ABCF->ab-angle angle

Percentage Accurate: 54.5% → 83.0%
Time: 17.3s
Alternatives: 19
Speedup: 3.6×

Specification

?
\[\begin{array}{l} \\ 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \end{array} \]
(FPCore (A B C)
 :precision binary64
 (*
  180.0
  (/
   (atan (* (/ 1.0 B) (- (- C A) (sqrt (+ (pow (- A C) 2.0) (pow B 2.0))))))
   PI)))
double code(double A, double B, double C) {
	return 180.0 * (atan(((1.0 / B) * ((C - A) - sqrt((pow((A - C), 2.0) + pow(B, 2.0)))))) / ((double) M_PI));
}
public static double code(double A, double B, double C) {
	return 180.0 * (Math.atan(((1.0 / B) * ((C - A) - Math.sqrt((Math.pow((A - C), 2.0) + Math.pow(B, 2.0)))))) / Math.PI);
}
def code(A, B, C):
	return 180.0 * (math.atan(((1.0 / B) * ((C - A) - math.sqrt((math.pow((A - C), 2.0) + math.pow(B, 2.0)))))) / math.pi)
function code(A, B, C)
	return Float64(180.0 * Float64(atan(Float64(Float64(1.0 / B) * Float64(Float64(C - A) - sqrt(Float64((Float64(A - C) ^ 2.0) + (B ^ 2.0)))))) / pi))
end
function tmp = code(A, B, C)
	tmp = 180.0 * (atan(((1.0 / B) * ((C - A) - sqrt((((A - C) ^ 2.0) + (B ^ 2.0)))))) / pi);
end
code[A_, B_, C_] := N[(180.0 * N[(N[ArcTan[N[(N[(1.0 / B), $MachinePrecision] * N[(N[(C - A), $MachinePrecision] - N[Sqrt[N[(N[Power[N[(A - C), $MachinePrecision], 2.0], $MachinePrecision] + N[Power[B, 2.0], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi}
\end{array}

Sampling outcomes in binary64 precision:

Local Percentage Accuracy vs ?

The average percentage accuracy by input value. Horizontal axis shows value of an input variable; the variable is choosen in the title. Vertical axis is accuracy; higher is better. Red represent the original program, while blue represents Herbie's suggestion. These can be toggled with buttons below the plot. The line is an average while dots represent individual samples.

Accuracy vs Speed?

Herbie found 19 alternatives:

AlternativeAccuracySpeedup
The accuracy (vertical axis) and speed (horizontal axis) of each alternatives. Up and to the right is better. The red square shows the initial program, and each blue circle shows an alternative.The line shows the best available speed-accuracy tradeoffs.

Initial Program: 54.5% accurate, 1.0× speedup?

\[\begin{array}{l} \\ 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \end{array} \]
(FPCore (A B C)
 :precision binary64
 (*
  180.0
  (/
   (atan (* (/ 1.0 B) (- (- C A) (sqrt (+ (pow (- A C) 2.0) (pow B 2.0))))))
   PI)))
double code(double A, double B, double C) {
	return 180.0 * (atan(((1.0 / B) * ((C - A) - sqrt((pow((A - C), 2.0) + pow(B, 2.0)))))) / ((double) M_PI));
}
public static double code(double A, double B, double C) {
	return 180.0 * (Math.atan(((1.0 / B) * ((C - A) - Math.sqrt((Math.pow((A - C), 2.0) + Math.pow(B, 2.0)))))) / Math.PI);
}
def code(A, B, C):
	return 180.0 * (math.atan(((1.0 / B) * ((C - A) - math.sqrt((math.pow((A - C), 2.0) + math.pow(B, 2.0)))))) / math.pi)
function code(A, B, C)
	return Float64(180.0 * Float64(atan(Float64(Float64(1.0 / B) * Float64(Float64(C - A) - sqrt(Float64((Float64(A - C) ^ 2.0) + (B ^ 2.0)))))) / pi))
end
function tmp = code(A, B, C)
	tmp = 180.0 * (atan(((1.0 / B) * ((C - A) - sqrt((((A - C) ^ 2.0) + (B ^ 2.0)))))) / pi);
end
code[A_, B_, C_] := N[(180.0 * N[(N[ArcTan[N[(N[(1.0 / B), $MachinePrecision] * N[(N[(C - A), $MachinePrecision] - N[Sqrt[N[(N[Power[N[(A - C), $MachinePrecision], 2.0], $MachinePrecision] + N[Power[B, 2.0], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi}
\end{array}

Alternative 1: 83.0% accurate, 0.5× speedup?

\[\begin{array}{l} \\ \begin{array}{l} t_0 := \frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\\ t_1 := \tan^{-1} \left(\frac{\left(C - A\right) - \mathsf{hypot}\left(B, A - C\right)}{B}\right)\\ \mathbf{if}\;t\_0 \leq -0.5:\\ \;\;\;\;\frac{180 \cdot t\_1}{\pi}\\ \mathbf{elif}\;t\_0 \leq 0:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{B \cdot 0.5}{A}\right)}{\pi}\\ \mathbf{else}:\\ \;\;\;\;180 \cdot \frac{t\_1}{\pi}\\ \end{array} \end{array} \]
(FPCore (A B C)
 :precision binary64
 (let* ((t_0
         (* (/ 1.0 B) (- (- C A) (sqrt (+ (pow (- A C) 2.0) (pow B 2.0))))))
        (t_1 (atan (/ (- (- C A) (hypot B (- A C))) B))))
   (if (<= t_0 -0.5)
     (/ (* 180.0 t_1) PI)
     (if (<= t_0 0.0)
       (* 180.0 (/ (atan (/ (* B 0.5) A)) PI))
       (* 180.0 (/ t_1 PI))))))
double code(double A, double B, double C) {
	double t_0 = (1.0 / B) * ((C - A) - sqrt((pow((A - C), 2.0) + pow(B, 2.0))));
	double t_1 = atan((((C - A) - hypot(B, (A - C))) / B));
	double tmp;
	if (t_0 <= -0.5) {
		tmp = (180.0 * t_1) / ((double) M_PI);
	} else if (t_0 <= 0.0) {
		tmp = 180.0 * (atan(((B * 0.5) / A)) / ((double) M_PI));
	} else {
		tmp = 180.0 * (t_1 / ((double) M_PI));
	}
	return tmp;
}
public static double code(double A, double B, double C) {
	double t_0 = (1.0 / B) * ((C - A) - Math.sqrt((Math.pow((A - C), 2.0) + Math.pow(B, 2.0))));
	double t_1 = Math.atan((((C - A) - Math.hypot(B, (A - C))) / B));
	double tmp;
	if (t_0 <= -0.5) {
		tmp = (180.0 * t_1) / Math.PI;
	} else if (t_0 <= 0.0) {
		tmp = 180.0 * (Math.atan(((B * 0.5) / A)) / Math.PI);
	} else {
		tmp = 180.0 * (t_1 / Math.PI);
	}
	return tmp;
}
def code(A, B, C):
	t_0 = (1.0 / B) * ((C - A) - math.sqrt((math.pow((A - C), 2.0) + math.pow(B, 2.0))))
	t_1 = math.atan((((C - A) - math.hypot(B, (A - C))) / B))
	tmp = 0
	if t_0 <= -0.5:
		tmp = (180.0 * t_1) / math.pi
	elif t_0 <= 0.0:
		tmp = 180.0 * (math.atan(((B * 0.5) / A)) / math.pi)
	else:
		tmp = 180.0 * (t_1 / math.pi)
	return tmp
function code(A, B, C)
	t_0 = Float64(Float64(1.0 / B) * Float64(Float64(C - A) - sqrt(Float64((Float64(A - C) ^ 2.0) + (B ^ 2.0)))))
	t_1 = atan(Float64(Float64(Float64(C - A) - hypot(B, Float64(A - C))) / B))
	tmp = 0.0
	if (t_0 <= -0.5)
		tmp = Float64(Float64(180.0 * t_1) / pi);
	elseif (t_0 <= 0.0)
		tmp = Float64(180.0 * Float64(atan(Float64(Float64(B * 0.5) / A)) / pi));
	else
		tmp = Float64(180.0 * Float64(t_1 / pi));
	end
	return tmp
end
function tmp_2 = code(A, B, C)
	t_0 = (1.0 / B) * ((C - A) - sqrt((((A - C) ^ 2.0) + (B ^ 2.0))));
	t_1 = atan((((C - A) - hypot(B, (A - C))) / B));
	tmp = 0.0;
	if (t_0 <= -0.5)
		tmp = (180.0 * t_1) / pi;
	elseif (t_0 <= 0.0)
		tmp = 180.0 * (atan(((B * 0.5) / A)) / pi);
	else
		tmp = 180.0 * (t_1 / pi);
	end
	tmp_2 = tmp;
end
code[A_, B_, C_] := Block[{t$95$0 = N[(N[(1.0 / B), $MachinePrecision] * N[(N[(C - A), $MachinePrecision] - N[Sqrt[N[(N[Power[N[(A - C), $MachinePrecision], 2.0], $MachinePrecision] + N[Power[B, 2.0], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$1 = N[ArcTan[N[(N[(N[(C - A), $MachinePrecision] - N[Sqrt[B ^ 2 + N[(A - C), $MachinePrecision] ^ 2], $MachinePrecision]), $MachinePrecision] / B), $MachinePrecision]], $MachinePrecision]}, If[LessEqual[t$95$0, -0.5], N[(N[(180.0 * t$95$1), $MachinePrecision] / Pi), $MachinePrecision], If[LessEqual[t$95$0, 0.0], N[(180.0 * N[(N[ArcTan[N[(N[(B * 0.5), $MachinePrecision] / A), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision], N[(180.0 * N[(t$95$1 / Pi), $MachinePrecision]), $MachinePrecision]]]]]
\begin{array}{l}

\\
\begin{array}{l}
t_0 := \frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\\
t_1 := \tan^{-1} \left(\frac{\left(C - A\right) - \mathsf{hypot}\left(B, A - C\right)}{B}\right)\\
\mathbf{if}\;t\_0 \leq -0.5:\\
\;\;\;\;\frac{180 \cdot t\_1}{\pi}\\

\mathbf{elif}\;t\_0 \leq 0:\\
\;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{B \cdot 0.5}{A}\right)}{\pi}\\

\mathbf{else}:\\
\;\;\;\;180 \cdot \frac{t\_1}{\pi}\\


\end{array}
\end{array}
Derivation
  1. Split input into 3 regimes
  2. if (*.f64 (/.f64 #s(literal 1 binary64) B) (-.f64 (-.f64 C A) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))) < -0.5

    1. Initial program 67.6%

      \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
    2. Add Preprocessing
    3. Step-by-step derivation
      1. associate-*r/67.6%

        \[\leadsto \color{blue}{\frac{180 \cdot \tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi}} \]
    4. Applied egg-rr93.8%

      \[\leadsto \color{blue}{\frac{180 \cdot \tan^{-1} \left(\frac{\left(C - A\right) - \mathsf{hypot}\left(B, A - C\right)}{B}\right)}{\pi}} \]

    if -0.5 < (*.f64 (/.f64 #s(literal 1 binary64) B) (-.f64 (-.f64 C A) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))) < 0.0

    1. Initial program 15.0%

      \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
    2. Add Preprocessing
    3. Taylor expanded in A around -inf 59.9%

      \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(0.5 \cdot \frac{B}{A}\right)}}{\pi} \]
    4. Step-by-step derivation
      1. associate-*r/59.9%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{0.5 \cdot B}{A}\right)}}{\pi} \]
    5. Simplified59.9%

      \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{0.5 \cdot B}{A}\right)}}{\pi} \]

    if 0.0 < (*.f64 (/.f64 #s(literal 1 binary64) B) (-.f64 (-.f64 C A) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64))))))

    1. Initial program 62.8%

      \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
    2. Step-by-step derivation
      1. associate-*l/62.8%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{1 \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}{B}\right)}}{\pi} \]
      2. *-lft-identity62.8%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\color{blue}{\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}}}{B}\right)}{\pi} \]
      3. +-commutative62.8%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\left(C - A\right) - \sqrt{\color{blue}{{B}^{2} + {\left(A - C\right)}^{2}}}}{B}\right)}{\pi} \]
      4. unpow262.8%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\left(C - A\right) - \sqrt{\color{blue}{B \cdot B} + {\left(A - C\right)}^{2}}}{B}\right)}{\pi} \]
      5. unpow262.8%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\left(C - A\right) - \sqrt{B \cdot B + \color{blue}{\left(A - C\right) \cdot \left(A - C\right)}}}{B}\right)}{\pi} \]
      6. hypot-define90.4%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\left(C - A\right) - \color{blue}{\mathsf{hypot}\left(B, A - C\right)}}{B}\right)}{\pi} \]
    3. Simplified90.4%

      \[\leadsto \color{blue}{180 \cdot \frac{\tan^{-1} \left(\frac{\left(C - A\right) - \mathsf{hypot}\left(B, A - C\right)}{B}\right)}{\pi}} \]
    4. Add Preprocessing
  3. Recombined 3 regimes into one program.
  4. Final simplification88.1%

    \[\leadsto \begin{array}{l} \mathbf{if}\;\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \leq -0.5:\\ \;\;\;\;\frac{180 \cdot \tan^{-1} \left(\frac{\left(C - A\right) - \mathsf{hypot}\left(B, A - C\right)}{B}\right)}{\pi}\\ \mathbf{elif}\;\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \leq 0:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{B \cdot 0.5}{A}\right)}{\pi}\\ \mathbf{else}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{\left(C - A\right) - \mathsf{hypot}\left(B, A - C\right)}{B}\right)}{\pi}\\ \end{array} \]
  5. Add Preprocessing

Alternative 2: 77.7% accurate, 1.9× speedup?

\[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;C \leq -1.05 \cdot 10^{+48}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{C - \mathsf{hypot}\left(C, B\right)}{B}\right)}{\pi}\\ \mathbf{elif}\;C \leq 1.4 \cdot 10^{+59}:\\ \;\;\;\;\frac{180 \cdot \tan^{-1} \left(\frac{A + \mathsf{hypot}\left(A, B\right)}{-B}\right)}{\pi}\\ \mathbf{else}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(-0.5 \cdot \frac{B}{C}\right)}{\pi}\\ \end{array} \end{array} \]
(FPCore (A B C)
 :precision binary64
 (if (<= C -1.05e+48)
   (* 180.0 (/ (atan (/ (- C (hypot C B)) B)) PI))
   (if (<= C 1.4e+59)
     (/ (* 180.0 (atan (/ (+ A (hypot A B)) (- B)))) PI)
     (* 180.0 (/ (atan (* -0.5 (/ B C))) PI)))))
double code(double A, double B, double C) {
	double tmp;
	if (C <= -1.05e+48) {
		tmp = 180.0 * (atan(((C - hypot(C, B)) / B)) / ((double) M_PI));
	} else if (C <= 1.4e+59) {
		tmp = (180.0 * atan(((A + hypot(A, B)) / -B))) / ((double) M_PI);
	} else {
		tmp = 180.0 * (atan((-0.5 * (B / C))) / ((double) M_PI));
	}
	return tmp;
}
public static double code(double A, double B, double C) {
	double tmp;
	if (C <= -1.05e+48) {
		tmp = 180.0 * (Math.atan(((C - Math.hypot(C, B)) / B)) / Math.PI);
	} else if (C <= 1.4e+59) {
		tmp = (180.0 * Math.atan(((A + Math.hypot(A, B)) / -B))) / Math.PI;
	} else {
		tmp = 180.0 * (Math.atan((-0.5 * (B / C))) / Math.PI);
	}
	return tmp;
}
def code(A, B, C):
	tmp = 0
	if C <= -1.05e+48:
		tmp = 180.0 * (math.atan(((C - math.hypot(C, B)) / B)) / math.pi)
	elif C <= 1.4e+59:
		tmp = (180.0 * math.atan(((A + math.hypot(A, B)) / -B))) / math.pi
	else:
		tmp = 180.0 * (math.atan((-0.5 * (B / C))) / math.pi)
	return tmp
function code(A, B, C)
	tmp = 0.0
	if (C <= -1.05e+48)
		tmp = Float64(180.0 * Float64(atan(Float64(Float64(C - hypot(C, B)) / B)) / pi));
	elseif (C <= 1.4e+59)
		tmp = Float64(Float64(180.0 * atan(Float64(Float64(A + hypot(A, B)) / Float64(-B)))) / pi);
	else
		tmp = Float64(180.0 * Float64(atan(Float64(-0.5 * Float64(B / C))) / pi));
	end
	return tmp
end
function tmp_2 = code(A, B, C)
	tmp = 0.0;
	if (C <= -1.05e+48)
		tmp = 180.0 * (atan(((C - hypot(C, B)) / B)) / pi);
	elseif (C <= 1.4e+59)
		tmp = (180.0 * atan(((A + hypot(A, B)) / -B))) / pi;
	else
		tmp = 180.0 * (atan((-0.5 * (B / C))) / pi);
	end
	tmp_2 = tmp;
end
code[A_, B_, C_] := If[LessEqual[C, -1.05e+48], N[(180.0 * N[(N[ArcTan[N[(N[(C - N[Sqrt[C ^ 2 + B ^ 2], $MachinePrecision]), $MachinePrecision] / B), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision], If[LessEqual[C, 1.4e+59], N[(N[(180.0 * N[ArcTan[N[(N[(A + N[Sqrt[A ^ 2 + B ^ 2], $MachinePrecision]), $MachinePrecision] / (-B)), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] / Pi), $MachinePrecision], N[(180.0 * N[(N[ArcTan[N[(-0.5 * N[(B / C), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision]]]
\begin{array}{l}

\\
\begin{array}{l}
\mathbf{if}\;C \leq -1.05 \cdot 10^{+48}:\\
\;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{C - \mathsf{hypot}\left(C, B\right)}{B}\right)}{\pi}\\

\mathbf{elif}\;C \leq 1.4 \cdot 10^{+59}:\\
\;\;\;\;\frac{180 \cdot \tan^{-1} \left(\frac{A + \mathsf{hypot}\left(A, B\right)}{-B}\right)}{\pi}\\

\mathbf{else}:\\
\;\;\;\;180 \cdot \frac{\tan^{-1} \left(-0.5 \cdot \frac{B}{C}\right)}{\pi}\\


\end{array}
\end{array}
Derivation
  1. Split input into 3 regimes
  2. if C < -1.0499999999999999e48

    1. Initial program 83.9%

      \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
    2. Add Preprocessing
    3. Taylor expanded in A around 0 83.9%

