VandenBroeck and Keller, Equation (24)

Percentage Accurate: 99.7% → 99.8%
Time: 9.3s
Alternatives: 11
Speedup: 1.0×

Specification

?
\[\begin{array}{l} \\ \left(-x \cdot \frac{1}{\tan B}\right) + \frac{1}{\sin B} \end{array} \]
(FPCore (B x)
 :precision binary64
 (+ (- (* x (/ 1.0 (tan B)))) (/ 1.0 (sin B))))
double code(double B, double x) {
	return -(x * (1.0 / tan(B))) + (1.0 / sin(B));
}
real(8) function code(b, x)
    real(8), intent (in) :: b
    real(8), intent (in) :: x
    code = -(x * (1.0d0 / tan(b))) + (1.0d0 / sin(b))
end function
public static double code(double B, double x) {
	return -(x * (1.0 / Math.tan(B))) + (1.0 / Math.sin(B));
}
def code(B, x):
	return -(x * (1.0 / math.tan(B))) + (1.0 / math.sin(B))
function code(B, x)
	return Float64(Float64(-Float64(x * Float64(1.0 / tan(B)))) + Float64(1.0 / sin(B)))
end
function tmp = code(B, x)
	tmp = -(x * (1.0 / tan(B))) + (1.0 / sin(B));
end
code[B_, x_] := N[((-N[(x * N[(1.0 / N[Tan[B], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]) + N[(1.0 / N[Sin[B], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
\left(-x \cdot \frac{1}{\tan B}\right) + \frac{1}{\sin B}
\end{array}

Sampling outcomes in binary64 precision:

Local Percentage Accuracy vs ?

The average percentage accuracy by input value. Horizontal axis shows value of an input variable; the variable is choosen in the title. Vertical axis is accuracy; higher is better. Red represent the original program, while blue represents Herbie's suggestion. These can be toggled with buttons below the plot. The line is an average while dots represent individual samples.

Accuracy vs Speed?

Herbie found 11 alternatives:

AlternativeAccuracySpeedup
The accuracy (vertical axis) and speed (horizontal axis) of each alternatives. Up and to the right is better. The red square shows the initial program, and each blue circle shows an alternative.The line shows the best available speed-accuracy tradeoffs.

Initial Program: 99.7% accurate, 1.0× speedup?

\[\begin{array}{l} \\ \left(-x \cdot \frac{1}{\tan B}\right) + \frac{1}{\sin B} \end{array} \]
(FPCore (B x)
 :precision binary64
 (+ (- (* x (/ 1.0 (tan B)))) (/ 1.0 (sin B))))
double code(double B, double x) {
	return -(x * (1.0 / tan(B))) + (1.0 / sin(B));
}
real(8) function code(b, x)
    real(8), intent (in) :: b
    real(8), intent (in) :: x
    code = -(x * (1.0d0 / tan(b))) + (1.0d0 / sin(b))
end function
public static double code(double B, double x) {
	return -(x * (1.0 / Math.tan(B))) + (1.0 / Math.sin(B));
}
def code(B, x):
	return -(x * (1.0 / math.tan(B))) + (1.0 / math.sin(B))
function code(B, x)
	return Float64(Float64(-Float64(x * Float64(1.0 / tan(B)))) + Float64(1.0 / sin(B)))
end
function tmp = code(B, x)
	tmp = -(x * (1.0 / tan(B))) + (1.0 / sin(B));
end
code[B_, x_] := N[((-N[(x * N[(1.0 / N[Tan[B], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]) + N[(1.0 / N[Sin[B], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
\left(-x \cdot \frac{1}{\tan B}\right) + \frac{1}{\sin B}
\end{array}

Alternative 1: 99.8% accurate, 1.0× speedup?

\[\begin{array}{l} \\ \frac{1}{\sin B} - \frac{x}{\tan B} \end{array} \]
(FPCore (B x) :precision binary64 (- (/ 1.0 (sin B)) (/ x (tan B))))
double code(double B, double x) {
	return (1.0 / sin(B)) - (x / tan(B));
}
real(8) function code(b, x)
    real(8), intent (in) :: b
    real(8), intent (in) :: x
    code = (1.0d0 / sin(b)) - (x / tan(b))
end function
public static double code(double B, double x) {
	return (1.0 / Math.sin(B)) - (x / Math.tan(B));
}
def code(B, x):
	return (1.0 / math.sin(B)) - (x / math.tan(B))
function code(B, x)
	return Float64(Float64(1.0 / sin(B)) - Float64(x / tan(B)))
end
function tmp = code(B, x)
	tmp = (1.0 / sin(B)) - (x / tan(B));
end
code[B_, x_] := N[(N[(1.0 / N[Sin[B], $MachinePrecision]), $MachinePrecision] - N[(x / N[Tan[B], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
\frac{1}{\sin B} - \frac{x}{\tan B}
\end{array}
Derivation
  1. Initial program 99.7%

    \[\left(-x \cdot \frac{1}{\tan B}\right) + \frac{1}{\sin B} \]
  2. Step-by-step derivation
    1. distribute-lft-neg-in99.7%

      \[\leadsto \color{blue}{\left(-x\right) \cdot \frac{1}{\tan B}} + \frac{1}{\sin B} \]
    2. +-commutative99.7%

      \[\leadsto \color{blue}{\frac{1}{\sin B} + \left(-x\right) \cdot \frac{1}{\tan B}} \]
    3. *-commutative99.7%

      \[\leadsto \frac{1}{\sin B} + \color{blue}{\frac{1}{\tan B} \cdot \left(-x\right)} \]
    4. remove-double-neg99.7%

      \[\leadsto \frac{1}{\sin B} + \color{blue}{\left(-\left(-\frac{1}{\tan B}\right)\right)} \cdot \left(-x\right) \]
    5. distribute-frac-neg299.7%

      \[\leadsto \frac{1}{\sin B} + \left(-\color{blue}{\frac{1}{-\tan B}}\right) \cdot \left(-x\right) \]
    6. tan-neg99.7%

      \[\leadsto \frac{1}{\sin B} + \left(-\frac{1}{\color{blue}{\tan \left(-B\right)}}\right) \cdot \left(-x\right) \]
    7. cancel-sign-sub-inv99.7%

      \[\leadsto \color{blue}{\frac{1}{\sin B} - \frac{1}{\tan \left(-B\right)} \cdot \left(-x\right)} \]
    8. *-commutative99.7%

      \[\leadsto \frac{1}{\sin B} - \color{blue}{\left(-x\right) \cdot \frac{1}{\tan \left(-B\right)}} \]
    9. associate-*r/99.8%

      \[\leadsto \frac{1}{\sin B} - \color{blue}{\frac{\left(-x\right) \cdot 1}{\tan \left(-B\right)}} \]
    10. *-rgt-identity99.8%

