Main:bigenough2 from A

Percentage Accurate: 100.0% → 100.0%
Time: 4.2s
Alternatives: 8
Speedup: 1.0×

Specification

?
\[\begin{array}{l} \\ x + y \cdot \left(z + x\right) \end{array} \]
(FPCore (x y z) :precision binary64 (+ x (* y (+ z x))))
double code(double x, double y, double z) {
	return x + (y * (z + x));
}
real(8) function code(x, y, z)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    real(8), intent (in) :: z
    code = x + (y * (z + x))
end function
public static double code(double x, double y, double z) {
	return x + (y * (z + x));
}
def code(x, y, z):
	return x + (y * (z + x))
function code(x, y, z)
	return Float64(x + Float64(y * Float64(z + x)))
end
function tmp = code(x, y, z)
	tmp = x + (y * (z + x));
end
code[x_, y_, z_] := N[(x + N[(y * N[(z + x), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
x + y \cdot \left(z + x\right)
\end{array}

Sampling outcomes in binary64 precision:

Local Percentage Accuracy vs ?

The average percentage accuracy by input value. Horizontal axis shows value of an input variable; the variable is choosen in the title. Vertical axis is accuracy; higher is better. Red represent the original program, while blue represents Herbie's suggestion. These can be toggled with buttons below the plot. The line is an average while dots represent individual samples.

Accuracy vs Speed?

Herbie found 8 alternatives:

AlternativeAccuracySpeedup
The accuracy (vertical axis) and speed (horizontal axis) of each alternatives. Up and to the right is better. The red square shows the initial program, and each blue circle shows an alternative.The line shows the best available speed-accuracy tradeoffs.

Initial Program: 100.0% accurate, 1.0× speedup?

\[\begin{array}{l} \\ x + y \cdot \left(z + x\right) \end{array} \]
(FPCore (x y z) :precision binary64 (+ x (* y (+ z x))))
double code(double x, double y, double z) {
	return x + (y * (z + x));
}
real(8) function code(x, y, z)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    real(8), intent (in) :: z
    code = x + (y * (z + x))
end function
public static double code(double x, double y, double z) {
	return x + (y * (z + x));
}
def code(x, y, z):
	return x + (y * (z + x))
function code(x, y, z)
	return Float64(x + Float64(y * Float64(z + x)))
end
function tmp = code(x, y, z)
	tmp = x + (y * (z + x));
end
code[x_, y_, z_] := N[(x + N[(y * N[(z + x), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
x + y \cdot \left(z + x\right)
\end{array}

Alternative 1: 100.0% accurate, 1.0× speedup?

\[\begin{array}{l} \\ x + y \cdot \left(x + z\right) \end{array} \]
(FPCore (x y z) :precision binary64 (+ x (* y (+ x z))))
double code(double x, double y, double z) {
	return x + (y * (x + z));
}
real(8) function code(x, y, z)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    real(8), intent (in) :: z
    code = x + (y * (x + z))
end function
public static double code(double x, double y, double z) {
	return x + (y * (x + z));
}
def code(x, y, z):
	return x + (y * (x + z))
function code(x, y, z)
	return Float64(x + Float64(y * Float64(x + z)))
end
function tmp = code(x, y, z)
	tmp = x + (y * (x + z));
end
code[x_, y_, z_] := N[(x + N[(y * N[(x + z), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
x + y \cdot \left(x + z\right)
\end{array}
Derivation
  1. Initial program 100.0%

    \[x + y \cdot \left(z + x\right) \]
  2. Add Preprocessing
  3. Final simplification100.0%

    \[\leadsto x + y \cdot \left(x + z\right) \]
  4. Add Preprocessing

Alternative 2: 60.8% accurate, 0.3× speedup?

