ABCF->ab-angle angle

Percentage Accurate: 54.9% → 80.7%
Time: 20.7s
Alternatives: 15
Speedup: 3.6×

Specification

?
\[\begin{array}{l} \\ 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \end{array} \]
(FPCore (A B C)
 :precision binary64
 (*
  180.0
  (/
   (atan (* (/ 1.0 B) (- (- C A) (sqrt (+ (pow (- A C) 2.0) (pow B 2.0))))))
   PI)))
double code(double A, double B, double C) {
	return 180.0 * (atan(((1.0 / B) * ((C - A) - sqrt((pow((A - C), 2.0) + pow(B, 2.0)))))) / ((double) M_PI));
}
public static double code(double A, double B, double C) {
	return 180.0 * (Math.atan(((1.0 / B) * ((C - A) - Math.sqrt((Math.pow((A - C), 2.0) + Math.pow(B, 2.0)))))) / Math.PI);
}
def code(A, B, C):
	return 180.0 * (math.atan(((1.0 / B) * ((C - A) - math.sqrt((math.pow((A - C), 2.0) + math.pow(B, 2.0)))))) / math.pi)
function code(A, B, C)
	return Float64(180.0 * Float64(atan(Float64(Float64(1.0 / B) * Float64(Float64(C - A) - sqrt(Float64((Float64(A - C) ^ 2.0) + (B ^ 2.0)))))) / pi))
end
function tmp = code(A, B, C)
	tmp = 180.0 * (atan(((1.0 / B) * ((C - A) - sqrt((((A - C) ^ 2.0) + (B ^ 2.0)))))) / pi);
end
code[A_, B_, C_] := N[(180.0 * N[(N[ArcTan[N[(N[(1.0 / B), $MachinePrecision] * N[(N[(C - A), $MachinePrecision] - N[Sqrt[N[(N[Power[N[(A - C), $MachinePrecision], 2.0], $MachinePrecision] + N[Power[B, 2.0], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi}
\end{array}

Sampling outcomes in binary64 precision:

Local Percentage Accuracy vs ?

The average percentage accuracy by input value. Horizontal axis shows value of an input variable; the variable is choosen in the title. Vertical axis is accuracy; higher is better. Red represent the original program, while blue represents Herbie's suggestion. These can be toggled with buttons below the plot. The line is an average while dots represent individual samples.

Accuracy vs Speed?

Herbie found 15 alternatives:

AlternativeAccuracySpeedup
The accuracy (vertical axis) and speed (horizontal axis) of each alternatives. Up and to the right is better. The red square shows the initial program, and each blue circle shows an alternative.The line shows the best available speed-accuracy tradeoffs.

Initial Program: 54.9% accurate, 1.0× speedup?

\[\begin{array}{l} \\ 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \end{array} \]
(FPCore (A B C)
 :precision binary64
 (*
  180.0
  (/
   (atan (* (/ 1.0 B) (- (- C A) (sqrt (+ (pow (- A C) 2.0) (pow B 2.0))))))
   PI)))
double code(double A, double B, double C) {
	return 180.0 * (atan(((1.0 / B) * ((C - A) - sqrt((pow((A - C), 2.0) + pow(B, 2.0)))))) / ((double) M_PI));
}
public static double code(double A, double B, double C) {
	return 180.0 * (Math.atan(((1.0 / B) * ((C - A) - Math.sqrt((Math.pow((A - C), 2.0) + Math.pow(B, 2.0)))))) / Math.PI);
}
def code(A, B, C):
	return 180.0 * (math.atan(((1.0 / B) * ((C - A) - math.sqrt((math.pow((A - C), 2.0) + math.pow(B, 2.0)))))) / math.pi)
function code(A, B, C)
	return Float64(180.0 * Float64(atan(Float64(Float64(1.0 / B) * Float64(Float64(C - A) - sqrt(Float64((Float64(A - C) ^ 2.0) + (B ^ 2.0)))))) / pi))
end
function tmp = code(A, B, C)
	tmp = 180.0 * (atan(((1.0 / B) * ((C - A) - sqrt((((A - C) ^ 2.0) + (B ^ 2.0)))))) / pi);
end
code[A_, B_, C_] := N[(180.0 * N[(N[ArcTan[N[(N[(1.0 / B), $MachinePrecision] * N[(N[(C - A), $MachinePrecision] - N[Sqrt[N[(N[Power[N[(A - C), $MachinePrecision], 2.0], $MachinePrecision] + N[Power[B, 2.0], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi}
\end{array}

Alternative 1: 80.7% accurate, 1.9× speedup?

\[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;A \leq -2.5 \cdot 10^{+154}:\\ \;\;\;\;\frac{180}{\pi} \cdot \tan^{-1} \left(\frac{B}{\frac{A}{0.5}}\right)\\ \mathbf{else}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{C - \left(A + \mathsf{hypot}\left(B, A - C\right)\right)}{B}\right)}{\pi}\\ \end{array} \end{array} \]
(FPCore (A B C)
 :precision binary64
 (if (<= A -2.5e+154)
   (* (/ 180.0 PI) (atan (/ B (/ A 0.5))))
   (* 180.0 (/ (atan (/ (- C (+ A (hypot B (- A C)))) B)) PI))))
double code(double A, double B, double C) {
	double tmp;
	if (A <= -2.5e+154) {
		tmp = (180.0 / ((double) M_PI)) * atan((B / (A / 0.5)));
	} else {
		tmp = 180.0 * (atan(((C - (A + hypot(B, (A - C)))) / B)) / ((double) M_PI));
	}
	return tmp;
}
public static double code(double A, double B, double C) {
	double tmp;
	if (A <= -2.5e+154) {
		tmp = (180.0 / Math.PI) * Math.atan((B / (A / 0.5)));
	} else {
		tmp = 180.0 * (Math.atan(((C - (A + Math.hypot(B, (A - C)))) / B)) / Math.PI);
	}
	return tmp;
}
def code(A, B, C):
	tmp = 0
	if A <= -2.5e+154:
		tmp = (180.0 / math.pi) * math.atan((B / (A / 0.5)))
	else:
		tmp = 180.0 * (math.atan(((C - (A + math.hypot(B, (A - C)))) / B)) / math.pi)
	return tmp
function code(A, B, C)
	tmp = 0.0
	if (A <= -2.5e+154)
		tmp = Float64(Float64(180.0 / pi) * atan(Float64(B / Float64(A / 0.5))));
	else
		tmp = Float64(180.0 * Float64(atan(Float64(Float64(C - Float64(A + hypot(B, Float64(A - C)))) / B)) / pi));
	end
	return tmp
end
function tmp_2 = code(A, B, C)
	tmp = 0.0;
	if (A <= -2.5e+154)
		tmp = (180.0 / pi) * atan((B / (A / 0.5)));
	else
		tmp = 180.0 * (atan(((C - (A + hypot(B, (A - C)))) / B)) / pi);
	end
	tmp_2 = tmp;
end
code[A_, B_, C_] := If[LessEqual[A, -2.5e+154], N[(N[(180.0 / Pi), $MachinePrecision] * N[ArcTan[N[(B / N[(A / 0.5), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision], N[(180.0 * N[(N[ArcTan[N[(N[(C - N[(A + N[Sqrt[B ^ 2 + N[(A - C), $MachinePrecision] ^ 2], $MachinePrecision]), $MachinePrecision]), $MachinePrecision] / B), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision]]
\begin{array}{l}

\\
\begin{array}{l}
\mathbf{if}\;A \leq -2.5 \cdot 10^{+154}:\\
\;\;\;\;\frac{180}{\pi} \cdot \tan^{-1} \left(\frac{B}{\frac{A}{0.5}}\right)\\

\mathbf{else}:\\
\;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{C - \left(A + \mathsf{hypot}\left(B, A - C\right)\right)}{B}\right)}{\pi}\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if A < -2.50000000000000002e154

    1. Initial program 12.4%

      \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
    2. Add Preprocessing
    3. Taylor expanded in A around -inf 87.1%

      \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(0.5 \cdot \frac{B}{A}\right)}}{\pi} \]
    4. Step-by-step derivation
      1. associate-*r/87.1%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{0.5 \cdot B}{A}\right)}}{\pi} \]
    5. Simplified87.1%

      \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{0.5 \cdot B}{A}\right)}}{\pi} \]
    6. Taylor expanded in B around 0 87.1%

      \[\leadsto \color{blue}{180 \cdot \frac{\tan^{-1} \left(0.5 \cdot \frac{B}{A}\right)}{\pi}} \]
    7. Step-by-step derivation
      1. associate-*r/87.2%

        \[\leadsto \color{blue}{\frac{180 \cdot \tan^{-1} \left(0.5 \cdot \frac{B}{A}\right)}{\pi}} \]
      2. associate-/l*87.2%

        \[\leadsto \color{blue}{\frac{180}{\frac{\pi}{\tan^{-1} \left(0.5 \cdot \frac{B}{A}\right)}}} \]
      3. associate-*r/87.2%

        \[\leadsto \frac{180}{\frac{\pi}{\tan^{-1} \color{blue}{\left(\frac{0.5 \cdot B}{A}\right)}}} \]
      4. associate-/l*87.2%

        \[\leadsto \frac{180}{\frac{\pi}{\tan^{-1} \color{blue}{\left(\frac{0.5}{\frac{A}{B}}\right)}}} \]
      5. associate-/r/87.1%

        \[\leadsto \color{blue}{\frac{180}{\pi} \cdot \tan^{-1} \left(\frac{0.5}{\frac{A}{B}}\right)} \]
      6. associate-/l*87.2%

        \[\leadsto \frac{180}{\pi} \cdot \tan^{-1} \color{blue}{\left(\frac{0.5 \cdot B}{A}\right)} \]
      7. *-commutative87.2%

        \[\leadsto \frac{180}{\pi} \cdot \tan^{-1} \left(\frac{\color{blue}{B \cdot 0.5}}{A}\right) \]
      8. associate-/l*87.2%

        \[\leadsto \frac{180}{\pi} \cdot \tan^{-1} \color{blue}{\left(\frac{B}{\frac{A}{0.5}}\right)} \]
    8. Simplified87.2%

      \[\leadsto \color{blue}{\frac{180}{\pi} \cdot \tan^{-1} \left(\frac{B}{\frac{A}{0.5}}\right)} \]

    if -2.50000000000000002e154 < A

    1. Initial program 63.7%

      \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
    2. Step-by-step derivation
      1. Simplified84.3%

        \[\leadsto \color{blue}{180 \cdot \frac{\tan^{-1} \left(\frac{C - \left(A + \mathsf{hypot}\left(B, A - C\right)\right)}{B}\right)}{\pi}} \]
      2. Add Preprocessing
    3. Recombined 2 regimes into one program.
    4. Final simplification84.6%

      \[\leadsto \begin{array}{l} \mathbf{if}\;A \leq -2.5 \cdot 10^{+154}:\\ \;\;\;\;\frac{180}{\pi} \cdot \tan^{-1} \left(\frac{B}{\frac{A}{0.5}}\right)\\ \mathbf{else}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{C - \left(A + \mathsf{hypot}\left(B, A - C\right)\right)}{B}\right)}{\pi}\\ \end{array} \]
    5. Add Preprocessing

    Alternative 2: 78.5% accurate, 1.9× speedup?

    \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;C \leq -1.4 \cdot 10^{-17}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{C - \mathsf{hypot}\left(B, C\right)}{B}\right)}{\pi}\\ \mathbf{elif}\;C \leq 2 \cdot 10^{+109}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{\left(-A\right) - \mathsf{hypot}\left(B, A\right)}{B}\right)}{\pi}\\ \mathbf{else}:\\ \;\;\;\;\frac{180 \cdot \tan^{-1} \left(-0.5 \cdot \frac{B}{C}\right)}{\pi}\\ \end{array} \end{array} \]
    (FPCore (A B C)
     :precision binary64
     (if (<= C -1.4e-17)
       (* 180.0 (/ (atan (/ (- C (hypot B C)) B)) PI))
       (if (<= C 2e+109)
         (* 180.0 (/ (atan (/ (- (- A) (hypot B A)) B)) PI))
         (/ (* 180.0 (atan (* -0.5 (/ B C)))) PI))))
    double code(double A, double B, double C) {
    	double tmp;
    	if (C <= -1.4e-17) {
    		tmp = 180.0 * (atan(((C - hypot(B, C)) / B)) / ((double) M_PI));
    	} else if (C <= 2e+109) {
    		tmp = 180.0 * (atan(((-A - hypot(B, A)) / B)) / ((double) M_PI));
    	} else {
    		tmp = (180.0 * atan((-0.5 * (B / C)))) / ((double) M_PI);
    	}
    	return tmp;
    }
    
    public static double code(double A, double B, double C) {
    	double tmp;
    	if (C <= -1.4e-17) {
    		tmp = 180.0 * (Math.atan(((C - Math.hypot(B, C)) / B)) / Math.PI);
    	} else if (C <= 2e+109) {
    		tmp = 180.0 * (Math.atan(((-A - Math.hypot(B, A)) / B)) / Math.PI);
    	} else {
    		tmp = (180.0 * Math.atan((-0.5 * (B / C)))) / Math.PI;
    	}
    	return tmp;
    }
    
    def code(A, B, C):
    	tmp = 0
    	if C <= -1.4e-17:
    		tmp = 180.0 * (math.atan(((C - math.hypot(B, C)) / B)) / math.pi)
    	elif C <= 2e+109:
    		tmp = 180.0 * (math.atan(((-A - math.hypot(B, A)) / B)) / math.pi)
    	else:
    		tmp = (180.0 * math.atan((-0.5 * (B / C)))) / math.pi
    	return tmp
    
    function code(A, B, C)
    	tmp = 0.0
    	if (C <= -1.4e-17)
    		tmp = Float64(180.0 * Float64(atan(Float64(Float64(C - hypot(B, C)) / B)) / pi));
    	elseif (C <= 2e+109)
    		tmp = Float64(180.0 * Float64(atan(Float64(Float64(Float64(-A) - hypot(B, A)) / B)) / pi));
    	else
    		tmp = Float64(Float64(180.0 * atan(Float64(-0.5 * Float64(B / C)))) / pi);
    	end
    	return tmp
    end
    
    function tmp_2 = code(A, B, C)
    	tmp = 0.0;
    	if (C <= -1.4e-17)
    		tmp = 180.0 * (atan(((C - hypot(B, C)) / B)) / pi);
    	elseif (C <= 2e+109)
    		tmp = 180.0 * (atan(((-A - hypot(B, A)) / B)) / pi);
    	else
    		tmp = (180.0 * atan((-0.5 * (B / C)))) / pi;
    	end
    	tmp_2 = tmp;
    end
    
    code[A_, B_, C_] := If[LessEqual[C, -1.4e-17], N[(180.0 * N[(N[ArcTan[N[(N[(C - N[Sqrt[B ^ 2 + C ^ 2], $MachinePrecision]), $MachinePrecision] / B), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision], If[LessEqual[C, 2e+109], N[(180.0 * N[(N[ArcTan[N[(N[((-A) - N[Sqrt[B ^ 2 + A ^ 2], $MachinePrecision]), $MachinePrecision] / B), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision], N[(N[(180.0 * N[ArcTan[N[(-0.5 * N[(B / C), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] / Pi), $MachinePrecision]]]
    
    \begin{array}{l}
    
    \\
    \begin{array}{l}
    \mathbf{if}\;C \leq -1.4 \cdot 10^{-17}:\\
    \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{C - \mathsf{hypot}\left(B, C\right)}{B}\right)}{\pi}\\
    
    \mathbf{elif}\;C \leq 2 \cdot 10^{+109}:\\
    \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{\left(-A\right) - \mathsf{hypot}\left(B, A\right)}{B}\right)}{\pi}\\
    
    \mathbf{else}:\\
    \;\;\;\;\frac{180 \cdot \tan^{-1} \left(-0.5 \cdot \frac{B}{C}\right)}{\pi}\\
    
    
    \end{array}
    \end{array}
    
    Derivation
    1. Split input into 3 regimes
    2. if C < -1.3999999999999999e-17

