FastMath test3

Percentage Accurate: 97.7% → 99.9%
Time: 2.2min
Alternatives: 7
Speedup: 1.6×

Specification

?
\[\begin{array}{l} \\ \left(d1 \cdot 3 + d1 \cdot d2\right) + d1 \cdot d3 \end{array} \]
(FPCore (d1 d2 d3) :precision binary64 (+ (+ (* d1 3.0) (* d1 d2)) (* d1 d3)))
double code(double d1, double d2, double d3) {
	return ((d1 * 3.0) + (d1 * d2)) + (d1 * d3);
}
real(8) function code(d1, d2, d3)
    real(8), intent (in) :: d1
    real(8), intent (in) :: d2
    real(8), intent (in) :: d3
    code = ((d1 * 3.0d0) + (d1 * d2)) + (d1 * d3)
end function
public static double code(double d1, double d2, double d3) {
	return ((d1 * 3.0) + (d1 * d2)) + (d1 * d3);
}
def code(d1, d2, d3):
	return ((d1 * 3.0) + (d1 * d2)) + (d1 * d3)
function code(d1, d2, d3)
	return Float64(Float64(Float64(d1 * 3.0) + Float64(d1 * d2)) + Float64(d1 * d3))
end
function tmp = code(d1, d2, d3)
	tmp = ((d1 * 3.0) + (d1 * d2)) + (d1 * d3);
end
code[d1_, d2_, d3_] := N[(N[(N[(d1 * 3.0), $MachinePrecision] + N[(d1 * d2), $MachinePrecision]), $MachinePrecision] + N[(d1 * d3), $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
\left(d1 \cdot 3 + d1 \cdot d2\right) + d1 \cdot d3
\end{array}

Sampling outcomes in binary64 precision:

Local Percentage Accuracy vs ?

The average percentage accuracy by input value. Horizontal axis shows value of an input variable; the variable is choosen in the title. Vertical axis is accuracy; higher is better. Red represent the original program, while blue represents Herbie's suggestion. These can be toggled with buttons below the plot. The line is an average while dots represent individual samples.

Accuracy vs Speed?

Herbie found 7 alternatives:

AlternativeAccuracySpeedup
The accuracy (vertical axis) and speed (horizontal axis) of each alternatives. Up and to the right is better. The red square shows the initial program, and each blue circle shows an alternative.The line shows the best available speed-accuracy tradeoffs.

Initial Program: 97.7% accurate, 1.0× speedup?

\[\begin{array}{l} \\ \left(d1 \cdot 3 + d1 \cdot d2\right) + d1 \cdot d3 \end{array} \]
(FPCore (d1 d2 d3) :precision binary64 (+ (+ (* d1 3.0) (* d1 d2)) (* d1 d3)))
double code(double d1, double d2, double d3) {
	return ((d1 * 3.0) + (d1 * d2)) + (d1 * d3);
}
real(8) function code(d1, d2, d3)
    real(8), intent (in) :: d1
    real(8), intent (in) :: d2
    real(8), intent (in) :: d3
    code = ((d1 * 3.0d0) + (d1 * d2)) + (d1 * d3)
end function
public static double code(double d1, double d2, double d3) {
	return ((d1 * 3.0) + (d1 * d2)) + (d1 * d3);
}
def code(d1, d2, d3):
	return ((d1 * 3.0) + (d1 * d2)) + (d1 * d3)
function code(d1, d2, d3)
	return Float64(Float64(Float64(d1 * 3.0) + Float64(d1 * d2)) + Float64(d1 * d3))
end
function tmp = code(d1, d2, d3)
	tmp = ((d1 * 3.0) + (d1 * d2)) + (d1 * d3);
end
code[d1_, d2_, d3_] := N[(N[(N[(d1 * 3.0), $MachinePrecision] + N[(d1 * d2), $MachinePrecision]), $MachinePrecision] + N[(d1 * d3), $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
\left(d1 \cdot 3 + d1 \cdot d2\right) + d1 \cdot d3
\end{array}

Alternative 1: 99.9% accurate, 1.6× speedup?

\[\begin{array}{l} \\ d1 \cdot \left(d2 + \left(3 + d3\right)\right) \end{array} \]
(FPCore (d1 d2 d3) :precision binary64 (* d1 (+ d2 (+ 3.0 d3))))
double code(double d1, double d2, double d3) {
	return d1 * (d2 + (3.0 + d3));
}
real(8) function code(d1, d2, d3)
    real(8), intent (in) :: d1
    real(8), intent (in) :: d2
    real(8), intent (in) :: d3
    code = d1 * (d2 + (3.0d0 + d3))
end function
public static double code(double d1, double d2, double d3) {
	return d1 * (d2 + (3.0 + d3));
}
def code(d1, d2, d3):
	return d1 * (d2 + (3.0 + d3))
function code(d1, d2, d3)
	return Float64(d1 * Float64(d2 + Float64(3.0 + d3)))
end
function tmp = code(d1, d2, d3)
	tmp = d1 * (d2 + (3.0 + d3));
end
code[d1_, d2_, d3_] := N[(d1 * N[(d2 + N[(3.0 + d3), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
d1 \cdot \left(d2 + \left(3 + d3\right)\right)
\end{array}
Derivation
  1. Initial program 98.7%

    \[\left(d1 \cdot 3 + d1 \cdot d2\right) + d1 \cdot d3 \]
  2. Step-by-step derivation
    1. distribute-lft-outN/A

      \[\leadsto d1 \cdot \left(3 + d2\right) + \color{blue}{d1} \cdot d3 \]
    2. distribute-lft-outN/A

      \[\leadsto d1 \cdot \color{blue}{\left(\left(3 + d2\right) + d3\right)} \]
    3. *-lowering-*.f64N/A

      \[\leadsto \mathsf{*.f64}\left(d1, \color{blue}{\left(\left(3 + d2\right) + d3\right)}\right) \]
    4. +-commutativeN/A

      \[\leadsto \mathsf{*.f64}\left(d1, \left(\left(d2 + 3\right) + d3\right)\right) \]
    5. associate-+l+N/A

      \[\leadsto \mathsf{*.f64}\left(d1, \left(d2 + \color{blue}{\left(3 + d3\right)}\right)\right) \]
    6. +-lowering-+.f64N/A

      \[\leadsto \mathsf{*.f64}\left(d1, \mathsf{+.f64}\left(d2, \color{blue}{\left(3 + d3\right)}\right)\right) \]
    7. +-lowering-+.f64100.0%

      \[\leadsto \mathsf{*.f64}\left(d1, \mathsf{+.f64}\left(d2, \mathsf{+.f64}\left(3, \color{blue}{d3}\right)\right)\right) \]
  3. Simplified100.0%

    \[\leadsto \color{blue}{d1 \cdot \left(d2 + \left(3 + d3\right)\right)} \]
  4. Add Preprocessing
  5. Add Preprocessing

