Cubic critical, narrow range

Percentage Accurate: 55.7% → 91.6%
Time: 14.8s
Alternatives: 10
Speedup: 23.2×

Specification

?
\[\left(\left(1.0536712127723509 \cdot 10^{-8} < a \land a < 94906265.62425156\right) \land \left(1.0536712127723509 \cdot 10^{-8} < b \land b < 94906265.62425156\right)\right) \land \left(1.0536712127723509 \cdot 10^{-8} < c \land c < 94906265.62425156\right)\]
\[\begin{array}{l} \\ \frac{\left(-b\right) + \sqrt{b \cdot b - \left(3 \cdot a\right) \cdot c}}{3 \cdot a} \end{array} \]
(FPCore (a b c)
 :precision binary64
 (/ (+ (- b) (sqrt (- (* b b) (* (* 3.0 a) c)))) (* 3.0 a)))
double code(double a, double b, double c) {
	return (-b + sqrt(((b * b) - ((3.0 * a) * c)))) / (3.0 * a);
}
real(8) function code(a, b, c)
    real(8), intent (in) :: a
    real(8), intent (in) :: b
    real(8), intent (in) :: c
    code = (-b + sqrt(((b * b) - ((3.0d0 * a) * c)))) / (3.0d0 * a)
end function
public static double code(double a, double b, double c) {
	return (-b + Math.sqrt(((b * b) - ((3.0 * a) * c)))) / (3.0 * a);
}
def code(a, b, c):
	return (-b + math.sqrt(((b * b) - ((3.0 * a) * c)))) / (3.0 * a)
function code(a, b, c)
	return Float64(Float64(Float64(-b) + sqrt(Float64(Float64(b * b) - Float64(Float64(3.0 * a) * c)))) / Float64(3.0 * a))
end
function tmp = code(a, b, c)
	tmp = (-b + sqrt(((b * b) - ((3.0 * a) * c)))) / (3.0 * a);
end
code[a_, b_, c_] := N[(N[((-b) + N[Sqrt[N[(N[(b * b), $MachinePrecision] - N[(N[(3.0 * a), $MachinePrecision] * c), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] / N[(3.0 * a), $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
\frac{\left(-b\right) + \sqrt{b \cdot b - \left(3 \cdot a\right) \cdot c}}{3 \cdot a}
\end{array}

Sampling outcomes in binary64 precision:

Local Percentage Accuracy vs ?

The average percentage accuracy by input value. Horizontal axis shows value of an input variable; the variable is choosen in the title. Vertical axis is accuracy; higher is better. Red represent the original program, while blue represents Herbie's suggestion. These can be toggled with buttons below the plot. The line is an average while dots represent individual samples.

Accuracy vs Speed?

Herbie found 10 alternatives:

AlternativeAccuracySpeedup
The accuracy (vertical axis) and speed (horizontal axis) of each alternatives. Up and to the right is better. The red square shows the initial program, and each blue circle shows an alternative.The line shows the best available speed-accuracy tradeoffs.

Initial Program: 55.7% accurate, 1.0× speedup?

\[\begin{array}{l} \\ \frac{\left(-b\right) + \sqrt{b \cdot b - \left(3 \cdot a\right) \cdot c}}{3 \cdot a} \end{array} \]
(FPCore (a b c)
 :precision binary64
 (/ (+ (- b) (sqrt (- (* b b) (* (* 3.0 a) c)))) (* 3.0 a)))
double code(double a, double b, double c) {
	return (-b + sqrt(((b * b) - ((3.0 * a) * c)))) / (3.0 * a);
}
real(8) function code(a, b, c)
    real(8), intent (in) :: a
    real(8), intent (in) :: b
    real(8), intent (in) :: c
    code = (-b + sqrt(((b * b) - ((3.0d0 * a) * c)))) / (3.0d0 * a)
end function
public static double code(double a, double b, double c) {
	return (-b + Math.sqrt(((b * b) - ((3.0 * a) * c)))) / (3.0 * a);
}
def code(a, b, c):
	return (-b + math.sqrt(((b * b) - ((3.0 * a) * c)))) / (3.0 * a)
function code(a, b, c)
	return Float64(Float64(Float64(-b) + sqrt(Float64(Float64(b * b) - Float64(Float64(3.0 * a) * c)))) / Float64(3.0 * a))
end
function tmp = code(a, b, c)
	tmp = (-b + sqrt(((b * b) - ((3.0 * a) * c)))) / (3.0 * a);
end
code[a_, b_, c_] := N[(N[((-b) + N[Sqrt[N[(N[(b * b), $MachinePrecision] - N[(N[(3.0 * a), $MachinePrecision] * c), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] / N[(3.0 * a), $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
\frac{\left(-b\right) + \sqrt{b \cdot b - \left(3 \cdot a\right) \cdot c}}{3 \cdot a}
\end{array}

Alternative 1: 91.6% accurate, 0.2× speedup?

\[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;\frac{\sqrt{b \cdot b - \left(3 \cdot a\right) \cdot c} - b}{3 \cdot a} \leq -50:\\ \;\;\;\;\frac{\sqrt{\mathsf{fma}\left(b, b, a \cdot \left(c \cdot -3\right)\right)} - b}{e^{\log \left(3 \cdot a\right)}}\\ \mathbf{else}:\\ \;\;\;\;-0.5 \cdot \frac{c}{b} + a \cdot \left(-0.375 \cdot \frac{{c}^{2}}{{b}^{3}} + a \cdot \left(-0.5625 \cdot \frac{{c}^{3}}{{b}^{5}} + -1.0546875 \cdot \frac{a \cdot {c}^{4}}{{b}^{7}}\right)\right)\\ \end{array} \end{array} \]
(FPCore (a b c)
 :precision binary64
 (if (<= (/ (- (sqrt (- (* b b) (* (* 3.0 a) c))) b) (* 3.0 a)) -50.0)
   (/ (- (sqrt (fma b b (* a (* c -3.0)))) b) (exp (log (* 3.0 a))))
   (+
    (* -0.5 (/ c b))
    (*
     a
     (+
      (* -0.375 (/ (pow c 2.0) (pow b 3.0)))
      (*
       a
       (+
        (* -0.5625 (/ (pow c 3.0) (pow b 5.0)))
        (* -1.0546875 (/ (* a (pow c 4.0)) (pow b 7.0))))))))))
double code(double a, double b, double c) {
	double tmp;
	if (((sqrt(((b * b) - ((3.0 * a) * c))) - b) / (3.0 * a)) <= -50.0) {
		tmp = (sqrt(fma(b, b, (a * (c * -3.0)))) - b) / exp(log((3.0 * a)));
	} else {
		tmp = (-0.5 * (c / b)) + (a * ((-0.375 * (pow(c, 2.0) / pow(b, 3.0))) + (a * ((-0.5625 * (pow(c, 3.0) / pow(b, 5.0))) + (-1.0546875 * ((a * pow(c, 4.0)) / pow(b, 7.0)))))));
	}
	return tmp;
}
function code(a, b, c)
	tmp = 0.0
	if (Float64(Float64(sqrt(Float64(Float64(b * b) - Float64(Float64(3.0 * a) * c))) - b) / Float64(3.0 * a)) <= -50.0)
		tmp = Float64(Float64(sqrt(fma(b, b, Float64(a * Float64(c * -3.0)))) - b) / exp(log(Float64(3.0 * a))));
	else
		tmp = Float64(Float64(-0.5 * Float64(c / b)) + Float64(a * Float64(Float64(-0.375 * Float64((c ^ 2.0) / (b ^ 3.0))) + Float64(a * Float64(Float64(-0.5625 * Float64((c ^ 3.0) / (b ^ 5.0))) + Float64(-1.0546875 * Float64(Float64(a * (c ^ 4.0)) / (b ^ 7.0))))))));
	end
	return tmp
end
code[a_, b_, c_] := If[LessEqual[N[(N[(N[Sqrt[N[(N[(b * b), $MachinePrecision] - N[(N[(3.0 * a), $MachinePrecision] * c), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] - b), $MachinePrecision] / N[(3.0 * a), $MachinePrecision]), $MachinePrecision], -50.0], N[(N[(N[Sqrt[N[(b * b + N[(a * N[(c * -3.0), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] - b), $MachinePrecision] / N[Exp[N[Log[N[(3.0 * a), $MachinePrecision]], $MachinePrecision]], $MachinePrecision]), $MachinePrecision], N[(N[(-0.5 * N[(c / b), $MachinePrecision]), $MachinePrecision] + N[(a * N[(N[(-0.375 * N[(N[Power[c, 2.0], $MachinePrecision] / N[Power[b, 3.0], $MachinePrecision]), $MachinePrecision]), $MachinePrecision] + N[(a * N[(N[(-0.5625 * N[(N[Power[c, 3.0], $MachinePrecision] / N[Power[b, 5.0], $MachinePrecision]), $MachinePrecision]), $MachinePrecision] + N[(-1.0546875 * N[(N[(a * N[Power[c, 4.0], $MachinePrecision]), $MachinePrecision] / N[Power[b, 7.0], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]]
\begin{array}{l}

\\
\begin{array}{l}
\mathbf{if}\;\frac{\sqrt{b \cdot b - \left(3 \cdot a\right) \cdot c} - b}{3 \cdot a} \leq -50:\\
\;\;\;\;\frac{\sqrt{\mathsf{fma}\left(b, b, a \cdot \left(c \cdot -3\right)\right)} - b}{e^{\log \left(3 \cdot a\right)}}\\

\mathbf{else}:\\
\;\;\;\;-0.5 \cdot \frac{c}{b} + a \cdot \left(-0.375 \cdot \frac{{c}^{2}}{{b}^{3}} + a \cdot \left(-0.5625 \cdot \frac{{c}^{3}}{{b}^{5}} + -1.0546875 \cdot \frac{a \cdot {c}^{4}}{{b}^{7}}\right)\right)\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if (/.f64 (+.f64 (neg.f64 b) (sqrt.f64 (-.f64 (*.f64 b b) (*.f64 (*.f64 #s(literal 3 binary64) a) c)))) (*.f64 #s(literal 3 binary64) a)) < -50

