symmetry log of sum of exp

Percentage Accurate: 54.6% → 98.8%
Time: 10.6s
Alternatives: 11
Speedup: 2.9×

Specification

?
\[\begin{array}{l} \\ \log \left(e^{a} + e^{b}\right) \end{array} \]
(FPCore (a b) :precision binary64 (log (+ (exp a) (exp b))))
double code(double a, double b) {
	return log((exp(a) + exp(b)));
}
real(8) function code(a, b)
    real(8), intent (in) :: a
    real(8), intent (in) :: b
    code = log((exp(a) + exp(b)))
end function
public static double code(double a, double b) {
	return Math.log((Math.exp(a) + Math.exp(b)));
}
def code(a, b):
	return math.log((math.exp(a) + math.exp(b)))
function code(a, b)
	return log(Float64(exp(a) + exp(b)))
end
function tmp = code(a, b)
	tmp = log((exp(a) + exp(b)));
end
code[a_, b_] := N[Log[N[(N[Exp[a], $MachinePrecision] + N[Exp[b], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]
\begin{array}{l}

\\
\log \left(e^{a} + e^{b}\right)
\end{array}

Sampling outcomes in binary64 precision:

Local Percentage Accuracy vs ?

The average percentage accuracy by input value. Horizontal axis shows value of an input variable; the variable is choosen in the title. Vertical axis is accuracy; higher is better. Red represent the original program, while blue represents Herbie's suggestion. These can be toggled with buttons below the plot. The line is an average while dots represent individual samples.

Accuracy vs Speed?

Herbie found 11 alternatives:

AlternativeAccuracySpeedup
The accuracy (vertical axis) and speed (horizontal axis) of each alternatives. Up and to the right is better. The red square shows the initial program, and each blue circle shows an alternative.The line shows the best available speed-accuracy tradeoffs.

Initial Program: 54.6% accurate, 1.0× speedup?

\[\begin{array}{l} \\ \log \left(e^{a} + e^{b}\right) \end{array} \]
(FPCore (a b) :precision binary64 (log (+ (exp a) (exp b))))
double code(double a, double b) {
	return log((exp(a) + exp(b)));
}
real(8) function code(a, b)
    real(8), intent (in) :: a
    real(8), intent (in) :: b
    code = log((exp(a) + exp(b)))
end function
public static double code(double a, double b) {
	return Math.log((Math.exp(a) + Math.exp(b)));
}
def code(a, b):
	return math.log((math.exp(a) + math.exp(b)))
function code(a, b)
	return log(Float64(exp(a) + exp(b)))
end
function tmp = code(a, b)
	tmp = log((exp(a) + exp(b)));
end
code[a_, b_] := N[Log[N[(N[Exp[a], $MachinePrecision] + N[Exp[b], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]
\begin{array}{l}

\\
\log \left(e^{a} + e^{b}\right)
\end{array}

Alternative 1: 98.8% accurate, 0.7× speedup?

\[\begin{array}{l} [a, b] = \mathsf{sort}([a, b])\\ \\ \begin{array}{l} \mathbf{if}\;e^{a} \leq 0:\\ \;\;\;\;\frac{b}{e^{a} + 1}\\ \mathbf{else}:\\ \;\;\;\;\log \left(e^{a} + e^{b}\right)\\ \end{array} \end{array} \]
NOTE: a and b should be sorted in increasing order before calling this function.
(FPCore (a b)
 :precision binary64
 (if (<= (exp a) 0.0) (/ b (+ (exp a) 1.0)) (log (+ (exp a) (exp b)))))
assert(a < b);
double code(double a, double b) {
	double tmp;
	if (exp(a) <= 0.0) {
		tmp = b / (exp(a) + 1.0);
	} else {
		tmp = log((exp(a) + exp(b)));
	}
	return tmp;
}
NOTE: a and b should be sorted in increasing order before calling this function.
real(8) function code(a, b)
    real(8), intent (in) :: a
    real(8), intent (in) :: b
    real(8) :: tmp
    if (exp(a) <= 0.0d0) then
        tmp = b / (exp(a) + 1.0d0)
    else
        tmp = log((exp(a) + exp(b)))
    end if
    code = tmp
end function
assert a < b;
public static double code(double a, double b) {
	double tmp;
	if (Math.exp(a) <= 0.0) {
		tmp = b / (Math.exp(a) + 1.0);
	} else {
		tmp = Math.log((Math.exp(a) + Math.exp(b)));
	}
	return tmp;
}
[a, b] = sort([a, b])
def code(a, b):
	tmp = 0
	if math.exp(a) <= 0.0:
		tmp = b / (math.exp(a) + 1.0)
	else:
		tmp = math.log((math.exp(a) + math.exp(b)))
	return tmp
a, b = sort([a, b])
function code(a, b)
	tmp = 0.0
	if (exp(a) <= 0.0)
		tmp = Float64(b / Float64(exp(a) + 1.0));
	else
		tmp = log(Float64(exp(a) + exp(b)));
	end
	return tmp
end
a, b = num2cell(sort([a, b])){:}
function tmp_2 = code(a, b)
	tmp = 0.0;
	if (exp(a) <= 0.0)
		tmp = b / (exp(a) + 1.0);
	else
		tmp = log((exp(a) + exp(b)));
	end
	tmp_2 = tmp;
end
NOTE: a and b should be sorted in increasing order before calling this function.
code[a_, b_] := If[LessEqual[N[Exp[a], $MachinePrecision], 0.0], N[(b / N[(N[Exp[a], $MachinePrecision] + 1.0), $MachinePrecision]), $MachinePrecision], N[Log[N[(N[Exp[a], $MachinePrecision] + N[Exp[b], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]]
\begin{array}{l}
[a, b] = \mathsf{sort}([a, b])\\
\\
\begin{array}{l}
\mathbf{if}\;e^{a} \leq 0:\\
\;\;\;\;\frac{b}{e^{a} + 1}\\

\mathbf{else}:\\
\;\;\;\;\log \left(e^{a} + e^{b}\right)\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if (exp.f64 a) < 0.0

    1. Initial program 7.0%

      \[\log \left(e^{a} + e^{b}\right) \]
    2. Add Preprocessing
    3. Taylor expanded in b around 0 97.3%

      \[\leadsto \color{blue}{\log \left(1 + e^{a}\right) + \frac{b}{1 + e^{a}}} \]
    4. Step-by-step derivation
      1. log1p-define97.3%

        \[\leadsto \color{blue}{\mathsf{log1p}\left(e^{a}\right)} + \frac{b}{1 + e^{a}} \]
    5. Simplified97.3%

      \[\leadsto \color{blue}{\mathsf{log1p}\left(e^{a}\right) + \frac{b}{1 + e^{a}}} \]
    6. Taylor expanded in b around inf 97.3%

      \[\leadsto \color{blue}{\frac{b}{1 + e^{a}}} \]

    if 0.0 < (exp.f64 a)

