (sqrt (+ (pow (- A C) 2.0) (pow B 2.0))))))))
         (if (<= t_0 -5e-102)
           (* 180.0 (/ (atan (- -1.0 (/ A B))) PI))
           (if (<= t_0 0.0)
             (* 180.0 (/ (atan (* B (/ -0.5 C))) PI))
             (* 180.0 (/ (atan (- 1.0 (/ A B))) PI))))))
      double code(double A, double B, double C) {
      	double t_0 = atan(((1.0 / B) * ((C - A) - sqrt((pow((A - C), 2.0) + pow(B, 2.0))))));
      	double tmp;
      	if (t_0 <= -5e-102) {
      		tmp = 180.0 * (atan((-1.0 - (A / B))) / ((double) M_PI));
      	} else if (t_0 <= 0.0) {
      		tmp = 180.0 * (atan((B * (-0.5 / C))) / ((double) M_PI));
      	} else {
      		tmp = 180.0 * (atan((1.0 - (A / B))) / ((double) M_PI));
      	}
      	return tmp;
      }
      
      public static double code(double A, double B, double C) {
      	double t_0 = Math.atan(((1.0 / B) * ((C - A) - Math.sqrt((Math.pow((A - C), 2.0) + Math.pow(B, 2.0))))));
      	double tmp;
      	if (t_0 <= -5e-102) {
      		tmp = 180.0 * (Math.atan((-1.0 - (A / B))) / Math.PI);
      	} else if (t_0 <= 0.0) {
      		tmp = 180.0 * (Math.atan((B * (-0.5 / C))) / Math.PI);
      	} else {
      		tmp = 180.0 * (Math.atan((1.0 - (A / B))) / Math.PI);
      	}
      	return tmp;
      }
      
      def code(A, B, C):
      	t_0 = math.atan(((1.0 / B) * ((C - A) - math.sqrt((math.pow((A - C), 2.0) + math.pow(B, 2.0))))))
      	tmp = 0
      	if t_0 <= -5e-102:
      		tmp = 180.0 * (math.atan((-1.0 - (A / B))) / math.pi)
      	elif t_0 <= 0.0:
      		tmp = 180.0 * (math.atan((B * (-0.5 / C))) / math.pi)
      	else:
      		tmp = 180.0 * (math.atan((1.0 - (A / B))) / math.pi)
      	return tmp
      
      function code(A, B, C)
      	t_0 = atan(Float64(Float64(1.0 / B) * Float64(Float64(C - A) - sqrt(Float64((Float64(A - C) ^ 2.0) + (B ^ 2.0))))))
      	tmp = 0.0
      	if (t_0 <= -5e-102)
      		tmp = Float64(180.0 * Float64(atan(Float64(-1.0 - Float64(A / B))) / pi));
      	elseif (t_0 <= 0.0)
      		tmp = Float64(180.0 * Float64(atan(Float64(B * Float64(-0.5 / C))) / pi));
      	else
      		tmp = Float64(180.0 * Float64(atan(Float64(1.0 - Float64(A / B))) / pi));
      	end
      	return tmp
      end
      
      function tmp_2 = code(A, B, C)
      	t_0 = atan(((1.0 / B) * ((C - A) - sqrt((((A - C) ^ 2.0) + (B ^ 2.0))))));
      	tmp = 0.0;
      	if (t_0 <= -5e-102)
      		tmp = 180.0 * (atan((-1.0 - (A / B))) / pi);
      	elseif (t_0 <= 0.0)
      		tmp = 180.0 * (atan((B * (-0.5 / C))) / pi);
      	else
      		tmp = 180.0 * (atan((1.0 - (A / B))) / pi);
      	end
      	tmp_2 = tmp;
      end
      
      code[A_, B_, C_] := Block[{t$95$0 = N[ArcTan[N[(N[(1.0 / B), $MachinePrecision] * N[(N[(C - A), $MachinePrecision] - N[Sqrt[N[(N[Power[N[(A - C), $MachinePrecision], 2.0], $MachinePrecision] + N[Power[B, 2.0], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]}, If[LessEqual[t$95$0, -5e-102], N[(180.0 * N[(N[ArcTan[N[(-1.0 - N[(A / B), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision], If[LessEqual[t$95$0, 0.0], N[(180.0 * N[(N[ArcTan[N[(B * N[(-0.5 / C), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision], N[(180.0 * N[(N[ArcTan[N[(1.0 - N[(A / B), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision]]]]
      
      \begin{array}{l}
      
      \\
      \begin{array}{l}
      t_0 := \tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)\\
      \mathbf{if}\;t\_0 \leq -5 \cdot 10^{-102}:\\
      \;\;\;\;180 \cdot \frac{\tan^{-1} \left(-1 - \frac{A}{B}\right)}{\pi}\\
      
      \mathbf{elif}\;t\_0 \leq 0:\\
      \;\;\;\;180 \cdot \frac{\tan^{-1} \left(B \cdot \frac{-0.5}{C}\right)}{\pi}\\
      
      \mathbf{else}:\\
      \;\;\;\;180 \cdot \frac{\tan^{-1} \left(1 - \frac{A}{B}\right)}{\pi}\\
      
      
      \end{array}
      \end{array}
      
      Derivation
      1. Split input into 3 regimes
      2. if (atan.f64 (*.f64 (/.f64 #s(literal 1 binary64) B) (-.f64 (-.f64 C A) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64))))))) < -5.00000000000000026e-102

        1. Initial program 62.7%

          \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
        2. Add Preprocessing
        3. Step-by-step derivation
          1. lift--.f64N/A

            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\color{blue}{\left(C - A\right)} - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\mathsf{PI}\left(\right)} \]
          2. lift--.f64N/A

            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\color{blue}{\left(A - C\right)}}^{2} + {B}^{2}}\right)\right)}{\mathsf{PI}\left(\right)} \]
          3. lift-pow.f64N/A

            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{\color{blue}{{\left(A - C\right)}^{2}} + {B}^{2}}\right)\right)}{\mathsf{PI}\left(\right)} \]
          4. lift-pow.f64N/A

            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + \color{blue}{{B}^{2}}}\right)\right)}{\mathsf{PI}\left(\right)} \]
          5. lift-+.f64N/A

            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{\color{blue}{{\left(A - C\right)}^{2} + {B}^{2}}}\right)\right)}{\mathsf{PI}\left(\right)} \]
          6. lift-sqrt.f64N/A

            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \color{blue}{\sqrt{{\left(A - C\right)}^{2} + {B}^{2}}}\right)\right)}{\mathsf{PI}\left(\right)} \]
          7. lift--.f64N/A

            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \color{blue}{\left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}\right)}{\mathsf{PI}\left(\right)} \]
          8. associate-*l/N/A

            \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{1 \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}{B}\right)}}{\mathsf{PI}\left(\right)} \]
          9. *-lft-identityN/A

            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\color{blue}{\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}}}{B}\right)}{\mathsf{PI}\left(\right)} \]
          10. lift--.f64N/A

            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\color{blue}{\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}}}{B}\right)}{\mathsf{PI}\left(\right)} \]
          11. div-subN/A

            \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{C - A}{B} - \frac{\sqrt{{\left(A - C\right)}^{2} + {B}^{2}}}{B}\right)}}{\mathsf{PI}\left(\right)} \]
          12. un-div-invN/A

            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\color{blue}{\left(C - A\right) \cdot \frac{1}{B}} - \frac{\sqrt{{\left(A - C\right)}^{2} + {B}^{2}}}{B}\right)}{\mathsf{PI}\left(\right)} \]
          13. lift-/.f64N/A

            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\left(C - A\right) \cdot \color{blue}{\frac{1}{B}} - \frac{\sqrt{{\left(A - C\right)}^{2} + {B}^{2}}}{B}\right)}{\mathsf{PI}\left(\right)} \]
          14. lower--.f64N/A

            \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\left(C - A\right) \cdot \frac{1}{B} - \frac{\sqrt{{\left(A - C\right)}^{2} + {B}^{2}}}{B}\right)}}{\mathsf{PI}\left(\right)} \]
        4. Applied egg-rr62.4%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{C - A}{B} - \frac{\sqrt{\mathsf{fma}\left(A - C, A - C, B \cdot B\right)}}{B}\right)}}{\pi} \]
        5. Taylor expanded in A around 0

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{C - A}{B} - \frac{\color{blue}{\sqrt{{B}^{2} + {C}^{2}}}}{B}\right)}{\mathsf{PI}\left(\right)} \]
        6. Step-by-step derivation
          1. lower-sqrt.f64N/A

            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{C - A}{B} - \frac{\color{blue}{\sqrt{{B}^{2} + {C}^{2}}}}{B}\right)}{\mathsf{PI}\left(\right)} \]
          2. unpow2N/A

            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{C - A}{B} - \frac{\sqrt{\color{blue}{B \cdot B} + {C}^{2}}}{B}\right)}{\mathsf{PI}\left(\right)} \]
          3. lower-fma.f64N/A

            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{C - A}{B} - \frac{\sqrt{\color{blue}{\mathsf{fma}\left(B, B, {C}^{2}\right)}}}{B}\right)}{\mathsf{PI}\left(\right)} \]
          4. unpow2N/A

            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{C - A}{B} - \frac{\sqrt{\mathsf{fma}\left(B, B, \color{blue}{C \cdot C}\right)}}{B}\right)}{\mathsf{PI}\left(\right)} \]
          5. lower-*.f6462.2

            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{C - A}{B} - \frac{\sqrt{\mathsf{fma}\left(B, B, \color{blue}{C \cdot C}\right)}}{B}\right)}{\pi} \]
        7. Simplified62.2%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{C - A}{B} - \frac{\color{blue}{\sqrt{\mathsf{fma}\left(B, B, C \cdot C\right)}}}{B}\right)}{\pi} \]
        8. Taylor expanded in C around 0

          \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(-1 \cdot \left(1 + \frac{A}{B}\right)\right)}}{\mathsf{PI}\left(\right)} \]
        9. Step-by-step derivation
          1. distribute-lft-inN/A

            \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(-1 \cdot 1 + -1 \cdot \frac{A}{B}\right)}}{\mathsf{PI}\left(\right)} \]
          2. metadata-evalN/A

            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\color{blue}{-1} + -1 \cdot \frac{A}{B}\right)}{\mathsf{PI}\left(\right)} \]
          3. mul-1-negN/A

            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(-1 + \color{blue}{\left(\mathsf{neg}\left(\frac{A}{B}\right)\right)}\right)}{\mathsf{PI}\left(\right)} \]
          4. unsub-negN/A

            \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(-1 - \frac{A}{B}\right)}}{\mathsf{PI}\left(\right)} \]
          5. lower--.f64N/A

            \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(-1 - \frac{A}{B}\right)}}{\mathsf{PI}\left(\right)} \]
          6. lower-/.f6468.1

            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(-1 - \color{blue}{\frac{A}{B}}\right)}{\pi} \]
        10. Simplified68.1%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(-1 - \frac{A}{B}\right)}}{\pi} \]

        if -5.00000000000000026e-102 < (atan.f64 (*.f64 (/.f64 #s(literal 1 binary64) B) (-.f64 (-.f64 C A) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64))))))) < 0.0

