Cubic critical, narrow range

Percentage Accurate: 55.3% → 92.3%
Time: 14.8s
Alternatives: 11
Speedup: 23.2×

Specification

?
\[\left(\left(1.0536712127723509 \cdot 10^{-8} < a \land a < 94906265.62425156\right) \land \left(1.0536712127723509 \cdot 10^{-8} < b \land b < 94906265.62425156\right)\right) \land \left(1.0536712127723509 \cdot 10^{-8} < c \land c < 94906265.62425156\right)\]
\[\begin{array}{l} \\ \frac{\left(-b\right) + \sqrt{b \cdot b - \left(3 \cdot a\right) \cdot c}}{3 \cdot a} \end{array} \]
(FPCore (a b c)
 :precision binary64
 (/ (+ (- b) (sqrt (- (* b b) (* (* 3.0 a) c)))) (* 3.0 a)))
double code(double a, double b, double c) {
	return (-b + sqrt(((b * b) - ((3.0 * a) * c)))) / (3.0 * a);
}
real(8) function code(a, b, c)
    real(8), intent (in) :: a
    real(8), intent (in) :: b
    real(8), intent (in) :: c
    code = (-b + sqrt(((b * b) - ((3.0d0 * a) * c)))) / (3.0d0 * a)
end function
public static double code(double a, double b, double c) {
	return (-b + Math.sqrt(((b * b) - ((3.0 * a) * c)))) / (3.0 * a);
}
def code(a, b, c):
	return (-b + math.sqrt(((b * b) - ((3.0 * a) * c)))) / (3.0 * a)
function code(a, b, c)
	return Float64(Float64(Float64(-b) + sqrt(Float64(Float64(b * b) - Float64(Float64(3.0 * a) * c)))) / Float64(3.0 * a))
end
function tmp = code(a, b, c)
	tmp = (-b + sqrt(((b * b) - ((3.0 * a) * c)))) / (3.0 * a);
end
code[a_, b_, c_] := N[(N[((-b) + N[Sqrt[N[(N[(b * b), $MachinePrecision] - N[(N[(3.0 * a), $MachinePrecision] * c), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] / N[(3.0 * a), $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
\frac{\left(-b\right) + \sqrt{b \cdot b - \left(3 \cdot a\right) \cdot c}}{3 \cdot a}
\end{array}

Sampling outcomes in binary64 precision:

Local Percentage Accuracy vs ?

The average percentage accuracy by input value. Horizontal axis shows value of an input variable; the variable is choosen in the title. Vertical axis is accuracy; higher is better. Red represent the original program, while blue represents Herbie's suggestion. These can be toggled with buttons below the plot. The line is an average while dots represent individual samples.

Accuracy vs Speed?

Herbie found 11 alternatives:

AlternativeAccuracySpeedup
The accuracy (vertical axis) and speed (horizontal axis) of each alternatives. Up and to the right is better. The red square shows the initial program, and each blue circle shows an alternative.The line shows the best available speed-accuracy tradeoffs.

Initial Program: 55.3% accurate, 1.0× speedup?

\[\begin{array}{l} \\ \frac{\left(-b\right) + \sqrt{b \cdot b - \left(3 \cdot a\right) \cdot c}}{3 \cdot a} \end{array} \]
(FPCore (a b c)
 :precision binary64
 (/ (+ (- b) (sqrt (- (* b b) (* (* 3.0 a) c)))) (* 3.0 a)))
double code(double a, double b, double c) {
	return (-b + sqrt(((b * b) - ((3.0 * a) * c)))) / (3.0 * a);
}
real(8) function code(a, b, c)
    real(8), intent (in) :: a
    real(8), intent (in) :: b
    real(8), intent (in) :: c
    code = (-b + sqrt(((b * b) - ((3.0d0 * a) * c)))) / (3.0d0 * a)
end function
public static double code(double a, double b, double c) {
	return (-b + Math.sqrt(((b * b) - ((3.0 * a) * c)))) / (3.0 * a);
}
def code(a, b, c):
	return (-b + math.sqrt(((b * b) - ((3.0 * a) * c)))) / (3.0 * a)
function code(a, b, c)
	return Float64(Float64(Float64(-b) + sqrt(Float64(Float64(b * b) - Float64(Float64(3.0 * a) * c)))) / Float64(3.0 * a))
end
function tmp = code(a, b, c)
	tmp = (-b + sqrt(((b * b) - ((3.0 * a) * c)))) / (3.0 * a);
end
code[a_, b_, c_] := N[(N[((-b) + N[Sqrt[N[(N[(b * b), $MachinePrecision] - N[(N[(3.0 * a), $MachinePrecision] * c), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] / N[(3.0 * a), $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
\frac{\left(-b\right) + \sqrt{b \cdot b - \left(3 \cdot a\right) \cdot c}}{3 \cdot a}
\end{array}

Alternative 1: 92.3% accurate, 0.2× speedup?

\[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;\frac{\sqrt{b \cdot b - \left(3 \cdot a\right) \cdot c} - b}{3 \cdot a} \leq -15:\\ \;\;\;\;\frac{\mathsf{fma}\left(\sqrt{c}, \sqrt{\mathsf{fma}\left(a, -3, \frac{{b}^{2}}{c}\right)}, -b\right)}{3 \cdot a}\\ \mathbf{else}:\\ \;\;\;\;-0.5 \cdot \frac{c}{b} + a \cdot \left(-0.375 \cdot \frac{{c}^{2}}{{b}^{3}} + a \cdot \left(-0.5625 \cdot \frac{{c}^{3}}{{b}^{5}} + -1.0546875 \cdot \frac{a \cdot {c}^{4}}{{b}^{7}}\right)\right)\\ \end{array} \end{array} \]
(FPCore (a b c)
 :precision binary64
 (if (<= (/ (- (sqrt (- (* b b) (* (* 3.0 a) c))) b) (* 3.0 a)) -15.0)
   (/ (fma (sqrt c) (sqrt (fma a -3.0 (/ (pow b 2.0) c))) (- b)) (* 3.0 a))
   (+
    (* -0.5 (/ c b))
    (*
     a
     (+
      (* -0.375 (/ (pow c 2.0) (pow b 3.0)))
      (*
       a
       (+
        (* -0.5625 (/ (pow c 3.0) (pow b 5.0)))
        (* -1.0546875 (/ (* a (pow c 4.0)) (pow b 7.0))))))))))
double code(double a, double b, double c) {
	double tmp;
	if (((sqrt(((b * b) - ((3.0 * a) * c))) - b) / (3.0 * a)) <= -15.0) {
		tmp = fma(sqrt(c), sqrt(fma(a, -3.0, (pow(b, 2.0) / c))), -b) / (3.0 * a);
	} else {
		tmp = (-0.5 * (c / b)) + (a * ((-0.375 * (pow(c, 2.0) / pow(b, 3.0))) + (a * ((-0.5625 * (pow(c, 3.0) / pow(b, 5.0))) + (-1.0546875 * ((a * pow(c, 4.0)) / pow(b, 7.0)))))));
	}
	return tmp;
}
function code(a, b, c)
	tmp = 0.0
	if (Float64(Float64(sqrt(Float64(Float64(b * b) - Float64(Float64(3.0 * a) * c))) - b) / Float64(3.0 * a)) <= -15.0)
		tmp = Float64(fma(sqrt(c), sqrt(fma(a, -3.0, Float64((b ^ 2.0) / c))), Float64(-b)) / Float64(3.0 * a));
	else
		tmp = Float64(Float64(-0.5 * Float64(c / b)) + Float64(a * Float64(Float64(-0.375 * Float64((c ^ 2.0) / (b ^ 3.0))) + Float64(a * Float64(Float64(-0.5625 * Float64((c ^ 3.0) / (b ^ 5.0))) + Float64(-1.0546875 * Float64(Float64(a * (c ^ 4.0)) / (b ^ 7.0))))))));
	end
	return tmp
end
code[a_, b_, c_] := If[LessEqual[N[(N[(N[Sqrt[N[(N[(b * b), $MachinePrecision] - N[(N[(3.0 * a), $MachinePrecision] * c), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] - b), $MachinePrecision] / N[(3.0 * a), $MachinePrecision]), $MachinePrecision], -15.0], N[(N[(N[Sqrt[c], $MachinePrecision] * N[Sqrt[N[(a * -3.0 + N[(N[Power[b, 2.0], $MachinePrecision] / c), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] + (-b)), $MachinePrecision] / N[(3.0 * a), $MachinePrecision]), $MachinePrecision], N[(N[(-0.5 * N[(c / b), $MachinePrecision]), $MachinePrecision] + N[(a * N[(N[(-0.375 * N[(N[Power[c, 2.0], $MachinePrecision] / N[Power[b, 3.0], $MachinePrecision]), $MachinePrecision]), $MachinePrecision] + N[(a * N[(N[(-0.5625 * N[(N[Power[c, 3.0], $MachinePrecision] / N[Power[b, 5.0], $MachinePrecision]), $MachinePrecision]), $MachinePrecision] + N[(-1.0546875 * N[(N[(a * N[Power[c, 4.0], $MachinePrecision]), $MachinePrecision] / N[Power[b, 7.0], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]]
\begin{array}{l}

\\
\begin{array}{l}
\mathbf{if}\;\frac{\sqrt{b \cdot b - \left(3 \cdot a\right) \cdot c} - b}{3 \cdot a} \leq -15:\\
\;\;\;\;\frac{\mathsf{fma}\left(\sqrt{c}, \sqrt{\mathsf{fma}\left(a, -3, \frac{{b}^{2}}{c}\right)}, -b\right)}{3 \cdot a}\\

\mathbf{else}:\\
\;\;\;\;-0.5 \cdot \frac{c}{b} + a \cdot \left(-0.375 \cdot \frac{{c}^{2}}{{b}^{3}} + a \cdot \left(-0.5625 \cdot \frac{{c}^{3}}{{b}^{5}} + -1.0546875 \cdot \frac{a \cdot {c}^{4}}{{b}^{7}}\right)\right)\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if (/.f64 (+.f64 (neg.f64 b) (sqrt.f64 (-.f64 (*.f64 b b) (*.f64 (*.f64 #s(literal 3 binary64) a) c)))) (*.f64 #s(literal 3 binary64) a)) < -15

    1. Initial program 90.2%

      \[\frac{\left(-b\right) + \sqrt{b \cdot b - \left(3 \cdot a\right) \cdot c}}{3 \cdot a} \]
    2. Step-by-step derivation
      1. Simplified90.3%

        \[\leadsto \color{blue}{\frac{\sqrt{\mathsf{fma}\left(b, b, a \cdot \left(c \cdot -3\right)\right)} - b}{3 \cdot a}} \]
      2. Add Preprocessing
      3. Taylor expanded in c around inf 89.9%

        \[\leadsto \frac{\sqrt{\color{blue}{c \cdot \left(-3 \cdot a + \frac{{b}^{2}}{c}\right)}} - b}{3 \cdot a} \]
      4. Step-by-step derivation
        1. sqrt-prod89.6%

          \[\leadsto \frac{\color{blue}{\sqrt{c} \cdot \sqrt{-3 \cdot a + \frac{{b}^{2}}{c}}} - b}{3 \cdot a} \]
        2. fmm-def90.7%

          \[\leadsto \frac{\color{blue}{\mathsf{fma}\left(\sqrt{c}, \sqrt{-3 \cdot a + \frac{{b}^{2}}{c}}, -b\right)}}{3 \cdot a} \]
        3. *-commutative90.7%

          \[\leadsto \frac{\mathsf{fma}\left(\sqrt{c}, \sqrt{\color{blue}{a \cdot -3} + \frac{{b}^{2}}{c}}, -b\right)}{3 \cdot a} \]
        4. fma-define90.7%

          \[\leadsto \frac{\mathsf{fma}\left(\sqrt{c}, \sqrt{\color{blue}{\mathsf{fma}\left(a, -3, \frac{{b}^{2}}{c}\right)}}, -b\right)}{3 \cdot a} \]
      5. Applied egg-rr90.7%

        \[\leadsto \frac{\color{blue}{\mathsf{fma}\left(\sqrt{c}, \sqrt{\mathsf{fma}\left(a, -3, \frac{{b}^{2}}{c}\right)}, -b\right)}}{3 \cdot a} \]

      if -15 < (/.f64 (+.f64 (neg.f64 b) (sqrt.f64 (-.f64 (*.f64 b b) (*.f64 (*.f64 #s(literal 3 binary64) a) c)))) (*.f64 #s(literal 3 binary64) a))

