Data.Random.Distribution.Triangular:triangularCDF from random-fu-0.2.6.2, A

Percentage Accurate: 99.2% → 98.7%
Time: 11.3s
Alternatives: 11
Speedup: 1.0×

Specification

?
\[\begin{array}{l} \\ 1 - \frac{x}{\left(y - z\right) \cdot \left(y - t\right)} \end{array} \]
(FPCore (x y z t) :precision binary64 (- 1.0 (/ x (* (- y z) (- y t)))))
double code(double x, double y, double z, double t) {
	return 1.0 - (x / ((y - z) * (y - t)));
}
real(8) function code(x, y, z, t)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    real(8), intent (in) :: z
    real(8), intent (in) :: t
    code = 1.0d0 - (x / ((y - z) * (y - t)))
end function
public static double code(double x, double y, double z, double t) {
	return 1.0 - (x / ((y - z) * (y - t)));
}
def code(x, y, z, t):
	return 1.0 - (x / ((y - z) * (y - t)))
function code(x, y, z, t)
	return Float64(1.0 - Float64(x / Float64(Float64(y - z) * Float64(y - t))))
end
function tmp = code(x, y, z, t)
	tmp = 1.0 - (x / ((y - z) * (y - t)));
end
code[x_, y_, z_, t_] := N[(1.0 - N[(x / N[(N[(y - z), $MachinePrecision] * N[(y - t), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
1 - \frac{x}{\left(y - z\right) \cdot \left(y - t\right)}
\end{array}

Sampling outcomes in binary64 precision:

Local Percentage Accuracy vs ?

The average percentage accuracy by input value. Horizontal axis shows value of an input variable; the variable is choosen in the title. Vertical axis is accuracy; higher is better. Red represent the original program, while blue represents Herbie's suggestion. These can be toggled with buttons below the plot. The line is an average while dots represent individual samples.

Accuracy vs Speed?

Herbie found 11 alternatives:

AlternativeAccuracySpeedup
The accuracy (vertical axis) and speed (horizontal axis) of each alternatives. Up and to the right is better. The red square shows the initial program, and each blue circle shows an alternative.The line shows the best available speed-accuracy tradeoffs.

Initial Program: 99.2% accurate, 1.0× speedup?

\[\begin{array}{l} \\ 1 - \frac{x}{\left(y - z\right) \cdot \left(y - t\right)} \end{array} \]
(FPCore (x y z t) :precision binary64 (- 1.0 (/ x (* (- y z) (- y t)))))
double code(double x, double y, double z, double t) {
	return 1.0 - (x / ((y - z) * (y - t)));
}
real(8) function code(x, y, z, t)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    real(8), intent (in) :: z
    real(8), intent (in) :: t
    code = 1.0d0 - (x / ((y - z) * (y - t)))
end function
public static double code(double x, double y, double z, double t) {
	return 1.0 - (x / ((y - z) * (y - t)));
}
def code(x, y, z, t):
	return 1.0 - (x / ((y - z) * (y - t)))
function code(x, y, z, t)
	return Float64(1.0 - Float64(x / Float64(Float64(y - z) * Float64(y - t))))
end
function tmp = code(x, y, z, t)
	tmp = 1.0 - (x / ((y - z) * (y - t)));
end
code[x_, y_, z_, t_] := N[(1.0 - N[(x / N[(N[(y - z), $MachinePrecision] * N[(y - t), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
1 - \frac{x}{\left(y - z\right) \cdot \left(y - t\right)}
\end{array}

Alternative 1: 98.7% accurate, 0.8× speedup?

\[\begin{array}{l} [x, y, z, t] = \mathsf{sort}([x, y, z, t])\\ \\ 1 - \frac{x}{\mathsf{fma}\left(y - t, y, z \cdot \left(t - y\right)\right)} \end{array} \]
NOTE: x, y, z, and t should be sorted in increasing order before calling this function.
(FPCore (x y z t)
 :precision binary64
 (- 1.0 (/ x (fma (- y t) y (* z (- t y))))))
assert(x < y && y < z && z < t);
double code(double x, double y, double z, double t) {
	return 1.0 - (x / fma((y - t), y, (z * (t - y))));
}
x, y, z, t = sort([x, y, z, t])
function code(x, y, z, t)
	return Float64(1.0 - Float64(x / fma(Float64(y - t), y, Float64(z * Float64(t - y)))))
end
NOTE: x, y, z, and t should be sorted in increasing order before calling this function.
code[x_, y_, z_, t_] := N[(1.0 - N[(x / N[(N[(y - t), $MachinePrecision] * y + N[(z * N[(t - y), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
\begin{array}{l}
[x, y, z, t] = \mathsf{sort}([x, y, z, t])\\
\\
1 - \frac{x}{\mathsf{fma}\left(y - t, y, z \cdot \left(t - y\right)\right)}
\end{array}
Derivation
  1. Initial program 99.5%

    \[1 - \frac{x}{\left(y - z\right) \cdot \left(y - t\right)} \]
  2. Add Preprocessing
  3. Step-by-step derivation
    1. *-commutativeN/A

      \[\leadsto 1 - \frac{x}{\color{blue}{\left(y - t\right) \cdot \left(y - z\right)}} \]
    2. sub-negN/A

      \[\leadsto 1 - \frac{x}{\left(y - t\right) \cdot \color{blue}{\left(y + \left(\mathsf{neg}\left(z\right)\right)\right)}} \]
    3. distribute-lft-inN/A

      \[\leadsto 1 - \frac{x}{\color{blue}{\left(y - t\right) \cdot y + \left(y - t\right) \cdot \left(\mathsf{neg}\left(z\right)\right)}} \]
    4. accelerator-lowering-fma.f64N/A

      \[\leadsto 1 - \frac{x}{\color{blue}{\mathsf{fma}\left(y - t, y, \left(y - t\right) \cdot \left(\mathsf{neg}\left(z\right)\right)\right)}} \]
    5. --lowering--.f64N/A

      \[\leadsto 1 - \frac{x}{\mathsf{fma}\left(\color{blue}{y - t}, y, \left(y - t\right) \cdot \left(\mathsf{neg}\left(z\right)\right)\right)} \]
    6. distribute-rgt-neg-outN/A

      \[\leadsto 1 - \frac{x}{\mathsf{fma}\left(y - t, y, \color{blue}{\mathsf{neg}\left(\left(y - t\right) \cdot z\right)}\right)} \]
    7. neg-lowering-neg.f64N/A

      \[\leadsto 1 - \frac{x}{\mathsf{fma}\left(y - t, y, \color{blue}{\mathsf{neg}\left(\left(y - t\right) \cdot z\right)}\right)} \]
    8. *-lowering-*.f64N/A

      \[\leadsto 1 - \frac{x}{\mathsf{fma}\left(y - t, y, \mathsf{neg}\left(\color{blue}{\left(y - t\right) \cdot z}\right)\right)} \]
    9. --lowering--.f6499.5

      \[\leadsto 1 - \frac{x}{\mathsf{fma}\left(y - t, y, -\color{blue}{\left(y - t\right)} \cdot z\right)} \]
  4. Applied egg-rr99.5%

    \[\leadsto 1 - \frac{x}{\color{blue}{\mathsf{fma}\left(y - t, y, -\left(y - t\right) \cdot z\right)}} \]
  5. Final simplification99.5%

    \[\leadsto 1 - \frac{x}{\mathsf{fma}\left(y - t, y, z \cdot \left(t - y\right)\right)} \]
  6. Add Preprocessing

Alternative 2: 85.3% accurate, 0.2× speedup?

\[\begin{array}{l} [x, y, z, t] = \mathsf{sort}([x, y, z, t])\\ \\ \begin{array}{l} t_1 := 1 + \frac{x}{\left(y - t\right) \cdot \left(z - y\right)}\\ t_2 := \frac{x}{y \cdot \left(z - y\right)}\\ \mathbf{if}\;t\_1 \leq -2 \cdot 10^{+59}:\\ \;\;\;\;1 - \frac{x}{t \cdot z}\\ \mathbf{elif}\;t\_1 \leq -1000000:\\ \;\;\;\;t\_2\\ \mathbf{elif}\;t\_1 \leq 50000000:\\ \;\;\;\;1\\ \mathbf{else}:\\ \;\;\;\;t\_2\\ \end{array} \end{array} \]
NOTE: x, y, z, and t should be sorted in increasing order before calling this function.
(FPCore (x y z t)
 :precision binary64
 (let* ((t_1 (+ 1.0 (/ x (* (- y t) (- z y))))) (t_2 (/ x (* y (- z y)))))
   (if (<= t_1 -2e+59)
     (- 1.0 (/ x (* t z)))
     (if (<= t_1 -1000000.0) t_2 (if (<= t_1 50000000.0) 1.0 t_2)))))
assert(x < y && y < z && z < t);
double code(double x, double y, double z, double t) {
	double t_1 = 1.0 + (x / ((y - t) * (z - y)));
	double t_2 = x / (y * (z - y));
	double tmp;
	if (t_1 <= -2e+59) {
		tmp = 1.0 - (x / (t * z));
	} else if (t_1 <= -1000000.0) {
		tmp = t_2;
	} else if (t_1 <= 50000000.0) {
		tmp = 1.0;
	} else {
		tmp = t_2;
	}
	return tmp;
}
NOTE: x, y, z, and t should be sorted in increasing order before calling this function.
real(8) function code(x, y, z, t)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    real(8), intent (in) :: z
    real(8), intent (in) :: t
    real(8) :: t_1
    real(8) :: t_2
    real(8) :: tmp
    t_1 = 1.0d0 + (x / ((y - t) * (z - y)))
    t_2 = x / (y * (z - y))
    if (t_1 <= (-2d+59)) then
        tmp = 1.0d0 - (x / (t * z))
    else if (t_1 <= (-1000000.0d0)) then
        tmp = t_2
    else if (t_1 <= 50000000.0d0) then
        tmp = 1.0d0
    else
        tmp = t_2
    end if
    code = tmp
end function
assert x < y && y < z && z < t;
public static double code(double x, double y, double z, double t) {
	double t_1 = 1.0 + (x / ((y - t) * (z - y)));
	double t_2 = x / (y * (z - y));
	double tmp;
	if (t_1 <= -2e+59) {
		tmp = 1.0 - (x / (t * z));
	} else if (t_1 <= -1000000.0) {
		tmp = t_2;
	} else if (t_1 <= 50000000.0) {
		tmp = 1.0;
	} else {
		tmp = t_2;
	}
	return tmp;
}
[x, y, z, t] = sort([x, y, z, t])
def code(x, y, z, t):
	t_1 = 1.0 + (x / ((y - t) * (z - y)))
	t_2 = x / (y * (z - y))
	tmp = 0
	if t_1 <= -2e+59:
		tmp = 1.0 - (x / (t * z))
	elif t_1 <= -1000000.0:
		tmp = t_2
	elif t_1 <= 50000000.0:
		tmp = 1.0
	else:
		tmp = t_2
	return tmp
x, y, z, t = sort([x, y, z, t])
function code(x, y, z, t)
	t_1 = Float64(1.0 + Float64(x / Float64(Float64(y - t) * Float64(z - y))))
	t_2 = Float64(x / Float64(y * Float64(z - y)))
	tmp = 0.0
	if (t_1 <= -2e+59)
		tmp = Float64(1.0 - Float64(x / Float64(t * z)));
	elseif (t_1 <= -1000000.0)
		tmp = t_2;
	elseif (t_1 <= 50000000.0)
		tmp = 1.0;
	else
		tmp = t_2;
	end
	return tmp
end
x, y, z, t = num2cell(sort([x, y, z, t])){:}
function tmp_2 = code(x, y, z, t)
	t_1 = 1.0 + (x / ((y - t) * (z - y)));
	t_2 = x / (y * (z - y));
	tmp = 0.0;
	if (t_1 <= -2e+59)
		tmp = 1.0 - (x / (t * z));
	elseif (t_1 <= -1000000.0)
		tmp = t_2;
	elseif (t_1 <= 50000000.0)
		tmp = 1.0;
	else
		tmp = t_2;
	end
	tmp_2 = tmp;
end
NOTE: x, y, z, and t should be sorted in increasing order before calling this function.
code[x_, y_, z_, t_] := Block[{t$95$1 = N[(1.0 + N[(x / N[(N[(y - t), $MachinePrecision] * N[(z - y), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$2 = N[(x / N[(y * N[(z - y), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[t$95$1, -2e+59], N[(1.0 - N[(x / N[(t * z), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], If[LessEqual[t$95$1, -1000000.0], t$95$2, If[LessEqual[t$95$1, 50000000.0], 1.0, t$95$2]]]]]
\begin{array}{l}
[x, y, z, t] = \mathsf{sort}([x, y, z, t])\\
\\
\begin{array}{l}
t_1 := 1 + \frac{x}{\left(y - t\right) \cdot \left(z - y\right)}\\
t_2 := \frac{x}{y \cdot \left(z - y\right)}\\
\mathbf{if}\;t\_1 \leq -2 \cdot 10^{+59}:\\
\;\;\;\;1 - \frac{x}{t \cdot z}\\