        1. Initial program 19.5%

          \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
        2. Add Preprocessing
        3. Taylor expanded in C around inf

          \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(-1 \cdot \frac{A + -1 \cdot A}{B} + \frac{-1}{2} \cdot \frac{B}{C}\right)}}{\mathsf{PI}\left(\right)} \]
        4. Step-by-step derivation
          1. +-commutativeN/A

            \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{-1}{2} \cdot \frac{B}{C} + -1 \cdot \frac{A + -1 \cdot A}{B}\right)}}{\mathsf{PI}\left(\right)} \]
          2. distribute-rgt1-inN/A

            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{-1}{2} \cdot \frac{B}{C} + -1 \cdot \frac{\color{blue}{\left(-1 + 1\right) \cdot A}}{B}\right)}{\mathsf{PI}\left(\right)} \]
          3. metadata-evalN/A

            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{-1}{2} \cdot \frac{B}{C} + -1 \cdot \frac{\color{blue}{0} \cdot A}{B}\right)}{\mathsf{PI}\left(\right)} \]
          4. mul0-lftN/A

            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{-1}{2} \cdot \frac{B}{C} + -1 \cdot \frac{\color{blue}{0}}{B}\right)}{\mathsf{PI}\left(\right)} \]
          5. div0N/A

            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{-1}{2} \cdot \frac{B}{C} + -1 \cdot \color{blue}{0}\right)}{\mathsf{PI}\left(\right)} \]
          6. metadata-evalN/A

            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{-1}{2} \cdot \frac{B}{C} + \color{blue}{0}\right)}{\mathsf{PI}\left(\right)} \]
          7. lower-fma.f64N/A

            \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\mathsf{fma}\left(\frac{-1}{2}, \frac{B}{C}, 0\right)\right)}}{\mathsf{PI}\left(\right)} \]
          8. lower-/.f6451.5

            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\mathsf{fma}\left(-0.5, \color{blue}{\frac{B}{C}}, 0\right)\right)}{\pi} \]
        5. Simplified51.5%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\mathsf{fma}\left(-0.5, \frac{B}{C}, 0\right)\right)}}{\pi} \]
        6. Step-by-step derivation
          1. lift-/.f64N/A

            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{-1}{2} \cdot \color{blue}{\frac{B}{C}} + 0\right)}{\mathsf{PI}\left(\right)} \]
          2. +-rgt-identityN/A

            \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{-1}{2} \cdot \frac{B}{C}\right)}}{\mathsf{PI}\left(\right)} \]
          3. *-commutativeN/A

            \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{B}{C} \cdot \frac{-1}{2}\right)}}{\mathsf{PI}\left(\right)} \]
          4. lift-/.f64N/A

            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\color{blue}{\frac{B}{C}} \cdot \frac{-1}{2}\right)}{\mathsf{PI}\left(\right)} \]
          5. frac-2negN/A

            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\color{blue}{\frac{\mathsf{neg}\left(B\right)}{\mathsf{neg}\left(C\right)}} \cdot \frac{-1}{2}\right)}{\mathsf{PI}\left(\right)} \]
          6. associate-*l/N/A

            \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{\left(\mathsf{neg}\left(B\right)\right) \cdot \frac{-1}{2}}{\mathsf{neg}\left(C\right)}\right)}}{\mathsf{PI}\left(\right)} \]
          7. neg-mul-1N/A

            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\left(\mathsf{neg}\left(B\right)\right) \cdot \frac{-1}{2}}{\color{blue}{-1 \cdot C}}\right)}{\mathsf{PI}\left(\right)} \]
          8. times-fracN/A

            \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{\mathsf{neg}\left(B\right)}{-1} \cdot \frac{\frac{-1}{2}}{C}\right)}}{\mathsf{PI}\left(\right)} \]
          9. metadata-evalN/A

            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\mathsf{neg}\left(B\right)}{\color{blue}{\mathsf{neg}\left(1\right)}} \cdot \frac{\frac{-1}{2}}{C}\right)}{\mathsf{PI}\left(\right)} \]
          10. frac-2negN/A

            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\color{blue}{\frac{B}{1}} \cdot \frac{\frac{-1}{2}}{C}\right)}{\mathsf{PI}\left(\right)} \]
          11. /-rgt-identityN/A

            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\color{blue}{B} \cdot \frac{\frac{-1}{2}}{C}\right)}{\mathsf{PI}\left(\right)} \]
          12. lower-*.f64N/A

            \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(B \cdot \frac{\frac{-1}{2}}{C}\right)}}{\mathsf{PI}\left(\right)} \]
          13. lower-/.f6451.6

            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(B \cdot \color{blue}{\frac{-0.5}{C}}\right)}{\pi} \]
        7. Applied egg-rr51.6%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(B \cdot \frac{-0.5}{C}\right)}}{\pi} \]

        if 0.0 < (atan.f64 (*.f64 (/.f64 #s(literal 1 binary64) B) (-.f64 (-.f64 C A) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))

        1. Initial program 57.6%

          \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
        2. Add Preprocessing
        3. Taylor expanded in B around -inf

          \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\left(1 + \frac{C}{B}\right) - \frac{A}{B}\right)}}{\mathsf{PI}\left(\right)} \]
        4. Step-by-step derivation
          1. associate--l+N/A

            \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(1 + \left(\frac{C}{B} - \frac{A}{B}\right)\right)}}{\mathsf{PI}\left(\right)} \]
          2. div-subN/A

            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \color{blue}{\frac{C - A}{B}}\right)}{\mathsf{PI}\left(\right)} \]
          3. lower-+.f64N/A

            \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(1 + \frac{C - A}{B}\right)}}{\mathsf{PI}\left(\right)} \]
          4. lower-/.f64N/A

            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \color{blue}{\frac{C - A}{B}}\right)}{\mathsf{PI}\left(\right)} \]
          5. lower--.f6479.1

            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \frac{\color{blue}{C - A}}{B}\right)}{\pi} \]
        5. Simplified79.1%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(1 + \frac{C - A}{B}\right)}}{\pi} \]
        6. Taylor expanded in C around 0

          \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(1 - \frac{A}{B}\right)}}{\mathsf{PI}\left(\right)} \]
        7. Step-by-step derivation
          1. lower--.f64N/A

            \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(1 - \frac{A}{B}\right)}}{\mathsf{PI}\left(\right)} \]
          2. lower-/.f6469.4

            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 - \color{blue}{\frac{A}{B}}\right)}{\pi} \]
        8. Simplified69.4%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(1 - \frac{A}{B}\right)}}{\pi} \]
      3. Recombined 3 regimes into one program.
      4. Add Preprocessing

      Alternative 5: 79.5% accurate, 0.6× speedup?

      \[\begin{array}{l} \\ \begin{array}{l} t_0 := \frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\\ t_1 := \frac{C - A}{B}\\ \mathbf{if}\;t\_0 \leq -0.5:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(t\_1 + -1\right)}{\pi}\\ \mathbf{elif}\;t\_0 \leq 0:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(B \cdot \frac{-0.5}{C - A}\right)}{\pi}\\ \mathbf{else}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(1 + t\_1\right)}{\pi}\\ \end{array} \end{array} \]
      (FPCore (A B C)
       :precision binary64
       (let* ((t_0
               (* (/ 1.0 B) (- (- C A) (sqrt (+ (pow (- A C) 2.0) (pow B 2.0))))))
              (t_1 (/ (- C A) B)))
         (if (<= t_0 -0.5)
           (* 180.0 (/ (atan (+ t_1 -1.0)) PI))
           (if (<= t_0 0.0)
             (* 180.0 (/ (atan (* B (/ -0.5 (- C A)))) PI))
             (* 180.0 (/ (atan (+ 1.0 t_1)) PI))))))
      double code(double A, double B, double C) {
      	double t_0 = (1.0 / B) * ((C - A) - sqrt((pow((A - C), 2.0) + pow(B, 2.0))));
      	double t_1 = (C - A) / B;
      	double tmp;
      	if (t_0 <= -0.5) {
      		tmp = 180.0 * (atan((t_1 + -1.0)) / ((double) M_PI));
      	} else if (t_0 <= 0.0) {
      		tmp = 180.0 * (atan((B * (-0.5 / (C - A)))) / ((double) M_PI));
      	} else {
      		tmp = 180.0 * (atan((1.0 + t_1)) / ((double) M_PI));
      	}
      	return tmp;
      }
      
      public static double code(double A, double B, double C) {
      	double t_0 = (1.0 / B) * ((C - A) - Math.sqrt((Math.pow((A - C), 2.0) + Math.pow(B, 2.0))));
      	double t_1 = (C - A) / B;
      	double tmp;
      	if (t_0 <= -0.5) {
      		tmp = 180.0 * (Math.atan((t_1 + -1.0)) / Math.PI);
      	} else if (t_0 <= 0.0) {
      		tmp = 180.0 * (Math.atan((B * (-0.5 / (C - A)))) / Math.PI);
      	} else {
      		tmp = 180.0 * (Math.atan((1.0 + t_1)) / Math.PI);
      	}
      	return tmp;
      }
      
      def code(A, B, C):
      	t_0 = (1.0 / B) * ((C - A) - math.sqrt((math.pow((A - C), 2.0) + math.pow(B, 2.0))))
      	t_1 = (C - A) / B
      	tmp = 0
      	if t_0 <= -0.5:
      		tmp = 180.0 * (math.atan((t_1 + -1.0)) / math.pi)
      	elif t_0 <= 0.0:
      		tmp = 180.0 * (math.atan((B * (-0.5 / (C - A)))) / math.pi)
      	else:
      		tmp = 180.0 * (math.atan((1.0 + t_1)) / math.pi)
      	return tmp
      
      function code(A, B, C)
      	t_0 = Float64(Float64(1.0 / B) * Float64(Float64(C - A) - sqrt(Float64((Float64(A - C) ^ 2.0) + (B ^ 2.0)))))
      	t_1 = Float64(Float64(C - A) / B)
      	tmp = 0.0
      	if (t_0 <= -0.5)
      		tmp = Float64(180.0 * Float64(atan(Float64(t_1 + -1.0)) / pi));
      	elseif (t_0 <= 0.0)
      		tmp = Float64(180.0 * Float64(atan(Float64(B * Float64(-0.5 / Float64(C - A)))) / pi));
      	else
      		tmp = Float64(180.0 * Float64(atan(Float64(1.0 + t_1)) / pi));
      	end
      	return tmp
      end
      
      function tmp_2 = code(A, B, C)
      	t_0 = (1.0 / B) * ((C - A) - sqrt((((A - C) ^ 2.0) + (B ^ 2.0))));
      	t_1 = (C - A) / B;
      	tmp = 0.0;
      	if (t_0 <= -0.5)
      		tmp = 180.0 * (atan((t_1 + -1.0)) / pi);
      	elseif (t_0 <= 0.0)
      		tmp = 180.0 * (atan((B * (-0.5 / (C - A)))) / pi);
      	else
      		tmp = 180.0 * (atan((1.0 + t_1)) / pi);
      	end
      	tmp_2 = tmp;
      end
      
      code[A_, B_, C_] := Block[{t$95$0 = N[(N[(1.0 / B), $MachinePrecision] * N[(N[(C - A), $MachinePrecision] - N[Sqrt[N[(N[Power[N[(A - C), $MachinePrecision], 2.0], $MachinePrecision] + N[Power[B, 2.0], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$1 = N[(N[(C - A), $MachinePrecision] / B), $MachinePrecision]}, If[LessEqual[t$95$0, -0.5], N[(180.0 * N[(N[ArcTan[N[(t$95$1 + -1.0), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision], If[LessEqual[t$95$0, 0.0], N[(180.0 * N[(N[ArcTan[N[(B * N[(-0.5 / N[(C - A), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision], N[(180.0 * N[(N[ArcTan[N[(1.0 + t$95$1), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision]]]]]
      
      \begin{array}{l}
      
      \\
      \begin{array}{l}
      t_0 := \frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\\
      t_1 := \frac{C - A}{B}\\
      \mathbf{if}\;t\_0 \leq -0.5:\\
      \;\;\;\;180 \cdot \frac{\tan^{-1} \left(t\_1 + -1\right)}{\pi}\\
      
