Kahan p13 Example 2

Percentage Accurate: 99.9% → 100.0%
Time: 14.7s
Alternatives: 5
Speedup: 1.9×

Specification

?
\[\begin{array}{l} \\ \begin{array}{l} t_1 := 2 - \frac{\frac{2}{t}}{1 + \frac{1}{t}}\\ t_2 := t\_1 \cdot t\_1\\ \frac{1 + t\_2}{2 + t\_2} \end{array} \end{array} \]
(FPCore (t)
 :precision binary64
 (let* ((t_1 (- 2.0 (/ (/ 2.0 t) (+ 1.0 (/ 1.0 t))))) (t_2 (* t_1 t_1)))
   (/ (+ 1.0 t_2) (+ 2.0 t_2))))
double code(double t) {
	double t_1 = 2.0 - ((2.0 / t) / (1.0 + (1.0 / t)));
	double t_2 = t_1 * t_1;
	return (1.0 + t_2) / (2.0 + t_2);
}
real(8) function code(t)
    real(8), intent (in) :: t
    real(8) :: t_1
    real(8) :: t_2
    t_1 = 2.0d0 - ((2.0d0 / t) / (1.0d0 + (1.0d0 / t)))
    t_2 = t_1 * t_1
    code = (1.0d0 + t_2) / (2.0d0 + t_2)
end function
public static double code(double t) {
	double t_1 = 2.0 - ((2.0 / t) / (1.0 + (1.0 / t)));
	double t_2 = t_1 * t_1;
	return (1.0 + t_2) / (2.0 + t_2);
}
def code(t):
	t_1 = 2.0 - ((2.0 / t) / (1.0 + (1.0 / t)))
	t_2 = t_1 * t_1
	return (1.0 + t_2) / (2.0 + t_2)
function code(t)
	t_1 = Float64(2.0 - Float64(Float64(2.0 / t) / Float64(1.0 + Float64(1.0 / t))))
	t_2 = Float64(t_1 * t_1)
	return Float64(Float64(1.0 + t_2) / Float64(2.0 + t_2))
end
function tmp = code(t)
	t_1 = 2.0 - ((2.0 / t) / (1.0 + (1.0 / t)));
	t_2 = t_1 * t_1;
	tmp = (1.0 + t_2) / (2.0 + t_2);
end
code[t_] := Block[{t$95$1 = N[(2.0 - N[(N[(2.0 / t), $MachinePrecision] / N[(1.0 + N[(1.0 / t), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$2 = N[(t$95$1 * t$95$1), $MachinePrecision]}, N[(N[(1.0 + t$95$2), $MachinePrecision] / N[(2.0 + t$95$2), $MachinePrecision]), $MachinePrecision]]]
\begin{array}{l}

\\
\begin{array}{l}
t_1 := 2 - \frac{\frac{2}{t}}{1 + \frac{1}{t}}\\
t_2 := t\_1 \cdot t\_1\\
\frac{1 + t\_2}{2 + t\_2}
\end{array}
\end{array}

Sampling outcomes in binary64 precision:

Local Percentage Accuracy vs ?

The average percentage accuracy by input value. Horizontal axis shows value of an input variable; the variable is choosen in the title. Vertical axis is accuracy; higher is better. Red represent the original program, while blue represents Herbie's suggestion. These can be toggled with buttons below the plot. The line is an average while dots represent individual samples.

Accuracy vs Speed?

Herbie found 5 alternatives:

AlternativeAccuracySpeedup
The accuracy (vertical axis) and speed (horizontal axis) of each alternatives. Up and to the right is better. The red square shows the initial program, and each blue circle shows an alternative.The line shows the best available speed-accuracy tradeoffs.

