bug323 (missed optimization)

Percentage Accurate: 6.7% → 10.3%
Time: 9.7s
Alternatives: 9
Speedup: 1.0×

Specification

?
\[0 \leq x \land x \leq 0.5\]
\[\begin{array}{l} \\ \cos^{-1} \left(1 - x\right) \end{array} \]
(FPCore (x) :precision binary64 (acos (- 1.0 x)))
double code(double x) {
	return acos((1.0 - x));
}
real(8) function code(x)
    real(8), intent (in) :: x
    code = acos((1.0d0 - x))
end function
public static double code(double x) {
	return Math.acos((1.0 - x));
}
def code(x):
	return math.acos((1.0 - x))
function code(x)
	return acos(Float64(1.0 - x))
end
function tmp = code(x)
	tmp = acos((1.0 - x));
end
code[x_] := N[ArcCos[N[(1.0 - x), $MachinePrecision]], $MachinePrecision]
\begin{array}{l}

\\
\cos^{-1} \left(1 - x\right)
\end{array}

Sampling outcomes in binary64 precision:

Local Percentage Accuracy vs ?

The average percentage accuracy by input value. Horizontal axis shows value of an input variable; the variable is choosen in the title. Vertical axis is accuracy; higher is better. Red represent the original program, while blue represents Herbie's suggestion. These can be toggled with buttons below the plot. The line is an average while dots represent individual samples.

Accuracy vs Speed?

Herbie found 9 alternatives:

AlternativeAccuracySpeedup
The accuracy (vertical axis) and speed (horizontal axis) of each alternatives. Up and to the right is better. The red square shows the initial program, and each blue circle shows an alternative.The line shows the best available speed-accuracy tradeoffs.

Initial Program: 6.7% accurate, 1.0× speedup?

\[\begin{array}{l} \\ \cos^{-1} \left(1 - x\right) \end{array} \]
(FPCore (x) :precision binary64 (acos (- 1.0 x)))
double code(double x) {
	return acos((1.0 - x));
}
real(8) function code(x)
    real(8), intent (in) :: x
    code = acos((1.0d0 - x))
end function
public static double code(double x) {
	return Math.acos((1.0 - x));
}
def code(x):
	return math.acos((1.0 - x))
function code(x)
	return acos(Float64(1.0 - x))
end
function tmp = code(x)
	tmp = acos((1.0 - x));
end
code[x_] := N[ArcCos[N[(1.0 - x), $MachinePrecision]], $MachinePrecision]
\begin{array}{l}

\\
\cos^{-1} \left(1 - x\right)
\end{array}

Alternative 1: 10.3% accurate, 0.1× speedup?

\[\begin{array}{l} \\ \begin{array}{l} t_0 := \mathsf{fma}\left(\pi, \pi \cdot 0.25, \sin^{-1} 1 \cdot \mathsf{fma}\left(\pi, 0.5, \sin^{-1} 1\right)\right)\\ \mathbf{if}\;x \leq 5.6 \cdot 10^{-17}:\\ \;\;\;\;\frac{\mathsf{fma}\left(\left(\pi \cdot \left(\pi \cdot \pi\right)\right) \cdot 0.125, t\_0, t\_0 \cdot \left(-{\sin^{-1} 1}^{3}\right)\right)}{{t\_0}^{2}}\\ \mathbf{else}:\\ \;\;\;\;\cos^{-1} \left(1 - x\right)\\ \end{array} \end{array} \]
(FPCore (x)
 :precision binary64
 (let* ((t_0 (fma PI (* PI 0.25) (* (asin 1.0) (fma PI 0.5 (asin 1.0))))))
   (if (<= x 5.6e-17)
     (/
      (fma (* (* PI (* PI PI)) 0.125) t_0 (* t_0 (- (pow (asin 1.0) 3.0))))
      (pow t_0 2.0))
     (acos (- 1.0 x)))))
double code(double x) {
	double t_0 = fma(((double) M_PI), (((double) M_PI) * 0.25), (asin(1.0) * fma(((double) M_PI), 0.5, asin(1.0))));
	double tmp;
	if (x <= 5.6e-17) {
		tmp = fma(((((double) M_PI) * (((double) M_PI) * ((double) M_PI))) * 0.125), t_0, (t_0 * -pow(asin(1.0), 3.0))) / pow(t_0, 2.0);
	} else {
		tmp = acos((1.0 - x));
	}
	return tmp;
}
function code(x)
	t_0 = fma(pi, Float64(pi * 0.25), Float64(asin(1.0) * fma(pi, 0.5, asin(1.0))))
	tmp = 0.0
	if (x <= 5.6e-17)
		tmp = Float64(fma(Float64(Float64(pi * Float64(pi * pi)) * 0.125), t_0, Float64(t_0 * Float64(-(asin(1.0) ^ 3.0)))) / (t_0 ^ 2.0));
	else
		tmp = acos(Float64(1.0 - x));
	end
	return tmp
end
code[x_] := Block[{t$95$0 = N[(Pi * N[(Pi * 0.25), $MachinePrecision] + N[(N[ArcSin[1.0], $MachinePrecision] * N[(Pi * 0.5 + N[ArcSin[1.0], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[x, 5.6e-17], N[(N[(N[(N[(Pi * N[(Pi * Pi), $MachinePrecision]), $MachinePrecision] * 0.125), $MachinePrecision] * t$95$0 + N[(t$95$0 * (-N[Power[N[ArcSin[1.0], $MachinePrecision], 3.0], $MachinePrecision])), $MachinePrecision]), $MachinePrecision] / N[Power[t$95$0, 2.0], $MachinePrecision]), $MachinePrecision], N[ArcCos[N[(1.0 - x), $MachinePrecision]], $MachinePrecision]]]
\begin{array}{l}

\\
\begin{array}{l}
t_0 := \mathsf{fma}\left(\pi, \pi \cdot 0.25, \sin^{-1} 1 \cdot \mathsf{fma}\left(\pi, 0.5, \sin^{-1} 1\right)\right)\\
\mathbf{if}\;x \leq 5.6 \cdot 10^{-17}:\\
\;\;\;\;\frac{\mathsf{fma}\left(\left(\pi \cdot \left(\pi \cdot \pi\right)\right) \cdot 0.125, t\_0, t\_0 \cdot \left(-{\sin^{-1} 1}^{3}\right)\right)}{{t\_0}^{2}}\\

\mathbf{else}:\\
\;\;\;\;\cos^{-1} \left(1 - x\right)\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if x < 5.5999999999999998e-17

    1. Initial program 3.9%

      \[\cos^{-1} \left(1 - x\right) \]
    2. Add Preprocessing
    3. Taylor expanded in x around 0

      \[\leadsto \cos^{-1} \color{blue}{1} \]
    4. Step-by-step derivation
      1. Simplified3.9%

        \[\leadsto \cos^{-1} \color{blue}{1} \]
      2. Step-by-step derivation
        1. acos-asinN/A

          \[\leadsto \color{blue}{\frac{\mathsf{PI}\left(\right)}{2} - \sin^{-1} 1} \]
        2. flip3--N/A

          \[\leadsto \color{blue}{\frac{{\left(\frac{\mathsf{PI}\left(\right)}{2}\right)}^{3} - {\sin^{-1} 1}^{3}}{\frac{\mathsf{PI}\left(\right)}{2} \cdot \frac{\mathsf{PI}\left(\right)}{2} + \left(\sin^{-1} 1 \cdot \sin^{-1} 1 + \frac{\mathsf{PI}\left(\right)}{2} \cdot \sin^{-1} 1\right)}} \]
        3. div-subN/A

          \[\leadsto \color{blue}{\frac{{\left(\frac{\mathsf{PI}\left(\right)}{2}\right)}^{3}}{\frac{\mathsf{PI}\left(\right)}{2} \cdot \frac{\mathsf{PI}\left(\right)}{2} + \left(\sin^{-1} 1 \cdot \sin^{-1} 1 + \frac{\mathsf{PI}\left(\right)}{2} \cdot \sin^{-1} 1\right)} - \frac{{\sin^{-1} 1}^{3}}{\frac{\mathsf{PI}\left(\right)}{2} \cdot \frac{\mathsf{PI}\left(\right)}{2} + \left(\sin^{-1} 1 \cdot \sin^{-1} 1 + \frac{\mathsf{PI}\left(\right)}{2} \cdot \sin^{-1} 1\right)}} \]
        4. sub-negN/A

          \[\leadsto \color{blue}{\frac{{\left(\frac{\mathsf{PI}\left(\right)}{2}\right)}^{3}}{\frac{\mathsf{PI}\left(\right)}{2} \cdot \frac{\mathsf{PI}\left(\right)}{2} + \left(\sin^{-1} 1 \cdot \sin^{-1} 1 + \frac{\mathsf{PI}\left(\right)}{2} \cdot \sin^{-1} 1\right)} + \left(\mathsf{neg}\left(\frac{{\sin^{-1} 1}^{3}}{\frac{\mathsf{PI}\left(\right)}{2} \cdot \frac{\mathsf{PI}\left(\right)}{2} + \left(\sin^{-1} 1 \cdot \sin^{-1} 1 + \frac{\mathsf{PI}\left(\right)}{2} \cdot \sin^{-1} 1\right)}\right)\right)} \]
        5. div-invN/A

          \[\leadsto \color{blue}{{\left(\frac{\mathsf{PI}\left(\right)}{2}\right)}^{3} \cdot \frac{1}{\frac{\mathsf{PI}\left(\right)}{2} \cdot \frac{\mathsf{PI}\left(\right)}{2} + \left(\sin^{-1} 1 \cdot \sin^{-1} 1 + \frac{\mathsf{PI}\left(\right)}{2} \cdot \sin^{-1} 1\right)}} + \left(\mathsf{neg}\left(\frac{{\sin^{-1} 1}^{3}}{\frac{\mathsf{PI}\left(\right)}{2} \cdot \frac{\mathsf{PI}\left(\right)}{2} + \left(\sin^{-1} 1 \cdot \sin^{-1} 1 + \frac{\mathsf{PI}\left(\right)}{2} \cdot \sin^{-1} 1\right)}\right)\right) \]
        6. accelerator-lowering-fma.f64N/A

          \[\leadsto \color{blue}{\mathsf{fma}\left({\left(\frac{\mathsf{PI}\left(\right)}{2}\right)}^{3}, \frac{1}{\frac{\mathsf{PI}\left(\right)}{2} \cdot \frac{\mathsf{PI}\left(\right)}{2} + \left(\sin^{-1} 1 \cdot \sin^{-1} 1 + \frac{\mathsf{PI}\left(\right)}{2} \cdot \sin^{-1} 1\right)}, \mathsf{neg}\left(\frac{{\sin^{-1} 1}^{3}}{\frac{\mathsf{PI}\left(\right)}{2} \cdot \frac{\mathsf{PI}\left(\right)}{2} + \left(\sin^{-1} 1 \cdot \sin^{-1} 1 + \frac{\mathsf{PI}\left(\right)}{2} \cdot \sin^{-1} 1\right)}\right)\right)} \]
      3. Applied egg-rr7.6%

