Given's Rotation SVD example

Percentage Accurate: 79.7% → 99.7%
Time: 7.3s
Alternatives: 5
Speedup: 0.7×

Specification

?
\[10^{-150} < \left|x\right| \land \left|x\right| < 10^{+150}\]
\[\begin{array}{l} \\ \sqrt{0.5 \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)} \end{array} \]
(FPCore (p x)
 :precision binary64
 (sqrt (* 0.5 (+ 1.0 (/ x (sqrt (+ (* (* 4.0 p) p) (* x x))))))))
double code(double p, double x) {
	return sqrt((0.5 * (1.0 + (x / sqrt((((4.0 * p) * p) + (x * x)))))));
}
real(8) function code(p, x)
    real(8), intent (in) :: p
    real(8), intent (in) :: x
    code = sqrt((0.5d0 * (1.0d0 + (x / sqrt((((4.0d0 * p) * p) + (x * x)))))))
end function
public static double code(double p, double x) {
	return Math.sqrt((0.5 * (1.0 + (x / Math.sqrt((((4.0 * p) * p) + (x * x)))))));
}
def code(p, x):
	return math.sqrt((0.5 * (1.0 + (x / math.sqrt((((4.0 * p) * p) + (x * x)))))))
function code(p, x)
	return sqrt(Float64(0.5 * Float64(1.0 + Float64(x / sqrt(Float64(Float64(Float64(4.0 * p) * p) + Float64(x * x)))))))
end
function tmp = code(p, x)
	tmp = sqrt((0.5 * (1.0 + (x / sqrt((((4.0 * p) * p) + (x * x)))))));
end
code[p_, x_] := N[Sqrt[N[(0.5 * N[(1.0 + N[(x / N[Sqrt[N[(N[(N[(4.0 * p), $MachinePrecision] * p), $MachinePrecision] + N[(x * x), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]
\begin{array}{l}

\\
\sqrt{0.5 \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)}
\end{array}

Sampling outcomes in binary64 precision:

Local Percentage Accuracy vs ?

The average percentage accuracy by input value. Horizontal axis shows value of an input variable; the variable is choosen in the title. Vertical axis is accuracy; higher is better. Red represent the original program, while blue represents Herbie's suggestion. These can be toggled with buttons below the plot. The line is an average while dots represent individual samples.

Accuracy vs Speed?

Herbie found 5 alternatives:

AlternativeAccuracySpeedup
The accuracy (vertical axis) and speed (horizontal axis) of each alternatives. Up and to the right is better. The red square shows the initial program, and each blue circle shows an alternative.The line shows the best available speed-accuracy tradeoffs.

Initial Program: 79.7% accurate, 1.0× speedup?

\[\begin{array}{l} \\ \sqrt{0.5 \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)} \end{array} \]
(FPCore (p x)
 :precision binary64
 (sqrt (* 0.5 (+ 1.0 (/ x (sqrt (+ (* (* 4.0 p) p) (* x x))))))))
double code(double p, double x) {
	return sqrt((0.5 * (1.0 + (x / sqrt((((4.0 * p) * p) + (x * x)))))));
}
real(8) function code(p, x)
    real(8), intent (in) :: p
    real(8), intent (in) :: x
    code = sqrt((0.5d0 * (1.0d0 + (x / sqrt((((4.0d0 * p) * p) + (x * x)))))))
end function
public static double code(double p, double x) {
	return Math.sqrt((0.5 * (1.0 + (x / Math.sqrt((((4.0 * p) * p) + (x * x)))))));
}
def code(p, x):
	return math.sqrt((0.5 * (1.0 + (x / math.sqrt((((4.0 * p) * p) + (x * x)))))))
function code(p, x)
	return sqrt(Float64(0.5 * Float64(1.0 + Float64(x / sqrt(Float64(Float64(Float64(4.0 * p) * p) + Float64(x * x)))))))
end
function tmp = code(p, x)
	tmp = sqrt((0.5 * (1.0 + (x / sqrt((((4.0 * p) * p) + (x * x)))))));
end
code[p_, x_] := N[Sqrt[N[(0.5 * N[(1.0 + N[(x / N[Sqrt[N[(N[(N[(4.0 * p), $MachinePrecision] * p), $MachinePrecision] + N[(x * x), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]
\begin{array}{l}

\\
\sqrt{0.5 \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)}
\end{array}

Alternative 1: 99.7% accurate, 0.7× speedup?

