Graphics.Rendering.Plot.Render.Plot.Legend:renderLegendOutside from plot-0.2.3.4, B

Percentage Accurate: 99.9% → 99.9%
Time: 15.1s
Alternatives: 15
Speedup: 1.0×

Specification

?
\[\begin{array}{l} \\ x \cdot \left(\left(\left(\left(y + z\right) + z\right) + y\right) + t\right) + y \cdot 5 \end{array} \]
(FPCore (x y z t)
 :precision binary64
 (+ (* x (+ (+ (+ (+ y z) z) y) t)) (* y 5.0)))
double code(double x, double y, double z, double t) {
	return (x * ((((y + z) + z) + y) + t)) + (y * 5.0);
}
real(8) function code(x, y, z, t)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    real(8), intent (in) :: z
    real(8), intent (in) :: t
    code = (x * ((((y + z) + z) + y) + t)) + (y * 5.0d0)
end function
public static double code(double x, double y, double z, double t) {
	return (x * ((((y + z) + z) + y) + t)) + (y * 5.0);
}
def code(x, y, z, t):
	return (x * ((((y + z) + z) + y) + t)) + (y * 5.0)
function code(x, y, z, t)
	return Float64(Float64(x * Float64(Float64(Float64(Float64(y + z) + z) + y) + t)) + Float64(y * 5.0))
end
function tmp = code(x, y, z, t)
	tmp = (x * ((((y + z) + z) + y) + t)) + (y * 5.0);
end
code[x_, y_, z_, t_] := N[(N[(x * N[(N[(N[(N[(y + z), $MachinePrecision] + z), $MachinePrecision] + y), $MachinePrecision] + t), $MachinePrecision]), $MachinePrecision] + N[(y * 5.0), $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
x \cdot \left(\left(\left(\left(y + z\right) + z\right) + y\right) + t\right) + y \cdot 5
\end{array}

Sampling outcomes in binary64 precision:

Local Percentage Accuracy vs ?

The average percentage accuracy by input value. Horizontal axis shows value of an input variable; the variable is choosen in the title. Vertical axis is accuracy; higher is better. Red represent the original program, while blue represents Herbie's suggestion. These can be toggled with buttons below the plot. The line is an average while dots represent individual samples.

Accuracy vs Speed?

Herbie found 15 alternatives:

AlternativeAccuracySpeedup
The accuracy (vertical axis) and speed (horizontal axis) of each alternatives. Up and to the right is better. The red square shows the initial program, and each blue circle shows an alternative.The line shows the best available speed-accuracy tradeoffs.

Initial Program: 99.9% accurate, 1.0× speedup?

\[\begin{array}{l} \\ x \cdot \left(\left(\left(\left(y + z\right) + z\right) + y\right) + t\right) + y \cdot 5 \end{array} \]
(FPCore (x y z t)
 :precision binary64
 (+ (* x (+ (+ (+ (+ y z) z) y) t)) (* y 5.0)))
double code(double x, double y, double z, double t) {
	return (x * ((((y + z) + z) + y) + t)) + (y * 5.0);
}
real(8) function code(x, y, z, t)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    real(8), intent (in) :: z
    real(8), intent (in) :: t
    code = (x * ((((y + z) + z) + y) + t)) + (y * 5.0d0)
end function
public static double code(double x, double y, double z, double t) {
	return (x * ((((y + z) + z) + y) + t)) + (y * 5.0);
}
def code(x, y, z, t):
	return (x * ((((y + z) + z) + y) + t)) + (y * 5.0)
function code(x, y, z, t)
	return Float64(Float64(x * Float64(Float64(Float64(Float64(y + z) + z) + y) + t)) + Float64(y * 5.0))
end
function tmp = code(x, y, z, t)
	tmp = (x * ((((y + z) + z) + y) + t)) + (y * 5.0);
end
code[x_, y_, z_, t_] := N[(N[(x * N[(N[(N[(N[(y + z), $MachinePrecision] + z), $MachinePrecision] + y), $MachinePrecision] + t), $MachinePrecision]), $MachinePrecision] + N[(y * 5.0), $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
x \cdot \left(\left(\left(\left(y + z\right) + z\right) + y\right) + t\right) + y \cdot 5
\end{array}

Alternative 1: 99.9% accurate, 0.1× speedup?

\[\begin{array}{l} \\ \mathsf{fma}\left(x, 2 \cdot \left(y + z\right) + t, y \cdot 5\right) \end{array} \]
(FPCore (x y z t) :precision binary64 (fma x (+ (* 2.0 (+ y z)) t) (* y 5.0)))
double code(double x, double y, double z, double t) {
	return fma(x, ((2.0 * (y + z)) + t), (y * 5.0));
}
function code(x, y, z, t)
	return fma(x, Float64(Float64(2.0 * Float64(y + z)) + t), Float64(y * 5.0))
end
code[x_, y_, z_, t_] := N[(x * N[(N[(2.0 * N[(y + z), $MachinePrecision]), $MachinePrecision] + t), $MachinePrecision] + N[(y * 5.0), $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
\mathsf{fma}\left(x, 2 \cdot \left(y + z\right) + t, y \cdot 5\right)
\end{array}
Derivation
  1. Initial program 99.9%

    \[x \cdot \left(\left(\left(\left(y + z\right) + z\right) + y\right) + t\right) + y \cdot 5 \]
  2. Step-by-step derivation
    1. fma-define99.9%

      \[\leadsto \color{blue}{\mathsf{fma}\left(x, \left(\left(\left(y + z\right) + z\right) + y\right) + t, y \cdot 5\right)} \]
    2. associate-+l+99.9%

      \[\leadsto \mathsf{fma}\left(x, \color{blue}{\left(\left(y + z\right) + \left(z + y\right)\right)} + t, y \cdot 5\right) \]
    3. +-commutative99.9%

      \[\leadsto \mathsf{fma}\left(x, \left(\left(y + z\right) + \color{blue}{\left(y + z\right)}\right) + t, y \cdot 5\right) \]
    4. count-299.9%

      \[\leadsto \mathsf{fma}\left(x, \color{blue}{2 \cdot \left(y + z\right)} + t, y \cdot 5\right) \]
  3. Simplified99.9%

    \[\leadsto \color{blue}{\mathsf{fma}\left(x, 2 \cdot \left(y + z\right) + t, y \cdot 5\right)} \]
  4. Add Preprocessing
  5. Add Preprocessing

Alternative 2: 62.9% accurate, 0.6× speedup?

\[\begin{array}{l} \\ \begin{array}{l} t_1 := x \cdot \left(t + 2 \cdot y\right)\\ \mathbf{if}\;x \leq -1.7 \cdot 10^{-12}:\\ \;\;\;\;t\_1\\ \mathbf{elif}\;x \leq 6.2 \cdot 10^{-48}:\\ \;\;\;\;y \cdot 5\\ \mathbf{elif}\;x \leq 1.25 \cdot 10^{+212} \lor \neg \left(x \leq 1.95 \cdot 10^{+235}\right):\\ \;\;\;\;t\_1\\ \mathbf{else}:\\ \;\;\;\;z \cdot \left(x \cdot 2\right)\\ \end{array} \end{array} \]
(FPCore (x y z t)
 :precision binary64
 (let* ((t_1 (* x (+ t (* 2.0 y)))))
   (if (<= x -1.7e-12)
     t_1
     (if (<= x 6.2e-48)
       (* y 5.0)
       (if (or (<= x 1.25e+212) (not (<= x 1.95e+235)))
         t_1
         (* z (* x 2.0)))))))
double code(double x, double y, double z, double t) {
	double t_1 = x * (t + (2.0 * y));
	double tmp;
	if (x <= -1.7e-12) {
		tmp = t_1;
	} else if (x <= 6.2e-48) {
		tmp = y * 5.0;
	} else if ((x <= 1.25e+212) || !(x <= 1.95e+235)) {
		tmp = t_1;
	} else {
		tmp = z * (x * 2.0);
	}
	return tmp;
}
real(8) function code(x, y, z, t)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    real(8), intent (in) :: z
    real(8), intent (in) :: t
    real(8) :: t_1
    real(8) :: tmp
    t_1 = x * (t + (2.0d0 * y))
    if (x <= (-1.7d-12)) then
        tmp = t_1
    else if (x <= 6.2d-48) then
        tmp = y * 5.0d0
    else if ((x <= 1.25d+212) .or. (.not. (x <= 1.95d+235))) then
        tmp = t_1
    else
        tmp = z * (x * 2.0d0)
    end if
    code = tmp
end function
public static double code(double x, double y, double z, double t) {
	double t_1 = x * (t + (2.0 * y));
	double tmp;
	if (x <= -1.7e-12) {
		tmp = t_1;
	} else if (x <= 6.2e-48) {
		tmp = y * 5.0;
	} else if ((x <= 1.25e+212) || !(x <= 1.95e+235)) {
		tmp = t_1;
	} else {
		tmp = z * (x * 2.0);
	}
	return tmp;
}
def code(x, y, z, t):
	t_1 = x * (t + (2.0 * y))
	tmp = 0
	if x <= -1.7e-12:
		tmp = t_1
	elif x <= 6.2e-48:
		tmp = y * 5.0
	elif (x <= 1.25e+212) or not (x <= 1.95e+235):
		tmp = t_1
	else:
		tmp = z * (x * 2.0)
	return tmp
function code(x, y, z, t)
	t_1 = Float64(x * Float64(t + Float64(2.0 * y)))
	tmp = 0.0
	if (x <= -1.7e-12)
		tmp = t_1;
	elseif (x <= 6.2e-48)
		tmp = Float64(y * 5.0);
	elseif ((x <= 1.25e+212) || !(x <= 1.95e+235))
		tmp = t_1;
	else
		tmp = Float64(z * Float64(x * 2.0));
	end
	return tmp
end
function tmp_2 = code(x, y, z, t)
	t_1 = x * (t + (2.0 * y));
	tmp = 0.0;
	if (x <= -1.7e-12)
		tmp = t_1;
	elseif (x <= 6.2e-48)
		tmp = y * 5.0;
	elseif ((x <= 1.25e+212) || ~((x <= 1.95e+235)))
		tmp = t_1;
	else
		tmp = z * (x * 2.0);
	end
	tmp_2 = tmp;
end
code[x_, y_, z_, t_] := Block[{t$95$1 = N[(x * N[(t + N[(2.0 * y), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[x, -1.7e-12], t$95$1, If[LessEqual[x, 6.2e-48], N[(y * 5.0), $MachinePrecision], If[Or[LessEqual[x, 1.25e+212], N[Not[LessEqual[x, 1.95e+235]], $MachinePrecision]], t$95$1, N[(z * N[(x * 2.0), $MachinePrecision]), $MachinePrecision]]]]]
\begin{array}{l}

\\
\begin{array}{l}
t_1 := x \cdot \left(t + 2 \cdot y\right)\\
\mathbf{if}\;x \leq -1.7 \cdot 10^{-12}:\\
\;\;\;\;t\_1\\

\mathbf{elif}\;x \leq 6.2 \cdot 10^{-48}:\\
\;\;\;\;y \cdot 5\\

\mathbf{elif}\;x \leq 1.25 \cdot 10^{+212} \lor \neg \left(x \leq 1.95 \cdot 10^{+235}\right):\\
\;\;\;\;t\_1\\

\mathbf{else}:\\
\;\;\;\;z \cdot \left(x \cdot 2\right)\\


\end{array}
\end{array}
Derivation
  1. Split input into 3 regimes
  2. if x < -1.7e-12 or 6.20000000000000033e-48 < x < 1.24999999999999998e212 or 1.9500000000000001e235 < x

