ab-angle->ABCF C

Percentage Accurate: 79.5% → 79.5%
Time: 39.8s
Alternatives: 10
Speedup: 1.3×

Specification

?
\[\begin{array}{l} \\ \begin{array}{l} t_0 := \pi \cdot \frac{angle}{180}\\ {\left(a \cdot \cos t\_0\right)}^{2} + {\left(b \cdot \sin t\_0\right)}^{2} \end{array} \end{array} \]
(FPCore (a b angle)
 :precision binary64
 (let* ((t_0 (* PI (/ angle 180.0))))
   (+ (pow (* a (cos t_0)) 2.0) (pow (* b (sin t_0)) 2.0))))
double code(double a, double b, double angle) {
	double t_0 = ((double) M_PI) * (angle / 180.0);
	return pow((a * cos(t_0)), 2.0) + pow((b * sin(t_0)), 2.0);
}
public static double code(double a, double b, double angle) {
	double t_0 = Math.PI * (angle / 180.0);
	return Math.pow((a * Math.cos(t_0)), 2.0) + Math.pow((b * Math.sin(t_0)), 2.0);
}
def code(a, b, angle):
	t_0 = math.pi * (angle / 180.0)
	return math.pow((a * math.cos(t_0)), 2.0) + math.pow((b * math.sin(t_0)), 2.0)
function code(a, b, angle)
	t_0 = Float64(pi * Float64(angle / 180.0))
	return Float64((Float64(a * cos(t_0)) ^ 2.0) + (Float64(b * sin(t_0)) ^ 2.0))
end
function tmp = code(a, b, angle)
	t_0 = pi * (angle / 180.0);
	tmp = ((a * cos(t_0)) ^ 2.0) + ((b * sin(t_0)) ^ 2.0);
end
code[a_, b_, angle_] := Block[{t$95$0 = N[(Pi * N[(angle / 180.0), $MachinePrecision]), $MachinePrecision]}, N[(N[Power[N[(a * N[Cos[t$95$0], $MachinePrecision]), $MachinePrecision], 2.0], $MachinePrecision] + N[Power[N[(b * N[Sin[t$95$0], $MachinePrecision]), $MachinePrecision], 2.0], $MachinePrecision]), $MachinePrecision]]
\begin{array}{l}

\\
\begin{array}{l}
t_0 := \pi \cdot \frac{angle}{180}\\
{\left(a \cdot \cos t\_0\right)}^{2} + {\left(b \cdot \sin t\_0\right)}^{2}
\end{array}
\end{array}

Sampling outcomes in binary64 precision:

Local Percentage Accuracy vs ?

The average percentage accuracy by input value. Horizontal axis shows value of an input variable; the variable is choosen in the title. Vertical axis is accuracy; higher is better. Red represent the original program, while blue represents Herbie's suggestion. These can be toggled with buttons below the plot. The line is an average while dots represent individual samples.

Accuracy vs Speed?

Herbie found 10 alternatives:

AlternativeAccuracySpeedup
The accuracy (vertical axis) and speed (horizontal axis) of each alternatives. Up and to the right is better. The red square shows the initial program, and each blue circle shows an alternative.The line shows the best available speed-accuracy tradeoffs.

Initial Program: 79.5% accurate, 1.0× speedup?

\[\begin{array}{l} \\ \begin{array}{l} t_0 := \pi \cdot \frac{angle}{180}\\ {\left(a \cdot \cos t\_0\right)}^{2} + {\left(b \cdot \sin t\_0\right)}^{2} \end{array} \end{array} \]
(FPCore (a b angle)
 :precision binary64
 (let* ((t_0 (* PI (/ angle 180.0))))
   (+ (pow (* a (cos t_0)) 2.0) (pow (* b (sin t_0)) 2.0))))
double code(double a, double b, double angle) {
	double t_0 = ((double) M_PI) * (angle / 180.0);
	return pow((a * cos(t_0)), 2.0) + pow((b * sin(t_0)), 2.0);
}
public static double code(double a, double b, double angle) {
	double t_0 = Math.PI * (angle / 180.0);
	return Math.pow((a * Math.cos(t_0)), 2.0) + Math.pow((b * Math.sin(t_0)), 2.0);
}
def code(a, b, angle):
	t_0 = math.pi * (angle / 180.0)
	return math.pow((a * math.cos(t_0)), 2.0) + math.pow((b * math.sin(t_0)), 2.0)
function code(a, b, angle)
	t_0 = Float64(pi * Float64(angle / 180.0))
	return Float64((Float64(a * cos(t_0)) ^ 2.0) + (Float64(b * sin(t_0)) ^ 2.0))
end
function tmp = code(a, b, angle)
	t_0 = pi * (angle / 180.0);
	tmp = ((a * cos(t_0)) ^ 2.0) + ((b * sin(t_0)) ^ 2.0);
end
code[a_, b_, angle_] := Block[{t$95$0 = N[(Pi * N[(angle / 180.0), $MachinePrecision]), $MachinePrecision]}, N[(N[Power[N[(a * N[Cos[t$95$0], $MachinePrecision]), $MachinePrecision], 2.0], $MachinePrecision] + N[Power[N[(b * N[Sin[t$95$0], $MachinePrecision]), $MachinePrecision], 2.0], $MachinePrecision]), $MachinePrecision]]
\begin{array}{l}

\\
\begin{array}{l}
t_0 := \pi \cdot \frac{angle}{180}\\
{\left(a \cdot \cos t\_0\right)}^{2} + {\left(b \cdot \sin t\_0\right)}^{2}
\end{array}
\end{array}

Alternative 1: 79.5% accurate, 0.5× speedup?

\[\begin{array}{l} angle_m = \left|angle\right| \\ {\left(a \cdot \cos \left(\pi \cdot {\left(\sqrt[3]{angle\_m \cdot 0.005555555555555556}\right)}^{3}\right)\right)}^{2} + {\left(b \cdot \sin \left(\mathsf{expm1}\left(\mathsf{log1p}\left(\pi \cdot \left(angle\_m \cdot 0.005555555555555556\right)\right)\right)\right)\right)}^{2} \end{array} \]
angle_m = (fabs.f64 angle)
(FPCore (a b angle_m)
 :precision binary64
 (+
  (pow
   (* a (cos (* PI (pow (cbrt (* angle_m 0.005555555555555556)) 3.0))))
   2.0)
  (pow
   (* b (sin (expm1 (log1p (* PI (* angle_m 0.005555555555555556))))))
   2.0)))
angle_m = fabs(angle);
double code(double a, double b, double angle_m) {
	return pow((a * cos((((double) M_PI) * pow(cbrt((angle_m * 0.005555555555555556)), 3.0)))), 2.0) + pow((b * sin(expm1(log1p((((double) M_PI) * (angle_m * 0.005555555555555556)))))), 2.0);
}
angle_m = Math.abs(angle);
public static double code(double a, double b, double angle_m) {
	return Math.pow((a * Math.cos((Math.PI * Math.pow(Math.cbrt((angle_m * 0.005555555555555556)), 3.0)))), 2.0) + Math.pow((b * Math.sin(Math.expm1(Math.log1p((Math.PI * (angle_m * 0.005555555555555556)))))), 2.0);
}
angle_m = abs(angle)
function code(a, b, angle_m)
	return Float64((Float64(a * cos(Float64(pi * (cbrt(Float64(angle_m * 0.005555555555555556)) ^ 3.0)))) ^ 2.0) + (Float64(b * sin(expm1(log1p(Float64(pi * Float64(angle_m * 0.005555555555555556)))))) ^ 2.0))
end
angle_m = N[Abs[angle], $MachinePrecision]
code[a_, b_, angle$95$m_] := N[(N[Power[N[(a * N[Cos[N[(Pi * N[Power[N[Power[N[(angle$95$m * 0.005555555555555556), $MachinePrecision], 1/3], $MachinePrecision], 3.0], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision], 2.0], $MachinePrecision] + N[Power[N[(b * N[Sin[N[(Exp[N[Log[1 + N[(Pi * N[(angle$95$m * 0.005555555555555556), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]] - 1), $MachinePrecision]], $MachinePrecision]), $MachinePrecision], 2.0], $MachinePrecision]), $MachinePrecision]
\begin{array}{l}
angle_m = \left|angle\right|