      \mathbf{elif}\;t\_0 \leq 0:\\
      \;\;\;\;180 \cdot \frac{\tan^{-1} \left(B \cdot \frac{-0.5}{C - A}\right)}{\pi}\\
      
      \mathbf{else}:\\
      \;\;\;\;180 \cdot \frac{\tan^{-1} \left(1 + t\_1\right)}{\pi}\\
      
      
      \end{array}
      \end{array}
      
      Derivation
      1. Split input into 3 regimes
      2. if (*.f64 (/.f64 #s(literal 1 binary64) B) (-.f64 (-.f64 C A) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))) < -0.5

        1. Initial program 63.3%

          \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
        2. Add Preprocessing
        3. Taylor expanded in B around inf

          \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{C}{B} - \left(1 + \frac{A}{B}\right)\right)}}{\mathsf{PI}\left(\right)} \]
        4. Step-by-step derivation
          1. +-commutativeN/A

            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{C}{B} - \color{blue}{\left(\frac{A}{B} + 1\right)}\right)}{\mathsf{PI}\left(\right)} \]
          2. associate--r+N/A

            \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\left(\frac{C}{B} - \frac{A}{B}\right) - 1\right)}}{\mathsf{PI}\left(\right)} \]
          3. div-subN/A

            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\color{blue}{\frac{C - A}{B}} - 1\right)}{\mathsf{PI}\left(\right)} \]
          4. sub-negN/A

            \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{C - A}{B} + \left(\mathsf{neg}\left(1\right)\right)\right)}}{\mathsf{PI}\left(\right)} \]
          5. metadata-evalN/A

            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{C - A}{B} + \color{blue}{-1}\right)}{\mathsf{PI}\left(\right)} \]
          6. lower-+.f64N/A

            \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{C - A}{B} + -1\right)}}{\mathsf{PI}\left(\right)} \]
          7. lower-/.f64N/A

            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\color{blue}{\frac{C - A}{B}} + -1\right)}{\mathsf{PI}\left(\right)} \]
          8. lower--.f6478.4

            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\color{blue}{C - A}}{B} + -1\right)}{\pi} \]
        5. Simplified78.4%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{C - A}{B} + -1\right)}}{\pi} \]

        if -0.5 < (*.f64 (/.f64 #s(literal 1 binary64) B) (-.f64 (-.f64 C A) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))) < 0.0

        1. Initial program 19.1%

          \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
        2. Add Preprocessing
        3. Step-by-step derivation
          1. Applied egg-rr21.4%

            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \color{blue}{\mathsf{hypot}\left(C - A, B\right)}\right)\right)}{\pi} \]
          2. Taylor expanded in B around 0

            \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{-1}{2} \cdot \frac{B}{C - A}\right)}}{\mathsf{PI}\left(\right)} \]
          3. Step-by-step derivation
            1. associate-*r/N/A

              \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{\frac{-1}{2} \cdot B}{C - A}\right)}}{\mathsf{PI}\left(\right)} \]
            2. *-commutativeN/A

              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\color{blue}{B \cdot \frac{-1}{2}}}{C - A}\right)}{\mathsf{PI}\left(\right)} \]
            3. associate-/l*N/A

              \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(B \cdot \frac{\frac{-1}{2}}{C - A}\right)}}{\mathsf{PI}\left(\right)} \]
            4. metadata-evalN/A

              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(B \cdot \frac{\color{blue}{\mathsf{neg}\left(\frac{1}{2}\right)}}{C - A}\right)}{\mathsf{PI}\left(\right)} \]
            5. distribute-neg-fracN/A

              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(B \cdot \color{blue}{\left(\mathsf{neg}\left(\frac{\frac{1}{2}}{C - A}\right)\right)}\right)}{\mathsf{PI}\left(\right)} \]
            6. metadata-evalN/A

              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(B \cdot \left(\mathsf{neg}\left(\frac{\color{blue}{\frac{1}{2} \cdot 1}}{C - A}\right)\right)\right)}{\mathsf{PI}\left(\right)} \]
            7. associate-*r/N/A

              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(B \cdot \left(\mathsf{neg}\left(\color{blue}{\frac{1}{2} \cdot \frac{1}{C - A}}\right)\right)\right)}{\mathsf{PI}\left(\right)} \]
            8. lower-*.f64N/A

              \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(B \cdot \left(\mathsf{neg}\left(\frac{1}{2} \cdot \frac{1}{C - A}\right)\right)\right)}}{\mathsf{PI}\left(\right)} \]
            9. associate-*r/N/A

              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(B \cdot \left(\mathsf{neg}\left(\color{blue}{\frac{\frac{1}{2} \cdot 1}{C - A}}\right)\right)\right)}{\mathsf{PI}\left(\right)} \]
            10. metadata-evalN/A

              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(B \cdot \left(\mathsf{neg}\left(\frac{\color{blue}{\frac{1}{2}}}{C - A}\right)\right)\right)}{\mathsf{PI}\left(\right)} \]
            11. distribute-neg-fracN/A

              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(B \cdot \color{blue}{\frac{\mathsf{neg}\left(\frac{1}{2}\right)}{C - A}}\right)}{\mathsf{PI}\left(\right)} \]
            12. metadata-evalN/A

              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(B \cdot \frac{\color{blue}{\frac{-1}{2}}}{C - A}\right)}{\mathsf{PI}\left(\right)} \]
            13. lower-/.f64N/A

              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(B \cdot \color{blue}{\frac{\frac{-1}{2}}{C - A}}\right)}{\mathsf{PI}\left(\right)} \]
            14. lower--.f6497.2

              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(B \cdot \frac{-0.5}{\color{blue}{C - A}}\right)}{\pi} \]
          4. Simplified97.2%

            \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(B \cdot \frac{-0.5}{C - A}\right)}}{\pi} \]

          if 0.0 < (*.f64 (/.f64 #s(literal 1 binary64) B) (-.f64 (-.f64 C A) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64))))))

          1. Initial program 57.6%

            \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
          2. Add Preprocessing
          3. Taylor expanded in B around -inf

            \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\left(1 + \frac{C}{B}\right) - \frac{A}{B}\right)}}{\mathsf{PI}\left(\right)} \]
          4. Step-by-step derivation
            1. associate--l+N/A

              \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(1 + \left(\frac{C}{B} - \frac{A}{B}\right)\right)}}{\mathsf{PI}\left(\right)} \]
            2. div-subN/A

              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \color{blue}{\frac{C - A}{B}}\right)}{\mathsf{PI}\left(\right)} \]
            3. lower-+.f64N/A

              \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(1 + \frac{C - A}{B}\right)}}{\mathsf{PI}\left(\right)} \]
            4. lower-/.f64N/A

              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \color{blue}{\frac{C - A}{B}}\right)}{\mathsf{PI}\left(\right)} \]
            5. lower--.f6479.1

              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \frac{\color{blue}{C - A}}{B}\right)}{\pi} \]
          5. Simplified79.1%

            \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(1 + \frac{C - A}{B}\right)}}{\pi} \]
        4. Recombined 3 regimes into one program.
        5. Add Preprocessing

        Alternative 6: 73.1% accurate, 0.6× speedup?

        \[\begin{array}{l} \\ \begin{array}{l} t_0 := \frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\\ t_1 := \frac{C - A}{B}\\ \mathbf{if}\;t\_0 \leq -0.5:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(t\_1 + -1\right)}{\pi}\\ \mathbf{elif}\;t\_0 \leq 0:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{B \cdot 0.5}{A}\right)}{\pi}\\ \mathbf{else}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(1 + t\_1\right)}{\pi}\\ \end{array} \end{array} \]
        (FPCore (A B C)
         :precision binary64
         (let* ((t_0
                 (* (/ 1.0 B) (- (- C A) (sqrt (+ (pow (- A C) 2.0) (pow B 2.0))))))
                (t_1 (/ (- C A) B)))
           (if (<= t_0 -0.5)
             (* 180.0 (/ (atan (+ t_1 -1.0)) PI))
             (if (<= t_0 0.0)
               (* 180.0 (/ (atan (/ (* B 0.5) A)) PI))
               (* 180.0 (/ (atan (+ 1.0 t_1)) PI))))))
        double code(double A, double B, double C) {
        	double t_0 = (1.0 / B) * ((C - A) - sqrt((pow((A - C), 2.0) + pow(B, 2.0))));
        	double t_1 = (C - A) / B;
        	double tmp;
        	if (t_0 <= -0.5) {
        		tmp = 180.0 * (atan((t_1 + -1.0)) / ((double) M_PI));
        	} else if (t_0 <= 0.0) {
        		tmp = 180.0 * (atan(((B * 0.5) / A)) / ((double) M_PI));
        	} else {
        		tmp = 180.0 * (atan((1.0 + t_1)) / ((double) M_PI));
        	}
        	return tmp;
        }
        
        public static double code(double A, double B, double C) {
        	double t_0 = (1.0 / B) * ((C - A) - Math.sqrt((Math.pow((A - C), 2.0) + Math.pow(B, 2.0))));
        	double t_1 = (C - A) / B;
        	double tmp;
        	if (t_0 <= -0.5) {
        		tmp = 180.0 * (Math.atan((t_1 + -1.0)) / Math.PI);
        	} else if (t_0 <= 0.0) {
        		tmp = 180.0 * (Math.atan(((B * 0.5) / A)) / Math.PI);
        	} else {
        		tmp = 180.0 * (Math.atan((1.0 + t_1)) / Math.PI);
        	}
        	return tmp;
        }
        
