Given's Rotation SVD example

Percentage Accurate: 79.3% → 99.7%
Time: 12.1s
Alternatives: 7
Speedup: 1.0×

Specification

?
\[10^{-150} < \left|x\right| \land \left|x\right| < 10^{+150}\]
\[\begin{array}{l} \\ \sqrt{0.5 \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)} \end{array} \]
(FPCore (p x)
 :precision binary64
 (sqrt (* 0.5 (+ 1.0 (/ x (sqrt (+ (* (* 4.0 p) p) (* x x))))))))
double code(double p, double x) {
	return sqrt((0.5 * (1.0 + (x / sqrt((((4.0 * p) * p) + (x * x)))))));
}
real(8) function code(p, x)
    real(8), intent (in) :: p
    real(8), intent (in) :: x
    code = sqrt((0.5d0 * (1.0d0 + (x / sqrt((((4.0d0 * p) * p) + (x * x)))))))
end function
public static double code(double p, double x) {
	return Math.sqrt((0.5 * (1.0 + (x / Math.sqrt((((4.0 * p) * p) + (x * x)))))));
}
def code(p, x):
	return math.sqrt((0.5 * (1.0 + (x / math.sqrt((((4.0 * p) * p) + (x * x)))))))
function code(p, x)
	return sqrt(Float64(0.5 * Float64(1.0 + Float64(x / sqrt(Float64(Float64(Float64(4.0 * p) * p) + Float64(x * x)))))))
end
function tmp = code(p, x)
	tmp = sqrt((0.5 * (1.0 + (x / sqrt((((4.0 * p) * p) + (x * x)))))));
end
code[p_, x_] := N[Sqrt[N[(0.5 * N[(1.0 + N[(x / N[Sqrt[N[(N[(N[(4.0 * p), $MachinePrecision] * p), $MachinePrecision] + N[(x * x), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]
\begin{array}{l}

\\
\sqrt{0.5 \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)}
\end{array}

Sampling outcomes in binary64 precision:

Local Percentage Accuracy vs ?

The average percentage accuracy by input value. Horizontal axis shows value of an input variable; the variable is choosen in the title. Vertical axis is accuracy; higher is better. Red represent the original program, while blue represents Herbie's suggestion. These can be toggled with buttons below the plot. The line is an average while dots represent individual samples.

Accuracy vs Speed?

Herbie found 7 alternatives:

AlternativeAccuracySpeedup
The accuracy (vertical axis) and speed (horizontal axis) of each alternatives. Up and to the right is better. The red square shows the initial program, and each blue circle shows an alternative.The line shows the best available speed-accuracy tradeoffs.

Initial Program: 79.3% accurate, 1.0× speedup?

\[\begin{array}{l} \\ \sqrt{0.5 \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)} \end{array} \]
(FPCore (p x)
 :precision binary64
 (sqrt (* 0.5 (+ 1.0 (/ x (sqrt (+ (* (* 4.0 p) p) (* x x))))))))
double code(double p, double x) {
	return sqrt((0.5 * (1.0 + (x / sqrt((((4.0 * p) * p) + (x * x)))))));
}
real(8) function code(p, x)
    real(8), intent (in) :: p
    real(8), intent (in) :: x
    code = sqrt((0.5d0 * (1.0d0 + (x / sqrt((((4.0d0 * p) * p) + (x * x)))))))
end function
public static double code(double p, double x) {
	return Math.sqrt((0.5 * (1.0 + (x / Math.sqrt((((4.0 * p) * p) + (x * x)))))));
}
def code(p, x):
	return math.sqrt((0.5 * (1.0 + (x / math.sqrt((((4.0 * p) * p) + (x * x)))))))
function code(p, x)
	return sqrt(Float64(0.5 * Float64(1.0 + Float64(x / sqrt(Float64(Float64(Float64(4.0 * p) * p) + Float64(x * x)))))))
end
function tmp = code(p, x)
	tmp = sqrt((0.5 * (1.0 + (x / sqrt((((4.0 * p) * p) + (x * x)))))));
end
code[p_, x_] := N[Sqrt[N[(0.5 * N[(1.0 + N[(x / N[Sqrt[N[(N[(N[(4.0 * p), $MachinePrecision] * p), $MachinePrecision] + N[(x * x), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]
\begin{array}{l}

\\
\sqrt{0.5 \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)}
\end{array}

Alternative 1: 99.7% accurate, 0.4× speedup?

\[\begin{array}{l} p_m = \left|p\right| \\ \begin{array}{l} \mathbf{if}\;\frac{x}{\sqrt{p\_m \cdot \left(4 \cdot p\_m\right) + x \cdot x}} \leq -0.9999:\\ \;\;\;\;\frac{\frac{{p\_m}^{3}}{{x}^{2}} \cdot 1.5 - p\_m}{x}\\ \mathbf{else}:\\ \;\;\;\;{\left({\left(\mathsf{fma}\left(\frac{x}{\mathsf{hypot}\left(x, p\_m \cdot 2\right)}, 0.5, 0.5\right)\right)}^{1.5}\right)}^{0.3333333333333333}\\ \end{array} \end{array} \]
p_m = (fabs.f64 p)
(FPCore (p_m x)
 :precision binary64
 (if (<= (/ x (sqrt (+ (* p_m (* 4.0 p_m)) (* x x)))) -0.9999)
   (/ (- (* (/ (pow p_m 3.0) (pow x 2.0)) 1.5) p_m) x)
   (pow
    (pow (fma (/ x (hypot x (* p_m 2.0))) 0.5 0.5) 1.5)
    0.3333333333333333)))
p_m = fabs(p);
double code(double p_m, double x) {
	double tmp;
	if ((x / sqrt(((p_m * (4.0 * p_m)) + (x * x)))) <= -0.9999) {
		tmp = (((pow(p_m, 3.0) / pow(x, 2.0)) * 1.5) - p_m) / x;
	} else {
		tmp = pow(pow(fma((x / hypot(x, (p_m * 2.0))), 0.5, 0.5), 1.5), 0.3333333333333333);
	}
	return tmp;
}
p_m = abs(p)
function code(p_m, x)
	tmp = 0.0
	if (Float64(x / sqrt(Float64(Float64(p_m * Float64(4.0 * p_m)) + Float64(x * x)))) <= -0.9999)
		tmp = Float64(Float64(Float64(Float64((p_m ^ 3.0) / (x ^ 2.0)) * 1.5) - p_m) / x);
	else
		tmp = (fma(Float64(x / hypot(x, Float64(p_m * 2.0))), 0.5, 0.5) ^ 1.5) ^ 0.3333333333333333;
	end
	return tmp
end
p_m = N[Abs[p], $MachinePrecision]
code[p$95$m_, x_] := If[LessEqual[N[(x / N[Sqrt[N[(N[(p$95$m * N[(4.0 * p$95$m), $MachinePrecision]), $MachinePrecision] + N[(x * x), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision], -0.9999], N[(N[(N[(N[(N[Power[p$95$m, 3.0], $MachinePrecision] / N[Power[x, 2.0], $MachinePrecision]), $MachinePrecision] * 1.5), $MachinePrecision] - p$95$m), $MachinePrecision] / x), $MachinePrecision], N[Power[N[Power[N[(N[(x / N[Sqrt[x ^ 2 + N[(p$95$m * 2.0), $MachinePrecision] ^ 2], $MachinePrecision]), $MachinePrecision] * 0.5 + 0.5), $MachinePrecision], 1.5], $MachinePrecision], 0.3333333333333333], $MachinePrecision]]
\begin{array}{l}
p_m = \left|p\right|

\\
\begin{array}{l}
\mathbf{if}\;\frac{x}{\sqrt{p\_m \cdot \left(4 \cdot p\_m\right) + x \cdot x}} \leq -0.9999:\\
\;\;\;\;\frac{\frac{{p\_m}^{3}}{{x}^{2}} \cdot 1.5 - p\_m}{x}\\

