Cubic critical, narrow range

Percentage Accurate: 55.7% → 91.9%
Time: 15.6s
Alternatives: 15
Speedup: 23.2×

Specification

?
\[\left(\left(1.0536712127723509 \cdot 10^{-8} < a \land a < 94906265.62425156\right) \land \left(1.0536712127723509 \cdot 10^{-8} < b \land b < 94906265.62425156\right)\right) \land \left(1.0536712127723509 \cdot 10^{-8} < c \land c < 94906265.62425156\right)\]
\[\begin{array}{l} \\ \frac{\left(-b\right) + \sqrt{b \cdot b - \left(3 \cdot a\right) \cdot c}}{3 \cdot a} \end{array} \]
(FPCore (a b c)
 :precision binary64
 (/ (+ (- b) (sqrt (- (* b b) (* (* 3.0 a) c)))) (* 3.0 a)))
double code(double a, double b, double c) {
	return (-b + sqrt(((b * b) - ((3.0 * a) * c)))) / (3.0 * a);
}
real(8) function code(a, b, c)
    real(8), intent (in) :: a
    real(8), intent (in) :: b
    real(8), intent (in) :: c
    code = (-b + sqrt(((b * b) - ((3.0d0 * a) * c)))) / (3.0d0 * a)
end function
public static double code(double a, double b, double c) {
	return (-b + Math.sqrt(((b * b) - ((3.0 * a) * c)))) / (3.0 * a);
}
def code(a, b, c):
	return (-b + math.sqrt(((b * b) - ((3.0 * a) * c)))) / (3.0 * a)
function code(a, b, c)
	return Float64(Float64(Float64(-b) + sqrt(Float64(Float64(b * b) - Float64(Float64(3.0 * a) * c)))) / Float64(3.0 * a))
end
function tmp = code(a, b, c)
	tmp = (-b + sqrt(((b * b) - ((3.0 * a) * c)))) / (3.0 * a);
end
code[a_, b_, c_] := N[(N[((-b) + N[Sqrt[N[(N[(b * b), $MachinePrecision] - N[(N[(3.0 * a), $MachinePrecision] * c), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] / N[(3.0 * a), $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
\frac{\left(-b\right) + \sqrt{b \cdot b - \left(3 \cdot a\right) \cdot c}}{3 \cdot a}
\end{array}

Sampling outcomes in binary64 precision:

Local Percentage Accuracy vs ?

The average percentage accuracy by input value. Horizontal axis shows value of an input variable; the variable is choosen in the title. Vertical axis is accuracy; higher is better. Red represent the original program, while blue represents Herbie's suggestion. These can be toggled with buttons below the plot. The line is an average while dots represent individual samples.

Accuracy vs Speed?

Herbie found 15 alternatives:

AlternativeAccuracySpeedup
The accuracy (vertical axis) and speed (horizontal axis) of each alternatives. Up and to the right is better. The red square shows the initial program, and each blue circle shows an alternative.The line shows the best available speed-accuracy tradeoffs.

Initial Program: 55.7% accurate, 1.0× speedup?

\[\begin{array}{l} \\ \frac{\left(-b\right) + \sqrt{b \cdot b - \left(3 \cdot a\right) \cdot c}}{3 \cdot a} \end{array} \]
(FPCore (a b c)
 :precision binary64
 (/ (+ (- b) (sqrt (- (* b b) (* (* 3.0 a) c)))) (* 3.0 a)))
double code(double a, double b, double c) {
	return (-b + sqrt(((b * b) - ((3.0 * a) * c)))) / (3.0 * a);
}
real(8) function code(a, b, c)
    real(8), intent (in) :: a
    real(8), intent (in) :: b
    real(8), intent (in) :: c
    code = (-b + sqrt(((b * b) - ((3.0d0 * a) * c)))) / (3.0d0 * a)
end function
public static double code(double a, double b, double c) {
	return (-b + Math.sqrt(((b * b) - ((3.0 * a) * c)))) / (3.0 * a);
}
def code(a, b, c):
	return (-b + math.sqrt(((b * b) - ((3.0 * a) * c)))) / (3.0 * a)
function code(a, b, c)
	return Float64(Float64(Float64(-b) + sqrt(Float64(Float64(b * b) - Float64(Float64(3.0 * a) * c)))) / Float64(3.0 * a))
end
function tmp = code(a, b, c)
	tmp = (-b + sqrt(((b * b) - ((3.0 * a) * c)))) / (3.0 * a);
end
code[a_, b_, c_] := N[(N[((-b) + N[Sqrt[N[(N[(b * b), $MachinePrecision] - N[(N[(3.0 * a), $MachinePrecision] * c), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] / N[(3.0 * a), $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
\frac{\left(-b\right) + \sqrt{b \cdot b - \left(3 \cdot a\right) \cdot c}}{3 \cdot a}
\end{array}

Alternative 1: 91.9% accurate, 0.1× speedup?

\[\begin{array}{l} \\ \begin{array}{l} t_0 := \mathsf{fma}\left(a, -3, \frac{{b}^{2}}{c}\right)\\ \mathbf{if}\;b \leq 0.092:\\ \;\;\;\;\frac{\frac{\mathsf{fma}\left(c, t\_0, -{b}^{2}\right)}{\mathsf{fma}\left(\sqrt{c}, \sqrt{t\_0}, b\right)}}{a \cdot 3}\\ \mathbf{else}:\\ \;\;\;\;\frac{c \cdot -0.5 + a \cdot \left(-0.375 \cdot \frac{c \cdot c}{{b}^{2}} + a \cdot \left(-1.0546875 \cdot \frac{a \cdot {c}^{4}}{{b}^{6}} + -0.5625 \cdot \frac{{c}^{3}}{{b}^{4}}\right)\right)}{b}\\ \end{array} \end{array} \]
(FPCore (a b c)
 :precision binary64
 (let* ((t_0 (fma a -3.0 (/ (pow b 2.0) c))))
   (if (<= b 0.092)
     (/ (/ (fma c t_0 (- (pow b 2.0))) (fma (sqrt c) (sqrt t_0) b)) (* a 3.0))
     (/
      (+
       (* c -0.5)
       (*
        a
        (+
         (* -0.375 (/ (* c c) (pow b 2.0)))
         (*
          a
          (+
           (* -1.0546875 (/ (* a (pow c 4.0)) (pow b 6.0)))
           (* -0.5625 (/ (pow c 3.0) (pow b 4.0))))))))
      b))))
double code(double a, double b, double c) {
	double t_0 = fma(a, -3.0, (pow(b, 2.0) / c));
	double tmp;
	if (b <= 0.092) {
		tmp = (fma(c, t_0, -pow(b, 2.0)) / fma(sqrt(c), sqrt(t_0), b)) / (a * 3.0);
	} else {
		tmp = ((c * -0.5) + (a * ((-0.375 * ((c * c) / pow(b, 2.0))) + (a * ((-1.0546875 * ((a * pow(c, 4.0)) / pow(b, 6.0))) + (-0.5625 * (pow(c, 3.0) / pow(b, 4.0)))))))) / b;
	}
	return tmp;
}
function code(a, b, c)
	t_0 = fma(a, -3.0, Float64((b ^ 2.0) / c))
	tmp = 0.0
	if (b <= 0.092)
		tmp = Float64(Float64(fma(c, t_0, Float64(-(b ^ 2.0))) / fma(sqrt(c), sqrt(t_0), b)) / Float64(a * 3.0));
	else
		tmp = Float64(Float64(Float64(c * -0.5) + Float64(a * Float64(Float64(-0.375 * Float64(Float64(c * c) / (b ^ 2.0))) + Float64(a * Float64(Float64(-1.0546875 * Float64(Float64(a * (c ^ 4.0)) / (b ^ 6.0))) + Float64(-0.5625 * Float64((c ^ 3.0) / (b ^ 4.0)))))))) / b);
	end
	return tmp
end
code[a_, b_, c_] := Block[{t$95$0 = N[(a * -3.0 + N[(N[Power[b, 2.0], $MachinePrecision] / c), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[b, 0.092], N[(N[(N[(c * t$95$0 + (-N[Power[b, 2.0], $MachinePrecision])), $MachinePrecision] / N[(N[Sqrt[c], $MachinePrecision] * N[Sqrt[t$95$0], $MachinePrecision] + b), $MachinePrecision]), $MachinePrecision] / N[(a * 3.0), $MachinePrecision]), $MachinePrecision], N[(N[(N[(c * -0.5), $MachinePrecision] + N[(a * N[(N[(-0.375 * N[(N[(c * c), $MachinePrecision] / N[Power[b, 2.0], $MachinePrecision]), $MachinePrecision]), $MachinePrecision] + N[(a * N[(N[(-1.0546875 * N[(N[(a * N[Power[c, 4.0], $MachinePrecision]), $MachinePrecision] / N[Power[b, 6.0], $MachinePrecision]), $MachinePrecision]), $MachinePrecision] + N[(-0.5625 * N[(N[Power[c, 3.0], $MachinePrecision] / N[Power[b, 4.0], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] / b), $MachinePrecision]]]
\begin{array}{l}

\\
\begin{array}{l}
t_0 := \mathsf{fma}\left(a, -3, \frac{{b}^{2}}{c}\right)\\
\mathbf{if}\;b \leq 0.092:\\
\;\;\;\;\frac{\frac{\mathsf{fma}\left(c, t\_0, -{b}^{2}\right)}{\mathsf{fma}\left(\sqrt{c}, \sqrt{t\_0}, b\right)}}{a \cdot 3}\\

\mathbf{else}:\\
\;\;\;\;\frac{c \cdot -0.5 + a \cdot \left(-0.375 \cdot \frac{c \cdot c}{{b}^{2}} + a \cdot \left(-1.0546875 \cdot \frac{a \cdot {c}^{4}}{{b}^{6}} + -0.5625 \cdot \frac{{c}^{3}}{{b}^{4}}\right)\right)}{b}\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if b < 0.091999999999999998

    1. Initial program 85.5%

      \[\frac{\left(-b\right) + \sqrt{b \cdot b - \left(3 \cdot a\right) \cdot c}}{3 \cdot a} \]
    2. Step-by-step derivation
      1. Simplified85.9%

        \[\leadsto \color{blue}{\frac{\sqrt{\mathsf{fma}\left(b, b, a \cdot \left(c \cdot -3\right)\right)} - b}{3 \cdot a}} \]
      2. Add Preprocessing
      3. Taylor expanded in c around inf 85.4%

        \[\leadsto \frac{\sqrt{\color{blue}{c \cdot \left(-3 \cdot a + \frac{{b}^{2}}{c}\right)}} - b}{3 \cdot a} \]
      4. Step-by-step derivation
        1. flip--85.9%

          \[\leadsto \frac{\color{blue}{\frac{\sqrt{c \cdot \left(-3 \cdot a + \frac{{b}^{2}}{c}\right)} \cdot \sqrt{c \cdot \left(-3 \cdot a + \frac{{b}^{2}}{c}\right)} - b \cdot b}{\sqrt{c \cdot \left(-3 \cdot a + \frac{{b}^{2}}{c}\right)} + b}}}{3 \cdot a} \]
        2. add-sqr-sqrt86.5%

          \[\leadsto \frac{\frac{\color{blue}{c \cdot \left(-3 \cdot a + \frac{{b}^{2}}{c}\right)} - b \cdot b}{\sqrt{c \cdot \left(-3 \cdot a + \frac{{b}^{2}}{c}\right)} + b}}{3 \cdot a} \]
        3. unpow286.5%

          \[\leadsto \frac{\frac{c \cdot \left(-3 \cdot a + \frac{{b}^{2}}{c}\right) - \color{blue}{{b}^{2}}}{\sqrt{c \cdot \left(-3 \cdot a + \frac{{b}^{2}}{c}\right)} + b}}{3 \cdot a} \]
        4. fmm-def87.6%

          \[\leadsto \frac{\frac{\color{blue}{\mathsf{fma}\left(c, -3 \cdot a + \frac{{b}^{2}}{c}, -{b}^{2}\right)}}{\sqrt{c \cdot \left(-3 \cdot a + \frac{{b}^{2}}{c}\right)} + b}}{3 \cdot a} \]
        5. *-commutative87.6%

          \[\leadsto \frac{\frac{\mathsf{fma}\left(c, \color{blue}{a \cdot -3} + \frac{{b}^{2}}{c}, -{b}^{2}\right)}{\sqrt{c \cdot \left(-3 \cdot a + \frac{{b}^{2}}{c}\right)} + b}}{3 \cdot a} \]
        6. fma-define87.5%

          \[\leadsto \frac{\frac{\mathsf{fma}\left(c, \color{blue}{\mathsf{fma}\left(a, -3, \frac{{b}^{2}}{c}\right)}, -{b}^{2}\right)}{\sqrt{c \cdot \left(-3 \cdot a + \frac{{b}^{2}}{c}\right)} + b}}{3 \cdot a} \]
        7. sqrt-prod87.5%

          \[\leadsto \frac{\frac{\mathsf{fma}\left(c, \mathsf{fma}\left(a, -3, \frac{{b}^{2}}{c}\right), -{b}^{2}\right)}{\color{blue}{\sqrt{c} \cdot \sqrt{-3 \cdot a + \frac{{b}^{2}}{c}}} + b}}{3 \cdot a} \]
        8. fma-define87.5%

          \[\leadsto \frac{\frac{\mathsf{fma}\left(c, \mathsf{fma}\left(a, -3, \frac{{b}^{2}}{c}\right), -{b}^{2}\right)}{\color{blue}{\mathsf{fma}\left(\sqrt{c}, \sqrt{-3 \cdot a + \frac{{b}^{2}}{c}}, b\right)}}}{3 \cdot a} \]
        9. *-commutative87.5%