        def code(A, B, C):
        	t_0 = (1.0 / B) * ((C - A) - math.sqrt((math.pow((A - C), 2.0) + math.pow(B, 2.0))))
        	t_1 = (C - A) / B
        	tmp = 0
        	if t_0 <= -0.5:
        		tmp = 180.0 * (math.atan((t_1 + -1.0)) / math.pi)
        	elif t_0 <= 0.0:
        		tmp = 180.0 * (math.atan(((B * 0.5) / A)) / math.pi)
        	else:
        		tmp = 180.0 * (math.atan((1.0 + t_1)) / math.pi)
        	return tmp
        
        function code(A, B, C)
        	t_0 = Float64(Float64(1.0 / B) * Float64(Float64(C - A) - sqrt(Float64((Float64(A - C) ^ 2.0) + (B ^ 2.0)))))
        	t_1 = Float64(Float64(C - A) / B)
        	tmp = 0.0
        	if (t_0 <= -0.5)
        		tmp = Float64(180.0 * Float64(atan(Float64(t_1 + -1.0)) / pi));
        	elseif (t_0 <= 0.0)
        		tmp = Float64(180.0 * Float64(atan(Float64(Float64(B * 0.5) / A)) / pi));
        	else
        		tmp = Float64(180.0 * Float64(atan(Float64(1.0 + t_1)) / pi));
        	end
        	return tmp
        end
        
        function tmp_2 = code(A, B, C)
        	t_0 = (1.0 / B) * ((C - A) - sqrt((((A - C) ^ 2.0) + (B ^ 2.0))));
        	t_1 = (C - A) / B;
        	tmp = 0.0;
        	if (t_0 <= -0.5)
        		tmp = 180.0 * (atan((t_1 + -1.0)) / pi);
        	elseif (t_0 <= 0.0)
        		tmp = 180.0 * (atan(((B * 0.5) / A)) / pi);
        	else
        		tmp = 180.0 * (atan((1.0 + t_1)) / pi);
        	end
        	tmp_2 = tmp;
        end
        
        code[A_, B_, C_] := Block[{t$95$0 = N[(N[(1.0 / B), $MachinePrecision] * N[(N[(C - A), $MachinePrecision] - N[Sqrt[N[(N[Power[N[(A - C), $MachinePrecision], 2.0], $MachinePrecision] + N[Power[B, 2.0], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$1 = N[(N[(C - A), $MachinePrecision] / B), $MachinePrecision]}, If[LessEqual[t$95$0, -0.5], N[(180.0 * N[(N[ArcTan[N[(t$95$1 + -1.0), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision], If[LessEqual[t$95$0, 0.0], N[(180.0 * N[(N[ArcTan[N[(N[(B * 0.5), $MachinePrecision] / A), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision], N[(180.0 * N[(N[ArcTan[N[(1.0 + t$95$1), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision]]]]]
        
        \begin{array}{l}
        
        \\
        \begin{array}{l}
        t_0 := \frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\\
        t_1 := \frac{C - A}{B}\\
        \mathbf{if}\;t\_0 \leq -0.5:\\
        \;\;\;\;180 \cdot \frac{\tan^{-1} \left(t\_1 + -1\right)}{\pi}\\
        
        \mathbf{elif}\;t\_0 \leq 0:\\
        \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{B \cdot 0.5}{A}\right)}{\pi}\\
        
        \mathbf{else}:\\
        \;\;\;\;180 \cdot \frac{\tan^{-1} \left(1 + t\_1\right)}{\pi}\\
        
        
        \end{array}
        \end{array}
        
        Derivation
        1. Split input into 3 regimes
        2. if (*.f64 (/.f64 #s(literal 1 binary64) B) (-.f64 (-.f64 C A) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))) < -0.5

          1. Initial program 63.3%

            \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
          2. Add Preprocessing
          3. Taylor expanded in B around inf

            \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{C}{B} - \left(1 + \frac{A}{B}\right)\right)}}{\mathsf{PI}\left(\right)} \]
          4. Step-by-step derivation
            1. +-commutativeN/A

              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{C}{B} - \color{blue}{\left(\frac{A}{B} + 1\right)}\right)}{\mathsf{PI}\left(\right)} \]
            2. associate--r+N/A

              \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\left(\frac{C}{B} - \frac{A}{B}\right) - 1\right)}}{\mathsf{PI}\left(\right)} \]
            3. div-subN/A

              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\color{blue}{\frac{C - A}{B}} - 1\right)}{\mathsf{PI}\left(\right)} \]
            4. sub-negN/A

              \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{C - A}{B} + \left(\mathsf{neg}\left(1\right)\right)\right)}}{\mathsf{PI}\left(\right)} \]
            5. metadata-evalN/A

              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{C - A}{B} + \color{blue}{-1}\right)}{\mathsf{PI}\left(\right)} \]
            6. lower-+.f64N/A

              \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{C - A}{B} + -1\right)}}{\mathsf{PI}\left(\right)} \]
            7. lower-/.f64N/A

              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\color{blue}{\frac{C - A}{B}} + -1\right)}{\mathsf{PI}\left(\right)} \]
            8. lower--.f6478.4

              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\color{blue}{C - A}}{B} + -1\right)}{\pi} \]
          5. Simplified78.4%

            \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{C - A}{B} + -1\right)}}{\pi} \]

          if -0.5 < (*.f64 (/.f64 #s(literal 1 binary64) B) (-.f64 (-.f64 C A) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))) < 0.0

          1. Initial program 19.1%

            \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
          2. Add Preprocessing
          3. Taylor expanded in A around -inf

            \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{1}{2} \cdot \frac{B}{A}\right)}}{\mathsf{PI}\left(\right)} \]
          4. Step-by-step derivation
            1. associate-*r/N/A

              \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{\frac{1}{2} \cdot B}{A}\right)}}{\mathsf{PI}\left(\right)} \]
            2. lower-/.f64N/A

              \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{\frac{1}{2} \cdot B}{A}\right)}}{\mathsf{PI}\left(\right)} \]
            3. *-commutativeN/A

              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\color{blue}{B \cdot \frac{1}{2}}}{A}\right)}{\mathsf{PI}\left(\right)} \]
            4. lower-*.f6453.2

              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\color{blue}{B \cdot 0.5}}{A}\right)}{\pi} \]
          5. Simplified53.2%

            \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{B \cdot 0.5}{A}\right)}}{\pi} \]

          if 0.0 < (*.f64 (/.f64 #s(literal 1 binary64) B) (-.f64 (-.f64 C A) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64))))))

          1. Initial program 57.6%

            \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
          2. Add Preprocessing
          3. Taylor expanded in B around -inf

            \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\left(1 + \frac{C}{B}\right) - \frac{A}{B}\right)}}{\mathsf{PI}\left(\right)} \]
          4. Step-by-step derivation
            1. associate--l+N/A

              \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(1 + \left(\frac{C}{B} - \frac{A}{B}\right)\right)}}{\mathsf{PI}\left(\right)} \]
            2. div-subN/A

              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \color{blue}{\frac{C - A}{B}}\right)}{\mathsf{PI}\left(\right)} \]
            3. lower-+.f64N/A

              \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(1 + \frac{C - A}{B}\right)}}{\mathsf{PI}\left(\right)} \]
            4. lower-/.f64N/A

              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \color{blue}{\frac{C - A}{B}}\right)}{\mathsf{PI}\left(\right)} \]
            5. lower--.f6479.1

              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \frac{\color{blue}{C - A}}{B}\right)}{\pi} \]
          5. Simplified79.1%

            \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(1 + \frac{C - A}{B}\right)}}{\pi} \]
        3. Recombined 3 regimes into one program.
        4. Add Preprocessing

        Alternative 7: 56.8% accurate, 2.5× speedup?

        \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;B \leq -4.6 \cdot 10^{-36}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(1 - \frac{A}{B}\right)}{\pi}\\ \mathbf{elif}\;B \leq 1.7 \cdot 10^{-216}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(1 + \frac{C}{B}\right)}{\pi}\\ \mathbf{else}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(-1 - \frac{A}{B}\right)}{\pi}\\ \end{array} \end{array} \]
        (FPCore (A B C)
         :precision binary64
         (if (<= B -4.6e-36)
           (* 180.0 (/ (atan (- 1.0 (/ A B))) PI))
           (if (<= B 1.7e-216)
             (* 180.0 (/ (atan (+ 1.0 (/ C B))) PI))
             (* 180.0 (/ (atan (- -1.0 (/ A B))) PI)))))
        double code(double A, double B, double C) {
        	double tmp;
        	if (B <= -4.6e-36) {
        		tmp = 180.0 * (atan((1.0 - (A / B))) / ((double) M_PI));
        	} else if (B <= 1.7e-216) {
        		tmp = 180.0 * (atan((1.0 + (C / B))) / ((double) M_PI));
        	} else {
        		tmp = 180.0 * (atan((-1.0 - (A / B))) / ((double) M_PI));
        	}
        	return tmp;
        }
        
        public static double code(double A, double B, double C) {
        	double tmp;
        	if (B <= -4.6e-36) {
        		tmp = 180.0 * (Math.atan((1.0 - (A / B))) / Math.PI);
        	} else if (B <= 1.7e-216) {
        		tmp = 180.0 * (Math.atan((1.0 + (C / B))) / Math.PI);
        	} else {
        		tmp = 180.0 * (Math.atan((-1.0 - (A / B))) / Math.PI);
        	}
        	return tmp;
        }
        
        def code(A, B, C):
        	tmp = 0
        	if B <= -4.6e-36:
        		tmp = 180.0 * (math.atan((1.0 - (A / B))) / math.pi)
        	elif B <= 1.7e-216:
        		tmp = 180.0 * (math.atan((1.0 + (C / B))) / math.pi)
        	else:
        		tmp = 180.0 * (math.atan((-1.0 - (A / B))) / math.pi)
        	return tmp
        
        function code(A, B, C)
        	tmp = 0.0
        	if (B <= -4.6e-36)
        		tmp = Float64(180.0 * Float64(atan(Float64(1.0 - Float64(A / B))) / pi));
        	elseif (B <= 1.7e-216)
        		tmp = Float64(180.0 * Float64(atan(Float64(1.0 + Float64(C / B))) / pi));
        	else
        		tmp = Float64(180.0 * Float64(atan(Float64(-1.0 - Float64(A / B))) / pi));
        	end
        	return tmp
        end
        
        function tmp_2 = code(A, B, C)
        	tmp = 0.0;
        	if (B <= -4.6e-36)
        		tmp = 180.0 * (atan((1.0 - (A / B))) / pi);
        	elseif (B <= 1.7e-216)
        		tmp = 180.0 * (atan((1.0 + (C / B))) / pi);
        	else
        		tmp = 180.0 * (atan((-1.0 - (A / B))) / pi);
        	end
        	tmp_2 = tmp;
        end
        
        code[A_, B_, C_] := If[LessEqual[B, -4.6e-36], N[(180.0 * N[(N[ArcTan[N[(1.0 - N[(A / B), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision], If[LessEqual[B, 1.7e-216], N[(180.0 * N[(N[ArcTan[N[(1.0 + N[(C / B), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision], N[(180.0 * N[(N[ArcTan[N[(-1.0 - N[(A / B), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision]]]
        
        \begin{array}{l}
        
        \\
        \begin{array}{l}
        \mathbf{if}\;B \leq -4.6 \cdot 10^{-36}:\\
        \;\;\;\;180 \cdot \frac{\tan^{-1} \left(1 - \frac{A}{B}\right)}{\pi}\\
        