    1. Initial program 67.1%

      \[\log \left(e^{a} + e^{b}\right) \]
    2. Add Preprocessing
  3. Recombined 2 regimes into one program.
  4. Final simplification75.5%

    \[\leadsto \begin{array}{l} \mathbf{if}\;e^{a} \leq 0:\\ \;\;\;\;\frac{b}{e^{a} + 1}\\ \mathbf{else}:\\ \;\;\;\;\log \left(e^{a} + e^{b}\right)\\ \end{array} \]
  5. Add Preprocessing

Alternative 2: 98.4% accurate, 0.7× speedup?

\[\begin{array}{l} [a, b] = \mathsf{sort}([a, b])\\ \\ \begin{array}{l} \mathbf{if}\;e^{a} \leq 1:\\ \;\;\;\;\mathsf{log1p}\left(e^{a}\right) + \frac{b}{e^{a} + 1}\\ \mathbf{else}:\\ \;\;\;\;\mathsf{log1p}\left(e^{b}\right)\\ \end{array} \end{array} \]
NOTE: a and b should be sorted in increasing order before calling this function.
(FPCore (a b)
 :precision binary64
 (if (<= (exp a) 1.0)
   (+ (log1p (exp a)) (/ b (+ (exp a) 1.0)))
   (log1p (exp b))))
assert(a < b);
double code(double a, double b) {
	double tmp;
	if (exp(a) <= 1.0) {
		tmp = log1p(exp(a)) + (b / (exp(a) + 1.0));
	} else {
		tmp = log1p(exp(b));
	}
	return tmp;
}
assert a < b;
public static double code(double a, double b) {
	double tmp;
	if (Math.exp(a) <= 1.0) {
		tmp = Math.log1p(Math.exp(a)) + (b / (Math.exp(a) + 1.0));
	} else {
		tmp = Math.log1p(Math.exp(b));
	}
	return tmp;
}
[a, b] = sort([a, b])
def code(a, b):
	tmp = 0
	if math.exp(a) <= 1.0:
		tmp = math.log1p(math.exp(a)) + (b / (math.exp(a) + 1.0))
	else:
		tmp = math.log1p(math.exp(b))
	return tmp
a, b = sort([a, b])
function code(a, b)
	tmp = 0.0
	if (exp(a) <= 1.0)
		tmp = Float64(log1p(exp(a)) + Float64(b / Float64(exp(a) + 1.0)));
	else
		tmp = log1p(exp(b));
	end
	return tmp
end
NOTE: a and b should be sorted in increasing order before calling this function.
code[a_, b_] := If[LessEqual[N[Exp[a], $MachinePrecision], 1.0], N[(N[Log[1 + N[Exp[a], $MachinePrecision]], $MachinePrecision] + N[(b / N[(N[Exp[a], $MachinePrecision] + 1.0), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], N[Log[1 + N[Exp[b], $MachinePrecision]], $MachinePrecision]]
\begin{array}{l}
[a, b] = \mathsf{sort}([a, b])\\
\\
\begin{array}{l}
\mathbf{if}\;e^{a} \leq 1:\\
\;\;\;\;\mathsf{log1p}\left(e^{a}\right) + \frac{b}{e^{a} + 1}\\

\mathbf{else}:\\
\;\;\;\;\mathsf{log1p}\left(e^{b}\right)\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if (exp.f64 a) < 1

    1. Initial program 49.2%

      \[\log \left(e^{a} + e^{b}\right) \]
    2. Add Preprocessing
    3. Taylor expanded in b around 0 73.2%

      \[\leadsto \color{blue}{\log \left(1 + e^{a}\right) + \frac{b}{1 + e^{a}}} \]
    4. Step-by-step derivation
      1. log1p-define73.5%

        \[\leadsto \color{blue}{\mathsf{log1p}\left(e^{a}\right)} + \frac{b}{1 + e^{a}} \]
    5. Simplified73.5%

      \[\leadsto \color{blue}{\mathsf{log1p}\left(e^{a}\right) + \frac{b}{1 + e^{a}}} \]

    if 1 < (exp.f64 a)

    1. Initial program 75.5%

      \[\log \left(e^{a} + e^{b}\right) \]
    2. Add Preprocessing
    3. Taylor expanded in a around 0 20.5%

      \[\leadsto \color{blue}{\log \left(1 + e^{b}\right)} \]
    4. Step-by-step derivation
      1. log1p-define20.5%

        \[\leadsto \color{blue}{\mathsf{log1p}\left(e^{b}\right)} \]
    5. Simplified20.5%

      \[\leadsto \color{blue}{\mathsf{log1p}\left(e^{b}\right)} \]
  3. Recombined 2 regimes into one program.
  4. Final simplification71.0%

    \[\leadsto \begin{array}{l} \mathbf{if}\;e^{a} \leq 1:\\ \;\;\;\;\mathsf{log1p}\left(e^{a}\right) + \frac{b}{e^{a} + 1}\\ \mathbf{else}:\\ \;\;\;\;\mathsf{log1p}\left(e^{b}\right)\\ \end{array} \]
  5. Add Preprocessing

Alternative 3: 97.6% accurate, 1.0× speedup?

\[\begin{array}{l} [a, b] = \mathsf{sort}([a, b])\\ \\ \begin{array}{l} \mathbf{if}\;e^{a} \leq 0:\\ \;\;\;\;\frac{b}{e^{a} + 1}\\ \mathbf{else}:\\ \;\;\;\;\mathsf{log1p}\left(e^{b}\right)\\ \end{array} \end{array} \]
NOTE: a and b should be sorted in increasing order before calling this function.
(FPCore (a b)
 :precision binary64
 (if (<= (exp a) 0.0) (/ b (+ (exp a) 1.0)) (log1p (exp b))))
assert(a < b);
double code(double a, double b) {
	double tmp;
	if (exp(a) <= 0.0) {
		tmp = b / (exp(a) + 1.0);
	} else {
		tmp = log1p(exp(b));
	}
	return tmp;
}
assert a < b;
public static double code(double a, double b) {
	double tmp;
	if (Math.exp(a) <= 0.0) {
		tmp = b / (Math.exp(a) + 1.0);
	} else {
		tmp = Math.log1p(Math.exp(b));
	}
	return tmp;
}
[a, b] = sort([a, b])
def code(a, b):
	tmp = 0
	if math.exp(a) <= 0.0:
		tmp = b / (math.exp(a) + 1.0)
	else:
		tmp = math.log1p(math.exp(b))
	return tmp
a, b = sort([a, b])
function code(a, b)
	tmp = 0.0
	if (exp(a) <= 0.0)
		tmp = Float64(b / Float64(exp(a) + 1.0));
	else
		tmp = log1p(exp(b));
	end
	return tmp
end
NOTE: a and b should be sorted in increasing order before calling this function.
code[a_, b_] := If[LessEqual[N[Exp[a], $MachinePrecision], 0.0], N[(b / N[(N[Exp[a], $MachinePrecision] + 1.0), $MachinePrecision]), $MachinePrecision], N[Log[1 + N[Exp[b], $MachinePrecision]], $MachinePrecision]]
\begin{array}{l}
[a, b] = \mathsf{sort}([a, b])\\
\\
\begin{array}{l}
\mathbf{if}\;e^{a} \leq 0:\\
\;\;\;\;\frac{b}{e^{a} + 1}\\