\[\begin{array}{l} p_m = \left|p\right| \\ \begin{array}{l} \mathbf{if}\;\frac{x}{\sqrt{p\_m \cdot \left(4 \cdot p\_m\right) + x \cdot x}} \leq -0.5:\\ \;\;\;\;\frac{-p\_m}{x}\\ \mathbf{else}:\\ \;\;\;\;\sqrt{0.5 \cdot \left(1 + \frac{x}{\mathsf{hypot}\left(p\_m \cdot 2, x\right)}\right)}\\ \end{array} \end{array} \]
p_m = (fabs.f64 p)
(FPCore (p_m x)
 :precision binary64
 (if (<= (/ x (sqrt (+ (* p_m (* 4.0 p_m)) (* x x)))) -0.5)
   (/ (- p_m) x)
   (sqrt (* 0.5 (+ 1.0 (/ x (hypot (* p_m 2.0) x)))))))
p_m = fabs(p);
double code(double p_m, double x) {
	double tmp;
	if ((x / sqrt(((p_m * (4.0 * p_m)) + (x * x)))) <= -0.5) {
		tmp = -p_m / x;
	} else {
		tmp = sqrt((0.5 * (1.0 + (x / hypot((p_m * 2.0), x)))));
	}
	return tmp;
}
p_m = Math.abs(p);
public static double code(double p_m, double x) {
	double tmp;
	if ((x / Math.sqrt(((p_m * (4.0 * p_m)) + (x * x)))) <= -0.5) {
		tmp = -p_m / x;
	} else {
		tmp = Math.sqrt((0.5 * (1.0 + (x / Math.hypot((p_m * 2.0), x)))));
	}
	return tmp;
}
p_m = math.fabs(p)
def code(p_m, x):
	tmp = 0
	if (x / math.sqrt(((p_m * (4.0 * p_m)) + (x * x)))) <= -0.5:
		tmp = -p_m / x
	else:
		tmp = math.sqrt((0.5 * (1.0 + (x / math.hypot((p_m * 2.0), x)))))
	return tmp
p_m = abs(p)
function code(p_m, x)
	tmp = 0.0
	if (Float64(x / sqrt(Float64(Float64(p_m * Float64(4.0 * p_m)) + Float64(x * x)))) <= -0.5)
		tmp = Float64(Float64(-p_m) / x);
	else
		tmp = sqrt(Float64(0.5 * Float64(1.0 + Float64(x / hypot(Float64(p_m * 2.0), x)))));
	end
	return tmp
end
p_m = abs(p);
function tmp_2 = code(p_m, x)
	tmp = 0.0;
	if ((x / sqrt(((p_m * (4.0 * p_m)) + (x * x)))) <= -0.5)
		tmp = -p_m / x;
	else
		tmp = sqrt((0.5 * (1.0 + (x / hypot((p_m * 2.0), x)))));
	end
	tmp_2 = tmp;
end
p_m = N[Abs[p], $MachinePrecision]
code[p$95$m_, x_] := If[LessEqual[N[(x / N[Sqrt[N[(N[(p$95$m * N[(4.0 * p$95$m), $MachinePrecision]), $MachinePrecision] + N[(x * x), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision], -0.5], N[((-p$95$m) / x), $MachinePrecision], N[Sqrt[N[(0.5 * N[(1.0 + N[(x / N[Sqrt[N[(p$95$m * 2.0), $MachinePrecision] ^ 2 + x ^ 2], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]]
\begin{array}{l}
p_m = \left|p\right|

\\
\begin{array}{l}
\mathbf{if}\;\frac{x}{\sqrt{p\_m \cdot \left(4 \cdot p\_m\right) + x \cdot x}} \leq -0.5:\\
\;\;\;\;\frac{-p\_m}{x}\\

\mathbf{else}:\\
\;\;\;\;\sqrt{0.5 \cdot \left(1 + \frac{x}{\mathsf{hypot}\left(p\_m \cdot 2, x\right)}\right)}\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if (/.f64 x (sqrt.f64 (+.f64 (*.f64 (*.f64 4 p) p) (*.f64 x x)))) < -0.5

