ABCF->ab-angle a

Percentage Accurate: 20.5% → 54.4%
Time: 18.7s
Alternatives: 12
Speedup: 6.0×

Specification

?
\[\begin{array}{l} \\ \begin{array}{l} t_0 := {B}^{2} - \left(4 \cdot A\right) \cdot C\\ \frac{-\sqrt{\left(2 \cdot \left(t\_0 \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{t\_0} \end{array} \end{array} \]
(FPCore (A B C F)
 :precision binary64
 (let* ((t_0 (- (pow B 2.0) (* (* 4.0 A) C))))
   (/
    (-
     (sqrt
      (*
       (* 2.0 (* t_0 F))
       (+ (+ A C) (sqrt (+ (pow (- A C) 2.0) (pow B 2.0)))))))
    t_0)))
double code(double A, double B, double C, double F) {
	double t_0 = pow(B, 2.0) - ((4.0 * A) * C);
	return -sqrt(((2.0 * (t_0 * F)) * ((A + C) + sqrt((pow((A - C), 2.0) + pow(B, 2.0)))))) / t_0;
}
real(8) function code(a, b, c, f)
    real(8), intent (in) :: a
    real(8), intent (in) :: b
    real(8), intent (in) :: c
    real(8), intent (in) :: f
    real(8) :: t_0
    t_0 = (b ** 2.0d0) - ((4.0d0 * a) * c)
    code = -sqrt(((2.0d0 * (t_0 * f)) * ((a + c) + sqrt((((a - c) ** 2.0d0) + (b ** 2.0d0)))))) / t_0
end function
public static double code(double A, double B, double C, double F) {
	double t_0 = Math.pow(B, 2.0) - ((4.0 * A) * C);
	return -Math.sqrt(((2.0 * (t_0 * F)) * ((A + C) + Math.sqrt((Math.pow((A - C), 2.0) + Math.pow(B, 2.0)))))) / t_0;
}
def code(A, B, C, F):
	t_0 = math.pow(B, 2.0) - ((4.0 * A) * C)
	return -math.sqrt(((2.0 * (t_0 * F)) * ((A + C) + math.sqrt((math.pow((A - C), 2.0) + math.pow(B, 2.0)))))) / t_0
function code(A, B, C, F)
	t_0 = Float64((B ^ 2.0) - Float64(Float64(4.0 * A) * C))
	return Float64(Float64(-sqrt(Float64(Float64(2.0 * Float64(t_0 * F)) * Float64(Float64(A + C) + sqrt(Float64((Float64(A - C) ^ 2.0) + (B ^ 2.0))))))) / t_0)
end
function tmp = code(A, B, C, F)
	t_0 = (B ^ 2.0) - ((4.0 * A) * C);
	tmp = -sqrt(((2.0 * (t_0 * F)) * ((A + C) + sqrt((((A - C) ^ 2.0) + (B ^ 2.0)))))) / t_0;
end
code[A_, B_, C_, F_] := Block[{t$95$0 = N[(N[Power[B, 2.0], $MachinePrecision] - N[(N[(4.0 * A), $MachinePrecision] * C), $MachinePrecision]), $MachinePrecision]}, N[((-N[Sqrt[N[(N[(2.0 * N[(t$95$0 * F), $MachinePrecision]), $MachinePrecision] * N[(N[(A + C), $MachinePrecision] + N[Sqrt[N[(N[Power[N[(A - C), $MachinePrecision], 2.0], $MachinePrecision] + N[Power[B, 2.0], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]) / t$95$0), $MachinePrecision]]
\begin{array}{l}

\\
\begin{array}{l}
t_0 := {B}^{2} - \left(4 \cdot A\right) \cdot C\\
\frac{-\sqrt{\left(2 \cdot \left(t\_0 \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{t\_0}
\end{array}
\end{array}

Sampling outcomes in binary64 precision:

Local Percentage Accuracy vs ?

The average percentage accuracy by input value. Horizontal axis shows value of an input variable; the variable is choosen in the title. Vertical axis is accuracy; higher is better. Red represent the original program, while blue represents Herbie's suggestion. These can be toggled with buttons below the plot. The line is an average while dots represent individual samples.

Accuracy vs Speed?

Herbie found 12 alternatives:

AlternativeAccuracySpeedup
The accuracy (vertical axis) and speed (horizontal axis) of each alternatives. Up and to the right is better. The red square shows the initial program, and each blue circle shows an alternative.The line shows the best available speed-accuracy tradeoffs.

Initial Program: 20.5% accurate, 1.0× speedup?

\[\begin{array}{l} \\ \begin{array}{l} t_0 := {B}^{2} - \left(4 \cdot A\right) \cdot C\\ \frac{-\sqrt{\left(2 \cdot \left(t\_0 \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{t\_0} \end{array} \end{array} \]
(FPCore (A B C F)
 :precision binary64
 (let* ((t_0 (- (pow B 2.0) (* (* 4.0 A) C))))
   (/
    (-
     (sqrt
      (*
       (* 2.0 (* t_0 F))
       (+ (+ A C) (sqrt (+ (pow (- A C) 2.0) (pow B 2.0)))))))
    t_0)))
double code(double A, double B, double C, double F) {
	double t_0 = pow(B, 2.0) - ((4.0 * A) * C);
	return -sqrt(((2.0 * (t_0 * F)) * ((A + C) + sqrt((pow((A - C), 2.0) + pow(B, 2.0)))))) / t_0;
}
real(8) function code(a, b, c, f)
    real(8), intent (in) :: a
    real(8), intent (in) :: b
    real(8), intent (in) :: c
    real(8), intent (in) :: f
    real(8) :: t_0
    t_0 = (b ** 2.0d0) - ((4.0d0 * a) * c)
    code = -sqrt(((2.0d0 * (t_0 * f)) * ((a + c) + sqrt((((a - c) ** 2.0d0) + (b ** 2.0d0)))))) / t_0
end function
public static double code(double A, double B, double C, double F) {
	double t_0 = Math.pow(B, 2.0) - ((4.0 * A) * C);
	return -Math.sqrt(((2.0 * (t_0 * F)) * ((A + C) + Math.sqrt((Math.pow((A - C), 2.0) + Math.pow(B, 2.0)))))) / t_0;
}
def code(A, B, C, F):
	t_0 = math.pow(B, 2.0) - ((4.0 * A) * C)
	return -math.sqrt(((2.0 * (t_0 * F)) * ((A + C) + math.sqrt((math.pow((A - C), 2.0) + math.pow(B, 2.0)))))) / t_0
function code(A, B, C, F)
	t_0 = Float64((B ^ 2.0) - Float64(Float64(4.0 * A) * C))
	return Float64(Float64(-sqrt(Float64(Float64(2.0 * Float64(t_0 * F)) * Float64(Float64(A + C) + sqrt(Float64((Float64(A - C) ^ 2.0) + (B ^ 2.0))))))) / t_0)
end
function tmp = code(A, B, C, F)
	t_0 = (B ^ 2.0) - ((4.0 * A) * C);
	tmp = -sqrt(((2.0 * (t_0 * F)) * ((A + C) + sqrt((((A - C) ^ 2.0) + (B ^ 2.0)))))) / t_0;
end
code[A_, B_, C_, F_] := Block[{t$95$0 = N[(N[Power[B, 2.0], $MachinePrecision] - N[(N[(4.0 * A), $MachinePrecision] * C), $MachinePrecision]), $MachinePrecision]}, N[((-N[Sqrt[N[(N[(2.0 * N[(t$95$0 * F), $MachinePrecision]), $MachinePrecision] * N[(N[(A + C), $MachinePrecision] + N[Sqrt[N[(N[Power[N[(A - C), $MachinePrecision], 2.0], $MachinePrecision] + N[Power[B, 2.0], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]) / t$95$0), $MachinePrecision]]
\begin{array}{l}

\\
\begin{array}{l}
t_0 := {B}^{2} - \left(4 \cdot A\right) \cdot C\\
\frac{-\sqrt{\left(2 \cdot \left(t\_0 \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{t\_0}
\end{array}
\end{array}

Alternative 1: 54.4% accurate, 0.7× speedup?

\[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} t_0 := \mathsf{fma}\left(B\_m, B\_m, A \cdot \left(C \cdot -4\right)\right)\\ \mathbf{if}\;{B\_m}^{2} \leq 10^{-294}:\\ \;\;\;\;-\sqrt{\left|-0.5 \cdot \left(2 \cdot \frac{F}{A}\right)\right|}\\ \mathbf{elif}\;{B\_m}^{2} \leq 5 \cdot 10^{-230}:\\ \;\;\;\;\frac{\sqrt{\left(F \cdot t\_0\right) \cdot \left(C \cdot 4\right)}}{-t\_0}\\ \mathbf{elif}\;{B\_m}^{2} \leq 5 \cdot 10^{+233}:\\ \;\;\;\;\sqrt{F \cdot \frac{\left(A + C\right) + \mathsf{hypot}\left(B\_m, A - C\right)}{\mathsf{fma}\left(-4, A \cdot C, {B\_m}^{2}\right)}} \cdot \left(-e^{\log 2 \cdot 0.5}\right)\\ \mathbf{else}:\\ \;\;\;\;\left(\sqrt{C + \mathsf{hypot}\left(C, B\_m\right)} \cdot \sqrt{F}\right) \cdot \frac{\sqrt{2}}{-B\_m}\\ \end{array} \end{array} \]
B_m = (fabs.f64 B)
NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
(FPCore (A B_m C F)
 :precision binary64
 (let* ((t_0 (fma B_m B_m (* A (* C -4.0)))))
   (if (<= (pow B_m 2.0) 1e-294)
     (- (sqrt (fabs (* -0.5 (* 2.0 (/ F A))))))
     (if (<= (pow B_m 2.0) 5e-230)
       (/ (sqrt (* (* F t_0) (* C 4.0))) (- t_0))
       (if (<= (pow B_m 2.0) 5e+233)
         (*
          (sqrt
           (*
            F
            (/
             (+ (+ A C) (hypot B_m (- A C)))
             (fma -4.0 (* A C) (pow B_m 2.0)))))
          (- (exp (* (log 2.0) 0.5))))
         (*
          (* (sqrt (+ C (hypot C B_m))) (sqrt F))
          (/ (sqrt 2.0) (- B_m))))))))
B_m = fabs(B);
assert(A < B_m && B_m < C && C < F);
double code(double A, double B_m, double C, double F) {
	double t_0 = fma(B_m, B_m, (A * (C * -4.0)));
	double tmp;
	if (pow(B_m, 2.0) <= 1e-294) {
		tmp = -sqrt(fabs((-0.5 * (2.0 * (F / A)))));
	} else if (pow(B_m, 2.0) <= 5e-230) {
		tmp = sqrt(((F * t_0) * (C * 4.0))) / -t_0;
	} else if (pow(B_m, 2.0) <= 5e+233) {
		tmp = sqrt((F * (((A + C) + hypot(B_m, (A - C))) / fma(-4.0, (A * C), pow(B_m, 2.0))))) * -exp((log(2.0) * 0.5));
	} else {
		tmp = (sqrt((C + hypot(C, B_m))) * sqrt(F)) * (sqrt(2.0) / -B_m);
	}
	return tmp;
}
B_m = abs(B)
A, B_m, C, F = sort([A, B_m, C, F])
function code(A, B_m, C, F)
	t_0 = fma(B_m, B_m, Float64(A * Float64(C * -4.0)))
	tmp = 0.0
	if ((B_m ^ 2.0) <= 1e-294)
		tmp = Float64(-sqrt(abs(Float64(-0.5 * Float64(2.0 * Float64(F / A))))));
	elseif ((B_m ^ 2.0) <= 5e-230)
		tmp = Float64(sqrt(Float64(Float64(F * t_0) * Float64(C * 4.0))) / Float64(-t_0));
	elseif ((B_m ^ 2.0) <= 5e+233)
		tmp = Float64(sqrt(Float64(F * Float64(Float64(Float64(A + C) + hypot(B_m, Float64(A - C))) / fma(-4.0, Float64(A * C), (B_m ^ 2.0))))) * Float64(-exp(Float64(log(2.0) * 0.5))));
	else
		tmp = Float64(Float64(sqrt(Float64(C + hypot(C, B_m))) * sqrt(F)) * Float64(sqrt(2.0) / Float64(-B_m)));
	end
	return tmp
end
B_m = N[Abs[B], $MachinePrecision]
NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
code[A_, B$95$m_, C_, F_] := Block[{t$95$0 = N[(B$95$m * B$95$m + N[(A * N[(C * -4.0), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[N[Power[B$95$m, 2.0], $MachinePrecision], 1e-294], (-N[Sqrt[N[Abs[N[(-0.5 * N[(2.0 * N[(F / A), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]], $MachinePrecision]), If[LessEqual[N[Power[B$95$m, 2.0], $MachinePrecision], 5e-230], N[(N[Sqrt[N[(N[(F * t$95$0), $MachinePrecision] * N[(C * 4.0), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / (-t$95$0)), $MachinePrecision], If[LessEqual[N[Power[B$95$m, 2.0], $MachinePrecision], 5e+233], N[(N[Sqrt[N[(F * N[(N[(N[(A + C), $MachinePrecision] + N[Sqrt[B$95$m ^ 2 + N[(A - C), $MachinePrecision] ^ 2], $MachinePrecision]), $MachinePrecision] / N[(-4.0 * N[(A * C), $MachinePrecision] + N[Power[B$95$m, 2.0], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] * (-N[Exp[N[(N[Log[2.0], $MachinePrecision] * 0.5), $MachinePrecision]], $MachinePrecision])), $MachinePrecision], N[(N[(N[Sqrt[N[(C + N[Sqrt[C ^ 2 + B$95$m ^ 2], $MachinePrecision]), $MachinePrecision]], $MachinePrecision] * N[Sqrt[F], $MachinePrecision]), $MachinePrecision] * N[(N[Sqrt[2.0], $MachinePrecision] / (-B$95$m)), $MachinePrecision]), $MachinePrecision]]]]]
\begin{array}{l}
B_m = \left|B\right|
\\
[A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
\\
\begin{array}{l}
t_0 := \mathsf{fma}\left(B\_m, B\_m, A \cdot \left(C \cdot -4\right)\right)\\
\mathbf{if}\;{B\_m}^{2} \leq 10^{-294}:\\
\;\;\;\;-\sqrt{\left|-0.5 \cdot \left(2 \cdot \frac{F}{A}\right)\right|}\\

\mathbf{elif}\;{B\_m}^{2} \leq 5 \cdot 10^{-230}:\\
\;\;\;\;\frac{\sqrt{\left(F \cdot t\_0\right) \cdot \left(C \cdot 4\right)}}{-t\_0}\\

\mathbf{elif}\;{B\_m}^{2} \leq 5 \cdot 10^{+233}:\\
\;\;\;\;\sqrt{F \cdot \frac{\left(A + C\right) + \mathsf{hypot}\left(B\_m, A - C\right)}{\mathsf{fma}\left(-4, A \cdot C, {B\_m}^{2}\right)}} \cdot \left(-e^{\log 2 \cdot 0.5}\right)\\

\mathbf{else}:\\
\;\;\;\;\left(\sqrt{C + \mathsf{hypot}\left(C, B\_m\right)} \cdot \sqrt{F}\right) \cdot \frac{\sqrt{2}}{-B\_m}\\


\end{array}
\end{array}
Derivation
  1. Split input into 4 regimes
  2. if (pow.f64 B #s(literal 2 binary64)) < 1.00000000000000002e-294

    1. Initial program 20.5%

      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    2. Add Preprocessing
    3. Taylor expanded in F around 0 22.1%

      \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2}\right)} \]
    4. Simplified34.5%

      \[\leadsto \color{blue}{-\sqrt{2} \cdot \sqrt{F \cdot \frac{\left(C + A\right) + \mathsf{hypot}\left(B, A - C\right)}{\mathsf{fma}\left(-4, C \cdot A, {B}^{2}\right)}}} \]
    5. Taylor expanded in C around inf 29.8%

      \[\leadsto -\sqrt{2} \cdot \sqrt{\color{blue}{-0.5 \cdot \frac{F}{A}}} \]
    6. Step-by-step derivation
      1. *-commutative29.8%

        \[\leadsto -\color{blue}{\sqrt{-0.5 \cdot \frac{F}{A}} \cdot \sqrt{2}} \]
      2. pow1/229.9%

        \[\leadsto -\color{blue}{{\left(-0.5 \cdot \frac{F}{A}\right)}^{0.5}} \cdot \sqrt{2} \]
      3. pow1/229.9%

        \[\leadsto -{\left(-0.5 \cdot \frac{F}{A}\right)}^{0.5} \cdot \color{blue}{{2}^{0.5}} \]
      4. pow-prod-down30.0%

        \[\leadsto -\color{blue}{{\left(\left(-0.5 \cdot \frac{F}{A}\right) \cdot 2\right)}^{0.5}} \]
      5. associate-*r/30.0%

        \[\leadsto -{\left(\color{blue}{\frac{-0.5 \cdot F}{A}} \cdot 2\right)}^{0.5} \]
    7. Applied egg-rr30.0%

      \[\leadsto -\color{blue}{{\left(\frac{-0.5 \cdot F}{A} \cdot 2\right)}^{0.5}} \]
    8. Step-by-step derivation
      1. unpow1/229.9%

        \[\leadsto -\color{blue}{\sqrt{\frac{-0.5 \cdot F}{A} \cdot 2}} \]
    9. Simplified29.9%

      \[\leadsto -\color{blue}{\sqrt{\frac{-0.5 \cdot F}{A} \cdot 2}} \]
    10. Step-by-step derivation
      1. add-sqr-sqrt29.9%

        \[\leadsto -\sqrt{\color{blue}{\sqrt{\frac{-0.5 \cdot F}{A} \cdot 2} \cdot \sqrt{\frac{-0.5 \cdot F}{A} \cdot 2}}} \]
      2. pow1/229.9%

        \[\leadsto -\sqrt{\color{blue}{{\left(\frac{-0.5 \cdot F}{A} \cdot 2\right)}^{0.5}} \cdot \sqrt{\frac{-0.5 \cdot F}{A} \cdot 2}} \]
      3. pow1/230.0%

        \[\leadsto -\sqrt{{\left(\frac{-0.5 \cdot F}{A} \cdot 2\right)}^{0.5} \cdot \color{blue}{{\left(\frac{-0.5 \cdot F}{A} \cdot 2\right)}^{0.5}}} \]
      4. pow-prod-down25.6%

        \[\leadsto -\sqrt{\color{blue}{{\left(\left(\frac{-0.5 \cdot F}{A} \cdot 2\right) \cdot \left(\frac{-0.5 \cdot F}{A} \cdot 2\right)\right)}^{0.5}}} \]
      5. pow225.6%

        \[\leadsto -\sqrt{{\color{blue}{\left({\left(\frac{-0.5 \cdot F}{A} \cdot 2\right)}^{2}\right)}}^{0.5}} \]
      6. associate-/l*25.6%

        \[\leadsto -\sqrt{{\left({\left(\color{blue}{\left(-0.5 \cdot \frac{F}{A}\right)} \cdot 2\right)}^{2}\right)}^{0.5}} \]
    11. Applied egg-rr25.6%

      \[\leadsto -\sqrt{\color{blue}{{\left({\left(\left(-0.5 \cdot \frac{F}{A}\right) \cdot 2\right)}^{2}\right)}^{0.5}}} \]
    12. Step-by-step derivation
      1. unpow1/225.6%

        \[\leadsto -\sqrt{\color{blue}{\sqrt{{\left(\left(-0.5 \cdot \frac{F}{A}\right) \cdot 2\right)}^{2}}}} \]
      2. unpow225.6%

        \[\leadsto -\sqrt{\sqrt{\color{blue}{\left(\left(-0.5 \cdot \frac{F}{A}\right) \cdot 2\right) \cdot \left(\left(-0.5 \cdot \frac{F}{A}\right) \cdot 2\right)}}} \]
      3. rem-sqrt-square31.8%

        \[\leadsto -\sqrt{\color{blue}{\left|\left(-0.5 \cdot \frac{F}{A}\right) \cdot 2\right|}} \]
      4. associate-*l*31.8%

        \[\leadsto -\sqrt{\left|\color{blue}{-0.5 \cdot \left(\frac{F}{A} \cdot 2\right)}\right|} \]
    13. Simplified31.8%

      \[\leadsto -\sqrt{\color{blue}{\left|-0.5 \cdot \left(\frac{F}{A} \cdot 2\right)\right|}} \]

    if 1.00000000000000002e-294 < (pow.f64 B #s(literal 2 binary64)) < 5.00000000000000035e-230