          \[\leadsto \frac{\frac{\mathsf{fma}\left(c, \mathsf{fma}\left(a, -3, \frac{{b}^{2}}{c}\right), -{b}^{2}\right)}{\mathsf{fma}\left(\sqrt{c}, \sqrt{\color{blue}{a \cdot -3} + \frac{{b}^{2}}{c}}, b\right)}}{3 \cdot a} \]
        10. fma-define87.5%

          \[\leadsto \frac{\frac{\mathsf{fma}\left(c, \mathsf{fma}\left(a, -3, \frac{{b}^{2}}{c}\right), -{b}^{2}\right)}{\mathsf{fma}\left(\sqrt{c}, \sqrt{\color{blue}{\mathsf{fma}\left(a, -3, \frac{{b}^{2}}{c}\right)}}, b\right)}}{3 \cdot a} \]
      5. Applied egg-rr87.5%

        \[\leadsto \frac{\color{blue}{\frac{\mathsf{fma}\left(c, \mathsf{fma}\left(a, -3, \frac{{b}^{2}}{c}\right), -{b}^{2}\right)}{\mathsf{fma}\left(\sqrt{c}, \sqrt{\mathsf{fma}\left(a, -3, \frac{{b}^{2}}{c}\right)}, b\right)}}}{3 \cdot a} \]

      if 0.091999999999999998 < b

      1. Initial program 52.1%

        \[\frac{\left(-b\right) + \sqrt{b \cdot b - \left(3 \cdot a\right) \cdot c}}{3 \cdot a} \]
      2. Step-by-step derivation
        1. Simplified51.9%

          \[\leadsto \color{blue}{\frac{\sqrt{\mathsf{fma}\left(b, b, a \cdot \left(c \cdot -3\right)\right)} - b}{3 \cdot a}} \]
        2. Add Preprocessing
        3. Taylor expanded in b around inf 94.2%

          \[\leadsto \color{blue}{\frac{-0.5625 \cdot \frac{{a}^{2} \cdot {c}^{3}}{{b}^{4}} + \left(-0.5 \cdot c + \left(-0.375 \cdot \frac{a \cdot {c}^{2}}{{b}^{2}} + -0.16666666666666666 \cdot \frac{1.265625 \cdot \left({a}^{4} \cdot {c}^{4}\right) + 5.0625 \cdot \left({a}^{4} \cdot {c}^{4}\right)}{a \cdot {b}^{6}}\right)\right)}{b}} \]
        4. Step-by-step derivation
          1. associate-*r/94.2%

            \[\leadsto \frac{-0.5625 \cdot \frac{{a}^{2} \cdot {c}^{3}}{{b}^{4}} + \left(-0.5 \cdot c + \left(-0.375 \cdot \frac{a \cdot {c}^{2}}{{b}^{2}} + \color{blue}{\frac{-0.16666666666666666 \cdot \left(1.265625 \cdot \left({a}^{4} \cdot {c}^{4}\right) + 5.0625 \cdot \left({a}^{4} \cdot {c}^{4}\right)\right)}{a \cdot {b}^{6}}}\right)\right)}{b} \]
          2. distribute-rgt-out94.2%

            \[\leadsto \frac{-0.5625 \cdot \frac{{a}^{2} \cdot {c}^{3}}{{b}^{4}} + \left(-0.5 \cdot c + \left(-0.375 \cdot \frac{a \cdot {c}^{2}}{{b}^{2}} + \frac{-0.16666666666666666 \cdot \color{blue}{\left(\left({a}^{4} \cdot {c}^{4}\right) \cdot \left(1.265625 + 5.0625\right)\right)}}{a \cdot {b}^{6}}\right)\right)}{b} \]
          3. pow-prod-down94.2%

            \[\leadsto \frac{-0.5625 \cdot \frac{{a}^{2} \cdot {c}^{3}}{{b}^{4}} + \left(-0.5 \cdot c + \left(-0.375 \cdot \frac{a \cdot {c}^{2}}{{b}^{2}} + \frac{-0.16666666666666666 \cdot \left(\color{blue}{{\left(a \cdot c\right)}^{4}} \cdot \left(1.265625 + 5.0625\right)\right)}{a \cdot {b}^{6}}\right)\right)}{b} \]
          4. metadata-eval94.2%

            \[\leadsto \frac{-0.5625 \cdot \frac{{a}^{2} \cdot {c}^{3}}{{b}^{4}} + \left(-0.5 \cdot c + \left(-0.375 \cdot \frac{a \cdot {c}^{2}}{{b}^{2}} + \frac{-0.16666666666666666 \cdot \left({\left(a \cdot c\right)}^{4} \cdot \color{blue}{6.328125}\right)}{a \cdot {b}^{6}}\right)\right)}{b} \]
        5. Applied egg-rr94.2%

          \[\leadsto \frac{-0.5625 \cdot \frac{{a}^{2} \cdot {c}^{3}}{{b}^{4}} + \left(-0.5 \cdot c + \left(-0.375 \cdot \frac{a \cdot {c}^{2}}{{b}^{2}} + \color{blue}{\frac{-0.16666666666666666 \cdot \left({\left(a \cdot c\right)}^{4} \cdot 6.328125\right)}{a \cdot {b}^{6}}}\right)\right)}{b} \]
        6. Taylor expanded in a around 0 94.3%

          \[\leadsto \frac{\color{blue}{-0.5 \cdot c + a \cdot \left(-0.375 \cdot \frac{{c}^{2}}{{b}^{2}} + a \cdot \left(-1.0546875 \cdot \frac{a \cdot {c}^{4}}{{b}^{6}} + -0.5625 \cdot \frac{{c}^{3}}{{b}^{4}}\right)\right)}}{b} \]
        7. Step-by-step derivation
          1. unpow294.3%

            \[\leadsto \frac{-0.5 \cdot c + a \cdot \left(-0.375 \cdot \frac{\color{blue}{c \cdot c}}{{b}^{2}} + a \cdot \left(-1.0546875 \cdot \frac{a \cdot {c}^{4}}{{b}^{6}} + -0.5625 \cdot \frac{{c}^{3}}{{b}^{4}}\right)\right)}{b} \]
        8. Applied egg-rr94.3%

          \[\leadsto \frac{-0.5 \cdot c + a \cdot \left(-0.375 \cdot \frac{\color{blue}{c \cdot c}}{{b}^{2}} + a \cdot \left(-1.0546875 \cdot \frac{a \cdot {c}^{4}}{{b}^{6}} + -0.5625 \cdot \frac{{c}^{3}}{{b}^{4}}\right)\right)}{b} \]
      3. Recombined 2 regimes into one program.
      4. Final simplification93.6%

        \[\leadsto \begin{array}{l} \mathbf{if}\;b \leq 0.092:\\ \;\;\;\;\frac{\frac{\mathsf{fma}\left(c, \mathsf{fma}\left(a, -3, \frac{{b}^{2}}{c}\right), -{b}^{2}\right)}{\mathsf{fma}\left(\sqrt{c}, \sqrt{\mathsf{fma}\left(a, -3, \frac{{b}^{2}}{c}\right)}, b\right)}}{a \cdot 3}\\ \mathbf{else}:\\ \;\;\;\;\frac{c \cdot -0.5 + a \cdot \left(-0.375 \cdot \frac{c \cdot c}{{b}^{2}} + a \cdot \left(-1.0546875 \cdot \frac{a \cdot {c}^{4}}{{b}^{6}} + -0.5625 \cdot \frac{{c}^{3}}{{b}^{4}}\right)\right)}{b}\\ \end{array} \]
      5. Add Preprocessing

      Alternative 2: 90.8% accurate, 0.2× speedup?

      \[\begin{array}{l} \\ \frac{c \cdot -0.5 + a \cdot \left(-0.375 \cdot \frac{c \cdot c}{{b}^{2}} + a \cdot \left(-1.0546875 \cdot \frac{a \cdot {c}^{4}}{{b}^{6}} + -0.5625 \cdot \frac{{c}^{3}}{{b}^{4}}\right)\right)}{b} \end{array} \]
      (FPCore (a b c)
       :precision binary64
       (/
        (+
         (* c -0.5)
         (*
          a
          (+
           (* -0.375 (/ (* c c) (pow b 2.0)))
           (*
            a
            (+
             (* -1.0546875 (/ (* a (pow c 4.0)) (pow b 6.0)))
             (* -0.5625 (/ (pow c 3.0) (pow b 4.0))))))))
        b))
      double code(double a, double b, double c) {
      	return ((c * -0.5) + (a * ((-0.375 * ((c * c) / pow(b, 2.0))) + (a * ((-1.0546875 * ((a * pow(c, 4.0)) / pow(b, 6.0))) + (-0.5625 * (pow(c, 3.0) / pow(b, 4.0)))))))) / b;
      }
      
      real(8) function code(a, b, c)
          real(8), intent (in) :: a
          real(8), intent (in) :: b
          real(8), intent (in) :: c
          code = ((c * (-0.5d0)) + (a * (((-0.375d0) * ((c * c) / (b ** 2.0d0))) + (a * (((-1.0546875d0) * ((a * (c ** 4.0d0)) / (b ** 6.0d0))) + ((-0.5625d0) * ((c ** 3.0d0) / (b ** 4.0d0)))))))) / b
      end function
      
      public static double code(double a, double b, double c) {
      	return ((c * -0.5) + (a * ((-0.375 * ((c * c) / Math.pow(b, 2.0))) + (a * ((-1.0546875 * ((a * Math.pow(c, 4.0)) / Math.pow(b, 6.0))) + (-0.5625 * (Math.pow(c, 3.0) / Math.pow(b, 4.0)))))))) / b;
      }
      
      def code(a, b, c):
      	return ((c * -0.5) + (a * ((-0.375 * ((c * c) / math.pow(b, 2.0))) + (a * ((-1.0546875 * ((a * math.pow(c, 4.0)) / math.pow(b, 6.0))) + (-0.5625 * (math.pow(c, 3.0) / math.pow(b, 4.0)))))))) / b
      
      function code(a, b, c)
      	return Float64(Float64(Float64(c * -0.5) + Float64(a * Float64(Float64(-0.375 * Float64(Float64(c * c) / (b ^ 2.0))) + Float64(a * Float64(Float64(-1.0546875 * Float64(Float64(a * (c ^ 4.0)) / (b ^ 6.0))) + Float64(-0.5625 * Float64((c ^ 3.0) / (b ^ 4.0)))))))) / b)
      end
      
      function tmp = code(a, b, c)
      	tmp = ((c * -0.5) + (a * ((-0.375 * ((c * c) / (b ^ 2.0))) + (a * ((-1.0546875 * ((a * (c ^ 4.0)) / (b ^ 6.0))) + (-0.5625 * ((c ^ 3.0) / (b ^ 4.0)))))))) / b;
      end
      
      code[a_, b_, c_] := N[(N[(N[(c * -0.5), $MachinePrecision] + N[(a * N[(N[(-0.375 * N[(N[(c * c), $MachinePrecision] / N[Power[b, 2.0], $MachinePrecision]), $MachinePrecision]), $MachinePrecision] + N[(a * N[(N[(-1.0546875 * N[(N[(a * N[Power[c, 4.0], $MachinePrecision]), $MachinePrecision] / N[Power[b, 6.0], $MachinePrecision]), $MachinePrecision]), $MachinePrecision] + N[(-0.5625 * N[(N[Power[c, 3.0], $MachinePrecision] / N[Power[b, 4.0], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] / b), $MachinePrecision]
      
      \begin{array}{l}
      
      \\
      \frac{c \cdot -0.5 + a \cdot \left(-0.375 \cdot \frac{c \cdot c}{{b}^{2}} + a \cdot \left(-1.0546875 \cdot \frac{a \cdot {c}^{4}}{{b}^{6}} + -0.5625 \cdot \frac{{c}^{3}}{{b}^{4}}\right)\right)}{b}
      \end{array}
      