    1. Initial program 16.5%

      \[\sqrt{0.5 \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)} \]
    2. Add Preprocessing
    3. Taylor expanded in x around -inf 45.9%

      \[\leadsto \sqrt{0.5 \cdot \color{blue}{\left(2 \cdot \frac{{p}^{2}}{{x}^{2}}\right)}} \]
    4. Taylor expanded in p around -inf 52.5%

      \[\leadsto \color{blue}{-1 \cdot \frac{p}{x}} \]
    5. Step-by-step derivation
      1. associate-*r/52.5%

        \[\leadsto \color{blue}{\frac{-1 \cdot p}{x}} \]
      2. mul-1-neg52.5%

        \[\leadsto \frac{\color{blue}{-p}}{x} \]
    6. Simplified52.5%

      \[\leadsto \color{blue}{\frac{-p}{x}} \]

    if -0.5 < (/.f64 x (sqrt.f64 (+.f64 (*.f64 (*.f64 4 p) p) (*.f64 x x))))

    1. Initial program 100.0%

      \[\sqrt{0.5 \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)} \]
    2. Add Preprocessing
    3. Step-by-step derivation
      1. add-sqr-sqrt100.0%

        \[\leadsto \sqrt{0.5 \cdot \left(1 + \frac{x}{\sqrt{\color{blue}{\sqrt{\left(4 \cdot p\right) \cdot p} \cdot \sqrt{\left(4 \cdot p\right) \cdot p}} + x \cdot x}}\right)} \]
      2. hypot-def100.0%

        \[\leadsto \sqrt{0.5 \cdot \left(1 + \frac{x}{\color{blue}{\mathsf{hypot}\left(\sqrt{\left(4 \cdot p\right) \cdot p}, x\right)}}\right)} \]
      3. associate-*l*100.0%

        \[\leadsto \sqrt{0.5 \cdot \left(1 + \frac{x}{\mathsf{hypot}\left(\sqrt{\color{blue}{4 \cdot \left(p \cdot p\right)}}, x\right)}\right)} \]
      4. sqrt-prod100.0%

        \[\leadsto \sqrt{0.5 \cdot \left(1 + \frac{x}{\mathsf{hypot}\left(\color{blue}{\sqrt{4} \cdot \sqrt{p \cdot p}}, x\right)}\right)} \]
      5. metadata-eval100.0%

        \[\leadsto \sqrt{0.5 \cdot \left(1 + \frac{x}{\mathsf{hypot}\left(\color{blue}{2} \cdot \sqrt{p \cdot p}, x\right)}\right)} \]
      6. sqrt-unprod48.0%

        \[\leadsto \sqrt{0.5 \cdot \left(1 + \frac{x}{\mathsf{hypot}\left(2 \cdot \color{blue}{\left(\sqrt{p} \cdot \sqrt{p}\right)}, x\right)}\right)} \]
      7. add-sqr-sqrt100.0%

        \[\leadsto \sqrt{0.5 \cdot \left(1 + \frac{x}{\mathsf{hypot}\left(2 \cdot \color{blue}{p}, x\right)}\right)} \]
    4. Applied egg-rr100.0%

      \[\leadsto \sqrt{0.5 \cdot \left(1 + \frac{x}{\color{blue}{\mathsf{hypot}\left(2 \cdot p, x\right)}}\right)} \]
  3. Recombined 2 regimes into one program.
  4. Final simplification88.9%

    \[\leadsto \begin{array}{l} \mathbf{if}\;\frac{x}{\sqrt{p \cdot \left(4 \cdot p\right) + x \cdot x}} \leq -0.5:\\ \;\;\;\;\frac{-p}{x}\\ \mathbf{else}:\\ \;\;\;\;\sqrt{0.5 \cdot \left(1 + \frac{x}{\mathsf{hypot}\left(p \cdot 2, x\right)}\right)}\\ \end{array} \]
  5. Add Preprocessing

Alternative 2: 69.3% accurate, 1.6× speedup?