\mathbf{else}:\\
\;\;\;\;{\left({\left(\mathsf{fma}\left(\frac{x}{\mathsf{hypot}\left(x, p\_m \cdot 2\right)}, 0.5, 0.5\right)\right)}^{1.5}\right)}^{0.3333333333333333}\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if (/.f64 x (sqrt.f64 (+.f64 (*.f64 (*.f64 #s(literal 4 binary64) p) p) (*.f64 x x)))) < -0.99990000000000001

    1. Initial program 16.0%

      \[\sqrt{0.5 \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)} \]
    2. Add Preprocessing
    3. Step-by-step derivation
      1. add-cbrt-cube16.0%

        \[\leadsto \color{blue}{\sqrt[3]{\left(\sqrt{0.5 \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)} \cdot \sqrt{0.5 \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)}\right) \cdot \sqrt{0.5 \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)}}} \]
      2. pow1/316.0%

        \[\leadsto \color{blue}{{\left(\left(\sqrt{0.5 \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)} \cdot \sqrt{0.5 \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)}\right) \cdot \sqrt{0.5 \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)}\right)}^{0.3333333333333333}} \]
    4. Applied egg-rr16.0%

      \[\leadsto \color{blue}{{\left({\left(\mathsf{fma}\left(\frac{x}{\mathsf{hypot}\left(x, 2 \cdot p\right)}, 0.5, 0.5\right)\right)}^{1.5}\right)}^{0.3333333333333333}} \]
    5. Taylor expanded in x around -inf 42.1%

      \[\leadsto \color{blue}{-1 \cdot \frac{p + 0.125 \cdot \frac{-16 \cdot {p}^{4} + 4 \cdot {p}^{4}}{p \cdot {x}^{2}}}{x}} \]
    6. Step-by-step derivation
      1. mul-1-neg42.1%

        \[\leadsto \color{blue}{-\frac{p + 0.125 \cdot \frac{-16 \cdot {p}^{4} + 4 \cdot {p}^{4}}{p \cdot {x}^{2}}}{x}} \]
      2. distribute-neg-frac242.1%

        \[\leadsto \color{blue}{\frac{p + 0.125 \cdot \frac{-16 \cdot {p}^{4} + 4 \cdot {p}^{4}}{p \cdot {x}^{2}}}{-x}} \]
      3. distribute-rgt-out42.1%

        \[\leadsto \frac{p + 0.125 \cdot \frac{\color{blue}{{p}^{4} \cdot \left(-16 + 4\right)}}{p \cdot {x}^{2}}}{-x} \]
      4. *-commutative42.1%

        \[\leadsto \frac{p + 0.125 \cdot \frac{{p}^{4} \cdot \left(-16 + 4\right)}{\color{blue}{{x}^{2} \cdot p}}}{-x} \]
      5. times-frac53.4%

        \[\leadsto \frac{p + 0.125 \cdot \color{blue}{\left(\frac{{p}^{4}}{{x}^{2}} \cdot \frac{-16 + 4}{p}\right)}}{-x} \]
      6. metadata-eval53.4%

        \[\leadsto \frac{p + 0.125 \cdot \left(\frac{{p}^{4}}{{x}^{2}} \cdot \frac{\color{blue}{-12}}{p}\right)}{-x} \]
    7. Simplified53.4%

      \[\leadsto \color{blue}{\frac{p + 0.125 \cdot \left(\frac{{p}^{4}}{{x}^{2}} \cdot \frac{-12}{p}\right)}{-x}} \]
    8. Taylor expanded in x around inf 54.8%

      \[\leadsto \color{blue}{\frac{-1 \cdot p + 1.5 \cdot \frac{{p}^{3}}{{x}^{2}}}{x}} \]
    9. Step-by-step derivation
      1. neg-mul-154.8%

        \[\leadsto \frac{\color{blue}{\left(-p\right)} + 1.5 \cdot \frac{{p}^{3}}{{x}^{2}}}{x} \]
      2. +-commutative54.8%

        \[\leadsto \frac{\color{blue}{1.5 \cdot \frac{{p}^{3}}{{x}^{2}} + \left(-p\right)}}{x} \]
      3. unsub-neg54.8%

        \[\leadsto \frac{\color{blue}{1.5 \cdot \frac{{p}^{3}}{{x}^{2}} - p}}{x} \]
      4. *-commutative54.8%

        \[\leadsto \frac{\color{blue}{\frac{{p}^{3}}{{x}^{2}} \cdot 1.5} - p}{x} \]
    10. Simplified54.8%

      \[\leadsto \color{blue}{\frac{\frac{{p}^{3}}{{x}^{2}} \cdot 1.5 - p}{x}} \]

    if -0.99990000000000001 < (/.f64 x (sqrt.f64 (+.f64 (*.f64 (*.f64 #s(literal 4 binary64) p) p) (*.f64 x x))))

    1. Initial program 99.9%

      \[\sqrt{0.5 \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)} \]
    2. Add Preprocessing
    3. Step-by-step derivation
      1. add-cbrt-cube99.9%

        \[\leadsto \color{blue}{\sqrt[3]{\left(\sqrt{0.5 \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)} \cdot \sqrt{0.5 \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)}\right) \cdot \sqrt{0.5 \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)}}} \]
      2. pow1/399.9%

        \[\leadsto \color{blue}{{\left(\left(\sqrt{0.5 \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)} \cdot \sqrt{0.5 \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)}\right) \cdot \sqrt{0.5 \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)}\right)}^{0.3333333333333333}} \]
    4. Applied egg-rr99.9%

      \[\leadsto \color{blue}{{\left({\left(\mathsf{fma}\left(\frac{x}{\mathsf{hypot}\left(x, 2 \cdot p\right)}, 0.5, 0.5\right)\right)}^{1.5}\right)}^{0.3333333333333333}} \]
  3. Recombined 2 regimes into one program.
  4. Final simplification87.0%

    \[\leadsto \begin{array}{l} \mathbf{if}\;\frac{x}{\sqrt{p \cdot \left(4 \cdot p\right) + x \cdot x}} \leq -0.9999:\\ \;\;\;\;\frac{\frac{{p}^{3}}{{x}^{2}} \cdot 1.5 - p}{x}\\ \mathbf{else}:\\ \;\;\;\;{\left({\left(\mathsf{fma}\left(\frac{x}{\mathsf{hypot}\left(x, p \cdot 2\right)}, 0.5, 0.5\right)\right)}^{1.5}\right)}^{0.3333333333333333}\\ \end{array} \]
  5. Add Preprocessing

Alternative 2: 99.7% accurate, 0.5× speedup?

\[\begin{array}{l} p_m = \left|p\right| \\ \begin{array}{l} \mathbf{if}\;\frac{x}{\sqrt{p\_m \cdot \left(4 \cdot p\_m\right) + x \cdot x}} \leq -0.9999:\\ \;\;\;\;\frac{\frac{{p\_m}^{3}}{{x}^{2}} \cdot 1.5 - p\_m}{x}\\ \mathbf{else}:\\ \;\;\;\;\sqrt{0.5 \cdot \mathsf{fma}\left(\frac{1}{\mathsf{hypot}\left(x, p\_m \cdot 2\right)}, x, 1\right)}\\ \end{array} \end{array} \]
p_m = (fabs.f64 p)
(FPCore (p_m x)
 :precision binary64
 (if (<= (/ x (sqrt (+ (* p_m (* 4.0 p_m)) (* x x)))) -0.9999)
   (/ (- (* (/ (pow p_m 3.0) (pow x 2.0)) 1.5) p_m) x)
   (sqrt (* 0.5 (fma (/ 1.0 (hypot x (* p_m 2.0))) x 1.0)))))
p_m = fabs(p);
double code(double p_m, double x) {
	double tmp;
	if ((x / sqrt(((p_m * (4.0 * p_m)) + (x * x)))) <= -0.9999) {
		tmp = (((pow(p_m, 3.0) / pow(x, 2.0)) * 1.5) - p_m) / x;
	} else {
		tmp = sqrt((0.5 * fma((1.0 / hypot(x, (p_m * 2.0))), x, 1.0)));
	}
	return tmp;
}
p_m = abs(p)
function code(p_m, x)
	tmp = 0.0
	if (Float64(x / sqrt(Float64(Float64(p_m * Float64(4.0 * p_m)) + Float64(x * x)))) <= -0.9999)
		tmp = Float64(Float64(Float64(Float64((p_m ^ 3.0) / (x ^ 2.0)) * 1.5) - p_m) / x);
	else
		tmp = sqrt(Float64(0.5 * fma(Float64(1.0 / hypot(x, Float64(p_m * 2.0))), x, 1.0)));
	end
	return tmp
end
p_m = N[Abs[p], $MachinePrecision]
code[p$95$m_, x_] := If[LessEqual[N[(x / N[Sqrt[N[(N[(p$95$m * N[(4.0 * p$95$m), $MachinePrecision]), $MachinePrecision] + N[(x * x), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision], -0.9999], N[(N[(N[(N[(N[Power[p$95$m, 3.0], $MachinePrecision] / N[Power[x, 2.0], $MachinePrecision]), $MachinePrecision] * 1.5), $MachinePrecision] - p$95$m), $MachinePrecision] / x), $MachinePrecision], N[Sqrt[N[(0.5 * N[(N[(1.0 / N[Sqrt[x ^ 2 + N[(p$95$m * 2.0), $MachinePrecision] ^ 2], $MachinePrecision]), $MachinePrecision] * x + 1.0), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]]
\begin{array}{l}
p_m = \left|p\right|

