Kahan p13 Example 2

Percentage Accurate: 100.0% → 100.0%
Time: 14.8s
Alternatives: 6
Speedup: 1.5×

Specification

?
\[\begin{array}{l} \\ \begin{array}{l} t_1 := 2 - \frac{\frac{2}{t}}{1 + \frac{1}{t}}\\ t_2 := t\_1 \cdot t\_1\\ \frac{1 + t\_2}{2 + t\_2} \end{array} \end{array} \]
(FPCore (t)
 :precision binary64
 (let* ((t_1 (- 2.0 (/ (/ 2.0 t) (+ 1.0 (/ 1.0 t))))) (t_2 (* t_1 t_1)))
   (/ (+ 1.0 t_2) (+ 2.0 t_2))))
double code(double t) {
	double t_1 = 2.0 - ((2.0 / t) / (1.0 + (1.0 / t)));
	double t_2 = t_1 * t_1;
	return (1.0 + t_2) / (2.0 + t_2);
}
real(8) function code(t)
    real(8), intent (in) :: t
    real(8) :: t_1
    real(8) :: t_2
    t_1 = 2.0d0 - ((2.0d0 / t) / (1.0d0 + (1.0d0 / t)))
    t_2 = t_1 * t_1
    code = (1.0d0 + t_2) / (2.0d0 + t_2)
end function
public static double code(double t) {
	double t_1 = 2.0 - ((2.0 / t) / (1.0 + (1.0 / t)));
	double t_2 = t_1 * t_1;
	return (1.0 + t_2) / (2.0 + t_2);
}
def code(t):
	t_1 = 2.0 - ((2.0 / t) / (1.0 + (1.0 / t)))
	t_2 = t_1 * t_1
	return (1.0 + t_2) / (2.0 + t_2)
function code(t)
	t_1 = Float64(2.0 - Float64(Float64(2.0 / t) / Float64(1.0 + Float64(1.0 / t))))
	t_2 = Float64(t_1 * t_1)
	return Float64(Float64(1.0 + t_2) / Float64(2.0 + t_2))
end
function tmp = code(t)
	t_1 = 2.0 - ((2.0 / t) / (1.0 + (1.0 / t)));
	t_2 = t_1 * t_1;
	tmp = (1.0 + t_2) / (2.0 + t_2);
end
code[t_] := Block[{t$95$1 = N[(2.0 - N[(N[(2.0 / t), $MachinePrecision] / N[(1.0 + N[(1.0 / t), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$2 = N[(t$95$1 * t$95$1), $MachinePrecision]}, N[(N[(1.0 + t$95$2), $MachinePrecision] / N[(2.0 + t$95$2), $MachinePrecision]), $MachinePrecision]]]
\begin{array}{l}

\\
\begin{array}{l}
t_1 := 2 - \frac{\frac{2}{t}}{1 + \frac{1}{t}}\\
t_2 := t\_1 \cdot t\_1\\
\frac{1 + t\_2}{2 + t\_2}
\end{array}
\end{array}

Sampling outcomes in binary64 precision:

Local Percentage Accuracy vs ?

The average percentage accuracy by input value. Horizontal axis shows value of an input variable; the variable is choosen in the title. Vertical axis is accuracy; higher is better. Red represent the original program, while blue represents Herbie's suggestion. These can be toggled with buttons below the plot. The line is an average while dots represent individual samples.

Accuracy vs Speed?

Herbie found 6 alternatives:

AlternativeAccuracySpeedup
The accuracy (vertical axis) and speed (horizontal axis) of each alternatives. Up and to the right is better. The red square shows the initial program, and each blue circle shows an alternative.The line shows the best available speed-accuracy tradeoffs.

Initial Program: 100.0% accurate, 1.0× speedup?

\[\begin{array}{l} \\ \begin{array}{l} t_1 := 2 - \frac{\frac{2}{t}}{1 + \frac{1}{t}}\\ t_2 := t\_1 \cdot t\_1\\ \frac{1 + t\_2}{2 + t\_2} \end{array} \end{array} \]
(FPCore (t)
 :precision binary64
 (let* ((t_1 (- 2.0 (/ (/ 2.0 t) (+ 1.0 (/ 1.0 t))))) (t_2 (* t_1 t_1)))
   (/ (+ 1.0 t_2) (+ 2.0 t_2))))
double code(double t) {
	double t_1 = 2.0 - ((2.0 / t) / (1.0 + (1.0 / t)));
	double t_2 = t_1 * t_1;
	return (1.0 + t_2) / (2.0 + t_2);
}
real(8) function code(t)
    real(8), intent (in) :: t
    real(8) :: t_1
    real(8) :: t_2
    t_1 = 2.0d0 - ((2.0d0 / t) / (1.0d0 + (1.0d0 / t)))
    t_2 = t_1 * t_1
    code = (1.0d0 + t_2) / (2.0d0 + t_2)
end function
public static double code(double t) {
	double t_1 = 2.0 - ((2.0 / t) / (1.0 + (1.0 / t)));
	double t_2 = t_1 * t_1;
	return (1.0 + t_2) / (2.0 + t_2);
}
def code(t):
	t_1 = 2.0 - ((2.0 / t) / (1.0 + (1.0 / t)))
	t_2 = t_1 * t_1
	return (1.0 + t_2) / (2.0 + t_2)
function code(t)
	t_1 = Float64(2.0 - Float64(Float64(2.0 / t) / Float64(1.0 + Float64(1.0 / t))))
	t_2 = Float64(t_1 * t_1)
	return Float64(Float64(1.0 + t_2) / Float64(2.0 + t_2))
end
function tmp = code(t)
	t_1 = 2.0 - ((2.0 / t) / (1.0 + (1.0 / t)));
	t_2 = t_1 * t_1;
	tmp = (1.0 + t_2) / (2.0 + t_2);
end
code[t_] := Block[{t$95$1 = N[(2.0 - N[(N[(2.0 / t), $MachinePrecision] / N[(1.0 + N[(1.0 / t), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$2 = N[(t$95$1 * t$95$1), $MachinePrecision]}, N[(N[(1.0 + t$95$2), $MachinePrecision] / N[(2.0 + t$95$2), $MachinePrecision]), $MachinePrecision]]]
\begin{array}{l}