        \[\leadsto \color{blue}{\mathsf{fma}\left(\left(\pi \cdot \left(\pi \cdot \pi\right)\right) \cdot 0.125, \frac{1}{\mathsf{fma}\left(\sin^{-1} 1, \mathsf{fma}\left(\pi, 0.5, \sin^{-1} 1\right), \left(\pi \cdot \pi\right) \cdot 0.25\right)}, -\frac{{\sin^{-1} 1}^{3}}{\mathsf{fma}\left(\sin^{-1} 1, \mathsf{fma}\left(\pi, 0.5, \sin^{-1} 1\right), \left(\pi \cdot \pi\right) \cdot 0.25\right)}\right)} \]
      4. Step-by-step derivation
        1. un-div-invN/A

          \[\leadsto \color{blue}{\frac{\left(\mathsf{PI}\left(\right) \cdot \left(\mathsf{PI}\left(\right) \cdot \mathsf{PI}\left(\right)\right)\right) \cdot \frac{1}{8}}{\sin^{-1} 1 \cdot \left(\mathsf{PI}\left(\right) \cdot \frac{1}{2} + \sin^{-1} 1\right) + \left(\mathsf{PI}\left(\right) \cdot \mathsf{PI}\left(\right)\right) \cdot \frac{1}{4}}} + \left(\mathsf{neg}\left(\frac{{\sin^{-1} 1}^{3}}{\sin^{-1} 1 \cdot \left(\mathsf{PI}\left(\right) \cdot \frac{1}{2} + \sin^{-1} 1\right) + \left(\mathsf{PI}\left(\right) \cdot \mathsf{PI}\left(\right)\right) \cdot \frac{1}{4}}\right)\right) \]
        2. distribute-neg-fracN/A

          \[\leadsto \frac{\left(\mathsf{PI}\left(\right) \cdot \left(\mathsf{PI}\left(\right) \cdot \mathsf{PI}\left(\right)\right)\right) \cdot \frac{1}{8}}{\sin^{-1} 1 \cdot \left(\mathsf{PI}\left(\right) \cdot \frac{1}{2} + \sin^{-1} 1\right) + \left(\mathsf{PI}\left(\right) \cdot \mathsf{PI}\left(\right)\right) \cdot \frac{1}{4}} + \color{blue}{\frac{\mathsf{neg}\left({\sin^{-1} 1}^{3}\right)}{\sin^{-1} 1 \cdot \left(\mathsf{PI}\left(\right) \cdot \frac{1}{2} + \sin^{-1} 1\right) + \left(\mathsf{PI}\left(\right) \cdot \mathsf{PI}\left(\right)\right) \cdot \frac{1}{4}}} \]
        3. frac-addN/A

          \[\leadsto \color{blue}{\frac{\left(\left(\mathsf{PI}\left(\right) \cdot \left(\mathsf{PI}\left(\right) \cdot \mathsf{PI}\left(\right)\right)\right) \cdot \frac{1}{8}\right) \cdot \left(\sin^{-1} 1 \cdot \left(\mathsf{PI}\left(\right) \cdot \frac{1}{2} + \sin^{-1} 1\right) + \left(\mathsf{PI}\left(\right) \cdot \mathsf{PI}\left(\right)\right) \cdot \frac{1}{4}\right) + \left(\sin^{-1} 1 \cdot \left(\mathsf{PI}\left(\right) \cdot \frac{1}{2} + \sin^{-1} 1\right) + \left(\mathsf{PI}\left(\right) \cdot \mathsf{PI}\left(\right)\right) \cdot \frac{1}{4}\right) \cdot \left(\mathsf{neg}\left({\sin^{-1} 1}^{3}\right)\right)}{\left(\sin^{-1} 1 \cdot \left(\mathsf{PI}\left(\right) \cdot \frac{1}{2} + \sin^{-1} 1\right) + \left(\mathsf{PI}\left(\right) \cdot \mathsf{PI}\left(\right)\right) \cdot \frac{1}{4}\right) \cdot \left(\sin^{-1} 1 \cdot \left(\mathsf{PI}\left(\right) \cdot \frac{1}{2} + \sin^{-1} 1\right) + \left(\mathsf{PI}\left(\right) \cdot \mathsf{PI}\left(\right)\right) \cdot \frac{1}{4}\right)}} \]
      5. Applied egg-rr7.7%

        \[\leadsto \color{blue}{\frac{\mathsf{fma}\left(\left(\pi \cdot \left(\pi \cdot \pi\right)\right) \cdot 0.125, \mathsf{fma}\left(\pi, \pi \cdot 0.25, \sin^{-1} 1 \cdot \mathsf{fma}\left(\pi, 0.5, \sin^{-1} 1\right)\right), \mathsf{fma}\left(\pi, \pi \cdot 0.25, \sin^{-1} 1 \cdot \mathsf{fma}\left(\pi, 0.5, \sin^{-1} 1\right)\right) \cdot \left(-{\sin^{-1} 1}^{3}\right)\right)}{{\left(\mathsf{fma}\left(\pi, \pi \cdot 0.25, \sin^{-1} 1 \cdot \mathsf{fma}\left(\pi, 0.5, \sin^{-1} 1\right)\right)\right)}^{2}}} \]

      if 5.5999999999999998e-17 < x

      1. Initial program 68.8%

        \[\cos^{-1} \left(1 - x\right) \]
      2. Add Preprocessing
    5. Recombined 2 regimes into one program.
    6. Add Preprocessing

    Alternative 2: 10.3% accurate, 0.2× speedup?

    \[\begin{array}{l} \\ \begin{array}{l} t_0 := \mathsf{fma}\left(\pi, \pi \cdot 0.25, \sin^{-1} 1 \cdot \mathsf{fma}\left(\pi, 0.5, \sin^{-1} 1\right)\right)\\ \mathbf{if}\;x \leq 5.6 \cdot 10^{-17}:\\ \;\;\;\;\mathsf{fma}\left(\frac{0.125}{t\_0}, \pi \cdot \left(\pi \cdot \pi\right), \frac{-{\sin^{-1} 1}^{3}}{t\_0}\right)\\ \mathbf{else}:\\ \;\;\;\;\cos^{-1} \left(1 - x\right)\\ \end{array} \end{array} \]
    (FPCore (x)
     :precision binary64
     (let* ((t_0 (fma PI (* PI 0.25) (* (asin 1.0) (fma PI 0.5 (asin 1.0))))))
       (if (<= x 5.6e-17)
         (fma (/ 0.125 t_0) (* PI (* PI PI)) (/ (- (pow (asin 1.0) 3.0)) t_0))
         (acos (- 1.0 x)))))
    double code(double x) {
    	double t_0 = fma(((double) M_PI), (((double) M_PI) * 0.25), (asin(1.0) * fma(((double) M_PI), 0.5, asin(1.0))));
    	double tmp;
    	if (x <= 5.6e-17) {
    		tmp = fma((0.125 / t_0), (((double) M_PI) * (((double) M_PI) * ((double) M_PI))), (-pow(asin(1.0), 3.0) / t_0));
    	} else {
    		tmp = acos((1.0 - x));
    	}
    	return tmp;
    }
    
    function code(x)
    	t_0 = fma(pi, Float64(pi * 0.25), Float64(asin(1.0) * fma(pi, 0.5, asin(1.0))))
    	tmp = 0.0
    	if (x <= 5.6e-17)
    		tmp = fma(Float64(0.125 / t_0), Float64(pi * Float64(pi * pi)), Float64(Float64(-(asin(1.0) ^ 3.0)) / t_0));
    	else
    		tmp = acos(Float64(1.0 - x));
    	end
    	return tmp
    end
    
    code[x_] := Block[{t$95$0 = N[(Pi * N[(Pi * 0.25), $MachinePrecision] + N[(N[ArcSin[1.0], $MachinePrecision] * N[(Pi * 0.5 + N[ArcSin[1.0], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[x, 5.6e-17], N[(N[(0.125 / t$95$0), $MachinePrecision] * N[(Pi * N[(Pi * Pi), $MachinePrecision]), $MachinePrecision] + N[((-N[Power[N[ArcSin[1.0], $MachinePrecision], 3.0], $MachinePrecision]) / t$95$0), $MachinePrecision]), $MachinePrecision], N[ArcCos[N[(1.0 - x), $MachinePrecision]], $MachinePrecision]]]
    
    \begin{array}{l}
    
    \\
    \begin{array}{l}
    t_0 := \mathsf{fma}\left(\pi, \pi \cdot 0.25, \sin^{-1} 1 \cdot \mathsf{fma}\left(\pi, 0.5, \sin^{-1} 1\right)\right)\\
    \mathbf{if}\;x \leq 5.6 \cdot 10^{-17}:\\
    \;\;\;\;\mathsf{fma}\left(\frac{0.125}{t\_0}, \pi \cdot \left(\pi \cdot \pi\right), \frac{-{\sin^{-1} 1}^{3}}{t\_0}\right)\\
    
    \mathbf{else}:\\
    \;\;\;\;\cos^{-1} \left(1 - x\right)\\
    
    
    \end{array}
    \end{array}
    
    Derivation
    1. Split input into 2 regimes
    2. if x < 5.5999999999999998e-17

      1. Initial program 3.9%

        \[\cos^{-1} \left(1 - x\right) \]
      2. Add Preprocessing
      3. Taylor expanded in x around 0

        \[\leadsto \cos^{-1} \color{blue}{1} \]
      4. Step-by-step derivation
        1. Simplified3.9%

          \[\leadsto \cos^{-1} \color{blue}{1} \]
        2. Step-by-step derivation
          1. acos-asinN/A

            \[\leadsto \color{blue}{\frac{\mathsf{PI}\left(\right)}{2} - \sin^{-1} 1} \]
          2. flip3--N/A

            \[\leadsto \color{blue}{\frac{{\left(\frac{\mathsf{PI}\left(\right)}{2}\right)}^{3} - {\sin^{-1} 1}^{3}}{\frac{\mathsf{PI}\left(\right)}{2} \cdot \frac{\mathsf{PI}\left(\right)}{2} + \left(\sin^{-1} 1 \cdot \sin^{-1} 1 + \frac{\mathsf{PI}\left(\right)}{2} \cdot \sin^{-1} 1\right)}} \]
          3. div-subN/A

            \[\leadsto \color{blue}{\frac{{\left(\frac{\mathsf{PI}\left(\right)}{2}\right)}^{3}}{\frac{\mathsf{PI}\left(\right)}{2} \cdot \frac{\mathsf{PI}\left(\right)}{2} + \left(\sin^{-1} 1 \cdot \sin^{-1} 1 + \frac{\mathsf{PI}\left(\right)}{2} \cdot \sin^{-1} 1\right)} - \frac{{\sin^{-1} 1}^{3}}{\frac{\mathsf{PI}\left(\right)}{2} \cdot \frac{\mathsf{PI}\left(\right)}{2} + \left(\sin^{-1} 1 \cdot \sin^{-1} 1 + \frac{\mathsf{PI}\left(\right)}{2} \cdot \sin^{-1} 1\right)}} \]
          4. sub-negN/A

            \[\leadsto \color{blue}{\frac{{\left(\frac{\mathsf{PI}\left(\right)}{2}\right)}^{3}}{\frac{\mathsf{PI}\left(\right)}{2} \cdot \frac{\mathsf{PI}\left(\right)}{2} + \left(\sin^{-1} 1 \cdot \sin^{-1} 1 + \frac{\mathsf{PI}\left(\right)}{2} \cdot \sin^{-1} 1\right)} + \left(\mathsf{neg}\left(\frac{{\sin^{-1} 1}^{3}}{\frac{\mathsf{PI}\left(\right)}{2} \cdot \frac{\mathsf{PI}\left(\right)}{2} + \left(\sin^{-1} 1 \cdot \sin^{-1} 1 + \frac{\mathsf{PI}\left(\right)}{2} \cdot \sin^{-1} 1\right)}\right)\right)} \]
          5. div-invN/A