\mathbf{elif}\;t\_1 \leq -1000000:\\
\;\;\;\;t\_2\\

\mathbf{elif}\;t\_1 \leq 50000000:\\
\;\;\;\;1\\

\mathbf{else}:\\
\;\;\;\;t\_2\\


\end{array}
\end{array}
Derivation
  1. Split input into 3 regimes
  2. if (-.f64 #s(literal 1 binary64) (/.f64 x (*.f64 (-.f64 y z) (-.f64 y t)))) < -1.99999999999999994e59

    1. Initial program 96.4%

      \[1 - \frac{x}{\left(y - z\right) \cdot \left(y - t\right)} \]
    2. Add Preprocessing
    3. Taylor expanded in y around 0

      \[\leadsto \color{blue}{1 - \frac{x}{t \cdot z}} \]
    4. Step-by-step derivation
      1. --lowering--.f64N/A

        \[\leadsto \color{blue}{1 - \frac{x}{t \cdot z}} \]
      2. /-lowering-/.f64N/A

        \[\leadsto 1 - \color{blue}{\frac{x}{t \cdot z}} \]
      3. *-lowering-*.f6443.1

        \[\leadsto 1 - \frac{x}{\color{blue}{t \cdot z}} \]
    5. Simplified43.1%

      \[\leadsto \color{blue}{1 - \frac{x}{t \cdot z}} \]

    if -1.99999999999999994e59 < (-.f64 #s(literal 1 binary64) (/.f64 x (*.f64 (-.f64 y z) (-.f64 y t)))) < -1e6 or 5e7 < (-.f64 #s(literal 1 binary64) (/.f64 x (*.f64 (-.f64 y z) (-.f64 y t))))

    1. Initial program 99.5%

      \[1 - \frac{x}{\left(y - z\right) \cdot \left(y - t\right)} \]
    2. Add Preprocessing
    3. Taylor expanded in x around inf

      \[\leadsto \color{blue}{-1 \cdot \frac{x}{\left(y - t\right) \cdot \left(y - z\right)}} \]
    4. Step-by-step derivation
      1. mul-1-negN/A

        \[\leadsto \color{blue}{\mathsf{neg}\left(\frac{x}{\left(y - t\right) \cdot \left(y - z\right)}\right)} \]
      2. distribute-neg-frac2N/A

        \[\leadsto \color{blue}{\frac{x}{\mathsf{neg}\left(\left(y - t\right) \cdot \left(y - z\right)\right)}} \]
      3. /-lowering-/.f64N/A

        \[\leadsto \color{blue}{\frac{x}{\mathsf{neg}\left(\left(y - t\right) \cdot \left(y - z\right)\right)}} \]
      4. distribute-rgt-neg-inN/A

        \[\leadsto \frac{x}{\color{blue}{\left(y - t\right) \cdot \left(\mathsf{neg}\left(\left(y - z\right)\right)\right)}} \]
      5. mul-1-negN/A

        \[\leadsto \frac{x}{\left(y - t\right) \cdot \color{blue}{\left(-1 \cdot \left(y - z\right)\right)}} \]
      6. *-lowering-*.f64N/A

        \[\leadsto \frac{x}{\color{blue}{\left(y - t\right) \cdot \left(-1 \cdot \left(y - z\right)\right)}} \]
      7. --lowering--.f64N/A

        \[\leadsto \frac{x}{\color{blue}{\left(y - t\right)} \cdot \left(-1 \cdot \left(y - z\right)\right)} \]
      8. mul-1-negN/A

        \[\leadsto \frac{x}{\left(y - t\right) \cdot \color{blue}{\left(\mathsf{neg}\left(\left(y - z\right)\right)\right)}} \]
      9. sub-negN/A

        \[\leadsto \frac{x}{\left(y - t\right) \cdot \left(\mathsf{neg}\left(\color{blue}{\left(y + \left(\mathsf{neg}\left(z\right)\right)\right)}\right)\right)} \]
      10. mul-1-negN/A

        \[\leadsto \frac{x}{\left(y - t\right) \cdot \left(\mathsf{neg}\left(\left(y + \color{blue}{-1 \cdot z}\right)\right)\right)} \]
      11. +-commutativeN/A

        \[\leadsto \frac{x}{\left(y - t\right) \cdot \left(\mathsf{neg}\left(\color{blue}{\left(-1 \cdot z + y\right)}\right)\right)} \]
      12. distribute-neg-inN/A

        \[\leadsto \frac{x}{\left(y - t\right) \cdot \color{blue}{\left(\left(\mathsf{neg}\left(-1 \cdot z\right)\right) + \left(\mathsf{neg}\left(y\right)\right)\right)}} \]
      13. unsub-negN/A

        \[\leadsto \frac{x}{\left(y - t\right) \cdot \color{blue}{\left(\left(\mathsf{neg}\left(-1 \cdot z\right)\right) - y\right)}} \]
      14. mul-1-negN/A

        \[\leadsto \frac{x}{\left(y - t\right) \cdot \left(\left(\mathsf{neg}\left(\color{blue}{\left(\mathsf{neg}\left(z\right)\right)}\right)\right) - y\right)} \]
      15. remove-double-negN/A

        \[\leadsto \frac{x}{\left(y - t\right) \cdot \left(\color{blue}{z} - y\right)} \]
      16. --lowering--.f6496.1

        \[\leadsto \frac{x}{\left(y - t\right) \cdot \color{blue}{\left(z - y\right)}} \]
    5. Simplified96.1%

      \[\leadsto \color{blue}{\frac{x}{\left(y - t\right) \cdot \left(z - y\right)}} \]
    6. Taylor expanded in y around inf

      \[\leadsto \frac{x}{\color{blue}{y} \cdot \left(z - y\right)} \]
    7. Step-by-step derivation
      1. Simplified60.6%

        \[\leadsto \frac{x}{\color{blue}{y} \cdot \left(z - y\right)} \]

      if -1e6 < (-.f64 #s(literal 1 binary64) (/.f64 x (*.f64 (-.f64 y z) (-.f64 y t)))) < 5e7

      1. Initial program 100.0%

        \[1 - \frac{x}{\left(y - z\right) \cdot \left(y - t\right)} \]
      2. Add Preprocessing
      3. Taylor expanded in x around 0

        \[\leadsto \color{blue}{1} \]
      4. Step-by-step derivation
        1. Simplified98.4%

          \[\leadsto \color{blue}{1} \]
      5. Recombined 3 regimes into one program.
      6. Final simplification86.8%

        \[\leadsto \begin{array}{l} \mathbf{if}\;1 + \frac{x}{\left(y - t\right) \cdot \left(z - y\right)} \leq -2 \cdot 10^{+59}:\\ \;\;\;\;1 - \frac{x}{t \cdot z}\\ \mathbf{elif}\;1 + \frac{x}{\left(y - t\right) \cdot \left(z - y\right)} \leq -1000000:\\ \;\;\;\;\frac{x}{y \cdot \left(z - y\right)}\\ \mathbf{elif}\;1 + \frac{x}{\left(y - t\right) \cdot \left(z - y\right)} \leq 50000000:\\ \;\;\;\;1\\ \mathbf{else}:\\ \;\;\;\;\frac{x}{y \cdot \left(z - y\right)}\\ \end{array} \]
      7. Add Preprocessing

      Alternative 3: 97.9% accurate, 0.3× speedup?

      \[\begin{array}{l} [x, y, z, t] = \mathsf{sort}([x, y, z, t])\\ \\ \begin{array}{l} t_1 := \frac{x}{\left(y - t\right) \cdot \left(z - y\right)}\\ t_2 := 1 + t\_1\\ \mathbf{if}\;t\_2 \leq -1000000:\\ \;\;\;\;t\_1\\ \mathbf{elif}\;t\_2 \leq 2:\\ \;\;\;\;1\\ \mathbf{else}:\\ \;\;\;\;t\_1\\ \end{array} \end{array} \]
      NOTE: x, y, z, and t should be sorted in increasing order before calling this function.
      (FPCore (x y z t)
       :precision binary64
       (let* ((t_1 (/ x (* (- y t) (- z y)))) (t_2 (+ 1.0 t_1)))
         (if (<= t_2 -1000000.0) t_1 (if (<= t_2 2.0) 1.0 t_1))))
      assert(x < y && y < z && z < t);
      double code(double x, double y, double z, double t) {
      	double t_1 = x / ((y - t) * (z - y));
      	double t_2 = 1.0 + t_1;
      	double tmp;
      	if (t_2 <= -1000000.0) {
      		tmp = t_1;
      	} else if (t_2 <= 2.0) {
      		tmp = 1.0;
      	} else {
      		tmp = t_1;
      	}
      	return tmp;
      }
      
      NOTE: x, y, z, and t should be sorted in increasing order before calling this function.
      real(8) function code(x, y, z, t)
          real(8), intent (in) :: x
          real(8), intent (in) :: y
          real(8), intent (in) :: z
          real(8), intent (in) :: t
          real(8) :: t_1
          real(8) :: t_2
          real(8) :: tmp
          t_1 = x / ((y - t) * (z - y))
          t_2 = 1.0d0 + t_1
          if (t_2 <= (-1000000.0d0)) then
              tmp = t_1
          else if (t_2 <= 2.0d0) then
              tmp = 1.0d0
          else
              tmp = t_1
          end if
          code = tmp
      end function
      
      assert x < y && y < z && z < t;
      public static double code(double x, double y, double z, double t) {
      	double t_1 = x / ((y - t) * (z - y));
      	double t_2 = 1.0 + t_1;
      	double tmp;
      	if (t_2 <= -1000000.0) {
      		tmp = t_1;
      	} else if (t_2 <= 2.0) {
      		tmp = 1.0;
      	} else {
      		tmp = t_1;
      	}
      	return tmp;
      }
      
      [x, y, z, t] = sort([x, y, z, t])
      def code(x, y, z, t):
      	t_1 = x / ((y - t) * (z - y))
      	t_2 = 1.0 + t_1
      	tmp = 0
      	if t_2 <= -1000000.0:
      		tmp = t_1
      	elif t_2 <= 2.0:
      		tmp = 1.0
      	else:
      		tmp = t_1
      	return tmp
      
      x, y, z, t = sort([x, y, z, t])
      function code(x, y, z, t)
      	t_1 = Float64(x / Float64(Float64(y - t) * Float64(z - y)))
      	t_2 = Float64(1.0 + t_1)
      	tmp = 0.0
      	if (t_2 <= -1000000.0)
      		tmp = t_1;
      	elseif (t_2 <= 2.0)
      		tmp = 1.0;
      	else
      		tmp = t_1;
      	end
      	return tmp
      end
      
      x, y, z, t = num2cell(sort([x, y, z, t])){:}
      function tmp_2 = code(x, y, z, t)
      	t_1 = x / ((y - t) * (z - y));
      	t_2 = 1.0 + t_1;
      	tmp = 0.0;
      	if (t_2 <= -1000000.0)
      		tmp = t_1;
      	elseif (t_2 <= 2.0)
      		tmp = 1.0;
      	else
      		tmp = t_1;
      	end
      	tmp_2 = tmp;
      end
      