\mathbf{else}:\\
\;\;\;\;\mathsf{log1p}\left(e^{b}\right)\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if (exp.f64 a) < 0.0

    1. Initial program 7.0%

      \[\log \left(e^{a} + e^{b}\right) \]
    2. Add Preprocessing
    3. Taylor expanded in b around 0 97.3%

      \[\leadsto \color{blue}{\log \left(1 + e^{a}\right) + \frac{b}{1 + e^{a}}} \]
    4. Step-by-step derivation
      1. log1p-define97.3%

        \[\leadsto \color{blue}{\mathsf{log1p}\left(e^{a}\right)} + \frac{b}{1 + e^{a}} \]
    5. Simplified97.3%

      \[\leadsto \color{blue}{\mathsf{log1p}\left(e^{a}\right) + \frac{b}{1 + e^{a}}} \]
    6. Taylor expanded in b around inf 97.3%

      \[\leadsto \color{blue}{\frac{b}{1 + e^{a}}} \]

    if 0.0 < (exp.f64 a)

    1. Initial program 67.1%

      \[\log \left(e^{a} + e^{b}\right) \]
    2. Add Preprocessing
    3. Taylor expanded in a around 0 62.1%

      \[\leadsto \color{blue}{\log \left(1 + e^{b}\right)} \]
    4. Step-by-step derivation
      1. log1p-define62.1%

        \[\leadsto \color{blue}{\mathsf{log1p}\left(e^{b}\right)} \]
    5. Simplified62.1%

      \[\leadsto \color{blue}{\mathsf{log1p}\left(e^{b}\right)} \]
  3. Recombined 2 regimes into one program.
  4. Final simplification71.9%

    \[\leadsto \begin{array}{l} \mathbf{if}\;e^{a} \leq 0:\\ \;\;\;\;\frac{b}{e^{a} + 1}\\ \mathbf{else}:\\ \;\;\;\;\mathsf{log1p}\left(e^{b}\right)\\ \end{array} \]
  5. Add Preprocessing

Alternative 4: 97.2% accurate, 1.4× speedup?

\[\begin{array}{l} [a, b] = \mathsf{sort}([a, b])\\ \\ \begin{array}{l} \mathbf{if}\;e^{a} \leq 0:\\ \;\;\;\;\frac{b}{e^{a} + 1}\\ \mathbf{else}:\\ \;\;\;\;\log 2 + b \cdot \left(0.5 + b \cdot 0.125\right)\\ \end{array} \end{array} \]
NOTE: a and b should be sorted in increasing order before calling this function.
(FPCore (a b)
 :precision binary64
 (if (<= (exp a) 0.0)
   (/ b (+ (exp a) 1.0))
   (+ (log 2.0) (* b (+ 0.5 (* b 0.125))))))
assert(a < b);
double code(double a, double b) {
	double tmp;
	if (exp(a) <= 0.0) {
		tmp = b / (exp(a) + 1.0);
	} else {
		tmp = log(2.0) + (b * (0.5 + (b * 0.125)));
	}
	return tmp;
}
NOTE: a and b should be sorted in increasing order before calling this function.
real(8) function code(a, b)
    real(8), intent (in) :: a
    real(8), intent (in) :: b
    real(8) :: tmp
    if (exp(a) <= 0.0d0) then
        tmp = b / (exp(a) + 1.0d0)
    else
        tmp = log(2.0d0) + (b * (0.5d0 + (b * 0.125d0)))
    end if
    code = tmp
end function
assert a < b;
public static double code(double a, double b) {
	double tmp;
	if (Math.exp(a) <= 0.0) {
		tmp = b / (Math.exp(a) + 1.0);
	} else {
		tmp = Math.log(2.0) + (b * (0.5 + (b * 0.125)));
	}
	return tmp;
}
[a, b] = sort([a, b])
def code(a, b):
	tmp = 0
	if math.exp(a) <= 0.0:
		tmp = b / (math.exp(a) + 1.0)
	else:
		tmp = math.log(2.0) + (b * (0.5 + (b * 0.125)))
	return tmp
a, b = sort([a, b])
function code(a, b)
	tmp = 0.0
	if (exp(a) <= 0.0)
		tmp = Float64(b / Float64(exp(a) + 1.0));
	else
		tmp = Float64(log(2.0) + Float64(b * Float64(0.5 + Float64(b * 0.125))));
	end
	return tmp
end
a, b = num2cell(sort([a, b])){:}
function tmp_2 = code(a, b)
	tmp = 0.0;
	if (exp(a) <= 0.0)
		tmp = b / (exp(a) + 1.0);
	else
		tmp = log(2.0) + (b * (0.5 + (b * 0.125)));
	end
	tmp_2 = tmp;
end
NOTE: a and b should be sorted in increasing order before calling this function.
code[a_, b_] := If[LessEqual[N[Exp[a], $MachinePrecision], 0.0], N[(b / N[(N[Exp[a], $MachinePrecision] + 1.0), $MachinePrecision]), $MachinePrecision], N[(N[Log[2.0], $MachinePrecision] + N[(b * N[(0.5 + N[(b * 0.125), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]]
\begin{array}{l}
[a, b] = \mathsf{sort}([a, b])\\
\\
\begin{array}{l}
\mathbf{if}\;e^{a} \leq 0:\\
\;\;\;\;\frac{b}{e^{a} + 1}\\

\mathbf{else}:\\
\;\;\;\;\log 2 + b \cdot \left(0.5 + b \cdot 0.125\right)\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if (exp.f64 a) < 0.0

    1. Initial program 7.0%

      \[\log \left(e^{a} + e^{b}\right) \]
    2. Add Preprocessing
    3. Taylor expanded in b around 0 97.3%

      \[\leadsto \color{blue}{\log \left(1 + e^{a}\right) + \frac{b}{1 + e^{a}}} \]
    4. Step-by-step derivation
      1. log1p-define97.3%

        \[\leadsto \color{blue}{\mathsf{log1p}\left(e^{a}\right)} + \frac{b}{1 + e^{a}} \]
    5. Simplified97.3%

      \[\leadsto \color{blue}{\mathsf{log1p}\left(e^{a}\right) + \frac{b}{1 + e^{a}}} \]
    6. Taylor expanded in b around inf 97.3%

      \[\leadsto \color{blue}{\frac{b}{1 + e^{a}}} \]

    if 0.0 < (exp.f64 a)

