ABCF->ab-angle b

Percentage Accurate: 19.3% → 56.9%
Time: 26.1s
Alternatives: 18
Speedup: 5.9×

Specification

?
\[\begin{array}{l} \\ \begin{array}{l} t_0 := {B}^{2} - \left(4 \cdot A\right) \cdot C\\ \frac{-\sqrt{\left(2 \cdot \left(t\_0 \cdot F\right)\right) \cdot \left(\left(A + C\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{t\_0} \end{array} \end{array} \]
(FPCore (A B C F)
 :precision binary64
 (let* ((t_0 (- (pow B 2.0) (* (* 4.0 A) C))))
   (/
    (-
     (sqrt
      (*
       (* 2.0 (* t_0 F))
       (- (+ A C) (sqrt (+ (pow (- A C) 2.0) (pow B 2.0)))))))
    t_0)))
double code(double A, double B, double C, double F) {
	double t_0 = pow(B, 2.0) - ((4.0 * A) * C);
	return -sqrt(((2.0 * (t_0 * F)) * ((A + C) - sqrt((pow((A - C), 2.0) + pow(B, 2.0)))))) / t_0;
}
real(8) function code(a, b, c, f)
    real(8), intent (in) :: a
    real(8), intent (in) :: b
    real(8), intent (in) :: c
    real(8), intent (in) :: f
    real(8) :: t_0
    t_0 = (b ** 2.0d0) - ((4.0d0 * a) * c)
    code = -sqrt(((2.0d0 * (t_0 * f)) * ((a + c) - sqrt((((a - c) ** 2.0d0) + (b ** 2.0d0)))))) / t_0
end function
public static double code(double A, double B, double C, double F) {
	double t_0 = Math.pow(B, 2.0) - ((4.0 * A) * C);
	return -Math.sqrt(((2.0 * (t_0 * F)) * ((A + C) - Math.sqrt((Math.pow((A - C), 2.0) + Math.pow(B, 2.0)))))) / t_0;
}
def code(A, B, C, F):
	t_0 = math.pow(B, 2.0) - ((4.0 * A) * C)
	return -math.sqrt(((2.0 * (t_0 * F)) * ((A + C) - math.sqrt((math.pow((A - C), 2.0) + math.pow(B, 2.0)))))) / t_0
function code(A, B, C, F)
	t_0 = Float64((B ^ 2.0) - Float64(Float64(4.0 * A) * C))
	return Float64(Float64(-sqrt(Float64(Float64(2.0 * Float64(t_0 * F)) * Float64(Float64(A + C) - sqrt(Float64((Float64(A - C) ^ 2.0) + (B ^ 2.0))))))) / t_0)
end
function tmp = code(A, B, C, F)
	t_0 = (B ^ 2.0) - ((4.0 * A) * C);
	tmp = -sqrt(((2.0 * (t_0 * F)) * ((A + C) - sqrt((((A - C) ^ 2.0) + (B ^ 2.0)))))) / t_0;
end
code[A_, B_, C_, F_] := Block[{t$95$0 = N[(N[Power[B, 2.0], $MachinePrecision] - N[(N[(4.0 * A), $MachinePrecision] * C), $MachinePrecision]), $MachinePrecision]}, N[((-N[Sqrt[N[(N[(2.0 * N[(t$95$0 * F), $MachinePrecision]), $MachinePrecision] * N[(N[(A + C), $MachinePrecision] - N[Sqrt[N[(N[Power[N[(A - C), $MachinePrecision], 2.0], $MachinePrecision] + N[Power[B, 2.0], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]) / t$95$0), $MachinePrecision]]
\begin{array}{l}

\\
\begin{array}{l}
t_0 := {B}^{2} - \left(4 \cdot A\right) \cdot C\\
\frac{-\sqrt{\left(2 \cdot \left(t\_0 \cdot F\right)\right) \cdot \left(\left(A + C\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{t\_0}
\end{array}
\end{array}

Sampling outcomes in binary64 precision:

Local Percentage Accuracy vs ?

The average percentage accuracy by input value. Horizontal axis shows value of an input variable; the variable is choosen in the title. Vertical axis is accuracy; higher is better. Red represent the original program, while blue represents Herbie's suggestion. These can be toggled with buttons below the plot. The line is an average while dots represent individual samples.

Accuracy vs Speed?

Herbie found 18 alternatives:

AlternativeAccuracySpeedup
The accuracy (vertical axis) and speed (horizontal axis) of each alternatives. Up and to the right is better. The red square shows the initial program, and each blue circle shows an alternative.The line shows the best available speed-accuracy tradeoffs.

Initial Program: 19.3% accurate, 1.0× speedup?

\[\begin{array}{l} \\ \begin{array}{l} t_0 := {B}^{2} - \left(4 \cdot A\right) \cdot C\\ \frac{-\sqrt{\left(2 \cdot \left(t\_0 \cdot F\right)\right) \cdot \left(\left(A + C\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{t\_0} \end{array} \end{array} \]
(FPCore (A B C F)
 :precision binary64
 (let* ((t_0 (- (pow B 2.0) (* (* 4.0 A) C))))
   (/
    (-
     (sqrt
      (*
       (* 2.0 (* t_0 F))
       (- (+ A C) (sqrt (+ (pow (- A C) 2.0) (pow B 2.0)))))))
    t_0)))
double code(double A, double B, double C, double F) {
	double t_0 = pow(B, 2.0) - ((4.0 * A) * C);
	return -sqrt(((2.0 * (t_0 * F)) * ((A + C) - sqrt((pow((A - C), 2.0) + pow(B, 2.0)))))) / t_0;
}
real(8) function code(a, b, c, f)
    real(8), intent (in) :: a
    real(8), intent (in) :: b
    real(8), intent (in) :: c
    real(8), intent (in) :: f
    real(8) :: t_0
    t_0 = (b ** 2.0d0) - ((4.0d0 * a) * c)
    code = -sqrt(((2.0d0 * (t_0 * f)) * ((a + c) - sqrt((((a - c) ** 2.0d0) + (b ** 2.0d0)))))) / t_0
end function
public static double code(double A, double B, double C, double F) {
	double t_0 = Math.pow(B, 2.0) - ((4.0 * A) * C);
	return -Math.sqrt(((2.0 * (t_0 * F)) * ((A + C) - Math.sqrt((Math.pow((A - C), 2.0) + Math.pow(B, 2.0)))))) / t_0;
}
def code(A, B, C, F):
	t_0 = math.pow(B, 2.0) - ((4.0 * A) * C)
	return -math.sqrt(((2.0 * (t_0 * F)) * ((A + C) - math.sqrt((math.pow((A - C), 2.0) + math.pow(B, 2.0)))))) / t_0
function code(A, B, C, F)
	t_0 = Float64((B ^ 2.0) - Float64(Float64(4.0 * A) * C))
	return Float64(Float64(-sqrt(Float64(Float64(2.0 * Float64(t_0 * F)) * Float64(Float64(A + C) - sqrt(Float64((Float64(A - C) ^ 2.0) + (B ^ 2.0))))))) / t_0)
end
function tmp = code(A, B, C, F)
	t_0 = (B ^ 2.0) - ((4.0 * A) * C);
	tmp = -sqrt(((2.0 * (t_0 * F)) * ((A + C) - sqrt((((A - C) ^ 2.0) + (B ^ 2.0)))))) / t_0;
end
code[A_, B_, C_, F_] := Block[{t$95$0 = N[(N[Power[B, 2.0], $MachinePrecision] - N[(N[(4.0 * A), $MachinePrecision] * C), $MachinePrecision]), $MachinePrecision]}, N[((-N[Sqrt[N[(N[(2.0 * N[(t$95$0 * F), $MachinePrecision]), $MachinePrecision] * N[(N[(A + C), $MachinePrecision] - N[Sqrt[N[(N[Power[N[(A - C), $MachinePrecision], 2.0], $MachinePrecision] + N[Power[B, 2.0], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]) / t$95$0), $MachinePrecision]]
\begin{array}{l}

\\
\begin{array}{l}
t_0 := {B}^{2} - \left(4 \cdot A\right) \cdot C\\
\frac{-\sqrt{\left(2 \cdot \left(t\_0 \cdot F\right)\right) \cdot \left(\left(A + C\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{t\_0}
\end{array}
\end{array}

Alternative 1: 56.9% accurate, 0.3× speedup?

\[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} t_0 := \mathsf{fma}\left(B\_m, B\_m, A \cdot \left(C \cdot -4\right)\right)\\ t_1 := \sqrt[3]{\frac{-1}{F}}\\ t_2 := \left(4 \cdot A\right) \cdot C\\ t_3 := \frac{\sqrt{\left(2 \cdot \left(\left({B\_m}^{2} - t\_2\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) - \sqrt{{B\_m}^{2} + {\left(A - C\right)}^{2}}\right)}}{t\_2 - {B\_m}^{2}}\\ t_4 := \mathsf{fma}\left(C, A \cdot -4, {B\_m}^{2}\right)\\ \mathbf{if}\;t\_3 \leq -2 \cdot 10^{-204}:\\ \;\;\;\;\frac{\sqrt{F \cdot \left(A + \left(C - \mathsf{hypot}\left(B\_m, A - C\right)\right)\right)} \cdot \sqrt{2 \cdot t\_4}}{-t\_4}\\ \mathbf{elif}\;t\_3 \leq \infty:\\ \;\;\;\;\frac{\sqrt{\left(F \cdot t\_0\right) \cdot \left(2 \cdot \left(A + \left(A + -0.5 \cdot \frac{{B\_m}^{2}}{C}\right)\right)\right)}}{-t\_0}\\ \mathbf{else}:\\ \;\;\;\;e^{\left(\log \left(\mathsf{hypot}\left(B\_m, A\right) - A\right) - \left(\log \left({t\_1}^{2}\right) + \log t\_1\right)\right) \cdot 0.5} \cdot \frac{\sqrt{2}}{-B\_m}\\ \end{array} \end{array} \]
B_m = (fabs.f64 B)
NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
(FPCore (A B_m C F)
 :precision binary64
 (let* ((t_0 (fma B_m B_m (* A (* C -4.0))))
        (t_1 (cbrt (/ -1.0 F)))
        (t_2 (* (* 4.0 A) C))
        (t_3
         (/
          (sqrt
           (*
            (* 2.0 (* (- (pow B_m 2.0) t_2) F))
            (- (+ A C) (sqrt (+ (pow B_m 2.0) (pow (- A C) 2.0))))))
          (- t_2 (pow B_m 2.0))))
        (t_4 (fma C (* A -4.0) (pow B_m 2.0))))
   (if (<= t_3 -2e-204)
     (/
      (* (sqrt (* F (+ A (- C (hypot B_m (- A C)))))) (sqrt (* 2.0 t_4)))
      (- t_4))
     (if (<= t_3 INFINITY)
       (/
        (sqrt (* (* F t_0) (* 2.0 (+ A (+ A (* -0.5 (/ (pow B_m 2.0) C)))))))
        (- t_0))
       (*
        (exp
         (*
          (- (log (- (hypot B_m A) A)) (+ (log (pow t_1 2.0)) (log t_1)))
          0.5))
        (/ (sqrt 2.0) (- B_m)))))))
B_m = fabs(B);
assert(A < B_m && B_m < C && C < F);
double code(double A, double B_m, double C, double F) {
	double t_0 = fma(B_m, B_m, (A * (C * -4.0)));
	double t_1 = cbrt((-1.0 / F));
	double t_2 = (4.0 * A) * C;
	double t_3 = sqrt(((2.0 * ((pow(B_m, 2.0) - t_2) * F)) * ((A + C) - sqrt((pow(B_m, 2.0) + pow((A - C), 2.0)))))) / (t_2 - pow(B_m, 2.0));
	double t_4 = fma(C, (A * -4.0), pow(B_m, 2.0));
	double tmp;
	if (t_3 <= -2e-204) {
		tmp = (sqrt((F * (A + (C - hypot(B_m, (A - C)))))) * sqrt((2.0 * t_4))) / -t_4;
	} else if (t_3 <= ((double) INFINITY)) {
		tmp = sqrt(((F * t_0) * (2.0 * (A + (A + (-0.5 * (pow(B_m, 2.0) / C))))))) / -t_0;
	} else {
		tmp = exp(((log((hypot(B_m, A) - A)) - (log(pow(t_1, 2.0)) + log(t_1))) * 0.5)) * (sqrt(2.0) / -B_m);
	}
	return tmp;
}
B_m = abs(B)
A, B_m, C, F = sort([A, B_m, C, F])
function code(A, B_m, C, F)
	t_0 = fma(B_m, B_m, Float64(A * Float64(C * -4.0)))
	t_1 = cbrt(Float64(-1.0 / F))
	t_2 = Float64(Float64(4.0 * A) * C)
	t_3 = Float64(sqrt(Float64(Float64(2.0 * Float64(Float64((B_m ^ 2.0) - t_2) * F)) * Float64(Float64(A + C) - sqrt(Float64((B_m ^ 2.0) + (Float64(A - C) ^ 2.0)))))) / Float64(t_2 - (B_m ^ 2.0)))
	t_4 = fma(C, Float64(A * -4.0), (B_m ^ 2.0))
	tmp = 0.0
	if (t_3 <= -2e-204)
		tmp = Float64(Float64(sqrt(Float64(F * Float64(A + Float64(C - hypot(B_m, Float64(A - C)))))) * sqrt(Float64(2.0 * t_4))) / Float64(-t_4));
	elseif (t_3 <= Inf)
		tmp = Float64(sqrt(Float64(Float64(F * t_0) * Float64(2.0 * Float64(A + Float64(A + Float64(-0.5 * Float64((B_m ^ 2.0) / C))))))) / Float64(-t_0));
	else
		tmp = Float64(exp(Float64(Float64(log(Float64(hypot(B_m, A) - A)) - Float64(log((t_1 ^ 2.0)) + log(t_1))) * 0.5)) * Float64(sqrt(2.0) / Float64(-B_m)));
	end
	return tmp
end
B_m = N[Abs[B], $MachinePrecision]
NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
code[A_, B$95$m_, C_, F_] := Block[{t$95$0 = N[(B$95$m * B$95$m + N[(A * N[(C * -4.0), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$1 = N[Power[N[(-1.0 / F), $MachinePrecision], 1/3], $MachinePrecision]}, Block[{t$95$2 = N[(N[(4.0 * A), $MachinePrecision] * C), $MachinePrecision]}, Block[{t$95$3 = N[(N[Sqrt[N[(N[(2.0 * N[(N[(N[Power[B$95$m, 2.0], $MachinePrecision] - t$95$2), $MachinePrecision] * F), $MachinePrecision]), $MachinePrecision] * N[(N[(A + C), $MachinePrecision] - N[Sqrt[N[(N[Power[B$95$m, 2.0], $MachinePrecision] + N[Power[N[(A - C), $MachinePrecision], 2.0], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / N[(t$95$2 - N[Power[B$95$m, 2.0], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$4 = N[(C * N[(A * -4.0), $MachinePrecision] + N[Power[B$95$m, 2.0], $MachinePrecision]), $MachinePrecision]}, If[LessEqual[t$95$3, -2e-204], N[(N[(N[Sqrt[N[(F * N[(A + N[(C - N[Sqrt[B$95$m ^ 2 + N[(A - C), $MachinePrecision] ^ 2], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] * N[Sqrt[N[(2.0 * t$95$4), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] / (-t$95$4)), $MachinePrecision], If[LessEqual[t$95$3, Infinity], N[(N[Sqrt[N[(N[(F * t$95$0), $MachinePrecision] * N[(2.0 * N[(A + N[(A + N[(-0.5 * N[(N[Power[B$95$m, 2.0], $MachinePrecision] / C), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / (-t$95$0)), $MachinePrecision], N[(N[Exp[N[(N[(N[Log[N[(N[Sqrt[B$95$m ^ 2 + A ^ 2], $MachinePrecision] - A), $MachinePrecision]], $MachinePrecision] - N[(N[Log[N[Power[t$95$1, 2.0], $MachinePrecision]], $MachinePrecision] + N[Log[t$95$1], $MachinePrecision]), $MachinePrecision]), $MachinePrecision] * 0.5), $MachinePrecision]], $MachinePrecision] * N[(N[Sqrt[2.0], $MachinePrecision] / (-B$95$m)), $MachinePrecision]), $MachinePrecision]]]]]]]]
\begin{array}{l}
B_m = \left|B\right|
\\
[A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
\\
\begin{array}{l}
t_0 := \mathsf{fma}\left(B\_m, B\_m, A \cdot \left(C \cdot -4\right)\right)\\
t_1 := \sqrt[3]{\frac{-1}{F}}\\
t_2 := \left(4 \cdot A\right) \cdot C\\
t_3 := \frac{\sqrt{\left(2 \cdot \left(\left({B\_m}^{2} - t\_2\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) - \sqrt{{B\_m}^{2} + {\left(A - C\right)}^{2}}\right)}}{t\_2 - {B\_m}^{2}}\\
t_4 := \mathsf{fma}\left(C, A \cdot -4, {B\_m}^{2}\right)\\
\mathbf{if}\;t\_3 \leq -2 \cdot 10^{-204}:\\
\;\;\;\;\frac{\sqrt{F \cdot \left(A + \left(C - \mathsf{hypot}\left(B\_m, A - C\right)\right)\right)} \cdot \sqrt{2 \cdot t\_4}}{-t\_4}\\

\mathbf{elif}\;t\_3 \leq \infty:\\
\;\;\;\;\frac{\sqrt{\left(F \cdot t\_0\right) \cdot \left(2 \cdot \left(A + \left(A + -0.5 \cdot \frac{{B\_m}^{2}}{C}\right)\right)\right)}}{-t\_0}\\

\mathbf{else}:\\
\;\;\;\;e^{\left(\log \left(\mathsf{hypot}\left(B\_m, A\right) - A\right) - \left(\log \left({t\_1}^{2}\right) + \log t\_1\right)\right) \cdot 0.5} \cdot \frac{\sqrt{2}}{-B\_m}\\


\end{array}
\end{array}
Derivation
  1. Split input into 3 regimes
  2. if (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (-.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C))) < -2e-204

    1. Initial program 51.1%

      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    2. Simplified46.8%

      \[\leadsto \color{blue}{\frac{\sqrt{F \cdot \left(\left(A + \left(C - \mathsf{hypot}\left(B, A - C\right)\right)\right) \cdot \left(2 \cdot \mathsf{fma}\left(C, A \cdot -4, {B}^{2}\right)\right)\right)}}{-\mathsf{fma}\left(C, A \cdot -4, {B}^{2}\right)}} \]
    3. Add Preprocessing
    4. Step-by-step derivation
      1. pow1/246.8%

        \[\leadsto \frac{\color{blue}{{\left(F \cdot \left(\left(A + \left(C - \mathsf{hypot}\left(B, A - C\right)\right)\right) \cdot \left(2 \cdot \mathsf{fma}\left(C, A \cdot -4, {B}^{2}\right)\right)\right)\right)}^{0.5}}}{-\mathsf{fma}\left(C, A \cdot -4, {B}^{2}\right)} \]
      2. associate-*r*62.0%

        \[\leadsto \frac{{\color{blue}{\left(\left(F \cdot \left(A + \left(C - \mathsf{hypot}\left(B, A - C\right)\right)\right)\right) \cdot \left(2 \cdot \mathsf{fma}\left(C, A \cdot -4, {B}^{2}\right)\right)\right)}}^{0.5}}{-\mathsf{fma}\left(C, A \cdot -4, {B}^{2}\right)} \]
      3. unpow-prod-down77.2%

        \[\leadsto \frac{\color{blue}{{\left(F \cdot \left(A + \left(C - \mathsf{hypot}\left(B, A - C\right)\right)\right)\right)}^{0.5} \cdot {\left(2 \cdot \mathsf{fma}\left(C, A \cdot -4, {B}^{2}\right)\right)}^{0.5}}}{-\mathsf{fma}\left(C, A \cdot -4, {B}^{2}\right)} \]
      4. associate-+r-76.4%

        \[\leadsto \frac{{\left(F \cdot \color{blue}{\left(\left(A + C\right) - \mathsf{hypot}\left(B, A - C\right)\right)}\right)}^{0.5} \cdot {\left(2 \cdot \mathsf{fma}\left(C, A \cdot -4, {B}^{2}\right)\right)}^{0.5}}{-\mathsf{fma}\left(C, A \cdot -4, {B}^{2}\right)} \]
      5. hypot-undefine61.8%

        \[\leadsto \frac{{\left(F \cdot \left(\left(A + C\right) - \color{blue}{\sqrt{B \cdot B + \left(A - C\right) \cdot \left(A - C\right)}}\right)\right)}^{0.5} \cdot {\left(2 \cdot \mathsf{fma}\left(C, A \cdot -4, {B}^{2}\right)\right)}^{0.5}}{-\mathsf{fma}\left(C, A \cdot -4, {B}^{2}\right)} \]
      6. unpow261.8%

        \[\leadsto \frac{{\left(F \cdot \left(\left(A + C\right) - \sqrt{\color{blue}{{B}^{2}} + \left(A - C\right) \cdot \left(A - C\right)}\right)\right)}^{0.5} \cdot {\left(2 \cdot \mathsf{fma}\left(C, A \cdot -4, {B}^{2}\right)\right)}^{0.5}}{-\mathsf{fma}\left(C, A \cdot -4, {B}^{2}\right)} \]
      7. unpow261.8%

        \[\leadsto \frac{{\left(F \cdot \left(\left(A + C\right) - \sqrt{{B}^{2} + \color{blue}{{\left(A - C\right)}^{2}}}\right)\right)}^{0.5} \cdot {\left(2 \cdot \mathsf{fma}\left(C, A \cdot -4, {B}^{2}\right)\right)}^{0.5}}{-\mathsf{fma}\left(C, A \cdot -4, {B}^{2}\right)} \]
      8. +-commutative61.8%

        \[\leadsto \frac{{\left(F \cdot \left(\left(A + C\right) - \sqrt{\color{blue}{{\left(A - C\right)}^{2} + {B}^{2}}}\right)\right)}^{0.5} \cdot {\left(2 \cdot \mathsf{fma}\left(C, A \cdot -4, {B}^{2}\right)\right)}^{0.5}}{-\mathsf{fma}\left(C, A \cdot -4, {B}^{2}\right)} \]
      9. unpow261.8%

        \[\leadsto \frac{{\left(F \cdot \left(\left(A + C\right) - \sqrt{\color{blue}{\left(A - C\right) \cdot \left(A - C\right)} + {B}^{2}}\right)\right)}^{0.5} \cdot {\left(2 \cdot \mathsf{fma}\left(C, A \cdot -4, {B}^{2}\right)\right)}^{0.5}}{-\mathsf{fma}\left(C, A \cdot -4, {B}^{2}\right)} \]
      10. unpow261.8%

        \[\leadsto \frac{{\left(F \cdot \left(\left(A + C\right) - \sqrt{\left(A - C\right) \cdot \left(A - C\right) + \color{blue}{B \cdot B}}\right)\right)}^{0.5} \cdot {\left(2 \cdot \mathsf{fma}\left(C, A \cdot -4, {B}^{2}\right)\right)}^{0.5}}{-\mathsf{fma}\left(C, A \cdot -4, {B}^{2}\right)} \]
      11. hypot-define76.4%

        \[\leadsto \frac{{\left(F \cdot \left(\left(A + C\right) - \color{blue}{\mathsf{hypot}\left(A - C, B\right)}\right)\right)}^{0.5} \cdot {\left(2 \cdot \mathsf{fma}\left(C, A \cdot -4, {B}^{2}\right)\right)}^{0.5}}{-\mathsf{fma}\left(C, A \cdot -4, {B}^{2}\right)} \]
      12. pow1/276.4%

        \[\leadsto \frac{{\left(F \cdot \left(\left(A + C\right) - \mathsf{hypot}\left(A - C, B\right)\right)\right)}^{0.5} \cdot \color{blue}{\sqrt{2 \cdot \mathsf{fma}\left(C, A \cdot -4, {B}^{2}\right)}}}{-\mathsf{fma}\left(C, A \cdot -4, {B}^{2}\right)} \]
    5. Applied egg-rr76.4%

      \[\leadsto \frac{\color{blue}{{\left(F \cdot \left(\left(A + C\right) - \mathsf{hypot}\left(A - C, B\right)\right)\right)}^{0.5} \cdot \sqrt{2 \cdot \mathsf{fma}\left(C, A \cdot -4, {B}^{2}\right)}}}{-\mathsf{fma}\left(C, A \cdot -4, {B}^{2}\right)} \]
    6. Step-by-step derivation
      1. unpow1/276.4%

        \[\leadsto \frac{\color{blue}{\sqrt{F \cdot \left(\left(A + C\right) - \mathsf{hypot}\left(A - C, B\right)\right)}} \cdot \sqrt{2 \cdot \mathsf{fma}\left(C, A \cdot -4, {B}^{2}\right)}}{-\mathsf{fma}\left(C, A \cdot -4, {B}^{2}\right)} \]
      2. sub-neg76.4%

        \[\leadsto \frac{\sqrt{F \cdot \color{blue}{\left(\left(A + C\right) + \left(-\mathsf{hypot}\left(A - C, B\right)\right)\right)}} \cdot \sqrt{2 \cdot \mathsf{fma}\left(C, A \cdot -4, {B}^{2}\right)}}{-\mathsf{fma}\left(C, A \cdot -4, {B}^{2}\right)} \]
      3. associate-+l+77.2%

        \[\leadsto \frac{\sqrt{F \cdot \color{blue}{\left(A + \left(C + \left(-\mathsf{hypot}\left(A - C, B\right)\right)\right)\right)}} \cdot \sqrt{2 \cdot \mathsf{fma}\left(C, A \cdot -4, {B}^{2}\right)}}{-\mathsf{fma}\left(C, A \cdot -4, {B}^{2}\right)} \]
      4. sub-neg77.2%

        \[\leadsto \frac{\sqrt{F \cdot \left(A + \color{blue}{\left(C - \mathsf{hypot}\left(A - C, B\right)\right)}\right)} \cdot \sqrt{2 \cdot \mathsf{fma}\left(C, A \cdot -4, {B}^{2}\right)}}{-\mathsf{fma}\left(C, A \cdot -4, {B}^{2}\right)} \]
      5. hypot-undefine61.8%

        \[\leadsto \frac{\sqrt{F \cdot \left(A + \left(C - \color{blue}{\sqrt{\left(A - C\right) \cdot \left(A - C\right) + B \cdot B}}\right)\right)} \cdot \sqrt{2 \cdot \mathsf{fma}\left(C, A \cdot -4, {B}^{2}\right)}}{-\mathsf{fma}\left(C, A \cdot -4, {B}^{2}\right)} \]
      6. unpow261.8%

        \[\leadsto \frac{\sqrt{F \cdot \left(A + \left(C - \sqrt{\color{blue}{{\left(A - C\right)}^{2}} + B \cdot B}\right)\right)} \cdot \sqrt{2 \cdot \mathsf{fma}\left(C, A \cdot -4, {B}^{2}\right)}}{-\mathsf{fma}\left(C, A \cdot -4, {B}^{2}\right)} \]
      7. unpow261.8%

        \[\leadsto \frac{\sqrt{F \cdot \left(A + \left(C - \sqrt{{\left(A - C\right)}^{2} + \color{blue}{{B}^{2}}}\right)\right)} \cdot \sqrt{2 \cdot \mathsf{fma}\left(C, A \cdot -4, {B}^{2}\right)}}{-\mathsf{fma}\left(C, A \cdot -4, {B}^{2}\right)} \]
      8. +-commutative61.8%

        \[\leadsto \frac{\sqrt{F \cdot \left(A + \left(C - \sqrt{\color{blue}{{B}^{2} + {\left(A - C\right)}^{2}}}\right)\right)} \cdot \sqrt{2 \cdot \mathsf{fma}\left(C, A \cdot -4, {B}^{2}\right)}}{-\mathsf{fma}\left(C, A \cdot -4, {B}^{2}\right)} \]
      9. unpow261.8%

        \[\leadsto \frac{\sqrt{F \cdot \left(A + \left(C - \sqrt{\color{blue}{B \cdot B} + {\left(A - C\right)}^{2}}\right)\right)} \cdot \sqrt{2 \cdot \mathsf{fma}\left(C, A \cdot -4, {B}^{2}\right)}}{-\mathsf{fma}\left(C, A \cdot -4, {B}^{2}\right)} \]
      10. unpow261.8%

        \[\leadsto \frac{\sqrt{F \cdot \left(A + \left(C - \sqrt{B \cdot B + \color{blue}{\left(A - C\right) \cdot \left(A - C\right)}}\right)\right)} \cdot \sqrt{2 \cdot \mathsf{fma}\left(C, A \cdot -4, {B}^{2}\right)}}{-\mathsf{fma}\left(C, A \cdot -4, {B}^{2}\right)} \]
      11. hypot-undefine77.2%

        \[\leadsto \frac{\sqrt{F \cdot \left(A + \left(C - \color{blue}{\mathsf{hypot}\left(B, A - C\right)}\right)\right)} \cdot \sqrt{2 \cdot \mathsf{fma}\left(C, A \cdot -4, {B}^{2}\right)}}{-\mathsf{fma}\left(C, A \cdot -4, {B}^{2}\right)} \]
    7. Simplified77.2%

      \[\leadsto \frac{\color{blue}{\sqrt{F \cdot \left(A + \left(C - \mathsf{hypot}\left(B, A - C\right)\right)\right)} \cdot \sqrt{2 \cdot \mathsf{fma}\left(C, A \cdot -4, {B}^{2}\right)}}}{-\mathsf{fma}\left(C, A \cdot -4, {B}^{2}\right)} \]

    if -2e-204 < (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (-.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C))) < +inf.0

