Data.Colour.RGBSpace.HSV:hsv from colour-2.3.3, I

Percentage Accurate: 95.9% → 97.0%
Time: 10.3s
Alternatives: 6
Speedup: 0.5×

Specification

?
\[\begin{array}{l} \\ x \cdot \left(1 - y \cdot z\right) \end{array} \]
(FPCore (x y z) :precision binary64 (* x (- 1.0 (* y z))))
double code(double x, double y, double z) {
	return x * (1.0 - (y * z));
}
real(8) function code(x, y, z)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    real(8), intent (in) :: z
    code = x * (1.0d0 - (y * z))
end function
public static double code(double x, double y, double z) {
	return x * (1.0 - (y * z));
}
def code(x, y, z):
	return x * (1.0 - (y * z))
function code(x, y, z)
	return Float64(x * Float64(1.0 - Float64(y * z)))
end
function tmp = code(x, y, z)
	tmp = x * (1.0 - (y * z));
end
code[x_, y_, z_] := N[(x * N[(1.0 - N[(y * z), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
x \cdot \left(1 - y \cdot z\right)
\end{array}

Sampling outcomes in binary64 precision:

Local Percentage Accuracy vs ?

The average percentage accuracy by input value. Horizontal axis shows value of an input variable; the variable is choosen in the title. Vertical axis is accuracy; higher is better. Red represent the original program, while blue represents Herbie's suggestion. These can be toggled with buttons below the plot. The line is an average while dots represent individual samples.

Accuracy vs Speed?

Herbie found 6 alternatives:

AlternativeAccuracySpeedup
The accuracy (vertical axis) and speed (horizontal axis) of each alternatives. Up and to the right is better. The red square shows the initial program, and each blue circle shows an alternative.The line shows the best available speed-accuracy tradeoffs.

Initial Program: 95.9% accurate, 1.0× speedup?

\[\begin{array}{l} \\ x \cdot \left(1 - y \cdot z\right) \end{array} \]
(FPCore (x y z) :precision binary64 (* x (- 1.0 (* y z))))
double code(double x, double y, double z) {
	return x * (1.0 - (y * z));
}
real(8) function code(x, y, z)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    real(8), intent (in) :: z
    code = x * (1.0d0 - (y * z))
end function
public static double code(double x, double y, double z) {
	return x * (1.0 - (y * z));
}
def code(x, y, z):
	return x * (1.0 - (y * z))
function code(x, y, z)
	return Float64(x * Float64(1.0 - Float64(y * z)))
end
function tmp = code(x, y, z)
	tmp = x * (1.0 - (y * z));
end
code[x_, y_, z_] := N[(x * N[(1.0 - N[(y * z), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
x \cdot \left(1 - y \cdot z\right)
\end{array}

Alternative 1: 97.0% accurate, 0.3× speedup?

\[\begin{array}{l} [x, y, z] = \mathsf{sort}([x, y, z])\\ \\ \begin{array}{l} \mathbf{if}\;1 - y \cdot z \leq -1 \cdot 10^{+75}:\\ \;\;\;\;-z \cdot \left(y \cdot x\right)\\ \mathbf{else}:\\ \;\;\;\;\frac{x}{\frac{-1}{\mathsf{fma}\left(y, z, -1\right)}}\\ \end{array} \end{array} \]
NOTE: x, y, and z should be sorted in increasing order before calling this function.
(FPCore (x y z)
 :precision binary64
 (if (<= (- 1.0 (* y z)) -1e+75)
   (- (* z (* y x)))
   (/ x (/ -1.0 (fma y z -1.0)))))
assert(x < y && y < z);
double code(double x, double y, double z) {
	double tmp;
	if ((1.0 - (y * z)) <= -1e+75) {
		tmp = -(z * (y * x));
	} else {
		tmp = x / (-1.0 / fma(y, z, -1.0));
	}
	return tmp;
}
x, y, z = sort([x, y, z])
function code(x, y, z)
	tmp = 0.0
	if (Float64(1.0 - Float64(y * z)) <= -1e+75)
		tmp = Float64(-Float64(z * Float64(y * x)));
	else
		tmp = Float64(x / Float64(-1.0 / fma(y, z, -1.0)));
	end
	return tmp
end
NOTE: x, y, and z should be sorted in increasing order before calling this function.
code[x_, y_, z_] := If[LessEqual[N[(1.0 - N[(y * z), $MachinePrecision]), $MachinePrecision], -1e+75], (-N[(z * N[(y * x), $MachinePrecision]), $MachinePrecision]), N[(x / N[(-1.0 / N[(y * z + -1.0), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]]
\begin{array}{l}
[x, y, z] = \mathsf{sort}([x, y, z])\\
\\
\begin{array}{l}
\mathbf{if}\;1 - y \cdot z \leq -1 \cdot 10^{+75}:\\
\;\;\;\;-z \cdot \left(y \cdot x\right)\\

\mathbf{else}:\\
\;\;\;\;\frac{x}{\frac{-1}{\mathsf{fma}\left(y, z, -1\right)}}\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if (-.f64 #s(literal 1 binary64) (*.f64 y z)) < -9.99999999999999927e74

    1. Initial program 87.0%

      \[x \cdot \left(1 - y \cdot z\right) \]
    2. Add Preprocessing
    3. Taylor expanded in y around inf

      \[\leadsto \color{blue}{-1 \cdot \left(x \cdot \left(y \cdot z\right)\right)} \]
    4. Step-by-step derivation
      1. associate-*r*N/A

        \[\leadsto \color{blue}{\left(-1 \cdot x\right) \cdot \left(y \cdot z\right)} \]
      2. *-commutativeN/A

        \[\leadsto \left(-1 \cdot x\right) \cdot \color{blue}{\left(z \cdot y\right)} \]
      3. associate-*r*N/A

        \[\leadsto \color{blue}{\left(\left(-1 \cdot x\right) \cdot z\right) \cdot y} \]
      4. associate-*r*N/A

        \[\leadsto \color{blue}{\left(-1 \cdot \left(x \cdot z\right)\right)} \cdot y \]
      5. *-commutativeN/A

        \[\leadsto \color{blue}{y \cdot \left(-1 \cdot \left(x \cdot z\right)\right)} \]
      6. *-lowering-*.f64N/A

        \[\leadsto \color{blue}{y \cdot \left(-1 \cdot \left(x \cdot z\right)\right)} \]
      7. associate-*r*N/A

        \[\leadsto y \cdot \color{blue}{\left(\left(-1 \cdot x\right) \cdot z\right)} \]
      8. *-commutativeN/A