      NOTE: x, y, z, and t should be sorted in increasing order before calling this function.
      code[x_, y_, z_, t_] := Block[{t$95$1 = N[(x / N[(N[(y - t), $MachinePrecision] * N[(z - y), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$2 = N[(1.0 + t$95$1), $MachinePrecision]}, If[LessEqual[t$95$2, -1000000.0], t$95$1, If[LessEqual[t$95$2, 2.0], 1.0, t$95$1]]]]
      
      \begin{array}{l}
      [x, y, z, t] = \mathsf{sort}([x, y, z, t])\\
      \\
      \begin{array}{l}
      t_1 := \frac{x}{\left(y - t\right) \cdot \left(z - y\right)}\\
      t_2 := 1 + t\_1\\
      \mathbf{if}\;t\_2 \leq -1000000:\\
      \;\;\;\;t\_1\\
      
      \mathbf{elif}\;t\_2 \leq 2:\\
      \;\;\;\;1\\
      
      \mathbf{else}:\\
      \;\;\;\;t\_1\\
      
      
      \end{array}
      \end{array}
      
      Derivation
      1. Split input into 2 regimes
      2. if (-.f64 #s(literal 1 binary64) (/.f64 x (*.f64 (-.f64 y z) (-.f64 y t)))) < -1e6 or 2 < (-.f64 #s(literal 1 binary64) (/.f64 x (*.f64 (-.f64 y z) (-.f64 y t))))

        1. Initial program 98.2%

          \[1 - \frac{x}{\left(y - z\right) \cdot \left(y - t\right)} \]
        2. Add Preprocessing
        3. Taylor expanded in x around inf

          \[\leadsto \color{blue}{-1 \cdot \frac{x}{\left(y - t\right) \cdot \left(y - z\right)}} \]
        4. Step-by-step derivation
          1. mul-1-negN/A

            \[\leadsto \color{blue}{\mathsf{neg}\left(\frac{x}{\left(y - t\right) \cdot \left(y - z\right)}\right)} \]
          2. distribute-neg-frac2N/A

            \[\leadsto \color{blue}{\frac{x}{\mathsf{neg}\left(\left(y - t\right) \cdot \left(y - z\right)\right)}} \]
          3. /-lowering-/.f64N/A

            \[\leadsto \color{blue}{\frac{x}{\mathsf{neg}\left(\left(y - t\right) \cdot \left(y - z\right)\right)}} \]
          4. distribute-rgt-neg-inN/A

            \[\leadsto \frac{x}{\color{blue}{\left(y - t\right) \cdot \left(\mathsf{neg}\left(\left(y - z\right)\right)\right)}} \]
          5. mul-1-negN/A

            \[\leadsto \frac{x}{\left(y - t\right) \cdot \color{blue}{\left(-1 \cdot \left(y - z\right)\right)}} \]
          6. *-lowering-*.f64N/A

            \[\leadsto \frac{x}{\color{blue}{\left(y - t\right) \cdot \left(-1 \cdot \left(y - z\right)\right)}} \]
          7. --lowering--.f64N/A

            \[\leadsto \frac{x}{\color{blue}{\left(y - t\right)} \cdot \left(-1 \cdot \left(y - z\right)\right)} \]
          8. mul-1-negN/A

            \[\leadsto \frac{x}{\left(y - t\right) \cdot \color{blue}{\left(\mathsf{neg}\left(\left(y - z\right)\right)\right)}} \]
          9. sub-negN/A

            \[\leadsto \frac{x}{\left(y - t\right) \cdot \left(\mathsf{neg}\left(\color{blue}{\left(y + \left(\mathsf{neg}\left(z\right)\right)\right)}\right)\right)} \]
          10. mul-1-negN/A

            \[\leadsto \frac{x}{\left(y - t\right) \cdot \left(\mathsf{neg}\left(\left(y + \color{blue}{-1 \cdot z}\right)\right)\right)} \]
          11. +-commutativeN/A

            \[\leadsto \frac{x}{\left(y - t\right) \cdot \left(\mathsf{neg}\left(\color{blue}{\left(-1 \cdot z + y\right)}\right)\right)} \]
          12. distribute-neg-inN/A

            \[\leadsto \frac{x}{\left(y - t\right) \cdot \color{blue}{\left(\left(\mathsf{neg}\left(-1 \cdot z\right)\right) + \left(\mathsf{neg}\left(y\right)\right)\right)}} \]
          13. unsub-negN/A

            \[\leadsto \frac{x}{\left(y - t\right) \cdot \color{blue}{\left(\left(\mathsf{neg}\left(-1 \cdot z\right)\right) - y\right)}} \]
          14. mul-1-negN/A

            \[\leadsto \frac{x}{\left(y - t\right) \cdot \left(\left(\mathsf{neg}\left(\color{blue}{\left(\mathsf{neg}\left(z\right)\right)}\right)\right) - y\right)} \]
          15. remove-double-negN/A

            \[\leadsto \frac{x}{\left(y - t\right) \cdot \left(\color{blue}{z} - y\right)} \]
          16. --lowering--.f6494.7

            \[\leadsto \frac{x}{\left(y - t\right) \cdot \color{blue}{\left(z - y\right)}} \]
        5. Simplified94.7%

          \[\leadsto \color{blue}{\frac{x}{\left(y - t\right) \cdot \left(z - y\right)}} \]

        if -1e6 < (-.f64 #s(literal 1 binary64) (/.f64 x (*.f64 (-.f64 y z) (-.f64 y t)))) < 2

        1. Initial program 100.0%

          \[1 - \frac{x}{\left(y - z\right) \cdot \left(y - t\right)} \]
        2. Add Preprocessing
        3. Taylor expanded in x around 0

          \[\leadsto \color{blue}{1} \]
        4. Step-by-step derivation
          1. Simplified99.4%

            \[\leadsto \color{blue}{1} \]
        5. Recombined 2 regimes into one program.
        6. Final simplification98.1%

          \[\leadsto \begin{array}{l} \mathbf{if}\;1 + \frac{x}{\left(y - t\right) \cdot \left(z - y\right)} \leq -1000000:\\ \;\;\;\;\frac{x}{\left(y - t\right) \cdot \left(z - y\right)}\\ \mathbf{elif}\;1 + \frac{x}{\left(y - t\right) \cdot \left(z - y\right)} \leq 2:\\ \;\;\;\;1\\ \mathbf{else}:\\ \;\;\;\;\frac{x}{\left(y - t\right) \cdot \left(z - y\right)}\\ \end{array} \]
        7. Add Preprocessing

        Alternative 4: 89.0% accurate, 0.3× speedup?

        \[\begin{array}{l} [x, y, z, t] = \mathsf{sort}([x, y, z, t])\\ \\ \begin{array}{l} t_1 := \frac{x}{\left(y - t\right) \cdot z}\\ t_2 := 1 + \frac{x}{\left(y - t\right) \cdot \left(z - y\right)}\\ \mathbf{if}\;t\_2 \leq -1000000:\\ \;\;\;\;t\_1\\ \mathbf{elif}\;t\_2 \leq 2:\\ \;\;\;\;1\\ \mathbf{else}:\\ \;\;\;\;t\_1\\ \end{array} \end{array} \]
        NOTE: x, y, z, and t should be sorted in increasing order before calling this function.
        (FPCore (x y z t)
         :precision binary64
         (let* ((t_1 (/ x (* (- y t) z))) (t_2 (+ 1.0 (/ x (* (- y t) (- z y))))))
           (if (<= t_2 -1000000.0) t_1 (if (<= t_2 2.0) 1.0 t_1))))
        assert(x < y && y < z && z < t);
        double code(double x, double y, double z, double t) {
        	double t_1 = x / ((y - t) * z);
        	double t_2 = 1.0 + (x / ((y - t) * (z - y)));
        	double tmp;
        	if (t_2 <= -1000000.0) {
        		tmp = t_1;
        	} else if (t_2 <= 2.0) {
        		tmp = 1.0;
        	} else {
        		tmp = t_1;
        	}
        	return tmp;
        }
        
        NOTE: x, y, z, and t should be sorted in increasing order before calling this function.
        real(8) function code(x, y, z, t)
            real(8), intent (in) :: x
            real(8), intent (in) :: y
            real(8), intent (in) :: z
            real(8), intent (in) :: t
            real(8) :: t_1
            real(8) :: t_2
            real(8) :: tmp
            t_1 = x / ((y - t) * z)
            t_2 = 1.0d0 + (x / ((y - t) * (z - y)))
            if (t_2 <= (-1000000.0d0)) then
                tmp = t_1
            else if (t_2 <= 2.0d0) then
                tmp = 1.0d0
            else
                tmp = t_1
            end if
            code = tmp
        end function
        
        assert x < y && y < z && z < t;
        public static double code(double x, double y, double z, double t) {
        	double t_1 = x / ((y - t) * z);
        	double t_2 = 1.0 + (x / ((y - t) * (z - y)));
        	double tmp;
        	if (t_2 <= -1000000.0) {
        		tmp = t_1;
        	} else if (t_2 <= 2.0) {
        		tmp = 1.0;
        	} else {
        		tmp = t_1;
        	}
        	return tmp;
        }
        
        [x, y, z, t] = sort([x, y, z, t])
        def code(x, y, z, t):
        	t_1 = x / ((y - t) * z)
        	t_2 = 1.0 + (x / ((y - t) * (z - y)))
        	tmp = 0
        	if t_2 <= -1000000.0:
        		tmp = t_1
        	elif t_2 <= 2.0:
        		tmp = 1.0
        	else:
        		tmp = t_1
        	return tmp
        
        x, y, z, t = sort([x, y, z, t])
        function code(x, y, z, t)
        	t_1 = Float64(x / Float64(Float64(y - t) * z))
        	t_2 = Float64(1.0 + Float64(x / Float64(Float64(y - t) * Float64(z - y))))
        	tmp = 0.0
        	if (t_2 <= -1000000.0)
        		tmp = t_1;
        	elseif (t_2 <= 2.0)
        		tmp = 1.0;
        	else
        		tmp = t_1;
        	end
        	return tmp
        end
        
        x, y, z, t = num2cell(sort([x, y, z, t])){:}
        function tmp_2 = code(x, y, z, t)
        	t_1 = x / ((y - t) * z);
        	t_2 = 1.0 + (x / ((y - t) * (z - y)));
        	tmp = 0.0;
        	if (t_2 <= -1000000.0)
        		tmp = t_1;
        	elseif (t_2 <= 2.0)
        		tmp = 1.0;
        	else
        		tmp = t_1;
        	end
        	tmp_2 = tmp;
        end
        
        NOTE: x, y, z, and t should be sorted in increasing order before calling this function.
        code[x_, y_, z_, t_] := Block[{t$95$1 = N[(x / N[(N[(y - t), $MachinePrecision] * z), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$2 = N[(1.0 + N[(x / N[(N[(y - t), $MachinePrecision] * N[(z - y), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[t$95$2, -1000000.0], t$95$1, If[LessEqual[t$95$2, 2.0], 1.0, t$95$1]]]]
        
        \begin{array}{l}
        [x, y, z, t] = \mathsf{sort}([x, y, z, t])\\
        \\
        \begin{array}{l}
        t_1 := \frac{x}{\left(y - t\right) \cdot z}\\
        t_2 := 1 + \frac{x}{\left(y - t\right) \cdot \left(z - y\right)}\\
        \mathbf{if}\;t\_2 \leq -1000000:\\
        \;\;\;\;t\_1\\
        
        \mathbf{elif}\;t\_2 \leq 2:\\
        \;\;\;\;1\\
        
        \mathbf{else}:\\
        \;\;\;\;t\_1\\
        
        
        \end{array}
        \end{array}
        
        Derivation
        1. Split input into 2 regimes
        2. if (-.f64 #s(literal 1 binary64) (/.f64 x (*.f64 (-.f64 y z) (-.f64 y t)))) < -1e6 or 2 < (-.f64 #s(literal 1 binary64) (/.f64 x (*.f64 (-.f64 y z) (-.f64 y t))))

          1. Initial program 98.2%

            \[1 - \frac{x}{\left(y - z\right) \cdot \left(y - t\right)} \]
          2. Add Preprocessing
          3. Step-by-step derivation
            1. sub-negN/A

              \[\leadsto \color{blue}{1 + \left(\mathsf{neg}\left(\frac{x}{\left(y - z\right) \cdot \left(y - t\right)}\right)\right)} \]
            2. +-commutativeN/A