    1. Initial program 23.5%

      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    2. Simplified32.2%

      \[\leadsto \color{blue}{\frac{\sqrt{\left(\mathsf{fma}\left(B, B, A \cdot \left(C \cdot -4\right)\right) \cdot F\right) \cdot \left(2 \cdot \left(A + \left(C - \mathsf{hypot}\left(B, A - C\right)\right)\right)\right)}}{-\mathsf{fma}\left(B, B, A \cdot \left(C \cdot -4\right)\right)}} \]
    3. Add Preprocessing
    4. Taylor expanded in C around inf 34.0%

      \[\leadsto \frac{\sqrt{\left(\mathsf{fma}\left(B, B, A \cdot \left(C \cdot -4\right)\right) \cdot F\right) \cdot \left(2 \cdot \left(A + \color{blue}{\left(-0.5 \cdot \frac{{B}^{2}}{C} - -1 \cdot A\right)}\right)\right)}}{-\mathsf{fma}\left(B, B, A \cdot \left(C \cdot -4\right)\right)} \]
    5. Step-by-step derivation
      1. mul-1-neg34.0%

        \[\leadsto \frac{\sqrt{\left(\mathsf{fma}\left(B, B, A \cdot \left(C \cdot -4\right)\right) \cdot F\right) \cdot \left(2 \cdot \left(A + \left(-0.5 \cdot \frac{{B}^{2}}{C} - \color{blue}{\left(-A\right)}\right)\right)\right)}}{-\mathsf{fma}\left(B, B, A \cdot \left(C \cdot -4\right)\right)} \]
    6. Simplified34.0%

      \[\leadsto \frac{\sqrt{\left(\mathsf{fma}\left(B, B, A \cdot \left(C \cdot -4\right)\right) \cdot F\right) \cdot \left(2 \cdot \left(A + \color{blue}{\left(-0.5 \cdot \frac{{B}^{2}}{C} - \left(-A\right)\right)}\right)\right)}}{-\mathsf{fma}\left(B, B, A \cdot \left(C \cdot -4\right)\right)} \]

    if +inf.0 < (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (-.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)))

    1. Initial program 0.0%

      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    2. Add Preprocessing
    3. Taylor expanded in C around 0 2.0%

      \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}\right)} \]
    4. Step-by-step derivation
      1. mul-1-neg2.0%

        \[\leadsto \color{blue}{-\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}} \]
      2. +-commutative2.0%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{\color{blue}{{B}^{2} + {A}^{2}}}\right)} \]
    5. Simplified2.0%

      \[\leadsto \color{blue}{-\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{{B}^{2} + {A}^{2}}\right)}} \]
    6. Step-by-step derivation
      1. pow1/22.0%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot \color{blue}{{\left(F \cdot \left(A - \sqrt{{B}^{2} + {A}^{2}}\right)\right)}^{0.5}} \]
      2. pow-to-exp2.0%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot \color{blue}{e^{\log \left(F \cdot \left(A - \sqrt{{B}^{2} + {A}^{2}}\right)\right) \cdot 0.5}} \]
      3. unpow22.0%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{\log \left(F \cdot \left(A - \sqrt{\color{blue}{B \cdot B} + {A}^{2}}\right)\right) \cdot 0.5} \]
      4. unpow22.0%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{\log \left(F \cdot \left(A - \sqrt{B \cdot B + \color{blue}{A \cdot A}}\right)\right) \cdot 0.5} \]
      5. hypot-undefine15.8%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{\log \left(F \cdot \left(A - \color{blue}{\mathsf{hypot}\left(B, A\right)}\right)\right) \cdot 0.5} \]
    7. Applied egg-rr15.8%

      \[\leadsto -\frac{\sqrt{2}}{B} \cdot \color{blue}{e^{\log \left(F \cdot \left(A - \mathsf{hypot}\left(B, A\right)\right)\right) \cdot 0.5}} \]
    8. Taylor expanded in F around -inf 1.9%

      \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{\color{blue}{\left(\log \left(-1 \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)\right) + -1 \cdot \log \left(\frac{-1}{F}\right)\right)} \cdot 0.5} \]
    9. Step-by-step derivation
      1. mul-1-neg1.9%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{\left(\log \left(-1 \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)\right) + \color{blue}{\left(-\log \left(\frac{-1}{F}\right)\right)}\right) \cdot 0.5} \]
      2. unsub-neg1.9%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{\color{blue}{\left(\log \left(-1 \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)\right) - \log \left(\frac{-1}{F}\right)\right)} \cdot 0.5} \]
      3. mul-1-neg1.9%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{\left(\log \color{blue}{\left(-\left(A - \sqrt{{A}^{2} + {B}^{2}}\right)\right)} - \log \left(\frac{-1}{F}\right)\right) \cdot 0.5} \]
      4. +-commutative1.9%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{\left(\log \left(-\left(A - \sqrt{\color{blue}{{B}^{2} + {A}^{2}}}\right)\right) - \log \left(\frac{-1}{F}\right)\right) \cdot 0.5} \]
      5. unpow21.9%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{\left(\log \left(-\left(A - \sqrt{\color{blue}{B \cdot B} + {A}^{2}}\right)\right) - \log \left(\frac{-1}{F}\right)\right) \cdot 0.5} \]
      6. unpow21.9%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{\left(\log \left(-\left(A - \sqrt{B \cdot B + \color{blue}{A \cdot A}}\right)\right) - \log \left(\frac{-1}{F}\right)\right) \cdot 0.5} \]
      7. hypot-undefine23.9%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{\left(\log \left(-\left(A - \color{blue}{\mathsf{hypot}\left(B, A\right)}\right)\right) - \log \left(\frac{-1}{F}\right)\right) \cdot 0.5} \]
    10. Simplified23.9%

      \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{\color{blue}{\left(\log \left(-\left(A - \mathsf{hypot}\left(B, A\right)\right)\right) - \log \left(\frac{-1}{F}\right)\right)} \cdot 0.5} \]
    11. Step-by-step derivation
      1. add-cube-cbrt23.9%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{\left(\log \left(-\left(A - \mathsf{hypot}\left(B, A\right)\right)\right) - \log \color{blue}{\left(\left(\sqrt[3]{\frac{-1}{F}} \cdot \sqrt[3]{\frac{-1}{F}}\right) \cdot \sqrt[3]{\frac{-1}{F}}\right)}\right) \cdot 0.5} \]
      2. log-prod23.9%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{\left(\log \left(-\left(A - \mathsf{hypot}\left(B, A\right)\right)\right) - \color{blue}{\left(\log \left(\sqrt[3]{\frac{-1}{F}} \cdot \sqrt[3]{\frac{-1}{F}}\right) + \log \left(\sqrt[3]{\frac{-1}{F}}\right)\right)}\right) \cdot 0.5} \]
      3. pow223.9%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{\left(\log \left(-\left(A - \mathsf{hypot}\left(B, A\right)\right)\right) - \left(\log \color{blue}{\left({\left(\sqrt[3]{\frac{-1}{F}}\right)}^{2}\right)} + \log \left(\sqrt[3]{\frac{-1}{F}}\right)\right)\right) \cdot 0.5} \]
    12. Applied egg-rr23.9%

      \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{\left(\log \left(-\left(A - \mathsf{hypot}\left(B, A\right)\right)\right) - \color{blue}{\left(\log \left({\left(\sqrt[3]{\frac{-1}{F}}\right)}^{2}\right) + \log \left(\sqrt[3]{\frac{-1}{F}}\right)\right)}\right) \cdot 0.5} \]
  3. Recombined 3 regimes into one program.
  4. Final simplification44.9%

    \[\leadsto \begin{array}{l} \mathbf{if}\;\frac{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) - \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)}}{\left(4 \cdot A\right) \cdot C - {B}^{2}} \leq -2 \cdot 10^{-204}:\\ \;\;\;\;\frac{\sqrt{F \cdot \left(A + \left(C - \mathsf{hypot}\left(B, A - C\right)\right)\right)} \cdot \sqrt{2 \cdot \mathsf{fma}\left(C, A \cdot -4, {B}^{2}\right)}}{-\mathsf{fma}\left(C, A \cdot -4, {B}^{2}\right)}\\ \mathbf{elif}\;\frac{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) - \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)}}{\left(4 \cdot A\right) \cdot C - {B}^{2}} \leq \infty:\\ \;\;\;\;\frac{\sqrt{\left(F \cdot \mathsf{fma}\left(B, B, A \cdot \left(C \cdot -4\right)\right)\right) \cdot \left(2 \cdot \left(A + \left(A + -0.5 \cdot \frac{{B}^{2}}{C}\right)\right)\right)}}{-\mathsf{fma}\left(B, B, A \cdot \left(C \cdot -4\right)\right)}\\ \mathbf{else}:\\ \;\;\;\;e^{\left(\log \left(\mathsf{hypot}\left(B, A\right) - A\right) - \left(\log \left({\left(\sqrt[3]{\frac{-1}{F}}\right)}^{2}\right) + \log \left(\sqrt[3]{\frac{-1}{F}}\right)\right)\right) \cdot 0.5} \cdot \frac{\sqrt{2}}{-B}\\ \end{array} \]
  5. Add Preprocessing

Alternative 2: 57.0% accurate, 0.4× speedup?

\[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} t_0 := \mathsf{fma}\left(B\_m, B\_m, A \cdot \left(C \cdot -4\right)\right)\\ t_1 := \left(4 \cdot A\right) \cdot C\\ t_2 := \frac{\sqrt{\left(2 \cdot \left(\left({B\_m}^{2} - t\_1\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) - \sqrt{{B\_m}^{2} + {\left(A - C\right)}^{2}}\right)}}{t\_1 - {B\_m}^{2}}\\ t_3 := \mathsf{fma}\left(C, A \cdot -4, {B\_m}^{2}\right)\\ \mathbf{if}\;t\_2 \leq -2 \cdot 10^{-204}:\\ \;\;\;\;\frac{\sqrt{F \cdot \left(A + \left(C - \mathsf{hypot}\left(B\_m, A - C\right)\right)\right)} \cdot \sqrt{2 \cdot t\_3}}{-t\_3}\\ \mathbf{elif}\;t\_2 \leq \infty:\\ \;\;\;\;\frac{\sqrt{\left(F \cdot t\_0\right) \cdot \left(2 \cdot \left(A + \left(A + -0.5 \cdot \frac{{B\_m}^{2}}{C}\right)\right)\right)}}{-t\_0}\\ \mathbf{else}:\\ \;\;\;\;\frac{\sqrt{2}}{B\_m} \cdot \left(-e^{0.5 \cdot \left(\log \left(\mathsf{hypot}\left(B\_m, A\right) - A\right) - \log \left(\frac{-1}{F}\right)\right)}\right)\\ \end{array} \end{array} \]
B_m = (fabs.f64 B)
NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
(FPCore (A B_m C F)
 :precision binary64
 (let* ((t_0 (fma B_m B_m (* A (* C -4.0))))
        (t_1 (* (* 4.0 A) C))
        (t_2
         (/
          (sqrt
           (*
            (* 2.0 (* (- (pow B_m 2.0) t_1) F))
            (- (+ A C) (sqrt (+ (pow B_m 2.0) (pow (- A C) 2.0))))))
          (- t_1 (pow B_m 2.0))))
        (t_3 (fma C (* A -4.0) (pow B_m 2.0))))
   (if (<= t_2 -2e-204)
     (/
      (* (sqrt (* F (+ A (- C (hypot B_m (- A C)))))) (sqrt (* 2.0 t_3)))
      (- t_3))
     (if (<= t_2 INFINITY)
       (/
        (sqrt (* (* F t_0) (* 2.0 (+ A (+ A (* -0.5 (/ (pow B_m 2.0) C)))))))
        (- t_0))
       (*
        (/ (sqrt 2.0) B_m)
        (- (exp (* 0.5 (- (log (- (hypot B_m A) A)) (log (/ -1.0 F)))))))))))
B_m = fabs(B);
assert(A < B_m && B_m < C && C < F);
double code(double A, double B_m, double C, double F) {
	double t_0 = fma(B_m, B_m, (A * (C * -4.0)));
	double t_1 = (4.0 * A) * C;
	double t_2 = sqrt(((2.0 * ((pow(B_m, 2.0) - t_1) * F)) * ((A + C) - sqrt((pow(B_m, 2.0) + pow((A - C), 2.0)))))) / (t_1 - pow(B_m, 2.0));
	double t_3 = fma(C, (A * -4.0), pow(B_m, 2.0));
	double tmp;
	if (t_2 <= -2e-204) {
		tmp = (sqrt((F * (A + (C - hypot(B_m, (A - C)))))) * sqrt((2.0 * t_3))) / -t_3;
	} else if (t_2 <= ((double) INFINITY)) {
		tmp = sqrt(((F * t_0) * (2.0 * (A + (A + (-0.5 * (pow(B_m, 2.0) / C))))))) / -t_0;
	} else {
		tmp = (sqrt(2.0) / B_m) * -exp((0.5 * (log((hypot(B_m, A) - A)) - log((-1.0 / F)))));
	}
	return tmp;
}
B_m = abs(B)
A, B_m, C, F = sort([A, B_m, C, F])
function code(A, B_m, C, F)
	t_0 = fma(B_m, B_m, Float64(A * Float64(C * -4.0)))
	t_1 = Float64(Float64(4.0 * A) * C)
	t_2 = Float64(sqrt(Float64(Float64(2.0 * Float64(Float64((B_m ^ 2.0) - t_1) * F)) * Float64(Float64(A + C) - sqrt(Float64((B_m ^ 2.0) + (Float64(A - C) ^ 2.0)))))) / Float64(t_1 - (B_m ^ 2.0)))
	t_3 = fma(C, Float64(A * -4.0), (B_m ^ 2.0))
	tmp = 0.0
	if (t_2 <= -2e-204)
		tmp = Float64(Float64(sqrt(Float64(F * Float64(A + Float64(C - hypot(B_m, Float64(A - C)))))) * sqrt(Float64(2.0 * t_3))) / Float64(-t_3));
	elseif (t_2 <= Inf)
		tmp = Float64(sqrt(Float64(Float64(F * t_0) * Float64(2.0 * Float64(A + Float64(A + Float64(-0.5 * Float64((B_m ^ 2.0) / C))))))) / Float64(-t_0));
	else
		tmp = Float64(Float64(sqrt(2.0) / B_m) * Float64(-exp(Float64(0.5 * Float64(log(Float64(hypot(B_m, A) - A)) - log(Float64(-1.0 / F)))))));
	end
	return tmp
end
B_m = N[Abs[B], $MachinePrecision]
NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
code[A_, B$95$m_, C_, F_] := Block[{t$95$0 = N[(B$95$m * B$95$m + N[(A * N[(C * -4.0), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$1 = N[(N[(4.0 * A), $MachinePrecision] * C), $MachinePrecision]}, Block[{t$95$2 = N[(N[Sqrt[N[(N[(2.0 * N[(N[(N[Power[B$95$m, 2.0], $MachinePrecision] - t$95$1), $MachinePrecision] * F), $MachinePrecision]), $MachinePrecision] * N[(N[(A + C), $MachinePrecision] - N[Sqrt[N[(N[Power[B$95$m, 2.0], $MachinePrecision] + N[Power[N[(A - C), $MachinePrecision], 2.0], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / N[(t$95$1 - N[Power[B$95$m, 2.0], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$3 = N[(C * N[(A * -4.0), $MachinePrecision] + N[Power[B$95$m, 2.0], $MachinePrecision]), $MachinePrecision]}, If[LessEqual[t$95$2, -2e-204], N[(N[(N[Sqrt[N[(F * N[(A + N[(C - N[Sqrt[B$95$m ^ 2 + N[(A - C), $MachinePrecision] ^ 2], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] * N[Sqrt[N[(2.0 * t$95$3), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] / (-t$95$3)), $MachinePrecision], If[LessEqual[t$95$2, Infinity], N[(N[Sqrt[N[(N[(F * t$95$0), $MachinePrecision] * N[(2.0 * N[(A + N[(A + N[(-0.5 * N[(N[Power[B$95$m, 2.0], $MachinePrecision] / C), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / (-t$95$0)), $MachinePrecision], N[(N[(N[Sqrt[2.0], $MachinePrecision] / B$95$m), $MachinePrecision] * (-N[Exp[N[(0.5 * N[(N[Log[N[(N[Sqrt[B$95$m ^ 2 + A ^ 2], $MachinePrecision] - A), $MachinePrecision]], $MachinePrecision] - N[Log[N[(-1.0 / F), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision])), $MachinePrecision]]]]]]]
\begin{array}{l}
B_m = \left|B\right|
\\
[A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
\\
\begin{array}{l}
t_0 := \mathsf{fma}\left(B\_m, B\_m, A \cdot \left(C \cdot -4\right)\right)\\
t_1 := \left(4 \cdot A\right) \cdot C\\
t_2 := \frac{\sqrt{\left(2 \cdot \left(\left({B\_m}^{2} - t\_1\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) - \sqrt{{B\_m}^{2} + {\left(A - C\right)}^{2}}\right)}}{t\_1 - {B\_m}^{2}}\\
t_3 := \mathsf{fma}\left(C, A \cdot -4, {B\_m}^{2}\right)\\
\mathbf{if}\;t\_2 \leq -2 \cdot 10^{-204}:\\
\;\;\;\;\frac{\sqrt{F \cdot \left(A + \left(C - \mathsf{hypot}\left(B\_m, A - C\right)\right)\right)} \cdot \sqrt{2 \cdot t\_3}}{-t\_3}\\

\mathbf{elif}\;t\_2 \leq \infty:\\
\;\;\;\;\frac{\sqrt{\left(F \cdot t\_0\right) \cdot \left(2 \cdot \left(A + \left(A + -0.5 \cdot \frac{{B\_m}^{2}}{C}\right)\right)\right)}}{-t\_0}\\

\mathbf{else}:\\
\;\;\;\;\frac{\sqrt{2}}{B\_m} \cdot \left(-e^{0.5 \cdot \left(\log \left(\mathsf{hypot}\left(B\_m, A\right) - A\right) - \log \left(\frac{-1}{F}\right)\right)}\right)\\


\end{array}
\end{array}
Derivation
  1. Split input into 3 regimes
  2. if (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (-.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C))) < -2e-204

    1. Initial program 51.1%

      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    2. Simplified46.8%

      \[\leadsto \color{blue}{\frac{\sqrt{F \cdot \left(\left(A + \left(C - \mathsf{hypot}\left(B, A - C\right)\right)\right) \cdot \left(2 \cdot \mathsf{fma}\left(C, A \cdot -4, {B}^{2}\right)\right)\right)}}{-\mathsf{fma}\left(C, A \cdot -4, {B}^{2}\right)}} \]
    3. Add Preprocessing
    4. Step-by-step derivation
      1. pow1/246.8%

        \[\leadsto \frac{\color{blue}{{\left(F \cdot \left(\left(A + \left(C - \mathsf{hypot}\left(B, A - C\right)\right)\right) \cdot \left(2 \cdot \mathsf{fma}\left(C, A \cdot -4, {B}^{2}\right)\right)\right)\right)}^{0.5}}}{-\mathsf{fma}\left(C, A \cdot -4, {B}^{2}\right)} \]
      2. associate-*r*62.0%

        \[\leadsto \frac{{\color{blue}{\left(\left(F \cdot \left(A + \left(C - \mathsf{hypot}\left(B, A - C\right)\right)\right)\right) \cdot \left(2 \cdot \mathsf{fma}\left(C, A \cdot -4, {B}^{2}\right)\right)\right)}}^{0.5}}{-\mathsf{fma}\left(C, A \cdot -4, {B}^{2}\right)} \]
      3. unpow-prod-down77.2%

        \[\leadsto \frac{\color{blue}{{\left(F \cdot \left(A + \left(C - \mathsf{hypot}\left(B, A - C\right)\right)\right)\right)}^{0.5} \cdot {\left(2 \cdot \mathsf{fma}\left(C, A \cdot -4, {B}^{2}\right)\right)}^{0.5}}}{-\mathsf{fma}\left(C, A \cdot -4, {B}^{2}\right)} \]
      4. associate-+r-76.4%

        \[\leadsto \frac{{\left(F \cdot \color{blue}{\left(\left(A + C\right) - \mathsf{hypot}\left(B, A - C\right)\right)}\right)}^{0.5} \cdot {\left(2 \cdot \mathsf{fma}\left(C, A \cdot -4, {B}^{2}\right)\right)}^{0.5}}{-\mathsf{fma}\left(C, A \cdot -4, {B}^{2}\right)} \]
      5. hypot-undefine61.8%

        \[\leadsto \frac{{\left(F \cdot \left(\left(A + C\right) - \color{blue}{\sqrt{B \cdot B + \left(A - C\right) \cdot \left(A - C\right)}}\right)\right)}^{0.5} \cdot {\left(2 \cdot \mathsf{fma}\left(C, A \cdot -4, {B}^{2}\right)\right)}^{0.5}}{-\mathsf{fma}\left(C, A \cdot -4, {B}^{2}\right)} \]
      6. unpow261.8%

        \[\leadsto \frac{{\left(F \cdot \left(\left(A + C\right) - \sqrt{\color{blue}{{B}^{2}} + \left(A - C\right) \cdot \left(A - C\right)}\right)\right)}^{0.5} \cdot {\left(2 \cdot \mathsf{fma}\left(C, A \cdot -4, {B}^{2}\right)\right)}^{0.5}}{-\mathsf{fma}\left(C, A \cdot -4, {B}^{2}\right)} \]
      7. unpow261.8%

        \[\leadsto \frac{{\left(F \cdot \left(\left(A + C\right) - \sqrt{{B}^{2} + \color{blue}{{\left(A - C\right)}^{2}}}\right)\right)}^{0.5} \cdot {\left(2 \cdot \mathsf{fma}\left(C, A \cdot -4, {B}^{2}\right)\right)}^{0.5}}{-\mathsf{fma}\left(C, A \cdot -4, {B}^{2}\right)} \]
      8. +-commutative61.8%

        \[\leadsto \frac{{\left(F \cdot \left(\left(A + C\right) - \sqrt{\color{blue}{{\left(A - C\right)}^{2} + {B}^{2}}}\right)\right)}^{0.5} \cdot {\left(2 \cdot \mathsf{fma}\left(C, A \cdot -4, {B}^{2}\right)\right)}^{0.5}}{-\mathsf{fma}\left(C, A \cdot -4, {B}^{2}\right)} \]
      9. unpow261.8%

        \[\leadsto \frac{{\left(F \cdot \left(\left(A + C\right) - \sqrt{\color{blue}{\left(A - C\right) \cdot \left(A - C\right)} + {B}^{2}}\right)\right)}^{0.5} \cdot {\left(2 \cdot \mathsf{fma}\left(C, A \cdot -4, {B}^{2}\right)\right)}^{0.5}}{-\mathsf{fma}\left(C, A \cdot -4, {B}^{2}\right)} \]
      10. unpow261.8%

        \[\leadsto \frac{{\left(F \cdot \left(\left(A + C\right) - \sqrt{\left(A - C\right) \cdot \left(A - C\right) + \color{blue}{B \cdot B}}\right)\right)}^{0.5} \cdot {\left(2 \cdot \mathsf{fma}\left(C, A \cdot -4, {B}^{2}\right)\right)}^{0.5}}{-\mathsf{fma}\left(C, A \cdot -4, {B}^{2}\right)} \]
      11. hypot-define76.4%

        \[\leadsto \frac{{\left(F \cdot \left(\left(A + C\right) - \color{blue}{\mathsf{hypot}\left(A - C, B\right)}\right)\right)}^{0.5} \cdot {\left(2 \cdot \mathsf{fma}\left(C, A \cdot -4, {B}^{2}\right)\right)}^{0.5}}{-\mathsf{fma}\left(C, A \cdot -4, {B}^{2}\right)} \]
      12. pow1/276.4%

        \[\leadsto \frac{{\left(F \cdot \left(\left(A + C\right) - \mathsf{hypot}\left(A - C, B\right)\right)\right)}^{0.5} \cdot \color{blue}{\sqrt{2 \cdot \mathsf{fma}\left(C, A \cdot -4, {B}^{2}\right)}}}{-\mathsf{fma}\left(C, A \cdot -4, {B}^{2}\right)} \]
    5. Applied egg-rr76.4%

      \[\leadsto \frac{\color{blue}{{\left(F \cdot \left(\left(A + C\right) - \mathsf{hypot}\left(A - C, B\right)\right)\right)}^{0.5} \cdot \sqrt{2 \cdot \mathsf{fma}\left(C, A \cdot -4, {B}^{2}\right)}}}{-\mathsf{fma}\left(C, A \cdot -4, {B}^{2}\right)} \]
    6. Step-by-step derivation
      1. unpow1/276.4%

        \[\leadsto \frac{\color{blue}{\sqrt{F \cdot \left(\left(A + C\right) - \mathsf{hypot}\left(A - C, B\right)\right)}} \cdot \sqrt{2 \cdot \mathsf{fma}\left(C, A \cdot -4, {B}^{2}\right)}}{-\mathsf{fma}\left(C, A \cdot -4, {B}^{2}\right)} \]
      2. sub-neg76.4%

        \[\leadsto \frac{\sqrt{F \cdot \color{blue}{\left(\left(A + C\right) + \left(-\mathsf{hypot}\left(A - C, B\right)\right)\right)}} \cdot \sqrt{2 \cdot \mathsf{fma}\left(C, A \cdot -4, {B}^{2}\right)}}{-\mathsf{fma}\left(C, A \cdot -4, {B}^{2}\right)} \]
      3. associate-+l+77.2%

        \[\leadsto \frac{\sqrt{F \cdot \color{blue}{\left(A + \left(C + \left(-\mathsf{hypot}\left(A - C, B\right)\right)\right)\right)}} \cdot \sqrt{2 \cdot \mathsf{fma}\left(C, A \cdot -4, {B}^{2}\right)}}{-\mathsf{fma}\left(C, A \cdot -4, {B}^{2}\right)} \]
      4. sub-neg77.2%

        \[\leadsto \frac{\sqrt{F \cdot \left(A + \color{blue}{\left(C - \mathsf{hypot}\left(A - C, B\right)\right)}\right)} \cdot \sqrt{2 \cdot \mathsf{fma}\left(C, A \cdot -4, {B}^{2}\right)}}{-\mathsf{fma}\left(C, A \cdot -4, {B}^{2}\right)} \]
      5. hypot-undefine61.8%

        \[\leadsto \frac{\sqrt{F \cdot \left(A + \left(C - \color{blue}{\sqrt{\left(A - C\right) \cdot \left(A - C\right) + B \cdot B}}\right)\right)} \cdot \sqrt{2 \cdot \mathsf{fma}\left(C, A \cdot -4, {B}^{2}\right)}}{-\mathsf{fma}\left(C, A \cdot -4, {B}^{2}\right)} \]
      6. unpow261.8%

        \[\leadsto \frac{\sqrt{F \cdot \left(A + \left(C - \sqrt{\color{blue}{{\left(A - C\right)}^{2}} + B \cdot B}\right)\right)} \cdot \sqrt{2 \cdot \mathsf{fma}\left(C, A \cdot -4, {B}^{2}\right)}}{-\mathsf{fma}\left(C, A \cdot -4, {B}^{2}\right)} \]
      7. unpow261.8%

        \[\leadsto \frac{\sqrt{F \cdot \left(A + \left(C - \sqrt{{\left(A - C\right)}^{2} + \color{blue}{{B}^{2}}}\right)\right)} \cdot \sqrt{2 \cdot \mathsf{fma}\left(C, A \cdot -4, {B}^{2}\right)}}{-\mathsf{fma}\left(C, A \cdot -4, {B}^{2}\right)} \]
      8. +-commutative61.8%

        \[\leadsto \frac{\sqrt{F \cdot \left(A + \left(C - \sqrt{\color{blue}{{B}^{2} + {\left(A - C\right)}^{2}}}\right)\right)} \cdot \sqrt{2 \cdot \mathsf{fma}\left(C, A \cdot -4, {B}^{2}\right)}}{-\mathsf{fma}\left(C, A \cdot -4, {B}^{2}\right)} \]
      9. unpow261.8%

        \[\leadsto \frac{\sqrt{F \cdot \left(A + \left(C - \sqrt{\color{blue}{B \cdot B} + {\left(A - C\right)}^{2}}\right)\right)} \cdot \sqrt{2 \cdot \mathsf{fma}\left(C, A \cdot -4, {B}^{2}\right)}}{-\mathsf{fma}\left(C, A \cdot -4, {B}^{2}\right)} \]
      10. unpow261.8%

        \[\leadsto \frac{\sqrt{F \cdot \left(A + \left(C - \sqrt{B \cdot B + \color{blue}{\left(A - C\right) \cdot \left(A - C\right)}}\right)\right)} \cdot \sqrt{2 \cdot \mathsf{fma}\left(C, A \cdot -4, {B}^{2}\right)}}{-\mathsf{fma}\left(C, A \cdot -4, {B}^{2}\right)} \]
      11. hypot-undefine77.2%

        \[\leadsto \frac{\sqrt{F \cdot \left(A + \left(C - \color{blue}{\mathsf{hypot}\left(B, A - C\right)}\right)\right)} \cdot \sqrt{2 \cdot \mathsf{fma}\left(C, A \cdot -4, {B}^{2}\right)}}{-\mathsf{fma}\left(C, A \cdot -4, {B}^{2}\right)} \]
    7. Simplified77.2%

      \[\leadsto \frac{\color{blue}{\sqrt{F \cdot \left(A + \left(C - \mathsf{hypot}\left(B, A - C\right)\right)\right)} \cdot \sqrt{2 \cdot \mathsf{fma}\left(C, A \cdot -4, {B}^{2}\right)}}}{-\mathsf{fma}\left(C, A \cdot -4, {B}^{2}\right)} \]

    if -2e-204 < (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (-.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C))) < +inf.0

    1. Initial program 23.5%

      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    2. Simplified32.2%

      \[\leadsto \color{blue}{\frac{\sqrt{\left(\mathsf{fma}\left(B, B, A \cdot \left(C \cdot -4\right)\right) \cdot F\right) \cdot \left(2 \cdot \left(A + \left(C - \mathsf{hypot}\left(B, A - C\right)\right)\right)\right)}}{-\mathsf{fma}\left(B, B, A \cdot \left(C \cdot -4\right)\right)}} \]
    3. Add Preprocessing
    4. Taylor expanded in C around inf 34.0%

      \[\leadsto \frac{\sqrt{\left(\mathsf{fma}\left(B, B, A \cdot \left(C \cdot -4\right)\right) \cdot F\right) \cdot \left(2 \cdot \left(A + \color{blue}{\left(-0.5 \cdot \frac{{B}^{2}}{C} - -1 \cdot A\right)}\right)\right)}}{-\mathsf{fma}\left(B, B, A \cdot \left(C \cdot -4\right)\right)} \]
    5. Step-by-step derivation
      1. mul-1-neg34.0%

        \[\leadsto \frac{\sqrt{\left(\mathsf{fma}\left(B, B, A \cdot \left(C \cdot -4\right)\right) \cdot F\right) \cdot \left(2 \cdot \left(A + \left(-0.5 \cdot \frac{{B}^{2}}{C} - \color{blue}{\left(-A\right)}\right)\right)\right)}}{-\mathsf{fma}\left(B, B, A \cdot \left(C \cdot -4\right)\right)} \]
    6. Simplified34.0%

      \[\leadsto \frac{\sqrt{\left(\mathsf{fma}\left(B, B, A \cdot \left(C \cdot -4\right)\right) \cdot F\right) \cdot \left(2 \cdot \left(A + \color{blue}{\left(-0.5 \cdot \frac{{B}^{2}}{C} - \left(-A\right)\right)}\right)\right)}}{-\mathsf{fma}\left(B, B, A \cdot \left(C \cdot -4\right)\right)} \]

    if +inf.0 < (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (-.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)))