\\
{\left(a \cdot \cos \left(\pi \cdot {\left(\sqrt[3]{angle\_m \cdot 0.005555555555555556}\right)}^{3}\right)\right)}^{2} + {\left(b \cdot \sin \left(\mathsf{expm1}\left(\mathsf{log1p}\left(\pi \cdot \left(angle\_m \cdot 0.005555555555555556\right)\right)\right)\right)\right)}^{2}
\end{array}
Derivation
  1. Initial program 79.4%

    \[{\left(a \cdot \cos \left(\pi \cdot \frac{angle}{180}\right)\right)}^{2} + {\left(b \cdot \sin \left(\pi \cdot \frac{angle}{180}\right)\right)}^{2} \]
  2. Step-by-step derivation
    1. Simplified79.4%

      \[\leadsto \color{blue}{{\left(a \cdot \cos \left(\pi \cdot \left(angle \cdot 0.005555555555555556\right)\right)\right)}^{2} + {\left(b \cdot \sin \left(\pi \cdot \left(angle \cdot 0.005555555555555556\right)\right)\right)}^{2}} \]
    2. Add Preprocessing
    3. Step-by-step derivation
      1. expm1-log1p-u62.7%

        \[\leadsto {\left(a \cdot \cos \left(\pi \cdot \left(angle \cdot 0.005555555555555556\right)\right)\right)}^{2} + {\left(b \cdot \sin \color{blue}{\left(\mathsf{expm1}\left(\mathsf{log1p}\left(\pi \cdot \left(angle \cdot 0.005555555555555556\right)\right)\right)\right)}\right)}^{2} \]
    4. Applied egg-rr62.7%

      \[\leadsto {\left(a \cdot \cos \left(\pi \cdot \left(angle \cdot 0.005555555555555556\right)\right)\right)}^{2} + {\left(b \cdot \sin \color{blue}{\left(\mathsf{expm1}\left(\mathsf{log1p}\left(\pi \cdot \left(angle \cdot 0.005555555555555556\right)\right)\right)\right)}\right)}^{2} \]
    5. Step-by-step derivation
      1. add-cube-cbrt62.7%

        \[\leadsto {\left(a \cdot \cos \left(\pi \cdot \color{blue}{\left(\left(\sqrt[3]{angle \cdot 0.005555555555555556} \cdot \sqrt[3]{angle \cdot 0.005555555555555556}\right) \cdot \sqrt[3]{angle \cdot 0.005555555555555556}\right)}\right)\right)}^{2} + {\left(b \cdot \sin \left(\mathsf{expm1}\left(\mathsf{log1p}\left(\pi \cdot \left(angle \cdot 0.005555555555555556\right)\right)\right)\right)\right)}^{2} \]
      2. pow362.8%

        \[\leadsto {\left(a \cdot \cos \left(\pi \cdot \color{blue}{{\left(\sqrt[3]{angle \cdot 0.005555555555555556}\right)}^{3}}\right)\right)}^{2} + {\left(b \cdot \sin \left(\mathsf{expm1}\left(\mathsf{log1p}\left(\pi \cdot \left(angle \cdot 0.005555555555555556\right)\right)\right)\right)\right)}^{2} \]
    6. Applied egg-rr62.8%

      \[\leadsto {\left(a \cdot \cos \left(\pi \cdot \color{blue}{{\left(\sqrt[3]{angle \cdot 0.005555555555555556}\right)}^{3}}\right)\right)}^{2} + {\left(b \cdot \sin \left(\mathsf{expm1}\left(\mathsf{log1p}\left(\pi \cdot \left(angle \cdot 0.005555555555555556\right)\right)\right)\right)\right)}^{2} \]
    7. Add Preprocessing

    Alternative 2: 79.5% accurate, 0.7× speedup?

    \[\begin{array}{l} angle_m = \left|angle\right| \\ \begin{array}{l} t_0 := \pi \cdot \left(angle\_m \cdot 0.005555555555555556\right)\\ {\left(b \cdot \sin \left(\mathsf{expm1}\left(\mathsf{log1p}\left(t\_0\right)\right)\right)\right)}^{2} + {\left(a \cdot \cos t\_0\right)}^{2} \end{array} \end{array} \]
    angle_m = (fabs.f64 angle)
    (FPCore (a b angle_m)
     :precision binary64
     (let* ((t_0 (* PI (* angle_m 0.005555555555555556))))
       (+ (pow (* b (sin (expm1 (log1p t_0)))) 2.0) (pow (* a (cos t_0)) 2.0))))
    angle_m = fabs(angle);
    double code(double a, double b, double angle_m) {
    	double t_0 = ((double) M_PI) * (angle_m * 0.005555555555555556);
    	return pow((b * sin(expm1(log1p(t_0)))), 2.0) + pow((a * cos(t_0)), 2.0);
    }
    
    angle_m = Math.abs(angle);
    public static double code(double a, double b, double angle_m) {
    	double t_0 = Math.PI * (angle_m * 0.005555555555555556);
    	return Math.pow((b * Math.sin(Math.expm1(Math.log1p(t_0)))), 2.0) + Math.pow((a * Math.cos(t_0)), 2.0);
    }
    
    angle_m = math.fabs(angle)
    def code(a, b, angle_m):
    	t_0 = math.pi * (angle_m * 0.005555555555555556)
    	return math.pow((b * math.sin(math.expm1(math.log1p(t_0)))), 2.0) + math.pow((a * math.cos(t_0)), 2.0)
    
    angle_m = abs(angle)
    function code(a, b, angle_m)
    	t_0 = Float64(pi * Float64(angle_m * 0.005555555555555556))
    	return Float64((Float64(b * sin(expm1(log1p(t_0)))) ^ 2.0) + (Float64(a * cos(t_0)) ^ 2.0))
    end
    
    angle_m = N[Abs[angle], $MachinePrecision]
    code[a_, b_, angle$95$m_] := Block[{t$95$0 = N[(Pi * N[(angle$95$m * 0.005555555555555556), $MachinePrecision]), $MachinePrecision]}, N[(N[Power[N[(b * N[Sin[N[(Exp[N[Log[1 + t$95$0], $MachinePrecision]] - 1), $MachinePrecision]], $MachinePrecision]), $MachinePrecision], 2.0], $MachinePrecision] + N[Power[N[(a * N[Cos[t$95$0], $MachinePrecision]), $MachinePrecision], 2.0], $MachinePrecision]), $MachinePrecision]]
    
    \begin{array}{l}
    angle_m = \left|angle\right|
    
    \\
    \begin{array}{l}
    t_0 := \pi \cdot \left(angle\_m \cdot 0.005555555555555556\right)\\
    {\left(b \cdot \sin \left(\mathsf{expm1}\left(\mathsf{log1p}\left(t\_0\right)\right)\right)\right)}^{2} + {\left(a \cdot \cos t\_0\right)}^{2}
    \end{array}
    \end{array}
    
