math.exp on complex, imaginary part

Percentage Accurate: 100.0% → 100.0%
Time: 7.4s
Alternatives: 15
Speedup: 1.0×

Specification

?
\[\begin{array}{l} \\ e^{re} \cdot \sin im \end{array} \]
(FPCore (re im) :precision binary64 (* (exp re) (sin im)))
double code(double re, double im) {
	return exp(re) * sin(im);
}
real(8) function code(re, im)
    real(8), intent (in) :: re
    real(8), intent (in) :: im
    code = exp(re) * sin(im)
end function
public static double code(double re, double im) {
	return Math.exp(re) * Math.sin(im);
}
def code(re, im):
	return math.exp(re) * math.sin(im)
function code(re, im)
	return Float64(exp(re) * sin(im))
end
function tmp = code(re, im)
	tmp = exp(re) * sin(im);
end
code[re_, im_] := N[(N[Exp[re], $MachinePrecision] * N[Sin[im], $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
e^{re} \cdot \sin im
\end{array}

Sampling outcomes in binary64 precision:

Local Percentage Accuracy vs ?

The average percentage accuracy by input value. Horizontal axis shows value of an input variable; the variable is choosen in the title. Vertical axis is accuracy; higher is better. Red represent the original program, while blue represents Herbie's suggestion. These can be toggled with buttons below the plot. The line is an average while dots represent individual samples.

Accuracy vs Speed?

Herbie found 15 alternatives:

AlternativeAccuracySpeedup
The accuracy (vertical axis) and speed (horizontal axis) of each alternatives. Up and to the right is better. The red square shows the initial program, and each blue circle shows an alternative.The line shows the best available speed-accuracy tradeoffs.

Initial Program: 100.0% accurate, 1.0× speedup?

\[\begin{array}{l} \\ e^{re} \cdot \sin im \end{array} \]
(FPCore (re im) :precision binary64 (* (exp re) (sin im)))
double code(double re, double im) {
	return exp(re) * sin(im);
}
real(8) function code(re, im)
    real(8), intent (in) :: re
    real(8), intent (in) :: im
    code = exp(re) * sin(im)
end function
public static double code(double re, double im) {
	return Math.exp(re) * Math.sin(im);
}
def code(re, im):
	return math.exp(re) * math.sin(im)
function code(re, im)
	return Float64(exp(re) * sin(im))
end
function tmp = code(re, im)
	tmp = exp(re) * sin(im);
end
code[re_, im_] := N[(N[Exp[re], $MachinePrecision] * N[Sin[im], $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
e^{re} \cdot \sin im
\end{array}

Alternative 1: 100.0% accurate, 1.0× speedup?

\[\begin{array}{l} \\ \frac{e^{1 + re}}{e} \cdot \sin im \end{array} \]
(FPCore (re im) :precision binary64 (* (/ (exp (+ 1.0 re)) E) (sin im)))
double code(double re, double im) {
	return (exp((1.0 + re)) / ((double) M_E)) * sin(im);
}
public static double code(double re, double im) {
	return (Math.exp((1.0 + re)) / Math.E) * Math.sin(im);
}
def code(re, im):
	return (math.exp((1.0 + re)) / math.e) * math.sin(im)
function code(re, im)
	return Float64(Float64(exp(Float64(1.0 + re)) / exp(1)) * sin(im))
end
function tmp = code(re, im)
	tmp = (exp((1.0 + re)) / 2.71828182845904523536) * sin(im);
end
code[re_, im_] := N[(N[(N[Exp[N[(1.0 + re), $MachinePrecision]], $MachinePrecision] / E), $MachinePrecision] * N[Sin[im], $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
\frac{e^{1 + re}}{e} \cdot \sin im
\end{array}
Derivation
  1. Initial program 100.0%

    \[e^{re} \cdot \sin im \]
  2. Add Preprocessing
  3. Step-by-step derivation
    1. expm1-log1p-u80.4%

      \[\leadsto e^{\color{blue}{\mathsf{expm1}\left(\mathsf{log1p}\left(re\right)\right)}} \cdot \sin im \]
    2. expm1-undefine80.4%

      \[\leadsto e^{\color{blue}{e^{\mathsf{log1p}\left(re\right)} - 1}} \cdot \sin im \]
    3. exp-diff80.4%

      \[\leadsto \color{blue}{\frac{e^{e^{\mathsf{log1p}\left(re\right)}}}{e^{1}}} \cdot \sin im \]
    4. log1p-undefine80.4%

      \[\leadsto \frac{e^{e^{\color{blue}{\log \left(1 + re\right)}}}}{e^{1}} \cdot \sin im \]
    5. rem-exp-log100.0%

      \[\leadsto \frac{e^{\color{blue}{1 + re}}}{e^{1}} \cdot \sin im \]
    6. exp-1-e100.0%

      \[\leadsto \frac{e^{1 + re}}{\color{blue}{e}} \cdot \sin im \]
  4. Applied egg-rr100.0%

    \[\leadsto \color{blue}{\frac{e^{1 + re}}{e}} \cdot \sin im \]
  5. Add Preprocessing

Alternative 2: 93.0% accurate, 0.6× speedup?

\[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;e^{re} \leq 0.99999995:\\ \;\;\;\;im \cdot \left(1 + \mathsf{expm1}\left(re\right)\right)\\ \mathbf{elif}\;e^{re} \leq 1.000002:\\ \;\;\;\;\left(1 + re\right) \cdot \sin im\\ \mathbf{else}:\\ \;\;\;\;im \cdot e^{re}\\ \end{array} \end{array} \]
(FPCore (re im)
 :precision binary64
 (if (<= (exp re) 0.99999995)
   (* im (+ 1.0 (expm1 re)))
   (if (<= (exp re) 1.000002) (* (+ 1.0 re) (sin im)) (* im (exp re)))))
double code(double re, double im) {
	double tmp;
	if (exp(re) <= 0.99999995) {
		tmp = im * (1.0 + expm1(re));
	} else if (exp(re) <= 1.000002) {
		tmp = (1.0 + re) * sin(im);
	} else {
		tmp = im * exp(re);
	}
	return tmp;
}
public static double code(double re, double im) {
	double tmp;
	if (Math.exp(re) <= 0.99999995) {
		tmp = im * (1.0 + Math.expm1(re));
	} else if (Math.exp(re) <= 1.000002) {
		tmp = (1.0 + re) * Math.sin(im);
	} else {
		tmp = im * Math.exp(re);
	}
	return tmp;
}
def code(re, im):
	tmp = 0
	if math.exp(re) <= 0.99999995:
		tmp = im * (1.0 + math.expm1(re))
	elif math.exp(re) <= 1.000002:
		tmp = (1.0 + re) * math.sin(im)
	else:
		tmp = im * math.exp(re)
	return tmp
function code(re, im)
	tmp = 0.0
	if (exp(re) <= 0.99999995)
		tmp = Float64(im * Float64(1.0 + expm1(re)));
	elseif (exp(re) <= 1.000002)
		tmp = Float64(Float64(1.0 + re) * sin(im));
	else
		tmp = Float64(im * exp(re));
	end
	return tmp
end
code[re_, im_] := If[LessEqual[N[Exp[re], $MachinePrecision], 0.99999995], N[(im * N[(1.0 + N[(Exp[re] - 1), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], If[LessEqual[N[Exp[re], $MachinePrecision], 1.000002], N[(N[(1.0 + re), $MachinePrecision] * N[Sin[im], $MachinePrecision]), $MachinePrecision], N[(im * N[Exp[re], $MachinePrecision]), $MachinePrecision]]]
\begin{array}{l}