    1. Initial program 20.9%

      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    2. Simplified41.6%

      \[\leadsto \color{blue}{\frac{\sqrt{\left(\mathsf{fma}\left(B, B, A \cdot \left(C \cdot -4\right)\right) \cdot F\right) \cdot \left(2 \cdot \left(A + \left(C + \mathsf{hypot}\left(B, A - C\right)\right)\right)\right)}}{-\mathsf{fma}\left(B, B, A \cdot \left(C \cdot -4\right)\right)}} \]
    3. Add Preprocessing
    4. Taylor expanded in A around -inf 32.8%

      \[\leadsto \frac{\sqrt{\left(\mathsf{fma}\left(B, B, A \cdot \left(C \cdot -4\right)\right) \cdot F\right) \cdot \color{blue}{\left(4 \cdot C\right)}}}{-\mathsf{fma}\left(B, B, A \cdot \left(C \cdot -4\right)\right)} \]
    5. Step-by-step derivation
      1. *-commutative32.8%

        \[\leadsto \frac{\sqrt{\left(\mathsf{fma}\left(B, B, A \cdot \left(C \cdot -4\right)\right) \cdot F\right) \cdot \color{blue}{\left(C \cdot 4\right)}}}{-\mathsf{fma}\left(B, B, A \cdot \left(C \cdot -4\right)\right)} \]
    6. Simplified32.8%

      \[\leadsto \frac{\sqrt{\left(\mathsf{fma}\left(B, B, A \cdot \left(C \cdot -4\right)\right) \cdot F\right) \cdot \color{blue}{\left(C \cdot 4\right)}}}{-\mathsf{fma}\left(B, B, A \cdot \left(C \cdot -4\right)\right)} \]

    if 5.00000000000000035e-230 < (pow.f64 B #s(literal 2 binary64)) < 5.00000000000000009e233

    1. Initial program 31.3%

      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    2. Add Preprocessing
    3. Taylor expanded in F around 0 28.7%

      \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2}\right)} \]
    4. Simplified50.5%

      \[\leadsto \color{blue}{-\sqrt{2} \cdot \sqrt{F \cdot \frac{\left(C + A\right) + \mathsf{hypot}\left(B, A - C\right)}{\mathsf{fma}\left(-4, C \cdot A, {B}^{2}\right)}}} \]
    5. Step-by-step derivation
      1. pow1/250.5%

        \[\leadsto -\color{blue}{{2}^{0.5}} \cdot \sqrt{F \cdot \frac{\left(C + A\right) + \mathsf{hypot}\left(B, A - C\right)}{\mathsf{fma}\left(-4, C \cdot A, {B}^{2}\right)}} \]
      2. pow-to-exp50.6%

        \[\leadsto -\color{blue}{e^{\log 2 \cdot 0.5}} \cdot \sqrt{F \cdot \frac{\left(C + A\right) + \mathsf{hypot}\left(B, A - C\right)}{\mathsf{fma}\left(-4, C \cdot A, {B}^{2}\right)}} \]
    6. Applied egg-rr50.6%

      \[\leadsto -\color{blue}{e^{\log 2 \cdot 0.5}} \cdot \sqrt{F \cdot \frac{\left(C + A\right) + \mathsf{hypot}\left(B, A - C\right)}{\mathsf{fma}\left(-4, C \cdot A, {B}^{2}\right)}} \]

    if 5.00000000000000009e233 < (pow.f64 B #s(literal 2 binary64))

    1. Initial program 5.1%

      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    2. Add Preprocessing
    3. Taylor expanded in A around 0 6.7%

      \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right)} \]
    4. Step-by-step derivation
      1. mul-1-neg6.7%

        \[\leadsto \color{blue}{-\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
      2. *-commutative6.7%

        \[\leadsto -\color{blue}{\sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \cdot \frac{\sqrt{2}}{B}} \]
      3. *-commutative6.7%

        \[\leadsto -\sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \cdot \frac{\sqrt{2}}{B} \]
      4. +-commutative6.7%

        \[\leadsto -\sqrt{\left(C + \sqrt{\color{blue}{{C}^{2} + {B}^{2}}}\right) \cdot F} \cdot \frac{\sqrt{2}}{B} \]
      5. unpow26.7%

        \[\leadsto -\sqrt{\left(C + \sqrt{\color{blue}{C \cdot C} + {B}^{2}}\right) \cdot F} \cdot \frac{\sqrt{2}}{B} \]
      6. unpow26.7%

        \[\leadsto -\sqrt{\left(C + \sqrt{C \cdot C + \color{blue}{B \cdot B}}\right) \cdot F} \cdot \frac{\sqrt{2}}{B} \]
      7. hypot-define27.2%

        \[\leadsto -\sqrt{\left(C + \color{blue}{\mathsf{hypot}\left(C, B\right)}\right) \cdot F} \cdot \frac{\sqrt{2}}{B} \]
    5. Simplified27.2%

      \[\leadsto \color{blue}{-\sqrt{\left(C + \mathsf{hypot}\left(C, B\right)\right) \cdot F} \cdot \frac{\sqrt{2}}{B}} \]
    6. Step-by-step derivation
      1. sqrt-prod39.4%

        \[\leadsto -\color{blue}{\left(\sqrt{C + \mathsf{hypot}\left(C, B\right)} \cdot \sqrt{F}\right)} \cdot \frac{\sqrt{2}}{B} \]
    7. Applied egg-rr39.4%

      \[\leadsto -\color{blue}{\left(\sqrt{C + \mathsf{hypot}\left(C, B\right)} \cdot \sqrt{F}\right)} \cdot \frac{\sqrt{2}}{B} \]
  3. Recombined 4 regimes into one program.
  4. Final simplification40.8%

    \[\leadsto \begin{array}{l} \mathbf{if}\;{B}^{2} \leq 10^{-294}:\\ \;\;\;\;-\sqrt{\left|-0.5 \cdot \left(2 \cdot \frac{F}{A}\right)\right|}\\ \mathbf{elif}\;{B}^{2} \leq 5 \cdot 10^{-230}:\\ \;\;\;\;\frac{\sqrt{\left(F \cdot \mathsf{fma}\left(B, B, A \cdot \left(C \cdot -4\right)\right)\right) \cdot \left(C \cdot 4\right)}}{-\mathsf{fma}\left(B, B, A \cdot \left(C \cdot -4\right)\right)}\\ \mathbf{elif}\;{B}^{2} \leq 5 \cdot 10^{+233}:\\ \;\;\;\;\sqrt{F \cdot \frac{\left(A + C\right) + \mathsf{hypot}\left(B, A - C\right)}{\mathsf{fma}\left(-4, A \cdot C, {B}^{2}\right)}} \cdot \left(-e^{\log 2 \cdot 0.5}\right)\\ \mathbf{else}:\\ \;\;\;\;\left(\sqrt{C + \mathsf{hypot}\left(C, B\right)} \cdot \sqrt{F}\right) \cdot \frac{\sqrt{2}}{-B}\\ \end{array} \]
  5. Add Preprocessing

Alternative 2: 54.4% accurate, 0.9× speedup?

\[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} t_0 := \mathsf{fma}\left(B\_m, B\_m, A \cdot \left(C \cdot -4\right)\right)\\ \mathbf{if}\;{B\_m}^{2} \leq 10^{-294}:\\ \;\;\;\;-\sqrt{\left|-0.5 \cdot \left(2 \cdot \frac{F}{A}\right)\right|}\\ \mathbf{elif}\;{B\_m}^{2} \leq 5 \cdot 10^{-230}:\\ \;\;\;\;\frac{\sqrt{\left(F \cdot t\_0\right) \cdot \left(C \cdot 4\right)}}{-t\_0}\\ \mathbf{elif}\;{B\_m}^{2} \leq 5 \cdot 10^{+233}:\\ \;\;\;\;\sqrt{F \cdot \frac{\left(A + C\right) + \mathsf{hypot}\left(B\_m, A - C\right)}{\mathsf{fma}\left(-4, A \cdot C, B\_m \cdot B\_m\right)}} \cdot \left(-\sqrt{2}\right)\\ \mathbf{else}:\\ \;\;\;\;\left(\sqrt{C + \mathsf{hypot}\left(C, B\_m\right)} \cdot \sqrt{F}\right) \cdot \frac{\sqrt{2}}{-B\_m}\\ \end{array} \end{array} \]
B_m = (fabs.f64 B)
NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
(FPCore (A B_m C F)
 :precision binary64
 (let* ((t_0 (fma B_m B_m (* A (* C -4.0)))))
   (if (<= (pow B_m 2.0) 1e-294)
     (- (sqrt (fabs (* -0.5 (* 2.0 (/ F A))))))
     (if (<= (pow B_m 2.0) 5e-230)
       (/ (sqrt (* (* F t_0) (* C 4.0))) (- t_0))
       (if (<= (pow B_m 2.0) 5e+233)
         (*
          (sqrt
           (*
            F
            (/
             (+ (+ A C) (hypot B_m (- A C)))
             (fma -4.0 (* A C) (* B_m B_m)))))
          (- (sqrt 2.0)))
         (*
          (* (sqrt (+ C (hypot C B_m))) (sqrt F))
          (/ (sqrt 2.0) (- B_m))))))))
B_m = fabs(B);
assert(A < B_m && B_m < C && C < F);
double code(double A, double B_m, double C, double F) {
	double t_0 = fma(B_m, B_m, (A * (C * -4.0)));
	double tmp;
	if (pow(B_m, 2.0) <= 1e-294) {
		tmp = -sqrt(fabs((-0.5 * (2.0 * (F / A)))));
	} else if (pow(B_m, 2.0) <= 5e-230) {
		tmp = sqrt(((F * t_0) * (C * 4.0))) / -t_0;
	} else if (pow(B_m, 2.0) <= 5e+233) {
		tmp = sqrt((F * (((A + C) + hypot(B_m, (A - C))) / fma(-4.0, (A * C), (B_m * B_m))))) * -sqrt(2.0);
	} else {
		tmp = (sqrt((C + hypot(C, B_m))) * sqrt(F)) * (sqrt(2.0) / -B_m);
	}
	return tmp;
}
B_m = abs(B)
A, B_m, C, F = sort([A, B_m, C, F])
function code(A, B_m, C, F)
	t_0 = fma(B_m, B_m, Float64(A * Float64(C * -4.0)))
	tmp = 0.0
	if ((B_m ^ 2.0) <= 1e-294)
		tmp = Float64(-sqrt(abs(Float64(-0.5 * Float64(2.0 * Float64(F / A))))));
	elseif ((B_m ^ 2.0) <= 5e-230)
		tmp = Float64(sqrt(Float64(Float64(F * t_0) * Float64(C * 4.0))) / Float64(-t_0));
	elseif ((B_m ^ 2.0) <= 5e+233)
		tmp = Float64(sqrt(Float64(F * Float64(Float64(Float64(A + C) + hypot(B_m, Float64(A - C))) / fma(-4.0, Float64(A * C), Float64(B_m * B_m))))) * Float64(-sqrt(2.0)));
	else
		tmp = Float64(Float64(sqrt(Float64(C + hypot(C, B_m))) * sqrt(F)) * Float64(sqrt(2.0) / Float64(-B_m)));
	end
	return tmp
end
B_m = N[Abs[B], $MachinePrecision]
NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
code[A_, B$95$m_, C_, F_] := Block[{t$95$0 = N[(B$95$m * B$95$m + N[(A * N[(C * -4.0), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[N[Power[B$95$m, 2.0], $MachinePrecision], 1e-294], (-N[Sqrt[N[Abs[N[(-0.5 * N[(2.0 * N[(F / A), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]], $MachinePrecision]), If[LessEqual[N[Power[B$95$m, 2.0], $MachinePrecision], 5e-230], N[(N[Sqrt[N[(N[(F * t$95$0), $MachinePrecision] * N[(C * 4.0), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / (-t$95$0)), $MachinePrecision], If[LessEqual[N[Power[B$95$m, 2.0], $MachinePrecision], 5e+233], N[(N[Sqrt[N[(F * N[(N[(N[(A + C), $MachinePrecision] + N[Sqrt[B$95$m ^ 2 + N[(A - C), $MachinePrecision] ^ 2], $MachinePrecision]), $MachinePrecision] / N[(-4.0 * N[(A * C), $MachinePrecision] + N[(B$95$m * B$95$m), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] * (-N[Sqrt[2.0], $MachinePrecision])), $MachinePrecision], N[(N[(N[Sqrt[N[(C + N[Sqrt[C ^ 2 + B$95$m ^ 2], $MachinePrecision]), $MachinePrecision]], $MachinePrecision] * N[Sqrt[F], $MachinePrecision]), $MachinePrecision] * N[(N[Sqrt[2.0], $MachinePrecision] / (-B$95$m)), $MachinePrecision]), $MachinePrecision]]]]]
\begin{array}{l}
B_m = \left|B\right|
\\
[A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
\\
\begin{array}{l}
t_0 := \mathsf{fma}\left(B\_m, B\_m, A \cdot \left(C \cdot -4\right)\right)\\
\mathbf{if}\;{B\_m}^{2} \leq 10^{-294}:\\
\;\;\;\;-\sqrt{\left|-0.5 \cdot \left(2 \cdot \frac{F}{A}\right)\right|}\\

\mathbf{elif}\;{B\_m}^{2} \leq 5 \cdot 10^{-230}:\\
\;\;\;\;\frac{\sqrt{\left(F \cdot t\_0\right) \cdot \left(C \cdot 4\right)}}{-t\_0}\\

\mathbf{elif}\;{B\_m}^{2} \leq 5 \cdot 10^{+233}:\\
\;\;\;\;\sqrt{F \cdot \frac{\left(A + C\right) + \mathsf{hypot}\left(B\_m, A - C\right)}{\mathsf{fma}\left(-4, A \cdot C, B\_m \cdot B\_m\right)}} \cdot \left(-\sqrt{2}\right)\\

\mathbf{else}:\\
\;\;\;\;\left(\sqrt{C + \mathsf{hypot}\left(C, B\_m\right)} \cdot \sqrt{F}\right) \cdot \frac{\sqrt{2}}{-B\_m}\\


\end{array}
\end{array}
Derivation
  1. Split input into 4 regimes
  2. if (pow.f64 B #s(literal 2 binary64)) < 1.00000000000000002e-294

    1. Initial program 20.5%

      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    2. Add Preprocessing
    3. Taylor expanded in F around 0 22.1%

      \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2}\right)} \]
    4. Simplified34.5%

      \[\leadsto \color{blue}{-\sqrt{2} \cdot \sqrt{F \cdot \frac{\left(C + A\right) + \mathsf{hypot}\left(B, A - C\right)}{\mathsf{fma}\left(-4, C \cdot A, {B}^{2}\right)}}} \]
    5. Taylor expanded in C around inf 29.8%

      \[\leadsto -\sqrt{2} \cdot \sqrt{\color{blue}{-0.5 \cdot \frac{F}{A}}} \]
    6. Step-by-step derivation
      1. *-commutative29.8%

        \[\leadsto -\color{blue}{\sqrt{-0.5 \cdot \frac{F}{A}} \cdot \sqrt{2}} \]
      2. pow1/229.9%

        \[\leadsto -\color{blue}{{\left(-0.5 \cdot \frac{F}{A}\right)}^{0.5}} \cdot \sqrt{2} \]
      3. pow1/229.9%

        \[\leadsto -{\left(-0.5 \cdot \frac{F}{A}\right)}^{0.5} \cdot \color{blue}{{2}^{0.5}} \]
      4. pow-prod-down30.0%

        \[\leadsto -\color{blue}{{\left(\left(-0.5 \cdot \frac{F}{A}\right) \cdot 2\right)}^{0.5}} \]
      5. associate-*r/30.0%

        \[\leadsto -{\left(\color{blue}{\frac{-0.5 \cdot F}{A}} \cdot 2\right)}^{0.5} \]
    7. Applied egg-rr30.0%

      \[\leadsto -\color{blue}{{\left(\frac{-0.5 \cdot F}{A} \cdot 2\right)}^{0.5}} \]
    8. Step-by-step derivation
      1. unpow1/229.9%

        \[\leadsto -\color{blue}{\sqrt{\frac{-0.5 \cdot F}{A} \cdot 2}} \]
    9. Simplified29.9%

      \[\leadsto -\color{blue}{\sqrt{\frac{-0.5 \cdot F}{A} \cdot 2}} \]
    10. Step-by-step derivation
      1. add-sqr-sqrt29.9%

        \[\leadsto -\sqrt{\color{blue}{\sqrt{\frac{-0.5 \cdot F}{A} \cdot 2} \cdot \sqrt{\frac{-0.5 \cdot F}{A} \cdot 2}}} \]
      2. pow1/229.9%

        \[\leadsto -\sqrt{\color{blue}{{\left(\frac{-0.5 \cdot F}{A} \cdot 2\right)}^{0.5}} \cdot \sqrt{\frac{-0.5 \cdot F}{A} \cdot 2}} \]
      3. pow1/230.0%

        \[\leadsto -\sqrt{{\left(\frac{-0.5 \cdot F}{A} \cdot 2\right)}^{0.5} \cdot \color{blue}{{\left(\frac{-0.5 \cdot F}{A} \cdot 2\right)}^{0.5}}} \]
      4. pow-prod-down25.6%

        \[\leadsto -\sqrt{\color{blue}{{\left(\left(\frac{-0.5 \cdot F}{A} \cdot 2\right) \cdot \left(\frac{-0.5 \cdot F}{A} \cdot 2\right)\right)}^{0.5}}} \]
      5. pow225.6%

        \[\leadsto -\sqrt{{\color{blue}{\left({\left(\frac{-0.5 \cdot F}{A} \cdot 2\right)}^{2}\right)}}^{0.5}} \]
      6. associate-/l*25.6%

        \[\leadsto -\sqrt{{\left({\left(\color{blue}{\left(-0.5 \cdot \frac{F}{A}\right)} \cdot 2\right)}^{2}\right)}^{0.5}} \]
    11. Applied egg-rr25.6%

      \[\leadsto -\sqrt{\color{blue}{{\left({\left(\left(-0.5 \cdot \frac{F}{A}\right) \cdot 2\right)}^{2}\right)}^{0.5}}} \]
    12. Step-by-step derivation
      1. unpow1/225.6%

        \[\leadsto -\sqrt{\color{blue}{\sqrt{{\left(\left(-0.5 \cdot \frac{F}{A}\right) \cdot 2\right)}^{2}}}} \]
      2. unpow225.6%

        \[\leadsto -\sqrt{\sqrt{\color{blue}{\left(\left(-0.5 \cdot \frac{F}{A}\right) \cdot 2\right) \cdot \left(\left(-0.5 \cdot \frac{F}{A}\right) \cdot 2\right)}}} \]
      3. rem-sqrt-square31.8%

        \[\leadsto -\sqrt{\color{blue}{\left|\left(-0.5 \cdot \frac{F}{A}\right) \cdot 2\right|}} \]
      4. associate-*l*31.8%

        \[\leadsto -\sqrt{\left|\color{blue}{-0.5 \cdot \left(\frac{F}{A} \cdot 2\right)}\right|} \]
    13. Simplified31.8%

      \[\leadsto -\sqrt{\color{blue}{\left|-0.5 \cdot \left(\frac{F}{A} \cdot 2\right)\right|}} \]

    if 1.00000000000000002e-294 < (pow.f64 B #s(literal 2 binary64)) < 5.00000000000000035e-230