Alternative 2: 52.1% accurate, 0.8× speedup?

\[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;d2 \leq -110:\\ \;\;\;\;d1 \cdot d2\\ \mathbf{elif}\;d2 \leq 2 \cdot 10^{-169}:\\ \;\;\;\;d1 \cdot 3\\ \mathbf{else}:\\ \;\;\;\;d1 \cdot d3\\ \end{array} \end{array} \]
(FPCore (d1 d2 d3)
 :precision binary64
 (if (<= d2 -110.0) (* d1 d2) (if (<= d2 2e-169) (* d1 3.0) (* d1 d3))))
double code(double d1, double d2, double d3) {
	double tmp;
	if (d2 <= -110.0) {
		tmp = d1 * d2;
	} else if (d2 <= 2e-169) {
		tmp = d1 * 3.0;
	} else {
		tmp = d1 * d3;
	}
	return tmp;
}
real(8) function code(d1, d2, d3)
    real(8), intent (in) :: d1
    real(8), intent (in) :: d2
    real(8), intent (in) :: d3
    real(8) :: tmp
    if (d2 <= (-110.0d0)) then
        tmp = d1 * d2
    else if (d2 <= 2d-169) then
        tmp = d1 * 3.0d0
    else
        tmp = d1 * d3
    end if
    code = tmp
end function
public static double code(double d1, double d2, double d3) {
	double tmp;
	if (d2 <= -110.0) {
		tmp = d1 * d2;
	} else if (d2 <= 2e-169) {
		tmp = d1 * 3.0;
	} else {
		tmp = d1 * d3;
	}
	return tmp;
}
def code(d1, d2, d3):
	tmp = 0
	if d2 <= -110.0:
		tmp = d1 * d2
	elif d2 <= 2e-169:
		tmp = d1 * 3.0
	else:
		tmp = d1 * d3
	return tmp
function code(d1, d2, d3)
	tmp = 0.0
	if (d2 <= -110.0)
		tmp = Float64(d1 * d2);
	elseif (d2 <= 2e-169)
		tmp = Float64(d1 * 3.0);
	else
		tmp = Float64(d1 * d3);
	end
	return tmp
end
function tmp_2 = code(d1, d2, d3)
	tmp = 0.0;
	if (d2 <= -110.0)
		tmp = d1 * d2;
	elseif (d2 <= 2e-169)
		tmp = d1 * 3.0;
	else
		tmp = d1 * d3;
	end
	tmp_2 = tmp;
end
code[d1_, d2_, d3_] := If[LessEqual[d2, -110.0], N[(d1 * d2), $MachinePrecision], If[LessEqual[d2, 2e-169], N[(d1 * 3.0), $MachinePrecision], N[(d1 * d3), $MachinePrecision]]]
\begin{array}{l}

\\
\begin{array}{l}
\mathbf{if}\;d2 \leq -110:\\
\;\;\;\;d1 \cdot d2\\

\mathbf{elif}\;d2 \leq 2 \cdot 10^{-169}:\\
\;\;\;\;d1 \cdot 3\\

\mathbf{else}:\\
\;\;\;\;d1 \cdot d3\\


\end{array}
\end{array}
Derivation
  1. Split input into 3 regimes
  2. if d2 < -110

    1. Initial program 98.2%

      \[\left(d1 \cdot 3 + d1 \cdot d2\right) + d1 \cdot d3 \]
    2. Step-by-step derivation
      1. distribute-lft-outN/A

        \[\leadsto d1 \cdot \left(3 + d2\right) + \color{blue}{d1} \cdot d3 \]
      2. distribute-lft-outN/A

        \[\leadsto d1 \cdot \color{blue}{\left(\left(3 + d2\right) + d3\right)} \]
      3. *-lowering-*.f64N/A

        \[\leadsto \mathsf{*.f64}\left(d1, \color{blue}{\left(\left(3 + d2\right) + d3\right)}\right) \]
      4. +-commutativeN/A

        \[\leadsto \mathsf{*.f64}\left(d1, \left(\left(d2 + 3\right) + d3\right)\right) \]
      5. associate-+l+N/A

        \[\leadsto \mathsf{*.f64}\left(d1, \left(d2 + \color{blue}{\left(3 + d3\right)}\right)\right) \]
      6. +-lowering-+.f64N/A

        \[\leadsto \mathsf{*.f64}\left(d1, \mathsf{+.f64}\left(d2, \color{blue}{\left(3 + d3\right)}\right)\right) \]
      7. +-lowering-+.f64100.0%

        \[\leadsto \mathsf{*.f64}\left(d1, \mathsf{+.f64}\left(d2, \mathsf{+.f64}\left(3, \color{blue}{d3}\right)\right)\right) \]
    3. Simplified100.0%

      \[\leadsto \color{blue}{d1 \cdot \left(d2 + \left(3 + d3\right)\right)} \]
    4. Add Preprocessing
    5. Taylor expanded in d2 around inf

      \[\leadsto \color{blue}{d1 \cdot d2} \]
    6. Step-by-step derivation
      1. *-lowering-*.f6482.4%

        \[\leadsto \mathsf{*.f64}\left(d1, \color{blue}{d2}\right) \]
    7. Simplified82.4%

      \[\leadsto \color{blue}{d1 \cdot d2} \]

    if -110 < d2 < 2.00000000000000004e-169

    1. Initial program 99.8%

      \[\left(d1 \cdot 3 + d1 \cdot d2\right) + d1 \cdot d3 \]
    2. Step-by-step derivation
      1. distribute-lft-outN/A

        \[\leadsto d1 \cdot \left(3 + d2\right) + \color{blue}{d1} \cdot d3 \]
      2. distribute-lft-outN/A

        \[\leadsto d1 \cdot \color{blue}{\left(\left(3 + d2\right) + d3\right)} \]
      3. *-lowering-*.f64N/A

        \[\leadsto \mathsf{*.f64}\left(d1, \color{blue}{\left(\left(3 + d2\right) + d3\right)}\right) \]
      4. +-commutativeN/A