    Derivation
    1. Initial program 79.4%

      \[{\left(a \cdot \cos \left(\pi \cdot \frac{angle}{180}\right)\right)}^{2} + {\left(b \cdot \sin \left(\pi \cdot \frac{angle}{180}\right)\right)}^{2} \]
    2. Step-by-step derivation
      1. Simplified79.4%

        \[\leadsto \color{blue}{{\left(a \cdot \cos \left(\pi \cdot \left(angle \cdot 0.005555555555555556\right)\right)\right)}^{2} + {\left(b \cdot \sin \left(\pi \cdot \left(angle \cdot 0.005555555555555556\right)\right)\right)}^{2}} \]
      2. Add Preprocessing
      3. Step-by-step derivation
        1. expm1-log1p-u62.7%

          \[\leadsto {\left(a \cdot \cos \left(\pi \cdot \left(angle \cdot 0.005555555555555556\right)\right)\right)}^{2} + {\left(b \cdot \sin \color{blue}{\left(\mathsf{expm1}\left(\mathsf{log1p}\left(\pi \cdot \left(angle \cdot 0.005555555555555556\right)\right)\right)\right)}\right)}^{2} \]
      4. Applied egg-rr62.7%

        \[\leadsto {\left(a \cdot \cos \left(\pi \cdot \left(angle \cdot 0.005555555555555556\right)\right)\right)}^{2} + {\left(b \cdot \sin \color{blue}{\left(\mathsf{expm1}\left(\mathsf{log1p}\left(\pi \cdot \left(angle \cdot 0.005555555555555556\right)\right)\right)\right)}\right)}^{2} \]
      5. Final simplification62.7%

        \[\leadsto {\left(b \cdot \sin \left(\mathsf{expm1}\left(\mathsf{log1p}\left(\pi \cdot \left(angle \cdot 0.005555555555555556\right)\right)\right)\right)\right)}^{2} + {\left(a \cdot \cos \left(\pi \cdot \left(angle \cdot 0.005555555555555556\right)\right)\right)}^{2} \]
      6. Add Preprocessing

      Alternative 3: 79.5% accurate, 1.0× speedup?

      \[\begin{array}{l} angle_m = \left|angle\right| \\ {\left(a \cdot \cos \left(\frac{\pi \cdot angle\_m}{180}\right)\right)}^{2} + {\left(b \cdot \sin \left(\pi \cdot \left(angle\_m \cdot 0.005555555555555556\right)\right)\right)}^{2} \end{array} \]
      angle_m = (fabs.f64 angle)
      (FPCore (a b angle_m)
       :precision binary64
       (+
        (pow (* a (cos (/ (* PI angle_m) 180.0))) 2.0)
        (pow (* b (sin (* PI (* angle_m 0.005555555555555556)))) 2.0)))
      angle_m = fabs(angle);
      double code(double a, double b, double angle_m) {
      	return pow((a * cos(((((double) M_PI) * angle_m) / 180.0))), 2.0) + pow((b * sin((((double) M_PI) * (angle_m * 0.005555555555555556)))), 2.0);
      }
      
      angle_m = Math.abs(angle);
      public static double code(double a, double b, double angle_m) {
      	return Math.pow((a * Math.cos(((Math.PI * angle_m) / 180.0))), 2.0) + Math.pow((b * Math.sin((Math.PI * (angle_m * 0.005555555555555556)))), 2.0);
      }
      
      angle_m = math.fabs(angle)
      def code(a, b, angle_m):
      	return math.pow((a * math.cos(((math.pi * angle_m) / 180.0))), 2.0) + math.pow((b * math.sin((math.pi * (angle_m * 0.005555555555555556)))), 2.0)
      
      angle_m = abs(angle)
      function code(a, b, angle_m)
      	return Float64((Float64(a * cos(Float64(Float64(pi * angle_m) / 180.0))) ^ 2.0) + (Float64(b * sin(Float64(pi * Float64(angle_m * 0.005555555555555556)))) ^ 2.0))
      end
      
      angle_m = abs(angle);
      function tmp = code(a, b, angle_m)
      	tmp = ((a * cos(((pi * angle_m) / 180.0))) ^ 2.0) + ((b * sin((pi * (angle_m * 0.005555555555555556)))) ^ 2.0);
      end
      
      angle_m = N[Abs[angle], $MachinePrecision]
      code[a_, b_, angle$95$m_] := N[(N[Power[N[(a * N[Cos[N[(N[(Pi * angle$95$m), $MachinePrecision] / 180.0), $MachinePrecision]], $MachinePrecision]), $MachinePrecision], 2.0], $MachinePrecision] + N[Power[N[(b * N[Sin[N[(Pi * N[(angle$95$m * 0.005555555555555556), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision], 2.0], $MachinePrecision]), $MachinePrecision]
      
      \begin{array}{l}
      angle_m = \left|angle\right|
      
      \\
      {\left(a \cdot \cos \left(\frac{\pi \cdot angle\_m}{180}\right)\right)}^{2} + {\left(b \cdot \sin \left(\pi \cdot \left(angle\_m \cdot 0.005555555555555556\right)\right)\right)}^{2}
      \end{array}
      
      Derivation
      1. Initial program 79.4%

        \[{\left(a \cdot \cos \left(\pi \cdot \frac{angle}{180}\right)\right)}^{2} + {\left(b \cdot \sin \left(\pi \cdot \frac{angle}{180}\right)\right)}^{2} \]
      2. Step-by-step derivation
        1. Simplified79.4%

          \[\leadsto \color{blue}{{\left(a \cdot \cos \left(\pi \cdot \left(angle \cdot 0.005555555555555556\right)\right)\right)}^{2} + {\left(b \cdot \sin \left(\pi \cdot \left(angle \cdot 0.005555555555555556\right)\right)\right)}^{2}} \]
        2. Add Preprocessing
        3. Step-by-step derivation
          1. metadata-eval79.4%

            \[\leadsto {\left(a \cdot \cos \left(\pi \cdot \left(angle \cdot \color{blue}{\frac{1}{180}}\right)\right)\right)}^{2} + {\left(b \cdot \sin \left(\pi \cdot \left(angle \cdot 0.005555555555555556\right)\right)\right)}^{2} \]
          2. div-inv79.4%

            \[\leadsto {\left(a \cdot \cos \left(\pi \cdot \color{blue}{\frac{angle}{180}}\right)\right)}^{2} + {\left(b \cdot \sin \left(\pi \cdot \left(angle \cdot 0.005555555555555556\right)\right)\right)}^{2} \]
          3. associate-*r/79.5%

            \[\leadsto {\left(a \cdot \cos \color{blue}{\left(\frac{\pi \cdot angle}{180}\right)}\right)}^{2} + {\left(b \cdot \sin \left(\pi \cdot \left(angle \cdot 0.005555555555555556\right)\right)\right)}^{2} \]
        4. Applied egg-rr79.5%

          \[\leadsto {\left(a \cdot \cos \color{blue}{\left(\frac{\pi \cdot angle}{180}\right)}\right)}^{2} + {\left(b \cdot \sin \left(\pi \cdot \left(angle \cdot 0.005555555555555556\right)\right)\right)}^{2} \]
        5. Add Preprocessing

        Alternative 4: 79.5% accurate, 1.0× speedup?

        \[\begin{array}{l} angle_m = \left|angle\right| \\ {\left(b \cdot \sin \left(\pi \cdot \left(angle\_m \cdot 0.005555555555555556\right)\right)\right)}^{2} + {\left(a \cdot \cos \left(0.005555555555555556 \cdot \left(\pi \cdot angle\_m\right)\right)\right)}^{2} \end{array} \]
        angle_m = (fabs.f64 angle)
        (FPCore (a b angle_m)
         :precision binary64
         (+
          (pow (* b (sin (* PI (* angle_m 0.005555555555555556)))) 2.0)
          (pow (* a (cos (* 0.005555555555555556 (* PI angle_m)))) 2.0)))
        angle_m = fabs(angle);
        double code(double a, double b, double angle_m) {
        	return pow((b * sin((((double) M_PI) * (angle_m * 0.005555555555555556)))), 2.0) + pow((a * cos((0.005555555555555556 * (((double) M_PI) * angle_m)))), 2.0);
        }
        
        angle_m = Math.abs(angle);
        public static double code(double a, double b, double angle_m) {
        	return Math.pow((b * Math.sin((Math.PI * (angle_m * 0.005555555555555556)))), 2.0) + Math.pow((a * Math.cos((0.005555555555555556 * (Math.PI * angle_m)))), 2.0);
        }
        
        angle_m = math.fabs(angle)
        def code(a, b, angle_m):
        	return math.pow((b * math.sin((math.pi * (angle_m * 0.005555555555555556)))), 2.0) + math.pow((a * math.cos((0.005555555555555556 * (math.pi * angle_m)))), 2.0)
        