    1. Initial program 67.1%

      \[\log \left(e^{a} + e^{b}\right) \]
    2. Add Preprocessing
    3. Taylor expanded in b around 0 61.8%

      \[\leadsto \log \color{blue}{\left(1 + \left(e^{a} + b \cdot \left(1 + b \cdot \left(0.5 + 0.16666666666666666 \cdot b\right)\right)\right)\right)} \]
    4. Step-by-step derivation
      1. associate-+r+61.9%

        \[\leadsto \log \color{blue}{\left(\left(1 + e^{a}\right) + b \cdot \left(1 + b \cdot \left(0.5 + 0.16666666666666666 \cdot b\right)\right)\right)} \]
      2. *-commutative61.9%

        \[\leadsto \log \left(\left(1 + e^{a}\right) + b \cdot \left(1 + b \cdot \left(0.5 + \color{blue}{b \cdot 0.16666666666666666}\right)\right)\right) \]
    5. Simplified61.9%

      \[\leadsto \log \color{blue}{\left(\left(1 + e^{a}\right) + b \cdot \left(1 + b \cdot \left(0.5 + b \cdot 0.16666666666666666\right)\right)\right)} \]
    6. Taylor expanded in a around 0 59.4%

      \[\leadsto \log \left(\color{blue}{2} + b \cdot \left(1 + b \cdot \left(0.5 + b \cdot 0.16666666666666666\right)\right)\right) \]
    7. Taylor expanded in b around 0 60.2%

      \[\leadsto \color{blue}{\log 2 + b \cdot \left(0.5 + 0.125 \cdot b\right)} \]
    8. Step-by-step derivation
      1. *-commutative60.2%

        \[\leadsto \log 2 + b \cdot \left(0.5 + \color{blue}{b \cdot 0.125}\right) \]
    9. Simplified60.2%

      \[\leadsto \color{blue}{\log 2 + b \cdot \left(0.5 + b \cdot 0.125\right)} \]
  3. Recombined 2 regimes into one program.
  4. Final simplification70.5%

    \[\leadsto \begin{array}{l} \mathbf{if}\;e^{a} \leq 0:\\ \;\;\;\;\frac{b}{e^{a} + 1}\\ \mathbf{else}:\\ \;\;\;\;\log 2 + b \cdot \left(0.5 + b \cdot 0.125\right)\\ \end{array} \]
  5. Add Preprocessing

Alternative 5: 97.0% accurate, 2.8× speedup?

\[\begin{array}{l} [a, b] = \mathsf{sort}([a, b])\\ \\ \begin{array}{l} \mathbf{if}\;a \leq -39:\\ \;\;\;\;\frac{b}{e^{a} + 1}\\ \mathbf{else}:\\ \;\;\;\;\log 2 + b \cdot 0.5\\ \end{array} \end{array} \]
NOTE: a and b should be sorted in increasing order before calling this function.
(FPCore (a b)
 :precision binary64
 (if (<= a -39.0) (/ b (+ (exp a) 1.0)) (+ (log 2.0) (* b 0.5))))
assert(a < b);
double code(double a, double b) {
	double tmp;
	if (a <= -39.0) {
		tmp = b / (exp(a) + 1.0);
	} else {
		tmp = log(2.0) + (b * 0.5);
	}
	return tmp;
}
NOTE: a and b should be sorted in increasing order before calling this function.
real(8) function code(a, b)
    real(8), intent (in) :: a
    real(8), intent (in) :: b
    real(8) :: tmp
    if (a <= (-39.0d0)) then
        tmp = b / (exp(a) + 1.0d0)
    else
        tmp = log(2.0d0) + (b * 0.5d0)
    end if
    code = tmp
end function
assert a < b;
public static double code(double a, double b) {
	double tmp;
	if (a <= -39.0) {
		tmp = b / (Math.exp(a) + 1.0);
	} else {
		tmp = Math.log(2.0) + (b * 0.5);
	}
	return tmp;
}
[a, b] = sort([a, b])
def code(a, b):
	tmp = 0
	if a <= -39.0:
		tmp = b / (math.exp(a) + 1.0)
	else:
		tmp = math.log(2.0) + (b * 0.5)
	return tmp
a, b = sort([a, b])
function code(a, b)
	tmp = 0.0
	if (a <= -39.0)
		tmp = Float64(b / Float64(exp(a) + 1.0));
	else
		tmp = Float64(log(2.0) + Float64(b * 0.5));
	end
	return tmp
end
a, b = num2cell(sort([a, b])){:}
function tmp_2 = code(a, b)
	tmp = 0.0;
	if (a <= -39.0)
		tmp = b / (exp(a) + 1.0);
	else
		tmp = log(2.0) + (b * 0.5);
	end
	tmp_2 = tmp;
end
NOTE: a and b should be sorted in increasing order before calling this function.
code[a_, b_] := If[LessEqual[a, -39.0], N[(b / N[(N[Exp[a], $MachinePrecision] + 1.0), $MachinePrecision]), $MachinePrecision], N[(N[Log[2.0], $MachinePrecision] + N[(b * 0.5), $MachinePrecision]), $MachinePrecision]]
\begin{array}{l}
[a, b] = \mathsf{sort}([a, b])\\
\\
\begin{array}{l}
\mathbf{if}\;a \leq -39:\\
\;\;\;\;\frac{b}{e^{a} + 1}\\

\mathbf{else}:\\
\;\;\;\;\log 2 + b \cdot 0.5\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if a < -39

    1. Initial program 7.0%

      \[\log \left(e^{a} + e^{b}\right) \]
    2. Add Preprocessing
    3. Taylor expanded in b around 0 97.3%

      \[\leadsto \color{blue}{\log \left(1 + e^{a}\right) + \frac{b}{1 + e^{a}}} \]
    4. Step-by-step derivation
      1. log1p-define97.3%

        \[\leadsto \color{blue}{\mathsf{log1p}\left(e^{a}\right)} + \frac{b}{1 + e^{a}} \]
    5. Simplified97.3%

      \[\leadsto \color{blue}{\mathsf{log1p}\left(e^{a}\right) + \frac{b}{1 + e^{a}}} \]
    6. Taylor expanded in b around inf 97.3%

      \[\leadsto \color{blue}{\frac{b}{1 + e^{a}}} \]

    if -39 < a

    1. Initial program 67.1%

      \[\log \left(e^{a} + e^{b}\right) \]
    2. Add Preprocessing
    3. Taylor expanded in b around 0 62.4%

      \[\leadsto \color{blue}{\log \left(1 + e^{a}\right) + \frac{b}{1 + e^{a}}} \]
    4. Step-by-step derivation
      1. log1p-define62.8%

        \[\leadsto \color{blue}{\mathsf{log1p}\left(e^{a}\right)} + \frac{b}{1 + e^{a}} \]
    5. Simplified62.8%

      \[\leadsto \color{blue}{\mathsf{log1p}\left(e^{a}\right) + \frac{b}{1 + e^{a}}} \]
    6. Taylor expanded in a around 0 60.0%

      \[\leadsto \color{blue}{\log 2 + 0.5 \cdot b} \]
  3. Recombined 2 regimes into one program.
  4. Final simplification70.3%

    \[\leadsto \begin{array}{l} \mathbf{if}\;a \leq -39:\\ \;\;\;\;\frac{b}{e^{a} + 1}\\ \mathbf{else}:\\ \;\;\;\;\log 2 + b \cdot 0.5\\ \end{array} \]
  5. Add Preprocessing