        \[\leadsto \mathsf{*.f64}\left(d1, \left(\left(d2 + 3\right) + d3\right)\right) \]
      5. associate-+l+N/A

        \[\leadsto \mathsf{*.f64}\left(d1, \left(d2 + \color{blue}{\left(3 + d3\right)}\right)\right) \]
      6. +-lowering-+.f64N/A

        \[\leadsto \mathsf{*.f64}\left(d1, \mathsf{+.f64}\left(d2, \color{blue}{\left(3 + d3\right)}\right)\right) \]
      7. +-lowering-+.f6499.9%

        \[\leadsto \mathsf{*.f64}\left(d1, \mathsf{+.f64}\left(d2, \mathsf{+.f64}\left(3, \color{blue}{d3}\right)\right)\right) \]
    3. Simplified99.9%

      \[\leadsto \color{blue}{d1 \cdot \left(d2 + \left(3 + d3\right)\right)} \]
    4. Add Preprocessing
    5. Taylor expanded in d2 around 0

      \[\leadsto \color{blue}{d1 \cdot \left(3 + d3\right)} \]
    6. Step-by-step derivation
      1. *-lowering-*.f64N/A

        \[\leadsto \mathsf{*.f64}\left(d1, \color{blue}{\left(3 + d3\right)}\right) \]
      2. +-lowering-+.f6498.6%

        \[\leadsto \mathsf{*.f64}\left(d1, \mathsf{+.f64}\left(3, \color{blue}{d3}\right)\right) \]
    7. Simplified98.6%

      \[\leadsto \color{blue}{d1 \cdot \left(3 + d3\right)} \]
    8. Taylor expanded in d3 around 0

      \[\leadsto \color{blue}{3 \cdot d1} \]
    9. Step-by-step derivation
      1. *-commutativeN/A

        \[\leadsto d1 \cdot \color{blue}{3} \]
      2. *-lowering-*.f6461.5%

        \[\leadsto \mathsf{*.f64}\left(d1, \color{blue}{3}\right) \]
    10. Simplified61.5%

      \[\leadsto \color{blue}{d1 \cdot 3} \]

    if 2.00000000000000004e-169 < d2

    1. Initial program 97.9%

      \[\left(d1 \cdot 3 + d1 \cdot d2\right) + d1 \cdot d3 \]
    2. Step-by-step derivation
      1. distribute-lft-outN/A

        \[\leadsto d1 \cdot \left(3 + d2\right) + \color{blue}{d1} \cdot d3 \]
      2. distribute-lft-outN/A

        \[\leadsto d1 \cdot \color{blue}{\left(\left(3 + d2\right) + d3\right)} \]
      3. *-lowering-*.f64N/A

        \[\leadsto \mathsf{*.f64}\left(d1, \color{blue}{\left(\left(3 + d2\right) + d3\right)}\right) \]
      4. +-commutativeN/A

        \[\leadsto \mathsf{*.f64}\left(d1, \left(\left(d2 + 3\right) + d3\right)\right) \]
      5. associate-+l+N/A

        \[\leadsto \mathsf{*.f64}\left(d1, \left(d2 + \color{blue}{\left(3 + d3\right)}\right)\right) \]
      6. +-lowering-+.f64N/A

        \[\leadsto \mathsf{*.f64}\left(d1, \mathsf{+.f64}\left(d2, \color{blue}{\left(3 + d3\right)}\right)\right) \]
      7. +-lowering-+.f64100.0%

        \[\leadsto \mathsf{*.f64}\left(d1, \mathsf{+.f64}\left(d2, \mathsf{+.f64}\left(3, \color{blue}{d3}\right)\right)\right) \]
    3. Simplified100.0%

      \[\leadsto \color{blue}{d1 \cdot \left(d2 + \left(3 + d3\right)\right)} \]
    4. Add Preprocessing
    5. Taylor expanded in d3 around inf

      \[\leadsto \color{blue}{d1 \cdot d3} \]
    6. Step-by-step derivation
      1. *-lowering-*.f6442.0%

        \[\leadsto \mathsf{*.f64}\left(d1, \color{blue}{d3}\right) \]
    7. Simplified42.0%

      \[\leadsto \color{blue}{d1 \cdot d3} \]
  3. Recombined 3 regimes into one program.
  4. Add Preprocessing

Alternative 3: 81.3% accurate, 1.1× speedup?

\[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;d3 \leq 3:\\ \;\;\;\;d1 \cdot \left(d2 + 3\right)\\ \mathbf{else}:\\ \;\;\;\;d1 \cdot \left(d2 + d3\right)\\ \end{array} \end{array} \]
(FPCore (d1 d2 d3)
 :precision binary64
 (if (<= d3 3.0) (* d1 (+ d2 3.0)) (* d1 (+ d2 d3))))
double code(double d1, double d2, double d3) {
	double tmp;
	if (d3 <= 3.0) {
		tmp = d1 * (d2 + 3.0);
	} else {
		tmp = d1 * (d2 + d3);
	}
	return tmp;
}
real(8) function code(d1, d2, d3)
    real(8), intent (in) :: d1
    real(8), intent (in) :: d2
    real(8), intent (in) :: d3
    real(8) :: tmp
    if (d3 <= 3.0d0) then
        tmp = d1 * (d2 + 3.0d0)
    else
        tmp = d1 * (d2 + d3)
    end if
    code = tmp
end function
public static double code(double d1, double d2, double d3) {
	double tmp;
	if (d3 <= 3.0) {
		tmp = d1 * (d2 + 3.0);
	} else {
		tmp = d1 * (d2 + d3);
	}
	return tmp;
}
def code(d1, d2, d3):
	tmp = 0
	if d3 <= 3.0:
		tmp = d1 * (d2 + 3.0)
	else:
		tmp = d1 * (d2 + d3)
	return tmp
function code(d1, d2, d3)
	tmp = 0.0
	if (d3 <= 3.0)
		tmp = Float64(d1 * Float64(d2 + 3.0));
	else
		tmp = Float64(d1 * Float64(d2 + d3));
	end
	return tmp
end
function tmp_2 = code(d1, d2, d3)
	tmp = 0.0;
	if (d3 <= 3.0)
		tmp = d1 * (d2 + 3.0);
	else
		tmp = d1 * (d2 + d3);
	end
	tmp_2 = tmp;
end
code[d1_, d2_, d3_] := If[LessEqual[d3, 3.0], N[(d1 * N[(d2 + 3.0), $MachinePrecision]), $MachinePrecision], N[(d1 * N[(d2 + d3), $MachinePrecision]), $MachinePrecision]]
\begin{array}{l}