\\
\begin{array}{l}
\mathbf{if}\;e^{re} \leq 0.99999995:\\
\;\;\;\;im \cdot \left(1 + \mathsf{expm1}\left(re\right)\right)\\

\mathbf{elif}\;e^{re} \leq 1.000002:\\
\;\;\;\;\left(1 + re\right) \cdot \sin im\\

\mathbf{else}:\\
\;\;\;\;im \cdot e^{re}\\


\end{array}
\end{array}
Derivation
  1. Split input into 3 regimes
  2. if (exp.f64 re) < 0.999999949999999971

    1. Initial program 100.0%

      \[e^{re} \cdot \sin im \]
    2. Add Preprocessing
    3. Taylor expanded in im around 0 98.1%

      \[\leadsto e^{re} \cdot \color{blue}{im} \]
    4. Step-by-step derivation
      1. log1p-expm1-u98.1%

        \[\leadsto e^{\color{blue}{\mathsf{log1p}\left(\mathsf{expm1}\left(re\right)\right)}} \cdot im \]
      2. log1p-undefine98.1%

        \[\leadsto e^{\color{blue}{\log \left(1 + \mathsf{expm1}\left(re\right)\right)}} \cdot im \]
      3. add-exp-log98.1%

        \[\leadsto \color{blue}{\left(1 + \mathsf{expm1}\left(re\right)\right)} \cdot im \]
    5. Applied egg-rr98.1%

      \[\leadsto \color{blue}{\left(1 + \mathsf{expm1}\left(re\right)\right)} \cdot im \]

    if 0.999999949999999971 < (exp.f64 re) < 1.00000200000000006

    1. Initial program 100.0%

      \[e^{re} \cdot \sin im \]
    2. Add Preprocessing
    3. Taylor expanded in re around 0 100.0%

      \[\leadsto \color{blue}{\sin im + re \cdot \sin im} \]
    4. Step-by-step derivation
      1. distribute-rgt1-in100.0%

        \[\leadsto \color{blue}{\left(re + 1\right) \cdot \sin im} \]
    5. Simplified100.0%

      \[\leadsto \color{blue}{\left(re + 1\right) \cdot \sin im} \]

    if 1.00000200000000006 < (exp.f64 re)

    1. Initial program 100.0%

      \[e^{re} \cdot \sin im \]
    2. Add Preprocessing
    3. Taylor expanded in im around 0 76.8%

      \[\leadsto e^{re} \cdot \color{blue}{im} \]
  3. Recombined 3 regimes into one program.
  4. Final simplification93.4%

    \[\leadsto \begin{array}{l} \mathbf{if}\;e^{re} \leq 0.99999995:\\ \;\;\;\;im \cdot \left(1 + \mathsf{expm1}\left(re\right)\right)\\ \mathbf{elif}\;e^{re} \leq 1.000002:\\ \;\;\;\;\left(1 + re\right) \cdot \sin im\\ \mathbf{else}:\\ \;\;\;\;im \cdot e^{re}\\ \end{array} \]
  5. Add Preprocessing

Alternative 3: 92.7% accurate, 0.6× speedup?

\[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;e^{re} \leq 0.99999995 \lor \neg \left(e^{re} \leq 1.000002\right):\\ \;\;\;\;im \cdot e^{re}\\ \mathbf{else}:\\ \;\;\;\;\sin im\\ \end{array} \end{array} \]
(FPCore (re im)
 :precision binary64
 (if (or (<= (exp re) 0.99999995) (not (<= (exp re) 1.000002)))
   (* im (exp re))
   (sin im)))
double code(double re, double im) {
	double tmp;
	if ((exp(re) <= 0.99999995) || !(exp(re) <= 1.000002)) {
		tmp = im * exp(re);
	} else {
		tmp = sin(im);
	}
	return tmp;
}
real(8) function code(re, im)
    real(8), intent (in) :: re
    real(8), intent (in) :: im
    real(8) :: tmp
    if ((exp(re) <= 0.99999995d0) .or. (.not. (exp(re) <= 1.000002d0))) then
        tmp = im * exp(re)
    else
        tmp = sin(im)
    end if
    code = tmp
end function
public static double code(double re, double im) {
	double tmp;
	if ((Math.exp(re) <= 0.99999995) || !(Math.exp(re) <= 1.000002)) {
		tmp = im * Math.exp(re);
	} else {
		tmp = Math.sin(im);
	}
	return tmp;
}
def code(re, im):
	tmp = 0
	if (math.exp(re) <= 0.99999995) or not (math.exp(re) <= 1.000002):
		tmp = im * math.exp(re)
	else:
		tmp = math.sin(im)
	return tmp
function code(re, im)
	tmp = 0.0
	if ((exp(re) <= 0.99999995) || !(exp(re) <= 1.000002))
		tmp = Float64(im * exp(re));
	else
		tmp = sin(im);
	end
	return tmp
end
function tmp_2 = code(re, im)
	tmp = 0.0;
	if ((exp(re) <= 0.99999995) || ~((exp(re) <= 1.000002)))
		tmp = im * exp(re);
	else
		tmp = sin(im);
	end
	tmp_2 = tmp;
end
code[re_, im_] := If[Or[LessEqual[N[Exp[re], $MachinePrecision], 0.99999995], N[Not[LessEqual[N[Exp[re], $MachinePrecision], 1.000002]], $MachinePrecision]], N[(im * N[Exp[re], $MachinePrecision]), $MachinePrecision], N[Sin[im], $MachinePrecision]]
\begin{array}{l}

\\
\begin{array}{l}
\mathbf{if}\;e^{re} \leq 0.99999995 \lor \neg \left(e^{re} \leq 1.000002\right):\\
\;\;\;\;im \cdot e^{re}\\

\mathbf{else}:\\
\;\;\;\;\sin im\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if (exp.f64 re) < 0.999999949999999971 or 1.00000200000000006 < (exp.f64 re)

    1. Initial program 100.0%

      \[e^{re} \cdot \sin im \]
    2. Add Preprocessing
    3. Taylor expanded in im around 0 85.9%

      \[\leadsto e^{re} \cdot \color{blue}{im} \]

    if 0.999999949999999971 < (exp.f64 re) < 1.00000200000000006

    1. Initial program 100.0%

      \[e^{re} \cdot \sin im \]
    2. Add Preprocessing
    3. Taylor expanded in re around 0 99.6%

      \[\leadsto \color{blue}{\sin im} \]
  3. Recombined 2 regimes into one program.
  4. Final simplification93.2%

    \[\leadsto \begin{array}{l} \mathbf{if}\;e^{re} \leq 0.99999995 \lor \neg \left(e^{re} \leq 1.000002\right):\\ \;\;\;\;im \cdot e^{re}\\ \mathbf{else}:\\ \;\;\;\;\sin im\\ \end{array} \]
  5. Add Preprocessing

Alternative 4: 92.6% accurate, 0.6× speedup?