        \mathbf{elif}\;B \leq 1.7 \cdot 10^{-216}:\\
        \;\;\;\;180 \cdot \frac{\tan^{-1} \left(1 + \frac{C}{B}\right)}{\pi}\\
        
        \mathbf{else}:\\
        \;\;\;\;180 \cdot \frac{\tan^{-1} \left(-1 - \frac{A}{B}\right)}{\pi}\\
        
        
        \end{array}
        \end{array}
        
        Derivation
        1. Split input into 3 regimes
        2. if B < -4.59999999999999993e-36

          1. Initial program 41.6%

            \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
          2. Add Preprocessing
          3. Taylor expanded in B around -inf

            \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\left(1 + \frac{C}{B}\right) - \frac{A}{B}\right)}}{\mathsf{PI}\left(\right)} \]
          4. Step-by-step derivation
            1. associate--l+N/A

              \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(1 + \left(\frac{C}{B} - \frac{A}{B}\right)\right)}}{\mathsf{PI}\left(\right)} \]
            2. div-subN/A

              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \color{blue}{\frac{C - A}{B}}\right)}{\mathsf{PI}\left(\right)} \]
            3. lower-+.f64N/A

              \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(1 + \frac{C - A}{B}\right)}}{\mathsf{PI}\left(\right)} \]
            4. lower-/.f64N/A

              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \color{blue}{\frac{C - A}{B}}\right)}{\mathsf{PI}\left(\right)} \]
            5. lower--.f6475.3

              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \frac{\color{blue}{C - A}}{B}\right)}{\pi} \]
          5. Simplified75.3%

            \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(1 + \frac{C - A}{B}\right)}}{\pi} \]
          6. Taylor expanded in C around 0

            \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(1 - \frac{A}{B}\right)}}{\mathsf{PI}\left(\right)} \]
          7. Step-by-step derivation
            1. lower--.f64N/A

              \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(1 - \frac{A}{B}\right)}}{\mathsf{PI}\left(\right)} \]
            2. lower-/.f6473.5

              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 - \color{blue}{\frac{A}{B}}\right)}{\pi} \]
          8. Simplified73.5%

            \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(1 - \frac{A}{B}\right)}}{\pi} \]

          if -4.59999999999999993e-36 < B < 1.6999999999999999e-216

          1. Initial program 63.4%

            \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
          2. Add Preprocessing
          3. Taylor expanded in B around -inf

            \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\left(1 + \frac{C}{B}\right) - \frac{A}{B}\right)}}{\mathsf{PI}\left(\right)} \]
          4. Step-by-step derivation
            1. associate--l+N/A

              \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(1 + \left(\frac{C}{B} - \frac{A}{B}\right)\right)}}{\mathsf{PI}\left(\right)} \]
            2. div-subN/A

              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \color{blue}{\frac{C - A}{B}}\right)}{\mathsf{PI}\left(\right)} \]
            3. lower-+.f64N/A

              \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(1 + \frac{C - A}{B}\right)}}{\mathsf{PI}\left(\right)} \]
            4. lower-/.f64N/A

              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \color{blue}{\frac{C - A}{B}}\right)}{\mathsf{PI}\left(\right)} \]
            5. lower--.f6457.4

              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \frac{\color{blue}{C - A}}{B}\right)}{\pi} \]
          5. Simplified57.4%

            \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(1 + \frac{C - A}{B}\right)}}{\pi} \]
          6. Taylor expanded in A around 0

            \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(1 + \frac{C}{B}\right)}}{\mathsf{PI}\left(\right)} \]
          7. Step-by-step derivation
            1. lower-+.f64N/A

              \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(1 + \frac{C}{B}\right)}}{\mathsf{PI}\left(\right)} \]
            2. lower-/.f6449.1

              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \color{blue}{\frac{C}{B}}\right)}{\pi} \]
          8. Simplified49.1%

            \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(1 + \frac{C}{B}\right)}}{\pi} \]

          if 1.6999999999999999e-216 < B

          1. Initial program 53.8%

            \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
          2. Add Preprocessing
          3. Step-by-step derivation
            1. lift--.f64N/A

              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\color{blue}{\left(C - A\right)} - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\mathsf{PI}\left(\right)} \]
            2. lift--.f64N/A

              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\color{blue}{\left(A - C\right)}}^{2} + {B}^{2}}\right)\right)}{\mathsf{PI}\left(\right)} \]
            3. lift-pow.f64N/A

              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{\color{blue}{{\left(A - C\right)}^{2}} + {B}^{2}}\right)\right)}{\mathsf{PI}\left(\right)} \]
            4. lift-pow.f64N/A

              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + \color{blue}{{B}^{2}}}\right)\right)}{\mathsf{PI}\left(\right)} \]
            5. lift-+.f64N/A

              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{\color{blue}{{\left(A - C\right)}^{2} + {B}^{2}}}\right)\right)}{\mathsf{PI}\left(\right)} \]
            6. lift-sqrt.f64N/A

              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \color{blue}{\sqrt{{\left(A - C\right)}^{2} + {B}^{2}}}\right)\right)}{\mathsf{PI}\left(\right)} \]
            7. lift--.f64N/A

              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \color{blue}{\left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}\right)}{\mathsf{PI}\left(\right)} \]
            8. associate-*l/N/A

              \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{1 \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}{B}\right)}}{\mathsf{PI}\left(\right)} \]
            9. *-lft-identityN/A

              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\color{blue}{\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}}}{B}\right)}{\mathsf{PI}\left(\right)} \]
            10. lift--.f64N/A

              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\color{blue}{\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}}}{B}\right)}{\mathsf{PI}\left(\right)} \]
            11. div-subN/A

              \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{C - A}{B} - \frac{\sqrt{{\left(A - C\right)}^{2} + {B}^{2}}}{B}\right)}}{\mathsf{PI}\left(\right)} \]
            12. un-div-invN/A

              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\color{blue}{\left(C - A\right) \cdot \frac{1}{B}} - \frac{\sqrt{{\left(A - C\right)}^{2} + {B}^{2}}}{B}\right)}{\mathsf{PI}\left(\right)} \]
            13. lift-/.f64N/A

              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\left(C - A\right) \cdot \color{blue}{\frac{1}{B}} - \frac{\sqrt{{\left(A - C\right)}^{2} + {B}^{2}}}{B}\right)}{\mathsf{PI}\left(\right)} \]
            14. lower--.f64N/A

              \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\left(C - A\right) \cdot \frac{1}{B} - \frac{\sqrt{{\left(A - C\right)}^{2} + {B}^{2}}}{B}\right)}}{\mathsf{PI}\left(\right)} \]
          4. Applied egg-rr52.7%

            \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{C - A}{B} - \frac{\sqrt{\mathsf{fma}\left(A - C, A - C, B \cdot B\right)}}{B}\right)}}{\pi} \]
          5. Taylor expanded in A around 0

            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{C - A}{B} - \frac{\color{blue}{\sqrt{{B}^{2} + {C}^{2}}}}{B}\right)}{\mathsf{PI}\left(\right)} \]
          6. Step-by-step derivation
            1. lower-sqrt.f64N/A

              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{C - A}{B} - \frac{\color{blue}{\sqrt{{B}^{2} + {C}^{2}}}}{B}\right)}{\mathsf{PI}\left(\right)} \]
            2. unpow2N/A

              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{C - A}{B} - \frac{\sqrt{\color{blue}{B \cdot B} + {C}^{2}}}{B}\right)}{\mathsf{PI}\left(\right)} \]
            3. lower-fma.f64N/A

              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{C - A}{B} - \frac{\sqrt{\color{blue}{\mathsf{fma}\left(B, B, {C}^{2}\right)}}}{B}\right)}{\mathsf{PI}\left(\right)} \]
            4. unpow2N/A

              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{C - A}{B} - \frac{\sqrt{\mathsf{fma}\left(B, B, \color{blue}{C \cdot C}\right)}}{B}\right)}{\mathsf{PI}\left(\right)} \]
            5. lower-*.f6452.2

              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{C - A}{B} - \frac{\sqrt{\mathsf{fma}\left(B, B, \color{blue}{C \cdot C}\right)}}{B}\right)}{\pi} \]
          7. Simplified52.2%

            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{C - A}{B} - \frac{\color{blue}{\sqrt{\mathsf{fma}\left(B, B, C \cdot C\right)}}}{B}\right)}{\pi} \]
          8. Taylor expanded in C around 0

            \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(-1 \cdot \left(1 + \frac{A}{B}\right)\right)}}{\mathsf{PI}\left(\right)} \]
          9. Step-by-step derivation
            1. distribute-lft-inN/A

              \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(-1 \cdot 1 + -1 \cdot \frac{A}{B}\right)}}{\mathsf{PI}\left(\right)} \]
            2. metadata-evalN/A

              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\color{blue}{-1} + -1 \cdot \frac{A}{B}\right)}{\mathsf{PI}\left(\right)} \]
            3. mul-1-negN/A

              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(-1 + \color{blue}{\left(\mathsf{neg}\left(\frac{A}{B}\right)\right)}\right)}{\mathsf{PI}\left(\right)} \]
            4. unsub-negN/A

              \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(-1 - \frac{A}{B}\right)}}{\mathsf{PI}\left(\right)} \]
            5. lower--.f64N/A

              \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(-1 - \frac{A}{B}\right)}}{\mathsf{PI}\left(\right)} \]
            6. lower-/.f6461.7

              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(-1 - \color{blue}{\frac{A}{B}}\right)}{\pi} \]
          10. Simplified61.7%

            \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(-1 - \frac{A}{B}\right)}}{\pi} \]
        3. Recombined 3 regimes into one program.
        4. Add Preprocessing

        Alternative 8: 47.9% accurate, 2.5× speedup?