      \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{C - \sqrt{{B}^{2} + {C}^{2}}}{B}\right)}}{\pi} \]
    4. Step-by-step derivation
      1. +-commutative83.9%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{C - \sqrt{\color{blue}{{C}^{2} + {B}^{2}}}}{B}\right)}{\pi} \]
      2. unpow283.9%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{C - \sqrt{\color{blue}{C \cdot C} + {B}^{2}}}{B}\right)}{\pi} \]
      3. unpow283.9%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{C - \sqrt{C \cdot C + \color{blue}{B \cdot B}}}{B}\right)}{\pi} \]
      4. hypot-define98.0%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{C - \color{blue}{\mathsf{hypot}\left(C, B\right)}}{B}\right)}{\pi} \]
    5. Simplified98.0%

      \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{C - \mathsf{hypot}\left(C, B\right)}{B}\right)}}{\pi} \]

    if -1.0499999999999999e48 < C < 1.3999999999999999e59

    1. Initial program 62.3%

      \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
    2. Add Preprocessing
    3. Step-by-step derivation
      1. associate-*r/62.3%

        \[\leadsto \color{blue}{\frac{180 \cdot \tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi}} \]
    4. Applied egg-rr85.2%

      \[\leadsto \color{blue}{\frac{180 \cdot \tan^{-1} \left(\frac{\left(C - A\right) - \mathsf{hypot}\left(B, A - C\right)}{B}\right)}{\pi}} \]
    5. Taylor expanded in C around 0 57.9%

      \[\leadsto \frac{180 \cdot \tan^{-1} \color{blue}{\left(-1 \cdot \frac{A + \sqrt{{A}^{2} + {B}^{2}}}{B}\right)}}{\pi} \]
    6. Step-by-step derivation
      1. mul-1-neg57.9%

        \[\leadsto \frac{180 \cdot \tan^{-1} \color{blue}{\left(-\frac{A + \sqrt{{A}^{2} + {B}^{2}}}{B}\right)}}{\pi} \]
      2. distribute-neg-frac257.9%

        \[\leadsto \frac{180 \cdot \tan^{-1} \color{blue}{\left(\frac{A + \sqrt{{A}^{2} + {B}^{2}}}{-B}\right)}}{\pi} \]
      3. unpow257.9%

        \[\leadsto \frac{180 \cdot \tan^{-1} \left(\frac{A + \sqrt{\color{blue}{A \cdot A} + {B}^{2}}}{-B}\right)}{\pi} \]
      4. unpow257.9%

        \[\leadsto \frac{180 \cdot \tan^{-1} \left(\frac{A + \sqrt{A \cdot A + \color{blue}{B \cdot B}}}{-B}\right)}{\pi} \]
      5. hypot-define80.6%

        \[\leadsto \frac{180 \cdot \tan^{-1} \left(\frac{A + \color{blue}{\mathsf{hypot}\left(A, B\right)}}{-B}\right)}{\pi} \]
    7. Simplified80.6%

      \[\leadsto \frac{180 \cdot \tan^{-1} \color{blue}{\left(\frac{A + \mathsf{hypot}\left(A, B\right)}{-B}\right)}}{\pi} \]

    if 1.3999999999999999e59 < C

    1. Initial program 23.3%

      \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
    2. Add Preprocessing
    3. Taylor expanded in A around 0 17.8%

      \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{C - \sqrt{{B}^{2} + {C}^{2}}}{B}\right)}}{\pi} \]
    4. Step-by-step derivation
      1. +-commutative17.8%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{C - \sqrt{\color{blue}{{C}^{2} + {B}^{2}}}}{B}\right)}{\pi} \]
      2. unpow217.8%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{C - \sqrt{\color{blue}{C \cdot C} + {B}^{2}}}{B}\right)}{\pi} \]
      3. unpow217.8%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{C - \sqrt{C \cdot C + \color{blue}{B \cdot B}}}{B}\right)}{\pi} \]
      4. hypot-define47.5%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{C - \color{blue}{\mathsf{hypot}\left(C, B\right)}}{B}\right)}{\pi} \]
    5. Simplified47.5%

      \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{C - \mathsf{hypot}\left(C, B\right)}{B}\right)}}{\pi} \]
    6. Taylor expanded in C around inf 74.5%

      \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(-0.5 \cdot \frac{B}{C}\right)}}{\pi} \]
  3. Recombined 3 regimes into one program.
  4. Add Preprocessing

Alternative 3: 77.7% accurate, 1.9× speedup?

\[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;C \leq -8.5 \cdot 10^{+47}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{C - \mathsf{hypot}\left(C, B\right)}{B}\right)}{\pi}\\ \mathbf{elif}\;C \leq 7.2 \cdot 10^{+56}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{A + \mathsf{hypot}\left(A, B\right)}{-B}\right)}{\pi}\\ \mathbf{else}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(-0.5 \cdot \frac{B}{C}\right)}{\pi}\\ \end{array} \end{array} \]
(FPCore (A B C)
 :precision binary64
 (if (<= C -8.5e+47)
   (* 180.0 (/ (atan (/ (- C (hypot C B)) B)) PI))
   (if (<= C 7.2e+56)
     (* 180.0 (/ (atan (/ (+ A (hypot A B)) (- B))) PI))
     (* 180.0 (/ (atan (* -0.5 (/ B C))) PI)))))
double code(double A, double B, double C) {
	double tmp;
	if (C <= -8.5e+47) {
		tmp = 180.0 * (atan(((C - hypot(C, B)) / B)) / ((double) M_PI));
	} else if (C <= 7.2e+56) {
		tmp = 180.0 * (atan(((A + hypot(A, B)) / -B)) / ((double) M_PI));
	} else {
		tmp = 180.0 * (atan((-0.5 * (B / C))) / ((double) M_PI));
	}
	return tmp;
}
public static double code(double A, double B, double C) {
	double tmp;
	if (C <= -8.5e+47) {
		tmp = 180.0 * (Math.atan(((C - Math.hypot(C, B)) / B)) / Math.PI);
	} else if (C <= 7.2e+56) {
		tmp = 180.0 * (Math.atan(((A + Math.hypot(A, B)) / -B)) / Math.PI);
	} else {
		tmp = 180.0 * (Math.atan((-0.5 * (B / C))) / Math.PI);
	}
	return tmp;
}
def code(A, B, C):
	tmp = 0
	if C <= -8.5e+47:
		tmp = 180.0 * (math.atan(((C - math.hypot(C, B)) / B)) / math.pi)
	elif C <= 7.2e+56:
		tmp = 180.0 * (math.atan(((A + math.hypot(A, B)) / -B)) / math.pi)
	else:
		tmp = 180.0 * (math.atan((-0.5 * (B / C))) / math.pi)
	return tmp
function code(A, B, C)
	tmp = 0.0
	if (C <= -8.5e+47)
		tmp = Float64(180.0 * Float64(atan(Float64(Float64(C - hypot(C, B)) / B)) / pi));
	elseif (C <= 7.2e+56)
		tmp = Float64(180.0 * Float64(atan(Float64(Float64(A + hypot(A, B)) / Float64(-B))) / pi));
	else
		tmp = Float64(180.0 * Float64(atan(Float64(-0.5 * Float64(B / C))) / pi));
	end
	return tmp
end
function tmp_2 = code(A, B, C)
	tmp = 0.0;
	if (C <= -8.5e+47)
		tmp = 180.0 * (atan(((C - hypot(C, B)) / B)) / pi);
	elseif (C <= 7.2e+56)
		tmp = 180.0 * (atan(((A + hypot(A, B)) / -B)) / pi);
	else
		tmp = 180.0 * (atan((-0.5 * (B / C))) / pi);
	end
	tmp_2 = tmp;
end
code[A_, B_, C_] := If[LessEqual[C, -8.5e+47], N[(180.0 * N[(N[ArcTan[N[(N[(C - N[Sqrt[C ^ 2 + B ^ 2], $MachinePrecision]), $MachinePrecision] / B), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision], If[LessEqual[C, 7.2e+56], N[(180.0 * N[(N[ArcTan[N[(N[(A + N[Sqrt[A ^ 2 + B ^ 2], $MachinePrecision]), $MachinePrecision] / (-B)), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision], N[(180.0 * N[(N[ArcTan[N[(-0.5 * N[(B / C), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision]]]
\begin{array}{l}

\\
\begin{array}{l}
\mathbf{if}\;C \leq -8.5 \cdot 10^{+47}:\\
\;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{C - \mathsf{hypot}\left(C, B\right)}{B}\right)}{\pi}\\

\mathbf{elif}\;C \leq 7.2 \cdot 10^{+56}:\\
\;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{A + \mathsf{hypot}\left(A, B\right)}{-B}\right)}{\pi}\\

\mathbf{else}:\\
\;\;\;\;180 \cdot \frac{\tan^{-1} \left(-0.5 \cdot \frac{B}{C}\right)}{\pi}\\


\end{array}
\end{array}
Derivation
  1. Split input into 3 regimes
  2. if C < -8.5000000000000008e47

    1. Initial program 83.9%

      \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
    2. Add Preprocessing
    3. Taylor expanded in A around 0 83.9%

      \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{C - \sqrt{{B}^{2} + {C}^{2}}}{B}\right)}}{\pi} \]
    4. Step-by-step derivation
      1. +-commutative83.9%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{C - \sqrt{\color{blue}{{C}^{2} + {B}^{2}}}}{B}\right)}{\pi} \]
      2. unpow283.9%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{C - \sqrt{\color{blue}{C \cdot C} + {B}^{2}}}{B}\right)}{\pi} \]
      3. unpow283.9%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{C - \sqrt{C \cdot C + \color{blue}{B \cdot B}}}{B}\right)}{\pi} \]
      4. hypot-define98.0%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{C - \color{blue}{\mathsf{hypot}\left(C, B\right)}}{B}\right)}{\pi} \]
    5. Simplified98.0%

      \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{C - \mathsf{hypot}\left(C, B\right)}{B}\right)}}{\pi} \]

    if -8.5000000000000008e47 < C < 7.19999999999999996e56

    1. Initial program 62.3%

      \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
    2. Add Preprocessing
    3. Taylor expanded in C around 0 57.9%

      \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(-1 \cdot \frac{A + \sqrt{{A}^{2} + {B}^{2}}}{B}\right)}}{\pi} \]
    4. Step-by-step derivation
      1. associate-*r/57.9%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{-1 \cdot \left(A + \sqrt{{A}^{2} + {B}^{2}}\right)}{B}\right)}}{\pi} \]
      2. mul-1-neg57.9%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\color{blue}{-\left(A + \sqrt{{A}^{2} + {B}^{2}}\right)}}{B}\right)}{\pi} \]
      3. unpow257.9%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{-\left(A + \sqrt{\color{blue}{A \cdot A} + {B}^{2}}\right)}{B}\right)}{\pi} \]
      4. unpow257.9%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{-\left(A + \sqrt{A \cdot A + \color{blue}{B \cdot B}}\right)}{B}\right)}{\pi} \]
      5. hypot-define80.6%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{-\left(A + \color{blue}{\mathsf{hypot}\left(A, B\right)}\right)}{B}\right)}{\pi} \]
    5. Simplified80.6%

      \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{-\left(A + \mathsf{hypot}\left(A, B\right)\right)}{B}\right)}}{\pi} \]

    if 7.19999999999999996e56 < C

    1. Initial program 23.3%

      \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
    2. Add Preprocessing
    3. Taylor expanded in A around 0 17.8%

      \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{C - \sqrt{{B}^{2} + {C}^{2}}}{B}\right)}}{\pi} \]
    4. Step-by-step derivation
      1. +-commutative17.8%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{C - \sqrt{\color{blue}{{C}^{2} + {B}^{2}}}}{B}\right)}{\pi} \]
      2. unpow217.8%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{C - \sqrt{\color{blue}{C \cdot C} + {B}^{2}}}{B}\right)}{\pi} \]
      3. unpow217.8%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{C - \sqrt{C \cdot C + \color{blue}{B \cdot B}}}{B}\right)}{\pi} \]
      4. hypot-define47.5%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{C - \color{blue}{\mathsf{hypot}\left(C, B\right)}}{B}\right)}{\pi} \]
    5. Simplified47.5%

      \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{C - \mathsf{hypot}\left(C, B\right)}{B}\right)}}{\pi} \]
    6. Taylor expanded in C around inf 74.5%

      \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(-0.5 \cdot \frac{B}{C}\right)}}{\pi} \]
  3. Recombined 3 regimes into one program.
  4. Final simplification82.6%

    \[\leadsto \begin{array}{l} \mathbf{if}\;C \leq -8.5 \cdot 10^{+47}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{C - \mathsf{hypot}\left(C, B\right)}{B}\right)}{\pi}\\ \mathbf{elif}\;C \leq 7.2 \cdot 10^{+56}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{A + \mathsf{hypot}\left(A, B\right)}{-B}\right)}{\pi}\\ \mathbf{else}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(-0.5 \cdot \frac{B}{C}\right)}{\pi}\\ \end{array} \]
  5. Add Preprocessing

Alternative 4: 75.3% accurate, 1.9× speedup?

\[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;A \leq -4.5 \cdot 10^{+124}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{B \cdot 0.5}{A}\right)}{\pi}\\ \mathbf{elif}\;A \leq 9.5 \cdot 10^{-55}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{C - \mathsf{hypot}\left(C, B\right)}{B}\right)}{\pi}\\ \mathbf{else}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(1 + \frac{C - A}{B}\right)}{\pi}\\ \end{array} \end{array} \]
(FPCore (A B C)
 :precision binary64
 (if (<= A -4.5e+124)
   (* 180.0 (/ (atan (/ (* B 0.5) A)) PI))
   (if (<= A 9.5e-55)
     (* 180.0 (/ (atan (/ (- C (hypot C B)) B)) PI))
     (* 180.0 (/ (atan (+ 1.0 (/ (- C A) B))) PI)))))
double code(double A, double B, double C) {
	double tmp;
	if (A <= -4.5e+124) {
		tmp = 180.0 * (atan(((B * 0.5) / A)) / ((double) M_PI));
	} else if (A <= 9.5e-55) {
		tmp = 180.0 * (atan(((C - hypot(C, B)) / B)) / ((double) M_PI));
	} else {
		tmp = 180.0 * (atan((1.0 + ((C - A) / B))) / ((double) M_PI));
	}
	return tmp;
}
public static double code(double A, double B, double C) {
	double tmp;
	if (A <= -4.5e+124) {
		tmp = 180.0 * (Math.atan(((B * 0.5) / A)) / Math.PI);
	} else if (A <= 9.5e-55) {
		tmp = 180.0 * (Math.atan(((C - Math.hypot(C, B)) / B)) / Math.PI);
	} else {
		tmp = 180.0 * (Math.atan((1.0 + ((C - A) / B))) / Math.PI);
	}
	return tmp;
}
def code(A, B, C):
	tmp = 0
	if A <= -4.5e+124:
		tmp = 180.0 * (math.atan(((B * 0.5) / A)) / math.pi)
	elif A <= 9.5e-55:
		tmp = 180.0 * (math.atan(((C - math.hypot(C, B)) / B)) / math.pi)
	else:
		tmp = 180.0 * (math.atan((1.0 + ((C - A) / B))) / math.pi)
	return tmp
function code(A, B, C)
	tmp = 0.0
	if (A <= -4.5e+124)
		tmp = Float64(180.0 * Float64(atan(Float64(Float64(B * 0.5) / A)) / pi));
	elseif (A <= 9.5e-55)
		tmp = Float64(180.0 * Float64(atan(Float64(Float64(C - hypot(C, B)) / B)) / pi));
	else
		tmp = Float64(180.0 * Float64(atan(Float64(1.0 + Float64(Float64(C - A) / B))) / pi));
	end
	return tmp
end
function tmp_2 = code(A, B, C)
	tmp = 0.0;
	if (A <= -4.5e+124)
		tmp = 180.0 * (atan(((B * 0.5) / A)) / pi);
	elseif (A <= 9.5e-55)
		tmp = 180.0 * (atan(((C - hypot(C, B)) / B)) / pi);
	else
		tmp = 180.0 * (atan((1.0 + ((C - A) / B))) / pi);
	end
	tmp_2 = tmp;
end
code[A_, B_, C_] := If[LessEqual[A, -4.5e+124], N[(180.0 * N[(N[ArcTan[N[(N[(B * 0.5), $MachinePrecision] / A), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision], If[LessEqual[A, 9.5e-55], N[(180.0 * N[(N[ArcTan[N[(N[(C - N[Sqrt[C ^ 2 + B ^ 2], $MachinePrecision]), $MachinePrecision] / B), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision], N[(180.0 * N[(N[ArcTan[N[(1.0 + N[(N[(C - A), $MachinePrecision] / B), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision]]]
\begin{array}{l}

\\
\begin{array}{l}
\mathbf{if}\;A \leq -4.5 \cdot 10^{+124}:\\
\;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{B \cdot 0.5}{A}\right)}{\pi}\\

\mathbf{elif}\;A \leq 9.5 \cdot 10^{-55}:\\
\;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{C - \mathsf{hypot}\left(C, B\right)}{B}\right)}{\pi}\\

\mathbf{else}:\\
\;\;\;\;180 \cdot \frac{\tan^{-1} \left(1 + \frac{C - A}{B}\right)}{\pi}\\


\end{array}
\end{array}
Derivation
  1. Split input into 3 regimes
  2. if A < -4.5000000000000004e124

    1. Initial program 11.3%

      \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
    2. Add Preprocessing
    3. Taylor expanded in A around -inf 79.9%

      \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(0.5 \cdot \frac{B}{A}\right)}}{\pi} \]
    4. Step-by-step derivation
      1. associate-*r/79.9%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{0.5 \cdot B}{A}\right)}}{\pi} \]
    5. Simplified79.9%

      \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{0.5 \cdot B}{A}\right)}}{\pi} \]

    if -4.5000000000000004e124 < A < 9.5000000000000006e-55

    1. Initial program 57.6%

      \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
    2. Add Preprocessing
    3. Taylor expanded in A around 0 54.8%

      \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{C - \sqrt{{B}^{2} + {C}^{2}}}{B}\right)}}{\pi} \]
    4. Step-by-step derivation
      1. +-commutative54.8%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{C - \sqrt{\color{blue}{{C}^{2} + {B}^{2}}}}{B}\right)}{\pi} \]
      2. unpow254.8%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{C - \sqrt{\color{blue}{C \cdot C} + {B}^{2}}}{B}\right)}{\pi} \]
      3. unpow254.8%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{C - \sqrt{C \cdot C + \color{blue}{B \cdot B}}}{B}\right)}{\pi} \]
      4. hypot-define78.3%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{C - \color{blue}{\mathsf{hypot}\left(C, B\right)}}{B}\right)}{\pi} \]
    5. Simplified78.3%