    1. Initial program 0.0%

      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    2. Add Preprocessing
    3. Taylor expanded in C around 0 2.0%

      \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}\right)} \]
    4. Step-by-step derivation
      1. mul-1-neg2.0%

        \[\leadsto \color{blue}{-\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}} \]
      2. +-commutative2.0%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{\color{blue}{{B}^{2} + {A}^{2}}}\right)} \]
    5. Simplified2.0%

      \[\leadsto \color{blue}{-\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{{B}^{2} + {A}^{2}}\right)}} \]
    6. Step-by-step derivation
      1. pow1/22.0%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot \color{blue}{{\left(F \cdot \left(A - \sqrt{{B}^{2} + {A}^{2}}\right)\right)}^{0.5}} \]
      2. pow-to-exp2.0%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot \color{blue}{e^{\log \left(F \cdot \left(A - \sqrt{{B}^{2} + {A}^{2}}\right)\right) \cdot 0.5}} \]
      3. unpow22.0%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{\log \left(F \cdot \left(A - \sqrt{\color{blue}{B \cdot B} + {A}^{2}}\right)\right) \cdot 0.5} \]
      4. unpow22.0%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{\log \left(F \cdot \left(A - \sqrt{B \cdot B + \color{blue}{A \cdot A}}\right)\right) \cdot 0.5} \]
      5. hypot-undefine15.8%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{\log \left(F \cdot \left(A - \color{blue}{\mathsf{hypot}\left(B, A\right)}\right)\right) \cdot 0.5} \]
    7. Applied egg-rr15.8%

      \[\leadsto -\frac{\sqrt{2}}{B} \cdot \color{blue}{e^{\log \left(F \cdot \left(A - \mathsf{hypot}\left(B, A\right)\right)\right) \cdot 0.5}} \]
    8. Taylor expanded in F around -inf 1.9%

      \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{\color{blue}{\left(\log \left(-1 \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)\right) + -1 \cdot \log \left(\frac{-1}{F}\right)\right)} \cdot 0.5} \]
    9. Step-by-step derivation
      1. mul-1-neg1.9%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{\left(\log \left(-1 \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)\right) + \color{blue}{\left(-\log \left(\frac{-1}{F}\right)\right)}\right) \cdot 0.5} \]
      2. unsub-neg1.9%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{\color{blue}{\left(\log \left(-1 \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)\right) - \log \left(\frac{-1}{F}\right)\right)} \cdot 0.5} \]
      3. mul-1-neg1.9%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{\left(\log \color{blue}{\left(-\left(A - \sqrt{{A}^{2} + {B}^{2}}\right)\right)} - \log \left(\frac{-1}{F}\right)\right) \cdot 0.5} \]
      4. +-commutative1.9%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{\left(\log \left(-\left(A - \sqrt{\color{blue}{{B}^{2} + {A}^{2}}}\right)\right) - \log \left(\frac{-1}{F}\right)\right) \cdot 0.5} \]
      5. unpow21.9%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{\left(\log \left(-\left(A - \sqrt{\color{blue}{B \cdot B} + {A}^{2}}\right)\right) - \log \left(\frac{-1}{F}\right)\right) \cdot 0.5} \]
      6. unpow21.9%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{\left(\log \left(-\left(A - \sqrt{B \cdot B + \color{blue}{A \cdot A}}\right)\right) - \log \left(\frac{-1}{F}\right)\right) \cdot 0.5} \]
      7. hypot-undefine23.9%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{\left(\log \left(-\left(A - \color{blue}{\mathsf{hypot}\left(B, A\right)}\right)\right) - \log \left(\frac{-1}{F}\right)\right) \cdot 0.5} \]
    10. Simplified23.9%

      \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{\color{blue}{\left(\log \left(-\left(A - \mathsf{hypot}\left(B, A\right)\right)\right) - \log \left(\frac{-1}{F}\right)\right)} \cdot 0.5} \]
    11. Taylor expanded in F around -inf 1.9%

      \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{\color{blue}{0.5 \cdot \left(\log \left(\sqrt{{A}^{2} + {B}^{2}} - A\right) - \log \left(\frac{-1}{F}\right)\right)}} \]
    12. Step-by-step derivation
      1. +-commutative1.9%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{0.5 \cdot \left(\log \left(\sqrt{\color{blue}{{B}^{2} + {A}^{2}}} - A\right) - \log \left(\frac{-1}{F}\right)\right)} \]
      2. unpow21.9%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{0.5 \cdot \left(\log \left(\sqrt{\color{blue}{B \cdot B} + {A}^{2}} - A\right) - \log \left(\frac{-1}{F}\right)\right)} \]
      3. unpow21.9%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{0.5 \cdot \left(\log \left(\sqrt{B \cdot B + \color{blue}{A \cdot A}} - A\right) - \log \left(\frac{-1}{F}\right)\right)} \]
      4. hypot-undefine23.9%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{0.5 \cdot \left(\log \left(\color{blue}{\mathsf{hypot}\left(B, A\right)} - A\right) - \log \left(\frac{-1}{F}\right)\right)} \]
    13. Simplified23.9%

      \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{\color{blue}{0.5 \cdot \left(\log \left(\mathsf{hypot}\left(B, A\right) - A\right) - \log \left(\frac{-1}{F}\right)\right)}} \]
  3. Recombined 3 regimes into one program.
  4. Final simplification45.0%

    \[\leadsto \begin{array}{l} \mathbf{if}\;\frac{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) - \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)}}{\left(4 \cdot A\right) \cdot C - {B}^{2}} \leq -2 \cdot 10^{-204}:\\ \;\;\;\;\frac{\sqrt{F \cdot \left(A + \left(C - \mathsf{hypot}\left(B, A - C\right)\right)\right)} \cdot \sqrt{2 \cdot \mathsf{fma}\left(C, A \cdot -4, {B}^{2}\right)}}{-\mathsf{fma}\left(C, A \cdot -4, {B}^{2}\right)}\\ \mathbf{elif}\;\frac{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) - \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)}}{\left(4 \cdot A\right) \cdot C - {B}^{2}} \leq \infty:\\ \;\;\;\;\frac{\sqrt{\left(F \cdot \mathsf{fma}\left(B, B, A \cdot \left(C \cdot -4\right)\right)\right) \cdot \left(2 \cdot \left(A + \left(A + -0.5 \cdot \frac{{B}^{2}}{C}\right)\right)\right)}}{-\mathsf{fma}\left(B, B, A \cdot \left(C \cdot -4\right)\right)}\\ \mathbf{else}:\\ \;\;\;\;\frac{\sqrt{2}}{B} \cdot \left(-e^{0.5 \cdot \left(\log \left(\mathsf{hypot}\left(B, A\right) - A\right) - \log \left(\frac{-1}{F}\right)\right)}\right)\\ \end{array} \]
  5. Add Preprocessing

Alternative 3: 54.2% accurate, 0.9× speedup?

\[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} t_0 := \mathsf{fma}\left(B\_m, B\_m, A \cdot \left(C \cdot -4\right)\right)\\ \mathbf{if}\;{B\_m}^{2} \leq 2 \cdot 10^{+39}:\\ \;\;\;\;\frac{\sqrt{\left(F \cdot t\_0\right) \cdot \left(2 \cdot \left(A + \left(A + -0.5 \cdot \frac{{B\_m}^{2}}{C}\right)\right)\right)}}{-t\_0}\\ \mathbf{else}:\\ \;\;\;\;\frac{\sqrt{2}}{B\_m} \cdot \left(-{\left(e^{0.5}\right)}^{\left(\log \left(\mathsf{hypot}\left(A, B\_m\right) - A\right) - \log \left(\frac{-1}{F}\right)\right)}\right)\\ \end{array} \end{array} \]
B_m = (fabs.f64 B)
NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
(FPCore (A B_m C F)
 :precision binary64
 (let* ((t_0 (fma B_m B_m (* A (* C -4.0)))))
   (if (<= (pow B_m 2.0) 2e+39)
     (/
      (sqrt (* (* F t_0) (* 2.0 (+ A (+ A (* -0.5 (/ (pow B_m 2.0) C)))))))
      (- t_0))
     (*
      (/ (sqrt 2.0) B_m)
      (- (pow (exp 0.5) (- (log (- (hypot A B_m) A)) (log (/ -1.0 F)))))))))
B_m = fabs(B);
assert(A < B_m && B_m < C && C < F);
double code(double A, double B_m, double C, double F) {
	double t_0 = fma(B_m, B_m, (A * (C * -4.0)));
	double tmp;
	if (pow(B_m, 2.0) <= 2e+39) {
		tmp = sqrt(((F * t_0) * (2.0 * (A + (A + (-0.5 * (pow(B_m, 2.0) / C))))))) / -t_0;
	} else {
		tmp = (sqrt(2.0) / B_m) * -pow(exp(0.5), (log((hypot(A, B_m) - A)) - log((-1.0 / F))));
	}
	return tmp;
}
B_m = abs(B)
A, B_m, C, F = sort([A, B_m, C, F])
function code(A, B_m, C, F)
	t_0 = fma(B_m, B_m, Float64(A * Float64(C * -4.0)))
	tmp = 0.0
	if ((B_m ^ 2.0) <= 2e+39)
		tmp = Float64(sqrt(Float64(Float64(F * t_0) * Float64(2.0 * Float64(A + Float64(A + Float64(-0.5 * Float64((B_m ^ 2.0) / C))))))) / Float64(-t_0));
	else
		tmp = Float64(Float64(sqrt(2.0) / B_m) * Float64(-(exp(0.5) ^ Float64(log(Float64(hypot(A, B_m) - A)) - log(Float64(-1.0 / F))))));
	end
	return tmp
end
B_m = N[Abs[B], $MachinePrecision]
NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
code[A_, B$95$m_, C_, F_] := Block[{t$95$0 = N[(B$95$m * B$95$m + N[(A * N[(C * -4.0), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[N[Power[B$95$m, 2.0], $MachinePrecision], 2e+39], N[(N[Sqrt[N[(N[(F * t$95$0), $MachinePrecision] * N[(2.0 * N[(A + N[(A + N[(-0.5 * N[(N[Power[B$95$m, 2.0], $MachinePrecision] / C), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / (-t$95$0)), $MachinePrecision], N[(N[(N[Sqrt[2.0], $MachinePrecision] / B$95$m), $MachinePrecision] * (-N[Power[N[Exp[0.5], $MachinePrecision], N[(N[Log[N[(N[Sqrt[A ^ 2 + B$95$m ^ 2], $MachinePrecision] - A), $MachinePrecision]], $MachinePrecision] - N[Log[N[(-1.0 / F), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]], $MachinePrecision])), $MachinePrecision]]]
\begin{array}{l}
B_m = \left|B\right|
\\
[A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
\\
\begin{array}{l}
t_0 := \mathsf{fma}\left(B\_m, B\_m, A \cdot \left(C \cdot -4\right)\right)\\
\mathbf{if}\;{B\_m}^{2} \leq 2 \cdot 10^{+39}:\\
\;\;\;\;\frac{\sqrt{\left(F \cdot t\_0\right) \cdot \left(2 \cdot \left(A + \left(A + -0.5 \cdot \frac{{B\_m}^{2}}{C}\right)\right)\right)}}{-t\_0}\\

\mathbf{else}:\\
\;\;\;\;\frac{\sqrt{2}}{B\_m} \cdot \left(-{\left(e^{0.5}\right)}^{\left(\log \left(\mathsf{hypot}\left(A, B\_m\right) - A\right) - \log \left(\frac{-1}{F}\right)\right)}\right)\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if (pow.f64 B #s(literal 2 binary64)) < 1.99999999999999988e39

    1. Initial program 25.3%

      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    2. Simplified35.0%

      \[\leadsto \color{blue}{\frac{\sqrt{\left(\mathsf{fma}\left(B, B, A \cdot \left(C \cdot -4\right)\right) \cdot F\right) \cdot \left(2 \cdot \left(A + \left(C - \mathsf{hypot}\left(B, A - C\right)\right)\right)\right)}}{-\mathsf{fma}\left(B, B, A \cdot \left(C \cdot -4\right)\right)}} \]
    3. Add Preprocessing
    4. Taylor expanded in C around inf 24.4%

      \[\leadsto \frac{\sqrt{\left(\mathsf{fma}\left(B, B, A \cdot \left(C \cdot -4\right)\right) \cdot F\right) \cdot \left(2 \cdot \left(A + \color{blue}{\left(-0.5 \cdot \frac{{B}^{2}}{C} - -1 \cdot A\right)}\right)\right)}}{-\mathsf{fma}\left(B, B, A \cdot \left(C \cdot -4\right)\right)} \]
    5. Step-by-step derivation
      1. mul-1-neg24.4%

        \[\leadsto \frac{\sqrt{\left(\mathsf{fma}\left(B, B, A \cdot \left(C \cdot -4\right)\right) \cdot F\right) \cdot \left(2 \cdot \left(A + \left(-0.5 \cdot \frac{{B}^{2}}{C} - \color{blue}{\left(-A\right)}\right)\right)\right)}}{-\mathsf{fma}\left(B, B, A \cdot \left(C \cdot -4\right)\right)} \]
    6. Simplified24.4%

      \[\leadsto \frac{\sqrt{\left(\mathsf{fma}\left(B, B, A \cdot \left(C \cdot -4\right)\right) \cdot F\right) \cdot \left(2 \cdot \left(A + \color{blue}{\left(-0.5 \cdot \frac{{B}^{2}}{C} - \left(-A\right)\right)}\right)\right)}}{-\mathsf{fma}\left(B, B, A \cdot \left(C \cdot -4\right)\right)} \]

    if 1.99999999999999988e39 < (pow.f64 B #s(literal 2 binary64))

    1. Initial program 20.4%

      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    2. Add Preprocessing
    3. Taylor expanded in C around 0 15.8%

      \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}\right)} \]
    4. Step-by-step derivation
      1. mul-1-neg15.8%

        \[\leadsto \color{blue}{-\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}} \]
      2. +-commutative15.8%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{\color{blue}{{B}^{2} + {A}^{2}}}\right)} \]
    5. Simplified15.8%

      \[\leadsto \color{blue}{-\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{{B}^{2} + {A}^{2}}\right)}} \]
    6. Step-by-step derivation
      1. pow1/215.8%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot \color{blue}{{\left(F \cdot \left(A - \sqrt{{B}^{2} + {A}^{2}}\right)\right)}^{0.5}} \]
      2. pow-to-exp14.9%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot \color{blue}{e^{\log \left(F \cdot \left(A - \sqrt{{B}^{2} + {A}^{2}}\right)\right) \cdot 0.5}} \]
      3. unpow214.9%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{\log \left(F \cdot \left(A - \sqrt{\color{blue}{B \cdot B} + {A}^{2}}\right)\right) \cdot 0.5} \]
      4. unpow214.9%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{\log \left(F \cdot \left(A - \sqrt{B \cdot B + \color{blue}{A \cdot A}}\right)\right) \cdot 0.5} \]
      5. hypot-undefine30.3%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{\log \left(F \cdot \left(A - \color{blue}{\mathsf{hypot}\left(B, A\right)}\right)\right) \cdot 0.5} \]
    7. Applied egg-rr30.3%

      \[\leadsto -\frac{\sqrt{2}}{B} \cdot \color{blue}{e^{\log \left(F \cdot \left(A - \mathsf{hypot}\left(B, A\right)\right)\right) \cdot 0.5}} \]
    8. Taylor expanded in F around -inf 14.7%

      \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{\color{blue}{\left(\log \left(-1 \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)\right) + -1 \cdot \log \left(\frac{-1}{F}\right)\right)} \cdot 0.5} \]
    9. Step-by-step derivation
      1. mul-1-neg14.7%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{\left(\log \left(-1 \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)\right) + \color{blue}{\left(-\log \left(\frac{-1}{F}\right)\right)}\right) \cdot 0.5} \]
      2. unsub-neg14.7%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{\color{blue}{\left(\log \left(-1 \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)\right) - \log \left(\frac{-1}{F}\right)\right)} \cdot 0.5} \]
      3. mul-1-neg14.7%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{\left(\log \color{blue}{\left(-\left(A - \sqrt{{A}^{2} + {B}^{2}}\right)\right)} - \log \left(\frac{-1}{F}\right)\right) \cdot 0.5} \]
      4. +-commutative14.7%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{\left(\log \left(-\left(A - \sqrt{\color{blue}{{B}^{2} + {A}^{2}}}\right)\right) - \log \left(\frac{-1}{F}\right)\right) \cdot 0.5} \]
      5. unpow214.7%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{\left(\log \left(-\left(A - \sqrt{\color{blue}{B \cdot B} + {A}^{2}}\right)\right) - \log \left(\frac{-1}{F}\right)\right) \cdot 0.5} \]
      6. unpow214.7%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{\left(\log \left(-\left(A - \sqrt{B \cdot B + \color{blue}{A \cdot A}}\right)\right) - \log \left(\frac{-1}{F}\right)\right) \cdot 0.5} \]
      7. hypot-undefine38.3%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{\left(\log \left(-\left(A - \color{blue}{\mathsf{hypot}\left(B, A\right)}\right)\right) - \log \left(\frac{-1}{F}\right)\right) \cdot 0.5} \]
    10. Simplified38.3%

      \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{\color{blue}{\left(\log \left(-\left(A - \mathsf{hypot}\left(B, A\right)\right)\right) - \log \left(\frac{-1}{F}\right)\right)} \cdot 0.5} \]
    11. Taylor expanded in F around -inf 14.7%

      \[\leadsto \color{blue}{-1 \cdot \frac{e^{0.5 \cdot \left(\log \left(\sqrt{{A}^{2} + {B}^{2}} - A\right) - \log \left(\frac{-1}{F}\right)\right)} \cdot \sqrt{2}}{B}} \]
    12. Step-by-step derivation
      1. mul-1-neg14.7%

        \[\leadsto \color{blue}{-\frac{e^{0.5 \cdot \left(\log \left(\sqrt{{A}^{2} + {B}^{2}} - A\right) - \log \left(\frac{-1}{F}\right)\right)} \cdot \sqrt{2}}{B}} \]
      2. associate-/l*14.7%

        \[\leadsto -\color{blue}{e^{0.5 \cdot \left(\log \left(\sqrt{{A}^{2} + {B}^{2}} - A\right) - \log \left(\frac{-1}{F}\right)\right)} \cdot \frac{\sqrt{2}}{B}} \]
      3. distribute-lft-neg-in14.7%

        \[\leadsto \color{blue}{\left(-e^{0.5 \cdot \left(\log \left(\sqrt{{A}^{2} + {B}^{2}} - A\right) - \log \left(\frac{-1}{F}\right)\right)}\right) \cdot \frac{\sqrt{2}}{B}} \]
    13. Simplified38.3%

      \[\leadsto \color{blue}{\left(-{\left(e^{0.5}\right)}^{\left(\log \left(\mathsf{hypot}\left(A, B\right) - A\right) - \log \left(\frac{-1}{F}\right)\right)}\right) \cdot \frac{\sqrt{2}}{B}} \]
  3. Recombined 2 regimes into one program.
  4. Final simplification30.1%

    \[\leadsto \begin{array}{l} \mathbf{if}\;{B}^{2} \leq 2 \cdot 10^{+39}:\\ \;\;\;\;\frac{\sqrt{\left(F \cdot \mathsf{fma}\left(B, B, A \cdot \left(C \cdot -4\right)\right)\right) \cdot \left(2 \cdot \left(A + \left(A + -0.5 \cdot \frac{{B}^{2}}{C}\right)\right)\right)}}{-\mathsf{fma}\left(B, B, A \cdot \left(C \cdot -4\right)\right)}\\ \mathbf{else}:\\ \;\;\;\;\frac{\sqrt{2}}{B} \cdot \left(-{\left(e^{0.5}\right)}^{\left(\log \left(\mathsf{hypot}\left(A, B\right) - A\right) - \log \left(\frac{-1}{F}\right)\right)}\right)\\ \end{array} \]
  5. Add Preprocessing

Alternative 4: 54.4% accurate, 1.0× speedup?

\[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} t_0 := \mathsf{fma}\left(B\_m, B\_m, A \cdot \left(C \cdot -4\right)\right)\\ \mathbf{if}\;{B\_m}^{2} \leq 2 \cdot 10^{+39}:\\ \;\;\;\;\frac{\sqrt{\left(F \cdot t\_0\right) \cdot \left(2 \cdot \left(A + \left(A + -0.5 \cdot \frac{{B\_m}^{2}}{C}\right)\right)\right)}}{-t\_0}\\ \mathbf{else}:\\ \;\;\;\;\frac{\sqrt{2}}{B\_m} \cdot \left(-e^{0.5 \cdot \left(\log \left(\mathsf{hypot}\left(B\_m, A\right) - A\right) - \log \left(\frac{-1}{F}\right)\right)}\right)\\ \end{array} \end{array} \]
B_m = (fabs.f64 B)
NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
(FPCore (A B_m C F)
 :precision binary64
 (let* ((t_0 (fma B_m B_m (* A (* C -4.0)))))
   (if (<= (pow B_m 2.0) 2e+39)
     (/
      (sqrt (* (* F t_0) (* 2.0 (+ A (+ A (* -0.5 (/ (pow B_m 2.0) C)))))))
      (- t_0))
     (*
      (/ (sqrt 2.0) B_m)
      (- (exp (* 0.5 (- (log (- (hypot B_m A) A)) (log (/ -1.0 F))))))))))
B_m = fabs(B);
assert(A < B_m && B_m < C && C < F);
double code(double A, double B_m, double C, double F) {
	double t_0 = fma(B_m, B_m, (A * (C * -4.0)));
	double tmp;
	if (pow(B_m, 2.0) <= 2e+39) {
		tmp = sqrt(((F * t_0) * (2.0 * (A + (A + (-0.5 * (pow(B_m, 2.0) / C))))))) / -t_0;
	} else {
		tmp = (sqrt(2.0) / B_m) * -exp((0.5 * (log((hypot(B_m, A) - A)) - log((-1.0 / F)))));
	}
	return tmp;
}
B_m = abs(B)
A, B_m, C, F = sort([A, B_m, C, F])
function code(A, B_m, C, F)
	t_0 = fma(B_m, B_m, Float64(A * Float64(C * -4.0)))
	tmp = 0.0
	if ((B_m ^ 2.0) <= 2e+39)
		tmp = Float64(sqrt(Float64(Float64(F * t_0) * Float64(2.0 * Float64(A + Float64(A + Float64(-0.5 * Float64((B_m ^ 2.0) / C))))))) / Float64(-t_0));
	else
		tmp = Float64(Float64(sqrt(2.0) / B_m) * Float64(-exp(Float64(0.5 * Float64(log(Float64(hypot(B_m, A) - A)) - log(Float64(-1.0 / F)))))));
	end
	return tmp
end
B_m = N[Abs[B], $MachinePrecision]
NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
code[A_, B$95$m_, C_, F_] := Block[{t$95$0 = N[(B$95$m * B$95$m + N[(A * N[(C * -4.0), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[N[Power[B$95$m, 2.0], $MachinePrecision], 2e+39], N[(N[Sqrt[N[(N[(F * t$95$0), $MachinePrecision] * N[(2.0 * N[(A + N[(A + N[(-0.5 * N[(N[Power[B$95$m, 2.0], $MachinePrecision] / C), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / (-t$95$0)), $MachinePrecision], N[(N[(N[Sqrt[2.0], $MachinePrecision] / B$95$m), $MachinePrecision] * (-N[Exp[N[(0.5 * N[(N[Log[N[(N[Sqrt[B$95$m ^ 2 + A ^ 2], $MachinePrecision] - A), $MachinePrecision]], $MachinePrecision] - N[Log[N[(-1.0 / F), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision])), $MachinePrecision]]]
\begin{array}{l}
B_m = \left|B\right|
\\
[A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
\\
\begin{array}{l}
t_0 := \mathsf{fma}\left(B\_m, B\_m, A \cdot \left(C \cdot -4\right)\right)\\
\mathbf{if}\;{B\_m}^{2} \leq 2 \cdot 10^{+39}:\\
\;\;\;\;\frac{\sqrt{\left(F \cdot t\_0\right) \cdot \left(2 \cdot \left(A + \left(A + -0.5 \cdot \frac{{B\_m}^{2}}{C}\right)\right)\right)}}{-t\_0}\\

\mathbf{else}:\\
\;\;\;\;\frac{\sqrt{2}}{B\_m} \cdot \left(-e^{0.5 \cdot \left(\log \left(\mathsf{hypot}\left(B\_m, A\right) - A\right) - \log \left(\frac{-1}{F}\right)\right)}\right)\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if (pow.f64 B #s(literal 2 binary64)) < 1.99999999999999988e39

    1. Initial program 25.3%

      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    2. Simplified35.0%

      \[\leadsto \color{blue}{\frac{\sqrt{\left(\mathsf{fma}\left(B, B, A \cdot \left(C \cdot -4\right)\right) \cdot F\right) \cdot \left(2 \cdot \left(A + \left(C - \mathsf{hypot}\left(B, A - C\right)\right)\right)\right)}}{-\mathsf{fma}\left(B, B, A \cdot \left(C \cdot -4\right)\right)}} \]
    3. Add Preprocessing
    4. Taylor expanded in C around inf 24.4%

      \[\leadsto \frac{\sqrt{\left(\mathsf{fma}\left(B, B, A \cdot \left(C \cdot -4\right)\right) \cdot F\right) \cdot \left(2 \cdot \left(A + \color{blue}{\left(-0.5 \cdot \frac{{B}^{2}}{C} - -1 \cdot A\right)}\right)\right)}}{-\mathsf{fma}\left(B, B, A \cdot \left(C \cdot -4\right)\right)} \]
    5. Step-by-step derivation
      1. mul-1-neg24.4%

        \[\leadsto \frac{\sqrt{\left(\mathsf{fma}\left(B, B, A \cdot \left(C \cdot -4\right)\right) \cdot F\right) \cdot \left(2 \cdot \left(A + \left(-0.5 \cdot \frac{{B}^{2}}{C} - \color{blue}{\left(-A\right)}\right)\right)\right)}}{-\mathsf{fma}\left(B, B, A \cdot \left(C \cdot -4\right)\right)} \]
    6. Simplified24.4%

      \[\leadsto \frac{\sqrt{\left(\mathsf{fma}\left(B, B, A \cdot \left(C \cdot -4\right)\right) \cdot F\right) \cdot \left(2 \cdot \left(A + \color{blue}{\left(-0.5 \cdot \frac{{B}^{2}}{C} - \left(-A\right)\right)}\right)\right)}}{-\mathsf{fma}\left(B, B, A \cdot \left(C \cdot -4\right)\right)} \]

    if 1.99999999999999988e39 < (pow.f64 B #s(literal 2 binary64))

    1. Initial program 20.4%

      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    2. Add Preprocessing
    3. Taylor expanded in C around 0 15.8%

      \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}\right)} \]
    4. Step-by-step derivation
      1. mul-1-neg15.8%

        \[\leadsto \color{blue}{-\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}} \]
      2. +-commutative15.8%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{\color{blue}{{B}^{2} + {A}^{2}}}\right)} \]
    5. Simplified15.8%

      \[\leadsto \color{blue}{-\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{{B}^{2} + {A}^{2}}\right)}} \]
    6. Step-by-step derivation
      1. pow1/215.8%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot \color{blue}{{\left(F \cdot \left(A - \sqrt{{B}^{2} + {A}^{2}}\right)\right)}^{0.5}} \]
      2. pow-to-exp14.9%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot \color{blue}{e^{\log \left(F \cdot \left(A - \sqrt{{B}^{2} + {A}^{2}}\right)\right) \cdot 0.5}} \]
      3. unpow214.9%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{\log \left(F \cdot \left(A - \sqrt{\color{blue}{B \cdot B} + {A}^{2}}\right)\right) \cdot 0.5} \]
      4. unpow214.9%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{\log \left(F \cdot \left(A - \sqrt{B \cdot B + \color{blue}{A \cdot A}}\right)\right) \cdot 0.5} \]
      5. hypot-undefine30.3%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{\log \left(F \cdot \left(A - \color{blue}{\mathsf{hypot}\left(B, A\right)}\right)\right) \cdot 0.5} \]
    7. Applied egg-rr30.3%

      \[\leadsto -\frac{\sqrt{2}}{B} \cdot \color{blue}{e^{\log \left(F \cdot \left(A - \mathsf{hypot}\left(B, A\right)\right)\right) \cdot 0.5}} \]
    8. Taylor expanded in F around -inf 14.7%

      \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{\color{blue}{\left(\log \left(-1 \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)\right) + -1 \cdot \log \left(\frac{-1}{F}\right)\right)} \cdot 0.5} \]
    9. Step-by-step derivation
      1. mul-1-neg14.7%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{\left(\log \left(-1 \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)\right) + \color{blue}{\left(-\log \left(\frac{-1}{F}\right)\right)}\right) \cdot 0.5} \]
      2. unsub-neg14.7%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{\color{blue}{\left(\log \left(-1 \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)\right) - \log \left(\frac{-1}{F}\right)\right)} \cdot 0.5} \]
      3. mul-1-neg14.7%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{\left(\log \color{blue}{\left(-\left(A - \sqrt{{A}^{2} + {B}^{2}}\right)\right)} - \log \left(\frac{-1}{F}\right)\right) \cdot 0.5} \]
      4. +-commutative14.7%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{\left(\log \left(-\left(A - \sqrt{\color{blue}{{B}^{2} + {A}^{2}}}\right)\right) - \log \left(\frac{-1}{F}\right)\right) \cdot 0.5} \]
      5. unpow214.7%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{\left(\log \left(-\left(A - \sqrt{\color{blue}{B \cdot B} + {A}^{2}}\right)\right) - \log \left(\frac{-1}{F}\right)\right) \cdot 0.5} \]
      6. unpow214.7%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{\left(\log \left(-\left(A - \sqrt{B \cdot B + \color{blue}{A \cdot A}}\right)\right) - \log \left(\frac{-1}{F}\right)\right) \cdot 0.5} \]
      7. hypot-undefine38.3%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{\left(\log \left(-\left(A - \color{blue}{\mathsf{hypot}\left(B, A\right)}\right)\right) - \log \left(\frac{-1}{F}\right)\right) \cdot 0.5} \]
    10. Simplified38.3%