        \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;B \leq -4.8 \cdot 10^{-53}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} 1}{\pi}\\ \mathbf{elif}\;B \leq 5.7 \cdot 10^{-92}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{C}{B}\right)}{\pi}\\ \mathbf{else}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} -1}{\pi}\\ \end{array} \end{array} \]
        (FPCore (A B C)
         :precision binary64
         (if (<= B -4.8e-53)
           (* 180.0 (/ (atan 1.0) PI))
           (if (<= B 5.7e-92)
             (* 180.0 (/ (atan (/ C B)) PI))
             (* 180.0 (/ (atan -1.0) PI)))))
        double code(double A, double B, double C) {
        	double tmp;
        	if (B <= -4.8e-53) {
        		tmp = 180.0 * (atan(1.0) / ((double) M_PI));
        	} else if (B <= 5.7e-92) {
        		tmp = 180.0 * (atan((C / B)) / ((double) M_PI));
        	} else {
        		tmp = 180.0 * (atan(-1.0) / ((double) M_PI));
        	}
        	return tmp;
        }
        
        public static double code(double A, double B, double C) {
        	double tmp;
        	if (B <= -4.8e-53) {
        		tmp = 180.0 * (Math.atan(1.0) / Math.PI);
        	} else if (B <= 5.7e-92) {
        		tmp = 180.0 * (Math.atan((C / B)) / Math.PI);
        	} else {
        		tmp = 180.0 * (Math.atan(-1.0) / Math.PI);
        	}
        	return tmp;
        }
        
        def code(A, B, C):
        	tmp = 0
        	if B <= -4.8e-53:
        		tmp = 180.0 * (math.atan(1.0) / math.pi)
        	elif B <= 5.7e-92:
        		tmp = 180.0 * (math.atan((C / B)) / math.pi)
        	else:
        		tmp = 180.0 * (math.atan(-1.0) / math.pi)
        	return tmp
        
        function code(A, B, C)
        	tmp = 0.0
        	if (B <= -4.8e-53)
        		tmp = Float64(180.0 * Float64(atan(1.0) / pi));
        	elseif (B <= 5.7e-92)
        		tmp = Float64(180.0 * Float64(atan(Float64(C / B)) / pi));
        	else
        		tmp = Float64(180.0 * Float64(atan(-1.0) / pi));
        	end
        	return tmp
        end
        
        function tmp_2 = code(A, B, C)
        	tmp = 0.0;
        	if (B <= -4.8e-53)
        		tmp = 180.0 * (atan(1.0) / pi);
        	elseif (B <= 5.7e-92)
        		tmp = 180.0 * (atan((C / B)) / pi);
        	else
        		tmp = 180.0 * (atan(-1.0) / pi);
        	end
        	tmp_2 = tmp;
        end
        
        code[A_, B_, C_] := If[LessEqual[B, -4.8e-53], N[(180.0 * N[(N[ArcTan[1.0], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision], If[LessEqual[B, 5.7e-92], N[(180.0 * N[(N[ArcTan[N[(C / B), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision], N[(180.0 * N[(N[ArcTan[-1.0], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision]]]
        
        \begin{array}{l}
        
        \\
        \begin{array}{l}
        \mathbf{if}\;B \leq -4.8 \cdot 10^{-53}:\\
        \;\;\;\;180 \cdot \frac{\tan^{-1} 1}{\pi}\\
        
        \mathbf{elif}\;B \leq 5.7 \cdot 10^{-92}:\\
        \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{C}{B}\right)}{\pi}\\
        
        \mathbf{else}:\\
        \;\;\;\;180 \cdot \frac{\tan^{-1} -1}{\pi}\\
        
        
        \end{array}
        \end{array}
        
        Derivation
        1. Split input into 3 regimes
        2. if B < -4.80000000000000015e-53

          1. Initial program 41.7%

            \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
          2. Add Preprocessing
          3. Taylor expanded in B around -inf

            \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{1}}{\mathsf{PI}\left(\right)} \]
          4. Step-by-step derivation
            1. Simplified59.1%

              \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{1}}{\pi} \]

            if -4.80000000000000015e-53 < B < 5.70000000000000009e-92

            1. Initial program 62.8%

              \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
            2. Add Preprocessing
            3. Taylor expanded in B around -inf

              \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\left(1 + \frac{C}{B}\right) - \frac{A}{B}\right)}}{\mathsf{PI}\left(\right)} \]
            4. Step-by-step derivation
              1. associate--l+N/A

                \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(1 + \left(\frac{C}{B} - \frac{A}{B}\right)\right)}}{\mathsf{PI}\left(\right)} \]
              2. div-subN/A

                \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \color{blue}{\frac{C - A}{B}}\right)}{\mathsf{PI}\left(\right)} \]
              3. lower-+.f64N/A

                \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(1 + \frac{C - A}{B}\right)}}{\mathsf{PI}\left(\right)} \]
              4. lower-/.f64N/A

                \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \color{blue}{\frac{C - A}{B}}\right)}{\mathsf{PI}\left(\right)} \]
              5. lower--.f6456.4

                \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \frac{\color{blue}{C - A}}{B}\right)}{\pi} \]
            5. Simplified56.4%

              \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(1 + \frac{C - A}{B}\right)}}{\pi} \]
            6. Taylor expanded in C around inf

              \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{C}{B}\right)}}{\mathsf{PI}\left(\right)} \]
            7. Step-by-step derivation
              1. lower-/.f6439.7

                \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{C}{B}\right)}}{\pi} \]
            8. Simplified39.7%

              \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{C}{B}\right)}}{\pi} \]

            if 5.70000000000000009e-92 < B

            1. Initial program 51.8%

              \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
            2. Add Preprocessing
            3. Taylor expanded in B around inf

              \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{-1}}{\mathsf{PI}\left(\right)} \]
            4. Step-by-step derivation
              1. Simplified58.7%

                \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{-1}}{\pi} \]
            5. Recombined 3 regimes into one program.
            6. Add Preprocessing

            Alternative 9: 56.5% accurate, 2.6× speedup?

            \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;B \leq 1.7 \cdot 10^{-216}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(1 + \frac{C}{B}\right)}{\pi}\\ \mathbf{else}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(-1 - \frac{A}{B}\right)}{\pi}\\ \end{array} \end{array} \]
            (FPCore (A B C)
             :precision binary64
             (if (<= B 1.7e-216)
               (* 180.0 (/ (atan (+ 1.0 (/ C B))) PI))
               (* 180.0 (/ (atan (- -1.0 (/ A B))) PI))))
            double code(double A, double B, double C) {
            	double tmp;
            	if (B <= 1.7e-216) {
            		tmp = 180.0 * (atan((1.0 + (C / B))) / ((double) M_PI));
            	} else {
            		tmp = 180.0 * (atan((-1.0 - (A / B))) / ((double) M_PI));
            	}
            	return tmp;
            }
            
            public static double code(double A, double B, double C) {
            	double tmp;
            	if (B <= 1.7e-216) {
            		tmp = 180.0 * (Math.atan((1.0 + (C / B))) / Math.PI);
            	} else {
            		tmp = 180.0 * (Math.atan((-1.0 - (A / B))) / Math.PI);
            	}
            	return tmp;
            }
            
            def code(A, B, C):
            	tmp = 0
            	if B <= 1.7e-216:
            		tmp = 180.0 * (math.atan((1.0 + (C / B))) / math.pi)
            	else:
            		tmp = 180.0 * (math.atan((-1.0 - (A / B))) / math.pi)
            	return tmp
            
            function code(A, B, C)
            	tmp = 0.0
            	if (B <= 1.7e-216)
            		tmp = Float64(180.0 * Float64(atan(Float64(1.0 + Float64(C / B))) / pi));
            	else
            		tmp = Float64(180.0 * Float64(atan(Float64(-1.0 - Float64(A / B))) / pi));
            	end
            	return tmp
            end
            
            function tmp_2 = code(A, B, C)
            	tmp = 0.0;
            	if (B <= 1.7e-216)
            		tmp = 180.0 * (atan((1.0 + (C / B))) / pi);
            	else
            		tmp = 180.0 * (atan((-1.0 - (A / B))) / pi);
            	end
            	tmp_2 = tmp;
            end
            
            code[A_, B_, C_] := If[LessEqual[B, 1.7e-216], N[(180.0 * N[(N[ArcTan[N[(1.0 + N[(C / B), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision], N[(180.0 * N[(N[ArcTan[N[(-1.0 - N[(A / B), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision]]
            
            \begin{array}{l}
            
            \\
            \begin{array}{l}
            \mathbf{if}\;B \leq 1.7 \cdot 10^{-216}:\\
            \;\;\;\;180 \cdot \frac{\tan^{-1} \left(1 + \frac{C}{B}\right)}{\pi}\\
            
            \mathbf{else}:\\
            \;\;\;\;180 \cdot \frac{\tan^{-1} \left(-1 - \frac{A}{B}\right)}{\pi}\\
            
            
            \end{array}
            \end{array}
            
            Derivation
            1. Split input into 2 regimes
            2. if B < 1.6999999999999999e-216

              1. Initial program 53.1%

                \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
              2. Add Preprocessing
              3. Taylor expanded in B around -inf

                \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\left(1 + \frac{C}{B}\right) - \frac{A}{B}\right)}}{\mathsf{PI}\left(\right)} \]
              4. Step-by-step derivation
                1. associate--l+N/A

                  \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(1 + \left(\frac{C}{B} - \frac{A}{B}\right)\right)}}{\mathsf{PI}\left(\right)} \]
                2. div-subN/A

                  \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \color{blue}{\frac{C - A}{B}}\right)}{\mathsf{PI}\left(\right)} \]
                3. lower-+.f64N/A

                  \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(1 + \frac{C - A}{B}\right)}}{\mathsf{PI}\left(\right)} \]
                4. lower-/.f64N/A

                  \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \color{blue}{\frac{C - A}{B}}\right)}{\mathsf{PI}\left(\right)} \]
                5. lower--.f6465.9

                  \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \frac{\color{blue}{C - A}}{B}\right)}{\pi} \]
              5. Simplified65.9%

                \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(1 + \frac{C - A}{B}\right)}}{\pi} \]
              6. Taylor expanded in A around 0

                \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(1 + \frac{C}{B}\right)}}{\mathsf{PI}\left(\right)} \]
              7. Step-by-step derivation
                1. lower-+.f64N/A

                  \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(1 + \frac{C}{B}\right)}}{\mathsf{PI}\left(\right)} \]
                2. lower-/.f6456.1

                  \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \color{blue}{\frac{C}{B}}\right)}{\pi} \]
              8. Simplified56.1%

                \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(1 + \frac{C}{B}\right)}}{\pi} \]

              if 1.6999999999999999e-216 < B

              1. Initial program 53.8%

                \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
              2. Add Preprocessing
              3. Step-by-step derivation
                1. lift--.f64N/A

                  \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\color{blue}{\left(C - A\right)} - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\mathsf{PI}\left(\right)} \]
                2. lift--.f64N/A

                  \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\color{blue}{\left(A - C\right)}}^{2} + {B}^{2}}\right)\right)}{\mathsf{PI}\left(\right)} \]
                3. lift-pow.f64N/A

                  \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{\color{blue}{{\left(A - C\right)}^{2}} + {B}^{2}}\right)\right)}{\mathsf{PI}\left(\right)} \]
                4. lift-pow.f64N/A

                  \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + \color{blue}{{B}^{2}}}\right)\right)}{\mathsf{PI}\left(\right)} \]
                5. lift-+.f64N/A

                  \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{\color{blue}{{\left(A - C\right)}^{2} + {B}^{2}}}\right)\right)}{\mathsf{PI}\left(\right)} \]
                6. lift-sqrt.f64N/A

                  \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \color{blue}{\sqrt{{\left(A - C\right)}^{2} + {B}^{2}}}\right)\right)}{\mathsf{PI}\left(\right)} \]
                7. lift--.f64N/A