      \[\leadsto \frac{1}{\sin B} - \frac{\color{blue}{-x}}{\tan \left(-B\right)} \]
    11. tan-neg99.8%

      \[\leadsto \frac{1}{\sin B} - \frac{-x}{\color{blue}{-\tan B}} \]
    12. distribute-neg-frac299.8%

      \[\leadsto \frac{1}{\sin B} - \color{blue}{\left(-\frac{-x}{\tan B}\right)} \]
    13. distribute-neg-frac99.8%

      \[\leadsto \frac{1}{\sin B} - \color{blue}{\frac{-\left(-x\right)}{\tan B}} \]
    14. remove-double-neg99.8%

      \[\leadsto \frac{1}{\sin B} - \frac{\color{blue}{x}}{\tan B} \]
  3. Simplified99.8%

    \[\leadsto \color{blue}{\frac{1}{\sin B} - \frac{x}{\tan B}} \]
  4. Add Preprocessing
  5. Add Preprocessing

Alternative 2: 97.8% accurate, 1.0× speedup?

\[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;x \leq -3.4 \cdot 10^{+20} \lor \neg \left(x \leq 2600000\right):\\ \;\;\;\;\cos B \cdot \frac{x}{-\sin B}\\ \mathbf{else}:\\ \;\;\;\;\frac{1 - x}{\sin B}\\ \end{array} \end{array} \]
(FPCore (B x)
 :precision binary64
 (if (or (<= x -3.4e+20) (not (<= x 2600000.0)))
   (* (cos B) (/ x (- (sin B))))
   (/ (- 1.0 x) (sin B))))
double code(double B, double x) {
	double tmp;
	if ((x <= -3.4e+20) || !(x <= 2600000.0)) {
		tmp = cos(B) * (x / -sin(B));
	} else {
		tmp = (1.0 - x) / sin(B);
	}
	return tmp;
}
real(8) function code(b, x)
    real(8), intent (in) :: b
    real(8), intent (in) :: x
    real(8) :: tmp
    if ((x <= (-3.4d+20)) .or. (.not. (x <= 2600000.0d0))) then
        tmp = cos(b) * (x / -sin(b))
    else
        tmp = (1.0d0 - x) / sin(b)
    end if
    code = tmp
end function
public static double code(double B, double x) {
	double tmp;
	if ((x <= -3.4e+20) || !(x <= 2600000.0)) {
		tmp = Math.cos(B) * (x / -Math.sin(B));
	} else {
		tmp = (1.0 - x) / Math.sin(B);
	}
	return tmp;
}
def code(B, x):
	tmp = 0
	if (x <= -3.4e+20) or not (x <= 2600000.0):
		tmp = math.cos(B) * (x / -math.sin(B))
	else:
		tmp = (1.0 - x) / math.sin(B)
	return tmp
function code(B, x)
	tmp = 0.0
	if ((x <= -3.4e+20) || !(x <= 2600000.0))
		tmp = Float64(cos(B) * Float64(x / Float64(-sin(B))));
	else
		tmp = Float64(Float64(1.0 - x) / sin(B));
	end
	return tmp
end
function tmp_2 = code(B, x)
	tmp = 0.0;
	if ((x <= -3.4e+20) || ~((x <= 2600000.0)))
		tmp = cos(B) * (x / -sin(B));
	else
		tmp = (1.0 - x) / sin(B);
	end
	tmp_2 = tmp;
end
code[B_, x_] := If[Or[LessEqual[x, -3.4e+20], N[Not[LessEqual[x, 2600000.0]], $MachinePrecision]], N[(N[Cos[B], $MachinePrecision] * N[(x / (-N[Sin[B], $MachinePrecision])), $MachinePrecision]), $MachinePrecision], N[(N[(1.0 - x), $MachinePrecision] / N[Sin[B], $MachinePrecision]), $MachinePrecision]]
\begin{array}{l}

\\
\begin{array}{l}
\mathbf{if}\;x \leq -3.4 \cdot 10^{+20} \lor \neg \left(x \leq 2600000\right):\\
\;\;\;\;\cos B \cdot \frac{x}{-\sin B}\\

\mathbf{else}:\\
\;\;\;\;\frac{1 - x}{\sin B}\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if x < -3.4e20 or 2.6e6 < x

    1. Initial program 99.6%

      \[\left(-x \cdot \frac{1}{\tan B}\right) + \frac{1}{\sin B} \]
    2. Add Preprocessing
    3. Taylor expanded in B around inf 99.6%

      \[\leadsto \color{blue}{\frac{1}{\sin B} - \frac{x \cdot \cos B}{\sin B}} \]
    4. Step-by-step derivation
      1. sub-div99.7%

        \[\leadsto \color{blue}{\frac{1 - x \cdot \cos B}{\sin B}} \]
      2. div-inv99.6%

        \[\leadsto \color{blue}{\left(1 - x \cdot \cos B\right) \cdot \frac{1}{\sin B}} \]
    5. Applied egg-rr99.6%

      \[\leadsto \color{blue}{\left(1 - x \cdot \cos B\right) \cdot \frac{1}{\sin B}} \]
    6. Taylor expanded in x around inf 99.2%

      \[\leadsto \color{blue}{-1 \cdot \frac{x \cdot \cos B}{\sin B}} \]
    7. Step-by-step derivation
      1. mul-1-neg99.2%

        \[\leadsto \color{blue}{-\frac{x \cdot \cos B}{\sin B}} \]
      2. associate-*l/99.3%

        \[\leadsto -\color{blue}{\frac{x}{\sin B} \cdot \cos B} \]
      3. *-commutative99.3%

        \[\leadsto -\color{blue}{\cos B \cdot \frac{x}{\sin B}} \]
      4. distribute-rgt-neg-in99.3%

        \[\leadsto \color{blue}{\cos B \cdot \left(-\frac{x}{\sin B}\right)} \]
      5. distribute-neg-frac299.3%

        \[\leadsto \cos B \cdot \color{blue}{\frac{x}{-\sin B}} \]
    8. Simplified99.3%

      \[\leadsto \color{blue}{\cos B \cdot \frac{x}{-\sin B}} \]

    if -3.4e20 < x < 2.6e6

    1. Initial program 99.8%

      \[\left(-x \cdot \frac{1}{\tan B}\right) + \frac{1}{\sin B} \]
    2. Add Preprocessing
    3. Taylor expanded in B around inf 99.8%

      \[\leadsto \color{blue}{\frac{1}{\sin B} - \frac{x \cdot \cos B}{\sin B}} \]
    4. Taylor expanded in x around 0 99.8%