            \[\leadsto \color{blue}{{\left(\frac{\mathsf{PI}\left(\right)}{2}\right)}^{3} \cdot \frac{1}{\frac{\mathsf{PI}\left(\right)}{2} \cdot \frac{\mathsf{PI}\left(\right)}{2} + \left(\sin^{-1} 1 \cdot \sin^{-1} 1 + \frac{\mathsf{PI}\left(\right)}{2} \cdot \sin^{-1} 1\right)}} + \left(\mathsf{neg}\left(\frac{{\sin^{-1} 1}^{3}}{\frac{\mathsf{PI}\left(\right)}{2} \cdot \frac{\mathsf{PI}\left(\right)}{2} + \left(\sin^{-1} 1 \cdot \sin^{-1} 1 + \frac{\mathsf{PI}\left(\right)}{2} \cdot \sin^{-1} 1\right)}\right)\right) \]
          6. accelerator-lowering-fma.f64N/A

            \[\leadsto \color{blue}{\mathsf{fma}\left({\left(\frac{\mathsf{PI}\left(\right)}{2}\right)}^{3}, \frac{1}{\frac{\mathsf{PI}\left(\right)}{2} \cdot \frac{\mathsf{PI}\left(\right)}{2} + \left(\sin^{-1} 1 \cdot \sin^{-1} 1 + \frac{\mathsf{PI}\left(\right)}{2} \cdot \sin^{-1} 1\right)}, \mathsf{neg}\left(\frac{{\sin^{-1} 1}^{3}}{\frac{\mathsf{PI}\left(\right)}{2} \cdot \frac{\mathsf{PI}\left(\right)}{2} + \left(\sin^{-1} 1 \cdot \sin^{-1} 1 + \frac{\mathsf{PI}\left(\right)}{2} \cdot \sin^{-1} 1\right)}\right)\right)} \]
        3. Applied egg-rr7.6%

          \[\leadsto \color{blue}{\mathsf{fma}\left(\left(\pi \cdot \left(\pi \cdot \pi\right)\right) \cdot 0.125, \frac{1}{\mathsf{fma}\left(\sin^{-1} 1, \mathsf{fma}\left(\pi, 0.5, \sin^{-1} 1\right), \left(\pi \cdot \pi\right) \cdot 0.25\right)}, -\frac{{\sin^{-1} 1}^{3}}{\mathsf{fma}\left(\sin^{-1} 1, \mathsf{fma}\left(\pi, 0.5, \sin^{-1} 1\right), \left(\pi \cdot \pi\right) \cdot 0.25\right)}\right)} \]
        4. Step-by-step derivation
          1. associate-*l*N/A

            \[\leadsto \color{blue}{\left(\mathsf{PI}\left(\right) \cdot \left(\mathsf{PI}\left(\right) \cdot \mathsf{PI}\left(\right)\right)\right) \cdot \left(\frac{1}{8} \cdot \frac{1}{\sin^{-1} 1 \cdot \left(\mathsf{PI}\left(\right) \cdot \frac{1}{2} + \sin^{-1} 1\right) + \left(\mathsf{PI}\left(\right) \cdot \mathsf{PI}\left(\right)\right) \cdot \frac{1}{4}}\right)} + \left(\mathsf{neg}\left(\frac{{\sin^{-1} 1}^{3}}{\sin^{-1} 1 \cdot \left(\mathsf{PI}\left(\right) \cdot \frac{1}{2} + \sin^{-1} 1\right) + \left(\mathsf{PI}\left(\right) \cdot \mathsf{PI}\left(\right)\right) \cdot \frac{1}{4}}\right)\right) \]
          2. *-commutativeN/A

            \[\leadsto \color{blue}{\left(\frac{1}{8} \cdot \frac{1}{\sin^{-1} 1 \cdot \left(\mathsf{PI}\left(\right) \cdot \frac{1}{2} + \sin^{-1} 1\right) + \left(\mathsf{PI}\left(\right) \cdot \mathsf{PI}\left(\right)\right) \cdot \frac{1}{4}}\right) \cdot \left(\mathsf{PI}\left(\right) \cdot \left(\mathsf{PI}\left(\right) \cdot \mathsf{PI}\left(\right)\right)\right)} + \left(\mathsf{neg}\left(\frac{{\sin^{-1} 1}^{3}}{\sin^{-1} 1 \cdot \left(\mathsf{PI}\left(\right) \cdot \frac{1}{2} + \sin^{-1} 1\right) + \left(\mathsf{PI}\left(\right) \cdot \mathsf{PI}\left(\right)\right) \cdot \frac{1}{4}}\right)\right) \]
          3. accelerator-lowering-fma.f64N/A

            \[\leadsto \color{blue}{\mathsf{fma}\left(\frac{1}{8} \cdot \frac{1}{\sin^{-1} 1 \cdot \left(\mathsf{PI}\left(\right) \cdot \frac{1}{2} + \sin^{-1} 1\right) + \left(\mathsf{PI}\left(\right) \cdot \mathsf{PI}\left(\right)\right) \cdot \frac{1}{4}}, \mathsf{PI}\left(\right) \cdot \left(\mathsf{PI}\left(\right) \cdot \mathsf{PI}\left(\right)\right), \mathsf{neg}\left(\frac{{\sin^{-1} 1}^{3}}{\sin^{-1} 1 \cdot \left(\mathsf{PI}\left(\right) \cdot \frac{1}{2} + \sin^{-1} 1\right) + \left(\mathsf{PI}\left(\right) \cdot \mathsf{PI}\left(\right)\right) \cdot \frac{1}{4}}\right)\right)} \]
        5. Applied egg-rr7.6%

          \[\leadsto \color{blue}{\mathsf{fma}\left(\frac{0.125}{\mathsf{fma}\left(\pi, \pi \cdot 0.25, \sin^{-1} 1 \cdot \mathsf{fma}\left(\pi, 0.5, \sin^{-1} 1\right)\right)}, \pi \cdot \left(\pi \cdot \pi\right), -\frac{{\sin^{-1} 1}^{3}}{\mathsf{fma}\left(\pi, \pi \cdot 0.25, \sin^{-1} 1 \cdot \mathsf{fma}\left(\pi, 0.5, \sin^{-1} 1\right)\right)}\right)} \]

        if 5.5999999999999998e-17 < x

        1. Initial program 68.8%

          \[\cos^{-1} \left(1 - x\right) \]
        2. Add Preprocessing
      5. Recombined 2 regimes into one program.
      6. Final simplification9.7%

        \[\leadsto \begin{array}{l} \mathbf{if}\;x \leq 5.6 \cdot 10^{-17}:\\ \;\;\;\;\mathsf{fma}\left(\frac{0.125}{\mathsf{fma}\left(\pi, \pi \cdot 0.25, \sin^{-1} 1 \cdot \mathsf{fma}\left(\pi, 0.5, \sin^{-1} 1\right)\right)}, \pi \cdot \left(\pi \cdot \pi\right), \frac{-{\sin^{-1} 1}^{3}}{\mathsf{fma}\left(\pi, \pi \cdot 0.25, \sin^{-1} 1 \cdot \mathsf{fma}\left(\pi, 0.5, \sin^{-1} 1\right)\right)}\right)\\ \mathbf{else}:\\ \;\;\;\;\cos^{-1} \left(1 - x\right)\\ \end{array} \]
      7. Add Preprocessing

      Alternative 3: 10.3% accurate, 0.2× speedup?

      \[\begin{array}{l} \\ \begin{array}{l} t_0 := \mathsf{fma}\left(\pi, \pi \cdot 0.25, \sin^{-1} 1 \cdot \mathsf{fma}\left(\pi, 0.5, \sin^{-1} 1\right)\right)\\ \mathbf{if}\;x \leq 5.6 \cdot 10^{-17}:\\ \;\;\;\;\mathsf{fma}\left(\pi, \frac{\left(\pi \cdot \pi\right) \cdot 0.125}{t\_0}, \frac{-{\sin^{-1} 1}^{3}}{t\_0}\right)\\ \mathbf{else}:\\ \;\;\;\;\cos^{-1} \left(1 - x\right)\\ \end{array} \end{array} \]
      (FPCore (x)
       :precision binary64
       (let* ((t_0 (fma PI (* PI 0.25) (* (asin 1.0) (fma PI 0.5 (asin 1.0))))))
         (if (<= x 5.6e-17)
           (fma PI (/ (* (* PI PI) 0.125) t_0) (/ (- (pow (asin 1.0) 3.0)) t_0))
           (acos (- 1.0 x)))))
      double code(double x) {
      	double t_0 = fma(((double) M_PI), (((double) M_PI) * 0.25), (asin(1.0) * fma(((double) M_PI), 0.5, asin(1.0))));
      	double tmp;
      	if (x <= 5.6e-17) {
      		tmp = fma(((double) M_PI), (((((double) M_PI) * ((double) M_PI)) * 0.125) / t_0), (-pow(asin(1.0), 3.0) / t_0));
      	} else {
      		tmp = acos((1.0 - x));
      	}
      	return tmp;
      }
      
      function code(x)
      	t_0 = fma(pi, Float64(pi * 0.25), Float64(asin(1.0) * fma(pi, 0.5, asin(1.0))))
      	tmp = 0.0
      	if (x <= 5.6e-17)
      		tmp = fma(pi, Float64(Float64(Float64(pi * pi) * 0.125) / t_0), Float64(Float64(-(asin(1.0) ^ 3.0)) / t_0));
      	else
      		tmp = acos(Float64(1.0 - x));
      	end
      	return tmp
      end
      
      code[x_] := Block[{t$95$0 = N[(Pi * N[(Pi * 0.25), $MachinePrecision] + N[(N[ArcSin[1.0], $MachinePrecision] * N[(Pi * 0.5 + N[ArcSin[1.0], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[x, 5.6e-17], N[(Pi * N[(N[(N[(Pi * Pi), $MachinePrecision] * 0.125), $MachinePrecision] / t$95$0), $MachinePrecision] + N[((-N[Power[N[ArcSin[1.0], $MachinePrecision], 3.0], $MachinePrecision]) / t$95$0), $MachinePrecision]), $MachinePrecision], N[ArcCos[N[(1.0 - x), $MachinePrecision]], $MachinePrecision]]]
      
      \begin{array}{l}
      
      \\
      \begin{array}{l}
      t_0 := \mathsf{fma}\left(\pi, \pi \cdot 0.25, \sin^{-1} 1 \cdot \mathsf{fma}\left(\pi, 0.5, \sin^{-1} 1\right)\right)\\
      \mathbf{if}\;x \leq 5.6 \cdot 10^{-17}:\\
      \;\;\;\;\mathsf{fma}\left(\pi, \frac{\left(\pi \cdot \pi\right) \cdot 0.125}{t\_0}, \frac{-{\sin^{-1} 1}^{3}}{t\_0}\right)\\
      
      \mathbf{else}:\\
      \;\;\;\;\cos^{-1} \left(1 - x\right)\\
      
      
      \end{array}
      \end{array}
      
      Derivation
      1. Split input into 2 regimes
      2. if x < 5.5999999999999998e-17