        angle_m = abs(angle)
        function code(a, b, angle_m)
        	return Float64((Float64(b * sin(Float64(pi * Float64(angle_m * 0.005555555555555556)))) ^ 2.0) + (Float64(a * cos(Float64(0.005555555555555556 * Float64(pi * angle_m)))) ^ 2.0))
        end
        
        angle_m = abs(angle);
        function tmp = code(a, b, angle_m)
        	tmp = ((b * sin((pi * (angle_m * 0.005555555555555556)))) ^ 2.0) + ((a * cos((0.005555555555555556 * (pi * angle_m)))) ^ 2.0);
        end
        
        angle_m = N[Abs[angle], $MachinePrecision]
        code[a_, b_, angle$95$m_] := N[(N[Power[N[(b * N[Sin[N[(Pi * N[(angle$95$m * 0.005555555555555556), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision], 2.0], $MachinePrecision] + N[Power[N[(a * N[Cos[N[(0.005555555555555556 * N[(Pi * angle$95$m), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision], 2.0], $MachinePrecision]), $MachinePrecision]
        
        \begin{array}{l}
        angle_m = \left|angle\right|
        
        \\
        {\left(b \cdot \sin \left(\pi \cdot \left(angle\_m \cdot 0.005555555555555556\right)\right)\right)}^{2} + {\left(a \cdot \cos \left(0.005555555555555556 \cdot \left(\pi \cdot angle\_m\right)\right)\right)}^{2}
        \end{array}
        
        Derivation
        1. Initial program 79.4%

          \[{\left(a \cdot \cos \left(\pi \cdot \frac{angle}{180}\right)\right)}^{2} + {\left(b \cdot \sin \left(\pi \cdot \frac{angle}{180}\right)\right)}^{2} \]
        2. Step-by-step derivation
          1. Simplified79.4%

            \[\leadsto \color{blue}{{\left(a \cdot \cos \left(\pi \cdot \left(angle \cdot 0.005555555555555556\right)\right)\right)}^{2} + {\left(b \cdot \sin \left(\pi \cdot \left(angle \cdot 0.005555555555555556\right)\right)\right)}^{2}} \]
          2. Add Preprocessing
          3. Taylor expanded in angle around inf 79.5%

            \[\leadsto {\left(a \cdot \color{blue}{\cos \left(0.005555555555555556 \cdot \left(angle \cdot \pi\right)\right)}\right)}^{2} + {\left(b \cdot \sin \left(\pi \cdot \left(angle \cdot 0.005555555555555556\right)\right)\right)}^{2} \]
          4. Final simplification79.5%

            \[\leadsto {\left(b \cdot \sin \left(\pi \cdot \left(angle \cdot 0.005555555555555556\right)\right)\right)}^{2} + {\left(a \cdot \cos \left(0.005555555555555556 \cdot \left(\pi \cdot angle\right)\right)\right)}^{2} \]
          5. Add Preprocessing

          Alternative 5: 79.5% accurate, 1.3× speedup?

          \[\begin{array}{l} angle_m = \left|angle\right| \\ {a}^{2} + {\left(b \cdot \sin \left(\frac{\pi}{\frac{180}{angle\_m}}\right)\right)}^{2} \end{array} \]
          angle_m = (fabs.f64 angle)
          (FPCore (a b angle_m)
           :precision binary64
           (+ (pow a 2.0) (pow (* b (sin (/ PI (/ 180.0 angle_m)))) 2.0)))
          angle_m = fabs(angle);
          double code(double a, double b, double angle_m) {
          	return pow(a, 2.0) + pow((b * sin((((double) M_PI) / (180.0 / angle_m)))), 2.0);
          }
          
          angle_m = Math.abs(angle);
          public static double code(double a, double b, double angle_m) {
          	return Math.pow(a, 2.0) + Math.pow((b * Math.sin((Math.PI / (180.0 / angle_m)))), 2.0);
          }
          
          angle_m = math.fabs(angle)
          def code(a, b, angle_m):
          	return math.pow(a, 2.0) + math.pow((b * math.sin((math.pi / (180.0 / angle_m)))), 2.0)
          
          angle_m = abs(angle)
          function code(a, b, angle_m)
          	return Float64((a ^ 2.0) + (Float64(b * sin(Float64(pi / Float64(180.0 / angle_m)))) ^ 2.0))
          end
          
          angle_m = abs(angle);
          function tmp = code(a, b, angle_m)
          	tmp = (a ^ 2.0) + ((b * sin((pi / (180.0 / angle_m)))) ^ 2.0);
          end
          
          angle_m = N[Abs[angle], $MachinePrecision]
          code[a_, b_, angle$95$m_] := N[(N[Power[a, 2.0], $MachinePrecision] + N[Power[N[(b * N[Sin[N[(Pi / N[(180.0 / angle$95$m), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision], 2.0], $MachinePrecision]), $MachinePrecision]
          
          \begin{array}{l}
          angle_m = \left|angle\right|
          
          \\
          {a}^{2} + {\left(b \cdot \sin \left(\frac{\pi}{\frac{180}{angle\_m}}\right)\right)}^{2}
          \end{array}
          
          Derivation
          1. Initial program 79.4%

            \[{\left(a \cdot \cos \left(\pi \cdot \frac{angle}{180}\right)\right)}^{2} + {\left(b \cdot \sin \left(\pi \cdot \frac{angle}{180}\right)\right)}^{2} \]
          2. Step-by-step derivation
            1. Simplified79.4%

              \[\leadsto \color{blue}{{\left(a \cdot \cos \left(\pi \cdot \left(angle \cdot 0.005555555555555556\right)\right)\right)}^{2} + {\left(b \cdot \sin \left(\pi \cdot \left(angle \cdot 0.005555555555555556\right)\right)\right)}^{2}} \]
            2. Add Preprocessing
            3. Taylor expanded in angle around 0 79.1%

              \[\leadsto {\left(a \cdot \color{blue}{1}\right)}^{2} + {\left(b \cdot \sin \left(\pi \cdot \left(angle \cdot 0.005555555555555556\right)\right)\right)}^{2} \]
            4. Step-by-step derivation
              1. metadata-eval79.1%

                \[\leadsto {\left(a \cdot 1\right)}^{2} + {\left(b \cdot \sin \left(\pi \cdot \left(angle \cdot \color{blue}{\frac{1}{180}}\right)\right)\right)}^{2} \]
              2. div-inv79.1%

                \[\leadsto {\left(a \cdot 1\right)}^{2} + {\left(b \cdot \sin \left(\pi \cdot \color{blue}{\frac{angle}{180}}\right)\right)}^{2} \]
              3. clear-num79.1%

                \[\leadsto {\left(a \cdot 1\right)}^{2} + {\left(b \cdot \sin \left(\pi \cdot \color{blue}{\frac{1}{\frac{180}{angle}}}\right)\right)}^{2} \]
              4. un-div-inv79.2%

                \[\leadsto {\left(a \cdot 1\right)}^{2} + {\left(b \cdot \sin \color{blue}{\left(\frac{\pi}{\frac{180}{angle}}\right)}\right)}^{2} \]
            5. Applied egg-rr79.2%

              \[\leadsto {\left(a \cdot 1\right)}^{2} + {\left(b \cdot \sin \color{blue}{\left(\frac{\pi}{\frac{180}{angle}}\right)}\right)}^{2} \]
            6. Final simplification79.2%

              \[\leadsto {a}^{2} + {\left(b \cdot \sin \left(\frac{\pi}{\frac{180}{angle}}\right)\right)}^{2} \]
            7. Add Preprocessing

            Alternative 6: 79.6% accurate, 1.3× speedup?