      \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{\color{blue}{\left(\log \left(-\left(A - \mathsf{hypot}\left(B, A\right)\right)\right) - \log \left(\frac{-1}{F}\right)\right)} \cdot 0.5} \]
    11. Taylor expanded in F around -inf 14.7%

      \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{\color{blue}{0.5 \cdot \left(\log \left(\sqrt{{A}^{2} + {B}^{2}} - A\right) - \log \left(\frac{-1}{F}\right)\right)}} \]
    12. Step-by-step derivation
      1. +-commutative14.7%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{0.5 \cdot \left(\log \left(\sqrt{\color{blue}{{B}^{2} + {A}^{2}}} - A\right) - \log \left(\frac{-1}{F}\right)\right)} \]
      2. unpow214.7%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{0.5 \cdot \left(\log \left(\sqrt{\color{blue}{B \cdot B} + {A}^{2}} - A\right) - \log \left(\frac{-1}{F}\right)\right)} \]
      3. unpow214.7%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{0.5 \cdot \left(\log \left(\sqrt{B \cdot B + \color{blue}{A \cdot A}} - A\right) - \log \left(\frac{-1}{F}\right)\right)} \]
      4. hypot-undefine38.3%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{0.5 \cdot \left(\log \left(\color{blue}{\mathsf{hypot}\left(B, A\right)} - A\right) - \log \left(\frac{-1}{F}\right)\right)} \]
    13. Simplified38.3%

      \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{\color{blue}{0.5 \cdot \left(\log \left(\mathsf{hypot}\left(B, A\right) - A\right) - \log \left(\frac{-1}{F}\right)\right)}} \]
  3. Recombined 2 regimes into one program.
  4. Final simplification30.1%

    \[\leadsto \begin{array}{l} \mathbf{if}\;{B}^{2} \leq 2 \cdot 10^{+39}:\\ \;\;\;\;\frac{\sqrt{\left(F \cdot \mathsf{fma}\left(B, B, A \cdot \left(C \cdot -4\right)\right)\right) \cdot \left(2 \cdot \left(A + \left(A + -0.5 \cdot \frac{{B}^{2}}{C}\right)\right)\right)}}{-\mathsf{fma}\left(B, B, A \cdot \left(C \cdot -4\right)\right)}\\ \mathbf{else}:\\ \;\;\;\;\frac{\sqrt{2}}{B} \cdot \left(-e^{0.5 \cdot \left(\log \left(\mathsf{hypot}\left(B, A\right) - A\right) - \log \left(\frac{-1}{F}\right)\right)}\right)\\ \end{array} \]
  5. Add Preprocessing

Alternative 5: 50.6% accurate, 1.5× speedup?

\[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} t_0 := \mathsf{fma}\left(B\_m, B\_m, A \cdot \left(C \cdot -4\right)\right)\\ \mathbf{if}\;B\_m \leq 3.5 \cdot 10^{+21}:\\ \;\;\;\;\frac{\sqrt{\left(F \cdot t\_0\right) \cdot \left(2 \cdot \left(A + \left(A + -0.5 \cdot \frac{{B\_m}^{2}}{C}\right)\right)\right)}}{-t\_0}\\ \mathbf{elif}\;B\_m \leq 1.65 \cdot 10^{+205}:\\ \;\;\;\;\frac{-1}{B\_m} \cdot \sqrt{2 \cdot \left(F \cdot \left(A - \mathsf{hypot}\left(B\_m, A\right)\right)\right)}\\ \mathbf{else}:\\ \;\;\;\;e^{0.5 \cdot \left(\log \left(-F\right) + \left(\log B\_m - \frac{A}{B\_m}\right)\right)} \cdot \frac{\sqrt{2}}{-B\_m}\\ \end{array} \end{array} \]
B_m = (fabs.f64 B)
NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
(FPCore (A B_m C F)
 :precision binary64
 (let* ((t_0 (fma B_m B_m (* A (* C -4.0)))))
   (if (<= B_m 3.5e+21)
     (/
      (sqrt (* (* F t_0) (* 2.0 (+ A (+ A (* -0.5 (/ (pow B_m 2.0) C)))))))
      (- t_0))
     (if (<= B_m 1.65e+205)
       (* (/ -1.0 B_m) (sqrt (* 2.0 (* F (- A (hypot B_m A))))))
       (*
        (exp (* 0.5 (+ (log (- F)) (- (log B_m) (/ A B_m)))))
        (/ (sqrt 2.0) (- B_m)))))))
B_m = fabs(B);
assert(A < B_m && B_m < C && C < F);
double code(double A, double B_m, double C, double F) {
	double t_0 = fma(B_m, B_m, (A * (C * -4.0)));
	double tmp;
	if (B_m <= 3.5e+21) {
		tmp = sqrt(((F * t_0) * (2.0 * (A + (A + (-0.5 * (pow(B_m, 2.0) / C))))))) / -t_0;
	} else if (B_m <= 1.65e+205) {
		tmp = (-1.0 / B_m) * sqrt((2.0 * (F * (A - hypot(B_m, A)))));
	} else {
		tmp = exp((0.5 * (log(-F) + (log(B_m) - (A / B_m))))) * (sqrt(2.0) / -B_m);
	}
	return tmp;
}
B_m = abs(B)
A, B_m, C, F = sort([A, B_m, C, F])
function code(A, B_m, C, F)
	t_0 = fma(B_m, B_m, Float64(A * Float64(C * -4.0)))
	tmp = 0.0
	if (B_m <= 3.5e+21)
		tmp = Float64(sqrt(Float64(Float64(F * t_0) * Float64(2.0 * Float64(A + Float64(A + Float64(-0.5 * Float64((B_m ^ 2.0) / C))))))) / Float64(-t_0));
	elseif (B_m <= 1.65e+205)
		tmp = Float64(Float64(-1.0 / B_m) * sqrt(Float64(2.0 * Float64(F * Float64(A - hypot(B_m, A))))));
	else
		tmp = Float64(exp(Float64(0.5 * Float64(log(Float64(-F)) + Float64(log(B_m) - Float64(A / B_m))))) * Float64(sqrt(2.0) / Float64(-B_m)));
	end
	return tmp
end
B_m = N[Abs[B], $MachinePrecision]
NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
code[A_, B$95$m_, C_, F_] := Block[{t$95$0 = N[(B$95$m * B$95$m + N[(A * N[(C * -4.0), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[B$95$m, 3.5e+21], N[(N[Sqrt[N[(N[(F * t$95$0), $MachinePrecision] * N[(2.0 * N[(A + N[(A + N[(-0.5 * N[(N[Power[B$95$m, 2.0], $MachinePrecision] / C), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / (-t$95$0)), $MachinePrecision], If[LessEqual[B$95$m, 1.65e+205], N[(N[(-1.0 / B$95$m), $MachinePrecision] * N[Sqrt[N[(2.0 * N[(F * N[(A - N[Sqrt[B$95$m ^ 2 + A ^ 2], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision], N[(N[Exp[N[(0.5 * N[(N[Log[(-F)], $MachinePrecision] + N[(N[Log[B$95$m], $MachinePrecision] - N[(A / B$95$m), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] * N[(N[Sqrt[2.0], $MachinePrecision] / (-B$95$m)), $MachinePrecision]), $MachinePrecision]]]]
\begin{array}{l}
B_m = \left|B\right|
\\
[A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
\\
\begin{array}{l}
t_0 := \mathsf{fma}\left(B\_m, B\_m, A \cdot \left(C \cdot -4\right)\right)\\
\mathbf{if}\;B\_m \leq 3.5 \cdot 10^{+21}:\\
\;\;\;\;\frac{\sqrt{\left(F \cdot t\_0\right) \cdot \left(2 \cdot \left(A + \left(A + -0.5 \cdot \frac{{B\_m}^{2}}{C}\right)\right)\right)}}{-t\_0}\\

\mathbf{elif}\;B\_m \leq 1.65 \cdot 10^{+205}:\\
\;\;\;\;\frac{-1}{B\_m} \cdot \sqrt{2 \cdot \left(F \cdot \left(A - \mathsf{hypot}\left(B\_m, A\right)\right)\right)}\\

\mathbf{else}:\\
\;\;\;\;e^{0.5 \cdot \left(\log \left(-F\right) + \left(\log B\_m - \frac{A}{B\_m}\right)\right)} \cdot \frac{\sqrt{2}}{-B\_m}\\


\end{array}
\end{array}
Derivation
  1. Split input into 3 regimes
  2. if B < 3.5e21

    1. Initial program 26.1%

      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    2. Simplified33.8%

      \[\leadsto \color{blue}{\frac{\sqrt{\left(\mathsf{fma}\left(B, B, A \cdot \left(C \cdot -4\right)\right) \cdot F\right) \cdot \left(2 \cdot \left(A + \left(C - \mathsf{hypot}\left(B, A - C\right)\right)\right)\right)}}{-\mathsf{fma}\left(B, B, A \cdot \left(C \cdot -4\right)\right)}} \]
    3. Add Preprocessing
    4. Taylor expanded in C around inf 20.3%

      \[\leadsto \frac{\sqrt{\left(\mathsf{fma}\left(B, B, A \cdot \left(C \cdot -4\right)\right) \cdot F\right) \cdot \left(2 \cdot \left(A + \color{blue}{\left(-0.5 \cdot \frac{{B}^{2}}{C} - -1 \cdot A\right)}\right)\right)}}{-\mathsf{fma}\left(B, B, A \cdot \left(C \cdot -4\right)\right)} \]
    5. Step-by-step derivation
      1. mul-1-neg20.3%

        \[\leadsto \frac{\sqrt{\left(\mathsf{fma}\left(B, B, A \cdot \left(C \cdot -4\right)\right) \cdot F\right) \cdot \left(2 \cdot \left(A + \left(-0.5 \cdot \frac{{B}^{2}}{C} - \color{blue}{\left(-A\right)}\right)\right)\right)}}{-\mathsf{fma}\left(B, B, A \cdot \left(C \cdot -4\right)\right)} \]
    6. Simplified20.3%

      \[\leadsto \frac{\sqrt{\left(\mathsf{fma}\left(B, B, A \cdot \left(C \cdot -4\right)\right) \cdot F\right) \cdot \left(2 \cdot \left(A + \color{blue}{\left(-0.5 \cdot \frac{{B}^{2}}{C} - \left(-A\right)\right)}\right)\right)}}{-\mathsf{fma}\left(B, B, A \cdot \left(C \cdot -4\right)\right)} \]

    if 3.5e21 < B < 1.6500000000000001e205

    1. Initial program 22.9%

      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    2. Add Preprocessing
    3. Taylor expanded in C around 0 38.0%

      \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}\right)} \]
    4. Step-by-step derivation
      1. mul-1-neg38.0%

        \[\leadsto \color{blue}{-\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}} \]
      2. +-commutative38.0%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{\color{blue}{{B}^{2} + {A}^{2}}}\right)} \]
      3. unpow238.0%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{\color{blue}{B \cdot B} + {A}^{2}}\right)} \]
      4. unpow238.0%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{B \cdot B + \color{blue}{A \cdot A}}\right)} \]
      5. hypot-define48.5%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \color{blue}{\mathsf{hypot}\left(B, A\right)}\right)} \]
    5. Simplified48.5%

      \[\leadsto \color{blue}{-\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \mathsf{hypot}\left(B, A\right)\right)}} \]
    6. Step-by-step derivation
      1. div-inv48.4%

        \[\leadsto -\color{blue}{\left(\sqrt{2} \cdot \frac{1}{B}\right)} \cdot \sqrt{F \cdot \left(A - \mathsf{hypot}\left(B, A\right)\right)} \]
    7. Applied egg-rr48.4%

      \[\leadsto -\color{blue}{\left(\sqrt{2} \cdot \frac{1}{B}\right)} \cdot \sqrt{F \cdot \left(A - \mathsf{hypot}\left(B, A\right)\right)} \]
    8. Step-by-step derivation
      1. pow1/248.4%

        \[\leadsto -\left(\sqrt{2} \cdot \frac{1}{B}\right) \cdot \color{blue}{{\left(F \cdot \left(A - \mathsf{hypot}\left(B, A\right)\right)\right)}^{0.5}} \]
      2. exp-to-pow45.3%

        \[\leadsto -\left(\sqrt{2} \cdot \frac{1}{B}\right) \cdot \color{blue}{e^{\log \left(F \cdot \left(A - \mathsf{hypot}\left(B, A\right)\right)\right) \cdot 0.5}} \]
      3. div-inv45.3%

        \[\leadsto -\color{blue}{\frac{\sqrt{2}}{B}} \cdot e^{\log \left(F \cdot \left(A - \mathsf{hypot}\left(B, A\right)\right)\right) \cdot 0.5} \]
      4. associate-*l/45.3%

        \[\leadsto -\color{blue}{\frac{\sqrt{2} \cdot e^{\log \left(F \cdot \left(A - \mathsf{hypot}\left(B, A\right)\right)\right) \cdot 0.5}}{B}} \]
      5. exp-to-pow48.4%

        \[\leadsto -\frac{\sqrt{2} \cdot \color{blue}{{\left(F \cdot \left(A - \mathsf{hypot}\left(B, A\right)\right)\right)}^{0.5}}}{B} \]
      6. pow1/248.4%

        \[\leadsto -\frac{\sqrt{2} \cdot \color{blue}{\sqrt{F \cdot \left(A - \mathsf{hypot}\left(B, A\right)\right)}}}{B} \]
      7. sqrt-prod48.6%

        \[\leadsto -\frac{\color{blue}{\sqrt{2 \cdot \left(F \cdot \left(A - \mathsf{hypot}\left(B, A\right)\right)\right)}}}{B} \]
      8. distribute-frac-neg248.6%

        \[\leadsto \color{blue}{\frac{\sqrt{2 \cdot \left(F \cdot \left(A - \mathsf{hypot}\left(B, A\right)\right)\right)}}{-B}} \]
      9. clear-num48.6%

        \[\leadsto \color{blue}{\frac{1}{\frac{-B}{\sqrt{2 \cdot \left(F \cdot \left(A - \mathsf{hypot}\left(B, A\right)\right)\right)}}}} \]
      10. frac-2neg48.6%

        \[\leadsto \color{blue}{\frac{-1}{-\frac{-B}{\sqrt{2 \cdot \left(F \cdot \left(A - \mathsf{hypot}\left(B, A\right)\right)\right)}}}} \]
      11. metadata-eval48.6%

        \[\leadsto \frac{\color{blue}{-1}}{-\frac{-B}{\sqrt{2 \cdot \left(F \cdot \left(A - \mathsf{hypot}\left(B, A\right)\right)\right)}}} \]
    9. Applied egg-rr48.6%

      \[\leadsto \color{blue}{\frac{-1}{\frac{B}{\sqrt{F \cdot \left(\left(A - \mathsf{hypot}\left(B, A\right)\right) \cdot 2\right)}}}} \]
    10. Step-by-step derivation
      1. associate-/r/48.7%

        \[\leadsto \color{blue}{\frac{-1}{B} \cdot \sqrt{F \cdot \left(\left(A - \mathsf{hypot}\left(B, A\right)\right) \cdot 2\right)}} \]
      2. associate-*r*48.7%

        \[\leadsto \frac{-1}{B} \cdot \sqrt{\color{blue}{\left(F \cdot \left(A - \mathsf{hypot}\left(B, A\right)\right)\right) \cdot 2}} \]
      3. hypot-undefine38.1%

        \[\leadsto \frac{-1}{B} \cdot \sqrt{\left(F \cdot \left(A - \color{blue}{\sqrt{B \cdot B + A \cdot A}}\right)\right) \cdot 2} \]
      4. unpow238.1%

        \[\leadsto \frac{-1}{B} \cdot \sqrt{\left(F \cdot \left(A - \sqrt{\color{blue}{{B}^{2}} + A \cdot A}\right)\right) \cdot 2} \]
      5. unpow238.1%

        \[\leadsto \frac{-1}{B} \cdot \sqrt{\left(F \cdot \left(A - \sqrt{{B}^{2} + \color{blue}{{A}^{2}}}\right)\right) \cdot 2} \]
      6. +-commutative38.1%

        \[\leadsto \frac{-1}{B} \cdot \sqrt{\left(F \cdot \left(A - \sqrt{\color{blue}{{A}^{2} + {B}^{2}}}\right)\right) \cdot 2} \]
      7. *-commutative38.1%

        \[\leadsto \frac{-1}{B} \cdot \sqrt{\color{blue}{2 \cdot \left(F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)\right)}} \]
      8. +-commutative38.1%

        \[\leadsto \frac{-1}{B} \cdot \sqrt{2 \cdot \left(F \cdot \left(A - \sqrt{\color{blue}{{B}^{2} + {A}^{2}}}\right)\right)} \]
      9. unpow238.1%

        \[\leadsto \frac{-1}{B} \cdot \sqrt{2 \cdot \left(F \cdot \left(A - \sqrt{\color{blue}{B \cdot B} + {A}^{2}}\right)\right)} \]
      10. unpow238.1%

        \[\leadsto \frac{-1}{B} \cdot \sqrt{2 \cdot \left(F \cdot \left(A - \sqrt{B \cdot B + \color{blue}{A \cdot A}}\right)\right)} \]
      11. hypot-undefine48.7%

        \[\leadsto \frac{-1}{B} \cdot \sqrt{2 \cdot \left(F \cdot \left(A - \color{blue}{\mathsf{hypot}\left(B, A\right)}\right)\right)} \]
    11. Simplified48.7%

      \[\leadsto \color{blue}{\frac{-1}{B} \cdot \sqrt{2 \cdot \left(F \cdot \left(A - \mathsf{hypot}\left(B, A\right)\right)\right)}} \]

    if 1.6500000000000001e205 < B

    1. Initial program 0.0%

      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    2. Add Preprocessing
    3. Taylor expanded in C around 0 2.4%

      \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}\right)} \]
    4. Step-by-step derivation
      1. mul-1-neg2.4%

        \[\leadsto \color{blue}{-\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}} \]
      2. +-commutative2.4%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{\color{blue}{{B}^{2} + {A}^{2}}}\right)} \]
    5. Simplified2.4%

      \[\leadsto \color{blue}{-\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{{B}^{2} + {A}^{2}}\right)}} \]
    6. Step-by-step derivation
      1. pow1/22.4%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot \color{blue}{{\left(F \cdot \left(A - \sqrt{{B}^{2} + {A}^{2}}\right)\right)}^{0.5}} \]
      2. pow-to-exp2.4%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot \color{blue}{e^{\log \left(F \cdot \left(A - \sqrt{{B}^{2} + {A}^{2}}\right)\right) \cdot 0.5}} \]
      3. unpow22.4%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{\log \left(F \cdot \left(A - \sqrt{\color{blue}{B \cdot B} + {A}^{2}}\right)\right) \cdot 0.5} \]
      4. unpow22.4%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{\log \left(F \cdot \left(A - \sqrt{B \cdot B + \color{blue}{A \cdot A}}\right)\right) \cdot 0.5} \]
      5. hypot-undefine54.1%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{\log \left(F \cdot \left(A - \color{blue}{\mathsf{hypot}\left(B, A\right)}\right)\right) \cdot 0.5} \]
    7. Applied egg-rr54.1%

      \[\leadsto -\frac{\sqrt{2}}{B} \cdot \color{blue}{e^{\log \left(F \cdot \left(A - \mathsf{hypot}\left(B, A\right)\right)\right) \cdot 0.5}} \]
    8. Taylor expanded in B around inf 84.6%

      \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{\color{blue}{\left(\log \left(-1 \cdot F\right) + \left(-1 \cdot \log \left(\frac{1}{B}\right) + -1 \cdot \frac{A}{B}\right)\right)} \cdot 0.5} \]
    9. Step-by-step derivation
      1. neg-mul-184.6%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{\left(\log \color{blue}{\left(-F\right)} + \left(-1 \cdot \log \left(\frac{1}{B}\right) + -1 \cdot \frac{A}{B}\right)\right) \cdot 0.5} \]
      2. mul-1-neg84.6%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{\left(\log \left(-F\right) + \left(-1 \cdot \log \left(\frac{1}{B}\right) + \color{blue}{\left(-\frac{A}{B}\right)}\right)\right) \cdot 0.5} \]
      3. unsub-neg84.6%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{\left(\log \left(-F\right) + \color{blue}{\left(-1 \cdot \log \left(\frac{1}{B}\right) - \frac{A}{B}\right)}\right) \cdot 0.5} \]
      4. mul-1-neg84.6%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{\left(\log \left(-F\right) + \left(\color{blue}{\left(-\log \left(\frac{1}{B}\right)\right)} - \frac{A}{B}\right)\right) \cdot 0.5} \]
      5. log-rec84.6%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{\left(\log \left(-F\right) + \left(\color{blue}{\log \left(\frac{1}{\frac{1}{B}}\right)} - \frac{A}{B}\right)\right) \cdot 0.5} \]
      6. remove-double-div84.6%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{\left(\log \left(-F\right) + \left(\log \color{blue}{B} - \frac{A}{B}\right)\right) \cdot 0.5} \]
    10. Simplified84.6%

      \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{\color{blue}{\left(\log \left(-F\right) + \left(\log B - \frac{A}{B}\right)\right)} \cdot 0.5} \]
  3. Recombined 3 regimes into one program.
  4. Final simplification30.6%

    \[\leadsto \begin{array}{l} \mathbf{if}\;B \leq 3.5 \cdot 10^{+21}:\\ \;\;\;\;\frac{\sqrt{\left(F \cdot \mathsf{fma}\left(B, B, A \cdot \left(C \cdot -4\right)\right)\right) \cdot \left(2 \cdot \left(A + \left(A + -0.5 \cdot \frac{{B}^{2}}{C}\right)\right)\right)}}{-\mathsf{fma}\left(B, B, A \cdot \left(C \cdot -4\right)\right)}\\ \mathbf{elif}\;B \leq 1.65 \cdot 10^{+205}:\\ \;\;\;\;\frac{-1}{B} \cdot \sqrt{2 \cdot \left(F \cdot \left(A - \mathsf{hypot}\left(B, A\right)\right)\right)}\\ \mathbf{else}:\\ \;\;\;\;e^{0.5 \cdot \left(\log \left(-F\right) + \left(\log B - \frac{A}{B}\right)\right)} \cdot \frac{\sqrt{2}}{-B}\\ \end{array} \]
  5. Add Preprocessing

Alternative 6: 51.2% accurate, 1.5× speedup?

\[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} t_0 := \mathsf{fma}\left(B\_m, B\_m, A \cdot \left(C \cdot -4\right)\right)\\ \mathbf{if}\;B\_m \leq 4800:\\ \;\;\;\;\frac{\sqrt{\left(4 \cdot A\right) \cdot \left(F \cdot t\_0\right)}}{-t\_0}\\ \mathbf{elif}\;B\_m \leq 7.2 \cdot 10^{+204}:\\ \;\;\;\;\frac{{\left(2 \cdot \frac{\mathsf{hypot}\left(B\_m, A\right) - A}{\frac{-1}{F}}\right)}^{0.5}}{-B\_m}\\ \mathbf{else}:\\ \;\;\;\;e^{0.5 \cdot \left(\log \left(-F\right) + \left(\log B\_m - \frac{A}{B\_m}\right)\right)} \cdot \frac{\sqrt{2}}{-B\_m}\\ \end{array} \end{array} \]
B_m = (fabs.f64 B)
NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
(FPCore (A B_m C F)
 :precision binary64
 (let* ((t_0 (fma B_m B_m (* A (* C -4.0)))))
   (if (<= B_m 4800.0)
     (/ (sqrt (* (* 4.0 A) (* F t_0))) (- t_0))
     (if (<= B_m 7.2e+204)
       (/ (pow (* 2.0 (/ (- (hypot B_m A) A) (/ -1.0 F))) 0.5) (- B_m))
       (*
        (exp (* 0.5 (+ (log (- F)) (- (log B_m) (/ A B_m)))))
        (/ (sqrt 2.0) (- B_m)))))))
B_m = fabs(B);
assert(A < B_m && B_m < C && C < F);
double code(double A, double B_m, double C, double F) {
	double t_0 = fma(B_m, B_m, (A * (C * -4.0)));
	double tmp;
	if (B_m <= 4800.0) {
		tmp = sqrt(((4.0 * A) * (F * t_0))) / -t_0;
	} else if (B_m <= 7.2e+204) {
		tmp = pow((2.0 * ((hypot(B_m, A) - A) / (-1.0 / F))), 0.5) / -B_m;
	} else {
		tmp = exp((0.5 * (log(-F) + (log(B_m) - (A / B_m))))) * (sqrt(2.0) / -B_m);
	}
	return tmp;
}
B_m = abs(B)
A, B_m, C, F = sort([A, B_m, C, F])
function code(A, B_m, C, F)
	t_0 = fma(B_m, B_m, Float64(A * Float64(C * -4.0)))
	tmp = 0.0
	if (B_m <= 4800.0)
		tmp = Float64(sqrt(Float64(Float64(4.0 * A) * Float64(F * t_0))) / Float64(-t_0));
	elseif (B_m <= 7.2e+204)
		tmp = Float64((Float64(2.0 * Float64(Float64(hypot(B_m, A) - A) / Float64(-1.0 / F))) ^ 0.5) / Float64(-B_m));
	else
		tmp = Float64(exp(Float64(0.5 * Float64(log(Float64(-F)) + Float64(log(B_m) - Float64(A / B_m))))) * Float64(sqrt(2.0) / Float64(-B_m)));
	end
	return tmp
end
B_m = N[Abs[B], $MachinePrecision]
NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
code[A_, B$95$m_, C_, F_] := Block[{t$95$0 = N[(B$95$m * B$95$m + N[(A * N[(C * -4.0), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[B$95$m, 4800.0], N[(N[Sqrt[N[(N[(4.0 * A), $MachinePrecision] * N[(F * t$95$0), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / (-t$95$0)), $MachinePrecision], If[LessEqual[B$95$m, 7.2e+204], N[(N[Power[N[(2.0 * N[(N[(N[Sqrt[B$95$m ^ 2 + A ^ 2], $MachinePrecision] - A), $MachinePrecision] / N[(-1.0 / F), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], 0.5], $MachinePrecision] / (-B$95$m)), $MachinePrecision], N[(N[Exp[N[(0.5 * N[(N[Log[(-F)], $MachinePrecision] + N[(N[Log[B$95$m], $MachinePrecision] - N[(A / B$95$m), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] * N[(N[Sqrt[2.0], $MachinePrecision] / (-B$95$m)), $MachinePrecision]), $MachinePrecision]]]]
\begin{array}{l}
B_m = \left|B\right|
\\
[A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
\\
\begin{array}{l}
t_0 := \mathsf{fma}\left(B\_m, B\_m, A \cdot \left(C \cdot -4\right)\right)\\
\mathbf{if}\;B\_m \leq 4800:\\
\;\;\;\;\frac{\sqrt{\left(4 \cdot A\right) \cdot \left(F \cdot t\_0\right)}}{-t\_0}\\

\mathbf{elif}\;B\_m \leq 7.2 \cdot 10^{+204}:\\
\;\;\;\;\frac{{\left(2 \cdot \frac{\mathsf{hypot}\left(B\_m, A\right) - A}{\frac{-1}{F}}\right)}^{0.5}}{-B\_m}\\

\mathbf{else}:\\
\;\;\;\;e^{0.5 \cdot \left(\log \left(-F\right) + \left(\log B\_m - \frac{A}{B\_m}\right)\right)} \cdot \frac{\sqrt{2}}{-B\_m}\\


\end{array}
\end{array}
Derivation
  1. Split input into 3 regimes
  2. if B < 4800

    1. Initial program 26.7%

      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    2. Simplified34.4%

      \[\leadsto \color{blue}{\frac{\sqrt{\left(\mathsf{fma}\left(B, B, A \cdot \left(C \cdot -4\right)\right) \cdot F\right) \cdot \left(2 \cdot \left(A + \left(C - \mathsf{hypot}\left(B, A - C\right)\right)\right)\right)}}{-\mathsf{fma}\left(B, B, A \cdot \left(C \cdot -4\right)\right)}} \]
    3. Add Preprocessing
    4. Taylor expanded in A around -inf 20.6%

      \[\leadsto \frac{\sqrt{\left(\mathsf{fma}\left(B, B, A \cdot \left(C \cdot -4\right)\right) \cdot F\right) \cdot \color{blue}{\left(4 \cdot A\right)}}}{-\mathsf{fma}\left(B, B, A \cdot \left(C \cdot -4\right)\right)} \]

    if 4800 < B < 7.2000000000000005e204

    1. Initial program 21.0%

      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    2. Add Preprocessing
    3. Taylor expanded in C around 0 34.9%

      \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}\right)} \]
    4. Step-by-step derivation
      1. mul-1-neg34.9%

        \[\leadsto \color{blue}{-\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}} \]
      2. +-commutative34.9%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{\color{blue}{{B}^{2} + {A}^{2}}}\right)} \]
    5. Simplified34.9%

      \[\leadsto \color{blue}{-\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{{B}^{2} + {A}^{2}}\right)}} \]
    6. Step-by-step derivation
      1. pow1/235.0%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot \color{blue}{{\left(F \cdot \left(A - \sqrt{{B}^{2} + {A}^{2}}\right)\right)}^{0.5}} \]
      2. pow-to-exp32.7%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot \color{blue}{e^{\log \left(F \cdot \left(A - \sqrt{{B}^{2} + {A}^{2}}\right)\right) \cdot 0.5}} \]
      3. unpow232.7%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{\log \left(F \cdot \left(A - \sqrt{\color{blue}{B \cdot B} + {A}^{2}}\right)\right) \cdot 0.5} \]
      4. unpow232.7%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{\log \left(F \cdot \left(A - \sqrt{B \cdot B + \color{blue}{A \cdot A}}\right)\right) \cdot 0.5} \]
      5. hypot-undefine41.6%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{\log \left(F \cdot \left(A - \color{blue}{\mathsf{hypot}\left(B, A\right)}\right)\right) \cdot 0.5} \]
    7. Applied egg-rr41.6%

      \[\leadsto -\frac{\sqrt{2}}{B} \cdot \color{blue}{e^{\log \left(F \cdot \left(A - \mathsf{hypot}\left(B, A\right)\right)\right) \cdot 0.5}} \]
    8. Taylor expanded in F around -inf 32.2%