\\
\begin{array}{l}
\mathbf{if}\;d3 \leq 3:\\
\;\;\;\;d1 \cdot \left(d2 + 3\right)\\

\mathbf{else}:\\
\;\;\;\;d1 \cdot \left(d2 + d3\right)\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if d3 < 3

    1. Initial program 98.9%

      \[\left(d1 \cdot 3 + d1 \cdot d2\right) + d1 \cdot d3 \]
    2. Step-by-step derivation
      1. distribute-lft-outN/A

        \[\leadsto d1 \cdot \left(3 + d2\right) + \color{blue}{d1} \cdot d3 \]
      2. distribute-lft-outN/A

        \[\leadsto d1 \cdot \color{blue}{\left(\left(3 + d2\right) + d3\right)} \]
      3. *-lowering-*.f64N/A

        \[\leadsto \mathsf{*.f64}\left(d1, \color{blue}{\left(\left(3 + d2\right) + d3\right)}\right) \]
      4. +-commutativeN/A

        \[\leadsto \mathsf{*.f64}\left(d1, \left(\left(d2 + 3\right) + d3\right)\right) \]
      5. associate-+l+N/A

        \[\leadsto \mathsf{*.f64}\left(d1, \left(d2 + \color{blue}{\left(3 + d3\right)}\right)\right) \]
      6. +-lowering-+.f64N/A

        \[\leadsto \mathsf{*.f64}\left(d1, \mathsf{+.f64}\left(d2, \color{blue}{\left(3 + d3\right)}\right)\right) \]
      7. +-lowering-+.f6499.9%

        \[\leadsto \mathsf{*.f64}\left(d1, \mathsf{+.f64}\left(d2, \mathsf{+.f64}\left(3, \color{blue}{d3}\right)\right)\right) \]
    3. Simplified99.9%

      \[\leadsto \color{blue}{d1 \cdot \left(d2 + \left(3 + d3\right)\right)} \]
    4. Add Preprocessing
    5. Taylor expanded in d3 around 0

      \[\leadsto \mathsf{*.f64}\left(d1, \mathsf{+.f64}\left(d2, \color{blue}{3}\right)\right) \]
    6. Step-by-step derivation
      1. Simplified77.2%

        \[\leadsto d1 \cdot \left(d2 + \color{blue}{3}\right) \]

      if 3 < d3

      1. Initial program 98.1%

        \[\left(d1 \cdot 3 + d1 \cdot d2\right) + d1 \cdot d3 \]
      2. Step-by-step derivation
        1. distribute-lft-outN/A

          \[\leadsto d1 \cdot \left(3 + d2\right) + \color{blue}{d1} \cdot d3 \]
        2. distribute-lft-outN/A

          \[\leadsto d1 \cdot \color{blue}{\left(\left(3 + d2\right) + d3\right)} \]
        3. *-lowering-*.f64N/A

          \[\leadsto \mathsf{*.f64}\left(d1, \color{blue}{\left(\left(3 + d2\right) + d3\right)}\right) \]
        4. +-commutativeN/A

          \[\leadsto \mathsf{*.f64}\left(d1, \left(\left(d2 + 3\right) + d3\right)\right) \]
        5. associate-+l+N/A

          \[\leadsto \mathsf{*.f64}\left(d1, \left(d2 + \color{blue}{\left(3 + d3\right)}\right)\right) \]
        6. +-lowering-+.f64N/A

          \[\leadsto \mathsf{*.f64}\left(d1, \mathsf{+.f64}\left(d2, \color{blue}{\left(3 + d3\right)}\right)\right) \]
        7. +-lowering-+.f64100.0%

          \[\leadsto \mathsf{*.f64}\left(d1, \mathsf{+.f64}\left(d2, \mathsf{+.f64}\left(3, \color{blue}{d3}\right)\right)\right) \]
      3. Simplified100.0%

        \[\leadsto \color{blue}{d1 \cdot \left(d2 + \left(3 + d3\right)\right)} \]
      4. Add Preprocessing
      5. Taylor expanded in d3 around inf

        \[\leadsto \mathsf{*.f64}\left(d1, \mathsf{+.f64}\left(d2, \color{blue}{d3}\right)\right) \]
      6. Step-by-step derivation
        1. Simplified98.7%

          \[\leadsto d1 \cdot \left(d2 + \color{blue}{d3}\right) \]
      7. Recombined 2 regimes into one program.
      8. Add Preprocessing

      Alternative 4: 76.1% accurate, 1.1× speedup?

      \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;d2 \leq -2.4 \cdot 10^{-14}:\\ \;\;\;\;d1 \cdot \left(d2 + 3\right)\\ \mathbf{else}:\\ \;\;\;\;d1 \cdot \left(3 + d3\right)\\ \end{array} \end{array} \]
      (FPCore (d1 d2 d3)
       :precision binary64
       (if (<= d2 -2.4e-14) (* d1 (+ d2 3.0)) (* d1 (+ 3.0 d3))))
      double code(double d1, double d2, double d3) {
      	double tmp;
      	if (d2 <= -2.4e-14) {
      		tmp = d1 * (d2 + 3.0);
      	} else {
      		tmp = d1 * (3.0 + d3);
      	}
      	return tmp;
      }
      
      real(8) function code(d1, d2, d3)
          real(8), intent (in) :: d1
          real(8), intent (in) :: d2
          real(8), intent (in) :: d3
          real(8) :: tmp
          if (d2 <= (-2.4d-14)) then
              tmp = d1 * (d2 + 3.0d0)
          else
              tmp = d1 * (3.0d0 + d3)
          end if
          code = tmp
      end function
      
      public static double code(double d1, double d2, double d3) {
      	double tmp;
      	if (d2 <= -2.4e-14) {
      		tmp = d1 * (d2 + 3.0);
      	} else {
      		tmp = d1 * (3.0 + d3);
      	}
      	return tmp;
      }
      
      def code(d1, d2, d3):
      	tmp = 0
      	if d2 <= -2.4e-14:
      		tmp = d1 * (d2 + 3.0)
      	else:
      		tmp = d1 * (3.0 + d3)
      	return tmp
      
      function code(d1, d2, d3)
      	tmp = 0.0
      	if (d2 <= -2.4e-14)
      		tmp = Float64(d1 * Float64(d2 + 3.0));
      	else
      		tmp = Float64(d1 * Float64(3.0 + d3));
      	end
      	return tmp
      end
      
      function tmp_2 = code(d1, d2, d3)
      	tmp = 0.0;
      	if (d2 <= -2.4e-14)
      		tmp = d1 * (d2 + 3.0);
      	else
      		tmp = d1 * (3.0 + d3);
      	end
      	tmp_2 = tmp;
      end
      
      code[d1_, d2_, d3_] := If[LessEqual[d2, -2.4e-14], N[(d1 * N[(d2 + 3.0), $MachinePrecision]), $MachinePrecision], N[(d1 * N[(3.0 + d3), $MachinePrecision]), $MachinePrecision]]
      
      \begin{array}{l}
      
      \\
      \begin{array}{l}
      \mathbf{if}\;d2 \leq -2.4 \cdot 10^{-14}:\\
      \;\;\;\;d1 \cdot \left(d2 + 3\right)\\
      