    1. Initial program 100.0%

      \[x \cdot \left(\left(\left(\left(y + z\right) + z\right) + y\right) + t\right) + y \cdot 5 \]
    2. Step-by-step derivation
      1. fma-define100.0%

        \[\leadsto \color{blue}{\mathsf{fma}\left(x, \left(\left(\left(y + z\right) + z\right) + y\right) + t, y \cdot 5\right)} \]
      2. associate-+l+100.0%

        \[\leadsto \mathsf{fma}\left(x, \color{blue}{\left(\left(y + z\right) + \left(z + y\right)\right)} + t, y \cdot 5\right) \]
      3. +-commutative100.0%

        \[\leadsto \mathsf{fma}\left(x, \left(\left(y + z\right) + \color{blue}{\left(y + z\right)}\right) + t, y \cdot 5\right) \]
      4. count-2100.0%

        \[\leadsto \mathsf{fma}\left(x, \color{blue}{2 \cdot \left(y + z\right)} + t, y \cdot 5\right) \]
    3. Simplified100.0%

      \[\leadsto \color{blue}{\mathsf{fma}\left(x, 2 \cdot \left(y + z\right) + t, y \cdot 5\right)} \]
    4. Add Preprocessing
    5. Taylor expanded in x around inf 99.6%

      \[\leadsto \color{blue}{x \cdot \left(t + 2 \cdot \left(y + z\right)\right)} \]
    6. Taylor expanded in z around 0 76.4%

      \[\leadsto \color{blue}{x \cdot \left(t + 2 \cdot y\right)} \]

    if -1.7e-12 < x < 6.20000000000000033e-48

    1. Initial program 99.8%

      \[x \cdot \left(\left(\left(\left(y + z\right) + z\right) + y\right) + t\right) + y \cdot 5 \]
    2. Add Preprocessing
    3. Taylor expanded in x around 0 63.8%

      \[\leadsto \color{blue}{5 \cdot y} \]

    if 1.24999999999999998e212 < x < 1.9500000000000001e235

    1. Initial program 100.0%

      \[x \cdot \left(\left(\left(\left(y + z\right) + z\right) + y\right) + t\right) + y \cdot 5 \]
    2. Add Preprocessing
    3. Taylor expanded in z around inf 86.1%

      \[\leadsto \color{blue}{2 \cdot \left(x \cdot z\right)} \]
    4. Simplified86.1%

      \[\leadsto \color{blue}{\left(x \cdot 2\right) \cdot z} \]
  3. Recombined 3 regimes into one program.
  4. Final simplification71.4%

    \[\leadsto \begin{array}{l} \mathbf{if}\;x \leq -1.7 \cdot 10^{-12}:\\ \;\;\;\;x \cdot \left(t + 2 \cdot y\right)\\ \mathbf{elif}\;x \leq 6.2 \cdot 10^{-48}:\\ \;\;\;\;y \cdot 5\\ \mathbf{elif}\;x \leq 1.25 \cdot 10^{+212} \lor \neg \left(x \leq 1.95 \cdot 10^{+235}\right):\\ \;\;\;\;x \cdot \left(t + 2 \cdot y\right)\\ \mathbf{else}:\\ \;\;\;\;z \cdot \left(x \cdot 2\right)\\ \end{array} \]
  5. Add Preprocessing

Alternative 3: 65.5% accurate, 0.6× speedup?

\[\begin{array}{l} \\ \begin{array}{l} t_1 := x \cdot \left(t + 2 \cdot z\right)\\ t_2 := x \cdot \left(t + 2 \cdot y\right)\\ \mathbf{if}\;x \leq -8 \cdot 10^{+41}:\\ \;\;\;\;t\_2\\ \mathbf{elif}\;x \leq -2.8 \cdot 10^{-101}:\\ \;\;\;\;t\_1\\ \mathbf{elif}\;x \leq 5.5 \cdot 10^{-48}:\\ \;\;\;\;y \cdot 5\\ \mathbf{elif}\;x \leq 1.25 \cdot 10^{+212}:\\ \;\;\;\;t\_2\\ \mathbf{else}:\\ \;\;\;\;t\_1\\ \end{array} \end{array} \]
(FPCore (x y z t)
 :precision binary64
 (let* ((t_1 (* x (+ t (* 2.0 z)))) (t_2 (* x (+ t (* 2.0 y)))))
   (if (<= x -8e+41)
     t_2
     (if (<= x -2.8e-101)
       t_1
       (if (<= x 5.5e-48) (* y 5.0) (if (<= x 1.25e+212) t_2 t_1))))))
double code(double x, double y, double z, double t) {
	double t_1 = x * (t + (2.0 * z));
	double t_2 = x * (t + (2.0 * y));
	double tmp;
	if (x <= -8e+41) {
		tmp = t_2;
	} else if (x <= -2.8e-101) {
		tmp = t_1;
	} else if (x <= 5.5e-48) {
		tmp = y * 5.0;
	} else if (x <= 1.25e+212) {
		tmp = t_2;
	} else {
		tmp = t_1;
	}
	return tmp;
}
real(8) function code(x, y, z, t)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    real(8), intent (in) :: z
    real(8), intent (in) :: t
    real(8) :: t_1
    real(8) :: t_2
    real(8) :: tmp
    t_1 = x * (t + (2.0d0 * z))
    t_2 = x * (t + (2.0d0 * y))
    if (x <= (-8d+41)) then
        tmp = t_2
    else if (x <= (-2.8d-101)) then
        tmp = t_1
    else if (x <= 5.5d-48) then
        tmp = y * 5.0d0
    else if (x <= 1.25d+212) then
        tmp = t_2
    else
        tmp = t_1
    end if
    code = tmp
end function
public static double code(double x, double y, double z, double t) {
	double t_1 = x * (t + (2.0 * z));
	double t_2 = x * (t + (2.0 * y));
	double tmp;
	if (x <= -8e+41) {
		tmp = t_2;
	} else if (x <= -2.8e-101) {
		tmp = t_1;
	} else if (x <= 5.5e-48) {
		tmp = y * 5.0;
	} else if (x <= 1.25e+212) {
		tmp = t_2;
	} else {
		tmp = t_1;
	}
	return tmp;
}
def code(x, y, z, t):
	t_1 = x * (t + (2.0 * z))
	t_2 = x * (t + (2.0 * y))
	tmp = 0
	if x <= -8e+41:
		tmp = t_2
	elif x <= -2.8e-101:
		tmp = t_1
	elif x <= 5.5e-48:
		tmp = y * 5.0
	elif x <= 1.25e+212:
		tmp = t_2
	else:
		tmp = t_1
	return tmp
function code(x, y, z, t)
	t_1 = Float64(x * Float64(t + Float64(2.0 * z)))
	t_2 = Float64(x * Float64(t + Float64(2.0 * y)))
	tmp = 0.0
	if (x <= -8e+41)
		tmp = t_2;
	elseif (x <= -2.8e-101)
		tmp = t_1;
	elseif (x <= 5.5e-48)
		tmp = Float64(y * 5.0);
	elseif (x <= 1.25e+212)
		tmp = t_2;
	else
		tmp = t_1;
	end
	return tmp
end
function tmp_2 = code(x, y, z, t)
	t_1 = x * (t + (2.0 * z));
	t_2 = x * (t + (2.0 * y));
	tmp = 0.0;
	if (x <= -8e+41)
		tmp = t_2;
	elseif (x <= -2.8e-101)
		tmp = t_1;
	elseif (x <= 5.5e-48)
		tmp = y * 5.0;
	elseif (x <= 1.25e+212)
		tmp = t_2;
	else
		tmp = t_1;
	end
	tmp_2 = tmp;
end
code[x_, y_, z_, t_] := Block[{t$95$1 = N[(x * N[(t + N[(2.0 * z), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$2 = N[(x * N[(t + N[(2.0 * y), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[x, -8e+41], t$95$2, If[LessEqual[x, -2.8e-101], t$95$1, If[LessEqual[x, 5.5e-48], N[(y * 5.0), $MachinePrecision], If[LessEqual[x, 1.25e+212], t$95$2, t$95$1]]]]]]
\begin{array}{l}

\\
\begin{array}{l}
t_1 := x \cdot \left(t + 2 \cdot z\right)\\
t_2 := x \cdot \left(t + 2 \cdot y\right)\\
\mathbf{if}\;x \leq -8 \cdot 10^{+41}:\\
\;\;\;\;t\_2\\

\mathbf{elif}\;x \leq -2.8 \cdot 10^{-101}:\\
\;\;\;\;t\_1\\

\mathbf{elif}\;x \leq 5.5 \cdot 10^{-48}:\\
\;\;\;\;y \cdot 5\\

\mathbf{elif}\;x \leq 1.25 \cdot 10^{+212}:\\
\;\;\;\;t\_2\\

\mathbf{else}:\\
\;\;\;\;t\_1\\


\end{array}
\end{array}
Derivation
  1. Split input into 3 regimes
  2. if x < -8.00000000000000005e41 or 5.50000000000000047e-48 < x < 1.24999999999999998e212

    1. Initial program 100.0%

      \[x \cdot \left(\left(\left(\left(y + z\right) + z\right) + y\right) + t\right) + y \cdot 5 \]
    2. Step-by-step derivation
      1. fma-define100.0%

        \[\leadsto \color{blue}{\mathsf{fma}\left(x, \left(\left(\left(y + z\right) + z\right) + y\right) + t, y \cdot 5\right)} \]
      2. associate-+l+100.0%

        \[\leadsto \mathsf{fma}\left(x, \color{blue}{\left(\left(y + z\right) + \left(z + y\right)\right)} + t, y \cdot 5\right) \]
      3. +-commutative100.0%

        \[\leadsto \mathsf{fma}\left(x, \left(\left(y + z\right) + \color{blue}{\left(y + z\right)}\right) + t, y \cdot 5\right) \]
      4. count-2100.0%

        \[\leadsto \mathsf{fma}\left(x, \color{blue}{2 \cdot \left(y + z\right)} + t, y \cdot 5\right) \]
    3. Simplified100.0%

      \[\leadsto \color{blue}{\mathsf{fma}\left(x, 2 \cdot \left(y + z\right) + t, y \cdot 5\right)} \]
    4. Add Preprocessing
    5. Taylor expanded in x around inf 99.5%

      \[\leadsto \color{blue}{x \cdot \left(t + 2 \cdot \left(y + z\right)\right)} \]
    6. Taylor expanded in z around 0 77.8%

      \[\leadsto \color{blue}{x \cdot \left(t + 2 \cdot y\right)} \]

    if -8.00000000000000005e41 < x < -2.79999999999999989e-101 or 1.24999999999999998e212 < x

    1. Initial program 99.9%

      \[x \cdot \left(\left(\left(\left(y + z\right) + z\right) + y\right) + t\right) + y \cdot 5 \]
    2. Add Preprocessing
    3. Taylor expanded in y around 0 75.0%

      \[\leadsto \color{blue}{x \cdot \left(t + 2 \cdot z\right)} \]

    if -2.79999999999999989e-101 < x < 5.50000000000000047e-48

    1. Initial program 99.8%

      \[x \cdot \left(\left(\left(\left(y + z\right) + z\right) + y\right) + t\right) + y \cdot 5 \]
    2. Add Preprocessing
    3. Taylor expanded in x around 0 68.9%

      \[\leadsto \color{blue}{5 \cdot y} \]
  3. Recombined 3 regimes into one program.
  4. Final simplification74.2%

    \[\leadsto \begin{array}{l} \mathbf{if}\;x \leq -8 \cdot 10^{+41}:\\ \;\;\;\;x \cdot \left(t + 2 \cdot y\right)\\ \mathbf{elif}\;x \leq -2.8 \cdot 10^{-101}:\\ \;\;\;\;x \cdot \left(t + 2 \cdot z\right)\\ \mathbf{elif}\;x \leq 5.5 \cdot 10^{-48}:\\ \;\;\;\;y \cdot 5\\ \mathbf{elif}\;x \leq 1.25 \cdot 10^{+212}:\\ \;\;\;\;x \cdot \left(t + 2 \cdot y\right)\\ \mathbf{else}:\\ \;\;\;\;x \cdot \left(t + 2 \cdot z\right)\\ \end{array} \]
  5. Add Preprocessing

Alternative 4: 47.1% accurate, 0.6× speedup?