            \[\begin{array}{l} angle_m = \left|angle\right| \\ {\left(b \cdot \sin \left(\pi \cdot \left(angle\_m \cdot 0.005555555555555556\right)\right)\right)}^{2} + {a}^{2} \end{array} \]
            angle_m = (fabs.f64 angle)
            (FPCore (a b angle_m)
             :precision binary64
             (+ (pow (* b (sin (* PI (* angle_m 0.005555555555555556)))) 2.0) (pow a 2.0)))
            angle_m = fabs(angle);
            double code(double a, double b, double angle_m) {
            	return pow((b * sin((((double) M_PI) * (angle_m * 0.005555555555555556)))), 2.0) + pow(a, 2.0);
            }
            
            angle_m = Math.abs(angle);
            public static double code(double a, double b, double angle_m) {
            	return Math.pow((b * Math.sin((Math.PI * (angle_m * 0.005555555555555556)))), 2.0) + Math.pow(a, 2.0);
            }
            
            angle_m = math.fabs(angle)
            def code(a, b, angle_m):
            	return math.pow((b * math.sin((math.pi * (angle_m * 0.005555555555555556)))), 2.0) + math.pow(a, 2.0)
            
            angle_m = abs(angle)
            function code(a, b, angle_m)
            	return Float64((Float64(b * sin(Float64(pi * Float64(angle_m * 0.005555555555555556)))) ^ 2.0) + (a ^ 2.0))
            end
            
            angle_m = abs(angle);
            function tmp = code(a, b, angle_m)
            	tmp = ((b * sin((pi * (angle_m * 0.005555555555555556)))) ^ 2.0) + (a ^ 2.0);
            end
            
            angle_m = N[Abs[angle], $MachinePrecision]
            code[a_, b_, angle$95$m_] := N[(N[Power[N[(b * N[Sin[N[(Pi * N[(angle$95$m * 0.005555555555555556), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision], 2.0], $MachinePrecision] + N[Power[a, 2.0], $MachinePrecision]), $MachinePrecision]
            
            \begin{array}{l}
            angle_m = \left|angle\right|
            
            \\
            {\left(b \cdot \sin \left(\pi \cdot \left(angle\_m \cdot 0.005555555555555556\right)\right)\right)}^{2} + {a}^{2}
            \end{array}
            
            Derivation
            1. Initial program 79.4%

              \[{\left(a \cdot \cos \left(\pi \cdot \frac{angle}{180}\right)\right)}^{2} + {\left(b \cdot \sin \left(\pi \cdot \frac{angle}{180}\right)\right)}^{2} \]
            2. Step-by-step derivation
              1. Simplified79.4%

                \[\leadsto \color{blue}{{\left(a \cdot \cos \left(\pi \cdot \left(angle \cdot 0.005555555555555556\right)\right)\right)}^{2} + {\left(b \cdot \sin \left(\pi \cdot \left(angle \cdot 0.005555555555555556\right)\right)\right)}^{2}} \]
              2. Add Preprocessing
              3. Taylor expanded in angle around 0 79.1%

                \[\leadsto {\left(a \cdot \color{blue}{1}\right)}^{2} + {\left(b \cdot \sin \left(\pi \cdot \left(angle \cdot 0.005555555555555556\right)\right)\right)}^{2} \]
              4. Final simplification79.1%

                \[\leadsto {\left(b \cdot \sin \left(\pi \cdot \left(angle \cdot 0.005555555555555556\right)\right)\right)}^{2} + {a}^{2} \]
              5. Add Preprocessing

              Alternative 7: 79.6% accurate, 1.3× speedup?

              \[\begin{array}{l} angle_m = \left|angle\right| \\ {a}^{2} + {\left(b \cdot \sin \left(0.005555555555555556 \cdot \left(\pi \cdot angle\_m\right)\right)\right)}^{2} \end{array} \]
              angle_m = (fabs.f64 angle)
              (FPCore (a b angle_m)
               :precision binary64
               (+ (pow a 2.0) (pow (* b (sin (* 0.005555555555555556 (* PI angle_m)))) 2.0)))
              angle_m = fabs(angle);
              double code(double a, double b, double angle_m) {
              	return pow(a, 2.0) + pow((b * sin((0.005555555555555556 * (((double) M_PI) * angle_m)))), 2.0);
              }
              
              angle_m = Math.abs(angle);
              public static double code(double a, double b, double angle_m) {
              	return Math.pow(a, 2.0) + Math.pow((b * Math.sin((0.005555555555555556 * (Math.PI * angle_m)))), 2.0);
              }
              
              angle_m = math.fabs(angle)
              def code(a, b, angle_m):
              	return math.pow(a, 2.0) + math.pow((b * math.sin((0.005555555555555556 * (math.pi * angle_m)))), 2.0)
              
              angle_m = abs(angle)
              function code(a, b, angle_m)
              	return Float64((a ^ 2.0) + (Float64(b * sin(Float64(0.005555555555555556 * Float64(pi * angle_m)))) ^ 2.0))
              end
              
              angle_m = abs(angle);
              function tmp = code(a, b, angle_m)
              	tmp = (a ^ 2.0) + ((b * sin((0.005555555555555556 * (pi * angle_m)))) ^ 2.0);
              end
              
              angle_m = N[Abs[angle], $MachinePrecision]
              code[a_, b_, angle$95$m_] := N[(N[Power[a, 2.0], $MachinePrecision] + N[Power[N[(b * N[Sin[N[(0.005555555555555556 * N[(Pi * angle$95$m), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision], 2.0], $MachinePrecision]), $MachinePrecision]
              
              \begin{array}{l}
              angle_m = \left|angle\right|
              
              \\
              {a}^{2} + {\left(b \cdot \sin \left(0.005555555555555556 \cdot \left(\pi \cdot angle\_m\right)\right)\right)}^{2}
              \end{array}
              
              Derivation
              1. Initial program 79.4%

                \[{\left(a \cdot \cos \left(\pi \cdot \frac{angle}{180}\right)\right)}^{2} + {\left(b \cdot \sin \left(\pi \cdot \frac{angle}{180}\right)\right)}^{2} \]
              2. Step-by-step derivation
                1. Simplified79.4%

                  \[\leadsto \color{blue}{{\left(a \cdot \cos \left(\pi \cdot \left(angle \cdot 0.005555555555555556\right)\right)\right)}^{2} + {\left(b \cdot \sin \left(\pi \cdot \left(angle \cdot 0.005555555555555556\right)\right)\right)}^{2}} \]
                2. Add Preprocessing
                3. Taylor expanded in angle around 0 79.1%

                  \[\leadsto {\left(a \cdot \color{blue}{1}\right)}^{2} + {\left(b \cdot \sin \left(\pi \cdot \left(angle \cdot 0.005555555555555556\right)\right)\right)}^{2} \]
                4. Taylor expanded in angle around inf 79.1%

                  \[\leadsto {\left(a \cdot 1\right)}^{2} + {\left(b \cdot \color{blue}{\sin \left(0.005555555555555556 \cdot \left(angle \cdot \pi\right)\right)}\right)}^{2} \]
                5. Final simplification79.1%

                  \[\leadsto {a}^{2} + {\left(b \cdot \sin \left(0.005555555555555556 \cdot \left(\pi \cdot angle\right)\right)\right)}^{2} \]
                6. Add Preprocessing

                Alternative 8: 74.5% accurate, 3.5× speedup?