    1. Initial program 92.6%

      \[\frac{\left(-b\right) + \sqrt{b \cdot b - \left(3 \cdot a\right) \cdot c}}{3 \cdot a} \]
    2. Step-by-step derivation
      1. Simplified92.8%

        \[\leadsto \color{blue}{\frac{\sqrt{\mathsf{fma}\left(b, b, a \cdot \left(c \cdot -3\right)\right)} - b}{3 \cdot a}} \]
      2. Add Preprocessing
      3. Step-by-step derivation
        1. add-exp-log93.2%

          \[\leadsto \frac{\sqrt{\mathsf{fma}\left(b, b, a \cdot \left(c \cdot -3\right)\right)} - b}{\color{blue}{e^{\log \left(3 \cdot a\right)}}} \]
      4. Applied egg-rr93.2%

        \[\leadsto \frac{\sqrt{\mathsf{fma}\left(b, b, a \cdot \left(c \cdot -3\right)\right)} - b}{\color{blue}{e^{\log \left(3 \cdot a\right)}}} \]

      if -50 < (/.f64 (+.f64 (neg.f64 b) (sqrt.f64 (-.f64 (*.f64 b b) (*.f64 (*.f64 #s(literal 3 binary64) a) c)))) (*.f64 #s(literal 3 binary64) a))

      1. Initial program 52.9%

        \[\frac{\left(-b\right) + \sqrt{b \cdot b - \left(3 \cdot a\right) \cdot c}}{3 \cdot a} \]
      2. Step-by-step derivation
        1. Simplified53.0%

          \[\leadsto \color{blue}{\frac{\sqrt{\mathsf{fma}\left(b, b, a \cdot \left(c \cdot -3\right)\right)} - b}{3 \cdot a}} \]
        2. Add Preprocessing
        3. Taylor expanded in a around 0 93.1%

          \[\leadsto \color{blue}{-0.5 \cdot \frac{c}{b} + a \cdot \left(-0.375 \cdot \frac{{c}^{2}}{{b}^{3}} + a \cdot \left(-0.5625 \cdot \frac{{c}^{3}}{{b}^{5}} + -0.16666666666666666 \cdot \frac{a \cdot \left(1.265625 \cdot \frac{{c}^{4}}{{b}^{6}} + 5.0625 \cdot \frac{{c}^{4}}{{b}^{6}}\right)}{b}\right)\right)} \]
        4. Taylor expanded in c around 0 93.1%

          \[\leadsto -0.5 \cdot \frac{c}{b} + a \cdot \left(-0.375 \cdot \frac{{c}^{2}}{{b}^{3}} + a \cdot \left(-0.5625 \cdot \frac{{c}^{3}}{{b}^{5}} + \color{blue}{-1.0546875 \cdot \frac{a \cdot {c}^{4}}{{b}^{7}}}\right)\right) \]
      3. Recombined 2 regimes into one program.
      4. Final simplification93.1%

        \[\leadsto \begin{array}{l} \mathbf{if}\;\frac{\sqrt{b \cdot b - \left(3 \cdot a\right) \cdot c} - b}{3 \cdot a} \leq -50:\\ \;\;\;\;\frac{\sqrt{\mathsf{fma}\left(b, b, a \cdot \left(c \cdot -3\right)\right)} - b}{e^{\log \left(3 \cdot a\right)}}\\ \mathbf{else}:\\ \;\;\;\;-0.5 \cdot \frac{c}{b} + a \cdot \left(-0.375 \cdot \frac{{c}^{2}}{{b}^{3}} + a \cdot \left(-0.5625 \cdot \frac{{c}^{3}}{{b}^{5}} + -1.0546875 \cdot \frac{a \cdot {c}^{4}}{{b}^{7}}\right)\right)\\ \end{array} \]
      5. Add Preprocessing

      Alternative 2: 89.1% accurate, 0.3× speedup?

      \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;b \leq 0.32:\\ \;\;\;\;\frac{\sqrt{b \cdot b - \left(3 \cdot a\right) \cdot c} - b}{\sqrt{{a}^{2} \cdot 9}}\\ \mathbf{else}:\\ \;\;\;\;-0.5 \cdot \frac{c}{b} + a \cdot \left(-0.375 \cdot \frac{{c}^{2}}{{b}^{3}} + -0.5625 \cdot \frac{a \cdot {c}^{3}}{{b}^{5}}\right)\\ \end{array} \end{array} \]
      (FPCore (a b c)
       :precision binary64
       (if (<= b 0.32)
         (/ (- (sqrt (- (* b b) (* (* 3.0 a) c))) b) (sqrt (* (pow a 2.0) 9.0)))
         (+
          (* -0.5 (/ c b))
          (*
           a
           (+
            (* -0.375 (/ (pow c 2.0) (pow b 3.0)))
            (* -0.5625 (/ (* a (pow c 3.0)) (pow b 5.0))))))))
      double code(double a, double b, double c) {
      	double tmp;
      	if (b <= 0.32) {
      		tmp = (sqrt(((b * b) - ((3.0 * a) * c))) - b) / sqrt((pow(a, 2.0) * 9.0));
      	} else {
      		tmp = (-0.5 * (c / b)) + (a * ((-0.375 * (pow(c, 2.0) / pow(b, 3.0))) + (-0.5625 * ((a * pow(c, 3.0)) / pow(b, 5.0)))));
      	}
      	return tmp;
      }
      
      real(8) function code(a, b, c)
          real(8), intent (in) :: a
          real(8), intent (in) :: b
          real(8), intent (in) :: c
          real(8) :: tmp
          if (b <= 0.32d0) then
              tmp = (sqrt(((b * b) - ((3.0d0 * a) * c))) - b) / sqrt(((a ** 2.0d0) * 9.0d0))
          else
              tmp = ((-0.5d0) * (c / b)) + (a * (((-0.375d0) * ((c ** 2.0d0) / (b ** 3.0d0))) + ((-0.5625d0) * ((a * (c ** 3.0d0)) / (b ** 5.0d0)))))
          end if
          code = tmp
      end function
      
      public static double code(double a, double b, double c) {
      	double tmp;
      	if (b <= 0.32) {
      		tmp = (Math.sqrt(((b * b) - ((3.0 * a) * c))) - b) / Math.sqrt((Math.pow(a, 2.0) * 9.0));
      	} else {
      		tmp = (-0.5 * (c / b)) + (a * ((-0.375 * (Math.pow(c, 2.0) / Math.pow(b, 3.0))) + (-0.5625 * ((a * Math.pow(c, 3.0)) / Math.pow(b, 5.0)))));
      	}
      	return tmp;
      }
      
      def code(a, b, c):
      	tmp = 0
      	if b <= 0.32:
      		tmp = (math.sqrt(((b * b) - ((3.0 * a) * c))) - b) / math.sqrt((math.pow(a, 2.0) * 9.0))
      	else:
      		tmp = (-0.5 * (c / b)) + (a * ((-0.375 * (math.pow(c, 2.0) / math.pow(b, 3.0))) + (-0.5625 * ((a * math.pow(c, 3.0)) / math.pow(b, 5.0)))))
      	return tmp
      
      function code(a, b, c)
      	tmp = 0.0
      	if (b <= 0.32)
      		tmp = Float64(Float64(sqrt(Float64(Float64(b * b) - Float64(Float64(3.0 * a) * c))) - b) / sqrt(Float64((a ^ 2.0) * 9.0)));
      	else
      		tmp = Float64(Float64(-0.5 * Float64(c / b)) + Float64(a * Float64(Float64(-0.375 * Float64((c ^ 2.0) / (b ^ 3.0))) + Float64(-0.5625 * Float64(Float64(a * (c ^ 3.0)) / (b ^ 5.0))))));
      	end
      	return tmp
      end
      
      function tmp_2 = code(a, b, c)
      	tmp = 0.0;
      	if (b <= 0.32)
      		tmp = (sqrt(((b * b) - ((3.0 * a) * c))) - b) / sqrt(((a ^ 2.0) * 9.0));
      	else
      		tmp = (-0.5 * (c / b)) + (a * ((-0.375 * ((c ^ 2.0) / (b ^ 3.0))) + (-0.5625 * ((a * (c ^ 3.0)) / (b ^ 5.0)))));
      	end
      	tmp_2 = tmp;
      end
      
      code[a_, b_, c_] := If[LessEqual[b, 0.32], N[(N[(N[Sqrt[N[(N[(b * b), $MachinePrecision] - N[(N[(3.0 * a), $MachinePrecision] * c), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] - b), $MachinePrecision] / N[Sqrt[N[(N[Power[a, 2.0], $MachinePrecision] * 9.0), $MachinePrecision]], $MachinePrecision]), $MachinePrecision], N[(N[(-0.5 * N[(c / b), $MachinePrecision]), $MachinePrecision] + N[(a * N[(N[(-0.375 * N[(N[Power[c, 2.0], $MachinePrecision] / N[Power[b, 3.0], $MachinePrecision]), $MachinePrecision]), $MachinePrecision] + N[(-0.5625 * N[(N[(a * N[Power[c, 3.0], $MachinePrecision]), $MachinePrecision] / N[Power[b, 5.0], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]]
      
      \begin{array}{l}
      
      \\
      \begin{array}{l}
      \mathbf{if}\;b \leq 0.32:\\
      \;\;\;\;\frac{\sqrt{b \cdot b - \left(3 \cdot a\right) \cdot c} - b}{\sqrt{{a}^{2} \cdot 9}}\\
      
      \mathbf{else}:\\
      \;\;\;\;-0.5 \cdot \frac{c}{b} + a \cdot \left(-0.375 \cdot \frac{{c}^{2}}{{b}^{3}} + -0.5625 \cdot \frac{a \cdot {c}^{3}}{{b}^{5}}\right)\\
      
      
      \end{array}
      \end{array}
      
      Derivation
      1. Split input into 2 regimes
      2. if b < 0.320000000000000007

