Trigonometry B

Percentage Accurate: 99.5% → 99.5%
Time: 15.1s
Alternatives: 9
Speedup: 1.0×

Specification

?
\[\begin{array}{l} \\ \begin{array}{l} t_0 := \tan x \cdot \tan x\\ \frac{1 - t\_0}{1 + t\_0} \end{array} \end{array} \]
(FPCore (x)
 :precision binary64
 (let* ((t_0 (* (tan x) (tan x)))) (/ (- 1.0 t_0) (+ 1.0 t_0))))
double code(double x) {
	double t_0 = tan(x) * tan(x);
	return (1.0 - t_0) / (1.0 + t_0);
}
real(8) function code(x)
    real(8), intent (in) :: x
    real(8) :: t_0
    t_0 = tan(x) * tan(x)
    code = (1.0d0 - t_0) / (1.0d0 + t_0)
end function
public static double code(double x) {
	double t_0 = Math.tan(x) * Math.tan(x);
	return (1.0 - t_0) / (1.0 + t_0);
}
def code(x):
	t_0 = math.tan(x) * math.tan(x)
	return (1.0 - t_0) / (1.0 + t_0)
function code(x)
	t_0 = Float64(tan(x) * tan(x))
	return Float64(Float64(1.0 - t_0) / Float64(1.0 + t_0))
end
function tmp = code(x)
	t_0 = tan(x) * tan(x);
	tmp = (1.0 - t_0) / (1.0 + t_0);
end
code[x_] := Block[{t$95$0 = N[(N[Tan[x], $MachinePrecision] * N[Tan[x], $MachinePrecision]), $MachinePrecision]}, N[(N[(1.0 - t$95$0), $MachinePrecision] / N[(1.0 + t$95$0), $MachinePrecision]), $MachinePrecision]]
\begin{array}{l}

\\
\begin{array}{l}
t_0 := \tan x \cdot \tan x\\
\frac{1 - t\_0}{1 + t\_0}
\end{array}
\end{array}

Sampling outcomes in binary64 precision:

Local Percentage Accuracy vs ?

The average percentage accuracy by input value. Horizontal axis shows value of an input variable; the variable is choosen in the title. Vertical axis is accuracy; higher is better. Red represent the original program, while blue represents Herbie's suggestion. These can be toggled with buttons below the plot. The line is an average while dots represent individual samples.

Accuracy vs Speed?

Herbie found 9 alternatives:

AlternativeAccuracySpeedup
The accuracy (vertical axis) and speed (horizontal axis) of each alternatives. Up and to the right is better. The red square shows the initial program, and each blue circle shows an alternative.The line shows the best available speed-accuracy tradeoffs.

Initial Program: 99.5% accurate, 1.0× speedup?

\[\begin{array}{l} \\ \begin{array}{l} t_0 := \tan x \cdot \tan x\\ \frac{1 - t\_0}{1 + t\_0} \end{array} \end{array} \]
(FPCore (x)
 :precision binary64
 (let* ((t_0 (* (tan x) (tan x)))) (/ (- 1.0 t_0) (+ 1.0 t_0))))
double code(double x) {
	double t_0 = tan(x) * tan(x);
	return (1.0 - t_0) / (1.0 + t_0);
}
real(8) function code(x)
    real(8), intent (in) :: x
    real(8) :: t_0
    t_0 = tan(x) * tan(x)
    code = (1.0d0 - t_0) / (1.0d0 + t_0)
end function
public static double code(double x) {
	double t_0 = Math.tan(x) * Math.tan(x);
	return (1.0 - t_0) / (1.0 + t_0);
}
def code(x):
	t_0 = math.tan(x) * math.tan(x)
	return (1.0 - t_0) / (1.0 + t_0)
function code(x)
	t_0 = Float64(tan(x) * tan(x))
	return Float64(Float64(1.0 - t_0) / Float64(1.0 + t_0))
end
function tmp = code(x)
	t_0 = tan(x) * tan(x);
	tmp = (1.0 - t_0) / (1.0 + t_0);
end
code[x_] := Block[{t$95$0 = N[(N[Tan[x], $MachinePrecision] * N[Tan[x], $MachinePrecision]), $MachinePrecision]}, N[(N[(1.0 - t$95$0), $MachinePrecision] / N[(1.0 + t$95$0), $MachinePrecision]), $MachinePrecision]]
\begin{array}{l}

\\
\begin{array}{l}
t_0 := \tan x \cdot \tan x\\
\frac{1 - t\_0}{1 + t\_0}
\end{array}
\end{array}

Alternative 1: 99.5% accurate, 0.9× speedup?

\[\begin{array}{l} \\ \begin{array}{l} t_0 := \cos \left(x + x\right)\\ \frac{1 - \frac{\mathsf{fma}\left(t\_0, -0.5, 0.5\right)}{\mathsf{fma}\left(0.5, t\_0, 0.5\right)}}{1 + \frac{\mathsf{fma}\left(t\_0, 0.5, -0.5\right)}{\mathsf{fma}\left(t\_0, -0.5, -0.5\right)}} \end{array} \end{array} \]
(FPCore (x)
 :precision binary64
 (let* ((t_0 (cos (+ x x))))
   (/
    (- 1.0 (/ (fma t_0 -0.5 0.5) (fma 0.5 t_0 0.5)))
    (+ 1.0 (/ (fma t_0 0.5 -0.5) (fma t_0 -0.5 -0.5))))))
double code(double x) {
	double t_0 = cos((x + x));
	return (1.0 - (fma(t_0, -0.5, 0.5) / fma(0.5, t_0, 0.5))) / (1.0 + (fma(t_0, 0.5, -0.5) / fma(t_0, -0.5, -0.5)));
}
function code(x)
	t_0 = cos(Float64(x + x))
	return Float64(Float64(1.0 - Float64(fma(t_0, -0.5, 0.5) / fma(0.5, t_0, 0.5))) / Float64(1.0 + Float64(fma(t_0, 0.5, -0.5) / fma(t_0, -0.5, -0.5))))
end
code[x_] := Block[{t$95$0 = N[Cos[N[(x + x), $MachinePrecision]], $MachinePrecision]}, N[(N[(1.0 - N[(N[(t$95$0 * -0.5 + 0.5), $MachinePrecision] / N[(0.5 * t$95$0 + 0.5), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] / N[(1.0 + N[(N[(t$95$0 * 0.5 + -0.5), $MachinePrecision] / N[(t$95$0 * -0.5 + -0.5), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]]
\begin{array}{l}

\\
\begin{array}{l}
t_0 := \cos \left(x + x\right)\\
\frac{1 - \frac{\mathsf{fma}\left(t\_0, -0.5, 0.5\right)}{\mathsf{fma}\left(0.5, t\_0, 0.5\right)}}{1 + \frac{\mathsf{fma}\left(t\_0, 0.5, -0.5\right)}{\mathsf{fma}\left(t\_0, -0.5, -0.5\right)}}
\end{array}
\end{array}
Derivation
  1. Initial program 99.5%

    \[\frac{1 - \tan x \cdot \tan x}{1 + \tan x \cdot \tan x} \]
  2. Add Preprocessing
  3. Step-by-step derivation
    1. tan-quotN/A

      \[\leadsto \frac{1 - \tan x \cdot \tan x}{1 + \color{blue}{\frac{\sin x}{\cos x}} \cdot \tan x} \]
    2. tan-quotN/A

      \[\leadsto \frac{1 - \tan x \cdot \tan x}{1 + \frac{\sin x}{\cos x} \cdot \color{blue}{\frac{\sin x}{\cos x}}} \]
    3. frac-timesN/A

      \[\leadsto \frac{1 - \tan x \cdot \tan x}{1 + \color{blue}{\frac{\sin x \cdot \sin x}{\cos x \cdot \cos x}}} \]
    4. /-lowering-/.f64N/A