        1. Initial program 3.9%

          \[\cos^{-1} \left(1 - x\right) \]
        2. Add Preprocessing
        3. Taylor expanded in x around 0

          \[\leadsto \cos^{-1} \color{blue}{1} \]
        4. Step-by-step derivation
          1. Simplified3.9%

            \[\leadsto \cos^{-1} \color{blue}{1} \]
          2. Step-by-step derivation
            1. acos-asinN/A

              \[\leadsto \color{blue}{\frac{\mathsf{PI}\left(\right)}{2} - \sin^{-1} 1} \]
            2. flip3--N/A

              \[\leadsto \color{blue}{\frac{{\left(\frac{\mathsf{PI}\left(\right)}{2}\right)}^{3} - {\sin^{-1} 1}^{3}}{\frac{\mathsf{PI}\left(\right)}{2} \cdot \frac{\mathsf{PI}\left(\right)}{2} + \left(\sin^{-1} 1 \cdot \sin^{-1} 1 + \frac{\mathsf{PI}\left(\right)}{2} \cdot \sin^{-1} 1\right)}} \]
            3. div-subN/A

              \[\leadsto \color{blue}{\frac{{\left(\frac{\mathsf{PI}\left(\right)}{2}\right)}^{3}}{\frac{\mathsf{PI}\left(\right)}{2} \cdot \frac{\mathsf{PI}\left(\right)}{2} + \left(\sin^{-1} 1 \cdot \sin^{-1} 1 + \frac{\mathsf{PI}\left(\right)}{2} \cdot \sin^{-1} 1\right)} - \frac{{\sin^{-1} 1}^{3}}{\frac{\mathsf{PI}\left(\right)}{2} \cdot \frac{\mathsf{PI}\left(\right)}{2} + \left(\sin^{-1} 1 \cdot \sin^{-1} 1 + \frac{\mathsf{PI}\left(\right)}{2} \cdot \sin^{-1} 1\right)}} \]
            4. sub-negN/A

              \[\leadsto \color{blue}{\frac{{\left(\frac{\mathsf{PI}\left(\right)}{2}\right)}^{3}}{\frac{\mathsf{PI}\left(\right)}{2} \cdot \frac{\mathsf{PI}\left(\right)}{2} + \left(\sin^{-1} 1 \cdot \sin^{-1} 1 + \frac{\mathsf{PI}\left(\right)}{2} \cdot \sin^{-1} 1\right)} + \left(\mathsf{neg}\left(\frac{{\sin^{-1} 1}^{3}}{\frac{\mathsf{PI}\left(\right)}{2} \cdot \frac{\mathsf{PI}\left(\right)}{2} + \left(\sin^{-1} 1 \cdot \sin^{-1} 1 + \frac{\mathsf{PI}\left(\right)}{2} \cdot \sin^{-1} 1\right)}\right)\right)} \]
            5. div-invN/A

              \[\leadsto \color{blue}{{\left(\frac{\mathsf{PI}\left(\right)}{2}\right)}^{3} \cdot \frac{1}{\frac{\mathsf{PI}\left(\right)}{2} \cdot \frac{\mathsf{PI}\left(\right)}{2} + \left(\sin^{-1} 1 \cdot \sin^{-1} 1 + \frac{\mathsf{PI}\left(\right)}{2} \cdot \sin^{-1} 1\right)}} + \left(\mathsf{neg}\left(\frac{{\sin^{-1} 1}^{3}}{\frac{\mathsf{PI}\left(\right)}{2} \cdot \frac{\mathsf{PI}\left(\right)}{2} + \left(\sin^{-1} 1 \cdot \sin^{-1} 1 + \frac{\mathsf{PI}\left(\right)}{2} \cdot \sin^{-1} 1\right)}\right)\right) \]
            6. accelerator-lowering-fma.f64N/A

              \[\leadsto \color{blue}{\mathsf{fma}\left({\left(\frac{\mathsf{PI}\left(\right)}{2}\right)}^{3}, \frac{1}{\frac{\mathsf{PI}\left(\right)}{2} \cdot \frac{\mathsf{PI}\left(\right)}{2} + \left(\sin^{-1} 1 \cdot \sin^{-1} 1 + \frac{\mathsf{PI}\left(\right)}{2} \cdot \sin^{-1} 1\right)}, \mathsf{neg}\left(\frac{{\sin^{-1} 1}^{3}}{\frac{\mathsf{PI}\left(\right)}{2} \cdot \frac{\mathsf{PI}\left(\right)}{2} + \left(\sin^{-1} 1 \cdot \sin^{-1} 1 + \frac{\mathsf{PI}\left(\right)}{2} \cdot \sin^{-1} 1\right)}\right)\right)} \]
          3. Applied egg-rr7.6%

            \[\leadsto \color{blue}{\mathsf{fma}\left(\left(\pi \cdot \left(\pi \cdot \pi\right)\right) \cdot 0.125, \frac{1}{\mathsf{fma}\left(\sin^{-1} 1, \mathsf{fma}\left(\pi, 0.5, \sin^{-1} 1\right), \left(\pi \cdot \pi\right) \cdot 0.25\right)}, -\frac{{\sin^{-1} 1}^{3}}{\mathsf{fma}\left(\sin^{-1} 1, \mathsf{fma}\left(\pi, 0.5, \sin^{-1} 1\right), \left(\pi \cdot \pi\right) \cdot 0.25\right)}\right)} \]
          4. Step-by-step derivation
            1. un-div-invN/A

              \[\leadsto \color{blue}{\frac{\left(\mathsf{PI}\left(\right) \cdot \left(\mathsf{PI}\left(\right) \cdot \mathsf{PI}\left(\right)\right)\right) \cdot \frac{1}{8}}{\sin^{-1} 1 \cdot \left(\mathsf{PI}\left(\right) \cdot \frac{1}{2} + \sin^{-1} 1\right) + \left(\mathsf{PI}\left(\right) \cdot \mathsf{PI}\left(\right)\right) \cdot \frac{1}{4}}} + \left(\mathsf{neg}\left(\frac{{\sin^{-1} 1}^{3}}{\sin^{-1} 1 \cdot \left(\mathsf{PI}\left(\right) \cdot \frac{1}{2} + \sin^{-1} 1\right) + \left(\mathsf{PI}\left(\right) \cdot \mathsf{PI}\left(\right)\right) \cdot \frac{1}{4}}\right)\right) \]
            2. associate-*l*N/A

              \[\leadsto \frac{\color{blue}{\mathsf{PI}\left(\right) \cdot \left(\left(\mathsf{PI}\left(\right) \cdot \mathsf{PI}\left(\right)\right) \cdot \frac{1}{8}\right)}}{\sin^{-1} 1 \cdot \left(\mathsf{PI}\left(\right) \cdot \frac{1}{2} + \sin^{-1} 1\right) + \left(\mathsf{PI}\left(\right) \cdot \mathsf{PI}\left(\right)\right) \cdot \frac{1}{4}} + \left(\mathsf{neg}\left(\frac{{\sin^{-1} 1}^{3}}{\sin^{-1} 1 \cdot \left(\mathsf{PI}\left(\right) \cdot \frac{1}{2} + \sin^{-1} 1\right) + \left(\mathsf{PI}\left(\right) \cdot \mathsf{PI}\left(\right)\right) \cdot \frac{1}{4}}\right)\right) \]
            3. associate-/l*N/A

              \[\leadsto \color{blue}{\mathsf{PI}\left(\right) \cdot \frac{\left(\mathsf{PI}\left(\right) \cdot \mathsf{PI}\left(\right)\right) \cdot \frac{1}{8}}{\sin^{-1} 1 \cdot \left(\mathsf{PI}\left(\right) \cdot \frac{1}{2} + \sin^{-1} 1\right) + \left(\mathsf{PI}\left(\right) \cdot \mathsf{PI}\left(\right)\right) \cdot \frac{1}{4}}} + \left(\mathsf{neg}\left(\frac{{\sin^{-1} 1}^{3}}{\sin^{-1} 1 \cdot \left(\mathsf{PI}\left(\right) \cdot \frac{1}{2} + \sin^{-1} 1\right) + \left(\mathsf{PI}\left(\right) \cdot \mathsf{PI}\left(\right)\right) \cdot \frac{1}{4}}\right)\right) \]
            4. accelerator-lowering-fma.f64N/A

              \[\leadsto \color{blue}{\mathsf{fma}\left(\mathsf{PI}\left(\right), \frac{\left(\mathsf{PI}\left(\right) \cdot \mathsf{PI}\left(\right)\right) \cdot \frac{1}{8}}{\sin^{-1} 1 \cdot \left(\mathsf{PI}\left(\right) \cdot \frac{1}{2} + \sin^{-1} 1\right) + \left(\mathsf{PI}\left(\right) \cdot \mathsf{PI}\left(\right)\right) \cdot \frac{1}{4}}, \mathsf{neg}\left(\frac{{\sin^{-1} 1}^{3}}{\sin^{-1} 1 \cdot \left(\mathsf{PI}\left(\right) \cdot \frac{1}{2} + \sin^{-1} 1\right) + \left(\mathsf{PI}\left(\right) \cdot \mathsf{PI}\left(\right)\right) \cdot \frac{1}{4}}\right)\right)} \]
          5. Applied egg-rr7.5%

            \[\leadsto \color{blue}{\mathsf{fma}\left(\pi, \frac{\left(\pi \cdot \pi\right) \cdot 0.125}{\mathsf{fma}\left(\pi, \pi \cdot 0.25, \sin^{-1} 1 \cdot \mathsf{fma}\left(\pi, 0.5, \sin^{-1} 1\right)\right)}, -\frac{{\sin^{-1} 1}^{3}}{\mathsf{fma}\left(\pi, \pi \cdot 0.25, \sin^{-1} 1 \cdot \mathsf{fma}\left(\pi, 0.5, \sin^{-1} 1\right)\right)}\right)} \]

          if 5.5999999999999998e-17 < x

          1. Initial program 68.8%

            \[\cos^{-1} \left(1 - x\right) \]
          2. Add Preprocessing
        5. Recombined 2 regimes into one program.
        6. Final simplification9.7%

          \[\leadsto \begin{array}{l} \mathbf{if}\;x \leq 5.6 \cdot 10^{-17}:\\ \;\;\;\;\mathsf{fma}\left(\pi, \frac{\left(\pi \cdot \pi\right) \cdot 0.125}{\mathsf{fma}\left(\pi, \pi \cdot 0.25, \sin^{-1} 1 \cdot \mathsf{fma}\left(\pi, 0.5, \sin^{-1} 1\right)\right)}, \frac{-{\sin^{-1} 1}^{3}}{\mathsf{fma}\left(\pi, \pi \cdot 0.25, \sin^{-1} 1 \cdot \mathsf{fma}\left(\pi, 0.5, \sin^{-1} 1\right)\right)}\right)\\ \mathbf{else}:\\ \;\;\;\;\cos^{-1} \left(1 - x\right)\\ \end{array} \]
        7. Add Preprocessing

        Alternative 4: 10.3% accurate, 0.2× speedup?