    1. Initial program 20.9%

      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    2. Simplified41.6%

      \[\leadsto \color{blue}{\frac{\sqrt{\left(\mathsf{fma}\left(B, B, A \cdot \left(C \cdot -4\right)\right) \cdot F\right) \cdot \left(2 \cdot \left(A + \left(C + \mathsf{hypot}\left(B, A - C\right)\right)\right)\right)}}{-\mathsf{fma}\left(B, B, A \cdot \left(C \cdot -4\right)\right)}} \]
    3. Add Preprocessing
    4. Taylor expanded in A around -inf 32.8%

      \[\leadsto \frac{\sqrt{\left(\mathsf{fma}\left(B, B, A \cdot \left(C \cdot -4\right)\right) \cdot F\right) \cdot \color{blue}{\left(4 \cdot C\right)}}}{-\mathsf{fma}\left(B, B, A \cdot \left(C \cdot -4\right)\right)} \]
    5. Step-by-step derivation
      1. *-commutative32.8%

        \[\leadsto \frac{\sqrt{\left(\mathsf{fma}\left(B, B, A \cdot \left(C \cdot -4\right)\right) \cdot F\right) \cdot \color{blue}{\left(C \cdot 4\right)}}}{-\mathsf{fma}\left(B, B, A \cdot \left(C \cdot -4\right)\right)} \]
    6. Simplified32.8%

      \[\leadsto \frac{\sqrt{\left(\mathsf{fma}\left(B, B, A \cdot \left(C \cdot -4\right)\right) \cdot F\right) \cdot \color{blue}{\left(C \cdot 4\right)}}}{-\mathsf{fma}\left(B, B, A \cdot \left(C \cdot -4\right)\right)} \]

    if 5.00000000000000035e-230 < (pow.f64 B #s(literal 2 binary64)) < 5.00000000000000009e233

    1. Initial program 31.3%

      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    2. Add Preprocessing
    3. Taylor expanded in F around 0 28.7%

      \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2}\right)} \]
    4. Simplified50.5%

      \[\leadsto \color{blue}{-\sqrt{2} \cdot \sqrt{F \cdot \frac{\left(C + A\right) + \mathsf{hypot}\left(B, A - C\right)}{\mathsf{fma}\left(-4, C \cdot A, {B}^{2}\right)}}} \]
    5. Step-by-step derivation
      1. unpow250.5%

        \[\leadsto -\sqrt{2} \cdot \sqrt{F \cdot \frac{\left(C + A\right) + \mathsf{hypot}\left(B, A - C\right)}{\mathsf{fma}\left(-4, C \cdot A, \color{blue}{B \cdot B}\right)}} \]
    6. Applied egg-rr50.5%

      \[\leadsto -\sqrt{2} \cdot \sqrt{F \cdot \frac{\left(C + A\right) + \mathsf{hypot}\left(B, A - C\right)}{\mathsf{fma}\left(-4, C \cdot A, \color{blue}{B \cdot B}\right)}} \]

    if 5.00000000000000009e233 < (pow.f64 B #s(literal 2 binary64))

    1. Initial program 5.1%

      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    2. Add Preprocessing
    3. Taylor expanded in A around 0 6.7%

      \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right)} \]
    4. Step-by-step derivation
      1. mul-1-neg6.7%

        \[\leadsto \color{blue}{-\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
      2. *-commutative6.7%

        \[\leadsto -\color{blue}{\sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \cdot \frac{\sqrt{2}}{B}} \]
      3. *-commutative6.7%

        \[\leadsto -\sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \cdot \frac{\sqrt{2}}{B} \]
      4. +-commutative6.7%

        \[\leadsto -\sqrt{\left(C + \sqrt{\color{blue}{{C}^{2} + {B}^{2}}}\right) \cdot F} \cdot \frac{\sqrt{2}}{B} \]
      5. unpow26.7%

        \[\leadsto -\sqrt{\left(C + \sqrt{\color{blue}{C \cdot C} + {B}^{2}}\right) \cdot F} \cdot \frac{\sqrt{2}}{B} \]
      6. unpow26.7%

        \[\leadsto -\sqrt{\left(C + \sqrt{C \cdot C + \color{blue}{B \cdot B}}\right) \cdot F} \cdot \frac{\sqrt{2}}{B} \]
      7. hypot-define27.2%

        \[\leadsto -\sqrt{\left(C + \color{blue}{\mathsf{hypot}\left(C, B\right)}\right) \cdot F} \cdot \frac{\sqrt{2}}{B} \]
    5. Simplified27.2%

      \[\leadsto \color{blue}{-\sqrt{\left(C + \mathsf{hypot}\left(C, B\right)\right) \cdot F} \cdot \frac{\sqrt{2}}{B}} \]
    6. Step-by-step derivation
      1. sqrt-prod39.4%

        \[\leadsto -\color{blue}{\left(\sqrt{C + \mathsf{hypot}\left(C, B\right)} \cdot \sqrt{F}\right)} \cdot \frac{\sqrt{2}}{B} \]
    7. Applied egg-rr39.4%

      \[\leadsto -\color{blue}{\left(\sqrt{C + \mathsf{hypot}\left(C, B\right)} \cdot \sqrt{F}\right)} \cdot \frac{\sqrt{2}}{B} \]
  3. Recombined 4 regimes into one program.
  4. Final simplification40.8%

    \[\leadsto \begin{array}{l} \mathbf{if}\;{B}^{2} \leq 10^{-294}:\\ \;\;\;\;-\sqrt{\left|-0.5 \cdot \left(2 \cdot \frac{F}{A}\right)\right|}\\ \mathbf{elif}\;{B}^{2} \leq 5 \cdot 10^{-230}:\\ \;\;\;\;\frac{\sqrt{\left(F \cdot \mathsf{fma}\left(B, B, A \cdot \left(C \cdot -4\right)\right)\right) \cdot \left(C \cdot 4\right)}}{-\mathsf{fma}\left(B, B, A \cdot \left(C \cdot -4\right)\right)}\\ \mathbf{elif}\;{B}^{2} \leq 5 \cdot 10^{+233}:\\ \;\;\;\;\sqrt{F \cdot \frac{\left(A + C\right) + \mathsf{hypot}\left(B, A - C\right)}{\mathsf{fma}\left(-4, A \cdot C, B \cdot B\right)}} \cdot \left(-\sqrt{2}\right)\\ \mathbf{else}:\\ \;\;\;\;\left(\sqrt{C + \mathsf{hypot}\left(C, B\right)} \cdot \sqrt{F}\right) \cdot \frac{\sqrt{2}}{-B}\\ \end{array} \]
  5. Add Preprocessing

Alternative 3: 52.9% accurate, 1.0× speedup?

\[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} \mathbf{if}\;{B\_m}^{2} \leq 10^{-155}:\\ \;\;\;\;-\sqrt{\left|-0.5 \cdot \left(2 \cdot \frac{F}{A}\right)\right|}\\ \mathbf{elif}\;{B\_m}^{2} \leq 10^{+100}:\\ \;\;\;\;-\sqrt{2 \cdot \frac{F \cdot \left(\left(A + C\right) + \mathsf{hypot}\left(B\_m, A - C\right)\right)}{\mathsf{fma}\left(-4, A \cdot C, {B\_m}^{2}\right)}}\\ \mathbf{else}:\\ \;\;\;\;\left(\sqrt{C + \mathsf{hypot}\left(C, B\_m\right)} \cdot \sqrt{F}\right) \cdot \frac{\sqrt{2}}{-B\_m}\\ \end{array} \end{array} \]
B_m = (fabs.f64 B)
NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
(FPCore (A B_m C F)
 :precision binary64
 (if (<= (pow B_m 2.0) 1e-155)
   (- (sqrt (fabs (* -0.5 (* 2.0 (/ F A))))))
   (if (<= (pow B_m 2.0) 1e+100)
     (-
      (sqrt
       (*
        2.0
        (/
         (* F (+ (+ A C) (hypot B_m (- A C))))
         (fma -4.0 (* A C) (pow B_m 2.0))))))
     (* (* (sqrt (+ C (hypot C B_m))) (sqrt F)) (/ (sqrt 2.0) (- B_m))))))
B_m = fabs(B);
assert(A < B_m && B_m < C && C < F);
double code(double A, double B_m, double C, double F) {
	double tmp;
	if (pow(B_m, 2.0) <= 1e-155) {
		tmp = -sqrt(fabs((-0.5 * (2.0 * (F / A)))));
	} else if (pow(B_m, 2.0) <= 1e+100) {
		tmp = -sqrt((2.0 * ((F * ((A + C) + hypot(B_m, (A - C)))) / fma(-4.0, (A * C), pow(B_m, 2.0)))));
	} else {
		tmp = (sqrt((C + hypot(C, B_m))) * sqrt(F)) * (sqrt(2.0) / -B_m);
	}
	return tmp;
}
B_m = abs(B)
A, B_m, C, F = sort([A, B_m, C, F])
function code(A, B_m, C, F)
	tmp = 0.0
	if ((B_m ^ 2.0) <= 1e-155)
		tmp = Float64(-sqrt(abs(Float64(-0.5 * Float64(2.0 * Float64(F / A))))));
	elseif ((B_m ^ 2.0) <= 1e+100)
		tmp = Float64(-sqrt(Float64(2.0 * Float64(Float64(F * Float64(Float64(A + C) + hypot(B_m, Float64(A - C)))) / fma(-4.0, Float64(A * C), (B_m ^ 2.0))))));
	else
		tmp = Float64(Float64(sqrt(Float64(C + hypot(C, B_m))) * sqrt(F)) * Float64(sqrt(2.0) / Float64(-B_m)));
	end
	return tmp
end
B_m = N[Abs[B], $MachinePrecision]
NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
code[A_, B$95$m_, C_, F_] := If[LessEqual[N[Power[B$95$m, 2.0], $MachinePrecision], 1e-155], (-N[Sqrt[N[Abs[N[(-0.5 * N[(2.0 * N[(F / A), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]], $MachinePrecision]), If[LessEqual[N[Power[B$95$m, 2.0], $MachinePrecision], 1e+100], (-N[Sqrt[N[(2.0 * N[(N[(F * N[(N[(A + C), $MachinePrecision] + N[Sqrt[B$95$m ^ 2 + N[(A - C), $MachinePrecision] ^ 2], $MachinePrecision]), $MachinePrecision]), $MachinePrecision] / N[(-4.0 * N[(A * C), $MachinePrecision] + N[Power[B$95$m, 2.0], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), N[(N[(N[Sqrt[N[(C + N[Sqrt[C ^ 2 + B$95$m ^ 2], $MachinePrecision]), $MachinePrecision]], $MachinePrecision] * N[Sqrt[F], $MachinePrecision]), $MachinePrecision] * N[(N[Sqrt[2.0], $MachinePrecision] / (-B$95$m)), $MachinePrecision]), $MachinePrecision]]]
\begin{array}{l}
B_m = \left|B\right|
\\
[A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
\\
\begin{array}{l}
\mathbf{if}\;{B\_m}^{2} \leq 10^{-155}:\\
\;\;\;\;-\sqrt{\left|-0.5 \cdot \left(2 \cdot \frac{F}{A}\right)\right|}\\

\mathbf{elif}\;{B\_m}^{2} \leq 10^{+100}:\\
\;\;\;\;-\sqrt{2 \cdot \frac{F \cdot \left(\left(A + C\right) + \mathsf{hypot}\left(B\_m, A - C\right)\right)}{\mathsf{fma}\left(-4, A \cdot C, {B\_m}^{2}\right)}}\\

\mathbf{else}:\\
\;\;\;\;\left(\sqrt{C + \mathsf{hypot}\left(C, B\_m\right)} \cdot \sqrt{F}\right) \cdot \frac{\sqrt{2}}{-B\_m}\\


\end{array}
\end{array}
Derivation
  1. Split input into 3 regimes
  2. if (pow.f64 B #s(literal 2 binary64)) < 1.00000000000000001e-155

    1. Initial program 22.7%

      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    2. Add Preprocessing
    3. Taylor expanded in F around 0 21.7%

      \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2}\right)} \]
    4. Simplified35.6%

      \[\leadsto \color{blue}{-\sqrt{2} \cdot \sqrt{F \cdot \frac{\left(C + A\right) + \mathsf{hypot}\left(B, A - C\right)}{\mathsf{fma}\left(-4, C \cdot A, {B}^{2}\right)}}} \]
    5. Taylor expanded in C around inf 27.6%

      \[\leadsto -\sqrt{2} \cdot \sqrt{\color{blue}{-0.5 \cdot \frac{F}{A}}} \]
    6. Step-by-step derivation
      1. *-commutative27.6%

        \[\leadsto -\color{blue}{\sqrt{-0.5 \cdot \frac{F}{A}} \cdot \sqrt{2}} \]
      2. pow1/227.8%

        \[\leadsto -\color{blue}{{\left(-0.5 \cdot \frac{F}{A}\right)}^{0.5}} \cdot \sqrt{2} \]
      3. pow1/227.8%

        \[\leadsto -{\left(-0.5 \cdot \frac{F}{A}\right)}^{0.5} \cdot \color{blue}{{2}^{0.5}} \]
      4. pow-prod-down27.9%

        \[\leadsto -\color{blue}{{\left(\left(-0.5 \cdot \frac{F}{A}\right) \cdot 2\right)}^{0.5}} \]
      5. associate-*r/27.9%

        \[\leadsto -{\left(\color{blue}{\frac{-0.5 \cdot F}{A}} \cdot 2\right)}^{0.5} \]
    7. Applied egg-rr27.9%

      \[\leadsto -\color{blue}{{\left(\frac{-0.5 \cdot F}{A} \cdot 2\right)}^{0.5}} \]
    8. Step-by-step derivation
      1. unpow1/227.7%

        \[\leadsto -\color{blue}{\sqrt{\frac{-0.5 \cdot F}{A} \cdot 2}} \]
    9. Simplified27.7%

      \[\leadsto -\color{blue}{\sqrt{\frac{-0.5 \cdot F}{A} \cdot 2}} \]
    10. Step-by-step derivation
      1. add-sqr-sqrt27.7%

        \[\leadsto -\sqrt{\color{blue}{\sqrt{\frac{-0.5 \cdot F}{A} \cdot 2} \cdot \sqrt{\frac{-0.5 \cdot F}{A} \cdot 2}}} \]
      2. pow1/227.7%

        \[\leadsto -\sqrt{\color{blue}{{\left(\frac{-0.5 \cdot F}{A} \cdot 2\right)}^{0.5}} \cdot \sqrt{\frac{-0.5 \cdot F}{A} \cdot 2}} \]
      3. pow1/227.9%

        \[\leadsto -\sqrt{{\left(\frac{-0.5 \cdot F}{A} \cdot 2\right)}^{0.5} \cdot \color{blue}{{\left(\frac{-0.5 \cdot F}{A} \cdot 2\right)}^{0.5}}} \]
      4. pow-prod-down25.2%

        \[\leadsto -\sqrt{\color{blue}{{\left(\left(\frac{-0.5 \cdot F}{A} \cdot 2\right) \cdot \left(\frac{-0.5 \cdot F}{A} \cdot 2\right)\right)}^{0.5}}} \]
      5. pow225.2%

        \[\leadsto -\sqrt{{\color{blue}{\left({\left(\frac{-0.5 \cdot F}{A} \cdot 2\right)}^{2}\right)}}^{0.5}} \]
      6. associate-/l*25.2%

        \[\leadsto -\sqrt{{\left({\left(\color{blue}{\left(-0.5 \cdot \frac{F}{A}\right)} \cdot 2\right)}^{2}\right)}^{0.5}} \]
    11. Applied egg-rr25.2%

      \[\leadsto -\sqrt{\color{blue}{{\left({\left(\left(-0.5 \cdot \frac{F}{A}\right) \cdot 2\right)}^{2}\right)}^{0.5}}} \]
    12. Step-by-step derivation
      1. unpow1/225.2%

        \[\leadsto -\sqrt{\color{blue}{\sqrt{{\left(\left(-0.5 \cdot \frac{F}{A}\right) \cdot 2\right)}^{2}}}} \]
      2. unpow225.2%

        \[\leadsto -\sqrt{\sqrt{\color{blue}{\left(\left(-0.5 \cdot \frac{F}{A}\right) \cdot 2\right) \cdot \left(\left(-0.5 \cdot \frac{F}{A}\right) \cdot 2\right)}}} \]
      3. rem-sqrt-square29.8%

        \[\leadsto -\sqrt{\color{blue}{\left|\left(-0.5 \cdot \frac{F}{A}\right) \cdot 2\right|}} \]
      4. associate-*l*29.8%

        \[\leadsto -\sqrt{\left|\color{blue}{-0.5 \cdot \left(\frac{F}{A} \cdot 2\right)}\right|} \]
    13. Simplified29.8%

      \[\leadsto -\sqrt{\color{blue}{\left|-0.5 \cdot \left(\frac{F}{A} \cdot 2\right)\right|}} \]

    if 1.00000000000000001e-155 < (pow.f64 B #s(literal 2 binary64)) < 1.00000000000000002e100

    1. Initial program 33.9%

      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    2. Add Preprocessing
    3. Taylor expanded in F around 0 32.4%

      \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2}\right)} \]
    4. Simplified48.3%

      \[\leadsto \color{blue}{-\sqrt{2} \cdot \sqrt{F \cdot \frac{\left(C + A\right) + \mathsf{hypot}\left(B, A - C\right)}{\mathsf{fma}\left(-4, C \cdot A, {B}^{2}\right)}}} \]
    5. Step-by-step derivation
      1. *-commutative48.3%

        \[\leadsto -\color{blue}{\sqrt{F \cdot \frac{\left(C + A\right) + \mathsf{hypot}\left(B, A - C\right)}{\mathsf{fma}\left(-4, C \cdot A, {B}^{2}\right)}} \cdot \sqrt{2}} \]
      2. pow1/248.3%

        \[\leadsto -\color{blue}{{\left(F \cdot \frac{\left(C + A\right) + \mathsf{hypot}\left(B, A - C\right)}{\mathsf{fma}\left(-4, C \cdot A, {B}^{2}\right)}\right)}^{0.5}} \cdot \sqrt{2} \]
      3. pow1/248.3%

        \[\leadsto -{\left(F \cdot \frac{\left(C + A\right) + \mathsf{hypot}\left(B, A - C\right)}{\mathsf{fma}\left(-4, C \cdot A, {B}^{2}\right)}\right)}^{0.5} \cdot \color{blue}{{2}^{0.5}} \]
      4. pow-prod-down48.4%

        \[\leadsto -\color{blue}{{\left(\left(F \cdot \frac{\left(C + A\right) + \mathsf{hypot}\left(B, A - C\right)}{\mathsf{fma}\left(-4, C \cdot A, {B}^{2}\right)}\right) \cdot 2\right)}^{0.5}} \]
      5. associate-*r/46.8%

        \[\leadsto -{\left(\color{blue}{\frac{F \cdot \left(\left(C + A\right) + \mathsf{hypot}\left(B, A - C\right)\right)}{\mathsf{fma}\left(-4, C \cdot A, {B}^{2}\right)}} \cdot 2\right)}^{0.5} \]
      6. +-commutative46.8%

        \[\leadsto -{\left(\frac{F \cdot \color{blue}{\left(\mathsf{hypot}\left(B, A - C\right) + \left(C + A\right)\right)}}{\mathsf{fma}\left(-4, C \cdot A, {B}^{2}\right)} \cdot 2\right)}^{0.5} \]
    6. Applied egg-rr46.8%

      \[\leadsto -\color{blue}{{\left(\frac{F \cdot \left(\mathsf{hypot}\left(B, A - C\right) + \left(C + A\right)\right)}{\mathsf{fma}\left(-4, C \cdot A, {B}^{2}\right)} \cdot 2\right)}^{0.5}} \]
    7. Step-by-step derivation
      1. unpow1/246.8%

        \[\leadsto -\color{blue}{\sqrt{\frac{F \cdot \left(\mathsf{hypot}\left(B, A - C\right) + \left(C + A\right)\right)}{\mathsf{fma}\left(-4, C \cdot A, {B}^{2}\right)} \cdot 2}} \]
    8. Simplified46.8%

      \[\leadsto -\color{blue}{\sqrt{\frac{F \cdot \left(\mathsf{hypot}\left(B, A - C\right) + \left(C + A\right)\right)}{\mathsf{fma}\left(-4, C \cdot A, {B}^{2}\right)} \cdot 2}} \]

    if 1.00000000000000002e100 < (pow.f64 B #s(literal 2 binary64))