\\
\begin{array}{l}
\mathbf{if}\;\frac{x}{\sqrt{p\_m \cdot \left(4 \cdot p\_m\right) + x \cdot x}} \leq -0.9999:\\
\;\;\;\;\frac{\frac{{p\_m}^{3}}{{x}^{2}} \cdot 1.5 - p\_m}{x}\\

\mathbf{else}:\\
\;\;\;\;\sqrt{0.5 \cdot \mathsf{fma}\left(\frac{1}{\mathsf{hypot}\left(x, p\_m \cdot 2\right)}, x, 1\right)}\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if (/.f64 x (sqrt.f64 (+.f64 (*.f64 (*.f64 #s(literal 4 binary64) p) p) (*.f64 x x)))) < -0.99990000000000001

    1. Initial program 16.0%

      \[\sqrt{0.5 \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)} \]
    2. Add Preprocessing
    3. Step-by-step derivation
      1. add-cbrt-cube16.0%

        \[\leadsto \color{blue}{\sqrt[3]{\left(\sqrt{0.5 \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)} \cdot \sqrt{0.5 \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)}\right) \cdot \sqrt{0.5 \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)}}} \]
      2. pow1/316.0%

        \[\leadsto \color{blue}{{\left(\left(\sqrt{0.5 \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)} \cdot \sqrt{0.5 \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)}\right) \cdot \sqrt{0.5 \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)}\right)}^{0.3333333333333333}} \]
    4. Applied egg-rr16.0%

      \[\leadsto \color{blue}{{\left({\left(\mathsf{fma}\left(\frac{x}{\mathsf{hypot}\left(x, 2 \cdot p\right)}, 0.5, 0.5\right)\right)}^{1.5}\right)}^{0.3333333333333333}} \]
    5. Taylor expanded in x around -inf 42.1%

      \[\leadsto \color{blue}{-1 \cdot \frac{p + 0.125 \cdot \frac{-16 \cdot {p}^{4} + 4 \cdot {p}^{4}}{p \cdot {x}^{2}}}{x}} \]
    6. Step-by-step derivation
      1. mul-1-neg42.1%

        \[\leadsto \color{blue}{-\frac{p + 0.125 \cdot \frac{-16 \cdot {p}^{4} + 4 \cdot {p}^{4}}{p \cdot {x}^{2}}}{x}} \]
      2. distribute-neg-frac242.1%

        \[\leadsto \color{blue}{\frac{p + 0.125 \cdot \frac{-16 \cdot {p}^{4} + 4 \cdot {p}^{4}}{p \cdot {x}^{2}}}{-x}} \]
      3. distribute-rgt-out42.1%

        \[\leadsto \frac{p + 0.125 \cdot \frac{\color{blue}{{p}^{4} \cdot \left(-16 + 4\right)}}{p \cdot {x}^{2}}}{-x} \]
      4. *-commutative42.1%

        \[\leadsto \frac{p + 0.125 \cdot \frac{{p}^{4} \cdot \left(-16 + 4\right)}{\color{blue}{{x}^{2} \cdot p}}}{-x} \]
      5. times-frac53.4%

        \[\leadsto \frac{p + 0.125 \cdot \color{blue}{\left(\frac{{p}^{4}}{{x}^{2}} \cdot \frac{-16 + 4}{p}\right)}}{-x} \]
      6. metadata-eval53.4%

        \[\leadsto \frac{p + 0.125 \cdot \left(\frac{{p}^{4}}{{x}^{2}} \cdot \frac{\color{blue}{-12}}{p}\right)}{-x} \]
    7. Simplified53.4%

      \[\leadsto \color{blue}{\frac{p + 0.125 \cdot \left(\frac{{p}^{4}}{{x}^{2}} \cdot \frac{-12}{p}\right)}{-x}} \]
    8. Taylor expanded in x around inf 54.8%

      \[\leadsto \color{blue}{\frac{-1 \cdot p + 1.5 \cdot \frac{{p}^{3}}{{x}^{2}}}{x}} \]
    9. Step-by-step derivation
      1. neg-mul-154.8%

        \[\leadsto \frac{\color{blue}{\left(-p\right)} + 1.5 \cdot \frac{{p}^{3}}{{x}^{2}}}{x} \]
      2. +-commutative54.8%

        \[\leadsto \frac{\color{blue}{1.5 \cdot \frac{{p}^{3}}{{x}^{2}} + \left(-p\right)}}{x} \]
      3. unsub-neg54.8%

        \[\leadsto \frac{\color{blue}{1.5 \cdot \frac{{p}^{3}}{{x}^{2}} - p}}{x} \]
      4. *-commutative54.8%

        \[\leadsto \frac{\color{blue}{\frac{{p}^{3}}{{x}^{2}} \cdot 1.5} - p}{x} \]
    10. Simplified54.8%

      \[\leadsto \color{blue}{\frac{\frac{{p}^{3}}{{x}^{2}} \cdot 1.5 - p}{x}} \]

    if -0.99990000000000001 < (/.f64 x (sqrt.f64 (+.f64 (*.f64 (*.f64 #s(literal 4 binary64) p) p) (*.f64 x x))))

    1. Initial program 99.9%

      \[\sqrt{0.5 \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)} \]
    2. Add Preprocessing
    3. Step-by-step derivation
      1. +-commutative99.9%

        \[\leadsto \sqrt{0.5 \cdot \color{blue}{\left(\frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}} + 1\right)}} \]
      2. clear-num99.9%

        \[\leadsto \sqrt{0.5 \cdot \left(\color{blue}{\frac{1}{\frac{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}{x}}} + 1\right)} \]
      3. associate-/r/99.9%

        \[\leadsto \sqrt{0.5 \cdot \left(\color{blue}{\frac{1}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}} \cdot x} + 1\right)} \]
      4. fma-define99.9%

        \[\leadsto \sqrt{0.5 \cdot \color{blue}{\mathsf{fma}\left(\frac{1}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}, x, 1\right)}} \]
      5. +-commutative99.9%

        \[\leadsto \sqrt{0.5 \cdot \mathsf{fma}\left(\frac{1}{\sqrt{\color{blue}{x \cdot x + \left(4 \cdot p\right) \cdot p}}}, x, 1\right)} \]
      6. add-sqr-sqrt99.9%

        \[\leadsto \sqrt{0.5 \cdot \mathsf{fma}\left(\frac{1}{\sqrt{x \cdot x + \color{blue}{\sqrt{\left(4 \cdot p\right) \cdot p} \cdot \sqrt{\left(4 \cdot p\right) \cdot p}}}}, x, 1\right)} \]
      7. hypot-define99.9%