\[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;y \leq -1.24 \cdot 10^{+194}:\\ \;\;\;\;x \cdot y\\ \mathbf{elif}\;y \leq -6.5 \cdot 10^{-59}:\\ \;\;\;\;y \cdot z\\ \mathbf{elif}\;y \leq 4.5 \cdot 10^{-15}:\\ \;\;\;\;x\\ \mathbf{elif}\;y \leq 2.5 \cdot 10^{+293}:\\ \;\;\;\;y \cdot z\\ \mathbf{else}:\\ \;\;\;\;x \cdot y\\ \end{array} \end{array} \]
(FPCore (x y z)
 :precision binary64
 (if (<= y -1.24e+194)
   (* x y)
   (if (<= y -6.5e-59)
     (* y z)
     (if (<= y 4.5e-15) x (if (<= y 2.5e+293) (* y z) (* x y))))))
double code(double x, double y, double z) {
	double tmp;
	if (y <= -1.24e+194) {
		tmp = x * y;
	} else if (y <= -6.5e-59) {
		tmp = y * z;
	} else if (y <= 4.5e-15) {
		tmp = x;
	} else if (y <= 2.5e+293) {
		tmp = y * z;
	} else {
		tmp = x * y;
	}
	return tmp;
}
real(8) function code(x, y, z)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    real(8), intent (in) :: z
    real(8) :: tmp
    if (y <= (-1.24d+194)) then
        tmp = x * y
    else if (y <= (-6.5d-59)) then
        tmp = y * z
    else if (y <= 4.5d-15) then
        tmp = x
    else if (y <= 2.5d+293) then
        tmp = y * z
    else
        tmp = x * y
    end if
    code = tmp
end function
public static double code(double x, double y, double z) {
	double tmp;
	if (y <= -1.24e+194) {
		tmp = x * y;
	} else if (y <= -6.5e-59) {
		tmp = y * z;
	} else if (y <= 4.5e-15) {
		tmp = x;
	} else if (y <= 2.5e+293) {
		tmp = y * z;
	} else {
		tmp = x * y;
	}
	return tmp;
}
def code(x, y, z):
	tmp = 0
	if y <= -1.24e+194:
		tmp = x * y
	elif y <= -6.5e-59:
		tmp = y * z
	elif y <= 4.5e-15:
		tmp = x
	elif y <= 2.5e+293:
		tmp = y * z
	else:
		tmp = x * y
	return tmp
function code(x, y, z)
	tmp = 0.0
	if (y <= -1.24e+194)
		tmp = Float64(x * y);
	elseif (y <= -6.5e-59)
		tmp = Float64(y * z);
	elseif (y <= 4.5e-15)
		tmp = x;
	elseif (y <= 2.5e+293)
		tmp = Float64(y * z);
	else
		tmp = Float64(x * y);
	end
	return tmp
end
function tmp_2 = code(x, y, z)
	tmp = 0.0;
	if (y <= -1.24e+194)
		tmp = x * y;
	elseif (y <= -6.5e-59)
		tmp = y * z;
	elseif (y <= 4.5e-15)
		tmp = x;
	elseif (y <= 2.5e+293)
		tmp = y * z;
	else
		tmp = x * y;
	end
	tmp_2 = tmp;
end
code[x_, y_, z_] := If[LessEqual[y, -1.24e+194], N[(x * y), $MachinePrecision], If[LessEqual[y, -6.5e-59], N[(y * z), $MachinePrecision], If[LessEqual[y, 4.5e-15], x, If[LessEqual[y, 2.5e+293], N[(y * z), $MachinePrecision], N[(x * y), $MachinePrecision]]]]]
\begin{array}{l}

\\
\begin{array}{l}
\mathbf{if}\;y \leq -1.24 \cdot 10^{+194}:\\
\;\;\;\;x \cdot y\\

\mathbf{elif}\;y \leq -6.5 \cdot 10^{-59}:\\
\;\;\;\;y \cdot z\\

\mathbf{elif}\;y \leq 4.5 \cdot 10^{-15}:\\
\;\;\;\;x\\

\mathbf{elif}\;y \leq 2.5 \cdot 10^{+293}:\\
\;\;\;\;y \cdot z\\

\mathbf{else}:\\
\;\;\;\;x \cdot y\\


\end{array}
\end{array}
Derivation
  1. Split input into 3 regimes
  2. if y < -1.23999999999999994e194 or 2.50000000000000017e293 < y