        1. Initial program 83.4%

          \[\frac{\left(-b\right) + \sqrt{b \cdot b - \left(3 \cdot a\right) \cdot c}}{3 \cdot a} \]
        2. Add Preprocessing
        3. Step-by-step derivation
          1. add-sqr-sqrt83.3%

            \[\leadsto \frac{\left(-b\right) + \sqrt{b \cdot b - \left(3 \cdot a\right) \cdot c}}{\color{blue}{\sqrt{3 \cdot a} \cdot \sqrt{3 \cdot a}}} \]
          2. sqrt-unprod83.4%

            \[\leadsto \frac{\left(-b\right) + \sqrt{b \cdot b - \left(3 \cdot a\right) \cdot c}}{\color{blue}{\sqrt{\left(3 \cdot a\right) \cdot \left(3 \cdot a\right)}}} \]
          3. *-commutative83.4%

            \[\leadsto \frac{\left(-b\right) + \sqrt{b \cdot b - \left(3 \cdot a\right) \cdot c}}{\sqrt{\color{blue}{\left(a \cdot 3\right)} \cdot \left(3 \cdot a\right)}} \]
          4. *-commutative83.4%

            \[\leadsto \frac{\left(-b\right) + \sqrt{b \cdot b - \left(3 \cdot a\right) \cdot c}}{\sqrt{\left(a \cdot 3\right) \cdot \color{blue}{\left(a \cdot 3\right)}}} \]
          5. swap-sqr83.4%

            \[\leadsto \frac{\left(-b\right) + \sqrt{b \cdot b - \left(3 \cdot a\right) \cdot c}}{\sqrt{\color{blue}{\left(a \cdot a\right) \cdot \left(3 \cdot 3\right)}}} \]
          6. pow283.4%

            \[\leadsto \frac{\left(-b\right) + \sqrt{b \cdot b - \left(3 \cdot a\right) \cdot c}}{\sqrt{\color{blue}{{a}^{2}} \cdot \left(3 \cdot 3\right)}} \]
          7. metadata-eval83.4%

            \[\leadsto \frac{\left(-b\right) + \sqrt{b \cdot b - \left(3 \cdot a\right) \cdot c}}{\sqrt{{a}^{2} \cdot \color{blue}{9}}} \]
        4. Applied egg-rr83.4%

          \[\leadsto \frac{\left(-b\right) + \sqrt{b \cdot b - \left(3 \cdot a\right) \cdot c}}{\color{blue}{\sqrt{{a}^{2} \cdot 9}}} \]

        if 0.320000000000000007 < b

        1. Initial program 49.4%

          \[\frac{\left(-b\right) + \sqrt{b \cdot b - \left(3 \cdot a\right) \cdot c}}{3 \cdot a} \]
        2. Step-by-step derivation
          1. Simplified49.5%

            \[\leadsto \color{blue}{\frac{\sqrt{\mathsf{fma}\left(b, b, a \cdot \left(c \cdot -3\right)\right)} - b}{3 \cdot a}} \]
          2. Add Preprocessing
          3. Taylor expanded in a around 0 92.4%

            \[\leadsto \color{blue}{-0.5 \cdot \frac{c}{b} + a \cdot \left(-0.5625 \cdot \frac{a \cdot {c}^{3}}{{b}^{5}} + -0.375 \cdot \frac{{c}^{2}}{{b}^{3}}\right)} \]
        3. Recombined 2 regimes into one program.
        4. Final simplification91.0%

          \[\leadsto \begin{array}{l} \mathbf{if}\;b \leq 0.32:\\ \;\;\;\;\frac{\sqrt{b \cdot b - \left(3 \cdot a\right) \cdot c} - b}{\sqrt{{a}^{2} \cdot 9}}\\ \mathbf{else}:\\ \;\;\;\;-0.5 \cdot \frac{c}{b} + a \cdot \left(-0.375 \cdot \frac{{c}^{2}}{{b}^{3}} + -0.5625 \cdot \frac{a \cdot {c}^{3}}{{b}^{5}}\right)\\ \end{array} \]
        5. Add Preprocessing

        Alternative 3: 88.9% accurate, 0.4× speedup?

        \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;b \leq 0.28:\\ \;\;\;\;\frac{\sqrt{b \cdot b - \left(3 \cdot a\right) \cdot c} - b}{\sqrt{{a}^{2} \cdot 9}}\\ \mathbf{else}:\\ \;\;\;\;c \cdot \left(c \cdot \left(a \cdot \left(-0.5625 \cdot \left(a \cdot \frac{c}{{b}^{5}}\right) - \frac{0.375}{{b}^{3}}\right)\right) + 0.5 \cdot \frac{-1}{b}\right)\\ \end{array} \end{array} \]
        (FPCore (a b c)
         :precision binary64
         (if (<= b 0.28)
           (/ (- (sqrt (- (* b b) (* (* 3.0 a) c))) b) (sqrt (* (pow a 2.0) 9.0)))
           (*
            c
            (+
             (* c (* a (- (* -0.5625 (* a (/ c (pow b 5.0)))) (/ 0.375 (pow b 3.0)))))
             (* 0.5 (/ -1.0 b))))))
        double code(double a, double b, double c) {
        	double tmp;
        	if (b <= 0.28) {
        		tmp = (sqrt(((b * b) - ((3.0 * a) * c))) - b) / sqrt((pow(a, 2.0) * 9.0));
        	} else {
        		tmp = c * ((c * (a * ((-0.5625 * (a * (c / pow(b, 5.0)))) - (0.375 / pow(b, 3.0))))) + (0.5 * (-1.0 / b)));
        	}
        	return tmp;
        }
        
        real(8) function code(a, b, c)
            real(8), intent (in) :: a
            real(8), intent (in) :: b
            real(8), intent (in) :: c
            real(8) :: tmp
            if (b <= 0.28d0) then
                tmp = (sqrt(((b * b) - ((3.0d0 * a) * c))) - b) / sqrt(((a ** 2.0d0) * 9.0d0))
            else
                tmp = c * ((c * (a * (((-0.5625d0) * (a * (c / (b ** 5.0d0)))) - (0.375d0 / (b ** 3.0d0))))) + (0.5d0 * ((-1.0d0) / b)))
            end if
            code = tmp
        end function
        
        public static double code(double a, double b, double c) {
        	double tmp;
        	if (b <= 0.28) {
        		tmp = (Math.sqrt(((b * b) - ((3.0 * a) * c))) - b) / Math.sqrt((Math.pow(a, 2.0) * 9.0));
        	} else {
        		tmp = c * ((c * (a * ((-0.5625 * (a * (c / Math.pow(b, 5.0)))) - (0.375 / Math.pow(b, 3.0))))) + (0.5 * (-1.0 / b)));
        	}
        	return tmp;
        }
        
        def code(a, b, c):
        	tmp = 0
        	if b <= 0.28:
        		tmp = (math.sqrt(((b * b) - ((3.0 * a) * c))) - b) / math.sqrt((math.pow(a, 2.0) * 9.0))
        	else:
        		tmp = c * ((c * (a * ((-0.5625 * (a * (c / math.pow(b, 5.0)))) - (0.375 / math.pow(b, 3.0))))) + (0.5 * (-1.0 / b)))
        	return tmp
        
        function code(a, b, c)
        	tmp = 0.0
        	if (b <= 0.28)
        		tmp = Float64(Float64(sqrt(Float64(Float64(b * b) - Float64(Float64(3.0 * a) * c))) - b) / sqrt(Float64((a ^ 2.0) * 9.0)));
        	else
        		tmp = Float64(c * Float64(Float64(c * Float64(a * Float64(Float64(-0.5625 * Float64(a * Float64(c / (b ^ 5.0)))) - Float64(0.375 / (b ^ 3.0))))) + Float64(0.5 * Float64(-1.0 / b))));
        	end
        	return tmp
        end
        
        function tmp_2 = code(a, b, c)
        	tmp = 0.0;
        	if (b <= 0.28)
        		tmp = (sqrt(((b * b) - ((3.0 * a) * c))) - b) / sqrt(((a ^ 2.0) * 9.0));
        	else
        		tmp = c * ((c * (a * ((-0.5625 * (a * (c / (b ^ 5.0)))) - (0.375 / (b ^ 3.0))))) + (0.5 * (-1.0 / b)));
        	end
        	tmp_2 = tmp;
        end
        
        code[a_, b_, c_] := If[LessEqual[b, 0.28], N[(N[(N[Sqrt[N[(N[(b * b), $MachinePrecision] - N[(N[(3.0 * a), $MachinePrecision] * c), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] - b), $MachinePrecision] / N[Sqrt[N[(N[Power[a, 2.0], $MachinePrecision] * 9.0), $MachinePrecision]], $MachinePrecision]), $MachinePrecision], N[(c * N[(N[(c * N[(a * N[(N[(-0.5625 * N[(a * N[(c / N[Power[b, 5.0], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] - N[(0.375 / N[Power[b, 3.0], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] + N[(0.5 * N[(-1.0 / b), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]]
        
        \begin{array}{l}
        
        \\
        \begin{array}{l}
        \mathbf{if}\;b \leq 0.28:\\
        \;\;\;\;\frac{\sqrt{b \cdot b - \left(3 \cdot a\right) \cdot c} - b}{\sqrt{{a}^{2} \cdot 9}}\\
        
        \mathbf{else}:\\
        \;\;\;\;c \cdot \left(c \cdot \left(a \cdot \left(-0.5625 \cdot \left(a \cdot \frac{c}{{b}^{5}}\right) - \frac{0.375}{{b}^{3}}\right)\right) + 0.5 \cdot \frac{-1}{b}\right)\\
        
        
        \end{array}
        \end{array}
        
        Derivation
        1. Split input into 2 regimes
        2. if b < 0.28000000000000003

          1. Initial program 83.4%

            \[\frac{\left(-b\right) + \sqrt{b \cdot b - \left(3 \cdot a\right) \cdot c}}{3 \cdot a} \]
          2. Add Preprocessing
          3. Step-by-step derivation
            1. add-sqr-sqrt83.3%

              \[\leadsto \frac{\left(-b\right) + \sqrt{b \cdot b - \left(3 \cdot a\right) \cdot c}}{\color{blue}{\sqrt{3 \cdot a} \cdot \sqrt{3 \cdot a}}} \]
            2. sqrt-unprod83.4%

              \[\leadsto \frac{\left(-b\right) + \sqrt{b \cdot b - \left(3 \cdot a\right) \cdot c}}{\color{blue}{\sqrt{\left(3 \cdot a\right) \cdot \left(3 \cdot a\right)}}} \]
            3. *-commutative83.4%

              \[\leadsto \frac{\left(-b\right) + \sqrt{b \cdot b - \left(3 \cdot a\right) \cdot c}}{\sqrt{\color{blue}{\left(a \cdot 3\right)} \cdot \left(3 \cdot a\right)}} \]
            4. *-commutative83.4%

              \[\leadsto \frac{\left(-b\right) + \sqrt{b \cdot b - \left(3 \cdot a\right) \cdot c}}{\sqrt{\left(a \cdot 3\right) \cdot \color{blue}{\left(a \cdot 3\right)}}} \]
            5. swap-sqr83.4%

              \[\leadsto \frac{\left(-b\right) + \sqrt{b \cdot b - \left(3 \cdot a\right) \cdot c}}{\sqrt{\color{blue}{\left(a \cdot a\right) \cdot \left(3 \cdot 3\right)}}} \]
            6. pow283.4%

              \[\leadsto \frac{\left(-b\right) + \sqrt{b \cdot b - \left(3 \cdot a\right) \cdot c}}{\sqrt{\color{blue}{{a}^{2}} \cdot \left(3 \cdot 3\right)}} \]
            7. metadata-eval83.4%

              \[\leadsto \frac{\left(-b\right) + \sqrt{b \cdot b - \left(3 \cdot a\right) \cdot c}}{\sqrt{{a}^{2} \cdot \color{blue}{9}}} \]
          4. Applied egg-rr83.4%