        \[\leadsto y \cdot \color{blue}{\left(z \cdot \left(-1 \cdot x\right)\right)} \]
      9. *-lowering-*.f64N/A

        \[\leadsto y \cdot \color{blue}{\left(z \cdot \left(-1 \cdot x\right)\right)} \]
      10. mul-1-negN/A

        \[\leadsto y \cdot \left(z \cdot \color{blue}{\left(\mathsf{neg}\left(x\right)\right)}\right) \]
      11. neg-lowering-neg.f6496.1

        \[\leadsto y \cdot \left(z \cdot \color{blue}{\left(-x\right)}\right) \]
    5. Simplified96.1%

      \[\leadsto \color{blue}{y \cdot \left(z \cdot \left(-x\right)\right)} \]
    6. Step-by-step derivation
      1. *-commutativeN/A

        \[\leadsto y \cdot \color{blue}{\left(\left(\mathsf{neg}\left(x\right)\right) \cdot z\right)} \]
      2. associate-*r*N/A

        \[\leadsto \color{blue}{\left(y \cdot \left(\mathsf{neg}\left(x\right)\right)\right) \cdot z} \]
      3. *-lowering-*.f64N/A

        \[\leadsto \color{blue}{\left(y \cdot \left(\mathsf{neg}\left(x\right)\right)\right) \cdot z} \]
      4. *-lowering-*.f64N/A

        \[\leadsto \color{blue}{\left(y \cdot \left(\mathsf{neg}\left(x\right)\right)\right)} \cdot z \]
      5. neg-lowering-neg.f6496.1

        \[\leadsto \left(y \cdot \color{blue}{\left(-x\right)}\right) \cdot z \]
    7. Applied egg-rr96.1%

      \[\leadsto \color{blue}{\left(y \cdot \left(-x\right)\right) \cdot z} \]

    if -9.99999999999999927e74 < (-.f64 #s(literal 1 binary64) (*.f64 y z))

    1. Initial program 98.9%

      \[x \cdot \left(1 - y \cdot z\right) \]
    2. Add Preprocessing
    3. Step-by-step derivation
      1. flip--N/A

        \[\leadsto x \cdot \color{blue}{\frac{1 \cdot 1 - \left(y \cdot z\right) \cdot \left(y \cdot z\right)}{1 + y \cdot z}} \]
      2. metadata-evalN/A

        \[\leadsto x \cdot \frac{\color{blue}{1} - \left(y \cdot z\right) \cdot \left(y \cdot z\right)}{1 + y \cdot z} \]
      3. div-subN/A

        \[\leadsto x \cdot \color{blue}{\left(\frac{1}{1 + y \cdot z} - \frac{\left(y \cdot z\right) \cdot \left(y \cdot z\right)}{1 + y \cdot z}\right)} \]
      4. swap-sqrN/A

        \[\leadsto x \cdot \left(\frac{1}{1 + y \cdot z} - \frac{\color{blue}{\left(y \cdot y\right) \cdot \left(z \cdot z\right)}}{1 + y \cdot z}\right) \]
      5. associate-/l*N/A

        \[\leadsto x \cdot \left(\frac{1}{1 + y \cdot z} - \color{blue}{\left(y \cdot y\right) \cdot \frac{z \cdot z}{1 + y \cdot z}}\right) \]
      6. cancel-sign-sub-invN/A

        \[\leadsto x \cdot \color{blue}{\left(\frac{1}{1 + y \cdot z} + \left(\mathsf{neg}\left(y \cdot y\right)\right) \cdot \frac{z \cdot z}{1 + y \cdot z}\right)} \]
      7. +-lowering-+.f64N/A

        \[\leadsto x \cdot \color{blue}{\left(\frac{1}{1 + y \cdot z} + \left(\mathsf{neg}\left(y \cdot y\right)\right) \cdot \frac{z \cdot z}{1 + y \cdot z}\right)} \]
      8. /-lowering-/.f64N/A

        \[\leadsto x \cdot \left(\color{blue}{\frac{1}{1 + y \cdot z}} + \left(\mathsf{neg}\left(y \cdot y\right)\right) \cdot \frac{z \cdot z}{1 + y \cdot z}\right) \]
      9. +-commutativeN/A

        \[\leadsto x \cdot \left(\frac{1}{\color{blue}{y \cdot z + 1}} + \left(\mathsf{neg}\left(y \cdot y\right)\right) \cdot \frac{z \cdot z}{1 + y \cdot z}\right) \]
      10. accelerator-lowering-fma.f64N/A

        \[\leadsto x \cdot \left(\frac{1}{\color{blue}{\mathsf{fma}\left(y, z, 1\right)}} + \left(\mathsf{neg}\left(y \cdot y\right)\right) \cdot \frac{z \cdot z}{1 + y \cdot z}\right) \]
      11. *-lowering-*.f64N/A

        \[\leadsto x \cdot \left(\frac{1}{\mathsf{fma}\left(y, z, 1\right)} + \color{blue}{\left(\mathsf{neg}\left(y \cdot y\right)\right) \cdot \frac{z \cdot z}{1 + y \cdot z}}\right) \]
      12. neg-lowering-neg.f64N/A

        \[\leadsto x \cdot \left(\frac{1}{\mathsf{fma}\left(y, z, 1\right)} + \color{blue}{\left(\mathsf{neg}\left(y \cdot y\right)\right)} \cdot \frac{z \cdot z}{1 + y \cdot z}\right) \]
      13. *-lowering-*.f64N/A

        \[\leadsto x \cdot \left(\frac{1}{\mathsf{fma}\left(y, z, 1\right)} + \left(\mathsf{neg}\left(\color{blue}{y \cdot y}\right)\right) \cdot \frac{z \cdot z}{1 + y \cdot z}\right) \]
      14. /-lowering-/.f64N/A

        \[\leadsto x \cdot \left(\frac{1}{\mathsf{fma}\left(y, z, 1\right)} + \left(\mathsf{neg}\left(y \cdot y\right)\right) \cdot \color{blue}{\frac{z \cdot z}{1 + y \cdot z}}\right) \]
      15. *-lowering-*.f64N/A

        \[\leadsto x \cdot \left(\frac{1}{\mathsf{fma}\left(y, z, 1\right)} + \left(\mathsf{neg}\left(y \cdot y\right)\right) \cdot \frac{\color{blue}{z \cdot z}}{1 + y \cdot z}\right) \]
      16. +-commutativeN/A

        \[\leadsto x \cdot \left(\frac{1}{\mathsf{fma}\left(y, z, 1\right)} + \left(\mathsf{neg}\left(y \cdot y\right)\right) \cdot \frac{z \cdot z}{\color{blue}{y \cdot z + 1}}\right) \]
      17. accelerator-lowering-fma.f6475.8