      Derivation
      1. Initial program 55.3%

        \[\frac{\left(-b\right) + \sqrt{b \cdot b - \left(3 \cdot a\right) \cdot c}}{3 \cdot a} \]
      2. Step-by-step derivation
        1. Simplified55.2%

          \[\leadsto \color{blue}{\frac{\sqrt{\mathsf{fma}\left(b, b, a \cdot \left(c \cdot -3\right)\right)} - b}{3 \cdot a}} \]
        2. Add Preprocessing
        3. Taylor expanded in b around inf 91.9%

          \[\leadsto \color{blue}{\frac{-0.5625 \cdot \frac{{a}^{2} \cdot {c}^{3}}{{b}^{4}} + \left(-0.5 \cdot c + \left(-0.375 \cdot \frac{a \cdot {c}^{2}}{{b}^{2}} + -0.16666666666666666 \cdot \frac{1.265625 \cdot \left({a}^{4} \cdot {c}^{4}\right) + 5.0625 \cdot \left({a}^{4} \cdot {c}^{4}\right)}{a \cdot {b}^{6}}\right)\right)}{b}} \]
        4. Step-by-step derivation
          1. associate-*r/91.9%

            \[\leadsto \frac{-0.5625 \cdot \frac{{a}^{2} \cdot {c}^{3}}{{b}^{4}} + \left(-0.5 \cdot c + \left(-0.375 \cdot \frac{a \cdot {c}^{2}}{{b}^{2}} + \color{blue}{\frac{-0.16666666666666666 \cdot \left(1.265625 \cdot \left({a}^{4} \cdot {c}^{4}\right) + 5.0625 \cdot \left({a}^{4} \cdot {c}^{4}\right)\right)}{a \cdot {b}^{6}}}\right)\right)}{b} \]
          2. distribute-rgt-out91.9%

            \[\leadsto \frac{-0.5625 \cdot \frac{{a}^{2} \cdot {c}^{3}}{{b}^{4}} + \left(-0.5 \cdot c + \left(-0.375 \cdot \frac{a \cdot {c}^{2}}{{b}^{2}} + \frac{-0.16666666666666666 \cdot \color{blue}{\left(\left({a}^{4} \cdot {c}^{4}\right) \cdot \left(1.265625 + 5.0625\right)\right)}}{a \cdot {b}^{6}}\right)\right)}{b} \]
          3. pow-prod-down91.9%

            \[\leadsto \frac{-0.5625 \cdot \frac{{a}^{2} \cdot {c}^{3}}{{b}^{4}} + \left(-0.5 \cdot c + \left(-0.375 \cdot \frac{a \cdot {c}^{2}}{{b}^{2}} + \frac{-0.16666666666666666 \cdot \left(\color{blue}{{\left(a \cdot c\right)}^{4}} \cdot \left(1.265625 + 5.0625\right)\right)}{a \cdot {b}^{6}}\right)\right)}{b} \]
          4. metadata-eval91.9%

            \[\leadsto \frac{-0.5625 \cdot \frac{{a}^{2} \cdot {c}^{3}}{{b}^{4}} + \left(-0.5 \cdot c + \left(-0.375 \cdot \frac{a \cdot {c}^{2}}{{b}^{2}} + \frac{-0.16666666666666666 \cdot \left({\left(a \cdot c\right)}^{4} \cdot \color{blue}{6.328125}\right)}{a \cdot {b}^{6}}\right)\right)}{b} \]
        5. Applied egg-rr91.9%

          \[\leadsto \frac{-0.5625 \cdot \frac{{a}^{2} \cdot {c}^{3}}{{b}^{4}} + \left(-0.5 \cdot c + \left(-0.375 \cdot \frac{a \cdot {c}^{2}}{{b}^{2}} + \color{blue}{\frac{-0.16666666666666666 \cdot \left({\left(a \cdot c\right)}^{4} \cdot 6.328125\right)}{a \cdot {b}^{6}}}\right)\right)}{b} \]
        6. Taylor expanded in a around 0 91.9%

          \[\leadsto \frac{\color{blue}{-0.5 \cdot c + a \cdot \left(-0.375 \cdot \frac{{c}^{2}}{{b}^{2}} + a \cdot \left(-1.0546875 \cdot \frac{a \cdot {c}^{4}}{{b}^{6}} + -0.5625 \cdot \frac{{c}^{3}}{{b}^{4}}\right)\right)}}{b} \]
        7. Step-by-step derivation
          1. unpow291.9%

            \[\leadsto \frac{-0.5 \cdot c + a \cdot \left(-0.375 \cdot \frac{\color{blue}{c \cdot c}}{{b}^{2}} + a \cdot \left(-1.0546875 \cdot \frac{a \cdot {c}^{4}}{{b}^{6}} + -0.5625 \cdot \frac{{c}^{3}}{{b}^{4}}\right)\right)}{b} \]
        8. Applied egg-rr91.9%

          \[\leadsto \frac{-0.5 \cdot c + a \cdot \left(-0.375 \cdot \frac{\color{blue}{c \cdot c}}{{b}^{2}} + a \cdot \left(-1.0546875 \cdot \frac{a \cdot {c}^{4}}{{b}^{6}} + -0.5625 \cdot \frac{{c}^{3}}{{b}^{4}}\right)\right)}{b} \]
        9. Final simplification91.9%

          \[\leadsto \frac{c \cdot -0.5 + a \cdot \left(-0.375 \cdot \frac{c \cdot c}{{b}^{2}} + a \cdot \left(-1.0546875 \cdot \frac{a \cdot {c}^{4}}{{b}^{6}} + -0.5625 \cdot \frac{{c}^{3}}{{b}^{4}}\right)\right)}{b} \]
        10. Add Preprocessing

        Alternative 3: 90.6% accurate, 0.2× speedup?

        \[\begin{array}{l} \\ \frac{c \cdot \left(c \cdot \left(-0.375 \cdot \frac{a}{{b}^{2}} + c \cdot \left(-1.0546875 \cdot \frac{c \cdot {a}^{3}}{{b}^{6}} + -0.5625 \cdot \frac{{a}^{2}}{{b}^{4}}\right)\right) - 0.5\right)}{b} \end{array} \]
        (FPCore (a b c)
         :precision binary64
         (/
          (*
           c
           (-
            (*
             c
             (+
              (* -0.375 (/ a (pow b 2.0)))
              (*
               c
               (+
                (* -1.0546875 (/ (* c (pow a 3.0)) (pow b 6.0)))
                (* -0.5625 (/ (pow a 2.0) (pow b 4.0)))))))
            0.5))
          b))
        double code(double a, double b, double c) {
        	return (c * ((c * ((-0.375 * (a / pow(b, 2.0))) + (c * ((-1.0546875 * ((c * pow(a, 3.0)) / pow(b, 6.0))) + (-0.5625 * (pow(a, 2.0) / pow(b, 4.0))))))) - 0.5)) / b;
        }
        
        real(8) function code(a, b, c)
            real(8), intent (in) :: a
            real(8), intent (in) :: b
            real(8), intent (in) :: c
            code = (c * ((c * (((-0.375d0) * (a / (b ** 2.0d0))) + (c * (((-1.0546875d0) * ((c * (a ** 3.0d0)) / (b ** 6.0d0))) + ((-0.5625d0) * ((a ** 2.0d0) / (b ** 4.0d0))))))) - 0.5d0)) / b
        end function
        
        public static double code(double a, double b, double c) {
        	return (c * ((c * ((-0.375 * (a / Math.pow(b, 2.0))) + (c * ((-1.0546875 * ((c * Math.pow(a, 3.0)) / Math.pow(b, 6.0))) + (-0.5625 * (Math.pow(a, 2.0) / Math.pow(b, 4.0))))))) - 0.5)) / b;
        }
        
        def code(a, b, c):
        	return (c * ((c * ((-0.375 * (a / math.pow(b, 2.0))) + (c * ((-1.0546875 * ((c * math.pow(a, 3.0)) / math.pow(b, 6.0))) + (-0.5625 * (math.pow(a, 2.0) / math.pow(b, 4.0))))))) - 0.5)) / b
        
        function code(a, b, c)
        	return Float64(Float64(c * Float64(Float64(c * Float64(Float64(-0.375 * Float64(a / (b ^ 2.0))) + Float64(c * Float64(Float64(-1.0546875 * Float64(Float64(c * (a ^ 3.0)) / (b ^ 6.0))) + Float64(-0.5625 * Float64((a ^ 2.0) / (b ^ 4.0))))))) - 0.5)) / b)
        end
        
        function tmp = code(a, b, c)
        	tmp = (c * ((c * ((-0.375 * (a / (b ^ 2.0))) + (c * ((-1.0546875 * ((c * (a ^ 3.0)) / (b ^ 6.0))) + (-0.5625 * ((a ^ 2.0) / (b ^ 4.0))))))) - 0.5)) / b;
        end
        
        code[a_, b_, c_] := N[(N[(c * N[(N[(c * N[(N[(-0.375 * N[(a / N[Power[b, 2.0], $MachinePrecision]), $MachinePrecision]), $MachinePrecision] + N[(c * N[(N[(-1.0546875 * N[(N[(c * N[Power[a, 3.0], $MachinePrecision]), $MachinePrecision] / N[Power[b, 6.0], $MachinePrecision]), $MachinePrecision]), $MachinePrecision] + N[(-0.5625 * N[(N[Power[a, 2.0], $MachinePrecision] / N[Power[b, 4.0], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] - 0.5), $MachinePrecision]), $MachinePrecision] / b), $MachinePrecision]
        
        \begin{array}{l}
        
        \\
        \frac{c \cdot \left(c \cdot \left(-0.375 \cdot \frac{a}{{b}^{2}} + c \cdot \left(-1.0546875 \cdot \frac{c \cdot {a}^{3}}{{b}^{6}} + -0.5625 \cdot \frac{{a}^{2}}{{b}^{4}}\right)\right) - 0.5\right)}{b}
        \end{array}
        
        Derivation
        1. Initial program 55.3%

          \[\frac{\left(-b\right) + \sqrt{b \cdot b - \left(3 \cdot a\right) \cdot c}}{3 \cdot a} \]
        2. Step-by-step derivation
          1. Simplified55.2%

            \[\leadsto \color{blue}{\frac{\sqrt{\mathsf{fma}\left(b, b, a \cdot \left(c \cdot -3\right)\right)} - b}{3 \cdot a}} \]
          2. Add Preprocessing
          3. Taylor expanded in b around inf 91.9%

            \[\leadsto \color{blue}{\frac{-0.5625 \cdot \frac{{a}^{2} \cdot {c}^{3}}{{b}^{4}} + \left(-0.5 \cdot c + \left(-0.375 \cdot \frac{a \cdot {c}^{2}}{{b}^{2}} + -0.16666666666666666 \cdot \frac{1.265625 \cdot \left({a}^{4} \cdot {c}^{4}\right) + 5.0625 \cdot \left({a}^{4} \cdot {c}^{4}\right)}{a \cdot {b}^{6}}\right)\right)}{b}} \]
          4. Step-by-step derivation
            1. associate-*r/91.9%

              \[\leadsto \frac{-0.5625 \cdot \frac{{a}^{2} \cdot {c}^{3}}{{b}^{4}} + \left(-0.5 \cdot c + \left(-0.375 \cdot \frac{a \cdot {c}^{2}}{{b}^{2}} + \color{blue}{\frac{-0.16666666666666666 \cdot \left(1.265625 \cdot \left({a}^{4} \cdot {c}^{4}\right) + 5.0625 \cdot \left({a}^{4} \cdot {c}^{4}\right)\right)}{a \cdot {b}^{6}}}\right)\right)}{b} \]
            2. distribute-rgt-out91.9%

              \[\leadsto \frac{-0.5625 \cdot \frac{{a}^{2} \cdot {c}^{3}}{{b}^{4}} + \left(-0.5 \cdot c + \left(-0.375 \cdot \frac{a \cdot {c}^{2}}{{b}^{2}} + \frac{-0.16666666666666666 \cdot \color{blue}{\left(\left({a}^{4} \cdot {c}^{4}\right) \cdot \left(1.265625 + 5.0625\right)\right)}}{a \cdot {b}^{6}}\right)\right)}{b} \]
            3. pow-prod-down91.9%

              \[\leadsto \frac{-0.5625 \cdot \frac{{a}^{2} \cdot {c}^{3}}{{b}^{4}} + \left(-0.5 \cdot c + \left(-0.375 \cdot \frac{a \cdot {c}^{2}}{{b}^{2}} + \frac{-0.16666666666666666 \cdot \left(\color{blue}{{\left(a \cdot c\right)}^{4}} \cdot \left(1.265625 + 5.0625\right)\right)}{a \cdot {b}^{6}}\right)\right)}{b} \]
            4. metadata-eval91.9%

              \[\leadsto \frac{-0.5625 \cdot \frac{{a}^{2} \cdot {c}^{3}}{{b}^{4}} + \left(-0.5 \cdot c + \left(-0.375 \cdot \frac{a \cdot {c}^{2}}{{b}^{2}} + \frac{-0.16666666666666666 \cdot \left({\left(a \cdot c\right)}^{4} \cdot \color{blue}{6.328125}\right)}{a \cdot {b}^{6}}\right)\right)}{b} \]
          5. Applied egg-rr91.9%

            \[\leadsto \frac{-0.5625 \cdot \frac{{a}^{2} \cdot {c}^{3}}{{b}^{4}} + \left(-0.5 \cdot c + \left(-0.375 \cdot \frac{a \cdot {c}^{2}}{{b}^{2}} + \color{blue}{\frac{-0.16666666666666666 \cdot \left({\left(a \cdot c\right)}^{4} \cdot 6.328125\right)}{a \cdot {b}^{6}}}\right)\right)}{b} \]
          6. Taylor expanded in c around 0 91.8%

            \[\leadsto \frac{\color{blue}{c \cdot \left(c \cdot \left(-0.375 \cdot \frac{a}{{b}^{2}} + c \cdot \left(-1.0546875 \cdot \frac{{a}^{3} \cdot c}{{b}^{6}} + -0.5625 \cdot \frac{{a}^{2}}{{b}^{4}}\right)\right) - 0.5\right)}}{b} \]
          7. Final simplification91.8%

            \[\leadsto \frac{c \cdot \left(c \cdot \left(-0.375 \cdot \frac{a}{{b}^{2}} + c \cdot \left(-1.0546875 \cdot \frac{c \cdot {a}^{3}}{{b}^{6}} + -0.5625 \cdot \frac{{a}^{2}}{{b}^{4}}\right)\right) - 0.5\right)}{b} \]
          8. Add Preprocessing

          Alternative 4: 89.3% accurate, 0.3× speedup?