      \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{C - \mathsf{hypot}\left(C, B\right)}{B}\right)}}{\pi} \]

    if 9.5000000000000006e-55 < A

    1. Initial program 75.8%

      \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
    2. Add Preprocessing
    3. Taylor expanded in B around -inf 79.9%

      \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\left(1 + \frac{C}{B}\right) - \frac{A}{B}\right)}}{\pi} \]
    4. Step-by-step derivation
      1. associate--l+79.9%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(1 + \left(\frac{C}{B} - \frac{A}{B}\right)\right)}}{\pi} \]
      2. div-sub82.2%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \color{blue}{\frac{C - A}{B}}\right)}{\pi} \]
    5. Simplified82.2%

      \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(1 + \frac{C - A}{B}\right)}}{\pi} \]
  3. Recombined 3 regimes into one program.
  4. Final simplification79.7%

    \[\leadsto \begin{array}{l} \mathbf{if}\;A \leq -4.5 \cdot 10^{+124}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{B \cdot 0.5}{A}\right)}{\pi}\\ \mathbf{elif}\;A \leq 9.5 \cdot 10^{-55}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{C - \mathsf{hypot}\left(C, B\right)}{B}\right)}{\pi}\\ \mathbf{else}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(1 + \frac{C - A}{B}\right)}{\pi}\\ \end{array} \]
  5. Add Preprocessing

Alternative 5: 81.3% accurate, 1.9× speedup?

\[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;C \leq 4 \cdot 10^{+58}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{\left(C - A\right) - \mathsf{hypot}\left(B, A - C\right)}{B}\right)}{\pi}\\ \mathbf{else}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(-0.5 \cdot \frac{B}{C}\right)}{\pi}\\ \end{array} \end{array} \]
(FPCore (A B C)
 :precision binary64
 (if (<= C 4e+58)
   (* 180.0 (/ (atan (/ (- (- C A) (hypot B (- A C))) B)) PI))
   (* 180.0 (/ (atan (* -0.5 (/ B C))) PI))))
double code(double A, double B, double C) {
	double tmp;
	if (C <= 4e+58) {
		tmp = 180.0 * (atan((((C - A) - hypot(B, (A - C))) / B)) / ((double) M_PI));
	} else {
		tmp = 180.0 * (atan((-0.5 * (B / C))) / ((double) M_PI));
	}
	return tmp;
}
public static double code(double A, double B, double C) {
	double tmp;
	if (C <= 4e+58) {
		tmp = 180.0 * (Math.atan((((C - A) - Math.hypot(B, (A - C))) / B)) / Math.PI);
	} else {
		tmp = 180.0 * (Math.atan((-0.5 * (B / C))) / Math.PI);
	}
	return tmp;
}
def code(A, B, C):
	tmp = 0
	if C <= 4e+58:
		tmp = 180.0 * (math.atan((((C - A) - math.hypot(B, (A - C))) / B)) / math.pi)
	else:
		tmp = 180.0 * (math.atan((-0.5 * (B / C))) / math.pi)
	return tmp
function code(A, B, C)
	tmp = 0.0
	if (C <= 4e+58)
		tmp = Float64(180.0 * Float64(atan(Float64(Float64(Float64(C - A) - hypot(B, Float64(A - C))) / B)) / pi));
	else
		tmp = Float64(180.0 * Float64(atan(Float64(-0.5 * Float64(B / C))) / pi));
	end
	return tmp
end
function tmp_2 = code(A, B, C)
	tmp = 0.0;
	if (C <= 4e+58)
		tmp = 180.0 * (atan((((C - A) - hypot(B, (A - C))) / B)) / pi);
	else
		tmp = 180.0 * (atan((-0.5 * (B / C))) / pi);
	end
	tmp_2 = tmp;
end
code[A_, B_, C_] := If[LessEqual[C, 4e+58], N[(180.0 * N[(N[ArcTan[N[(N[(N[(C - A), $MachinePrecision] - N[Sqrt[B ^ 2 + N[(A - C), $MachinePrecision] ^ 2], $MachinePrecision]), $MachinePrecision] / B), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision], N[(180.0 * N[(N[ArcTan[N[(-0.5 * N[(B / C), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision]]
\begin{array}{l}

\\
\begin{array}{l}
\mathbf{if}\;C \leq 4 \cdot 10^{+58}:\\
\;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{\left(C - A\right) - \mathsf{hypot}\left(B, A - C\right)}{B}\right)}{\pi}\\

\mathbf{else}:\\
\;\;\;\;180 \cdot \frac{\tan^{-1} \left(-0.5 \cdot \frac{B}{C}\right)}{\pi}\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if C < 3.99999999999999978e58

    1. Initial program 67.0%

      \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
    2. Step-by-step derivation
      1. associate-*l/67.0%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{1 \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}{B}\right)}}{\pi} \]
      2. *-lft-identity67.0%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\color{blue}{\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}}}{B}\right)}{\pi} \]
      3. +-commutative67.0%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\left(C - A\right) - \sqrt{\color{blue}{{B}^{2} + {\left(A - C\right)}^{2}}}}{B}\right)}{\pi} \]
      4. unpow267.0%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\left(C - A\right) - \sqrt{\color{blue}{B \cdot B} + {\left(A - C\right)}^{2}}}{B}\right)}{\pi} \]
      5. unpow267.0%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\left(C - A\right) - \sqrt{B \cdot B + \color{blue}{\left(A - C\right) \cdot \left(A - C\right)}}}{B}\right)}{\pi} \]
      6. hypot-define88.0%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\left(C - A\right) - \color{blue}{\mathsf{hypot}\left(B, A - C\right)}}{B}\right)}{\pi} \]
    3. Simplified88.0%

      \[\leadsto \color{blue}{180 \cdot \frac{\tan^{-1} \left(\frac{\left(C - A\right) - \mathsf{hypot}\left(B, A - C\right)}{B}\right)}{\pi}} \]
    4. Add Preprocessing

    if 3.99999999999999978e58 < C

    1. Initial program 23.3%

      \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
    2. Add Preprocessing
    3. Taylor expanded in A around 0 17.8%

      \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{C - \sqrt{{B}^{2} + {C}^{2}}}{B}\right)}}{\pi} \]
    4. Step-by-step derivation
      1. +-commutative17.8%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{C - \sqrt{\color{blue}{{C}^{2} + {B}^{2}}}}{B}\right)}{\pi} \]
      2. unpow217.8%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{C - \sqrt{\color{blue}{C \cdot C} + {B}^{2}}}{B}\right)}{\pi} \]
      3. unpow217.8%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{C - \sqrt{C \cdot C + \color{blue}{B \cdot B}}}{B}\right)}{\pi} \]
      4. hypot-define47.5%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{C - \color{blue}{\mathsf{hypot}\left(C, B\right)}}{B}\right)}{\pi} \]
    5. Simplified47.5%

      \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{C - \mathsf{hypot}\left(C, B\right)}{B}\right)}}{\pi} \]
    6. Taylor expanded in C around inf 74.5%

      \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(-0.5 \cdot \frac{B}{C}\right)}}{\pi} \]
  3. Recombined 2 regimes into one program.
  4. Add Preprocessing

Alternative 6: 81.3% accurate, 1.9× speedup?

\[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;A \leq -4 \cdot 10^{+124}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{B \cdot 0.5}{A}\right)}{\pi}\\ \mathbf{else}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{C - \left(A + \mathsf{hypot}\left(B, A - C\right)\right)}{B}\right)}{\pi}\\ \end{array} \end{array} \]
(FPCore (A B C)
 :precision binary64
 (if (<= A -4e+124)
   (* 180.0 (/ (atan (/ (* B 0.5) A)) PI))
   (* 180.0 (/ (atan (/ (- C (+ A (hypot B (- A C)))) B)) PI))))
double code(double A, double B, double C) {
	double tmp;
	if (A <= -4e+124) {
		tmp = 180.0 * (atan(((B * 0.5) / A)) / ((double) M_PI));
	} else {
		tmp = 180.0 * (atan(((C - (A + hypot(B, (A - C)))) / B)) / ((double) M_PI));
	}
	return tmp;
}
public static double code(double A, double B, double C) {
	double tmp;
	if (A <= -4e+124) {
		tmp = 180.0 * (Math.atan(((B * 0.5) / A)) / Math.PI);
	} else {
		tmp = 180.0 * (Math.atan(((C - (A + Math.hypot(B, (A - C)))) / B)) / Math.PI);
	}
	return tmp;
}
def code(A, B, C):
	tmp = 0
	if A <= -4e+124:
		tmp = 180.0 * (math.atan(((B * 0.5) / A)) / math.pi)
	else:
		tmp = 180.0 * (math.atan(((C - (A + math.hypot(B, (A - C)))) / B)) / math.pi)
	return tmp
function code(A, B, C)
	tmp = 0.0
	if (A <= -4e+124)
		tmp = Float64(180.0 * Float64(atan(Float64(Float64(B * 0.5) / A)) / pi));
	else
		tmp = Float64(180.0 * Float64(atan(Float64(Float64(C - Float64(A + hypot(B, Float64(A - C)))) / B)) / pi));
	end
	return tmp
end
function tmp_2 = code(A, B, C)
	tmp = 0.0;
	if (A <= -4e+124)
		tmp = 180.0 * (atan(((B * 0.5) / A)) / pi);
	else
		tmp = 180.0 * (atan(((C - (A + hypot(B, (A - C)))) / B)) / pi);
	end
	tmp_2 = tmp;
end
code[A_, B_, C_] := If[LessEqual[A, -4e+124], N[(180.0 * N[(N[ArcTan[N[(N[(B * 0.5), $MachinePrecision] / A), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision], N[(180.0 * N[(N[ArcTan[N[(N[(C - N[(A + N[Sqrt[B ^ 2 + N[(A - C), $MachinePrecision] ^ 2], $MachinePrecision]), $MachinePrecision]), $MachinePrecision] / B), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision]]
\begin{array}{l}

\\
\begin{array}{l}
\mathbf{if}\;A \leq -4 \cdot 10^{+124}:\\
\;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{B \cdot 0.5}{A}\right)}{\pi}\\

\mathbf{else}:\\
\;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{C - \left(A + \mathsf{hypot}\left(B, A - C\right)\right)}{B}\right)}{\pi}\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if A < -3.99999999999999979e124

    1. Initial program 11.3%

      \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
    2. Add Preprocessing
    3. Taylor expanded in A around -inf 79.9%

      \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(0.5 \cdot \frac{B}{A}\right)}}{\pi} \]
    4. Step-by-step derivation
      1. associate-*r/79.9%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{0.5 \cdot B}{A}\right)}}{\pi} \]
    5. Simplified79.9%

      \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{0.5 \cdot B}{A}\right)}}{\pi} \]

    if -3.99999999999999979e124 < A

    1. Initial program 64.4%

      \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
    2. Step-by-step derivation
      1. Simplified84.8%

        \[\leadsto \color{blue}{180 \cdot \frac{\tan^{-1} \left(\frac{C - \left(A + \mathsf{hypot}\left(B, A - C\right)\right)}{B}\right)}{\pi}} \]
      2. Add Preprocessing
    3. Recombined 2 regimes into one program.
    4. Final simplification84.3%

      \[\leadsto \begin{array}{l} \mathbf{if}\;A \leq -4 \cdot 10^{+124}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{B \cdot 0.5}{A}\right)}{\pi}\\ \mathbf{else}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{C - \left(A + \mathsf{hypot}\left(B, A - C\right)\right)}{B}\right)}{\pi}\\ \end{array} \]
    5. Add Preprocessing

    Alternative 7: 56.9% accurate, 3.2× speedup?

    \[\begin{array}{l} \\ \begin{array}{l} t_0 := \frac{180 \cdot \tan^{-1} \left(1 + \frac{C}{B}\right)}{\pi}\\ \mathbf{if}\;A \leq -1260000:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{B \cdot 0.5}{A}\right)}{\pi}\\ \mathbf{elif}\;A \leq -1.2 \cdot 10^{-181}:\\ \;\;\;\;t\_0\\ \mathbf{elif}\;A \leq 1.1 \cdot 10^{-189}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{C - B}{B}\right)}{\pi}\\ \mathbf{elif}\;A \leq 380:\\ \;\;\;\;t\_0\\ \mathbf{else}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{A \cdot -2}{B}\right)}{\pi}\\ \end{array} \end{array} \]
    (FPCore (A B C)
     :precision binary64
     (let* ((t_0 (/ (* 180.0 (atan (+ 1.0 (/ C B)))) PI)))
       (if (<= A -1260000.0)
         (* 180.0 (/ (atan (/ (* B 0.5) A)) PI))
         (if (<= A -1.2e-181)
           t_0
           (if (<= A 1.1e-189)
             (* 180.0 (/ (atan (/ (- C B) B)) PI))
             (if (<= A 380.0) t_0 (* 180.0 (/ (atan (/ (* A -2.0) B)) PI))))))))
    double code(double A, double B, double C) {
    	double t_0 = (180.0 * atan((1.0 + (C / B)))) / ((double) M_PI);
    	double tmp;
    	if (A <= -1260000.0) {
    		tmp = 180.0 * (atan(((B * 0.5) / A)) / ((double) M_PI));
    	} else if (A <= -1.2e-181) {
    		tmp = t_0;
    	} else if (A <= 1.1e-189) {
    		tmp = 180.0 * (atan(((C - B) / B)) / ((double) M_PI));
    	} else if (A <= 380.0) {
    		tmp = t_0;
    	} else {
    		tmp = 180.0 * (atan(((A * -2.0) / B)) / ((double) M_PI));
    	}
    	return tmp;
    }
    
    public static double code(double A, double B, double C) {
    	double t_0 = (180.0 * Math.atan((1.0 + (C / B)))) / Math.PI;
    	double tmp;
    	if (A <= -1260000.0) {
    		tmp = 180.0 * (Math.atan(((B * 0.5) / A)) / Math.PI);
    	} else if (A <= -1.2e-181) {
    		tmp = t_0;
    	} else if (A <= 1.1e-189) {
    		tmp = 180.0 * (Math.atan(((C - B) / B)) / Math.PI);
    	} else if (A <= 380.0) {
    		tmp = t_0;
    	} else {
    		tmp = 180.0 * (Math.atan(((A * -2.0) / B)) / Math.PI);
    	}
    	return tmp;
    }
    
    def code(A, B, C):
    	t_0 = (180.0 * math.atan((1.0 + (C / B)))) / math.pi
    	tmp = 0
    	if A <= -1260000.0:
    		tmp = 180.0 * (math.atan(((B * 0.5) / A)) / math.pi)
    	elif A <= -1.2e-181:
    		tmp = t_0
    	elif A <= 1.1e-189:
    		tmp = 180.0 * (math.atan(((C - B) / B)) / math.pi)
    	elif A <= 380.0:
    		tmp = t_0
    	else:
    		tmp = 180.0 * (math.atan(((A * -2.0) / B)) / math.pi)
    	return tmp
    
    function code(A, B, C)
    	t_0 = Float64(Float64(180.0 * atan(Float64(1.0 + Float64(C / B)))) / pi)
    	tmp = 0.0
    	if (A <= -1260000.0)
    		tmp = Float64(180.0 * Float64(atan(Float64(Float64(B * 0.5) / A)) / pi));
    	elseif (A <= -1.2e-181)
    		tmp = t_0;
    	elseif (A <= 1.1e-189)
    		tmp = Float64(180.0 * Float64(atan(Float64(Float64(C - B) / B)) / pi));
    	elseif (A <= 380.0)
    		tmp = t_0;
    	else
    		tmp = Float64(180.0 * Float64(atan(Float64(Float64(A * -2.0) / B)) / pi));
    	end
    	return tmp
    end
    
    function tmp_2 = code(A, B, C)
    	t_0 = (180.0 * atan((1.0 + (C / B)))) / pi;
    	tmp = 0.0;
    	if (A <= -1260000.0)
    		tmp = 180.0 * (atan(((B * 0.5) / A)) / pi);
    	elseif (A <= -1.2e-181)
    		tmp = t_0;
    	elseif (A <= 1.1e-189)
    		tmp = 180.0 * (atan(((C - B) / B)) / pi);
    	elseif (A <= 380.0)
    		tmp = t_0;
    	else
    		tmp = 180.0 * (atan(((A * -2.0) / B)) / pi);
    	end
    	tmp_2 = tmp;
    end
    
    code[A_, B_, C_] := Block[{t$95$0 = N[(N[(180.0 * N[ArcTan[N[(1.0 + N[(C / B), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] / Pi), $MachinePrecision]}, If[LessEqual[A, -1260000.0], N[(180.0 * N[(N[ArcTan[N[(N[(B * 0.5), $MachinePrecision] / A), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision], If[LessEqual[A, -1.2e-181], t$95$0, If[LessEqual[A, 1.1e-189], N[(180.0 * N[(N[ArcTan[N[(N[(C - B), $MachinePrecision] / B), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision], If[LessEqual[A, 380.0], t$95$0, N[(180.0 * N[(N[ArcTan[N[(N[(A * -2.0), $MachinePrecision] / B), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision]]]]]]
    
    \begin{array}{l}
    
    \\
    \begin{array}{l}
    t_0 := \frac{180 \cdot \tan^{-1} \left(1 + \frac{C}{B}\right)}{\pi}\\
    \mathbf{if}\;A \leq -1260000:\\
    \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{B \cdot 0.5}{A}\right)}{\pi}\\
    
    \mathbf{elif}\;A \leq -1.2 \cdot 10^{-181}:\\
    \;\;\;\;t\_0\\
    
    \mathbf{elif}\;A \leq 1.1 \cdot 10^{-189}:\\
    \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{C - B}{B}\right)}{\pi}\\
    
    \mathbf{elif}\;A \leq 380:\\
    \;\;\;\;t\_0\\
    
    \mathbf{else}:\\
    \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{A \cdot -2}{B}\right)}{\pi}\\
    