        \[\leadsto \sqrt{0.5 \cdot \mathsf{fma}\left(\frac{1}{\color{blue}{\mathsf{hypot}\left(x, \sqrt{\left(4 \cdot p\right) \cdot p}\right)}}, x, 1\right)} \]
      8. associate-*l*99.9%

        \[\leadsto \sqrt{0.5 \cdot \mathsf{fma}\left(\frac{1}{\mathsf{hypot}\left(x, \sqrt{\color{blue}{4 \cdot \left(p \cdot p\right)}}\right)}, x, 1\right)} \]
      9. sqrt-prod99.9%

        \[\leadsto \sqrt{0.5 \cdot \mathsf{fma}\left(\frac{1}{\mathsf{hypot}\left(x, \color{blue}{\sqrt{4} \cdot \sqrt{p \cdot p}}\right)}, x, 1\right)} \]
      10. metadata-eval99.9%

        \[\leadsto \sqrt{0.5 \cdot \mathsf{fma}\left(\frac{1}{\mathsf{hypot}\left(x, \color{blue}{2} \cdot \sqrt{p \cdot p}\right)}, x, 1\right)} \]
      11. sqrt-unprod43.6%

        \[\leadsto \sqrt{0.5 \cdot \mathsf{fma}\left(\frac{1}{\mathsf{hypot}\left(x, 2 \cdot \color{blue}{\left(\sqrt{p} \cdot \sqrt{p}\right)}\right)}, x, 1\right)} \]
      12. add-sqr-sqrt99.9%

        \[\leadsto \sqrt{0.5 \cdot \mathsf{fma}\left(\frac{1}{\mathsf{hypot}\left(x, 2 \cdot \color{blue}{p}\right)}, x, 1\right)} \]
    4. Applied egg-rr99.9%

      \[\leadsto \sqrt{0.5 \cdot \color{blue}{\mathsf{fma}\left(\frac{1}{\mathsf{hypot}\left(x, 2 \cdot p\right)}, x, 1\right)}} \]
  3. Recombined 2 regimes into one program.
  4. Final simplification87.0%

    \[\leadsto \begin{array}{l} \mathbf{if}\;\frac{x}{\sqrt{p \cdot \left(4 \cdot p\right) + x \cdot x}} \leq -0.9999:\\ \;\;\;\;\frac{\frac{{p}^{3}}{{x}^{2}} \cdot 1.5 - p}{x}\\ \mathbf{else}:\\ \;\;\;\;\sqrt{0.5 \cdot \mathsf{fma}\left(\frac{1}{\mathsf{hypot}\left(x, p \cdot 2\right)}, x, 1\right)}\\ \end{array} \]
  5. Add Preprocessing

Alternative 3: 99.7% accurate, 0.7× speedup?

\[\begin{array}{l} p_m = \left|p\right| \\ \begin{array}{l} \mathbf{if}\;\frac{x}{\sqrt{p\_m \cdot \left(4 \cdot p\_m\right) + x \cdot x}} \leq -0.9999:\\ \;\;\;\;\frac{\frac{{p\_m}^{3}}{{x}^{2}} \cdot 1.5 - p\_m}{x}\\ \mathbf{else}:\\ \;\;\;\;\sqrt{0.5 \cdot \left(1 + \frac{x}{\mathsf{hypot}\left(p\_m \cdot 2, x\right)}\right)}\\ \end{array} \end{array} \]
p_m = (fabs.f64 p)
(FPCore (p_m x)
 :precision binary64
 (if (<= (/ x (sqrt (+ (* p_m (* 4.0 p_m)) (* x x)))) -0.9999)
   (/ (- (* (/ (pow p_m 3.0) (pow x 2.0)) 1.5) p_m) x)
   (sqrt (* 0.5 (+ 1.0 (/ x (hypot (* p_m 2.0) x)))))))
p_m = fabs(p);
double code(double p_m, double x) {
	double tmp;
	if ((x / sqrt(((p_m * (4.0 * p_m)) + (x * x)))) <= -0.9999) {
		tmp = (((pow(p_m, 3.0) / pow(x, 2.0)) * 1.5) - p_m) / x;
	} else {
		tmp = sqrt((0.5 * (1.0 + (x / hypot((p_m * 2.0), x)))));
	}
	return tmp;
}
p_m = Math.abs(p);
public static double code(double p_m, double x) {
	double tmp;
	if ((x / Math.sqrt(((p_m * (4.0 * p_m)) + (x * x)))) <= -0.9999) {
		tmp = (((Math.pow(p_m, 3.0) / Math.pow(x, 2.0)) * 1.5) - p_m) / x;
	} else {
		tmp = Math.sqrt((0.5 * (1.0 + (x / Math.hypot((p_m * 2.0), x)))));
	}
	return tmp;
}
p_m = math.fabs(p)
def code(p_m, x):
	tmp = 0
	if (x / math.sqrt(((p_m * (4.0 * p_m)) + (x * x)))) <= -0.9999:
		tmp = (((math.pow(p_m, 3.0) / math.pow(x, 2.0)) * 1.5) - p_m) / x
	else:
		tmp = math.sqrt((0.5 * (1.0 + (x / math.hypot((p_m * 2.0), x)))))
	return tmp
p_m = abs(p)
function code(p_m, x)
	tmp = 0.0
	if (Float64(x / sqrt(Float64(Float64(p_m * Float64(4.0 * p_m)) + Float64(x * x)))) <= -0.9999)
		tmp = Float64(Float64(Float64(Float64((p_m ^ 3.0) / (x ^ 2.0)) * 1.5) - p_m) / x);
	else
		tmp = sqrt(Float64(0.5 * Float64(1.0 + Float64(x / hypot(Float64(p_m * 2.0), x)))));
	end
	return tmp
end
p_m = abs(p);
function tmp_2 = code(p_m, x)
	tmp = 0.0;
	if ((x / sqrt(((p_m * (4.0 * p_m)) + (x * x)))) <= -0.9999)
		tmp = ((((p_m ^ 3.0) / (x ^ 2.0)) * 1.5) - p_m) / x;
	else
		tmp = sqrt((0.5 * (1.0 + (x / hypot((p_m * 2.0), x)))));
	end
	tmp_2 = tmp;
end
p_m = N[Abs[p], $MachinePrecision]
code[p$95$m_, x_] := If[LessEqual[N[(x / N[Sqrt[N[(N[(p$95$m * N[(4.0 * p$95$m), $MachinePrecision]), $MachinePrecision] + N[(x * x), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision], -0.9999], N[(N[(N[(N[(N[Power[p$95$m, 3.0], $MachinePrecision] / N[Power[x, 2.0], $MachinePrecision]), $MachinePrecision] * 1.5), $MachinePrecision] - p$95$m), $MachinePrecision] / x), $MachinePrecision], N[Sqrt[N[(0.5 * N[(1.0 + N[(x / N[Sqrt[N[(p$95$m * 2.0), $MachinePrecision] ^ 2 + x ^ 2], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]]
\begin{array}{l}
p_m = \left|p\right|

\\
\begin{array}{l}
\mathbf{if}\;\frac{x}{\sqrt{p\_m \cdot \left(4 \cdot p\_m\right) + x \cdot x}} \leq -0.9999:\\
\;\;\;\;\frac{\frac{{p\_m}^{3}}{{x}^{2}} \cdot 1.5 - p\_m}{x}\\

\mathbf{else}:\\
\;\;\;\;\sqrt{0.5 \cdot \left(1 + \frac{x}{\mathsf{hypot}\left(p\_m \cdot 2, x\right)}\right)}\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if (/.f64 x (sqrt.f64 (+.f64 (*.f64 (*.f64 #s(literal 4 binary64) p) p) (*.f64 x x)))) < -0.99990000000000001