                \[\begin{array}{l} angle_m = \left|angle\right| \\ {a}^{2} + \left(0.005555555555555556 \cdot \left(\left(angle\_m \cdot 0.005555555555555556\right) \cdot \left(\pi \cdot b\right)\right)\right) \cdot \left(\pi \cdot \left(angle\_m \cdot b\right)\right) \end{array} \]
                angle_m = (fabs.f64 angle)
                (FPCore (a b angle_m)
                 :precision binary64
                 (+
                  (pow a 2.0)
                  (*
                   (* 0.005555555555555556 (* (* angle_m 0.005555555555555556) (* PI b)))
                   (* PI (* angle_m b)))))
                angle_m = fabs(angle);
                double code(double a, double b, double angle_m) {
                	return pow(a, 2.0) + ((0.005555555555555556 * ((angle_m * 0.005555555555555556) * (((double) M_PI) * b))) * (((double) M_PI) * (angle_m * b)));
                }
                
                angle_m = Math.abs(angle);
                public static double code(double a, double b, double angle_m) {
                	return Math.pow(a, 2.0) + ((0.005555555555555556 * ((angle_m * 0.005555555555555556) * (Math.PI * b))) * (Math.PI * (angle_m * b)));
                }
                
                angle_m = math.fabs(angle)
                def code(a, b, angle_m):
                	return math.pow(a, 2.0) + ((0.005555555555555556 * ((angle_m * 0.005555555555555556) * (math.pi * b))) * (math.pi * (angle_m * b)))
                
                angle_m = abs(angle)
                function code(a, b, angle_m)
                	return Float64((a ^ 2.0) + Float64(Float64(0.005555555555555556 * Float64(Float64(angle_m * 0.005555555555555556) * Float64(pi * b))) * Float64(pi * Float64(angle_m * b))))
                end
                
                angle_m = abs(angle);
                function tmp = code(a, b, angle_m)
                	tmp = (a ^ 2.0) + ((0.005555555555555556 * ((angle_m * 0.005555555555555556) * (pi * b))) * (pi * (angle_m * b)));
                end
                
                angle_m = N[Abs[angle], $MachinePrecision]
                code[a_, b_, angle$95$m_] := N[(N[Power[a, 2.0], $MachinePrecision] + N[(N[(0.005555555555555556 * N[(N[(angle$95$m * 0.005555555555555556), $MachinePrecision] * N[(Pi * b), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] * N[(Pi * N[(angle$95$m * b), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
                
                \begin{array}{l}
                angle_m = \left|angle\right|
                
                \\
                {a}^{2} + \left(0.005555555555555556 \cdot \left(\left(angle\_m \cdot 0.005555555555555556\right) \cdot \left(\pi \cdot b\right)\right)\right) \cdot \left(\pi \cdot \left(angle\_m \cdot b\right)\right)
                \end{array}
                
                Derivation
                1. Initial program 79.4%

                  \[{\left(a \cdot \cos \left(\pi \cdot \frac{angle}{180}\right)\right)}^{2} + {\left(b \cdot \sin \left(\pi \cdot \frac{angle}{180}\right)\right)}^{2} \]
                2. Step-by-step derivation
                  1. Simplified79.4%

                    \[\leadsto \color{blue}{{\left(a \cdot \cos \left(\pi \cdot \left(angle \cdot 0.005555555555555556\right)\right)\right)}^{2} + {\left(b \cdot \sin \left(\pi \cdot \left(angle \cdot 0.005555555555555556\right)\right)\right)}^{2}} \]
                  2. Add Preprocessing
                  3. Taylor expanded in angle around 0 79.1%

                    \[\leadsto {\left(a \cdot \color{blue}{1}\right)}^{2} + {\left(b \cdot \sin \left(\pi \cdot \left(angle \cdot 0.005555555555555556\right)\right)\right)}^{2} \]
                  4. Taylor expanded in angle around 0 74.7%

                    \[\leadsto {\left(a \cdot 1\right)}^{2} + {\left(b \cdot \color{blue}{\left(0.005555555555555556 \cdot \left(angle \cdot \pi\right)\right)}\right)}^{2} \]
                  5. Taylor expanded in b around 0 74.7%

                    \[\leadsto {\left(a \cdot 1\right)}^{2} + {\color{blue}{\left(0.005555555555555556 \cdot \left(angle \cdot \left(b \cdot \pi\right)\right)\right)}}^{2} \]
                  6. Step-by-step derivation
                    1. *-commutative74.7%

                      \[\leadsto {\left(a \cdot 1\right)}^{2} + {\left(0.005555555555555556 \cdot \left(angle \cdot \color{blue}{\left(\pi \cdot b\right)}\right)\right)}^{2} \]
                  7. Simplified74.7%

                    \[\leadsto {\left(a \cdot 1\right)}^{2} + {\color{blue}{\left(0.005555555555555556 \cdot \left(angle \cdot \left(\pi \cdot b\right)\right)\right)}}^{2} \]
                  8. Step-by-step derivation
                    1. unpow274.7%

                      \[\leadsto {\left(a \cdot 1\right)}^{2} + \color{blue}{\left(0.005555555555555556 \cdot \left(angle \cdot \left(\pi \cdot b\right)\right)\right) \cdot \left(0.005555555555555556 \cdot \left(angle \cdot \left(\pi \cdot b\right)\right)\right)} \]
                    2. associate-*r*74.7%

                      \[\leadsto {\left(a \cdot 1\right)}^{2} + \color{blue}{\left(\left(0.005555555555555556 \cdot \left(angle \cdot \left(\pi \cdot b\right)\right)\right) \cdot 0.005555555555555556\right) \cdot \left(angle \cdot \left(\pi \cdot b\right)\right)} \]
                    3. *-commutative74.7%

                      \[\leadsto {\left(a \cdot 1\right)}^{2} + \left(\color{blue}{\left(\left(angle \cdot \left(\pi \cdot b\right)\right) \cdot 0.005555555555555556\right)} \cdot 0.005555555555555556\right) \cdot \left(angle \cdot \left(\pi \cdot b\right)\right) \]
                    4. *-commutative74.7%

                      \[\leadsto {\left(a \cdot 1\right)}^{2} + \left(\left(\color{blue}{\left(\left(\pi \cdot b\right) \cdot angle\right)} \cdot 0.005555555555555556\right) \cdot 0.005555555555555556\right) \cdot \left(angle \cdot \left(\pi \cdot b\right)\right) \]
                    5. associate-*l*74.8%

                      \[\leadsto {\left(a \cdot 1\right)}^{2} + \left(\color{blue}{\left(\left(\pi \cdot b\right) \cdot \left(angle \cdot 0.005555555555555556\right)\right)} \cdot 0.005555555555555556\right) \cdot \left(angle \cdot \left(\pi \cdot b\right)\right) \]
                    6. *-commutative74.8%

                      \[\leadsto {\left(a \cdot 1\right)}^{2} + \left(\left(\left(\pi \cdot b\right) \cdot \left(angle \cdot 0.005555555555555556\right)\right) \cdot 0.005555555555555556\right) \cdot \color{blue}{\left(\left(\pi \cdot b\right) \cdot angle\right)} \]
                    7. associate-*l*74.8%

                      \[\leadsto {\left(a \cdot 1\right)}^{2} + \left(\left(\left(\pi \cdot b\right) \cdot \left(angle \cdot 0.005555555555555556\right)\right) \cdot 0.005555555555555556\right) \cdot \color{blue}{\left(\pi \cdot \left(b \cdot angle\right)\right)} \]
                  9. Applied egg-rr74.8%

                    \[\leadsto {\left(a \cdot 1\right)}^{2} + \color{blue}{\left(\left(\left(\pi \cdot b\right) \cdot \left(angle \cdot 0.005555555555555556\right)\right) \cdot 0.005555555555555556\right) \cdot \left(\pi \cdot \left(b \cdot angle\right)\right)} \]
                  10. Final simplification74.8%

                    \[\leadsto {a}^{2} + \left(0.005555555555555556 \cdot \left(\left(angle \cdot 0.005555555555555556\right) \cdot \left(\pi \cdot b\right)\right)\right) \cdot \left(\pi \cdot \left(angle \cdot b\right)\right) \]
                  11. Add Preprocessing

                  Alternative 9: 74.5% accurate, 3.5× speedup?