      \mathbf{else}:\\
      \;\;\;\;d1 \cdot \left(3 + d3\right)\\
      
      
      \end{array}
      \end{array}
      
      Derivation
      1. Split input into 2 regimes
      2. if d2 < -2.4e-14

        1. Initial program 98.3%

          \[\left(d1 \cdot 3 + d1 \cdot d2\right) + d1 \cdot d3 \]
        2. Step-by-step derivation
          1. distribute-lft-outN/A

            \[\leadsto d1 \cdot \left(3 + d2\right) + \color{blue}{d1} \cdot d3 \]
          2. distribute-lft-outN/A

            \[\leadsto d1 \cdot \color{blue}{\left(\left(3 + d2\right) + d3\right)} \]
          3. *-lowering-*.f64N/A

            \[\leadsto \mathsf{*.f64}\left(d1, \color{blue}{\left(\left(3 + d2\right) + d3\right)}\right) \]
          4. +-commutativeN/A

            \[\leadsto \mathsf{*.f64}\left(d1, \left(\left(d2 + 3\right) + d3\right)\right) \]
          5. associate-+l+N/A

            \[\leadsto \mathsf{*.f64}\left(d1, \left(d2 + \color{blue}{\left(3 + d3\right)}\right)\right) \]
          6. +-lowering-+.f64N/A

            \[\leadsto \mathsf{*.f64}\left(d1, \mathsf{+.f64}\left(d2, \color{blue}{\left(3 + d3\right)}\right)\right) \]
          7. +-lowering-+.f64100.0%

            \[\leadsto \mathsf{*.f64}\left(d1, \mathsf{+.f64}\left(d2, \mathsf{+.f64}\left(3, \color{blue}{d3}\right)\right)\right) \]
        3. Simplified100.0%

          \[\leadsto \color{blue}{d1 \cdot \left(d2 + \left(3 + d3\right)\right)} \]
        4. Add Preprocessing
        5. Taylor expanded in d3 around 0

          \[\leadsto \mathsf{*.f64}\left(d1, \mathsf{+.f64}\left(d2, \color{blue}{3}\right)\right) \]
        6. Step-by-step derivation
          1. Simplified84.4%

            \[\leadsto d1 \cdot \left(d2 + \color{blue}{3}\right) \]

          if -2.4e-14 < d2

          1. Initial program 98.9%

            \[\left(d1 \cdot 3 + d1 \cdot d2\right) + d1 \cdot d3 \]
          2. Step-by-step derivation
            1. distribute-lft-outN/A

              \[\leadsto d1 \cdot \left(3 + d2\right) + \color{blue}{d1} \cdot d3 \]
            2. distribute-lft-outN/A

              \[\leadsto d1 \cdot \color{blue}{\left(\left(3 + d2\right) + d3\right)} \]
            3. *-lowering-*.f64N/A

              \[\leadsto \mathsf{*.f64}\left(d1, \color{blue}{\left(\left(3 + d2\right) + d3\right)}\right) \]
            4. +-commutativeN/A

              \[\leadsto \mathsf{*.f64}\left(d1, \left(\left(d2 + 3\right) + d3\right)\right) \]
            5. associate-+l+N/A

              \[\leadsto \mathsf{*.f64}\left(d1, \left(d2 + \color{blue}{\left(3 + d3\right)}\right)\right) \]
            6. +-lowering-+.f64N/A

              \[\leadsto \mathsf{*.f64}\left(d1, \mathsf{+.f64}\left(d2, \color{blue}{\left(3 + d3\right)}\right)\right) \]
            7. +-lowering-+.f6499.9%

              \[\leadsto \mathsf{*.f64}\left(d1, \mathsf{+.f64}\left(d2, \mathsf{+.f64}\left(3, \color{blue}{d3}\right)\right)\right) \]
          3. Simplified99.9%

            \[\leadsto \color{blue}{d1 \cdot \left(d2 + \left(3 + d3\right)\right)} \]
          4. Add Preprocessing
          5. Taylor expanded in d2 around 0

            \[\leadsto \color{blue}{d1 \cdot \left(3 + d3\right)} \]
          6. Step-by-step derivation
            1. *-lowering-*.f64N/A

              \[\leadsto \mathsf{*.f64}\left(d1, \color{blue}{\left(3 + d3\right)}\right) \]
            2. +-lowering-+.f6479.7%

              \[\leadsto \mathsf{*.f64}\left(d1, \mathsf{+.f64}\left(3, \color{blue}{d3}\right)\right) \]
          7. Simplified79.7%

            \[\leadsto \color{blue}{d1 \cdot \left(3 + d3\right)} \]
        7. Recombined 2 regimes into one program.
        8. Add Preprocessing

        Alternative 5: 76.3% accurate, 1.1× speedup?