        \[\begin{array}{l} \\ \begin{array}{l} t_0 := \mathsf{fma}\left(\pi, 0.5, \sin^{-1} 1\right)\\ \mathbf{if}\;x \leq 5.6 \cdot 10^{-17}:\\ \;\;\;\;\frac{\mathsf{fma}\left(\left(\pi \cdot \pi\right) \cdot 0.25, t\_0, t\_0 \cdot \left(-{\sin^{-1} 1}^{2}\right)\right)}{{t\_0}^{2}}\\ \mathbf{else}:\\ \;\;\;\;\cos^{-1} \left(1 - x\right)\\ \end{array} \end{array} \]
        (FPCore (x)
         :precision binary64
         (let* ((t_0 (fma PI 0.5 (asin 1.0))))
           (if (<= x 5.6e-17)
             (/
              (fma (* (* PI PI) 0.25) t_0 (* t_0 (- (pow (asin 1.0) 2.0))))
              (pow t_0 2.0))
             (acos (- 1.0 x)))))
        double code(double x) {
        	double t_0 = fma(((double) M_PI), 0.5, asin(1.0));
        	double tmp;
        	if (x <= 5.6e-17) {
        		tmp = fma(((((double) M_PI) * ((double) M_PI)) * 0.25), t_0, (t_0 * -pow(asin(1.0), 2.0))) / pow(t_0, 2.0);
        	} else {
        		tmp = acos((1.0 - x));
        	}
        	return tmp;
        }
        
        function code(x)
        	t_0 = fma(pi, 0.5, asin(1.0))
        	tmp = 0.0
        	if (x <= 5.6e-17)
        		tmp = Float64(fma(Float64(Float64(pi * pi) * 0.25), t_0, Float64(t_0 * Float64(-(asin(1.0) ^ 2.0)))) / (t_0 ^ 2.0));
        	else
        		tmp = acos(Float64(1.0 - x));
        	end
        	return tmp
        end
        
        code[x_] := Block[{t$95$0 = N[(Pi * 0.5 + N[ArcSin[1.0], $MachinePrecision]), $MachinePrecision]}, If[LessEqual[x, 5.6e-17], N[(N[(N[(N[(Pi * Pi), $MachinePrecision] * 0.25), $MachinePrecision] * t$95$0 + N[(t$95$0 * (-N[Power[N[ArcSin[1.0], $MachinePrecision], 2.0], $MachinePrecision])), $MachinePrecision]), $MachinePrecision] / N[Power[t$95$0, 2.0], $MachinePrecision]), $MachinePrecision], N[ArcCos[N[(1.0 - x), $MachinePrecision]], $MachinePrecision]]]
        
        \begin{array}{l}
        
        \\
        \begin{array}{l}
        t_0 := \mathsf{fma}\left(\pi, 0.5, \sin^{-1} 1\right)\\
        \mathbf{if}\;x \leq 5.6 \cdot 10^{-17}:\\
        \;\;\;\;\frac{\mathsf{fma}\left(\left(\pi \cdot \pi\right) \cdot 0.25, t\_0, t\_0 \cdot \left(-{\sin^{-1} 1}^{2}\right)\right)}{{t\_0}^{2}}\\
        
        \mathbf{else}:\\
        \;\;\;\;\cos^{-1} \left(1 - x\right)\\
        
        
        \end{array}
        \end{array}
        
        Derivation
        1. Split input into 2 regimes
        2. if x < 5.5999999999999998e-17

          1. Initial program 3.9%

            \[\cos^{-1} \left(1 - x\right) \]
          2. Add Preprocessing
          3. Taylor expanded in x around 0

            \[\leadsto \cos^{-1} \color{blue}{1} \]
          4. Step-by-step derivation
            1. Simplified3.9%

              \[\leadsto \cos^{-1} \color{blue}{1} \]
            2. Step-by-step derivation
              1. acos-asinN/A

                \[\leadsto \color{blue}{\frac{\mathsf{PI}\left(\right)}{2} - \sin^{-1} 1} \]
              2. flip3--N/A

                \[\leadsto \color{blue}{\frac{{\left(\frac{\mathsf{PI}\left(\right)}{2}\right)}^{3} - {\sin^{-1} 1}^{3}}{\frac{\mathsf{PI}\left(\right)}{2} \cdot \frac{\mathsf{PI}\left(\right)}{2} + \left(\sin^{-1} 1 \cdot \sin^{-1} 1 + \frac{\mathsf{PI}\left(\right)}{2} \cdot \sin^{-1} 1\right)}} \]
              3. div-subN/A

                \[\leadsto \color{blue}{\frac{{\left(\frac{\mathsf{PI}\left(\right)}{2}\right)}^{3}}{\frac{\mathsf{PI}\left(\right)}{2} \cdot \frac{\mathsf{PI}\left(\right)}{2} + \left(\sin^{-1} 1 \cdot \sin^{-1} 1 + \frac{\mathsf{PI}\left(\right)}{2} \cdot \sin^{-1} 1\right)} - \frac{{\sin^{-1} 1}^{3}}{\frac{\mathsf{PI}\left(\right)}{2} \cdot \frac{\mathsf{PI}\left(\right)}{2} + \left(\sin^{-1} 1 \cdot \sin^{-1} 1 + \frac{\mathsf{PI}\left(\right)}{2} \cdot \sin^{-1} 1\right)}} \]
              4. sub-negN/A

                \[\leadsto \color{blue}{\frac{{\left(\frac{\mathsf{PI}\left(\right)}{2}\right)}^{3}}{\frac{\mathsf{PI}\left(\right)}{2} \cdot \frac{\mathsf{PI}\left(\right)}{2} + \left(\sin^{-1} 1 \cdot \sin^{-1} 1 + \frac{\mathsf{PI}\left(\right)}{2} \cdot \sin^{-1} 1\right)} + \left(\mathsf{neg}\left(\frac{{\sin^{-1} 1}^{3}}{\frac{\mathsf{PI}\left(\right)}{2} \cdot \frac{\mathsf{PI}\left(\right)}{2} + \left(\sin^{-1} 1 \cdot \sin^{-1} 1 + \frac{\mathsf{PI}\left(\right)}{2} \cdot \sin^{-1} 1\right)}\right)\right)} \]
              5. div-invN/A

                \[\leadsto \color{blue}{{\left(\frac{\mathsf{PI}\left(\right)}{2}\right)}^{3} \cdot \frac{1}{\frac{\mathsf{PI}\left(\right)}{2} \cdot \frac{\mathsf{PI}\left(\right)}{2} + \left(\sin^{-1} 1 \cdot \sin^{-1} 1 + \frac{\mathsf{PI}\left(\right)}{2} \cdot \sin^{-1} 1\right)}} + \left(\mathsf{neg}\left(\frac{{\sin^{-1} 1}^{3}}{\frac{\mathsf{PI}\left(\right)}{2} \cdot \frac{\mathsf{PI}\left(\right)}{2} + \left(\sin^{-1} 1 \cdot \sin^{-1} 1 + \frac{\mathsf{PI}\left(\right)}{2} \cdot \sin^{-1} 1\right)}\right)\right) \]
              6. accelerator-lowering-fma.f64N/A

                \[\leadsto \color{blue}{\mathsf{fma}\left({\left(\frac{\mathsf{PI}\left(\right)}{2}\right)}^{3}, \frac{1}{\frac{\mathsf{PI}\left(\right)}{2} \cdot \frac{\mathsf{PI}\left(\right)}{2} + \left(\sin^{-1} 1 \cdot \sin^{-1} 1 + \frac{\mathsf{PI}\left(\right)}{2} \cdot \sin^{-1} 1\right)}, \mathsf{neg}\left(\frac{{\sin^{-1} 1}^{3}}{\frac{\mathsf{PI}\left(\right)}{2} \cdot \frac{\mathsf{PI}\left(\right)}{2} + \left(\sin^{-1} 1 \cdot \sin^{-1} 1 + \frac{\mathsf{PI}\left(\right)}{2} \cdot \sin^{-1} 1\right)}\right)\right)} \]
            3. Applied egg-rr7.6%

              \[\leadsto \color{blue}{\mathsf{fma}\left(\left(\pi \cdot \left(\pi \cdot \pi\right)\right) \cdot 0.125, \frac{1}{\mathsf{fma}\left(\sin^{-1} 1, \mathsf{fma}\left(\pi, 0.5, \sin^{-1} 1\right), \left(\pi \cdot \pi\right) \cdot 0.25\right)}, -\frac{{\sin^{-1} 1}^{3}}{\mathsf{fma}\left(\sin^{-1} 1, \mathsf{fma}\left(\pi, 0.5, \sin^{-1} 1\right), \left(\pi \cdot \pi\right) \cdot 0.25\right)}\right)} \]
            4. Applied egg-rr7.5%

              \[\leadsto \color{blue}{\frac{\mathsf{fma}\left(\left(\pi \cdot \pi\right) \cdot 0.25, \mathsf{fma}\left(\pi, 0.5, \sin^{-1} 1\right), \mathsf{fma}\left(\pi, 0.5, \sin^{-1} 1\right) \cdot \left(-{\sin^{-1} 1}^{2}\right)\right)}{{\left(\mathsf{fma}\left(\pi, 0.5, \sin^{-1} 1\right)\right)}^{2}}} \]

            if 5.5999999999999998e-17 < x

            1. Initial program 68.8%

              \[\cos^{-1} \left(1 - x\right) \]
            2. Add Preprocessing
          5. Recombined 2 regimes into one program.
          6. Add Preprocessing

          Alternative 5: 10.3% accurate, 0.2× speedup?

          \[\begin{array}{l} \\ \begin{array}{l} t_0 := \mathsf{fma}\left(\pi, 0.5, \sin^{-1} 1\right)\\ \mathbf{if}\;x \leq 5.6 \cdot 10^{-17}:\\ \;\;\;\;\mathsf{fma}\left(\frac{0.25}{t\_0}, \pi \cdot \pi, \frac{{\sin^{-1} 1}^{2}}{-t\_0}\right)\\ \mathbf{else}:\\ \;\;\;\;\cos^{-1} \left(1 - x\right)\\ \end{array} \end{array} \]
          (FPCore (x)
           :precision binary64
           (let* ((t_0 (fma PI 0.5 (asin 1.0))))
             (if (<= x 5.6e-17)
               (fma (/ 0.25 t_0) (* PI PI) (/ (pow (asin 1.0) 2.0) (- t_0)))
               (acos (- 1.0 x)))))
          double code(double x) {
          	double t_0 = fma(((double) M_PI), 0.5, asin(1.0));
          	double tmp;
          	if (x <= 5.6e-17) {
          		tmp = fma((0.25 / t_0), (((double) M_PI) * ((double) M_PI)), (pow(asin(1.0), 2.0) / -t_0));
          	} else {
          		tmp = acos((1.0 - x));
          	}
          	return tmp;
          }
          
          function code(x)
          	t_0 = fma(pi, 0.5, asin(1.0))
          	tmp = 0.0
          	if (x <= 5.6e-17)
          		tmp = fma(Float64(0.25 / t_0), Float64(pi * pi), Float64((asin(1.0) ^ 2.0) / Float64(-t_0)));
          	else
          		tmp = acos(Float64(1.0 - x));
          	end
          	return tmp
          end
          
          code[x_] := Block[{t$95$0 = N[(Pi * 0.5 + N[ArcSin[1.0], $MachinePrecision]), $MachinePrecision]}, If[LessEqual[x, 5.6e-17], N[(N[(0.25 / t$95$0), $MachinePrecision] * N[(Pi * Pi), $MachinePrecision] + N[(N[Power[N[ArcSin[1.0], $MachinePrecision], 2.0], $MachinePrecision] / (-t$95$0)), $MachinePrecision]), $MachinePrecision], N[ArcCos[N[(1.0 - x), $MachinePrecision]], $MachinePrecision]]]
          
          \begin{array}{l}
          
          \\
          \begin{array}{l}
          t_0 := \mathsf{fma}\left(\pi, 0.5, \sin^{-1} 1\right)\\
          \mathbf{if}\;x \leq 5.6 \cdot 10^{-17}:\\
          \;\;\;\;\mathsf{fma}\left(\frac{0.25}{t\_0}, \pi \cdot \pi, \frac{{\sin^{-1} 1}^{2}}{-t\_0}\right)\\
          