                  \[\begin{array}{l} angle_m = \left|angle\right| \\ \begin{array}{l} t_0 := \left(angle\_m \cdot 0.005555555555555556\right) \cdot \left(\pi \cdot b\right)\\ {a}^{2} + t\_0 \cdot t\_0 \end{array} \end{array} \]
                  angle_m = (fabs.f64 angle)
                  (FPCore (a b angle_m)
                   :precision binary64
                   (let* ((t_0 (* (* angle_m 0.005555555555555556) (* PI b))))
                     (+ (pow a 2.0) (* t_0 t_0))))
                  angle_m = fabs(angle);
                  double code(double a, double b, double angle_m) {
                  	double t_0 = (angle_m * 0.005555555555555556) * (((double) M_PI) * b);
                  	return pow(a, 2.0) + (t_0 * t_0);
                  }
                  
                  angle_m = Math.abs(angle);
                  public static double code(double a, double b, double angle_m) {
                  	double t_0 = (angle_m * 0.005555555555555556) * (Math.PI * b);
                  	return Math.pow(a, 2.0) + (t_0 * t_0);
                  }
                  
                  angle_m = math.fabs(angle)
                  def code(a, b, angle_m):
                  	t_0 = (angle_m * 0.005555555555555556) * (math.pi * b)
                  	return math.pow(a, 2.0) + (t_0 * t_0)
                  
                  angle_m = abs(angle)
                  function code(a, b, angle_m)
                  	t_0 = Float64(Float64(angle_m * 0.005555555555555556) * Float64(pi * b))
                  	return Float64((a ^ 2.0) + Float64(t_0 * t_0))
                  end
                  
                  angle_m = abs(angle);
                  function tmp = code(a, b, angle_m)
                  	t_0 = (angle_m * 0.005555555555555556) * (pi * b);
                  	tmp = (a ^ 2.0) + (t_0 * t_0);
                  end
                  
                  angle_m = N[Abs[angle], $MachinePrecision]
                  code[a_, b_, angle$95$m_] := Block[{t$95$0 = N[(N[(angle$95$m * 0.005555555555555556), $MachinePrecision] * N[(Pi * b), $MachinePrecision]), $MachinePrecision]}, N[(N[Power[a, 2.0], $MachinePrecision] + N[(t$95$0 * t$95$0), $MachinePrecision]), $MachinePrecision]]
                  
                  \begin{array}{l}
                  angle_m = \left|angle\right|
                  
                  \\
                  \begin{array}{l}
                  t_0 := \left(angle\_m \cdot 0.005555555555555556\right) \cdot \left(\pi \cdot b\right)\\
                  {a}^{2} + t\_0 \cdot t\_0
                  \end{array}
                  \end{array}
                  
                  Derivation
                  1. Initial program 79.4%

                    \[{\left(a \cdot \cos \left(\pi \cdot \frac{angle}{180}\right)\right)}^{2} + {\left(b \cdot \sin \left(\pi \cdot \frac{angle}{180}\right)\right)}^{2} \]
                  2. Step-by-step derivation
                    1. Simplified79.4%

                      \[\leadsto \color{blue}{{\left(a \cdot \cos \left(\pi \cdot \left(angle \cdot 0.005555555555555556\right)\right)\right)}^{2} + {\left(b \cdot \sin \left(\pi \cdot \left(angle \cdot 0.005555555555555556\right)\right)\right)}^{2}} \]
                    2. Add Preprocessing
                    3. Taylor expanded in angle around 0 79.1%

                      \[\leadsto {\left(a \cdot \color{blue}{1}\right)}^{2} + {\left(b \cdot \sin \left(\pi \cdot \left(angle \cdot 0.005555555555555556\right)\right)\right)}^{2} \]
                    4. Taylor expanded in angle around 0 74.7%

                      \[\leadsto {\left(a \cdot 1\right)}^{2} + {\left(b \cdot \color{blue}{\left(0.005555555555555556 \cdot \left(angle \cdot \pi\right)\right)}\right)}^{2} \]
                    5. Taylor expanded in b around 0 74.7%

                      \[\leadsto {\left(a \cdot 1\right)}^{2} + {\color{blue}{\left(0.005555555555555556 \cdot \left(angle \cdot \left(b \cdot \pi\right)\right)\right)}}^{2} \]
                    6. Step-by-step derivation
                      1. *-commutative74.7%

                        \[\leadsto {\left(a \cdot 1\right)}^{2} + {\left(0.005555555555555556 \cdot \left(angle \cdot \color{blue}{\left(\pi \cdot b\right)}\right)\right)}^{2} \]
                    7. Simplified74.7%

                      \[\leadsto {\left(a \cdot 1\right)}^{2} + {\color{blue}{\left(0.005555555555555556 \cdot \left(angle \cdot \left(\pi \cdot b\right)\right)\right)}}^{2} \]
                    8. Step-by-step derivation
                      1. unpow274.7%

                        \[\leadsto {\left(a \cdot 1\right)}^{2} + \color{blue}{\left(0.005555555555555556 \cdot \left(angle \cdot \left(\pi \cdot b\right)\right)\right) \cdot \left(0.005555555555555556 \cdot \left(angle \cdot \left(\pi \cdot b\right)\right)\right)} \]
                      2. *-commutative74.7%

                        \[\leadsto {\left(a \cdot 1\right)}^{2} + \color{blue}{\left(\left(angle \cdot \left(\pi \cdot b\right)\right) \cdot 0.005555555555555556\right)} \cdot \left(0.005555555555555556 \cdot \left(angle \cdot \left(\pi \cdot b\right)\right)\right) \]
                      3. *-commutative74.7%

                        \[\leadsto {\left(a \cdot 1\right)}^{2} + \left(\color{blue}{\left(\left(\pi \cdot b\right) \cdot angle\right)} \cdot 0.005555555555555556\right) \cdot \left(0.005555555555555556 \cdot \left(angle \cdot \left(\pi \cdot b\right)\right)\right) \]
                      4. associate-*l*74.7%

                        \[\leadsto {\left(a \cdot 1\right)}^{2} + \color{blue}{\left(\left(\pi \cdot b\right) \cdot \left(angle \cdot 0.005555555555555556\right)\right)} \cdot \left(0.005555555555555556 \cdot \left(angle \cdot \left(\pi \cdot b\right)\right)\right) \]
                      5. *-commutative74.7%

                        \[\leadsto {\left(a \cdot 1\right)}^{2} + \left(\left(\pi \cdot b\right) \cdot \left(angle \cdot 0.005555555555555556\right)\right) \cdot \color{blue}{\left(\left(angle \cdot \left(\pi \cdot b\right)\right) \cdot 0.005555555555555556\right)} \]
                      6. *-commutative74.7%

                        \[\leadsto {\left(a \cdot 1\right)}^{2} + \left(\left(\pi \cdot b\right) \cdot \left(angle \cdot 0.005555555555555556\right)\right) \cdot \left(\color{blue}{\left(\left(\pi \cdot b\right) \cdot angle\right)} \cdot 0.005555555555555556\right) \]
                      7. associate-*l*74.7%

                        \[\leadsto {\left(a \cdot 1\right)}^{2} + \left(\left(\pi \cdot b\right) \cdot \left(angle \cdot 0.005555555555555556\right)\right) \cdot \color{blue}{\left(\left(\pi \cdot b\right) \cdot \left(angle \cdot 0.005555555555555556\right)\right)} \]
                    9. Applied egg-rr74.7%

                      \[\leadsto {\left(a \cdot 1\right)}^{2} + \color{blue}{\left(\left(\pi \cdot b\right) \cdot \left(angle \cdot 0.005555555555555556\right)\right) \cdot \left(\left(\pi \cdot b\right) \cdot \left(angle \cdot 0.005555555555555556\right)\right)} \]
                    10. Final simplification74.7%

                      \[\leadsto {a}^{2} + \left(\left(angle \cdot 0.005555555555555556\right) \cdot \left(\pi \cdot b\right)\right) \cdot \left(\left(angle \cdot 0.005555555555555556\right) \cdot \left(\pi \cdot b\right)\right) \]
                    11. Add Preprocessing

                    Alternative 10: 72.9% accurate, 3.5× speedup?