\[\begin{array}{l} p_m = \left|p\right| \\ \begin{array}{l} t_0 := \frac{-p\_m}{x}\\ \mathbf{if}\;p\_m \leq 7.8 \cdot 10^{-305}:\\ \;\;\;\;t\_0\\ \mathbf{elif}\;p\_m \leq 2.8 \cdot 10^{-262}:\\ \;\;\;\;1\\ \mathbf{elif}\;p\_m \leq 3.3 \cdot 10^{-184}:\\ \;\;\;\;t\_0\\ \mathbf{elif}\;p\_m \leq 1.56 \cdot 10^{-132}:\\ \;\;\;\;1\\ \mathbf{elif}\;p\_m \leq 1.6 \cdot 10^{-115}:\\ \;\;\;\;t\_0\\ \mathbf{elif}\;p\_m \leq 1.46 \cdot 10^{-58}:\\ \;\;\;\;1\\ \mathbf{else}:\\ \;\;\;\;\sqrt{0.5}\\ \end{array} \end{array} \]
p_m = (fabs.f64 p)
(FPCore (p_m x)
 :precision binary64
 (let* ((t_0 (/ (- p_m) x)))
   (if (<= p_m 7.8e-305)
     t_0
     (if (<= p_m 2.8e-262)
       1.0
       (if (<= p_m 3.3e-184)
         t_0
         (if (<= p_m 1.56e-132)
           1.0
           (if (<= p_m 1.6e-115)
             t_0
             (if (<= p_m 1.46e-58) 1.0 (sqrt 0.5)))))))))
p_m = fabs(p);
double code(double p_m, double x) {
	double t_0 = -p_m / x;
	double tmp;
	if (p_m <= 7.8e-305) {
		tmp = t_0;
	} else if (p_m <= 2.8e-262) {
		tmp = 1.0;
	} else if (p_m <= 3.3e-184) {
		tmp = t_0;
	} else if (p_m <= 1.56e-132) {
		tmp = 1.0;
	} else if (p_m <= 1.6e-115) {
		tmp = t_0;
	} else if (p_m <= 1.46e-58) {
		tmp = 1.0;
	} else {
		tmp = sqrt(0.5);
	}
	return tmp;
}
p_m = abs(p)
real(8) function code(p_m, x)
    real(8), intent (in) :: p_m
    real(8), intent (in) :: x
    real(8) :: t_0
    real(8) :: tmp
    t_0 = -p_m / x
    if (p_m <= 7.8d-305) then
        tmp = t_0
    else if (p_m <= 2.8d-262) then
        tmp = 1.0d0
    else if (p_m <= 3.3d-184) then
        tmp = t_0
    else if (p_m <= 1.56d-132) then
        tmp = 1.0d0
    else if (p_m <= 1.6d-115) then
        tmp = t_0
    else if (p_m <= 1.46d-58) then
        tmp = 1.0d0
    else
        tmp = sqrt(0.5d0)
    end if
    code = tmp
end function
p_m = Math.abs(p);
public static double code(double p_m, double x) {
	double t_0 = -p_m / x;
	double tmp;
	if (p_m <= 7.8e-305) {
		tmp = t_0;
	} else if (p_m <= 2.8e-262) {
		tmp = 1.0;
	} else if (p_m <= 3.3e-184) {
		tmp = t_0;
	} else if (p_m <= 1.56e-132) {
		tmp = 1.0;
	} else if (p_m <= 1.6e-115) {
		tmp = t_0;
	} else if (p_m <= 1.46e-58) {
		tmp = 1.0;
	} else {
		tmp = Math.sqrt(0.5);
	}
	return tmp;
}
p_m = math.fabs(p)
def code(p_m, x):
	t_0 = -p_m / x
	tmp = 0
	if p_m <= 7.8e-305:
		tmp = t_0
	elif p_m <= 2.8e-262:
		tmp = 1.0
	elif p_m <= 3.3e-184:
		tmp = t_0
	elif p_m <= 1.56e-132:
		tmp = 1.0
	elif p_m <= 1.6e-115:
		tmp = t_0
	elif p_m <= 1.46e-58:
		tmp = 1.0
	else:
		tmp = math.sqrt(0.5)
	return tmp
p_m = abs(p)
function code(p_m, x)
	t_0 = Float64(Float64(-p_m) / x)
	tmp = 0.0
	if (p_m <= 7.8e-305)
		tmp = t_0;
	elseif (p_m <= 2.8e-262)
		tmp = 1.0;
	elseif (p_m <= 3.3e-184)
		tmp = t_0;
	elseif (p_m <= 1.56e-132)
		tmp = 1.0;
	elseif (p_m <= 1.6e-115)
		tmp = t_0;
	elseif (p_m <= 1.46e-58)
		tmp = 1.0;
	else
		tmp = sqrt(0.5);
	end
	return tmp
end
p_m = abs(p);
function tmp_2 = code(p_m, x)
	t_0 = -p_m / x;
	tmp = 0.0;
	if (p_m <= 7.8e-305)
		tmp = t_0;
	elseif (p_m <= 2.8e-262)
		tmp = 1.0;
	elseif (p_m <= 3.3e-184)
		tmp = t_0;
	elseif (p_m <= 1.56e-132)
		tmp = 1.0;
	elseif (p_m <= 1.6e-115)
		tmp = t_0;
	elseif (p_m <= 1.46e-58)
		tmp = 1.0;
	else
		tmp = sqrt(0.5);
	end
	tmp_2 = tmp;
end
p_m = N[Abs[p], $MachinePrecision]
code[p$95$m_, x_] := Block[{t$95$0 = N[((-p$95$m) / x), $MachinePrecision]}, If[LessEqual[p$95$m, 7.8e-305], t$95$0, If[LessEqual[p$95$m, 2.8e-262], 1.0, If[LessEqual[p$95$m, 3.3e-184], t$95$0, If[LessEqual[p$95$m, 1.56e-132], 1.0, If[LessEqual[p$95$m, 1.6e-115], t$95$0, If[LessEqual[p$95$m, 1.46e-58], 1.0, N[Sqrt[0.5], $MachinePrecision]]]]]]]]
\begin{array}{l}
p_m = \left|p\right|