      \[\leadsto \color{blue}{-1 \cdot \frac{x \cdot \cos B}{\sin B} + \frac{1}{\sin B}} \]
    5. Step-by-step derivation
      1. +-commutative99.8%

        \[\leadsto \color{blue}{\frac{1}{\sin B} + -1 \cdot \frac{x \cdot \cos B}{\sin B}} \]
      2. mul-1-neg99.8%

        \[\leadsto \frac{1}{\sin B} + \color{blue}{\left(-\frac{x \cdot \cos B}{\sin B}\right)} \]
      3. sub-neg99.8%

        \[\leadsto \color{blue}{\frac{1}{\sin B} - \frac{x \cdot \cos B}{\sin B}} \]
      4. div-sub99.8%

        \[\leadsto \color{blue}{\frac{1 - x \cdot \cos B}{\sin B}} \]
    6. Simplified99.8%

      \[\leadsto \color{blue}{\frac{1 - x \cdot \cos B}{\sin B}} \]
    7. Taylor expanded in B around 0 97.9%

      \[\leadsto \frac{1 - \color{blue}{x}}{\sin B} \]
  3. Recombined 2 regimes into one program.
  4. Final simplification98.5%

    \[\leadsto \begin{array}{l} \mathbf{if}\;x \leq -3.4 \cdot 10^{+20} \lor \neg \left(x \leq 2600000\right):\\ \;\;\;\;\cos B \cdot \frac{x}{-\sin B}\\ \mathbf{else}:\\ \;\;\;\;\frac{1 - x}{\sin B}\\ \end{array} \]
  5. Add Preprocessing

Alternative 3: 97.7% accurate, 1.0× speedup?

\[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;x \leq -3.4 \cdot 10^{+20} \lor \neg \left(x \leq 850000\right):\\ \;\;\;\;x \cdot \frac{\cos B}{-\sin B}\\ \mathbf{else}:\\ \;\;\;\;\frac{1 - x}{\sin B}\\ \end{array} \end{array} \]
(FPCore (B x)
 :precision binary64
 (if (or (<= x -3.4e+20) (not (<= x 850000.0)))
   (* x (/ (cos B) (- (sin B))))
   (/ (- 1.0 x) (sin B))))
double code(double B, double x) {
	double tmp;
	if ((x <= -3.4e+20) || !(x <= 850000.0)) {
		tmp = x * (cos(B) / -sin(B));
	} else {
		tmp = (1.0 - x) / sin(B);
	}
	return tmp;
}
real(8) function code(b, x)
    real(8), intent (in) :: b
    real(8), intent (in) :: x
    real(8) :: tmp
    if ((x <= (-3.4d+20)) .or. (.not. (x <= 850000.0d0))) then
        tmp = x * (cos(b) / -sin(b))
    else
        tmp = (1.0d0 - x) / sin(b)
    end if
    code = tmp
end function
public static double code(double B, double x) {
	double tmp;
	if ((x <= -3.4e+20) || !(x <= 850000.0)) {
		tmp = x * (Math.cos(B) / -Math.sin(B));
	} else {
		tmp = (1.0 - x) / Math.sin(B);
	}
	return tmp;
}
def code(B, x):
	tmp = 0
	if (x <= -3.4e+20) or not (x <= 850000.0):
		tmp = x * (math.cos(B) / -math.sin(B))
	else:
		tmp = (1.0 - x) / math.sin(B)
	return tmp
function code(B, x)
	tmp = 0.0
	if ((x <= -3.4e+20) || !(x <= 850000.0))
		tmp = Float64(x * Float64(cos(B) / Float64(-sin(B))));
	else
		tmp = Float64(Float64(1.0 - x) / sin(B));
	end
	return tmp
end
function tmp_2 = code(B, x)
	tmp = 0.0;
	if ((x <= -3.4e+20) || ~((x <= 850000.0)))
		tmp = x * (cos(B) / -sin(B));
	else
		tmp = (1.0 - x) / sin(B);
	end
	tmp_2 = tmp;
end
code[B_, x_] := If[Or[LessEqual[x, -3.4e+20], N[Not[LessEqual[x, 850000.0]], $MachinePrecision]], N[(x * N[(N[Cos[B], $MachinePrecision] / (-N[Sin[B], $MachinePrecision])), $MachinePrecision]), $MachinePrecision], N[(N[(1.0 - x), $MachinePrecision] / N[Sin[B], $MachinePrecision]), $MachinePrecision]]
\begin{array}{l}

\\
\begin{array}{l}
\mathbf{if}\;x \leq -3.4 \cdot 10^{+20} \lor \neg \left(x \leq 850000\right):\\
\;\;\;\;x \cdot \frac{\cos B}{-\sin B}\\

\mathbf{else}:\\
\;\;\;\;\frac{1 - x}{\sin B}\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if x < -3.4e20 or 8.5e5 < x

    1. Initial program 99.6%

      \[\left(-x \cdot \frac{1}{\tan B}\right) + \frac{1}{\sin B} \]
    2. Add Preprocessing
    3. Taylor expanded in x around inf 99.2%

      \[\leadsto \color{blue}{-1 \cdot \frac{x \cdot \cos B}{\sin B}} \]
    4. Step-by-step derivation
      1. mul-1-neg99.2%

        \[\leadsto \color{blue}{-\frac{x \cdot \cos B}{\sin B}} \]
      2. associate-/l*99.1%

        \[\leadsto -\color{blue}{x \cdot \frac{\cos B}{\sin B}} \]
      3. distribute-rgt-neg-in99.1%

        \[\leadsto \color{blue}{x \cdot \left(-\frac{\cos B}{\sin B}\right)} \]
      4. distribute-neg-frac99.1%

        \[\leadsto x \cdot \color{blue}{\frac{-\cos B}{\sin B}} \]
    5. Simplified99.1%

      \[\leadsto \color{blue}{x \cdot \frac{-\cos B}{\sin B}} \]

    if -3.4e20 < x < 8.5e5

    1. Initial program 99.8%

      \[\left(-x \cdot \frac{1}{\tan B}\right) + \frac{1}{\sin B} \]
    2. Add Preprocessing
    3. Taylor expanded in B around inf 99.8%

      \[\leadsto \color{blue}{\frac{1}{\sin B} - \frac{x \cdot \cos B}{\sin B}} \]
    4. Taylor expanded in x around 0 99.8%

      \[\leadsto \color{blue}{-1 \cdot \frac{x \cdot \cos B}{\sin B} + \frac{1}{\sin B}} \]
    5. Step-by-step derivation
      1. +-commutative99.8%

        \[\leadsto \color{blue}{\frac{1}{\sin B} + -1 \cdot \frac{x \cdot \cos B}{\sin B}} \]
      2. mul-1-neg99.8%