      1. Initial program 84.4%

        \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
      2. Add Preprocessing
      3. Taylor expanded in A around 0 84.4%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{C - \sqrt{{B}^{2} + {C}^{2}}}{B}\right)}}{\pi} \]
      4. Step-by-step derivation
        1. unpow284.4%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{C - \sqrt{\color{blue}{B \cdot B} + {C}^{2}}}{B}\right)}{\pi} \]
        2. unpow284.4%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{C - \sqrt{B \cdot B + \color{blue}{C \cdot C}}}{B}\right)}{\pi} \]
        3. hypot-def90.8%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{C - \color{blue}{\mathsf{hypot}\left(B, C\right)}}{B}\right)}{\pi} \]
      5. Simplified90.8%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{C - \mathsf{hypot}\left(B, C\right)}{B}\right)}}{\pi} \]

      if -1.3999999999999999e-17 < C < 1.99999999999999996e109

      1. Initial program 55.1%

        \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
      2. Add Preprocessing
      3. Taylor expanded in C around 0 53.8%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(-1 \cdot \frac{A + \sqrt{{A}^{2} + {B}^{2}}}{B}\right)}}{\pi} \]
      4. Step-by-step derivation
        1. associate-*r/53.8%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{-1 \cdot \left(A + \sqrt{{A}^{2} + {B}^{2}}\right)}{B}\right)}}{\pi} \]
        2. mul-1-neg53.8%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\color{blue}{-\left(A + \sqrt{{A}^{2} + {B}^{2}}\right)}}{B}\right)}{\pi} \]
        3. +-commutative53.8%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{-\left(A + \sqrt{\color{blue}{{B}^{2} + {A}^{2}}}\right)}{B}\right)}{\pi} \]
        4. unpow253.8%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{-\left(A + \sqrt{\color{blue}{B \cdot B} + {A}^{2}}\right)}{B}\right)}{\pi} \]
        5. unpow253.8%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{-\left(A + \sqrt{B \cdot B + \color{blue}{A \cdot A}}\right)}{B}\right)}{\pi} \]
        6. hypot-def81.9%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{-\left(A + \color{blue}{\mathsf{hypot}\left(B, A\right)}\right)}{B}\right)}{\pi} \]
      5. Simplified81.9%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{-\left(A + \mathsf{hypot}\left(B, A\right)\right)}{B}\right)}}{\pi} \]

      if 1.99999999999999996e109 < C

      1. Initial program 21.0%

        \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
      2. Add Preprocessing
      3. Taylor expanded in A around 0 21.0%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{C - \sqrt{{B}^{2} + {C}^{2}}}{B}\right)}}{\pi} \]
      4. Step-by-step derivation
        1. unpow221.0%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{C - \sqrt{\color{blue}{B \cdot B} + {C}^{2}}}{B}\right)}{\pi} \]
        2. unpow221.0%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{C - \sqrt{B \cdot B + \color{blue}{C \cdot C}}}{B}\right)}{\pi} \]
        3. hypot-def54.1%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{C - \color{blue}{\mathsf{hypot}\left(B, C\right)}}{B}\right)}{\pi} \]
      5. Simplified54.1%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{C - \mathsf{hypot}\left(B, C\right)}{B}\right)}}{\pi} \]
      6. Taylor expanded in C around inf 70.5%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\color{blue}{-0.5 \cdot \frac{{B}^{2}}{C}}}{B}\right)}{\pi} \]
      7. Taylor expanded in B around 0 81.8%

        \[\leadsto \color{blue}{180 \cdot \frac{\tan^{-1} \left(-0.5 \cdot \frac{B}{C}\right)}{\pi}} \]
      8. Step-by-step derivation
        1. associate-*r/81.9%

          \[\leadsto \color{blue}{\frac{180 \cdot \tan^{-1} \left(-0.5 \cdot \frac{B}{C}\right)}{\pi}} \]
      9. Simplified81.9%

        \[\leadsto \color{blue}{\frac{180 \cdot \tan^{-1} \left(-0.5 \cdot \frac{B}{C}\right)}{\pi}} \]
    3. Recombined 3 regimes into one program.
    4. Final simplification84.6%

      \[\leadsto \begin{array}{l} \mathbf{if}\;C \leq -1.4 \cdot 10^{-17}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{C - \mathsf{hypot}\left(B, C\right)}{B}\right)}{\pi}\\ \mathbf{elif}\;C \leq 2 \cdot 10^{+109}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{\left(-A\right) - \mathsf{hypot}\left(B, A\right)}{B}\right)}{\pi}\\ \mathbf{else}:\\ \;\;\;\;\frac{180 \cdot \tan^{-1} \left(-0.5 \cdot \frac{B}{C}\right)}{\pi}\\ \end{array} \]
    5. Add Preprocessing

    Alternative 3: 75.7% accurate, 1.9× speedup?

    \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;A \leq -2.3 \cdot 10^{+164}:\\ \;\;\;\;\frac{180}{\pi} \cdot \tan^{-1} \left(\frac{B}{\frac{A}{0.5}}\right)\\ \mathbf{elif}\;A \leq 1.05 \cdot 10^{+128}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{C - \mathsf{hypot}\left(B, C\right)}{B}\right)}{\pi}\\ \mathbf{else}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(1 - \frac{A}{B}\right)}{\pi}\\ \end{array} \end{array} \]
    (FPCore (A B C)
     :precision binary64
     (if (<= A -2.3e+164)
       (* (/ 180.0 PI) (atan (/ B (/ A 0.5))))
       (if (<= A 1.05e+128)
         (* 180.0 (/ (atan (/ (- C (hypot B C)) B)) PI))
         (* 180.0 (/ (atan (- 1.0 (/ A B))) PI)))))
    double code(double A, double B, double C) {
    	double tmp;
    	if (A <= -2.3e+164) {
    		tmp = (180.0 / ((double) M_PI)) * atan((B / (A / 0.5)));
    	} else if (A <= 1.05e+128) {
    		tmp = 180.0 * (atan(((C - hypot(B, C)) / B)) / ((double) M_PI));
    	} else {
    		tmp = 180.0 * (atan((1.0 - (A / B))) / ((double) M_PI));
    	}
    	return tmp;
    }
    
    public static double code(double A, double B, double C) {
    	double tmp;
    	if (A <= -2.3e+164) {
    		tmp = (180.0 / Math.PI) * Math.atan((B / (A / 0.5)));
    	} else if (A <= 1.05e+128) {
    		tmp = 180.0 * (Math.atan(((C - Math.hypot(B, C)) / B)) / Math.PI);
    	} else {
    		tmp = 180.0 * (Math.atan((1.0 - (A / B))) / Math.PI);
    	}
    	return tmp;
    }
    
    def code(A, B, C):
    	tmp = 0
    	if A <= -2.3e+164:
    		tmp = (180.0 / math.pi) * math.atan((B / (A / 0.5)))
    	elif A <= 1.05e+128:
    		tmp = 180.0 * (math.atan(((C - math.hypot(B, C)) / B)) / math.pi)
    	else:
    		tmp = 180.0 * (math.atan((1.0 - (A / B))) / math.pi)
    	return tmp
    
    function code(A, B, C)
    	tmp = 0.0
    	if (A <= -2.3e+164)
    		tmp = Float64(Float64(180.0 / pi) * atan(Float64(B / Float64(A / 0.5))));
    	elseif (A <= 1.05e+128)
    		tmp = Float64(180.0 * Float64(atan(Float64(Float64(C - hypot(B, C)) / B)) / pi));
    	else
    		tmp = Float64(180.0 * Float64(atan(Float64(1.0 - Float64(A / B))) / pi));
    	end
    	return tmp
    end
    
    function tmp_2 = code(A, B, C)
    	tmp = 0.0;
    	if (A <= -2.3e+164)
    		tmp = (180.0 / pi) * atan((B / (A / 0.5)));
    	elseif (A <= 1.05e+128)
    		tmp = 180.0 * (atan(((C - hypot(B, C)) / B)) / pi);
    	else
    		tmp = 180.0 * (atan((1.0 - (A / B))) / pi);
    	end
    	tmp_2 = tmp;
    end
    
    code[A_, B_, C_] := If[LessEqual[A, -2.3e+164], N[(N[(180.0 / Pi), $MachinePrecision] * N[ArcTan[N[(B / N[(A / 0.5), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision], If[LessEqual[A, 1.05e+128], N[(180.0 * N[(N[ArcTan[N[(N[(C - N[Sqrt[B ^ 2 + C ^ 2], $MachinePrecision]), $MachinePrecision] / B), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision], N[(180.0 * N[(N[ArcTan[N[(1.0 - N[(A / B), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision]]]
    
    \begin{array}{l}
    
    \\
    \begin{array}{l}
    \mathbf{if}\;A \leq -2.3 \cdot 10^{+164}:\\
    \;\;\;\;\frac{180}{\pi} \cdot \tan^{-1} \left(\frac{B}{\frac{A}{0.5}}\right)\\
    
    \mathbf{elif}\;A \leq 1.05 \cdot 10^{+128}:\\
    \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{C - \mathsf{hypot}\left(B, C\right)}{B}\right)}{\pi}\\
    
    \mathbf{else}:\\
    \;\;\;\;180 \cdot \frac{\tan^{-1} \left(1 - \frac{A}{B}\right)}{\pi}\\
    
    
    \end{array}
    \end{array}
    
    Derivation
    1. Split input into 3 regimes
    2. if A < -2.3e164

      1. Initial program 12.4%

        \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
      2. Add Preprocessing
      3. Taylor expanded in A around -inf 87.1%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(0.5 \cdot \frac{B}{A}\right)}}{\pi} \]
      4. Step-by-step derivation
        1. associate-*r/87.1%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{0.5 \cdot B}{A}\right)}}{\pi} \]
      5. Simplified87.1%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{0.5 \cdot B}{A}\right)}}{\pi} \]
      6. Taylor expanded in B around 0 87.1%

        \[\leadsto \color{blue}{180 \cdot \frac{\tan^{-1} \left(0.5 \cdot \frac{B}{A}\right)}{\pi}} \]
      7. Step-by-step derivation
        1. associate-*r/87.2%

          \[\leadsto \color{blue}{\frac{180 \cdot \tan^{-1} \left(0.5 \cdot \frac{B}{A}\right)}{\pi}} \]
        2. associate-/l*87.2%

          \[\leadsto \color{blue}{\frac{180}{\frac{\pi}{\tan^{-1} \left(0.5 \cdot \frac{B}{A}\right)}}} \]
        3. associate-*r/87.2%

          \[\leadsto \frac{180}{\frac{\pi}{\tan^{-1} \color{blue}{\left(\frac{0.5 \cdot B}{A}\right)}}} \]
        4. associate-/l*87.2%

          \[\leadsto \frac{180}{\frac{\pi}{\tan^{-1} \color{blue}{\left(\frac{0.5}{\frac{A}{B}}\right)}}} \]
        5. associate-/r/87.1%

          \[\leadsto \color{blue}{\frac{180}{\pi} \cdot \tan^{-1} \left(\frac{0.5}{\frac{A}{B}}\right)} \]
        6. associate-/l*87.2%

          \[\leadsto \frac{180}{\pi} \cdot \tan^{-1} \color{blue}{\left(\frac{0.5 \cdot B}{A}\right)} \]
        7. *-commutative87.2%

          \[\leadsto \frac{180}{\pi} \cdot \tan^{-1} \left(\frac{\color{blue}{B \cdot 0.5}}{A}\right) \]
        8. associate-/l*87.2%

          \[\leadsto \frac{180}{\pi} \cdot \tan^{-1} \color{blue}{\left(\frac{B}{\frac{A}{0.5}}\right)} \]
      8. Simplified87.2%

        \[\leadsto \color{blue}{\frac{180}{\pi} \cdot \tan^{-1} \left(\frac{B}{\frac{A}{0.5}}\right)} \]

      if -2.3e164 < A < 1.05e128

      1. Initial program 59.7%

        \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
      2. Add Preprocessing
      3. Taylor expanded in A around 0 55.3%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{C - \sqrt{{B}^{2} + {C}^{2}}}{B}\right)}}{\pi} \]
      4. Step-by-step derivation
        1. unpow255.3%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{C - \sqrt{\color{blue}{B \cdot B} + {C}^{2}}}{B}\right)}{\pi} \]
        2. unpow255.3%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{C - \sqrt{B \cdot B + \color{blue}{C \cdot C}}}{B}\right)}{\pi} \]
        3. hypot-def80.6%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{C - \color{blue}{\mathsf{hypot}\left(B, C\right)}}{B}\right)}{\pi} \]
      5. Simplified80.6%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{C - \mathsf{hypot}\left(B, C\right)}{B}\right)}}{\pi} \]

      if 1.05e128 < A

      1. Initial program 82.6%

        \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
      2. Add Preprocessing
      3. Taylor expanded in C around 0 82.6%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(-1 \cdot \frac{A + \sqrt{{A}^{2} + {B}^{2}}}{B}\right)}}{\pi} \]
      4. Step-by-step derivation
        1. associate-*r/82.6%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{-1 \cdot \left(A + \sqrt{{A}^{2} + {B}^{2}}\right)}{B}\right)}}{\pi} \]
        2. mul-1-neg82.6%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\color{blue}{-\left(A + \sqrt{{A}^{2} + {B}^{2}}\right)}}{B}\right)}{\pi} \]
        3. +-commutative82.6%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{-\left(A + \sqrt{\color{blue}{{B}^{2} + {A}^{2}}}\right)}{B}\right)}{\pi} \]
        4. unpow282.6%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{-\left(A + \sqrt{\color{blue}{B \cdot B} + {A}^{2}}\right)}{B}\right)}{\pi} \]
        5. unpow282.6%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{-\left(A + \sqrt{B \cdot B + \color{blue}{A \cdot A}}\right)}{B}\right)}{\pi} \]
        6. hypot-def92.7%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{-\left(A + \color{blue}{\mathsf{hypot}\left(B, A\right)}\right)}{B}\right)}{\pi} \]
      5. Simplified92.7%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{-\left(A + \mathsf{hypot}\left(B, A\right)\right)}{B}\right)}}{\pi} \]
      6. Taylor expanded in B around -inf 80.9%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(1 + -1 \cdot \frac{A}{B}\right)}}{\pi} \]
      7. Step-by-step derivation
        1. mul-1-neg80.9%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \color{blue}{\left(-\frac{A}{B}\right)}\right)}{\pi} \]
        2. unsub-neg80.9%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(1 - \frac{A}{B}\right)}}{\pi} \]
      8. Simplified80.9%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(1 - \frac{A}{B}\right)}}{\pi} \]
    3. Recombined 3 regimes into one program.
    4. Final simplification81.4%

      \[\leadsto \begin{array}{l} \mathbf{if}\;A \leq -2.3 \cdot 10^{+164}:\\ \;\;\;\;\frac{180}{\pi} \cdot \tan^{-1} \left(\frac{B}{\frac{A}{0.5}}\right)\\ \mathbf{elif}\;A \leq 1.05 \cdot 10^{+128}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{C - \mathsf{hypot}\left(B, C\right)}{B}\right)}{\pi}\\ \mathbf{else}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(1 - \frac{A}{B}\right)}{\pi}\\ \end{array} \]
    5. Add Preprocessing

    Alternative 4: 53.2% accurate, 3.0× speedup?

    \[\begin{array}{l} \\ \begin{array}{l} t_0 := 180 \cdot \frac{\tan^{-1} \left(1 - \frac{A}{B}\right)}{\pi}\\ \mathbf{if}\;C \leq -0.185:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(2 \cdot \frac{C}{B}\right)}{\pi}\\ \mathbf{elif}\;C \leq -1.35 \cdot 10^{-164}:\\ \;\;\;\;t\_0\\ \mathbf{elif}\;C \leq -1.5 \cdot 10^{-213}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{B \cdot 0.5}{A}\right)}{\pi}\\ \mathbf{elif}\;C \leq -8.4 \cdot 10^{-280}:\\ \;\;\;\;t\_0\\ \mathbf{elif}\;C \leq 3.2 \cdot 10^{-154}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} -1}{\pi}\\ \mathbf{elif}\;C \leq 6.5 \cdot 10^{+50}:\\ \;\;\;\;t\_0\\ \mathbf{else}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{B \cdot -0.5}{C}\right)}{\pi}\\ \end{array} \end{array} \]
    (FPCore (A B C)
     :precision binary64
     (let* ((t_0 (* 180.0 (/ (atan (- 1.0 (/ A B))) PI))))
       (if (<= C -0.185)
         (* 180.0 (/ (atan (* 2.0 (/ C B))) PI))
         (if (<= C -1.35e-164)
           t_0
           (if (<= C -1.5e-213)
             (* 180.0 (/ (atan (/ (* B 0.5) A)) PI))
             (if (<= C -8.4e-280)
               t_0
               (if (<= C 3.2e-154)
                 (* 180.0 (/ (atan -1.0) PI))
                 (if (<= C 6.5e+50)
                   t_0
                   (* 180.0 (/ (atan (/ (* B -0.5) C)) PI))))))))))
    double code(double A, double B, double C) {
    	double t_0 = 180.0 * (atan((1.0 - (A / B))) / ((double) M_PI));
    	double tmp;
    	if (C <= -0.185) {
    		tmp = 180.0 * (atan((2.0 * (C / B))) / ((double) M_PI));
    	} else if (C <= -1.35e-164) {
    		tmp = t_0;
    	} else if (C <= -1.5e-213) {
    		tmp = 180.0 * (atan(((B * 0.5) / A)) / ((double) M_PI));
    	} else if (C <= -8.4e-280) {
    		tmp = t_0;
    	} else if (C <= 3.2e-154) {
    		tmp = 180.0 * (atan(-1.0) / ((double) M_PI));
    	} else if (C <= 6.5e+50) {
    		tmp = t_0;
    	} else {
    		tmp = 180.0 * (atan(((B * -0.5) / C)) / ((double) M_PI));
    	}
    	return tmp;
    }
    