Alternative 6: 94.5% accurate, 2.8× speedup?

\[\begin{array}{l} [a, b] = \mathsf{sort}([a, b])\\ \\ \begin{array}{l} \mathbf{if}\;a \leq -80:\\ \;\;\;\;\mathsf{log1p}\left(b\right)\\ \mathbf{else}:\\ \;\;\;\;\log 2 + b \cdot 0.5\\ \end{array} \end{array} \]
NOTE: a and b should be sorted in increasing order before calling this function.
(FPCore (a b)
 :precision binary64
 (if (<= a -80.0) (log1p b) (+ (log 2.0) (* b 0.5))))
assert(a < b);
double code(double a, double b) {
	double tmp;
	if (a <= -80.0) {
		tmp = log1p(b);
	} else {
		tmp = log(2.0) + (b * 0.5);
	}
	return tmp;
}
assert a < b;
public static double code(double a, double b) {
	double tmp;
	if (a <= -80.0) {
		tmp = Math.log1p(b);
	} else {
		tmp = Math.log(2.0) + (b * 0.5);
	}
	return tmp;
}
[a, b] = sort([a, b])
def code(a, b):
	tmp = 0
	if a <= -80.0:
		tmp = math.log1p(b)
	else:
		tmp = math.log(2.0) + (b * 0.5)
	return tmp
a, b = sort([a, b])
function code(a, b)
	tmp = 0.0
	if (a <= -80.0)
		tmp = log1p(b);
	else
		tmp = Float64(log(2.0) + Float64(b * 0.5));
	end
	return tmp
end
NOTE: a and b should be sorted in increasing order before calling this function.
code[a_, b_] := If[LessEqual[a, -80.0], N[Log[1 + b], $MachinePrecision], N[(N[Log[2.0], $MachinePrecision] + N[(b * 0.5), $MachinePrecision]), $MachinePrecision]]
\begin{array}{l}
[a, b] = \mathsf{sort}([a, b])\\
\\
\begin{array}{l}
\mathbf{if}\;a \leq -80:\\
\;\;\;\;\mathsf{log1p}\left(b\right)\\

\mathbf{else}:\\
\;\;\;\;\log 2 + b \cdot 0.5\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if a < -80

    1. Initial program 7.0%

      \[\log \left(e^{a} + e^{b}\right) \]
    2. Add Preprocessing
    3. Taylor expanded in b around 0 6.5%

      \[\leadsto \log \color{blue}{\left(1 + \left(b + e^{a}\right)\right)} \]
    4. Step-by-step derivation
      1. associate-+r+6.5%

        \[\leadsto \log \color{blue}{\left(\left(1 + b\right) + e^{a}\right)} \]
      2. +-commutative6.5%

        \[\leadsto \log \color{blue}{\left(e^{a} + \left(1 + b\right)\right)} \]
    5. Simplified6.5%

      \[\leadsto \log \color{blue}{\left(e^{a} + \left(1 + b\right)\right)} \]
    6. Taylor expanded in a around 0 3.7%

      \[\leadsto \color{blue}{\log \left(2 + b\right)} \]
    7. Step-by-step derivation
      1. metadata-eval3.7%

        \[\leadsto \log \left(\color{blue}{\left(1 + 1\right)} + b\right) \]
      2. associate-+r+3.7%

        \[\leadsto \log \color{blue}{\left(1 + \left(1 + b\right)\right)} \]
      3. +-commutative3.7%

        \[\leadsto \log \left(1 + \color{blue}{\left(b + 1\right)}\right) \]
      4. log1p-undefine3.7%

        \[\leadsto \color{blue}{\mathsf{log1p}\left(b + 1\right)} \]
    8. Simplified3.7%

      \[\leadsto \color{blue}{\mathsf{log1p}\left(b + 1\right)} \]
    9. Taylor expanded in b around inf 93.3%

      \[\leadsto \mathsf{log1p}\left(\color{blue}{b}\right) \]

    if -80 < a

    1. Initial program 67.1%

      \[\log \left(e^{a} + e^{b}\right) \]
    2. Add Preprocessing
    3. Taylor expanded in b around 0 62.4%

      \[\leadsto \color{blue}{\log \left(1 + e^{a}\right) + \frac{b}{1 + e^{a}}} \]
    4. Step-by-step derivation
      1. log1p-define62.8%

        \[\leadsto \color{blue}{\mathsf{log1p}\left(e^{a}\right)} + \frac{b}{1 + e^{a}} \]
    5. Simplified62.8%

      \[\leadsto \color{blue}{\mathsf{log1p}\left(e^{a}\right) + \frac{b}{1 + e^{a}}} \]
    6. Taylor expanded in a around 0 60.0%

      \[\leadsto \color{blue}{\log 2 + 0.5 \cdot b} \]
  3. Recombined 2 regimes into one program.
  4. Final simplification69.2%

    \[\leadsto \begin{array}{l} \mathbf{if}\;a \leq -80:\\ \;\;\;\;\mathsf{log1p}\left(b\right)\\ \mathbf{else}:\\ \;\;\;\;\log 2 + b \cdot 0.5\\ \end{array} \]
  5. Add Preprocessing

Alternative 7: 94.4% accurate, 2.8× speedup?

\[\begin{array}{l} [a, b] = \mathsf{sort}([a, b])\\ \\ \begin{array}{l} \mathbf{if}\;a \leq -68:\\ \;\;\;\;\mathsf{log1p}\left(b\right)\\ \mathbf{else}:\\ \;\;\;\;\mathsf{log1p}\left(1 + b\right)\\ \end{array} \end{array} \]
NOTE: a and b should be sorted in increasing order before calling this function.
(FPCore (a b)
 :precision binary64
 (if (<= a -68.0) (log1p b) (log1p (+ 1.0 b))))
assert(a < b);
double code(double a, double b) {
	double tmp;
	if (a <= -68.0) {
		tmp = log1p(b);
	} else {
		tmp = log1p((1.0 + b));
	}
	return tmp;
}
assert a < b;
public static double code(double a, double b) {
	double tmp;
	if (a <= -68.0) {
		tmp = Math.log1p(b);
	} else {
		tmp = Math.log1p((1.0 + b));
	}
	return tmp;
}
[a, b] = sort([a, b])
def code(a, b):
	tmp = 0
	if a <= -68.0:
		tmp = math.log1p(b)
	else:
		tmp = math.log1p((1.0 + b))
	return tmp
a, b = sort([a, b])
function code(a, b)
	tmp = 0.0
	if (a <= -68.0)
		tmp = log1p(b);
	else
		tmp = log1p(Float64(1.0 + b));
	end
	return tmp
end
NOTE: a and b should be sorted in increasing order before calling this function.
code[a_, b_] := If[LessEqual[a, -68.0], N[Log[1 + b], $MachinePrecision], N[Log[1 + N[(1.0 + b), $MachinePrecision]], $MachinePrecision]]
\begin{array}{l}
[a, b] = \mathsf{sort}([a, b])\\
\\
\begin{array}{l}
\mathbf{if}\;a \leq -68:\\
\;\;\;\;\mathsf{log1p}\left(b\right)\\