        \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;d2 \leq -7800000000000:\\ \;\;\;\;d1 \cdot d2\\ \mathbf{else}:\\ \;\;\;\;d1 \cdot \left(3 + d3\right)\\ \end{array} \end{array} \]
        (FPCore (d1 d2 d3)
         :precision binary64
         (if (<= d2 -7800000000000.0) (* d1 d2) (* d1 (+ 3.0 d3))))
        double code(double d1, double d2, double d3) {
        	double tmp;
        	if (d2 <= -7800000000000.0) {
        		tmp = d1 * d2;
        	} else {
        		tmp = d1 * (3.0 + d3);
        	}
        	return tmp;
        }
        
        real(8) function code(d1, d2, d3)
            real(8), intent (in) :: d1
            real(8), intent (in) :: d2
            real(8), intent (in) :: d3
            real(8) :: tmp
            if (d2 <= (-7800000000000.0d0)) then
                tmp = d1 * d2
            else
                tmp = d1 * (3.0d0 + d3)
            end if
            code = tmp
        end function
        
        public static double code(double d1, double d2, double d3) {
        	double tmp;
        	if (d2 <= -7800000000000.0) {
        		tmp = d1 * d2;
        	} else {
        		tmp = d1 * (3.0 + d3);
        	}
        	return tmp;
        }
        
        def code(d1, d2, d3):
        	tmp = 0
        	if d2 <= -7800000000000.0:
        		tmp = d1 * d2
        	else:
        		tmp = d1 * (3.0 + d3)
        	return tmp
        
        function code(d1, d2, d3)
        	tmp = 0.0
        	if (d2 <= -7800000000000.0)
        		tmp = Float64(d1 * d2);
        	else
        		tmp = Float64(d1 * Float64(3.0 + d3));
        	end
        	return tmp
        end
        
        function tmp_2 = code(d1, d2, d3)
        	tmp = 0.0;
        	if (d2 <= -7800000000000.0)
        		tmp = d1 * d2;
        	else
        		tmp = d1 * (3.0 + d3);
        	end
        	tmp_2 = tmp;
        end
        
        code[d1_, d2_, d3_] := If[LessEqual[d2, -7800000000000.0], N[(d1 * d2), $MachinePrecision], N[(d1 * N[(3.0 + d3), $MachinePrecision]), $MachinePrecision]]
        
        \begin{array}{l}
        
        \\
        \begin{array}{l}
        \mathbf{if}\;d2 \leq -7800000000000:\\
        \;\;\;\;d1 \cdot d2\\
        
        \mathbf{else}:\\
        \;\;\;\;d1 \cdot \left(3 + d3\right)\\
        
        
        \end{array}
        \end{array}
        
        Derivation
        1. Split input into 2 regimes
        2. if d2 < -7.8e12

          1. Initial program 98.2%

            \[\left(d1 \cdot 3 + d1 \cdot d2\right) + d1 \cdot d3 \]
          2. Step-by-step derivation
            1. distribute-lft-outN/A

              \[\leadsto d1 \cdot \left(3 + d2\right) + \color{blue}{d1} \cdot d3 \]
            2. distribute-lft-outN/A

              \[\leadsto d1 \cdot \color{blue}{\left(\left(3 + d2\right) + d3\right)} \]
            3. *-lowering-*.f64N/A

              \[\leadsto \mathsf{*.f64}\left(d1, \color{blue}{\left(\left(3 + d2\right) + d3\right)}\right) \]
            4. +-commutativeN/A

              \[\leadsto \mathsf{*.f64}\left(d1, \left(\left(d2 + 3\right) + d3\right)\right) \]
            5. associate-+l+N/A

              \[\leadsto \mathsf{*.f64}\left(d1, \left(d2 + \color{blue}{\left(3 + d3\right)}\right)\right) \]
            6. +-lowering-+.f64N/A

              \[\leadsto \mathsf{*.f64}\left(d1, \mathsf{+.f64}\left(d2, \color{blue}{\left(3 + d3\right)}\right)\right) \]
            7. +-lowering-+.f64100.0%

              \[\leadsto \mathsf{*.f64}\left(d1, \mathsf{+.f64}\left(d2, \mathsf{+.f64}\left(3, \color{blue}{d3}\right)\right)\right) \]
          3. Simplified100.0%

            \[\leadsto \color{blue}{d1 \cdot \left(d2 + \left(3 + d3\right)\right)} \]
          4. Add Preprocessing
          5. Taylor expanded in d2 around inf

            \[\leadsto \color{blue}{d1 \cdot d2} \]
          6. Step-by-step derivation
            1. *-lowering-*.f6484.5%

              \[\leadsto \mathsf{*.f64}\left(d1, \color{blue}{d2}\right) \]
          7. Simplified84.5%

            \[\leadsto \color{blue}{d1 \cdot d2} \]

          if -7.8e12 < d2

          1. Initial program 98.9%

            \[\left(d1 \cdot 3 + d1 \cdot d2\right) + d1 \cdot d3 \]
          2. Step-by-step derivation
            1. distribute-lft-outN/A

              \[\leadsto d1 \cdot \left(3 + d2\right) + \color{blue}{d1} \cdot d3 \]
            2. distribute-lft-outN/A

              \[\leadsto d1 \cdot \color{blue}{\left(\left(3 + d2\right) + d3\right)} \]
            3. *-lowering-*.f64N/A

              \[\leadsto \mathsf{*.f64}\left(d1, \color{blue}{\left(\left(3 + d2\right) + d3\right)}\right) \]
            4. +-commutativeN/A

              \[\leadsto \mathsf{*.f64}\left(d1, \left(\left(d2 + 3\right) + d3\right)\right) \]
            5. associate-+l+N/A

              \[\leadsto \mathsf{*.f64}\left(d1, \left(d2 + \color{blue}{\left(3 + d3\right)}\right)\right) \]
            6. +-lowering-+.f64N/A

              \[\leadsto \mathsf{*.f64}\left(d1, \mathsf{+.f64}\left(d2, \color{blue}{\left(3 + d3\right)}\right)\right) \]
            7. +-lowering-+.f6499.9%

              \[\leadsto \mathsf{*.f64}\left(d1, \mathsf{+.f64}\left(d2, \mathsf{+.f64}\left(3, \color{blue}{d3}\right)\right)\right) \]
          3. Simplified99.9%

            \[\leadsto \color{blue}{d1 \cdot \left(d2 + \left(3 + d3\right)\right)} \]
          4. Add Preprocessing
          5. Taylor expanded in d2 around 0

            \[\leadsto \color{blue}{d1 \cdot \left(3 + d3\right)} \]
          6. Step-by-step derivation
            1. *-lowering-*.f64N/A

              \[\leadsto \mathsf{*.f64}\left(d1, \color{blue}{\left(3 + d3\right)}\right) \]
            2. +-lowering-+.f6479.2%

              \[\leadsto \mathsf{*.f64}\left(d1, \mathsf{+.f64}\left(3, \color{blue}{d3}\right)\right) \]
          7. Simplified79.2%

            \[\leadsto \color{blue}{d1 \cdot \left(3 + d3\right)} \]
        3. Recombined 2 regimes into one program.
        4. Add Preprocessing

        Alternative 6: 45.4% accurate, 1.4× speedup?