    1. Initial program 100.0%

      \[x + y \cdot \left(z + x\right) \]
    2. Add Preprocessing
    3. Taylor expanded in x around inf 71.5%

      \[\leadsto \color{blue}{x \cdot \left(1 + y\right)} \]
    4. Step-by-step derivation
      1. +-commutative71.5%

        \[\leadsto x \cdot \color{blue}{\left(y + 1\right)} \]
    5. Simplified71.5%

      \[\leadsto \color{blue}{x \cdot \left(y + 1\right)} \]
    6. Taylor expanded in y around inf 71.5%

      \[\leadsto \color{blue}{x \cdot y} \]
    7. Step-by-step derivation
      1. *-commutative71.5%

        \[\leadsto \color{blue}{y \cdot x} \]
    8. Simplified71.5%

      \[\leadsto \color{blue}{y \cdot x} \]

    if -1.23999999999999994e194 < y < -6.50000000000000017e-59 or 4.4999999999999998e-15 < y < 2.50000000000000017e293

    1. Initial program 100.0%

      \[x + y \cdot \left(z + x\right) \]
    2. Add Preprocessing
    3. Taylor expanded in z around inf 64.9%

      \[\leadsto x + \color{blue}{y \cdot z} \]
    4. Taylor expanded in x around 0 58.8%

      \[\leadsto \color{blue}{y \cdot z} \]

    if -6.50000000000000017e-59 < y < 4.4999999999999998e-15

    1. Initial program 100.0%

      \[x + y \cdot \left(z + x\right) \]
    2. Add Preprocessing
    3. Taylor expanded in x around inf 73.7%

      \[\leadsto \color{blue}{x \cdot \left(1 + y\right)} \]
    4. Step-by-step derivation
      1. +-commutative73.7%

        \[\leadsto x \cdot \color{blue}{\left(y + 1\right)} \]
    5. Simplified73.7%

      \[\leadsto \color{blue}{x \cdot \left(y + 1\right)} \]
    6. Taylor expanded in y around 0 73.7%

      \[\leadsto \color{blue}{x} \]
  3. Recombined 3 regimes into one program.
  4. Final simplification66.0%

    \[\leadsto \begin{array}{l} \mathbf{if}\;y \leq -1.24 \cdot 10^{+194}:\\ \;\;\;\;x \cdot y\\ \mathbf{elif}\;y \leq -6.5 \cdot 10^{-59}:\\ \;\;\;\;y \cdot z\\ \mathbf{elif}\;y \leq 4.5 \cdot 10^{-15}:\\ \;\;\;\;x\\ \mathbf{elif}\;y \leq 2.5 \cdot 10^{+293}:\\ \;\;\;\;y \cdot z\\ \mathbf{else}:\\ \;\;\;\;x \cdot y\\ \end{array} \]
  5. Add Preprocessing

Alternative 3: 98.9% accurate, 0.5× speedup?

\[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;y \leq -1 \lor \neg \left(y \leq 1\right):\\ \;\;\;\;y \cdot \left(x + z\right)\\ \mathbf{else}:\\ \;\;\;\;x + y \cdot z\\ \end{array} \end{array} \]
(FPCore (x y z)
 :precision binary64
 (if (or (<= y -1.0) (not (<= y 1.0))) (* y (+ x z)) (+ x (* y z))))
double code(double x, double y, double z) {
	double tmp;
	if ((y <= -1.0) || !(y <= 1.0)) {
		tmp = y * (x + z);
	} else {
		tmp = x + (y * z);
	}
	return tmp;
}
real(8) function code(x, y, z)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    real(8), intent (in) :: z
    real(8) :: tmp
    if ((y <= (-1.0d0)) .or. (.not. (y <= 1.0d0))) then
        tmp = y * (x + z)
    else
        tmp = x + (y * z)
    end if
    code = tmp
end function
public static double code(double x, double y, double z) {
	double tmp;
	if ((y <= -1.0) || !(y <= 1.0)) {
		tmp = y * (x + z);
	} else {
		tmp = x + (y * z);
	}
	return tmp;
}
def code(x, y, z):
	tmp = 0
	if (y <= -1.0) or not (y <= 1.0):
		tmp = y * (x + z)
	else:
		tmp = x + (y * z)
	return tmp
function code(x, y, z)
	tmp = 0.0
	if ((y <= -1.0) || !(y <= 1.0))
		tmp = Float64(y * Float64(x + z));
	else
		tmp = Float64(x + Float64(y * z));
	end
	return tmp
end
function tmp_2 = code(x, y, z)
	tmp = 0.0;
	if ((y <= -1.0) || ~((y <= 1.0)))
		tmp = y * (x + z);
	else
		tmp = x + (y * z);
	end
	tmp_2 = tmp;
end
code[x_, y_, z_] := If[Or[LessEqual[y, -1.0], N[Not[LessEqual[y, 1.0]], $MachinePrecision]], N[(y * N[(x + z), $MachinePrecision]), $MachinePrecision], N[(x + N[(y * z), $MachinePrecision]), $MachinePrecision]]
\begin{array}{l}