      \[\leadsto \frac{1 - \tan x \cdot \tan x}{1 + \color{blue}{\frac{\sin x \cdot \sin x}{\cos x \cdot \cos x}}} \]
    5. sqr-sin-aN/A

      \[\leadsto \frac{1 - \tan x \cdot \tan x}{1 + \frac{\color{blue}{\frac{1}{2} - \frac{1}{2} \cdot \cos \left(2 \cdot x\right)}}{\cos x \cdot \cos x}} \]
    6. --lowering--.f64N/A

      \[\leadsto \frac{1 - \tan x \cdot \tan x}{1 + \frac{\color{blue}{\frac{1}{2} - \frac{1}{2} \cdot \cos \left(2 \cdot x\right)}}{\cos x \cdot \cos x}} \]
    7. cos-2N/A

      \[\leadsto \frac{1 - \tan x \cdot \tan x}{1 + \frac{\frac{1}{2} - \frac{1}{2} \cdot \color{blue}{\left(\cos x \cdot \cos x - \sin x \cdot \sin x\right)}}{\cos x \cdot \cos x}} \]
    8. cos-sumN/A

      \[\leadsto \frac{1 - \tan x \cdot \tan x}{1 + \frac{\frac{1}{2} - \frac{1}{2} \cdot \color{blue}{\cos \left(x + x\right)}}{\cos x \cdot \cos x}} \]
    9. *-lowering-*.f64N/A

      \[\leadsto \frac{1 - \tan x \cdot \tan x}{1 + \frac{\frac{1}{2} - \color{blue}{\frac{1}{2} \cdot \cos \left(x + x\right)}}{\cos x \cdot \cos x}} \]
    10. cos-lowering-cos.f64N/A

      \[\leadsto \frac{1 - \tan x \cdot \tan x}{1 + \frac{\frac{1}{2} - \frac{1}{2} \cdot \color{blue}{\cos \left(x + x\right)}}{\cos x \cdot \cos x}} \]
    11. +-lowering-+.f64N/A

      \[\leadsto \frac{1 - \tan x \cdot \tan x}{1 + \frac{\frac{1}{2} - \frac{1}{2} \cdot \cos \color{blue}{\left(x + x\right)}}{\cos x \cdot \cos x}} \]
    12. sqr-cos-aN/A

      \[\leadsto \frac{1 - \tan x \cdot \tan x}{1 + \frac{\frac{1}{2} - \frac{1}{2} \cdot \cos \left(x + x\right)}{\color{blue}{\frac{1}{2} + \frac{1}{2} \cdot \cos \left(2 \cdot x\right)}}} \]
    13. +-lowering-+.f64N/A

      \[\leadsto \frac{1 - \tan x \cdot \tan x}{1 + \frac{\frac{1}{2} - \frac{1}{2} \cdot \cos \left(x + x\right)}{\color{blue}{\frac{1}{2} + \frac{1}{2} \cdot \cos \left(2 \cdot x\right)}}} \]
    14. cos-2N/A

      \[\leadsto \frac{1 - \tan x \cdot \tan x}{1 + \frac{\frac{1}{2} - \frac{1}{2} \cdot \cos \left(x + x\right)}{\frac{1}{2} + \frac{1}{2} \cdot \color{blue}{\left(\cos x \cdot \cos x - \sin x \cdot \sin x\right)}}} \]
    15. cos-sumN/A

      \[\leadsto \frac{1 - \tan x \cdot \tan x}{1 + \frac{\frac{1}{2} - \frac{1}{2} \cdot \cos \left(x + x\right)}{\frac{1}{2} + \frac{1}{2} \cdot \color{blue}{\cos \left(x + x\right)}}} \]
    16. *-lowering-*.f64N/A

      \[\leadsto \frac{1 - \tan x \cdot \tan x}{1 + \frac{\frac{1}{2} - \frac{1}{2} \cdot \cos \left(x + x\right)}{\frac{1}{2} + \color{blue}{\frac{1}{2} \cdot \cos \left(x + x\right)}}} \]
    17. cos-lowering-cos.f64N/A

      \[\leadsto \frac{1 - \tan x \cdot \tan x}{1 + \frac{\frac{1}{2} - \frac{1}{2} \cdot \cos \left(x + x\right)}{\frac{1}{2} + \frac{1}{2} \cdot \color{blue}{\cos \left(x + x\right)}}} \]
    18. +-lowering-+.f6498.9

      \[\leadsto \frac{1 - \tan x \cdot \tan x}{1 + \frac{0.5 - 0.5 \cdot \cos \left(x + x\right)}{0.5 + 0.5 \cdot \cos \color{blue}{\left(x + x\right)}}} \]
  4. Applied egg-rr98.9%

    \[\leadsto \frac{1 - \tan x \cdot \tan x}{1 + \color{blue}{\frac{0.5 - 0.5 \cdot \cos \left(x + x\right)}{0.5 + 0.5 \cdot \cos \left(x + x\right)}}} \]
  5. Step-by-step derivation
    1. tan-quotN/A

      \[\leadsto \frac{1 - \color{blue}{\frac{\sin x}{\cos x}} \cdot \tan x}{1 + \frac{\frac{1}{2} - \frac{1}{2} \cdot \cos \left(x + x\right)}{\frac{1}{2} + \frac{1}{2} \cdot \cos \left(x + x\right)}} \]
    2. tan-quotN/A

      \[\leadsto \frac{1 - \frac{\sin x}{\cos x} \cdot \color{blue}{\frac{\sin x}{\cos x}}}{1 + \frac{\frac{1}{2} - \frac{1}{2} \cdot \cos \left(x + x\right)}{\frac{1}{2} + \frac{1}{2} \cdot \cos \left(x + x\right)}} \]
    3. frac-timesN/A

      \[\leadsto \frac{1 - \color{blue}{\frac{\sin x \cdot \sin x}{\cos x \cdot \cos x}}}{1 + \frac{\frac{1}{2} - \frac{1}{2} \cdot \cos \left(x + x\right)}{\frac{1}{2} + \frac{1}{2} \cdot \cos \left(x + x\right)}} \]
    4. sqr-sin-aN/A

      \[\leadsto \frac{1 - \frac{\color{blue}{\frac{1}{2} - \frac{1}{2} \cdot \cos \left(2 \cdot x\right)}}{\cos x \cdot \cos x}}{1 + \frac{\frac{1}{2} - \frac{1}{2} \cdot \cos \left(x + x\right)}{\frac{1}{2} + \frac{1}{2} \cdot \cos \left(x + x\right)}} \]
    5. count-2N/A

      \[\leadsto \frac{1 - \frac{\frac{1}{2} - \frac{1}{2} \cdot \cos \color{blue}{\left(x + x\right)}}{\cos x \cdot \cos x}}{1 + \frac{\frac{1}{2} - \frac{1}{2} \cdot \cos \left(x + x\right)}{\frac{1}{2} + \frac{1}{2} \cdot \cos \left(x + x\right)}} \]
    6. sqr-cos-aN/A

      \[\leadsto \frac{1 - \frac{\frac{1}{2} - \frac{1}{2} \cdot \cos \left(x + x\right)}{\color{blue}{\frac{1}{2} + \frac{1}{2} \cdot \cos \left(2 \cdot x\right)}}}{1 + \frac{\frac{1}{2} - \frac{1}{2} \cdot \cos \left(x + x\right)}{\frac{1}{2} + \frac{1}{2} \cdot \cos \left(x + x\right)}} \]
    7. count-2N/A

      \[\leadsto \frac{1 - \frac{\frac{1}{2} - \frac{1}{2} \cdot \cos \left(x + x\right)}{\frac{1}{2} + \frac{1}{2} \cdot \cos \color{blue}{\left(x + x\right)}}}{1 + \frac{\frac{1}{2} - \frac{1}{2} \cdot \cos \left(x + x\right)}{\frac{1}{2} + \frac{1}{2} \cdot \cos \left(x + x\right)}} \]
    8. /-lowering-/.f64N/A