              \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\frac{x}{\left(y - z\right) \cdot \left(y - t\right)}\right)\right) + 1} \]
            3. clear-numN/A

              \[\leadsto \left(\mathsf{neg}\left(\color{blue}{\frac{1}{\frac{\left(y - z\right) \cdot \left(y - t\right)}{x}}}\right)\right) + 1 \]
            4. associate-/r/N/A

              \[\leadsto \left(\mathsf{neg}\left(\color{blue}{\frac{1}{\left(y - z\right) \cdot \left(y - t\right)} \cdot x}\right)\right) + 1 \]
            5. distribute-lft-neg-inN/A

              \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\frac{1}{\left(y - z\right) \cdot \left(y - t\right)}\right)\right) \cdot x} + 1 \]
            6. distribute-frac-neg2N/A

              \[\leadsto \color{blue}{\frac{1}{\mathsf{neg}\left(\left(y - z\right) \cdot \left(y - t\right)\right)}} \cdot x + 1 \]
            7. accelerator-lowering-fma.f64N/A

              \[\leadsto \color{blue}{\mathsf{fma}\left(\frac{1}{\mathsf{neg}\left(\left(y - z\right) \cdot \left(y - t\right)\right)}, x, 1\right)} \]
            8. distribute-frac-neg2N/A

              \[\leadsto \mathsf{fma}\left(\color{blue}{\mathsf{neg}\left(\frac{1}{\left(y - z\right) \cdot \left(y - t\right)}\right)}, x, 1\right) \]
            9. distribute-neg-fracN/A

              \[\leadsto \mathsf{fma}\left(\color{blue}{\frac{\mathsf{neg}\left(1\right)}{\left(y - z\right) \cdot \left(y - t\right)}}, x, 1\right) \]
            10. metadata-evalN/A

              \[\leadsto \mathsf{fma}\left(\frac{\color{blue}{-1}}{\left(y - z\right) \cdot \left(y - t\right)}, x, 1\right) \]
            11. /-lowering-/.f64N/A

              \[\leadsto \mathsf{fma}\left(\color{blue}{\frac{-1}{\left(y - z\right) \cdot \left(y - t\right)}}, x, 1\right) \]
            12. *-lowering-*.f64N/A

              \[\leadsto \mathsf{fma}\left(\frac{-1}{\color{blue}{\left(y - z\right) \cdot \left(y - t\right)}}, x, 1\right) \]
            13. --lowering--.f64N/A

              \[\leadsto \mathsf{fma}\left(\frac{-1}{\color{blue}{\left(y - z\right)} \cdot \left(y - t\right)}, x, 1\right) \]
            14. --lowering--.f6498.1

              \[\leadsto \mathsf{fma}\left(\frac{-1}{\left(y - z\right) \cdot \color{blue}{\left(y - t\right)}}, x, 1\right) \]
          4. Applied egg-rr98.1%

            \[\leadsto \color{blue}{\mathsf{fma}\left(\frac{-1}{\left(y - z\right) \cdot \left(y - t\right)}, x, 1\right)} \]
          5. Taylor expanded in z around inf

            \[\leadsto \mathsf{fma}\left(\color{blue}{\frac{1}{z \cdot \left(y - t\right)}}, x, 1\right) \]
          6. Step-by-step derivation
            1. /-lowering-/.f64N/A

              \[\leadsto \mathsf{fma}\left(\color{blue}{\frac{1}{z \cdot \left(y - t\right)}}, x, 1\right) \]
            2. *-lowering-*.f64N/A

              \[\leadsto \mathsf{fma}\left(\frac{1}{\color{blue}{z \cdot \left(y - t\right)}}, x, 1\right) \]
            3. --lowering--.f6458.7

              \[\leadsto \mathsf{fma}\left(\frac{1}{z \cdot \color{blue}{\left(y - t\right)}}, x, 1\right) \]
          7. Simplified58.7%

            \[\leadsto \mathsf{fma}\left(\color{blue}{\frac{1}{z \cdot \left(y - t\right)}}, x, 1\right) \]
          8. Taylor expanded in z around 0

            \[\leadsto \color{blue}{\frac{x}{z \cdot \left(y - t\right)}} \]
          9. Step-by-step derivation
            1. /-lowering-/.f64N/A

              \[\leadsto \color{blue}{\frac{x}{z \cdot \left(y - t\right)}} \]
            2. *-lowering-*.f64N/A

              \[\leadsto \frac{x}{\color{blue}{z \cdot \left(y - t\right)}} \]
            3. --lowering--.f6456.0

              \[\leadsto \frac{x}{z \cdot \color{blue}{\left(y - t\right)}} \]
          10. Simplified56.0%

            \[\leadsto \color{blue}{\frac{x}{z \cdot \left(y - t\right)}} \]

          if -1e6 < (-.f64 #s(literal 1 binary64) (/.f64 x (*.f64 (-.f64 y z) (-.f64 y t)))) < 2

          1. Initial program 100.0%

            \[1 - \frac{x}{\left(y - z\right) \cdot \left(y - t\right)} \]
          2. Add Preprocessing
          3. Taylor expanded in x around 0

            \[\leadsto \color{blue}{1} \]
          4. Step-by-step derivation
            1. Simplified99.4%

              \[\leadsto \color{blue}{1} \]
          5. Recombined 2 regimes into one program.
          6. Final simplification87.8%

            \[\leadsto \begin{array}{l} \mathbf{if}\;1 + \frac{x}{\left(y - t\right) \cdot \left(z - y\right)} \leq -1000000:\\ \;\;\;\;\frac{x}{\left(y - t\right) \cdot z}\\ \mathbf{elif}\;1 + \frac{x}{\left(y - t\right) \cdot \left(z - y\right)} \leq 2:\\ \;\;\;\;1\\ \mathbf{else}:\\ \;\;\;\;\frac{x}{\left(y - t\right) \cdot z}\\ \end{array} \]
          7. Add Preprocessing

          Alternative 5: 81.0% accurate, 0.3× speedup?

          \[\begin{array}{l} [x, y, z, t] = \mathsf{sort}([x, y, z, t])\\ \\ \begin{array}{l} t_1 := 1 + \frac{x}{y \cdot z}\\ t_2 := 1 + \frac{x}{\left(y - t\right) \cdot \left(z - y\right)}\\ \mathbf{if}\;t\_2 \leq 0.9999998861946734:\\ \;\;\;\;t\_1\\ \mathbf{elif}\;t\_2 \leq 50000000:\\ \;\;\;\;1\\ \mathbf{else}:\\ \;\;\;\;t\_1\\ \end{array} \end{array} \]
          NOTE: x, y, z, and t should be sorted in increasing order before calling this function.
          (FPCore (x y z t)
           :precision binary64
           (let* ((t_1 (+ 1.0 (/ x (* y z)))) (t_2 (+ 1.0 (/ x (* (- y t) (- z y))))))
             (if (<= t_2 0.9999998861946734) t_1 (if (<= t_2 50000000.0) 1.0 t_1))))
          assert(x < y && y < z && z < t);
          double code(double x, double y, double z, double t) {
          	double t_1 = 1.0 + (x / (y * z));
          	double t_2 = 1.0 + (x / ((y - t) * (z - y)));
          	double tmp;
          	if (t_2 <= 0.9999998861946734) {
          		tmp = t_1;
          	} else if (t_2 <= 50000000.0) {
          		tmp = 1.0;
          	} else {
          		tmp = t_1;
          	}
          	return tmp;
          }
          
          NOTE: x, y, z, and t should be sorted in increasing order before calling this function.
          real(8) function code(x, y, z, t)
              real(8), intent (in) :: x
              real(8), intent (in) :: y
              real(8), intent (in) :: z
              real(8), intent (in) :: t
              real(8) :: t_1
              real(8) :: t_2
              real(8) :: tmp
              t_1 = 1.0d0 + (x / (y * z))
              t_2 = 1.0d0 + (x / ((y - t) * (z - y)))
              if (t_2 <= 0.9999998861946734d0) then
                  tmp = t_1
              else if (t_2 <= 50000000.0d0) then
                  tmp = 1.0d0
              else
                  tmp = t_1
              end if
              code = tmp
          end function
          
          assert x < y && y < z && z < t;
          public static double code(double x, double y, double z, double t) {
          	double t_1 = 1.0 + (x / (y * z));
          	double t_2 = 1.0 + (x / ((y - t) * (z - y)));
          	double tmp;
          	if (t_2 <= 0.9999998861946734) {
          		tmp = t_1;
          	} else if (t_2 <= 50000000.0) {
          		tmp = 1.0;
          	} else {
          		tmp = t_1;
          	}
          	return tmp;
          }
          
          [x, y, z, t] = sort([x, y, z, t])
          def code(x, y, z, t):
          	t_1 = 1.0 + (x / (y * z))
          	t_2 = 1.0 + (x / ((y - t) * (z - y)))
          	tmp = 0
          	if t_2 <= 0.9999998861946734:
          		tmp = t_1
          	elif t_2 <= 50000000.0:
          		tmp = 1.0
          	else:
          		tmp = t_1
          	return tmp
          
          x, y, z, t = sort([x, y, z, t])
          function code(x, y, z, t)
          	t_1 = Float64(1.0 + Float64(x / Float64(y * z)))
          	t_2 = Float64(1.0 + Float64(x / Float64(Float64(y - t) * Float64(z - y))))
          	tmp = 0.0
          	if (t_2 <= 0.9999998861946734)
          		tmp = t_1;
          	elseif (t_2 <= 50000000.0)
          		tmp = 1.0;
          	else
          		tmp = t_1;
          	end
          	return tmp
          end
          
          x, y, z, t = num2cell(sort([x, y, z, t])){:}
          function tmp_2 = code(x, y, z, t)
          	t_1 = 1.0 + (x / (y * z));
          	t_2 = 1.0 + (x / ((y - t) * (z - y)));
          	tmp = 0.0;
          	if (t_2 <= 0.9999998861946734)
          		tmp = t_1;
          	elseif (t_2 <= 50000000.0)
          		tmp = 1.0;
          	else
          		tmp = t_1;
          	end
          	tmp_2 = tmp;
          end
          
          NOTE: x, y, z, and t should be sorted in increasing order before calling this function.
          code[x_, y_, z_, t_] := Block[{t$95$1 = N[(1.0 + N[(x / N[(y * z), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$2 = N[(1.0 + N[(x / N[(N[(y - t), $MachinePrecision] * N[(z - y), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[t$95$2, 0.9999998861946734], t$95$1, If[LessEqual[t$95$2, 50000000.0], 1.0, t$95$1]]]]
          
          \begin{array}{l}
          [x, y, z, t] = \mathsf{sort}([x, y, z, t])\\
          \\
          \begin{array}{l}
          t_1 := 1 + \frac{x}{y \cdot z}\\
          t_2 := 1 + \frac{x}{\left(y - t\right) \cdot \left(z - y\right)}\\
          \mathbf{if}\;t\_2 \leq 0.9999998861946734:\\
          \;\;\;\;t\_1\\
          
          \mathbf{elif}\;t\_2 \leq 50000000:\\
          \;\;\;\;1\\
          
          \mathbf{else}:\\
          \;\;\;\;t\_1\\
          
          
          \end{array}
          \end{array}
          
          Derivation
          1. Split input into 2 regimes
          2. if (-.f64 #s(literal 1 binary64) (/.f64 x (*.f64 (-.f64 y z) (-.f64 y t)))) < 0.999999886194673393 or 5e7 < (-.f64 #s(literal 1 binary64) (/.f64 x (*.f64 (-.f64 y z) (-.f64 y t))))