      1. Initial program 53.3%

        \[\frac{\left(-b\right) + \sqrt{b \cdot b - \left(3 \cdot a\right) \cdot c}}{3 \cdot a} \]
      2. Step-by-step derivation
        1. Simplified53.3%

          \[\leadsto \color{blue}{\frac{\sqrt{\mathsf{fma}\left(b, b, a \cdot \left(c \cdot -3\right)\right)} - b}{3 \cdot a}} \]
        2. Add Preprocessing
        3. Taylor expanded in a around 0 92.5%

          \[\leadsto \color{blue}{-0.5 \cdot \frac{c}{b} + a \cdot \left(-0.375 \cdot \frac{{c}^{2}}{{b}^{3}} + a \cdot \left(-0.5625 \cdot \frac{{c}^{3}}{{b}^{5}} + -0.16666666666666666 \cdot \frac{a \cdot \left(1.265625 \cdot \frac{{c}^{4}}{{b}^{6}} + 5.0625 \cdot \frac{{c}^{4}}{{b}^{6}}\right)}{b}\right)\right)} \]
        4. Taylor expanded in c around 0 92.5%

          \[\leadsto -0.5 \cdot \frac{c}{b} + a \cdot \left(-0.375 \cdot \frac{{c}^{2}}{{b}^{3}} + a \cdot \left(-0.5625 \cdot \frac{{c}^{3}}{{b}^{5}} + \color{blue}{-1.0546875 \cdot \frac{a \cdot {c}^{4}}{{b}^{7}}}\right)\right) \]
      3. Recombined 2 regimes into one program.
      4. Final simplification92.4%

        \[\leadsto \begin{array}{l} \mathbf{if}\;\frac{\sqrt{b \cdot b - \left(3 \cdot a\right) \cdot c} - b}{3 \cdot a} \leq -15:\\ \;\;\;\;\frac{\mathsf{fma}\left(\sqrt{c}, \sqrt{\mathsf{fma}\left(a, -3, \frac{{b}^{2}}{c}\right)}, -b\right)}{3 \cdot a}\\ \mathbf{else}:\\ \;\;\;\;-0.5 \cdot \frac{c}{b} + a \cdot \left(-0.375 \cdot \frac{{c}^{2}}{{b}^{3}} + a \cdot \left(-0.5625 \cdot \frac{{c}^{3}}{{b}^{5}} + -1.0546875 \cdot \frac{a \cdot {c}^{4}}{{b}^{7}}\right)\right)\\ \end{array} \]
      5. Add Preprocessing

      Alternative 2: 92.1% accurate, 0.2× speedup?

      \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;\frac{\sqrt{b \cdot b - \left(3 \cdot a\right) \cdot c} - b}{3 \cdot a} \leq -15:\\ \;\;\;\;\frac{\mathsf{fma}\left(\sqrt{c}, \sqrt{\mathsf{fma}\left(a, -3, \frac{{b}^{2}}{c}\right)}, -b\right)}{3 \cdot a}\\ \mathbf{else}:\\ \;\;\;\;c \cdot \left(c \cdot \left(a \cdot \left(a \cdot \left(-1.0546875 \cdot \frac{a \cdot {c}^{2}}{{b}^{7}} + -0.5625 \cdot \frac{c}{{b}^{5}}\right) + 0.375 \cdot \frac{-1}{{b}^{3}}\right)\right) - \frac{0.5}{b}\right)\\ \end{array} \end{array} \]
      (FPCore (a b c)
       :precision binary64
       (if (<= (/ (- (sqrt (- (* b b) (* (* 3.0 a) c))) b) (* 3.0 a)) -15.0)
         (/ (fma (sqrt c) (sqrt (fma a -3.0 (/ (pow b 2.0) c))) (- b)) (* 3.0 a))
         (*
          c
          (-
           (*
            c
            (*
             a
             (+
              (*
               a
               (+
                (* -1.0546875 (/ (* a (pow c 2.0)) (pow b 7.0)))
                (* -0.5625 (/ c (pow b 5.0)))))
              (* 0.375 (/ -1.0 (pow b 3.0))))))
           (/ 0.5 b)))))
      double code(double a, double b, double c) {
      	double tmp;
      	if (((sqrt(((b * b) - ((3.0 * a) * c))) - b) / (3.0 * a)) <= -15.0) {
      		tmp = fma(sqrt(c), sqrt(fma(a, -3.0, (pow(b, 2.0) / c))), -b) / (3.0 * a);
      	} else {
      		tmp = c * ((c * (a * ((a * ((-1.0546875 * ((a * pow(c, 2.0)) / pow(b, 7.0))) + (-0.5625 * (c / pow(b, 5.0))))) + (0.375 * (-1.0 / pow(b, 3.0)))))) - (0.5 / b));
      	}
      	return tmp;
      }
      
      function code(a, b, c)
      	tmp = 0.0
      	if (Float64(Float64(sqrt(Float64(Float64(b * b) - Float64(Float64(3.0 * a) * c))) - b) / Float64(3.0 * a)) <= -15.0)
      		tmp = Float64(fma(sqrt(c), sqrt(fma(a, -3.0, Float64((b ^ 2.0) / c))), Float64(-b)) / Float64(3.0 * a));
      	else
      		tmp = Float64(c * Float64(Float64(c * Float64(a * Float64(Float64(a * Float64(Float64(-1.0546875 * Float64(Float64(a * (c ^ 2.0)) / (b ^ 7.0))) + Float64(-0.5625 * Float64(c / (b ^ 5.0))))) + Float64(0.375 * Float64(-1.0 / (b ^ 3.0)))))) - Float64(0.5 / b)));
      	end
      	return tmp
      end
      
      code[a_, b_, c_] := If[LessEqual[N[(N[(N[Sqrt[N[(N[(b * b), $MachinePrecision] - N[(N[(3.0 * a), $MachinePrecision] * c), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] - b), $MachinePrecision] / N[(3.0 * a), $MachinePrecision]), $MachinePrecision], -15.0], N[(N[(N[Sqrt[c], $MachinePrecision] * N[Sqrt[N[(a * -3.0 + N[(N[Power[b, 2.0], $MachinePrecision] / c), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] + (-b)), $MachinePrecision] / N[(3.0 * a), $MachinePrecision]), $MachinePrecision], N[(c * N[(N[(c * N[(a * N[(N[(a * N[(N[(-1.0546875 * N[(N[(a * N[Power[c, 2.0], $MachinePrecision]), $MachinePrecision] / N[Power[b, 7.0], $MachinePrecision]), $MachinePrecision]), $MachinePrecision] + N[(-0.5625 * N[(c / N[Power[b, 5.0], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] + N[(0.375 * N[(-1.0 / N[Power[b, 3.0], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] - N[(0.5 / b), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]]
      
      \begin{array}{l}
      
      \\
      \begin{array}{l}
      \mathbf{if}\;\frac{\sqrt{b \cdot b - \left(3 \cdot a\right) \cdot c} - b}{3 \cdot a} \leq -15:\\
      \;\;\;\;\frac{\mathsf{fma}\left(\sqrt{c}, \sqrt{\mathsf{fma}\left(a, -3, \frac{{b}^{2}}{c}\right)}, -b\right)}{3 \cdot a}\\
      
      \mathbf{else}:\\
      \;\;\;\;c \cdot \left(c \cdot \left(a \cdot \left(a \cdot \left(-1.0546875 \cdot \frac{a \cdot {c}^{2}}{{b}^{7}} + -0.5625 \cdot \frac{c}{{b}^{5}}\right) + 0.375 \cdot \frac{-1}{{b}^{3}}\right)\right) - \frac{0.5}{b}\right)\\
      
      
      \end{array}
      \end{array}
      
      Derivation
      1. Split input into 2 regimes
      2. if (/.f64 (+.f64 (neg.f64 b) (sqrt.f64 (-.f64 (*.f64 b b) (*.f64 (*.f64 #s(literal 3 binary64) a) c)))) (*.f64 #s(literal 3 binary64) a)) < -15

        1. Initial program 90.2%

          \[\frac{\left(-b\right) + \sqrt{b \cdot b - \left(3 \cdot a\right) \cdot c}}{3 \cdot a} \]
        2. Step-by-step derivation
          1. Simplified90.3%

            \[\leadsto \color{blue}{\frac{\sqrt{\mathsf{fma}\left(b, b, a \cdot \left(c \cdot -3\right)\right)} - b}{3 \cdot a}} \]
          2. Add Preprocessing
          3. Taylor expanded in c around inf 89.9%

            \[\leadsto \frac{\sqrt{\color{blue}{c \cdot \left(-3 \cdot a + \frac{{b}^{2}}{c}\right)}} - b}{3 \cdot a} \]
          4. Step-by-step derivation
            1. sqrt-prod89.6%

              \[\leadsto \frac{\color{blue}{\sqrt{c} \cdot \sqrt{-3 \cdot a + \frac{{b}^{2}}{c}}} - b}{3 \cdot a} \]
            2. fmm-def90.7%

              \[\leadsto \frac{\color{blue}{\mathsf{fma}\left(\sqrt{c}, \sqrt{-3 \cdot a + \frac{{b}^{2}}{c}}, -b\right)}}{3 \cdot a} \]
            3. *-commutative90.7%

              \[\leadsto \frac{\mathsf{fma}\left(\sqrt{c}, \sqrt{\color{blue}{a \cdot -3} + \frac{{b}^{2}}{c}}, -b\right)}{3 \cdot a} \]
            4. fma-define90.7%

              \[\leadsto \frac{\mathsf{fma}\left(\sqrt{c}, \sqrt{\color{blue}{\mathsf{fma}\left(a, -3, \frac{{b}^{2}}{c}\right)}}, -b\right)}{3 \cdot a} \]
          5. Applied egg-rr90.7%

            \[\leadsto \frac{\color{blue}{\mathsf{fma}\left(\sqrt{c}, \sqrt{\mathsf{fma}\left(a, -3, \frac{{b}^{2}}{c}\right)}, -b\right)}}{3 \cdot a} \]

          if -15 < (/.f64 (+.f64 (neg.f64 b) (sqrt.f64 (-.f64 (*.f64 b b) (*.f64 (*.f64 #s(literal 3 binary64) a) c)))) (*.f64 #s(literal 3 binary64) a))