            \[\leadsto \frac{\left(-b\right) + \sqrt{b \cdot b - \left(3 \cdot a\right) \cdot c}}{\color{blue}{\sqrt{{a}^{2} \cdot 9}}} \]

          if 0.28000000000000003 < b

          1. Initial program 49.4%

            \[\frac{\left(-b\right) + \sqrt{b \cdot b - \left(3 \cdot a\right) \cdot c}}{3 \cdot a} \]
          2. Step-by-step derivation
            1. Simplified49.5%

              \[\leadsto \color{blue}{\frac{\sqrt{\mathsf{fma}\left(b, b, a \cdot \left(c \cdot -3\right)\right)} - b}{3 \cdot a}} \]
            2. Add Preprocessing
            3. Taylor expanded in c around 0 92.2%

              \[\leadsto \color{blue}{c \cdot \left(c \cdot \left(-0.5625 \cdot \frac{{a}^{2} \cdot c}{{b}^{5}} + -0.375 \cdot \frac{a}{{b}^{3}}\right) - 0.5 \cdot \frac{1}{b}\right)} \]
            4. Taylor expanded in a around 0 92.2%

              \[\leadsto c \cdot \left(c \cdot \color{blue}{\left(a \cdot \left(-0.5625 \cdot \frac{a \cdot c}{{b}^{5}} - 0.375 \cdot \frac{1}{{b}^{3}}\right)\right)} - 0.5 \cdot \frac{1}{b}\right) \]
            5. Step-by-step derivation
              1. associate-/l*92.2%

                \[\leadsto c \cdot \left(c \cdot \left(a \cdot \left(-0.5625 \cdot \color{blue}{\left(a \cdot \frac{c}{{b}^{5}}\right)} - 0.375 \cdot \frac{1}{{b}^{3}}\right)\right) - 0.5 \cdot \frac{1}{b}\right) \]
              2. associate-*r/92.2%

                \[\leadsto c \cdot \left(c \cdot \left(a \cdot \left(-0.5625 \cdot \left(a \cdot \frac{c}{{b}^{5}}\right) - \color{blue}{\frac{0.375 \cdot 1}{{b}^{3}}}\right)\right) - 0.5 \cdot \frac{1}{b}\right) \]
              3. metadata-eval92.2%

                \[\leadsto c \cdot \left(c \cdot \left(a \cdot \left(-0.5625 \cdot \left(a \cdot \frac{c}{{b}^{5}}\right) - \frac{\color{blue}{0.375}}{{b}^{3}}\right)\right) - 0.5 \cdot \frac{1}{b}\right) \]
            6. Simplified92.2%

              \[\leadsto c \cdot \left(c \cdot \color{blue}{\left(a \cdot \left(-0.5625 \cdot \left(a \cdot \frac{c}{{b}^{5}}\right) - \frac{0.375}{{b}^{3}}\right)\right)} - 0.5 \cdot \frac{1}{b}\right) \]
          3. Recombined 2 regimes into one program.
          4. Final simplification90.9%

            \[\leadsto \begin{array}{l} \mathbf{if}\;b \leq 0.28:\\ \;\;\;\;\frac{\sqrt{b \cdot b - \left(3 \cdot a\right) \cdot c} - b}{\sqrt{{a}^{2} \cdot 9}}\\ \mathbf{else}:\\ \;\;\;\;c \cdot \left(c \cdot \left(a \cdot \left(-0.5625 \cdot \left(a \cdot \frac{c}{{b}^{5}}\right) - \frac{0.375}{{b}^{3}}\right)\right) + 0.5 \cdot \frac{-1}{b}\right)\\ \end{array} \]
          5. Add Preprocessing

          Alternative 4: 88.9% accurate, 0.4× speedup?

          \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;b \leq 0.28:\\ \;\;\;\;0.3333333333333333 \cdot \frac{\mathsf{fma}\left(-1, b, \sqrt{\mathsf{fma}\left(b, b, -3 \cdot \left(a \cdot c\right)\right)}\right)}{a}\\ \mathbf{else}:\\ \;\;\;\;c \cdot \left(c \cdot \left(a \cdot \left(-0.5625 \cdot \left(a \cdot \frac{c}{{b}^{5}}\right) - \frac{0.375}{{b}^{3}}\right)\right) + 0.5 \cdot \frac{-1}{b}\right)\\ \end{array} \end{array} \]
          (FPCore (a b c)
           :precision binary64
           (if (<= b 0.28)
             (* 0.3333333333333333 (/ (fma -1.0 b (sqrt (fma b b (* -3.0 (* a c))))) a))
             (*
              c
              (+
               (* c (* a (- (* -0.5625 (* a (/ c (pow b 5.0)))) (/ 0.375 (pow b 3.0)))))
               (* 0.5 (/ -1.0 b))))))
          double code(double a, double b, double c) {
          	double tmp;
          	if (b <= 0.28) {
          		tmp = 0.3333333333333333 * (fma(-1.0, b, sqrt(fma(b, b, (-3.0 * (a * c))))) / a);
          	} else {
          		tmp = c * ((c * (a * ((-0.5625 * (a * (c / pow(b, 5.0)))) - (0.375 / pow(b, 3.0))))) + (0.5 * (-1.0 / b)));
          	}
          	return tmp;
          }
          
          function code(a, b, c)
          	tmp = 0.0
          	if (b <= 0.28)
          		tmp = Float64(0.3333333333333333 * Float64(fma(-1.0, b, sqrt(fma(b, b, Float64(-3.0 * Float64(a * c))))) / a));
          	else
          		tmp = Float64(c * Float64(Float64(c * Float64(a * Float64(Float64(-0.5625 * Float64(a * Float64(c / (b ^ 5.0)))) - Float64(0.375 / (b ^ 3.0))))) + Float64(0.5 * Float64(-1.0 / b))));
          	end
          	return tmp
          end
          
          code[a_, b_, c_] := If[LessEqual[b, 0.28], N[(0.3333333333333333 * N[(N[(-1.0 * b + N[Sqrt[N[(b * b + N[(-3.0 * N[(a * c), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] / a), $MachinePrecision]), $MachinePrecision], N[(c * N[(N[(c * N[(a * N[(N[(-0.5625 * N[(a * N[(c / N[Power[b, 5.0], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] - N[(0.375 / N[Power[b, 3.0], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] + N[(0.5 * N[(-1.0 / b), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]]
          
          \begin{array}{l}
          
          \\
          \begin{array}{l}
          \mathbf{if}\;b \leq 0.28:\\
          \;\;\;\;0.3333333333333333 \cdot \frac{\mathsf{fma}\left(-1, b, \sqrt{\mathsf{fma}\left(b, b, -3 \cdot \left(a \cdot c\right)\right)}\right)}{a}\\
          
          \mathbf{else}:\\
          \;\;\;\;c \cdot \left(c \cdot \left(a \cdot \left(-0.5625 \cdot \left(a \cdot \frac{c}{{b}^{5}}\right) - \frac{0.375}{{b}^{3}}\right)\right) + 0.5 \cdot \frac{-1}{b}\right)\\
          
          
          \end{array}
          \end{array}
          
          Derivation
          1. Split input into 2 regimes
          2. if b < 0.28000000000000003

            1. Initial program 83.4%

              \[\frac{\left(-b\right) + \sqrt{b \cdot b - \left(3 \cdot a\right) \cdot c}}{3 \cdot a} \]
            2. Add Preprocessing
            3. Step-by-step derivation
              1. add-sqr-sqrt83.3%

                \[\leadsto \frac{\left(-b\right) + \sqrt{b \cdot b - \left(3 \cdot a\right) \cdot c}}{\color{blue}{\sqrt{3 \cdot a} \cdot \sqrt{3 \cdot a}}} \]
              2. pow283.3%

                \[\leadsto \frac{\left(-b\right) + \sqrt{b \cdot b - \left(3 \cdot a\right) \cdot c}}{\color{blue}{{\left(\sqrt{3 \cdot a}\right)}^{2}}} \]
            4. Applied egg-rr83.3%

              \[\leadsto \frac{\left(-b\right) + \sqrt{b \cdot b - \left(3 \cdot a\right) \cdot c}}{\color{blue}{{\left(\sqrt{3 \cdot a}\right)}^{2}}} \]
            5. Step-by-step derivation
              1. unpow283.3%

                \[\leadsto \frac{\left(-b\right) + \sqrt{b \cdot b - \left(3 \cdot a\right) \cdot c}}{\color{blue}{\sqrt{3 \cdot a} \cdot \sqrt{3 \cdot a}}} \]
              2. add-sqr-sqrt83.4%

                \[\leadsto \frac{\left(-b\right) + \sqrt{b \cdot b - \left(3 \cdot a\right) \cdot c}}{\color{blue}{3 \cdot a}} \]
              3. div-inv83.4%

                \[\leadsto \color{blue}{\left(\left(-b\right) + \sqrt{b \cdot b - \left(3 \cdot a\right) \cdot c}\right) \cdot \frac{1}{3 \cdot a}} \]
              4. neg-mul-183.4%

                \[\leadsto \left(\color{blue}{-1 \cdot b} + \sqrt{b \cdot b - \left(3 \cdot a\right) \cdot c}\right) \cdot \frac{1}{3 \cdot a} \]
              5. fma-define83.4%

                \[\leadsto \color{blue}{\mathsf{fma}\left(-1, b, \sqrt{b \cdot b - \left(3 \cdot a\right) \cdot c}\right)} \cdot \frac{1}{3 \cdot a} \]
              6. pow283.4%

                \[\leadsto \mathsf{fma}\left(-1, b, \sqrt{\color{blue}{{b}^{2}} - \left(3 \cdot a\right) \cdot c}\right) \cdot \frac{1}{3 \cdot a} \]
              7. associate-*l*83.4%

                \[\leadsto \mathsf{fma}\left(-1, b, \sqrt{{b}^{2} - \color{blue}{3 \cdot \left(a \cdot c\right)}}\right) \cdot \frac{1}{3 \cdot a} \]
              8. *-commutative83.4%

                \[\leadsto \mathsf{fma}\left(-1, b, \sqrt{{b}^{2} - 3 \cdot \left(a \cdot c\right)}\right) \cdot \frac{1}{\color{blue}{a \cdot 3}} \]
            6. Applied egg-rr83.4%

              \[\leadsto \color{blue}{\mathsf{fma}\left(-1, b, \sqrt{{b}^{2} - 3 \cdot \left(a \cdot c\right)}\right) \cdot \frac{1}{a \cdot 3}} \]
            7. Step-by-step derivation
              1. associate-*r/83.4%

                \[\leadsto \color{blue}{\frac{\mathsf{fma}\left(-1, b, \sqrt{{b}^{2} - 3 \cdot \left(a \cdot c\right)}\right) \cdot 1}{a \cdot 3}} \]
              2. *-commutative83.4%