\[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;e^{re} \leq 0.99999995:\\ \;\;\;\;im \cdot \left(1 + \mathsf{expm1}\left(re\right)\right)\\ \mathbf{elif}\;e^{re} \leq 1.000002:\\ \;\;\;\;\sin im\\ \mathbf{else}:\\ \;\;\;\;im \cdot e^{re}\\ \end{array} \end{array} \]
(FPCore (re im)
 :precision binary64
 (if (<= (exp re) 0.99999995)
   (* im (+ 1.0 (expm1 re)))
   (if (<= (exp re) 1.000002) (sin im) (* im (exp re)))))
double code(double re, double im) {
	double tmp;
	if (exp(re) <= 0.99999995) {
		tmp = im * (1.0 + expm1(re));
	} else if (exp(re) <= 1.000002) {
		tmp = sin(im);
	} else {
		tmp = im * exp(re);
	}
	return tmp;
}
public static double code(double re, double im) {
	double tmp;
	if (Math.exp(re) <= 0.99999995) {
		tmp = im * (1.0 + Math.expm1(re));
	} else if (Math.exp(re) <= 1.000002) {
		tmp = Math.sin(im);
	} else {
		tmp = im * Math.exp(re);
	}
	return tmp;
}
def code(re, im):
	tmp = 0
	if math.exp(re) <= 0.99999995:
		tmp = im * (1.0 + math.expm1(re))
	elif math.exp(re) <= 1.000002:
		tmp = math.sin(im)
	else:
		tmp = im * math.exp(re)
	return tmp
function code(re, im)
	tmp = 0.0
	if (exp(re) <= 0.99999995)
		tmp = Float64(im * Float64(1.0 + expm1(re)));
	elseif (exp(re) <= 1.000002)
		tmp = sin(im);
	else
		tmp = Float64(im * exp(re));
	end
	return tmp
end
code[re_, im_] := If[LessEqual[N[Exp[re], $MachinePrecision], 0.99999995], N[(im * N[(1.0 + N[(Exp[re] - 1), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], If[LessEqual[N[Exp[re], $MachinePrecision], 1.000002], N[Sin[im], $MachinePrecision], N[(im * N[Exp[re], $MachinePrecision]), $MachinePrecision]]]
\begin{array}{l}

\\
\begin{array}{l}
\mathbf{if}\;e^{re} \leq 0.99999995:\\
\;\;\;\;im \cdot \left(1 + \mathsf{expm1}\left(re\right)\right)\\

\mathbf{elif}\;e^{re} \leq 1.000002:\\
\;\;\;\;\sin im\\

\mathbf{else}:\\
\;\;\;\;im \cdot e^{re}\\


\end{array}
\end{array}
Derivation
  1. Split input into 3 regimes
  2. if (exp.f64 re) < 0.999999949999999971

    1. Initial program 100.0%

      \[e^{re} \cdot \sin im \]
    2. Add Preprocessing
    3. Taylor expanded in im around 0 98.1%

      \[\leadsto e^{re} \cdot \color{blue}{im} \]
    4. Step-by-step derivation
      1. log1p-expm1-u98.1%

        \[\leadsto e^{\color{blue}{\mathsf{log1p}\left(\mathsf{expm1}\left(re\right)\right)}} \cdot im \]
      2. log1p-undefine98.1%

        \[\leadsto e^{\color{blue}{\log \left(1 + \mathsf{expm1}\left(re\right)\right)}} \cdot im \]
      3. add-exp-log98.1%

        \[\leadsto \color{blue}{\left(1 + \mathsf{expm1}\left(re\right)\right)} \cdot im \]
    5. Applied egg-rr98.1%

      \[\leadsto \color{blue}{\left(1 + \mathsf{expm1}\left(re\right)\right)} \cdot im \]

    if 0.999999949999999971 < (exp.f64 re) < 1.00000200000000006

    1. Initial program 100.0%

      \[e^{re} \cdot \sin im \]
    2. Add Preprocessing
    3. Taylor expanded in re around 0 99.6%

      \[\leadsto \color{blue}{\sin im} \]

    if 1.00000200000000006 < (exp.f64 re)

    1. Initial program 100.0%

      \[e^{re} \cdot \sin im \]
    2. Add Preprocessing
    3. Taylor expanded in im around 0 76.8%

      \[\leadsto e^{re} \cdot \color{blue}{im} \]
  3. Recombined 3 regimes into one program.
  4. Final simplification93.2%

    \[\leadsto \begin{array}{l} \mathbf{if}\;e^{re} \leq 0.99999995:\\ \;\;\;\;im \cdot \left(1 + \mathsf{expm1}\left(re\right)\right)\\ \mathbf{elif}\;e^{re} \leq 1.000002:\\ \;\;\;\;\sin im\\ \mathbf{else}:\\ \;\;\;\;im \cdot e^{re}\\ \end{array} \]
  5. Add Preprocessing

Alternative 5: 100.0% accurate, 1.0× speedup?

\[\begin{array}{l} \\ \sin im \cdot e^{re} \end{array} \]
(FPCore (re im) :precision binary64 (* (sin im) (exp re)))
double code(double re, double im) {
	return sin(im) * exp(re);
}
real(8) function code(re, im)
    real(8), intent (in) :: re
    real(8), intent (in) :: im
    code = sin(im) * exp(re)
end function
public static double code(double re, double im) {
	return Math.sin(im) * Math.exp(re);
}
def code(re, im):
	return math.sin(im) * math.exp(re)
function code(re, im)
	return Float64(sin(im) * exp(re))
end
function tmp = code(re, im)
	tmp = sin(im) * exp(re);
end
code[re_, im_] := N[(N[Sin[im], $MachinePrecision] * N[Exp[re], $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
\sin im \cdot e^{re}
\end{array}
Derivation
  1. Initial program 100.0%

    \[e^{re} \cdot \sin im \]
  2. Add Preprocessing
  3. Final simplification100.0%

    \[\leadsto \sin im \cdot e^{re} \]
  4. Add Preprocessing

Alternative 6: 97.4% accurate, 1.6× speedup?

\[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;re \leq -0.0255 \lor \neg \left(re \leq 1.7\right) \land re \leq 1.05 \cdot 10^{+103}:\\ \;\;\;\;im \cdot \left(1 + \mathsf{expm1}\left(re\right)\right)\\ \mathbf{else}:\\ \;\;\;\;\sin im \cdot \left(1 + re \cdot \left(1 + re \cdot \left(0.5 + re \cdot 0.16666666666666666\right)\right)\right)\\ \end{array} \end{array} \]
(FPCore (re im)
 :precision binary64
 (if (or (<= re -0.0255) (and (not (<= re 1.7)) (<= re 1.05e+103)))
   (* im (+ 1.0 (expm1 re)))
   (*
    (sin im)
    (+ 1.0 (* re (+ 1.0 (* re (+ 0.5 (* re 0.16666666666666666)))))))))
double code(double re, double im) {
	double tmp;
	if ((re <= -0.0255) || (!(re <= 1.7) && (re <= 1.05e+103))) {
		tmp = im * (1.0 + expm1(re));
	} else {
		tmp = sin(im) * (1.0 + (re * (1.0 + (re * (0.5 + (re * 0.16666666666666666))))));
	}
	return tmp;
}
public static double code(double re, double im) {
	double tmp;
	if ((re <= -0.0255) || (!(re <= 1.7) && (re <= 1.05e+103))) {
		tmp = im * (1.0 + Math.expm1(re));
	} else {
		tmp = Math.sin(im) * (1.0 + (re * (1.0 + (re * (0.5 + (re * 0.16666666666666666))))));
	}
	return tmp;
}
def code(re, im):
	tmp = 0
	if (re <= -0.0255) or (not (re <= 1.7) and (re <= 1.05e+103)):
		tmp = im * (1.0 + math.expm1(re))
	else:
		tmp = math.sin(im) * (1.0 + (re * (1.0 + (re * (0.5 + (re * 0.16666666666666666))))))
	return tmp
function code(re, im)
	tmp = 0.0
	if ((re <= -0.0255) || (!(re <= 1.7) && (re <= 1.05e+103)))
		tmp = Float64(im * Float64(1.0 + expm1(re)));
	else
		tmp = Float64(sin(im) * Float64(1.0 + Float64(re * Float64(1.0 + Float64(re * Float64(0.5 + Float64(re * 0.16666666666666666)))))));
	end
	return tmp
end
code[re_, im_] := If[Or[LessEqual[re, -0.0255], And[N[Not[LessEqual[re, 1.7]], $MachinePrecision], LessEqual[re, 1.05e+103]]], N[(im * N[(1.0 + N[(Exp[re] - 1), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], N[(N[Sin[im], $MachinePrecision] * N[(1.0 + N[(re * N[(1.0 + N[(re * N[(0.5 + N[(re * 0.16666666666666666), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]]
\begin{array}{l}