        \[\leadsto x \cdot \left(\frac{1}{\mathsf{fma}\left(y, z, 1\right)} + \left(-y \cdot y\right) \cdot \frac{z \cdot z}{\color{blue}{\mathsf{fma}\left(y, z, 1\right)}}\right) \]
    4. Applied egg-rr75.8%

      \[\leadsto x \cdot \color{blue}{\left(\frac{1}{\mathsf{fma}\left(y, z, 1\right)} + \left(-y \cdot y\right) \cdot \frac{z \cdot z}{\mathsf{fma}\left(y, z, 1\right)}\right)} \]
    5. Step-by-step derivation
      1. flip3-+N/A

        \[\leadsto x \cdot \color{blue}{\frac{{\left(\frac{1}{y \cdot z + 1}\right)}^{3} + {\left(\left(\mathsf{neg}\left(y \cdot y\right)\right) \cdot \frac{z \cdot z}{y \cdot z + 1}\right)}^{3}}{\frac{1}{y \cdot z + 1} \cdot \frac{1}{y \cdot z + 1} + \left(\left(\left(\mathsf{neg}\left(y \cdot y\right)\right) \cdot \frac{z \cdot z}{y \cdot z + 1}\right) \cdot \left(\left(\mathsf{neg}\left(y \cdot y\right)\right) \cdot \frac{z \cdot z}{y \cdot z + 1}\right) - \frac{1}{y \cdot z + 1} \cdot \left(\left(\mathsf{neg}\left(y \cdot y\right)\right) \cdot \frac{z \cdot z}{y \cdot z + 1}\right)\right)}} \]
      2. clear-numN/A

        \[\leadsto x \cdot \color{blue}{\frac{1}{\frac{\frac{1}{y \cdot z + 1} \cdot \frac{1}{y \cdot z + 1} + \left(\left(\left(\mathsf{neg}\left(y \cdot y\right)\right) \cdot \frac{z \cdot z}{y \cdot z + 1}\right) \cdot \left(\left(\mathsf{neg}\left(y \cdot y\right)\right) \cdot \frac{z \cdot z}{y \cdot z + 1}\right) - \frac{1}{y \cdot z + 1} \cdot \left(\left(\mathsf{neg}\left(y \cdot y\right)\right) \cdot \frac{z \cdot z}{y \cdot z + 1}\right)\right)}{{\left(\frac{1}{y \cdot z + 1}\right)}^{3} + {\left(\left(\mathsf{neg}\left(y \cdot y\right)\right) \cdot \frac{z \cdot z}{y \cdot z + 1}\right)}^{3}}}} \]
      3. un-div-invN/A

        \[\leadsto \color{blue}{\frac{x}{\frac{\frac{1}{y \cdot z + 1} \cdot \frac{1}{y \cdot z + 1} + \left(\left(\left(\mathsf{neg}\left(y \cdot y\right)\right) \cdot \frac{z \cdot z}{y \cdot z + 1}\right) \cdot \left(\left(\mathsf{neg}\left(y \cdot y\right)\right) \cdot \frac{z \cdot z}{y \cdot z + 1}\right) - \frac{1}{y \cdot z + 1} \cdot \left(\left(\mathsf{neg}\left(y \cdot y\right)\right) \cdot \frac{z \cdot z}{y \cdot z + 1}\right)\right)}{{\left(\frac{1}{y \cdot z + 1}\right)}^{3} + {\left(\left(\mathsf{neg}\left(y \cdot y\right)\right) \cdot \frac{z \cdot z}{y \cdot z + 1}\right)}^{3}}}} \]
    6. Applied egg-rr98.9%

      \[\leadsto \color{blue}{\frac{x}{\frac{-1}{\mathsf{fma}\left(y, z, -1\right)}}} \]
  3. Recombined 2 regimes into one program.
  4. Final simplification98.4%

    \[\leadsto \begin{array}{l} \mathbf{if}\;1 - y \cdot z \leq -1 \cdot 10^{+75}:\\ \;\;\;\;-z \cdot \left(y \cdot x\right)\\ \mathbf{else}:\\ \;\;\;\;\frac{x}{\frac{-1}{\mathsf{fma}\left(y, z, -1\right)}}\\ \end{array} \]
  5. Add Preprocessing

Alternative 2: 95.1% accurate, 0.3× speedup?