\[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;x \leq -1.02 \cdot 10^{-8}:\\ \;\;\;\;y \cdot \left(x \cdot 2\right)\\ \mathbf{elif}\;x \leq 8.5 \cdot 10^{-48}:\\ \;\;\;\;y \cdot 5\\ \mathbf{elif}\;x \leq 5.2 \cdot 10^{+211} \lor \neg \left(x \leq 2.55 \cdot 10^{+238}\right):\\ \;\;\;\;x \cdot t\\ \mathbf{else}:\\ \;\;\;\;z \cdot \left(x \cdot 2\right)\\ \end{array} \end{array} \]
(FPCore (x y z t)
 :precision binary64
 (if (<= x -1.02e-8)
   (* y (* x 2.0))
   (if (<= x 8.5e-48)
     (* y 5.0)
     (if (or (<= x 5.2e+211) (not (<= x 2.55e+238)))
       (* x t)
       (* z (* x 2.0))))))
double code(double x, double y, double z, double t) {
	double tmp;
	if (x <= -1.02e-8) {
		tmp = y * (x * 2.0);
	} else if (x <= 8.5e-48) {
		tmp = y * 5.0;
	} else if ((x <= 5.2e+211) || !(x <= 2.55e+238)) {
		tmp = x * t;
	} else {
		tmp = z * (x * 2.0);
	}
	return tmp;
}
real(8) function code(x, y, z, t)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    real(8), intent (in) :: z
    real(8), intent (in) :: t
    real(8) :: tmp
    if (x <= (-1.02d-8)) then
        tmp = y * (x * 2.0d0)
    else if (x <= 8.5d-48) then
        tmp = y * 5.0d0
    else if ((x <= 5.2d+211) .or. (.not. (x <= 2.55d+238))) then
        tmp = x * t
    else
        tmp = z * (x * 2.0d0)
    end if
    code = tmp
end function
public static double code(double x, double y, double z, double t) {
	double tmp;
	if (x <= -1.02e-8) {
		tmp = y * (x * 2.0);
	} else if (x <= 8.5e-48) {
		tmp = y * 5.0;
	} else if ((x <= 5.2e+211) || !(x <= 2.55e+238)) {
		tmp = x * t;
	} else {
		tmp = z * (x * 2.0);
	}
	return tmp;
}
def code(x, y, z, t):
	tmp = 0
	if x <= -1.02e-8:
		tmp = y * (x * 2.0)
	elif x <= 8.5e-48:
		tmp = y * 5.0
	elif (x <= 5.2e+211) or not (x <= 2.55e+238):
		tmp = x * t
	else:
		tmp = z * (x * 2.0)
	return tmp
function code(x, y, z, t)
	tmp = 0.0
	if (x <= -1.02e-8)
		tmp = Float64(y * Float64(x * 2.0));
	elseif (x <= 8.5e-48)
		tmp = Float64(y * 5.0);
	elseif ((x <= 5.2e+211) || !(x <= 2.55e+238))
		tmp = Float64(x * t);
	else
		tmp = Float64(z * Float64(x * 2.0));
	end
	return tmp
end
function tmp_2 = code(x, y, z, t)
	tmp = 0.0;
	if (x <= -1.02e-8)
		tmp = y * (x * 2.0);
	elseif (x <= 8.5e-48)
		tmp = y * 5.0;
	elseif ((x <= 5.2e+211) || ~((x <= 2.55e+238)))
		tmp = x * t;
	else
		tmp = z * (x * 2.0);
	end
	tmp_2 = tmp;
end
code[x_, y_, z_, t_] := If[LessEqual[x, -1.02e-8], N[(y * N[(x * 2.0), $MachinePrecision]), $MachinePrecision], If[LessEqual[x, 8.5e-48], N[(y * 5.0), $MachinePrecision], If[Or[LessEqual[x, 5.2e+211], N[Not[LessEqual[x, 2.55e+238]], $MachinePrecision]], N[(x * t), $MachinePrecision], N[(z * N[(x * 2.0), $MachinePrecision]), $MachinePrecision]]]]
\begin{array}{l}

\\
\begin{array}{l}
\mathbf{if}\;x \leq -1.02 \cdot 10^{-8}:\\
\;\;\;\;y \cdot \left(x \cdot 2\right)\\

\mathbf{elif}\;x \leq 8.5 \cdot 10^{-48}:\\
\;\;\;\;y \cdot 5\\

\mathbf{elif}\;x \leq 5.2 \cdot 10^{+211} \lor \neg \left(x \leq 2.55 \cdot 10^{+238}\right):\\
\;\;\;\;x \cdot t\\

\mathbf{else}:\\
\;\;\;\;z \cdot \left(x \cdot 2\right)\\


\end{array}
\end{array}
Derivation
  1. Split input into 4 regimes
  2. if x < -1.02000000000000003e-8

    1. Initial program 100.0%

      \[x \cdot \left(\left(\left(\left(y + z\right) + z\right) + y\right) + t\right) + y \cdot 5 \]
    2. Add Preprocessing
    3. Taylor expanded in y around inf 48.0%

      \[\leadsto \color{blue}{y \cdot \left(5 + 2 \cdot x\right)} \]
    4. Simplified48.0%

      \[\leadsto \color{blue}{y \cdot \left(5 + x \cdot 2\right)} \]
    5. Taylor expanded in x around inf 48.1%

      \[\leadsto \color{blue}{2 \cdot \left(x \cdot y\right)} \]
    6. Step-by-step derivation
      1. *-commutative48.1%

        \[\leadsto \color{blue}{\left(x \cdot y\right) \cdot 2} \]
      2. *-commutative48.1%

        \[\leadsto \color{blue}{\left(y \cdot x\right)} \cdot 2 \]
      3. associate-*r*48.1%

        \[\leadsto \color{blue}{y \cdot \left(x \cdot 2\right)} \]
    7. Simplified48.1%

      \[\leadsto \color{blue}{y \cdot \left(x \cdot 2\right)} \]

    if -1.02000000000000003e-8 < x < 8.5000000000000004e-48

    1. Initial program 99.8%

      \[x \cdot \left(\left(\left(\left(y + z\right) + z\right) + y\right) + t\right) + y \cdot 5 \]
    2. Add Preprocessing
    3. Taylor expanded in x around 0 63.3%

      \[\leadsto \color{blue}{5 \cdot y} \]

    if 8.5000000000000004e-48 < x < 5.1999999999999997e211 or 2.5500000000000001e238 < x

    1. Initial program 100.0%

      \[x \cdot \left(\left(\left(\left(y + z\right) + z\right) + y\right) + t\right) + y \cdot 5 \]
    2. Add Preprocessing
    3. Taylor expanded in t around inf 45.1%

      \[\leadsto \color{blue}{t \cdot x} \]
    4. Simplified45.1%

      \[\leadsto \color{blue}{x \cdot t} \]

    if 5.1999999999999997e211 < x < 2.5500000000000001e238

    1. Initial program 100.0%

      \[x \cdot \left(\left(\left(\left(y + z\right) + z\right) + y\right) + t\right) + y \cdot 5 \]
    2. Add Preprocessing
    3. Taylor expanded in z around inf 86.1%

      \[\leadsto \color{blue}{2 \cdot \left(x \cdot z\right)} \]
    4. Simplified86.1%

      \[\leadsto \color{blue}{\left(x \cdot 2\right) \cdot z} \]
  3. Recombined 4 regimes into one program.
  4. Final simplification55.0%

    \[\leadsto \begin{array}{l} \mathbf{if}\;x \leq -1.02 \cdot 10^{-8}:\\ \;\;\;\;y \cdot \left(x \cdot 2\right)\\ \mathbf{elif}\;x \leq 8.5 \cdot 10^{-48}:\\ \;\;\;\;y \cdot 5\\ \mathbf{elif}\;x \leq 5.2 \cdot 10^{+211} \lor \neg \left(x \leq 2.55 \cdot 10^{+238}\right):\\ \;\;\;\;x \cdot t\\ \mathbf{else}:\\ \;\;\;\;z \cdot \left(x \cdot 2\right)\\ \end{array} \]
  5. Add Preprocessing

Alternative 5: 95.6% accurate, 0.6× speedup?

\[\begin{array}{l} \\ \begin{array}{l} t_1 := 2 \cdot \left(y + z\right)\\ \mathbf{if}\;y \leq -3.1 \cdot 10^{+168} \lor \neg \left(y \leq 9 \cdot 10^{+77}\right):\\ \;\;\;\;y \cdot 5 + x \cdot t\_1\\ \mathbf{else}:\\ \;\;\;\;x \cdot \left(t + \left(t\_1 + 5 \cdot \frac{y}{x}\right)\right)\\ \end{array} \end{array} \]
(FPCore (x y z t)
 :precision binary64
 (let* ((t_1 (* 2.0 (+ y z))))
   (if (or (<= y -3.1e+168) (not (<= y 9e+77)))
     (+ (* y 5.0) (* x t_1))
     (* x (+ t (+ t_1 (* 5.0 (/ y x))))))))
double code(double x, double y, double z, double t) {
	double t_1 = 2.0 * (y + z);
	double tmp;
	if ((y <= -3.1e+168) || !(y <= 9e+77)) {
		tmp = (y * 5.0) + (x * t_1);
	} else {
		tmp = x * (t + (t_1 + (5.0 * (y / x))));
	}
	return tmp;
}
real(8) function code(x, y, z, t)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    real(8), intent (in) :: z
    real(8), intent (in) :: t
    real(8) :: t_1
    real(8) :: tmp
    t_1 = 2.0d0 * (y + z)
    if ((y <= (-3.1d+168)) .or. (.not. (y <= 9d+77))) then
        tmp = (y * 5.0d0) + (x * t_1)
    else
        tmp = x * (t + (t_1 + (5.0d0 * (y / x))))
    end if
    code = tmp
end function
public static double code(double x, double y, double z, double t) {
	double t_1 = 2.0 * (y + z);
	double tmp;
	if ((y <= -3.1e+168) || !(y <= 9e+77)) {
		tmp = (y * 5.0) + (x * t_1);
	} else {
		tmp = x * (t + (t_1 + (5.0 * (y / x))));
	}
	return tmp;
}
def code(x, y, z, t):
	t_1 = 2.0 * (y + z)
	tmp = 0
	if (y <= -3.1e+168) or not (y <= 9e+77):
		tmp = (y * 5.0) + (x * t_1)
	else:
		tmp = x * (t + (t_1 + (5.0 * (y / x))))
	return tmp
function code(x, y, z, t)
	t_1 = Float64(2.0 * Float64(y + z))
	tmp = 0.0
	if ((y <= -3.1e+168) || !(y <= 9e+77))
		tmp = Float64(Float64(y * 5.0) + Float64(x * t_1));
	else
		tmp = Float64(x * Float64(t + Float64(t_1 + Float64(5.0 * Float64(y / x)))));
	end
	return tmp
end
function tmp_2 = code(x, y, z, t)
	t_1 = 2.0 * (y + z);
	tmp = 0.0;
	if ((y <= -3.1e+168) || ~((y <= 9e+77)))
		tmp = (y * 5.0) + (x * t_1);
	else
		tmp = x * (t + (t_1 + (5.0 * (y / x))));
	end
	tmp_2 = tmp;
end
code[x_, y_, z_, t_] := Block[{t$95$1 = N[(2.0 * N[(y + z), $MachinePrecision]), $MachinePrecision]}, If[Or[LessEqual[y, -3.1e+168], N[Not[LessEqual[y, 9e+77]], $MachinePrecision]], N[(N[(y * 5.0), $MachinePrecision] + N[(x * t$95$1), $MachinePrecision]), $MachinePrecision], N[(x * N[(t + N[(t$95$1 + N[(5.0 * N[(y / x), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]]]
\begin{array}{l}

\\
\begin{array}{l}
t_1 := 2 \cdot \left(y + z\right)\\
\mathbf{if}\;y \leq -3.1 \cdot 10^{+168} \lor \neg \left(y \leq 9 \cdot 10^{+77}\right):\\
\;\;\;\;y \cdot 5 + x \cdot t\_1\\

\mathbf{else}:\\
\;\;\;\;x \cdot \left(t + \left(t\_1 + 5 \cdot \frac{y}{x}\right)\right)\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if y < -3.09999999999999996e168 or 9.00000000000000049e77 < y

    1. Initial program 99.9%

      \[x \cdot \left(\left(\left(\left(y + z\right) + z\right) + y\right) + t\right) + y \cdot 5 \]
    2. Add Preprocessing
    3. Taylor expanded in t around 0 96.5%

      \[\leadsto \color{blue}{x \cdot \left(2 \cdot y + 2 \cdot z\right)} + y \cdot 5 \]
    4. Simplified96.5%

      \[\leadsto \color{blue}{x \cdot \left(2 \cdot \left(y + z\right)\right)} + y \cdot 5 \]

    if -3.09999999999999996e168 < y < 9.00000000000000049e77

    1. Initial program 99.9%

      \[x \cdot \left(\left(\left(\left(y + z\right) + z\right) + y\right) + t\right) + y \cdot 5 \]
    2. Step-by-step derivation
      1. fma-define100.0%

        \[\leadsto \color{blue}{\mathsf{fma}\left(x, \left(\left(\left(y + z\right) + z\right) + y\right) + t, y \cdot 5\right)} \]
      2. associate-+l+100.0%

        \[\leadsto \mathsf{fma}\left(x, \color{blue}{\left(\left(y + z\right) + \left(z + y\right)\right)} + t, y \cdot 5\right) \]
      3. +-commutative100.0%

        \[\leadsto \mathsf{fma}\left(x, \left(\left(y + z\right) + \color{blue}{\left(y + z\right)}\right) + t, y \cdot 5\right) \]
      4. count-2100.0%

        \[\leadsto \mathsf{fma}\left(x, \color{blue}{2 \cdot \left(y + z\right)} + t, y \cdot 5\right) \]
    3. Simplified100.0%

      \[\leadsto \color{blue}{\mathsf{fma}\left(x, 2 \cdot \left(y + z\right) + t, y \cdot 5\right)} \]
    4. Add Preprocessing
    5. Taylor expanded in x around inf 99.3%

      \[\leadsto \color{blue}{x \cdot \left(t + \left(2 \cdot \left(y + z\right) + 5 \cdot \frac{y}{x}\right)\right)} \]
  3. Recombined 2 regimes into one program.
  4. Final simplification98.4%

    \[\leadsto \begin{array}{l} \mathbf{if}\;y \leq -3.1 \cdot 10^{+168} \lor \neg \left(y \leq 9 \cdot 10^{+77}\right):\\ \;\;\;\;y \cdot 5 + x \cdot \left(2 \cdot \left(y + z\right)\right)\\ \mathbf{else}:\\ \;\;\;\;x \cdot \left(t + \left(2 \cdot \left(y + z\right) + 5 \cdot \frac{y}{x}\right)\right)\\ \end{array} \]
  5. Add Preprocessing