          \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;b \leq 0.095:\\ \;\;\;\;\frac{\sqrt{\mathsf{fma}\left(b, b, a \cdot \left(c \cdot -3\right)\right)} - b}{a \cdot 3}\\ \mathbf{else}:\\ \;\;\;\;\frac{c \cdot -0.5 + a \cdot \left(-0.5625 \cdot \frac{a \cdot {c}^{3}}{{b}^{4}} + -0.375 \cdot \frac{{c}^{2}}{{b}^{2}}\right)}{b}\\ \end{array} \end{array} \]
          (FPCore (a b c)
           :precision binary64
           (if (<= b 0.095)
             (/ (- (sqrt (fma b b (* a (* c -3.0)))) b) (* a 3.0))
             (/
              (+
               (* c -0.5)
               (*
                a
                (+
                 (* -0.5625 (/ (* a (pow c 3.0)) (pow b 4.0)))
                 (* -0.375 (/ (pow c 2.0) (pow b 2.0))))))
              b)))
          double code(double a, double b, double c) {
          	double tmp;
          	if (b <= 0.095) {
          		tmp = (sqrt(fma(b, b, (a * (c * -3.0)))) - b) / (a * 3.0);
          	} else {
          		tmp = ((c * -0.5) + (a * ((-0.5625 * ((a * pow(c, 3.0)) / pow(b, 4.0))) + (-0.375 * (pow(c, 2.0) / pow(b, 2.0)))))) / b;
          	}
          	return tmp;
          }
          
          function code(a, b, c)
          	tmp = 0.0
          	if (b <= 0.095)
          		tmp = Float64(Float64(sqrt(fma(b, b, Float64(a * Float64(c * -3.0)))) - b) / Float64(a * 3.0));
          	else
          		tmp = Float64(Float64(Float64(c * -0.5) + Float64(a * Float64(Float64(-0.5625 * Float64(Float64(a * (c ^ 3.0)) / (b ^ 4.0))) + Float64(-0.375 * Float64((c ^ 2.0) / (b ^ 2.0)))))) / b);
          	end
          	return tmp
          end
          
          code[a_, b_, c_] := If[LessEqual[b, 0.095], N[(N[(N[Sqrt[N[(b * b + N[(a * N[(c * -3.0), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] - b), $MachinePrecision] / N[(a * 3.0), $MachinePrecision]), $MachinePrecision], N[(N[(N[(c * -0.5), $MachinePrecision] + N[(a * N[(N[(-0.5625 * N[(N[(a * N[Power[c, 3.0], $MachinePrecision]), $MachinePrecision] / N[Power[b, 4.0], $MachinePrecision]), $MachinePrecision]), $MachinePrecision] + N[(-0.375 * N[(N[Power[c, 2.0], $MachinePrecision] / N[Power[b, 2.0], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] / b), $MachinePrecision]]
          
          \begin{array}{l}
          
          \\
          \begin{array}{l}
          \mathbf{if}\;b \leq 0.095:\\
          \;\;\;\;\frac{\sqrt{\mathsf{fma}\left(b, b, a \cdot \left(c \cdot -3\right)\right)} - b}{a \cdot 3}\\
          
          \mathbf{else}:\\
          \;\;\;\;\frac{c \cdot -0.5 + a \cdot \left(-0.5625 \cdot \frac{a \cdot {c}^{3}}{{b}^{4}} + -0.375 \cdot \frac{{c}^{2}}{{b}^{2}}\right)}{b}\\
          
          
          \end{array}
          \end{array}
          
          Derivation
          1. Split input into 2 regimes
          2. if b < 0.095000000000000001

            1. Initial program 85.5%

              \[\frac{\left(-b\right) + \sqrt{b \cdot b - \left(3 \cdot a\right) \cdot c}}{3 \cdot a} \]
            2. Step-by-step derivation
              1. Simplified85.9%

                \[\leadsto \color{blue}{\frac{\sqrt{\mathsf{fma}\left(b, b, a \cdot \left(c \cdot -3\right)\right)} - b}{3 \cdot a}} \]
              2. Add Preprocessing

              if 0.095000000000000001 < b

              1. Initial program 52.1%

                \[\frac{\left(-b\right) + \sqrt{b \cdot b - \left(3 \cdot a\right) \cdot c}}{3 \cdot a} \]
              2. Step-by-step derivation
                1. Simplified51.9%

                  \[\leadsto \color{blue}{\frac{\sqrt{\mathsf{fma}\left(b, b, a \cdot \left(c \cdot -3\right)\right)} - b}{3 \cdot a}} \]
                2. Add Preprocessing
                3. Taylor expanded in b around inf 94.2%

                  \[\leadsto \color{blue}{\frac{-0.5625 \cdot \frac{{a}^{2} \cdot {c}^{3}}{{b}^{4}} + \left(-0.5 \cdot c + \left(-0.375 \cdot \frac{a \cdot {c}^{2}}{{b}^{2}} + -0.16666666666666666 \cdot \frac{1.265625 \cdot \left({a}^{4} \cdot {c}^{4}\right) + 5.0625 \cdot \left({a}^{4} \cdot {c}^{4}\right)}{a \cdot {b}^{6}}\right)\right)}{b}} \]
                4. Taylor expanded in a around 0 91.5%

                  \[\leadsto \frac{\color{blue}{-0.5 \cdot c + a \cdot \left(-0.5625 \cdot \frac{a \cdot {c}^{3}}{{b}^{4}} + -0.375 \cdot \frac{{c}^{2}}{{b}^{2}}\right)}}{b} \]
              3. Recombined 2 regimes into one program.
              4. Final simplification91.0%

                \[\leadsto \begin{array}{l} \mathbf{if}\;b \leq 0.095:\\ \;\;\;\;\frac{\sqrt{\mathsf{fma}\left(b, b, a \cdot \left(c \cdot -3\right)\right)} - b}{a \cdot 3}\\ \mathbf{else}:\\ \;\;\;\;\frac{c \cdot -0.5 + a \cdot \left(-0.5625 \cdot \frac{a \cdot {c}^{3}}{{b}^{4}} + -0.375 \cdot \frac{{c}^{2}}{{b}^{2}}\right)}{b}\\ \end{array} \]
              5. Add Preprocessing

              Alternative 5: 89.3% accurate, 0.3× speedup?

              \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;b \leq 0.095:\\ \;\;\;\;\frac{\sqrt{\mathsf{fma}\left(b, b, a \cdot \left(c \cdot -3\right)\right)} - b}{a \cdot 3}\\ \mathbf{else}:\\ \;\;\;\;-0.5 \cdot \frac{c}{b} + a \cdot \left(-0.5625 \cdot \frac{a \cdot {c}^{3}}{{b}^{5}} + -0.375 \cdot \frac{{c}^{2}}{{b}^{3}}\right)\\ \end{array} \end{array} \]
              (FPCore (a b c)
               :precision binary64
               (if (<= b 0.095)
                 (/ (- (sqrt (fma b b (* a (* c -3.0)))) b) (* a 3.0))
                 (+
                  (* -0.5 (/ c b))
                  (*
                   a
                   (+
                    (* -0.5625 (/ (* a (pow c 3.0)) (pow b 5.0)))
                    (* -0.375 (/ (pow c 2.0) (pow b 3.0))))))))
              double code(double a, double b, double c) {
              	double tmp;
              	if (b <= 0.095) {
              		tmp = (sqrt(fma(b, b, (a * (c * -3.0)))) - b) / (a * 3.0);
              	} else {
              		tmp = (-0.5 * (c / b)) + (a * ((-0.5625 * ((a * pow(c, 3.0)) / pow(b, 5.0))) + (-0.375 * (pow(c, 2.0) / pow(b, 3.0)))));
              	}
              	return tmp;
              }
              
              function code(a, b, c)
              	tmp = 0.0
              	if (b <= 0.095)
              		tmp = Float64(Float64(sqrt(fma(b, b, Float64(a * Float64(c * -3.0)))) - b) / Float64(a * 3.0));
              	else
              		tmp = Float64(Float64(-0.5 * Float64(c / b)) + Float64(a * Float64(Float64(-0.5625 * Float64(Float64(a * (c ^ 3.0)) / (b ^ 5.0))) + Float64(-0.375 * Float64((c ^ 2.0) / (b ^ 3.0))))));
              	end
              	return tmp
              end
              
              code[a_, b_, c_] := If[LessEqual[b, 0.095], N[(N[(N[Sqrt[N[(b * b + N[(a * N[(c * -3.0), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] - b), $MachinePrecision] / N[(a * 3.0), $MachinePrecision]), $MachinePrecision], N[(N[(-0.5 * N[(c / b), $MachinePrecision]), $MachinePrecision] + N[(a * N[(N[(-0.5625 * N[(N[(a * N[Power[c, 3.0], $MachinePrecision]), $MachinePrecision] / N[Power[b, 5.0], $MachinePrecision]), $MachinePrecision]), $MachinePrecision] + N[(-0.375 * N[(N[Power[c, 2.0], $MachinePrecision] / N[Power[b, 3.0], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]]
              
              \begin{array}{l}
              
              \\
              \begin{array}{l}
              \mathbf{if}\;b \leq 0.095:\\
              \;\;\;\;\frac{\sqrt{\mathsf{fma}\left(b, b, a \cdot \left(c \cdot -3\right)\right)} - b}{a \cdot 3}\\
              
              \mathbf{else}:\\
              \;\;\;\;-0.5 \cdot \frac{c}{b} + a \cdot \left(-0.5625 \cdot \frac{a \cdot {c}^{3}}{{b}^{5}} + -0.375 \cdot \frac{{c}^{2}}{{b}^{3}}\right)\\
              
              
              \end{array}
              \end{array}
              
              Derivation
              1. Split input into 2 regimes
              2. if b < 0.095000000000000001

                1. Initial program 85.5%

                  \[\frac{\left(-b\right) + \sqrt{b \cdot b - \left(3 \cdot a\right) \cdot c}}{3 \cdot a} \]
                2. Step-by-step derivation
                  1. Simplified85.9%

                    \[\leadsto \color{blue}{\frac{\sqrt{\mathsf{fma}\left(b, b, a \cdot \left(c \cdot -3\right)\right)} - b}{3 \cdot a}} \]
                  2. Add Preprocessing

                  if 0.095000000000000001 < b

                  1. Initial program 52.1%

                    \[\frac{\left(-b\right) + \sqrt{b \cdot b - \left(3 \cdot a\right) \cdot c}}{3 \cdot a} \]
                  2. Step-by-step derivation
                    1. Simplified51.9%

                      \[\leadsto \color{blue}{\frac{\sqrt{\mathsf{fma}\left(b, b, a \cdot \left(c \cdot -3\right)\right)} - b}{3 \cdot a}} \]
                    2. Add Preprocessing
                    3. Taylor expanded in a around 0 91.5%

                      \[\leadsto \color{blue}{-0.5 \cdot \frac{c}{b} + a \cdot \left(-0.5625 \cdot \frac{a \cdot {c}^{3}}{{b}^{5}} + -0.375 \cdot \frac{{c}^{2}}{{b}^{3}}\right)} \]
                  3. Recombined 2 regimes into one program.
                  4. Final simplification90.9%

                    \[\leadsto \begin{array}{l} \mathbf{if}\;b \leq 0.095:\\ \;\;\;\;\frac{\sqrt{\mathsf{fma}\left(b, b, a \cdot \left(c \cdot -3\right)\right)} - b}{a \cdot 3}\\ \mathbf{else}:\\ \;\;\;\;-0.5 \cdot \frac{c}{b} + a \cdot \left(-0.5625 \cdot \frac{a \cdot {c}^{3}}{{b}^{5}} + -0.375 \cdot \frac{{c}^{2}}{{b}^{3}}\right)\\ \end{array} \]
                  5. Add Preprocessing

                  Alternative 6: 85.1% accurate, 0.3× speedup?

                  \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;\frac{\sqrt{b \cdot b - c \cdot \left(a \cdot 3\right)} - b}{a \cdot 3} \leq -0.095:\\ \;\;\;\;\frac{\sqrt{\mathsf{fma}\left(b, b, a \cdot \left(c \cdot -3\right)\right)} - b}{a \cdot 3}\\ \mathbf{else}:\\ \;\;\;\;\frac{c \cdot -0.5 + -0.375 \cdot \frac{a \cdot {c}^{2}}{{b}^{2}}}{b}\\ \end{array} \end{array} \]
                  (FPCore (a b c)
                   :precision binary64
                   (if (<= (/ (- (sqrt (- (* b b) (* c (* a 3.0)))) b) (* a 3.0)) -0.095)
                     (/ (- (sqrt (fma b b (* a (* c -3.0)))) b) (* a 3.0))
                     (/ (+ (* c -0.5) (* -0.375 (/ (* a (pow c 2.0)) (pow b 2.0)))) b)))
                  double code(double a, double b, double c) {
                  	double tmp;
                  	if (((sqrt(((b * b) - (c * (a * 3.0)))) - b) / (a * 3.0)) <= -0.095) {
                  		tmp = (sqrt(fma(b, b, (a * (c * -3.0)))) - b) / (a * 3.0);
                  	} else {
                  		tmp = ((c * -0.5) + (-0.375 * ((a * pow(c, 2.0)) / pow(b, 2.0)))) / b;
                  	}
                  	return tmp;
                  }
                  
                  function code(a, b, c)
                  	tmp = 0.0
                  	if (Float64(Float64(sqrt(Float64(Float64(b * b) - Float64(c * Float64(a * 3.0)))) - b) / Float64(a * 3.0)) <= -0.095)
                  		tmp = Float64(Float64(sqrt(fma(b, b, Float64(a * Float64(c * -3.0)))) - b) / Float64(a * 3.0));
                  	else
                  		tmp = Float64(Float64(Float64(c * -0.5) + Float64(-0.375 * Float64(Float64(a * (c ^ 2.0)) / (b ^ 2.0)))) / b);
                  	end
                  	return tmp
                  end
                  
                  code[a_, b_, c_] := If[LessEqual[N[(N[(N[Sqrt[N[(N[(b * b), $MachinePrecision] - N[(c * N[(a * 3.0), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] - b), $MachinePrecision] / N[(a * 3.0), $MachinePrecision]), $MachinePrecision], -0.095], N[(N[(N[Sqrt[N[(b * b + N[(a * N[(c * -3.0), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] - b), $MachinePrecision] / N[(a * 3.0), $MachinePrecision]), $MachinePrecision], N[(N[(N[(c * -0.5), $MachinePrecision] + N[(-0.375 * N[(N[(a * N[Power[c, 2.0], $MachinePrecision]), $MachinePrecision] / N[Power[b, 2.0], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] / b), $MachinePrecision]]
                  