\\
\begin{array}{l}
\mathbf{if}\;y \leq -1 \lor \neg \left(y \leq 1\right):\\
\;\;\;\;y \cdot \left(x + z\right)\\

\mathbf{else}:\\
\;\;\;\;x + y \cdot z\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if y < -1 or 1 < y

    1. Initial program 100.0%

      \[x + y \cdot \left(z + x\right) \]
    2. Add Preprocessing
    3. Taylor expanded in x around 0 95.3%

      \[\leadsto \color{blue}{x \cdot \left(1 + y\right) + y \cdot z} \]
    4. Taylor expanded in y around inf 99.3%

      \[\leadsto \color{blue}{y \cdot \left(x + z\right)} \]

    if -1 < y < 1

    1. Initial program 100.0%

      \[x + y \cdot \left(z + x\right) \]
    2. Add Preprocessing
    3. Taylor expanded in z around inf 96.7%

      \[\leadsto x + \color{blue}{y \cdot z} \]
  3. Recombined 2 regimes into one program.
  4. Final simplification98.0%

    \[\leadsto \begin{array}{l} \mathbf{if}\;y \leq -1 \lor \neg \left(y \leq 1\right):\\ \;\;\;\;y \cdot \left(x + z\right)\\ \mathbf{else}:\\ \;\;\;\;x + y \cdot z\\ \end{array} \]
  5. Add Preprocessing

Alternative 4: 84.8% accurate, 0.5× speedup?

\[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;y \leq -160 \lor \neg \left(y \leq 2 \cdot 10^{-15}\right):\\ \;\;\;\;y \cdot \left(x + z\right)\\ \mathbf{else}:\\ \;\;\;\;x + x \cdot y\\ \end{array} \end{array} \]
(FPCore (x y z)
 :precision binary64
 (if (or (<= y -160.0) (not (<= y 2e-15))) (* y (+ x z)) (+ x (* x y))))
double code(double x, double y, double z) {
	double tmp;
	if ((y <= -160.0) || !(y <= 2e-15)) {
		tmp = y * (x + z);
	} else {
		tmp = x + (x * y);
	}
	return tmp;
}
real(8) function code(x, y, z)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    real(8), intent (in) :: z
    real(8) :: tmp
    if ((y <= (-160.0d0)) .or. (.not. (y <= 2d-15))) then
        tmp = y * (x + z)
    else
        tmp = x + (x * y)
    end if
    code = tmp
end function
public static double code(double x, double y, double z) {
	double tmp;
	if ((y <= -160.0) || !(y <= 2e-15)) {
		tmp = y * (x + z);
	} else {
		tmp = x + (x * y);
	}
	return tmp;
}
def code(x, y, z):
	tmp = 0
	if (y <= -160.0) or not (y <= 2e-15):
		tmp = y * (x + z)
	else:
		tmp = x + (x * y)
	return tmp
function code(x, y, z)
	tmp = 0.0
	if ((y <= -160.0) || !(y <= 2e-15))
		tmp = Float64(y * Float64(x + z));
	else
		tmp = Float64(x + Float64(x * y));
	end
	return tmp
end
function tmp_2 = code(x, y, z)
	tmp = 0.0;
	if ((y <= -160.0) || ~((y <= 2e-15)))
		tmp = y * (x + z);
	else
		tmp = x + (x * y);
	end
	tmp_2 = tmp;
end
code[x_, y_, z_] := If[Or[LessEqual[y, -160.0], N[Not[LessEqual[y, 2e-15]], $MachinePrecision]], N[(y * N[(x + z), $MachinePrecision]), $MachinePrecision], N[(x + N[(x * y), $MachinePrecision]), $MachinePrecision]]
\begin{array}{l}