      \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{\color{blue}{\left(\log \left(-1 \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)\right) + -1 \cdot \log \left(\frac{-1}{F}\right)\right)} \cdot 0.5} \]
    9. Step-by-step derivation
      1. mul-1-neg32.2%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{\left(\log \left(-1 \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)\right) + \color{blue}{\left(-\log \left(\frac{-1}{F}\right)\right)}\right) \cdot 0.5} \]
      2. unsub-neg32.2%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{\color{blue}{\left(\log \left(-1 \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)\right) - \log \left(\frac{-1}{F}\right)\right)} \cdot 0.5} \]
      3. mul-1-neg32.2%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{\left(\log \color{blue}{\left(-\left(A - \sqrt{{A}^{2} + {B}^{2}}\right)\right)} - \log \left(\frac{-1}{F}\right)\right) \cdot 0.5} \]
      4. +-commutative32.2%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{\left(\log \left(-\left(A - \sqrt{\color{blue}{{B}^{2} + {A}^{2}}}\right)\right) - \log \left(\frac{-1}{F}\right)\right) \cdot 0.5} \]
      5. unpow232.2%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{\left(\log \left(-\left(A - \sqrt{\color{blue}{B \cdot B} + {A}^{2}}\right)\right) - \log \left(\frac{-1}{F}\right)\right) \cdot 0.5} \]
      6. unpow232.2%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{\left(\log \left(-\left(A - \sqrt{B \cdot B + \color{blue}{A \cdot A}}\right)\right) - \log \left(\frac{-1}{F}\right)\right) \cdot 0.5} \]
      7. hypot-undefine44.7%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{\left(\log \left(-\left(A - \color{blue}{\mathsf{hypot}\left(B, A\right)}\right)\right) - \log \left(\frac{-1}{F}\right)\right) \cdot 0.5} \]
    10. Simplified44.7%

      \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{\color{blue}{\left(\log \left(-\left(A - \mathsf{hypot}\left(B, A\right)\right)\right) - \log \left(\frac{-1}{F}\right)\right)} \cdot 0.5} \]
    11. Step-by-step derivation
      1. associate-*l/44.7%

        \[\leadsto -\color{blue}{\frac{\sqrt{2} \cdot e^{\left(\log \left(-\left(A - \mathsf{hypot}\left(B, A\right)\right)\right) - \log \left(\frac{-1}{F}\right)\right) \cdot 0.5}}{B}} \]
      2. pow1/244.7%

        \[\leadsto -\frac{\color{blue}{{2}^{0.5}} \cdot e^{\left(\log \left(-\left(A - \mathsf{hypot}\left(B, A\right)\right)\right) - \log \left(\frac{-1}{F}\right)\right) \cdot 0.5}}{B} \]
      3. exp-prod41.0%

        \[\leadsto -\frac{{2}^{0.5} \cdot \color{blue}{{\left(e^{\log \left(-\left(A - \mathsf{hypot}\left(B, A\right)\right)\right) - \log \left(\frac{-1}{F}\right)}\right)}^{0.5}}}{B} \]
      4. pow-prod-down40.9%

        \[\leadsto -\frac{\color{blue}{{\left(2 \cdot e^{\log \left(-\left(A - \mathsf{hypot}\left(B, A\right)\right)\right) - \log \left(\frac{-1}{F}\right)}\right)}^{0.5}}}{B} \]
      5. diff-log41.6%

        \[\leadsto -\frac{{\left(2 \cdot e^{\color{blue}{\log \left(\frac{-\left(A - \mathsf{hypot}\left(B, A\right)\right)}{\frac{-1}{F}}\right)}}\right)}^{0.5}}{B} \]
      6. add-exp-log44.7%

        \[\leadsto -\frac{{\left(2 \cdot \color{blue}{\frac{-\left(A - \mathsf{hypot}\left(B, A\right)\right)}{\frac{-1}{F}}}\right)}^{0.5}}{B} \]
    12. Applied egg-rr44.7%

      \[\leadsto -\color{blue}{\frac{{\left(2 \cdot \frac{-\left(A - \mathsf{hypot}\left(B, A\right)\right)}{\frac{-1}{F}}\right)}^{0.5}}{B}} \]

    if 7.2000000000000005e204 < B

    1. Initial program 0.0%

      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    2. Add Preprocessing
    3. Taylor expanded in C around 0 2.4%

      \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}\right)} \]
    4. Step-by-step derivation
      1. mul-1-neg2.4%

        \[\leadsto \color{blue}{-\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}} \]
      2. +-commutative2.4%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{\color{blue}{{B}^{2} + {A}^{2}}}\right)} \]
    5. Simplified2.4%

      \[\leadsto \color{blue}{-\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{{B}^{2} + {A}^{2}}\right)}} \]
    6. Step-by-step derivation
      1. pow1/22.4%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot \color{blue}{{\left(F \cdot \left(A - \sqrt{{B}^{2} + {A}^{2}}\right)\right)}^{0.5}} \]
      2. pow-to-exp2.4%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot \color{blue}{e^{\log \left(F \cdot \left(A - \sqrt{{B}^{2} + {A}^{2}}\right)\right) \cdot 0.5}} \]
      3. unpow22.4%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{\log \left(F \cdot \left(A - \sqrt{\color{blue}{B \cdot B} + {A}^{2}}\right)\right) \cdot 0.5} \]
      4. unpow22.4%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{\log \left(F \cdot \left(A - \sqrt{B \cdot B + \color{blue}{A \cdot A}}\right)\right) \cdot 0.5} \]
      5. hypot-undefine54.1%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{\log \left(F \cdot \left(A - \color{blue}{\mathsf{hypot}\left(B, A\right)}\right)\right) \cdot 0.5} \]
    7. Applied egg-rr54.1%

      \[\leadsto -\frac{\sqrt{2}}{B} \cdot \color{blue}{e^{\log \left(F \cdot \left(A - \mathsf{hypot}\left(B, A\right)\right)\right) \cdot 0.5}} \]
    8. Taylor expanded in B around inf 84.6%

      \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{\color{blue}{\left(\log \left(-1 \cdot F\right) + \left(-1 \cdot \log \left(\frac{1}{B}\right) + -1 \cdot \frac{A}{B}\right)\right)} \cdot 0.5} \]
    9. Step-by-step derivation
      1. neg-mul-184.6%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{\left(\log \color{blue}{\left(-F\right)} + \left(-1 \cdot \log \left(\frac{1}{B}\right) + -1 \cdot \frac{A}{B}\right)\right) \cdot 0.5} \]
      2. mul-1-neg84.6%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{\left(\log \left(-F\right) + \left(-1 \cdot \log \left(\frac{1}{B}\right) + \color{blue}{\left(-\frac{A}{B}\right)}\right)\right) \cdot 0.5} \]
      3. unsub-neg84.6%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{\left(\log \left(-F\right) + \color{blue}{\left(-1 \cdot \log \left(\frac{1}{B}\right) - \frac{A}{B}\right)}\right) \cdot 0.5} \]
      4. mul-1-neg84.6%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{\left(\log \left(-F\right) + \left(\color{blue}{\left(-\log \left(\frac{1}{B}\right)\right)} - \frac{A}{B}\right)\right) \cdot 0.5} \]
      5. log-rec84.6%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{\left(\log \left(-F\right) + \left(\color{blue}{\log \left(\frac{1}{\frac{1}{B}}\right)} - \frac{A}{B}\right)\right) \cdot 0.5} \]
      6. remove-double-div84.6%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{\left(\log \left(-F\right) + \left(\log \color{blue}{B} - \frac{A}{B}\right)\right) \cdot 0.5} \]
    10. Simplified84.6%

      \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{\color{blue}{\left(\log \left(-F\right) + \left(\log B - \frac{A}{B}\right)\right)} \cdot 0.5} \]
  3. Recombined 3 regimes into one program.
  4. Final simplification30.6%

    \[\leadsto \begin{array}{l} \mathbf{if}\;B \leq 4800:\\ \;\;\;\;\frac{\sqrt{\left(4 \cdot A\right) \cdot \left(F \cdot \mathsf{fma}\left(B, B, A \cdot \left(C \cdot -4\right)\right)\right)}}{-\mathsf{fma}\left(B, B, A \cdot \left(C \cdot -4\right)\right)}\\ \mathbf{elif}\;B \leq 7.2 \cdot 10^{+204}:\\ \;\;\;\;\frac{{\left(2 \cdot \frac{\mathsf{hypot}\left(B, A\right) - A}{\frac{-1}{F}}\right)}^{0.5}}{-B}\\ \mathbf{else}:\\ \;\;\;\;e^{0.5 \cdot \left(\log \left(-F\right) + \left(\log B - \frac{A}{B}\right)\right)} \cdot \frac{\sqrt{2}}{-B}\\ \end{array} \]
  5. Add Preprocessing

Alternative 7: 40.0% accurate, 1.5× speedup?

\[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} \mathbf{if}\;{B\_m}^{2} \leq 4 \cdot 10^{-174}:\\ \;\;\;\;\frac{\sqrt{-16 \cdot \left({A}^{2} \cdot \left(C \cdot F\right)\right)}}{\left(4 \cdot A\right) \cdot C - {B\_m}^{2}}\\ \mathbf{else}:\\ \;\;\;\;\frac{{\left(2 \cdot \frac{\mathsf{hypot}\left(B\_m, A\right) - A}{\frac{-1}{F}}\right)}^{0.5}}{-B\_m}\\ \end{array} \end{array} \]
B_m = (fabs.f64 B)
NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
(FPCore (A B_m C F)
 :precision binary64
 (if (<= (pow B_m 2.0) 4e-174)
   (/
    (sqrt (* -16.0 (* (pow A 2.0) (* C F))))
    (- (* (* 4.0 A) C) (pow B_m 2.0)))
   (/ (pow (* 2.0 (/ (- (hypot B_m A) A) (/ -1.0 F))) 0.5) (- B_m))))
B_m = fabs(B);
assert(A < B_m && B_m < C && C < F);
double code(double A, double B_m, double C, double F) {
	double tmp;
	if (pow(B_m, 2.0) <= 4e-174) {
		tmp = sqrt((-16.0 * (pow(A, 2.0) * (C * F)))) / (((4.0 * A) * C) - pow(B_m, 2.0));
	} else {
		tmp = pow((2.0 * ((hypot(B_m, A) - A) / (-1.0 / F))), 0.5) / -B_m;
	}
	return tmp;
}
B_m = Math.abs(B);
assert A < B_m && B_m < C && C < F;
public static double code(double A, double B_m, double C, double F) {
	double tmp;
	if (Math.pow(B_m, 2.0) <= 4e-174) {
		tmp = Math.sqrt((-16.0 * (Math.pow(A, 2.0) * (C * F)))) / (((4.0 * A) * C) - Math.pow(B_m, 2.0));
	} else {
		tmp = Math.pow((2.0 * ((Math.hypot(B_m, A) - A) / (-1.0 / F))), 0.5) / -B_m;
	}
	return tmp;
}
B_m = math.fabs(B)
[A, B_m, C, F] = sort([A, B_m, C, F])
def code(A, B_m, C, F):
	tmp = 0
	if math.pow(B_m, 2.0) <= 4e-174:
		tmp = math.sqrt((-16.0 * (math.pow(A, 2.0) * (C * F)))) / (((4.0 * A) * C) - math.pow(B_m, 2.0))
	else:
		tmp = math.pow((2.0 * ((math.hypot(B_m, A) - A) / (-1.0 / F))), 0.5) / -B_m
	return tmp
B_m = abs(B)
A, B_m, C, F = sort([A, B_m, C, F])
function code(A, B_m, C, F)
	tmp = 0.0
	if ((B_m ^ 2.0) <= 4e-174)
		tmp = Float64(sqrt(Float64(-16.0 * Float64((A ^ 2.0) * Float64(C * F)))) / Float64(Float64(Float64(4.0 * A) * C) - (B_m ^ 2.0)));
	else
		tmp = Float64((Float64(2.0 * Float64(Float64(hypot(B_m, A) - A) / Float64(-1.0 / F))) ^ 0.5) / Float64(-B_m));
	end
	return tmp
end
B_m = abs(B);
A, B_m, C, F = num2cell(sort([A, B_m, C, F])){:}
function tmp_2 = code(A, B_m, C, F)
	tmp = 0.0;
	if ((B_m ^ 2.0) <= 4e-174)
		tmp = sqrt((-16.0 * ((A ^ 2.0) * (C * F)))) / (((4.0 * A) * C) - (B_m ^ 2.0));
	else
		tmp = ((2.0 * ((hypot(B_m, A) - A) / (-1.0 / F))) ^ 0.5) / -B_m;
	end
	tmp_2 = tmp;
end
B_m = N[Abs[B], $MachinePrecision]
NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
code[A_, B$95$m_, C_, F_] := If[LessEqual[N[Power[B$95$m, 2.0], $MachinePrecision], 4e-174], N[(N[Sqrt[N[(-16.0 * N[(N[Power[A, 2.0], $MachinePrecision] * N[(C * F), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / N[(N[(N[(4.0 * A), $MachinePrecision] * C), $MachinePrecision] - N[Power[B$95$m, 2.0], $MachinePrecision]), $MachinePrecision]), $MachinePrecision], N[(N[Power[N[(2.0 * N[(N[(N[Sqrt[B$95$m ^ 2 + A ^ 2], $MachinePrecision] - A), $MachinePrecision] / N[(-1.0 / F), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], 0.5], $MachinePrecision] / (-B$95$m)), $MachinePrecision]]
\begin{array}{l}
B_m = \left|B\right|
\\
[A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
\\
\begin{array}{l}
\mathbf{if}\;{B\_m}^{2} \leq 4 \cdot 10^{-174}:\\
\;\;\;\;\frac{\sqrt{-16 \cdot \left({A}^{2} \cdot \left(C \cdot F\right)\right)}}{\left(4 \cdot A\right) \cdot C - {B\_m}^{2}}\\

\mathbf{else}:\\
\;\;\;\;\frac{{\left(2 \cdot \frac{\mathsf{hypot}\left(B\_m, A\right) - A}{\frac{-1}{F}}\right)}^{0.5}}{-B\_m}\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if (pow.f64 B #s(literal 2 binary64)) < 4e-174

    1. Initial program 23.5%

      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    2. Simplified29.6%

      \[\leadsto \color{blue}{\frac{\sqrt{F \cdot \left(\left(A + \left(C - \mathsf{hypot}\left(B, A - C\right)\right)\right) \cdot \left(2 \cdot \mathsf{fma}\left(C, A \cdot -4, {B}^{2}\right)\right)\right)}}{-\mathsf{fma}\left(C, A \cdot -4, {B}^{2}\right)}} \]
    3. Add Preprocessing
    4. Taylor expanded in A around -inf 20.7%

      \[\leadsto \frac{\sqrt{\color{blue}{-16 \cdot \left({A}^{2} \cdot \left(C \cdot F\right)\right)}}}{-\mathsf{fma}\left(C, A \cdot -4, {B}^{2}\right)} \]
    5. Taylor expanded in C around 0 20.7%

      \[\leadsto \frac{\sqrt{-16 \cdot \left({A}^{2} \cdot \left(C \cdot F\right)\right)}}{\color{blue}{4 \cdot \left(A \cdot C\right) - {B}^{2}}} \]
    6. Step-by-step derivation
      1. associate-*r*20.7%

        \[\leadsto \frac{\sqrt{-16 \cdot \left({A}^{2} \cdot \left(C \cdot F\right)\right)}}{\color{blue}{\left(4 \cdot A\right) \cdot C} - {B}^{2}} \]
    7. Simplified20.7%

      \[\leadsto \frac{\sqrt{-16 \cdot \left({A}^{2} \cdot \left(C \cdot F\right)\right)}}{\color{blue}{\left(4 \cdot A\right) \cdot C - {B}^{2}}} \]

    if 4e-174 < (pow.f64 B #s(literal 2 binary64))

    1. Initial program 23.2%

      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    2. Add Preprocessing
    3. Taylor expanded in C around 0 13.9%

      \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}\right)} \]
    4. Step-by-step derivation
      1. mul-1-neg13.9%

        \[\leadsto \color{blue}{-\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}} \]
      2. +-commutative13.9%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{\color{blue}{{B}^{2} + {A}^{2}}}\right)} \]
    5. Simplified13.9%

      \[\leadsto \color{blue}{-\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{{B}^{2} + {A}^{2}}\right)}} \]
    6. Step-by-step derivation
      1. pow1/213.9%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot \color{blue}{{\left(F \cdot \left(A - \sqrt{{B}^{2} + {A}^{2}}\right)\right)}^{0.5}} \]
      2. pow-to-exp13.1%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot \color{blue}{e^{\log \left(F \cdot \left(A - \sqrt{{B}^{2} + {A}^{2}}\right)\right) \cdot 0.5}} \]
      3. unpow213.1%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{\log \left(F \cdot \left(A - \sqrt{\color{blue}{B \cdot B} + {A}^{2}}\right)\right) \cdot 0.5} \]
      4. unpow213.1%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{\log \left(F \cdot \left(A - \sqrt{B \cdot B + \color{blue}{A \cdot A}}\right)\right) \cdot 0.5} \]
      5. hypot-undefine23.5%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{\log \left(F \cdot \left(A - \color{blue}{\mathsf{hypot}\left(B, A\right)}\right)\right) \cdot 0.5} \]
    7. Applied egg-rr23.5%

      \[\leadsto -\frac{\sqrt{2}}{B} \cdot \color{blue}{e^{\log \left(F \cdot \left(A - \mathsf{hypot}\left(B, A\right)\right)\right) \cdot 0.5}} \]
    8. Taylor expanded in F around -inf 12.9%

      \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{\color{blue}{\left(\log \left(-1 \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)\right) + -1 \cdot \log \left(\frac{-1}{F}\right)\right)} \cdot 0.5} \]
    9. Step-by-step derivation
      1. mul-1-neg12.9%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{\left(\log \left(-1 \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)\right) + \color{blue}{\left(-\log \left(\frac{-1}{F}\right)\right)}\right) \cdot 0.5} \]
      2. unsub-neg12.9%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{\color{blue}{\left(\log \left(-1 \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)\right) - \log \left(\frac{-1}{F}\right)\right)} \cdot 0.5} \]
      3. mul-1-neg12.9%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{\left(\log \color{blue}{\left(-\left(A - \sqrt{{A}^{2} + {B}^{2}}\right)\right)} - \log \left(\frac{-1}{F}\right)\right) \cdot 0.5} \]
      4. +-commutative12.9%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{\left(\log \left(-\left(A - \sqrt{\color{blue}{{B}^{2} + {A}^{2}}}\right)\right) - \log \left(\frac{-1}{F}\right)\right) \cdot 0.5} \]
      5. unpow212.9%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{\left(\log \left(-\left(A - \sqrt{\color{blue}{B \cdot B} + {A}^{2}}\right)\right) - \log \left(\frac{-1}{F}\right)\right) \cdot 0.5} \]
      6. unpow212.9%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{\left(\log \left(-\left(A - \sqrt{B \cdot B + \color{blue}{A \cdot A}}\right)\right) - \log \left(\frac{-1}{F}\right)\right) \cdot 0.5} \]
      7. hypot-undefine28.7%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{\left(\log \left(-\left(A - \color{blue}{\mathsf{hypot}\left(B, A\right)}\right)\right) - \log \left(\frac{-1}{F}\right)\right) \cdot 0.5} \]
    10. Simplified28.7%

      \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{\color{blue}{\left(\log \left(-\left(A - \mathsf{hypot}\left(B, A\right)\right)\right) - \log \left(\frac{-1}{F}\right)\right)} \cdot 0.5} \]
    11. Step-by-step derivation
      1. associate-*l/28.7%

        \[\leadsto -\color{blue}{\frac{\sqrt{2} \cdot e^{\left(\log \left(-\left(A - \mathsf{hypot}\left(B, A\right)\right)\right) - \log \left(\frac{-1}{F}\right)\right) \cdot 0.5}}{B}} \]
      2. pow1/228.7%

        \[\leadsto -\frac{\color{blue}{{2}^{0.5}} \cdot e^{\left(\log \left(-\left(A - \mathsf{hypot}\left(B, A\right)\right)\right) - \log \left(\frac{-1}{F}\right)\right) \cdot 0.5}}{B} \]
      3. exp-prod23.0%

        \[\leadsto -\frac{{2}^{0.5} \cdot \color{blue}{{\left(e^{\log \left(-\left(A - \mathsf{hypot}\left(B, A\right)\right)\right) - \log \left(\frac{-1}{F}\right)}\right)}^{0.5}}}{B} \]
      4. pow-prod-down23.0%

        \[\leadsto -\frac{\color{blue}{{\left(2 \cdot e^{\log \left(-\left(A - \mathsf{hypot}\left(B, A\right)\right)\right) - \log \left(\frac{-1}{F}\right)}\right)}^{0.5}}}{B} \]
      5. diff-log23.5%

        \[\leadsto -\frac{{\left(2 \cdot e^{\color{blue}{\log \left(\frac{-\left(A - \mathsf{hypot}\left(B, A\right)\right)}{\frac{-1}{F}}\right)}}\right)}^{0.5}}{B} \]
      6. add-exp-log25.0%

        \[\leadsto -\frac{{\left(2 \cdot \color{blue}{\frac{-\left(A - \mathsf{hypot}\left(B, A\right)\right)}{\frac{-1}{F}}}\right)}^{0.5}}{B} \]
    12. Applied egg-rr25.0%

      \[\leadsto -\color{blue}{\frac{{\left(2 \cdot \frac{-\left(A - \mathsf{hypot}\left(B, A\right)\right)}{\frac{-1}{F}}\right)}^{0.5}}{B}} \]
  3. Recombined 2 regimes into one program.
  4. Final simplification23.4%

    \[\leadsto \begin{array}{l} \mathbf{if}\;{B}^{2} \leq 4 \cdot 10^{-174}:\\ \;\;\;\;\frac{\sqrt{-16 \cdot \left({A}^{2} \cdot \left(C \cdot F\right)\right)}}{\left(4 \cdot A\right) \cdot C - {B}^{2}}\\ \mathbf{else}:\\ \;\;\;\;\frac{{\left(2 \cdot \frac{\mathsf{hypot}\left(B, A\right) - A}{\frac{-1}{F}}\right)}^{0.5}}{-B}\\ \end{array} \]
  5. Add Preprocessing

Alternative 8: 51.2% accurate, 1.5× speedup?

\[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} t_0 := \mathsf{fma}\left(B\_m, B\_m, A \cdot \left(C \cdot -4\right)\right)\\ \mathbf{if}\;B\_m \leq 5000:\\ \;\;\;\;\frac{\sqrt{\left(4 \cdot A\right) \cdot \left(F \cdot t\_0\right)}}{-t\_0}\\ \mathbf{elif}\;B\_m \leq 1.65 \cdot 10^{+205}:\\ \;\;\;\;\frac{{\left(2 \cdot \frac{\mathsf{hypot}\left(B\_m, A\right) - A}{\frac{-1}{F}}\right)}^{0.5}}{-B\_m}\\ \mathbf{else}:\\ \;\;\;\;\frac{\sqrt{2}}{B\_m} \cdot \left(-e^{0.5 \cdot \left(\log \left(-F\right) + \log B\_m\right)}\right)\\ \end{array} \end{array} \]
B_m = (fabs.f64 B)
NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
(FPCore (A B_m C F)
 :precision binary64
 (let* ((t_0 (fma B_m B_m (* A (* C -4.0)))))
   (if (<= B_m 5000.0)
     (/ (sqrt (* (* 4.0 A) (* F t_0))) (- t_0))
     (if (<= B_m 1.65e+205)
       (/ (pow (* 2.0 (/ (- (hypot B_m A) A) (/ -1.0 F))) 0.5) (- B_m))
       (* (/ (sqrt 2.0) B_m) (- (exp (* 0.5 (+ (log (- F)) (log B_m))))))))))
B_m = fabs(B);
assert(A < B_m && B_m < C && C < F);
double code(double A, double B_m, double C, double F) {
	double t_0 = fma(B_m, B_m, (A * (C * -4.0)));
	double tmp;
	if (B_m <= 5000.0) {
		tmp = sqrt(((4.0 * A) * (F * t_0))) / -t_0;
	} else if (B_m <= 1.65e+205) {
		tmp = pow((2.0 * ((hypot(B_m, A) - A) / (-1.0 / F))), 0.5) / -B_m;
	} else {
		tmp = (sqrt(2.0) / B_m) * -exp((0.5 * (log(-F) + log(B_m))));
	}
	return tmp;
}
B_m = abs(B)
A, B_m, C, F = sort([A, B_m, C, F])
function code(A, B_m, C, F)
	t_0 = fma(B_m, B_m, Float64(A * Float64(C * -4.0)))
	tmp = 0.0
	if (B_m <= 5000.0)
		tmp = Float64(sqrt(Float64(Float64(4.0 * A) * Float64(F * t_0))) / Float64(-t_0));
	elseif (B_m <= 1.65e+205)
		tmp = Float64((Float64(2.0 * Float64(Float64(hypot(B_m, A) - A) / Float64(-1.0 / F))) ^ 0.5) / Float64(-B_m));
	else
		tmp = Float64(Float64(sqrt(2.0) / B_m) * Float64(-exp(Float64(0.5 * Float64(log(Float64(-F)) + log(B_m))))));
	end
	return tmp
end
B_m = N[Abs[B], $MachinePrecision]
NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
code[A_, B$95$m_, C_, F_] := Block[{t$95$0 = N[(B$95$m * B$95$m + N[(A * N[(C * -4.0), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[B$95$m, 5000.0], N[(N[Sqrt[N[(N[(4.0 * A), $MachinePrecision] * N[(F * t$95$0), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / (-t$95$0)), $MachinePrecision], If[LessEqual[B$95$m, 1.65e+205], N[(N[Power[N[(2.0 * N[(N[(N[Sqrt[B$95$m ^ 2 + A ^ 2], $MachinePrecision] - A), $MachinePrecision] / N[(-1.0 / F), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], 0.5], $MachinePrecision] / (-B$95$m)), $MachinePrecision], N[(N[(N[Sqrt[2.0], $MachinePrecision] / B$95$m), $MachinePrecision] * (-N[Exp[N[(0.5 * N[(N[Log[(-F)], $MachinePrecision] + N[Log[B$95$m], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision])), $MachinePrecision]]]]
\begin{array}{l}
B_m = \left|B\right|
\\
[A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
\\
\begin{array}{l}
t_0 := \mathsf{fma}\left(B\_m, B\_m, A \cdot \left(C \cdot -4\right)\right)\\
\mathbf{if}\;B\_m \leq 5000:\\
\;\;\;\;\frac{\sqrt{\left(4 \cdot A\right) \cdot \left(F \cdot t\_0\right)}}{-t\_0}\\

\mathbf{elif}\;B\_m \leq 1.65 \cdot 10^{+205}:\\
\;\;\;\;\frac{{\left(2 \cdot \frac{\mathsf{hypot}\left(B\_m, A\right) - A}{\frac{-1}{F}}\right)}^{0.5}}{-B\_m}\\

\mathbf{else}:\\
\;\;\;\;\frac{\sqrt{2}}{B\_m} \cdot \left(-e^{0.5 \cdot \left(\log \left(-F\right) + \log B\_m\right)}\right)\\


\end{array}
\end{array}
Derivation
  1. Split input into 3 regimes
  2. if B < 5e3

    1. Initial program 26.7%

      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    2. Simplified34.4%

      \[\leadsto \color{blue}{\frac{\sqrt{\left(\mathsf{fma}\left(B, B, A \cdot \left(C \cdot -4\right)\right) \cdot F\right) \cdot \left(2 \cdot \left(A + \left(C - \mathsf{hypot}\left(B, A - C\right)\right)\right)\right)}}{-\mathsf{fma}\left(B, B, A \cdot \left(C \cdot -4\right)\right)}} \]
    3. Add Preprocessing
    4. Taylor expanded in A around -inf 20.6%

      \[\leadsto \frac{\sqrt{\left(\mathsf{fma}\left(B, B, A \cdot \left(C \cdot -4\right)\right) \cdot F\right) \cdot \color{blue}{\left(4 \cdot A\right)}}}{-\mathsf{fma}\left(B, B, A \cdot \left(C \cdot -4\right)\right)} \]

    if 5e3 < B < 1.6500000000000001e205

    1. Initial program 21.0%

      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    2. Add Preprocessing
    3. Taylor expanded in C around 0 34.9%

      \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}\right)} \]
    4. Step-by-step derivation
      1. mul-1-neg34.9%

        \[\leadsto \color{blue}{-\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}} \]
      2. +-commutative34.9%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{\color{blue}{{B}^{2} + {A}^{2}}}\right)} \]
    5. Simplified34.9%

      \[\leadsto \color{blue}{-\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{{B}^{2} + {A}^{2}}\right)}} \]
    6. Step-by-step derivation
      1. pow1/235.0%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot \color{blue}{{\left(F \cdot \left(A - \sqrt{{B}^{2} + {A}^{2}}\right)\right)}^{0.5}} \]
      2. pow-to-exp32.7%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot \color{blue}{e^{\log \left(F \cdot \left(A - \sqrt{{B}^{2} + {A}^{2}}\right)\right) \cdot 0.5}} \]
      3. unpow232.7%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{\log \left(F \cdot \left(A - \sqrt{\color{blue}{B \cdot B} + {A}^{2}}\right)\right) \cdot 0.5} \]
      4. unpow232.7%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{\log \left(F \cdot \left(A - \sqrt{B \cdot B + \color{blue}{A \cdot A}}\right)\right) \cdot 0.5} \]
      5. hypot-undefine41.6%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{\log \left(F \cdot \left(A - \color{blue}{\mathsf{hypot}\left(B, A\right)}\right)\right) \cdot 0.5} \]
    7. Applied egg-rr41.6%

      \[\leadsto -\frac{\sqrt{2}}{B} \cdot \color{blue}{e^{\log \left(F \cdot \left(A - \mathsf{hypot}\left(B, A\right)\right)\right) \cdot 0.5}} \]
    8. Taylor expanded in F around -inf 32.2%