        \[\leadsto \frac{1}{\sin B} + \color{blue}{\left(-\frac{x \cdot \cos B}{\sin B}\right)} \]
      3. sub-neg99.8%

        \[\leadsto \color{blue}{\frac{1}{\sin B} - \frac{x \cdot \cos B}{\sin B}} \]
      4. div-sub99.8%

        \[\leadsto \color{blue}{\frac{1 - x \cdot \cos B}{\sin B}} \]
    6. Simplified99.8%

      \[\leadsto \color{blue}{\frac{1 - x \cdot \cos B}{\sin B}} \]
    7. Taylor expanded in B around 0 97.9%

      \[\leadsto \frac{1 - \color{blue}{x}}{\sin B} \]
  3. Recombined 2 regimes into one program.
  4. Final simplification98.4%

    \[\leadsto \begin{array}{l} \mathbf{if}\;x \leq -3.4 \cdot 10^{+20} \lor \neg \left(x \leq 850000\right):\\ \;\;\;\;x \cdot \frac{\cos B}{-\sin B}\\ \mathbf{else}:\\ \;\;\;\;\frac{1 - x}{\sin B}\\ \end{array} \]
  5. Add Preprocessing

Alternative 4: 75.0% accurate, 1.8× speedup?

\[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;x \leq -21.5 \lor \neg \left(x \leq 12500000\right):\\ \;\;\;\;\frac{x}{-\sin B}\\ \mathbf{else}:\\ \;\;\;\;\frac{1 + x}{\sin B}\\ \end{array} \end{array} \]
(FPCore (B x)
 :precision binary64
 (if (or (<= x -21.5) (not (<= x 12500000.0)))
   (/ x (- (sin B)))
   (/ (+ 1.0 x) (sin B))))
double code(double B, double x) {
	double tmp;
	if ((x <= -21.5) || !(x <= 12500000.0)) {
		tmp = x / -sin(B);
	} else {
		tmp = (1.0 + x) / sin(B);
	}
	return tmp;
}
real(8) function code(b, x)
    real(8), intent (in) :: b
    real(8), intent (in) :: x
    real(8) :: tmp
    if ((x <= (-21.5d0)) .or. (.not. (x <= 12500000.0d0))) then
        tmp = x / -sin(b)
    else
        tmp = (1.0d0 + x) / sin(b)
    end if
    code = tmp
end function
public static double code(double B, double x) {
	double tmp;
	if ((x <= -21.5) || !(x <= 12500000.0)) {
		tmp = x / -Math.sin(B);
	} else {
		tmp = (1.0 + x) / Math.sin(B);
	}
	return tmp;
}
def code(B, x):
	tmp = 0
	if (x <= -21.5) or not (x <= 12500000.0):
		tmp = x / -math.sin(B)
	else:
		tmp = (1.0 + x) / math.sin(B)
	return tmp
function code(B, x)
	tmp = 0.0
	if ((x <= -21.5) || !(x <= 12500000.0))
		tmp = Float64(x / Float64(-sin(B)));
	else
		tmp = Float64(Float64(1.0 + x) / sin(B));
	end
	return tmp
end
function tmp_2 = code(B, x)
	tmp = 0.0;
	if ((x <= -21.5) || ~((x <= 12500000.0)))
		tmp = x / -sin(B);
	else
		tmp = (1.0 + x) / sin(B);
	end
	tmp_2 = tmp;
end
code[B_, x_] := If[Or[LessEqual[x, -21.5], N[Not[LessEqual[x, 12500000.0]], $MachinePrecision]], N[(x / (-N[Sin[B], $MachinePrecision])), $MachinePrecision], N[(N[(1.0 + x), $MachinePrecision] / N[Sin[B], $MachinePrecision]), $MachinePrecision]]
\begin{array}{l}

\\
\begin{array}{l}
\mathbf{if}\;x \leq -21.5 \lor \neg \left(x \leq 12500000\right):\\
\;\;\;\;\frac{x}{-\sin B}\\

\mathbf{else}:\\
\;\;\;\;\frac{1 + x}{\sin B}\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if x < -21.5 or 1.25e7 < x

    1. Initial program 99.6%

      \[\left(-x \cdot \frac{1}{\tan B}\right) + \frac{1}{\sin B} \]
    2. Add Preprocessing
    3. Taylor expanded in B around inf 99.7%

      \[\leadsto \color{blue}{\frac{1}{\sin B} - \frac{x \cdot \cos B}{\sin B}} \]
    4. Taylor expanded in x around 0 99.7%

      \[\leadsto \color{blue}{-1 \cdot \frac{x \cdot \cos B}{\sin B} + \frac{1}{\sin B}} \]
    5. Step-by-step derivation
      1. +-commutative99.7%

        \[\leadsto \color{blue}{\frac{1}{\sin B} + -1 \cdot \frac{x \cdot \cos B}{\sin B}} \]
      2. mul-1-neg99.7%

        \[\leadsto \frac{1}{\sin B} + \color{blue}{\left(-\frac{x \cdot \cos B}{\sin B}\right)} \]
      3. sub-neg99.7%

        \[\leadsto \color{blue}{\frac{1}{\sin B} - \frac{x \cdot \cos B}{\sin B}} \]
      4. div-sub99.7%

        \[\leadsto \color{blue}{\frac{1 - x \cdot \cos B}{\sin B}} \]
    6. Simplified99.7%

      \[\leadsto \color{blue}{\frac{1 - x \cdot \cos B}{\sin B}} \]
    7. Taylor expanded in x around inf 99.2%

      \[\leadsto \color{blue}{-1 \cdot \frac{x \cdot \cos B}{\sin B}} \]
    8. Step-by-step derivation
      1. associate-*r/99.2%

        \[\leadsto \color{blue}{\frac{-1 \cdot \left(x \cdot \cos B\right)}{\sin B}} \]
      2. associate-*r*99.2%

        \[\leadsto \frac{\color{blue}{\left(-1 \cdot x\right) \cdot \cos B}}{\sin B} \]
      3. neg-mul-199.2%

        \[\leadsto \frac{\color{blue}{\left(-x\right)} \cdot \cos B}{\sin B} \]
    9. Simplified99.2%

      \[\leadsto \color{blue}{\frac{\left(-x\right) \cdot \cos B}{\sin B}} \]
    10. Taylor expanded in B around 0 52.1%

      \[\leadsto \frac{\color{blue}{-1 \cdot x}}{\sin B} \]
    11. Step-by-step derivation
      1. mul-1-neg52.1%

        \[\leadsto \frac{\color{blue}{-x}}{\sin B} \]
    12. Simplified52.1%

      \[\leadsto \frac{\color{blue}{-x}}{\sin B} \]