\\
\begin{array}{l}
t_1 := 2 - \frac{\frac{2}{t}}{1 + \frac{1}{t}}\\
t_2 := t\_1 \cdot t\_1\\
\frac{1 + t\_2}{2 + t\_2}
\end{array}
\end{array}

Alternative 1: 100.0% accurate, 1.3× speedup?

\[\begin{array}{l} \\ \begin{array}{l} t_1 := 2 + \frac{2}{-1 - t}\\ t_2 := \frac{4}{-1 - t}\\ \frac{1 + \left(4 + \left(t\_2 + \frac{4 + t\_2}{-1 - t}\right)\right)}{2 + t\_1 \cdot t\_1} \end{array} \end{array} \]
(FPCore (t)
 :precision binary64
 (let* ((t_1 (+ 2.0 (/ 2.0 (- -1.0 t)))) (t_2 (/ 4.0 (- -1.0 t))))
   (/ (+ 1.0 (+ 4.0 (+ t_2 (/ (+ 4.0 t_2) (- -1.0 t))))) (+ 2.0 (* t_1 t_1)))))
double code(double t) {
	double t_1 = 2.0 + (2.0 / (-1.0 - t));
	double t_2 = 4.0 / (-1.0 - t);
	return (1.0 + (4.0 + (t_2 + ((4.0 + t_2) / (-1.0 - t))))) / (2.0 + (t_1 * t_1));
}
real(8) function code(t)
    real(8), intent (in) :: t
    real(8) :: t_1
    real(8) :: t_2
    t_1 = 2.0d0 + (2.0d0 / ((-1.0d0) - t))
    t_2 = 4.0d0 / ((-1.0d0) - t)
    code = (1.0d0 + (4.0d0 + (t_2 + ((4.0d0 + t_2) / ((-1.0d0) - t))))) / (2.0d0 + (t_1 * t_1))
end function
public static double code(double t) {
	double t_1 = 2.0 + (2.0 / (-1.0 - t));
	double t_2 = 4.0 / (-1.0 - t);
	return (1.0 + (4.0 + (t_2 + ((4.0 + t_2) / (-1.0 - t))))) / (2.0 + (t_1 * t_1));
}
def code(t):
	t_1 = 2.0 + (2.0 / (-1.0 - t))
	t_2 = 4.0 / (-1.0 - t)
	return (1.0 + (4.0 + (t_2 + ((4.0 + t_2) / (-1.0 - t))))) / (2.0 + (t_1 * t_1))
function code(t)
	t_1 = Float64(2.0 + Float64(2.0 / Float64(-1.0 - t)))
	t_2 = Float64(4.0 / Float64(-1.0 - t))
	return Float64(Float64(1.0 + Float64(4.0 + Float64(t_2 + Float64(Float64(4.0 + t_2) / Float64(-1.0 - t))))) / Float64(2.0 + Float64(t_1 * t_1)))
end
function tmp = code(t)
	t_1 = 2.0 + (2.0 / (-1.0 - t));
	t_2 = 4.0 / (-1.0 - t);
	tmp = (1.0 + (4.0 + (t_2 + ((4.0 + t_2) / (-1.0 - t))))) / (2.0 + (t_1 * t_1));
end
code[t_] := Block[{t$95$1 = N[(2.0 + N[(2.0 / N[(-1.0 - t), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$2 = N[(4.0 / N[(-1.0 - t), $MachinePrecision]), $MachinePrecision]}, N[(N[(1.0 + N[(4.0 + N[(t$95$2 + N[(N[(4.0 + t$95$2), $MachinePrecision] / N[(-1.0 - t), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] / N[(2.0 + N[(t$95$1 * t$95$1), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]]]
\begin{array}{l}

\\
\begin{array}{l}
t_1 := 2 + \frac{2}{-1 - t}\\
t_2 := \frac{4}{-1 - t}\\
\frac{1 + \left(4 + \left(t\_2 + \frac{4 + t\_2}{-1 - t}\right)\right)}{2 + t\_1 \cdot t\_1}
\end{array}
\end{array}
Derivation
  1. Initial program 99.6%

    \[\frac{1 + \left(2 - \frac{\frac{2}{t}}{1 + \frac{1}{t}}\right) \cdot \left(2 - \frac{\frac{2}{t}}{1 + \frac{1}{t}}\right)}{2 + \left(2 - \frac{\frac{2}{t}}{1 + \frac{1}{t}}\right) \cdot \left(2 - \frac{\frac{2}{t}}{1 + \frac{1}{t}}\right)} \]
  2. Step-by-step derivation
    1. Simplified100.0%

      \[\leadsto \color{blue}{\frac{1 + \left(2 + \frac{2}{-1 - t}\right) \cdot \left(2 + \frac{2}{-1 - t}\right)}{2 + \left(2 + \frac{2}{-1 - t}\right) \cdot \left(2 + \frac{2}{-1 - t}\right)}} \]
    2. Add Preprocessing
    3. Step-by-step derivation
      1. distribute-lft-in100.0%