Initial Program: 99.9% accurate, 1.0× speedup?

\[\begin{array}{l} \\ \begin{array}{l} t_1 := 2 - \frac{\frac{2}{t}}{1 + \frac{1}{t}}\\ t_2 := t\_1 \cdot t\_1\\ \frac{1 + t\_2}{2 + t\_2} \end{array} \end{array} \]
(FPCore (t)
 :precision binary64
 (let* ((t_1 (- 2.0 (/ (/ 2.0 t) (+ 1.0 (/ 1.0 t))))) (t_2 (* t_1 t_1)))
   (/ (+ 1.0 t_2) (+ 2.0 t_2))))
double code(double t) {
	double t_1 = 2.0 - ((2.0 / t) / (1.0 + (1.0 / t)));
	double t_2 = t_1 * t_1;
	return (1.0 + t_2) / (2.0 + t_2);
}
real(8) function code(t)
    real(8), intent (in) :: t
    real(8) :: t_1
    real(8) :: t_2
    t_1 = 2.0d0 - ((2.0d0 / t) / (1.0d0 + (1.0d0 / t)))
    t_2 = t_1 * t_1
    code = (1.0d0 + t_2) / (2.0d0 + t_2)
end function
public static double code(double t) {
	double t_1 = 2.0 - ((2.0 / t) / (1.0 + (1.0 / t)));
	double t_2 = t_1 * t_1;
	return (1.0 + t_2) / (2.0 + t_2);
}
def code(t):
	t_1 = 2.0 - ((2.0 / t) / (1.0 + (1.0 / t)))
	t_2 = t_1 * t_1
	return (1.0 + t_2) / (2.0 + t_2)
function code(t)
	t_1 = Float64(2.0 - Float64(Float64(2.0 / t) / Float64(1.0 + Float64(1.0 / t))))
	t_2 = Float64(t_1 * t_1)
	return Float64(Float64(1.0 + t_2) / Float64(2.0 + t_2))
end
function tmp = code(t)
	t_1 = 2.0 - ((2.0 / t) / (1.0 + (1.0 / t)));
	t_2 = t_1 * t_1;
	tmp = (1.0 + t_2) / (2.0 + t_2);
end
code[t_] := Block[{t$95$1 = N[(2.0 - N[(N[(2.0 / t), $MachinePrecision] / N[(1.0 + N[(1.0 / t), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$2 = N[(t$95$1 * t$95$1), $MachinePrecision]}, N[(N[(1.0 + t$95$2), $MachinePrecision] / N[(2.0 + t$95$2), $MachinePrecision]), $MachinePrecision]]]
\begin{array}{l}

\\
\begin{array}{l}
t_1 := 2 - \frac{\frac{2}{t}}{1 + \frac{1}{t}}\\
t_2 := t\_1 \cdot t\_1\\
\frac{1 + t\_2}{2 + t\_2}
\end{array}
\end{array}

Alternative 1: 100.0% accurate, 1.9× speedup?

\[\begin{array}{l} \\ \begin{array}{l} t_1 := \frac{8 + \frac{-4}{t + 1}}{t + 1}\\ \frac{t\_1 + -5}{t\_1 + -6} \end{array} \end{array} \]
(FPCore (t)
 :precision binary64
 (let* ((t_1 (/ (+ 8.0 (/ -4.0 (+ t 1.0))) (+ t 1.0))))
   (/ (+ t_1 -5.0) (+ t_1 -6.0))))
double code(double t) {
	double t_1 = (8.0 + (-4.0 / (t + 1.0))) / (t + 1.0);
	return (t_1 + -5.0) / (t_1 + -6.0);
}
real(8) function code(t)
    real(8), intent (in) :: t
    real(8) :: t_1
    t_1 = (8.0d0 + ((-4.0d0) / (t + 1.0d0))) / (t + 1.0d0)
    code = (t_1 + (-5.0d0)) / (t_1 + (-6.0d0))
end function
public static double code(double t) {
	double t_1 = (8.0 + (-4.0 / (t + 1.0))) / (t + 1.0);
	return (t_1 + -5.0) / (t_1 + -6.0);
}
def code(t):
	t_1 = (8.0 + (-4.0 / (t + 1.0))) / (t + 1.0)
	return (t_1 + -5.0) / (t_1 + -6.0)
function code(t)
	t_1 = Float64(Float64(8.0 + Float64(-4.0 / Float64(t + 1.0))) / Float64(t + 1.0))
	return Float64(Float64(t_1 + -5.0) / Float64(t_1 + -6.0))
end
function tmp = code(t)
	t_1 = (8.0 + (-4.0 / (t + 1.0))) / (t + 1.0);
	tmp = (t_1 + -5.0) / (t_1 + -6.0);
end
code[t_] := Block[{t$95$1 = N[(N[(8.0 + N[(-4.0 / N[(t + 1.0), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] / N[(t + 1.0), $MachinePrecision]), $MachinePrecision]}, N[(N[(t$95$1 + -5.0), $MachinePrecision] / N[(t$95$1 + -6.0), $MachinePrecision]), $MachinePrecision]]
\begin{array}{l}