      \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{\color{blue}{\left(\log \left(-1 \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)\right) + -1 \cdot \log \left(\frac{-1}{F}\right)\right)} \cdot 0.5} \]
    9. Step-by-step derivation
      1. mul-1-neg32.2%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{\left(\log \left(-1 \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)\right) + \color{blue}{\left(-\log \left(\frac{-1}{F}\right)\right)}\right) \cdot 0.5} \]
      2. unsub-neg32.2%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{\color{blue}{\left(\log \left(-1 \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)\right) - \log \left(\frac{-1}{F}\right)\right)} \cdot 0.5} \]
      3. mul-1-neg32.2%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{\left(\log \color{blue}{\left(-\left(A - \sqrt{{A}^{2} + {B}^{2}}\right)\right)} - \log \left(\frac{-1}{F}\right)\right) \cdot 0.5} \]
      4. +-commutative32.2%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{\left(\log \left(-\left(A - \sqrt{\color{blue}{{B}^{2} + {A}^{2}}}\right)\right) - \log \left(\frac{-1}{F}\right)\right) \cdot 0.5} \]
      5. unpow232.2%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{\left(\log \left(-\left(A - \sqrt{\color{blue}{B \cdot B} + {A}^{2}}\right)\right) - \log \left(\frac{-1}{F}\right)\right) \cdot 0.5} \]
      6. unpow232.2%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{\left(\log \left(-\left(A - \sqrt{B \cdot B + \color{blue}{A \cdot A}}\right)\right) - \log \left(\frac{-1}{F}\right)\right) \cdot 0.5} \]
      7. hypot-undefine44.7%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{\left(\log \left(-\left(A - \color{blue}{\mathsf{hypot}\left(B, A\right)}\right)\right) - \log \left(\frac{-1}{F}\right)\right) \cdot 0.5} \]
    10. Simplified44.7%

      \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{\color{blue}{\left(\log \left(-\left(A - \mathsf{hypot}\left(B, A\right)\right)\right) - \log \left(\frac{-1}{F}\right)\right)} \cdot 0.5} \]
    11. Step-by-step derivation
      1. associate-*l/44.7%

        \[\leadsto -\color{blue}{\frac{\sqrt{2} \cdot e^{\left(\log \left(-\left(A - \mathsf{hypot}\left(B, A\right)\right)\right) - \log \left(\frac{-1}{F}\right)\right) \cdot 0.5}}{B}} \]
      2. pow1/244.7%

        \[\leadsto -\frac{\color{blue}{{2}^{0.5}} \cdot e^{\left(\log \left(-\left(A - \mathsf{hypot}\left(B, A\right)\right)\right) - \log \left(\frac{-1}{F}\right)\right) \cdot 0.5}}{B} \]
      3. exp-prod41.0%

        \[\leadsto -\frac{{2}^{0.5} \cdot \color{blue}{{\left(e^{\log \left(-\left(A - \mathsf{hypot}\left(B, A\right)\right)\right) - \log \left(\frac{-1}{F}\right)}\right)}^{0.5}}}{B} \]
      4. pow-prod-down40.9%

        \[\leadsto -\frac{\color{blue}{{\left(2 \cdot e^{\log \left(-\left(A - \mathsf{hypot}\left(B, A\right)\right)\right) - \log \left(\frac{-1}{F}\right)}\right)}^{0.5}}}{B} \]
      5. diff-log41.6%

        \[\leadsto -\frac{{\left(2 \cdot e^{\color{blue}{\log \left(\frac{-\left(A - \mathsf{hypot}\left(B, A\right)\right)}{\frac{-1}{F}}\right)}}\right)}^{0.5}}{B} \]
      6. add-exp-log44.7%

        \[\leadsto -\frac{{\left(2 \cdot \color{blue}{\frac{-\left(A - \mathsf{hypot}\left(B, A\right)\right)}{\frac{-1}{F}}}\right)}^{0.5}}{B} \]
    12. Applied egg-rr44.7%

      \[\leadsto -\color{blue}{\frac{{\left(2 \cdot \frac{-\left(A - \mathsf{hypot}\left(B, A\right)\right)}{\frac{-1}{F}}\right)}^{0.5}}{B}} \]

    if 1.6500000000000001e205 < B

    1. Initial program 0.0%

      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    2. Add Preprocessing
    3. Taylor expanded in C around 0 2.4%

      \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}\right)} \]
    4. Step-by-step derivation
      1. mul-1-neg2.4%

        \[\leadsto \color{blue}{-\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}} \]
      2. +-commutative2.4%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{\color{blue}{{B}^{2} + {A}^{2}}}\right)} \]
    5. Simplified2.4%

      \[\leadsto \color{blue}{-\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{{B}^{2} + {A}^{2}}\right)}} \]
    6. Step-by-step derivation
      1. pow1/22.4%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot \color{blue}{{\left(F \cdot \left(A - \sqrt{{B}^{2} + {A}^{2}}\right)\right)}^{0.5}} \]
      2. pow-to-exp2.4%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot \color{blue}{e^{\log \left(F \cdot \left(A - \sqrt{{B}^{2} + {A}^{2}}\right)\right) \cdot 0.5}} \]
      3. unpow22.4%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{\log \left(F \cdot \left(A - \sqrt{\color{blue}{B \cdot B} + {A}^{2}}\right)\right) \cdot 0.5} \]
      4. unpow22.4%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{\log \left(F \cdot \left(A - \sqrt{B \cdot B + \color{blue}{A \cdot A}}\right)\right) \cdot 0.5} \]
      5. hypot-undefine54.1%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{\log \left(F \cdot \left(A - \color{blue}{\mathsf{hypot}\left(B, A\right)}\right)\right) \cdot 0.5} \]
    7. Applied egg-rr54.1%

      \[\leadsto -\frac{\sqrt{2}}{B} \cdot \color{blue}{e^{\log \left(F \cdot \left(A - \mathsf{hypot}\left(B, A\right)\right)\right) \cdot 0.5}} \]
    8. Taylor expanded in B around inf 83.8%

      \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{\color{blue}{\left(\log \left(-1 \cdot F\right) + -1 \cdot \log \left(\frac{1}{B}\right)\right)} \cdot 0.5} \]
    9. Step-by-step derivation
      1. neg-mul-183.8%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{\left(\log \color{blue}{\left(-F\right)} + -1 \cdot \log \left(\frac{1}{B}\right)\right) \cdot 0.5} \]
      2. mul-1-neg83.8%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{\left(\log \left(-F\right) + \color{blue}{\left(-\log \left(\frac{1}{B}\right)\right)}\right) \cdot 0.5} \]
      3. log-rec83.8%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{\left(\log \left(-F\right) + \color{blue}{\log \left(\frac{1}{\frac{1}{B}}\right)}\right) \cdot 0.5} \]
      4. remove-double-div83.8%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{\left(\log \left(-F\right) + \log \color{blue}{B}\right) \cdot 0.5} \]
    10. Simplified83.8%

      \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{\color{blue}{\left(\log \left(-F\right) + \log B\right)} \cdot 0.5} \]
  3. Recombined 3 regimes into one program.
  4. Final simplification30.5%

    \[\leadsto \begin{array}{l} \mathbf{if}\;B \leq 5000:\\ \;\;\;\;\frac{\sqrt{\left(4 \cdot A\right) \cdot \left(F \cdot \mathsf{fma}\left(B, B, A \cdot \left(C \cdot -4\right)\right)\right)}}{-\mathsf{fma}\left(B, B, A \cdot \left(C \cdot -4\right)\right)}\\ \mathbf{elif}\;B \leq 1.65 \cdot 10^{+205}:\\ \;\;\;\;\frac{{\left(2 \cdot \frac{\mathsf{hypot}\left(B, A\right) - A}{\frac{-1}{F}}\right)}^{0.5}}{-B}\\ \mathbf{else}:\\ \;\;\;\;\frac{\sqrt{2}}{B} \cdot \left(-e^{0.5 \cdot \left(\log \left(-F\right) + \log B\right)}\right)\\ \end{array} \]
  5. Add Preprocessing

Alternative 9: 47.6% accurate, 1.9× speedup?

\[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} t_0 := \mathsf{fma}\left(B\_m, B\_m, A \cdot \left(C \cdot -4\right)\right)\\ \mathbf{if}\;B\_m \leq 1000:\\ \;\;\;\;\frac{\sqrt{\left(4 \cdot A\right) \cdot \left(F \cdot t\_0\right)}}{-t\_0}\\ \mathbf{else}:\\ \;\;\;\;\frac{{\left(2 \cdot \frac{\mathsf{hypot}\left(B\_m, A\right) - A}{\frac{-1}{F}}\right)}^{0.5}}{-B\_m}\\ \end{array} \end{array} \]
B_m = (fabs.f64 B)
NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
(FPCore (A B_m C F)
 :precision binary64
 (let* ((t_0 (fma B_m B_m (* A (* C -4.0)))))
   (if (<= B_m 1000.0)
     (/ (sqrt (* (* 4.0 A) (* F t_0))) (- t_0))
     (/ (pow (* 2.0 (/ (- (hypot B_m A) A) (/ -1.0 F))) 0.5) (- B_m)))))
B_m = fabs(B);
assert(A < B_m && B_m < C && C < F);
double code(double A, double B_m, double C, double F) {
	double t_0 = fma(B_m, B_m, (A * (C * -4.0)));
	double tmp;
	if (B_m <= 1000.0) {
		tmp = sqrt(((4.0 * A) * (F * t_0))) / -t_0;
	} else {
		tmp = pow((2.0 * ((hypot(B_m, A) - A) / (-1.0 / F))), 0.5) / -B_m;
	}
	return tmp;
}
B_m = abs(B)
A, B_m, C, F = sort([A, B_m, C, F])
function code(A, B_m, C, F)
	t_0 = fma(B_m, B_m, Float64(A * Float64(C * -4.0)))
	tmp = 0.0
	if (B_m <= 1000.0)
		tmp = Float64(sqrt(Float64(Float64(4.0 * A) * Float64(F * t_0))) / Float64(-t_0));
	else
		tmp = Float64((Float64(2.0 * Float64(Float64(hypot(B_m, A) - A) / Float64(-1.0 / F))) ^ 0.5) / Float64(-B_m));
	end
	return tmp
end
B_m = N[Abs[B], $MachinePrecision]
NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
code[A_, B$95$m_, C_, F_] := Block[{t$95$0 = N[(B$95$m * B$95$m + N[(A * N[(C * -4.0), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[B$95$m, 1000.0], N[(N[Sqrt[N[(N[(4.0 * A), $MachinePrecision] * N[(F * t$95$0), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / (-t$95$0)), $MachinePrecision], N[(N[Power[N[(2.0 * N[(N[(N[Sqrt[B$95$m ^ 2 + A ^ 2], $MachinePrecision] - A), $MachinePrecision] / N[(-1.0 / F), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], 0.5], $MachinePrecision] / (-B$95$m)), $MachinePrecision]]]
\begin{array}{l}
B_m = \left|B\right|
\\
[A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
\\
\begin{array}{l}
t_0 := \mathsf{fma}\left(B\_m, B\_m, A \cdot \left(C \cdot -4\right)\right)\\
\mathbf{if}\;B\_m \leq 1000:\\
\;\;\;\;\frac{\sqrt{\left(4 \cdot A\right) \cdot \left(F \cdot t\_0\right)}}{-t\_0}\\

\mathbf{else}:\\
\;\;\;\;\frac{{\left(2 \cdot \frac{\mathsf{hypot}\left(B\_m, A\right) - A}{\frac{-1}{F}}\right)}^{0.5}}{-B\_m}\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if B < 1e3

    1. Initial program 26.7%

      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    2. Simplified34.4%

      \[\leadsto \color{blue}{\frac{\sqrt{\left(\mathsf{fma}\left(B, B, A \cdot \left(C \cdot -4\right)\right) \cdot F\right) \cdot \left(2 \cdot \left(A + \left(C - \mathsf{hypot}\left(B, A - C\right)\right)\right)\right)}}{-\mathsf{fma}\left(B, B, A \cdot \left(C \cdot -4\right)\right)}} \]
    3. Add Preprocessing
    4. Taylor expanded in A around -inf 20.6%

      \[\leadsto \frac{\sqrt{\left(\mathsf{fma}\left(B, B, A \cdot \left(C \cdot -4\right)\right) \cdot F\right) \cdot \color{blue}{\left(4 \cdot A\right)}}}{-\mathsf{fma}\left(B, B, A \cdot \left(C \cdot -4\right)\right)} \]

    if 1e3 < B

    1. Initial program 13.9%

      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    2. Add Preprocessing
    3. Taylor expanded in C around 0 23.9%

      \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}\right)} \]
    4. Step-by-step derivation
      1. mul-1-neg23.9%

        \[\leadsto \color{blue}{-\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}} \]
      2. +-commutative23.9%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{\color{blue}{{B}^{2} + {A}^{2}}}\right)} \]
    5. Simplified23.9%

      \[\leadsto \color{blue}{-\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{{B}^{2} + {A}^{2}}\right)}} \]
    6. Step-by-step derivation
      1. pow1/224.0%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot \color{blue}{{\left(F \cdot \left(A - \sqrt{{B}^{2} + {A}^{2}}\right)\right)}^{0.5}} \]
      2. pow-to-exp22.4%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot \color{blue}{e^{\log \left(F \cdot \left(A - \sqrt{{B}^{2} + {A}^{2}}\right)\right) \cdot 0.5}} \]
      3. unpow222.4%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{\log \left(F \cdot \left(A - \sqrt{\color{blue}{B \cdot B} + {A}^{2}}\right)\right) \cdot 0.5} \]
      4. unpow222.4%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{\log \left(F \cdot \left(A - \sqrt{B \cdot B + \color{blue}{A \cdot A}}\right)\right) \cdot 0.5} \]
      5. hypot-undefine45.9%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{\log \left(F \cdot \left(A - \color{blue}{\mathsf{hypot}\left(B, A\right)}\right)\right) \cdot 0.5} \]
    7. Applied egg-rr45.9%

      \[\leadsto -\frac{\sqrt{2}}{B} \cdot \color{blue}{e^{\log \left(F \cdot \left(A - \mathsf{hypot}\left(B, A\right)\right)\right) \cdot 0.5}} \]
    8. Taylor expanded in F around -inf 22.1%

      \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{\color{blue}{\left(\log \left(-1 \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)\right) + -1 \cdot \log \left(\frac{-1}{F}\right)\right)} \cdot 0.5} \]
    9. Step-by-step derivation
      1. mul-1-neg22.1%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{\left(\log \left(-1 \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)\right) + \color{blue}{\left(-\log \left(\frac{-1}{F}\right)\right)}\right) \cdot 0.5} \]
      2. unsub-neg22.1%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{\color{blue}{\left(\log \left(-1 \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)\right) - \log \left(\frac{-1}{F}\right)\right)} \cdot 0.5} \]
      3. mul-1-neg22.1%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{\left(\log \color{blue}{\left(-\left(A - \sqrt{{A}^{2} + {B}^{2}}\right)\right)} - \log \left(\frac{-1}{F}\right)\right) \cdot 0.5} \]
      4. +-commutative22.1%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{\left(\log \left(-\left(A - \sqrt{\color{blue}{{B}^{2} + {A}^{2}}}\right)\right) - \log \left(\frac{-1}{F}\right)\right) \cdot 0.5} \]
      5. unpow222.1%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{\left(\log \left(-\left(A - \sqrt{\color{blue}{B \cdot B} + {A}^{2}}\right)\right) - \log \left(\frac{-1}{F}\right)\right) \cdot 0.5} \]
      6. unpow222.1%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{\left(\log \left(-\left(A - \sqrt{B \cdot B + \color{blue}{A \cdot A}}\right)\right) - \log \left(\frac{-1}{F}\right)\right) \cdot 0.5} \]
      7. hypot-undefine58.2%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{\left(\log \left(-\left(A - \color{blue}{\mathsf{hypot}\left(B, A\right)}\right)\right) - \log \left(\frac{-1}{F}\right)\right) \cdot 0.5} \]
    10. Simplified58.2%

      \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{\color{blue}{\left(\log \left(-\left(A - \mathsf{hypot}\left(B, A\right)\right)\right) - \log \left(\frac{-1}{F}\right)\right)} \cdot 0.5} \]
    11. Step-by-step derivation
      1. associate-*l/58.2%

        \[\leadsto -\color{blue}{\frac{\sqrt{2} \cdot e^{\left(\log \left(-\left(A - \mathsf{hypot}\left(B, A\right)\right)\right) - \log \left(\frac{-1}{F}\right)\right) \cdot 0.5}}{B}} \]
      2. pow1/258.2%

        \[\leadsto -\frac{\color{blue}{{2}^{0.5}} \cdot e^{\left(\log \left(-\left(A - \mathsf{hypot}\left(B, A\right)\right)\right) - \log \left(\frac{-1}{F}\right)\right) \cdot 0.5}}{B} \]
      3. exp-prod44.8%

        \[\leadsto -\frac{{2}^{0.5} \cdot \color{blue}{{\left(e^{\log \left(-\left(A - \mathsf{hypot}\left(B, A\right)\right)\right) - \log \left(\frac{-1}{F}\right)}\right)}^{0.5}}}{B} \]
      4. pow-prod-down44.8%

        \[\leadsto -\frac{\color{blue}{{\left(2 \cdot e^{\log \left(-\left(A - \mathsf{hypot}\left(B, A\right)\right)\right) - \log \left(\frac{-1}{F}\right)}\right)}^{0.5}}}{B} \]
      5. diff-log45.8%

        \[\leadsto -\frac{{\left(2 \cdot e^{\color{blue}{\log \left(\frac{-\left(A - \mathsf{hypot}\left(B, A\right)\right)}{\frac{-1}{F}}\right)}}\right)}^{0.5}}{B} \]
      6. add-exp-log49.0%

        \[\leadsto -\frac{{\left(2 \cdot \color{blue}{\frac{-\left(A - \mathsf{hypot}\left(B, A\right)\right)}{\frac{-1}{F}}}\right)}^{0.5}}{B} \]
    12. Applied egg-rr49.0%

      \[\leadsto -\color{blue}{\frac{{\left(2 \cdot \frac{-\left(A - \mathsf{hypot}\left(B, A\right)\right)}{\frac{-1}{F}}\right)}^{0.5}}{B}} \]
  3. Recombined 2 regimes into one program.
  4. Final simplification28.1%

    \[\leadsto \begin{array}{l} \mathbf{if}\;B \leq 1000:\\ \;\;\;\;\frac{\sqrt{\left(4 \cdot A\right) \cdot \left(F \cdot \mathsf{fma}\left(B, B, A \cdot \left(C \cdot -4\right)\right)\right)}}{-\mathsf{fma}\left(B, B, A \cdot \left(C \cdot -4\right)\right)}\\ \mathbf{else}:\\ \;\;\;\;\frac{{\left(2 \cdot \frac{\mathsf{hypot}\left(B, A\right) - A}{\frac{-1}{F}}\right)}^{0.5}}{-B}\\ \end{array} \]
  5. Add Preprocessing

Alternative 10: 45.3% accurate, 2.0× speedup?

\[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} \mathbf{if}\;B\_m \leq 6.5 \cdot 10^{-84}:\\ \;\;\;\;\frac{\sqrt{\left(A \cdot -8\right) \cdot \left(C \cdot \left(F \cdot \left(A + A\right)\right)\right)}}{-\mathsf{fma}\left(C, A \cdot -4, {B\_m}^{2}\right)}\\ \mathbf{else}:\\ \;\;\;\;\frac{{\left(2 \cdot \frac{\mathsf{hypot}\left(B\_m, A\right) - A}{\frac{-1}{F}}\right)}^{0.5}}{-B\_m}\\ \end{array} \end{array} \]
B_m = (fabs.f64 B)
NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
(FPCore (A B_m C F)
 :precision binary64
 (if (<= B_m 6.5e-84)
   (/
    (sqrt (* (* A -8.0) (* C (* F (+ A A)))))
    (- (fma C (* A -4.0) (pow B_m 2.0))))
   (/ (pow (* 2.0 (/ (- (hypot B_m A) A) (/ -1.0 F))) 0.5) (- B_m))))
B_m = fabs(B);
assert(A < B_m && B_m < C && C < F);
double code(double A, double B_m, double C, double F) {
	double tmp;
	if (B_m <= 6.5e-84) {
		tmp = sqrt(((A * -8.0) * (C * (F * (A + A))))) / -fma(C, (A * -4.0), pow(B_m, 2.0));
	} else {
		tmp = pow((2.0 * ((hypot(B_m, A) - A) / (-1.0 / F))), 0.5) / -B_m;
	}
	return tmp;
}
B_m = abs(B)
A, B_m, C, F = sort([A, B_m, C, F])
function code(A, B_m, C, F)
	tmp = 0.0
	if (B_m <= 6.5e-84)
		tmp = Float64(sqrt(Float64(Float64(A * -8.0) * Float64(C * Float64(F * Float64(A + A))))) / Float64(-fma(C, Float64(A * -4.0), (B_m ^ 2.0))));
	else
		tmp = Float64((Float64(2.0 * Float64(Float64(hypot(B_m, A) - A) / Float64(-1.0 / F))) ^ 0.5) / Float64(-B_m));
	end
	return tmp
end
B_m = N[Abs[B], $MachinePrecision]
NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
code[A_, B$95$m_, C_, F_] := If[LessEqual[B$95$m, 6.5e-84], N[(N[Sqrt[N[(N[(A * -8.0), $MachinePrecision] * N[(C * N[(F * N[(A + A), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / (-N[(C * N[(A * -4.0), $MachinePrecision] + N[Power[B$95$m, 2.0], $MachinePrecision]), $MachinePrecision])), $MachinePrecision], N[(N[Power[N[(2.0 * N[(N[(N[Sqrt[B$95$m ^ 2 + A ^ 2], $MachinePrecision] - A), $MachinePrecision] / N[(-1.0 / F), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], 0.5], $MachinePrecision] / (-B$95$m)), $MachinePrecision]]
\begin{array}{l}
B_m = \left|B\right|
\\
[A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
\\
\begin{array}{l}
\mathbf{if}\;B\_m \leq 6.5 \cdot 10^{-84}:\\
\;\;\;\;\frac{\sqrt{\left(A \cdot -8\right) \cdot \left(C \cdot \left(F \cdot \left(A + A\right)\right)\right)}}{-\mathsf{fma}\left(C, A \cdot -4, {B\_m}^{2}\right)}\\

\mathbf{else}:\\
\;\;\;\;\frac{{\left(2 \cdot \frac{\mathsf{hypot}\left(B\_m, A\right) - A}{\frac{-1}{F}}\right)}^{0.5}}{-B\_m}\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if B < 6.50000000000000022e-84

    1. Initial program 27.0%

      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    2. Simplified29.2%

      \[\leadsto \color{blue}{\frac{\sqrt{F \cdot \left(\left(A + \left(C - \mathsf{hypot}\left(B, A - C\right)\right)\right) \cdot \left(2 \cdot \mathsf{fma}\left(C, A \cdot -4, {B}^{2}\right)\right)\right)}}{-\mathsf{fma}\left(C, A \cdot -4, {B}^{2}\right)}} \]
    3. Add Preprocessing
    4. Taylor expanded in C around inf 18.6%

      \[\leadsto \frac{\sqrt{\color{blue}{-8 \cdot \left(A \cdot \left(C \cdot \left(F \cdot \left(A - -1 \cdot A\right)\right)\right)\right)}}}{-\mathsf{fma}\left(C, A \cdot -4, {B}^{2}\right)} \]
    5. Step-by-step derivation
      1. associate-*r*18.6%

        \[\leadsto \frac{\sqrt{\color{blue}{\left(-8 \cdot A\right) \cdot \left(C \cdot \left(F \cdot \left(A - -1 \cdot A\right)\right)\right)}}}{-\mathsf{fma}\left(C, A \cdot -4, {B}^{2}\right)} \]
      2. mul-1-neg18.6%

        \[\leadsto \frac{\sqrt{\left(-8 \cdot A\right) \cdot \left(C \cdot \left(F \cdot \left(A - \color{blue}{\left(-A\right)}\right)\right)\right)}}{-\mathsf{fma}\left(C, A \cdot -4, {B}^{2}\right)} \]
    6. Simplified18.6%

      \[\leadsto \frac{\sqrt{\color{blue}{\left(-8 \cdot A\right) \cdot \left(C \cdot \left(F \cdot \left(A - \left(-A\right)\right)\right)\right)}}}{-\mathsf{fma}\left(C, A \cdot -4, {B}^{2}\right)} \]

    if 6.50000000000000022e-84 < B

    1. Initial program 15.9%

      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    2. Add Preprocessing
    3. Taylor expanded in C around 0 24.4%

      \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}\right)} \]
    4. Step-by-step derivation
      1. mul-1-neg24.4%

        \[\leadsto \color{blue}{-\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}} \]
      2. +-commutative24.4%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{\color{blue}{{B}^{2} + {A}^{2}}}\right)} \]
    5. Simplified24.4%

      \[\leadsto \color{blue}{-\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{{B}^{2} + {A}^{2}}\right)}} \]
    6. Step-by-step derivation
      1. pow1/224.5%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot \color{blue}{{\left(F \cdot \left(A - \sqrt{{B}^{2} + {A}^{2}}\right)\right)}^{0.5}} \]
      2. pow-to-exp23.1%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot \color{blue}{e^{\log \left(F \cdot \left(A - \sqrt{{B}^{2} + {A}^{2}}\right)\right) \cdot 0.5}} \]
      3. unpow223.1%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{\log \left(F \cdot \left(A - \sqrt{\color{blue}{B \cdot B} + {A}^{2}}\right)\right) \cdot 0.5} \]
      4. unpow223.1%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{\log \left(F \cdot \left(A - \sqrt{B \cdot B + \color{blue}{A \cdot A}}\right)\right) \cdot 0.5} \]
      5. hypot-undefine41.7%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{\log \left(F \cdot \left(A - \color{blue}{\mathsf{hypot}\left(B, A\right)}\right)\right) \cdot 0.5} \]
    7. Applied egg-rr41.7%

      \[\leadsto -\frac{\sqrt{2}}{B} \cdot \color{blue}{e^{\log \left(F \cdot \left(A - \mathsf{hypot}\left(B, A\right)\right)\right) \cdot 0.5}} \]
    8. Taylor expanded in F around -inf 22.7%

      \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{\color{blue}{\left(\log \left(-1 \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)\right) + -1 \cdot \log \left(\frac{-1}{F}\right)\right)} \cdot 0.5} \]
    9. Step-by-step derivation
      1. mul-1-neg22.7%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{\left(\log \left(-1 \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)\right) + \color{blue}{\left(-\log \left(\frac{-1}{F}\right)\right)}\right) \cdot 0.5} \]
      2. unsub-neg22.7%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{\color{blue}{\left(\log \left(-1 \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)\right) - \log \left(\frac{-1}{F}\right)\right)} \cdot 0.5} \]
      3. mul-1-neg22.7%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{\left(\log \color{blue}{\left(-\left(A - \sqrt{{A}^{2} + {B}^{2}}\right)\right)} - \log \left(\frac{-1}{F}\right)\right) \cdot 0.5} \]
      4. +-commutative22.7%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{\left(\log \left(-\left(A - \sqrt{\color{blue}{{B}^{2} + {A}^{2}}}\right)\right) - \log \left(\frac{-1}{F}\right)\right) \cdot 0.5} \]
      5. unpow222.7%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{\left(\log \left(-\left(A - \sqrt{\color{blue}{B \cdot B} + {A}^{2}}\right)\right) - \log \left(\frac{-1}{F}\right)\right) \cdot 0.5} \]
      6. unpow222.7%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{\left(\log \left(-\left(A - \sqrt{B \cdot B + \color{blue}{A \cdot A}}\right)\right) - \log \left(\frac{-1}{F}\right)\right) \cdot 0.5} \]
      7. hypot-undefine51.4%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{\left(\log \left(-\left(A - \color{blue}{\mathsf{hypot}\left(B, A\right)}\right)\right) - \log \left(\frac{-1}{F}\right)\right) \cdot 0.5} \]
    10. Simplified51.4%

      \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{\color{blue}{\left(\log \left(-\left(A - \mathsf{hypot}\left(B, A\right)\right)\right) - \log \left(\frac{-1}{F}\right)\right)} \cdot 0.5} \]
    11. Step-by-step derivation
      1. associate-*l/51.4%

        \[\leadsto -\color{blue}{\frac{\sqrt{2} \cdot e^{\left(\log \left(-\left(A - \mathsf{hypot}\left(B, A\right)\right)\right) - \log \left(\frac{-1}{F}\right)\right) \cdot 0.5}}{B}} \]
      2. pow1/251.4%

        \[\leadsto -\frac{\color{blue}{{2}^{0.5}} \cdot e^{\left(\log \left(-\left(A - \mathsf{hypot}\left(B, A\right)\right)\right) - \log \left(\frac{-1}{F}\right)\right) \cdot 0.5}}{B} \]
      3. exp-prod40.8%

        \[\leadsto -\frac{{2}^{0.5} \cdot \color{blue}{{\left(e^{\log \left(-\left(A - \mathsf{hypot}\left(B, A\right)\right)\right) - \log \left(\frac{-1}{F}\right)}\right)}^{0.5}}}{B} \]
      4. pow-prod-down40.8%

        \[\leadsto -\frac{\color{blue}{{\left(2 \cdot e^{\log \left(-\left(A - \mathsf{hypot}\left(B, A\right)\right)\right) - \log \left(\frac{-1}{F}\right)}\right)}^{0.5}}}{B} \]
      5. diff-log41.7%

        \[\leadsto -\frac{{\left(2 \cdot e^{\color{blue}{\log \left(\frac{-\left(A - \mathsf{hypot}\left(B, A\right)\right)}{\frac{-1}{F}}\right)}}\right)}^{0.5}}{B} \]
      6. add-exp-log44.4%

        \[\leadsto -\frac{{\left(2 \cdot \color{blue}{\frac{-\left(A - \mathsf{hypot}\left(B, A\right)\right)}{\frac{-1}{F}}}\right)}^{0.5}}{B} \]
    12. Applied egg-rr44.4%

      \[\leadsto -\color{blue}{\frac{{\left(2 \cdot \frac{-\left(A - \mathsf{hypot}\left(B, A\right)\right)}{\frac{-1}{F}}\right)}^{0.5}}{B}} \]
  3. Recombined 2 regimes into one program.
  4. Final simplification27.3%

    \[\leadsto \begin{array}{l} \mathbf{if}\;B \leq 6.5 \cdot 10^{-84}:\\ \;\;\;\;\frac{\sqrt{\left(A \cdot -8\right) \cdot \left(C \cdot \left(F \cdot \left(A + A\right)\right)\right)}}{-\mathsf{fma}\left(C, A \cdot -4, {B}^{2}\right)}\\ \mathbf{else}:\\ \;\;\;\;\frac{{\left(2 \cdot \frac{\mathsf{hypot}\left(B, A\right) - A}{\frac{-1}{F}}\right)}^{0.5}}{-B}\\ \end{array} \]
  5. Add Preprocessing

Alternative 11: 40.0% accurate, 2.0× speedup?