    public static double code(double A, double B, double C) {
    	double t_0 = 180.0 * (Math.atan((1.0 - (A / B))) / Math.PI);
    	double tmp;
    	if (C <= -0.185) {
    		tmp = 180.0 * (Math.atan((2.0 * (C / B))) / Math.PI);
    	} else if (C <= -1.35e-164) {
    		tmp = t_0;
    	} else if (C <= -1.5e-213) {
    		tmp = 180.0 * (Math.atan(((B * 0.5) / A)) / Math.PI);
    	} else if (C <= -8.4e-280) {
    		tmp = t_0;
    	} else if (C <= 3.2e-154) {
    		tmp = 180.0 * (Math.atan(-1.0) / Math.PI);
    	} else if (C <= 6.5e+50) {
    		tmp = t_0;
    	} else {
    		tmp = 180.0 * (Math.atan(((B * -0.5) / C)) / Math.PI);
    	}
    	return tmp;
    }
    
    def code(A, B, C):
    	t_0 = 180.0 * (math.atan((1.0 - (A / B))) / math.pi)
    	tmp = 0
    	if C <= -0.185:
    		tmp = 180.0 * (math.atan((2.0 * (C / B))) / math.pi)
    	elif C <= -1.35e-164:
    		tmp = t_0
    	elif C <= -1.5e-213:
    		tmp = 180.0 * (math.atan(((B * 0.5) / A)) / math.pi)
    	elif C <= -8.4e-280:
    		tmp = t_0
    	elif C <= 3.2e-154:
    		tmp = 180.0 * (math.atan(-1.0) / math.pi)
    	elif C <= 6.5e+50:
    		tmp = t_0
    	else:
    		tmp = 180.0 * (math.atan(((B * -0.5) / C)) / math.pi)
    	return tmp
    
    function code(A, B, C)
    	t_0 = Float64(180.0 * Float64(atan(Float64(1.0 - Float64(A / B))) / pi))
    	tmp = 0.0
    	if (C <= -0.185)
    		tmp = Float64(180.0 * Float64(atan(Float64(2.0 * Float64(C / B))) / pi));
    	elseif (C <= -1.35e-164)
    		tmp = t_0;
    	elseif (C <= -1.5e-213)
    		tmp = Float64(180.0 * Float64(atan(Float64(Float64(B * 0.5) / A)) / pi));
    	elseif (C <= -8.4e-280)
    		tmp = t_0;
    	elseif (C <= 3.2e-154)
    		tmp = Float64(180.0 * Float64(atan(-1.0) / pi));
    	elseif (C <= 6.5e+50)
    		tmp = t_0;
    	else
    		tmp = Float64(180.0 * Float64(atan(Float64(Float64(B * -0.5) / C)) / pi));
    	end
    	return tmp
    end
    
    function tmp_2 = code(A, B, C)
    	t_0 = 180.0 * (atan((1.0 - (A / B))) / pi);
    	tmp = 0.0;
    	if (C <= -0.185)
    		tmp = 180.0 * (atan((2.0 * (C / B))) / pi);
    	elseif (C <= -1.35e-164)
    		tmp = t_0;
    	elseif (C <= -1.5e-213)
    		tmp = 180.0 * (atan(((B * 0.5) / A)) / pi);
    	elseif (C <= -8.4e-280)
    		tmp = t_0;
    	elseif (C <= 3.2e-154)
    		tmp = 180.0 * (atan(-1.0) / pi);
    	elseif (C <= 6.5e+50)
    		tmp = t_0;
    	else
    		tmp = 180.0 * (atan(((B * -0.5) / C)) / pi);
    	end
    	tmp_2 = tmp;
    end
    
    code[A_, B_, C_] := Block[{t$95$0 = N[(180.0 * N[(N[ArcTan[N[(1.0 - N[(A / B), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[C, -0.185], N[(180.0 * N[(N[ArcTan[N[(2.0 * N[(C / B), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision], If[LessEqual[C, -1.35e-164], t$95$0, If[LessEqual[C, -1.5e-213], N[(180.0 * N[(N[ArcTan[N[(N[(B * 0.5), $MachinePrecision] / A), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision], If[LessEqual[C, -8.4e-280], t$95$0, If[LessEqual[C, 3.2e-154], N[(180.0 * N[(N[ArcTan[-1.0], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision], If[LessEqual[C, 6.5e+50], t$95$0, N[(180.0 * N[(N[ArcTan[N[(N[(B * -0.5), $MachinePrecision] / C), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision]]]]]]]]
    
    \begin{array}{l}
    
    \\
    \begin{array}{l}
    t_0 := 180 \cdot \frac{\tan^{-1} \left(1 - \frac{A}{B}\right)}{\pi}\\
    \mathbf{if}\;C \leq -0.185:\\
    \;\;\;\;180 \cdot \frac{\tan^{-1} \left(2 \cdot \frac{C}{B}\right)}{\pi}\\
    
    \mathbf{elif}\;C \leq -1.35 \cdot 10^{-164}:\\
    \;\;\;\;t\_0\\
    
    \mathbf{elif}\;C \leq -1.5 \cdot 10^{-213}:\\
    \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{B \cdot 0.5}{A}\right)}{\pi}\\
    
    \mathbf{elif}\;C \leq -8.4 \cdot 10^{-280}:\\
    \;\;\;\;t\_0\\
    
    \mathbf{elif}\;C \leq 3.2 \cdot 10^{-154}:\\
    \;\;\;\;180 \cdot \frac{\tan^{-1} -1}{\pi}\\
    
    \mathbf{elif}\;C \leq 6.5 \cdot 10^{+50}:\\
    \;\;\;\;t\_0\\
    
    \mathbf{else}:\\
    \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{B \cdot -0.5}{C}\right)}{\pi}\\
    
    
    \end{array}
    \end{array}
    
    Derivation
    1. Split input into 5 regimes
    2. if C < -0.185

      1. Initial program 82.6%

        \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
      2. Add Preprocessing
      3. Taylor expanded in C around -inf 74.9%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(2 \cdot \frac{C}{B}\right)}}{\pi} \]

      if -0.185 < C < -1.3500000000000001e-164 or -1.49999999999999993e-213 < C < -8.40000000000000003e-280 or 3.20000000000000005e-154 < C < 6.5000000000000003e50

      1. Initial program 63.2%

        \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
      2. Add Preprocessing
      3. Taylor expanded in C around 0 59.6%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(-1 \cdot \frac{A + \sqrt{{A}^{2} + {B}^{2}}}{B}\right)}}{\pi} \]
      4. Step-by-step derivation
        1. associate-*r/59.6%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{-1 \cdot \left(A + \sqrt{{A}^{2} + {B}^{2}}\right)}{B}\right)}}{\pi} \]
        2. mul-1-neg59.6%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\color{blue}{-\left(A + \sqrt{{A}^{2} + {B}^{2}}\right)}}{B}\right)}{\pi} \]
        3. +-commutative59.6%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{-\left(A + \sqrt{\color{blue}{{B}^{2} + {A}^{2}}}\right)}{B}\right)}{\pi} \]
        4. unpow259.6%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{-\left(A + \sqrt{\color{blue}{B \cdot B} + {A}^{2}}\right)}{B}\right)}{\pi} \]
        5. unpow259.6%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{-\left(A + \sqrt{B \cdot B + \color{blue}{A \cdot A}}\right)}{B}\right)}{\pi} \]
        6. hypot-def85.7%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{-\left(A + \color{blue}{\mathsf{hypot}\left(B, A\right)}\right)}{B}\right)}{\pi} \]
      5. Simplified85.7%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{-\left(A + \mathsf{hypot}\left(B, A\right)\right)}{B}\right)}}{\pi} \]
      6. Taylor expanded in B around -inf 57.2%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(1 + -1 \cdot \frac{A}{B}\right)}}{\pi} \]
      7. Step-by-step derivation
        1. mul-1-neg57.2%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \color{blue}{\left(-\frac{A}{B}\right)}\right)}{\pi} \]
        2. unsub-neg57.2%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(1 - \frac{A}{B}\right)}}{\pi} \]
      8. Simplified57.2%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(1 - \frac{A}{B}\right)}}{\pi} \]

      if -1.3500000000000001e-164 < C < -1.49999999999999993e-213

      1. Initial program 46.4%

        \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
      2. Add Preprocessing
      3. Taylor expanded in A around -inf 61.0%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(0.5 \cdot \frac{B}{A}\right)}}{\pi} \]
      4. Step-by-step derivation
        1. associate-*r/61.0%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{0.5 \cdot B}{A}\right)}}{\pi} \]
      5. Simplified61.0%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{0.5 \cdot B}{A}\right)}}{\pi} \]

      if -8.40000000000000003e-280 < C < 3.20000000000000005e-154

      1. Initial program 49.7%

        \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
      2. Add Preprocessing
      3. Taylor expanded in B around inf 48.6%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{-1}}{\pi} \]

      if 6.5000000000000003e50 < C

      1. Initial program 21.2%

        \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
      2. Add Preprocessing
      3. Taylor expanded in A around 0 21.7%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{C - \sqrt{{B}^{2} + {C}^{2}}}{B}\right)}}{\pi} \]
      4. Step-by-step derivation
        1. unpow221.7%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{C - \sqrt{\color{blue}{B \cdot B} + {C}^{2}}}{B}\right)}{\pi} \]
        2. unpow221.7%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{C - \sqrt{B \cdot B + \color{blue}{C \cdot C}}}{B}\right)}{\pi} \]
        3. hypot-def52.4%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{C - \color{blue}{\mathsf{hypot}\left(B, C\right)}}{B}\right)}{\pi} \]
      5. Simplified52.4%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{C - \mathsf{hypot}\left(B, C\right)}{B}\right)}}{\pi} \]
      6. Taylor expanded in C around inf 76.7%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(-0.5 \cdot \frac{B}{C}\right)}}{\pi} \]
      7. Step-by-step derivation
        1. associate-*r/76.7%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{-0.5 \cdot B}{C}\right)}}{\pi} \]
      8. Simplified76.7%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{-0.5 \cdot B}{C}\right)}}{\pi} \]
    3. Recombined 5 regimes into one program.
    4. Final simplification65.1%

      \[\leadsto \begin{array}{l} \mathbf{if}\;C \leq -0.185:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(2 \cdot \frac{C}{B}\right)}{\pi}\\ \mathbf{elif}\;C \leq -1.35 \cdot 10^{-164}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(1 - \frac{A}{B}\right)}{\pi}\\ \mathbf{elif}\;C \leq -1.5 \cdot 10^{-213}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{B \cdot 0.5}{A}\right)}{\pi}\\ \mathbf{elif}\;C \leq -8.4 \cdot 10^{-280}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(1 - \frac{A}{B}\right)}{\pi}\\ \mathbf{elif}\;C \leq 3.2 \cdot 10^{-154}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} -1}{\pi}\\ \mathbf{elif}\;C \leq 6.5 \cdot 10^{+50}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(1 - \frac{A}{B}\right)}{\pi}\\ \mathbf{else}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{B \cdot -0.5}{C}\right)}{\pi}\\ \end{array} \]
    5. Add Preprocessing

    Alternative 5: 51.9% accurate, 3.2× speedup?

    \[\begin{array}{l} \\ \begin{array}{l} t_0 := 180 \cdot \frac{\tan^{-1} \left(1 - \frac{A}{B}\right)}{\pi}\\ \mathbf{if}\;C \leq -3.2:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(2 \cdot \frac{C}{B}\right)}{\pi}\\ \mathbf{elif}\;C \leq -6.2 \cdot 10^{-137}:\\ \;\;\;\;t\_0\\ \mathbf{elif}\;C \leq 3.6 \cdot 10^{-153}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} -1}{\pi}\\ \mathbf{elif}\;C \leq 4.1 \cdot 10^{+50}:\\ \;\;\;\;t\_0\\ \mathbf{else}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{B \cdot -0.5}{C}\right)}{\pi}\\ \end{array} \end{array} \]
    (FPCore (A B C)
     :precision binary64
     (let* ((t_0 (* 180.0 (/ (atan (- 1.0 (/ A B))) PI))))
       (if (<= C -3.2)
         (* 180.0 (/ (atan (* 2.0 (/ C B))) PI))
         (if (<= C -6.2e-137)
           t_0
           (if (<= C 3.6e-153)
             (* 180.0 (/ (atan -1.0) PI))
             (if (<= C 4.1e+50) t_0 (* 180.0 (/ (atan (/ (* B -0.5) C)) PI))))))))
    double code(double A, double B, double C) {
    	double t_0 = 180.0 * (atan((1.0 - (A / B))) / ((double) M_PI));
    	double tmp;
    	if (C <= -3.2) {
    		tmp = 180.0 * (atan((2.0 * (C / B))) / ((double) M_PI));
    	} else if (C <= -6.2e-137) {
    		tmp = t_0;
    	} else if (C <= 3.6e-153) {
    		tmp = 180.0 * (atan(-1.0) / ((double) M_PI));
    	} else if (C <= 4.1e+50) {
    		tmp = t_0;
    	} else {
    		tmp = 180.0 * (atan(((B * -0.5) / C)) / ((double) M_PI));
    	}
    	return tmp;
    }
    
    public static double code(double A, double B, double C) {
    	double t_0 = 180.0 * (Math.atan((1.0 - (A / B))) / Math.PI);
    	double tmp;
    	if (C <= -3.2) {
    		tmp = 180.0 * (Math.atan((2.0 * (C / B))) / Math.PI);
    	} else if (C <= -6.2e-137) {
    		tmp = t_0;
    	} else if (C <= 3.6e-153) {
    		tmp = 180.0 * (Math.atan(-1.0) / Math.PI);
    	} else if (C <= 4.1e+50) {
    		tmp = t_0;
    	} else {
    		tmp = 180.0 * (Math.atan(((B * -0.5) / C)) / Math.PI);
    	}
    	return tmp;
    }
    
    def code(A, B, C):
    	t_0 = 180.0 * (math.atan((1.0 - (A / B))) / math.pi)
    	tmp = 0
    	if C <= -3.2:
    		tmp = 180.0 * (math.atan((2.0 * (C / B))) / math.pi)
    	elif C <= -6.2e-137:
    		tmp = t_0
    	elif C <= 3.6e-153:
    		tmp = 180.0 * (math.atan(-1.0) / math.pi)
    	elif C <= 4.1e+50:
    		tmp = t_0
    	else:
    		tmp = 180.0 * (math.atan(((B * -0.5) / C)) / math.pi)
    	return tmp
    
    function code(A, B, C)
    	t_0 = Float64(180.0 * Float64(atan(Float64(1.0 - Float64(A / B))) / pi))
    	tmp = 0.0
    	if (C <= -3.2)
    		tmp = Float64(180.0 * Float64(atan(Float64(2.0 * Float64(C / B))) / pi));
    	elseif (C <= -6.2e-137)
    		tmp = t_0;
    	elseif (C <= 3.6e-153)
    		tmp = Float64(180.0 * Float64(atan(-1.0) / pi));
    	elseif (C <= 4.1e+50)
    		tmp = t_0;
    	else
    		tmp = Float64(180.0 * Float64(atan(Float64(Float64(B * -0.5) / C)) / pi));
    	end
    	return tmp
    end
    
    function tmp_2 = code(A, B, C)
    	t_0 = 180.0 * (atan((1.0 - (A / B))) / pi);
    	tmp = 0.0;
    	if (C <= -3.2)
    		tmp = 180.0 * (atan((2.0 * (C / B))) / pi);
    	elseif (C <= -6.2e-137)
    		tmp = t_0;
    	elseif (C <= 3.6e-153)
    		tmp = 180.0 * (atan(-1.0) / pi);
    	elseif (C <= 4.1e+50)
    		tmp = t_0;
    	else
    		tmp = 180.0 * (atan(((B * -0.5) / C)) / pi);
    	end
    	tmp_2 = tmp;
    end
    
    code[A_, B_, C_] := Block[{t$95$0 = N[(180.0 * N[(N[ArcTan[N[(1.0 - N[(A / B), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[C, -3.2], N[(180.0 * N[(N[ArcTan[N[(2.0 * N[(C / B), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision], If[LessEqual[C, -6.2e-137], t$95$0, If[LessEqual[C, 3.6e-153], N[(180.0 * N[(N[ArcTan[-1.0], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision], If[LessEqual[C, 4.1e+50], t$95$0, N[(180.0 * N[(N[ArcTan[N[(N[(B * -0.5), $MachinePrecision] / C), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision]]]]]]
    
    \begin{array}{l}
    
    \\
    \begin{array}{l}
    t_0 := 180 \cdot \frac{\tan^{-1} \left(1 - \frac{A}{B}\right)}{\pi}\\
    \mathbf{if}\;C \leq -3.2:\\
    \;\;\;\;180 \cdot \frac{\tan^{-1} \left(2 \cdot \frac{C}{B}\right)}{\pi}\\
    
    \mathbf{elif}\;C \leq -6.2 \cdot 10^{-137}:\\
    \;\;\;\;t\_0\\
    
    \mathbf{elif}\;C \leq 3.6 \cdot 10^{-153}:\\
    \;\;\;\;180 \cdot \frac{\tan^{-1} -1}{\pi}\\
    
    \mathbf{elif}\;C \leq 4.1 \cdot 10^{+50}:\\
    \;\;\;\;t\_0\\
    
    \mathbf{else}:\\
    \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{B \cdot -0.5}{C}\right)}{\pi}\\
    