      \[\leadsto \frac{1 - \color{blue}{\frac{\frac{1}{2} - \frac{1}{2} \cdot \cos \left(x + x\right)}{\frac{1}{2} + \frac{1}{2} \cdot \cos \left(x + x\right)}}}{1 + \frac{\frac{1}{2} - \frac{1}{2} \cdot \cos \left(x + x\right)}{\frac{1}{2} + \frac{1}{2} \cdot \cos \left(x + x\right)}} \]
  6. Applied egg-rr99.6%

    \[\leadsto \frac{1 - \color{blue}{\frac{\mathsf{fma}\left(\cos \left(x + x\right), -0.5, 0.5\right)}{\mathsf{fma}\left(0.5, \cos \left(x + x\right), 0.5\right)}}}{1 + \frac{0.5 - 0.5 \cdot \cos \left(x + x\right)}{0.5 + 0.5 \cdot \cos \left(x + x\right)}} \]
  7. Step-by-step derivation
    1. frac-2negN/A

      \[\leadsto \frac{1 - \frac{\mathsf{fma}\left(\cos \left(x + x\right), \frac{-1}{2}, \frac{1}{2}\right)}{\mathsf{fma}\left(\frac{1}{2}, \cos \left(x + x\right), \frac{1}{2}\right)}}{1 + \color{blue}{\frac{\mathsf{neg}\left(\left(\frac{1}{2} - \frac{1}{2} \cdot \cos \left(x + x\right)\right)\right)}{\mathsf{neg}\left(\left(\frac{1}{2} + \frac{1}{2} \cdot \cos \left(x + x\right)\right)\right)}}} \]
  8. Applied egg-rr99.6%

    \[\leadsto \frac{1 - \frac{\mathsf{fma}\left(\cos \left(x + x\right), -0.5, 0.5\right)}{\mathsf{fma}\left(0.5, \cos \left(x + x\right), 0.5\right)}}{1 + \color{blue}{\frac{\mathsf{fma}\left(\cos \left(x + x\right), 0.5, -0.5\right)}{\mathsf{fma}\left(\cos \left(x + x\right), -0.5, -0.5\right)}}} \]
  9. Add Preprocessing

Alternative 2: 99.5% accurate, 1.0× speedup?

\[\begin{array}{l} \\ \frac{\mathsf{fma}\left(0 - \tan x, \tan x, 1\right)}{1 + {\tan x}^{2}} \end{array} \]
(FPCore (x)
 :precision binary64
 (/ (fma (- 0.0 (tan x)) (tan x) 1.0) (+ 1.0 (pow (tan x) 2.0))))
double code(double x) {
	return fma((0.0 - tan(x)), tan(x), 1.0) / (1.0 + pow(tan(x), 2.0));
}
function code(x)
	return Float64(fma(Float64(0.0 - tan(x)), tan(x), 1.0) / Float64(1.0 + (tan(x) ^ 2.0)))
end
code[x_] := N[(N[(N[(0.0 - N[Tan[x], $MachinePrecision]), $MachinePrecision] * N[Tan[x], $MachinePrecision] + 1.0), $MachinePrecision] / N[(1.0 + N[Power[N[Tan[x], $MachinePrecision], 2.0], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
\frac{\mathsf{fma}\left(0 - \tan x, \tan x, 1\right)}{1 + {\tan x}^{2}}
\end{array}
Derivation
  1. Initial program 99.5%

    \[\frac{1 - \tan x \cdot \tan x}{1 + \tan x \cdot \tan x} \]
  2. Add Preprocessing
  3. Step-by-step derivation
    1. sub-negN/A

      \[\leadsto \frac{\color{blue}{1 + \left(\mathsf{neg}\left(\tan x \cdot \tan x\right)\right)}}{1 + \tan x \cdot \tan x} \]
    2. +-commutativeN/A

      \[\leadsto \frac{\color{blue}{\left(\mathsf{neg}\left(\tan x \cdot \tan x\right)\right) + 1}}{1 + \tan x \cdot \tan x} \]
    3. distribute-lft-neg-inN/A

      \[\leadsto \frac{\color{blue}{\left(\mathsf{neg}\left(\tan x\right)\right) \cdot \tan x} + 1}{1 + \tan x \cdot \tan x} \]
    4. accelerator-lowering-fma.f64N/A

      \[\leadsto \frac{\color{blue}{\mathsf{fma}\left(\mathsf{neg}\left(\tan x\right), \tan x, 1\right)}}{1 + \tan x \cdot \tan x} \]
    5. neg-sub0N/A

      \[\leadsto \frac{\mathsf{fma}\left(\color{blue}{0 - \tan x}, \tan x, 1\right)}{1 + \tan x \cdot \tan x} \]
    6. --lowering--.f64N/A

      \[\leadsto \frac{\mathsf{fma}\left(\color{blue}{0 - \tan x}, \tan x, 1\right)}{1 + \tan x \cdot \tan x} \]
    7. tan-lowering-tan.f64N/A

      \[\leadsto \frac{\mathsf{fma}\left(0 - \color{blue}{\tan x}, \tan x, 1\right)}{1 + \tan x \cdot \tan x} \]
    8. tan-lowering-tan.f6499.5

      \[\leadsto \frac{\mathsf{fma}\left(0 - \tan x, \color{blue}{\tan x}, 1\right)}{1 + \tan x \cdot \tan x} \]
  4. Applied egg-rr99.5%

    \[\leadsto \frac{\color{blue}{\mathsf{fma}\left(0 - \tan x, \tan x, 1\right)}}{1 + \tan x \cdot \tan x} \]
  5. Step-by-step derivation
    1. +-commutativeN/A

      \[\leadsto \frac{\mathsf{fma}\left(0 - \tan x, \tan x, 1\right)}{\color{blue}{\tan x \cdot \tan x + 1}} \]
    2. +-lowering-+.f64N/A

      \[\leadsto \frac{\mathsf{fma}\left(0 - \tan x, \tan x, 1\right)}{\color{blue}{\tan x \cdot \tan x + 1}} \]
    3. pow2N/A

      \[\leadsto \frac{\mathsf{fma}\left(0 - \tan x, \tan x, 1\right)}{\color{blue}{{\tan x}^{2}} + 1} \]
    4. pow-lowering-pow.f64N/A

      \[\leadsto \frac{\mathsf{fma}\left(0 - \tan x, \tan x, 1\right)}{\color{blue}{{\tan x}^{2}} + 1} \]
    5. tan-lowering-tan.f6499.5

      \[\leadsto \frac{\mathsf{fma}\left(0 - \tan x, \tan x, 1\right)}{{\color{blue}{\tan x}}^{2} + 1} \]
  6. Applied egg-rr99.5%

    \[\leadsto \frac{\mathsf{fma}\left(0 - \tan x, \tan x, 1\right)}{\color{blue}{{\tan x}^{2} + 1}} \]
  7. Step-by-step derivation
    1. sub0-negN/A

      \[\leadsto \frac{\mathsf{fma}\left(\color{blue}{\mathsf{neg}\left(\tan x\right)}, \tan x, 1\right)}{{\tan x}^{2} + 1} \]
    2. neg-lowering-neg.f64N/A

      \[\leadsto \frac{\mathsf{fma}\left(\color{blue}{\mathsf{neg}\left(\tan x\right)}, \tan x, 1\right)}{{\tan x}^{2} + 1} \]
    3. tan-lowering-tan.f6499.5

      \[\leadsto \frac{\mathsf{fma}\left(-\color{blue}{\tan x}, \tan x, 1\right)}{{\tan x}^{2} + 1} \]
  8. Applied egg-rr99.5%

    \[\leadsto \frac{\mathsf{fma}\left(\color{blue}{-\tan x}, \tan x, 1\right)}{{\tan x}^{2} + 1} \]
  9. Final simplification99.5%

    \[\leadsto \frac{\mathsf{fma}\left(0 - \tan x, \tan x, 1\right)}{1 + {\tan x}^{2}} \]
  10. Add Preprocessing