    1. Initial program 9.0%

      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    2. Add Preprocessing
    3. Taylor expanded in A around 0 9.1%

      \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right)} \]
    4. Step-by-step derivation
      1. mul-1-neg9.1%

        \[\leadsto \color{blue}{-\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
      2. *-commutative9.1%

        \[\leadsto -\color{blue}{\sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \cdot \frac{\sqrt{2}}{B}} \]
      3. *-commutative9.1%

        \[\leadsto -\sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \cdot \frac{\sqrt{2}}{B} \]
      4. +-commutative9.1%

        \[\leadsto -\sqrt{\left(C + \sqrt{\color{blue}{{C}^{2} + {B}^{2}}}\right) \cdot F} \cdot \frac{\sqrt{2}}{B} \]
      5. unpow29.1%

        \[\leadsto -\sqrt{\left(C + \sqrt{\color{blue}{C \cdot C} + {B}^{2}}\right) \cdot F} \cdot \frac{\sqrt{2}}{B} \]
      6. unpow29.1%

        \[\leadsto -\sqrt{\left(C + \sqrt{C \cdot C + \color{blue}{B \cdot B}}\right) \cdot F} \cdot \frac{\sqrt{2}}{B} \]
      7. hypot-define25.7%

        \[\leadsto -\sqrt{\left(C + \color{blue}{\mathsf{hypot}\left(C, B\right)}\right) \cdot F} \cdot \frac{\sqrt{2}}{B} \]
    5. Simplified25.7%

      \[\leadsto \color{blue}{-\sqrt{\left(C + \mathsf{hypot}\left(C, B\right)\right) \cdot F} \cdot \frac{\sqrt{2}}{B}} \]
    6. Step-by-step derivation
      1. sqrt-prod36.2%

        \[\leadsto -\color{blue}{\left(\sqrt{C + \mathsf{hypot}\left(C, B\right)} \cdot \sqrt{F}\right)} \cdot \frac{\sqrt{2}}{B} \]
    7. Applied egg-rr36.2%

      \[\leadsto -\color{blue}{\left(\sqrt{C + \mathsf{hypot}\left(C, B\right)} \cdot \sqrt{F}\right)} \cdot \frac{\sqrt{2}}{B} \]
  3. Recombined 3 regimes into one program.
  4. Final simplification35.8%

    \[\leadsto \begin{array}{l} \mathbf{if}\;{B}^{2} \leq 10^{-155}:\\ \;\;\;\;-\sqrt{\left|-0.5 \cdot \left(2 \cdot \frac{F}{A}\right)\right|}\\ \mathbf{elif}\;{B}^{2} \leq 10^{+100}:\\ \;\;\;\;-\sqrt{2 \cdot \frac{F \cdot \left(\left(A + C\right) + \mathsf{hypot}\left(B, A - C\right)\right)}{\mathsf{fma}\left(-4, A \cdot C, {B}^{2}\right)}}\\ \mathbf{else}:\\ \;\;\;\;\left(\sqrt{C + \mathsf{hypot}\left(C, B\right)} \cdot \sqrt{F}\right) \cdot \frac{\sqrt{2}}{-B}\\ \end{array} \]
  5. Add Preprocessing

Alternative 4: 50.5% accurate, 1.0× speedup?

\[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} \mathbf{if}\;{B\_m}^{2} \leq 5000000000000:\\ \;\;\;\;-\sqrt{\left|-0.5 \cdot \left(2 \cdot \frac{F}{A}\right)\right|}\\ \mathbf{elif}\;{B\_m}^{2} \leq 5 \cdot 10^{+150}:\\ \;\;\;\;\frac{\sqrt{2}}{B\_m} \cdot \left(-\sqrt{F \cdot \left(A + \mathsf{hypot}\left(B\_m, A\right)\right)}\right)\\ \mathbf{else}:\\ \;\;\;\;\left(\sqrt{C + \mathsf{hypot}\left(C, B\_m\right)} \cdot \sqrt{F}\right) \cdot \frac{\sqrt{2}}{-B\_m}\\ \end{array} \end{array} \]
B_m = (fabs.f64 B)
NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
(FPCore (A B_m C F)
 :precision binary64
 (if (<= (pow B_m 2.0) 5000000000000.0)
   (- (sqrt (fabs (* -0.5 (* 2.0 (/ F A))))))
   (if (<= (pow B_m 2.0) 5e+150)
     (* (/ (sqrt 2.0) B_m) (- (sqrt (* F (+ A (hypot B_m A))))))
     (* (* (sqrt (+ C (hypot C B_m))) (sqrt F)) (/ (sqrt 2.0) (- B_m))))))
B_m = fabs(B);
assert(A < B_m && B_m < C && C < F);
double code(double A, double B_m, double C, double F) {
	double tmp;
	if (pow(B_m, 2.0) <= 5000000000000.0) {
		tmp = -sqrt(fabs((-0.5 * (2.0 * (F / A)))));
	} else if (pow(B_m, 2.0) <= 5e+150) {
		tmp = (sqrt(2.0) / B_m) * -sqrt((F * (A + hypot(B_m, A))));
	} else {
		tmp = (sqrt((C + hypot(C, B_m))) * sqrt(F)) * (sqrt(2.0) / -B_m);
	}
	return tmp;
}
B_m = Math.abs(B);
assert A < B_m && B_m < C && C < F;
public static double code(double A, double B_m, double C, double F) {
	double tmp;
	if (Math.pow(B_m, 2.0) <= 5000000000000.0) {
		tmp = -Math.sqrt(Math.abs((-0.5 * (2.0 * (F / A)))));
	} else if (Math.pow(B_m, 2.0) <= 5e+150) {
		tmp = (Math.sqrt(2.0) / B_m) * -Math.sqrt((F * (A + Math.hypot(B_m, A))));
	} else {
		tmp = (Math.sqrt((C + Math.hypot(C, B_m))) * Math.sqrt(F)) * (Math.sqrt(2.0) / -B_m);
	}
	return tmp;
}
B_m = math.fabs(B)
[A, B_m, C, F] = sort([A, B_m, C, F])
def code(A, B_m, C, F):
	tmp = 0
	if math.pow(B_m, 2.0) <= 5000000000000.0:
		tmp = -math.sqrt(math.fabs((-0.5 * (2.0 * (F / A)))))
	elif math.pow(B_m, 2.0) <= 5e+150:
		tmp = (math.sqrt(2.0) / B_m) * -math.sqrt((F * (A + math.hypot(B_m, A))))
	else:
		tmp = (math.sqrt((C + math.hypot(C, B_m))) * math.sqrt(F)) * (math.sqrt(2.0) / -B_m)
	return tmp
B_m = abs(B)
A, B_m, C, F = sort([A, B_m, C, F])
function code(A, B_m, C, F)
	tmp = 0.0
	if ((B_m ^ 2.0) <= 5000000000000.0)
		tmp = Float64(-sqrt(abs(Float64(-0.5 * Float64(2.0 * Float64(F / A))))));
	elseif ((B_m ^ 2.0) <= 5e+150)
		tmp = Float64(Float64(sqrt(2.0) / B_m) * Float64(-sqrt(Float64(F * Float64(A + hypot(B_m, A))))));
	else
		tmp = Float64(Float64(sqrt(Float64(C + hypot(C, B_m))) * sqrt(F)) * Float64(sqrt(2.0) / Float64(-B_m)));
	end
	return tmp
end
B_m = abs(B);
A, B_m, C, F = num2cell(sort([A, B_m, C, F])){:}
function tmp_2 = code(A, B_m, C, F)
	tmp = 0.0;
	if ((B_m ^ 2.0) <= 5000000000000.0)
		tmp = -sqrt(abs((-0.5 * (2.0 * (F / A)))));
	elseif ((B_m ^ 2.0) <= 5e+150)
		tmp = (sqrt(2.0) / B_m) * -sqrt((F * (A + hypot(B_m, A))));
	else
		tmp = (sqrt((C + hypot(C, B_m))) * sqrt(F)) * (sqrt(2.0) / -B_m);
	end
	tmp_2 = tmp;
end
B_m = N[Abs[B], $MachinePrecision]
NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
code[A_, B$95$m_, C_, F_] := If[LessEqual[N[Power[B$95$m, 2.0], $MachinePrecision], 5000000000000.0], (-N[Sqrt[N[Abs[N[(-0.5 * N[(2.0 * N[(F / A), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]], $MachinePrecision]), If[LessEqual[N[Power[B$95$m, 2.0], $MachinePrecision], 5e+150], N[(N[(N[Sqrt[2.0], $MachinePrecision] / B$95$m), $MachinePrecision] * (-N[Sqrt[N[(F * N[(A + N[Sqrt[B$95$m ^ 2 + A ^ 2], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision])), $MachinePrecision], N[(N[(N[Sqrt[N[(C + N[Sqrt[C ^ 2 + B$95$m ^ 2], $MachinePrecision]), $MachinePrecision]], $MachinePrecision] * N[Sqrt[F], $MachinePrecision]), $MachinePrecision] * N[(N[Sqrt[2.0], $MachinePrecision] / (-B$95$m)), $MachinePrecision]), $MachinePrecision]]]
\begin{array}{l}
B_m = \left|B\right|
\\
[A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
\\
\begin{array}{l}
\mathbf{if}\;{B\_m}^{2} \leq 5000000000000:\\
\;\;\;\;-\sqrt{\left|-0.5 \cdot \left(2 \cdot \frac{F}{A}\right)\right|}\\

\mathbf{elif}\;{B\_m}^{2} \leq 5 \cdot 10^{+150}:\\
\;\;\;\;\frac{\sqrt{2}}{B\_m} \cdot \left(-\sqrt{F \cdot \left(A + \mathsf{hypot}\left(B\_m, A\right)\right)}\right)\\

\mathbf{else}:\\
\;\;\;\;\left(\sqrt{C + \mathsf{hypot}\left(C, B\_m\right)} \cdot \sqrt{F}\right) \cdot \frac{\sqrt{2}}{-B\_m}\\


\end{array}
\end{array}
Derivation
  1. Split input into 3 regimes
  2. if (pow.f64 B #s(literal 2 binary64)) < 5e12

    1. Initial program 25.3%

      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    2. Add Preprocessing
    3. Taylor expanded in F around 0 23.9%

      \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2}\right)} \]
    4. Simplified38.3%

      \[\leadsto \color{blue}{-\sqrt{2} \cdot \sqrt{F \cdot \frac{\left(C + A\right) + \mathsf{hypot}\left(B, A - C\right)}{\mathsf{fma}\left(-4, C \cdot A, {B}^{2}\right)}}} \]
    5. Taylor expanded in C around inf 26.3%

      \[\leadsto -\sqrt{2} \cdot \sqrt{\color{blue}{-0.5 \cdot \frac{F}{A}}} \]
    6. Step-by-step derivation
      1. *-commutative26.3%

        \[\leadsto -\color{blue}{\sqrt{-0.5 \cdot \frac{F}{A}} \cdot \sqrt{2}} \]
      2. pow1/226.4%

        \[\leadsto -\color{blue}{{\left(-0.5 \cdot \frac{F}{A}\right)}^{0.5}} \cdot \sqrt{2} \]
      3. pow1/226.4%

        \[\leadsto -{\left(-0.5 \cdot \frac{F}{A}\right)}^{0.5} \cdot \color{blue}{{2}^{0.5}} \]
      4. pow-prod-down26.5%

        \[\leadsto -\color{blue}{{\left(\left(-0.5 \cdot \frac{F}{A}\right) \cdot 2\right)}^{0.5}} \]
      5. associate-*r/26.5%

        \[\leadsto -{\left(\color{blue}{\frac{-0.5 \cdot F}{A}} \cdot 2\right)}^{0.5} \]
    7. Applied egg-rr26.5%

      \[\leadsto -\color{blue}{{\left(\frac{-0.5 \cdot F}{A} \cdot 2\right)}^{0.5}} \]
    8. Step-by-step derivation
      1. unpow1/226.4%

        \[\leadsto -\color{blue}{\sqrt{\frac{-0.5 \cdot F}{A} \cdot 2}} \]
    9. Simplified26.4%

      \[\leadsto -\color{blue}{\sqrt{\frac{-0.5 \cdot F}{A} \cdot 2}} \]
    10. Step-by-step derivation
      1. add-sqr-sqrt26.4%

        \[\leadsto -\sqrt{\color{blue}{\sqrt{\frac{-0.5 \cdot F}{A} \cdot 2} \cdot \sqrt{\frac{-0.5 \cdot F}{A} \cdot 2}}} \]
      2. pow1/226.4%

        \[\leadsto -\sqrt{\color{blue}{{\left(\frac{-0.5 \cdot F}{A} \cdot 2\right)}^{0.5}} \cdot \sqrt{\frac{-0.5 \cdot F}{A} \cdot 2}} \]
      3. pow1/226.5%

        \[\leadsto -\sqrt{{\left(\frac{-0.5 \cdot F}{A} \cdot 2\right)}^{0.5} \cdot \color{blue}{{\left(\frac{-0.5 \cdot F}{A} \cdot 2\right)}^{0.5}}} \]
      4. pow-prod-down24.3%

        \[\leadsto -\sqrt{\color{blue}{{\left(\left(\frac{-0.5 \cdot F}{A} \cdot 2\right) \cdot \left(\frac{-0.5 \cdot F}{A} \cdot 2\right)\right)}^{0.5}}} \]
      5. pow224.3%

        \[\leadsto -\sqrt{{\color{blue}{\left({\left(\frac{-0.5 \cdot F}{A} \cdot 2\right)}^{2}\right)}}^{0.5}} \]
      6. associate-/l*24.3%

        \[\leadsto -\sqrt{{\left({\left(\color{blue}{\left(-0.5 \cdot \frac{F}{A}\right)} \cdot 2\right)}^{2}\right)}^{0.5}} \]
    11. Applied egg-rr24.3%

      \[\leadsto -\sqrt{\color{blue}{{\left({\left(\left(-0.5 \cdot \frac{F}{A}\right) \cdot 2\right)}^{2}\right)}^{0.5}}} \]
    12. Step-by-step derivation
      1. unpow1/224.3%

        \[\leadsto -\sqrt{\color{blue}{\sqrt{{\left(\left(-0.5 \cdot \frac{F}{A}\right) \cdot 2\right)}^{2}}}} \]
      2. unpow224.3%

        \[\leadsto -\sqrt{\sqrt{\color{blue}{\left(\left(-0.5 \cdot \frac{F}{A}\right) \cdot 2\right) \cdot \left(\left(-0.5 \cdot \frac{F}{A}\right) \cdot 2\right)}}} \]
      3. rem-sqrt-square28.4%

        \[\leadsto -\sqrt{\color{blue}{\left|\left(-0.5 \cdot \frac{F}{A}\right) \cdot 2\right|}} \]
      4. associate-*l*28.4%

        \[\leadsto -\sqrt{\left|\color{blue}{-0.5 \cdot \left(\frac{F}{A} \cdot 2\right)}\right|} \]
    13. Simplified28.4%

      \[\leadsto -\sqrt{\color{blue}{\left|-0.5 \cdot \left(\frac{F}{A} \cdot 2\right)\right|}} \]

    if 5e12 < (pow.f64 B #s(literal 2 binary64)) < 5.00000000000000009e150

    1. Initial program 35.4%

      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    2. Add Preprocessing
    3. Taylor expanded in C around 0 23.1%

      \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A + \sqrt{{A}^{2} + {B}^{2}}\right)}\right)} \]
    4. Step-by-step derivation
      1. mul-1-neg23.1%

        \[\leadsto \color{blue}{-\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A + \sqrt{{A}^{2} + {B}^{2}}\right)}} \]
      2. *-commutative23.1%

        \[\leadsto -\color{blue}{\sqrt{F \cdot \left(A + \sqrt{{A}^{2} + {B}^{2}}\right)} \cdot \frac{\sqrt{2}}{B}} \]
      3. *-commutative23.1%

        \[\leadsto -\sqrt{\color{blue}{\left(A + \sqrt{{A}^{2} + {B}^{2}}\right) \cdot F}} \cdot \frac{\sqrt{2}}{B} \]
      4. +-commutative23.1%

        \[\leadsto -\sqrt{\left(A + \sqrt{\color{blue}{{B}^{2} + {A}^{2}}}\right) \cdot F} \cdot \frac{\sqrt{2}}{B} \]
      5. unpow223.1%

        \[\leadsto -\sqrt{\left(A + \sqrt{\color{blue}{B \cdot B} + {A}^{2}}\right) \cdot F} \cdot \frac{\sqrt{2}}{B} \]
      6. unpow223.1%

        \[\leadsto -\sqrt{\left(A + \sqrt{B \cdot B + \color{blue}{A \cdot A}}\right) \cdot F} \cdot \frac{\sqrt{2}}{B} \]
      7. hypot-define30.3%

        \[\leadsto -\sqrt{\left(A + \color{blue}{\mathsf{hypot}\left(B, A\right)}\right) \cdot F} \cdot \frac{\sqrt{2}}{B} \]
    5. Simplified30.3%

      \[\leadsto \color{blue}{-\sqrt{\left(A + \mathsf{hypot}\left(B, A\right)\right) \cdot F} \cdot \frac{\sqrt{2}}{B}} \]

    if 5.00000000000000009e150 < (pow.f64 B #s(literal 2 binary64))

    1. Initial program 6.1%

      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    2. Add Preprocessing
    3. Taylor expanded in A around 0 7.4%

      \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right)} \]
    4. Step-by-step derivation
      1. mul-1-neg7.4%

        \[\leadsto \color{blue}{-\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
      2. *-commutative7.4%

        \[\leadsto -\color{blue}{\sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \cdot \frac{\sqrt{2}}{B}} \]
      3. *-commutative7.4%

        \[\leadsto -\sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \cdot \frac{\sqrt{2}}{B} \]
      4. +-commutative7.4%

        \[\leadsto -\sqrt{\left(C + \sqrt{\color{blue}{{C}^{2} + {B}^{2}}}\right) \cdot F} \cdot \frac{\sqrt{2}}{B} \]
      5. unpow27.4%

        \[\leadsto -\sqrt{\left(C + \sqrt{\color{blue}{C \cdot C} + {B}^{2}}\right) \cdot F} \cdot \frac{\sqrt{2}}{B} \]
      6. unpow27.4%

        \[\leadsto -\sqrt{\left(C + \sqrt{C \cdot C + \color{blue}{B \cdot B}}\right) \cdot F} \cdot \frac{\sqrt{2}}{B} \]
      7. hypot-define25.9%

        \[\leadsto -\sqrt{\left(C + \color{blue}{\mathsf{hypot}\left(C, B\right)}\right) \cdot F} \cdot \frac{\sqrt{2}}{B} \]
    5. Simplified25.9%

      \[\leadsto \color{blue}{-\sqrt{\left(C + \mathsf{hypot}\left(C, B\right)\right) \cdot F} \cdot \frac{\sqrt{2}}{B}} \]
    6. Step-by-step derivation
      1. sqrt-prod37.5%

        \[\leadsto -\color{blue}{\left(\sqrt{C + \mathsf{hypot}\left(C, B\right)} \cdot \sqrt{F}\right)} \cdot \frac{\sqrt{2}}{B} \]
    7. Applied egg-rr37.5%

      \[\leadsto -\color{blue}{\left(\sqrt{C + \mathsf{hypot}\left(C, B\right)} \cdot \sqrt{F}\right)} \cdot \frac{\sqrt{2}}{B} \]
  3. Recombined 3 regimes into one program.
  4. Final simplification31.4%

    \[\leadsto \begin{array}{l} \mathbf{if}\;{B}^{2} \leq 5000000000000:\\ \;\;\;\;-\sqrt{\left|-0.5 \cdot \left(2 \cdot \frac{F}{A}\right)\right|}\\ \mathbf{elif}\;{B}^{2} \leq 5 \cdot 10^{+150}:\\ \;\;\;\;\frac{\sqrt{2}}{B} \cdot \left(-\sqrt{F \cdot \left(A + \mathsf{hypot}\left(B, A\right)\right)}\right)\\ \mathbf{else}:\\ \;\;\;\;\left(\sqrt{C + \mathsf{hypot}\left(C, B\right)} \cdot \sqrt{F}\right) \cdot \frac{\sqrt{2}}{-B}\\ \end{array} \]
  5. Add Preprocessing

