math.exp on complex, imaginary part

Percentage Accurate: 100.0% → 100.0%
Time: 7.1s
Alternatives: 12
Speedup: 1.0×

Specification

?
\[\begin{array}{l} \\ e^{re} \cdot \sin im \end{array} \]
(FPCore (re im) :precision binary64 (* (exp re) (sin im)))
double code(double re, double im) {
	return exp(re) * sin(im);
}
real(8) function code(re, im)
    real(8), intent (in) :: re
    real(8), intent (in) :: im
    code = exp(re) * sin(im)
end function
public static double code(double re, double im) {
	return Math.exp(re) * Math.sin(im);
}
def code(re, im):
	return math.exp(re) * math.sin(im)
function code(re, im)
	return Float64(exp(re) * sin(im))
end
function tmp = code(re, im)
	tmp = exp(re) * sin(im);
end
code[re_, im_] := N[(N[Exp[re], $MachinePrecision] * N[Sin[im], $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
e^{re} \cdot \sin im
\end{array}

Sampling outcomes in binary64 precision:

Local Percentage Accuracy vs ?

The average percentage accuracy by input value. Horizontal axis shows value of an input variable; the variable is choosen in the title. Vertical axis is accuracy; higher is better. Red represent the original program, while blue represents Herbie's suggestion. These can be toggled with buttons below the plot. The line is an average while dots represent individual samples.

Accuracy vs Speed?

Herbie found 12 alternatives:

AlternativeAccuracySpeedup
The accuracy (vertical axis) and speed (horizontal axis) of each alternatives. Up and to the right is better. The red square shows the initial program, and each blue circle shows an alternative.The line shows the best available speed-accuracy tradeoffs.

Initial Program: 100.0% accurate, 1.0× speedup?

\[\begin{array}{l} \\ e^{re} \cdot \sin im \end{array} \]
(FPCore (re im) :precision binary64 (* (exp re) (sin im)))
double code(double re, double im) {
	return exp(re) * sin(im);
}
real(8) function code(re, im)
    real(8), intent (in) :: re
    real(8), intent (in) :: im
    code = exp(re) * sin(im)
end function
public static double code(double re, double im) {
	return Math.exp(re) * Math.sin(im);
}
def code(re, im):
	return math.exp(re) * math.sin(im)
function code(re, im)
	return Float64(exp(re) * sin(im))
end
function tmp = code(re, im)
	tmp = exp(re) * sin(im);
end
code[re_, im_] := N[(N[Exp[re], $MachinePrecision] * N[Sin[im], $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
e^{re} \cdot \sin im
\end{array}

Alternative 1: 100.0% accurate, 1.0× speedup?

\[\begin{array}{l} \\ e^{re} \cdot \sin im \end{array} \]
(FPCore (re im) :precision binary64 (* (exp re) (sin im)))
double code(double re, double im) {
	return exp(re) * sin(im);
}
real(8) function code(re, im)
    real(8), intent (in) :: re
    real(8), intent (in) :: im
    code = exp(re) * sin(im)
end function
public static double code(double re, double im) {
	return Math.exp(re) * Math.sin(im);
}
def code(re, im):
	return math.exp(re) * math.sin(im)
function code(re, im)
	return Float64(exp(re) * sin(im))
end
function tmp = code(re, im)
	tmp = exp(re) * sin(im);
end
code[re_, im_] := N[(N[Exp[re], $MachinePrecision] * N[Sin[im], $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
e^{re} \cdot \sin im
\end{array}
Derivation
  1. Initial program 100.0%

    \[e^{re} \cdot \sin im \]
  2. Add Preprocessing
  3. Add Preprocessing

Alternative 2: 69.6% accurate, 0.6× speedup?

\[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;e^{re} \leq 1 \lor \neg \left(e^{re} \leq 500000000000\right):\\ \;\;\;\;e^{re} \cdot im\\ \mathbf{else}:\\ \;\;\;\;\sin im\\ \end{array} \end{array} \]
(FPCore (re im)
 :precision binary64
 (if (or (<= (exp re) 1.0) (not (<= (exp re) 500000000000.0)))
   (* (exp re) im)
   (sin im)))
double code(double re, double im) {
	double tmp;
	if ((exp(re) <= 1.0) || !(exp(re) <= 500000000000.0)) {
		tmp = exp(re) * im;
	} else {
		tmp = sin(im);
	}
	return tmp;
}
real(8) function code(re, im)
    real(8), intent (in) :: re
    real(8), intent (in) :: im
    real(8) :: tmp
    if ((exp(re) <= 1.0d0) .or. (.not. (exp(re) <= 500000000000.0d0))) then
        tmp = exp(re) * im
    else
        tmp = sin(im)
    end if
    code = tmp
end function
public static double code(double re, double im) {
	double tmp;
	if ((Math.exp(re) <= 1.0) || !(Math.exp(re) <= 500000000000.0)) {
		tmp = Math.exp(re) * im;
	} else {
		tmp = Math.sin(im);
	}
	return tmp;
}
def code(re, im):
	tmp = 0
	if (math.exp(re) <= 1.0) or not (math.exp(re) <= 500000000000.0):
		tmp = math.exp(re) * im
	else:
		tmp = math.sin(im)
	return tmp
function code(re, im)
	tmp = 0.0
	if ((exp(re) <= 1.0) || !(exp(re) <= 500000000000.0))
		tmp = Float64(exp(re) * im);
	else
		tmp = sin(im);
	end
	return tmp
end
function tmp_2 = code(re, im)
	tmp = 0.0;
	if ((exp(re) <= 1.0) || ~((exp(re) <= 500000000000.0)))
		tmp = exp(re) * im;
	else
		tmp = sin(im);
	end
	tmp_2 = tmp;
end
code[re_, im_] := If[Or[LessEqual[N[Exp[re], $MachinePrecision], 1.0], N[Not[LessEqual[N[Exp[re], $MachinePrecision], 500000000000.0]], $MachinePrecision]], N[(N[Exp[re], $MachinePrecision] * im), $MachinePrecision], N[Sin[im], $MachinePrecision]]
\begin{array}{l}

\\
\begin{array}{l}
\mathbf{if}\;e^{re} \leq 1 \lor \neg \left(e^{re} \leq 500000000000\right):\\
\;\;\;\;e^{re} \cdot im\\

\mathbf{else}:\\
\;\;\;\;\sin im\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if (exp.f64 re) < 1 or 5e11 < (exp.f64 re)