Alternative 3: 99.5% accurate, 1.0× speedup?

\[\begin{array}{l} \\ \frac{1 - {\tan x}^{2}}{\mathsf{fma}\left(\tan x, \tan x, 1\right)} \end{array} \]
(FPCore (x)
 :precision binary64
 (/ (- 1.0 (pow (tan x) 2.0)) (fma (tan x) (tan x) 1.0)))
double code(double x) {
	return (1.0 - pow(tan(x), 2.0)) / fma(tan(x), tan(x), 1.0);
}
function code(x)
	return Float64(Float64(1.0 - (tan(x) ^ 2.0)) / fma(tan(x), tan(x), 1.0))
end
code[x_] := N[(N[(1.0 - N[Power[N[Tan[x], $MachinePrecision], 2.0], $MachinePrecision]), $MachinePrecision] / N[(N[Tan[x], $MachinePrecision] * N[Tan[x], $MachinePrecision] + 1.0), $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
\frac{1 - {\tan x}^{2}}{\mathsf{fma}\left(\tan x, \tan x, 1\right)}
\end{array}
Derivation
  1. Initial program 99.5%

    \[\frac{1 - \tan x \cdot \tan x}{1 + \tan x \cdot \tan x} \]
  2. Add Preprocessing
  3. Step-by-step derivation
    1. +-commutativeN/A

      \[\leadsto \frac{1 - \tan x \cdot \tan x}{\color{blue}{\tan x \cdot \tan x + 1}} \]
    2. accelerator-lowering-fma.f64N/A

      \[\leadsto \frac{1 - \tan x \cdot \tan x}{\color{blue}{\mathsf{fma}\left(\tan x, \tan x, 1\right)}} \]
    3. tan-lowering-tan.f64N/A

      \[\leadsto \frac{1 - \tan x \cdot \tan x}{\mathsf{fma}\left(\color{blue}{\tan x}, \tan x, 1\right)} \]
    4. tan-lowering-tan.f6499.5

      \[\leadsto \frac{1 - \tan x \cdot \tan x}{\mathsf{fma}\left(\tan x, \color{blue}{\tan x}, 1\right)} \]
  4. Applied egg-rr99.5%

    \[\leadsto \frac{1 - \tan x \cdot \tan x}{\color{blue}{\mathsf{fma}\left(\tan x, \tan x, 1\right)}} \]
  5. Step-by-step derivation
    1. pow2N/A

      \[\leadsto \frac{1 - \color{blue}{{\tan x}^{2}}}{\mathsf{fma}\left(\tan x, \tan x, 1\right)} \]
    2. pow-lowering-pow.f64N/A

      \[\leadsto \frac{1 - \color{blue}{{\tan x}^{2}}}{\mathsf{fma}\left(\tan x, \tan x, 1\right)} \]
    3. tan-lowering-tan.f6499.5

      \[\leadsto \frac{1 - {\color{blue}{\tan x}}^{2}}{\mathsf{fma}\left(\tan x, \tan x, 1\right)} \]
  6. Applied egg-rr99.5%

    \[\leadsto \frac{1 - \color{blue}{{\tan x}^{2}}}{\mathsf{fma}\left(\tan x, \tan x, 1\right)} \]
  7. Add Preprocessing

Alternative 4: 99.5% accurate, 1.0× speedup?

\[\begin{array}{l} \\ \begin{array}{l} t_0 := {\tan x}^{2}\\ \frac{1 - t\_0}{1 + t\_0} \end{array} \end{array} \]
(FPCore (x)
 :precision binary64
 (let* ((t_0 (pow (tan x) 2.0))) (/ (- 1.0 t_0) (+ 1.0 t_0))))
double code(double x) {
	double t_0 = pow(tan(x), 2.0);
	return (1.0 - t_0) / (1.0 + t_0);
}
real(8) function code(x)
    real(8), intent (in) :: x
    real(8) :: t_0
    t_0 = tan(x) ** 2.0d0
    code = (1.0d0 - t_0) / (1.0d0 + t_0)
end function
public static double code(double x) {
	double t_0 = Math.pow(Math.tan(x), 2.0);
	return (1.0 - t_0) / (1.0 + t_0);
}
def code(x):
	t_0 = math.pow(math.tan(x), 2.0)
	return (1.0 - t_0) / (1.0 + t_0)
function code(x)
	t_0 = tan(x) ^ 2.0
	return Float64(Float64(1.0 - t_0) / Float64(1.0 + t_0))
end
function tmp = code(x)
	t_0 = tan(x) ^ 2.0;
	tmp = (1.0 - t_0) / (1.0 + t_0);
end
code[x_] := Block[{t$95$0 = N[Power[N[Tan[x], $MachinePrecision], 2.0], $MachinePrecision]}, N[(N[(1.0 - t$95$0), $MachinePrecision] / N[(1.0 + t$95$0), $MachinePrecision]), $MachinePrecision]]
\begin{array}{l}

\\
\begin{array}{l}
t_0 := {\tan x}^{2}\\
\frac{1 - t\_0}{1 + t\_0}
\end{array}
\end{array}
Derivation
  1. Initial program 99.5%

    \[\frac{1 - \tan x \cdot \tan x}{1 + \tan x \cdot \tan x} \]
  2. Add Preprocessing
  3. Step-by-step derivation
    1. sub-negN/A

      \[\leadsto \frac{\color{blue}{1 + \left(\mathsf{neg}\left(\tan x \cdot \tan x\right)\right)}}{1 + \tan x \cdot \tan x} \]
    2. +-commutativeN/A

      \[\leadsto \frac{\color{blue}{\left(\mathsf{neg}\left(\tan x \cdot \tan x\right)\right) + 1}}{1 + \tan x \cdot \tan x} \]
    3. distribute-lft-neg-inN/A

      \[\leadsto \frac{\color{blue}{\left(\mathsf{neg}\left(\tan x\right)\right) \cdot \tan x} + 1}{1 + \tan x \cdot \tan x} \]
    4. accelerator-lowering-fma.f64N/A

      \[\leadsto \frac{\color{blue}{\mathsf{fma}\left(\mathsf{neg}\left(\tan x\right), \tan x, 1\right)}}{1 + \tan x \cdot \tan x} \]
    5. neg-sub0N/A

      \[\leadsto \frac{\mathsf{fma}\left(\color{blue}{0 - \tan x}, \tan x, 1\right)}{1 + \tan x \cdot \tan x} \]
    6. --lowering--.f64N/A

      \[\leadsto \frac{\mathsf{fma}\left(\color{blue}{0 - \tan x}, \tan x, 1\right)}{1 + \tan x \cdot \tan x} \]
    7. tan-lowering-tan.f64N/A

      \[\leadsto \frac{\mathsf{fma}\left(0 - \color{blue}{\tan x}, \tan x, 1\right)}{1 + \tan x \cdot \tan x} \]
    8. tan-lowering-tan.f6499.5

      \[\leadsto \frac{\mathsf{fma}\left(0 - \tan x, \color{blue}{\tan x}, 1\right)}{1 + \tan x \cdot \tan x} \]
  4. Applied egg-rr99.5%

    \[\leadsto \frac{\color{blue}{\mathsf{fma}\left(0 - \tan x, \tan x, 1\right)}}{1 + \tan x \cdot \tan x} \]
  5. Step-by-step derivation
    1. +-commutativeN/A