\\
\begin{array}{l}
\mathbf{if}\;y \leq -160 \lor \neg \left(y \leq 2 \cdot 10^{-15}\right):\\
\;\;\;\;y \cdot \left(x + z\right)\\

\mathbf{else}:\\
\;\;\;\;x + x \cdot y\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if y < -160 or 2.0000000000000002e-15 < y

    1. Initial program 100.0%

      \[x + y \cdot \left(z + x\right) \]
    2. Add Preprocessing
    3. Taylor expanded in x around 0 95.5%

      \[\leadsto \color{blue}{x \cdot \left(1 + y\right) + y \cdot z} \]
    4. Taylor expanded in y around inf 98.6%

      \[\leadsto \color{blue}{y \cdot \left(x + z\right)} \]

    if -160 < y < 2.0000000000000002e-15

    1. Initial program 100.0%

      \[x + y \cdot \left(z + x\right) \]
    2. Add Preprocessing
    3. Taylor expanded in z around 0 70.3%

      \[\leadsto x + \color{blue}{x \cdot y} \]
    4. Step-by-step derivation
      1. *-commutative70.3%

        \[\leadsto x + \color{blue}{y \cdot x} \]
    5. Simplified70.3%

      \[\leadsto x + \color{blue}{y \cdot x} \]
  3. Recombined 2 regimes into one program.
  4. Final simplification85.0%

    \[\leadsto \begin{array}{l} \mathbf{if}\;y \leq -160 \lor \neg \left(y \leq 2 \cdot 10^{-15}\right):\\ \;\;\;\;y \cdot \left(x + z\right)\\ \mathbf{else}:\\ \;\;\;\;x + x \cdot y\\ \end{array} \]
  5. Add Preprocessing

Alternative 5: 84.8% accurate, 0.5× speedup?

\[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;y \leq -1650 \lor \neg \left(y \leq 3.3 \cdot 10^{-18}\right):\\ \;\;\;\;y \cdot \left(x + z\right)\\ \mathbf{else}:\\ \;\;\;\;x \cdot \left(y + 1\right)\\ \end{array} \end{array} \]
(FPCore (x y z)
 :precision binary64
 (if (or (<= y -1650.0) (not (<= y 3.3e-18))) (* y (+ x z)) (* x (+ y 1.0))))
double code(double x, double y, double z) {
	double tmp;
	if ((y <= -1650.0) || !(y <= 3.3e-18)) {
		tmp = y * (x + z);
	} else {
		tmp = x * (y + 1.0);
	}
	return tmp;
}
real(8) function code(x, y, z)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    real(8), intent (in) :: z
    real(8) :: tmp
    if ((y <= (-1650.0d0)) .or. (.not. (y <= 3.3d-18))) then
        tmp = y * (x + z)
    else
        tmp = x * (y + 1.0d0)
    end if
    code = tmp
end function
public static double code(double x, double y, double z) {
	double tmp;
	if ((y <= -1650.0) || !(y <= 3.3e-18)) {
		tmp = y * (x + z);
	} else {
		tmp = x * (y + 1.0);
	}
	return tmp;
}
def code(x, y, z):
	tmp = 0
	if (y <= -1650.0) or not (y <= 3.3e-18):
		tmp = y * (x + z)
	else:
		tmp = x * (y + 1.0)
	return tmp
function code(x, y, z)
	tmp = 0.0
	if ((y <= -1650.0) || !(y <= 3.3e-18))
		tmp = Float64(y * Float64(x + z));
	else
		tmp = Float64(x * Float64(y + 1.0));
	end
	return tmp
end
function tmp_2 = code(x, y, z)
	tmp = 0.0;
	if ((y <= -1650.0) || ~((y <= 3.3e-18)))
		tmp = y * (x + z);
	else
		tmp = x * (y + 1.0);
	end
	tmp_2 = tmp;
end
code[x_, y_, z_] := If[Or[LessEqual[y, -1650.0], N[Not[LessEqual[y, 3.3e-18]], $MachinePrecision]], N[(y * N[(x + z), $MachinePrecision]), $MachinePrecision], N[(x * N[(y + 1.0), $MachinePrecision]), $MachinePrecision]]
\begin{array}{l}