\\
\begin{array}{l}
t_0 := \frac{-p\_m}{x}\\
\mathbf{if}\;p\_m \leq 7.8 \cdot 10^{-305}:\\
\;\;\;\;t\_0\\

\mathbf{elif}\;p\_m \leq 2.8 \cdot 10^{-262}:\\
\;\;\;\;1\\

\mathbf{elif}\;p\_m \leq 3.3 \cdot 10^{-184}:\\
\;\;\;\;t\_0\\

\mathbf{elif}\;p\_m \leq 1.56 \cdot 10^{-132}:\\
\;\;\;\;1\\

\mathbf{elif}\;p\_m \leq 1.6 \cdot 10^{-115}:\\
\;\;\;\;t\_0\\

\mathbf{elif}\;p\_m \leq 1.46 \cdot 10^{-58}:\\
\;\;\;\;1\\

\mathbf{else}:\\
\;\;\;\;\sqrt{0.5}\\


\end{array}
\end{array}
Derivation
  1. Split input into 3 regimes
  2. if p < 7.8000000000000005e-305 or 2.79999999999999975e-262 < p < 3.2999999999999997e-184 or 1.56000000000000012e-132 < p < 1.6e-115

    1. Initial program 73.3%

      \[\sqrt{0.5 \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)} \]
    2. Add Preprocessing
    3. Taylor expanded in x around -inf 15.2%

      \[\leadsto \sqrt{0.5 \cdot \color{blue}{\left(2 \cdot \frac{{p}^{2}}{{x}^{2}}\right)}} \]
    4. Taylor expanded in p around -inf 15.2%

      \[\leadsto \color{blue}{-1 \cdot \frac{p}{x}} \]
    5. Step-by-step derivation
      1. associate-*r/15.2%

        \[\leadsto \color{blue}{\frac{-1 \cdot p}{x}} \]
      2. mul-1-neg15.2%

        \[\leadsto \frac{\color{blue}{-p}}{x} \]
    6. Simplified15.2%

      \[\leadsto \color{blue}{\frac{-p}{x}} \]

    if 7.8000000000000005e-305 < p < 2.79999999999999975e-262 or 3.2999999999999997e-184 < p < 1.56000000000000012e-132 or 1.6e-115 < p < 1.4600000000000001e-58

    1. Initial program 84.7%

      \[\sqrt{0.5 \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)} \]
    2. Add Preprocessing
    3. Taylor expanded in x around inf 66.2%

      \[\leadsto \sqrt{0.5 \cdot \color{blue}{2}} \]

    if 1.4600000000000001e-58 < p

    1. Initial program 94.5%

      \[\sqrt{0.5 \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)} \]
    2. Add Preprocessing
    3. Taylor expanded in x around 0 89.0%

      \[\leadsto \color{blue}{\sqrt{0.5}} \]
  3. Recombined 3 regimes into one program.
  4. Final simplification41.3%

    \[\leadsto \begin{array}{l} \mathbf{if}\;p \leq 7.8 \cdot 10^{-305}:\\ \;\;\;\;\frac{-p}{x}\\ \mathbf{elif}\;p \leq 2.8 \cdot 10^{-262}:\\ \;\;\;\;1\\ \mathbf{elif}\;p \leq 3.3 \cdot 10^{-184}:\\ \;\;\;\;\frac{-p}{x}\\ \mathbf{elif}\;p \leq 1.56 \cdot 10^{-132}:\\ \;\;\;\;1\\ \mathbf{elif}\;p \leq 1.6 \cdot 10^{-115}:\\ \;\;\;\;\frac{-p}{x}\\ \mathbf{elif}\;p \leq 1.46 \cdot 10^{-58}:\\ \;\;\;\;1\\ \mathbf{else}:\\ \;\;\;\;\sqrt{0.5}\\ \end{array} \]
  5. Add Preprocessing