      \[\leadsto \frac{\mathsf{fma}\left(0 - \tan x, \tan x, 1\right)}{\color{blue}{\tan x \cdot \tan x + 1}} \]
    2. +-lowering-+.f64N/A

      \[\leadsto \frac{\mathsf{fma}\left(0 - \tan x, \tan x, 1\right)}{\color{blue}{\tan x \cdot \tan x + 1}} \]
    3. pow2N/A

      \[\leadsto \frac{\mathsf{fma}\left(0 - \tan x, \tan x, 1\right)}{\color{blue}{{\tan x}^{2}} + 1} \]
    4. pow-lowering-pow.f64N/A

      \[\leadsto \frac{\mathsf{fma}\left(0 - \tan x, \tan x, 1\right)}{\color{blue}{{\tan x}^{2}} + 1} \]
    5. tan-lowering-tan.f6499.5

      \[\leadsto \frac{\mathsf{fma}\left(0 - \tan x, \tan x, 1\right)}{{\color{blue}{\tan x}}^{2} + 1} \]
  6. Applied egg-rr99.5%

    \[\leadsto \frac{\mathsf{fma}\left(0 - \tan x, \tan x, 1\right)}{\color{blue}{{\tan x}^{2} + 1}} \]
  7. Step-by-step derivation
    1. +-commutativeN/A

      \[\leadsto \frac{\color{blue}{1 + \left(0 - \tan x\right) \cdot \tan x}}{{\tan x}^{2} + 1} \]
    2. sub0-negN/A

      \[\leadsto \frac{1 + \color{blue}{\left(\mathsf{neg}\left(\tan x\right)\right)} \cdot \tan x}{{\tan x}^{2} + 1} \]
    3. cancel-sign-sub-invN/A

      \[\leadsto \frac{\color{blue}{1 - \tan x \cdot \tan x}}{{\tan x}^{2} + 1} \]
    4. --lowering--.f64N/A

      \[\leadsto \frac{\color{blue}{1 - \tan x \cdot \tan x}}{{\tan x}^{2} + 1} \]
    5. pow2N/A

      \[\leadsto \frac{1 - \color{blue}{{\tan x}^{2}}}{{\tan x}^{2} + 1} \]
    6. pow-lowering-pow.f64N/A

      \[\leadsto \frac{1 - \color{blue}{{\tan x}^{2}}}{{\tan x}^{2} + 1} \]
    7. tan-lowering-tan.f6499.5

      \[\leadsto \frac{1 - {\color{blue}{\tan x}}^{2}}{{\tan x}^{2} + 1} \]
  8. Applied egg-rr99.5%

    \[\leadsto \frac{\color{blue}{1 - {\tan x}^{2}}}{{\tan x}^{2} + 1} \]
  9. Final simplification99.5%

    \[\leadsto \frac{1 - {\tan x}^{2}}{1 + {\tan x}^{2}} \]
  10. Add Preprocessing

Alternative 5: 61.8% accurate, 1.2× speedup?

\[\begin{array}{l} \\ \begin{array}{l} t_0 := \cos \left(x + x\right)\\ \frac{1 - \frac{\mathsf{fma}\left(t\_0, -0.5, 0.5\right)}{\mathsf{fma}\left(0.5, t\_0, 0.5\right)}}{1 + \left(0.5 - t\_0 \cdot 0.5\right)} \end{array} \end{array} \]
(FPCore (x)
 :precision binary64
 (let* ((t_0 (cos (+ x x))))
   (/
    (- 1.0 (/ (fma t_0 -0.5 0.5) (fma 0.5 t_0 0.5)))
    (+ 1.0 (- 0.5 (* t_0 0.5))))))
double code(double x) {
	double t_0 = cos((x + x));
	return (1.0 - (fma(t_0, -0.5, 0.5) / fma(0.5, t_0, 0.5))) / (1.0 + (0.5 - (t_0 * 0.5)));
}
function code(x)
	t_0 = cos(Float64(x + x))
	return Float64(Float64(1.0 - Float64(fma(t_0, -0.5, 0.5) / fma(0.5, t_0, 0.5))) / Float64(1.0 + Float64(0.5 - Float64(t_0 * 0.5))))
end
code[x_] := Block[{t$95$0 = N[Cos[N[(x + x), $MachinePrecision]], $MachinePrecision]}, N[(N[(1.0 - N[(N[(t$95$0 * -0.5 + 0.5), $MachinePrecision] / N[(0.5 * t$95$0 + 0.5), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] / N[(1.0 + N[(0.5 - N[(t$95$0 * 0.5), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]]
\begin{array}{l}

\\
\begin{array}{l}
t_0 := \cos \left(x + x\right)\\
\frac{1 - \frac{\mathsf{fma}\left(t\_0, -0.5, 0.5\right)}{\mathsf{fma}\left(0.5, t\_0, 0.5\right)}}{1 + \left(0.5 - t\_0 \cdot 0.5\right)}
\end{array}
\end{array}
Derivation
  1. Initial program 99.5%

    \[\frac{1 - \tan x \cdot \tan x}{1 + \tan x \cdot \tan x} \]
  2. Add Preprocessing
  3. Step-by-step derivation
    1. tan-quotN/A

      \[\leadsto \frac{1 - \tan x \cdot \tan x}{1 + \color{blue}{\frac{\sin x}{\cos x}} \cdot \tan x} \]
    2. tan-quotN/A

      \[\leadsto \frac{1 - \tan x \cdot \tan x}{1 + \frac{\sin x}{\cos x} \cdot \color{blue}{\frac{\sin x}{\cos x}}} \]
    3. frac-timesN/A

      \[\leadsto \frac{1 - \tan x \cdot \tan x}{1 + \color{blue}{\frac{\sin x \cdot \sin x}{\cos x \cdot \cos x}}} \]
    4. /-lowering-/.f64N/A

      \[\leadsto \frac{1 - \tan x \cdot \tan x}{1 + \color{blue}{\frac{\sin x \cdot \sin x}{\cos x \cdot \cos x}}} \]
    5. sqr-sin-aN/A

      \[\leadsto \frac{1 - \tan x \cdot \tan x}{1 + \frac{\color{blue}{\frac{1}{2} - \frac{1}{2} \cdot \cos \left(2 \cdot x\right)}}{\cos x \cdot \cos x}} \]
    6. --lowering--.f64N/A

      \[\leadsto \frac{1 - \tan x \cdot \tan x}{1 + \frac{\color{blue}{\frac{1}{2} - \frac{1}{2} \cdot \cos \left(2 \cdot x\right)}}{\cos x \cdot \cos x}} \]
    7. cos-2N/A

      \[\leadsto \frac{1 - \tan x \cdot \tan x}{1 + \frac{\frac{1}{2} - \frac{1}{2} \cdot \color{blue}{\left(\cos x \cdot \cos x - \sin x \cdot \sin x\right)}}{\cos x \cdot \cos x}} \]
    8. cos-sumN/A

      \[\leadsto \frac{1 - \tan x \cdot \tan x}{1 + \frac{\frac{1}{2} - \frac{1}{2} \cdot \color{blue}{\cos \left(x + x\right)}}{\cos x \cdot \cos x}} \]
    9. *-lowering-*.f64N/A

      \[\leadsto \frac{1 - \tan x \cdot \tan x}{1 + \frac{\frac{1}{2} - \color{blue}{\frac{1}{2} \cdot \cos \left(x + x\right)}}{\cos x \cdot \cos x}} \]
    10. cos-lowering-cos.f64N/A

      \[\leadsto \frac{1 - \tan x \cdot \tan x}{1 + \frac{\frac{1}{2} - \frac{1}{2} \cdot \color{blue}{\cos \left(x + x\right)}}{\cos x \cdot \cos x}} \]
    11. +-lowering-+.f64N/A