Alternative 5: 43.4% accurate, 1.5× speedup?

\[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} \mathbf{if}\;{B\_m}^{2} \leq 10^{+261}:\\ \;\;\;\;-\sqrt{\left|-0.5 \cdot \left(2 \cdot \frac{F}{A}\right)\right|}\\ \mathbf{else}:\\ \;\;\;\;\left(\sqrt{F} \cdot \sqrt{\frac{1 + \left(\frac{A}{B\_m} + \frac{C}{B\_m}\right)}{B\_m}}\right) \cdot \left(-\sqrt{2}\right)\\ \end{array} \end{array} \]
B_m = (fabs.f64 B)
NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
(FPCore (A B_m C F)
 :precision binary64
 (if (<= (pow B_m 2.0) 1e+261)
   (- (sqrt (fabs (* -0.5 (* 2.0 (/ F A))))))
   (*
    (* (sqrt F) (sqrt (/ (+ 1.0 (+ (/ A B_m) (/ C B_m))) B_m)))
    (- (sqrt 2.0)))))
B_m = fabs(B);
assert(A < B_m && B_m < C && C < F);
double code(double A, double B_m, double C, double F) {
	double tmp;
	if (pow(B_m, 2.0) <= 1e+261) {
		tmp = -sqrt(fabs((-0.5 * (2.0 * (F / A)))));
	} else {
		tmp = (sqrt(F) * sqrt(((1.0 + ((A / B_m) + (C / B_m))) / B_m))) * -sqrt(2.0);
	}
	return tmp;
}
B_m = abs(b)
NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
real(8) function code(a, b_m, c, f)
    real(8), intent (in) :: a
    real(8), intent (in) :: b_m
    real(8), intent (in) :: c
    real(8), intent (in) :: f
    real(8) :: tmp
    if ((b_m ** 2.0d0) <= 1d+261) then
        tmp = -sqrt(abs(((-0.5d0) * (2.0d0 * (f / a)))))
    else
        tmp = (sqrt(f) * sqrt(((1.0d0 + ((a / b_m) + (c / b_m))) / b_m))) * -sqrt(2.0d0)
    end if
    code = tmp
end function
B_m = Math.abs(B);
assert A < B_m && B_m < C && C < F;
public static double code(double A, double B_m, double C, double F) {
	double tmp;
	if (Math.pow(B_m, 2.0) <= 1e+261) {
		tmp = -Math.sqrt(Math.abs((-0.5 * (2.0 * (F / A)))));
	} else {
		tmp = (Math.sqrt(F) * Math.sqrt(((1.0 + ((A / B_m) + (C / B_m))) / B_m))) * -Math.sqrt(2.0);
	}
	return tmp;
}
B_m = math.fabs(B)
[A, B_m, C, F] = sort([A, B_m, C, F])
def code(A, B_m, C, F):
	tmp = 0
	if math.pow(B_m, 2.0) <= 1e+261:
		tmp = -math.sqrt(math.fabs((-0.5 * (2.0 * (F / A)))))
	else:
		tmp = (math.sqrt(F) * math.sqrt(((1.0 + ((A / B_m) + (C / B_m))) / B_m))) * -math.sqrt(2.0)
	return tmp
B_m = abs(B)
A, B_m, C, F = sort([A, B_m, C, F])
function code(A, B_m, C, F)
	tmp = 0.0
	if ((B_m ^ 2.0) <= 1e+261)
		tmp = Float64(-sqrt(abs(Float64(-0.5 * Float64(2.0 * Float64(F / A))))));
	else
		tmp = Float64(Float64(sqrt(F) * sqrt(Float64(Float64(1.0 + Float64(Float64(A / B_m) + Float64(C / B_m))) / B_m))) * Float64(-sqrt(2.0)));
	end
	return tmp
end
B_m = abs(B);
A, B_m, C, F = num2cell(sort([A, B_m, C, F])){:}
function tmp_2 = code(A, B_m, C, F)
	tmp = 0.0;
	if ((B_m ^ 2.0) <= 1e+261)
		tmp = -sqrt(abs((-0.5 * (2.0 * (F / A)))));
	else
		tmp = (sqrt(F) * sqrt(((1.0 + ((A / B_m) + (C / B_m))) / B_m))) * -sqrt(2.0);
	end
	tmp_2 = tmp;
end
B_m = N[Abs[B], $MachinePrecision]
NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
code[A_, B$95$m_, C_, F_] := If[LessEqual[N[Power[B$95$m, 2.0], $MachinePrecision], 1e+261], (-N[Sqrt[N[Abs[N[(-0.5 * N[(2.0 * N[(F / A), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]], $MachinePrecision]), N[(N[(N[Sqrt[F], $MachinePrecision] * N[Sqrt[N[(N[(1.0 + N[(N[(A / B$95$m), $MachinePrecision] + N[(C / B$95$m), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] / B$95$m), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] * (-N[Sqrt[2.0], $MachinePrecision])), $MachinePrecision]]
\begin{array}{l}
B_m = \left|B\right|
\\
[A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
\\
\begin{array}{l}
\mathbf{if}\;{B\_m}^{2} \leq 10^{+261}:\\
\;\;\;\;-\sqrt{\left|-0.5 \cdot \left(2 \cdot \frac{F}{A}\right)\right|}\\

\mathbf{else}:\\
\;\;\;\;\left(\sqrt{F} \cdot \sqrt{\frac{1 + \left(\frac{A}{B\_m} + \frac{C}{B\_m}\right)}{B\_m}}\right) \cdot \left(-\sqrt{2}\right)\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if (pow.f64 B #s(literal 2 binary64)) < 9.9999999999999993e260

    1. Initial program 25.0%

      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    2. Add Preprocessing
    3. Taylor expanded in F around 0 24.5%

      \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2}\right)} \]
    4. Simplified41.4%

      \[\leadsto \color{blue}{-\sqrt{2} \cdot \sqrt{F \cdot \frac{\left(C + A\right) + \mathsf{hypot}\left(B, A - C\right)}{\mathsf{fma}\left(-4, C \cdot A, {B}^{2}\right)}}} \]
    5. Taylor expanded in C around inf 26.2%

      \[\leadsto -\sqrt{2} \cdot \sqrt{\color{blue}{-0.5 \cdot \frac{F}{A}}} \]
    6. Step-by-step derivation
      1. *-commutative26.2%

        \[\leadsto -\color{blue}{\sqrt{-0.5 \cdot \frac{F}{A}} \cdot \sqrt{2}} \]
      2. pow1/226.4%

        \[\leadsto -\color{blue}{{\left(-0.5 \cdot \frac{F}{A}\right)}^{0.5}} \cdot \sqrt{2} \]
      3. pow1/226.4%

        \[\leadsto -{\left(-0.5 \cdot \frac{F}{A}\right)}^{0.5} \cdot \color{blue}{{2}^{0.5}} \]
      4. pow-prod-down26.5%

        \[\leadsto -\color{blue}{{\left(\left(-0.5 \cdot \frac{F}{A}\right) \cdot 2\right)}^{0.5}} \]
      5. associate-*r/26.5%

        \[\leadsto -{\left(\color{blue}{\frac{-0.5 \cdot F}{A}} \cdot 2\right)}^{0.5} \]
    7. Applied egg-rr26.5%

      \[\leadsto -\color{blue}{{\left(\frac{-0.5 \cdot F}{A} \cdot 2\right)}^{0.5}} \]
    8. Step-by-step derivation
      1. unpow1/226.3%

        \[\leadsto -\color{blue}{\sqrt{\frac{-0.5 \cdot F}{A} \cdot 2}} \]
    9. Simplified26.3%

      \[\leadsto -\color{blue}{\sqrt{\frac{-0.5 \cdot F}{A} \cdot 2}} \]
    10. Step-by-step derivation
      1. add-sqr-sqrt26.3%

        \[\leadsto -\sqrt{\color{blue}{\sqrt{\frac{-0.5 \cdot F}{A} \cdot 2} \cdot \sqrt{\frac{-0.5 \cdot F}{A} \cdot 2}}} \]
      2. pow1/226.3%

        \[\leadsto -\sqrt{\color{blue}{{\left(\frac{-0.5 \cdot F}{A} \cdot 2\right)}^{0.5}} \cdot \sqrt{\frac{-0.5 \cdot F}{A} \cdot 2}} \]
      3. pow1/226.5%

        \[\leadsto -\sqrt{{\left(\frac{-0.5 \cdot F}{A} \cdot 2\right)}^{0.5} \cdot \color{blue}{{\left(\frac{-0.5 \cdot F}{A} \cdot 2\right)}^{0.5}}} \]
      4. pow-prod-down23.7%

        \[\leadsto -\sqrt{\color{blue}{{\left(\left(\frac{-0.5 \cdot F}{A} \cdot 2\right) \cdot \left(\frac{-0.5 \cdot F}{A} \cdot 2\right)\right)}^{0.5}}} \]
      5. pow223.7%

        \[\leadsto -\sqrt{{\color{blue}{\left({\left(\frac{-0.5 \cdot F}{A} \cdot 2\right)}^{2}\right)}}^{0.5}} \]
      6. associate-/l*23.7%

        \[\leadsto -\sqrt{{\left({\left(\color{blue}{\left(-0.5 \cdot \frac{F}{A}\right)} \cdot 2\right)}^{2}\right)}^{0.5}} \]
    11. Applied egg-rr23.7%

      \[\leadsto -\sqrt{\color{blue}{{\left({\left(\left(-0.5 \cdot \frac{F}{A}\right) \cdot 2\right)}^{2}\right)}^{0.5}}} \]
    12. Step-by-step derivation
      1. unpow1/223.7%

        \[\leadsto -\sqrt{\color{blue}{\sqrt{{\left(\left(-0.5 \cdot \frac{F}{A}\right) \cdot 2\right)}^{2}}}} \]
      2. unpow223.7%

        \[\leadsto -\sqrt{\sqrt{\color{blue}{\left(\left(-0.5 \cdot \frac{F}{A}\right) \cdot 2\right) \cdot \left(\left(-0.5 \cdot \frac{F}{A}\right) \cdot 2\right)}}} \]
      3. rem-sqrt-square28.3%

        \[\leadsto -\sqrt{\color{blue}{\left|\left(-0.5 \cdot \frac{F}{A}\right) \cdot 2\right|}} \]
      4. associate-*l*28.3%

        \[\leadsto -\sqrt{\left|\color{blue}{-0.5 \cdot \left(\frac{F}{A} \cdot 2\right)}\right|} \]
    13. Simplified28.3%

      \[\leadsto -\sqrt{\color{blue}{\left|-0.5 \cdot \left(\frac{F}{A} \cdot 2\right)\right|}} \]

    if 9.9999999999999993e260 < (pow.f64 B #s(literal 2 binary64))

    1. Initial program 5.5%

      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    2. Add Preprocessing
    3. Taylor expanded in F around 0 7.2%

      \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2}\right)} \]
    4. Simplified14.4%

      \[\leadsto \color{blue}{-\sqrt{2} \cdot \sqrt{F \cdot \frac{\left(C + A\right) + \mathsf{hypot}\left(B, A - C\right)}{\mathsf{fma}\left(-4, C \cdot A, {B}^{2}\right)}}} \]
    5. Taylor expanded in B around inf 28.6%

      \[\leadsto -\sqrt{2} \cdot \sqrt{F \cdot \color{blue}{\frac{1 + \left(\frac{A}{B} + \frac{C}{B}\right)}{B}}} \]
    6. Step-by-step derivation
      1. pow1/228.6%

        \[\leadsto -\sqrt{2} \cdot \color{blue}{{\left(F \cdot \frac{1 + \left(\frac{A}{B} + \frac{C}{B}\right)}{B}\right)}^{0.5}} \]
      2. *-commutative28.6%

        \[\leadsto -\sqrt{2} \cdot {\color{blue}{\left(\frac{1 + \left(\frac{A}{B} + \frac{C}{B}\right)}{B} \cdot F\right)}}^{0.5} \]
      3. unpow-prod-down40.8%

        \[\leadsto -\sqrt{2} \cdot \color{blue}{\left({\left(\frac{1 + \left(\frac{A}{B} + \frac{C}{B}\right)}{B}\right)}^{0.5} \cdot {F}^{0.5}\right)} \]
      4. pow1/240.8%

        \[\leadsto -\sqrt{2} \cdot \left(\color{blue}{\sqrt{\frac{1 + \left(\frac{A}{B} + \frac{C}{B}\right)}{B}}} \cdot {F}^{0.5}\right) \]
      5. pow1/240.8%

        \[\leadsto -\sqrt{2} \cdot \left(\sqrt{\frac{1 + \left(\frac{A}{B} + \frac{C}{B}\right)}{B}} \cdot \color{blue}{\sqrt{F}}\right) \]
    7. Applied egg-rr40.8%

      \[\leadsto -\sqrt{2} \cdot \color{blue}{\left(\sqrt{\frac{1 + \left(\frac{A}{B} + \frac{C}{B}\right)}{B}} \cdot \sqrt{F}\right)} \]
  3. Recombined 2 regimes into one program.
  4. Final simplification31.1%

    \[\leadsto \begin{array}{l} \mathbf{if}\;{B}^{2} \leq 10^{+261}:\\ \;\;\;\;-\sqrt{\left|-0.5 \cdot \left(2 \cdot \frac{F}{A}\right)\right|}\\ \mathbf{else}:\\ \;\;\;\;\left(\sqrt{F} \cdot \sqrt{\frac{1 + \left(\frac{A}{B} + \frac{C}{B}\right)}{B}}\right) \cdot \left(-\sqrt{2}\right)\\ \end{array} \]
  5. Add Preprocessing

Alternative 6: 43.3% accurate, 2.0× speedup?

\[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} \mathbf{if}\;{B\_m}^{2} \leq 10^{+260}:\\ \;\;\;\;-\sqrt{\left|-0.5 \cdot \left(2 \cdot \frac{F}{A}\right)\right|}\\ \mathbf{else}:\\ \;\;\;\;\sqrt{\frac{2}{B\_m}} \cdot \left(-\sqrt{F}\right)\\ \end{array} \end{array} \]
B_m = (fabs.f64 B)
NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
(FPCore (A B_m C F)
 :precision binary64
 (if (<= (pow B_m 2.0) 1e+260)
   (- (sqrt (fabs (* -0.5 (* 2.0 (/ F A))))))
   (* (sqrt (/ 2.0 B_m)) (- (sqrt F)))))
B_m = fabs(B);
assert(A < B_m && B_m < C && C < F);
double code(double A, double B_m, double C, double F) {
	double tmp;
	if (pow(B_m, 2.0) <= 1e+260) {
		tmp = -sqrt(fabs((-0.5 * (2.0 * (F / A)))));
	} else {
		tmp = sqrt((2.0 / B_m)) * -sqrt(F);
	}
	return tmp;
}
B_m = abs(b)
NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
real(8) function code(a, b_m, c, f)
    real(8), intent (in) :: a
    real(8), intent (in) :: b_m
    real(8), intent (in) :: c
    real(8), intent (in) :: f
    real(8) :: tmp
    if ((b_m ** 2.0d0) <= 1d+260) then
        tmp = -sqrt(abs(((-0.5d0) * (2.0d0 * (f / a)))))
    else
        tmp = sqrt((2.0d0 / b_m)) * -sqrt(f)
    end if
    code = tmp
end function
B_m = Math.abs(B);
assert A < B_m && B_m < C && C < F;
public static double code(double A, double B_m, double C, double F) {
	double tmp;
	if (Math.pow(B_m, 2.0) <= 1e+260) {
		tmp = -Math.sqrt(Math.abs((-0.5 * (2.0 * (F / A)))));
	} else {
		tmp = Math.sqrt((2.0 / B_m)) * -Math.sqrt(F);
	}
	return tmp;
}
B_m = math.fabs(B)
[A, B_m, C, F] = sort([A, B_m, C, F])
def code(A, B_m, C, F):
	tmp = 0
	if math.pow(B_m, 2.0) <= 1e+260:
		tmp = -math.sqrt(math.fabs((-0.5 * (2.0 * (F / A)))))
	else:
		tmp = math.sqrt((2.0 / B_m)) * -math.sqrt(F)
	return tmp
B_m = abs(B)
A, B_m, C, F = sort([A, B_m, C, F])
function code(A, B_m, C, F)
	tmp = 0.0
	if ((B_m ^ 2.0) <= 1e+260)
		tmp = Float64(-sqrt(abs(Float64(-0.5 * Float64(2.0 * Float64(F / A))))));
	else
		tmp = Float64(sqrt(Float64(2.0 / B_m)) * Float64(-sqrt(F)));
	end
	return tmp
end
B_m = abs(B);
A, B_m, C, F = num2cell(sort([A, B_m, C, F])){:}
function tmp_2 = code(A, B_m, C, F)
	tmp = 0.0;
	if ((B_m ^ 2.0) <= 1e+260)
		tmp = -sqrt(abs((-0.5 * (2.0 * (F / A)))));
	else
		tmp = sqrt((2.0 / B_m)) * -sqrt(F);
	end
	tmp_2 = tmp;
end
B_m = N[Abs[B], $MachinePrecision]
NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
code[A_, B$95$m_, C_, F_] := If[LessEqual[N[Power[B$95$m, 2.0], $MachinePrecision], 1e+260], (-N[Sqrt[N[Abs[N[(-0.5 * N[(2.0 * N[(F / A), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]], $MachinePrecision]), N[(N[Sqrt[N[(2.0 / B$95$m), $MachinePrecision]], $MachinePrecision] * (-N[Sqrt[F], $MachinePrecision])), $MachinePrecision]]
\begin{array}{l}
B_m = \left|B\right|
\\
[A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
\\
\begin{array}{l}
\mathbf{if}\;{B\_m}^{2} \leq 10^{+260}:\\
\;\;\;\;-\sqrt{\left|-0.5 \cdot \left(2 \cdot \frac{F}{A}\right)\right|}\\

\mathbf{else}:\\
\;\;\;\;\sqrt{\frac{2}{B\_m}} \cdot \left(-\sqrt{F}\right)\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if (pow.f64 B #s(literal 2 binary64)) < 1.00000000000000007e260

    1. Initial program 25.1%

      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    2. Add Preprocessing
    3. Taylor expanded in F around 0 24.6%