Alternative 3: 68.4% accurate, 2.0× speedup?

\[\begin{array}{l} p_m = \left|p\right| \\ \begin{array}{l} \mathbf{if}\;p\_m \leq 2.05 \cdot 10^{-63}:\\ \;\;\;\;\frac{-p\_m}{x}\\ \mathbf{else}:\\ \;\;\;\;\sqrt{0.5}\\ \end{array} \end{array} \]
p_m = (fabs.f64 p)
(FPCore (p_m x)
 :precision binary64
 (if (<= p_m 2.05e-63) (/ (- p_m) x) (sqrt 0.5)))
p_m = fabs(p);
double code(double p_m, double x) {
	double tmp;
	if (p_m <= 2.05e-63) {
		tmp = -p_m / x;
	} else {
		tmp = sqrt(0.5);
	}
	return tmp;
}
p_m = abs(p)
real(8) function code(p_m, x)
    real(8), intent (in) :: p_m
    real(8), intent (in) :: x
    real(8) :: tmp
    if (p_m <= 2.05d-63) then
        tmp = -p_m / x
    else
        tmp = sqrt(0.5d0)
    end if
    code = tmp
end function
p_m = Math.abs(p);
public static double code(double p_m, double x) {
	double tmp;
	if (p_m <= 2.05e-63) {
		tmp = -p_m / x;
	} else {
		tmp = Math.sqrt(0.5);
	}
	return tmp;
}
p_m = math.fabs(p)
def code(p_m, x):
	tmp = 0
	if p_m <= 2.05e-63:
		tmp = -p_m / x
	else:
		tmp = math.sqrt(0.5)
	return tmp
p_m = abs(p)
function code(p_m, x)
	tmp = 0.0
	if (p_m <= 2.05e-63)
		tmp = Float64(Float64(-p_m) / x);
	else
		tmp = sqrt(0.5);
	end
	return tmp
end
p_m = abs(p);
function tmp_2 = code(p_m, x)
	tmp = 0.0;
	if (p_m <= 2.05e-63)
		tmp = -p_m / x;
	else
		tmp = sqrt(0.5);
	end
	tmp_2 = tmp;
end
p_m = N[Abs[p], $MachinePrecision]
code[p$95$m_, x_] := If[LessEqual[p$95$m, 2.05e-63], N[((-p$95$m) / x), $MachinePrecision], N[Sqrt[0.5], $MachinePrecision]]
\begin{array}{l}
p_m = \left|p\right|

\\
\begin{array}{l}
\mathbf{if}\;p\_m \leq 2.05 \cdot 10^{-63}:\\
\;\;\;\;\frac{-p\_m}{x}\\

\mathbf{else}:\\
\;\;\;\;\sqrt{0.5}\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if p < 2.0499999999999999e-63

    1. Initial program 74.9%

      \[\sqrt{0.5 \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)} \]
    2. Add Preprocessing
    3. Taylor expanded in x around -inf 16.3%

      \[\leadsto \sqrt{0.5 \cdot \color{blue}{\left(2 \cdot \frac{{p}^{2}}{{x}^{2}}\right)}} \]
    4. Taylor expanded in p around -inf 17.5%

      \[\leadsto \color{blue}{-1 \cdot \frac{p}{x}} \]
    5. Step-by-step derivation
      1. associate-*r/17.5%

        \[\leadsto \color{blue}{\frac{-1 \cdot p}{x}} \]
      2. mul-1-neg17.5%

        \[\leadsto \frac{\color{blue}{-p}}{x} \]
    6. Simplified17.5%

      \[\leadsto \color{blue}{\frac{-p}{x}} \]

    if 2.0499999999999999e-63 < p

    1. Initial program 94.7%

      \[\sqrt{0.5 \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)} \]
    2. Add Preprocessing
    3. Taylor expanded in x around 0 87.0%

      \[\leadsto \color{blue}{\sqrt{0.5}} \]
  3. Recombined 2 regimes into one program.
  4. Final simplification37.0%

    \[\leadsto \begin{array}{l} \mathbf{if}\;p \leq 2.05 \cdot 10^{-63}:\\ \;\;\;\;\frac{-p}{x}\\ \mathbf{else}:\\ \;\;\;\;\sqrt{0.5}\\ \end{array} \]
  5. Add Preprocessing