\[\begin{array}{l} [x, y, z] = \mathsf{sort}([x, y, z])\\ \\ \begin{array}{l} t_0 := -\left(y \cdot z\right) \cdot x\\ \mathbf{if}\;y \cdot z \leq -500:\\ \;\;\;\;t\_0\\ \mathbf{elif}\;y \cdot z \leq 2 \cdot 10^{-5}:\\ \;\;\;\;x\\ \mathbf{elif}\;y \cdot z \leq 5 \cdot 10^{+121}:\\ \;\;\;\;t\_0\\ \mathbf{else}:\\ \;\;\;\;-y \cdot \left(z \cdot x\right)\\ \end{array} \end{array} \]
NOTE: x, y, and z should be sorted in increasing order before calling this function.
(FPCore (x y z)
 :precision binary64
 (let* ((t_0 (- (* (* y z) x))))
   (if (<= (* y z) -500.0)
     t_0
     (if (<= (* y z) 2e-5) x (if (<= (* y z) 5e+121) t_0 (- (* y (* z x))))))))
assert(x < y && y < z);
double code(double x, double y, double z) {
	double t_0 = -((y * z) * x);
	double tmp;
	if ((y * z) <= -500.0) {
		tmp = t_0;
	} else if ((y * z) <= 2e-5) {
		tmp = x;
	} else if ((y * z) <= 5e+121) {
		tmp = t_0;
	} else {
		tmp = -(y * (z * x));
	}
	return tmp;
}
NOTE: x, y, and z should be sorted in increasing order before calling this function.
real(8) function code(x, y, z)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    real(8), intent (in) :: z
    real(8) :: t_0
    real(8) :: tmp
    t_0 = -((y * z) * x)
    if ((y * z) <= (-500.0d0)) then
        tmp = t_0
    else if ((y * z) <= 2d-5) then
        tmp = x
    else if ((y * z) <= 5d+121) then
        tmp = t_0
    else
        tmp = -(y * (z * x))
    end if
    code = tmp
end function
assert x < y && y < z;
public static double code(double x, double y, double z) {
	double t_0 = -((y * z) * x);
	double tmp;
	if ((y * z) <= -500.0) {
		tmp = t_0;
	} else if ((y * z) <= 2e-5) {
		tmp = x;
	} else if ((y * z) <= 5e+121) {
		tmp = t_0;
	} else {
		tmp = -(y * (z * x));
	}
	return tmp;
}
[x, y, z] = sort([x, y, z])
def code(x, y, z):
	t_0 = -((y * z) * x)
	tmp = 0
	if (y * z) <= -500.0:
		tmp = t_0
	elif (y * z) <= 2e-5:
		tmp = x
	elif (y * z) <= 5e+121:
		tmp = t_0
	else:
		tmp = -(y * (z * x))
	return tmp
x, y, z = sort([x, y, z])
function code(x, y, z)
	t_0 = Float64(-Float64(Float64(y * z) * x))
	tmp = 0.0
	if (Float64(y * z) <= -500.0)
		tmp = t_0;
	elseif (Float64(y * z) <= 2e-5)
		tmp = x;
	elseif (Float64(y * z) <= 5e+121)
		tmp = t_0;
	else
		tmp = Float64(-Float64(y * Float64(z * x)));
	end
	return tmp
end
x, y, z = num2cell(sort([x, y, z])){:}
function tmp_2 = code(x, y, z)
	t_0 = -((y * z) * x);
	tmp = 0.0;
	if ((y * z) <= -500.0)
		tmp = t_0;
	elseif ((y * z) <= 2e-5)
		tmp = x;
	elseif ((y * z) <= 5e+121)
		tmp = t_0;
	else
		tmp = -(y * (z * x));
	end
	tmp_2 = tmp;
end
NOTE: x, y, and z should be sorted in increasing order before calling this function.
code[x_, y_, z_] := Block[{t$95$0 = (-N[(N[(y * z), $MachinePrecision] * x), $MachinePrecision])}, If[LessEqual[N[(y * z), $MachinePrecision], -500.0], t$95$0, If[LessEqual[N[(y * z), $MachinePrecision], 2e-5], x, If[LessEqual[N[(y * z), $MachinePrecision], 5e+121], t$95$0, (-N[(y * N[(z * x), $MachinePrecision]), $MachinePrecision])]]]]
\begin{array}{l}
[x, y, z] = \mathsf{sort}([x, y, z])\\
\\
\begin{array}{l}
t_0 := -\left(y \cdot z\right) \cdot x\\
\mathbf{if}\;y \cdot z \leq -500:\\
\;\;\;\;t\_0\\

\mathbf{elif}\;y \cdot z \leq 2 \cdot 10^{-5}:\\
\;\;\;\;x\\

\mathbf{elif}\;y \cdot z \leq 5 \cdot 10^{+121}:\\
\;\;\;\;t\_0\\

\mathbf{else}:\\
\;\;\;\;-y \cdot \left(z \cdot x\right)\\


\end{array}
\end{array}
Derivation
  1. Split input into 3 regimes
  2. if (*.f64 y z) < -500 or 2.00000000000000016e-5 < (*.f64 y z) < 5.00000000000000007e121

    1. Initial program 97.2%

      \[x \cdot \left(1 - y \cdot z\right) \]
    2. Add Preprocessing
    3. Taylor expanded in y around inf

      \[\leadsto x \cdot \color{blue}{\left(-1 \cdot \left(y \cdot z\right)\right)} \]
    4. Step-by-step derivation
      1. mul-1-negN/A

        \[\leadsto x \cdot \color{blue}{\left(\mathsf{neg}\left(y \cdot z\right)\right)} \]
      2. distribute-rgt-neg-inN/A

        \[\leadsto x \cdot \color{blue}{\left(y \cdot \left(\mathsf{neg}\left(z\right)\right)\right)} \]
      3. mul-1-negN/A

        \[\leadsto x \cdot \left(y \cdot \color{blue}{\left(-1 \cdot z\right)}\right) \]
      4. *-lowering-*.f64N/A

        \[\leadsto x \cdot \color{blue}{\left(y \cdot \left(-1 \cdot z\right)\right)} \]
      5. mul-1-negN/A

        \[\leadsto x \cdot \left(y \cdot \color{blue}{\left(\mathsf{neg}\left(z\right)\right)}\right) \]
      6. neg-lowering-neg.f6494.2

        \[\leadsto x \cdot \left(y \cdot \color{blue}{\left(-z\right)}\right) \]
    5. Simplified94.2%

      \[\leadsto x \cdot \color{blue}{\left(y \cdot \left(-z\right)\right)} \]

    if -500 < (*.f64 y z) < 2.00000000000000016e-5

    1. Initial program 100.0%

      \[x \cdot \left(1 - y \cdot z\right) \]
    2. Add Preprocessing
    3. Taylor expanded in y around 0

      \[\leadsto \color{blue}{x} \]
    4. Step-by-step derivation
      1. Simplified98.6%

        \[\leadsto \color{blue}{x} \]

      if 5.00000000000000007e121 < (*.f64 y z)

      1. Initial program 84.3%

        \[x \cdot \left(1 - y \cdot z\right) \]
      2. Add Preprocessing
      3. Taylor expanded in y around inf

        \[\leadsto \color{blue}{-1 \cdot \left(x \cdot \left(y \cdot z\right)\right)} \]
      4. Step-by-step derivation
        1. associate-*r*N/A

          \[\leadsto \color{blue}{\left(-1 \cdot x\right) \cdot \left(y \cdot z\right)} \]
        2. *-commutativeN/A

          \[\leadsto \left(-1 \cdot x\right) \cdot \color{blue}{\left(z \cdot y\right)} \]
        3. associate-*r*N/A

          \[\leadsto \color{blue}{\left(\left(-1 \cdot x\right) \cdot z\right) \cdot y} \]
        4. associate-*r*N/A

          \[\leadsto \color{blue}{\left(-1 \cdot \left(x \cdot z\right)\right)} \cdot y \]
        5. *-commutativeN/A

          \[\leadsto \color{blue}{y \cdot \left(-1 \cdot \left(x \cdot z\right)\right)} \]
        6. *-lowering-*.f64N/A

          \[\leadsto \color{blue}{y \cdot \left(-1 \cdot \left(x \cdot z\right)\right)} \]
        7. associate-*r*N/A

          \[\leadsto y \cdot \color{blue}{\left(\left(-1 \cdot x\right) \cdot z\right)} \]
        8. *-commutativeN/A

          \[\leadsto y \cdot \color{blue}{\left(z \cdot \left(-1 \cdot x\right)\right)} \]
        9. *-lowering-*.f64N/A

          \[\leadsto y \cdot \color{blue}{\left(z \cdot \left(-1 \cdot x\right)\right)} \]
        10. mul-1-negN/A