Alternative 6: 88.7% accurate, 0.6× speedup?

\[\begin{array}{l} \\ \begin{array}{l} t_1 := 2 \cdot \left(y + z\right)\\ \mathbf{if}\;z \leq -9.6 \cdot 10^{+27}:\\ \;\;\;\;y \cdot 5 + x \cdot t\_1\\ \mathbf{elif}\;z \leq 3.1 \cdot 10^{+27}:\\ \;\;\;\;y \cdot 5 + x \cdot \left(t + \left(y + y\right)\right)\\ \mathbf{elif}\;z \leq 3.1 \cdot 10^{+159}:\\ \;\;\;\;x \cdot \left(t\_1 + t\right)\\ \mathbf{else}:\\ \;\;\;\;y \cdot 5 + x \cdot \left(2 \cdot z\right)\\ \end{array} \end{array} \]
(FPCore (x y z t)
 :precision binary64
 (let* ((t_1 (* 2.0 (+ y z))))
   (if (<= z -9.6e+27)
     (+ (* y 5.0) (* x t_1))
     (if (<= z 3.1e+27)
       (+ (* y 5.0) (* x (+ t (+ y y))))
       (if (<= z 3.1e+159) (* x (+ t_1 t)) (+ (* y 5.0) (* x (* 2.0 z))))))))
double code(double x, double y, double z, double t) {
	double t_1 = 2.0 * (y + z);
	double tmp;
	if (z <= -9.6e+27) {
		tmp = (y * 5.0) + (x * t_1);
	} else if (z <= 3.1e+27) {
		tmp = (y * 5.0) + (x * (t + (y + y)));
	} else if (z <= 3.1e+159) {
		tmp = x * (t_1 + t);
	} else {
		tmp = (y * 5.0) + (x * (2.0 * z));
	}
	return tmp;
}
real(8) function code(x, y, z, t)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    real(8), intent (in) :: z
    real(8), intent (in) :: t
    real(8) :: t_1
    real(8) :: tmp
    t_1 = 2.0d0 * (y + z)
    if (z <= (-9.6d+27)) then
        tmp = (y * 5.0d0) + (x * t_1)
    else if (z <= 3.1d+27) then
        tmp = (y * 5.0d0) + (x * (t + (y + y)))
    else if (z <= 3.1d+159) then
        tmp = x * (t_1 + t)
    else
        tmp = (y * 5.0d0) + (x * (2.0d0 * z))
    end if
    code = tmp
end function
public static double code(double x, double y, double z, double t) {
	double t_1 = 2.0 * (y + z);
	double tmp;
	if (z <= -9.6e+27) {
		tmp = (y * 5.0) + (x * t_1);
	} else if (z <= 3.1e+27) {
		tmp = (y * 5.0) + (x * (t + (y + y)));
	} else if (z <= 3.1e+159) {
		tmp = x * (t_1 + t);
	} else {
		tmp = (y * 5.0) + (x * (2.0 * z));
	}
	return tmp;
}
def code(x, y, z, t):
	t_1 = 2.0 * (y + z)
	tmp = 0
	if z <= -9.6e+27:
		tmp = (y * 5.0) + (x * t_1)
	elif z <= 3.1e+27:
		tmp = (y * 5.0) + (x * (t + (y + y)))
	elif z <= 3.1e+159:
		tmp = x * (t_1 + t)
	else:
		tmp = (y * 5.0) + (x * (2.0 * z))
	return tmp
function code(x, y, z, t)
	t_1 = Float64(2.0 * Float64(y + z))
	tmp = 0.0
	if (z <= -9.6e+27)
		tmp = Float64(Float64(y * 5.0) + Float64(x * t_1));
	elseif (z <= 3.1e+27)
		tmp = Float64(Float64(y * 5.0) + Float64(x * Float64(t + Float64(y + y))));
	elseif (z <= 3.1e+159)
		tmp = Float64(x * Float64(t_1 + t));
	else
		tmp = Float64(Float64(y * 5.0) + Float64(x * Float64(2.0 * z)));
	end
	return tmp
end
function tmp_2 = code(x, y, z, t)
	t_1 = 2.0 * (y + z);
	tmp = 0.0;
	if (z <= -9.6e+27)
		tmp = (y * 5.0) + (x * t_1);
	elseif (z <= 3.1e+27)
		tmp = (y * 5.0) + (x * (t + (y + y)));
	elseif (z <= 3.1e+159)
		tmp = x * (t_1 + t);
	else
		tmp = (y * 5.0) + (x * (2.0 * z));
	end
	tmp_2 = tmp;
end
code[x_, y_, z_, t_] := Block[{t$95$1 = N[(2.0 * N[(y + z), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[z, -9.6e+27], N[(N[(y * 5.0), $MachinePrecision] + N[(x * t$95$1), $MachinePrecision]), $MachinePrecision], If[LessEqual[z, 3.1e+27], N[(N[(y * 5.0), $MachinePrecision] + N[(x * N[(t + N[(y + y), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], If[LessEqual[z, 3.1e+159], N[(x * N[(t$95$1 + t), $MachinePrecision]), $MachinePrecision], N[(N[(y * 5.0), $MachinePrecision] + N[(x * N[(2.0 * z), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]]]]]
\begin{array}{l}

\\
\begin{array}{l}
t_1 := 2 \cdot \left(y + z\right)\\
\mathbf{if}\;z \leq -9.6 \cdot 10^{+27}:\\
\;\;\;\;y \cdot 5 + x \cdot t\_1\\

\mathbf{elif}\;z \leq 3.1 \cdot 10^{+27}:\\
\;\;\;\;y \cdot 5 + x \cdot \left(t + \left(y + y\right)\right)\\

\mathbf{elif}\;z \leq 3.1 \cdot 10^{+159}:\\
\;\;\;\;x \cdot \left(t\_1 + t\right)\\

\mathbf{else}:\\
\;\;\;\;y \cdot 5 + x \cdot \left(2 \cdot z\right)\\


\end{array}
\end{array}
Derivation
  1. Split input into 4 regimes
  2. if z < -9.59999999999999991e27

    1. Initial program 99.9%

      \[x \cdot \left(\left(\left(\left(y + z\right) + z\right) + y\right) + t\right) + y \cdot 5 \]
    2. Add Preprocessing
    3. Taylor expanded in t around 0 89.7%

      \[\leadsto \color{blue}{x \cdot \left(2 \cdot y + 2 \cdot z\right)} + y \cdot 5 \]
    4. Simplified89.7%

      \[\leadsto \color{blue}{x \cdot \left(2 \cdot \left(y + z\right)\right)} + y \cdot 5 \]

    if -9.59999999999999991e27 < z < 3.09999999999999996e27

    1. Initial program 99.9%

      \[x \cdot \left(\left(\left(\left(y + z\right) + z\right) + y\right) + t\right) + y \cdot 5 \]
    2. Add Preprocessing
    3. Taylor expanded in y around inf 95.6%

      \[\leadsto x \cdot \left(\left(\color{blue}{y} + y\right) + t\right) + y \cdot 5 \]

    if 3.09999999999999996e27 < z < 3.0999999999999998e159

    1. Initial program 100.0%

      \[x \cdot \left(\left(\left(\left(y + z\right) + z\right) + y\right) + t\right) + y \cdot 5 \]
    2. Step-by-step derivation
      1. fma-define100.0%

        \[\leadsto \color{blue}{\mathsf{fma}\left(x, \left(\left(\left(y + z\right) + z\right) + y\right) + t, y \cdot 5\right)} \]
      2. associate-+l+100.0%

        \[\leadsto \mathsf{fma}\left(x, \color{blue}{\left(\left(y + z\right) + \left(z + y\right)\right)} + t, y \cdot 5\right) \]
      3. +-commutative100.0%

        \[\leadsto \mathsf{fma}\left(x, \left(\left(y + z\right) + \color{blue}{\left(y + z\right)}\right) + t, y \cdot 5\right) \]
      4. count-2100.0%

        \[\leadsto \mathsf{fma}\left(x, \color{blue}{2 \cdot \left(y + z\right)} + t, y \cdot 5\right) \]
    3. Simplified100.0%

      \[\leadsto \color{blue}{\mathsf{fma}\left(x, 2 \cdot \left(y + z\right) + t, y \cdot 5\right)} \]
    4. Add Preprocessing
    5. Taylor expanded in x around inf 87.0%

      \[\leadsto \color{blue}{x \cdot \left(t + 2 \cdot \left(y + z\right)\right)} \]

    if 3.0999999999999998e159 < z

    1. Initial program 100.0%

      \[x \cdot \left(\left(\left(\left(y + z\right) + z\right) + y\right) + t\right) + y \cdot 5 \]
    2. Add Preprocessing
    3. Taylor expanded in t around 0 93.6%

      \[\leadsto \color{blue}{x \cdot \left(2 \cdot y + 2 \cdot z\right)} + y \cdot 5 \]
    4. Simplified93.6%

      \[\leadsto \color{blue}{x \cdot \left(2 \cdot \left(y + z\right)\right)} + y \cdot 5 \]
    5. Taylor expanded in y around 0 93.6%

      \[\leadsto x \cdot \left(2 \cdot \color{blue}{z}\right) + y \cdot 5 \]
  3. Recombined 4 regimes into one program.
  4. Final simplification92.9%

    \[\leadsto \begin{array}{l} \mathbf{if}\;z \leq -9.6 \cdot 10^{+27}:\\ \;\;\;\;y \cdot 5 + x \cdot \left(2 \cdot \left(y + z\right)\right)\\ \mathbf{elif}\;z \leq 3.1 \cdot 10^{+27}:\\ \;\;\;\;y \cdot 5 + x \cdot \left(t + \left(y + y\right)\right)\\ \mathbf{elif}\;z \leq 3.1 \cdot 10^{+159}:\\ \;\;\;\;x \cdot \left(2 \cdot \left(y + z\right) + t\right)\\ \mathbf{else}:\\ \;\;\;\;y \cdot 5 + x \cdot \left(2 \cdot z\right)\\ \end{array} \]
  5. Add Preprocessing

Alternative 7: 88.9% accurate, 0.6× speedup?

\[\begin{array}{l} \\ \begin{array}{l} t_1 := 2 \cdot \left(y + z\right)\\ t_2 := x \cdot \left(t\_1 + t\right)\\ \mathbf{if}\;x \leq -4.6 \cdot 10^{-12}:\\ \;\;\;\;t\_2\\ \mathbf{elif}\;x \leq -4.5 \cdot 10^{-194}:\\ \;\;\;\;y \cdot 5 + x \cdot t\_1\\ \mathbf{elif}\;x \leq 7.8 \cdot 10^{-48}:\\ \;\;\;\;y \cdot 5 + x \cdot t\\ \mathbf{else}:\\ \;\;\;\;t\_2\\ \end{array} \end{array} \]
(FPCore (x y z t)
 :precision binary64
 (let* ((t_1 (* 2.0 (+ y z))) (t_2 (* x (+ t_1 t))))
   (if (<= x -4.6e-12)
     t_2
     (if (<= x -4.5e-194)
       (+ (* y 5.0) (* x t_1))
       (if (<= x 7.8e-48) (+ (* y 5.0) (* x t)) t_2)))))
double code(double x, double y, double z, double t) {
	double t_1 = 2.0 * (y + z);
	double t_2 = x * (t_1 + t);
	double tmp;
	if (x <= -4.6e-12) {
		tmp = t_2;
	} else if (x <= -4.5e-194) {
		tmp = (y * 5.0) + (x * t_1);
	} else if (x <= 7.8e-48) {
		tmp = (y * 5.0) + (x * t);
	} else {
		tmp = t_2;
	}
	return tmp;
}
real(8) function code(x, y, z, t)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    real(8), intent (in) :: z
    real(8), intent (in) :: t
    real(8) :: t_1
    real(8) :: t_2
    real(8) :: tmp
    t_1 = 2.0d0 * (y + z)
    t_2 = x * (t_1 + t)
    if (x <= (-4.6d-12)) then
        tmp = t_2
    else if (x <= (-4.5d-194)) then
        tmp = (y * 5.0d0) + (x * t_1)
    else if (x <= 7.8d-48) then
        tmp = (y * 5.0d0) + (x * t)
    else
        tmp = t_2
    end if
    code = tmp
end function
public static double code(double x, double y, double z, double t) {
	double t_1 = 2.0 * (y + z);
	double t_2 = x * (t_1 + t);
	double tmp;
	if (x <= -4.6e-12) {
		tmp = t_2;
	} else if (x <= -4.5e-194) {
		tmp = (y * 5.0) + (x * t_1);
	} else if (x <= 7.8e-48) {
		tmp = (y * 5.0) + (x * t);
	} else {
		tmp = t_2;
	}
	return tmp;
}
def code(x, y, z, t):
	t_1 = 2.0 * (y + z)
	t_2 = x * (t_1 + t)
	tmp = 0
	if x <= -4.6e-12:
		tmp = t_2
	elif x <= -4.5e-194:
		tmp = (y * 5.0) + (x * t_1)
	elif x <= 7.8e-48:
		tmp = (y * 5.0) + (x * t)
	else:
		tmp = t_2
	return tmp
function code(x, y, z, t)
	t_1 = Float64(2.0 * Float64(y + z))
	t_2 = Float64(x * Float64(t_1 + t))
	tmp = 0.0
	if (x <= -4.6e-12)
		tmp = t_2;
	elseif (x <= -4.5e-194)
		tmp = Float64(Float64(y * 5.0) + Float64(x * t_1));
	elseif (x <= 7.8e-48)
		tmp = Float64(Float64(y * 5.0) + Float64(x * t));
	else
		tmp = t_2;
	end
	return tmp
end
function tmp_2 = code(x, y, z, t)
	t_1 = 2.0 * (y + z);
	t_2 = x * (t_1 + t);
	tmp = 0.0;
	if (x <= -4.6e-12)
		tmp = t_2;
	elseif (x <= -4.5e-194)
		tmp = (y * 5.0) + (x * t_1);
	elseif (x <= 7.8e-48)
		tmp = (y * 5.0) + (x * t);
	else
		tmp = t_2;
	end
	tmp_2 = tmp;
end
code[x_, y_, z_, t_] := Block[{t$95$1 = N[(2.0 * N[(y + z), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$2 = N[(x * N[(t$95$1 + t), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[x, -4.6e-12], t$95$2, If[LessEqual[x, -4.5e-194], N[(N[(y * 5.0), $MachinePrecision] + N[(x * t$95$1), $MachinePrecision]), $MachinePrecision], If[LessEqual[x, 7.8e-48], N[(N[(y * 5.0), $MachinePrecision] + N[(x * t), $MachinePrecision]), $MachinePrecision], t$95$2]]]]]
\begin{array}{l}