    1. Initial program 16.0%

      \[\sqrt{0.5 \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)} \]
    2. Add Preprocessing
    3. Step-by-step derivation
      1. add-cbrt-cube16.0%

        \[\leadsto \color{blue}{\sqrt[3]{\left(\sqrt{0.5 \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)} \cdot \sqrt{0.5 \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)}\right) \cdot \sqrt{0.5 \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)}}} \]
      2. pow1/316.0%

        \[\leadsto \color{blue}{{\left(\left(\sqrt{0.5 \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)} \cdot \sqrt{0.5 \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)}\right) \cdot \sqrt{0.5 \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)}\right)}^{0.3333333333333333}} \]
    4. Applied egg-rr16.0%

      \[\leadsto \color{blue}{{\left({\left(\mathsf{fma}\left(\frac{x}{\mathsf{hypot}\left(x, 2 \cdot p\right)}, 0.5, 0.5\right)\right)}^{1.5}\right)}^{0.3333333333333333}} \]
    5. Taylor expanded in x around -inf 42.1%

      \[\leadsto \color{blue}{-1 \cdot \frac{p + 0.125 \cdot \frac{-16 \cdot {p}^{4} + 4 \cdot {p}^{4}}{p \cdot {x}^{2}}}{x}} \]
    6. Step-by-step derivation
      1. mul-1-neg42.1%

        \[\leadsto \color{blue}{-\frac{p + 0.125 \cdot \frac{-16 \cdot {p}^{4} + 4 \cdot {p}^{4}}{p \cdot {x}^{2}}}{x}} \]
      2. distribute-neg-frac242.1%

        \[\leadsto \color{blue}{\frac{p + 0.125 \cdot \frac{-16 \cdot {p}^{4} + 4 \cdot {p}^{4}}{p \cdot {x}^{2}}}{-x}} \]
      3. distribute-rgt-out42.1%

        \[\leadsto \frac{p + 0.125 \cdot \frac{\color{blue}{{p}^{4} \cdot \left(-16 + 4\right)}}{p \cdot {x}^{2}}}{-x} \]
      4. *-commutative42.1%

        \[\leadsto \frac{p + 0.125 \cdot \frac{{p}^{4} \cdot \left(-16 + 4\right)}{\color{blue}{{x}^{2} \cdot p}}}{-x} \]
      5. times-frac53.4%

        \[\leadsto \frac{p + 0.125 \cdot \color{blue}{\left(\frac{{p}^{4}}{{x}^{2}} \cdot \frac{-16 + 4}{p}\right)}}{-x} \]
      6. metadata-eval53.4%

        \[\leadsto \frac{p + 0.125 \cdot \left(\frac{{p}^{4}}{{x}^{2}} \cdot \frac{\color{blue}{-12}}{p}\right)}{-x} \]
    7. Simplified53.4%

      \[\leadsto \color{blue}{\frac{p + 0.125 \cdot \left(\frac{{p}^{4}}{{x}^{2}} \cdot \frac{-12}{p}\right)}{-x}} \]
    8. Taylor expanded in x around inf 54.8%

      \[\leadsto \color{blue}{\frac{-1 \cdot p + 1.5 \cdot \frac{{p}^{3}}{{x}^{2}}}{x}} \]
    9. Step-by-step derivation
      1. neg-mul-154.8%

        \[\leadsto \frac{\color{blue}{\left(-p\right)} + 1.5 \cdot \frac{{p}^{3}}{{x}^{2}}}{x} \]
      2. +-commutative54.8%

        \[\leadsto \frac{\color{blue}{1.5 \cdot \frac{{p}^{3}}{{x}^{2}} + \left(-p\right)}}{x} \]
      3. unsub-neg54.8%

        \[\leadsto \frac{\color{blue}{1.5 \cdot \frac{{p}^{3}}{{x}^{2}} - p}}{x} \]
      4. *-commutative54.8%

        \[\leadsto \frac{\color{blue}{\frac{{p}^{3}}{{x}^{2}} \cdot 1.5} - p}{x} \]
    10. Simplified54.8%

      \[\leadsto \color{blue}{\frac{\frac{{p}^{3}}{{x}^{2}} \cdot 1.5 - p}{x}} \]

    if -0.99990000000000001 < (/.f64 x (sqrt.f64 (+.f64 (*.f64 (*.f64 #s(literal 4 binary64) p) p) (*.f64 x x))))

    1. Initial program 99.9%

      \[\sqrt{0.5 \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)} \]
    2. Add Preprocessing
    3. Step-by-step derivation
      1. add-sqr-sqrt99.9%

        \[\leadsto \sqrt{0.5 \cdot \left(1 + \frac{x}{\sqrt{\color{blue}{\sqrt{\left(4 \cdot p\right) \cdot p} \cdot \sqrt{\left(4 \cdot p\right) \cdot p}} + x \cdot x}}\right)} \]
      2. hypot-define99.9%

        \[\leadsto \sqrt{0.5 \cdot \left(1 + \frac{x}{\color{blue}{\mathsf{hypot}\left(\sqrt{\left(4 \cdot p\right) \cdot p}, x\right)}}\right)} \]
      3. associate-*l*99.9%

        \[\leadsto \sqrt{0.5 \cdot \left(1 + \frac{x}{\mathsf{hypot}\left(\sqrt{\color{blue}{4 \cdot \left(p \cdot p\right)}}, x\right)}\right)} \]
      4. sqrt-prod99.9%

        \[\leadsto \sqrt{0.5 \cdot \left(1 + \frac{x}{\mathsf{hypot}\left(\color{blue}{\sqrt{4} \cdot \sqrt{p \cdot p}}, x\right)}\right)} \]
      5. metadata-eval99.9%

        \[\leadsto \sqrt{0.5 \cdot \left(1 + \frac{x}{\mathsf{hypot}\left(\color{blue}{2} \cdot \sqrt{p \cdot p}, x\right)}\right)} \]
      6. sqrt-unprod43.6%

        \[\leadsto \sqrt{0.5 \cdot \left(1 + \frac{x}{\mathsf{hypot}\left(2 \cdot \color{blue}{\left(\sqrt{p} \cdot \sqrt{p}\right)}, x\right)}\right)} \]
      7. add-sqr-sqrt99.9%

        \[\leadsto \sqrt{0.5 \cdot \left(1 + \frac{x}{\mathsf{hypot}\left(2 \cdot \color{blue}{p}, x\right)}\right)} \]
    4. Applied egg-rr99.9%

      \[\leadsto \sqrt{0.5 \cdot \left(1 + \frac{x}{\color{blue}{\mathsf{hypot}\left(2 \cdot p, x\right)}}\right)} \]
  3. Recombined 2 regimes into one program.
  4. Final simplification87.0%

    \[\leadsto \begin{array}{l} \mathbf{if}\;\frac{x}{\sqrt{p \cdot \left(4 \cdot p\right) + x \cdot x}} \leq -0.9999:\\ \;\;\;\;\frac{\frac{{p}^{3}}{{x}^{2}} \cdot 1.5 - p}{x}\\ \mathbf{else}:\\ \;\;\;\;\sqrt{0.5 \cdot \left(1 + \frac{x}{\mathsf{hypot}\left(p \cdot 2, x\right)}\right)}\\ \end{array} \]
  5. Add Preprocessing

Alternative 4: 80.1% accurate, 1.0× speedup?