    1. Initial program 100.0%

      \[e^{re} \cdot \sin im \]
    2. Add Preprocessing
    3. Taylor expanded in im around 0 75.9%

      \[\leadsto e^{re} \cdot \color{blue}{im} \]

    if 1 < (exp.f64 re) < 5e11

    1. Initial program 99.4%

      \[e^{re} \cdot \sin im \]
    2. Add Preprocessing
    3. Taylor expanded in re around 0 47.1%

      \[\leadsto \color{blue}{\sin im} \]
  3. Recombined 2 regimes into one program.
  4. Final simplification75.3%

    \[\leadsto \begin{array}{l} \mathbf{if}\;e^{re} \leq 1 \lor \neg \left(e^{re} \leq 500000000000\right):\\ \;\;\;\;e^{re} \cdot im\\ \mathbf{else}:\\ \;\;\;\;\sin im\\ \end{array} \]
  5. Add Preprocessing

Alternative 3: 96.0% accurate, 1.6× speedup?

\[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;re \leq -3.2 \cdot 10^{-5} \lor \neg \left(re \leq 26.5\right) \land re \leq 1.9 \cdot 10^{+154}:\\ \;\;\;\;e^{re} \cdot im\\ \mathbf{else}:\\ \;\;\;\;\sin im \cdot \left(1 + re \cdot \left(1 + re \cdot 0.5\right)\right)\\ \end{array} \end{array} \]
(FPCore (re im)
 :precision binary64
 (if (or (<= re -3.2e-5) (and (not (<= re 26.5)) (<= re 1.9e+154)))
   (* (exp re) im)
   (* (sin im) (+ 1.0 (* re (+ 1.0 (* re 0.5)))))))
double code(double re, double im) {
	double tmp;
	if ((re <= -3.2e-5) || (!(re <= 26.5) && (re <= 1.9e+154))) {
		tmp = exp(re) * im;
	} else {
		tmp = sin(im) * (1.0 + (re * (1.0 + (re * 0.5))));
	}
	return tmp;
}
real(8) function code(re, im)
    real(8), intent (in) :: re
    real(8), intent (in) :: im
    real(8) :: tmp
    if ((re <= (-3.2d-5)) .or. (.not. (re <= 26.5d0)) .and. (re <= 1.9d+154)) then
        tmp = exp(re) * im
    else
        tmp = sin(im) * (1.0d0 + (re * (1.0d0 + (re * 0.5d0))))
    end if
    code = tmp
end function
public static double code(double re, double im) {
	double tmp;
	if ((re <= -3.2e-5) || (!(re <= 26.5) && (re <= 1.9e+154))) {
		tmp = Math.exp(re) * im;
	} else {
		tmp = Math.sin(im) * (1.0 + (re * (1.0 + (re * 0.5))));
	}
	return tmp;
}
def code(re, im):
	tmp = 0
	if (re <= -3.2e-5) or (not (re <= 26.5) and (re <= 1.9e+154)):
		tmp = math.exp(re) * im
	else:
		tmp = math.sin(im) * (1.0 + (re * (1.0 + (re * 0.5))))
	return tmp
function code(re, im)
	tmp = 0.0
	if ((re <= -3.2e-5) || (!(re <= 26.5) && (re <= 1.9e+154)))
		tmp = Float64(exp(re) * im);
	else
		tmp = Float64(sin(im) * Float64(1.0 + Float64(re * Float64(1.0 + Float64(re * 0.5)))));
	end
	return tmp
end
function tmp_2 = code(re, im)
	tmp = 0.0;
	if ((re <= -3.2e-5) || (~((re <= 26.5)) && (re <= 1.9e+154)))
		tmp = exp(re) * im;
	else
		tmp = sin(im) * (1.0 + (re * (1.0 + (re * 0.5))));
	end
	tmp_2 = tmp;
end
code[re_, im_] := If[Or[LessEqual[re, -3.2e-5], And[N[Not[LessEqual[re, 26.5]], $MachinePrecision], LessEqual[re, 1.9e+154]]], N[(N[Exp[re], $MachinePrecision] * im), $MachinePrecision], N[(N[Sin[im], $MachinePrecision] * N[(1.0 + N[(re * N[(1.0 + N[(re * 0.5), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]]
\begin{array}{l}

\\
\begin{array}{l}
\mathbf{if}\;re \leq -3.2 \cdot 10^{-5} \lor \neg \left(re \leq 26.5\right) \land re \leq 1.9 \cdot 10^{+154}:\\
\;\;\;\;e^{re} \cdot im\\

\mathbf{else}:\\
\;\;\;\;\sin im \cdot \left(1 + re \cdot \left(1 + re \cdot 0.5\right)\right)\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if re < -3.19999999999999986e-5 or 26.5 < re < 1.8999999999999999e154

    1. Initial program 100.0%

      \[e^{re} \cdot \sin im \]
    2. Add Preprocessing
    3. Taylor expanded in im around 0 93.6%

      \[\leadsto e^{re} \cdot \color{blue}{im} \]

    if -3.19999999999999986e-5 < re < 26.5 or 1.8999999999999999e154 < re

    1. Initial program 100.0%

      \[e^{re} \cdot \sin im \]
    2. Add Preprocessing
    3. Taylor expanded in re around 0 98.6%

      \[\leadsto \color{blue}{\left(1 + re \cdot \left(1 + 0.5 \cdot re\right)\right)} \cdot \sin im \]
    4. Step-by-step derivation
      1. *-commutative98.6%

        \[\leadsto \left(1 + re \cdot \left(1 + \color{blue}{re \cdot 0.5}\right)\right) \cdot \sin im \]
    5. Simplified98.6%

      \[\leadsto \color{blue}{\left(1 + re \cdot \left(1 + re \cdot 0.5\right)\right)} \cdot \sin im \]
  3. Recombined 2 regimes into one program.
  4. Final simplification96.5%

    \[\leadsto \begin{array}{l} \mathbf{if}\;re \leq -3.2 \cdot 10^{-5} \lor \neg \left(re \leq 26.5\right) \land re \leq 1.9 \cdot 10^{+154}:\\ \;\;\;\;e^{re} \cdot im\\ \mathbf{else}:\\ \;\;\;\;\sin im \cdot \left(1 + re \cdot \left(1 + re \cdot 0.5\right)\right)\\ \end{array} \]
  5. Add Preprocessing

Alternative 4: 96.1% accurate, 1.6× speedup?