          \mathbf{else}:\\
          \;\;\;\;\cos^{-1} \left(1 - x\right)\\
          
          
          \end{array}
          \end{array}
          
          Derivation
          1. Split input into 2 regimes
          2. if x < 5.5999999999999998e-17

            1. Initial program 3.9%

              \[\cos^{-1} \left(1 - x\right) \]
            2. Add Preprocessing
            3. Taylor expanded in x around 0

              \[\leadsto \cos^{-1} \color{blue}{1} \]
            4. Step-by-step derivation
              1. Simplified3.9%

                \[\leadsto \cos^{-1} \color{blue}{1} \]
              2. Step-by-step derivation
                1. acos-asinN/A

                  \[\leadsto \color{blue}{\frac{\mathsf{PI}\left(\right)}{2} - \sin^{-1} 1} \]
                2. flip3--N/A

                  \[\leadsto \color{blue}{\frac{{\left(\frac{\mathsf{PI}\left(\right)}{2}\right)}^{3} - {\sin^{-1} 1}^{3}}{\frac{\mathsf{PI}\left(\right)}{2} \cdot \frac{\mathsf{PI}\left(\right)}{2} + \left(\sin^{-1} 1 \cdot \sin^{-1} 1 + \frac{\mathsf{PI}\left(\right)}{2} \cdot \sin^{-1} 1\right)}} \]
                3. div-subN/A

                  \[\leadsto \color{blue}{\frac{{\left(\frac{\mathsf{PI}\left(\right)}{2}\right)}^{3}}{\frac{\mathsf{PI}\left(\right)}{2} \cdot \frac{\mathsf{PI}\left(\right)}{2} + \left(\sin^{-1} 1 \cdot \sin^{-1} 1 + \frac{\mathsf{PI}\left(\right)}{2} \cdot \sin^{-1} 1\right)} - \frac{{\sin^{-1} 1}^{3}}{\frac{\mathsf{PI}\left(\right)}{2} \cdot \frac{\mathsf{PI}\left(\right)}{2} + \left(\sin^{-1} 1 \cdot \sin^{-1} 1 + \frac{\mathsf{PI}\left(\right)}{2} \cdot \sin^{-1} 1\right)}} \]
                4. sub-negN/A

                  \[\leadsto \color{blue}{\frac{{\left(\frac{\mathsf{PI}\left(\right)}{2}\right)}^{3}}{\frac{\mathsf{PI}\left(\right)}{2} \cdot \frac{\mathsf{PI}\left(\right)}{2} + \left(\sin^{-1} 1 \cdot \sin^{-1} 1 + \frac{\mathsf{PI}\left(\right)}{2} \cdot \sin^{-1} 1\right)} + \left(\mathsf{neg}\left(\frac{{\sin^{-1} 1}^{3}}{\frac{\mathsf{PI}\left(\right)}{2} \cdot \frac{\mathsf{PI}\left(\right)}{2} + \left(\sin^{-1} 1 \cdot \sin^{-1} 1 + \frac{\mathsf{PI}\left(\right)}{2} \cdot \sin^{-1} 1\right)}\right)\right)} \]
                5. div-invN/A

                  \[\leadsto \color{blue}{{\left(\frac{\mathsf{PI}\left(\right)}{2}\right)}^{3} \cdot \frac{1}{\frac{\mathsf{PI}\left(\right)}{2} \cdot \frac{\mathsf{PI}\left(\right)}{2} + \left(\sin^{-1} 1 \cdot \sin^{-1} 1 + \frac{\mathsf{PI}\left(\right)}{2} \cdot \sin^{-1} 1\right)}} + \left(\mathsf{neg}\left(\frac{{\sin^{-1} 1}^{3}}{\frac{\mathsf{PI}\left(\right)}{2} \cdot \frac{\mathsf{PI}\left(\right)}{2} + \left(\sin^{-1} 1 \cdot \sin^{-1} 1 + \frac{\mathsf{PI}\left(\right)}{2} \cdot \sin^{-1} 1\right)}\right)\right) \]
                6. accelerator-lowering-fma.f64N/A

                  \[\leadsto \color{blue}{\mathsf{fma}\left({\left(\frac{\mathsf{PI}\left(\right)}{2}\right)}^{3}, \frac{1}{\frac{\mathsf{PI}\left(\right)}{2} \cdot \frac{\mathsf{PI}\left(\right)}{2} + \left(\sin^{-1} 1 \cdot \sin^{-1} 1 + \frac{\mathsf{PI}\left(\right)}{2} \cdot \sin^{-1} 1\right)}, \mathsf{neg}\left(\frac{{\sin^{-1} 1}^{3}}{\frac{\mathsf{PI}\left(\right)}{2} \cdot \frac{\mathsf{PI}\left(\right)}{2} + \left(\sin^{-1} 1 \cdot \sin^{-1} 1 + \frac{\mathsf{PI}\left(\right)}{2} \cdot \sin^{-1} 1\right)}\right)\right)} \]
              3. Applied egg-rr7.6%

                \[\leadsto \color{blue}{\mathsf{fma}\left(\left(\pi \cdot \left(\pi \cdot \pi\right)\right) \cdot 0.125, \frac{1}{\mathsf{fma}\left(\sin^{-1} 1, \mathsf{fma}\left(\pi, 0.5, \sin^{-1} 1\right), \left(\pi \cdot \pi\right) \cdot 0.25\right)}, -\frac{{\sin^{-1} 1}^{3}}{\mathsf{fma}\left(\sin^{-1} 1, \mathsf{fma}\left(\pi, 0.5, \sin^{-1} 1\right), \left(\pi \cdot \pi\right) \cdot 0.25\right)}\right)} \]
              4. Step-by-step derivation
                1. unsub-negN/A

                  \[\leadsto \color{blue}{\left(\left(\mathsf{PI}\left(\right) \cdot \left(\mathsf{PI}\left(\right) \cdot \mathsf{PI}\left(\right)\right)\right) \cdot \frac{1}{8}\right) \cdot \frac{1}{\sin^{-1} 1 \cdot \left(\mathsf{PI}\left(\right) \cdot \frac{1}{2} + \sin^{-1} 1\right) + \left(\mathsf{PI}\left(\right) \cdot \mathsf{PI}\left(\right)\right) \cdot \frac{1}{4}} - \frac{{\sin^{-1} 1}^{3}}{\sin^{-1} 1 \cdot \left(\mathsf{PI}\left(\right) \cdot \frac{1}{2} + \sin^{-1} 1\right) + \left(\mathsf{PI}\left(\right) \cdot \mathsf{PI}\left(\right)\right) \cdot \frac{1}{4}}} \]
                2. un-div-invN/A

                  \[\leadsto \color{blue}{\frac{\left(\mathsf{PI}\left(\right) \cdot \left(\mathsf{PI}\left(\right) \cdot \mathsf{PI}\left(\right)\right)\right) \cdot \frac{1}{8}}{\sin^{-1} 1 \cdot \left(\mathsf{PI}\left(\right) \cdot \frac{1}{2} + \sin^{-1} 1\right) + \left(\mathsf{PI}\left(\right) \cdot \mathsf{PI}\left(\right)\right) \cdot \frac{1}{4}}} - \frac{{\sin^{-1} 1}^{3}}{\sin^{-1} 1 \cdot \left(\mathsf{PI}\left(\right) \cdot \frac{1}{2} + \sin^{-1} 1\right) + \left(\mathsf{PI}\left(\right) \cdot \mathsf{PI}\left(\right)\right) \cdot \frac{1}{4}} \]
                3. sub-divN/A

                  \[\leadsto \color{blue}{\frac{\left(\mathsf{PI}\left(\right) \cdot \left(\mathsf{PI}\left(\right) \cdot \mathsf{PI}\left(\right)\right)\right) \cdot \frac{1}{8} - {\sin^{-1} 1}^{3}}{\sin^{-1} 1 \cdot \left(\mathsf{PI}\left(\right) \cdot \frac{1}{2} + \sin^{-1} 1\right) + \left(\mathsf{PI}\left(\right) \cdot \mathsf{PI}\left(\right)\right) \cdot \frac{1}{4}}} \]
              5. Applied egg-rr7.5%

                \[\leadsto \color{blue}{\mathsf{fma}\left(\frac{0.25}{\mathsf{fma}\left(\pi, 0.5, \sin^{-1} 1\right)}, \pi \cdot \pi, \frac{{\sin^{-1} 1}^{2}}{-\mathsf{fma}\left(\pi, 0.5, \sin^{-1} 1\right)}\right)} \]

              if 5.5999999999999998e-17 < x

              1. Initial program 68.8%

                \[\cos^{-1} \left(1 - x\right) \]
              2. Add Preprocessing
            5. Recombined 2 regimes into one program.
            6. Add Preprocessing

            Alternative 6: 9.3% accurate, 0.5× speedup?

            \[\begin{array}{l} \\ \begin{array}{l} t_0 := \cos^{-1} \left(1 - x\right)\\ \mathbf{if}\;t\_0 \leq 0:\\ \;\;\;\;\cos^{-1} \left(-x\right)\\ \mathbf{else}:\\ \;\;\;\;t\_0\\ \end{array} \end{array} \]
            (FPCore (x)
             :precision binary64
             (let* ((t_0 (acos (- 1.0 x)))) (if (<= t_0 0.0) (acos (- x)) t_0)))
            double code(double x) {
            	double t_0 = acos((1.0 - x));
            	double tmp;
            	if (t_0 <= 0.0) {
            		tmp = acos(-x);
            	} else {
            		tmp = t_0;
            	}
            	return tmp;
            }
            
            real(8) function code(x)
                real(8), intent (in) :: x
                real(8) :: t_0
                real(8) :: tmp
                t_0 = acos((1.0d0 - x))
                if (t_0 <= 0.0d0) then
                    tmp = acos(-x)
                else
                    tmp = t_0
                end if
                code = tmp
            end function
            
            public static double code(double x) {
            	double t_0 = Math.acos((1.0 - x));
            	double tmp;
            	if (t_0 <= 0.0) {
            		tmp = Math.acos(-x);
            	} else {
            		tmp = t_0;
            	}
            	return tmp;
            }
            
            def code(x):
            	t_0 = math.acos((1.0 - x))
            	tmp = 0
            	if t_0 <= 0.0:
            		tmp = math.acos(-x)
            	else:
            		tmp = t_0
            	return tmp
            
            function code(x)
            	t_0 = acos(Float64(1.0 - x))
            	tmp = 0.0
            	if (t_0 <= 0.0)
            		tmp = acos(Float64(-x));
            	else
            		tmp = t_0;
            	end
            	return tmp
            end
            
            function tmp_2 = code(x)
            	t_0 = acos((1.0 - x));
            	tmp = 0.0;
            	if (t_0 <= 0.0)
            		tmp = acos(-x);
            	else
            		tmp = t_0;
            	end
            	tmp_2 = tmp;
            end
            
            code[x_] := Block[{t$95$0 = N[ArcCos[N[(1.0 - x), $MachinePrecision]], $MachinePrecision]}, If[LessEqual[t$95$0, 0.0], N[ArcCos[(-x)], $MachinePrecision], t$95$0]]
            
            \begin{array}{l}
            
            \\
            \begin{array}{l}
            t_0 := \cos^{-1} \left(1 - x\right)\\
            \mathbf{if}\;t\_0 \leq 0:\\
            \;\;\;\;\cos^{-1} \left(-x\right)\\
            