                  \begin{array}{l}
                  
                  \\
                  \begin{array}{l}
                  \mathbf{if}\;\frac{\sqrt{b \cdot b - c \cdot \left(a \cdot 3\right)} - b}{a \cdot 3} \leq -0.095:\\
                  \;\;\;\;\frac{\sqrt{\mathsf{fma}\left(b, b, a \cdot \left(c \cdot -3\right)\right)} - b}{a \cdot 3}\\
                  
                  \mathbf{else}:\\
                  \;\;\;\;\frac{c \cdot -0.5 + -0.375 \cdot \frac{a \cdot {c}^{2}}{{b}^{2}}}{b}\\
                  
                  
                  \end{array}
                  \end{array}
                  
                  Derivation
                  1. Split input into 2 regimes
                  2. if (/.f64 (+.f64 (neg.f64 b) (sqrt.f64 (-.f64 (*.f64 b b) (*.f64 (*.f64 #s(literal 3 binary64) a) c)))) (*.f64 #s(literal 3 binary64) a)) < -0.095000000000000001

                    1. Initial program 82.1%

                      \[\frac{\left(-b\right) + \sqrt{b \cdot b - \left(3 \cdot a\right) \cdot c}}{3 \cdot a} \]
                    2. Step-by-step derivation
                      1. Simplified82.3%

                        \[\leadsto \color{blue}{\frac{\sqrt{\mathsf{fma}\left(b, b, a \cdot \left(c \cdot -3\right)\right)} - b}{3 \cdot a}} \]
                      2. Add Preprocessing

                      if -0.095000000000000001 < (/.f64 (+.f64 (neg.f64 b) (sqrt.f64 (-.f64 (*.f64 b b) (*.f64 (*.f64 #s(literal 3 binary64) a) c)))) (*.f64 #s(literal 3 binary64) a))

                      1. Initial program 48.8%

                        \[\frac{\left(-b\right) + \sqrt{b \cdot b - \left(3 \cdot a\right) \cdot c}}{3 \cdot a} \]
                      2. Step-by-step derivation
                        1. Simplified48.7%

                          \[\leadsto \color{blue}{\frac{\sqrt{\mathsf{fma}\left(b, b, a \cdot \left(c \cdot -3\right)\right)} - b}{3 \cdot a}} \]
                        2. Add Preprocessing
                        3. Taylor expanded in b around inf 87.6%

                          \[\leadsto \color{blue}{\frac{-0.5 \cdot c + -0.375 \cdot \frac{a \cdot {c}^{2}}{{b}^{2}}}{b}} \]
                      3. Recombined 2 regimes into one program.
                      4. Final simplification86.6%

                        \[\leadsto \begin{array}{l} \mathbf{if}\;\frac{\sqrt{b \cdot b - c \cdot \left(a \cdot 3\right)} - b}{a \cdot 3} \leq -0.095:\\ \;\;\;\;\frac{\sqrt{\mathsf{fma}\left(b, b, a \cdot \left(c \cdot -3\right)\right)} - b}{a \cdot 3}\\ \mathbf{else}:\\ \;\;\;\;\frac{c \cdot -0.5 + -0.375 \cdot \frac{a \cdot {c}^{2}}{{b}^{2}}}{b}\\ \end{array} \]
                      5. Add Preprocessing

                      Alternative 7: 85.1% accurate, 0.3× speedup?

                      \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;\frac{\sqrt{b \cdot b - c \cdot \left(a \cdot 3\right)} - b}{a \cdot 3} \leq -0.095:\\ \;\;\;\;\frac{\sqrt{\mathsf{fma}\left(b, b, a \cdot \left(c \cdot -3\right)\right)} - b}{a \cdot 3}\\ \mathbf{else}:\\ \;\;\;\;-0.5 \cdot \frac{c}{b} + -0.375 \cdot \frac{a \cdot {c}^{2}}{{b}^{3}}\\ \end{array} \end{array} \]
                      (FPCore (a b c)
                       :precision binary64
                       (if (<= (/ (- (sqrt (- (* b b) (* c (* a 3.0)))) b) (* a 3.0)) -0.095)
                         (/ (- (sqrt (fma b b (* a (* c -3.0)))) b) (* a 3.0))
                         (+ (* -0.5 (/ c b)) (* -0.375 (/ (* a (pow c 2.0)) (pow b 3.0))))))
                      double code(double a, double b, double c) {
                      	double tmp;
                      	if (((sqrt(((b * b) - (c * (a * 3.0)))) - b) / (a * 3.0)) <= -0.095) {
                      		tmp = (sqrt(fma(b, b, (a * (c * -3.0)))) - b) / (a * 3.0);
                      	} else {
                      		tmp = (-0.5 * (c / b)) + (-0.375 * ((a * pow(c, 2.0)) / pow(b, 3.0)));
                      	}
                      	return tmp;
                      }
                      
                      function code(a, b, c)
                      	tmp = 0.0
                      	if (Float64(Float64(sqrt(Float64(Float64(b * b) - Float64(c * Float64(a * 3.0)))) - b) / Float64(a * 3.0)) <= -0.095)
                      		tmp = Float64(Float64(sqrt(fma(b, b, Float64(a * Float64(c * -3.0)))) - b) / Float64(a * 3.0));
                      	else
                      		tmp = Float64(Float64(-0.5 * Float64(c / b)) + Float64(-0.375 * Float64(Float64(a * (c ^ 2.0)) / (b ^ 3.0))));
                      	end
                      	return tmp
                      end
                      
                      code[a_, b_, c_] := If[LessEqual[N[(N[(N[Sqrt[N[(N[(b * b), $MachinePrecision] - N[(c * N[(a * 3.0), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] - b), $MachinePrecision] / N[(a * 3.0), $MachinePrecision]), $MachinePrecision], -0.095], N[(N[(N[Sqrt[N[(b * b + N[(a * N[(c * -3.0), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] - b), $MachinePrecision] / N[(a * 3.0), $MachinePrecision]), $MachinePrecision], N[(N[(-0.5 * N[(c / b), $MachinePrecision]), $MachinePrecision] + N[(-0.375 * N[(N[(a * N[Power[c, 2.0], $MachinePrecision]), $MachinePrecision] / N[Power[b, 3.0], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]]
                      
                      \begin{array}{l}
                      
                      \\
                      \begin{array}{l}
                      \mathbf{if}\;\frac{\sqrt{b \cdot b - c \cdot \left(a \cdot 3\right)} - b}{a \cdot 3} \leq -0.095:\\
                      \;\;\;\;\frac{\sqrt{\mathsf{fma}\left(b, b, a \cdot \left(c \cdot -3\right)\right)} - b}{a \cdot 3}\\
                      
                      \mathbf{else}:\\
                      \;\;\;\;-0.5 \cdot \frac{c}{b} + -0.375 \cdot \frac{a \cdot {c}^{2}}{{b}^{3}}\\
                      
                      
                      \end{array}
                      \end{array}
                      
                      Derivation
                      1. Split input into 2 regimes
                      2. if (/.f64 (+.f64 (neg.f64 b) (sqrt.f64 (-.f64 (*.f64 b b) (*.f64 (*.f64 #s(literal 3 binary64) a) c)))) (*.f64 #s(literal 3 binary64) a)) < -0.095000000000000001

                        1. Initial program 82.1%

                          \[\frac{\left(-b\right) + \sqrt{b \cdot b - \left(3 \cdot a\right) \cdot c}}{3 \cdot a} \]
                        2. Step-by-step derivation
                          1. Simplified82.3%

                            \[\leadsto \color{blue}{\frac{\sqrt{\mathsf{fma}\left(b, b, a \cdot \left(c \cdot -3\right)\right)} - b}{3 \cdot a}} \]
                          2. Add Preprocessing

                          if -0.095000000000000001 < (/.f64 (+.f64 (neg.f64 b) (sqrt.f64 (-.f64 (*.f64 b b) (*.f64 (*.f64 #s(literal 3 binary64) a) c)))) (*.f64 #s(literal 3 binary64) a))

                          1. Initial program 48.8%

                            \[\frac{\left(-b\right) + \sqrt{b \cdot b - \left(3 \cdot a\right) \cdot c}}{3 \cdot a} \]
                          2. Step-by-step derivation
                            1. Simplified48.7%

                              \[\leadsto \color{blue}{\frac{\sqrt{\mathsf{fma}\left(b, b, a \cdot \left(c \cdot -3\right)\right)} - b}{3 \cdot a}} \]
                            2. Add Preprocessing
                            3. Taylor expanded in a around 0 87.6%

                              \[\leadsto \color{blue}{-0.5 \cdot \frac{c}{b} + -0.375 \cdot \frac{a \cdot {c}^{2}}{{b}^{3}}} \]
                          3. Recombined 2 regimes into one program.
                          4. Final simplification86.5%

                            \[\leadsto \begin{array}{l} \mathbf{if}\;\frac{\sqrt{b \cdot b - c \cdot \left(a \cdot 3\right)} - b}{a \cdot 3} \leq -0.095:\\ \;\;\;\;\frac{\sqrt{\mathsf{fma}\left(b, b, a \cdot \left(c \cdot -3\right)\right)} - b}{a \cdot 3}\\ \mathbf{else}:\\ \;\;\;\;-0.5 \cdot \frac{c}{b} + -0.375 \cdot \frac{a \cdot {c}^{2}}{{b}^{3}}\\ \end{array} \]
                          5. Add Preprocessing

                          Alternative 8: 85.0% accurate, 0.3× speedup?

                          \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;\frac{\sqrt{b \cdot b - c \cdot \left(a \cdot 3\right)} - b}{a \cdot 3} \leq -0.095:\\ \;\;\;\;\frac{\sqrt{\mathsf{fma}\left(b, b, a \cdot \left(c \cdot -3\right)\right)} - b}{a \cdot 3}\\ \mathbf{else}:\\ \;\;\;\;\frac{c \cdot \left(-0.375 \cdot \frac{c \cdot a}{{b}^{2}} - 0.5\right)}{b}\\ \end{array} \end{array} \]
                          (FPCore (a b c)
                           :precision binary64
                           (if (<= (/ (- (sqrt (- (* b b) (* c (* a 3.0)))) b) (* a 3.0)) -0.095)
                             (/ (- (sqrt (fma b b (* a (* c -3.0)))) b) (* a 3.0))
                             (/ (* c (- (* -0.375 (/ (* c a) (pow b 2.0))) 0.5)) b)))
                          double code(double a, double b, double c) {
                          	double tmp;
                          	if (((sqrt(((b * b) - (c * (a * 3.0)))) - b) / (a * 3.0)) <= -0.095) {
                          		tmp = (sqrt(fma(b, b, (a * (c * -3.0)))) - b) / (a * 3.0);
                          	} else {
                          		tmp = (c * ((-0.375 * ((c * a) / pow(b, 2.0))) - 0.5)) / b;
                          	}
                          	return tmp;
                          }
                          
                          function code(a, b, c)
                          	tmp = 0.0
                          	if (Float64(Float64(sqrt(Float64(Float64(b * b) - Float64(c * Float64(a * 3.0)))) - b) / Float64(a * 3.0)) <= -0.095)
                          		tmp = Float64(Float64(sqrt(fma(b, b, Float64(a * Float64(c * -3.0)))) - b) / Float64(a * 3.0));
                          	else
                          		tmp = Float64(Float64(c * Float64(Float64(-0.375 * Float64(Float64(c * a) / (b ^ 2.0))) - 0.5)) / b);
                          	end
                          	return tmp
                          end
                          
                          code[a_, b_, c_] := If[LessEqual[N[(N[(N[Sqrt[N[(N[(b * b), $MachinePrecision] - N[(c * N[(a * 3.0), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] - b), $MachinePrecision] / N[(a * 3.0), $MachinePrecision]), $MachinePrecision], -0.095], N[(N[(N[Sqrt[N[(b * b + N[(a * N[(c * -3.0), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] - b), $MachinePrecision] / N[(a * 3.0), $MachinePrecision]), $MachinePrecision], N[(N[(c * N[(N[(-0.375 * N[(N[(c * a), $MachinePrecision] / N[Power[b, 2.0], $MachinePrecision]), $MachinePrecision]), $MachinePrecision] - 0.5), $MachinePrecision]), $MachinePrecision] / b), $MachinePrecision]]
                          
                          \begin{array}{l}
                          
                          \\
                          \begin{array}{l}
                          \mathbf{if}\;\frac{\sqrt{b \cdot b - c \cdot \left(a \cdot 3\right)} - b}{a \cdot 3} \leq -0.095:\\
                          \;\;\;\;\frac{\sqrt{\mathsf{fma}\left(b, b, a \cdot \left(c \cdot -3\right)\right)} - b}{a \cdot 3}\\
                          
                          \mathbf{else}:\\
                          \;\;\;\;\frac{c \cdot \left(-0.375 \cdot \frac{c \cdot a}{{b}^{2}} - 0.5\right)}{b}\\
                          
                          
                          \end{array}
                          \end{array}
                          
                          Derivation
                          1. Split input into 2 regimes
                          2. if (/.f64 (+.f64 (neg.f64 b) (sqrt.f64 (-.f64 (*.f64 b b) (*.f64 (*.f64 #s(literal 3 binary64) a) c)))) (*.f64 #s(literal 3 binary64) a)) < -0.095000000000000001

                            1. Initial program 82.1%

                              \[\frac{\left(-b\right) + \sqrt{b \cdot b - \left(3 \cdot a\right) \cdot c}}{3 \cdot a} \]
                            2. Step-by-step derivation
                              1. Simplified82.3%

                                \[\leadsto \color{blue}{\frac{\sqrt{\mathsf{fma}\left(b, b, a \cdot \left(c \cdot -3\right)\right)} - b}{3 \cdot a}} \]
                              2. Add Preprocessing