    
    \end{array}
    \end{array}
    
    Derivation
    1. Split input into 4 regimes
    2. if C < -3.2000000000000002

      1. Initial program 82.6%

        \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
      2. Add Preprocessing
      3. Taylor expanded in C around -inf 74.9%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(2 \cdot \frac{C}{B}\right)}}{\pi} \]

      if -3.2000000000000002 < C < -6.19999999999999955e-137 or 3.5999999999999998e-153 < C < 4.1000000000000001e50

      1. Initial program 67.5%

        \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
      2. Add Preprocessing
      3. Taylor expanded in C around 0 62.7%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(-1 \cdot \frac{A + \sqrt{{A}^{2} + {B}^{2}}}{B}\right)}}{\pi} \]
      4. Step-by-step derivation
        1. associate-*r/62.7%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{-1 \cdot \left(A + \sqrt{{A}^{2} + {B}^{2}}\right)}{B}\right)}}{\pi} \]
        2. mul-1-neg62.7%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\color{blue}{-\left(A + \sqrt{{A}^{2} + {B}^{2}}\right)}}{B}\right)}{\pi} \]
        3. +-commutative62.7%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{-\left(A + \sqrt{\color{blue}{{B}^{2} + {A}^{2}}}\right)}{B}\right)}{\pi} \]
        4. unpow262.7%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{-\left(A + \sqrt{\color{blue}{B \cdot B} + {A}^{2}}\right)}{B}\right)}{\pi} \]
        5. unpow262.7%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{-\left(A + \sqrt{B \cdot B + \color{blue}{A \cdot A}}\right)}{B}\right)}{\pi} \]
        6. hypot-def86.4%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{-\left(A + \color{blue}{\mathsf{hypot}\left(B, A\right)}\right)}{B}\right)}{\pi} \]
      5. Simplified86.4%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{-\left(A + \mathsf{hypot}\left(B, A\right)\right)}{B}\right)}}{\pi} \]
      6. Taylor expanded in B around -inf 61.3%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(1 + -1 \cdot \frac{A}{B}\right)}}{\pi} \]
      7. Step-by-step derivation
        1. mul-1-neg61.3%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \color{blue}{\left(-\frac{A}{B}\right)}\right)}{\pi} \]
        2. unsub-neg61.3%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(1 - \frac{A}{B}\right)}}{\pi} \]
      8. Simplified61.3%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(1 - \frac{A}{B}\right)}}{\pi} \]

      if -6.19999999999999955e-137 < C < 3.5999999999999998e-153

      1. Initial program 49.5%

        \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
      2. Add Preprocessing
      3. Taylor expanded in B around inf 40.5%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{-1}}{\pi} \]

      if 4.1000000000000001e50 < C

      1. Initial program 21.2%

        \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
      2. Add Preprocessing
      3. Taylor expanded in A around 0 21.7%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{C - \sqrt{{B}^{2} + {C}^{2}}}{B}\right)}}{\pi} \]
      4. Step-by-step derivation
        1. unpow221.7%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{C - \sqrt{\color{blue}{B \cdot B} + {C}^{2}}}{B}\right)}{\pi} \]
        2. unpow221.7%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{C - \sqrt{B \cdot B + \color{blue}{C \cdot C}}}{B}\right)}{\pi} \]
        3. hypot-def52.4%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{C - \color{blue}{\mathsf{hypot}\left(B, C\right)}}{B}\right)}{\pi} \]
      5. Simplified52.4%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{C - \mathsf{hypot}\left(B, C\right)}{B}\right)}}{\pi} \]
      6. Taylor expanded in C around inf 76.7%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(-0.5 \cdot \frac{B}{C}\right)}}{\pi} \]
      7. Step-by-step derivation
        1. associate-*r/76.7%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{-0.5 \cdot B}{C}\right)}}{\pi} \]
      8. Simplified76.7%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{-0.5 \cdot B}{C}\right)}}{\pi} \]
    3. Recombined 4 regimes into one program.
    4. Final simplification62.8%

      \[\leadsto \begin{array}{l} \mathbf{if}\;C \leq -3.2:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(2 \cdot \frac{C}{B}\right)}{\pi}\\ \mathbf{elif}\;C \leq -6.2 \cdot 10^{-137}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(1 - \frac{A}{B}\right)}{\pi}\\ \mathbf{elif}\;C \leq 3.6 \cdot 10^{-153}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} -1}{\pi}\\ \mathbf{elif}\;C \leq 4.1 \cdot 10^{+50}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(1 - \frac{A}{B}\right)}{\pi}\\ \mathbf{else}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{B \cdot -0.5}{C}\right)}{\pi}\\ \end{array} \]
    5. Add Preprocessing

    Alternative 6: 54.2% accurate, 3.2× speedup?

    \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;C \leq -3.2 \cdot 10^{-163}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{B + C}{B}\right)}{\pi}\\ \mathbf{elif}\;C \leq -4.3 \cdot 10^{-262}:\\ \;\;\;\;\frac{180}{\pi} \cdot \tan^{-1} \left(\frac{B}{\frac{A}{0.5}}\right)\\ \mathbf{elif}\;C \leq 6.2 \cdot 10^{-154}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} -1}{\pi}\\ \mathbf{elif}\;C \leq 9.4 \cdot 10^{+51}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(1 - \frac{A}{B}\right)}{\pi}\\ \mathbf{else}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{B \cdot -0.5}{C}\right)}{\pi}\\ \end{array} \end{array} \]
    (FPCore (A B C)
     :precision binary64
     (if (<= C -3.2e-163)
       (* 180.0 (/ (atan (/ (+ B C) B)) PI))
       (if (<= C -4.3e-262)
         (* (/ 180.0 PI) (atan (/ B (/ A 0.5))))
         (if (<= C 6.2e-154)
           (* 180.0 (/ (atan -1.0) PI))
           (if (<= C 9.4e+51)
             (* 180.0 (/ (atan (- 1.0 (/ A B))) PI))
             (* 180.0 (/ (atan (/ (* B -0.5) C)) PI)))))))
    double code(double A, double B, double C) {
    	double tmp;
    	if (C <= -3.2e-163) {
    		tmp = 180.0 * (atan(((B + C) / B)) / ((double) M_PI));
    	} else if (C <= -4.3e-262) {
    		tmp = (180.0 / ((double) M_PI)) * atan((B / (A / 0.5)));
    	} else if (C <= 6.2e-154) {
    		tmp = 180.0 * (atan(-1.0) / ((double) M_PI));
    	} else if (C <= 9.4e+51) {
    		tmp = 180.0 * (atan((1.0 - (A / B))) / ((double) M_PI));
    	} else {
    		tmp = 180.0 * (atan(((B * -0.5) / C)) / ((double) M_PI));
    	}
    	return tmp;
    }
    
    public static double code(double A, double B, double C) {
    	double tmp;
    	if (C <= -3.2e-163) {
    		tmp = 180.0 * (Math.atan(((B + C) / B)) / Math.PI);
    	} else if (C <= -4.3e-262) {
    		tmp = (180.0 / Math.PI) * Math.atan((B / (A / 0.5)));
    	} else if (C <= 6.2e-154) {
    		tmp = 180.0 * (Math.atan(-1.0) / Math.PI);
    	} else if (C <= 9.4e+51) {
    		tmp = 180.0 * (Math.atan((1.0 - (A / B))) / Math.PI);
    	} else {
    		tmp = 180.0 * (Math.atan(((B * -0.5) / C)) / Math.PI);
    	}
    	return tmp;
    }
    
    def code(A, B, C):
    	tmp = 0
    	if C <= -3.2e-163:
    		tmp = 180.0 * (math.atan(((B + C) / B)) / math.pi)
    	elif C <= -4.3e-262:
    		tmp = (180.0 / math.pi) * math.atan((B / (A / 0.5)))
    	elif C <= 6.2e-154:
    		tmp = 180.0 * (math.atan(-1.0) / math.pi)
    	elif C <= 9.4e+51:
    		tmp = 180.0 * (math.atan((1.0 - (A / B))) / math.pi)
    	else:
    		tmp = 180.0 * (math.atan(((B * -0.5) / C)) / math.pi)
    	return tmp
    
    function code(A, B, C)
    	tmp = 0.0
    	if (C <= -3.2e-163)
    		tmp = Float64(180.0 * Float64(atan(Float64(Float64(B + C) / B)) / pi));
    	elseif (C <= -4.3e-262)
    		tmp = Float64(Float64(180.0 / pi) * atan(Float64(B / Float64(A / 0.5))));
    	elseif (C <= 6.2e-154)
    		tmp = Float64(180.0 * Float64(atan(-1.0) / pi));
    	elseif (C <= 9.4e+51)
    		tmp = Float64(180.0 * Float64(atan(Float64(1.0 - Float64(A / B))) / pi));
    	else
    		tmp = Float64(180.0 * Float64(atan(Float64(Float64(B * -0.5) / C)) / pi));
    	end
    	return tmp
    end
    
    function tmp_2 = code(A, B, C)
    	tmp = 0.0;
    	if (C <= -3.2e-163)
    		tmp = 180.0 * (atan(((B + C) / B)) / pi);
    	elseif (C <= -4.3e-262)
    		tmp = (180.0 / pi) * atan((B / (A / 0.5)));
    	elseif (C <= 6.2e-154)
    		tmp = 180.0 * (atan(-1.0) / pi);
    	elseif (C <= 9.4e+51)
    		tmp = 180.0 * (atan((1.0 - (A / B))) / pi);
    	else
    		tmp = 180.0 * (atan(((B * -0.5) / C)) / pi);
    	end
    	tmp_2 = tmp;
    end
    
    code[A_, B_, C_] := If[LessEqual[C, -3.2e-163], N[(180.0 * N[(N[ArcTan[N[(N[(B + C), $MachinePrecision] / B), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision], If[LessEqual[C, -4.3e-262], N[(N[(180.0 / Pi), $MachinePrecision] * N[ArcTan[N[(B / N[(A / 0.5), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision], If[LessEqual[C, 6.2e-154], N[(180.0 * N[(N[ArcTan[-1.0], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision], If[LessEqual[C, 9.4e+51], N[(180.0 * N[(N[ArcTan[N[(1.0 - N[(A / B), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision], N[(180.0 * N[(N[ArcTan[N[(N[(B * -0.5), $MachinePrecision] / C), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision]]]]]
    
    \begin{array}{l}
    
    \\
    \begin{array}{l}
    \mathbf{if}\;C \leq -3.2 \cdot 10^{-163}:\\
    \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{B + C}{B}\right)}{\pi}\\
    
    \mathbf{elif}\;C \leq -4.3 \cdot 10^{-262}:\\
    \;\;\;\;\frac{180}{\pi} \cdot \tan^{-1} \left(\frac{B}{\frac{A}{0.5}}\right)\\
    
    \mathbf{elif}\;C \leq 6.2 \cdot 10^{-154}:\\
    \;\;\;\;180 \cdot \frac{\tan^{-1} -1}{\pi}\\
    
    \mathbf{elif}\;C \leq 9.4 \cdot 10^{+51}:\\
    \;\;\;\;180 \cdot \frac{\tan^{-1} \left(1 - \frac{A}{B}\right)}{\pi}\\
    
    \mathbf{else}:\\
    \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{B \cdot -0.5}{C}\right)}{\pi}\\
    
    
    \end{array}
    \end{array}
    
    Derivation
    1. Split input into 5 regimes
    2. if C < -3.19999999999999988e-163

      1. Initial program 78.7%

        \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
      2. Add Preprocessing
      3. Taylor expanded in A around 0 75.0%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{C - \sqrt{{B}^{2} + {C}^{2}}}{B}\right)}}{\pi} \]
      4. Step-by-step derivation
        1. unpow275.0%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{C - \sqrt{\color{blue}{B \cdot B} + {C}^{2}}}{B}\right)}{\pi} \]
        2. unpow275.0%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{C - \sqrt{B \cdot B + \color{blue}{C \cdot C}}}{B}\right)}{\pi} \]
        3. hypot-def86.3%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{C - \color{blue}{\mathsf{hypot}\left(B, C\right)}}{B}\right)}{\pi} \]
      5. Simplified86.3%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{C - \mathsf{hypot}\left(B, C\right)}{B}\right)}}{\pi} \]
      6. Taylor expanded in B around -inf 72.1%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\color{blue}{B + C}}{B}\right)}{\pi} \]

      if -3.19999999999999988e-163 < C < -4.3000000000000001e-262

      1. Initial program 48.3%

        \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
      2. Add Preprocessing
      3. Taylor expanded in A around -inf 45.9%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(0.5 \cdot \frac{B}{A}\right)}}{\pi} \]
      4. Step-by-step derivation
        1. associate-*r/45.9%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{0.5 \cdot B}{A}\right)}}{\pi} \]
      5. Simplified45.9%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{0.5 \cdot B}{A}\right)}}{\pi} \]
      6. Taylor expanded in B around 0 45.9%

        \[\leadsto \color{blue}{180 \cdot \frac{\tan^{-1} \left(0.5 \cdot \frac{B}{A}\right)}{\pi}} \]
      7. Step-by-step derivation
        1. associate-*r/46.1%

          \[\leadsto \color{blue}{\frac{180 \cdot \tan^{-1} \left(0.5 \cdot \frac{B}{A}\right)}{\pi}} \]
        2. associate-/l*45.4%

          \[\leadsto \color{blue}{\frac{180}{\frac{\pi}{\tan^{-1} \left(0.5 \cdot \frac{B}{A}\right)}}} \]
        3. associate-*r/45.4%

          \[\leadsto \frac{180}{\frac{\pi}{\tan^{-1} \color{blue}{\left(\frac{0.5 \cdot B}{A}\right)}}} \]
        4. associate-/l*45.3%

          \[\leadsto \frac{180}{\frac{\pi}{\tan^{-1} \color{blue}{\left(\frac{0.5}{\frac{A}{B}}\right)}}} \]
        5. associate-/r/45.3%

          \[\leadsto \color{blue}{\frac{180}{\pi} \cdot \tan^{-1} \left(\frac{0.5}{\frac{A}{B}}\right)} \]
        6. associate-/l*46.2%

          \[\leadsto \frac{180}{\pi} \cdot \tan^{-1} \color{blue}{\left(\frac{0.5 \cdot B}{A}\right)} \]
        7. *-commutative46.2%

          \[\leadsto \frac{180}{\pi} \cdot \tan^{-1} \left(\frac{\color{blue}{B \cdot 0.5}}{A}\right) \]
        8. associate-/l*46.2%

          \[\leadsto \frac{180}{\pi} \cdot \tan^{-1} \color{blue}{\left(\frac{B}{\frac{A}{0.5}}\right)} \]
      8. Simplified46.2%

        \[\leadsto \color{blue}{\frac{180}{\pi} \cdot \tan^{-1} \left(\frac{B}{\frac{A}{0.5}}\right)} \]

      if -4.3000000000000001e-262 < C < 6.19999999999999963e-154

      1. Initial program 49.3%

        \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
      2. Add Preprocessing
      3. Taylor expanded in B around inf 47.1%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{-1}}{\pi} \]

      if 6.19999999999999963e-154 < C < 9.4000000000000005e51

      1. Initial program 62.4%

        \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
      2. Add Preprocessing
      3. Taylor expanded in C around 0 59.9%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(-1 \cdot \frac{A + \sqrt{{A}^{2} + {B}^{2}}}{B}\right)}}{\pi} \]
      4. Step-by-step derivation
        1. associate-*r/59.9%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{-1 \cdot \left(A + \sqrt{{A}^{2} + {B}^{2}}\right)}{B}\right)}}{\pi} \]
        2. mul-1-neg59.9%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\color{blue}{-\left(A + \sqrt{{A}^{2} + {B}^{2}}\right)}}{B}\right)}{\pi} \]
        3. +-commutative59.9%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{-\left(A + \sqrt{\color{blue}{{B}^{2} + {A}^{2}}}\right)}{B}\right)}{\pi} \]
        4. unpow259.9%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{-\left(A + \sqrt{\color{blue}{B \cdot B} + {A}^{2}}\right)}{B}\right)}{\pi} \]
        5. unpow259.9%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{-\left(A + \sqrt{B \cdot B + \color{blue}{A \cdot A}}\right)}{B}\right)}{\pi} \]
        6. hypot-def82.8%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{-\left(A + \color{blue}{\mathsf{hypot}\left(B, A\right)}\right)}{B}\right)}{\pi} \]
      5. Simplified82.8%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{-\left(A + \mathsf{hypot}\left(B, A\right)\right)}{B}\right)}}{\pi} \]
      6. Taylor expanded in B around -inf 53.2%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(1 + -1 \cdot \frac{A}{B}\right)}}{\pi} \]
      7. Step-by-step derivation
        1. mul-1-neg53.2%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \color{blue}{\left(-\frac{A}{B}\right)}\right)}{\pi} \]
        2. unsub-neg53.2%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(1 - \frac{A}{B}\right)}}{\pi} \]
      8. Simplified53.2%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(1 - \frac{A}{B}\right)}}{\pi} \]

      if 9.4000000000000005e51 < C

      1. Initial program 21.2%

        \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
      2. Add Preprocessing
      3. Taylor expanded in A around 0 21.7%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{C - \sqrt{{B}^{2} + {C}^{2}}}{B}\right)}}{\pi} \]
      4. Step-by-step derivation
        1. unpow221.7%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{C - \sqrt{\color{blue}{B \cdot B} + {C}^{2}}}{B}\right)}{\pi} \]
        2. unpow221.7%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{C - \sqrt{B \cdot B + \color{blue}{C \cdot C}}}{B}\right)}{\pi} \]
        3. hypot-def52.4%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{C - \color{blue}{\mathsf{hypot}\left(B, C\right)}}{B}\right)}{\pi} \]
      5. Simplified52.4%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{C - \mathsf{hypot}\left(B, C\right)}{B}\right)}}{\pi} \]
      6. Taylor expanded in C around inf 76.7%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(-0.5 \cdot \frac{B}{C}\right)}}{\pi} \]
      7. Step-by-step derivation
        1. associate-*r/76.7%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{-0.5 \cdot B}{C}\right)}}{\pi} \]
      8. Simplified76.7%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{-0.5 \cdot B}{C}\right)}}{\pi} \]
    3. Recombined 5 regimes into one program.
    4. Final simplification64.3%

      \[\leadsto \begin{array}{l} \mathbf{if}\;C \leq -3.2 \cdot 10^{-163}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{B + C}{B}\right)}{\pi}\\ \mathbf{elif}\;C \leq -4.3 \cdot 10^{-262}:\\ \;\;\;\;\frac{180}{\pi} \cdot \tan^{-1} \left(\frac{B}{\frac{A}{0.5}}\right)\\ \mathbf{elif}\;C \leq 6.2 \cdot 10^{-154}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} -1}{\pi}\\ \mathbf{elif}\;C \leq 9.4 \cdot 10^{+51}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(1 - \frac{A}{B}\right)}{\pi}\\ \mathbf{else}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{B \cdot -0.5}{C}\right)}{\pi}\\ \end{array} \]
    5. Add Preprocessing

    Alternative 7: 54.2% accurate, 3.2× speedup?