          \[\leadsto y \cdot \left(z \cdot \color{blue}{\left(\mathsf{neg}\left(x\right)\right)}\right) \]
        11. neg-lowering-neg.f6499.8

          \[\leadsto y \cdot \left(z \cdot \color{blue}{\left(-x\right)}\right) \]
      5. Simplified99.8%

        \[\leadsto \color{blue}{y \cdot \left(z \cdot \left(-x\right)\right)} \]
    5. Recombined 3 regimes into one program.
    6. Final simplification97.4%

      \[\leadsto \begin{array}{l} \mathbf{if}\;y \cdot z \leq -500:\\ \;\;\;\;-\left(y \cdot z\right) \cdot x\\ \mathbf{elif}\;y \cdot z \leq 2 \cdot 10^{-5}:\\ \;\;\;\;x\\ \mathbf{elif}\;y \cdot z \leq 5 \cdot 10^{+121}:\\ \;\;\;\;-\left(y \cdot z\right) \cdot x\\ \mathbf{else}:\\ \;\;\;\;-y \cdot \left(z \cdot x\right)\\ \end{array} \]
    7. Add Preprocessing

    Alternative 3: 94.4% accurate, 0.4× speedup?

    \[\begin{array}{l} [x, y, z] = \mathsf{sort}([x, y, z])\\ \\ \begin{array}{l} t_0 := -z \cdot \left(y \cdot x\right)\\ \mathbf{if}\;y \cdot z \leq -500:\\ \;\;\;\;t\_0\\ \mathbf{elif}\;y \cdot z \leq 2 \cdot 10^{-5}:\\ \;\;\;\;x\\ \mathbf{else}:\\ \;\;\;\;t\_0\\ \end{array} \end{array} \]
    NOTE: x, y, and z should be sorted in increasing order before calling this function.
    (FPCore (x y z)
     :precision binary64
     (let* ((t_0 (- (* z (* y x)))))
       (if (<= (* y z) -500.0) t_0 (if (<= (* y z) 2e-5) x t_0))))
    assert(x < y && y < z);
    double code(double x, double y, double z) {
    	double t_0 = -(z * (y * x));
    	double tmp;
    	if ((y * z) <= -500.0) {
    		tmp = t_0;
    	} else if ((y * z) <= 2e-5) {
    		tmp = x;
    	} else {
    		tmp = t_0;
    	}
    	return tmp;
    }
    
    NOTE: x, y, and z should be sorted in increasing order before calling this function.
    real(8) function code(x, y, z)
        real(8), intent (in) :: x
        real(8), intent (in) :: y
        real(8), intent (in) :: z
        real(8) :: t_0
        real(8) :: tmp
        t_0 = -(z * (y * x))
        if ((y * z) <= (-500.0d0)) then
            tmp = t_0
        else if ((y * z) <= 2d-5) then
            tmp = x
        else
            tmp = t_0
        end if
        code = tmp
    end function
    
    assert x < y && y < z;
    public static double code(double x, double y, double z) {
    	double t_0 = -(z * (y * x));
    	double tmp;
    	if ((y * z) <= -500.0) {
    		tmp = t_0;
    	} else if ((y * z) <= 2e-5) {
    		tmp = x;
    	} else {
    		tmp = t_0;
    	}
    	return tmp;
    }
    
    [x, y, z] = sort([x, y, z])
    def code(x, y, z):
    	t_0 = -(z * (y * x))
    	tmp = 0
    	if (y * z) <= -500.0:
    		tmp = t_0
    	elif (y * z) <= 2e-5:
    		tmp = x
    	else:
    		tmp = t_0
    	return tmp
    
    x, y, z = sort([x, y, z])
    function code(x, y, z)
    	t_0 = Float64(-Float64(z * Float64(y * x)))
    	tmp = 0.0
    	if (Float64(y * z) <= -500.0)
    		tmp = t_0;
    	elseif (Float64(y * z) <= 2e-5)
    		tmp = x;
    	else
    		tmp = t_0;
    	end
    	return tmp
    end
    
    x, y, z = num2cell(sort([x, y, z])){:}
    function tmp_2 = code(x, y, z)
    	t_0 = -(z * (y * x));
    	tmp = 0.0;
    	if ((y * z) <= -500.0)
    		tmp = t_0;
    	elseif ((y * z) <= 2e-5)
    		tmp = x;
    	else
    		tmp = t_0;
    	end
    	tmp_2 = tmp;
    end
    
    NOTE: x, y, and z should be sorted in increasing order before calling this function.
    code[x_, y_, z_] := Block[{t$95$0 = (-N[(z * N[(y * x), $MachinePrecision]), $MachinePrecision])}, If[LessEqual[N[(y * z), $MachinePrecision], -500.0], t$95$0, If[LessEqual[N[(y * z), $MachinePrecision], 2e-5], x, t$95$0]]]
    
    \begin{array}{l}
    [x, y, z] = \mathsf{sort}([x, y, z])\\
    \\
    \begin{array}{l}
    t_0 := -z \cdot \left(y \cdot x\right)\\
    \mathbf{if}\;y \cdot z \leq -500:\\
    \;\;\;\;t\_0\\
    
    \mathbf{elif}\;y \cdot z \leq 2 \cdot 10^{-5}:\\
    \;\;\;\;x\\
    
    \mathbf{else}:\\
    \;\;\;\;t\_0\\
    
    
    \end{array}
    \end{array}
    
    Derivation
    1. Split input into 2 regimes
    2. if (*.f64 y z) < -500 or 2.00000000000000016e-5 < (*.f64 y z)

      1. Initial program 92.7%

        \[x \cdot \left(1 - y \cdot z\right) \]
      2. Add Preprocessing
      3. Taylor expanded in y around inf

        \[\leadsto \color{blue}{-1 \cdot \left(x \cdot \left(y \cdot z\right)\right)} \]
      4. Step-by-step derivation
        1. associate-*r*N/A

          \[\leadsto \color{blue}{\left(-1 \cdot x\right) \cdot \left(y \cdot z\right)} \]
        2. *-commutativeN/A

          \[\leadsto \left(-1 \cdot x\right) \cdot \color{blue}{\left(z \cdot y\right)} \]
        3. associate-*r*N/A

          \[\leadsto \color{blue}{\left(\left(-1 \cdot x\right) \cdot z\right) \cdot y} \]
        4. associate-*r*N/A

          \[\leadsto \color{blue}{\left(-1 \cdot \left(x \cdot z\right)\right)} \cdot y \]
        5. *-commutativeN/A