      \[\leadsto \frac{1 - \tan x \cdot \tan x}{1 + \frac{\frac{1}{2} - \frac{1}{2} \cdot \cos \color{blue}{\left(x + x\right)}}{\cos x \cdot \cos x}} \]
    12. sqr-cos-aN/A

      \[\leadsto \frac{1 - \tan x \cdot \tan x}{1 + \frac{\frac{1}{2} - \frac{1}{2} \cdot \cos \left(x + x\right)}{\color{blue}{\frac{1}{2} + \frac{1}{2} \cdot \cos \left(2 \cdot x\right)}}} \]
    13. +-lowering-+.f64N/A

      \[\leadsto \frac{1 - \tan x \cdot \tan x}{1 + \frac{\frac{1}{2} - \frac{1}{2} \cdot \cos \left(x + x\right)}{\color{blue}{\frac{1}{2} + \frac{1}{2} \cdot \cos \left(2 \cdot x\right)}}} \]
    14. cos-2N/A

      \[\leadsto \frac{1 - \tan x \cdot \tan x}{1 + \frac{\frac{1}{2} - \frac{1}{2} \cdot \cos \left(x + x\right)}{\frac{1}{2} + \frac{1}{2} \cdot \color{blue}{\left(\cos x \cdot \cos x - \sin x \cdot \sin x\right)}}} \]
    15. cos-sumN/A

      \[\leadsto \frac{1 - \tan x \cdot \tan x}{1 + \frac{\frac{1}{2} - \frac{1}{2} \cdot \cos \left(x + x\right)}{\frac{1}{2} + \frac{1}{2} \cdot \color{blue}{\cos \left(x + x\right)}}} \]
    16. *-lowering-*.f64N/A

      \[\leadsto \frac{1 - \tan x \cdot \tan x}{1 + \frac{\frac{1}{2} - \frac{1}{2} \cdot \cos \left(x + x\right)}{\frac{1}{2} + \color{blue}{\frac{1}{2} \cdot \cos \left(x + x\right)}}} \]
    17. cos-lowering-cos.f64N/A

      \[\leadsto \frac{1 - \tan x \cdot \tan x}{1 + \frac{\frac{1}{2} - \frac{1}{2} \cdot \cos \left(x + x\right)}{\frac{1}{2} + \frac{1}{2} \cdot \color{blue}{\cos \left(x + x\right)}}} \]
    18. +-lowering-+.f6498.9

      \[\leadsto \frac{1 - \tan x \cdot \tan x}{1 + \frac{0.5 - 0.5 \cdot \cos \left(x + x\right)}{0.5 + 0.5 \cdot \cos \color{blue}{\left(x + x\right)}}} \]
  4. Applied egg-rr98.9%

    \[\leadsto \frac{1 - \tan x \cdot \tan x}{1 + \color{blue}{\frac{0.5 - 0.5 \cdot \cos \left(x + x\right)}{0.5 + 0.5 \cdot \cos \left(x + x\right)}}} \]
  5. Step-by-step derivation
    1. tan-quotN/A

      \[\leadsto \frac{1 - \color{blue}{\frac{\sin x}{\cos x}} \cdot \tan x}{1 + \frac{\frac{1}{2} - \frac{1}{2} \cdot \cos \left(x + x\right)}{\frac{1}{2} + \frac{1}{2} \cdot \cos \left(x + x\right)}} \]
    2. tan-quotN/A

      \[\leadsto \frac{1 - \frac{\sin x}{\cos x} \cdot \color{blue}{\frac{\sin x}{\cos x}}}{1 + \frac{\frac{1}{2} - \frac{1}{2} \cdot \cos \left(x + x\right)}{\frac{1}{2} + \frac{1}{2} \cdot \cos \left(x + x\right)}} \]
    3. frac-timesN/A

      \[\leadsto \frac{1 - \color{blue}{\frac{\sin x \cdot \sin x}{\cos x \cdot \cos x}}}{1 + \frac{\frac{1}{2} - \frac{1}{2} \cdot \cos \left(x + x\right)}{\frac{1}{2} + \frac{1}{2} \cdot \cos \left(x + x\right)}} \]
    4. sqr-sin-aN/A

      \[\leadsto \frac{1 - \frac{\color{blue}{\frac{1}{2} - \frac{1}{2} \cdot \cos \left(2 \cdot x\right)}}{\cos x \cdot \cos x}}{1 + \frac{\frac{1}{2} - \frac{1}{2} \cdot \cos \left(x + x\right)}{\frac{1}{2} + \frac{1}{2} \cdot \cos \left(x + x\right)}} \]
    5. count-2N/A

      \[\leadsto \frac{1 - \frac{\frac{1}{2} - \frac{1}{2} \cdot \cos \color{blue}{\left(x + x\right)}}{\cos x \cdot \cos x}}{1 + \frac{\frac{1}{2} - \frac{1}{2} \cdot \cos \left(x + x\right)}{\frac{1}{2} + \frac{1}{2} \cdot \cos \left(x + x\right)}} \]
    6. sqr-cos-aN/A

      \[\leadsto \frac{1 - \frac{\frac{1}{2} - \frac{1}{2} \cdot \cos \left(x + x\right)}{\color{blue}{\frac{1}{2} + \frac{1}{2} \cdot \cos \left(2 \cdot x\right)}}}{1 + \frac{\frac{1}{2} - \frac{1}{2} \cdot \cos \left(x + x\right)}{\frac{1}{2} + \frac{1}{2} \cdot \cos \left(x + x\right)}} \]
    7. count-2N/A

      \[\leadsto \frac{1 - \frac{\frac{1}{2} - \frac{1}{2} \cdot \cos \left(x + x\right)}{\frac{1}{2} + \frac{1}{2} \cdot \cos \color{blue}{\left(x + x\right)}}}{1 + \frac{\frac{1}{2} - \frac{1}{2} \cdot \cos \left(x + x\right)}{\frac{1}{2} + \frac{1}{2} \cdot \cos \left(x + x\right)}} \]
    8. /-lowering-/.f64N/A

      \[\leadsto \frac{1 - \color{blue}{\frac{\frac{1}{2} - \frac{1}{2} \cdot \cos \left(x + x\right)}{\frac{1}{2} + \frac{1}{2} \cdot \cos \left(x + x\right)}}}{1 + \frac{\frac{1}{2} - \frac{1}{2} \cdot \cos \left(x + x\right)}{\frac{1}{2} + \frac{1}{2} \cdot \cos \left(x + x\right)}} \]
  6. Applied egg-rr99.6%

    \[\leadsto \frac{1 - \color{blue}{\frac{\mathsf{fma}\left(\cos \left(x + x\right), -0.5, 0.5\right)}{\mathsf{fma}\left(0.5, \cos \left(x + x\right), 0.5\right)}}}{1 + \frac{0.5 - 0.5 \cdot \cos \left(x + x\right)}{0.5 + 0.5 \cdot \cos \left(x + x\right)}} \]
  7. Taylor expanded in x around 0

    \[\leadsto \frac{1 - \frac{\mathsf{fma}\left(\cos \left(x + x\right), \frac{-1}{2}, \frac{1}{2}\right)}{\mathsf{fma}\left(\frac{1}{2}, \cos \left(x + x\right), \frac{1}{2}\right)}}{1 + \frac{\frac{1}{2} - \frac{1}{2} \cdot \cos \left(x + x\right)}{\color{blue}{1}}} \]
  8. Step-by-step derivation
    1. Simplified58.8%

      \[\leadsto \frac{1 - \frac{\mathsf{fma}\left(\cos \left(x + x\right), -0.5, 0.5\right)}{\mathsf{fma}\left(0.5, \cos \left(x + x\right), 0.5\right)}}{1 + \frac{0.5 - 0.5 \cdot \cos \left(x + x\right)}{\color{blue}{1}}} \]
    2. Final simplification58.8%

      \[\leadsto \frac{1 - \frac{\mathsf{fma}\left(\cos \left(x + x\right), -0.5, 0.5\right)}{\mathsf{fma}\left(0.5, \cos \left(x + x\right), 0.5\right)}}{1 + \left(0.5 - \cos \left(x + x\right) \cdot 0.5\right)} \]
    3. Add Preprocessing