    if -21.5 < x < 1.25e7

    1. Initial program 99.8%

      \[\left(-x \cdot \frac{1}{\tan B}\right) + \frac{1}{\sin B} \]
    2. Add Preprocessing
    3. Taylor expanded in B around inf 99.8%

      \[\leadsto \color{blue}{\frac{1}{\sin B} - \frac{x \cdot \cos B}{\sin B}} \]
    4. Taylor expanded in x around 0 99.8%

      \[\leadsto \color{blue}{-1 \cdot \frac{x \cdot \cos B}{\sin B} + \frac{1}{\sin B}} \]
    5. Step-by-step derivation
      1. +-commutative99.8%

        \[\leadsto \color{blue}{\frac{1}{\sin B} + -1 \cdot \frac{x \cdot \cos B}{\sin B}} \]
      2. mul-1-neg99.8%

        \[\leadsto \frac{1}{\sin B} + \color{blue}{\left(-\frac{x \cdot \cos B}{\sin B}\right)} \]
      3. sub-neg99.8%

        \[\leadsto \color{blue}{\frac{1}{\sin B} - \frac{x \cdot \cos B}{\sin B}} \]
      4. div-sub99.8%

        \[\leadsto \color{blue}{\frac{1 - x \cdot \cos B}{\sin B}} \]
    6. Simplified99.8%

      \[\leadsto \color{blue}{\frac{1 - x \cdot \cos B}{\sin B}} \]
    7. Taylor expanded in B around 0 97.1%

      \[\leadsto \frac{1 - \color{blue}{x}}{\sin B} \]
    8. Step-by-step derivation
      1. *-un-lft-identity97.1%

        \[\leadsto \color{blue}{1 \cdot \frac{1 - x}{\sin B}} \]
      2. *-un-lft-identity97.1%

        \[\leadsto 1 \cdot \frac{\color{blue}{1 \cdot \left(1 - x\right)}}{\sin B} \]
      3. *-un-lft-identity97.1%

        \[\leadsto 1 \cdot \frac{\color{blue}{1 - x}}{\sin B} \]
      4. sub-neg97.1%

        \[\leadsto 1 \cdot \frac{\color{blue}{1 + \left(-x\right)}}{\sin B} \]
      5. add-sqr-sqrt48.6%

        \[\leadsto 1 \cdot \frac{1 + \color{blue}{\sqrt{-x} \cdot \sqrt{-x}}}{\sin B} \]
      6. sqrt-unprod96.9%

        \[\leadsto 1 \cdot \frac{1 + \color{blue}{\sqrt{\left(-x\right) \cdot \left(-x\right)}}}{\sin B} \]
      7. sqr-neg96.9%

        \[\leadsto 1 \cdot \frac{1 + \sqrt{\color{blue}{x \cdot x}}}{\sin B} \]
      8. sqrt-unprod48.3%

        \[\leadsto 1 \cdot \frac{1 + \color{blue}{\sqrt{x} \cdot \sqrt{x}}}{\sin B} \]
      9. add-sqr-sqrt96.3%

        \[\leadsto 1 \cdot \frac{1 + \color{blue}{x}}{\sin B} \]
    9. Applied egg-rr96.3%

      \[\leadsto \color{blue}{1 \cdot \frac{1 + x}{\sin B}} \]
    10. Step-by-step derivation
      1. *-lft-identity96.3%

        \[\leadsto \color{blue}{\frac{1 + x}{\sin B}} \]
    11. Simplified96.3%

      \[\leadsto \color{blue}{\frac{1 + x}{\sin B}} \]
  3. Recombined 2 regimes into one program.
  4. Final simplification75.9%

    \[\leadsto \begin{array}{l} \mathbf{if}\;x \leq -21.5 \lor \neg \left(x \leq 12500000\right):\\ \;\;\;\;\frac{x}{-\sin B}\\ \mathbf{else}:\\ \;\;\;\;\frac{1 + x}{\sin B}\\ \end{array} \]
  5. Add Preprocessing

Alternative 5: 75.0% accurate, 1.8× speedup?

\[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;x \leq -1 \lor \neg \left(x \leq 12500000\right):\\ \;\;\;\;\frac{x}{-\sin B}\\ \mathbf{else}:\\ \;\;\;\;\frac{1}{\sin B}\\ \end{array} \end{array} \]
(FPCore (B x)
 :precision binary64
 (if (or (<= x -1.0) (not (<= x 12500000.0)))
   (/ x (- (sin B)))
   (/ 1.0 (sin B))))
double code(double B, double x) {
	double tmp;
	if ((x <= -1.0) || !(x <= 12500000.0)) {
		tmp = x / -sin(B);
	} else {
		tmp = 1.0 / sin(B);
	}
	return tmp;
}
real(8) function code(b, x)
    real(8), intent (in) :: b
    real(8), intent (in) :: x
    real(8) :: tmp
    if ((x <= (-1.0d0)) .or. (.not. (x <= 12500000.0d0))) then
        tmp = x / -sin(b)
    else
        tmp = 1.0d0 / sin(b)
    end if
    code = tmp
end function
public static double code(double B, double x) {
	double tmp;
	if ((x <= -1.0) || !(x <= 12500000.0)) {
		tmp = x / -Math.sin(B);
	} else {
		tmp = 1.0 / Math.sin(B);
	}
	return tmp;
}
def code(B, x):
	tmp = 0
	if (x <= -1.0) or not (x <= 12500000.0):
		tmp = x / -math.sin(B)
	else:
		tmp = 1.0 / math.sin(B)
	return tmp
function code(B, x)
	tmp = 0.0
	if ((x <= -1.0) || !(x <= 12500000.0))
		tmp = Float64(x / Float64(-sin(B)));
	else
		tmp = Float64(1.0 / sin(B));
	end
	return tmp
end
function tmp_2 = code(B, x)
	tmp = 0.0;
	if ((x <= -1.0) || ~((x <= 12500000.0)))
		tmp = x / -sin(B);
	else
		tmp = 1.0 / sin(B);
	end
	tmp_2 = tmp;
end
code[B_, x_] := If[Or[LessEqual[x, -1.0], N[Not[LessEqual[x, 12500000.0]], $MachinePrecision]], N[(x / (-N[Sin[B], $MachinePrecision])), $MachinePrecision], N[(1.0 / N[Sin[B], $MachinePrecision]), $MachinePrecision]]
\begin{array}{l}

\\
\begin{array}{l}
\mathbf{if}\;x \leq -1 \lor \neg \left(x \leq 12500000\right):\\
\;\;\;\;\frac{x}{-\sin B}\\

\mathbf{else}:\\
\;\;\;\;\frac{1}{\sin B}\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if x < -1 or 1.25e7 < x