\[\begin{array}{l} p_m = \left|p\right| \\ \begin{array}{l} \mathbf{if}\;x \leq -3.2 \cdot 10^{-83}:\\ \;\;\;\;\frac{p\_m}{-x}\\ \mathbf{else}:\\ \;\;\;\;\sqrt{0.5 \cdot \left(1 + \frac{x}{\mathsf{hypot}\left(p\_m \cdot 2, x\right)}\right)}\\ \end{array} \end{array} \]
p_m = (fabs.f64 p)
(FPCore (p_m x)
 :precision binary64
 (if (<= x -3.2e-83)
   (/ p_m (- x))
   (sqrt (* 0.5 (+ 1.0 (/ x (hypot (* p_m 2.0) x)))))))
p_m = fabs(p);
double code(double p_m, double x) {
	double tmp;
	if (x <= -3.2e-83) {
		tmp = p_m / -x;
	} else {
		tmp = sqrt((0.5 * (1.0 + (x / hypot((p_m * 2.0), x)))));
	}
	return tmp;
}
p_m = Math.abs(p);
public static double code(double p_m, double x) {
	double tmp;
	if (x <= -3.2e-83) {
		tmp = p_m / -x;
	} else {
		tmp = Math.sqrt((0.5 * (1.0 + (x / Math.hypot((p_m * 2.0), x)))));
	}
	return tmp;
}
p_m = math.fabs(p)
def code(p_m, x):
	tmp = 0
	if x <= -3.2e-83:
		tmp = p_m / -x
	else:
		tmp = math.sqrt((0.5 * (1.0 + (x / math.hypot((p_m * 2.0), x)))))
	return tmp
p_m = abs(p)
function code(p_m, x)
	tmp = 0.0
	if (x <= -3.2e-83)
		tmp = Float64(p_m / Float64(-x));
	else
		tmp = sqrt(Float64(0.5 * Float64(1.0 + Float64(x / hypot(Float64(p_m * 2.0), x)))));
	end
	return tmp
end
p_m = abs(p);
function tmp_2 = code(p_m, x)
	tmp = 0.0;
	if (x <= -3.2e-83)
		tmp = p_m / -x;
	else
		tmp = sqrt((0.5 * (1.0 + (x / hypot((p_m * 2.0), x)))));
	end
	tmp_2 = tmp;
end
p_m = N[Abs[p], $MachinePrecision]
code[p$95$m_, x_] := If[LessEqual[x, -3.2e-83], N[(p$95$m / (-x)), $MachinePrecision], N[Sqrt[N[(0.5 * N[(1.0 + N[(x / N[Sqrt[N[(p$95$m * 2.0), $MachinePrecision] ^ 2 + x ^ 2], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]]
\begin{array}{l}
p_m = \left|p\right|

\\
\begin{array}{l}
\mathbf{if}\;x \leq -3.2 \cdot 10^{-83}:\\
\;\;\;\;\frac{p\_m}{-x}\\

\mathbf{else}:\\
\;\;\;\;\sqrt{0.5 \cdot \left(1 + \frac{x}{\mathsf{hypot}\left(p\_m \cdot 2, x\right)}\right)}\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if x < -3.2000000000000001e-83

    1. Initial program 46.1%

      \[\sqrt{0.5 \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)} \]
    2. Add Preprocessing
    3. Step-by-step derivation
      1. add-cbrt-cube46.1%

        \[\leadsto \color{blue}{\sqrt[3]{\left(\sqrt{0.5 \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)} \cdot \sqrt{0.5 \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)}\right) \cdot \sqrt{0.5 \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)}}} \]
      2. pow1/346.1%

        \[\leadsto \color{blue}{{\left(\left(\sqrt{0.5 \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)} \cdot \sqrt{0.5 \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)}\right) \cdot \sqrt{0.5 \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)}\right)}^{0.3333333333333333}} \]
    4. Applied egg-rr46.1%

      \[\leadsto \color{blue}{{\left({\left(\mathsf{fma}\left(\frac{x}{\mathsf{hypot}\left(x, 2 \cdot p\right)}, 0.5, 0.5\right)\right)}^{1.5}\right)}^{0.3333333333333333}} \]
    5. Taylor expanded in x around -inf 37.9%

      \[\leadsto \color{blue}{-1 \cdot \frac{p}{x}} \]
    6. Step-by-step derivation
      1. mul-1-neg37.9%

        \[\leadsto \color{blue}{-\frac{p}{x}} \]
      2. distribute-neg-frac237.9%

        \[\leadsto \color{blue}{\frac{p}{-x}} \]
    7. Simplified37.9%

      \[\leadsto \color{blue}{\frac{p}{-x}} \]

    if -3.2000000000000001e-83 < x

    1. Initial program 93.9%

      \[\sqrt{0.5 \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)} \]
    2. Add Preprocessing
    3. Step-by-step derivation
      1. add-sqr-sqrt93.9%

        \[\leadsto \sqrt{0.5 \cdot \left(1 + \frac{x}{\sqrt{\color{blue}{\sqrt{\left(4 \cdot p\right) \cdot p} \cdot \sqrt{\left(4 \cdot p\right) \cdot p}} + x \cdot x}}\right)} \]
      2. hypot-define93.9%

        \[\leadsto \sqrt{0.5 \cdot \left(1 + \frac{x}{\color{blue}{\mathsf{hypot}\left(\sqrt{\left(4 \cdot p\right) \cdot p}, x\right)}}\right)} \]
      3. associate-*l*93.9%

        \[\leadsto \sqrt{0.5 \cdot \left(1 + \frac{x}{\mathsf{hypot}\left(\sqrt{\color{blue}{4 \cdot \left(p \cdot p\right)}}, x\right)}\right)} \]
      4. sqrt-prod93.9%

        \[\leadsto \sqrt{0.5 \cdot \left(1 + \frac{x}{\mathsf{hypot}\left(\color{blue}{\sqrt{4} \cdot \sqrt{p \cdot p}}, x\right)}\right)} \]
      5. metadata-eval93.9%

        \[\leadsto \sqrt{0.5 \cdot \left(1 + \frac{x}{\mathsf{hypot}\left(\color{blue}{2} \cdot \sqrt{p \cdot p}, x\right)}\right)} \]
      6. sqrt-unprod41.3%

        \[\leadsto \sqrt{0.5 \cdot \left(1 + \frac{x}{\mathsf{hypot}\left(2 \cdot \color{blue}{\left(\sqrt{p} \cdot \sqrt{p}\right)}, x\right)}\right)} \]
      7. add-sqr-sqrt93.9%

        \[\leadsto \sqrt{0.5 \cdot \left(1 + \frac{x}{\mathsf{hypot}\left(2 \cdot \color{blue}{p}, x\right)}\right)} \]
    4. Applied egg-rr93.9%

      \[\leadsto \sqrt{0.5 \cdot \left(1 + \frac{x}{\color{blue}{\mathsf{hypot}\left(2 \cdot p, x\right)}}\right)} \]
  3. Recombined 2 regimes into one program.
  4. Final simplification72.9%

    \[\leadsto \begin{array}{l} \mathbf{if}\;x \leq -3.2 \cdot 10^{-83}:\\ \;\;\;\;\frac{p}{-x}\\ \mathbf{else}:\\ \;\;\;\;\sqrt{0.5 \cdot \left(1 + \frac{x}{\mathsf{hypot}\left(p \cdot 2, x\right)}\right)}\\ \end{array} \]
  5. Add Preprocessing

Alternative 5: 68.1% accurate, 2.0× speedup?

\[\begin{array}{l} p_m = \left|p\right| \\ \begin{array}{l} \mathbf{if}\;p\_m \leq 2 \cdot 10^{-35}:\\ \;\;\;\;\frac{p\_m}{-x}\\ \mathbf{else}:\\ \;\;\;\;\sqrt{0.5}\\ \end{array} \end{array} \]
p_m = (fabs.f64 p)
(FPCore (p_m x)
 :precision binary64
 (if (<= p_m 2e-35) (/ p_m (- x)) (sqrt 0.5)))
p_m = fabs(p);
double code(double p_m, double x) {
	double tmp;
	if (p_m <= 2e-35) {
		tmp = p_m / -x;
	} else {
		tmp = sqrt(0.5);
	}
	return tmp;
}
p_m = abs(p)
real(8) function code(p_m, x)
    real(8), intent (in) :: p_m
    real(8), intent (in) :: x
    real(8) :: tmp
    if (p_m <= 2d-35) then
        tmp = p_m / -x
    else
        tmp = sqrt(0.5d0)
    end if
    code = tmp
end function
p_m = Math.abs(p);
public static double code(double p_m, double x) {
	double tmp;
	if (p_m <= 2e-35) {
		tmp = p_m / -x;
	} else {
		tmp = Math.sqrt(0.5);
	}
	return tmp;
}
p_m = math.fabs(p)
def code(p_m, x):
	tmp = 0
	if p_m <= 2e-35:
		tmp = p_m / -x
	else:
		tmp = math.sqrt(0.5)
	return tmp
p_m = abs(p)
function code(p_m, x)
	tmp = 0.0
	if (p_m <= 2e-35)
		tmp = Float64(p_m / Float64(-x));
	else
		tmp = sqrt(0.5);
	end
	return tmp
end
p_m = abs(p);
function tmp_2 = code(p_m, x)
	tmp = 0.0;
	if (p_m <= 2e-35)
		tmp = p_m / -x;
	else
		tmp = sqrt(0.5);
	end
	tmp_2 = tmp;
end
p_m = N[Abs[p], $MachinePrecision]
code[p$95$m_, x_] := If[LessEqual[p$95$m, 2e-35], N[(p$95$m / (-x)), $MachinePrecision], N[Sqrt[0.5], $MachinePrecision]]
\begin{array}{l}
p_m = \left|p\right|