\mathbf{else}:\\
\;\;\;\;\mathsf{log1p}\left(1 + b\right)\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if a < -68

    1. Initial program 7.0%

      \[\log \left(e^{a} + e^{b}\right) \]
    2. Add Preprocessing
    3. Taylor expanded in b around 0 6.5%

      \[\leadsto \log \color{blue}{\left(1 + \left(b + e^{a}\right)\right)} \]
    4. Step-by-step derivation
      1. associate-+r+6.5%

        \[\leadsto \log \color{blue}{\left(\left(1 + b\right) + e^{a}\right)} \]
      2. +-commutative6.5%

        \[\leadsto \log \color{blue}{\left(e^{a} + \left(1 + b\right)\right)} \]
    5. Simplified6.5%

      \[\leadsto \log \color{blue}{\left(e^{a} + \left(1 + b\right)\right)} \]
    6. Taylor expanded in a around 0 3.7%

      \[\leadsto \color{blue}{\log \left(2 + b\right)} \]
    7. Step-by-step derivation
      1. metadata-eval3.7%

        \[\leadsto \log \left(\color{blue}{\left(1 + 1\right)} + b\right) \]
      2. associate-+r+3.7%

        \[\leadsto \log \color{blue}{\left(1 + \left(1 + b\right)\right)} \]
      3. +-commutative3.7%

        \[\leadsto \log \left(1 + \color{blue}{\left(b + 1\right)}\right) \]
      4. log1p-undefine3.7%

        \[\leadsto \color{blue}{\mathsf{log1p}\left(b + 1\right)} \]
    8. Simplified3.7%

      \[\leadsto \color{blue}{\mathsf{log1p}\left(b + 1\right)} \]
    9. Taylor expanded in b around inf 93.3%

      \[\leadsto \mathsf{log1p}\left(\color{blue}{b}\right) \]

    if -68 < a

    1. Initial program 67.1%

      \[\log \left(e^{a} + e^{b}\right) \]
    2. Add Preprocessing
    3. Taylor expanded in b around 0 61.5%

      \[\leadsto \log \color{blue}{\left(1 + \left(b + e^{a}\right)\right)} \]
    4. Step-by-step derivation
      1. associate-+r+61.5%

        \[\leadsto \log \color{blue}{\left(\left(1 + b\right) + e^{a}\right)} \]
      2. +-commutative61.5%

        \[\leadsto \log \color{blue}{\left(e^{a} + \left(1 + b\right)\right)} \]
    5. Simplified61.5%

      \[\leadsto \log \color{blue}{\left(e^{a} + \left(1 + b\right)\right)} \]
    6. Taylor expanded in a around 0 59.0%

      \[\leadsto \color{blue}{\log \left(2 + b\right)} \]
    7. Step-by-step derivation
      1. metadata-eval59.0%

        \[\leadsto \log \left(\color{blue}{\left(1 + 1\right)} + b\right) \]
      2. associate-+r+59.0%

        \[\leadsto \log \color{blue}{\left(1 + \left(1 + b\right)\right)} \]
      3. +-commutative59.0%

        \[\leadsto \log \left(1 + \color{blue}{\left(b + 1\right)}\right) \]
      4. log1p-undefine59.1%

        \[\leadsto \color{blue}{\mathsf{log1p}\left(b + 1\right)} \]
    8. Simplified59.1%

      \[\leadsto \color{blue}{\mathsf{log1p}\left(b + 1\right)} \]
  3. Recombined 2 regimes into one program.
  4. Final simplification68.5%

    \[\leadsto \begin{array}{l} \mathbf{if}\;a \leq -68:\\ \;\;\;\;\mathsf{log1p}\left(b\right)\\ \mathbf{else}:\\ \;\;\;\;\mathsf{log1p}\left(1 + b\right)\\ \end{array} \]
  5. Add Preprocessing

Alternative 8: 94.4% accurate, 2.8× speedup?

\[\begin{array}{l} [a, b] = \mathsf{sort}([a, b])\\ \\ \begin{array}{l} \mathbf{if}\;a \leq -47:\\ \;\;\;\;\mathsf{log1p}\left(b\right)\\ \mathbf{else}:\\ \;\;\;\;\log \left(b + 2\right)\\ \end{array} \end{array} \]
NOTE: a and b should be sorted in increasing order before calling this function.
(FPCore (a b) :precision binary64 (if (<= a -47.0) (log1p b) (log (+ b 2.0))))
assert(a < b);
double code(double a, double b) {
	double tmp;
	if (a <= -47.0) {
		tmp = log1p(b);
	} else {
		tmp = log((b + 2.0));
	}
	return tmp;
}
assert a < b;
public static double code(double a, double b) {
	double tmp;
	if (a <= -47.0) {
		tmp = Math.log1p(b);
	} else {
		tmp = Math.log((b + 2.0));
	}
	return tmp;
}
[a, b] = sort([a, b])
def code(a, b):
	tmp = 0
	if a <= -47.0:
		tmp = math.log1p(b)
	else:
		tmp = math.log((b + 2.0))
	return tmp
a, b = sort([a, b])
function code(a, b)
	tmp = 0.0
	if (a <= -47.0)
		tmp = log1p(b);
	else
		tmp = log(Float64(b + 2.0));
	end
	return tmp
end
NOTE: a and b should be sorted in increasing order before calling this function.
code[a_, b_] := If[LessEqual[a, -47.0], N[Log[1 + b], $MachinePrecision], N[Log[N[(b + 2.0), $MachinePrecision]], $MachinePrecision]]
\begin{array}{l}
[a, b] = \mathsf{sort}([a, b])\\
\\
\begin{array}{l}
\mathbf{if}\;a \leq -47:\\
\;\;\;\;\mathsf{log1p}\left(b\right)\\

\mathbf{else}:\\
\;\;\;\;\log \left(b + 2\right)\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if a < -47