                    \[\begin{array}{l} angle_m = \left|angle\right| \\ {a}^{2} + \left(angle\_m \cdot 0.005555555555555556\right) \cdot \left(\left(\pi \cdot b\right) \cdot \left(\left(angle\_m \cdot 0.005555555555555556\right) \cdot \left(\pi \cdot b\right)\right)\right) \end{array} \]
                    angle_m = (fabs.f64 angle)
                    (FPCore (a b angle_m)
                     :precision binary64
                     (+
                      (pow a 2.0)
                      (*
                       (* angle_m 0.005555555555555556)
                       (* (* PI b) (* (* angle_m 0.005555555555555556) (* PI b))))))
                    angle_m = fabs(angle);
                    double code(double a, double b, double angle_m) {
                    	return pow(a, 2.0) + ((angle_m * 0.005555555555555556) * ((((double) M_PI) * b) * ((angle_m * 0.005555555555555556) * (((double) M_PI) * b))));
                    }
                    
                    angle_m = Math.abs(angle);
                    public static double code(double a, double b, double angle_m) {
                    	return Math.pow(a, 2.0) + ((angle_m * 0.005555555555555556) * ((Math.PI * b) * ((angle_m * 0.005555555555555556) * (Math.PI * b))));
                    }
                    
                    angle_m = math.fabs(angle)
                    def code(a, b, angle_m):
                    	return math.pow(a, 2.0) + ((angle_m * 0.005555555555555556) * ((math.pi * b) * ((angle_m * 0.005555555555555556) * (math.pi * b))))
                    
                    angle_m = abs(angle)
                    function code(a, b, angle_m)
                    	return Float64((a ^ 2.0) + Float64(Float64(angle_m * 0.005555555555555556) * Float64(Float64(pi * b) * Float64(Float64(angle_m * 0.005555555555555556) * Float64(pi * b)))))
                    end
                    
                    angle_m = abs(angle);
                    function tmp = code(a, b, angle_m)
                    	tmp = (a ^ 2.0) + ((angle_m * 0.005555555555555556) * ((pi * b) * ((angle_m * 0.005555555555555556) * (pi * b))));
                    end
                    
                    angle_m = N[Abs[angle], $MachinePrecision]
                    code[a_, b_, angle$95$m_] := N[(N[Power[a, 2.0], $MachinePrecision] + N[(N[(angle$95$m * 0.005555555555555556), $MachinePrecision] * N[(N[(Pi * b), $MachinePrecision] * N[(N[(angle$95$m * 0.005555555555555556), $MachinePrecision] * N[(Pi * b), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
                    
                    \begin{array}{l}
                    angle_m = \left|angle\right|
                    
                    \\
                    {a}^{2} + \left(angle\_m \cdot 0.005555555555555556\right) \cdot \left(\left(\pi \cdot b\right) \cdot \left(\left(angle\_m \cdot 0.005555555555555556\right) \cdot \left(\pi \cdot b\right)\right)\right)
                    \end{array}
                    
                    Derivation
                    1. Initial program 79.4%

                      \[{\left(a \cdot \cos \left(\pi \cdot \frac{angle}{180}\right)\right)}^{2} + {\left(b \cdot \sin \left(\pi \cdot \frac{angle}{180}\right)\right)}^{2} \]
                    2. Step-by-step derivation
                      1. Simplified79.4%

                        \[\leadsto \color{blue}{{\left(a \cdot \cos \left(\pi \cdot \left(angle \cdot 0.005555555555555556\right)\right)\right)}^{2} + {\left(b \cdot \sin \left(\pi \cdot \left(angle \cdot 0.005555555555555556\right)\right)\right)}^{2}} \]
                      2. Add Preprocessing
                      3. Taylor expanded in angle around 0 79.1%

                        \[\leadsto {\left(a \cdot \color{blue}{1}\right)}^{2} + {\left(b \cdot \sin \left(\pi \cdot \left(angle \cdot 0.005555555555555556\right)\right)\right)}^{2} \]
                      4. Taylor expanded in angle around 0 74.7%

                        \[\leadsto {\left(a \cdot 1\right)}^{2} + {\left(b \cdot \color{blue}{\left(0.005555555555555556 \cdot \left(angle \cdot \pi\right)\right)}\right)}^{2} \]
                      5. Taylor expanded in b around 0 74.7%

                        \[\leadsto {\left(a \cdot 1\right)}^{2} + {\color{blue}{\left(0.005555555555555556 \cdot \left(angle \cdot \left(b \cdot \pi\right)\right)\right)}}^{2} \]
                      6. Step-by-step derivation
                        1. *-commutative74.7%

                          \[\leadsto {\left(a \cdot 1\right)}^{2} + {\left(0.005555555555555556 \cdot \left(angle \cdot \color{blue}{\left(\pi \cdot b\right)}\right)\right)}^{2} \]
                      7. Simplified74.7%

                        \[\leadsto {\left(a \cdot 1\right)}^{2} + {\color{blue}{\left(0.005555555555555556 \cdot \left(angle \cdot \left(\pi \cdot b\right)\right)\right)}}^{2} \]
                      8. Step-by-step derivation
                        1. unpow274.7%

                          \[\leadsto {\left(a \cdot 1\right)}^{2} + \color{blue}{\left(0.005555555555555556 \cdot \left(angle \cdot \left(\pi \cdot b\right)\right)\right) \cdot \left(0.005555555555555556 \cdot \left(angle \cdot \left(\pi \cdot b\right)\right)\right)} \]
                        2. associate-*r*74.7%

                          \[\leadsto {\left(a \cdot 1\right)}^{2} + \color{blue}{\left(\left(0.005555555555555556 \cdot angle\right) \cdot \left(\pi \cdot b\right)\right)} \cdot \left(0.005555555555555556 \cdot \left(angle \cdot \left(\pi \cdot b\right)\right)\right) \]
                        3. *-commutative74.7%

                          \[\leadsto {\left(a \cdot 1\right)}^{2} + \left(\color{blue}{\left(angle \cdot 0.005555555555555556\right)} \cdot \left(\pi \cdot b\right)\right) \cdot \left(0.005555555555555556 \cdot \left(angle \cdot \left(\pi \cdot b\right)\right)\right) \]
                        4. associate-*l*71.7%

                          \[\leadsto {\left(a \cdot 1\right)}^{2} + \color{blue}{\left(angle \cdot 0.005555555555555556\right) \cdot \left(\left(\pi \cdot b\right) \cdot \left(0.005555555555555556 \cdot \left(angle \cdot \left(\pi \cdot b\right)\right)\right)\right)} \]
                        5. *-commutative71.7%

                          \[\leadsto {\left(a \cdot 1\right)}^{2} + \left(angle \cdot 0.005555555555555556\right) \cdot \left(\left(\pi \cdot b\right) \cdot \color{blue}{\left(\left(angle \cdot \left(\pi \cdot b\right)\right) \cdot 0.005555555555555556\right)}\right) \]
                        6. *-commutative71.7%

                          \[\leadsto {\left(a \cdot 1\right)}^{2} + \left(angle \cdot 0.005555555555555556\right) \cdot \left(\left(\pi \cdot b\right) \cdot \left(\color{blue}{\left(\left(\pi \cdot b\right) \cdot angle\right)} \cdot 0.005555555555555556\right)\right) \]
                        7. associate-*l*71.7%

                          \[\leadsto {\left(a \cdot 1\right)}^{2} + \left(angle \cdot 0.005555555555555556\right) \cdot \left(\left(\pi \cdot b\right) \cdot \color{blue}{\left(\left(\pi \cdot b\right) \cdot \left(angle \cdot 0.005555555555555556\right)\right)}\right) \]
                      9. Applied egg-rr71.7%

                        \[\leadsto {\left(a \cdot 1\right)}^{2} + \color{blue}{\left(angle \cdot 0.005555555555555556\right) \cdot \left(\left(\pi \cdot b\right) \cdot \left(\left(\pi \cdot b\right) \cdot \left(angle \cdot 0.005555555555555556\right)\right)\right)} \]
                      10. Final simplification71.7%

                        \[\leadsto {a}^{2} + \left(angle \cdot 0.005555555555555556\right) \cdot \left(\left(\pi \cdot b\right) \cdot \left(\left(angle \cdot 0.005555555555555556\right) \cdot \left(\pi \cdot b\right)\right)\right) \]
                      11. Add Preprocessing

                      Reproduce

                      ?
                      herbie shell --seed 2024103 
                      (FPCore (a b angle)
                        :name "ab-angle->ABCF C"
                        :precision binary64
                        (+ (pow (* a (cos (* PI (/ angle 180.0)))) 2.0) (pow (* b (sin (* PI (/ angle 180.0)))) 2.0)))