        \[\leadsto \frac{1 + \color{blue}{\left(\left(2 + \frac{2}{-1 - t}\right) \cdot 2 + \left(2 + \frac{2}{-1 - t}\right) \cdot \frac{2}{-1 - t}\right)}}{2 + \left(2 + \frac{2}{-1 - t}\right) \cdot \left(2 + \frac{2}{-1 - t}\right)} \]
      2. *-commutative100.0%

        \[\leadsto \frac{1 + \left(\color{blue}{2 \cdot \left(2 + \frac{2}{-1 - t}\right)} + \left(2 + \frac{2}{-1 - t}\right) \cdot \frac{2}{-1 - t}\right)}{2 + \left(2 + \frac{2}{-1 - t}\right) \cdot \left(2 + \frac{2}{-1 - t}\right)} \]
      3. distribute-lft-in100.0%

        \[\leadsto \frac{1 + \left(\color{blue}{\left(2 \cdot 2 + 2 \cdot \frac{2}{-1 - t}\right)} + \left(2 + \frac{2}{-1 - t}\right) \cdot \frac{2}{-1 - t}\right)}{2 + \left(2 + \frac{2}{-1 - t}\right) \cdot \left(2 + \frac{2}{-1 - t}\right)} \]
      4. metadata-eval100.0%

        \[\leadsto \frac{1 + \left(\left(\color{blue}{4} + 2 \cdot \frac{2}{-1 - t}\right) + \left(2 + \frac{2}{-1 - t}\right) \cdot \frac{2}{-1 - t}\right)}{2 + \left(2 + \frac{2}{-1 - t}\right) \cdot \left(2 + \frac{2}{-1 - t}\right)} \]
      5. associate-*r/100.0%

        \[\leadsto \frac{1 + \left(\left(4 + \color{blue}{\frac{2 \cdot 2}{-1 - t}}\right) + \left(2 + \frac{2}{-1 - t}\right) \cdot \frac{2}{-1 - t}\right)}{2 + \left(2 + \frac{2}{-1 - t}\right) \cdot \left(2 + \frac{2}{-1 - t}\right)} \]
      6. metadata-eval100.0%

        \[\leadsto \frac{1 + \left(\left(4 + \frac{\color{blue}{4}}{-1 - t}\right) + \left(2 + \frac{2}{-1 - t}\right) \cdot \frac{2}{-1 - t}\right)}{2 + \left(2 + \frac{2}{-1 - t}\right) \cdot \left(2 + \frac{2}{-1 - t}\right)} \]
      7. associate-*r/100.0%

        \[\leadsto \frac{1 + \left(\left(4 + \frac{4}{-1 - t}\right) + \color{blue}{\frac{\left(2 + \frac{2}{-1 - t}\right) \cdot 2}{-1 - t}}\right)}{2 + \left(2 + \frac{2}{-1 - t}\right) \cdot \left(2 + \frac{2}{-1 - t}\right)} \]
      8. *-commutative100.0%

        \[\leadsto \frac{1 + \left(\left(4 + \frac{4}{-1 - t}\right) + \frac{\color{blue}{2 \cdot \left(2 + \frac{2}{-1 - t}\right)}}{-1 - t}\right)}{2 + \left(2 + \frac{2}{-1 - t}\right) \cdot \left(2 + \frac{2}{-1 - t}\right)} \]
      9. distribute-lft-in100.0%

        \[\leadsto \frac{1 + \left(\left(4 + \frac{4}{-1 - t}\right) + \frac{\color{blue}{2 \cdot 2 + 2 \cdot \frac{2}{-1 - t}}}{-1 - t}\right)}{2 + \left(2 + \frac{2}{-1 - t}\right) \cdot \left(2 + \frac{2}{-1 - t}\right)} \]
      10. metadata-eval100.0%

        \[\leadsto \frac{1 + \left(\left(4 + \frac{4}{-1 - t}\right) + \frac{\color{blue}{4} + 2 \cdot \frac{2}{-1 - t}}{-1 - t}\right)}{2 + \left(2 + \frac{2}{-1 - t}\right) \cdot \left(2 + \frac{2}{-1 - t}\right)} \]
      11. associate-*r/100.0%

        \[\leadsto \frac{1 + \left(\left(4 + \frac{4}{-1 - t}\right) + \frac{4 + \color{blue}{\frac{2 \cdot 2}{-1 - t}}}{-1 - t}\right)}{2 + \left(2 + \frac{2}{-1 - t}\right) \cdot \left(2 + \frac{2}{-1 - t}\right)} \]
      12. metadata-eval100.0%

        \[\leadsto \frac{1 + \left(\left(4 + \frac{4}{-1 - t}\right) + \frac{4 + \frac{\color{blue}{4}}{-1 - t}}{-1 - t}\right)}{2 + \left(2 + \frac{2}{-1 - t}\right) \cdot \left(2 + \frac{2}{-1 - t}\right)} \]
    4. Applied egg-rr100.0%

      \[\leadsto \frac{1 + \color{blue}{\left(\left(4 + \frac{4}{-1 - t}\right) + \frac{4 + \frac{4}{-1 - t}}{-1 - t}\right)}}{2 + \left(2 + \frac{2}{-1 - t}\right) \cdot \left(2 + \frac{2}{-1 - t}\right)} \]
    5. Step-by-step derivation
      1. associate-+l+100.0%

        \[\leadsto \frac{1 + \color{blue}{\left(4 + \left(\frac{4}{-1 - t} + \frac{4 + \frac{4}{-1 - t}}{-1 - t}\right)\right)}}{2 + \left(2 + \frac{2}{-1 - t}\right) \cdot \left(2 + \frac{2}{-1 - t}\right)} \]
    6. Simplified100.0%