\[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} \mathbf{if}\;{B\_m}^{2} \leq 4 \cdot 10^{-174}:\\ \;\;\;\;\frac{\sqrt{-16 \cdot \left({A}^{2} \cdot \left(C \cdot F\right)\right)}}{\left(4 \cdot A\right) \cdot C}\\ \mathbf{else}:\\ \;\;\;\;\frac{{\left(2 \cdot \frac{\mathsf{hypot}\left(B\_m, A\right) - A}{\frac{-1}{F}}\right)}^{0.5}}{-B\_m}\\ \end{array} \end{array} \]
B_m = (fabs.f64 B)
NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
(FPCore (A B_m C F)
 :precision binary64
 (if (<= (pow B_m 2.0) 4e-174)
   (/ (sqrt (* -16.0 (* (pow A 2.0) (* C F)))) (* (* 4.0 A) C))
   (/ (pow (* 2.0 (/ (- (hypot B_m A) A) (/ -1.0 F))) 0.5) (- B_m))))
B_m = fabs(B);
assert(A < B_m && B_m < C && C < F);
double code(double A, double B_m, double C, double F) {
	double tmp;
	if (pow(B_m, 2.0) <= 4e-174) {
		tmp = sqrt((-16.0 * (pow(A, 2.0) * (C * F)))) / ((4.0 * A) * C);
	} else {
		tmp = pow((2.0 * ((hypot(B_m, A) - A) / (-1.0 / F))), 0.5) / -B_m;
	}
	return tmp;
}
B_m = Math.abs(B);
assert A < B_m && B_m < C && C < F;
public static double code(double A, double B_m, double C, double F) {
	double tmp;
	if (Math.pow(B_m, 2.0) <= 4e-174) {
		tmp = Math.sqrt((-16.0 * (Math.pow(A, 2.0) * (C * F)))) / ((4.0 * A) * C);
	} else {
		tmp = Math.pow((2.0 * ((Math.hypot(B_m, A) - A) / (-1.0 / F))), 0.5) / -B_m;
	}
	return tmp;
}
B_m = math.fabs(B)
[A, B_m, C, F] = sort([A, B_m, C, F])
def code(A, B_m, C, F):
	tmp = 0
	if math.pow(B_m, 2.0) <= 4e-174:
		tmp = math.sqrt((-16.0 * (math.pow(A, 2.0) * (C * F)))) / ((4.0 * A) * C)
	else:
		tmp = math.pow((2.0 * ((math.hypot(B_m, A) - A) / (-1.0 / F))), 0.5) / -B_m
	return tmp
B_m = abs(B)
A, B_m, C, F = sort([A, B_m, C, F])
function code(A, B_m, C, F)
	tmp = 0.0
	if ((B_m ^ 2.0) <= 4e-174)
		tmp = Float64(sqrt(Float64(-16.0 * Float64((A ^ 2.0) * Float64(C * F)))) / Float64(Float64(4.0 * A) * C));
	else
		tmp = Float64((Float64(2.0 * Float64(Float64(hypot(B_m, A) - A) / Float64(-1.0 / F))) ^ 0.5) / Float64(-B_m));
	end
	return tmp
end
B_m = abs(B);
A, B_m, C, F = num2cell(sort([A, B_m, C, F])){:}
function tmp_2 = code(A, B_m, C, F)
	tmp = 0.0;
	if ((B_m ^ 2.0) <= 4e-174)
		tmp = sqrt((-16.0 * ((A ^ 2.0) * (C * F)))) / ((4.0 * A) * C);
	else
		tmp = ((2.0 * ((hypot(B_m, A) - A) / (-1.0 / F))) ^ 0.5) / -B_m;
	end
	tmp_2 = tmp;
end
B_m = N[Abs[B], $MachinePrecision]
NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
code[A_, B$95$m_, C_, F_] := If[LessEqual[N[Power[B$95$m, 2.0], $MachinePrecision], 4e-174], N[(N[Sqrt[N[(-16.0 * N[(N[Power[A, 2.0], $MachinePrecision] * N[(C * F), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / N[(N[(4.0 * A), $MachinePrecision] * C), $MachinePrecision]), $MachinePrecision], N[(N[Power[N[(2.0 * N[(N[(N[Sqrt[B$95$m ^ 2 + A ^ 2], $MachinePrecision] - A), $MachinePrecision] / N[(-1.0 / F), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], 0.5], $MachinePrecision] / (-B$95$m)), $MachinePrecision]]
\begin{array}{l}
B_m = \left|B\right|
\\
[A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
\\
\begin{array}{l}
\mathbf{if}\;{B\_m}^{2} \leq 4 \cdot 10^{-174}:\\
\;\;\;\;\frac{\sqrt{-16 \cdot \left({A}^{2} \cdot \left(C \cdot F\right)\right)}}{\left(4 \cdot A\right) \cdot C}\\

\mathbf{else}:\\
\;\;\;\;\frac{{\left(2 \cdot \frac{\mathsf{hypot}\left(B\_m, A\right) - A}{\frac{-1}{F}}\right)}^{0.5}}{-B\_m}\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if (pow.f64 B #s(literal 2 binary64)) < 4e-174

    1. Initial program 23.5%

      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    2. Simplified29.6%

      \[\leadsto \color{blue}{\frac{\sqrt{F \cdot \left(\left(A + \left(C - \mathsf{hypot}\left(B, A - C\right)\right)\right) \cdot \left(2 \cdot \mathsf{fma}\left(C, A \cdot -4, {B}^{2}\right)\right)\right)}}{-\mathsf{fma}\left(C, A \cdot -4, {B}^{2}\right)}} \]
    3. Add Preprocessing
    4. Taylor expanded in A around -inf 20.7%

      \[\leadsto \frac{\sqrt{\color{blue}{-16 \cdot \left({A}^{2} \cdot \left(C \cdot F\right)\right)}}}{-\mathsf{fma}\left(C, A \cdot -4, {B}^{2}\right)} \]
    5. Taylor expanded in C around inf 20.6%

      \[\leadsto \frac{\sqrt{-16 \cdot \left({A}^{2} \cdot \left(C \cdot F\right)\right)}}{\color{blue}{4 \cdot \left(A \cdot C\right)}} \]
    6. Step-by-step derivation
      1. associate-*r*20.6%

        \[\leadsto \frac{\sqrt{-16 \cdot \left({A}^{2} \cdot \left(C \cdot F\right)\right)}}{\color{blue}{\left(4 \cdot A\right) \cdot C}} \]
    7. Simplified20.6%

      \[\leadsto \frac{\sqrt{-16 \cdot \left({A}^{2} \cdot \left(C \cdot F\right)\right)}}{\color{blue}{\left(4 \cdot A\right) \cdot C}} \]

    if 4e-174 < (pow.f64 B #s(literal 2 binary64))

    1. Initial program 23.2%

      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    2. Add Preprocessing
    3. Taylor expanded in C around 0 13.9%

      \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}\right)} \]
    4. Step-by-step derivation
      1. mul-1-neg13.9%

        \[\leadsto \color{blue}{-\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}} \]
      2. +-commutative13.9%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{\color{blue}{{B}^{2} + {A}^{2}}}\right)} \]
    5. Simplified13.9%

      \[\leadsto \color{blue}{-\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{{B}^{2} + {A}^{2}}\right)}} \]
    6. Step-by-step derivation
      1. pow1/213.9%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot \color{blue}{{\left(F \cdot \left(A - \sqrt{{B}^{2} + {A}^{2}}\right)\right)}^{0.5}} \]
      2. pow-to-exp13.1%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot \color{blue}{e^{\log \left(F \cdot \left(A - \sqrt{{B}^{2} + {A}^{2}}\right)\right) \cdot 0.5}} \]
      3. unpow213.1%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{\log \left(F \cdot \left(A - \sqrt{\color{blue}{B \cdot B} + {A}^{2}}\right)\right) \cdot 0.5} \]
      4. unpow213.1%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{\log \left(F \cdot \left(A - \sqrt{B \cdot B + \color{blue}{A \cdot A}}\right)\right) \cdot 0.5} \]
      5. hypot-undefine23.5%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{\log \left(F \cdot \left(A - \color{blue}{\mathsf{hypot}\left(B, A\right)}\right)\right) \cdot 0.5} \]
    7. Applied egg-rr23.5%

      \[\leadsto -\frac{\sqrt{2}}{B} \cdot \color{blue}{e^{\log \left(F \cdot \left(A - \mathsf{hypot}\left(B, A\right)\right)\right) \cdot 0.5}} \]
    8. Taylor expanded in F around -inf 12.9%

      \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{\color{blue}{\left(\log \left(-1 \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)\right) + -1 \cdot \log \left(\frac{-1}{F}\right)\right)} \cdot 0.5} \]
    9. Step-by-step derivation
      1. mul-1-neg12.9%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{\left(\log \left(-1 \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)\right) + \color{blue}{\left(-\log \left(\frac{-1}{F}\right)\right)}\right) \cdot 0.5} \]
      2. unsub-neg12.9%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{\color{blue}{\left(\log \left(-1 \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)\right) - \log \left(\frac{-1}{F}\right)\right)} \cdot 0.5} \]
      3. mul-1-neg12.9%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{\left(\log \color{blue}{\left(-\left(A - \sqrt{{A}^{2} + {B}^{2}}\right)\right)} - \log \left(\frac{-1}{F}\right)\right) \cdot 0.5} \]
      4. +-commutative12.9%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{\left(\log \left(-\left(A - \sqrt{\color{blue}{{B}^{2} + {A}^{2}}}\right)\right) - \log \left(\frac{-1}{F}\right)\right) \cdot 0.5} \]
      5. unpow212.9%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{\left(\log \left(-\left(A - \sqrt{\color{blue}{B \cdot B} + {A}^{2}}\right)\right) - \log \left(\frac{-1}{F}\right)\right) \cdot 0.5} \]
      6. unpow212.9%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{\left(\log \left(-\left(A - \sqrt{B \cdot B + \color{blue}{A \cdot A}}\right)\right) - \log \left(\frac{-1}{F}\right)\right) \cdot 0.5} \]
      7. hypot-undefine28.7%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{\left(\log \left(-\left(A - \color{blue}{\mathsf{hypot}\left(B, A\right)}\right)\right) - \log \left(\frac{-1}{F}\right)\right) \cdot 0.5} \]
    10. Simplified28.7%

      \[\leadsto -\frac{\sqrt{2}}{B} \cdot e^{\color{blue}{\left(\log \left(-\left(A - \mathsf{hypot}\left(B, A\right)\right)\right) - \log \left(\frac{-1}{F}\right)\right)} \cdot 0.5} \]
    11. Step-by-step derivation
      1. associate-*l/28.7%

        \[\leadsto -\color{blue}{\frac{\sqrt{2} \cdot e^{\left(\log \left(-\left(A - \mathsf{hypot}\left(B, A\right)\right)\right) - \log \left(\frac{-1}{F}\right)\right) \cdot 0.5}}{B}} \]
      2. pow1/228.7%

        \[\leadsto -\frac{\color{blue}{{2}^{0.5}} \cdot e^{\left(\log \left(-\left(A - \mathsf{hypot}\left(B, A\right)\right)\right) - \log \left(\frac{-1}{F}\right)\right) \cdot 0.5}}{B} \]
      3. exp-prod23.0%

        \[\leadsto -\frac{{2}^{0.5} \cdot \color{blue}{{\left(e^{\log \left(-\left(A - \mathsf{hypot}\left(B, A\right)\right)\right) - \log \left(\frac{-1}{F}\right)}\right)}^{0.5}}}{B} \]
      4. pow-prod-down23.0%

        \[\leadsto -\frac{\color{blue}{{\left(2 \cdot e^{\log \left(-\left(A - \mathsf{hypot}\left(B, A\right)\right)\right) - \log \left(\frac{-1}{F}\right)}\right)}^{0.5}}}{B} \]
      5. diff-log23.5%

        \[\leadsto -\frac{{\left(2 \cdot e^{\color{blue}{\log \left(\frac{-\left(A - \mathsf{hypot}\left(B, A\right)\right)}{\frac{-1}{F}}\right)}}\right)}^{0.5}}{B} \]
      6. add-exp-log25.0%

        \[\leadsto -\frac{{\left(2 \cdot \color{blue}{\frac{-\left(A - \mathsf{hypot}\left(B, A\right)\right)}{\frac{-1}{F}}}\right)}^{0.5}}{B} \]
    12. Applied egg-rr25.0%

      \[\leadsto -\color{blue}{\frac{{\left(2 \cdot \frac{-\left(A - \mathsf{hypot}\left(B, A\right)\right)}{\frac{-1}{F}}\right)}^{0.5}}{B}} \]
  3. Recombined 2 regimes into one program.
  4. Final simplification23.3%

    \[\leadsto \begin{array}{l} \mathbf{if}\;{B}^{2} \leq 4 \cdot 10^{-174}:\\ \;\;\;\;\frac{\sqrt{-16 \cdot \left({A}^{2} \cdot \left(C \cdot F\right)\right)}}{\left(4 \cdot A\right) \cdot C}\\ \mathbf{else}:\\ \;\;\;\;\frac{{\left(2 \cdot \frac{\mathsf{hypot}\left(B, A\right) - A}{\frac{-1}{F}}\right)}^{0.5}}{-B}\\ \end{array} \]
  5. Add Preprocessing

Alternative 12: 40.0% accurate, 2.9× speedup?

\[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} \mathbf{if}\;B\_m \leq 3.1 \cdot 10^{-87}:\\ \;\;\;\;\frac{\sqrt{-16 \cdot \left({A}^{2} \cdot \left(C \cdot F\right)\right)}}{\left(4 \cdot A\right) \cdot C}\\ \mathbf{else}:\\ \;\;\;\;\frac{\sqrt{2 \cdot \left(F \cdot \left(A - \mathsf{hypot}\left(B\_m, A\right)\right)\right)}}{-B\_m}\\ \end{array} \end{array} \]
B_m = (fabs.f64 B)
NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
(FPCore (A B_m C F)
 :precision binary64
 (if (<= B_m 3.1e-87)
   (/ (sqrt (* -16.0 (* (pow A 2.0) (* C F)))) (* (* 4.0 A) C))
   (/ (sqrt (* 2.0 (* F (- A (hypot B_m A))))) (- B_m))))
B_m = fabs(B);
assert(A < B_m && B_m < C && C < F);
double code(double A, double B_m, double C, double F) {
	double tmp;
	if (B_m <= 3.1e-87) {
		tmp = sqrt((-16.0 * (pow(A, 2.0) * (C * F)))) / ((4.0 * A) * C);
	} else {
		tmp = sqrt((2.0 * (F * (A - hypot(B_m, A))))) / -B_m;
	}
	return tmp;
}
B_m = Math.abs(B);
assert A < B_m && B_m < C && C < F;
public static double code(double A, double B_m, double C, double F) {
	double tmp;
	if (B_m <= 3.1e-87) {
		tmp = Math.sqrt((-16.0 * (Math.pow(A, 2.0) * (C * F)))) / ((4.0 * A) * C);
	} else {
		tmp = Math.sqrt((2.0 * (F * (A - Math.hypot(B_m, A))))) / -B_m;
	}
	return tmp;
}
B_m = math.fabs(B)
[A, B_m, C, F] = sort([A, B_m, C, F])
def code(A, B_m, C, F):
	tmp = 0
	if B_m <= 3.1e-87:
		tmp = math.sqrt((-16.0 * (math.pow(A, 2.0) * (C * F)))) / ((4.0 * A) * C)
	else:
		tmp = math.sqrt((2.0 * (F * (A - math.hypot(B_m, A))))) / -B_m
	return tmp
B_m = abs(B)
A, B_m, C, F = sort([A, B_m, C, F])
function code(A, B_m, C, F)
	tmp = 0.0
	if (B_m <= 3.1e-87)
		tmp = Float64(sqrt(Float64(-16.0 * Float64((A ^ 2.0) * Float64(C * F)))) / Float64(Float64(4.0 * A) * C));
	else
		tmp = Float64(sqrt(Float64(2.0 * Float64(F * Float64(A - hypot(B_m, A))))) / Float64(-B_m));
	end
	return tmp
end
B_m = abs(B);
A, B_m, C, F = num2cell(sort([A, B_m, C, F])){:}
function tmp_2 = code(A, B_m, C, F)
	tmp = 0.0;
	if (B_m <= 3.1e-87)
		tmp = sqrt((-16.0 * ((A ^ 2.0) * (C * F)))) / ((4.0 * A) * C);
	else
		tmp = sqrt((2.0 * (F * (A - hypot(B_m, A))))) / -B_m;
	end
	tmp_2 = tmp;
end
B_m = N[Abs[B], $MachinePrecision]
NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
code[A_, B$95$m_, C_, F_] := If[LessEqual[B$95$m, 3.1e-87], N[(N[Sqrt[N[(-16.0 * N[(N[Power[A, 2.0], $MachinePrecision] * N[(C * F), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / N[(N[(4.0 * A), $MachinePrecision] * C), $MachinePrecision]), $MachinePrecision], N[(N[Sqrt[N[(2.0 * N[(F * N[(A - N[Sqrt[B$95$m ^ 2 + A ^ 2], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / (-B$95$m)), $MachinePrecision]]
\begin{array}{l}
B_m = \left|B\right|
\\
[A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
\\
\begin{array}{l}
\mathbf{if}\;B\_m \leq 3.1 \cdot 10^{-87}:\\
\;\;\;\;\frac{\sqrt{-16 \cdot \left({A}^{2} \cdot \left(C \cdot F\right)\right)}}{\left(4 \cdot A\right) \cdot C}\\

\mathbf{else}:\\
\;\;\;\;\frac{\sqrt{2 \cdot \left(F \cdot \left(A - \mathsf{hypot}\left(B\_m, A\right)\right)\right)}}{-B\_m}\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if B < 3.09999999999999998e-87

    1. Initial program 27.1%

      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    2. Simplified29.4%

      \[\leadsto \color{blue}{\frac{\sqrt{F \cdot \left(\left(A + \left(C - \mathsf{hypot}\left(B, A - C\right)\right)\right) \cdot \left(2 \cdot \mathsf{fma}\left(C, A \cdot -4, {B}^{2}\right)\right)\right)}}{-\mathsf{fma}\left(C, A \cdot -4, {B}^{2}\right)}} \]
    3. Add Preprocessing
    4. Taylor expanded in A around -inf 13.5%

      \[\leadsto \frac{\sqrt{\color{blue}{-16 \cdot \left({A}^{2} \cdot \left(C \cdot F\right)\right)}}}{-\mathsf{fma}\left(C, A \cdot -4, {B}^{2}\right)} \]
    5. Taylor expanded in C around inf 14.6%

      \[\leadsto \frac{\sqrt{-16 \cdot \left({A}^{2} \cdot \left(C \cdot F\right)\right)}}{\color{blue}{4 \cdot \left(A \cdot C\right)}} \]
    6. Step-by-step derivation
      1. associate-*r*14.6%

        \[\leadsto \frac{\sqrt{-16 \cdot \left({A}^{2} \cdot \left(C \cdot F\right)\right)}}{\color{blue}{\left(4 \cdot A\right) \cdot C}} \]
    7. Simplified14.6%

      \[\leadsto \frac{\sqrt{-16 \cdot \left({A}^{2} \cdot \left(C \cdot F\right)\right)}}{\color{blue}{\left(4 \cdot A\right) \cdot C}} \]

    if 3.09999999999999998e-87 < B

    1. Initial program 15.8%

      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    2. Add Preprocessing
    3. Taylor expanded in C around 0 24.2%

      \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}\right)} \]
    4. Step-by-step derivation
      1. mul-1-neg24.2%

        \[\leadsto \color{blue}{-\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}} \]
      2. +-commutative24.2%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{\color{blue}{{B}^{2} + {A}^{2}}}\right)} \]
      3. unpow224.2%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{\color{blue}{B \cdot B} + {A}^{2}}\right)} \]
      4. unpow224.2%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{B \cdot B + \color{blue}{A \cdot A}}\right)} \]
      5. hypot-define43.8%

        \[\leadsto -\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \color{blue}{\mathsf{hypot}\left(B, A\right)}\right)} \]
    5. Simplified43.8%

      \[\leadsto \color{blue}{-\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \mathsf{hypot}\left(B, A\right)\right)}} \]
    6. Step-by-step derivation
      1. neg-sub043.8%

        \[\leadsto \color{blue}{0 - \frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \mathsf{hypot}\left(B, A\right)\right)}} \]
      2. associate-*l/43.8%

        \[\leadsto 0 - \color{blue}{\frac{\sqrt{2} \cdot \sqrt{F \cdot \left(A - \mathsf{hypot}\left(B, A\right)\right)}}{B}} \]
      3. pow1/243.8%

        \[\leadsto 0 - \frac{\color{blue}{{2}^{0.5}} \cdot \sqrt{F \cdot \left(A - \mathsf{hypot}\left(B, A\right)\right)}}{B} \]
      4. pow1/243.8%

        \[\leadsto 0 - \frac{{2}^{0.5} \cdot \color{blue}{{\left(F \cdot \left(A - \mathsf{hypot}\left(B, A\right)\right)\right)}^{0.5}}}{B} \]
      5. hypot-undefine24.2%

        \[\leadsto 0 - \frac{{2}^{0.5} \cdot {\left(F \cdot \left(A - \color{blue}{\sqrt{B \cdot B + A \cdot A}}\right)\right)}^{0.5}}{B} \]
      6. unpow224.2%

        \[\leadsto 0 - \frac{{2}^{0.5} \cdot {\left(F \cdot \left(A - \sqrt{\color{blue}{{B}^{2}} + A \cdot A}\right)\right)}^{0.5}}{B} \]
      7. unpow224.2%

        \[\leadsto 0 - \frac{{2}^{0.5} \cdot {\left(F \cdot \left(A - \sqrt{{B}^{2} + \color{blue}{{A}^{2}}}\right)\right)}^{0.5}}{B} \]
      8. pow-prod-down24.2%

        \[\leadsto 0 - \frac{\color{blue}{{\left(2 \cdot \left(F \cdot \left(A - \sqrt{{B}^{2} + {A}^{2}}\right)\right)\right)}^{0.5}}}{B} \]
      9. unpow224.2%

        \[\leadsto 0 - \frac{{\left(2 \cdot \left(F \cdot \left(A - \sqrt{\color{blue}{B \cdot B} + {A}^{2}}\right)\right)\right)}^{0.5}}{B} \]
      10. unpow224.2%

        \[\leadsto 0 - \frac{{\left(2 \cdot \left(F \cdot \left(A - \sqrt{B \cdot B + \color{blue}{A \cdot A}}\right)\right)\right)}^{0.5}}{B} \]
      11. hypot-undefine43.9%

        \[\leadsto 0 - \frac{{\left(2 \cdot \left(F \cdot \left(A - \color{blue}{\mathsf{hypot}\left(B, A\right)}\right)\right)\right)}^{0.5}}{B} \]
    7. Applied egg-rr43.9%

      \[\leadsto \color{blue}{0 - \frac{{\left(2 \cdot \left(F \cdot \left(A - \mathsf{hypot}\left(B, A\right)\right)\right)\right)}^{0.5}}{B}} \]
    8. Step-by-step derivation
      1. neg-sub043.9%

        \[\leadsto \color{blue}{-\frac{{\left(2 \cdot \left(F \cdot \left(A - \mathsf{hypot}\left(B, A\right)\right)\right)\right)}^{0.5}}{B}} \]
      2. distribute-neg-frac243.9%

        \[\leadsto \color{blue}{\frac{{\left(2 \cdot \left(F \cdot \left(A - \mathsf{hypot}\left(B, A\right)\right)\right)\right)}^{0.5}}{-B}} \]
      3. unpow1/243.9%

        \[\leadsto \frac{\color{blue}{\sqrt{2 \cdot \left(F \cdot \left(A - \mathsf{hypot}\left(B, A\right)\right)\right)}}}{-B} \]
    9. Simplified43.9%

      \[\leadsto \color{blue}{\frac{\sqrt{2 \cdot \left(F \cdot \left(A - \mathsf{hypot}\left(B, A\right)\right)\right)}}{-B}} \]
  3. Recombined 2 regimes into one program.
  4. Add Preprocessing

Alternative 13: 32.0% accurate, 3.0× speedup?

\[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \frac{\sqrt{2 \cdot \left(F \cdot \left(A - \mathsf{hypot}\left(B\_m, A\right)\right)\right)}}{-B\_m} \end{array} \]
B_m = (fabs.f64 B)
NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
(FPCore (A B_m C F)
 :precision binary64
 (/ (sqrt (* 2.0 (* F (- A (hypot B_m A))))) (- B_m)))
B_m = fabs(B);
assert(A < B_m && B_m < C && C < F);
double code(double A, double B_m, double C, double F) {
	return sqrt((2.0 * (F * (A - hypot(B_m, A))))) / -B_m;
}
B_m = Math.abs(B);
assert A < B_m && B_m < C && C < F;
public static double code(double A, double B_m, double C, double F) {
	return Math.sqrt((2.0 * (F * (A - Math.hypot(B_m, A))))) / -B_m;
}
B_m = math.fabs(B)
[A, B_m, C, F] = sort([A, B_m, C, F])
def code(A, B_m, C, F):
	return math.sqrt((2.0 * (F * (A - math.hypot(B_m, A))))) / -B_m
B_m = abs(B)
A, B_m, C, F = sort([A, B_m, C, F])
function code(A, B_m, C, F)
	return Float64(sqrt(Float64(2.0 * Float64(F * Float64(A - hypot(B_m, A))))) / Float64(-B_m))
end
B_m = abs(B);
A, B_m, C, F = num2cell(sort([A, B_m, C, F])){:}
function tmp = code(A, B_m, C, F)
	tmp = sqrt((2.0 * (F * (A - hypot(B_m, A))))) / -B_m;
end
B_m = N[Abs[B], $MachinePrecision]
NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
code[A_, B$95$m_, C_, F_] := N[(N[Sqrt[N[(2.0 * N[(F * N[(A - N[Sqrt[B$95$m ^ 2 + A ^ 2], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / (-B$95$m)), $MachinePrecision]
\begin{array}{l}
B_m = \left|B\right|
\\
[A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
\\
\frac{\sqrt{2 \cdot \left(F \cdot \left(A - \mathsf{hypot}\left(B\_m, A\right)\right)\right)}}{-B\_m}
\end{array}
Derivation
  1. Initial program 23.3%

    \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
  2. Add Preprocessing
  3. Taylor expanded in C around 0 9.9%

    \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}\right)} \]
  4. Step-by-step derivation
    1. mul-1-neg9.9%

      \[\leadsto \color{blue}{-\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}} \]
    2. +-commutative9.9%

      \[\leadsto -\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{\color{blue}{{B}^{2} + {A}^{2}}}\right)} \]
    3. unpow29.9%

      \[\leadsto -\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{\color{blue}{B \cdot B} + {A}^{2}}\right)} \]
    4. unpow29.9%

      \[\leadsto -\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{B \cdot B + \color{blue}{A \cdot A}}\right)} \]
    5. hypot-define17.1%

      \[\leadsto -\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \color{blue}{\mathsf{hypot}\left(B, A\right)}\right)} \]
  5. Simplified17.1%

    \[\leadsto \color{blue}{-\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \mathsf{hypot}\left(B, A\right)\right)}} \]
  6. Step-by-step derivation
    1. neg-sub017.1%

      \[\leadsto \color{blue}{0 - \frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \mathsf{hypot}\left(B, A\right)\right)}} \]
    2. associate-*l/17.1%

      \[\leadsto 0 - \color{blue}{\frac{\sqrt{2} \cdot \sqrt{F \cdot \left(A - \mathsf{hypot}\left(B, A\right)\right)}}{B}} \]
    3. pow1/217.1%

      \[\leadsto 0 - \frac{\color{blue}{{2}^{0.5}} \cdot \sqrt{F \cdot \left(A - \mathsf{hypot}\left(B, A\right)\right)}}{B} \]
    4. pow1/217.1%

      \[\leadsto 0 - \frac{{2}^{0.5} \cdot \color{blue}{{\left(F \cdot \left(A - \mathsf{hypot}\left(B, A\right)\right)\right)}^{0.5}}}{B} \]
    5. hypot-undefine10.0%

      \[\leadsto 0 - \frac{{2}^{0.5} \cdot {\left(F \cdot \left(A - \color{blue}{\sqrt{B \cdot B + A \cdot A}}\right)\right)}^{0.5}}{B} \]
    6. unpow210.0%

      \[\leadsto 0 - \frac{{2}^{0.5} \cdot {\left(F \cdot \left(A - \sqrt{\color{blue}{{B}^{2}} + A \cdot A}\right)\right)}^{0.5}}{B} \]
    7. unpow210.0%

      \[\leadsto 0 - \frac{{2}^{0.5} \cdot {\left(F \cdot \left(A - \sqrt{{B}^{2} + \color{blue}{{A}^{2}}}\right)\right)}^{0.5}}{B} \]
    8. pow-prod-down10.0%

      \[\leadsto 0 - \frac{\color{blue}{{\left(2 \cdot \left(F \cdot \left(A - \sqrt{{B}^{2} + {A}^{2}}\right)\right)\right)}^{0.5}}}{B} \]
    9. unpow210.0%

      \[\leadsto 0 - \frac{{\left(2 \cdot \left(F \cdot \left(A - \sqrt{\color{blue}{B \cdot B} + {A}^{2}}\right)\right)\right)}^{0.5}}{B} \]
    10. unpow210.0%

      \[\leadsto 0 - \frac{{\left(2 \cdot \left(F \cdot \left(A - \sqrt{B \cdot B + \color{blue}{A \cdot A}}\right)\right)\right)}^{0.5}}{B} \]
    11. hypot-undefine17.1%

      \[\leadsto 0 - \frac{{\left(2 \cdot \left(F \cdot \left(A - \color{blue}{\mathsf{hypot}\left(B, A\right)}\right)\right)\right)}^{0.5}}{B} \]
  7. Applied egg-rr17.1%

    \[\leadsto \color{blue}{0 - \frac{{\left(2 \cdot \left(F \cdot \left(A - \mathsf{hypot}\left(B, A\right)\right)\right)\right)}^{0.5}}{B}} \]
  8. Step-by-step derivation
    1. neg-sub017.1%

      \[\leadsto \color{blue}{-\frac{{\left(2 \cdot \left(F \cdot \left(A - \mathsf{hypot}\left(B, A\right)\right)\right)\right)}^{0.5}}{B}} \]
    2. distribute-neg-frac217.1%

      \[\leadsto \color{blue}{\frac{{\left(2 \cdot \left(F \cdot \left(A - \mathsf{hypot}\left(B, A\right)\right)\right)\right)}^{0.5}}{-B}} \]
    3. unpow1/217.1%

      \[\leadsto \frac{\color{blue}{\sqrt{2 \cdot \left(F \cdot \left(A - \mathsf{hypot}\left(B, A\right)\right)\right)}}}{-B} \]
  9. Simplified17.1%

    \[\leadsto \color{blue}{\frac{\sqrt{2 \cdot \left(F \cdot \left(A - \mathsf{hypot}\left(B, A\right)\right)\right)}}{-B}} \]
  10. Add Preprocessing