                \[\leadsto \frac{\mathsf{fma}\left(-1, b, \sqrt{{b}^{2} - 3 \cdot \left(a \cdot c\right)}\right) \cdot 1}{\color{blue}{3 \cdot a}} \]
              3. *-rgt-identity83.4%

                \[\leadsto \frac{\color{blue}{\mathsf{fma}\left(-1, b, \sqrt{{b}^{2} - 3 \cdot \left(a \cdot c\right)}\right)}}{3 \cdot a} \]
              4. *-lft-identity83.4%

                \[\leadsto \frac{\color{blue}{1 \cdot \mathsf{fma}\left(-1, b, \sqrt{{b}^{2} - 3 \cdot \left(a \cdot c\right)}\right)}}{3 \cdot a} \]
              5. times-frac83.5%

                \[\leadsto \color{blue}{\frac{1}{3} \cdot \frac{\mathsf{fma}\left(-1, b, \sqrt{{b}^{2} - 3 \cdot \left(a \cdot c\right)}\right)}{a}} \]
              6. metadata-eval83.5%

                \[\leadsto \color{blue}{0.3333333333333333} \cdot \frac{\mathsf{fma}\left(-1, b, \sqrt{{b}^{2} - 3 \cdot \left(a \cdot c\right)}\right)}{a} \]
              7. unpow283.5%

                \[\leadsto 0.3333333333333333 \cdot \frac{\mathsf{fma}\left(-1, b, \sqrt{\color{blue}{b \cdot b} - 3 \cdot \left(a \cdot c\right)}\right)}{a} \]
              8. fmm-def83.4%

                \[\leadsto 0.3333333333333333 \cdot \frac{\mathsf{fma}\left(-1, b, \sqrt{\color{blue}{\mathsf{fma}\left(b, b, -3 \cdot \left(a \cdot c\right)\right)}}\right)}{a} \]
              9. *-commutative83.4%

                \[\leadsto 0.3333333333333333 \cdot \frac{\mathsf{fma}\left(-1, b, \sqrt{\mathsf{fma}\left(b, b, -\color{blue}{\left(a \cdot c\right) \cdot 3}\right)}\right)}{a} \]
              10. distribute-rgt-neg-in83.4%

                \[\leadsto 0.3333333333333333 \cdot \frac{\mathsf{fma}\left(-1, b, \sqrt{\mathsf{fma}\left(b, b, \color{blue}{\left(a \cdot c\right) \cdot \left(-3\right)}\right)}\right)}{a} \]
              11. metadata-eval83.4%

                \[\leadsto 0.3333333333333333 \cdot \frac{\mathsf{fma}\left(-1, b, \sqrt{\mathsf{fma}\left(b, b, \left(a \cdot c\right) \cdot \color{blue}{-3}\right)}\right)}{a} \]
            8. Simplified83.4%

              \[\leadsto \color{blue}{0.3333333333333333 \cdot \frac{\mathsf{fma}\left(-1, b, \sqrt{\mathsf{fma}\left(b, b, \left(a \cdot c\right) \cdot -3\right)}\right)}{a}} \]

            if 0.28000000000000003 < b

            1. Initial program 49.4%

              \[\frac{\left(-b\right) + \sqrt{b \cdot b - \left(3 \cdot a\right) \cdot c}}{3 \cdot a} \]
            2. Step-by-step derivation
              1. Simplified49.5%

                \[\leadsto \color{blue}{\frac{\sqrt{\mathsf{fma}\left(b, b, a \cdot \left(c \cdot -3\right)\right)} - b}{3 \cdot a}} \]
              2. Add Preprocessing
              3. Taylor expanded in c around 0 92.2%

                \[\leadsto \color{blue}{c \cdot \left(c \cdot \left(-0.5625 \cdot \frac{{a}^{2} \cdot c}{{b}^{5}} + -0.375 \cdot \frac{a}{{b}^{3}}\right) - 0.5 \cdot \frac{1}{b}\right)} \]
              4. Taylor expanded in a around 0 92.2%

                \[\leadsto c \cdot \left(c \cdot \color{blue}{\left(a \cdot \left(-0.5625 \cdot \frac{a \cdot c}{{b}^{5}} - 0.375 \cdot \frac{1}{{b}^{3}}\right)\right)} - 0.5 \cdot \frac{1}{b}\right) \]
              5. Step-by-step derivation
                1. associate-/l*92.2%

                  \[\leadsto c \cdot \left(c \cdot \left(a \cdot \left(-0.5625 \cdot \color{blue}{\left(a \cdot \frac{c}{{b}^{5}}\right)} - 0.375 \cdot \frac{1}{{b}^{3}}\right)\right) - 0.5 \cdot \frac{1}{b}\right) \]
                2. associate-*r/92.2%

                  \[\leadsto c \cdot \left(c \cdot \left(a \cdot \left(-0.5625 \cdot \left(a \cdot \frac{c}{{b}^{5}}\right) - \color{blue}{\frac{0.375 \cdot 1}{{b}^{3}}}\right)\right) - 0.5 \cdot \frac{1}{b}\right) \]
                3. metadata-eval92.2%

                  \[\leadsto c \cdot \left(c \cdot \left(a \cdot \left(-0.5625 \cdot \left(a \cdot \frac{c}{{b}^{5}}\right) - \frac{\color{blue}{0.375}}{{b}^{3}}\right)\right) - 0.5 \cdot \frac{1}{b}\right) \]
              6. Simplified92.2%

                \[\leadsto c \cdot \left(c \cdot \color{blue}{\left(a \cdot \left(-0.5625 \cdot \left(a \cdot \frac{c}{{b}^{5}}\right) - \frac{0.375}{{b}^{3}}\right)\right)} - 0.5 \cdot \frac{1}{b}\right) \]
            3. Recombined 2 regimes into one program.
            4. Final simplification90.9%

              \[\leadsto \begin{array}{l} \mathbf{if}\;b \leq 0.28:\\ \;\;\;\;0.3333333333333333 \cdot \frac{\mathsf{fma}\left(-1, b, \sqrt{\mathsf{fma}\left(b, b, -3 \cdot \left(a \cdot c\right)\right)}\right)}{a}\\ \mathbf{else}:\\ \;\;\;\;c \cdot \left(c \cdot \left(a \cdot \left(-0.5625 \cdot \left(a \cdot \frac{c}{{b}^{5}}\right) - \frac{0.375}{{b}^{3}}\right)\right) + 0.5 \cdot \frac{-1}{b}\right)\\ \end{array} \]
            5. Add Preprocessing

            Alternative 5: 88.9% accurate, 0.5× speedup?

            \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;b \leq 0.28:\\ \;\;\;\;\frac{\sqrt{b \cdot b - \left(3 \cdot a\right) \cdot c} - b}{3 \cdot a}\\ \mathbf{else}:\\ \;\;\;\;c \cdot \left(c \cdot \left(a \cdot \left(-0.5625 \cdot \left(a \cdot \frac{c}{{b}^{5}}\right) - \frac{0.375}{{b}^{3}}\right)\right) + 0.5 \cdot \frac{-1}{b}\right)\\ \end{array} \end{array} \]
            (FPCore (a b c)
             :precision binary64
             (if (<= b 0.28)
               (/ (- (sqrt (- (* b b) (* (* 3.0 a) c))) b) (* 3.0 a))
               (*
                c
                (+
                 (* c (* a (- (* -0.5625 (* a (/ c (pow b 5.0)))) (/ 0.375 (pow b 3.0)))))
                 (* 0.5 (/ -1.0 b))))))
            double code(double a, double b, double c) {
            	double tmp;
            	if (b <= 0.28) {
            		tmp = (sqrt(((b * b) - ((3.0 * a) * c))) - b) / (3.0 * a);
            	} else {
            		tmp = c * ((c * (a * ((-0.5625 * (a * (c / pow(b, 5.0)))) - (0.375 / pow(b, 3.0))))) + (0.5 * (-1.0 / b)));
            	}
            	return tmp;
            }
            
            real(8) function code(a, b, c)
                real(8), intent (in) :: a
                real(8), intent (in) :: b
                real(8), intent (in) :: c
                real(8) :: tmp
                if (b <= 0.28d0) then
                    tmp = (sqrt(((b * b) - ((3.0d0 * a) * c))) - b) / (3.0d0 * a)
                else
                    tmp = c * ((c * (a * (((-0.5625d0) * (a * (c / (b ** 5.0d0)))) - (0.375d0 / (b ** 3.0d0))))) + (0.5d0 * ((-1.0d0) / b)))
                end if
                code = tmp
            end function
            
            public static double code(double a, double b, double c) {
            	double tmp;
            	if (b <= 0.28) {
            		tmp = (Math.sqrt(((b * b) - ((3.0 * a) * c))) - b) / (3.0 * a);
            	} else {
            		tmp = c * ((c * (a * ((-0.5625 * (a * (c / Math.pow(b, 5.0)))) - (0.375 / Math.pow(b, 3.0))))) + (0.5 * (-1.0 / b)));
            	}
            	return tmp;
            }
            
            def code(a, b, c):
            	tmp = 0
            	if b <= 0.28:
            		tmp = (math.sqrt(((b * b) - ((3.0 * a) * c))) - b) / (3.0 * a)
            	else:
            		tmp = c * ((c * (a * ((-0.5625 * (a * (c / math.pow(b, 5.0)))) - (0.375 / math.pow(b, 3.0))))) + (0.5 * (-1.0 / b)))
            	return tmp
            
            function code(a, b, c)
            	tmp = 0.0
            	if (b <= 0.28)
            		tmp = Float64(Float64(sqrt(Float64(Float64(b * b) - Float64(Float64(3.0 * a) * c))) - b) / Float64(3.0 * a));
            	else
            		tmp = Float64(c * Float64(Float64(c * Float64(a * Float64(Float64(-0.5625 * Float64(a * Float64(c / (b ^ 5.0)))) - Float64(0.375 / (b ^ 3.0))))) + Float64(0.5 * Float64(-1.0 / b))));
            	end
            	return tmp
            end
            
            function tmp_2 = code(a, b, c)
            	tmp = 0.0;
            	if (b <= 0.28)
            		tmp = (sqrt(((b * b) - ((3.0 * a) * c))) - b) / (3.0 * a);
            	else
            		tmp = c * ((c * (a * ((-0.5625 * (a * (c / (b ^ 5.0)))) - (0.375 / (b ^ 3.0))))) + (0.5 * (-1.0 / b)));
            	end
            	tmp_2 = tmp;
            end
            
            code[a_, b_, c_] := If[LessEqual[b, 0.28], N[(N[(N[Sqrt[N[(N[(b * b), $MachinePrecision] - N[(N[(3.0 * a), $MachinePrecision] * c), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] - b), $MachinePrecision] / N[(3.0 * a), $MachinePrecision]), $MachinePrecision], N[(c * N[(N[(c * N[(a * N[(N[(-0.5625 * N[(a * N[(c / N[Power[b, 5.0], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] - N[(0.375 / N[Power[b, 3.0], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] + N[(0.5 * N[(-1.0 / b), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]]
            
            \begin{array}{l}
            
            \\
            \begin{array}{l}
            \mathbf{if}\;b \leq 0.28:\\
            \;\;\;\;\frac{\sqrt{b \cdot b - \left(3 \cdot a\right) \cdot c} - b}{3 \cdot a}\\
            