          \[\leadsto \color{blue}{y \cdot \left(-1 \cdot \left(x \cdot z\right)\right)} \]
        6. *-lowering-*.f64N/A

          \[\leadsto \color{blue}{y \cdot \left(-1 \cdot \left(x \cdot z\right)\right)} \]
        7. associate-*r*N/A

          \[\leadsto y \cdot \color{blue}{\left(\left(-1 \cdot x\right) \cdot z\right)} \]
        8. *-commutativeN/A

          \[\leadsto y \cdot \color{blue}{\left(z \cdot \left(-1 \cdot x\right)\right)} \]
        9. *-lowering-*.f64N/A

          \[\leadsto y \cdot \color{blue}{\left(z \cdot \left(-1 \cdot x\right)\right)} \]
        10. mul-1-negN/A

          \[\leadsto y \cdot \left(z \cdot \color{blue}{\left(\mathsf{neg}\left(x\right)\right)}\right) \]
        11. neg-lowering-neg.f6489.8

          \[\leadsto y \cdot \left(z \cdot \color{blue}{\left(-x\right)}\right) \]
      5. Simplified89.8%

        \[\leadsto \color{blue}{y \cdot \left(z \cdot \left(-x\right)\right)} \]
      6. Step-by-step derivation
        1. *-commutativeN/A

          \[\leadsto y \cdot \color{blue}{\left(\left(\mathsf{neg}\left(x\right)\right) \cdot z\right)} \]
        2. associate-*r*N/A

          \[\leadsto \color{blue}{\left(y \cdot \left(\mathsf{neg}\left(x\right)\right)\right) \cdot z} \]
        3. *-lowering-*.f64N/A

          \[\leadsto \color{blue}{\left(y \cdot \left(\mathsf{neg}\left(x\right)\right)\right) \cdot z} \]
        4. *-lowering-*.f64N/A

          \[\leadsto \color{blue}{\left(y \cdot \left(\mathsf{neg}\left(x\right)\right)\right)} \cdot z \]
        5. neg-lowering-neg.f6493.7

          \[\leadsto \left(y \cdot \color{blue}{\left(-x\right)}\right) \cdot z \]
      7. Applied egg-rr93.7%

        \[\leadsto \color{blue}{\left(y \cdot \left(-x\right)\right) \cdot z} \]

      if -500 < (*.f64 y z) < 2.00000000000000016e-5

      1. Initial program 100.0%

        \[x \cdot \left(1 - y \cdot z\right) \]
      2. Add Preprocessing
      3. Taylor expanded in y around 0

        \[\leadsto \color{blue}{x} \]
      4. Step-by-step derivation
        1. Simplified98.6%

          \[\leadsto \color{blue}{x} \]
      5. Recombined 2 regimes into one program.
      6. Final simplification96.3%

        \[\leadsto \begin{array}{l} \mathbf{if}\;y \cdot z \leq -500:\\ \;\;\;\;-z \cdot \left(y \cdot x\right)\\ \mathbf{elif}\;y \cdot z \leq 2 \cdot 10^{-5}:\\ \;\;\;\;x\\ \mathbf{else}:\\ \;\;\;\;-z \cdot \left(y \cdot x\right)\\ \end{array} \]
      7. Add Preprocessing

      Alternative 4: 93.6% accurate, 0.4× speedup?

      \[\begin{array}{l} [x, y, z] = \mathsf{sort}([x, y, z])\\ \\ \begin{array}{l} t_0 := -\left(y \cdot z\right) \cdot x\\ \mathbf{if}\;y \cdot z \leq -500:\\ \;\;\;\;t\_0\\ \mathbf{elif}\;y \cdot z \leq 2 \cdot 10^{-5}:\\ \;\;\;\;x\\ \mathbf{else}:\\ \;\;\;\;t\_0\\ \end{array} \end{array} \]
      NOTE: x, y, and z should be sorted in increasing order before calling this function.
      (FPCore (x y z)
       :precision binary64
       (let* ((t_0 (- (* (* y z) x))))
         (if (<= (* y z) -500.0) t_0 (if (<= (* y z) 2e-5) x t_0))))
      assert(x < y && y < z);
      double code(double x, double y, double z) {
      	double t_0 = -((y * z) * x);
      	double tmp;
      	if ((y * z) <= -500.0) {
      		tmp = t_0;
      	} else if ((y * z) <= 2e-5) {
      		tmp = x;
      	} else {
      		tmp = t_0;
      	}
      	return tmp;
      }
      
      NOTE: x, y, and z should be sorted in increasing order before calling this function.
      real(8) function code(x, y, z)
          real(8), intent (in) :: x
          real(8), intent (in) :: y
          real(8), intent (in) :: z
          real(8) :: t_0
          real(8) :: tmp
          t_0 = -((y * z) * x)
          if ((y * z) <= (-500.0d0)) then
              tmp = t_0
          else if ((y * z) <= 2d-5) then
              tmp = x
          else
              tmp = t_0
          end if
          code = tmp
      end function
      
      assert x < y && y < z;
      public static double code(double x, double y, double z) {
      	double t_0 = -((y * z) * x);
      	double tmp;
      	if ((y * z) <= -500.0) {
      		tmp = t_0;
      	} else if ((y * z) <= 2e-5) {
      		tmp = x;
      	} else {
      		tmp = t_0;
      	}
      	return tmp;
      }
      
      [x, y, z] = sort([x, y, z])
      def code(x, y, z):
      	t_0 = -((y * z) * x)
      	tmp = 0
      	if (y * z) <= -500.0:
      		tmp = t_0
      	elif (y * z) <= 2e-5:
      		tmp = x
      	else:
      		tmp = t_0
      	return tmp
      
      x, y, z = sort([x, y, z])
      function code(x, y, z)
      	t_0 = Float64(-Float64(Float64(y * z) * x))
      	tmp = 0.0
      	if (Float64(y * z) <= -500.0)
      		tmp = t_0;
      	elseif (Float64(y * z) <= 2e-5)
      		tmp = x;
      	else
      		tmp = t_0;
      	end
      	return tmp
      end
      
      x, y, z = num2cell(sort([x, y, z])){:}
      function tmp_2 = code(x, y, z)
      	t_0 = -((y * z) * x);
      	tmp = 0.0;
      	if ((y * z) <= -500.0)
      		tmp = t_0;
      	elseif ((y * z) <= 2e-5)
      		tmp = x;
      	else
      		tmp = t_0;
      	end
      	tmp_2 = tmp;
      end
      