            1. Initial program 98.2%

              \[1 - \frac{x}{\left(y - z\right) \cdot \left(y - t\right)} \]
            2. Add Preprocessing
            3. Taylor expanded in z around inf

              \[\leadsto 1 - \color{blue}{-1 \cdot \frac{x}{z \cdot \left(y - t\right)}} \]
            4. Step-by-step derivation
              1. mul-1-negN/A

                \[\leadsto 1 - \color{blue}{\left(\mathsf{neg}\left(\frac{x}{z \cdot \left(y - t\right)}\right)\right)} \]
              2. distribute-neg-frac2N/A

                \[\leadsto 1 - \color{blue}{\frac{x}{\mathsf{neg}\left(z \cdot \left(y - t\right)\right)}} \]
              3. mul-1-negN/A

                \[\leadsto 1 - \frac{x}{\color{blue}{-1 \cdot \left(z \cdot \left(y - t\right)\right)}} \]
              4. /-lowering-/.f64N/A

                \[\leadsto 1 - \color{blue}{\frac{x}{-1 \cdot \left(z \cdot \left(y - t\right)\right)}} \]
              5. mul-1-negN/A

                \[\leadsto 1 - \frac{x}{\color{blue}{\mathsf{neg}\left(z \cdot \left(y - t\right)\right)}} \]
              6. distribute-rgt-neg-inN/A

                \[\leadsto 1 - \frac{x}{\color{blue}{z \cdot \left(\mathsf{neg}\left(\left(y - t\right)\right)\right)}} \]
              7. mul-1-negN/A

                \[\leadsto 1 - \frac{x}{z \cdot \color{blue}{\left(-1 \cdot \left(y - t\right)\right)}} \]
              8. *-lowering-*.f64N/A

                \[\leadsto 1 - \frac{x}{\color{blue}{z \cdot \left(-1 \cdot \left(y - t\right)\right)}} \]
              9. mul-1-negN/A

                \[\leadsto 1 - \frac{x}{z \cdot \color{blue}{\left(\mathsf{neg}\left(\left(y - t\right)\right)\right)}} \]
              10. sub-negN/A

                \[\leadsto 1 - \frac{x}{z \cdot \left(\mathsf{neg}\left(\color{blue}{\left(y + \left(\mathsf{neg}\left(t\right)\right)\right)}\right)\right)} \]
              11. mul-1-negN/A

                \[\leadsto 1 - \frac{x}{z \cdot \left(\mathsf{neg}\left(\left(y + \color{blue}{-1 \cdot t}\right)\right)\right)} \]
              12. +-commutativeN/A

                \[\leadsto 1 - \frac{x}{z \cdot \left(\mathsf{neg}\left(\color{blue}{\left(-1 \cdot t + y\right)}\right)\right)} \]
              13. distribute-neg-inN/A

                \[\leadsto 1 - \frac{x}{z \cdot \color{blue}{\left(\left(\mathsf{neg}\left(-1 \cdot t\right)\right) + \left(\mathsf{neg}\left(y\right)\right)\right)}} \]
              14. unsub-negN/A

                \[\leadsto 1 - \frac{x}{z \cdot \color{blue}{\left(\left(\mathsf{neg}\left(-1 \cdot t\right)\right) - y\right)}} \]
              15. mul-1-negN/A

                \[\leadsto 1 - \frac{x}{z \cdot \left(\left(\mathsf{neg}\left(\color{blue}{\left(\mathsf{neg}\left(t\right)\right)}\right)\right) - y\right)} \]
              16. remove-double-negN/A

                \[\leadsto 1 - \frac{x}{z \cdot \left(\color{blue}{t} - y\right)} \]
              17. --lowering--.f6458.2

                \[\leadsto 1 - \frac{x}{z \cdot \color{blue}{\left(t - y\right)}} \]
            5. Simplified58.2%

              \[\leadsto 1 - \color{blue}{\frac{x}{z \cdot \left(t - y\right)}} \]
            6. Taylor expanded in t around 0

              \[\leadsto \color{blue}{1 - -1 \cdot \frac{x}{y \cdot z}} \]
            7. Step-by-step derivation
              1. sub-negN/A

                \[\leadsto \color{blue}{1 + \left(\mathsf{neg}\left(-1 \cdot \frac{x}{y \cdot z}\right)\right)} \]
              2. mul-1-negN/A

                \[\leadsto 1 + \left(\mathsf{neg}\left(\color{blue}{\left(\mathsf{neg}\left(\frac{x}{y \cdot z}\right)\right)}\right)\right) \]
              3. remove-double-negN/A

                \[\leadsto 1 + \color{blue}{\frac{x}{y \cdot z}} \]
              4. +-lowering-+.f64N/A

                \[\leadsto \color{blue}{1 + \frac{x}{y \cdot z}} \]
              5. /-lowering-/.f64N/A

                \[\leadsto 1 + \color{blue}{\frac{x}{y \cdot z}} \]
              6. *-commutativeN/A

                \[\leadsto 1 + \frac{x}{\color{blue}{z \cdot y}} \]
              7. *-lowering-*.f6431.1

                \[\leadsto 1 + \frac{x}{\color{blue}{z \cdot y}} \]
            8. Simplified31.1%

              \[\leadsto \color{blue}{1 + \frac{x}{z \cdot y}} \]

            if 0.999999886194673393 < (-.f64 #s(literal 1 binary64) (/.f64 x (*.f64 (-.f64 y z) (-.f64 y t)))) < 5e7

            1. Initial program 100.0%

              \[1 - \frac{x}{\left(y - z\right) \cdot \left(y - t\right)} \]
            2. Add Preprocessing
            3. Taylor expanded in x around 0

              \[\leadsto \color{blue}{1} \]
            4. Step-by-step derivation
              1. Simplified98.7%

                \[\leadsto \color{blue}{1} \]
            5. Recombined 2 regimes into one program.
            6. Final simplification81.0%

              \[\leadsto \begin{array}{l} \mathbf{if}\;1 + \frac{x}{\left(y - t\right) \cdot \left(z - y\right)} \leq 0.9999998861946734:\\ \;\;\;\;1 + \frac{x}{y \cdot z}\\ \mathbf{elif}\;1 + \frac{x}{\left(y - t\right) \cdot \left(z - y\right)} \leq 50000000:\\ \;\;\;\;1\\ \mathbf{else}:\\ \;\;\;\;1 + \frac{x}{y \cdot z}\\ \end{array} \]
            7. Add Preprocessing

            Alternative 6: 80.9% accurate, 0.3× speedup?

            \[\begin{array}{l} [x, y, z, t] = \mathsf{sort}([x, y, z, t])\\ \\ \begin{array}{l} t_1 := \frac{x}{y \cdot z}\\ t_2 := 1 + \frac{x}{\left(y - t\right) \cdot \left(z - y\right)}\\ \mathbf{if}\;t\_2 \leq -1000000:\\ \;\;\;\;t\_1\\ \mathbf{elif}\;t\_2 \leq 50000000:\\ \;\;\;\;1\\ \mathbf{else}:\\ \;\;\;\;t\_1\\ \end{array} \end{array} \]
            NOTE: x, y, z, and t should be sorted in increasing order before calling this function.
            (FPCore (x y z t)
             :precision binary64
             (let* ((t_1 (/ x (* y z))) (t_2 (+ 1.0 (/ x (* (- y t) (- z y))))))
               (if (<= t_2 -1000000.0) t_1 (if (<= t_2 50000000.0) 1.0 t_1))))
            assert(x < y && y < z && z < t);
            double code(double x, double y, double z, double t) {
            	double t_1 = x / (y * z);
            	double t_2 = 1.0 + (x / ((y - t) * (z - y)));
            	double tmp;
            	if (t_2 <= -1000000.0) {
            		tmp = t_1;
            	} else if (t_2 <= 50000000.0) {
            		tmp = 1.0;
            	} else {
            		tmp = t_1;
            	}
            	return tmp;
            }
            
            NOTE: x, y, z, and t should be sorted in increasing order before calling this function.
            real(8) function code(x, y, z, t)
                real(8), intent (in) :: x
                real(8), intent (in) :: y
                real(8), intent (in) :: z
                real(8), intent (in) :: t
                real(8) :: t_1
                real(8) :: t_2
                real(8) :: tmp
                t_1 = x / (y * z)
                t_2 = 1.0d0 + (x / ((y - t) * (z - y)))
                if (t_2 <= (-1000000.0d0)) then
                    tmp = t_1
                else if (t_2 <= 50000000.0d0) then
                    tmp = 1.0d0
                else
                    tmp = t_1
                end if
                code = tmp
            end function
            
            assert x < y && y < z && z < t;
            public static double code(double x, double y, double z, double t) {
            	double t_1 = x / (y * z);
            	double t_2 = 1.0 + (x / ((y - t) * (z - y)));
            	double tmp;
            	if (t_2 <= -1000000.0) {
            		tmp = t_1;
            	} else if (t_2 <= 50000000.0) {
            		tmp = 1.0;
            	} else {
            		tmp = t_1;
            	}
            	return tmp;
            }
            
            [x, y, z, t] = sort([x, y, z, t])
            def code(x, y, z, t):
            	t_1 = x / (y * z)
            	t_2 = 1.0 + (x / ((y - t) * (z - y)))
            	tmp = 0
            	if t_2 <= -1000000.0:
            		tmp = t_1
            	elif t_2 <= 50000000.0:
            		tmp = 1.0
            	else:
            		tmp = t_1
            	return tmp
            
            x, y, z, t = sort([x, y, z, t])
            function code(x, y, z, t)
            	t_1 = Float64(x / Float64(y * z))
            	t_2 = Float64(1.0 + Float64(x / Float64(Float64(y - t) * Float64(z - y))))
            	tmp = 0.0
            	if (t_2 <= -1000000.0)
            		tmp = t_1;
            	elseif (t_2 <= 50000000.0)
            		tmp = 1.0;
            	else
            		tmp = t_1;
            	end
            	return tmp
            end
            
            x, y, z, t = num2cell(sort([x, y, z, t])){:}
            function tmp_2 = code(x, y, z, t)
            	t_1 = x / (y * z);
            	t_2 = 1.0 + (x / ((y - t) * (z - y)));
            	tmp = 0.0;
            	if (t_2 <= -1000000.0)
            		tmp = t_1;
            	elseif (t_2 <= 50000000.0)
            		tmp = 1.0;
            	else
            		tmp = t_1;
            	end
            	tmp_2 = tmp;
            end
            
            NOTE: x, y, z, and t should be sorted in increasing order before calling this function.
            code[x_, y_, z_, t_] := Block[{t$95$1 = N[(x / N[(y * z), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$2 = N[(1.0 + N[(x / N[(N[(y - t), $MachinePrecision] * N[(z - y), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[t$95$2, -1000000.0], t$95$1, If[LessEqual[t$95$2, 50000000.0], 1.0, t$95$1]]]]
            
            \begin{array}{l}
            [x, y, z, t] = \mathsf{sort}([x, y, z, t])\\
            \\
            \begin{array}{l}
            t_1 := \frac{x}{y \cdot z}\\
            t_2 := 1 + \frac{x}{\left(y - t\right) \cdot \left(z - y\right)}\\
            \mathbf{if}\;t\_2 \leq -1000000:\\
            \;\;\;\;t\_1\\
            
            \mathbf{elif}\;t\_2 \leq 50000000:\\
            \;\;\;\;1\\
            
            \mathbf{else}:\\
            \;\;\;\;t\_1\\
            
            
            \end{array}
            \end{array}
            
            Derivation
            1. Split input into 2 regimes
            2. if (-.f64 #s(literal 1 binary64) (/.f64 x (*.f64 (-.f64 y z) (-.f64 y t)))) < -1e6 or 5e7 < (-.f64 #s(literal 1 binary64) (/.f64 x (*.f64 (-.f64 y z) (-.f64 y t))))