\\
\begin{array}{l}
\mathbf{if}\;y \leq -1650 \lor \neg \left(y \leq 3.3 \cdot 10^{-18}\right):\\
\;\;\;\;y \cdot \left(x + z\right)\\

\mathbf{else}:\\
\;\;\;\;x \cdot \left(y + 1\right)\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if y < -1650 or 3.3000000000000002e-18 < y

    1. Initial program 100.0%

      \[x + y \cdot \left(z + x\right) \]
    2. Add Preprocessing
    3. Taylor expanded in x around 0 95.5%

      \[\leadsto \color{blue}{x \cdot \left(1 + y\right) + y \cdot z} \]
    4. Taylor expanded in y around inf 98.6%

      \[\leadsto \color{blue}{y \cdot \left(x + z\right)} \]

    if -1650 < y < 3.3000000000000002e-18

    1. Initial program 100.0%

      \[x + y \cdot \left(z + x\right) \]
    2. Add Preprocessing
    3. Taylor expanded in x around inf 70.3%

      \[\leadsto \color{blue}{x \cdot \left(1 + y\right)} \]
    4. Step-by-step derivation
      1. +-commutative70.3%

        \[\leadsto x \cdot \color{blue}{\left(y + 1\right)} \]
    5. Simplified70.3%

      \[\leadsto \color{blue}{x \cdot \left(y + 1\right)} \]
  3. Recombined 2 regimes into one program.
  4. Final simplification85.0%

    \[\leadsto \begin{array}{l} \mathbf{if}\;y \leq -1650 \lor \neg \left(y \leq 3.3 \cdot 10^{-18}\right):\\ \;\;\;\;y \cdot \left(x + z\right)\\ \mathbf{else}:\\ \;\;\;\;x \cdot \left(y + 1\right)\\ \end{array} \]
  5. Add Preprocessing

Alternative 6: 74.9% accurate, 0.5× speedup?

\[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;x \leq -3.7 \cdot 10^{-23} \lor \neg \left(x \leq 6.2 \cdot 10^{-97}\right):\\ \;\;\;\;x \cdot \left(y + 1\right)\\ \mathbf{else}:\\ \;\;\;\;y \cdot z\\ \end{array} \end{array} \]
(FPCore (x y z)
 :precision binary64
 (if (or (<= x -3.7e-23) (not (<= x 6.2e-97))) (* x (+ y 1.0)) (* y z)))
double code(double x, double y, double z) {
	double tmp;
	if ((x <= -3.7e-23) || !(x <= 6.2e-97)) {
		tmp = x * (y + 1.0);
	} else {
		tmp = y * z;
	}
	return tmp;
}
real(8) function code(x, y, z)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    real(8), intent (in) :: z
    real(8) :: tmp
    if ((x <= (-3.7d-23)) .or. (.not. (x <= 6.2d-97))) then
        tmp = x * (y + 1.0d0)
    else
        tmp = y * z
    end if
    code = tmp
end function
public static double code(double x, double y, double z) {
	double tmp;
	if ((x <= -3.7e-23) || !(x <= 6.2e-97)) {
		tmp = x * (y + 1.0);
	} else {
		tmp = y * z;
	}
	return tmp;
}
def code(x, y, z):
	tmp = 0
	if (x <= -3.7e-23) or not (x <= 6.2e-97):
		tmp = x * (y + 1.0)
	else:
		tmp = y * z
	return tmp
function code(x, y, z)
	tmp = 0.0
	if ((x <= -3.7e-23) || !(x <= 6.2e-97))
		tmp = Float64(x * Float64(y + 1.0));
	else
		tmp = Float64(y * z);
	end
	return tmp
end
function tmp_2 = code(x, y, z)
	tmp = 0.0;
	if ((x <= -3.7e-23) || ~((x <= 6.2e-97)))
		tmp = x * (y + 1.0);
	else
		tmp = y * z;
	end
	tmp_2 = tmp;
end
code[x_, y_, z_] := If[Or[LessEqual[x, -3.7e-23], N[Not[LessEqual[x, 6.2e-97]], $MachinePrecision]], N[(x * N[(y + 1.0), $MachinePrecision]), $MachinePrecision], N[(y * z), $MachinePrecision]]
\begin{array}{l}