\[\begin{array}{l} \\ \begin{array}{l} t_0 := e^{re} \cdot im\\ \mathbf{if}\;re \leq -0.00145:\\ \;\;\;\;t\_0\\ \mathbf{elif}\;re \leq 26.5:\\ \;\;\;\;\sin im \cdot \left(1 + re \cdot \left(1 + re \cdot \left(0.5 + re \cdot 0.16666666666666666\right)\right)\right)\\ \mathbf{elif}\;re \leq 1.9 \cdot 10^{+154}:\\ \;\;\;\;t\_0\\ \mathbf{else}:\\ \;\;\;\;\sin im \cdot \left(1 + re \cdot \left(1 + re \cdot 0.5\right)\right)\\ \end{array} \end{array} \]
(FPCore (re im)
 :precision binary64
 (let* ((t_0 (* (exp re) im)))
   (if (<= re -0.00145)
     t_0
     (if (<= re 26.5)
       (*
        (sin im)
        (+ 1.0 (* re (+ 1.0 (* re (+ 0.5 (* re 0.16666666666666666)))))))
       (if (<= re 1.9e+154)
         t_0
         (* (sin im) (+ 1.0 (* re (+ 1.0 (* re 0.5))))))))))
double code(double re, double im) {
	double t_0 = exp(re) * im;
	double tmp;
	if (re <= -0.00145) {
		tmp = t_0;
	} else if (re <= 26.5) {
		tmp = sin(im) * (1.0 + (re * (1.0 + (re * (0.5 + (re * 0.16666666666666666))))));
	} else if (re <= 1.9e+154) {
		tmp = t_0;
	} else {
		tmp = sin(im) * (1.0 + (re * (1.0 + (re * 0.5))));
	}
	return tmp;
}
real(8) function code(re, im)
    real(8), intent (in) :: re
    real(8), intent (in) :: im
    real(8) :: t_0
    real(8) :: tmp
    t_0 = exp(re) * im
    if (re <= (-0.00145d0)) then
        tmp = t_0
    else if (re <= 26.5d0) then
        tmp = sin(im) * (1.0d0 + (re * (1.0d0 + (re * (0.5d0 + (re * 0.16666666666666666d0))))))
    else if (re <= 1.9d+154) then
        tmp = t_0
    else
        tmp = sin(im) * (1.0d0 + (re * (1.0d0 + (re * 0.5d0))))
    end if
    code = tmp
end function
public static double code(double re, double im) {
	double t_0 = Math.exp(re) * im;
	double tmp;
	if (re <= -0.00145) {
		tmp = t_0;
	} else if (re <= 26.5) {
		tmp = Math.sin(im) * (1.0 + (re * (1.0 + (re * (0.5 + (re * 0.16666666666666666))))));
	} else if (re <= 1.9e+154) {
		tmp = t_0;
	} else {
		tmp = Math.sin(im) * (1.0 + (re * (1.0 + (re * 0.5))));
	}
	return tmp;
}
def code(re, im):
	t_0 = math.exp(re) * im
	tmp = 0
	if re <= -0.00145:
		tmp = t_0
	elif re <= 26.5:
		tmp = math.sin(im) * (1.0 + (re * (1.0 + (re * (0.5 + (re * 0.16666666666666666))))))
	elif re <= 1.9e+154:
		tmp = t_0
	else:
		tmp = math.sin(im) * (1.0 + (re * (1.0 + (re * 0.5))))
	return tmp
function code(re, im)
	t_0 = Float64(exp(re) * im)
	tmp = 0.0
	if (re <= -0.00145)
		tmp = t_0;
	elseif (re <= 26.5)
		tmp = Float64(sin(im) * Float64(1.0 + Float64(re * Float64(1.0 + Float64(re * Float64(0.5 + Float64(re * 0.16666666666666666)))))));
	elseif (re <= 1.9e+154)
		tmp = t_0;
	else
		tmp = Float64(sin(im) * Float64(1.0 + Float64(re * Float64(1.0 + Float64(re * 0.5)))));
	end
	return tmp
end
function tmp_2 = code(re, im)
	t_0 = exp(re) * im;
	tmp = 0.0;
	if (re <= -0.00145)
		tmp = t_0;
	elseif (re <= 26.5)
		tmp = sin(im) * (1.0 + (re * (1.0 + (re * (0.5 + (re * 0.16666666666666666))))));
	elseif (re <= 1.9e+154)
		tmp = t_0;
	else
		tmp = sin(im) * (1.0 + (re * (1.0 + (re * 0.5))));
	end
	tmp_2 = tmp;
end
code[re_, im_] := Block[{t$95$0 = N[(N[Exp[re], $MachinePrecision] * im), $MachinePrecision]}, If[LessEqual[re, -0.00145], t$95$0, If[LessEqual[re, 26.5], N[(N[Sin[im], $MachinePrecision] * N[(1.0 + N[(re * N[(1.0 + N[(re * N[(0.5 + N[(re * 0.16666666666666666), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], If[LessEqual[re, 1.9e+154], t$95$0, N[(N[Sin[im], $MachinePrecision] * N[(1.0 + N[(re * N[(1.0 + N[(re * 0.5), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]]]]]
\begin{array}{l}

\\
\begin{array}{l}
t_0 := e^{re} \cdot im\\
\mathbf{if}\;re \leq -0.00145:\\
\;\;\;\;t\_0\\

\mathbf{elif}\;re \leq 26.5:\\
\;\;\;\;\sin im \cdot \left(1 + re \cdot \left(1 + re \cdot \left(0.5 + re \cdot 0.16666666666666666\right)\right)\right)\\

\mathbf{elif}\;re \leq 1.9 \cdot 10^{+154}:\\
\;\;\;\;t\_0\\

\mathbf{else}:\\
\;\;\;\;\sin im \cdot \left(1 + re \cdot \left(1 + re \cdot 0.5\right)\right)\\


\end{array}
\end{array}
Derivation
  1. Split input into 3 regimes
  2. if re < -0.00145 or 26.5 < re < 1.8999999999999999e154

    1. Initial program 100.0%

      \[e^{re} \cdot \sin im \]
    2. Add Preprocessing
    3. Taylor expanded in im around 0 93.6%

      \[\leadsto e^{re} \cdot \color{blue}{im} \]

    if -0.00145 < re < 26.5

    1. Initial program 100.0%

      \[e^{re} \cdot \sin im \]
    2. Add Preprocessing
    3. Taylor expanded in re around 0 98.4%

      \[\leadsto \color{blue}{\left(1 + re \cdot \left(1 + re \cdot \left(0.5 + 0.16666666666666666 \cdot re\right)\right)\right)} \cdot \sin im \]
    4. Step-by-step derivation
      1. *-commutative98.4%

        \[\leadsto \left(1 + re \cdot \left(1 + re \cdot \left(0.5 + \color{blue}{re \cdot 0.16666666666666666}\right)\right)\right) \cdot \sin im \]
    5. Simplified98.4%

      \[\leadsto \color{blue}{\left(1 + re \cdot \left(1 + re \cdot \left(0.5 + re \cdot 0.16666666666666666\right)\right)\right)} \cdot \sin im \]