            \mathbf{else}:\\
            \;\;\;\;t\_0\\
            
            
            \end{array}
            \end{array}
            
            Derivation
            1. Split input into 2 regimes
            2. if (acos.f64 (-.f64 #s(literal 1 binary64) x)) < 0.0

              1. Initial program 3.9%

                \[\cos^{-1} \left(1 - x\right) \]
              2. Add Preprocessing
              3. Taylor expanded in x around inf

                \[\leadsto \cos^{-1} \color{blue}{\left(-1 \cdot x\right)} \]
              4. Step-by-step derivation
                1. mul-1-negN/A

                  \[\leadsto \cos^{-1} \color{blue}{\left(\mathsf{neg}\left(x\right)\right)} \]
                2. neg-lowering-neg.f646.6

                  \[\leadsto \cos^{-1} \color{blue}{\left(-x\right)} \]
              5. Simplified6.6%

                \[\leadsto \cos^{-1} \color{blue}{\left(-x\right)} \]

              if 0.0 < (acos.f64 (-.f64 #s(literal 1 binary64) x))

              1. Initial program 68.8%

                \[\cos^{-1} \left(1 - x\right) \]
              2. Add Preprocessing
            3. Recombined 2 regimes into one program.
            4. Add Preprocessing

            Alternative 7: 10.2% accurate, 0.6× speedup?

            \[\begin{array}{l} \\ \begin{array}{l} t_0 := \sqrt{\sqrt{\pi}}\\ \mathbf{if}\;1 - x \leq 0.9999999999999999:\\ \;\;\;\;\cos^{-1} \left(1 - x\right)\\ \mathbf{else}:\\ \;\;\;\;\mathsf{fma}\left(\left(0.5 \cdot \sqrt{\pi}\right) \cdot t\_0, t\_0, -\sin^{-1} 1\right)\\ \end{array} \end{array} \]
            (FPCore (x)
             :precision binary64
             (let* ((t_0 (sqrt (sqrt PI))))
               (if (<= (- 1.0 x) 0.9999999999999999)
                 (acos (- 1.0 x))
                 (fma (* (* 0.5 (sqrt PI)) t_0) t_0 (- (asin 1.0))))))
            double code(double x) {
            	double t_0 = sqrt(sqrt(((double) M_PI)));
            	double tmp;
            	if ((1.0 - x) <= 0.9999999999999999) {
            		tmp = acos((1.0 - x));
            	} else {
            		tmp = fma(((0.5 * sqrt(((double) M_PI))) * t_0), t_0, -asin(1.0));
            	}
            	return tmp;
            }
            
            function code(x)
            	t_0 = sqrt(sqrt(pi))
            	tmp = 0.0
            	if (Float64(1.0 - x) <= 0.9999999999999999)
            		tmp = acos(Float64(1.0 - x));
            	else
            		tmp = fma(Float64(Float64(0.5 * sqrt(pi)) * t_0), t_0, Float64(-asin(1.0)));
            	end
            	return tmp
            end
            
            code[x_] := Block[{t$95$0 = N[Sqrt[N[Sqrt[Pi], $MachinePrecision]], $MachinePrecision]}, If[LessEqual[N[(1.0 - x), $MachinePrecision], 0.9999999999999999], N[ArcCos[N[(1.0 - x), $MachinePrecision]], $MachinePrecision], N[(N[(N[(0.5 * N[Sqrt[Pi], $MachinePrecision]), $MachinePrecision] * t$95$0), $MachinePrecision] * t$95$0 + (-N[ArcSin[1.0], $MachinePrecision])), $MachinePrecision]]]
            
            \begin{array}{l}
            
            \\
            \begin{array}{l}
            t_0 := \sqrt{\sqrt{\pi}}\\
            \mathbf{if}\;1 - x \leq 0.9999999999999999:\\
            \;\;\;\;\cos^{-1} \left(1 - x\right)\\
            
            \mathbf{else}:\\
            \;\;\;\;\mathsf{fma}\left(\left(0.5 \cdot \sqrt{\pi}\right) \cdot t\_0, t\_0, -\sin^{-1} 1\right)\\
            
            
            \end{array}
            \end{array}
            
            Derivation
            1. Split input into 2 regimes
            2. if (-.f64 #s(literal 1 binary64) x) < 0.999999999999999889

              1. Initial program 68.8%

                \[\cos^{-1} \left(1 - x\right) \]
              2. Add Preprocessing

              if 0.999999999999999889 < (-.f64 #s(literal 1 binary64) x)

              1. Initial program 3.9%

                \[\cos^{-1} \left(1 - x\right) \]
              2. Add Preprocessing
              3. Taylor expanded in x around 0

                \[\leadsto \cos^{-1} \color{blue}{1} \]
              4. Step-by-step derivation
                1. Simplified3.9%

                  \[\leadsto \cos^{-1} \color{blue}{1} \]
                2. Step-by-step derivation
                  1. acos-asinN/A

                    \[\leadsto \color{blue}{\frac{\mathsf{PI}\left(\right)}{2} - \sin^{-1} 1} \]
                  2. flip3--N/A

                    \[\leadsto \color{blue}{\frac{{\left(\frac{\mathsf{PI}\left(\right)}{2}\right)}^{3} - {\sin^{-1} 1}^{3}}{\frac{\mathsf{PI}\left(\right)}{2} \cdot \frac{\mathsf{PI}\left(\right)}{2} + \left(\sin^{-1} 1 \cdot \sin^{-1} 1 + \frac{\mathsf{PI}\left(\right)}{2} \cdot \sin^{-1} 1\right)}} \]
                  3. div-subN/A

                    \[\leadsto \color{blue}{\frac{{\left(\frac{\mathsf{PI}\left(\right)}{2}\right)}^{3}}{\frac{\mathsf{PI}\left(\right)}{2} \cdot \frac{\mathsf{PI}\left(\right)}{2} + \left(\sin^{-1} 1 \cdot \sin^{-1} 1 + \frac{\mathsf{PI}\left(\right)}{2} \cdot \sin^{-1} 1\right)} - \frac{{\sin^{-1} 1}^{3}}{\frac{\mathsf{PI}\left(\right)}{2} \cdot \frac{\mathsf{PI}\left(\right)}{2} + \left(\sin^{-1} 1 \cdot \sin^{-1} 1 + \frac{\mathsf{PI}\left(\right)}{2} \cdot \sin^{-1} 1\right)}} \]
                  4. sub-negN/A

                    \[\leadsto \color{blue}{\frac{{\left(\frac{\mathsf{PI}\left(\right)}{2}\right)}^{3}}{\frac{\mathsf{PI}\left(\right)}{2} \cdot \frac{\mathsf{PI}\left(\right)}{2} + \left(\sin^{-1} 1 \cdot \sin^{-1} 1 + \frac{\mathsf{PI}\left(\right)}{2} \cdot \sin^{-1} 1\right)} + \left(\mathsf{neg}\left(\frac{{\sin^{-1} 1}^{3}}{\frac{\mathsf{PI}\left(\right)}{2} \cdot \frac{\mathsf{PI}\left(\right)}{2} + \left(\sin^{-1} 1 \cdot \sin^{-1} 1 + \frac{\mathsf{PI}\left(\right)}{2} \cdot \sin^{-1} 1\right)}\right)\right)} \]
                  5. div-invN/A

                    \[\leadsto \color{blue}{{\left(\frac{\mathsf{PI}\left(\right)}{2}\right)}^{3} \cdot \frac{1}{\frac{\mathsf{PI}\left(\right)}{2} \cdot \frac{\mathsf{PI}\left(\right)}{2} + \left(\sin^{-1} 1 \cdot \sin^{-1} 1 + \frac{\mathsf{PI}\left(\right)}{2} \cdot \sin^{-1} 1\right)}} + \left(\mathsf{neg}\left(\frac{{\sin^{-1} 1}^{3}}{\frac{\mathsf{PI}\left(\right)}{2} \cdot \frac{\mathsf{PI}\left(\right)}{2} + \left(\sin^{-1} 1 \cdot \sin^{-1} 1 + \frac{\mathsf{PI}\left(\right)}{2} \cdot \sin^{-1} 1\right)}\right)\right) \]
                  6. accelerator-lowering-fma.f64N/A

                    \[\leadsto \color{blue}{\mathsf{fma}\left({\left(\frac{\mathsf{PI}\left(\right)}{2}\right)}^{3}, \frac{1}{\frac{\mathsf{PI}\left(\right)}{2} \cdot \frac{\mathsf{PI}\left(\right)}{2} + \left(\sin^{-1} 1 \cdot \sin^{-1} 1 + \frac{\mathsf{PI}\left(\right)}{2} \cdot \sin^{-1} 1\right)}, \mathsf{neg}\left(\frac{{\sin^{-1} 1}^{3}}{\frac{\mathsf{PI}\left(\right)}{2} \cdot \frac{\mathsf{PI}\left(\right)}{2} + \left(\sin^{-1} 1 \cdot \sin^{-1} 1 + \frac{\mathsf{PI}\left(\right)}{2} \cdot \sin^{-1} 1\right)}\right)\right)} \]
                3. Applied egg-rr7.6%

                  \[\leadsto \color{blue}{\mathsf{fma}\left(\left(\pi \cdot \left(\pi \cdot \pi\right)\right) \cdot 0.125, \frac{1}{\mathsf{fma}\left(\sin^{-1} 1, \mathsf{fma}\left(\pi, 0.5, \sin^{-1} 1\right), \left(\pi \cdot \pi\right) \cdot 0.25\right)}, -\frac{{\sin^{-1} 1}^{3}}{\mathsf{fma}\left(\sin^{-1} 1, \mathsf{fma}\left(\pi, 0.5, \sin^{-1} 1\right), \left(\pi \cdot \pi\right) \cdot 0.25\right)}\right)} \]
                4. Step-by-step derivation
                  1. un-div-invN/A

                    \[\leadsto \color{blue}{\frac{\left(\mathsf{PI}\left(\right) \cdot \left(\mathsf{PI}\left(\right) \cdot \mathsf{PI}\left(\right)\right)\right) \cdot \frac{1}{8}}{\sin^{-1} 1 \cdot \left(\mathsf{PI}\left(\right) \cdot \frac{1}{2} + \sin^{-1} 1\right) + \left(\mathsf{PI}\left(\right) \cdot \mathsf{PI}\left(\right)\right) \cdot \frac{1}{4}}} + \left(\mathsf{neg}\left(\frac{{\sin^{-1} 1}^{3}}{\sin^{-1} 1 \cdot \left(\mathsf{PI}\left(\right) \cdot \frac{1}{2} + \sin^{-1} 1\right) + \left(\mathsf{PI}\left(\right) \cdot \mathsf{PI}\left(\right)\right) \cdot \frac{1}{4}}\right)\right) \]
                  2. distribute-neg-fracN/A