Alternative 14: 27.1% accurate, 5.7× speedup?

\[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \frac{\sqrt{2 \cdot \left(A \cdot F - B\_m \cdot F\right)}}{-B\_m} \end{array} \]
B_m = (fabs.f64 B)
NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
(FPCore (A B_m C F)
 :precision binary64
 (/ (sqrt (* 2.0 (- (* A F) (* B_m F)))) (- B_m)))
B_m = fabs(B);
assert(A < B_m && B_m < C && C < F);
double code(double A, double B_m, double C, double F) {
	return sqrt((2.0 * ((A * F) - (B_m * F)))) / -B_m;
}
B_m = abs(b)
NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
real(8) function code(a, b_m, c, f)
    real(8), intent (in) :: a
    real(8), intent (in) :: b_m
    real(8), intent (in) :: c
    real(8), intent (in) :: f
    code = sqrt((2.0d0 * ((a * f) - (b_m * f)))) / -b_m
end function
B_m = Math.abs(B);
assert A < B_m && B_m < C && C < F;
public static double code(double A, double B_m, double C, double F) {
	return Math.sqrt((2.0 * ((A * F) - (B_m * F)))) / -B_m;
}
B_m = math.fabs(B)
[A, B_m, C, F] = sort([A, B_m, C, F])
def code(A, B_m, C, F):
	return math.sqrt((2.0 * ((A * F) - (B_m * F)))) / -B_m
B_m = abs(B)
A, B_m, C, F = sort([A, B_m, C, F])
function code(A, B_m, C, F)
	return Float64(sqrt(Float64(2.0 * Float64(Float64(A * F) - Float64(B_m * F)))) / Float64(-B_m))
end
B_m = abs(B);
A, B_m, C, F = num2cell(sort([A, B_m, C, F])){:}
function tmp = code(A, B_m, C, F)
	tmp = sqrt((2.0 * ((A * F) - (B_m * F)))) / -B_m;
end
B_m = N[Abs[B], $MachinePrecision]
NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
code[A_, B$95$m_, C_, F_] := N[(N[Sqrt[N[(2.0 * N[(N[(A * F), $MachinePrecision] - N[(B$95$m * F), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / (-B$95$m)), $MachinePrecision]
\begin{array}{l}
B_m = \left|B\right|
\\
[A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
\\
\frac{\sqrt{2 \cdot \left(A \cdot F - B\_m \cdot F\right)}}{-B\_m}
\end{array}
Derivation
  1. Initial program 23.3%

    \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
  2. Add Preprocessing
  3. Taylor expanded in C around 0 9.9%

    \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}\right)} \]
  4. Step-by-step derivation
    1. mul-1-neg9.9%

      \[\leadsto \color{blue}{-\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}} \]
    2. +-commutative9.9%

      \[\leadsto -\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{\color{blue}{{B}^{2} + {A}^{2}}}\right)} \]
    3. unpow29.9%

      \[\leadsto -\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{\color{blue}{B \cdot B} + {A}^{2}}\right)} \]
    4. unpow29.9%

      \[\leadsto -\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{B \cdot B + \color{blue}{A \cdot A}}\right)} \]
    5. hypot-define17.1%

      \[\leadsto -\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \color{blue}{\mathsf{hypot}\left(B, A\right)}\right)} \]
  5. Simplified17.1%

    \[\leadsto \color{blue}{-\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \mathsf{hypot}\left(B, A\right)\right)}} \]
  6. Step-by-step derivation
    1. neg-sub017.1%

      \[\leadsto \color{blue}{0 - \frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \mathsf{hypot}\left(B, A\right)\right)}} \]
    2. associate-*l/17.1%

      \[\leadsto 0 - \color{blue}{\frac{\sqrt{2} \cdot \sqrt{F \cdot \left(A - \mathsf{hypot}\left(B, A\right)\right)}}{B}} \]
    3. pow1/217.1%

      \[\leadsto 0 - \frac{\color{blue}{{2}^{0.5}} \cdot \sqrt{F \cdot \left(A - \mathsf{hypot}\left(B, A\right)\right)}}{B} \]
    4. pow1/217.1%

      \[\leadsto 0 - \frac{{2}^{0.5} \cdot \color{blue}{{\left(F \cdot \left(A - \mathsf{hypot}\left(B, A\right)\right)\right)}^{0.5}}}{B} \]
    5. hypot-undefine10.0%

      \[\leadsto 0 - \frac{{2}^{0.5} \cdot {\left(F \cdot \left(A - \color{blue}{\sqrt{B \cdot B + A \cdot A}}\right)\right)}^{0.5}}{B} \]
    6. unpow210.0%

      \[\leadsto 0 - \frac{{2}^{0.5} \cdot {\left(F \cdot \left(A - \sqrt{\color{blue}{{B}^{2}} + A \cdot A}\right)\right)}^{0.5}}{B} \]
    7. unpow210.0%

      \[\leadsto 0 - \frac{{2}^{0.5} \cdot {\left(F \cdot \left(A - \sqrt{{B}^{2} + \color{blue}{{A}^{2}}}\right)\right)}^{0.5}}{B} \]
    8. pow-prod-down10.0%

      \[\leadsto 0 - \frac{\color{blue}{{\left(2 \cdot \left(F \cdot \left(A - \sqrt{{B}^{2} + {A}^{2}}\right)\right)\right)}^{0.5}}}{B} \]
    9. unpow210.0%

      \[\leadsto 0 - \frac{{\left(2 \cdot \left(F \cdot \left(A - \sqrt{\color{blue}{B \cdot B} + {A}^{2}}\right)\right)\right)}^{0.5}}{B} \]
    10. unpow210.0%

      \[\leadsto 0 - \frac{{\left(2 \cdot \left(F \cdot \left(A - \sqrt{B \cdot B + \color{blue}{A \cdot A}}\right)\right)\right)}^{0.5}}{B} \]
    11. hypot-undefine17.1%

      \[\leadsto 0 - \frac{{\left(2 \cdot \left(F \cdot \left(A - \color{blue}{\mathsf{hypot}\left(B, A\right)}\right)\right)\right)}^{0.5}}{B} \]
  7. Applied egg-rr17.1%

    \[\leadsto \color{blue}{0 - \frac{{\left(2 \cdot \left(F \cdot \left(A - \mathsf{hypot}\left(B, A\right)\right)\right)\right)}^{0.5}}{B}} \]
  8. Step-by-step derivation
    1. neg-sub017.1%

      \[\leadsto \color{blue}{-\frac{{\left(2 \cdot \left(F \cdot \left(A - \mathsf{hypot}\left(B, A\right)\right)\right)\right)}^{0.5}}{B}} \]
    2. distribute-neg-frac217.1%

      \[\leadsto \color{blue}{\frac{{\left(2 \cdot \left(F \cdot \left(A - \mathsf{hypot}\left(B, A\right)\right)\right)\right)}^{0.5}}{-B}} \]
    3. unpow1/217.1%

      \[\leadsto \frac{\color{blue}{\sqrt{2 \cdot \left(F \cdot \left(A - \mathsf{hypot}\left(B, A\right)\right)\right)}}}{-B} \]
  9. Simplified17.1%

    \[\leadsto \color{blue}{\frac{\sqrt{2 \cdot \left(F \cdot \left(A - \mathsf{hypot}\left(B, A\right)\right)\right)}}{-B}} \]
  10. Taylor expanded in A around 0 15.1%

    \[\leadsto \frac{\sqrt{2 \cdot \color{blue}{\left(-1 \cdot \left(B \cdot F\right) + A \cdot F\right)}}}{-B} \]
  11. Step-by-step derivation
    1. +-commutative15.1%

      \[\leadsto \frac{\sqrt{2 \cdot \color{blue}{\left(A \cdot F + -1 \cdot \left(B \cdot F\right)\right)}}}{-B} \]
    2. mul-1-neg15.1%

      \[\leadsto \frac{\sqrt{2 \cdot \left(A \cdot F + \color{blue}{\left(-B \cdot F\right)}\right)}}{-B} \]
    3. unsub-neg15.1%

      \[\leadsto \frac{\sqrt{2 \cdot \color{blue}{\left(A \cdot F - B \cdot F\right)}}}{-B} \]
    4. *-commutative15.1%

      \[\leadsto \frac{\sqrt{2 \cdot \left(\color{blue}{F \cdot A} - B \cdot F\right)}}{-B} \]
  12. Simplified15.1%

    \[\leadsto \frac{\sqrt{2 \cdot \color{blue}{\left(F \cdot A - B \cdot F\right)}}}{-B} \]
  13. Final simplification15.1%

    \[\leadsto \frac{\sqrt{2 \cdot \left(A \cdot F - B \cdot F\right)}}{-B} \]
  14. Add Preprocessing

Alternative 15: 26.8% accurate, 5.9× speedup?

\[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \frac{\sqrt{\left(B\_m \cdot F\right) \cdot -2}}{-B\_m} \end{array} \]
B_m = (fabs.f64 B)
NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
(FPCore (A B_m C F) :precision binary64 (/ (sqrt (* (* B_m F) -2.0)) (- B_m)))
B_m = fabs(B);
assert(A < B_m && B_m < C && C < F);
double code(double A, double B_m, double C, double F) {
	return sqrt(((B_m * F) * -2.0)) / -B_m;
}
B_m = abs(b)
NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
real(8) function code(a, b_m, c, f)
    real(8), intent (in) :: a
    real(8), intent (in) :: b_m
    real(8), intent (in) :: c
    real(8), intent (in) :: f
    code = sqrt(((b_m * f) * (-2.0d0))) / -b_m
end function
B_m = Math.abs(B);
assert A < B_m && B_m < C && C < F;
public static double code(double A, double B_m, double C, double F) {
	return Math.sqrt(((B_m * F) * -2.0)) / -B_m;
}
B_m = math.fabs(B)
[A, B_m, C, F] = sort([A, B_m, C, F])
def code(A, B_m, C, F):
	return math.sqrt(((B_m * F) * -2.0)) / -B_m
B_m = abs(B)
A, B_m, C, F = sort([A, B_m, C, F])
function code(A, B_m, C, F)
	return Float64(sqrt(Float64(Float64(B_m * F) * -2.0)) / Float64(-B_m))
end
B_m = abs(B);
A, B_m, C, F = num2cell(sort([A, B_m, C, F])){:}
function tmp = code(A, B_m, C, F)
	tmp = sqrt(((B_m * F) * -2.0)) / -B_m;
end
B_m = N[Abs[B], $MachinePrecision]
NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
code[A_, B$95$m_, C_, F_] := N[(N[Sqrt[N[(N[(B$95$m * F), $MachinePrecision] * -2.0), $MachinePrecision]], $MachinePrecision] / (-B$95$m)), $MachinePrecision]
\begin{array}{l}
B_m = \left|B\right|
\\
[A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
\\
\frac{\sqrt{\left(B\_m \cdot F\right) \cdot -2}}{-B\_m}
\end{array}
Derivation
  1. Initial program 23.3%

    \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
  2. Add Preprocessing
  3. Taylor expanded in C around 0 9.9%

    \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}\right)} \]
  4. Step-by-step derivation
    1. mul-1-neg9.9%

      \[\leadsto \color{blue}{-\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}} \]
    2. +-commutative9.9%

      \[\leadsto -\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{\color{blue}{{B}^{2} + {A}^{2}}}\right)} \]
    3. unpow29.9%

      \[\leadsto -\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{\color{blue}{B \cdot B} + {A}^{2}}\right)} \]
    4. unpow29.9%

      \[\leadsto -\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{B \cdot B + \color{blue}{A \cdot A}}\right)} \]
    5. hypot-define17.1%

      \[\leadsto -\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \color{blue}{\mathsf{hypot}\left(B, A\right)}\right)} \]
  5. Simplified17.1%

    \[\leadsto \color{blue}{-\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \mathsf{hypot}\left(B, A\right)\right)}} \]
  6. Step-by-step derivation
    1. neg-sub017.1%

      \[\leadsto \color{blue}{0 - \frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \mathsf{hypot}\left(B, A\right)\right)}} \]
    2. associate-*l/17.1%

      \[\leadsto 0 - \color{blue}{\frac{\sqrt{2} \cdot \sqrt{F \cdot \left(A - \mathsf{hypot}\left(B, A\right)\right)}}{B}} \]
    3. pow1/217.1%

      \[\leadsto 0 - \frac{\color{blue}{{2}^{0.5}} \cdot \sqrt{F \cdot \left(A - \mathsf{hypot}\left(B, A\right)\right)}}{B} \]
    4. pow1/217.1%

      \[\leadsto 0 - \frac{{2}^{0.5} \cdot \color{blue}{{\left(F \cdot \left(A - \mathsf{hypot}\left(B, A\right)\right)\right)}^{0.5}}}{B} \]
    5. hypot-undefine10.0%

      \[\leadsto 0 - \frac{{2}^{0.5} \cdot {\left(F \cdot \left(A - \color{blue}{\sqrt{B \cdot B + A \cdot A}}\right)\right)}^{0.5}}{B} \]
    6. unpow210.0%

      \[\leadsto 0 - \frac{{2}^{0.5} \cdot {\left(F \cdot \left(A - \sqrt{\color{blue}{{B}^{2}} + A \cdot A}\right)\right)}^{0.5}}{B} \]
    7. unpow210.0%

      \[\leadsto 0 - \frac{{2}^{0.5} \cdot {\left(F \cdot \left(A - \sqrt{{B}^{2} + \color{blue}{{A}^{2}}}\right)\right)}^{0.5}}{B} \]
    8. pow-prod-down10.0%

      \[\leadsto 0 - \frac{\color{blue}{{\left(2 \cdot \left(F \cdot \left(A - \sqrt{{B}^{2} + {A}^{2}}\right)\right)\right)}^{0.5}}}{B} \]
    9. unpow210.0%

      \[\leadsto 0 - \frac{{\left(2 \cdot \left(F \cdot \left(A - \sqrt{\color{blue}{B \cdot B} + {A}^{2}}\right)\right)\right)}^{0.5}}{B} \]
    10. unpow210.0%

      \[\leadsto 0 - \frac{{\left(2 \cdot \left(F \cdot \left(A - \sqrt{B \cdot B + \color{blue}{A \cdot A}}\right)\right)\right)}^{0.5}}{B} \]
    11. hypot-undefine17.1%

      \[\leadsto 0 - \frac{{\left(2 \cdot \left(F \cdot \left(A - \color{blue}{\mathsf{hypot}\left(B, A\right)}\right)\right)\right)}^{0.5}}{B} \]
  7. Applied egg-rr17.1%

    \[\leadsto \color{blue}{0 - \frac{{\left(2 \cdot \left(F \cdot \left(A - \mathsf{hypot}\left(B, A\right)\right)\right)\right)}^{0.5}}{B}} \]
  8. Step-by-step derivation
    1. neg-sub017.1%

      \[\leadsto \color{blue}{-\frac{{\left(2 \cdot \left(F \cdot \left(A - \mathsf{hypot}\left(B, A\right)\right)\right)\right)}^{0.5}}{B}} \]
    2. distribute-neg-frac217.1%

      \[\leadsto \color{blue}{\frac{{\left(2 \cdot \left(F \cdot \left(A - \mathsf{hypot}\left(B, A\right)\right)\right)\right)}^{0.5}}{-B}} \]
    3. unpow1/217.1%

      \[\leadsto \frac{\color{blue}{\sqrt{2 \cdot \left(F \cdot \left(A - \mathsf{hypot}\left(B, A\right)\right)\right)}}}{-B} \]
  9. Simplified17.1%

    \[\leadsto \color{blue}{\frac{\sqrt{2 \cdot \left(F \cdot \left(A - \mathsf{hypot}\left(B, A\right)\right)\right)}}{-B}} \]
  10. Taylor expanded in A around 0 15.4%

    \[\leadsto \frac{\sqrt{\color{blue}{-2 \cdot \left(B \cdot F\right)}}}{-B} \]
  11. Final simplification15.4%

    \[\leadsto \frac{\sqrt{\left(B \cdot F\right) \cdot -2}}{-B} \]
  12. Add Preprocessing

Alternative 16: 9.0% accurate, 5.9× speedup?

\[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \sqrt{A \cdot F} \cdot \frac{-2}{B\_m} \end{array} \]
B_m = (fabs.f64 B)
NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
(FPCore (A B_m C F) :precision binary64 (* (sqrt (* A F)) (/ -2.0 B_m)))
B_m = fabs(B);
assert(A < B_m && B_m < C && C < F);
double code(double A, double B_m, double C, double F) {
	return sqrt((A * F)) * (-2.0 / B_m);
}
B_m = abs(b)
NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
real(8) function code(a, b_m, c, f)
    real(8), intent (in) :: a
    real(8), intent (in) :: b_m
    real(8), intent (in) :: c
    real(8), intent (in) :: f
    code = sqrt((a * f)) * ((-2.0d0) / b_m)
end function
B_m = Math.abs(B);
assert A < B_m && B_m < C && C < F;
public static double code(double A, double B_m, double C, double F) {
	return Math.sqrt((A * F)) * (-2.0 / B_m);
}
B_m = math.fabs(B)
[A, B_m, C, F] = sort([A, B_m, C, F])
def code(A, B_m, C, F):
	return math.sqrt((A * F)) * (-2.0 / B_m)
B_m = abs(B)
A, B_m, C, F = sort([A, B_m, C, F])
function code(A, B_m, C, F)
	return Float64(sqrt(Float64(A * F)) * Float64(-2.0 / B_m))
end
B_m = abs(B);
A, B_m, C, F = num2cell(sort([A, B_m, C, F])){:}
function tmp = code(A, B_m, C, F)
	tmp = sqrt((A * F)) * (-2.0 / B_m);
end
B_m = N[Abs[B], $MachinePrecision]
NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
code[A_, B$95$m_, C_, F_] := N[(N[Sqrt[N[(A * F), $MachinePrecision]], $MachinePrecision] * N[(-2.0 / B$95$m), $MachinePrecision]), $MachinePrecision]
\begin{array}{l}
B_m = \left|B\right|
\\
[A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
\\
\sqrt{A \cdot F} \cdot \frac{-2}{B\_m}
\end{array}
Derivation
  1. Initial program 23.3%

    \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
  2. Add Preprocessing
  3. Taylor expanded in C around 0 9.9%

    \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}\right)} \]
  4. Step-by-step derivation
    1. mul-1-neg9.9%

      \[\leadsto \color{blue}{-\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}} \]
    2. +-commutative9.9%

      \[\leadsto -\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{\color{blue}{{B}^{2} + {A}^{2}}}\right)} \]
    3. unpow29.9%

      \[\leadsto -\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{\color{blue}{B \cdot B} + {A}^{2}}\right)} \]
    4. unpow29.9%

      \[\leadsto -\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{B \cdot B + \color{blue}{A \cdot A}}\right)} \]
    5. hypot-define17.1%

      \[\leadsto -\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \color{blue}{\mathsf{hypot}\left(B, A\right)}\right)} \]
  5. Simplified17.1%

    \[\leadsto \color{blue}{-\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \mathsf{hypot}\left(B, A\right)\right)}} \]
  6. Step-by-step derivation
    1. div-inv17.0%

      \[\leadsto -\color{blue}{\left(\sqrt{2} \cdot \frac{1}{B}\right)} \cdot \sqrt{F \cdot \left(A - \mathsf{hypot}\left(B, A\right)\right)} \]
  7. Applied egg-rr17.0%

    \[\leadsto -\color{blue}{\left(\sqrt{2} \cdot \frac{1}{B}\right)} \cdot \sqrt{F \cdot \left(A - \mathsf{hypot}\left(B, A\right)\right)} \]
  8. Taylor expanded in A around -inf 0.0%

    \[\leadsto \color{blue}{\sqrt{A \cdot F} \cdot \frac{{\left(\sqrt{-1}\right)}^{2} \cdot {\left(\sqrt{2}\right)}^{2}}{B}} \]
  9. Step-by-step derivation
    1. *-commutative0.0%

      \[\leadsto \sqrt{\color{blue}{F \cdot A}} \cdot \frac{{\left(\sqrt{-1}\right)}^{2} \cdot {\left(\sqrt{2}\right)}^{2}}{B} \]
    2. unpow20.0%

      \[\leadsto \sqrt{F \cdot A} \cdot \frac{\color{blue}{\left(\sqrt{-1} \cdot \sqrt{-1}\right)} \cdot {\left(\sqrt{2}\right)}^{2}}{B} \]
    3. unpow20.0%

      \[\leadsto \sqrt{F \cdot A} \cdot \frac{\left(\sqrt{-1} \cdot \sqrt{-1}\right) \cdot \color{blue}{\left(\sqrt{2} \cdot \sqrt{2}\right)}}{B} \]
    4. rem-square-sqrt2.9%

      \[\leadsto \sqrt{F \cdot A} \cdot \frac{\color{blue}{-1} \cdot \left(\sqrt{2} \cdot \sqrt{2}\right)}{B} \]
    5. rem-square-sqrt2.9%

      \[\leadsto \sqrt{F \cdot A} \cdot \frac{-1 \cdot \color{blue}{2}}{B} \]
    6. metadata-eval2.9%

      \[\leadsto \sqrt{F \cdot A} \cdot \frac{\color{blue}{-2}}{B} \]
  10. Simplified2.9%

    \[\leadsto \color{blue}{\sqrt{F \cdot A} \cdot \frac{-2}{B}} \]
  11. Final simplification2.9%

    \[\leadsto \sqrt{A \cdot F} \cdot \frac{-2}{B} \]
  12. Add Preprocessing

Alternative 17: 1.7% accurate, 6.0× speedup?

\[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ {\left(2 \cdot \frac{F}{B\_m}\right)}^{0.5} \end{array} \]
B_m = (fabs.f64 B)
NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
(FPCore (A B_m C F) :precision binary64 (pow (* 2.0 (/ F B_m)) 0.5))
B_m = fabs(B);
assert(A < B_m && B_m < C && C < F);
double code(double A, double B_m, double C, double F) {
	return pow((2.0 * (F / B_m)), 0.5);
}
B_m = abs(b)
NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
real(8) function code(a, b_m, c, f)
    real(8), intent (in) :: a
    real(8), intent (in) :: b_m
    real(8), intent (in) :: c
    real(8), intent (in) :: f
    code = (2.0d0 * (f / b_m)) ** 0.5d0
end function
B_m = Math.abs(B);
assert A < B_m && B_m < C && C < F;
public static double code(double A, double B_m, double C, double F) {
	return Math.pow((2.0 * (F / B_m)), 0.5);
}
B_m = math.fabs(B)
[A, B_m, C, F] = sort([A, B_m, C, F])
def code(A, B_m, C, F):
	return math.pow((2.0 * (F / B_m)), 0.5)
B_m = abs(B)
A, B_m, C, F = sort([A, B_m, C, F])
function code(A, B_m, C, F)
	return Float64(2.0 * Float64(F / B_m)) ^ 0.5
end
B_m = abs(B);
A, B_m, C, F = num2cell(sort([A, B_m, C, F])){:}
function tmp = code(A, B_m, C, F)
	tmp = (2.0 * (F / B_m)) ^ 0.5;
end
B_m = N[Abs[B], $MachinePrecision]
NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
code[A_, B$95$m_, C_, F_] := N[Power[N[(2.0 * N[(F / B$95$m), $MachinePrecision]), $MachinePrecision], 0.5], $MachinePrecision]
\begin{array}{l}
B_m = \left|B\right|
\\
[A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
\\
{\left(2 \cdot \frac{F}{B\_m}\right)}^{0.5}
\end{array}
Derivation
  1. Initial program 23.3%

    \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
  2. Add Preprocessing
  3. Taylor expanded in B around -inf 0.0%

    \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F}{B}} \cdot \left({\left(\sqrt{-1}\right)}^{2} \cdot \sqrt{2}\right)\right)} \]
  4. Step-by-step derivation
    1. mul-1-neg0.0%

      \[\leadsto \color{blue}{-\sqrt{\frac{F}{B}} \cdot \left({\left(\sqrt{-1}\right)}^{2} \cdot \sqrt{2}\right)} \]
    2. unpow20.0%

      \[\leadsto -\sqrt{\frac{F}{B}} \cdot \left(\color{blue}{\left(\sqrt{-1} \cdot \sqrt{-1}\right)} \cdot \sqrt{2}\right) \]
    3. rem-square-sqrt2.3%

      \[\leadsto -\sqrt{\frac{F}{B}} \cdot \left(\color{blue}{-1} \cdot \sqrt{2}\right) \]
  5. Simplified2.3%

    \[\leadsto \color{blue}{-\sqrt{\frac{F}{B}} \cdot \left(-1 \cdot \sqrt{2}\right)} \]
  6. Taylor expanded in F around 0 2.3%

    \[\leadsto \color{blue}{\sqrt{\frac{F}{B}} \cdot \sqrt{2}} \]
  7. Step-by-step derivation
    1. *-commutative2.3%

      \[\leadsto \color{blue}{\sqrt{2} \cdot \sqrt{\frac{F}{B}}} \]
    2. pow1/22.3%

      \[\leadsto \color{blue}{{2}^{0.5}} \cdot \sqrt{\frac{F}{B}} \]
    3. pow1/22.4%

      \[\leadsto {2}^{0.5} \cdot \color{blue}{{\left(\frac{F}{B}\right)}^{0.5}} \]
    4. pow-prod-down2.4%

      \[\leadsto \color{blue}{{\left(2 \cdot \frac{F}{B}\right)}^{0.5}} \]
  8. Applied egg-rr2.4%

    \[\leadsto \color{blue}{{\left(2 \cdot \frac{F}{B}\right)}^{0.5}} \]
  9. Add Preprocessing

Alternative 18: 1.6% accurate, 6.0× speedup?

\[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \sqrt{\frac{2 \cdot F}{B\_m}} \end{array} \]
B_m = (fabs.f64 B)
NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
(FPCore (A B_m C F) :precision binary64 (sqrt (/ (* 2.0 F) B_m)))
B_m = fabs(B);
assert(A < B_m && B_m < C && C < F);
double code(double A, double B_m, double C, double F) {
	return sqrt(((2.0 * F) / B_m));
}
B_m = abs(b)
NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
real(8) function code(a, b_m, c, f)
    real(8), intent (in) :: a
    real(8), intent (in) :: b_m
    real(8), intent (in) :: c
    real(8), intent (in) :: f
    code = sqrt(((2.0d0 * f) / b_m))
end function
B_m = Math.abs(B);
assert A < B_m && B_m < C && C < F;
public static double code(double A, double B_m, double C, double F) {
	return Math.sqrt(((2.0 * F) / B_m));
}
B_m = math.fabs(B)
[A, B_m, C, F] = sort([A, B_m, C, F])
def code(A, B_m, C, F):
	return math.sqrt(((2.0 * F) / B_m))
B_m = abs(B)
A, B_m, C, F = sort([A, B_m, C, F])
function code(A, B_m, C, F)
	return sqrt(Float64(Float64(2.0 * F) / B_m))
end
B_m = abs(B);
A, B_m, C, F = num2cell(sort([A, B_m, C, F])){:}
function tmp = code(A, B_m, C, F)
	tmp = sqrt(((2.0 * F) / B_m));
end
B_m = N[Abs[B], $MachinePrecision]
NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
code[A_, B$95$m_, C_, F_] := N[Sqrt[N[(N[(2.0 * F), $MachinePrecision] / B$95$m), $MachinePrecision]], $MachinePrecision]
\begin{array}{l}
B_m = \left|B\right|
\\
[A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
\\
\sqrt{\frac{2 \cdot F}{B\_m}}
\end{array}
Derivation
  1. Initial program 23.3%

    \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
  2. Add Preprocessing
  3. Taylor expanded in B around -inf 0.0%

    \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F}{B}} \cdot \left({\left(\sqrt{-1}\right)}^{2} \cdot \sqrt{2}\right)\right)} \]
  4. Step-by-step derivation
    1. mul-1-neg0.0%

      \[\leadsto \color{blue}{-\sqrt{\frac{F}{B}} \cdot \left({\left(\sqrt{-1}\right)}^{2} \cdot \sqrt{2}\right)} \]
    2. unpow20.0%

      \[\leadsto -\sqrt{\frac{F}{B}} \cdot \left(\color{blue}{\left(\sqrt{-1} \cdot \sqrt{-1}\right)} \cdot \sqrt{2}\right) \]
    3. rem-square-sqrt2.3%

      \[\leadsto -\sqrt{\frac{F}{B}} \cdot \left(\color{blue}{-1} \cdot \sqrt{2}\right) \]
  5. Simplified2.3%

    \[\leadsto \color{blue}{-\sqrt{\frac{F}{B}} \cdot \left(-1 \cdot \sqrt{2}\right)} \]
  6. Taylor expanded in F around 0 2.3%

    \[\leadsto \color{blue}{\sqrt{\frac{F}{B}} \cdot \sqrt{2}} \]
  7. Step-by-step derivation
    1. pow12.3%

      \[\leadsto \color{blue}{{\left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)}^{1}} \]
    2. *-commutative2.3%

      \[\leadsto {\color{blue}{\left(\sqrt{2} \cdot \sqrt{\frac{F}{B}}\right)}}^{1} \]
    3. sqrt-unprod2.3%

      \[\leadsto {\color{blue}{\left(\sqrt{2 \cdot \frac{F}{B}}\right)}}^{1} \]
  8. Applied egg-rr2.3%

    \[\leadsto \color{blue}{{\left(\sqrt{2 \cdot \frac{F}{B}}\right)}^{1}} \]
  9. Step-by-step derivation
    1. unpow12.3%

      \[\leadsto \color{blue}{\sqrt{2 \cdot \frac{F}{B}}} \]
    2. associate-*r/2.3%

      \[\leadsto \sqrt{\color{blue}{\frac{2 \cdot F}{B}}} \]
  10. Simplified2.3%

    \[\leadsto \color{blue}{\sqrt{\frac{2 \cdot F}{B}}} \]
  11. Add Preprocessing

Reproduce

?
herbie shell --seed 2024170 
(FPCore (A B C F)
  :name "ABCF->ab-angle b"
  :precision binary64
  (/ (- (sqrt (* (* 2.0 (* (- (pow B 2.0) (* (* 4.0 A) C)) F)) (- (+ A C) (sqrt (+ (pow (- A C) 2.0) (pow B 2.0))))))) (- (pow B 2.0) (* (* 4.0 A) C))))