    \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;C \leq -2 \cdot 10^{-164}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{B + C}{B}\right)}{\pi}\\ \mathbf{elif}\;C \leq -3.8 \cdot 10^{-259}:\\ \;\;\;\;\frac{180}{\pi} \cdot \tan^{-1} \left(\frac{B}{\frac{A}{0.5}}\right)\\ \mathbf{elif}\;C \leq 1.32 \cdot 10^{-151}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} -1}{\pi}\\ \mathbf{elif}\;C \leq 1.08 \cdot 10^{+53}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(1 - \frac{A}{B}\right)}{\pi}\\ \mathbf{else}:\\ \;\;\;\;\frac{180 \cdot \tan^{-1} \left(-0.5 \cdot \frac{B}{C}\right)}{\pi}\\ \end{array} \end{array} \]
    (FPCore (A B C)
     :precision binary64
     (if (<= C -2e-164)
       (* 180.0 (/ (atan (/ (+ B C) B)) PI))
       (if (<= C -3.8e-259)
         (* (/ 180.0 PI) (atan (/ B (/ A 0.5))))
         (if (<= C 1.32e-151)
           (* 180.0 (/ (atan -1.0) PI))
           (if (<= C 1.08e+53)
             (* 180.0 (/ (atan (- 1.0 (/ A B))) PI))
             (/ (* 180.0 (atan (* -0.5 (/ B C)))) PI))))))
    double code(double A, double B, double C) {
    	double tmp;
    	if (C <= -2e-164) {
    		tmp = 180.0 * (atan(((B + C) / B)) / ((double) M_PI));
    	} else if (C <= -3.8e-259) {
    		tmp = (180.0 / ((double) M_PI)) * atan((B / (A / 0.5)));
    	} else if (C <= 1.32e-151) {
    		tmp = 180.0 * (atan(-1.0) / ((double) M_PI));
    	} else if (C <= 1.08e+53) {
    		tmp = 180.0 * (atan((1.0 - (A / B))) / ((double) M_PI));
    	} else {
    		tmp = (180.0 * atan((-0.5 * (B / C)))) / ((double) M_PI);
    	}
    	return tmp;
    }
    
    public static double code(double A, double B, double C) {
    	double tmp;
    	if (C <= -2e-164) {
    		tmp = 180.0 * (Math.atan(((B + C) / B)) / Math.PI);
    	} else if (C <= -3.8e-259) {
    		tmp = (180.0 / Math.PI) * Math.atan((B / (A / 0.5)));
    	} else if (C <= 1.32e-151) {
    		tmp = 180.0 * (Math.atan(-1.0) / Math.PI);
    	} else if (C <= 1.08e+53) {
    		tmp = 180.0 * (Math.atan((1.0 - (A / B))) / Math.PI);
    	} else {
    		tmp = (180.0 * Math.atan((-0.5 * (B / C)))) / Math.PI;
    	}
    	return tmp;
    }
    
    def code(A, B, C):
    	tmp = 0
    	if C <= -2e-164:
    		tmp = 180.0 * (math.atan(((B + C) / B)) / math.pi)
    	elif C <= -3.8e-259:
    		tmp = (180.0 / math.pi) * math.atan((B / (A / 0.5)))
    	elif C <= 1.32e-151:
    		tmp = 180.0 * (math.atan(-1.0) / math.pi)
    	elif C <= 1.08e+53:
    		tmp = 180.0 * (math.atan((1.0 - (A / B))) / math.pi)
    	else:
    		tmp = (180.0 * math.atan((-0.5 * (B / C)))) / math.pi
    	return tmp
    
    function code(A, B, C)
    	tmp = 0.0
    	if (C <= -2e-164)
    		tmp = Float64(180.0 * Float64(atan(Float64(Float64(B + C) / B)) / pi));
    	elseif (C <= -3.8e-259)
    		tmp = Float64(Float64(180.0 / pi) * atan(Float64(B / Float64(A / 0.5))));
    	elseif (C <= 1.32e-151)
    		tmp = Float64(180.0 * Float64(atan(-1.0) / pi));
    	elseif (C <= 1.08e+53)
    		tmp = Float64(180.0 * Float64(atan(Float64(1.0 - Float64(A / B))) / pi));
    	else
    		tmp = Float64(Float64(180.0 * atan(Float64(-0.5 * Float64(B / C)))) / pi);
    	end
    	return tmp
    end
    
    function tmp_2 = code(A, B, C)
    	tmp = 0.0;
    	if (C <= -2e-164)
    		tmp = 180.0 * (atan(((B + C) / B)) / pi);
    	elseif (C <= -3.8e-259)
    		tmp = (180.0 / pi) * atan((B / (A / 0.5)));
    	elseif (C <= 1.32e-151)
    		tmp = 180.0 * (atan(-1.0) / pi);
    	elseif (C <= 1.08e+53)
    		tmp = 180.0 * (atan((1.0 - (A / B))) / pi);
    	else
    		tmp = (180.0 * atan((-0.5 * (B / C)))) / pi;
    	end
    	tmp_2 = tmp;
    end
    
    code[A_, B_, C_] := If[LessEqual[C, -2e-164], N[(180.0 * N[(N[ArcTan[N[(N[(B + C), $MachinePrecision] / B), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision], If[LessEqual[C, -3.8e-259], N[(N[(180.0 / Pi), $MachinePrecision] * N[ArcTan[N[(B / N[(A / 0.5), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision], If[LessEqual[C, 1.32e-151], N[(180.0 * N[(N[ArcTan[-1.0], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision], If[LessEqual[C, 1.08e+53], N[(180.0 * N[(N[ArcTan[N[(1.0 - N[(A / B), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision], N[(N[(180.0 * N[ArcTan[N[(-0.5 * N[(B / C), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] / Pi), $MachinePrecision]]]]]
    
    \begin{array}{l}
    
    \\
    \begin{array}{l}
    \mathbf{if}\;C \leq -2 \cdot 10^{-164}:\\
    \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{B + C}{B}\right)}{\pi}\\
    
    \mathbf{elif}\;C \leq -3.8 \cdot 10^{-259}:\\
    \;\;\;\;\frac{180}{\pi} \cdot \tan^{-1} \left(\frac{B}{\frac{A}{0.5}}\right)\\
    
    \mathbf{elif}\;C \leq 1.32 \cdot 10^{-151}:\\
    \;\;\;\;180 \cdot \frac{\tan^{-1} -1}{\pi}\\
    
    \mathbf{elif}\;C \leq 1.08 \cdot 10^{+53}:\\
    \;\;\;\;180 \cdot \frac{\tan^{-1} \left(1 - \frac{A}{B}\right)}{\pi}\\
    
    \mathbf{else}:\\
    \;\;\;\;\frac{180 \cdot \tan^{-1} \left(-0.5 \cdot \frac{B}{C}\right)}{\pi}\\
    
    
    \end{array}
    \end{array}
    
    Derivation
    1. Split input into 5 regimes
    2. if C < -1.99999999999999992e-164

      1. Initial program 78.7%

        \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
      2. Add Preprocessing
      3. Taylor expanded in A around 0 75.0%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{C - \sqrt{{B}^{2} + {C}^{2}}}{B}\right)}}{\pi} \]
      4. Step-by-step derivation
        1. unpow275.0%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{C - \sqrt{\color{blue}{B \cdot B} + {C}^{2}}}{B}\right)}{\pi} \]
        2. unpow275.0%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{C - \sqrt{B \cdot B + \color{blue}{C \cdot C}}}{B}\right)}{\pi} \]
        3. hypot-def86.3%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{C - \color{blue}{\mathsf{hypot}\left(B, C\right)}}{B}\right)}{\pi} \]
      5. Simplified86.3%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{C - \mathsf{hypot}\left(B, C\right)}{B}\right)}}{\pi} \]
      6. Taylor expanded in B around -inf 72.1%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\color{blue}{B + C}}{B}\right)}{\pi} \]

      if -1.99999999999999992e-164 < C < -3.8e-259

      1. Initial program 48.3%

        \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
      2. Add Preprocessing
      3. Taylor expanded in A around -inf 45.9%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(0.5 \cdot \frac{B}{A}\right)}}{\pi} \]
      4. Step-by-step derivation
        1. associate-*r/45.9%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{0.5 \cdot B}{A}\right)}}{\pi} \]
      5. Simplified45.9%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{0.5 \cdot B}{A}\right)}}{\pi} \]
      6. Taylor expanded in B around 0 45.9%

        \[\leadsto \color{blue}{180 \cdot \frac{\tan^{-1} \left(0.5 \cdot \frac{B}{A}\right)}{\pi}} \]
      7. Step-by-step derivation
        1. associate-*r/46.1%

          \[\leadsto \color{blue}{\frac{180 \cdot \tan^{-1} \left(0.5 \cdot \frac{B}{A}\right)}{\pi}} \]
        2. associate-/l*45.4%

          \[\leadsto \color{blue}{\frac{180}{\frac{\pi}{\tan^{-1} \left(0.5 \cdot \frac{B}{A}\right)}}} \]
        3. associate-*r/45.4%

          \[\leadsto \frac{180}{\frac{\pi}{\tan^{-1} \color{blue}{\left(\frac{0.5 \cdot B}{A}\right)}}} \]
        4. associate-/l*45.3%

          \[\leadsto \frac{180}{\frac{\pi}{\tan^{-1} \color{blue}{\left(\frac{0.5}{\frac{A}{B}}\right)}}} \]
        5. associate-/r/45.3%

          \[\leadsto \color{blue}{\frac{180}{\pi} \cdot \tan^{-1} \left(\frac{0.5}{\frac{A}{B}}\right)} \]
        6. associate-/l*46.2%

          \[\leadsto \frac{180}{\pi} \cdot \tan^{-1} \color{blue}{\left(\frac{0.5 \cdot B}{A}\right)} \]
        7. *-commutative46.2%

          \[\leadsto \frac{180}{\pi} \cdot \tan^{-1} \left(\frac{\color{blue}{B \cdot 0.5}}{A}\right) \]
        8. associate-/l*46.2%

          \[\leadsto \frac{180}{\pi} \cdot \tan^{-1} \color{blue}{\left(\frac{B}{\frac{A}{0.5}}\right)} \]
      8. Simplified46.2%

        \[\leadsto \color{blue}{\frac{180}{\pi} \cdot \tan^{-1} \left(\frac{B}{\frac{A}{0.5}}\right)} \]

      if -3.8e-259 < C < 1.31999999999999999e-151

      1. Initial program 49.3%

        \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
      2. Add Preprocessing
      3. Taylor expanded in B around inf 47.1%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{-1}}{\pi} \]

      if 1.31999999999999999e-151 < C < 1.08e53

      1. Initial program 62.4%

        \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
      2. Add Preprocessing
      3. Taylor expanded in C around 0 59.9%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(-1 \cdot \frac{A + \sqrt{{A}^{2} + {B}^{2}}}{B}\right)}}{\pi} \]
      4. Step-by-step derivation
        1. associate-*r/59.9%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{-1 \cdot \left(A + \sqrt{{A}^{2} + {B}^{2}}\right)}{B}\right)}}{\pi} \]
        2. mul-1-neg59.9%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\color{blue}{-\left(A + \sqrt{{A}^{2} + {B}^{2}}\right)}}{B}\right)}{\pi} \]
        3. +-commutative59.9%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{-\left(A + \sqrt{\color{blue}{{B}^{2} + {A}^{2}}}\right)}{B}\right)}{\pi} \]
        4. unpow259.9%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{-\left(A + \sqrt{\color{blue}{B \cdot B} + {A}^{2}}\right)}{B}\right)}{\pi} \]
        5. unpow259.9%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{-\left(A + \sqrt{B \cdot B + \color{blue}{A \cdot A}}\right)}{B}\right)}{\pi} \]
        6. hypot-def82.8%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{-\left(A + \color{blue}{\mathsf{hypot}\left(B, A\right)}\right)}{B}\right)}{\pi} \]
      5. Simplified82.8%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{-\left(A + \mathsf{hypot}\left(B, A\right)\right)}{B}\right)}}{\pi} \]
      6. Taylor expanded in B around -inf 53.2%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(1 + -1 \cdot \frac{A}{B}\right)}}{\pi} \]
      7. Step-by-step derivation
        1. mul-1-neg53.2%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \color{blue}{\left(-\frac{A}{B}\right)}\right)}{\pi} \]
        2. unsub-neg53.2%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(1 - \frac{A}{B}\right)}}{\pi} \]
      8. Simplified53.2%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(1 - \frac{A}{B}\right)}}{\pi} \]

      if 1.08e53 < C

      1. Initial program 21.2%

        \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
      2. Add Preprocessing
      3. Taylor expanded in A around 0 21.7%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{C - \sqrt{{B}^{2} + {C}^{2}}}{B}\right)}}{\pi} \]
      4. Step-by-step derivation
        1. unpow221.7%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{C - \sqrt{\color{blue}{B \cdot B} + {C}^{2}}}{B}\right)}{\pi} \]
        2. unpow221.7%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{C - \sqrt{B \cdot B + \color{blue}{C \cdot C}}}{B}\right)}{\pi} \]
        3. hypot-def52.4%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{C - \color{blue}{\mathsf{hypot}\left(B, C\right)}}{B}\right)}{\pi} \]
      5. Simplified52.4%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{C - \mathsf{hypot}\left(B, C\right)}{B}\right)}}{\pi} \]
      6. Taylor expanded in C around inf 68.7%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\color{blue}{-0.5 \cdot \frac{{B}^{2}}{C}}}{B}\right)}{\pi} \]
      7. Taylor expanded in B around 0 76.7%

        \[\leadsto \color{blue}{180 \cdot \frac{\tan^{-1} \left(-0.5 \cdot \frac{B}{C}\right)}{\pi}} \]
      8. Step-by-step derivation
        1. associate-*r/76.8%

          \[\leadsto \color{blue}{\frac{180 \cdot \tan^{-1} \left(-0.5 \cdot \frac{B}{C}\right)}{\pi}} \]
      9. Simplified76.8%

        \[\leadsto \color{blue}{\frac{180 \cdot \tan^{-1} \left(-0.5 \cdot \frac{B}{C}\right)}{\pi}} \]
    3. Recombined 5 regimes into one program.
    4. Final simplification64.3%

      \[\leadsto \begin{array}{l} \mathbf{if}\;C \leq -2 \cdot 10^{-164}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{B + C}{B}\right)}{\pi}\\ \mathbf{elif}\;C \leq -3.8 \cdot 10^{-259}:\\ \;\;\;\;\frac{180}{\pi} \cdot \tan^{-1} \left(\frac{B}{\frac{A}{0.5}}\right)\\ \mathbf{elif}\;C \leq 1.32 \cdot 10^{-151}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} -1}{\pi}\\ \mathbf{elif}\;C \leq 1.08 \cdot 10^{+53}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(1 - \frac{A}{B}\right)}{\pi}\\ \mathbf{else}:\\ \;\;\;\;\frac{180 \cdot \tan^{-1} \left(-0.5 \cdot \frac{B}{C}\right)}{\pi}\\ \end{array} \]
    5. Add Preprocessing

    Alternative 8: 45.3% accurate, 3.4× speedup?