          1. Initial program 53.3%

            \[\frac{\left(-b\right) + \sqrt{b \cdot b - \left(3 \cdot a\right) \cdot c}}{3 \cdot a} \]
          2. Step-by-step derivation
            1. Simplified53.3%

              \[\leadsto \color{blue}{\frac{\sqrt{\mathsf{fma}\left(b, b, a \cdot \left(c \cdot -3\right)\right)} - b}{3 \cdot a}} \]
            2. Add Preprocessing
            3. Taylor expanded in c around 0 92.3%

              \[\leadsto \color{blue}{c \cdot \left(c \cdot \left(-0.375 \cdot \frac{a}{{b}^{3}} + c \cdot \left(-0.5625 \cdot \frac{{a}^{2}}{{b}^{5}} + -0.16666666666666666 \cdot \frac{c \cdot \left(1.265625 \cdot \frac{{a}^{4}}{{b}^{6}} + 5.0625 \cdot \frac{{a}^{4}}{{b}^{6}}\right)}{a \cdot b}\right)\right) - 0.5 \cdot \frac{1}{b}\right)} \]
            4. Step-by-step derivation
              1. Simplified92.3%

                \[\leadsto \color{blue}{c \cdot \left(c \cdot \mathsf{fma}\left(-0.375, \frac{a}{{b}^{3}}, c \cdot \mathsf{fma}\left(-0.5625, \frac{{a}^{2}}{{b}^{5}}, -0.16666666666666666 \cdot \left(c \cdot \frac{\frac{{a}^{4}}{{b}^{6}} \cdot 6.328125}{b \cdot a}\right)\right)\right) - \frac{0.5}{b}\right)} \]
              2. Taylor expanded in a around 0 92.3%

                \[\leadsto c \cdot \left(c \cdot \color{blue}{\left(a \cdot \left(a \cdot \left(-1.0546875 \cdot \frac{a \cdot {c}^{2}}{{b}^{7}} + -0.5625 \cdot \frac{c}{{b}^{5}}\right) - 0.375 \cdot \frac{1}{{b}^{3}}\right)\right)} - \frac{0.5}{b}\right) \]
            5. Recombined 2 regimes into one program.
            6. Final simplification92.2%

              \[\leadsto \begin{array}{l} \mathbf{if}\;\frac{\sqrt{b \cdot b - \left(3 \cdot a\right) \cdot c} - b}{3 \cdot a} \leq -15:\\ \;\;\;\;\frac{\mathsf{fma}\left(\sqrt{c}, \sqrt{\mathsf{fma}\left(a, -3, \frac{{b}^{2}}{c}\right)}, -b\right)}{3 \cdot a}\\ \mathbf{else}:\\ \;\;\;\;c \cdot \left(c \cdot \left(a \cdot \left(a \cdot \left(-1.0546875 \cdot \frac{a \cdot {c}^{2}}{{b}^{7}} + -0.5625 \cdot \frac{c}{{b}^{5}}\right) + 0.375 \cdot \frac{-1}{{b}^{3}}\right)\right) - \frac{0.5}{b}\right)\\ \end{array} \]
            7. Add Preprocessing

            Alternative 3: 92.2% accurate, 0.2× speedup?

            \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;\frac{\sqrt{b \cdot b - \left(3 \cdot a\right) \cdot c} - b}{3 \cdot a} \leq -15:\\ \;\;\;\;\frac{\sqrt{b \cdot b - 3 \cdot \left(a \cdot c\right)} - b}{3 \cdot a}\\ \mathbf{else}:\\ \;\;\;\;c \cdot \left(c \cdot \left(a \cdot \left(a \cdot \left(-1.0546875 \cdot \frac{a \cdot {c}^{2}}{{b}^{7}} + -0.5625 \cdot \frac{c}{{b}^{5}}\right) + 0.375 \cdot \frac{-1}{{b}^{3}}\right)\right) - \frac{0.5}{b}\right)\\ \end{array} \end{array} \]
            (FPCore (a b c)
             :precision binary64
             (if (<= (/ (- (sqrt (- (* b b) (* (* 3.0 a) c))) b) (* 3.0 a)) -15.0)
               (/ (- (sqrt (- (* b b) (* 3.0 (* a c)))) b) (* 3.0 a))
               (*
                c
                (-
                 (*
                  c
                  (*
                   a
                   (+
                    (*
                     a
                     (+
                      (* -1.0546875 (/ (* a (pow c 2.0)) (pow b 7.0)))
                      (* -0.5625 (/ c (pow b 5.0)))))
                    (* 0.375 (/ -1.0 (pow b 3.0))))))
                 (/ 0.5 b)))))
            double code(double a, double b, double c) {
            	double tmp;
            	if (((sqrt(((b * b) - ((3.0 * a) * c))) - b) / (3.0 * a)) <= -15.0) {
            		tmp = (sqrt(((b * b) - (3.0 * (a * c)))) - b) / (3.0 * a);
            	} else {
            		tmp = c * ((c * (a * ((a * ((-1.0546875 * ((a * pow(c, 2.0)) / pow(b, 7.0))) + (-0.5625 * (c / pow(b, 5.0))))) + (0.375 * (-1.0 / pow(b, 3.0)))))) - (0.5 / b));
            	}
            	return tmp;
            }
            
            real(8) function code(a, b, c)
                real(8), intent (in) :: a
                real(8), intent (in) :: b
                real(8), intent (in) :: c
                real(8) :: tmp
                if (((sqrt(((b * b) - ((3.0d0 * a) * c))) - b) / (3.0d0 * a)) <= (-15.0d0)) then
                    tmp = (sqrt(((b * b) - (3.0d0 * (a * c)))) - b) / (3.0d0 * a)
                else
                    tmp = c * ((c * (a * ((a * (((-1.0546875d0) * ((a * (c ** 2.0d0)) / (b ** 7.0d0))) + ((-0.5625d0) * (c / (b ** 5.0d0))))) + (0.375d0 * ((-1.0d0) / (b ** 3.0d0)))))) - (0.5d0 / b))
                end if
                code = tmp
            end function
            
            public static double code(double a, double b, double c) {
            	double tmp;
            	if (((Math.sqrt(((b * b) - ((3.0 * a) * c))) - b) / (3.0 * a)) <= -15.0) {
            		tmp = (Math.sqrt(((b * b) - (3.0 * (a * c)))) - b) / (3.0 * a);
            	} else {
            		tmp = c * ((c * (a * ((a * ((-1.0546875 * ((a * Math.pow(c, 2.0)) / Math.pow(b, 7.0))) + (-0.5625 * (c / Math.pow(b, 5.0))))) + (0.375 * (-1.0 / Math.pow(b, 3.0)))))) - (0.5 / b));
            	}
            	return tmp;
            }
            
            def code(a, b, c):
            	tmp = 0
            	if ((math.sqrt(((b * b) - ((3.0 * a) * c))) - b) / (3.0 * a)) <= -15.0:
            		tmp = (math.sqrt(((b * b) - (3.0 * (a * c)))) - b) / (3.0 * a)
            	else:
            		tmp = c * ((c * (a * ((a * ((-1.0546875 * ((a * math.pow(c, 2.0)) / math.pow(b, 7.0))) + (-0.5625 * (c / math.pow(b, 5.0))))) + (0.375 * (-1.0 / math.pow(b, 3.0)))))) - (0.5 / b))
            	return tmp
            
            function code(a, b, c)
            	tmp = 0.0
            	if (Float64(Float64(sqrt(Float64(Float64(b * b) - Float64(Float64(3.0 * a) * c))) - b) / Float64(3.0 * a)) <= -15.0)
            		tmp = Float64(Float64(sqrt(Float64(Float64(b * b) - Float64(3.0 * Float64(a * c)))) - b) / Float64(3.0 * a));
            	else
            		tmp = Float64(c * Float64(Float64(c * Float64(a * Float64(Float64(a * Float64(Float64(-1.0546875 * Float64(Float64(a * (c ^ 2.0)) / (b ^ 7.0))) + Float64(-0.5625 * Float64(c / (b ^ 5.0))))) + Float64(0.375 * Float64(-1.0 / (b ^ 3.0)))))) - Float64(0.5 / b)));
            	end
            	return tmp
            end
            
            function tmp_2 = code(a, b, c)
            	tmp = 0.0;
            	if (((sqrt(((b * b) - ((3.0 * a) * c))) - b) / (3.0 * a)) <= -15.0)
            		tmp = (sqrt(((b * b) - (3.0 * (a * c)))) - b) / (3.0 * a);
            	else
            		tmp = c * ((c * (a * ((a * ((-1.0546875 * ((a * (c ^ 2.0)) / (b ^ 7.0))) + (-0.5625 * (c / (b ^ 5.0))))) + (0.375 * (-1.0 / (b ^ 3.0)))))) - (0.5 / b));
            	end
            	tmp_2 = tmp;
            end
            
            code[a_, b_, c_] := If[LessEqual[N[(N[(N[Sqrt[N[(N[(b * b), $MachinePrecision] - N[(N[(3.0 * a), $MachinePrecision] * c), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] - b), $MachinePrecision] / N[(3.0 * a), $MachinePrecision]), $MachinePrecision], -15.0], N[(N[(N[Sqrt[N[(N[(b * b), $MachinePrecision] - N[(3.0 * N[(a * c), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] - b), $MachinePrecision] / N[(3.0 * a), $MachinePrecision]), $MachinePrecision], N[(c * N[(N[(c * N[(a * N[(N[(a * N[(N[(-1.0546875 * N[(N[(a * N[Power[c, 2.0], $MachinePrecision]), $MachinePrecision] / N[Power[b, 7.0], $MachinePrecision]), $MachinePrecision]), $MachinePrecision] + N[(-0.5625 * N[(c / N[Power[b, 5.0], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] + N[(0.375 * N[(-1.0 / N[Power[b, 3.0], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] - N[(0.5 / b), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]]
            
            \begin{array}{l}
            
            \\
            \begin{array}{l}
            \mathbf{if}\;\frac{\sqrt{b \cdot b - \left(3 \cdot a\right) \cdot c} - b}{3 \cdot a} \leq -15:\\
            \;\;\;\;\frac{\sqrt{b \cdot b - 3 \cdot \left(a \cdot c\right)} - b}{3 \cdot a}\\
            
            \mathbf{else}:\\
            \;\;\;\;c \cdot \left(c \cdot \left(a \cdot \left(a \cdot \left(-1.0546875 \cdot \frac{a \cdot {c}^{2}}{{b}^{7}} + -0.5625 \cdot \frac{c}{{b}^{5}}\right) + 0.375 \cdot \frac{-1}{{b}^{3}}\right)\right) - \frac{0.5}{b}\right)\\
            
            
            \end{array}
            \end{array}
            
            Derivation
            1. Split input into 2 regimes
            2. if (/.f64 (+.f64 (neg.f64 b) (sqrt.f64 (-.f64 (*.f64 b b) (*.f64 (*.f64 #s(literal 3 binary64) a) c)))) (*.f64 #s(literal 3 binary64) a)) < -15

              1. Initial program 90.2%

                \[\frac{\left(-b\right) + \sqrt{b \cdot b - \left(3 \cdot a\right) \cdot c}}{3 \cdot a} \]
              2. Step-by-step derivation
                1. sqr-neg90.2%

                  \[\leadsto \frac{\left(-b\right) + \sqrt{\color{blue}{\left(-b\right) \cdot \left(-b\right)} - \left(3 \cdot a\right) \cdot c}}{3 \cdot a} \]
                2. sqr-neg90.2%

                  \[\leadsto \frac{\left(-b\right) + \sqrt{\color{blue}{b \cdot b} - \left(3 \cdot a\right) \cdot c}}{3 \cdot a} \]
                3. associate-*l*90.3%

                  \[\leadsto \frac{\left(-b\right) + \sqrt{b \cdot b - \color{blue}{3 \cdot \left(a \cdot c\right)}}}{3 \cdot a} \]
              3. Simplified90.3%

                \[\leadsto \color{blue}{\frac{\left(-b\right) + \sqrt{b \cdot b - 3 \cdot \left(a \cdot c\right)}}{3 \cdot a}} \]
              4. Add Preprocessing

              if -15 < (/.f64 (+.f64 (neg.f64 b) (sqrt.f64 (-.f64 (*.f64 b b) (*.f64 (*.f64 #s(literal 3 binary64) a) c)))) (*.f64 #s(literal 3 binary64) a))