    1. Initial program 7.0%

      \[\log \left(e^{a} + e^{b}\right) \]
    2. Add Preprocessing
    3. Taylor expanded in b around 0 6.5%

      \[\leadsto \log \color{blue}{\left(1 + \left(b + e^{a}\right)\right)} \]
    4. Step-by-step derivation
      1. associate-+r+6.5%

        \[\leadsto \log \color{blue}{\left(\left(1 + b\right) + e^{a}\right)} \]
      2. +-commutative6.5%

        \[\leadsto \log \color{blue}{\left(e^{a} + \left(1 + b\right)\right)} \]
    5. Simplified6.5%

      \[\leadsto \log \color{blue}{\left(e^{a} + \left(1 + b\right)\right)} \]
    6. Taylor expanded in a around 0 3.7%

      \[\leadsto \color{blue}{\log \left(2 + b\right)} \]
    7. Step-by-step derivation
      1. metadata-eval3.7%

        \[\leadsto \log \left(\color{blue}{\left(1 + 1\right)} + b\right) \]
      2. associate-+r+3.7%

        \[\leadsto \log \color{blue}{\left(1 + \left(1 + b\right)\right)} \]
      3. +-commutative3.7%

        \[\leadsto \log \left(1 + \color{blue}{\left(b + 1\right)}\right) \]
      4. log1p-undefine3.7%

        \[\leadsto \color{blue}{\mathsf{log1p}\left(b + 1\right)} \]
    8. Simplified3.7%

      \[\leadsto \color{blue}{\mathsf{log1p}\left(b + 1\right)} \]
    9. Taylor expanded in b around inf 93.3%

      \[\leadsto \mathsf{log1p}\left(\color{blue}{b}\right) \]

    if -47 < a

    1. Initial program 67.1%

      \[\log \left(e^{a} + e^{b}\right) \]
    2. Add Preprocessing
    3. Taylor expanded in b around 0 61.5%

      \[\leadsto \log \color{blue}{\left(1 + \left(b + e^{a}\right)\right)} \]
    4. Step-by-step derivation
      1. associate-+r+61.5%

        \[\leadsto \log \color{blue}{\left(\left(1 + b\right) + e^{a}\right)} \]
      2. +-commutative61.5%

        \[\leadsto \log \color{blue}{\left(e^{a} + \left(1 + b\right)\right)} \]
    5. Simplified61.5%

      \[\leadsto \log \color{blue}{\left(e^{a} + \left(1 + b\right)\right)} \]
    6. Taylor expanded in a around 0 59.0%

      \[\leadsto \color{blue}{\log \left(2 + b\right)} \]
  3. Recombined 2 regimes into one program.
  4. Final simplification68.5%

    \[\leadsto \begin{array}{l} \mathbf{if}\;a \leq -47:\\ \;\;\;\;\mathsf{log1p}\left(b\right)\\ \mathbf{else}:\\ \;\;\;\;\log \left(b + 2\right)\\ \end{array} \]
  5. Add Preprocessing

Alternative 9: 93.9% accurate, 2.9× speedup?

\[\begin{array}{l} [a, b] = \mathsf{sort}([a, b])\\ \\ \begin{array}{l} \mathbf{if}\;a \leq -55:\\ \;\;\;\;\mathsf{log1p}\left(b\right)\\ \mathbf{else}:\\ \;\;\;\;\mathsf{log1p}\left(1\right)\\ \end{array} \end{array} \]
NOTE: a and b should be sorted in increasing order before calling this function.
(FPCore (a b) :precision binary64 (if (<= a -55.0) (log1p b) (log1p 1.0)))
assert(a < b);
double code(double a, double b) {
	double tmp;
	if (a <= -55.0) {
		tmp = log1p(b);
	} else {
		tmp = log1p(1.0);
	}
	return tmp;
}
assert a < b;
public static double code(double a, double b) {
	double tmp;
	if (a <= -55.0) {
		tmp = Math.log1p(b);
	} else {
		tmp = Math.log1p(1.0);
	}
	return tmp;
}
[a, b] = sort([a, b])
def code(a, b):
	tmp = 0
	if a <= -55.0:
		tmp = math.log1p(b)
	else:
		tmp = math.log1p(1.0)
	return tmp
a, b = sort([a, b])
function code(a, b)
	tmp = 0.0
	if (a <= -55.0)
		tmp = log1p(b);
	else
		tmp = log1p(1.0);
	end
	return tmp
end
NOTE: a and b should be sorted in increasing order before calling this function.
code[a_, b_] := If[LessEqual[a, -55.0], N[Log[1 + b], $MachinePrecision], N[Log[1 + 1.0], $MachinePrecision]]
\begin{array}{l}
[a, b] = \mathsf{sort}([a, b])\\
\\
\begin{array}{l}
\mathbf{if}\;a \leq -55:\\
\;\;\;\;\mathsf{log1p}\left(b\right)\\

\mathbf{else}:\\
\;\;\;\;\mathsf{log1p}\left(1\right)\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if a < -55

    1. Initial program 7.0%

      \[\log \left(e^{a} + e^{b}\right) \]
    2. Add Preprocessing
    3. Taylor expanded in b around 0 6.5%

      \[\leadsto \log \color{blue}{\left(1 + \left(b + e^{a}\right)\right)} \]
    4. Step-by-step derivation
      1. associate-+r+6.5%

        \[\leadsto \log \color{blue}{\left(\left(1 + b\right) + e^{a}\right)} \]
      2. +-commutative6.5%

        \[\leadsto \log \color{blue}{\left(e^{a} + \left(1 + b\right)\right)} \]
    5. Simplified6.5%

      \[\leadsto \log \color{blue}{\left(e^{a} + \left(1 + b\right)\right)} \]
    6. Taylor expanded in a around 0 3.7%

      \[\leadsto \color{blue}{\log \left(2 + b\right)} \]
    7. Step-by-step derivation
      1. metadata-eval3.7%

        \[\leadsto \log \left(\color{blue}{\left(1 + 1\right)} + b\right) \]
      2. associate-+r+3.7%

        \[\leadsto \log \color{blue}{\left(1 + \left(1 + b\right)\right)} \]
      3. +-commutative3.7%

        \[\leadsto \log \left(1 + \color{blue}{\left(b + 1\right)}\right) \]
      4. log1p-undefine3.7%

        \[\leadsto \color{blue}{\mathsf{log1p}\left(b + 1\right)} \]
    8. Simplified3.7%

      \[\leadsto \color{blue}{\mathsf{log1p}\left(b + 1\right)} \]
    9. Taylor expanded in b around inf 93.3%

      \[\leadsto \mathsf{log1p}\left(\color{blue}{b}\right) \]

    if -55 < a

    1. Initial program 67.1%

      \[\log \left(e^{a} + e^{b}\right) \]
    2. Add Preprocessing
    3. Taylor expanded in b around 0 62.3%

      \[\leadsto \color{blue}{\log \left(1 + e^{a}\right)} \]
    4. Step-by-step derivation
      1. log1p-define62.7%

        \[\leadsto \color{blue}{\mathsf{log1p}\left(e^{a}\right)} \]
    5. Simplified62.7%

      \[\leadsto \color{blue}{\mathsf{log1p}\left(e^{a}\right)} \]
    6. Taylor expanded in a around 0 59.9%

      \[\leadsto \mathsf{log1p}\left(\color{blue}{1}\right) \]
  3. Recombined 2 regimes into one program.
  4. Add Preprocessing