            \mathbf{else}:\\
            \;\;\;\;c \cdot \left(c \cdot \left(a \cdot \left(-0.5625 \cdot \left(a \cdot \frac{c}{{b}^{5}}\right) - \frac{0.375}{{b}^{3}}\right)\right) + 0.5 \cdot \frac{-1}{b}\right)\\
            
            
            \end{array}
            \end{array}
            
            Derivation
            1. Split input into 2 regimes
            2. if b < 0.28000000000000003

              1. Initial program 83.4%

                \[\frac{\left(-b\right) + \sqrt{b \cdot b - \left(3 \cdot a\right) \cdot c}}{3 \cdot a} \]
              2. Add Preprocessing

              if 0.28000000000000003 < b

              1. Initial program 49.4%

                \[\frac{\left(-b\right) + \sqrt{b \cdot b - \left(3 \cdot a\right) \cdot c}}{3 \cdot a} \]
              2. Step-by-step derivation
                1. Simplified49.5%

                  \[\leadsto \color{blue}{\frac{\sqrt{\mathsf{fma}\left(b, b, a \cdot \left(c \cdot -3\right)\right)} - b}{3 \cdot a}} \]
                2. Add Preprocessing
                3. Taylor expanded in c around 0 92.2%

                  \[\leadsto \color{blue}{c \cdot \left(c \cdot \left(-0.5625 \cdot \frac{{a}^{2} \cdot c}{{b}^{5}} + -0.375 \cdot \frac{a}{{b}^{3}}\right) - 0.5 \cdot \frac{1}{b}\right)} \]
                4. Taylor expanded in a around 0 92.2%

                  \[\leadsto c \cdot \left(c \cdot \color{blue}{\left(a \cdot \left(-0.5625 \cdot \frac{a \cdot c}{{b}^{5}} - 0.375 \cdot \frac{1}{{b}^{3}}\right)\right)} - 0.5 \cdot \frac{1}{b}\right) \]
                5. Step-by-step derivation
                  1. associate-/l*92.2%

                    \[\leadsto c \cdot \left(c \cdot \left(a \cdot \left(-0.5625 \cdot \color{blue}{\left(a \cdot \frac{c}{{b}^{5}}\right)} - 0.375 \cdot \frac{1}{{b}^{3}}\right)\right) - 0.5 \cdot \frac{1}{b}\right) \]
                  2. associate-*r/92.2%

                    \[\leadsto c \cdot \left(c \cdot \left(a \cdot \left(-0.5625 \cdot \left(a \cdot \frac{c}{{b}^{5}}\right) - \color{blue}{\frac{0.375 \cdot 1}{{b}^{3}}}\right)\right) - 0.5 \cdot \frac{1}{b}\right) \]
                  3. metadata-eval92.2%

                    \[\leadsto c \cdot \left(c \cdot \left(a \cdot \left(-0.5625 \cdot \left(a \cdot \frac{c}{{b}^{5}}\right) - \frac{\color{blue}{0.375}}{{b}^{3}}\right)\right) - 0.5 \cdot \frac{1}{b}\right) \]
                6. Simplified92.2%

                  \[\leadsto c \cdot \left(c \cdot \color{blue}{\left(a \cdot \left(-0.5625 \cdot \left(a \cdot \frac{c}{{b}^{5}}\right) - \frac{0.375}{{b}^{3}}\right)\right)} - 0.5 \cdot \frac{1}{b}\right) \]
              3. Recombined 2 regimes into one program.
              4. Final simplification90.9%

                \[\leadsto \begin{array}{l} \mathbf{if}\;b \leq 0.28:\\ \;\;\;\;\frac{\sqrt{b \cdot b - \left(3 \cdot a\right) \cdot c} - b}{3 \cdot a}\\ \mathbf{else}:\\ \;\;\;\;c \cdot \left(c \cdot \left(a \cdot \left(-0.5625 \cdot \left(a \cdot \frac{c}{{b}^{5}}\right) - \frac{0.375}{{b}^{3}}\right)\right) + 0.5 \cdot \frac{-1}{b}\right)\\ \end{array} \]
              5. Add Preprocessing

              Alternative 6: 84.4% accurate, 0.5× speedup?

              \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;b \leq 0.28:\\ \;\;\;\;\frac{\sqrt{b \cdot b - \left(3 \cdot a\right) \cdot c} - b}{3 \cdot a}\\ \mathbf{else}:\\ \;\;\;\;-0.5 \cdot \frac{c}{b} + -0.375 \cdot \frac{a \cdot {c}^{2}}{{b}^{3}}\\ \end{array} \end{array} \]
              (FPCore (a b c)
               :precision binary64
               (if (<= b 0.28)
                 (/ (- (sqrt (- (* b b) (* (* 3.0 a) c))) b) (* 3.0 a))
                 (+ (* -0.5 (/ c b)) (* -0.375 (/ (* a (pow c 2.0)) (pow b 3.0))))))
              double code(double a, double b, double c) {
              	double tmp;
              	if (b <= 0.28) {
              		tmp = (sqrt(((b * b) - ((3.0 * a) * c))) - b) / (3.0 * a);
              	} else {
              		tmp = (-0.5 * (c / b)) + (-0.375 * ((a * pow(c, 2.0)) / pow(b, 3.0)));
              	}
              	return tmp;
              }
              
              real(8) function code(a, b, c)
                  real(8), intent (in) :: a
                  real(8), intent (in) :: b
                  real(8), intent (in) :: c
                  real(8) :: tmp
                  if (b <= 0.28d0) then
                      tmp = (sqrt(((b * b) - ((3.0d0 * a) * c))) - b) / (3.0d0 * a)
                  else
                      tmp = ((-0.5d0) * (c / b)) + ((-0.375d0) * ((a * (c ** 2.0d0)) / (b ** 3.0d0)))
                  end if
                  code = tmp
              end function
              
              public static double code(double a, double b, double c) {
              	double tmp;
              	if (b <= 0.28) {
              		tmp = (Math.sqrt(((b * b) - ((3.0 * a) * c))) - b) / (3.0 * a);
              	} else {
              		tmp = (-0.5 * (c / b)) + (-0.375 * ((a * Math.pow(c, 2.0)) / Math.pow(b, 3.0)));
              	}
              	return tmp;
              }
              
              def code(a, b, c):
              	tmp = 0
              	if b <= 0.28:
              		tmp = (math.sqrt(((b * b) - ((3.0 * a) * c))) - b) / (3.0 * a)
              	else:
              		tmp = (-0.5 * (c / b)) + (-0.375 * ((a * math.pow(c, 2.0)) / math.pow(b, 3.0)))
              	return tmp
              
              function code(a, b, c)
              	tmp = 0.0
              	if (b <= 0.28)
              		tmp = Float64(Float64(sqrt(Float64(Float64(b * b) - Float64(Float64(3.0 * a) * c))) - b) / Float64(3.0 * a));
              	else
              		tmp = Float64(Float64(-0.5 * Float64(c / b)) + Float64(-0.375 * Float64(Float64(a * (c ^ 2.0)) / (b ^ 3.0))));
              	end
              	return tmp
              end
              
              function tmp_2 = code(a, b, c)
              	tmp = 0.0;
              	if (b <= 0.28)
              		tmp = (sqrt(((b * b) - ((3.0 * a) * c))) - b) / (3.0 * a);
              	else
              		tmp = (-0.5 * (c / b)) + (-0.375 * ((a * (c ^ 2.0)) / (b ^ 3.0)));
              	end
              	tmp_2 = tmp;
              end
              
              code[a_, b_, c_] := If[LessEqual[b, 0.28], N[(N[(N[Sqrt[N[(N[(b * b), $MachinePrecision] - N[(N[(3.0 * a), $MachinePrecision] * c), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] - b), $MachinePrecision] / N[(3.0 * a), $MachinePrecision]), $MachinePrecision], N[(N[(-0.5 * N[(c / b), $MachinePrecision]), $MachinePrecision] + N[(-0.375 * N[(N[(a * N[Power[c, 2.0], $MachinePrecision]), $MachinePrecision] / N[Power[b, 3.0], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]]
              
              \begin{array}{l}
              
              \\
              \begin{array}{l}
              \mathbf{if}\;b \leq 0.28:\\
              \;\;\;\;\frac{\sqrt{b \cdot b - \left(3 \cdot a\right) \cdot c} - b}{3 \cdot a}\\
              
              \mathbf{else}:\\
              \;\;\;\;-0.5 \cdot \frac{c}{b} + -0.375 \cdot \frac{a \cdot {c}^{2}}{{b}^{3}}\\
              
              
              \end{array}
              \end{array}
              
              Derivation
              1. Split input into 2 regimes
              2. if b < 0.28000000000000003

                1. Initial program 83.4%

                  \[\frac{\left(-b\right) + \sqrt{b \cdot b - \left(3 \cdot a\right) \cdot c}}{3 \cdot a} \]
                2. Add Preprocessing

                if 0.28000000000000003 < b

                1. Initial program 49.4%

                  \[\frac{\left(-b\right) + \sqrt{b \cdot b - \left(3 \cdot a\right) \cdot c}}{3 \cdot a} \]
                2. Step-by-step derivation
                  1. Simplified49.5%

                    \[\leadsto \color{blue}{\frac{\sqrt{\mathsf{fma}\left(b, b, a \cdot \left(c \cdot -3\right)\right)} - b}{3 \cdot a}} \]
                  2. Add Preprocessing
                  3. Taylor expanded in a around 0 87.1%

                    \[\leadsto \color{blue}{-0.5 \cdot \frac{c}{b} + -0.375 \cdot \frac{a \cdot {c}^{2}}{{b}^{3}}} \]
                3. Recombined 2 regimes into one program.
                4. Final simplification86.6%

                  \[\leadsto \begin{array}{l} \mathbf{if}\;b \leq 0.28:\\ \;\;\;\;\frac{\sqrt{b \cdot b - \left(3 \cdot a\right) \cdot c} - b}{3 \cdot a}\\ \mathbf{else}:\\ \;\;\;\;-0.5 \cdot \frac{c}{b} + -0.375 \cdot \frac{a \cdot {c}^{2}}{{b}^{3}}\\ \end{array} \]
                5. Add Preprocessing

                Alternative 7: 84.4% accurate, 0.5× speedup?