\\
\begin{array}{l}
t_1 := 2 \cdot \left(y + z\right)\\
t_2 := x \cdot \left(t\_1 + t\right)\\
\mathbf{if}\;x \leq -4.6 \cdot 10^{-12}:\\
\;\;\;\;t\_2\\

\mathbf{elif}\;x \leq -4.5 \cdot 10^{-194}:\\
\;\;\;\;y \cdot 5 + x \cdot t\_1\\

\mathbf{elif}\;x \leq 7.8 \cdot 10^{-48}:\\
\;\;\;\;y \cdot 5 + x \cdot t\\

\mathbf{else}:\\
\;\;\;\;t\_2\\


\end{array}
\end{array}
Derivation
  1. Split input into 3 regimes
  2. if x < -4.59999999999999979e-12 or 7.800000000000001e-48 < x

    1. Initial program 100.0%

      \[x \cdot \left(\left(\left(\left(y + z\right) + z\right) + y\right) + t\right) + y \cdot 5 \]
    2. Step-by-step derivation
      1. fma-define100.0%

        \[\leadsto \color{blue}{\mathsf{fma}\left(x, \left(\left(\left(y + z\right) + z\right) + y\right) + t, y \cdot 5\right)} \]
      2. associate-+l+100.0%

        \[\leadsto \mathsf{fma}\left(x, \color{blue}{\left(\left(y + z\right) + \left(z + y\right)\right)} + t, y \cdot 5\right) \]
      3. +-commutative100.0%

        \[\leadsto \mathsf{fma}\left(x, \left(\left(y + z\right) + \color{blue}{\left(y + z\right)}\right) + t, y \cdot 5\right) \]
      4. count-2100.0%

        \[\leadsto \mathsf{fma}\left(x, \color{blue}{2 \cdot \left(y + z\right)} + t, y \cdot 5\right) \]
    3. Simplified100.0%

      \[\leadsto \color{blue}{\mathsf{fma}\left(x, 2 \cdot \left(y + z\right) + t, y \cdot 5\right)} \]
    4. Add Preprocessing
    5. Taylor expanded in x around inf 99.6%

      \[\leadsto \color{blue}{x \cdot \left(t + 2 \cdot \left(y + z\right)\right)} \]

    if -4.59999999999999979e-12 < x < -4.4999999999999999e-194

    1. Initial program 99.8%

      \[x \cdot \left(\left(\left(\left(y + z\right) + z\right) + y\right) + t\right) + y \cdot 5 \]
    2. Add Preprocessing
    3. Taylor expanded in t around 0 88.6%

      \[\leadsto \color{blue}{x \cdot \left(2 \cdot y + 2 \cdot z\right)} + y \cdot 5 \]
    4. Simplified88.6%

      \[\leadsto \color{blue}{x \cdot \left(2 \cdot \left(y + z\right)\right)} + y \cdot 5 \]

    if -4.4999999999999999e-194 < x < 7.800000000000001e-48

    1. Initial program 99.8%

      \[x \cdot \left(\left(\left(\left(y + z\right) + z\right) + y\right) + t\right) + y \cdot 5 \]
    2. Step-by-step derivation
      1. fma-define99.8%

        \[\leadsto \color{blue}{\mathsf{fma}\left(x, \left(\left(\left(y + z\right) + z\right) + y\right) + t, y \cdot 5\right)} \]
      2. associate-+l+99.8%

        \[\leadsto \mathsf{fma}\left(x, \color{blue}{\left(\left(y + z\right) + \left(z + y\right)\right)} + t, y \cdot 5\right) \]
      3. +-commutative99.8%

        \[\leadsto \mathsf{fma}\left(x, \left(\left(y + z\right) + \color{blue}{\left(y + z\right)}\right) + t, y \cdot 5\right) \]
      4. count-299.8%

        \[\leadsto \mathsf{fma}\left(x, \color{blue}{2 \cdot \left(y + z\right)} + t, y \cdot 5\right) \]
    3. Simplified99.8%

      \[\leadsto \color{blue}{\mathsf{fma}\left(x, 2 \cdot \left(y + z\right) + t, y \cdot 5\right)} \]
    4. Add Preprocessing
    5. Taylor expanded in x around inf 65.5%

      \[\leadsto \color{blue}{x \cdot \left(t + \left(2 \cdot \left(y + z\right) + 5 \cdot \frac{y}{x}\right)\right)} \]
    6. Taylor expanded in t around inf 62.8%

      \[\leadsto \color{blue}{t \cdot \left(x + \frac{x \cdot \left(2 \cdot \left(y + z\right) + 5 \cdot \frac{y}{x}\right)}{t}\right)} \]
    7. Taylor expanded in x around 0 71.2%

      \[\leadsto t \cdot \left(x + \color{blue}{5 \cdot \frac{y}{t}}\right) \]
    8. Step-by-step derivation
      1. associate-*r/71.4%

        \[\leadsto t \cdot \left(x + \color{blue}{\frac{5 \cdot y}{t}}\right) \]
      2. *-commutative71.4%

        \[\leadsto t \cdot \left(x + \frac{\color{blue}{y \cdot 5}}{t}\right) \]
      3. associate-/l*71.3%

        \[\leadsto t \cdot \left(x + \color{blue}{y \cdot \frac{5}{t}}\right) \]
    9. Simplified71.3%

      \[\leadsto t \cdot \left(x + \color{blue}{y \cdot \frac{5}{t}}\right) \]
    10. Taylor expanded in t around 0 89.1%

      \[\leadsto \color{blue}{5 \cdot y + t \cdot x} \]
  3. Recombined 3 regimes into one program.
  4. Final simplification95.1%

    \[\leadsto \begin{array}{l} \mathbf{if}\;x \leq -4.6 \cdot 10^{-12}:\\ \;\;\;\;x \cdot \left(2 \cdot \left(y + z\right) + t\right)\\ \mathbf{elif}\;x \leq -4.5 \cdot 10^{-194}:\\ \;\;\;\;y \cdot 5 + x \cdot \left(2 \cdot \left(y + z\right)\right)\\ \mathbf{elif}\;x \leq 7.8 \cdot 10^{-48}:\\ \;\;\;\;y \cdot 5 + x \cdot t\\ \mathbf{else}:\\ \;\;\;\;x \cdot \left(2 \cdot \left(y + z\right) + t\right)\\ \end{array} \]
  5. Add Preprocessing

Alternative 8: 88.9% accurate, 0.6× speedup?

\[\begin{array}{l} \\ \begin{array}{l} t_1 := x \cdot \left(2 \cdot \left(y + z\right) + t\right)\\ \mathbf{if}\;x \leq -1.65 \cdot 10^{-12}:\\ \;\;\;\;t\_1\\ \mathbf{elif}\;x \leq -1.2 \cdot 10^{-194}:\\ \;\;\;\;y \cdot 5 + x \cdot \left(2 \cdot z\right)\\ \mathbf{elif}\;x \leq 9 \cdot 10^{-48}:\\ \;\;\;\;y \cdot 5 + x \cdot t\\ \mathbf{else}:\\ \;\;\;\;t\_1\\ \end{array} \end{array} \]
(FPCore (x y z t)
 :precision binary64
 (let* ((t_1 (* x (+ (* 2.0 (+ y z)) t))))
   (if (<= x -1.65e-12)
     t_1
     (if (<= x -1.2e-194)
       (+ (* y 5.0) (* x (* 2.0 z)))
       (if (<= x 9e-48) (+ (* y 5.0) (* x t)) t_1)))))
double code(double x, double y, double z, double t) {
	double t_1 = x * ((2.0 * (y + z)) + t);
	double tmp;
	if (x <= -1.65e-12) {
		tmp = t_1;
	} else if (x <= -1.2e-194) {
		tmp = (y * 5.0) + (x * (2.0 * z));
	} else if (x <= 9e-48) {
		tmp = (y * 5.0) + (x * t);
	} else {
		tmp = t_1;
	}
	return tmp;
}
real(8) function code(x, y, z, t)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    real(8), intent (in) :: z
    real(8), intent (in) :: t
    real(8) :: t_1
    real(8) :: tmp
    t_1 = x * ((2.0d0 * (y + z)) + t)
    if (x <= (-1.65d-12)) then
        tmp = t_1
    else if (x <= (-1.2d-194)) then
        tmp = (y * 5.0d0) + (x * (2.0d0 * z))
    else if (x <= 9d-48) then
        tmp = (y * 5.0d0) + (x * t)
    else
        tmp = t_1
    end if
    code = tmp
end function
public static double code(double x, double y, double z, double t) {
	double t_1 = x * ((2.0 * (y + z)) + t);
	double tmp;
	if (x <= -1.65e-12) {
		tmp = t_1;
	} else if (x <= -1.2e-194) {
		tmp = (y * 5.0) + (x * (2.0 * z));
	} else if (x <= 9e-48) {
		tmp = (y * 5.0) + (x * t);
	} else {
		tmp = t_1;
	}
	return tmp;
}
def code(x, y, z, t):
	t_1 = x * ((2.0 * (y + z)) + t)
	tmp = 0
	if x <= -1.65e-12:
		tmp = t_1
	elif x <= -1.2e-194:
		tmp = (y * 5.0) + (x * (2.0 * z))
	elif x <= 9e-48:
		tmp = (y * 5.0) + (x * t)
	else:
		tmp = t_1
	return tmp
function code(x, y, z, t)
	t_1 = Float64(x * Float64(Float64(2.0 * Float64(y + z)) + t))
	tmp = 0.0
	if (x <= -1.65e-12)
		tmp = t_1;
	elseif (x <= -1.2e-194)
		tmp = Float64(Float64(y * 5.0) + Float64(x * Float64(2.0 * z)));
	elseif (x <= 9e-48)
		tmp = Float64(Float64(y * 5.0) + Float64(x * t));
	else
		tmp = t_1;
	end
	return tmp
end
function tmp_2 = code(x, y, z, t)
	t_1 = x * ((2.0 * (y + z)) + t);
	tmp = 0.0;
	if (x <= -1.65e-12)
		tmp = t_1;
	elseif (x <= -1.2e-194)
		tmp = (y * 5.0) + (x * (2.0 * z));
	elseif (x <= 9e-48)
		tmp = (y * 5.0) + (x * t);
	else
		tmp = t_1;
	end
	tmp_2 = tmp;
end
code[x_, y_, z_, t_] := Block[{t$95$1 = N[(x * N[(N[(2.0 * N[(y + z), $MachinePrecision]), $MachinePrecision] + t), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[x, -1.65e-12], t$95$1, If[LessEqual[x, -1.2e-194], N[(N[(y * 5.0), $MachinePrecision] + N[(x * N[(2.0 * z), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], If[LessEqual[x, 9e-48], N[(N[(y * 5.0), $MachinePrecision] + N[(x * t), $MachinePrecision]), $MachinePrecision], t$95$1]]]]
\begin{array}{l}

\\
\begin{array}{l}
t_1 := x \cdot \left(2 \cdot \left(y + z\right) + t\right)\\
\mathbf{if}\;x \leq -1.65 \cdot 10^{-12}:\\
\;\;\;\;t\_1\\