\\
\begin{array}{l}
\mathbf{if}\;p\_m \leq 2 \cdot 10^{-35}:\\
\;\;\;\;\frac{p\_m}{-x}\\

\mathbf{else}:\\
\;\;\;\;\sqrt{0.5}\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if p < 2.00000000000000002e-35

    1. Initial program 70.0%

      \[\sqrt{0.5 \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)} \]
    2. Add Preprocessing
    3. Step-by-step derivation
      1. add-cbrt-cube70.0%

        \[\leadsto \color{blue}{\sqrt[3]{\left(\sqrt{0.5 \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)} \cdot \sqrt{0.5 \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)}\right) \cdot \sqrt{0.5 \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)}}} \]
      2. pow1/370.0%

        \[\leadsto \color{blue}{{\left(\left(\sqrt{0.5 \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)} \cdot \sqrt{0.5 \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)}\right) \cdot \sqrt{0.5 \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)}\right)}^{0.3333333333333333}} \]
    4. Applied egg-rr70.0%

      \[\leadsto \color{blue}{{\left({\left(\mathsf{fma}\left(\frac{x}{\mathsf{hypot}\left(x, 2 \cdot p\right)}, 0.5, 0.5\right)\right)}^{1.5}\right)}^{0.3333333333333333}} \]
    5. Taylor expanded in x around -inf 21.8%

      \[\leadsto \color{blue}{-1 \cdot \frac{p}{x}} \]
    6. Step-by-step derivation
      1. mul-1-neg21.8%

        \[\leadsto \color{blue}{-\frac{p}{x}} \]
      2. distribute-neg-frac221.8%

        \[\leadsto \color{blue}{\frac{p}{-x}} \]
    7. Simplified21.8%

      \[\leadsto \color{blue}{\frac{p}{-x}} \]

    if 2.00000000000000002e-35 < p

    1. Initial program 98.2%

      \[\sqrt{0.5 \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)} \]
    2. Add Preprocessing
    3. Taylor expanded in x around 0 91.4%

      \[\leadsto \color{blue}{\sqrt{0.5}} \]
  3. Recombined 2 regimes into one program.
  4. Add Preprocessing

Alternative 6: 28.5% accurate, 23.8× speedup?

\[\begin{array}{l} p_m = \left|p\right| \\ \begin{array}{l} \mathbf{if}\;x \leq -4 \cdot 10^{-310}:\\ \;\;\;\;\frac{p\_m}{-x}\\ \mathbf{else}:\\ \;\;\;\;\frac{p\_m}{x}\\ \end{array} \end{array} \]
p_m = (fabs.f64 p)
(FPCore (p_m x)
 :precision binary64
 (if (<= x -4e-310) (/ p_m (- x)) (/ p_m x)))
p_m = fabs(p);
double code(double p_m, double x) {
	double tmp;
	if (x <= -4e-310) {
		tmp = p_m / -x;
	} else {
		tmp = p_m / x;
	}
	return tmp;
}
p_m = abs(p)
real(8) function code(p_m, x)
    real(8), intent (in) :: p_m
    real(8), intent (in) :: x
    real(8) :: tmp
    if (x <= (-4d-310)) then
        tmp = p_m / -x
    else
        tmp = p_m / x
    end if
    code = tmp
end function
p_m = Math.abs(p);
public static double code(double p_m, double x) {
	double tmp;
	if (x <= -4e-310) {
		tmp = p_m / -x;
	} else {
		tmp = p_m / x;
	}
	return tmp;
}
p_m = math.fabs(p)
def code(p_m, x):
	tmp = 0
	if x <= -4e-310:
		tmp = p_m / -x
	else:
		tmp = p_m / x
	return tmp
p_m = abs(p)
function code(p_m, x)
	tmp = 0.0
	if (x <= -4e-310)
		tmp = Float64(p_m / Float64(-x));
	else
		tmp = Float64(p_m / x);
	end
	return tmp
end
p_m = abs(p);
function tmp_2 = code(p_m, x)
	tmp = 0.0;
	if (x <= -4e-310)
		tmp = p_m / -x;
	else
		tmp = p_m / x;
	end
	tmp_2 = tmp;
end
p_m = N[Abs[p], $MachinePrecision]
code[p$95$m_, x_] := If[LessEqual[x, -4e-310], N[(p$95$m / (-x)), $MachinePrecision], N[(p$95$m / x), $MachinePrecision]]
\begin{array}{l}
p_m = \left|p\right|

\\
\begin{array}{l}
\mathbf{if}\;x \leq -4 \cdot 10^{-310}:\\
\;\;\;\;\frac{p\_m}{-x}\\

\mathbf{else}:\\
\;\;\;\;\frac{p\_m}{x}\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if x < -3.999999999999988e-310

    1. Initial program 52.0%

      \[\sqrt{0.5 \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)} \]
    2. Add Preprocessing
    3. Step-by-step derivation
      1. add-cbrt-cube52.0%

        \[\leadsto \color{blue}{\sqrt[3]{\left(\sqrt{0.5 \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)} \cdot \sqrt{0.5 \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)}\right) \cdot \sqrt{0.5 \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)}}} \]
      2. pow1/352.0%

        \[\leadsto \color{blue}{{\left(\left(\sqrt{0.5 \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)} \cdot \sqrt{0.5 \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)}\right) \cdot \sqrt{0.5 \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)}\right)}^{0.3333333333333333}} \]
    4. Applied egg-rr52.0%

      \[\leadsto \color{blue}{{\left({\left(\mathsf{fma}\left(\frac{x}{\mathsf{hypot}\left(x, 2 \cdot p\right)}, 0.5, 0.5\right)\right)}^{1.5}\right)}^{0.3333333333333333}} \]
    5. Taylor expanded in x around -inf 32.4%

      \[\leadsto \color{blue}{-1 \cdot \frac{p}{x}} \]
    6. Step-by-step derivation
      1. mul-1-neg32.4%

        \[\leadsto \color{blue}{-\frac{p}{x}} \]
      2. distribute-neg-frac232.4%

        \[\leadsto \color{blue}{\frac{p}{-x}} \]
    7. Simplified32.4%

      \[\leadsto \color{blue}{\frac{p}{-x}} \]

    if -3.999999999999988e-310 < x

    1. Initial program 100.0%

      \[\sqrt{0.5 \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)} \]
    2. Add Preprocessing
    3. Step-by-step derivation
      1. add-cbrt-cube99.9%

        \[\leadsto \color{blue}{\sqrt[3]{\left(\sqrt{0.5 \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)} \cdot \sqrt{0.5 \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)}\right) \cdot \sqrt{0.5 \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)}}} \]
      2. pow1/3100.0%

        \[\leadsto \color{blue}{{\left(\left(\sqrt{0.5 \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)} \cdot \sqrt{0.5 \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)}\right) \cdot \sqrt{0.5 \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)}\right)}^{0.3333333333333333}} \]
    4. Applied egg-rr100.0%

      \[\leadsto \color{blue}{{\left({\left(\mathsf{fma}\left(\frac{x}{\mathsf{hypot}\left(x, 2 \cdot p\right)}, 0.5, 0.5\right)\right)}^{1.5}\right)}^{0.3333333333333333}} \]
    5. Taylor expanded in x around -inf 3.8%

      \[\leadsto \color{blue}{-1 \cdot \frac{p}{x}} \]
    6. Step-by-step derivation
      1. mul-1-neg3.8%