              1. Initial program 53.3%

                \[\frac{\left(-b\right) + \sqrt{b \cdot b - \left(3 \cdot a\right) \cdot c}}{3 \cdot a} \]
              2. Step-by-step derivation
                1. Simplified53.3%

                  \[\leadsto \color{blue}{\frac{\sqrt{\mathsf{fma}\left(b, b, a \cdot \left(c \cdot -3\right)\right)} - b}{3 \cdot a}} \]
                2. Add Preprocessing
                3. Taylor expanded in c around 0 92.3%

                  \[\leadsto \color{blue}{c \cdot \left(c \cdot \left(-0.375 \cdot \frac{a}{{b}^{3}} + c \cdot \left(-0.5625 \cdot \frac{{a}^{2}}{{b}^{5}} + -0.16666666666666666 \cdot \frac{c \cdot \left(1.265625 \cdot \frac{{a}^{4}}{{b}^{6}} + 5.0625 \cdot \frac{{a}^{4}}{{b}^{6}}\right)}{a \cdot b}\right)\right) - 0.5 \cdot \frac{1}{b}\right)} \]
                4. Step-by-step derivation
                  1. Simplified92.3%

                    \[\leadsto \color{blue}{c \cdot \left(c \cdot \mathsf{fma}\left(-0.375, \frac{a}{{b}^{3}}, c \cdot \mathsf{fma}\left(-0.5625, \frac{{a}^{2}}{{b}^{5}}, -0.16666666666666666 \cdot \left(c \cdot \frac{\frac{{a}^{4}}{{b}^{6}} \cdot 6.328125}{b \cdot a}\right)\right)\right) - \frac{0.5}{b}\right)} \]
                  2. Taylor expanded in a around 0 92.3%

                    \[\leadsto c \cdot \left(c \cdot \color{blue}{\left(a \cdot \left(a \cdot \left(-1.0546875 \cdot \frac{a \cdot {c}^{2}}{{b}^{7}} + -0.5625 \cdot \frac{c}{{b}^{5}}\right) - 0.375 \cdot \frac{1}{{b}^{3}}\right)\right)} - \frac{0.5}{b}\right) \]
                5. Recombined 2 regimes into one program.
                6. Final simplification92.2%

                  \[\leadsto \begin{array}{l} \mathbf{if}\;\frac{\sqrt{b \cdot b - \left(3 \cdot a\right) \cdot c} - b}{3 \cdot a} \leq -15:\\ \;\;\;\;\frac{\sqrt{b \cdot b - 3 \cdot \left(a \cdot c\right)} - b}{3 \cdot a}\\ \mathbf{else}:\\ \;\;\;\;c \cdot \left(c \cdot \left(a \cdot \left(a \cdot \left(-1.0546875 \cdot \frac{a \cdot {c}^{2}}{{b}^{7}} + -0.5625 \cdot \frac{c}{{b}^{5}}\right) + 0.375 \cdot \frac{-1}{{b}^{3}}\right)\right) - \frac{0.5}{b}\right)\\ \end{array} \]
                7. Add Preprocessing

                Alternative 4: 89.8% accurate, 0.2× speedup?

                \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;\frac{\sqrt{b \cdot b - \left(3 \cdot a\right) \cdot c} - b}{3 \cdot a} \leq -15:\\ \;\;\;\;\frac{\sqrt{b \cdot b - 3 \cdot \left(a \cdot c\right)} - b}{3 \cdot a}\\ \mathbf{else}:\\ \;\;\;\;-0.5 \cdot \frac{c}{b} + a \cdot \left(-0.375 \cdot \frac{{c}^{2}}{{b}^{3}} + -0.5625 \cdot \frac{a \cdot {c}^{3}}{{b}^{5}}\right)\\ \end{array} \end{array} \]
                (FPCore (a b c)
                 :precision binary64
                 (if (<= (/ (- (sqrt (- (* b b) (* (* 3.0 a) c))) b) (* 3.0 a)) -15.0)
                   (/ (- (sqrt (- (* b b) (* 3.0 (* a c)))) b) (* 3.0 a))
                   (+
                    (* -0.5 (/ c b))
                    (*
                     a
                     (+
                      (* -0.375 (/ (pow c 2.0) (pow b 3.0)))
                      (* -0.5625 (/ (* a (pow c 3.0)) (pow b 5.0))))))))
                double code(double a, double b, double c) {
                	double tmp;
                	if (((sqrt(((b * b) - ((3.0 * a) * c))) - b) / (3.0 * a)) <= -15.0) {
                		tmp = (sqrt(((b * b) - (3.0 * (a * c)))) - b) / (3.0 * a);
                	} else {
                		tmp = (-0.5 * (c / b)) + (a * ((-0.375 * (pow(c, 2.0) / pow(b, 3.0))) + (-0.5625 * ((a * pow(c, 3.0)) / pow(b, 5.0)))));
                	}
                	return tmp;
                }
                
                real(8) function code(a, b, c)
                    real(8), intent (in) :: a
                    real(8), intent (in) :: b
                    real(8), intent (in) :: c
                    real(8) :: tmp
                    if (((sqrt(((b * b) - ((3.0d0 * a) * c))) - b) / (3.0d0 * a)) <= (-15.0d0)) then
                        tmp = (sqrt(((b * b) - (3.0d0 * (a * c)))) - b) / (3.0d0 * a)
                    else
                        tmp = ((-0.5d0) * (c / b)) + (a * (((-0.375d0) * ((c ** 2.0d0) / (b ** 3.0d0))) + ((-0.5625d0) * ((a * (c ** 3.0d0)) / (b ** 5.0d0)))))
                    end if
                    code = tmp
                end function
                
                public static double code(double a, double b, double c) {
                	double tmp;
                	if (((Math.sqrt(((b * b) - ((3.0 * a) * c))) - b) / (3.0 * a)) <= -15.0) {
                		tmp = (Math.sqrt(((b * b) - (3.0 * (a * c)))) - b) / (3.0 * a);
                	} else {
                		tmp = (-0.5 * (c / b)) + (a * ((-0.375 * (Math.pow(c, 2.0) / Math.pow(b, 3.0))) + (-0.5625 * ((a * Math.pow(c, 3.0)) / Math.pow(b, 5.0)))));
                	}
                	return tmp;
                }
                
                def code(a, b, c):
                	tmp = 0
                	if ((math.sqrt(((b * b) - ((3.0 * a) * c))) - b) / (3.0 * a)) <= -15.0:
                		tmp = (math.sqrt(((b * b) - (3.0 * (a * c)))) - b) / (3.0 * a)
                	else:
                		tmp = (-0.5 * (c / b)) + (a * ((-0.375 * (math.pow(c, 2.0) / math.pow(b, 3.0))) + (-0.5625 * ((a * math.pow(c, 3.0)) / math.pow(b, 5.0)))))
                	return tmp
                
                function code(a, b, c)
                	tmp = 0.0
                	if (Float64(Float64(sqrt(Float64(Float64(b * b) - Float64(Float64(3.0 * a) * c))) - b) / Float64(3.0 * a)) <= -15.0)
                		tmp = Float64(Float64(sqrt(Float64(Float64(b * b) - Float64(3.0 * Float64(a * c)))) - b) / Float64(3.0 * a));
                	else
                		tmp = Float64(Float64(-0.5 * Float64(c / b)) + Float64(a * Float64(Float64(-0.375 * Float64((c ^ 2.0) / (b ^ 3.0))) + Float64(-0.5625 * Float64(Float64(a * (c ^ 3.0)) / (b ^ 5.0))))));
                	end
                	return tmp
                end
                
                function tmp_2 = code(a, b, c)
                	tmp = 0.0;
                	if (((sqrt(((b * b) - ((3.0 * a) * c))) - b) / (3.0 * a)) <= -15.0)
                		tmp = (sqrt(((b * b) - (3.0 * (a * c)))) - b) / (3.0 * a);
                	else
                		tmp = (-0.5 * (c / b)) + (a * ((-0.375 * ((c ^ 2.0) / (b ^ 3.0))) + (-0.5625 * ((a * (c ^ 3.0)) / (b ^ 5.0)))));
                	end
                	tmp_2 = tmp;
                end
                
                code[a_, b_, c_] := If[LessEqual[N[(N[(N[Sqrt[N[(N[(b * b), $MachinePrecision] - N[(N[(3.0 * a), $MachinePrecision] * c), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] - b), $MachinePrecision] / N[(3.0 * a), $MachinePrecision]), $MachinePrecision], -15.0], N[(N[(N[Sqrt[N[(N[(b * b), $MachinePrecision] - N[(3.0 * N[(a * c), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] - b), $MachinePrecision] / N[(3.0 * a), $MachinePrecision]), $MachinePrecision], N[(N[(-0.5 * N[(c / b), $MachinePrecision]), $MachinePrecision] + N[(a * N[(N[(-0.375 * N[(N[Power[c, 2.0], $MachinePrecision] / N[Power[b, 3.0], $MachinePrecision]), $MachinePrecision]), $MachinePrecision] + N[(-0.5625 * N[(N[(a * N[Power[c, 3.0], $MachinePrecision]), $MachinePrecision] / N[Power[b, 5.0], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]]
                
                \begin{array}{l}
                
                \\
                \begin{array}{l}
                \mathbf{if}\;\frac{\sqrt{b \cdot b - \left(3 \cdot a\right) \cdot c} - b}{3 \cdot a} \leq -15:\\
                \;\;\;\;\frac{\sqrt{b \cdot b - 3 \cdot \left(a \cdot c\right)} - b}{3 \cdot a}\\
                
                \mathbf{else}:\\
                \;\;\;\;-0.5 \cdot \frac{c}{b} + a \cdot \left(-0.375 \cdot \frac{{c}^{2}}{{b}^{3}} + -0.5625 \cdot \frac{a \cdot {c}^{3}}{{b}^{5}}\right)\\
                
                
                \end{array}
                \end{array}
                
                Derivation
                1. Split input into 2 regimes
                2. if (/.f64 (+.f64 (neg.f64 b) (sqrt.f64 (-.f64 (*.f64 b b) (*.f64 (*.f64 #s(literal 3 binary64) a) c)))) (*.f64 #s(literal 3 binary64) a)) < -15

                  1. Initial program 90.2%

                    \[\frac{\left(-b\right) + \sqrt{b \cdot b - \left(3 \cdot a\right) \cdot c}}{3 \cdot a} \]
                  2. Step-by-step derivation
                    1. sqr-neg90.2%

                      \[\leadsto \frac{\left(-b\right) + \sqrt{\color{blue}{\left(-b\right) \cdot \left(-b\right)} - \left(3 \cdot a\right) \cdot c}}{3 \cdot a} \]
                    2. sqr-neg90.2%

                      \[\leadsto \frac{\left(-b\right) + \sqrt{\color{blue}{b \cdot b} - \left(3 \cdot a\right) \cdot c}}{3 \cdot a} \]
                    3. associate-*l*90.3%

                      \[\leadsto \frac{\left(-b\right) + \sqrt{b \cdot b - \color{blue}{3 \cdot \left(a \cdot c\right)}}}{3 \cdot a} \]
                  3. Simplified90.3%

                    \[\leadsto \color{blue}{\frac{\left(-b\right) + \sqrt{b \cdot b - 3 \cdot \left(a \cdot c\right)}}{3 \cdot a}} \]
                  4. Add Preprocessing

                  if -15 < (/.f64 (+.f64 (neg.f64 b) (sqrt.f64 (-.f64 (*.f64 b b) (*.f64 (*.f64 #s(literal 3 binary64) a) c)))) (*.f64 #s(literal 3 binary64) a))