\mathbf{elif}\;x \leq -1.2 \cdot 10^{-194}:\\
\;\;\;\;y \cdot 5 + x \cdot \left(2 \cdot z\right)\\

\mathbf{elif}\;x \leq 9 \cdot 10^{-48}:\\
\;\;\;\;y \cdot 5 + x \cdot t\\

\mathbf{else}:\\
\;\;\;\;t\_1\\


\end{array}
\end{array}
Derivation
  1. Split input into 3 regimes
  2. if x < -1.65e-12 or 8.99999999999999977e-48 < x

    1. Initial program 100.0%

      \[x \cdot \left(\left(\left(\left(y + z\right) + z\right) + y\right) + t\right) + y \cdot 5 \]
    2. Step-by-step derivation
      1. fma-define100.0%

        \[\leadsto \color{blue}{\mathsf{fma}\left(x, \left(\left(\left(y + z\right) + z\right) + y\right) + t, y \cdot 5\right)} \]
      2. associate-+l+100.0%

        \[\leadsto \mathsf{fma}\left(x, \color{blue}{\left(\left(y + z\right) + \left(z + y\right)\right)} + t, y \cdot 5\right) \]
      3. +-commutative100.0%

        \[\leadsto \mathsf{fma}\left(x, \left(\left(y + z\right) + \color{blue}{\left(y + z\right)}\right) + t, y \cdot 5\right) \]
      4. count-2100.0%

        \[\leadsto \mathsf{fma}\left(x, \color{blue}{2 \cdot \left(y + z\right)} + t, y \cdot 5\right) \]
    3. Simplified100.0%

      \[\leadsto \color{blue}{\mathsf{fma}\left(x, 2 \cdot \left(y + z\right) + t, y \cdot 5\right)} \]
    4. Add Preprocessing
    5. Taylor expanded in x around inf 99.6%

      \[\leadsto \color{blue}{x \cdot \left(t + 2 \cdot \left(y + z\right)\right)} \]

    if -1.65e-12 < x < -1.2e-194

    1. Initial program 99.8%

      \[x \cdot \left(\left(\left(\left(y + z\right) + z\right) + y\right) + t\right) + y \cdot 5 \]
    2. Add Preprocessing
    3. Taylor expanded in t around 0 88.6%

      \[\leadsto \color{blue}{x \cdot \left(2 \cdot y + 2 \cdot z\right)} + y \cdot 5 \]
    4. Simplified88.6%

      \[\leadsto \color{blue}{x \cdot \left(2 \cdot \left(y + z\right)\right)} + y \cdot 5 \]
    5. Taylor expanded in y around 0 88.5%

      \[\leadsto x \cdot \left(2 \cdot \color{blue}{z}\right) + y \cdot 5 \]

    if -1.2e-194 < x < 8.99999999999999977e-48

    1. Initial program 99.8%

      \[x \cdot \left(\left(\left(\left(y + z\right) + z\right) + y\right) + t\right) + y \cdot 5 \]
    2. Step-by-step derivation
      1. fma-define99.8%

        \[\leadsto \color{blue}{\mathsf{fma}\left(x, \left(\left(\left(y + z\right) + z\right) + y\right) + t, y \cdot 5\right)} \]
      2. associate-+l+99.8%

        \[\leadsto \mathsf{fma}\left(x, \color{blue}{\left(\left(y + z\right) + \left(z + y\right)\right)} + t, y \cdot 5\right) \]
      3. +-commutative99.8%

        \[\leadsto \mathsf{fma}\left(x, \left(\left(y + z\right) + \color{blue}{\left(y + z\right)}\right) + t, y \cdot 5\right) \]
      4. count-299.8%

        \[\leadsto \mathsf{fma}\left(x, \color{blue}{2 \cdot \left(y + z\right)} + t, y \cdot 5\right) \]
    3. Simplified99.8%

      \[\leadsto \color{blue}{\mathsf{fma}\left(x, 2 \cdot \left(y + z\right) + t, y \cdot 5\right)} \]
    4. Add Preprocessing
    5. Taylor expanded in x around inf 65.5%

      \[\leadsto \color{blue}{x \cdot \left(t + \left(2 \cdot \left(y + z\right) + 5 \cdot \frac{y}{x}\right)\right)} \]
    6. Taylor expanded in t around inf 62.8%

      \[\leadsto \color{blue}{t \cdot \left(x + \frac{x \cdot \left(2 \cdot \left(y + z\right) + 5 \cdot \frac{y}{x}\right)}{t}\right)} \]
    7. Taylor expanded in x around 0 71.2%

      \[\leadsto t \cdot \left(x + \color{blue}{5 \cdot \frac{y}{t}}\right) \]
    8. Step-by-step derivation
      1. associate-*r/71.4%

        \[\leadsto t \cdot \left(x + \color{blue}{\frac{5 \cdot y}{t}}\right) \]
      2. *-commutative71.4%

        \[\leadsto t \cdot \left(x + \frac{\color{blue}{y \cdot 5}}{t}\right) \]
      3. associate-/l*71.3%

        \[\leadsto t \cdot \left(x + \color{blue}{y \cdot \frac{5}{t}}\right) \]
    9. Simplified71.3%

      \[\leadsto t \cdot \left(x + \color{blue}{y \cdot \frac{5}{t}}\right) \]
    10. Taylor expanded in t around 0 89.1%

      \[\leadsto \color{blue}{5 \cdot y + t \cdot x} \]
  3. Recombined 3 regimes into one program.
  4. Final simplification95.0%

    \[\leadsto \begin{array}{l} \mathbf{if}\;x \leq -1.65 \cdot 10^{-12}:\\ \;\;\;\;x \cdot \left(2 \cdot \left(y + z\right) + t\right)\\ \mathbf{elif}\;x \leq -1.2 \cdot 10^{-194}:\\ \;\;\;\;y \cdot 5 + x \cdot \left(2 \cdot z\right)\\ \mathbf{elif}\;x \leq 9 \cdot 10^{-48}:\\ \;\;\;\;y \cdot 5 + x \cdot t\\ \mathbf{else}:\\ \;\;\;\;x \cdot \left(2 \cdot \left(y + z\right) + t\right)\\ \end{array} \]
  5. Add Preprocessing

Alternative 9: 91.4% accurate, 0.7× speedup?

\[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;y \leq -6.6 \cdot 10^{+37} \lor \neg \left(y \leq 6.6 \cdot 10^{+77}\right):\\ \;\;\;\;y \cdot 5 + x \cdot \left(2 \cdot \left(y + z\right)\right)\\ \mathbf{else}:\\ \;\;\;\;x \cdot \left(t + \left(5 \cdot \frac{y}{x} + 2 \cdot z\right)\right)\\ \end{array} \end{array} \]
(FPCore (x y z t)
 :precision binary64
 (if (or (<= y -6.6e+37) (not (<= y 6.6e+77)))
   (+ (* y 5.0) (* x (* 2.0 (+ y z))))
   (* x (+ t (+ (* 5.0 (/ y x)) (* 2.0 z))))))
double code(double x, double y, double z, double t) {
	double tmp;
	if ((y <= -6.6e+37) || !(y <= 6.6e+77)) {
		tmp = (y * 5.0) + (x * (2.0 * (y + z)));
	} else {
		tmp = x * (t + ((5.0 * (y / x)) + (2.0 * z)));
	}
	return tmp;
}
real(8) function code(x, y, z, t)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    real(8), intent (in) :: z
    real(8), intent (in) :: t
    real(8) :: tmp
    if ((y <= (-6.6d+37)) .or. (.not. (y <= 6.6d+77))) then
        tmp = (y * 5.0d0) + (x * (2.0d0 * (y + z)))
    else
        tmp = x * (t + ((5.0d0 * (y / x)) + (2.0d0 * z)))
    end if
    code = tmp
end function
public static double code(double x, double y, double z, double t) {
	double tmp;
	if ((y <= -6.6e+37) || !(y <= 6.6e+77)) {
		tmp = (y * 5.0) + (x * (2.0 * (y + z)));
	} else {
		tmp = x * (t + ((5.0 * (y / x)) + (2.0 * z)));
	}
	return tmp;
}
def code(x, y, z, t):
	tmp = 0
	if (y <= -6.6e+37) or not (y <= 6.6e+77):
		tmp = (y * 5.0) + (x * (2.0 * (y + z)))
	else:
		tmp = x * (t + ((5.0 * (y / x)) + (2.0 * z)))
	return tmp
function code(x, y, z, t)
	tmp = 0.0
	if ((y <= -6.6e+37) || !(y <= 6.6e+77))
		tmp = Float64(Float64(y * 5.0) + Float64(x * Float64(2.0 * Float64(y + z))));
	else
		tmp = Float64(x * Float64(t + Float64(Float64(5.0 * Float64(y / x)) + Float64(2.0 * z))));
	end
	return tmp
end
function tmp_2 = code(x, y, z, t)
	tmp = 0.0;
	if ((y <= -6.6e+37) || ~((y <= 6.6e+77)))
		tmp = (y * 5.0) + (x * (2.0 * (y + z)));
	else
		tmp = x * (t + ((5.0 * (y / x)) + (2.0 * z)));
	end
	tmp_2 = tmp;
end
code[x_, y_, z_, t_] := If[Or[LessEqual[y, -6.6e+37], N[Not[LessEqual[y, 6.6e+77]], $MachinePrecision]], N[(N[(y * 5.0), $MachinePrecision] + N[(x * N[(2.0 * N[(y + z), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], N[(x * N[(t + N[(N[(5.0 * N[(y / x), $MachinePrecision]), $MachinePrecision] + N[(2.0 * z), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]]
\begin{array}{l}

\\
\begin{array}{l}
\mathbf{if}\;y \leq -6.6 \cdot 10^{+37} \lor \neg \left(y \leq 6.6 \cdot 10^{+77}\right):\\
\;\;\;\;y \cdot 5 + x \cdot \left(2 \cdot \left(y + z\right)\right)\\

\mathbf{else}:\\
\;\;\;\;x \cdot \left(t + \left(5 \cdot \frac{y}{x} + 2 \cdot z\right)\right)\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if y < -6.6000000000000002e37 or 6.5999999999999996e77 < y

    1. Initial program 99.9%

      \[x \cdot \left(\left(\left(\left(y + z\right) + z\right) + y\right) + t\right) + y \cdot 5 \]
    2. Add Preprocessing
    3. Taylor expanded in t around 0 94.9%

      \[\leadsto \color{blue}{x \cdot \left(2 \cdot y + 2 \cdot z\right)} + y \cdot 5 \]
    4. Simplified94.9%

      \[\leadsto \color{blue}{x \cdot \left(2 \cdot \left(y + z\right)\right)} + y \cdot 5 \]

    if -6.6000000000000002e37 < y < 6.5999999999999996e77

    1. Initial program 99.9%

      \[x \cdot \left(\left(\left(\left(y + z\right) + z\right) + y\right) + t\right) + y \cdot 5 \]
    2. Step-by-step derivation
      1. fma-define100.0%

        \[\leadsto \color{blue}{\mathsf{fma}\left(x, \left(\left(\left(y + z\right) + z\right) + y\right) + t, y \cdot 5\right)} \]
      2. associate-+l+100.0%

        \[\leadsto \mathsf{fma}\left(x, \color{blue}{\left(\left(y + z\right) + \left(z + y\right)\right)} + t, y \cdot 5\right) \]
      3. +-commutative100.0%

        \[\leadsto \mathsf{fma}\left(x, \left(\left(y + z\right) + \color{blue}{\left(y + z\right)}\right) + t, y \cdot 5\right) \]
      4. count-2100.0%

        \[\leadsto \mathsf{fma}\left(x, \color{blue}{2 \cdot \left(y + z\right)} + t, y \cdot 5\right) \]
    3. Simplified100.0%

      \[\leadsto \color{blue}{\mathsf{fma}\left(x, 2 \cdot \left(y + z\right) + t, y \cdot 5\right)} \]
    4. Add Preprocessing
    5. Taylor expanded in x around inf 99.9%

      \[\leadsto \color{blue}{x \cdot \left(t + \left(2 \cdot \left(y + z\right) + 5 \cdot \frac{y}{x}\right)\right)} \]
    6. Taylor expanded in y around 0 92.9%

      \[\leadsto x \cdot \left(t + \left(2 \cdot \color{blue}{z} + 5 \cdot \frac{y}{x}\right)\right) \]
  3. Recombined 2 regimes into one program.
  4. Final simplification93.8%

    \[\leadsto \begin{array}{l} \mathbf{if}\;y \leq -6.6 \cdot 10^{+37} \lor \neg \left(y \leq 6.6 \cdot 10^{+77}\right):\\ \;\;\;\;y \cdot 5 + x \cdot \left(2 \cdot \left(y + z\right)\right)\\ \mathbf{else}:\\ \;\;\;\;x \cdot \left(t + \left(5 \cdot \frac{y}{x} + 2 \cdot z\right)\right)\\ \end{array} \]
  5. Add Preprocessing