      \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2}\right)} \]
    4. Simplified41.6%

      \[\leadsto \color{blue}{-\sqrt{2} \cdot \sqrt{F \cdot \frac{\left(C + A\right) + \mathsf{hypot}\left(B, A - C\right)}{\mathsf{fma}\left(-4, C \cdot A, {B}^{2}\right)}}} \]
    5. Taylor expanded in C around inf 26.3%

      \[\leadsto -\sqrt{2} \cdot \sqrt{\color{blue}{-0.5 \cdot \frac{F}{A}}} \]
    6. Step-by-step derivation
      1. *-commutative26.3%

        \[\leadsto -\color{blue}{\sqrt{-0.5 \cdot \frac{F}{A}} \cdot \sqrt{2}} \]
      2. pow1/226.5%

        \[\leadsto -\color{blue}{{\left(-0.5 \cdot \frac{F}{A}\right)}^{0.5}} \cdot \sqrt{2} \]
      3. pow1/226.5%

        \[\leadsto -{\left(-0.5 \cdot \frac{F}{A}\right)}^{0.5} \cdot \color{blue}{{2}^{0.5}} \]
      4. pow-prod-down26.6%

        \[\leadsto -\color{blue}{{\left(\left(-0.5 \cdot \frac{F}{A}\right) \cdot 2\right)}^{0.5}} \]
      5. associate-*r/26.6%

        \[\leadsto -{\left(\color{blue}{\frac{-0.5 \cdot F}{A}} \cdot 2\right)}^{0.5} \]
    7. Applied egg-rr26.6%

      \[\leadsto -\color{blue}{{\left(\frac{-0.5 \cdot F}{A} \cdot 2\right)}^{0.5}} \]
    8. Step-by-step derivation
      1. unpow1/226.4%

        \[\leadsto -\color{blue}{\sqrt{\frac{-0.5 \cdot F}{A} \cdot 2}} \]
    9. Simplified26.4%

      \[\leadsto -\color{blue}{\sqrt{\frac{-0.5 \cdot F}{A} \cdot 2}} \]
    10. Step-by-step derivation
      1. add-sqr-sqrt26.4%

        \[\leadsto -\sqrt{\color{blue}{\sqrt{\frac{-0.5 \cdot F}{A} \cdot 2} \cdot \sqrt{\frac{-0.5 \cdot F}{A} \cdot 2}}} \]
      2. pow1/226.4%

        \[\leadsto -\sqrt{\color{blue}{{\left(\frac{-0.5 \cdot F}{A} \cdot 2\right)}^{0.5}} \cdot \sqrt{\frac{-0.5 \cdot F}{A} \cdot 2}} \]
      3. pow1/226.6%

        \[\leadsto -\sqrt{{\left(\frac{-0.5 \cdot F}{A} \cdot 2\right)}^{0.5} \cdot \color{blue}{{\left(\frac{-0.5 \cdot F}{A} \cdot 2\right)}^{0.5}}} \]
      4. pow-prod-down23.8%

        \[\leadsto -\sqrt{\color{blue}{{\left(\left(\frac{-0.5 \cdot F}{A} \cdot 2\right) \cdot \left(\frac{-0.5 \cdot F}{A} \cdot 2\right)\right)}^{0.5}}} \]
      5. pow223.8%

        \[\leadsto -\sqrt{{\color{blue}{\left({\left(\frac{-0.5 \cdot F}{A} \cdot 2\right)}^{2}\right)}}^{0.5}} \]
      6. associate-/l*23.8%

        \[\leadsto -\sqrt{{\left({\left(\color{blue}{\left(-0.5 \cdot \frac{F}{A}\right)} \cdot 2\right)}^{2}\right)}^{0.5}} \]
    11. Applied egg-rr23.8%

      \[\leadsto -\sqrt{\color{blue}{{\left({\left(\left(-0.5 \cdot \frac{F}{A}\right) \cdot 2\right)}^{2}\right)}^{0.5}}} \]
    12. Step-by-step derivation
      1. unpow1/223.8%

        \[\leadsto -\sqrt{\color{blue}{\sqrt{{\left(\left(-0.5 \cdot \frac{F}{A}\right) \cdot 2\right)}^{2}}}} \]
      2. unpow223.8%

        \[\leadsto -\sqrt{\sqrt{\color{blue}{\left(\left(-0.5 \cdot \frac{F}{A}\right) \cdot 2\right) \cdot \left(\left(-0.5 \cdot \frac{F}{A}\right) \cdot 2\right)}}} \]
      3. rem-sqrt-square28.4%

        \[\leadsto -\sqrt{\color{blue}{\left|\left(-0.5 \cdot \frac{F}{A}\right) \cdot 2\right|}} \]
      4. associate-*l*28.4%

        \[\leadsto -\sqrt{\left|\color{blue}{-0.5 \cdot \left(\frac{F}{A} \cdot 2\right)}\right|} \]
    13. Simplified28.4%

      \[\leadsto -\sqrt{\color{blue}{\left|-0.5 \cdot \left(\frac{F}{A} \cdot 2\right)\right|}} \]

    if 1.00000000000000007e260 < (pow.f64 B #s(literal 2 binary64))

    1. Initial program 5.4%

      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    2. Add Preprocessing
    3. Taylor expanded in B around inf 26.7%

      \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
    4. Step-by-step derivation
      1. mul-1-neg26.7%

        \[\leadsto \color{blue}{-\sqrt{\frac{F}{B}} \cdot \sqrt{2}} \]
      2. *-commutative26.7%

        \[\leadsto -\color{blue}{\sqrt{2} \cdot \sqrt{\frac{F}{B}}} \]
    5. Simplified26.7%

      \[\leadsto \color{blue}{-\sqrt{2} \cdot \sqrt{\frac{F}{B}}} \]
    6. Step-by-step derivation
      1. *-commutative26.7%

        \[\leadsto -\color{blue}{\sqrt{\frac{F}{B}} \cdot \sqrt{2}} \]
      2. pow1/226.7%

        \[\leadsto -\color{blue}{{\left(\frac{F}{B}\right)}^{0.5}} \cdot \sqrt{2} \]
      3. pow1/226.7%

        \[\leadsto -{\left(\frac{F}{B}\right)}^{0.5} \cdot \color{blue}{{2}^{0.5}} \]
      4. pow-prod-down26.9%

        \[\leadsto -\color{blue}{{\left(\frac{F}{B} \cdot 2\right)}^{0.5}} \]
    7. Applied egg-rr26.9%

      \[\leadsto -\color{blue}{{\left(\frac{F}{B} \cdot 2\right)}^{0.5}} \]
    8. Step-by-step derivation
      1. unpow1/226.9%

        \[\leadsto -\color{blue}{\sqrt{\frac{F}{B} \cdot 2}} \]
    9. Simplified26.9%

      \[\leadsto -\color{blue}{\sqrt{\frac{F}{B} \cdot 2}} \]
    10. Step-by-step derivation
      1. associate-*l/26.9%

        \[\leadsto -\sqrt{\color{blue}{\frac{F \cdot 2}{B}}} \]
    11. Applied egg-rr26.9%

      \[\leadsto -\sqrt{\color{blue}{\frac{F \cdot 2}{B}}} \]
    12. Step-by-step derivation
      1. associate-/l*26.9%

        \[\leadsto -\sqrt{\color{blue}{F \cdot \frac{2}{B}}} \]
    13. Simplified26.9%

      \[\leadsto -\sqrt{\color{blue}{F \cdot \frac{2}{B}}} \]
    14. Step-by-step derivation
      1. pow1/226.9%

        \[\leadsto -\color{blue}{{\left(F \cdot \frac{2}{B}\right)}^{0.5}} \]
      2. *-commutative26.9%

        \[\leadsto -{\color{blue}{\left(\frac{2}{B} \cdot F\right)}}^{0.5} \]
      3. unpow-prod-down38.4%

        \[\leadsto -\color{blue}{{\left(\frac{2}{B}\right)}^{0.5} \cdot {F}^{0.5}} \]
      4. pow1/238.4%

        \[\leadsto -\color{blue}{\sqrt{\frac{2}{B}}} \cdot {F}^{0.5} \]
      5. pow1/238.4%

        \[\leadsto -\sqrt{\frac{2}{B}} \cdot \color{blue}{\sqrt{F}} \]
    15. Applied egg-rr38.4%

      \[\leadsto -\color{blue}{\sqrt{\frac{2}{B}} \cdot \sqrt{F}} \]
  3. Recombined 2 regimes into one program.
  4. Final simplification30.7%

    \[\leadsto \begin{array}{l} \mathbf{if}\;{B}^{2} \leq 10^{+260}:\\ \;\;\;\;-\sqrt{\left|-0.5 \cdot \left(2 \cdot \frac{F}{A}\right)\right|}\\ \mathbf{else}:\\ \;\;\;\;\sqrt{\frac{2}{B}} \cdot \left(-\sqrt{F}\right)\\ \end{array} \]
  5. Add Preprocessing

Alternative 7: 42.8% accurate, 3.0× speedup?

\[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} \mathbf{if}\;B\_m \leq 7.5 \cdot 10^{+129}:\\ \;\;\;\;-\sqrt{\frac{-F}{A}}\\ \mathbf{else}:\\ \;\;\;\;\sqrt{\frac{2}{B\_m}} \cdot \left(-\sqrt{F}\right)\\ \end{array} \end{array} \]
B_m = (fabs.f64 B)
NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
(FPCore (A B_m C F)
 :precision binary64
 (if (<= B_m 7.5e+129)
   (- (sqrt (/ (- F) A)))
   (* (sqrt (/ 2.0 B_m)) (- (sqrt F)))))
B_m = fabs(B);
assert(A < B_m && B_m < C && C < F);
double code(double A, double B_m, double C, double F) {
	double tmp;
	if (B_m <= 7.5e+129) {
		tmp = -sqrt((-F / A));
	} else {
		tmp = sqrt((2.0 / B_m)) * -sqrt(F);
	}
	return tmp;
}
B_m = abs(b)
NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
real(8) function code(a, b_m, c, f)
    real(8), intent (in) :: a
    real(8), intent (in) :: b_m
    real(8), intent (in) :: c
    real(8), intent (in) :: f
    real(8) :: tmp
    if (b_m <= 7.5d+129) then
        tmp = -sqrt((-f / a))
    else
        tmp = sqrt((2.0d0 / b_m)) * -sqrt(f)
    end if
    code = tmp
end function
B_m = Math.abs(B);
assert A < B_m && B_m < C && C < F;
public static double code(double A, double B_m, double C, double F) {
	double tmp;
	if (B_m <= 7.5e+129) {
		tmp = -Math.sqrt((-F / A));
	} else {
		tmp = Math.sqrt((2.0 / B_m)) * -Math.sqrt(F);
	}
	return tmp;
}
B_m = math.fabs(B)
[A, B_m, C, F] = sort([A, B_m, C, F])
def code(A, B_m, C, F):
	tmp = 0
	if B_m <= 7.5e+129:
		tmp = -math.sqrt((-F / A))
	else:
		tmp = math.sqrt((2.0 / B_m)) * -math.sqrt(F)
	return tmp
B_m = abs(B)
A, B_m, C, F = sort([A, B_m, C, F])
function code(A, B_m, C, F)
	tmp = 0.0
	if (B_m <= 7.5e+129)
		tmp = Float64(-sqrt(Float64(Float64(-F) / A)));
	else
		tmp = Float64(sqrt(Float64(2.0 / B_m)) * Float64(-sqrt(F)));
	end
	return tmp
end
B_m = abs(B);
A, B_m, C, F = num2cell(sort([A, B_m, C, F])){:}
function tmp_2 = code(A, B_m, C, F)
	tmp = 0.0;
	if (B_m <= 7.5e+129)
		tmp = -sqrt((-F / A));
	else
		tmp = sqrt((2.0 / B_m)) * -sqrt(F);
	end
	tmp_2 = tmp;
end
B_m = N[Abs[B], $MachinePrecision]
NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
code[A_, B$95$m_, C_, F_] := If[LessEqual[B$95$m, 7.5e+129], (-N[Sqrt[N[((-F) / A), $MachinePrecision]], $MachinePrecision]), N[(N[Sqrt[N[(2.0 / B$95$m), $MachinePrecision]], $MachinePrecision] * (-N[Sqrt[F], $MachinePrecision])), $MachinePrecision]]
\begin{array}{l}
B_m = \left|B\right|
\\
[A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
\\
\begin{array}{l}
\mathbf{if}\;B\_m \leq 7.5 \cdot 10^{+129}:\\
\;\;\;\;-\sqrt{\frac{-F}{A}}\\

\mathbf{else}:\\
\;\;\;\;\sqrt{\frac{2}{B\_m}} \cdot \left(-\sqrt{F}\right)\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if B < 7.4999999999999998e129

    1. Initial program 22.9%

      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    2. Add Preprocessing
    3. Taylor expanded in F around 0 22.4%

      \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2}\right)} \]
    4. Simplified38.2%

      \[\leadsto \color{blue}{-\sqrt{2} \cdot \sqrt{F \cdot \frac{\left(C + A\right) + \mathsf{hypot}\left(B, A - C\right)}{\mathsf{fma}\left(-4, C \cdot A, {B}^{2}\right)}}} \]
    5. Taylor expanded in C around inf 23.9%

      \[\leadsto -\sqrt{2} \cdot \sqrt{\color{blue}{-0.5 \cdot \frac{F}{A}}} \]
    6. Step-by-step derivation
      1. *-commutative23.9%

        \[\leadsto -\color{blue}{\sqrt{-0.5 \cdot \frac{F}{A}} \cdot \sqrt{2}} \]
      2. pow1/224.1%

        \[\leadsto -\color{blue}{{\left(-0.5 \cdot \frac{F}{A}\right)}^{0.5}} \cdot \sqrt{2} \]
      3. pow1/224.1%

        \[\leadsto -{\left(-0.5 \cdot \frac{F}{A}\right)}^{0.5} \cdot \color{blue}{{2}^{0.5}} \]
      4. pow-prod-down24.2%

        \[\leadsto -\color{blue}{{\left(\left(-0.5 \cdot \frac{F}{A}\right) \cdot 2\right)}^{0.5}} \]
      5. associate-*r/24.2%

        \[\leadsto -{\left(\color{blue}{\frac{-0.5 \cdot F}{A}} \cdot 2\right)}^{0.5} \]
    7. Applied egg-rr24.2%

      \[\leadsto -\color{blue}{{\left(\frac{-0.5 \cdot F}{A} \cdot 2\right)}^{0.5}} \]
    8. Step-by-step derivation
      1. unpow1/224.0%

        \[\leadsto -\color{blue}{\sqrt{\frac{-0.5 \cdot F}{A} \cdot 2}} \]
    9. Simplified24.0%

      \[\leadsto -\color{blue}{\sqrt{\frac{-0.5 \cdot F}{A} \cdot 2}} \]
    10. Taylor expanded in F around 0 24.0%

      \[\leadsto -\sqrt{\color{blue}{-1 \cdot \frac{F}{A}}} \]
    11. Step-by-step derivation
      1. associate-*r/24.0%

        \[\leadsto -\sqrt{\color{blue}{\frac{-1 \cdot F}{A}}} \]
      2. mul-1-neg24.0%

        \[\leadsto -\sqrt{\frac{\color{blue}{-F}}{A}} \]
    12. Simplified24.0%

      \[\leadsto -\sqrt{\color{blue}{\frac{-F}{A}}} \]

    if 7.4999999999999998e129 < B

    1. Initial program 3.8%

      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    2. Add Preprocessing
    3. Taylor expanded in B around inf 50.1%

      \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
    4. Step-by-step derivation
      1. mul-1-neg50.1%

        \[\leadsto \color{blue}{-\sqrt{\frac{F}{B}} \cdot \sqrt{2}} \]
      2. *-commutative50.1%

        \[\leadsto -\color{blue}{\sqrt{2} \cdot \sqrt{\frac{F}{B}}} \]
    5. Simplified50.1%

      \[\leadsto \color{blue}{-\sqrt{2} \cdot \sqrt{\frac{F}{B}}} \]
    6. Step-by-step derivation
      1. *-commutative50.1%

        \[\leadsto -\color{blue}{\sqrt{\frac{F}{B}} \cdot \sqrt{2}} \]
      2. pow1/250.1%

        \[\leadsto -\color{blue}{{\left(\frac{F}{B}\right)}^{0.5}} \cdot \sqrt{2} \]
      3. pow1/250.1%

        \[\leadsto -{\left(\frac{F}{B}\right)}^{0.5} \cdot \color{blue}{{2}^{0.5}} \]
      4. pow-prod-down50.4%

        \[\leadsto -\color{blue}{{\left(\frac{F}{B} \cdot 2\right)}^{0.5}} \]
    7. Applied egg-rr50.4%

      \[\leadsto -\color{blue}{{\left(\frac{F}{B} \cdot 2\right)}^{0.5}} \]
    8. Step-by-step derivation
      1. unpow1/250.4%

        \[\leadsto -\color{blue}{\sqrt{\frac{F}{B} \cdot 2}} \]
    9. Simplified50.4%

      \[\leadsto -\color{blue}{\sqrt{\frac{F}{B} \cdot 2}} \]
    10. Step-by-step derivation
      1. associate-*l/50.4%

        \[\leadsto -\sqrt{\color{blue}{\frac{F \cdot 2}{B}}} \]
    11. Applied egg-rr50.4%

      \[\leadsto -\sqrt{\color{blue}{\frac{F \cdot 2}{B}}} \]
    12. Step-by-step derivation
      1. associate-/l*50.4%

        \[\leadsto -\sqrt{\color{blue}{F \cdot \frac{2}{B}}} \]
    13. Simplified50.4%

      \[\leadsto -\sqrt{\color{blue}{F \cdot \frac{2}{B}}} \]
    14. Step-by-step derivation
      1. pow1/250.4%

        \[\leadsto -\color{blue}{{\left(F \cdot \frac{2}{B}\right)}^{0.5}} \]
      2. *-commutative50.4%

        \[\leadsto -{\color{blue}{\left(\frac{2}{B} \cdot F\right)}}^{0.5} \]
      3. unpow-prod-down74.2%

        \[\leadsto -\color{blue}{{\left(\frac{2}{B}\right)}^{0.5} \cdot {F}^{0.5}} \]
      4. pow1/274.2%

        \[\leadsto -\color{blue}{\sqrt{\frac{2}{B}}} \cdot {F}^{0.5} \]
      5. pow1/274.2%

        \[\leadsto -\sqrt{\frac{2}{B}} \cdot \color{blue}{\sqrt{F}} \]
    15. Applied egg-rr74.2%

      \[\leadsto -\color{blue}{\sqrt{\frac{2}{B}} \cdot \sqrt{F}} \]
  3. Recombined 2 regimes into one program.
  4. Final simplification29.9%

    \[\leadsto \begin{array}{l} \mathbf{if}\;B \leq 7.5 \cdot 10^{+129}:\\ \;\;\;\;-\sqrt{\frac{-F}{A}}\\ \mathbf{else}:\\ \;\;\;\;\sqrt{\frac{2}{B}} \cdot \left(-\sqrt{F}\right)\\ \end{array} \]
  5. Add Preprocessing

Alternative 8: 36.4% accurate, 5.2× speedup?