    if 1.8999999999999999e154 < re

    1. Initial program 100.0%

      \[e^{re} \cdot \sin im \]
    2. Add Preprocessing
    3. Taylor expanded in re around 0 100.0%

      \[\leadsto \color{blue}{\left(1 + re \cdot \left(1 + 0.5 \cdot re\right)\right)} \cdot \sin im \]
    4. Step-by-step derivation
      1. *-commutative100.0%

        \[\leadsto \left(1 + re \cdot \left(1 + \color{blue}{re \cdot 0.5}\right)\right) \cdot \sin im \]
    5. Simplified100.0%

      \[\leadsto \color{blue}{\left(1 + re \cdot \left(1 + re \cdot 0.5\right)\right)} \cdot \sin im \]
  3. Recombined 3 regimes into one program.
  4. Final simplification96.5%

    \[\leadsto \begin{array}{l} \mathbf{if}\;re \leq -0.00145:\\ \;\;\;\;e^{re} \cdot im\\ \mathbf{elif}\;re \leq 26.5:\\ \;\;\;\;\sin im \cdot \left(1 + re \cdot \left(1 + re \cdot \left(0.5 + re \cdot 0.16666666666666666\right)\right)\right)\\ \mathbf{elif}\;re \leq 1.9 \cdot 10^{+154}:\\ \;\;\;\;e^{re} \cdot im\\ \mathbf{else}:\\ \;\;\;\;\sin im \cdot \left(1 + re \cdot \left(1 + re \cdot 0.5\right)\right)\\ \end{array} \]
  5. Add Preprocessing

Alternative 5: 93.0% accurate, 1.8× speedup?

\[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;re \leq -3.2 \cdot 10^{-5} \lor \neg \left(re \leq 26.5\right):\\ \;\;\;\;e^{re} \cdot im\\ \mathbf{else}:\\ \;\;\;\;\sin im \cdot \left(re + 1\right)\\ \end{array} \end{array} \]
(FPCore (re im)
 :precision binary64
 (if (or (<= re -3.2e-5) (not (<= re 26.5)))
   (* (exp re) im)
   (* (sin im) (+ re 1.0))))
double code(double re, double im) {
	double tmp;
	if ((re <= -3.2e-5) || !(re <= 26.5)) {
		tmp = exp(re) * im;
	} else {
		tmp = sin(im) * (re + 1.0);
	}
	return tmp;
}
real(8) function code(re, im)
    real(8), intent (in) :: re
    real(8), intent (in) :: im
    real(8) :: tmp
    if ((re <= (-3.2d-5)) .or. (.not. (re <= 26.5d0))) then
        tmp = exp(re) * im
    else
        tmp = sin(im) * (re + 1.0d0)
    end if
    code = tmp
end function
public static double code(double re, double im) {
	double tmp;
	if ((re <= -3.2e-5) || !(re <= 26.5)) {
		tmp = Math.exp(re) * im;
	} else {
		tmp = Math.sin(im) * (re + 1.0);
	}
	return tmp;
}
def code(re, im):
	tmp = 0
	if (re <= -3.2e-5) or not (re <= 26.5):
		tmp = math.exp(re) * im
	else:
		tmp = math.sin(im) * (re + 1.0)
	return tmp
function code(re, im)
	tmp = 0.0
	if ((re <= -3.2e-5) || !(re <= 26.5))
		tmp = Float64(exp(re) * im);
	else
		tmp = Float64(sin(im) * Float64(re + 1.0));
	end
	return tmp
end
function tmp_2 = code(re, im)
	tmp = 0.0;
	if ((re <= -3.2e-5) || ~((re <= 26.5)))
		tmp = exp(re) * im;
	else
		tmp = sin(im) * (re + 1.0);
	end
	tmp_2 = tmp;
end
code[re_, im_] := If[Or[LessEqual[re, -3.2e-5], N[Not[LessEqual[re, 26.5]], $MachinePrecision]], N[(N[Exp[re], $MachinePrecision] * im), $MachinePrecision], N[(N[Sin[im], $MachinePrecision] * N[(re + 1.0), $MachinePrecision]), $MachinePrecision]]
\begin{array}{l}

\\
\begin{array}{l}
\mathbf{if}\;re \leq -3.2 \cdot 10^{-5} \lor \neg \left(re \leq 26.5\right):\\
\;\;\;\;e^{re} \cdot im\\

\mathbf{else}:\\
\;\;\;\;\sin im \cdot \left(re + 1\right)\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if re < -3.19999999999999986e-5 or 26.5 < re

    1. Initial program 100.0%

      \[e^{re} \cdot \sin im \]
    2. Add Preprocessing
    3. Taylor expanded in im around 0 89.9%

      \[\leadsto e^{re} \cdot \color{blue}{im} \]

    if -3.19999999999999986e-5 < re < 26.5

    1. Initial program 100.0%

      \[e^{re} \cdot \sin im \]
    2. Add Preprocessing
    3. Taylor expanded in re around 0 98.1%

      \[\leadsto \color{blue}{\sin im + re \cdot \sin im} \]
    4. Step-by-step derivation
      1. distribute-rgt1-in98.1%

        \[\leadsto \color{blue}{\left(re + 1\right) \cdot \sin im} \]
    5. Simplified98.1%

      \[\leadsto \color{blue}{\left(re + 1\right) \cdot \sin im} \]
  3. Recombined 2 regimes into one program.
  4. Final simplification93.7%

    \[\leadsto \begin{array}{l} \mathbf{if}\;re \leq -3.2 \cdot 10^{-5} \lor \neg \left(re \leq 26.5\right):\\ \;\;\;\;e^{re} \cdot im\\ \mathbf{else}:\\ \;\;\;\;\sin im \cdot \left(re + 1\right)\\ \end{array} \]
  5. Add Preprocessing

Alternative 6: 70.4% accurate, 1.8× speedup?