\\
\begin{array}{l}
\mathbf{if}\;re \leq -0.0255 \lor \neg \left(re \leq 1.7\right) \land re \leq 1.05 \cdot 10^{+103}:\\
\;\;\;\;im \cdot \left(1 + \mathsf{expm1}\left(re\right)\right)\\

\mathbf{else}:\\
\;\;\;\;\sin im \cdot \left(1 + re \cdot \left(1 + re \cdot \left(0.5 + re \cdot 0.16666666666666666\right)\right)\right)\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if re < -0.0254999999999999984 or 1.69999999999999996 < re < 1.0500000000000001e103

    1. Initial program 100.0%

      \[e^{re} \cdot \sin im \]
    2. Add Preprocessing
    3. Taylor expanded in im around 0 91.6%

      \[\leadsto e^{re} \cdot \color{blue}{im} \]
    4. Step-by-step derivation
      1. log1p-expm1-u91.6%

        \[\leadsto e^{\color{blue}{\mathsf{log1p}\left(\mathsf{expm1}\left(re\right)\right)}} \cdot im \]
      2. log1p-undefine91.6%

        \[\leadsto e^{\color{blue}{\log \left(1 + \mathsf{expm1}\left(re\right)\right)}} \cdot im \]
      3. add-exp-log91.6%

        \[\leadsto \color{blue}{\left(1 + \mathsf{expm1}\left(re\right)\right)} \cdot im \]
    5. Applied egg-rr91.6%

      \[\leadsto \color{blue}{\left(1 + \mathsf{expm1}\left(re\right)\right)} \cdot im \]

    if -0.0254999999999999984 < re < 1.69999999999999996 or 1.0500000000000001e103 < re

    1. Initial program 100.0%

      \[e^{re} \cdot \sin im \]
    2. Add Preprocessing
    3. Taylor expanded in re around 0 99.4%

      \[\leadsto \color{blue}{\left(1 + re \cdot \left(1 + re \cdot \left(0.5 + 0.16666666666666666 \cdot re\right)\right)\right)} \cdot \sin im \]
    4. Step-by-step derivation
      1. *-commutative99.4%

        \[\leadsto \left(1 + re \cdot \left(1 + re \cdot \left(0.5 + \color{blue}{re \cdot 0.16666666666666666}\right)\right)\right) \cdot \sin im \]
    5. Simplified99.4%

      \[\leadsto \color{blue}{\left(1 + re \cdot \left(1 + re \cdot \left(0.5 + re \cdot 0.16666666666666666\right)\right)\right)} \cdot \sin im \]
  3. Recombined 2 regimes into one program.
  4. Final simplification97.2%

    \[\leadsto \begin{array}{l} \mathbf{if}\;re \leq -0.0255 \lor \neg \left(re \leq 1.7\right) \land re \leq 1.05 \cdot 10^{+103}:\\ \;\;\;\;im \cdot \left(1 + \mathsf{expm1}\left(re\right)\right)\\ \mathbf{else}:\\ \;\;\;\;\sin im \cdot \left(1 + re \cdot \left(1 + re \cdot \left(0.5 + re \cdot 0.16666666666666666\right)\right)\right)\\ \end{array} \]
  5. Add Preprocessing

Alternative 7: 96.4% accurate, 1.6× speedup?

\[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;re \leq -0.0154:\\ \;\;\;\;im \cdot \left(1 + \mathsf{expm1}\left(re\right)\right)\\ \mathbf{elif}\;re \leq 0.23 \lor \neg \left(re \leq 1.9 \cdot 10^{+154}\right):\\ \;\;\;\;\sin im \cdot \left(1 + re \cdot \left(1 + re \cdot 0.5\right)\right)\\ \mathbf{else}:\\ \;\;\;\;im \cdot e^{re}\\ \end{array} \end{array} \]
(FPCore (re im)
 :precision binary64
 (if (<= re -0.0154)
   (* im (+ 1.0 (expm1 re)))
   (if (or (<= re 0.23) (not (<= re 1.9e+154)))
     (* (sin im) (+ 1.0 (* re (+ 1.0 (* re 0.5)))))
     (* im (exp re)))))
double code(double re, double im) {
	double tmp;
	if (re <= -0.0154) {
		tmp = im * (1.0 + expm1(re));
	} else if ((re <= 0.23) || !(re <= 1.9e+154)) {
		tmp = sin(im) * (1.0 + (re * (1.0 + (re * 0.5))));
	} else {
		tmp = im * exp(re);
	}
	return tmp;
}
public static double code(double re, double im) {
	double tmp;
	if (re <= -0.0154) {
		tmp = im * (1.0 + Math.expm1(re));
	} else if ((re <= 0.23) || !(re <= 1.9e+154)) {
		tmp = Math.sin(im) * (1.0 + (re * (1.0 + (re * 0.5))));
	} else {
		tmp = im * Math.exp(re);
	}
	return tmp;
}
def code(re, im):
	tmp = 0
	if re <= -0.0154:
		tmp = im * (1.0 + math.expm1(re))
	elif (re <= 0.23) or not (re <= 1.9e+154):
		tmp = math.sin(im) * (1.0 + (re * (1.0 + (re * 0.5))))
	else:
		tmp = im * math.exp(re)
	return tmp
function code(re, im)
	tmp = 0.0
	if (re <= -0.0154)
		tmp = Float64(im * Float64(1.0 + expm1(re)));
	elseif ((re <= 0.23) || !(re <= 1.9e+154))
		tmp = Float64(sin(im) * Float64(1.0 + Float64(re * Float64(1.0 + Float64(re * 0.5)))));
	else
		tmp = Float64(im * exp(re));
	end
	return tmp
end
code[re_, im_] := If[LessEqual[re, -0.0154], N[(im * N[(1.0 + N[(Exp[re] - 1), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], If[Or[LessEqual[re, 0.23], N[Not[LessEqual[re, 1.9e+154]], $MachinePrecision]], N[(N[Sin[im], $MachinePrecision] * N[(1.0 + N[(re * N[(1.0 + N[(re * 0.5), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], N[(im * N[Exp[re], $MachinePrecision]), $MachinePrecision]]]
\begin{array}{l}

\\
\begin{array}{l}
\mathbf{if}\;re \leq -0.0154:\\
\;\;\;\;im \cdot \left(1 + \mathsf{expm1}\left(re\right)\right)\\

\mathbf{elif}\;re \leq 0.23 \lor \neg \left(re \leq 1.9 \cdot 10^{+154}\right):\\
\;\;\;\;\sin im \cdot \left(1 + re \cdot \left(1 + re \cdot 0.5\right)\right)\\

\mathbf{else}:\\
\;\;\;\;im \cdot e^{re}\\


\end{array}
\end{array}
Derivation
  1. Split input into 3 regimes
  2. if re < -0.0154