      \[\leadsto \frac{1 + \color{blue}{\left(4 + \left(\frac{4}{-1 - t} + \frac{4 + \frac{4}{-1 - t}}{-1 - t}\right)\right)}}{2 + \left(2 + \frac{2}{-1 - t}\right) \cdot \left(2 + \frac{2}{-1 - t}\right)} \]
    7. Final simplification100.0%

      \[\leadsto \frac{1 + \left(4 + \left(\frac{4}{-1 - t} + \frac{4 + \frac{4}{-1 - t}}{-1 - t}\right)\right)}{2 + \left(2 + \frac{2}{-1 - t}\right) \cdot \left(2 + \frac{2}{-1 - t}\right)} \]
    8. Add Preprocessing

    Alternative 2: 100.0% accurate, 1.5× speedup?

    \[\begin{array}{l} \\ \begin{array}{l} t_1 := 2 + \frac{2}{-1 - t}\\ t_2 := t\_1 \cdot t\_1\\ \frac{1 + t\_2}{2 + t\_2} \end{array} \end{array} \]
    (FPCore (t)
     :precision binary64
     (let* ((t_1 (+ 2.0 (/ 2.0 (- -1.0 t)))) (t_2 (* t_1 t_1)))
       (/ (+ 1.0 t_2) (+ 2.0 t_2))))
    double code(double t) {
    	double t_1 = 2.0 + (2.0 / (-1.0 - t));
    	double t_2 = t_1 * t_1;
    	return (1.0 + t_2) / (2.0 + t_2);
    }
    
    real(8) function code(t)
        real(8), intent (in) :: t
        real(8) :: t_1
        real(8) :: t_2
        t_1 = 2.0d0 + (2.0d0 / ((-1.0d0) - t))
        t_2 = t_1 * t_1
        code = (1.0d0 + t_2) / (2.0d0 + t_2)
    end function
    
    public static double code(double t) {
    	double t_1 = 2.0 + (2.0 / (-1.0 - t));
    	double t_2 = t_1 * t_1;
    	return (1.0 + t_2) / (2.0 + t_2);
    }
    
    def code(t):
    	t_1 = 2.0 + (2.0 / (-1.0 - t))
    	t_2 = t_1 * t_1
    	return (1.0 + t_2) / (2.0 + t_2)
    
    function code(t)
    	t_1 = Float64(2.0 + Float64(2.0 / Float64(-1.0 - t)))
    	t_2 = Float64(t_1 * t_1)
    	return Float64(Float64(1.0 + t_2) / Float64(2.0 + t_2))
    end
    
    function tmp = code(t)
    	t_1 = 2.0 + (2.0 / (-1.0 - t));
    	t_2 = t_1 * t_1;
    	tmp = (1.0 + t_2) / (2.0 + t_2);
    end
    
    code[t_] := Block[{t$95$1 = N[(2.0 + N[(2.0 / N[(-1.0 - t), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$2 = N[(t$95$1 * t$95$1), $MachinePrecision]}, N[(N[(1.0 + t$95$2), $MachinePrecision] / N[(2.0 + t$95$2), $MachinePrecision]), $MachinePrecision]]]
    
    \begin{array}{l}
    
    \\
    \begin{array}{l}
    t_1 := 2 + \frac{2}{-1 - t}\\
    t_2 := t\_1 \cdot t\_1\\
    \frac{1 + t\_2}{2 + t\_2}
    \end{array}
    \end{array}
    
    Derivation
    1. Initial program 99.6%

      \[\frac{1 + \left(2 - \frac{\frac{2}{t}}{1 + \frac{1}{t}}\right) \cdot \left(2 - \frac{\frac{2}{t}}{1 + \frac{1}{t}}\right)}{2 + \left(2 - \frac{\frac{2}{t}}{1 + \frac{1}{t}}\right) \cdot \left(2 - \frac{\frac{2}{t}}{1 + \frac{1}{t}}\right)} \]
    2. Step-by-step derivation
      1. Simplified100.0%

        \[\leadsto \color{blue}{\frac{1 + \left(2 + \frac{2}{-1 - t}\right) \cdot \left(2 + \frac{2}{-1 - t}\right)}{2 + \left(2 + \frac{2}{-1 - t}\right) \cdot \left(2 + \frac{2}{-1 - t}\right)}} \]
      2. Add Preprocessing
      3. Final simplification100.0%

        \[\leadsto \frac{1 + \left(2 + \frac{2}{-1 - t}\right) \cdot \left(2 + \frac{2}{-1 - t}\right)}{2 + \left(2 + \frac{2}{-1 - t}\right) \cdot \left(2 + \frac{2}{-1 - t}\right)} \]
      4. Add Preprocessing

      Alternative 3: 99.4% accurate, 1.5× speedup?