\[\begin{array}{l} \\ \begin{array}{l} t_0 := 1 + re \cdot \left(1 + re \cdot \left(0.5 + re \cdot 0.16666666666666666\right)\right)\\ \mathbf{if}\;re \leq -64:\\ \;\;\;\;t\_0 \cdot 0\\ \mathbf{elif}\;re \leq 750000000:\\ \;\;\;\;\sin im\\ \mathbf{else}:\\ \;\;\;\;im \cdot t\_0\\ \end{array} \end{array} \]
(FPCore (re im)
 :precision binary64
 (let* ((t_0 (+ 1.0 (* re (+ 1.0 (* re (+ 0.5 (* re 0.16666666666666666))))))))
   (if (<= re -64.0)
     (* t_0 0.0)
     (if (<= re 750000000.0) (sin im) (* im t_0)))))
double code(double re, double im) {
	double t_0 = 1.0 + (re * (1.0 + (re * (0.5 + (re * 0.16666666666666666)))));
	double tmp;
	if (re <= -64.0) {
		tmp = t_0 * 0.0;
	} else if (re <= 750000000.0) {
		tmp = sin(im);
	} else {
		tmp = im * t_0;
	}
	return tmp;
}
real(8) function code(re, im)
    real(8), intent (in) :: re
    real(8), intent (in) :: im
    real(8) :: t_0
    real(8) :: tmp
    t_0 = 1.0d0 + (re * (1.0d0 + (re * (0.5d0 + (re * 0.16666666666666666d0)))))
    if (re <= (-64.0d0)) then
        tmp = t_0 * 0.0d0
    else if (re <= 750000000.0d0) then
        tmp = sin(im)
    else
        tmp = im * t_0
    end if
    code = tmp
end function
public static double code(double re, double im) {
	double t_0 = 1.0 + (re * (1.0 + (re * (0.5 + (re * 0.16666666666666666)))));
	double tmp;
	if (re <= -64.0) {
		tmp = t_0 * 0.0;
	} else if (re <= 750000000.0) {
		tmp = Math.sin(im);
	} else {
		tmp = im * t_0;
	}
	return tmp;
}
def code(re, im):
	t_0 = 1.0 + (re * (1.0 + (re * (0.5 + (re * 0.16666666666666666)))))
	tmp = 0
	if re <= -64.0:
		tmp = t_0 * 0.0
	elif re <= 750000000.0:
		tmp = math.sin(im)
	else:
		tmp = im * t_0
	return tmp
function code(re, im)
	t_0 = Float64(1.0 + Float64(re * Float64(1.0 + Float64(re * Float64(0.5 + Float64(re * 0.16666666666666666))))))
	tmp = 0.0
	if (re <= -64.0)
		tmp = Float64(t_0 * 0.0);
	elseif (re <= 750000000.0)
		tmp = sin(im);
	else
		tmp = Float64(im * t_0);
	end
	return tmp
end
function tmp_2 = code(re, im)
	t_0 = 1.0 + (re * (1.0 + (re * (0.5 + (re * 0.16666666666666666)))));
	tmp = 0.0;
	if (re <= -64.0)
		tmp = t_0 * 0.0;
	elseif (re <= 750000000.0)
		tmp = sin(im);
	else
		tmp = im * t_0;
	end
	tmp_2 = tmp;
end
code[re_, im_] := Block[{t$95$0 = N[(1.0 + N[(re * N[(1.0 + N[(re * N[(0.5 + N[(re * 0.16666666666666666), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[re, -64.0], N[(t$95$0 * 0.0), $MachinePrecision], If[LessEqual[re, 750000000.0], N[Sin[im], $MachinePrecision], N[(im * t$95$0), $MachinePrecision]]]]
\begin{array}{l}

\\
\begin{array}{l}
t_0 := 1 + re \cdot \left(1 + re \cdot \left(0.5 + re \cdot 0.16666666666666666\right)\right)\\
\mathbf{if}\;re \leq -64:\\
\;\;\;\;t\_0 \cdot 0\\

\mathbf{elif}\;re \leq 750000000:\\
\;\;\;\;\sin im\\

\mathbf{else}:\\
\;\;\;\;im \cdot t\_0\\


\end{array}
\end{array}
Derivation
  1. Split input into 3 regimes
  2. if re < -64

    1. Initial program 100.0%

      \[e^{re} \cdot \sin im \]
    2. Add Preprocessing
    3. Taylor expanded in re around 0 1.9%

      \[\leadsto \color{blue}{\left(1 + re \cdot \left(1 + re \cdot \left(0.5 + 0.16666666666666666 \cdot re\right)\right)\right)} \cdot \sin im \]
    4. Step-by-step derivation
      1. *-commutative1.9%

        \[\leadsto \left(1 + re \cdot \left(1 + re \cdot \left(0.5 + \color{blue}{re \cdot 0.16666666666666666}\right)\right)\right) \cdot \sin im \]
    5. Simplified1.9%

      \[\leadsto \color{blue}{\left(1 + re \cdot \left(1 + re \cdot \left(0.5 + re \cdot 0.16666666666666666\right)\right)\right)} \cdot \sin im \]
    6. Step-by-step derivation
      1. expm1-log1p-u1.9%

        \[\leadsto \left(1 + re \cdot \left(1 + re \cdot \left(0.5 + re \cdot 0.16666666666666666\right)\right)\right) \cdot \color{blue}{\mathsf{expm1}\left(\mathsf{log1p}\left(\sin im\right)\right)} \]
      2. expm1-undefine11.3%

        \[\leadsto \left(1 + re \cdot \left(1 + re \cdot \left(0.5 + re \cdot 0.16666666666666666\right)\right)\right) \cdot \color{blue}{\left(e^{\mathsf{log1p}\left(\sin im\right)} - 1\right)} \]
      3. log1p-undefine11.3%

        \[\leadsto \left(1 + re \cdot \left(1 + re \cdot \left(0.5 + re \cdot 0.16666666666666666\right)\right)\right) \cdot \left(e^{\color{blue}{\log \left(1 + \sin im\right)}} - 1\right) \]
      4. rem-exp-log11.3%

        \[\leadsto \left(1 + re \cdot \left(1 + re \cdot \left(0.5 + re \cdot 0.16666666666666666\right)\right)\right) \cdot \left(\color{blue}{\left(1 + \sin im\right)} - 1\right) \]
    7. Applied egg-rr11.3%

      \[\leadsto \left(1 + re \cdot \left(1 + re \cdot \left(0.5 + re \cdot 0.16666666666666666\right)\right)\right) \cdot \color{blue}{\left(\left(1 + \sin im\right) - 1\right)} \]
    8. Taylor expanded in im around 0 29.5%

      \[\leadsto \left(1 + re \cdot \left(1 + re \cdot \left(0.5 + re \cdot 0.16666666666666666\right)\right)\right) \cdot \left(\color{blue}{1} - 1\right) \]

    if -64 < re < 7.5e8

    1. Initial program 100.0%

      \[e^{re} \cdot \sin im \]
    2. Add Preprocessing
    3. Taylor expanded in re around 0 95.8%

      \[\leadsto \color{blue}{\sin im} \]

    if 7.5e8 < re

    1. Initial program 100.0%

      \[e^{re} \cdot \sin im \]
    2. Add Preprocessing
    3. Taylor expanded in im around 0 75.9%