              1. Initial program 98.2%

                \[1 - \frac{x}{\left(y - z\right) \cdot \left(y - t\right)} \]
              2. Add Preprocessing
              3. Taylor expanded in z around inf

                \[\leadsto 1 - \color{blue}{-1 \cdot \frac{x}{z \cdot \left(y - t\right)}} \]
              4. Step-by-step derivation
                1. mul-1-negN/A

                  \[\leadsto 1 - \color{blue}{\left(\mathsf{neg}\left(\frac{x}{z \cdot \left(y - t\right)}\right)\right)} \]
                2. distribute-neg-frac2N/A

                  \[\leadsto 1 - \color{blue}{\frac{x}{\mathsf{neg}\left(z \cdot \left(y - t\right)\right)}} \]
                3. mul-1-negN/A

                  \[\leadsto 1 - \frac{x}{\color{blue}{-1 \cdot \left(z \cdot \left(y - t\right)\right)}} \]
                4. /-lowering-/.f64N/A

                  \[\leadsto 1 - \color{blue}{\frac{x}{-1 \cdot \left(z \cdot \left(y - t\right)\right)}} \]
                5. mul-1-negN/A

                  \[\leadsto 1 - \frac{x}{\color{blue}{\mathsf{neg}\left(z \cdot \left(y - t\right)\right)}} \]
                6. distribute-rgt-neg-inN/A

                  \[\leadsto 1 - \frac{x}{\color{blue}{z \cdot \left(\mathsf{neg}\left(\left(y - t\right)\right)\right)}} \]
                7. mul-1-negN/A

                  \[\leadsto 1 - \frac{x}{z \cdot \color{blue}{\left(-1 \cdot \left(y - t\right)\right)}} \]
                8. *-lowering-*.f64N/A

                  \[\leadsto 1 - \frac{x}{\color{blue}{z \cdot \left(-1 \cdot \left(y - t\right)\right)}} \]
                9. mul-1-negN/A

                  \[\leadsto 1 - \frac{x}{z \cdot \color{blue}{\left(\mathsf{neg}\left(\left(y - t\right)\right)\right)}} \]
                10. sub-negN/A

                  \[\leadsto 1 - \frac{x}{z \cdot \left(\mathsf{neg}\left(\color{blue}{\left(y + \left(\mathsf{neg}\left(t\right)\right)\right)}\right)\right)} \]
                11. mul-1-negN/A

                  \[\leadsto 1 - \frac{x}{z \cdot \left(\mathsf{neg}\left(\left(y + \color{blue}{-1 \cdot t}\right)\right)\right)} \]
                12. +-commutativeN/A

                  \[\leadsto 1 - \frac{x}{z \cdot \left(\mathsf{neg}\left(\color{blue}{\left(-1 \cdot t + y\right)}\right)\right)} \]
                13. distribute-neg-inN/A

                  \[\leadsto 1 - \frac{x}{z \cdot \color{blue}{\left(\left(\mathsf{neg}\left(-1 \cdot t\right)\right) + \left(\mathsf{neg}\left(y\right)\right)\right)}} \]
                14. unsub-negN/A

                  \[\leadsto 1 - \frac{x}{z \cdot \color{blue}{\left(\left(\mathsf{neg}\left(-1 \cdot t\right)\right) - y\right)}} \]
                15. mul-1-negN/A

                  \[\leadsto 1 - \frac{x}{z \cdot \left(\left(\mathsf{neg}\left(\color{blue}{\left(\mathsf{neg}\left(t\right)\right)}\right)\right) - y\right)} \]
                16. remove-double-negN/A

                  \[\leadsto 1 - \frac{x}{z \cdot \left(\color{blue}{t} - y\right)} \]
                17. --lowering--.f6457.5

                  \[\leadsto 1 - \frac{x}{z \cdot \color{blue}{\left(t - y\right)}} \]
              5. Simplified57.5%

                \[\leadsto 1 - \color{blue}{\frac{x}{z \cdot \left(t - y\right)}} \]
              6. Taylor expanded in t around 0

                \[\leadsto \color{blue}{1 - -1 \cdot \frac{x}{y \cdot z}} \]
              7. Step-by-step derivation
                1. sub-negN/A

                  \[\leadsto \color{blue}{1 + \left(\mathsf{neg}\left(-1 \cdot \frac{x}{y \cdot z}\right)\right)} \]
                2. mul-1-negN/A

                  \[\leadsto 1 + \left(\mathsf{neg}\left(\color{blue}{\left(\mathsf{neg}\left(\frac{x}{y \cdot z}\right)\right)}\right)\right) \]
                3. remove-double-negN/A

                  \[\leadsto 1 + \color{blue}{\frac{x}{y \cdot z}} \]
                4. +-lowering-+.f64N/A

                  \[\leadsto \color{blue}{1 + \frac{x}{y \cdot z}} \]
                5. /-lowering-/.f64N/A

                  \[\leadsto 1 + \color{blue}{\frac{x}{y \cdot z}} \]
                6. *-commutativeN/A

                  \[\leadsto 1 + \frac{x}{\color{blue}{z \cdot y}} \]
                7. *-lowering-*.f6430.1

                  \[\leadsto 1 + \frac{x}{\color{blue}{z \cdot y}} \]
              8. Simplified30.1%

                \[\leadsto \color{blue}{1 + \frac{x}{z \cdot y}} \]
              9. Taylor expanded in x around inf

                \[\leadsto \color{blue}{\frac{x}{y \cdot z}} \]
              10. Step-by-step derivation
                1. /-lowering-/.f64N/A

                  \[\leadsto \color{blue}{\frac{x}{y \cdot z}} \]
                2. *-commutativeN/A

                  \[\leadsto \frac{x}{\color{blue}{z \cdot y}} \]
                3. *-lowering-*.f6428.9

                  \[\leadsto \frac{x}{\color{blue}{z \cdot y}} \]
              11. Simplified28.9%

                \[\leadsto \color{blue}{\frac{x}{z \cdot y}} \]

              if -1e6 < (-.f64 #s(literal 1 binary64) (/.f64 x (*.f64 (-.f64 y z) (-.f64 y t)))) < 5e7

              1. Initial program 100.0%

                \[1 - \frac{x}{\left(y - z\right) \cdot \left(y - t\right)} \]
              2. Add Preprocessing
              3. Taylor expanded in x around 0

                \[\leadsto \color{blue}{1} \]
              4. Step-by-step derivation
                1. Simplified98.4%

                  \[\leadsto \color{blue}{1} \]
              5. Recombined 2 regimes into one program.
              6. Final simplification80.5%

                \[\leadsto \begin{array}{l} \mathbf{if}\;1 + \frac{x}{\left(y - t\right) \cdot \left(z - y\right)} \leq -1000000:\\ \;\;\;\;\frac{x}{y \cdot z}\\ \mathbf{elif}\;1 + \frac{x}{\left(y - t\right) \cdot \left(z - y\right)} \leq 50000000:\\ \;\;\;\;1\\ \mathbf{else}:\\ \;\;\;\;\frac{x}{y \cdot z}\\ \end{array} \]
              7. Add Preprocessing

              Alternative 7: 85.5% accurate, 0.3× speedup?

              \[\begin{array}{l} [x, y, z, t] = \mathsf{sort}([x, y, z, t])\\ \\ \begin{array}{l} t_1 := \frac{x}{\left(y - t\right) \cdot \left(y - z\right)}\\ t_2 := 1 - \frac{x}{t \cdot z}\\ \mathbf{if}\;t\_1 \leq -500:\\ \;\;\;\;t\_2\\ \mathbf{elif}\;t\_1 \leq 2 \cdot 10^{-7}:\\ \;\;\;\;1\\ \mathbf{else}:\\ \;\;\;\;t\_2\\ \end{array} \end{array} \]
              NOTE: x, y, z, and t should be sorted in increasing order before calling this function.
              (FPCore (x y z t)
               :precision binary64
               (let* ((t_1 (/ x (* (- y t) (- y z)))) (t_2 (- 1.0 (/ x (* t z)))))
                 (if (<= t_1 -500.0) t_2 (if (<= t_1 2e-7) 1.0 t_2))))
              assert(x < y && y < z && z < t);
              double code(double x, double y, double z, double t) {
              	double t_1 = x / ((y - t) * (y - z));
              	double t_2 = 1.0 - (x / (t * z));
              	double tmp;
              	if (t_1 <= -500.0) {
              		tmp = t_2;
              	} else if (t_1 <= 2e-7) {
              		tmp = 1.0;
              	} else {
              		tmp = t_2;
              	}
              	return tmp;
              }
              
              NOTE: x, y, z, and t should be sorted in increasing order before calling this function.
              real(8) function code(x, y, z, t)
                  real(8), intent (in) :: x
                  real(8), intent (in) :: y
                  real(8), intent (in) :: z
                  real(8), intent (in) :: t
                  real(8) :: t_1
                  real(8) :: t_2
                  real(8) :: tmp
                  t_1 = x / ((y - t) * (y - z))
                  t_2 = 1.0d0 - (x / (t * z))
                  if (t_1 <= (-500.0d0)) then
                      tmp = t_2
                  else if (t_1 <= 2d-7) then
                      tmp = 1.0d0
                  else
                      tmp = t_2
                  end if
                  code = tmp
              end function
              
              assert x < y && y < z && z < t;
              public static double code(double x, double y, double z, double t) {
              	double t_1 = x / ((y - t) * (y - z));
              	double t_2 = 1.0 - (x / (t * z));
              	double tmp;
              	if (t_1 <= -500.0) {
              		tmp = t_2;
              	} else if (t_1 <= 2e-7) {
              		tmp = 1.0;
              	} else {
              		tmp = t_2;
              	}
              	return tmp;
              }
              
              [x, y, z, t] = sort([x, y, z, t])
              def code(x, y, z, t):
              	t_1 = x / ((y - t) * (y - z))
              	t_2 = 1.0 - (x / (t * z))
              	tmp = 0
              	if t_1 <= -500.0:
              		tmp = t_2
              	elif t_1 <= 2e-7:
              		tmp = 1.0
              	else:
              		tmp = t_2
              	return tmp
              
              x, y, z, t = sort([x, y, z, t])
              function code(x, y, z, t)
              	t_1 = Float64(x / Float64(Float64(y - t) * Float64(y - z)))
              	t_2 = Float64(1.0 - Float64(x / Float64(t * z)))
              	tmp = 0.0
              	if (t_1 <= -500.0)
              		tmp = t_2;
              	elseif (t_1 <= 2e-7)
              		tmp = 1.0;
              	else
              		tmp = t_2;
              	end
              	return tmp
              end
              
              x, y, z, t = num2cell(sort([x, y, z, t])){:}
              function tmp_2 = code(x, y, z, t)
              	t_1 = x / ((y - t) * (y - z));
              	t_2 = 1.0 - (x / (t * z));
              	tmp = 0.0;
              	if (t_1 <= -500.0)
              		tmp = t_2;
              	elseif (t_1 <= 2e-7)
              		tmp = 1.0;
              	else
              		tmp = t_2;
              	end
              	tmp_2 = tmp;
              end
              
              NOTE: x, y, z, and t should be sorted in increasing order before calling this function.
              code[x_, y_, z_, t_] := Block[{t$95$1 = N[(x / N[(N[(y - t), $MachinePrecision] * N[(y - z), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$2 = N[(1.0 - N[(x / N[(t * z), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[t$95$1, -500.0], t$95$2, If[LessEqual[t$95$1, 2e-7], 1.0, t$95$2]]]]
              
              \begin{array}{l}
              [x, y, z, t] = \mathsf{sort}([x, y, z, t])\\
              \\
              \begin{array}{l}
              t_1 := \frac{x}{\left(y - t\right) \cdot \left(y - z\right)}\\
              t_2 := 1 - \frac{x}{t \cdot z}\\
              \mathbf{if}\;t\_1 \leq -500:\\
              \;\;\;\;t\_2\\
              
              \mathbf{elif}\;t\_1 \leq 2 \cdot 10^{-7}:\\
              \;\;\;\;1\\
              
              \mathbf{else}:\\
              \;\;\;\;t\_2\\
              
              
              \end{array}
              \end{array}
              
              Derivation
              1. Split input into 2 regimes
              2. if (/.f64 x (*.f64 (-.f64 y z) (-.f64 y t))) < -500 or 1.9999999999999999e-7 < (/.f64 x (*.f64 (-.f64 y z) (-.f64 y t)))

