Diagrams.Solve.Polynomial:quadForm from diagrams-solve-0.1, A

Percentage Accurate: 100.0% → 100.0%
Time: 4.7s
Alternatives: 3
Speedup: 1.0×

Specification

?
\[\begin{array}{l} \\ x - \left(y \cdot 4\right) \cdot z \end{array} \]
(FPCore (x y z) :precision binary64 (- x (* (* y 4.0) z)))
double code(double x, double y, double z) {
	return x - ((y * 4.0) * z);
}

real(8) function code(x, y, z)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    real(8), intent (in) :: z
    code = x - ((y * 4.0d0) * z)
end function

public static double code(double x, double y, double z) {
	return x - ((y * 4.0) * z);
}

def code(x, y, z):
	return x - ((y * 4.0) * z)

function code(x, y, z)
	return Float64(x - Float64(Float64(y * 4.0) * z))
end

function tmp = code(x, y, z)
	tmp = x - ((y * 4.0) * z);
end

code[x_, y_, z_] := N[(x - N[(N[(y * 4.0), $MachinePrecision] * z), $MachinePrecision]), $MachinePrecision]

\begin{array}{l}

\\
x - \left(y \cdot 4\right) \cdot z
\end{array}

Sampling outcomes in binary64 precision:

Local Percentage Accuracy vs ?

The average percentage accuracy by input value. Horizontal axis shows value of an input variable; the variable is choosen in the title. Vertical axis is accuracy; higher is better. Red represent the original program, while blue represents Herbie's suggestion. These can be toggled with buttons below the plot. The line is an average while dots represent individual samples.

Accuracy vs Speed?

Herbie found 3 alternatives:

AlternativeAccuracySpeedup
The accuracy (vertical axis) and speed (horizontal axis) of each alternatives. Up and to the right is better. The red square shows the initial program, and each blue circle shows an alternative.The line shows the best available speed-accuracy tradeoffs.

Initial Program: 100.0% accurate, 1.0× speedup?

\[\begin{array}{l} \\ x - \left(y \cdot 4\right) \cdot z \end{array} \]
(FPCore (x y z) :precision binary64 (- x (* (* y 4.0) z)))
double code(double x, double y, double z) {
	return x - ((y * 4.0) * z);
}

real(8) function code(x, y, z)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    real(8), intent (in) :: z
    code = x - ((y * 4.0d0) * z)
end function

public static double code(double x, double y, double z) {
	return x - ((y * 4.0) * z);
}

def code(x, y, z):
	return x - ((y * 4.0) * z)

function code(x, y, z)
	return Float64(x - Float64(Float64(y * 4.0) * z))
end

function tmp = code(x, y, z)
	tmp = x - ((y * 4.0) * z);
end

code[x_, y_, z_] := N[(x - N[(N[(y * 4.0), $MachinePrecision] * z), $MachinePrecision]), $MachinePrecision]

\begin{array}{l}

\\
x - \left(y \cdot 4\right) \cdot z
\end{array}

Alternative 1: 100.0% accurate, 1.0× speedup?

\[\begin{array}{l} \\ x - \left(y \cdot 4\right) \cdot z \end{array} \]
(FPCore (x y z) :precision binary64 (- x (* (* y 4.0) z)))
double code(double x, double y, double z) {
	return x - ((y * 4.0) * z);
}

real(8) function code(x, y, z)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    real(8), intent (in) :: z
    code = x - ((y * 4.0d0) * z)
end function

public static double code(double x, double y, double z) {
	return x - ((y * 4.0) * z);
}

def code(x, y, z):
	return x - ((y * 4.0) * z)

function code(x, y, z)
	return Float64(x - Float64(Float64(y * 4.0) * z))
end

function tmp = code(x, y, z)
	tmp = x - ((y * 4.0) * z);
end

code[x_, y_, z_] := N[(x - N[(N[(y * 4.0), $MachinePrecision] * z), $MachinePrecision]), $MachinePrecision]

\begin{array}{l}

\\
x - \left(y \cdot 4\right) \cdot z
\end{array}
Derivation

  1. Initial program 100.0%

    \[x - \left(y \cdot 4\right) \cdot z \]
  2. Add Preprocessing
  3. Add Preprocessing

Alternative 2: 70.6% accurate, 0.5× speedup?

\[\begin{array}{l} \\ \begin{array}{l} t_0 := -4 \cdot \left(y \cdot z\right)\\ \mathbf{if}\;y \leq -4.5 \cdot 10^{+94}:\\ \;\;\;\;t\_0\\ \mathbf{elif}\;y \leq 1.32 \cdot 10^{-88}:\\ \;\;\;\;x\\ \mathbf{else}:\\ \;\;\;\;t\_0\\ \end{array} \end{array} \]
(FPCore (x y z)
 :precision binary64
 (let* ((t_0 (* -4.0 (* y z))))
   (if (<= y -4.5e+94) t_0 (if (<= y 1.32e-88) x t_0))))
double code(double x, double y, double z) {
	double t_0 = -4.0 * (y * z);
	double tmp;
	if (y <= -4.5e+94) {
		tmp = t_0;
	} else if (y <= 1.32e-88) {
		tmp = x;
	} else {
		tmp = t_0;
	}
	return tmp;
}