    
    \end{array}
    \end{array}
    
    Derivation
    1. Split input into 4 regimes
    2. if A < -1.26e6

      1. Initial program 23.3%

        \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
      2. Add Preprocessing
      3. Taylor expanded in A around -inf 63.2%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(0.5 \cdot \frac{B}{A}\right)}}{\pi} \]
      4. Step-by-step derivation
        1. associate-*r/63.2%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{0.5 \cdot B}{A}\right)}}{\pi} \]
      5. Simplified63.2%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{0.5 \cdot B}{A}\right)}}{\pi} \]

      if -1.26e6 < A < -1.2000000000000001e-181 or 1.1000000000000001e-189 < A < 380

      1. Initial program 67.8%

        \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
      2. Add Preprocessing
      3. Step-by-step derivation
        1. associate-*r/67.8%

          \[\leadsto \color{blue}{\frac{180 \cdot \tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi}} \]
      4. Applied egg-rr83.5%

        \[\leadsto \color{blue}{\frac{180 \cdot \tan^{-1} \left(\frac{\left(C - A\right) - \mathsf{hypot}\left(B, A - C\right)}{B}\right)}{\pi}} \]
      5. Taylor expanded in B around -inf 72.0%

        \[\leadsto \frac{180 \cdot \tan^{-1} \color{blue}{\left(\left(1 + \frac{C}{B}\right) - \frac{A}{B}\right)}}{\pi} \]
      6. Step-by-step derivation
        1. associate--l+72.0%

          \[\leadsto \frac{180 \cdot \tan^{-1} \color{blue}{\left(1 + \left(\frac{C}{B} - \frac{A}{B}\right)\right)}}{\pi} \]
        2. div-sub72.0%

          \[\leadsto \frac{180 \cdot \tan^{-1} \left(1 + \color{blue}{\frac{C - A}{B}}\right)}{\pi} \]
      7. Simplified72.0%

        \[\leadsto \frac{180 \cdot \tan^{-1} \color{blue}{\left(1 + \frac{C - A}{B}\right)}}{\pi} \]
      8. Taylor expanded in A around 0 62.6%

        \[\leadsto \frac{180 \cdot \tan^{-1} \color{blue}{\left(1 + \frac{C}{B}\right)}}{\pi} \]

      if -1.2000000000000001e-181 < A < 1.1000000000000001e-189

      1. Initial program 61.0%

        \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
      2. Add Preprocessing
      3. Taylor expanded in A around 0 61.1%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{C - \sqrt{{B}^{2} + {C}^{2}}}{B}\right)}}{\pi} \]
      4. Step-by-step derivation
        1. +-commutative61.1%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{C - \sqrt{\color{blue}{{C}^{2} + {B}^{2}}}}{B}\right)}{\pi} \]
        2. unpow261.1%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{C - \sqrt{\color{blue}{C \cdot C} + {B}^{2}}}{B}\right)}{\pi} \]
        3. unpow261.1%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{C - \sqrt{C \cdot C + \color{blue}{B \cdot B}}}{B}\right)}{\pi} \]
        4. hypot-define89.7%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{C - \color{blue}{\mathsf{hypot}\left(C, B\right)}}{B}\right)}{\pi} \]
      5. Simplified89.7%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{C - \mathsf{hypot}\left(C, B\right)}{B}\right)}}{\pi} \]
      6. Taylor expanded in C around 0 60.5%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\color{blue}{C - B}}{B}\right)}{\pi} \]

      if 380 < A

      1. Initial program 77.6%

        \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
      2. Step-by-step derivation
        1. associate-*l/77.6%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{1 \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}{B}\right)}}{\pi} \]
        2. *-lft-identity77.6%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\color{blue}{\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}}}{B}\right)}{\pi} \]
        3. +-commutative77.6%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\left(C - A\right) - \sqrt{\color{blue}{{B}^{2} + {\left(A - C\right)}^{2}}}}{B}\right)}{\pi} \]
        4. unpow277.6%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\left(C - A\right) - \sqrt{\color{blue}{B \cdot B} + {\left(A - C\right)}^{2}}}{B}\right)}{\pi} \]
        5. unpow277.6%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\left(C - A\right) - \sqrt{B \cdot B + \color{blue}{\left(A - C\right) \cdot \left(A - C\right)}}}{B}\right)}{\pi} \]
        6. hypot-define93.3%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\left(C - A\right) - \color{blue}{\mathsf{hypot}\left(B, A - C\right)}}{B}\right)}{\pi} \]
      3. Simplified93.3%

        \[\leadsto \color{blue}{180 \cdot \frac{\tan^{-1} \left(\frac{\left(C - A\right) - \mathsf{hypot}\left(B, A - C\right)}{B}\right)}{\pi}} \]
      4. Add Preprocessing
      5. Taylor expanded in A around inf 71.3%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\color{blue}{-2 \cdot A}}{B}\right)}{\pi} \]
      6. Step-by-step derivation
        1. *-commutative71.3%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\color{blue}{A \cdot -2}}{B}\right)}{\pi} \]
      7. Simplified71.3%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\color{blue}{A \cdot -2}}{B}\right)}{\pi} \]
    3. Recombined 4 regimes into one program.
    4. Final simplification64.7%

      \[\leadsto \begin{array}{l} \mathbf{if}\;A \leq -1260000:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{B \cdot 0.5}{A}\right)}{\pi}\\ \mathbf{elif}\;A \leq -1.2 \cdot 10^{-181}:\\ \;\;\;\;\frac{180 \cdot \tan^{-1} \left(1 + \frac{C}{B}\right)}{\pi}\\ \mathbf{elif}\;A \leq 1.1 \cdot 10^{-189}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{C - B}{B}\right)}{\pi}\\ \mathbf{elif}\;A \leq 380:\\ \;\;\;\;\frac{180 \cdot \tan^{-1} \left(1 + \frac{C}{B}\right)}{\pi}\\ \mathbf{else}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{A \cdot -2}{B}\right)}{\pi}\\ \end{array} \]
    5. Add Preprocessing

    Alternative 8: 58.8% accurate, 3.4× speedup?

    \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;A \leq -3950000:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{B \cdot 0.5}{A}\right)}{\pi}\\ \mathbf{elif}\;A \leq -2 \cdot 10^{-171}:\\ \;\;\;\;\frac{180 \cdot \tan^{-1} \left(1 + \frac{C}{B}\right)}{\pi}\\ \mathbf{elif}\;A \leq 1.3 \cdot 10^{-189}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{C - B}{B}\right)}{\pi}\\ \mathbf{else}:\\ \;\;\;\;\frac{180 \cdot \tan^{-1} \left(1 - \frac{A}{B}\right)}{\pi}\\ \end{array} \end{array} \]
    (FPCore (A B C)
     :precision binary64
     (if (<= A -3950000.0)
       (* 180.0 (/ (atan (/ (* B 0.5) A)) PI))
       (if (<= A -2e-171)
         (/ (* 180.0 (atan (+ 1.0 (/ C B)))) PI)
         (if (<= A 1.3e-189)
           (* 180.0 (/ (atan (/ (- C B) B)) PI))
           (/ (* 180.0 (atan (- 1.0 (/ A B)))) PI)))))
    double code(double A, double B, double C) {
    	double tmp;
    	if (A <= -3950000.0) {
    		tmp = 180.0 * (atan(((B * 0.5) / A)) / ((double) M_PI));
    	} else if (A <= -2e-171) {
    		tmp = (180.0 * atan((1.0 + (C / B)))) / ((double) M_PI);
    	} else if (A <= 1.3e-189) {
    		tmp = 180.0 * (atan(((C - B) / B)) / ((double) M_PI));
    	} else {
    		tmp = (180.0 * atan((1.0 - (A / B)))) / ((double) M_PI);
    	}
    	return tmp;
    }
    
    public static double code(double A, double B, double C) {
    	double tmp;
    	if (A <= -3950000.0) {
    		tmp = 180.0 * (Math.atan(((B * 0.5) / A)) / Math.PI);
    	} else if (A <= -2e-171) {
    		tmp = (180.0 * Math.atan((1.0 + (C / B)))) / Math.PI;
    	} else if (A <= 1.3e-189) {
    		tmp = 180.0 * (Math.atan(((C - B) / B)) / Math.PI);
    	} else {
    		tmp = (180.0 * Math.atan((1.0 - (A / B)))) / Math.PI;
    	}
    	return tmp;
    }
    
    def code(A, B, C):
    	tmp = 0
    	if A <= -3950000.0:
    		tmp = 180.0 * (math.atan(((B * 0.5) / A)) / math.pi)
    	elif A <= -2e-171:
    		tmp = (180.0 * math.atan((1.0 + (C / B)))) / math.pi
    	elif A <= 1.3e-189:
    		tmp = 180.0 * (math.atan(((C - B) / B)) / math.pi)
    	else:
    		tmp = (180.0 * math.atan((1.0 - (A / B)))) / math.pi
    	return tmp
    
    function code(A, B, C)
    	tmp = 0.0
    	if (A <= -3950000.0)
    		tmp = Float64(180.0 * Float64(atan(Float64(Float64(B * 0.5) / A)) / pi));
    	elseif (A <= -2e-171)
    		tmp = Float64(Float64(180.0 * atan(Float64(1.0 + Float64(C / B)))) / pi);
    	elseif (A <= 1.3e-189)
    		tmp = Float64(180.0 * Float64(atan(Float64(Float64(C - B) / B)) / pi));
    	else
    		tmp = Float64(Float64(180.0 * atan(Float64(1.0 - Float64(A / B)))) / pi);
    	end
    	return tmp
    end
    
    function tmp_2 = code(A, B, C)
    	tmp = 0.0;
    	if (A <= -3950000.0)
    		tmp = 180.0 * (atan(((B * 0.5) / A)) / pi);
    	elseif (A <= -2e-171)
    		tmp = (180.0 * atan((1.0 + (C / B)))) / pi;
    	elseif (A <= 1.3e-189)
    		tmp = 180.0 * (atan(((C - B) / B)) / pi);
    	else
    		tmp = (180.0 * atan((1.0 - (A / B)))) / pi;
    	end
    	tmp_2 = tmp;
    end
    
    code[A_, B_, C_] := If[LessEqual[A, -3950000.0], N[(180.0 * N[(N[ArcTan[N[(N[(B * 0.5), $MachinePrecision] / A), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision], If[LessEqual[A, -2e-171], N[(N[(180.0 * N[ArcTan[N[(1.0 + N[(C / B), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] / Pi), $MachinePrecision], If[LessEqual[A, 1.3e-189], N[(180.0 * N[(N[ArcTan[N[(N[(C - B), $MachinePrecision] / B), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision], N[(N[(180.0 * N[ArcTan[N[(1.0 - N[(A / B), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] / Pi), $MachinePrecision]]]]
    
    \begin{array}{l}
    
    \\
    \begin{array}{l}
    \mathbf{if}\;A \leq -3950000:\\
    \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{B \cdot 0.5}{A}\right)}{\pi}\\
    
    \mathbf{elif}\;A \leq -2 \cdot 10^{-171}:\\
    \;\;\;\;\frac{180 \cdot \tan^{-1} \left(1 + \frac{C}{B}\right)}{\pi}\\
    
    \mathbf{elif}\;A \leq 1.3 \cdot 10^{-189}:\\
    \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{C - B}{B}\right)}{\pi}\\
    
    \mathbf{else}:\\
    \;\;\;\;\frac{180 \cdot \tan^{-1} \left(1 - \frac{A}{B}\right)}{\pi}\\
    
    
    \end{array}
    \end{array}
    
    Derivation
    1. Split input into 4 regimes
    2. if A < -3.95e6

      1. Initial program 23.3%

        \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
      2. Add Preprocessing
      3. Taylor expanded in A around -inf 63.2%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(0.5 \cdot \frac{B}{A}\right)}}{\pi} \]
      4. Step-by-step derivation
        1. associate-*r/63.2%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{0.5 \cdot B}{A}\right)}}{\pi} \]
      5. Simplified63.2%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{0.5 \cdot B}{A}\right)}}{\pi} \]

      if -3.95e6 < A < -2e-171

      1. Initial program 70.8%

        \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
      2. Add Preprocessing
      3. Step-by-step derivation
        1. associate-*r/70.8%

          \[\leadsto \color{blue}{\frac{180 \cdot \tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi}} \]
      4. Applied egg-rr77.1%

        \[\leadsto \color{blue}{\frac{180 \cdot \tan^{-1} \left(\frac{\left(C - A\right) - \mathsf{hypot}\left(B, A - C\right)}{B}\right)}{\pi}} \]
      5. Taylor expanded in B around -inf 70.9%

        \[\leadsto \frac{180 \cdot \tan^{-1} \color{blue}{\left(\left(1 + \frac{C}{B}\right) - \frac{A}{B}\right)}}{\pi} \]
      6. Step-by-step derivation
        1. associate--l+70.9%

          \[\leadsto \frac{180 \cdot \tan^{-1} \color{blue}{\left(1 + \left(\frac{C}{B} - \frac{A}{B}\right)\right)}}{\pi} \]
        2. div-sub70.9%

          \[\leadsto \frac{180 \cdot \tan^{-1} \left(1 + \color{blue}{\frac{C - A}{B}}\right)}{\pi} \]
      7. Simplified70.9%

        \[\leadsto \frac{180 \cdot \tan^{-1} \color{blue}{\left(1 + \frac{C - A}{B}\right)}}{\pi} \]
      8. Taylor expanded in A around 0 71.2%

        \[\leadsto \frac{180 \cdot \tan^{-1} \color{blue}{\left(1 + \frac{C}{B}\right)}}{\pi} \]

      if -2e-171 < A < 1.2999999999999999e-189

      1. Initial program 61.0%

        \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
      2. Add Preprocessing
      3. Taylor expanded in A around 0 61.1%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{C - \sqrt{{B}^{2} + {C}^{2}}}{B}\right)}}{\pi} \]
      4. Step-by-step derivation
        1. +-commutative61.1%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{C - \sqrt{\color{blue}{{C}^{2} + {B}^{2}}}}{B}\right)}{\pi} \]
        2. unpow261.1%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{C - \sqrt{\color{blue}{C \cdot C} + {B}^{2}}}{B}\right)}{\pi} \]
        3. unpow261.1%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{C - \sqrt{C \cdot C + \color{blue}{B \cdot B}}}{B}\right)}{\pi} \]
        4. hypot-define89.7%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{C - \color{blue}{\mathsf{hypot}\left(C, B\right)}}{B}\right)}{\pi} \]
      5. Simplified89.7%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{C - \mathsf{hypot}\left(C, B\right)}{B}\right)}}{\pi} \]
      6. Taylor expanded in C around 0 60.5%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\color{blue}{C - B}}{B}\right)}{\pi} \]

      if 1.2999999999999999e-189 < A

      1. Initial program 72.9%

        \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
      2. Add Preprocessing
      3. Step-by-step derivation
        1. associate-*r/72.9%

          \[\leadsto \color{blue}{\frac{180 \cdot \tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi}} \]
      4. Applied egg-rr90.5%

        \[\leadsto \color{blue}{\frac{180 \cdot \tan^{-1} \left(\frac{\left(C - A\right) - \mathsf{hypot}\left(B, A - C\right)}{B}\right)}{\pi}} \]
      5. Taylor expanded in B around -inf 76.6%

        \[\leadsto \frac{180 \cdot \tan^{-1} \color{blue}{\left(\left(1 + \frac{C}{B}\right) - \frac{A}{B}\right)}}{\pi} \]
      6. Step-by-step derivation
        1. associate--l+76.6%

          \[\leadsto \frac{180 \cdot \tan^{-1} \color{blue}{\left(1 + \left(\frac{C}{B} - \frac{A}{B}\right)\right)}}{\pi} \]
        2. div-sub78.2%

          \[\leadsto \frac{180 \cdot \tan^{-1} \left(1 + \color{blue}{\frac{C - A}{B}}\right)}{\pi} \]
      7. Simplified78.2%

        \[\leadsto \frac{180 \cdot \tan^{-1} \color{blue}{\left(1 + \frac{C - A}{B}\right)}}{\pi} \]
      8. Taylor expanded in C around 0 72.5%

        \[\leadsto \frac{180 \cdot \tan^{-1} \color{blue}{\left(1 - \frac{A}{B}\right)}}{\pi} \]
    3. Recombined 4 regimes into one program.
    4. Final simplification67.8%

      \[\leadsto \begin{array}{l} \mathbf{if}\;A \leq -3950000:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{B \cdot 0.5}{A}\right)}{\pi}\\ \mathbf{elif}\;A \leq -2 \cdot 10^{-171}:\\ \;\;\;\;\frac{180 \cdot \tan^{-1} \left(1 + \frac{C}{B}\right)}{\pi}\\ \mathbf{elif}\;A \leq 1.3 \cdot 10^{-189}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{C - B}{B}\right)}{\pi}\\ \mathbf{else}:\\ \;\;\;\;\frac{180 \cdot \tan^{-1} \left(1 - \frac{A}{B}\right)}{\pi}\\ \end{array} \]
    5. Add Preprocessing

    Alternative 9: 56.0% accurate, 3.4× speedup?