    \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;B \leq -3.45 \cdot 10^{-12}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} 1}{\pi}\\ \mathbf{elif}\;B \leq 1.55 \cdot 10^{-289}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{C}{B}\right)}{\pi}\\ \mathbf{elif}\;B \leq 4.5 \cdot 10^{-34}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{0}{B}\right)}{\pi}\\ \mathbf{else}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} -1}{\pi}\\ \end{array} \end{array} \]
    (FPCore (A B C)
     :precision binary64
     (if (<= B -3.45e-12)
       (* 180.0 (/ (atan 1.0) PI))
       (if (<= B 1.55e-289)
         (* 180.0 (/ (atan (/ C B)) PI))
         (if (<= B 4.5e-34)
           (* 180.0 (/ (atan (/ 0.0 B)) PI))
           (* 180.0 (/ (atan -1.0) PI))))))
    double code(double A, double B, double C) {
    	double tmp;
    	if (B <= -3.45e-12) {
    		tmp = 180.0 * (atan(1.0) / ((double) M_PI));
    	} else if (B <= 1.55e-289) {
    		tmp = 180.0 * (atan((C / B)) / ((double) M_PI));
    	} else if (B <= 4.5e-34) {
    		tmp = 180.0 * (atan((0.0 / B)) / ((double) M_PI));
    	} else {
    		tmp = 180.0 * (atan(-1.0) / ((double) M_PI));
    	}
    	return tmp;
    }
    
    public static double code(double A, double B, double C) {
    	double tmp;
    	if (B <= -3.45e-12) {
    		tmp = 180.0 * (Math.atan(1.0) / Math.PI);
    	} else if (B <= 1.55e-289) {
    		tmp = 180.0 * (Math.atan((C / B)) / Math.PI);
    	} else if (B <= 4.5e-34) {
    		tmp = 180.0 * (Math.atan((0.0 / B)) / Math.PI);
    	} else {
    		tmp = 180.0 * (Math.atan(-1.0) / Math.PI);
    	}
    	return tmp;
    }
    
    def code(A, B, C):
    	tmp = 0
    	if B <= -3.45e-12:
    		tmp = 180.0 * (math.atan(1.0) / math.pi)
    	elif B <= 1.55e-289:
    		tmp = 180.0 * (math.atan((C / B)) / math.pi)
    	elif B <= 4.5e-34:
    		tmp = 180.0 * (math.atan((0.0 / B)) / math.pi)
    	else:
    		tmp = 180.0 * (math.atan(-1.0) / math.pi)
    	return tmp
    
    function code(A, B, C)
    	tmp = 0.0
    	if (B <= -3.45e-12)
    		tmp = Float64(180.0 * Float64(atan(1.0) / pi));
    	elseif (B <= 1.55e-289)
    		tmp = Float64(180.0 * Float64(atan(Float64(C / B)) / pi));
    	elseif (B <= 4.5e-34)
    		tmp = Float64(180.0 * Float64(atan(Float64(0.0 / B)) / pi));
    	else
    		tmp = Float64(180.0 * Float64(atan(-1.0) / pi));
    	end
    	return tmp
    end
    
    function tmp_2 = code(A, B, C)
    	tmp = 0.0;
    	if (B <= -3.45e-12)
    		tmp = 180.0 * (atan(1.0) / pi);
    	elseif (B <= 1.55e-289)
    		tmp = 180.0 * (atan((C / B)) / pi);
    	elseif (B <= 4.5e-34)
    		tmp = 180.0 * (atan((0.0 / B)) / pi);
    	else
    		tmp = 180.0 * (atan(-1.0) / pi);
    	end
    	tmp_2 = tmp;
    end
    
    code[A_, B_, C_] := If[LessEqual[B, -3.45e-12], N[(180.0 * N[(N[ArcTan[1.0], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision], If[LessEqual[B, 1.55e-289], N[(180.0 * N[(N[ArcTan[N[(C / B), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision], If[LessEqual[B, 4.5e-34], N[(180.0 * N[(N[ArcTan[N[(0.0 / B), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision], N[(180.0 * N[(N[ArcTan[-1.0], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision]]]]
    
    \begin{array}{l}
    
    \\
    \begin{array}{l}
    \mathbf{if}\;B \leq -3.45 \cdot 10^{-12}:\\
    \;\;\;\;180 \cdot \frac{\tan^{-1} 1}{\pi}\\
    
    \mathbf{elif}\;B \leq 1.55 \cdot 10^{-289}:\\
    \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{C}{B}\right)}{\pi}\\
    
    \mathbf{elif}\;B \leq 4.5 \cdot 10^{-34}:\\
    \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{0}{B}\right)}{\pi}\\
    
    \mathbf{else}:\\
    \;\;\;\;180 \cdot \frac{\tan^{-1} -1}{\pi}\\
    
    
    \end{array}
    \end{array}
    
    Derivation
    1. Split input into 4 regimes
    2. if B < -3.45e-12

      1. Initial program 58.4%

        \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
      2. Add Preprocessing
      3. Taylor expanded in B around -inf 61.8%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{1}}{\pi} \]

      if -3.45e-12 < B < 1.55e-289

      1. Initial program 68.2%

        \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
      2. Add Preprocessing
      3. Taylor expanded in A around 0 57.1%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{C - \sqrt{{B}^{2} + {C}^{2}}}{B}\right)}}{\pi} \]
      4. Step-by-step derivation
        1. unpow257.1%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{C - \sqrt{\color{blue}{B \cdot B} + {C}^{2}}}{B}\right)}{\pi} \]
        2. unpow257.1%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{C - \sqrt{B \cdot B + \color{blue}{C \cdot C}}}{B}\right)}{\pi} \]
        3. hypot-def65.5%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{C - \color{blue}{\mathsf{hypot}\left(B, C\right)}}{B}\right)}{\pi} \]
      5. Simplified65.5%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{C - \mathsf{hypot}\left(B, C\right)}{B}\right)}}{\pi} \]
      6. Taylor expanded in B around -inf 49.0%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\color{blue}{B + C}}{B}\right)}{\pi} \]
      7. Taylor expanded in B around 0 48.1%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{C}{B}\right)}}{\pi} \]

      if 1.55e-289 < B < 4.50000000000000042e-34

      1. Initial program 50.8%

        \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
      2. Add Preprocessing
      3. Taylor expanded in C around inf 48.1%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(-1 \cdot \frac{A + -1 \cdot A}{B}\right)}}{\pi} \]
      4. Step-by-step derivation
        1. associate-*r/48.1%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{-1 \cdot \left(A + -1 \cdot A\right)}{B}\right)}}{\pi} \]
        2. distribute-rgt1-in48.1%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{-1 \cdot \color{blue}{\left(\left(-1 + 1\right) \cdot A\right)}}{B}\right)}{\pi} \]
        3. metadata-eval48.1%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{-1 \cdot \left(\color{blue}{0} \cdot A\right)}{B}\right)}{\pi} \]
        4. mul0-lft48.1%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{-1 \cdot \color{blue}{0}}{B}\right)}{\pi} \]
        5. metadata-eval48.1%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\color{blue}{0}}{B}\right)}{\pi} \]
      5. Simplified48.1%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{0}{B}\right)}}{\pi} \]

      if 4.50000000000000042e-34 < B

      1. Initial program 54.7%

        \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
      2. Add Preprocessing
      3. Taylor expanded in B around inf 60.5%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{-1}}{\pi} \]
    3. Recombined 4 regimes into one program.
    4. Final simplification55.8%

      \[\leadsto \begin{array}{l} \mathbf{if}\;B \leq -3.45 \cdot 10^{-12}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} 1}{\pi}\\ \mathbf{elif}\;B \leq 1.55 \cdot 10^{-289}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{C}{B}\right)}{\pi}\\ \mathbf{elif}\;B \leq 4.5 \cdot 10^{-34}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{0}{B}\right)}{\pi}\\ \mathbf{else}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} -1}{\pi}\\ \end{array} \]
    5. Add Preprocessing

    Alternative 9: 45.3% accurate, 3.4× speedup?

    \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;B \leq -6.5 \cdot 10^{-15}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} 1}{\pi}\\ \mathbf{elif}\;B \leq 3.8 \cdot 10^{-291}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(2 \cdot \frac{C}{B}\right)}{\pi}\\ \mathbf{elif}\;B \leq 2.1 \cdot 10^{-36}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{0}{B}\right)}{\pi}\\ \mathbf{else}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} -1}{\pi}\\ \end{array} \end{array} \]
    (FPCore (A B C)
     :precision binary64
     (if (<= B -6.5e-15)
       (* 180.0 (/ (atan 1.0) PI))
       (if (<= B 3.8e-291)
         (* 180.0 (/ (atan (* 2.0 (/ C B))) PI))
         (if (<= B 2.1e-36)
           (* 180.0 (/ (atan (/ 0.0 B)) PI))
           (* 180.0 (/ (atan -1.0) PI))))))
    double code(double A, double B, double C) {
    	double tmp;
    	if (B <= -6.5e-15) {
    		tmp = 180.0 * (atan(1.0) / ((double) M_PI));
    	} else if (B <= 3.8e-291) {
    		tmp = 180.0 * (atan((2.0 * (C / B))) / ((double) M_PI));
    	} else if (B <= 2.1e-36) {
    		tmp = 180.0 * (atan((0.0 / B)) / ((double) M_PI));
    	} else {
    		tmp = 180.0 * (atan(-1.0) / ((double) M_PI));
    	}
    	return tmp;
    }
    
    public static double code(double A, double B, double C) {
    	double tmp;
    	if (B <= -6.5e-15) {
    		tmp = 180.0 * (Math.atan(1.0) / Math.PI);
    	} else if (B <= 3.8e-291) {
    		tmp = 180.0 * (Math.atan((2.0 * (C / B))) / Math.PI);
    	} else if (B <= 2.1e-36) {
    		tmp = 180.0 * (Math.atan((0.0 / B)) / Math.PI);
    	} else {
    		tmp = 180.0 * (Math.atan(-1.0) / Math.PI);
    	}
    	return tmp;
    }
    
    def code(A, B, C):
    	tmp = 0
    	if B <= -6.5e-15:
    		tmp = 180.0 * (math.atan(1.0) / math.pi)
    	elif B <= 3.8e-291:
    		tmp = 180.0 * (math.atan((2.0 * (C / B))) / math.pi)
    	elif B <= 2.1e-36:
    		tmp = 180.0 * (math.atan((0.0 / B)) / math.pi)
    	else:
    		tmp = 180.0 * (math.atan(-1.0) / math.pi)
    	return tmp
    
    function code(A, B, C)
    	tmp = 0.0
    	if (B <= -6.5e-15)
    		tmp = Float64(180.0 * Float64(atan(1.0) / pi));
    	elseif (B <= 3.8e-291)
    		tmp = Float64(180.0 * Float64(atan(Float64(2.0 * Float64(C / B))) / pi));
    	elseif (B <= 2.1e-36)
    		tmp = Float64(180.0 * Float64(atan(Float64(0.0 / B)) / pi));
    	else
    		tmp = Float64(180.0 * Float64(atan(-1.0) / pi));
    	end
    	return tmp
    end
    
    function tmp_2 = code(A, B, C)
    	tmp = 0.0;
    	if (B <= -6.5e-15)
    		tmp = 180.0 * (atan(1.0) / pi);
    	elseif (B <= 3.8e-291)
    		tmp = 180.0 * (atan((2.0 * (C / B))) / pi);
    	elseif (B <= 2.1e-36)
    		tmp = 180.0 * (atan((0.0 / B)) / pi);
    	else
    		tmp = 180.0 * (atan(-1.0) / pi);
    	end
    	tmp_2 = tmp;
    end
    
    code[A_, B_, C_] := If[LessEqual[B, -6.5e-15], N[(180.0 * N[(N[ArcTan[1.0], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision], If[LessEqual[B, 3.8e-291], N[(180.0 * N[(N[ArcTan[N[(2.0 * N[(C / B), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision], If[LessEqual[B, 2.1e-36], N[(180.0 * N[(N[ArcTan[N[(0.0 / B), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision], N[(180.0 * N[(N[ArcTan[-1.0], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision]]]]
    
    \begin{array}{l}
    
    \\
    \begin{array}{l}
    \mathbf{if}\;B \leq -6.5 \cdot 10^{-15}:\\
    \;\;\;\;180 \cdot \frac{\tan^{-1} 1}{\pi}\\
    
    \mathbf{elif}\;B \leq 3.8 \cdot 10^{-291}:\\
    \;\;\;\;180 \cdot \frac{\tan^{-1} \left(2 \cdot \frac{C}{B}\right)}{\pi}\\
    
    \mathbf{elif}\;B \leq 2.1 \cdot 10^{-36}:\\
    \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{0}{B}\right)}{\pi}\\
    
    \mathbf{else}:\\
    \;\;\;\;180 \cdot \frac{\tan^{-1} -1}{\pi}\\
    
    
    \end{array}
    \end{array}
    
    Derivation
    1. Split input into 4 regimes
    2. if B < -6.49999999999999991e-15

      1. Initial program 58.4%

        \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
      2. Add Preprocessing
      3. Taylor expanded in B around -inf 61.8%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{1}}{\pi} \]

      if -6.49999999999999991e-15 < B < 3.7999999999999998e-291

      1. Initial program 68.2%

        \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
      2. Add Preprocessing
      3. Taylor expanded in C around -inf 49.0%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(2 \cdot \frac{C}{B}\right)}}{\pi} \]

      if 3.7999999999999998e-291 < B < 2.09999999999999991e-36

      1. Initial program 50.8%

        \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
      2. Add Preprocessing
      3. Taylor expanded in C around inf 48.1%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(-1 \cdot \frac{A + -1 \cdot A}{B}\right)}}{\pi} \]
      4. Step-by-step derivation
        1. associate-*r/48.1%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{-1 \cdot \left(A + -1 \cdot A\right)}{B}\right)}}{\pi} \]
        2. distribute-rgt1-in48.1%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{-1 \cdot \color{blue}{\left(\left(-1 + 1\right) \cdot A\right)}}{B}\right)}{\pi} \]
        3. metadata-eval48.1%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{-1 \cdot \left(\color{blue}{0} \cdot A\right)}{B}\right)}{\pi} \]
        4. mul0-lft48.1%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{-1 \cdot \color{blue}{0}}{B}\right)}{\pi} \]
        5. metadata-eval48.1%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\color{blue}{0}}{B}\right)}{\pi} \]
      5. Simplified48.1%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{0}{B}\right)}}{\pi} \]

      if 2.09999999999999991e-36 < B

      1. Initial program 54.7%

        \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
      2. Add Preprocessing
      3. Taylor expanded in B around inf 60.5%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{-1}}{\pi} \]
    3. Recombined 4 regimes into one program.
    4. Final simplification56.1%

      \[\leadsto \begin{array}{l} \mathbf{if}\;B \leq -6.5 \cdot 10^{-15}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} 1}{\pi}\\ \mathbf{elif}\;B \leq 3.8 \cdot 10^{-291}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(2 \cdot \frac{C}{B}\right)}{\pi}\\ \mathbf{elif}\;B \leq 2.1 \cdot 10^{-36}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{0}{B}\right)}{\pi}\\ \mathbf{else}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} -1}{\pi}\\ \end{array} \]
    5. Add Preprocessing

    Alternative 10: 49.7% accurate, 3.4× speedup?