\[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} \mathbf{if}\;B\_m \leq 1.32 \cdot 10^{+132}:\\ \;\;\;\;-\sqrt{\frac{-F}{A}}\\ \mathbf{else}:\\ \;\;\;\;-\sqrt{F \cdot \left(2 \cdot \frac{1 + \left(\frac{A}{B\_m} + \frac{C}{B\_m}\right)}{B\_m}\right)}\\ \end{array} \end{array} \]
B_m = (fabs.f64 B)
NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
(FPCore (A B_m C F)
 :precision binary64
 (if (<= B_m 1.32e+132)
   (- (sqrt (/ (- F) A)))
   (- (sqrt (* F (* 2.0 (/ (+ 1.0 (+ (/ A B_m) (/ C B_m))) B_m)))))))
B_m = fabs(B);
assert(A < B_m && B_m < C && C < F);
double code(double A, double B_m, double C, double F) {
	double tmp;
	if (B_m <= 1.32e+132) {
		tmp = -sqrt((-F / A));
	} else {
		tmp = -sqrt((F * (2.0 * ((1.0 + ((A / B_m) + (C / B_m))) / B_m))));
	}
	return tmp;
}
B_m = abs(b)
NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
real(8) function code(a, b_m, c, f)
    real(8), intent (in) :: a
    real(8), intent (in) :: b_m
    real(8), intent (in) :: c
    real(8), intent (in) :: f
    real(8) :: tmp
    if (b_m <= 1.32d+132) then
        tmp = -sqrt((-f / a))
    else
        tmp = -sqrt((f * (2.0d0 * ((1.0d0 + ((a / b_m) + (c / b_m))) / b_m))))
    end if
    code = tmp
end function
B_m = Math.abs(B);
assert A < B_m && B_m < C && C < F;
public static double code(double A, double B_m, double C, double F) {
	double tmp;
	if (B_m <= 1.32e+132) {
		tmp = -Math.sqrt((-F / A));
	} else {
		tmp = -Math.sqrt((F * (2.0 * ((1.0 + ((A / B_m) + (C / B_m))) / B_m))));
	}
	return tmp;
}
B_m = math.fabs(B)
[A, B_m, C, F] = sort([A, B_m, C, F])
def code(A, B_m, C, F):
	tmp = 0
	if B_m <= 1.32e+132:
		tmp = -math.sqrt((-F / A))
	else:
		tmp = -math.sqrt((F * (2.0 * ((1.0 + ((A / B_m) + (C / B_m))) / B_m))))
	return tmp
B_m = abs(B)
A, B_m, C, F = sort([A, B_m, C, F])
function code(A, B_m, C, F)
	tmp = 0.0
	if (B_m <= 1.32e+132)
		tmp = Float64(-sqrt(Float64(Float64(-F) / A)));
	else
		tmp = Float64(-sqrt(Float64(F * Float64(2.0 * Float64(Float64(1.0 + Float64(Float64(A / B_m) + Float64(C / B_m))) / B_m)))));
	end
	return tmp
end
B_m = abs(B);
A, B_m, C, F = num2cell(sort([A, B_m, C, F])){:}
function tmp_2 = code(A, B_m, C, F)
	tmp = 0.0;
	if (B_m <= 1.32e+132)
		tmp = -sqrt((-F / A));
	else
		tmp = -sqrt((F * (2.0 * ((1.0 + ((A / B_m) + (C / B_m))) / B_m))));
	end
	tmp_2 = tmp;
end
B_m = N[Abs[B], $MachinePrecision]
NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
code[A_, B$95$m_, C_, F_] := If[LessEqual[B$95$m, 1.32e+132], (-N[Sqrt[N[((-F) / A), $MachinePrecision]], $MachinePrecision]), (-N[Sqrt[N[(F * N[(2.0 * N[(N[(1.0 + N[(N[(A / B$95$m), $MachinePrecision] + N[(C / B$95$m), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] / B$95$m), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision])]
\begin{array}{l}
B_m = \left|B\right|
\\
[A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
\\
\begin{array}{l}
\mathbf{if}\;B\_m \leq 1.32 \cdot 10^{+132}:\\
\;\;\;\;-\sqrt{\frac{-F}{A}}\\

\mathbf{else}:\\
\;\;\;\;-\sqrt{F \cdot \left(2 \cdot \frac{1 + \left(\frac{A}{B\_m} + \frac{C}{B\_m}\right)}{B\_m}\right)}\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if B < 1.3199999999999999e132

    1. Initial program 22.8%

      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    2. Add Preprocessing
    3. Taylor expanded in F around 0 22.3%

      \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2}\right)} \]
    4. Simplified38.1%

      \[\leadsto \color{blue}{-\sqrt{2} \cdot \sqrt{F \cdot \frac{\left(C + A\right) + \mathsf{hypot}\left(B, A - C\right)}{\mathsf{fma}\left(-4, C \cdot A, {B}^{2}\right)}}} \]
    5. Taylor expanded in C around inf 23.8%

      \[\leadsto -\sqrt{2} \cdot \sqrt{\color{blue}{-0.5 \cdot \frac{F}{A}}} \]
    6. Step-by-step derivation
      1. *-commutative23.8%

        \[\leadsto -\color{blue}{\sqrt{-0.5 \cdot \frac{F}{A}} \cdot \sqrt{2}} \]
      2. pow1/224.0%

        \[\leadsto -\color{blue}{{\left(-0.5 \cdot \frac{F}{A}\right)}^{0.5}} \cdot \sqrt{2} \]
      3. pow1/224.0%

        \[\leadsto -{\left(-0.5 \cdot \frac{F}{A}\right)}^{0.5} \cdot \color{blue}{{2}^{0.5}} \]
      4. pow-prod-down24.1%

        \[\leadsto -\color{blue}{{\left(\left(-0.5 \cdot \frac{F}{A}\right) \cdot 2\right)}^{0.5}} \]
      5. associate-*r/24.1%

        \[\leadsto -{\left(\color{blue}{\frac{-0.5 \cdot F}{A}} \cdot 2\right)}^{0.5} \]
    7. Applied egg-rr24.1%

      \[\leadsto -\color{blue}{{\left(\frac{-0.5 \cdot F}{A} \cdot 2\right)}^{0.5}} \]
    8. Step-by-step derivation
      1. unpow1/223.9%

        \[\leadsto -\color{blue}{\sqrt{\frac{-0.5 \cdot F}{A} \cdot 2}} \]
    9. Simplified23.9%

      \[\leadsto -\color{blue}{\sqrt{\frac{-0.5 \cdot F}{A} \cdot 2}} \]
    10. Taylor expanded in F around 0 23.9%

      \[\leadsto -\sqrt{\color{blue}{-1 \cdot \frac{F}{A}}} \]
    11. Step-by-step derivation
      1. associate-*r/23.9%

        \[\leadsto -\sqrt{\color{blue}{\frac{-1 \cdot F}{A}}} \]
      2. mul-1-neg23.9%

        \[\leadsto -\sqrt{\frac{\color{blue}{-F}}{A}} \]
    12. Simplified23.9%

      \[\leadsto -\sqrt{\color{blue}{\frac{-F}{A}}} \]

    if 1.3199999999999999e132 < B

    1. Initial program 3.8%

      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    2. Add Preprocessing
    3. Taylor expanded in F around 0 7.2%

      \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2}\right)} \]
    4. Simplified14.2%

      \[\leadsto \color{blue}{-\sqrt{2} \cdot \sqrt{F \cdot \frac{\left(C + A\right) + \mathsf{hypot}\left(B, A - C\right)}{\mathsf{fma}\left(-4, C \cdot A, {B}^{2}\right)}}} \]
    5. Taylor expanded in B around inf 51.6%

      \[\leadsto -\sqrt{2} \cdot \sqrt{F \cdot \color{blue}{\frac{1 + \left(\frac{A}{B} + \frac{C}{B}\right)}{B}}} \]
    6. Step-by-step derivation
      1. pow151.6%

        \[\leadsto -\color{blue}{{\left(\sqrt{2} \cdot \sqrt{F \cdot \frac{1 + \left(\frac{A}{B} + \frac{C}{B}\right)}{B}}\right)}^{1}} \]
      2. sqrt-unprod51.9%

        \[\leadsto -{\color{blue}{\left(\sqrt{2 \cdot \left(F \cdot \frac{1 + \left(\frac{A}{B} + \frac{C}{B}\right)}{B}\right)}\right)}}^{1} \]
    7. Applied egg-rr51.9%

      \[\leadsto -\color{blue}{{\left(\sqrt{2 \cdot \left(F \cdot \frac{1 + \left(\frac{A}{B} + \frac{C}{B}\right)}{B}\right)}\right)}^{1}} \]
    8. Step-by-step derivation
      1. unpow151.9%

        \[\leadsto -\color{blue}{\sqrt{2 \cdot \left(F \cdot \frac{1 + \left(\frac{A}{B} + \frac{C}{B}\right)}{B}\right)}} \]
      2. *-commutative51.9%

        \[\leadsto -\sqrt{\color{blue}{\left(F \cdot \frac{1 + \left(\frac{A}{B} + \frac{C}{B}\right)}{B}\right) \cdot 2}} \]
      3. associate-*l*51.9%

        \[\leadsto -\sqrt{\color{blue}{F \cdot \left(\frac{1 + \left(\frac{A}{B} + \frac{C}{B}\right)}{B} \cdot 2\right)}} \]
      4. +-commutative51.9%

        \[\leadsto -\sqrt{F \cdot \left(\frac{1 + \color{blue}{\left(\frac{C}{B} + \frac{A}{B}\right)}}{B} \cdot 2\right)} \]
    9. Simplified51.9%

      \[\leadsto -\color{blue}{\sqrt{F \cdot \left(\frac{1 + \left(\frac{C}{B} + \frac{A}{B}\right)}{B} \cdot 2\right)}} \]
  3. Recombined 2 regimes into one program.
  4. Final simplification27.1%

    \[\leadsto \begin{array}{l} \mathbf{if}\;B \leq 1.32 \cdot 10^{+132}:\\ \;\;\;\;-\sqrt{\frac{-F}{A}}\\ \mathbf{else}:\\ \;\;\;\;-\sqrt{F \cdot \left(2 \cdot \frac{1 + \left(\frac{A}{B} + \frac{C}{B}\right)}{B}\right)}\\ \end{array} \]
  5. Add Preprocessing

Alternative 9: 36.4% accurate, 5.7× speedup?

\[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} \mathbf{if}\;B\_m \leq 1.7 \cdot 10^{+130}:\\ \;\;\;\;-\sqrt{\frac{-F}{A}}\\ \mathbf{else}:\\ \;\;\;\;-{\left(\frac{2 \cdot F}{B\_m}\right)}^{0.5}\\ \end{array} \end{array} \]
B_m = (fabs.f64 B)
NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
(FPCore (A B_m C F)
 :precision binary64
 (if (<= B_m 1.7e+130) (- (sqrt (/ (- F) A))) (- (pow (/ (* 2.0 F) B_m) 0.5))))
B_m = fabs(B);
assert(A < B_m && B_m < C && C < F);
double code(double A, double B_m, double C, double F) {
	double tmp;
	if (B_m <= 1.7e+130) {
		tmp = -sqrt((-F / A));
	} else {
		tmp = -pow(((2.0 * F) / B_m), 0.5);
	}
	return tmp;
}
B_m = abs(b)
NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
real(8) function code(a, b_m, c, f)
    real(8), intent (in) :: a
    real(8), intent (in) :: b_m
    real(8), intent (in) :: c
    real(8), intent (in) :: f
    real(8) :: tmp
    if (b_m <= 1.7d+130) then
        tmp = -sqrt((-f / a))
    else
        tmp = -(((2.0d0 * f) / b_m) ** 0.5d0)
    end if
    code = tmp
end function
B_m = Math.abs(B);
assert A < B_m && B_m < C && C < F;
public static double code(double A, double B_m, double C, double F) {
	double tmp;
	if (B_m <= 1.7e+130) {
		tmp = -Math.sqrt((-F / A));
	} else {
		tmp = -Math.pow(((2.0 * F) / B_m), 0.5);
	}
	return tmp;
}
B_m = math.fabs(B)
[A, B_m, C, F] = sort([A, B_m, C, F])
def code(A, B_m, C, F):
	tmp = 0
	if B_m <= 1.7e+130:
		tmp = -math.sqrt((-F / A))
	else:
		tmp = -math.pow(((2.0 * F) / B_m), 0.5)
	return tmp
B_m = abs(B)
A, B_m, C, F = sort([A, B_m, C, F])
function code(A, B_m, C, F)
	tmp = 0.0
	if (B_m <= 1.7e+130)
		tmp = Float64(-sqrt(Float64(Float64(-F) / A)));
	else
		tmp = Float64(-(Float64(Float64(2.0 * F) / B_m) ^ 0.5));
	end
	return tmp
end
B_m = abs(B);
A, B_m, C, F = num2cell(sort([A, B_m, C, F])){:}
function tmp_2 = code(A, B_m, C, F)
	tmp = 0.0;
	if (B_m <= 1.7e+130)
		tmp = -sqrt((-F / A));
	else
		tmp = -(((2.0 * F) / B_m) ^ 0.5);
	end
	tmp_2 = tmp;
end
B_m = N[Abs[B], $MachinePrecision]
NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
code[A_, B$95$m_, C_, F_] := If[LessEqual[B$95$m, 1.7e+130], (-N[Sqrt[N[((-F) / A), $MachinePrecision]], $MachinePrecision]), (-N[Power[N[(N[(2.0 * F), $MachinePrecision] / B$95$m), $MachinePrecision], 0.5], $MachinePrecision])]
\begin{array}{l}
B_m = \left|B\right|
\\
[A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
\\
\begin{array}{l}
\mathbf{if}\;B\_m \leq 1.7 \cdot 10^{+130}:\\
\;\;\;\;-\sqrt{\frac{-F}{A}}\\

\mathbf{else}:\\
\;\;\;\;-{\left(\frac{2 \cdot F}{B\_m}\right)}^{0.5}\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if B < 1.7e130

    1. Initial program 22.9%

      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    2. Add Preprocessing
    3. Taylor expanded in F around 0 22.4%

      \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2}\right)} \]
    4. Simplified38.2%

      \[\leadsto \color{blue}{-\sqrt{2} \cdot \sqrt{F \cdot \frac{\left(C + A\right) + \mathsf{hypot}\left(B, A - C\right)}{\mathsf{fma}\left(-4, C \cdot A, {B}^{2}\right)}}} \]
    5. Taylor expanded in C around inf 23.9%

      \[\leadsto -\sqrt{2} \cdot \sqrt{\color{blue}{-0.5 \cdot \frac{F}{A}}} \]
    6. Step-by-step derivation
      1. *-commutative23.9%

        \[\leadsto -\color{blue}{\sqrt{-0.5 \cdot \frac{F}{A}} \cdot \sqrt{2}} \]
      2. pow1/224.1%

        \[\leadsto -\color{blue}{{\left(-0.5 \cdot \frac{F}{A}\right)}^{0.5}} \cdot \sqrt{2} \]
      3. pow1/224.1%

        \[\leadsto -{\left(-0.5 \cdot \frac{F}{A}\right)}^{0.5} \cdot \color{blue}{{2}^{0.5}} \]
      4. pow-prod-down24.2%

        \[\leadsto -\color{blue}{{\left(\left(-0.5 \cdot \frac{F}{A}\right) \cdot 2\right)}^{0.5}} \]
      5. associate-*r/24.2%

        \[\leadsto -{\left(\color{blue}{\frac{-0.5 \cdot F}{A}} \cdot 2\right)}^{0.5} \]
    7. Applied egg-rr24.2%

      \[\leadsto -\color{blue}{{\left(\frac{-0.5 \cdot F}{A} \cdot 2\right)}^{0.5}} \]
    8. Step-by-step derivation
      1. unpow1/224.0%

        \[\leadsto -\color{blue}{\sqrt{\frac{-0.5 \cdot F}{A} \cdot 2}} \]
    9. Simplified24.0%

      \[\leadsto -\color{blue}{\sqrt{\frac{-0.5 \cdot F}{A} \cdot 2}} \]
    10. Taylor expanded in F around 0 24.0%

      \[\leadsto -\sqrt{\color{blue}{-1 \cdot \frac{F}{A}}} \]
    11. Step-by-step derivation
      1. associate-*r/24.0%

        \[\leadsto -\sqrt{\color{blue}{\frac{-1 \cdot F}{A}}} \]
      2. mul-1-neg24.0%

        \[\leadsto -\sqrt{\frac{\color{blue}{-F}}{A}} \]
    12. Simplified24.0%

      \[\leadsto -\sqrt{\color{blue}{\frac{-F}{A}}} \]

    if 1.7e130 < B

    1. Initial program 3.8%

      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    2. Add Preprocessing
    3. Taylor expanded in B around inf 50.1%

      \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
    4. Step-by-step derivation
      1. mul-1-neg50.1%

        \[\leadsto \color{blue}{-\sqrt{\frac{F}{B}} \cdot \sqrt{2}} \]
      2. *-commutative50.1%

        \[\leadsto -\color{blue}{\sqrt{2} \cdot \sqrt{\frac{F}{B}}} \]
    5. Simplified50.1%

      \[\leadsto \color{blue}{-\sqrt{2} \cdot \sqrt{\frac{F}{B}}} \]
    6. Step-by-step derivation
      1. *-commutative50.1%

        \[\leadsto -\color{blue}{\sqrt{\frac{F}{B}} \cdot \sqrt{2}} \]
      2. pow1/250.1%

        \[\leadsto -\color{blue}{{\left(\frac{F}{B}\right)}^{0.5}} \cdot \sqrt{2} \]
      3. pow1/250.1%

        \[\leadsto -{\left(\frac{F}{B}\right)}^{0.5} \cdot \color{blue}{{2}^{0.5}} \]
      4. pow-prod-down50.4%

        \[\leadsto -\color{blue}{{\left(\frac{F}{B} \cdot 2\right)}^{0.5}} \]
    7. Applied egg-rr50.4%

      \[\leadsto -\color{blue}{{\left(\frac{F}{B} \cdot 2\right)}^{0.5}} \]
    8. Step-by-step derivation
      1. unpow1/250.4%

        \[\leadsto -\color{blue}{\sqrt{\frac{F}{B} \cdot 2}} \]
    9. Simplified50.4%

      \[\leadsto -\color{blue}{\sqrt{\frac{F}{B} \cdot 2}} \]
    10. Step-by-step derivation
      1. associate-*l/50.4%

        \[\leadsto -\sqrt{\color{blue}{\frac{F \cdot 2}{B}}} \]
    11. Applied egg-rr50.4%

      \[\leadsto -\sqrt{\color{blue}{\frac{F \cdot 2}{B}}} \]
    12. Step-by-step derivation
      1. associate-/l*50.4%

        \[\leadsto -\sqrt{\color{blue}{F \cdot \frac{2}{B}}} \]
    13. Simplified50.4%

      \[\leadsto -\sqrt{\color{blue}{F \cdot \frac{2}{B}}} \]
    14. Step-by-step derivation
      1. pow1/250.4%

        \[\leadsto -\color{blue}{{\left(F \cdot \frac{2}{B}\right)}^{0.5}} \]
      2. associate-*r/50.4%

        \[\leadsto -{\color{blue}{\left(\frac{F \cdot 2}{B}\right)}}^{0.5} \]
    15. Applied egg-rr50.4%

      \[\leadsto -\color{blue}{{\left(\frac{F \cdot 2}{B}\right)}^{0.5}} \]
  3. Recombined 2 regimes into one program.
  4. Final simplification27.1%

    \[\leadsto \begin{array}{l} \mathbf{if}\;B \leq 1.7 \cdot 10^{+130}:\\ \;\;\;\;-\sqrt{\frac{-F}{A}}\\ \mathbf{else}:\\ \;\;\;\;-{\left(\frac{2 \cdot F}{B}\right)}^{0.5}\\ \end{array} \]
  5. Add Preprocessing

Alternative 10: 36.4% accurate, 5.7× speedup?

\[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} \mathbf{if}\;B\_m \leq 7.5 \cdot 10^{+129}:\\ \;\;\;\;-\sqrt{\frac{-F}{A}}\\ \mathbf{else}:\\ \;\;\;\;-\sqrt{2 \cdot \frac{F}{B\_m}}\\ \end{array} \end{array} \]
B_m = (fabs.f64 B)
NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
(FPCore (A B_m C F)
 :precision binary64
 (if (<= B_m 7.5e+129) (- (sqrt (/ (- F) A))) (- (sqrt (* 2.0 (/ F B_m))))))
B_m = fabs(B);
assert(A < B_m && B_m < C && C < F);
double code(double A, double B_m, double C, double F) {
	double tmp;
	if (B_m <= 7.5e+129) {
		tmp = -sqrt((-F / A));
	} else {
		tmp = -sqrt((2.0 * (F / B_m)));
	}
	return tmp;
}
B_m = abs(b)
NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
real(8) function code(a, b_m, c, f)
    real(8), intent (in) :: a
    real(8), intent (in) :: b_m
    real(8), intent (in) :: c
    real(8), intent (in) :: f
    real(8) :: tmp
    if (b_m <= 7.5d+129) then
        tmp = -sqrt((-f / a))
    else
        tmp = -sqrt((2.0d0 * (f / b_m)))
    end if
    code = tmp
end function
B_m = Math.abs(B);
assert A < B_m && B_m < C && C < F;
public static double code(double A, double B_m, double C, double F) {
	double tmp;
	if (B_m <= 7.5e+129) {
		tmp = -Math.sqrt((-F / A));
	} else {
		tmp = -Math.sqrt((2.0 * (F / B_m)));
	}
	return tmp;
}
B_m = math.fabs(B)
[A, B_m, C, F] = sort([A, B_m, C, F])
def code(A, B_m, C, F):
	tmp = 0
	if B_m <= 7.5e+129:
		tmp = -math.sqrt((-F / A))
	else:
		tmp = -math.sqrt((2.0 * (F / B_m)))
	return tmp
B_m = abs(B)
A, B_m, C, F = sort([A, B_m, C, F])
function code(A, B_m, C, F)
	tmp = 0.0
	if (B_m <= 7.5e+129)
		tmp = Float64(-sqrt(Float64(Float64(-F) / A)));
	else
		tmp = Float64(-sqrt(Float64(2.0 * Float64(F / B_m))));
	end
	return tmp
end
B_m = abs(B);
A, B_m, C, F = num2cell(sort([A, B_m, C, F])){:}
function tmp_2 = code(A, B_m, C, F)
	tmp = 0.0;
	if (B_m <= 7.5e+129)
		tmp = -sqrt((-F / A));
	else
		tmp = -sqrt((2.0 * (F / B_m)));
	end
	tmp_2 = tmp;
end
B_m = N[Abs[B], $MachinePrecision]
NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
code[A_, B$95$m_, C_, F_] := If[LessEqual[B$95$m, 7.5e+129], (-N[Sqrt[N[((-F) / A), $MachinePrecision]], $MachinePrecision]), (-N[Sqrt[N[(2.0 * N[(F / B$95$m), $MachinePrecision]), $MachinePrecision]], $MachinePrecision])]
\begin{array}{l}
B_m = \left|B\right|
\\
[A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
\\
\begin{array}{l}
\mathbf{if}\;B\_m \leq 7.5 \cdot 10^{+129}:\\
\;\;\;\;-\sqrt{\frac{-F}{A}}\\