Alternative 10: 56.8% accurate, 2.9× speedup?

\[\begin{array}{l} [a, b] = \mathsf{sort}([a, b])\\ \\ \begin{array}{l} \mathbf{if}\;a \leq -105:\\ \;\;\;\;b \cdot 0.5\\ \mathbf{else}:\\ \;\;\;\;\mathsf{log1p}\left(1\right)\\ \end{array} \end{array} \]
NOTE: a and b should be sorted in increasing order before calling this function.
(FPCore (a b) :precision binary64 (if (<= a -105.0) (* b 0.5) (log1p 1.0)))
assert(a < b);
double code(double a, double b) {
	double tmp;
	if (a <= -105.0) {
		tmp = b * 0.5;
	} else {
		tmp = log1p(1.0);
	}
	return tmp;
}
assert a < b;
public static double code(double a, double b) {
	double tmp;
	if (a <= -105.0) {
		tmp = b * 0.5;
	} else {
		tmp = Math.log1p(1.0);
	}
	return tmp;
}
[a, b] = sort([a, b])
def code(a, b):
	tmp = 0
	if a <= -105.0:
		tmp = b * 0.5
	else:
		tmp = math.log1p(1.0)
	return tmp
a, b = sort([a, b])
function code(a, b)
	tmp = 0.0
	if (a <= -105.0)
		tmp = Float64(b * 0.5);
	else
		tmp = log1p(1.0);
	end
	return tmp
end
NOTE: a and b should be sorted in increasing order before calling this function.
code[a_, b_] := If[LessEqual[a, -105.0], N[(b * 0.5), $MachinePrecision], N[Log[1 + 1.0], $MachinePrecision]]
\begin{array}{l}
[a, b] = \mathsf{sort}([a, b])\\
\\
\begin{array}{l}
\mathbf{if}\;a \leq -105:\\
\;\;\;\;b \cdot 0.5\\

\mathbf{else}:\\
\;\;\;\;\mathsf{log1p}\left(1\right)\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if a < -105

    1. Initial program 7.0%

      \[\log \left(e^{a} + e^{b}\right) \]
    2. Add Preprocessing
    3. Taylor expanded in b around 0 97.3%

      \[\leadsto \color{blue}{\log \left(1 + e^{a}\right) + \frac{b}{1 + e^{a}}} \]
    4. Step-by-step derivation
      1. log1p-define97.3%

        \[\leadsto \color{blue}{\mathsf{log1p}\left(e^{a}\right)} + \frac{b}{1 + e^{a}} \]
    5. Simplified97.3%

      \[\leadsto \color{blue}{\mathsf{log1p}\left(e^{a}\right) + \frac{b}{1 + e^{a}}} \]
    6. Taylor expanded in a around 0 4.2%

      \[\leadsto \color{blue}{\log 2 + 0.5 \cdot b} \]
    7. Taylor expanded in b around inf 18.4%

      \[\leadsto \color{blue}{0.5 \cdot b} \]
    8. Step-by-step derivation
      1. *-commutative18.4%

        \[\leadsto \color{blue}{b \cdot 0.5} \]
    9. Simplified18.4%

      \[\leadsto \color{blue}{b \cdot 0.5} \]

    if -105 < a

    1. Initial program 67.1%

      \[\log \left(e^{a} + e^{b}\right) \]
    2. Add Preprocessing
    3. Taylor expanded in b around 0 62.3%

      \[\leadsto \color{blue}{\log \left(1 + e^{a}\right)} \]
    4. Step-by-step derivation
      1. log1p-define62.7%

        \[\leadsto \color{blue}{\mathsf{log1p}\left(e^{a}\right)} \]
    5. Simplified62.7%

      \[\leadsto \color{blue}{\mathsf{log1p}\left(e^{a}\right)} \]
    6. Taylor expanded in a around 0 59.9%

      \[\leadsto \mathsf{log1p}\left(\color{blue}{1}\right) \]
  3. Recombined 2 regimes into one program.
  4. Add Preprocessing

Alternative 11: 11.9% accurate, 101.0× speedup?

\[\begin{array}{l} [a, b] = \mathsf{sort}([a, b])\\ \\ b \cdot 0.5 \end{array} \]
NOTE: a and b should be sorted in increasing order before calling this function.
(FPCore (a b) :precision binary64 (* b 0.5))
assert(a < b);
double code(double a, double b) {
	return b * 0.5;
}
NOTE: a and b should be sorted in increasing order before calling this function.
real(8) function code(a, b)
    real(8), intent (in) :: a
    real(8), intent (in) :: b
    code = b * 0.5d0
end function
assert a < b;
public static double code(double a, double b) {
	return b * 0.5;
}
[a, b] = sort([a, b])
def code(a, b):
	return b * 0.5
a, b = sort([a, b])
function code(a, b)
	return Float64(b * 0.5)
end
a, b = num2cell(sort([a, b])){:}
function tmp = code(a, b)
	tmp = b * 0.5;
end
NOTE: a and b should be sorted in increasing order before calling this function.
code[a_, b_] := N[(b * 0.5), $MachinePrecision]
\begin{array}{l}
[a, b] = \mathsf{sort}([a, b])\\
\\
b \cdot 0.5
\end{array}
Derivation
  1. Initial program 50.4%

    \[\log \left(e^{a} + e^{b}\right) \]
  2. Add Preprocessing
  3. Taylor expanded in b around 0 72.1%

    \[\leadsto \color{blue}{\log \left(1 + e^{a}\right) + \frac{b}{1 + e^{a}}} \]
  4. Step-by-step derivation
    1. log1p-define72.4%

      \[\leadsto \color{blue}{\mathsf{log1p}\left(e^{a}\right)} + \frac{b}{1 + e^{a}} \]
  5. Simplified72.4%

    \[\leadsto \color{blue}{\mathsf{log1p}\left(e^{a}\right) + \frac{b}{1 + e^{a}}} \]
  6. Taylor expanded in a around 0 44.5%

    \[\leadsto \color{blue}{\log 2 + 0.5 \cdot b} \]
  7. Taylor expanded in b around inf 7.7%

    \[\leadsto \color{blue}{0.5 \cdot b} \]
  8. Step-by-step derivation
    1. *-commutative7.7%

      \[\leadsto \color{blue}{b \cdot 0.5} \]
  9. Simplified7.7%

    \[\leadsto \color{blue}{b \cdot 0.5} \]
  10. Add Preprocessing

Reproduce

?
herbie shell --seed 2024181 
(FPCore (a b)
  :name "symmetry log of sum of exp"
  :precision binary64
  (log (+ (exp a) (exp b))))