      \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;t \leq -0.55 \lor \neg \left(t \leq 0.75\right):\\ \;\;\;\;0.8333333333333334 - \frac{0.2222222222222222}{t}\\ \mathbf{else}:\\ \;\;\;\;\frac{1 + \left(2 + \frac{2}{-1 - t}\right) \cdot \left(t \cdot 2\right)}{2 + \left(t \cdot 2\right) \cdot \left(t \cdot 2\right)}\\ \end{array} \end{array} \]
      (FPCore (t)
       :precision binary64
       (if (or (<= t -0.55) (not (<= t 0.75)))
         (- 0.8333333333333334 (/ 0.2222222222222222 t))
         (/
          (+ 1.0 (* (+ 2.0 (/ 2.0 (- -1.0 t))) (* t 2.0)))
          (+ 2.0 (* (* t 2.0) (* t 2.0))))))
      double code(double t) {
      	double tmp;
      	if ((t <= -0.55) || !(t <= 0.75)) {
      		tmp = 0.8333333333333334 - (0.2222222222222222 / t);
      	} else {
      		tmp = (1.0 + ((2.0 + (2.0 / (-1.0 - t))) * (t * 2.0))) / (2.0 + ((t * 2.0) * (t * 2.0)));
      	}
      	return tmp;
      }
      
      real(8) function code(t)
          real(8), intent (in) :: t
          real(8) :: tmp
          if ((t <= (-0.55d0)) .or. (.not. (t <= 0.75d0))) then
              tmp = 0.8333333333333334d0 - (0.2222222222222222d0 / t)
          else
              tmp = (1.0d0 + ((2.0d0 + (2.0d0 / ((-1.0d0) - t))) * (t * 2.0d0))) / (2.0d0 + ((t * 2.0d0) * (t * 2.0d0)))
          end if
          code = tmp
      end function
      
      public static double code(double t) {
      	double tmp;
      	if ((t <= -0.55) || !(t <= 0.75)) {
      		tmp = 0.8333333333333334 - (0.2222222222222222 / t);
      	} else {
      		tmp = (1.0 + ((2.0 + (2.0 / (-1.0 - t))) * (t * 2.0))) / (2.0 + ((t * 2.0) * (t * 2.0)));
      	}
      	return tmp;
      }
      
      def code(t):
      	tmp = 0
      	if (t <= -0.55) or not (t <= 0.75):
      		tmp = 0.8333333333333334 - (0.2222222222222222 / t)
      	else:
      		tmp = (1.0 + ((2.0 + (2.0 / (-1.0 - t))) * (t * 2.0))) / (2.0 + ((t * 2.0) * (t * 2.0)))
      	return tmp
      
      function code(t)
      	tmp = 0.0
      	if ((t <= -0.55) || !(t <= 0.75))
      		tmp = Float64(0.8333333333333334 - Float64(0.2222222222222222 / t));
      	else
      		tmp = Float64(Float64(1.0 + Float64(Float64(2.0 + Float64(2.0 / Float64(-1.0 - t))) * Float64(t * 2.0))) / Float64(2.0 + Float64(Float64(t * 2.0) * Float64(t * 2.0))));
      	end
      	return tmp
      end
      
      function tmp_2 = code(t)
      	tmp = 0.0;
      	if ((t <= -0.55) || ~((t <= 0.75)))
      		tmp = 0.8333333333333334 - (0.2222222222222222 / t);
      	else
      		tmp = (1.0 + ((2.0 + (2.0 / (-1.0 - t))) * (t * 2.0))) / (2.0 + ((t * 2.0) * (t * 2.0)));
      	end
      	tmp_2 = tmp;
      end
      
      code[t_] := If[Or[LessEqual[t, -0.55], N[Not[LessEqual[t, 0.75]], $MachinePrecision]], N[(0.8333333333333334 - N[(0.2222222222222222 / t), $MachinePrecision]), $MachinePrecision], N[(N[(1.0 + N[(N[(2.0 + N[(2.0 / N[(-1.0 - t), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] * N[(t * 2.0), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] / N[(2.0 + N[(N[(t * 2.0), $MachinePrecision] * N[(t * 2.0), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]]
      
      \begin{array}{l}
      
      \\
      \begin{array}{l}
      \mathbf{if}\;t \leq -0.55 \lor \neg \left(t \leq 0.75\right):\\
      \;\;\;\;0.8333333333333334 - \frac{0.2222222222222222}{t}\\
      
      \mathbf{else}:\\
      \;\;\;\;\frac{1 + \left(2 + \frac{2}{-1 - t}\right) \cdot \left(t \cdot 2\right)}{2 + \left(t \cdot 2\right) \cdot \left(t \cdot 2\right)}\\
      
      
      \end{array}
      \end{array}
      
      Derivation
      1. Split input into 2 regimes
      2. if t < -0.55000000000000004 or 0.75 < t

        1. Initial program 100.0%

          \[\frac{1 + \left(2 - \frac{\frac{2}{t}}{1 + \frac{1}{t}}\right) \cdot \left(2 - \frac{\frac{2}{t}}{1 + \frac{1}{t}}\right)}{2 + \left(2 - \frac{\frac{2}{t}}{1 + \frac{1}{t}}\right) \cdot \left(2 - \frac{\frac{2}{t}}{1 + \frac{1}{t}}\right)} \]
        2. Step-by-step derivation
          1. Simplified100.0%

            \[\leadsto \color{blue}{\frac{1 + \left(2 + \frac{2}{-1 - t}\right) \cdot \left(2 + \frac{2}{-1 - t}\right)}{2 + \left(2 + \frac{2}{-1 - t}\right) \cdot \left(2 + \frac{2}{-1 - t}\right)}} \]
          2. Add Preprocessing
          3. Taylor expanded in t around inf 98.9%

            \[\leadsto \color{blue}{0.8333333333333334 - 0.2222222222222222 \cdot \frac{1}{t}} \]
          4. Step-by-step derivation
            1. associate-*r/98.9%

              \[\leadsto 0.8333333333333334 - \color{blue}{\frac{0.2222222222222222 \cdot 1}{t}} \]
            2. metadata-eval98.9%

              \[\leadsto 0.8333333333333334 - \frac{\color{blue}{0.2222222222222222}}{t} \]
          5. Simplified98.9%