                              if -0.095000000000000001 < (/.f64 (+.f64 (neg.f64 b) (sqrt.f64 (-.f64 (*.f64 b b) (*.f64 (*.f64 #s(literal 3 binary64) a) c)))) (*.f64 #s(literal 3 binary64) a))

                              1. Initial program 48.8%

                                \[\frac{\left(-b\right) + \sqrt{b \cdot b - \left(3 \cdot a\right) \cdot c}}{3 \cdot a} \]
                              2. Step-by-step derivation
                                1. Simplified48.7%

                                  \[\leadsto \color{blue}{\frac{\sqrt{\mathsf{fma}\left(b, b, a \cdot \left(c \cdot -3\right)\right)} - b}{3 \cdot a}} \]
                                2. Add Preprocessing
                                3. Taylor expanded in b around inf 95.1%

                                  \[\leadsto \color{blue}{\frac{-0.5625 \cdot \frac{{a}^{2} \cdot {c}^{3}}{{b}^{4}} + \left(-0.5 \cdot c + \left(-0.375 \cdot \frac{a \cdot {c}^{2}}{{b}^{2}} + -0.16666666666666666 \cdot \frac{1.265625 \cdot \left({a}^{4} \cdot {c}^{4}\right) + 5.0625 \cdot \left({a}^{4} \cdot {c}^{4}\right)}{a \cdot {b}^{6}}\right)\right)}{b}} \]
                                4. Taylor expanded in c around 0 87.5%

                                  \[\leadsto \frac{\color{blue}{c \cdot \left(-0.375 \cdot \frac{a \cdot c}{{b}^{2}} - 0.5\right)}}{b} \]
                              3. Recombined 2 regimes into one program.
                              4. Final simplification86.5%

                                \[\leadsto \begin{array}{l} \mathbf{if}\;\frac{\sqrt{b \cdot b - c \cdot \left(a \cdot 3\right)} - b}{a \cdot 3} \leq -0.095:\\ \;\;\;\;\frac{\sqrt{\mathsf{fma}\left(b, b, a \cdot \left(c \cdot -3\right)\right)} - b}{a \cdot 3}\\ \mathbf{else}:\\ \;\;\;\;\frac{c \cdot \left(-0.375 \cdot \frac{c \cdot a}{{b}^{2}} - 0.5\right)}{b}\\ \end{array} \]
                              5. Add Preprocessing

                              Alternative 9: 84.9% accurate, 0.5× speedup?

                              \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;\frac{\sqrt{b \cdot b - c \cdot \left(a \cdot 3\right)} - b}{a \cdot 3} \leq -0.095:\\ \;\;\;\;\frac{\sqrt{b \cdot b - 3 \cdot \left(c \cdot a\right)} - b}{a \cdot 3}\\ \mathbf{else}:\\ \;\;\;\;\frac{c \cdot \left(-0.375 \cdot \frac{c \cdot a}{{b}^{2}} - 0.5\right)}{b}\\ \end{array} \end{array} \]
                              (FPCore (a b c)
                               :precision binary64
                               (if (<= (/ (- (sqrt (- (* b b) (* c (* a 3.0)))) b) (* a 3.0)) -0.095)
                                 (/ (- (sqrt (- (* b b) (* 3.0 (* c a)))) b) (* a 3.0))
                                 (/ (* c (- (* -0.375 (/ (* c a) (pow b 2.0))) 0.5)) b)))
                              double code(double a, double b, double c) {
                              	double tmp;
                              	if (((sqrt(((b * b) - (c * (a * 3.0)))) - b) / (a * 3.0)) <= -0.095) {
                              		tmp = (sqrt(((b * b) - (3.0 * (c * a)))) - b) / (a * 3.0);
                              	} else {
                              		tmp = (c * ((-0.375 * ((c * a) / pow(b, 2.0))) - 0.5)) / b;
                              	}
                              	return tmp;
                              }
                              
                              real(8) function code(a, b, c)
                                  real(8), intent (in) :: a
                                  real(8), intent (in) :: b
                                  real(8), intent (in) :: c
                                  real(8) :: tmp
                                  if (((sqrt(((b * b) - (c * (a * 3.0d0)))) - b) / (a * 3.0d0)) <= (-0.095d0)) then
                                      tmp = (sqrt(((b * b) - (3.0d0 * (c * a)))) - b) / (a * 3.0d0)
                                  else
                                      tmp = (c * (((-0.375d0) * ((c * a) / (b ** 2.0d0))) - 0.5d0)) / b
                                  end if
                                  code = tmp
                              end function
                              
                              public static double code(double a, double b, double c) {
                              	double tmp;
                              	if (((Math.sqrt(((b * b) - (c * (a * 3.0)))) - b) / (a * 3.0)) <= -0.095) {
                              		tmp = (Math.sqrt(((b * b) - (3.0 * (c * a)))) - b) / (a * 3.0);
                              	} else {
                              		tmp = (c * ((-0.375 * ((c * a) / Math.pow(b, 2.0))) - 0.5)) / b;
                              	}
                              	return tmp;
                              }
                              
                              def code(a, b, c):
                              	tmp = 0
                              	if ((math.sqrt(((b * b) - (c * (a * 3.0)))) - b) / (a * 3.0)) <= -0.095:
                              		tmp = (math.sqrt(((b * b) - (3.0 * (c * a)))) - b) / (a * 3.0)
                              	else:
                              		tmp = (c * ((-0.375 * ((c * a) / math.pow(b, 2.0))) - 0.5)) / b
                              	return tmp
                              
                              function code(a, b, c)
                              	tmp = 0.0
                              	if (Float64(Float64(sqrt(Float64(Float64(b * b) - Float64(c * Float64(a * 3.0)))) - b) / Float64(a * 3.0)) <= -0.095)
                              		tmp = Float64(Float64(sqrt(Float64(Float64(b * b) - Float64(3.0 * Float64(c * a)))) - b) / Float64(a * 3.0));
                              	else
                              		tmp = Float64(Float64(c * Float64(Float64(-0.375 * Float64(Float64(c * a) / (b ^ 2.0))) - 0.5)) / b);
                              	end
                              	return tmp
                              end
                              
                              function tmp_2 = code(a, b, c)
                              	tmp = 0.0;
                              	if (((sqrt(((b * b) - (c * (a * 3.0)))) - b) / (a * 3.0)) <= -0.095)
                              		tmp = (sqrt(((b * b) - (3.0 * (c * a)))) - b) / (a * 3.0);
                              	else
                              		tmp = (c * ((-0.375 * ((c * a) / (b ^ 2.0))) - 0.5)) / b;
                              	end
                              	tmp_2 = tmp;
                              end
                              
                              code[a_, b_, c_] := If[LessEqual[N[(N[(N[Sqrt[N[(N[(b * b), $MachinePrecision] - N[(c * N[(a * 3.0), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] - b), $MachinePrecision] / N[(a * 3.0), $MachinePrecision]), $MachinePrecision], -0.095], N[(N[(N[Sqrt[N[(N[(b * b), $MachinePrecision] - N[(3.0 * N[(c * a), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] - b), $MachinePrecision] / N[(a * 3.0), $MachinePrecision]), $MachinePrecision], N[(N[(c * N[(N[(-0.375 * N[(N[(c * a), $MachinePrecision] / N[Power[b, 2.0], $MachinePrecision]), $MachinePrecision]), $MachinePrecision] - 0.5), $MachinePrecision]), $MachinePrecision] / b), $MachinePrecision]]
                              
                              \begin{array}{l}
                              
                              \\
                              \begin{array}{l}
                              \mathbf{if}\;\frac{\sqrt{b \cdot b - c \cdot \left(a \cdot 3\right)} - b}{a \cdot 3} \leq -0.095:\\
                              \;\;\;\;\frac{\sqrt{b \cdot b - 3 \cdot \left(c \cdot a\right)} - b}{a \cdot 3}\\
                              
                              \mathbf{else}:\\
                              \;\;\;\;\frac{c \cdot \left(-0.375 \cdot \frac{c \cdot a}{{b}^{2}} - 0.5\right)}{b}\\
                              
                              
                              \end{array}
                              \end{array}
                              
                              Derivation
                              1. Split input into 2 regimes
                              2. if (/.f64 (+.f64 (neg.f64 b) (sqrt.f64 (-.f64 (*.f64 b b) (*.f64 (*.f64 #s(literal 3 binary64) a) c)))) (*.f64 #s(literal 3 binary64) a)) < -0.095000000000000001

                                1. Initial program 82.1%

                                  \[\frac{\left(-b\right) + \sqrt{b \cdot b - \left(3 \cdot a\right) \cdot c}}{3 \cdot a} \]
                                2. Step-by-step derivation
                                  1. sqr-neg82.1%

                                    \[\leadsto \frac{\left(-b\right) + \sqrt{\color{blue}{\left(-b\right) \cdot \left(-b\right)} - \left(3 \cdot a\right) \cdot c}}{3 \cdot a} \]
                                  2. sqr-neg82.1%

                                    \[\leadsto \frac{\left(-b\right) + \sqrt{\color{blue}{b \cdot b} - \left(3 \cdot a\right) \cdot c}}{3 \cdot a} \]
                                  3. associate-*l*82.1%

                                    \[\leadsto \frac{\left(-b\right) + \sqrt{b \cdot b - \color{blue}{3 \cdot \left(a \cdot c\right)}}}{3 \cdot a} \]
                                3. Simplified82.1%

                                  \[\leadsto \color{blue}{\frac{\left(-b\right) + \sqrt{b \cdot b - 3 \cdot \left(a \cdot c\right)}}{3 \cdot a}} \]
                                4. Add Preprocessing

                                if -0.095000000000000001 < (/.f64 (+.f64 (neg.f64 b) (sqrt.f64 (-.f64 (*.f64 b b) (*.f64 (*.f64 #s(literal 3 binary64) a) c)))) (*.f64 #s(literal 3 binary64) a))

                                1. Initial program 48.8%

                                  \[\frac{\left(-b\right) + \sqrt{b \cdot b - \left(3 \cdot a\right) \cdot c}}{3 \cdot a} \]
                                2. Step-by-step derivation
                                  1. Simplified48.7%

                                    \[\leadsto \color{blue}{\frac{\sqrt{\mathsf{fma}\left(b, b, a \cdot \left(c \cdot -3\right)\right)} - b}{3 \cdot a}} \]
                                  2. Add Preprocessing
                                  3. Taylor expanded in b around inf 95.1%

                                    \[\leadsto \color{blue}{\frac{-0.5625 \cdot \frac{{a}^{2} \cdot {c}^{3}}{{b}^{4}} + \left(-0.5 \cdot c + \left(-0.375 \cdot \frac{a \cdot {c}^{2}}{{b}^{2}} + -0.16666666666666666 \cdot \frac{1.265625 \cdot \left({a}^{4} \cdot {c}^{4}\right) + 5.0625 \cdot \left({a}^{4} \cdot {c}^{4}\right)}{a \cdot {b}^{6}}\right)\right)}{b}} \]
                                  4. Taylor expanded in c around 0 87.5%

                                    \[\leadsto \frac{\color{blue}{c \cdot \left(-0.375 \cdot \frac{a \cdot c}{{b}^{2}} - 0.5\right)}}{b} \]
                                3. Recombined 2 regimes into one program.
                                4. Final simplification86.5%

                                  \[\leadsto \begin{array}{l} \mathbf{if}\;\frac{\sqrt{b \cdot b - c \cdot \left(a \cdot 3\right)} - b}{a \cdot 3} \leq -0.095:\\ \;\;\;\;\frac{\sqrt{b \cdot b - 3 \cdot \left(c \cdot a\right)} - b}{a \cdot 3}\\ \mathbf{else}:\\ \;\;\;\;\frac{c \cdot \left(-0.375 \cdot \frac{c \cdot a}{{b}^{2}} - 0.5\right)}{b}\\ \end{array} \]
                                5. Add Preprocessing

                                Alternative 10: 89.2% accurate, 0.5× speedup?