\\
\begin{array}{l}
\mathbf{if}\;x \leq -3.7 \cdot 10^{-23} \lor \neg \left(x \leq 6.2 \cdot 10^{-97}\right):\\
\;\;\;\;x \cdot \left(y + 1\right)\\

\mathbf{else}:\\
\;\;\;\;y \cdot z\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if x < -3.7000000000000003e-23 or 6.20000000000000004e-97 < x

    1. Initial program 100.0%

      \[x + y \cdot \left(z + x\right) \]
    2. Add Preprocessing
    3. Taylor expanded in x around inf 78.9%

      \[\leadsto \color{blue}{x \cdot \left(1 + y\right)} \]
    4. Step-by-step derivation
      1. +-commutative78.9%

        \[\leadsto x \cdot \color{blue}{\left(y + 1\right)} \]
    5. Simplified78.9%

      \[\leadsto \color{blue}{x \cdot \left(y + 1\right)} \]

    if -3.7000000000000003e-23 < x < 6.20000000000000004e-97

    1. Initial program 100.0%

      \[x + y \cdot \left(z + x\right) \]
    2. Add Preprocessing
    3. Taylor expanded in z around inf 91.2%

      \[\leadsto x + \color{blue}{y \cdot z} \]
    4. Taylor expanded in x around 0 75.7%

      \[\leadsto \color{blue}{y \cdot z} \]
  3. Recombined 2 regimes into one program.
  4. Final simplification77.7%

    \[\leadsto \begin{array}{l} \mathbf{if}\;x \leq -3.7 \cdot 10^{-23} \lor \neg \left(x \leq 6.2 \cdot 10^{-97}\right):\\ \;\;\;\;x \cdot \left(y + 1\right)\\ \mathbf{else}:\\ \;\;\;\;y \cdot z\\ \end{array} \]
  5. Add Preprocessing

Alternative 7: 60.0% accurate, 0.5× speedup?

\[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;y \leq -1 \lor \neg \left(y \leq 620000000000\right):\\ \;\;\;\;x \cdot y\\ \mathbf{else}:\\ \;\;\;\;x\\ \end{array} \end{array} \]
(FPCore (x y z)
 :precision binary64
 (if (or (<= y -1.0) (not (<= y 620000000000.0))) (* x y) x))
double code(double x, double y, double z) {
	double tmp;
	if ((y <= -1.0) || !(y <= 620000000000.0)) {
		tmp = x * y;
	} else {
		tmp = x;
	}
	return tmp;
}
real(8) function code(x, y, z)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    real(8), intent (in) :: z
    real(8) :: tmp
    if ((y <= (-1.0d0)) .or. (.not. (y <= 620000000000.0d0))) then
        tmp = x * y
    else
        tmp = x
    end if
    code = tmp
end function
public static double code(double x, double y, double z) {
	double tmp;
	if ((y <= -1.0) || !(y <= 620000000000.0)) {
		tmp = x * y;
	} else {
		tmp = x;
	}
	return tmp;
}
def code(x, y, z):
	tmp = 0
	if (y <= -1.0) or not (y <= 620000000000.0):
		tmp = x * y
	else:
		tmp = x
	return tmp
function code(x, y, z)
	tmp = 0.0
	if ((y <= -1.0) || !(y <= 620000000000.0))
		tmp = Float64(x * y);
	else
		tmp = x;
	end
	return tmp
end
function tmp_2 = code(x, y, z)
	tmp = 0.0;
	if ((y <= -1.0) || ~((y <= 620000000000.0)))
		tmp = x * y;
	else
		tmp = x;
	end
	tmp_2 = tmp;
end
code[x_, y_, z_] := If[Or[LessEqual[y, -1.0], N[Not[LessEqual[y, 620000000000.0]], $MachinePrecision]], N[(x * y), $MachinePrecision], x]
\begin{array}{l}