\\
\begin{array}{l}
t_1 := \frac{8 + \frac{-4}{t + 1}}{t + 1}\\
\frac{t\_1 + -5}{t\_1 + -6}
\end{array}
\end{array}
Derivation
  1. Initial program 100.0%

    \[\frac{1 + \left(2 - \frac{\frac{2}{t}}{1 + \frac{1}{t}}\right) \cdot \left(2 - \frac{\frac{2}{t}}{1 + \frac{1}{t}}\right)}{2 + \left(2 - \frac{\frac{2}{t}}{1 + \frac{1}{t}}\right) \cdot \left(2 - \frac{\frac{2}{t}}{1 + \frac{1}{t}}\right)} \]
  2. Simplified100.0%

    \[\leadsto \color{blue}{\frac{5 + \frac{2}{1 + t} \cdot \left(\frac{2}{1 + t} - 4\right)}{6 + \frac{2}{1 + t} \cdot \left(\frac{2}{1 + t} - 4\right)}} \]
  3. Add Preprocessing
  4. Step-by-step derivation
    1. expm1-log1p-u99.2%

      \[\leadsto \color{blue}{\mathsf{expm1}\left(\mathsf{log1p}\left(\frac{5 + \frac{2}{1 + t} \cdot \left(\frac{2}{1 + t} - 4\right)}{6 + \frac{2}{1 + t} \cdot \left(\frac{2}{1 + t} - 4\right)}\right)\right)} \]
    2. expm1-udef99.2%

      \[\leadsto \color{blue}{e^{\mathsf{log1p}\left(\frac{5 + \frac{2}{1 + t} \cdot \left(\frac{2}{1 + t} - 4\right)}{6 + \frac{2}{1 + t} \cdot \left(\frac{2}{1 + t} - 4\right)}\right)} - 1} \]
  5. Applied egg-rr99.2%

    \[\leadsto \color{blue}{e^{\mathsf{log1p}\left(\frac{\mathsf{fma}\left(\frac{2}{t + 1}, \frac{2}{t + 1} + -4, 5\right)}{\mathsf{fma}\left(\frac{2}{t + 1}, \frac{2}{t + 1} + -4, 6\right)}\right)} - 1} \]
  6. Step-by-step derivation
    1. expm1-def99.2%

      \[\leadsto \color{blue}{\mathsf{expm1}\left(\mathsf{log1p}\left(\frac{\mathsf{fma}\left(\frac{2}{t + 1}, \frac{2}{t + 1} + -4, 5\right)}{\mathsf{fma}\left(\frac{2}{t + 1}, \frac{2}{t + 1} + -4, 6\right)}\right)\right)} \]
    2. expm1-log1p100.0%

      \[\leadsto \color{blue}{\frac{\mathsf{fma}\left(\frac{2}{t + 1}, \frac{2}{t + 1} + -4, 5\right)}{\mathsf{fma}\left(\frac{2}{t + 1}, \frac{2}{t + 1} + -4, 6\right)}} \]
    3. *-lft-identity100.0%