                1. Initial program 98.2%

                  \[1 - \frac{x}{\left(y - z\right) \cdot \left(y - t\right)} \]
                2. Add Preprocessing
                3. Taylor expanded in y around 0

                  \[\leadsto \color{blue}{1 - \frac{x}{t \cdot z}} \]
                4. Step-by-step derivation
                  1. --lowering--.f64N/A

                    \[\leadsto \color{blue}{1 - \frac{x}{t \cdot z}} \]
                  2. /-lowering-/.f64N/A

                    \[\leadsto 1 - \color{blue}{\frac{x}{t \cdot z}} \]
                  3. *-lowering-*.f6438.7

                    \[\leadsto 1 - \frac{x}{\color{blue}{t \cdot z}} \]
                5. Simplified38.7%

                  \[\leadsto \color{blue}{1 - \frac{x}{t \cdot z}} \]

                if -500 < (/.f64 x (*.f64 (-.f64 y z) (-.f64 y t))) < 1.9999999999999999e-7

                1. Initial program 100.0%

                  \[1 - \frac{x}{\left(y - z\right) \cdot \left(y - t\right)} \]
                2. Add Preprocessing
                3. Taylor expanded in x around 0

                  \[\leadsto \color{blue}{1} \]
                4. Step-by-step derivation
                  1. Simplified99.4%

                    \[\leadsto \color{blue}{1} \]
                5. Recombined 2 regimes into one program.
                6. Final simplification83.2%

                  \[\leadsto \begin{array}{l} \mathbf{if}\;\frac{x}{\left(y - t\right) \cdot \left(y - z\right)} \leq -500:\\ \;\;\;\;1 - \frac{x}{t \cdot z}\\ \mathbf{elif}\;\frac{x}{\left(y - t\right) \cdot \left(y - z\right)} \leq 2 \cdot 10^{-7}:\\ \;\;\;\;1\\ \mathbf{else}:\\ \;\;\;\;1 - \frac{x}{t \cdot z}\\ \end{array} \]
                7. Add Preprocessing

                Alternative 8: 91.2% accurate, 0.7× speedup?

                \[\begin{array}{l} [x, y, z, t] = \mathsf{sort}([x, y, z, t])\\ \\ \begin{array}{l} t_1 := 1 + \frac{x}{\left(y - t\right) \cdot z}\\ \mathbf{if}\;z \leq -9.4 \cdot 10^{-60}:\\ \;\;\;\;t\_1\\ \mathbf{elif}\;z \leq 9 \cdot 10^{-150}:\\ \;\;\;\;1 + \frac{x}{y \cdot \left(t - y\right)}\\ \mathbf{else}:\\ \;\;\;\;t\_1\\ \end{array} \end{array} \]
                NOTE: x, y, z, and t should be sorted in increasing order before calling this function.
                (FPCore (x y z t)
                 :precision binary64
                 (let* ((t_1 (+ 1.0 (/ x (* (- y t) z)))))
                   (if (<= z -9.4e-60)
                     t_1
                     (if (<= z 9e-150) (+ 1.0 (/ x (* y (- t y)))) t_1))))
                assert(x < y && y < z && z < t);
                double code(double x, double y, double z, double t) {
                	double t_1 = 1.0 + (x / ((y - t) * z));
                	double tmp;
                	if (z <= -9.4e-60) {
                		tmp = t_1;
                	} else if (z <= 9e-150) {
                		tmp = 1.0 + (x / (y * (t - y)));
                	} else {
                		tmp = t_1;
                	}
                	return tmp;
                }
                
                NOTE: x, y, z, and t should be sorted in increasing order before calling this function.
                real(8) function code(x, y, z, t)
                    real(8), intent (in) :: x
                    real(8), intent (in) :: y
                    real(8), intent (in) :: z
                    real(8), intent (in) :: t
                    real(8) :: t_1
                    real(8) :: tmp
                    t_1 = 1.0d0 + (x / ((y - t) * z))
                    if (z <= (-9.4d-60)) then
                        tmp = t_1
                    else if (z <= 9d-150) then
                        tmp = 1.0d0 + (x / (y * (t - y)))
                    else
                        tmp = t_1
                    end if
                    code = tmp
                end function
                
                assert x < y && y < z && z < t;
                public static double code(double x, double y, double z, double t) {
                	double t_1 = 1.0 + (x / ((y - t) * z));
                	double tmp;
                	if (z <= -9.4e-60) {
                		tmp = t_1;
                	} else if (z <= 9e-150) {
                		tmp = 1.0 + (x / (y * (t - y)));
                	} else {
                		tmp = t_1;
                	}
                	return tmp;
                }
                
                [x, y, z, t] = sort([x, y, z, t])
                def code(x, y, z, t):
                	t_1 = 1.0 + (x / ((y - t) * z))
                	tmp = 0
                	if z <= -9.4e-60:
                		tmp = t_1
                	elif z <= 9e-150:
                		tmp = 1.0 + (x / (y * (t - y)))
                	else:
                		tmp = t_1
                	return tmp
                
                x, y, z, t = sort([x, y, z, t])
                function code(x, y, z, t)
                	t_1 = Float64(1.0 + Float64(x / Float64(Float64(y - t) * z)))
                	tmp = 0.0
                	if (z <= -9.4e-60)
                		tmp = t_1;
                	elseif (z <= 9e-150)
                		tmp = Float64(1.0 + Float64(x / Float64(y * Float64(t - y))));
                	else
                		tmp = t_1;
                	end
                	return tmp
                end
                
                x, y, z, t = num2cell(sort([x, y, z, t])){:}
                function tmp_2 = code(x, y, z, t)
                	t_1 = 1.0 + (x / ((y - t) * z));
                	tmp = 0.0;
                	if (z <= -9.4e-60)
                		tmp = t_1;
                	elseif (z <= 9e-150)
                		tmp = 1.0 + (x / (y * (t - y)));
                	else
                		tmp = t_1;
                	end
                	tmp_2 = tmp;
                end
                
                NOTE: x, y, z, and t should be sorted in increasing order before calling this function.
                code[x_, y_, z_, t_] := Block[{t$95$1 = N[(1.0 + N[(x / N[(N[(y - t), $MachinePrecision] * z), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[z, -9.4e-60], t$95$1, If[LessEqual[z, 9e-150], N[(1.0 + N[(x / N[(y * N[(t - y), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], t$95$1]]]
                
                \begin{array}{l}
                [x, y, z, t] = \mathsf{sort}([x, y, z, t])\\
                \\
                \begin{array}{l}
                t_1 := 1 + \frac{x}{\left(y - t\right) \cdot z}\\
                \mathbf{if}\;z \leq -9.4 \cdot 10^{-60}:\\
                \;\;\;\;t\_1\\
                
                \mathbf{elif}\;z \leq 9 \cdot 10^{-150}:\\
                \;\;\;\;1 + \frac{x}{y \cdot \left(t - y\right)}\\
                
                \mathbf{else}:\\
                \;\;\;\;t\_1\\
                
                
                \end{array}
                \end{array}
                
                Derivation
                1. Split input into 2 regimes
                2. if z < -9.4e-60 or 9.0000000000000005e-150 < z

                  1. Initial program 99.9%

                    \[1 - \frac{x}{\left(y - z\right) \cdot \left(y - t\right)} \]
                  2. Add Preprocessing
                  3. Taylor expanded in z around inf

                    \[\leadsto 1 - \color{blue}{-1 \cdot \frac{x}{z \cdot \left(y - t\right)}} \]
                  4. Step-by-step derivation
                    1. mul-1-negN/A

                      \[\leadsto 1 - \color{blue}{\left(\mathsf{neg}\left(\frac{x}{z \cdot \left(y - t\right)}\right)\right)} \]
                    2. distribute-neg-frac2N/A

                      \[\leadsto 1 - \color{blue}{\frac{x}{\mathsf{neg}\left(z \cdot \left(y - t\right)\right)}} \]
                    3. mul-1-negN/A

                      \[\leadsto 1 - \frac{x}{\color{blue}{-1 \cdot \left(z \cdot \left(y - t\right)\right)}} \]
                    4. /-lowering-/.f64N/A

                      \[\leadsto 1 - \color{blue}{\frac{x}{-1 \cdot \left(z \cdot \left(y - t\right)\right)}} \]
                    5. mul-1-negN/A

                      \[\leadsto 1 - \frac{x}{\color{blue}{\mathsf{neg}\left(z \cdot \left(y - t\right)\right)}} \]
                    6. distribute-rgt-neg-inN/A

                      \[\leadsto 1 - \frac{x}{\color{blue}{z \cdot \left(\mathsf{neg}\left(\left(y - t\right)\right)\right)}} \]
                    7. mul-1-negN/A

                      \[\leadsto 1 - \frac{x}{z \cdot \color{blue}{\left(-1 \cdot \left(y - t\right)\right)}} \]
                    8. *-lowering-*.f64N/A

                      \[\leadsto 1 - \frac{x}{\color{blue}{z \cdot \left(-1 \cdot \left(y - t\right)\right)}} \]
                    9. mul-1-negN/A

                      \[\leadsto 1 - \frac{x}{z \cdot \color{blue}{\left(\mathsf{neg}\left(\left(y - t\right)\right)\right)}} \]
                    10. sub-negN/A

                      \[\leadsto 1 - \frac{x}{z \cdot \left(\mathsf{neg}\left(\color{blue}{\left(y + \left(\mathsf{neg}\left(t\right)\right)\right)}\right)\right)} \]
                    11. mul-1-negN/A

                      \[\leadsto 1 - \frac{x}{z \cdot \left(\mathsf{neg}\left(\left(y + \color{blue}{-1 \cdot t}\right)\right)\right)} \]
                    12. +-commutativeN/A

                      \[\leadsto 1 - \frac{x}{z \cdot \left(\mathsf{neg}\left(\color{blue}{\left(-1 \cdot t + y\right)}\right)\right)} \]
                    13. distribute-neg-inN/A

                      \[\leadsto 1 - \frac{x}{z \cdot \color{blue}{\left(\left(\mathsf{neg}\left(-1 \cdot t\right)\right) + \left(\mathsf{neg}\left(y\right)\right)\right)}} \]
                    14. unsub-negN/A

                      \[\leadsto 1 - \frac{x}{z \cdot \color{blue}{\left(\left(\mathsf{neg}\left(-1 \cdot t\right)\right) - y\right)}} \]
                    15. mul-1-negN/A

                      \[\leadsto 1 - \frac{x}{z \cdot \left(\left(\mathsf{neg}\left(\color{blue}{\left(\mathsf{neg}\left(t\right)\right)}\right)\right) - y\right)} \]
                    16. remove-double-negN/A

                      \[\leadsto 1 - \frac{x}{z \cdot \left(\color{blue}{t} - y\right)} \]
                    17. --lowering--.f6491.1

                      \[\leadsto 1 - \frac{x}{z \cdot \color{blue}{\left(t - y\right)}} \]
                  5. Simplified91.1%

                    \[\leadsto 1 - \color{blue}{\frac{x}{z \cdot \left(t - y\right)}} \]

                  if -9.4e-60 < z < 9.0000000000000005e-150

                  1. Initial program 98.6%

                    \[1 - \frac{x}{\left(y - z\right) \cdot \left(y - t\right)} \]
                  2. Add Preprocessing
                  3. Taylor expanded in z around 0

                    \[\leadsto \color{blue}{1 - \frac{x}{y \cdot \left(y - t\right)}} \]
                  4. Step-by-step derivation
                    1. --lowering--.f64N/A

                      \[\leadsto \color{blue}{1 - \frac{x}{y \cdot \left(y - t\right)}} \]
                    2. /-lowering-/.f64N/A

                      \[\leadsto 1 - \color{blue}{\frac{x}{y \cdot \left(y - t\right)}} \]
                    3. *-lowering-*.f64N/A

                      \[\leadsto 1 - \frac{x}{\color{blue}{y \cdot \left(y - t\right)}} \]
                    4. --lowering--.f6491.9

                      \[\leadsto 1 - \frac{x}{y \cdot \color{blue}{\left(y - t\right)}} \]
                  5. Simplified91.9%

                    \[\leadsto \color{blue}{1 - \frac{x}{y \cdot \left(y - t\right)}} \]
                3. Recombined 2 regimes into one program.
                4. Final simplification91.3%

                  \[\leadsto \begin{array}{l} \mathbf{if}\;z \leq -9.4 \cdot 10^{-60}:\\ \;\;\;\;1 + \frac{x}{\left(y - t\right) \cdot z}\\ \mathbf{elif}\;z \leq 9 \cdot 10^{-150}:\\ \;\;\;\;1 + \frac{x}{y \cdot \left(t - y\right)}\\ \mathbf{else}:\\ \;\;\;\;1 + \frac{x}{\left(y - t\right) \cdot z}\\ \end{array} \]
                5. Add Preprocessing

                Alternative 9: 86.5% accurate, 0.7× speedup?