    \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;A \leq -2.6 \cdot 10^{-48}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{B \cdot 0.5}{A}\right)}{\pi}\\ \mathbf{elif}\;A \leq -2.4 \cdot 10^{-98}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} 1}{\pi}\\ \mathbf{elif}\;A \leq 1.3 \cdot 10^{-58}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{C - B}{B}\right)}{\pi}\\ \mathbf{else}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{A \cdot -2}{B}\right)}{\pi}\\ \end{array} \end{array} \]
    (FPCore (A B C)
     :precision binary64
     (if (<= A -2.6e-48)
       (* 180.0 (/ (atan (/ (* B 0.5) A)) PI))
       (if (<= A -2.4e-98)
         (* 180.0 (/ (atan 1.0) PI))
         (if (<= A 1.3e-58)
           (* 180.0 (/ (atan (/ (- C B) B)) PI))
           (* 180.0 (/ (atan (/ (* A -2.0) B)) PI))))))
    double code(double A, double B, double C) {
    	double tmp;
    	if (A <= -2.6e-48) {
    		tmp = 180.0 * (atan(((B * 0.5) / A)) / ((double) M_PI));
    	} else if (A <= -2.4e-98) {
    		tmp = 180.0 * (atan(1.0) / ((double) M_PI));
    	} else if (A <= 1.3e-58) {
    		tmp = 180.0 * (atan(((C - B) / B)) / ((double) M_PI));
    	} else {
    		tmp = 180.0 * (atan(((A * -2.0) / B)) / ((double) M_PI));
    	}
    	return tmp;
    }
    
    public static double code(double A, double B, double C) {
    	double tmp;
    	if (A <= -2.6e-48) {
    		tmp = 180.0 * (Math.atan(((B * 0.5) / A)) / Math.PI);
    	} else if (A <= -2.4e-98) {
    		tmp = 180.0 * (Math.atan(1.0) / Math.PI);
    	} else if (A <= 1.3e-58) {
    		tmp = 180.0 * (Math.atan(((C - B) / B)) / Math.PI);
    	} else {
    		tmp = 180.0 * (Math.atan(((A * -2.0) / B)) / Math.PI);
    	}
    	return tmp;
    }
    
    def code(A, B, C):
    	tmp = 0
    	if A <= -2.6e-48:
    		tmp = 180.0 * (math.atan(((B * 0.5) / A)) / math.pi)
    	elif A <= -2.4e-98:
    		tmp = 180.0 * (math.atan(1.0) / math.pi)
    	elif A <= 1.3e-58:
    		tmp = 180.0 * (math.atan(((C - B) / B)) / math.pi)
    	else:
    		tmp = 180.0 * (math.atan(((A * -2.0) / B)) / math.pi)
    	return tmp
    
    function code(A, B, C)
    	tmp = 0.0
    	if (A <= -2.6e-48)
    		tmp = Float64(180.0 * Float64(atan(Float64(Float64(B * 0.5) / A)) / pi));
    	elseif (A <= -2.4e-98)
    		tmp = Float64(180.0 * Float64(atan(1.0) / pi));
    	elseif (A <= 1.3e-58)
    		tmp = Float64(180.0 * Float64(atan(Float64(Float64(C - B) / B)) / pi));
    	else
    		tmp = Float64(180.0 * Float64(atan(Float64(Float64(A * -2.0) / B)) / pi));
    	end
    	return tmp
    end
    
    function tmp_2 = code(A, B, C)
    	tmp = 0.0;
    	if (A <= -2.6e-48)
    		tmp = 180.0 * (atan(((B * 0.5) / A)) / pi);
    	elseif (A <= -2.4e-98)
    		tmp = 180.0 * (atan(1.0) / pi);
    	elseif (A <= 1.3e-58)
    		tmp = 180.0 * (atan(((C - B) / B)) / pi);
    	else
    		tmp = 180.0 * (atan(((A * -2.0) / B)) / pi);
    	end
    	tmp_2 = tmp;
    end
    
    code[A_, B_, C_] := If[LessEqual[A, -2.6e-48], N[(180.0 * N[(N[ArcTan[N[(N[(B * 0.5), $MachinePrecision] / A), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision], If[LessEqual[A, -2.4e-98], N[(180.0 * N[(N[ArcTan[1.0], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision], If[LessEqual[A, 1.3e-58], N[(180.0 * N[(N[ArcTan[N[(N[(C - B), $MachinePrecision] / B), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision], N[(180.0 * N[(N[ArcTan[N[(N[(A * -2.0), $MachinePrecision] / B), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision]]]]
    
    \begin{array}{l}
    
    \\
    \begin{array}{l}
    \mathbf{if}\;A \leq -2.6 \cdot 10^{-48}:\\
    \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{B \cdot 0.5}{A}\right)}{\pi}\\
    
    \mathbf{elif}\;A \leq -2.4 \cdot 10^{-98}:\\
    \;\;\;\;180 \cdot \frac{\tan^{-1} 1}{\pi}\\
    
    \mathbf{elif}\;A \leq 1.3 \cdot 10^{-58}:\\
    \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{C - B}{B}\right)}{\pi}\\
    
    \mathbf{else}:\\
    \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{A \cdot -2}{B}\right)}{\pi}\\
    
    
    \end{array}
    \end{array}
    
    Derivation
    1. Split input into 4 regimes
    2. if A < -2.59999999999999987e-48

      1. Initial program 26.8%

        \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
      2. Add Preprocessing
      3. Taylor expanded in A around -inf 59.9%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(0.5 \cdot \frac{B}{A}\right)}}{\pi} \]
      4. Step-by-step derivation
        1. associate-*r/59.9%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{0.5 \cdot B}{A}\right)}}{\pi} \]
      5. Simplified59.9%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{0.5 \cdot B}{A}\right)}}{\pi} \]

      if -2.59999999999999987e-48 < A < -2.40000000000000005e-98

      1. Initial program 80.2%

        \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
      2. Add Preprocessing
      3. Taylor expanded in B around -inf 73.1%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{1}}{\pi} \]

      if -2.40000000000000005e-98 < A < 1.30000000000000003e-58

      1. Initial program 65.7%

        \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
      2. Add Preprocessing
      3. Taylor expanded in A around 0 62.3%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{C - \sqrt{{B}^{2} + {C}^{2}}}{B}\right)}}{\pi} \]
      4. Step-by-step derivation
        1. +-commutative62.3%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{C - \sqrt{\color{blue}{{C}^{2} + {B}^{2}}}}{B}\right)}{\pi} \]
        2. unpow262.3%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{C - \sqrt{\color{blue}{C \cdot C} + {B}^{2}}}{B}\right)}{\pi} \]
        3. unpow262.3%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{C - \sqrt{C \cdot C + \color{blue}{B \cdot B}}}{B}\right)}{\pi} \]
        4. hypot-define84.6%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{C - \color{blue}{\mathsf{hypot}\left(C, B\right)}}{B}\right)}{\pi} \]
      5. Simplified84.6%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{C - \mathsf{hypot}\left(C, B\right)}{B}\right)}}{\pi} \]
      6. Taylor expanded in C around 0 52.0%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\color{blue}{C - B}}{B}\right)}{\pi} \]

      if 1.30000000000000003e-58 < A

      1. Initial program 74.3%

        \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
      2. Step-by-step derivation
        1. associate-*l/74.3%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{1 \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}{B}\right)}}{\pi} \]
        2. *-lft-identity74.3%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\color{blue}{\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}}}{B}\right)}{\pi} \]
        3. +-commutative74.3%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\left(C - A\right) - \sqrt{\color{blue}{{B}^{2} + {\left(A - C\right)}^{2}}}}{B}\right)}{\pi} \]
        4. unpow274.3%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\left(C - A\right) - \sqrt{\color{blue}{B \cdot B} + {\left(A - C\right)}^{2}}}{B}\right)}{\pi} \]
        5. unpow274.3%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\left(C - A\right) - \sqrt{B \cdot B + \color{blue}{\left(A - C\right) \cdot \left(A - C\right)}}}{B}\right)}{\pi} \]
        6. hypot-define92.5%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\left(C - A\right) - \color{blue}{\mathsf{hypot}\left(B, A - C\right)}}{B}\right)}{\pi} \]
      3. Simplified92.5%

        \[\leadsto \color{blue}{180 \cdot \frac{\tan^{-1} \left(\frac{\left(C - A\right) - \mathsf{hypot}\left(B, A - C\right)}{B}\right)}{\pi}} \]
      4. Add Preprocessing
      5. Taylor expanded in A around inf 66.4%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\color{blue}{-2 \cdot A}}{B}\right)}{\pi} \]
      6. Step-by-step derivation
        1. *-commutative66.4%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\color{blue}{A \cdot -2}}{B}\right)}{\pi} \]
      7. Simplified66.4%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\color{blue}{A \cdot -2}}{B}\right)}{\pi} \]
    3. Recombined 4 regimes into one program.
    4. Final simplification59.8%

      \[\leadsto \begin{array}{l} \mathbf{if}\;A \leq -2.6 \cdot 10^{-48}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{B \cdot 0.5}{A}\right)}{\pi}\\ \mathbf{elif}\;A \leq -2.4 \cdot 10^{-98}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} 1}{\pi}\\ \mathbf{elif}\;A \leq 1.3 \cdot 10^{-58}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{C - B}{B}\right)}{\pi}\\ \mathbf{else}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{A \cdot -2}{B}\right)}{\pi}\\ \end{array} \]
    5. Add Preprocessing

    Alternative 10: 48.0% accurate, 3.4× speedup?

    \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;B \leq -9.8 \cdot 10^{-82}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} 1}{\pi}\\ \mathbf{elif}\;B \leq 1.06 \cdot 10^{-283}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{C \cdot 2}{B}\right)}{\pi}\\ \mathbf{elif}\;B \leq 6.5 \cdot 10^{-14}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{A \cdot -2}{B}\right)}{\pi}\\ \mathbf{else}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} -1}{\pi}\\ \end{array} \end{array} \]
    (FPCore (A B C)
     :precision binary64
     (if (<= B -9.8e-82)
       (* 180.0 (/ (atan 1.0) PI))
       (if (<= B 1.06e-283)
         (* 180.0 (/ (atan (/ (* C 2.0) B)) PI))
         (if (<= B 6.5e-14)
           (* 180.0 (/ (atan (/ (* A -2.0) B)) PI))
           (* 180.0 (/ (atan -1.0) PI))))))
    double code(double A, double B, double C) {
    	double tmp;
    	if (B <= -9.8e-82) {
    		tmp = 180.0 * (atan(1.0) / ((double) M_PI));
    	} else if (B <= 1.06e-283) {
    		tmp = 180.0 * (atan(((C * 2.0) / B)) / ((double) M_PI));
    	} else if (B <= 6.5e-14) {
    		tmp = 180.0 * (atan(((A * -2.0) / B)) / ((double) M_PI));
    	} else {
    		tmp = 180.0 * (atan(-1.0) / ((double) M_PI));
    	}
    	return tmp;
    }
    
    public static double code(double A, double B, double C) {
    	double tmp;
    	if (B <= -9.8e-82) {
    		tmp = 180.0 * (Math.atan(1.0) / Math.PI);
    	} else if (B <= 1.06e-283) {
    		tmp = 180.0 * (Math.atan(((C * 2.0) / B)) / Math.PI);
    	} else if (B <= 6.5e-14) {
    		tmp = 180.0 * (Math.atan(((A * -2.0) / B)) / Math.PI);
    	} else {
    		tmp = 180.0 * (Math.atan(-1.0) / Math.PI);
    	}
    	return tmp;
    }
    
    def code(A, B, C):
    	tmp = 0
    	if B <= -9.8e-82:
    		tmp = 180.0 * (math.atan(1.0) / math.pi)
    	elif B <= 1.06e-283:
    		tmp = 180.0 * (math.atan(((C * 2.0) / B)) / math.pi)
    	elif B <= 6.5e-14:
    		tmp = 180.0 * (math.atan(((A * -2.0) / B)) / math.pi)
    	else:
    		tmp = 180.0 * (math.atan(-1.0) / math.pi)
    	return tmp
    
    function code(A, B, C)
    	tmp = 0.0
    	if (B <= -9.8e-82)
    		tmp = Float64(180.0 * Float64(atan(1.0) / pi));
    	elseif (B <= 1.06e-283)
    		tmp = Float64(180.0 * Float64(atan(Float64(Float64(C * 2.0) / B)) / pi));
    	elseif (B <= 6.5e-14)
    		tmp = Float64(180.0 * Float64(atan(Float64(Float64(A * -2.0) / B)) / pi));
    	else
    		tmp = Float64(180.0 * Float64(atan(-1.0) / pi));
    	end
    	return tmp
    end
    
    function tmp_2 = code(A, B, C)
    	tmp = 0.0;
    	if (B <= -9.8e-82)
    		tmp = 180.0 * (atan(1.0) / pi);
    	elseif (B <= 1.06e-283)
    		tmp = 180.0 * (atan(((C * 2.0) / B)) / pi);
    	elseif (B <= 6.5e-14)
    		tmp = 180.0 * (atan(((A * -2.0) / B)) / pi);
    	else
    		tmp = 180.0 * (atan(-1.0) / pi);
    	end
    	tmp_2 = tmp;
    end
    
    code[A_, B_, C_] := If[LessEqual[B, -9.8e-82], N[(180.0 * N[(N[ArcTan[1.0], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision], If[LessEqual[B, 1.06e-283], N[(180.0 * N[(N[ArcTan[N[(N[(C * 2.0), $MachinePrecision] / B), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision], If[LessEqual[B, 6.5e-14], N[(180.0 * N[(N[ArcTan[N[(N[(A * -2.0), $MachinePrecision] / B), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision], N[(180.0 * N[(N[ArcTan[-1.0], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision]]]]
    
    \begin{array}{l}
    
    \\
    \begin{array}{l}
    \mathbf{if}\;B \leq -9.8 \cdot 10^{-82}:\\
    \;\;\;\;180 \cdot \frac{\tan^{-1} 1}{\pi}\\
    
    \mathbf{elif}\;B \leq 1.06 \cdot 10^{-283}:\\
    \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{C \cdot 2}{B}\right)}{\pi}\\
    
    \mathbf{elif}\;B \leq 6.5 \cdot 10^{-14}:\\
    \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{A \cdot -2}{B}\right)}{\pi}\\
    
    \mathbf{else}:\\
    \;\;\;\;180 \cdot \frac{\tan^{-1} -1}{\pi}\\
    
    
    \end{array}
    \end{array}
    
    Derivation
    1. Split input into 4 regimes
    2. if B < -9.8000000000000006e-82

      1. Initial program 56.0%

        \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
      2. Add Preprocessing
      3. Taylor expanded in B around -inf 60.7%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{1}}{\pi} \]

      if -9.8000000000000006e-82 < B < 1.06e-283

      1. Initial program 68.1%

        \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
      2. Add Preprocessing
      3. Taylor expanded in C around -inf 48.3%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(2 \cdot \frac{C}{B}\right)}}{\pi} \]
      4. Step-by-step derivation
        1. associate-*r/48.3%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{2 \cdot C}{B}\right)}}{\pi} \]
        2. *-commutative48.3%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\color{blue}{C \cdot 2}}{B}\right)}{\pi} \]
      5. Simplified48.3%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{C \cdot 2}{B}\right)}}{\pi} \]

      if 1.06e-283 < B < 6.5000000000000001e-14

      1. Initial program 63.9%

        \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
      2. Step-by-step derivation
        1. associate-*l/63.9%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{1 \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}{B}\right)}}{\pi} \]
        2. *-lft-identity63.9%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\color{blue}{\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}}}{B}\right)}{\pi} \]
        3. +-commutative63.9%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\left(C - A\right) - \sqrt{\color{blue}{{B}^{2} + {\left(A - C\right)}^{2}}}}{B}\right)}{\pi} \]
        4. unpow263.9%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\left(C - A\right) - \sqrt{\color{blue}{B \cdot B} + {\left(A - C\right)}^{2}}}{B}\right)}{\pi} \]
        5. unpow263.9%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\left(C - A\right) - \sqrt{B \cdot B + \color{blue}{\left(A - C\right) \cdot \left(A - C\right)}}}{B}\right)}{\pi} \]
        6. hypot-define80.9%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\left(C - A\right) - \color{blue}{\mathsf{hypot}\left(B, A - C\right)}}{B}\right)}{\pi} \]
      3. Simplified80.9%

        \[\leadsto \color{blue}{180 \cdot \frac{\tan^{-1} \left(\frac{\left(C - A\right) - \mathsf{hypot}\left(B, A - C\right)}{B}\right)}{\pi}} \]
      4. Add Preprocessing
      5. Taylor expanded in A around inf 46.2%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\color{blue}{-2 \cdot A}}{B}\right)}{\pi} \]
      6. Step-by-step derivation
        1. *-commutative46.2%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\color{blue}{A \cdot -2}}{B}\right)}{\pi} \]
      7. Simplified46.2%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\color{blue}{A \cdot -2}}{B}\right)}{\pi} \]

      if 6.5000000000000001e-14 < B

      1. Initial program 51.1%

        \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
      2. Add Preprocessing
      3. Taylor expanded in B around inf 57.7%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{-1}}{\pi} \]
    3. Recombined 4 regimes into one program.
    4. Add Preprocessing

    Alternative 11: 48.0% accurate, 3.4× speedup?

    \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;B \leq -1.55 \cdot 10^{-77}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} 1}{\pi}\\ \mathbf{elif}\;B \leq 1.05 \cdot 10^{-282}:\\ \;\;\;\;\frac{180 \cdot \tan^{-1} \left(\frac{C}{B}\right)}{\pi}\\ \mathbf{elif}\;B \leq 6.5 \cdot 10^{-14}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{A \cdot -2}{B}\right)}{\pi}\\ \mathbf{else}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} -1}{\pi}\\ \end{array} \end{array} \]
    (FPCore (A B C)
     :precision binary64
     (if (<= B -1.55e-77)
       (* 180.0 (/ (atan 1.0) PI))
       (if (<= B 1.05e-282)
         (/ (* 180.0 (atan (/ C B))) PI)
         (if (<= B 6.5e-14)
           (* 180.0 (/ (atan (/ (* A -2.0) B)) PI))
           (* 180.0 (/ (atan -1.0) PI))))))
    double code(double A, double B, double C) {
    	double tmp;
    	if (B <= -1.55e-77) {
    		tmp = 180.0 * (atan(1.0) / ((double) M_PI));
    	} else if (B <= 1.05e-282) {
    		tmp = (180.0 * atan((C / B))) / ((double) M_PI);
    	} else if (B <= 6.5e-14) {
    		tmp = 180.0 * (atan(((A * -2.0) / B)) / ((double) M_PI));
    	} else {
    		tmp = 180.0 * (atan(-1.0) / ((double) M_PI));
    	}
    	return tmp;
    }
    
    public static double code(double A, double B, double C) {
    	double tmp;
    	if (B <= -1.55e-77) {
    		tmp = 180.0 * (Math.atan(1.0) / Math.PI);
    	} else if (B <= 1.05e-282) {
    		tmp = (180.0 * Math.atan((C / B))) / Math.PI;
    	} else if (B <= 6.5e-14) {
    		tmp = 180.0 * (Math.atan(((A * -2.0) / B)) / Math.PI);
    	} else {
    		tmp = 180.0 * (Math.atan(-1.0) / Math.PI);
    	}
    	return tmp;
    }
    
    def code(A, B, C):
    	tmp = 0
    	if B <= -1.55e-77:
    		tmp = 180.0 * (math.atan(1.0) / math.pi)
    	elif B <= 1.05e-282:
    		tmp = (180.0 * math.atan((C / B))) / math.pi
    	elif B <= 6.5e-14:
    		tmp = 180.0 * (math.atan(((A * -2.0) / B)) / math.pi)
    	else:
    		tmp = 180.0 * (math.atan(-1.0) / math.pi)
    	return tmp
    
    function code(A, B, C)
    	tmp = 0.0
    	if (B <= -1.55e-77)
    		tmp = Float64(180.0 * Float64(atan(1.0) / pi));
    	elseif (B <= 1.05e-282)
    		tmp = Float64(Float64(180.0 * atan(Float64(C / B))) / pi);
    	elseif (B <= 6.5e-14)
    		tmp = Float64(180.0 * Float64(atan(Float64(Float64(A * -2.0) / B)) / pi));
    	else
    		tmp = Float64(180.0 * Float64(atan(-1.0) / pi));
    	end
    	return tmp
    end
    
    function tmp_2 = code(A, B, C)
    	tmp = 0.0;
    	if (B <= -1.55e-77)
    		tmp = 180.0 * (atan(1.0) / pi);
    	elseif (B <= 1.05e-282)
    		tmp = (180.0 * atan((C / B))) / pi;
    	elseif (B <= 6.5e-14)
    		tmp = 180.0 * (atan(((A * -2.0) / B)) / pi);
    	else
    		tmp = 180.0 * (atan(-1.0) / pi);
    	end
    	tmp_2 = tmp;
    end
    
    code[A_, B_, C_] := If[LessEqual[B, -1.55e-77], N[(180.0 * N[(N[ArcTan[1.0], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision], If[LessEqual[B, 1.05e-282], N[(N[(180.0 * N[ArcTan[N[(C / B), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] / Pi), $MachinePrecision], If[LessEqual[B, 6.5e-14], N[(180.0 * N[(N[ArcTan[N[(N[(A * -2.0), $MachinePrecision] / B), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision], N[(180.0 * N[(N[ArcTan[-1.0], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision]]]]
    
    \begin{array}{l}
    
    \\
    \begin{array}{l}
    \mathbf{if}\;B \leq -1.55 \cdot 10^{-77}:\\
    \;\;\;\;180 \cdot \frac{\tan^{-1} 1}{\pi}\\
    