      \[\leadsto \color{blue}{1 \cdot \frac{\mathsf{fma}\left(\frac{2}{t + 1}, \frac{2}{t + 1} + -4, 5\right)}{\mathsf{fma}\left(\frac{2}{t + 1}, \frac{2}{t + 1} + -4, 6\right)}} \]
    4. metadata-eval100.0%

      \[\leadsto \color{blue}{\frac{-1}{-1}} \cdot \frac{\mathsf{fma}\left(\frac{2}{t + 1}, \frac{2}{t + 1} + -4, 5\right)}{\mathsf{fma}\left(\frac{2}{t + 1}, \frac{2}{t + 1} + -4, 6\right)} \]
    5. times-frac100.0%

      \[\leadsto \color{blue}{\frac{-1 \cdot \mathsf{fma}\left(\frac{2}{t + 1}, \frac{2}{t + 1} + -4, 5\right)}{-1 \cdot \mathsf{fma}\left(\frac{2}{t + 1}, \frac{2}{t + 1} + -4, 6\right)}} \]
    6. neg-mul-1100.0%

      \[\leadsto \frac{\color{blue}{-\mathsf{fma}\left(\frac{2}{t + 1}, \frac{2}{t + 1} + -4, 5\right)}}{-1 \cdot \mathsf{fma}\left(\frac{2}{t + 1}, \frac{2}{t + 1} + -4, 6\right)} \]
    7. neg-mul-1100.0%

      \[\leadsto \frac{-\mathsf{fma}\left(\frac{2}{t + 1}, \frac{2}{t + 1} + -4, 5\right)}{\color{blue}{-\mathsf{fma}\left(\frac{2}{t + 1}, \frac{2}{t + 1} + -4, 6\right)}} \]
  7. Simplified100.0%

    \[\leadsto \color{blue}{\frac{\frac{8 + \frac{-4}{t + 1}}{t + 1} + -5}{\frac{8 + \frac{-4}{t + 1}}{t + 1} + -6}} \]
  8. Final simplification100.0%

    \[\leadsto \frac{\frac{8 + \frac{-4}{t + 1}}{t + 1} + -5}{\frac{8 + \frac{-4}{t + 1}}{t + 1} + -6} \]
  9. Add Preprocessing

Alternative 2: 57.5% accurate, 2.2× speedup?

\[\begin{array}{l} \\ \frac{5 + \frac{8 + \frac{-4}{t + 1}}{-1 - t}}{6 + \frac{2}{t \cdot -0.25 - 0.375}} \end{array} \]
(FPCore (t)
 :precision binary64
 (/
  (+ 5.0 (/ (+ 8.0 (/ -4.0 (+ t 1.0))) (- -1.0 t)))
  (+ 6.0 (/ 2.0 (- (* t -0.25) 0.375)))))
double code(double t) {
	return (5.0 + ((8.0 + (-4.0 / (t + 1.0))) / (-1.0 - t))) / (6.0 + (2.0 / ((t * -0.25) - 0.375)));
}
real(8) function code(t)
    real(8), intent (in) :: t
    code = (5.0d0 + ((8.0d0 + ((-4.0d0) / (t + 1.0d0))) / ((-1.0d0) - t))) / (6.0d0 + (2.0d0 / ((t * (-0.25d0)) - 0.375d0)))
end function
public static double code(double t) {
	return (5.0 + ((8.0 + (-4.0 / (t + 1.0))) / (-1.0 - t))) / (6.0 + (2.0 / ((t * -0.25) - 0.375)));
}
def code(t):
	return (5.0 + ((8.0 + (-4.0 / (t + 1.0))) / (-1.0 - t))) / (6.0 + (2.0 / ((t * -0.25) - 0.375)))
function code(t)
	return Float64(Float64(5.0 + Float64(Float64(8.0 + Float64(-4.0 / Float64(t + 1.0))) / Float64(-1.0 - t))) / Float64(6.0 + Float64(2.0 / Float64(Float64(t * -0.25) - 0.375))))
end
function tmp = code(t)
	tmp = (5.0 + ((8.0 + (-4.0 / (t + 1.0))) / (-1.0 - t))) / (6.0 + (2.0 / ((t * -0.25) - 0.375)));
end
code[t_] := N[(N[(5.0 + N[(N[(8.0 + N[(-4.0 / N[(t + 1.0), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] / N[(-1.0 - t), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] / N[(6.0 + N[(2.0 / N[(N[(t * -0.25), $MachinePrecision] - 0.375), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
\frac{5 + \frac{8 + \frac{-4}{t + 1}}{-1 - t}}{6 + \frac{2}{t \cdot -0.25 - 0.375}}
\end{array}
Derivation
  1. Initial program 100.0%