Alternative 4: 28.3% accurate, 23.8× speedup?

\[\begin{array}{l} p_m = \left|p\right| \\ \begin{array}{l} \mathbf{if}\;x \leq -5 \cdot 10^{-310}:\\ \;\;\;\;\frac{-p\_m}{x}\\ \mathbf{else}:\\ \;\;\;\;\frac{p\_m}{x}\\ \end{array} \end{array} \]
p_m = (fabs.f64 p)
(FPCore (p_m x)
 :precision binary64
 (if (<= x -5e-310) (/ (- p_m) x) (/ p_m x)))
p_m = fabs(p);
double code(double p_m, double x) {
	double tmp;
	if (x <= -5e-310) {
		tmp = -p_m / x;
	} else {
		tmp = p_m / x;
	}
	return tmp;
}
p_m = abs(p)
real(8) function code(p_m, x)
    real(8), intent (in) :: p_m
    real(8), intent (in) :: x
    real(8) :: tmp
    if (x <= (-5d-310)) then
        tmp = -p_m / x
    else
        tmp = p_m / x
    end if
    code = tmp
end function
p_m = Math.abs(p);
public static double code(double p_m, double x) {
	double tmp;
	if (x <= -5e-310) {
		tmp = -p_m / x;
	} else {
		tmp = p_m / x;
	}
	return tmp;
}
p_m = math.fabs(p)
def code(p_m, x):
	tmp = 0
	if x <= -5e-310:
		tmp = -p_m / x
	else:
		tmp = p_m / x
	return tmp
p_m = abs(p)
function code(p_m, x)
	tmp = 0.0
	if (x <= -5e-310)
		tmp = Float64(Float64(-p_m) / x);
	else
		tmp = Float64(p_m / x);
	end
	return tmp
end
p_m = abs(p);
function tmp_2 = code(p_m, x)
	tmp = 0.0;
	if (x <= -5e-310)
		tmp = -p_m / x;
	else
		tmp = p_m / x;
	end
	tmp_2 = tmp;
end
p_m = N[Abs[p], $MachinePrecision]
code[p$95$m_, x_] := If[LessEqual[x, -5e-310], N[((-p$95$m) / x), $MachinePrecision], N[(p$95$m / x), $MachinePrecision]]
\begin{array}{l}
p_m = \left|p\right|

\\
\begin{array}{l}
\mathbf{if}\;x \leq -5 \cdot 10^{-310}:\\
\;\;\;\;\frac{-p\_m}{x}\\

\mathbf{else}:\\
\;\;\;\;\frac{p\_m}{x}\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if x < -4.999999999999985e-310

    1. Initial program 61.8%

      \[\sqrt{0.5 \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)} \]
    2. Add Preprocessing
    3. Taylor expanded in x around -inf 23.5%

      \[\leadsto \sqrt{0.5 \cdot \color{blue}{\left(2 \cdot \frac{{p}^{2}}{{x}^{2}}\right)}} \]
    4. Taylor expanded in p around -inf 25.5%

      \[\leadsto \color{blue}{-1 \cdot \frac{p}{x}} \]
    5. Step-by-step derivation
      1. associate-*r/25.5%

        \[\leadsto \color{blue}{\frac{-1 \cdot p}{x}} \]
      2. mul-1-neg25.5%

        \[\leadsto \frac{\color{blue}{-p}}{x} \]
    6. Simplified25.5%

      \[\leadsto \color{blue}{\frac{-p}{x}} \]

    if -4.999999999999985e-310 < x

    1. Initial program 100.0%

      \[\sqrt{0.5 \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)} \]
    2. Add Preprocessing
    3. Taylor expanded in x around -inf 5.0%

      \[\leadsto \sqrt{0.5 \cdot \color{blue}{\left(2 \cdot \frac{{p}^{2}}{{x}^{2}}\right)}} \]
    4. Taylor expanded in p around 0 3.5%

      \[\leadsto \color{blue}{\frac{p}{x}} \]
  3. Recombined 2 regimes into one program.
  4. Final simplification14.8%

    \[\leadsto \begin{array}{l} \mathbf{if}\;x \leq -5 \cdot 10^{-310}:\\ \;\;\;\;\frac{-p}{x}\\ \mathbf{else}:\\ \;\;\;\;\frac{p}{x}\\ \end{array} \]
  5. Add Preprocessing