      NOTE: x, y, and z should be sorted in increasing order before calling this function.
      code[x_, y_, z_] := Block[{t$95$0 = (-N[(N[(y * z), $MachinePrecision] * x), $MachinePrecision])}, If[LessEqual[N[(y * z), $MachinePrecision], -500.0], t$95$0, If[LessEqual[N[(y * z), $MachinePrecision], 2e-5], x, t$95$0]]]
      
      \begin{array}{l}
      [x, y, z] = \mathsf{sort}([x, y, z])\\
      \\
      \begin{array}{l}
      t_0 := -\left(y \cdot z\right) \cdot x\\
      \mathbf{if}\;y \cdot z \leq -500:\\
      \;\;\;\;t\_0\\
      
      \mathbf{elif}\;y \cdot z \leq 2 \cdot 10^{-5}:\\
      \;\;\;\;x\\
      
      \mathbf{else}:\\
      \;\;\;\;t\_0\\
      
      
      \end{array}
      \end{array}
      
      Derivation
      1. Split input into 2 regimes
      2. if (*.f64 y z) < -500 or 2.00000000000000016e-5 < (*.f64 y z)

        1. Initial program 92.7%

          \[x \cdot \left(1 - y \cdot z\right) \]
        2. Add Preprocessing
        3. Taylor expanded in y around inf

          \[\leadsto x \cdot \color{blue}{\left(-1 \cdot \left(y \cdot z\right)\right)} \]
        4. Step-by-step derivation
          1. mul-1-negN/A

            \[\leadsto x \cdot \color{blue}{\left(\mathsf{neg}\left(y \cdot z\right)\right)} \]
          2. distribute-rgt-neg-inN/A

            \[\leadsto x \cdot \color{blue}{\left(y \cdot \left(\mathsf{neg}\left(z\right)\right)\right)} \]
          3. mul-1-negN/A

            \[\leadsto x \cdot \left(y \cdot \color{blue}{\left(-1 \cdot z\right)}\right) \]
          4. *-lowering-*.f64N/A

            \[\leadsto x \cdot \color{blue}{\left(y \cdot \left(-1 \cdot z\right)\right)} \]
          5. mul-1-negN/A

            \[\leadsto x \cdot \left(y \cdot \color{blue}{\left(\mathsf{neg}\left(z\right)\right)}\right) \]
          6. neg-lowering-neg.f6490.8

            \[\leadsto x \cdot \left(y \cdot \color{blue}{\left(-z\right)}\right) \]
        5. Simplified90.8%

          \[\leadsto x \cdot \color{blue}{\left(y \cdot \left(-z\right)\right)} \]

        if -500 < (*.f64 y z) < 2.00000000000000016e-5

        1. Initial program 100.0%

          \[x \cdot \left(1 - y \cdot z\right) \]
        2. Add Preprocessing
        3. Taylor expanded in y around 0

          \[\leadsto \color{blue}{x} \]
        4. Step-by-step derivation
          1. Simplified98.6%

            \[\leadsto \color{blue}{x} \]
        5. Recombined 2 regimes into one program.
        6. Final simplification94.9%

          \[\leadsto \begin{array}{l} \mathbf{if}\;y \cdot z \leq -500:\\ \;\;\;\;-\left(y \cdot z\right) \cdot x\\ \mathbf{elif}\;y \cdot z \leq 2 \cdot 10^{-5}:\\ \;\;\;\;x\\ \mathbf{else}:\\ \;\;\;\;-\left(y \cdot z\right) \cdot x\\ \end{array} \]
        7. Add Preprocessing

        Alternative 5: 97.3% accurate, 0.5× speedup?

        \[\begin{array}{l} [x, y, z] = \mathsf{sort}([x, y, z])\\ \\ \begin{array}{l} t_0 := 1 - y \cdot z\\ \mathbf{if}\;t\_0 \leq -5 \cdot 10^{+94}:\\ \;\;\;\;-z \cdot \left(y \cdot x\right)\\ \mathbf{else}:\\ \;\;\;\;t\_0 \cdot x\\ \end{array} \end{array} \]
        NOTE: x, y, and z should be sorted in increasing order before calling this function.
        (FPCore (x y z)
         :precision binary64
         (let* ((t_0 (- 1.0 (* y z))))
           (if (<= t_0 -5e+94) (- (* z (* y x))) (* t_0 x))))
        assert(x < y && y < z);
        double code(double x, double y, double z) {
        	double t_0 = 1.0 - (y * z);
        	double tmp;
        	if (t_0 <= -5e+94) {
        		tmp = -(z * (y * x));
        	} else {
        		tmp = t_0 * x;
        	}
        	return tmp;
        }
        
        NOTE: x, y, and z should be sorted in increasing order before calling this function.
        real(8) function code(x, y, z)
            real(8), intent (in) :: x
            real(8), intent (in) :: y
            real(8), intent (in) :: z
            real(8) :: t_0
            real(8) :: tmp
            t_0 = 1.0d0 - (y * z)
            if (t_0 <= (-5d+94)) then
                tmp = -(z * (y * x))
            else
                tmp = t_0 * x
            end if
            code = tmp
        end function
        
        assert x < y && y < z;
        public static double code(double x, double y, double z) {
        	double t_0 = 1.0 - (y * z);
        	double tmp;
        	if (t_0 <= -5e+94) {
        		tmp = -(z * (y * x));
        	} else {
        		tmp = t_0 * x;
        	}
        	return tmp;
        }
        
        [x, y, z] = sort([x, y, z])
        def code(x, y, z):
        	t_0 = 1.0 - (y * z)
        	tmp = 0
        	if t_0 <= -5e+94:
        		tmp = -(z * (y * x))
        	else:
        		tmp = t_0 * x
        	return tmp
        
        x, y, z = sort([x, y, z])
        function code(x, y, z)
        	t_0 = Float64(1.0 - Float64(y * z))
        	tmp = 0.0
        	if (t_0 <= -5e+94)
        		tmp = Float64(-Float64(z * Float64(y * x)));
        	else
        		tmp = Float64(t_0 * x);
        	end
        	return tmp
        end
        
        x, y, z = num2cell(sort([x, y, z])){:}
        function tmp_2 = code(x, y, z)
        	t_0 = 1.0 - (y * z);
        	tmp = 0.0;
        	if (t_0 <= -5e+94)
        		tmp = -(z * (y * x));
        	else
        		tmp = t_0 * x;
        	end
        	tmp_2 = tmp;
        end
        