      \[\leadsto e^{re} \cdot \color{blue}{im} \]
    4. Taylor expanded in re around 0 55.9%

      \[\leadsto \color{blue}{\left(1 + re \cdot \left(1 + re \cdot \left(0.5 + 0.16666666666666666 \cdot re\right)\right)\right)} \cdot im \]
    5. Step-by-step derivation
      1. *-commutative62.2%

        \[\leadsto \left(1 + re \cdot \left(1 + re \cdot \left(0.5 + \color{blue}{re \cdot 0.16666666666666666}\right)\right)\right) \cdot \sin im \]
    6. Simplified55.9%

      \[\leadsto \color{blue}{\left(1 + re \cdot \left(1 + re \cdot \left(0.5 + re \cdot 0.16666666666666666\right)\right)\right)} \cdot im \]
  3. Recombined 3 regimes into one program.
  4. Final simplification66.6%

    \[\leadsto \begin{array}{l} \mathbf{if}\;re \leq -64:\\ \;\;\;\;\left(1 + re \cdot \left(1 + re \cdot \left(0.5 + re \cdot 0.16666666666666666\right)\right)\right) \cdot 0\\ \mathbf{elif}\;re \leq 750000000:\\ \;\;\;\;\sin im\\ \mathbf{else}:\\ \;\;\;\;im \cdot \left(1 + re \cdot \left(1 + re \cdot \left(0.5 + re \cdot 0.16666666666666666\right)\right)\right)\\ \end{array} \]
  5. Add Preprocessing

Alternative 7: 47.3% accurate, 10.1× speedup?

\[\begin{array}{l} \\ \begin{array}{l} t_0 := 1 + re \cdot \left(1 + re \cdot \left(0.5 + re \cdot 0.16666666666666666\right)\right)\\ \mathbf{if}\;re \leq -1.7:\\ \;\;\;\;t\_0 \cdot 0\\ \mathbf{else}:\\ \;\;\;\;im \cdot t\_0\\ \end{array} \end{array} \]
(FPCore (re im)
 :precision binary64
 (let* ((t_0 (+ 1.0 (* re (+ 1.0 (* re (+ 0.5 (* re 0.16666666666666666))))))))
   (if (<= re -1.7) (* t_0 0.0) (* im t_0))))
double code(double re, double im) {
	double t_0 = 1.0 + (re * (1.0 + (re * (0.5 + (re * 0.16666666666666666)))));
	double tmp;
	if (re <= -1.7) {
		tmp = t_0 * 0.0;
	} else {
		tmp = im * t_0;
	}
	return tmp;
}
real(8) function code(re, im)
    real(8), intent (in) :: re
    real(8), intent (in) :: im
    real(8) :: t_0
    real(8) :: tmp
    t_0 = 1.0d0 + (re * (1.0d0 + (re * (0.5d0 + (re * 0.16666666666666666d0)))))
    if (re <= (-1.7d0)) then
        tmp = t_0 * 0.0d0
    else
        tmp = im * t_0
    end if
    code = tmp
end function
public static double code(double re, double im) {
	double t_0 = 1.0 + (re * (1.0 + (re * (0.5 + (re * 0.16666666666666666)))));
	double tmp;
	if (re <= -1.7) {
		tmp = t_0 * 0.0;
	} else {
		tmp = im * t_0;
	}
	return tmp;
}
def code(re, im):
	t_0 = 1.0 + (re * (1.0 + (re * (0.5 + (re * 0.16666666666666666)))))
	tmp = 0
	if re <= -1.7:
		tmp = t_0 * 0.0
	else:
		tmp = im * t_0
	return tmp
function code(re, im)
	t_0 = Float64(1.0 + Float64(re * Float64(1.0 + Float64(re * Float64(0.5 + Float64(re * 0.16666666666666666))))))
	tmp = 0.0
	if (re <= -1.7)
		tmp = Float64(t_0 * 0.0);
	else
		tmp = Float64(im * t_0);
	end
	return tmp
end
function tmp_2 = code(re, im)
	t_0 = 1.0 + (re * (1.0 + (re * (0.5 + (re * 0.16666666666666666)))));
	tmp = 0.0;
	if (re <= -1.7)
		tmp = t_0 * 0.0;
	else
		tmp = im * t_0;
	end
	tmp_2 = tmp;
end
code[re_, im_] := Block[{t$95$0 = N[(1.0 + N[(re * N[(1.0 + N[(re * N[(0.5 + N[(re * 0.16666666666666666), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[re, -1.7], N[(t$95$0 * 0.0), $MachinePrecision], N[(im * t$95$0), $MachinePrecision]]]
\begin{array}{l}

\\
\begin{array}{l}
t_0 := 1 + re \cdot \left(1 + re \cdot \left(0.5 + re \cdot 0.16666666666666666\right)\right)\\
\mathbf{if}\;re \leq -1.7:\\
\;\;\;\;t\_0 \cdot 0\\

\mathbf{else}:\\
\;\;\;\;im \cdot t\_0\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if re < -1.69999999999999996

    1. Initial program 100.0%

      \[e^{re} \cdot \sin im \]
    2. Add Preprocessing
    3. Taylor expanded in re around 0 1.9%

      \[\leadsto \color{blue}{\left(1 + re \cdot \left(1 + re \cdot \left(0.5 + 0.16666666666666666 \cdot re\right)\right)\right)} \cdot \sin im \]
    4. Step-by-step derivation
      1. *-commutative1.9%

        \[\leadsto \left(1 + re \cdot \left(1 + re \cdot \left(0.5 + \color{blue}{re \cdot 0.16666666666666666}\right)\right)\right) \cdot \sin im \]
    5. Simplified1.9%

      \[\leadsto \color{blue}{\left(1 + re \cdot \left(1 + re \cdot \left(0.5 + re \cdot 0.16666666666666666\right)\right)\right)} \cdot \sin im \]
    6. Step-by-step derivation
      1. expm1-log1p-u1.9%

        \[\leadsto \left(1 + re \cdot \left(1 + re \cdot \left(0.5 + re \cdot 0.16666666666666666\right)\right)\right) \cdot \color{blue}{\mathsf{expm1}\left(\mathsf{log1p}\left(\sin im\right)\right)} \]
      2. expm1-undefine11.3%

        \[\leadsto \left(1 + re \cdot \left(1 + re \cdot \left(0.5 + re \cdot 0.16666666666666666\right)\right)\right) \cdot \color{blue}{\left(e^{\mathsf{log1p}\left(\sin im\right)} - 1\right)} \]
      3. log1p-undefine11.3%