Alternative 10: 88.9% accurate, 0.8× speedup?

\[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;x \leq -3.4 \cdot 10^{-51} \lor \neg \left(x \leq 7 \cdot 10^{-48}\right):\\ \;\;\;\;x \cdot \left(2 \cdot \left(y + z\right) + t\right)\\ \mathbf{else}:\\ \;\;\;\;y \cdot 5 + x \cdot t\\ \end{array} \end{array} \]
(FPCore (x y z t)
 :precision binary64
 (if (or (<= x -3.4e-51) (not (<= x 7e-48)))
   (* x (+ (* 2.0 (+ y z)) t))
   (+ (* y 5.0) (* x t))))
double code(double x, double y, double z, double t) {
	double tmp;
	if ((x <= -3.4e-51) || !(x <= 7e-48)) {
		tmp = x * ((2.0 * (y + z)) + t);
	} else {
		tmp = (y * 5.0) + (x * t);
	}
	return tmp;
}
real(8) function code(x, y, z, t)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    real(8), intent (in) :: z
    real(8), intent (in) :: t
    real(8) :: tmp
    if ((x <= (-3.4d-51)) .or. (.not. (x <= 7d-48))) then
        tmp = x * ((2.0d0 * (y + z)) + t)
    else
        tmp = (y * 5.0d0) + (x * t)
    end if
    code = tmp
end function
public static double code(double x, double y, double z, double t) {
	double tmp;
	if ((x <= -3.4e-51) || !(x <= 7e-48)) {
		tmp = x * ((2.0 * (y + z)) + t);
	} else {
		tmp = (y * 5.0) + (x * t);
	}
	return tmp;
}
def code(x, y, z, t):
	tmp = 0
	if (x <= -3.4e-51) or not (x <= 7e-48):
		tmp = x * ((2.0 * (y + z)) + t)
	else:
		tmp = (y * 5.0) + (x * t)
	return tmp
function code(x, y, z, t)
	tmp = 0.0
	if ((x <= -3.4e-51) || !(x <= 7e-48))
		tmp = Float64(x * Float64(Float64(2.0 * Float64(y + z)) + t));
	else
		tmp = Float64(Float64(y * 5.0) + Float64(x * t));
	end
	return tmp
end
function tmp_2 = code(x, y, z, t)
	tmp = 0.0;
	if ((x <= -3.4e-51) || ~((x <= 7e-48)))
		tmp = x * ((2.0 * (y + z)) + t);
	else
		tmp = (y * 5.0) + (x * t);
	end
	tmp_2 = tmp;
end
code[x_, y_, z_, t_] := If[Or[LessEqual[x, -3.4e-51], N[Not[LessEqual[x, 7e-48]], $MachinePrecision]], N[(x * N[(N[(2.0 * N[(y + z), $MachinePrecision]), $MachinePrecision] + t), $MachinePrecision]), $MachinePrecision], N[(N[(y * 5.0), $MachinePrecision] + N[(x * t), $MachinePrecision]), $MachinePrecision]]
\begin{array}{l}

\\
\begin{array}{l}
\mathbf{if}\;x \leq -3.4 \cdot 10^{-51} \lor \neg \left(x \leq 7 \cdot 10^{-48}\right):\\
\;\;\;\;x \cdot \left(2 \cdot \left(y + z\right) + t\right)\\

\mathbf{else}:\\
\;\;\;\;y \cdot 5 + x \cdot t\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if x < -3.40000000000000003e-51 or 6.99999999999999982e-48 < x

    1. Initial program 100.0%

      \[x \cdot \left(\left(\left(\left(y + z\right) + z\right) + y\right) + t\right) + y \cdot 5 \]
    2. Step-by-step derivation
      1. fma-define100.0%

        \[\leadsto \color{blue}{\mathsf{fma}\left(x, \left(\left(\left(y + z\right) + z\right) + y\right) + t, y \cdot 5\right)} \]
      2. associate-+l+100.0%

        \[\leadsto \mathsf{fma}\left(x, \color{blue}{\left(\left(y + z\right) + \left(z + y\right)\right)} + t, y \cdot 5\right) \]
      3. +-commutative100.0%

        \[\leadsto \mathsf{fma}\left(x, \left(\left(y + z\right) + \color{blue}{\left(y + z\right)}\right) + t, y \cdot 5\right) \]
      4. count-2100.0%

        \[\leadsto \mathsf{fma}\left(x, \color{blue}{2 \cdot \left(y + z\right)} + t, y \cdot 5\right) \]
    3. Simplified100.0%

      \[\leadsto \color{blue}{\mathsf{fma}\left(x, 2 \cdot \left(y + z\right) + t, y \cdot 5\right)} \]
    4. Add Preprocessing
    5. Taylor expanded in x around inf 97.1%

      \[\leadsto \color{blue}{x \cdot \left(t + 2 \cdot \left(y + z\right)\right)} \]

    if -3.40000000000000003e-51 < x < 6.99999999999999982e-48

    1. Initial program 99.8%

      \[x \cdot \left(\left(\left(\left(y + z\right) + z\right) + y\right) + t\right) + y \cdot 5 \]
    2. Step-by-step derivation
      1. fma-define99.8%

        \[\leadsto \color{blue}{\mathsf{fma}\left(x, \left(\left(\left(y + z\right) + z\right) + y\right) + t, y \cdot 5\right)} \]
      2. associate-+l+99.8%

        \[\leadsto \mathsf{fma}\left(x, \color{blue}{\left(\left(y + z\right) + \left(z + y\right)\right)} + t, y \cdot 5\right) \]
      3. +-commutative99.8%

        \[\leadsto \mathsf{fma}\left(x, \left(\left(y + z\right) + \color{blue}{\left(y + z\right)}\right) + t, y \cdot 5\right) \]
      4. count-299.8%

        \[\leadsto \mathsf{fma}\left(x, \color{blue}{2 \cdot \left(y + z\right)} + t, y \cdot 5\right) \]
    3. Simplified99.8%

      \[\leadsto \color{blue}{\mathsf{fma}\left(x, 2 \cdot \left(y + z\right) + t, y \cdot 5\right)} \]
    4. Add Preprocessing
    5. Taylor expanded in x around inf 72.5%

      \[\leadsto \color{blue}{x \cdot \left(t + \left(2 \cdot \left(y + z\right) + 5 \cdot \frac{y}{x}\right)\right)} \]
    6. Taylor expanded in t around inf 63.9%

      \[\leadsto \color{blue}{t \cdot \left(x + \frac{x \cdot \left(2 \cdot \left(y + z\right) + 5 \cdot \frac{y}{x}\right)}{t}\right)} \]
    7. Taylor expanded in x around 0 66.7%

      \[\leadsto t \cdot \left(x + \color{blue}{5 \cdot \frac{y}{t}}\right) \]
    8. Step-by-step derivation
      1. associate-*r/66.8%

        \[\leadsto t \cdot \left(x + \color{blue}{\frac{5 \cdot y}{t}}\right) \]
      2. *-commutative66.8%

        \[\leadsto t \cdot \left(x + \frac{\color{blue}{y \cdot 5}}{t}\right) \]
      3. associate-/l*66.7%

        \[\leadsto t \cdot \left(x + \color{blue}{y \cdot \frac{5}{t}}\right) \]
    9. Simplified66.7%

      \[\leadsto t \cdot \left(x + \color{blue}{y \cdot \frac{5}{t}}\right) \]
    10. Taylor expanded in t around 0 82.8%

      \[\leadsto \color{blue}{5 \cdot y + t \cdot x} \]
  3. Recombined 2 regimes into one program.
  4. Final simplification91.6%

    \[\leadsto \begin{array}{l} \mathbf{if}\;x \leq -3.4 \cdot 10^{-51} \lor \neg \left(x \leq 7 \cdot 10^{-48}\right):\\ \;\;\;\;x \cdot \left(2 \cdot \left(y + z\right) + t\right)\\ \mathbf{else}:\\ \;\;\;\;y \cdot 5 + x \cdot t\\ \end{array} \]
  5. Add Preprocessing

Alternative 11: 78.0% accurate, 0.9× speedup?

\[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;y \leq -1.55 \cdot 10^{+21} \lor \neg \left(y \leq 7.8 \cdot 10^{+77}\right):\\ \;\;\;\;y \cdot \left(5 + x \cdot 2\right)\\ \mathbf{else}:\\ \;\;\;\;x \cdot \left(t + 2 \cdot z\right)\\ \end{array} \end{array} \]
(FPCore (x y z t)
 :precision binary64
 (if (or (<= y -1.55e+21) (not (<= y 7.8e+77)))
   (* y (+ 5.0 (* x 2.0)))
   (* x (+ t (* 2.0 z)))))
double code(double x, double y, double z, double t) {
	double tmp;
	if ((y <= -1.55e+21) || !(y <= 7.8e+77)) {
		tmp = y * (5.0 + (x * 2.0));
	} else {
		tmp = x * (t + (2.0 * z));
	}
	return tmp;
}
real(8) function code(x, y, z, t)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    real(8), intent (in) :: z
    real(8), intent (in) :: t
    real(8) :: tmp
    if ((y <= (-1.55d+21)) .or. (.not. (y <= 7.8d+77))) then
        tmp = y * (5.0d0 + (x * 2.0d0))
    else
        tmp = x * (t + (2.0d0 * z))
    end if
    code = tmp
end function
public static double code(double x, double y, double z, double t) {
	double tmp;
	if ((y <= -1.55e+21) || !(y <= 7.8e+77)) {
		tmp = y * (5.0 + (x * 2.0));
	} else {
		tmp = x * (t + (2.0 * z));
	}
	return tmp;
}
def code(x, y, z, t):
	tmp = 0
	if (y <= -1.55e+21) or not (y <= 7.8e+77):
		tmp = y * (5.0 + (x * 2.0))
	else:
		tmp = x * (t + (2.0 * z))
	return tmp
function code(x, y, z, t)
	tmp = 0.0
	if ((y <= -1.55e+21) || !(y <= 7.8e+77))
		tmp = Float64(y * Float64(5.0 + Float64(x * 2.0)));
	else
		tmp = Float64(x * Float64(t + Float64(2.0 * z)));
	end
	return tmp
end
function tmp_2 = code(x, y, z, t)
	tmp = 0.0;
	if ((y <= -1.55e+21) || ~((y <= 7.8e+77)))
		tmp = y * (5.0 + (x * 2.0));
	else
		tmp = x * (t + (2.0 * z));
	end
	tmp_2 = tmp;
end
code[x_, y_, z_, t_] := If[Or[LessEqual[y, -1.55e+21], N[Not[LessEqual[y, 7.8e+77]], $MachinePrecision]], N[(y * N[(5.0 + N[(x * 2.0), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], N[(x * N[(t + N[(2.0 * z), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]]
\begin{array}{l}

\\
\begin{array}{l}
\mathbf{if}\;y \leq -1.55 \cdot 10^{+21} \lor \neg \left(y \leq 7.8 \cdot 10^{+77}\right):\\
\;\;\;\;y \cdot \left(5 + x \cdot 2\right)\\

\mathbf{else}:\\
\;\;\;\;x \cdot \left(t + 2 \cdot z\right)\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if y < -1.55e21 or 7.7999999999999995e77 < y

    1. Initial program 99.9%

      \[x \cdot \left(\left(\left(\left(y + z\right) + z\right) + y\right) + t\right) + y \cdot 5 \]
    2. Add Preprocessing
    3. Taylor expanded in y around inf 83.1%

      \[\leadsto \color{blue}{y \cdot \left(5 + 2 \cdot x\right)} \]
    4. Simplified83.1%

      \[\leadsto \color{blue}{y \cdot \left(5 + x \cdot 2\right)} \]

    if -1.55e21 < y < 7.7999999999999995e77

    1. Initial program 99.9%

      \[x \cdot \left(\left(\left(\left(y + z\right) + z\right) + y\right) + t\right) + y \cdot 5 \]
    2. Add Preprocessing
    3. Taylor expanded in y around 0 78.6%

      \[\leadsto \color{blue}{x \cdot \left(t + 2 \cdot z\right)} \]
  3. Recombined 2 regimes into one program.
  4. Final simplification80.6%

    \[\leadsto \begin{array}{l} \mathbf{if}\;y \leq -1.55 \cdot 10^{+21} \lor \neg \left(y \leq 7.8 \cdot 10^{+77}\right):\\ \;\;\;\;y \cdot \left(5 + x \cdot 2\right)\\ \mathbf{else}:\\ \;\;\;\;x \cdot \left(t + 2 \cdot z\right)\\ \end{array} \]
  5. Add Preprocessing

Alternative 12: 99.9% accurate, 1.0× speedup?