    1. Initial program 100.0%

      \[e^{re} \cdot \sin im \]
    2. Add Preprocessing
    3. Taylor expanded in im around 0 98.1%

      \[\leadsto e^{re} \cdot \color{blue}{im} \]
    4. Step-by-step derivation
      1. log1p-expm1-u98.1%

        \[\leadsto e^{\color{blue}{\mathsf{log1p}\left(\mathsf{expm1}\left(re\right)\right)}} \cdot im \]
      2. log1p-undefine98.1%

        \[\leadsto e^{\color{blue}{\log \left(1 + \mathsf{expm1}\left(re\right)\right)}} \cdot im \]
      3. add-exp-log98.1%

        \[\leadsto \color{blue}{\left(1 + \mathsf{expm1}\left(re\right)\right)} \cdot im \]
    5. Applied egg-rr98.1%

      \[\leadsto \color{blue}{\left(1 + \mathsf{expm1}\left(re\right)\right)} \cdot im \]

    if -0.0154 < re < 0.23000000000000001 or 1.8999999999999999e154 < re

    1. Initial program 100.0%

      \[e^{re} \cdot \sin im \]
    2. Add Preprocessing
    3. Taylor expanded in re around 0 99.2%

      \[\leadsto \color{blue}{\left(1 + re \cdot \left(1 + 0.5 \cdot re\right)\right)} \cdot \sin im \]
    4. Step-by-step derivation
      1. *-commutative99.2%

        \[\leadsto \left(1 + re \cdot \left(1 + \color{blue}{re \cdot 0.5}\right)\right) \cdot \sin im \]
    5. Simplified99.2%

      \[\leadsto \color{blue}{\left(1 + re \cdot \left(1 + re \cdot 0.5\right)\right)} \cdot \sin im \]

    if 0.23000000000000001 < re < 1.8999999999999999e154

    1. Initial program 100.0%

      \[e^{re} \cdot \sin im \]
    2. Add Preprocessing
    3. Taylor expanded in im around 0 79.4%

      \[\leadsto e^{re} \cdot \color{blue}{im} \]
  3. Recombined 3 regimes into one program.
  4. Final simplification96.3%

    \[\leadsto \begin{array}{l} \mathbf{if}\;re \leq -0.0154:\\ \;\;\;\;im \cdot \left(1 + \mathsf{expm1}\left(re\right)\right)\\ \mathbf{elif}\;re \leq 0.23 \lor \neg \left(re \leq 1.9 \cdot 10^{+154}\right):\\ \;\;\;\;\sin im \cdot \left(1 + re \cdot \left(1 + re \cdot 0.5\right)\right)\\ \mathbf{else}:\\ \;\;\;\;im \cdot e^{re}\\ \end{array} \]
  5. Add Preprocessing

Alternative 8: 93.0% accurate, 1.7× speedup?

\[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;re \leq -9.6 \cdot 10^{-8}:\\ \;\;\;\;im \cdot \left(1 + \mathsf{expm1}\left(re\right)\right)\\ \mathbf{elif}\;re \leq 2.4 \cdot 10^{-6}:\\ \;\;\;\;\sin im \cdot \frac{\left(1 + re\right) \cdot e}{e}\\ \mathbf{else}:\\ \;\;\;\;im \cdot e^{re}\\ \end{array} \end{array} \]
(FPCore (re im)
 :precision binary64
 (if (<= re -9.6e-8)
   (* im (+ 1.0 (expm1 re)))
   (if (<= re 2.4e-6) (* (sin im) (/ (* (+ 1.0 re) E) E)) (* im (exp re)))))
double code(double re, double im) {
	double tmp;
	if (re <= -9.6e-8) {
		tmp = im * (1.0 + expm1(re));
	} else if (re <= 2.4e-6) {
		tmp = sin(im) * (((1.0 + re) * ((double) M_E)) / ((double) M_E));
	} else {
		tmp = im * exp(re);
	}
	return tmp;
}
public static double code(double re, double im) {
	double tmp;
	if (re <= -9.6e-8) {
		tmp = im * (1.0 + Math.expm1(re));
	} else if (re <= 2.4e-6) {
		tmp = Math.sin(im) * (((1.0 + re) * Math.E) / Math.E);
	} else {
		tmp = im * Math.exp(re);
	}
	return tmp;
}
def code(re, im):
	tmp = 0
	if re <= -9.6e-8:
		tmp = im * (1.0 + math.expm1(re))
	elif re <= 2.4e-6:
		tmp = math.sin(im) * (((1.0 + re) * math.e) / math.e)
	else:
		tmp = im * math.exp(re)
	return tmp
function code(re, im)
	tmp = 0.0
	if (re <= -9.6e-8)
		tmp = Float64(im * Float64(1.0 + expm1(re)));
	elseif (re <= 2.4e-6)
		tmp = Float64(sin(im) * Float64(Float64(Float64(1.0 + re) * exp(1)) / exp(1)));
	else
		tmp = Float64(im * exp(re));
	end
	return tmp
end
code[re_, im_] := If[LessEqual[re, -9.6e-8], N[(im * N[(1.0 + N[(Exp[re] - 1), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], If[LessEqual[re, 2.4e-6], N[(N[Sin[im], $MachinePrecision] * N[(N[(N[(1.0 + re), $MachinePrecision] * E), $MachinePrecision] / E), $MachinePrecision]), $MachinePrecision], N[(im * N[Exp[re], $MachinePrecision]), $MachinePrecision]]]
\begin{array}{l}

\\
\begin{array}{l}
\mathbf{if}\;re \leq -9.6 \cdot 10^{-8}:\\
\;\;\;\;im \cdot \left(1 + \mathsf{expm1}\left(re\right)\right)\\

\mathbf{elif}\;re \leq 2.4 \cdot 10^{-6}:\\
\;\;\;\;\sin im \cdot \frac{\left(1 + re\right) \cdot e}{e}\\

\mathbf{else}:\\
\;\;\;\;im \cdot e^{re}\\


\end{array}
\end{array}
Derivation
  1. Split input into 3 regimes
  2. if re < -9.59999999999999994e-8

    1. Initial program 100.0%

      \[e^{re} \cdot \sin im \]
    2. Add Preprocessing
    3. Taylor expanded in im around 0 98.1%

      \[\leadsto e^{re} \cdot \color{blue}{im} \]
    4. Step-by-step derivation
      1. log1p-expm1-u98.1%

        \[\leadsto e^{\color{blue}{\mathsf{log1p}\left(\mathsf{expm1}\left(re\right)\right)}} \cdot im \]
      2. log1p-undefine98.1%

        \[\leadsto e^{\color{blue}{\log \left(1 + \mathsf{expm1}\left(re\right)\right)}} \cdot im \]
      3. add-exp-log98.1%

        \[\leadsto \color{blue}{\left(1 + \mathsf{expm1}\left(re\right)\right)} \cdot im \]
    5. Applied egg-rr98.1%

      \[\leadsto \color{blue}{\left(1 + \mathsf{expm1}\left(re\right)\right)} \cdot im \]

    if -9.59999999999999994e-8 < re < 2.3999999999999999e-6

    1. Initial program 100.0%

      \[e^{re} \cdot \sin im \]
    2. Add Preprocessing
    3. Step-by-step derivation
      1. expm1-log1p-u100.0%

        \[\leadsto e^{\color{blue}{\mathsf{expm1}\left(\mathsf{log1p}\left(re\right)\right)}} \cdot \sin im \]
      2. expm1-undefine100.0%

        \[\leadsto e^{\color{blue}{e^{\mathsf{log1p}\left(re\right)} - 1}} \cdot \sin im \]
      3. exp-diff100.0%

        \[\leadsto \color{blue}{\frac{e^{e^{\mathsf{log1p}\left(re\right)}}}{e^{1}}} \cdot \sin im \]
      4. log1p-undefine100.0%