    \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;B \leq -2 \cdot 10^{-162}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(1 - \frac{A}{B}\right)}{\pi}\\ \mathbf{elif}\;B \leq 1.56 \cdot 10^{-291}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{C}{B}\right)}{\pi}\\ \mathbf{elif}\;B \leq 2.1 \cdot 10^{-36}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{0}{B}\right)}{\pi}\\ \mathbf{else}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} -1}{\pi}\\ \end{array} \end{array} \]
    (FPCore (A B C)
     :precision binary64
     (if (<= B -2e-162)
       (* 180.0 (/ (atan (- 1.0 (/ A B))) PI))
       (if (<= B 1.56e-291)
         (* 180.0 (/ (atan (/ C B)) PI))
         (if (<= B 2.1e-36)
           (* 180.0 (/ (atan (/ 0.0 B)) PI))
           (* 180.0 (/ (atan -1.0) PI))))))
    double code(double A, double B, double C) {
    	double tmp;
    	if (B <= -2e-162) {
    		tmp = 180.0 * (atan((1.0 - (A / B))) / ((double) M_PI));
    	} else if (B <= 1.56e-291) {
    		tmp = 180.0 * (atan((C / B)) / ((double) M_PI));
    	} else if (B <= 2.1e-36) {
    		tmp = 180.0 * (atan((0.0 / B)) / ((double) M_PI));
    	} else {
    		tmp = 180.0 * (atan(-1.0) / ((double) M_PI));
    	}
    	return tmp;
    }
    
    public static double code(double A, double B, double C) {
    	double tmp;
    	if (B <= -2e-162) {
    		tmp = 180.0 * (Math.atan((1.0 - (A / B))) / Math.PI);
    	} else if (B <= 1.56e-291) {
    		tmp = 180.0 * (Math.atan((C / B)) / Math.PI);
    	} else if (B <= 2.1e-36) {
    		tmp = 180.0 * (Math.atan((0.0 / B)) / Math.PI);
    	} else {
    		tmp = 180.0 * (Math.atan(-1.0) / Math.PI);
    	}
    	return tmp;
    }
    
    def code(A, B, C):
    	tmp = 0
    	if B <= -2e-162:
    		tmp = 180.0 * (math.atan((1.0 - (A / B))) / math.pi)
    	elif B <= 1.56e-291:
    		tmp = 180.0 * (math.atan((C / B)) / math.pi)
    	elif B <= 2.1e-36:
    		tmp = 180.0 * (math.atan((0.0 / B)) / math.pi)
    	else:
    		tmp = 180.0 * (math.atan(-1.0) / math.pi)
    	return tmp
    
    function code(A, B, C)
    	tmp = 0.0
    	if (B <= -2e-162)
    		tmp = Float64(180.0 * Float64(atan(Float64(1.0 - Float64(A / B))) / pi));
    	elseif (B <= 1.56e-291)
    		tmp = Float64(180.0 * Float64(atan(Float64(C / B)) / pi));
    	elseif (B <= 2.1e-36)
    		tmp = Float64(180.0 * Float64(atan(Float64(0.0 / B)) / pi));
    	else
    		tmp = Float64(180.0 * Float64(atan(-1.0) / pi));
    	end
    	return tmp
    end
    
    function tmp_2 = code(A, B, C)
    	tmp = 0.0;
    	if (B <= -2e-162)
    		tmp = 180.0 * (atan((1.0 - (A / B))) / pi);
    	elseif (B <= 1.56e-291)
    		tmp = 180.0 * (atan((C / B)) / pi);
    	elseif (B <= 2.1e-36)
    		tmp = 180.0 * (atan((0.0 / B)) / pi);
    	else
    		tmp = 180.0 * (atan(-1.0) / pi);
    	end
    	tmp_2 = tmp;
    end
    
    code[A_, B_, C_] := If[LessEqual[B, -2e-162], N[(180.0 * N[(N[ArcTan[N[(1.0 - N[(A / B), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision], If[LessEqual[B, 1.56e-291], N[(180.0 * N[(N[ArcTan[N[(C / B), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision], If[LessEqual[B, 2.1e-36], N[(180.0 * N[(N[ArcTan[N[(0.0 / B), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision], N[(180.0 * N[(N[ArcTan[-1.0], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision]]]]
    
    \begin{array}{l}
    
    \\
    \begin{array}{l}
    \mathbf{if}\;B \leq -2 \cdot 10^{-162}:\\
    \;\;\;\;180 \cdot \frac{\tan^{-1} \left(1 - \frac{A}{B}\right)}{\pi}\\
    
    \mathbf{elif}\;B \leq 1.56 \cdot 10^{-291}:\\
    \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{C}{B}\right)}{\pi}\\
    
    \mathbf{elif}\;B \leq 2.1 \cdot 10^{-36}:\\
    \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{0}{B}\right)}{\pi}\\
    
    \mathbf{else}:\\
    \;\;\;\;180 \cdot \frac{\tan^{-1} -1}{\pi}\\
    
    
    \end{array}
    \end{array}
    
    Derivation
    1. Split input into 4 regimes
    2. if B < -1.99999999999999991e-162

      1. Initial program 60.3%

        \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
      2. Add Preprocessing
      3. Taylor expanded in C around 0 50.8%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(-1 \cdot \frac{A + \sqrt{{A}^{2} + {B}^{2}}}{B}\right)}}{\pi} \]
      4. Step-by-step derivation
        1. associate-*r/50.8%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{-1 \cdot \left(A + \sqrt{{A}^{2} + {B}^{2}}\right)}{B}\right)}}{\pi} \]
        2. mul-1-neg50.8%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\color{blue}{-\left(A + \sqrt{{A}^{2} + {B}^{2}}\right)}}{B}\right)}{\pi} \]
        3. +-commutative50.8%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{-\left(A + \sqrt{\color{blue}{{B}^{2} + {A}^{2}}}\right)}{B}\right)}{\pi} \]
        4. unpow250.8%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{-\left(A + \sqrt{\color{blue}{B \cdot B} + {A}^{2}}\right)}{B}\right)}{\pi} \]
        5. unpow250.8%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{-\left(A + \sqrt{B \cdot B + \color{blue}{A \cdot A}}\right)}{B}\right)}{\pi} \]
        6. hypot-def65.5%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{-\left(A + \color{blue}{\mathsf{hypot}\left(B, A\right)}\right)}{B}\right)}{\pi} \]
      5. Simplified65.5%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{-\left(A + \mathsf{hypot}\left(B, A\right)\right)}{B}\right)}}{\pi} \]
      6. Taylor expanded in B around -inf 63.8%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(1 + -1 \cdot \frac{A}{B}\right)}}{\pi} \]
      7. Step-by-step derivation
        1. mul-1-neg63.8%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \color{blue}{\left(-\frac{A}{B}\right)}\right)}{\pi} \]
        2. unsub-neg63.8%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(1 - \frac{A}{B}\right)}}{\pi} \]
      8. Simplified63.8%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(1 - \frac{A}{B}\right)}}{\pi} \]

      if -1.99999999999999991e-162 < B < 1.56e-291

      1. Initial program 70.1%

        \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
      2. Add Preprocessing
      3. Taylor expanded in A around 0 64.9%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{C - \sqrt{{B}^{2} + {C}^{2}}}{B}\right)}}{\pi} \]
      4. Step-by-step derivation
        1. unpow264.9%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{C - \sqrt{\color{blue}{B \cdot B} + {C}^{2}}}{B}\right)}{\pi} \]
        2. unpow264.9%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{C - \sqrt{B \cdot B + \color{blue}{C \cdot C}}}{B}\right)}{\pi} \]
        3. hypot-def73.8%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{C - \color{blue}{\mathsf{hypot}\left(B, C\right)}}{B}\right)}{\pi} \]
      5. Simplified73.8%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{C - \mathsf{hypot}\left(B, C\right)}{B}\right)}}{\pi} \]
      6. Taylor expanded in B around -inf 56.1%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\color{blue}{B + C}}{B}\right)}{\pi} \]
      7. Taylor expanded in B around 0 56.0%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{C}{B}\right)}}{\pi} \]

      if 1.56e-291 < B < 2.09999999999999991e-36

      1. Initial program 50.8%

        \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
      2. Add Preprocessing
      3. Taylor expanded in C around inf 48.1%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(-1 \cdot \frac{A + -1 \cdot A}{B}\right)}}{\pi} \]
      4. Step-by-step derivation
        1. associate-*r/48.1%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{-1 \cdot \left(A + -1 \cdot A\right)}{B}\right)}}{\pi} \]
        2. distribute-rgt1-in48.1%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{-1 \cdot \color{blue}{\left(\left(-1 + 1\right) \cdot A\right)}}{B}\right)}{\pi} \]
        3. metadata-eval48.1%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{-1 \cdot \left(\color{blue}{0} \cdot A\right)}{B}\right)}{\pi} \]
        4. mul0-lft48.1%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{-1 \cdot \color{blue}{0}}{B}\right)}{\pi} \]
        5. metadata-eval48.1%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\color{blue}{0}}{B}\right)}{\pi} \]
      5. Simplified48.1%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{0}{B}\right)}}{\pi} \]

      if 2.09999999999999991e-36 < B

      1. Initial program 54.7%

        \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
      2. Add Preprocessing
      3. Taylor expanded in B around inf 60.5%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{-1}}{\pi} \]
    3. Recombined 4 regimes into one program.
    4. Final simplification59.0%

      \[\leadsto \begin{array}{l} \mathbf{if}\;B \leq -2 \cdot 10^{-162}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(1 - \frac{A}{B}\right)}{\pi}\\ \mathbf{elif}\;B \leq 1.56 \cdot 10^{-291}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{C}{B}\right)}{\pi}\\ \mathbf{elif}\;B \leq 2.1 \cdot 10^{-36}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{0}{B}\right)}{\pi}\\ \mathbf{else}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} -1}{\pi}\\ \end{array} \]
    5. Add Preprocessing

    Alternative 11: 58.6% accurate, 3.5× speedup?

    \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;C \leq -1.32 \cdot 10^{-17}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{B + C}{B}\right)}{\pi}\\ \mathbf{elif}\;C \leq 1.4 \cdot 10^{+53}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(1 - \frac{A}{B}\right)}{\pi}\\ \mathbf{else}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{B \cdot -0.5}{C}\right)}{\pi}\\ \end{array} \end{array} \]
    (FPCore (A B C)
     :precision binary64
     (if (<= C -1.32e-17)
       (* 180.0 (/ (atan (/ (+ B C) B)) PI))
       (if (<= C 1.4e+53)
         (* 180.0 (/ (atan (- 1.0 (/ A B))) PI))
         (* 180.0 (/ (atan (/ (* B -0.5) C)) PI)))))
    double code(double A, double B, double C) {
    	double tmp;
    	if (C <= -1.32e-17) {
    		tmp = 180.0 * (atan(((B + C) / B)) / ((double) M_PI));
    	} else if (C <= 1.4e+53) {
    		tmp = 180.0 * (atan((1.0 - (A / B))) / ((double) M_PI));
    	} else {
    		tmp = 180.0 * (atan(((B * -0.5) / C)) / ((double) M_PI));
    	}
    	return tmp;
    }
    
    public static double code(double A, double B, double C) {
    	double tmp;
    	if (C <= -1.32e-17) {
    		tmp = 180.0 * (Math.atan(((B + C) / B)) / Math.PI);
    	} else if (C <= 1.4e+53) {
    		tmp = 180.0 * (Math.atan((1.0 - (A / B))) / Math.PI);
    	} else {
    		tmp = 180.0 * (Math.atan(((B * -0.5) / C)) / Math.PI);
    	}
    	return tmp;
    }
    
    def code(A, B, C):
    	tmp = 0
    	if C <= -1.32e-17:
    		tmp = 180.0 * (math.atan(((B + C) / B)) / math.pi)
    	elif C <= 1.4e+53:
    		tmp = 180.0 * (math.atan((1.0 - (A / B))) / math.pi)
    	else:
    		tmp = 180.0 * (math.atan(((B * -0.5) / C)) / math.pi)
    	return tmp
    
    function code(A, B, C)
    	tmp = 0.0
    	if (C <= -1.32e-17)
    		tmp = Float64(180.0 * Float64(atan(Float64(Float64(B + C) / B)) / pi));
    	elseif (C <= 1.4e+53)
    		tmp = Float64(180.0 * Float64(atan(Float64(1.0 - Float64(A / B))) / pi));
    	else
    		tmp = Float64(180.0 * Float64(atan(Float64(Float64(B * -0.5) / C)) / pi));
    	end
    	return tmp
    end
    
    function tmp_2 = code(A, B, C)
    	tmp = 0.0;
    	if (C <= -1.32e-17)
    		tmp = 180.0 * (atan(((B + C) / B)) / pi);
    	elseif (C <= 1.4e+53)
    		tmp = 180.0 * (atan((1.0 - (A / B))) / pi);
    	else
    		tmp = 180.0 * (atan(((B * -0.5) / C)) / pi);
    	end
    	tmp_2 = tmp;
    end
    
    code[A_, B_, C_] := If[LessEqual[C, -1.32e-17], N[(180.0 * N[(N[ArcTan[N[(N[(B + C), $MachinePrecision] / B), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision], If[LessEqual[C, 1.4e+53], N[(180.0 * N[(N[ArcTan[N[(1.0 - N[(A / B), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision], N[(180.0 * N[(N[ArcTan[N[(N[(B * -0.5), $MachinePrecision] / C), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision]]]
    
    \begin{array}{l}
    
    \\
    \begin{array}{l}
    \mathbf{if}\;C \leq -1.32 \cdot 10^{-17}:\\
    \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{B + C}{B}\right)}{\pi}\\
    
    \mathbf{elif}\;C \leq 1.4 \cdot 10^{+53}:\\
    \;\;\;\;180 \cdot \frac{\tan^{-1} \left(1 - \frac{A}{B}\right)}{\pi}\\
    
    \mathbf{else}:\\
    \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{B \cdot -0.5}{C}\right)}{\pi}\\
    
    
    \end{array}
    \end{array}
    
    Derivation
    1. Split input into 3 regimes
    2. if C < -1.3200000000000001e-17

      1. Initial program 84.4%

        \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
      2. Add Preprocessing
      3. Taylor expanded in A around 0 84.4%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{C - \sqrt{{B}^{2} + {C}^{2}}}{B}\right)}}{\pi} \]
      4. Step-by-step derivation
        1. unpow284.4%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{C - \sqrt{\color{blue}{B \cdot B} + {C}^{2}}}{B}\right)}{\pi} \]
        2. unpow284.4%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{C - \sqrt{B \cdot B + \color{blue}{C \cdot C}}}{B}\right)}{\pi} \]
        3. hypot-def90.8%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{C - \color{blue}{\mathsf{hypot}\left(B, C\right)}}{B}\right)}{\pi} \]
      5. Simplified90.8%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{C - \mathsf{hypot}\left(B, C\right)}{B}\right)}}{\pi} \]
      6. Taylor expanded in B around -inf 79.8%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\color{blue}{B + C}}{B}\right)}{\pi} \]

      if -1.3200000000000001e-17 < C < 1.4e53

      1. Initial program 56.7%

        \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
      2. Add Preprocessing
      3. Taylor expanded in C around 0 55.3%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(-1 \cdot \frac{A + \sqrt{{A}^{2} + {B}^{2}}}{B}\right)}}{\pi} \]
      4. Step-by-step derivation
        1. associate-*r/55.3%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{-1 \cdot \left(A + \sqrt{{A}^{2} + {B}^{2}}\right)}{B}\right)}}{\pi} \]
        2. mul-1-neg55.3%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\color{blue}{-\left(A + \sqrt{{A}^{2} + {B}^{2}}\right)}}{B}\right)}{\pi} \]
        3. +-commutative55.3%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{-\left(A + \sqrt{\color{blue}{{B}^{2} + {A}^{2}}}\right)}{B}\right)}{\pi} \]
        4. unpow255.3%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{-\left(A + \sqrt{\color{blue}{B \cdot B} + {A}^{2}}\right)}{B}\right)}{\pi} \]
        5. unpow255.3%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{-\left(A + \sqrt{B \cdot B + \color{blue}{A \cdot A}}\right)}{B}\right)}{\pi} \]
        6. hypot-def83.2%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{-\left(A + \color{blue}{\mathsf{hypot}\left(B, A\right)}\right)}{B}\right)}{\pi} \]
      5. Simplified83.2%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{-\left(A + \mathsf{hypot}\left(B, A\right)\right)}{B}\right)}}{\pi} \]
      6. Taylor expanded in B around -inf 45.9%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(1 + -1 \cdot \frac{A}{B}\right)}}{\pi} \]
      7. Step-by-step derivation
        1. mul-1-neg45.9%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \color{blue}{\left(-\frac{A}{B}\right)}\right)}{\pi} \]
        2. unsub-neg45.9%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(1 - \frac{A}{B}\right)}}{\pi} \]
      8. Simplified45.9%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(1 - \frac{A}{B}\right)}}{\pi} \]

      if 1.4e53 < C

      1. Initial program 21.2%

        \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
      2. Add Preprocessing
      3. Taylor expanded in A around 0 21.7%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{C - \sqrt{{B}^{2} + {C}^{2}}}{B}\right)}}{\pi} \]
      4. Step-by-step derivation
        1. unpow221.7%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{C - \sqrt{\color{blue}{B \cdot B} + {C}^{2}}}{B}\right)}{\pi} \]
        2. unpow221.7%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{C - \sqrt{B \cdot B + \color{blue}{C \cdot C}}}{B}\right)}{\pi} \]
        3. hypot-def52.4%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{C - \color{blue}{\mathsf{hypot}\left(B, C\right)}}{B}\right)}{\pi} \]
      5. Simplified52.4%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{C - \mathsf{hypot}\left(B, C\right)}{B}\right)}}{\pi} \]
      6. Taylor expanded in C around inf 76.7%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(-0.5 \cdot \frac{B}{C}\right)}}{\pi} \]
      7. Step-by-step derivation
        1. associate-*r/76.7%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{-0.5 \cdot B}{C}\right)}}{\pi} \]
      8. Simplified76.7%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{-0.5 \cdot B}{C}\right)}}{\pi} \]
    3. Recombined 3 regimes into one program.
    4. Final simplification62.1%

      \[\leadsto \begin{array}{l} \mathbf{if}\;C \leq -1.32 \cdot 10^{-17}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{B + C}{B}\right)}{\pi}\\ \mathbf{elif}\;C \leq 1.4 \cdot 10^{+53}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(1 - \frac{A}{B}\right)}{\pi}\\ \mathbf{else}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{B \cdot -0.5}{C}\right)}{\pi}\\ \end{array} \]
    5. Add Preprocessing

    Alternative 12: 45.0% accurate, 3.6× speedup?