    \mathbf{elif}\;B \leq 1.05 \cdot 10^{-282}:\\
    \;\;\;\;\frac{180 \cdot \tan^{-1} \left(\frac{C}{B}\right)}{\pi}\\
    
    \mathbf{elif}\;B \leq 6.5 \cdot 10^{-14}:\\
    \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{A \cdot -2}{B}\right)}{\pi}\\
    
    \mathbf{else}:\\
    \;\;\;\;180 \cdot \frac{\tan^{-1} -1}{\pi}\\
    
    
    \end{array}
    \end{array}
    
    Derivation
    1. Split input into 4 regimes
    2. if B < -1.55000000000000004e-77

      1. Initial program 56.0%

        \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
      2. Add Preprocessing
      3. Taylor expanded in B around -inf 60.7%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{1}}{\pi} \]

      if -1.55000000000000004e-77 < B < 1.05000000000000006e-282

      1. Initial program 68.1%

        \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
      2. Add Preprocessing
      3. Step-by-step derivation
        1. associate-*r/68.1%

          \[\leadsto \color{blue}{\frac{180 \cdot \tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi}} \]
      4. Applied egg-rr86.8%

        \[\leadsto \color{blue}{\frac{180 \cdot \tan^{-1} \left(\frac{\left(C - A\right) - \mathsf{hypot}\left(B, A - C\right)}{B}\right)}{\pi}} \]
      5. Taylor expanded in B around -inf 57.6%

        \[\leadsto \frac{180 \cdot \tan^{-1} \color{blue}{\left(\left(1 + \frac{C}{B}\right) - \frac{A}{B}\right)}}{\pi} \]
      6. Step-by-step derivation
        1. associate--l+57.6%

          \[\leadsto \frac{180 \cdot \tan^{-1} \color{blue}{\left(1 + \left(\frac{C}{B} - \frac{A}{B}\right)\right)}}{\pi} \]
        2. div-sub59.7%

          \[\leadsto \frac{180 \cdot \tan^{-1} \left(1 + \color{blue}{\frac{C - A}{B}}\right)}{\pi} \]
      7. Simplified59.7%

        \[\leadsto \frac{180 \cdot \tan^{-1} \color{blue}{\left(1 + \frac{C - A}{B}\right)}}{\pi} \]
      8. Taylor expanded in C around inf 47.3%

        \[\leadsto \frac{180 \cdot \tan^{-1} \color{blue}{\left(\frac{C}{B}\right)}}{\pi} \]

      if 1.05000000000000006e-282 < B < 6.5000000000000001e-14

      1. Initial program 63.9%

        \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
      2. Step-by-step derivation
        1. associate-*l/63.9%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{1 \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}{B}\right)}}{\pi} \]
        2. *-lft-identity63.9%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\color{blue}{\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}}}{B}\right)}{\pi} \]
        3. +-commutative63.9%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\left(C - A\right) - \sqrt{\color{blue}{{B}^{2} + {\left(A - C\right)}^{2}}}}{B}\right)}{\pi} \]
        4. unpow263.9%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\left(C - A\right) - \sqrt{\color{blue}{B \cdot B} + {\left(A - C\right)}^{2}}}{B}\right)}{\pi} \]
        5. unpow263.9%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\left(C - A\right) - \sqrt{B \cdot B + \color{blue}{\left(A - C\right) \cdot \left(A - C\right)}}}{B}\right)}{\pi} \]
        6. hypot-define80.9%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\left(C - A\right) - \color{blue}{\mathsf{hypot}\left(B, A - C\right)}}{B}\right)}{\pi} \]
      3. Simplified80.9%

        \[\leadsto \color{blue}{180 \cdot \frac{\tan^{-1} \left(\frac{\left(C - A\right) - \mathsf{hypot}\left(B, A - C\right)}{B}\right)}{\pi}} \]
      4. Add Preprocessing
      5. Taylor expanded in A around inf 46.2%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\color{blue}{-2 \cdot A}}{B}\right)}{\pi} \]
      6. Step-by-step derivation
        1. *-commutative46.2%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\color{blue}{A \cdot -2}}{B}\right)}{\pi} \]
      7. Simplified46.2%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\color{blue}{A \cdot -2}}{B}\right)}{\pi} \]

      if 6.5000000000000001e-14 < B

      1. Initial program 51.1%

        \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
      2. Add Preprocessing
      3. Taylor expanded in B around inf 57.7%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{-1}}{\pi} \]
    3. Recombined 4 regimes into one program.
    4. Add Preprocessing

    Alternative 12: 47.9% accurate, 3.4× speedup?

    \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;B \leq -3.4 \cdot 10^{-81}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} 1}{\pi}\\ \mathbf{elif}\;B \leq 1.05 \cdot 10^{-282}:\\ \;\;\;\;\frac{180 \cdot \tan^{-1} \left(\frac{C}{B}\right)}{\pi}\\ \mathbf{elif}\;B \leq 7.2 \cdot 10^{-14}:\\ \;\;\;\;\frac{180 \cdot \tan^{-1} \left(\frac{A}{-B}\right)}{\pi}\\ \mathbf{else}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} -1}{\pi}\\ \end{array} \end{array} \]
    (FPCore (A B C)
     :precision binary64
     (if (<= B -3.4e-81)
       (* 180.0 (/ (atan 1.0) PI))
       (if (<= B 1.05e-282)
         (/ (* 180.0 (atan (/ C B))) PI)
         (if (<= B 7.2e-14)
           (/ (* 180.0 (atan (/ A (- B)))) PI)
           (* 180.0 (/ (atan -1.0) PI))))))
    double code(double A, double B, double C) {
    	double tmp;
    	if (B <= -3.4e-81) {
    		tmp = 180.0 * (atan(1.0) / ((double) M_PI));
    	} else if (B <= 1.05e-282) {
    		tmp = (180.0 * atan((C / B))) / ((double) M_PI);
    	} else if (B <= 7.2e-14) {
    		tmp = (180.0 * atan((A / -B))) / ((double) M_PI);
    	} else {
    		tmp = 180.0 * (atan(-1.0) / ((double) M_PI));
    	}
    	return tmp;
    }
    
    public static double code(double A, double B, double C) {
    	double tmp;
    	if (B <= -3.4e-81) {
    		tmp = 180.0 * (Math.atan(1.0) / Math.PI);
    	} else if (B <= 1.05e-282) {
    		tmp = (180.0 * Math.atan((C / B))) / Math.PI;
    	} else if (B <= 7.2e-14) {
    		tmp = (180.0 * Math.atan((A / -B))) / Math.PI;
    	} else {
    		tmp = 180.0 * (Math.atan(-1.0) / Math.PI);
    	}
    	return tmp;
    }
    
    def code(A, B, C):
    	tmp = 0
    	if B <= -3.4e-81:
    		tmp = 180.0 * (math.atan(1.0) / math.pi)
    	elif B <= 1.05e-282:
    		tmp = (180.0 * math.atan((C / B))) / math.pi
    	elif B <= 7.2e-14:
    		tmp = (180.0 * math.atan((A / -B))) / math.pi
    	else:
    		tmp = 180.0 * (math.atan(-1.0) / math.pi)
    	return tmp
    
    function code(A, B, C)
    	tmp = 0.0
    	if (B <= -3.4e-81)
    		tmp = Float64(180.0 * Float64(atan(1.0) / pi));
    	elseif (B <= 1.05e-282)
    		tmp = Float64(Float64(180.0 * atan(Float64(C / B))) / pi);
    	elseif (B <= 7.2e-14)
    		tmp = Float64(Float64(180.0 * atan(Float64(A / Float64(-B)))) / pi);
    	else
    		tmp = Float64(180.0 * Float64(atan(-1.0) / pi));
    	end
    	return tmp
    end
    
    function tmp_2 = code(A, B, C)
    	tmp = 0.0;
    	if (B <= -3.4e-81)
    		tmp = 180.0 * (atan(1.0) / pi);
    	elseif (B <= 1.05e-282)
    		tmp = (180.0 * atan((C / B))) / pi;
    	elseif (B <= 7.2e-14)
    		tmp = (180.0 * atan((A / -B))) / pi;
    	else
    		tmp = 180.0 * (atan(-1.0) / pi);
    	end
    	tmp_2 = tmp;
    end
    
    code[A_, B_, C_] := If[LessEqual[B, -3.4e-81], N[(180.0 * N[(N[ArcTan[1.0], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision], If[LessEqual[B, 1.05e-282], N[(N[(180.0 * N[ArcTan[N[(C / B), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] / Pi), $MachinePrecision], If[LessEqual[B, 7.2e-14], N[(N[(180.0 * N[ArcTan[N[(A / (-B)), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] / Pi), $MachinePrecision], N[(180.0 * N[(N[ArcTan[-1.0], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision]]]]
    
    \begin{array}{l}
    
    \\
    \begin{array}{l}
    \mathbf{if}\;B \leq -3.4 \cdot 10^{-81}:\\
    \;\;\;\;180 \cdot \frac{\tan^{-1} 1}{\pi}\\
    
    \mathbf{elif}\;B \leq 1.05 \cdot 10^{-282}:\\
    \;\;\;\;\frac{180 \cdot \tan^{-1} \left(\frac{C}{B}\right)}{\pi}\\
    
    \mathbf{elif}\;B \leq 7.2 \cdot 10^{-14}:\\
    \;\;\;\;\frac{180 \cdot \tan^{-1} \left(\frac{A}{-B}\right)}{\pi}\\
    
    \mathbf{else}:\\
    \;\;\;\;180 \cdot \frac{\tan^{-1} -1}{\pi}\\
    
    
    \end{array}
    \end{array}
    
    Derivation
    1. Split input into 4 regimes
    2. if B < -3.3999999999999999e-81

      1. Initial program 56.0%

        \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
      2. Add Preprocessing
      3. Taylor expanded in B around -inf 60.7%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{1}}{\pi} \]

      if -3.3999999999999999e-81 < B < 1.05000000000000006e-282

      1. Initial program 68.1%

        \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
      2. Add Preprocessing
      3. Step-by-step derivation
        1. associate-*r/68.1%

          \[\leadsto \color{blue}{\frac{180 \cdot \tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi}} \]
      4. Applied egg-rr86.8%

        \[\leadsto \color{blue}{\frac{180 \cdot \tan^{-1} \left(\frac{\left(C - A\right) - \mathsf{hypot}\left(B, A - C\right)}{B}\right)}{\pi}} \]
      5. Taylor expanded in B around -inf 57.6%

        \[\leadsto \frac{180 \cdot \tan^{-1} \color{blue}{\left(\left(1 + \frac{C}{B}\right) - \frac{A}{B}\right)}}{\pi} \]
      6. Step-by-step derivation
        1. associate--l+57.6%

          \[\leadsto \frac{180 \cdot \tan^{-1} \color{blue}{\left(1 + \left(\frac{C}{B} - \frac{A}{B}\right)\right)}}{\pi} \]
        2. div-sub59.7%

          \[\leadsto \frac{180 \cdot \tan^{-1} \left(1 + \color{blue}{\frac{C - A}{B}}\right)}{\pi} \]
      7. Simplified59.7%

        \[\leadsto \frac{180 \cdot \tan^{-1} \color{blue}{\left(1 + \frac{C - A}{B}\right)}}{\pi} \]
      8. Taylor expanded in C around inf 47.3%

        \[\leadsto \frac{180 \cdot \tan^{-1} \color{blue}{\left(\frac{C}{B}\right)}}{\pi} \]

      if 1.05000000000000006e-282 < B < 7.1999999999999996e-14

      1. Initial program 63.9%

        \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
      2. Add Preprocessing
      3. Step-by-step derivation
        1. associate-*r/63.9%

          \[\leadsto \color{blue}{\frac{180 \cdot \tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi}} \]
      4. Applied egg-rr80.8%

        \[\leadsto \color{blue}{\frac{180 \cdot \tan^{-1} \left(\frac{\left(C - A\right) - \mathsf{hypot}\left(B, A - C\right)}{B}\right)}{\pi}} \]
      5. Taylor expanded in B around -inf 53.1%

        \[\leadsto \frac{180 \cdot \tan^{-1} \color{blue}{\left(\left(1 + \frac{C}{B}\right) - \frac{A}{B}\right)}}{\pi} \]
      6. Step-by-step derivation
        1. associate--l+53.1%

          \[\leadsto \frac{180 \cdot \tan^{-1} \color{blue}{\left(1 + \left(\frac{C}{B} - \frac{A}{B}\right)\right)}}{\pi} \]
        2. div-sub56.3%

          \[\leadsto \frac{180 \cdot \tan^{-1} \left(1 + \color{blue}{\frac{C - A}{B}}\right)}{\pi} \]
      7. Simplified56.3%

        \[\leadsto \frac{180 \cdot \tan^{-1} \color{blue}{\left(1 + \frac{C - A}{B}\right)}}{\pi} \]
      8. Taylor expanded in A around inf 46.2%

        \[\leadsto \frac{180 \cdot \tan^{-1} \color{blue}{\left(-1 \cdot \frac{A}{B}\right)}}{\pi} \]
      9. Step-by-step derivation
        1. associate-*r/46.2%

          \[\leadsto \frac{180 \cdot \tan^{-1} \color{blue}{\left(\frac{-1 \cdot A}{B}\right)}}{\pi} \]
        2. mul-1-neg46.2%

          \[\leadsto \frac{180 \cdot \tan^{-1} \left(\frac{\color{blue}{-A}}{B}\right)}{\pi} \]
      10. Simplified46.2%

        \[\leadsto \frac{180 \cdot \tan^{-1} \color{blue}{\left(\frac{-A}{B}\right)}}{\pi} \]

      if 7.1999999999999996e-14 < B

      1. Initial program 51.1%

        \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
      2. Add Preprocessing
      3. Taylor expanded in B around inf 57.7%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{-1}}{\pi} \]
    3. Recombined 4 regimes into one program.
    4. Final simplification54.0%

      \[\leadsto \begin{array}{l} \mathbf{if}\;B \leq -3.4 \cdot 10^{-81}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} 1}{\pi}\\ \mathbf{elif}\;B \leq 1.05 \cdot 10^{-282}:\\ \;\;\;\;\frac{180 \cdot \tan^{-1} \left(\frac{C}{B}\right)}{\pi}\\ \mathbf{elif}\;B \leq 7.2 \cdot 10^{-14}:\\ \;\;\;\;\frac{180 \cdot \tan^{-1} \left(\frac{A}{-B}\right)}{\pi}\\ \mathbf{else}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} -1}{\pi}\\ \end{array} \]
    5. Add Preprocessing

    Alternative 13: 67.1% accurate, 3.6× speedup?

    \[\begin{array}{l} \\ \begin{array}{l} t_0 := \frac{C - A}{B}\\ \mathbf{if}\;B \leq -4 \cdot 10^{-163}:\\ \;\;\;\;\frac{1}{\frac{\frac{\pi}{180}}{\tan^{-1} \left(1 + t\_0\right)}}\\ \mathbf{else}:\\ \;\;\;\;\frac{180 \cdot \tan^{-1} \left(t\_0 + -1\right)}{\pi}\\ \end{array} \end{array} \]
    (FPCore (A B C)
     :precision binary64
     (let* ((t_0 (/ (- C A) B)))
       (if (<= B -4e-163)
         (/ 1.0 (/ (/ PI 180.0) (atan (+ 1.0 t_0))))
         (/ (* 180.0 (atan (+ t_0 -1.0))) PI))))
    double code(double A, double B, double C) {
    	double t_0 = (C - A) / B;
    	double tmp;
    	if (B <= -4e-163) {
    		tmp = 1.0 / ((((double) M_PI) / 180.0) / atan((1.0 + t_0)));
    	} else {
    		tmp = (180.0 * atan((t_0 + -1.0))) / ((double) M_PI);
    	}
    	return tmp;
    }
    
    public static double code(double A, double B, double C) {
    	double t_0 = (C - A) / B;
    	double tmp;
    	if (B <= -4e-163) {
    		tmp = 1.0 / ((Math.PI / 180.0) / Math.atan((1.0 + t_0)));
    	} else {
    		tmp = (180.0 * Math.atan((t_0 + -1.0))) / Math.PI;
    	}
    	return tmp;
    }
    
    def code(A, B, C):
    	t_0 = (C - A) / B
    	tmp = 0
    	if B <= -4e-163:
    		tmp = 1.0 / ((math.pi / 180.0) / math.atan((1.0 + t_0)))
    	else:
    		tmp = (180.0 * math.atan((t_0 + -1.0))) / math.pi
    	return tmp
    
    function code(A, B, C)
    	t_0 = Float64(Float64(C - A) / B)
    	tmp = 0.0
    	if (B <= -4e-163)
    		tmp = Float64(1.0 / Float64(Float64(pi / 180.0) / atan(Float64(1.0 + t_0))));
    	else
    		tmp = Float64(Float64(180.0 * atan(Float64(t_0 + -1.0))) / pi);
    	end
    	return tmp
    end
    
    function tmp_2 = code(A, B, C)
    	t_0 = (C - A) / B;
    	tmp = 0.0;
    	if (B <= -4e-163)
    		tmp = 1.0 / ((pi / 180.0) / atan((1.0 + t_0)));
    	else
    		tmp = (180.0 * atan((t_0 + -1.0))) / pi;
    	end
    	tmp_2 = tmp;
    end
    
    code[A_, B_, C_] := Block[{t$95$0 = N[(N[(C - A), $MachinePrecision] / B), $MachinePrecision]}, If[LessEqual[B, -4e-163], N[(1.0 / N[(N[(Pi / 180.0), $MachinePrecision] / N[ArcTan[N[(1.0 + t$95$0), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision], N[(N[(180.0 * N[ArcTan[N[(t$95$0 + -1.0), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] / Pi), $MachinePrecision]]]
    
    \begin{array}{l}
    
    \\
    \begin{array}{l}
    t_0 := \frac{C - A}{B}\\
    \mathbf{if}\;B \leq -4 \cdot 10^{-163}:\\
    \;\;\;\;\frac{1}{\frac{\frac{\pi}{180}}{\tan^{-1} \left(1 + t\_0\right)}}\\
    