\\
\begin{array}{l}
\mathbf{if}\;y \leq -1 \lor \neg \left(y \leq 620000000000\right):\\
\;\;\;\;x \cdot y\\

\mathbf{else}:\\
\;\;\;\;x\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if y < -1 or 6.2e11 < y

    1. Initial program 100.0%

      \[x + y \cdot \left(z + x\right) \]
    2. Add Preprocessing
    3. Taylor expanded in x around inf 50.8%

      \[\leadsto \color{blue}{x \cdot \left(1 + y\right)} \]
    4. Step-by-step derivation
      1. +-commutative50.8%

        \[\leadsto x \cdot \color{blue}{\left(y + 1\right)} \]
    5. Simplified50.8%

      \[\leadsto \color{blue}{x \cdot \left(y + 1\right)} \]
    6. Taylor expanded in y around inf 50.1%

      \[\leadsto \color{blue}{x \cdot y} \]
    7. Step-by-step derivation
      1. *-commutative50.1%

        \[\leadsto \color{blue}{y \cdot x} \]
    8. Simplified50.1%

      \[\leadsto \color{blue}{y \cdot x} \]

    if -1 < y < 6.2e11

    1. Initial program 100.0%

      \[x + y \cdot \left(z + x\right) \]
    2. Add Preprocessing
    3. Taylor expanded in x around inf 68.0%

      \[\leadsto \color{blue}{x \cdot \left(1 + y\right)} \]
    4. Step-by-step derivation
      1. +-commutative68.0%

        \[\leadsto x \cdot \color{blue}{\left(y + 1\right)} \]
    5. Simplified68.0%

      \[\leadsto \color{blue}{x \cdot \left(y + 1\right)} \]
    6. Taylor expanded in y around 0 65.2%

      \[\leadsto \color{blue}{x} \]
  3. Recombined 2 regimes into one program.
  4. Final simplification57.7%

    \[\leadsto \begin{array}{l} \mathbf{if}\;y \leq -1 \lor \neg \left(y \leq 620000000000\right):\\ \;\;\;\;x \cdot y\\ \mathbf{else}:\\ \;\;\;\;x\\ \end{array} \]
  5. Add Preprocessing

Alternative 8: 35.5% accurate, 7.0× speedup?

\[\begin{array}{l} \\ x \end{array} \]
(FPCore (x y z) :precision binary64 x)
double code(double x, double y, double z) {
	return x;
}
real(8) function code(x, y, z)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    real(8), intent (in) :: z
    code = x
end function
public static double code(double x, double y, double z) {
	return x;
}
def code(x, y, z):
	return x
function code(x, y, z)
	return x
end
function tmp = code(x, y, z)
	tmp = x;
end
code[x_, y_, z_] := x
\begin{array}{l}

\\
x
\end{array}
Derivation
  1. Initial program 100.0%

    \[x + y \cdot \left(z + x\right) \]
  2. Add Preprocessing
  3. Taylor expanded in x around inf 59.4%

    \[\leadsto \color{blue}{x \cdot \left(1 + y\right)} \]
  4. Step-by-step derivation
    1. +-commutative59.4%

      \[\leadsto x \cdot \color{blue}{\left(y + 1\right)} \]
  5. Simplified59.4%

    \[\leadsto \color{blue}{x \cdot \left(y + 1\right)} \]
  6. Taylor expanded in y around 0 33.9%

    \[\leadsto \color{blue}{x} \]
  7. Add Preprocessing

Reproduce

?
herbie shell --seed 2024137 
(FPCore (x y z)
  :name "Main:bigenough2 from A"
  :precision binary64
  (+ x (* y (+ z x))))