                \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;b \leq 0.34:\\ \;\;\;\;\frac{\sqrt{b \cdot b - \left(3 \cdot a\right) \cdot c} - b}{3 \cdot a}\\ \mathbf{else}:\\ \;\;\;\;\frac{\mathsf{fma}\left(c, -0.5, -0.375 \cdot \left(a \cdot {\left(\frac{c}{b}\right)}^{2}\right)\right)}{b}\\ \end{array} \end{array} \]
                (FPCore (a b c)
                 :precision binary64
                 (if (<= b 0.34)
                   (/ (- (sqrt (- (* b b) (* (* 3.0 a) c))) b) (* 3.0 a))
                   (/ (fma c -0.5 (* -0.375 (* a (pow (/ c b) 2.0)))) b)))
                double code(double a, double b, double c) {
                	double tmp;
                	if (b <= 0.34) {
                		tmp = (sqrt(((b * b) - ((3.0 * a) * c))) - b) / (3.0 * a);
                	} else {
                		tmp = fma(c, -0.5, (-0.375 * (a * pow((c / b), 2.0)))) / b;
                	}
                	return tmp;
                }
                
                function code(a, b, c)
                	tmp = 0.0
                	if (b <= 0.34)
                		tmp = Float64(Float64(sqrt(Float64(Float64(b * b) - Float64(Float64(3.0 * a) * c))) - b) / Float64(3.0 * a));
                	else
                		tmp = Float64(fma(c, -0.5, Float64(-0.375 * Float64(a * (Float64(c / b) ^ 2.0)))) / b);
                	end
                	return tmp
                end
                
                code[a_, b_, c_] := If[LessEqual[b, 0.34], N[(N[(N[Sqrt[N[(N[(b * b), $MachinePrecision] - N[(N[(3.0 * a), $MachinePrecision] * c), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] - b), $MachinePrecision] / N[(3.0 * a), $MachinePrecision]), $MachinePrecision], N[(N[(c * -0.5 + N[(-0.375 * N[(a * N[Power[N[(c / b), $MachinePrecision], 2.0], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] / b), $MachinePrecision]]
                
                \begin{array}{l}
                
                \\
                \begin{array}{l}
                \mathbf{if}\;b \leq 0.34:\\
                \;\;\;\;\frac{\sqrt{b \cdot b - \left(3 \cdot a\right) \cdot c} - b}{3 \cdot a}\\
                
                \mathbf{else}:\\
                \;\;\;\;\frac{\mathsf{fma}\left(c, -0.5, -0.375 \cdot \left(a \cdot {\left(\frac{c}{b}\right)}^{2}\right)\right)}{b}\\
                
                
                \end{array}
                \end{array}
                
                Derivation
                1. Split input into 2 regimes
                2. if b < 0.340000000000000024

                  1. Initial program 83.4%

                    \[\frac{\left(-b\right) + \sqrt{b \cdot b - \left(3 \cdot a\right) \cdot c}}{3 \cdot a} \]
                  2. Add Preprocessing

                  if 0.340000000000000024 < b

                  1. Initial program 49.4%

                    \[\frac{\left(-b\right) + \sqrt{b \cdot b - \left(3 \cdot a\right) \cdot c}}{3 \cdot a} \]
                  2. Step-by-step derivation
                    1. Simplified49.5%

                      \[\leadsto \color{blue}{\frac{\sqrt{\mathsf{fma}\left(b, b, a \cdot \left(c \cdot -3\right)\right)} - b}{3 \cdot a}} \]
                    2. Add Preprocessing
                    3. Taylor expanded in a around 0 86.8%

                      \[\leadsto \frac{\color{blue}{a \cdot \left(-1.5 \cdot \frac{c}{b} + -1.125 \cdot \frac{a \cdot {c}^{2}}{{b}^{3}}\right)}}{3 \cdot a} \]
                    4. Taylor expanded in b around inf 87.1%

                      \[\leadsto \color{blue}{\frac{-0.5 \cdot c + -0.375 \cdot \frac{a \cdot {c}^{2}}{{b}^{2}}}{b}} \]
                    5. Step-by-step derivation
                      1. *-commutative87.1%

                        \[\leadsto \frac{\color{blue}{c \cdot -0.5} + -0.375 \cdot \frac{a \cdot {c}^{2}}{{b}^{2}}}{b} \]
                      2. fma-define87.1%

                        \[\leadsto \frac{\color{blue}{\mathsf{fma}\left(c, -0.5, -0.375 \cdot \frac{a \cdot {c}^{2}}{{b}^{2}}\right)}}{b} \]
                      3. associate-/l*87.1%

                        \[\leadsto \frac{\mathsf{fma}\left(c, -0.5, -0.375 \cdot \color{blue}{\left(a \cdot \frac{{c}^{2}}{{b}^{2}}\right)}\right)}{b} \]
                      4. unpow287.1%

                        \[\leadsto \frac{\mathsf{fma}\left(c, -0.5, -0.375 \cdot \left(a \cdot \frac{\color{blue}{c \cdot c}}{{b}^{2}}\right)\right)}{b} \]
                      5. unpow287.1%

                        \[\leadsto \frac{\mathsf{fma}\left(c, -0.5, -0.375 \cdot \left(a \cdot \frac{c \cdot c}{\color{blue}{b \cdot b}}\right)\right)}{b} \]
                      6. times-frac87.1%

                        \[\leadsto \frac{\mathsf{fma}\left(c, -0.5, -0.375 \cdot \left(a \cdot \color{blue}{\left(\frac{c}{b} \cdot \frac{c}{b}\right)}\right)\right)}{b} \]
                      7. unpow287.1%

                        \[\leadsto \frac{\mathsf{fma}\left(c, -0.5, -0.375 \cdot \left(a \cdot \color{blue}{{\left(\frac{c}{b}\right)}^{2}}\right)\right)}{b} \]
                    6. Simplified87.1%

                      \[\leadsto \color{blue}{\frac{\mathsf{fma}\left(c, -0.5, -0.375 \cdot \left(a \cdot {\left(\frac{c}{b}\right)}^{2}\right)\right)}{b}} \]
                  3. Recombined 2 regimes into one program.
                  4. Final simplification86.5%

                    \[\leadsto \begin{array}{l} \mathbf{if}\;b \leq 0.34:\\ \;\;\;\;\frac{\sqrt{b \cdot b - \left(3 \cdot a\right) \cdot c} - b}{3 \cdot a}\\ \mathbf{else}:\\ \;\;\;\;\frac{\mathsf{fma}\left(c, -0.5, -0.375 \cdot \left(a \cdot {\left(\frac{c}{b}\right)}^{2}\right)\right)}{b}\\ \end{array} \]
                  5. Add Preprocessing

                  Alternative 8: 84.3% accurate, 1.0× speedup?

                  \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;b \leq 0.3:\\ \;\;\;\;\frac{\sqrt{b \cdot b - \left(3 \cdot a\right) \cdot c} - b}{3 \cdot a}\\ \mathbf{else}:\\ \;\;\;\;c \cdot \left(-0.375 \cdot \left(a \cdot \frac{c}{{b}^{3}}\right) - \frac{0.5}{b}\right)\\ \end{array} \end{array} \]
                  (FPCore (a b c)
                   :precision binary64
                   (if (<= b 0.3)
                     (/ (- (sqrt (- (* b b) (* (* 3.0 a) c))) b) (* 3.0 a))
                     (* c (- (* -0.375 (* a (/ c (pow b 3.0)))) (/ 0.5 b)))))
                  double code(double a, double b, double c) {
                  	double tmp;
                  	if (b <= 0.3) {
                  		tmp = (sqrt(((b * b) - ((3.0 * a) * c))) - b) / (3.0 * a);
                  	} else {
                  		tmp = c * ((-0.375 * (a * (c / pow(b, 3.0)))) - (0.5 / b));
                  	}
                  	return tmp;
                  }
                  
                  real(8) function code(a, b, c)
                      real(8), intent (in) :: a
                      real(8), intent (in) :: b
                      real(8), intent (in) :: c
                      real(8) :: tmp
                      if (b <= 0.3d0) then
                          tmp = (sqrt(((b * b) - ((3.0d0 * a) * c))) - b) / (3.0d0 * a)
                      else
                          tmp = c * (((-0.375d0) * (a * (c / (b ** 3.0d0)))) - (0.5d0 / b))
                      end if
                      code = tmp
                  end function
                  
                  public static double code(double a, double b, double c) {
                  	double tmp;
                  	if (b <= 0.3) {
                  		tmp = (Math.sqrt(((b * b) - ((3.0 * a) * c))) - b) / (3.0 * a);
                  	} else {
                  		tmp = c * ((-0.375 * (a * (c / Math.pow(b, 3.0)))) - (0.5 / b));
                  	}
                  	return tmp;
                  }
                  
                  def code(a, b, c):
                  	tmp = 0
                  	if b <= 0.3:
                  		tmp = (math.sqrt(((b * b) - ((3.0 * a) * c))) - b) / (3.0 * a)
                  	else:
                  		tmp = c * ((-0.375 * (a * (c / math.pow(b, 3.0)))) - (0.5 / b))
                  	return tmp
                  
                  function code(a, b, c)
                  	tmp = 0.0
                  	if (b <= 0.3)
                  		tmp = Float64(Float64(sqrt(Float64(Float64(b * b) - Float64(Float64(3.0 * a) * c))) - b) / Float64(3.0 * a));
                  	else
                  		tmp = Float64(c * Float64(Float64(-0.375 * Float64(a * Float64(c / (b ^ 3.0)))) - Float64(0.5 / b)));
                  	end
                  	return tmp
                  end
                  
                  function tmp_2 = code(a, b, c)
                  	tmp = 0.0;
                  	if (b <= 0.3)
                  		tmp = (sqrt(((b * b) - ((3.0 * a) * c))) - b) / (3.0 * a);
                  	else
                  		tmp = c * ((-0.375 * (a * (c / (b ^ 3.0)))) - (0.5 / b));
                  	end
                  	tmp_2 = tmp;
                  end
                  
                  code[a_, b_, c_] := If[LessEqual[b, 0.3], N[(N[(N[Sqrt[N[(N[(b * b), $MachinePrecision] - N[(N[(3.0 * a), $MachinePrecision] * c), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] - b), $MachinePrecision] / N[(3.0 * a), $MachinePrecision]), $MachinePrecision], N[(c * N[(N[(-0.375 * N[(a * N[(c / N[Power[b, 3.0], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] - N[(0.5 / b), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]]
                  