    \mathbf{else}:\\
    \;\;\;\;\frac{180 \cdot \tan^{-1} \left(t\_0 + -1\right)}{\pi}\\
    
    
    \end{array}
    \end{array}
    
    Derivation
    1. Split input into 2 regimes
    2. if B < -3.99999999999999969e-163

      1. Initial program 57.9%

        \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
      2. Add Preprocessing
      3. Step-by-step derivation
        1. associate-*r/57.9%

          \[\leadsto \color{blue}{\frac{180 \cdot \tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi}} \]
      4. Applied egg-rr80.9%

        \[\leadsto \color{blue}{\frac{180 \cdot \tan^{-1} \left(\frac{\left(C - A\right) - \mathsf{hypot}\left(B, A - C\right)}{B}\right)}{\pi}} \]
      5. Taylor expanded in B around -inf 75.6%

        \[\leadsto \frac{180 \cdot \tan^{-1} \color{blue}{\left(\left(1 + \frac{C}{B}\right) - \frac{A}{B}\right)}}{\pi} \]
      6. Step-by-step derivation
        1. associate--l+75.6%

          \[\leadsto \frac{180 \cdot \tan^{-1} \color{blue}{\left(1 + \left(\frac{C}{B} - \frac{A}{B}\right)\right)}}{\pi} \]
        2. div-sub75.6%

          \[\leadsto \frac{180 \cdot \tan^{-1} \left(1 + \color{blue}{\frac{C - A}{B}}\right)}{\pi} \]
      7. Simplified75.6%

        \[\leadsto \frac{180 \cdot \tan^{-1} \color{blue}{\left(1 + \frac{C - A}{B}\right)}}{\pi} \]
      8. Step-by-step derivation
        1. clear-num75.6%

          \[\leadsto \color{blue}{\frac{1}{\frac{\pi}{180 \cdot \tan^{-1} \left(1 + \frac{C - A}{B}\right)}}} \]
        2. inv-pow75.6%

          \[\leadsto \color{blue}{{\left(\frac{\pi}{180 \cdot \tan^{-1} \left(1 + \frac{C - A}{B}\right)}\right)}^{-1}} \]
      9. Applied egg-rr75.6%

        \[\leadsto \color{blue}{{\left(\frac{\pi}{180 \cdot \tan^{-1} \left(1 + \frac{C - A}{B}\right)}\right)}^{-1}} \]
      10. Step-by-step derivation
        1. unpow-175.6%

          \[\leadsto \color{blue}{\frac{1}{\frac{\pi}{180 \cdot \tan^{-1} \left(1 + \frac{C - A}{B}\right)}}} \]
        2. associate-/r*75.6%

          \[\leadsto \frac{1}{\color{blue}{\frac{\frac{\pi}{180}}{\tan^{-1} \left(1 + \frac{C - A}{B}\right)}}} \]
      11. Simplified75.6%

        \[\leadsto \color{blue}{\frac{1}{\frac{\frac{\pi}{180}}{\tan^{-1} \left(1 + \frac{C - A}{B}\right)}}} \]

      if -3.99999999999999969e-163 < B

      1. Initial program 59.7%

        \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
      2. Add Preprocessing
      3. Step-by-step derivation
        1. associate-*r/59.7%

          \[\leadsto \color{blue}{\frac{180 \cdot \tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi}} \]
      4. Applied egg-rr83.9%

        \[\leadsto \color{blue}{\frac{180 \cdot \tan^{-1} \left(\frac{\left(C - A\right) - \mathsf{hypot}\left(B, A - C\right)}{B}\right)}{\pi}} \]
      5. Taylor expanded in B around inf 67.5%

        \[\leadsto \frac{180 \cdot \tan^{-1} \color{blue}{\left(\frac{C}{B} - \left(1 + \frac{A}{B}\right)\right)}}{\pi} \]
      6. Step-by-step derivation
        1. +-commutative67.5%

          \[\leadsto \frac{180 \cdot \tan^{-1} \left(\frac{C}{B} - \color{blue}{\left(\frac{A}{B} + 1\right)}\right)}{\pi} \]
        2. associate--r+67.5%

          \[\leadsto \frac{180 \cdot \tan^{-1} \color{blue}{\left(\left(\frac{C}{B} - \frac{A}{B}\right) - 1\right)}}{\pi} \]
        3. div-sub69.5%

          \[\leadsto \frac{180 \cdot \tan^{-1} \left(\color{blue}{\frac{C - A}{B}} - 1\right)}{\pi} \]
      7. Simplified69.5%

        \[\leadsto \frac{180 \cdot \tan^{-1} \color{blue}{\left(\frac{C - A}{B} - 1\right)}}{\pi} \]
    3. Recombined 2 regimes into one program.
    4. Final simplification72.0%

      \[\leadsto \begin{array}{l} \mathbf{if}\;B \leq -4 \cdot 10^{-163}:\\ \;\;\;\;\frac{1}{\frac{\frac{\pi}{180}}{\tan^{-1} \left(1 + \frac{C - A}{B}\right)}}\\ \mathbf{else}:\\ \;\;\;\;\frac{180 \cdot \tan^{-1} \left(\frac{C - A}{B} + -1\right)}{\pi}\\ \end{array} \]
    5. Add Preprocessing

    Alternative 14: 47.7% accurate, 3.6× speedup?

    \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;B \leq -1.25 \cdot 10^{-80}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} 1}{\pi}\\ \mathbf{elif}\;B \leq 2.3 \cdot 10^{-111}:\\ \;\;\;\;\frac{180 \cdot \tan^{-1} \left(\frac{C}{B}\right)}{\pi}\\ \mathbf{else}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} -1}{\pi}\\ \end{array} \end{array} \]
    (FPCore (A B C)
     :precision binary64
     (if (<= B -1.25e-80)
       (* 180.0 (/ (atan 1.0) PI))
       (if (<= B 2.3e-111)
         (/ (* 180.0 (atan (/ C B))) PI)
         (* 180.0 (/ (atan -1.0) PI)))))
    double code(double A, double B, double C) {
    	double tmp;
    	if (B <= -1.25e-80) {
    		tmp = 180.0 * (atan(1.0) / ((double) M_PI));
    	} else if (B <= 2.3e-111) {
    		tmp = (180.0 * atan((C / B))) / ((double) M_PI);
    	} else {
    		tmp = 180.0 * (atan(-1.0) / ((double) M_PI));
    	}
    	return tmp;
    }
    
    public static double code(double A, double B, double C) {
    	double tmp;
    	if (B <= -1.25e-80) {
    		tmp = 180.0 * (Math.atan(1.0) / Math.PI);
    	} else if (B <= 2.3e-111) {
    		tmp = (180.0 * Math.atan((C / B))) / Math.PI;
    	} else {
    		tmp = 180.0 * (Math.atan(-1.0) / Math.PI);
    	}
    	return tmp;
    }
    
    def code(A, B, C):
    	tmp = 0
    	if B <= -1.25e-80:
    		tmp = 180.0 * (math.atan(1.0) / math.pi)
    	elif B <= 2.3e-111:
    		tmp = (180.0 * math.atan((C / B))) / math.pi
    	else:
    		tmp = 180.0 * (math.atan(-1.0) / math.pi)
    	return tmp
    
    function code(A, B, C)
    	tmp = 0.0
    	if (B <= -1.25e-80)
    		tmp = Float64(180.0 * Float64(atan(1.0) / pi));
    	elseif (B <= 2.3e-111)
    		tmp = Float64(Float64(180.0 * atan(Float64(C / B))) / pi);
    	else
    		tmp = Float64(180.0 * Float64(atan(-1.0) / pi));
    	end
    	return tmp
    end
    
    function tmp_2 = code(A, B, C)
    	tmp = 0.0;
    	if (B <= -1.25e-80)
    		tmp = 180.0 * (atan(1.0) / pi);
    	elseif (B <= 2.3e-111)
    		tmp = (180.0 * atan((C / B))) / pi;
    	else
    		tmp = 180.0 * (atan(-1.0) / pi);
    	end
    	tmp_2 = tmp;
    end
    
    code[A_, B_, C_] := If[LessEqual[B, -1.25e-80], N[(180.0 * N[(N[ArcTan[1.0], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision], If[LessEqual[B, 2.3e-111], N[(N[(180.0 * N[ArcTan[N[(C / B), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] / Pi), $MachinePrecision], N[(180.0 * N[(N[ArcTan[-1.0], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision]]]
    
    \begin{array}{l}
    
    \\
    \begin{array}{l}
    \mathbf{if}\;B \leq -1.25 \cdot 10^{-80}:\\
    \;\;\;\;180 \cdot \frac{\tan^{-1} 1}{\pi}\\
    
    \mathbf{elif}\;B \leq 2.3 \cdot 10^{-111}:\\
    \;\;\;\;\frac{180 \cdot \tan^{-1} \left(\frac{C}{B}\right)}{\pi}\\
    
    \mathbf{else}:\\
    \;\;\;\;180 \cdot \frac{\tan^{-1} -1}{\pi}\\
    
    
    \end{array}
    \end{array}
    
    Derivation
    1. Split input into 3 regimes
    2. if B < -1.25e-80

      1. Initial program 56.0%

        \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
      2. Add Preprocessing
      3. Taylor expanded in B around -inf 60.7%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{1}}{\pi} \]

      if -1.25e-80 < B < 2.3e-111

      1. Initial program 66.2%

        \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
      2. Add Preprocessing
      3. Step-by-step derivation
        1. associate-*r/66.2%

          \[\leadsto \color{blue}{\frac{180 \cdot \tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi}} \]
      4. Applied egg-rr85.9%

        \[\leadsto \color{blue}{\frac{180 \cdot \tan^{-1} \left(\frac{\left(C - A\right) - \mathsf{hypot}\left(B, A - C\right)}{B}\right)}{\pi}} \]
      5. Taylor expanded in B around -inf 57.6%

        \[\leadsto \frac{180 \cdot \tan^{-1} \color{blue}{\left(\left(1 + \frac{C}{B}\right) - \frac{A}{B}\right)}}{\pi} \]
      6. Step-by-step derivation
        1. associate--l+57.6%

          \[\leadsto \frac{180 \cdot \tan^{-1} \color{blue}{\left(1 + \left(\frac{C}{B} - \frac{A}{B}\right)\right)}}{\pi} \]
        2. div-sub61.0%

          \[\leadsto \frac{180 \cdot \tan^{-1} \left(1 + \color{blue}{\frac{C - A}{B}}\right)}{\pi} \]
      7. Simplified61.0%

        \[\leadsto \frac{180 \cdot \tan^{-1} \color{blue}{\left(1 + \frac{C - A}{B}\right)}}{\pi} \]
      8. Taylor expanded in C around inf 41.6%

        \[\leadsto \frac{180 \cdot \tan^{-1} \color{blue}{\left(\frac{C}{B}\right)}}{\pi} \]

      if 2.3e-111 < B

      1. Initial program 54.2%

        \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
      2. Add Preprocessing
      3. Taylor expanded in B around inf 50.4%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{-1}}{\pi} \]
    3. Recombined 3 regimes into one program.
    4. Add Preprocessing

    Alternative 15: 67.3% accurate, 3.6× speedup?

    \[\begin{array}{l} \\ \begin{array}{l} t_0 := \frac{C - A}{B}\\ \mathbf{if}\;B \leq -1 \cdot 10^{-251}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(1 + t\_0\right)}{\pi}\\ \mathbf{else}:\\ \;\;\;\;\frac{180 \cdot \tan^{-1} \left(t\_0 + -1\right)}{\pi}\\ \end{array} \end{array} \]
    (FPCore (A B C)
     :precision binary64
     (let* ((t_0 (/ (- C A) B)))
       (if (<= B -1e-251)
         (* 180.0 (/ (atan (+ 1.0 t_0)) PI))
         (/ (* 180.0 (atan (+ t_0 -1.0))) PI))))
    double code(double A, double B, double C) {
    	double t_0 = (C - A) / B;
    	double tmp;
    	if (B <= -1e-251) {
    		tmp = 180.0 * (atan((1.0 + t_0)) / ((double) M_PI));
    	} else {
    		tmp = (180.0 * atan((t_0 + -1.0))) / ((double) M_PI);
    	}
    	return tmp;
    }
    
    public static double code(double A, double B, double C) {
    	double t_0 = (C - A) / B;
    	double tmp;
    	if (B <= -1e-251) {
    		tmp = 180.0 * (Math.atan((1.0 + t_0)) / Math.PI);
    	} else {
    		tmp = (180.0 * Math.atan((t_0 + -1.0))) / Math.PI;
    	}
    	return tmp;
    }
    
    def code(A, B, C):
    	t_0 = (C - A) / B
    	tmp = 0
    	if B <= -1e-251:
    		tmp = 180.0 * (math.atan((1.0 + t_0)) / math.pi)
    	else:
    		tmp = (180.0 * math.atan((t_0 + -1.0))) / math.pi
    	return tmp
    
    function code(A, B, C)
    	t_0 = Float64(Float64(C - A) / B)
    	tmp = 0.0
    	if (B <= -1e-251)
    		tmp = Float64(180.0 * Float64(atan(Float64(1.0 + t_0)) / pi));
    	else
    		tmp = Float64(Float64(180.0 * atan(Float64(t_0 + -1.0))) / pi);
    	end
    	return tmp
    end
    
    function tmp_2 = code(A, B, C)
    	t_0 = (C - A) / B;
    	tmp = 0.0;
    	if (B <= -1e-251)
    		tmp = 180.0 * (atan((1.0 + t_0)) / pi);
    	else
    		tmp = (180.0 * atan((t_0 + -1.0))) / pi;
    	end
    	tmp_2 = tmp;
    end
    
    code[A_, B_, C_] := Block[{t$95$0 = N[(N[(C - A), $MachinePrecision] / B), $MachinePrecision]}, If[LessEqual[B, -1e-251], N[(180.0 * N[(N[ArcTan[N[(1.0 + t$95$0), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision], N[(N[(180.0 * N[ArcTan[N[(t$95$0 + -1.0), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] / Pi), $MachinePrecision]]]
    
    \begin{array}{l}
    
    \\
    \begin{array}{l}
    t_0 := \frac{C - A}{B}\\
    \mathbf{if}\;B \leq -1 \cdot 10^{-251}:\\
    \;\;\;\;180 \cdot \frac{\tan^{-1} \left(1 + t\_0\right)}{\pi}\\
    
    \mathbf{else}:\\
    \;\;\;\;\frac{180 \cdot \tan^{-1} \left(t\_0 + -1\right)}{\pi}\\
    
    
    \end{array}
    \end{array}
    
    Derivation
    1. Split input into 2 regimes
    2. if B < -1.00000000000000002e-251

      1. Initial program 57.5%

        \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
      2. Add Preprocessing
      3. Taylor expanded in B around -inf 72.1%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\left(1 + \frac{C}{B}\right) - \frac{A}{B}\right)}}{\pi} \]
      4. Step-by-step derivation
        1. associate--l+72.1%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(1 + \left(\frac{C}{B} - \frac{A}{B}\right)\right)}}{\pi} \]
        2. div-sub73.0%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \color{blue}{\frac{C - A}{B}}\right)}{\pi} \]
      5. Simplified73.0%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(1 + \frac{C - A}{B}\right)}}{\pi} \]

      if -1.00000000000000002e-251 < B

      1. Initial program 60.2%

        \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
      2. Add Preprocessing
      3. Step-by-step derivation
        1. associate-*r/60.2%

          \[\leadsto \color{blue}{\frac{180 \cdot \tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi}} \]
      4. Applied egg-rr82.9%

        \[\leadsto \color{blue}{\frac{180 \cdot \tan^{-1} \left(\frac{\left(C - A\right) - \mathsf{hypot}\left(B, A - C\right)}{B}\right)}{\pi}} \]
      5. Taylor expanded in B around inf 69.7%

        \[\leadsto \frac{180 \cdot \tan^{-1} \color{blue}{\left(\frac{C}{B} - \left(1 + \frac{A}{B}\right)\right)}}{\pi} \]
      6. Step-by-step derivation
        1. +-commutative69.7%

          \[\leadsto \frac{180 \cdot \tan^{-1} \left(\frac{C}{B} - \color{blue}{\left(\frac{A}{B} + 1\right)}\right)}{\pi} \]
        2. associate--r+69.7%

          \[\leadsto \frac{180 \cdot \tan^{-1} \color{blue}{\left(\left(\frac{C}{B} - \frac{A}{B}\right) - 1\right)}}{\pi} \]
        3. div-sub71.1%

          \[\leadsto \frac{180 \cdot \tan^{-1} \left(\color{blue}{\frac{C - A}{B}} - 1\right)}{\pi} \]
      7. Simplified71.1%

        \[\leadsto \frac{180 \cdot \tan^{-1} \color{blue}{\left(\frac{C - A}{B} - 1\right)}}{\pi} \]
    3. Recombined 2 regimes into one program.
    4. Final simplification72.0%

      \[\leadsto \begin{array}{l} \mathbf{if}\;B \leq -1 \cdot 10^{-251}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(1 + \frac{C - A}{B}\right)}{\pi}\\ \mathbf{else}:\\ \;\;\;\;\frac{180 \cdot \tan^{-1} \left(\frac{C - A}{B} + -1\right)}{\pi}\\ \end{array} \]
    5. Add Preprocessing

    Alternative 16: 61.1% accurate, 3.6× speedup?