real(8) function code(x, y, z)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    real(8), intent (in) :: z
    real(8) :: t_0
    real(8) :: tmp
    t_0 = (-4.0d0) * (y * z)
    if (y <= (-4.5d+94)) then
        tmp = t_0
    else if (y <= 1.32d-88) then
        tmp = x
    else
        tmp = t_0
    end if
    code = tmp
end function

public static double code(double x, double y, double z) {
	double t_0 = -4.0 * (y * z);
	double tmp;
	if (y <= -4.5e+94) {
		tmp = t_0;
	} else if (y <= 1.32e-88) {
		tmp = x;
	} else {
		tmp = t_0;
	}
	return tmp;
}

def code(x, y, z):
	t_0 = -4.0 * (y * z)
	tmp = 0
	if y <= -4.5e+94:
		tmp = t_0
	elif y <= 1.32e-88:
		tmp = x
	else:
		tmp = t_0
	return tmp

function code(x, y, z)
	t_0 = Float64(-4.0 * Float64(y * z))
	tmp = 0.0
	if (y <= -4.5e+94)
		tmp = t_0;
	elseif (y <= 1.32e-88)
		tmp = x;
	else
		tmp = t_0;
	end
	return tmp
end

function tmp_2 = code(x, y, z)
	t_0 = -4.0 * (y * z);
	tmp = 0.0;
	if (y <= -4.5e+94)
		tmp = t_0;
	elseif (y <= 1.32e-88)
		tmp = x;
	else
		tmp = t_0;
	end
	tmp_2 = tmp;
end

code[x_, y_, z_] := Block[{t$95$0 = N[(-4.0 * N[(y * z), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[y, -4.5e+94], t$95$0, If[LessEqual[y, 1.32e-88], x, t$95$0]]]

\begin{array}{l}

\\
\begin{array}{l}
t_0 := -4 \cdot \left(y \cdot z\right)\\
\mathbf{if}\;y \leq -4.5 \cdot 10^{+94}:\\
\;\;\;\;t\_0\\

\mathbf{elif}\;y \leq 1.32 \cdot 10^{-88}:\\
\;\;\;\;x\\

\mathbf{else}:\\
\;\;\;\;t\_0\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes

  2. if y < -4.49999999999999972e94 or 1.3199999999999999e-88 < y

    1. Initial program 100.0%

      \[x - \left(y \cdot 4\right) \cdot z \]
    2. Add Preprocessing

    3. Taylor expanded in x around 0

      \[\leadsto \color{blue}{-4 \cdot \left(y \cdot z\right)} \]
    4. Step-by-step derivation

      1. *-lowering-*.f64N/A

        \[\leadsto \mathsf{*.f64}\left(-4, \color{blue}{\left(y \cdot z\right)}\right) \]

      2. *-lowering-*.f6478.0%

        \[\leadsto \mathsf{*.f64}\left(-4, \mathsf{*.f64}\left(y, \color{blue}{z}\right)\right) \]

    5. Simplified78.0%

      \[\leadsto \color{blue}{-4 \cdot \left(y \cdot z\right)} \]

    if -4.49999999999999972e94 < y < 1.3199999999999999e-88

    1. Initial program 100.0%

      \[x - \left(y \cdot 4\right) \cdot z \]
    2. Add Preprocessing

    3. Taylor expanded in x around inf

      \[\leadsto \color{blue}{x} \]
    4. Step-by-step derivation

      1. Simplified73.1%

        \[\leadsto \color{blue}{x} \]
    5. Recombined 2 regimes into one program.
    6. Add Preprocessing

    Alternative 3: 51.9% accurate, 7.0× speedup?

    \[\begin{array}{l} \\ x \end{array} \]
    (FPCore (x y z) :precision binary64 x)
    double code(double x, double y, double z) {
	return x;
}

    real(8) function code(x, y, z)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    real(8), intent (in) :: z
    code = x
end function

    public static double code(double x, double y, double z) {
	return x;
}

    def code(x, y, z):
	return x

    function code(x, y, z)
	return x
end

    function tmp = code(x, y, z)
	tmp = x;
end

    code[x_, y_, z_] := x

    \begin{array}{l}

\\
x
\end{array}
    Derivation

    1. Initial program 100.0%

      \[x - \left(y \cdot 4\right) \cdot z \]
    2. Add Preprocessing

    3. Taylor expanded in x around inf

      \[\leadsto \color{blue}{x} \]
    4. Step-by-step derivation

      1. Simplified48.6%

        \[\leadsto \color{blue}{x} \]
      2. Add Preprocessing

      Reproduce

      ?
      herbie shell --seed 2024163 
(FPCore (x y z)
  :name "Diagrams.Solve.Polynomial:quadForm from diagrams-solve-0.1, A"
  :precision binary64
  (- x (* (* y 4.0) z)))