            \[\leadsto \color{blue}{0.8333333333333334 - \frac{0.2222222222222222}{t}} \]

          if -0.55000000000000004 < t < 0.75

          1. Initial program 99.1%

            \[\frac{1 + \left(2 - \frac{\frac{2}{t}}{1 + \frac{1}{t}}\right) \cdot \left(2 - \frac{\frac{2}{t}}{1 + \frac{1}{t}}\right)}{2 + \left(2 - \frac{\frac{2}{t}}{1 + \frac{1}{t}}\right) \cdot \left(2 - \frac{\frac{2}{t}}{1 + \frac{1}{t}}\right)} \]
          2. Step-by-step derivation
            1. Simplified99.9%

              \[\leadsto \color{blue}{\frac{1 + \left(2 + \frac{2}{-1 - t}\right) \cdot \left(2 + \frac{2}{-1 - t}\right)}{2 + \left(2 + \frac{2}{-1 - t}\right) \cdot \left(2 + \frac{2}{-1 - t}\right)}} \]
            2. Add Preprocessing
            3. Taylor expanded in t around 0 99.7%

              \[\leadsto \frac{1 + \left(2 + \frac{2}{-1 - t}\right) \cdot \left(2 + \frac{2}{-1 - t}\right)}{2 + \left(2 + \frac{2}{-1 - t}\right) \cdot \color{blue}{\left(2 \cdot t\right)}} \]
            4. Taylor expanded in t around 0 99.7%

              \[\leadsto \frac{1 + \left(2 + \frac{2}{-1 - t}\right) \cdot \color{blue}{\left(2 \cdot t\right)}}{2 + \left(2 + \frac{2}{-1 - t}\right) \cdot \left(2 \cdot t\right)} \]
            5. Taylor expanded in t around 0 99.9%

              \[\leadsto \frac{1 + \left(2 + \frac{2}{-1 - t}\right) \cdot \left(2 \cdot t\right)}{2 + \color{blue}{\left(2 \cdot t\right)} \cdot \left(2 \cdot t\right)} \]
          3. Recombined 2 regimes into one program.
          4. Final simplification99.4%

            \[\leadsto \begin{array}{l} \mathbf{if}\;t \leq -0.55 \lor \neg \left(t \leq 0.75\right):\\ \;\;\;\;0.8333333333333334 - \frac{0.2222222222222222}{t}\\ \mathbf{else}:\\ \;\;\;\;\frac{1 + \left(2 + \frac{2}{-1 - t}\right) \cdot \left(t \cdot 2\right)}{2 + \left(t \cdot 2\right) \cdot \left(t \cdot 2\right)}\\ \end{array} \]
          5. Add Preprocessing

          Alternative 4: 99.2% accurate, 3.4× speedup?

          \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;t \leq -0.48 \lor \neg \left(t \leq 0.65\right):\\ \;\;\;\;0.8333333333333334 - \frac{0.2222222222222222}{t}\\ \mathbf{else}:\\ \;\;\;\;0.5\\ \end{array} \end{array} \]
          (FPCore (t)
           :precision binary64
           (if (or (<= t -0.48) (not (<= t 0.65)))
             (- 0.8333333333333334 (/ 0.2222222222222222 t))
             0.5))
          double code(double t) {
          	double tmp;
          	if ((t <= -0.48) || !(t <= 0.65)) {
          		tmp = 0.8333333333333334 - (0.2222222222222222 / t);
          	} else {
          		tmp = 0.5;
          	}
          	return tmp;
          }
          
          real(8) function code(t)
              real(8), intent (in) :: t
              real(8) :: tmp
              if ((t <= (-0.48d0)) .or. (.not. (t <= 0.65d0))) then
                  tmp = 0.8333333333333334d0 - (0.2222222222222222d0 / t)
              else
                  tmp = 0.5d0
              end if
              code = tmp
          end function
          
          public static double code(double t) {
          	double tmp;
          	if ((t <= -0.48) || !(t <= 0.65)) {
          		tmp = 0.8333333333333334 - (0.2222222222222222 / t);
          	} else {
          		tmp = 0.5;
          	}
          	return tmp;
          }
          
          def code(t):
          	tmp = 0
          	if (t <= -0.48) or not (t <= 0.65):
          		tmp = 0.8333333333333334 - (0.2222222222222222 / t)
          	else:
          		tmp = 0.5
          	return tmp
          
          function code(t)
          	tmp = 0.0
          	if ((t <= -0.48) || !(t <= 0.65))
          		tmp = Float64(0.8333333333333334 - Float64(0.2222222222222222 / t));
          	else
          		tmp = 0.5;
          	end
          	return tmp
          end
          
          function tmp_2 = code(t)
          	tmp = 0.0;
          	if ((t <= -0.48) || ~((t <= 0.65)))
          		tmp = 0.8333333333333334 - (0.2222222222222222 / t);
          	else
          		tmp = 0.5;
          	end
          	tmp_2 = tmp;
          end
          
          code[t_] := If[Or[LessEqual[t, -0.48], N[Not[LessEqual[t, 0.65]], $MachinePrecision]], N[(0.8333333333333334 - N[(0.2222222222222222 / t), $MachinePrecision]), $MachinePrecision], 0.5]
          
          \begin{array}{l}
          
          \\
          \begin{array}{l}
          \mathbf{if}\;t \leq -0.48 \lor \neg \left(t \leq 0.65\right):\\
          \;\;\;\;0.8333333333333334 - \frac{0.2222222222222222}{t}\\
          
          \mathbf{else}:\\
          \;\;\;\;0.5\\
          
          
          \end{array}
          \end{array}
          
          Derivation
          1. Split input into 2 regimes
          2. if t < -0.47999999999999998 or 0.650000000000000022 < t