        \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;d2 \leq -110:\\ \;\;\;\;d1 \cdot d2\\ \mathbf{else}:\\ \;\;\;\;d1 \cdot 3\\ \end{array} \end{array} \]
        (FPCore (d1 d2 d3)
         :precision binary64
         (if (<= d2 -110.0) (* d1 d2) (* d1 3.0)))
        double code(double d1, double d2, double d3) {
        	double tmp;
        	if (d2 <= -110.0) {
        		tmp = d1 * d2;
        	} else {
        		tmp = d1 * 3.0;
        	}
        	return tmp;
        }
        
        real(8) function code(d1, d2, d3)
            real(8), intent (in) :: d1
            real(8), intent (in) :: d2
            real(8), intent (in) :: d3
            real(8) :: tmp
            if (d2 <= (-110.0d0)) then
                tmp = d1 * d2
            else
                tmp = d1 * 3.0d0
            end if
            code = tmp
        end function
        
        public static double code(double d1, double d2, double d3) {
        	double tmp;
        	if (d2 <= -110.0) {
        		tmp = d1 * d2;
        	} else {
        		tmp = d1 * 3.0;
        	}
        	return tmp;
        }
        
        def code(d1, d2, d3):
        	tmp = 0
        	if d2 <= -110.0:
        		tmp = d1 * d2
        	else:
        		tmp = d1 * 3.0
        	return tmp
        
        function code(d1, d2, d3)
        	tmp = 0.0
        	if (d2 <= -110.0)
        		tmp = Float64(d1 * d2);
        	else
        		tmp = Float64(d1 * 3.0);
        	end
        	return tmp
        end
        
        function tmp_2 = code(d1, d2, d3)
        	tmp = 0.0;
        	if (d2 <= -110.0)
        		tmp = d1 * d2;
        	else
        		tmp = d1 * 3.0;
        	end
        	tmp_2 = tmp;
        end
        
        code[d1_, d2_, d3_] := If[LessEqual[d2, -110.0], N[(d1 * d2), $MachinePrecision], N[(d1 * 3.0), $MachinePrecision]]
        
        \begin{array}{l}
        
        \\
        \begin{array}{l}
        \mathbf{if}\;d2 \leq -110:\\
        \;\;\;\;d1 \cdot d2\\
        
        \mathbf{else}:\\
        \;\;\;\;d1 \cdot 3\\
        
        
        \end{array}
        \end{array}
        
        Derivation
        1. Split input into 2 regimes
        2. if d2 < -110

          1. Initial program 98.2%

            \[\left(d1 \cdot 3 + d1 \cdot d2\right) + d1 \cdot d3 \]
          2. Step-by-step derivation
            1. distribute-lft-outN/A

              \[\leadsto d1 \cdot \left(3 + d2\right) + \color{blue}{d1} \cdot d3 \]
            2. distribute-lft-outN/A

              \[\leadsto d1 \cdot \color{blue}{\left(\left(3 + d2\right) + d3\right)} \]
            3. *-lowering-*.f64N/A

              \[\leadsto \mathsf{*.f64}\left(d1, \color{blue}{\left(\left(3 + d2\right) + d3\right)}\right) \]
            4. +-commutativeN/A

              \[\leadsto \mathsf{*.f64}\left(d1, \left(\left(d2 + 3\right) + d3\right)\right) \]
            5. associate-+l+N/A

              \[\leadsto \mathsf{*.f64}\left(d1, \left(d2 + \color{blue}{\left(3 + d3\right)}\right)\right) \]
            6. +-lowering-+.f64N/A

              \[\leadsto \mathsf{*.f64}\left(d1, \mathsf{+.f64}\left(d2, \color{blue}{\left(3 + d3\right)}\right)\right) \]
            7. +-lowering-+.f64100.0%

              \[\leadsto \mathsf{*.f64}\left(d1, \mathsf{+.f64}\left(d2, \mathsf{+.f64}\left(3, \color{blue}{d3}\right)\right)\right) \]
          3. Simplified100.0%

            \[\leadsto \color{blue}{d1 \cdot \left(d2 + \left(3 + d3\right)\right)} \]
          4. Add Preprocessing
          5. Taylor expanded in d2 around inf

            \[\leadsto \color{blue}{d1 \cdot d2} \]
          6. Step-by-step derivation
            1. *-lowering-*.f6482.4%

              \[\leadsto \mathsf{*.f64}\left(d1, \color{blue}{d2}\right) \]
          7. Simplified82.4%

            \[\leadsto \color{blue}{d1 \cdot d2} \]

          if -110 < d2

          1. Initial program 98.9%

            \[\left(d1 \cdot 3 + d1 \cdot d2\right) + d1 \cdot d3 \]
          2. Step-by-step derivation
            1. distribute-lft-outN/A

              \[\leadsto d1 \cdot \left(3 + d2\right) + \color{blue}{d1} \cdot d3 \]
            2. distribute-lft-outN/A

              \[\leadsto d1 \cdot \color{blue}{\left(\left(3 + d2\right) + d3\right)} \]
            3. *-lowering-*.f64N/A

              \[\leadsto \mathsf{*.f64}\left(d1, \color{blue}{\left(\left(3 + d2\right) + d3\right)}\right) \]
            4. +-commutativeN/A

              \[\leadsto \mathsf{*.f64}\left(d1, \left(\left(d2 + 3\right) + d3\right)\right) \]
            5. associate-+l+N/A

              \[\leadsto \mathsf{*.f64}\left(d1, \left(d2 + \color{blue}{\left(3 + d3\right)}\right)\right) \]
            6. +-lowering-+.f64N/A

              \[\leadsto \mathsf{*.f64}\left(d1, \mathsf{+.f64}\left(d2, \color{blue}{\left(3 + d3\right)}\right)\right) \]
            7. +-lowering-+.f6499.9%

              \[\leadsto \mathsf{*.f64}\left(d1, \mathsf{+.f64}\left(d2, \mathsf{+.f64}\left(3, \color{blue}{d3}\right)\right)\right) \]
          3. Simplified99.9%

            \[\leadsto \color{blue}{d1 \cdot \left(d2 + \left(3 + d3\right)\right)} \]
          4. Add Preprocessing
          5. Taylor expanded in d2 around 0

            \[\leadsto \color{blue}{d1 \cdot \left(3 + d3\right)} \]
          6. Step-by-step derivation
            1. *-lowering-*.f64N/A

              \[\leadsto \mathsf{*.f64}\left(d1, \color{blue}{\left(3 + d3\right)}\right) \]
            2. +-lowering-+.f6479.4%

              \[\leadsto \mathsf{*.f64}\left(d1, \mathsf{+.f64}\left(3, \color{blue}{d3}\right)\right) \]
          7. Simplified79.4%

            \[\leadsto \color{blue}{d1 \cdot \left(3 + d3\right)} \]
          8. Taylor expanded in d3 around 0

            \[\leadsto \color{blue}{3 \cdot d1} \]
          9. Step-by-step derivation
            1. *-commutativeN/A

              \[\leadsto d1 \cdot \color{blue}{3} \]
            2. *-lowering-*.f6441.8%

              \[\leadsto \mathsf{*.f64}\left(d1, \color{blue}{3}\right) \]
          10. Simplified41.8%

            \[\leadsto \color{blue}{d1 \cdot 3} \]
        3. Recombined 2 regimes into one program.
        4. Add Preprocessing