    1. Initial program 99.6%

      \[\left(-x \cdot \frac{1}{\tan B}\right) + \frac{1}{\sin B} \]
    2. Add Preprocessing
    3. Taylor expanded in B around inf 99.7%

      \[\leadsto \color{blue}{\frac{1}{\sin B} - \frac{x \cdot \cos B}{\sin B}} \]
    4. Taylor expanded in x around 0 99.7%

      \[\leadsto \color{blue}{-1 \cdot \frac{x \cdot \cos B}{\sin B} + \frac{1}{\sin B}} \]
    5. Step-by-step derivation
      1. +-commutative99.7%

        \[\leadsto \color{blue}{\frac{1}{\sin B} + -1 \cdot \frac{x \cdot \cos B}{\sin B}} \]
      2. mul-1-neg99.7%

        \[\leadsto \frac{1}{\sin B} + \color{blue}{\left(-\frac{x \cdot \cos B}{\sin B}\right)} \]
      3. sub-neg99.7%

        \[\leadsto \color{blue}{\frac{1}{\sin B} - \frac{x \cdot \cos B}{\sin B}} \]
      4. div-sub99.7%

        \[\leadsto \color{blue}{\frac{1 - x \cdot \cos B}{\sin B}} \]
    6. Simplified99.7%

      \[\leadsto \color{blue}{\frac{1 - x \cdot \cos B}{\sin B}} \]
    7. Taylor expanded in x around inf 99.2%

      \[\leadsto \color{blue}{-1 \cdot \frac{x \cdot \cos B}{\sin B}} \]
    8. Step-by-step derivation
      1. associate-*r/99.2%

        \[\leadsto \color{blue}{\frac{-1 \cdot \left(x \cdot \cos B\right)}{\sin B}} \]
      2. associate-*r*99.2%

        \[\leadsto \frac{\color{blue}{\left(-1 \cdot x\right) \cdot \cos B}}{\sin B} \]
      3. neg-mul-199.2%

        \[\leadsto \frac{\color{blue}{\left(-x\right)} \cdot \cos B}{\sin B} \]
    9. Simplified99.2%

      \[\leadsto \color{blue}{\frac{\left(-x\right) \cdot \cos B}{\sin B}} \]
    10. Taylor expanded in B around 0 52.1%

      \[\leadsto \frac{\color{blue}{-1 \cdot x}}{\sin B} \]
    11. Step-by-step derivation
      1. mul-1-neg52.1%

        \[\leadsto \frac{\color{blue}{-x}}{\sin B} \]
    12. Simplified52.1%

      \[\leadsto \frac{\color{blue}{-x}}{\sin B} \]

    if -1 < x < 1.25e7

    1. Initial program 99.8%

      \[\left(-x \cdot \frac{1}{\tan B}\right) + \frac{1}{\sin B} \]
    2. Add Preprocessing
    3. Taylor expanded in x around 0 96.2%

      \[\leadsto \color{blue}{\frac{1}{\sin B}} \]
  3. Recombined 2 regimes into one program.
  4. Final simplification75.8%

    \[\leadsto \begin{array}{l} \mathbf{if}\;x \leq -1 \lor \neg \left(x \leq 12500000\right):\\ \;\;\;\;\frac{x}{-\sin B}\\ \mathbf{else}:\\ \;\;\;\;\frac{1}{\sin B}\\ \end{array} \]
  5. Add Preprocessing

Alternative 6: 62.2% accurate, 1.9× speedup?

\[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;B \leq 2600:\\ \;\;\;\;B \cdot 0.16666666666666666 + \left(\frac{1}{B} + x \cdot \left(B \cdot 0.3333333333333333 - \frac{1}{B}\right)\right)\\ \mathbf{else}:\\ \;\;\;\;\frac{1}{\sin B}\\ \end{array} \end{array} \]
(FPCore (B x)
 :precision binary64
 (if (<= B 2600.0)
   (+
    (* B 0.16666666666666666)
    (+ (/ 1.0 B) (* x (- (* B 0.3333333333333333) (/ 1.0 B)))))
   (/ 1.0 (sin B))))
double code(double B, double x) {
	double tmp;
	if (B <= 2600.0) {
		tmp = (B * 0.16666666666666666) + ((1.0 / B) + (x * ((B * 0.3333333333333333) - (1.0 / B))));
	} else {
		tmp = 1.0 / sin(B);
	}
	return tmp;
}
real(8) function code(b, x)
    real(8), intent (in) :: b
    real(8), intent (in) :: x
    real(8) :: tmp
    if (b <= 2600.0d0) then
        tmp = (b * 0.16666666666666666d0) + ((1.0d0 / b) + (x * ((b * 0.3333333333333333d0) - (1.0d0 / b))))
    else
        tmp = 1.0d0 / sin(b)
    end if
    code = tmp
end function
public static double code(double B, double x) {
	double tmp;
	if (B <= 2600.0) {
		tmp = (B * 0.16666666666666666) + ((1.0 / B) + (x * ((B * 0.3333333333333333) - (1.0 / B))));
	} else {
		tmp = 1.0 / Math.sin(B);
	}
	return tmp;
}
def code(B, x):
	tmp = 0
	if B <= 2600.0:
		tmp = (B * 0.16666666666666666) + ((1.0 / B) + (x * ((B * 0.3333333333333333) - (1.0 / B))))
	else:
		tmp = 1.0 / math.sin(B)
	return tmp
function code(B, x)
	tmp = 0.0
	if (B <= 2600.0)
		tmp = Float64(Float64(B * 0.16666666666666666) + Float64(Float64(1.0 / B) + Float64(x * Float64(Float64(B * 0.3333333333333333) - Float64(1.0 / B)))));
	else
		tmp = Float64(1.0 / sin(B));
	end
	return tmp
end
function tmp_2 = code(B, x)
	tmp = 0.0;
	if (B <= 2600.0)
		tmp = (B * 0.16666666666666666) + ((1.0 / B) + (x * ((B * 0.3333333333333333) - (1.0 / B))));
	else
		tmp = 1.0 / sin(B);
	end
	tmp_2 = tmp;
end
code[B_, x_] := If[LessEqual[B, 2600.0], N[(N[(B * 0.16666666666666666), $MachinePrecision] + N[(N[(1.0 / B), $MachinePrecision] + N[(x * N[(N[(B * 0.3333333333333333), $MachinePrecision] - N[(1.0 / B), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], N[(1.0 / N[Sin[B], $MachinePrecision]), $MachinePrecision]]
\begin{array}{l}

\\
\begin{array}{l}
\mathbf{if}\;B \leq 2600:\\
\;\;\;\;B \cdot 0.16666666666666666 + \left(\frac{1}{B} + x \cdot \left(B \cdot 0.3333333333333333 - \frac{1}{B}\right)\right)\\