            1. Initial program 100.0%

              \[\frac{1 + \left(2 - \frac{\frac{2}{t}}{1 + \frac{1}{t}}\right) \cdot \left(2 - \frac{\frac{2}{t}}{1 + \frac{1}{t}}\right)}{2 + \left(2 - \frac{\frac{2}{t}}{1 + \frac{1}{t}}\right) \cdot \left(2 - \frac{\frac{2}{t}}{1 + \frac{1}{t}}\right)} \]
            2. Step-by-step derivation
              1. Simplified100.0%

                \[\leadsto \color{blue}{\frac{1 + \left(2 + \frac{2}{-1 - t}\right) \cdot \left(2 + \frac{2}{-1 - t}\right)}{2 + \left(2 + \frac{2}{-1 - t}\right) \cdot \left(2 + \frac{2}{-1 - t}\right)}} \]
              2. Add Preprocessing
              3. Taylor expanded in t around inf 98.9%

                \[\leadsto \color{blue}{0.8333333333333334 - 0.2222222222222222 \cdot \frac{1}{t}} \]
              4. Step-by-step derivation
                1. associate-*r/98.9%

                  \[\leadsto 0.8333333333333334 - \color{blue}{\frac{0.2222222222222222 \cdot 1}{t}} \]
                2. metadata-eval98.9%

                  \[\leadsto 0.8333333333333334 - \frac{\color{blue}{0.2222222222222222}}{t} \]
              5. Simplified98.9%

                \[\leadsto \color{blue}{0.8333333333333334 - \frac{0.2222222222222222}{t}} \]

              if -0.47999999999999998 < t < 0.650000000000000022

              1. Initial program 99.1%

                \[\frac{1 + \left(2 - \frac{\frac{2}{t}}{1 + \frac{1}{t}}\right) \cdot \left(2 - \frac{\frac{2}{t}}{1 + \frac{1}{t}}\right)}{2 + \left(2 - \frac{\frac{2}{t}}{1 + \frac{1}{t}}\right) \cdot \left(2 - \frac{\frac{2}{t}}{1 + \frac{1}{t}}\right)} \]
              2. Step-by-step derivation
                1. Simplified99.9%

                  \[\leadsto \color{blue}{\frac{1 + \left(2 + \frac{2}{-1 - t}\right) \cdot \left(2 + \frac{2}{-1 - t}\right)}{2 + \left(2 + \frac{2}{-1 - t}\right) \cdot \left(2 + \frac{2}{-1 - t}\right)}} \]
                2. Add Preprocessing
                3. Taylor expanded in t around 0 99.1%

                  \[\leadsto \color{blue}{0.5} \]
              3. Recombined 2 regimes into one program.
              4. Final simplification99.0%

                \[\leadsto \begin{array}{l} \mathbf{if}\;t \leq -0.48 \lor \neg \left(t \leq 0.65\right):\\ \;\;\;\;0.8333333333333334 - \frac{0.2222222222222222}{t}\\ \mathbf{else}:\\ \;\;\;\;0.5\\ \end{array} \]
              5. Add Preprocessing

              Alternative 5: 98.7% accurate, 4.6× speedup?

              \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;t \leq -0.33:\\ \;\;\;\;0.8333333333333334\\ \mathbf{elif}\;t \leq 1:\\ \;\;\;\;0.5\\ \mathbf{else}:\\ \;\;\;\;0.8333333333333334\\ \end{array} \end{array} \]
              (FPCore (t)
               :precision binary64
               (if (<= t -0.33) 0.8333333333333334 (if (<= t 1.0) 0.5 0.8333333333333334)))
              double code(double t) {
              	double tmp;
              	if (t <= -0.33) {
              		tmp = 0.8333333333333334;
              	} else if (t <= 1.0) {
              		tmp = 0.5;
              	} else {
              		tmp = 0.8333333333333334;
              	}
              	return tmp;
              }
              
              real(8) function code(t)
                  real(8), intent (in) :: t
                  real(8) :: tmp
                  if (t <= (-0.33d0)) then
                      tmp = 0.8333333333333334d0
                  else if (t <= 1.0d0) then
                      tmp = 0.5d0
                  else
                      tmp = 0.8333333333333334d0
                  end if
                  code = tmp
              end function
              
              public static double code(double t) {
              	double tmp;
              	if (t <= -0.33) {
              		tmp = 0.8333333333333334;
              	} else if (t <= 1.0) {
              		tmp = 0.5;
              	} else {
              		tmp = 0.8333333333333334;
              	}
              	return tmp;
              }
              
              def code(t):
              	tmp = 0
              	if t <= -0.33:
              		tmp = 0.8333333333333334
              	elif t <= 1.0:
              		tmp = 0.5
              	else:
              		tmp = 0.8333333333333334
              	return tmp
              
              function code(t)
              	tmp = 0.0
              	if (t <= -0.33)
              		tmp = 0.8333333333333334;
              	elseif (t <= 1.0)
              		tmp = 0.5;
              	else
              		tmp = 0.8333333333333334;
              	end
              	return tmp
              end
              
              function tmp_2 = code(t)
              	tmp = 0.0;
              	if (t <= -0.33)
              		tmp = 0.8333333333333334;
              	elseif (t <= 1.0)
              		tmp = 0.5;
              	else
              		tmp = 0.8333333333333334;
              	end
              	tmp_2 = tmp;
              end
              
              code[t_] := If[LessEqual[t, -0.33], 0.8333333333333334, If[LessEqual[t, 1.0], 0.5, 0.8333333333333334]]
              
              \begin{array}{l}
              
              \\
              \begin{array}{l}
              \mathbf{if}\;t \leq -0.33:\\
              \;\;\;\;0.8333333333333334\\
              