    Alternative 6: 61.8% accurate, 1.3× speedup?

    \[\begin{array}{l} \\ \frac{1 - \tan x \cdot \tan x}{\mathsf{fma}\left(0.5 - 0.5 \cdot \cos \left(x \cdot 2\right), 1, 1\right)} \end{array} \]
    (FPCore (x)
     :precision binary64
     (/ (- 1.0 (* (tan x) (tan x))) (fma (- 0.5 (* 0.5 (cos (* x 2.0)))) 1.0 1.0)))
    double code(double x) {
    	return (1.0 - (tan(x) * tan(x))) / fma((0.5 - (0.5 * cos((x * 2.0)))), 1.0, 1.0);
    }
    
    function code(x)
    	return Float64(Float64(1.0 - Float64(tan(x) * tan(x))) / fma(Float64(0.5 - Float64(0.5 * cos(Float64(x * 2.0)))), 1.0, 1.0))
    end
    
    code[x_] := N[(N[(1.0 - N[(N[Tan[x], $MachinePrecision] * N[Tan[x], $MachinePrecision]), $MachinePrecision]), $MachinePrecision] / N[(N[(0.5 - N[(0.5 * N[Cos[N[(x * 2.0), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision] * 1.0 + 1.0), $MachinePrecision]), $MachinePrecision]
    
    \begin{array}{l}
    
    \\
    \frac{1 - \tan x \cdot \tan x}{\mathsf{fma}\left(0.5 - 0.5 \cdot \cos \left(x \cdot 2\right), 1, 1\right)}
    \end{array}
    
    Derivation
    1. Initial program 99.5%

      \[\frac{1 - \tan x \cdot \tan x}{1 + \tan x \cdot \tan x} \]
    2. Add Preprocessing
    3. Step-by-step derivation
      1. +-commutativeN/A

        \[\leadsto \frac{1 - \tan x \cdot \tan x}{\color{blue}{\tan x \cdot \tan x + 1}} \]
      2. tan-quotN/A

        \[\leadsto \frac{1 - \tan x \cdot \tan x}{\color{blue}{\frac{\sin x}{\cos x}} \cdot \tan x + 1} \]
      3. associate-*l/N/A

        \[\leadsto \frac{1 - \tan x \cdot \tan x}{\color{blue}{\frac{\sin x \cdot \tan x}{\cos x}} + 1} \]
      4. associate-/l*N/A

        \[\leadsto \frac{1 - \tan x \cdot \tan x}{\color{blue}{\sin x \cdot \frac{\tan x}{\cos x}} + 1} \]
      5. accelerator-lowering-fma.f64N/A

        \[\leadsto \frac{1 - \tan x \cdot \tan x}{\color{blue}{\mathsf{fma}\left(\sin x, \frac{\tan x}{\cos x}, 1\right)}} \]
      6. sin-lowering-sin.f64N/A

        \[\leadsto \frac{1 - \tan x \cdot \tan x}{\mathsf{fma}\left(\color{blue}{\sin x}, \frac{\tan x}{\cos x}, 1\right)} \]
      7. /-lowering-/.f64N/A

        \[\leadsto \frac{1 - \tan x \cdot \tan x}{\mathsf{fma}\left(\sin x, \color{blue}{\frac{\tan x}{\cos x}}, 1\right)} \]
      8. tan-lowering-tan.f64N/A

        \[\leadsto \frac{1 - \tan x \cdot \tan x}{\mathsf{fma}\left(\sin x, \frac{\color{blue}{\tan x}}{\cos x}, 1\right)} \]
      9. cos-lowering-cos.f6499.4

        \[\leadsto \frac{1 - \tan x \cdot \tan x}{\mathsf{fma}\left(\sin x, \frac{\tan x}{\color{blue}{\cos x}}, 1\right)} \]
    4. Applied egg-rr99.4%

      \[\leadsto \frac{1 - \tan x \cdot \tan x}{\color{blue}{\mathsf{fma}\left(\sin x, \frac{\tan x}{\cos x}, 1\right)}} \]
    5. Step-by-step derivation
      1. associate-*r/N/A

        \[\leadsto \frac{1 - \tan x \cdot \tan x}{\color{blue}{\frac{\sin x \cdot \tan x}{\cos x}} + 1} \]
      2. associate-*l/N/A

        \[\leadsto \frac{1 - \tan x \cdot \tan x}{\color{blue}{\frac{\sin x}{\cos x} \cdot \tan x} + 1} \]
      3. tan-quotN/A

        \[\leadsto \frac{1 - \tan x \cdot \tan x}{\color{blue}{\tan x} \cdot \tan x + 1} \]
      4. pow2N/A

        \[\leadsto \frac{1 - \tan x \cdot \tan x}{\color{blue}{{\tan x}^{2}} + 1} \]
      5. tan-quotN/A

        \[\leadsto \frac{1 - \tan x \cdot \tan x}{{\color{blue}{\left(\frac{\sin x}{\cos x}\right)}}^{2} + 1} \]
      6. div-invN/A

        \[\leadsto \frac{1 - \tan x \cdot \tan x}{{\color{blue}{\left(\sin x \cdot \frac{1}{\cos x}\right)}}^{2} + 1} \]
      7. unpow-prod-downN/A

        \[\leadsto \frac{1 - \tan x \cdot \tan x}{\color{blue}{{\sin x}^{2} \cdot {\left(\frac{1}{\cos x}\right)}^{2}} + 1} \]
      8. pow2N/A

        \[\leadsto \frac{1 - \tan x \cdot \tan x}{\color{blue}{\left(\sin x \cdot \sin x\right)} \cdot {\left(\frac{1}{\cos x}\right)}^{2} + 1} \]
      9. accelerator-lowering-fma.f64N/A

        \[\leadsto \frac{1 - \tan x \cdot \tan x}{\color{blue}{\mathsf{fma}\left(\sin x \cdot \sin x, {\left(\frac{1}{\cos x}\right)}^{2}, 1\right)}} \]
    6. Applied egg-rr99.3%

      \[\leadsto \frac{1 - \tan x \cdot \tan x}{\color{blue}{\mathsf{fma}\left(0.5 - 0.5 \cdot \cos \left(2 \cdot x\right), {\left(\frac{1}{\cos x}\right)}^{2}, 1\right)}} \]
    7. Taylor expanded in x around 0

      \[\leadsto \frac{1 - \tan x \cdot \tan x}{\mathsf{fma}\left(\frac{1}{2} - \frac{1}{2} \cdot \cos \left(2 \cdot x\right), \color{blue}{1}, 1\right)} \]
    8. Step-by-step derivation
      1. Simplified58.8%

        \[\leadsto \frac{1 - \tan x \cdot \tan x}{\mathsf{fma}\left(0.5 - 0.5 \cdot \cos \left(2 \cdot x\right), \color{blue}{1}, 1\right)} \]
      2. Final simplification58.8%

        \[\leadsto \frac{1 - \tan x \cdot \tan x}{\mathsf{fma}\left(0.5 - 0.5 \cdot \cos \left(x \cdot 2\right), 1, 1\right)} \]
      3. Add Preprocessing

      Alternative 7: 55.9% accurate, 2.0× speedup?