                  1. Initial program 53.3%

                    \[\frac{\left(-b\right) + \sqrt{b \cdot b - \left(3 \cdot a\right) \cdot c}}{3 \cdot a} \]
                  2. Step-by-step derivation
                    1. Simplified53.3%

                      \[\leadsto \color{blue}{\frac{\sqrt{\mathsf{fma}\left(b, b, a \cdot \left(c \cdot -3\right)\right)} - b}{3 \cdot a}} \]
                    2. Add Preprocessing
                    3. Taylor expanded in a around 0 89.7%

                      \[\leadsto \color{blue}{-0.5 \cdot \frac{c}{b} + a \cdot \left(-0.5625 \cdot \frac{a \cdot {c}^{3}}{{b}^{5}} + -0.375 \cdot \frac{{c}^{2}}{{b}^{3}}\right)} \]
                  3. Recombined 2 regimes into one program.
                  4. Final simplification89.8%

                    \[\leadsto \begin{array}{l} \mathbf{if}\;\frac{\sqrt{b \cdot b - \left(3 \cdot a\right) \cdot c} - b}{3 \cdot a} \leq -15:\\ \;\;\;\;\frac{\sqrt{b \cdot b - 3 \cdot \left(a \cdot c\right)} - b}{3 \cdot a}\\ \mathbf{else}:\\ \;\;\;\;-0.5 \cdot \frac{c}{b} + a \cdot \left(-0.375 \cdot \frac{{c}^{2}}{{b}^{3}} + -0.5625 \cdot \frac{a \cdot {c}^{3}}{{b}^{5}}\right)\\ \end{array} \]
                  5. Add Preprocessing

                  Alternative 5: 89.7% accurate, 0.3× speedup?

                  \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;\frac{\sqrt{b \cdot b - \left(3 \cdot a\right) \cdot c} - b}{3 \cdot a} \leq -15:\\ \;\;\;\;\frac{\sqrt{b \cdot b - 3 \cdot \left(a \cdot c\right)} - b}{3 \cdot a}\\ \mathbf{else}:\\ \;\;\;\;c \cdot \left(c \cdot \left(a \cdot \left(\frac{-0.5625 \cdot \left(a \cdot c\right)}{{b}^{5}} - \frac{0.375}{{b}^{3}}\right)\right) - \frac{0.5}{b}\right)\\ \end{array} \end{array} \]
                  (FPCore (a b c)
                   :precision binary64
                   (if (<= (/ (- (sqrt (- (* b b) (* (* 3.0 a) c))) b) (* 3.0 a)) -15.0)
                     (/ (- (sqrt (- (* b b) (* 3.0 (* a c)))) b) (* 3.0 a))
                     (*
                      c
                      (-
                       (* c (* a (- (/ (* -0.5625 (* a c)) (pow b 5.0)) (/ 0.375 (pow b 3.0)))))
                       (/ 0.5 b)))))
                  double code(double a, double b, double c) {
                  	double tmp;
                  	if (((sqrt(((b * b) - ((3.0 * a) * c))) - b) / (3.0 * a)) <= -15.0) {
                  		tmp = (sqrt(((b * b) - (3.0 * (a * c)))) - b) / (3.0 * a);
                  	} else {
                  		tmp = c * ((c * (a * (((-0.5625 * (a * c)) / pow(b, 5.0)) - (0.375 / pow(b, 3.0))))) - (0.5 / b));
                  	}
                  	return tmp;
                  }
                  
                  real(8) function code(a, b, c)
                      real(8), intent (in) :: a
                      real(8), intent (in) :: b
                      real(8), intent (in) :: c
                      real(8) :: tmp
                      if (((sqrt(((b * b) - ((3.0d0 * a) * c))) - b) / (3.0d0 * a)) <= (-15.0d0)) then
                          tmp = (sqrt(((b * b) - (3.0d0 * (a * c)))) - b) / (3.0d0 * a)
                      else
                          tmp = c * ((c * (a * ((((-0.5625d0) * (a * c)) / (b ** 5.0d0)) - (0.375d0 / (b ** 3.0d0))))) - (0.5d0 / b))
                      end if
                      code = tmp
                  end function
                  
                  public static double code(double a, double b, double c) {
                  	double tmp;
                  	if (((Math.sqrt(((b * b) - ((3.0 * a) * c))) - b) / (3.0 * a)) <= -15.0) {
                  		tmp = (Math.sqrt(((b * b) - (3.0 * (a * c)))) - b) / (3.0 * a);
                  	} else {
                  		tmp = c * ((c * (a * (((-0.5625 * (a * c)) / Math.pow(b, 5.0)) - (0.375 / Math.pow(b, 3.0))))) - (0.5 / b));
                  	}
                  	return tmp;
                  }
                  
                  def code(a, b, c):
                  	tmp = 0
                  	if ((math.sqrt(((b * b) - ((3.0 * a) * c))) - b) / (3.0 * a)) <= -15.0:
                  		tmp = (math.sqrt(((b * b) - (3.0 * (a * c)))) - b) / (3.0 * a)
                  	else:
                  		tmp = c * ((c * (a * (((-0.5625 * (a * c)) / math.pow(b, 5.0)) - (0.375 / math.pow(b, 3.0))))) - (0.5 / b))
                  	return tmp
                  
                  function code(a, b, c)
                  	tmp = 0.0
                  	if (Float64(Float64(sqrt(Float64(Float64(b * b) - Float64(Float64(3.0 * a) * c))) - b) / Float64(3.0 * a)) <= -15.0)
                  		tmp = Float64(Float64(sqrt(Float64(Float64(b * b) - Float64(3.0 * Float64(a * c)))) - b) / Float64(3.0 * a));
                  	else
                  		tmp = Float64(c * Float64(Float64(c * Float64(a * Float64(Float64(Float64(-0.5625 * Float64(a * c)) / (b ^ 5.0)) - Float64(0.375 / (b ^ 3.0))))) - Float64(0.5 / b)));
                  	end
                  	return tmp
                  end
                  
                  function tmp_2 = code(a, b, c)
                  	tmp = 0.0;
                  	if (((sqrt(((b * b) - ((3.0 * a) * c))) - b) / (3.0 * a)) <= -15.0)
                  		tmp = (sqrt(((b * b) - (3.0 * (a * c)))) - b) / (3.0 * a);
                  	else
                  		tmp = c * ((c * (a * (((-0.5625 * (a * c)) / (b ^ 5.0)) - (0.375 / (b ^ 3.0))))) - (0.5 / b));
                  	end
                  	tmp_2 = tmp;
                  end
                  
                  code[a_, b_, c_] := If[LessEqual[N[(N[(N[Sqrt[N[(N[(b * b), $MachinePrecision] - N[(N[(3.0 * a), $MachinePrecision] * c), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] - b), $MachinePrecision] / N[(3.0 * a), $MachinePrecision]), $MachinePrecision], -15.0], N[(N[(N[Sqrt[N[(N[(b * b), $MachinePrecision] - N[(3.0 * N[(a * c), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] - b), $MachinePrecision] / N[(3.0 * a), $MachinePrecision]), $MachinePrecision], N[(c * N[(N[(c * N[(a * N[(N[(N[(-0.5625 * N[(a * c), $MachinePrecision]), $MachinePrecision] / N[Power[b, 5.0], $MachinePrecision]), $MachinePrecision] - N[(0.375 / N[Power[b, 3.0], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] - N[(0.5 / b), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]]
                  
                  \begin{array}{l}
                  
                  \\
                  \begin{array}{l}
                  \mathbf{if}\;\frac{\sqrt{b \cdot b - \left(3 \cdot a\right) \cdot c} - b}{3 \cdot a} \leq -15:\\
                  \;\;\;\;\frac{\sqrt{b \cdot b - 3 \cdot \left(a \cdot c\right)} - b}{3 \cdot a}\\
                  
                  \mathbf{else}:\\
                  \;\;\;\;c \cdot \left(c \cdot \left(a \cdot \left(\frac{-0.5625 \cdot \left(a \cdot c\right)}{{b}^{5}} - \frac{0.375}{{b}^{3}}\right)\right) - \frac{0.5}{b}\right)\\
                  
                  
                  \end{array}
                  \end{array}
                  
                  Derivation
                  1. Split input into 2 regimes
                  2. if (/.f64 (+.f64 (neg.f64 b) (sqrt.f64 (-.f64 (*.f64 b b) (*.f64 (*.f64 #s(literal 3 binary64) a) c)))) (*.f64 #s(literal 3 binary64) a)) < -15

                    1. Initial program 90.2%

                      \[\frac{\left(-b\right) + \sqrt{b \cdot b - \left(3 \cdot a\right) \cdot c}}{3 \cdot a} \]
                    2. Step-by-step derivation
                      1. sqr-neg90.2%

                        \[\leadsto \frac{\left(-b\right) + \sqrt{\color{blue}{\left(-b\right) \cdot \left(-b\right)} - \left(3 \cdot a\right) \cdot c}}{3 \cdot a} \]
                      2. sqr-neg90.2%

                        \[\leadsto \frac{\left(-b\right) + \sqrt{\color{blue}{b \cdot b} - \left(3 \cdot a\right) \cdot c}}{3 \cdot a} \]
                      3. associate-*l*90.3%

                        \[\leadsto \frac{\left(-b\right) + \sqrt{b \cdot b - \color{blue}{3 \cdot \left(a \cdot c\right)}}}{3 \cdot a} \]
                    3. Simplified90.3%

                      \[\leadsto \color{blue}{\frac{\left(-b\right) + \sqrt{b \cdot b - 3 \cdot \left(a \cdot c\right)}}{3 \cdot a}} \]
                    4. Add Preprocessing

                    if -15 < (/.f64 (+.f64 (neg.f64 b) (sqrt.f64 (-.f64 (*.f64 b b) (*.f64 (*.f64 #s(literal 3 binary64) a) c)))) (*.f64 #s(literal 3 binary64) a))

                    1. Initial program 53.3%

                      \[\frac{\left(-b\right) + \sqrt{b \cdot b - \left(3 \cdot a\right) \cdot c}}{3 \cdot a} \]
                    2. Step-by-step derivation
                      1. Simplified53.3%

                        \[\leadsto \color{blue}{\frac{\sqrt{\mathsf{fma}\left(b, b, a \cdot \left(c \cdot -3\right)\right)} - b}{3 \cdot a}} \]
                      2. Add Preprocessing
                      3. Taylor expanded in c around 0 92.3%

                        \[\leadsto \color{blue}{c \cdot \left(c \cdot \left(-0.375 \cdot \frac{a}{{b}^{3}} + c \cdot \left(-0.5625 \cdot \frac{{a}^{2}}{{b}^{5}} + -0.16666666666666666 \cdot \frac{c \cdot \left(1.265625 \cdot \frac{{a}^{4}}{{b}^{6}} + 5.0625 \cdot \frac{{a}^{4}}{{b}^{6}}\right)}{a \cdot b}\right)\right) - 0.5 \cdot \frac{1}{b}\right)} \]
                      4. Step-by-step derivation
                        1. Simplified92.3%

                          \[\leadsto \color{blue}{c \cdot \left(c \cdot \mathsf{fma}\left(-0.375, \frac{a}{{b}^{3}}, c \cdot \mathsf{fma}\left(-0.5625, \frac{{a}^{2}}{{b}^{5}}, -0.16666666666666666 \cdot \left(c \cdot \frac{\frac{{a}^{4}}{{b}^{6}} \cdot 6.328125}{b \cdot a}\right)\right)\right) - \frac{0.5}{b}\right)} \]
                        2. Taylor expanded in a around 0 89.5%