    \[\frac{1 + \left(2 - \frac{\frac{2}{t}}{1 + \frac{1}{t}}\right) \cdot \left(2 - \frac{\frac{2}{t}}{1 + \frac{1}{t}}\right)}{2 + \left(2 - \frac{\frac{2}{t}}{1 + \frac{1}{t}}\right) \cdot \left(2 - \frac{\frac{2}{t}}{1 + \frac{1}{t}}\right)} \]
  2. Simplified100.0%

    \[\leadsto \color{blue}{\frac{5 + \frac{2}{1 + t} \cdot \left(\frac{2}{1 + t} - 4\right)}{6 + \frac{2}{1 + t} \cdot \left(\frac{2}{1 + t} - 4\right)}} \]
  3. Add Preprocessing
  4. Step-by-step derivation
    1. associate-*l/100.0%

      \[\leadsto \frac{5 + \frac{2}{1 + t} \cdot \left(\frac{2}{1 + t} - 4\right)}{6 + \color{blue}{\frac{2 \cdot \left(\frac{2}{1 + t} - 4\right)}{1 + t}}} \]
    2. associate-/l*100.0%

      \[\leadsto \frac{5 + \frac{2}{1 + t} \cdot \left(\frac{2}{1 + t} - 4\right)}{6 + \color{blue}{\frac{2}{\frac{1 + t}{\frac{2}{1 + t} - 4}}}} \]
    3. +-commutative100.0%

      \[\leadsto \frac{5 + \frac{2}{1 + t} \cdot \left(\frac{2}{1 + t} - 4\right)}{6 + \frac{2}{\frac{\color{blue}{t + 1}}{\frac{2}{1 + t} - 4}}} \]
    4. sub-neg100.0%

      \[\leadsto \frac{5 + \frac{2}{1 + t} \cdot \left(\frac{2}{1 + t} - 4\right)}{6 + \frac{2}{\frac{t + 1}{\color{blue}{\frac{2}{1 + t} + \left(-4\right)}}}} \]
    5. +-commutative100.0%

      \[\leadsto \frac{5 + \frac{2}{1 + t} \cdot \left(\frac{2}{1 + t} - 4\right)}{6 + \frac{2}{\frac{t + 1}{\frac{2}{\color{blue}{t + 1}} + \left(-4\right)}}} \]
    6. metadata-eval100.0%

      \[\leadsto \frac{5 + \frac{2}{1 + t} \cdot \left(\frac{2}{1 + t} - 4\right)}{6 + \frac{2}{\frac{t + 1}{\frac{2}{t + 1} + \color{blue}{-4}}}} \]
  5. Applied egg-rr100.0%

    \[\leadsto \frac{5 + \frac{2}{1 + t} \cdot \left(\frac{2}{1 + t} - 4\right)}{6 + \color{blue}{\frac{2}{\frac{t + 1}{\frac{2}{t + 1} + -4}}}} \]
  6. Taylor expanded in t around inf 58.9%