      \[\begin{array}{l} \\ \frac{1}{1 + {\tan x}^{2}} \end{array} \]
      (FPCore (x) :precision binary64 (/ 1.0 (+ 1.0 (pow (tan x) 2.0))))
      double code(double x) {
      	return 1.0 / (1.0 + pow(tan(x), 2.0));
      }
      
      real(8) function code(x)
          real(8), intent (in) :: x
          code = 1.0d0 / (1.0d0 + (tan(x) ** 2.0d0))
      end function
      
      public static double code(double x) {
      	return 1.0 / (1.0 + Math.pow(Math.tan(x), 2.0));
      }
      
      def code(x):
      	return 1.0 / (1.0 + math.pow(math.tan(x), 2.0))
      
      function code(x)
      	return Float64(1.0 / Float64(1.0 + (tan(x) ^ 2.0)))
      end
      
      function tmp = code(x)
      	tmp = 1.0 / (1.0 + (tan(x) ^ 2.0));
      end
      
      code[x_] := N[(1.0 / N[(1.0 + N[Power[N[Tan[x], $MachinePrecision], 2.0], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
      
      \begin{array}{l}
      
      \\
      \frac{1}{1 + {\tan x}^{2}}
      \end{array}
      
      Derivation
      1. Initial program 99.5%

        \[\frac{1 - \tan x \cdot \tan x}{1 + \tan x \cdot \tan x} \]
      2. Add Preprocessing
      3. Step-by-step derivation
        1. sub-negN/A

          \[\leadsto \frac{\color{blue}{1 + \left(\mathsf{neg}\left(\tan x \cdot \tan x\right)\right)}}{1 + \tan x \cdot \tan x} \]
        2. +-commutativeN/A

          \[\leadsto \frac{\color{blue}{\left(\mathsf{neg}\left(\tan x \cdot \tan x\right)\right) + 1}}{1 + \tan x \cdot \tan x} \]
        3. distribute-lft-neg-inN/A

          \[\leadsto \frac{\color{blue}{\left(\mathsf{neg}\left(\tan x\right)\right) \cdot \tan x} + 1}{1 + \tan x \cdot \tan x} \]
        4. accelerator-lowering-fma.f64N/A

          \[\leadsto \frac{\color{blue}{\mathsf{fma}\left(\mathsf{neg}\left(\tan x\right), \tan x, 1\right)}}{1 + \tan x \cdot \tan x} \]
        5. neg-sub0N/A

          \[\leadsto \frac{\mathsf{fma}\left(\color{blue}{0 - \tan x}, \tan x, 1\right)}{1 + \tan x \cdot \tan x} \]
        6. --lowering--.f64N/A

          \[\leadsto \frac{\mathsf{fma}\left(\color{blue}{0 - \tan x}, \tan x, 1\right)}{1 + \tan x \cdot \tan x} \]
        7. tan-lowering-tan.f64N/A

          \[\leadsto \frac{\mathsf{fma}\left(0 - \color{blue}{\tan x}, \tan x, 1\right)}{1 + \tan x \cdot \tan x} \]
        8. tan-lowering-tan.f6499.5

          \[\leadsto \frac{\mathsf{fma}\left(0 - \tan x, \color{blue}{\tan x}, 1\right)}{1 + \tan x \cdot \tan x} \]
      4. Applied egg-rr99.5%

        \[\leadsto \frac{\color{blue}{\mathsf{fma}\left(0 - \tan x, \tan x, 1\right)}}{1 + \tan x \cdot \tan x} \]
      5. Step-by-step derivation
        1. +-commutativeN/A

          \[\leadsto \frac{\mathsf{fma}\left(0 - \tan x, \tan x, 1\right)}{\color{blue}{\tan x \cdot \tan x + 1}} \]
        2. +-lowering-+.f64N/A

          \[\leadsto \frac{\mathsf{fma}\left(0 - \tan x, \tan x, 1\right)}{\color{blue}{\tan x \cdot \tan x + 1}} \]
        3. pow2N/A

          \[\leadsto \frac{\mathsf{fma}\left(0 - \tan x, \tan x, 1\right)}{\color{blue}{{\tan x}^{2}} + 1} \]
        4. pow-lowering-pow.f64N/A

          \[\leadsto \frac{\mathsf{fma}\left(0 - \tan x, \tan x, 1\right)}{\color{blue}{{\tan x}^{2}} + 1} \]
        5. tan-lowering-tan.f6499.5

          \[\leadsto \frac{\mathsf{fma}\left(0 - \tan x, \tan x, 1\right)}{{\color{blue}{\tan x}}^{2} + 1} \]
      6. Applied egg-rr99.5%

        \[\leadsto \frac{\mathsf{fma}\left(0 - \tan x, \tan x, 1\right)}{\color{blue}{{\tan x}^{2} + 1}} \]
      7. Taylor expanded in x around 0

        \[\leadsto \frac{\color{blue}{1}}{{\tan x}^{2} + 1} \]
      8. Step-by-step derivation
        1. Simplified52.2%

          \[\leadsto \frac{\color{blue}{1}}{{\tan x}^{2} + 1} \]
        2. Final simplification52.2%

          \[\leadsto \frac{1}{1 + {\tan x}^{2}} \]
        3. Add Preprocessing

        Alternative 8: 59.7% accurate, 2.0× speedup?

        \[\begin{array}{l} \\ 1 - \tan x \cdot \tan x \end{array} \]
        (FPCore (x) :precision binary64 (- 1.0 (* (tan x) (tan x))))
        double code(double x) {
        	return 1.0 - (tan(x) * tan(x));
        }
        
        real(8) function code(x)
            real(8), intent (in) :: x
            code = 1.0d0 - (tan(x) * tan(x))
        end function
        
        public static double code(double x) {
        	return 1.0 - (Math.tan(x) * Math.tan(x));
        }
        
        def code(x):
        	return 1.0 - (math.tan(x) * math.tan(x))
        
        function code(x)
        	return Float64(1.0 - Float64(tan(x) * tan(x)))
        end
        
        function tmp = code(x)
        	tmp = 1.0 - (tan(x) * tan(x));
        end
        
        code[x_] := N[(1.0 - N[(N[Tan[x], $MachinePrecision] * N[Tan[x], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
        
        \begin{array}{l}
        
        \\
        1 - \tan x \cdot \tan x
        \end{array}
        
        Derivation
        1. Initial program 99.5%

          \[\frac{1 - \tan x \cdot \tan x}{1 + \tan x \cdot \tan x} \]
        2. Add Preprocessing
        3. Taylor expanded in x around 0

          \[\leadsto \frac{1 - \tan x \cdot \tan x}{\color{blue}{1}} \]
        4. Step-by-step derivation
          1. Simplified56.4%

            \[\leadsto \frac{1 - \tan x \cdot \tan x}{\color{blue}{1}} \]
          2. Final simplification56.4%

            \[\leadsto 1 - \tan x \cdot \tan x \]
          3. Add Preprocessing

          Alternative 9: 55.5% accurate, 428.0× speedup?

          \[\begin{array}{l} \\ 1 \end{array} \]
          (FPCore (x) :precision binary64 1.0)
          double code(double x) {
          	return 1.0;
          }
          
          real(8) function code(x)
              real(8), intent (in) :: x
              code = 1.0d0
          end function
          
          public static double code(double x) {
          	return 1.0;
          }
          
          def code(x):
          	return 1.0
          
          function code(x)
          	return 1.0
          end
          
          function tmp = code(x)
          	tmp = 1.0;
          end
          
          code[x_] := 1.0
          
          \begin{array}{l}
          
          \\
          1
          \end{array}
          
          Derivation
          1. Initial program 99.5%

            \[\frac{1 - \tan x \cdot \tan x}{1 + \tan x \cdot \tan x} \]
          2. Add Preprocessing
          3. Applied egg-rr51.8%

            \[\leadsto \color{blue}{1} \]
          4. Add Preprocessing

          Reproduce

          ?
          herbie shell --seed 2024196 
          (FPCore (x)
            :name "Trigonometry B"
            :precision binary64
            (/ (- 1.0 (* (tan x) (tan x))) (+ 1.0 (* (tan x) (tan x)))))