                  \begin{array}{l}
                  
                  \\
                  \begin{array}{l}
                  \mathbf{if}\;b \leq 0.3:\\
                  \;\;\;\;\frac{\sqrt{b \cdot b - \left(3 \cdot a\right) \cdot c} - b}{3 \cdot a}\\
                  
                  \mathbf{else}:\\
                  \;\;\;\;c \cdot \left(-0.375 \cdot \left(a \cdot \frac{c}{{b}^{3}}\right) - \frac{0.5}{b}\right)\\
                  
                  
                  \end{array}
                  \end{array}
                  
                  Derivation
                  1. Split input into 2 regimes
                  2. if b < 0.299999999999999989

                    1. Initial program 83.4%

                      \[\frac{\left(-b\right) + \sqrt{b \cdot b - \left(3 \cdot a\right) \cdot c}}{3 \cdot a} \]
                    2. Add Preprocessing

                    if 0.299999999999999989 < b

                    1. Initial program 49.4%

                      \[\frac{\left(-b\right) + \sqrt{b \cdot b - \left(3 \cdot a\right) \cdot c}}{3 \cdot a} \]
                    2. Step-by-step derivation
                      1. Simplified49.5%

                        \[\leadsto \color{blue}{\frac{\sqrt{\mathsf{fma}\left(b, b, a \cdot \left(c \cdot -3\right)\right)} - b}{3 \cdot a}} \]
                      2. Add Preprocessing
                      3. Taylor expanded in a around 0 86.8%

                        \[\leadsto \frac{\color{blue}{a \cdot \left(-1.5 \cdot \frac{c}{b} + -1.125 \cdot \frac{a \cdot {c}^{2}}{{b}^{3}}\right)}}{3 \cdot a} \]
                      4. Taylor expanded in a around inf 86.8%

                        \[\leadsto \frac{a \cdot \color{blue}{\left(a \cdot \left(-1.5 \cdot \frac{c}{a \cdot b} + -1.125 \cdot \frac{{c}^{2}}{{b}^{3}}\right)\right)}}{3 \cdot a} \]
                      5. Taylor expanded in c around 0 87.0%

                        \[\leadsto \color{blue}{c \cdot \left(-0.375 \cdot \frac{a \cdot c}{{b}^{3}} - 0.5 \cdot \frac{1}{b}\right)} \]
                      6. Step-by-step derivation
                        1. associate-/l*87.0%

                          \[\leadsto c \cdot \left(-0.375 \cdot \color{blue}{\left(a \cdot \frac{c}{{b}^{3}}\right)} - 0.5 \cdot \frac{1}{b}\right) \]
                        2. associate-*r/87.0%

                          \[\leadsto c \cdot \left(-0.375 \cdot \left(a \cdot \frac{c}{{b}^{3}}\right) - \color{blue}{\frac{0.5 \cdot 1}{b}}\right) \]
                        3. metadata-eval87.0%

                          \[\leadsto c \cdot \left(-0.375 \cdot \left(a \cdot \frac{c}{{b}^{3}}\right) - \frac{\color{blue}{0.5}}{b}\right) \]
                      7. Simplified87.0%

                        \[\leadsto \color{blue}{c \cdot \left(-0.375 \cdot \left(a \cdot \frac{c}{{b}^{3}}\right) - \frac{0.5}{b}\right)} \]
                    3. Recombined 2 regimes into one program.
                    4. Final simplification86.4%

                      \[\leadsto \begin{array}{l} \mathbf{if}\;b \leq 0.3:\\ \;\;\;\;\frac{\sqrt{b \cdot b - \left(3 \cdot a\right) \cdot c} - b}{3 \cdot a}\\ \mathbf{else}:\\ \;\;\;\;c \cdot \left(-0.375 \cdot \left(a \cdot \frac{c}{{b}^{3}}\right) - \frac{0.5}{b}\right)\\ \end{array} \]
                    5. Add Preprocessing

                    Alternative 9: 81.2% accurate, 1.0× speedup?

                    \[\begin{array}{l} \\ c \cdot \left(-0.375 \cdot \left(a \cdot \frac{c}{{b}^{3}}\right) - \frac{0.5}{b}\right) \end{array} \]
                    (FPCore (a b c)
                     :precision binary64
                     (* c (- (* -0.375 (* a (/ c (pow b 3.0)))) (/ 0.5 b))))
                    double code(double a, double b, double c) {
                    	return c * ((-0.375 * (a * (c / pow(b, 3.0)))) - (0.5 / b));
                    }
                    
                    real(8) function code(a, b, c)
                        real(8), intent (in) :: a
                        real(8), intent (in) :: b
                        real(8), intent (in) :: c
                        code = c * (((-0.375d0) * (a * (c / (b ** 3.0d0)))) - (0.5d0 / b))
                    end function
                    
                    public static double code(double a, double b, double c) {
                    	return c * ((-0.375 * (a * (c / Math.pow(b, 3.0)))) - (0.5 / b));
                    }
                    
                    def code(a, b, c):
                    	return c * ((-0.375 * (a * (c / math.pow(b, 3.0)))) - (0.5 / b))
                    
                    function code(a, b, c)
                    	return Float64(c * Float64(Float64(-0.375 * Float64(a * Float64(c / (b ^ 3.0)))) - Float64(0.5 / b)))
                    end
                    
                    function tmp = code(a, b, c)
                    	tmp = c * ((-0.375 * (a * (c / (b ^ 3.0)))) - (0.5 / b));
                    end
                    
                    code[a_, b_, c_] := N[(c * N[(N[(-0.375 * N[(a * N[(c / N[Power[b, 3.0], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] - N[(0.5 / b), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
                    
                    \begin{array}{l}
                    
                    \\
                    c \cdot \left(-0.375 \cdot \left(a \cdot \frac{c}{{b}^{3}}\right) - \frac{0.5}{b}\right)
                    \end{array}
                    
                    Derivation
                    1. Initial program 54.7%

                      \[\frac{\left(-b\right) + \sqrt{b \cdot b - \left(3 \cdot a\right) \cdot c}}{3 \cdot a} \]
                    2. Step-by-step derivation
                      1. Simplified54.8%

                        \[\leadsto \color{blue}{\frac{\sqrt{\mathsf{fma}\left(b, b, a \cdot \left(c \cdot -3\right)\right)} - b}{3 \cdot a}} \]
                      2. Add Preprocessing
                      3. Taylor expanded in a around 0 82.1%

                        \[\leadsto \frac{\color{blue}{a \cdot \left(-1.5 \cdot \frac{c}{b} + -1.125 \cdot \frac{a \cdot {c}^{2}}{{b}^{3}}\right)}}{3 \cdot a} \]
                      4. Taylor expanded in a around inf 82.1%

                        \[\leadsto \frac{a \cdot \color{blue}{\left(a \cdot \left(-1.5 \cdot \frac{c}{a \cdot b} + -1.125 \cdot \frac{{c}^{2}}{{b}^{3}}\right)\right)}}{3 \cdot a} \]
                      5. Taylor expanded in c around 0 82.2%

                        \[\leadsto \color{blue}{c \cdot \left(-0.375 \cdot \frac{a \cdot c}{{b}^{3}} - 0.5 \cdot \frac{1}{b}\right)} \]
                      6. Step-by-step derivation
                        1. associate-/l*82.2%

                          \[\leadsto c \cdot \left(-0.375 \cdot \color{blue}{\left(a \cdot \frac{c}{{b}^{3}}\right)} - 0.5 \cdot \frac{1}{b}\right) \]
                        2. associate-*r/82.2%

                          \[\leadsto c \cdot \left(-0.375 \cdot \left(a \cdot \frac{c}{{b}^{3}}\right) - \color{blue}{\frac{0.5 \cdot 1}{b}}\right) \]
                        3. metadata-eval82.2%

                          \[\leadsto c \cdot \left(-0.375 \cdot \left(a \cdot \frac{c}{{b}^{3}}\right) - \frac{\color{blue}{0.5}}{b}\right) \]
                      7. Simplified82.2%

                        \[\leadsto \color{blue}{c \cdot \left(-0.375 \cdot \left(a \cdot \frac{c}{{b}^{3}}\right) - \frac{0.5}{b}\right)} \]
                      8. Add Preprocessing

                      Alternative 10: 64.2% accurate, 23.2× speedup?

                      \[\begin{array}{l} \\ -0.5 \cdot \frac{c}{b} \end{array} \]
                      (FPCore (a b c) :precision binary64 (* -0.5 (/ c b)))
                      double code(double a, double b, double c) {
                      	return -0.5 * (c / b);
                      }
                      
                      real(8) function code(a, b, c)
                          real(8), intent (in) :: a
                          real(8), intent (in) :: b
                          real(8), intent (in) :: c
                          code = (-0.5d0) * (c / b)
                      end function
                      
                      public static double code(double a, double b, double c) {
                      	return -0.5 * (c / b);
                      }
                      
                      def code(a, b, c):
                      	return -0.5 * (c / b)
                      
                      function code(a, b, c)
                      	return Float64(-0.5 * Float64(c / b))
                      end
                      
                      function tmp = code(a, b, c)
                      	tmp = -0.5 * (c / b);
                      end
                      
                      code[a_, b_, c_] := N[(-0.5 * N[(c / b), $MachinePrecision]), $MachinePrecision]
                      
                      \begin{array}{l}
                      
                      \\
                      -0.5 \cdot \frac{c}{b}
                      \end{array}
                      
                      Derivation
                      1. Initial program 54.7%

                        \[\frac{\left(-b\right) + \sqrt{b \cdot b - \left(3 \cdot a\right) \cdot c}}{3 \cdot a} \]
                      2. Step-by-step derivation
                        1. Simplified54.8%

                          \[\leadsto \color{blue}{\frac{\sqrt{\mathsf{fma}\left(b, b, a \cdot \left(c \cdot -3\right)\right)} - b}{3 \cdot a}} \]
                        2. Add Preprocessing
                        3. Taylor expanded in b around inf 64.9%

                          \[\leadsto \color{blue}{-0.5 \cdot \frac{c}{b}} \]
                        4. Add Preprocessing

                        Reproduce

                        ?
                        herbie shell --seed 2024185 
                        (FPCore (a b c)
                          :name "Cubic critical, narrow range"
                          :precision binary64
                          :pre (and (and (and (< 1.0536712127723509e-8 a) (< a 94906265.62425156)) (and (< 1.0536712127723509e-8 b) (< b 94906265.62425156))) (and (< 1.0536712127723509e-8 c) (< c 94906265.62425156)))
                          (/ (+ (- b) (sqrt (- (* b b) (* (* 3.0 a) c)))) (* 3.0 a)))