\[\begin{array}{l} \\ y \cdot 5 + x \cdot \left(t + \left(y + \left(z + \left(y + z\right)\right)\right)\right) \end{array} \]
(FPCore (x y z t)
 :precision binary64
 (+ (* y 5.0) (* x (+ t (+ y (+ z (+ y z)))))))
double code(double x, double y, double z, double t) {
	return (y * 5.0) + (x * (t + (y + (z + (y + z)))));
}
real(8) function code(x, y, z, t)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    real(8), intent (in) :: z
    real(8), intent (in) :: t
    code = (y * 5.0d0) + (x * (t + (y + (z + (y + z)))))
end function
public static double code(double x, double y, double z, double t) {
	return (y * 5.0) + (x * (t + (y + (z + (y + z)))));
}
def code(x, y, z, t):
	return (y * 5.0) + (x * (t + (y + (z + (y + z)))))
function code(x, y, z, t)
	return Float64(Float64(y * 5.0) + Float64(x * Float64(t + Float64(y + Float64(z + Float64(y + z))))))
end
function tmp = code(x, y, z, t)
	tmp = (y * 5.0) + (x * (t + (y + (z + (y + z)))));
end
code[x_, y_, z_, t_] := N[(N[(y * 5.0), $MachinePrecision] + N[(x * N[(t + N[(y + N[(z + N[(y + z), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
y \cdot 5 + x \cdot \left(t + \left(y + \left(z + \left(y + z\right)\right)\right)\right)
\end{array}
Derivation
  1. Initial program 99.9%

    \[x \cdot \left(\left(\left(\left(y + z\right) + z\right) + y\right) + t\right) + y \cdot 5 \]
  2. Add Preprocessing
  3. Final simplification99.9%

    \[\leadsto y \cdot 5 + x \cdot \left(t + \left(y + \left(z + \left(y + z\right)\right)\right)\right) \]
  4. Add Preprocessing

Alternative 13: 47.3% accurate, 1.1× speedup?

\[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;x \leq -7.6 \cdot 10^{-12} \lor \neg \left(x \leq 6.5 \cdot 10^{-48}\right):\\ \;\;\;\;x \cdot t\\ \mathbf{else}:\\ \;\;\;\;y \cdot 5\\ \end{array} \end{array} \]
(FPCore (x y z t)
 :precision binary64
 (if (or (<= x -7.6e-12) (not (<= x 6.5e-48))) (* x t) (* y 5.0)))
double code(double x, double y, double z, double t) {
	double tmp;
	if ((x <= -7.6e-12) || !(x <= 6.5e-48)) {
		tmp = x * t;
	} else {
		tmp = y * 5.0;
	}
	return tmp;
}
real(8) function code(x, y, z, t)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    real(8), intent (in) :: z
    real(8), intent (in) :: t
    real(8) :: tmp
    if ((x <= (-7.6d-12)) .or. (.not. (x <= 6.5d-48))) then
        tmp = x * t
    else
        tmp = y * 5.0d0
    end if
    code = tmp
end function
public static double code(double x, double y, double z, double t) {
	double tmp;
	if ((x <= -7.6e-12) || !(x <= 6.5e-48)) {
		tmp = x * t;
	} else {
		tmp = y * 5.0;
	}
	return tmp;
}
def code(x, y, z, t):
	tmp = 0
	if (x <= -7.6e-12) or not (x <= 6.5e-48):
		tmp = x * t
	else:
		tmp = y * 5.0
	return tmp
function code(x, y, z, t)
	tmp = 0.0
	if ((x <= -7.6e-12) || !(x <= 6.5e-48))
		tmp = Float64(x * t);
	else
		tmp = Float64(y * 5.0);
	end
	return tmp
end
function tmp_2 = code(x, y, z, t)
	tmp = 0.0;
	if ((x <= -7.6e-12) || ~((x <= 6.5e-48)))
		tmp = x * t;
	else
		tmp = y * 5.0;
	end
	tmp_2 = tmp;
end
code[x_, y_, z_, t_] := If[Or[LessEqual[x, -7.6e-12], N[Not[LessEqual[x, 6.5e-48]], $MachinePrecision]], N[(x * t), $MachinePrecision], N[(y * 5.0), $MachinePrecision]]
\begin{array}{l}

\\
\begin{array}{l}
\mathbf{if}\;x \leq -7.6 \cdot 10^{-12} \lor \neg \left(x \leq 6.5 \cdot 10^{-48}\right):\\
\;\;\;\;x \cdot t\\

\mathbf{else}:\\
\;\;\;\;y \cdot 5\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if x < -7.59999999999999993e-12 or 6.5e-48 < x

    1. Initial program 100.0%

      \[x \cdot \left(\left(\left(\left(y + z\right) + z\right) + y\right) + t\right) + y \cdot 5 \]
    2. Add Preprocessing
    3. Taylor expanded in t around inf 39.0%

      \[\leadsto \color{blue}{t \cdot x} \]
    4. Simplified39.0%

      \[\leadsto \color{blue}{x \cdot t} \]

    if -7.59999999999999993e-12 < x < 6.5e-48

    1. Initial program 99.8%

      \[x \cdot \left(\left(\left(\left(y + z\right) + z\right) + y\right) + t\right) + y \cdot 5 \]
    2. Add Preprocessing
    3. Taylor expanded in x around 0 63.8%

      \[\leadsto \color{blue}{5 \cdot y} \]
  3. Recombined 2 regimes into one program.
  4. Final simplification49.6%

    \[\leadsto \begin{array}{l} \mathbf{if}\;x \leq -7.6 \cdot 10^{-12} \lor \neg \left(x \leq 6.5 \cdot 10^{-48}\right):\\ \;\;\;\;x \cdot t\\ \mathbf{else}:\\ \;\;\;\;y \cdot 5\\ \end{array} \]
  5. Add Preprocessing

Alternative 14: 47.2% accurate, 1.2× speedup?

\[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;x \leq -1.02 \cdot 10^{-8}:\\ \;\;\;\;y \cdot \left(x \cdot 2\right)\\ \mathbf{elif}\;x \leq 4.8 \cdot 10^{-48}:\\ \;\;\;\;y \cdot 5\\ \mathbf{else}:\\ \;\;\;\;x \cdot t\\ \end{array} \end{array} \]
(FPCore (x y z t)
 :precision binary64
 (if (<= x -1.02e-8) (* y (* x 2.0)) (if (<= x 4.8e-48) (* y 5.0) (* x t))))
double code(double x, double y, double z, double t) {
	double tmp;
	if (x <= -1.02e-8) {
		tmp = y * (x * 2.0);
	} else if (x <= 4.8e-48) {
		tmp = y * 5.0;
	} else {
		tmp = x * t;
	}
	return tmp;
}
real(8) function code(x, y, z, t)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    real(8), intent (in) :: z
    real(8), intent (in) :: t
    real(8) :: tmp
    if (x <= (-1.02d-8)) then
        tmp = y * (x * 2.0d0)
    else if (x <= 4.8d-48) then
        tmp = y * 5.0d0
    else
        tmp = x * t
    end if
    code = tmp
end function
public static double code(double x, double y, double z, double t) {
	double tmp;
	if (x <= -1.02e-8) {
		tmp = y * (x * 2.0);
	} else if (x <= 4.8e-48) {
		tmp = y * 5.0;
	} else {
		tmp = x * t;
	}
	return tmp;
}
def code(x, y, z, t):
	tmp = 0
	if x <= -1.02e-8:
		tmp = y * (x * 2.0)
	elif x <= 4.8e-48:
		tmp = y * 5.0
	else:
		tmp = x * t
	return tmp
function code(x, y, z, t)
	tmp = 0.0
	if (x <= -1.02e-8)
		tmp = Float64(y * Float64(x * 2.0));
	elseif (x <= 4.8e-48)
		tmp = Float64(y * 5.0);
	else
		tmp = Float64(x * t);
	end
	return tmp
end
function tmp_2 = code(x, y, z, t)
	tmp = 0.0;
	if (x <= -1.02e-8)
		tmp = y * (x * 2.0);
	elseif (x <= 4.8e-48)
		tmp = y * 5.0;
	else
		tmp = x * t;
	end
	tmp_2 = tmp;
end
code[x_, y_, z_, t_] := If[LessEqual[x, -1.02e-8], N[(y * N[(x * 2.0), $MachinePrecision]), $MachinePrecision], If[LessEqual[x, 4.8e-48], N[(y * 5.0), $MachinePrecision], N[(x * t), $MachinePrecision]]]
\begin{array}{l}

\\
\begin{array}{l}
\mathbf{if}\;x \leq -1.02 \cdot 10^{-8}:\\
\;\;\;\;y \cdot \left(x \cdot 2\right)\\

\mathbf{elif}\;x \leq 4.8 \cdot 10^{-48}:\\
\;\;\;\;y \cdot 5\\

\mathbf{else}:\\
\;\;\;\;x \cdot t\\


\end{array}
\end{array}
Derivation
  1. Split input into 3 regimes
  2. if x < -1.02000000000000003e-8

    1. Initial program 100.0%

      \[x \cdot \left(\left(\left(\left(y + z\right) + z\right) + y\right) + t\right) + y \cdot 5 \]
    2. Add Preprocessing
    3. Taylor expanded in y around inf 48.0%

      \[\leadsto \color{blue}{y \cdot \left(5 + 2 \cdot x\right)} \]
    4. Simplified48.0%

      \[\leadsto \color{blue}{y \cdot \left(5 + x \cdot 2\right)} \]
    5. Taylor expanded in x around inf 48.1%

      \[\leadsto \color{blue}{2 \cdot \left(x \cdot y\right)} \]
    6. Step-by-step derivation
      1. *-commutative48.1%

        \[\leadsto \color{blue}{\left(x \cdot y\right) \cdot 2} \]
      2. *-commutative48.1%

        \[\leadsto \color{blue}{\left(y \cdot x\right)} \cdot 2 \]
      3. associate-*r*48.1%

        \[\leadsto \color{blue}{y \cdot \left(x \cdot 2\right)} \]
    7. Simplified48.1%

      \[\leadsto \color{blue}{y \cdot \left(x \cdot 2\right)} \]

    if -1.02000000000000003e-8 < x < 4.8e-48

    1. Initial program 99.8%

      \[x \cdot \left(\left(\left(\left(y + z\right) + z\right) + y\right) + t\right) + y \cdot 5 \]
    2. Add Preprocessing
    3. Taylor expanded in x around 0 63.3%

      \[\leadsto \color{blue}{5 \cdot y} \]

    if 4.8e-48 < x

    1. Initial program 100.0%

      \[x \cdot \left(\left(\left(\left(y + z\right) + z\right) + y\right) + t\right) + y \cdot 5 \]
    2. Add Preprocessing
    3. Taylor expanded in t around inf 42.0%

      \[\leadsto \color{blue}{t \cdot x} \]
    4. Simplified42.0%

      \[\leadsto \color{blue}{x \cdot t} \]
  3. Recombined 3 regimes into one program.
  4. Final simplification52.4%

    \[\leadsto \begin{array}{l} \mathbf{if}\;x \leq -1.02 \cdot 10^{-8}:\\ \;\;\;\;y \cdot \left(x \cdot 2\right)\\ \mathbf{elif}\;x \leq 4.8 \cdot 10^{-48}:\\ \;\;\;\;y \cdot 5\\ \mathbf{else}:\\ \;\;\;\;x \cdot t\\ \end{array} \]
  5. Add Preprocessing

Alternative 15: 29.5% accurate, 5.0× speedup?

\[\begin{array}{l} \\ y \cdot 5 \end{array} \]
(FPCore (x y z t) :precision binary64 (* y 5.0))
double code(double x, double y, double z, double t) {
	return y * 5.0;
}
real(8) function code(x, y, z, t)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    real(8), intent (in) :: z
    real(8), intent (in) :: t
    code = y * 5.0d0
end function
public static double code(double x, double y, double z, double t) {
	return y * 5.0;
}
def code(x, y, z, t):
	return y * 5.0
function code(x, y, z, t)
	return Float64(y * 5.0)
end
function tmp = code(x, y, z, t)
	tmp = y * 5.0;
end
code[x_, y_, z_, t_] := N[(y * 5.0), $MachinePrecision]
\begin{array}{l}

\\
y \cdot 5
\end{array}
Derivation
  1. Initial program 99.9%

    \[x \cdot \left(\left(\left(\left(y + z\right) + z\right) + y\right) + t\right) + y \cdot 5 \]
  2. Add Preprocessing
  3. Taylor expanded in x around 0 28.9%

    \[\leadsto \color{blue}{5 \cdot y} \]
  4. Final simplification28.9%

    \[\leadsto y \cdot 5 \]
  5. Add Preprocessing

Reproduce

?
herbie shell --seed 2024110 
(FPCore (x y z t)
  :name "Graphics.Rendering.Plot.Render.Plot.Legend:renderLegendOutside from plot-0.2.3.4, B"
  :precision binary64
  (+ (* x (+ (+ (+ (+ y z) z) y) t)) (* y 5.0)))