    \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;B \leq -1.55 \cdot 10^{-71}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} 1}{\pi}\\ \mathbf{elif}\;B \leq 6.5 \cdot 10^{-33}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{0}{B}\right)}{\pi}\\ \mathbf{else}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} -1}{\pi}\\ \end{array} \end{array} \]
    (FPCore (A B C)
     :precision binary64
     (if (<= B -1.55e-71)
       (* 180.0 (/ (atan 1.0) PI))
       (if (<= B 6.5e-33)
         (* 180.0 (/ (atan (/ 0.0 B)) PI))
         (* 180.0 (/ (atan -1.0) PI)))))
    double code(double A, double B, double C) {
    	double tmp;
    	if (B <= -1.55e-71) {
    		tmp = 180.0 * (atan(1.0) / ((double) M_PI));
    	} else if (B <= 6.5e-33) {
    		tmp = 180.0 * (atan((0.0 / B)) / ((double) M_PI));
    	} else {
    		tmp = 180.0 * (atan(-1.0) / ((double) M_PI));
    	}
    	return tmp;
    }
    
    public static double code(double A, double B, double C) {
    	double tmp;
    	if (B <= -1.55e-71) {
    		tmp = 180.0 * (Math.atan(1.0) / Math.PI);
    	} else if (B <= 6.5e-33) {
    		tmp = 180.0 * (Math.atan((0.0 / B)) / Math.PI);
    	} else {
    		tmp = 180.0 * (Math.atan(-1.0) / Math.PI);
    	}
    	return tmp;
    }
    
    def code(A, B, C):
    	tmp = 0
    	if B <= -1.55e-71:
    		tmp = 180.0 * (math.atan(1.0) / math.pi)
    	elif B <= 6.5e-33:
    		tmp = 180.0 * (math.atan((0.0 / B)) / math.pi)
    	else:
    		tmp = 180.0 * (math.atan(-1.0) / math.pi)
    	return tmp
    
    function code(A, B, C)
    	tmp = 0.0
    	if (B <= -1.55e-71)
    		tmp = Float64(180.0 * Float64(atan(1.0) / pi));
    	elseif (B <= 6.5e-33)
    		tmp = Float64(180.0 * Float64(atan(Float64(0.0 / B)) / pi));
    	else
    		tmp = Float64(180.0 * Float64(atan(-1.0) / pi));
    	end
    	return tmp
    end
    
    function tmp_2 = code(A, B, C)
    	tmp = 0.0;
    	if (B <= -1.55e-71)
    		tmp = 180.0 * (atan(1.0) / pi);
    	elseif (B <= 6.5e-33)
    		tmp = 180.0 * (atan((0.0 / B)) / pi);
    	else
    		tmp = 180.0 * (atan(-1.0) / pi);
    	end
    	tmp_2 = tmp;
    end
    
    code[A_, B_, C_] := If[LessEqual[B, -1.55e-71], N[(180.0 * N[(N[ArcTan[1.0], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision], If[LessEqual[B, 6.5e-33], N[(180.0 * N[(N[ArcTan[N[(0.0 / B), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision], N[(180.0 * N[(N[ArcTan[-1.0], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision]]]
    
    \begin{array}{l}
    
    \\
    \begin{array}{l}
    \mathbf{if}\;B \leq -1.55 \cdot 10^{-71}:\\
    \;\;\;\;180 \cdot \frac{\tan^{-1} 1}{\pi}\\
    
    \mathbf{elif}\;B \leq 6.5 \cdot 10^{-33}:\\
    \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{0}{B}\right)}{\pi}\\
    
    \mathbf{else}:\\
    \;\;\;\;180 \cdot \frac{\tan^{-1} -1}{\pi}\\
    
    
    \end{array}
    \end{array}
    
    Derivation
    1. Split input into 3 regimes
    2. if B < -1.55000000000000001e-71

      1. Initial program 60.4%

        \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
      2. Add Preprocessing
      3. Taylor expanded in B around -inf 55.4%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{1}}{\pi} \]

      if -1.55000000000000001e-71 < B < 6.4999999999999993e-33

      1. Initial program 59.0%

        \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
      2. Add Preprocessing
      3. Taylor expanded in C around inf 37.7%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(-1 \cdot \frac{A + -1 \cdot A}{B}\right)}}{\pi} \]
      4. Step-by-step derivation
        1. associate-*r/37.7%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{-1 \cdot \left(A + -1 \cdot A\right)}{B}\right)}}{\pi} \]
        2. distribute-rgt1-in37.7%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{-1 \cdot \color{blue}{\left(\left(-1 + 1\right) \cdot A\right)}}{B}\right)}{\pi} \]
        3. metadata-eval37.7%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{-1 \cdot \left(\color{blue}{0} \cdot A\right)}{B}\right)}{\pi} \]
        4. mul0-lft37.7%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{-1 \cdot \color{blue}{0}}{B}\right)}{\pi} \]
        5. metadata-eval37.7%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\color{blue}{0}}{B}\right)}{\pi} \]
      5. Simplified37.7%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{0}{B}\right)}}{\pi} \]

      if 6.4999999999999993e-33 < B

      1. Initial program 54.7%

        \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
      2. Add Preprocessing
      3. Taylor expanded in B around inf 60.5%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{-1}}{\pi} \]
    3. Recombined 3 regimes into one program.
    4. Final simplification50.7%

      \[\leadsto \begin{array}{l} \mathbf{if}\;B \leq -1.55 \cdot 10^{-71}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} 1}{\pi}\\ \mathbf{elif}\;B \leq 6.5 \cdot 10^{-33}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{0}{B}\right)}{\pi}\\ \mathbf{else}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} -1}{\pi}\\ \end{array} \]
    5. Add Preprocessing

    Alternative 13: 59.9% accurate, 3.6× speedup?

    \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;A \leq -5.1 \cdot 10^{+39}:\\ \;\;\;\;\frac{180}{\pi} \cdot \tan^{-1} \left(\frac{B}{\frac{A}{0.5}}\right)\\ \mathbf{else}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(1 + \frac{C - A}{B}\right)}{\pi}\\ \end{array} \end{array} \]
    (FPCore (A B C)
     :precision binary64
     (if (<= A -5.1e+39)
       (* (/ 180.0 PI) (atan (/ B (/ A 0.5))))
       (* 180.0 (/ (atan (+ 1.0 (/ (- C A) B))) PI))))
    double code(double A, double B, double C) {
    	double tmp;
    	if (A <= -5.1e+39) {
    		tmp = (180.0 / ((double) M_PI)) * atan((B / (A / 0.5)));
    	} else {
    		tmp = 180.0 * (atan((1.0 + ((C - A) / B))) / ((double) M_PI));
    	}
    	return tmp;
    }
    
    public static double code(double A, double B, double C) {
    	double tmp;
    	if (A <= -5.1e+39) {
    		tmp = (180.0 / Math.PI) * Math.atan((B / (A / 0.5)));
    	} else {
    		tmp = 180.0 * (Math.atan((1.0 + ((C - A) / B))) / Math.PI);
    	}
    	return tmp;
    }
    
    def code(A, B, C):
    	tmp = 0
    	if A <= -5.1e+39:
    		tmp = (180.0 / math.pi) * math.atan((B / (A / 0.5)))
    	else:
    		tmp = 180.0 * (math.atan((1.0 + ((C - A) / B))) / math.pi)
    	return tmp
    
    function code(A, B, C)
    	tmp = 0.0
    	if (A <= -5.1e+39)
    		tmp = Float64(Float64(180.0 / pi) * atan(Float64(B / Float64(A / 0.5))));
    	else
    		tmp = Float64(180.0 * Float64(atan(Float64(1.0 + Float64(Float64(C - A) / B))) / pi));
    	end
    	return tmp
    end
    
    function tmp_2 = code(A, B, C)
    	tmp = 0.0;
    	if (A <= -5.1e+39)
    		tmp = (180.0 / pi) * atan((B / (A / 0.5)));
    	else
    		tmp = 180.0 * (atan((1.0 + ((C - A) / B))) / pi);
    	end
    	tmp_2 = tmp;
    end
    
    code[A_, B_, C_] := If[LessEqual[A, -5.1e+39], N[(N[(180.0 / Pi), $MachinePrecision] * N[ArcTan[N[(B / N[(A / 0.5), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision], N[(180.0 * N[(N[ArcTan[N[(1.0 + N[(N[(C - A), $MachinePrecision] / B), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision]]
    
    \begin{array}{l}
    
    \\
    \begin{array}{l}
    \mathbf{if}\;A \leq -5.1 \cdot 10^{+39}:\\
    \;\;\;\;\frac{180}{\pi} \cdot \tan^{-1} \left(\frac{B}{\frac{A}{0.5}}\right)\\
    
    \mathbf{else}:\\
    \;\;\;\;180 \cdot \frac{\tan^{-1} \left(1 + \frac{C - A}{B}\right)}{\pi}\\
    
    
    \end{array}
    \end{array}
    
    Derivation
    1. Split input into 2 regimes
    2. if A < -5.0999999999999998e39

      1. Initial program 27.1%

        \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
      2. Add Preprocessing
      3. Taylor expanded in A around -inf 67.9%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(0.5 \cdot \frac{B}{A}\right)}}{\pi} \]
      4. Step-by-step derivation
        1. associate-*r/67.9%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{0.5 \cdot B}{A}\right)}}{\pi} \]
      5. Simplified67.9%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{0.5 \cdot B}{A}\right)}}{\pi} \]
      6. Taylor expanded in B around 0 67.9%

        \[\leadsto \color{blue}{180 \cdot \frac{\tan^{-1} \left(0.5 \cdot \frac{B}{A}\right)}{\pi}} \]
      7. Step-by-step derivation
        1. associate-*r/68.1%

          \[\leadsto \color{blue}{\frac{180 \cdot \tan^{-1} \left(0.5 \cdot \frac{B}{A}\right)}{\pi}} \]
        2. associate-/l*68.0%

          \[\leadsto \color{blue}{\frac{180}{\frac{\pi}{\tan^{-1} \left(0.5 \cdot \frac{B}{A}\right)}}} \]
        3. associate-*r/68.0%

          \[\leadsto \frac{180}{\frac{\pi}{\tan^{-1} \color{blue}{\left(\frac{0.5 \cdot B}{A}\right)}}} \]
        4. associate-/l*68.0%

          \[\leadsto \frac{180}{\frac{\pi}{\tan^{-1} \color{blue}{\left(\frac{0.5}{\frac{A}{B}}\right)}}} \]
        5. associate-/r/67.9%

          \[\leadsto \color{blue}{\frac{180}{\pi} \cdot \tan^{-1} \left(\frac{0.5}{\frac{A}{B}}\right)} \]
        6. associate-/l*68.1%

          \[\leadsto \frac{180}{\pi} \cdot \tan^{-1} \color{blue}{\left(\frac{0.5 \cdot B}{A}\right)} \]
        7. *-commutative68.1%

          \[\leadsto \frac{180}{\pi} \cdot \tan^{-1} \left(\frac{\color{blue}{B \cdot 0.5}}{A}\right) \]
        8. associate-/l*68.1%

          \[\leadsto \frac{180}{\pi} \cdot \tan^{-1} \color{blue}{\left(\frac{B}{\frac{A}{0.5}}\right)} \]
      8. Simplified68.1%

        \[\leadsto \color{blue}{\frac{180}{\pi} \cdot \tan^{-1} \left(\frac{B}{\frac{A}{0.5}}\right)} \]

      if -5.0999999999999998e39 < A

      1. Initial program 66.8%

        \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
      2. Add Preprocessing
      3. Taylor expanded in B around -inf 59.6%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\left(1 + \frac{C}{B}\right) - \frac{A}{B}\right)}}{\pi} \]
      4. Step-by-step derivation
        1. associate--l+59.6%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(1 + \left(\frac{C}{B} - \frac{A}{B}\right)\right)}}{\pi} \]
        2. div-sub60.1%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \color{blue}{\frac{C - A}{B}}\right)}{\pi} \]
      5. Simplified60.1%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(1 + \frac{C - A}{B}\right)}}{\pi} \]
    3. Recombined 2 regimes into one program.
    4. Final simplification61.9%

      \[\leadsto \begin{array}{l} \mathbf{if}\;A \leq -5.1 \cdot 10^{+39}:\\ \;\;\;\;\frac{180}{\pi} \cdot \tan^{-1} \left(\frac{B}{\frac{A}{0.5}}\right)\\ \mathbf{else}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(1 + \frac{C - A}{B}\right)}{\pi}\\ \end{array} \]
    5. Add Preprocessing

    Alternative 14: 39.7% accurate, 3.8× speedup?

    \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;B \leq -5 \cdot 10^{-310}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} 1}{\pi}\\ \mathbf{else}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} -1}{\pi}\\ \end{array} \end{array} \]
    (FPCore (A B C)
     :precision binary64
     (if (<= B -5e-310) (* 180.0 (/ (atan 1.0) PI)) (* 180.0 (/ (atan -1.0) PI))))
    double code(double A, double B, double C) {
    	double tmp;
    	if (B <= -5e-310) {
    		tmp = 180.0 * (atan(1.0) / ((double) M_PI));
    	} else {
    		tmp = 180.0 * (atan(-1.0) / ((double) M_PI));
    	}
    	return tmp;
    }
    
    public static double code(double A, double B, double C) {
    	double tmp;
    	if (B <= -5e-310) {
    		tmp = 180.0 * (Math.atan(1.0) / Math.PI);
    	} else {
    		tmp = 180.0 * (Math.atan(-1.0) / Math.PI);
    	}
    	return tmp;
    }
    
    def code(A, B, C):
    	tmp = 0
    	if B <= -5e-310:
    		tmp = 180.0 * (math.atan(1.0) / math.pi)
    	else:
    		tmp = 180.0 * (math.atan(-1.0) / math.pi)
    	return tmp
    
    function code(A, B, C)
    	tmp = 0.0
    	if (B <= -5e-310)
    		tmp = Float64(180.0 * Float64(atan(1.0) / pi));
    	else
    		tmp = Float64(180.0 * Float64(atan(-1.0) / pi));
    	end
    	return tmp
    end
    
    function tmp_2 = code(A, B, C)
    	tmp = 0.0;
    	if (B <= -5e-310)
    		tmp = 180.0 * (atan(1.0) / pi);
    	else
    		tmp = 180.0 * (atan(-1.0) / pi);
    	end
    	tmp_2 = tmp;
    end
    
    code[A_, B_, C_] := If[LessEqual[B, -5e-310], N[(180.0 * N[(N[ArcTan[1.0], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision], N[(180.0 * N[(N[ArcTan[-1.0], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision]]
    
    \begin{array}{l}
    
    \\
    \begin{array}{l}
    \mathbf{if}\;B \leq -5 \cdot 10^{-310}:\\
    \;\;\;\;180 \cdot \frac{\tan^{-1} 1}{\pi}\\
    
    \mathbf{else}:\\
    \;\;\;\;180 \cdot \frac{\tan^{-1} -1}{\pi}\\
    
    
    \end{array}
    \end{array}
    
    Derivation
    1. Split input into 2 regimes
    2. if B < -4.999999999999985e-310

      1. Initial program 62.4%

        \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
      2. Add Preprocessing
      3. Taylor expanded in B around -inf 40.4%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{1}}{\pi} \]

      if -4.999999999999985e-310 < B

      1. Initial program 54.0%

        \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
      2. Add Preprocessing
      3. Taylor expanded in B around inf 41.5%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{-1}}{\pi} \]
    3. Recombined 2 regimes into one program.
    4. Final simplification41.0%

      \[\leadsto \begin{array}{l} \mathbf{if}\;B \leq -5 \cdot 10^{-310}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} 1}{\pi}\\ \mathbf{else}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} -1}{\pi}\\ \end{array} \]
    5. Add Preprocessing

    Alternative 15: 21.0% accurate, 4.0× speedup?

    \[\begin{array}{l} \\ 180 \cdot \frac{\tan^{-1} -1}{\pi} \end{array} \]
    (FPCore (A B C) :precision binary64 (* 180.0 (/ (atan -1.0) PI)))
    double code(double A, double B, double C) {
    	return 180.0 * (atan(-1.0) / ((double) M_PI));
    }
    
    public static double code(double A, double B, double C) {
    	return 180.0 * (Math.atan(-1.0) / Math.PI);
    }
    
    def code(A, B, C):
    	return 180.0 * (math.atan(-1.0) / math.pi)
    
    function code(A, B, C)
    	return Float64(180.0 * Float64(atan(-1.0) / pi))
    end
    
    function tmp = code(A, B, C)
    	tmp = 180.0 * (atan(-1.0) / pi);
    end
    
    code[A_, B_, C_] := N[(180.0 * N[(N[ArcTan[-1.0], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision]
    
    \begin{array}{l}
    
    \\
    180 \cdot \frac{\tan^{-1} -1}{\pi}
    \end{array}
    
    Derivation
    1. Initial program 58.1%

      \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
    2. Add Preprocessing
    3. Taylor expanded in B around inf 22.3%

      \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{-1}}{\pi} \]
    4. Final simplification22.3%

      \[\leadsto 180 \cdot \frac{\tan^{-1} -1}{\pi} \]
    5. Add Preprocessing

    Reproduce

    ?
    herbie shell --seed 2024031 
    (FPCore (A B C)
      :name "ABCF->ab-angle angle"
      :precision binary64
      (* 180.0 (/ (atan (* (/ 1.0 B) (- (- C A) (sqrt (+ (pow (- A C) 2.0) (pow B 2.0)))))) PI)))