                \[\begin{array}{l} [x, y, z, t] = \mathsf{sort}([x, y, z, t])\\ \\ \begin{array}{l} t_1 := 1 + \frac{x}{y \cdot \left(t - y\right)}\\ \mathbf{if}\;y \leq -2.12 \cdot 10^{-106}:\\ \;\;\;\;t\_1\\ \mathbf{elif}\;y \leq 6.8 \cdot 10^{-115}:\\ \;\;\;\;1 - \frac{x}{t \cdot z}\\ \mathbf{else}:\\ \;\;\;\;t\_1\\ \end{array} \end{array} \]
                NOTE: x, y, z, and t should be sorted in increasing order before calling this function.
                (FPCore (x y z t)
                 :precision binary64
                 (let* ((t_1 (+ 1.0 (/ x (* y (- t y))))))
                   (if (<= y -2.12e-106) t_1 (if (<= y 6.8e-115) (- 1.0 (/ x (* t z))) t_1))))
                assert(x < y && y < z && z < t);
                double code(double x, double y, double z, double t) {
                	double t_1 = 1.0 + (x / (y * (t - y)));
                	double tmp;
                	if (y <= -2.12e-106) {
                		tmp = t_1;
                	} else if (y <= 6.8e-115) {
                		tmp = 1.0 - (x / (t * z));
                	} else {
                		tmp = t_1;
                	}
                	return tmp;
                }
                
                NOTE: x, y, z, and t should be sorted in increasing order before calling this function.
                real(8) function code(x, y, z, t)
                    real(8), intent (in) :: x
                    real(8), intent (in) :: y
                    real(8), intent (in) :: z
                    real(8), intent (in) :: t
                    real(8) :: t_1
                    real(8) :: tmp
                    t_1 = 1.0d0 + (x / (y * (t - y)))
                    if (y <= (-2.12d-106)) then
                        tmp = t_1
                    else if (y <= 6.8d-115) then
                        tmp = 1.0d0 - (x / (t * z))
                    else
                        tmp = t_1
                    end if
                    code = tmp
                end function
                
                assert x < y && y < z && z < t;
                public static double code(double x, double y, double z, double t) {
                	double t_1 = 1.0 + (x / (y * (t - y)));
                	double tmp;
                	if (y <= -2.12e-106) {
                		tmp = t_1;
                	} else if (y <= 6.8e-115) {
                		tmp = 1.0 - (x / (t * z));
                	} else {
                		tmp = t_1;
                	}
                	return tmp;
                }
                
                [x, y, z, t] = sort([x, y, z, t])
                def code(x, y, z, t):
                	t_1 = 1.0 + (x / (y * (t - y)))
                	tmp = 0
                	if y <= -2.12e-106:
                		tmp = t_1
                	elif y <= 6.8e-115:
                		tmp = 1.0 - (x / (t * z))
                	else:
                		tmp = t_1
                	return tmp
                
                x, y, z, t = sort([x, y, z, t])
                function code(x, y, z, t)
                	t_1 = Float64(1.0 + Float64(x / Float64(y * Float64(t - y))))
                	tmp = 0.0
                	if (y <= -2.12e-106)
                		tmp = t_1;
                	elseif (y <= 6.8e-115)
                		tmp = Float64(1.0 - Float64(x / Float64(t * z)));
                	else
                		tmp = t_1;
                	end
                	return tmp
                end
                
                x, y, z, t = num2cell(sort([x, y, z, t])){:}
                function tmp_2 = code(x, y, z, t)
                	t_1 = 1.0 + (x / (y * (t - y)));
                	tmp = 0.0;
                	if (y <= -2.12e-106)
                		tmp = t_1;
                	elseif (y <= 6.8e-115)
                		tmp = 1.0 - (x / (t * z));
                	else
                		tmp = t_1;
                	end
                	tmp_2 = tmp;
                end
                
                NOTE: x, y, z, and t should be sorted in increasing order before calling this function.
                code[x_, y_, z_, t_] := Block[{t$95$1 = N[(1.0 + N[(x / N[(y * N[(t - y), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[y, -2.12e-106], t$95$1, If[LessEqual[y, 6.8e-115], N[(1.0 - N[(x / N[(t * z), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], t$95$1]]]
                
                \begin{array}{l}
                [x, y, z, t] = \mathsf{sort}([x, y, z, t])\\
                \\
                \begin{array}{l}
                t_1 := 1 + \frac{x}{y \cdot \left(t - y\right)}\\
                \mathbf{if}\;y \leq -2.12 \cdot 10^{-106}:\\
                \;\;\;\;t\_1\\
                
                \mathbf{elif}\;y \leq 6.8 \cdot 10^{-115}:\\
                \;\;\;\;1 - \frac{x}{t \cdot z}\\
                
                \mathbf{else}:\\
                \;\;\;\;t\_1\\
                
                
                \end{array}
                \end{array}
                
                Derivation
                1. Split input into 2 regimes
                2. if y < -2.12e-106 or 6.7999999999999996e-115 < y

                  1. Initial program 99.9%

                    \[1 - \frac{x}{\left(y - z\right) \cdot \left(y - t\right)} \]
                  2. Add Preprocessing
                  3. Taylor expanded in z around 0

                    \[\leadsto \color{blue}{1 - \frac{x}{y \cdot \left(y - t\right)}} \]
                  4. Step-by-step derivation
                    1. --lowering--.f64N/A

                      \[\leadsto \color{blue}{1 - \frac{x}{y \cdot \left(y - t\right)}} \]
                    2. /-lowering-/.f64N/A

                      \[\leadsto 1 - \color{blue}{\frac{x}{y \cdot \left(y - t\right)}} \]
                    3. *-lowering-*.f64N/A

                      \[\leadsto 1 - \frac{x}{\color{blue}{y \cdot \left(y - t\right)}} \]
                    4. --lowering--.f6485.5

                      \[\leadsto 1 - \frac{x}{y \cdot \color{blue}{\left(y - t\right)}} \]
                  5. Simplified85.5%

                    \[\leadsto \color{blue}{1 - \frac{x}{y \cdot \left(y - t\right)}} \]

                  if -2.12e-106 < y < 6.7999999999999996e-115

                  1. Initial program 98.7%

                    \[1 - \frac{x}{\left(y - z\right) \cdot \left(y - t\right)} \]
                  2. Add Preprocessing
                  3. Taylor expanded in y around 0

                    \[\leadsto \color{blue}{1 - \frac{x}{t \cdot z}} \]
                  4. Step-by-step derivation
                    1. --lowering--.f64N/A

                      \[\leadsto \color{blue}{1 - \frac{x}{t \cdot z}} \]
                    2. /-lowering-/.f64N/A

                      \[\leadsto 1 - \color{blue}{\frac{x}{t \cdot z}} \]
                    3. *-lowering-*.f6482.2

                      \[\leadsto 1 - \frac{x}{\color{blue}{t \cdot z}} \]
                  5. Simplified82.2%

                    \[\leadsto \color{blue}{1 - \frac{x}{t \cdot z}} \]
                3. Recombined 2 regimes into one program.
                4. Final simplification84.4%

                  \[\leadsto \begin{array}{l} \mathbf{if}\;y \leq -2.12 \cdot 10^{-106}:\\ \;\;\;\;1 + \frac{x}{y \cdot \left(t - y\right)}\\ \mathbf{elif}\;y \leq 6.8 \cdot 10^{-115}:\\ \;\;\;\;1 - \frac{x}{t \cdot z}\\ \mathbf{else}:\\ \;\;\;\;1 + \frac{x}{y \cdot \left(t - y\right)}\\ \end{array} \]
                5. Add Preprocessing

                Alternative 10: 99.2% accurate, 1.0× speedup?

                \[\begin{array}{l} [x, y, z, t] = \mathsf{sort}([x, y, z, t])\\ \\ 1 + \frac{x}{\left(y - t\right) \cdot \left(z - y\right)} \end{array} \]
                NOTE: x, y, z, and t should be sorted in increasing order before calling this function.
                (FPCore (x y z t) :precision binary64 (+ 1.0 (/ x (* (- y t) (- z y)))))
                assert(x < y && y < z && z < t);
                double code(double x, double y, double z, double t) {
                	return 1.0 + (x / ((y - t) * (z - y)));
                }
                
                NOTE: x, y, z, and t should be sorted in increasing order before calling this function.
                real(8) function code(x, y, z, t)
                    real(8), intent (in) :: x
                    real(8), intent (in) :: y
                    real(8), intent (in) :: z
                    real(8), intent (in) :: t
                    code = 1.0d0 + (x / ((y - t) * (z - y)))
                end function
                
                assert x < y && y < z && z < t;
                public static double code(double x, double y, double z, double t) {
                	return 1.0 + (x / ((y - t) * (z - y)));
                }
                
                [x, y, z, t] = sort([x, y, z, t])
                def code(x, y, z, t):
                	return 1.0 + (x / ((y - t) * (z - y)))
                
                x, y, z, t = sort([x, y, z, t])
                function code(x, y, z, t)
                	return Float64(1.0 + Float64(x / Float64(Float64(y - t) * Float64(z - y))))
                end
                
                x, y, z, t = num2cell(sort([x, y, z, t])){:}
                function tmp = code(x, y, z, t)
                	tmp = 1.0 + (x / ((y - t) * (z - y)));
                end
                
                NOTE: x, y, z, and t should be sorted in increasing order before calling this function.
                code[x_, y_, z_, t_] := N[(1.0 + N[(x / N[(N[(y - t), $MachinePrecision] * N[(z - y), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
                
                \begin{array}{l}
                [x, y, z, t] = \mathsf{sort}([x, y, z, t])\\
                \\
                1 + \frac{x}{\left(y - t\right) \cdot \left(z - y\right)}
                \end{array}
                
                Derivation
                1. Initial program 99.5%

                  \[1 - \frac{x}{\left(y - z\right) \cdot \left(y - t\right)} \]
                2. Add Preprocessing
                3. Final simplification99.5%

                  \[\leadsto 1 + \frac{x}{\left(y - t\right) \cdot \left(z - y\right)} \]
                4. Add Preprocessing

                Alternative 11: 74.4% accurate, 26.0× speedup?

                \[\begin{array}{l} [x, y, z, t] = \mathsf{sort}([x, y, z, t])\\ \\ 1 \end{array} \]
                NOTE: x, y, z, and t should be sorted in increasing order before calling this function.
                (FPCore (x y z t) :precision binary64 1.0)
                assert(x < y && y < z && z < t);
                double code(double x, double y, double z, double t) {
                	return 1.0;
                }
                
                NOTE: x, y, z, and t should be sorted in increasing order before calling this function.
                real(8) function code(x, y, z, t)
                    real(8), intent (in) :: x
                    real(8), intent (in) :: y
                    real(8), intent (in) :: z
                    real(8), intent (in) :: t
                    code = 1.0d0
                end function
                
                assert x < y && y < z && z < t;
                public static double code(double x, double y, double z, double t) {
                	return 1.0;
                }
                
                [x, y, z, t] = sort([x, y, z, t])
                def code(x, y, z, t):
                	return 1.0
                
                x, y, z, t = sort([x, y, z, t])
                function code(x, y, z, t)
                	return 1.0
                end
                
                x, y, z, t = num2cell(sort([x, y, z, t])){:}
                function tmp = code(x, y, z, t)
                	tmp = 1.0;
                end
                
                NOTE: x, y, z, and t should be sorted in increasing order before calling this function.
                code[x_, y_, z_, t_] := 1.0
                
                \begin{array}{l}
                [x, y, z, t] = \mathsf{sort}([x, y, z, t])\\
                \\
                1
                \end{array}
                
                Derivation
                1. Initial program 99.5%

                  \[1 - \frac{x}{\left(y - z\right) \cdot \left(y - t\right)} \]
                2. Add Preprocessing
                3. Taylor expanded in x around 0

                  \[\leadsto \color{blue}{1} \]
                4. Step-by-step derivation
                  1. Simplified73.9%

                    \[\leadsto \color{blue}{1} \]
                  2. Add Preprocessing

                  Reproduce

                  ?
                  herbie shell --seed 2024196 
                  (FPCore (x y z t)
                    :name "Data.Random.Distribution.Triangular:triangularCDF from random-fu-0.2.6.2, A"
                    :precision binary64
                    (- 1.0 (/ x (* (- y z) (- y t)))))