        \[\leadsto \frac{e^{e^{\color{blue}{\log \left(1 + re\right)}}}}{e^{1}} \cdot \sin im \]
      5. rem-exp-log100.0%

        \[\leadsto \frac{e^{\color{blue}{1 + re}}}{e^{1}} \cdot \sin im \]
      6. exp-1-e100.0%

        \[\leadsto \frac{e^{1 + re}}{\color{blue}{e}} \cdot \sin im \]
    4. Applied egg-rr100.0%

      \[\leadsto \color{blue}{\frac{e^{1 + re}}{e}} \cdot \sin im \]
    5. Taylor expanded in re around 0 100.0%

      \[\leadsto \frac{\color{blue}{e^{1} + re \cdot e^{1}}}{e} \cdot \sin im \]
    6. Step-by-step derivation
      1. exp-1-e100.0%

        \[\leadsto \frac{\color{blue}{e} + re \cdot e^{1}}{e} \cdot \sin im \]
      2. exp-1-e100.0%

        \[\leadsto \frac{e + re \cdot \color{blue}{e}}{e} \cdot \sin im \]
      3. distribute-rgt1-in100.0%

        \[\leadsto \frac{\color{blue}{\left(re + 1\right) \cdot e}}{e} \cdot \sin im \]
      4. +-commutative100.0%

        \[\leadsto \frac{\color{blue}{\left(1 + re\right)} \cdot e}{e} \cdot \sin im \]
    7. Simplified100.0%

      \[\leadsto \frac{\color{blue}{\left(1 + re\right) \cdot e}}{e} \cdot \sin im \]

    if 2.3999999999999999e-6 < re

    1. Initial program 100.0%

      \[e^{re} \cdot \sin im \]
    2. Add Preprocessing
    3. Taylor expanded in im around 0 76.8%

      \[\leadsto e^{re} \cdot \color{blue}{im} \]
  3. Recombined 3 regimes into one program.
  4. Final simplification93.4%

    \[\leadsto \begin{array}{l} \mathbf{if}\;re \leq -9.6 \cdot 10^{-8}:\\ \;\;\;\;im \cdot \left(1 + \mathsf{expm1}\left(re\right)\right)\\ \mathbf{elif}\;re \leq 2.4 \cdot 10^{-6}:\\ \;\;\;\;\sin im \cdot \frac{\left(1 + re\right) \cdot e}{e}\\ \mathbf{else}:\\ \;\;\;\;im \cdot e^{re}\\ \end{array} \]
  5. Add Preprocessing

Alternative 9: 63.5% accurate, 1.9× speedup?

\[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;re \leq 8 \cdot 10^{-9}:\\ \;\;\;\;\sin im\\ \mathbf{else}:\\ \;\;\;\;im \cdot \left(1 + re \cdot \left(1 + re \cdot \left(0.5 + re \cdot 0.16666666666666666\right)\right)\right)\\ \end{array} \end{array} \]
(FPCore (re im)
 :precision binary64
 (if (<= re 8e-9)
   (sin im)
   (* im (+ 1.0 (* re (+ 1.0 (* re (+ 0.5 (* re 0.16666666666666666)))))))))
double code(double re, double im) {
	double tmp;
	if (re <= 8e-9) {
		tmp = sin(im);
	} else {
		tmp = im * (1.0 + (re * (1.0 + (re * (0.5 + (re * 0.16666666666666666))))));
	}
	return tmp;
}
real(8) function code(re, im)
    real(8), intent (in) :: re
    real(8), intent (in) :: im
    real(8) :: tmp
    if (re <= 8d-9) then
        tmp = sin(im)
    else
        tmp = im * (1.0d0 + (re * (1.0d0 + (re * (0.5d0 + (re * 0.16666666666666666d0))))))
    end if
    code = tmp
end function
public static double code(double re, double im) {
	double tmp;
	if (re <= 8e-9) {
		tmp = Math.sin(im);
	} else {
		tmp = im * (1.0 + (re * (1.0 + (re * (0.5 + (re * 0.16666666666666666))))));
	}
	return tmp;
}
def code(re, im):
	tmp = 0
	if re <= 8e-9:
		tmp = math.sin(im)
	else:
		tmp = im * (1.0 + (re * (1.0 + (re * (0.5 + (re * 0.16666666666666666))))))
	return tmp
function code(re, im)
	tmp = 0.0
	if (re <= 8e-9)
		tmp = sin(im);
	else
		tmp = Float64(im * Float64(1.0 + Float64(re * Float64(1.0 + Float64(re * Float64(0.5 + Float64(re * 0.16666666666666666)))))));
	end
	return tmp
end
function tmp_2 = code(re, im)
	tmp = 0.0;
	if (re <= 8e-9)
		tmp = sin(im);
	else
		tmp = im * (1.0 + (re * (1.0 + (re * (0.5 + (re * 0.16666666666666666))))));
	end
	tmp_2 = tmp;
end
code[re_, im_] := If[LessEqual[re, 8e-9], N[Sin[im], $MachinePrecision], N[(im * N[(1.0 + N[(re * N[(1.0 + N[(re * N[(0.5 + N[(re * 0.16666666666666666), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]]
\begin{array}{l}

\\
\begin{array}{l}
\mathbf{if}\;re \leq 8 \cdot 10^{-9}:\\
\;\;\;\;\sin im\\

\mathbf{else}:\\
\;\;\;\;im \cdot \left(1 + re \cdot \left(1 + re \cdot \left(0.5 + re \cdot 0.16666666666666666\right)\right)\right)\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if re < 8.0000000000000005e-9

    1. Initial program 100.0%

      \[e^{re} \cdot \sin im \]
    2. Add Preprocessing
    3. Taylor expanded in re around 0 73.8%

      \[\leadsto \color{blue}{\sin im} \]

    if 8.0000000000000005e-9 < re

    1. Initial program 100.0%

      \[e^{re} \cdot \sin im \]
    2. Add Preprocessing
    3. Taylor expanded in re around 0 69.6%

      \[\leadsto \color{blue}{\left(1 + re \cdot \left(1 + re \cdot \left(0.5 + 0.16666666666666666 \cdot re\right)\right)\right)} \cdot \sin im \]
    4. Step-by-step derivation
      1. *-commutative69.6%

        \[\leadsto \left(1 + re \cdot \left(1 + re \cdot \left(0.5 + \color{blue}{re \cdot 0.16666666666666666}\right)\right)\right) \cdot \sin im \]
    5. Simplified69.6%

      \[\leadsto \color{blue}{\left(1 + re \cdot \left(1 + re \cdot \left(0.5 + re \cdot 0.16666666666666666\right)\right)\right)} \cdot \sin im \]
    6. Taylor expanded in im around 0 63.1%

      \[\leadsto \left(1 + re \cdot \left(1 + re \cdot \left(0.5 + re \cdot 0.16666666666666666\right)\right)\right) \cdot \color{blue}{im} \]
  3. Recombined 2 regimes into one program.
  4. Final simplification70.9%

    \[\leadsto \begin{array}{l} \mathbf{if}\;re \leq 8 \cdot 10^{-9}:\\ \;\;\;\;\sin im\\ \mathbf{else}:\\ \;\;\;\;im \cdot \left(1 + re \cdot \left(1 + re \cdot \left(0.5 + re \cdot 0.16666666666666666\right)\right)\right)\\ \end{array} \]
  5. Add Preprocessing

Alternative 10: 39.0% accurate, 13.5× speedup?