                          \[\leadsto c \cdot \left(c \cdot \color{blue}{\left(a \cdot \left(-0.5625 \cdot \frac{a \cdot c}{{b}^{5}} - 0.375 \cdot \frac{1}{{b}^{3}}\right)\right)} - \frac{0.5}{b}\right) \]
                        3. Step-by-step derivation
                          1. associate-*r/89.5%

                            \[\leadsto c \cdot \left(c \cdot \left(a \cdot \left(\color{blue}{\frac{-0.5625 \cdot \left(a \cdot c\right)}{{b}^{5}}} - 0.375 \cdot \frac{1}{{b}^{3}}\right)\right) - \frac{0.5}{b}\right) \]
                          2. associate-*r/89.5%

                            \[\leadsto c \cdot \left(c \cdot \left(a \cdot \left(\frac{-0.5625 \cdot \left(a \cdot c\right)}{{b}^{5}} - \color{blue}{\frac{0.375 \cdot 1}{{b}^{3}}}\right)\right) - \frac{0.5}{b}\right) \]
                          3. metadata-eval89.5%

                            \[\leadsto c \cdot \left(c \cdot \left(a \cdot \left(\frac{-0.5625 \cdot \left(a \cdot c\right)}{{b}^{5}} - \frac{\color{blue}{0.375}}{{b}^{3}}\right)\right) - \frac{0.5}{b}\right) \]
                        4. Simplified89.5%

                          \[\leadsto c \cdot \left(c \cdot \color{blue}{\left(a \cdot \left(\frac{-0.5625 \cdot \left(a \cdot c\right)}{{b}^{5}} - \frac{0.375}{{b}^{3}}\right)\right)} - \frac{0.5}{b}\right) \]
                      5. Recombined 2 regimes into one program.
                      6. Final simplification89.6%

                        \[\leadsto \begin{array}{l} \mathbf{if}\;\frac{\sqrt{b \cdot b - \left(3 \cdot a\right) \cdot c} - b}{3 \cdot a} \leq -15:\\ \;\;\;\;\frac{\sqrt{b \cdot b - 3 \cdot \left(a \cdot c\right)} - b}{3 \cdot a}\\ \mathbf{else}:\\ \;\;\;\;c \cdot \left(c \cdot \left(a \cdot \left(\frac{-0.5625 \cdot \left(a \cdot c\right)}{{b}^{5}} - \frac{0.375}{{b}^{3}}\right)\right) - \frac{0.5}{b}\right)\\ \end{array} \]
                      7. Add Preprocessing

                      Alternative 6: 85.3% accurate, 0.5× speedup?

                      \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;b \leq 14.5:\\ \;\;\;\;\frac{\sqrt{\mathsf{fma}\left(b, b, a \cdot \left(c \cdot -3\right)\right)} - b}{3 \cdot a}\\ \mathbf{else}:\\ \;\;\;\;\frac{\mathsf{fma}\left(-0.375, a \cdot {\left(\frac{c}{b}\right)}^{2}, c \cdot -0.5\right)}{b}\\ \end{array} \end{array} \]
                      (FPCore (a b c)
                       :precision binary64
                       (if (<= b 14.5)
                         (/ (- (sqrt (fma b b (* a (* c -3.0)))) b) (* 3.0 a))
                         (/ (fma -0.375 (* a (pow (/ c b) 2.0)) (* c -0.5)) b)))
                      double code(double a, double b, double c) {
                      	double tmp;
                      	if (b <= 14.5) {
                      		tmp = (sqrt(fma(b, b, (a * (c * -3.0)))) - b) / (3.0 * a);
                      	} else {
                      		tmp = fma(-0.375, (a * pow((c / b), 2.0)), (c * -0.5)) / b;
                      	}
                      	return tmp;
                      }
                      
                      function code(a, b, c)
                      	tmp = 0.0
                      	if (b <= 14.5)
                      		tmp = Float64(Float64(sqrt(fma(b, b, Float64(a * Float64(c * -3.0)))) - b) / Float64(3.0 * a));
                      	else
                      		tmp = Float64(fma(-0.375, Float64(a * (Float64(c / b) ^ 2.0)), Float64(c * -0.5)) / b);
                      	end
                      	return tmp
                      end
                      
                      code[a_, b_, c_] := If[LessEqual[b, 14.5], N[(N[(N[Sqrt[N[(b * b + N[(a * N[(c * -3.0), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] - b), $MachinePrecision] / N[(3.0 * a), $MachinePrecision]), $MachinePrecision], N[(N[(-0.375 * N[(a * N[Power[N[(c / b), $MachinePrecision], 2.0], $MachinePrecision]), $MachinePrecision] + N[(c * -0.5), $MachinePrecision]), $MachinePrecision] / b), $MachinePrecision]]
                      
                      \begin{array}{l}
                      
                      \\
                      \begin{array}{l}
                      \mathbf{if}\;b \leq 14.5:\\
                      \;\;\;\;\frac{\sqrt{\mathsf{fma}\left(b, b, a \cdot \left(c \cdot -3\right)\right)} - b}{3 \cdot a}\\
                      
                      \mathbf{else}:\\
                      \;\;\;\;\frac{\mathsf{fma}\left(-0.375, a \cdot {\left(\frac{c}{b}\right)}^{2}, c \cdot -0.5\right)}{b}\\
                      
                      
                      \end{array}
                      \end{array}
                      
                      Derivation
                      1. Split input into 2 regimes
                      2. if b < 14.5

                        1. Initial program 80.2%

                          \[\frac{\left(-b\right) + \sqrt{b \cdot b - \left(3 \cdot a\right) \cdot c}}{3 \cdot a} \]
                        2. Step-by-step derivation
                          1. Simplified80.2%

                            \[\leadsto \color{blue}{\frac{\sqrt{\mathsf{fma}\left(b, b, a \cdot \left(c \cdot -3\right)\right)} - b}{3 \cdot a}} \]
                          2. Add Preprocessing

                          if 14.5 < b

                          1. Initial program 47.9%

                            \[\frac{\left(-b\right) + \sqrt{b \cdot b - \left(3 \cdot a\right) \cdot c}}{3 \cdot a} \]
                          2. Step-by-step derivation
                            1. Simplified47.9%

                              \[\leadsto \color{blue}{\frac{\sqrt{\mathsf{fma}\left(b, b, a \cdot \left(c \cdot -3\right)\right)} - b}{3 \cdot a}} \]
                            2. Add Preprocessing
                            3. Taylor expanded in a around 0 86.8%

                              \[\leadsto \color{blue}{-0.5 \cdot \frac{c}{b} + -0.375 \cdot \frac{a \cdot {c}^{2}}{{b}^{3}}} \]
                            4. Taylor expanded in b around inf 86.8%

                              \[\leadsto \color{blue}{\frac{-0.5 \cdot c + -0.375 \cdot \frac{a \cdot {c}^{2}}{{b}^{2}}}{b}} \]
                            5. Step-by-step derivation
                              1. +-commutative86.8%

                                \[\leadsto \frac{\color{blue}{-0.375 \cdot \frac{a \cdot {c}^{2}}{{b}^{2}} + -0.5 \cdot c}}{b} \]
                              2. fma-define86.8%

                                \[\leadsto \frac{\color{blue}{\mathsf{fma}\left(-0.375, \frac{a \cdot {c}^{2}}{{b}^{2}}, -0.5 \cdot c\right)}}{b} \]
                              3. associate-/l*86.8%

                                \[\leadsto \frac{\mathsf{fma}\left(-0.375, \color{blue}{a \cdot \frac{{c}^{2}}{{b}^{2}}}, -0.5 \cdot c\right)}{b} \]
                              4. unpow286.8%

                                \[\leadsto \frac{\mathsf{fma}\left(-0.375, a \cdot \frac{{c}^{2}}{\color{blue}{b \cdot b}}, -0.5 \cdot c\right)}{b} \]
                              5. unpow286.8%

                                \[\leadsto \frac{\mathsf{fma}\left(-0.375, a \cdot \frac{\color{blue}{c \cdot c}}{b \cdot b}, -0.5 \cdot c\right)}{b} \]
                              6. times-frac86.8%

                                \[\leadsto \frac{\mathsf{fma}\left(-0.375, a \cdot \color{blue}{\left(\frac{c}{b} \cdot \frac{c}{b}\right)}, -0.5 \cdot c\right)}{b} \]
                              7. unpow286.8%

                                \[\leadsto \frac{\mathsf{fma}\left(-0.375, a \cdot \color{blue}{{\left(\frac{c}{b}\right)}^{2}}, -0.5 \cdot c\right)}{b} \]
                            6. Simplified86.8%

                              \[\leadsto \color{blue}{\frac{\mathsf{fma}\left(-0.375, a \cdot {\left(\frac{c}{b}\right)}^{2}, -0.5 \cdot c\right)}{b}} \]
                          3. Recombined 2 regimes into one program.
                          4. Final simplification85.0%

                            \[\leadsto \begin{array}{l} \mathbf{if}\;b \leq 14.5:\\ \;\;\;\;\frac{\sqrt{\mathsf{fma}\left(b, b, a \cdot \left(c \cdot -3\right)\right)} - b}{3 \cdot a}\\ \mathbf{else}:\\ \;\;\;\;\frac{\mathsf{fma}\left(-0.375, a \cdot {\left(\frac{c}{b}\right)}^{2}, c \cdot -0.5\right)}{b}\\ \end{array} \]
                          5. Add Preprocessing

                          Alternative 7: 85.3% accurate, 0.5× speedup?

                          \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;b \leq 13.5:\\ \;\;\;\;\frac{\sqrt{b \cdot b - 3 \cdot \left(a \cdot c\right)} - b}{3 \cdot a}\\ \mathbf{else}:\\ \;\;\;\;\frac{\mathsf{fma}\left(-0.375, a \cdot {\left(\frac{c}{b}\right)}^{2}, c \cdot -0.5\right)}{b}\\ \end{array} \end{array} \]
                          (FPCore (a b c)
                           :precision binary64
                           (if (<= b 13.5)
                             (/ (- (sqrt (- (* b b) (* 3.0 (* a c)))) b) (* 3.0 a))
                             (/ (fma -0.375 (* a (pow (/ c b) 2.0)) (* c -0.5)) b)))
                          double code(double a, double b, double c) {
                          	double tmp;
                          	if (b <= 13.5) {
                          		tmp = (sqrt(((b * b) - (3.0 * (a * c)))) - b) / (3.0 * a);
                          	} else {
                          		tmp = fma(-0.375, (a * pow((c / b), 2.0)), (c * -0.5)) / b;
                          	}
                          	return tmp;
                          }
                          
                          function code(a, b, c)
                          	tmp = 0.0
                          	if (b <= 13.5)
                          		tmp = Float64(Float64(sqrt(Float64(Float64(b * b) - Float64(3.0 * Float64(a * c)))) - b) / Float64(3.0 * a));
                          	else
                          		tmp = Float64(fma(-0.375, Float64(a * (Float64(c / b) ^ 2.0)), Float64(c * -0.5)) / b);
                          	end
                          	return tmp
                          end
                          
                          code[a_, b_, c_] := If[LessEqual[b, 13.5], N[(N[(N[Sqrt[N[(N[(b * b), $MachinePrecision] - N[(3.0 * N[(a * c), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] - b), $MachinePrecision] / N[(3.0 * a), $MachinePrecision]), $MachinePrecision], N[(N[(-0.375 * N[(a * N[Power[N[(c / b), $MachinePrecision], 2.0], $MachinePrecision]), $MachinePrecision] + N[(c * -0.5), $MachinePrecision]), $MachinePrecision] / b), $MachinePrecision]]
                          