    \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;C \leq 4.1 \cdot 10^{+57}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(1 + \frac{C - A}{B}\right)}{\pi}\\ \mathbf{else}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(-0.5 \cdot \frac{B}{C}\right)}{\pi}\\ \end{array} \end{array} \]
    (FPCore (A B C)
     :precision binary64
     (if (<= C 4.1e+57)
       (* 180.0 (/ (atan (+ 1.0 (/ (- C A) B))) PI))
       (* 180.0 (/ (atan (* -0.5 (/ B C))) PI))))
    double code(double A, double B, double C) {
    	double tmp;
    	if (C <= 4.1e+57) {
    		tmp = 180.0 * (atan((1.0 + ((C - A) / B))) / ((double) M_PI));
    	} else {
    		tmp = 180.0 * (atan((-0.5 * (B / C))) / ((double) M_PI));
    	}
    	return tmp;
    }
    
    public static double code(double A, double B, double C) {
    	double tmp;
    	if (C <= 4.1e+57) {
    		tmp = 180.0 * (Math.atan((1.0 + ((C - A) / B))) / Math.PI);
    	} else {
    		tmp = 180.0 * (Math.atan((-0.5 * (B / C))) / Math.PI);
    	}
    	return tmp;
    }
    
    def code(A, B, C):
    	tmp = 0
    	if C <= 4.1e+57:
    		tmp = 180.0 * (math.atan((1.0 + ((C - A) / B))) / math.pi)
    	else:
    		tmp = 180.0 * (math.atan((-0.5 * (B / C))) / math.pi)
    	return tmp
    
    function code(A, B, C)
    	tmp = 0.0
    	if (C <= 4.1e+57)
    		tmp = Float64(180.0 * Float64(atan(Float64(1.0 + Float64(Float64(C - A) / B))) / pi));
    	else
    		tmp = Float64(180.0 * Float64(atan(Float64(-0.5 * Float64(B / C))) / pi));
    	end
    	return tmp
    end
    
    function tmp_2 = code(A, B, C)
    	tmp = 0.0;
    	if (C <= 4.1e+57)
    		tmp = 180.0 * (atan((1.0 + ((C - A) / B))) / pi);
    	else
    		tmp = 180.0 * (atan((-0.5 * (B / C))) / pi);
    	end
    	tmp_2 = tmp;
    end
    
    code[A_, B_, C_] := If[LessEqual[C, 4.1e+57], N[(180.0 * N[(N[ArcTan[N[(1.0 + N[(N[(C - A), $MachinePrecision] / B), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision], N[(180.0 * N[(N[ArcTan[N[(-0.5 * N[(B / C), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision]]
    
    \begin{array}{l}
    
    \\
    \begin{array}{l}
    \mathbf{if}\;C \leq 4.1 \cdot 10^{+57}:\\
    \;\;\;\;180 \cdot \frac{\tan^{-1} \left(1 + \frac{C - A}{B}\right)}{\pi}\\
    
    \mathbf{else}:\\
    \;\;\;\;180 \cdot \frac{\tan^{-1} \left(-0.5 \cdot \frac{B}{C}\right)}{\pi}\\
    
    
    \end{array}
    \end{array}
    
    Derivation
    1. Split input into 2 regimes
    2. if C < 4.1e57

      1. Initial program 67.0%

        \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
      2. Add Preprocessing
      3. Taylor expanded in B around -inf 66.3%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\left(1 + \frac{C}{B}\right) - \frac{A}{B}\right)}}{\pi} \]
      4. Step-by-step derivation
        1. associate--l+66.3%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(1 + \left(\frac{C}{B} - \frac{A}{B}\right)\right)}}{\pi} \]
        2. div-sub66.8%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \color{blue}{\frac{C - A}{B}}\right)}{\pi} \]
      5. Simplified66.8%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(1 + \frac{C - A}{B}\right)}}{\pi} \]

      if 4.1e57 < C

      1. Initial program 23.3%

        \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
      2. Add Preprocessing
      3. Taylor expanded in A around 0 17.8%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{C - \sqrt{{B}^{2} + {C}^{2}}}{B}\right)}}{\pi} \]
      4. Step-by-step derivation
        1. +-commutative17.8%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{C - \sqrt{\color{blue}{{C}^{2} + {B}^{2}}}}{B}\right)}{\pi} \]
        2. unpow217.8%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{C - \sqrt{\color{blue}{C \cdot C} + {B}^{2}}}{B}\right)}{\pi} \]
        3. unpow217.8%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{C - \sqrt{C \cdot C + \color{blue}{B \cdot B}}}{B}\right)}{\pi} \]
        4. hypot-define47.5%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{C - \color{blue}{\mathsf{hypot}\left(C, B\right)}}{B}\right)}{\pi} \]
      5. Simplified47.5%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{C - \mathsf{hypot}\left(C, B\right)}{B}\right)}}{\pi} \]
      6. Taylor expanded in C around inf 74.5%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(-0.5 \cdot \frac{B}{C}\right)}}{\pi} \]
    3. Recombined 2 regimes into one program.
    4. Add Preprocessing

    Alternative 17: 44.8% accurate, 3.6× speedup?

    \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;B \leq -1.2 \cdot 10^{-175}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} 1}{\pi}\\ \mathbf{elif}\;B \leq 1.38 \cdot 10^{-98}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} 0}{\pi}\\ \mathbf{else}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} -1}{\pi}\\ \end{array} \end{array} \]
    (FPCore (A B C)
     :precision binary64
     (if (<= B -1.2e-175)
       (* 180.0 (/ (atan 1.0) PI))
       (if (<= B 1.38e-98)
         (* 180.0 (/ (atan 0.0) PI))
         (* 180.0 (/ (atan -1.0) PI)))))
    double code(double A, double B, double C) {
    	double tmp;
    	if (B <= -1.2e-175) {
    		tmp = 180.0 * (atan(1.0) / ((double) M_PI));
    	} else if (B <= 1.38e-98) {
    		tmp = 180.0 * (atan(0.0) / ((double) M_PI));
    	} else {
    		tmp = 180.0 * (atan(-1.0) / ((double) M_PI));
    	}
    	return tmp;
    }
    
    public static double code(double A, double B, double C) {
    	double tmp;
    	if (B <= -1.2e-175) {
    		tmp = 180.0 * (Math.atan(1.0) / Math.PI);
    	} else if (B <= 1.38e-98) {
    		tmp = 180.0 * (Math.atan(0.0) / Math.PI);
    	} else {
    		tmp = 180.0 * (Math.atan(-1.0) / Math.PI);
    	}
    	return tmp;
    }
    
    def code(A, B, C):
    	tmp = 0
    	if B <= -1.2e-175:
    		tmp = 180.0 * (math.atan(1.0) / math.pi)
    	elif B <= 1.38e-98:
    		tmp = 180.0 * (math.atan(0.0) / math.pi)
    	else:
    		tmp = 180.0 * (math.atan(-1.0) / math.pi)
    	return tmp
    
    function code(A, B, C)
    	tmp = 0.0
    	if (B <= -1.2e-175)
    		tmp = Float64(180.0 * Float64(atan(1.0) / pi));
    	elseif (B <= 1.38e-98)
    		tmp = Float64(180.0 * Float64(atan(0.0) / pi));
    	else
    		tmp = Float64(180.0 * Float64(atan(-1.0) / pi));
    	end
    	return tmp
    end
    
    function tmp_2 = code(A, B, C)
    	tmp = 0.0;
    	if (B <= -1.2e-175)
    		tmp = 180.0 * (atan(1.0) / pi);
    	elseif (B <= 1.38e-98)
    		tmp = 180.0 * (atan(0.0) / pi);
    	else
    		tmp = 180.0 * (atan(-1.0) / pi);
    	end
    	tmp_2 = tmp;
    end
    
    code[A_, B_, C_] := If[LessEqual[B, -1.2e-175], N[(180.0 * N[(N[ArcTan[1.0], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision], If[LessEqual[B, 1.38e-98], N[(180.0 * N[(N[ArcTan[0.0], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision], N[(180.0 * N[(N[ArcTan[-1.0], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision]]]
    
    \begin{array}{l}
    
    \\
    \begin{array}{l}
    \mathbf{if}\;B \leq -1.2 \cdot 10^{-175}:\\
    \;\;\;\;180 \cdot \frac{\tan^{-1} 1}{\pi}\\
    
    \mathbf{elif}\;B \leq 1.38 \cdot 10^{-98}:\\
    \;\;\;\;180 \cdot \frac{\tan^{-1} 0}{\pi}\\
    
    \mathbf{else}:\\
    \;\;\;\;180 \cdot \frac{\tan^{-1} -1}{\pi}\\
    
    
    \end{array}
    \end{array}
    
    Derivation
    1. Split input into 3 regimes
    2. if B < -1.2e-175

      1. Initial program 58.7%

        \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
      2. Add Preprocessing
      3. Taylor expanded in B around -inf 52.6%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{1}}{\pi} \]

      if -1.2e-175 < B < 1.3800000000000001e-98

      1. Initial program 61.7%

        \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
      2. Add Preprocessing
      3. Step-by-step derivation
        1. *-commutative61.7%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \frac{1}{B}\right)}}{\pi} \]
        2. associate--l-60.1%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\color{blue}{\left(C - \left(A + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)} \cdot \frac{1}{B}\right)}{\pi} \]
        3. +-commutative60.1%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\left(C - \left(A + \sqrt{\color{blue}{{B}^{2} + {\left(A - C\right)}^{2}}}\right)\right) \cdot \frac{1}{B}\right)}{\pi} \]
        4. unpow260.1%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\left(C - \left(A + \sqrt{\color{blue}{B \cdot B} + {\left(A - C\right)}^{2}}\right)\right) \cdot \frac{1}{B}\right)}{\pi} \]
        5. unpow260.1%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\left(C - \left(A + \sqrt{B \cdot B + \color{blue}{\left(A - C\right) \cdot \left(A - C\right)}}\right)\right) \cdot \frac{1}{B}\right)}{\pi} \]
        6. hypot-undefine74.9%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\left(C - \left(A + \color{blue}{\mathsf{hypot}\left(B, A - C\right)}\right)\right) \cdot \frac{1}{B}\right)}{\pi} \]
        7. associate--r+86.0%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\color{blue}{\left(\left(C - A\right) - \mathsf{hypot}\left(B, A - C\right)\right)} \cdot \frac{1}{B}\right)}{\pi} \]
        8. div-inv86.0%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{\left(C - A\right) - \mathsf{hypot}\left(B, A - C\right)}{B}\right)}}{\pi} \]
        9. div-sub59.1%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{C - A}{B} - \frac{\mathsf{hypot}\left(B, A - C\right)}{B}\right)}}{\pi} \]
      4. Applied egg-rr59.1%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{C - A}{B} - \frac{\mathsf{hypot}\left(B, A - C\right)}{B}\right)}}{\pi} \]
      5. Taylor expanded in C around inf 17.3%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(-1 \cdot \left(-1 \cdot \frac{A}{B} + \frac{A}{B}\right)\right)}}{\pi} \]
      6. Step-by-step derivation
        1. distribute-lft1-in17.3%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(-1 \cdot \color{blue}{\left(\left(-1 + 1\right) \cdot \frac{A}{B}\right)}\right)}{\pi} \]
        2. metadata-eval17.3%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(-1 \cdot \left(\color{blue}{0} \cdot \frac{A}{B}\right)\right)}{\pi} \]
        3. mul0-lft29.5%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(-1 \cdot \color{blue}{0}\right)}{\pi} \]
        4. metadata-eval29.5%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{0}}{\pi} \]
      7. Simplified29.5%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{0}}{\pi} \]

      if 1.3800000000000001e-98 < B

      1. Initial program 56.8%

        \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
      2. Add Preprocessing
      3. Taylor expanded in B around inf 52.7%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{-1}}{\pi} \]
    3. Recombined 3 regimes into one program.
    4. Add Preprocessing

    Alternative 18: 29.4% accurate, 3.8× speedup?

    \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;B \leq 6.3 \cdot 10^{-99}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} 0}{\pi}\\ \mathbf{else}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} -1}{\pi}\\ \end{array} \end{array} \]
    (FPCore (A B C)
     :precision binary64
     (if (<= B 6.3e-99) (* 180.0 (/ (atan 0.0) PI)) (* 180.0 (/ (atan -1.0) PI))))
    double code(double A, double B, double C) {
    	double tmp;
    	if (B <= 6.3e-99) {
    		tmp = 180.0 * (atan(0.0) / ((double) M_PI));
    	} else {
    		tmp = 180.0 * (atan(-1.0) / ((double) M_PI));
    	}
    	return tmp;
    }
    
    public static double code(double A, double B, double C) {
    	double tmp;
    	if (B <= 6.3e-99) {
    		tmp = 180.0 * (Math.atan(0.0) / Math.PI);
    	} else {
    		tmp = 180.0 * (Math.atan(-1.0) / Math.PI);
    	}
    	return tmp;
    }
    
    def code(A, B, C):
    	tmp = 0
    	if B <= 6.3e-99:
    		tmp = 180.0 * (math.atan(0.0) / math.pi)
    	else:
    		tmp = 180.0 * (math.atan(-1.0) / math.pi)
    	return tmp
    
    function code(A, B, C)
    	tmp = 0.0
    	if (B <= 6.3e-99)
    		tmp = Float64(180.0 * Float64(atan(0.0) / pi));
    	else
    		tmp = Float64(180.0 * Float64(atan(-1.0) / pi));
    	end
    	return tmp
    end
    
    function tmp_2 = code(A, B, C)
    	tmp = 0.0;
    	if (B <= 6.3e-99)
    		tmp = 180.0 * (atan(0.0) / pi);
    	else
    		tmp = 180.0 * (atan(-1.0) / pi);
    	end
    	tmp_2 = tmp;
    end
    
    code[A_, B_, C_] := If[LessEqual[B, 6.3e-99], N[(180.0 * N[(N[ArcTan[0.0], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision], N[(180.0 * N[(N[ArcTan[-1.0], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision]]
    
    \begin{array}{l}
    
    \\
    \begin{array}{l}
    \mathbf{if}\;B \leq 6.3 \cdot 10^{-99}:\\
    \;\;\;\;180 \cdot \frac{\tan^{-1} 0}{\pi}\\
    
    \mathbf{else}:\\
    \;\;\;\;180 \cdot \frac{\tan^{-1} -1}{\pi}\\
    
    
    \end{array}
    \end{array}
    
    Derivation
    1. Split input into 2 regimes
    2. if B < 6.29999999999999992e-99

      1. Initial program 59.9%

        \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
      2. Add Preprocessing
      3. Step-by-step derivation
        1. *-commutative59.9%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \frac{1}{B}\right)}}{\pi} \]
        2. associate--l-59.2%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\color{blue}{\left(C - \left(A + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)} \cdot \frac{1}{B}\right)}{\pi} \]
        3. +-commutative59.2%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\left(C - \left(A + \sqrt{\color{blue}{{B}^{2} + {\left(A - C\right)}^{2}}}\right)\right) \cdot \frac{1}{B}\right)}{\pi} \]
        4. unpow259.2%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\left(C - \left(A + \sqrt{\color{blue}{B \cdot B} + {\left(A - C\right)}^{2}}\right)\right) \cdot \frac{1}{B}\right)}{\pi} \]
        5. unpow259.2%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\left(C - \left(A + \sqrt{B \cdot B + \color{blue}{\left(A - C\right) \cdot \left(A - C\right)}}\right)\right) \cdot \frac{1}{B}\right)}{\pi} \]
        6. hypot-undefine77.1%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\left(C - \left(A + \color{blue}{\mathsf{hypot}\left(B, A - C\right)}\right)\right) \cdot \frac{1}{B}\right)}{\pi} \]
        7. associate--r+83.2%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\color{blue}{\left(\left(C - A\right) - \mathsf{hypot}\left(B, A - C\right)\right)} \cdot \frac{1}{B}\right)}{\pi} \]
        8. div-inv83.2%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{\left(C - A\right) - \mathsf{hypot}\left(B, A - C\right)}{B}\right)}}{\pi} \]
        9. div-sub70.6%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{C - A}{B} - \frac{\mathsf{hypot}\left(B, A - C\right)}{B}\right)}}{\pi} \]
      4. Applied egg-rr70.6%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{C - A}{B} - \frac{\mathsf{hypot}\left(B, A - C\right)}{B}\right)}}{\pi} \]
      5. Taylor expanded in C around inf 8.9%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(-1 \cdot \left(-1 \cdot \frac{A}{B} + \frac{A}{B}\right)\right)}}{\pi} \]
      6. Step-by-step derivation
        1. distribute-lft1-in8.9%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(-1 \cdot \color{blue}{\left(\left(-1 + 1\right) \cdot \frac{A}{B}\right)}\right)}{\pi} \]
        2. metadata-eval8.9%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(-1 \cdot \left(\color{blue}{0} \cdot \frac{A}{B}\right)\right)}{\pi} \]
        3. mul0-lft15.6%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(-1 \cdot \color{blue}{0}\right)}{\pi} \]
        4. metadata-eval15.6%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{0}}{\pi} \]
      7. Simplified15.6%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{0}}{\pi} \]

      if 6.29999999999999992e-99 < B

      1. Initial program 56.8%

        \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
      2. Add Preprocessing
      3. Taylor expanded in B around inf 52.7%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{-1}}{\pi} \]
    3. Recombined 2 regimes into one program.
    4. Add Preprocessing

    Alternative 19: 21.6% accurate, 4.0× speedup?

    \[\begin{array}{l} \\ 180 \cdot \frac{\tan^{-1} -1}{\pi} \end{array} \]
    (FPCore (A B C) :precision binary64 (* 180.0 (/ (atan -1.0) PI)))
    double code(double A, double B, double C) {
    	return 180.0 * (atan(-1.0) / ((double) M_PI));
    }
    
    public static double code(double A, double B, double C) {
    	return 180.0 * (Math.atan(-1.0) / Math.PI);
    }
    
    def code(A, B, C):
    	return 180.0 * (math.atan(-1.0) / math.pi)
    
    function code(A, B, C)
    	return Float64(180.0 * Float64(atan(-1.0) / pi))
    end
    
    function tmp = code(A, B, C)
    	tmp = 180.0 * (atan(-1.0) / pi);
    end
    
    code[A_, B_, C_] := N[(180.0 * N[(N[ArcTan[-1.0], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision]
    
    \begin{array}{l}
    
    \\
    180 \cdot \frac{\tan^{-1} -1}{\pi}
    \end{array}
    
    Derivation
    1. Initial program 59.0%

      \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
    2. Add Preprocessing
    3. Taylor expanded in B around inf 19.8%

      \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{-1}}{\pi} \]
    4. Add Preprocessing

    Reproduce

    ?
    herbie shell --seed 2024139 
    (FPCore (A B C)
      :name "ABCF->ab-angle angle"
      :precision binary64
      (* 180.0 (/ (atan (* (/ 1.0 B) (- (- C A) (sqrt (+ (pow (- A C) 2.0) (pow B 2.0)))))) PI)))