\[\begin{array}{l} \\ im \cdot \left(1 + re \cdot \left(1 + re \cdot \left(0.5 + re \cdot 0.16666666666666666\right)\right)\right) \end{array} \]
(FPCore (re im)
 :precision binary64
 (* im (+ 1.0 (* re (+ 1.0 (* re (+ 0.5 (* re 0.16666666666666666))))))))
double code(double re, double im) {
	return im * (1.0 + (re * (1.0 + (re * (0.5 + (re * 0.16666666666666666))))));
}
real(8) function code(re, im)
    real(8), intent (in) :: re
    real(8), intent (in) :: im
    code = im * (1.0d0 + (re * (1.0d0 + (re * (0.5d0 + (re * 0.16666666666666666d0))))))
end function
public static double code(double re, double im) {
	return im * (1.0 + (re * (1.0 + (re * (0.5 + (re * 0.16666666666666666))))));
}
def code(re, im):
	return im * (1.0 + (re * (1.0 + (re * (0.5 + (re * 0.16666666666666666))))))
function code(re, im)
	return Float64(im * Float64(1.0 + Float64(re * Float64(1.0 + Float64(re * Float64(0.5 + Float64(re * 0.16666666666666666)))))))
end
function tmp = code(re, im)
	tmp = im * (1.0 + (re * (1.0 + (re * (0.5 + (re * 0.16666666666666666))))));
end
code[re_, im_] := N[(im * N[(1.0 + N[(re * N[(1.0 + N[(re * N[(0.5 + N[(re * 0.16666666666666666), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
im \cdot \left(1 + re \cdot \left(1 + re \cdot \left(0.5 + re \cdot 0.16666666666666666\right)\right)\right)
\end{array}
Derivation
  1. Initial program 100.0%

    \[e^{re} \cdot \sin im \]
  2. Add Preprocessing
  3. Taylor expanded in re around 0 72.6%

    \[\leadsto \color{blue}{\left(1 + re \cdot \left(1 + re \cdot \left(0.5 + 0.16666666666666666 \cdot re\right)\right)\right)} \cdot \sin im \]
  4. Step-by-step derivation
    1. *-commutative72.6%

      \[\leadsto \left(1 + re \cdot \left(1 + re \cdot \left(0.5 + \color{blue}{re \cdot 0.16666666666666666}\right)\right)\right) \cdot \sin im \]
  5. Simplified72.6%

    \[\leadsto \color{blue}{\left(1 + re \cdot \left(1 + re \cdot \left(0.5 + re \cdot 0.16666666666666666\right)\right)\right)} \cdot \sin im \]
  6. Taylor expanded in im around 0 43.0%

    \[\leadsto \left(1 + re \cdot \left(1 + re \cdot \left(0.5 + re \cdot 0.16666666666666666\right)\right)\right) \cdot \color{blue}{im} \]
  7. Final simplification43.0%

    \[\leadsto im \cdot \left(1 + re \cdot \left(1 + re \cdot \left(0.5 + re \cdot 0.16666666666666666\right)\right)\right) \]
  8. Add Preprocessing

Alternative 11: 36.3% accurate, 18.5× speedup?

\[\begin{array}{l} \\ im \cdot \left(1 + re \cdot \left(1 + re \cdot 0.5\right)\right) \end{array} \]
(FPCore (re im) :precision binary64 (* im (+ 1.0 (* re (+ 1.0 (* re 0.5))))))
double code(double re, double im) {
	return im * (1.0 + (re * (1.0 + (re * 0.5))));
}
real(8) function code(re, im)
    real(8), intent (in) :: re
    real(8), intent (in) :: im
    code = im * (1.0d0 + (re * (1.0d0 + (re * 0.5d0))))
end function
public static double code(double re, double im) {
	return im * (1.0 + (re * (1.0 + (re * 0.5))));
}
def code(re, im):
	return im * (1.0 + (re * (1.0 + (re * 0.5))))
function code(re, im)
	return Float64(im * Float64(1.0 + Float64(re * Float64(1.0 + Float64(re * 0.5)))))
end
function tmp = code(re, im)
	tmp = im * (1.0 + (re * (1.0 + (re * 0.5))));
end
code[re_, im_] := N[(im * N[(1.0 + N[(re * N[(1.0 + N[(re * 0.5), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
im \cdot \left(1 + re \cdot \left(1 + re \cdot 0.5\right)\right)
\end{array}
Derivation
  1. Initial program 100.0%

    \[e^{re} \cdot \sin im \]
  2. Add Preprocessing
  3. Taylor expanded in im around 0 65.5%

    \[\leadsto e^{re} \cdot \color{blue}{im} \]
  4. Taylor expanded in re around 0 38.5%

    \[\leadsto \color{blue}{\left(1 + re \cdot \left(1 + 0.5 \cdot re\right)\right)} \cdot im \]
  5. Step-by-step derivation
    1. *-commutative67.6%

      \[\leadsto \left(1 + re \cdot \left(1 + \color{blue}{re \cdot 0.5}\right)\right) \cdot \sin im \]
  6. Simplified38.5%

    \[\leadsto \color{blue}{\left(1 + re \cdot \left(1 + re \cdot 0.5\right)\right)} \cdot im \]
  7. Final simplification38.5%

    \[\leadsto im \cdot \left(1 + re \cdot \left(1 + re \cdot 0.5\right)\right) \]
  8. Add Preprocessing

Alternative 12: 27.5% accurate, 25.3× speedup?

\[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;im \leq 1.36 \cdot 10^{+35}:\\ \;\;\;\;im\\ \mathbf{else}:\\ \;\;\;\;re \cdot im\\ \end{array} \end{array} \]
(FPCore (re im) :precision binary64 (if (<= im 1.36e+35) im (* re im)))
double code(double re, double im) {
	double tmp;
	if (im <= 1.36e+35) {
		tmp = im;
	} else {
		tmp = re * im;
	}
	return tmp;
}
real(8) function code(re, im)
    real(8), intent (in) :: re
    real(8), intent (in) :: im
    real(8) :: tmp
    if (im <= 1.36d+35) then
        tmp = im
    else
        tmp = re * im
    end if
    code = tmp
end function
public static double code(double re, double im) {
	double tmp;
	if (im <= 1.36e+35) {
		tmp = im;
	} else {
		tmp = re * im;
	}
	return tmp;
}
def code(re, im):
	tmp = 0
	if im <= 1.36e+35:
		tmp = im
	else:
		tmp = re * im
	return tmp
function code(re, im)
	tmp = 0.0
	if (im <= 1.36e+35)
		tmp = im;
	else
		tmp = Float64(re * im);
	end
	return tmp
end
function tmp_2 = code(re, im)
	tmp = 0.0;
	if (im <= 1.36e+35)
		tmp = im;
	else
		tmp = re * im;
	end
	tmp_2 = tmp;
end
code[re_, im_] := If[LessEqual[im, 1.36e+35], im, N[(re * im), $MachinePrecision]]
\begin{array}{l}

\\
\begin{array}{l}
\mathbf{if}\;im \leq 1.36 \cdot 10^{+35}:\\
\;\;\;\;im\\

\mathbf{else}:\\
\;\;\;\;re \cdot im\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if im < 1.36e35