              \mathbf{elif}\;t \leq 1:\\
              \;\;\;\;0.5\\
              
              \mathbf{else}:\\
              \;\;\;\;0.8333333333333334\\
              
              
              \end{array}
              \end{array}
              
              Derivation
              1. Split input into 2 regimes
              2. if t < -0.330000000000000016 or 1 < t

                1. Initial program 100.0%

                  \[\frac{1 + \left(2 - \frac{\frac{2}{t}}{1 + \frac{1}{t}}\right) \cdot \left(2 - \frac{\frac{2}{t}}{1 + \frac{1}{t}}\right)}{2 + \left(2 - \frac{\frac{2}{t}}{1 + \frac{1}{t}}\right) \cdot \left(2 - \frac{\frac{2}{t}}{1 + \frac{1}{t}}\right)} \]
                2. Step-by-step derivation
                  1. Simplified100.0%

                    \[\leadsto \color{blue}{\frac{1 + \left(2 + \frac{2}{-1 - t}\right) \cdot \left(2 + \frac{2}{-1 - t}\right)}{2 + \left(2 + \frac{2}{-1 - t}\right) \cdot \left(2 + \frac{2}{-1 - t}\right)}} \]
                  2. Add Preprocessing
                  3. Taylor expanded in t around inf 97.2%

                    \[\leadsto \color{blue}{0.8333333333333334} \]

                  if -0.330000000000000016 < t < 1

                  1. Initial program 99.1%

                    \[\frac{1 + \left(2 - \frac{\frac{2}{t}}{1 + \frac{1}{t}}\right) \cdot \left(2 - \frac{\frac{2}{t}}{1 + \frac{1}{t}}\right)}{2 + \left(2 - \frac{\frac{2}{t}}{1 + \frac{1}{t}}\right) \cdot \left(2 - \frac{\frac{2}{t}}{1 + \frac{1}{t}}\right)} \]
                  2. Step-by-step derivation
                    1. Simplified99.9%

                      \[\leadsto \color{blue}{\frac{1 + \left(2 + \frac{2}{-1 - t}\right) \cdot \left(2 + \frac{2}{-1 - t}\right)}{2 + \left(2 + \frac{2}{-1 - t}\right) \cdot \left(2 + \frac{2}{-1 - t}\right)}} \]
                    2. Add Preprocessing
                    3. Taylor expanded in t around 0 99.1%

                      \[\leadsto \color{blue}{0.5} \]
                  3. Recombined 2 regimes into one program.
                  4. Final simplification98.0%

                    \[\leadsto \begin{array}{l} \mathbf{if}\;t \leq -0.33:\\ \;\;\;\;0.8333333333333334\\ \mathbf{elif}\;t \leq 1:\\ \;\;\;\;0.5\\ \mathbf{else}:\\ \;\;\;\;0.8333333333333334\\ \end{array} \]
                  5. Add Preprocessing

                  Alternative 6: 59.2% accurate, 51.0× speedup?

                  \[\begin{array}{l} \\ 0.5 \end{array} \]
                  (FPCore (t) :precision binary64 0.5)
                  double code(double t) {
                  	return 0.5;
                  }
                  
                  real(8) function code(t)
                      real(8), intent (in) :: t
                      code = 0.5d0
                  end function
                  
                  public static double code(double t) {
                  	return 0.5;
                  }
                  
                  def code(t):
                  	return 0.5
                  
                  function code(t)
                  	return 0.5
                  end
                  
                  function tmp = code(t)
                  	tmp = 0.5;
                  end
                  
                  code[t_] := 0.5
                  
                  \begin{array}{l}
                  
                  \\
                  0.5
                  \end{array}
                  
                  Derivation
                  1. Initial program 99.6%

                    \[\frac{1 + \left(2 - \frac{\frac{2}{t}}{1 + \frac{1}{t}}\right) \cdot \left(2 - \frac{\frac{2}{t}}{1 + \frac{1}{t}}\right)}{2 + \left(2 - \frac{\frac{2}{t}}{1 + \frac{1}{t}}\right) \cdot \left(2 - \frac{\frac{2}{t}}{1 + \frac{1}{t}}\right)} \]
                  2. Step-by-step derivation
                    1. Simplified100.0%

                      \[\leadsto \color{blue}{\frac{1 + \left(2 + \frac{2}{-1 - t}\right) \cdot \left(2 + \frac{2}{-1 - t}\right)}{2 + \left(2 + \frac{2}{-1 - t}\right) \cdot \left(2 + \frac{2}{-1 - t}\right)}} \]
                    2. Add Preprocessing
                    3. Taylor expanded in t around 0 55.1%

                      \[\leadsto \color{blue}{0.5} \]
                    4. Final simplification55.1%

                      \[\leadsto 0.5 \]
                    5. Add Preprocessing

                    Reproduce

                    ?
                    herbie shell --seed 2024048 
                    (FPCore (t)
                      :name "Kahan p13 Example 2"
                      :precision binary64
                      (/ (+ 1.0 (* (- 2.0 (/ (/ 2.0 t) (+ 1.0 (/ 1.0 t)))) (- 2.0 (/ (/ 2.0 t) (+ 1.0 (/ 1.0 t)))))) (+ 2.0 (* (- 2.0 (/ (/ 2.0 t) (+ 1.0 (/ 1.0 t)))) (- 2.0 (/ (/ 2.0 t) (+ 1.0 (/ 1.0 t))))))))