        \[\leadsto \color{blue}{-\frac{p}{x}} \]
      2. distribute-neg-frac23.8%

        \[\leadsto \color{blue}{\frac{p}{-x}} \]
    7. Simplified3.8%

      \[\leadsto \color{blue}{\frac{p}{-x}} \]
    8. Step-by-step derivation
      1. add-sqr-sqrt0.0%

        \[\leadsto \frac{p}{\color{blue}{\sqrt{-x} \cdot \sqrt{-x}}} \]
      2. sqrt-unprod3.2%

        \[\leadsto \frac{p}{\color{blue}{\sqrt{\left(-x\right) \cdot \left(-x\right)}}} \]
      3. sqr-neg3.2%

        \[\leadsto \frac{p}{\sqrt{\color{blue}{x \cdot x}}} \]
      4. sqrt-prod3.2%

        \[\leadsto \frac{p}{\color{blue}{\sqrt{x} \cdot \sqrt{x}}} \]
      5. add-sqr-sqrt3.2%

        \[\leadsto \frac{p}{\color{blue}{x}} \]
      6. *-un-lft-identity3.2%

        \[\leadsto \frac{p}{\color{blue}{1 \cdot x}} \]
    9. Applied egg-rr3.2%

      \[\leadsto \frac{p}{\color{blue}{1 \cdot x}} \]
    10. Step-by-step derivation
      1. *-lft-identity3.2%

        \[\leadsto \frac{p}{\color{blue}{x}} \]
    11. Simplified3.2%

      \[\leadsto \frac{p}{\color{blue}{x}} \]
  3. Recombined 2 regimes into one program.
  4. Add Preprocessing

Alternative 7: 6.2% accurate, 71.7× speedup?

\[\begin{array}{l} p_m = \left|p\right| \\ \frac{p\_m}{x} \end{array} \]
p_m = (fabs.f64 p)
(FPCore (p_m x) :precision binary64 (/ p_m x))
p_m = fabs(p);
double code(double p_m, double x) {
	return p_m / x;
}
p_m = abs(p)
real(8) function code(p_m, x)
    real(8), intent (in) :: p_m
    real(8), intent (in) :: x
    code = p_m / x
end function
p_m = Math.abs(p);
public static double code(double p_m, double x) {
	return p_m / x;
}
p_m = math.fabs(p)
def code(p_m, x):
	return p_m / x
p_m = abs(p)
function code(p_m, x)
	return Float64(p_m / x)
end
p_m = abs(p);
function tmp = code(p_m, x)
	tmp = p_m / x;
end
p_m = N[Abs[p], $MachinePrecision]
code[p$95$m_, x_] := N[(p$95$m / x), $MachinePrecision]
\begin{array}{l}
p_m = \left|p\right|

\\
\frac{p\_m}{x}
\end{array}
Derivation
  1. Initial program 76.0%

    \[\sqrt{0.5 \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)} \]
  2. Add Preprocessing
  3. Step-by-step derivation
    1. add-cbrt-cube75.9%

      \[\leadsto \color{blue}{\sqrt[3]{\left(\sqrt{0.5 \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)} \cdot \sqrt{0.5 \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)}\right) \cdot \sqrt{0.5 \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)}}} \]
    2. pow1/376.0%

      \[\leadsto \color{blue}{{\left(\left(\sqrt{0.5 \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)} \cdot \sqrt{0.5 \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)}\right) \cdot \sqrt{0.5 \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)}\right)}^{0.3333333333333333}} \]
  4. Applied egg-rr76.0%

    \[\leadsto \color{blue}{{\left({\left(\mathsf{fma}\left(\frac{x}{\mathsf{hypot}\left(x, 2 \cdot p\right)}, 0.5, 0.5\right)\right)}^{1.5}\right)}^{0.3333333333333333}} \]
  5. Taylor expanded in x around -inf 18.1%

    \[\leadsto \color{blue}{-1 \cdot \frac{p}{x}} \]
  6. Step-by-step derivation
    1. mul-1-neg18.1%

      \[\leadsto \color{blue}{-\frac{p}{x}} \]
    2. distribute-neg-frac218.1%

      \[\leadsto \color{blue}{\frac{p}{-x}} \]
  7. Simplified18.1%

    \[\leadsto \color{blue}{\frac{p}{-x}} \]
  8. Step-by-step derivation
    1. add-sqr-sqrt16.1%

      \[\leadsto \frac{p}{\color{blue}{\sqrt{-x} \cdot \sqrt{-x}}} \]
    2. sqrt-unprod17.8%

      \[\leadsto \frac{p}{\color{blue}{\sqrt{\left(-x\right) \cdot \left(-x\right)}}} \]
    3. sqr-neg17.8%

      \[\leadsto \frac{p}{\sqrt{\color{blue}{x \cdot x}}} \]
    4. sqrt-prod1.6%

      \[\leadsto \frac{p}{\color{blue}{\sqrt{x} \cdot \sqrt{x}}} \]
    5. add-sqr-sqrt19.2%

      \[\leadsto \frac{p}{\color{blue}{x}} \]
    6. *-un-lft-identity19.2%

      \[\leadsto \frac{p}{\color{blue}{1 \cdot x}} \]
  9. Applied egg-rr19.2%

    \[\leadsto \frac{p}{\color{blue}{1 \cdot x}} \]
  10. Step-by-step derivation
    1. *-lft-identity19.2%

      \[\leadsto \frac{p}{\color{blue}{x}} \]
  11. Simplified19.2%

    \[\leadsto \frac{p}{\color{blue}{x}} \]
  12. Add Preprocessing

Developer Target 1: 79.3% accurate, 0.7× speedup?

\[\begin{array}{l} \\ \sqrt{0.5 + \frac{\mathsf{copysign}\left(0.5, x\right)}{\mathsf{hypot}\left(1, \frac{2 \cdot p}{x}\right)}} \end{array} \]
(FPCore (p x)
 :precision binary64
 (sqrt (+ 0.5 (/ (copysign 0.5 x) (hypot 1.0 (/ (* 2.0 p) x))))))
double code(double p, double x) {
	return sqrt((0.5 + (copysign(0.5, x) / hypot(1.0, ((2.0 * p) / x)))));
}
public static double code(double p, double x) {
	return Math.sqrt((0.5 + (Math.copySign(0.5, x) / Math.hypot(1.0, ((2.0 * p) / x)))));
}
def code(p, x):
	return math.sqrt((0.5 + (math.copysign(0.5, x) / math.hypot(1.0, ((2.0 * p) / x)))))
function code(p, x)
	return sqrt(Float64(0.5 + Float64(copysign(0.5, x) / hypot(1.0, Float64(Float64(2.0 * p) / x)))))
end
function tmp = code(p, x)
	tmp = sqrt((0.5 + ((sign(x) * abs(0.5)) / hypot(1.0, ((2.0 * p) / x)))));
end
code[p_, x_] := N[Sqrt[N[(0.5 + N[(N[With[{TMP1 = Abs[0.5], TMP2 = Sign[x]}, TMP1 * If[TMP2 == 0, 1, TMP2]], $MachinePrecision] / N[Sqrt[1.0 ^ 2 + N[(N[(2.0 * p), $MachinePrecision] / x), $MachinePrecision] ^ 2], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]
\begin{array}{l}

\\
\sqrt{0.5 + \frac{\mathsf{copysign}\left(0.5, x\right)}{\mathsf{hypot}\left(1, \frac{2 \cdot p}{x}\right)}}
\end{array}

Reproduce

?
herbie shell --seed 2024135 
(FPCore (p x)
  :name "Given's Rotation SVD example"
  :precision binary64
  :pre (and (< 1e-150 (fabs x)) (< (fabs x) 1e+150))

  :alt
  (! :herbie-platform default (sqrt (+ 1/2 (/ (copysign 1/2 x) (hypot 1 (/ (* 2 p) x))))))

  (sqrt (* 0.5 (+ 1.0 (/ x (sqrt (+ (* (* 4.0 p) p) (* x x))))))))