    1. Initial program 100.0%

      \[e^{re} \cdot \sin im \]
    2. Add Preprocessing
    3. Taylor expanded in re around 0 53.0%

      \[\leadsto \color{blue}{\sin im} \]
    4. Taylor expanded in im around 0 35.4%

      \[\leadsto \color{blue}{im} \]

    if 1.36e35 < im

    1. Initial program 100.0%

      \[e^{re} \cdot \sin im \]
    2. Add Preprocessing
    3. Taylor expanded in re around 0 62.8%

      \[\leadsto \color{blue}{\sin im + re \cdot \sin im} \]
    4. Step-by-step derivation
      1. distribute-rgt1-in62.8%

        \[\leadsto \color{blue}{\left(re + 1\right) \cdot \sin im} \]
    5. Simplified62.8%

      \[\leadsto \color{blue}{\left(re + 1\right) \cdot \sin im} \]
    6. Taylor expanded in im around 0 9.8%

      \[\leadsto \left(re + 1\right) \cdot \color{blue}{im} \]
    7. Taylor expanded in re around inf 11.4%

      \[\leadsto \color{blue}{im \cdot re} \]
    8. Step-by-step derivation
      1. *-commutative11.4%

        \[\leadsto \color{blue}{re \cdot im} \]
    9. Simplified11.4%

      \[\leadsto \color{blue}{re \cdot im} \]
  3. Recombined 2 regimes into one program.
  4. Add Preprocessing

Alternative 13: 28.8% accurate, 29.0× speedup?

\[\begin{array}{l} \\ im \cdot \left(-1 + \left(re + 2\right)\right) \end{array} \]
(FPCore (re im) :precision binary64 (* im (+ -1.0 (+ re 2.0))))
double code(double re, double im) {
	return im * (-1.0 + (re + 2.0));
}
real(8) function code(re, im)
    real(8), intent (in) :: re
    real(8), intent (in) :: im
    code = im * ((-1.0d0) + (re + 2.0d0))
end function
public static double code(double re, double im) {
	return im * (-1.0 + (re + 2.0));
}
def code(re, im):
	return im * (-1.0 + (re + 2.0))
function code(re, im)
	return Float64(im * Float64(-1.0 + Float64(re + 2.0)))
end
function tmp = code(re, im)
	tmp = im * (-1.0 + (re + 2.0));
end
code[re_, im_] := N[(im * N[(-1.0 + N[(re + 2.0), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
im \cdot \left(-1 + \left(re + 2\right)\right)
\end{array}
Derivation
  1. Initial program 100.0%

    \[e^{re} \cdot \sin im \]
  2. Add Preprocessing
  3. Taylor expanded in re around 0 55.9%

    \[\leadsto \color{blue}{\sin im + re \cdot \sin im} \]
  4. Step-by-step derivation
    1. distribute-rgt1-in55.9%

      \[\leadsto \color{blue}{\left(re + 1\right) \cdot \sin im} \]
  5. Simplified55.9%

    \[\leadsto \color{blue}{\left(re + 1\right) \cdot \sin im} \]
  6. Taylor expanded in im around 0 30.9%

    \[\leadsto \left(re + 1\right) \cdot \color{blue}{im} \]
  7. Step-by-step derivation
    1. expm1-log1p-u30.4%

      \[\leadsto \color{blue}{\mathsf{expm1}\left(\mathsf{log1p}\left(re + 1\right)\right)} \cdot im \]
    2. expm1-undefine30.4%

      \[\leadsto \color{blue}{\left(e^{\mathsf{log1p}\left(re + 1\right)} - 1\right)} \cdot im \]
  8. Applied egg-rr30.4%

    \[\leadsto \color{blue}{\left(e^{\mathsf{log1p}\left(re + 1\right)} - 1\right)} \cdot im \]
  9. Step-by-step derivation
    1. sub-neg30.4%

      \[\leadsto \color{blue}{\left(e^{\mathsf{log1p}\left(re + 1\right)} + \left(-1\right)\right)} \cdot im \]
    2. metadata-eval30.4%

      \[\leadsto \left(e^{\mathsf{log1p}\left(re + 1\right)} + \color{blue}{-1}\right) \cdot im \]
    3. +-commutative30.4%

      \[\leadsto \color{blue}{\left(-1 + e^{\mathsf{log1p}\left(re + 1\right)}\right)} \cdot im \]
    4. log1p-undefine30.4%

      \[\leadsto \left(-1 + e^{\color{blue}{\log \left(1 + \left(re + 1\right)\right)}}\right) \cdot im \]
    5. rem-exp-log30.9%

      \[\leadsto \left(-1 + \color{blue}{\left(1 + \left(re + 1\right)\right)}\right) \cdot im \]
    6. +-commutative30.9%

      \[\leadsto \left(-1 + \left(1 + \color{blue}{\left(1 + re\right)}\right)\right) \cdot im \]
    7. associate-+r+30.9%

      \[\leadsto \left(-1 + \color{blue}{\left(\left(1 + 1\right) + re\right)}\right) \cdot im \]
    8. metadata-eval30.9%

      \[\leadsto \left(-1 + \left(\color{blue}{2} + re\right)\right) \cdot im \]
  10. Simplified30.9%

    \[\leadsto \color{blue}{\left(-1 + \left(2 + re\right)\right)} \cdot im \]
  11. Final simplification30.9%

    \[\leadsto im \cdot \left(-1 + \left(re + 2\right)\right) \]
  12. Add Preprocessing

Alternative 14: 28.8% accurate, 40.6× speedup?

\[\begin{array}{l} \\ \left(1 + re\right) \cdot im \end{array} \]
(FPCore (re im) :precision binary64 (* (+ 1.0 re) im))
double code(double re, double im) {
	return (1.0 + re) * im;
}
real(8) function code(re, im)
    real(8), intent (in) :: re
    real(8), intent (in) :: im
    code = (1.0d0 + re) * im
end function
public static double code(double re, double im) {
	return (1.0 + re) * im;
}
def code(re, im):
	return (1.0 + re) * im
function code(re, im)
	return Float64(Float64(1.0 + re) * im)
end
function tmp = code(re, im)
	tmp = (1.0 + re) * im;
end
code[re_, im_] := N[(N[(1.0 + re), $MachinePrecision] * im), $MachinePrecision]
\begin{array}{l}

\\
\left(1 + re\right) \cdot im
\end{array}
Derivation
  1. Initial program 100.0%

    \[e^{re} \cdot \sin im \]
  2. Add Preprocessing
  3. Taylor expanded in re around 0 55.9%

    \[\leadsto \color{blue}{\sin im + re \cdot \sin im} \]
  4. Step-by-step derivation
    1. distribute-rgt1-in55.9%

      \[\leadsto \color{blue}{\left(re + 1\right) \cdot \sin im} \]
  5. Simplified55.9%

    \[\leadsto \color{blue}{\left(re + 1\right) \cdot \sin im} \]
  6. Taylor expanded in im around 0 30.9%

    \[\leadsto \left(re + 1\right) \cdot \color{blue}{im} \]
  7. Final simplification30.9%

    \[\leadsto \left(1 + re\right) \cdot im \]
  8. Add Preprocessing

Alternative 15: 25.8% accurate, 203.0× speedup?

\[\begin{array}{l} \\ im \end{array} \]
(FPCore (re im) :precision binary64 im)
double code(double re, double im) {
	return im;
}
real(8) function code(re, im)
    real(8), intent (in) :: re
    real(8), intent (in) :: im
    code = im
end function
public static double code(double re, double im) {
	return im;
}
def code(re, im):
	return im
function code(re, im)
	return im
end
function tmp = code(re, im)
	tmp = im;
end
code[re_, im_] := im
\begin{array}{l}

\\
im
\end{array}
Derivation
  1. Initial program 100.0%

    \[e^{re} \cdot \sin im \]
  2. Add Preprocessing
  3. Taylor expanded in re around 0 55.2%

    \[\leadsto \color{blue}{\sin im} \]
  4. Taylor expanded in im around 0 27.3%

    \[\leadsto \color{blue}{im} \]
  5. Add Preprocessing

Reproduce

?
herbie shell --seed 2024176 
(FPCore (re im)
  :name "math.exp on complex, imaginary part"
  :precision binary64
  (* (exp re) (sin im)))