        \[\leadsto \left(1 + re \cdot \left(1 + re \cdot \left(0.5 + re \cdot 0.16666666666666666\right)\right)\right) \cdot \left(e^{\color{blue}{\log \left(1 + \sin im\right)}} - 1\right) \]
      4. rem-exp-log11.3%

        \[\leadsto \left(1 + re \cdot \left(1 + re \cdot \left(0.5 + re \cdot 0.16666666666666666\right)\right)\right) \cdot \left(\color{blue}{\left(1 + \sin im\right)} - 1\right) \]
    7. Applied egg-rr11.3%

      \[\leadsto \left(1 + re \cdot \left(1 + re \cdot \left(0.5 + re \cdot 0.16666666666666666\right)\right)\right) \cdot \color{blue}{\left(\left(1 + \sin im\right) - 1\right)} \]
    8. Taylor expanded in im around 0 29.2%

      \[\leadsto \left(1 + re \cdot \left(1 + re \cdot \left(0.5 + re \cdot 0.16666666666666666\right)\right)\right) \cdot \left(\color{blue}{1} - 1\right) \]

    if -1.69999999999999996 < re

    1. Initial program 100.0%

      \[e^{re} \cdot \sin im \]
    2. Add Preprocessing
    3. Taylor expanded in im around 0 63.1%

      \[\leadsto e^{re} \cdot \color{blue}{im} \]
    4. Taylor expanded in re around 0 56.5%

      \[\leadsto \color{blue}{\left(1 + re \cdot \left(1 + re \cdot \left(0.5 + 0.16666666666666666 \cdot re\right)\right)\right)} \cdot im \]
    5. Step-by-step derivation
      1. *-commutative86.5%

        \[\leadsto \left(1 + re \cdot \left(1 + re \cdot \left(0.5 + \color{blue}{re \cdot 0.16666666666666666}\right)\right)\right) \cdot \sin im \]
    6. Simplified56.5%

      \[\leadsto \color{blue}{\left(1 + re \cdot \left(1 + re \cdot \left(0.5 + re \cdot 0.16666666666666666\right)\right)\right)} \cdot im \]
  3. Recombined 2 regimes into one program.
  4. Final simplification48.1%

    \[\leadsto \begin{array}{l} \mathbf{if}\;re \leq -1.7:\\ \;\;\;\;\left(1 + re \cdot \left(1 + re \cdot \left(0.5 + re \cdot 0.16666666666666666\right)\right)\right) \cdot 0\\ \mathbf{else}:\\ \;\;\;\;im \cdot \left(1 + re \cdot \left(1 + re \cdot \left(0.5 + re \cdot 0.16666666666666666\right)\right)\right)\\ \end{array} \]
  5. Add Preprocessing

Alternative 8: 39.9% accurate, 13.5× speedup?

\[\begin{array}{l} \\ im \cdot \left(1 + re \cdot \left(1 + re \cdot \left(0.5 + re \cdot 0.16666666666666666\right)\right)\right) \end{array} \]
(FPCore (re im)
 :precision binary64
 (* im (+ 1.0 (* re (+ 1.0 (* re (+ 0.5 (* re 0.16666666666666666))))))))
double code(double re, double im) {
	return im * (1.0 + (re * (1.0 + (re * (0.5 + (re * 0.16666666666666666))))));
}
real(8) function code(re, im)
    real(8), intent (in) :: re
    real(8), intent (in) :: im
    code = im * (1.0d0 + (re * (1.0d0 + (re * (0.5d0 + (re * 0.16666666666666666d0))))))
end function
public static double code(double re, double im) {
	return im * (1.0 + (re * (1.0 + (re * (0.5 + (re * 0.16666666666666666))))));
}
def code(re, im):
	return im * (1.0 + (re * (1.0 + (re * (0.5 + (re * 0.16666666666666666))))))
function code(re, im)
	return Float64(im * Float64(1.0 + Float64(re * Float64(1.0 + Float64(re * Float64(0.5 + Float64(re * 0.16666666666666666)))))))
end
function tmp = code(re, im)
	tmp = im * (1.0 + (re * (1.0 + (re * (0.5 + (re * 0.16666666666666666))))));
end
code[re_, im_] := N[(im * N[(1.0 + N[(re * N[(1.0 + N[(re * N[(0.5 + N[(re * 0.16666666666666666), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
im \cdot \left(1 + re \cdot \left(1 + re \cdot \left(0.5 + re \cdot 0.16666666666666666\right)\right)\right)
\end{array}
Derivation
  1. Initial program 100.0%

    \[e^{re} \cdot \sin im \]
  2. Add Preprocessing
  3. Taylor expanded in im around 0 74.5%

    \[\leadsto e^{re} \cdot \color{blue}{im} \]
  4. Taylor expanded in re around 0 39.6%

    \[\leadsto \color{blue}{\left(1 + re \cdot \left(1 + re \cdot \left(0.5 + 0.16666666666666666 \cdot re\right)\right)\right)} \cdot im \]
  5. Step-by-step derivation
    1. *-commutative60.4%

      \[\leadsto \left(1 + re \cdot \left(1 + re \cdot \left(0.5 + \color{blue}{re \cdot 0.16666666666666666}\right)\right)\right) \cdot \sin im \]
  6. Simplified39.6%

    \[\leadsto \color{blue}{\left(1 + re \cdot \left(1 + re \cdot \left(0.5 + re \cdot 0.16666666666666666\right)\right)\right)} \cdot im \]
  7. Final simplification39.6%

    \[\leadsto im \cdot \left(1 + re \cdot \left(1 + re \cdot \left(0.5 + re \cdot 0.16666666666666666\right)\right)\right) \]
  8. Add Preprocessing

Alternative 9: 37.4% accurate, 18.5× speedup?

\[\begin{array}{l} \\ im \cdot \left(1 + re \cdot \left(1 + re \cdot 0.5\right)\right) \end{array} \]
(FPCore (re im) :precision binary64 (* im (+ 1.0 (* re (+ 1.0 (* re 0.5))))))
double code(double re, double im) {
	return im * (1.0 + (re * (1.0 + (re * 0.5))));
}
real(8) function code(re, im)
    real(8), intent (in) :: re
    real(8), intent (in) :: im
    code = im * (1.0d0 + (re * (1.0d0 + (re * 0.5d0))))
end function
public static double code(double re, double im) {
	return im * (1.0 + (re * (1.0 + (re * 0.5))));
}
def code(re, im):
	return im * (1.0 + (re * (1.0 + (re * 0.5))))
function code(re, im)
	return Float64(im * Float64(1.0 + Float64(re * Float64(1.0 + Float64(re * 0.5)))))
end
function tmp = code(re, im)
	tmp = im * (1.0 + (re * (1.0 + (re * 0.5))));
end
code[re_, im_] := N[(im * N[(1.0 + N[(re * N[(1.0 + N[(re * 0.5), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
im \cdot \left(1 + re \cdot \left(1 + re \cdot 0.5\right)\right)
\end{array}
Derivation
  1. Initial program 100.0%