        Alternative 7: 26.1% accurate, 3.7× speedup?

        \[\begin{array}{l} \\ d1 \cdot 3 \end{array} \]
        (FPCore (d1 d2 d3) :precision binary64 (* d1 3.0))
        double code(double d1, double d2, double d3) {
        	return d1 * 3.0;
        }
        
        real(8) function code(d1, d2, d3)
            real(8), intent (in) :: d1
            real(8), intent (in) :: d2
            real(8), intent (in) :: d3
            code = d1 * 3.0d0
        end function
        
        public static double code(double d1, double d2, double d3) {
        	return d1 * 3.0;
        }
        
        def code(d1, d2, d3):
        	return d1 * 3.0
        
        function code(d1, d2, d3)
        	return Float64(d1 * 3.0)
        end
        
        function tmp = code(d1, d2, d3)
        	tmp = d1 * 3.0;
        end
        
        code[d1_, d2_, d3_] := N[(d1 * 3.0), $MachinePrecision]
        
        \begin{array}{l}
        
        \\
        d1 \cdot 3
        \end{array}
        
        Derivation
        1. Initial program 98.7%

          \[\left(d1 \cdot 3 + d1 \cdot d2\right) + d1 \cdot d3 \]
        2. Step-by-step derivation
          1. distribute-lft-outN/A

            \[\leadsto d1 \cdot \left(3 + d2\right) + \color{blue}{d1} \cdot d3 \]
          2. distribute-lft-outN/A

            \[\leadsto d1 \cdot \color{blue}{\left(\left(3 + d2\right) + d3\right)} \]
          3. *-lowering-*.f64N/A

            \[\leadsto \mathsf{*.f64}\left(d1, \color{blue}{\left(\left(3 + d2\right) + d3\right)}\right) \]
          4. +-commutativeN/A

            \[\leadsto \mathsf{*.f64}\left(d1, \left(\left(d2 + 3\right) + d3\right)\right) \]
          5. associate-+l+N/A

            \[\leadsto \mathsf{*.f64}\left(d1, \left(d2 + \color{blue}{\left(3 + d3\right)}\right)\right) \]
          6. +-lowering-+.f64N/A

            \[\leadsto \mathsf{*.f64}\left(d1, \mathsf{+.f64}\left(d2, \color{blue}{\left(3 + d3\right)}\right)\right) \]
          7. +-lowering-+.f64100.0%

            \[\leadsto \mathsf{*.f64}\left(d1, \mathsf{+.f64}\left(d2, \mathsf{+.f64}\left(3, \color{blue}{d3}\right)\right)\right) \]
        3. Simplified100.0%

          \[\leadsto \color{blue}{d1 \cdot \left(d2 + \left(3 + d3\right)\right)} \]
        4. Add Preprocessing
        5. Taylor expanded in d2 around 0

          \[\leadsto \color{blue}{d1 \cdot \left(3 + d3\right)} \]
        6. Step-by-step derivation
          1. *-lowering-*.f64N/A

            \[\leadsto \mathsf{*.f64}\left(d1, \color{blue}{\left(3 + d3\right)}\right) \]
          2. +-lowering-+.f6467.0%

            \[\leadsto \mathsf{*.f64}\left(d1, \mathsf{+.f64}\left(3, \color{blue}{d3}\right)\right) \]
        7. Simplified67.0%

          \[\leadsto \color{blue}{d1 \cdot \left(3 + d3\right)} \]
        8. Taylor expanded in d3 around 0

          \[\leadsto \color{blue}{3 \cdot d1} \]
        9. Step-by-step derivation
          1. *-commutativeN/A

            \[\leadsto d1 \cdot \color{blue}{3} \]
          2. *-lowering-*.f6432.9%

            \[\leadsto \mathsf{*.f64}\left(d1, \color{blue}{3}\right) \]
        10. Simplified32.9%

          \[\leadsto \color{blue}{d1 \cdot 3} \]
        11. Add Preprocessing

        Developer Target 1: 99.9% accurate, 1.6× speedup?

        \[\begin{array}{l} \\ d1 \cdot \left(\left(3 + d2\right) + d3\right) \end{array} \]
        (FPCore (d1 d2 d3) :precision binary64 (* d1 (+ (+ 3.0 d2) d3)))
        double code(double d1, double d2, double d3) {
        	return d1 * ((3.0 + d2) + d3);
        }
        
        real(8) function code(d1, d2, d3)
            real(8), intent (in) :: d1
            real(8), intent (in) :: d2
            real(8), intent (in) :: d3
            code = d1 * ((3.0d0 + d2) + d3)
        end function
        
        public static double code(double d1, double d2, double d3) {
        	return d1 * ((3.0 + d2) + d3);
        }
        
        def code(d1, d2, d3):
        	return d1 * ((3.0 + d2) + d3)
        
        function code(d1, d2, d3)
        	return Float64(d1 * Float64(Float64(3.0 + d2) + d3))
        end
        
        function tmp = code(d1, d2, d3)
        	tmp = d1 * ((3.0 + d2) + d3);
        end
        
        code[d1_, d2_, d3_] := N[(d1 * N[(N[(3.0 + d2), $MachinePrecision] + d3), $MachinePrecision]), $MachinePrecision]
        
        \begin{array}{l}
        
        \\
        d1 \cdot \left(\left(3 + d2\right) + d3\right)
        \end{array}
        

        Reproduce

        ?
        herbie shell --seed 2024138 
        (FPCore (d1 d2 d3)
          :name "FastMath test3"
          :precision binary64
        
          :alt
          (! :herbie-platform default (* d1 (+ 3 d2 d3)))
        
          (+ (+ (* d1 3.0) (* d1 d2)) (* d1 d3)))