\mathbf{else}:\\
\;\;\;\;\frac{1}{\sin B}\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if B < 2600

    1. Initial program 99.8%

      \[\left(-x \cdot \frac{1}{\tan B}\right) + \frac{1}{\sin B} \]
    2. Add Preprocessing
    3. Taylor expanded in B around 0 63.8%

      \[\leadsto \color{blue}{\frac{\left(1 + {B}^{2} \cdot \left(0.16666666666666666 + 0.3333333333333333 \cdot x\right)\right) - x}{B}} \]
    4. Taylor expanded in x around 0 63.9%

      \[\leadsto \color{blue}{0.16666666666666666 \cdot B + \left(x \cdot \left(0.3333333333333333 \cdot B - \frac{1}{B}\right) + \frac{1}{B}\right)} \]

    if 2600 < B

    1. Initial program 99.4%

      \[\left(-x \cdot \frac{1}{\tan B}\right) + \frac{1}{\sin B} \]
    2. Add Preprocessing
    3. Taylor expanded in x around 0 48.8%

      \[\leadsto \color{blue}{\frac{1}{\sin B}} \]
  3. Recombined 2 regimes into one program.
  4. Final simplification60.0%

    \[\leadsto \begin{array}{l} \mathbf{if}\;B \leq 2600:\\ \;\;\;\;B \cdot 0.16666666666666666 + \left(\frac{1}{B} + x \cdot \left(B \cdot 0.3333333333333333 - \frac{1}{B}\right)\right)\\ \mathbf{else}:\\ \;\;\;\;\frac{1}{\sin B}\\ \end{array} \]
  5. Add Preprocessing

Alternative 7: 76.3% accurate, 2.0× speedup?

\[\begin{array}{l} \\ \frac{1 - x}{\sin B} \end{array} \]
(FPCore (B x) :precision binary64 (/ (- 1.0 x) (sin B)))
double code(double B, double x) {
	return (1.0 - x) / sin(B);
}
real(8) function code(b, x)
    real(8), intent (in) :: b
    real(8), intent (in) :: x
    code = (1.0d0 - x) / sin(b)
end function
public static double code(double B, double x) {
	return (1.0 - x) / Math.sin(B);
}
def code(B, x):
	return (1.0 - x) / math.sin(B)
function code(B, x)
	return Float64(Float64(1.0 - x) / sin(B))
end
function tmp = code(B, x)
	tmp = (1.0 - x) / sin(B);
end
code[B_, x_] := N[(N[(1.0 - x), $MachinePrecision] / N[Sin[B], $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
\frac{1 - x}{\sin B}
\end{array}
Derivation
  1. Initial program 99.7%

    \[\left(-x \cdot \frac{1}{\tan B}\right) + \frac{1}{\sin B} \]
  2. Add Preprocessing
  3. Taylor expanded in B around inf 99.7%

    \[\leadsto \color{blue}{\frac{1}{\sin B} - \frac{x \cdot \cos B}{\sin B}} \]
  4. Taylor expanded in x around 0 99.7%

    \[\leadsto \color{blue}{-1 \cdot \frac{x \cdot \cos B}{\sin B} + \frac{1}{\sin B}} \]
  5. Step-by-step derivation
    1. +-commutative99.7%

      \[\leadsto \color{blue}{\frac{1}{\sin B} + -1 \cdot \frac{x \cdot \cos B}{\sin B}} \]
    2. mul-1-neg99.7%

      \[\leadsto \frac{1}{\sin B} + \color{blue}{\left(-\frac{x \cdot \cos B}{\sin B}\right)} \]
    3. sub-neg99.7%

      \[\leadsto \color{blue}{\frac{1}{\sin B} - \frac{x \cdot \cos B}{\sin B}} \]
    4. div-sub99.7%

      \[\leadsto \color{blue}{\frac{1 - x \cdot \cos B}{\sin B}} \]
  6. Simplified99.7%

    \[\leadsto \color{blue}{\frac{1 - x \cdot \cos B}{\sin B}} \]
  7. Taylor expanded in B around 0 76.6%

    \[\leadsto \frac{1 - \color{blue}{x}}{\sin B} \]
  8. Add Preprocessing

Alternative 8: 49.3% accurate, 14.9× speedup?

\[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;x \leq -0.06 \lor \neg \left(x \leq 1\right):\\ \;\;\;\;\frac{x}{-B}\\ \mathbf{else}:\\ \;\;\;\;\frac{1}{B}\\ \end{array} \end{array} \]
(FPCore (B x)
 :precision binary64
 (if (or (<= x -0.06) (not (<= x 1.0))) (/ x (- B)) (/ 1.0 B)))
double code(double B, double x) {
	double tmp;
	if ((x <= -0.06) || !(x <= 1.0)) {
		tmp = x / -B;
	} else {
		tmp = 1.0 / B;
	}
	return tmp;
}
real(8) function code(b, x)
    real(8), intent (in) :: b
    real(8), intent (in) :: x
    real(8) :: tmp
    if ((x <= (-0.06d0)) .or. (.not. (x <= 1.0d0))) then
        tmp = x / -b
    else
        tmp = 1.0d0 / b
    end if
    code = tmp
end function
public static double code(double B, double x) {
	double tmp;
	if ((x <= -0.06) || !(x <= 1.0)) {
		tmp = x / -B;
	} else {
		tmp = 1.0 / B;
	}
	return tmp;
}
def code(B, x):
	tmp = 0
	if (x <= -0.06) or not (x <= 1.0):
		tmp = x / -B
	else:
		tmp = 1.0 / B
	return tmp
function code(B, x)
	tmp = 0.0
	if ((x <= -0.06) || !(x <= 1.0))
		tmp = Float64(x / Float64(-B));
	else
		tmp = Float64(1.0 / B);
	end
	return tmp
end
function tmp_2 = code(B, x)
	tmp = 0.0;
	if ((x <= -0.06) || ~((x <= 1.0)))
		tmp = x / -B;
	else
		tmp = 1.0 / B;
	end
	tmp_2 = tmp;
end
code[B_, x_] := If[Or[LessEqual[x, -0.06], N[Not[LessEqual[x, 1.0]], $MachinePrecision]], N[(x / (-B)), $MachinePrecision], N[(1.0 / B), $MachinePrecision]]
\begin{array}{l}

\\
\begin{array}{l}
\mathbf{if}\;x \leq -0.06 \lor \neg \left(x \leq 1\right):\\
\;\;\;\;\frac{x}{-B}\\

\mathbf{else}:\\
\;\;\;\;\frac{1}{B}\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if x < -0.059999999999999998 or 1 < x