                                \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;b \leq 0.096:\\ \;\;\;\;\frac{\sqrt{\mathsf{fma}\left(b, b, a \cdot \left(c \cdot -3\right)\right)} - b}{a \cdot 3}\\ \mathbf{else}:\\ \;\;\;\;\frac{c \cdot \left(c \cdot \left(-0.5625 \cdot \frac{c \cdot {a}^{2}}{{b}^{4}} + -0.375 \cdot \frac{a}{b \cdot b}\right) - 0.5\right)}{b}\\ \end{array} \end{array} \]
                                (FPCore (a b c)
                                 :precision binary64
                                 (if (<= b 0.096)
                                   (/ (- (sqrt (fma b b (* a (* c -3.0)))) b) (* a 3.0))
                                   (/
                                    (*
                                     c
                                     (-
                                      (*
                                       c
                                       (+
                                        (* -0.5625 (/ (* c (pow a 2.0)) (pow b 4.0)))
                                        (* -0.375 (/ a (* b b)))))
                                      0.5))
                                    b)))
                                double code(double a, double b, double c) {
                                	double tmp;
                                	if (b <= 0.096) {
                                		tmp = (sqrt(fma(b, b, (a * (c * -3.0)))) - b) / (a * 3.0);
                                	} else {
                                		tmp = (c * ((c * ((-0.5625 * ((c * pow(a, 2.0)) / pow(b, 4.0))) + (-0.375 * (a / (b * b))))) - 0.5)) / b;
                                	}
                                	return tmp;
                                }
                                
                                function code(a, b, c)
                                	tmp = 0.0
                                	if (b <= 0.096)
                                		tmp = Float64(Float64(sqrt(fma(b, b, Float64(a * Float64(c * -3.0)))) - b) / Float64(a * 3.0));
                                	else
                                		tmp = Float64(Float64(c * Float64(Float64(c * Float64(Float64(-0.5625 * Float64(Float64(c * (a ^ 2.0)) / (b ^ 4.0))) + Float64(-0.375 * Float64(a / Float64(b * b))))) - 0.5)) / b);
                                	end
                                	return tmp
                                end
                                
                                code[a_, b_, c_] := If[LessEqual[b, 0.096], N[(N[(N[Sqrt[N[(b * b + N[(a * N[(c * -3.0), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] - b), $MachinePrecision] / N[(a * 3.0), $MachinePrecision]), $MachinePrecision], N[(N[(c * N[(N[(c * N[(N[(-0.5625 * N[(N[(c * N[Power[a, 2.0], $MachinePrecision]), $MachinePrecision] / N[Power[b, 4.0], $MachinePrecision]), $MachinePrecision]), $MachinePrecision] + N[(-0.375 * N[(a / N[(b * b), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] - 0.5), $MachinePrecision]), $MachinePrecision] / b), $MachinePrecision]]
                                
                                \begin{array}{l}
                                
                                \\
                                \begin{array}{l}
                                \mathbf{if}\;b \leq 0.096:\\
                                \;\;\;\;\frac{\sqrt{\mathsf{fma}\left(b, b, a \cdot \left(c \cdot -3\right)\right)} - b}{a \cdot 3}\\
                                
                                \mathbf{else}:\\
                                \;\;\;\;\frac{c \cdot \left(c \cdot \left(-0.5625 \cdot \frac{c \cdot {a}^{2}}{{b}^{4}} + -0.375 \cdot \frac{a}{b \cdot b}\right) - 0.5\right)}{b}\\
                                
                                
                                \end{array}
                                \end{array}
                                
                                Derivation
                                1. Split input into 2 regimes
                                2. if b < 0.096000000000000002

                                  1. Initial program 85.5%

                                    \[\frac{\left(-b\right) + \sqrt{b \cdot b - \left(3 \cdot a\right) \cdot c}}{3 \cdot a} \]
                                  2. Step-by-step derivation
                                    1. Simplified85.9%

                                      \[\leadsto \color{blue}{\frac{\sqrt{\mathsf{fma}\left(b, b, a \cdot \left(c \cdot -3\right)\right)} - b}{3 \cdot a}} \]
                                    2. Add Preprocessing

                                    if 0.096000000000000002 < b

                                    1. Initial program 52.1%

                                      \[\frac{\left(-b\right) + \sqrt{b \cdot b - \left(3 \cdot a\right) \cdot c}}{3 \cdot a} \]
                                    2. Step-by-step derivation
                                      1. Simplified51.9%

                                        \[\leadsto \color{blue}{\frac{\sqrt{\mathsf{fma}\left(b, b, a \cdot \left(c \cdot -3\right)\right)} - b}{3 \cdot a}} \]
                                      2. Add Preprocessing
                                      3. Taylor expanded in b around inf 94.2%

                                        \[\leadsto \color{blue}{\frac{-0.5625 \cdot \frac{{a}^{2} \cdot {c}^{3}}{{b}^{4}} + \left(-0.5 \cdot c + \left(-0.375 \cdot \frac{a \cdot {c}^{2}}{{b}^{2}} + -0.16666666666666666 \cdot \frac{1.265625 \cdot \left({a}^{4} \cdot {c}^{4}\right) + 5.0625 \cdot \left({a}^{4} \cdot {c}^{4}\right)}{a \cdot {b}^{6}}\right)\right)}{b}} \]
                                      4. Taylor expanded in c around 0 91.4%

                                        \[\leadsto \frac{\color{blue}{c \cdot \left(c \cdot \left(-0.5625 \cdot \frac{{a}^{2} \cdot c}{{b}^{4}} + -0.375 \cdot \frac{a}{{b}^{2}}\right) - 0.5\right)}}{b} \]
                                      5. Step-by-step derivation
                                        1. unpow291.4%

                                          \[\leadsto \frac{c \cdot \left(c \cdot \left(-0.5625 \cdot \frac{{a}^{2} \cdot c}{{b}^{4}} + -0.375 \cdot \frac{a}{\color{blue}{b \cdot b}}\right) - 0.5\right)}{b} \]
                                      6. Applied egg-rr91.4%

                                        \[\leadsto \frac{c \cdot \left(c \cdot \left(-0.5625 \cdot \frac{{a}^{2} \cdot c}{{b}^{4}} + -0.375 \cdot \frac{a}{\color{blue}{b \cdot b}}\right) - 0.5\right)}{b} \]
                                    3. Recombined 2 regimes into one program.
                                    4. Final simplification90.8%

                                      \[\leadsto \begin{array}{l} \mathbf{if}\;b \leq 0.096:\\ \;\;\;\;\frac{\sqrt{\mathsf{fma}\left(b, b, a \cdot \left(c \cdot -3\right)\right)} - b}{a \cdot 3}\\ \mathbf{else}:\\ \;\;\;\;\frac{c \cdot \left(c \cdot \left(-0.5625 \cdot \frac{c \cdot {a}^{2}}{{b}^{4}} + -0.375 \cdot \frac{a}{b \cdot b}\right) - 0.5\right)}{b}\\ \end{array} \]
                                    5. Add Preprocessing

                                    Alternative 11: 81.1% accurate, 1.0× speedup?

                                    \[\begin{array}{l} \\ \frac{c \cdot \left(c \cdot \left(-0.375 \cdot \frac{a}{{b}^{2}}\right) - 0.5\right)}{b} \end{array} \]
                                    (FPCore (a b c)
                                     :precision binary64
                                     (/ (* c (- (* c (* -0.375 (/ a (pow b 2.0)))) 0.5)) b))
                                    double code(double a, double b, double c) {
                                    	return (c * ((c * (-0.375 * (a / pow(b, 2.0)))) - 0.5)) / b;
                                    }
                                    
                                    real(8) function code(a, b, c)
                                        real(8), intent (in) :: a
                                        real(8), intent (in) :: b
                                        real(8), intent (in) :: c
                                        code = (c * ((c * ((-0.375d0) * (a / (b ** 2.0d0)))) - 0.5d0)) / b
                                    end function
                                    
                                    public static double code(double a, double b, double c) {
                                    	return (c * ((c * (-0.375 * (a / Math.pow(b, 2.0)))) - 0.5)) / b;
                                    }
                                    
                                    def code(a, b, c):
                                    	return (c * ((c * (-0.375 * (a / math.pow(b, 2.0)))) - 0.5)) / b
                                    
                                    function code(a, b, c)
                                    	return Float64(Float64(c * Float64(Float64(c * Float64(-0.375 * Float64(a / (b ^ 2.0)))) - 0.5)) / b)
                                    end
                                    
                                    function tmp = code(a, b, c)
                                    	tmp = (c * ((c * (-0.375 * (a / (b ^ 2.0)))) - 0.5)) / b;
                                    end
                                    
                                    code[a_, b_, c_] := N[(N[(c * N[(N[(c * N[(-0.375 * N[(a / N[Power[b, 2.0], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] - 0.5), $MachinePrecision]), $MachinePrecision] / b), $MachinePrecision]
                                    
                                    \begin{array}{l}
                                    
                                    \\
                                    \frac{c \cdot \left(c \cdot \left(-0.375 \cdot \frac{a}{{b}^{2}}\right) - 0.5\right)}{b}
                                    \end{array}
                                    
                                    Derivation
                                    1. Initial program 55.3%

                                      \[\frac{\left(-b\right) + \sqrt{b \cdot b - \left(3 \cdot a\right) \cdot c}}{3 \cdot a} \]
                                    2. Step-by-step derivation
                                      1. Simplified55.2%

                                        \[\leadsto \color{blue}{\frac{\sqrt{\mathsf{fma}\left(b, b, a \cdot \left(c \cdot -3\right)\right)} - b}{3 \cdot a}} \]
                                      2. Add Preprocessing
                                      3. Taylor expanded in b around inf 91.9%

                                        \[\leadsto \color{blue}{\frac{-0.5625 \cdot \frac{{a}^{2} \cdot {c}^{3}}{{b}^{4}} + \left(-0.5 \cdot c + \left(-0.375 \cdot \frac{a \cdot {c}^{2}}{{b}^{2}} + -0.16666666666666666 \cdot \frac{1.265625 \cdot \left({a}^{4} \cdot {c}^{4}\right) + 5.0625 \cdot \left({a}^{4} \cdot {c}^{4}\right)}{a \cdot {b}^{6}}\right)\right)}{b}} \]
                                      4. Taylor expanded in c around 0 88.7%

                                        \[\leadsto \frac{\color{blue}{c \cdot \left(c \cdot \left(-0.5625 \cdot \frac{{a}^{2} \cdot c}{{b}^{4}} + -0.375 \cdot \frac{a}{{b}^{2}}\right) - 0.5\right)}}{b} \]
                                      5. Taylor expanded in a around 0 82.2%

                                        \[\leadsto \frac{c \cdot \left(c \cdot \color{blue}{\left(-0.375 \cdot \frac{a}{{b}^{2}}\right)} - 0.5\right)}{b} \]
                                      6. Add Preprocessing

                                      Alternative 12: 81.1% accurate, 1.0× speedup?

                                      \[\begin{array}{l} \\ \frac{c \cdot \left(-0.375 \cdot \frac{c \cdot a}{{b}^{2}} - 0.5\right)}{b} \end{array} \]
                                      (FPCore (a b c)
                                       :precision binary64
                                       (/ (* c (- (* -0.375 (/ (* c a) (pow b 2.0))) 0.5)) b))
                                      double code(double a, double b, double c) {
                                      	return (c * ((-0.375 * ((c * a) / pow(b, 2.0))) - 0.5)) / b;
                                      }
                                      
                                      real(8) function code(a, b, c)
                                          real(8), intent (in) :: a
                                          real(8), intent (in) :: b
                                          real(8), intent (in) :: c
                                          code = (c * (((-0.375d0) * ((c * a) / (b ** 2.0d0))) - 0.5d0)) / b
                                      end function
                                      
                                      public static double code(double a, double b, double c) {
                                      	return (c * ((-0.375 * ((c * a) / Math.pow(b, 2.0))) - 0.5)) / b;
                                      }
                                      
                                      def code(a, b, c):
                                      	return (c * ((-0.375 * ((c * a) / math.pow(b, 2.0))) - 0.5)) / b
                                      
                                      function code(a, b, c)
                                      	return Float64(Float64(c * Float64(Float64(-0.375 * Float64(Float64(c * a) / (b ^ 2.0))) - 0.5)) / b)
                                      end
                                      
                                      function tmp = code(a, b, c)
                                      	tmp = (c * ((-0.375 * ((c * a) / (b ^ 2.0))) - 0.5)) / b;
                                      end
                                      
                                      code[a_, b_, c_] := N[(N[(c * N[(N[(-0.375 * N[(N[(c * a), $MachinePrecision] / N[Power[b, 2.0], $MachinePrecision]), $MachinePrecision]), $MachinePrecision] - 0.5), $MachinePrecision]), $MachinePrecision] / b), $MachinePrecision]
                                      
                                      \begin{array}{l}
                                      
                                      \\
                                      \frac{c \cdot \left(-0.375 \cdot \frac{c \cdot a}{{b}^{2}} - 0.5\right)}{b}
                                      \end{array}
                                      
                                      Derivation
                                      1. Initial program 55.3%

                                        \[\frac{\left(-b\right) + \sqrt{b \cdot b - \left(3 \cdot a\right) \cdot c}}{3 \cdot a} \]
                                      2. Step-by-step derivation
                                        1. Simplified55.2%

                                          \[\leadsto \color{blue}{\frac{\sqrt{\mathsf{fma}\left(b, b, a \cdot \left(c \cdot -3\right)\right)} - b}{3 \cdot a}} \]
                                        2. Add Preprocessing
                                        3. Taylor expanded in b around inf 91.9%

                                          \[\leadsto \color{blue}{\frac{-0.5625 \cdot \frac{{a}^{2} \cdot {c}^{3}}{{b}^{4}} + \left(-0.5 \cdot c + \left(-0.375 \cdot \frac{a \cdot {c}^{2}}{{b}^{2}} + -0.16666666666666666 \cdot \frac{1.265625 \cdot \left({a}^{4} \cdot {c}^{4}\right) + 5.0625 \cdot \left({a}^{4} \cdot {c}^{4}\right)}{a \cdot {b}^{6}}\right)\right)}{b}} \]
                                        4. Taylor expanded in c around 0 82.2%

                                          \[\leadsto \frac{\color{blue}{c \cdot \left(-0.375 \cdot \frac{a \cdot c}{{b}^{2}} - 0.5\right)}}{b} \]
                                        5. Final simplification82.2%

                                          \[\leadsto \frac{c \cdot \left(-0.375 \cdot \frac{c \cdot a}{{b}^{2}} - 0.5\right)}{b} \]
                                        6. Add Preprocessing

                                        Alternative 13: 81.1% accurate, 1.0× speedup?