        NOTE: x, y, and z should be sorted in increasing order before calling this function.
        code[x_, y_, z_] := Block[{t$95$0 = N[(1.0 - N[(y * z), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[t$95$0, -5e+94], (-N[(z * N[(y * x), $MachinePrecision]), $MachinePrecision]), N[(t$95$0 * x), $MachinePrecision]]]
        
        \begin{array}{l}
        [x, y, z] = \mathsf{sort}([x, y, z])\\
        \\
        \begin{array}{l}
        t_0 := 1 - y \cdot z\\
        \mathbf{if}\;t\_0 \leq -5 \cdot 10^{+94}:\\
        \;\;\;\;-z \cdot \left(y \cdot x\right)\\
        
        \mathbf{else}:\\
        \;\;\;\;t\_0 \cdot x\\
        
        
        \end{array}
        \end{array}
        
        Derivation
        1. Split input into 2 regimes
        2. if (-.f64 #s(literal 1 binary64) (*.f64 y z)) < -5.0000000000000001e94

          1. Initial program 86.2%

            \[x \cdot \left(1 - y \cdot z\right) \]
          2. Add Preprocessing
          3. Taylor expanded in y around inf

            \[\leadsto \color{blue}{-1 \cdot \left(x \cdot \left(y \cdot z\right)\right)} \]
          4. Step-by-step derivation
            1. associate-*r*N/A

              \[\leadsto \color{blue}{\left(-1 \cdot x\right) \cdot \left(y \cdot z\right)} \]
            2. *-commutativeN/A

              \[\leadsto \left(-1 \cdot x\right) \cdot \color{blue}{\left(z \cdot y\right)} \]
            3. associate-*r*N/A

              \[\leadsto \color{blue}{\left(\left(-1 \cdot x\right) \cdot z\right) \cdot y} \]
            4. associate-*r*N/A

              \[\leadsto \color{blue}{\left(-1 \cdot \left(x \cdot z\right)\right)} \cdot y \]
            5. *-commutativeN/A

              \[\leadsto \color{blue}{y \cdot \left(-1 \cdot \left(x \cdot z\right)\right)} \]
            6. *-lowering-*.f64N/A

              \[\leadsto \color{blue}{y \cdot \left(-1 \cdot \left(x \cdot z\right)\right)} \]
            7. associate-*r*N/A

              \[\leadsto y \cdot \color{blue}{\left(\left(-1 \cdot x\right) \cdot z\right)} \]
            8. *-commutativeN/A

              \[\leadsto y \cdot \color{blue}{\left(z \cdot \left(-1 \cdot x\right)\right)} \]
            9. *-lowering-*.f64N/A

              \[\leadsto y \cdot \color{blue}{\left(z \cdot \left(-1 \cdot x\right)\right)} \]
            10. mul-1-negN/A

              \[\leadsto y \cdot \left(z \cdot \color{blue}{\left(\mathsf{neg}\left(x\right)\right)}\right) \]
            11. neg-lowering-neg.f6495.9

              \[\leadsto y \cdot \left(z \cdot \color{blue}{\left(-x\right)}\right) \]
          5. Simplified95.9%

            \[\leadsto \color{blue}{y \cdot \left(z \cdot \left(-x\right)\right)} \]
          6. Step-by-step derivation
            1. *-commutativeN/A

              \[\leadsto y \cdot \color{blue}{\left(\left(\mathsf{neg}\left(x\right)\right) \cdot z\right)} \]
            2. associate-*r*N/A

              \[\leadsto \color{blue}{\left(y \cdot \left(\mathsf{neg}\left(x\right)\right)\right) \cdot z} \]
            3. *-lowering-*.f64N/A

              \[\leadsto \color{blue}{\left(y \cdot \left(\mathsf{neg}\left(x\right)\right)\right) \cdot z} \]
            4. *-lowering-*.f64N/A

              \[\leadsto \color{blue}{\left(y \cdot \left(\mathsf{neg}\left(x\right)\right)\right)} \cdot z \]
            5. neg-lowering-neg.f6495.9

              \[\leadsto \left(y \cdot \color{blue}{\left(-x\right)}\right) \cdot z \]
          7. Applied egg-rr95.9%

            \[\leadsto \color{blue}{\left(y \cdot \left(-x\right)\right) \cdot z} \]

          if -5.0000000000000001e94 < (-.f64 #s(literal 1 binary64) (*.f64 y z))

          1. Initial program 98.9%

            \[x \cdot \left(1 - y \cdot z\right) \]
          2. Add Preprocessing
        3. Recombined 2 regimes into one program.
        4. Final simplification98.4%

          \[\leadsto \begin{array}{l} \mathbf{if}\;1 - y \cdot z \leq -5 \cdot 10^{+94}:\\ \;\;\;\;-z \cdot \left(y \cdot x\right)\\ \mathbf{else}:\\ \;\;\;\;\left(1 - y \cdot z\right) \cdot x\\ \end{array} \]
        5. Add Preprocessing

        Alternative 6: 50.8% accurate, 14.0× speedup?

        \[\begin{array}{l} [x, y, z] = \mathsf{sort}([x, y, z])\\ \\ x \end{array} \]
        NOTE: x, y, and z should be sorted in increasing order before calling this function.
        (FPCore (x y z) :precision binary64 x)
        assert(x < y && y < z);
        double code(double x, double y, double z) {
        	return x;
        }
        
        NOTE: x, y, and z should be sorted in increasing order before calling this function.
        real(8) function code(x, y, z)
            real(8), intent (in) :: x
            real(8), intent (in) :: y
            real(8), intent (in) :: z
            code = x
        end function
        
        assert x < y && y < z;
        public static double code(double x, double y, double z) {
        	return x;
        }
        
        [x, y, z] = sort([x, y, z])
        def code(x, y, z):
        	return x
        
        x, y, z = sort([x, y, z])
        function code(x, y, z)
        	return x
        end
        
        x, y, z = num2cell(sort([x, y, z])){:}
        function tmp = code(x, y, z)
        	tmp = x;
        end
        
        NOTE: x, y, and z should be sorted in increasing order before calling this function.
        code[x_, y_, z_] := x
        
        \begin{array}{l}
        [x, y, z] = \mathsf{sort}([x, y, z])\\
        \\
        x
        \end{array}
        
        Derivation
        1. Initial program 96.5%

          \[x \cdot \left(1 - y \cdot z\right) \]
        2. Add Preprocessing
        3. Taylor expanded in y around 0

          \[\leadsto \color{blue}{x} \]
        4. Step-by-step derivation
          1. Simplified53.7%

            \[\leadsto \color{blue}{x} \]
          2. Add Preprocessing

          Reproduce

          ?
          herbie shell --seed 2024204 
          (FPCore (x y z)
            :name "Data.Colour.RGBSpace.HSV:hsv from colour-2.3.3, I"
            :precision binary64
            (* x (- 1.0 (* y z))))