    \[e^{re} \cdot \sin im \]
  2. Add Preprocessing
  3. Taylor expanded in im around 0 74.5%

    \[\leadsto e^{re} \cdot \color{blue}{im} \]
  4. Taylor expanded in re around 0 37.0%

    \[\leadsto \color{blue}{\left(1 + re \cdot \left(1 + 0.5 \cdot re\right)\right)} \cdot im \]
  5. Step-by-step derivation
    1. *-commutative58.0%

      \[\leadsto \left(1 + re \cdot \left(1 + \color{blue}{re \cdot 0.5}\right)\right) \cdot \sin im \]
  6. Simplified37.0%

    \[\leadsto \color{blue}{\left(1 + re \cdot \left(1 + re \cdot 0.5\right)\right)} \cdot im \]
  7. Final simplification37.0%

    \[\leadsto im \cdot \left(1 + re \cdot \left(1 + re \cdot 0.5\right)\right) \]
  8. Add Preprocessing

Alternative 10: 28.3% accurate, 25.3× speedup?

\[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;im \leq 6.3 \cdot 10^{+16}:\\ \;\;\;\;im\\ \mathbf{else}:\\ \;\;\;\;re \cdot im\\ \end{array} \end{array} \]
(FPCore (re im) :precision binary64 (if (<= im 6.3e+16) im (* re im)))
double code(double re, double im) {
	double tmp;
	if (im <= 6.3e+16) {
		tmp = im;
	} else {
		tmp = re * im;
	}
	return tmp;
}
real(8) function code(re, im)
    real(8), intent (in) :: re
    real(8), intent (in) :: im
    real(8) :: tmp
    if (im <= 6.3d+16) then
        tmp = im
    else
        tmp = re * im
    end if
    code = tmp
end function
public static double code(double re, double im) {
	double tmp;
	if (im <= 6.3e+16) {
		tmp = im;
	} else {
		tmp = re * im;
	}
	return tmp;
}
def code(re, im):
	tmp = 0
	if im <= 6.3e+16:
		tmp = im
	else:
		tmp = re * im
	return tmp
function code(re, im)
	tmp = 0.0
	if (im <= 6.3e+16)
		tmp = im;
	else
		tmp = Float64(re * im);
	end
	return tmp
end
function tmp_2 = code(re, im)
	tmp = 0.0;
	if (im <= 6.3e+16)
		tmp = im;
	else
		tmp = re * im;
	end
	tmp_2 = tmp;
end
code[re_, im_] := If[LessEqual[im, 6.3e+16], im, N[(re * im), $MachinePrecision]]
\begin{array}{l}

\\
\begin{array}{l}
\mathbf{if}\;im \leq 6.3 \cdot 10^{+16}:\\
\;\;\;\;im\\

\mathbf{else}:\\
\;\;\;\;re \cdot im\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if im < 6.3e16

    1. Initial program 100.0%

      \[e^{re} \cdot \sin im \]
    2. Add Preprocessing
    3. Taylor expanded in im around 0 80.6%

      \[\leadsto e^{re} \cdot \color{blue}{im} \]
    4. Taylor expanded in re around 0 35.3%

      \[\leadsto \color{blue}{im} \]

    if 6.3e16 < im

    1. Initial program 100.0%

      \[e^{re} \cdot \sin im \]
    2. Add Preprocessing
    3. Taylor expanded in re around 0 33.0%

      \[\leadsto \color{blue}{\sin im + re \cdot \sin im} \]
    4. Step-by-step derivation
      1. distribute-rgt1-in33.0%

        \[\leadsto \color{blue}{\left(re + 1\right) \cdot \sin im} \]
    5. Simplified33.0%

      \[\leadsto \color{blue}{\left(re + 1\right) \cdot \sin im} \]
    6. Taylor expanded in re around inf 4.0%

      \[\leadsto \color{blue}{re \cdot \sin im} \]
    7. Taylor expanded in im around 0 12.5%

      \[\leadsto re \cdot \color{blue}{im} \]
  3. Recombined 2 regimes into one program.
  4. Add Preprocessing

Alternative 11: 29.8% accurate, 40.6× speedup?

\[\begin{array}{l} \\ im + re \cdot im \end{array} \]
(FPCore (re im) :precision binary64 (+ im (* re im)))
double code(double re, double im) {
	return im + (re * im);
}
real(8) function code(re, im)
    real(8), intent (in) :: re
    real(8), intent (in) :: im
    code = im + (re * im)
end function
public static double code(double re, double im) {
	return im + (re * im);
}
def code(re, im):
	return im + (re * im)
function code(re, im)
	return Float64(im + Float64(re * im))
end
function tmp = code(re, im)
	tmp = im + (re * im);
end
code[re_, im_] := N[(im + N[(re * im), $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
im + re \cdot im
\end{array}
Derivation
  1. Initial program 100.0%

    \[e^{re} \cdot \sin im \]
  2. Add Preprocessing
  3. Taylor expanded in im around 0 74.5%

    \[\leadsto e^{re} \cdot \color{blue}{im} \]
  4. Taylor expanded in re around 0 31.3%

    \[\leadsto \color{blue}{im + im \cdot re} \]
  5. Final simplification31.3%

    \[\leadsto im + re \cdot im \]
  6. Add Preprocessing

Alternative 12: 26.5% accurate, 203.0× speedup?

\[\begin{array}{l} \\ im \end{array} \]
(FPCore (re im) :precision binary64 im)
double code(double re, double im) {
	return im;
}
real(8) function code(re, im)
    real(8), intent (in) :: re
    real(8), intent (in) :: im
    code = im
end function
public static double code(double re, double im) {
	return im;
}
def code(re, im):
	return im
function code(re, im)
	return im
end
function tmp = code(re, im)
	tmp = im;
end
code[re_, im_] := im
\begin{array}{l}

\\
im
\end{array}
Derivation
  1. Initial program 100.0%

    \[e^{re} \cdot \sin im \]
  2. Add Preprocessing
  3. Taylor expanded in im around 0 74.5%

    \[\leadsto e^{re} \cdot \color{blue}{im} \]
  4. Taylor expanded in re around 0 27.7%

    \[\leadsto \color{blue}{im} \]
  5. Add Preprocessing

Reproduce

?
herbie shell --seed 2024141 
(FPCore (re im)
  :name "math.exp on complex, imaginary part"
  :precision binary64
  (* (exp re) (sin im)))