                          \begin{array}{l}
                          
                          \\
                          \begin{array}{l}
                          \mathbf{if}\;b \leq 13.5:\\
                          \;\;\;\;\frac{\sqrt{b \cdot b - 3 \cdot \left(a \cdot c\right)} - b}{3 \cdot a}\\
                          
                          \mathbf{else}:\\
                          \;\;\;\;\frac{\mathsf{fma}\left(-0.375, a \cdot {\left(\frac{c}{b}\right)}^{2}, c \cdot -0.5\right)}{b}\\
                          
                          
                          \end{array}
                          \end{array}
                          
                          Derivation
                          1. Split input into 2 regimes
                          2. if b < 13.5

                            1. Initial program 80.2%

                              \[\frac{\left(-b\right) + \sqrt{b \cdot b - \left(3 \cdot a\right) \cdot c}}{3 \cdot a} \]
                            2. Step-by-step derivation
                              1. sqr-neg80.2%

                                \[\leadsto \frac{\left(-b\right) + \sqrt{\color{blue}{\left(-b\right) \cdot \left(-b\right)} - \left(3 \cdot a\right) \cdot c}}{3 \cdot a} \]
                              2. sqr-neg80.2%

                                \[\leadsto \frac{\left(-b\right) + \sqrt{\color{blue}{b \cdot b} - \left(3 \cdot a\right) \cdot c}}{3 \cdot a} \]
                              3. associate-*l*80.2%

                                \[\leadsto \frac{\left(-b\right) + \sqrt{b \cdot b - \color{blue}{3 \cdot \left(a \cdot c\right)}}}{3 \cdot a} \]
                            3. Simplified80.2%

                              \[\leadsto \color{blue}{\frac{\left(-b\right) + \sqrt{b \cdot b - 3 \cdot \left(a \cdot c\right)}}{3 \cdot a}} \]
                            4. Add Preprocessing

                            if 13.5 < b

                            1. Initial program 47.9%

                              \[\frac{\left(-b\right) + \sqrt{b \cdot b - \left(3 \cdot a\right) \cdot c}}{3 \cdot a} \]
                            2. Step-by-step derivation
                              1. Simplified47.9%

                                \[\leadsto \color{blue}{\frac{\sqrt{\mathsf{fma}\left(b, b, a \cdot \left(c \cdot -3\right)\right)} - b}{3 \cdot a}} \]
                              2. Add Preprocessing
                              3. Taylor expanded in a around 0 86.8%

                                \[\leadsto \color{blue}{-0.5 \cdot \frac{c}{b} + -0.375 \cdot \frac{a \cdot {c}^{2}}{{b}^{3}}} \]
                              4. Taylor expanded in b around inf 86.8%

                                \[\leadsto \color{blue}{\frac{-0.5 \cdot c + -0.375 \cdot \frac{a \cdot {c}^{2}}{{b}^{2}}}{b}} \]
                              5. Step-by-step derivation
                                1. +-commutative86.8%

                                  \[\leadsto \frac{\color{blue}{-0.375 \cdot \frac{a \cdot {c}^{2}}{{b}^{2}} + -0.5 \cdot c}}{b} \]
                                2. fma-define86.8%

                                  \[\leadsto \frac{\color{blue}{\mathsf{fma}\left(-0.375, \frac{a \cdot {c}^{2}}{{b}^{2}}, -0.5 \cdot c\right)}}{b} \]
                                3. associate-/l*86.8%

                                  \[\leadsto \frac{\mathsf{fma}\left(-0.375, \color{blue}{a \cdot \frac{{c}^{2}}{{b}^{2}}}, -0.5 \cdot c\right)}{b} \]
                                4. unpow286.8%

                                  \[\leadsto \frac{\mathsf{fma}\left(-0.375, a \cdot \frac{{c}^{2}}{\color{blue}{b \cdot b}}, -0.5 \cdot c\right)}{b} \]
                                5. unpow286.8%

                                  \[\leadsto \frac{\mathsf{fma}\left(-0.375, a \cdot \frac{\color{blue}{c \cdot c}}{b \cdot b}, -0.5 \cdot c\right)}{b} \]
                                6. times-frac86.8%

                                  \[\leadsto \frac{\mathsf{fma}\left(-0.375, a \cdot \color{blue}{\left(\frac{c}{b} \cdot \frac{c}{b}\right)}, -0.5 \cdot c\right)}{b} \]
                                7. unpow286.8%

                                  \[\leadsto \frac{\mathsf{fma}\left(-0.375, a \cdot \color{blue}{{\left(\frac{c}{b}\right)}^{2}}, -0.5 \cdot c\right)}{b} \]
                              6. Simplified86.8%

                                \[\leadsto \color{blue}{\frac{\mathsf{fma}\left(-0.375, a \cdot {\left(\frac{c}{b}\right)}^{2}, -0.5 \cdot c\right)}{b}} \]
                            3. Recombined 2 regimes into one program.
                            4. Final simplification85.0%

                              \[\leadsto \begin{array}{l} \mathbf{if}\;b \leq 13.5:\\ \;\;\;\;\frac{\sqrt{b \cdot b - 3 \cdot \left(a \cdot c\right)} - b}{3 \cdot a}\\ \mathbf{else}:\\ \;\;\;\;\frac{\mathsf{fma}\left(-0.375, a \cdot {\left(\frac{c}{b}\right)}^{2}, c \cdot -0.5\right)}{b}\\ \end{array} \]
                            5. Add Preprocessing

                            Alternative 8: 85.2% accurate, 1.0× speedup?

                            \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;b \leq 5:\\ \;\;\;\;\frac{\sqrt{b \cdot b - 3 \cdot \left(a \cdot c\right)} - b}{3 \cdot a}\\ \mathbf{else}:\\ \;\;\;\;c \cdot \left(-0.375 \cdot \left(a \cdot \frac{c}{{b}^{3}}\right) - \frac{0.5}{b}\right)\\ \end{array} \end{array} \]
                            (FPCore (a b c)
                             :precision binary64
                             (if (<= b 5.0)
                               (/ (- (sqrt (- (* b b) (* 3.0 (* a c)))) b) (* 3.0 a))
                               (* c (- (* -0.375 (* a (/ c (pow b 3.0)))) (/ 0.5 b)))))
                            double code(double a, double b, double c) {
                            	double tmp;
                            	if (b <= 5.0) {
                            		tmp = (sqrt(((b * b) - (3.0 * (a * c)))) - b) / (3.0 * a);
                            	} else {
                            		tmp = c * ((-0.375 * (a * (c / pow(b, 3.0)))) - (0.5 / b));
                            	}
                            	return tmp;
                            }
                            
                            real(8) function code(a, b, c)
                                real(8), intent (in) :: a
                                real(8), intent (in) :: b
                                real(8), intent (in) :: c
                                real(8) :: tmp
                                if (b <= 5.0d0) then
                                    tmp = (sqrt(((b * b) - (3.0d0 * (a * c)))) - b) / (3.0d0 * a)
                                else
                                    tmp = c * (((-0.375d0) * (a * (c / (b ** 3.0d0)))) - (0.5d0 / b))
                                end if
                                code = tmp
                            end function
                            
                            public static double code(double a, double b, double c) {
                            	double tmp;
                            	if (b <= 5.0) {
                            		tmp = (Math.sqrt(((b * b) - (3.0 * (a * c)))) - b) / (3.0 * a);
                            	} else {
                            		tmp = c * ((-0.375 * (a * (c / Math.pow(b, 3.0)))) - (0.5 / b));
                            	}
                            	return tmp;
                            }
                            
                            def code(a, b, c):
                            	tmp = 0
                            	if b <= 5.0:
                            		tmp = (math.sqrt(((b * b) - (3.0 * (a * c)))) - b) / (3.0 * a)
                            	else:
                            		tmp = c * ((-0.375 * (a * (c / math.pow(b, 3.0)))) - (0.5 / b))
                            	return tmp
                            
                            function code(a, b, c)
                            	tmp = 0.0
                            	if (b <= 5.0)
                            		tmp = Float64(Float64(sqrt(Float64(Float64(b * b) - Float64(3.0 * Float64(a * c)))) - b) / Float64(3.0 * a));
                            	else
                            		tmp = Float64(c * Float64(Float64(-0.375 * Float64(a * Float64(c / (b ^ 3.0)))) - Float64(0.5 / b)));
                            	end
                            	return tmp
                            end
                            
                            function tmp_2 = code(a, b, c)
                            	tmp = 0.0;
                            	if (b <= 5.0)
                            		tmp = (sqrt(((b * b) - (3.0 * (a * c)))) - b) / (3.0 * a);
                            	else
                            		tmp = c * ((-0.375 * (a * (c / (b ^ 3.0)))) - (0.5 / b));
                            	end
                            	tmp_2 = tmp;
                            end
                            
                            code[a_, b_, c_] := If[LessEqual[b, 5.0], N[(N[(N[Sqrt[N[(N[(b * b), $MachinePrecision] - N[(3.0 * N[(a * c), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] - b), $MachinePrecision] / N[(3.0 * a), $MachinePrecision]), $MachinePrecision], N[(c * N[(N[(-0.375 * N[(a * N[(c / N[Power[b, 3.0], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] - N[(0.5 / b), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]]
                            
                            \begin{array}{l}
                            
                            \\
                            \begin{array}{l}
                            \mathbf{if}\;b \leq 5:\\
                            \;\;\;\;\frac{\sqrt{b \cdot b - 3 \cdot \left(a \cdot c\right)} - b}{3 \cdot a}\\
                            
                            \mathbf{else}:\\
                            \;\;\;\;c \cdot \left(-0.375 \cdot \left(a \cdot \frac{c}{{b}^{3}}\right) - \frac{0.5}{b}\right)\\
                            
                            
                            \end{array}
                            \end{array}
                            
                            Derivation
                            1. Split input into 2 regimes
                            2. if b < 5

                              1. Initial program 81.2%

                                \[\frac{\left(-b\right) + \sqrt{b \cdot b - \left(3 \cdot a\right) \cdot c}}{3 \cdot a} \]
                              2. Step-by-step derivation
                                1. sqr-neg81.2%

                                  \[\leadsto \frac{\left(-b\right) + \sqrt{\color{blue}{\left(-b\right) \cdot \left(-b\right)} - \left(3 \cdot a\right) \cdot c}}{3 \cdot a} \]
                                2. sqr-neg81.2%

                                  \[\leadsto \frac{\left(-b\right) + \sqrt{\color{blue}{b \cdot b} - \left(3 \cdot a\right) \cdot c}}{3 \cdot a} \]
                                3. associate-*l*81.3%

                                  \[\leadsto \frac{\left(-b\right) + \sqrt{b \cdot b - \color{blue}{3 \cdot \left(a \cdot c\right)}}}{3 \cdot a} \]
                              3. Simplified81.3%

                                \[\leadsto \color{blue}{\frac{\left(-b\right) + \sqrt{b \cdot b - 3 \cdot \left(a \cdot c\right)}}{3 \cdot a}} \]
                              4. Add Preprocessing

                              if 5 < b

                              1. Initial program 48.9%

                                \[\frac{\left(-b\right) + \sqrt{b \cdot b - \left(3 \cdot a\right) \cdot c}}{3 \cdot a} \]
                              2. Step-by-step derivation
                                1. Simplified48.9%

                                  \[\leadsto \color{blue}{\frac{\sqrt{\mathsf{fma}\left(b, b, a \cdot \left(c \cdot -3\right)\right)} - b}{3 \cdot a}} \]
                                2. Add Preprocessing
                                3. Taylor expanded in c around 0 86.0%