                    \[\leadsto \frac{\left(\mathsf{PI}\left(\right) \cdot \left(\mathsf{PI}\left(\right) \cdot \mathsf{PI}\left(\right)\right)\right) \cdot \frac{1}{8}}{\sin^{-1} 1 \cdot \left(\mathsf{PI}\left(\right) \cdot \frac{1}{2} + \sin^{-1} 1\right) + \left(\mathsf{PI}\left(\right) \cdot \mathsf{PI}\left(\right)\right) \cdot \frac{1}{4}} + \color{blue}{\frac{\mathsf{neg}\left({\sin^{-1} 1}^{3}\right)}{\sin^{-1} 1 \cdot \left(\mathsf{PI}\left(\right) \cdot \frac{1}{2} + \sin^{-1} 1\right) + \left(\mathsf{PI}\left(\right) \cdot \mathsf{PI}\left(\right)\right) \cdot \frac{1}{4}}} \]
                  3. frac-addN/A

                    \[\leadsto \color{blue}{\frac{\left(\left(\mathsf{PI}\left(\right) \cdot \left(\mathsf{PI}\left(\right) \cdot \mathsf{PI}\left(\right)\right)\right) \cdot \frac{1}{8}\right) \cdot \left(\sin^{-1} 1 \cdot \left(\mathsf{PI}\left(\right) \cdot \frac{1}{2} + \sin^{-1} 1\right) + \left(\mathsf{PI}\left(\right) \cdot \mathsf{PI}\left(\right)\right) \cdot \frac{1}{4}\right) + \left(\sin^{-1} 1 \cdot \left(\mathsf{PI}\left(\right) \cdot \frac{1}{2} + \sin^{-1} 1\right) + \left(\mathsf{PI}\left(\right) \cdot \mathsf{PI}\left(\right)\right) \cdot \frac{1}{4}\right) \cdot \left(\mathsf{neg}\left({\sin^{-1} 1}^{3}\right)\right)}{\left(\sin^{-1} 1 \cdot \left(\mathsf{PI}\left(\right) \cdot \frac{1}{2} + \sin^{-1} 1\right) + \left(\mathsf{PI}\left(\right) \cdot \mathsf{PI}\left(\right)\right) \cdot \frac{1}{4}\right) \cdot \left(\sin^{-1} 1 \cdot \left(\mathsf{PI}\left(\right) \cdot \frac{1}{2} + \sin^{-1} 1\right) + \left(\mathsf{PI}\left(\right) \cdot \mathsf{PI}\left(\right)\right) \cdot \frac{1}{4}\right)}} \]
                5. Applied egg-rr7.7%

                  \[\leadsto \color{blue}{\frac{\mathsf{fma}\left(\left(\pi \cdot \left(\pi \cdot \pi\right)\right) \cdot 0.125, \mathsf{fma}\left(\pi, \pi \cdot 0.25, \sin^{-1} 1 \cdot \mathsf{fma}\left(\pi, 0.5, \sin^{-1} 1\right)\right), \mathsf{fma}\left(\pi, \pi \cdot 0.25, \sin^{-1} 1 \cdot \mathsf{fma}\left(\pi, 0.5, \sin^{-1} 1\right)\right) \cdot \left(-{\sin^{-1} 1}^{3}\right)\right)}{{\left(\mathsf{fma}\left(\pi, \pi \cdot 0.25, \sin^{-1} 1 \cdot \mathsf{fma}\left(\pi, 0.5, \sin^{-1} 1\right)\right)\right)}^{2}}} \]
                6. Step-by-step derivation
                  1. distribute-rgt-neg-outN/A

                    \[\leadsto \frac{\left(\left(\mathsf{PI}\left(\right) \cdot \left(\mathsf{PI}\left(\right) \cdot \mathsf{PI}\left(\right)\right)\right) \cdot \frac{1}{8}\right) \cdot \left(\mathsf{PI}\left(\right) \cdot \left(\mathsf{PI}\left(\right) \cdot \frac{1}{4}\right) + \sin^{-1} 1 \cdot \left(\mathsf{PI}\left(\right) \cdot \frac{1}{2} + \sin^{-1} 1\right)\right) + \color{blue}{\left(\mathsf{neg}\left(\left(\mathsf{PI}\left(\right) \cdot \left(\mathsf{PI}\left(\right) \cdot \frac{1}{4}\right) + \sin^{-1} 1 \cdot \left(\mathsf{PI}\left(\right) \cdot \frac{1}{2} + \sin^{-1} 1\right)\right) \cdot {\sin^{-1} 1}^{3}\right)\right)}}{{\left(\mathsf{PI}\left(\right) \cdot \left(\mathsf{PI}\left(\right) \cdot \frac{1}{4}\right) + \sin^{-1} 1 \cdot \left(\mathsf{PI}\left(\right) \cdot \frac{1}{2} + \sin^{-1} 1\right)\right)}^{2}} \]
                  2. unsub-negN/A

                    \[\leadsto \frac{\color{blue}{\left(\left(\mathsf{PI}\left(\right) \cdot \left(\mathsf{PI}\left(\right) \cdot \mathsf{PI}\left(\right)\right)\right) \cdot \frac{1}{8}\right) \cdot \left(\mathsf{PI}\left(\right) \cdot \left(\mathsf{PI}\left(\right) \cdot \frac{1}{4}\right) + \sin^{-1} 1 \cdot \left(\mathsf{PI}\left(\right) \cdot \frac{1}{2} + \sin^{-1} 1\right)\right) - \left(\mathsf{PI}\left(\right) \cdot \left(\mathsf{PI}\left(\right) \cdot \frac{1}{4}\right) + \sin^{-1} 1 \cdot \left(\mathsf{PI}\left(\right) \cdot \frac{1}{2} + \sin^{-1} 1\right)\right) \cdot {\sin^{-1} 1}^{3}}}{{\left(\mathsf{PI}\left(\right) \cdot \left(\mathsf{PI}\left(\right) \cdot \frac{1}{4}\right) + \sin^{-1} 1 \cdot \left(\mathsf{PI}\left(\right) \cdot \frac{1}{2} + \sin^{-1} 1\right)\right)}^{2}} \]
                7. Applied egg-rr7.5%

                  \[\leadsto \color{blue}{\mathsf{fma}\left(\left(0.5 \cdot \sqrt{\pi}\right) \cdot \sqrt{\sqrt{\pi}}, \sqrt{\sqrt{\pi}}, -\sin^{-1} 1\right)} \]
              5. Recombined 2 regimes into one program.
              6. Add Preprocessing

              Alternative 8: 6.9% accurate, 1.0× speedup?

              \[\begin{array}{l} \\ \cos^{-1} \left(-x\right) \end{array} \]
              (FPCore (x) :precision binary64 (acos (- x)))
              double code(double x) {
              	return acos(-x);
              }
              
              real(8) function code(x)
                  real(8), intent (in) :: x
                  code = acos(-x)
              end function
              
              public static double code(double x) {
              	return Math.acos(-x);
              }
              
              def code(x):
              	return math.acos(-x)
              
              function code(x)
              	return acos(Float64(-x))
              end
              
              function tmp = code(x)
              	tmp = acos(-x);
              end
              
              code[x_] := N[ArcCos[(-x)], $MachinePrecision]
              
              \begin{array}{l}
              
              \\
              \cos^{-1} \left(-x\right)
              \end{array}
              
              Derivation
              1. Initial program 6.1%

                \[\cos^{-1} \left(1 - x\right) \]
              2. Add Preprocessing
              3. Taylor expanded in x around inf

                \[\leadsto \cos^{-1} \color{blue}{\left(-1 \cdot x\right)} \]
              4. Step-by-step derivation
                1. mul-1-negN/A

                  \[\leadsto \cos^{-1} \color{blue}{\left(\mathsf{neg}\left(x\right)\right)} \]
                2. neg-lowering-neg.f646.8

                  \[\leadsto \cos^{-1} \color{blue}{\left(-x\right)} \]
              5. Simplified6.8%

                \[\leadsto \cos^{-1} \color{blue}{\left(-x\right)} \]
              6. Add Preprocessing

              Alternative 9: 3.8% accurate, 1.0× speedup?

              \[\begin{array}{l} \\ \cos^{-1} 1 \end{array} \]
              (FPCore (x) :precision binary64 (acos 1.0))
              double code(double x) {
              	return acos(1.0);
              }
              
              real(8) function code(x)
                  real(8), intent (in) :: x
                  code = acos(1.0d0)
              end function
              
              public static double code(double x) {
              	return Math.acos(1.0);
              }
              
              def code(x):
              	return math.acos(1.0)
              
              function code(x)
              	return acos(1.0)
              end
              
              function tmp = code(x)
              	tmp = acos(1.0);
              end
              
              code[x_] := N[ArcCos[1.0], $MachinePrecision]
              
              \begin{array}{l}
              
              \\
              \cos^{-1} 1
              \end{array}
              
              Derivation
              1. Initial program 6.1%

                \[\cos^{-1} \left(1 - x\right) \]
              2. Add Preprocessing
              3. Taylor expanded in x around 0

                \[\leadsto \cos^{-1} \color{blue}{1} \]
              4. Step-by-step derivation
                1. Simplified3.8%

                  \[\leadsto \cos^{-1} \color{blue}{1} \]
                2. Add Preprocessing

                Developer Target 1: 100.0% accurate, 0.8× speedup?

                \[\begin{array}{l} \\ 2 \cdot \sin^{-1} \left(\sqrt{\frac{x}{2}}\right) \end{array} \]
                (FPCore (x) :precision binary64 (* 2.0 (asin (sqrt (/ x 2.0)))))
                double code(double x) {
                	return 2.0 * asin(sqrt((x / 2.0)));
                }
                
                real(8) function code(x)
                    real(8), intent (in) :: x
                    code = 2.0d0 * asin(sqrt((x / 2.0d0)))
                end function
                
                public static double code(double x) {
                	return 2.0 * Math.asin(Math.sqrt((x / 2.0)));
                }
                
                def code(x):
                	return 2.0 * math.asin(math.sqrt((x / 2.0)))
                
                function code(x)
                	return Float64(2.0 * asin(sqrt(Float64(x / 2.0))))
                end
                
                function tmp = code(x)
                	tmp = 2.0 * asin(sqrt((x / 2.0)));
                end
                
                code[x_] := N[(2.0 * N[ArcSin[N[Sqrt[N[(x / 2.0), $MachinePrecision]], $MachinePrecision]], $MachinePrecision]), $MachinePrecision]
                
                \begin{array}{l}
                
                \\
                2 \cdot \sin^{-1} \left(\sqrt{\frac{x}{2}}\right)
                \end{array}
                

                Reproduce

                ?
                herbie shell --seed 2024199 
                (FPCore (x)
                  :name "bug323 (missed optimization)"
                  :precision binary64
                  :pre (and (<= 0.0 x) (<= x 0.5))
                
                  :alt
                  (! :herbie-platform default (* 2 (asin (sqrt (/ x 2)))))
                
                  (acos (- 1.0 x)))