    \[\leadsto \frac{5 + \frac{2}{1 + t} \cdot \left(\frac{2}{1 + t} - 4\right)}{6 + \frac{2}{\color{blue}{-0.25 \cdot t - 0.375}}} \]
  7. Step-by-step derivation
    1. associate-*l/58.9%

      \[\leadsto \frac{5 + \color{blue}{\frac{2 \cdot \left(\frac{2}{1 + t} - 4\right)}{1 + t}}}{6 + \frac{2}{-0.25 \cdot t - 0.375}} \]
    2. frac-2neg58.9%

      \[\leadsto \frac{5 + \color{blue}{\frac{-2 \cdot \left(\frac{2}{1 + t} - 4\right)}{-\left(1 + t\right)}}}{6 + \frac{2}{-0.25 \cdot t - 0.375}} \]
    3. sub-neg58.9%

      \[\leadsto \frac{5 + \frac{-2 \cdot \color{blue}{\left(\frac{2}{1 + t} + \left(-4\right)\right)}}{-\left(1 + t\right)}}{6 + \frac{2}{-0.25 \cdot t - 0.375}} \]
    4. distribute-lft-in58.9%

      \[\leadsto \frac{5 + \frac{-\color{blue}{\left(2 \cdot \frac{2}{1 + t} + 2 \cdot \left(-4\right)\right)}}{-\left(1 + t\right)}}{6 + \frac{2}{-0.25 \cdot t - 0.375}} \]
    5. +-commutative58.9%

      \[\leadsto \frac{5 + \frac{-\left(2 \cdot \frac{2}{\color{blue}{t + 1}} + 2 \cdot \left(-4\right)\right)}{-\left(1 + t\right)}}{6 + \frac{2}{-0.25 \cdot t - 0.375}} \]
    6. metadata-eval58.9%

      \[\leadsto \frac{5 + \frac{-\left(2 \cdot \frac{2}{t + 1} + 2 \cdot \color{blue}{-4}\right)}{-\left(1 + t\right)}}{6 + \frac{2}{-0.25 \cdot t - 0.375}} \]
    7. metadata-eval58.9%

      \[\leadsto \frac{5 + \frac{-\left(2 \cdot \frac{2}{t + 1} + \color{blue}{-8}\right)}{-\left(1 + t\right)}}{6 + \frac{2}{-0.25 \cdot t - 0.375}} \]
    8. distribute-neg-in58.9%

      \[\leadsto \frac{5 + \frac{-\left(2 \cdot \frac{2}{t + 1} + -8\right)}{\color{blue}{\left(-1\right) + \left(-t\right)}}}{6 + \frac{2}{-0.25 \cdot t - 0.375}} \]
    9. metadata-eval58.9%

      \[\leadsto \frac{5 + \frac{-\left(2 \cdot \frac{2}{t + 1} + -8\right)}{\color{blue}{-1} + \left(-t\right)}}{6 + \frac{2}{-0.25 \cdot t - 0.375}} \]
  8. Applied egg-rr58.9%

    \[\leadsto \frac{5 + \color{blue}{\frac{-\left(2 \cdot \frac{2}{t + 1} + -8\right)}{-1 + \left(-t\right)}}}{6 + \frac{2}{-0.25 \cdot t - 0.375}} \]
  9. Step-by-step derivation
    1. +-commutative58.9%

      \[\leadsto \frac{5 + \frac{-\color{blue}{\left(-8 + 2 \cdot \frac{2}{t + 1}\right)}}{-1 + \left(-t\right)}}{6 + \frac{2}{-0.25 \cdot t - 0.375}} \]
    2. distribute-neg-in58.9%

      \[\leadsto \frac{5 + \frac{\color{blue}{\left(--8\right) + \left(-2 \cdot \frac{2}{t + 1}\right)}}{-1 + \left(-t\right)}}{6 + \frac{2}{-0.25 \cdot t - 0.375}} \]
    3. metadata-eval58.9%