\mathbf{else}:\\
\;\;\;\;-\sqrt{2 \cdot \frac{F}{B\_m}}\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if B < 7.4999999999999998e129

    1. Initial program 22.9%

      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    2. Add Preprocessing
    3. Taylor expanded in F around 0 22.4%

      \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2}\right)} \]
    4. Simplified38.2%

      \[\leadsto \color{blue}{-\sqrt{2} \cdot \sqrt{F \cdot \frac{\left(C + A\right) + \mathsf{hypot}\left(B, A - C\right)}{\mathsf{fma}\left(-4, C \cdot A, {B}^{2}\right)}}} \]
    5. Taylor expanded in C around inf 23.9%

      \[\leadsto -\sqrt{2} \cdot \sqrt{\color{blue}{-0.5 \cdot \frac{F}{A}}} \]
    6. Step-by-step derivation
      1. *-commutative23.9%

        \[\leadsto -\color{blue}{\sqrt{-0.5 \cdot \frac{F}{A}} \cdot \sqrt{2}} \]
      2. pow1/224.1%

        \[\leadsto -\color{blue}{{\left(-0.5 \cdot \frac{F}{A}\right)}^{0.5}} \cdot \sqrt{2} \]
      3. pow1/224.1%

        \[\leadsto -{\left(-0.5 \cdot \frac{F}{A}\right)}^{0.5} \cdot \color{blue}{{2}^{0.5}} \]
      4. pow-prod-down24.2%

        \[\leadsto -\color{blue}{{\left(\left(-0.5 \cdot \frac{F}{A}\right) \cdot 2\right)}^{0.5}} \]
      5. associate-*r/24.2%

        \[\leadsto -{\left(\color{blue}{\frac{-0.5 \cdot F}{A}} \cdot 2\right)}^{0.5} \]
    7. Applied egg-rr24.2%

      \[\leadsto -\color{blue}{{\left(\frac{-0.5 \cdot F}{A} \cdot 2\right)}^{0.5}} \]
    8. Step-by-step derivation
      1. unpow1/224.0%

        \[\leadsto -\color{blue}{\sqrt{\frac{-0.5 \cdot F}{A} \cdot 2}} \]
    9. Simplified24.0%

      \[\leadsto -\color{blue}{\sqrt{\frac{-0.5 \cdot F}{A} \cdot 2}} \]
    10. Taylor expanded in F around 0 24.0%

      \[\leadsto -\sqrt{\color{blue}{-1 \cdot \frac{F}{A}}} \]
    11. Step-by-step derivation
      1. associate-*r/24.0%

        \[\leadsto -\sqrt{\color{blue}{\frac{-1 \cdot F}{A}}} \]
      2. mul-1-neg24.0%

        \[\leadsto -\sqrt{\frac{\color{blue}{-F}}{A}} \]
    12. Simplified24.0%

      \[\leadsto -\sqrt{\color{blue}{\frac{-F}{A}}} \]

    if 7.4999999999999998e129 < B

    1. Initial program 3.8%

      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    2. Add Preprocessing
    3. Taylor expanded in B around inf 50.1%

      \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
    4. Step-by-step derivation
      1. mul-1-neg50.1%

        \[\leadsto \color{blue}{-\sqrt{\frac{F}{B}} \cdot \sqrt{2}} \]
      2. *-commutative50.1%

        \[\leadsto -\color{blue}{\sqrt{2} \cdot \sqrt{\frac{F}{B}}} \]
    5. Simplified50.1%

      \[\leadsto \color{blue}{-\sqrt{2} \cdot \sqrt{\frac{F}{B}}} \]
    6. Step-by-step derivation
      1. *-commutative50.1%

        \[\leadsto -\color{blue}{\sqrt{\frac{F}{B}} \cdot \sqrt{2}} \]
      2. pow1/250.1%

        \[\leadsto -\color{blue}{{\left(\frac{F}{B}\right)}^{0.5}} \cdot \sqrt{2} \]
      3. pow1/250.1%

        \[\leadsto -{\left(\frac{F}{B}\right)}^{0.5} \cdot \color{blue}{{2}^{0.5}} \]
      4. pow-prod-down50.4%

        \[\leadsto -\color{blue}{{\left(\frac{F}{B} \cdot 2\right)}^{0.5}} \]
    7. Applied egg-rr50.4%

      \[\leadsto -\color{blue}{{\left(\frac{F}{B} \cdot 2\right)}^{0.5}} \]
    8. Step-by-step derivation
      1. unpow1/250.4%

        \[\leadsto -\color{blue}{\sqrt{\frac{F}{B} \cdot 2}} \]
    9. Simplified50.4%

      \[\leadsto -\color{blue}{\sqrt{\frac{F}{B} \cdot 2}} \]
  3. Recombined 2 regimes into one program.
  4. Final simplification27.1%

    \[\leadsto \begin{array}{l} \mathbf{if}\;B \leq 7.5 \cdot 10^{+129}:\\ \;\;\;\;-\sqrt{\frac{-F}{A}}\\ \mathbf{else}:\\ \;\;\;\;-\sqrt{2 \cdot \frac{F}{B}}\\ \end{array} \]
  5. Add Preprocessing

Alternative 11: 36.4% accurate, 5.7× speedup?

\[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} \mathbf{if}\;B\_m \leq 9 \cdot 10^{+129}:\\ \;\;\;\;-\sqrt{\frac{-F}{A}}\\ \mathbf{else}:\\ \;\;\;\;-\sqrt{F \cdot \frac{2}{B\_m}}\\ \end{array} \end{array} \]
B_m = (fabs.f64 B)
NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
(FPCore (A B_m C F)
 :precision binary64
 (if (<= B_m 9e+129) (- (sqrt (/ (- F) A))) (- (sqrt (* F (/ 2.0 B_m))))))
B_m = fabs(B);
assert(A < B_m && B_m < C && C < F);
double code(double A, double B_m, double C, double F) {
	double tmp;
	if (B_m <= 9e+129) {
		tmp = -sqrt((-F / A));
	} else {
		tmp = -sqrt((F * (2.0 / B_m)));
	}
	return tmp;
}
B_m = abs(b)
NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
real(8) function code(a, b_m, c, f)
    real(8), intent (in) :: a
    real(8), intent (in) :: b_m
    real(8), intent (in) :: c
    real(8), intent (in) :: f
    real(8) :: tmp
    if (b_m <= 9d+129) then
        tmp = -sqrt((-f / a))
    else
        tmp = -sqrt((f * (2.0d0 / b_m)))
    end if
    code = tmp
end function
B_m = Math.abs(B);
assert A < B_m && B_m < C && C < F;
public static double code(double A, double B_m, double C, double F) {
	double tmp;
	if (B_m <= 9e+129) {
		tmp = -Math.sqrt((-F / A));
	} else {
		tmp = -Math.sqrt((F * (2.0 / B_m)));
	}
	return tmp;
}
B_m = math.fabs(B)
[A, B_m, C, F] = sort([A, B_m, C, F])
def code(A, B_m, C, F):
	tmp = 0
	if B_m <= 9e+129:
		tmp = -math.sqrt((-F / A))
	else:
		tmp = -math.sqrt((F * (2.0 / B_m)))
	return tmp
B_m = abs(B)
A, B_m, C, F = sort([A, B_m, C, F])
function code(A, B_m, C, F)
	tmp = 0.0
	if (B_m <= 9e+129)
		tmp = Float64(-sqrt(Float64(Float64(-F) / A)));
	else
		tmp = Float64(-sqrt(Float64(F * Float64(2.0 / B_m))));
	end
	return tmp
end
B_m = abs(B);
A, B_m, C, F = num2cell(sort([A, B_m, C, F])){:}
function tmp_2 = code(A, B_m, C, F)
	tmp = 0.0;
	if (B_m <= 9e+129)
		tmp = -sqrt((-F / A));
	else
		tmp = -sqrt((F * (2.0 / B_m)));
	end
	tmp_2 = tmp;
end
B_m = N[Abs[B], $MachinePrecision]
NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
code[A_, B$95$m_, C_, F_] := If[LessEqual[B$95$m, 9e+129], (-N[Sqrt[N[((-F) / A), $MachinePrecision]], $MachinePrecision]), (-N[Sqrt[N[(F * N[(2.0 / B$95$m), $MachinePrecision]), $MachinePrecision]], $MachinePrecision])]
\begin{array}{l}
B_m = \left|B\right|
\\
[A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
\\
\begin{array}{l}
\mathbf{if}\;B\_m \leq 9 \cdot 10^{+129}:\\
\;\;\;\;-\sqrt{\frac{-F}{A}}\\

\mathbf{else}:\\
\;\;\;\;-\sqrt{F \cdot \frac{2}{B\_m}}\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if B < 9.0000000000000003e129

    1. Initial program 22.9%

      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    2. Add Preprocessing
    3. Taylor expanded in F around 0 22.4%

      \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2}\right)} \]
    4. Simplified38.2%

      \[\leadsto \color{blue}{-\sqrt{2} \cdot \sqrt{F \cdot \frac{\left(C + A\right) + \mathsf{hypot}\left(B, A - C\right)}{\mathsf{fma}\left(-4, C \cdot A, {B}^{2}\right)}}} \]
    5. Taylor expanded in C around inf 23.9%

      \[\leadsto -\sqrt{2} \cdot \sqrt{\color{blue}{-0.5 \cdot \frac{F}{A}}} \]
    6. Step-by-step derivation
      1. *-commutative23.9%

        \[\leadsto -\color{blue}{\sqrt{-0.5 \cdot \frac{F}{A}} \cdot \sqrt{2}} \]
      2. pow1/224.1%

        \[\leadsto -\color{blue}{{\left(-0.5 \cdot \frac{F}{A}\right)}^{0.5}} \cdot \sqrt{2} \]
      3. pow1/224.1%

        \[\leadsto -{\left(-0.5 \cdot \frac{F}{A}\right)}^{0.5} \cdot \color{blue}{{2}^{0.5}} \]
      4. pow-prod-down24.2%

        \[\leadsto -\color{blue}{{\left(\left(-0.5 \cdot \frac{F}{A}\right) \cdot 2\right)}^{0.5}} \]
      5. associate-*r/24.2%

        \[\leadsto -{\left(\color{blue}{\frac{-0.5 \cdot F}{A}} \cdot 2\right)}^{0.5} \]
    7. Applied egg-rr24.2%

      \[\leadsto -\color{blue}{{\left(\frac{-0.5 \cdot F}{A} \cdot 2\right)}^{0.5}} \]
    8. Step-by-step derivation
      1. unpow1/224.0%

        \[\leadsto -\color{blue}{\sqrt{\frac{-0.5 \cdot F}{A} \cdot 2}} \]
    9. Simplified24.0%

      \[\leadsto -\color{blue}{\sqrt{\frac{-0.5 \cdot F}{A} \cdot 2}} \]
    10. Taylor expanded in F around 0 24.0%

      \[\leadsto -\sqrt{\color{blue}{-1 \cdot \frac{F}{A}}} \]
    11. Step-by-step derivation
      1. associate-*r/24.0%

        \[\leadsto -\sqrt{\color{blue}{\frac{-1 \cdot F}{A}}} \]
      2. mul-1-neg24.0%

        \[\leadsto -\sqrt{\frac{\color{blue}{-F}}{A}} \]
    12. Simplified24.0%

      \[\leadsto -\sqrt{\color{blue}{\frac{-F}{A}}} \]

    if 9.0000000000000003e129 < B

    1. Initial program 3.8%

      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    2. Add Preprocessing
    3. Taylor expanded in B around inf 50.1%

      \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
    4. Step-by-step derivation
      1. mul-1-neg50.1%

        \[\leadsto \color{blue}{-\sqrt{\frac{F}{B}} \cdot \sqrt{2}} \]
      2. *-commutative50.1%

        \[\leadsto -\color{blue}{\sqrt{2} \cdot \sqrt{\frac{F}{B}}} \]
    5. Simplified50.1%

      \[\leadsto \color{blue}{-\sqrt{2} \cdot \sqrt{\frac{F}{B}}} \]
    6. Step-by-step derivation
      1. *-commutative50.1%

        \[\leadsto -\color{blue}{\sqrt{\frac{F}{B}} \cdot \sqrt{2}} \]
      2. pow1/250.1%

        \[\leadsto -\color{blue}{{\left(\frac{F}{B}\right)}^{0.5}} \cdot \sqrt{2} \]
      3. pow1/250.1%

        \[\leadsto -{\left(\frac{F}{B}\right)}^{0.5} \cdot \color{blue}{{2}^{0.5}} \]
      4. pow-prod-down50.4%

        \[\leadsto -\color{blue}{{\left(\frac{F}{B} \cdot 2\right)}^{0.5}} \]
    7. Applied egg-rr50.4%

      \[\leadsto -\color{blue}{{\left(\frac{F}{B} \cdot 2\right)}^{0.5}} \]
    8. Step-by-step derivation
      1. unpow1/250.4%

        \[\leadsto -\color{blue}{\sqrt{\frac{F}{B} \cdot 2}} \]
    9. Simplified50.4%

      \[\leadsto -\color{blue}{\sqrt{\frac{F}{B} \cdot 2}} \]
    10. Step-by-step derivation
      1. associate-*l/50.4%

        \[\leadsto -\sqrt{\color{blue}{\frac{F \cdot 2}{B}}} \]
    11. Applied egg-rr50.4%

      \[\leadsto -\sqrt{\color{blue}{\frac{F \cdot 2}{B}}} \]
    12. Step-by-step derivation
      1. associate-/l*50.4%

        \[\leadsto -\sqrt{\color{blue}{F \cdot \frac{2}{B}}} \]
    13. Simplified50.4%

      \[\leadsto -\sqrt{\color{blue}{F \cdot \frac{2}{B}}} \]
  3. Recombined 2 regimes into one program.
  4. Add Preprocessing

Alternative 12: 26.4% accurate, 6.0× speedup?

\[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ -\sqrt{\frac{-F}{A}} \end{array} \]
B_m = (fabs.f64 B)
NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
(FPCore (A B_m C F) :precision binary64 (- (sqrt (/ (- F) A))))
B_m = fabs(B);
assert(A < B_m && B_m < C && C < F);
double code(double A, double B_m, double C, double F) {
	return -sqrt((-F / A));
}
B_m = abs(b)
NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
real(8) function code(a, b_m, c, f)
    real(8), intent (in) :: a
    real(8), intent (in) :: b_m
    real(8), intent (in) :: c
    real(8), intent (in) :: f
    code = -sqrt((-f / a))
end function
B_m = Math.abs(B);
assert A < B_m && B_m < C && C < F;
public static double code(double A, double B_m, double C, double F) {
	return -Math.sqrt((-F / A));
}
B_m = math.fabs(B)
[A, B_m, C, F] = sort([A, B_m, C, F])
def code(A, B_m, C, F):
	return -math.sqrt((-F / A))
B_m = abs(B)
A, B_m, C, F = sort([A, B_m, C, F])
function code(A, B_m, C, F)
	return Float64(-sqrt(Float64(Float64(-F) / A)))
end
B_m = abs(B);
A, B_m, C, F = num2cell(sort([A, B_m, C, F])){:}
function tmp = code(A, B_m, C, F)
	tmp = -sqrt((-F / A));
end
B_m = N[Abs[B], $MachinePrecision]
NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
code[A_, B$95$m_, C_, F_] := (-N[Sqrt[N[((-F) / A), $MachinePrecision]], $MachinePrecision])
\begin{array}{l}
B_m = \left|B\right|
\\
[A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
\\
-\sqrt{\frac{-F}{A}}
\end{array}
Derivation
  1. Initial program 20.7%

    \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
  2. Add Preprocessing
  3. Taylor expanded in F around 0 20.6%

    \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2}\right)} \]
  4. Simplified35.4%

    \[\leadsto \color{blue}{-\sqrt{2} \cdot \sqrt{F \cdot \frac{\left(C + A\right) + \mathsf{hypot}\left(B, A - C\right)}{\mathsf{fma}\left(-4, C \cdot A, {B}^{2}\right)}}} \]
  5. Taylor expanded in C around inf 21.4%

    \[\leadsto -\sqrt{2} \cdot \sqrt{\color{blue}{-0.5 \cdot \frac{F}{A}}} \]
  6. Step-by-step derivation
    1. *-commutative21.4%

      \[\leadsto -\color{blue}{\sqrt{-0.5 \cdot \frac{F}{A}} \cdot \sqrt{2}} \]
    2. pow1/221.5%

      \[\leadsto -\color{blue}{{\left(-0.5 \cdot \frac{F}{A}\right)}^{0.5}} \cdot \sqrt{2} \]
    3. pow1/221.5%

      \[\leadsto -{\left(-0.5 \cdot \frac{F}{A}\right)}^{0.5} \cdot \color{blue}{{2}^{0.5}} \]
    4. pow-prod-down21.6%

      \[\leadsto -\color{blue}{{\left(\left(-0.5 \cdot \frac{F}{A}\right) \cdot 2\right)}^{0.5}} \]
    5. associate-*r/21.6%

      \[\leadsto -{\left(\color{blue}{\frac{-0.5 \cdot F}{A}} \cdot 2\right)}^{0.5} \]
  7. Applied egg-rr21.6%

    \[\leadsto -\color{blue}{{\left(\frac{-0.5 \cdot F}{A} \cdot 2\right)}^{0.5}} \]
  8. Step-by-step derivation
    1. unpow1/221.5%

      \[\leadsto -\color{blue}{\sqrt{\frac{-0.5 \cdot F}{A} \cdot 2}} \]
  9. Simplified21.5%

    \[\leadsto -\color{blue}{\sqrt{\frac{-0.5 \cdot F}{A} \cdot 2}} \]
  10. Taylor expanded in F around 0 21.5%

    \[\leadsto -\sqrt{\color{blue}{-1 \cdot \frac{F}{A}}} \]
  11. Step-by-step derivation
    1. associate-*r/21.5%

      \[\leadsto -\sqrt{\color{blue}{\frac{-1 \cdot F}{A}}} \]
    2. mul-1-neg21.5%

      \[\leadsto -\sqrt{\frac{\color{blue}{-F}}{A}} \]
  12. Simplified21.5%

    \[\leadsto -\sqrt{\color{blue}{\frac{-F}{A}}} \]
  13. Add Preprocessing

Reproduce

?
herbie shell --seed 2024181 
(FPCore (A B C F)
  :name "ABCF->ab-angle a"
  :precision binary64
  (/ (- (sqrt (* (* 2.0 (* (- (pow B 2.0) (* (* 4.0 A) C)) F)) (+ (+ A C) (sqrt (+ (pow (- A C) 2.0) (pow B 2.0))))))) (- (pow B 2.0) (* (* 4.0 A) C))))