Alternative 5: 6.4% accurate, 71.7× speedup?

\[\begin{array}{l} p_m = \left|p\right| \\ \frac{p\_m}{x} \end{array} \]
p_m = (fabs.f64 p)
(FPCore (p_m x) :precision binary64 (/ p_m x))
p_m = fabs(p);
double code(double p_m, double x) {
	return p_m / x;
}
p_m = abs(p)
real(8) function code(p_m, x)
    real(8), intent (in) :: p_m
    real(8), intent (in) :: x
    code = p_m / x
end function
p_m = Math.abs(p);
public static double code(double p_m, double x) {
	return p_m / x;
}
p_m = math.fabs(p)
def code(p_m, x):
	return p_m / x
p_m = abs(p)
function code(p_m, x)
	return Float64(p_m / x)
end
p_m = abs(p);
function tmp = code(p_m, x)
	tmp = p_m / x;
end
p_m = N[Abs[p], $MachinePrecision]
code[p$95$m_, x_] := N[(p$95$m / x), $MachinePrecision]
\begin{array}{l}
p_m = \left|p\right|

\\
\frac{p\_m}{x}
\end{array}
Derivation
  1. Initial program 80.4%

    \[\sqrt{0.5 \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)} \]
  2. Add Preprocessing
  3. Taylor expanded in x around -inf 14.4%

    \[\leadsto \sqrt{0.5 \cdot \color{blue}{\left(2 \cdot \frac{{p}^{2}}{{x}^{2}}\right)}} \]
  4. Taylor expanded in p around 0 17.1%

    \[\leadsto \color{blue}{\frac{p}{x}} \]
  5. Final simplification17.1%

    \[\leadsto \frac{p}{x} \]
  6. Add Preprocessing

Developer target: 79.7% accurate, 0.7× speedup?

\[\begin{array}{l} \\ \sqrt{0.5 + \frac{\mathsf{copysign}\left(0.5, x\right)}{\mathsf{hypot}\left(1, \frac{2 \cdot p}{x}\right)}} \end{array} \]
(FPCore (p x)
 :precision binary64
 (sqrt (+ 0.5 (/ (copysign 0.5 x) (hypot 1.0 (/ (* 2.0 p) x))))))
double code(double p, double x) {
	return sqrt((0.5 + (copysign(0.5, x) / hypot(1.0, ((2.0 * p) / x)))));
}
public static double code(double p, double x) {
	return Math.sqrt((0.5 + (Math.copySign(0.5, x) / Math.hypot(1.0, ((2.0 * p) / x)))));
}
def code(p, x):
	return math.sqrt((0.5 + (math.copysign(0.5, x) / math.hypot(1.0, ((2.0 * p) / x)))))
function code(p, x)
	return sqrt(Float64(0.5 + Float64(copysign(0.5, x) / hypot(1.0, Float64(Float64(2.0 * p) / x)))))
end
function tmp = code(p, x)
	tmp = sqrt((0.5 + ((sign(x) * abs(0.5)) / hypot(1.0, ((2.0 * p) / x)))));
end
code[p_, x_] := N[Sqrt[N[(0.5 + N[(N[With[{TMP1 = Abs[0.5], TMP2 = Sign[x]}, TMP1 * If[TMP2 == 0, 1, TMP2]], $MachinePrecision] / N[Sqrt[1.0 ^ 2 + N[(N[(2.0 * p), $MachinePrecision] / x), $MachinePrecision] ^ 2], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]
\begin{array}{l}

\\
\sqrt{0.5 + \frac{\mathsf{copysign}\left(0.5, x\right)}{\mathsf{hypot}\left(1, \frac{2 \cdot p}{x}\right)}}
\end{array}

Reproduce

?
herbie shell --seed 2024031 
(FPCore (p x)
  :name "Given's Rotation SVD example"
  :precision binary64
  :pre (and (< 1e-150 (fabs x)) (< (fabs x) 1e+150))

  :herbie-target
  (sqrt (+ 0.5 (/ (copysign 0.5 x) (hypot 1.0 (/ (* 2.0 p) x)))))

  (sqrt (* 0.5 (+ 1.0 (/ x (sqrt (+ (* (* 4.0 p) p) (* x x))))))))