    1. Initial program 99.6%

      \[\left(-x \cdot \frac{1}{\tan B}\right) + \frac{1}{\sin B} \]
    2. Add Preprocessing
    3. Taylor expanded in B around 0 46.8%

      \[\leadsto \color{blue}{\frac{1 - x}{B}} \]
    4. Taylor expanded in x around inf 46.3%

      \[\leadsto \color{blue}{-1 \cdot \frac{x}{B}} \]
    5. Step-by-step derivation
      1. neg-mul-146.3%

        \[\leadsto \color{blue}{-\frac{x}{B}} \]
      2. distribute-neg-frac246.3%

        \[\leadsto \color{blue}{\frac{x}{-B}} \]
    6. Simplified46.3%

      \[\leadsto \color{blue}{\frac{x}{-B}} \]

    if -0.059999999999999998 < x < 1

    1. Initial program 99.8%

      \[\left(-x \cdot \frac{1}{\tan B}\right) + \frac{1}{\sin B} \]
    2. Add Preprocessing
    3. Taylor expanded in B around 0 49.8%

      \[\leadsto \color{blue}{\frac{1 - x}{B}} \]
    4. Taylor expanded in x around 0 48.8%

      \[\leadsto \color{blue}{\frac{1}{B}} \]
  3. Recombined 2 regimes into one program.
  4. Final simplification47.7%

    \[\leadsto \begin{array}{l} \mathbf{if}\;x \leq -0.06 \lor \neg \left(x \leq 1\right):\\ \;\;\;\;\frac{x}{-B}\\ \mathbf{else}:\\ \;\;\;\;\frac{1}{B}\\ \end{array} \]
  5. Add Preprocessing

Alternative 9: 50.4% accurate, 42.0× speedup?

\[\begin{array}{l} \\ \frac{1 - x}{B} \end{array} \]
(FPCore (B x) :precision binary64 (/ (- 1.0 x) B))
double code(double B, double x) {
	return (1.0 - x) / B;
}
real(8) function code(b, x)
    real(8), intent (in) :: b
    real(8), intent (in) :: x
    code = (1.0d0 - x) / b
end function
public static double code(double B, double x) {
	return (1.0 - x) / B;
}
def code(B, x):
	return (1.0 - x) / B
function code(B, x)
	return Float64(Float64(1.0 - x) / B)
end
function tmp = code(B, x)
	tmp = (1.0 - x) / B;
end
code[B_, x_] := N[(N[(1.0 - x), $MachinePrecision] / B), $MachinePrecision]
\begin{array}{l}

\\
\frac{1 - x}{B}
\end{array}
Derivation
  1. Initial program 99.7%

    \[\left(-x \cdot \frac{1}{\tan B}\right) + \frac{1}{\sin B} \]
  2. Add Preprocessing
  3. Taylor expanded in B around 0 48.4%

    \[\leadsto \color{blue}{\frac{1 - x}{B}} \]
  4. Add Preprocessing

Alternative 10: 26.4% accurate, 70.0× speedup?

\[\begin{array}{l} \\ \frac{1}{B} \end{array} \]
(FPCore (B x) :precision binary64 (/ 1.0 B))
double code(double B, double x) {
	return 1.0 / B;
}
real(8) function code(b, x)
    real(8), intent (in) :: b
    real(8), intent (in) :: x
    code = 1.0d0 / b
end function
public static double code(double B, double x) {
	return 1.0 / B;
}
def code(B, x):
	return 1.0 / B
function code(B, x)
	return Float64(1.0 / B)
end
function tmp = code(B, x)
	tmp = 1.0 / B;
end
code[B_, x_] := N[(1.0 / B), $MachinePrecision]
\begin{array}{l}

\\
\frac{1}{B}
\end{array}
Derivation
  1. Initial program 99.7%

    \[\left(-x \cdot \frac{1}{\tan B}\right) + \frac{1}{\sin B} \]
  2. Add Preprocessing
  3. Taylor expanded in B around 0 48.4%

    \[\leadsto \color{blue}{\frac{1 - x}{B}} \]
  4. Taylor expanded in x around 0 27.3%

    \[\leadsto \color{blue}{\frac{1}{B}} \]
  5. Add Preprocessing

Alternative 11: 3.1% accurate, 70.0× speedup?

\[\begin{array}{l} \\ B \cdot 0.16666666666666666 \end{array} \]
(FPCore (B x) :precision binary64 (* B 0.16666666666666666))
double code(double B, double x) {
	return B * 0.16666666666666666;
}
real(8) function code(b, x)
    real(8), intent (in) :: b
    real(8), intent (in) :: x
    code = b * 0.16666666666666666d0
end function
public static double code(double B, double x) {
	return B * 0.16666666666666666;
}
def code(B, x):
	return B * 0.16666666666666666
function code(B, x)
	return Float64(B * 0.16666666666666666)
end
function tmp = code(B, x)
	tmp = B * 0.16666666666666666;
end
code[B_, x_] := N[(B * 0.16666666666666666), $MachinePrecision]
\begin{array}{l}

\\
B \cdot 0.16666666666666666
\end{array}
Derivation
  1. Initial program 99.7%

    \[\left(-x \cdot \frac{1}{\tan B}\right) + \frac{1}{\sin B} \]
  2. Add Preprocessing
  3. Taylor expanded in B around 0 48.2%

    \[\leadsto \color{blue}{\frac{\left(1 + {B}^{2} \cdot \left(0.16666666666666666 + 0.3333333333333333 \cdot x\right)\right) - x}{B}} \]
  4. Taylor expanded in x around 0 48.1%

    \[\leadsto \frac{\left(1 + \color{blue}{0.16666666666666666 \cdot {B}^{2}}\right) - x}{B} \]
  5. Step-by-step derivation
    1. *-commutative48.1%

      \[\leadsto \frac{\left(1 + \color{blue}{{B}^{2} \cdot 0.16666666666666666}\right) - x}{B} \]
  6. Simplified48.1%

    \[\leadsto \frac{\left(1 + \color{blue}{{B}^{2} \cdot 0.16666666666666666}\right) - x}{B} \]
  7. Taylor expanded in B around inf 3.0%

    \[\leadsto \color{blue}{0.16666666666666666 \cdot B} \]
  8. Step-by-step derivation
    1. *-commutative3.0%

      \[\leadsto \color{blue}{B \cdot 0.16666666666666666} \]
  9. Simplified3.0%

    \[\leadsto \color{blue}{B \cdot 0.16666666666666666} \]
  10. Add Preprocessing

Reproduce

?
herbie shell --seed 2024088 
(FPCore (B x)
  :name "VandenBroeck and Keller, Equation (24)"
  :precision binary64
  (+ (- (* x (/ 1.0 (tan B)))) (/ 1.0 (sin B))))