      \[\leadsto \frac{5 + \frac{\color{blue}{8} + \left(-2 \cdot \frac{2}{t + 1}\right)}{-1 + \left(-t\right)}}{6 + \frac{2}{-0.25 \cdot t - 0.375}} \]
    4. associate-*r/58.9%

      \[\leadsto \frac{5 + \frac{8 + \left(-\color{blue}{\frac{2 \cdot 2}{t + 1}}\right)}{-1 + \left(-t\right)}}{6 + \frac{2}{-0.25 \cdot t - 0.375}} \]
    5. metadata-eval58.9%

      \[\leadsto \frac{5 + \frac{8 + \left(-\frac{\color{blue}{4}}{t + 1}\right)}{-1 + \left(-t\right)}}{6 + \frac{2}{-0.25 \cdot t - 0.375}} \]
    6. distribute-neg-frac58.9%

      \[\leadsto \frac{5 + \frac{8 + \color{blue}{\frac{-4}{t + 1}}}{-1 + \left(-t\right)}}{6 + \frac{2}{-0.25 \cdot t - 0.375}} \]
    7. metadata-eval58.9%

      \[\leadsto \frac{5 + \frac{8 + \frac{\color{blue}{-4}}{t + 1}}{-1 + \left(-t\right)}}{6 + \frac{2}{-0.25 \cdot t - 0.375}} \]
    8. unsub-neg58.9%

      \[\leadsto \frac{5 + \frac{8 + \frac{-4}{t + 1}}{\color{blue}{-1 - t}}}{6 + \frac{2}{-0.25 \cdot t - 0.375}} \]
  10. Simplified58.9%

    \[\leadsto \frac{5 + \color{blue}{\frac{8 + \frac{-4}{t + 1}}{-1 - t}}}{6 + \frac{2}{-0.25 \cdot t - 0.375}} \]
  11. Final simplification58.9%

    \[\leadsto \frac{5 + \frac{8 + \frac{-4}{t + 1}}{-1 - t}}{6 + \frac{2}{t \cdot -0.25 - 0.375}} \]
  12. Add Preprocessing

Alternative 3: 49.9% accurate, 10.2× speedup?

\[\begin{array}{l} \\ 0.8333333333333334 - \frac{0.2222222222222222}{t} \end{array} \]
(FPCore (t)
 :precision binary64
 (- 0.8333333333333334 (/ 0.2222222222222222 t)))
double code(double t) {
	return 0.8333333333333334 - (0.2222222222222222 / t);
}
real(8) function code(t)
    real(8), intent (in) :: t
    code = 0.8333333333333334d0 - (0.2222222222222222d0 / t)
end function
public static double code(double t) {
	return 0.8333333333333334 - (0.2222222222222222 / t);
}
def code(t):
	return 0.8333333333333334 - (0.2222222222222222 / t)
function code(t)
	return Float64(0.8333333333333334 - Float64(0.2222222222222222 / t))
end
function tmp = code(t)
	tmp = 0.8333333333333334 - (0.2222222222222222 / t);
end
code[t_] := N[(0.8333333333333334 - N[(0.2222222222222222 / t), $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
0.8333333333333334 - \frac{0.2222222222222222}{t}
\end{array}
Derivation
  1. Initial program 100.0%

    \[\frac{1 + \left(2 - \frac{\frac{2}{t}}{1 + \frac{1}{t}}\right) \cdot \left(2 - \frac{\frac{2}{t}}{1 + \frac{1}{t}}\right)}{2 + \left(2 - \frac{\frac{2}{t}}{1 + \frac{1}{t}}\right) \cdot \left(2 - \frac{\frac{2}{t}}{1 + \frac{1}{t}}\right)} \]
  2. Add Preprocessing
  3. Taylor expanded in t around inf 51.4%

    \[\leadsto \color{blue}{0.8333333333333334 - 0.2222222222222222 \cdot \frac{1}{t}} \]
  4. Step-by-step derivation
    1. associate-*r/51.4%

      \[\leadsto 0.8333333333333334 - \color{blue}{\frac{0.2222222222222222 \cdot 1}{t}} \]
    2. metadata-eval51.4%

      \[\leadsto 0.8333333333333334 - \frac{\color{blue}{0.2222222222222222}}{t} \]
  5. Simplified51.4%

    \[\leadsto \color{blue}{0.8333333333333334 - \frac{0.2222222222222222}{t}} \]
  6. Final simplification51.4%

    \[\leadsto 0.8333333333333334 - \frac{0.2222222222222222}{t} \]
  7. Add Preprocessing