                                        \[\begin{array}{l} \\ c \cdot \left(\frac{c \cdot \left(a \cdot -0.375\right)}{{b}^{3}} + \frac{-0.5}{b}\right) \end{array} \]
                                        (FPCore (a b c)
                                         :precision binary64
                                         (* c (+ (/ (* c (* a -0.375)) (pow b 3.0)) (/ -0.5 b))))
                                        double code(double a, double b, double c) {
                                        	return c * (((c * (a * -0.375)) / pow(b, 3.0)) + (-0.5 / b));
                                        }
                                        
                                        real(8) function code(a, b, c)
                                            real(8), intent (in) :: a
                                            real(8), intent (in) :: b
                                            real(8), intent (in) :: c
                                            code = c * (((c * (a * (-0.375d0))) / (b ** 3.0d0)) + ((-0.5d0) / b))
                                        end function
                                        
                                        public static double code(double a, double b, double c) {
                                        	return c * (((c * (a * -0.375)) / Math.pow(b, 3.0)) + (-0.5 / b));
                                        }
                                        
                                        def code(a, b, c):
                                        	return c * (((c * (a * -0.375)) / math.pow(b, 3.0)) + (-0.5 / b))
                                        
                                        function code(a, b, c)
                                        	return Float64(c * Float64(Float64(Float64(c * Float64(a * -0.375)) / (b ^ 3.0)) + Float64(-0.5 / b)))
                                        end
                                        
                                        function tmp = code(a, b, c)
                                        	tmp = c * (((c * (a * -0.375)) / (b ^ 3.0)) + (-0.5 / b));
                                        end
                                        
                                        code[a_, b_, c_] := N[(c * N[(N[(N[(c * N[(a * -0.375), $MachinePrecision]), $MachinePrecision] / N[Power[b, 3.0], $MachinePrecision]), $MachinePrecision] + N[(-0.5 / b), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
                                        
                                        \begin{array}{l}
                                        
                                        \\
                                        c \cdot \left(\frac{c \cdot \left(a \cdot -0.375\right)}{{b}^{3}} + \frac{-0.5}{b}\right)
                                        \end{array}
                                        
                                        Derivation
                                        1. Initial program 55.3%

                                          \[\frac{\left(-b\right) + \sqrt{b \cdot b - \left(3 \cdot a\right) \cdot c}}{3 \cdot a} \]
                                        2. Step-by-step derivation
                                          1. Simplified55.2%

                                            \[\leadsto \color{blue}{\frac{\sqrt{\mathsf{fma}\left(b, b, a \cdot \left(c \cdot -3\right)\right)} - b}{3 \cdot a}} \]
                                          2. Add Preprocessing
                                          3. Taylor expanded in b around inf 91.9%

                                            \[\leadsto \color{blue}{\frac{-0.5625 \cdot \frac{{a}^{2} \cdot {c}^{3}}{{b}^{4}} + \left(-0.5 \cdot c + \left(-0.375 \cdot \frac{a \cdot {c}^{2}}{{b}^{2}} + -0.16666666666666666 \cdot \frac{1.265625 \cdot \left({a}^{4} \cdot {c}^{4}\right) + 5.0625 \cdot \left({a}^{4} \cdot {c}^{4}\right)}{a \cdot {b}^{6}}\right)\right)}{b}} \]
                                          4. Step-by-step derivation
                                            1. associate-*r/91.9%

                                              \[\leadsto \frac{-0.5625 \cdot \frac{{a}^{2} \cdot {c}^{3}}{{b}^{4}} + \left(-0.5 \cdot c + \left(-0.375 \cdot \frac{a \cdot {c}^{2}}{{b}^{2}} + \color{blue}{\frac{-0.16666666666666666 \cdot \left(1.265625 \cdot \left({a}^{4} \cdot {c}^{4}\right) + 5.0625 \cdot \left({a}^{4} \cdot {c}^{4}\right)\right)}{a \cdot {b}^{6}}}\right)\right)}{b} \]
                                            2. distribute-rgt-out91.9%

                                              \[\leadsto \frac{-0.5625 \cdot \frac{{a}^{2} \cdot {c}^{3}}{{b}^{4}} + \left(-0.5 \cdot c + \left(-0.375 \cdot \frac{a \cdot {c}^{2}}{{b}^{2}} + \frac{-0.16666666666666666 \cdot \color{blue}{\left(\left({a}^{4} \cdot {c}^{4}\right) \cdot \left(1.265625 + 5.0625\right)\right)}}{a \cdot {b}^{6}}\right)\right)}{b} \]
                                            3. pow-prod-down91.9%

                                              \[\leadsto \frac{-0.5625 \cdot \frac{{a}^{2} \cdot {c}^{3}}{{b}^{4}} + \left(-0.5 \cdot c + \left(-0.375 \cdot \frac{a \cdot {c}^{2}}{{b}^{2}} + \frac{-0.16666666666666666 \cdot \left(\color{blue}{{\left(a \cdot c\right)}^{4}} \cdot \left(1.265625 + 5.0625\right)\right)}{a \cdot {b}^{6}}\right)\right)}{b} \]
                                            4. metadata-eval91.9%

                                              \[\leadsto \frac{-0.5625 \cdot \frac{{a}^{2} \cdot {c}^{3}}{{b}^{4}} + \left(-0.5 \cdot c + \left(-0.375 \cdot \frac{a \cdot {c}^{2}}{{b}^{2}} + \frac{-0.16666666666666666 \cdot \left({\left(a \cdot c\right)}^{4} \cdot \color{blue}{6.328125}\right)}{a \cdot {b}^{6}}\right)\right)}{b} \]
                                          5. Applied egg-rr91.9%

                                            \[\leadsto \frac{-0.5625 \cdot \frac{{a}^{2} \cdot {c}^{3}}{{b}^{4}} + \left(-0.5 \cdot c + \left(-0.375 \cdot \frac{a \cdot {c}^{2}}{{b}^{2}} + \color{blue}{\frac{-0.16666666666666666 \cdot \left({\left(a \cdot c\right)}^{4} \cdot 6.328125\right)}{a \cdot {b}^{6}}}\right)\right)}{b} \]
                                          6. Taylor expanded in c around 0 82.1%

                                            \[\leadsto \color{blue}{c \cdot \left(-0.375 \cdot \frac{a \cdot c}{{b}^{3}} - 0.5 \cdot \frac{1}{b}\right)} \]
                                          7. Step-by-step derivation
                                            1. cancel-sign-sub-inv82.1%

                                              \[\leadsto c \cdot \color{blue}{\left(-0.375 \cdot \frac{a \cdot c}{{b}^{3}} + \left(-0.5\right) \cdot \frac{1}{b}\right)} \]
                                            2. metadata-eval82.1%

                                              \[\leadsto c \cdot \left(-0.375 \cdot \frac{a \cdot c}{{b}^{3}} + \color{blue}{-0.5} \cdot \frac{1}{b}\right) \]
                                            3. associate-*r/82.1%

                                              \[\leadsto c \cdot \left(-0.375 \cdot \frac{a \cdot c}{{b}^{3}} + \color{blue}{\frac{-0.5 \cdot 1}{b}}\right) \]
                                            4. metadata-eval82.1%

                                              \[\leadsto c \cdot \left(-0.375 \cdot \frac{a \cdot c}{{b}^{3}} + \frac{\color{blue}{-0.5}}{b}\right) \]
                                            5. associate-*r/82.1%

                                              \[\leadsto c \cdot \left(\color{blue}{\frac{-0.375 \cdot \left(a \cdot c\right)}{{b}^{3}}} + \frac{-0.5}{b}\right) \]
                                            6. associate-*r*82.1%

                                              \[\leadsto c \cdot \left(\frac{\color{blue}{\left(-0.375 \cdot a\right) \cdot c}}{{b}^{3}} + \frac{-0.5}{b}\right) \]
                                          8. Simplified82.1%

                                            \[\leadsto \color{blue}{c \cdot \left(\frac{\left(-0.375 \cdot a\right) \cdot c}{{b}^{3}} + \frac{-0.5}{b}\right)} \]
                                          9. Final simplification82.1%

                                            \[\leadsto c \cdot \left(\frac{c \cdot \left(a \cdot -0.375\right)}{{b}^{3}} + \frac{-0.5}{b}\right) \]
                                          10. Add Preprocessing

                                          Alternative 14: 64.2% accurate, 23.2× speedup?

                                          \[\begin{array}{l} \\ \frac{c \cdot -0.5}{b} \end{array} \]
                                          (FPCore (a b c) :precision binary64 (/ (* c -0.5) b))
                                          double code(double a, double b, double c) {
                                          	return (c * -0.5) / b;
                                          }
                                          
                                          real(8) function code(a, b, c)
                                              real(8), intent (in) :: a
                                              real(8), intent (in) :: b
                                              real(8), intent (in) :: c
                                              code = (c * (-0.5d0)) / b
                                          end function
                                          
                                          public static double code(double a, double b, double c) {
                                          	return (c * -0.5) / b;
                                          }
                                          
                                          def code(a, b, c):
                                          	return (c * -0.5) / b
                                          
                                          function code(a, b, c)
                                          	return Float64(Float64(c * -0.5) / b)
                                          end
                                          
                                          function tmp = code(a, b, c)
                                          	tmp = (c * -0.5) / b;
                                          end
                                          
                                          code[a_, b_, c_] := N[(N[(c * -0.5), $MachinePrecision] / b), $MachinePrecision]
                                          
                                          \begin{array}{l}
                                          
                                          \\
                                          \frac{c \cdot -0.5}{b}
                                          \end{array}
                                          
                                          Derivation
                                          1. Initial program 55.3%

                                            \[\frac{\left(-b\right) + \sqrt{b \cdot b - \left(3 \cdot a\right) \cdot c}}{3 \cdot a} \]
                                          2. Step-by-step derivation
                                            1. Simplified55.2%

                                              \[\leadsto \color{blue}{\frac{\sqrt{\mathsf{fma}\left(b, b, a \cdot \left(c \cdot -3\right)\right)} - b}{3 \cdot a}} \]
                                            2. Add Preprocessing
                                            3. Taylor expanded in b around inf 64.7%

                                              \[\leadsto \color{blue}{-0.5 \cdot \frac{c}{b}} \]
                                            4. Step-by-step derivation
                                              1. associate-*r/64.7%

                                                \[\leadsto \color{blue}{\frac{-0.5 \cdot c}{b}} \]
                                              2. *-commutative64.7%

                                                \[\leadsto \frac{\color{blue}{c \cdot -0.5}}{b} \]
                                            5. Simplified64.7%

                                              \[\leadsto \color{blue}{\frac{c \cdot -0.5}{b}} \]
                                            6. Add Preprocessing

                                            Alternative 15: 64.2% accurate, 23.2× speedup?

                                            \[\begin{array}{l} \\ c \cdot \frac{-0.5}{b} \end{array} \]
                                            (FPCore (a b c) :precision binary64 (* c (/ -0.5 b)))
                                            double code(double a, double b, double c) {
                                            	return c * (-0.5 / b);
                                            }
                                            
                                            real(8) function code(a, b, c)
                                                real(8), intent (in) :: a
                                                real(8), intent (in) :: b
                                                real(8), intent (in) :: c
                                                code = c * ((-0.5d0) / b)
                                            end function
                                            
                                            public static double code(double a, double b, double c) {
                                            	return c * (-0.5 / b);
                                            }
                                            
                                            def code(a, b, c):
                                            	return c * (-0.5 / b)
                                            
                                            function code(a, b, c)
                                            	return Float64(c * Float64(-0.5 / b))
                                            end
                                            
                                            function tmp = code(a, b, c)
                                            	tmp = c * (-0.5 / b);
                                            end
                                            
                                            code[a_, b_, c_] := N[(c * N[(-0.5 / b), $MachinePrecision]), $MachinePrecision]
                                            
                                            \begin{array}{l}
                                            
                                            \\
                                            c \cdot \frac{-0.5}{b}
                                            \end{array}
                                            
                                            Derivation
                                            1. Initial program 55.3%

                                              \[\frac{\left(-b\right) + \sqrt{b \cdot b - \left(3 \cdot a\right) \cdot c}}{3 \cdot a} \]
                                            2. Step-by-step derivation
                                              1. Simplified55.2%

                                                \[\leadsto \color{blue}{\frac{\sqrt{\mathsf{fma}\left(b, b, a \cdot \left(c \cdot -3\right)\right)} - b}{3 \cdot a}} \]
                                              2. Add Preprocessing
                                              3. Taylor expanded in b around inf 91.9%

                                                \[\leadsto \color{blue}{\frac{-0.5625 \cdot \frac{{a}^{2} \cdot {c}^{3}}{{b}^{4}} + \left(-0.5 \cdot c + \left(-0.375 \cdot \frac{a \cdot {c}^{2}}{{b}^{2}} + -0.16666666666666666 \cdot \frac{1.265625 \cdot \left({a}^{4} \cdot {c}^{4}\right) + 5.0625 \cdot \left({a}^{4} \cdot {c}^{4}\right)}{a \cdot {b}^{6}}\right)\right)}{b}} \]
                                              4. Taylor expanded in a around 0 64.7%

                                                \[\leadsto \color{blue}{-0.5 \cdot \frac{c}{b}} \]
                                              5. Step-by-step derivation
                                                1. associate-*r/64.7%

                                                  \[\leadsto \color{blue}{\frac{-0.5 \cdot c}{b}} \]
                                                2. *-commutative64.7%

                                                  \[\leadsto \frac{\color{blue}{c \cdot -0.5}}{b} \]
                                                3. associate-*r/64.6%

                                                  \[\leadsto \color{blue}{c \cdot \frac{-0.5}{b}} \]
                                              6. Simplified64.6%

                                                \[\leadsto \color{blue}{c \cdot \frac{-0.5}{b}} \]
                                              7. Add Preprocessing

                                              Reproduce

                                              ?
                                              herbie shell --seed 2024170 
                                              (FPCore (a b c)
                                                :name "Cubic critical, narrow range"
                                                :precision binary64
                                                :pre (and (and (and (< 1.0536712127723509e-8 a) (< a 94906265.62425156)) (and (< 1.0536712127723509e-8 b) (< b 94906265.62425156))) (and (< 1.0536712127723509e-8 c) (< c 94906265.62425156)))
                                                (/ (+ (- b) (sqrt (- (* b b) (* (* 3.0 a) c)))) (* 3.0 a)))