                                  \[\leadsto \color{blue}{c \cdot \left(-0.375 \cdot \frac{a \cdot c}{{b}^{3}} - 0.5 \cdot \frac{1}{b}\right)} \]
                                4. Step-by-step derivation
                                  1. associate-/l*86.0%

                                    \[\leadsto c \cdot \left(-0.375 \cdot \color{blue}{\left(a \cdot \frac{c}{{b}^{3}}\right)} - 0.5 \cdot \frac{1}{b}\right) \]
                                  2. associate-*r/86.0%

                                    \[\leadsto c \cdot \left(-0.375 \cdot \left(a \cdot \frac{c}{{b}^{3}}\right) - \color{blue}{\frac{0.5 \cdot 1}{b}}\right) \]
                                  3. metadata-eval86.0%

                                    \[\leadsto c \cdot \left(-0.375 \cdot \left(a \cdot \frac{c}{{b}^{3}}\right) - \frac{\color{blue}{0.5}}{b}\right) \]
                                5. Simplified86.0%

                                  \[\leadsto \color{blue}{c \cdot \left(-0.375 \cdot \left(a \cdot \frac{c}{{b}^{3}}\right) - \frac{0.5}{b}\right)} \]
                              3. Recombined 2 regimes into one program.
                              4. Final simplification84.9%

                                \[\leadsto \begin{array}{l} \mathbf{if}\;b \leq 5:\\ \;\;\;\;\frac{\sqrt{b \cdot b - 3 \cdot \left(a \cdot c\right)} - b}{3 \cdot a}\\ \mathbf{else}:\\ \;\;\;\;c \cdot \left(-0.375 \cdot \left(a \cdot \frac{c}{{b}^{3}}\right) - \frac{0.5}{b}\right)\\ \end{array} \]
                              5. Add Preprocessing

                              Alternative 9: 81.7% accurate, 1.0× speedup?

                              \[\begin{array}{l} \\ c \cdot \left(-0.375 \cdot \left(a \cdot \frac{c}{{b}^{3}}\right) - \frac{0.5}{b}\right) \end{array} \]
                              (FPCore (a b c)
                               :precision binary64
                               (* c (- (* -0.375 (* a (/ c (pow b 3.0)))) (/ 0.5 b))))
                              double code(double a, double b, double c) {
                              	return c * ((-0.375 * (a * (c / pow(b, 3.0)))) - (0.5 / b));
                              }
                              
                              real(8) function code(a, b, c)
                                  real(8), intent (in) :: a
                                  real(8), intent (in) :: b
                                  real(8), intent (in) :: c
                                  code = c * (((-0.375d0) * (a * (c / (b ** 3.0d0)))) - (0.5d0 / b))
                              end function
                              
                              public static double code(double a, double b, double c) {
                              	return c * ((-0.375 * (a * (c / Math.pow(b, 3.0)))) - (0.5 / b));
                              }
                              
                              def code(a, b, c):
                              	return c * ((-0.375 * (a * (c / math.pow(b, 3.0)))) - (0.5 / b))
                              
                              function code(a, b, c)
                              	return Float64(c * Float64(Float64(-0.375 * Float64(a * Float64(c / (b ^ 3.0)))) - Float64(0.5 / b)))
                              end
                              
                              function tmp = code(a, b, c)
                              	tmp = c * ((-0.375 * (a * (c / (b ^ 3.0)))) - (0.5 / b));
                              end
                              
                              code[a_, b_, c_] := N[(c * N[(N[(-0.375 * N[(a * N[(c / N[Power[b, 3.0], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] - N[(0.5 / b), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
                              
                              \begin{array}{l}
                              
                              \\
                              c \cdot \left(-0.375 \cdot \left(a \cdot \frac{c}{{b}^{3}}\right) - \frac{0.5}{b}\right)
                              \end{array}
                              
                              Derivation
                              1. Initial program 56.5%

                                \[\frac{\left(-b\right) + \sqrt{b \cdot b - \left(3 \cdot a\right) \cdot c}}{3 \cdot a} \]
                              2. Step-by-step derivation
                                1. Simplified56.5%

                                  \[\leadsto \color{blue}{\frac{\sqrt{\mathsf{fma}\left(b, b, a \cdot \left(c \cdot -3\right)\right)} - b}{3 \cdot a}} \]
                                2. Add Preprocessing
                                3. Taylor expanded in c around 0 80.1%

                                  \[\leadsto \color{blue}{c \cdot \left(-0.375 \cdot \frac{a \cdot c}{{b}^{3}} - 0.5 \cdot \frac{1}{b}\right)} \]
                                4. Step-by-step derivation
                                  1. associate-/l*80.1%

                                    \[\leadsto c \cdot \left(-0.375 \cdot \color{blue}{\left(a \cdot \frac{c}{{b}^{3}}\right)} - 0.5 \cdot \frac{1}{b}\right) \]
                                  2. associate-*r/80.1%

                                    \[\leadsto c \cdot \left(-0.375 \cdot \left(a \cdot \frac{c}{{b}^{3}}\right) - \color{blue}{\frac{0.5 \cdot 1}{b}}\right) \]
                                  3. metadata-eval80.1%

                                    \[\leadsto c \cdot \left(-0.375 \cdot \left(a \cdot \frac{c}{{b}^{3}}\right) - \frac{\color{blue}{0.5}}{b}\right) \]
                                5. Simplified80.1%

                                  \[\leadsto \color{blue}{c \cdot \left(-0.375 \cdot \left(a \cdot \frac{c}{{b}^{3}}\right) - \frac{0.5}{b}\right)} \]
                                6. Add Preprocessing

                                Alternative 10: 64.6% accurate, 23.2× speedup?

                                \[\begin{array}{l} \\ \frac{c \cdot -0.5}{b} \end{array} \]
                                (FPCore (a b c) :precision binary64 (/ (* c -0.5) b))
                                double code(double a, double b, double c) {
                                	return (c * -0.5) / b;
                                }
                                
                                real(8) function code(a, b, c)
                                    real(8), intent (in) :: a
                                    real(8), intent (in) :: b
                                    real(8), intent (in) :: c
                                    code = (c * (-0.5d0)) / b
                                end function
                                
                                public static double code(double a, double b, double c) {
                                	return (c * -0.5) / b;
                                }
                                
                                def code(a, b, c):
                                	return (c * -0.5) / b
                                
                                function code(a, b, c)
                                	return Float64(Float64(c * -0.5) / b)
                                end
                                
                                function tmp = code(a, b, c)
                                	tmp = (c * -0.5) / b;
                                end
                                
                                code[a_, b_, c_] := N[(N[(c * -0.5), $MachinePrecision] / b), $MachinePrecision]
                                
                                \begin{array}{l}
                                
                                \\
                                \frac{c \cdot -0.5}{b}
                                \end{array}
                                
                                Derivation
                                1. Initial program 56.5%

                                  \[\frac{\left(-b\right) + \sqrt{b \cdot b - \left(3 \cdot a\right) \cdot c}}{3 \cdot a} \]
                                2. Step-by-step derivation
                                  1. Simplified56.5%

                                    \[\leadsto \color{blue}{\frac{\sqrt{\mathsf{fma}\left(b, b, a \cdot \left(c \cdot -3\right)\right)} - b}{3 \cdot a}} \]
                                  2. Add Preprocessing
                                  3. Taylor expanded in b around inf 63.6%

                                    \[\leadsto \color{blue}{-0.5 \cdot \frac{c}{b}} \]
                                  4. Step-by-step derivation
                                    1. associate-*r/63.6%

                                      \[\leadsto \color{blue}{\frac{-0.5 \cdot c}{b}} \]
                                    2. *-commutative63.6%

                                      \[\leadsto \frac{\color{blue}{c \cdot -0.5}}{b} \]
                                  5. Simplified63.6%

                                    \[\leadsto \color{blue}{\frac{c \cdot -0.5}{b}} \]
                                  6. Add Preprocessing

                                  Alternative 11: 64.5% accurate, 23.2× speedup?

                                  \[\begin{array}{l} \\ c \cdot \frac{-0.5}{b} \end{array} \]
                                  (FPCore (a b c) :precision binary64 (* c (/ -0.5 b)))
                                  double code(double a, double b, double c) {
                                  	return c * (-0.5 / b);
                                  }
                                  
                                  real(8) function code(a, b, c)
                                      real(8), intent (in) :: a
                                      real(8), intent (in) :: b
                                      real(8), intent (in) :: c
                                      code = c * ((-0.5d0) / b)
                                  end function
                                  
                                  public static double code(double a, double b, double c) {
                                  	return c * (-0.5 / b);
                                  }
                                  
                                  def code(a, b, c):
                                  	return c * (-0.5 / b)
                                  
                                  function code(a, b, c)
                                  	return Float64(c * Float64(-0.5 / b))
                                  end
                                  
                                  function tmp = code(a, b, c)
                                  	tmp = c * (-0.5 / b);
                                  end
                                  
                                  code[a_, b_, c_] := N[(c * N[(-0.5 / b), $MachinePrecision]), $MachinePrecision]
                                  
                                  \begin{array}{l}
                                  
                                  \\
                                  c \cdot \frac{-0.5}{b}
                                  \end{array}
                                  
                                  Derivation
                                  1. Initial program 56.5%

                                    \[\frac{\left(-b\right) + \sqrt{b \cdot b - \left(3 \cdot a\right) \cdot c}}{3 \cdot a} \]
                                  2. Step-by-step derivation
                                    1. Simplified56.5%

                                      \[\leadsto \color{blue}{\frac{\sqrt{\mathsf{fma}\left(b, b, a \cdot \left(c \cdot -3\right)\right)} - b}{3 \cdot a}} \]
                                    2. Add Preprocessing
                                    3. Taylor expanded in b around inf 63.6%

                                      \[\leadsto \color{blue}{-0.5 \cdot \frac{c}{b}} \]
                                    4. Step-by-step derivation
                                      1. associate-*r/63.6%

                                        \[\leadsto \color{blue}{\frac{-0.5 \cdot c}{b}} \]
                                      2. *-commutative63.6%

                                        \[\leadsto \frac{\color{blue}{c \cdot -0.5}}{b} \]
                                    5. Simplified63.6%

                                      \[\leadsto \color{blue}{\frac{c \cdot -0.5}{b}} \]
                                    6. Taylor expanded in c around 0 63.6%

                                      \[\leadsto \color{blue}{-0.5 \cdot \frac{c}{b}} \]
                                    7. Step-by-step derivation
                                      1. associate-*r/63.6%

                                        \[\leadsto \color{blue}{\frac{-0.5 \cdot c}{b}} \]
                                      2. *-commutative63.6%

                                        \[\leadsto \frac{\color{blue}{c \cdot -0.5}}{b} \]
                                      3. associate-*r/63.5%

                                        \[\leadsto \color{blue}{c \cdot \frac{-0.5}{b}} \]
                                    8. Simplified63.5%

                                      \[\leadsto \color{blue}{c \cdot \frac{-0.5}{b}} \]
                                    9. Add Preprocessing

                                    Reproduce

                                    ?
                                    herbie shell --seed 2024191 
                                    (FPCore (a b c)
                                      :name "Cubic critical, narrow range"
                                      :precision binary64
                                      :pre (and (and (and (< 1.0536712127723509e-8 a) (< a 94906265.62425156)) (and (< 1.0536712127723509e-8 b) (< b 94906265.62425156))) (and (< 1.0536712127723509e-8 c) (< c 94906265.62425156)))
                                      (/ (+ (- b) (sqrt (- (* b b) (* (* 3.0 a) c)))) (* 3.0 a)))