                  \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \color{blue}{\left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}\right)}{\mathsf{PI}\left(\right)} \]
                8. associate-*l/N/A

                  \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{1 \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}{B}\right)}}{\mathsf{PI}\left(\right)} \]
                9. *-lft-identityN/A

                  \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\color{blue}{\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}}}{B}\right)}{\mathsf{PI}\left(\right)} \]
                10. lift--.f64N/A

                  \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\color{blue}{\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}}}{B}\right)}{\mathsf{PI}\left(\right)} \]
                11. div-subN/A

                  \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{C - A}{B} - \frac{\sqrt{{\left(A - C\right)}^{2} + {B}^{2}}}{B}\right)}}{\mathsf{PI}\left(\right)} \]
                12. un-div-invN/A

                  \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\color{blue}{\left(C - A\right) \cdot \frac{1}{B}} - \frac{\sqrt{{\left(A - C\right)}^{2} + {B}^{2}}}{B}\right)}{\mathsf{PI}\left(\right)} \]
                13. lift-/.f64N/A

                  \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\left(C - A\right) \cdot \color{blue}{\frac{1}{B}} - \frac{\sqrt{{\left(A - C\right)}^{2} + {B}^{2}}}{B}\right)}{\mathsf{PI}\left(\right)} \]
                14. lower--.f64N/A

                  \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\left(C - A\right) \cdot \frac{1}{B} - \frac{\sqrt{{\left(A - C\right)}^{2} + {B}^{2}}}{B}\right)}}{\mathsf{PI}\left(\right)} \]
              4. Applied egg-rr52.7%

                \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{C - A}{B} - \frac{\sqrt{\mathsf{fma}\left(A - C, A - C, B \cdot B\right)}}{B}\right)}}{\pi} \]
              5. Taylor expanded in A around 0

                \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{C - A}{B} - \frac{\color{blue}{\sqrt{{B}^{2} + {C}^{2}}}}{B}\right)}{\mathsf{PI}\left(\right)} \]
              6. Step-by-step derivation
                1. lower-sqrt.f64N/A

                  \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{C - A}{B} - \frac{\color{blue}{\sqrt{{B}^{2} + {C}^{2}}}}{B}\right)}{\mathsf{PI}\left(\right)} \]
                2. unpow2N/A

                  \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{C - A}{B} - \frac{\sqrt{\color{blue}{B \cdot B} + {C}^{2}}}{B}\right)}{\mathsf{PI}\left(\right)} \]
                3. lower-fma.f64N/A

                  \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{C - A}{B} - \frac{\sqrt{\color{blue}{\mathsf{fma}\left(B, B, {C}^{2}\right)}}}{B}\right)}{\mathsf{PI}\left(\right)} \]
                4. unpow2N/A

                  \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{C - A}{B} - \frac{\sqrt{\mathsf{fma}\left(B, B, \color{blue}{C \cdot C}\right)}}{B}\right)}{\mathsf{PI}\left(\right)} \]
                5. lower-*.f6452.2

                  \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{C - A}{B} - \frac{\sqrt{\mathsf{fma}\left(B, B, \color{blue}{C \cdot C}\right)}}{B}\right)}{\pi} \]
              7. Simplified52.2%

                \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{C - A}{B} - \frac{\color{blue}{\sqrt{\mathsf{fma}\left(B, B, C \cdot C\right)}}}{B}\right)}{\pi} \]
              8. Taylor expanded in C around 0

                \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(-1 \cdot \left(1 + \frac{A}{B}\right)\right)}}{\mathsf{PI}\left(\right)} \]
              9. Step-by-step derivation
                1. distribute-lft-inN/A

                  \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(-1 \cdot 1 + -1 \cdot \frac{A}{B}\right)}}{\mathsf{PI}\left(\right)} \]
                2. metadata-evalN/A

                  \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\color{blue}{-1} + -1 \cdot \frac{A}{B}\right)}{\mathsf{PI}\left(\right)} \]
                3. mul-1-negN/A

                  \[\leadsto 180 \cdot \frac{\tan^{-1} \left(-1 + \color{blue}{\left(\mathsf{neg}\left(\frac{A}{B}\right)\right)}\right)}{\mathsf{PI}\left(\right)} \]
                4. unsub-negN/A

                  \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(-1 - \frac{A}{B}\right)}}{\mathsf{PI}\left(\right)} \]
                5. lower--.f64N/A

                  \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(-1 - \frac{A}{B}\right)}}{\mathsf{PI}\left(\right)} \]
                6. lower-/.f6461.7

                  \[\leadsto 180 \cdot \frac{\tan^{-1} \left(-1 - \color{blue}{\frac{A}{B}}\right)}{\pi} \]
              10. Simplified61.7%

                \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(-1 - \frac{A}{B}\right)}}{\pi} \]
            3. Recombined 2 regimes into one program.
            4. Add Preprocessing

            Alternative 10: 52.0% accurate, 2.6× speedup?

            \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;B \leq 5.7 \cdot 10^{-92}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(1 + \frac{C}{B}\right)}{\pi}\\ \mathbf{else}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} -1}{\pi}\\ \end{array} \end{array} \]
            (FPCore (A B C)
             :precision binary64
             (if (<= B 5.7e-92)
               (* 180.0 (/ (atan (+ 1.0 (/ C B))) PI))
               (* 180.0 (/ (atan -1.0) PI))))
            double code(double A, double B, double C) {
            	double tmp;
            	if (B <= 5.7e-92) {
            		tmp = 180.0 * (atan((1.0 + (C / B))) / ((double) M_PI));
            	} else {
            		tmp = 180.0 * (atan(-1.0) / ((double) M_PI));
            	}
            	return tmp;
            }
            
            public static double code(double A, double B, double C) {
            	double tmp;
            	if (B <= 5.7e-92) {
            		tmp = 180.0 * (Math.atan((1.0 + (C / B))) / Math.PI);
            	} else {
            		tmp = 180.0 * (Math.atan(-1.0) / Math.PI);
            	}
            	return tmp;
            }
            
            def code(A, B, C):
            	tmp = 0
            	if B <= 5.7e-92:
            		tmp = 180.0 * (math.atan((1.0 + (C / B))) / math.pi)
            	else:
            		tmp = 180.0 * (math.atan(-1.0) / math.pi)
            	return tmp
            
            function code(A, B, C)
            	tmp = 0.0
            	if (B <= 5.7e-92)
            		tmp = Float64(180.0 * Float64(atan(Float64(1.0 + Float64(C / B))) / pi));
            	else
            		tmp = Float64(180.0 * Float64(atan(-1.0) / pi));
            	end
            	return tmp
            end
            
            function tmp_2 = code(A, B, C)
            	tmp = 0.0;
            	if (B <= 5.7e-92)
            		tmp = 180.0 * (atan((1.0 + (C / B))) / pi);
            	else
            		tmp = 180.0 * (atan(-1.0) / pi);
            	end
            	tmp_2 = tmp;
            end
            
            code[A_, B_, C_] := If[LessEqual[B, 5.7e-92], N[(180.0 * N[(N[ArcTan[N[(1.0 + N[(C / B), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision], N[(180.0 * N[(N[ArcTan[-1.0], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision]]
            
            \begin{array}{l}
            
            \\
            \begin{array}{l}
            \mathbf{if}\;B \leq 5.7 \cdot 10^{-92}:\\
            \;\;\;\;180 \cdot \frac{\tan^{-1} \left(1 + \frac{C}{B}\right)}{\pi}\\
            
            \mathbf{else}:\\
            \;\;\;\;180 \cdot \frac{\tan^{-1} -1}{\pi}\\
            
            
            \end{array}
            \end{array}
            
            Derivation
            1. Split input into 2 regimes
            2. if B < 5.70000000000000009e-92

              1. Initial program 54.0%

                \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
              2. Add Preprocessing
              3. Taylor expanded in B around -inf

                \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\left(1 + \frac{C}{B}\right) - \frac{A}{B}\right)}}{\mathsf{PI}\left(\right)} \]
              4. Step-by-step derivation
                1. associate--l+N/A

                  \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(1 + \left(\frac{C}{B} - \frac{A}{B}\right)\right)}}{\mathsf{PI}\left(\right)} \]
                2. div-subN/A

                  \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \color{blue}{\frac{C - A}{B}}\right)}{\mathsf{PI}\left(\right)} \]
                3. lower-+.f64N/A

                  \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(1 + \frac{C - A}{B}\right)}}{\mathsf{PI}\left(\right)} \]
                4. lower-/.f64N/A

                  \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \color{blue}{\frac{C - A}{B}}\right)}{\mathsf{PI}\left(\right)} \]
                5. lower--.f6463.3

                  \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \frac{\color{blue}{C - A}}{B}\right)}{\pi} \]
              5. Simplified63.3%

                \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(1 + \frac{C - A}{B}\right)}}{\pi} \]
              6. Taylor expanded in A around 0

                \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(1 + \frac{C}{B}\right)}}{\mathsf{PI}\left(\right)} \]
              7. Step-by-step derivation
                1. lower-+.f64N/A

                  \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(1 + \frac{C}{B}\right)}}{\mathsf{PI}\left(\right)} \]
                2. lower-/.f6452.1

                  \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \color{blue}{\frac{C}{B}}\right)}{\pi} \]
              8. Simplified52.1%

                \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(1 + \frac{C}{B}\right)}}{\pi} \]

              if 5.70000000000000009e-92 < B

              1. Initial program 51.8%

                \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
              2. Add Preprocessing
              3. Taylor expanded in B around inf

                \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{-1}}{\mathsf{PI}\left(\right)} \]
              4. Step-by-step derivation
                1. Simplified58.7%

                  \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{-1}}{\pi} \]
              5. Recombined 2 regimes into one program.
              6. Add Preprocessing

              Alternative 11: 44.3% accurate, 2.8× speedup?