Alternative 4: 60.3% accurate, 51.0× speedup?

\[\begin{array}{l} \\ 0.5 \end{array} \]
(FPCore (t) :precision binary64 0.5)
double code(double t) {
	return 0.5;
}
real(8) function code(t)
    real(8), intent (in) :: t
    code = 0.5d0
end function
public static double code(double t) {
	return 0.5;
}
def code(t):
	return 0.5
function code(t)
	return 0.5
end
function tmp = code(t)
	tmp = 0.5;
end
code[t_] := 0.5
\begin{array}{l}

\\
0.5
\end{array}
Derivation
  1. Initial program 100.0%

    \[\frac{1 + \left(2 - \frac{\frac{2}{t}}{1 + \frac{1}{t}}\right) \cdot \left(2 - \frac{\frac{2}{t}}{1 + \frac{1}{t}}\right)}{2 + \left(2 - \frac{\frac{2}{t}}{1 + \frac{1}{t}}\right) \cdot \left(2 - \frac{\frac{2}{t}}{1 + \frac{1}{t}}\right)} \]
  2. Add Preprocessing
  3. Taylor expanded in t around 0 59.2%

    \[\leadsto \color{blue}{0.5} \]
  4. Final simplification59.2%

    \[\leadsto 0.5 \]
  5. Add Preprocessing

Alternative 5: 57.8% accurate, 51.0× speedup?

\[\begin{array}{l} \\ 0.8333333333333334 \end{array} \]
(FPCore (t) :precision binary64 0.8333333333333334)
double code(double t) {
	return 0.8333333333333334;
}
real(8) function code(t)
    real(8), intent (in) :: t
    code = 0.8333333333333334d0
end function
public static double code(double t) {
	return 0.8333333333333334;
}
def code(t):
	return 0.8333333333333334
function code(t)
	return 0.8333333333333334
end
function tmp = code(t)
	tmp = 0.8333333333333334;
end
code[t_] := 0.8333333333333334
\begin{array}{l}

\\
0.8333333333333334
\end{array}
Derivation
  1. Initial program 100.0%

    \[\frac{1 + \left(2 - \frac{\frac{2}{t}}{1 + \frac{1}{t}}\right) \cdot \left(2 - \frac{\frac{2}{t}}{1 + \frac{1}{t}}\right)}{2 + \left(2 - \frac{\frac{2}{t}}{1 + \frac{1}{t}}\right) \cdot \left(2 - \frac{\frac{2}{t}}{1 + \frac{1}{t}}\right)} \]
  2. Add Preprocessing
  3. Taylor expanded in t around inf 59.0%

    \[\leadsto \color{blue}{0.8333333333333334} \]
  4. Final simplification59.0%

    \[\leadsto 0.8333333333333334 \]
  5. Add Preprocessing

Reproduce

?
herbie shell --seed 2024033 
(FPCore (t)
  :name "Kahan p13 Example 2"
  :precision binary64
  (/ (+ 1.0 (* (- 2.0 (/ (/ 2.0 t) (+ 1.0 (/ 1.0 t)))) (- 2.0 (/ (/ 2.0 t) (+ 1.0 (/ 1.0 t)))))) (+ 2.0 (* (- 2.0 (/ (/ 2.0 t) (+ 1.0 (/ 1.0 t)))) (- 2.0 (/ (/ 2.0 t) (+ 1.0 (/ 1.0 t))))))))