              \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;B \leq -3.4 \cdot 10^{-203}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} 1}{\pi}\\ \mathbf{elif}\;B \leq 2.85 \cdot 10^{-154}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} 0}{\pi}\\ \mathbf{else}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} -1}{\pi}\\ \end{array} \end{array} \]
              (FPCore (A B C)
               :precision binary64
               (if (<= B -3.4e-203)
                 (* 180.0 (/ (atan 1.0) PI))
                 (if (<= B 2.85e-154)
                   (* 180.0 (/ (atan 0.0) PI))
                   (* 180.0 (/ (atan -1.0) PI)))))
              double code(double A, double B, double C) {
              	double tmp;
              	if (B <= -3.4e-203) {
              		tmp = 180.0 * (atan(1.0) / ((double) M_PI));
              	} else if (B <= 2.85e-154) {
              		tmp = 180.0 * (atan(0.0) / ((double) M_PI));
              	} else {
              		tmp = 180.0 * (atan(-1.0) / ((double) M_PI));
              	}
              	return tmp;
              }
              
              public static double code(double A, double B, double C) {
              	double tmp;
              	if (B <= -3.4e-203) {
              		tmp = 180.0 * (Math.atan(1.0) / Math.PI);
              	} else if (B <= 2.85e-154) {
              		tmp = 180.0 * (Math.atan(0.0) / Math.PI);
              	} else {
              		tmp = 180.0 * (Math.atan(-1.0) / Math.PI);
              	}
              	return tmp;
              }
              
              def code(A, B, C):
              	tmp = 0
              	if B <= -3.4e-203:
              		tmp = 180.0 * (math.atan(1.0) / math.pi)
              	elif B <= 2.85e-154:
              		tmp = 180.0 * (math.atan(0.0) / math.pi)
              	else:
              		tmp = 180.0 * (math.atan(-1.0) / math.pi)
              	return tmp
              
              function code(A, B, C)
              	tmp = 0.0
              	if (B <= -3.4e-203)
              		tmp = Float64(180.0 * Float64(atan(1.0) / pi));
              	elseif (B <= 2.85e-154)
              		tmp = Float64(180.0 * Float64(atan(0.0) / pi));
              	else
              		tmp = Float64(180.0 * Float64(atan(-1.0) / pi));
              	end
              	return tmp
              end
              
              function tmp_2 = code(A, B, C)
              	tmp = 0.0;
              	if (B <= -3.4e-203)
              		tmp = 180.0 * (atan(1.0) / pi);
              	elseif (B <= 2.85e-154)
              		tmp = 180.0 * (atan(0.0) / pi);
              	else
              		tmp = 180.0 * (atan(-1.0) / pi);
              	end
              	tmp_2 = tmp;
              end
              
              code[A_, B_, C_] := If[LessEqual[B, -3.4e-203], N[(180.0 * N[(N[ArcTan[1.0], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision], If[LessEqual[B, 2.85e-154], N[(180.0 * N[(N[ArcTan[0.0], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision], N[(180.0 * N[(N[ArcTan[-1.0], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision]]]
              
              \begin{array}{l}
              
              \\
              \begin{array}{l}
              \mathbf{if}\;B \leq -3.4 \cdot 10^{-203}:\\
              \;\;\;\;180 \cdot \frac{\tan^{-1} 1}{\pi}\\
              
              \mathbf{elif}\;B \leq 2.85 \cdot 10^{-154}:\\
              \;\;\;\;180 \cdot \frac{\tan^{-1} 0}{\pi}\\
              
              \mathbf{else}:\\
              \;\;\;\;180 \cdot \frac{\tan^{-1} -1}{\pi}\\
              
              
              \end{array}
              \end{array}
              
              Derivation
              1. Split input into 3 regimes
              2. if B < -3.3999999999999999e-203

                1. Initial program 50.1%

                  \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
                2. Add Preprocessing
                3. Taylor expanded in B around -inf

                  \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{1}}{\mathsf{PI}\left(\right)} \]
                4. Step-by-step derivation
                  1. Simplified48.5%

                    \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{1}}{\pi} \]

                  if -3.3999999999999999e-203 < B < 2.8499999999999999e-154

                  1. Initial program 57.3%

                    \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
                  2. Add Preprocessing
                  3. Taylor expanded in C around inf

                    \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(-1 \cdot \frac{A + -1 \cdot A}{B}\right)}}{\mathsf{PI}\left(\right)} \]
                  4. Step-by-step derivation
                    1. distribute-rgt1-inN/A

                      \[\leadsto 180 \cdot \frac{\tan^{-1} \left(-1 \cdot \frac{\color{blue}{\left(-1 + 1\right) \cdot A}}{B}\right)}{\mathsf{PI}\left(\right)} \]
                    2. metadata-evalN/A

                      \[\leadsto 180 \cdot \frac{\tan^{-1} \left(-1 \cdot \frac{\color{blue}{0} \cdot A}{B}\right)}{\mathsf{PI}\left(\right)} \]
                    3. mul0-lftN/A

                      \[\leadsto 180 \cdot \frac{\tan^{-1} \left(-1 \cdot \frac{\color{blue}{0}}{B}\right)}{\mathsf{PI}\left(\right)} \]
                    4. div0N/A

                      \[\leadsto 180 \cdot \frac{\tan^{-1} \left(-1 \cdot \color{blue}{0}\right)}{\mathsf{PI}\left(\right)} \]
                    5. metadata-eval33.9

                      \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{0}}{\pi} \]
                  5. Simplified33.9%

                    \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{0}}{\pi} \]

                  if 2.8499999999999999e-154 < B

                  1. Initial program 55.2%

                    \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
                  2. Add Preprocessing
                  3. Taylor expanded in B around inf

                    \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{-1}}{\mathsf{PI}\left(\right)} \]
                  4. Step-by-step derivation
                    1. Simplified51.5%

                      \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{-1}}{\pi} \]
                  5. Recombined 3 regimes into one program.
                  6. Add Preprocessing

                  Alternative 12: 29.0% accurate, 2.9× speedup?

                  \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;B \leq 2.85 \cdot 10^{-154}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} 0}{\pi}\\ \mathbf{else}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} -1}{\pi}\\ \end{array} \end{array} \]
                  (FPCore (A B C)
                   :precision binary64
                   (if (<= B 2.85e-154)
                     (* 180.0 (/ (atan 0.0) PI))
                     (* 180.0 (/ (atan -1.0) PI))))
                  double code(double A, double B, double C) {
                  	double tmp;
                  	if (B <= 2.85e-154) {
                  		tmp = 180.0 * (atan(0.0) / ((double) M_PI));
                  	} else {
                  		tmp = 180.0 * (atan(-1.0) / ((double) M_PI));
                  	}
                  	return tmp;
                  }
                  
                  public static double code(double A, double B, double C) {
                  	double tmp;
                  	if (B <= 2.85e-154) {
                  		tmp = 180.0 * (Math.atan(0.0) / Math.PI);
                  	} else {
                  		tmp = 180.0 * (Math.atan(-1.0) / Math.PI);
                  	}
                  	return tmp;
                  }
                  
                  def code(A, B, C):
                  	tmp = 0
                  	if B <= 2.85e-154:
                  		tmp = 180.0 * (math.atan(0.0) / math.pi)
                  	else:
                  		tmp = 180.0 * (math.atan(-1.0) / math.pi)
                  	return tmp
                  
                  function code(A, B, C)
                  	tmp = 0.0
                  	if (B <= 2.85e-154)
                  		tmp = Float64(180.0 * Float64(atan(0.0) / pi));
                  	else
                  		tmp = Float64(180.0 * Float64(atan(-1.0) / pi));
                  	end
                  	return tmp
                  end
                  
                  function tmp_2 = code(A, B, C)
                  	tmp = 0.0;
                  	if (B <= 2.85e-154)
                  		tmp = 180.0 * (atan(0.0) / pi);
                  	else
                  		tmp = 180.0 * (atan(-1.0) / pi);
                  	end
                  	tmp_2 = tmp;
                  end
                  
                  code[A_, B_, C_] := If[LessEqual[B, 2.85e-154], N[(180.0 * N[(N[ArcTan[0.0], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision], N[(180.0 * N[(N[ArcTan[-1.0], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision]]
                  
                  \begin{array}{l}
                  
                  \\
                  \begin{array}{l}
                  \mathbf{if}\;B \leq 2.85 \cdot 10^{-154}:\\
                  \;\;\;\;180 \cdot \frac{\tan^{-1} 0}{\pi}\\
                  
                  \mathbf{else}:\\
                  \;\;\;\;180 \cdot \frac{\tan^{-1} -1}{\pi}\\
                  
                  
                  \end{array}
                  \end{array}
                  
                  Derivation
                  1. Split input into 2 regimes
                  2. if B < 2.8499999999999999e-154

                    1. Initial program 52.4%

                      \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
                    2. Add Preprocessing
                    3. Taylor expanded in C around inf

                      \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(-1 \cdot \frac{A + -1 \cdot A}{B}\right)}}{\mathsf{PI}\left(\right)} \]
                    4. Step-by-step derivation
                      1. distribute-rgt1-inN/A

                        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(-1 \cdot \frac{\color{blue}{\left(-1 + 1\right) \cdot A}}{B}\right)}{\mathsf{PI}\left(\right)} \]
                      2. metadata-evalN/A

                        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(-1 \cdot \frac{\color{blue}{0} \cdot A}{B}\right)}{\mathsf{PI}\left(\right)} \]
                      3. mul0-lftN/A

                        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(-1 \cdot \frac{\color{blue}{0}}{B}\right)}{\mathsf{PI}\left(\right)} \]
                      4. div0N/A

                        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(-1 \cdot \color{blue}{0}\right)}{\mathsf{PI}\left(\right)} \]
                      5. metadata-eval15.7

                        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{0}}{\pi} \]
                    5. Simplified15.7%

                      \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{0}}{\pi} \]

                    if 2.8499999999999999e-154 < B

                    1. Initial program 55.2%

                      \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
                    2. Add Preprocessing
                    3. Taylor expanded in B around inf

                      \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{-1}}{\mathsf{PI}\left(\right)} \]
                    4. Step-by-step derivation
                      1. Simplified51.5%

                        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{-1}}{\pi} \]
                    5. Recombined 2 regimes into one program.
                    6. Add Preprocessing

                    Alternative 13: 21.7% accurate, 3.1× speedup?

                    \[\begin{array}{l} \\ 180 \cdot \frac{\tan^{-1} -1}{\pi} \end{array} \]
                    (FPCore (A B C) :precision binary64 (* 180.0 (/ (atan -1.0) PI)))
                    double code(double A, double B, double C) {
                    	return 180.0 * (atan(-1.0) / ((double) M_PI));
                    }
                    
                    public static double code(double A, double B, double C) {
                    	return 180.0 * (Math.atan(-1.0) / Math.PI);
                    }
                    
                    def code(A, B, C):
                    	return 180.0 * (math.atan(-1.0) / math.pi)
                    
                    function code(A, B, C)
                    	return Float64(180.0 * Float64(atan(-1.0) / pi))
                    end
                    
                    function tmp = code(A, B, C)
                    	tmp = 180.0 * (atan(-1.0) / pi);
                    end
                    
                    code[A_, B_, C_] := N[(180.0 * N[(N[ArcTan[-1.0], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision]
                    
                    \begin{array}{l}
                    
                    \\
                    180 \cdot \frac{\tan^{-1} -1}{\pi}
                    \end{array}
                    
                    Derivation
                    1. Initial program 53.4%

                      \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
                    2. Add Preprocessing
                    3. Taylor expanded in B around inf

                      \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{-1}}{\mathsf{PI}\left(\right)} \]
                    4. Step-by-step derivation
                      1. Simplified20.0%

                        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{-1}}{\pi} \]
                      2. Add Preprocessing

                      Reproduce

                      ?
                      herbie shell --seed 2024215 
                      (FPCore (A B C)
                        :name "ABCF->ab-angle angle"
                        :precision binary64
                        (* 180.0 (/ (atan (* (/ 1.0 B) (- (- C A) (sqrt (+ (pow (- A C) 2.0) (pow B 2.0)))))) PI)))